99 bottles of beer
(Redirected from 99 Bottles of beer)
You are encouraged to solve this task according to the task description, using any language you may know.
- Task
Display the complete lyrics for the song: 99 Bottles of Beer on the Wall.
- The beer song
The lyrics follow this form:
- 99 bottles of beer on the wall
- 99 bottles of beer
- Take one down, pass it around
- 98 bottles of beer on the wall
- 98 bottles of beer on the wall
- 98 bottles of beer
- Take one down, pass it around
- 97 bottles of beer on the wall
... and so on, until reaching 0 (zero).
Grammatical support for 1 bottle of beer is optional.
As with any puzzle, try to do it in as creative/concise/comical a way as possible (simple, obvious solutions allowed, too).
Other tasks related to string operations:
- Metrics
- Counting
- Word frequency
- Letter frequency
- Jewels and stones
- I before E except after C
- Bioinformatics/base count
- Count occurrences of a substring
- Count how many vowels and consonants occur in a string
- Remove/replace
- XXXX redacted
- Conjugate a Latin verb
- Remove vowels from a string
- String interpolation (included)
- Strip block comments
- Strip comments from a string
- Strip a set of characters from a string
- Strip whitespace from a string -- top and tail
- Strip control codes and extended characters from a string
- Anagrams/Derangements/shuffling
- Word wheel
- ABC problem
- Sattolo cycle
- Knuth shuffle
- Ordered words
- Superpermutation minimisation
- Textonyms (using a phone text pad)
- Anagrams
- Anagrams/Deranged anagrams
- Permutations/Derangements
- Find/Search/Determine
- ABC words
- Odd words
- Word ladder
- Semordnilap
- Word search
- Wordiff (game)
- String matching
- Tea cup rim text
- Alternade words
- Changeable words
- State name puzzle
- String comparison
- Unique characters
- Unique characters in each string
- Extract file extension
- Levenshtein distance
- Palindrome detection
- Common list elements
- Longest common suffix
- Longest common prefix
- Compare a list of strings
- Longest common substring
- Find common directory path
- Words from neighbour ones
- Change e letters to i in words
- Non-continuous subsequences
- Longest common subsequence
- Longest palindromic substrings
- Longest increasing subsequence
- Words containing "the" substring
- Sum of the digits of n is substring of n
- Determine if a string is numeric
- Determine if a string is collapsible
- Determine if a string is squeezable
- Determine if a string has all unique characters
- Determine if a string has all the same characters
- Longest substrings without repeating characters
- Find words which contains all the vowels
- Find words which contains most consonants
- Find words which contains more than 3 vowels
- Find words which first and last three letters are equals
- Find words which odd letters are consonants and even letters are vowels or vice_versa
- Formatting
- Substring
- Rep-string
- Word wrap
- String case
- Align columns
- Literals/String
- Repeat a string
- Brace expansion
- Brace expansion using ranges
- Reverse a string
- Phrase reversals
- Comma quibbling
- Special characters
- String concatenation
- Substring/Top and tail
- Commatizing numbers
- Reverse words in a string
- Suffixation of decimal numbers
- Long literals, with continuations
- Numerical and alphabetical suffixes
- Abbreviations, easy
- Abbreviations, simple
- Abbreviations, automatic
- Song lyrics/poems/Mad Libs/phrases
- Mad Libs
- Magic 8-ball
- 99 Bottles of Beer
- The Name Game (a song)
- The Old lady swallowed a fly
- The Twelve Days of Christmas
- Tokenize
- Text between
- Tokenize a string
- Word break problem
- Tokenize a string with escaping
- Split a character string based on change of character
- Sequences
- See also
- http://99-bottles-of-beer.net/
- Category:99_Bottles_of_Beer
- Category:Programming language families
- Wikipedia 99 bottles of beer
0815[edit]
See 99 Bottles of Beer/EsoLang
11l[edit]
L(i) (99..1).step(-1)
print(i‘ bottles of beer on the wall’)
print(i‘ bottles of beer’)
print(‘Take one down, pass it around’)
print((i - 1)" bottles of beer on the wall\n")360 Assembly[edit]
See 99 Bottles of Beer/Assembly
6502 Assembly[edit]
See 99 Bottles of Beer/Assembly
6800 Assembly[edit]
See 99 Bottles of Beer/Assembly
68000 Assembly[edit]
See 99 Bottles of Beer/Assembly
8080 Assembly[edit]
See 99 Bottles of Beer/Assembly
8th[edit]
\ 99 bottles of beer on the wall:
: allout "no more bottles" ;
: just-one "1 bottle" ;
: yeah! dup . " bottles" ;
[
' allout ,
' just-one ,
' yeah! ,
] var, bottles
: .bottles dup 2 n:min bottles @ swap caseof ;
: .beer .bottles . " of beer" . ;
: .wall .beer " on the wall" . ;
: .take " Take one down and pass it around" . ;
: beers .wall ", " . .beer '; putc cr
n:1- 0 max .take ", " .
.wall '. putc cr drop ;
' beers 1 99 loop- bye
AArch64 Assembly[edit]
/* ARM assembly AARCH64 Raspberry PI 3B */
/* program bootleBeer64.s */
/*******************************************/
/* Constantes file */
/*******************************************/
/* for this file see task include a file in language AArch64 assembly*/
.include "../includeConstantesARM64.inc"
.equ MAXI, 99
/*********************************/
/* Initialized data */
/*********************************/
.data
szMessLine1: .asciz "@ bottles of beer on the wall\n"
szMessLine2: .ascii "@ bottles of beer\n"
.asciz "Take one down, pass it around\n"
szMessLine3: .asciz "@ bottles of beer on the wall\n\n"
szMessLine4: .ascii "\nNo more bottles of beer on the wall, no more bottles of beer.\n"
.asciz "Go to the store and buy some more, 99 bottles of beer on the wall.\n"
szCarriageReturn: .asciz "\n"
/*********************************/
/* UnInitialized data */
/*********************************/
.bss
sZoneConv: .skip 24
/*********************************/
/* code section */
/*********************************/
.text
.global main
main: // entry of program
mov x2,#MAXI
1:
mov x0,x2
ldr x1,qAdrsZoneConv
bl conversion10 // call decimal conversion
ldr x0,qAdrszMessLine1
ldr x1,qAdrsZoneConv // insert conversion in message
bl strInsertAtCharInc
bl affichageMess
ldr x0,qAdrszMessLine2
ldr x1,qAdrsZoneConv // insert conversion in message
bl strInsertAtCharInc
bl affichageMess
subs x0,x2,#1
ble 2f
ldr x1,qAdrsZoneConv
bl conversion10 // call decimal conversion
ldr x0,qAdrszMessLine3
ldr x1,qAdrsZoneConv // insert conversion in message
bl strInsertAtCharInc
bl affichageMess
2:
subs x2,x2,1
bgt 1b
ldr x0,qAdrszMessLine4
bl affichageMess
100: // standard end of the program
mov x0, #0 // return code
mov x8, #EXIT // request to exit program
svc #0 // perform the system call
qAdrszCarriageReturn: .quad szCarriageReturn
qAdrszMessLine1: .quad szMessLine1
qAdrszMessLine2: .quad szMessLine2
qAdrszMessLine3: .quad szMessLine3
qAdrszMessLine4: .quad szMessLine4
qAdrsZoneConv: .quad sZoneConv
/********************************************************/
/* File Include fonctions */
/********************************************************/
/* for this file see task include a file in language AArch64 assembly */
.include "../includeARM64.inc"ABAP[edit]
REPORT z99bottles.
DATA lv_no_bottles(2) TYPE n VALUE 99.
DO lv_no_bottles TIMES.
WRITE lv_no_bottles NO-ZERO.
WRITE ' bottles of beer on the wall'.
NEW-LINE.
WRITE lv_no_bottles NO-ZERO.
WRITE ' bottles of beer'.
NEW-LINE.
WRITE 'Take one down, pass it around'.
NEW-LINE.
SUBTRACT 1 FROM lv_no_bottles.
WRITE lv_no_bottles NO-ZERO.
WRITE ' bottles of beer on the wall'.
WRITE /.
ENDDO.
or (With ABAP 7.40)
REPORT YCL_99_BOTTLES.
DATA it_99_bottles TYPE TABLE OF string WITH EMPTY KEY.
DATA(cr_lf) = cl_abap_char_utilities=>cr_lf.
it_99_bottles = VALUE #(
FOR i = 99 THEN i - 1 UNTIL i = 0 ( COND string( LET lv = ( i - 1 )
lr = i && | bottles of beer on the wall|
&& cr_lf
&& i && | bottles of beer|
&& cr_lf
&& |Take one down, pass it around|
&& cr_lf
&& lv && | bottles of beer on the wall|
&& cr_lf IN WHEN 1 = 1 THEN lr )
)
).
cl_demo_output=>write( it_99_bottles ).
cl_demo_output=>display( ).
ACL2[edit]
Action![edit]
PROC Bottles(BYTE i)
IF i=0 THEN
Print("No more")
ELSE
PrintB(i)
FI
Print(" bottle")
IF i#1 THEN
Print("s")
FI
RETURN
PROC Main()
BYTE i=[99]
WHILE i>0
DO
Bottles(i) PrintE(" of beer on the wall,")
Bottles(i) PrintE(" of beer,")
Print("Take ")
IF i>1 THEN
Print("one")
ELSE
Print("it")
FI
PrintE(" down and pass it around,")
i==-1
Bottles(i) PrintE(" of beer on the wall.")
IF i>0 THEN
PutE()
FI
OD
RETURN- Output:
Screenshot from Atari 8-bit computer
99 bottles of beer on the wall, 99 bottles of beer, Take one down and pass it around, 98 bottles of beer on the wall. ... 2 bottles of beer on the wall, 2 bottles of beer, Take one down and pass it around, 1 bottle of beer on the wall. 1 bottle of beer on the wall, 1 bottle of beer, Take it down and pass it around, No more bottles of beer on the wall.
ActionScript[edit]
for(var numBottles:uint = 99; numBottles > 0; numBottles--)
{
trace(numBottles, " bottles of beer on the wall");
trace(numBottles, " bottles of beer");
trace("Take one down, pass it around");
trace(numBottles - 1, " bottles of beer on the wall\n");
}
Ada[edit]
Simple version[edit]
with Ada.Text_Io; use Ada.Text_Io;
procedure Bottles is
begin
for X in reverse 1..99 loop
Put_Line(Integer'Image(X) & " bottles of beer on the wall");
Put_Line(Integer'Image(X) & " bottles of beer");
Put_Line("Take one down, pass it around");
Put_Line(Integer'Image(X - 1) & " bottles of beer on the wall");
New_Line;
end loop;
end Bottles;
Concurrent version[edit]
with 1 task to print out the information and 99 tasks to specify the number of bottles
with Ada.Text_Io; use Ada.Text_Io;
procedure Tasking_99_Bottles is
subtype Num_Bottles is Natural range 1..99;
task Print is
entry Set (Num_Bottles);
end Print;
task body Print is
Num : Natural;
begin
for I in reverse Num_Bottles'range loop
select
accept
Set(I) do -- Rendezvous with Counter task I
Num := I;
end Set;
Put_Line(Integer'Image(Num) & " bottles of beer on the wall");
Put_Line(Integer'Image(Num) & " bottles of beer");
Put_Line("Take one down, pass it around");
Put_Line(Integer'Image(Num - 1) & " bottles of beer on the wall");
New_Line;
or terminate; -- end when all Counter tasks have completed
end select;
end loop;
end Print;
task type Counter(I : Num_Bottles);
task body Counter is
begin
Print.Set(I);
end Counter;
type Task_Access is access Counter;
Task_List : array(Num_Bottles) of Task_Access;
begin
for I in Task_List'range loop -- Create 99 Counter tasks
Task_List(I) := new Counter(I);
end loop;
end Tasking_99_Bottles;
Aime[edit]
integer bottles;
bottles = 99;
do {
o_(bottles, " bottles of beer on the wall\n");
o_(bottles, " bottles of beer\n");
o_("Take one down, pass it around\n");
o_(bottles -= 1, " bottles of beer on the wall\n\n");
} while (bottles);Algae[edit]
# 99 Bottles of Beer on the Wall
# in Algae
# bottles.A
for (i in 99:1:1) {
if (i != 1) {
printf("%d bottles of beer on the wall\n";i);
printf("%d bottles of beer...\n";i);
printf("you take on down and pass it around...\n");
if ( i == 2) {
printf("%d bottles of beer on the wall\n\n";i-1);
else
printf("%d bottles of beer on the wall\n\n";i-1);
}
else
printf("1 bottle of beer on the wall\n");
printf("1 bottle of beer...\n");
printf("you take on down and pass it around..\n");
printf("no more bottles of beer on the wall!\n\n");
}
}ALGOL 60[edit]
begin
integer n;
for n:= 99 step -1 until 2 do
begin
outinteger(1,n);
outstring(1,"bottles of beer on the wall,");
outinteger(1,n);
outstring(1,"bottles of beer.\nTake one down and pass it around,");
outstring(1,"of beer on the wall...\n\n")
end;
outstring(1," 1 bottle of beer on the wall, 1 bottle of beer.\n");
outstring(1,"Take one down and pass it around, no more bottles of beer on the wall...\n\n");
outstring(1,"No more bottles of beer on the wall, no more bottles of beer.\n");
outstring(1,"Go to the store and buy some more, 99 bottles of beer on the wall.")
endALGOL 68[edit]
main:(
FOR bottles FROM 99 TO 1 BY -1 DO
printf(($z-d" bottles of beer on the wall"l$, bottles));
printf(($z-d" bottles of beer"l$, bottles));
printf(($"Take one down, pass it around"l$));
printf(($z-d" bottles of beer on the wall"ll$, bottles-1))
OD
)ALGOL-M[edit]
BEGIN
COMMENT PRINT LYRICS TO "99 BOTTLES OF BEER ON THE WALL";
STRING FUNCTION BOTTLE(N); % GIVE CORRECT GRAMMATICAL FORM %
INTEGER N;
BEGIN
IF N = 1 THEN
BOTTLE := " BOTTLE"
ELSE
BOTTLE := " BOTTLES";
END;
INTEGER N;
N := 99;
WHILE N > 0 DO
BEGIN
WRITE(N, BOTTLE(N), " OF BEER ON THE WALL,");
WRITEON(N, BOTTLE(N), " OF BEER");
WRITE("TAKE ONE DOWN AND PASS IT AROUND, ");
N := N - 1;
IF N = 0 THEN
WRITEON("NO MORE")
ELSE
WRITEON(N);
WRITEON(BOTTLE(N), " OF BEER ON THE WALL");
WRITE(" "); % BLANK LINE BETWEEN STANZAS %
END;
WRITE("THANKS FOR SINGING ALONG!");
ENDAmigaE[edit]
PROC main()
DEF t: PTR TO CHAR,
s: PTR TO CHAR,
u: PTR TO CHAR, i, x
t := 'Take one down, pass it around\n'
s := '\d bottle\s of beer\s\n'
u := ' on the wall'
FOR i := 99 TO 0 STEP -1
ForAll({x}, [u, NIL], `WriteF(s, i, IF i <> 1 THEN 's' ELSE NIL,
x))
IF i > 0 THEN WriteF(t)
ENDFOR
ENDPROCApache Ant[edit]
Implementation in Apache Ant, due to the limitations of Ant, this requires ant-contrib for arithmetic operations and a dummy target to keep Ant from detecting the loop.
<?xml version="1.0"?>
<project name="n bottles" default="99_bottles">
<!-- ant-contrib.sourceforge.net for arithmetic and if -->
<taskdef resource="net/sf/antcontrib/antcontrib.properties"/>
<!-- start count of bottles, you can set this with
e.g. ant -f 99.xml -Dcount=10 -->
<property name="count" value="99"/>
<target name="99_bottles">
<antcall target="bottle">
<param name="number" value="${count}"/>
</antcall>
</target>
<target name="bottle">
<echo message="${number} bottles of beer on the wall"/>
<echo message="${number} bottles of beer"/>
<echo message="Take one down, pass it around"/>
<math result="result" operand1="${number}" operation="-" operand2="1" datatype="int"/>
<echo message="${result} bottles of beer on the wall"/>
<if>
<not><equals arg1="${result}" arg2="0" /></not>
<then>
<antcall target="bottleiterate">
<param name="number" value="${result}"/>
</antcall>
</then>
</if>
</target>
<target name="bottleiterate">
<antcall target="bottle">
<param name="number" value="${number}"/>
</antcall>
</target>
</project>
Apex[edit]
for(Integer i = 99; i=0; i--){
system.debug(i + ' bottles of beer on the wall');
system.debug('\n');
system.debug(i + ' bottles of beer on the wall');
system.debug(i + ' bottles of beer');
system.debug('take one down, pass it around');
}APL[edit]
Classic version[edit]
bob ← { (⍕⍵), ' bottle', (1=⍵)↓'s of beer'}
bobw ← {(bob ⍵) , ' on the wall'}
beer ← { (bobw ⍵) , ', ', (bob ⍵) , '; take one down and pass it around, ', bobw ⍵-1}
⍝ Dyalog APL invocation
99↑beer¨ ⌽(1-⎕IO)+⍳99
⍝ GNU APL invocation (↑ and ⊃ differ, traditional APL2 meanings)
⊃beer¨ ⌽(1-⎕IO)+⍳99
One line version[edit]
⍝ Dyalog and GNU APL
⍪{(⍕⍵),' bottles of beer on the wall, take one down and pass it around, ',(⍕⍵-1),' bottles of beer on the wall'}¨⌽⍳99
App Inventor[edit]
Using a 'for each <number>' block (simplest)[edit]
Note that the output label text is not displayed until the entire lyrics text has been built and there is some delay between button press and display. <CLICK HERE TO VIEW THE BLOCKS AND OUTPUT>
Using a Clock Timer block (preferrred)[edit]
Output can be sent directly to a label with this preferred method as there is no noticeable delay between button press and output. <CLICK HERE TO VIEW THE BLOCKS AND OUTPUT>
AppleScript[edit]
Iteration[edit]
repeat with beerCount from 99 to 1 by -1
set bottles to "bottles"
if beerCount < 99 then
if beerCount = 1 then
set bottles to "bottle"
end
log "" & beerCount & " " & bottles & " of beer on the wall"
log ""
end
log "" & beerCount & " " & bottles & " of beer on the wall"
log "" & beerCount & " " & bottles & " of beer"
log "Take one down, pass it around"
end
log "No more bottles of beer on the wall!"
Declaration[edit]
-- BRIEF -----------------------------------------------------------------------
on run
set localisations to ¬
{"on the wall", ¬
"Take one down, pass it around", ¬
"Better go to the store to buy some more", "bottle"}
intercalate("\n\n", ¬
(map(curry(incantation)'s |λ|(localisations), enumFromTo(99, 0))))
end run
-- DECLARATIVE -----------------------------------------------------------------
-- incantation :: [String] -> Int -> String
on incantation(xs, n)
script asset
on |λ|(n)
unwords({(n as string), item -1 of xs & cond(n ≠ 1, "s", "")})
end |λ|
end script
script store
on |λ|(n)
unwords({asset's |λ|(n), item 1 of xs})
end |λ|
end script
set {distribute, solve} to items 2 thru 3 of xs
if n > 0 then
unlines({store's |λ|(n), asset's |λ|(n), distribute, store's |λ|(n - 1)})
else
solve
end if
end incantation
-- GENERICALLY DYSFUNCTIONAL ---------------------------------------------------
-- cond :: Bool -> a -> a -> a
on cond(bln, f, g)
if bln then
f
else
g
end if
end cond
-- curry :: (Script|Handler) -> Script
on curry(f)
script
on |λ|(a)
script
on |λ|(b)
|λ|(a, b) of mReturn(f)
end |λ|
end script
end |λ|
end script
end curry
-- enumFromTo :: Int -> Int -> [Int]
on enumFromTo(m, n)
if m > n then
set d to -1
else
set d to 1
end if
set lst to {}
repeat with i from m to n by d
set end of lst to i
end repeat
return lst
end enumFromTo
-- intercalate :: Text -> [Text] -> Text
on intercalate(strText, lstText)
set {dlm, my text item delimiters} to {my text item delimiters, strText}
set strJoined to lstText as text
set my text item delimiters to dlm
return strJoined
end intercalate
-- map :: (a -> b) -> [a] -> [b]
on map(f, xs)
tell mReturn(f)
set lng to length of xs
set lst to {}
repeat with i from 1 to lng
set end of lst to |λ|(item i of xs, i, xs)
end repeat
return lst
end tell
end map
-- Lift 2nd class handler function into 1st class script wrapper
-- mReturn :: Handler -> Script
on mReturn(f)
if class of f is script then
f
else
script
property |λ| : f
end script
end if
end mReturn
-- unlines :: [String] -> String
on unlines(xs)
intercalate(linefeed, xs)
end unlines
-- unwords :: [String] -> String
on unwords(xs)
intercalate(space, xs)
end unwords
Arbre[edit]
bottle(x):
template: '
$x bottles of beer on the wall.
$x bottles of beer.
Take one down and pass it around,
$y bottles of beer on the wall.
'
if x==0
template~{x: 'No more', y: 'No more'}
else
if x==1
template~{x: x, y: 'No more'}
else
template~{x: x, y: x-1}
bottles(n):
for x in [n..0]
bottle(x)
99bottles():
bottles(99) -> ioArgile[edit]
use std
let X be an int
for each X from 99 down to 1
prints X bottles of beer on the wall
prints X bottles of beer
prints "Take one down, pass it" around
if X == 1
echo No more "beer." Call da "amber lamps"
break
X--
prints X bottles of beer on the wall "\n"
X++
.:around :. -> text {X>59 ? "around", "to me"}
.:bottles:. -> text {X> 5 ? "bottles", (X>1 ? "buttles", "wall")}
.:of beer:. -> text {X>11 ? "of beer", "ov beeer"}
.:on the wall:. -> text {
X>17 ? "on the wall", (X>1 ? "on the bwall", "in the buttle")
}ARM Assembly[edit]
See 99 Bottles of Beer/Assembly
ArnoldC[edit]
As ArnoldC does not feature string concatenation, the numbers of bottles and the rest of the parts of the lyrics are printed on separate lines.
IT'S SHOWTIME
HEY CHRISTMAS TREE is0
YOU SET US UP @NO PROBLEMO
HEY CHRISTMAS TREE bottles
YOU SET US UP 99
STICK AROUND is0
TALK TO THE HAND bottles
TALK TO THE HAND " bottles of beer on the wall"
TALK TO THE HAND bottles
TALK TO THE HAND " bottles of beer"
TALK TO THE HAND "Take one down, pass it around"
GET TO THE CHOPPER bottles
HERE IS MY INVITATION bottles
GET DOWN 1
ENOUGH TALK
TALK TO THE HAND bottles
TALK TO THE HAND " bottles of beer on the wall"
GET TO THE CHOPPER is0
HERE IS MY INVITATION bottles
LET OFF SOME STEAM BENNET 0
ENOUGH TALK
CHILL
YOU HAVE BEEN TERMINATEDArturo[edit]
s: "s"
loop 99..1 'i [
print ~"|i| bottle|s| of beer on the wall,"
print ~"|i| bottle|s| of beer"
print ~"Take one down, pass it around!"
if 1=i-1 -> s: ""
if? i>1 [
print ~"|i-1| bottle|s| of beer on the wall!"
print ""
]
else -> print "No more bottles of beer on the wall!"
]
AsciiDots[edit]
/-99#-.
/>*$_#-$_" bottles of beer on the wall, "-$_#-$" bottles of beer."\
|[-]1#-----" ,dnuora ti ssap dna nwod eno ekaT"_$-----------------/
| |
| | &-".llaw eht no reeb fo selttob 99 ,erom emos yub dna erots eht ot oG"$\
| |/$""-$"No more bottles of beer on the wall, no more bottles of beer."---/
| |\".llaw eht no reeb fo selttob erom on ,dnuora ti ssap dna nwod eno ekaT"$-".reeb fo elttob 1"$\
| | /-$"1 bottle of beer on the wall."-$""-$_"1 bottle of beer on the wall, "------------/
| | /-------\|
| \-*--{=}-\\~$_#-$" bottles of beer on the wall."\
| \-#1/ \-/ |
\----------------------------------------------""$/Astro[edit]
fun bottles(n): match __args__:
(0) => "No more bottles"
(1) => "1 bottle"
(_) => "$n bottles"
for n in 99..-1..1:
print @format"""
{bottles n} of beer on the wall
{bottles n} of beer
Take one down, pass it around
{bottles n-1} of beer on the wall\n
"""
Asymptote[edit]
// Rosetta Code problem: http://rosettacode.org/wiki/99_bottles_of_beer
// by Jjuanhdez, 05/2022
int bottles = 99;
for (int i = bottles; i > 0; --i) {
write(string(i), " bottles of beer on the wall,");
write(string(i), " bottles of beer.");
write("Take one down and pass it around,");
if (i == 1) {
write("no more bottles of beer on the wall...");
} else {
write(string(i-1), " bottles of beer on the wall...");
}
}
write("No more bottles of beer on the wall,");
write("no more bottles of beer.");
write("Go to the store and buy some more,");
write(" 99 bottles of beer on the wall.");
ATS[edit]
//
#include
"share/atspre_staload.hats"
//
(* ****** ****** *)
fun bottles
(n0: int): void = let
//
fun loop (n: int): void =
(
if n > 0 then
(
if n0 > n then println! ();
println! (n, " bottles of beer on the wall");
println! (n, " bottles of beer");
println! ("Take one down, pass it around");
println! (n-1, " bottles of beer on the wall");
loop (n - 1)
) (* end of [if] *)
)
//
in
loop (n0)
end // end of [bottles]
(* ****** ****** *)
implement main0 () = bottles (99)AutoHotkey[edit]
AutoIt[edit]
AWK[edit]
Regular version[edit]
If you don't want so many beers, here you can specify the starting amount.
For example, just a sixpack:
# usage: gawk -v i=6 -f beersong.awk
function bb(n) {
b = " bottles of beer"
if( n==1 ) { sub("s","",b) }
if( n==0 ) { n="No more" }
return n b
}
BEGIN {
if( !i ) { i = 99 }
ow = "on the wall"
td = "Take one down, pass it around."
print "The beersong:\n"
while (i > 0) {
printf( "%s %s,\n%s.\n%s\n%s %s.\n\n",
bb(i), ow, bb(i), td, bb(--i), ow )
if( i==1 ) sub( "one","it", td )
}
print "Go to the store and buy some more!"
}
- Output:
The beersong: 99 bottles of beer on the wall, 99 bottles of beer. Take one down, pass it around. 98 bottles of beer on the wall. ... 3 bottles of beer on the wall, 3 bottles of beer. Take one down, pass it around. 2 bottles of beer on the wall. 2 bottles of beer on the wall, 2 bottles of beer. Take one down, pass it around. 1 bottle of beer on the wall. 1 bottle of beer on the wall, 1 bottle of beer. Take it down, pass it around. No more bottles of beer on the wall. Go to the store and buy some more!
Bottled version[edit]
Axe[edit]
Pauses are added to accommodate the small calculator screen so all of the text can be read.
99→B
While B
Disp B▶Dec," BOTTLES OF","BEER ON THE WALL"
Disp B▶Dec," BOTTLES OF","BEER",i,i
getKeyʳ
Disp "TAKE ONE DOWN",i,"PASS IT AROUND",i
B--
Disp B▶Dec," BOTTLES OF","BEER ON THE WALL",i
getKeyʳ
EndBabel[edit]
-- beer.sp
{b " bottles of beer" <
bi { itoa << } <
bb { bi ! b << w << "\n" << } <
w " on the wall" <
beer
{<-
{ iter 1 + dup
<- bb ! ->
bi ! b << "\n" <<
"Take one down, pass it around\n" <<
iter bb ! "\n" << }
->
times}
< }
-- At the prompt, type 'N beer !' (no quotes), where N is the number of stanzas you desireBASIC[edit]
Applesoft BASIC[edit]
BaCon[edit]
See 99 Bottles of Beer/Basic#BaCon
BASIC256[edit]
BBC BASIC[edit]
Commodore BASIC[edit]
See 99 Bottles of Beer/Basic#Commodore_BASIC
Craft Basic[edit]
See 99 Bottles of Beer/Basic#Craft_Basic
Creative Basic[edit]
FBSL[edit]
FreeBASIC[edit]
FUZE BASIC[edit]
GW-BASIC[edit]
Integer BASIC[edit]
Liberty BASIC[edit]
Microsoft Small Basic[edit]
Minimal BASIC[edit]
MSX Basic[edit]
OxygenBasic[edit]
PowerBASIC[edit]
PureBasic[edit]
QB64[edit]
QBasic[edit]
QuickBASIC[edit]
REALbasic[edit]
Run BASIC[edit]
Sinclair ZX81 BASIC[edit]
smart BASIC[edit]
TI-83 BASIC[edit]
TI-89 BASIC[edit]
Tiny BASIC[edit]
True BASIC[edit]
Visual Basic[edit]
Visual Basic .NET[edit]
XBasic[edit]
Yabasic[edit]
ZX Spectrum Basic[edit]
Batch File[edit]
Battlestar[edit]
const bottle = " bottle"
const plural = "s"
const ofbeer = " of beer"
const wall = " on the wall"
const sep = ", "
const takedown = "Take one down and pass it around, "
const u_no = "No"
const l_no = "no"
const more = " more bottles of beer"
const store = "Go to the store and buy some more, "
const dotnl = ".\n"
const nl = "\n"
// Reserve 1024 bytes in the .bss section
var x 1024
// Write two digits, based on the value in a
fun printnum
b = a
a >= 10
a /= 10
// modulo is in the d register after idiv
b = d
a += 48 // ASCII value for '0'
print(chr(a))
end
a = b
a += 48 // ASCII value for '0'
print(chr(a))
end
fun main
loop 99
// Save loop counter for later, twice
c -> stack
c -> stack
// Print the loop counter (passed in the a register)
a = c
printnum()
// N, "bottles of beer on the wall, "
x = bottle
x += plural
x += ofbeer
x += wall
x += sep
print(x)
// Retrieve and print the number
stack -> a
printnum()
// N, "bottles of beer.\nTake one down and pass it around,"
x = bottle
x += plural
x += ofbeer
x += dotnl
x += takedown
print(x)
// N-1, "bottles of beer on the wall."
stack -> a
a--
// Store N-1, used just a few lines down
a -> stack
printnum()
print(bottle)
// Retrieve N-1
stack -> a
// Write an "s" if the count is not 1
a != 1
print(plural)
end
// Write the rest + a blank line
x = ofbeer
x += wall
x += dotnl
x += nl
print(x)
// Skip to the top of the loop while the counter is >= 2
continue (c >= 2)
// At the last two
// "1 bottle of beer on the wall,"
a = 1
printnum()
x = bottle
x += ofbeer
x += wall
x += sep
print(x)
// "1"
a = 1
printnum()
// "bottle of beer. Take one down and pass it around,"
// "no more bottles of beer on the wall."
// Blank line
// "No more bottles of beer on the wall,"
// "no more bottles of beer."
// "Go to the store and buy some more,"
x = bottle
x += ofbeer
x += dotnl
x += takedown
x += l_no
x += more
x += wall
x += dotnl
x += nl
x += u_no
x += more
x += wall
x += sep
x += l_no
x += more
x += dotnl
x += store
print(x)
// "99"
a = 99
printnum()
// "bottles of beer on the wall."
x = bottle
x += plural
x += ofbeer
x += wall
x += dotnl
print(x)
end
end
// vim: set syntax=c ts=4 sw=4 et:
Bc[edit]
i = 99;
while ( 1 ) {
print i , " bottles of beer on the wall\n";
print i , " bottles of beer\nTake one down, pass it around\n";
if (i == 2) {
break
}
print --i , " bottles of beer on the wall\n";
}
print --i , " bottle of beer on the wall\n";
print i , " bottle of beer on the wall\n";
print i , " bottle of beer\nTake it down, pass it around\nno more bottles of beer on the wall\n";
quit
BCPL[edit]
get "libhdr"
let number(n) be
test n=0
then writes("No more")
else writen(n)
let plural(n) be
test n=1
then writes(" bottle")
else writes(" bottles")
let bottles(n) be
$( number(n)
plural(n)
$)
let verse(n) be
$( bottles(n)
writes(" of beer on the wall,*N")
bottles(n)
writes(" of beer,*NTake ")
test n=1
then writes("it")
else writes("one")
writes(" down and pass it around,*N")
bottles(n-1)
writes(" of beer on the wall!*N*N")
$)
let start() be
for n = 99 to 1 by -1 do verse(n)beeswax[edit]
Straightforward implementation, displaying the full lyrics given on [ http://99-bottles-of-beer.net/ ]
> NN p
> d#_8~2~(P~3~.~1~>{` bottles of beer on the wall, `{` bottles of beer.`q
d`.llaw eht no reeb fo selttob `{pLM` ,dnuora ti ssap dna nwod eno ekaT`N<
q`.llaw eht no reeb fo elttob ` {<
> NN >{` bottle of beer on the wall, `{` bottle of beer.`N q
pN `.llaw eht no reeb fo selttob erom on ,dnuora ti ssap dna nwod eno ekaT`<
>N`No more bottles of beer on the wall, no more bottles of beer.`N q
;`.llaw eht no reeb fo selttob 99 ,erom emos yub dna erots eht ot oG`<A much more “economic” version that tries to avoid repetition at the price of complicated conditional jumps and self-modifying code that takes up more place than the actual strings themselves. Output is the same as in the straightforward version.
#D@.9~2~@M.7~P9zE `N`p
DMM@.9@.~2~.++~5zE `n`>`o`p
>0f1ff# q `erom `< #h3~1z< #h3~1z< #h3~1z<
d_8~2~(P~3~. ~1~>"b{>X^^^` bottle` ` of beer`@g"pX` on the wall`g"pX `, ` @p #
> d <#XL#^^^^^`s`# # ## # > `.`NN@ X#
b < < <
>~L#^^^^`s`# #h3~1zX #h3~1z<# # # # #
d #h3~1z<# #> `.` g"pXN @"p `Take one down and `p
>^^^^^^^^^; .# b XgNN < bM` ,dnuora ti ssap`<
d^^^^^^^^^^^^^^^^X~3~P(~2~8` ,erom emos yub dna erots eht ot`` oG`<Befunge[edit]
See 99 Bottles of Beer/EsoLang
BlitzMax[edit]
local bot:int = 99
repeat
print string(bot)+" bottles of beer on the wall,"
print string(bot)+" bottles of beer."
print "Take one down, pass it around,"
bot:-1
print string(bot)+" bottles of beer on the wall."
print
until bot = 1
print "1 bottle of beer on the wall,"
print "1 bottle of beer."
print "Take it down, pass it around,"
print "No more bottles of beer on the wall!"
BlooP[edit]
Output is always in caps in the interpreter I use, but I typed the input in correct case to spare those whose interpreter might do lowercase and don't want to have this song shouted at them ;D.
DEFINE PROCEDURE ''MINUS'' [A,B]:
BLOCK 0: BEGIN
IF A < B, THEN:
QUIT BLOCK 0;
LOOP AT MOST A TIMES:
BLOCK 1: BEGIN
IF OUTPUT + B = A, THEN:
QUIT BLOCK 0;
OUTPUT <= OUTPUT + 1;
BLOCK 1: END;
BLOCK 0: END.
DEFINE PROCEDURE ''BOTTLES'' [COUNT]:
BLOCK 0: BEGIN
CELL(0) <= COUNT;
LOOP COUNT + 1 TIMES:
BLOCK 1: BEGIN
IF CELL(0) > 1, THEN:
PRINT[CELL(0), ' bottles of beer on the wall, ', CELL(0), ' bottles of beer. Take one down, pass it around, ', MINUS[CELL(0), 1], ' bottles of beer on the wall.'];
IF CELL(0) = 1, THEN:
PRINT['1 botle of beer on the wall, 1 bottle of beer. Take one down, pass it around, No more bottles of beer on the wall.'];
IF CELL(0) = 0, THEN:
PRINT['No more bottles of beer on the wall, no more bottles of beer. Go to the store, buy 99 more, 99 bottles of beer on the wall!'];
CELL(0) <= MINUS[CELL(0), 1];
BLOCK 1: END;
BLOCK 0: END.
BOTTLES[99];Bracmat[edit]
Copy the code to a file called BottlesOfBeer.bra.
Start Bracmat and after the {?} prompt write get$"BottlesOfBeer.bra" <Enter>.
Then, after the next prompt, write
!r <Enter>.
Notice that the lyrics has two more lines at the end:
No more bottles of beer on the wall, no more bottles of beer. Go to the store and buy some more, 99 bottles of beer on the wall.
Code to save to BottlesOfBeer.bra:
{BottlesOfBeer.bra
See http://99-bottles-of-beer.net/}
X=
new
= n upper nbottles lyrics
. 99:?n
& ( upper
= .@(!arg:%@?a ?z)&str$(upp$!a !z)
)
& ( nbottles
=
. str
$ ( ( !arg:>0
& !arg
" bottle"
(!arg:1&|s)
| "no more bottles"
)
" of beer"
)
)
& ( lyrics
= (upper$(nbottles$!n:?x) " on the wall, " !x ".\n")
( !n+-1:?n:~<0
& "Take one down and pass it around, "
nbottles$!n
" on the wall.
"
!lyrics
| "Go to the store and buy some more, "
nbottles$99
" on the wall.
"
)
)
& put$(str$!lyrics);
r=
get'"BottlesOfBeer.bra"
& rmv$(str$(BottlesOfBeer ".bak"))
& ren$("BottlesOfBeer.bra".str$(BottlesOfBeer ".bak"))
& put
$ ( "{BottlesOfBeer.bra
See http://99-bottles-of-beer.net/}
"
, "BottlesOfBeer.bra"
, NEW
)
& lst'(X,"BottlesOfBeer.bra",APP)
& put'(\n,"BottlesOfBeer.bra",APP)
& lst'(r,"BottlesOfBeer.bra",APP)
& put$(str$("\nnew'" X ";\n"),"BottlesOfBeer.bra",APP);
new'X;Brainf***[edit]
See 99 Bottles of Beer/EsoLang
Brat[edit]
99.to 2 { n |
p "#{n} bottles of beer on the wall, #{n} bottles of beer!"
p "Take one down, pass it around, #{n - 1} bottle#{true? n > 2 's' ''} of beer on the wall."
}
p "One bottle of beer on the wall, one bottle of beer!"
p "Take one down, pass it around, no more bottles of beer on the wall."BQN[edit]
Pl ← {(𝕩≠1)/"s"}
{𝕨∾(@+10)∾𝕩}´{(•Fmt 𝕨)∾" "∾𝕩}´¨∾{
⟨
⟨𝕩,"bottle"∾(Pl 𝕩)∾" of beer on the wall"⟩
⟨𝕩,"bottle"∾(Pl 𝕩)∾" of beer"⟩
⟨"Take one down, pass it around"⟩
⟨𝕩-1,"bottle"∾(Pl 𝕩-1)∾" of beer on the wall"∾@+10⟩
⟩
}¨⌽1+↕99•Fmt is used to convert numbers to strings.
Pl tells whether the number is singular or plural.
Then, the two folds join all the individual lines together.
C[edit]
The simple solution[edit]
/*
* 99 Bottles, C, KISS (i.e. keep it simple and straightforward) version
*/
#include <stdio.h>
int main(void)
{
int n;
for( n = 99; n > 2; n-- )
printf(
"%d bottles of beer on the wall, %d bottles of beer.\n"
"Take one down and pass it around, %d bottles of beer on the wall.\n\n",
n, n, n - 1);
printf(
"2 bottles of beer on the wall, 2 bottles of beer.\n"
"Take one down and pass it around, 1 bottle of beer on the wall.\n\n"
"1 bottle of beer on the wall, 1 bottle of beer.\n"
"Take one down and pass it around, no more bottles of beer on the wall.\n\n"
"No more bottles of beer on the wall, no more bottles of beer.\n"
"Go to the store and buy some more, 99 bottles of beer on the wall.\n");
return 0;
}
A recursive solution[edit]
#include <stdio.h>
int main(int argc, char *argv[])
{
if(argc == 99)
return 99;
if(argv[0] != NULL){
argv[0] = NULL;
argc = 0;
}
argc = main(argc + 1, argv);
printf("%d bottle%c of beer on the wall\n", argc, argc == 1?'\0': 's');
printf("%d bottle%c of beer\n", argc, argc == 1?'\0': 's');
printf("Take one down, pass it around\n");
printf("%d bottle%c of beer on the wall\n\n", argc - 1, (argc - 1) == 1?'\0': 's');
return argc - 1;
}
Code golf[edit]
#include <stdio.h>
main(){_=100;while(--_)printf("%i bottle%s of beer in the wall,\n%i bottle%"
"s of beer.\nTake one down, pass it round,\n%s%s\n\n",_,_-1?"s":"",_,_-1?"s"
:"",_-1?(char[]){(_-1)/10?(_-1)/10+48:(_-1)%10+48,(_-1)/10?(_-1)%10+48:2+30,
(_-1)/10?32:0,0}:"",_-1?"bottles of beer in the wall":"No more beers");}
A preprocessor solution[edit]
Of course, with the template metaprogramming solution, the program has still do the conversion of numbers to strings at runtime, and those function calls also cost unnecessary time. Couldn't we just compose the complete text at compile time, and just output it at run time? Well, with the preprocessor, that's indeed possible:
#include <stdlib.h>
#include <stdio.h>
#define BOTTLE(nstr) nstr " bottles of beer"
#define WALL(nstr) BOTTLE(nstr) " on the wall"
#define PART1(nstr) WALL(nstr) "\n" BOTTLE(nstr) \
"\nTake one down, pass it around\n"
#define PART2(nstr) WALL(nstr) "\n\n"
#define MIDDLE(nstr) PART2(nstr) PART1(nstr)
#define SONG PART1("100") CD2 PART2("0")
#define CD2 CD3("9") CD3("8") CD3("7") CD3("6") CD3("5") \
CD3("4") CD3("3") CD3("2") CD3("1") CD4("")
#define CD3(pre) CD4(pre) MIDDLE(pre "0")
#define CD4(pre) MIDDLE(pre "9") MIDDLE(pre "8") MIDDLE(pre "7") \
MIDDLE(pre "6") MIDDLE(pre "5") MIDDLE(pre "4") MIDDLE(pre "3") \
MIDDLE(pre "2") MIDDLE(pre "1")
int main(void)
{
(void) printf(SONG);
return EXIT_SUCCESS;
}
An inspection of the generated executable proves that it indeed contains the complete text of the song in one block.
The bottled version[edit]
WYSIWYG (with correct plurals and can buy some more): int b =99,u =1;
#include<stdio.h>
char *d[16],y[]
= "#:ottle/ of"
":eer_ a_Go<o5"
"st>y\x20some6"
"_Take8;down4p"
"a=1rou7_17 _<"
"h;_ m?_nd_ on"
"_085wal" "l_ "
"b_e _ t_ss it"
"_?4bu_ore_9, "
"\060.""@, 9$";
# define x c ^=
#include <string.h>
#define or(t,z) else\
if(c==t && !(c = 0) &&\
(c =! z)); int p(char *t)
{ char *s = t; int c; for (
d[c = 0] = y; !t && (d[c +1
]= strchr(s = d[c], '_'));*
(d[++c]++) = 0); for(t = s?
s:t;(c= *s++); c && putchar
(c)) { if (!((( x 48)& ~0xf
) && ( x 48)) ) p(d[c]), c=
0 ; or('$', p(b - 99?".\n":
"." ) && p(b - 99? t : ""))
or ('\x40', c && p( d[!!b--
+ 2])) or('/', c && p( b^1?
"s": "")) or ('\043', b++ ?
p("So6" + --b):!printf("%d"
, b ? --b : (b += 99))) or(
'S',!(++u % 3) * 32+ 78) or
('.', puts("."))}return c;}
int main() {return p(0);}
C#[edit]
using System;
class Program
{
static void Main(string[] args)
{
for (int i = 99; i > -1; i--)
{
if (i == 0)
{
Console.WriteLine("No more bottles of beer on the wall, no more bottles of beer.");
Console.WriteLine("Go to the store and buy some more, 99 bottles of beer on the wall.");
break;
}
if (i == 1)
{
Console.WriteLine("1 bottle of beer on the wall, 1 bottle of beer.");
Console.WriteLine("Take one down and pass it around, no more bottles of beer on the wall.");
Console.WriteLine();
}
else
{
Console.WriteLine("{0} bottles of beer on the wall, {0} bottles of beer.", i);
Console.WriteLine("Take one down and pass it around, {0} bottles of beer on the wall.", i - 1);
Console.WriteLine();
}
}
}
}
C#6 Implementation[edit]
using System;
class Program
{
static void Main()
{
Func<int, bool, string> f = (x, y) =>
$"{(x == 0 ? "No more" : x.ToString())} bottle{(x == 1 ? "" : "s")} of beer{(y ? " on the wall" : "")}\r\n";
for (int i = 99; i > 0; i--)
Console.WriteLine($"{f(i, true)}{f(i, false)}Take one down, pass it around\r\n{f(i - 1, true)}");
}
}
Linq Implementation[edit]
using System;
using System.Linq;
class Program
{
static void Main()
{
Enumerable.Range(1, 99).Reverse().Select(x =>
$"{x} bottle{(x == 1 ? "" : "s")} of beer on the wall, {x} bottle{(x == 1 ? "" : "s")} of beer!\n" +
$"Take {(x == 1 ? "it" : "one")} down, pass it around, {(x == 1 ? "no more" : (x - 1).ToString())} bottles of beer on the wall!\n"
).ToList().ForEach(x => Console.WriteLine(x));
}
}
Flexible Version[edit]
using System;
using System.Globalization;
class Program
{
const string Vessel = "bottle";
const string Beverage = "beer";
const string Location = "on the wall";
private static string DefaultAction(ref int bottles)
{
bottles--;
return "take one down, pass it around,";
}
private static string FallbackAction(ref int bottles)
{
bottles += 99;
return "go to the store, buy some more,";
}
private static string Act(ref int bottles)
{
return bottles > 0 ? DefaultAction(ref bottles) : FallbackAction(ref bottles);
}
static void Main()
{
Func<int, string> plural = b => b == 1 ? "" : "s";
Func<int, string> describeCount = b => b == 0 ? "no more" : b.ToString();
Func<int, string> describeBottles = b => string.Format("{0} {1}{2} of {3}", describeCount(b), Vessel, plural(b), Beverage);
Action<string> write = s => Console.WriteLine(CultureInfo.CurrentCulture.TextInfo.ToTitleCase(s));
int bottles = 99;
while (true)
{
write(string.Format("{0} {1}, {0},", describeBottles(bottles), Location));
write(Act(ref bottles));
write(string.Format("{0} {1}.", describeBottles(bottles), Location));
write(string.Empty);
}
}
}
Using Formatting[edit]
class songs
{
static void Main(string[] args)
{
beer(3);
}
private static void beer(int bottles)
{
for (int i = bottles; i > 0; i--)
{
if (i > 1)
{
Console.Write("{0}\n{1}\n{2}\n{3}\n\n",
i + " bottles of beer on the wall",
i + " bottles of beer",
"Take one down, pass it around",
(i - 1) + " bottles of beer on the wall");
}
else
Console.Write("{0}\n{1}\n{2}\n{3}\n\n",
i + " bottle of beer on the wall",
i + " bottle of beer",
"Take one down, pass it around",
(i - 1) + " bottles of beer on the wall....");
}
}
}
- Output:
3 bottles of beer on the wall 3 bottles of beer Take one down, pass it around 2 bottles of beer on the wall 2 bottles of beer on the wall 2 bottles of beer Take one down, pass it around 1 bottles of beer on the wall 1 bottle of beer on the wall 1 bottle of beer Take one down, pass it around 0 bottles of beer on the wall....
Using iterator blocks[edit]
using System;
using System.Linq;
class Program
{
static void Main()
{
BeerBottles().Take(99).ToList().ForEach(Console.WriteLine);
}
static IEnumerable<String> BeerBottles()
{
int i = 100;
String f = "{0}, {1}. Take one down, pass it around, {2}";
Func<int, bool, String> booze = (c , b) =>
String.Format("{0} bottle{1} of beer{2}", c>0 ? c.ToString() : "no more", (c==1 ? "" : "s"), b ? " on the wall" : "");
while (--i >= 1)
yield return String.Format(f, booze(i, true), booze(i, false), booze(i - 1, true));
}
}
A Fun One[edit]
string[] bottles = { "80 Shilling",
"Abita Amber",
"Adams Broadside Ale",
"Altenmünster Premium",
"August Schell's SnowStorm",
"Bah Humbug! Christmas Ale",
"Beck's Oktoberfest",
"Belhaven Wee Heavy",
"Bison Chocolate Stout",
"Blue Star Wheat Beer",
"Bridgeport Black Strap Stout",
"Brother Thelonius Belgian-Style Abbey Ale",
"Capital Blonde Doppelbock",
"Carta Blanca",
"Celis Raspberry Wheat",
"Christian Moerlein Select Lager",
"Corona",
"Czechvar",
"Delirium Tremens",
"Diamond Bear Southern Blonde",
"Don De Dieu",
"Eastside Dark",
"Eliot Ness",
"Flying Dog K-9 Cruiser Altitude Ale",
"Fuller's London Porter",
"Gaffel Kölsch",
"Golden Horseshoe",
"Guinness Pub Draught",
"Hacker-Pschorr Weisse",
"Hereford & Hops Black Spring Double Stout",
"Highland Oatmeal Porter",
"Ipswich Ale",
"Iron City",
"Jack Daniel's Amber Lager",
"Jamaica Sunset India Pale Ale",
"Killian's Red",
"König Ludwig Weiss",
"Kronenbourg 1664",
"Lagunitas Hairy Eyball Ale",
"Left Hand Juju Ginger",
"Locktender Lager",
"Magic Hat Blind Faith",
"Missing Elf Double Bock",
"Muskoka Cream Ale ",
"New Glarus Cherry Stout",
"Nostradamus Bruin",
"Old Devil",
"Ommegang Three Philosophers",
"Paulaner Hefe-Weizen Dunkel",
"Perla Chmielowa Pils",
"Pete's Wicked Springfest",
"Point White Biere",
"Prostel Alkoholfrei",
"Quilmes",
"Rahr's Red",
"Rebel Garnet",
"Rickard's Red",
"Rio Grande Elfego Bock",
"Rogue Brutal Bitter",
"Roswell Alien Amber Ale",
"Russian River Pliny The Elder",
"Samuel Adams Blackberry Witbier",
"Samuel Smith's Taddy Porter",
"Schlafly Pilsner",
"Sea Dog Wild Blueberry Wheat Ale",
"Sharp's",
"Shiner 99",
"Sierra Dorada",
"Skullsplitter Orkney Ale",
"Snake Chaser Irish Style Stout",
"St. Arnold Bock",
"St. Peter's Cream Stout",
"Stag",
"Stella Artois",
"Stone Russian Imperial Stout",
"Sweetwater Happy Ending Imperial Stout",
"Taiwan Gold Medal",
"Terrapin Big Hoppy Monster",
"Thomas Hooker American Pale Ale",
"Tie Die Red Ale",
"Toohey's Premium",
"Tsingtao",
"Ugly Pug Black Lager",
"Unibroue Qatre-Centieme",
"Victoria Bitter",
"Voll-Damm Doble Malta",
"Wailing Wench Ale",
"Warsteiner Dunkel",
"Wellhead Crude Oil Stout",
"Weyerbacher Blithering Idiot Barley-Wine Style Ale",
"Wild Boar Amber",
"Würzburger Oktoberfest",
"Xingu Black Beer",
"Yanjing",
"Younger's Tartan Special",
"Yuengling Black & Tan",
"Zagorka Special",
"Zig Zag River Lager",
"Zywiec" };
int bottlesLeft = 99;
const int FIRST_LINE_SINGULAR = 98;
const int FINAL_LINE_SINGULAR = 97;
string firstLine = "";
string finalLine = "";
for (int i = 0; i < 99; i++)
{
firstLine = bottlesLeft.ToString() + " bottle";
if (i != FIRST_LINE_SINGULAR)
firstLine += "s";
firstLine += " of beer on the wall, " + bottlesLeft.ToString() + " bottle";
if (i != FIRST_LINE_SINGULAR)
firstLine += "s";
firstLine += " of beer";
Console.WriteLine(firstLine);
Console.WriteLine("Take the " + bottles[i] + " down, pass it around,");
bottlesLeft--;
finalLine = bottlesLeft.ToString() + " bottle";
if (i != FINAL_LINE_SINGULAR)
finalLine += "s";
finalLine += " of beer on the wall!";
Console.WriteLine(finalLine);
Console.WriteLine();
Console.ReadLine();
}
Using recursion[edit]
public static void BottlesSong(int numberOfBottles)
{
if (numberOfBottles > 0)
{
Console.WriteLine("{0} bottles of beer on the wall", numberOfBottles);
Console.WriteLine("{0} bottles of beer ", numberOfBottles);
Console.WriteLine("Take one down, pass it around");
Console.WriteLine("{0} bottles of beer ", numberOfBottles - 1);
Console.WriteLine();
BottlesSong(--numberOfBottles);
}
}
Using a While Loop[edit]
static void Main(string[] args)
{
int numBottles = 99;
while (numBottles > 0)
{
if (numBottles > 1)
{
WriteLine("{0} bottles of beer on the wall, {0} bottles of beer.", numBottles);
numBottles -= 1;
WriteLine("Take one down, pass it around, {0} bottles of beer on the wall.\n", numBottles);
}
else
{
WriteLine("{0} bottle of beer on the wall, {0} bottle of beer.", numBottles);
numBottles -= 1;
WriteLine("Take one down, pass it around, no more bottles of beer on the wall.\n");
}
}
WriteLine("No more bottles of beer on the wall, no more bottles of beer.");
WriteLine("Go to the store to buy some more, 99 bottles of beer on the wall...");
}
C++[edit]
The simple solution[edit]
#include <iostream>
using std::cout;
int main()
{
for(int bottles(99); bottles > 0; bottles -= 1){
cout << bottles << " bottles of beer on the wall\n"
<< bottles << " bottles of beer\n"
<< "Take one down, pass it around\n"
<< bottles - 1 << " bottles of beer on the wall\n\n";
}
}
An object-oriented solution[edit]
See: 99 Bottles of Beer/C++/Object Oriented
A template metaprogramming solution[edit]
Of course, the output of the program always looks the same. One may therefore question why the program has to do all that tedious subtracting during runtime. Couldn't the compiler just generate the code to output the text, with ready-calculated constants? Indeed, it can, and the technique is called template metaprogramming. The following short code gives the text without containing a single variable, let alone a loop:
#include <iostream>
template<int max, int min> struct bottle_countdown
{
static const int middle = (min + max)/2;
static void print()
{
bottle_countdown<max, middle+1>::print();
bottle_countdown<middle, min>::print();
}
};
template<int value> struct bottle_countdown<value, value>
{
static void print()
{
std::cout << value << " bottles of beer on the wall\n"
<< value << " bottles of beer\n"
<< "Take one down, pass it around\n"
<< value-1 << " bottles of beer\n\n";
}
};
int main()
{
bottle_countdown<100, 1>::print();
return 0;
}
A function template solution[edit]
Function templates are a different approach to template metaprogramming:
#include <iostream>
template<unsigned int N> void bottles(){
std::cout << N << " bottles of beer on the wall\n"
<< N << " bottles of beer\n"
<< "Take one down, pass it around\n"
<< N - 1 << " bottles of beer on the wall\n\n";
bottles<N-1>();
}
template<> void bottles<0>(){
std::cout<<"No more bottles of beer on the wall\n"
"No more bottles of beer\n"
"Go to the store and buy some more\n"
"99 bottles of beer on the wall...\n\n";
}
int main(){
bottles<99>();
}
A Recursive solution[edit]
#include <iostream>
using namespace std;
void rec(int bottles)
{
if ( bottles!=0)
{
cout << bottles << " bottles of beer on the wall" << endl;
cout << bottles << " bottles of beer" << endl;
cout << "Take one down, pass it around" << endl;
cout << --bottles << " bottles of beer on the wall\n" << endl;
rec(bottles);
}
}
int main()
{
rec(99);
system("pause");
return 0;
}
A preprocessor solution[edit]
Of course, with the template metaprogramming solution, the program has still do the conversion of numbers to strings at runtime, and those function calls also cost unnecessary time. Couldn't we just compose the complete text at compile time, and just output it at run time? Well, with the preprocessor, that's indeed possible:
#include <iostream>
#include <ostream>
#define BOTTLE(nstr) nstr " bottles of beer"
#define WALL(nstr) BOTTLE(nstr) " on the wall"
#define PART1(nstr) WALL(nstr) "\n" BOTTLE(nstr) \
"\nTake one down, pass it around\n"
#define PART2(nstr) WALL(nstr) "\n\n"
#define MIDDLE(nstr) PART2(nstr) PART1(nstr)
#define SONG PART1("100") CD2 PART2("0")
#define CD2 CD3("9") CD3("8") CD3("7") CD3("6") CD3("5") \
CD3("4") CD3("3") CD3("2") CD3("1") CD4("")
#define CD3(pre) CD4(pre) MIDDLE(pre "0")
#define CD4(pre) MIDDLE(pre "9") MIDDLE(pre "8") MIDDLE(pre "7") \
MIDDLE(pre "6") MIDDLE(pre "5") MIDDLE(pre "4") MIDDLE(pre "3") \
MIDDLE(pre "2") MIDDLE(pre "1")
int main()
{
std::cout << SONG;
return 0;
}
Bottled Version[edit]
//>,_
//Beer Song>,_
#include <iostream>
using namespace std;
int main(){ for( int
b=-1; b<99; cout <<
'\n') for ( int w=0;
w<3; cout << ".\n"){
if (w==2) cout << ((
b--) ?"Take one dow"
"n and pass it arou"
"nd":"Go to the sto"
"re and buy some mo"
"re"); if (b<0) b=99
; do{ if (w) cout <<
", "; if (b) cout <<
b; else cout << (
(w) ? 'n' : 'N') <<
"o more"; cout <<
" bottle" ; if
(b!=1) cout <<
's' ; cout <<
" of beer";
if (w!=1)
cout <<
" on th"
"e wall"
;} while
(!w++);}
return
0
;
}
//
// by barrym 2011-05-01
// no bottles were harmed in the
// making of this program!!!
Ceylon[edit]
shared void ninetyNineBottles() {
String bottles(Integer count) =>
"``count == 0 then "No" else count``
bottle``count == 1 then "" else "s"``".normalized;
for(i in 99..1) {
print("``bottles(i)`` of beer on the wall
``bottles(i)`` of beer!
Take one down, pass it around
``bottles(i - 1)`` of beer on the wall!\n");
}
}
Chapel[edit]
copied from http://99-bottles-of-beer.net/language-chapel-1215.html, with minor modifications for chapel 1.7
/***********************************************************************
* Chapel implementation of "99 bottles of beer"
*
* by Brad Chamberlain and Steve Deitz
* 07/13/2006 in Knoxville airport while waiting for flight home from
* HPLS workshop
* compiles and runs with chpl compiler version 1.7.0
* for more information, contact: chapel_info@cray.com
*
*
* Notes:
* o as in all good parallel computations, boundary conditions
* constitute the vast bulk of complexity in this code (invite Brad to
* tell you about his zany boundary condition simplification scheme)
* o uses type inference for variables, arguments
* o relies on integer->string coercions
* o uses named argument passing (for documentation purposes only)
***********************************************************************/
// allow executable command-line specification of number of bottles
// (e.g., ./a.out -snumBottles=999999)
config const numBottles = 99;
const numVerses = numBottles+1;
// a domain to describe the space of lyrics
var LyricsSpace: domain(1) = {1..numVerses};
// array of lyrics
var Lyrics: [LyricsSpace] string;
// parallel computation of lyrics array
[verse in LyricsSpace] Lyrics(verse) = computeLyric(verse);
// as in any good parallel language, I/O to stdout is serialized.
// (Note that I/O to a file could be parallelized using a parallel
// prefix computation on the verse strings' lengths with file seeking)
writeln(Lyrics);
// HELPER FUNCTIONS:
proc computeLyric(verseNum) {
var bottleNum = numBottles - (verseNum - 1);
var nextBottle = (bottleNum + numVerses - 1)%numVerses;
return "\n" // disguise space used to separate elements in array I/O
+ describeBottles(bottleNum, startOfVerse=true) + " on the wall, "
+ describeBottles(bottleNum) + ".\n"
+ computeAction(bottleNum)
+ describeBottles(nextBottle) + " on the wall.\n";
}
proc describeBottles(bottleNum, startOfVerse:bool = false) {
// NOTE: bool should not be necessary here (^^^^); working around bug
var bottleDescription = if (bottleNum) then bottleNum:string
else (if startOfVerse then "N"
else "n")
+ "o more";
return bottleDescription
+ " bottle" + (if (bottleNum == 1) then "" else "s")
+ " of beer";
}
proc computeAction(bottleNum) {
return if (bottleNum == 0) then "Go to the store and buy some more, "
else "Take one down and pass it around, ";
}
Chef[edit]
See 99 Bottles of Beer/EsoLang
Cind[edit]
execute() {
// this class provides synchronization
// to get unique number of the bottle
class monitor giver {
int number = 100;
.get() { return --number; }
}
var g = new giver();
// start 99 concurrently worked threads
// each thread gets own number of the bottle and prints out his own verse
// (notice that the output lines from the threads will be mixed together)
{#[99]
int nr = g.get(); // get own number
host.println(nr," bottles of beer on the wall, "+nr+" bottles of beer");
host.print("Take one down, pass it around,");
if (nr > 1) {
host.println((nr-1)," bottles of beer on the wall.");
}
else {
host.println("no more bottles of beer on the wall.");
}
}
host.println("No more bottles of beer on the wall, no more bottles of beer.");
host.println("Go to the store and buy some more, 99 bottles of beer on the wall.");
return 0;
}Clay[edit]
/* A few options here: I could give n type Int; or specify that n is of any
numeric type; but here I just let it go -- that way it'll work with anything
that compares with 1 and that printTo knows how to convert to a string. And
all checked at compile time, remember. */
getRound(n) {
var s = String();
var bottle = if (n == 1) " bottle " else " bottles ";
printTo(s,
n, bottle, "of beer on the wall\n",
n, bottle, "of beer\n",
"take one down, pass it around\n",
n, bottle, "of beer on the wall!\n");
return s;
}
main() {
println(join("\n", mapped(getRound, reversed(range(100)))));
}
Clio[edit]
fn bottle n:
n -> if = 0: 'no more bottles'
elif = 1: n + ' bottle'
else: n + ' bottles'
[99:0] -> * (@eager) fn i:
i -> bottle -> print (transform i: sentence-case) 'of beer on the wall,' @ 'of beer.'
if i = 0:
'Go to the store, buy some more, 99 bottles of beer on the wall.' -> print
else:
i - 1 -> bottle -> print 'Take one down and pass it around,' @ 'of beer on the wall.\n'CLIPS[edit]
(deffacts beer-bottles
(bottles 99))
(deffunction bottle-count
(?count)
(switch ?count
(case 0 then "No more bottles of beer")
(case 1 then "1 more bottle of beer")
(default (str-cat ?count " bottles of beer"))))
(defrule stanza
?bottles <- (bottles ?count)
=>
(retract ?bottles)
(printout t (bottle-count ?count) " on the wall," crlf)
(printout t (bottle-count ?count) "." crlf)
(printout t "Take one down, pass it around," crlf)
(printout t (bottle-count (- ?count 1)) " on the wall." crlf crlf)
(if (> ?count 1) then (assert (bottles (- ?count 1)))))Clojure[edit]
(defn paragraph [num]
(str num " bottles of beer on the wall\n"
num " bottles of beer\n"
"Take one down, pass it around\n"
(dec num) " bottles of beer on the wall.\n"))
(defn lyrics []
(let [numbers (range 99 0 -1)
paragraphs (map paragraph numbers)]
(clojure.string/join "\n" paragraphs)))
(print (lyrics))
Or, using cl-format:
(clojure.pprint/cl-format
true
"~{~[~^~]~:*~D bottle~:P of beer on the wall~%~:*~D bottle~:P of beer
Take one down, pass it around,~%~D bottle~:P~:* of beer on the wall.~2%~}"
(range 99 0 -1))
CLU[edit]
bottles = proc (n: int) returns (string)
if n<0 then return("99 bottles")
elseif n=0 then return("No more bottles")
elseif n=1 then return("1 bottle")
else return(int$unparse(n) || " bottles")
end
end bottles
thirdline = proc (n: int) returns (string)
if n=0 then
return("Go to the store and buy some more,\n")
else
s: string
if n=1 then s := "it"
else s := "one"
end
return("Take " || s || " down and pass it around,\n");
end
end thirdline
verse = proc (n: int) returns (string)
v: string := bottles(n) || " bottles of beer on the wall,\n"
v := v || bottles(n) || " bottles of beer,\n"
v := v || thirdline(n)
v := v || bottles(n-1) || " bottles of beer on the wall.\n\n"
return(v)
end verse
start_up = proc ()
po: stream := stream$primary_output()
for n: int in int$from_to_by(99, 0, -1) do
stream$puts(po, verse(n))
end
end start_upCOBOL[edit]
Free form version.
identification division.
program-id. ninety-nine.
environment division.
data division.
working-storage section.
01 counter pic 99.
88 no-bottles-left value 0.
88 one-bottle-left value 1.
01 parts-of-counter redefines counter.
05 tens pic 9.
05 digits pic 9.
01 after-ten-words.
05 filler pic x(7) value spaces.
05 filler pic x(7) value "Twenty".
05 filler pic x(7) value "Thirty".
05 filler pic x(7) value "Forty".
05 filler pic x(7) value "Fifty".
05 filler pic x(7) value "Sixty".
05 filler pic x(7) value "Seventy".
05 filler pic x(7) value "Eighty".
05 filler pic x(7) value "Ninety".
05 filler pic x(7) value spaces.
01 after-ten-array redefines after-ten-words.
05 atens occurs 10 times pic x(7).
01 digit-words.
05 filler pic x(9) value "One".
05 filler pic x(9) value "Two".
05 filler pic x(9) value "Three".
05 filler pic x(9) value "Four".
05 filler pic x(9) value "Five".
05 filler pic x(9) value "Six".
05 filler pic x(9) value "Seven".
05 filler pic x(9) value "Eight".
05 filler pic x(9) value "Nine".
05 filler pic x(9) value "Ten".
05 filler pic x(9) value "Eleven".
05 filler pic x(9) value "Twelve".
05 filler pic x(9) value "Thirteen".
05 filler pic x(9) value "Fourteen".
05 filler pic x(9) value "Fifteen".
05 filler pic x(9) value "Sixteen".
05 filler pic x(9) value "Seventeen".
05 filler pic x(9) value "Eighteen".
05 filler pic x(9) value "Nineteen".
05 filler pic x(9) value spaces.
01 digit-array redefines digit-words.
05 adigits occurs 20 times pic x(9).
01 number-name pic x(15).
procedure division.
100-main section.
100-setup.
perform varying counter from 99 by -1 until no-bottles-left
perform 100-show-number
display " of beer on the wall"
perform 100-show-number
display " of beer"
display "Take " with no advancing
if one-bottle-left
display "it " with no advancing
else
display "one " with no advancing
end-if
display "down and pass it round"
subtract 1 from counter giving counter
perform 100-show-number
display " of beer on the wall"
add 1 to counter giving counter
display space
end-perform.
display "No more bottles of beer on the wall"
display "No more bottles of beer"
display "Go to the store and buy some more"
display "Ninety Nine bottles of beer on the wall"
stop run.
100-show-number.
if no-bottles-left
display "No more" with no advancing
else
if counter < 20
display function trim( adigits( counter ) ) with no advancing
else
if counter < 100
move spaces to number-name
string atens( tens ) delimited by space, space delimited by size, adigits( digits ) delimited by space into number-name
display function trim( number-name) with no advancing
end-if
end-if
end-if.
if one-bottle-left
display " bottle" with no advancing
else
display " bottles" with no advancing
end-if.
100-end.
end-program.
Another free-form version, without using DISPLAY NO ADVANCING.
identification division.
program-id. ninety-nine.
environment division.
data division.
working-storage section.
01 counter pic 99.
88 no-bottles-left value 0.
88 one-bottle-left value 1.
01 parts-of-counter redefines counter.
05 tens pic 9.
05 digits pic 9.
01 after-ten-words.
05 filler pic x(7) value spaces.
05 filler pic x(7) value "Twenty".
05 filler pic x(7) value "Thirty".
05 filler pic x(7) value "Forty".
05 filler pic x(7) value "Fifty".
05 filler pic x(7) value "Sixty".
05 filler pic x(7) value "Seventy".
05 filler pic x(7) value "Eighty".
05 filler pic x(7) value "Ninety".
05 filler pic x(7) value spaces.
01 after-ten-array redefines after-ten-words.
05 atens occurs 10 times pic x(7).
01 digit-words.
05 filler pic x(9) value "One".
05 filler pic x(9) value "Two".
05 filler pic x(9) value "Three".
05 filler pic x(9) value "Four".
05 filler pic x(9) value "Five".
05 filler pic x(9) value "Six".
05 filler pic x(9) value "Seven".
05 filler pic x(9) value "Eight".
05 filler pic x(9) value "Nine".
05 filler pic x(9) value "Ten".
05 filler pic x(9) value "Eleven".
05 filler pic x(9) value "Twelve".
05 filler pic x(9) value "Thirteen".
05 filler pic x(9) value "Fourteen".
05 filler pic x(9) value "Fifteen".
05 filler pic x(9) value "Sixteen".
05 filler pic x(9) value "Seventeen".
05 filler pic x(9) value "Eighteen".
05 filler pic x(9) value "Nineteen".
05 filler pic x(9) value spaces.
01 digit-array redefines digit-words.
05 adigits occurs 20 times pic x(9).
01 number-name pic x(15).
01 stringified pic x(30).
01 outline pic x(50).
01 other-numbers.
03 n pic 999.
03 r pic 999.
procedure division.
100-main section.
100-setup.
perform varying counter from 99 by -1 until no-bottles-left
move spaces to outline
perform 100-show-number
string stringified delimited by "|", space, "of beer on the wall" into outline end-string
display outline end-display
move spaces to outline
string stringified delimited by "|", space, "of beer" into outline end-string
display outline end-display
move spaces to outline
move "Take" to outline
if one-bottle-left
string outline delimited by space, space, "it" delimited by size, space, "|" into outline end-string
else
string outline delimited by space, space, "one" delimited by size, space, "|" into outline end-string
end-if
string outline delimited by "|", "down and pass it round" delimited by size into outline end-string
display outline end-display
move spaces to outline
subtract 1 from counter giving counter end-subtract
perform 100-show-number
string stringified delimited by "|", space, "of beer on the wall" into outline end-string
display outline end-display
add 1 to counter giving counter end-add
display space end-display
end-perform.
display "No more bottles of beer on the wall"
display "No more bottles of beer"
display "Go to the store and buy some more"
display "Ninety-Nine bottles of beer on the wall"
stop run.
100-show-number.
if no-bottles-left
move "No more|" to stringified
else
if counter < 20
string function trim( adigits( counter ) ), "|" into stringified
else
if counter < 100
move spaces to number-name
string atens( tens ) delimited by space, space delimited by size, adigits( digits ) delimited by space into number-name end-string
move function trim( number-name) to stringified
divide counter by 10 giving n remainder r end-divide
if r not = zero
inspect stringified replacing first space by "-"
end-if
inspect stringified replacing first space by "|"
end-if
end-if
end-if.
if one-bottle-left
string stringified delimited by "|", space, "bottle|" delimited by size into stringified end-string
else
string stringified delimited by "|", space, "bottles|" delimited by size into stringified end-string
end-if.
100-end.
end-program.
A more concise version that adheres to the minimum guidelines. Leading zeros are not suppressed. (OpenCOBOL - 1.1.0)
program-id. ninety-nine.
data division.
working-storage section.
01 cnt pic 99.
procedure division.
perform varying cnt from 99 by -1 until cnt < 1
display cnt " bottles of beer on the wall"
display cnt " bottles of beer"
display "Take one down, pass it around"
subtract 1 from cnt
display cnt " bottles of beer on the wall"
add 1 to cnt
display space
end-perform.
CoffeeScript[edit]
bottlesOfBeer = (n) ->
"#{n} bottle#{if n is 1 then '' else 's'} of beer"
console.log """
#{bottlesOfBeer n} on the wall
#{bottlesOfBeer n}
Take one down, pass it around
#{bottlesOfBeer n - 1} on the wall
\n""" for n in [99..1]
With completely different approach...
for j in [99..1]
x=''
x += [j,j-1,'\nTake one down, pass it around\n'," bottles of beer",' on the wall\n'][i] for i in [0,3,4,0,3,2,1,3,4]
console.log x.replace /(1.+)s/g, '$1'
or as a one liner...
console.log( if (j+2)%4 then (x=Math.round j/4)+" bottle#{if x-1 then 's' else ''} of beer#{if (j+1)%4 then ' on the wall' else ''}" else "Take one down, pass it around" ) for j in [396..1]
or another completely different one liner
((console.log if i is 2 then "Take one down, pass it around" else "#{b-!(i-1%4)} bottle#{if 4*b+i<10 and b-i then '' else 's'} of beer#{if i%3 then ' on the wall' else ''}") for i in [4..1]) for b in [99..1]
ColdFusion[edit]
Classic tag based CFML[edit]
<cfoutput>
<cfloop index="x" from="99" to="0" step="-1">
<cfset plur = iif(x is 1,"",DE("s"))>
#x# bottle#plur# of beer on the wall<br>
#x# bottle#plur# of beer<br>
Take one down, pass it around<br>
#iif(x is 1,DE("No more"),"x-1")# bottle#iif(x is 2,"",DE("s"))# of beer on the wall<br><br>
</cfloop>
</cfoutput>
or if you prefer: (identical output, grammatically correct to the last stanza)
CFScript[edit]
<cfscript>
for (x=99; x gte 1; x--) {
plur = iif(x==1,'',DE('s'));
WriteOutput("#x# bottle#plur# of beer on the wall<br>#x# bottle#plur# of beer<br>Take one down, pass it around<br>#iif(x is 1,DE('No more'),'x-1')# bottle#iif(x is 2,'',DE('s'))# of beer on the wall<br><br>");
}
</cfscript>
Comal[edit]
0010 DIM itone$(0:1)
0020 itone$(0):="one";itone$(1):="it"
0030 FOR b#:=99 TO 1 STEP -1 DO
0040 bottles(b#)
0050 PRINT "of beer on the wall,"
0060 bottles(b#)
0070 PRINT "of beer,"
0080 PRINT "Take ",itone$(b#=1)," down and pass it around,"
0090 bottles(b#-1)
0100 PRINT "of beer on the wall!"
0110 PRINT
0120 ENDFOR b#
0130 PROC bottles(b#) CLOSED
0140 CASE b# OF
0150 WHEN 0
0160 PRINT "No more bottles ",
0170 WHEN 1
0180 PRINT "1 bottle ",
0190 OTHERWISE
0200 PRINT b#," bottles ",
0210 ENDCASE
0220 ENDPROC bottles
0230 ENDComefrom0x10[edit]
bottles = ' bottles '
remaining = 99
one_less_bottle = remaining
depluralize
comefrom drinking if one_less_bottle is 1
bottles = ' bottle '
drinking
comefrom if remaining is one_less_bottle
remaining bottles 'of beer on the wall'
remaining bottles 'of beer'
'Take one down, pass it around'
one_less_bottle = remaining - 1
one_less_bottle bottles 'of beer on the wall`n'
remaining = remaining - 1
comefrom if one_less_bottle is 0
'No more bottles of beer on the wall'- Output:
2 bottles of beer on the wall 2 bottles of beer Take one down, pass it around 1 bottle of beer on the wall 1 bottle of beer on the wall 1 bottle of beer Take one down, pass it around No more bottles of beer on the wall
Common Lisp[edit]
Component Pascal[edit]
Cowgol[edit]
include "cowgol.coh";
sub Bottles(n: uint8) is
if n == 0 then
print("No more");
else
print_i8(n);
end if;
print(" bottle");
if n != 1 then
print("s");
end if;
end sub;
sub Verse(n: uint8) is
Bottles(n);
print(" of beer on the wall,\n");
Bottles(n);
print(" of beer,\n");
print("Take ");
if n == 1 then
print("it");
else
print("one");
end if;
print(" down and pass it around,\n");
Bottles(n-1);
print(" of beer on the wall.\n\n");
end sub;
var verse: uint8 := 99;
while verse > 0 loop
Verse(verse);
verse := verse - 1;
end loop;- Output:
99 bottles of beer on the wall, 99 bottles of beer, Take one down and pass it around, 98 bottles of beer on the wall. 98 bottles of beer on the wall, 98 bottles of beer, Take one down and pass it around, 97 bottles of beer on the wall. 97 bottles of beer on the wall, 97 bottles of beer, Take one down and pass it around, 96 bottles of beer on the wall. 96 bottles of beer on the wall, 96 bottles of beer, Take one down and pass it around, 95 bottles of beer on the wall. 95 bottles of beer on the wall, 95 bottles of beer, Take one down and pass it around, 94 bottles of beer on the wall. 94 bottles of beer on the wall, 94 bottles of beer, Take one down and pass it around, 93 bottles of beer on the wall. 93 bottles of beer on the wall, 93 bottles of beer, Take one down and pass it around, 92 bottles of beer on the wall. 92 bottles of beer on the wall, 92 bottles of beer, Take one down and pass it around, 91 bottles of beer on the wall. 91 bottles of beer on the wall, 91 bottles of beer, Take one down and pass it around, 90 bottles of beer on the wall. 90 bottles of beer on the wall, 90 bottles of beer, Take one down and pass it around, 89 bottles of beer on the wall. 89 bottles of beer on the wall, 89 bottles of beer, Take one down and pass it around, 88 bottles of beer on the wall. 88 bottles of beer on the wall, 88 bottles of beer, Take one down and pass it around, 87 bottles of beer on the wall. 87 bottles of beer on the wall, 87 bottles of beer, Take one down and pass it around, 86 bottles of beer on the wall. 86 bottles of beer on the wall, 86 bottles of beer, Take one down and pass it around, 85 bottles of beer on the wall. 85 bottles of beer on the wall, 85 bottles of beer, Take one down and pass it around, 84 bottles of beer on the wall. 84 bottles of beer on the wall, 84 bottles of beer, Take one down and pass it around, 83 bottles of beer on the wall. 83 bottles of beer on the wall, 83 bottles of beer, Take one down and pass it around, 82 bottles of beer on the wall. 82 bottles of beer on the wall, 82 bottles of beer, Take one down and pass it around, 81 bottles of beer on the wall. 81 bottles of beer on the wall, 81 bottles of beer, Take one down and pass it around, 80 bottles of beer on the wall. 80 bottles of beer on the wall, 80 bottles of beer, Take one down and pass it around, 79 bottles of beer on the wall. 79 bottles of beer on the wall, 79 bottles of beer, Take one down and pass it around, 78 bottles of beer on the wall. 78 bottles of beer on the wall, 78 bottles of beer, Take one down and pass it around, 77 bottles of beer on the wall. 77 bottles of beer on the wall, 77 bottles of beer, Take one down and pass it around, 76 bottles of beer on the wall. 76 bottles of beer on the wall, 76 bottles of beer, Take one down and pass it around, 75 bottles of beer on the wall. 75 bottles of beer on the wall, 75 bottles of beer, Take one down and pass it around, 74 bottles of beer on the wall. 74 bottles of beer on the wall, 74 bottles of beer, Take one down and pass it around, 73 bottles of beer on the wall. 73 bottles of beer on the wall, 73 bottles of beer, Take one down and pass it around, 72 bottles of beer on the wall. 72 bottles of beer on the wall, 72 bottles of beer, Take one down and pass it around, 71 bottles of beer on the wall. 71 bottles of beer on the wall, 71 bottles of beer, Take one down and pass it around, 70 bottles of beer on the wall. 70 bottles of beer on the wall, 70 bottles of beer, Take one down and pass it around, 69 bottles of beer on the wall. 69 bottles of beer on the wall, 69 bottles of beer, Take one down and pass it around, 68 bottles of beer on the wall. 68 bottles of beer on the wall, 68 bottles of beer, Take one down and pass it around, 67 bottles of beer on the wall. 67 bottles of beer on the wall, 67 bottles of beer, Take one down and pass it around, 66 bottles of beer on the wall. 66 bottles of beer on the wall, 66 bottles of beer, Take one down and pass it around, 65 bottles of beer on the wall. 65 bottles of beer on the wall, 65 bottles of beer, Take one down and pass it around, 64 bottles of beer on the wall. 64 bottles of beer on the wall, 64 bottles of beer, Take one down and pass it around, 63 bottles of beer on the wall. 63 bottles of beer on the wall, 63 bottles of beer, Take one down and pass it around, 62 bottles of beer on the wall. 62 bottles of beer on the wall, 62 bottles of beer, Take one down and pass it around, 61 bottles of beer on the wall. 61 bottles of beer on the wall, 61 bottles of beer, Take one down and pass it around, 60 bottles of beer on the wall. 60 bottles of beer on the wall, 60 bottles of beer, Take one down and pass it around, 59 bottles of beer on the wall. 59 bottles of beer on the wall, 59 bottles of beer, Take one down and pass it around, 58 bottles of beer on the wall. 58 bottles of beer on the wall, 58 bottles of beer, Take one down and pass it around, 57 bottles of beer on the wall. 57 bottles of beer on the wall, 57 bottles of beer, Take one down and pass it around, 56 bottles of beer on the wall. 56 bottles of beer on the wall, 56 bottles of beer, Take one down and pass it around, 55 bottles of beer on the wall. 55 bottles of beer on the wall, 55 bottles of beer, Take one down and pass it around, 54 bottles of beer on the wall. 54 bottles of beer on the wall, 54 bottles of beer, Take one down and pass it around, 53 bottles of beer on the wall. 53 bottles of beer on the wall, 53 bottles of beer, Take one down and pass it around, 52 bottles of beer on the wall. 52 bottles of beer on the wall, 52 bottles of beer, Take one down and pass it around, 51 bottles of beer on the wall. 51 bottles of beer on the wall, 51 bottles of beer, Take one down and pass it around, 50 bottles of beer on the wall. 50 bottles of beer on the wall, 50 bottles of beer, Take one down and pass it around, 49 bottles of beer on the wall. 49 bottles of beer on the wall, 49 bottles of beer, Take one down and pass it around, 48 bottles of beer on the wall. 48 bottles of beer on the wall, 48 bottles of beer, Take one down and pass it around, 47 bottles of beer on the wall. 47 bottles of beer on the wall, 47 bottles of beer, Take one down and pass it around, 46 bottles of beer on the wall. 46 bottles of beer on the wall, 46 bottles of beer, Take one down and pass it around, 45 bottles of beer on the wall. 45 bottles of beer on the wall, 45 bottles of beer, Take one down and pass it around, 44 bottles of beer on the wall. 44 bottles of beer on the wall, 44 bottles of beer, Take one down and pass it around, 43 bottles of beer on the wall. 43 bottles of beer on the wall, 43 bottles of beer, Take one down and pass it around, 42 bottles of beer on the wall. 42 bottles of beer on the wall, 42 bottles of beer, Take one down and pass it around, 41 bottles of beer on the wall. 41 bottles of beer on the wall, 41 bottles of beer, Take one down and pass it around, 40 bottles of beer on the wall. 40 bottles of beer on the wall, 40 bottles of beer, Take one down and pass it around, 39 bottles of beer on the wall. 39 bottles of beer on the wall, 39 bottles of beer, Take one down and pass it around, 38 bottles of beer on the wall. 38 bottles of beer on the wall, 38 bottles of beer, Take one down and pass it around, 37 bottles of beer on the wall. 37 bottles of beer on the wall, 37 bottles of beer, Take one down and pass it around, 36 bottles of beer on the wall. 36 bottles of beer on the wall, 36 bottles of beer, Take one down and pass it around, 35 bottles of beer on the wall. 35 bottles of beer on the wall, 35 bottles of beer, Take one down and pass it around, 34 bottles of beer on the wall. 34 bottles of beer on the wall, 34 bottles of beer, Take one down and pass it around, 33 bottles of beer on the wall. 33 bottles of beer on the wall, 33 bottles of beer, Take one down and pass it around, 32 bottles of beer on the wall. 32 bottles of beer on the wall, 32 bottles of beer, Take one down and pass it around, 31 bottles of beer on the wall. 31 bottles of beer on the wall, 31 bottles of beer, Take one down and pass it around, 30 bottles of beer on the wall. 30 bottles of beer on the wall, 30 bottles of beer, Take one down and pass it around, 29 bottles of beer on the wall. 29 bottles of beer on the wall, 29 bottles of beer, Take one down and pass it around, 28 bottles of beer on the wall. 28 bottles of beer on the wall, 28 bottles of beer, Take one down and pass it around, 27 bottles of beer on the wall. 27 bottles of beer on the wall, 27 bottles of beer, Take one down and pass it around, 26 bottles of beer on the wall. 26 bottles of beer on the wall, 26 bottles of beer, Take one down and pass it around, 25 bottles of beer on the wall. 25 bottles of beer on the wall, 25 bottles of beer, Take one down and pass it around, 24 bottles of beer on the wall. 24 bottles of beer on the wall, 24 bottles of beer, Take one down and pass it around, 23 bottles of beer on the wall. 23 bottles of beer on the wall, 23 bottles of beer, Take one down and pass it around, 22 bottles of beer on the wall. 22 bottles of beer on the wall, 22 bottles of beer, Take one down and pass it around, 21 bottles of beer on the wall. 21 bottles of beer on the wall, 21 bottles of beer, Take one down and pass it around, 20 bottles of beer on the wall. 20 bottles of beer on the wall, 20 bottles of beer, Take one down and pass it around, 19 bottles of beer on the wall. 19 bottles of beer on the wall, 19 bottles of beer, Take one down and pass it around, 18 bottles of beer on the wall. 18 bottles of beer on the wall, 18 bottles of beer, Take one down and pass it around, 17 bottles of beer on the wall. 17 bottles of beer on the wall, 17 bottles of beer, Take one down and pass it around, 16 bottles of beer on the wall. 16 bottles of beer on the wall, 16 bottles of beer, Take one down and pass it around, 15 bottles of beer on the wall. 15 bottles of beer on the wall, 15 bottles of beer, Take one down and pass it around, 14 bottles of beer on the wall. 14 bottles of beer on the wall, 14 bottles of beer, Take one down and pass it around, 13 bottles of beer on the wall. 13 bottles of beer on the wall, 13 bottles of beer, Take one down and pass it around, 12 bottles of beer on the wall. 12 bottles of beer on the wall, 12 bottles of beer, Take one down and pass it around, 11 bottles of beer on the wall. 11 bottles of beer on the wall, 11 bottles of beer, Take one down and pass it around, 10 bottles of beer on the wall. 10 bottles of beer on the wall, 10 bottles of beer, Take one down and pass it around, 9 bottles of beer on the wall. 9 bottles of beer on the wall, 9 bottles of beer, Take one down and pass it around, 8 bottles of beer on the wall. 8 bottles of beer on the wall, 8 bottles of beer, Take one down and pass it around, 7 bottles of beer on the wall. 7 bottles of beer on the wall, 7 bottles of beer, Take one down and pass it around, 6 bottles of beer on the wall. 6 bottles of beer on the wall, 6 bottles of beer, Take one down and pass it around, 5 bottles of beer on the wall. 5 bottles of beer on the wall, 5 bottles of beer, Take one down and pass it around, 4 bottles of beer on the wall. 4 bottles of beer on the wall, 4 bottles of beer, Take one down and pass it around, 3 bottles of beer on the wall. 3 bottles of beer on the wall, 3 bottles of beer, Take one down and pass it around, 2 bottles of beer on the wall. 2 bottles of beer on the wall, 2 bottles of beer, Take one down and pass it around, 1 bottle of beer on the wall. 1 bottle of beer on the wall, 1 bottle of beer, Take it down and pass it around, No more bottles of beer on the wall.
Crystal[edit]
99.downto(1) do |n|
puts "#{n} bottle#{n > 1 ? "s" : ""} of beer on the wall"
puts "#{n} bottle#{n > 1 ? "s" : ""} of beer"
puts "Take one down, pass it around"
puts "#{n-1} bottle#{n > 2 ? "s" : ""} of beer on the wall\n\n" if n > 1
end
puts "No more bottles of beer on the wall"
D[edit]
Simple Solution[edit]
Based on Steward Gordon's code at: 99-bottles-of-beer.net.
import std.stdio;
void main() {
int bottles = 99;
while (bottles > 1) {
writeln(bottles, " bottles of beer on the wall,");
writeln(bottles, " bottles of beer.");
writeln("Take one down, pass it around,");
if (--bottles > 1) {
writeln(bottles, " bottles of beer on the wall.\n");
}
}
writeln("1 bottle of beer on the wall.\n");
writeln("No more bottles of beer on the wall,");
writeln("no more bottles of beer.");
writeln("Go to the store and buy some more,");
writeln("99 bottles of beer on the wall.");
}
CTFE Solution[edit]
CTFE (Compile-Time Function Execution) is a feature of D that allows for pure functions of arbitrary complexity to be completely evaluated at compile time when every parameter is known. Note that this is distinct from the template meta-programming tricks used by some other languages, and this bottles() function could just as easily be executed during run-time. The compiled result of this program simply prints the pre-generated lyrics to the song, using a standard compiler pragma directive.
import std.stdio, std.conv;
string bottles(in size_t num) pure {
static string bottlesRecurse(in size_t num) pure {
return num.text ~ " bottles of beer on the wall,\n"
~ num.text ~ " bottles of beer!\n"
~ "Take one down, pass it around,\n"
~ (num - 1).text ~ " bottle" ~ ((num - 1 == 1) ? "" : "s")
~ " of beer on the wall.\n\n"
~ ((num > 2)
? bottlesRecurse(num - 1)
: "1 bottle of beer on the wall,\n"
~ "1 bottle of beer!\n"
~ "Take one down, pass it around,\n"
~ "No bottles of beer on the wall!\n\n");
}
return bottlesRecurse(num)
~ "Go to the store and buy some more...\n"
~ num.text ~ " bottles of beer on the wall!";
}
pragma(msg, 99.bottles);
void main() {}
Template Meta-Programming Solution[edit]
Uses D template meta-programming and recursion to pre-generate the song lyrics and prints it at compile via pragma(msg,...)
module bottles;
template BeerSong(int Bottles)
{
static if (Bottles == 1)
{
enum BeerSong = "1 bottle of beer on the wall\n" ~
"1 bottle of beer\ntake it down, pass it around\n" ~ "
no more bottles of beer on the wall\n";
}
else
{
enum BeerSong = Bottles.stringof ~ " bottles of beer on the wall\n" ~
Bottles.stringof ~ " bottles of beer\ntake it down, pass it around\n" ~
BeerSong!(Bottles-1);
}
}
pragma(msg,BeerSong!99);
void main(){}
Dart[edit]
// Making use of polymorphism
main() {
BeerSong beerSong = BeerSong();
//pass a 'starting point' and 'end point' as parameters respectively
String printTheLyrics = beerSong.recite(99, 1).join('\n');
print(printTheLyrics);
}
class Song {
String bottleOnTheWall(int index) {
String bottleOnTheWallText =
'$index bottles of beer on the wall, $index bottles of beer,';
return bottleOnTheWallText;
}
String bottleTakenDown(int index) {
String englishGrammar = (index >= 2) ? 'bottle' : 'bottles';
String bottleTakenDownText =
'Take one down and pass it around, ${index - 1} $englishGrammar of beer on the wall.';
return bottleTakenDownText;
}
}
class BeerSong extends Song {
@override
String bottleOnTheWall(int index) {
String originalText = super.bottleOnTheWall(index);
if (index < 2) {
String bottleOnTheWallText =
'$index bottle of beer on the wall, $index bottle of beer,';
return bottleOnTheWallText;
}
return originalText;
}
@override
String bottleTakenDown(int index) {
if (index < 2) {
String bottleTakenDownText =
'Take it down and pass it around, no more bottles of beer on the wall.';
return bottleTakenDownText;
}
String originalText = super.bottleTakenDown(index);
return originalText;
}
List<String> recite(int actualBottleOnTheWall, int remainingBottleOnTheWall) {
List<String> theLyrics = [];
for (int index = actualBottleOnTheWall;
index >= remainingBottleOnTheWall;
index--) {
String onTheWall = bottleOnTheWall(index);
String takenDown = bottleTakenDown(index);
theLyrics.add(onTheWall);
theLyrics.add(takenDown);
theLyrics.add('');
}
return theLyrics;
}
}
}
Dc[edit]
[
dnrpr
dnlBP
lCP
1-dnrp
rd2r >L
]sL
[Take one down, pass it around
]sC
[ bottles of beer
]sB
[ bottles of beer on the wall]
99
lLx
dnrpsA
dnlBP
lCP
1-
dn[ bottle of beer on the wall]p
rdnrpsA
n[ bottle of beer
]P
[Take it down, pass it around
]P
[no more bottles of beer on the wall
]PSimilar to the program above, but without 'n' and 'r' commands. It prints the numbers on separate lines than the strings.
[
plAP
plBP
lCP
1-dplAP
d2r >L
]sL
[Take one down, pass it around
]sC
[bottles of beer
]sB
[bottles of beer on the wall
]sA
99
lLx
plAP
plBP
lCP
1-
p
[bottle of beer on the wall
]P
p
[bottle of beer
]P
[Take it down, pass it around
]P
[no more bottles of beer on the wall
]P
DBL[edit]
;
;===============================================================================
; Oringinal Author: Bob Welton (welton@pui.com)
; Language: DIBOL or DBL
;
; Modified to work with DBL version 4
; by Dario B.
;===============================================================================
RECORD
NRBOT,D2,99 ;Default # of bottles to 99
A2, A2
PROC
;-------------------------------------------------------------------------------
XCALL FLAGS (0007000000,1) ;Suppress STOP message
OPEN (1,O,"TT:") ;Open the terminal/display
DO FOREVER
BEGIN
A2=NRBOT,'ZX'
DISPLAY (1,A2," Bottles of Beer on the wall,",10)
A2=NRBOT,'ZX'
DISPLAY (1,A2," Bottles of Beer,",10)
DISPLAY (1," Take one down, pass it around,",10)
DECR NRBOT ;Reduce # of bottles by 1
IF (NRBOT.LE.1) EXITLOOP ;If just 1 bottle left, get out
A2=NRBOT,'ZX'
DISPLAY (1,A2," Bottles of Beer on the wall.",10,10)
END
A2=NRBOT,'ZX'
DISPLAY (1,A2," Bottle of Beer on the wall,",10,10)
A2=NRBOT,'ZX'
DISPLAY (1,A2," Bottle of Beer,",10)
DISPLAY (1," Take one down, pass it around,",10)
DISPLAY (1,"0 Bottles of Beer on the wall,",10)
DISPLAY (1,"0 Bottles of Beer,",10)
DISPLAY (1,"Go to the store and buy some more,",10)
DISPLAY (1,"99 Bottles of Beer on the wall,",10,10,10)
CLOSE 1
STOP
Delphi[edit]
Draco[edit]
proc nonrec bottles(byte b) void:
if b=0 then write("No more") else write(b) fi;
write(" bottle");
if b~=1 then write("s") fi
corp;
proc nonrec verse(byte v) void:
bottles(v);
writeln(" of beer on the wall,");
bottles(v);
writeln(" of beer,");
writeln("Take ",
if v=1 then "it" else "one" fi,
" down and pass it around");
bottles(v-1);
writeln(" of beer on the wall!\n");
corp;
proc nonrec main() void:
byte v;
for v from 99 downto 1 do verse(v) od
corpDyalect[edit]
for i in 99^-1..1 {
print("\(i) bottles of beer on the wall, \(i) bottles of beer.")
let next = i is 1 ? "no" : i - 1
print("Take one down and pass it around, \(next) bottles of beer on the wall.")
}Dylan[edit]
Module: bottles
define method bottles (n :: <integer>)
for (n from 99 to 1 by -1)
format-out("%d bottles of beer on the wall,\n"
"%d bottles of beer\n"
"Take one down, pass it around\n"
"%d bottles of beer on the wall\n",
n, n, n - 1);
end
end method
Déjà Vu[edit]
plural i:
if = 1 i "" "s"
bottles i:
local :s plural i
!print( to-str i " bottle"s" of beer on the wall, " to-str i " bottle"s" of beer," )
!print\ "You take one down, pass it around, "
set :i -- i
if i:
set :s plural i
!print( to-str i " bottle"s" of beer on the wall." )
bottles i
else:
!print "no more bottles of beer on the wall, no more bottles of beer."
!print "Go to the store and buy some more, 99 bottles of beer on the wall."
bottles 99DIBOL-11[edit]
;
;===============================================================================
========================
; Oringinal Author: Bob Welton (welton@pui.com)
; Language: DIBOL or DBL
;
; Modified to work with DEC DIBOL-11
; by Bill Gunshannon
;===============================================================================
========================
RECORD MISC
NUMBOTTLES ,D2,99 ;Default # of bottles to 99
RECORD LINE1
ANUMBOTTLES, A2
, A32, " Bottles of Beer on the wall,"
RECORD LINE2
BNUMBOTTLES, A2
, A32, " Bottles of Beer,"
RECORD LINE3
CNUMBOTTLES, A2
, A32, " Bottles of Beer on the wall."
RECORD LINE4
DNUMBOTTLES, A2
, A32, " Bottle of Beer on the wall,"
RECORD LINE5
ENUMBOTTLES, A2
, A32, " Bottle of Beer,"
.PROC
XCALL FLAGS (0007000000,1) ;Suppress STOP message
OPEN (8,O:C,"TT:") ;Open the terminal/display
REPEAT
BEGIN
ANUMBOTTLES = NUMBOTTLES,'ZX'
WRITES (8,LINE1)
BNUMBOTTLES = NUMBOTTLES,'ZX'
WRITES (8,LINE2)
WRITES (8," Take one down, pass it around,")
DECR NUMBOTTLES ;Reduce # of bottles by 1
IF (NUMBOTTLES .LE. 1) EXITLOOP ;If just 1 bottle left, get out
CNUMBOTTLES = NUMBOTTLES,'ZX'
WRITES (8,LINE3)
WRITES (8," ")
END
DNUMBOTTLES = NUMBOTTLES,'ZX'
WRITES(8,LINE4)
WRITES (8," ")
ENUMBOTTLES = NUMBOTTLES,'ZX'
WRITES(8,LINE5)
WRITES (8," Take one down, pass it around,")
WRITES(8,"0 Bottles of Beer on the wall,")
WRITES(8,"0 Bottles of Beer,")
WRITES(8,"Go to the store and buy some more,")
WRITES(8,"99 Bottles of Beer on the wall,")
WRITES (8," ")
WRITES (8," ")
SLEEP 2
CLOSE 8
STOP
.ENDE[edit]
def bottles(n) {
return switch (n) {
match ==0 { "No bottles" }
match ==1 { "1 bottle" }
match _ { `$n bottles` }
}
}
for n in (1..99).descending() {
println(`${bottles(n)} of beer on the wall,
${bottles(n)} of beer.
Take one down, pass it around,
${bottles(n.previous())} of beer on the wall.
`)
}EasyLang[edit]
proc checkPlural num . word$ .
if num = 1
word$ = "bottle"
else
word$ = "bottles"
.
.
#
for i = 99 step -1 to 1
call checkPlural i pluralWord$
print i & " " & pluralWord$ & " of beer on the wall"
print i & " " & pluralWord$ & " of beer"
print "Take one down, pass it around"
call checkPlural i - 1 pluralWord$
if i - 1 = 0
print "No more bottles of beer on the wall"
else
print i - 1 & " " & pluralWord$ & " of beer on the wall"
.
print ""
.ECL[edit]
Layout := RECORD
UNSIGNED1 RecID1;
UNSIGNED1 RecID2;
STRING30 txt;
END;
Beers := DATASET(99,TRANSFORM(Layout,
SELF.RecID1 := COUNTER,SELF.RecID2 := 0,SELF.txt := ''));
Layout XF(Layout L,INTEGER C) := TRANSFORM
IsOneNext := L.RecID1-1 = 1;
IsOne := L.RecID1 = 1;
SELF.txt := CHOOSE(C,
(STRING)(L.RecID1-1) + ' bottle'+IF(IsOneNext,'','s')+' of beer on the wall',
'Take one down, pass it around',
(STRING)(L.RecID1) + ' bottle'+IF(IsOne,'','s')+' of beer',
(STRING)(L.RecID1) + ' bottle'+IF(IsOne,'','s')+' of beer on the wall','');
SELF.RecID2 := C;
SELF := L;
END;
Rev := NORMALIZE(Beers,5,XF(LEFT,COUNTER));
OUTPUT(SORT(Rev,-Recid1,-RecID2),{txt},ALL);
Ecstasy[edit]
module Bottles
{
@Inject Console console;
void run()
{
function String(Int) num = i -> i==0 ? "No" : i.toString();
function String(Int) bottles = i -> i==1 ? "bottle" : "bottles";
for (Int remain : 99..1)
{
console.print($|{num(remain)} {bottles(remain)} of beer on the wall
|{num(remain)} {bottles(remain)} of beer
|Take one down, pass it around
|{num(remain-1)} {bottles(remain-1)} of beer on the wall
|
);
}
}
}
Egel[edit]
import "prelude.eg"
import "io.ego"
using System
using IO
def print_rhyme =
[ 0 ->
print "better go to the store, and buy some more\n"
| N ->
let _ = print N " bottles of beer on the wall\n" in
let _ = print N " bottles of beer\n" in
let _ = print "take one down, pass it around\n" in
print_rhyme (N - 1) ]
def main = print_rhyme 99EGL[edit]
program TestProgram type BasicProgram {}
function main()
for (count int from 99 to 1 decrement by 1)
SysLib.writeStdout( bottleStr( count ) :: " of beer on the wall." );
SysLib.writeStdout( bottleStr( count ) :: " of beer." );
SysLib.writeStdout( "Take one down, pass it around." );
SysLib.writeStdout( bottleStr( count - 1) :: " of beer on the wall.\n");
end
end
private function bottleStr( count int in) returns( string )
case ( count )
when ( 1 )
return( "1 bottle" );
when ( 0 )
return( "No more bottles" );
otherwise
return( count :: " bottles" );
end
end
endEiffel[edit]
class
APPLICATION
create
make
feature {NONE} -- Initialization
make
local
bottles: INTEGER
do
from
bottles := 99
invariant
bottles <= 99 and bottles >= 1
until
bottles = 1
loop
print (bottles)
print (" bottles of beer on the wall,%N")
print (bottles)
print (" bottles of beer.%N")
print ("Take one down, pass it around,%N")
bottles := bottles - 1
if bottles > 1 then
print (bottles)
print (" bottles of beer on the wall.%N%N")
end
variant
bottles
end
print ("1 bottle of beer on the wall.%N%N");
print ("No more bottles of beer on the wall,%N");
print ("no more bottles of beer.%N");
print ("Go to the store and buy some more,%N");
print ("99 bottles of beer on the wall.%N");
end
end
An alternative version written using the across-loop construct.
output_lyrics
-- Output the lyrics to 99-bottles-of-beer.
local
l_bottles: LINKED_LIST [INTEGER]
do
create l_bottles.make
across (1 |..| 99) as ic loop l_bottles.force (ic.item) end
across l_bottles.new_cursor.reversed as ic_bottles loop
print (ic_bottles.item)
print (" bottles of beer on the wall, ")
print (ic_bottles.item)
print (" bottles of beer.%N")
print ("Take one down, pass it around, ")
if ic_bottles.item > 1 then
print (ic_bottles.item)
print (" bottles of beer on the wall.%N%N")
end
end
print ("1 bottle of beer on the wall.%N")
print ("No more bottles of beer on the wall, no more bottles of beer.%N")
print ("Go to the store and buy some more, 99 bottles of beer on the wall.%N")
end
Ela[edit]
open list
beer 1 = "1 bottle of beer on the wall\n1 bottle of beer\nTake one down, pass it around"
beer 0 = "better go to the store and buy some more."
beer v = show v ++ " bottles of beer on the wall\n"
++ show v
++" bottles of beer\nTake one down, pass it around\n"
map beer [99,98..0]Elan[edit]
INT VAR number of bottles;
PROCEDURE print how many bottles are on the wall (INT CONST number):
print number;
print bottle;
print trailing text.
print number:
IF number = 0 THEN
put ("No")
ELSE
put (number)
END IF.
print bottle:
out ("Bottle");
IF no <> 1 THEN
out ("s")
END IF.
print trailing text:
out (" of beer").
END PROCEDURE print how many bottles are on the wall;
say hello;
print song;
say goodbye.
say hello:
putline ("99 Bottles of Beer");
putline ("==================");
line.
print song:
FOR number of bottles FROM 99 DOWNTO 1 REPEAT
print first line;
print second line;
print third line
END REPEAT.
say goodbye:
line;
putline ("=====================");
putline ("You need a ride home?");
line.
print first line:
print how many bottles are on the wall (number of bottles);
out (" on the wall, ");
print how many bottles are on the wall (number of bottles);
line.
print second line:
putline ("Take one down and pass it around,").
print third line:
print how many bottles are on the wall (number of bottles - 1);
putline (" on the wall");
line.Elena[edit]
ELENA 5.0 :
import system'routines;
import extensions;
import extensions'routines;
import extensions'text;
extension bottleOp
{
bottleDescription()
= self.toPrintable() + (self != 1).iif(" bottles"," bottle");
bottleEnumerator() = new Variable(self).doWith:(n)
{
^ new Enumerator
{
bool next() = n > 0;
get() = new StringWriter()
.printLine(n.bottleDescription()," of beer on the wall")
.printLine(n.bottleDescription()," of beer")
.printLine("Take one down, pass it around")
.printLine((n.reduce:1).bottleDescription()," of beer on the wall");
reset() {}
enumerable() = __target;
}
};
}
public program()
{
var bottles := 99;
bottles.bottleEnumerator().forEach:printingLn
}- Output:
5 bottles of beer on the wall 5 bottles of beer Take one down, pass it around 4 bottles of beer on the wall 4 bottles of beer on the wall 4 bottles of beer Take one down, pass it around 3 bottles of beer on the wall 3 bottles of beer on the wall 3 bottles of beer Take one down, pass it around 2 bottles of beer on the wall 2 bottles of beer on the wall 2 bottles of beer Take one down, pass it around 1 bottle of beer on the wall 1 bottle of beer on the wall 1 bottle of beer Take one down, pass it around 0 bottles of beer on the wall
Elixir[edit]
defmodule Bottles do
def run do
Enum.each 99..1, fn idx ->
IO.puts "#{idx} bottle#{plural(idx)} of beer on the wall"
IO.puts "#{idx} bottle#{plural(idx)} of beer"
IO.puts "Take one down, pass it around"
IO.puts "#{idx - 1} bottle#{plural(idx-1)} of beer on the wall"
IO.puts ""
end
end
def plural(1), do: ""
def plural(num), do: "s"
end
Bottles.run
Elm[edit]
module Main exposing (main)
import Html
main =
List.range 1 100
|> List.reverse
|> List.map
(\n ->
let
nString =
String.fromInt n
n1String =
String.fromInt (n - 1)
in
[ nString ++ " bottles of beer on the wall"
, nString ++ " bottles of beer"
, "Take one down, pass it around"
, n1String ++ " bottles of beer on the wall"
]
|> List.map Html.text
|> List.intersperse (Html.br [] [])
|> Html.p []
)
|> Html.div []
Emacs Lisp[edit]
(let ((i 99))
(while (> i 0)
(message "%d bottles of beer on the wall" i)
(message "%d bottles of beer" i)
(message "Take one down, pass it around")
(message "%d bottles of beer on the wall" (1- i))
(setq i (1- i))))
EMal[edit]
This version writes the lyrics as described here: https://99-bottles-of-beer.net/lyrics.html
type NinetynineBottles
int DEFAULT_BOTTLES_COUNT = 99
model
int initialBottlesCount, bottlesCount
new by int bottlesCount
me.initialBottlesCount = bottlesCount
me.bottlesCount = bottlesCount
end
fun subject = text by block do return when(me.bottlesCount == 1, "bottle", "bottles") end
fun bottles = text by block do return when(me.bottlesCount == 0, "no more", text!me.bottlesCount) end
fun goToWall = void by block
text line = me.bottles() + " " + me.subject() + " of beer on the wall, " +
me.bottles() + " " + me.subject() + " of beer."
if me.bottlesCount == 0 do line[0] = line[0].upper() end # text can be modified
writeLine(line)
end
fun takeOne = logic by block
if --me.bottlesCount < 0 do return false end # cannot take a beer down
writeLine("Take one down and pass it around, " + me.bottles() +
" " + me.subject() + " of beer on the wall.")
writeLine()
return true
end
fun goToStore = void by block
writeLine("Go to the store and buy some more, " + me.initialBottlesCount +
" bottles of beer on the wall.")
end
fun play = void by block
for ever
me.goToWall()
if not me.takeOne()
me.goToStore()
break
end
end
end
end
NinetynineBottles(when(Runtime.args.length > 0, int!Runtime.args[0], DEFAULT_BOTTLES_COUNT)).play()The output for two bottles of beer is as follows.
- Output:
2 bottles of beer on the wall, 2 bottles of beer. Take one down and pass it around, 1 bottle of beer on the wall. 1 bottle of beer on the wall, 1 bottle of beer. Take one down and pass it around, no more bottles of beer on the wall. No more bottles of beer on the wall, no more bottles of beer. Go to the store and buy some more, 2 bottles of beer on the wall.
Erlang[edit]
-module(beersong).
-export([sing/0]).
-define(TEMPLATE_0, "~s of beer on the wall, ~s of beer.~nGo to the store and buy some more, 99
bottles of beer on the wall.~n").
-define(TEMPLATE_N, "~s of beer on the wall, ~s of beer.~nTake one down and pass it around, ~s of
beer on the wall.~n~n").
create_verse(0) -> {0, io_lib:format(?TEMPLATE_0, phrase(0))};
create_verse(Bottle) -> {Bottle, io_lib:format(?TEMPLATE_N, phrase(Bottle))}.
phrase(0) -> ["No more bottles", "no more bottles"];
phrase(1) -> ["1 bottle", "1 bottle", "no more bottles"];
phrase(2) -> ["2 bottles", "2 bottles", "1 bottle"];
phrase(Bottle) -> lists:duplicate(2, integer_to_list(Bottle) ++ " bottles") ++
[integer_to_list(Bottle-1) ++ " bottles"].
bottles() -> lists:reverse(lists:seq(0,99)).
sing() ->
lists:foreach(fun spawn_singer/1, bottles()),
sing_verse(99).
spawn_singer(Bottle) ->
Pid = self(),
spawn(fun() -> Pid ! create_verse(Bottle) end).
sing_verse(Bottle) ->
receive
{_, Verse} when Bottle == 0 ->
io:format(Verse);
{N, Verse} when Bottle == N ->
io:format(Verse),
sing_verse(Bottle-1)
after
3000 ->
io:format("Verse not received - re-starting singer~n"),
spawn_singer(Bottle),
sing_verse(Bottle)
end.
Euphoria[edit]
constant
bottles = "bottles",
bottle = "bottle"
procedure beers (integer how_much)
sequence word1 = bottles, word2 = bottles
switch how_much do
case 2 then
word2 = bottle
case 1 then
word1 = bottle
word2 = bottle
end switch
printf (1,
"%d %s of beer on the wall \n" &
"%d %s of beer \n" &
"Take one down, and pass it around \n" &
"%d %s of beer on the wall \n\n",
{ how_much, word1,
how_much, word1,
how_much-1, word2 }
)
end procedure
for a = 99 to 1 by -1 do
beers (a)
end for-- An alternate version
include std/console.e
sequence howmany = {"No more bottles","%d bottle","","s"}
for beer = 99 to 1 by -1 do
display(`
[1] bottles of beer on the wall,
[1] bottles of beer.
Take one down, drink it right down,
[2][3] of beer.
`,{beer,
sprintf(howmany[(beer>1)+1],beer-1),
howmany[(beer>2)+3]
})
end for-- yet another version:
include std/console.e
object stanza = {
"[] bottles of beer on the wall,",
"[] bottles of beer,",
"take one down, and pass it around,"
}
object bottles = 99
loop do
display(stanza[1],bottles)
display(stanza[2],bottles)
display(stanza[3])
bottles -= 1
display(stanza[1]&"\n",{bottles})
until bottles = 0
end loopExtended BrainF***[edit]
See 99 Bottles of Beer/EsoLang
F#[edit]
#light
let rec bottles n =
let (before, after) = match n with
| 1 -> ("bottle", "bottles")
| 2 -> ("bottles", "bottle")
| n -> ("bottles", "bottles")
printfn "%d %s of beer on the wall" n before
printfn "%d %s of beer" n before
printfn "Take one down, pass it around"
printfn "%d %s of beer on the wall\n" (n - 1) after
if n > 1 then
bottles (n - 1)
Factor[edit]
USING: io kernel make math math.parser math.ranges sequences ;
: bottle ( -- quot )
[
[
[
[ # " bottles of beer on the wall,\n" % ]
[ # " bottles of beer.\n" % ] bi
] keep
"Take one down, pass it around,\n" %
1 - # " bottles of beer on the wall\n" %
] " " make print
] ; inline
: last-verse ( -- )
"Go to the store and buy some more,"
"no more bottles of beer on the wall!" [ print ] bi@ ;
: bottles ( n -- )
1 [a,b] bottle each last-verse ;
! Usage: 99 bottles
Falcon[edit]
for i in [99:1]
> i, " bottles of beer on the wall"
> i, " bottles of beer"
> "Take one down, pass it around"
> i-1, " bottles of beer on the wall\n"
endA more robust version to handle plural/not plural conditions
for i in [99:1]
plural = (i != 1) ? 's' : ""
> @ "$i bottle$plural of beer on the wall"
> @ "$i bottle$plural of beer"
> "Take one down, pass it around"
> i-1, @ " bottle$plural of beer on the wall\n"
endFALSE[edit]
See 99 Bottles of Beer/EsoLang
Fe[edit]
(= n 99)
(while (< 0 n)
(print n "bottles of beer on the wall")
(print n "bottles of beer")
(print "Take one down, pass it around")
(= n (- n 1))
(print n "bottles of beer on the wall\n"))
ferite[edit]
copied from 99-bottles-of-beer.net.
uses "console";
number bottles = 99;
boolean looping = true;
object counter = closure {
if (--bottles > 0) {
return true;
} else {
return false;
}
};
while (looping) {
Console.println("${bottles} bottles of beer on the wall,");
Console.println("${bottles} bottles of beer,");
Console.println("Take one down, pass it around,");
looping = counter.invoke();
Console.println("${bottles} bottles of beer on the wall.");Fexl[edit]
\suffix=(\n eq n 1 "" "s")
\sing_count=(\n put [n " bottle" (suffix n) " of beer"])
\sing_line1=(\n sing_count n say " on the wall")
\sing_line2=(\n sing_count n nl)
\sing==
(\n
le n 0 ();
sing_line1 n
sing_line2 n
say "Take one down, pass it around"
\n=(- n 1)
sing_line1 n
nl
sing n
)
sing 3- Output:
3 bottles of beer on the wall 3 bottles of beer Take one down, pass it around 2 bottles of beer on the wall 2 bottles of beer on the wall 2 bottles of beer Take one down, pass it around 1 bottle of beer on the wall 1 bottle of beer on the wall 1 bottle of beer Take one down, pass it around 0 bottles of beer on the wall
FOCAL[edit]
01.10 S N=99
01.15 D 2;T " OF BEER ON THE WALL,",!
01.20 D 2;T " OF BEER,",!
01.24 S N=N-1
01.25 T "TAKE ";I (N),1.3,1.4,1.3
01.30 T "IT";G 1.5
01.40 T "ONE"
01.50 T " DOWN AND PASS IT AROUND,",!
01.60 D 2;T " OF BEER ON THE WALL!",!!
01.70 I (N),1.8,1.15
01.80 Q
02.01 C-PRINT N BOTTLE(S)
02.10 I (N)2.2,2.2,2.3
02.20 T "NO MORE";G 2.4
02.30 D 3
02.40 T " BOTTLE";I (N-1)2.5,2.6,2.5
02.50 T "S"
02.60 R
03.01 C-PRINT 2-DIGIT NUMBER IN N
03.02 C-THIS IS NECESSARY BECAUSE T ALWAYS PREPENDS = TO NUMBERS
03.10 S A=FITR(N/10);I (A),3.3,3.2
03.20 D 4
03.30 S A=N-FITR(N/10)*10;D 4
04.01 C-PRINT DIGIT IN A
04.10 I (A-0),4.20,4.11
04.11 I (A-1),4.21,4.12
04.12 I (A-2),4.22,4.13
04.13 I (A-3),4.23,4.14
04.14 I (A-4),4.24,4.15
04.15 I (A-5),4.25,4.16
04.16 I (A-6),4.26,4.17
04.17 I (A-7),4.27,4.18
04.18 I (A-8),4.28,4.19
04.19 T "9";R
04.20 T "0";R
04.21 T "1";R
04.22 T "2";R
04.23 T "3";R
04.24 T "4";R
04.25 T "5";R
04.26 T "6";R
04.27 T "7";R
04.28 T "8";RForth[edit]
:noname dup . ." bottles" ;
:noname ." 1 bottle" ;
:noname ." no more bottles" ;
create bottles , , ,
: .bottles dup 2 min cells bottles + @ execute ;
: .beer .bottles ." of beer" ;
: .wall .beer ." on the wall" ;
: .take ." Take one down, pass it around" ;
: .verse .wall cr .beer cr
1- .take cr .wall cr ;
: verses begin cr .verse ?dup 0= until ;
99 verses
Version 2: create a beer language and write the program
DECIMAL
: BOTTLES ( n -- )
DUP
CASE
1 OF ." One more bottle " DROP ENDOF
0 OF ." NO MORE bottles " DROP ENDOF
. ." bottles " \ DEFAULT CASE
ENDCASE ;
: , [CHAR] , EMIT SPACE 100 MS CR ;
: . [CHAR] . EMIT 300 MS CR CR CR ;
: OF ." of " ; : BEER ." beer " ;
: ON ." on " ; : THE ." the " ;
: WALL ." wall" ; : TAKE ." take " ;
: ONE ." one " ; : DOWN ." down, " ;
: PASS ." pass " ; : IT ." it " ;
: AROUND ." around" ;
: POPONE 1 SWAP CR ;
: DRINK POSTPONE DO ; IMMEDIATE
: ANOTHER S" -1 +LOOP" EVALUATE ; IMMEDIATE
: HOWMANY S" I " EVALUATE ; IMMEDIATE
: ONELESS S" I 1- " EVALUATE ; IMMEDIATE
: HANGOVER ." :-(" CR QUIT ;
: BEERS ( n -- ) \ Usage: 99 BEERS
POPONE
DRINK
HOWMANY BOTTLES OF BEER ON THE WALL ,
HOWMANY BOTTLES OF BEER ,
TAKE ONE DOWN PASS IT AROUND ,
ONELESS BOTTLES OF BEER ON THE WALL .
ANOTHER
HANGOVER ;
Forth Console Output
2 beers
2 bottles of beer on the wall,
2 bottles of beer ,
take one down, pass it around,
One more bottle of beer on the wall.
One more bottle of beer on the wall,
One more bottle of beer ,
take one down, pass it around,
No more bottles of beer on the wall.
ok
Fortran[edit]
F90 version[edit]
program bottlestest
implicit none
integer :: i
character(len=*), parameter :: bwall = " on the wall", &
bottles = "bottles of beer", &
bottle = "bottle of beer", &
take = "Take one down, pass it around", &
form = "(I0, ' ', A)"
do i = 99,0,-1
if ( i /= 1 ) then
write (*,form) i, bottles // bwall
if ( i > 0 ) write (*,form) i, bottles
else
write (*,form) i, bottle // bwall
write (*,form) i, bottle
end if
if ( i > 0 ) write (*,*) take
end do
end program bottlestest
MPI version[edit]
program bottlesMPI
implicit none
integer :: ierr,rank,nproc
character(len=*), parameter :: bwall = " on the wall", &
bottles = "bottles of beer", &
bottle = "bottle of beer", &
take = "Take one down, pass it around", &
form = "(I0, ' ', A)"
call mpi_init(ierr)
call mpi_comm_size(MPI_COMM_WORLD,nproc, ierr)
call mpi_comm_rank(MPI_COMM_WORLD,rank,ierr)
if ( rank /= 1 ) then
write (*,form) rank, bottles // bwall
if ( rank > 0 ) write (*,form) rank, bottles
else
write (*,form) rank, bottle // bwall
write (*,form) rank, bottle
end if
if ( rank > 0 ) write (*,*) take
call mpi_finalize(ierr)
end program bottlesMPI
Usage:
mpif90 filename.f90 mpiexec -np 99 a.out
Fortran 2003/2008 OOP version[edit]
Works with GNU gfortran 5.0.0 and Intel ifort 15.0.2
module song_typedefs
implicit none
private ! all
public :: TBottles
type, abstract :: TContainer
integer :: quantity
contains
! deferred method i.e. abstract method = must be overridden in extended type
procedure(take_one), deferred, pass :: take_one
procedure(show_quantity), deferred, pass :: show_quantity
end type TContainer
abstract interface
subroutine take_one(this)
import TContainer
implicit none
class(TContainer) :: this
end subroutine take_one
subroutine show_quantity(this)
import TContainer
implicit none
class(TContainer) :: this
end subroutine show_quantity
end interface
! extended derived type
type, extends(TContainer) :: TBottles
contains
procedure, pass :: take_one => take_one_bottle
procedure, pass :: show_quantity => show_bottles
final :: finalize_bottles
end type TBottles
contains
subroutine show_bottles(this)
implicit none
class(TBottles) :: this
! integer :: show_bottles
character(len=*), parameter :: bw0 = "No more bottles of beer on the wall,"
character(len=*), parameter :: bwx = "bottles of beer on the wall,"
character(len=*), parameter :: bw1 = "bottle of beer on the wall,"
character(len=*), parameter :: bb0 = "no more bottles of beer."
character(len=*), parameter :: bbx = "bottles of beer."
character(len=*), parameter :: bb1 = "bottle of beer."
character(len=*), parameter :: fmtxdd = "(I2,1X,A28,1X,I2,1X,A16)"
character(len=*), parameter :: fmtxd = "(I1,1X,A28,1X,I1,1X,A16)"
character(len=*), parameter :: fmt1 = "(I1,1X,A27,1X,I1,1X,A15)"
character(len=*), parameter :: fmt0 = "(A36,1X,A24)"
select case (this % quantity)
case (10:)
write(*,fmtxdd) this % quantity, bwx, this % quantity, bbx
case (2:9)
write(*,fmtxd) this % quantity, bwx, this % quantity, bbx
case (1)
write(*,fmt1) this % quantity, bw1, this % quantity, bb1
case (0)
write(*,*)
write(*,fmt0) bw0, bb0
case default
write(*,*)"Warning! Number of bottles exception, error 42. STOP"
stop
end select
! show_bottles = this % quantity
end subroutine show_bottles
subroutine take_one_bottle(this) ! bind(c, name='take_one_bottle')
implicit none
class(TBottles) :: this
! integer :: take_one_bottle
character(len=*), parameter :: t1 = "Take one down and pass it around,"
character(len=*), parameter :: remx = "bottles of beer on the wall."
character(len=*), parameter :: rem1 = "bottle of beer on the wall."
character(len=*), parameter :: rem0 = "no more bottles of beer on the wall."
character(len=*), parameter :: fmtx = "(A33,1X,I2,1X,A28)"
character(len=*), parameter :: fmt1 = "(A33,1X,I2,1X,A27)"
character(len=*), parameter :: fmt0 = "(A33,1X,A36)"
this % quantity = this % quantity -1
select case (this%quantity)
case (2:)
write(*,fmtx) t1, this%quantity, remx
case (1)
write(*,fmt1) t1, this%quantity, rem1
case (0)
write(*,fmt0) t1, rem0
case (-1)
write(*,'(A66)') "Go to the store and buy some more, 99 bottles of beer on the wall."
case default
write(*,*)"Warning! Number of bottles exception, error 42. STOP"
stop
end select
end subroutine take_one_bottle
subroutine finalize_bottles(bottles)
implicit none
type(TBottles) :: bottles
! here can be more code
end subroutine finalize_bottles
end module song_typedefs
!-----------------------------------------------------------------------
!Main program
!-----------------------------------------------------------------------
program bottles_song
use song_typedefs
implicit none
integer, parameter :: MAGIC_NUMBER = 99
type(TBottles), target :: BTLS
BTLS = TBottles(MAGIC_NUMBER)
call make_song(BTLS)
contains
subroutine make_song(bottles)
type(TBottles) :: bottles
do while(bottles%quantity >= 0)
call bottles%show_quantity()
call bottles%take_one()
enddo
end subroutine make_song
end program bottles_song
Frege[edit]
(identical to the Haskell, apart from adding the module declaration)module Beer where
main = mapM_ (putStrLn . beer) [99, 98 .. 0]
beer 1 = "1 bottle of beer on the wall\n1 bottle of beer\nTake one down, pass it around"
beer 0 = "better go to the store and buy some more."
beer v = show v ++ " bottles of beer on the wall\n"
++ show v
++ " bottles of beer\nTake one down, pass it around\n"
++ head (lines $ beer $ v-1) ++ "\n"friendly interactive shell[edit]
Frink[edit]
Frink tracks units of measure through all calculations. It has a large library of built-in units of measure, including volume. The following program prints out the remaining volume of beer (assuming we start with 99 bottles of beer, each containing 12 fluid ounces) in different random units of volume, never repeating a unit.
units = array[units[volume]]
showApproximations[false]
for n = 99 to 0 step -1
{
unit = units.removeRandom[]
str = getBottleString[n, unit]
println["$str of beer on the wall, $str."]
if (n == 0)
println["Go to the store and buy some more, 99 bottles of beer on the wall."]
else
println["Take one down and pass it around, " + getBottleString[n-1, unit] + " on the wall.\n"]
}
getBottleString[n, unit] := format[n*12 floz, unit, 6] + "s"Sample randomized output:
0.019386 facecords of beer on the wall, 0.019386 facecords. Take one down and pass it around, 0.019190 facecords on the wall. 36.750000 quarts of beer on the wall, 36.750000 quarts. Take one down and pass it around, 36.375000 quarts on the wall. 581539.650545 brminims of beer on the wall, 581539.650545 brminims. Take one down and pass it around, 575544.396416 brminims on the wall. 10.377148 scotsoatlippys of beer on the wall, 10.377148 scotsoatlippys. Take one down and pass it around, 10.269053 scotsoatlippys on the wall. 7.416004 cangallons of beer on the wall, 7.416004 cangallons. Take one down and pass it around, 7.337941 cangallons on the wall. 3335.894135 dessertspoons of beer on the wall, 3335.894135 dessertspoons. Take one down and pass it around, 3300.405899 dessertspoons on the wall. 0.233105 barrelbulks of beer on the wall, 0.233105 barrelbulks. Take one down and pass it around, 0.230599 barrelbulks on the wall. 21.766118 magnums of beer on the wall, 21.766118 magnums. Take one down and pass it around, 21.529530 magnums on the wall. 1092.000000 fluidounces of beer on the wall, 1092.000000 fluidounces. Take one down and pass it around, 1080.000000 fluidounces on the wall. ... 12.000000 ponys of beer on the wall, 12.000000 ponys. Take one down and pass it around, 0.000000 ponys on the wall. 0.000000 brfluidounces of beer on the wall, 0.000000 brfluidounces. Go to the store and buy some more, 99 bottles of beer on the wall.
FunL[edit]
val
numbers = {1:'one', 2:'two', 3:'three', 4:'four', 5:'five', 6:'six', 7:'seven',
8:'eight', 9:'nine', 10:'ten', 11:'eleven', 12:'twelve'}
alt = {3:'thir', 5:'fif'}
def
suffix( a, b ) = (if a.endsWith( 't' ) then a.substring( 0, a.length()-1 ) else a) + b
number( n@(13 | 15) ) = suffix( alt(n%10), 'teen' )
number( 20 ) = 'twenty'
number( n@(30 | 50) ) = suffix( alt(n\10), 'ty' )
number( n )
| n <= 12 = numbers(n)
| n <= 19 = suffix( numbers(n%10), 'teen' )
| 10|n = suffix( numbers(n\10), 'ty' )
| otherwise = number( n\10*10 ) + '-' + number( n%10 )
cap( s ) = s.substring( 0, 1 ).toUpperCase() + s.substring( 1, s.length() )
bottles( 0 ) = 'no more bottles'
bottles( 1 ) = 'one bottle'
bottles( n ) = number( n ) + ' bottles'
verse( 0 ) = ('No more bottles of beer on the wall, no more bottles of beer.\n'
+ 'Go to the store and buy some more, ninety-nine bottles of beer on the wall.')
verse( n ) = (cap( bottles(n) ) + ' of beer on the wall, ' + bottles( n ) + ' of beer.\n'
+ 'Take one down and pass it around, ' + bottles( n-1 )
+ ' of beer on the wall.\n')
for i <- 99..0 by -1 do println( verse(i) )FutureBasic[edit]
include "NSLog.incl"
NSUInteger i
CFStringRef a, b, c
a = @" bottles of beer on the wall,\n"
b = @" bottles of beer.\n"
c = @"Take one down, pass it around,\n"
for i = 99 to 1 step -1
NSLog( @"%ld%@%ld%@%@%ld%@\n", i, a, i, b, c, i -1, a )
next
HandleEventsGambas[edit]
Implementation of the code '99 bottles of beer' written in Visual Basic. Code tested in Gambas 3.15.2
' Gambas module file
Public Const bottlesofbeer As String = " bottles of beer."
Public Const onthewall As String = " on the wall."
Public Const takeonedown As String = "Take one down, pass it around."
Public Const onebeer As String = "1 bottle of beer"
Public Sub Main()
Dim bottles As Byte
For bottles = 99 To 3 Step -1
Print CStr(bottles) & bottlesofbeer & onthewall
Print CStr(bottles) & bottlesofbeer
Print takeonedown
Print CStr(bottles - 1) & bottlesofbeer & onthewall
Print
Next
Print "2" & bottlesofbeer & onthewall
Print "2" & bottlesofbeer
Print takeonedown
Print onebeer & onthewall
Print
Print onebeer & onthewall
Print onebeer
Print takeonedown
Print "No more" & bottlesofbeer & onthewall
Print
Print "No" & bottlesofbeer & onthewall
Print "No" & bottlesofbeer
Print "Go to the store, buy some more."
Print "99" & bottlesofbeer & onthewall
End
GAP[edit]
Bottles := function(n)
local line, i, j, u;
line := function(n)
s := String(n);
if n < 2 then
return Concatenation(String(n), " bottle of beer");
else
return Concatenation(String(n), " bottles of beer");
fi;
end;
for i in [1 .. n] do
j := n - i + 1;
u := line(j);
Display(Concatenation(u, " on the wall"));
Display(u);
Display("Take one down, pass it around");
Display(Concatenation(line(j - 1), " on the wall"));
if i <> n then
Display("");
fi;
od;
end;
GDScript[edit]
extends MainLoop
# Represents a count of bottles
class Bottles:
var count := 99
func take(n: int = 1) -> void:
count -= n
func _to_string() -> String:
match count:
0: return "No more bottles"
1: return "1 bottle"
_: return "%s bottles" % count
func _process(_delta: float) -> bool:
var bottles := Bottles.new()
while bottles.count > 0:
print("%s of beer on the wall" % bottles)
print("%s of beer" % bottles)
print("Take one down, pass it around")
bottles.take()
print("%s of beer on the wall" % bottles)
# Seperate paragraphs
if bottles.count > 0:
print()
return true # Makes the program exit
Silly node-tree version[edit]
This uses the node's children as the display method (which can be viewed in-editor with the remote tab).
extends Node
@export var alcoholism: int = 99
func _ready():
# Add the lyrics as child nodes
var padding := "" # Avoid name clashes by adding spaces
for bottleCount in range(alcoholism, 0, -1):
# Seperate paragraphs with blank nodes
if bottleCount < alcoholism:
add_lyric(padding)
add_lyric("%s of beer on the wall" % [_formatBottles(bottleCount)])
add_lyric("%s of beer" % [_formatBottles(bottleCount)])
add_lyric("Take one down, pass it around" + padding)
add_lyric("%s of beer on the wall " % [_formatBottles(bottleCount - 1)]) # Extra space for name clash avoidance
padding += " " # Add spaces so the names don't clash
func _formatBottles(bottleCount: int) -> String:
return "%d bottle%s" % [bottleCount, "" if bottleCount == 1 else "s"]
func add_lyric(lyric: String) -> void:
var new_child := Node.new()
new_child.name = lyric
add_child(new_child)
Genie[edit]
[indent=4]
def plural(n:uint):string
return (n == 1) ? "" : "s"
def no(n:uint):string
return (n == 0) ? "No" : n.to_string()
init
bottles:uint = 99;
do
print "%u bottle%s of beer on the wall", bottles, plural(bottles)
print "%u bottle%s of beer", bottles, plural(bottles)
print "Take one down, pass it around"
--bottles
print "%s bottle%s of beer on the wall\n", no(bottles), plural(bottles)
while bottles != 0- Output:
prompt$ valac 99bottles.gs prompt$ ./99bottles | tail -10 2 bottles of beer on the wall 2 bottles of beer Take one down, pass it around 1 bottle of beer on the wall 1 bottle of beer on the wall 1 bottle of beer Take one down, pass it around No bottles of beer on the wall
gnuplot[edit]
if (!exists("bottles")) bottles = 99
print sprintf("%i bottles of beer on the wall", bottles)
print sprintf("%i bottles of beer", bottles)
print "Take one down, pass it around"
bottles = bottles - 1
print sprintf("%i bottles of beer on the wall", bottles)
print ""
if (bottles > 0) reread
Go[edit]
No sense of humor[edit]
package main
import "fmt"
func main() {
bottles := func(i int) string {
switch i {
case 0:
return "No more bottles"
case 1:
return "1 bottle"
default:
return fmt.Sprintf("%d bottles", i)
}
}
for i := 99; i > 0; i-- {
fmt.Printf("%s of beer on the wall\n", bottles(i))
fmt.Printf("%s of beer\n", bottles(i))
fmt.Printf("Take one down, pass it around\n")
fmt.Printf("%s of beer on the wall\n", bottles(i-1))
}
}
Typoglycemic[edit]
With code from RC tasks Number names, Knuth shuffle.
package main
import (
"fmt"
"math/rand"
"strings"
"time"
)
func main() {
rand.Seed(time.Now().UnixNano())
for i := 99; i > 0; i-- {
fmt.Printf("%s %s %s\n",
slur(numberName(i), i),
pluralizeFirst(slur("bottle of", i), i),
slur("beer on the wall", i))
fmt.Printf("%s %s %s\n",
slur(numberName(i), i),
pluralizeFirst(slur("bottle of", i), i),
slur("beer", i))
fmt.Printf("%s %s %s\n",
slur("take one", i),
slur("down", i),
slur("pass it around", i))
fmt.Printf("%s %s %s\n",
slur(numberName(i-1), i),
pluralizeFirst(slur("bottle of", i), i-1),
slur("beer on the wall", i))
}
}
// adapted from Number names task
func numberName(n int) string {
switch {
case n < 0:
case n < 20:
return small[n]
case n < 100:
t := tens[n/10]
s := n % 10
if s > 0 {
t += " " + small[s]
}
return t
}
return ""
}
var small = []string{"no", "one", "two", "three", "four", "five", "six",
"seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen",
"fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"}
var tens = []string{"ones", "ten", "twenty", "thirty", "forty",
"fifty", "sixty", "seventy", "eighty", "ninety"}
// pluralize first word of s by adding an s, but only if n is not 1.
func pluralizeFirst(s string, n int) string {
if n == 1 {
return s
}
w := strings.Fields(s)
w[0] += "s"
return strings.Join(w, " ")
}
// p is string to slur, d is drunkenness, from 0 to 99
func slur(p string, d int) string {
// shuffle only interior letters
a := []byte(p[1 : len(p)-1])
// adapted from Knuth shuffle task.
// shuffle letters with probability d/100.
for i := len(a) - 1; i >= 1; i-- {
if rand.Intn(100) >= d {
j := rand.Intn(i + 1)
a[i], a[j] = a[j], a[i]
}
}
// condense spaces
w := strings.Fields(p[:1] + string(a) + p[len(p)-1:])
return strings.Join(w, " ")
}
- Output:
Things start out pretty well...
ninety nine bottles of beer on the wall ninety nine bottles of beer take one down pass it around ninety eight bottles of beer on the wall ninety eight bottles of beer on the wall ninety eight bottles of beer take one down pass it around ninety seven bottles of beer on the wall ninety seven boetlts of beer on the wall ninety seven bottles of beer take one down pass it around ninety six botelts of beer on the wall
Soon,
eighty four bottles of bere wn the oall ehigty four bottles of beer tkae one down pnssti arouad eihhty tgree bttoles of beer en tho wall eighty three blottes of beet on rhe wall eighty three bottles of beer taen oke down pass it around eiwyth tgo bttoles of beew on lhr eatl
It ends very well, if you're drinking along.
two btloots ef bre enehta wo ll two bs tleootf beer tnoeka e dwon pts ou nsaaird one bolote tf betwr le ao enhl one beoo ttlf blwtenr ehoa el one bltooe tf beer tne okae down pasaostiu rnd no bletts oof beloethw r ea nl
Go![edit]
Copied from The 99 Bottles of Beer web site with a minor bug fix.
--
-- 99 Bottles of Beer in Go!
-- John Knottenbelt
--
-- Go! is a multi-paradigm programming language that is oriented
-- to the needs of programming secure, production quality, agent
-- based applications.
--
-- http://www.doc.ic.ac.uk/~klc/dalt03.html
--
main .. {
include "sys:go/io.gof".
include "sys:go/stdlib.gof".
main() ->
drink(99);
stdout.outLine("Time to buy some more beer...").
drink(0) -> {}.
drink(i) -> stdout.outLine(
bottles(i) <> " on the wall,\n" <>
bottles(i) <> ".\n" <>
"take one down, pass it around,\n" <>
bottles(i-1) <> " on the wall.\n");
drink(i-1).
bottles(0) => "no bottles of beer".
bottles(1) => "1 bottle of beer".
bottles(i) => i^0 <> " bottles of beer".
}Golfscript[edit]
[296,{3/)}%-1%["No more"]+[" bottles":b]294*[b-1<]2*+[b]+[" of beer on the wall\n".8<"\nTake one down, pass it around\n"+1$n+]99*]zipGolo[edit]
module Bottles
augment java.lang.Integer {
function bottles = |self| -> match {
when self == 0 then "No bottles"
when self == 1 then "One bottle"
otherwise self + " bottles"
}
}
function main = |args| {
99: downTo(1, |i| {
println(i: bottles() + " of beer on the wall,")
println(i: bottles() + " of beer!")
println("Take one down, pass it around,")
println((i - 1): bottles() + " of beer on the wall!")
println("--------------------------------------")
})
}
Gosu[edit]
for (i in 99..0) {
print("${i} bottles of beer on the wall")
if (i > 0) {
print("${i} bottles of beer")
print("Take one down, pass it around")
}
print("");
}
Groovy[edit]
Basic Solution[edit]
With a closure to handle special cardinalities of bottles.
def bottles = { "${it==0 ? 'No more' : it} bottle${it==1 ? '' : 's' }" }
99.downto(1) { i ->
print """
${bottles(i)} of beer on the wall
${bottles(i)} of beer
Take one down, pass it around
${bottles(i-1)} of beer on the wall
"""
}
Single Print Version[edit]
Uses a single print algorithm for all four lines. Handles cardinality on bottles, uses 'No more' instead of 0.
298.downto(2) {
def (m,d) = [it%3,(int)it/3]
print "${m==1?'\n':''}${d?:'No more'} bottle${d!=1?'s':''} of beer" +
"${m?' on the wall':'\nTake one down, pass it around'}\n"
}
Bottomless Beer Solution[edit]
Using more closures to create a richer lyrical experience.
def bottles = { "${it==0 ? 'No more' : it} bottle${it==1 ? '' : 's' }" }
def initialState = {
"""${result(it)}
${resultShort(it)}"""
}
def act = {
it > 0 ?
"Take ${it==1 ? 'it' : 'one'} down, pass it around" :
"Go to the store, buy some more"
}
def delta = { it > 0 ? -1 : 99 }
def resultShort = { "${bottles(it)} of beer" }
def result = { "${resultShort(it)} on the wall" }
// //// uncomment commented lines to create endless drunken binge //// //
// while (true) {
99.downto(0) { i ->
print """
${initialState(i)}
${act(i)}
${result(i+delta(i))}
"""
}
// Thread.sleep(1000)
// }
GUISS[edit]
We will just use the calculator and keep taking one off. We do not get the full text here, but the number of the calculator shows how many bottles we still have left to drink:
Start,Programs,Accessories,Calculator,Button:9,Button:9,
Button:[hyphen],Button:1,Button:[equals],Button:[hyphen],Button:1,Button:[equals],
Button:[hyphen],Button:1,Button:[equals],Button:[hyphen],Button:1,Button:[equals],
Button:[hyphen],Button:1,Button:[equals],Button:[hyphen],Button:1,Button:[equals],
Button:[hyphen],Button:1,Button:[equals],Button:[hyphen],Button:1,Button:[equals]We haven't drank all of the bottles at this point, but we can keep going, if we want.
Halon[edit]
$plural = "s";
$x = 99;
while ($x > 0) {
echo "$x bottle$plural of beer on the wall";
echo "$x bottle$plural of beer";
echo "Take one down, pass it around";
$x -= 1;
if ($x == 1)
$plural = "";
if ($x > 0)
echo "$x bottle$plural of beer on the wall\n";
else
echo "No more bottles of beer on the wall!";
}Haskell[edit]
Brevity[edit]
A relatively concise solution:
main = mapM_ (putStrLn . beer) [99, 98 .. 0]
beer 1 = "1 bottle of beer on the wall\n1 bottle of beer\nTake one down, pass it around"
beer 0 = "better go to the store and buy some more."
beer v = show v ++ " bottles of beer on the wall\n"
++ show v
++" bottles of beer\nTake one down, pass it around\n"
++ head (lines $ beer $ v-1) ++ "\n"
List comprehension[edit]
As a list comprehension:
import qualified Char
main = putStr $ concat
[up (bob n) ++ wall ++ ", " ++ bob n ++ ".\n" ++
pass n ++ bob (n - 1) ++ wall ++ ".\n\n" |
n <- [99, 98 .. 0]]
where bob n = (num n) ++ " bottle" ++ (s n) ++ " of beer"
wall = " on the wall"
pass 0 = "Go to the store and buy some more, "
pass _ = "Take one down and pass it around, "
up (x : xs) = Char.toUpper x : xs
num (-1) = "99"
num 0 = "no more"
num n = show n
s 1 = ""
s _ = "s"
Writer monad and Template Haskell[edit]
Another version, which uses a Writer monad to collect each part of the song. It also uses Template Haskell to generate the song at compile time.
{-# LANGUAGE TemplateHaskell #-}
-- build with "ghc --make beer.hs"
module Main where
import Language.Haskell.TH
import Control.Monad.Writer
-- This is calculated at compile time, and is equivalent to
-- songString = "99 bottles of beer on the wall\n99 bottles..."
songString =
$(let
sing = tell -- we can't sing very well...
someBottles 1 = "1 bottle of beer "
someBottles n = show n ++ " bottles of beer "
bottlesOfBeer n = (someBottles n ++)
verse n = do
sing $ n `bottlesOfBeer` "on the wall\n"
sing $ n `bottlesOfBeer` "\n"
sing $ "Take one down, pass it around\n"
sing $ (n - 1) `bottlesOfBeer` "on the wall\n\n"
song = execWriter $ mapM_ verse [99,98..1]
in return $ LitE $ StringL $ song)
main = putStr songString
Avoiding append by spelling bottle backwards[edit]
Is there something just a little prickly and displeasing about (++) ? Monoid (<>) is less spiky, but neither is needed when 'bottle' is written backwards.
location, distribution, solution :: String
[location, distribution, solution] =
[ "on the wall",
"Take one down, pass it around",
"Better go to the store to buy some more"
]
incantation :: Int -> String
incantation n
| 0 == n = solution
| otherwise =
unlines
[ inventory n,
asset n,
distribution,
inventory $ pred n
]
inventory :: Int -> String
inventory = unwords . (: [location]) . asset
asset :: Int -> String
asset n =
let suffix n
| 1 == n = []
| otherwise = ['s']
in unwords
[show n, (reverse . concat) $ suffix n : ["elttob"]]
main :: IO ()
main = putStrLn $ unlines (incantation <$> [99, 98 .. 0])
Haxe[edit]
Simple solution[edit]
class RosettaDemo
{
static public function main()
{
singBottlesOfBeer(100);
}
static function singBottlesOfBeer(bottles : Int)
{
var plural : String = 's';
while (bottles >= 1)
{
Sys.println(bottles + " bottle" + plural + " of beer on the wall,");
Sys.println(bottles + " bottle" + plural + " of beer!");
Sys.println("Take one down, pass it around,");
if (bottles - 1 == 1)
{
plural = '';
}
if (bottles > 1)
{
Sys.println(bottles-1 + " bottle" + plural + " of beer on the wall!\n");
}
else
{
Sys.println("No more bottles of beer on the wall!");
}
bottles--;
}
}
}
Macro solution[edit]
All those counters, loops and conditinal blocks are pretty expensive in runtime compared to single print of fully inlined text of the song. Let's generate that print with macro.
class Bottles {
static public function main () : Void {
singBottlesOfBeer(100);
}
macro static public function singBottlesOfBeer (bottles:Int) {
var lines = [];
var s : String = 's';
var song : String = '';
while( bottles >= 1 ){
song += '$bottles bottle$s of beer on the wall,\n';
song += '$bottles bottle$s of beer!\n';
song += 'Take one down, pass it around,\n';
bottles --;
if( bottles > 1 ){
song += '$bottles bottles of beer on the wall!\n\n';
}else if( bottles == 1 ){
s = '';
song += '$bottles bottle of beer on the wall!\n\n';
}else{
song += 'No more bottles of beer on the wall!\n';
}
}
return macro Sys.print($v{song});
}
}
hexiscript[edit]
fun bottles amount beverage location
let bottle " bottles of "
if amount = 0; let amount "No more"
elif amount = 1; let bottle " bottle of "; endif
return amount + bottle + beverage + " " + location
endfun
fun take amount location
return "Take " + amount + " " + location
endfun
fun pass entity destination
return ", pass " + entity + " " + destination
endfun
let amount 99
while amount > 0
println bottles amount "beer" "on the wall"
println bottles amount "beer" ""
println take "one" "down" + pass "it" "around"
println bottles (--amount) "beer" "on the wall\n"
endwhileHicEst[edit]
DO x = 99, 1, -1
WRITE() x , "bottles of beer on the wall"
BEEP("T16 be be be bH bH bH be be be 2be ")
WRITE() x , "bottles of beer"
BEEP("2p f f f c c c 2f ")
WRITE() "take one down, pass it around"
BEEP("2p 2d d d 2p d d d 2d ")
WRITE() x , "bottles of beer on the wall"
BEEP("2p #A #A #A c c d #d #d #d 2#d 2p")
ENDDOHolyC[edit]
The default is 99 bottles, but it can be modified by the parameter.
U0 BottlesOfBeer (I64 initial=99) {
// This is made I64 rather than U64
// Because, a U64 would overflow
// At the end of the loop, thus it would loop forever (i-- would be 0-1 so it overflows and is always greater than or equal to 0)
I64 i = initial;
for (; i >= 0; i--) {
if (i == 1) {
// Just a string on it's own will pass it to an inbuilt HolyC function that puts it to terminal
"1 Bottle of Beer on the wall, 1 bottle of beer.\n";
"Take one down and pass it around, no more bottles of beer on the wall.\n";
} else if (i == 0) {
"No more bottles of beer on the wall, no more bottles of beer.\n";
"Go to the store and buy some more, 99 bottles of beer on the wall.\n";
} else {
"%d bottles of beer on the wall, %d bottles of beer.\n",i,i;
"Take one down and pass it around, %d bottle",(i-1);
// Only add the s if it's not 1
if ((i-1) != 1) {
"s";
}
" of beer on the wall.\n";
}
}
}
// Calls the function, which goes to the default parameters
BottlesOfBeer;Hoon[edit]
:- %say
|= [* * [bottles=_99 ~]]
:- %noun
^- wall
=/ output `(list tape)`~
|-
?: =(1 bottles)
%- flop
:- "1 bottle of beer on the wall"
:- "Take one down, pass it around"
:- "1 bottle of beer"
:- "1 bottle of beer on the wall"
output
%= $
bottles (dec bottles)
output
:- "{<bottles>} bottles of beer on the wall"
:- "Take one down, pass it around"
:- "{<bottles>} bottles of beer"
:- "{<bottles>} bottles of beer on the wall"
output
==Hope[edit]
El código es de Wolfgang Lohmann (wlohmann@informatik.uni-rostock.de)
dec app :( list ( char ) X list ( char )) -> list ( char ) ;
dec i2c : num -> char;
dec i2s : num -> list(char);
dec beer : num -> list(char);
--- app ( nil , w )
<= w ;
--- app (( a :: v ), w )
<=( a :: app ( v , w )) ;
--- i2c(0) <= '0';
--- i2c(1) <= '1';
--- i2c(2) <= '2';
--- i2c(3) <= '3';
--- i2c(4) <= '4';
--- i2c(5) <= '5';
--- i2c(6) <= '6';
--- i2c(7) <= '7';
--- i2c(8) <= '8';
--- i2c(9) <= '9';
--- i2s(x) <= if x < 10 then [i2c(x)] else
app(i2s(x div 10), i2s( x mod 10));
--- beer(x) <= if x = 1 then app( i2s(x),
" bottle of beer. No more beer on the wall.")
else app( app( app( app( app(
i2s(x),
" bottles of beer on the wall, "),
i2s(x)),
" bottles of beer. "),
"Take one down, pass it around. "),
beer(y))
where y== x-1;
HQ9+[edit]
See 99 Bottles of Beer/EsoLang
Huginn[edit]
#! /bin/sh
exec huginn --no-argv -E "${0}" "${@}"
#! huginn
import Algorithms as algo;
main() {
x = "{} bottle{} of beer on the wall,\n"
"{} bottle{} of beer.\n"
"Take one down, pass it around,\n"
"{} bottle{} of beer on the wall.\n\n";
for ( n : algo.range( 99, 0, -1 ) ) {
bot = n > 0 ? n : "No";
plu = n != 1 ? "s" : "";
print( x.format( bot, plu, bot, plu, n > 1 ? n - 1 : "No", n != 2 ? "s" : "" ) );
}
print(
"No bottles of beer on the wall,\n"
"No bottles of beer.\n"
"Go to the store, buy some more,\n"
"99 bottles of beer on the wall.\n"
);
return ( 0 );
}HyperTalk[edit]
El código es de Eric Carlson eric@bungdabba.com
on BeerSong99
BottlesOfBeer 99
end BeerSong99
on OutputBeerLyric beerString
if ( beerString is "<reset>" ) then
put empty into cd fld "beer song"
else
put beerString & return after cd fld "beer song"
end if
end OutputBeerLyric
on BottlesOfBeer bottleCount
put bottleCount into initialCount
OutputBeerLyric "<reset>"
repeat until ( bottleCount < 1 )
set cursor to busy -- let 'em know this might take a while
put BottleString(bottleCount) into currentString
OutputBeerLyric currentString && "of beer on the wall,"
OutputBeerLyric currentString && "of beer."
OutputBeerLyric "Take one down, and pass it around,"
subtract one from bottleCount
OutputBeerLyric BottleString(bottleCount) && "of beer on the wall." & return
end repeat
OutputBeerLyric "Go to the store and buy some more..."
OutputBeerLyric initialCount & " bottles of beer on the wall."
end BottlesOfBeer
function BottleString bottleCount
if ( bottleCount is 1 ) then
return "1 bottle"
else if ( bottleCount is 0 ) then
return "no more bottles"
else
return bottleCount && "bottles"
end if
end BottleStringIcon and Unicon[edit]
The default is 99 bottles, but you can change this on the command line for really long trips...
IDL[edit]
Pro bottles
for i=1,99 do begin
print, 100-i, " bottles of beer on the wall.", 100-i, $
" bottles of beer.", " Take one down, pass it around," , $
99-i, " bottles of beer on the wall."
endfor
End
Since in IDL "FOR"-loops are the embodiment of pure evil (see http://www.idlcoyote.com/tips/forloops.html and http://www.idlcoyote.com/tips/forloops2.html) there is also a loop free IDL way:
Pro bottles_noloop
b=(reverse(shift(sindgen(100),-1)))[1:99]
b2=reverse(sindgen(99))
wallT=replicate(' bottles of beer on the wall.', 100)
wallT2=replicate(' bottles of beer.', 100)
takeT=replicate('Take one down, pass it around,', 100)
print, b+wallT+string(10B)+b+wallT2+string(10B)+takeT+string(10B)+b2+wallT+string(10B)
End
I found the above example very helpful but overdone. This is a more simple version:
Pro bottles_noloop2
n_bottles=99
b1 = reverse(SINDGEN(n_bottles,START=1))
b2= reverse(SINDGEN(n_bottles))
wallT=replicate(' bottles of beer on the wall.', n_bottles)
wallT2=replicate(' bottles of beer.', n_bottles)
takeT=replicate('Take one down, pass it around,', n_bottles)
print, b1+wallT+string(10B)+b1+wallT2+string(10B)+takeT+string(10B)+b2+wallT+string(10B)
End
Idris[edit]
beerSong : Fin 100 -> String
beerSong x = verses x where
bottlesOfBeer : Fin n -> String
bottlesOfBeer fZ = "No more bottles of beer"
bottlesOfBeer (fS fZ) = "1 bottle of beer"
bottlesOfBeer k = (show (finToInteger k)) ++ " bottles of beer"
verse : Fin n -> String
verse fZ = ""
verse (fS n) =
(bottlesOfBeer (fS n)) ++ " on the wall,\n" ++
(bottlesOfBeer (fS n)) ++ "\n" ++
"Take one down, pass it around\n" ++
(bottlesOfBeer n) ++ " on the wall\n"
verses : Fin n -> String
verses fZ = ""
verses (fS n) = (verse (fS n)) ++ (verses n)
Inform 6[edit]
[ Bottles i;
if(i == 1) return "bottle";
return "bottles";
];
[ Beer i;
print i, " ", (string) Bottles(i), " of beer on the wall^";
print i, " ", (string) Bottles(i), " of beer^";
print "Take one down, pass it around^";
i--;
print i, " ", (string) Bottles(i), " of beer on the wall^^";
if(i ~= 0) Beer(i);
];
[ Main;
Beer(99);
];
Inform 7[edit]
Programmatic solution[edit]
Beer Hall is a room.
When play begins:
repeat with iteration running from 1 to 99:
let N be 100 - iteration;
say "[N] bottle[s] of beer on the wall[line break]";
say "[N] bottle[s] of beer[line break]";
say "Take one down, pass it around[line break]";
say "[N - 1] bottle[s] of beer on the wall[paragraph break]";
end the story.
World model solution[edit]
This solution uses in-game objects to represent the wall and the bottles.
Beer Hall is a room.
The plural of bottle of beer is bottles of beer. A bottle of beer is a kind of thing.
The wall is a scenery supporter in Beer Hall. 99 bottles of beer are on the wall.
When play begins:
while something is on the wall:
say "[what's on the wall] on the wall[line break]";
say "[what's on the wall][line break]";
say "Take one down, pass it around[line break]";
remove a random thing on the wall from play;
say "[what's on the wall] on the wall[paragraph break]";
end the story.
To say what's on the wall:
if more than one thing is on the wall, say list of things on the wall;
otherwise say "[number of things on the wall in words] bottle[s] of beer".
Io[edit]
bottles := method(i,
if(i==0, return "no more bottles of beer")
if(i==1, return "1 bottle of beer")
"" .. i .. " bottles of beer"
)
for(i, 99, 1, -1,
write(
bottles(i), " on the wall, ",
bottles(i), ",\n",
"take one down, pass it around,\n",
bottles(i - 1), " on the wall.\n\n"
)
)
Intercal[edit]
PLEASE DO ,10 <- #1
PLEASE DO ,10SUB#1 <- #176
PLEASE DO ,11 <- #30
PLEASE DO ,11SUB#1 <- #76
DO ,11SUB#2 <- #190
DO ,11SUB#3 <- #80
DO ,11SUB#4 <- #200
PLEASE DO ,11SUB#5 <- #256
DO ,11SUB#6 <- #248
DO ,11SUB#7 <- #144
DO ,11SUB#8 <- #216
PLEASE DO ,11SUB#9 <- #202
DO ,11SUB#10 <- #14
DO ,11SUB#11 <- #144
DO ,11SUB#12 <- #98
PLEASE DO ,11SUB#13 <- #190
DO ,11SUB#14 <- #160
DO ,11SUB#15 <- #256
DO ,11SUB#16 <- #88
PLEASE DO ,11SUB#17 <- #74
DO ,11SUB#18 <- #14
DO ,11SUB#19 <- #128
DO ,11SUB#20 <- #114
PLEASE DO ,11SUB#21 <- #214
DO ,11SUB#22 <- #24
DO ,11SUB#23 <- #112
DO ,11SUB#24 <- #162
PLEASE DO ,11SUB#25 <- #22
DO ,11SUB#26 <- #104
DO ,11SUB#27 <- #80
DO ,11SUB#28 <- #256
PLEASE DO ,11SUB#29 <- #2
DO ,11SUB#30 <- #228
PLEASE DO ,12 <- #49
PLEASE DO ,12SUB#1 <- #76
DO ,12SUB#2 <- #190
DO ,12SUB#3 <- #80
DO ,12SUB#4 <- #200
PLEASE DO ,12SUB#5 <- #256
DO ,12SUB#6 <- #248
DO ,12SUB#7 <- #144
DO ,12SUB#8 <- #216
PLEASE DO ,12SUB#9 <- #202
DO ,12SUB#10 <- #14
DO ,12SUB#11 <- #144
DO ,12SUB#12 <- #98
PLEASE DO ,12SUB#13 <- #190
DO ,12SUB#14 <- #160
DO ,12SUB#15 <- #256
DO ,12SUB#16 <- #88
PLEASE DO ,12SUB#17 <- #218
DO ,12SUB#18 <- #36
DO ,12SUB#19 <- #38
DO ,12SUB#20 <- #164
PLEASE DO ,12SUB#21 <- #176
DO ,12SUB#22 <- #48
DO ,12SUB#23 <- #162
DO ,12SUB#24 <- #14
PLEASE DO ,12SUB#25 <- #128
DO ,12SUB#26 <- #208
DO ,12SUB#27 <- #162
DO ,12SUB#28 <- #222
PLEASE DO ,12SUB#29 <- #48
DO ,12SUB#30 <- #8
DO ,12SUB#31 <- #120
DO ,12SUB#32 <- #66
PLEASE DO ,12SUB#33 <- #48
DO ,12SUB#34 <- #246
DO ,12SUB#35 <- #136
DO ,12SUB#36 <- #184
PLEASE DO ,12SUB#37 <- #256
DO ,12SUB#38 <- #202
DO ,12SUB#39 <- #110
DO ,12SUB#40 <- #104
PLEASE DO ,12SUB#41 <- #42
DO ,12SUB#42 <- #126
DO ,12SUB#43 <- #56
DO ,12SUB#44 <- #88
PLEASE DO ,12SUB#45 <- #72
DO ,12SUB#46 <- #56
DO ,12SUB#47 <- #80
DO ,12SUB#48 <- #242
PLEASE DO ,12SUB#49 <- #228
PLEASE DO ,13 <- #31
PLEASE DO ,13SUB#1 <- #76
DO ,13SUB#2 <- #190
DO ,13SUB#3 <- #80
DO ,13SUB#4 <- #200
PLEASE DO ,13SUB#5 <- #256
DO ,13SUB#6 <- #248
DO ,13SUB#7 <- #144
DO ,13SUB#8 <- #216
PLEASE DO ,13SUB#9 <- #202
DO ,13SUB#10 <- #14
DO ,13SUB#11 <- #144
DO ,13SUB#12 <- #98
PLEASE DO ,13SUB#13 <- #190
DO ,13SUB#14 <- #160
DO ,13SUB#15 <- #256
DO ,13SUB#16 <- #88
PLEASE DO ,13SUB#17 <- #74
DO ,13SUB#18 <- #14
DO ,13SUB#19 <- #128
DO ,13SUB#20 <- #114
PLEASE DO ,13SUB#21 <- #214
DO ,13SUB#22 <- #24
DO ,13SUB#23 <- #112
DO ,13SUB#24 <- #162
PLEASE DO ,13SUB#25 <- #22
DO ,13SUB#26 <- #104
DO ,13SUB#27 <- #80
DO ,13SUB#28 <- #256
PLEASE DO ,13SUB#29 <- #194
DO ,13SUB#30 <- #36
DO ,13SUB#31 <- #256
PLEASE DO ,20 <- #10
PLEASE DO ,20 SUB #1 <- #76
DO ,20 SUB #2 <- #196
DO ,20 SUB #3 <- #4
DO ,20 SUB #4 <- #132
PLEASE DO ,20 SUB #5 <- #36
DO ,20 SUB #6 <- #164
DO ,20 SUB #7 <- #228
DO ,20 SUB #8 <- #100
PLEASE DO ,20 SUB #9 <- #52
DO ,20 SUB #10 <- #180
PLEASE DO ,21 <- #10 BY #10
PLEASE DO ,21SUB#1#1 <- #248
PLEASE DO ,21SUB#1#2 <- #120
PLEASE DO ,21SUB#1#3 <- #184
PLEASE DO ,21SUB#1#4 <- #56
PLEASE DO ,21SUB#1#5 <- #216
PLEASE DO ,21SUB#1#6 <- #88
PLEASE DO ,21SUB#1#7 <- #152
PLEASE DO ,21SUB#1#8 <- #24
PLEASE DO ,21SUB#1#9 <- #232
PLEASE DO ,21SUB#1#10 <- #104
DO ,21SUB#2#1 <- #128
DO ,21SUB#2#2 <- #256
DO ,21SUB#2#3 <- #64
DO ,21SUB#2#4 <- #192
DO ,21SUB#2#5 <- #96
DO ,21SUB#2#6 <- #224
DO ,21SUB#2#7 <- #32
DO ,21SUB#2#8 <- #160
DO ,21SUB#2#9 <- #112
DO ,21SUB#2#10 <- #240
DO ,21SUB#3#1 <- #64
DO ,21SUB#3#2 <- #192
DO ,21SUB#3#3 <- #256
DO ,21SUB#3#4 <- #128
DO ,21SUB#3#5 <- #32
DO ,21SUB#3#6 <- #160
DO ,21SUB#3#7 <- #224
DO ,21SUB#3#8 <- #96
DO ,21SUB#3#9 <- #48
DO ,21SUB#3#10 <- #176
DO ,21SUB#4#1 <- #192
DO ,21SUB#4#2 <- #64
DO ,21SUB#4#3 <- #128
DO ,21SUB#4#4 <- #256
DO ,21SUB#4#5 <- #160
DO ,21SUB#4#6 <- #32
DO ,21SUB#4#7 <- #96
DO ,21SUB#4#8 <- #224
DO ,21SUB#4#9 <- #176
DO ,21SUB#4#10 <- #48
PLEASE DO ,21SUB#5#1 <- #32
PLEASE DO ,21SUB#5#2 <- #160
PLEASE DO ,21SUB#5#3 <- #224
PLEASE DO ,21SUB#5#4 <- #96
PLEASE DO ,21SUB#5#5 <- #256
PLEASE DO ,21SUB#5#6 <- #128
PLEASE DO ,21SUB#5#7 <- #192
PLEASE DO ,21SUB#5#8 <- #64
PLEASE DO ,21SUB#5#9 <- #16
PLEASE DO ,21SUB#5#10 <- #144
DO ,21SUB#6#1 <- #160
DO ,21SUB#6#2 <- #32
DO ,21SUB#6#3 <- #96
DO ,21SUB#6#4 <- #224
DO ,21SUB#6#5 <- #128
DO ,21SUB#6#6 <- #256
DO ,21SUB#6#7 <- #64
DO ,21SUB#6#8 <- #192
DO ,21SUB#6#9 <- #144
DO ,21SUB#6#10 <- #16
DO ,21SUB#7#1 <- #96
DO ,21SUB#7#2 <- #224
DO ,21SUB#7#3 <- #32
DO ,21SUB#7#4 <- #160
DO ,21SUB#7#5 <- #64
DO ,21SUB#7#6 <- #192
DO ,21SUB#7#7 <- #256
DO ,21SUB#7#8 <- #128
DO ,21SUB#7#9 <- #80
DO ,21SUB#7#10 <- #208
DO ,21SUB#8#1 <- #224
DO ,21SUB#8#2 <- #96
DO ,21SUB#8#3 <- #160
DO ,21SUB#8#4 <- #32
DO ,21SUB#8#5 <- #192
DO ,21SUB#8#6 <- #64
DO ,21SUB#8#7 <- #128
DO ,21SUB#8#8 <- #256
DO ,21SUB#8#9 <- #208
DO ,21SUB#8#10 <- #80
PLEASE DO ,21SUB#9#1 <- #16
PLEASE DO ,21SUB#9#2 <- #144
PLEASE DO ,21SUB#9#3 <- #208
PLEASE DO ,21SUB#9#4 <- #80
PLEASE DO ,21SUB#9#5 <- #240
PLEASE DO ,21SUB#9#6 <- #112
PLEASE DO ,21SUB#9#7 <- #176
PLEASE DO ,21SUB#9#8 <- #48
PLEASE DO ,21SUB#9#9 <- #256
PLEASE DO ,21SUB#9#10 <- #128
DO ,21SUB#10#1 <- #144
DO ,21SUB#10#2 <- #16
DO ,21SUB#10#3 <- #80
DO ,21SUB#10#4 <- #208
DO ,21SUB#10#5 <- #112
DO ,21SUB#10#6 <- #240
DO ,21SUB#10#7 <- #48
DO ,21SUB#10#8 <- #176
DO ,21SUB#10#9 <- #128
DO ,21SUB#10#10 <- #256
PLEASE DO ,22 <- #10
PLEASE DO ,22 SUB #1 <- #8
DO ,22 SUB #2 <- #136
DO ,22 SUB #3 <- #72
DO ,22 SUB #4 <- #200
PLEASE DO ,22 SUB #5 <- #40
DO ,22 SUB #6 <- #168
DO ,22 SUB #7 <- #104
DO ,22 SUB #8 <- #232
PLEASE DO ,22 SUB #9 <- #24
DO ,22 SUB #10 <- #152
DO .10 <- #9
DO .11 <- #9
PLEASE DO ,10 <- #1
PLEASE DO ,10SUB#1 <- #176
DO READ OUT ,10
DO COME FROM (999)
DO (500) NEXT
PLEASE DO ,11SUB#1 <- .5
DO READ OUT ,11
DO (500) NEXT
DO ,12SUB#1 <- .5
PLEASE DO READ OUT ,12
PLEASE DO .6 <- '?"!10~.10'~#1"$#1'~#3
DO (50) NEXT
PLEASE DO .7 <- '?"!11~.11'~#1"$#1'~#3
DO (70) NEXT
DO .2 <- #1
DO .1 <- .11
PLEASE DO (1010) NEXT
DO .11 <- .3
DO (600) NEXT
DO (101) NEXT
(70) DO (71) NEXT
DO .11 <- #9
DO .2 <- #1
PLEASE DO .1 <- .10
DO (1010) NEXT
DO .10 <- .3
DO (600) NEXT
DO (101) NEXT
(71) DO RESUME .7
(50) DO (51) NEXT
PLEASE DO FORGET #1
DO .2 <- #1
DO .1 <- .11
PLEASE DO (1010) NEXT
DO .11 <- .3
DO (600) NEXT
PLEASE DO .7 <- '?"!11~.11'~#1"$#1'~#3
DO (80) NEXT
DO (101) NEXT
(80) DO (81) NEXT
DO GIVE UP
(81) DO RESUME .7
(51) DO RESUME .6
(101) DO FORGET #1
(999) DO FORGET #1
(600) DO (500) NEXT
DO ,13SUB#1 <- .5
DO READ OUT ,13
DO RESUME #1
(500) DO ,30 <- #1
DO .1 <- .10
DO (1020) NEXT
PLEASE DO ,30SUB#1 <- ,20SUB.1
DO READ OUT ,30
DO .3 <- .1
DO .1 <- .11
DO (1020) NEXT
PLEASE DO ,30SUB#1 <- ,21SUB .3 .1
DO READ OUT ,30
DO .5 <- ,22SUB.1
PLEASE DO RESUME #1Ioke[edit]
bottle = method(i,
case(i,
0, "no more bottles of beer",
1, "1 bottle of beer",
"#{i} bottles of beer"))
(99..1) each(i,
"#{bottle(i)} on the wall, " println
"take one down, pass it around," println
"#{bottle(i - 1)} on the wall.\n" println
)
J[edit]
As posted at the J wiki
bob =: ": , ' bottle' , (1 = ]) }. 's of beer'"_
bobw=: bob , ' on the wall'"_
beer=: bobw , ', ' , bob , '; take one down and pass it around, ' , bobw@<:
beer"0 >:i.-99
- Output:
99 bottles of beer on the wall, 99 bottles of beer; take one down and pass it around, 98 bottles of beer on the wall 98 bottles of beer on the wall, 98 bottles of beer; take one down and pass it around, 97 bottles of beer on the wall ... 3 bottles of beer on the wall, 3 bottles of beer; take one down and pass it around, 2 bottles of beer on the wall 2 bottles of beer on the wall, 2 bottles of beer; take one down and pass it around, 1 bottle of beer on the wall 1 bottle of beer on the wall, 1 bottle of beer; take one down and pass it around, 0 bottles of beer on the wall
Jakt[edit]
fn bottle_string(bottle_count: i64) throws -> String => match bottle_count {
0 => "No more bottles"
1 => "1 bottle"
else => format("{} bottles", bottle_count)
}
fn main() {
mut bottle_count = 99
while bottle_count > 0 {
println("{} of beer on the wall", bottle_string(bottle_count))
println("{} of beer", bottle_string(bottle_count))
println("Take one down, pass it around")
bottle_count--
println("{} of beer on the wall", bottle_string(bottle_count))
if bottle_count > 0 {
println("")
}
}
}Janet[edit]
(defn bottles [n]
(match n
0 "No more bottles"
1 "1 bottle"
_ (string n " bottles")))
(loop [i :down [99 0]]
(print
(bottles i) " of beer on the wall\n"
(bottles i) " of beer\nTake one down, pass it around\n"
(bottles (- i 1)) " of beer on the wall\n\n"))Java[edit]
Console[edit]
MessageFormat's choice operator is used to properly format plurals.
import java.text.MessageFormat;
public class Beer {
static String bottles(int n) {
return MessageFormat.format("{0,choice,0#No more bottles|1#One bottle|2#{0} bottles} of beer", n);
}
public static void main(String[] args) {
String bottles = bottles(99);
for (int n = 99; n > 0; ) {
System.out.println(bottles + " on the wall");
System.out.println(bottles);
System.out.println("Take one down, pass it around");
bottles = bottles(--n);
System.out.println(bottles + " on the wall");
System.out.println();
}
}
}
Optimized for speed and few I/O operations
public class Beer {
public static void main(String[] args) {
int bottles = 99;
StringBuilder sb = new StringBuilder();
String verse1 = " bottles of beer on the wall\n";
String verse2 = " bottles of beer.\nTake one down, pass it around,\n";
String verse3 = "Better go to the store and buy some more.";
while (bottles > 0)
sb.append(bottles).append(verse1).append(bottles).append(verse2).append(--bottles).append(verse1).append("\n");
System.out.println(sb.append(verse3));
}
}
Recursive
public class Beer {
public static void main(String args[]) {
song(99);
}
public static void song(int bottles) {
if (bottles >= 0) {
if (bottles > 1)
System.out.println(bottles + " bottles of beer on the wall\n" + bottles + " bottles of beer\nTake one down, pass it around\n" + (bottles - 1) + " bottles of beer on the wall.\n");
else if (bottles == 1)
System.out.println(bottles + " bottle of beer on the wall\n" + bottles + " bottle of beer\nTake one down, pass it around\n" + (bottles - 1) + " bottles of beer on the wall.\n");
else
System.out.println(bottles + " bottles of beer on the wall\n" + bottles + " bottles of beer\nBetter go to the store and buy some more!");
song(bottles - 1);
}
}
}
An object-oriented solution[edit]
See: 99 Bottles of Beer/Java/Object Oriented
GUI[edit]
This version requires user interaction. The first two lines are shown in a text area on a window. The third line is shown on a button which you need to click to see the fourth line in a message box. The numbers update and the process repeats until "0 bottles of beer on the wall" is shown in a message box, when the program ends.
import java.awt.BorderLayout;
import java.awt.event.ActionEvent;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JOptionPane;
import javax.swing.JTextArea;
public class Beer extends JFrame {
private int x;
private JTextArea text;
public static void main(String[] args) {
new Beer().setVisible(true);
}
public Beer() {
x = 99;
JButton take = new JButton("Take one down, pass it around");
take.addActionListener(this::onTakeClick);
text = new JTextArea(4, 30);
text.setText(x + " bottles of beer on the wall\n" + x + " bottles of beer");
text.setEditable(false);
setLayout(new BorderLayout());
add(text, BorderLayout.CENTER);
add(take, BorderLayout.PAGE_END);
pack();
setLocationRelativeTo(null);
setDefaultCloseOperation(JFrame.DISPOSE_ON_CLOSE);
}
private void onTakeClick(ActionEvent event) {
JOptionPane.showMessageDialog(null, --x + " bottles of beer on the wall");
text.setText(x + " bottles of beer on the wall\n" + x + " bottles of beer");
if (x == 0) {
dispose();
}
}
}
JavaScript[edit]
ES3-5[edit]
var beer = 99;
while (beer > 0) {
var verse = [
beer + " bottles of beer on the wall,",
beer + " bottles of beer!",
"Take one down, pass it around",
(beer - 1) + " bottles of beer on the wall!"
].join("\n");
console.log(verse);
beer--;
}
ES6[edit]
let beer = 99;
while (beer > 0) {
let verse = `${beer} bottles of beer on the wall,
${beer} bottles of beer!
Take one down, pass it around
${beer-1} bottles of beer on the wall`;
console.log(verse);
beer--;
}
Functional / Recursive[edit]
var bottles = 99;
var songTemplate = "{X} bottles of beer on the wall \n" +
"{X} bottles of beer \n"+
"Take one down, pass it around \n"+
"{X-1} bottles of beer on the wall \n";
function song(x, txt) {
return txt.replace(/\{X\}/gi, x).replace(/\{X-1\}/gi, x-1) + (x > 1 ? song(x-1, txt) : "");
}
console.log(song(bottles, songTemplate));
Other Examples[edit]
More skilled solution "one-liner" with grammar check
Comment: This being a "one-liner" is arguable. The author has chosen not to put a line break after the declaration of the beer variable. By using the authors definition, most of the other solutions could pass as a "one-liner".
// Line breaks are in HTML
var beer; while ((beer = typeof beer === "undefined" ? 99 : beer) > 0) document.write( beer + " bottle" + (beer != 1 ? "s" : "") + " of beer on the wall<br>" + beer + " bottle" + (beer != 1 ? "s" : "") + " of beer<br>Take one down, pass it around<br>" + (--beer) + " bottle" + (beer != 1 ? "s" : "") + " of beer on the wall<br>" );
Legitimate "one-liner" with grammar check, using declarative methods.
Array.from(Array(100).keys()).splice(1).reverse().forEach(n => console.log(`${n} bottle${n !== 1 ? 's' : ''} of beer on the wall\n${n} bottle${n !== 1 ? 's' : ''} of beer\nTake one down, pass it around\n${n - 1} bottle${n - 1 !== 1 ? 's' : ''} of beer on the wall\n\n`));
Object Oriented
function Bottles(count) {
this.count = count || 99;
}
Bottles.prototype.take = function() {
var verse = [
this.count + " bottles of beer on the wall,",
this.count + " bottles of beer!",
"Take one down, pass it around",
(this.count - 1) + " bottles of beer on the wall!"
].join("\n");
console.log(verse);
this.count--;
};
Bottles.prototype.sing = function() {
while (this.count) {
this.take();
}
};
var bar = new Bottles(99);
bar.sing();
An alternative version:
function bottleSong(n) {
if (!isFinite(Number(n)) || n == 0) n = 100;
var a = '%% bottles of beer',
b = ' on the wall',
c = 'Take one down, pass it around',
r = '<br>'
p = document.createElement('p'),
s = [],
re = /%%/g;
while(n) {
s.push((a+b+r+a+r+c+r).replace(re, n) + (a+b).replace(re, --n));
}
p.innerHTML = s.join(r+r);
document.body.appendChild(p);
}
window.onload = bottleSong;
Joy[edit]
LIBRA
_beerlib == true;
HIDE
beer == "of beer " putchars;
wall == "on the wall" putchars;
take1 == "Take one down and pass it around, " putchars;
dup3 == dup dup dup;
comma == ", " putchars;
period == ". " putchars;
bottles == [small]
[[null] [pop "no more bottles " putchars] [put "bottle " putchars] ifte]
[put "bottles " putchars] ifte;
sing-verse == dup3 bottles beer wall comma
bottles beer ".\n" putchars
take1 pred bottles beer wall period newline newline;
sing-verse-0 == "No more bottles of beer on the wall, no more bottles of beer\n" putchars
"Go to the store and buy some more, " putchars
99 bottles pop beer wall period newline
IN
(* n -- *)
sing-verses == [null]
[sing-verse-0]
[sing-verse pred] tailrec
END.
99 sing-verses.jq[edit]
Minimalist:
99
| (. - range(0;.+1) )
| "
\(.) bottles of beer on the wall
\(.) bottles of beer
Take one down, pass it around
\(.) bottles of beer on the wall"- Output:
$ jq -n -r -f 99_bottles.jq
...
2 bottles of beer on the wall
2 bottles of beer
Take one down, pass it around
2 bottles of beer on the wall
1 bottles of beer on the wall
1 bottles of beer
Take one down, pass it around
1 bottles of beer on the wall
0 bottles of beer on the wall
0 bottles of beer
Take one down, pass it around
0 bottles of beer on the wall
Variant:
def sing:
def s: if . == 1 then "" else "s" end;
def bottles:
if . == 0 then "No more"
else "\(.)"
end + " bottle\(s)";
(. - range(0;.+1) )
| "
\(bottles) of beer on the wall
\(bottles) of beer
Take one down, pass it around
\(bottles) of beer on the wall."
;
$bottles | tonumber | sing- Output:
$ jq -r --arg bottles 99 -f 99_bottles_variant.jq
...
2 bottles of beer on the wall
2 bottles of beer
Take one down, pass it around
2 bottles of beer on the wall.
1 bottle of beer on the wall
1 bottle of beer
Take one down, pass it around
1 bottle of beer on the wall.
No more bottles of beer on the wall
No more bottles of beer
Take one down, pass it around
No more bottles of beer on the wall.
Jsish[edit]
/* 99 Bottles, in Jsish */
function plural(n:number):string { return (bottles == 1) ? "" : "s"; }
function no(n:number):string { return (bottles == 0) ? "No" : n.toString(); }
var bottles = 99;
do {
printf("%d bottle%s of beer on the wall\n", bottles, plural(bottles));
printf("%d bottle%s of beer\n", bottles, plural(bottles));
puts("Take one down, pass it around");
bottles--;
printf("%s bottle%s of beer on the wall\n\n", no(bottles), plural(bottles));
} while (bottles > 0);Julia[edit]
one-liner
for i = 99:-1:1 print("\n$i bottles of beer on the wall\n$i bottles of beer\nTake one down, pass it around\n$(i-1) bottles of beer on the wall\n") end
another solution, handling grammar cases "No more bottles", "1 bottle", "<n> bottles"
bottles(n) = n==0 ? "No more bottles" :
n==1 ? "1 bottle" :
"$n bottles"
for n = 99:-1:1
println("""
$(bottles(n)) of beer on the wall
$(bottles(n)) of beer
Take one down, pass it around
$(bottles(n-1)) of beer on the wall
""")
end
shorter, but more cryptic, version of the previous `bottles` function
bottles(n) = "$(n==0 ? "No more" : n) bottle$(n==1 ? "" : "s")"
K[edit]
`0:\:{x[z],y,a,x[z],a,"Take one down, pass it around",a,x[z-1],y,a,a:"\n"}[{($x)," bottle",:[x=1;"";"s"]," of beer"};" on the wall"]'|1_!100Kabap[edit]
// Loop that spits lyrics to "99 Bottles of Beer"
$n = 99;
$out = "";
:loop;
$out = $out << $n << " bottles of beer on the wall, " << $n << " bottles of beer. Take one down, pass it around, " << $n - 1 << " bottles of beer on the wall… ";
$n = $n - 1;
if $n > 0;
goto loop;
return = $out;Kitten[edit]
99 bottles_of_beer_on_the_wall
define bottles_of_beer_on_the_wall (Int32 -> +IO):
-> n;
n th_verse
if (n > 1): (n - 1) bottles_of_beer_on_the_wall
define th_verse (Int32 -> +IO):
-> n;
n bottles_of_beer on_the_wall say
n bottles_of_beer say
take_one_down_pass_it_around say
(n - 1) bottles_of_beer on_the_wall say
newline
define bottles_of_beer (Int32 -> List<Char>):
bottles " of beer" cat
define on_the_wall (List<Char> -> List<Char>):
" on the wall" cat
define take_one_down_pass_it_around (-> List<Char>):
"take one down, pass it around"
define bottles (Int32 -> List<Char>):
-> n;
if (n = 0):
"no more bottles"
elif (n = 1):
"one bottle"
else:
n show " bottles" catKlingphix[edit]
include ..\Utilitys.tlhy
:bottles
dup 0 ==
(
["no more bottles of beer"]
[ dup 1 ==
(
["1 bottle of beer"]
[dup tostr " bottles of beer" chain]
) if
]
) if
;
( 99 1 -1 )
[ bottles print " on the wall," ?
bottles "," chain ?
"take one down, pass it around," ?
1 - bottles print " on the wall." ? nl
drop] for
" " input
Klong[edit]
bottles::{:[x=1;"bottle";"bottles"]}
itone::{:[x=1;"it";"one"]}
numno::{:[x=0;"no";x]}
drink::{.d(numno(x));
.d(" ");
.d(bottles(x));
.p(" of beer on the wall");
.d(numno(x));
.d(" ");
.d(bottles(x));
.p(" of beer");
.d("take ");
.d(itone(x));
.p(" down and pass it round");
.d(numno(x-1));
.d(" ");
.d(bottles(x-1));
.p(" of beer on the wall");.p("")}
drink'1+|!99Kotlin[edit]
fun main(args: Array<String>) {
for (i in 99.downTo(1)) {
println("$i bottles of beer on the wall")
println("$i bottles of beer")
println("Take one down, pass it around")
}
println("No more bottles of beer on the wall!")
}
LabVIEW[edit]
Lambda Prolog[edit]
The signature file:
sig bottles.
type println string -> o.
type round int -> o.
type bottles_song int -> o.The module file:
module bottles.
println Str :- print Str, print "\n".
round N :- M is N - 1,
NStr is int_to_string N,
MStr is int_to_string M,
BOB = " bottles of beer ",
Line1 is NStr ^ BOB ^ "on the wall",
Line2 is NStr ^ BOB,
Line3 is "take one down, pass it around",
Line4 is MStr ^ BOB ^ "on the wall",
println Line1,
println Line2,
println Line3,
println Line4.
bottles_song 0.
bottles_song N :- N > 0,
round N,
M is N - 1,
bottles_song M.Then we produce the desired output by setting the system to solve for this goal:
[bottles] ?- bottles_song 99.Lambdatalk[edit]
{def beer
{lambda {:i}
{br}:i bottles of beer on the wall
{br}:i bottles of beer
{br}Take one down, pass it around
{br}{- :i 1} bottles of beer on the wall
{br}
}}
{S.map beer {S.serie 99 98 -1}}
...
{S.map beer {S.serie 2 1 -1}}
->
99 bottles of beer on the wall
99 bottles of beer
Take one down, pass it around
98 bottles of beer on the wall
98 bottles of beer on the wall
98 bottles of beer
Take one down, pass it around
97 bottles of beer on the wall
...
2 bottles of beer on the wall
2 bottles of beer
Take one down, pass it around
1 bottles of beer on the wall
1 bottles of beer on the wall
1 bottles of beer
Take one down, pass it around
0 bottles of beer on the wall
Lang[edit]
$i = 99
until($i == 0) {
fn.println($i bottles of beer on the wall)
fn.println($i bottles of beer)
fn.println(Take one down, pass it around)
$i -= 1
if($i > 0) {
fn.println($i bottles of beer)
fn.println()
}else {
fn.println(No more bottles of beer on the wall)
}
}lang5[edit]
: ~ 2 compress "" join ;
: verses(*)
dup " bottles of beer on the wall\n" ~ .
dup " bottles of beer\n" ~ .
"Take one down, pass it around\n" .
1 - " bottles of beer on the wall\n\n" ~ .
;
99 iota 1 + reverse versesLasso[edit]
Simple loop[edit]
local(
beer = 99,
song = ''
)
while(#beer > 0) => {
#song->append(
#beer + ' bottles of beer on the wall\n' +
#beer + ' bottles of beer\n' +
'Take one down, pass it around\n' +
(#beer-1) + ' bottles of beer on the wall\n\n'
)
#beer--
}
#song
Query Expression[edit]
(with beer in 99 to 1 by -1 select
#beer + ' bottles of beer on the wall' +
#beer + ' bottles of beer\n' +
'Take one down, pass it around\n' +
--#beer + ' bottles of beer on the wall\n'
)->join('\n')
Query Expression with Autocollect[edit]
// this example adds an "s" to bottle until there is only 1 bottle left on the wall
local(s = 's')
with n in 99 to 1 by -1 do {^
#n + ' bottle' + #s + ' of beer on the wall,<br>'
#n + ' bottle' + #s + ' of beer,<br>'
#n = #n - 1
#s = (#n != 1 ? 's' | '')
'Take one down, pass it around,<br>'
#n + ' bottle' + #s + ' of beer on the wall.<br><br>'
^}
LaTeX[edit]
Recursive[edit]
\documentclass{minimal}
\newcounter{beer}
\newcommand{\verses}[1]{
\setcounter{beer}{#1}
\par\noindent
\arabic{beer} bottles of beer on the wall,\\
\arabic{beer} bottles of beer!\\
Take one down, pass it around---\\
\addtocounter{beer}{-1}
\arabic{beer} bottles of beer on the wall!\\
\ifnum#1>0
\verses{\value{beer}}
\fi
}
\begin{document}
\verses{99}
\end{document}
Iterative[edit]
The \loop macro is tail-recursive (Knuth 1984, page 219). Just for fun, this version uses Roman numerals.
\documentclass{minimal}
\newcounter{beer}
\newcounter{showC}
\newcommand{\verses}[1]{
\setcounter{beer}{#1}
\loop
\par\noindent
\Roman{beer} bottles of beer on the wall,\\
\Roman{beer} bottles of beer!\\
Take one down, pass it around---\\
\addtocounter{beer}{-1}
% Romans didn't know how to write zero ;-)
\ifnum\value{beer}=0 ZERO \else\Roman{beer} \fi
bottles of beer on the wall!\\
\ifnum\value{beer}>0
\repeat
}
\begin{document}
\verses{99}
\end{document}
References[edit]
- Knuth, Donald E. (1984). The TeXbook, Addison Wesley.
LDPL[edit]
DATA:
bottles-in-the-wall is number
plural is text
PROCEDURE:
store 99 in bottles-in-the-wall
sub-procedure check-plural
if bottles-in-the-wall is not equal to 1 then
store "s" in plural
else
store "" in plural
end if
end sub-procedure
while bottles-in-the-wall is greater than 0 do
call sub-procedure check-plural
display bottles-in-the-wall " bottle" plural " of beer on the wall," crlf
display bottles-in-the-wall " bottle" plural " of beer." crlf
display "Take one down, pass it around," crlf
subtract 1 from bottles-in-the-wall in bottles-in-the-wall
call sub-procedure check-plural
if bottles-in-the-wall is greater than 0 then
display bottles-in-the-wall " bottle" plural " of beer on the wall." crlf crlf
else
display "No bottles of beer on the wall." crlf
end if
repeatLhogho[edit]
to bottle :i
if :i = 0 [output "|No more bottles of beer|]
if :i = 1 [output "|One bottle of beer|]
output word :i "| bottles of beer|
end
to it_one :n
if :n = 1 [output "it][output "one]
end
to verse :i
(print bottle :i "| on the wall,|)
(print word bottle :i ".)
(print "Take it_one :i "|down, pass it round|)
(print bottle :i - 1 "| on the wall.|)
print
end
to sing :i
if :i = 0
[
print "|No more bottles of beer on the wall,
No more bottles of beer.
Go to the store and buy some more.
99 bottles of beer on the wall.|
stop
]
verse :i
sing :i - 1
end
;Using it:
sing 99Limbo[edit]
implement Beer;
include "sys.m";
include "draw.m";
sys: Sys;
Beer : module
{
init : fn(ctxt : ref Draw->Context, args : list of string);
};
init (ctxt: ref Draw->Context, args: list of string)
{
sys = load Sys Sys->PATH;
beers := 99;
for (; beers > 1; --beers) {
sys->print("%d bottles of beer on the wall\n", beers);
sys->print("%d bottles of beer\n", beers);
sys->print("Take one down, pass it around,\n");
sys->print("%d bottles of beer on the wall\n\n", beers-1);
};
sys->print("1 bottle of beer on the wall\n1 bottle of beer\n");
sys->print("Take it down, pass it around\nand nothing is left!\n\n");
}
Lingo[edit]
repeat with i = 99 down to 2
put i & " bottles of beer on the wall"
put i & " bottles of beer"
put "Take one down, pass it around"
put (i-1) & " bottles of beer on the wall"
put
end repeat
put "1 bottle of beer on the wall"
put "1 bottle of beer"
put "Take one down, pass it around"
put "No more bottles of beer on the wall"
put
put "No more bottles of beer on the wall"
put "No more bottles of beer"
put "Go to the store and buy some more"
put "99 bottles of beer on the wall"Lisp[edit]
LLVM[edit]
See 99 Bottles of Beer/Assembly
Logo[edit]
to bottles :n
if :n = 0 [output [No more bottles]]
if :n = 1 [output [1 bottle]]
output sentence :n "bottles
end
to verse :n
print sentence bottles :n [of beer on the wall]
print sentence bottles :n [of beer]
print [Take one down, pass it around]
print sentence bottles :n-1 [of beer on the wall]
end
for [n 99 1] [verse :n (print)]Logtalk[edit]
:- object(bottles).
:- initialization(sing(99)).
sing(0) :-
write('No more bottles of beer on the wall, no more bottles of beer.'), nl,
write('Go to the store and buy some more, 99 bottles of beer on the wall.'), nl, nl.
sing(N) :-
N > 0,
N2 is N -1,
beers(N), write(' of beer on the wall, '), beers(N), write(' of beer.'), nl,
write('Take one down and pass it around, '), beers(N2), write(' of beer on the wall.'), nl, nl,
sing(N2).
beers(0) :-
write('no more bottles').
beers(1) :-
write('1 bottle').
beers(N) :-
N > 1,
write(N), write(' bottles').
:- end_object.
LOLCODE[edit]
See 99 Bottles of Beer/EsoLang
Lua[edit]
local bottles = 99
local function plural (bottles) if bottles == 1 then return '' end return 's' end
while bottles > 0 do
print (bottles..' bottle'..plural(bottles)..' of beer on the wall')
print (bottles..' bottle'..plural(bottles)..' of beer')
print ('Take one down, pass it around')
bottles = bottles - 1
print (bottles..' bottle'..plural(bottles)..' of beer on the wall')
print ()
end
With a numeric for-loop and string formatting:
verse = [[%i bottle%s of beer on the wall
%i bottle%s of beer
Take one down, pass it around
%i bottle%s of beer on the wall
]]
function suffix(i) return i ~= 1 and 's' or '' end
for i = 99, 1, -1 do
print(verse:format(i, suffix(i), i, suffix(i), i-1, suffix(i-1)))
end
Using Lua relational operators and multiple return values:
function bottles(i)
local s = i == 1 and "1 bottle of beer" or
i == 0 and "no more bottles of beer" or
tostring(i) .. " bottles of beer"
return s, s
end
for i = 99, 1, -1 do
print( string.format("%s on the wall,\n%s,\ntake one down, pass it around,", bottles(i)),
string.format("\n%s on the wall.\n", bottles(i-1)) )
end
Lucid[edit]
// Run luval with -s inside the lucid shell script
// The print out is a list of lines. So the output is not separated by new lines, rather
// by '[' and ']' -- I cant figure out how to do string concatenation with numbers in lucid.
// beer(N) ^ bottle(N) ^ wall ^ beer(N) ^ bottle(N) ^ pass ^ beer(N-1) ^ bottle(N-1) ^ wall
// should have worked but doesn't
[%beer(N),bottle(N),wall,beer(N),bottle(N),pass,beer(N-1),bottle(N-1),wall%]
where
N = 100 fby N - 1;
wall = if N > 0 then ` On the wall ' else eod fi;
pass = `Take one down and pass it around.';
beer(A) = if A > 0 then A else `No more' fi;
bottle(A) = if A eq 1 then `bottle of beer' else `bottles of beer' fi;
end
NATURAL[edit]
El código es de Chris Bednara
DEFINE DATA
LOCAL
01 #BOTTLES (I2)
END-DEFINE
*
FOR #BOTTLES 99 TO 2 STEP -1
IF #BOTTLES < 98
WRITE #BOTTLES ' BOTTLES OF BEER ON THE WALL'
WRITE ' '
END-IF
*
WRITE #BOTTLES ' BOTTLES OF BEER ON THE WALL'
WRITE #BOTTLES ' BOTTLES OF BEER'
WRITE 'TAKE ONE DOWN, PASS IT AROUND'
END-FOR
*
WRITE '1 BOTTLE OF BEER ON THE WALL'
WRITE ' '
WRITE '1 BOTTLE OF BEER ON THE WALL'
WRITE '1 BOTTLE OF BEER'
WRITE 'TAKE IT DOWN, PASS IT AROUND'
WRITE 'NO MORE BOTTLES OF BEER ON THE WALL'
WRITE ' '
WRITE 'NO MORE BOTTLES OF BEER ON THE WALL'
WRITE 'NO MORE BOTTLES OF BEER'
WRITE 'GO TO THE STORE AND BUY SOME MORE'
WRITE '99 BOTTLES OF BEER'
END
WRITE 'TAKE ONE DOWN, PASS IT AROUND'
*
END
M4[edit]
define(`BOTTLES', `bottles of beer')dnl
define(`BOTTLE', `bottle of beer')dnl
define(`WALL', `on the wall')dnl
define(`TAKE', `take one down, pass it around')dnl
define(`NINETEEN', `$1 ifelse(`$1',`1',BOTTLE,BOTTLES) WALL
$1 ifelse(`$1',`1',BOTTLE,BOTTLES)
ifelse(`$1',`0',,`TAKE')
ifelse(`$1',`0',,`NINETEEN(eval($1-1))')')dnl
NINETEEN(99)MACRO-11[edit]
;
; 99 BOTTLES OF BEER
; WRITTEN BY: BILL GUNSHANNON
;
.MCALL .PRINT .EXIT
.RADIX 10
MESG1:
CNUM1: .ASCII " "
.ASCII " BOTTLES OF BEER ON THE WALL, "
CNUM2: .ASCII " "
.ASCII " BOTTLES OF BEER."<13><10>
.ASCII "TAKE ONE DOWN AND PASS IT AROUND, "
CNUM3: .ASCII " "
.ASCIZ " BOTTLES OF BEER ON THE WALL."<13><10><10>
MESG2: .ASCII " 2 BOTTLES OF BEER ON THE WALL, "
.ASCII " 2 BOTTLES OF BEER."<13><10>
.ASCII "TAKE ONE DOWN AND PASS IT AROUND, "
.ASCIZ " 1 BOTTLE OF BEER ON THE WALL."<13><10><10>
MESG3: .ASCII " 1 BOTTLE OF BEER ON THE WALL, "
.ASCII " 1 BOTTLE OF BEER."<13><10>
.ASCII "TAKE ONE DOWN AND PASS IT AROUND, "
.ASCIZ "NO MORE BOTTLES OF BEER ON THE WALL."<13><10><10>
MESG4: .ASCII "NO MORE BOTTLES OF BEER ON THE WALL, "
.ASCII "NO MORE BOTTLES OF BEER."<13><10>
.ASCII "GO TO THE STORE AND BUY SOME MORE, "
.ASCIZ "99 BOTTLES OF BEER ON THE WALL."<13><10><10>
.EVEN
COUNT1: .WORD 99 ; STARTING NUMBER OF BOTTLES
PV: .WORD 10.,1, ; POSITION VALUES FOR 2 DIGITS
START:
MOV COUNT1, R0
MOV R0, R5
DEC R5
AGAIN:
MOV #CNUM1, R1
; CONVERT NUMBER OF BOTTLES TO ASCII FOR THE FIRST FIELD
MOV R0,-(SP)
MOV R1,-(SP)
MOV R2,-(SP)
MOV R3,-(SP)
MOV R4,-(SP)
MOV R5,-(SP)
MOV #PV, R3
MOV #2, R2
A1$: MOV #-1,R4
A2$: INC R4
SUB (R3), R0
BCC A2$
ADD (R3)+, R0
ADD #48, R4
MOVB R4, (R1)+
A21$: SOB R2, A1$
; REMOVE LEADING ZERO - JUST LOOKS BETTER THAT WAY
MOV #CNUM1, R1
CMPB (R1), #48
BNE CONT1
MOVB #32, (R1)
CONT1: MOV #CNUM2, R0
; MOVE THE ASCII NUMBER TO FIELD TWO RATHER THAN COMPUTING IT AGAIN
MOVB (R1)+, (R0)+
MOVB (R1), (R0)
MOV R5, R0
MOV #CNUM3, R1
; CONVERT NUMBER OF BOTTLES TO ASCII FOR THE THIRD FIELD
MOV #PV, R3
MOV #2, R2
B1$: MOV #-1,R4
B2$: INC R4
SUB (R3), R0
BCC B2$
ADD (R3)+, R0
ADD #48, R4
MOVB R4, (R1)+
B21$: SOB R2, B1$
; REMOVE LEADING ZERO - JUST LOOKS BETTER THAT WAY
MOV #CNUM3, R1
CMPB (R1), #48
BNE CONT2
MOVB #32, (R1)
CONT2:
MOV (SP)+,R5
MOV (SP)+,R4
MOV (SP)+,R3
MOV (SP)+,R2
MOV (SP)+,R1
MOV (SP)+,R0
; HANDLE SPECIAL GRAMMER CASES
CMP R0, #2
BNE ONE
.PRINT #MESG2
BR DONE
ONE: CMP R0, #1
BNE GREATER
.PRINT #MESG3
BR DONE
GREATER:
.PRINT #MESG1
DONE:
; DECREMENT THE COUNT AND START AGAIN
MOV R5, R0
DEC R5
TST R0
BNE AGAIN
; OUT OF BEER, SEND THEM TO THE STORE
.PRINT #MESG4
; CLEAN UP AND GO BACK TO KMON
.EXIT
.END STARTMAD[edit]
NORMAL MODE IS INTEGER
BOTLES = 99
VERSE WALL.(BOTLES)
BOTL.(BOTLES)
PRINT FORMAT TKDWN
BOTLES = BOTLES - 1
WALL.(BOTLES)
PRINT FORMAT EMPTY
WHENEVER BOTLES .G. 0, TRANSFER TO VERSE
INTERNAL FUNCTION(B)
ENTRY TO BOTL.
WHENEVER B .E. 1
PRINT FORMAT ONEBTL
OTHERWISE
PRINT FORMAT BBTL,B
END OF CONDITIONAL
FUNCTION RETURN
END OF FUNCTION
INTERNAL FUNCTION(B)
ENTRY TO WALL.
WHENEVER B .E. 0
PRINT FORMAT NOMORE
OR WHENEVER B .E. 1
PRINT FORMAT ONEOTW
OTHERWISE
PRINT FORMAT BBOTW,B
END OF CONDITIONAL
FUNCTION RETURN
END OF FUNCTION
VECTOR VALUES BBOTW = $I2,S1,27HBOTTLES OF BEER ON THE WALL*$
VECTOR VALUES BBTL = $I2,S1,15HBOTTLES OF BEER*$
VECTOR VALUES TKDWN = $32HTAKE ONE DOWN AND PASS IT AROUND*$
VECTOR VALUES ONEOTW = $S1,29H 1 BOTTLE OF BEER ON THE WALL*$
VECTOR VALUES ONEBTL = $S1,17H 1 BOTTLE OF BEER*$
VECTOR VALUES NOMORE = $35HNO MORE BOTTLES OF BEER ON THE WALL*$
VECTOR VALUES EMPTY = $*$
END OF PROGRAMmake[edit]
BSD make[edit]
START = 99
UP != jot - 2 `expr $(START) - 1` 1
0-bottles-of-beer: 1-bottle-of-beer
@echo No more bottles of beer on the wall!
1-bottle-of-beer: 2-bottles-of-beer
@echo One last bottle of beer on the wall!
@echo
@echo One last bottle of beer on the wall,
@echo One last bottle of beer,
@echo Take it down, pass it around.
.for COUNT in $(UP)
ONE_MORE != expr 1 + $(COUNT)
$(COUNT)-bottles-of-beer: $(ONE_MORE)-bottles-of-beer
@echo $(COUNT) bottles of beer on the wall!
@echo
@echo $(COUNT) bottles of beer on the wall,
@echo $(COUNT) bottles of beer,
@echo Take one down, pass it around.
.endfor
$(START)-bottles-of-beer:
@echo $(START) bottles of beer on the wall,
@echo $(START) bottles of beer.
@echo Take one down, pass it around.
Usage: make or make START=99
GNU make[edit]
PRED=`expr $* - 1`
1-bottles: 1-beer pass
@echo "No more bottles of beer on the wall"
%-bottles: %-beer pass
@echo "$(PRED) bottles of beer on the wall\n"
@-$(MAKE) $(PRED)-bottles
1-beer:
@echo "One bottle of beer on the wall, One bottle of beer"
%-beer:
@echo "$* bottles of beer on the wall, $* bottles of beer"
pass:
@echo "Take one down and pass it around,"
Usage: make 99-bottles
This will fork 99 make processes. You might need to raise your process limit (ulimit -p).
GNU make[edit]
Without using a shell command to decrement the counter[edit]
digits:=9 8 7 6 5 4 3 2 1 0
numbers:=$(foreach x,$(filter-out 0,$(digits)),$(foreach y,$(digits),$x$y))
numbers+=$(digits)
bottles=bottle$(if $(findstring /1/,$@),,s)
num=$(if $(findstring /0/,$@),$(empty),$(@F))
action=$(if $(findstring /0/,$@),$(buy),$(pass))
beer:=of beer
wall:=on the wall
empty:=No more
pass:=Take one down and pass it around.
buy:=Go to the store and buy some more.
# Function to generate targets for each verse of the song.
define verse
.PHONY: $1
$1: verse/$1/$1 prelude/$2/$2 $2
.PHONY: $1-bottles
$1-bottles: $1
most?=$1
endef
# Recursive function that loops through the 100 numbers.
define verses
$$(eval $$(call verse,$$(word 1,$1),$$(word 2,$1)))
$$(if $$(word 2,$1),$$(eval $$(call verses,$$(filter-out $$(word 1,$1),$1))))
endef
# Generate the targets for the 100 numbers.
$(eval $(call verses,$(numbers)))
# Main lines in the verse.
.PHONY: verse/%
verse/%:
@echo "$(num) $(bottles) $(beer) $(wall)."
@echo "$(num) $(bottles) $(beer)."
@echo "$(action)"
# Last line of a verse, which is a prelude to the next verse.
.PHONY: prelude/%
prelude/%:
@echo "$(num) $(bottles) $(beer) $(wall)."
@echo ""
# Special target for the last line of the song.
.PHONY: prelude/
prelude/:
@echo "$(most) $(bottles) $(beer) $(wall)!"
@echo ""
Usage: make or make N-bottles or make N
A version of this script with more comments and an automated test can be found on github.com.
Malbolge[edit]
Long version (a real loop version made by Hisashi Iizawa):
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