Substring/Top and tail

From Rosetta Code
Task
Substring/Top and tail
You are encouraged to solve this task according to the task description, using any language you may know.

The task is to demonstrate how to remove the first and last characters from a string.

The solution should demonstrate how to obtain the following results:

  • String with first character removed
  • String with last character removed
  • String with both the first and last characters removed


If the program uses UTF-8 or UTF-16, it must work on any valid Unicode code point, whether in the Basic Multilingual Plane or above it.

The program must reference logical characters (code points), not 8-bit code units for UTF-8 or 16-bit code units for UTF-16.

Programs for other encodings (such as 8-bit ASCII, or EUC-JP) are not required to handle all Unicode characters.


Other tasks related to string operations:
Metrics
Counting
Remove/replace
Anagrams/Derangements/shuffling
Find/Search/Determine
Formatting
Song lyrics/poems/Mad Libs/phrases
Tokenize
Sequences



11l[edit]

Translation of: Python
print(‘knight’[1..])
print(‘socks’[0 .< (len)-1])
print(‘brooms’[1 .< (len)-1])
Output:
night
sock
room

360 Assembly[edit]

*        Substring/Top and tail    04/03/2017
SUBSTRTT CSECT
         USING  SUBSTRTT,R13       base register
         B      72(R15)            skip savearea
         DC     17F'0'             savearea
         STM    R14,R12,12(R13)    save previous context
         ST     R13,4(R15)         link backward
         ST     R15,8(R13)         link forward
         LR     R13,R15            set addressability
*
         XPRNT  S8,L'S8            print s8
         MVC    S7,S8+1            s7=substr(s8,2,7)
         XPRNT  S7,L'S7            print s7
         MVC    S7,S8              s7=substr(s8,1,7)
         XPRNT  S7,L'S7            print s7
         MVC    S6,S8+1            s6=substr(s8,2,6)
         XPRNT  S6,L'S6            print s6
*         
         L      R13,4(0,R13)       epilog
         LM     R14,R12,12(R13)    restore previous context
         XR     R15,R15            rc=0
         BR     R14                exit
S8       DC     CL8'12345678'
S7       DS     CL7
S6       DS     CL6
         YREGS
         END    SUBSTRTT
Output:
12345678
2345678
1234567
234567

ACL2[edit]

(defun str-rest (str)
   (coerce (rest (coerce str 'list)) 'string))

(defun rdc (xs)
   (if (endp (rest xs))
       nil
       (cons (first xs)
             (rdc (rest xs)))))

(defun str-rdc (str)
   (coerce (rdc (coerce str 'list)) 'string))

(str-rdc "string")
(str-rest "string")
(str-rest (str-rdc "string"))

Action![edit]

PROC Main()
  CHAR ARRAY text="qwertyuiop"
  CHAR ARRAY res(20)
  BYTE n,m

  PrintF("Original string:%E  ""%S""%E%E",text)

  SCopyS(res,text,2,text(0))
  PrintF("String without the top:%E  ""%S""%E%E",res)

  SCopyS(res,text,1,text(0)-1)
  PrintF("String without the tail:%E  ""%S""%E%E",res)

  SCopyS(res,text,2,text(0)-1)
  PrintF("String without the top and the tail:%E  ""%S""%E%E",res)
RETURN
Output:

Screenshot from Atari 8-bit computer

Original string:
  "qwertyuiop"

String without the top:
  "wertyuiop"

String without the tail:
  "qwertyuio"

String without the top and the tail:
  "wertyuio"

Ada[edit]

with Ada.Text_IO;

procedure Remove_Characters is
   S: String := "upraisers";
   use Ada.Text_IO;
begin
   Put_Line("Full String:   """ & S & """");
   Put_Line("Without_First: """ & S(S'First+1 .. S'Last) & """");
   Put_Line("Without_Last:  """ & S(S'First   .. S'Last-1) & """");
   Put_Line("Without_Both:  """ & S(S'First+1 .. S'Last-1) & """");
end Remove_Characters;

Output:

Full String:   "upraisers"
Without_First: "praisers"
Without_Last:  "upraiser"
Without_Both:  "praiser"

With UTF8 support in Ada 2012 (Wide_Character of literals is automatic):

with Ada.Text_IO;
with Ada.Strings.UTF_Encoding.Wide_Strings;

procedure Remove_Characters
is
   use Ada.Text_IO;
   use Ada.Strings.UTF_Encoding;
   use Ada.Strings.UTF_Encoding.Wide_Strings;
   
   S : String := "upraisers";
   U : Wide_String := Decode (UTF_8_String'(S));
   
   function To_String (X : Wide_String)return String
   is
   begin
      return String (UTF_8_String'(Encode (X)));
   end To_String;
   
begin
   Put_Line
     (To_String
        ("Full String:   """ & U & """"));
   Put_Line
     (To_String
        ("Without_First: """ & U (U'First + 1 .. U'Last) & """"));
   Put_Line
     (To_String
        ("Without_Last:  """ & U (U'First   .. U'Last - 1) & """"));
   Put_Line
     (To_String
        ("Without_Both:  """ & U (U'First + 1 .. U'Last - 1) & """"));

end Remove_Characters;

Output:

Full String:   "upraisers"
Without_First: "praisers"
Without_Last:  "upraiser"
Without_Both:  "praiser"

Aime[edit]

o_text(delete("knights", 0));
o_newline();
o_text(delete("knights", -1));
o_newline();
o_text(delete(delete("knights", 0), -1));
o_newline();
Output:
nights
knight
night

ALGOL 68[edit]

Translation of: AWK
Works with: ALGOL 68 version Revision 1 - no extensions to language used.
Works with: ALGOL 68G version Any - tested with release 1.18.0-9h.tiny.
#!/usr/local/bin/a68g --script #

STRING str="upraisers";
printf(($gl$,
  str,                      # remove no characters #
  str[LWB str+1:         ], # remove the first character #
  str[         :UPB str-1], # remove the last character #
  str[LWB str+1:UPB str-1], # remove both the first and last character #
  str[LWB str+2:         ], # remove the first 2 characters #
  str[         :UPB str-2], # remove the last 2 characters #
  str[LWB str+1:UPB str-2], # remove 1 before and 2 after #
  str[LWB str+2:UPB str-1], # remove 2 before and one after #
  str[LWB str+2:UPB str-2]  # remove both the first and last 2 characters #
))

Output:

upraisers
praisers
upraiser
praiser
raisers
upraise
praise
raiser
raise

Amazing Hopper[edit]

#include <hopper.h>
#proto showmessage(_X_)
main:
  s="message", t=s
  ++s, _show message(s)
  s=t
  --s, _show message(s)
  ++s, _show message(s)
{0}return

.locals
showmessage(_S_)
  {_S_,"\n"}print
back
Output:
essage
messag
essag

Apex[edit]

String strOrig = 'brooms';
String str1 = strOrig.substring(1, strOrig.length());
system.debug(str1);
String str2 = strOrig.substring(0, strOrig.length()-1);
system.debug(str2);
String str3 = strOrig.substring(1, strOrig.length()-1);
system.debug(str3);

// Regular Expressions approach
String strOrig = 'brooms';
String str1 = strOrig.replaceAll( '^.', '' );
system.debug(str1);
String str2 = strOrig.replaceAll( '.$', '' ) ;
system.debug(str2);
String str3 = strOrig.replaceAll( '^.|.$', '' );
system.debug(str3);
Output:
rooms

broom

room

AppleScript[edit]

set aString to "This is some text"

set stringLength to (count aString) -- The number of characters in the text.

-- AppleScript indices are 1-based. Ranges can be specified in several different ways.
if (stringLength > 1) then
    set substring1 to text 2 thru stringLength of aString
    -- set substring1 to text 2 thru -1 of aString
    -- set substring1 to text 2 thru end of aString
    -- set substring1 to text from character 2 to character stringLength of aString
    -- set substring1 to aString's text from 2 to -1
    -- Some combination of the above.
else
    set substring1 to ""
end if

if (stringLength > 1) then
    set substring2 to text 1 thru -2 of aString
else
    set substring2 to ""
end if

if (stringLength > 2) then
    set substring3 to text 2 thru -2 of aString
else
    set substring3 to ""
end if

return substring1 & linefeed & substring2 & linefeed & substring3
Output:
"his is some text
This is some tex
his is some tex"

Arturo[edit]

knight: "knight"
socks: "socks"
brooms: "brooms"

print drop knight 1                     ; strip first character
print slice knight 1 (size knight)-1    ; alternate way to strip first character

print chop socks                        ; strip last character
print take socks (size socks)-1         ; alternate way to strip last character
print slice socks 0 (size socks)-2      ; yet another way to strip last character

print chop drop brooms 1                ; strip both first and last characters
print slice brooms 1 (size brooms)-2    ; alternate way to strip both first and last characters
Output:
night
night
sock
sock
sock
room
room

AutoHotkey[edit]

myString := "knights"
MsgBox % SubStr(MyString, 2)
MsgBox % SubStr(MyString, 1, StrLen(MyString)-1)
MsgBox % SubStr(MyString, 2, StrLen(MyString)-2)

AWK[edit]

BEGIN {
  mystring="knights"
  print substr(mystring,2)                       # remove the first letter
  print substr(mystring,1,length(mystring)-1)    # remove the last character
  print substr(mystring,2,length(mystring)-2)    # remove both the first and last character
}

BASIC[edit]

10 PRINT FN F$("KNIGHTS"): REM STRIP THE FIRST LETTER
20 PRINT FN L$("SOCKS"): REM STRIP THE LAST LETTER
30 PRINT FN B$("BROOMS"): REM STRIP BOTH THE FIRST AND LAST LETTER
100 END
 
9000 DEF FN F$(A$)=RIGHT$(A$,LEN(A$)-1)
9010 DEF FN L$(A$)=LEFT$(A$,LEN(A$)-1)
9020 DEF FN B$(A$)=FN L$(FN F$(A$))

QBasic[edit]

Works with: QBasic version 1.1
Works with: QuickBasic version 4.5
s$ = "Rosetta Code"

PRINT s$
PRINT MID$(s$, 2)               'strip first
PRINT LEFT$(s$, LEN(s$) - 1)    'strip last
PRINT MID$(s$, 2, LEN(s$) - 2)  'strip first and last

BASIC256[edit]

s$ = "Rosetta Code"

print s$
PRINT MID$(s$, 2)               'strip first
PRINT LEFT$(s$, LEN(s$) - 1)    'strip last
PRINT MID$(s$, 2, LEN(s$) - 2)  'strip first and last

True BASIC[edit]

LET s$ = "Rosetta Code"
PRINT s$
PRINT (s$)[2:maxnum]              !strip first
PRINT (s$)[1:len(s$)-1]           !strip last
PRINT (s$)[2:2+len(s$)-2-1]       !strip first and last
END

XBasic[edit]

Works with: Windows XBasic
PROGRAM	"Substring"
VERSION	"0.0000"

DECLARE FUNCTION  Entry ()

FUNCTION  Entry ()
s$ = "Rosetta Code"

PRINT s$
PRINT MID$(s$, 2)               'strip first
PRINT LEFT$(s$, LEN(s$) - 1)    'strip last
PRINT MID$(s$, 2, LEN(s$) - 2)  'strip first and last

END FUNCTION
END PROGRAM

Yabasic[edit]

s$ = "Rosetta Code"

print s$
PRINT MID$(s$, 2)               'strip first
PRINT LEFT$(s$, LEN(s$) - 1)    'strip last
PRINT MID$(s$, 2, LEN(s$) - 2)  'strip first and last

IS-BASIC[edit]

100 LET S$="Knights"
110 PRINT S$(2:)
120 PRINT S$(:LEN(S$)-1)
130 PRINT S$(2:LEN(S$)-1)

Sinclair ZX81 BASIC[edit]

Note that strings are indexed from 1.

10 REM STRING SLICING EXAMPLE
20 LET S$="KNIGHTS"
30 REM WITH FIRST CHARACTER REMOVED:
40 PRINT S$(2 TO )
50 REM WITH LAST CHARACTER REMOVED:
60 PRINT S$( TO LEN S$-1)
70 REM WITH BOTH REMOVED:
80 PRINT S$(2 TO LEN S$-1)
Output:
NIGHTS
KNIGHT
NIGHT

Microsoft Small Basic[edit]

When I tried using Unicode characters, it printed question marks, though ASCII works fine.

string = "Small Basic"
TextWindow.WriteLine(Text.GetSubTextToEnd(string, 2)) 'Without the first character
TextWindow.WriteLine(Text.GetSubText(string, 1, Text.GetLength(string) - 1)) 'Without the last character
TextWindow.WriteLine(Text.GetSubText(string, 2, Text.GetLength(string) - 2)) 'Without the first and last characters
Output:
mall Basic
Small Basi
mall Basi

BQN[edit]

Drop() is the main function used here.

  str ← "substring"
"substring"
  1↓str
"ubstring"
  ¯1↓str
"substrin"
  1↓¯1↓str
"ubstrin"

BBC BASIC[edit]

      s$ = "Rosetta Code"
      PRINT MID$(s$, 2)
      PRINT LEFT$(s$)
      PRINT LEFT$(MID$(s$, 2))

Bracmat[edit]

Bracmat uses UTF-8 internally. The function utf fails if its argument isn't a valid UTF-8 multibyte string, but in two slightly different ways: an indefinite and a definite way. If the argument does not have the required number of bytes but otherwise seems to be ok, Bracmat's backtacking mechanism lenghtens the argument and then calls utf again. This is repeated until utf either succeeds or definitely fails. The code is far from efficient.

(substringUTF-8=
  @( Δημοτική
   : (%?a&utf$!a) ?"String with first character removed"
   )
& @( Δημοτική
   : ?"String with last character removed" (?z&utf$!z)
   )
& @( Δημοτική
   :   (%?a&utf$!a)
       ?"String with both the first and last characters removed"
       (?z&utf$!z)
   )
&   out
  $ ("String with first character removed:" !"String with first character removed")
&   out
  $ ("String with last character removed:" !"String with last character removed")
&   out
  $ ( "String with both the first and last characters removed:"
      !"String with both the first and last characters removed"
    ));
!substringUTF-8
String with first character removed: ημοτική
String with last character removed: Δημοτικ
String with both the first and last characters removed: ημοτικ

If the string is known to consist of 8-byte characters, we can use a simpler method. Essential are the % and @ prefixes. The % prefix matches 1 or more elements (bytes, in the case of string pattern matching), while @ matches 0 or 1 elements. In combination these prefixes match 1 and only 1 byte.

(substring-8-bit=
  @("8-bit string":%@ ?"String with first character removed")
& @("8-bit string":?"String with last character removed" @)
& @( "8-bit string"
   : %@ ?"String with both the first and last characters removed" @
   )
&   out
  $ ("String with first character removed:" !"String with first character removed")
&   out
  $ ("String with last character removed:" !"String with last character removed")
&   out
  $ ( "String with both the first and last characters removed:"
      !"String with both the first and last characters removed"
    ));
!substring-8-bit
String with first character removed: -bit string
String with last character removed: 8-bit strin
String with both the first and last characters removed: -bit strin

Burlesque[edit]

blsq ) "RosettaCode"[-
"osettaCode"
blsq ) "RosettaCode"-]
'R
blsq ) "RosettaCode"~]
"RosettaCod"
blsq ) "RosettaCode"[~
'e
blsq ) "RosettaCode"~-
"osettaCod"

C[edit]

#include <string.h>
#include <stdlib.h>
#include <stdio.h>

int main( int argc, char ** argv ){
  const char * str_a = "knight";
  const char * str_b = "socks";
  const char * str_c = "brooms";

  char * new_a = malloc( strlen( str_a ) - 1 );
  char * new_b = malloc( strlen( str_b ) - 1 );
  char * new_c = malloc( strlen( str_c ) - 2 );

  strcpy( new_a, str_a + 1 );
  strncpy( new_b, str_b, strlen( str_b ) - 1 );
  strncpy( new_c, str_c + 1, strlen( str_c ) - 2 );

  printf( "%s\n%s\n%s\n", new_a, new_b, new_c );

  free( new_a );
  free( new_b );
  free( new_c );

  return 0;
}

Result:

night
sock
room

ANSI C provides little functionality for text manipulation outside of string.h. While a number of libraries for this purpose have been written, this example uses only ANSI C.

C#[edit]

using System;

class Program
{
    static void Main(string[] args)
    {
        string testString = "test";
        Console.WriteLine(testString.Substring(1));
        Console.WriteLine(testString.Substring(0, testString.Length - 1));
        Console.WriteLine(testString.Substring(1, testString.Length - 2));
    }
}

Result:

est
tes
es

C++[edit]

#include <string>
#include <iostream>

int main( ) {
   std::string word( "Premier League" ) ;
   std::cout << "Without first letter: " << word.substr( 1 ) << " !\n" ;
   std::cout << "Without last letter: " << word.substr( 0 , word.length( ) - 1 ) << " !\n" ;
   std::cout << "Without first and last letter: " << word.substr( 1 , word.length( ) - 2 ) << " !\n" ;
   return 0 ;
}

Output:

Without first letter: remier League !
Without last letter: Premier Leagu !
Without first and last letter: remier Leagu !

Clojure[edit]

; using substring:
user=> (subs "knight" 1)
"night"
user=> (subs "socks" 0 4)
"sock"
user=> (.substring "brooms" 1 5)
"room"

; using rest and drop-last:
user=> (apply str (rest "knight"))
"night"
user=> (apply str (drop-last "socks"))
"sock"
user=> (apply str (rest (drop-last "brooms")))
"room"

COBOL[edit]

       identification division.
       program-id. toptail.

       data division.
       working-storage section.
       01 data-field.
          05 value "[this is a test]".

       procedure division.
       sample-main.
       display data-field
      *> Using reference modification, which is (start-position:length)
       display data-field(2:)
       display data-field(1:length of data-field - 1)
       display data-field(2:length of data-field - 2)
       goback.
       end program toptail.
Output:
prompt$ cobc -xj toptail.cob
[this is a test]
this is a test]
[this is a test
this is a test

Common Lisp[edit]

subseq will signal an error if you provide invalid start or end values.

> (defvar *str* "∀Ꮺ✤Л◒")
*STR*
> (subseq *str* 1) ; remove first character
"Ꮺ✤Л◒"
> (subseq *str* 0 (1- (length *str*))) ; remove last character
"∀Ꮺ✤Л"
> (subseq *str* 1 (1- (length *str*))) ; remove first and last character
"Ꮺ✤Л"

D[edit]

Version for ASCII strings or Unicode dstrings:

import std.stdio;

void main() {
    // strip first character
    writeln("knight"[1 .. $]);

    // strip last character
    writeln("socks"[0 .. $ - 1]);

    // strip both first and last characters
    writeln("brooms"[1 .. $ - 1]);
}
Output:
night
sock
room

Delphi[edit]

program TopAndTail;

{$APPTYPE CONSOLE}

const
  TEST_STRING = '1234567890';
begin
  Writeln(TEST_STRING);                                    // full string
  Writeln(Copy(TEST_STRING, 2, Length(TEST_STRING)));      // first character removed
  Writeln(Copy(TEST_STRING, 1, Length(TEST_STRING) - 1));  // last character removed
  Writeln(Copy(TEST_STRING, 2, Length(TEST_STRING) - 2));  // first and last characters removed

  Readln;
end.

EasyLang[edit]

string$ = "EasyLang"
print substr string$ 1 len string$ - 1 # Without the first character
print substr string$ 2 len string$ - 1 # Without the last character
print substr string$ 2 len string$ - 2 # Without the first and last characters
Output:
EasyLan
asyLang
asyLan

Eero[edit]

#import <Foundation/Foundation.h>

int main()
  autoreleasepool

    s := 'knight'
    Log( '%@', s[1 .. s.length-1] )  // strip first character

    s = 'socks'
    Log( '%@', s[0 .. s.length-2] )  // strip last character
   
    s = 'brooms'   
    Log( '%@', s[1 .. s.length-2] )  // strip both first and last characters

    s = 'Δημοτική'   
    Log( '%@', s[1 .. s.length-2] )  // strip both first and last characters

  return 0
Output:
2013-09-04 17:08:09.453 a.out[2257:507] night
2013-09-04 17:08:09.454 a.out[2257:507] sock
2013-09-04 17:08:09.454 a.out[2257:507] room
2013-09-04 17:08:09.455 a.out[2257:507] ημοτικ

Elena[edit]

ELENA 4.x :

import extensions;
 
public program()
{
    var testString := "test";
 
    console.printLine(testString.Substring(1));
    console.printLine(testString.Substring(0, testString.Length - 1));
    console.printLine(testString.Substring(1, testString.Length - 2))
}
Output:
est
tes
es

Elixir[edit]

iex(1)> str = "abcdefg"
"abcdefg"
iex(2)> String.slice(str, 1..-1)
"bcdefg"
iex(3)> String.slice(str, 0..-2)
"abcdef"
iex(4)> String.slice(str, 1..-2)
"bcdef"

Emacs Lisp[edit]

(let ((string "top and tail"))
  (substring string 1) ;=> "op and tail"
  (substring string 0 (1- (length string))) ;=> "top and tai"
  (substring string 1 (1- (length string)))) ;=> "op and tai"

Erlang[edit]

1> Str = "Hello".
"Hello"
2> string:sub_string(Str, 2).                   % To strip the string from the right by 1
"ello"
3> string:sub_string(Str, 1, length(Str)-1).    % To strip the string from the left by 1
"Hell"
4> string:sub_string(Str, 2, length(Str)-1).    % To strip the string from both sides by 1
"ell"

Euphoria[edit]

function strip_first(sequence s)
    return s[2..$]
end function

function strip_last(sequence s)
    return s[1..$-1]
end function

function strip_both(sequence s)
    return s[2..$-1]
end function

puts(1, strip_first("knight"))  -- strip first character
puts(1, strip_last("write"))    -- strip last character
puts(1, strip_both("brooms"))   -- strip both first and last characters

F#[edit]

[<EntryPoint>]
let main args =
    let s = "一二三四五六七八九十"
    printfn "%A" (s.Substring(1))
    printfn "%A" (s.Substring(0, s.Length - 1))
    printfn "%A" (s.Substring(1, s.Length - 2))
    0

Output

"二三四五六七八九十"
"一二三四五六七八九"
"二三四五六七八九"

Factor[edit]

USING: io kernel sequences ;
"Rosetta code" [ rest ] [ but-last ] [ rest but-last ] tri
[ print ] tri@
Output:
osetta code
Rosetta cod
osetta cod

Forth[edit]

In Forth, strings typically take up two cells on the stack, diagrammed ( c-addr u ), with C-ADDR the address of the string and U its length. Dropping leading and trailing characters then involves simple mathematical operations on the address or length, without mutating or copying the string.

: hello ( -- c-addr u )
  s" Hello" ;  

hello 1 /string type     \ => ello

hello 1- type            \ => hell

hello 1 /string 1- type  \ => ell

This works for ASCII, and a slight variation (2 instead of 1 per character) will suffice for BIG5, GB2312, and like, but Unicode-general code can use +X/STRING and X\STRING- from Forth-200x's XCHAR wordset.

Fortran[edit]

program substring

  character(len=5) :: string
  string = "Hello"
  
  write (*,*) string
  write (*,*) string(2:)
  write (*,*) string( :len(string)-1)
  write (*,*) string(2:len(string)-1)

end program substring

FreeBASIC[edit]

' FB 1.05.0 Win64

Dim s As String  = "panda"
Dim s1 As String = Mid(s, 2)
Dim s2 As String = Left(s, Len(s) - 1)
Dim s3 As String = Mid(s, 2, Len(s) - 2)
Print s
Print s1
Print s2
Print s3
Sleep
Output:
panda
anda
pand
and


FutureBasic[edit]

void local fn DoIt
  CFStringRef s = @"knights"
  print s
  CFStringRef s1 = mid(s, 1, len(s) - 1)
  print s1
  CFStringRef s2 = left(s,   len(s) - 1)
  print s2
  CFStringRef s3 = mid(s, 1, len(s) - 2)
  print s3
end fn

fn DoIt

HandleEvents
Output:
knights
nighs
knight
night


Go[edit]

Go strings are byte arrays that can hold whatever you want them to hold. Common contents are ASCII and UTF-8. You use different techniques depending on how you are interpreting the string. The utf8 package functions shown here allows efficient extraction of first and last runes without decoding the entire string.

package main

import (
    "fmt"
    "unicode/utf8"
)

func main() {
    // ASCII contents:  Interpreting "characters" as bytes.
    s := "ASCII"
    fmt.Println("String:                ", s)
    fmt.Println("First byte removed:    ", s[1:])
    fmt.Println("Last byte removed:     ", s[:len(s)-1])
    fmt.Println("First and last removed:", s[1:len(s)-1])
    // UTF-8 contents:  "Characters" as runes (unicode code points)
    u := "Δημοτική"
    fmt.Println("String:                ", u)
    _, sizeFirst := utf8.DecodeRuneInString(u)
    fmt.Println("First rune removed:    ", u[sizeFirst:])
    _, sizeLast := utf8.DecodeLastRuneInString(u)
    fmt.Println("Last rune removed:     ", u[:len(u)-sizeLast])
    fmt.Println("First and last removed:", u[sizeFirst:len(u)-sizeLast])
}

Output:

String:                 ASCII
First byte removed:     SCII
Last byte removed:      ASCI
First and last removed: SCI
String:                 Δημοτική
First rune removed:     ημοτική
Last rune removed:      Δημοτικ
First and last removed: ημοτικ

Golfscript[edit]

When I tried using Unicode characters, the interpreter generated a mess, though ASCII works fine.

"Golfscript"(;n
"Golfscript");n
"Golfscript"(;);
Output:
olfscript
Golfscrip
olfscrip

Groovy[edit]

Solution:

def top  = { it.size() > 1 ? it[0..-2] : '' }
def tail = { it.size() > 1 ? it[1..-1] : '' }

Test:

def testVal = 'upraisers'
println """
original: ${testVal}
top:      ${top(testVal)}
tail:     ${tail(testVal)}
top&tail: ${tail(top(testVal))}
"""

Output:

original: upraisers
top:      upraiser
tail:     praisers
top&tail: praiser

GW-BASIC[edit]

10 A$="knight":B$="socks":C$="brooms"
20 PRINT MID$(A$,2)
30 PRINT LEFT$(B$,LEN(B$)-1)
40 PRINT MID$(C$,2,LEN(C$)-2)

Haskell[edit]

-- We define the functions to return an empty string if the argument is too
-- short for the particular operation.

remFirst, remLast, remBoth :: String -> String

remFirst "" = ""
remFirst cs = tail cs

remLast "" = ""
remLast cs = init cs

remBoth (c:cs) = remLast cs
remBoth  _     = ""

main :: IO ()
main = do
  let s = "Some string."  
  mapM_ (\f -> putStrLn . f $ s) [remFirst, remLast, remBoth]

Alternative solution with builtin functions:

word = "knights"

main = do
    -- You can drop the first item
    -- using `tail`
    putStrLn (tail word)

    -- The `init` function will drop
    -- the last item
    putStrLn (init word)

    -- We can combine these two to drop
    -- the last and the first characters
    putStrLn (middle word)

-- You can combine functions using `.`,
-- which is pronounced "compose" or "of"
middle = init . tail

In short:

main :: IO ()
main = mapM_ print $ [tail, init, init . tail] <*> ["knights"]
Output:
"nights"
"knight"
"night"

Icon and Unicon[edit]

The task is accomplished by sub-stringing.

procedure main()
write(s := "knight"," --> ", s[2:0])  # drop 1st char
write(s := "sock"," --> ", s[1:-1])   # drop last
write(s := "brooms"," --> ", s[2:-1]) # drop both
end

It could also be accomplished (less clearly) by assigning into the string as below. Very awkward for both front and back.

write(s := "knight"," --> ", s[1] := "", s)  # drop 1st char

J[edit]

The monadic primitives }. (Behead) and }: (Curtail) are useful for this task.

Example use:

   }. 'knight'      NB. drop first item
night
   }: 'socks'       NB. drop last item
sock
   }: }. 'brooms'   NB. drop first and last items
room

Java[edit]

I solve this problem two ways. First I use substring which is relatively fast for small strings, since it simply grabs the characters within a set of given bounds. The second uses regular expressions, which have a higher overhead for such short strings.

public class RM_chars {
  public static void main( String[] args ){
    System.out.println( "knight".substring( 1 ) );
    System.out.println( "socks".substring( 0, 4 ) );
    System.out.println( "brooms".substring( 1, 5 ) );
      // first, do this by selecting a specific substring
      // to exclude the first and last characters
    
    System.out.println( "knight".replaceAll( "^.", "" ) );
    System.out.println( "socks".replaceAll( ".$", "" ) );
    System.out.println( "brooms".replaceAll( "^.|.$", "" ) );
      // then do this using a regular expressions
  }
}

Results:

night
sock
room
night
sock
room

JavaScript[edit]

alert("knight".slice(1));       // strip first character
alert("socks".slice(0, -1));    // strip last character
alert("brooms".slice(1, -1));   // strip both first and last characters

jq[edit]

jq uses 0-based indexing, so [1:] yields all but the first character, it being understood that data strings in jq are JSON strings. [0:-1], which can be abbreviated to [:-1], yields all but the last character, and so on. Here are some examples:
"一二三四五六七八九十"[1:]' => "二三四五六七八九十"

"一二三四五六七八九十"[:-1]' => "一二三四五六七八九"

"一二三四五六七八九十"[1:-1]' => "二三四五六七八九"

"a"[1:-1] # => ""
Recent versions of jq also have regular expression support, with named captures. This leads to many other possibilities, e.g.
"abc" | capture( ".(?<monkey>.*)." ).monkey => "b"

Julia[edit]

julia> "My String"[2:end] # without first character
"y String"

julia> "My String"[1:end-1] # without last character
"My Strin"

julia> "My String"[2:end-1] # without first and last characters
"y Strin"

K[edit]

K provides the system function _di to delete an element at a specified index. The following code is implemented using this feature.

    s: "1234567890"
"1234567890"
    s _di 0 /Delete 1st character
"234567890"
    s _di -1+#s /Delete last character
"123456789"
    (s _di -1+#s) _di 0 /String with both 1st and last character removed
"23456789"

Another way to implement without using the above system function:

    s: "1234567890"
"1234567890"
    1 _ s  /Delete 1st character
"234567890"
    -1 _ s /Delete last character
"123456789"
    1 - -1 _ s /Delete 1st and last character
"23456789"

Kotlin[edit]

// version 1.0.6
fun main(args: Array<String>) {
    val s = "Rosetta"
    println(s.drop(1))
    println(s.dropLast(1))
    println(s.drop(1).dropLast(1))
}
Output:
osetta
Rosett
osett

Lambdatalk[edit]

{def R rosetta}                               -> rosetta

{W.rest {R}}                                  ->  osetta
{W.reverse {W.rest {W.reverse {R}}}}          -> rosett
{W.rest {W.reverse {W.rest {W.reverse {R}}}}} ->  osett

or 

{W.slice 1 {W.length {R}} {R}}                ->  osetta
{W.slice 0 {- {W.length {R}} 1} {R}}          -> rosett
{W.slice 1 {- {W.length {R}} 1} {R}}          ->  osett

{def J ストリング}                              -> ストリング

{W.rest {J}}                                  ->   トリング
{W.reverse {W.rest {W.reverse {J}}}}          -> ストリン
{W.rest {W.reverse {W.rest {W.reverse {J}}}}} ->   トリン

Lasso[edit]

local(str = 'The quick grey rhino jumped over the lazy green fox.')

// String with first character removed
string_remove(#str,-startposition=1,-endposition=1)

// String with last character removed
string_remove(#str,-startposition=#str->size,-endposition=#str->size)

// String with both the first and last characters removed
string_remove(string_remove(#str,-startposition=#str->size,-endposition=#str->size),-startposition=1,-endposition=1)
Output:
he quick grey rhino jumped over the lazy green fox.
The quick grey rhino jumped over the lazy green fox
he quick grey rhino jumped over the lazy green fox
local(mystring = 'ÅÜÄÖカ')

#mystring -> remove(1,1)
#mystring
'<br />'
#mystring -> remove(#mystring -> size,1)
#mystring
'<br />'
#mystring -> remove(1,1)& -> remove(#mystring -> size,1)
#mystring

-> ÜÄÖカ

ÜÄÖ

Ä ==Lasso==

local(str = 'The quick grey rhino jumped over the lazy green fox.')

// String with first character removed
string_remove(#str,-startposition=1,-endposition=1)
// > he quick grey rhino jumped over the lazy green fox.

// String with last character removed
string_remove(#str,-startposition=#str->size,-endposition=#str->size)
// > The quick grey rhino jumped over the lazy green fox

// String with both the first and last characters removed
string_remove(string_remove(#str,-startposition=#str->size,-endposition=#str->size),-startposition=1,-endposition=1)
// > he quick grey rhino jumped over the lazy green fox

Liberty BASIC[edit]

string$ = "Rosetta Code"
Print Mid$(string$, 2)
Print Left$(string$, (Len(string$) - 1))
Print Mid$(string$, 2, (Len(string$) - 2))

LiveCode[edit]

put "pple" into x
answer char 2 to len(x) of x // pple
answer char 1 to -2 of x  // ppl
answer char 2 to -2 of x // ppl

Locomotive Basic[edit]

10 a$="knight":b$="socks":c$="brooms"
20 PRINT MID$(a$,2)
30 PRINT LEFT$(b$,LEN(b$)-1)
40 PRINT MID$(c$,2,LEN(c$)-2)

[edit]

make "s "|My string|
print butfirst :s
print butlast :s
print butfirst butlast :s

Logtalk[edit]

Using atoms for representing strings:

:- object(top_and_tail).

    :- public(test/1).
    test(String) :-
        sub_atom(String, 1, _, 0, MinusTop),
        write('String with first character cut: '), write(MinusTop), nl,
        sub_atom(String, 0, _, 1, MinusTail),
        write('String with last character cut: '), write(MinusTail), nl,
        sub_atom(String, 1, _, 1, MinusTopAndTail),
        write('String with first and last characters cut: '), write(MinusTopAndTail), nl.

:- end_object.

Sample output:

| ?- top_and_tail::test('Rosetta').
String with first character cut: osetta
String with last character cut: Rosett
String with first and last characters cut: osett
yes

Lua[edit]

print (string.sub("knights",2))    -- remove the first character
print (string.sub("knights",1,-2))    -- remove the last character
print (string.sub("knights",2,-2))    -- remove the first and last characters

Maple[edit]

There are several ways to do this. The first is, I think, the simplest.

> s := "some string":
> s[2..-1];
                              "ome string"

> s[1..-2];
                              "some strin"

> s[2..-2];
                              "ome strin"

The same functionality exists in the form of a procedure:

> substring( s, 2 .. -1 );
                              "ome string"

> substring( s, 1 .. -2 );
                              "some strin"

> substring( s, 2 .. -2 );
                              "ome strin"

Furthermore, there is a slightly different version in the "StringTools" package:

> use StringTools in
>     SubString( s, 2 .. -1 );
>     SubString( s, 1 .. -1 );
>     SubString( s, 2 .. -2 ) 
> end use;
                              "ome string"

                             "some string"

                              "ome strin"

(The difference between "substring" and "StringTools:-SubString" lies in how each treats a name as input; the former returns a name, while the latter returns a string.)

Mathematica/Wolfram Language[edit]

StringDrop["input string",1]
StringDrop["input string",-1]
StringTake["input string",{2,-2}]

MATLAB / Octave[edit]

The following case will not handle UTF-8. However, Matlab supports conversion of utf-8 to utf-16 using native2unicode().

 
    % String with first character removed
    str(2:end)
    % String with last character removed
    str(1:end-1)
    % String with both the first and last characters removed 
    str(2:end-1)

MiniScript[edit]

test = "This thing"
print test[1:]
print test[:-1]
print test[1:-1]
Output:
his thing
This thin
his thin

MIPS Assembly[edit]

Thanks to Chibialiens for the header/footer, font, and print routines.

.include "\SrcAll\Header.asm"
.include "\SrcAll\BasicMacros.asm"
.include "\SrcALL\AdvancedMacros.asm"
.include "\SrcALL\MemoryMap.asm"

; .definelabel UserRam,0xA0010000		(this is defined in the header)

CursorX equ 0x100 ;offset from label UserRam
CursorY equ 0x101 ;offset from label UserRam

main:
	jal Cls
	nop
	
	la a0,MyString
	la a1,UserRam+0x1000
	push a0
	push a1
		jal strcpy
		addiu a0,1		;branch delay slot - increment base address prior to branching
	pop a0				;deliberately pop in the "wrong order"
	pop a1				;because printString uses $a0
	
	jal PrintString
	nop
	jal NewLine
	nop
	
	
	
	la a0,MyString
	la a1,UserRam+0x1000
	
	push a0
	push a1
		jal strcpy
		nop				;branch delay slot
		;after a strcpy, a0/a1 both point to the null terminator
		subiu a1,1
		move t0,zero
		sb t0,(a1)
		.ifdef buildPSX
			nop		;load delay slot
		.endif
	pop a0
	pop a1
	
	jal PrintString
	nop
	jal NewLine
	nop
	
	la a0,MyString
	la a1,UserRam+0x1000
	
	push a0
	push a1
		jal strcpy
		addiu a0,1	;branch delay slot
		;after a strcpy, a0/a1 both point to the null terminator
		subiu a1,1
		move t0,zero
		sb t0,(a1)
		.ifdef buildPSX
			nop		;load delay slot
		.endif
	pop a0
	pop a1
	
	jal PrintString
	nop
	jal NewLine
	nop
	
	
halt:
	nop
	j halt
	nop
	
	
MyString:
	.ascii "Hello World"
	.byte 0
	.align 4
	
MyFont:

.ifdef buildn64				
	.incbin "\ResN64\ChibiAkumas.fnt"
.endif
.ifdef buildPSX				
	.incbin "\ResPSX\ChibiAkumas.fnt"
.endif

.include "\SrcALL\graphics.asm"
.include "\SrcAll\monitor.asm"
.include "\SrcALL\Multiplatform_Math_Integer.asm"
.include "\SrcALL\BasicFunctions_v2.asm"
.include "\SrcN64\Footer.asm"
Output:
ello World
Hello Worl
ello Worl

Screenshot of PlayStation 1 Emulator

Neko[edit]

Neko strings are mutable, fixed length buffers. The $ssize builtin uses the allocated size, not any internal sentinel terminator byte. With literals, the allocated size is the size of the data between quotes, i.e. no NUL byte appended.

$ssub sub-string takes string, position (zero-relative), length arguments.

/**
 Subtring/Top-Tail in Neko
*/

var data = "[this is a test]"
var len = $ssize(data)

$print(data, "\n")
$print($ssub(data, 1, len - 1), "\n")
$print($ssub(data, 0, len - 1), "\n")
$print($ssub(data, 1, len - 2), "\n")
Output:
prompt$ nekoc toptail.neko
prompt$ neko toptail.n
[this is a test]
this is a test]
[this is a test
this is a test

Nemerle[edit]

using System;
using System.Console;

module RemoveChars
{
    Main() : void
    {
        def str = "*A string*";
        def end = str.Remove(str.Length - 1);  // from pos to end
        def beg = str.Remove(0, 1);            // start pos, # of chars to remove
        def both = str.Trim(array['*']);       // with Trim() you need to know what char's you're removing
        
        WriteLine($"$str -> $beg -> $end -> $both");
    }
}

NetRexx[edit]

/**********************************************************************
* 02.08.2013 Walter Pachl  translated from REXX
**********************************************************************/
z = 'abcdefghijk'
l=z.length()
say '                  the original string =' z
If l>=1 Then Do
  Say 'string first        character removed =' z.substr(2)
  say 'string         last character removed =' z.left(l-1)
  End
If l>=2 Then
  Say 'string first & last character removed =' z.substr(2,l-2)

NewLISP[edit]

(let (str "rosetta")
  ;; strip first char
  (println (1 str))
  ;; strip last char
  (println (0 -1 str))
  ;; strip both first and last characters
  (println (1 -1 str)))

Nim[edit]

import unicode

let s = "Hänsel  ««: 10,00€"
echo "Original: ", s
echo "With first character removed: ", s.runeSubStr(1)
echo "With last character removed: ", s.runeSubStr(0, s.runeLen - 1)
echo "With first and last characters removed: ", s.runeSubStr(1, s.runeLen - 2)
# Using the runes type and slices
let r = s.toRunes
echo "With first and last characters removed (other way): ", r[1 .. ^2]
Output:
Original: Hänsel  ««: 10,00€
With first character removed: änsel  ««: 10,00€
With last character removed: Hänsel  ««: 10,00
With first and last characters removed: änsel  ««: 10,00
With first and last characters removed (other way): änsel  ««: 10,00

Objeck[edit]

bundle Default {
   class TopTail {
      function : Main(args : System.String[]) ~ Nil {
         string := "test";
         string->SubString(1, string->Size() - 1)->PrintLine();
         string->SubString(string->Size() - 1)->PrintLine();
         string->SubString(1, string->Size() - 2)->PrintLine();
      }
   }
}

OCaml[edit]

let strip_first_char str =
  if str = "" then "" else
  String.sub str 1 ((String.length str) - 1)

let strip_last_char str =
  if str = "" then "" else
  String.sub str 0 ((String.length str) - 1)

let strip_both_chars str =
  match String.length str with
  | 0 | 1 | 2 -> ""
  | len -> String.sub str 1 (len - 2)

let () =
  print_endline (strip_first_char "knight");
  print_endline (strip_last_char "socks");
  print_endline (strip_both_chars "brooms");
;;

Oforth[edit]

: topAndTail(s)
    s right(s size 1-) println
    s left(s size 1-) println
    s extract(2, s size 1- ) println ;
Output:
topAndTail("MyString")
yString
MyStrin
yStrin

PARI/GP[edit]

df(s)=concat(vecextract(Vec(s),1<<#s-2));
dl(s)=concat(vecextract(Vec(s),1<<(#s-1)-1));
db(s)=concat(vecextract(Vec(s),1<<(#s-1)-2));

Pascal[edit]

See also Delphi

Works with: Extended Pascal
program topAndTail(output);
var
	line: string(20);
begin
	line := 'ABCDEF';
	
	if length(line) > 1 then
	begin
		{ string with first character removed }
		writeLn(subStr(line, 2));
		{ index range expression: only possible for strings }
		{ _not_ designated `bindable` [e.g. `bindable string(20)`] }
		writeLn(line[2..length(line)]);
		
		{ string with last character removed }
		
		writeLn(subStr(line, 1, length(line) - 1));
		{ only legal with non-bindable strings: }
		writeLn(line[1..length(line)-1])
	end;
	
	{ string with both the first and last characters removed }
	if length(line) > 2 then
	begin
		writeLn(subStr(line, 2, length(line) - 2));
		{ only for non-bindable strings: }
		writeLn(line[2..length(line)-1])
	end
end.
It is imperative that firstCharacterIndex + substringLength specified to subStr(source, firstCharacterIndex, substringLength) must be valid index in source. Therefore you need to perform checks beforehand.

Perl[edit]

print substr("knight",1), "\n";        # strip first character
print substr("socks", 0, -1), "\n";    # strip last character
print substr("brooms", 1, -1), "\n";   # strip both first and last characters

In perl, we can also remove the last character from a string variable with the chop function:

$string = 'ouch';
$bits = chop($string);       # The last letter is returned by the chop function
print $bits;        # h
print $string;      # ouc    # See we really did chop the last letter off

Phix[edit]

Library: Phix/basics
constant s = "(test)"
?s[2..-1]
?s[1..-2]
?s[2..-2]
Output:
"test)"
"(test"
"test"

Phixmonti[edit]

include ..\Utilitys.pmt

"(test)"
dup 1 del ?
dup -1 del ?
dup 1 del -1 del ?

Or...

include ..\Utilitys.pmt

"(test)"
len 1 - 2 swap slice ?
len 1 - 1 swap slice ?
len 2 - 2 swap slice ?

PHP[edit]

<?php
echo substr("knight", 1), "\n";       // strip first character
echo substr("socks", 0, -1), "\n";    // strip last character
echo substr("brooms", 1, -1), "\n";   // strip both first and last characters
?>

Picat[edit]

Functions[edit]

go =>
  test("upraisers"),
  test("Δημοτική"),
  nl.

test(S) =>
  println(s=S),
  println(butfirst=S.slice(2)),
  println(butfirst=S.tail),
  println(butfirst=S[2..S.len]),  
  
  println(butlast=S.but_last()),
  
  println(butfirst_butlast=S.tail.but_last),
  println(butfirst_butlast=slice(S,2,S.length-1)),
  println(butfirst_butlast=[S[I] : I in 2..S.length-1]),
  println(butfirst_butlast=S[2..S.length-1]),  
  nl.

but_last(S)  = S.slice(1,S.length-1).
Output:
s = upraisers
butfirst = praisers
butfirst = praisers
butfirst = praisers
butlast = upraiser
butfirst_butlast = praiser
butfirst_butlast = praiser
butfirst_butlast = praiser
butfirst_butlast = praiser

s = Δημοτική
butfirst = ημοτική
butfirst = ημοτική
butfirst = ημοτική
butlast = Δημοτικ
butfirst_butlast = ημοτικ
butfirst_butlast = ημοτικ
butfirst_butlast = ημοτικ
butfirst_butlast = ημοτικ

Using append/3[edit]

Translation of: Prolog
go2 =>
  test2("upraisers"),
  nl,
  test2("Δημοτική"),
  nl.

test2(L) :-
    L = [_|L1],
    remove_last(L, L2),
    remove_last(L1, L3),
    writef("Original string          : %s\n", L),
    writef("Without first char       : %s\n", L1),
    writef("Without last char        : %s\n", L2),
    writef("Without first/last chars : %s\n", L3).
 
remove_last(L, LR) :-
    append(LR, [_], L).
Output:
Original string          : upraisers
Without first char       : praisers
Without last char        : upraiser
Without first/last chars : praiser

Original string          : Δημοτική
Without first char       : ημοτική
Without last char        : Δημοτικ
Without first/last chars : ημοτικ

PicoLisp[edit]

: (pack (cdr (chop "knight")))         # Remove first character
-> "night"

: (pack (head -1 (chop "socks")))      # Remove last character
-> "sock"

: (pack (cddr (rot (chop "brooms"))))  # Remove first and last characters
-> "room"

PL/I[edit]

declare s character (100) varying;
s = 'now is the time to come to the aid of the party';
if length(s) <= 2 then stop;
put skip list ('First character removed=' || substr(s,2) );
put skip list ('Last character removed='  || substr(s, 1, length(s)-1) );
put skip list ('One character from each end removed=' ||
   substr(s, 2, length(s)-2) );

OUTPUT:

First character removed=ow is the time to come to the aid of the party
Last character removed=now is the time to come to the aid of the part 
One character from each end removed=ow is the time to come to the aid of the part 

Plain English[edit]

To run:
Start up.
Demonstrate removing the first and last characters from "Rosetta Code".
Wait for the escape key.
Shut down.

To demonstrate removing the first and last characters from a string:
Slap a substring on the string.
Add 1 to the substring's first.
Write the substring on the console.
Subtract 1 from the substring's first.
Subtract 1 from the substring's last.
Write the substring on the console.
Add 1 to the substring's first.
Write the substring on the console.
Output:
osetta Code
Rosetta Cod
osetta Cod

PowerShell[edit]

Works with: PowerShell version 4.0

First method[edit]

$string = "top and tail"
$string
$string.Substring(1)
$string.Substring(0, $string.Length - 1)
$string.Substring(1, $string.Length - 2)

Second method[edit]

$string = "top and tail"
$string
$string[1..($string.Length - 1)] -join ""
$string[0..($string.Length - 2)] -join ""
$string[1..($string.Length - 2)] -join ""

Output:

top and tail
op and tail
top and tai
op and tai

Prolog[edit]

Works with SWI-Prolog.

remove_first_last_chars :-
    L = "Rosetta",
    L = [_|L1],
    remove_last(L, L2),
    remove_last(L1, L3),
    writef('Original string      : %s\n', [L]),
    writef('Without first char       : %s\n', [L1]),
    writef('Without last char        : %s\n', [L2]),
    writef('Without first/last chars : %s\n', [L3]).

remove_last(L, LR) :-
    append(LR, [_], L).

Output :

 ?- remove_first_last_chars.
Original string          : Rosetta
Without first char       : osetta
Without last char        : Rosett
Without first/last chars : osett
true.

PureBasic[edit]

If OpenConsole()  
  PrintN(Right("knight", Len("knight") - 1))  ;strip the first letter
  PrintN(Left("socks", Len("socks")- 1))      ;strip the last letter
  PrintN(Mid("brooms", 2, Len("brooms") - 2)) ;strip both the first and last letter
  
  Print(#CRLF$ + #CRLF$ + "Press ENTER to exit"): Input()
  CloseConsole()
EndIf

Sample output:

night
sock
room

Python[edit]

print "knight"[1:]     # strip first character
print "socks"[:-1]     # strip last character
print "brooms"[1:-1]   # strip both first and last characters


Or, composing atomic functional expressions for these slices:

from functools import (reduce)


def main():
    for xs in transpose(
        (chunksOf(3)(
            ap([tail, init, compose(init)(tail)])(
                ['knights', 'socks', 'brooms']
            )
        ))
    ):
        print(xs)


# GENERIC -------------------------------------------------

# tail :: [a] -> [a]
def tail(xs):
    return xs[1:]


# init::[a] - > [a]
def init(xs):
    return xs[:-1]


# ap (<*>) :: [(a -> b)] -> [a] -> [b]
def ap(fs):
    return lambda xs: reduce(
        lambda a, f: a + reduce(
            lambda a, x: a + [f(x)], xs, []
        ), fs, []
    )


# chunksOf :: Int -> [a] -> [[a]]
def chunksOf(n):
    return lambda xs: reduce(
        lambda a, i: a + [xs[i:n + i]],
        range(0, len(xs), n), []
    ) if 0 < n else []


# compose (<<<) :: (b -> c) -> (a -> b) -> a -> c
def compose(g):
    return lambda f: lambda x: g(f(x))


# transpose :: [[a]] -> [[a]]
def transpose(xs):
    return list(map(list, zip(*xs)))


if __name__ == '__main__':
    main()
Output:
['nights', 'knight', 'night']
['ocks', 'sock', 'ock']
['rooms', 'broom', 'room']

Quackery[edit]

As a dialogue in the Quackery shell.

/O> $ "callipygian"
... say "original string:   "
... dup echo$ cr
... say "without head:      "
... dup behead drop echo$ cr
... say "without tail:      "
... -1 split drop dup echo$ cr
... say "topped and tailed: "
... behead drop echo$ cr
... 
original string:   callipygian
without head:      allipygian
without tail:      callipygia
topped and tailed: allipygia

Racket[edit]

#lang racket

(define str "ストリング")

(substring str 1)
(substring str 0 (sub1 (string-length str)))
(substring str 1 (sub1 (string-length str)))

Output:

"トリング"
"ストリン"
"トリン"

Raku[edit]

(formerly Perl 6)

Raku provides both functional and method forms of substr. Note that, unlike in Perl 5, offsets from the end do not use negative numbers, but instead require a function expressing the negative offset relative to the length parameter, which is supplied by the operator. The form *-1 is just a simple way to write such a function.

We use musical sharps and flats to illustrate that Raku is comfortable with characters from any Unicode plane.

my $s = '𝄪♯♮♭𝄫';

print qq:to/END/;
    Original:
    $s

    Remove first character:
    { substr($s, 1) }
    { $s.substr(1) }

    Remove last character:
    { substr($s, 0, *-1) }
    { $s.substr( 0, *-1) }
    { $s.chop }

    Remove first and last characters:
    { substr($s, 1, *-1) }
    { $s.substr(1, *-1) }
    END
Output:
Original:
𝄪♯♮♭𝄫

Remove first character:
♯♮♭𝄫
♯♮♭𝄫
 
Remove last character:
𝄪♯♮♭
𝄪♯♮♭
𝄪♯♮♭
 
Remove first and last characters:
♯♮♭
♯♮♭

Raven[edit]

define println use $s
   $s print "\n" print

"0123456789" as $str

define offTheTop use $s
   $s 1 0x7FFFFFFF extract

define offTheTail use $s
   $s 0 -1 extract


$str offTheTop  println
$str offTheTail println
$str offTheTop  offTheTail  println
Output:
123456789
012345678
12345678

REXX[edit]

error prone[edit]

This REXX version is error prone in that if the string is less than two characters, then the   left   and/or   substr   BIFs will fail   (because of an invalid length specified).

/*REXX program demonstrates removal of  1st/last/1st-and-last  characters from a string.*/
@ = 'abcdefghijk'
say '                  the original string ='  @
say 'string first        character removed ='  substr(@, 2)
say 'string         last character removed ='  left(@, length(@) -1)
say 'string first & last character removed ='  substr(@, 2, length(@) -2)
                                                 /*stick a fork in it,  we're all done. */
   /* ╔═══════════════════════════════════════════════════════════════════════════════╗
      ║  However, the original string may be null or exactly one byte in length which ║
      ║  will cause the  BIFs to fail because of  either zero  or  a negative length. ║
      ╚═══════════════════════════════════════════════════════════════════════════════╝ */

output

                  the original string = abcdefghijk
string first        character removed = bcdefghijk
string         last character removed = abcdefghij
string first & last character removed = bcdefghij

robust version[edit]

This REXX version correctly handles a string of zero (null) or one byte.

/*REXX program demonstrates removal of  1st/last/1st-and-last  characters from a string.*/
@ = 'abcdefghijk'
say '                  the original string ='  @
say 'string first        character removed ='  substr(@, 2)
say 'string         last character removed ='  left(@, max(0, length(@) -1))
say 'string first & last character removed ='  substr(@, 2, max(0, length(@) -2))
exit                                             /*stick a fork in it,  we're all done. */

                              /* [↓]  an easier to read version using a length variable.*/
@ = 'abcdefghijk'
L=length(@)
say '                  the original string ='  @
say 'string first        character removed ='  substr(@, 2)
say 'string         last character removed ='  left(@, max(0, L-1) )
say 'string first & last character removed ='  substr(@, 2, max(0, L-2) )

output   is the same as the 1st REXX version.

faster version[edit]

This REXX version is faster   (uses   parse   instead of multiple BIFs).

/*REXX program demonstrates removal of  1st/last/1st-and-last  characters from a string.*/
@ = 'abcdefghijk'
say '                  the original string =' @

parse var @ 2 z
say 'string first        character removed =' z

m=length(@) - 1
parse var @ z +(m)
say 'string         last character removed =' z

n=length(@) - 2
parse var @ 2 z +(n)
if n==0  then z=                                /*handle special case of a length of 2.*/
say 'string first & last character removed =' z /*stick a fork in it,  we're all done. */

output   is the same as the 1st REXX version.

Ring[edit]

aString = "1Welcome to the Ring Programming Language2"
see substr(aString,2,len(aString)-1) + nl +
substr(aString,1,len(aString)-1) + nl +
substr(aString,2,len(aString)-2) + nl

RPL[edit]

Translation of: Python
"Knight" 2 OVER SIZE SUB
"Socks" 1 OVER SIZE 1 - SUB
"Brooms" 2 OVER SIZE 1 - SUB
Output:
3: night
2: Sock
1: room

Ruby[edit]

puts "knight"[1..-1]   # strip first character
puts "socks"[0..-2]    # strip last character
puts "socks".chop      # alternate way to strip last character
puts "brooms"[1..-2]   # strip both first and last characters
puts "与今令"[1..-2]    # => 今

Run BASIC[edit]

s$  = "Run BASIC"
print mid$(s$,2)             'strip first
print left$(s$,len(s$) -1)   'strip last
print mid$(s$,2,len(s$) -2)  'strip first and last

Rust[edit]

One possibility is to modify the owned string representation:

fn main() {
    let s = String::from("žluťoučký kůň");

    let mut modified = s.clone();
    modified.remove(0);
    println!("{}", modified);

    let mut modified = s.clone();
    modified.pop();
    println!("{}", modified);

    let mut modified = s;
    modified.remove(0);
    modified.pop();
    println!("{}", modified);
}

Another possibility is to cut a string slice (moreover, this version assumes nothing about the string length):

fn main() {
    let s = "žluťoučký kůň";

    println!(
        "{}",
        s.char_indices()
            .nth(1)
            .map(|(i, _)| &s[i..])
            .unwrap_or_default()
    );

    println!(
        "{}",
        s.char_indices()
            .nth_back(0)
            .map(|(i, _)| &s[..i])
            .unwrap_or_default()
    );

    println!(
        "{}",
        s.char_indices()
            .nth(1)
            .and_then(|(i, _)| s.char_indices().nth_back(0).map(|(j, _)| i..j))
            .map(|range| &s[range])
            .unwrap_or_default()
    );
}

Scala[edit]

Library: Scala
println("knight".tail)               // strip first character
println("socks".init)         // strip last character
println("brooms".tail.init)   // strip both first and last characters

Scheme[edit]

(define (string-top s)
  (if (string=? s "") s (substring s 0 (- (string-length s) 1))))

(define (string-tail s)
  (if (string=? s "") s (substring s 1 (string-length s))))

(define (string-top-tail s)
  (string-tail (string-top s)))

sed[edit]

Remove the first character:

s/.//

Remove the last character:

s/.$//

Remove the first and the last character in one step (a bit more complex, to correctly handle single-character strings):

s/.\(\(.*\).\)\{0,1\}/\2/

Seed7[edit]

$ include "seed7_05.s7i";

const proc: main is func
  local
    const string: stri is "upraisers";
  begin
    writeln("Full string:   " <& stri);
    writeln("Without first: " <& stri[2 ..]);
    writeln("Without last:  " <& stri[.. pred(length(stri))]);
    writeln("Without both:  " <& stri[2 .. pred(length(stri))]);
  end func;

Output:

Full string:   upraisers
Without first: praisers
Without last:  upraiser
Without both:  praiser

SenseTalk[edit]

set message to peaceSymbol & "Peace!"
put message
put characters second to last of message
put characters 1 to -2 of message
put the second to penultimate characters of message

Output:

☮Peace!
Peace!
☮Peace
Peace

Sidef[edit]

Strip any characters:

say "knight".substr(1);       # strip first character
say "socks".substr(0, -1);    # strip last character
say "brooms".substr(1, -1);   # strip both first and last characters
say "与今令".substr(1, -1);    # => 今
Output:
night
sock
room
今

Strip graphemes:

var gstr = "J\x{332}o\x{332}s\x{332}e\x{301}\x{332}";
say gstr-/^\X/;                    # strip first grapheme
say gstr-/\X\z/;                   # strip last grapheme
say gstr.sub(/^\X/).sub(/\X\z/);   # strip both first and last graphemes
Output:
o̲s̲é̲
J̲o̲s̲
o̲s̲

Smalltalk[edit]

Works with: GNU Smalltalk

These all use built-in collection methods that will work with any kind of ordered collection, not just Strings. There is no error checking. They will fail if the string is not at least two characters long.

s := 'upraisers'.
Transcript show: 'Top: ', s allButLast; nl. 
Transcript show: 'Tail: ', s allButFirst; nl.   
Transcript show: 'Without both: ', s allButFirst allButLast; nl.    
Transcript show: 'Without both using substring method: ', (s copyFrom: 2 to: s size - 1); nl.
Output:
Top: upraiser                                                                                                                           
Tail: praisers                                                                                                                          
Without both: praiser                                                                                                                   
Without both using substring method: praiser 

SNOBOL4[edit]

     "knight" len(1) rem . output       ;* strip first character
     "socks" rtab(1) . output           ;* strip last character
     "brooms" len(1) rtab(1) . output   ;* strip both first and last characters

Standard ML[edit]

- val str = "abcde";
val str = "abcde" : string
- String.substring(str, 1, String.size str - 1);
val it = "bcde" : string
- String.substring(str, 0, String.size str - 1);
val it = "abcd" : string
- String.substring(str, 1, String.size str - 2);
val it = "bcd" : string

Swift[edit]

Swift strings are native Unicode strings and do not index through the code points. Swift's String.Index refers to true Unicode characters (Unicode grapheme clusters). Swift standard library has generic functionality that not only works with strings, but also with any type that conforms to relevant protocols. The first method presented here uses generic functions from Swift standard library:

let txt = "0123456789"
println(dropFirst(txt))
println(dropLast(txt))
println(dropFirst(dropLast(txt)))
Output:
123456789
012345678
12345678

The other method is slicing by range subscripting:

let txt = "0123456789"
println(txt[txt.startIndex.successor() ..< txt.endIndex])
println(txt[txt.startIndex             ..< txt.endIndex.predecessor()])
println(txt[txt.startIndex.successor() ..< txt.endIndex.predecessor()])
Output:
123456789
012345678
12345678

Another way is mutating the string:

var txt = "0123456789"
txt.removeAtIndex(txt.startIndex)
txt.removeAtIndex(txt.endIndex.predecessor())

The above functions return what they remove. You can also extend String type and define BASIC-style functions:

extension String {
    
    /// Ensure positive indexes
    
    private func positive(index: Int) -> Int {
        
        if index >= 0 { return index }
        
        return count(self) + index
    }
    
    /// Unicode character by zero-based integer (character) `index`
    /// Supports negative character index to count from end. (-1 returns character before last)
    
    subscript(index: Int) -> Character {
        
        return self[advance(startIndex, positive(index))]
    }
    
    /// String slice by character index
    
    subscript(range: Range<Int>) -> String {
        
        return self[advance(startIndex, range.startIndex) ..<
                    advance(startIndex, range.endIndex, endIndex)]
    }
    
    /// Left portion of text to `index`
    
    func left(index : Int) -> String {
        
        return self[0 ..< positive(index)]
    }
    
    /// Right portion of text from `index`
    
    func right(index : Int) -> String{
        
        return self[positive(index) ..< count(self)]
    }
    
    /// From `start` index until `end` index
    
    func mid(start: Int, _ end: Int) -> String {
        
        return self[positive(start) ..< positive(end)]
    }
    
}

let txt = "0123456789"

txt.right(1) // Right part without first character
txt.left(-1) // Left part without last character
txt.mid(1,-1) // Middle part without first and last character

Tcl[edit]

puts [string range "knight" 1 end];       # strip first character
puts [string range "write" 0 end-1];        # strip last character
puts [string range "brooms" 1 end-1];       # strip both first and last characters

TorqueScript[edit]

String with first character removed

 %string = "Moo";
 %string = getSubStr(%string, 1, strLen(%string) - 1);
 echo(%string);

String with last character removed

 %string = "Moo";
 %string = getSubStr(%string, 0, strLen(%string) - 1);
 echo(%string);

String with both the first and last characters removed

 %string = "Moo";
 %string = getSubStr(%string, 1, strLen(%string) - 2);
 echo(%string);


Output:

 oo
 Mo
 o

TUSCRIPT[edit]

$$ MODE TUSCRIPT
str="upraisers"
str1=EXTRACT (str,2,0)
str2=EXTRACT (str,0,-1)
str3=EXTRACT (str,2,-1)
PRINT str
PRINT str1
PRINT str2
PRINT str3

Output:

upraisers
praisers
upraiser
upraiser 

UNIX Shell[edit]

First or last character:

str='abcdefg'
echo "${str#?}"   # Remove first char
echo "${str%?}"   # Remove last char

First and last character:

Only zsh supports nested string manipulation.
echo ${${str#?}%?}   # Remove first & last chars
bash and ksh, use substring expansion, from character index 1 for length of (string length) minus 2
echo "${s:1:${#s}-2}"
POSIX shells like dash, need a temp variable
tmp=${s#?}; tmp=${tmp%?}; echo "$tmp"

Vala[edit]

// declare test string
string s = "Hello, world!";
// remove first letter
string s_first = s[1:s.length];
//remove last letter
string s_last = s[0:s.length - 1];
// remove first and last letters
string s_first_last = s[1:s.length - 1];

VBScript[edit]

Function TopNTail(s,mode)
    Select Case mode
        Case "top"
            TopNTail = Mid(s,2,Len(s)-1)
        Case "tail"
            TopNTail = Mid(s,1,Len(s)-1)
        Case "both"
            TopNTail = Mid(s,2,Len(s)-2)
    End Select
End Function

WScript.Echo "Top: UPRAISERS = " & TopNTail("UPRAISERS","top")
WScript.Echo "Tail: UPRAISERS = " & TopNTail("UPRAISERS","tail")
WScript.Echo "Both: UPRAISERS = " & TopNTail("UPRAISERS","both")
Output:
Top: UPRAISERS = PRAISERS
Tail: UPRAISERS = UPRAISER
Both: UPRAISERS = PRAISER

Wren[edit]

Library: Wren-str

As Wren's string slicing and other built-in methods generally work at the byte level, we use the above module for this task which works at the code-point level.

import "/str" for Str

var a = "Beyoncé"
var b = Str.delete(a, 0)
var len = a.codePoints.count
var c = Str.delete(a, len-1)
var d = Str.delete(c, 0)
for (e in [a, b, c, d]) System.print(e)
Output:
Beyoncé
eyoncé
Beyonc
eyonc

XPL0[edit]

include c:\cxpl\stdlib;
char S, P;
[S:= "Smiles";
Text(0, S+1);           \first character removed
CrLf(0);
P:= S + StrLen(S) - 2;  \point to last character in string
P(0):= P(0) ! $80;      \set the MSb on the last character
Text(0, S);             \last character removed
CrLf(0);
Text(0, S+1);           \first and last characters removed
CrLf(0);
]

Output:

miles
Smile
mile

zkl[edit]

"Smiles"[1,*]  //-->miles
"Smiles"[0,-1] //-->Smile
"Smiles"[1,-1] //-->mile

[] format is [offset (zero based), length]. * means "to the end", a negative number means from the end.

ZX Spectrum Basic[edit]

10 PRINT FN f$("knight"): REM strip the first letter. You can also write PRINT "knight"(2 TO)
20 PRINT FN l$("socks"): REM strip the last letter
30 PRINT FN b$("brooms"): REM strip both the first and last letter
100 STOP

9000 DEF FN f$(a$)=a$(2 TO LEN(a$))
9010 DEF FN l$(a$)=a$(1 TO LEN(a$)-(1 AND (LEN(a$)>=1)))
9020 DEF FN b$(a$)=FN l$(FN f$(a$))