Words from neighbour ones: Difference between revisions
No edit summary |
|||
Line 1,506: | Line 1,506: | ||
=={{header|Vlang}}== |
=={{header|Vlang}}== |
||
{{trans|AutoHotkey}} |
{{trans|AutoHotkey}} |
||
<lang vlang> |
<lang vlang>import os |
||
fn main() { |
|||
mut result :='' |
mut result :='' |
||
unixdict := os.read_file('./unixdict.txt') or {panic('file not found')} |
unixdict := os.read_file('./unixdict.txt') or {panic('file not found')} |
Revision as of 08:48, 1 August 2022
- Task
Use the dictionary unixdict.txt
Ignore any word in the dictionary whose length is less than 9.
Let's take the words from next characters:
1 <= n < (dictionary length) - 9.
char1 = 1st character of nth word.
char2 = 2nd character of (n+1)th word.
char3 = 3rd character of (n+2)th word.
⋮
char9 = 9th character of (n+8)th word.
Concatenate (append) the nine characters by:
newword = char1 + char2 + char3 + ... + char9
If newword is in the dictionary, then show on this page.
Length of newword = 9
- Metrics
- Counting
- Word frequency
- Letter frequency
- Jewels and stones
- I before E except after C
- Bioinformatics/base count
- Count occurrences of a substring
- Count how many vowels and consonants occur in a string
- Remove/replace
- XXXX redacted
- Conjugate a Latin verb
- Remove vowels from a string
- String interpolation (included)
- Strip block comments
- Strip comments from a string
- Strip a set of characters from a string
- Strip whitespace from a string -- top and tail
- Strip control codes and extended characters from a string
- Anagrams/Derangements/shuffling
- Word wheel
- ABC problem
- Sattolo cycle
- Knuth shuffle
- Ordered words
- Superpermutation minimisation
- Textonyms (using a phone text pad)
- Anagrams
- Anagrams/Deranged anagrams
- Permutations/Derangements
- Find/Search/Determine
- ABC words
- Odd words
- Word ladder
- Semordnilap
- Word search
- Wordiff (game)
- String matching
- Tea cup rim text
- Alternade words
- Changeable words
- State name puzzle
- String comparison
- Unique characters
- Unique characters in each string
- Extract file extension
- Levenshtein distance
- Palindrome detection
- Common list elements
- Longest common suffix
- Longest common prefix
- Compare a list of strings
- Longest common substring
- Find common directory path
- Words from neighbour ones
- Change e letters to i in words
- Non-continuous subsequences
- Longest common subsequence
- Longest palindromic substrings
- Longest increasing subsequence
- Words containing "the" substring
- Sum of the digits of n is substring of n
- Determine if a string is numeric
- Determine if a string is collapsible
- Determine if a string is squeezable
- Determine if a string has all unique characters
- Determine if a string has all the same characters
- Longest substrings without repeating characters
- Find words which contains all the vowels
- Find words which contain the most consonants
- Find words which contains more than 3 vowels
- Find words whose first and last three letters are equal
- Find words with alternating vowels and consonants
- Formatting
- Substring
- Rep-string
- Word wrap
- String case
- Align columns
- Literals/String
- Repeat a string
- Brace expansion
- Brace expansion using ranges
- Reverse a string
- Phrase reversals
- Comma quibbling
- Special characters
- String concatenation
- Substring/Top and tail
- Commatizing numbers
- Reverse words in a string
- Suffixation of decimal numbers
- Long literals, with continuations
- Numerical and alphabetical suffixes
- Abbreviations, easy
- Abbreviations, simple
- Abbreviations, automatic
- Song lyrics/poems/Mad Libs/phrases
- Mad Libs
- Magic 8-ball
- 99 bottles of beer
- The Name Game (a song)
- The Old lady swallowed a fly
- The Twelve Days of Christmas
- Tokenize
- Text between
- Tokenize a string
- Word break problem
- Tokenize a string with escaping
- Split a character string based on change of character
- Sequences
11l
<lang 11l>V wordList = File(‘unixdict.txt’).read().split("\n")
V filteredWords = wordList.filter(chosenWord -> chosenWord.len >= 9)
L(word) filteredWords[0 .< (len)-9]
V position = filteredWords.index(word) V newWord = (0..8).map(i -> :filteredWords[@position + i][i]).join(‘’) I newWord C filteredWords print(newWord)</lang>
- Output:
applicate architect astronomy christine christoph committee committee committee committee committee composite constrict constrict construct different extensive greenwood implement improvise intercept interpret interrupt interrupt philosoph prescript receptive telephone transcend transcend transport transpose
AppleScript
Core language
<lang applescript>on task()
-- Since the task specifically involves unixdict.txt, this code's written in -- the knowlege that the words are on individual lines and in dictionary order. set dictPath to (path to desktop as text) & "unixdict.txt" script o property wordList : paragraphs of (read file dictPath as «class utf8») property matches : {} end script -- Zap words with fewer than 9 characters and work with what's left. repeat with i from 1 to (count o's wordList) if ((count item i of o's wordList) < 9) then set item i of o's wordList to missing value end repeat set o's wordList to o's wordList's every text set wordListCount to (count o's wordList) set previousNewWord to missing value repeat with i from 1 to (wordListCount - 8) set newWord to character 1 of item i of o's wordList set j to (i - 1) repeat with k from 2 to 9 set newWord to newWord & character k of item (j + k) of o's wordList end repeat -- Since wordList's known to be in dictionary order, a lot of time can be saved -- by only checking the necessary few words ahead for a match instead of -- using AppleScript's 'is in' or 'contains' commands, which check the entire list. if (newWord is not previousNewWord) then repeat with j from i to wordListCount set thisWord to item j of o's wordList if (newWord comes after thisWord) then else if (newWord is thisWord) then set end of o's matches to newWord exit repeat end if end repeat set previousNewWord to newWord end if end repeat return o's matches
end task
task()</lang>
- Output:
<lang applescript>{"applicate", "architect", "astronomy", "christine", "christoph", "committee", "composite", "constrict", "construct", "different", "extensive", "greenwood", "implement", "improvise", "intercept", "interpret", "interrupt", "philosoph", "prescript", "receptive", "telephone", "transcend", "transport", "transpose"}</lang>
AppleScriptObjC
Same output as above. <lang applescript>use AppleScript version "2.4" -- OS X 10.10 (Yosemite) or later use framework "Foundation" use scripting additions
on task()
set |⌘| to current application set dictPath to (POSIX path of (path to desktop)) & "unixdict.txt" set dictText to |⌘|'s class "NSString"'s stringWithContentsOfFile:(dictPath) ¬ usedEncoding:(missing value) |error|:(missing value) set newlineSet to |⌘|'s class "NSCharacterSet"'s newlineCharacterSet() set wordArray to dictText's componentsSeparatedByCharactersInSet:(newlineSet) -- Lose words with fewer than 9 characters. set filter to |⌘|'s class "NSPredicate"'s predicateWithFormat:("self MATCHES '.{9,}+'") set relevantWords to wordArray's filteredArrayUsingPredicate:(filter) -- Creating the new words is most easily and efficiently done with core AppleScript. script o property wordList : relevantWords as list property newWords : {} end script repeat with i from 1 to ((count o's wordList) - 8) set newWord to character 1 of item i of o's wordList set j to (i - 1) repeat with k from 2 to 9 set newWord to newWord & character k of item (j + k) of o's wordList end repeat set end of o's newWords to newWord end repeat -- But Foundation sets are good for filtering the results. set matches to |⌘|'s class "NSMutableOrderedSet"'s orderedSetWithArray:(o's newWords) tell matches to intersectSet:(|⌘|'s class "NSSet"'s setWithArray:(relevantWords)) return (matches's array()) as list
end task
task()</lang>
Arturo
<lang rebol>wordset: map read.lines relative "unixdict.txt" => strip wordset: select wordset 'word -> 9 =< size word
lastWord: "" newWord: " " count: 0
loop 0..(size wordset)-9 'i [
loop 0..8 'j -> newWord\[j]: wordset\[i+j]\[j] if and? [in? newWord wordset][lastWord <> newWord][ count: count + 1 print [(pad to :string count 3)++":" newWord] lastWord: new newWord ]
]</lang>
- Output:
1: applicate 2: architect 3: astronomy 4: christine 5: christoph 6: committee 7: composite 8: constrict 9: construct 10: different 11: extensive 12: greenwood 13: implement 14: improvise 15: intercept 16: interpret 17: interrupt 18: philosoph 19: prescript 20: receptive 21: telephone 22: transcend 23: transport 24: transpose
AutoHotkey
<lang AutoHotkey>FileRead, wList, % A_Desktop "\unixdict.txt" for word in neighbour(wList)
result .= word (Mod(A_Index, 6) ? "`t" : "`n")
MsgBox, 262144, , % result return
neighbour(wList){
words := [], wordExist := [], oRes := [] for i, w in StrSplit(wList, "`n", "`r") { if (StrLen(w) < 9) continue words.Push(w) wordExist[w] := true } loop % words.Count()-9 { n := A_Index newword := "" loop 9 newword .= SubStr(words[n+A_Index-1], A_Index, 1) if wordExist[newword] oRes[newword] := true } return oRes
}</lang>
- Output:
applicate architect astronomy christine christoph committee composite constrict construct different extensive greenwood implement improvise intercept interpret interrupt philosoph prescript receptive telephone transcend transport transpose
AWK
<lang AWK>
- syntax: GAWK -f WORDS_FROM_NEIGHBOUR_ONES.AWK unixdict.txt
{ if (length($0) < 9) { next }
arr1[++n] = $0 arr2[$0] = ""
} END {
for (i=1; i<=n; i++) { word = substr(arr1[i],1,1) for (j=2; j<=9; j++) { if (!((i+j) in arr1)) { continue } word = word substr(arr1[i+j],j,1) } if (word in arr2) { printf("%s\n",word) delete arr2[word] # eliminate duplicates } } exit(0)
} </lang>
- Output:
applicate architect astronomy christine christoph committee composite constrict construct different extensive greenwood implement improvise intercept interpret interrupt philosoph prescript receptive telephone transcend transport transpose
C
<lang c>#include <stdio.h>
- include <stdlib.h>
- include <string.h>
- define MAX_WORD_SIZE 80
- define MIN_LENGTH 9
- define WORD_SIZE (MIN_LENGTH + 1)
void fatal(const char* message) {
fprintf(stderr, "%s\n", message); exit(1);
}
void* xmalloc(size_t n) {
void* ptr = malloc(n); if (ptr == NULL) fatal("Out of memory"); return ptr;
}
void* xrealloc(void* p, size_t n) {
void* ptr = realloc(p, n); if (ptr == NULL) fatal("Out of memory"); return ptr;
}
int word_compare(const void* p1, const void* p2) {
return memcmp(p1, p2, WORD_SIZE);
}
int main(int argc, char** argv) {
const char* filename = argc < 2 ? "unixdict.txt" : argv[1]; FILE* in = fopen(filename, "r"); if (!in) { perror(filename); return EXIT_FAILURE; } char line[MAX_WORD_SIZE]; size_t size = 0, capacity = 1024; char* words = xmalloc(WORD_SIZE * capacity); while (fgets(line, sizeof(line), in)) { size_t len = strlen(line) - 1; // last character is newline if (len < MIN_LENGTH) continue; line[len] = '\0'; if (size == capacity) { capacity *= 2; words = xrealloc(words, WORD_SIZE * capacity); } memcpy(&words[size * WORD_SIZE], line, WORD_SIZE); ++size; } fclose(in); qsort(words, size, WORD_SIZE, word_compare); int count = 0; char prev_word[WORD_SIZE] = { 0 }; for (size_t i = 0; i + MIN_LENGTH <= size; ++i) { char word[WORD_SIZE] = { 0 }; for (size_t j = 0; j < MIN_LENGTH; ++j) word[j] = words[(i + j) * WORD_SIZE + j]; if (word_compare(word, prev_word) == 0) continue; if (bsearch(word, words, size, WORD_SIZE, word_compare)) printf("%2d. %s\n", ++count, word); memcpy(prev_word, word, WORD_SIZE); } free(words); return EXIT_SUCCESS;
}</lang>
- Output:
1. applicate 2. architect 3. astronomy 4. christine 5. christoph 6. committee 7. composite 8. constrict 9. construct 10. different 11. extensive 12. greenwood 13. implement 14. improvise 15. intercept 16. interpret 17. interrupt 18. philosoph 19. prescript 20. receptive 21. telephone 22. transcend 23. transport 24. transpose
C++
<lang cpp>#include <algorithm>
- include <cstdlib>
- include <fstream>
- include <iomanip>
- include <iostream>
- include <string>
- include <vector>
int main(int argc, char** argv) {
const int min_length = 9; const char* filename(argc < 2 ? "unixdict.txt" : argv[1]); std::ifstream in(filename); if (!in) { std::cerr << "Cannot open file '" << filename << "'.\n"; return EXIT_FAILURE; } std::string line; std::vector<std::string> words; while (getline(in, line)) { if (line.size() >= min_length) words.push_back(line); } std::sort(words.begin(), words.end()); std::string previous_word; int count = 0; for (size_t i = 0, n = words.size(); i + min_length <= n; ++i) { std::string word; word.reserve(min_length); for (size_t j = 0; j < min_length; ++j) word += words[i + j][j]; if (previous_word == word) continue; auto w = std::lower_bound(words.begin(), words.end(), word); if (w != words.end() && *w == word) std::cout << std::setw(2) << ++count << ". " << word << '\n'; previous_word = word; } return EXIT_SUCCESS;
}</lang>
- Output:
1. applicate 2. architect 3. astronomy 4. christine 5. christoph 6. committee 7. composite 8. constrict 9. construct 10. different 11. extensive 12. greenwood 13. implement 14. improvise 15. intercept 16. interpret 17. interrupt 18. philosoph 19. prescript 20. receptive 21. telephone 22. transcend 23. transport 24. transpose
Delphi
<lang Delphi> program Words_from_neighbour_ones;
{$APPTYPE CONSOLE}
uses
System.SysUtils, System.Classes;
function GetWords(minLength: Integer = 1): TStringList; var
i: Integer;
begin
Result := TStringList.create; Result.LoadFromFile('Unixdict.txt'); with Result do for i := Count - 1 downto 0 do if Strings[i].Length < minLength then Delete(i); Result.Sort;
end;
var
Words: TStringList;
const
minLength = 9;
begin
Words := GetWords(minLength); var previousWord := ; var count := 0; var n := Words.Count;
for var i := 0 to n - minLength do begin
var W := ; for var j := 0 to minLength - 1 do W := W + Words[i + j][j + 1]; if W.Equals(previousWord) then Continue; if Words.IndexOf(W) >= 0 then begin inc(count); writeln(count: 2, '. ', W); end; previousWord := W; end;
Words.Free; readln;
end.</lang>
- Output:
1. applicate 2. architect 3. astronomy 4. christine 5. christoph 6. committee 7. composite 8. constrict 9. construct 10. different 11. extensive 12. greenwood 13. implement 14. improvise 15. intercept 16. interpret 17. interrupt 18. philosoph 19. prescript 20. receptive 21. telephone 22. transcend 23. transport 24. transpose
F#
<lang fsharp> // Words from neighbour ones. Nigel Galloway: February 11th., 2021. let g=[|use n=System.IO.File.OpenText("unixdict.txt") in while not n.EndOfStream do yield n.ReadLine()|]|>Array.filter(fun n->n.Length>8) g|>Array.windowed 9|>Array.map(fun n->n|>Array.mapi(fun n g->g.[n])|>System.String)|>Array.filter(fun n-> Array.contains n g)|>Array.distinct|>Array.iter(printfn "%s") </lang>
- Output:
applicate architect astronomy christine christoph committee composite constrict construct different extensive greenwood implement improvise intercept interpret interrupt philosoph prescript receptive telephone transcend transport transpose
Factor
{ "abc" "def" "ghi" } 2 clump
produces
{ { "abc" "def" } { "def" "ghi" } }
.
<clumps>
is the same idea except it doesn't actually store all that redundant information in memory; it's a generator that generates clumps on demand. Notice that clumps are matrices, so we can take their diagonal with main-diagonal
.
<lang factor>USING: formatting grouping hash-sets io.encodings.ascii io.files kernel literals math math.matrices sequences sequences.extras sets strings ;
<< CONSTANT: words $[ "unixdict.txt" ascii file-lines ] >>
CONSTANT: wordset $[ words >hash-set ]
words ! place word list on data stack [ length 9 < ] reject ! remove small words from list 9 <clumps> ! create virtual sequence of every 9 adjacent words (overlapping) [ main-diagonal >string ] ! map clump to its diagonal [ wordset in? ] map-filter ! filter diagonals that are words members ! remove duplicates [ 1 + swap "%2d. %s\n" printf ] each-index ! print words formatted nicely</lang>
- Output:
1. applicate 2. architect 3. astronomy 4. christine 5. christoph 6. committee 7. composite 8. constrict 9. construct 10. different 11. extensive 12. greenwood 13. implement 14. improvise 15. intercept 16. interpret 17. interrupt 18. philosoph 19. prescript 20. receptive 21. telephone 22. transcend 23. transport 24. transpose
FreeBASIC
<lang freebasic> Open "unixdict.txt" For Input As #1 Dim As String cStr, wordList() Dim As Integer n, p = 0, posic = 0 Do While Not Eof(1)
Line Input #1, cStr p += 1 If Len(cStr) > 8 Then posic += 1 Redim Preserve wordList(posic) wordList(posic) = cStr End If
Loop Close #1
Print p; " palabras en el archivo de diccionario: unixdict.txt" Print Ubound(wordList); " palabras utilizables en el archivo del diccionario."
Dim As String char(1 To 9), palabra Dim As String nextwords(Ubound(wordList))
Print !"\ntrabajando...\n" Print !"Las nuevas palabras son:\n"
posic = 0 For n = 1 To Ubound(wordList)-8
palabra = "" For p = 1 To 9 char(p) = Mid(wordList(n+p-1),p,1) palabra += char(p) Next p For p = 1 To Ubound(wordList) If wordList(p) = palabra Then posic += 1 nextwords(posic) = palabra End If Next p
Next n
posic = 0 For n = 2 To Ubound(nextwords)
If nextwords(n) <> nextwords(n-1) Then posic += 1 Print ""; posic; ". "; nextwords(n-1) End If
Next n
Print !"\nterminado..." Sleep </lang>
- Output:
25104 palabras en el archivo de diccionario: unixdict.txt 7250 palabras utilizables en el archivo del diccionario. trabajando... Las nuevas palabras son: 1. applicate 2. architect 3. astronomy 4. christine 5. christoph 6. committee 7. composite 8. constrict 9. construct 10. different 11. extensive 12. greenwood 13. implement 14. improvise 15. intercept 16. interpret 17. interrupt 18. philosoph 19. prescript 20. receptive 21. telephone 22. transcend 23. transport 24. transpose terminado...
Go
<lang go>package main
import (
"bytes" "fmt" "io/ioutil" "log" "sort" "strings" "unicode/utf8"
)
func main() {
wordList := "unixdict.txt" b, err := ioutil.ReadFile(wordList) if err != nil { log.Fatal("Error reading file") } bwords := bytes.Fields(b) var words []string for _, bword := range bwords { s := string(bword) if utf8.RuneCountInString(s) >= 9 { words = append(words, s) } } count := 0 var alreadyFound []string le := len(words) var sb strings.Builder for i := 0; i < le-9; i++ { sb.Reset() for j := i; j < i+9; j++ { sb.WriteByte(words[j][j-i]) } word := sb.String() ix := sort.SearchStrings(words, word) if ix < le && word == words[ix] { ix2 := sort.SearchStrings(alreadyFound, word) if ix2 == len(alreadyFound) { count++ fmt.Printf("%2d: %s\n", count, word) alreadyFound = append(alreadyFound, word) } } }
}</lang>
- Output:
1: applicate 2: architect 3: astronomy 4: christine 5: christoph 6: committee 7: composite 8: constrict 9: construct 10: different 11: extensive 12: greenwood 13: implement 14: improvise 15: intercept 16: interpret 17: interrupt 18: philosoph 19: prescript 20: receptive 21: telephone 22: transcend 23: transport 24: transpose
J
<lang J> >(([-.-.)9 <@((=i.9)&(#&,))\ 9&{.@>@(#~ 8<#@>)) cutLF fread 'unixdict.txt' applicate architect astronomy christine christoph committee composite constrict construct different extensive greenwood implement improvise intercept interpret interrupt philosoph prescript receptive telephone transcend transport transpose</lang>
Java
<lang java>import java.io.*; import java.util.*;
public class NeighbourWords {
public static void main(String[] args) { try { int minLength = 9; List<String> words = new ArrayList<>(); try (BufferedReader reader = new BufferedReader(new FileReader("unixdict.txt"))) { String line; while ((line = reader.readLine()) != null) { if (line.length() >= minLength) words.add(line); } } Collections.sort(words); String previousWord = null; int count = 0; for (int i = 0, n = words.size(); i + minLength <= n; ++i) { StringBuilder sb = new StringBuilder(minLength); for (int j = 0; j < minLength; ++j) sb.append(words.get(i + j).charAt(j)); String word = sb.toString(); if (word.equals(previousWord)) continue; if (Collections.binarySearch(words, word) >= 0) System.out.printf("%2d. %s\n", ++count, word); previousWord = word; } } catch (Exception e) { e.printStackTrace(); } }
}</lang>
- Output:
1. applicate 2. architect 3. astronomy 4. christine 5. christoph 6. committee 7. composite 8. constrict 9. construct 10. different 11. extensive 12. greenwood 13. implement 14. improvise 15. intercept 16. interpret 17. interrupt 18. philosoph 19. prescript 20. receptive 21. telephone 22. transcend 23. transport 24. transpose
JavaScript
<lang javascript> document.write(`
Choose dictionary: <input id="dict" type="file">
Word length: <input id="wlen" type="number" value="9"
`);
function go(dict) {
let wordLen = parseInt(document.getElementById('wlen').value), result = []; dict = dict.replace(/\n|\r/g, '_'); dict = dict.replace(/__/g, ' ').split(' '); dict = dict.filter(e => e.length >= wordLen); for (let i = 0; i < dict.length - wordLen; i++) { let word = dict[i][0]; for (let j = 1; j < wordLen; j++) { word += dict[i+j][j]; } if (dict.includes(word) && !result.includes(word)) result.push(word); } document.getElementById('out').innerText = result.join(', ');
}
document.getElementById('dict').onchange = function() {
let f = document.getElementById('dict').files[0], fr = new FileReader(); fr.onload = function() { go(fr.result) } fr.readAsText(f);
} </lang>
- Output:
applicate, architect, astronomy, christine, christoph, committee, composite, constrict, construct, different, extensive, greenwood, implement, improvise, intercept, interpret, interrupt, philosoph, prescript, receptive, telephone, transcend, transport, transpose
jq
For speed, this solution constructs a JSON object as a dictionary ($hash):<lang jq>
- input: the dictionary
- $n: starting point (starting at 0)
def form_word($n):
. as $dict | reduce range(0;9) as $i (""; . + $dict[$n+$i][$i: $i+1] );
[inputs | select(length >= 9)] | . as $dict | (reduce.[] as $x ({}; .[$x]=true)) as $hash | range(0; length-9) as $i | form_word($i) | select($hash[.])</lang>
- Output:
["applicate","architect","astronomy","christine","christoph","committee","committee","committee","committee","committee","composite","constrict","constrict","construct","different","extensive","greenwood","implement","improvise","intercept","interpret","interrupt","interrupt","philosoph","prescript","receptive","telephone","transcend","transcend","transport","transpose"]
Removing duplicates efficiently
Using `def form_word`, we have only to modify the last line above: <lang jq>[inputs | select(length >= 9)] | . as $dict | (reduce.[] as $x ({}; .[$x]=true)) as $hash | reduce range(0; length-9) as $i ({$hash};
($dict | form_word($i)) as $w | if .hash[$w] then .hash[$w] = null | .words += [$w] else . end)
| .words</lang>
Julia
<lang julia>function wordsfromneighbourones(wordfile::String, len = 9, colwidth = 11, numcols = 8)
println("Word source: $wordfile\n") words = filter(w -> length(w) >= len, split(read(wordfile, String), r"\s+")) dict, shown, found = Dict(w => 1 for w in words), 0, String[] for position in eachindex(@view words[1:end-len+1]) new_word = prod([words[i + position - 1][i] for i in 1:len]) if haskey(dict, new_word) && !(new_word in found) push!(found, new_word) print(rpad(new_word, colwidth), (shown += 1) % numcols == 0 ? "\n" : "") end end
end
wordsfromneighbourones("unixdict.txt")
</lang>
- Output:
Word source: unixdict.txt applicate architect astronomy christine christoph committee composite constrict construct different extensive greenwood implement improvise intercept interpret interrupt philosoph prescript receptive telephone transcend transport transpose
Ksh
<lang ksh>
- !/bin/ksh
- Words from neighbour ones
- # Variables:
dict='/home/ostrande/prj/roscode/unixdict.txt' integer MIN_WORD_LEN=9 TRUE=1 FALSE=0
typeset -a word newword integer i j=0
- # Functions:
- # Function _buildword(arr) - build MIN_WORD_LEN word from arr eles
function _buildword { typeset _arr ; nameref _arr="$1" typeset _indx ; integer _indx=$2 typeset _i _str ; integer _i
for ((_i=0; _i<MIN_WORD_LEN; _i++)); do _str+=${_arr[$((_indx+_i))]:${_i}:1} done echo "${_str}" }
- # Function _isword(word, wordlist) - return 1 if word in wordlist
function _isword { typeset _word ; _word="$1" typeset _wordlist ; nameref _wordlist="$2"
[[ ${_word} == @(${_wordlist}) ]] && return $TRUE return $FALSE }
######
- main #
######
while read; do (( ${#REPLY} >= MIN_WORD_LEN )) && word+=( $REPLY ) done < ${dict} oldIFS="$IFS" ; IFS='|' ; words=${word[*]} ; IFS="${oldIFS}"
for ((i=0; i<${#word[*]}; i++)); do candidate=$(_buildword word ${i}) _isword "${candidate}" words if (( $? )); then if [[ ${candidate} != @(${uniq%\|*}) ]]; then print $((++j)) ${candidate} uniq+="${candidate}|" fi fi done</lang>
- Output:
1 applicate 2 architect 3 astronomy 4 christine 5 christoph 6 committee 7 composite 8 constrict 9 construct 10 different 11 extensive 12 greenwood 13 implement 14 improvise 15 intercept 16 interpret 17 interrupt 18 philosoph 19 prescript 20 receptive 21 telephone 22 transcend 23 transport
24 transpose
Lua
<lang lua>wordlist, wordhash = {}, {} for word in io.open("unixdict.txt", "r"):lines() do
if #word >= 9 then wordlist[#wordlist+1] = word wordhash[word] = #wordlist end
end for n = 1, #wordlist-8 do
local word = "" for i = 0, 8 do word = word .. wordlist[n+i]:sub(i+1,i+1) end if wordhash[word] then -- task appears to say "for every n, do all of the following" -- but doesn't appear to say "..unless a duplicate" -- so, intentionally verbose/redundant: print(word) end
end</lang>
- Output:
applicate architect astronomy christine christoph committee committee committee committee committee composite constrict constrict construct different extensive greenwood implement improvise intercept interpret interrupt interrupt philosoph prescript receptive telephone transcend transcend transport transpose
Mathematica /Wolfram Language
<lang Mathematica>dict = Once[Import["https://web.archive.org/web/20180611003215/http://www.puzzlers.org/pub/wordlists/unixdict.txt"]]; dict //= StringSplit[#,"\n"]&; dict //= Select[StringLength/*GreaterEqualThan[9]]; firsts9 = Characters[dict]All,;;9; words = StringJoin[Diagonal[firsts9,-#]]&/@Range[0,Length[firsts9]-9]; Intersection[words,dict]</lang>
- Output:
{"applicate", "architect", "astronomy", "christine", "christoph", "committee", "composite", "constrict", "construct", "different", "extensive", "greenwood", "implement", "improvise", "intercept", "interpret", "interrupt", "philosoph", "prescript", "receptive", "telephone", "transcend", "transport", "transpose"}
Nim
<lang Nim>import sets, strutils, sugar
- Build list and set of words with length >= 9.
let words = collect(newSeq):
for word in "unixdict.txt".lines: if word.len >= 9: word
let wordSet = words.toHashSet
var lastWord = "" var newWord = newString(9) var count = 0 for i in 0..words.high-9:
for j in 0..8: newWord[j] = words[i+j][j] if newWord in wordSet: if newWord != lastWord: inc count echo ($count).align(2), ' ', newWord lastWord = newWord</lang>
- Output:
1 applicate 2 architect 3 astronomy 4 christine 5 christoph 6 committee 7 composite 8 constrict 9 construct 10 different 11 extensive 12 greenwood 13 implement 14 improvise 15 intercept 16 interpret 17 interrupt 18 philosoph 19 prescript 20 receptive 21 telephone 22 transcend 23 transport 24 transpose
Perl
<lang perl>#!/usr/bin/perl
use strict; # https://rosettacode.org/wiki/Words_from_neighbour_ones use warnings;
@ARGV = 'unixdict.txt'; my $skew = join , map { s/^.{9}\K.+//r } my @words = grep length() > 9, <>; my %dict = map { $_ => 1 } grep length == 10, @words; my %seen; my $nextch = '.{10}(\\w)' x 8; while( $skew =~ /^(\w)(?=$nextch)/gms )
{ my $new = join , @{^CAPTURE}, "\n"; $dict{$new} and !$seen{$new}++ and print $new; }</lang>
- Output:
applicate architect astronomy christine christoph committee composite constrict construct different extensive greenwood implement improvise intercept interpret interrupt philosoph prescript receptive telephone transcend transport transpose
Phix
with javascript_semantics function over9(string word) return length(word)>=9 end function sequence words = filter(unix_dict(),over9) function slicen(integer n) return vslice(words,n)[n..-10+n] end function sequence neighwords = unique(filter(columnize(apply(tagset(9),slicen)),"in",words)) printf(1,"%d words: %s\n",{length(neighwords),join(shorten(neighwords,"",3))})
- Output:
24 words: applicate architect astronomy ... transcend transport transpose
Processing
<lang Processing>StringList words = new StringList(), found = new StringList(); for (String str : loadStrings("unixdict.txt")) {
if (str.length() >= 9) { words.append(str); }
} for (int i = 0; i < words.size() - 9; i++) {
String temp = ""; for (int j = 0; j < 9; j++) { temp += words.get(i + j).charAt(j); } if (words.hasValue(temp) && !found.hasValue(temp)) { found.append(temp); }
} for (String word : found) {
println(word);
}</lang>
- Output:
applicate architect astronomy christine christoph committee composite constrict construct different extensive greenwood implement improvise intercept interpret interrupt philosoph prescript receptive telephone transcend transport transpose
Python
Tested on Python 3+, the file download will work only if the link is still active. It is possible that you may be able to fetch the file in your browser but download via code may still fail. Check whether you are connected to a VPN, it works on open networks. <lang Python>
- Aamrun, 5th November 2021
import urllib.request from collections import Counter
urllib.request.urlretrieve("http://wiki.puzzlers.org/pub/wordlists/unixdict.txt", "unixdict.txt")
dictionary = open("unixdict.txt","r")
wordList = dictionary.read().split('\n')
dictionary.close()
filteredWords = [chosenWord for chosenWord in wordList if len(chosenWord)>=9]
for word in filteredWords[:-9]:
position = filteredWords.index(word) newWord = "".join([filteredWords[position+i][i] for i in range(0,9)]) if newWord in filteredWords: print(newWord)
</lang>
- Output:
Yes, there are duplicates, the task doesn't say that only unique elements should be present, hence the complete raw list will appear as below :
applicate architect astronomy christine christoph committee committee committee committee committee composite constrict constrict construct different extensive greenwood implement improvise intercept interpret interrupt interrupt philosoph prescript receptive telephone transcend transcend transport transpose
Raku
<lang perl6>my @words_ge_9 = 'unixdict.txt'.IO.lines.grep( *.chars >= 9 ); my %words_eq_9 = @words_ge_9 .grep( *.chars == 9 ).Set;
my @new_words = gather for @words_ge_9.rotor( 9 => -8 ) -> @nine_words {
my $new_word = [~] map { @nine_words[$_].substr($_, 1) }, ^9;
take $new_word if %words_eq_9{$new_word};
}
.say for unique @new_words;</lang>
- Output:
applicate architect astronomy christine christoph committee composite constrict construct different extensive greenwood implement improvise intercept interpret interrupt philosoph prescript receptive telephone transcend transport transpose
REXX
This REXX version doesn't care what order the words in the dictionary are in, nor does it care what
case (lower/upper/mixed) the words are in, the search for the words is caseless.
It also allows the minimum length to be specified on the command line (CL) as well as the dictionary file identifier. <lang rexx>/*REXX pgm finds words that're composed from neighbor words (within an identified dict).*/ parse arg minL iFID . /*obtain optional arguments from the CL*/ if minL== | minL=="," then minL= 9 /*Not specified? Then use the default.*/ if iFID== | iFID=="," then iFID='unixdict.txt' /* " " " " " " */
- = 0; @.=; !.= 0 /*number of usable words in dictionary.*/
do recs=0 while lines(iFID)\==0 /*read each word in the file (word=X).*/ x= strip( linein( iFID) ) /*pick off a word from the input line. */ if length(x)<minL then iterate /*Is the word too short? Then skip it.*/ #= # + 1 /*bump the count of usable words. */ @.#= x; upper x; !.x= 1 /*original case; create findable word.*/ end /*recs*/ /* [↑] semaphore name is uppercased. */
say copies('─', 30) recs "words in the dictionary file: " iFID say copies('─', 30) right(#, length(recs) ) "usable words in the dictionary file." finds= 0 /*count of the changable words found.*/ say; $=
do j=1 for #; y= left(@.j, 1) /*initialize the new word to be built. */ do k=2 to 9 until n>#; n= j + k /*use next 8 usable words in dictionary*/ y= y || substr(@.n, k, 1) /*build a new word, 1 letter at a time.*/ end /*k*/ uy=y; upper uy /*obtain uppercase version of the word.*/ if \!.uy then iterate /*Does the new word exist? No, skip it*/ if wordpos(uy, $)>0 then iterate /*Word is a dup? Then skip duplicate. */ finds= finds + 1 /*bump count of found neighboring words*/ $= $ uy /*add a word to the list of words found*/ say right( left(y, 30), 40) /*indent original word for readability.*/ end /*j*/ /*stick a fork in it, we're all done. */
say copies('─', 30) finds ' neighbor words found with a minimum length of ' minL</lang>
- output when using the default inputs:
────────────────────────────── 25104 words in the dictionary file: unixdict.txt ────────────────────────────── 7250 usable words in the dictionary file. applicate architect astronomy christine christoph committee composite constrict construct different extensive greenwood implement improvise intercept interpret interrupt philosoph prescript receptive telephone transcend transport transpose ────────────────────────────── 24 neighbor words found with a minimum length of 9
Ring
<lang ring> cStr = read("unixdict.txt") wordList = str2list(cStr) char = list(9) nextwords = [] num = 0
see "working..." + nl
ln = len(wordList) for n = ln to 1 step -1
if len(wordList[n]) < 9 del(wordList,n) ok
next
see "New words are:" + nl
for n = 1 to len(wordList)-8
for m = 1 to 9 char[m] = substr(wordList[n+m-1],m,1) next str = "" for p = 1 to 9 str = str + char[p] next ind = find(wordList,str) if ind > 0 add(nextwords,wordList[ind]) ok
next
nextwords = sort(nextwords) for n = len(nextwords) to 2 step -1
if nextwords[n] = nextwords[n-1] del(nextwords,n) ok
next
for n = 1 to len(nextwords)
see "" + n + ". " + nextwords[n] + nl
next
see "done..." + nl </lang> Output:
working... New words are: 1. applicate 2. architect 3. astronomy 4. christine 5. christoph 6. committee 7. composite 8. constrict 9. construct 10. different 11. extensive 12. greenwood 13. implement 14. improvise 15. intercept 16. interpret 17. interrupt 18. philosoph 19. prescript 20. receptive 21. telephone 22. transcend 23. transport 24. transpose done...
Vlang
<lang vlang>import os
fn main() {
mut result := unixdict := os.read_file('./unixdict.txt') or {panic('file not found')} for index, word in neighbour(unixdict) { idx := index + 1 if (idx % 6 == 0) == true {result += '$word \n'} else {result += '$word '} } println(result)
}
fn neighbour(list string) []string {
mut word_arr, mut res_arr := []string{}, []string{} mut word_exist := map[string]bool mut new_word := for word in list.split_into_lines() { if word.len >= 9 { word_arr << word word_exist[word] = true } }
for out_idx in 0..word_arr.len - 9 { new_word = for in_idx in 0..9 { new_word += word_arr[out_idx + in_idx].substr(in_idx, in_idx + 1) if word_exist[new_word] == true && res_arr.any(it == new_word) == false {res_arr << new_word} } } return res_arr
}</lang>
- Output:
applicate architect astronomy christine christoph committee composite constrict construct different extensive greenwood implement improvise intercept interpret interrupt philosoph prescript receptive telephone transcend transport transpose
Wren
<lang ecmascript>import "io" for File import "/sort" for Find import "/fmt" for Fmt
var wordList = "unixdict.txt" // local copy var words = File.read(wordList).trimEnd().split("\n").where { |w| w.count >= 9 }.toList var count = 0 var alreadyFound = [] for (i in 0...words.count - 9) {
var word = "" for (j in i...i+9) word = word + words[j][j-i] if (Find.all(words, word)[0] && !Find.all(alreadyFound, word)[0]) { count = count + 1 Fmt.print("$2d: $s", count, word) alreadyFound.add(word) }
}</lang>
- Output:
1: applicate 2: architect 3: astronomy 4: christine 5: christoph 6: committee 7: composite 8: constrict 9: construct 10: different 11: extensive 12: greenwood 13: implement 14: improvise 15: intercept 16: interpret 17: interrupt 18: philosoph 19: prescript 20: receptive 21: telephone 22: transcend 23: transport 24: transpose
XPL0
<lang XPL0>string 0; \use zero-terminated strings int Dict(26000); \pointers to words (enough for unixdict.txt) int DictSize; \actual number of pointers in Dict
func StrCmp(A, B); \Compare string A to B char A, B; \Returns: >0 if A>B, =0 if A=B, and <0 if A>1 do
[if A(I) # B(I) then return A(I) - B(I); if A(I) = 0 then return 0; ];
]; \StrCmp
func LookUp(Word); \Return 'true' if Word is in Dict char Word; int Lo, Hi, I, Cmp; [Lo:= 0; Hi:= DictSize-1; loop [I:= (Lo+Hi) / 2; \binary search
Cmp:= StrCmp(Word, Dict(I)); if Cmp < 0 then Hi:= I-1 else Lo:= I+1; if Cmp = 0 then return true; if Lo > Hi then return false; ];
]; \LookUp
int DI, I, Ch, Count; char Word, Neigh(10), Last(10); def LF=$0A, CR=$0D, EOF=$1A;
[FSet(FOpen("unixdict.txt", 0), ^I); \load dictionary OpenI(3); \assume alphabetical order and all lowercase DI:= 0; repeat Dict(DI):= Reserve(0); \get pointer to memory used to store Word
Word:= Dict(DI); I:= 0; loop [repeat Ch:= ChIn(3) until Ch # CR; \remove possible CR if Ch=LF or Ch=EOF then quit; Word(I):= Ch; I:= I+1; ]; if I >= 9 then \ignore words less than 9 characters [Word(I):= 0; \terminate Word string I:= Reserve(I+1); \reserve memory used for Word DI:= DI+1; \next dictionary entry ];
until Ch = EOF; DictSize:= DI;
DI:= 0; Count:= 0; Last(0):= 0; repeat for I:= 0 to 9-1 do \build Neigh word using letters from
[Word:= Dict(DI+I); \ following words Neigh(I):= Word(I); ]; Neigh(9):= 0; \terminate string if LookUp(Neigh) then \if it's a word and not already listed if StrCmp(Neigh, Last) # 0 then [CopyMem(Last, Neigh, 10); Count:= Count+1; Text(0, Neigh); if rem(Count/8) = 0 then CrLf(0) else ChOut(0, ^ ); ]; DI:= DI+1; \next word in dictionary
until DI >= DictSize-9; CrLf(0); ]</lang>
- Output:
applicate architect astronomy christine christoph committee composite constrict construct different extensive greenwood implement improvise intercept interpret interrupt philosoph prescript receptive telephone transcend transport transpose
Yabasic
<lang yabasic> open "unixdict.txt" for reading as #1 p = 0 posic = 0 while not eof(1)
line input #1 cStr$ p = p + 1 if len(cStr$) > 8 then posic = posic + 1 redim wordList$(posic) wordList$(posic) = cStr$ end if
wend close #1
print p, " palabras en el archivo de diccionario: unixdict.txt" print arraysize(wordList$(), 1), " palabras utilizables en el archivo del diccionario."
dim char$(9) dim nextwords$(arraysize(wordList$(), 1))
print chr$(10), "trabajando...", chr$(10)
print "Las nuevas palabras son:", chr$(10)
posic = 0 for n = 1 to arraysize(wordList$(), 1) - 8
palabra$ = "" for p = 1 to 9 char$(p) = mid$(wordList$(n + p - 1), p, 1) palabra$ = palabra$ + char$(p) next p for p = 1 to arraysize(wordList$(), 1) if wordList$(p) = palabra$ then posic = posic + 1 nextwords$(posic) = palabra$ end if next p
next n
posic = 0 for n = 2 to arraysize(nextwords$(), 1)
if nextwords$(n) <> nextwords$(n - 1) then posic = posic + 1 print "", posic, ". ", nextwords$(n - 1) end if
next n end </lang>
- Output:
Igual que la entrada de FreeBASIC.