Determine if a string has all the same characters

From Rosetta Code
Task
Determine if a string has all the same characters
You are encouraged to solve this task according to the task description, using any language you may know.
Task

Given a character string   (which may be empty, or have a length of zero characters):

  •   create a function/procedure/routine to:
  •   determine if all the characters in the string are the same
  •   indicate if or which character is different from the previous character
  •   display each string and its length   (as the strings are being examined)
  •   a zero─length (empty) string shall be considered as all the same character(s)
  •   process the strings from left─to─right
  •   if       all the same character,   display a message saying such
  •   if not all the same character,   then:
  •   display a message saying such
  •   display what character is different
  •   only the 1st different character need be displayed
  •   display where the different character is in the string
  •   the above messages can be part of a single message
  •   display the hexadecimal value of the different character


Use (at least) these seven test values   (strings):

  •   a string of length   0   (an empty string)
  •   a string of length   3   which contains three blanks
  •   a string of length   1   which contains:   2
  •   a string of length   3   which contains:   333
  •   a string of length   3   which contains:   .55
  •   a string of length   6   which contains:   tttTTT
  •   a string of length   9   with a blank in the middle:   4444   444k


Show all output here on this page.


Related tasks



ALGOL 68[edit]

BEGIN
# return the position of the first different character in s #
# or UPB s + 1 if all the characters are the same #
OP FIRSTDIFF = ( STRING s )INT:
IF UPB s <= LWB s
THEN
# 0 or 1 character #
UPB s + 1
ELSE
# two or more characters #
INT result := LWB s + 1;
CHAR c1 = s[ LWB s ];
FOR s pos FROM LWB s + 1 TO UPB s WHILE s[ s pos ] = c1 DO result +:= 1 OD;
result
FI # FIRSTDIFF # ;
# convert a character to a hex string #
PROC hex = ( CHAR c )STRING:
BEGIN
STRING result := "";
INT n := ABS c;
IF n = 0
THEN
result := "0"
ELSE
WHILE n > 0 DO
INT d = n MOD 16;
n OVERAB 16;
IF d < 10
THEN REPR ( d + ABS "0" )
ELSE REPR ( ( d - 10 ) + ABS "0" )
FI +=: result
OD
FI;
result
END # hex # ;
# show whether s contains all the same character of the first diff #
PROC show first diff = ( STRING s )VOID:
IF print( ( """", s, """ (length ", whole( ( UPB s + 1 ) - LWB s, 0 ), "): " ) );
INT diff pos = FIRSTDIFF s;
diff pos > UPB s
THEN
# all characters the same #
print( ( "all characters are the same", newline ) )
ELSE
# not all characters are the same #
print( ( "first different character """
, s[ diff pos ]
, """(0x", hex( s[ diff pos ] )
, ") at position: "
, whole( diff pos, 0 )
, newline
)
)
FI # show first diff # ;
# task test cases #
show first diff( "" );
show first diff( " " );
show first diff( "2" );
show first diff( "333" );
show first diff( ".55" );
show first diff( "tttTTT" );
show first diff( "4444 444k" )
END
Output:
"" (length 0): all characters are the same
"   " (length 3): all characters are the same
"2" (length 1): all characters are the same
"333" (length 3): all characters are the same
".55" (length 3): first different character "5"(0x35) at position: 2
"tttTTT" (length 6): first different character "T"(0x54) at position: 4
"4444 444k" (length 9): first different character " "(0x20) at position: 5

AWK[edit]

 
# syntax: GAWK -f DETERMINE_IF_A_STRING_HAS_ALL_THE_SAME_CHARACTERS.AWK
BEGIN {
for (i=0; i<=255; i++) { ord_arr[sprintf("%c",i)] = i } # build array[character]=ordinal_value
n = split(", ,2,333,.55,tttTTT,4444 444k",arr,",")
for (i in arr) {
width = max(width,length(arr[i]))
}
width += 2
fmt = "| %-*s | %-6s | %-8s | %-8s | %-3s | %-8s |\n"
head1 = head2 = sprintf(fmt,width,"string","length","all same","1st diff","hex","position")
gsub(/[^|\n]/,"-",head1)
printf(head1 head2 head1) # column headings
for (i=1; i<=n; i++) {
main(arr[i])
}
printf(head1) # column footing
exit(0)
}
function main(str, c,first_diff,hex,i,leng,msg,position) {
msg = "yes"
leng = length(str)
for (i=1; i<leng; i++) {
c = substr(str,i+1,1)
if (substr(str,i,1) != c) {
msg = "no"
first_diff = "'" c "'"
hex = sprintf("%2X",ord_arr[c])
position = i + 1
break
}
}
printf(fmt,width,"'" str "'",leng,msg,first_diff,hex,position)
}
function max(x,y) { return((x > y) ? x : y) }
 
Output:
|-------------|--------|----------|----------|-----|----------|
| string      | length | all same | 1st diff | hex | position |
|-------------|--------|----------|----------|-----|----------|
| ''          | 0      | yes      |          |     |          |
| '   '       | 3      | yes      |          |     |          |
| '2'         | 1      | yes      |          |     |          |
| '333'       | 3      | yes      |          |     |          |
| '.55'       | 3      | no       | '5'      | 35  | 2        |
| 'tttTTT'    | 6      | no       | 'T'      | 54  | 4        |
| '4444 444k' | 9      | no       | ' '      | 20  | 5        |
|-------------|--------|----------|----------|-----|----------|

C[edit]

In interactive mode, strings with spaces have to be enclosed in double quotes ("")

 
#include<string.h>
#include<stdio.h>
 
int main(int argc,char** argv)
{
int i,len;
char reference;
 
if(argc>2){
printf("Usage : %s <Test String>\n",argv[0]);
return 0;
}
 
if(argc==1||strlen(argv[1])==1){
printf("Input string : \"%s\"\nLength : %d\nAll characters are identical.\n",argc==1?"":argv[1],argc==1?0:(int)strlen(argv[1]));
return 0;
}
 
reference = argv[1][0];
len = strlen(argv[1]);
 
for(i=1;i<len;i++){
if(argv[1][i]!=reference){
printf("Input string : \"%s\"\nLength : %d\nFirst different character : \"%c\"(0x%x) at position : %d\n",argv[1],len,argv[1][i],argv[1][i],i+1);
return 0;
}
}
 
printf("Input string : \"%s\"\nLength : %d\nAll characters are identical.\n",argv[1],len);
 
return 0;
 
}
 

Output :

[email protected]:~/doodles$ ./a.out
Input string : ""
Length : 0
All characters are identical.
[email protected]:~/doodles$ ./a.out "   "
Input string : "   "
Length : 3
All characters are identical.
[email protected]:~/doodles$ ./a.out 2
Input string : "2"
Length : 1
All characters are identical.
[email protected]:~/doodles$ ./a.out 333
Input string : "333"
Length : 3
All characters are identical.
[email protected]:~/doodles$ ./a.out .55
Input string : ".55"
Length : 3
First different character : "5"(0x35) at position : 2
[email protected]:~/doodles$ ./a.out tttTTT
Input string : "tttTTT"
Length : 6
First different character : "T"(0x54) at position : 4
[email protected]:~/doodles$ ./a.out "4444 444k"
Input string : "4444 444k"
Length : 9
First different character : " "(0x20) at position : 5

Factor[edit]

USING: formatting io kernel math.parser sequences ;
 
: find-diff ( str -- i elt ) dup ?first [ = not ] curry find ;
: len. ( str -- ) dup length "%u — length %d — " printf ;
: same. ( -- ) "contains all the same character." print ;
: diff. ( -- ) "contains a different character at " write ;
 
: not-same. ( i elt -- )
dup >hex diff. "index %d: '%c' (0x%s)\n" printf ;
 
: sameness-report. ( str -- )
dup len. find-diff dup [ not-same. ] [ 2drop same. ] if ;
 
{
""
" "
"2"
"333"
".55"
"tttTTT"
"4444 444k"
} [ sameness-report. ] each
Output:
"" — length 0 — contains all the same character.
"   " — length 3 — contains all the same character.
"2" — length 1 — contains all the same character.
"333" — length 3 — contains all the same character.
".55" — length 3 — contains a different character at index 1: '5' (0x35)
"tttTTT" — length 6 — contains a different character at index 3: 'T' (0x54)
"4444 444k" — length 9 — contains a different character at index 4: ' ' (0x20)

Go[edit]

package main
 
import "fmt"
 
func analyze(s string) {
chars := []rune(s)
le := len(chars)
fmt.Printf("Analyzing %q which has a length of %d:\n", s, le)
if le > 1 {
for i := 1; i < le; i++ {
if chars[i] != chars[i-1] {
fmt.Println(" Not all characters in the string are the same.")
fmt.Printf("  %q (%#[1]x) is different at position %d.\n\n", chars[i], i+1)
return
}
}
}
fmt.Println(" All characters in the string are the same.\n")
}
 
func main() {
strings := []string{
"",
" ",
"2",
"333",
".55",
"tttTTT",
"4444 444k",
"pépé",
"🐶🐶🐺🐶",
"🎄🎄🎄🎄",
}
for _, s := range strings {
analyze(s)
}
}
Output:
Analyzing "" which has a length of 0:
  All characters in the string are the same.

Analyzing "   " which has a length of 3:
  All characters in the string are the same.

Analyzing "2" which has a length of 1:
  All characters in the string are the same.

Analyzing "333" which has a length of 3:
  All characters in the string are the same.

Analyzing ".55" which has a length of 3:
  Not all characters in the string are the same.
  '5' (0x35) is different at position 2.

Analyzing "tttTTT" which has a length of 6:
  Not all characters in the string are the same.
  'T' (0x54) is different at position 4.

Analyzing "4444 444k" which has a length of 9:
  Not all characters in the string are the same.
  ' ' (0x20) is different at position 5.

Analyzing "pépé" which has a length of 4:
  Not all characters in the string are the same.
  'é' (0xe9) is different at position 2.

Analyzing "🐶🐶🐺🐶" which has a length of 4:
  Not all characters in the string are the same.
  '🐺' (0x1f43a) is different at position 3.

Analyzing "🎄🎄🎄🎄" which has a length of 4:
  All characters in the string are the same.

Haskell[edit]

import Numeric (showHex)
import Data.List (span)
import Data.Char (ord)
 
inconsistentChar :: String -> Maybe (Int, Char)
inconsistentChar [] = Nothing
inconsistentChar xs@(x:_) =
let (pre, post) = span (x ==) xs
in if null post
then Nothing
else Just (length pre, head post)
 
 
---------------------------TEST----------------------------
samples :: [String]
samples = [" ", "2", "333", ".55", "tttTTT", "4444 444"]
 
main :: IO ()
main = do
let w = succ . maximum $ length <$> samples
justifyRight n c = (drop . length) <*> (replicate n c ++)
f = (++ "' -> ") . justifyRight w ' ' . ('\'' :)
(putStrLn . unlines) $
(\s ->
maybe
(f s ++ "consistent")
(\(n, c) ->
f s ++
"inconsistent '" ++
c : "' (0x" ++ showHex (ord c) ")" ++ " at char " ++ show (succ n))
(inconsistentChar s)) <$>
samples

and inconsistentChar could alternatively be defined in terms of findIndex:

import Data.List (findIndex)
 
inconsistentChar :: String -> Maybe (Int, Char)
inconsistentChar [] = Nothing
inconsistentChar xs@(x:_) = findIndex (x /=) xs >>= Just . ((,) <*> (xs !!))
Output:
     '   ' -> consistent
       '2' -> consistent
     '333' -> consistent
     '.55' -> inconsistent '5' (0x35) at char 2
  'tttTTT' -> inconsistent 'T' (0x54) at char 4
'4444 444' -> inconsistent ' ' (0x20) at char 5

Julia[edit]

firstdifferent(s) = isempty(s) ? nothing : findfirst(x -> x != s[1], s)
 
function testfunction(strings)
println("String | Length | All Same | First Different(Hex) | Position\n" *
"-----------------------------------------------------------------------------")
for s in strings
n = firstdifferent(s)
println(rpad(s, 27), rpad(length(s), 9), n == nothing ? "yes" :
rpad("no $(s[n]) ($(string(Int(s[n]), base=16)))", 36) * string(n))
end
end
 
testfunction([
"",
" ",
"2",
"333",
".55",
"tttTTT",
"4444 444k",
"pépé",
"🐶🐶🐺🐶",
"🎄🎄🎄🎄",
])
 
Output:
String                  | Length | All Same | First Different(Hex) | Position
-----------------------------------------------------------------------------
                           0        yes
                           3        yes
2                          1        yes
333                        3        yes
.55                        3        no               5   (35)           2
tttTTT                     6        no               T   (54)           4
4444 444k                  9        no                   (20)           5
pépé                       4        no               é   (e9)           2
🐶🐶🐺🐶                 4        no               🐺  (1f43a)        9
🎄🎄🎄🎄                   4        yes

Kotlin[edit]

Translation of: Go
fun analyze(s: String) {
println("Examining [$s] which has a length of ${s.length}:")
if (s.length > 1) {
val b = s[0]
for ((i, c) in s.withIndex()) {
if (c != b) {
println(" Not all characters in the string are the same.")
println(" '$c' (0x${Integer.toHexString(c.toInt())}) is different at position $i")
return
}
}
}
println(" All characters in the string are the same.")
}
 
fun main() {
val strs = listOf("", " ", "2", "333", ".55", "tttTTT", "4444 444k")
for (str in strs) {
analyze(str)
}
}
Output:
Examining [] which has a length of 0:
    All characters in the string are the same.
Examining [   ] which has a length of 3:
    All characters in the string are the same.
Examining [2] which has a length of 1:
    All characters in the string are the same.
Examining [333] which has a length of 3:
    All characters in the string are the same.
Examining [.55] which has a length of 3:
    Not all characters in the string are the same.
    '5' (0x35) is different at position 1
Examining [tttTTT] which has a length of 6:
    Not all characters in the string are the same.
    'T' (0x54) is different at position 3
Examining [4444 444k] which has a length of 9:
    Not all characters in the string are the same.
    ' ' (0x20) is different at position 4

Pascal[edit]

program SameNessOfChar;
{$IFDEF FPC}
{$MODE DELPHI}{$OPTIMIZATION ON,ALL}{$CODEALIGN proc=16}{$ALIGN 16}
{$ELSE}
{$APPTYPE CONSOLE}
{$ENDIF}
uses
sysutils;//Format
const
TestData : array[0..6] of String =
('',' ','2','333','.55','tttTTT','4444 444k');
function PosOfDifferentChar(const s: String):NativeInt;
var
i: Nativeint;
ch:char;
Begin
result := length(s);
IF result < 2 then
EXIT;
ch := s[1];
i := 2;
while (i< result) AND (S[i] =ch) do
inc(i);
result := i;
end;
 
procedure OutIsAllSame(const s: String);
var
l,len: NativeInt;
Begin
l := PosOfDifferentChar(s);
len := Length(s);
write('"',s,'" of length ',len);
IF l = len then
writeln(' contains all the same character')
else
writeln(Format(' is different at position %d "%s" (0x%X)',[l,s[l],Ord(s[l])]));
end;
 
var
i : NativeInt;
begin
For i := Low(TestData) to HIgh(TestData) do
OutIsAllSame(TestData[i]);
end.
Output:
"" of length 0 contains all the same character
"   " of length 3 contains all the same character
"2" of length 1 contains all the same character
"333" of length 3 contains all the same character
".55" of length 3 is different at position 2 "5" (0x35)
"tttTTT" of length 6 is different at position 4 "T" (0x54)
"4444 444k" of length 9 is different at position 5 " " (0x20)

Perl[edit]

use strict;
use warnings;
use feature 'say';
use utf8;
binmode(STDOUT, ':utf8');
use List::AllUtils qw(uniq);
use Unicode::UCD 'charinfo';
use Unicode::Normalize qw(NFC);
 
for my $str (
'',
' ',
'2',
'333',
'.55',
'tttTTT',
'4444 444k',
'Δ👍👨',
'🇬🇧🇬🇧🇬🇧🇬🇧',
"\N{LATIN CAPITAL LETTER A}\N{COMBINING DIAERESIS}\N{COMBINING MACRON}" .
"\N{LATIN CAPITAL LETTER A WITH DIAERESIS}\N{COMBINING MACRON}" .
"\N{LATIN CAPITAL LETTER A WITH DIAERESIS AND MACRON}"
) {
my @S;
push @S, NFC $1 while $str =~ /(\X)/g;
printf qq{\n"$str" (length: %d) has }, scalar @S;
my @U = uniq @S;
if (1 != @U and @U > 0) {
say 'different characters:';
for my $l (@U) {
printf "'%s' %s (0x%x) in positions: %s\n",
$l, charinfo(ord $l)->{'name'}, ord($l), join ', ', map { 1+$_ } grep { $l eq $S[$_] } 0..$#S;
}
} else {
say 'the same character in all positions.'
}
}
Output:
"" (length: 0) has the same character in all positions.

"   " (length: 3) has the same character in all positions.

"2" (length: 1) has the same character in all positions.

"333" (length: 3) has the same character in all positions.

".55" (length: 3) has different characters:
'.' FULL STOP (0x2e) in positions: 1
'5' DIGIT FIVE (0x35) in positions: 2, 3

"tttTTT" (length: 6) has different characters:
't' LATIN SMALL LETTER T (0x74) in positions: 1, 2, 3
'T' LATIN CAPITAL LETTER T (0x54) in positions: 4, 5, 6

"4444 444k" (length: 9) has different characters:
'4' DIGIT FOUR (0x34) in positions: 1, 2, 3, 4, 6, 7, 8
' ' SPACE (0x20) in positions: 5
'k' LATIN SMALL LETTER K (0x6b) in positions: 9

"Δ👍👨" (length: 3) has different characters:
'Δ' GREEK CAPITAL LETTER DELTA (0x394) in positions: 1
'👍' THUMBS UP SIGN (0x1f44d) in positions: 2
'👨' MAN (0x1f468) in positions: 3

"🇬🇧🇬🇧🇬🇧🇬🇧" (length: 4) has the same character in all positions.

"ǞǞǞ" (length: 3) has the same character in all positions.

Perl 6[edit]

Works with: Rakudo version 2019.07.1

The last string demonstrates how Perl 6 can recognize that glyphs made up of different combinations of combining characters can compare the same. It is built up from explicit codepoints to show that each of the glyphs is made up of different combinations.

  -> $str {
my $i = 0;
print "\n{$str.perl} (length: {$str.chars}), has ";
my %m;
%m{$_}.push: ++$i for $str.comb;
 
if %m > 1 {
say "different characters:";
say "'{.key}' ({.key.uninames}; hex ordinal: {(.key.ords).fmt: "0x%X"})" ~
" in positions: {.value.join: ', '}" for %m.sort( *.value[0] );
} else {
say "the same character in all positions."
}
} for
'',
' ',
'2',
'333',
'.55',
'tttTTT',
'4444 444k',
'🇬🇧🇬🇧🇬🇧🇬🇧',
"\c[LATIN CAPITAL LETTER A]\c[COMBINING DIAERESIS]\c[COMBINING MACRON]" ~
"\c[LATIN CAPITAL LETTER A WITH DIAERESIS]\c[COMBINING MACRON]" ~
"\c[LATIN CAPITAL LETTER A WITH DIAERESIS AND MACRON]",
'AАΑꓮ𐌀𐊠Ꭺ'
Output:
"" (length: 0), has the same character in all positions.

"   " (length: 3), has the same character in all positions.

"2" (length: 1), has the same character in all positions.

"333" (length: 3), has the same character in all positions.

".55" (length: 3), has different characters:
'.' (FULL STOP; hex ordinal: 0x2E) in positions: 1
'5' (DIGIT FIVE; hex ordinal: 0x35) in positions: 2, 3

"tttTTT" (length: 6), has different characters:
't' (LATIN SMALL LETTER T; hex ordinal: 0x74) in positions: 1, 2, 3
'T' (LATIN CAPITAL LETTER T; hex ordinal: 0x54) in positions: 4, 5, 6

"4444 444k" (length: 9), has different characters:
'4' (DIGIT FOUR; hex ordinal: 0x34) in positions: 1, 2, 3, 4, 6, 7, 8
' ' (SPACE; hex ordinal: 0x20) in positions: 5
'k' (LATIN SMALL LETTER K; hex ordinal: 0x6B) in positions: 9

"🇬🇧🇬🇧🇬🇧🇬🇧" (length: 4), has the same character in all positions.

"ǞǞǞ" (length: 3), has the same character in all positions.

"AАΑꓮ𐌀𐊠Ꭺ" (length: 7), has different characters:
'A' (LATIN CAPITAL LETTER A; hex ordinal: 0x41) in positions: 1
'А' (CYRILLIC CAPITAL LETTER A; hex ordinal: 0x410) in positions: 2
'Α' (GREEK CAPITAL LETTER ALPHA; hex ordinal: 0x391) in positions: 3
'ꓮ' (LISU LETTER A; hex ordinal: 0xA4EE) in positions: 4
'𐌀' (OLD ITALIC LETTER A; hex ordinal: 0x10300) in positions: 5
'𐊠' (CARIAN LETTER A; hex ordinal: 0x102A0) in positions: 6
'Ꭺ' (CHEROKEE LETTER GO; hex ordinal: 0x13AA) in positions: 7

Phix[edit]

procedure samechar(sequence s)
string msg = "all characters are the same"
integer l = length(s)
if l>=2 then
integer ch = s[1]
for i=2 to l do
integer si = s[i]
if si!=ch then
msg = sprintf(`first different character "%c"(#%02x) at position %d`,{si,si,i})
exit
end if
end for
end if
printf(1,"\"%s\" (length %d): %s\n",{s,l,msg})
end procedure
 
constant tests = {""," ","2","333",".55","tttTTT","4444 444k",
utf8_to_utf32("🐶🐶🐺🐶"),utf8_to_utf32("🎄🎄🎄🎄")}
for i=1 to length(tests) do samechar(tests[i]) end for
Output:
"" (length 0): all characters are the same
"   " (length 3): all characters are the same
"2" (length 1): all characters are the same
"333" (length 3): all characters are the same
".55" (length 3): first different character "5"(#35) at position 2
"tttTTT" (length 6): first different character "T"(#54) at position 4
"4444 444k" (length 9): first different character " "(#20) at position 5
"🐶🐶🐺🐶" (length 4): first different character "🐺"(#1F43A) at position 3
"🎄🎄🎄🎄" (length 4): all characters are the same

Python[edit]

Functional[edit]

What we are testing here is the cardinality of the set of characters from which a string is drawn, so the first thought might well be to use set.

On the other hand, itertools.groupby has the advantage of yielding richer information (the list of groups is ordered), for less work.

Works with: Python version 3.7
'''Determine if a string has all the same characters'''
 
from itertools import groupby
 
 
# firstDifferingCharLR :: String -> Either String Dict
def firstDifferingCharLR(s):
'''Either a message reporting that no character changes were
seen, or a dictionary with details of the first character
(if any) that differs from that at the head of the string.
'''

def details(xs):
c = xs[1][0]
return {
'char': repr(c),
'hex': hex(ord(c)),
'index': s.index(c),
'total': len(s)
}
xs = list(groupby(s))
return Right(details(xs)) if 1 < len(xs) else (
Left('Total length ' + str(len(s)) + ' - No character changes.')
)
 
 
# TEST ----------------------------------------------------
# main :: IO ()
def main():
'''Test of 7 strings'''
 
print(fTable('First, if any, points of difference:\n')(repr)(
either(identity)(
lambda dct: dct['char'] + ' (' + dct['hex'] +
') at character ' + str(1 + dct['index']) +
' of ' + str(dct['total']) + '.'
)
)(firstDifferingCharLR)([
'',
' ',
'2',
'333',
'.55',
'tttTTT',
'4444 444'
]))
 
 
# GENERIC -------------------------------------------------
 
# either :: (a -> c) -> (b -> c) -> Either a b -> c
def either(fl):
'''The application of fl to e if e is a Left value,
or the application of fr to e if e is a Right value.
'''

return lambda fr: lambda e: fl(e['Left']) if (
None is e['Right']
) else fr(e['Right'])
 
 
# identity :: a -> a
def identity(x):
'''The identity function.'''
return x
 
 
# fTable :: String -> (a -> String) ->
# (b -> String) -> (a -> b) -> [a] -> String
def fTable(s):
'''Heading -> x display function -> fx display function ->
f -> xs -> tabular string.
'''

def go(xShow, fxShow, f, xs):
ys = [xShow(x) for x in xs]
w = max(map(len, ys))
return s + '\n' + '\n'.join(map(
lambda x, y: y.rjust(w, ' ') + ' -> ' + fxShow(f(x)),
xs, ys
))
return lambda xShow: lambda fxShow: lambda f: lambda xs: go(
xShow, fxShow, f, xs
)
 
 
# Left :: a -> Either a b
def Left(x):
'''Constructor for an empty Either (option type) value
with an associated string.
'''

return {'type': 'Either', 'Right': None, 'Left': x}
 
 
# Right :: b -> Either a b
def Right(x):
'''Constructor for a populated Either (option type) value'''
return {'type': 'Either', 'Left': None, 'Right': x}
 
 
# MAIN ---
if __name__ == '__main__':
main()
Output:
First, if any, points of difference:

        '' -> Total length 0 - No character changes.
     '   ' -> Total length 3 - No character changes.
       '2' -> Total length 1 - No character changes.
     '333' -> Total length 3 - No character changes.
     '.55' -> '5' (0x35) at character 2 of 3.
  'tttTTT' -> 'T' (0x54) at character 4 of 6.
'4444 444' -> ' ' (0x20) at character 5 of 8.


and for very long strings, itertools.takewhile (here used in the definition of a more general span function), should be slightly more efficient:

'''Determine if a string has all the same characters'''
 
from itertools import takewhile
 
 
# inconsistentChar :: String -> Maybe (Int, Char)
def inconsistentChar(s):
'''Just the first inconsistent character and its position,
or Nothing if all the characters of s are the same,
'''

if s:
h = s[0]
pre, post = span(lambda c: h == c)(s)
return Just((len(pre), post[0])) if post else Nothing()
else:
return Nothing()
 
 
# --------------------------TEST---------------------------
# main :: IO ()
def main():
'''Consistency tests of seven strings'''
 
samples = ['', ' ', '2', '333', '.55', 'tttTTT', '4444 444']
w = 1 + max(map(len, samples))
 
def pfx(s):
return ("'" + s).rjust(w) + "' -> "
 
def charPosn(ic):
i, c = ic
return "inconsistent '" + c + "' (" + hex(ord(c)) + ")" + (
" at char " + str(1 + i)
)
 
print(main.__doc__ + ':\n')
print(
'\n'.join([
pfx(s) + maybe('consistent')(charPosn)(
inconsistentChar(s)
)
for s in samples
])
)
 
 
# -------------------------GENERIC-------------------------
 
# Just :: a -> Maybe a
def Just(x):
'''Constructor for an inhabited Maybe (option type) value.
Wrapper containing the result of a computation.
'''

return {'type': 'Maybe', 'Nothing': False, 'Just': x}
 
 
# Nothing :: Maybe a
def Nothing():
'''Constructor for an empty Maybe (option type) value.
Empty wrapper returned where a computation is not possible.
'''

return {'type': 'Maybe', 'Nothing': True}
 
 
# maybe :: b -> (a -> b) -> Maybe a -> b
def maybe(v):
'''Either the default value v, if m is Nothing,
or the application of f to x,
where m is Just(x).
'''

return lambda f: lambda m: v if None is m or m.get('Nothing') else (
f(m.get('Just'))
)
 
 
# span :: (a -> Bool) -> [a] -> ([a], [a])
def span(p):
'''The longest (possibly empty) prefix of xs
that contains only elements satisfying p,
tupled with the remainder of xs.
span p xs is equivalent to (takeWhile p xs, dropWhile p xs).
'''

def go(xs):
prefix = list(takewhile(p, xs))
return (prefix, xs[len(prefix):])
return lambda xs: go(xs)
 
 
# MAIN ---
if __name__ == '__main__':
main()

Putting itertools aside, we could equivalently define inconsistentChar as:

# inconsistentChar :: String -> Maybe (Int, Char)
def inconsistentChar(s):
'''Just the first inconsistent character and its index,
or Nothing if all the characters of s are the same.
'''

return next(
(Just(ix) for ix in enumerate(s) if s[0] != ix[1]),
Nothing()
)
Output:
Consistency tests of seven strings:

        '' -> consistent
     '   ' -> consistent
       '2' -> consistent
     '333' -> consistent
     '.55' -> inconsistent '5' (0x35) at char 2
  'tttTTT' -> inconsistent 'T' (0x54) at char 4
'4444 444' -> inconsistent ' ' (0x20) at char 5

Racket[edit]

#lang racket
 
(define (first-non-matching-index l =)
(and (not (null? l)) (index-where l (curry (negate =) (car l)))))
 
(define (report-string-sameness s)
(printf "~s (length: ~a): ~a~%"
s
(string-length s)
(cond [(first-non-matching-index (string->list s) char=?)
=> (λ (i)
(let ((c (string-ref s i)))
(format "first different character ~s(~a) at position: ~a" c (char->integer c) (add1 i))))]
[else "all characters are the same"])))
 
(module+ test
(for-each report-string-sameness '("" " " "2" "333" ".55" "tttTTT" "4444 444k")))
Output:
"" (length: 0): all characters are the same
"   " (length: 3): all characters are the same
"2" (length: 1): all characters are the same
"333" (length: 3): all characters are the same
".55" (length: 3): first different character #\5(53) at position: 2
"tttTTT" (length: 6): first different character #\T(84) at position: 4
"4444 444k" (length: 9): first different character #\space(32) at position: 5

REXX[edit]

/*REXX program verifies that  all characters  in a string are all the same (character). */
@chr= ' [character' /* define a literal used for SAY.*/
@all= 'all the same character for string (length' /* " " " " " " */
@.= /*define a default for the @. array. */
parse arg x /*obtain optional argument from the CL.*/
if x\='' then @.1= x /*if user specified an arg, use that. */
else do; @.1= /*use this null string if no arg given.*/
@.2= ' ' /* " " " " " " " */
@.3= 2 /* " " " " " " " */
@.4= 333 /* " " " " " " " */
@.5= .55 /* " " " " " " " */
@.6= 'tttTTT' /* " " " " " " " */
@.7= 4444 444k /* " " " " " " " */
end /* [↑] seventh value contains a blank.*/
 
do j=1; L= length(@.j) /*obtain the length of an array element*/
if j>1 & L==0 then leave /*if arg is null and J>1, then leave. */
r= allSame(@.j) /*R: ≡0, or the location of bad char.*/
if r\==0 then ?= substr(@.j,r,1) /*if not monolithic, obtain the char.*/
if r==0 then say ' ' @all L"):" @.j
else say 'not' @all L"):" @.j @chr ? "('"c2x(?)"'x) at position" r"]."
end /*j*/
exit /*stick a fork in it, we're all done. */
/*──────────────────────────────────────────────────────────────────────────────────────*/
allSame: procedure; parse arg y /*get a value from the argument list. */
if y=='' then return 0 /*if Y is null, then return 0 (zero)*/
return verify(y, left(y,1) ) /*All chars the same? Return 0 (zero)*/
/* else return location*/
output   when using the internal default inputs:
    all the same character for string (length 0):
    all the same character for string (length 3):
    all the same character for string (length 1): 2
    all the same character for string (length 3): 333
not all the same character for string (length 3): .55      [character 5 ('35'x)  at position 2].
not all the same character for string (length 6): tttTTT      [character T ('54'x)  at position 4].
not all the same character for string (length 9): 4444 444K      [character   ('20'x)  at position 5].

Scala[edit]

import scala.collection.immutable.ListMap
 
object StringAllSameCharacters {
 
/**Transform an input String into an HashMap of its characters and its first occurrence index*/
def countChar( s : String) : Map[Char, Int] = {
val mapChar = s.toSeq.groupBy(identity).map{ case (a,b) => a->s.indexOf(a) }
val orderedMapChar = ListMap(mapChar.toSeq.sortWith(_._2 < _._2):_*)
orderedMapChar
}
 
/**Check if all the characters of a String are the same given an input Hashmap of it */
def areAllCharEquals ( mapChar : Map[Char, Int] ) : Boolean = {
return mapChar.size <= 1
}
 
/**Retrieve the first "breaking" different character of a String*/
def findFirstDifferentChar ( mapChar : Map[Char, Int] ) : Char = {
if(areAllCharEquals(mapChar) == false) mapChar.keys.toList(1)
else 0.toChar
}
 
/**Convert char to hexadecimal values as "0xHEXVALUE" */
def charToHexString ( c : Char) : String = "0x" + c.toHexString
 
/**Display results as asked in the ask*/
def reportResults( s : String) : String = {
val mapChar = countChar(s)
if (areAllCharEquals(mapChar)) s + " -- length " + s.size + " -- contains all the same character."
else {
val diffChar = findFirstDifferentChar(mapChar)
s + " -- length " + s.size +
" -- contains a different character at index " +
(s.indexOf(diffChar).toInt+1).toString + " : " + charToHexString(diffChar)
}
}
 
def main(args: Array[String]): Unit = {
println(reportResults(""))
println(reportResults(" "))
println(reportResults("2"))
println(reportResults("333"))
println(reportResults(".55"))
println(reportResults("tttTTT"))
println(reportResults("4444 444k"))
}
 
 
}
 
 
Output:
 -- length 0 -- contains all the same character.
    -- length 3 -- contains all the same character.
2 -- length 1 -- contains all the same character.
333 -- length 3 -- contains all the same character.
.55 -- length 3 -- contains a different character at index 2 : 0x35
tttTTT -- length 6 -- contains a different character at index 4 : 0x54
4444 444k -- length 9 -- contains a different character at index 5 : 0x20

XPL0[edit]

include xpllib;                 \contains StrLen function
 
proc StrSame(S); \Show if string has same characters
char S;
int L, I, J, K;
[L:= StrLen(S);
IntOut(0, L); Text(0, ": ^""); Text(0, S); ChOut(0, ^"); CrLf(0);
for I:= 0 to L-1 do
for J:= I+1 to L-1 do
[if S(I) # S(J) then
[ChOut(0, \tab\ 9);
for K:= 0 to J do ChOut(0, ^ );
Text(0, "^^ Not same character: ");
ChOut(0, S(J));
Text(0, ", hex ");
SetHexDigits(2);
HexOut(0, S(J));
CrLf(0);
return;
];
];
Text(0, " All same character"); CrLf(0);
];
 
[Text(0, "Length"); CrLf(0);
StrSame("");
StrSame(" ");
StrSame("2");
StrSame("333");
StrSame(".55");
StrSame("tttTTT");
StrSame("4444 444k");
]
Output:
Length
0:      ""
        All same character
3:      "   "
        All same character
1:      "2"
        All same character
3:      "333"
        All same character
3:      ".55"
          ^ Not same character: 5, hex 35
6:      "tttTTT"
            ^ Not same character: T, hex 54
9:      "4444 444k"
             ^ Not same character:  , hex 20

zkl[edit]

fcn stringSameness(str){  // Does not handle Unicode
sz,unique,uz := str.len(), str.unique(), unique.len();
println("Length %d: \"%s\"".fmt(sz,str));
if(sz==uz or uz==1) println("\tSame character in all positions");
else
println("\tDifferent: ",
unique[1,*].pump(List,
'wrap(c){ "'%s' (0x%x)[%d]".fmt(c,c.toAsc(), str.find(c)+1) })
.concat(", "));
}
testStrings:=T("", "   ", "2", "333", ".55", "tttTTT", "4444 444k");
foreach s in (testStrings){ stringSameness(s) }
Output:
Length 0: ""
	Same character in all positions
Length 3: "   "
	Same character in all positions
Length 1: "2"
	Same character in all positions
Length 3: "333"
	Same character in all positions
Length 3: ".55"
	Different: '5' (0x35)[2]
Length 6: "tttTTT"
	Different: 'T' (0x54)[4]
Length 9: "4444 444k"
	Different: ' ' (0x20)[5], 'k' (0x6b)[9]