99 bottles of beer
Display the complete lyrics for the song: 99 Bottles of Beer on the Wall.
![Task](http://static.miraheze.org/rosettacodewiki/thumb/b/ba/Rcode-button-task-crushed.png/64px-Rcode-button-task-crushed.png)
You are encouraged to solve this task according to the task description, using any language you may know.
- Task
- The beer song
The lyrics follow this form:
- 99 bottles of beer on the wall
- 99 bottles of beer
- Take one down, pass it around
- 98 bottles of beer on the wall
- 98 bottles of beer on the wall
- 98 bottles of beer
- Take one down, pass it around
- 97 bottles of beer on the wall
... and so on, until reaching 0 (zero).
Grammatical support for 1 bottle of beer is optional.
As with any puzzle, try to do it in as creative/concise/comical a way as possible (simple, obvious solutions allowed, too).
- Metrics
- Counting
- Word frequency
- Letter frequency
- Jewels and stones
- I before E except after C
- Bioinformatics/base count
- Count occurrences of a substring
- Count how many vowels and consonants occur in a string
- Remove/replace
- XXXX redacted
- Conjugate a Latin verb
- Remove vowels from a string
- String interpolation (included)
- Strip block comments
- Strip comments from a string
- Strip a set of characters from a string
- Strip whitespace from a string -- top and tail
- Strip control codes and extended characters from a string
- Anagrams/Derangements/shuffling
- Word wheel
- ABC problem
- Sattolo cycle
- Knuth shuffle
- Ordered words
- Superpermutation minimisation
- Textonyms (using a phone text pad)
- Anagrams
- Anagrams/Deranged anagrams
- Permutations/Derangements
- Find/Search/Determine
- ABC words
- Odd words
- Word ladder
- Semordnilap
- Word search
- Wordiff (game)
- String matching
- Tea cup rim text
- Alternade words
- Changeable words
- State name puzzle
- String comparison
- Unique characters
- Unique characters in each string
- Extract file extension
- Levenshtein distance
- Palindrome detection
- Common list elements
- Longest common suffix
- Longest common prefix
- Compare a list of strings
- Longest common substring
- Find common directory path
- Words from neighbour ones
- Change e letters to i in words
- Non-continuous subsequences
- Longest common subsequence
- Longest palindromic substrings
- Longest increasing subsequence
- Words containing "the" substring
- Sum of the digits of n is substring of n
- Determine if a string is numeric
- Determine if a string is collapsible
- Determine if a string is squeezable
- Determine if a string has all unique characters
- Determine if a string has all the same characters
- Longest substrings without repeating characters
- Find words which contains all the vowels
- Find words which contain the most consonants
- Find words which contains more than 3 vowels
- Find words whose first and last three letters are equal
- Find words with alternating vowels and consonants
- Formatting
- Substring
- Rep-string
- Word wrap
- String case
- Align columns
- Literals/String
- Repeat a string
- Brace expansion
- Brace expansion using ranges
- Reverse a string
- Phrase reversals
- Comma quibbling
- Special characters
- String concatenation
- Substring/Top and tail
- Commatizing numbers
- Reverse words in a string
- Suffixation of decimal numbers
- Long literals, with continuations
- Numerical and alphabetical suffixes
- Abbreviations, easy
- Abbreviations, simple
- Abbreviations, automatic
- Song lyrics/poems/Mad Libs/phrases
- Mad Libs
- Magic 8-ball
- 99 bottles of beer
- The Name Game (a song)
- The Old lady swallowed a fly
- The Twelve Days of Christmas
- Tokenize
- Text between
- Tokenize a string
- Word break problem
- Tokenize a string with escaping
- Split a character string based on change of character
- Sequences
- See also
- http://99-bottles-of-beer.net/
- Category:99_Bottles_of_Beer
- Category:Programming language families
- Wikipedia 99 bottles of beer
0815
11l
L(i) (99..1).step(-1)
print(i‘ bottles of beer on the wall’)
print(i‘ bottles of beer’)
print(‘Take one down, pass it around’)
print((i - 1)" bottles of beer on the wall\n")
360 Assembly
6502 Assembly
6800 Assembly
68000 Assembly
8080 Assembly
8th
\ 99 bottles of beer on the wall:
[
"no more bottles" ,
"one bottle" ,
( dup . " bottles" )
] var, bottles
: .bottles
dup 2 n:min bottles @ caseof ;
: .beer
.bottles . " of beer" . ;
: .wall
.beer " on the wall" . ;
: .take
" Take one down and pass it around" . ;
: beers
.wall ", " . .beer '; putc cr
n:1- 0 max .take ", " .
.wall '. putc cr drop ;
' beers 1 99 loop-
bye
A more terse alternative:
[
( "Just one more bottle of beer on the wall, one bottle of beer.\n" . ) ,
( I dup "%d bottles of beer on the wall, %d bottles of beer.\n" s:strfmt . )
] constant lyrics
: app:main
(
dup lyrics [2,99] rot ' n:cmp a:pigeon w:exec
n:1- "Take one down, pass it around, %d bottles of beer on the wall.\n\n" s:strfmt .
) 1 99 loop-
"No more bottles of beer on the wall, no more bottles of beer.\n" . ;
AArch64 Assembly
/* ARM assembly AARCH64 Raspberry PI 3B */
/* program bootleBeer64.s */
/*******************************************/
/* Constantes file */
/*******************************************/
/* for this file see task include a file in language AArch64 assembly*/
.include "../includeConstantesARM64.inc"
.equ MAXI, 99
/*********************************/
/* Initialized data */
/*********************************/
.data
szMessLine1: .asciz "@ bottles of beer on the wall\n"
szMessLine2: .ascii "@ bottles of beer\n"
.asciz "Take one down, pass it around\n"
szMessLine3: .asciz "@ bottles of beer on the wall\n\n"
szMessLine4: .ascii "\nNo more bottles of beer on the wall, no more bottles of beer.\n"
.asciz "Go to the store and buy some more, 99 bottles of beer on the wall.\n"
szCarriageReturn: .asciz "\n"
/*********************************/
/* UnInitialized data */
/*********************************/
.bss
sZoneConv: .skip 24
/*********************************/
/* code section */
/*********************************/
.text
.global main
main: // entry of program
mov x2,#MAXI
1:
mov x0,x2
ldr x1,qAdrsZoneConv
bl conversion10 // call decimal conversion
ldr x0,qAdrszMessLine1
ldr x1,qAdrsZoneConv // insert conversion in message
bl strInsertAtCharInc
bl affichageMess
ldr x0,qAdrszMessLine2
ldr x1,qAdrsZoneConv // insert conversion in message
bl strInsertAtCharInc
bl affichageMess
subs x0,x2,#1
ble 2f
ldr x1,qAdrsZoneConv
bl conversion10 // call decimal conversion
ldr x0,qAdrszMessLine3
ldr x1,qAdrsZoneConv // insert conversion in message
bl strInsertAtCharInc
bl affichageMess
2:
subs x2,x2,1
bgt 1b
ldr x0,qAdrszMessLine4
bl affichageMess
100: // standard end of the program
mov x0, #0 // return code
mov x8, #EXIT // request to exit program
svc #0 // perform the system call
qAdrszCarriageReturn: .quad szCarriageReturn
qAdrszMessLine1: .quad szMessLine1
qAdrszMessLine2: .quad szMessLine2
qAdrszMessLine3: .quad szMessLine3
qAdrszMessLine4: .quad szMessLine4
qAdrsZoneConv: .quad sZoneConv
/********************************************************/
/* File Include fonctions */
/********************************************************/
/* for this file see task include a file in language AArch64 assembly */
.include "../includeARM64.inc"
ABAP
REPORT z99bottles.
DATA lv_no_bottles(2) TYPE n VALUE 99.
DO lv_no_bottles TIMES.
WRITE lv_no_bottles NO-ZERO.
WRITE ' bottles of beer on the wall'.
NEW-LINE.
WRITE lv_no_bottles NO-ZERO.
WRITE ' bottles of beer'.
NEW-LINE.
WRITE 'Take one down, pass it around'.
NEW-LINE.
SUBTRACT 1 FROM lv_no_bottles.
WRITE lv_no_bottles NO-ZERO.
WRITE ' bottles of beer on the wall'.
WRITE /.
ENDDO.
or (With ABAP 7.40)
REPORT YCL_99_BOTTLES.
DATA it_99_bottles TYPE TABLE OF string WITH EMPTY KEY.
DATA(cr_lf) = cl_abap_char_utilities=>cr_lf.
it_99_bottles = VALUE #(
FOR i = 99 THEN i - 1 UNTIL i = 0 ( COND string( LET lv = ( i - 1 )
lr = i && | bottles of beer on the wall|
&& cr_lf
&& i && | bottles of beer|
&& cr_lf
&& |Take one down, pass it around|
&& cr_lf
&& lv && | bottles of beer on the wall|
&& cr_lf IN WHEN 1 = 1 THEN lr )
)
).
cl_demo_output=>write( it_99_bottles ).
cl_demo_output=>display( ).
ABC
HOW TO RETURN bottles n:
SELECT:
n<0: RETURN "99 bottles"
n=0: RETURN "No more bottles"
n=1: RETURN "1 bottle"
n>1: RETURN "`n` bottles"
HOW TO SING VERSE n:
WRITE "`bottles n` of beer on the wall,"/
WRITE "`bottles n` of beer,"/
SELECT:
n=0: WRITE "Go to the store and buy some more,"/
n=1: WRITE "Take it down and pass it around,"/
n>1: WRITE "Take one down and pass it around,"/
WRITE "`bottles (n-1)` of beer on the wall."/
WRITE /
FOR n IN {0..99}:
SING VERSE 99-n
ACL2
Acornsoft Lisp
Action!
PROC Bottles(BYTE i)
IF i=0 THEN
Print("No more")
ELSE
PrintB(i)
FI
Print(" bottle")
IF i#1 THEN
Print("s")
FI
RETURN
PROC Main()
BYTE i=[99]
WHILE i>0
DO
Bottles(i) PrintE(" of beer on the wall,")
Bottles(i) PrintE(" of beer,")
Print("Take ")
IF i>1 THEN
Print("one")
ELSE
Print("it")
FI
PrintE(" down and pass it around,")
i==-1
Bottles(i) PrintE(" of beer on the wall.")
IF i>0 THEN
PutE()
FI
OD
RETURN
- Output:
Screenshot from Atari 8-bit computer
99 bottles of beer on the wall, 99 bottles of beer, Take one down and pass it around, 98 bottles of beer on the wall. ... 2 bottles of beer on the wall, 2 bottles of beer, Take one down and pass it around, 1 bottle of beer on the wall. 1 bottle of beer on the wall, 1 bottle of beer, Take it down and pass it around, No more bottles of beer on the wall.
ActionScript
for(var numBottles:uint = 99; numBottles > 0; numBottles--)
{
trace(numBottles, " bottles of beer on the wall");
trace(numBottles, " bottles of beer");
trace("Take one down, pass it around");
trace(numBottles - 1, " bottles of beer on the wall\n");
}
Ada
Simple version
with Ada.Text_Io; use Ada.Text_Io;
procedure Bottles is
begin
for X in reverse 1..99 loop
Put_Line(Integer'Image(X) & " bottles of beer on the wall");
Put_Line(Integer'Image(X) & " bottles of beer");
Put_Line("Take one down, pass it around");
Put_Line(Integer'Image(X - 1) & " bottles of beer on the wall");
New_Line;
end loop;
end Bottles;
Concurrent version
with 1 task to print out the information and 99 tasks to specify the number of bottles
with Ada.Text_Io; use Ada.Text_Io;
procedure Tasking_99_Bottles is
subtype Num_Bottles is Natural range 1..99;
task Print is
entry Set (Num_Bottles);
end Print;
task body Print is
Num : Natural;
begin
for I in reverse Num_Bottles'range loop
select
accept
Set(I) do -- Rendezvous with Counter task I
Num := I;
end Set;
Put_Line(Integer'Image(Num) & " bottles of beer on the wall");
Put_Line(Integer'Image(Num) & " bottles of beer");
Put_Line("Take one down, pass it around");
Put_Line(Integer'Image(Num - 1) & " bottles of beer on the wall");
New_Line;
or terminate; -- end when all Counter tasks have completed
end select;
end loop;
end Print;
task type Counter(I : Num_Bottles);
task body Counter is
begin
Print.Set(I);
end Counter;
type Task_Access is access Counter;
Task_List : array(Num_Bottles) of Task_Access;
begin
for I in Task_List'range loop -- Create 99 Counter tasks
Task_List(I) := new Counter(I);
end loop;
end Tasking_99_Bottles;
Aime
integer bottles;
bottles = 99;
do {
o_(bottles, " bottles of beer on the wall\n");
o_(bottles, " bottles of beer\n");
o_("Take one down, pass it around\n");
o_(bottles -= 1, " bottles of beer on the wall\n\n");
} while (bottles);
Algae
# 99 Bottles of Beer on the Wall
# in Algae
# bottles.A
for (i in 99:1:1) {
if (i != 1) {
printf("%d bottles of beer on the wall\n";i);
printf("%d bottles of beer...\n";i);
printf("you take on down and pass it around...\n");
if ( i == 2) {
printf("%d bottles of beer on the wall\n\n";i-1);
else
printf("%d bottles of beer on the wall\n\n";i-1);
}
else
printf("1 bottle of beer on the wall\n");
printf("1 bottle of beer...\n");
printf("you take on down and pass it around..\n");
printf("no more bottles of beer on the wall!\n\n");
}
}
ALGOL 60
begin
integer n;
for n:= 99 step -1 until 2 do
begin
outinteger(1,n);
outstring(1,"bottles of beer on the wall,");
outinteger(1,n);
outstring(1,"bottles of beer.\nTake one down and pass it around,");
outstring(1,"of beer on the wall...\n\n")
end;
outstring(1," 1 bottle of beer on the wall, 1 bottle of beer.\n");
outstring(1,"Take one down and pass it around, no more bottles of beer on the wall...\n\n");
outstring(1,"No more bottles of beer on the wall, no more bottles of beer.\n");
outstring(1,"Go to the store and buy some more, 99 bottles of beer on the wall.")
end
ALGOL 68
main:(
FOR bottles FROM 99 TO 1 BY -1 DO
printf(($z-d" bottles of beer on the wall"l$, bottles));
printf(($z-d" bottles of beer"l$, bottles));
printf(($"Take one down, pass it around"l$));
printf(($z-d" bottles of beer on the wall"ll$, bottles-1))
OD
)
ALGOL-M
BEGIN
COMMENT PRINT LYRICS TO "99 BOTTLES OF BEER ON THE WALL";
STRING FUNCTION BOTTLE(N); % GIVE CORRECT GRAMMATICAL FORM %
INTEGER N;
BEGIN
IF N = 1 THEN
BOTTLE := " BOTTLE"
ELSE
BOTTLE := " BOTTLES";
END;
INTEGER N;
N := 99;
WHILE N > 0 DO
BEGIN
WRITE(N, BOTTLE(N), " OF BEER ON THE WALL,");
WRITEON(N, BOTTLE(N), " OF BEER");
WRITE("TAKE ONE DOWN AND PASS IT AROUND, ");
N := N - 1;
IF N = 0 THEN
WRITEON("NO MORE")
ELSE
WRITEON(N);
WRITEON(BOTTLE(N), " OF BEER ON THE WALL");
WRITE(" "); % BLANK LINE BETWEEN STANZAS %
END;
WRITE("THANKS FOR SINGING ALONG!");
END
AmigaE
PROC main()
DEF t: PTR TO CHAR,
s: PTR TO CHAR,
u: PTR TO CHAR, i, x
t := 'Take one down, pass it around\n'
s := '\d bottle\s of beer\s\n'
u := ' on the wall'
FOR i := 99 TO 0 STEP -1
ForAll({x}, [u, NIL], `WriteF(s, i, IF i <> 1 THEN 's' ELSE NIL,
x))
IF i > 0 THEN WriteF(t)
ENDFOR
ENDPROC
Apache Ant
Implementation in Apache Ant, due to the limitations of Ant, this requires ant-contrib for arithmetic operations and a dummy target to keep Ant from detecting the loop.
<?xml version="1.0"?>
<project name="n bottles" default="99_bottles">
<!-- ant-contrib.sourceforge.net for arithmetic and if -->
<taskdef resource="net/sf/antcontrib/antcontrib.properties"/>
<!-- start count of bottles, you can set this with
e.g. ant -f 99.xml -Dcount=10 -->
<property name="count" value="99"/>
<target name="99_bottles">
<antcall target="bottle">
<param name="number" value="${count}"/>
</antcall>
</target>
<target name="bottle">
<echo message="${number} bottles of beer on the wall"/>
<echo message="${number} bottles of beer"/>
<echo message="Take one down, pass it around"/>
<math result="result" operand1="${number}" operation="-" operand2="1" datatype="int"/>
<echo message="${result} bottles of beer on the wall"/>
<if>
<not><equals arg1="${result}" arg2="0" /></not>
<then>
<antcall target="bottleiterate">
<param name="number" value="${result}"/>
</antcall>
</then>
</if>
</target>
<target name="bottleiterate">
<antcall target="bottle">
<param name="number" value="${number}"/>
</antcall>
</target>
</project>
Apex
for(Integer i = 99; i=0; i--){
system.debug(i + ' bottles of beer on the wall');
system.debug('\n');
system.debug(i + ' bottles of beer on the wall');
system.debug(i + ' bottles of beer');
system.debug('take one down, pass it around');
}
APL
Classic version
bob ← { (⍕⍵), ' bottle', (1=⍵)↓'s of beer'} bobw ← {(bob ⍵) , ' on the wall'} beer ← { (bobw ⍵) , ', ', (bob ⍵) , '; take one down and pass it around, ', bobw ⍵-1}
⍝ Dyalog APL invocation 99↑beer¨ ⌽(1-⎕IO)+⍳99
⍝ GNU APL invocation (↑ and ⊃ differ, traditional APL2 meanings) ⊃beer¨ ⌽(1-⎕IO)+⍳99
One line version
⍝ Dyalog and GNU APL ⍪{(⍕⍵),' bottles of beer on the wall, take one down and pass it around, ',(⍕⍵-1),' bottles of beer on the wall'}¨⌽⍳99
App Inventor
Using a 'for each <number>' block (simplest)
Note that the output label text is not displayed until the entire lyrics text has been built and there is some delay between button press and display. <CLICK HERE TO VIEW THE BLOCKS AND OUTPUT>
Using a Clock Timer block (preferrred)
Output can be sent directly to a label with this preferred method as there is no noticeable delay between button press and output. <CLICK HERE TO VIEW THE BLOCKS AND OUTPUT>
AppleScript
Iteration
repeat with beerCount from 99 to 1 by -1
set bottles to "bottles"
if beerCount < 99 then
if beerCount = 1 then
set bottles to "bottle"
end
log "" & beerCount & " " & bottles & " of beer on the wall"
log ""
end
log "" & beerCount & " " & bottles & " of beer on the wall"
log "" & beerCount & " " & bottles & " of beer"
log "Take one down, pass it around"
end
log "No more bottles of beer on the wall!"
Declaration
-- BRIEF -----------------------------------------------------------------------
on run
set localisations to ¬
{"on the wall", ¬
"Take one down, pass it around", ¬
"Better go to the store to buy some more", "bottle"}
intercalate("\n\n", ¬
(map(curry(incantation)'s |λ|(localisations), enumFromTo(99, 0))))
end run
-- DECLARATIVE -----------------------------------------------------------------
-- incantation :: [String] -> Int -> String
on incantation(xs, n)
script asset
on |λ|(n)
unwords({(n as string), item -1 of xs & cond(n ≠ 1, "s", "")})
end |λ|
end script
script store
on |λ|(n)
unwords({asset's |λ|(n), item 1 of xs})
end |λ|
end script
set {distribute, solve} to items 2 thru 3 of xs
if n > 0 then
unlines({store's |λ|(n), asset's |λ|(n), distribute, store's |λ|(n - 1)})
else
solve
end if
end incantation
-- GENERICALLY DYSFUNCTIONAL ---------------------------------------------------
-- cond :: Bool -> a -> a -> a
on cond(bln, f, g)
if bln then
f
else
g
end if
end cond
-- curry :: (Script|Handler) -> Script
on curry(f)
script
on |λ|(a)
script
on |λ|(b)
|λ|(a, b) of mReturn(f)
end |λ|
end script
end |λ|
end script
end curry
-- enumFromTo :: Int -> Int -> [Int]
on enumFromTo(m, n)
if m > n then
set d to -1
else
set d to 1
end if
set lst to {}
repeat with i from m to n by d
set end of lst to i
end repeat
return lst
end enumFromTo
-- intercalate :: Text -> [Text] -> Text
on intercalate(strText, lstText)
set {dlm, my text item delimiters} to {my text item delimiters, strText}
set strJoined to lstText as text
set my text item delimiters to dlm
return strJoined
end intercalate
-- map :: (a -> b) -> [a] -> [b]
on map(f, xs)
tell mReturn(f)
set lng to length of xs
set lst to {}
repeat with i from 1 to lng
set end of lst to |λ|(item i of xs, i, xs)
end repeat
return lst
end tell
end map
-- Lift 2nd class handler function into 1st class script wrapper
-- mReturn :: Handler -> Script
on mReturn(f)
if class of f is script then
f
else
script
property |λ| : f
end script
end if
end mReturn
-- unlines :: [String] -> String
on unlines(xs)
intercalate(linefeed, xs)
end unlines
-- unwords :: [String] -> String
on unwords(xs)
intercalate(space, xs)
end unwords
Arbre
bottle(x):
template: '
$x bottles of beer on the wall.
$x bottles of beer.
Take one down and pass it around,
$y bottles of beer on the wall.
'
if x==0
template~{x: 'No more', y: 'No more'}
else
if x==1
template~{x: x, y: 'No more'}
else
template~{x: x, y: x-1}
bottles(n):
for x in [n..0]
bottle(x)
99bottles():
bottles(99) -> io
Argile
use std
let X be an int
for each X from 99 down to 1
prints X bottles of beer on the wall
prints X bottles of beer
prints "Take one down, pass it" around
if X == 1
echo No more "beer." Call da "amber lamps"
break
X--
prints X bottles of beer on the wall "\n"
X++
.:around :. -> text {X>59 ? "around", "to me"}
.:bottles:. -> text {X> 5 ? "bottles", (X>1 ? "buttles", "wall")}
.:of beer:. -> text {X>11 ? "of beer", "ov beeer"}
.:on the wall:. -> text {
X>17 ? "on the wall", (X>1 ? "on the bwall", "in the buttle")
}
ARM Assembly
ArnoldC
As ArnoldC does not feature string concatenation, the numbers of bottles and the rest of the parts of the lyrics are printed on separate lines.
IT'S SHOWTIME
HEY CHRISTMAS TREE is0
YOU SET US UP @NO PROBLEMO
HEY CHRISTMAS TREE bottles
YOU SET US UP 99
STICK AROUND is0
TALK TO THE HAND bottles
TALK TO THE HAND " bottles of beer on the wall"
TALK TO THE HAND bottles
TALK TO THE HAND " bottles of beer"
TALK TO THE HAND "Take one down, pass it around"
GET TO THE CHOPPER bottles
HERE IS MY INVITATION bottles
GET DOWN 1
ENOUGH TALK
TALK TO THE HAND bottles
TALK TO THE HAND " bottles of beer on the wall"
GET TO THE CHOPPER is0
HERE IS MY INVITATION bottles
LET OFF SOME STEAM BENNET 0
ENOUGH TALK
CHILL
YOU HAVE BEEN TERMINATED
Arturo
s: "s"
loop 99..1 'i [
print ~"|i| bottle|s| of beer on the wall,"
print ~"|i| bottle|s| of beer"
print ~"Take one down, pass it around!"
if 1=i-1 -> s: ""
if? i>1 [
print ~"|i-1| bottle|s| of beer on the wall!"
print ""
]
else -> print "No more bottles of beer on the wall!"
]
AsciiDots
/-99#-.
/>*$_#-$_" bottles of beer on the wall, "-$_#-$" bottles of beer."\
|[-]1#-----" ,dnuora ti ssap dna nwod eno ekaT"_$-----------------/
| |
| | &-".llaw eht no reeb fo selttob 99 ,erom emos yub dna erots eht ot oG"$\
| |/$""-$"No more bottles of beer on the wall, no more bottles of beer."---/
| |\".llaw eht no reeb fo selttob erom on ,dnuora ti ssap dna nwod eno ekaT"$-".reeb fo elttob 1"$\
| | /-$"1 bottle of beer on the wall."-$""-$_"1 bottle of beer on the wall, "------------/
| | /-------\|
| \-*--{=}-\\~$_#-$" bottles of beer on the wall."\
| \-#1/ \-/ |
\----------------------------------------------""$/
Astro
fun bottles(n): match __args__:
(0) => "No more bottles"
(1) => "1 bottle"
(_) => "$n bottles"
for n in 99..-1..1:
print @format"""
{bottles n} of beer on the wall
{bottles n} of beer
Take one down, pass it around
{bottles n-1} of beer on the wall\n
"""
Asymptote
// Rosetta Code problem: http://rosettacode.org/wiki/99_bottles_of_beer
// by Jjuanhdez, 05/2022
int bottles = 99;
for (int i = bottles; i > 0; --i) {
write(string(i), " bottles of beer on the wall,");
write(string(i), " bottles of beer.");
write("Take one down and pass it around,");
if (i == 1) {
write("no more bottles of beer on the wall...");
} else {
write(string(i-1), " bottles of beer on the wall...");
}
}
write("No more bottles of beer on the wall,");
write("no more bottles of beer.");
write("Go to the store and buy some more,");
write(" 99 bottles of beer on the wall.");
ATS
//
#include
"share/atspre_staload.hats"
//
(* ****** ****** *)
fun bottles
(n0: int): void = let
//
fun loop (n: int): void =
(
if n > 0 then
(
if n0 > n then println! ();
println! (n, " bottles of beer on the wall");
println! (n, " bottles of beer");
println! ("Take one down, pass it around");
println! (n-1, " bottles of beer on the wall");
loop (n - 1)
) (* end of [if] *)
)
//
in
loop (n0)
end // end of [bottles]
(* ****** ****** *)
implement main0 () = bottles (99)
AutoHotkey
AutoIt
AWK
Regular version
If you don't want so many beers, here you can specify the starting amount.
For example, just a sixpack:
# usage: gawk -v i=6 -f beersong.awk
function bb(n) {
b = " bottles of beer"
if( n==1 ) { sub("s","",b) }
if( n==0 ) { n="No more" }
return n b
}
BEGIN {
if( !i ) { i = 99 }
ow = "on the wall"
td = "Take one down, pass it around."
print "The beersong:\n"
while (i > 0) {
printf( "%s %s,\n%s.\n%s\n%s %s.\n\n",
bb(i), ow, bb(i), td, bb(--i), ow )
if( i==1 ) sub( "one","it", td )
}
print "Go to the store and buy some more!"
}
- Output:
The beersong: 99 bottles of beer on the wall, 99 bottles of beer. Take one down, pass it around. 98 bottles of beer on the wall. ... 3 bottles of beer on the wall, 3 bottles of beer. Take one down, pass it around. 2 bottles of beer on the wall. 2 bottles of beer on the wall, 2 bottles of beer. Take one down, pass it around. 1 bottle of beer on the wall. 1 bottle of beer on the wall, 1 bottle of beer. Take it down, pass it around. No more bottles of beer on the wall. Go to the store and buy some more!
Bottled version
Axe
Pauses are added to accommodate the small calculator screen so all of the text can be read.
99→B
While B
Disp B▶Dec," BOTTLES OF","BEER ON THE WALL"
Disp B▶Dec," BOTTLES OF","BEER",i,i
getKeyʳ
Disp "TAKE ONE DOWN",i,"PASS IT AROUND",i
B--
Disp B▶Dec," BOTTLES OF","BEER ON THE WALL",i
getKeyʳ
End
Babel
-- beer.sp
{b " bottles of beer" <
bi { itoa << } <
bb { bi ! b << w << "\n" << } <
w " on the wall" <
beer
{<-
{ iter 1 + dup
<- bb ! ->
bi ! b << "\n" <<
"Take one down, pass it around\n" <<
iter bb ! "\n" << }
->
times}
< }
-- At the prompt, type 'N beer !' (no quotes), where N is the number of stanzas you desire
BabyCobol
* Pointing out some interesting things:
* - BY 0 subclause of VARYING (illegal in some COBOL dialects)
* - PERFORM THROUGH with internal/external GO TOs
* - using non-reserved keywords (END, DATA)
* - ALTER (works the same way in COBOL)
* - fall-through from MANY-BOTTLES
* - the last NEXT SENTENCE does nothing (plays the role of EXIT)
IDENTIFICATION DIVISION.
PROGRAM-ID. 99 BOTTLES.
DATA DIVISION.
01 DATA PICTURE IS 999.
PROCEDURE DIVISION.
LOOP VARYING DATA FROM 99 BY 0
PERFORM COUNT-BOTTLES THROUGH END
DISPLAY DATA "bottles of beer"
DISPLAY "Take one down, pass it around"
SUBTRACT 1 FROM DATA
IF DATA = 1
THEN ALTER COUNT-BOTTLES TO PROCEED TO SINGLE-BOTTLE
END
PERFORM COUNT-BOTTLES THROUGH END
DISPLAY ""
END.
NO-BOTTLES-LEFT.
DISPLAY "No bottles of beer on the wall"
DISPLAY ""
DISPLAY "Go to the store and buy some more"
DISPLAY "99 bottles of beer on the wall".
STOP.
COUNT-BOTTLES.
GO TO MANY-BOTTLES.
SINGLE-BOTTLE.
DISPLAY DATA "bottle of beer on the wall".
GO TO NO-BOTTLES-LEFT.
MANY-BOTTLES.
DISPLAY DATA "bottles of beer on the wall".
END.
NEXT SENTENCE.
BASIC
Applesoft BASIC
BaCon
See 99 Bottles of Beer/Basic#BaCon
BASIC256
BBC BASIC
Commodore BASIC
See 99 Bottles of Beer/Basic#Commodore_BASIC
Craft Basic
See 99 Bottles of Beer/Basic#Craft_Basic
Creative Basic
FBSL
FreeBASIC
FUZE BASIC
GW-BASIC
Integer BASIC
Liberty BASIC
Microsoft Small Basic
Minimal BASIC
MSX Basic
OxygenBasic
PowerBASIC
PureBasic
QB64
QBasic
QuickBASIC
REALbasic
Run BASIC
Sinclair ZX81 BASIC
smart BASIC
TI-83 BASIC
TI-89 BASIC
Tiny BASIC
True BASIC
Visual Basic
Visual Basic .NET
XBasic
Yabasic
ZX Spectrum Basic
Batch File
Battlestar
const bottle = " bottle"
const plural = "s"
const ofbeer = " of beer"
const wall = " on the wall"
const sep = ", "
const takedown = "Take one down and pass it around, "
const u_no = "No"
const l_no = "no"
const more = " more bottles of beer"
const store = "Go to the store and buy some more, "
const dotnl = ".\n"
const nl = "\n"
// Reserve 1024 bytes in the .bss section
var x 1024
// Write two digits, based on the value in a
fun printnum
b = a
a >= 10
a /= 10
// modulo is in the d register after idiv
b = d
a += 48 // ASCII value for '0'
print(chr(a))
end
a = b
a += 48 // ASCII value for '0'
print(chr(a))
end
fun main
loop 99
// Save loop counter for later, twice
c -> stack
c -> stack
// Print the loop counter (passed in the a register)
a = c
printnum()
// N, "bottles of beer on the wall, "
x = bottle
x += plural
x += ofbeer
x += wall
x += sep
print(x)
// Retrieve and print the number
stack -> a
printnum()
// N, "bottles of beer.\nTake one down and pass it around,"
x = bottle
x += plural
x += ofbeer
x += dotnl
x += takedown
print(x)
// N-1, "bottles of beer on the wall."
stack -> a
a--
// Store N-1, used just a few lines down
a -> stack
printnum()
print(bottle)
// Retrieve N-1
stack -> a
// Write an "s" if the count is not 1
a != 1
print(plural)
end
// Write the rest + a blank line
x = ofbeer
x += wall
x += dotnl
x += nl
print(x)
// Skip to the top of the loop while the counter is >= 2
continue (c >= 2)
// At the last two
// "1 bottle of beer on the wall,"
a = 1
printnum()
x = bottle
x += ofbeer
x += wall
x += sep
print(x)
// "1"
a = 1
printnum()
// "bottle of beer. Take one down and pass it around,"
// "no more bottles of beer on the wall."
// Blank line
// "No more bottles of beer on the wall,"
// "no more bottles of beer."
// "Go to the store and buy some more,"
x = bottle
x += ofbeer
x += dotnl
x += takedown
x += l_no
x += more
x += wall
x += dotnl
x += nl
x += u_no
x += more
x += wall
x += sep
x += l_no
x += more
x += dotnl
x += store
print(x)
// "99"
a = 99
printnum()
// "bottles of beer on the wall."
x = bottle
x += plural
x += ofbeer
x += wall
x += dotnl
print(x)
end
end
// vim: set syntax=c ts=4 sw=4 et:
Bc
i = 99;
while ( 1 ) {
print i , " bottles of beer on the wall\n";
print i , " bottles of beer\nTake one down, pass it around\n";
if (i == 2) {
break
}
print --i , " bottles of beer on the wall\n";
}
print --i , " bottle of beer on the wall\n";
print i , " bottle of beer on the wall\n";
print i , " bottle of beer\nTake it down, pass it around\nno more bottles of beer on the wall\n";
quit
BCPL
get "libhdr"
let number(n) be
test n=0
then writes("No more")
else writen(n)
let plural(n) be
test n=1
then writes(" bottle")
else writes(" bottles")
let bottles(n) be
$( number(n)
plural(n)
$)
let verse(n) be
$( bottles(n)
writes(" of beer on the wall,*N")
bottles(n)
writes(" of beer,*NTake ")
test n=1
then writes("it")
else writes("one")
writes(" down and pass it around,*N")
bottles(n-1)
writes(" of beer on the wall!*N*N")
$)
let start() be
for n = 99 to 1 by -1 do verse(n)
beeswax
Straightforward implementation, displaying the full lyrics given on [ http://99-bottles-of-beer.net/ ]
> NN p
> d#_8~2~(P~3~.~1~>{` bottles of beer on the wall, `{` bottles of beer.`q
d`.llaw eht no reeb fo selttob `{pLM` ,dnuora ti ssap dna nwod eno ekaT`N<
q`.llaw eht no reeb fo elttob ` {<
> NN >{` bottle of beer on the wall, `{` bottle of beer.`N q
pN `.llaw eht no reeb fo selttob erom on ,dnuora ti ssap dna nwod eno ekaT`<
>N`No more bottles of beer on the wall, no more bottles of beer.`N q
;`.llaw eht no reeb fo selttob 99 ,erom emos yub dna erots eht ot oG`<
A much more “economic” version that tries to avoid repetition at the price of complicated conditional jumps and self-modifying code that takes up more place than the actual strings themselves. Output is the same as in the straightforward version.
#D@.9~2~@M.7~P9zE `N`p
DMM@.9@.~2~.++~5zE `n`>`o`p
>0f1ff# q `erom `< #h3~1z< #h3~1z< #h3~1z<
d_8~2~(P~3~. ~1~>"b{>X^^^` bottle` ` of beer`@g"pX` on the wall`g"pX `, ` @p #
> d <#XL#^^^^^`s`# # ## # > `.`NN@ X#
b < < <
>~L#^^^^`s`# #h3~1zX #h3~1z<# # # # #
d #h3~1z<# #> `.` g"pXN @"p `Take one down and `p
>^^^^^^^^^; .# b XgNN < bM` ,dnuora ti ssap`<
d^^^^^^^^^^^^^^^^X~3~P(~2~8` ,erom emos yub dna erots eht ot`` oG`<
Befunge
BlitzMax
local bot:int = 99
repeat
print string(bot)+" bottles of beer on the wall,"
print string(bot)+" bottles of beer."
print "Take one down, pass it around,"
bot:-1
print string(bot)+" bottles of beer on the wall."
print
until bot = 1
print "1 bottle of beer on the wall,"
print "1 bottle of beer."
print "Take it down, pass it around,"
print "No more bottles of beer on the wall!"
BlooP
Output is always in caps in the interpreter I use, but I typed the input in correct case to spare those whose interpreter might do lowercase and don't want to have this song shouted at them ;D.
DEFINE PROCEDURE ''MINUS'' [A,B]:
BLOCK 0: BEGIN
IF A < B, THEN:
QUIT BLOCK 0;
LOOP AT MOST A TIMES:
BLOCK 1: BEGIN
IF OUTPUT + B = A, THEN:
QUIT BLOCK 0;
OUTPUT <= OUTPUT + 1;
BLOCK 1: END;
BLOCK 0: END.
DEFINE PROCEDURE ''BOTTLES'' [COUNT]:
BLOCK 0: BEGIN
CELL(0) <= COUNT;
LOOP COUNT + 1 TIMES:
BLOCK 1: BEGIN
IF CELL(0) > 1, THEN:
PRINT[CELL(0), ' bottles of beer on the wall, ', CELL(0), ' bottles of beer. Take one down, pass it around, ', MINUS[CELL(0), 1], ' bottles of beer on the wall.'];
IF CELL(0) = 1, THEN:
PRINT['1 botle of beer on the wall, 1 bottle of beer. Take one down, pass it around, No more bottles of beer on the wall.'];
IF CELL(0) = 0, THEN:
PRINT['No more bottles of beer on the wall, no more bottles of beer. Go to the store, buy 99 more, 99 bottles of beer on the wall!'];
CELL(0) <= MINUS[CELL(0), 1];
BLOCK 1: END;
BLOCK 0: END.
BOTTLES[99];
Bracmat
Copy the code to a file called BottlesOfBeer.bra.
Start Bracmat and after the {?}
prompt write get$"BottlesOfBeer.bra"
<Enter>.
Then, after the next prompt, write
!r
<Enter>.
Notice that the lyrics has two more lines at the end:
No more bottles of beer on the wall, no more bottles of beer. Go to the store and buy some more, 99 bottles of beer on the wall.
Code to save to BottlesOfBeer.bra:
{BottlesOfBeer.bra
See http://99-bottles-of-beer.net/}
X=
new
= n upper nbottles lyrics
. 99:?n
& ( upper
= .@(!arg:%@?a ?z)&str$(upp$!a !z)
)
& ( nbottles
=
. str
$ ( ( !arg:>0
& !arg
" bottle"
(!arg:1&|s)
| "no more bottles"
)
" of beer"
)
)
& ( lyrics
= (upper$(nbottles$!n:?x) " on the wall, " !x ".\n")
( !n+-1:?n:~<0
& "Take one down and pass it around, "
nbottles$!n
" on the wall.
"
!lyrics
| "Go to the store and buy some more, "
nbottles$99
" on the wall.
"
)
)
& put$(str$!lyrics);
r=
get'"BottlesOfBeer.bra"
& rmv$(str$(BottlesOfBeer ".bak"))
& ren$("BottlesOfBeer.bra".str$(BottlesOfBeer ".bak"))
& put
$ ( "{BottlesOfBeer.bra
See http://99-bottles-of-beer.net/}
"
, "BottlesOfBeer.bra"
, NEW
)
& lst'(X,"BottlesOfBeer.bra",APP)
& put'(\n,"BottlesOfBeer.bra",APP)
& lst'(r,"BottlesOfBeer.bra",APP)
& put$(str$("\nnew'" X ";\n"),"BottlesOfBeer.bra",APP);
new'X;
Brainf***
Brat
99.to 2 { n |
p "#{n} bottles of beer on the wall, #{n} bottles of beer!"
p "Take one down, pass it around, #{n - 1} bottle#{true? n > 2 's' ''} of beer on the wall."
}
p "One bottle of beer on the wall, one bottle of beer!"
p "Take one down, pass it around, no more bottles of beer on the wall."
Bruijn
:import std/Combinator .
:import std/Number .
:import std/String .
main [y [[=?0 case-end case-rec]] (+99)]
case-rec n ++ t1 ++ n ++ t2 ++ t3 ++ n ++ t1 ++ "\n" ++ (1 --0)
n number→string 0
t1 " bottles of beer on the wall\n"
t2 " bottles of beer\n"
t3 "Take one down, pass it around\n"
case-end empty
BQN
Pl ← {(𝕩≠1)/"s"}
{𝕨∾(@+10)∾𝕩}´{(•Fmt 𝕨)∾" "∾𝕩}´¨∾{
⟨
⟨𝕩,"bottle"∾(Pl 𝕩)∾" of beer on the wall"⟩
⟨𝕩,"bottle"∾(Pl 𝕩)∾" of beer"⟩
⟨"Take one down, pass it around"⟩
⟨𝕩-1,"bottle"∾(Pl 𝕩-1)∾" of beer on the wall"∾@+10⟩
⟩
}¨⌽1+↕99
•Fmt
is used to convert numbers to strings.
Pl
tells whether the number is singular or plural.
Then, the two folds join all the individual lines together.
C
The simple solution
/*
* 99 Bottles, C, KISS (i.e. keep it simple and straightforward) version
*/
#include <stdio.h>
int main(void)
{
int n;
for( n = 99; n > 2; n-- )
printf(
"%d bottles of beer on the wall, %d bottles of beer.\n"
"Take one down and pass it around, %d bottles of beer on the wall.\n\n",
n, n, n - 1);
printf(
"2 bottles of beer on the wall, 2 bottles of beer.\n"
"Take one down and pass it around, 1 bottle of beer on the wall.\n\n"
"1 bottle of beer on the wall, 1 bottle of beer.\n"
"Take one down and pass it around, no more bottles of beer on the wall.\n\n"
"No more bottles of beer on the wall, no more bottles of beer.\n"
"Go to the store and buy some more, 99 bottles of beer on the wall.\n");
return 0;
}
A recursive solution
#include <stdio.h>
int main(int argc, char *argv[])
{
if(argc == 99)
return 99;
if(argv[0] != NULL){
argv[0] = NULL;
argc = 0;
}
argc = main(argc + 1, argv);
printf("%d bottle%c of beer on the wall\n", argc, argc == 1?'\0': 's');
printf("%d bottle%c of beer\n", argc, argc == 1?'\0': 's');
printf("Take one down, pass it around\n");
printf("%d bottle%c of beer on the wall\n\n", argc - 1, (argc - 1) == 1?'\0': 's');
return argc - 1;
}
Code golf
#include <stdio.h>
main(){_=100;while(--_)printf("%i bottle%s of beer in the wall,\n%i bottle%"
"s of beer.\nTake one down, pass it round,\n%s%s\n\n",_,_-1?"s":"",_,_-1?"s"
:"",_-1?(char[]){(_-1)/10?(_-1)/10+48:(_-1)%10+48,(_-1)/10?(_-1)%10+48:2+30,
(_-1)/10?32:0,0}:"",_-1?"bottles of beer in the wall":"No more beers");}
A preprocessor solution
Of course, with the template metaprogramming solution, the program has still do the conversion of numbers to strings at runtime, and those function calls also cost unnecessary time. Couldn't we just compose the complete text at compile time, and just output it at run time? Well, with the preprocessor, that's indeed possible:
#include <stdlib.h>
#include <stdio.h>
#define BOTTLE(nstr) nstr " bottles of beer"
#define WALL(nstr) BOTTLE(nstr) " on the wall"
#define PART1(nstr) WALL(nstr) "\n" BOTTLE(nstr) \
"\nTake one down, pass it around\n"
#define PART2(nstr) WALL(nstr) "\n\n"
#define MIDDLE(nstr) PART2(nstr) PART1(nstr)
#define SONG PART1("100") CD2 PART2("0")
#define CD2 CD3("9") CD3("8") CD3("7") CD3("6") CD3("5") \
CD3("4") CD3("3") CD3("2") CD3("1") CD4("")
#define CD3(pre) CD4(pre) MIDDLE(pre "0")
#define CD4(pre) MIDDLE(pre "9") MIDDLE(pre "8") MIDDLE(pre "7") \
MIDDLE(pre "6") MIDDLE(pre "5") MIDDLE(pre "4") MIDDLE(pre "3") \
MIDDLE(pre "2") MIDDLE(pre "1")
int main(void)
{
(void) printf(SONG);
return EXIT_SUCCESS;
}
An inspection of the generated executable proves that it indeed contains the complete text of the song in one block.
The bottled version
WYSIWYG (with correct plurals and can buy some more):
int b =99,u =1;
#include<stdio.h>
char *d[16],y[]
= "#:ottle/ of"
":eer_ a_Go<o5"
"st>y\x20some6"
"_Take8;down4p"
"a=1rou7_17 _<"
"h;_ m?_nd_ on"
"_085wal" "l_ "
"b_e _ t_ss it"
"_?4bu_ore_9, "
"\060.""@, 9$";
# define x c ^=
#include <string.h>
#define or(t,z) else\
if(c==t && !(c = 0) &&\
(c =! z)); int p(char *t)
{ char *s = t; int c; for (
d[c = 0] = y; !t && (d[c +1
]= strchr(s = d[c], '_'));*
(d[++c]++) = 0); for(t = s?
s:t;(c= *s++); c && putchar
(c)) { if (!((( x 48)& ~0xf
) && ( x 48)) ) p(d[c]), c=
0 ; or('$', p(b - 99?".\n":
"." ) && p(b - 99? t : ""))
or ('\x40', c && p( d[!!b--
+ 2])) or('/', c && p( b^1?
"s": "")) or ('\043', b++ ?
p("So6" + --b):!printf("%d"
, b ? --b : (b += 99))) or(
'S',!(++u % 3) * 32+ 78) or
('.', puts("."))}return c;}
int main() {return p(0);}
C#
using System;
class Program
{
static void Main(string[] args)
{
for (int i = 99; i > -1; i--)
{
if (i == 0)
{
Console.WriteLine("No more bottles of beer on the wall, no more bottles of beer.");
Console.WriteLine("Go to the store and buy some more, 99 bottles of beer on the wall.");
break;
}
if (i == 1)
{
Console.WriteLine("1 bottle of beer on the wall, 1 bottle of beer.");
Console.WriteLine("Take one down and pass it around, no more bottles of beer on the wall.");
Console.WriteLine();
}
else
{
Console.WriteLine("{0} bottles of beer on the wall, {0} bottles of beer.", i);
Console.WriteLine("Take one down and pass it around, {0} bottles of beer on the wall.", i - 1);
Console.WriteLine();
}
}
}
}
C#6 Implementation
using System;
class Program
{
static void Main()
{
Func<int, bool, string> f = (x, y) =>
$"{(x == 0 ? "No more" : x.ToString())} bottle{(x == 1 ? "" : "s")} of beer{(y ? " on the wall" : "")}\r\n";
for (int i = 99; i > 0; i--)
Console.WriteLine($"{f(i, true)}{f(i, false)}Take one down, pass it around\r\n{f(i - 1, true)}");
}
}
Linq Implementation
using System;
using System.Linq;
class Program
{
static void Main()
{
Enumerable.Range(1, 99).Reverse().Select(x =>
$"{x} bottle{(x == 1 ? "" : "s")} of beer on the wall, {x} bottle{(x == 1 ? "" : "s")} of beer!\n" +
$"Take {(x == 1 ? "it" : "one")} down, pass it around, {(x == 1 ? "no more" : (x - 1).ToString())} bottles of beer on the wall!\n"
).ToList().ForEach(x => Console.WriteLine(x));
}
}
Flexible Version
using System;
using System.Globalization;
class Program
{
const string Vessel = "bottle";
const string Beverage = "beer";
const string Location = "on the wall";
private static string DefaultAction(ref int bottles)
{
bottles--;
return "take one down, pass it around,";
}
private static string FallbackAction(ref int bottles)
{
bottles += 99;
return "go to the store, buy some more,";
}
private static string Act(ref int bottles)
{
return bottles > 0 ? DefaultAction(ref bottles) : FallbackAction(ref bottles);
}
static void Main()
{
Func<int, string> plural = b => b == 1 ? "" : "s";
Func<int, string> describeCount = b => b == 0 ? "no more" : b.ToString();
Func<int, string> describeBottles = b => string.Format("{0} {1}{2} of {3}", describeCount(b), Vessel, plural(b), Beverage);
Action<string> write = s => Console.WriteLine(CultureInfo.CurrentCulture.TextInfo.ToTitleCase(s));
int bottles = 99;
while (true)
{
write(string.Format("{0} {1}, {0},", describeBottles(bottles), Location));
write(Act(ref bottles));
write(string.Format("{0} {1}.", describeBottles(bottles), Location));
write(string.Empty);
}
}
}
Using Formatting
class songs
{
static void Main(string[] args)
{
beer(3);
}
private static void beer(int bottles)
{
for (int i = bottles; i > 0; i--)
{
if (i > 1)
{
Console.Write("{0}\n{1}\n{2}\n{3}\n\n",
i + " bottles of beer on the wall",
i + " bottles of beer",
"Take one down, pass it around",
(i - 1) + " bottles of beer on the wall");
}
else
Console.Write("{0}\n{1}\n{2}\n{3}\n\n",
i + " bottle of beer on the wall",
i + " bottle of beer",
"Take one down, pass it around",
(i - 1) + " bottles of beer on the wall....");
}
}
}
- Output:
3 bottles of beer on the wall 3 bottles of beer Take one down, pass it around 2 bottles of beer on the wall 2 bottles of beer on the wall 2 bottles of beer Take one down, pass it around 1 bottles of beer on the wall 1 bottle of beer on the wall 1 bottle of beer Take one down, pass it around 0 bottles of beer on the wall....
Using iterator blocks
using System;
using System.Linq;
class Program
{
static void Main()
{
BeerBottles().Take(99).ToList().ForEach(Console.WriteLine);
}
static IEnumerable<String> BeerBottles()
{
int i = 100;
String f = "{0}, {1}. Take one down, pass it around, {2}";
Func<int, bool, String> booze = (c , b) =>
String.Format("{0} bottle{1} of beer{2}", c>0 ? c.ToString() : "no more", (c==1 ? "" : "s"), b ? " on the wall" : "");
while (--i >= 1)
yield return String.Format(f, booze(i, true), booze(i, false), booze(i - 1, true));
}
}
A Fun One
string[] bottles = { "80 Shilling",
"Abita Amber",
"Adams Broadside Ale",
"Altenmünster Premium",
"August Schell's SnowStorm",
"Bah Humbug! Christmas Ale",
"Beck's Oktoberfest",
"Belhaven Wee Heavy",
"Bison Chocolate Stout",
"Blue Star Wheat Beer",
"Bridgeport Black Strap Stout",
"Brother Thelonius Belgian-Style Abbey Ale",
"Capital Blonde Doppelbock",
"Carta Blanca",
"Celis Raspberry Wheat",
"Christian Moerlein Select Lager",
"Corona",
"Czechvar",
"Delirium Tremens",
"Diamond Bear Southern Blonde",
"Don De Dieu",
"Eastside Dark",
"Eliot Ness",
"Flying Dog K-9 Cruiser Altitude Ale",
"Fuller's London Porter",
"Gaffel Kölsch",
"Golden Horseshoe",
"Guinness Pub Draught",
"Hacker-Pschorr Weisse",
"Hereford & Hops Black Spring Double Stout",
"Highland Oatmeal Porter",
"Ipswich Ale",
"Iron City",
"Jack Daniel's Amber Lager",
"Jamaica Sunset India Pale Ale",
"Killian's Red",
"König Ludwig Weiss",
"Kronenbourg 1664",
"Lagunitas Hairy Eyball Ale",
"Left Hand Juju Ginger",
"Locktender Lager",
"Magic Hat Blind Faith",
"Missing Elf Double Bock",
"Muskoka Cream Ale ",
"New Glarus Cherry Stout",
"Nostradamus Bruin",
"Old Devil",
"Ommegang Three Philosophers",
"Paulaner Hefe-Weizen Dunkel",
"Perla Chmielowa Pils",
"Pete's Wicked Springfest",
"Point White Biere",
"Prostel Alkoholfrei",
"Quilmes",
"Rahr's Red",
"Rebel Garnet",
"Rickard's Red",
"Rio Grande Elfego Bock",
"Rogue Brutal Bitter",
"Roswell Alien Amber Ale",
"Russian River Pliny The Elder",
"Samuel Adams Blackberry Witbier",
"Samuel Smith's Taddy Porter",
"Schlafly Pilsner",
"Sea Dog Wild Blueberry Wheat Ale",
"Sharp's",
"Shiner 99",
"Sierra Dorada",
"Skullsplitter Orkney Ale",
"Snake Chaser Irish Style Stout",
"St. Arnold Bock",
"St. Peter's Cream Stout",
"Stag",
"Stella Artois",
"Stone Russian Imperial Stout",
"Sweetwater Happy Ending Imperial Stout",
"Taiwan Gold Medal",
"Terrapin Big Hoppy Monster",
"Thomas Hooker American Pale Ale",
"Tie Die Red Ale",
"Toohey's Premium",
"Tsingtao",
"Ugly Pug Black Lager",
"Unibroue Qatre-Centieme",
"Victoria Bitter",
"Voll-Damm Doble Malta",
"Wailing Wench Ale",
"Warsteiner Dunkel",
"Wellhead Crude Oil Stout",
"Weyerbacher Blithering Idiot Barley-Wine Style Ale",
"Wild Boar Amber",
"Würzburger Oktoberfest",
"Xingu Black Beer",
"Yanjing",
"Younger's Tartan Special",
"Yuengling Black & Tan",
"Zagorka Special",
"Zig Zag River Lager",
"Zywiec" };
int bottlesLeft = 99;
const int FIRST_LINE_SINGULAR = 98;
const int FINAL_LINE_SINGULAR = 97;
string firstLine = "";
string finalLine = "";
for (int i = 0; i < 99; i++)
{
firstLine = bottlesLeft.ToString() + " bottle";
if (i != FIRST_LINE_SINGULAR)
firstLine += "s";
firstLine += " of beer on the wall, " + bottlesLeft.ToString() + " bottle";
if (i != FIRST_LINE_SINGULAR)
firstLine += "s";
firstLine += " of beer";
Console.WriteLine(firstLine);
Console.WriteLine("Take the " + bottles[i] + " down, pass it around,");
bottlesLeft--;
finalLine = bottlesLeft.ToString() + " bottle";
if (i != FINAL_LINE_SINGULAR)
finalLine += "s";
finalLine += " of beer on the wall!";
Console.WriteLine(finalLine);
Console.WriteLine();
Console.ReadLine();
}
Using recursion
public static void BottlesSong(int numberOfBottles)
{
if (numberOfBottles > 0)
{
Console.WriteLine("{0} bottles of beer on the wall", numberOfBottles);
Console.WriteLine("{0} bottles of beer ", numberOfBottles);
Console.WriteLine("Take one down, pass it around");
Console.WriteLine("{0} bottles of beer ", numberOfBottles - 1);
Console.WriteLine();
BottlesSong(--numberOfBottles);
}
}
Using a While Loop
static void Main(string[] args)
{
int numBottles = 99;
while (numBottles > 0)
{
if (numBottles > 1)
{
WriteLine("{0} bottles of beer on the wall, {0} bottles of beer.", numBottles);
numBottles -= 1;
WriteLine("Take one down, pass it around, {0} bottles of beer on the wall.\n", numBottles);
}
else
{
WriteLine("{0} bottle of beer on the wall, {0} bottle of beer.", numBottles);
numBottles -= 1;
WriteLine("Take one down, pass it around, no more bottles of beer on the wall.\n");
}
}
WriteLine("No more bottles of beer on the wall, no more bottles of beer.");
WriteLine("Go to the store to buy some more, 99 bottles of beer on the wall...");
}
C/vFP16
#pragma SCH_64_16_IFP
#import <jobsched.c>
__attr(@canschedule)
volatile constricts async UVOID <__INVAR const T>base_000000 __PCON(
impure VFCTX_t^ ct_base,
impure MCHR_t^ sched_arg,
__LVAR <const T>XVF_fntype_t^ f,
<out VF_QSWitch_t>XVF_fn_t^ switchctx
) __ARGFILL {
VF_Xsched_ILock(ct_base, $->sched);
captured __VFObj <>VF_KeDbg^ ki = VF_Xg_KeDbg_Instance();
captured deferred <__VF_T_Auto>__VF_Auto^ vfke = copyof VF_KeDbg_GetRstream<MCHR_t^>(captures ki);
VF_Gsched_SOBFree(sched_arg);
VF_Gsched_Alloc_U16(65535);
VF_Msched_MChr_lim(1496);
VF_Osched_Begin();
VF_Fsched_Add2(%beer_000099);
VF_Xsched_IUnlock(ct_base, $->sched);
$switchctx(IMPURE_CTX, %beer_000099(%vfke));
}
__attr(@eUsesIo)
impure constricts UVOID synchronized beer_000099(
impure __noinline <MCHR_t^>RIGHTSTREAM_t^ outrs
) __NFILL {
pure UVOID^ uvid = __attr(@purify) $UVOID.;
while ( 99 > ((volatile NUM_t)^(NUM_t^)(uvid))++ ) {
VF_STM_Out_NUM((NUM_t^)uvid);
VF_STM_Out_x(__Dynamic C"bottles on the wall.\nPut one down, pass it around\n");
}
return $__;
}
C++
The simple solution
#include <iostream>
using std::cout;
int main()
{
for(int bottles(99); bottles > 0; bottles -= 1){
cout << bottles << " bottles of beer on the wall\n"
<< bottles << " bottles of beer\n"
<< "Take one down, pass it around\n"
<< bottles - 1 << " bottles of beer on the wall\n\n";
}
}
An object-oriented solution
See: 99 Bottles of Beer/C++/Object Oriented
A template metaprogramming solution
Of course, the output of the program always looks the same. One may therefore question why the program has to do all that tedious subtracting during runtime. Couldn't the compiler just generate the code to output the text, with ready-calculated constants? Indeed, it can, and the technique is called template metaprogramming. The following short code gives the text without containing a single variable, let alone a loop:
#include <iostream>
template<int max, int min> struct bottle_countdown
{
static const int middle = (min + max)/2;
static void print()
{
bottle_countdown<max, middle+1>::print();
bottle_countdown<middle, min>::print();
}
};
template<int value> struct bottle_countdown<value, value>
{
static void print()
{
std::cout << value << " bottles of beer on the wall\n"
<< value << " bottles of beer\n"
<< "Take one down, pass it around\n"
<< value-1 << " bottles of beer\n\n";
}
};
int main()
{
bottle_countdown<100, 1>::print();
return 0;
}
A function template solution
Function templates are a different approach to template metaprogramming:
#include <iostream>
template<unsigned int N> void bottles(){
std::cout << N << " bottles of beer on the wall\n"
<< N << " bottles of beer\n"
<< "Take one down, pass it around\n"
<< N - 1 << " bottles of beer on the wall\n\n";
bottles<N-1>();
}
template<> void bottles<0>(){
std::cout<<"No more bottles of beer on the wall\n"
"No more bottles of beer\n"
"Go to the store and buy some more\n"
"99 bottles of beer on the wall...\n\n";
}
int main(){
bottles<99>();
}
A Recursive solution
#include <iostream>
using namespace std;
void rec(int bottles)
{
if ( bottles!=0)
{
cout << bottles << " bottles of beer on the wall" << endl;
cout << bottles << " bottles of beer" << endl;
cout << "Take one down, pass it around" << endl;
cout << --bottles << " bottles of beer on the wall\n" << endl;
rec(bottles);
}
}
int main()
{
rec(99);
system("pause");
return 0;
}
A preprocessor solution
Of course, with the template metaprogramming solution, the program has still do the conversion of numbers to strings at runtime, and those function calls also cost unnecessary time. Couldn't we just compose the complete text at compile time, and just output it at run time? Well, with the preprocessor, that's indeed possible:
#include <iostream>
#include <ostream>
#define BOTTLE(nstr) nstr " bottles of beer"
#define WALL(nstr) BOTTLE(nstr) " on the wall"
#define PART1(nstr) WALL(nstr) "\n" BOTTLE(nstr) \
"\nTake one down, pass it around\n"
#define PART2(nstr) WALL(nstr) "\n\n"
#define MIDDLE(nstr) PART2(nstr) PART1(nstr)
#define SONG PART1("100") CD2 PART2("0")
#define CD2 CD3("9") CD3("8") CD3("7") CD3("6") CD3("5") \
CD3("4") CD3("3") CD3("2") CD3("1") CD4("")
#define CD3(pre) CD4(pre) MIDDLE(pre "0")
#define CD4(pre) MIDDLE(pre "9") MIDDLE(pre "8") MIDDLE(pre "7") \
MIDDLE(pre "6") MIDDLE(pre "5") MIDDLE(pre "4") MIDDLE(pre "3") \
MIDDLE(pre "2") MIDDLE(pre "1")
int main()
{
std::cout << SONG;
return 0;
}
Bottled Version
//>,_
//Beer Song>,_
#include <iostream>
using namespace std;
int main(){ for( int
b=-1; b<99; cout <<
'\n') for ( int w=0;
w<3; cout << ".\n"){
if (w==2) cout << ((
b--) ?"Take one dow"
"n and pass it arou"
"nd":"Go to the sto"
"re and buy some mo"
"re"); if (b<0) b=99
; do{ if (w) cout <<
", "; if (b) cout <<
b; else cout << (
(w) ? 'n' : 'N') <<
"o more"; cout <<
" bottle" ; if
(b!=1) cout <<
's' ; cout <<
" of beer";
if (w!=1)
cout <<
" on th"
"e wall"
;} while
(!w++);}
return
0
;
}
//
// by barrym 2011-05-01
// no bottles were harmed in the
// making of this program!!!
Ceylon
shared void ninetyNineBottles() {
String bottles(Integer count) =>
"``count == 0 then "No" else count``
bottle``count == 1 then "" else "s"``".normalized;
for(i in 99..1) {
print("``bottles(i)`` of beer on the wall
``bottles(i)`` of beer!
Take one down, pass it around
``bottles(i - 1)`` of beer on the wall!\n");
}
}
Chapel
copied from http://99-bottles-of-beer.net/language-chapel-1215.html, with minor modifications for chapel 1.7
/***********************************************************************
* Chapel implementation of "99 bottles of beer"
*
* by Brad Chamberlain and Steve Deitz
* 07/13/2006 in Knoxville airport while waiting for flight home from
* HPLS workshop
* compiles and runs with chpl compiler version 1.7.0
* for more information, contact: chapel_info@cray.com
*
*
* Notes:
* o as in all good parallel computations, boundary conditions
* constitute the vast bulk of complexity in this code (invite Brad to
* tell you about his zany boundary condition simplification scheme)
* o uses type inference for variables, arguments
* o relies on integer->string coercions
* o uses named argument passing (for documentation purposes only)
***********************************************************************/
// allow executable command-line specification of number of bottles
// (e.g., ./a.out -snumBottles=999999)
config const numBottles = 99;
const numVerses = numBottles+1;
// a domain to describe the space of lyrics
var LyricsSpace: domain(1) = {1..numVerses};
// array of lyrics
var Lyrics: [LyricsSpace] string;
// parallel computation of lyrics array
[verse in LyricsSpace] Lyrics(verse) = computeLyric(verse);
// as in any good parallel language, I/O to stdout is serialized.
// (Note that I/O to a file could be parallelized using a parallel
// prefix computation on the verse strings' lengths with file seeking)
writeln(Lyrics);
// HELPER FUNCTIONS:
proc computeLyric(verseNum) {
var bottleNum = numBottles - (verseNum - 1);
var nextBottle = (bottleNum + numVerses - 1)%numVerses;
return "\n" // disguise space used to separate elements in array I/O
+ describeBottles(bottleNum, startOfVerse=true) + " on the wall, "
+ describeBottles(bottleNum) + ".\n"
+ computeAction(bottleNum)
+ describeBottles(nextBottle) + " on the wall.\n";
}
proc describeBottles(bottleNum, startOfVerse:bool = false) {
// NOTE: bool should not be necessary here (^^^^); working around bug
var bottleDescription = if (bottleNum) then bottleNum:string
else (if startOfVerse then "N"
else "n")
+ "o more";
return bottleDescription
+ " bottle" + (if (bottleNum == 1) then "" else "s")
+ " of beer";
}
proc computeAction(bottleNum) {
return if (bottleNum == 0) then "Go to the store and buy some more, "
else "Take one down and pass it around, ";
}
Chef
Cind
execute() {
// this class provides synchronization
// to get unique number of the bottle
class monitor giver {
int number = 100;
.get() { return --number; }
}
var g = new giver();
// start 99 concurrently worked threads
// each thread gets own number of the bottle and prints out his own verse
// (notice that the output lines from the threads will be mixed together)
{#[99]
int nr = g.get(); // get own number
host.println(nr," bottles of beer on the wall, "+nr+" bottles of beer");
host.print("Take one down, pass it around,");
if (nr > 1) {
host.println((nr-1)," bottles of beer on the wall.");
}
else {
host.println("no more bottles of beer on the wall.");
}
}
host.println("No more bottles of beer on the wall, no more bottles of beer.");
host.println("Go to the store and buy some more, 99 bottles of beer on the wall.");
return 0;
}
Clay
/* A few options here: I could give n type Int; or specify that n is of any
numeric type; but here I just let it go -- that way it'll work with anything
that compares with 1 and that printTo knows how to convert to a string. And
all checked at compile time, remember. */
getRound(n) {
var s = String();
var bottle = if (n == 1) " bottle " else " bottles ";
printTo(s,
n, bottle, "of beer on the wall\n",
n, bottle, "of beer\n",
"take one down, pass it around\n",
n, bottle, "of beer on the wall!\n");
return s;
}
main() {
println(join("\n", mapped(getRound, reversed(range(100)))));
}
Clio
fn bottle n:
n -> if = 0: 'no more bottles'
elif = 1: n + ' bottle'
else: n + ' bottles'
[99:0] -> * (@eager) fn i:
i -> bottle -> print (transform i: sentence-case) 'of beer on the wall,' @ 'of beer.'
if i = 0:
'Go to the store, buy some more, 99 bottles of beer on the wall.' -> print
else:
i - 1 -> bottle -> print 'Take one down and pass it around,' @ 'of beer on the wall.\n'
CLIPS
(deffacts beer-bottles
(bottles 99))
(deffunction bottle-count
(?count)
(switch ?count
(case 0 then "No more bottles of beer")
(case 1 then "1 more bottle of beer")
(default (str-cat ?count " bottles of beer"))))
(defrule stanza
?bottles <- (bottles ?count)
=>
(retract ?bottles)
(printout t (bottle-count ?count) " on the wall," crlf)
(printout t (bottle-count ?count) "." crlf)
(printout t "Take one down, pass it around," crlf)
(printout t (bottle-count (- ?count 1)) " on the wall." crlf crlf)
(if (> ?count 1) then (assert (bottles (- ?count 1)))))
Clojure
(defn paragraph [num]
(str num " bottles of beer on the wall\n"
num " bottles of beer\n"
"Take one down, pass it around\n"
(dec num) " bottles of beer on the wall.\n"))
(defn lyrics []
(let [numbers (range 99 0 -1)
paragraphs (map paragraph numbers)]
(clojure.string/join "\n" paragraphs)))
(print (lyrics))
Or, using cl-format:
(clojure.pprint/cl-format
true
"~{~[~^~]~:*~D bottle~:P of beer on the wall~%~:*~D bottle~:P of beer
Take one down, pass it around,~%~D bottle~:P~:* of beer on the wall.~2%~}"
(range 99 0 -1))
CLU
bottles = proc (n: int) returns (string)
if n<0 then return("99 bottles")
elseif n=0 then return("No more bottles")
elseif n=1 then return("1 bottle")
else return(int$unparse(n) || " bottles")
end
end bottles
thirdline = proc (n: int) returns (string)
if n=0 then
return("Go to the store and buy some more,\n")
else
s: string
if n=1 then s := "it"
else s := "one"
end
return("Take " || s || " down and pass it around,\n");
end
end thirdline
verse = proc (n: int) returns (string)
v: string := bottles(n) || " bottles of beer on the wall,\n"
v := v || bottles(n) || " bottles of beer,\n"
v := v || thirdline(n)
v := v || bottles(n-1) || " bottles of beer on the wall.\n\n"
return(v)
end verse
start_up = proc ()
po: stream := stream$primary_output()
for n: int in int$from_to_by(99, 0, -1) do
stream$puts(po, verse(n))
end
end start_up
COBOL
Free form version.
identification division.
program-id. ninety-nine.
environment division.
data division.
working-storage section.
01 counter pic 99.
88 no-bottles-left value 0.
88 one-bottle-left value 1.
01 parts-of-counter redefines counter.
05 tens pic 9.
05 digits pic 9.
01 after-ten-words.
05 filler pic x(7) value spaces.
05 filler pic x(7) value "Twenty".
05 filler pic x(7) value "Thirty".
05 filler pic x(7) value "Forty".
05 filler pic x(7) value "Fifty".
05 filler pic x(7) value "Sixty".
05 filler pic x(7) value "Seventy".
05 filler pic x(7) value "Eighty".
05 filler pic x(7) value "Ninety".
05 filler pic x(7) value spaces.
01 after-ten-array redefines after-ten-words.
05 atens occurs 10 times pic x(7).
01 digit-words.
05 filler pic x(9) value "One".
05 filler pic x(9) value "Two".
05 filler pic x(9) value "Three".
05 filler pic x(9) value "Four".
05 filler pic x(9) value "Five".
05 filler pic x(9) value "Six".
05 filler pic x(9) value "Seven".
05 filler pic x(9) value "Eight".
05 filler pic x(9) value "Nine".
05 filler pic x(9) value "Ten".
05 filler pic x(9) value "Eleven".
05 filler pic x(9) value "Twelve".
05 filler pic x(9) value "Thirteen".
05 filler pic x(9) value "Fourteen".
05 filler pic x(9) value "Fifteen".
05 filler pic x(9) value "Sixteen".
05 filler pic x(9) value "Seventeen".
05 filler pic x(9) value "Eighteen".
05 filler pic x(9) value "Nineteen".
05 filler pic x(9) value spaces.
01 digit-array redefines digit-words.
05 adigits occurs 20 times pic x(9).
01 number-name pic x(15).
procedure division.
100-main section.
100-setup.
perform varying counter from 99 by -1 until no-bottles-left
perform 100-show-number
display " of beer on the wall"
perform 100-show-number
display " of beer"
display "Take " with no advancing
if one-bottle-left
display "it " with no advancing
else
display "one " with no advancing
end-if
display "down and pass it round"
subtract 1 from counter giving counter
perform 100-show-number
display " of beer on the wall"
add 1 to counter giving counter
display space
end-perform.
display "No more bottles of beer on the wall"
display "No more bottles of beer"
display "Go to the store and buy some more"
display "Ninety Nine bottles of beer on the wall"
stop run.
100-show-number.
if no-bottles-left
display "No more" with no advancing
else
if counter < 20
display function trim( adigits( counter ) ) with no advancing
else
if counter < 100
move spaces to number-name
string atens( tens ) delimited by space, space delimited by size, adigits( digits ) delimited by space into number-name
display function trim( number-name) with no advancing
end-if
end-if
end-if.
if one-bottle-left
display " bottle" with no advancing
else
display " bottles" with no advancing
end-if.
100-end.
end-program.
Another free-form version, without using DISPLAY NO ADVANCING
.
identification division.
program-id. ninety-nine.
environment division.
data division.
working-storage section.
01 counter pic 99.
88 no-bottles-left value 0.
88 one-bottle-left value 1.
01 parts-of-counter redefines counter.
05 tens pic 9.
05 digits pic 9.
01 after-ten-words.
05 filler pic x(7) value spaces.
05 filler pic x(7) value "Twenty".
05 filler pic x(7) value "Thirty".
05 filler pic x(7) value "Forty".
05 filler pic x(7) value "Fifty".
05 filler pic x(7) value "Sixty".
05 filler pic x(7) value "Seventy".
05 filler pic x(7) value "Eighty".
05 filler pic x(7) value "Ninety".
05 filler pic x(7) value spaces.
01 after-ten-array redefines after-ten-words.
05 atens occurs 10 times pic x(7).
01 digit-words.
05 filler pic x(9) value "One".
05 filler pic x(9) value "Two".
05 filler pic x(9) value "Three".
05 filler pic x(9) value "Four".
05 filler pic x(9) value "Five".
05 filler pic x(9) value "Six".
05 filler pic x(9) value "Seven".
05 filler pic x(9) value "Eight".
05 filler pic x(9) value "Nine".
05 filler pic x(9) value "Ten".
05 filler pic x(9) value "Eleven".
05 filler pic x(9) value "Twelve".
05 filler pic x(9) value "Thirteen".
05 filler pic x(9) value "Fourteen".
05 filler pic x(9) value "Fifteen".
05 filler pic x(9) value "Sixteen".
05 filler pic x(9) value "Seventeen".
05 filler pic x(9) value "Eighteen".
05 filler pic x(9) value "Nineteen".
05 filler pic x(9) value spaces.
01 digit-array redefines digit-words.
05 adigits occurs 20 times pic x(9).
01 number-name pic x(15).
01 stringified pic x(30).
01 outline pic x(50).
01 other-numbers.
03 n pic 999.
03 r pic 999.
procedure division.
100-main section.
100-setup.
perform varying counter from 99 by -1 until no-bottles-left
move spaces to outline
perform 100-show-number
string stringified delimited by "|", space, "of beer on the wall" into outline end-string
display outline end-display
move spaces to outline
string stringified delimited by "|", space, "of beer" into outline end-string
display outline end-display
move spaces to outline
move "Take" to outline
if one-bottle-left
string outline delimited by space, space, "it" delimited by size, space, "|" into outline end-string
else
string outline delimited by space, space, "one" delimited by size, space, "|" into outline end-string
end-if
string outline delimited by "|", "down and pass it round" delimited by size into outline end-string
display outline end-display
move spaces to outline
subtract 1 from counter giving counter end-subtract
perform 100-show-number
string stringified delimited by "|", space, "of beer on the wall" into outline end-string
display outline end-display
add 1 to counter giving counter end-add
display space end-display
end-perform.
display "No more bottles of beer on the wall"
display "No more bottles of beer"
display "Go to the store and buy some more"
display "Ninety-Nine bottles of beer on the wall"
stop run.
100-show-number.
if no-bottles-left
move "No more|" to stringified
else
if counter < 20
string function trim( adigits( counter ) ), "|" into stringified
else
if counter < 100
move spaces to number-name
string atens( tens ) delimited by space, space delimited by size, adigits( digits ) delimited by space into number-name end-string
move function trim( number-name) to stringified
divide counter by 10 giving n remainder r end-divide
if r not = zero
inspect stringified replacing first space by "-"
end-if
inspect stringified replacing first space by "|"
end-if
end-if
end-if.
if one-bottle-left
string stringified delimited by "|", space, "bottle|" delimited by size into stringified end-string
else
string stringified delimited by "|", space, "bottles|" delimited by size into stringified end-string
end-if.
100-end.
end-program.
A more concise version that adheres to the minimum guidelines. Leading zeros are not suppressed. (OpenCOBOL - 1.1.0)
program-id. ninety-nine.
data division.
working-storage section.
01 cnt pic 99.
procedure division.
perform varying cnt from 99 by -1 until cnt < 1
display cnt " bottles of beer on the wall"
display cnt " bottles of beer"
display "Take one down, pass it around"
subtract 1 from cnt
display cnt " bottles of beer on the wall"
add 1 to cnt
display space
end-perform.
CoffeeScript
bottlesOfBeer = (n) ->
"#{n} bottle#{if n is 1 then '' else 's'} of beer"
console.log """
#{bottlesOfBeer n} on the wall
#{bottlesOfBeer n}
Take one down, pass it around
#{bottlesOfBeer n - 1} on the wall
\n""" for n in [99..1]
With completely different approach...
for j in [99..1]
x=''
x += [j,j-1,'\nTake one down, pass it around\n'," bottles of beer",' on the wall\n'][i] for i in [0,3,4,0,3,2,1,3,4]
console.log x.replace /(1.+)s/g, '$1'
or as a one liner...
console.log( if (j+2)%4 then (x=Math.round j/4)+" bottle#{if x-1 then 's' else ''} of beer#{if (j+1)%4 then ' on the wall' else ''}" else "Take one down, pass it around" ) for j in [396..1]
or another completely different one liner
((console.log if i is 2 then "Take one down, pass it around" else "#{b-!(i-1%4)} bottle#{if 4*b+i<10 and b-i then '' else 's'} of beer#{if i%3 then ' on the wall' else ''}") for i in [4..1]) for b in [99..1]
ColdFusion
Classic tag based CFML
<cfoutput>
<cfloop index="x" from="99" to="0" step="-1">
<cfset plur = iif(x is 1,"",DE("s"))>
#x# bottle#plur# of beer on the wall<br>
#x# bottle#plur# of beer<br>
Take one down, pass it around<br>
#iif(x is 1,DE("No more"),"x-1")# bottle#iif(x is 2,"",DE("s"))# of beer on the wall<br><br>
</cfloop>
</cfoutput>
or if you prefer: (identical output, grammatically correct to the last stanza)
CFScript
<cfscript>
for (x=99; x gte 1; x--) {
plur = iif(x==1,'',DE('s'));
WriteOutput("#x# bottle#plur# of beer on the wall<br>#x# bottle#plur# of beer<br>Take one down, pass it around<br>#iif(x is 1,DE('No more'),'x-1')# bottle#iif(x is 2,'',DE('s'))# of beer on the wall<br><br>");
}
</cfscript>
Comal
0010 DIM itone$(0:1)
0020 itone$(0):="one";itone$(1):="it"
0030 FOR b#:=99 TO 1 STEP -1 DO
0040 bottles(b#)
0050 PRINT "of beer on the wall,"
0060 bottles(b#)
0070 PRINT "of beer,"
0080 PRINT "Take ",itone$(b#=1)," down and pass it around,"
0090 bottles(b#-1)
0100 PRINT "of beer on the wall!"
0110 PRINT
0120 ENDFOR b#
0130 PROC bottles(b#) CLOSED
0140 CASE b# OF
0150 WHEN 0
0160 PRINT "No more bottles ",
0170 WHEN 1
0180 PRINT "1 bottle ",
0190 OTHERWISE
0200 PRINT b#," bottles ",
0210 ENDCASE
0220 ENDPROC bottles
0230 END
Comefrom0x10
bottles = ' bottles '
remaining = 99
one_less_bottle = remaining
depluralize
comefrom drinking if one_less_bottle is 1
bottles = ' bottle '
drinking
comefrom if remaining is one_less_bottle
remaining bottles 'of beer on the wall'
remaining bottles 'of beer'
'Take one down, pass it around'
one_less_bottle = remaining - 1
one_less_bottle bottles 'of beer on the wall`n'
remaining = remaining - 1
comefrom if one_less_bottle is 0
'No more bottles of beer on the wall'
- Output:
2 bottles of beer on the wall 2 bottles of beer Take one down, pass it around 1 bottle of beer on the wall 1 bottle of beer on the wall 1 bottle of beer Take one down, pass it around No more bottles of beer on the wall
Common Lisp
Component Pascal
Cowgol
include "cowgol.coh";
sub Bottles(n: uint8) is
if n == 0 then
print("No more");
else
print_i8(n);
end if;
print(" bottle");
if n != 1 then
print("s");
end if;
end sub;
sub Verse(n: uint8) is
Bottles(n);
print(" of beer on the wall,\n");
Bottles(n);
print(" of beer,\n");
print("Take ");
if n == 1 then
print("it");
else
print("one");
end if;
print(" down and pass it around,\n");
Bottles(n-1);
print(" of beer on the wall.\n\n");
end sub;
var verse: uint8 := 99;
while verse > 0 loop
Verse(verse);
verse := verse - 1;
end loop;
- Output:
99 bottles of beer on the wall, 99 bottles of beer, Take one down and pass it around, 98 bottles of beer on the wall. 98 bottles of beer on the wall, 98 bottles of beer, Take one down and pass it around, 97 bottles of beer on the wall. 97 bottles of beer on the wall, 97 bottles of beer, Take one down and pass it around, 96 bottles of beer on the wall. 96 bottles of beer on the wall, 96 bottles of beer, Take one down and pass it around, 95 bottles of beer on the wall. 95 bottles of beer on the wall, 95 bottles of beer, Take one down and pass it around, 94 bottles of beer on the wall. 94 bottles of beer on the wall, 94 bottles of beer, Take one down and pass it around, 93 bottles of beer on the wall. 93 bottles of beer on the wall, 93 bottles of beer, Take one down and pass it around, 92 bottles of beer on the wall. 92 bottles of beer on the wall, 92 bottles of beer, Take one down and pass it around, 91 bottles of beer on the wall. 91 bottles of beer on the wall, 91 bottles of beer, Take one down and pass it around, 90 bottles of beer on the wall. 90 bottles of beer on the wall, 90 bottles of beer, Take one down and pass it around, 89 bottles of beer on the wall. 89 bottles of beer on the wall, 89 bottles of beer, Take one down and pass it around, 88 bottles of beer on the wall. 88 bottles of beer on the wall, 88 bottles of beer, Take one down and pass it around, 87 bottles of beer on the wall. 87 bottles of beer on the wall, 87 bottles of beer, Take one down and pass it around, 86 bottles of beer on the wall. 86 bottles of beer on the wall, 86 bottles of beer, Take one down and pass it around, 85 bottles of beer on the wall. 85 bottles of beer on the wall, 85 bottles of beer, Take one down and pass it around, 84 bottles of beer on the wall. 84 bottles of beer on the wall, 84 bottles of beer, Take one down and pass it around, 83 bottles of beer on the wall. 83 bottles of beer on the wall, 83 bottles of beer, Take one down and pass it around, 82 bottles of beer on the wall. 82 bottles of beer on the wall, 82 bottles of beer, Take one down and pass it around, 81 bottles of beer on the wall. 81 bottles of beer on the wall, 81 bottles of beer, Take one down and pass it around, 80 bottles of beer on the wall. 80 bottles of beer on the wall, 80 bottles of beer, Take one down and pass it around, 79 bottles of beer on the wall. 79 bottles of beer on the wall, 79 bottles of beer, Take one down and pass it around, 78 bottles of beer on the wall. 78 bottles of beer on the wall, 78 bottles of beer, Take one down and pass it around, 77 bottles of beer on the wall. 77 bottles of beer on the wall, 77 bottles of beer, Take one down and pass it around, 76 bottles of beer on the wall. 76 bottles of beer on the wall, 76 bottles of beer, Take one down and pass it around, 75 bottles of beer on the wall. 75 bottles of beer on the wall, 75 bottles of beer, Take one down and pass it around, 74 bottles of beer on the wall. 74 bottles of beer on the wall, 74 bottles of beer, Take one down and pass it around, 73 bottles of beer on the wall. 73 bottles of beer on the wall, 73 bottles of beer, Take one down and pass it around, 72 bottles of beer on the wall. 72 bottles of beer on the wall, 72 bottles of beer, Take one down and pass it around, 71 bottles of beer on the wall. 71 bottles of beer on the wall, 71 bottles of beer, Take one down and pass it around, 70 bottles of beer on the wall. 70 bottles of beer on the wall, 70 bottles of beer, Take one down and pass it around, 69 bottles of beer on the wall. 69 bottles of beer on the wall, 69 bottles of beer, Take one down and pass it around, 68 bottles of beer on the wall. 68 bottles of beer on the wall, 68 bottles of beer, Take one down and pass it around, 67 bottles of beer on the wall. 67 bottles of beer on the wall, 67 bottles of beer, Take one down and pass it around, 66 bottles of beer on the wall. 66 bottles of beer on the wall, 66 bottles of beer, Take one down and pass it around, 65 bottles of beer on the wall. 65 bottles of beer on the wall, 65 bottles of beer, Take one down and pass it around, 64 bottles of beer on the wall. 64 bottles of beer on the wall, 64 bottles of beer, Take one down and pass it around, 63 bottles of beer on the wall. 63 bottles of beer on the wall, 63 bottles of beer, Take one down and pass it around, 62 bottles of beer on the wall. 62 bottles of beer on the wall, 62 bottles of beer, Take one down and pass it around, 61 bottles of beer on the wall. 61 bottles of beer on the wall, 61 bottles of beer, Take one down and pass it around, 60 bottles of beer on the wall. 60 bottles of beer on the wall, 60 bottles of beer, Take one down and pass it around, 59 bottles of beer on the wall. 59 bottles of beer on the wall, 59 bottles of beer, Take one down and pass it around, 58 bottles of beer on the wall. 58 bottles of beer on the wall, 58 bottles of beer, Take one down and pass it around, 57 bottles of beer on the wall. 57 bottles of beer on the wall, 57 bottles of beer, Take one down and pass it around, 56 bottles of beer on the wall. 56 bottles of beer on the wall, 56 bottles of beer, Take one down and pass it around, 55 bottles of beer on the wall. 55 bottles of beer on the wall, 55 bottles of beer, Take one down and pass it around, 54 bottles of beer on the wall. 54 bottles of beer on the wall, 54 bottles of beer, Take one down and pass it around, 53 bottles of beer on the wall. 53 bottles of beer on the wall, 53 bottles of beer, Take one down and pass it around, 52 bottles of beer on the wall. 52 bottles of beer on the wall, 52 bottles of beer, Take one down and pass it around, 51 bottles of beer on the wall. 51 bottles of beer on the wall, 51 bottles of beer, Take one down and pass it around, 50 bottles of beer on the wall. 50 bottles of beer on the wall, 50 bottles of beer, Take one down and pass it around, 49 bottles of beer on the wall. 49 bottles of beer on the wall, 49 bottles of beer, Take one down and pass it around, 48 bottles of beer on the wall. 48 bottles of beer on the wall, 48 bottles of beer, Take one down and pass it around, 47 bottles of beer on the wall. 47 bottles of beer on the wall, 47 bottles of beer, Take one down and pass it around, 46 bottles of beer on the wall. 46 bottles of beer on the wall, 46 bottles of beer, Take one down and pass it around, 45 bottles of beer on the wall. 45 bottles of beer on the wall, 45 bottles of beer, Take one down and pass it around, 44 bottles of beer on the wall. 44 bottles of beer on the wall, 44 bottles of beer, Take one down and pass it around, 43 bottles of beer on the wall. 43 bottles of beer on the wall, 43 bottles of beer, Take one down and pass it around, 42 bottles of beer on the wall. 42 bottles of beer on the wall, 42 bottles of beer, Take one down and pass it around, 41 bottles of beer on the wall. 41 bottles of beer on the wall, 41 bottles of beer, Take one down and pass it around, 40 bottles of beer on the wall. 40 bottles of beer on the wall, 40 bottles of beer, Take one down and pass it around, 39 bottles of beer on the wall. 39 bottles of beer on the wall, 39 bottles of beer, Take one down and pass it around, 38 bottles of beer on the wall. 38 bottles of beer on the wall, 38 bottles of beer, Take one down and pass it around, 37 bottles of beer on the wall. 37 bottles of beer on the wall, 37 bottles of beer, Take one down and pass it around, 36 bottles of beer on the wall. 36 bottles of beer on the wall, 36 bottles of beer, Take one down and pass it around, 35 bottles of beer on the wall. 35 bottles of beer on the wall, 35 bottles of beer, Take one down and pass it around, 34 bottles of beer on the wall. 34 bottles of beer on the wall, 34 bottles of beer, Take one down and pass it around, 33 bottles of beer on the wall. 33 bottles of beer on the wall, 33 bottles of beer, Take one down and pass it around, 32 bottles of beer on the wall. 32 bottles of beer on the wall, 32 bottles of beer, Take one down and pass it around, 31 bottles of beer on the wall. 31 bottles of beer on the wall, 31 bottles of beer, Take one down and pass it around, 30 bottles of beer on the wall. 30 bottles of beer on the wall, 30 bottles of beer, Take one down and pass it around, 29 bottles of beer on the wall. 29 bottles of beer on the wall, 29 bottles of beer, Take one down and pass it around, 28 bottles of beer on the wall. 28 bottles of beer on the wall, 28 bottles of beer, Take one down and pass it around, 27 bottles of beer on the wall. 27 bottles of beer on the wall, 27 bottles of beer, Take one down and pass it around, 26 bottles of beer on the wall. 26 bottles of beer on the wall, 26 bottles of beer, Take one down and pass it around, 25 bottles of beer on the wall. 25 bottles of beer on the wall, 25 bottles of beer, Take one down and pass it around, 24 bottles of beer on the wall. 24 bottles of beer on the wall, 24 bottles of beer, Take one down and pass it around, 23 bottles of beer on the wall. 23 bottles of beer on the wall, 23 bottles of beer, Take one down and pass it around, 22 bottles of beer on the wall. 22 bottles of beer on the wall, 22 bottles of beer, Take one down and pass it around, 21 bottles of beer on the wall. 21 bottles of beer on the wall, 21 bottles of beer, Take one down and pass it around, 20 bottles of beer on the wall. 20 bottles of beer on the wall, 20 bottles of beer, Take one down and pass it around, 19 bottles of beer on the wall. 19 bottles of beer on the wall, 19 bottles of beer, Take one down and pass it around, 18 bottles of beer on the wall. 18 bottles of beer on the wall, 18 bottles of beer, Take one down and pass it around, 17 bottles of beer on the wall. 17 bottles of beer on the wall, 17 bottles of beer, Take one down and pass it around, 16 bottles of beer on the wall. 16 bottles of beer on the wall, 16 bottles of beer, Take one down and pass it around, 15 bottles of beer on the wall. 15 bottles of beer on the wall, 15 bottles of beer, Take one down and pass it around, 14 bottles of beer on the wall. 14 bottles of beer on the wall, 14 bottles of beer, Take one down and pass it around, 13 bottles of beer on the wall. 13 bottles of beer on the wall, 13 bottles of beer, Take one down and pass it around, 12 bottles of beer on the wall. 12 bottles of beer on the wall, 12 bottles of beer, Take one down and pass it around, 11 bottles of beer on the wall. 11 bottles of beer on the wall, 11 bottles of beer, Take one down and pass it around, 10 bottles of beer on the wall. 10 bottles of beer on the wall, 10 bottles of beer, Take one down and pass it around, 9 bottles of beer on the wall. 9 bottles of beer on the wall, 9 bottles of beer, Take one down and pass it around, 8 bottles of beer on the wall. 8 bottles of beer on the wall, 8 bottles of beer, Take one down and pass it around, 7 bottles of beer on the wall. 7 bottles of beer on the wall, 7 bottles of beer, Take one down and pass it around, 6 bottles of beer on the wall. 6 bottles of beer on the wall, 6 bottles of beer, Take one down and pass it around, 5 bottles of beer on the wall. 5 bottles of beer on the wall, 5 bottles of beer, Take one down and pass it around, 4 bottles of beer on the wall. 4 bottles of beer on the wall, 4 bottles of beer, Take one down and pass it around, 3 bottles of beer on the wall. 3 bottles of beer on the wall, 3 bottles of beer, Take one down and pass it around, 2 bottles of beer on the wall. 2 bottles of beer on the wall, 2 bottles of beer, Take one down and pass it around, 1 bottle of beer on the wall. 1 bottle of beer on the wall, 1 bottle of beer, Take it down and pass it around, No more bottles of beer on the wall.
Crystal
99.downto(1) do |n|
puts "#{n} bottle#{n > 1 ? "s" : ""} of beer on the wall"
puts "#{n} bottle#{n > 1 ? "s" : ""} of beer"
puts "Take one down, pass it around"
puts "#{n-1} bottle#{n > 2 ? "s" : ""} of beer on the wall\n\n" if n > 1
end
puts "No more bottles of beer on the wall"
D
Simple Solution
Based on Steward Gordon's code at: 99-bottles-of-beer.net.
import std.stdio;
void main() {
int bottles = 99;
while (bottles > 1) {
writeln(bottles, " bottles of beer on the wall,");
writeln(bottles, " bottles of beer.");
writeln("Take one down, pass it around,");
if (--bottles > 1) {
writeln(bottles, " bottles of beer on the wall.\n");
}
}
writeln("1 bottle of beer on the wall.\n");
writeln("No more bottles of beer on the wall,");
writeln("no more bottles of beer.");
writeln("Go to the store and buy some more,");
writeln("99 bottles of beer on the wall.");
}
CTFE Solution
CTFE (Compile-Time Function Execution) is a feature of D that allows for pure functions of arbitrary complexity to be completely evaluated at compile time when every parameter is known. Note that this is distinct from the template meta-programming tricks used by some other languages, and this bottles() function could just as easily be executed during run-time. The compiled result of this program simply prints the pre-generated lyrics to the song, using a standard compiler pragma directive.
import std.stdio, std.conv;
string bottles(in size_t num) pure {
static string bottlesRecurse(in size_t num) pure {
return num.text ~ " bottles of beer on the wall,\n"
~ num.text ~ " bottles of beer!\n"
~ "Take one down, pass it around,\n"
~ (num - 1).text ~ " bottle" ~ ((num - 1 == 1) ? "" : "s")
~ " of beer on the wall.\n\n"
~ ((num > 2)
? bottlesRecurse(num - 1)
: "1 bottle of beer on the wall,\n"
~ "1 bottle of beer!\n"
~ "Take one down, pass it around,\n"
~ "No bottles of beer on the wall!\n\n");
}
return bottlesRecurse(num)
~ "Go to the store and buy some more...\n"
~ num.text ~ " bottles of beer on the wall!";
}
pragma(msg, 99.bottles);
void main() {}
Template Meta-Programming Solution
Uses D template meta-programming and recursion to pre-generate the song lyrics and prints it at compile via pragma(msg,...)
module bottles;
template BeerSong(int Bottles)
{
static if (Bottles == 1)
{
enum BeerSong = "1 bottle of beer on the wall\n" ~
"1 bottle of beer\ntake it down, pass it around\n" ~ "
no more bottles of beer on the wall\n";
}
else
{
enum BeerSong = Bottles.stringof ~ " bottles of beer on the wall\n" ~
Bottles.stringof ~ " bottles of beer\ntake it down, pass it around\n" ~
BeerSong!(Bottles-1);
}
}
pragma(msg,BeerSong!99);
void main(){}
Dart
// Making use of polymorphism
main() {
BeerSong beerSong = BeerSong();
//pass a 'starting point' and 'end point' as parameters respectively
String printTheLyrics = beerSong.recite(99, 1).join('\n');
print(printTheLyrics);
}
class Song {
String bottleOnTheWall(int index) {
String bottleOnTheWallText =
'$index bottles of beer on the wall, $index bottles of beer,';
return bottleOnTheWallText;
}
String bottleTakenDown(int index) {
String englishGrammar = (index >= 2) ? 'bottle' : 'bottles';
String bottleTakenDownText =
'Take one down and pass it around, ${index - 1} $englishGrammar of beer on the wall.';
return bottleTakenDownText;
}
}
class BeerSong extends Song {
@override
String bottleOnTheWall(int index) {
String originalText = super.bottleOnTheWall(index);
if (index < 2) {
String bottleOnTheWallText =
'$index bottle of beer on the wall, $index bottle of beer,';
return bottleOnTheWallText;
}
return originalText;
}
@override
String bottleTakenDown(int index) {
if (index < 2) {
String bottleTakenDownText =
'Take it down and pass it around, no more bottles of beer on the wall.';
return bottleTakenDownText;
}
String originalText = super.bottleTakenDown(index);
return originalText;
}
List<String> recite(int actualBottleOnTheWall, int remainingBottleOnTheWall) {
List<String> theLyrics = [];
for (int index = actualBottleOnTheWall;
index >= remainingBottleOnTheWall;
index--) {
String onTheWall = bottleOnTheWall(index);
String takenDown = bottleTakenDown(index);
theLyrics.add(onTheWall);
theLyrics.add(takenDown);
theLyrics.add('');
}
return theLyrics;
}
}
}
Dc
[
dnrpr
dnlBP
lCP
1-dnrp
rd2r >L
]sL
[Take one down, pass it around
]sC
[ bottles of beer
]sB
[ bottles of beer on the wall]
99
lLx
dnrpsA
dnlBP
lCP
1-
dn[ bottle of beer on the wall]p
rdnrpsA
n[ bottle of beer
]P
[Take it down, pass it around
]P
[no more bottles of beer on the wall
]P
Similar to the program above, but without 'n' and 'r' commands. It prints the numbers on separate lines than the strings.
[
plAP
plBP
lCP
1-dplAP
d2r >L
]sL
[Take one down, pass it around
]sC
[bottles of beer
]sB
[bottles of beer on the wall
]sA
99
lLx
plAP
plBP
lCP
1-
p
[bottle of beer on the wall
]P
p
[bottle of beer
]P
[Take it down, pass it around
]P
[no more bottles of beer on the wall
]P
DBL
;
;===============================================================================
; Oringinal Author: Bob Welton (welton@pui.com)
; Language: DIBOL or DBL
;
; Modified to work with DBL version 4
; by Dario B.
;===============================================================================
RECORD
NRBOT,D2,99 ;Default # of bottles to 99
A2, A2
PROC
;-------------------------------------------------------------------------------
XCALL FLAGS (0007000000,1) ;Suppress STOP message
OPEN (1,O,"TT:") ;Open the terminal/display
DO FOREVER
BEGIN
A2=NRBOT,'ZX'
DISPLAY (1,A2," Bottles of Beer on the wall,",10)
A2=NRBOT,'ZX'
DISPLAY (1,A2," Bottles of Beer,",10)
DISPLAY (1," Take one down, pass it around,",10)
DECR NRBOT ;Reduce # of bottles by 1
IF (NRBOT.LE.1) EXITLOOP ;If just 1 bottle left, get out
A2=NRBOT,'ZX'
DISPLAY (1,A2," Bottles of Beer on the wall.",10,10)
END
A2=NRBOT,'ZX'
DISPLAY (1,A2," Bottle of Beer on the wall,",10,10)
A2=NRBOT,'ZX'
DISPLAY (1,A2," Bottle of Beer,",10)
DISPLAY (1," Take one down, pass it around,",10)
DISPLAY (1,"0 Bottles of Beer on the wall,",10)
DISPLAY (1,"0 Bottles of Beer,",10)
DISPLAY (1,"Go to the store and buy some more,",10)
DISPLAY (1,"99 Bottles of Beer on the wall,",10,10,10)
CLOSE 1
STOP
Delphi
DM
Uses the [] variable insertion into strings, see [1]
/client/New() ..() var/bottlestring for(var/i in 99 to 0) bottlestring = "[i || "No more"] Bottle[i != 1 ? "s" : ""] of Beer" src << "[bottlestring] on the wall," src << "[bottlestring]," src << "Take [i == 1 ? "it" : "one"] down, pass it around," src << "[bottlestring] on the wall,"
Draco
proc nonrec bottles(byte b) void:
if b=0 then write("No more") else write(b) fi;
write(" bottle");
if b~=1 then write("s") fi
corp;
proc nonrec verse(byte v) void:
bottles(v);
writeln(" of beer on the wall,");
bottles(v);
writeln(" of beer,");
writeln("Take ",
if v=1 then "it" else "one" fi,
" down and pass it around");
bottles(v-1);
writeln(" of beer on the wall!\n");
corp;
proc nonrec main() void:
byte v;
for v from 99 downto 1 do verse(v) od
corp
Dyalect
for i in 99^-1..1 {
print("\(i) bottles of beer on the wall, \(i) bottles of beer.")
let next = i is 1 ? "no" : i - 1
print("Take one down and pass it around, \(next) bottles of beer on the wall.")
}
Dylan
Module: bottles
define method bottles (n :: <integer>)
for (n from 99 to 1 by -1)
format-out("%d bottles of beer on the wall,\n"
"%d bottles of beer\n"
"Take one down, pass it around\n"
"%d bottles of beer on the wall\n",
n, n, n - 1);
end
end method
Déjà Vu
plural i:
if = 1 i "" "s"
bottles i:
local :s plural i
!print( to-str i " bottle"s" of beer on the wall, " to-str i " bottle"s" of beer," )
!print\ "You take one down, pass it around, "
set :i -- i
if i:
set :s plural i
!print( to-str i " bottle"s" of beer on the wall." )
bottles i
else:
!print "no more bottles of beer on the wall, no more bottles of beer."
!print "Go to the store and buy some more, 99 bottles of beer on the wall."
bottles 99
DIBOL-11
;
;===============================================================================
========================
; Oringinal Author: Bob Welton (welton@pui.com)
; Language: DIBOL or DBL
;
; Modified to work with DEC DIBOL-11
; by Bill Gunshannon
;===============================================================================
========================
RECORD MISC
NUMBOTTLES ,D2,99 ;Default # of bottles to 99
RECORD LINE1
ANUMBOTTLES, A2
, A32, " Bottles of Beer on the wall,"
RECORD LINE2
BNUMBOTTLES, A2
, A32, " Bottles of Beer,"
RECORD LINE3
CNUMBOTTLES, A2
, A32, " Bottles of Beer on the wall."
RECORD LINE4
DNUMBOTTLES, A2
, A32, " Bottle of Beer on the wall,"
RECORD LINE5
ENUMBOTTLES, A2
, A32, " Bottle of Beer,"
.PROC
XCALL FLAGS (0007000000,1) ;Suppress STOP message
OPEN (8,O:C,"TT:") ;Open the terminal/display
REPEAT
BEGIN
ANUMBOTTLES = NUMBOTTLES,'ZX'
WRITES (8,LINE1)
BNUMBOTTLES = NUMBOTTLES,'ZX'
WRITES (8,LINE2)
WRITES (8," Take one down, pass it around,")
DECR NUMBOTTLES ;Reduce # of bottles by 1
IF (NUMBOTTLES .LE. 1) EXITLOOP ;If just 1 bottle left, get out
CNUMBOTTLES = NUMBOTTLES,'ZX'
WRITES (8,LINE3)
WRITES (8," ")
END
DNUMBOTTLES = NUMBOTTLES,'ZX'
WRITES(8,LINE4)
WRITES (8," ")
ENUMBOTTLES = NUMBOTTLES,'ZX'
WRITES(8,LINE5)
WRITES (8," Take one down, pass it around,")
WRITES(8,"0 Bottles of Beer on the wall,")
WRITES(8,"0 Bottles of Beer,")
WRITES(8,"Go to the store and buy some more,")
WRITES(8,"99 Bottles of Beer on the wall,")
WRITES (8," ")
WRITES (8," ")
SLEEP 2
CLOSE 8
STOP
.END
E
def bottles(n) {
return switch (n) {
match ==0 { "No bottles" }
match ==1 { "1 bottle" }
match _ { `$n bottles` }
}
}
for n in (1..99).descending() {
println(`${bottles(n)} of beer on the wall,
${bottles(n)} of beer.
Take one down, pass it around,
${bottles(n.previous())} of beer on the wall.
`)
}
EasyLang
func$ bottle num .
if num = 1
return "bottle"
.
return "bottles"
.
#
i = 99
repeat
print i & " " & bottle i & " of beer on the wall"
print i & " " & bottle i & " of beer"
print "Take one down, pass it around"
i -= 1
until i = 0
print i & " " & bottle i & " of beer on the wall"
print ""
.
print "No more bottles of beer on the wall"
ECL
Layout := RECORD
UNSIGNED1 RecID1;
UNSIGNED1 RecID2;
STRING30 txt;
END;
Beers := DATASET(99,TRANSFORM(Layout,
SELF.RecID1 := COUNTER,SELF.RecID2 := 0,SELF.txt := ''));
Layout XF(Layout L,INTEGER C) := TRANSFORM
IsOneNext := L.RecID1-1 = 1;
IsOne := L.RecID1 = 1;
SELF.txt := CHOOSE(C,
(STRING)(L.RecID1-1) + ' bottle'+IF(IsOneNext,'','s')+' of beer on the wall',
'Take one down, pass it around',
(STRING)(L.RecID1) + ' bottle'+IF(IsOne,'','s')+' of beer',
(STRING)(L.RecID1) + ' bottle'+IF(IsOne,'','s')+' of beer on the wall','');
SELF.RecID2 := C;
SELF := L;
END;
Rev := NORMALIZE(Beers,5,XF(LEFT,COUNTER));
OUTPUT(SORT(Rev,-Recid1,-RecID2),{txt},ALL);
Ecstasy
module Bottles {
void run() {
function String(Int) num = i -> i==0 ? "No" : i.toString();
function String(Int) bottles = i -> i==1 ? "bottle" : "bottles";
@Inject Console console;
for (Int remain : 99..1) {
console.print($|{num(remain)} {bottles(remain)} of beer on the wall
|{num(remain)} {bottles(remain)} of beer
|Take one down, pass it around
|{num(remain-1)} {bottles(remain-1)} of beer on the wall
|
);
}
}
}
Egel
import "prelude.eg"
import "io.ego"
using System
using IO
def print_rhyme =
[ 0 ->
print "better go to the store, and buy some more\n"
| N ->
let _ = print N " bottles of beer on the wall\n" in
let _ = print N " bottles of beer\n" in
let _ = print "take one down, pass it around\n" in
print_rhyme (N - 1) ]
def main = print_rhyme 99
EGL
program TestProgram type BasicProgram {}
function main()
for (count int from 99 to 1 decrement by 1)
SysLib.writeStdout( bottleStr( count ) :: " of beer on the wall." );
SysLib.writeStdout( bottleStr( count ) :: " of beer." );
SysLib.writeStdout( "Take one down, pass it around." );
SysLib.writeStdout( bottleStr( count - 1) :: " of beer on the wall.\n");
end
end
private function bottleStr( count int in) returns( string )
case ( count )
when ( 1 )
return( "1 bottle" );
when ( 0 )
return( "No more bottles" );
otherwise
return( count :: " bottles" );
end
end
end
Eiffel
class
APPLICATION
create
make
feature {NONE} -- Initialization
make
local
bottles: INTEGER
do
from
bottles := 99
invariant
bottles <= 99 and bottles >= 1
until
bottles = 1
loop
print (bottles)
print (" bottles of beer on the wall,%N")
print (bottles)
print (" bottles of beer.%N")
print ("Take one down, pass it around,%N")
bottles := bottles - 1
if bottles > 1 then
print (bottles)
print (" bottles of beer on the wall.%N%N")
end
variant
bottles
end
print ("1 bottle of beer on the wall.%N%N");
print ("No more bottles of beer on the wall,%N");
print ("no more bottles of beer.%N");
print ("Go to the store and buy some more,%N");
print ("99 bottles of beer on the wall.%N");
end
end
An alternative version written using the across-loop construct.
output_lyrics
-- Output the lyrics to 99-bottles-of-beer.
local
l_bottles: LINKED_LIST [INTEGER]
do
create l_bottles.make
across (1 |..| 99) as ic loop l_bottles.force (ic.item) end
across l_bottles.new_cursor.reversed as ic_bottles loop
print (ic_bottles.item)
print (" bottles of beer on the wall, ")
print (ic_bottles.item)
print (" bottles of beer.%N")
print ("Take one down, pass it around, ")
if ic_bottles.item > 1 then
print (ic_bottles.item)
print (" bottles of beer on the wall.%N%N")
end
end
print ("1 bottle of beer on the wall.%N")
print ("No more bottles of beer on the wall, no more bottles of beer.%N")
print ("Go to the store and buy some more, 99 bottles of beer on the wall.%N")
end
Ela
open list
beer 1 = "1 bottle of beer on the wall\n1 bottle of beer\nTake one down, pass it around"
beer 0 = "better go to the store and buy some more."
beer v = show v ++ " bottles of beer on the wall\n"
++ show v
++" bottles of beer\nTake one down, pass it around\n"
map beer [99,98..0]
Elan
INT VAR number of bottles;
PROCEDURE print how many bottles are on the wall (INT CONST number):
print number;
print bottle;
print trailing text.
print number:
IF number = 0 THEN
put ("No")
ELSE
put (number)
END IF.
print bottle:
out ("Bottle");
IF no <> 1 THEN
out ("s")
END IF.
print trailing text:
out (" of beer").
END PROCEDURE print how many bottles are on the wall;
say hello;
print song;
say goodbye.
say hello:
putline ("99 Bottles of Beer");
putline ("==================");
line.
print song:
FOR number of bottles FROM 99 DOWNTO 1 REPEAT
print first line;
print second line;
print third line
END REPEAT.
say goodbye:
line;
putline ("=====================");
putline ("You need a ride home?");
line.
print first line:
print how many bottles are on the wall (number of bottles);
out (" on the wall, ");
print how many bottles are on the wall (number of bottles);
line.
print second line:
putline ("Take one down and pass it around,").
print third line:
print how many bottles are on the wall (number of bottles - 1);
putline (" on the wall");
line.
Elena
ELENA 6.0 :
import system'routines;
import extensions;
import extensions'routines;
import extensions'text;
extension bottleOp
{
bottleDescription()
= self.toPrintable() + (self != 1).iif(" bottles"," bottle");
bottleEnumerator() = new Variable(self).doWith::(n)
{
^ new Enumerator
{
bool next() = n > 0;
get Value() = new StringWriter()
.printLine(n.bottleDescription()," of beer on the wall")
.printLine(n.bottleDescription()," of beer")
.printLine("Take one down, pass it around")
.printLine((n.reduce(1)).bottleDescription()," of beer on the wall");
reset() {}
enumerable() = weak self;
}
};
}
public program()
{
var bottles := 99;
bottles.bottleEnumerator().forEach(printingLn)
}
- Output:
5 bottles of beer on the wall 5 bottles of beer Take one down, pass it around 4 bottles of beer on the wall 4 bottles of beer on the wall 4 bottles of beer Take one down, pass it around 3 bottles of beer on the wall 3 bottles of beer on the wall 3 bottles of beer Take one down, pass it around 2 bottles of beer on the wall 2 bottles of beer on the wall 2 bottles of beer Take one down, pass it around 1 bottle of beer on the wall 1 bottle of beer on the wall 1 bottle of beer Take one down, pass it around 0 bottles of beer on the wall
Elixir
defmodule Bottles do
def run do
Enum.each 99..1, fn idx ->
IO.puts "#{idx} bottle#{plural(idx)} of beer on the wall"
IO.puts "#{idx} bottle#{plural(idx)} of beer"
IO.puts "Take one down, pass it around"
IO.puts "#{idx - 1} bottle#{plural(idx-1)} of beer on the wall"
IO.puts ""
end
end
def plural(1), do: ""
def plural(num), do: "s"
end
Bottles.run
Elm
module Main exposing (main)
import Html
main =
List.range 1 100
|> List.reverse
|> List.map
(\n ->
let
nString =
String.fromInt n
n1String =
String.fromInt (n - 1)
in
[ nString ++ " bottles of beer on the wall"
, nString ++ " bottles of beer"
, "Take one down, pass it around"
, n1String ++ " bottles of beer on the wall"
]
|> List.map Html.text
|> List.intersperse (Html.br [] [])
|> Html.p []
)
|> Html.div []
Emacs Lisp
(let ((i 99))
(while (> i 0)
(message "%d bottles of beer on the wall" i)
(message "%d bottles of beer" i)
(message "Take one down, pass it around")
(message "%d bottles of beer on the wall" (1- i))
(setq i (1- i))))
EMal
This version writes the lyrics as described here: https://99-bottles-of-beer.net/lyrics.html
type NinetynineBottles
int DEFAULT_BOTTLES_COUNT = 99
model
int initialBottlesCount, bottlesCount
new by int =bottlesCount
me.initialBottlesCount = bottlesCount
end
fun subject = <|when(me.bottlesCount == 1, "bottle", "bottles")
fun bottles = <|when(me.bottlesCount == 0, "no more", text!me.bottlesCount)
fun goToWall = void by block
text line = me.bottles() + " " + me.subject() + " of beer on the wall, " +
me.bottles() + " " + me.subject() + " of beer."
if me.bottlesCount == 0 do line[0] = line[0].upper() end # text can be modified
writeLine(line)
end
fun takeOne = logic by block
if --me.bottlesCount < 0 do return false end # cannot take a beer down
writeLine("Take one down and pass it around, " + me.bottles() +
" " + me.subject() + " of beer on the wall.")
writeLine()
return true
end
fun goToStore = void by block
writeLine("Go to the store and buy some more, " + me.initialBottlesCount +
" bottles of beer on the wall.")
end
fun play = void by block
for ever
me.goToWall()
if not me.takeOne()
me.goToStore()
break
end
end
end
end
NinetynineBottles(when(Runtime.args.length > 0, int!Runtime.args[0], DEFAULT_BOTTLES_COUNT)).play()
The output for two bottles of beer is as follows.
- Output:
2 bottles of beer on the wall, 2 bottles of beer. Take one down and pass it around, 1 bottle of beer on the wall. 1 bottle of beer on the wall, 1 bottle of beer. Take one down and pass it around, no more bottles of beer on the wall. No more bottles of beer on the wall, no more bottles of beer. Go to the store and buy some more, 2 bottles of beer on the wall.
Erlang
-module(beersong).
-export([sing/0]).
-define(TEMPLATE_0, "~s of beer on the wall, ~s of beer.~nGo to the store and buy some more, 99
bottles of beer on the wall.~n").
-define(TEMPLATE_N, "~s of beer on the wall, ~s of beer.~nTake one down and pass it around, ~s of
beer on the wall.~n~n").
create_verse(0) -> {0, io_lib:format(?TEMPLATE_0, phrase(0))};
create_verse(Bottle) -> {Bottle, io_lib:format(?TEMPLATE_N, phrase(Bottle))}.
phrase(0) -> ["No more bottles", "no more bottles"];
phrase(1) -> ["1 bottle", "1 bottle", "no more bottles"];
phrase(2) -> ["2 bottles", "2 bottles", "1 bottle"];
phrase(Bottle) -> lists:duplicate(2, integer_to_list(Bottle) ++ " bottles") ++
[integer_to_list(Bottle-1) ++ " bottles"].
bottles() -> lists:reverse(lists:seq(0,99)).
sing() ->
lists:foreach(fun spawn_singer/1, bottles()),
sing_verse(99).
spawn_singer(Bottle) ->
Pid = self(),
spawn(fun() -> Pid ! create_verse(Bottle) end).
sing_verse(Bottle) ->
receive
{_, Verse} when Bottle == 0 ->
io:format(Verse);
{N, Verse} when Bottle == N ->
io:format(Verse),
sing_verse(Bottle-1)
after
3000 ->
io:format("Verse not received - re-starting singer~n"),
spawn_singer(Bottle),
sing_verse(Bottle)
end.
Euphoria
constant
bottles = "bottles",
bottle = "bottle"
procedure beers (integer how_much)
sequence word1 = bottles, word2 = bottles
switch how_much do
case 2 then
word2 = bottle
case 1 then
word1 = bottle
word2 = bottle
end switch
printf (1,
"%d %s of beer on the wall \n" &
"%d %s of beer \n" &
"Take one down, and pass it around \n" &
"%d %s of beer on the wall \n\n",
{ how_much, word1,
how_much, word1,
how_much-1, word2 }
)
end procedure
for a = 99 to 1 by -1 do
beers (a)
end for
-- An alternate version
include std/console.e
sequence howmany = {"No more bottles","%d bottle","","s"}
for beer = 99 to 1 by -1 do
display(`
[1] bottles of beer on the wall,
[1] bottles of beer.
Take one down, drink it right down,
[2][3] of beer.
`,{beer,
sprintf(howmany[(beer>1)+1],beer-1),
howmany[(beer>2)+3]
})
end for
-- yet another version:
include std/console.e
object stanza = {
"[] bottles of beer on the wall,",
"[] bottles of beer,",
"take one down, and pass it around,"
}
object bottles = 99
loop do
display(stanza[1],bottles)
display(stanza[2],bottles)
display(stanza[3])
bottles -= 1
display(stanza[1]&"\n",{bottles})
until bottles = 0
end loop
Extended BrainF***
F#
#light
let rec bottles n =
let (before, after) = match n with
| 1 -> ("bottle", "bottles")
| 2 -> ("bottles", "bottle")
| n -> ("bottles", "bottles")
printfn "%d %s of beer on the wall" n before
printfn "%d %s of beer" n before
printfn "Take one down, pass it around"
printfn "%d %s of beer on the wall\n" (n - 1) after
if n > 1 then
bottles (n - 1)
Factor
USING: io kernel make math math.parser math.ranges sequences ;
: bottle ( -- quot )
[
[
[
[ # " bottles of beer on the wall,\n" % ]
[ # " bottles of beer.\n" % ] bi
] keep
"Take one down, pass it around,\n" %
1 - # " bottles of beer on the wall\n" %
] " " make print
] ; inline
: last-verse ( -- )
"Go to the store and buy some more,"
"no more bottles of beer on the wall!" [ print ] bi@ ;
: bottles ( n -- )
1 [a,b] bottle each last-verse ;
! Usage: 99 bottles
Falcon
for i in [99:1]
> i, " bottles of beer on the wall"
> i, " bottles of beer"
> "Take one down, pass it around"
> i-1, " bottles of beer on the wall\n"
end
A more robust version to handle plural/not plural conditions
for i in [99:1]
plural = (i != 1) ? 's' : ""
> @ "$i bottle$plural of beer on the wall"
> @ "$i bottle$plural of beer"
> "Take one down, pass it around"
> i-1, @ " bottle$plural of beer on the wall\n"
end
FALSE
Fe
(= n 99)
(while (< 0 n)
(print n "bottles of beer on the wall")
(print n "bottles of beer")
(print "Take one down, pass it around")
(= n (- n 1))
(print n "bottles of beer on the wall\n"))
ferite
copied from 99-bottles-of-beer.net.
uses "console";
number bottles = 99;
boolean looping = true;
object counter = closure {
if (--bottles > 0) {
return true;
} else {
return false;
}
};
while (looping) {
Console.println("${bottles} bottles of beer on the wall,");
Console.println("${bottles} bottles of beer,");
Console.println("Take one down, pass it around,");
looping = counter.invoke();
Console.println("${bottles} bottles of beer on the wall.");
Fexl
\suffix=(\n eq n 1 "" "s")
\sing_count=(\n put [n " bottle" (suffix n) " of beer"])
\sing_line1=(\n sing_count n say " on the wall")
\sing_line2=(\n sing_count n nl)
\sing==
(\n
le n 0 ();
sing_line1 n
sing_line2 n
say "Take one down, pass it around"
\n=(- n 1)
sing_line1 n
nl
sing n
)
sing 3
- Output:
3 bottles of beer on the wall 3 bottles of beer Take one down, pass it around 2 bottles of beer on the wall 2 bottles of beer on the wall 2 bottles of beer Take one down, pass it around 1 bottle of beer on the wall 1 bottle of beer on the wall 1 bottle of beer Take one down, pass it around 0 bottles of beer on the wall
FOCAL
01.10 S N=99
01.15 D 2;T " OF BEER ON THE WALL,",!
01.20 D 2;T " OF BEER,",!
01.24 S N=N-1
01.25 T "TAKE ";I (N),1.3,1.4,1.3
01.30 T "IT";G 1.5
01.40 T "ONE"
01.50 T " DOWN AND PASS IT AROUND,",!
01.60 D 2;T " OF BEER ON THE WALL!",!!
01.70 I (N),1.8,1.15
01.80 Q
02.01 C-PRINT N BOTTLE(S)
02.10 I (N)2.2,2.2,2.3
02.20 T "NO MORE";G 2.4
02.30 D 3
02.40 T " BOTTLE";I (N-1)2.5,2.6,2.5
02.50 T "S"
02.60 R
03.01 C-PRINT 2-DIGIT NUMBER IN N
03.02 C-THIS IS NECESSARY BECAUSE T ALWAYS PREPENDS = TO NUMBERS
03.10 S A=FITR(N/10);I (A),3.3,3.2
03.20 D 4
03.30 S A=N-FITR(N/10)*10;D 4
04.01 C-PRINT DIGIT IN A
04.10 I (A-0),4.20,4.11
04.11 I (A-1),4.21,4.12
04.12 I (A-2),4.22,4.13
04.13 I (A-3),4.23,4.14
04.14 I (A-4),4.24,4.15
04.15 I (A-5),4.25,4.16
04.16 I (A-6),4.26,4.17
04.17 I (A-7),4.27,4.18
04.18 I (A-8),4.28,4.19
04.19 T "9";R
04.20 T "0";R
04.21 T "1";R
04.22 T "2";R
04.23 T "3";R
04.24 T "4";R
04.25 T "5";R
04.26 T "6";R
04.27 T "7";R
04.28 T "8";R
Forth
:noname dup . ." bottles" ;
:noname ." 1 bottle" ;
:noname ." no more bottles" ;
create bottles , , ,
: .bottles dup 2 min cells bottles + @ execute ;
: .beer .bottles ." of beer" ;
: .wall .beer ." on the wall" ;
: .take ." Take one down, pass it around" ;
: .verse .wall cr .beer cr
1- .take cr .wall cr ;
: verses begin cr .verse ?dup 0= until ;
99 verses
Version 2: create a beer language and write the program
DECIMAL
: BOTTLES ( n -- )
DUP
CASE
1 OF ." One more bottle " DROP ENDOF
0 OF ." NO MORE bottles " DROP ENDOF
. ." bottles " \ DEFAULT CASE
ENDCASE ;
: , [CHAR] , EMIT SPACE 100 MS CR ;
: . [CHAR] . EMIT 300 MS CR CR CR ;
: OF ." of " ; : BEER ." beer " ;
: ON ." on " ; : THE ." the " ;
: WALL ." wall" ; : TAKE ." take " ;
: ONE ." one " ; : DOWN ." down, " ;
: PASS ." pass " ; : IT ." it " ;
: AROUND ." around" ;
: POPONE 1 SWAP CR ;
: DRINK POSTPONE DO ; IMMEDIATE
: ANOTHER S" -1 +LOOP" EVALUATE ; IMMEDIATE
: HOWMANY S" I " EVALUATE ; IMMEDIATE
: ONELESS S" I 1- " EVALUATE ; IMMEDIATE
: HANGOVER ." :-(" CR QUIT ;
: BEERS ( n -- ) \ Usage: 99 BEERS
POPONE
DRINK
HOWMANY BOTTLES OF BEER ON THE WALL ,
HOWMANY BOTTLES OF BEER ,
TAKE ONE DOWN PASS IT AROUND ,
ONELESS BOTTLES OF BEER ON THE WALL .
ANOTHER
HANGOVER ;
Forth Console Output
2 beers
2 bottles of beer on the wall,
2 bottles of beer ,
take one down, pass it around,
One more bottle of beer on the wall.
One more bottle of beer on the wall,
One more bottle of beer ,
take one down, pass it around,
No more bottles of beer on the wall.
ok
Fortran
F90 version
program bottlestest
implicit none
integer :: i
character(len=*), parameter :: bwall = " on the wall", &
bottles = "bottles of beer", &
bottle = "bottle of beer", &
take = "Take one down, pass it around", &
form = "(I0, ' ', A)"
do i = 99,0,-1
if ( i /= 1 ) then
write (*,form) i, bottles // bwall
if ( i > 0 ) write (*,form) i, bottles
else
write (*,form) i, bottle // bwall
write (*,form) i, bottle
end if
if ( i > 0 ) write (*,*) take
end do
end program bottlestest
MPI version
program bottlesMPI
implicit none
integer :: ierr,rank,nproc
character(len=*), parameter :: bwall = " on the wall", &
bottles = "bottles of beer", &
bottle = "bottle of beer", &
take = "Take one down, pass it around", &
form = "(I0, ' ', A)"
call mpi_init(ierr)
call mpi_comm_size(MPI_COMM_WORLD,nproc, ierr)
call mpi_comm_rank(MPI_COMM_WORLD,rank,ierr)
if ( rank /= 1 ) then
write (*,form) rank, bottles // bwall
if ( rank > 0 ) write (*,form) rank, bottles
else
write (*,form) rank, bottle // bwall
write (*,form) rank, bottle
end if
if ( rank > 0 ) write (*,*) take
call mpi_finalize(ierr)
end program bottlesMPI
Usage:
mpif90 filename.f90 mpiexec -np 99 a.out
Fortran 2003/2008 OOP version
Works with GNU gfortran 5.0.0 and Intel ifort 15.0.2
module song_typedefs
implicit none
private ! all
public :: TBottles
type, abstract :: TContainer
integer :: quantity
contains
! deferred method i.e. abstract method = must be overridden in extended type
procedure(take_one), deferred, pass :: take_one
procedure(show_quantity), deferred, pass :: show_quantity
end type TContainer
abstract interface
subroutine take_one(this)
import TContainer
implicit none
class(TContainer) :: this
end subroutine take_one
subroutine show_quantity(this)
import TContainer
implicit none
class(TContainer) :: this
end subroutine show_quantity
end interface
! extended derived type
type, extends(TContainer) :: TBottles
contains
procedure, pass :: take_one => take_one_bottle
procedure, pass :: show_quantity => show_bottles
final :: finalize_bottles
end type TBottles
contains
subroutine show_bottles(this)
implicit none
class(TBottles) :: this
! integer :: show_bottles
character(len=*), parameter :: bw0 = "No more bottles of beer on the wall,"
character(len=*), parameter :: bwx = "bottles of beer on the wall,"
character(len=*), parameter :: bw1 = "bottle of beer on the wall,"
character(len=*), parameter :: bb0 = "no more bottles of beer."
character(len=*), parameter :: bbx = "bottles of beer."
character(len=*), parameter :: bb1 = "bottle of beer."
character(len=*), parameter :: fmtxdd = "(I2,1X,A28,1X,I2,1X,A16)"
character(len=*), parameter :: fmtxd = "(I1,1X,A28,1X,I1,1X,A16)"
character(len=*), parameter :: fmt1 = "(I1,1X,A27,1X,I1,1X,A15)"
character(len=*), parameter :: fmt0 = "(A36,1X,A24)"
select case (this % quantity)
case (10:)
write(*,fmtxdd) this % quantity, bwx, this % quantity, bbx
case (2:9)
write(*,fmtxd) this % quantity, bwx, this % quantity, bbx
case (1)
write(*,fmt1) this % quantity, bw1, this % quantity, bb1
case (0)
write(*,*)
write(*,fmt0) bw0, bb0
case default
write(*,*)"Warning! Number of bottles exception, error 42. STOP"
stop
end select
! show_bottles = this % quantity
end subroutine show_bottles
subroutine take_one_bottle(this) ! bind(c, name='take_one_bottle')
implicit none
class(TBottles) :: this
! integer :: take_one_bottle
character(len=*), parameter :: t1 = "Take one down and pass it around,"
character(len=*), parameter :: remx = "bottles of beer on the wall."
character(len=*), parameter :: rem1 = "bottle of beer on the wall."
character(len=*), parameter :: rem0 = "no more bottles of beer on the wall."
character(len=*), parameter :: fmtx = "(A33,1X,I2,1X,A28)"
character(len=*), parameter :: fmt1 = "(A33,1X,I2,1X,A27)"
character(len=*), parameter :: fmt0 = "(A33,1X,A36)"
this % quantity = this % quantity -1
select case (this%quantity)
case (2:)
write(*,fmtx) t1, this%quantity, remx
case (1)
write(*,fmt1) t1, this%quantity, rem1
case (0)
write(*,fmt0) t1, rem0
case (-1)
write(*,'(A66)') "Go to the store and buy some more, 99 bottles of beer on the wall."
case default
write(*,*)"Warning! Number of bottles exception, error 42. STOP"
stop
end select
end subroutine take_one_bottle
subroutine finalize_bottles(bottles)
implicit none
type(TBottles) :: bottles
! here can be more code
end subroutine finalize_bottles
end module song_typedefs
!-----------------------------------------------------------------------
!Main program
!-----------------------------------------------------------------------
program bottles_song
use song_typedefs
implicit none
integer, parameter :: MAGIC_NUMBER = 99
type(TBottles), target :: BTLS
BTLS = TBottles(MAGIC_NUMBER)
call make_song(BTLS)
contains
subroutine make_song(bottles)
type(TBottles) :: bottles
do while(bottles%quantity >= 0)
call bottles%show_quantity()
call bottles%take_one()
enddo
end subroutine make_song
end program bottles_song
Frege
(identical to the Haskell, apart from adding the module declaration)
module Beer where
main = mapM_ (putStrLn . beer) [99, 98 .. 0]
beer 1 = "1 bottle of beer on the wall\n1 bottle of beer\nTake one down, pass it around"
beer 0 = "better go to the store and buy some more."
beer v = show v ++ " bottles of beer on the wall\n"
++ show v
++ " bottles of beer\nTake one down, pass it around\n"
++ head (lines $ beer $ v-1) ++ "\n"
friendly interactive shell
Frink
Frink tracks units of measure through all calculations. It has a large library of built-in units of measure, including volume. The following program prints out the remaining volume of beer (assuming we start with 99 bottles of beer, each containing 12 fluid ounces) in different random units of volume, never repeating a unit.
units = array[units[volume]]
showApproximations[false]
for n = 99 to 0 step -1
{
unit = units.removeRandom[]
str = getBottleString[n, unit]
println["$str of beer on the wall, $str."]
if (n == 0)
println["Go to the store and buy some more, 99 bottles of beer on the wall."]
else
println["Take one down and pass it around, " + getBottleString[n-1, unit] + " on the wall.\n"]
}
getBottleString[n, unit] := format[n*12 floz, unit, 6] + "s"
Sample randomized output:
0.019386 facecords of beer on the wall, 0.019386 facecords. Take one down and pass it around, 0.019190 facecords on the wall. 36.750000 quarts of beer on the wall, 36.750000 quarts. Take one down and pass it around, 36.375000 quarts on the wall. 581539.650545 brminims of beer on the wall, 581539.650545 brminims. Take one down and pass it around, 575544.396416 brminims on the wall. 10.377148 scotsoatlippys of beer on the wall, 10.377148 scotsoatlippys. Take one down and pass it around, 10.269053 scotsoatlippys on the wall. 7.416004 cangallons of beer on the wall, 7.416004 cangallons. Take one down and pass it around, 7.337941 cangallons on the wall. 3335.894135 dessertspoons of beer on the wall, 3335.894135 dessertspoons. Take one down and pass it around, 3300.405899 dessertspoons on the wall. 0.233105 barrelbulks of beer on the wall, 0.233105 barrelbulks. Take one down and pass it around, 0.230599 barrelbulks on the wall. 21.766118 magnums of beer on the wall, 21.766118 magnums. Take one down and pass it around, 21.529530 magnums on the wall. 1092.000000 fluidounces of beer on the wall, 1092.000000 fluidounces. Take one down and pass it around, 1080.000000 fluidounces on the wall. ... 12.000000 ponys of beer on the wall, 12.000000 ponys. Take one down and pass it around, 0.000000 ponys on the wall. 0.000000 brfluidounces of beer on the wall, 0.000000 brfluidounces. Go to the store and buy some more, 99 bottles of beer on the wall.
FunL
val
numbers = {1:'one', 2:'two', 3:'three', 4:'four', 5:'five', 6:'six', 7:'seven',
8:'eight', 9:'nine', 10:'ten', 11:'eleven', 12:'twelve'}
alt = {3:'thir', 5:'fif'}
def
suffix( a, b ) = (if a.endsWith( 't' ) then a.substring( 0, a.length()-1 ) else a) + b
number( n@(13 | 15) ) = suffix( alt(n%10), 'teen' )
number( 20 ) = 'twenty'
number( n@(30 | 50) ) = suffix( alt(n\10), 'ty' )
number( n )
| n <= 12 = numbers(n)
| n <= 19 = suffix( numbers(n%10), 'teen' )
| 10|n = suffix( numbers(n\10), 'ty' )
| otherwise = number( n\10*10 ) + '-' + number( n%10 )
cap( s ) = s.substring( 0, 1 ).toUpperCase() + s.substring( 1, s.length() )
bottles( 0 ) = 'no more bottles'
bottles( 1 ) = 'one bottle'
bottles( n ) = number( n ) + ' bottles'
verse( 0 ) = ('No more bottles of beer on the wall, no more bottles of beer.\n'
+ 'Go to the store and buy some more, ninety-nine bottles of beer on the wall.')
verse( n ) = (cap( bottles(n) ) + ' of beer on the wall, ' + bottles( n ) + ' of beer.\n'
+ 'Take one down and pass it around, ' + bottles( n-1 )
+ ' of beer on the wall.\n')
for i <- 99..0 by -1 do println( verse(i) )
FutureBasic
include "NSLog.incl"
NSUInteger i
CFStringRef a, b, c
a = @" bottles of beer on the wall,\n"
b = @" bottles of beer.\n"
c = @"Take one down, pass it around,\n"
for i = 99 to 1 step -1
NSLog( @"%ld%@%ld%@%@%ld%@\n", i, a, i, b, c, i -1, a )
next
HandleEvents
Gambas
Implementation of the code '99 bottles of beer' written in Visual Basic. Code tested in Gambas 3.15.2
' Gambas module file
Public Const bottlesofbeer As String = " bottles of beer."
Public Const onthewall As String = " on the wall."
Public Const takeonedown As String = "Take one down, pass it around."
Public Const onebeer As String = "1 bottle of beer"
Public Sub Main()
Dim bottles As Byte
For bottles = 99 To 3 Step -1
Print CStr(bottles) & bottlesofbeer & onthewall
Print CStr(bottles) & bottlesofbeer
Print takeonedown
Print CStr(bottles - 1) & bottlesofbeer & onthewall
Print
Next
Print "2" & bottlesofbeer & onthewall
Print "2" & bottlesofbeer
Print takeonedown
Print onebeer & onthewall
Print
Print onebeer & onthewall
Print onebeer
Print takeonedown
Print "No more" & bottlesofbeer & onthewall
Print
Print "No" & bottlesofbeer & onthewall
Print "No" & bottlesofbeer
Print "Go to the store, buy some more."
Print "99" & bottlesofbeer & onthewall
End
GAP
Bottles := function(n)
local line, i, j, u;
line := function(n)
s := String(n);
if n < 2 then
return Concatenation(String(n), " bottle of beer");
else
return Concatenation(String(n), " bottles of beer");
fi;
end;
for i in [1 .. n] do
j := n - i + 1;
u := line(j);
Display(Concatenation(u, " on the wall"));
Display(u);
Display("Take one down, pass it around");
Display(Concatenation(line(j - 1), " on the wall"));
if i <> n then
Display("");
fi;
od;
end;
GDScript
extends MainLoop
# Represents a count of bottles
class Bottles:
var count := 99
func take(n: int = 1) -> void:
count -= n
func _to_string() -> String:
match count:
0: return "No more bottles"
1: return "1 bottle"
_: return "%s bottles" % count
func _process(_delta: float) -> bool:
var bottles := Bottles.new()
while bottles.count > 0:
print("%s of beer on the wall" % bottles)
print("%s of beer" % bottles)
print("Take one down, pass it around")
bottles.take()
print("%s of beer on the wall" % bottles)
# Seperate paragraphs
if bottles.count > 0:
print()
return true # Makes the program exit
Silly node-tree version
This uses the node's children as the display method (which can be viewed in-editor with the remote tab).
extends Node
@export var alcoholism: int = 99
func _ready():
# Add the lyrics as child nodes
var padding := "" # Avoid name clashes by adding spaces
for bottleCount in range(alcoholism, 0, -1):
# Seperate paragraphs with blank nodes
if bottleCount < alcoholism:
add_lyric(padding)
add_lyric("%s of beer on the wall" % [_formatBottles(bottleCount)])
add_lyric("%s of beer" % [_formatBottles(bottleCount)])
add_lyric("Take one down, pass it around" + padding)
add_lyric("%s of beer on the wall " % [_formatBottles(bottleCount - 1)]) # Extra space for name clash avoidance
padding += " " # Add spaces so the names don't clash
func _formatBottles(bottleCount: int) -> String:
return "%d bottle%s" % [bottleCount, "" if bottleCount == 1 else "s"]
func add_lyric(lyric: String) -> void:
var new_child := Node.new()
new_child.name = lyric
add_child(new_child)
Genie
[indent=4]
def plural(n:uint):string
return (n == 1) ? "" : "s"
def no(n:uint):string
return (n == 0) ? "No" : n.to_string()
init
bottles:uint = 99;
do
print "%u bottle%s of beer on the wall", bottles, plural(bottles)
print "%u bottle%s of beer", bottles, plural(bottles)
print "Take one down, pass it around"
--bottles
print "%s bottle%s of beer on the wall\n", no(bottles), plural(bottles)
while bottles != 0
- Output:
prompt$ valac 99bottles.gs prompt$ ./99bottles | tail -10 2 bottles of beer on the wall 2 bottles of beer Take one down, pass it around 1 bottle of beer on the wall 1 bottle of beer on the wall 1 bottle of beer Take one down, pass it around No bottles of beer on the wall
gnuplot
if (!exists("bottles")) bottles = 99
print sprintf("%i bottles of beer on the wall", bottles)
print sprintf("%i bottles of beer", bottles)
print "Take one down, pass it around"
bottles = bottles - 1
print sprintf("%i bottles of beer on the wall", bottles)
print ""
if (bottles > 0) reread
Go
No sense of humor
package main
import "fmt"
func main() {
bottles := func(i int) string {
switch i {
case 0:
return "No more bottles"
case 1:
return "1 bottle"
default:
return fmt.Sprintf("%d bottles", i)
}
}
for i := 99; i > 0; i-- {
fmt.Printf("%s of beer on the wall\n", bottles(i))
fmt.Printf("%s of beer\n", bottles(i))
fmt.Printf("Take one down, pass it around\n")
fmt.Printf("%s of beer on the wall\n", bottles(i-1))
}
}
Typoglycemic
With code from RC tasks Number names, Knuth shuffle.
package main
import (
"fmt"
"math/rand"
"strings"
"time"
)
func main() {
rand.Seed(time.Now().UnixNano())
for i := 99; i > 0; i-- {
fmt.Printf("%s %s %s\n",
slur(numberName(i), i),
pluralizeFirst(slur("bottle of", i), i),
slur("beer on the wall", i))
fmt.Printf("%s %s %s\n",
slur(numberName(i), i),
pluralizeFirst(slur("bottle of", i), i),
slur("beer", i))
fmt.Printf("%s %s %s\n",
slur("take one", i),
slur("down", i),
slur("pass it around", i))
fmt.Printf("%s %s %s\n",
slur(numberName(i-1), i),
pluralizeFirst(slur("bottle of", i), i-1),
slur("beer on the wall", i))
}
}
// adapted from Number names task
func numberName(n int) string {
switch {
case n < 0:
case n < 20:
return small[n]
case n < 100:
t := tens[n/10]
s := n % 10
if s > 0 {
t += " " + small[s]
}
return t
}
return ""
}
var small = []string{"no", "one", "two", "three", "four", "five", "six",
"seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen",
"fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"}
var tens = []string{"ones", "ten", "twenty", "thirty", "forty",
"fifty", "sixty", "seventy", "eighty", "ninety"}
// pluralize first word of s by adding an s, but only if n is not 1.
func pluralizeFirst(s string, n int) string {
if n == 1 {
return s
}
w := strings.Fields(s)
w[0] += "s"
return strings.Join(w, " ")
}
// p is string to slur, d is drunkenness, from 0 to 99
func slur(p string, d int) string {
// shuffle only interior letters
a := []byte(p[1 : len(p)-1])
// adapted from Knuth shuffle task.
// shuffle letters with probability d/100.
for i := len(a) - 1; i >= 1; i-- {
if rand.Intn(100) >= d {
j := rand.Intn(i + 1)
a[i], a[j] = a[j], a[i]
}
}
// condense spaces
w := strings.Fields(p[:1] + string(a) + p[len(p)-1:])
return strings.Join(w, " ")
}
- Output:
Things start out pretty well...
ninety nine bottles of beer on the wall ninety nine bottles of beer take one down pass it around ninety eight bottles of beer on the wall ninety eight bottles of beer on the wall ninety eight bottles of beer take one down pass it around ninety seven bottles of beer on the wall ninety seven boetlts of beer on the wall ninety seven bottles of beer take one down pass it around ninety six botelts of beer on the wall
Soon,
eighty four bottles of bere wn the oall ehigty four bottles of beer tkae one down pnssti arouad eihhty tgree bttoles of beer en tho wall eighty three blottes of beet on rhe wall eighty three bottles of beer taen oke down pass it around eiwyth tgo bttoles of beew on lhr eatl
It ends very well, if you're drinking along.
two btloots ef bre enehta wo ll two bs tleootf beer tnoeka e dwon pts ou nsaaird one bolote tf betwr le ao enhl one beoo ttlf blwtenr ehoa el one bltooe tf beer tne okae down pasaostiu rnd no bletts oof beloethw r ea nl
Go!
Copied from The 99 Bottles of Beer web site with a minor bug fix.
--
-- 99 Bottles of Beer in Go!
-- John Knottenbelt
--
-- Go! is a multi-paradigm programming language that is oriented
-- to the needs of programming secure, production quality, agent
-- based applications.
--
-- http://www.doc.ic.ac.uk/~klc/dalt03.html
--
main .. {
include "sys:go/io.gof".
include "sys:go/stdlib.gof".
main() ->
drink(99);
stdout.outLine("Time to buy some more beer...").
drink(0) -> {}.
drink(i) -> stdout.outLine(
bottles(i) <> " on the wall,\n" <>
bottles(i) <> ".\n" <>
"take one down, pass it around,\n" <>
bottles(i-1) <> " on the wall.\n");
drink(i-1).
bottles(0) => "no bottles of beer".
bottles(1) => "1 bottle of beer".
bottles(i) => i^0 <> " bottles of beer".
}
Golfscript
[296,{3/)}%-1%["No more"]+[" bottles":b]294*[b-1<]2*+[b]+[" of beer on the wall\n".8<"\nTake one down, pass it around\n"+1$n+]99*]zip
Golo
module Bottles
augment java.lang.Integer {
function bottles = |self| -> match {
when self == 0 then "No bottles"
when self == 1 then "One bottle"
otherwise self + " bottles"
}
}
function main = |args| {
99: downTo(1, |i| {
println(i: bottles() + " of beer on the wall,")
println(i: bottles() + " of beer!")
println("Take one down, pass it around,")
println((i - 1): bottles() + " of beer on the wall!")
println("--------------------------------------")
})
}
Gosu
for (i in 99..0) {
print("${i} bottles of beer on the wall")
if (i > 0) {
print("${i} bottles of beer")
print("Take one down, pass it around")
}
print("");
}
Groovy
Basic Solution
With a closure to handle special cardinalities of bottles.
def bottles = { "${it==0 ? 'No more' : it} bottle${it==1 ? '' : 's' }" }
99.downto(1) { i ->
print """
${bottles(i)} of beer on the wall
${bottles(i)} of beer
Take one down, pass it around
${bottles(i-1)} of beer on the wall
"""
}
Single Print Version
Uses a single print algorithm for all four lines. Handles cardinality on bottles, uses 'No more' instead of 0.
298.downto(2) {
def (m,d) = [it%3,(int)it/3]
print "${m==1?'\n':''}${d?:'No more'} bottle${d!=1?'s':''} of beer" +
"${m?' on the wall':'\nTake one down, pass it around'}\n"
}
Bottomless Beer Solution
Using more closures to create a richer lyrical experience.
def bottles = { "${it==0 ? 'No more' : it} bottle${it==1 ? '' : 's' }" }
def initialState = {
"""${result(it)}
${resultShort(it)}"""
}
def act = {
it > 0 ?
"Take ${it==1 ? 'it' : 'one'} down, pass it around" :
"Go to the store, buy some more"
}
def delta = { it > 0 ? -1 : 99 }
def resultShort = { "${bottles(it)} of beer" }
def result = { "${resultShort(it)} on the wall" }
// //// uncomment commented lines to create endless drunken binge //// //
// while (true) {
99.downto(0) { i ->
print """
${initialState(i)}
${act(i)}
${result(i+delta(i))}
"""
}
// Thread.sleep(1000)
// }
GUISS
We will just use the calculator and keep taking one off. We do not get the full text here, but the number of the calculator shows how many bottles we still have left to drink:
Start,Programs,Accessories,Calculator,Button:9,Button:9,
Button:[hyphen],Button:1,Button:[equals],Button:[hyphen],Button:1,Button:[equals],
Button:[hyphen],Button:1,Button:[equals],Button:[hyphen],Button:1,Button:[equals],
Button:[hyphen],Button:1,Button:[equals],Button:[hyphen],Button:1,Button:[equals],
Button:[hyphen],Button:1,Button:[equals],Button:[hyphen],Button:1,Button:[equals]
We haven't drank all of the bottles at this point, but we can keep going, if we want.
Halon
$plural = "s";
$x = 99;
while ($x > 0) {
echo "$x bottle$plural of beer on the wall";
echo "$x bottle$plural of beer";
echo "Take one down, pass it around";
$x -= 1;
if ($x == 1)
$plural = "";
if ($x > 0)
echo "$x bottle$plural of beer on the wall\n";
else
echo "No more bottles of beer on the wall!";
}
Haskell
Brevity
A relatively concise solution:
main = mapM_ (putStrLn . beer) [99, 98 .. 0]
beer 1 = "1 bottle of beer on the wall\n1 bottle of beer\nTake one down, pass it around"
beer 0 = "better go to the store and buy some more."
beer v = show v ++ " bottles of beer on the wall\n"
++ show v
++" bottles of beer\nTake one down, pass it around\n"
++ head (lines $ beer $ v-1) ++ "\n"
List comprehension
As a list comprehension:
import qualified Char
main = putStr $ concat
[up (bob n) ++ wall ++ ", " ++ bob n ++ ".\n" ++
pass n ++ bob (n - 1) ++ wall ++ ".\n\n" |
n <- [99, 98 .. 0]]
where bob n = (num n) ++ " bottle" ++ (s n) ++ " of beer"
wall = " on the wall"
pass 0 = "Go to the store and buy some more, "
pass _ = "Take one down and pass it around, "
up (x : xs) = Char.toUpper x : xs
num (-1) = "99"
num 0 = "no more"
num n = show n
s 1 = ""
s _ = "s"
Writer monad and Template Haskell
Another version, which uses a Writer monad to collect each part of the song. It also uses Template Haskell to generate the song at compile time.
{-# LANGUAGE TemplateHaskell #-}
-- build with "ghc --make beer.hs"
module Main where
import Language.Haskell.TH
import Control.Monad.Writer
-- This is calculated at compile time, and is equivalent to
-- songString = "99 bottles of beer on the wall\n99 bottles..."
songString =
$(let
sing = tell -- we can't sing very well...
someBottles 1 = "1 bottle of beer "
someBottles n = show n ++ " bottles of beer "
bottlesOfBeer n = (someBottles n ++)
verse n = do
sing $ n `bottlesOfBeer` "on the wall\n"
sing $ n `bottlesOfBeer` "\n"
sing $ "Take one down, pass it around\n"
sing $ (n - 1) `bottlesOfBeer` "on the wall\n\n"
song = execWriter $ mapM_ verse [99,98..1]
in return $ LitE $ StringL $ song)
main = putStr songString
Avoiding append by spelling bottle backwards
Is there something just a little prickly and displeasing about (++) ? Monoid (<>) is less spiky, but neither is needed when 'bottle' is written backwards.
location, distribution, solution :: String
[location, distribution, solution] =
[ "on the wall",
"Take one down, pass it around",
"Better go to the store to buy some more"
]
incantation :: Int -> String
incantation n
| 0 == n = solution
| otherwise =
unlines
[ inventory n,
asset n,
distribution,
inventory $ pred n
]
inventory :: Int -> String
inventory = unwords . (: [location]) . asset
asset :: Int -> String
asset n =
let suffix n
| 1 == n = []
| otherwise = ['s']
in unwords
[show n, (reverse . concat) $ suffix n : ["elttob"]]
main :: IO ()
main = putStrLn $ unlines (incantation <$> [99, 98 .. 0])
Haxe
Simple solution
class RosettaDemo
{
static public function main()
{
singBottlesOfBeer(100);
}
static function singBottlesOfBeer(bottles : Int)
{
var plural : String = 's';
while (bottles >= 1)
{
Sys.println(bottles + " bottle" + plural + " of beer on the wall,");
Sys.println(bottles + " bottle" + plural + " of beer!");
Sys.println("Take one down, pass it around,");
if (bottles - 1 == 1)
{
plural = '';
}
if (bottles > 1)
{
Sys.println(bottles-1 + " bottle" + plural + " of beer on the wall!\n");
}
else
{
Sys.println("No more bottles of beer on the wall!");
}
bottles--;
}
}
}
Macro solution
All those counters, loops and conditinal blocks are pretty expensive in runtime compared to single print of fully inlined text of the song. Let's generate that print with macro.
class Bottles {
static public function main () : Void {
singBottlesOfBeer(100);
}
macro static public function singBottlesOfBeer (bottles:Int) {
var lines = [];
var s : String = 's';
var song : String = '';
while( bottles >= 1 ){
song += '$bottles bottle$s of beer on the wall,\n';
song += '$bottles bottle$s of beer!\n';
song += 'Take one down, pass it around,\n';
bottles --;
if( bottles > 1 ){
song += '$bottles bottles of beer on the wall!\n\n';
}else if( bottles == 1 ){
s = '';
song += '$bottles bottle of beer on the wall!\n\n';
}else{
song += 'No more bottles of beer on the wall!\n';
}
}
return macro Sys.print($v{song});
}
}
hexiscript
fun bottles amount beverage location
let bottle " bottles of "
if amount = 0; let amount "No more"
elif amount = 1; let bottle " bottle of "; endif
return amount + bottle + beverage + " " + location
endfun
fun take amount location
return "Take " + amount + " " + location
endfun
fun pass entity destination
return ", pass " + entity + " " + destination
endfun
let amount 99
while amount > 0
println bottles amount "beer" "on the wall"
println bottles amount "beer" ""
println take "one" "down" + pass "it" "around"
println bottles (--amount) "beer" "on the wall\n"
endwhile
HicEst
DO x = 99, 1, -1
WRITE() x , "bottles of beer on the wall"
BEEP("T16 be be be bH bH bH be be be 2be ")
WRITE() x , "bottles of beer"
BEEP("2p f f f c c c 2f ")
WRITE() "take one down, pass it around"
BEEP("2p 2d d d 2p d d d 2d ")
WRITE() x , "bottles of beer on the wall"
BEEP("2p #A #A #A c c d #d #d #d 2#d 2p")
ENDDO
HolyC
The default is 99 bottles, but it can be modified by the parameter.
U0 BottlesOfBeer (I64 initial=99) {
// This is made I64 rather than U64
// Because, a U64 would overflow
// At the end of the loop, thus it would loop forever (i-- would be 0-1 so it overflows and is always greater than or equal to 0)
I64 i = initial;
for (; i >= 0; i--) {
if (i == 1) {
// Just a string on it's own will pass it to an inbuilt HolyC function that puts it to terminal
"1 Bottle of Beer on the wall, 1 bottle of beer.\n";
"Take one down and pass it around, no more bottles of beer on the wall.\n";
} else if (i == 0) {
"No more bottles of beer on the wall, no more bottles of beer.\n";
"Go to the store and buy some more, 99 bottles of beer on the wall.\n";
} else {
"%d bottles of beer on the wall, %d bottles of beer.\n",i,i;
"Take one down and pass it around, %d bottle",(i-1);
// Only add the s if it's not 1
if ((i-1) != 1) {
"s";
}
" of beer on the wall.\n";
}
}
}
// Calls the function, which goes to the default parameters
BottlesOfBeer;
Hoon
:- %say
|= [* * [bottles=_99 ~]]
:- %noun
^- wall
=/ output `(list tape)`~
|-
?: =(1 bottles)
%- flop
:- "1 bottle of beer on the wall"
:- "Take one down, pass it around"
:- "1 bottle of beer"
:- "1 bottle of beer on the wall"
output
%= $
bottles (dec bottles)
output
:- "{<bottles>} bottles of beer on the wall"
:- "Take one down, pass it around"
:- "{<bottles>} bottles of beer"
:- "{<bottles>} bottles of beer on the wall"
output
==
Hope
El código es de Wolfgang Lohmann (wlohmann@informatik.uni-rostock.de)
dec app :( list ( char ) X list ( char )) -> list ( char ) ;
dec i2c : num -> char;
dec i2s : num -> list(char);
dec beer : num -> list(char);
--- app ( nil , w )
<= w ;
--- app (( a :: v ), w )
<=( a :: app ( v , w )) ;
--- i2c(0) <= '0';
--- i2c(1) <= '1';
--- i2c(2) <= '2';
--- i2c(3) <= '3';
--- i2c(4) <= '4';
--- i2c(5) <= '5';
--- i2c(6) <= '6';
--- i2c(7) <= '7';
--- i2c(8) <= '8';
--- i2c(9) <= '9';
--- i2s(x) <= if x < 10 then [i2c(x)] else
app(i2s(x div 10), i2s( x mod 10));
--- beer(x) <= if x = 1 then app( i2s(x),
" bottle of beer. No more beer on the wall.")
else app( app( app( app( app(
i2s(x),
" bottles of beer on the wall, "),
i2s(x)),
" bottles of beer. "),
"Take one down, pass it around. "),
beer(y))
where y== x-1;
HQ9+
Huginn
#! /bin/sh
exec huginn --no-argv -E "${0}" "${@}"
#! huginn
import Algorithms as algo;
main() {
x = "{} bottle{} of beer on the wall,\n"
"{} bottle{} of beer.\n"
"Take one down, pass it around,\n"
"{} bottle{} of beer on the wall.\n\n";
for ( n : algo.range( 99, 0, -1 ) ) {
bot = n > 0 ? n : "No";
plu = n != 1 ? "s" : "";
print( x.format( bot, plu, bot, plu, n > 1 ? n - 1 : "No", n != 2 ? "s" : "" ) );
}
print(
"No bottles of beer on the wall,\n"
"No bottles of beer.\n"
"Go to the store, buy some more,\n"
"99 bottles of beer on the wall.\n"
);
return ( 0 );
}
HyperTalk
El código es de Eric Carlson eric@bungdabba.com
on BeerSong99
BottlesOfBeer 99
end BeerSong99
on OutputBeerLyric beerString
if ( beerString is "<reset>" ) then
put empty into cd fld "beer song"
else
put beerString & return after cd fld "beer song"
end if
end OutputBeerLyric
on BottlesOfBeer bottleCount
put bottleCount into initialCount
OutputBeerLyric "<reset>"
repeat until ( bottleCount < 1 )
set cursor to busy -- let 'em know this might take a while
put BottleString(bottleCount) into currentString
OutputBeerLyric currentString && "of beer on the wall,"
OutputBeerLyric currentString && "of beer."
OutputBeerLyric "Take one down, and pass it around,"
subtract one from bottleCount
OutputBeerLyric BottleString(bottleCount) && "of beer on the wall." & return
end repeat
OutputBeerLyric "Go to the store and buy some more..."
OutputBeerLyric initialCount & " bottles of beer on the wall."
end BottlesOfBeer
function BottleString bottleCount
if ( bottleCount is 1 ) then
return "1 bottle"
else if ( bottleCount is 0 ) then
return "no more bottles"
else
return bottleCount && "bottles"
end if
end BottleString
Icon and Unicon
The default is 99 bottles, but you can change this on the command line for really long trips...
IDL
Pro bottles
for i=1,99 do begin
print, 100-i, " bottles of beer on the wall.", 100-i, $
" bottles of beer.", " Take one down, pass it around," , $
99-i, " bottles of beer on the wall."
endfor
End
Since in IDL "FOR"-loops are the embodiment of pure evil (see http://www.idlcoyote.com/tips/forloops.html and http://www.idlcoyote.com/tips/forloops2.html) there is also a loop free IDL way:
Pro bottles_noloop
b=(reverse(shift(sindgen(100),-1)))[1:99]
b2=reverse(sindgen(99))
wallT=replicate(' bottles of beer on the wall.', 100)
wallT2=replicate(' bottles of beer.', 100)
takeT=replicate('Take one down, pass it around,', 100)
print, b+wallT+string(10B)+b+wallT2+string(10B)+takeT+string(10B)+b2+wallT+string(10B)
End
I found the above example very helpful but overdone. This is a more simple version:
Pro bottles_noloop2
n_bottles=99
b1 = reverse(SINDGEN(n_bottles,START=1))
b2= reverse(SINDGEN(n_bottles))
wallT=replicate(' bottles of beer on the wall.', n_bottles)
wallT2=replicate(' bottles of beer.', n_bottles)
takeT=replicate('Take one down, pass it around,', n_bottles)
print, b1+wallT+string(10B)+b1+wallT2+string(10B)+takeT+string(10B)+b2+wallT+string(10B)
End
Idris
beerSong : Fin 100 -> String
beerSong x = verses x where
bottlesOfBeer : Fin n -> String
bottlesOfBeer fZ = "No more bottles of beer"
bottlesOfBeer (fS fZ) = "1 bottle of beer"
bottlesOfBeer k = (show (finToInteger k)) ++ " bottles of beer"
verse : Fin n -> String
verse fZ = ""
verse (fS n) =
(bottlesOfBeer (fS n)) ++ " on the wall,\n" ++
(bottlesOfBeer (fS n)) ++ "\n" ++
"Take one down, pass it around\n" ++
(bottlesOfBeer n) ++ " on the wall\n"
verses : Fin n -> String
verses fZ = ""
verses (fS n) = (verse (fS n)) ++ (verses n)
Inform 6
[ Bottles i;
if(i == 1) return "bottle";
return "bottles";
];
[ Beer i;
print i, " ", (string) Bottles(i), " of beer on the wall^";
print i, " ", (string) Bottles(i), " of beer^";
print "Take one down, pass it around^";
i--;
print i, " ", (string) Bottles(i), " of beer on the wall^^";
if(i ~= 0) Beer(i);
];
[ Main;
Beer(99);
];
Inform 7
Programmatic solution
Beer Hall is a room.
When play begins:
repeat with iteration running from 1 to 99:
let N be 100 - iteration;
say "[N] bottle[s] of beer on the wall[line break]";
say "[N] bottle[s] of beer[line break]";
say "Take one down, pass it around[line break]";
say "[N - 1] bottle[s] of beer on the wall[paragraph break]";
end the story.
World model solution
This solution uses in-game objects to represent the wall and the bottles.
Beer Hall is a room.
The plural of bottle of beer is bottles of beer. A bottle of beer is a kind of thing.
The wall is a scenery supporter in Beer Hall. 99 bottles of beer are on the wall.
When play begins:
while something is on the wall:
say "[what's on the wall] on the wall[line break]";
say "[what's on the wall][line break]";
say "Take one down, pass it around[line break]";
remove a random thing on the wall from play;
say "[what's on the wall] on the wall[paragraph break]";
end the story.
To say what's on the wall:
if more than one thing is on the wall, say list of things on the wall;
otherwise say "[number of things on the wall in words] bottle[s] of beer".
Io
bottles := method(i,
if(i==0, return "no more bottles of beer")
if(i==1, return "1 bottle of beer")
"" .. i .. " bottles of beer"
)
for(i, 99, 1, -1,
write(
bottles(i), " on the wall, ",
bottles(i), ",\n",
"take one down, pass it around,\n",
bottles(i - 1), " on the wall.\n\n"
)
)
Intercal
PLEASE DO ,10 <- #1
PLEASE DO ,10SUB#1 <- #176
PLEASE DO ,11 <- #30
PLEASE DO ,11SUB#1 <- #76
DO ,11SUB#2 <- #190
DO ,11SUB#3 <- #80
DO ,11SUB#4 <- #200
PLEASE DO ,11SUB#5 <- #256
DO ,11SUB#6 <- #248
DO ,11SUB#7 <- #144
DO ,11SUB#8 <- #216
PLEASE DO ,11SUB#9 <- #202
DO ,11SUB#10 <- #14
DO ,11SUB#11 <- #144
DO ,11SUB#12 <- #98
PLEASE DO ,11SUB#13 <- #190
DO ,11SUB#14 <- #160
DO ,11SUB#15 <- #256
DO ,11SUB#16 <- #88
PLEASE DO ,11SUB#17 <- #74
DO ,11SUB#18 <- #14
DO ,11SUB#19 <- #128
DO ,11SUB#20 <- #114
PLEASE DO ,11SUB#21 <- #214
DO ,11SUB#22 <- #24
DO ,11SUB#23 <- #112
DO ,11SUB#24 <- #162
PLEASE DO ,11SUB#25 <- #22
DO ,11SUB#26 <- #104
DO ,11SUB#27 <- #80
DO ,11SUB#28 <- #256
PLEASE DO ,11SUB#29 <- #2
DO ,11SUB#30 <- #228
PLEASE DO ,12 <- #49
PLEASE DO ,12SUB#1 <- #76
DO ,12SUB#2 <- #190
DO ,12SUB#3 <- #80
DO ,12SUB#4 <- #200
PLEASE DO ,12SUB#5 <- #256
DO ,12SUB#6 <- #248
DO ,12SUB#7 <- #144
DO ,12SUB#8 <- #216
PLEASE DO ,12SUB#9 <- #202
DO ,12SUB#10 <- #14
DO ,12SUB#11 <- #144
DO ,12SUB#12 <- #98
PLEASE DO ,12SUB#13 <- #190
DO ,12SUB#14 <- #160
DO ,12SUB#15 <- #256
DO ,12SUB#16 <- #88
PLEASE DO ,12SUB#17 <- #218
DO ,12SUB#18 <- #36
DO ,12SUB#19 <- #38
DO ,12SUB#20 <- #164
PLEASE DO ,12SUB#21 <- #176
DO ,12SUB#22 <- #48
DO ,12SUB#23 <- #162
DO ,12SUB#24 <- #14
PLEASE DO ,12SUB#25 <- #128
DO ,12SUB#26 <- #208
DO ,12SUB#27 <- #162
DO ,12SUB#28 <- #222
PLEASE DO ,12SUB#29 <- #48
DO ,12SUB#30 <- #8
DO ,12SUB#31 <- #120
DO ,12SUB#32 <- #66
PLEASE DO ,12SUB#33 <- #48
DO ,12SUB#34 <- #246
DO ,12SUB#35 <- #136
DO ,12SUB#36 <- #184
PLEASE DO ,12SUB#37 <- #256
DO ,12SUB#38 <- #202
DO ,12SUB#39 <- #110
DO ,12SUB#40 <- #104
PLEASE DO ,12SUB#41 <- #42
DO ,12SUB#42 <- #126
DO ,12SUB#43 <- #56
DO ,12SUB#44 <- #88
PLEASE DO ,12SUB#45 <- #72
DO ,12SUB#46 <- #56
DO ,12SUB#47 <- #80
DO ,12SUB#48 <- #242
PLEASE DO ,12SUB#49 <- #228
PLEASE DO ,13 <- #31
PLEASE DO ,13SUB#1 <- #76
DO ,13SUB#2 <- #190
DO ,13SUB#3 <- #80
DO ,13SUB#4 <- #200
PLEASE DO ,13SUB#5 <- #256
DO ,13SUB#6 <- #248
DO ,13SUB#7 <- #144
DO ,13SUB#8 <- #216
PLEASE DO ,13SUB#9 <- #202
DO ,13SUB#10 <- #14
DO ,13SUB#11 <- #144
DO ,13SUB#12 <- #98
PLEASE DO ,13SUB#13 <- #190
DO ,13SUB#14 <- #160
DO ,13SUB#15 <- #256
DO ,13SUB#16 <- #88
PLEASE DO ,13SUB#17 <- #74
DO ,13SUB#18 <- #14
DO ,13SUB#19 <- #128
DO ,13SUB#20 <- #114
PLEASE DO ,13SUB#21 <- #214
DO ,13SUB#22 <- #24
DO ,13SUB#23 <- #112
DO ,13SUB#24 <- #162
PLEASE DO ,13SUB#25 <- #22
DO ,13SUB#26 <- #104
DO ,13SUB#27 <- #80
DO ,13SUB#28 <- #256
PLEASE DO ,13SUB#29 <- #194
DO ,13SUB#30 <- #36
DO ,13SUB#31 <- #256
PLEASE DO ,20 <- #10
PLEASE DO ,20 SUB #1 <- #76
DO ,20 SUB #2 <- #196
DO ,20 SUB #3 <- #4
DO ,20 SUB #4 <- #132
PLEASE DO ,20 SUB #5 <- #36
DO ,20 SUB #6 <- #164
DO ,20 SUB #7 <- #228
DO ,20 SUB #8 <- #100
PLEASE DO ,20 SUB #9 <- #52
DO ,20 SUB #10 <- #180
PLEASE DO ,21 <- #10 BY #10
PLEASE DO ,21SUB#1#1 <- #248
PLEASE DO ,21SUB#1#2 <- #120
PLEASE DO ,21SUB#1#3 <- #184
PLEASE DO ,21SUB#1#4 <- #56
PLEASE DO ,21SUB#1#5 <- #216
PLEASE DO ,21SUB#1#6 <- #88
PLEASE DO ,21SUB#1#7 <- #152
PLEASE DO ,21SUB#1#8 <- #24
PLEASE DO ,21SUB#1#9 <- #232
PLEASE DO ,21SUB#1#10 <- #104
DO ,21SUB#2#1 <- #128
DO ,21SUB#2#2 <- #256
DO ,21SUB#2#3 <- #64
DO ,21SUB#2#4 <- #192
DO ,21SUB#2#5 <- #96
DO ,21SUB#2#6 <- #224
DO ,21SUB#2#7 <- #32
DO ,21SUB#2#8 <- #160
DO ,21SUB#2#9 <- #112
DO ,21SUB#2#10 <- #240
DO ,21SUB#3#1 <- #64
DO ,21SUB#3#2 <- #192
DO ,21SUB#3#3 <- #256
DO ,21SUB#3#4 <- #128
DO ,21SUB#3#5 <- #32
DO ,21SUB#3#6 <- #160
DO ,21SUB#3#7 <- #224
DO ,21SUB#3#8 <- #96
DO ,21SUB#3#9 <- #48
DO ,21SUB#3#10 <- #176
DO ,21SUB#4#1 <- #192
DO ,21SUB#4#2 <- #64
DO ,21SUB#4#3 <- #128
DO ,21SUB#4#4 <- #256
DO ,21SUB#4#5 <- #160
DO ,21SUB#4#6 <- #32
DO ,21SUB#4#7 <- #96
DO ,21SUB#4#8 <- #224
DO ,21SUB#4#9 <- #176
DO ,21SUB#4#10 <- #48
PLEASE DO ,21SUB#5#1 <- #32
PLEASE DO ,21SUB#5#2 <- #160
PLEASE DO ,21SUB#5#3 <- #224
PLEASE DO ,21SUB#5#4 <- #96
PLEASE DO ,21SUB#5#5 <- #256
PLEASE DO ,21SUB#5#6 <- #128
PLEASE DO ,21SUB#5#7 <- #192
PLEASE DO ,21SUB#5#8 <- #64
PLEASE DO ,21SUB#5#9 <- #16
PLEASE DO ,21SUB#5#10 <- #144
DO ,21SUB#6#1 <- #160
DO ,21SUB#6#2 <- #32
DO ,21SUB#6#3 <- #96
DO ,21SUB#6#4 <- #224
DO ,21SUB#6#5 <- #128
DO ,21SUB#6#6 <- #256
DO ,21SUB#6#7 <- #64
DO ,21SUB#6#8 <- #192
DO ,21SUB#6#9 <- #144
DO ,21SUB#6#10 <- #16
DO ,21SUB#7#1 <- #96
DO ,21SUB#7#2 <- #224
DO ,21SUB#7#3 <- #32
DO ,21SUB#7#4 <- #160
DO ,21SUB#7#5 <- #64
DO ,21SUB#7#6 <- #192
DO ,21SUB#7#7 <- #256
DO ,21SUB#7#8 <- #128
DO ,21SUB#7#9 <- #80
DO ,21SUB#7#10 <- #208
DO ,21SUB#8#1 <- #224
DO ,21SUB#8#2 <- #96
DO ,21SUB#8#3 <- #160
DO ,21SUB#8#4 <- #32
DO ,21SUB#8#5 <- #192
DO ,21SUB#8#6 <- #64
DO ,21SUB#8#7 <- #128
DO ,21SUB#8#8 <- #256
DO ,21SUB#8#9 <- #208
DO ,21SUB#8#10 <- #80
PLEASE DO ,21SUB#9#1 <- #16
PLEASE DO ,21SUB#9#2 <- #144
PLEASE DO ,21SUB#9#3 <- #208
PLEASE DO ,21SUB#9#4 <- #80
PLEASE DO ,21SUB#9#5 <- #240
PLEASE DO ,21SUB#9#6 <- #112
PLEASE DO ,21SUB#9#7 <- #176
PLEASE DO ,21SUB#9#8 <- #48
PLEASE DO ,21SUB#9#9 <- #256
PLEASE DO ,21SUB#9#10 <- #128
DO ,21SUB#10#1 <- #144
DO ,21SUB#10#2 <- #16
DO ,21SUB#10#3 <- #80
DO ,21SUB#10#4 <- #208
DO ,21SUB#10#5 <- #112
DO ,21SUB#10#6 <- #240
DO ,21SUB#10#7 <- #48
DO ,21SUB#10#8 <- #176
DO ,21SUB#10#9 <- #128
DO ,21SUB#10#10 <- #256
PLEASE DO ,22 <- #10
PLEASE DO ,22 SUB #1 <- #8
DO ,22 SUB #2 <- #136
DO ,22 SUB #3 <- #72
DO ,22 SUB #4 <- #200
PLEASE DO ,22 SUB #5 <- #40
DO ,22 SUB #6 <- #168
DO ,22 SUB #7 <- #104
DO ,22 SUB #8 <- #232
PLEASE DO ,22 SUB #9 <- #24
DO ,22 SUB #10 <- #152
DO .10 <- #9
DO .11 <- #9
PLEASE DO ,10 <- #1
PLEASE DO ,10SUB#1 <- #176
DO READ OUT ,10
DO COME FROM (999)
DO (500) NEXT
PLEASE DO ,11SUB#1 <- .5
DO READ OUT ,11
DO (500) NEXT
DO ,12SUB#1 <- .5
PLEASE DO READ OUT ,12
PLEASE DO .6 <- '?"!10~.10'~#1"$#1'~#3
DO (50) NEXT
PLEASE DO .7 <- '?"!11~.11'~#1"$#1'~#3
DO (70) NEXT
DO .2 <- #1
DO .1 <- .11
PLEASE DO (1010) NEXT
DO .11 <- .3
DO (600) NEXT
DO (101) NEXT
(70) DO (71) NEXT
DO .11 <- #9
DO .2 <- #1
PLEASE DO .1 <- .10
DO (1010) NEXT
DO .10 <- .3
DO (600) NEXT
DO (101) NEXT
(71) DO RESUME .7
(50) DO (51) NEXT
PLEASE DO FORGET #1
DO .2 <- #1
DO .1 <- .11
PLEASE DO (1010) NEXT
DO .11 <- .3
DO (600) NEXT
PLEASE DO .7 <- '?"!11~.11'~#1"$#1'~#3
DO (80) NEXT
DO (101) NEXT
(80) DO (81) NEXT
DO GIVE UP
(81) DO RESUME .7
(51) DO RESUME .6
(101) DO FORGET #1
(999) DO FORGET #1
(600) DO (500) NEXT
DO ,13SUB#1 <- .5
DO READ OUT ,13
DO RESUME #1
(500) DO ,30 <- #1
DO .1 <- .10
DO (1020) NEXT
PLEASE DO ,30SUB#1 <- ,20SUB.1
DO READ OUT ,30
DO .3 <- .1
DO .1 <- .11
DO (1020) NEXT
PLEASE DO ,30SUB#1 <- ,21SUB .3 .1
DO READ OUT ,30
DO .5 <- ,22SUB.1
PLEASE DO RESUME #1
Ioke
bottle = method(i,
case(i,
0, "no more bottles of beer",
1, "1 bottle of beer",
"#{i} bottles of beer"))
(99..1) each(i,
"#{bottle(i)} on the wall, " println
"take one down, pass it around," println
"#{bottle(i - 1)} on the wall.\n" println
)
J
As posted at the J wiki
bob =: ": , ' bottle' , (1 = ]) }. 's of beer'"_
bobw=: bob , ' on the wall'"_
beer=: bobw , ', ' , bob , '; take one down and pass it around, ' , bobw@<:
beer"0 >:i.-99
- Output:
99 bottles of beer on the wall, 99 bottles of beer; take one down and pass it around, 98 bottles of beer on the wall 98 bottles of beer on the wall, 98 bottles of beer; take one down and pass it around, 97 bottles of beer on the wall ... 3 bottles of beer on the wall, 3 bottles of beer; take one down and pass it around, 2 bottles of beer on the wall 2 bottles of beer on the wall, 2 bottles of beer; take one down and pass it around, 1 bottle of beer on the wall 1 bottle of beer on the wall, 1 bottle of beer; take one down and pass it around, 0 bottles of beer on the wall
Jakt
fn bottle_string(bottle_count: i64) throws -> String => match bottle_count {
0 => "No more bottles"
1 => "1 bottle"
else => format("{} bottles", bottle_count)
}
fn main() {
mut bottle_count = 99
while bottle_count > 0 {
println("{} of beer on the wall", bottle_string(bottle_count))
println("{} of beer", bottle_string(bottle_count))
println("Take one down, pass it around")
bottle_count--
println("{} of beer on the wall", bottle_string(bottle_count))
if bottle_count > 0 {
println("")
}
}
}
Janet
(defn bottles [n]
(match n
0 "No more bottles"
1 "1 bottle"
_ (string n " bottles")))
(loop [i :down [99 0]]
(print
(bottles i) " of beer on the wall\n"
(bottles i) " of beer\nTake one down, pass it around\n"
(bottles (- i 1)) " of beer on the wall\n\n"))
Java
Console
MessageFormat's choice operator is used to properly format plurals.
import java.text.MessageFormat;
public class Beer {
static String bottles(int n) {
return MessageFormat.format("{0,choice,0#No more bottles|1#One bottle|2#{0} bottles} of beer", n);
}
public static void main(String[] args) {
String bottles = bottles(99);
for (int n = 99; n > 0; ) {
System.out.println(bottles + " on the wall");
System.out.println(bottles);
System.out.println("Take one down, pass it around");
bottles = bottles(--n);
System.out.println(bottles + " on the wall");
System.out.println();
}
}
}
Optimized for speed and few I/O operations
public class Beer {
public static void main(String[] args) {
int bottles = 99;
StringBuilder sb = new StringBuilder();
String verse1 = " bottles of beer on the wall\n";
String verse2 = " bottles of beer.\nTake one down, pass it around,\n";
String verse3 = "Better go to the store and buy some more.";
while (bottles > 0)
sb.append(bottles).append(verse1).append(bottles).append(verse2).append(--bottles).append(verse1).append("\n");
System.out.println(sb.append(verse3));
}
}
Recursive
public class Beer {
public static void main(String args[]) {
song(99);
}
public static void song(int bottles) {
if (bottles >= 0) {
if (bottles > 1)
System.out.println(bottles + " bottles of beer on the wall\n" + bottles + " bottles of beer\nTake one down, pass it around\n" + (bottles - 1) + " bottles of beer on the wall.\n");
else if (bottles == 1)
System.out.println(bottles + " bottle of beer on the wall\n" + bottles + " bottle of beer\nTake one down, pass it around\n" + (bottles - 1) + " bottles of beer on the wall.\n");
else
System.out.println(bottles + " bottles of beer on the wall\n" + bottles + " bottles of beer\nBetter go to the store and buy some more!");
song(bottles - 1);
}
}
}
An object-oriented solution
See: 99 Bottles of Beer/Java/Object Oriented
GUI
This version requires user interaction. The first two lines are shown in a text area on a window. The third line is shown on a button which you need to click to see the fourth line in a message box. The numbers update and the process repeats until "0 bottles of beer on the wall" is shown in a message box, when the program ends.
import java.awt.BorderLayout;
import java.awt.event.ActionEvent;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JOptionPane;
import javax.swing.JTextArea;
public class Beer extends JFrame {
private int x;
private JTextArea text;
public static void main(String[] args) {
new Beer().setVisible(true);
}
public Beer() {
x = 99;
JButton take = new JButton("Take one down, pass it around");
take.addActionListener(this::onTakeClick);
text = new JTextArea(4, 30);
text.setText(x + " bottles of beer on the wall\n" + x + " bottles of beer");
text.setEditable(false);
setLayout(new BorderLayout());
add(text, BorderLayout.CENTER);
add(take, BorderLayout.PAGE_END);
pack();
setLocationRelativeTo(null);
setDefaultCloseOperation(JFrame.DISPOSE_ON_CLOSE);
}
private void onTakeClick(ActionEvent event) {
JOptionPane.showMessageDialog(null, --x + " bottles of beer on the wall");
text.setText(x + " bottles of beer on the wall\n" + x + " bottles of beer");
if (x == 0) {
dispose();
}
}
}
JavaScript
ES3-5
var beer = 99;
while (beer > 0) {
var verse = [
beer + " bottles of beer on the wall,",
beer + " bottles of beer!",
"Take one down, pass it around",
(beer - 1) + " bottles of beer on the wall!"
].join("\n");
console.log(verse);
beer--;
}
ES6
let beer = 99;
while (beer > 0) {
let verse = `${beer} bottles of beer on the wall,
${beer} bottles of beer!
Take one down, pass it around
${beer-1} bottles of beer on the wall`;
console.log(verse);
beer--;
}
Functional / Recursive
var bottles = 99;
var songTemplate = "{X} bottles of beer on the wall \n" +
"{X} bottles of beer \n"+
"Take one down, pass it around \n"+
"{X-1} bottles of beer on the wall \n";
function song(x, txt) {
return txt.replace(/\{X\}/gi, x).replace(/\{X-1\}/gi, x-1) + (x > 1 ? song(x-1, txt) : "");
}
console.log(song(bottles, songTemplate));
Other Examples
More skilled solution "one-liner" with grammar check
Comment: This being a "one-liner" is arguable. The author has chosen not to put a line break after the declaration of the beer
variable. By using the authors definition, most of the other solutions could pass as a "one-liner".
// Line breaks are in HTML
var beer; while ((beer = typeof beer === "undefined" ? 99 : beer) > 0) document.write( beer + " bottle" + (beer != 1 ? "s" : "") + " of beer on the wall<br>" + beer + " bottle" + (beer != 1 ? "s" : "") + " of beer<br>Take one down, pass it around<br>" + (--beer) + " bottle" + (beer != 1 ? "s" : "") + " of beer on the wall<br>" );
Legitimate "one-liner" with grammar check, using declarative methods.
Array.from(Array(100).keys()).splice(1).reverse().forEach(n => console.log(`${n} bottle${n !== 1 ? 's' : ''} of beer on the wall\n${n} bottle${n !== 1 ? 's' : ''} of beer\nTake one down, pass it around\n${n - 1} bottle${n - 1 !== 1 ? 's' : ''} of beer on the wall\n\n`));
Object Oriented
function Bottles(count) {
this.count = count || 99;
}
Bottles.prototype.take = function() {
var verse = [
this.count + " bottles of beer on the wall,",
this.count + " bottles of beer!",
"Take one down, pass it around",
(this.count - 1) + " bottles of beer on the wall!"
].join("\n");
console.log(verse);
this.count--;
};
Bottles.prototype.sing = function() {
while (this.count) {
this.take();
}
};
var bar = new Bottles(99);
bar.sing();
An alternative version:
function bottleSong(n) {
if (!isFinite(Number(n)) || n == 0) n = 100;
var a = '%% bottles of beer',
b = ' on the wall',
c = 'Take one down, pass it around',
r = '<br>'
p = document.createElement('p'),
s = [],
re = /%%/g;
while(n) {
s.push((a+b+r+a+r+c+r).replace(re, n) + (a+b).replace(re, --n));
}
p.innerHTML = s.join(r+r);
document.body.appendChild(p);
}
window.onload = bottleSong;
Joy
LIBRA
_beerlib == true;
HIDE
beer == "of beer " putchars;
wall == "on the wall" putchars;
take1 == "Take one down and pass it around, " putchars;
dup3 == dup dup dup;
comma == ", " putchars;
period == ". " putchars;
bottles == [small]
[[null] [pop "no more bottles " putchars] [put "bottle " putchars] ifte]
[put "bottles " putchars] ifte;
sing-verse == dup3 bottles beer wall comma
bottles beer ".\n" putchars
take1 pred bottles beer wall period newline newline;
sing-verse-0 == "No more bottles of beer on the wall, no more bottles of beer\n" putchars
"Go to the store and buy some more, " putchars
99 bottles pop beer wall period newline
IN
(* n -- *)
sing-verses == [null]
[sing-verse-0]
[sing-verse pred] tailrec
END.
99 sing-verses.
jq
Minimalist:
99
| (. - range(0;.+1) )
| "
\(.) bottles of beer on the wall
\(.) bottles of beer
Take one down, pass it around
\(.) bottles of beer on the wall"
- Output:
$ jq -n -r -f 99_bottles.jq
...
2 bottles of beer on the wall
2 bottles of beer
Take one down, pass it around
2 bottles of beer on the wall
1 bottles of beer on the wall
1 bottles of beer
Take one down, pass it around
1 bottles of beer on the wall
0 bottles of beer on the wall
0 bottles of beer
Take one down, pass it around
0 bottles of beer on the wall
Variant:
def sing:
def s: if . == 1 then "" else "s" end;
def bottles:
if . == 0 then "No more"
else "\(.)"
end + " bottle\(s)";
(. - range(0;.+1) )
| "
\(bottles) of beer on the wall
\(bottles) of beer
Take one down, pass it around
\(bottles) of beer on the wall."
;
$bottles | tonumber | sing
- Output:
$ jq -r --arg bottles 99 -f 99_bottles_variant.jq
...
2 bottles of beer on the wall
2 bottles of beer
Take one down, pass it around
2 bottles of beer on the wall.
1 bottle of beer on the wall
1 bottle of beer
Take one down, pass it around
1 bottle of beer on the wall.
No more bottles of beer on the wall
No more bottles of beer
Take one down, pass it around
No more bottles of beer on the wall.
Jsish
/* 99 Bottles, in Jsish */
function plural(n:number):string { return (bottles == 1) ? "" : "s"; }
function no(n:number):string { return (bottles == 0) ? "No" : n.toString(); }
var bottles = 99;
do {
printf("%d bottle%s of beer on the wall\n", bottles, plural(bottles));
printf("%d bottle%s of beer\n", bottles, plural(bottles));
puts("Take one down, pass it around");
bottles--;
printf("%s bottle%s of beer on the wall\n\n", no(bottles), plural(bottles));
} while (bottles > 0);
Julia
one-liner
for i = 99:-1:1 print("\n$i bottles of beer on the wall\n$i bottles of beer\nTake one down, pass it around\n$(i-1) bottles of beer on the wall\n") end
another solution, handling grammar cases "No more bottles", "1 bottle", "<n> bottles"
bottles(n) = n==0 ? "No more bottles" :
n==1 ? "1 bottle" :
"$n bottles"
for n = 99:-1:1
println("""
$(bottles(n)) of beer on the wall
$(bottles(n)) of beer
Take one down, pass it around
$(bottles(n-1)) of beer on the wall
""")
end
shorter, but more cryptic, version of the previous `bottles` function
bottles(n) = "$(n==0 ? "No more" : n) bottle$(n==1 ? "" : "s")"
K
`0:\:{x[z],y,a,x[z],a,"Take one down, pass it around",a,x[z-1],y,a,a:"\n"}[{($x)," bottle",:[x=1;"";"s"]," of beer"};" on the wall"]'|1_!100
Kabap
// Loop that spits lyrics to "99 Bottles of Beer"
$n = 99;
$out = "";
:loop;
$out = $out << $n << " bottles of beer on the wall, " << $n << " bottles of beer. Take one down, pass it around, " << $n - 1 << " bottles of beer on the wall… ";
$n = $n - 1;
if $n > 0;
goto loop;
return = $out;
Kitten
99 bottles_of_beer_on_the_wall
define bottles_of_beer_on_the_wall (Int32 -> +IO):
-> n;
n th_verse
if (n > 1): (n - 1) bottles_of_beer_on_the_wall
define th_verse (Int32 -> +IO):
-> n;
n bottles_of_beer on_the_wall say
n bottles_of_beer say
take_one_down_pass_it_around say
(n - 1) bottles_of_beer on_the_wall say
newline
define bottles_of_beer (Int32 -> List<Char>):
bottles " of beer" cat
define on_the_wall (List<Char> -> List<Char>):
" on the wall" cat
define take_one_down_pass_it_around (-> List<Char>):
"take one down, pass it around"
define bottles (Int32 -> List<Char>):
-> n;
if (n = 0):
"no more bottles"
elif (n = 1):
"one bottle"
else:
n show " bottles" cat
Klingphix
include ..\Utilitys.tlhy
:bottles
dup 0 ==
(
["no more bottles of beer"]
[ dup 1 ==
(
["1 bottle of beer"]
[dup tostr " bottles of beer" chain]
) if
]
) if
;
( 99 1 -1 )
[ bottles print " on the wall," ?
bottles "," chain ?
"take one down, pass it around," ?
1 - bottles print " on the wall." ? nl
drop] for
" " input
Klong
bottles::{:[x=1;"bottle";"bottles"]}
itone::{:[x=1;"it";"one"]}
numno::{:[x=0;"no";x]}
drink::{.d(numno(x));
.d(" ");
.d(bottles(x));
.p(" of beer on the wall");
.d(numno(x));
.d(" ");
.d(bottles(x));
.p(" of beer");
.d("take ");
.d(itone(x));
.p(" down and pass it round");
.d(numno(x-1));
.d(" ");
.d(bottles(x-1));
.p(" of beer on the wall");.p("")}
drink'1+|!99
Kotlin
fun main(args: Array<String>) {
for (i in 99.downTo(1)) {
println("$i bottles of beer on the wall")
println("$i bottles of beer")
println("Take one down, pass it around")
}
println("No more bottles of beer on the wall!")
}
LabVIEW
Lambda Prolog
The signature file:
sig bottles.
type println string -> o.
type round int -> o.
type bottles_song int -> o.
The module file:
module bottles.
println Str :- print Str, print "\n".
round N :- M is N - 1,
NStr is int_to_string N,
MStr is int_to_string M,
BOB = " bottles of beer ",
Line1 is NStr ^ BOB ^ "on the wall",
Line2 is NStr ^ BOB,
Line3 is "take one down, pass it around",
Line4 is MStr ^ BOB ^ "on the wall",
println Line1,
println Line2,
println Line3,
println Line4.
bottles_song 0.
bottles_song N :- N > 0,
round N,
M is N - 1,
bottles_song M.
Then we produce the desired output by setting the system to solve for this goal:
[bottles] ?- bottles_song 99.
Lambdatalk
{def beer
{lambda {:i}
{br}:i bottles of beer on the wall
{br}:i bottles of beer
{br}Take one down, pass it around
{br}{- :i 1} bottles of beer on the wall
{br}
}}
{S.map beer {S.serie 99 98 -1}}
...
{S.map beer {S.serie 2 1 -1}}
->
99 bottles of beer on the wall
99 bottles of beer
Take one down, pass it around
98 bottles of beer on the wall
98 bottles of beer on the wall
98 bottles of beer
Take one down, pass it around
97 bottles of beer on the wall
...
2 bottles of beer on the wall
2 bottles of beer
Take one down, pass it around
1 bottles of beer on the wall
1 bottles of beer on the wall
1 bottles of beer
Take one down, pass it around
0 bottles of beer on the wall
Lang
$i = 99
until($i == 0) {
fn.println($i bottles of beer on the wall)
fn.println($i bottles of beer)
fn.println(Take one down, pass it around)
$i -= 1
if($i > 0) {
fn.println($i bottles of beer)
fn.println()
}else {
fn.println(No more bottles of beer on the wall)
}
}
lang5
: ~ 2 compress "" join ;
: verses(*)
dup " bottles of beer on the wall\n" ~ .
dup " bottles of beer\n" ~ .
"Take one down, pass it around\n" .
1 - " bottles of beer on the wall\n\n" ~ .
;
99 iota 1 + reverse verses
Lasso
Simple loop
local(
beer = 99,
song = ''
)
while(#beer > 0) => {
#song->append(
#beer + ' bottles of beer on the wall\n' +
#beer + ' bottles of beer\n' +
'Take one down, pass it around\n' +
(#beer-1) + ' bottles of beer on the wall\n\n'
)
#beer--
}
#song
Query Expression
(with beer in 99 to 1 by -1 select
#beer + ' bottles of beer on the wall' +
#beer + ' bottles of beer\n' +
'Take one down, pass it around\n' +
--#beer + ' bottles of beer on the wall\n'
)->join('\n')
Query Expression with Autocollect
// this example adds an "s" to bottle until there is only 1 bottle left on the wall
local(s = 's')
with n in 99 to 1 by -1 do {^
#n + ' bottle' + #s + ' of beer on the wall,<br>'
#n + ' bottle' + #s + ' of beer,<br>'
#n = #n - 1
#s = (#n != 1 ? 's' | '')
'Take one down, pass it around,<br>'
#n + ' bottle' + #s + ' of beer on the wall.<br><br>'
^}
LaTeX
Recursive
\documentclass{minimal}
\newcounter{beer}
\newcommand{\verses}[1]{
\setcounter{beer}{#1}
\par\noindent
\arabic{beer} bottles of beer on the wall,\\
\arabic{beer} bottles of beer!\\
Take one down, pass it around---\\
\addtocounter{beer}{-1}
\arabic{beer} bottles of beer on the wall!\\
\ifnum#1>0
\verses{\value{beer}}
\fi
}
\begin{document}
\verses{99}
\end{document}
Iterative
The \loop macro is tail-recursive (Knuth 1984, page 219). Just for fun, this version uses Roman numerals.
\documentclass{minimal}
\newcounter{beer}
\newcounter{showC}
\newcommand{\verses}[1]{
\setcounter{beer}{#1}
\loop
\par\noindent
\Roman{beer} bottles of beer on the wall,\\
\Roman{beer} bottles of beer!\\
Take one down, pass it around---\\
\addtocounter{beer}{-1}
% Romans didn't know how to write zero ;-)
\ifnum\value{beer}=0 ZERO \else\Roman{beer} \fi
bottles of beer on the wall!\\
\ifnum\value{beer}>0
\repeat
}
\begin{document}
\verses{99}
\end{document}
References
- Knuth, Donald E. (1984). The TeXbook, Addison Wesley.
LDPL
DATA:
bottles-in-the-wall is number
plural is text
PROCEDURE:
store 99 in bottles-in-the-wall
sub-procedure check-plural
if bottles-in-the-wall is not equal to 1 then
store "s" in plural
else
store "" in plural
end if
end sub-procedure
while bottles-in-the-wall is greater than 0 do
call sub-procedure check-plural
display bottles-in-the-wall " bottle" plural " of beer on the wall," crlf
display bottles-in-the-wall " bottle" plural " of beer." crlf
display "Take one down, pass it around," crlf
subtract 1 from bottles-in-the-wall in bottles-in-the-wall
call sub-procedure check-plural
if bottles-in-the-wall is greater than 0 then
display bottles-in-the-wall " bottle" plural " of beer on the wall." crlf crlf
else
display "No bottles of beer on the wall." crlf
end if
repeat
Lhogho
to bottle :i
if :i = 0 [output "|No more bottles of beer|]
if :i = 1 [output "|One bottle of beer|]
output word :i "| bottles of beer|
end
to it_one :n
if :n = 1 [output "it][output "one]
end
to verse :i
(print bottle :i "| on the wall,|)
(print word bottle :i ".)
(print "Take it_one :i "|down, pass it round|)
(print bottle :i - 1 "| on the wall.|)
print
end
to sing :i
if :i = 0
[
print "|No more bottles of beer on the wall,
No more bottles of beer.
Go to the store and buy some more.
99 bottles of beer on the wall.|
stop
]
verse :i
sing :i - 1
end
;Using it:
sing 99
Limbo
implement Beer;
include "sys.m";
include "draw.m";
sys: Sys;
Beer : module
{
init : fn(ctxt : ref Draw->Context, args : list of string);
};
init (ctxt: ref Draw->Context, args: list of string)
{
sys = load Sys Sys->PATH;
beers := 99;
for (; beers > 1; --beers) {
sys->print("%d bottles of beer on the wall\n", beers);
sys->print("%d bottles of beer\n", beers);
sys->print("Take one down, pass it around,\n");
sys->print("%d bottles of beer on the wall\n\n", beers-1);
};
sys->print("1 bottle of beer on the wall\n1 bottle of beer\n");
sys->print("Take it down, pass it around\nand nothing is left!\n\n");
}
Lingo
repeat with i = 99 down to 2
put i & " bottles of beer on the wall"
put i & " bottles of beer"
put "Take one down, pass it around"
put (i-1) & " bottles of beer on the wall"
put
end repeat
put "1 bottle of beer on the wall"
put "1 bottle of beer"
put "Take one down, pass it around"
put "No more bottles of beer on the wall"
put
put "No more bottles of beer on the wall"
put "No more bottles of beer"
put "Go to the store and buy some more"
put "99 bottles of beer on the wall"
Lisp
LLVM
Logo
to bottles :n
if :n = 0 [output [No more bottles]]
if :n = 1 [output [1 bottle]]
output sentence :n "bottles
end
to verse :n
print sentence bottles :n [of beer on the wall]
print sentence bottles :n [of beer]
print [Take one down, pass it around]
print sentence bottles :n-1 [of beer on the wall]
end
for [n 99 1] [verse :n (print)]
Logtalk
:- object(bottles).
:- initialization(sing(99)).
sing(0) :-
write('No more bottles of beer on the wall, no more bottles of beer.'), nl,
write('Go to the store and buy some more, 99 bottles of beer on the wall.'), nl, nl.
sing(N) :-
N > 0,
N2 is N -1,
beers(N), write(' of beer on the wall, '), beers(N), write(' of beer.'), nl,
write('Take one down and pass it around, '), beers(N2), write(' of beer on the wall.'), nl, nl,
sing(N2).
beers(0) :-
write('no more bottles').
beers(1) :-
write('1 bottle').
beers(N) :-
N > 1,
write(N), write(' bottles').
:- end_object.
LOLCODE
Lua
local bottles = 99
local function plural (bottles) if bottles == 1 then return '' end return 's' end
while bottles > 0 do
print (bottles..' bottle'..plural(bottles)..' of beer on the wall')
print (bottles..' bottle'..plural(bottles)..' of beer')
print ('Take one down, pass it around')
bottles = bottles - 1
print (bottles..' bottle'..plural(bottles)..' of beer on the wall')
print ()
end
With a numeric for-loop and string formatting:
verse = [[%i bottle%s of beer on the wall
%i bottle%s of beer
Take one down, pass it around
%i bottle%s of beer on the wall
]]
function suffix(i) return i ~= 1 and 's' or '' end
for i = 99, 1, -1 do
print(verse:format(i, suffix(i), i, suffix(i), i-1, suffix(i-1)))
end
Using Lua relational operators and multiple return values:
function bottles(i)
local s = i == 1 and "1 bottle of beer" or
i == 0 and "no more bottles of beer" or
tostring(i) .. " bottles of beer"
return s, s
end
for i = 99, 1, -1 do
print( string.format("%s on the wall,\n%s,\ntake one down, pass it around,", bottles(i)),
string.format("\n%s on the wall.\n", bottles(i-1)) )
end
Lucid
// Run luval with -s inside the lucid shell script
// The print out is a list of lines. So the output is not separated by new lines, rather
// by '[' and ']' -- I cant figure out how to do string concatenation with numbers in lucid.
// beer(N) ^ bottle(N) ^ wall ^ beer(N) ^ bottle(N) ^ pass ^ beer(N-1) ^ bottle(N-1) ^ wall
// should have worked but doesn't
[%beer(N),bottle(N),wall,beer(N),bottle(N),pass,beer(N-1),bottle(N-1),wall%]
where
N = 100 fby N - 1;
wall = if N > 0 then ` On the wall ' else eod fi;
pass = `Take one down and pass it around.';
beer(A) = if A > 0 then A else `No more' fi;
bottle(A) = if A eq 1 then `bottle of beer' else `bottles of beer' fi;
end
NATURAL
El código es de Chris Bednara
DEFINE DATA
LOCAL
01 #BOTTLES (I2)
END-DEFINE
*
FOR #BOTTLES 99 TO 2 STEP -1
IF #BOTTLES < 98
WRITE #BOTTLES ' BOTTLES OF BEER ON THE WALL'
WRITE ' '
END-IF
*
WRITE #BOTTLES ' BOTTLES OF BEER ON THE WALL'
WRITE #BOTTLES ' BOTTLES OF BEER'
WRITE 'TAKE ONE DOWN, PASS IT AROUND'
END-FOR
*
WRITE '1 BOTTLE OF BEER ON THE WALL'
WRITE ' '
WRITE '1 BOTTLE OF BEER ON THE WALL'
WRITE '1 BOTTLE OF BEER'
WRITE 'TAKE IT DOWN, PASS IT AROUND'
WRITE 'NO MORE BOTTLES OF BEER ON THE WALL'
WRITE ' '
WRITE 'NO MORE BOTTLES OF BEER ON THE WALL'
WRITE 'NO MORE BOTTLES OF BEER'
WRITE 'GO TO THE STORE AND BUY SOME MORE'
WRITE '99 BOTTLES OF BEER'
END
WRITE 'TAKE ONE DOWN, PASS IT AROUND'
*
END
M4
define(`BOTTLES', `bottles of beer')dnl
define(`BOTTLE', `bottle of beer')dnl
define(`WALL', `on the wall')dnl
define(`TAKE', `take one down, pass it around')dnl
define(`NINETEEN', `$1 ifelse(`$1',`1',BOTTLE,BOTTLES) WALL
$1 ifelse(`$1',`1',BOTTLE,BOTTLES)
ifelse(`$1',`0',,`TAKE')
ifelse(`$1',`0',,`NINETEEN(eval($1-1))')')dnl
NINETEEN(99)
MACRO-11
;
; 99 BOTTLES OF BEER
; WRITTEN BY: BILL GUNSHANNON
;
.MCALL .PRINT .EXIT
.RADIX 10
MESG1:
CNUM1: .ASCII " "
.ASCII " BOTTLES OF BEER ON THE WALL, "
CNUM2: .ASCII " "
.ASCII " BOTTLES OF BEER."<13><10>
.ASCII "TAKE ONE DOWN AND PASS IT AROUND, "
CNUM3: .ASCII " "
.ASCIZ " BOTTLES OF BEER ON THE WALL."<13><10><10>
MESG2: .ASCII " 2 BOTTLES OF BEER ON THE WALL, "
.ASCII " 2 BOTTLES OF BEER."<13><10>
.ASCII "TAKE ONE DOWN AND PASS IT AROUND, "
.ASCIZ " 1 BOTTLE OF BEER ON THE WALL."<13><10><10>
MESG3: .ASCII " 1 BOTTLE OF BEER ON THE WALL, "
.ASCII " 1 BOTTLE OF BEER."<13><10>
.ASCII "TAKE ONE DOWN AND PASS IT AROUND, "
.ASCIZ "NO MORE BOTTLES OF BEER ON THE WALL."<13><10><10>
MESG4: .ASCII "NO MORE BOTTLES OF BEER ON THE WALL, "
.ASCII "NO MORE BOTTLES OF BEER."<13><10>
.ASCII "GO TO THE STORE AND BUY SOME MORE, "
.ASCIZ "99 BOTTLES OF BEER ON THE WALL."<13><10><10>
.EVEN
COUNT1: .WORD 99 ; STARTING NUMBER OF BOTTLES
PV: .WORD 10.,1, ; POSITION VALUES FOR 2 DIGITS
START:
MOV COUNT1, R0
MOV R0, R5
DEC R5
AGAIN:
MOV #CNUM1, R1
; CONVERT NUMBER OF BOTTLES TO ASCII FOR THE FIRST FIELD
MOV R0,-(SP)
MOV R1,-(SP)
MOV R2,-(SP)
MOV R3,-(SP)
MOV R4,-(SP)
MOV R5,-(SP)
MOV #PV, R3
MOV #2, R2
A1$: MOV #-1,R4
A2$: INC R4
SUB (R3), R0
BCC A2$
ADD (R3)+, R0
ADD #48, R4
MOVB R4, (R1)+
A21$: SOB R2, A1$
; REMOVE LEADING ZERO - JUST LOOKS BETTER THAT WAY
MOV #CNUM1, R1
CMPB (R1), #48
BNE CONT1
MOVB #32, (R1)
CONT1: MOV #CNUM2, R0
; MOVE THE ASCII NUMBER TO FIELD TWO RATHER THAN COMPUTING IT AGAIN
MOVB (R1)+, (R0)+
MOVB (R1), (R0)
MOV R5, R0
MOV #CNUM3, R1
; CONVERT NUMBER OF BOTTLES TO ASCII FOR THE THIRD FIELD
MOV #PV, R3
MOV #2, R2
B1$: MOV #-1,R4
B2$: INC R4
SUB (R3), R0
BCC B2$
ADD (R3)+, R0
ADD #48, R4
MOVB R4, (R1)+
B21$: SOB R2, B1$
; REMOVE LEADING ZERO - JUST LOOKS BETTER THAT WAY
MOV #CNUM3, R1
CMPB (R1), #48
BNE CONT2
MOVB #32, (R1)
CONT2:
MOV (SP)+,R5
MOV (SP)+,R4
MOV (SP)+,R3
MOV (SP)+,R2
MOV (SP)+,R1
MOV (SP)+,R0
; HANDLE SPECIAL GRAMMER CASES
CMP R0, #2
BNE ONE
.PRINT #MESG2
BR DONE
ONE: CMP R0, #1
BNE GREATER
.PRINT #MESG3
BR DONE
GREATER:
.PRINT #MESG1
DONE:
; DECREMENT THE COUNT AND START AGAIN
MOV R5, R0
DEC R5
TST R0
BNE AGAIN
; OUT OF BEER, SEND THEM TO THE STORE
.PRINT #MESG4
; CLEAN UP AND GO BACK TO KMON
.EXIT
.END START
MAD
NORMAL MODE IS INTEGER
BOTLES = 99
VERSE WALL.(BOTLES)
BOTL.(BOTLES)
PRINT FORMAT TKDWN
BOTLES = BOTLES - 1
WALL.(BOTLES)
PRINT FORMAT EMPTY
WHENEVER BOTLES .G. 0, TRANSFER TO VERSE
INTERNAL FUNCTION(B)
ENTRY TO BOTL.
WHENEVER B .E. 1
PRINT FORMAT ONEBTL
OTHERWISE
PRINT FORMAT BBTL,B
END OF CONDITIONAL
FUNCTION RETURN
END OF FUNCTION
INTERNAL FUNCTION(B)
ENTRY TO WALL.
WHENEVER B .E. 0
PRINT FORMAT NOMORE
OR WHENEVER B .E. 1
PRINT FORMAT ONEOTW
OTHERWISE
PRINT FORMAT BBOTW,B
END OF CONDITIONAL
FUNCTION RETURN
END OF FUNCTION
VECTOR VALUES BBOTW = $I2,S1,27HBOTTLES OF BEER ON THE WALL*$
VECTOR VALUES BBTL = $I2,S1,15HBOTTLES OF BEER*$
VECTOR VALUES TKDWN = $32HTAKE ONE DOWN AND PASS IT AROUND*$
VECTOR VALUES ONEOTW = $S1,29H 1 BOTTLE OF BEER ON THE WALL*$
VECTOR VALUES ONEBTL = $S1,17H 1 BOTTLE OF BEER*$
VECTOR VALUES NOMORE = $35HNO MORE BOTTLES OF BEER ON THE WALL*$
VECTOR VALUES EMPTY = $*$
END OF PROGRAM
make
BSD make
START = 99
UP != jot - 2 `expr $(START) - 1` 1
0-bottles-of-beer: 1-bottle-of-beer
@echo No more bottles of beer on the wall!
1-bottle-of-beer: 2-bottles-of-beer
@echo One last bottle of beer on the wall!
@echo
@echo One last bottle of beer on the wall,
@echo One last bottle of beer,
@echo Take it down, pass it around.
.for COUNT in $(UP)
ONE_MORE != expr 1 + $(COUNT)
$(COUNT)-bottles-of-beer: $(ONE_MORE)-bottles-of-beer
@echo $(COUNT) bottles of beer on the wall!
@echo
@echo $(COUNT) bottles of beer on the wall,
@echo $(COUNT) bottles of beer,
@echo Take one down, pass it around.
.endfor
$(START)-bottles-of-beer:
@echo $(START) bottles of beer on the wall,
@echo $(START) bottles of beer.
@echo Take one down, pass it around.
Usage: make or make START=99
GNU make
PRED=`expr $* - 1`
1-bottles: 1-beer pass
@echo "No more bottles of beer on the wall"
%-bottles: %-beer pass
@echo "$(PRED) bottles of beer on the wall\n"
@-$(MAKE) $(PRED)-bottles
1-beer:
@echo "One bottle of beer on the wall, One bottle of beer"
%-beer:
@echo "$* bottles of beer on the wall, $* bottles of beer"
pass:
@echo "Take one down and pass it around,"
Usage: make 99-bottles
This will fork 99 make processes. You might need to raise your process limit (ulimit -p).
GNU make
Without using a shell command to decrement the counter
digits:=9 8 7 6 5 4 3 2 1 0
numbers:=$(foreach x,$(filter-out 0,$(digits)),$(foreach y,$(digits),$x$y))
numbers+=$(digits)
bottles=bottle$(if $(findstring /1/,$@),,s)
num=$(if $(findstring /0/,$@),$(empty),$(@F))
action=$(if $(findstring /0/,$@),$(buy),$(pass))
beer:=of beer
wall:=on the wall
empty:=No more
pass:=Take one down and pass it around.
buy:=Go to the store and buy some more.
# Function to generate targets for each verse of the song.
define verse
.PHONY: $1
$1: verse/$1/$1 prelude/$2/$2 $2
.PHONY: $1-bottles
$1-bottles: $1
most?=$1
endef
# Recursive function that loops through the 100 numbers.
define verses
$$(eval $$(call verse,$$(word 1,$1),$$(word 2,$1)))
$$(if $$(word 2,$1),$$(eval $$(call verses,$$(filter-out $$(word 1,$1),$1))))
endef
# Generate the targets for the 100 numbers.
$(eval $(call verses,$(numbers)))
# Main lines in the verse.
.PHONY: verse/%
verse/%:
@echo "$(num) $(bottles) $(beer) $(wall)."
@echo "$(num) $(bottles) $(beer)."
@echo "$(action)"
# Last line of a verse, which is a prelude to the next verse.
.PHONY: prelude/%
prelude/%:
@echo "$(num) $(bottles) $(beer) $(wall)."
@echo ""
# Special target for the last line of the song.
.PHONY: prelude/
prelude/:
@echo "$(most) $(bottles) $(beer) $(wall)!"
@echo ""
Usage: make or make N-bottles or make N
A version of this script with more comments and an automated test can be found on github.com.
Malbolge
Long version (a real loop version made by Hisashi Iizawa):
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M'&%I)('g}|{A!~`v<zyxwvX5srqSihgf,jiba'_^]#DZY}]?Uy<RvV8TMq4JIHGk.Dh+A@dDCB;_?>=
<|43W70/.R,+Op(L,l$#"!E%$dAyx>vu;yr8vun4rk1oh.Oe+ihgfeG]\"ZYXW{[=SRvVUTS5KoO1GFE
DhH*@?>=aA@?!=6543Wx0T4321q)(L,l*#"!E}|{z@~`|ut:xwvXnm3qjih.fe+iKg`&dcbD`YX|\>TS
RvV8NMq4POHGFEiIHG)?>=aA@?!765Y9210TuR210/.n&%$H"!~}C#z@~}v<t:xwvuWmlk1oQgfed*hJ
fed]#a`_^]\>Tx;WVUNMqQPO1GFEDhH*@?c&<;:98\65Y921U54321*)Mn&%I)(h~}|{z@a}vuts9wYo
n4rqSihg-kjLhg`&dcba`BXWVzZYXWPOs6LKJnNM/EDCg*@?cC<;_?!76Z:z870/S3s10/('K+k#"Fg%
|{A!~w=uts9wvXtmlkji/mlNdcba'e^]#a`BXW{>ZYXQuUNrRKoOHGFjJCBfFED&B;:9]=654321U543
210/.-,+k#"!E}|{Ab~}|{t:xwvXn4lk1ongfe+Lha'edF\"C_XWVUyYRQPOsS5KJnHGkKJCBf)?>=aA
#?87[;{9810T43s1*)M-,+*)i!~D$dA!~}|^;yxwvutsrT1ohg-kMcb(`_^]#DZ~AWVUTxRQPtTS5KJI
HlFEi,BA@dD&B;_?>765Yz21U54t,+*N.-&%I)('&%$dz@~}|{z\9Zpon4lkj0nmOe+iKa'edcba`_^@
VzZ<w:PONrRQPImM/EDhBA@dD=<`#?>=<;432V65432r0/.'&J*j"!~}|{z@~}|^;y[qpo5srqS0Qmf,
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xwvo5srqpih.Oedcba'Hd]\"`BX|VUy<RvVUT6qQJIHlLEiI+A@?>=aA@"8\654X87w5.R21*N.-,+k#
"F&%e{zyx>|{zsr8vXtslkji/Pfe+ihgI_^$E[Z~^]?UTxX:VUNMq4oONMLKJIHG)?>=aA@"876Z{3W7
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DCBA@">=<54X8x0T4321q)M-,+k#"F&f$#zyx>|{]s9wvonmlk1ongfedcb(feG]\[Z~^]?UyY;QuONr
RQPO1GFEDh+A@dDCBA@98\65Y9y1Uv.-,+*N.-,%Ij(!~}C#zyxw=^zsrqp6nm3qpoQmlkd*Ka`&G]\[
Z~^]\UyYX:VOs6qQJIm0k.DhHG)?cCBA#98\<|432V65.-Q+*No-&%I)('g}Cdzyxw=^zyxq7on4rTji
h.ledcba'_^$o
Maple
seq( printf( "%d %s of beer on the wall,\n%d %s of beer.\nTake one down, pass it around,\n%d %s of beer on the wall.\n\n",
i, `if`( i<>1, "bottles", "bottle" ),
i, `if`( i<>1, "bottles", "bottle" ),
i-1, `if`( i-1<>1, "bottles", "bottle") ),
i = 99..1, -1 );
Mathematica / Wolfram Language
Bottle[n_] := ToString[n] <> If[n==1," bottle"," bottles"] <> " of beer"
BottleSong[n_] := Speak[
Bottle[n] <> " on the wall," <>
Bottle[n] <>
", take one down, pass it around," <>
Bottle[n-1] <> " on the wall."
]
BottleSong /@ Range[99,1,-1]
MATLAB
function ninetyNineBottlesOfBeer()
disp( [ sprintf(['%d bottles of beer on the wall, %d bottles of beer.\n'...
'Take one down, pass it around...\n'],[(99:-1:2);(99:-1:2)])...
sprintf(['1 bottle of beer on the wall, 1 bottle of beer.\nTake'...
'one down, pass it around;\nNo more bottles of beer on the wall.']) ] );
%The end of this song makes me sad. The shelf should always have more
%beer...like college.
end
Maxima
bottles(n) := for i from n thru 1 step -1 do (
printf(true, "~d bottle~p of beer on the wall~%", i, i),
printf(true, "~d bottle~p of beer~%", i, i),
printf(true, "Take one down, pass it around~%"),
printf(true, "~d bottle~p of beer on the wall~%", i - 1, i - 1),
disp(""))$
bottles(3);
/*
3 bottles of beer on the wall
3 bottles of beer
Take one down, pass it around
2 bottles of beer on the wall
2 bottles of beer on the wall
2 bottles of beer
Take one down, pass it around
1 bottle of beer on the wall
1 bottle of beer on the wall
1 bottle of beer
Take one down, pass it around
0 bottles of beer on the wall
*/
MAXScript
escapeEnable = true
resetMaxFile #noPrompt
viewport.setType #view_top
max tool maximize
viewport.SetRenderLevel #smoothhighlights
delay = 1.6
a = text size:30
a.wirecolor = white
theMod = extrude()
addModifier a theMod
for i in 99 to 1 by -1 do -- this will iterate through 99 times use the escape key to terminate.
(
a.text = (i as string + " bottles of beer on the wall")
redrawViews()
sleep delay
a.text = (i as string + " bottles of beer")
redrawViews()
sleep delay
a.text = "Take one down, pass it around"
redrawViews()
sleep delay
a.text = ((i-1) as string + " bottles of beer on the wall")
redrawViews()
sleep delay
)
A one-line version
Since MAXscript is an expression based language (everything returns a value), it is relatively easy to write long expressions that are only one line long. the following single-line snippet (broken for clarity on the webpage) produces a grammatically correct printout of the song.
for i = 99 to 1 by -1 do (print (i as string + (if i == 1 then " bottle" else " bottles") + " of beer on the wall\n" + i as string +\
(if i == 1 then " bottle" else " bottles") + " of beer\nTake one down, pass it around\n" + (i - 1) as string + (if i - 1 == 1 then "\
bottle" else " bottles") + " of beer on the wall\n" + (if i - 1 == 0 then "\nno more beer" else "")))
MEL
// Rosetta Code problem: https://rosettacode.org/wiki/99_bottles_of_beer
// by Jjuanhdez, 10/2022
string $temp0[] , $temp1[] , $text0 , $text1;
string $theGrp = `group -em`;
for ($i = 99 ; $i > -1 ; $i--)
{
$text0 = string($i) + " bottles of beer on the wall, " + string($i) +" bottles of beer.";
$text1 = "Take one down and pass it around, " + string($i-1) +" bottles of beer on the wall.";
if ($i == 1)
{
$text0 = string($i) + " bottle of beer on the wall, " + string($i) +" bottle of beer.";
$text1 = "Take one down and pass it around, no more bottles of beer on the wall.";
}
if ($i == 0)
{
$text0 = "No more bottles of beer on the wall, no more bottles of beer. ";
$text1 = "Go to the store and buy some more, 99 bottles of beer on the wall.";
}
$temp0 = `textCurves -ch 0 -f "Times New Roman|h-13|w400|c0" -t ($text0)`;
$temp1 = `textCurves -ch 0 -f "Times New Roman|h-13|w400|c0" -t ($text1)`;
setAttr ($temp0[0] + ".ty") (($i * 8) + 3);
setAttr ($temp1[0] + ".ty") ($i * 8);
parent $temp0[0] $theGrp ;
parent $temp1[0] $theGrp ;
}
Mercury
% file: beer.m
% author:
% Fergus Henderson <fjh@cs.mu.oz.au> Thursday 9th November 1995
% Re-written with new syntax standard library calls:
% Paul Bone <paul@mercurylang.org> 2015-11-20
%
% This beer song is more idiomatic Mercury than the original, I feel bad
% saying that since Fergus is a founder of the language.
:- module beer.
:- interface.
:- import_module io.
:- pred main(io::di, io::uo) is det.
:- implementation.
:- import_module int.
:- import_module list.
:- import_module string.
main(!IO) :-
beer(99, !IO).
:- pred beer(int::in, io::di, io::uo) is det.
beer(N, !IO) :-
io.write_string(beer_stanza(N), !IO),
( N > 0 ->
io.nl(!IO),
beer(N - 1, !IO)
;
true
).
:- func beer_stanza(int) = string.
beer_stanza(N) = Stanza :-
( N = 0 ->
Stanza = "Go to the store and buy some more!\n"
;
NBottles = bottles_line(N),
N1Bottles = bottles_line(N - 1),
Stanza =
NBottles ++ " on the wall.\n" ++
NBottles ++ ".\n" ++
"Take one down, pass it around,\n" ++
N1Bottles ++ " on the wall.\n"
).
:- func bottles_line(int) = string.
bottles_line(N) =
( N = 0 ->
"No more bottles of beer"
; N = 1 ->
"1 bottle of beer"
;
string.format("%d bottles of beer", [i(N)])
).
min
(swap quote interpolate puts!) :line
(
(
("$1 bottles of beer on the wall" line)
("$1 bottles of beer" line)
(pop "Take one down, pass it around" puts!)
(pred dup "$1 bottles of beer on the wall" line newline)
) cleave
) :verse
99 'verse over times
MiniScript
Going for the simple/obvious solution here...
bottles = function(n)
if n == 0 then return "no bottles"
if n == 1 then return "1 bottle"
return n + " bottles"
end function
verse = function(n)
print bottles(n) + " of beer on the wall"
print bottles(n) + " of beer"
print "Take one down, pass it around"
print bottles(n-1) + " of beer on the wall"
print
end function
for i in range(99, 1)
verse i
end for
- Output:
99 bottles of beer on the wall 99 bottles of beer Take one down, pass it around 98 bottles of beer on the wall 98 bottles of beer on the wall 98 bottles of beer Take one down, pass it around 97 bottles of beer on the wall ... 2 bottles of beer on the wall 2 bottles of beer Take one down, pass it around 1 bottle of beer on the wall 1 bottle of beer on the wall 1 bottle of beer Take one down, pass it around no bottles of beer on the wall
MIPS Assembly
##################################
# 99 bottles of beer on the wall #
# MIPS Assembly targeting MARS #
# By Keith Stellyes #
# August 24, 2016 #
##################################
#It is simple, a loop that goes as follows:
#if accumulator is not 1:
#PRINT INTEGER: accumulator
#PRINT lyrica
#PRINT INTEGER: accumulator
#PRINT lyricb
#PRINT INTEGER: accumulator
#PRINT lyricc
#DECREMENT accumulator
#else:
#PRINT FINAL LYRICS
.data
lyrica: .asciiz " bottles of beer on the wall, "
lyricb: " bottles of beer.\nTake one down and pass it around, "
lyricc: " bottles of beer on the wall. \n\n"
#normally, I don't like going past 80 columns, but that was done here.
# there's an argument to be had for breaking this up. I chose not to
# for simpler instructions.
final_lyrics: "1 bottle of beer on the wall, 1 bottle of beer.\nTake one down and pass it around, no more bottles of beer on the wall.\n\nNo more bottles of beer on the wall, no more bottles of beer.\nGo to the store and buy some more, 99 bottles of beer on the wall."
.text
#lw $a0,accumulator #load address of accumulator into $a0 (or is it getting val?)
li $a1,99 #set the inital value of the counter to 99
loop:
###99
li $v0, 1 #specify print integer system service
move $a0,$a1
syscall #print that integer
### bottles of beer on the wall,
la $a0,lyrica
li $v0,4
syscall
###99
li $v0, 1 #specify print integer system service
move $a0,$a1
syscall #print that integer
### bottles of beer.\n Take one down and pass it around,
la $a0,lyricb
li $v0,4
syscall
###99
li $v0, 1 #specify print integer system service
move $a0,$a1
syscall #print that integer
### "bottles of beer on the wall. \n\n"
la $a0,lyricc
li $v0,4
syscall
#decrement counter, if at 1, print the final and exit.
subi $a1,$a1,1
bne $a1,1,loop
### PRINT FINAL LYRIC, THEN TERMINATE.
final: la $a0,final_lyrics
li $v0,4
syscall
li $v0,10
syscall
Mirah
plural = 's'
99.downto(1) do |i|
puts "#{i} bottle#{plural} of beer on the wall,"
puts "#{i} bottle#{plural} of beer"
puts "Take one down, pass it around!"
plural = '' if i - 1 == 1
if i > 1
puts "#{i-1} bottle#{plural} of beer on the wall!"
puts
else
puts "No more bottles of beer on the wall!"
end
end
Miranda
main :: [sys_message]
main = map (Stdout . verse) [99, 98 .. 1]
verse :: num->[char]
verse n = lay [bottles n ++ " of beer on the wall,",
bottles n ++ " of beer,",
"Take " ++ pronoun ++ " down and pass it around,",
bottles (n-1) ++ " of beer on the wall!",
[]]
where pronoun = "it", if n=1
= "one", otherwise
bottles :: num->[char]
bottles n = "No more bottles", if n=0
= "1 bottle", if n=1
= (show n) ++ " bottles", otherwise
mIRC Scripting Language
var %x = 99
while (%x) {
echo -ag %x bottles of beer on the wall
echo -ag %x bottles of beer
echo -ag Take one down, pass it around
dec %x
echo -ag %x bottles of beer on the wall
}
ML/I
Simple iterative version
MCSKIP "WITH" NL
"" 99 bottles - simple iterative version
MCSKIP MT,<>
MCINS %.
"" Macro to generate singular or plural bottle(s)
MCDEF BOT WITHS () AS <bottle<>MCGO L0 IF %A1. EN 1
s>
"" Main macro - argument is initial number of bottles
MCDEF BOTTLES NL AS <MCSET T1=%A1.
%L1.%T1. BOT(%T1.) of beer on the wall
%T1. BOT(%T1.) of beer
Take one down, pass it around
MCSET T1=T1-1
%T1. BOT(%T1.) of beer on the wall
MCGO L0 IF T1 EN 0
MCGO L1
>
"" Do it
BOTTLES 99
Recursive version
MCSKIP "WITH" NL
"" 99 bottles - recursive version
MCSKIP MT,<>
MCINS %.
"" Macro to generate singular or plural bottle(s)
MCDEF BOT WITHS () AS <bottle<>MCGO L0 IF %A1. EN 1
s>
"" Main macro - recurses for each verse - argument is initial number of bottles
MCDEF BOTTLES NL AS <MCSET T1=%A1.
%T1. BOT(%T1.) of beer on the wall
%T1. BOT(%T1.) of beer
Take one down, pass it around
MCSET T1=T1-1
%T1. BOT(%T1.) of beer on the wall
MCGO L0 IF T1 EN 0
BOTTLES %T1.
>
"" Do it
BOTTLES 99
Macro Processing generalized version in 99 lines
This version demonstrates the macro text replacement capabilities central to ML/I.
The code defines a macro
Sing n containers of contents somewhere : deed ! replenish .
where the text (macro call)
Sing 99 bottles of beer on the wall: Take one down, pass it around ! Go to the store and buy some more .
is macro substituted with the specified 99 bottles of beer song. The text
Sing 7 bottles of Armagnac on the table: Take a swig, throw it down ! Emilie vists, she brings some more .
would be substituted with a shorter, more expensive, less social and sexier lyric.
Internal macros define English word replacements for decimal numbers from 0 to 99.
MCSKIP - WITH - NL
-- The line above defines the comment syntax: -- through to newline is completely deleted.
-- 99 Bottles of beer in 99 lines of ML/I by Parzival Herzog.
-- ML/I is P.J. Brown's famous general purpose macro processor designed in 1967.
--
-- Define nestable quotes {...}, replaced by the unevaluated text within:
MCSKIP MT, {}
-- Define non-nestable quotes "...", replaced by the unevaluated text within:
MCSKIP T, ""
-- Define the argument insertion and expression evaluation syntax:
-- ?e. is replaced by the value of macro expression e:
MCINS ?.
--
-- Top level macro: Sing N CONTAINERS of CONTENTS SOMEWHERE : DO THE DEED! REPLENISH.
MCDEF "Sing WITH SPACE SPACE of WITH SPACE SPACE : ! ." AS --
{MCDEF "CONTAINERS" AS "{"?A2."}"
MCDEF "CONTAINER" AS "{"MCSUB(CONTAINERS,1,-1)"}"
MCDEF "CONTENTS" AS "{"?A3."}"
MCDEF "SOMEWHERE" AS "{"?A4."}"
MCDEF "DO WITHS THE WITHS DEED" AS "{"?A5."}"
MCDEF "REPLENISH" AS "{"?A6."}"
MCSET T1 = ?A1.
MCDEF "n" AS "("?T1.")"
MCDEF "N" AS "{"n"}"
?L1.n of CONTENTS SOMEWHERE,
n of CONTENTS.
MCGO L2 UNLESS ?T1. GR 0
MCSET T1 = T1 - 1
MCDEF "n" AS "("?T1.")"
DO THE DEED:
n of CONTENTS SOMEWHERE.
MCGO L1
?L2.REPLENISH:
N of CONTENTS SOMEWHERE!}
--
-- (n): Wordify 0 to 99 CONTAINERS
MCDEF "()" AS {MCSET T1=?A1.
MCGO L1 UNLESS T1 GR 99
?T1. CONTAINERS-- Return the decimal number instead of words.
MCGO L0
?L1.MCGO L2 IF T1 GR 9
MCDEF "0units" AS ?T1."Unit"
MCGO L3
?L2.MCSET T3 = T1 - T1/10*10
MCDEF "0units" AS ?T3."unit"
MCSET T1 = T1 / 10
MCDEF "0tens" AS ?T1."Ten"
0tens?L3.0units CONTAINERS}
-- Exceptions:
MCDEF "(WITH 0 WITH)" AS {"No more" CONTAINERS}
MCDEF "(WITH 1 WITH)" AS {"One more" CONTAINER}
MCDEF "(WITH 11 WITH)" AS {"Eleven" CONTAINERS}
MCDEF "(WITH 12 WITH)" AS {"Twelve" CONTAINERS}
MCDEF "(WITH 13 WITH)" AS {"Thirteen" CONTAINERS}
MCDEF "(WITH 14 WITH)" AS {"Fourteen" CONTAINERS}
MCDEF "(WITH 15 WITH)" AS {"Fifteen" CONTAINERS}
MCDEF "(WITH 16 WITH)" AS {"Sixteen" CONTAINERS}
MCDEF "(WITH 17 WITH)" AS {"Seventeen" CONTAINERS}
MCDEF "(WITH 18 WITH)" AS {"Eighteen" CONTAINERS}
MCDEF "(WITH 19 WITH)" AS {"Nineteen" CONTAINERS}
-- Regular cases:
MCDEF "2Unit" AS {"Two"}
MCDEF "3Unit" AS {"Three"}
MCDEF "4Unit" AS {"Four"}
MCDEF "5Unit" AS {"Five"}
MCDEF "6Unit" AS {"Six"}
MCDEF "7Unit" AS {"Seven"}
MCDEF "8Unit" AS {"Eight"}
MCDEF "9Unit" AS {"Nine"}
MCDEF "0unit" AS
MCDEF "1unit" AS {" one"}
MCDEF "2unit" AS {" two"}
MCDEF "3unit" AS {" three"}
MCDEF "4unit" AS {" four"}
MCDEF "5unit" AS {" five"}
MCDEF "6unit" AS {" six"}
MCDEF "7unit" AS {" seven"}
MCDEF "8unit" AS {" eight"}
MCDEF "9unit" AS {" nine"}
MCDEF "1Ten" AS {"Ten"}
MCDEF "2Ten" AS {"Twenty"}
MCDEF "3Ten" AS {"Thirty"}
MCDEF "4Ten" AS {"Forty"}
MCDEF "5Ten" AS {"Fifty"}
MCDEF "6Ten" AS {"Sixty"}
MCDEF "7Ten" AS {"Seventy"}
MCDEF "8Ten" AS {"Eighty"}
MCDEF "9Ten" AS {"Ninety"}
--
-- The specified song:
Sing 99 bottles of beer on the wall: Take one down, pass it around! --
Go to the store and buy some more.
--
--
-- Try uncommenting the next two lines:
-- Sing 7 flasks of Armagnac on the table: Take a swig, throw it down!
-- Emilie vists, she brings some more.
Usage:
ml1 "Bottles of Beer.ml1"
Output:
Ninety nine bottles of beer on the wall,
Ninety nine bottles of beer.
Take one down, pass it around:
Ninety eight bottles of beer on the wall.
Ninety eight bottles of beer on the wall,
Ninety eight bottles of beer.
Take one down, pass it around:
Ninety seven bottles of beer on the wall.
...
One more bottle of beer on the wall,
One more bottle of beer.
Take one down, pass it around:
No more bottles of beer on the wall.
No more bottles of beer on the wall,
No more bottles of beer.
Go to the store and buy some more:
Ninety nine bottles of beer on the wall!
mLite
val NL = implode [#"newline"]
fun itone 1 = "it"
| n = "one"
fun plural (s, 0) = ("no " @ s @ "s")
| (s, 1) = ("1 " @ s)
| (s, n) = (ntos n @ " " @ s @ "s")
fun verse 0 = "no bottles of beer on the wall" @ NL @
"no bottles of beer" @ NL @
"go to the store and buy some more" @ NL @
"99 bottles of beer on the wall" @ NL @ NL
| x = plural ("bottle",x) @ " of beer on the wall" @ NL @
plural ("bottle",x) @ " of beer" @ NL @
"take " @ (itone x) @ " down and pass it round" @ NL @
plural ("bottle", (x-1)) @ " of beer on the wall" @ NL @ NL
fun bottles x = map (print o verse) (rev (0 :: iota (1, x)))
fun default (false, y) = y | (x, _) = x
;
bottles ` ston ` default (argv 0, "99")
Allows for number of bottles to be specified on command line with the default being 99, viz
mlite -f 99bob.m 2
Which, having specified 2 bottles, gives
2 bottles of beer on the wall 2 bottles of beer take one down and pass it round 1 bottle of beer on the wall 1 bottle of beer on the wall 1 bottle of beer take it down and pass it round no bottles of beer on the wall no bottles of beer on the wall no bottles of beer go to the store and buy some more 99 bottles of beer on the wall
Modula-2
MODULE b99;
IMPORT InOut;
VAR nr : CARDINAL;
BEGIN
nr := 99;
REPEAT
InOut.WriteCard (nr, 4);
InOut.WriteString (" bottles of beer on the wall");
InOut.WriteLn;
InOut.WriteCard (nr, 4);
InOut.WriteString (" bottles of beer");
InOut.WriteLn;
InOut.WriteString ("Take one down, pass it around");
InOut.WriteLn;
DEC (nr);
InOut.WriteCard (nr, 4);
InOut.WriteString (" bottles of beer on the wall");
InOut.WriteLn;
InOut.WriteLn
UNTIL nr = 0
END b99.
Modula-3
MODULE Bottles EXPORTS Main;
IMPORT IO, Fmt;
BEGIN
FOR i := 99 TO 1 BY -1 DO
IO.Put(Fmt.Int(i) & " bottles of beer on the wall\n");
IO.Put(Fmt.Int(i) & " bottles of beer\n");
IO.Put("Take one down, pass it around\n");
IO.Put(Fmt.Int(i - 1) & " bottles of beer on the wall\n");
IO.Put("\n");
END;
END Bottles.
Monkey
Tic's every one and a half seconds and sings(text's) the song out.
Import mojo
Function Main ()
New NintyNineBottles
End
Class NintyNineBottles Extends App
Field _bottles:Int = 99
Field _y:Int=640
Field tic:Int
Field duration:Int = 1500
Field lyric:Int = 1
Method OnCreate ()
SetUpdateRate 60
End
' Stuff to do while running...
Method OnUpdate ()
If Millisecs()-Self.tic > Self.duration
Self.tic=Millisecs()
If Self.lyric= 4 Then Self._bottles-=1
Self.lyric+=1
End If
End
' Drawing code...
Method OnRender ()
Cls
Select Self.lyric
Case 1
DrawText(_bottles+" bottles of beer on the wall",10,10)
Case 2
DrawText(_bottles+" bottles of beer",10,10)
Case 3
If Self._bottles > 1
DrawText("take one down",10,10)
Else
DrawText("take it down",10,10)
End If
Case 4
DrawText("Pass it around",10,10)
Case 5
If Self._bottles>0
DrawText(Self._bottles+" bottles of beer on the wall",10,10)
Else
DrawText("no more bottles of beer on the wall",10,10)
End If
Case 6
If Self._bottles>0
Self.lyric=1'DrawText(Self._bottles+" bottles of beer on the wall",10,10)
Else
DrawText("no more bottles of beer",10,10)
End if
Case 7
DrawText("go to the store",10,10)
Case 8
DrawText("and buy some more",10,10)
Case 9
Self._bottles=99
DrawText(_bottles+" more bottles of beer on the wall",10,10)
Case 10
Self.lyric=1
End Select
End
End
MontiLang
99 VAR i .
WHILE i
i TOSTR OUT . | bottles of beer on the wall| PRINT .
i TOSTR OUT . | bottles of beer| PRINT .
|Take one down, pass it around| PRINT .
i 1 - VAR i .
ENDWHILE
Another way to solve the task that shows some more features of the language.
&DEFINE botellas 99&
def rima
OUT | bottles of beer on the wall| PRINT .
OUT | bottles of beer| PRINT .
enddef
botellas
for :
rima
|Take one down, pass it around| PRINT .
1 -
endfor
|No more| rima
|Press ENTER to end | INPUT clear
Infinite loop
99 var botellas .
def rima /# n -- n #/
OUT | bottles of beer on the wall| PRINT .
OUT | bottles of beer| PRINT .
enddef
def song /# n -- #/
for :
rima
|Take one down, pass it around| PRINT .
1 -
endfor
|No more| rima
clear
enddef
while 1
botellas
song
|Go to the store and buy some more, | print
botellas out | bottles of beer on the wall.| print
|Press ENTER to continue | INPUT clear
endwhile
MOO
bottles = 99;
while (bottles > 0)
unit = (bottles == 1 ? "bottle" | "bottles");
player:tell(bottles, " ", unit, " of beer on the wall.");
player:tell(bottles, " ", unit, " of beer.");
player:tell("Take one down, pass it around.");
bottles = bottles - 1;
endwhile
player:tell("0 bottles of beer on the wall.");
MoonScript
p = (i) ->
i != 1 and 's' or ''
for b = 99,1,-1
for i = 1,4
print if i == 3
'Take one down, pass it around'
else
string.format '%s bottle%s of beer%s',
i < 4 and b or b-1,
i < 4 and (p b) or (p b-1),
i%3 == 1 and ' on the wall' or ''
io.write '\n'
MUMPS
Recursive
beer(n) If n<1 Write "No bottles of beer on the wall... " Quit
Write !!,n," bottle",$Select(n=1:"",1:"s")," of beer on the wall."
Write !,n," bottle",$Select(n=1:"",1:"s")," of beer."
Write !,"Take one down, pass it around."
Do beer(n-1)
Quit
Do beer(99)
Iterative
beer(n) If n<1 Write "No bottles of beer on the wall... " Quit
Write !!,n," bottle",$Select(n=1:"",1:"s")," of beer on the wall."
Write !,n," bottle",$Select(n=1:"",1:"s")," of beer."
Write !,"Take one down, pass it around."
Quit
For ii=99:-1:0 Do beer(ii)
Brain-damaging
bottles
set template1="i_n_""of beer on the wall. ""_i_n_"" of beer. """
set template2="""Take""_n2_""down, pass it around. """
set template3="j_n3_""of beer on the wall."""
for i=99:-1:1 do write ! hang 1
. set:i>1 n=" bottles ",n2=" one " set:i=1 n=" bottle ",n2=" it "
. set n3=" bottle " set j=i-1 set:(j>1)!(j=0) n3=" bottles " set:j=0 j="No"
. write @template1,@template2,@template3
repeat
write "One more time!",! hang 5
goto bottles
MyDef
Compile with:
mydef_page -mgeneral bottles.def
It outputs bottles.txt, which contains the lyrics.
bottles
$(for:i in 99-1)
$(i) bottles of beer on the wall
$(i) bottles of beer
Take one down, pass it around
$(set:i-=1)
$(i) bottles of beer on the wall
NEWLINE
N/t/roff
Classical version (compatible with classical Bell Lab's TROFF)
Subroutine L1
calls upon itself recursively.
.nr BS 99 1
.de L1
.ie \\n(BS>1 \{ \
\\n(BS bottles of beer on the wall,
\\n(BS bottles of beer.\c
\}
.el \{ \
\\n(BS bottle of beer on the wall,
\\n(BS bottle of beer.\c
\}
Take one down, pass it around,
\\n-(BS bottles of beer on the wall.
.if \\n(BS>0 .L1
..
.nf
.L1
.fi
New version (compatible only with GNU TROFF)
Instead of recursion, a while
construct can be used instead, to achieve the same results. Technically, the program runs differently.
.nr beers 99 1
.nf
.while \n[beers]>0 \{ \
.ie \n[beers]>1 \{ \
\n[beers] bottles of beer on the wall,
\n[beers] bottles of beer.\c
\} \" ie \n[beers]>1
.el \{ \
\n[beers] bottle of beer on the wall,
\n[beers] bottle of beer.\c
\} \" el
Take one down, pass it around,
\n-[beers] bottles of beer on the wall.
\} \" while \n[beers]>0
.fi
Nanoquery
//
// 99 bottles of beer
//
for bottles in range(99, 1, -1)
bottlestr = ""
if bottles = 1
bottlestr = "bottle"
else
bottlestr = "bottles"
end if
println (bottles + " " + bottlestr + " of beer on the wall")
println (bottles + " " + bottlestr + " of beer")
println "Take one down, pass it around."
if !(bottles = 2)
println (bottles - 1 + " bottles of beer on the wall.\n")
else
println "1 bottle of beer on the wall.\n"
end if
end for
NASL
bottles = 99;
repeat {
display(bottles, ' bottles of beer on the wall\n');
display(bottles, ' bottles of beer\n');
display('Take one down, pass it around\n');
display(--bottles, ' bottles of beer on the wall\n\n');
} until bottles < 1;
Neko
/**
<doc>
<h3>Rosetta Code, 99 bottles of beer on the wall, in Neko</h3>
<pre>
Tectonics:
nekoc 99bottles.neko
neko 99bottles
</pre>
</doc>
**/
var message = " of beer on the wall\n";
var beers = 99;
var plural = function(n) {
return if (n == 1) " bottle" else " bottles";
}
var nonesome = function(n) {
return if (n > 0) n else "No more";
}
while (beers > 0) {
$print(nonesome(beers), plural(beers), message);
$print(nonesome(beers), plural(beers), " of beer\n");
$print("Take one down, pass it around\n");
beers -= 1;
$print(nonesome(beers), plural(beers), message);
if (beers > 0) $print("\n");
}
- Output:
prompt$ nekoc 99bottles.neko prompt$ neko 99bottles | { head -n 4; echo "..."; tail -n 4; } 99 bottles of beer on the wall 99 bottles of beer Take one down, pass it around 98 bottles of beer on the wall ... 1 bottle of beer on the wall 1 bottle of beer Take one down, pass it around No more bottles of beer on the wall
Nemerle
using System;
using System.Console;
module Bottles
{
Sing(x : int, bev = "beer", surface = "wall") : void
{
match(x)
{
|0 => WriteLine($"No more bottles of $bev on the $surface, no more bottles of $bev");
WriteLine($"Go to the store and get some more $bev, 99 bottles of $bev on the $surface")
|1 => WriteLine($"One bottle of $bev on the $surface, one bottle of $bev");
WriteLine($"Take it down, pass it around, no more bottles of $bev on the $surface")
|_ => WriteLine($"$x bottles of $bev on the $surface, $x bottles of $bev");
WriteLine($"Take one down and pass it around, $(x-1) bottles of $bev on the $surface")
}
}
Main() : void
{
foreach (i in [99, 98 .. 0])
Sing(i)
}
}
NetRexx
beer = "bottles of beer on the wall"
removeOne = "Take one down, pass it arround,"
say 99 beer","
say 99 beer.subword(1,3)","
loop i = 98 to 2 by -1
say removeOne
say i beer"."
say
say i beer","
say i beer.subword(1,3)","
end
lastCall = "bottle" beer.delword(1,1)
say removeOne
say i lastCall"."
say
say i lastCall","
say i lastCall.subword(1,3)","
say removeOne
say "No more" beer
newLISP
Nial
line is fork [
0=, 'No more bottles of beer' first,
1=, 'One bottle of beer' first,
link [string,' bottles of beer' first]
]
verse is link [
line, ' on the wall, ' first,line,
'. Take it down and pass it around, ' first,
line (-1+),'on the wall. ' first
]
bottles is iterate (write verse) reverse count
Night
null bottles(int x) {
if(x == 1) {
print("1 bottle of beer on the wall,\n");
print("1 bottle of beer,\n");
print("Take it down, pass it around,\n");
print("No more bottles of beer.\n");
}
else {
print(x);
print(" bottles of beer on the wall,\n");
print(x);
print(" bottles of beer,\n");
print("Take one down, pass it around,\n");
print(x - 1);
print(" bottles of beer on the wall,");
bottles(x-1);
}
}
bottles(1);
This code should work according to the docs, but due to a few bugs in the current implementation it doesn't.
Nim
proc getBottleNumber(n: int): string =
case n
of 0:
result = "No more bottles"
of 1:
result = "1 bottle"
else:
result = $n & " bottles"
result &= " of beer"
for bn in countdown(99, 1):
let cur = getBottleNumber(bn)
echo(cur, " on the wall, ", cur, ".")
echo("Take one down and pass it around, ", getBottleNumber(bn-1), " on the wall.\n")
echo "No more bottles of beer on the wall, no more bottles of beer."
echo "Go to the store and buy some more, 99 bottles of beer on the wall."
other:
from strutils import format
for i in countdown(99, 1):
case i
of 3..99:
echo format("""$1 bottles of beer on the wall
$1 bottles of beer
Take one down, pass it around
$2 bottles of beer on the wall""", i, i-1)
of 2:
echo format("""$1 bottles of beer on the wall
$1 bottles of beer
Take one down, pass it around
$2 bottle of beer on the wall""", i, i-1)
of 1:
echo format("""$1 bottle of beer on the wall
$1 bottle of beer
Take one down, pass it around
No more bottles of beer on the wall""", i)
else:
discard
compact:
from strutils import format
proc pluralize(a: int): string =
if a > 1 or a == 0: "s"
else: ""
for i in countdown(99, 1):
echo format("""$1 bottle$3 of beer on the wall
$1 bottle$3 of beer
Take one down, pass it around
$2 bottle$4 of beer on the wall""", i, i-1, pluralize(i), pluralize(i-1))
organized:
from strutils import format
var verse = """$1 bottle$3 of beer on the wall
$1 bottle$3 of beer
Take one down, pass it around
$2 bottle$4 of beer on the wall"""
proc pluralize(a: int): string =
if a > 1 or a == 0: "s"
else: ""
for i in countdown(99, 1):
echo format(verse, i, i-1, pluralize(i), pluralize(i-1))
Nix
with builtins;
let
bottle = x: "${toString x} bottle${if (x == 1) then "" else "s"} of beer";
beer = { x ? 99 }: if (x == 0) then "" else ''
${bottle x} on the wall
${bottle x}
Take one down, pass it around
${bottle (x - 1)} on the wall
${beer { x = x - 1; }}'';
in
beer { }
NS-HUBASIC
With grammatical support for "1 bottle of beer"
10 WALL$=" ON THE WALL"
20 FOR BOTTLES=99 TO 1 STEP -1
30 BOTTLES$=" BOTTLES OF BEER"
40 IF BOTTLES=1 THEN BOTTLE$=" BOTTLE OF BEER"
50 PRINT BOTTLES BOTTLES$ WALL$
60 PRINT BOTTLES BOTTLES$
70 PRINT "TAKE ONE DOWN, PASS IT AROUND"
80 IF BOTTLES-1=1 THEN BOTTLE$=" BOTTLE OF BEER"
90 IF BOTTLES-1=0 THEN BOTTLE$=" BOTTLES OF BEER"
100 PRINT BOTTLES-1 BOTTLES$ WALL$
110 NEXT
Without grammatical support for "1 bottle of beer"
10 BOTTLES$=" BOTTLES OF BEER"
20 WALL$=" ON THE WALL"
30 FOR BOTTLES=99 TO 1 STEP -1
40 PRINT BOTTLES BOTTLES$ WALL$
50 PRINT BOTTLES BOTTLES$
60 PRINT "TAKE ONE DOWN, PASS IT AROUND"
70 PRINT BOTTLES-1 BOTTLES$ WALL$
80 NEXT
Nutt
module main imports native.io.output.say
for i|->{1,2..99;<|>) do
say(""+i+" bottles of beer on the wall, "+i+" bottles of beer")
say("Take one down and pass it around, "+(i-1)+" bottles of beer on the wall.")
done
end
OASYS
class player {}
int count
property int dummy
method quit verbs {{quit}} {
quit
}
method beer verbs {{beer}} {
count = 99
while count {
print count
print " bottles of beer on the wall.\n"
print count
print " bottles of beer.\nTake one down and pass it around,\n"
count = count - 1
if count {
print count
print " bottles of beer on the wall.\n\n"
}
}
print "No more bottles of beer on the wall.\n"
}
method init {
player = create player
print "Type 'beer' for beer.\nType 'quit' to quit.\n"
}
OASYS Assembler
Oberon-2
MODULE b99;
IMPORT Out;
VAR nr : INTEGER;
BEGIN
nr := 99;
REPEAT
Out.Int (nr, 4);
Out.String (" bottles of beer on the wall");
Out.Ln;
Out.Int (nr, 4);
Out.String (" bottles of beer");
Out.Ln;
Out.String ("Take one down, pass it around");
Out.Ln;
DEC (nr);
Out.Int (nr, 4);
Out.String (" bottles of beer on the wall");
Out.Ln;
Out.Ln
UNTIL nr = 0
END b99.
Objeck
class Bottles {
function : Main(args : String[]) ~ Nil {
bottles := 99;
do {
"{$bottles} bottles of beer on the wall"->PrintLine();
"{$bottles} bottles of beer"->PrintLine();
"Take one down, pass it around"->PrintLine();
bottles--;
"{$bottles} bottles of beer on the wall"->PrintLine();
} while(bottles > 0);
}
}
Objective-C
#import <Foundation/Foundation.h>
int main()
{
@autoreleasepool {
int bottles = 99;
do
{
NSLog(@"%i bottles of beer on the wall\n", bottles);
NSLog(@"%i bottles of beer\n", bottles);
NSLog(@"Take one down, pass it around\n");
NSLog(@"%i bottles of beer on the wall\n\n", --bottles);
} while (bottles > 0);
}
return 0;
}
OCaml
For-loop
for n = 99 downto 1 do
Printf.printf "%d bottles of beer on the wall\n" n;
Printf.printf "%d bottles of beer\n" n;
Printf.printf "Take one down, pass it around\n";
Printf.printf "%d bottles of beer on the wall\n\n" (pred n);
done
Recursive
Recursive version that handles plurals.
let verse n =
let
line2 = function
| 0 -> "No more bottles of beer"
| 1 -> "1 bottle of beer"
| n -> string_of_int n ^ " bottles of beer"
in
let
line1or4 y = line2 y ^ " on the wall"
in
let
line3 = function
| 1 -> "Take it down, pass it around"
| _ -> "Take one down, pass it around"
in
line1or4 n ^ "\n" ^
line2 n ^ "\n" ^
line3 n ^ "\n" ^
line1or4 (n-1) ^ "\n";;
let rec beer n =
print_endline (verse n);
if n > 1 then beer (n-1);;
beer 99;;
Monadic
Monadic version, expressing actions which evolve the program state and log output. Special cases and grammar rules are handled.
(* A basic "Writer" monoid with emit *)
module Writer = struct
type 'a t = 'a * string
let ( >>= ) (x,s) f = let (y,s') = f x in (y, s ^ s')
let return x = (x,"")
let emit (x,s) = print_string s; x
end
(* Utility functions for handling strings and grammar *)
let line s = (String.capitalize s) ^ ".\n"
let count = function 0 -> "no more" | n -> string_of_int n
let plural = function 1 -> "" | _ -> "s"
let specify = function 1 -> "it" | _ -> "one"
let bottles n = count n ^ " bottle" ^ plural n ^ " of beer"
(* Actions, expressed as an int * string, for Writer *)
let report n = (n, line (bottles n ^ " on the wall, " ^ bottles n))
let take n = (n-1, "Take " ^ specify n ^ " down and pass it around")
let summary n = (n, ", " ^ bottles n ^ " on the wall.\n\n")
let shop = (99, "Go to the store and buy some more")
let rec verse state =
Writer.(state >>= report >>= function 0 -> shop >>= summary (* ends here *)
| n -> take n >>= summary |> verse)
let sing start =
Writer.(emit (verse (return start)))
Output for initial beer-count of two:
# sing 2;;
2 bottles of beer on the wall, 2 bottles of beer.
Take one down and pass it around, 1 bottle of beer on the wall.
1 bottle of beer on the wall, 1 bottle of beer.
Take it down and pass it around, no more bottles of beer on the wall.
No more bottles of beer on the wall, no more bottles of beer.
Go to the store and buy some more, 99 bottles of beer on the wall.
- : int = 99
Note the output value is 99... reflecting the state at termination.
Octave
function bottles(n)
bottle = "bottle";
ofbeer = "of beer";
wall = "on the wall";
for i = n:-1:0
if ( i == 1 )
s = "";
else
s = "s";
endif
for j = 0:1
w = wall;
if ( j == 1 )
w = "";
endif
printf("%d %s%s %s %s\n",\
i, bottle, s, ofbeer, w);
endfor
printf("Take one down, pass it around\n");
endfor
endfunction
bottles(99);
Odin
package main
import "core:fmt"
printf :: fmt.printf //Give fn on right an arbitrary name, or 9x fmt.printf("...")
bob :: proc( n: int , x: int){
for i := x; i > 0 ; i -=1 {
if n >= 2 do printf("%d bottles of beer",n)
else if n == 1 do printf("1 bottle of beer")
else if n == 0 do printf("No more bottles of beer")
if i == 1 do printf(".\n")
if i > 1 do printf(" on the wall.\n")
if i > 2 do printf("\n")
}
}
main :: proc(){
n := 99
bob(n, 2)
for i := n - 1 ; i >= 0 ; i -= 1 {
printf("Take one down; pass it around.\n")
bob(i, 3)
}
printf ("Go to the store and buy some more.\n")
printf ("%i bottles of beer on the wall.\n",n)
}
Oforth
"bottles of beer on the wall\n" const: B
"bottles of beer\nTake one down, pass it around\n" const: T
#[ 100 swap - dup . B print dup . T print 1- . B .cr ] 99 each
Ol
Onyx
$Bottles {
dup cvs ` bottle' cat exch 1 ne {`s' cat} if
` of beer' cat
} def
$GetPronoun {
1 eq {`it'}{`one'} ifelse cat
} def
$WriteStanza {
dup dup Bottles ` on the wall. ' cat exch Bottles `.\n' cat cat
exch `Take ' 1 idup GetPronoun ` down. Pass it around.\n' cat
exch dec Bottles ` on the wall.\n\n' 3 {cat} repeat print flush
} def
99 -1 1 {WriteStanza} for
Output:
99 bottles of beer on the wall. 99 bottles of beer. Take one down. Pass it around. 98 bottles of beer on the wall. . . . 2 bottles of beer on the wall. 2 bottles of beer. Take one down. Pass it around. 1 bottle of beer on the wall. 1 bottle of beer on the wall. 1 bottle of beer. Take it down. Pass it around. 0 bottles of beer on the wall.
OOC
sing_line: func (b: Int, suffix: Bool) {
"#{b > 0 ? "#{b}" : "No more"} bottle#{b == 1 ? "" : "s"}" print()
" of beer#{suffix ? " on the wall" : ""}" println()
}
sing_verse: func (b: Int) {
println()
sing_line(b, true)
sing_line(b, false)
if (b > 0) {
"Take one down, pass it around" println()
} else {
"Go to the store and buy some more" println()
b += 100
}
sing_line(b-1, true)
}
main: func {
b := 100
while (b > 0) {
sing_verse(--b)
}
}
ooRexx
The rexx example below runs unchanged on ooRexx
OpenEdge/Progress
DEFINE VARIABLE amountofbottles AS INTEGER NO-UNDO INITIAL 99.
&GLOBAL-DEFINE bbm bottles of beer
&GLOBAL-DEFINE bbs bottle of beer
&GLOBAL-DEFINE otw on the wall
&GLOBAL-DEFINE tow Take one down and pass it around,
&GLOBAL-DEFINE gts Go to the store and buy some more,
FUNCTION drinkBottle RETURNS INTEGER PRIVATE (INPUT bc AS INTEGER) FORWARD.
OUTPUT TO OUTPUT.txt.
drinkBottle(amountofbottles).
OUTPUT CLOSE.
FUNCTION drinkBottle RETURNS INTEGER.
IF bc >= 0 THEN DO:
CASE bc:
WHEN 2 THEN
PUT UNFORMATTED bc " {&bbm} {&otw}, " bc " {&bbm}" SKIP
"{&tow} " bc - 1 " {&bbs} {&otw}" SKIP.
WHEN 1 THEN
PUT UNFORMATTED bc " {&bbs} {&otw}, " bc " {&bbs}" SKIP
"{&tow} no more {&bbm} {&otw}" SKIP.
WHEN 0 THEN
PUT UNFORMATTED "no more" " {&bbm} {&otw}, no more {&bbm}" SKIP
"{>s} " amountofbottles " {&bbm} {&otw}" SKIP.
OTHERWISE
PUT UNFORMATTED bc " {&bbm} {&otw}, " bc " {&bbm}" SKIP
"{&tow} " bc - 1 " {&bbm} {&otw}" SKIP.
END CASE.
drinkBottle(bc - 1).
RETURN bc.
END.
RETURN 0.
END FUNCTION.
Openscad
El código es de Marc Vanlindt (marc@vanlindt.be)
num_bottles = 99;
s1 = " of beer";
s2 = " on the wall";
s3 = "Take one down and pass it around, ";
s4 = "No more";
s5 = "no more";
s6 = "Go to the store and buy some more, ";
b1 = " bottle";
b2 = " bottles";
beer(n = num_bottles);
module beer(n, biere) {
biere1 = str(n >= 1 ? n : s4,n == 1 ? b1 :b2,s1, s2,", ",n >= 1 ? n : s5,n == 1 ? b1 :b2,s1,".");
biere2 = str(n == 0 ? s6 : s3,n == 0 ? num_bottles : n == 1 ? s5 : n-1,n == 0 ? b2 : n-1 == 1 ? b1 : b2,s1,s2,".");
biere3 = str(biere1," ",biere2);
echo(biere3);
if(n > 0) {
beer(n = n-1);
}
}
Order
These examples are taken directly from a much longer tutorial in the Order documentation, which explains the construction of the solution to this problem in great detail.
"Pure" Order
This solution uses only Order language constructs to generate and manipulate tokens:
#include "order/interpreter.h"
ORDER_PP
(8let((8B, 8fn(8N,
8cond((8greater(8N, 1),
8separate(8N, 8quote(bottles)))
(8equal(8N, 1),
8quote(1 bottle))
(8else,
8quote(no more bottles))))),
8for_each_in_range
(8fn(8N,
8print(8ap(8B, 8N) (of beer on the wall,) 8space
8ap(8B, 8N) (of beer,) 8space
(take one down, pass it around,) 8space
8ap(8B, 8dec(8N)) (of beer on the wall.))),
100, 1)))
C Preprocessor
...but since most of the logic is simple substitution, it makes more sense (and is significantly more efficient) to make the C Preprocessor do most of the work without the help of the Order interpreter. This version shows how to integrate normal C Preprocessor macros into an Order program:
#include "order/interpreter.h"
#define GEN_phrase(N_bottles, N_minus_1_bottles) \
N_bottles of beer on the wall, \
N_bottles of beer, take one down, pass it around, \
N_minus_1_bottles of beer on the wall.
#define ORDER_PP_DEF_8bottles \
ORDER_PP_FN(8fn(8N, \
8cond((8greater(8N, 1), \
8separate(8N, 8quote(bottles))) \
(8equal(8N, 1), \
8quote(1 bottle)) \
(8else, \
8quote(no more bottles)))))
ORDER_PP(8for_each_in_range
(8fn(8N,
8emit(8quote(GEN_phrase),
8tuple(8bottles(8N),
8bottles(8dec(8N))))),
100, 1))
#undef GEN_phrase
Either example could obviously also form the core of a C solution (demonstrating the intended use of Order).
Oxygene
namespace ConsoleApplication2;
interface
type
ConsoleApp = class
public
class method Main(args: array of String);
end;
implementation
method bottles(number: Integer): String;
begin
if (number = 1) then
Result := "bottle"
else
Result := "bottles";
end;
class method ConsoleApp.Main(args: array of String);
begin
for n: Integer := 99 downto 1 do
begin
Console.WriteLine("{0} {1} of beer on the wall,",n,bottles(n));
Console.WriteLine("{0} {1} of beer,",n,bottles(n));
Console.WriteLine("Take one down, and pass it around,");
Console.WriteLine("{0} {1} of beer on the wall.",n-1,bottles(n-1));
Console.WriteLine();
end;
Console.ReadKey();
end;
end.
This version uses top-level declarations, string interpolation along with more idiomatic Object Pascal syntax vs C#.Net syntax:
namespace _99_beers;
method bottles(number: Integer): String;
begin
if (number = 1) then
Result := "bottle"
else
Result := "bottles";
end;
begin
for n: Integer := 99 downto 1 do
begin
writeLn($"{n} {bottles(n)} of beer on the wall,");
writeLn($"{n} {bottles(n)} of beer,");
writeLn($"Take one down, and pass it around,");
writeLn($"{n-1} {bottles(n-1)} of beer on the wall.");
writeLn();
end;
readLn;
end.
Oz
Constraint Programming
Note: In real life, you would never solve a simple iterative task like this with constraint programming. This is just for fun.
declare
%% describe the possible solutions of the beer 'puzzle'
proc {BeerDescription Solution}
N = {FD.int 1#99} %% N is an integer in [1, 99]
in
%% distribute starting with highest value
{FD.distribute generic(value:max) [N]}
Solution =
{Bottles N}#" of beer on the wall\n"#
{Bottles N}#" bottles of beer\n"#
"Take one down, pass it around\n"#
{Bottles N-1}#" of beer on the wall\n"
end
%% pluralization
proc {Bottles N Txt}
cond N = 1 then Txt ="1 bottle"
else Txt = N#" bottles"
end
end
in
%% show all solutions to the 'puzzle'
{ForAll {SearchAll BeerDescription}
System.showInfo}
Iterative
declare
fun {Bottles N}
if N == 1 then "1 bottle"
else N#" bottles"
end
end
in
for I in 99..1;~1 do
{System.showInfo
{Bottles I}#" of beer on the wall\n"#
{Bottles I}#" bottles of beer\n"#
"Take one down, pass it around\n"#
{Bottles I-1}#" of beer on the wall\n"}
end
PARI/GP
forstep(n=99,3,-1,
print(n" bottles of beer on the wall");
print(n" bottles of beer");
print("Take one down, pass it around");
print(n-1," bottles of beer on the wall\n")
);
print("2 bottles of beer on the wall\n2 bottles of beer\nTake one down, pass it around\n1 bottle of beer on the wall\n");
print("1 bottle of beer on the wall\n1 bottle of beer\nTake one down, pass it around\nNo more bottles of beer on the wall")
Pascal
PascalABC.NET
begin
for var i:=99 to 1 step -1 do
begin
Println(i,'bottles of beer on the wall');
Println(i,'bottles of beer');
Println('Take one down, pass it around');
Println(i-1,'bottles of beer on the wall');
Println
end;
end.
This version demonstrates uses of 'writeLn' vs 'Println' as well as string interpolation:
begin
for var i:=99 to 1 step -1 do
begin
writeLn($'{i} bottles of beer on the wall');
writeLn($'{i} bottles of beer');
writeLn($'Take one down, pass it around');
writeLn($'{i-1}bottles of beer on the wall');
writeLn
end;
end.
Perl
#!/usr/bin/perl -w
my $verse = <<"VERSE";
100 bottles of beer on the wall,
100 bottles of beer!
Take one down, pass it around!
99 bottles of beer on the wall!
VERSE
{
$verse =~ s/(\d+)/$1-1/ge;
$verse =~ s/\b1 bottles/1 bottle/g;
my $done = $verse =~ s/\b0 bottle/No bottles/g; # if we make this replacement, we're also done.
print $verse;
redo unless $done;
}
Alternatively:
for $n (reverse(0..99))
{
$bottles = sprintf("%s bottle%s of beer on the wall\n",(($n==0)?"No":$n), (($n==1)?"":"s"));
print( (($n==99)?"":"$bottles\n") .
(($n==0)?"":(substr(${bottles}x2,0,-12) . "\nTake one down, pass it around\n")) );
}
Correct grammar and nice spacing in modern perl:
use 5.10.0;
$num = 99;
while ($num > 0) {
my $s = "s" unless ($num == 1);
say "$num bottle$s of beer on the wall, $num bottle$s of beer";
$num--;
my $s = "s" unless ($num == 1);
$num = "No more" if ($num == 0);
say "Take one down, pass it around, $num bottle$s of beer on the wall\n"
}
say "No more bottles of beer on the wall, no more bottles of beer.";
say "Go to the store and buy some more, 99 bottles of beer on the wall.";
Using perl5 as a DSL factory leveraging $_'s global nature:
#!/usr/bin/env perl
use strict;
use warnings;
sub bottles() { sprintf qq{%s bottle%s of beer}
, $_ || 'No'
, $_==1 ? '' : 's';
}
sub store() { $_=99; qq{Go to the store, buy some more...\n}; }
sub wall() { qq{ on the wall\n} }
sub take() { $_-- ? qq{Take one down, pass it around\n} : store }
do { print bottles, wall
, bottles, qq{\n}
, take
, bottles, qq{\n\n}
} for reverse 0..99;
Phix
constant ninetynine = 99 -- (set to 9 for testing) function bottles(integer count) if count=0 then return "no more bottles " elsif count=1 then return "1 bottle " end if if count=-1 then count = ninetynine end if return sprintf("%d bottles ",count) end function function bob(integer count) return bottles(count)&"of beer" end function function up1(string bob) -- Capitalise sentence start (needed just the once, "no more"=>"No more") bob[1] = upper(bob[1]) return bob end function string many = bob(ninetynine) string down = "Take one down, pass it around,\n" for i=ninetynine to 0 by -1 do puts(1,up1(many)&" on the wall,\n") puts(1,many&".\n") if i=0 then down = "Go to the store, buy some more,\n" elsif i=1 then down[6..8] = "it" end if many = bob(i-1) puts(1,down&many&" on the wall.\n\n") end for {} = wait_key()
Phixmonti
def bottles
dup if
dup 1 == if
"1 bottle" print
else
dup print " bottles" print
endif
else
"No more bottles" print
endif
enddef
def verse
bottles " of beer on the wall" print nl
bottles " of beer" print nl
"Take one down, pass it around" print nl
1 - bottles " of beer on the wall" print nl nl
enddef
99 1 -1 3 tolist
for verse . endfor
With syntactic sugar
include ..\Utilitys.pmt
def bottles
dup 0 == if
"no more bottles of beer"
else
dup 1 == if
"1 bottle of beer"
else
dup tostr " bottles of beer" chain
endif
endif
enddef
( 99 1 -1 ) for
bottles print " on the wall," ?
bottles "," chain ?
"take one down, pass it around," ?
1 - bottles print " on the wall." ? nl
drop
endfor
PHL
module bottles;
extern printf;
@Integer main [
@Integer bottles = 99;
do
{
printf("%u bottles of beer on the wall\n", bottles);
printf("%u bottles of beer\n", bottles);
printf("Take one down, pass it around\n");
bottles = bottles::dec;
printf("%u bottles of beer on the wall\n\n", bottles);
} while(bottles > 0);
return 0;
]
PHP
<?php
$plural = 's';
foreach (range(99, 1) as $i) {
echo "$i bottle$plural of beer on the wall,\n";
echo "$i bottle$plural of beer!\n";
echo "Take one down, pass it around!\n";
if ($i - 1 == 1)
$plural = '';
if ($i > 1)
echo ($i - 1) . " bottle$plural of beer on the wall!\n\n";
else
echo "No more bottles of beer on the wall!\n";
}
?>
shorter way
<?php
foreach(range(99,1) as $i) {
$p = ($i>1)?"s":"";
echo <<< EOV
$i bottle$p of beer on the wall
$i bottle$p of beer
Take one down, pass it around
EOV;
}
echo "No more Bottles of beer on the wall";
?>
Tag syntax
<?php foreach(range(99,1) as $i):?>
<?=$i?> bottle<?=$i==1 ? '' : 's'?> of beer on the wall,
<?=$i?> bottle<?=$i==1 ? '' : 's'?> of beer!
Take one down, pass it around...
<?php if($i > 1):?>
<?=$i-1?> bottle<?=$i==1 ? '' : 's'?> of beer on the wall!
<?php else:?>
No more bottles of beer on the wall!
<?php endif?>
<?php endforeach?>
modifing way
<?php
$verse = <<<VERSE
100 bottles of beer on the wall,
100 bottles of beer!
Take one down, pass it around!
99 bottles of beer on the wall!
VERSE;
foreach (range(1,99) as $i) { // loop 99 times
$verse = preg_replace('/\d+/e', '$0 - 1', $verse);
$verse = preg_replace('/\b1 bottles/', '1 bottle', $verse);
$verse = preg_replace('/\b0 bottle/', 'No bottles', $verse);
echo $verse;
}
?>
ultra compact alternative
supports grammar and has no leading and trailing new lines or spaces. Also one does not have to close the <?php tag, it is even recommended not to close it, if closing it is not necessary
<?php
for($i=100;$i>0;$i--){
$p2=$i." bottle".(($i>1)?"s":"")." of beer";
$p1=$p2." on the wall\n";
$p3="Take one down, pass it around\n";
echo (($i<100)?$p1."\n":"").$p1.$p2."\n".$p3.(($i<2)?($i-1).substr($p1,1,28):"");
}
gettext alternative
supports grammar and translations.
<?php
$bottles = 99;
while ($bottles > 0) {
printf(ngettext('%d bottle', '%d bottles', $bottles) . " of beer on the wall\n", $bottles); //X bottles of beer on the wall
printf(ngettext('%d bottle', '%d bottles', $bottles) . " of beer\n", $bottles); //X bottles of beer
printf("Take one down, pass it around\n"); //Take one down, pass it around
$bottles--;
if ($bottles > 0) {
printf(ngettext('%d bottle', '%d bottles', $bottles) . " of beer on the wall\n\n", $bottles); //X bottles of beer on the wall
}
}
printf('No more bottles of beer on the wall'); //No more bottles of beer on the wall
Using printf
Fun with HEREDOC and printf placeholders
<?php
$lyrics = <<<ENDVERSE
%2\$d bottle%1\$s of beer on the wall
%2\$d bottle%1\$s of beer
Take one down, pass it around
%4\$s bottle%3\$s of beer on the wall
ENDVERSE;
$x = 99;
while ( $x > 0 ) {
printf( $lyrics, $x != 1 ? 's' : '', $x--, $x != 1 ? 's' : '', $x > 0 ? $x : 'No more' );
}
- Output:
99 bottles of beer on the wall 99 bottles of beer Take one down, pass it around 98 bottles of beer on the wall 98 bottles of beer on the wall 98 bottles of beer Take one down, pass it around 97 bottles of beer on the wall 97 bottles of beer on the wall 97 bottles of beer Take one down, pass it around 96 bottles of beer on the wall 96 bottles of beer on the wall 96 bottles of beer Take one down, pass it around 95 bottles of beer on the wall 95 bottles of beer on the wall 95 bottles of beer Take one down, pass it around 94 bottles of beer on the wall <!-- yada --> 4 bottles of beer on the wall 4 bottles of beer Take one down, pass it around 3 bottles of beer on the wall 3 bottles of beer on the wall 3 bottles of beer Take one down, pass it around 2 bottles of beer on the wall 2 bottles of beer on the wall 2 bottles of beer Take one down, pass it around 1 bottle of beer on the wall 1 bottle of beer on the wall 1 bottle of beer Take one down, pass it around No more bottles of beer on the wall
Picat
beer1(N) =>
Beer = N,
while (Beer > 0)
printf("%d bottles of beer on the wall,\n", Beer),
printf("%d bottles of beer.\n", Beer),
printf("Take one down, pass it around.\n"),
printf("%d bottles of beer.\n", Beer-1),
Beer := Beer -1
end,
print("0 more bottles of beer on the wall.\n"),
nl.
% With plurals.
beer2(B) = S =>
BS = B.to_string(),
BB = " bottle",
BT = BB,
if B > 1 then BB := BB ++ "s" end,
OB = " of beer",
NL = "\n",
BW = OB ++ " on the wall." ++ NL,
T = "Take one down, pass it around." ++ NL,
S1 = BS ++ BT ++ BW ++ BS ++ BT ++ OB ++ T ++
cond(B > 0, (B-1).to_string() ++ BT ++ BW ++ NL, ""),
S = S1.
PicoLisp
Piet
Pike
int main(){
for(int i = 99; i > 0; i--){
write(i + " bottles of beer on the wall, " + i + " bottles of beer.\n");
write("Take one down and pass it around, " + (i-1) + " bottles of beer on the wall.\n\n");
}
write("No more bottles of beer on the wall, no more bottles of beer.\n");
write("Go to the store and buy some more, 99 bottles of beer on the wall.\n");
}
alternate version:
// disclaimer: i prefer gingerale
void main()
{
array numbers = ({ "no more", "one", "two", "three", "four", "five", "six", "seven",
"eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen",
"fifteen", "sixteen", "seventeen", "eighteen", "nineteen" });
array decades = ({ "twenty", "thirty", "fourty", "fifty", "sixty", "seventy", "eighty",
"ninety" });
foreach (decades;; string decade)
{
numbers += decade+(({ "" }) + numbers[1..9])[*];
}
numbers = reverse(numbers);
array bottles = ((numbers[*]+" bottles of ale on the wall, ")[*] +
(numbers[*]+" bottles of ale.\n")[*]);
bottles[-2] = replace(bottles[-2], "one bottles", "one bottle");
string song = bottles * "take one down, pass it around,\n";
write(song);
}
PILOT
El código es de Akira KIDA (SDI00379@niftyserve.or.jp)
C :bottles = 99
U : *beers
*LOOP
T :$T of beer on the wall, $T.
T :Take one down, pass it around.
C :bottles = bottles - 1
U :*beers
T :$T on the wall.
T :
J(bottles > 0) :*LOOP
END:
*beers
C(bottles = 0) :$T = No more bottles
C(bottles = 1) :$T = 1 bottle
C(bottles > 1) :$T = #bottles bottles
E :
PIR
.sub sounding_smart_is_hard_after_drinking_this_many
.param int b
if b == 1 goto ONE
.return(" bottles ")
ONE:
.return(" bottle ")
end
.end
.sub main :main
.local int bottles
.local string b
bottles = 99
LUSH:
if bottles == 0 goto DRUNK
b = sounding_smart_is_hard_after_drinking_this_many( bottles )
print bottles
print b
print "of beer on the wall\n"
print bottles
print b
print "of beer\nTake one down, pass it around\n"
dec bottles
b = sounding_smart_is_hard_after_drinking_this_many( bottles )
print bottles
print b
print "of beer on the wall\n\n"
goto LUSH
DRUNK:
end
.end
Plain English
To run:
Start up.
Sing 99 of bottles of beer on the wall.
Wait for the escape key.
Shut down.
To sing a number of bottles of beer on the wall:
Put the number into a counter.
Loop.
Write the first line given the counter.
Write the second line given the counter.
Write "Take one down, pass it around" to the console.
Subtract 1 from the counter.
Write the first line given the counter.
If the counter is 0, break.
Write "" on the console.
Repeat.
To write the first line given a counter:
If the counter is 0, write "No more bottles of beer on the wall" to the console; exit.
If the counter is 1, write "1 bottle of beer on the wall" to the console; exit.
Write the counter then " bottles of beer on the wall" to the console.
To write the second line given a counter:
If the counter is 1, write "1 bottle of beer" to the console; exit.
Write the counter then " bottles of beer" to the console.
Plain TeX
\def\ifbeer{\ifnum\number\bottles}
\def\beers{
\par\ifbeer>0 \the\bottles~\else No more \fi
bottle\ifbeer=1\else s\fi~of beer%
}
\def\take #1 down,{
\par\advance\bottles by -#1
Take #1 down, pass it around,\par
}
\long\def\verse{
\beers~on the wall, \beers.
\take 1 down, % curious TeX \def syntax
\beers~on the wall.
\bigskip
}
\newcount\bottles\bottles99
\loop\verse
\ifnum\number\bottles>0\repeat
\bye
PL/I
bottles: procedure options(main);
nBottles: procedure(n);
declare n fixed;
if n = 0 then
put skip list('No more bottles');
else if n = 1 then
put skip list('1 bottle');
else do;
if n < 10 then
put skip edit(n) (F(1));
else
put skip edit(n) (F(2));
put list('bottles');
end;
end nBottles;
takeDown: procedure(n);
declare n fixed;
put skip list('Take');
if n=1 then
put list('it');
else
put list('one');
put list('down and take it around,');
end takeDown;
declare n fixed;
do n=99 by -1 to 1;
call nBottles(n);
put list('of beer on the wall,');
call nBottles(n);
put list('of beer,');
call takeDown(n);
call nBottles(n-1);
put list('of beer on the wall.');
put skip;
end;
end bottles;
PL/M
100H: /* CP/M ORIGIN */
BDOS: PROCEDURE(F,PARAM); /* CALL CP/M BDOS */
DECLARE F BYTE;
DECLARE PARAM ADDRESS;
GO TO 5;
END BDOS;
DECLARE BDOS$EXIT LITERALLY '0'; /* BDOS FUNCTIONS */
DECLARE BDOS$PUTS LITERALLY '9';
PRINT$BYTE: PROCEDURE(N); /* PRINT A DECIMAL BYTE */
DECLARE (N, D) BYTE, S (5) BYTE INITIAL ('... $');
DECLARE P ADDRESS, C BASED P BYTE;
P = .S(3);
DIGIT:
P = P - 1;
C = (N MOD 10) + 48;
N = N / 10;
IF N > 0 THEN GO TO DIGIT;
CALL BDOS(BDOS$PUTS, P);
END PRINT$BYTE;
PRINT$STR: PROCEDURE(S); /* PRINT A STRING */
DECLARE S ADDRESS;
CALL BDOS(BDOS$PUTS, S);
END PRINT$STR;
N$OF$BOTTLES: PROCEDURE(N); /* PRINT _N_ BOTTLES */
DECLARE N BYTE;
IF N = 0 THEN CALL PRINT$STR(.('NO MORE$'));
ELSE IF N = 1 THEN CALL PRINT$STR(.('1 BOTTLE$'));
ELSE DO;
CALL PRINT$BYTE(N);
CALL PRINT$STR(.('BOTTLES$'));
END;
END N$OF$BOTTLES;
TAKE$DOWN: PROCEDURE(N); /* PRINT TAKE (ONE/IT) DOWN */
DECLARE N BYTE;
CALL PRINT$STR(.('TAKE $'));
IF N=1 THEN CALL PRINT$STR(.('IT$'));
ELSE CALL PRINT$STR(.('ONE$'));
CALL PRINT$STR(.(' DOWN AND PASS IT AROUND',13,10,'$'));
END TAKE$DOWN;
DECLARE OF$BEER DATA (' OF BEER$');
DECLARE ON$WALL DATA (' ON THE WALL',13,10,'$');
DECLARE NEWLINE DATA (13,10,'$');
DECLARE BOTTLES BYTE INITIAL (99);
DO WHILE BOTTLES > 0;
CALL N$OF$BOTTLES(BOTTLES);
CALL PRINT$STR(.OF$BEER);
CALL PRINT$STR(.ON$WALL);
CALL N$OF$BOTTLES(BOTTLES);
CALL PRINT$STR(.OF$BEER);
CALL PRINT$STR(.NEWLINE);
CALL TAKE$DOWN(BOTTLES);
BOTTLES = BOTTLES - 1;
CALL N$OF$BOTTLES(BOTTLES);
CALL PRINT$STR(.OF$BEER);
CALL PRINT$STR(.ON$WALL);
CALL PRINT$STR(.NEWLINE);
END;
CALL BDOS(BDOS$EXIT,0);
EOF
Pointless
-----------------------------------------------------------
-- Print the lyrics to the song '99 bottles of beer'
output =
range(99, 1)
|> map(showBeer)
|> printLines
beerFmt = """{} of beer on the wall!
{} of beer!
You take one down, pass it around
{}"""
showBeer(n) =
format(
beerFmt,
[showBottle(n), showBottle(n), nextBeer(n - 1)]
)
nextBeer(n) =
if n == 0 then "No more bottles of beer on the wall!"
else format("{} of beer on the wall!\n", [showBottle(n)])
-----------------------------------------------------------
-- Get appropriate singular / plural form of 'n bottle(s)'
showBottle(n) =
format("{} {}", [n, bottleStr])
where bottleStr = if n == 1 then "bottle" else "bottles"
Pony
Recursive
actor Main
let _env: Env
new create(env: Env) =>
_env = env
bottles(99)
be bottles(n: U32) =>
if n == 0 then
_env.out.print("No more bottles of beer on the wall, no more bottles of beer.")
_env.out.print("Go to the store and buy some more, 99 bottles of beer on the wall.")
else
if n == 1 then
_env.out.print("1 bottle of beer on the wall, 1 bottle of beer.")
_env.out.print("Take one down and pass it around, no more bottles of beer on the wall.\n")
else
_env.out.print(n.string() + " bottles of beer on the wall, " + n.string() + " bottles of beer.")
_env.out.print("Take one down and pass it around, "+ (n - 1).string() +" bottles of beer on the wall.\n")
end
bottles(n-1)
end
Iterative
actor Main
let _env: Env
new create(env: Env) =>
_env = env
var n: I32 = 99
repeat
if n == 0 then
_env.out.print("No more bottles of beer on the wall, no more bottles of beer.")
_env.out.print("Go to the store and buy some more, 99 bottles of beer on the wall.")
elseif n == 1 then
_env.out.print("1 bottle of beer on the wall, 1 bottle of beer.")
_env.out.print("Take one down and pass it around, no more bottles of beer on the wall.\n")
else
_env.out.print(n.string() + " bottles of beer on the wall, " + n.string() + " bottles of beer.")
_env.out.print("Take one down and pass it around, "+ (n - 1).string() +" bottles of beer on the wall.\n")
end
n = n - 1
until n < 0 end
Pop11
define bootles(n);
while n > 0 do
printf(n, '%p bottles of beer on the wall\n');
printf(n, '%p bottles of beer\n');
printf('Take one down, pass it around\n');
n - 1 -> n;
printf(n, '%p bottles of beer on the wall\n');
endwhile;
enddefine;
bootles(99);
PostScript
%!PS
/Helvetica findfont 9 scalefont setfont
/printBeer {
dup
20 string cvs show
( bottle) show
1 ne
{ (s) show } if
( of beer) show
} def
/printVerse {
dup
dup
dup
7 mul
50 add
/yPos exch def
15 yPos moveto
printBeer
( on the wall, ) show
printBeer
(. ) show
(Take one down, pass it around, ) show
1 sub
printBeer
( on the wall. ) show
} def
/song {
100 -1 1 { printVerse } for
} def
song
showpage
%%EOF
Potion
No extra credit.
99 to 1 (i) :
verse = (n) :
(n, " bottles of beer on the wall\n"
n, " bottles of beer\n"
"Take one down, pass it around\n"
n - 1, " bottles of beer on the wall\n")
.
verse(i) join print
"\n" print
.
PowerShell
Processing
Console output
Immediately prints all output to the console.
for (int i = 99; i > 0; i--) {
print(i + " bottles of beer on the wall\n"
+ i + " bottles of beer\nTake one down, pass it around\n"
+ (i - 1) + " bottles of beer on the wall\n\n");
}
Visual and animated
This approach uses Processing's draw loop to display text on the sketch canvas, with a global counter for bottles--draw() is called at the default 60fps, and acts as the for loop. One round of lyrics is displayed at a time, and the counter advances by checking Processing's built-in frameCount. Lyrics may also be advanced manually by clicking the mouse on the canvas.
int i = 99;
void setup() {
size(200, 140);
}
void draw() {
background(0);
text(i + " bottles of beer on the wall\n"
+ i + " bottles of beer\nTake one down, pass it around\n"
+ (i-1) + " bottles of beer on the wall\n\n",
10, 20);
if (frameCount%240==239) next(); // auto-advance every 4 secs
}
void mouseReleased() {
next(); // manual advance
}
void next() {
i = max(i-1, 1); // stop decreasing at 1-0 bottles
}
Processing Python mode
i = 99
def setup():
size(200, 140)
def draw():
background(0)
text("{} bottles of beer on the wall\n".format(i) +
"{} bottles of beer\n".format(i) +
"Take one down, pass it around\n" +
"{} bottles of beer on the wall\n\n".format(i - 1),
10, 20)
if frameCount % 240 == 239: # auto-advance every 4 secs
next()
def mouseReleased():
next() # manual advance
def next():
global i
i = max(i - 1, 1) # stop decreasing at 1-0 bottles
Processing.R
Console output
setup <- function() {
stdout$print(bottlesong(99))
}
bottlesong <- function(num) {
verses = ""
for(i in num:1){
verses = paste0(verses,
num," bottles of beer on the wall \n",
num," bottles of beer \n",
"Take one down, pass it around \n",
num-1, " bottles of beer on the wall \n\n", sep="");
num <- num - 1
}
return(verses)
}
ProDOS
Prolog
Python
One line
Short, one-line version.
for i in range(99, 0, -1):b='bottles of beer';w=f' {b} on the wall';print(f'{i}{w}, {i} {b}\nTake one down and pass it around, {i-1}{w}.\n')
Pythonic version
VERSE = '''\
{n} bottle{s} of beer on the wall
{n} bottle{s} of beer
Take one down, pass it around
{n_minus_1} bottle{s2} of beer on the wall
'''
for n in range(99, 0, -1):
if n == 1:
n_minus_1 = 'No more'
s = ''
s2 = 's'
elif n == 2:
n_minus_1 = n - 1;
s = 's'
s2 = ''
else:
n_minus_1 = n - 1;
s = 's'
s2 = 's'
print(VERSE.format(n=n, s=s, s2=s2, n_minus_1=n_minus_1))
Functional
'''99 Units of Disposable Asset'''
from itertools import chain
# main :: IO ()
def main():
'''Modalised asset dispersal procedure.'''
# localisation :: (String, String, String)
localisation = (
'on the wall',
'Take one down, pass it around',
'Better go to the store to buy some more'
)
print(unlines(map(
incantation(localisation),
enumFromThenTo(99)(98)(0)
)))
# incantation :: (String, String, String) -> Int -> String
def incantation(localisation):
'''Versification of asset disposal
and inventory update.'''
location, distribution, solution = localisation
def inventory(n):
return unwords([asset(n), location])
return lambda n: solution if 0 == n else (
unlines([
inventory(n),
asset(n),
distribution,
inventory(pred(n))
])
)
# asset :: Int -> String
def asset(n):
'''Quantified asset.'''
def suffix(n):
return [] if 1 == n else 's'
return unwords([
str(n),
concat(reversed(concat(cons(suffix(n))(["elttob"]))))
])
# GENERIC -------------------------------------------------
# concat :: [[a]] -> [a]
# concat :: [String] -> String
def concat(xxs):
'''The concatenation of all the elements in a list.'''
xs = list(chain.from_iterable(xxs))
unit = '' if isinstance(xs, str) else []
return unit if not xs else (
''.join(xs) if isinstance(xs[0], str) else xs
)
# cons :: a -> [a] -> [a]
def cons(x):
'''Construction of a list from x as head,
and xs as tail.'''
return lambda xs: [x] + xs if (
isinstance(xs, list)
) else chain([x], xs)
# enumFromThenTo :: Int -> Int -> Int -> [Int]
def enumFromThenTo(m):
'''Integer values enumerated from m to n
with a step defined by nxt-m.'''
def go(nxt, n):
d = nxt - m
return list(range(m, d + n, d))
return lambda nxt: lambda n: (
go(nxt, n)
)
# pred :: Enum a => a -> a
def pred(x):
'''The predecessor of a value. For numeric types, (- 1).'''
return x - 1 if isinstance(x, int) else (
chr(ord(x) - 1)
)
# unlines :: [String] -> String
def unlines(xs):
'''A single string derived by the intercalation
of a list of strings with the newline character.'''
return '\n'.join(xs)
# unwords :: [String] -> String
def unwords(xs):
'''A space-separated string derived from
a list of words.'''
return ' '.join(xs)
if __name__ == '__main__':
main()
Functional, pythonic version
Inspired by Functional version
"""
99 Bottles of Beer on the Wall made functional
Main function accepts a number of parameters, so you can specify a name of
the drink, its container and other things. English only.
"""
from functools import partial
from typing import Callable
def regular_plural(noun: str) -> str:
"""English rule to get the plural form of a word"""
if noun[-1] == "s":
return noun + "es"
return noun + "s"
def beer_song(
*,
location: str = 'on the wall',
distribution: str = 'Take one down, pass it around',
solution: str = 'Better go to the store to buy some more!',
container: str = 'bottle',
plurifier: Callable[[str], str] = regular_plural,
liquid: str = "beer",
initial_count: int = 99,
) -> str:
"""
Return the lyrics of the beer song
:param location: initial location of the drink
:param distribution: specifies the process of its distribution
:param solution: what happens when we run out of drinks
:param container: bottle/barrel/flask or other containers
:param plurifier: function converting a word to its plural form
:param liquid: the name of the drink in the given container
:param initial_count: how many containers available initially
"""
verse = partial(
get_verse,
initial_count = initial_count,
location = location,
distribution = distribution,
solution = solution,
container = container,
plurifier = plurifier,
liquid = liquid,
)
verses = map(verse, range(initial_count, -1, -1))
return '\n\n'.join(verses)
def get_verse(
count: int,
*,
initial_count: str,
location: str,
distribution: str,
solution: str,
container: str,
plurifier: Callable[[str], str],
liquid: str,
) -> str:
"""Returns the verse for the given amount of drinks"""
asset = partial(
get_asset,
container = container,
plurifier = plurifier,
liquid = liquid,
)
current_asset = asset(count)
next_number = count - 1 if count else initial_count
next_asset = asset(next_number)
action = distribution if count else solution
inventory = partial(
get_inventory,
location = location,
)
return '\n'.join((
inventory(current_asset),
current_asset,
action,
inventory(next_asset),
))
def get_inventory(
asset: str,
*,
location: str,
) -> str:
"""
Used to return the first or the fourth line of the verse
>>> get_inventory("10 bottles of beer", location="on the wall")
"10 bottles of beer on the wall"
"""
return ' '.join((asset, location))
def get_asset(
count: int,
*,
container: str,
plurifier: Callable[[str], str],
liquid: str,
) -> str:
"""
Quantified asset
>>> get_asset(0, container="jar", plurifier=regular_plural, liquid='milk')
"No more jars of milk"
"""
containers = plurifier(container) if count != 1 else container
spelled_out_quantity = str(count) if count else "No more"
return ' '.join((spelled_out_quantity, containers, "of", liquid))
if __name__ == '__main__':
print(beer_song())
- Output:
>>> print(beer_song( liquid = 'milk', location = 'in the fridge', container = 'jug', distribution = 'Take one out, pass it around', initial_count = 2, )) 2 jugs of milk in the fridge 2 jugs of milk Take one out, pass it around 1 jug of milk in the fridge 1 jug of milk in the fridge 1 jug of milk Take one out, pass it around No more jugs of milk in the fridge No more jugs of milk in the fridge No more jugs of milk Better go to the store to buy some more! 2 jugs of milk in the fridge
Flexible, OOP, multiprocessing version (exercise of style)
Inspired by the Functional Pythonic Version
"""
Excercise of style. An overkill for the task :-D
1. OOP, with abstract class and implementation with much common magic methods
2. you can customize:
a. the initial number
b. the name of the item and its plural
c. the string to display when there's no more items
d. the normal action
e. the final action
f. the template used, for foreign languages
3. strofas of the song are created with multiprocessing
4. when you launch it as a script, you can specify an optional parameter for
the number of initial items
"""
from string import Template
from abc import ABC, abstractmethod
from multiprocessing.pool import Pool as ProcPool
from functools import partial
import sys
class Song(ABC):
@abstractmethod
def sing(self):
"""
it must return the song as a text-like object
"""
pass
class MuchItemsSomewhere(Song):
eq_attrs = (
"initial_number",
"zero_items",
"action1",
"action2",
"item",
"items",
"strofa_tpl"
)
hash_attrs = eq_attrs
repr_attrs = eq_attrs
__slots__ = eq_attrs + ("_repr", "_hash")
def __init__(
self,
items = "bottles of beer",
item = "bottle of beer",
where = "on the wall",
initial_number = None,
zero_items = "No more",
action1 = "Take one down, pass it around",
action2 = "Go to the store, buy some more",
template = None,
):
initial_number_true = 99 if initial_number is None else initial_number
try:
is_initial_number_int = (initial_number_true % 1) == 0
except Exception:
is_initial_number_int = False
if not is_initial_number_int:
raise ValueError("`initial_number` parameter must be None or a int-like object")
if initial_number_true < 0:
raise ValueError("`initial_number` parameter must be >=0")
true_tpl = template or """\
$i $items1 $where
$i $items1
$action
$j $items2 $where"""
strofa_tpl_tmp = Template(true_tpl)
strofa_tpl = Template(strofa_tpl_tmp.safe_substitute(where=where))
self.zero_items = zero_items
self.action1 = action1
self.action2 = action2
self.initial_number = initial_number_true
self.item = item
self.items = items
self.strofa_tpl = strofa_tpl
self._hash = None
self._repr = None
def strofa(self, number):
zero_items = self.zero_items
item = self.item
items = self.items
if number == 0:
i = zero_items
action = self.action2
j = self.initial_number
else:
i = number
action = self.action1
j = i - 1
if i == 1:
items1 = item
j = zero_items
else:
items1 = items
if j == 1:
items2 = item
else:
items2 = items
return self.strofa_tpl.substitute(
i = i,
j = j,
action = action,
items1 = items1,
items2 = items2
)
def sing(self):
with ProcPool() as proc_pool:
strofa = self.strofa
initial_number = self.initial_number
args = range(initial_number, -1, -1)
return "\n\n".join(proc_pool.map(strofa, args))
def __copy__(self, *args, **kwargs):
return self
def __deepcopy__(self, *args, **kwargs):
return self
def __eq__(self, other, *args, **kwargs):
if self is other:
return True
getmyattr = partial(getattr, self)
getotherattr = partial(getattr, other)
eq_attrs = self.eq_attrs
for attr in eq_attrs:
val = getmyattr(attr)
try:
val2 = getotherattr(attr)
except Exception:
return False
if attr == "strofa_tpl":
val_true = val.safe_substitute()
val2_true = val.safe_substitute()
else:
val_true = val
val2_true = val
if val_true != val2_true:
return False
return True
def __hash__(self, *args, **kwargs):
_hash = self._hash
if _hash is None:
getmyattr = partial(getattr, self)
attrs = self.hash_attrs
hash_true = self._hash = hash(tuple(map(getmyattr, attrs)))
else:
hash_true = _hash
return hash_true
def __repr__(self, *args, **kwargs):
_repr = self._repr
if _repr is None:
repr_attrs = self.repr_attrs
getmyattr = partial(getattr, self)
attrs = []
for attr in repr_attrs:
val = getmyattr(attr)
if attr == "strofa_tpl":
val_true = val.safe_substitute()
else:
val_true = val
attrs.append(f"{attr}={repr(val_true)}")
repr_true = self._repr = f"{self.__class__.__name__}({', '.join(attrs)})"
else:
repr_true = _repr
return repr_true
def muchBeersOnTheWall(num):
song = MuchItemsSomewhere(initial_number=num)
return song.sing()
def balladOfProgrammer(num):
"""
Prints
"99 Subtle Bugs in Production"
or
"The Ballad of Programmer"
"""
song = MuchItemsSomewhere(
initial_number = num,
items = "subtle bugs",
item = "subtle bug",
where = "in Production",
action1 = "Debug and catch, commit a patch",
action2 = "Release the fixes, wait for some tickets",
zero_items = "Zarro",
)
return song.sing()
def main(num):
print(f"### {num} Bottles of Beers on the Wall ###")
print()
print(muchBeersOnTheWall(num))
print()
print()
print('### "The Ballad of Programmer", by Marco Sulla')
print()
print(balladOfProgrammer(num))
if __name__ == "__main__":
# Ok, argparse is **really** too much
argv = sys.argv
if len(argv) == 1:
num = None
elif len(argv) == 2:
try:
num = int(argv[1])
except Exception:
raise ValueError(
f"{__file__} parameter must be an integer, or can be omitted"
)
else:
raise RuntimeError(f"{__file__} takes one parameter at max")
main(num)
__all__ = (Song.__name__, MuchItemsSomewhere.__name__, muchBeersOnTheWall.__name__, balladOfProgrammer.__name__)
Other solutions
Q
bobw:{[n] {x," bottles of beer on the wall\n",x," bottles of beer\nTake one down, pass it around\n",y," bottles of beer on the wall\n\n"} . string (n;n-1)}
-1 bobw each reverse 1 + til 99
QB64
[NOTE]: The code below is an amazing, full-on media event! For a simpler version, click HERE.
SCREEN _NEWIMAGE(800, 600, 32)
CONST BottleSpeed = 3
PLAY "<"
MakeBottle
ScaleImage bottle&, .5, .5
t1 = _FREETIMER
ON TIMER(t1, 0.01) DrawBottle
TIMER(t1) ON
FOR x = 99 TO 1 STEP -1
CLS
LOCATE , 35: PRINT x; "bottles of beer on the wall"
: PLAY "e-8e-8e-8<b-8b-8b-8>e-8e-8e-8e-4"
LOCATE , 35: PRINT x; "bottles of beer"
PLAY "f8f8f8c8c8c8f4"
LOCATE , 35: PRINT " Take one down, pass it around"
PLAY "d4d8d8 d8d8d8d4"
LOCATE , 35: PRINT x - 1; "bottles of beer on the wall"
PLAY "<a+8a+8a+8>c8c8d8d+8d+8d+8d+4"
IF INKEY$ <> "" THEN SYSTEM
NEXT x
CLS
LOCATE , 35: PRINT "Da fatman drunk all da beer on the wall!"
PLAY "e-8e-8e-8<b-8b-8b-8>e-8e-8e-8e-4"
LOCATE , 35: PRINT "Da fatman drunk it all!"
PLAY "f8f8f8c8c8c8f4"
LOCATE , 35: PRINT "Cuss da fatman, send him for more!"
PLAY "d4d8d8 d8d8d8d4"
LOCATE , 35: PRINT "Someone show him the way out the door!"
PLAY "<a+8a+8a+8>c8c8d8d+8d+8d+8d+4"
SUB MakeBottle
SHARED bottle&
bottle& = _NEWIMAGE(56, 144, 32)
_DEST bottle&
LOCATE 1, 1: PRINT " [=]";
LOCATE 2, 1: PRINT " | |";
LOCATE 3, 1: PRINT " }@{";
LOCATE 4, 1: PRINT " / \";
LOCATE 5, 1: PRINT ":_____;";
LOCATE 6, 1: PRINT "|&&&&&|";
LOCATE 7, 1: PRINT "|&&&&&|";
LOCATE 8, 1: PRINT "|-----|";
LOCATE 9, 1: PRINT "'-----'";
_DEST 0
END SUB
SUB ScaleImage (Image AS LONG, xscale AS SINGLE, yscale AS SINGLE)
w = _WIDTH(Image): h = _HEIGHT(Image)
w2 = w * xscale: h2 = h * yscale
NewImage& = _NEWIMAGE(w2, h2, 32)
_PUTIMAGE , Image&, NewImage&
_FREEIMAGE Image&
Image& = NewImage&
END SUB
SUB DrawBottle
SHARED x
SHARED bottle&
STATIC angle
LINE (0, 150)-(800, 600), _RGB32(0, 0, 0), BF
angle = angle + BottleSpeed
FOR i = 1 TO 20
FOR h = 1 TO 5
IF (h - 1) * 20 + (i - 1) < x THEN DisplayImage bottle&, i * 40 - 20, h * 75 + 150, angle, 0
NEXT
NEXT
_DISPLAY
END SUB
SUB DisplayImage (Image AS LONG, x AS INTEGER, y AS INTEGER, angle AS SINGLE, mode AS _BYTE)
'Image is the image handle which we use to reference our image.
'x,y is the X/Y coordinates where we want the image to be at on the screen.
'angle is the angle which we wish to rotate the image.
'mode determines HOW we place the image at point X,Y.
'Mode 0 we center the image at point X,Y
'Mode 1 we place the Top Left corner of oour image at point X,Y
'Mode 2 is Bottom Left
'Mode 3 is Top Right
'Mode 4 is Bottom Right
DIM px(3) AS INTEGER, py(3) AS INTEGER, w AS INTEGER, h AS INTEGER
DIM sinr AS SINGLE, cosr AS SINGLE, i AS _BYTE
w = _WIDTH(Image): h = _HEIGHT(Image)
SELECT CASE mode
CASE 0 'center
px(0) = -w \ 2: py(0) = -h \ 2: px(3) = w \ 2: py(3) = -h \ 2
px(1) = -w \ 2: py(1) = h \ 2: px(2) = w \ 2: py(2) = h \ 2
CASE 1 'top left
px(0) = 0: py(0) = 0: px(3) = w: py(3) = 0
px(1) = 0: py(1) = h: px(2) = w: py(2) = h
CASE 2 'bottom left
px(0) = 0: py(0) = -h: px(3) = w: py(3) = -h
px(1) = 0: py(1) = 0: px(2) = w: py(2) = 0
CASE 3 'top right
px(0) = -w: py(0) = 0: px(3) = 0: py(3) = 0
px(1) = -w: py(1) = h: px(2) = 0: py(2) = h
CASE 4 'bottom right
px(0) = -w: py(0) = -h: px(3) = 0: py(3) = -h
px(1) = -w: py(1) = 0: px(2) = 0: py(2) = 0
END SELECT
sinr = SIN(angle / 57.2957795131): cosr = COS(angle / 57.2957795131)
FOR i = 0 TO 3
x2 = (px(i) * cosr + sinr * py(i)) + x: y2 = (py(i) * cosr - px(i) * sinr) + y
px(i) = x2: py(i) = y2
NEXT
_MAPTRIANGLE (0, 0)-(0, h - 1)-(w - 1, h - 1), Image TO(px(0), py(0))-(px(1), py(1))-(px(2), py(2))
_MAPTRIANGLE (0, 0)-(w - 1, 0)-(w - 1, h - 1), Image TO(px(0), py(0))-(px(3), py(3))-(px(2), py(2))
END SUB
Qore
Simple Solution
#!/usr/bin/env qore
%enable-all-warnings
for (my $i = 99; $i > 0; $i--) {
printf("%d bottles of beer on the wall\n", $i);
printf("%d bottles of beer\n", $i);
printf("take one down, pass it around\n");
printf("%d bottles of beer on the wall\n", $i);
}
Concurrent (Unordered) Solution
#!/usr/bin/env qore
%enable-all-warnings
%require-types
# global variables (truly shared among threads) must be declared with "our" keyword
%require-our
our Counter $count();
sub t() {
on_exit {
$count.dec();
}
my int $i = gettid()-1;
printf("%d bottles of beer on the wall\n", $i);
printf("%d bottles of beer\n", $i);
printf("take one down, pass it around\n");
printf("%d bottles of beer on the wall\n", $i);
}
#-- following run by main thread
for (my int $i = 99; $i > 0; $i--) {
$count.inc();
background t();
}
$count.waitForZero();
Quackery
[ stack ] is bottles ( --> [ )
[ join carriage join ] is addline ( $ $ --> $ )
[ dup 0 = iff $ 'No more'
else [ dup number$ ]
$ ' bottle' join
swap 1 != if [ char s join ]
$ ' of beer ' join ] is beers ( n --> $ )
$ 'on the wall' is wall ( --> $ )
$ 'Take one down, pass it around'
is drink ( --> $ )
$ 'Go to the store, buy some more'
is restock ( --> $ )
[ dup beers wall addline
over beers addline
over 0 = iff
[ nip bottles share
swap restock ]
else drink addline
swap 1 -
beers wall join addline ] is verse ( n --> $ )
[ 1+ $ '' swap
dup bottles put
times [ i verse addline ]
bottles release ] is song ( n --> $ )
say 'The song "99 Bottles of Beer on the Wall":' cr cr
99 song echo$
Quill
bottles := void(int count) {
(count > 0) if {
new_count := count - 1;
(
count, " bottles of beer on the wall", nl,
count, " bottles of beer", nl,
"Take one down, pass it around", nl,
new_count, " bottles of beer on the wall"
) print;
new_count bottles
} else {
"No more bottles of beer on the wall!" print
}
};
99 bottles
Quite BASIC
With grammatical support for "1 bottle of beer"
10 let w=" on the wall"
20 for n=99 to 1 step -1
30 let b=" bottles of beer"
40 if n=1 then let b=" bottle of beer"
50 print n;b;w
60 print n;b
70 print "Take one down, pass it around"
80 if n-1=1 then let b=" bottle of beer"
90 if n-1=0 then let b=" bottles of beer"
100 print n-1;b;w
110 next n
Without grammatical support for "1 bottle of beer"
10 let b=" bottles of beer"
20 let w=" on the wall"
30 for n=99 to 1 step -1
40 print n;b;w
50 print n;b
60 print "Take one down, pass it around"
70 print n-1;b;w
80 next n
R
Simple looping solution
#a naive function to sing for N bottles of beer...
song = function(bottles){
for(i in bottles:1){ #for every integer bottles, bottles-1 ... 1
cat(bottles," bottles of beer on the wall \n",bottles," bottles of beer \nTake one down, pass it around \n",
bottles-1, " bottles of beer on the wall \n"," \n" ,sep="") #join and print the text (\n means new line)
bottles = bottles - 1 #take one down...
}
}
song(99)#play the song by calling the function
Vector solutions
#only one line!
cat(paste(99:1,ifelse((99:1)!=1," bottles"," bottle")," of beer on the wall\n",99:1,ifelse((99:1)!=1," bottles"," bottle")," of beer\n","Take one down, pass it around\n",98:0,ifelse((98:0)!=1," bottles"," bottle")," of beer on the wall\n\n",sep=""),sep="")
#alternative
cat(paste(lapply(99:1,function(i){paste(paste(rep(paste(i,' bottle',if(i!=1)'s',' of beer',sep=''),2),collapse =' on the wall\n'),'Take one down, pass it around',paste(i-1,' bottle',if(i!=2)'s',' of beer on the wall',sep=''), sep='\n')}),collapse='\n\n'))
#code golf - minimal characters
k=paste0;a=" bottles of beer";o=sub("s","",a);w=" on the wall\n";b=k(a,w);r=k(o,w);t="\nTake one down, pass it around\n";l=99:3;cat(k(l,b,l,a,t,l-1,b),k(2,b,2,a,t,1,r),k(1,r,1,o,t,0,b))
Ra
class BottlesOfBeer
**Prints the "99 Bottles of Beer" song"**
on start
args := program arguments
# If no arguments given, print the song once
if args empty
.printSong
# Otherwise, print the song the given number of times
else
.printSong(integer.parse(args[0]))
shared
define printSong(times := 1)
**Print the song the given number of times**
for times, _printSong
define _printSong
**Print the song**
# Print for bottles 99 to 1
for bottle in 99 to 0 by -1
print "[_bottles(bottle)] of beer on the wall
[_bottles(bottle)] of beer
Take one down, pass it around
[_bottles(bottle - 1)] of beer on the wall
"
print "No more bottles of beer on the wall
No more bottles of beer
Go to the store, buy some more
99 bottles of beer on the wall"
define _bottles(bottle as integer) as String
**
If bottle is 0, returns "No more bottles"
If bottle is 1, returns "1 bottle"
Otherwise, returns "[bottle] bottles"
**
if bottle = 0, return "No more bottles"
if bottle = 1, return "1 bottle"
return "[bottle] bottles"
Racket
#lang racket
(define (sing bottles)
(define (plural n) (~a n " bottle" (if (= n 1) "" "s")))
(printf "~a of beer on the wall\n~a of beer\n~
Take one down, pass it around\n~a of beer on the wall\n\n"
(plural bottles) (plural bottles) (plural (sub1 bottles)))
(unless (= 1 bottles) (sing (sub1 bottles))))
(sing 99)
Raku
(formerly Perl 6)
A Simple Way
my $b = 99;
repeat while --$b {
say "{b $b} on the wall";
say "{b $b}";
say "Take one down, pass it around";
say "{b $b-1} on the wall";
say "";
}
sub b($b) {
"$b bottle{'s' if $b != 1} of beer";
}
A Clearer Way
Similar to "A Simple Way", but with proper variable and subroutine naming, declarator documentation, strongly-typed function definition, better code reuse, and external ternary logic.
for 99...1 -> $bottles {
sing $bottles, :wall;
sing $bottles;
say "Take one down, pass it around";
sing $bottles - 1, :wall;
say "";
}
#| Prints a verse about a certain number of beers, possibly on a wall.
sub sing(
Int $number, #= Number of bottles of beer.
Bool :$wall, #= Mention that the beers are on a wall?
) {
my $quantity = $number == 0 ?? "No more" !! $number;
my $plural = $number == 1 ?? "" !! "s";
my $location = $wall ?? " on the wall" !! "";
say "$quantity bottle$plural of beer$location"
}
A More Extravagant Way
my @quantities = flat (99 ... 1), 'No more', 99;
my @bottles = flat 'bottles' xx 98, 'bottle', 'bottles' xx 2;
my @actions = flat 'Take one down, pass it around' xx 99,
'Go to the store, buy some more';
for @quantities Z @bottles Z @actions Z
@quantities[1 .. *] Z @bottles[1 .. *]
-> ($a, $b, $c, $d, $e) {
say "$a $b of beer on the wall";
say "$a $b of beer";
say $c;
say "$d $e of beer on the wall\n";
}
RapidQ
dim nBott as integer
nBott = 99
While nBott > 0
Print(str$(nBott ) + " bottle" + iif(nBott=1, "", "s") + " of beer on the wall")
Print(str$(nBott ) + " bottle" + iif(nBott=1, "", "s") + " of beer")
Print("Take one down, pass it around")
nBott--
Print(str$(nBott ) + " bottle" + iif(nBott=1, "", "s") + " of beer on the wall" + chr$(10))
Wend
while inkey$="":wend
end
Rascal
module demo::basic::Bottles
import IO;
str bottles(0) = "no more bottles";
str bottles(1) = "1 bottle";
default str bottles(int n) = "<n> bottles";
public void sing(){
for(n <- [99 .. 1]){
println("<bottles(n)> of beer on the wall, <bottles(n)> of beer.");
println("Take one down, pass it around, <bottles(n-1)> of beer on the wall.\n");
}
println("No more bottles of beer on the wall, no more bottles of beer.");
println("Go to the store and buy some more, 99 bottles of beer on the wall.");
}
Raven
99 0 1 range each as $i
$i 1 = if
"bottle" as $b
else
"bottles" format as $b
$b $i "%d %s of beer on the wall,\n" print
$b $i "%d %s of beer,\n" print
"Take one down, pass it around,\n" print
$i 2 = if
"1 bottle"
else
$i 1 - "%d bottles" format
"%s of beer on the wall.\n\n" print
- Output:
Last couple of stanzas are:
3 bottles of beer on the wall, 3 bottles of beer, Take one down, pass it around, 2 bottles of beer on the wall. 2 bottles of beer on the wall, 2 bottles of beer, Take one down, pass it around, 1 bottle of beer on the wall. 1 bottle of beer on the wall, 1 bottle of beer, Take one down, pass it around, 0 bottles of beer on the wall.
REBOL
rebol [
Title: "99 Bottles of Beer"
URL: http://rosettacode.org/wiki/99_Bottles_of_Beer
]
; The 'bottles' function maintains correct grammar.
bottles: func [n /local b][
b: either 1 = n ["bottle"]["bottles"]
if 0 = n [n: "no"]
reform [n b]
]
for n 99 1 -1 [print [
bottles n "of beer on the wall" crlf
bottles n "of beer" crlf
"Take one down, pass it around" crlf
bottles n - 1 "of beer on the wall" crlf
]]
Output (selected highlights):
99 bottles of beer on the wall 2 bottles of beer on the wall 99 bottles of beer 2 bottles of beer Take one down, pass it around Take one down, pass it around 98 bottles of beer on the wall 1 bottle of beer on the wall ...Continues... 1 bottle of beer on the wall 1 bottle of beer Take one down, pass it around no bottles of beer on the wall
This one prints with proper grammar. "Bottles" changed to "bottle" at the end of the 2 line, and throughout the 1 line. 0 changed to "No" in the last line:
for i 99 1 -1 [
x: rejoin [
i b: " bottles of beer" o: " on the wall. " i b
". Take one down, pass it around. " (i - 1) b o "^/"
]
r: :replace j: "bottles" k: "bottle"
switch i [1 [r x j k r at x 10 j k r x "0" "No"] 2 [r at x 40 j k]]
print x
] halt
Here's a simple 1 line console version:
for i 99 1 -1[print rejoin[i b:" bottles of beer"o:" on the wall. "i b". Take one down, pass it around. "(i - 1)b o"^/"]]
Red
Red [
Title: "99 Bottles of Beer"
Original-Author: oofoe
]
; The 'bottles' function maintains correct grammar.
bottles: function [n] [
b: either 1 = n ["bottle"]["bottles"]
if 0 = n [n: "no"]
form reduce [n b]
]
repeat x 99 [
n: 100 - x
print [
bottles n "of beer on the wall" crlf
bottles n "of beer" crlf
"Take one down, pass it around" crlf
bottles n - 1 "of beer on the wall" crlf
]]
Refal
$ENTRY Go {
= <Prout <Verses 99>>;
};
Verses {
'-'1 = ;
s.1 = <Verse s.1>
<Verses <- s.1 1>>;
};
Verse {
s.1 = <Bottles s.1> ' of beer on the wall,\n'
<Bottles s.1> ' of beer,\n'
<ThirdLine s.1> '\n'
<Bottles <- s.1 1>> ' of beer on the wall!\n\n';
};
Bottles {
'-'1 = '99 bottles';
0 = 'No more bottles';
1 = '1 bottle';
s.1 = s.1 'bottles';
};
ThirdLine {
0 = 'Go to the store and buy some more,';
1 = 'Take it down and pass it around,';
s.1 = 'Take one down and pass it around,';
};
Relation
program beer(n)
if n>1
echo n." bottles of beer on the wall"
echo n." bottles of beer"
else
echo "1 bottle of beer on the wall"
echo "1 bottle of beer"
end if
echo "Take one down, pass it around"
if n > 2
echo format(n-1,"%1d")." bottles of beer on the wall"
else
echo format(n-1,"%1d")." bottle of beer on the wall"
end if
echo " "
end program
set i = 99
while i > 0
run beer(i)
set i = i-1
end while
Retro
This is based on the Forth example.
# 99 Bottles
Display the text for the *99 Bottles of Beer* song.
~~~
{ 'bottle 'bottles 'of 'beer 'on 'the 'wall 'no 'more
'Take 'one 'down, 'pass 'it 'around }
[ dup ':%s_'%s_s:put_sp_; s:format s:evaluate ] a:for-each
{ [ no more bottles ]
[ #1 n:put sp bottle ]
[ dup n:put sp bottles ]
} 'BOTTLES const
:number-bottles
dup #2 n:min BOTTLES swap a:fetch call ;
:display-verse
number-bottles of beer on the wall nl
number-bottles of beer nl
n:dec Take one down, pass it around nl
number-bottles of beer on the wall nl ;
:verses (n-)
repeat 0; nl display-verse again ;
#99 verses
~~~
REXX
Complete with a PSA (Public Service Announcement) comment.
/*REXX program displays lyrics to the infamous song "99 Bottles of Beer on the Wall". */
parse arg N .; if N=='' | N=="," then N=99 /*allow number of bottles be specified.*/
/* [↓] downward count of beer bottles.*/
do #=N by -1 for N /*start the countdown and singdown. */
say # 'bottle's(#) "of beer on the wall," /*sing the number bottles of beer. */
say # 'bottle's(#) "of beer." /* ··· and also the song's refrain.*/
say 'Take one down, pass it around,' /*take a beer bottle ─── and share it.*/
m= # - 1 /*M: the number of bottles we have now*/
if m==0 then m= 'no' /*use word "no" instead of numeric 0.*/
say m 'bottle's(m) "of beer on the wall." /*sing the beer bottle inventory. */
say /*show a blank line between the verses.*/
end /*#*/ /*PSA: Please drink responsibly. */
/*Not quite tanked? Then sing it. */
say 'No more bottles of beer on the wall,' /*Finally! The last verse. */
say 'no more bottles of beer.' /*this is sooooooo sad and forlorn ··· */
say 'Go to the store and buy some more,' /*obtain replenishment of the beer. */
say N 'bottles of beer on the wall.' /*all is well in the ole town tavern. */
exit /*we're all done, and also sloshed !. */
/*──────────────────────────────────────────────────────────────────────────────────────*/
s: if arg(1)=1 then return ''; return 's' /*simple pluralizer for gooder English.*/
- output Below is the first and last three verses of the song:
99 bottles of beer on the wall, 99 bottles of beer. Take one down, pass it around, 98 bottles of beer on the wall. 98 bottles of beer on the wall, 98 bottles of beer. Take one down, pass it around, 97 bottles of beer on the wall. 97 bottles of beer on the wall, 97 bottles of beer. Take one down, pass it around, 96 bottles of beer on the wall. ∙ ∙ ∙ 2 bottles of beer on the wall, 2 bottles of beer. Take one down, pass it around, 1 bottle of beer on the wall. 1 bottle of beer on the wall, 1 bottle of beer. Take one down, pass it around, no bottles of beer on the wall. No more bottles of beer on the wall, no more bottles of beer. Go to the store and buy some more, 99 bottles of beer on the wall.
Ring
This is a simple solution
for i = 99 to 0 step -1
switch i
on 0
see "No more bottles of beer on the wall,
no more bottles of beer.
Go to the store and buy some more, 99 bottles of beer on the wall."
on 1
see "1 bottle of beer on the wall,
1 bottle of beer.
Take one down and pass it around,
No more bottles of beer on the wall.
"
other
see string(i) + " bottles of beer on the wall,
" + string(i) + " bottles of beer.
Take one down and pass it around,
" + string(i-1) + " bottles of beer on the wall.
"
off
next
- Output:
99 bottles of beer on the wall, 99 bottles of beer. Take one down, pass it around, 98 bottles of beer on the wall. ∙ ∙ ∙ 1 bottle of beer on the wall, 1 bottle of beer. Take one down, pass it around, no bottles of beer on the wall. No more bottles of beer on the wall, no more bottles of beer. Go to the store and buy some more, 99 bottles of beer on the wall.
Rockstar
Rockstar solution without special cases for the last 2 verses.
Love is " bottles of beer on the wall"
Problems are " bottles of beer"
Carol says Take one down, pass it around
The beers were numbering fa'too'many
While the beers ain't nothing
Shout it with Love
Shout it with Problems
Say Carol,
Knock the beers down
Say it with Love
RPG
H/TITLE 99 Bottles of Beer on the Wall - RPGIII (IBM System/38)
F********************************************************************
F*
F* Lines with an asterisk in column 7 (such as this one) are comments.
F*
F* The character in column 6 specifies the form type. Before the first
F* use of each form type is a comment with the template for the form.
F*
F********************************************************************
F* File Description Specifications
F*
F* Specify a default printer file for output, program described,
F* 132 columns wide, and an overflow indicator OV. The overflow
F* indicator is turned on when data is output to the last usable
F* line (line 60, for the default printer file QSYSPRT).
F*
F*ilenameIPEAF....RlenLK1AIOvKlocEDevice+......KExit++Entry+A....U1
FQSYSPRT O F 132 OV PRINTER
F*
C********************************************************************
C* If there were an input file, the RPG cycle would automatically
C* execute the output lines; since there is no input file, output
C* lines are produced as "exception" output with the EXCPT opcode.
C*
C* Calculation Specifications
C* vvvvvvvvv-- conditionally executes lines if indicators are on/off
C*0N01N02N03Factor1+++OpcdeFactor2+++ResultLenDHHiLoEqComments+++++++
C*
C* Zero, then add 99 to a variable named #BOTLS, which is defined
C* as packed decimal, 3 positions, 0 decimal places.
C Z-ADD99 #BOTLS 30
C*
C* Do until #BOTLS = 0. Each loop produces one complete verse.
C #BOTLS DOUEQ0
C*
C* When the overflow indicator is turned on, start a new page.
C* The indicator is automatically turned on when the overflow
C* line is printed on, and it is automatically turned off
C* when the heading is printed.
C OV EXCPTNEWPAG
C*
C* Print exception lines with names "LYRIC1" and "LYRIC2".
C EXCPTLYRIC1
C EXCPTLYRIC2
C*
C* Subtract 1 from #BOTLS, and turn on indicator LR (Last Record)
C* if the result is equal to zero (Eq); if LR is on, the program
C* will terminate at the end of the current cycle.
C SUB 1 #BOTLS LR
C*
C* Compare #BOTLS to 1, and turn on indicator 01 if equal.
C #BOTLS COMP 1 01
C*
C* Print exception lines with name "LYRIC1".
C EXCPTLYRIC1
C*
C* If LR is not on, print exception lines with name "SKIPLN"
C* (which, in this case, will produce a blank line between verses).
C NLR EXCPTSKIPLN
C*
C END end do
C*
O********************************************************************
O* Output Specifications
O* .-- E means "Exception" ("H" Header, "D" Detail, "T" Total)
O* v vv-- before printing, skip to line # 1 (of the next page)
O*ame++++DFBASbSaN01N02N03Excnam...........................................
OQSYSPRT E 1 NEWPAG
O* v-- space 1 line after printing
O E 1 LYRIC1
O*
O* .........-- conditionally print lines if indicators on/off
O* vvvvvvvvv v-- edit code Z (suppress leading Zeroes)
O*...............N01N02N03Field+YBEnd+PConstant/editword+++++++++
O #BOTLSZ 3
O N01NLR 11 'bottles'
O N01NLR 31 'of beer on the wall'
O 01NLR 10 'bottle'
O 01NLR 30 'of beer on the wall'
O LR 16 'No more bottles'
O LR 36 'of beer on the wall'
O E 1 LYRIC2
O #BOTLSZ 3
O N01 19 'bottles of beer'
O 01 18 'bottle of beer'
O E 1 LYRIC2
O 14 'Take one down'
O E 1 LYRIC2
O 15 'Pass it around'
O E 1 SKIPLN
RPL
≪ " bottles" " of beer" " on the wall" "Take one down and pass it around,"
→ n b of on take
≪ n 1 FOR j
j →STR b + of + DUP on + "," + 1 DISP
"," + 2 DISP
take 3 DISP
j 1 ≠ LAST - →STR "No more" IFTE
b +
IF j 2 == THEN 1 OVER SIZE 1 - SUB END
of + on + "." + 4 DISP
-1 STEP
≫ ≫ 'BOB' STO
99 BOB
RPL/2
Simple solution
BEER
<<
99 do
dup ->str PLURAL " on the wall," + disp
dup ->str PLURAL "." + disp
"Take one down, pass it around," disp
1 -
if dup then
dup ->str
else
"No more"
end
PLURAL " on the wall." + disp
"" disp
until dup 0 == end
drop
>>
PLURAL
<<
" bottle" + over if 1 <> then "s" + end " of beer" +
>>
Recursive and multithreaded solution
BOTTLES
<<
// Child process is started.
100 'RECURSIVE' detach
-> PROC
<<
do PROC recv until end drop2
do
// Parent waits for datas sent by child.
do PROC recv until end
list-> drop dup " on the wall," + disp "." + disp
"Take one down, pass it around," disp
if dup 1 same not then
do PROC recv until end list-> drop
else
1 "No more bottles of beer"
end
" on the wall." + disp drop "" disp
until
1 same
end
// Parent waits for Child's death.
PROC wfproc
>>
>>
RECURSIVE
<<
while
dup
repeat
1 - dup dup ->str
if over 1 > then " bottles " else " bottle " end +
"of beer" + 2 ->list dup
// Child send datas to parent process.
send send
// Recursive function is caught.
RECURSIVE
end
>>
Ruby
plural = 's'
99.downto(1) do |i|
puts "#{i} bottle#{plural} of beer on the wall,"
puts "#{i} bottle#{plural} of beer"
puts "Take one down, pass it around!"
plural = '' if i - 1 == 1
if i > 1
puts "#{i-1} bottle#{plural} of beer on the wall!"
puts
else
puts "No more bottles of beer on the wall!"
end
end
Ruby has variable traces, so we can do
trace_var :$bottle_num do |val|
$bottles = %Q{#{val == 0 ? 'No more' : val.to_s} bottle#{val == 1 ? '' : 's'}}
end
($bottle_num = 99).times do
puts "#{$bottles} of beer on the wall"
puts "#{$bottles} of beer"
puts "Take one down, pass it around"
$bottle_num -= 1
puts "#{$bottles} of beer on the wall"
puts ""
end
or...
def bottles(of_beer, ending)
puts "#{of_beer} bottle#{ending} of beer on the wall,"
puts "#{of_beer} bottle#{ending} of beer"
puts "Take one down, pass it around!"
end
99.downto(0) do |left|
if left > 1
bottles(left, "s")
elsif left == 1
bottles(left, "")
else
puts "No more bottles of beer on the wall!"
end
end
or...
def bottles(beer, wall = false)
"#{beer>0 ? beer : "no more"} bottle#{"s" if beer!=1} of beer#{" on the wall" if wall}"
end
99.downto(0) do |remaining|
puts "#{bottles(remaining,true).capitalize}, #{bottles(remaining)}."
if remaining==0
print "Go to the store and buy some more"
remaining=100
else
print "Take one down, pass it around"
end
puts ", #{bottles(remaining-1,true)}.\n\n"
end
Simple solution
99.downto(1) do |bottles|
puts "#{bottles} bottle#{"s" if bottles != 1} of beer on the wall.",
"#{bottles} bottle#{"s" if bottles != 1} of beer.",
"Take one down, pass it around.",
"#{bottles - 1} bottle#{"s" if bottles - 1 != 1} of beer on the wall.\n\n"
end
Rust
Simple Solution
fn main() {
for n in (0..100).rev() {
match n {
0 => {
println!("No more bottles of beer on the wall, no more bottles of beer.");
println!("Go to the store and buy some more, 99 bottles of beer on the wall.");
},
1 => {
println!("1 bottle of beer on the wall, 1 bottle of beer.");
println!("Take one down and pass it around, no more bottles of beer on the wall.\n");
},
_ => {
println!("{0:?} bottles of beer on the wall, {0:?} bottles of beer.", n);
println!("Take one down and pass it around, {} bottles of beer on the wall.\n", n-1);
},
}
}
}
Using a trait and impl
trait Bottles {
fn bottles_of_beer(&self) -> Self;
fn on_the_wall(&self);
}
impl Bottles for u32 {
fn bottles_of_beer(&self) -> u32 {
match *self {
0 => print!("No bottles of beer"),
1 => print!("{} bottle of beer", self),
_ => print!("{} bottles of beer", self)
}
*self // return a number for chaining
}
fn on_the_wall(&self) {
println!(" on the wall!");
}
}
fn main() {
for i in (1..100).rev() {
i.bottles_of_beer().on_the_wall();
i.bottles_of_beer();
println!("\nTake one down, pass it around...");
(i - 1).bottles_of_beer().on_the_wall();
println!("-----------------------------------");
}
}
S-BASIC
rem - print lyrics to "99 Bottles of Beer on the Wall"
$constant maxbottles = 99
function bottle_str(n = integer) = string
var b = string
if n = 1 then
b = " bottle"
else
b = " bottles"
end = b
procedure delay
var i = integer
for i = 1 to 500 do
rem - nothing
next
end
rem - begin main program
var n = integer
n = maxbottles
while n > 0 do
begin
print n; bottle_str(n); " of beer on the wall,";
print n; bottle_str(n); " of beer"
print "Take one down, and pass it around,";
n = n - 1
if (n = 0) then
print " No more bottles";
else
print n; bottle_str(n);
print " of beer on the wall"
print
delay
end
rem - finish up
print "No more bottles of beer on the wall, no more bottles of beer"
print "Go to the store and buy some more,";
print maxbottles; " bottles of beer on the wall"
end
Sather
class MAIN is
main is
s :STR;
p1 ::= "<##> bottle<#> of beer";
w ::= " on the wall";
t ::= "Take one down, pass it around\n";
loop i ::= 99.downto!(0);
if i /= 1 then s := "s" else s := ""; end;
#OUT + #FMT(p1 + w + "\n", i, "s");
#OUT + #FMT(p1 + "\n", i, "s");
if i > 0 then #OUT + t; end;
end;
end;
end;
Scala
Scheme
(define (sing)
(define (sing-to-x n)
(if (> n -1)
(begin
(display n)
(display "bottles of beer on the wall")
(newline)
(display "Take one down, pass it around")
(newline)
(sing-to-x (- n 1)))
(display "would you wanna me to sing it again?")))
(sing-to-x 99))
Scratch
sed
s/.*/99 bottles of beer on the wall/
h
: b
s/^0//
/^0/q
s/^1 bottles/1 bottle/
p
s/on.*//
p
s/.*/Take one down, pass it around/
p
g
/^.[1-9]/{
h
s/^.//
y/123456789/012345678/
x
s/^\(.\).*$/\1/
G
s/\n//
h
bb
}
y/0123456789/9012345678/
h
bb
Seed7
$ include "seed7_05.s7i";
const proc: main is func
local
var integer: number is 0;
begin
for number range 99 downto 2 do
write( number <& " bottles of beer on the wall, ");
writeln( number <& " bottles of beer.");
write( "Take one down and pass it around, ");
writeln( pred(number) <& " bottles of beer on the wall.");
writeln;
end for;
writeln("1 bottle of beer on the wall, 1 bottle of beer.");
writeln("Take one down and pass it around, no more bottles of beer on the wall.");
writeln;
writeln("No more bottles of beer on the wall, no more bottles of beer.");
writeln("Go to the store and buy some more, 99 bottles of beer on the wall.")
end func;
SenseTalk
Below is a straightforward implementation in SenseTalk. A completely fanciful version (which also works!) can be found here: http://www.99-bottles-of-beer.net/language-sensetalk-1794.html
set bottleCount to 99
set bottleCount's format to "Words"
repeat while bottleCount is greater than zero
set bottleWord to (if bottleCount is one then "bottle" else "bottles")
put bottleCount && bottleWord && "of beer on the wall,"
put bottleCount && bottleWord && "of beer!"
put "Take one down and pass it around,"
subtract one from bottleCount
set bottleWord to (if bottleCount is one then "bottle" else "bottles")
put bottleCount && bottleWord && "of beer on the wall!"
put empty
end repeat
Output:
Ninety-Nine bottles of beer on the wall,
Ninety-Nine bottles of beer!
Take one down and pass it around,
Ninety-Eight bottles of beer on the wall!
Ninety-Eight bottles of beer on the wall,
Ninety-Eight bottles of beer!
Take one down and pass it around,
Ninety-Seven bottles of beer on the wall!
[...]
Two bottles of beer on the wall,
Two bottles of beer!
Take one down and pass it around,
One bottle of beer on the wall!
One bottle of beer on the wall,
One bottle of beer!
Take one down and pass it around,
Zero bottles of beer on the wall!
SequenceL
import <Utilities/Conversion.sl>;
import <Utilities/Sequence.sl>;
main(args(2)) :=
join(phrase(reverse(0 ... 99)));
phrase(num) :=
let
action :=
"Take one down and pass it around" when num > 0
else
"Go to the store and buy some more";
in
describeCount(num, true) ++ " on the wall, " ++
describeCount(num, false) ++ ".\n" ++
action ++ ", " ++
describeCount(num - 1, false) ++ " on the wall.\n\n";
describeCount(num, capitalize) :=
let
count :=
intToString(num) when num > 0
else
intToString(99) when num < 0
else
("N" when capitalize else "n") ++ "o more";
plural := "s" when num /= 1 else "";
in
count ++ " bottle" ++ plural ++ " of beer";
Set lang
set l 10
set s 32
set m 44
set t 48
set a 57
set b 57
set e (a-c)
set f (b-d)
[i=4] set i 0
set ! e
set ! f
set ! s
set ! B
set ! O
set ! T
set ! T
set ! L
set ! E
set ! S
set ! s
set ! O
set ! F
set ! s
set ! B
set ! E
set ! E
set ! R
[i=1] set ? 49
set ! s
set ! O
set ! N
set ! s
set ! T
set ! H
set ! E
set ! s
set ! W
set ! A
set ! L
set ! L
set ! l
[k=1] set ? 97
[i=3] set i 4
[i=4] set ! l
[i=4] set ? 9
[i/2] set i 1
[i=1] set ? 9
[i=2] set ? 87
set ! l
set ! T
set ! A
set ! K
set ! E
set ! s
set ! O
set ! N
set ! E
set ! s
set ! D
set ! O
set ! W
set ! N
set ! m
set ! s
set ! P
set ! A
set ! S
set ! S
set ! s
set ! I
set ! T
set ! s
set ! A
set ! R
set ! O
set ! U
set ! N
set ! D
set ! l
set i 2
[d=9] set d l
[d/l] set d (d+1)
[d=l] set c (c+1)
[d=l] set d 0
set e (a-c)
set f (b-d)
[e=f] set ? 93
[c=l] set ? 91
[i=2] set i 3
[i=3] set ? 9
[d=l] set ? 93
[d/l] set ? 88
[e=t] set ? 95
set ? 88
set k 1
set ? 9
> EOF
Shen
Shiny
for 99 i:99-a
s: if i > 1 's' end
if i > 0 and i < 99 switch
if i = 6 say "A six-pack on the wall!\n" break
if i = 24 say "A carton on the wall!\n" break
say "$i bottle$s of beer on the wall!\n"
ends
say "$i bottle$s of beer on the wall,"
say "$i bottle$s of beer!"
say "Take one down, pass it around!"
end
say "Aww...no more bottles of beer on the wall... it must be your shout :)"
Sidef
for i in (100 ^.. 0) {
var bottles = "#{i == 0 ? 'No' : i} bottle#{i == 1 ? '' : 's'}"
var sentence = "#{bottles} of beer on the wall" -> say
if (i > 0) {
say sentence.substr(0, bottles.length + 8)
say "Take one down, pass it around\n"
}
}
Simpler:
for n in (100 ^.. 2) {
say "#{n} bottles of beer on the wall, #{n} bottles of beer!"
say "Take one down, pass it around, #{n - 1} bottle#{n > 2 ? 's' : ''} of beer on the wall.\n"
}
say "One bottle of beer on the wall, one bottle of beer!"
say "Take one down, pass it around, no more bottles of beer on the wall."
Simula
COMMENT HTTP://99-BOTTLES-OF-BEER.NET ;
COMMENT AUTHOR: TIM GOODWIN ;
COMMENT DATE: 04/20/05 ;
BEGIN
PROCEDURE BOTTLES(N); INTEGER N;
BEGIN
IF N = 0 THEN OUTTEXT("NO MORE BOTTLES") ELSE
IF N = 1 THEN OUTTEXT("ONE BOTTLE") ELSE
BEGIN
OUTINT(N, 0);
OUTTEXT(" BOTTLES");
END;
OUTTEXT(" OF BEER");
END OF BOTTLES;
PROCEDURE BEER(N); INTEGER N;
BEGIN
WHILE N > 0 DO BEGIN
BOTTLES(N);
OUTTEXT(" ON THE WALL");
OUTIMAGE;
BOTTLES(N);
OUTIMAGE;
OUTTEXT( "TAKE ONE DOWN, PASS IT AROUND");
OUTIMAGE;
BOTTLES(N - 1);
OUTTEXT( " ON THE WALL");
OUTIMAGE;
OUTIMAGE;
N := N - 1;
END;
END OF BEER;
BEER(99);
END;
Simpler:
COMMENT http://99-bottles-of-beer.net
author: Jack Leunissen
date: 03/10/07;
BEGIN
INTEGER BOTTLES;
INTEGER NUM;
NUM := 2;
FOR BOTTLES := 99 STEP -1 UNTIL 1 DO
BEGIN
IF BOTTLES < 10 THEN
NUM := 1;
OUTINT(BOTTLES, NUM);
OUTTEXT(" BOTTLE(S) OF BEER ON THE WALL, ");
OUTINT(BOTTLES, NUM);
OUTTEXT(" BOTTLE(S) OF BEER");
OUTIMAGE;
OUTTEXT("TAKE ONE DOWN, PASS IT AROUND, ");
OUTINT(BOTTLES - 1, NUM);
OUTTEXT(" BOTTLE(S) OF BEER ON THE WALL.");
OUTIMAGE;
OUTIMAGE;
END;
OUTTEXT("1 BOTTLE OF BEER ON THE WALL, ONE BOTTLE OF BEER.");
OUTIMAGE;
OUTTEXT("TAKE ONE DOWN, PASS IT AROUND, ");
OUTTEXT("NO MORE BOTTLES OF BEER ON THE WALL.");
OUTIMAGE;
END;
SkookumScript
!bottles: (Integer num) [num.String += if num=1 [" bottle"] else [" bottles"]]
99.to 1
[
print(
bottles(idx) " of beer on the wall\n"
bottles(idx) " of beer\n"
"Take one down, pass it around\n"
bottles(idx-1) " of beer on the wall\n")
]
Slate
n@(Integer traits) bottleVerse
[| nprinted |
nprinted: n printString ; ' bottle' ; (n > 1 ifTrue: ['s'] ifFalse: ['']) ; ' of beer'.
inform: nprinted ; ' on the wall.'.
inform: nprinted.
inform: 'Take one down, pass it around.'.
inform: nprinted ; ' on the wall.'.
].
x@(Integer traits) bottles
[
x downTo: 0 do: #bottleVerse `er
].
99 bottles.
Slope
;; 99 bottles of beer
;;
(define bottles-of-beer (lambda (bottles)
(if (> bottles -1)
(begin0
(for-each
(lambda (app)
(display
(list->string
(cond
((equal? bottles 0)
(list "No more beer"))
((equal? bottles 1)
(list "One bottle of beer"))
(else
(cons bottles " bottles of beer"))) "") app ))
[" on the wall, " "."])
(if (> bottles 0)
(display "\n\tTake one down, pass it around.\n")
(display "\n\tGo to the store and buy some more.\n"))
(bottles-of-beer (- bottles 1))))))
;; main
(bottles-of-beer 99)
Smalltalk
A straightforward approach:
Smalltalk at: #sr put: 0 ; at: #s put: 0 !
sr := Dictionary new.
sr at: 0 put: ' bottle' ;
at: 1 put: ' bottles' ;
at: 2 put: ' of beer' ;
at: 3 put: ' on the wall' ;
at: 4 put: 'Take one down, pass it around' !
99 to: 0 by: -1 do: [:v | v print.
( v == 1 ) ifTrue: [ s := 0. ]
ifFalse: [ s := 1. ].
Transcript show: (sr at:s) ; show: (sr at:2) ; show: (sr at:3) ; cr.
v print.
Transcript show: (sr at:s) ; show: (sr at:2) ; cr.
(v ~~ 0) ifTrue: [ Transcript show: (sr at:4) ; cr. ].
].
This version uses Squeak Smalltalk's String >> format: method. and SequencableCollection >> atPin: method
|bottles plurals |
Transcript clear.
bottles:='{1} bottle{2} of beer on the wall
{1} bottle{2} of beer
Take one down, pass it around
{3} bottle{4} of beer on the wall'.
plurals := #('' 's').
99 to: 1 by: -1 do:[:v |
Transcript show: (bottles format: {(v asString) . (plurals atPin:v) . ((v -1) asString). (plurals atPin:v) }); cr; cr].
Transcript show: 'hic!'; cr.
This version uses Squeak Smalltalk's String >> asPluralBasedOn: method to handle the plural and singular cases.
| bottles |
Transcript clear.
bottles := '{1} {2} of beer on the wall
{1} {2} of beer
Take one down, pass it around
{3} {4} of beer on the wall'.
99 to: 1 by: -1 do: [:i |
Transcript
show: (bottles format: {
i. 'bottle' asPluralBasedOn: i.
i - 1. 'bottle' asPluralBasedOn: i - 1});
cr; cr].
Transcript show: 'hic!'; cr.
SmileBASIC
Pretty comical version. MML tunes based on QB64 version.
DEF NUM(N)
IF N==-1 THEN
RETURN "99"
ELSEIF N==0 THEN
RETURN "No more"
ELSE
RETURN STR$(N)
ENDIF
END
DEF BTL(N)
IF N==1 THEN
RETURN " bottle"
ELSE
RETURN " bottles"
ENDIF
END
DEF ACT(N)
IF N==0 THEN
RETURN "Go to the store, buy some more,"
ELSEIF N==1 THEN
RETURN "Take it down, pass it around,"
ELSE
RETURN "Take one down, pass it around,"
ENDIF
END
DEF WAITPLAY TUNE
BGMPLAY TUNE
WHILE BGMCHK(0):WEND
END
BGMSET 128,"T180@6E-8E-8E-8>B-8B-8B-8<E-8E-8E-8E-4R8"
BGMSET 129,"T180@6F8F8F8C8C8C8F4R4."
BGMSET 130,"T180@6D4D8D8R4D8D8D8D4R8"
BGMSET 131,"T180@6>A+8A+8A+8<C8C8D8D+8D+8D+8D+4R8"
FOR I=99 TO 0 STEP -1
CLS
PRINT NUM(I);BTL(I);" of beer on the wall,"
WAITPLAY 128
PRINT NUM(I);BTL(I);" of beer."
WAITPLAY 129
PRINT ACT(I)
WAITPLAY 130
PRINT NUM(I-1);BTL(I-1);" of beer on the wall."
WAITPLAY 131
NEXT
SNOBOL4
x = 99
again output = X " bottles of beer on the wall"
output = X " bottles of beer" ?eq(X,0) :s(zero)
output = "Take one down, pass it around"
output = (X = gt(x,0) X - 1) " bottle of beer on the wall..." :s(again)
zero output = "Go to store, get some more"
output = "99 bottles of beer on the wall"
end
Function
Function version with string composition. Function returns one verse for x bottles. Correctly handles bottle/bottles.
define('bottles(x)')
nl = char(13) char(10) ;* Win/DOS, change as needed
s2 = ' of beer'; s3 = ' on the wall'
s4 = 'Take one down, pass it around'
s5 = 'Go to the store, get some more' :(bottles_end)
bottles s1 = (s1 = ' Bottle') ne(x,1) 's'
output = nl x s1 s2 s3 nl x s1 s2
x = gt(x,0) x - 1 :f(done)
s1 = (s1 = ' Bottle') ne(x,1) 's'
output = s4 nl x s1 s2 s3 :(return)
done output = s5 nl 99 s1 s2 s3 :(return)
bottles_end
* # Test and display, only 2 bottles!
n = 2
loop bottles(n); n = gt(n,0) n - 1 :s(loop)
end
Output:
2 Bottles of beer on the wall 2 Bottles of beer Take one down, pass it around 1 Bottle of beer on the wall 1 Bottle of beer on the wall 1 Bottle of beer Take one down, pass it around 0 Bottles of beer on the wall 0 Bottles of beer on the wall 0 Bottles of beer Go to the store, get some more 99 Bottles of beer on the wall
SNUSP
SparForte
As a structured script.
#!/usr/local/bin/spar
pragma annotate( summary, "bottles" );
pragma annotate( description, "In this puzzle, write code to print out the entire '99 bottles of beer" );
pragma annotate( description, "on the wall' song. A common interview test from Rosetta Code for" );
pragma annotate( description, "testing basic programming skills." );
pragma annotate( author, "Ken O. Burtch" );
pragma license( unrestricted );
pragma restriction( no_external_commands );
procedure Bottles is
begin
for X in reverse 1..99 loop
? strings.image( X ) & " bottles of beer on the wall";
? strings.image( X ) & " bottles of beer";
? "Take one down, pass it around";
? strings.image( integer(X-1) ) & " bottles of beer on the wall" @ "";
end loop;
end Bottles;
Sparkling
var bottles = 99;
do {
printf("%u bottles of beer on the wall\n", bottles);
printf("%u bottles of beer\n", bottles);
printf("Take one down, pass it around\n");
printf("%u bottles of beer on the wall\n\n", --bottles);
} while(bottles > 1);
printf("1 bottle of beer on the wall\n1 bottle of beer\nTake it down, pass it around\n0 bottles of beer on the wall\n");
SQL
select
( 100 - level ) || ' bottle' || case when level != 99 then 's' end || ' of beer on the wall'
|| chr(10)
|| ( 100 - level ) || ' bottle' || case when level != 99 then 's' end || ' of beer'
|| chr(10)
|| 'Take one down, pass it around'
|| chr(10)
|| ( 99 - level ) || ' bottle' || case when level != 98 then 's' end || ' of beer on the wall'
from dual connect by level <= 99;
DELIMITER $$
DROP PROCEDURE IF EXISTS bottles_$$
CREATE pROCEDURE `bottles_`(inout bottle_count int, inout song text)
BEGIN
declare bottles_text varchar(30);
IF bottle_count > 0 THEN
if bottle_count != 1 then
set bottles_text := ' bottles of beer ';
else set bottles_text = ' bottle of beer ';
end if;
SELECT concat(song, bottle_count, bottles_text, ' \n') INTO song;
SELECT concat(song, bottle_count, bottles_text, 'on the wall\n') INTO song;
SELECT concat(song, 'Take one down, pass it around\n') into song;
SELECT concat(song, bottle_count -1 , bottles_text, 'on the wall\n\n') INTO song;
set bottle_count := bottle_count -1;
CALL bottles_( bottle_count, song);
END IF;
END$$
set @bottles=99;
set max_sp_recursion_depth=@bottles;
set @song='';
call bottles_( @bottles, @song);
select @song;
This Statement does also work with T-SQL, but only up to 32 beers
CREATE PROCEDURE bottles
@bottle_count int,
@song varchar(MAX)
AS
BEGIN
declare @bottles_text VARCHAR(MAX);
IF @bottle_count > 0
BEGIN
IF @bottle_count != 1
BEGIN
SET @bottles_text = ' bottles of beer ';
END
ELSE
BEGIN
SET @bottles_text = ' bottle of beer ';
END
SET @song = @song + CAST(@bottle_count AS VARCHAR) + @bottles_text + '\n';
SET @song = @song + CAST(@bottle_count AS VARCHAR) + @bottles_text + 'on the wall\n'
SET @song = @song + 'Take one down, pass it around\n'
SET @song = @song + CAST((@bottle_count - 1) AS VARCHAR) + @bottles_text + 'on the wall\n'
SET @bottle_count = (@bottle_count - 1);
EXEC bottles @bottle_count, @song
END
ELSE
select @song AS 'RESULT'
END
/*****
AND IN ORDER TO CALL PROCEDURE:
****/
EXECUTE bottles 31, '';
/*These statements work in PostgreSQL (tested in 9.4)*/
SELECT generate_series || ' bottles of beer on the wall' || chr(10) ||
generate_series || ' bottles of beer' || chr(10) ||
'Take one down, pass it around' || chr(10) ||
coalesce(lead(generate_series) OVER (ORDER BY generate_series DESC),0) || ' bottles of beer on the wall' AS song
FROM generate_series(1,99)
ORDER BY generate_series DESC;
/*The next statement takes also into account the grammatical support for "1 bottle of beer".*/
SELECT generate_series || ' bottle' || CASE WHEN generate_series>1 THEN 's' ELSE '' END || ' of beer on the wall' || chr(10) ||
generate_series || ' bottle' || CASE WHEN generate_series>1 THEN 's' ELSE '' END || ' of beer' || chr(10) ||
'Take one down, pass it around' || chr(10) ||
coalesce(lead(generate_series) OVER (ORDER BY generate_series DESC),0) || ' bottle' || CASE WHEN coalesce(lead(generate_series) OVER (ORDER BY
generate_series DESC),0) <>1 THEN 's' ELSE '' END || ' of beer on the wall' AS song
FROM generate_series(1,99)
ORDER BY generate_series DESC;
/*The next statement uses recursive query.*/
WITH RECURSIVE t(n) AS (
VALUES (1)
UNION ALL
SELECT n+1 FROM t WHERE n < 99
)
SELECT n || ' bottle' || CASE WHEN n>1 THEN 's' ELSE '' END || ' of beer on the wall' || chr(10) ||
n || ' bottle' || CASE WHEN n>1 THEN 's' ELSE '' END || ' of beer' || chr(10) ||
'Take one down, pass it around' || chr(10) ||
coalesce(lead(n) OVER (ORDER BY n DESC),0) || ' bottle' ||
CASE WHEN coalesce(lead(n) OVER (ORDER BY n DESC),0) <>1 THEN 's' ELSE '' END || ' of beer on the wall' AS song
FROM t
ORDER BY n DESC;
Squirrel
function rec(bottles)
{
if (bottles > 0)
{
print(bottles+" bottles of beer on the wall\n")
print(bottles+" bottles of beer\n");
print("Take one down, pass it around\n");
print(--bottles+" bottles of beer on the wall\n\n")
return rec(bottles);
}
print("No more bottles of beer on the wall, no more bottles of beer\n");
print("Go to the store and get some more beer, 99 bottles of beer on the wall\n");
}
rec(99);
Standard ML
fun bottles 0 = ()
| bottles x = ( print (Int.toString x ^ " bottles of beer on the wall\n");
print (Int.toString x ^ " bottles of beer\n");
print "Take one down, pass it around\n";
print (Int.toString (x-1) ^ " bottles of beer on the wall\n");
bottles (x-1)
)
The following code outputs the full lyrics, generating duplicate text blocks only once.
fun capitalize s =
(str o Char.toUpper o String.sub) (s, 0) ^ String.extract (s, 1, NONE)
fun unfoldN (0, _, _) = []
| unfoldN (n, f, init) =
(fn (item, next) => item :: unfoldN (n - 1, f, next)) (f init)
fun textBlocks 0 = ("no more bottles", "Go to the store and buy some more", 99)
| textBlocks i = (if i = 1 then "1 bottle" else Int.toString i ^ " bottles",
"Take one down and pass it around", i - 1)
fun clauses i =
let
val (f, s, n) = textBlocks i
val f2 = f ^ " of beer"
in
(f2 ^ " on the wall", f2, s, n)
end
fun makeLine l =
concat (ListPair.map op^ (l, [", ", ".\n"]))
fun verse (f1, f2, s, n) =
let
val next as (f1', f2', _, _) = clauses n
in
(makeLine [capitalize f1, f2] ^ makeLine [s, f1'], next)
end
val () = (print o String.concatWith "\n" o unfoldN) (100, verse, clauses 99)
Stata
program drink
local s s
forvalues i=`1'(-1)0 {
if `i'>0 {
display "`i' bottle`s' of beer on the wall"
display "`i' bottle`s' of beer"
display "Take one down, pass it around"
if `i'==2 {
local s ""
}
if `i'>1 {
display "`=`i'-1' bottle`s' of beer on the wall..."
}
else {
display "No more bottles of beer on the wall"
}
display
}
else {
display "No more bottles of beer on the wall"
display "No more bottles of beer"
display "Go to the store and buy some more"
display "`1' bottles of beer on the wall..."
}
}
end
drink 2
2 bottles of beer on the wall
2 bottles of beer
Take one down, pass it around
1 bottle of beer on the wall...
1 bottle of beer on the wall
1 bottle of beer
Take one down, pass it around
No more bottles of beer on the wall
No more bottles of beer on the wall
No more bottles of beer
Go to the store and buy some more
2 bottles of beer on the wall...
Suneido
i = 99
while (i > 0)
{
Print(i $ ' bottles of beer on the wall')
Print(i $ ' bottles of beer')
Print('Take one down, pass it around')
--i
if i is 0
Print('Ahh poo, we are out of beer\n')
else
Print(i $ ' bottles of beer on the wall\n')
}
SuperCollider
// post to the REPL directly
(
(99..0).do { |n|
"% bottles of beer on the wall\n% bottles of beer\nTake one down, pass it around\n% bottles of beer on the wall\n".postf(n, n, n)
};
)
// post over time
(
fork {
100.reverseDo { |n|
n.post; " bottles of beer on the wall".postln; 0.5.wait;
n.post; " bottles of beer".postln; 0.5.wait;
"Take one down, pass it around".postln; 0.5.wait;
n.post; " bottles of beer on the wall".postln; 0.5.wait;
1.wait;
};
}
)
SuperTalk
-- Rosetta Code problem: https://rosettacode.org/wiki/99_bottles_of_beer
-- by Jjuanhdez, 10/2022
on mouseup
put 99 into numBeerz
put "s it" into modifier
repeat with x = numBeerz down to 1
put "one" into whichone
put "s" into modifier
put "s" into otherModifier
put x - 1 into nextCount
if x is 2 then put "" into otherModifier
if x is 1 then
put "it" into whichone
put "" into modifier
put "s" into otherModifier
put "no more" into nextCount
end if
put x & " bottle" & modifier& " of beer on the wall, " & x & " bottle" &
modifier & " of beer..." after y
put " Take " & whichOne & " down, pass it around, " & nextCount & "
bottle" & otherModifier & " of beer on the wall. " & cr after y
end repeat
put "No more bottles of beer on the wall, ya bastards drank them all! So
off to the store to buy some more, let's put 99 bottles of beer on the
wall!" & cr after y
put y into card field 1
-- say cd fld 1 -- uncomment this line to hear it sing.
end mouseup
Swift
for i in (1...99).reversed() {
print("\(i) bottles of beer on the wall, \(i) bottles of beer.")
let next = i == 1 ? "no" : (i-1).description
print("Take one down and pass it around, \(next) bottles of beer on the wall.")
}
Symsyn
BBW : ' Bottles of beer on the wall '
TOD : 'Take one down and pass it around '
if 99 GT 0 | numbers are variables initialized to value
~ 99 $S | convert to string
+ BBW $S | add phrase to end of string
+ $S $S | add string to itself
#$S N | size to N
- 12 N | decrement size by 12
N #$S | change size of string
$S [] | output string
- 99 | decrement counter
TOD $S | phrase to string
~ 99 $R | convert to string
+ $R $S | add to end of string $S
+ BBW $S | add phrase to end of $S
$S [] | output string
goif | go back to if
endif
Tailspin
templates sayBottleCount
when <=1> do
'1 bottle' !
when <=0> do
'No bottles' !
otherwise
'$; bottles' !
end sayBottleCount
99..1:-1 ->
'$->sayBottleCount; of beer on the wall,
$->sayBottleCount; of beer.
Take one down, pass it around,
$:$ - 1 -> sayBottleCount; of beer on the wall.
' -> !OUT::write
- Output:
99 bottles of beer on the wall, 99 bottles of beer. Take one down, pass it around, 98 bottles of beer on the wall. ... 2 bottles of beer on the wall, 2 bottles of beer. Take one down, pass it around, 1 bottle of beer on the wall. 1 bottle of beer on the wall, 1 bottle of beer. Take one down, pass it around, No bottles of beer on the wall.
Tcl
Thyrd
TIScript
var beer = 99;
while (beer > 0)
{
stdout.printf( "%d bottles of beer on the wall\n", beer);
stdout.printf( "%d bottles of beer\n", beer);
stdout.println( "Take one down, pass it around" );
stdout.printf( "%d bottles of beer on the wall\n", --beer );
}
TMG
Unix TMG:
loop: parse(line1) [--n] parse(line2) [n>=1?]\loop;
line1: beer = { 1 < on the wall, > 1 <.> * };
line2: beer = { <If one of those bottles should happen to fall, > 1 < on the wall.> * };
beer: rest plural = { 2 < bottle> 1 < of beer> };
rest: ( [n>=1?] decimal(n) | = { <no more> } );
plural: ( [n!=1?] = { <s> } | = { } );
n: 143;
TorqueScript
for(%i = 99; %i >= 0; %i--)
{
%n = %i - 1;
echo(%i SPC (%n == 1 ? "bottle" : "bottles") SPC "of beer on the wall ~");
echo("Take one down, pass it around,");
echo(%n SPC (%i == 1 ? "bottle" : "bottles") SPC "of beer on the wall.");
}
Transd
#lang transd
class MaterialAssets: {
what: (λ (textout quantity " " contents " ")),
consume: (λ (-= quantity 1)),
thereIs: (λ (ret quantity)),
quantity: Int(),
contents: String(),
@init: (λ _q Int(0) _c String()
(= quantity _q) (= contents _c))
}
class Storage: {
where: (λ (textout container)),
container: String(),
@init: (λ _c String() (= container _c))
}
class Activity: {
do: (λ (textout action) (consume stuff)),
provideStuff: (λ _s MaterialAssets() (rebind stuff _s)),
action: String(),
@init: (λ _a String() (= action _a)),
stuff: MaterialAssets()
}
class PartyMaker: {
letsRock: (λ
(while (thereIs stuff)
(what stuff) (where box) (lout "")
(what stuff) (lout "")
(do fun) (lout "")
(what stuff) (where box) (lout "\n"))
(lout "OK! What about one more?")
),
stuff: MaterialAssets(),
box: Storage(),
fun: Activity(),
@init: (λ _s MaterialAssets() _b Storage() _f Activity()
(rebind stuff _s) (rebind box _b) (rebind fun _f)
(provideStuff fun stuff))
}
MainModule: {
_start: (λ
locals: party PartyMaker(
MaterialAssets(99 "bottles of beer")
Storage("on the wall")
Activity("Take one down, pass it around"))
(letsRock party)
)
}
TUSCRIPT
$$ MODE TUSCRIPT
LOOP bottle=1,100
SET bottlenr=100-bottle
IF (bottlenr==0) THEN
PRINT "no bottle of beer on the wall"
EXIT
ELSEIF (bottlenr==1) THEN
PRINT bottlenr, " bottle of beer on the wall"
PRINT bottlenr, " bottle of beer"
ELSE
PRINT bottlenr, " bottles of beer on the wall"
PRINT bottlenr, " bottles of beer"
ENDIF
PRINT "Take one down, pass it around"
ENDLOOP
TXR
The (range 99 -1 -1)
expression produces a lazy list of integers from 99 down to -1. The mapcar*
function lazily maps these numbers to strings, and the rest of the code treats this lazy list as text stream to process, extracting the numbers with some pattern matching cases and interpolating them into the song's text. Functional programming with lazy semantics meets text processing, pattern matching and here documents.
@(next :list @(mapcar* (fun tostring) (range 99 -1 -1)))
@(collect)
@number
@ (trailer)
@number_less_1
@ (cases)
@ (bind number "1")
@ (output)
1 bottle of beer one the wall
1 bottle of beer
@ (end)
@ (or)
@ (output)
@number bottles of beer one the wall
@number bottles of beer
@ (end)
@ (end)
@ (cases)
@ (bind number "0")
@ (output)
Go to the store and get some more,
99 bottles of beer on the wall!
@ (end)
@ (or)
@ (output)
Take one down and pass it around
@number_less_1 bottles of beer on the wall
@ (end)
@ (end)
@(end)
To make the song repeat indefinitely, change the first line to:
@(next :list @(mapcar* (fun tostring) (repeat (range 99 0 -1))))
Now it's processing an infinite lazy lists consisting of repetitions of the integer sequences 99 98 ... 0.
TypeScript
function beerSong(){
function nbottles(howMany:number){
return `${howMany?howMany:'no'} bottle${howMany!=1?'s':''}`;
}
let song=[];
let beer = 99;
while (beer > 0) {
song.push(`
${nbottles(beer)} of beer on the wall,
${nbottles(beer)} of beer!
Take one down, pass it around
${nbottles(--beer)} of beer on the wall
`);
}
return song.join('');
}
console.log(beerSong());
uBasic/4tH
A very vanilla BASIC implementation.
0005 LET I=99
0006 PRINT "Lyrics of the song 99 Bottles of Beer"
0010 REM main
0011 IF I>2 THEN GOTO 20
0012 IF I=2 THEN GOTO 30
0013 IF I=1 THEN GOTO 40
0014 GOTO 50
0020 REM if greater than two
0021 PRINT I;" Bottles of beer on the wall, ";I;" bottles of beer."
0022 LET I=I-1
0023 PRINT "Take one down and pass it around, ";
0024 PRINT I;" bottles of beer on the wall."
0025 GOTO 10
0030 REM if equals two
0031 PRINT I;" Bottles of beer on the wall, ";I;" bottles of beer."
0032 LET I=I-1
0033 PRINT "Take one down and pass it around, ";
0034 PRINT I;" bottle of beer on the wall."
0035 GOTO 10
0040 REM if equals one
0041 PRINT I;" Bottle of beer on the wall, ";I;" bottle of beer."
0042 LET I=I-1
0043 PRINT "Take one down and pass it around,";
0044 PRINT " no more bottles of beer on the wall."
0045 GOTO 10
0050 REM if equals zero then exit
0051 PRINT "No more bottles of beer on the wall. No more bottles of beer..."
0052 PRINT "Go to the store and buy some more...99 bottles of beer."
And a more structured version.
for n=99 to 2 step -1
print n;" bottles of beer on the wall, ";n;" bottles of beer!"
print "Take one down, pass it around, ";n-1;" bottle";
print show(iif(n>2 , "s", ""));" of beer on the wall.\n"
next
print "One bottle of beer on the wall, one bottle of beer!"
print "Take one down, pass it around, no more bottles of beer on the wall.\n"
print "No more bottles of beer on the wall. No more bottles of beer..."
print "Go to the store and buy some more...99 bottles of beer."
UNIX Shell
UnixPipes
Unlambda
Ursa
#
# 99 bottles of beer
#
decl int bottles
decl string bottlestr
for (set bottles 99) (> bottles 0) (dec bottles)
if (= bottles 1)
set bottlestr "bottle"
else
set bottlestr "bottles"
end if
out bottles " " bottlestr " of beer on the wall" endl console
out bottles " " bottlestr " of beer" endl console
out "Take one down, pass it around." endl console
if (not (= bottles 2))
out (int (- bottles 1)) " bottles of beer on the wall." endl endl console
else
out (int (- bottles 1)) " bottle of beer on the wall." endl endl console
end if
end for
Ursala
#import nat
# each function takes a natural number to a block of text
quantity = # forms the plural as needed
~&iNC+ --' of beer'+ ~&?(
1?=/'1 bottle'! --' bottles'+ ~&h+ %nP,
'no more bottles'!)
verse =
^(successor,~&); ("s","n"). -[
-[quantity "s"]- on the wall, -[quantity "s"]-,
Take one down and pass it around, -[quantity "n"]- on the wall.]-
refrain "n" =
-[
No more bottles of beer on the wall, -[quantity 0]-.
Go to the store and buy some more, -[quantity "n"]- on the wall.]-
whole_song "n" = ~&ittt2BSSL (verse*x iota "n")--<refrain "n">
#show+
main = whole_song 99
Uxntal
( uxncli 99bottles.rom )
|10 @Console &vector $2 &read $1 &pad $4 &type $1 &write $1 &error $1
|0100 ( -> )
#63 &loop
DUP <print-verse>
[ LIT2 0a -Console/write ] DEO
#01 EQUk ?&done
POP #01 SUB
!&loop
&done BRK
@<print-verse> ( num -- )
DUP <print-bottle> ;dict/wall <print-string>
DUP <print-bottle> [ LIT2 0a -Console/write ] DEO
;dict/take <print-string>
#01 SUB <print-bottle> ;dict/wall !<print-string>
@<print-bottle> ( num -- )
DUP #00 EQU ?&zero
DUP #01 EQU ?&one
<print-dec> ;dict/bottle <print-string>
[ LIT2 "s -Console/write ] DEO
!&end
&one ( num -- )
<print-dec> ;dict/bottle <print-string>
!&end
&zero ( num -- )
POP ;dict/no-more <print-string>
;dict/bottle <print-string>
[ LIT2 "s -Console/write ] DEO
( >> )
&end
;dict/of-beer
( >> )
@<print-string> ( str -- )
&loop
LDAk .Console/write DEO
INC2 LDAk ?&loop
POP2 JMP2r
@<print-dec> ( byte -- )
DUP #64 DIV <print-num>/try
DUP #0a DIV <print-num>/try
( >> )
@<print-num> ( num -- )
#0a DIVk MUL SUB
[ LIT "0 ] ADD .Console/write DEO
JMP2r
&try ( num -- )
DUP ?<print-num>
POP JMP2r
@dict &no-more "No 20 "more $1
&bottle 20 "bottle $1
&of-beer 20 "of 20 "beer 20 $1
&wall "on 20 "the 20 "wall 0a $1
&take "Take 20 "one 20 "down, 20 "pass 20 "it 20 "around 0a $1
UTFool
···
http://rosettacode.org/wiki/99_Bottles_of_Beer
···
■ BottlesOfBeer
§ static
▶ main
• args⦂ String[]
∀ bottles ∈ 99 ⋯> 0
System.out.println ‷
⸨x bottles⸩ on the wall
⸨x bottles⸩
Take one down, pass it around
⸨x bottles - 1⸩ on the wall
‴
▶ x⦂ String
• many⦂ int
s⦂ String: many > 1 ? "s" ! ""
return "⸨many⸩ bottle⸨s⸩ of beer"
V_(Vlang)
[bottles
[newline '' puts].
[beer
[0 =] ['No more bottles of beer' put] if
[1 =] ['One bottle of beer' put] if
[1 >] [dup put ' bottles of beer' put] if].
[0 =] [newline]
[beer ' on the wall, ' put beer newline
'Take one down and pass it around, ' put pred beer ' on the wall' puts newline]
tailrec].
99 bottles
Vala
void main() {
uint bottles = 99;
do {
print("%u bottles of beer on the wall.\n", bottles);
print("%u bottles of beer!\n", bottles);
print("Take one down, pass it around!\n");
--bottles;
if (bottles == 0) {
print("No bottles");
}
else if (bottles == 1) {
print("1 bottle");
}
else {
print("%u bottles", bottles);
}
print(" of beer on the wall!\n\n");
} while (bottles != 0);
}
VBA
VBScript
Vedit macro language
Most of the keywords in Vedit macro language have both short and long format. Normally, long format is used here in Rosetta Code for clarity, so here is an example using the short keywords.
RS(1, " 99")
RS(2, " bottles of beer")
RS(3, " on the wall")
RS(4, " Take one down, pass it around")
#1 = 99
do {
RI(1) RI(2) RI(3) IN
RI(1) RI(2) IN
RI(4) IN
#1-- Num_Str(#1, 1)
RI(1) RI(2) RI(3) IN IN
} while (#1)
Return
Verbexx
fb @FN [x] { @IF (x == 1) then:{ 'bottle } else:{ 'bottles } };
@LOOP init:{@VAR n = 99} until:(n == 0)
{
@SAY n (@fb n) "of beer on the wall" ;
@SAY n (@fb n) "of beer." ;
n-- ;
@SAY "Take one down, pass it around" ;
@SAY n (@fb n) "of beer on the wall\n" ;
};
Verilog
module beer;
integer i;
initial begin
for (i=4; i>0; i=i-1)
begin
$display("%0d bottles of beer on the wall,", i);
$display("%0d bottles of beer.", i);
$display("Take one down and pass it around,");
if (i==1)
$display("no more bottles of beer on the wall...\n");
else
$display("%0d bottles of beer on the wall...\n", i-1);
end
$display("No more bottles of beer on the wall,\nno more bottles of beer.");
$display("Go to the store and buy some more,\n 99 bottles of beer on the wall.");
end
endmodule
Visual Prolog
Viua VM assembly
.function: bottles_of_beer_text/1
.name: %iota number_of_bottles
arg %number_of_bottles %0
.name: %iota bottles_of_beer
; support for "1 bottle of beer" and "N bottles of beer"
if (eq %iota %number_of_bottles (istore %iota 1)) +1 +3
text %bottles_of_beer " bottle of beer"
jump +2
text %bottles_of_beer " bottles of beer"
move %0 %bottles_of_beer
return
.end
.function: first_print/1
; this function prints the
;
; N bottles of beer on the wall
; N bottles of beer
; Take one down, pass it around
;
.name: %iota number_of_bottles
arg %number_of_bottles %0
.name: %iota bottles_of_beer
frame ^[(param %0 %number_of_bottles)]
call %bottles_of_beer bottles_of_beer_text/1
echo %number_of_bottles
echo %bottles_of_beer
print (text %iota " on the wall")
echo %number_of_bottles
print %bottles_of_beer
print (text %iota "Take one down, pass it around")
return
.end
.function: second_print/1
; this function prints the
;
; No more bottles of beer on the wall /
; N bottles of beer on the wall
;
; i.e. the last line of a paragraph
.name: %iota number_of_bottles
arg %number_of_bottles %0
.name: %iota bottles_of_beer
frame ^[(param %0 %number_of_bottles)]
call %bottles_of_beer bottles_of_beer_text/1
.name: %iota on_the_wall
text %on_the_wall " on the wall"
; say "No more" instead of "0 bottles"
if %number_of_bottles +1 +3
echo %number_of_bottles
jump +3
echo (text %iota "No more")
echo %bottles_of_beer
print %on_the_wall
if %number_of_bottles +1 +3
print (text %iota "")
return
.end
.function: bottles_of_beer/1
.name: %iota total_number_of_bottles
arg %total_number_of_bottles %0
; display first three lines of a paragraph
frame ^[(param %0 %total_number_of_bottles)]
call void first_print/1
; decrement the number of bottles
idec %total_number_of_bottles
; display last line of a paragraph
frame ^[(param %0 %total_number_of_bottles)]
call void second_print/1
; immediately return if there are no more bottles
if %total_number_of_bottles theres_more +1
return
.mark: theres_more
; if there are more bottles
; call the function once more
frame ^[(pamv %0 %total_number_of_bottles)]
tailcall bottles_of_beer/1
.end
.function: main/0
.name: %iota total_number_of_bottles
istore %total_number_of_bottles 9
frame ^[(pamv %0 %total_number_of_bottles)]
call void bottles_of_beer/1
izero %0 local
return
.end
V (Vlang)
Fails the task definition for more song, includes the no beer verse.
// 99 bottles of V
module main
// pluralize
fn plural(beers int) string {
if beers == 1 { return "" } else { return "s" }
}
// The repetitive song
fn verse(beers int) {
mut beer := beers - 1
mut numno := beers.str()
mut elipsis := ""
if beers == 0 { numno = "No" }
println("$numno bottle${plural(beers)} of beer on the wall")
println("$numno bottle${plural(beers)} of beer")
if beer == 0 { numno = "No" } else { numno = beer.str() }
if beers == 0 {
println("To the store, to buy some more")
numno = "99"
elipsis = "..."
} else {
println("Take one down, pass it around")
}
println("$numno bottle${plural(beer)} of beer on the wall${elipsis}")
}
// passing time
pub fn main() {
for beers := 99; beers >= 0; beers-- {
verse(beers)
println("")
}
}
Vox
// translated from <http://rosettacode.org/wiki/99_Bottles_of_Beer#JavaScript>
local beer;
while((beer = typeof beer == "null" ? 99 : beer) > 0)
println(
beer + " bottle" +
(beer != 1 ? "s" : "") +
" of beer on the wall\n" + beer + " bottle" +
(beer != 1 ? "s" : "") +
" of beer\nTake one down, pass it around\n" +
(--beer) + " bottle" +
(beer != 1 ? "s" : "") + " of beer on the wall\n"
);
VTL-2
10 B=99
20 #=200
30 ?=" of beer on the wall,"
40 #=200
50 ?=" of beer,"
60 ?="Take ";
70 #=B=1*100
80 ?="one";
90 #=110
100 ?="it";
110 ?=" down and pass it around,"
120 B=B-1
130 #=200
140 ?=" of beer on the wall!"
150 ?=""
160 #=B=0=0*20
170 #=999
200 ;=!
210 #=B=0*270
220 ?=B
230 ?=" bottle";
240 #=B=1*;
250 ?="s";
260 #=;
270 ?="No more";
280 #=!+10
Wart
Whenever
Whitespace
Wortel
!console.log @unlines ~!* 99..0 !? {
0 "0 bottles of beer on the wall\n0 bottles of beer\nbetter go to the store and buy some more."
"{@x} bottle{@?@x{1 @e 's}} of beer on the wall\n{@x} bottle{@?@x{1 @e 's}} of beer\nTake one down, pass it around"
}
Wrapl
MOD Bottles;
IMP IO.Terminal USE Out;
IMP Std.String;
VAR i, s <- "s", ob <- "of beer", otw <- "on the wall",
more <- "Take one down and pass it around", verse <- [];
EVERY i <- 99:to(0,-1) DO (
(i = 1) & (s <- "");
(i = 0) & (s <- "s"; i <- "No more"; more <- "Go to the store and buy some more");
verse:put('. {i} bottle{s} {ob} {otw}.\n');
verse:put('\n{i} bottle{s} {ob} {otw}, {(i@String.T):lower} bottle{s} {ob}.\n{more}');
);
Out:write(verse[2,0]@(String.T, "") + verse[1]);
END Bottles.
Wren
for (i in 99...0) {
System.print("%(i) bottles of beer on the wall,")
System.print("%(i) bottles of beer,")
System.print("Take one down, pass it around,")
System.print("%(i - 1) bottles of beer on the wall.\n")
}
X10
public class NinetyNineBottles{
public static def main(args: Rail[String]){
val beerSong: NinetyNineBottles = NinetyNineBottles.make(99);
beerSong.create();
beerSong.sing();
}
var numVerses: Int;
var verses: Array[String]{rank==1};
var bottles: Int;
public static def make(var numBottles: Int){
val s = new NinetyNineBottles();
s.numVerses = numBottles + 1;
val verses: Region{rank==1} = [1..s.numVerses];
s.verses = Array.make[String](verses, (Point) => new String());
s.bottles = numBottles;
return s;
}
public def create(){
finish ateach ( (p):Point in verses ){
val wallCount = bottles - p + 1;
verses(p) = createVerse( p ) ;
}
return;
}
public def sing(){
for ( (p):Point in verses ){
Console.OUT.println(verses(p));
}
return;
}
public def createVerse(var verseNum: Int): String{
val lineA:String,
lineB:String;
val wallCount = bottles - (verseNum - 1);
val nextWallCount = (wallCount + numVerses - 1)%numVerses;
if (wallCount > 0) {
lineA = line(wallCount);
lineB = lineA;
}else{
lineA = "No " + line(wallCount);
lineB = "no " + line(wallCount);
}
return lineA + " on the wall, " + lineB + ".\n" +
action(wallCount) + line(nextWallCount) + " on the wall.\n";
}
public static def line(val numBottles:Int):String{
switch(numBottles){
case 0: return "more bottles of beer";
case 1: return numBottles + " bottle of beer";
default: return numBottles + " bottles of beer";
}
}
public static def action(val numBottles:Int):String{
if (numBottles==0)
return "Go to the store and buy some more, ";
else
return "Take one down and pass it around, ";
}
}
X86 Assembly
XBS
set Bottles = 99;
while (Bottles > 0){
log(Bottles+" bottles of beer on the wall,");
log(Bottles+ " bottles of beer!");
log("Take one down, pass it around");
Bottles-=1;
log(Bottles+" bottles of beer on the wall");
}
xEec
Xojo
Place the following in the Run event handler of a Console application:
Dim bottles As Integer = 99
While bottles > 0
Print(bottles.ToText + " bottles of beer on the wall,")
Print(bottles.ToText + " bottles of beer.")
Print("Take one down, pass it around.")
bottles = bottles - 1
Print(bottles.ToText + " bottles of beer on the wall.")
Print ""
Wend
XPath
A solution written in pure XPath 3.0 (using XSLT as a host language).
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="3.0">
<xsl:output method="text"/>
<xsl:template match="/">
<xsl:value-of
select="
for $x in reverse(1 to 99)
return
let $suf := if ($x = 1) then '' else 's'
return
concat($x, ' bottle', $suf, ' of beer on the wall ',
$x, ' bottle', $suf, ' of beer Take one down, pass it around ',
$x - 1, ' bottle', if ($x = 2) then '' else 's', ' of beer on the wall')" separator=" "
/>
</xsl:template>
</xsl:stylesheet>
XPL0
code IntOut=11, Text=12;
int B;
[B:= 99;
repeat IntOut(0, B); Text(0, " bottles of beer on the wall^M^J");
IntOut(0, B); Text(0, " bottles of beer^M^J");
Text(0, "Take one down, pass it around^M^J");
B:= B-1;
IntOut(0, B); Text(0, " bottles of beer on the wall^M^J^J");
until B=0;
]
XSLT
XSLT 1.0
To run, transform any document with this stylesheet (the input document is ignored).
<?xml version="1.0" ?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="text" encoding="utf-8"/>
<!-- Main procedure -->
<xsl:template match="/">
<!-- Default parameters are used -->
<xsl:call-template name="sing-all-verses-in-range"/>
</xsl:template>
<!-- Calls sing-verse-starting-with-number over each value in a range. -->
<xsl:template name="sing-all-verses-in-range">
<!-- Default parameters: From 99 through 1 -->
<xsl:param name="first" select="99"/>
<xsl:param name="final" select="1"/>
<!-- Simulate a loop with tail recursion. -->
<xsl:if test="$first >= $final">
<!-- Process $first -->
<xsl:call-template name="sing-verse-starting-with-number">
<xsl:with-param name="n" select="$first"/>
</xsl:call-template>
<!-- Process $first - 1 through $final -->
<xsl:call-template name="sing-all-verses-in-range">
<xsl:with-param name="first" select="$first - 1"/>
<xsl:with-param name="final" select="$final"/>
</xsl:call-template>
</xsl:if>
</xsl:template>
<!-- Outputs a single verse. Each verse starts with $n bottles and ends with $n - 1 bottles. -->
<xsl:template name="sing-verse-starting-with-number">
<xsl:param name="n"/>
<!-- "$n bottles of beer on the wall" -->
<xsl:call-template name="sing-line-containing-number">
<xsl:with-param name="n" select="$n"/>
</xsl:call-template>
<!-- "$n bottles of beer" -->
<xsl:call-template name="sing-line-containing-number">
<xsl:with-param name="n" select="$n"/>
<!-- For the second line, specify blank suffix -->
<xsl:with-param name="suffix"/>
</xsl:call-template>
<xsl:text>Take one down, pass it around </xsl:text>
<!-- "($n - 1) bottles of beer on the wall" -->
<xsl:call-template name="sing-line-containing-number">
<!-- End verse with one less bottle -->
<xsl:with-param name="n" select="$n - 1"/>
</xsl:call-template>
<xsl:text> </xsl:text>
</xsl:template>
<!-- Outputs "[number] bottle[s] of beer[ on the wall]" -->
<xsl:template name="sing-line-containing-number">
<xsl:param name="n"/>
<!-- If no suffix is specified, use " on the wall" -->
<xsl:param name="suffix"> on the wall</xsl:param>
<xsl:value-of select="$n"/>
<xsl:text> bottle</xsl:text>
<!-- Add "s" iff appropriate -->
<xsl:if test="$n != 1">s</xsl:if>
<xsl:text> of beer</xsl:text>
<xsl:value-of select="$suffix"/>
<xsl:text> </xsl:text>
</xsl:template>
</xsl:stylesheet>
XSLT 3.0
To run, transform any document with this stylesheet.
There are fewer XSLT 3 parsers out there than for XSLT 1, but it is so much less painful to program with XSLT 3 (or 2). This code uses several features not available in XSLT 1 to produce output identical to that for the XSLT 1 code provided.
- xsl:iterate, more versatile than xsl:for-each [first available in XSLT 3.0]
- reverse() function [first available in XPath 2.0 / XSLT 2]
- "if ... then ... else" construction [ditto]
- use of text value templates (using "{ XPath code }") [first available XSLT 3, see https://www.w3.org/TR/xslt-30/#text-value-templates]
<?xml version="1.0" ?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xs" version="3.0">
<xsl:output method="text"/>
<xsl:variable name="startingNumberOfBottles" select="99"/>
<!-- Main procedure. -->
<xsl:template match="/" expand-text="true">
<xsl:iterate select="reverse(1 to $startingNumberOfBottles)">
<xsl:variable name="currentBottles" select="." as="xs:integer"/>
<xsl:variable name="newBottles" select=". - 1" as="xs:integer"/>
<xsl:text>{$currentBottles} bottle{if ($currentBottles ne 1) then 's' else ()} of beer on the wall </xsl:text>
<xsl:text>{$currentBottles} bottle{if ($currentBottles ne 1) then 's' else ()} of beer </xsl:text>
<xsl:text>Take one down, pass it around </xsl:text>
<xsl:text>{$newBottles} bottle{if ($newBottles ne 1) then 's' else ()} of beer on the wall </xsl:text>
</xsl:iterate>
</xsl:template>
</xsl:stylesheet>
xTalk
function beerMe numberOfBottles
put "XX bottles of beer on the wall" into verseA
put "Take one down, pass it around" into verseB
repeat with N = numberOfBottles down to 1
put replaceText(verseA,"XX",N) & cr & word 1 to 4 of \
replaceText(verseA,"XX",N) & cr & verseB & cr & replaceText(verseA,"XX",N-1) \
& cr & cr after theSong
end repeat
return theSong
end beerMe
Yabasic
sub bottle$(i)
if i=0 return "no more bottles of beer"
if i=1 return "1 bottle of beer"
return str$(i) + " bottles of beer"
end sub
for i = 99 to 1 step -1
print bottle$(i), " on the wall, \n", bottle$(i), "\n", "take one down, pass it around,\n", bottle$(i - 1), " on the wall.\n"
next
Yacas
For (b := 99, b > 0, b--)
Echo({b, "bottle(s) of beer on the wall," : Nl(),
b, "bottle(s) of beer." : Nl(),
"Take one down, pass it around," : Nl(),
b - 1, "bottle(s) of beer on the wall." : Nl()});
YAMLScript
#!/usr/bin/env ys-0
# Print the verses to "99 Bottles of Beer"
#
# usage:
# ys 99-bottles.ys [<count>]
defn main(number=99):
each [n (number .. 1)]:
say: paragraph(n)
defn paragraph(num): |
$bottles(num) of beer on the wall,
$bottles(num) of beer.
Take one down, pass it around.
$bottles(num - 1) of beer on the wall.
defn bottles(n):
cond:
n == 0 : 'No more bottles'
n == 1 : '1 bottle'
=> : "$n bottles"
Yorick
Looped version
bottles = 99;
while(bottles) {
write, format=" %d bottles of beer on the wall\n", bottles;
write, format=" %d bottles of beer\n", bottles;
write, "Take one down, pass it around";
write, format=" %d bottles of beer on the wall\n\n", --bottles;
}
Vectorized version
song = "%d bottles of beer on the wall\n";
song += "%d bottles of beer\n";
song += "Take one down, pass it around\n";
song += "%d bottles of beer on the wall\n";
beer = indgen(99:1:-1);
write, format=song, beer, beer, beer-1;
Z80 Assembly
Zig
const print = @import("std").debug.print;
pub fn main() void {
var i: u8 = 99;
while (i > 2) : (i-= 1) {
print(
\\{} bottles of beer on the wall, {} bottles of beer.
\\Take one down and pass it around, {} bottles of beer on the wall.
\\
\\
, .{i, i, i-1});
}
print(
\\2 bottles of beer on the wall, 2 bottles of beer.
\\Take one down and pass it around, 1 bottle of beer on the wall.
\\
\\1 bottle of beer on the wall, 1 bottle of beer.
\\Take one down and pass it around, no more bottles of beer on the wall.
\\
\\No more bottles of beer on the wall, no more bottles of beer.
\\Go to the store and buy some more, 99 bottles of beer on the wall.
, .{});
}
zkl
[99..0,-1].pump(fcn(n){
println(beers(n), " on the wall, ", beers(n).toLower(), ".\n",
n==0 and ("Go to the store and buy some more, 99 bottles of beer") or
("Take one down and pass it around, " + beers(n-1).toLower()),
" on the wall.\n")
});
fcn beers(n){
(n==0 and "No more bottles" or (n==1 and "1 bottle" or "" + n + " bottles"))
+ " of beer"
}
- Output:
99 bottles of beer on the wall, 99 bottles of beer. Take one down and pass it around, 98 bottles of beer on the wall. ... 1 bottle of beer on the wall, 1 bottle of beer. Take one down and pass it around, no more bottles of beer on the wall. No more bottles of beer on the wall, no more bottles of beer. Go to the store and buy some more, 99 bottles of beer on the wall.