A+B: Difference between revisions
Line 1,602: | Line 1,602: | ||
loop |
loop |
||
</syntaxhighlight> |
</syntaxhighlight> |
||
==={{header|ProgressBASIC}}=== |
|||
10 INPUT A |
|||
20 INPUT B |
|||
30 PRINT A+B |
|||
==={{header|Sinclair ZX81 BASIC}}=== |
==={{header|Sinclair ZX81 BASIC}}=== |
Revision as of 08:57, 15 July 2024
![Task](http://static.miraheze.org/rosettacodewiki/thumb/b/ba/Rcode-button-task-crushed.png/64px-Rcode-button-task-crushed.png)
You are encouraged to solve this task according to the task description, using any language you may know.
A+B ─── a classic problem in programming contests, it's given so contestants can gain familiarity with the online judging system being used.
- Task
Given two integers, A and B.
Their sum needs to be calculated.
- Input data
Two integers are written in the input stream, separated by space(s):
- Output data
The required output is one integer: the sum of A and B.
- Example
input output 2 2 4 3 2 5
0815
|x|+%
11l
print(sum(input().split(‘ ’, group_delimiters' 1B).map(i -> Int(i))))
360 Assembly
* A+B 29/08/2015
APLUSB CSECT
USING APLUSB,R12
LR R12,R15
OPEN (MYDATA,INPUT)
LOOP GET MYDATA,PG read a single record
XDECI R4,PG input A, in register 4
XDECI R5,PG+12 input B, in register 5
AR R4,R5 A+B, add register 5 to register 4, R4=R4+R
XDECO R4,PG+24 edit A+B
XPRNT PG,36 print A+B
B LOOP repeat
ATEND CLOSE MYDATA
RETURN XR R15,R15
BR R14
LTORG
MYDATA DCB LRECL=24,RECFM=FT,EODAD=ATEND,DDNAME=MYFILE
PG DS CL24 record
DC CL12' '
YREGS
END APLUSB
- Input:
27 53 123 321 999 1
- Output:
27 53 80 123 321 444 999 1 1000
4ME
ns ns + get
8th
gets dup . space eval n:+ . cr
8080 Assembly
As often happens with assembly of any kind, dealing with the I/O requirements turns the whole
task into a grand tour of the language and environment, as one needs to read and parse decimal
numbers, and then write back another decimal number. But simple addition is easy,
even 16-bit addition. The 8080 is otherwise an 8-bit processor, but it includes a 16-bit add
instruction (and only an add, not even a subtract), namely dad
(for "double add"),
which can take four forms:
dad b ; HL += BC (i.e., add BC reg pair to HL reg pair)
dad d ; HL += DE
dad h ; HL += HL (also known as "mul HL by two")
dad sp ; HL += SP (actually the only way to get at SP at all)
Merely doing A+B, with 16-bit numbers so that will fit, would look like this:
lxi h,123
lxi d,456
dad d
; HL is now 579
Then, the following is what is required to wrap it all in a CP/M command line utility. Computers based on the 8080 (or processors that are backwards compatible with it, such as the 8085 and Z80) usually ran the CP/M operating system (or something that is backwards compatible with it, such as MSX-DOS or ZSDOS). This program assembles to an 128-byte binary, which fits exactly in one CP/M block.
fcb1n: equ 5Ch+1 ; "Filename" in first FCB
fcb2n: equ 6Ch+1 ; "Filename" in second FCB
puts: equ 9 ; CP/M call to write string to console
bdos: equ 5 ; CP/M syscall address
org 100h
lxi d,fcb1n ; Get first "file name" (i.e, first number on cmdline)
call parse ; Parse it
push h ; Store the number on the stack
lxi d,fcb2n ; Get the second one
call parse ; Parse that one too
pop d ; Retrieve our first number and put it in DE
dad d ; <-- add DE to HL, giving our answer, then fall into:
;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
;;; Routine: print the signed integer in HL. ;;;
;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
puthl: mov a,h ; Get the sign bit of the integer,
ral ; which is the top bit of the high byte
sbb a ; A=00 if positive, FF if negative
sta negf ; Store it as the negative flag
cnz neghl ; And if HL was negative, make it positive
lxi d,num ; Load pointer to end of number string
push d ; Onto the stack
lxi b,-10 ; Divide by ten (by trial subtraction)
digit: lxi d,-1 ; DE = quotient. There is no 16-bit subtraction,
dgtdiv: dad b ; so we just add a negative value,
inx d
jc dgtdiv ; while that overflows.
mvi a,'0'+10 ; The loop runs once too much so we're 10 out
add l ; The remainder (minus 10) is in L
xthl ; Swap HL with top of stack (i.e., the string pointer)
dcx h ; Go back one byte
mov m,a ; And store the digit
xthl ; Put the pointer back on the stack
xchg ; Do all of this again with the quotient
mov a,h ; If it is zero, we're done
ora l
jnz digit ; But if not, there are more digits
mvi c,puts ; Prepare to call CP/M and print the string
pop d ; Put the string pointer from the stack in DE
lda negf ; See if the number was supposed to be negative
inr a
jnz bdos ; If not, print the string we have and return
dcx d ; But if so, we need to add a minus in front
mvi a,'-'
stax d
jmp bdos ; And only then print the string
;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
;;; Routine: parse (possibly negative) 16-bit integer at [DE], ;;;
;;; result in HL. ;;;
;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
parse: lxi h,negf ; Zero out the negative flag
mvi m,0
ldax d ; Get first byte of number string
cpi '-' ; If minus, it should be negative
jnz prspos ; If not, parse as positive number
inr m ; Set negative flag
inx d ; The actual number starts one byte further on
prspos: lxi h,0 ; Set our 16-bit accumulator to zero
prsdgt: ldax d ; Get current digit
sui '0' ; It's ASCII, so subtract '0'
cpi 10 ; Check if it is a valid digit (<10)
jnc prsdon ; If not, that was the last character, we're done
dad h ; Multiply accumulator by ten
mov b,h ; There is no MUL instruction, but 10*HL = 5*(2*HL),
mov c,l ; = 2*HL + 8*HL. BC=2*HL
dad h ; HL *= 2
dad h ; HL *= 2
dad b ; HL += BC
mov c,a ; Then, add the digit, extended to 16 bits
mvi b,0 ; by setting the top byte to zero.
dad b
inx d ; Then, get the next digit
jmp prsdgt
prsdon: lda negf ; Check if the result was supposed to be negative
dcr a
rnz ; If not, we're done, otherwise, fall through into...
;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
;;; Routine: negate the 16-bit integer in HL. ;;;
;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
neghl: mov a,h ; HL = -HL; i.e. HL = (~HL) + 1
cma ; Get bitwise complement of the high byte,
mov h,a
mov a,l ; And the low byte
cma ; We have to do it byte for byte since it is an 8-bit
mov l,a ; processor.
inx h ; Then add one
ret
negf: db 0 ; Space for negative flag
db '-00000'
num: db '$' ; Space for number
- Output:
A>add 10 10 20 A>add 10 -5 5 A>add -1000 1000 0 A>add -1234 5678 4444
AArch64 Assembly
/* ARM assembly AARCH64 Raspberry PI 3B */
/* program addAetB.s */
/*******************************************/
/* Constantes */
/*******************************************/
.equ STDOUT, 1 // linux output
.equ WRITE, 64 // call system Linux 64 bits
.equ EXIT, 93 // call system Linux 64 bits
/*******************************************/
/* Initialized data */
/*******************************************/
.data
szMessError: .asciz "Error : addAetB <number1> <number2>\n"
szMessResult: .asciz "Result = "
szRetourLigne: .asciz "\n"
/*******************************************/
/* Uninitialized data */
/*******************************************/
.bss
sZoneConv: .skip 100
.text
.global main
main:
mov fp,sp // fp <- adresse début
ldr x0,[fp] // load parameters number in command line
cmp x0,3 // number in command line
blt 99f // no -> error
ldr x0,[fp,16] // recup address of number 1 in command line
bl conversionAtoD // convert string in number in registre x0
mov x1,x0 // save number1
ldr x0,[fp,24] // recup address of number 2 in command line
bl conversionAtoD // convert string in number in registre x0
mov x2,x0 // save number2
add x0,x1,x2 // addition number1 number2
ldr x1,qAdrsZoneConv
bl conversion10S // result decimal conversion
ldr x0,qAdrszMessResult
bl affichageMess // call function display
ldr x0,qAdrsZoneConv
bl affichageMess // call function display
ldr x0, qAdrszRetourLigne
bl affichageMess
mov x0,0 // return code OK
b 100f
99:
ldr x0, qAdrszMessError // adresse of message
bl affichageMess // call function
mov x0,1 // return code error
100: // standard end programm
mov x8,EXIT // request to exit program
svc 0 // perform the system call
qAdrszMessError: .quad szMessError
qAdrszMessResult: .quad szMessResult
qAdrsZoneConv: .quad sZoneConv
qAdrszRetourLigne: .quad szRetourLigne
/******************************************************************/
/* String display with size compute */
/******************************************************************/
/* x0 contains string address (string ended with zero binary) */
affichageMess:
stp x0,x1,[sp,-16]! // save registers
stp x2,x8,[sp,-16]! // save registers
mov x2,0 // size counter
1: // loop start
ldrb w1,[x0,x2] // load a byte
cbz w1,2f // if zero -> end string
add x2,x2,#1 // else increment counter
b 1b // and loop
2: // x2 = string size
mov x1,x0 // string address
mov x0,STDOUT // output Linux standard
mov x8,WRITE // code call system "write"
svc 0 // call systeme Linux
ldp x2,x8,[sp],16 // restaur 2 registres
ldp x0,x1,[sp],16 // restaur 2 registres
ret // retour adresse lr x30
/******************************************************************/
/* Decimal conversion signed */
/******************************************************************/
/* x0 contains the value */
/* x1 contains the address of receiving area length >= 21 */
/* the receiving area return a string ascii left aligned */
/* et avec un zero final */
/* x0 return length string whitout zero final */
.equ LGZONECONV, 21
conversion10S:
stp x5,lr,[sp,-16]! // save registers
stp x3,x4,[sp,-16]! // save registers
stp x1,x2,[sp,-16]! // save registers
cmp x0,0 // is negative ?
bge 11f // no
mov x3,'-' // yes
neg x0,x0 // number inversion
b 12f
11:
mov x3,'+' // positive number
12:
strb w3,[x1]
mov x4,#LGZONECONV // position last digit
mov x5,#10 // decimal conversion
1: // loop conversion start
mov x2,x0 // copy starting number or successive quotients
udiv x0,x2,x5 // division by ten
msub x3,x0,x5,x2 //compute remainder
add x3,x3,#48 // conversion ascii
sub x4,x4,#1 // previous position
strb w3,[x1,x4] // store digit
cbnz x0,1b // end if quotient = zero
mov x2,LGZONECONV // compute string length (21 - dernière position)
sub x0,x2,x4 // no instruction rsb in 64 bits !!!
// move result to area begin
cmp x4,1
beq 3f // full area ?
mov x2,1 // no -> begin area
2:
ldrb w3,[x1,x4] // load a digit
strb w3,[x1,x2] // and store at begin area
add x4,x4,#1 // last position
add x2,x2,#1 // et begin last postion
cmp x4,LGZONECONV - 1 // end ?
ble 2b // no -> loop
3:
mov w3,0
strb w3,[x1,x2] // zero final
add x0,x0,1 // string length must take into account the sign
100:
ldp x1,x2,[sp],16 // restaur 2 registers
ldp x3,x4,[sp],16 // restaur 2 registers
ldp x5,lr,[sp],16 // restaur 2 registers
ret // return address lr x30
/******************************************************************/
/* conversion ascii string to number */
/******************************************************************/
/* x0 contains string address ended by 0x0 or 0xA */
/* x0 return the number */
conversionAtoD:
stp x5,lr,[sp,-16]! // save registers
stp x3,x4,[sp,-16]! // save registers
stp x1,x2,[sp,-16]! // save registers
mov x1,#0
mov x2,#10 // factor ten
mov x4,x0 // save address in x4
mov x3,#0 // positive signe by default
mov x0,#0 // init résult to zéro
mov x5,#0
1: // loop to remove space at begin of string
ldrb w5,[x4],1 // load in w5 string octet
cbz w5,100f // string end -> end routine
cmp w5,#0x0A // string end -> end routine
beq 100f
cmp w5,#' ' // space ?
beq 1b // yes -> loop
2:
cmp x5,#'-' // first character is -
bne 3f
mov x3,#1 // negative number
b 4f // previous position
3: // begin loop compute digit
cmp x5,#'0' // character not a digit
blt 4f
cmp x5,#'9' // character not a digit
bgt 4f
// character is a digit
sub w5,w5,#48
mul x0,x2,x0 // multiply last result by factor
smulh x1,x2,x0 // hight
cbnz x1,99f // overflow ?
add x0,x0,x5 // no -> add to result
4:
ldrb w5,[x4],1 // load new octet and increment to one
cbz w5,5f // string end -> end routine
cmp w5,#0xA // string end ?
bne 3b // no -> loop
5:
cmp x3,#1 // test register x3 for signe
cneg x0,x0,eq // if equal egal negate value
cmn x0,0 // carry to zero no error
b 100f
99: // overflow
adr x0,szMessErrDep
bl affichageMess
cmp x0,0 // carry to one error
mov x0,#0 // if error return zéro
100:
ldp x1,x2,[sp],16 // restaur 2 registers
ldp x3,x4,[sp],16 // restaur 2 registers
ldp x5,lr,[sp],16 // restaur 2 registers
ret // retur address lr x30
szMessErrDep: .asciz "Number too large: overflow of 64 bits. :\n"
.align 4 // instruction to realign the following routines
ABAP
report z_sum_a_b.
data: lv_output type i.
selection-screen begin of block input.
parameters:
p_first type i,
p_second type i.
selection-screen end of block input.
at selection-screen output.
%_p_first_%_app_%-text = 'First Number: '.
%_p_second_%_app_%-text = 'Second Number: '.
start-of-selection.
lv_output = p_first + p_second.
write : / lv_output.
Acornsoft Lisp
Evaluate: (print (plus (read) (read))) 3 2 5
Action!
BYTE FUNC Find(CHAR ARRAY s CHAR c BYTE POINTER err)
BYTE i
FOR i=1 TO s(0)
DO
IF s(i)=c THEN
err^=0 RETURN (i)
FI
OD
err^=1
RETURN (0)
INT FUNC Decode(CHAR ARRAY s BYTE start,stop BYTE POINTER err)
CHAR ARRAY tmp(20),tmp2(20)
INT value
IF s(start)='+ THEN
start==+1
FI
SCopyS(tmp,s,start,stop)
value=ValI(tmp)
;Check if conversion failed
IF value=0 AND s(start)#'0 THEN
err^=1 RETURN (0)
FI
;Check if value is out of range
IF value<-1000 OR value>1000 THEN
err^=1 RETURN (0)
FI
err^=0
RETURN (value)
PROC Main()
CHAR ARRAY s(20)
BYTE pos,err,err2,value
INT a,b,sum
DO
PrintE("Enter two integer numbers between -1000 and 1000, separated by a space or Q for quit")
InputS(s)
IF s(0)=1 AND (s(1)='Q OR s(1)='q) THEN
EXIT
FI
pos=Find(s,' ,@err)
IF err=0 THEN
a=Decode(s,1,pos-1,@err)
b=Decode(s,pos+1,s(0),@err2)
err=err OR err2
FI
IF err=0 THEN
sum=a+b
PrintF("Their sum is %I%E",sum)
ELSE
PrintE("Invalid input!")
FI
PutE();
OD
RETURN
- Output:
Screenshot from Atari 8-bit computer
Enter two integer numbers between -1000 and 1000, separated by a space or Q for quit -320 547 Their sum is 227 Enter two integer numbers between -1000 and 1000, separated by a space or Q for quit 512 -1234 Invalid input! Enter two integer numbers between -1000 and 1000, separated by a space or Q for quit
Ada
-- Standard I/O Streams
with Ada.Integer_Text_Io;
procedure APlusB is
A, B : Integer;
begin
Ada.Integer_Text_Io.Get (Item => A);
Ada.Integer_Text_Io.Get (Item => B);
Ada.Integer_Text_Io.Put (A+B);
end APlusB;
Using appropriate user defined types:
with Ada.Text_IO;
procedure A_Plus_B is
type Small_Integers is range -2_000 .. +2_000;
subtype Input_Values is Small_Integers range -1_000 .. +1_000;
package IO is new Ada.Text_IO.Integer_IO (Num => Small_Integers);
A, B : Input_Values;
begin
IO.Get (A);
IO.Get (B);
IO.Put (A + B, Width => 4, Base => 10);
end A_Plus_B;
Agena
Tested with Agena 2.9.5 Win32
scope
local f := trim( io.read() ) split " "; # read a line and split into fields
local a := tonumber( f[ 1 ] );
local b := tonumber( f[ 2 ] );
print( a + b )
epocs
Aime
file f;
list l;
f_affix(f, "/dev/stdin");
f_list(f, l, 0);
o_integer(atoi(l[0]) + atoi(l[1]));
o_newline();
ALGOL 60
begin
comment A+B;
integer a,b;
ininteger(0,a); ininteger(0,b);
outinteger(1,a+b)
end
- Input:
1 2
- Output:
3
ALGOL 68
Console
print((read int + read int))
Input:
1 2
- Output:
+3
File
open(stand in, "input.txt", stand in channel);
open(stand out, "output.txt", stand out channel);
print((read int + read int))
Input "input.txt":
3 4
Output "output.txt":
+7
ALGOL W
begin
integer a, b;
read( a, b );
write( a + b )
end.
Amazing Hopper
#include <hbasic.h>
#import lib/input.bas.lib
#include include/input.h
Begin
Token Init
Cls
Locate(5,1),Print(Utf8$("Ingrese dos números, separados por espacio: "))
msg=""
LocCol(45),Let( msg := ReadString(msg))
Token Sep(" ")
Print("Suma : ", Token(1),Val(Token$(msg)) Plus (Token(2),Val(Token$(msg))), Newl)
End
- Output:
Ingrese dos números, separados por espacio: -200 10 Suma : -190 Press any key to continue...
Version dos: hopper-BASIC acepta "programación fluída"
#include <hbasic.h>
#import lib/input.bas.lib
#include include/input.h
#define getValueOf(__X__) Token(__X__),Val(Token$(msg))
#define-a »»(__X__) ;Move to(__X__)
Begin
Token Init
Cls
Locate(5,1),Print(Utf8$("Ingrese dos números, separados por espacio: "))
msg=""
LocCol(45),Let( msg := ReadString(msg))
Token Sep(" ")
A=0, get Value Of(1)»»(A), CLamp(-1000,1000,A)
B=0, get Value Of(2)»»(B), CLamp(-1000,1000,B)
Print("Suma : ")
Take(A, B), and Add It; then Print It with a Newl
End
- Output:
Ingrese dos números, separados por espacio: -1005 500 Suma : -500 Press any key to continue...
ANTLR
![aplusb](http://static.miraheze.org/rosettacodewiki/5/59/Aplusb.jpg)
![aplusb](http://static.miraheze.org/rosettacodewiki/5/52/Num.png)
Apex
static Integer sumOfTwoNums(Integer A, Integer B) {
return A + B;
}
System.debug('A = 50 and B = 25: ' + sumOfTwoNums(50, 25));
System.debug('A = -50 and B = 25: ' +sumOfTwoNums(-50, 25));
System.debug('A = -50 and B = -25: ' +sumOfTwoNums(-50, -25));
System.debug('A = 50 and B = -25: ' +sumOfTwoNums(50, -25));
'''Output'''
A = 50 and B = 25: 75
A = -50 and B = 25: -25
A = -50 and B = -25: -75
A = 50 and B = -25: 25
APL
⎕+⎕
AppleScript
Open the AppleScript Editor and save this as A+B.scpt on your Desktop
on run argv
try
return ((first item of argv) as integer) + (second item of argv) as integer
on error
return "Usage with -1000 <= a,b <= 1000: " & tab & " A+B.scpt a b"
end try
end run
To make this run in Terminal open the Terminal.app and type osascript ~/Desktop/A+B.scpt -3 78 followed by enter.
Result: 75
Arc
(prn (+ (read)
(read)))
Argile
(: Standard input-output streams :)
use std, array
Cfunc scanf "%d%d" (&val int a) (&val int b)
printf "%d\n" (a + b)
(: Input file : input.txt :)
(: Output file: output.txt :)
use std, array
let in = fopen "input.txt" "r"
let out = fopen "output.txt" "w"
let int x, y.
Cfunc fscanf in "%d%d" (&x) (&y) (:fscanf not yet defined in std.arg:)
fprintf out "%d\n" (x+y)
fclose in
fclose out
ARM Assembly
Exploiting C standard library functions (scanf and printf). Requires arm-linux-gnueabi-gcc and qemu-arm. Compile with:
arm-linux-gnueabi-as src.s -o src.o && arm-linux-gnueabi-gcc -static src.o -o run && qemu-arm run
.text
.global main
.extern printf
.extern scanf
main:
push {lr}
ldr r0, =scanf_lit
ldr r1, =num_a
ldr r2, =num_b
bl scanf // scanf("%d %d", &num_a, &num_b);
ldr r0, =printf_lit
ldr r1, =num_a
ldr r1, [r1]
ldr r2, =num_b
ldr r2, [r2]
add r1, r1, r2
bl printf // printf("%d\n", num_a + num_b);
pop {pc}
.data
scanf_lit: .asciz "%d %d"
printf_lit: .asciz "%d\n"
.align 4
.bss
num_a: .skip 4
num_b: .skip 4
Todo: -need to print numbers w/o the leading 0's. Replace them with spaces, so alignment is still the same.
Read two strings from stdin, convert to integers calculate their sum, print to stdout. A valid int is a value between -2^31 (-2147483647) and 2^31-1 (2147483647). We do not allow -2147483648 as input, but it is a valid result. E.g. -1 -2147483647. Maximum number of digits is 10. Leading 0's are counted as number length. We read signed values. We ignore leading '+'s and allow '-' for negative values. If multiple plus or minus signs precede a number, only the last one counts. minval and maxval can be used to specify any valid range, (e.g. -1000 and +1000). The range is inclusive. If 0 is specified for both ranges, range checks are not done.
Tested on RaspberryPi model B (GNU/Linux, ARMv6) Save in ab.S Build with:
as -o ab.o ab.S
ld -o a.out ab.o
.data
.align 2
.code 32
.section .rodata
.align 2
.code 32
overflow_msg: .ascii "Invalid number. Overflow.\n"
overflow_msglen = . - overflow_msg
bad_input_msg: .ascii "Invalid input. NaN.\n"
bad_input_msglen = . - bad_input_msg
range_err_msg: .ascii "Value out of range.\n"
range_err_msglen = . - range_err_msg
io_error_msg: .ascii "I/O error.\n"
io_error_msglen = . - range_err_msg
sys_exit = 1
sys_read = 3
sys_write = 4
max_rd_buf = 14
lf = 10
m10_9 = 0x3b9aca00
maxval = 1000
minval = -1000
.text
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
@@ void main()
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
.align 2
.code 32
.type _start STT_FUNC
.global _start
_start:
stmfd sp!, {r4,r5,lr}
.read_lhs:
ldr r0, =max_rd_buf
bl readint
mov r4, r0
bl printint
mov r0, r4
bl range_check
.read_rhs:
ldr r0, =max_rd_buf
bl readint
mov r5, r0
bl printint
mov r0, r5
bl range_check
.sum_and_print:
adds r0, r4, r5
bvs overflow
bl printint
.main_exit:
mov r0, #0
bl exit
ldmfd sp!, {r4,r5,pc}
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
@@ Read from stdin until we encounter a non-digit, or we have read bytes2rd digits.
@@ Ignore leading spaces.
@@ Return value to the caller converted to a signed int.
@@ We read positive values, but if we read a leading '-' sign, we convert the
@@ return value to two's complement.
@@ The argument is max number of bytes to read from stdin.
@@ int readint(int bytes2rd)
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
.align 2
.code 32
.type readint STT_FUNC
.global readint
readint:
stmfd sp!, {r4,r5,r6,r7,lr}
@@@@@@@@@@@@@@@
@@ r0 : #0 for stdin arg to read.
@@ r1 : ptr to current pos in local buffer.
@@ r2 : #1 to read one byte at a time.
@@ r3,r7 : tmp.
@@ r4 : number of bytes read.
@@ r5 : value of current byte.
@@ r6 : 0 while we are reading leading spaces.
@@@@@@@@@@@@@@@
sub sp, sp, r0
mov r1, sp
mov r3, #0
push {r3} @ sp,#4: local var @isnegative. return in r1. Default value is 0/false. Positive number.
push {r0} @ sp,#0: local var @maxbytes. const.
mov r2, #1
mov r4, #0
mov r6, #0
b .rd
@ we get here if r6 is 0.
@ if space, goto .rd.
@ else set r6 to 1 and goto .noleading.
.leadchk:
mov r0, r5
bl isspace
cmp r0, #1
beq .rd
.sign_chk:
mov r0, r5
push {r1}
bl issign
cmp r0, #1
streq r0, [sp,#8] @ sp,#4 + 4 for the pushed r1.
movhi r1, #0
strhi r1, [sp,#8] @ sp,#4 + 4 for the pushed r1.
pop {r1}
bhs .rd
mov r6, #1
b .noleading
.rd:
mov r0, #0
bl read
cmp r0, #1
bne .sum_digits_eof @ eof
mov r5, #0
ldrb r5, [r1]
cmp r6, #0
beq .leadchk
.noleading:
mov r0, r5
bl isdigit
cmp r0, #1
bne .sum_digits_nan @ r5 is non-digit
add r4, r4, #1
add r1, r1, #1
@ max chars to read is received in arg[0], stored in local var at sp.
@ Only 10 can be valid, so the default of 12 leaves space for separator.
ldr r3, [sp]
cmp r4, r3
beq .sum_digits_maxrd @ max bytes read.
b .rd
@@@@@@@@@@@@@@@
@ We have read r4 (0..arg[0](default 12)) digits when we get here. Go through them
@ and add/mul them together to calculate a number.
@ We multiply and add the digits in reverse order to simplify the multiplication.
@@@@@@@@@@@@@@@
@ r0: return value.
@ r1: local variable for read buffer.
@ r2: tmp for conversion.
@ r3,r6,r7: tmp
@ r4: number of chars we have read.
@ r5: multiplier 1,10,100.
@@@@@@@@@@@@@@@
.sum_digits_nan:
mov r0, r5
bl isspace
cmp r0, #1
bne bad_input
.sum_digits_maxrd:
.sum_digits_eof:
mov r0, #0
mov r5, #1
.count:
cmp r4, #0
beq .readint_ret
sub r4, r4, #1
sub r1, #1
ldrb r2, [r1]
sub r2, r2, #48
mov r3, r2
@ multiply r3 (char value of digit) with r5 (multiplier).
@ possible overflow.
@ MI means negative.
@ smulls multiples two signed 32 bit vals and returns a 64 bit result.
@ If we get anything in r7, the value has overflowed.
@ having r2[31] set is overflow too.
smulls r2, r7, r3, r5
cmp r7, #0
bne overflow
cmp r2, #0
bmi overflow
@@ possible overflow.
adds r0, r0, r2
bvs overflow
bmi overflow
@@ end of array check.
@@ check is needed here too, for large numbers, since 10 billion is not a valid 32 bit val.
cmp r4, #0
beq .readint_ret
@@ multiple multiplier by 10.
@@ possible overflow.
@@ too many digits is input. happens if input is more than 10 digits.
mov r3, #10
mov r6, r5
smulls r5, r7, r3, r6
cmp r7, #0
bne overflow
cmp r5, #0
bmi overflow
b .count
.readint_ret:
ldr r1, [sp,#4] @ read isnegative value.
cmp r1, #0
rsbne r0, r0, #0
pop {r2}
add sp, sp, #4
add sp, sp, r2
ldmfd sp!, {r4,r5,r6,r7,pc}
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
@@ int isdigit(int)
@@ #48..#57 ascii range for '0'..'9'.
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
.align 2
.code 32
.type isdigit STT_FUNC
.global isdigit
isdigit:
stmfd sp!, {r1,lr}
cmp r0, #48
blo .o_range
cmp r0, #57
bhi .o_range
mov r0, #1
ldmfd sp!, {r1,pc}
.o_range:
mov r0, #0
ldmfd sp!, {r1,pc}
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
@@ int isspace(int)
@@ ascii space = 32, tab = 9, newline 10, cr = 13.
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
.align 2
.code 32
.type isspace STT_FUNC
.global isspace
isspace:
stmfd sp!, {lr}
cmp r0, #32
cmpne r0, #9
cmpne r0, #10
cmpne r0, #13
beq .is_space
mov r0, #0
ldmfd sp!, {pc}
.is_space:
mov r0, #1
ldmfd sp!, {pc}
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
@@ Return value is 1 for '-' 2 for '+'.
@@ int isspace(int)
@@ '+' = 43 and '-' = 45.
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
.align 2
.code 32
.type issign STT_FUNC
.global issign
issign:
stmfd sp!, {lr}
cmp r0, #43
beq .plus_sign
cmp r0, #45
beq .minus_sign
mov r0, #0
ldmfd sp!, {pc}
.plus_sign:
mov r0, #2
ldmfd sp!, {pc}
.minus_sign:
mov r0, #1
ldmfd sp!, {pc}
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
@@ ARGS:
@@ r0 : in out arg (current int value)
@@ r1 : in out arg (ptr to current pos in buffer)
@@ r2 : in arg (const increment. 1000_000_000, 100_000_000, 10_000_000, 1000_000, 100_000, 10_000, 1000, 100, 10, 1.)
@@
@@ r4 : tmp local. Outer scope must init to #10 and count down to #0.
@@ Special case is INTMAX. Must init to 5 if r4 >= 1000_000_000 (0x3b9aca00 = m10_9).
@@ r5: tmp
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
.align 2
.code 32
.type get_digit STT_FUNC
.global get_digit
get_digit:
stmfd sp!, {r2,r4,r5,lr}
ldr r5, =m10_9
cmp r2, r5
movlo r4, #10
movhs r4, #5
.get_digit_loop:
sub r4, #1
mul r5, r4, r2
cmp r0, r5
blo .get_digit_loop
sub r0, r5
add r4, r4, #48
strb r4, [r1], #1
ldmfd sp!, {r2,r4,r5,pc}
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
@@ A quick way to divide (numbers evenly divisible by 10) by 10.
@@ Most ARM cpus don't have a divide instruction,
@@ so this will always work.
@@ A generic div function is long and not needed here.
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
.align 2
.div_r2_10:
stmfd sp!, {r0,r1,r3,lr}
mov r0, #1
mov r1, #10
.find_x:
mul r3, r0, r1;
cmp r3, r2
movlo r0, r3
blo .find_x
mov r2, r0
ldmfd sp!, {r0,r1,r3,pc}
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
@@
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
.align 2
.print_neg_sign:
stmfd sp!, {r0,r1,r2,lr}
@ 45 = '-'
mov r1, #45
push {r1}
mov r2, #1
@ r1 is ptr to our local variable (holding '-').
mov r1, sp
mov r0, #1
bl write
cmp r0, #0
blne io_error
pop {r1}
ldmfd sp!, {r0,r1,r2,pc}
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
@@ void printint(int val)
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
.align 2
.code 32
.type printint STT_FUNC
.global printint
printint:
stmfd sp!, {r4,r5,r6,lr}
mov r1, #1
ands r1, r1, r0, LSR #31
rsbne r0, r0, #0
blne .print_neg_sign
sub sp, sp, #20
mov r1, sp
mov r3, sp
ldr r2, =m10_9
.getc_loop:
bl get_digit
cmp r2, #1
beq .exit_getc_loop
bl .div_r2_10
b .getc_loop
.exit_getc_loop:
ldr r0, =lf
strb r0, [r1], #1
sub r2, r1, r3
mov r1, r3
mov r0, #1
bl write
cmp r0, #0
blne io_error
add sp, sp, #20
ldmfd sp!, {r4,r5,r6,pc}
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
@@
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
.align 2
range_check:
stmfd sp!, {r4,r5,lr}
ldr r4, =minval
ldr r5, =maxval
cmp r4, #0
cmpeq r5, #0
beq .skip_range_check
cmp r0, r4
bllt range_err
cmp r0, r5
blgt range_err
.skip_range_check:
ldmfd sp!, {r4,r5,pc}
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
@ void range_err()
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
.align 2
range_err:
stmfd sp!, {lr}
ldr r2, =range_err_msglen
ldr r1, =range_err_msg
mov r0, #2
bl write
mov r0, #-1
bl exit
ldmfd sp!, {pc}
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
@ void overflow()
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
.align 2
overflow:
stmfd sp!, {lr}
ldr r2, =overflow_msglen
ldr r1, =overflow_msg
mov r0, #2
bl write
mov r0, #-1
bl exit
ldmfd sp!, { pc}
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
@ void bad_input()
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
.align 2
bad_input:
stmfd sp!, {lr}
ldr r2, =bad_input_msglen
ldr r1, =bad_input_msg
mov r0, #2
bl write
mov r0, #-1
bl exit
ldmfd sp!, {pc}
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
@ void io_error()
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
.align 2
io_error:
stmfd sp!, {lr}
ldr r2, =io_error_msglen
ldr r1, =io_error_msg
mov r0, #2
bl write
mov r0, #-1
bl exit
ldmfd sp!, {pc}
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
@ void exit(int)
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
.align 2
.code 32
.type _start STT_FUNC
.global exit
exit:
stmfd sp!, {r7, lr}
ldr r7, =sys_exit
svc #0
ldmfd sp!, {r7, pc}
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
@ int write(int fd,char*buf,int len)
@ Return 0 if we successfully write all bytes. Otherwise return the error code.
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
.align 2
.code 32
.type _start STT_FUNC
.global write
write:
stmfd sp!, {r4,r7, lr}
mov r4, r2
.wr_loop:
ldr r7, =sys_write
svc #0
@ If r0 is negative, it is more than r4 with LO (unsigned <).
cmp r0, r4
sublo r4, r0
blo .wr_loop
moveq r0, #0
ldmfd sp!, {r4,r7, pc}
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
@ int read(int fd,char*buf,int len)
@ Return number of bytes successfully read. Ignore errors.
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
.align 2
.code 32
.type _start STT_FUNC
.global read
read:
stmfd sp!, {r7, lr}
ldr r7, =sys_read
svc #0
cmp r0, #0
movlt r0, #0
ldmfd sp!, {r7, pc}
Arturo
while ø [
x: map split.words input "give me 2 numbers:" 'x -> to :integer x
print add x\0 x\1
]
- Output:
give me 2 numbers:3 4 7 give me 2 numbers:2 5 7
AsciiDots
<
&-#$-\
.-#?-[+]
.-#?--/
ATS
(* ****** ****** *)
//
#include
"share/atspre_staload.hats"
//
staload UN = $UNSAFE
//
(* ****** ****** *)
staload "libc/SATS/stdio.sats"
(* ****** ****** *)
implement
main0() = let
var A: int
var B: int
val () =
$extfcall
(void, "scanf", "%d%d", addr@A, addr@B)
// end of [val]
in
println! ($UN.cast2int(A) + $UN.cast2int(B))
end // end of [main0]
(* ****** ****** *)
AutoHotkey
This handles more than two inputs
Gui, Add, Edit, vEdit ;Enter your A+B, i.e. 5+3 or 5+3+1+4+6+2
Gui, Add, Button, gAdd, Add
Gui, Add, Edit, ReadOnly x+10 w80
Gui, Show
return
Add:
Gui, Submit, NoHide
Loop, Parse, Edit, + ;its taking each substring separated by "+" and its storing it in A_LoopField
var += A_LoopField ;here its adding it to var
GuiControl, Text, Edit2, %var% ;here it displays var in the second edit control
var := 0 ;here it makes sure var is 0 so it won't contain the value from the previous addition
return
AutoIt
;AutoIt Version: 3.2.10.0
$num = "45 54"
consolewrite ("Sum of " & $num & " is: " & sum($num))
Func sum($numbers)
$numm = StringSplit($numbers," ")
Return $numm[1]+$numm[$numm[0]]
EndFunc
Example2
This version can handle any amount of numbers in the input:
ConsoleWrite("# A+B:" & @CRLF)
Func Sum($inp)
Local $num = StringSplit($inp, " "), $sum = 0
For $i = 1 To $num[0]
;~ ConsoleWrite("# num["&$i&"]:" & $num[$i] & @CRLF) ;;
$sum = $sum + $num[$i]
Next
Return $sum
EndFunc ;==>Sum
$inp = "17 4"
$res = Sum($inp)
ConsoleWrite($inp & " --> " & $res & @CRLF)
$inp = "999 42 -999"
ConsoleWrite($inp & " --> " & Sum($inp) & @CRLF)
; In calculations, text counts as 0,
; so the program works correctly even with this input:
Local $inp = "999x y 42 -999", $res = Sum($inp)
ConsoleWrite($inp & " --> " & $res & @CRLF)
- Output:
# A+B: 17 4 --> 21 999 42 -999 --> 42 999x y 42 -999 --> 42
AWK
{print $1 + $2}
BabyCobol
* NB: COBOL's ACCEPT does not work with multiple identifiers
IDENTIFICATION DIVISION.
PROGRAM-ID. PLUS.
DATA DIVISION.
01 A PICTURE IS S9999.
01 B LIKE A.
PROCEDURE DIVISION.
DISPLAY "Enter two numbers: " WITH NO ADVANCING.
ACCEPT A B.
ADD A TO B.
DISPLAY "A+B =" B.
BASIC
DEFINT A-Z
tryagain:
backhere = CSRLIN
INPUT "", i$
i$ = LTRIM$(RTRIM$(i$))
where = INSTR(i$, " ")
IF where THEN
a = VAL(LEFT$(i$, where - 1))
b = VAL(MID$(i$, where + 1))
c = a + b
LOCATE backhere, LEN(i$) + 1
PRINT c
ELSE
GOTO tryagain
END IF
Applesoft BASIC
10 BH = PEEK(37)
20 INPUT ""; A$ : I$ = A$ : VTAB BH : A = PEEK(40) + PEEK(41) * 256 : FOR S = 0 TO 39 : IF PEEK(A + S) = 160 THEN NEXT S : S = 0
40 IF LEN(I$) THEN IF MID$(I$, LEN(I$), 1) = " " THEN I$ = MID$(I$, 1, LEN(I$) - 1) : GOTO 40RTRIM
50 IF LEN(I$) < 3 THEN 10"TRY AGAIN
60 FOR WHERE = 1 TO LEN(I$) : IF MID$(I$, WHERE, 1) <> " " THEN NEXT WHERE : GOTO 10"TRY AGAIN
70 A% = VAL(LEFT$(I$, WHERE - 1))
80 B% = VAL(MID$(I$, WHERE + 1, LEN(I$)))
90 C% = A% + B%
100 VTAB BH
110 HTAB LEN(A$) + 2 + S
120 PRINT C%
BaCon
' A+B
INPUT d$
PRINT VAL(TOKEN$(d$, 1)) + VAL(TOKEN$(d$, 2))
BASIC256
dim a(2)
input "Enter two numbers separated by a space?", t$
a = explode(t$," ")
print t$ & " " & int(a[0]) + int(a[1])
BBC BASIC
REPEAT
hereY% = VPOS
INPUT LINE "" q$
hereX% = LEN(q$) + 1
WHILE LEFT$(q$, 1) = " "
q$ = MID$(q$, 2)
ENDWHILE
space% = INSTR(q$, " ")
IF space% THEN
a = VAL(LEFT$(q$, space% - 1))
b = VAL(MID$(q$, space% + 1))
PRINT TAB(hereX%, hereY%) ; a + b
ENDIF
UNTIL FALSE
That seems overly complicated. What's wrong with:
REPEAT
INPUT LINE "" q$
space% = INSTR(q$," ")
PRINT VAL LEFT$(q$,space%-1) + VAL MID$(q$,space%+1)
UNTIL FALSE
Chipmunk Basic
10 CLS : rem 10 HOME for Applesoft BASIC
20 PRINT "ENTER TWO NUMBERS, SEPARATED BY A SPACE: ";
30 INPUT X$
40 I = 1 : N = LEN(X$)
50 IF MID$(X$, I, 1) <> " " AND I < N THEN I = I + 1 : GOTO 50
60 A = VAL(LEFT$(X$, I))
70 B = VAL(RIGHT$(X$, N - 1))
80 PRINT A + B
90 END
Commodore BASIC
10 PRINT "ENTER TWO NUMBERS, SEPARATED BY A SPACE: ";
20 INPUT X$
30 I = 1 : N = LEN(X$)
40 IF MID$(X$,I,1)<>" " AND I<N THEN I = I+1 : GOTO 40
50 A = VAL(LEFT$(X$,I))
60 B = VAL(RIGHT$(X$,N-1))
70 PRINT A+B
FreeBASIC
' fb 1.05.0 Win64
Dim As Integer a, b
Do
Print "Enter two integers separated by a space : ";
Input "", a, b
If Abs(a) > 1000 OrElse Abs(b) > 1000 then
Print "Both numbers must be in the interval [-1000, 1000] - try again"
Print
Else
Print "Their sum is"; a + b
Exit Do
End If
Loop
Print
Print "Press any key to quit the program"
Sleep
GW-BASIC
The Chipmunk Basic solution works without any changes.
FUZE BASIC
INPUT n$
PRINT VAL(LEFT$(n$,(LEN(STR$(VAL(n$))))))+VAL(RIGHT$(n$,(LEN(n$)-LEN(STR$(VAL(n$)))-1)))
END
IS-BASIC
100 DO
110 INPUT PROMPT "Ener two integers separated by a comma: ":A,B
120 IF ABS(A)>1000 OR ABS(B)>1000 OR IP(A)<>A OR IP(B)<>B THEN
130 PRINT "Both integers must be in the interval [-1000..1000] - try again.":PRINT
140 ELSE
150 PRINT "Their sum is";A+B
160 EXIT DO
170 END IF
180 LOOP
Liberty BASIC
input, n$
print eval(word$(n$,1);" + ";word$(n$,2))
Minimal BASIC
10 PRINT "ENTER NUMBER A";
20 INPUT A
30 PRINT "ENTER NUMBER B";
40 INPUT B
50 PRINT A+B
60 END
MSX Basic
The Chipmunk Basic solution works without any changes.
OxygenBasic
uses console
int i
string s
do
print "Enter 2 numbers separated by space "
s=input
s=ltrim(s)
exit if not s
i=instr(s," ")
exit if i<2
print val(s)+val(mid(s,i))+cr
loop
ProgressBASIC
10 INPUT A 20 INPUT B 30 PRINT A+B
Sinclair ZX81 BASIC
10 INPUT A$
20 LET I=1
30 IF A$(I)=" " THEN GOTO 60
40 LET I=I+1
50 GOTO 30
60 PRINT VAL A$( TO I-1)+VAL A$(I+1 TO )
SmallBASIC
input "Enter number A: "; a
input "Enter number B: "; b
print "A + B = "; a + b
Tiny BASIC
REM Rosetta Code problem: https://rosettacode.org/wiki/A+B
REM by Jjuanhdez, 06/2022
10 LET C = 0
LET D = 0
PRINT "Enter an integer: "
INPUT A
IF A < 0 THEN LET C = A * -1
PRINT "Enter other integer: "
INPUT B
IF B < 0 THEN LET D = B * -1
IF C > 1000 THEN GOTO 60
IF D > 1000 THEN GOTO 60
50 PRINT "Their sum is ", A + B
GOTO 70
60 PRINT "Both integers must be in the range [-1000..1000] - try again."
GOTO 10
70 END
True BASIC
DO
INPUT PROMPT "Enter two integers separated by a comma: ": A, B
IF ABS(A)>1000 OR ABS(B)>1000 OR IP(A)<>A OR IP(B)<>B THEN
PRINT "Both integers must be in the interval [-1000..1000] - try again."
PRINT
ELSE
PRINT "Their sum is";A+B
EXIT DO
END IF
LOOP
END
uBasic/4tH
s = FUNC(_GetInt(1000)) + FUNC(_GetInt(1000))
Print "The sum is: ";s
End
_GetInt
Param (1)
Local (1)
Do
Input "Enter a value: ", b@
Until (b@ > -a@-1 ) * (b@ < a@+1)
Print "Wrong, must be between "; -a@; " and "; a@; ". Try again.."
Loop
Return (b@)
XBasic
PROGRAM "A+B"
VERSION "0.0000"
DECLARE FUNCTION Entry ()
FUNCTION Entry ()
a$ = INLINE$("Enter integer A: ")
a = SLONG(a$)
b$ = INLINE$("Enter integer B: ")
b = SLONG(b$)
DO WHILE 1
IF ABS(a) > 1000 OR ABS(b) > 1000 THEN
PRINT "Both integers must be in the interval [-1000..1000] - try again."
PRINT
ELSE
PRINT "Their sum is"; a + b
EXIT DO
END IF
LOOP
END FUNCTION
END PROGRAM
Batch File
Prompts version
::aplusb.cmd
@echo off
setlocal
set /p a="A: "
set /p b="B: "
set /a c=a+b
echo %c%
endlocal
All on the commandline version
::aplusb.cmd
@echo off
setlocal
set a=%1
set b=%2
set /a c=a+b
echo %c%
endlocal
Formula on the command line version
::aplusb.cmd
@echo off
setlocal
set /a c=%~1
echo %c%
endlocal
Example of 'Formula on the command line version'
>aplusb 123+456 579 >aplusb "1+999" 1000
Parse the input stream version (thanks to Tom Lavedas on alt.msdos.batch.nt)
::aplusb.cmd
@echo off
setlocal
set /p a="Input stream: "
call :add %a%
echo %res%
endlocal
goto :eof
:add
set /a res=res+%1
shift
if "%1" neq "" goto :add
Example of 'parse the input stream version'
>aplusb Input stream: 1234 5678 6912 >aplusb Input stream: 123 234 345 456 567 678 789 890 4082
bc
read() + read()
Befunge
&&+.@
Bird
use Console Math
define Main
$a Console.Read
$b Console.Read
Console.Println Math.Add $a $b
end
BlooP
BlooP and FlooP can't actually read from stdin, but here's the procedure it would use, if it could.
DEFINE PROCEDURE ''ADD'' [A, B]:
BLOCK 0: BEGIN
OUTPUT <= A + B;
BLOCK 0: END.
bootBASIC
Both numbers are entered separately.
10 print "Number 1";
20 input a
30 print "Number 2";
40 input b
50 print a+b
BQN
#!/usr/bin/env bqn
# Cut 𝕩 at occurrences of 𝕨, removing separators and empty segments
# (BQNcrate phrase).
Split ← (¬-˜⊢×·+`»⊸>)∘≠⊔⊢
# Natural number from base-10 digits (BQNcrate phrase).
Base10 ← 10⊸×⊸+˜´∘⌽
# Parse any number of space-separated numbers from string 𝕩.
ParseNums ← {Base10¨ -⟜'0' ' ' Split 𝕩}
# •GetLine and •_while_ are nonstandard CBQN extensions.
{•Show +´ ParseNums 𝕩 ⋄ •GetLine@} •_while_ (@⊸≢) •GetLine@
Bracmat
filter
is a pattern that checks that input is a non-fractional number not less than -1000 and not greater than 1000. The filter is applied to each input.
( out
$ ( put$"Enter two integer numbers between -1000 and 1000:"
& (filter=~/#%:~<-1000:~>1000)
& get':(!filter:?a) (!filter:?b)
& !a+!b
| "Invalid input. Try again"
)
);
Brainf***
INPUT AND SUMMATION
TODO if first symbol is a minus sign print Qgo awayQ
+> initialize sum to one
++[ loop for each input ie twice
[>>,----------[----------------------[-<+>]]<] eat digits until space or newline
<[<]>>>
>[< until no next digit
---------------- subtract ascii zero minus what we subtracted above
[->++++++++++<] add ten timess that to the next digit
<[->+<]<[->+<]>> shift sum and loop counter
>>
]
<---------------- subtract as above from last digit as well
[-<<+>>] add to sum
<-
]
<- subtract original one from sum
OUTPUT
[ while a number divided by ten is bigger than zero
[->+<[->+<[->+<[->+<[->+<[->+<[->+<[->+<[->+<[->--------->+<<[->>>+<<<]]]]]]]]]]>>>[-<<<+>>>]<<<] divide by ten
>++++++++++++++++++++++++++++++++++++++++++++++++> convert remainder to ascii digit
]
<[.<<] print ascii digits
Brat
numbers = g.split[0,1].map(:to_i)
p numbers[0] + numbers[1] #Prints the sum of the input
Bruijn
:import std/Combinator .
:import std/String .
:import std/Number .
:import std/Char C
main (split-by (C.eq? ' ')) → &(add ⋔ string→number)
Burlesque
ps++
C
// Standard input-output streams
#include <stdio.h>
int main()
{
int a, b;
scanf("%d%d", &a, &b);
printf("%d\n", a + b);
return 0;
}
// Input file: input.txt
// Output file: output.txt
#include <stdio.h>
int main()
{
freopen("input.txt", "rt", stdin);
freopen("output.txt", "wt", stdout);
int a, b;
scanf("%d%d", &a, &b);
printf("%d\n", a + b);
return 0;
}
#include <stdio.h>
#include <stdlib.h>
int main(int argc, char **argv) //not sure if argv counts as input stream... certainly it is brought here via input stream.
{
printf("%d\n", atoi(*(argv+1)) + atoi(*(argv+2)));
return 0;
}
C#
using System;
using System.Linq;
class Program
{
static void Main()
{
Console.WriteLine(Console.ReadLine().Split().Select(int.Parse).Sum());
}
}
Another way (not recommended since it does not work with more than two numbers):
using System;
class Program
{
static void Main()
{
string input = Console.ReadLine();
int index = input.IndexOf(" ");
int num1 = int.Parse(input.Substring(0, index));
int num2 = int.Parse(input.Substring(index + 1));
int sum = num1 + num2;
Console.WriteLine(sum.ToString());
}
}
C++
// Standard input-output streams
#include <iostream>
using namespace std;
int main()
{
int a, b;
cin >> a >> b;
cout << a + b << endl;
}
// Input file: input.txt
// Output file: output.txt
#include <fstream>
using namespace std;
int main()
{
ifstream in("input.txt");
ofstream out("output.txt");
int a, b;
in >> a >> b;
out << a + b << endl;
return 0;
}
Ceylon
shared void run() {
print("please enter two numbers for me to add");
value input = process.readLine();
if (exists input) {
value tokens = input.split().map(Integer.parse);
if (tokens.any((element) => element is ParseException)) {
print("numbers only, please");
return;
}
value numbers = tokens.narrow<Integer>();
if (numbers.size != 2) {
print("two numbers, please");
}
else if (!numbers.every((Integer element) => -1k <= element <= 1k)) {
print("only numbers between -1000 and 1000, please");
}
else if (exists a = numbers.first, exists b = numbers.last) {
print(a + b);
}
else {
print("something went wrong");
}
}
}
CFEngine
There is no concept of CFEngine policy reading from stdin so I will read from a file.
$ cat sum.cf
bundle agent main
{
vars:
"line_count" int => readintarray(
"input",
"${this.promise_dirname}${const.dirsep}input.txt",
"#[^\n]*",
" ",
"inf",
"inf"
);
"indices" slist => getindices( "input" );
reports:
"${with}" with => format( "%d", eval( "${input[${indices}][0]} + ${input[${indices}][1]}" ));
DEBUG::
"line_count is ${line_count}";
"input is ${with}" with => storejson( "input" );
"input[${indices}] is ${with}" with => storejson( "input[${indices}]" );
}
$ cat input.txt
2 3
2 2
$ cf-agent -KIf ./sum.cf
R: 5
R: 4
The "R:" prefix is for a report promise and the only way to output to stdout with policy. You could also output to a file I suppose.
Clojure
(println (+ (Integer/parseInt (read-line)) (Integer/parseInt (read-line))))
3
4
=>7
(eval (read-string (str "(+ " (read-line) " )") ))
3 3
6
Translation of Common Lisp version:
(println (+ (read) (read)))
3 4
7
Safely and without reader tricks:
(let [ints (map #(Integer/parseInt %) (clojure.string/split (read-line) #"\s") )]
(println (reduce + ints)))
3 4
=>7
or same as above, but without "let":
(println (reduce + (map #(Integer/parseInt %) (clojure.string/split (read-line) #"\s") )))
3 4
=>7
COBOL
IDENTIFICATION DIVISION.
PROGRAM-ID. A-Plus-B.
DATA DIVISION.
WORKING-STORAGE SECTION.
01 A PIC S9(5).
01 B PIC S9(5).
01 A-B-Sum PIC S9(5).
PROCEDURE DIVISION.
ACCEPT A
ACCEPT B
ADD A TO B GIVING A-B-Sum
DISPLAY A-B-Sum
GOBACK
.
A second version.
IDENTIFICATION DIVISION.
PROGRAM-ID. A-Plus-B.
AUTHOR. Bill Gunshannon.
INSTALLATION. Home.
DATE-WRITTEN. 25 December 2021.
************************************************************
** Program Abstract:
** A re-worked version that more closely matches the
** desired format. Both numbers are taken in on one
** line separated by spaces. Sum is formated to remove
** leading zeros and/or spaces.
************************************************************
DATA DIVISION.
WORKING-STORAGE SECTION.
01 Input-Data PIC X(16).
01 A PIC S9(5).
01 B PIC S9(5).
01 A-B-Sum PIC -----9.
PROCEDURE DIVISION.
DISPLAY "Input pairs of numbers separated by spaces."
DISPLAY "Enter q to exit."
PERFORM WITH TEST BEFORE
UNTIL Input-Data = "q" or Input-Data = "Q"
ACCEPT Input-Data
IF Input-Data NOT = "q" and Input-Data NOT = "Q"
UNSTRING Input-Data DELIMITED BY SPACES
INTO A B
ADD A TO B GIVING A-B-Sum
DISPLAY "Sum = " FUNCTION TRIM(A-B-Sum)
END-IF
END-PERFORM.
STOP RUN.
CoffeeScript
<html>
<script type="text/javascript" src="http://jashkenas.github.com/coffee-script/extras/coffee-script.js"></script>
<script type="text/coffeescript">
a = window.prompt 'enter A number', ''
b = window.prompt 'enter B number', ''
document.getElementById('input').innerHTML = a + ' ' + b
sum = parseInt(a) + parseInt(b)
document.getElementById('output').innerHTML = sum
</script>
<body>
<div id='input'></div>
<div id='output'></div>
</body>
</html>
{ stdin } = process
sum = ( a, b ) -> a + b
display = ( messages... ) -> console.log messages...
parse = ( input ) ->
parseInt x for x in ( x.trim() for x in input.split ' ' ) when x?.length
check = ( numbers... ) ->
return no for x in numbers when isNaN x
return no for x in numbers when not ( -1000 < x < 1000 )
yes
prompt = ->
display 'Please enter two integers between -1000 and 1000, separated by a space:'
stdin.once 'data', ( data ) ->
[ a, b ] = parse data
if check a, b
display "#{ a } + #{ b } = #{ sum a, b }"
else
display "Invalid input: #{ a }, #{ b }"
do prompt
return
# Resume input and set the incoming encoding.
stdin.resume()
stdin.setEncoding 'utf8'
# Start the main loop.
do prompt
Common Lisp
(write (+ (read) (read)))
Component Pascal
BlackBox Component Builder
MODULE AB;
IMPORT StdLog, DevCommanders,TextMappers;
PROCEDURE DoAB(x,y: INTEGER);
BEGIN
StdLog.Int(x);StdLog.Int(y);StdLog.Int(x + y);StdLog.Ln;
END DoAB;
PROCEDURE Go*;
VAR
params: DevCommanders.Par;
s: TextMappers.Scanner;
p : ARRAY 2 OF INTEGER;
current: INTEGER;
BEGIN
current := 0;
params := DevCommanders.par;
s.ConnectTo(params.text);
s.SetPos(params.beg);
s.Scan;
WHILE(~s.rider.eot) DO
IF (s.type = TextMappers.int) THEN
p[current] := s.int; INC(current);
END;
s.Scan;
END;
IF current = 2 THEN DoAB(p[0],p[1]) END;
END Go;
END AB.
Execute: AB.Go 12 23 ~
- Output:
12 23 35
Computer/zero Assembly
STP ; wait for input
a: 0
b: 0
LDA a
ADD b
STP
Crystal
puts gets.not_nil!.split.map(&.to_i).sum
The not_nil!
call on gets
is needed because gets
might return nil
and the compiler forces us to deal with it.
In the case of nil
a runtime exception will be thrown.
To handle the nil
case we could do:
if line = gets
puts line.split.map(&.to_i).sum
else
puts "No input"
end
D
From Console
import std.stdio, std.conv, std.string;
void main() {
string[] r;
try
r = readln().split();
catch (StdioException e)
r = ["10", "20"];
writeln(to!int(r[0]) + to!int(r[1]));
}
- Output:
30
From File
void main() {
import std.stdio, std.file;
immutable ab = "sum_input.txt".slurp!(int, int)("%d %d")[0];
"sum_output.txt".File("w").writeln(ab[0] + ab[1]);
}
Dart
import 'dart:io';
// a little helper function that checks if the string only contains
// digits and an optional minus sign at the front
bool isAnInteger(String str) => str.contains(new RegExp(r'^-?\d+$'));
void main() {
while(true) {
String input = stdin.readLineSync();
var chunks = input.split(new RegExp(r'[ ]+')); // split on 1 or more spaces
if(!chunks.every(isAnInteger)) {
print("not an integer!");
} else if(chunks.length > 2) {
print("too many numbers!");
} else if(chunks.length < 2) {
print('not enough numbers!');
} else {
// parse the strings into integers
var nums = chunks.map((String s) => int.parse(s));
if(nums.any((num) => num < -1000 || num > 1000)) {
print("between -1000 and 1000 please!");
} else {
print(nums.reduce((a, b) => a + b));
}
}
}
}
- Output:
1 2 3 3 4 7
dc
? + psz
The question mark ? reads and executes a line of input. The user must enter a dc program that pushes two numbers to the stack, such as 2 3 or 5 _1. (The user must use underscore _ for negative numbers.)
DCL
$ read sys$command line
$ a = f$element( 0, " ", line )
$ b = f$element( 1, " ", line )
$ write sys$output a, "+", b, "=", a + b
Delphi
Console version.
program SUM;
{$APPTYPE CONSOLE}
uses
SysUtils;
procedure
var
s1, s2:string;
begin
ReadLn(s1);
Readln(s2);
Writeln(StrToIntDef(s1, 0) + StrToIntDef(s2,0));
end.
Diego
set_namespace(rosettacode)_me();
begin_instuct(A + B);
ask_human()_msg(Please enter two integers between -1000 and 1000, separated by a space:)_split( )_var(A, B);
with_var(A, B)_trim()_parse({integer})_test([A]<=-1000)_test([B]>=1000)
: with_human[]_msg(Invalid input: [A], [B]);
exec_instruct[];
;
add_var(sum)_calc([A]+[B]);
with_human[]_msg([A] + [B] = [sum]);
end_instruct[];
exec_instruct(A + B)_me();
reset_namespace[];
DMS
number a = GetNumber( "Please input 'a'", a, a ) // prompts for 'a'
number b = GetNumber( "Please input 'b'", b, b ) // prompts for 'b'
Result( a + b + "\n" )
Dragon
select "graphic"
select "types"
a = int(prompt("Enter A number"))
b = int(prompt("Enter B number"))
showln a + b
DWScript
Ghetto GUI version
var a := StrToInt(InputBox('A+B', 'Enter 1st number', '0'));
var b := StrToInt(InputBox('A+B', 'Enter 2nd number', '0'));
ShowMessage('Sum is '+IntToStr(a+b));
Déjà Vu
Console
0
for k in split !prompt "" " ":
+ to-num k
!print
EasyLang
a$ = input
repeat
i += 1
until i > len a$ or substr a$ i 1 = " "
.
a = number substr a$ 1 i
b = number substr a$ i 99
print a + b
EchoLisp
(+ (read-number 1 "value for A") (read-number 2 "value for B"))
Ed
Inputs are newline-separated integers up to 10000 (arbitrary limit, can be extended by adding more parsing/output lines).
H
g/[^0-9]{1,}/s///g
,p
# decimal -> unary
g/^0+([0-9])/s//\1/
g/^9([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiiiiiiii/
g/^8([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiiiiiii/
g/^7([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiiiiii/
g/^6([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiiiii/
g/^5([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiiii/
g/^4([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiii/
g/^3([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iii/
g/^2([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2ii/
g/^1([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2i/
g/^0([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2/
g/^9([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiiiiiiii/
g/^8([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiiiiiii/
g/^7([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiiiiii/
g/^6([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiiiii/
g/^5([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiiii/
g/^4([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiii/
g/^3([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iii/
g/^2([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2ii/
g/^1([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2i/
g/^0([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2/
g/^9([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiiiiiiii/
g/^8([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiiiiiii/
g/^7([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiiiiii/
g/^6([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiiiii/
g/^5([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiiii/
g/^4([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiii/
g/^3([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iii/
g/^2([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2ii/
g/^1([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2i/
g/^0([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2/
g/^9([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiiiiiiii/
g/^8([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiiiiiii/
g/^7([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiiiiii/
g/^6([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiiiii/
g/^5([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiiii/
g/^4([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiii/
g/^3([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iii/
g/^2([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2ii/
g/^1([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2i/
g/^0([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2/
g/^9([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiiiiiiii/
g/^8([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiiiiiii/
g/^7([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiiiiii/
g/^6([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiiiii/
g/^5([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiiii/
g/^4([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iiii/
g/^3([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2iii/
g/^2([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2ii/
g/^1([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2i/
g/^0([0-9]*)(i*)/s//\1\2\2\2\2\2\2\2\2\2\2/
# actual logic
,j
# unary -> decimal (for 0-10000 range)
g/i{9000}(i{0,999})/s//9\1/
g/i{8000}(i{0,999})/s//8\1/
g/i{7000}(i{0,999})/s//7\1/
g/i{6000}(i{0,999})/s//6\1/
g/i{5000}(i{0,999})/s//5\1/
g/i{4000}(i{0,999})/s//4\1/
g/i{3000}(i{0,999})/s//3\1/
g/i{2000}(i{0,999})/s//2\1/
g/i{1000}(i{0,999})/s//1\1/
v/^[0-9]i*$/s/.*/0&/
g/i{900}(i{0,99})/s//9\1/
g/i{800}(i{0,99})/s//8\1/
g/i{700}(i{0,99})/s//7\1/
g/i{600}(i{0,99})/s//6\1/
g/i{500}(i{0,99})/s//5\1/
g/i{400}(i{0,99})/s//4\1/
g/i{300}(i{0,99})/s//3\1/
g/i{200}(i{0,99})/s//2\1/
g/i{100}(i{0,99})/s//1\1/
v/^[0-9]{2}i*$/s/^([0-9])(i*)$/\10\2/
g/i{90}(i{0,9})/s//9\1/
g/i{80}(i{0,9})/s//8\1/
g/i{70}(i{0,9})/s//7\1/
g/i{60}(i{0,9})/s//6\1/
g/i{50}(i{0,9})/s//5\1/
g/i{40}(i{0,9})/s//4\1/
g/i{30}(i{0,9})/s//3\1/
g/i{20}(i{0,9})/s//2\1/
g/i{10}(i{0,9})/s//1\1/
v/^[0-9]{3}i*$/s/^([0-9]{2})(i*)$/\10\2/
g/i{9}/s//9/
g/i{8}/s//8/
g/i{7}/s//7/
g/i{6}/s//6/
g/i{5}/s//5/
g/i{4}/s//4/
g/i{3}/s//3/
g/i{2}/s//2/
g/i{1}/s//1/
v/^[0-9]{4}i*$/s/^([0-9]{3})(i*)$/\10\2/
g/^0+([0-9])/s//\1/
,p
Q
EDSAC order code
The EDSAC does not support input of data while a program is running, so A and B are pre-set to 37 and 28. Other values can of course be substituted: note the slightly idiosyncratic format in which integer data is written (the least significant bit set using an alphabetic character). The result of the computation is displayed in binary in the first address of storage tank 3.
[ A plus B
========
A program for the EDSAC
Adds two integers & displays
the sum at the top of storage
tank 3
Works with Initial Orders 2 ]
[ Set load point & base address ]
T56K [ Load at address 56 ]
GK [ Base addr (theta) here ]
[ Orders ]
T96F [ Clear accumulator ]
A5@ [ Acc += C(theta + 5) ]
A6@ [ Acc += C(theta + 6) ]
T96F [ C(96) = Acc; Acc = 0 ]
ZF [ Halt ]
[ Pseudo-orders (data) ]
P18D [ 5@: 18*2 + 1 = 37 ]
P14F [ 6@: 14*2 + 0 = 28 ]
[ When loading is finished: ]
EZPF [ Branch to load point ]
- Output:
00000000001000001
Alternative
This is a more elaborate solution, to demonstrate how the same program can be applied to different sets of data (cf. Wilkes, Wheeler and Gill, 1951 edition, page 47).
In the program below, the two integers to be added are placed at the end. On the original EDSAC, they would be on the same paper tape as the program. With Martin Campbell-Kelly's EdsacPC simulator, reading the data from a separate tape can be simulated as follows:
1. Remove the two integers from the end of this program and store them, or another pair of integers, in a separate text file. Each integer must be terminated by a non-digit or a blank tape row (represented by a full stop in the simulator).
2. Run the altered program. The simulator will stop with a message "End of input tape encountered".
3. Dismiss the message, make the file with the two integers the active file, and click Reset. The simulator will continue, read the integers, and print them together with their sum.
[A + B for Rosetta Code.
Read two integers and find their sum.
EDSAC program, Initial Orders 2.]
[Print signed number, up to 10 digits, right-justified.
Modification of library subroutine P7.
55 locations, load at even address.]
T 56 K
GKA3FT42@A47@T31@ADE10@T31@A48@T31@SDTDH44#@NDYFLDT4DS43@TF
H17@S17@A43@G23@UFS43@T1FV4DAFG50@SFLDUFXFOFFFSFL4FT4DA49@T31@
A1FA43@G20@XFP1024FP610D@524D!FO46@O26@XFO46@SFL8FT4DE39@
[Subroutine to read signed number from input, up to 10 digits.
Partly based on library subroutine R2. Result in 4D.
Working registers: 0F = dump to clear acc
1F < 0 if number starts with minus, = 0 if not.
6D = character code, as double-word value]
T 120 K
G K
A 3 F [make link for return]
T 36 @ [plant in code; clear acc]
H 7 @ [mult reg := 10/32]
T 4 D [initialize result to 0]
T 1 F [no minus sign yet]
T 6 D [ensure 7F and sandwich bit are 0]
[Loop until find valid first character of integer, namely
decimal digit (char codes 0..9), plus (13), or minus (22).]
[6] I 6 F [char code from input]
[7] T F [clear acc; also serves as constant 10/32]
S 6 F [load negative of char code]
A 39 @ [add 9]
E 24 @ [if decimal digit, out]
A 38 @ [add 3]
E 6 @ [if 10..12, try again]
A 37 @ [add 1]
E 20 @ [if plus, out with acc = 0]
A 39 @ [add 9]
G 6 @ [if 23..31, try again]
S 37 @ [subtract 1]
E 6 @ [if 14..21, try again]
T 1 F [minus, acc = -1, store in sign]
[Loop to read characters after first. Assumes acc = 0 here.]
[20] I 6 F [next char from input]
S 6 F [negative to acc]
A 39 @ [add 9]
G 30 @ [finished if not digit]
[24] T F [clear acc]
V 4 D [acc := 10/32 times partial sum]
L 8 F [shift 5 left]
A 6 D [add latest digit]
T 4 D [update partial sum]
E 20 @ [loop for next char]
[Here when no more digits]
[30] T F [clear acc]
A 1 F [load sign of result]
E 36 @ [exit (with acc = 0) if >= 0]
T F [< 0, clear acc]
S 4 D [subtract number]
T 4 D [store back negated; clear acc]
[36] E F [exit with acc = 0 (EDSAC convention)]
[Constants]
[37] P D [1]
[38] P 1 D [3]
[39] P 4 D [9]
[Main routine]
T 200 K
G K
[Variables]
[0] P F P F [integer A]
[2] P F P F [integer B]
[Constants]
[4] # F [figures]
[5] @ F [carriage return]
[6] & F [line feed]
[7] K 4096 F [null char]
[Enter with acc = 0]
[8] O 4 @ [set teleprinter to figures]
A 9 @
G 120 F [read integer A from input]
A 4 D [load]
U #@ [save]
T D [to 0D for printing]
A 14 @
G 56 F [print A]
O 5 @ [followed by new line]
O 6 @
A 18 @
G 120 F [read integer B from input]
A 4 D [load]
U 2#@ [save]
T D [to 0D for printing]
A 23 @
G 56 F [print B]
O 5 @ [followed by new line]
O 6 @
A #@ [load A]
A 2#@ [add B]
T D [A + B to 0D for printing]
A 30 @
G 56 F [print A + B]
O 5 @ [followed by new line]
O 6 @
O 7 @ [print null to flush teleprinter buffer]
Z F [stop]
E 8 Z
P F
-987.123.
- Output:
-987 123 -864
EGL
package programs;
// basic program
//
program AplusB type BasicProgram {}
function main()
try
arg1 string = SysLib.getCmdLineArg(1);
arg2 string = SysLib.getCmdLineArg(2);
int1 int = arg1;
int2 int = arg2;
sum int = int1 + int2;
SysLib.writeStdout("sum1: " + sum);
onException(exception AnyException)
SysLib.writeStdout("No valid input. Provide 2 integer numbers as arguments to the program.");
end
end
end
Eiffel
argument(0) contains the path of the executable - thus we start at argument(1)
class
APPLICATION
inherit
ARGUMENTS
create
make
feature {NONE} -- Initialization
make
-- Run application.
do
print(argument(1).to_integer + argument(2).to_integer)
end
end
Alternatively ...
make
-- Run application.
note
synopsis: "[
The specification implies command line input stream and also
implies a range for both `A' and `B' (e.g. (-1000 <= A,B <= +1000)).
To test in Eiffel Studio workbench, one can set Execution Parameters
of "2 2", where the expected output is 4. One may also create other
test Execution Parameters where the inputs are out-of-bounds and
confirm the failure.
]"
do
if attached {INTEGER} argument (1).to_integer as a and then
attached {INTEGER} argument (2).to_integer as b and then
(a >= -1000 and b >= -1000 and a <= 1000 and b <= 1000) then
print (a + b)
else
print ("Either argument 1 or 2 is out-of-bounds. Ensure: (-1000 <= A,B <= +1000)")
end
end
Ela
open monad io string list
a'b() = do
str <- readStr
putStrLn <| show <| sum <| map gread <| string.split " " <| str
a'b() ::: IO
- Output:
1 2 3 4 5 6 21
Elena
ELENA 6.0 :
import extensions;
public program()
{
var A := Integer.new();
var B := Integer.new();
console.loadLine(A,B).printLine(A + B)
}
Or more generic solution:
import system'routines;
import extensions;
public program()
{
console.printLine(console.readLine()
.split()
.selectBy(mssgconst toInt<intConvertOp>[1])
.summarize())
}
Elixir
IO.gets("Enter two numbers seperated by a space: ")
|> String.split
|> Enum.map(&String.to_integer(&1))
|> Enum.sum
|> IO.puts
Elm
--To write this function directly run cmd
--Type elm-repl to start
--Next enter this code
sum x y=x+y
--This creates a sum function
--When you enter sum A B
--You get output as A+B : number
--Task done!
--END
Emacs Lisp
(let* ((input (read-from-minibuffer ""))
(numbers (mapcar #'string-to-number (split-string input)))
(a (car numbers))
(b (cadr numbers)))
(message "%d" (+ a b)))
EMal
fun main = int by List args
text input = when(args.length == 1, args[0], ask(text, "Enter n integers separated by a space: "))
int sum, count
for each text word in input.split(" ")
word = word.trim()
if word.isEmpty() do continue end # ignore empty words
int nr = int!word # this can raise an exception
if abs(nr) > 1000
Event.error(0, "Integers must be in the interval [-1000, 1000]").raise()
end
sum += nr
++count
end
if count < 2 do Event.error(1, "At least two integers must be provided").raise() end
writeLine("The sum of " + count + " integers is: " + sum)
return 0
end
exit main(Runtime.args)
- Output:
emal.exe Org\RosettaCode\Aplusb.emal " 9 8 " The sum of 2 integers is: 17
Emojicode
🏁🍇
🆕🔡▶️👂🏼❗️ ➡️ input 💭 Get numbers as input string
🔫 input 🔤 🔤❗ ➡️ nums 💭 Split numbers by space
🍺🔢 🐽 nums 0❗ 10❗ ➡️ A 💭 Retrieve first number
🍺🔢 🐽 nums 1❗ 10❗ ➡️ B 💭 Retrieve second number
😀 🔤🧲A➕B🧲🔤 ❗ 💭 Output sum
🍉️
Erlang
-module(aplusb).
-export([start/0]).
start() ->
case io:fread("","~d~d") of
eof -> ok;
{ok, [A,B]} ->
io:format("~w~n",[A+B]),
start()
end.
ERRE
PROGRAM SUM2
BEGIN
LOOP
INPUT(LINE,Q$)
EXIT IF Q$=""
SP%=INSTR(Q$," ")
PRINT(VAL(LEFT$(Q$,SP%-1))+VAL(MID$(Q$,SP%+1)))
END LOOP
END PROGRAM
Euler
begin out in + in end $
Euler Math Toolbox
>s=lineinput("Two numbers seperated by a blank");
Two numbers seperated by a blank? >4 5
>vs=strtokens(s)
4
5
>vs[1]()+vs[2]()
9
Euphoria
include get.e
function snd(sequence s)
return s[2]
end function
integer a,b
a = snd(get(0))
b = snd(get(0))
printf(1," %d\n",a+b)
Excel
Take any 3 columns of any row or rows. Let's say A1,B1 and C1 are taken. In C1 type in :
=A1+B1
The value of C1 will change as the values of A1 and B1 are changed
1 2 3
F#
open System
let SumOf(str : string) =
str.Split() |> Array.sumBy(int)
[<EntryPoint>]
let main argv =
Console.WriteLine(SumOf(Console.ReadLine()))
0
Factor
USING: math.parser splitting ;
: a+b ( -- )
readln " " split1
[ string>number ] bi@ +
number>string print ;
( scratchpad ) a+b 2 2 4
FALSE
[0[^$$'9>'0@>|~]['0-\10*+]#%]n: {read an integer}
n;!n;!+.
Fantom
class APlusB
{
public static Void main ()
{
echo ("Enter two numbers: ")
Str input := Env.cur.in.readLine
Int sum := 0
input.split.each |n| { sum += n.toInt }
echo (sum)
}
}
FBSL
Using stdin and stdout
#APPTYPE CONSOLE
DIM %a, %b
SCANF("%d%d", @a, @b)
PRINT a, "+", b, "=", a + b
PAUSE
Fennel
(let [(a b) (io.read :*number :*number)]
(print (+ a b)))
Fhidwfe
function listint scanint (num:ptr) {// as of writing, fhidwfe has no builtin int scanning
reset negative
read = num
num1 = 0
num2 = 0
while ~ = deref_ubyte$ read ' ' {
char = deref_ubyte$ read
if = char '-' {
set negative
} {
num1 = + * 10 num1 as - char '0' int
}
read = + read 1u
}
if negative {
num1 = !num1
} ;
reset negative
read = + read 1u
while ~ = deref_ubyte$ read 0ub {
char2 = deref_ubyte$ read
if = char2 '-' {
set negative
} {
num2 = + * 10 num2 as - char2 '0' int
}
read = + read 1u
}
if negative {
num2 = !num2
} ;
return (num1 num2)
}
//the real program
text = malloc$ 12u//worst input is -1000 -1000, or 11 bytes + null terminator
getline$ text
inp = scanint$ text
free$ text
puti$ + access_word$ inp 0u access_word$ inp 1u
free$ inp
Fish
i:o:"-"=?v1$68*-v
v >~01-0 >
>i:o:" "=?v68*-$a*+
>~*i:o:"-"=?v1$68*-v
v >~01-0 >
>i:o:d=?v68*-$a*+
>~*+aonao;
Forth
pad dup 80 accept evaluate + .
Fortran
program a_plus_b
implicit none
integer :: a,b
read (*, *) a, b
write (*, '(i0)') a + b
end program a_plus_b
And in Fortran 77
READ (1,100) I,J
100 FORMAT(2I5)
WRITE (2,200) I+J
200 FORMAT(1X,I5)
END
Free Pascal
program SUMA;
uses
SysUtils;
var
s1, s2:integer;
begin
ReadLn(s1);
Readln(s2);
WriteLn(IntToStr(s1 + s2));
end.
Frink
This program handles arbitrarily-large integers, or even floating-point or rational numbers or complex numbers (as long as they're not internally separated with spaces, of course, which are the delimiters for this task.) It can even handle units of measure (with no embedded spaces) such as "3.3meter 2feet" and does the right thing when summing those units. It can handle any number of arbitrary whitespace characters separating the numbers. It also works whether the input is user-interactive, or input comes from stdin or a pipe. (It will bring up a user dialog for input when run in a graphical environment.)
sum[eval[split[%r/\s+/, input[""]]]]
FunL
println( sum(map(int, readLine().split(' +'))) )
Furor
cin sto mystring
#s dec mystring @mystring sprintnl
#g ."The length of the input is: " @mystring~ print ." characters.\n"
mylist @mystring 32 strtolist
."Quantity of the items: " mylist~ printnl
mylist~ mem sto nums
mylist 10 ![
."Item #" [:] #g print ." = " [|] sprintnl
@nums [:] [|] #s (#g) [^] ]
."Sum = "
0 #g mylist~ {| @nums {} [] + |}
printnl
@nums free @mystring free @mylist free
end
{ „mystring” }
{ „mylist” }
{ „nums” }
- Output:
echo "23 6 11 7" | furor aplusb.upu 23 6 11 7 The length of the input is: 9 characters. Quantity of the items: 4 Item #0 = 23 Item #1 = 6 Item #2 = 11 Item #3 = 7 Sum = 47 echo "20 11" | furor aplusb.upu 20 11 The length of the input is: 5 characters. Quantity of the items: 2 Item #0 = 20 Item #1 = 11 Sum = 31
FutureBasic
The input statement was removed from FB several years ago. However, it's trivial to write our own input field which compiles as a stand-alone Macintosh application.
_window = 1
begin enum 1
_label
_input
_result
end enum
void local fn BuildWindow
window _window, @"A + B", ( 0, 0, 260, 200 )
textlabel _label, @"Enter two signed integers separated by a comma, space/s or plus sign. Enter return to calculate.", ( 20, 130, 220, 48 ), _window
textfield _input,,,( 20, 90, 220, 24 ), _window
TextFieldSetMaximumNumberOfLines( _input, 1 )
ControlSetFormat( _input, @"0123456789 ,+-", YES, 0, NULL )
ControlSetAlignment( _input, NSTextAlignmentCenter )
textlabel _result,, ( 20, 50, 220, 24 ), _window
ControlSetAlignment( _result, NSTextAlignmentRight )
WindowMakeFirstResponder( _window, _input )
end fn
local fn DoCalc
NSInteger value1, value2
CFStringRef calcStr = fn ControlStringValue( _input )
calcStr = fn StringByReplacingOccurrencesOfString( calcStr, @",", @"\t" )
calcStr = fn StringByReplacingOccurrencesOfString( calcStr, @"+", @"\t" )
calcStr = fn StringByReplacingOccurrencesOfString( calcStr, @" ", @"\t" )
CFArrayRef calcArr = fn StringComponentsSeparatedByString( calcStr, @"\t" )
value1 = fn StringIntegerValue( fn ArrayFirstObject( calcArr ) )
value2 = fn StringIntegerValue( fn ArrayLastObject( calcArr ) )
ControlSetStringValue( _result, fn StringWithFormat( @"%ld + %ld = %ld", value1, value2, value1 + value2 ) )
end fn
void local fn DoDialog( ev as long, tag as long, wnd as long )
select ( ev )
case _textFieldDidEndEditing : fn DoCalc
case _windowWillClose : end
end select
end fn
on dialog fn DoDialog
fn BuildWindow
HandleEvents
- Output:
-250 1000 = 750 or -250,1000 = 750 or -250 + 1000 = 750
Gambas
Public Sub Main()
Dim sInput As String = InputBox("Input 2 numbers seperated by a space", "A + B")
Print Split(sInput, " ")[0] & " + " & Split(sInput, " ")[1] & " = " & Str(Val(Split(sInput, " ")[0]) + Val(Split(sInput, " ")[1]))
End
Output:
999 + 888 = 1887
Gastona
Taking A and B from command line arguments
#listix#
<main>
"@<p1> + @<p2> = "
=, p1 + p2
Using Graphical interface
#javaj#
<layout of main>
EVALAYOUT, 6, 6, 3,
, A , A
, lA , eA
, lB , eB
, bSum, eRes
#listix#
<-- bSum>
MSG, eRes data!,, @<suma>
<suma> =, eA + eB
GDScript
Requires Godot 4. Runs as a tool script using the input and output properties. Does not check for zero lines of input.
@tool
extends Node
@export var input: String:
set(value):
input = value # Save the input field
var fields := value.split(" ", false) # Split by spaces
if len(fields) == 2: # Basic input validation
output = str(int(fields[0]) + int(fields[1]))
else: # Invalid input
output = ""
@export var output: String
Gema
<D> <D>=@add{$1;$2}
Genie
[indent=4]
/*
A+B in Genie
valac aplusb-genie.gs
./aplusb-genie
*/
init
a:int64 = 0
b:int64 = 0
leftover:string = ""
print "Enter A and B, two numbers separated by space"
line:string = stdin.read_line()
res:bool = int64.try_parse(line, out a, out leftover)
res = int64.try_parse(leftover, out b)
warning:string = " outside range (-1000, 1000), but it's ok, no one will tell"
if a < -1000 or a > 1000
print "A" + warning
if b < -1000 or b > 1000
print "B" + warning
print "From %s\nA + B = %llu", line, a+b
- Output:
prompt$ valac aplusb-genie.gs prompt$ ./aplusb-genie Enter A and B, two numbers separated by space 20 22 From 20 22 A + B = 42 prompt$ echo '123 234' | ./aplusb-genie Enter A and B, two numbers separated by space From 123 234 A + B = 357 prompt$ echo '123 2345' | ./aplusb-genie Enter A and B, two numbers separated by space B outside range (-1000, 1000), but it's ok, no one will tell From 123 2345 A + B = 2468
GML
var add, a, b;
add = argument0; // get the string with the numbers to add
a = real(string_copy(add, 1, string_pos(" ", add)));
b = real(string_copy(add, string_pos(" ", add) + 1, string_length(add) - string_pos(" ", add)));
return(a + b);
Go
package main
import "fmt"
func main() {
var a, b int
fmt.Scan(&a, &b)
fmt.Println(a + b)
}
Golfscript
~+
Golo
#!/usr/bin/env golosh
----
This module asks for two numbers, adds them, and prints the result.
----
module Aplusb
import gololang.IO
function main = |args| {
let line = readln("Please enter two numbers (just leave a space in between them) ")
let numbers = line: split("[ ]+"): asList()
require(numbers: size() == 2, "we need two numbers")
try {
let a, b = numbers: map(|i| -> i: toInt())
require(a >= -1000 and a <= 1000 and b >= -1000 and b <= 1000, "both numbers need to be between -1000 and 1000")
println(a + b)
} catch (e) {
println("they both need to be numbers for this to work")
}
}
Gosu
uses java.io.InputStreamReader
uses java.util.Scanner
uses java.lang.System
var scanner = new Scanner( new InputStreamReader( System.in ) )
var a = scanner.nextInt()
var b = scanner.nextInt()
print( a + b )
Groovy
def abAdder = {
def reader = new Scanner(System.in)
def a = reader.nextInt();
def b = reader.nextInt();
assert (-1000..1000).containsAll([a,b]) : "both numbers must be between -1000 and 1000 (inclusive)"
a + b
}
abAdder()
GUISS
We cannot use variables, but we can find the sum of two numbers.Here we add 3 + 2:
Start,Programs,Accessories,Calculator,Button:3,Button:[plus],
Button:2,Button:[equals]
Harbour
PROCEDURE Main()
LOCAL GetList := {}
LOCAL bValid := { |n| iif(n>-1001, iif(n<1001, .T.,.F.),.F.) }
LOCAL a := 0 , b := 0
SetColor( "G+/N" )
CLS
@ 10, 01 SAY "Enter two integers (range -1000...+1000):" GET a VALID Eval(bValid,a)
@ Row(), Col() + 1 GET b VALID Eval(bValid,b)
READ
@ 12, 01 SAY "Sum of given numbers is " + hb_ntos(a+b)
RETURN
Screen output:
Enter two numbers (range -1000...+1000): -56 98
Sum of given numbers is 42
Haskell
main = print . sum . map read . words =<< getLine
hexiscript
fun split s delim
let ret dict 32
let l len s
let j 0
let ret[0] ""
for let i 0; i < l; i++
if s[i] = delim
if len ret[j] > 0
let ret[++j] ""
endif
continue
endif
let ret[j] (ret[j] + s[i])
endfor
return ret
endfun
let nums split (scan str) ' '
let a tonum nums[0]
let b tonum nums[1]
println a + b
HicEst
A and B are input via edit controls with spinners limiting inputs to +-1000.
DLG(Edit=A, DNum, MIn=-1000, MAx=1000, E=B, DN, MI=-1000, MA=1000)
WRITE(Messagebox, Name) A, B, "Sum = ", A+B
Hoon
|= [a=@ud b=@ud] (add a b)
Hope
This being my first hope program, and having no clue how to (have hope) read from stdin, I installed hope (but not hopeless) from https://github.com/dmbaturin/hope, read the Byte magazine article from 1980s which is a recast of the tutorial found in the github archive. Congratulations, the program worked on my first attempt.
$ cd lib $ ../src/hope >: dec add : num # num -> num; >: --- add(a,b) <= a + b; >: add(3,99) >: ^D >> 102 : num
Huginn
import Algorithms as algo;
import Text as text;
main() {
print(
"{}\n".format(
algo.reduce(
algo.map(
text.split( input().strip(), " " ),
integer
),
@( x, y ){ x + y; }
)
);
);
}
Hy
(print (sum (map int (.split (input)))))
Alternatively, with the "threading tail" macro:
(->> (input) (.split) (map int) (sum) (print))
i
main: print(integer(in(' '))+integer(in('\n'))); ignore
Icon and Unicon
Idris
main : IO()
main = do
line <- getLine
print $ sum $ map cast $ words line
Insitux
(+ (to-num (prompt "Enter first number: "))
(to-num (prompt "Enter second number: ")))
J
Typically, in J, you would find the sum of two numbers (let us say 2 and 3) by entering both of them on a line with a + sign between them:
2+3
5
Next we describe then implement a command line program to add some numbers.
1) In the following expression, 1!:1(3) reads a line from STDIN; -.LF drops the line ending character; ". converts the remaining text to a sequence of numbers which are then summed using +/.
+/". (1!:1(3))-.LF
2) Here's a little script, called "a+b.ijs":
#!/usr/bin/ijconsole
echo +/". (1!:1(3))-.LF
exit ''
3) Here is an execution of the script:
echo 2 3 | ./a+b.ijs
5
Note: under OSX, you should probably install a symbolic link at /usr/bin/ijconsole which links to something like /Applications/j602/bin/jconsole.
Java
The task description is somewhat vague, if the 'input stream' is in reference to the data provided at the command line, then Java will parse these values into a String
array, accessible via the args parameter of the main
method.
public static void main(String[] args) {
int A = Integer.parseInt(args[0]);
int B = Integer.parseInt(args[1]);
System.out.println(A + B);
}
If the 'input stream' is the standard-in, you can use the following.
The Scanner
class can be used to "scan" the standard-in stream from left to right, returning the next value requested.
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int A = scanner.nextInt();
int B = scanner.nextInt();
System.out.println(A + B);
}
If the 'input stream' is referring to any abstraction, then you can use the following.
In this example, the data is considered to be under a specific charset, so the integer values are parsed using UTF-8.
import static java.nio.charset.StandardCharsets.UTF_8;
import java.io.BufferedReader;
import java.io.ByteArrayInputStream;
import java.io.ByteArrayOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
int sum(InputStream input) throws IOException {
BufferedReader reader = new BufferedReader(new InputStreamReader(input));
String line = reader.readLine();
reader.close();
/* split parameter here is a regex */
String[] values = line.split(" +");
int A = Integer.parseInt(values[0]);
int B = Integer.parseInt(values[1]);
return A + B;
}
An alternate implemenation
import java.util.Scanner;
public class Sum2 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in); // Standard input
System.out.println(in.nextInt() + in.nextInt()); // Standard output
}
}
Object of class Scanner works slow enough, because of that contestants prefer to avoid its use. Often, longer solution works faster and easily scales to problems.
import java.io.*;
import java.util.*;
public class SumDif {
StreamTokenizer in;
PrintWriter out;
public static void main(String[] args) throws IOException {
new SumDif().run();
}
private int nextInt() throws IOException {
in.nextToken();
return (int)in.nval;
}
public void run() throws IOException {
in = new StreamTokenizer(new BufferedReader(new InputStreamReader(System.in))); // Standard input
out = new PrintWriter(new OutputStreamWriter(System.out)); // Standard output
solve();
out.flush();
}
private void solve() throws IOException {
out.println(nextInt() + nextInt());
}
}
The following code uses a StreamTokenizer instead of a Scanner.
import java.io.*;
import java.nio.charset.Charset;
public class AplusB {
public static void main(String[] args) throws IOException {
StreamTokenizer in = new StreamTokenizer(new InputStreamReader(System.in, Charset.defaultCharset()));
in.nextToken();
int a = (int) in.nval;
in.nextToken();
int b = (int) in.nval;
try (Writer out = new OutputStreamWriter(System.out, Charset.defaultCharset())) {
out.write(Integer.toString(a + b));
}
}
}
grammar aplusb ;
options {
language = Java;
}
aplusb : (WS* e1=Num WS+ e2=Num NEWLINE {System.out.println($e1.text + " + " + $e2.text + " = " + (Integer.parseInt($e1.text) + Integer.parseInt($e2.text)));})+
;
Num : '-'?('0'..'9')+
;
WS : (' ' | '\t')
;
NEWLINE : WS* '\r'? '\n'
;
Produces:
>java Test 1 2 23 89 13 567 -75 6 -75 -29 ^Z 1 + 2 = 3 23 + 89 = 112 13 + 567 = 580 -75 + 6 = -69 -75 + -29 = -104
JavaScript
ES5
Client side:
<html>
<body>
<div id='input'></div>
<div id='output'></div>
<script type='text/javascript'>
var a = window.prompt('enter A number', '');
var b = window.prompt('enter B number', '');
document.getElementById('input').innerHTML = a + ' ' + b;
var sum = Number(a) + Number(b);
document.getElementById('output').innerHTML = sum;
</script>
</body>
</html>
Server side (with node.js):
process.openStdin().on (
'data',
function (line) {
var xs = String(line).match(/^\s*(\d+)\s+(\d+)\s*/)
console.log (
xs ? Number(xs[1]) + Number(xs[2]) : 'usage: <number> <number>'
)
process.exit()
}
)
$ node io.js 2 3 5 $ node io.js x 3 usage: <integer> <integer>
ES6
Node.js in a terminal:
process.stdin.on("data", buffer => {
console.log(
(buffer + "").trim().split(" ").map(Number).reduce((a, v) => a + v, 0)
);
});
$ node io.js 2 3 5
JScript Windows Script Host Version 5.8
var a = WScript.StdIn.ReadLine();
var b = WScript.StdIn.ReadLine();
WSH.echo(a, " + " , b , " = " , Number(a)+Number(b));
Joy
Console
get get +.
File
"input.txt" include
"output.txt" "w" fopen
get get + fput pop quit.
jq
Since the given task is simply to add two numbers, the simplest approach in jq is illustrated by the following transcript:
$ jq -s add
3 2
5
This will work provided the numbers are neither too small nor too large. However, the above program will add **all** the numbers presented on the stream (assuming only numbers are presented). If the task were to add consecutive pairs of numbers, then the approach illustrated in the following transcript can be used, in conjunction with the jq "-s" option:
def addpairs:
if length < 2 then empty
else (.[0] + .[1]), (.[2:] | addpairs)
end;
addpairs
For example, here is a transcript that assumes the program is in a file named AB.jq:
$ jq -s -f AB.jq
1 2 3 4 5 6
3
7
11
Jsish
/* A+B in Jsish */
var line = console.input();
var nums = line.match(/^\s*([+-]?[0-9]+)\s+([+-]?[0-9]+)\s*/);
if (nums) {
var A = Number(nums[1]);
var B = Number(nums[2]);
if (A <= 1000 && A >= -1000 && B <= 1000 && B >= -1000) {
printf("%d\n", A + B);
} else {
puts("error: A and B both need to be in range -1000 thru 1000 inclusive");
}
} else {
puts("error: A+B requires two numbers separated by space");
}
- Output:
prompt$ jsish A+B.jsi a b error: A+B requires two numbers separated by space prompt$ jsish A+B.jsi 1234 123 error: A and B both need to be in range -1000 thru 1000 inclusive prompt$ jsish A+B.jsi -1000 +1000 0 prompt$ jsish A+B.jsi 123 -234 -111
Julia
Run from the command line:
input = parse.(Int, split(readline(stdin)))
println(stdout, sum(input))
- Output:
>julia AB.jl 1 1 2
In the next solution, an error is returned if the entry is not constituted from exactly two integers. Any number of spaces can follow an integer.
julia> println(parse(Int, readuntil(stdin, ' ')) + parse(Int, readuntil(stdin, '\n')))
1 2
3
K
split:{(a@&~&/' y=/: a:(0,&x=y)_ x) _dv\: y}
ab:{+/0$split[0:`;" "]}
ab[]
2 3
5
Keg
+.
Or, using flags (-hr
):
+
Kite
#!/usr/bin/kite
import "System.file";
in = System.file.stdin;
line = in|readline;
while(not (line is null)) [
arry = line|split(" ");
result = (arry[0])|int + (arry[1])|int;
result|print;
line = in|readline;
];
- Output:
$ kite a_plus_b.kt <<EOF 5 6 EOF 11 $
Klong
{(1:$(*x?0c )#x)+1:$(1+*|x?0c )_x}@.rl()
2 3
5
Kotlin
// version 1.0.5-2
fun main(args: Array<String>) {
val r = Regex("""-?\d+[ ]+-?\d+""")
while(true) {
print("Enter two integers separated by space(s) or q to quit: ")
val input: String = readLine()!!.trim()
if (input == "q" || input == "Q") break
if (!input.matches(r)) {
println("Invalid input, try again")
continue
}
val index = input.lastIndexOf(' ')
val a = input.substring(0, index).trimEnd().toInt()
val b = input.substring(index + 1).toInt()
if (Math.abs(a) > 1000 || Math.abs(b) > 1000) {
println("Both numbers must be in the interval [-1000, 1000] - try again")
}
else {
println("Their sum is ${a + b}\n")
}
}
}
- Output:
Enter two integers separated by space(s) or q to quit: 2 2 Their sum is 4 Enter two integers separated by space(s) or q to quit: 3 2 Their sum is 5 Enter two integers separated by space(s) or q to quit: q
KQL
datatable(Input:string)[
'2 2',
'3 2'
]
| parse Input with A:int ' ' B:int
| project Input, Output = A + B
L++
(main
(decl int a)
(decl int b)
(>> std::cin a b)
(prn (+ a b)))
Lambdatalk
Lambdatalk works in a wiki, lambdatank.
1) Open the wiki frame-editor and define a contenteditable box
{def box
{pre
{@ contenteditable
style="box-shadow:0 0 8px #000; padding:5px;"
ondblclick="this.innerHTML=LAMBDATALK.eval_forms(this.innerHTML)"
}}}
-> blockedit
2) create this box
{box}
and close the wiki frame-editor. The wiki-page displays a shadowed box,
(here simulated as a space between square brackets)
[ ]
3) Enter any valid lambdatalk expression, for instance
1+2+3 is equal to {+ 1 2 3}
then double-click. The expression is evaluated and the box displays
[ 1+2+3 is equal to 6 ]
Several boxes can be created in the wiki page
with any valid lambdatalk expressions.
Lang
fn.print(First number:\s)
$a = fn.int(fn.input())
fn.print(Second number:\s)
$b = fn.int(fn.input())
fn.println(Result: parser.op($a + $b))
Lang5
read read + .
read " " split expand drop + .
Lasso
[a + b]
LIL
# A+B, in LIL
# Requires lil shell readline routine
set in [readline]
set A [index $in 0]
set B [index $in 1]
if [expr $A < -1000 || $A > 1000] { print "A out of range: $A"; exit 1 }
if [expr $B < -1000 || $B > 1000] { print "B out of range: $B"; exit 1 }
print [expr $A + $B]
- Output:
prompt$ echo '40 2' | lil AB.lil 42
Lisaac
Section Header
+ name := A_PLUS_B
Section Public
- main <- ( (IO.read_integer; IO.last_integer) +
(IO.read_integer; IO.last_integer) ).println;
Little
void main() {
string a, b;
scan(gets(stdin), "%d %d", &a, &b);
puts(((int)a + (int)b));
}
Little Man Computer
Note: Both numbers are entered separately.
This is the "add" example from V1.3 of the implementation of Little Man Computer by Peter Higginson.
Assembly
INP
STA 99
INP
ADD 99
OUT
HLT
// Output the sum of two numbers
Machine code
00 INP
01 STA 99
02 INP
03 ADD 99
04 OUT
05 HLT
LiveCode
Using Livecode Server script
<?lc
if isNumber($0) and isNumber($1) then
put $0 + $1
else
put $0 && $1
end if
?>
A graphical version using an input dialog
on mouseUp
ask "Enter two numbers"
set itemdelimiter to space
put it into nums
if isNumber(item 1 of nums) and isNumber(item 2 of nums) then
answer item 1 of nums + item 2 of nums
else
answer item 1 of nums && item 2 of nums
end if
end mouseUp
Logo
show apply "sum readlist
Lua
a,b = io.read("*number", "*number")
print(a+b)
M2000 Interpreter
Def Range(X%)=Abs(X%)<=1000
Do {
Input A%, B%
} Until Range(A%) And Range(B%)
Print A%+B%
M4
define(`sumstr', `eval(patsubst(`$1',` ',`+'))')
sumstr(1 2)
3
Maple
convert( scanf( "%d %d" ), '`+`' );
23 34
57
Mathematica /Wolfram Language
Interactive in a notebook
Input[] + Input[]
MATLAB / Octave
function sumOfInputs = APlusB()
inputStream = input('Enter two numbers, separated by a space: ', 's');
numbers = str2num(inputStream); %#ok<ST2NM>
if any(numbers < -1000 | numbers > 1000)
warning('APlusB:OutOfRange', 'Some numbers are outside the range');
end
sumOfInputs = sum(numbers);
end
Maude
Built-in
red 3 + 4 .
With restrictions
fmod ADD is
protecting INT .
op undefined : -> Int .
op _add_ : Int Int -> Int [assoc comm] .
vars A B : Int .
eq A add B = if (A < -1000 or B < -1000) or (A > 1000 or B > 1000) then undefined else A + B fi .
endfm
Maxima
in_stream: openr("/dev/stdin");
unless (line: readline(in_stream), line=false) do (
q: map('parse_string, split(line, " ")),
print(q[1]+q[2])
);
close(in_stream);
Mercury
:- module a_plus_b.
:- interface.
:- import_module io.
:- pred main(io::di, io::uo) is det.
:- implementation.
:- import_module int, list, string.
main(!IO) :-
io.read_line_as_string(Result, !IO),
( if
Result = ok(Line),
[AStr, BStr] = string.words(Line),
string.to_int(AStr, A), string.to_int(BStr, B)
then
io.format("%d\n", [i(A + B)], !IO)
else
true
).
min
gets " " split 'bool filter 'int map sum puts!
MiniScript
The input
intrinsic in MiniScript isn't available in all implementations, so we've just hard-coded the input here:
s = " 2 3 "
fields = s.split
for i in range(fields.len-1, 0)
if fields[i] == "" then fields.remove i
end for
if fields.len < 2 then
print "Not enough input"
else
print val(fields[0]) + val(fields[1])
end if
- Output:
5
mIRC Scripting Language
alias a+b {
echo -ag $calc($1 + $2)
}
МК-61/52
С/П + С/П
ML/I
The two numbers are read from 'standard input' or its equivalent.
MCSKIP "WITH" NL
"" A+B
"" assumes macros on input stream 1, terminal on stream 2
MCSKIP MT,<>
MCINS %.
MCDEF SL SPACES NL AS <MCSET T1=%A1.
MCSET T2=%A2.
%T1+T2.
MCSET S10=0
>
MCSKIP SL WITH *
MCSET S1=1
*MCSET S10=2
Modula-2
MODULE ab;
IMPORT InOut;
VAR A, B : INTEGER;
BEGIN
InOut.ReadInt (A);
InOut.ReadInt (B);
InOut.WriteInt (A + B, 8);
InOut.WriteLn
END ab.
Modula-3
MODULE Ab EXPORTS Main;
IMPORT IO;
VAR
A,B:INTEGER;
BEGIN
TRY
A := IO.GetInt();
B := IO.GetInt();
EXCEPT
| IO.Error => IO.Put("Invalid number!\n");
END;
IO.PutInt(A+B);
IO.Put("\n");
END Ab.
MoonScript
a,b = io.read '*number','*number'
print a + b
Mosaic
proc main =
int a, b
print "?"
readln a, b
println a + b
end
MUMPS
ANB
NEW A,B,T,S
READ !,"Input two integers between -1000 and 1000, separated by a space: ",S
SET A=$PIECE(S," ",1),B=$PIECE(S," ",2)
SET T=(A>=-1000)&(A<=1000)&(B>=-1000)&(B<=1000)&(A\1=A)&(B\1=B)
IF T WRITE !,(A+B)
IF 'T WRITE !,"Bad input"
QUIT
Nanoquery
// get a line of input
line = input()
// split the line
strings = split(line, " ")
// add the two numbers and print the result
println int(strings[0]) + int(strings[1])
Neko
/**
A+B, Rosetta Code, in Neko
Tectonics:
nekoc a+b.neko
echo '4 5' | neko a+b.n
*/
/* load some primitives */
var regexp_new = $loader.loadprim("regexp@regexp_new", 1)
var regexp_match = $loader.loadprim("regexp@regexp_match", 4)
var regexp_matched = $loader.loadprim("regexp@regexp_matched", 2)
var stdin = $loader.loadprim("std@file_stdin", 0)()
var file_read_char = $loader.loadprim("std@file_read_char", 1)
/* Read a line from file f into string s returning length without any newline */
var NEWLINE = 10
var readline = function(f, s) {
var len = 0
var ch
while true {
try ch = file_read_char(f) catch a break;
if ch == NEWLINE break;
if $sset(s, len, ch) == null break; else len += 1
}
return len
}
/* Trim a string of trailing NUL and spaces, returning substring */
var SPACE = 32
var trim = function(s) {
var len = $ssize(s)
var ch
while len > 0 {
ch = $sget(s, len - 1)
if ch != 0 && ch != SPACE break; else len -= 1
}
return $ssub(s, 0, len)
}
/* The A+B task */
var RECL = 132
try {
/* whitespace(s), digit(s), whitespace(s), digit(s) */
var twonums = regexp_new("^\\s*(\\d+)\\s+(\\d+)\\b")
var s = $smake(RECL)
var len = readline(stdin, s)
s = trim(s)
var valid = regexp_match(twonums, s, 0, $ssize(s))
if valid {
var first = regexp_matched(twonums, 1)
var second = regexp_matched(twonums, 2)
first = $int(first)
second = $int(second)
if first < -1000 || first > 1000 $throw("First value out of range -1000,1000")
if second < -1000 || second > 1000 $throw("Second value out of range -1000,1000")
$print($int(first) + $int(second), "\n")
} else $print("Need two numbers, separated by whitespace\n")
} catch with $print("Exception: ", with, "\n")
- Output:
prompt$ nekoc a+b.neko prompt$ echo '2 2' | neko a+b 4 prompt$ neko a+b 2 3 5
Nemerle
using System;
using System.Console;
using System.Linq;
module AplusB
{
Main() : void
{
WriteLine(ReadLine().Split().Select(int.Parse).Sum());
}
}
NetRexx
/* NetRexx */
options replace format comments java symbols binary
parse ask a b .
say a '+' b '=' a + b
newLISP
(println (apply + (map int (parse (read-line)))))
Nim
A+B:
# Takes 2 inputs of Floats and adds them (which is not correct for the exercise, will revisit, Thank you
from strutils import parseFloat, formatFloat, ffDecimal
proc aplusb(a,b: float): float =
return a + b
proc getnumber(): float =
try:
parseFloat(readLine(stdin))
except ValueError:
echo("Please enter a number: ")
getnumber()
echo("First number please: ")
let first: float = getnumber()
echo("Second number please: ")
let second: float = getnumber()
echo("Result: " & formatFloat(aplusb(first, second), ffDecimal, 2))
The puzzle requires 1 input, 2 INTS separated by a space, than a+b Needs to be revisited
Nit
Generic non-robust version (source: the Nit’s official repository):
module ab
var words = gets.split(" ")
if words.length != 2 then
print "Expected two numbers"
return
end
print words[0].to_i + words[1].to_i
NS-HUBASIC
10 INPUT "ENTER NUMBER A: ",A
20 INPUT "ENTER NUMBER B: ",B
30 PRINT A+B
Nu
input | parse "{a} {b}" | first | values | into int | math sum
Nutt
module main
imports native.io{input.hear,output.say}
vals a=hear(Int),b=hear(Int)
say(a+b)
end
Nyquist
SAL Syntax
;nyquist plug-in
;version 1
;type tool
;name "A+B"
;debugflags trace
define variable a = 1
define variable b = 9
print a + b
return ""
Audacity plug-in (SAL syntax)
;nyquist plug-in
;version 1
;type tool
;name "A+B"
;debugflags trace
define variable a = 1
define variable b = 9
print a + b
return ""
Oberon-2
MODULE ab;
IMPORT In, Out;
VAR A, B : INTEGER;
BEGIN
In.Int (A);
In.Int (B);
Out.Int (A + B, 8);
Out.Ln
END ab.
Producing
12 34 46
Objeck
bundle Default {
class Vander {
function : Main(args : String[]) ~ Nil {
values := IO.Console->ReadString()->Split(" ");
if(values->Size() = 2) {
(values[0]->Trim()->ToInt() + values[1]->Trim()->ToInt())->PrintLine();
};
}
}
}
OCaml
Scanf.scanf "%d %d" (fun a b -> Printf.printf "%d\n" (a + b))
Oforth
Works with any number of integers separated by a space.
import: mapping
System.Console accept words map( #>integer) reduce( #+ ) printcr .
Ol
Note: input data must be separated by newline ([Enter] key press).
; simplest
(+ (read) (read))
; safe
(let ((a (read))
(b (read)))
(if (not (number? a))
(runtime-error "a is not a number! got:" a))
(if (not (number? b))
(runtime-error "b is not a number! got:" b))
(print a " + " b " = " (+ a b)))
Onyx
$Prompt {
`\nEnter two numbers between -1000 and +1000,\nseparated by a space: ' print flush
} def
$GetNumbers {
mark stdin readline pop # Reads input as a string. Pop gets rid of false.
cvx eval # Convert string to integers.
} def
$CheckRange { # (n1 n2 -- bool)
dup -1000 ge exch 1000 le and
} def
$CheckInput {
counttomark 2 ne
{`You have to enter exactly two numbers.\n' print flush quit} if
2 ndup CheckRange exch CheckRange and not
{`The numbers have to be between -1000 and +1000.\n' print flush quit} if
} def
$Answer {
add cvs `The sum is ' exch cat `.\n' cat print flush
} def
Prompt GetNumbers CheckInput Answer
ooRexx
version 1
Numeric digits 1000 /*just in case the user gets ka-razy. */
Say 'enter some numbers to be summed:'
parse pull y
yplus=add_plus(y)
sum=0
Do While y<>''
Parse Var y n y
If datatype(n)<>'NUM' Then Do
Say 'you entered something that is not recognized to be a number:' n
Exit
End
sum+=n
End
Say yplus '=' sum/1
Exit
add_plus:
Parse arg list
list=space(list)
return translate(list,'+',' ')
- Output:
enter some numbers to be summed: 1e10+7.777+33 = 10000000040.777
version 2
extend for negative numbers
Numeric digits 1000
Say 'enter some numbers to be summed:'
parse pull y
sum=0
yplus=''
Do i=1 By 1 While y<>''
Parse Var y n y
If datatype(n)<>'NUM' Then Do
Say 'you entered something that is not recognized to be a number:' n
Exit
End
Select
When i=1 Then
yplus=n
When n>0 Then yplus||='+'abs(n)
Otherwise yplus||=n
End
sum+=n
End
Say yplus '=' sum/1
Exit
OpenEdge/Progress
DEFINE VARIABLE a AS INTEGER NO-UNDO FORMAT "->>>9".
DEFINE VARIABLE b AS INTEGER NO-UNDO FORMAT "->>>9".
IF SESSION:BATCH THEN DO:
INPUT FROM "input.txt".
IMPORT a b.
INPUT CLOSE.
END.
ELSE
UPDATE a b.
MESSAGE a + b VIEW-AS ALERT-BOX
Openscad
There is no means of run-time input in Openscad
a = 5 + 4;
echo (a);
Order
Since Order is implemented in the C pre-processor, which cannot express arithmetic operations, this program has been built around Order's standard library simulated natural number arithmetic implementation, extended to handle a sign bit.
To run this Order program, you must define the macros A and B to values of the form 8int(SIGN, 8nat(VALUE)), where SIGN is 1/0 to represent signed/unsigned numbers, and VALUES is any comma-separated list of decimal digits. For example, to evaluate the sum of A=-150, B=275, define A to be 8int(1, 8nat(1,5,0)) and B to be 8int(0, 8nat(2,7,5)).
#define ORDER_PP_DEF_1int_is_positive \
ORDER_PP_FN(8fn(8X, 8is_0(8tuple_at_0(8X))))
#define ORDER_PP_DEF_1int_get_unsigned \
ORDER_PP_FN(8fn(8X, 8tuple_at_1(8X)))
#define ORDER_PP_DEF_1int_add_impl \
ORDER_PP_FN(8fn(8A, 8B, 8S, 8int(8S, 8add(8A, 8B))))
#define ORDER_PP_DEF_1int_sub_impl \
ORDER_PP_FN(8fn(8A, 8B, \
8if(8greater(8A, 8B), \
8int(0, 8sub(8A, 8B)), \
8int(1, 8sub(8B, 8A)))))
#define ORDER_PP_DEF_8int_add \
ORDER_PP_FN(8fn(8A, 8B, \
8cond((8and(1int_is_positive(8A), 1int_is_positive(8B)), \
1int_add_impl(1int_get_unsigned(8A), 1int_get_unsigned(8B), 0)) \
(8and(1int_is_positive(8A), 8not(1int_is_positive(8B))), \
1int_sub_impl(1int_get_unsigned(8A), 1int_get_unsigned(8B))) \
(8and(8not(1int_is_positive(8A)), 1int_is_positive(8B)), \
1int_sub_impl(1int_get_unsigned(8B), 1int_get_unsigned(8A))) \
(8and(8not(1int_is_positive(8A)), 8not(1int_is_positive(8B))), \
1int_add_impl(1int_get_unsigned(8A), 1int_get_unsigned(8B), 1)))))
#define ORDER_PP_DEF_8int_to_lit \
ORDER_PP_FN(8fn(8X, \
8if(1int_is_positive(8X), \
8to_lit(1int_get_unsigned(8X)), \
8adjacent(8(-), 8to_lit(1int_get_unsigned(8X))))))
#define ORDER_PP_DEF_8int \
ORDER_PP_FN(8fn(8S, 8N, 8pair(8S, 8N)))
ORDER_PP(8int_to_lit(8int_add(A, B)))
Oxygene
// Sum 2 integers read fron standard input
//
// Nigel Galloway - April 16th., 2012
//
namespace aplusb;
interface
uses System.Text.RegularExpressions.*;
type
aplusb = class
public
class method Main;
end;
implementation
class method aplusb.Main;
var
gc: GroupCollection;
m : Match;
begin
m := new Regex('^\s*(?<a>-?[1-9]\d{0,2}|0|-?1000)\s+(?<b>-?[1-9]\d{0,2}|0|-?1000)\s*$').Match(Console.ReadLine());
if m.Success then
begin
gc := m.Groups;
Console.WriteLine("{0} + {1} = {2}", gc['a'].Value, gc['b'].Value, Integer.Parse(gc['a'].Value) + Integer.Parse(gc['b'].Value));
end
else Console.WriteLine("Invalid Input");
end;
end.
Produces:
>aplusb 23 -99 23 + -99 = -76
Oz
declare
class TextFile from Open.file Open.text end
StdIn = {New TextFile init(name:stdin)}
fun {ReadInt}
{String.toInt {StdIn getS($)}}
end
in
{Show {ReadInt}+{ReadInt}}
PARI/GP
User input:
input()+input()
File input:
read("file1")+read("file2")
PascalABC.NET
##
var (a,b) := ReadInteger2;
Writeln(a + b);
Pascal
var
a, b: integer;
begin
readln(a, b);
writeln(a + b);
end.
Same with input from file input.txt and output from file output.txt.
var
a, b: integer;
begin
reset(input, 'input.txt');
rewrite(output, 'output.txt');
readln(a, b);
writeln(a + b);
close(input);
close(output);
end.
Version 2. Following the rules
{ Task: A + B
Sum of A + B while A, B >= -1000 and A,B <= 1000
Author: Sinuhe Masan (2019) }
program APlusB;
var
A, B : integer;
begin
repeat
write('Enter two numbers betwen -1000 and 1000 separated by space: ');
readln(A, B);
until ((abs(A) < 1000) and (abs(B) < 1000));
writeln('The sum is: ', A + B);
end.
Perl
my ($a,$b) = split(' ', scalar(<STDIN>));
print "$a $b " . ($a + $b) . "\n";
using the List::Util module
say sum split /\s+/, scalar <STDIN>;
Phix
-- demo\rosetta\AplusB.exw string s = prompt_string("Enter two numbers separated by a space : ") sequence r = scanf(s,"%d %d") if length(r)=1 then integer {a,b} = r[1], c = a+b printf(1,"%d + %d = %d\n",{a,b,c}) else printf(1,"invalid input\n") end if
- Output:
Enter two numbers separated by a space : 2 3 2 + 3 = 5
GUI version
(The above console version is now just a comment in the distributed file.)
-- demo\rosetta\AplusB.exw with javascript_semantics include pGUI.e Ihandle lab, tab, res, dlg function valuechanged_cb(Ihandle tab) string s = IupGetAttribute(tab,"VALUE") sequence r = scanf(s,"%d %d") if length(r)=1 then integer {a,b} = r[1] s = sprintf("%d + %d = %d", {a, b, a+b}) IupSetStrAttribute(res,"TITLE",s) IupRefresh(res) end if return IUP_DEFAULT end function procedure main() IupOpen() lab = IupLabel("Enter two numbers separated by a space") tab = IupText("VALUECHANGED_CB", Icallback("valuechanged_cb"),"EXPAND=HORIZONTAL") res = IupLabel("") dlg = IupDialog(IupVbox({IupHbox({lab,tab},"GAP=10,NORMALIZESIZE=VERTICAL"), IupHbox({res})},"MARGIN=5x5"),`TITLE="A plus B"`) IupShow(dlg) if platform()!=JS then IupMainLoop() IupClose() end if end procedure main()
Phixmonti
/# Rosetta Code problem: http://rosettacode.org/wiki/A+B
by Galileo, 05/2022 #/
include ..\Utilitys.pmt
def valid
dup -1000 >= swap 1000 <= and
enddef
true while
clear cls
"Enter two numbers (betwen -1000 ... +1000) separated by space: " input split pop pop drop tonum swap tonum
over valid over valid and not
endwhile
over over + >ps
nl "The sum of " print print " and " print print " is: " print ps> print
/#
swap over over + >ps >ps >ps
nl ( "The sum of " ps> " and " ps> " is: " ps> ) lprint
#/
- Output:
Enter two numbers (betwen -1000 ... +1000) separated by space: 2 3 The sum of 2 and 3 is: 5 === Press any key to exit ===
PHP
fscanf(STDIN, "%d %d\n", $a, $b); //Reads 2 numbers from STDIN
echo ($a + $b) . "\n";
$in = fopen("input.dat", "r");
fscanf($in, "%d %d\n", $a, $b); //Reads 2 numbers from file $in
fclose($in);
$out = fopen("output.dat", "w");
fwrite($out, ($a + $b) . "\n");
fclose($out);
Picat
go =>
println("Write two integers (and CR)"),
println(read_int()+read_int()).
- Output:
Picat> go Write two integers (and CR) 2 5 7
Or directly in the REPL:
Picat> read_int()+read_int()=X 2 5 X = 7
PicoLisp
(+ (read) (read))
3 4
-> 7
Piet
The code is fairly straightforward. The individual commands are as follows:
in(num)
in(num)
add
out(num)
Pike
string line = Stdio.stdin->gets();
sscanf(line, "%d %d", int a, int b);
write(a+b +"\n");
PL/I
get (a, b);
put (a+b);
Plain English
To run:
Start up.
Read a number from the console.
Read another number from the console.
Output the sum of the number and the other number.
Wait for the escape key.
Shut down.
To output the sum of a number and another number:
If the number is not valid, write "Invalid input" to the console; exit.
If the other number is not valid, write "Invalid input" to the console; exit.
Write the number plus the other number then " is the sum." to the console.
To decide if a number is valid:
If the number is not greater than or equal to -1000, say no.
If the number is not less than or equal to 1000, say no.
Say yes.
Pony
actor Main
let _env:Env
new create(env:Env)=>
_env=env
env.input(object iso is InputNotify
let _e:Main=this
fun ref apply(data:Array[U8] iso)=>
_e(consume data)
fun ref dispose()=>
None
end,
512)
be apply(s:Array[U8] iso)=>
let c=String.from_iso_array(consume s)
let parts:Array[String]=c.split(" ",0)
var sum:I32=0
try
for v in parts.values() do
sum=sum+match v.read_int[I32](0)?
|(let x:I32,_)=>x
end
end
end
_env.out.print(sum.string())
PostScript
(%stdin) (r) file % get stdin
dup
token pop % read A
exch
token pop % read B
add
=
Potion
# The numbers are entered, piped, or redirected in via STDIN and the format is proper (i.e., "%d %d").
input = read
i = 0
while (i < input length):
if (input(i) == " "):
break
.
i++
.
(input slice(0, i) number + input slice(i, nil) number) print
# The numbers are manually inputted, but the format is improper (i.e., "%d\n%d\n").
(read number + read number) print
PowerShell
$a,$b = -split "$input"
[int]$a + [int]$b
This solution does not work interactively, while the following only works interactively:
$a,$b = -split (Read-Host)
[int]$a + [int]$b
I think this works better and doesn't require string input (following the task closer):
filter add {
return [int]$args[0] + [int]$args[1]
}
Can be called in one line with
add 2 3
Processing
Rudimentary User Interface
Click on either side to add 1 to its value.
int a = 0;
int b = 0;
void setup() {
size(200, 200);
}
void draw() {
fill(255);
rect(0, 0, width, height);
fill(0);
line(width/2, 0, width/2, height * 3 / 4);
line(0, height * 3 / 4, width, height * 3 / 4);
text(a, width / 4, height / 4);
text(b, width * 3 / 4, height / 4);
text("Sum: " + (a + b), width / 4, height * 7 / 8);
}
void mousePressed() {
if (mouseX < width/2) {
a++;
} else {
b++;
}
}
ProDOS
With the math module:
editvar /newvar /value=a /title=Enter an integer:
editvar /newvar /value=b /title=Enter another integer:
editvar /newvar /value=c
do add -a-,-b-=-c-
printline -c-
Without the math module:
editvar /newvar /value=a /title=Enter an integer:
editvar /newvar /value=b /title=Enter another integer:
editvar /newvar /value=c=-a-+-b-
printline -c-
Prolog
plus :-
read_line_to_codes(user_input,X),
atom_codes(A, X),
atomic_list_concat(L, ' ', A),
maplist(atom_number, L, LN),
sumlist(LN, N),
write(N).
output :
?- plus.
|: 4 5
9
true.
Pure
using system;
printf "%d\n" (x+y) when x,y = scanf "%d %d" end;
PureBasic
Console
x$=Input()
a=Val(StringField(x$,1," "))
b=Val(StringField(x$,2," "))
PrintN(str(a+b))
File
If ReadFile(0,"in.txt")
x$=ReadString(0)
a=Val(StringField(x$,1," "))
b=Val(StringField(x$,2," "))
If OpenFile(1,"out.txt")
WriteString(1,str(a+b))
CloseFile(1)
EndIf
CloseFile(0)
EndIf
Python
Console
In Python 2, input
returns ints, while raw_input
returns strings.
In Python 3, input
returns strings, and raw_input
does not exist.
The first two lines allow the program to be run in either Python 2 or 3. In Python 2, raw_input
exists, and the lines are effectively skipped. In Python 3, calling raw_input
triggers an error, so the except
loop activates and assigns "raw_input" the value of Python 3's "input" function. Regardless of version, these two lines make sure that raw_input
will return a string.
try: raw_input
except: raw_input = input
print(sum(map(int, raw_input().split())))
File
For Python 2.X and 3.X taking input from stdin stream which can be redirected to be file input under Unix
import sys
for line in sys.stdin:
print(sum(map(int, line.split())))
Console, Python 3 only
a = int(input("First number: "))
b = int(input("Second number: "))
print("Result:", a+b)
QB64
DIM a AS INTEGER, b AS INTEGER
DIM c AS LONG
INPUT "Enter A: ", a
INPUT "Enter B: ", b
c = a + b
PRINT ""
PRINT "A + B = " + LTRIM$(STR$(c))
Fully implemented version:
CBTJD: 2020/03/13
- Task description requires:
- Both integers entered on one line.
- Integers between -1000 and +1000.
START:
PRINT "Enter two integers between -1000 and +1000 separated by at least one space: "
INPUT "> "; n$ ' | Enter two numbers with at least one space between.
n$ = _TRIM$(n$) ' | TRIM any leading or trailing spaces.
bpos = INSTR(n$, " ") ' | Find the first space between the two numbers.
a = VAL(LEFT$(n$, bpos - 1)) ' | Parse the first number from the input string.
b = VAL(_TRIM$(MID$(n$, bpos))) ' | Parse the second number from the input string.
IF (a < -1000 OR a > 1000) OR (b < -1000 OR b > 1000) THEN
PRINT "A number is outside of limit (-1000 to +1000). Try again.": PRINT
GOTO START ' | Check both number are within prescribed limit.
END IF
a$ = LTRIM$(STR$(a)) ' | Clean up both numbers and the sum for better printing.
b$ = LTRIM$(STR$(b)) ' | "
sum$ = LTRIM$(STR$(a + b)) ' | "
PRINT "The sum of the two integers a + b = "; a$; " + "; b$; " = "; sum$
Quackery
As a dialogue in the Quackery shell:
/O> $ "Please enter two numbers separated by a space: " input ... say "Their sum is: " quackery + echo cr ... Please enter two numbers separated by a space: 2 3 Their sum is: 5 Stack empty.
Quite BASIC
10 input "Enter number A: ";a
20 input "Enter number B: ";b
30 print a+b
R
sum(scan("", numeric(0), 2))
Ra
class Sum
**Adds two given integers**
on start
args := program arguments
if args empty
print to Console.error made !, "No arguments given"
exit program with error code
if args.count = 1
print to Console.error made !, "Only one argument given"
exit program with error code
try
print integer.parse(args[0]) + integer.parse(args[1])
catch FormatException
print to Console.error made !, "Arguments must be integers"
exit program with error code
catch OverflowException
print to Console.error made !, "Numbers too large"
exit program with error code
Racket
#lang racket
(+ (read) (read))
Or, with additional error checking:
#lang racket
(define a (read))
(unless (number? a) (error 'a+b "number" a))
(define b (read))
(unless (number? b) (error 'a+b "number" b))
(displayln (+ a b))
Raku
(formerly Perl 6)
Short version with very little "line noise":
get.words.sum.say;
Reduction operator [+]
, and say
as a function:
say [+] get.words;
Long version:
my ($a, $b) = $*IN.get.split(" ");
say $a + $b;
REBOL
forever [x: load input print x/1 + x/2]
- Output:
1 2 3 2 2 4 3 2 5
Red
x: load input print x/1 + x/2
- Output:
1 2 3 2 2 4 3 2 5
Alternative implementations:
print (first x: load input) + x/2
print head insert load input 'add
print load replace input " " " + "
Relation
set input = "2 2"
set a = regexreplace(input,"^(-?\d+)\s+(-?\d+)+$","$1")
set b = regexreplace(input,"^(-?\d+)\s+(-?\d+)+$","$2")
echo a + b
Retro
:try ("-n) s:get s:to-number s:get s:to-number + n:put ;
try
1
2
REXX
version 1, unnormalized
The numbers can be any valid REXX number (integer, fixed point decimal, floating point (with exponential notation, ···).
/*REXX program obtains two numbers from the input stream (the console), shows their sum.*/
parse pull a b /*obtain two numbers from input stream.*/
say a+b /*display the sum to the terminal. */
/*stick a fork in it, we're all done. */
version 2, normalizied
If the user entered 4.00000 and wanted to add 5 to that, and expects 9,
then the output needs to be normalized before displaying the result.
Normally, REXX will keep the greatest precision in the results;
adding 4.00000 and 5 will normally yield 9.00000
Dividing by one normalizes the number.
/*REXX program obtains two numbers from the input stream (the console), shows their sum.*/
parse pull a b /*obtain two numbers from input stream.*/
say (a+b) / 1 /*display normalized sum to terminal. */
/*stick a fork in it, we're all done. */
version 3, extended precision
Using the numeric digits statement allows more decimal digits to be used, the default is 9.
/*REXX program obtains two numbers from the input stream (the console), shows their sum.*/
numeric digits 300 /*the default is nine decimal digits.*/
parse pull a b /*obtain two numbers from input stream.*/
z= (a+b) / 1 /*add and normalize sum, store it in Z.*/
say z /*display normalized sum Z to terminal.*/
/*stick a fork in it, we're all done. */
version 4, multiple numbers
This REXX version adds all the numbers entered (not just two).
/*REXX program obtains some numbers from the input stream (the console), shows their sum*/
numeric digits 1000 /*just in case the user gets ka-razy. */
say 'enter some numbers to be summed:' /*display a prompt message to terminal.*/
parse pull y /*obtain all numbers from input stream.*/
many= words(y) /*obtain the number of numbers entered.*/
$= 0 /*initialize the sum to zero. */
do j=1 for many /*process each of the numbers. */
$= $ + word(y, j) /*add one number to the sum. */
end /*j*/
/*stick a fork in it, we're all done. */
say 'sum of ' many " numbers = " $/1 /*display normalized sum $ to terminal.*/
version 5, multiple numbers, tongue in cheek
/*REXX program obtains some numbers from the input stream (the console), shows their sum*/
numeric digits 1000 /*just in case the user gets ka-razy. */
say 'enter some numbers to be summed:' /*display a prompt message to terminal.*/
parse pull y /*obtain all numbers from input stream.*/
y=space(y)
y=translate(y,'+',' ')
Interpret 's='y
say 'sum of ' many " numbers = " s/1 /*display normalized sum s to terminal.*/
Ring
give Numbers
Numbers = split(Numbers)
sum = 0
for x in Numbers sum += x next
see sum
func Split Str
for x in str if x = " " x = nl ok next
return str2list(str)
Robotic
input string "Input A:"
set "A" to "input"
input string "Input B:"
set "B" to "input"
* "('A' + 'B')"
end
Although the function in the first and third line asks for a string as the input, so long as the variable isn't made to store a string, it will default to an integer instead. Inserting a string to this will return a 0.
Rockstar
Minimized:
Listen to A number
Listen to B
Say A number plus B
Idiomatic:
Listen to my voice
Listen to your thoughts
Shout your thoughts with my voice
RPL
Related task is natively implemented in RPL.
+
2 2 + 2 3 +
- Output:
2: 4 1: 5
Ruby
puts gets.split.sum(&:to_i)
Run BASIC
input, x$
print val(word$(x$,1)) + val(word$(x$,2))
Rust
use std::io;
fn main() {
let mut line = String::new();
io::stdin().read_line(&mut line).expect("reading stdin");
let mut i: i64 = 0;
for word in line.split_whitespace() {
i += word.parse::<i64>().expect("trying to interpret your input as numbers");
}
println!("{}", i);
}
or
use std::io;
fn main() {
let mut line = String::new();
io::stdin().read_line(&mut line).expect("reading stdin");
let sum: i64 = line.split_whitespace()
.map(|x| x.parse::<i64>().expect("Not an integer"))
.sum();
println!("{}", sum);
}
S-lang
% A+B from stdin, sans error checking
variable input, a, b;
() = fgets(&input, stdin);
input = strtrim_end(input, "\n");
() = sscanf(input, "%d%d", &a, &b);
print(a + b);
- Output:
prompt$ echo "12 34" | slsh A+B.sl 46
% A+B from stdin, basic validity testing
variable input, a, b, rc;
() = fgets(&input, stdin);
input = strtrim_end(input, "\n");
rc = sscanf(input, "%d%d", &a, &b);
if ((rc == 2) && (a >= -1000) && (a <= 1000) && (b >= -1000) && (b <= 1000)) {
print(a + b);
} else {
message("input invalid or out of range (-1000,1000): $input"$);
}
Scala
println(readLine().split(" ").map(_.toInt).sum)
This will work if the input is exactly as specified, with no extra whitespace. A slightly more robust version:
val s = new java.util.Scanner(System.in)
val sum = s.nextInt() + s.nextInt()
println(sum)
or
println(readLine().split(" ").filter(_.length>0).map(_.toInt).sum)
Scheme
(display (+ (read) (read)))
Scratch
Scratch is a graphical programming language. Follow the link to see an example solution for A + B
Scratch A + B
Since Scratch is an educational language, I've included comments in the code for new programmers to better understand what the program is doing.
sed
Sed is for string processing and has no facility for manipulating numbers as numeric values. However, being Turing complete, sed can be coerced into performing mathematics.
: Loop
# All done
/^-*00* /s///
/ -*00*$/s///
t
# Negative Check
/^\(-*\)[0-9].* \1[0-9]/!b Negative
# Create magic lookup table
s/\(.[0-9]*\) \(.[0-9]*\)/\1;987654321000009999000999009909 \2;012345678999990000999000990090/
s/ \(-\)*\(9*;\)/ \10\2/
# Decrement 1st number
s/\([^0]\)\(0*\);[^0]*\1\(.\).*\2\(9*\).* \(.*\)/\3\4 \5/
# Increment 2nd
s/\([^9]\)\(9*\);[^9]*\1\(.\).*\2\(0*\).*/\3\4/
t Loop
: Negative
# Create magic lookup table
s/\(.[0-9]*\) \(.[0-9]*\)/\1;987654321000009999000999009909 \2;987654321000009999000999009909/
# Decrement 1st number
s/\([^0]\)\(0*\);[^0]*\1\(.\).*\2\(9*\).* \(.*\)/\3\4 \5/
# Decrement 2nd
s/\([^0]\)\(0*\);[^0]*\1\(.\).*\2\(9*\).*/\3\4/
t Loop
Another method, based off of this StackExchange answer:
#!/bin/sed -f
# Add a marker in front of each digit, for tracking tens, hundreds, etc.
s/[0-9]/<&/g
# Convert numbers to, in essence, tally marks
s/0//g; s/1/|/g; s/2/||/g; s/3/|||/g; s/4/||||/g; s/5/|||||/g
s/6/||||||/g; s/7/|||||||/g; s/8/||||||||/g; s/9/|||||||||/g
# Multiply by ten for each digit from the back they were.
:tens
s/|</<||||||||||/g
t tens
# We don't want the digit markers any more
s/<//g
# Negative minus negative is the negation of their absolute values.
s/^-\(|*\) *-/-\1/
# Negative plus positive equals positive plus negative, and we want the negative at the back.
s/^-\(|*\) \+\(|*\)$/\2-\1/
# Get rid of any space between the numbers
s/ //g
# A tally on each side can be canceled.
:minus
s/|-|/-/
t minus
s/-$//
# Convert back to digits
:back
s/||||||||||/</g
s/<\([0-9]*\)$/<0\1/g
s/|||||||||/9/g;
s/|||||||||/9/g; s/||||||||/8/g; s/|||||||/7/g; s/||||||/6/g;
s/|||||/5/g; s/||||/4/g; s/|||/3/g; s/||/2/g; s/|/1/g;
s/</|/g
t back
s/^$/0/
Seed7
$ include "seed7_05.s7i";
const proc: main is func
local
var integer: a is 0;
var integer: b is 0;
begin
read(a);
read(b);
writeln(a + b);
end func;
Self
Works with positive and negative integers, and also more than two integers.
((stdin readLine splitOn: ' ') mapBy: [|:e| e asInteger]) sum printLine.
SenseTalk
ask "Enter the first number:"
put it into a
ask "Enter the second number:"
put it into b
put a + b
put file "input.txt" into inputFile
split inputFile by space
put sum of inputFile
SequenceL
import <Utilities/Conversion.sl>;
main(args(2)) := stringToInt(args[1]) + stringToInt(args[2]);
- Output:
cmd:> main.exe 3 4 7 cmd:> main.exe -5 7 2 cmd:> main.exe -12 -10 -22
SETL
read(A, B);
print(A + B);
Shiny
if (io.line 'stdin').match ~(\d+)\s+(\d+)~
say "$a $b %(a+b)d"
end
Sidef
Works with both positive and negative integers.
say STDIN.readline.words.map{.to_i}.sum
More idiomatically:
say read(String).words»to_i()»«+»
Explicit summation:
var (a, b) = read(String).words.map{.to_i}...
say a+b
Simula
BEGIN
WHILE NOT LASTITEM DO
BEGIN
OUTINT(ININT + ININT, 0);
OUTIMAGE;
END;
END.
Smalltalk
Most Smalltalk implementations do not have the notion of a standard input stream, since it has always been a GUI based programming environment. I've included test methods to demonstrate one way to create an input stream with two integers can be created. Opening a text file would be another.
'From Squeak3.7 of ''4 September 2004'' [latest update: #5989] on 8 August 2011 at 3:50:55 pm'!
Object subclass: #ABTask
instanceVariableNames: ''
classVariableNames: ''
poolDictionaries: ''
category: 'rosettacode'!
"-- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- "!
ABTask class
instanceVariableNames: ''!
!ABTask class methodsFor: 'demo'!
parseInteger: inputStream
^ Integer readFrom: inputStream skipSeparators! !
!ABTask class methodsFor: 'demo'!
sum: inputStream
^ (self parseInteger: inputStream)
+ (self parseInteger: inputStream)! !
!ABTask class methodsFor: 'demo'!
test2Plus2
^ self
sum: (ReadStream on: '2 2')! !
!ABTask class methodsFor: 'demo'!
test3Plus2
^ self
sum: (ReadStream on: '3 2')! !
but all have a stream hierarchy, so the task could be restated to pass input and output as stream arguments:
|task|
task := [:inStream :outStream |
|processLine|
processLine :=
[
|a b|
a := Integer readFrom: inStream.
b := Integer readFrom: inStream.
"is validation part of the task?"
self assert:( a between:-1000 and: 1000).
self assert:( b between:-1000 and: 1000).
outStream print (a+b); cr.
].
[ inStream atEnd ] whileFalse:processLine.
].
task value: ( 'dataIn.txt' asFilename readStream) value:Transcript.
or:
task value: Stdin value: Stdout.
smart BASIC
INPUT n$
PRINT VAL(LEFT$(n$,(LEN(STR$(VAL(n$))))))+VAL(RIGHT$(n$,(LEN(n$)-LEN(STR$(VAL(n$)))-1)))
NOTE: This is a horribly forced way of doing this. smart BASIC has commands to SPLIT strings. Surely someone can provide better code than what I've written here. ;@)
And someone did...
A FAR more elegant solution was provided by "Dutchman" on the smart BASIC Support Forum:
INPUT n$
SPLIT n$ TO m$,n WITH " "
PRINT m$(0),m$(1),m$(0)+m$(1)
NOTE: smart BASIC will intelligently interpret the contents of a string as a numeric value if necessary. Other versions of BASIC would require the values stored in a string to be converted to numeric values before calculation.
SmileBASIC
INPUT A
INPUT B
PRINT A+B
SNOBOL4
Simple-minded solution (literally "two somethings separated by space")
input break(" ") . a " " rem . b
output = a + b
end
"Integer aware" solution:
nums = "0123456789"
input span(nums) . a break(nums) span(nums) . b
output = a + b
end
SPAD
One of several possibilities:
(1) -> integer READ()$Lisp + integer READ()$Lisp
333 444
(1) 777
Type: PositiveInteger
Domain:SExpression
SparForte
As a structured script.
#!/usr/local/bin/spar
pragma annotate( summary, "aplusb" )
@( description, "A+B - in programming contests, classic problem, which is given so" )
@( description, "contestants can gain familiarity with online judging system being used. " )
@( description, "A+B is one of few problems on contests, which traditionally lacks fabula." )
@( description, "Given 2 integer numbers, A and B. One needs to find their sum. " )
@( category, "tutorials" )
@( author, "Ken O. Burtch" )
@( see_also, "http://rosettacode.org/wiki/A%2BB" );
pragma license( unrestricted );
pragma software_model( nonstandard );
pragma restriction( no_external_commands );
procedure aplusb is
s : string;
a : integer;
b : integer;
begin
s := get_line;
a := numerics.value( strings.field( s, 1, ' ' ) );
b := numerics.value( strings.field( s, 2, ' ' ) );
? a+b;
end aplusb;
SPARK
-- By Jacob Sparre Andersen
-- Validates with SPARK GPL 2010's Examiner/Simplifier
with SPARK_IO; --# inherit SPARK_IO;
--# main_program;
procedure A_Plus_B
--# global in out SPARK_IO.Inputs, SPARK_IO.Outputs;
--# derives SPARK_IO.Inputs from SPARK_IO.Inputs &
--# SPARK_IO.Outputs from SPARK_IO.Inputs, SPARK_IO.Outputs;
is
subtype Small_Integers is Integer range -1_000 .. +1_000;
A, B : Integer;
A_OK, B_OK : Boolean;
begin
SPARK_IO.Get_Integer
(File => SPARK_IO.Standard_Input,
Item => A,
Width => 0,
Read => A_OK);
A_OK := A_OK and A in Small_Integers;
SPARK_IO.Get_Integer
(File => SPARK_IO.Standard_Input,
Item => B,
Width => 0,
Read => B_OK);
B_OK := B_OK and B in Small_Integers;
if A_OK and B_OK then
SPARK_IO.Put_Integer
(File => SPARK_IO.Standard_Output,
Item => A + B,
Width => 4,
Base => 10);
else
SPARK_IO.Put_Line
(File => SPARK_IO.Standard_Output,
Item => "Input data does not match specification.",
Stop => 0);
end if;
end A_Plus_B;
SPL
n = #.split(#.input("Input two numbers, separated by space:")," ")
#.output(n[1],"+",n[2],"=",#.val(n[1])+#.val(n[2]))
- Input:
Input two numbers, separated by space: 2 3
- Output:
2+3=5
SQL
select A+B
Example:
select 2+3
This should produce a result set containing the value 5.
Note however that declaration of variables is outside the scope of the ANSI SQL standards, unless by variables you mean tables (which would complicate the example considerably).
SQL PL
With SQL only:
CREATE OR REPLACE FUNCTION splitadd (instring VARCHAR(255))
RETURNS INTEGER
NO EXTERNAL ACTION
F1: BEGIN ATOMIC
declare first INTEGER;
declare second INTEGER;
set first = REGEXP_SUBSTR(instring, '[0-9]+',1,1);
set second = REGEXP_SUBSTR(instring, '[0-9]+',1,2);
return first + second;
END
Output:
VALUES DBA.SPLITADD(VARCHAR('1234 2345')) 1 ---- 3579
SSEM
The SSEM has no Add instruction, so we rely on the fact that a + b = -(-a - b).
10100000000000100000000000000000 0. -5 to c acc = -A
01100000000001010000000000000000 1. Sub. 6 acc -= B
11100000000001100000000000000000 2. c to 7 X = acc
11100000000000100000000000000000 3. -7 to c acc = -X
00000000000001110000000000000000 4. Stop
10100100000000000000000000000000 5. 37 A
00111000000000000000000000000000 6. 28 B
00000000000000000000000000000000 7. 0 X
Standard ML
(*
* val split : string -> string list
* splits a string at it spaces
*)
val split = String.tokens Char.isSpace
(*
* val sum : int list -> int
* computes the sum of a list of numbers
*)
val sum = foldl op+ 0
(*
* val aplusb : unit -> int
* reads a line and gets the sum of the numbers
*)
fun aplusb () =
let
val input = valOf (TextIO.inputLine TextIO.stdIn)
in
(sum o List.mapPartial Int.fromString o split) input
end
- Output:
- aplusb(); 123 456 val it = 579 : int
Swift
Requires sending EOF.
import Foundation
let input = NSFileHandle.fileHandleWithStandardInput()
let data = input.availableData
let str = NSString(data: data, encoding: NSUTF8StringEncoding)!
let nums = str.componentsSeparatedByString(" ")
let a = (nums[0] as String).toInt()!
let b = (nums[1] as String).toInt()!
print(" \(a + b)")
Swift 4 and no requirement to send EOF (press enter/send newline like you normally would)
import Foundation
let input = FileHandle.standardInput
let data = input.availableData
let str = String(data: data, encoding: .utf8)!
let nums = str.split(separator: " ")
.map { String($0.unicodeScalars
.filter { CharacterSet.decimalDigits.contains($0) }) }
let a = Int(nums[0])!
let b = Int(nums[1])!
print(" \(a + b)")
Symsyn
[] $s
getitem $s x
getitem $s y
+ x y
y []
Tailspin
composer nums
[ (<WS>?) <INT> (<WS>) <INT> (<WS>?) ]
end nums
$IN::lines -> nums -> $(1) + $(2) -> '$;
' -> !OUT::write
Alternatively
composer nums
(<WS>?) (def a: <INT>;) (<WS>) <INT> -> $a + $ (<WS>?)
end nums
$IN::lines -> nums -> '$;
' -> !OUT::write
Tcl
scan [gets stdin] "%d %d" x y
puts [expr {$x + $y}]
Alternatively:
puts [tcl::mathop::+ {*}[gets stdin]]
To/from a file:
set in [open "input.txt"]
set out [open "output.txt" w]
scan [gets $in] "%d %d" x y
puts $out [expr {$x + $y}]
close $in
close $out
Terraform
#Aamrun, August 15th, 2022
variable "a" {
type = number
}
variable "b" {
type = number
}
output "a_plus_b" {
value = var.a + var.b
}
- Output:
$ terraform apply -var="a=136" -var="b=745" -auto-approve Changes to Outputs: + a_plus_b = 881 You can apply this plan to save these new output values to the Terraform state, without changing any real infrastructure. Apply complete! Resources: 0 added, 0 changed, 0 destroyed. Outputs: a_plus_b = 881 $
TI-83 BASIC
:Prompt A,B
:Disp A+B
TI-83 Hex Assembly
Note: Comments (after the semicolons) are just for explanation -- TI-83 hex assembly does not allow comments in program source code.
PROGRAM:APLUSB
:AsmPrgm
:
:EFC541 ; ZeroOP1
:217984 ; ld hl,op1+1
:3641 ; ld (hl),'A'
:EFE34A ; RclVarSym
:CF ; rst OP1toOP2
:
:EFC541 ; ZeroOP1
:217984 ; ld hl,op1+1
:3642 ; ld (hl),'B'
:EFE34A ; RclVarSym
:
:F7 ; rst FPAdd
:EFBF4A ; StoAns
:C9 ; ret
Store the inputs in the 'A' and 'B' OS variables. Run it with Asm(prgmAPLUSB) and the output will be stored in the Ans OS variable.
TI-89 BASIC
:aplusb(a,b)
:a+b
TorqueScript
Since torque is not compatible with standard input, I will show the closest to that. It's a function that takes a single string input, that will contain the 2 numbers.
Function aPlusB(%input)
{
return getWord(%input, 0) + getWord(%input, 1);
}
Transd
#lang transd
MainModule : {
a: Int(),
b: Int(),
_start: (lambda (textout (+ (read a) (read b))))
}
TSE SAL
INTEGER PROC FNMathGetSumAPlusBI( INTEGER A, INTEGER B )
RETURN( A + B )
END
//
PROC Main()
STRING s1[255] = "3"
STRING s2[255] = "2"
IF ( NOT ( Ask( "math: get: sum: a: plus: a (choose a number between -1000 and 1000) = ", s1, _EDIT_HISTORY_ ) ) AND ( Length( s1 ) > 0 ) ) RETURN() ENDIF
IF ( NOT ( Ask( "math: get: sum: a: plus: b (choose a number between -1000 and 1000) = ", s2, _EDIT_HISTORY_ ) ) AND ( Length( s2 ) > 0 ) ) RETURN() ENDIF
Message( FNMathGetSumAPlusBI( Val( s1 ), Val( s2 ) ) ) // gives e.g. 5
END
- Output:
output 5
TUSCRIPT
$$ MODE TUSCRIPT
SET input="1 2"
SET input=SPLIT(input,": :")
SET input=JOIN (input)
SET output=SUM(input)
TXR
$ txr -p '(+ (read) (read))' 1.2 2.3 3.5
TypeScript
function add(a: number, b: number) { return a+b; }
UNIX Shell
#!/bin/sh
read a b || exit
echo `expr "$a" + "$b"`
Script "a+b.sh":
#!/bin/bash
read a b || exit
echo $(( a + b ))
- Output:
echo 2 3 | ksh a+b.sh
5
One liner :
a=0;b=0;read a;read b;echo "Sum of $a and $b is "$((a+b))
Sample run :
3 4 Sum of 3 and 4 is 7
C Shell
set line=$<
set input=($line)
@ sum = $input[1] + $input[2]
echo $sum
Ursa
#
# a + b
#
# read a string containing the two ints
decl string input
set input (in string console)
# determine the sum
decl int sum
set sum (int (+ sum (int (split input " ")<0>)))
set sum (int (+ sum (int (split input " ")<1>)))
# output the sum
out sum endl console
Ultimate++
#include <Core/Core.h>
#include <stdio.h>
#include <iostream>
using namespace Upp;
CONSOLE_APP_MAIN
{
int a, b;
a = 2, b = 3;
printf("%d + %d = %d\n",a,b,(a + b));
std::cout << std::endl << a << " + " << b << " = " << (a + b) << std::endl;
const Vector<String>& cmdline = CommandLine();
for(int i = 0; i < cmdline.GetCount(); i++) {
}
}
Ursala
Using standard input and output streams:
#import std
#import int
#executable&
main = %zP+ sum:-0+ %zp*FiNCS+ sep` @L
Overwriting a text file named as a command line parameter:
#import std
#import int
#executable -[parameterized]-
main = ~command.files.&h; <.contents:= %zP+ sum:-0+ %zp*FiNCS+ sep` @L+ ~contents>
Creating a new file named after the input file with suffix .out
:
#import std
#import int
#executable -[parameterized]-
main =
~command.files.&h; ~&iNC+ file$[
contents: %zP+ sum:-0+ %zp*FiNCS+ sep` @L+ ~contents,
path: ~path; ^|C\~& ~=`.-~; ^|T/~& '.out'!]
Vala
Read from stdin while program running:
Using GLib;
int main (string[] args) {
stdout.printf ("Please enter int value for A\n");
var a = int.parse (stdin.read_line ());
stdout.printf ("Please enter int value for B\n");
var b = int.parse (stdin.read_line ());
stdout.printf ("A + B = %d\n", a + b);
return 0;
}
VBA
A simple version:
Sub AplusB()
Dim s As String, t As Variant, a As Integer, b As Integer
s = InputBox("Enter two numbers separated by a space")
t = Split(s)
a = CInt(t(0))
b = CInt(t(1))
MsgBox a + b
End Sub
An other version:
Sub Rosetta_AB()
Dim stEval As String
stEval = InputBox("Enter two numbers, separated only by a space", "Rosetta Code", "2 2")
MsgBox "You entered " & stEval & vbCr & vbCr & _
"VBA converted this input to " & Replace(stEval, " ", "+") & vbCr & vbCr & _
"And evaluated the result as " & Evaluate(Replace(stEval, " ", "+")), vbInformation + vbOKOnly, "XLSM"
End Sub
VBScript
A simple version:
s=InputBox("Enter two numbers separated by a blank")
t=Split(s)
a=CInt(t(0))
b=CInt(t(1))
c=a+b
MsgBox c
An other version:
Option Explicit
Dim a, b
Select Case WScript.Arguments.Count
Case 0 'No arguments, prompt for them.
WScript.Echo "Enter values for a and b"
a = WScript.Stdin.ReadLine
if Instr(a, " ") > 0 then 'If two variables were passed
b = Split(a)(1)
a = Split(a)(0)
else
WScript.Echo "Enter value for b"
b = WScript.Stdin.ReadLine
end if
Case 1 'One argument, assume it's an input file, e.g. "in.txt"
Dim FSO : Set FSO = CreateObject("Scripting.FileSystemObject")
With FSO.OpenTextFile(WScript.Arguments(0), 1)
a = .ReadLine
b = Split(a)(1)
a = Split(a)(0)
.Close
End With
Case 2 'Two arguments, assume they are values
a = WScript.Arguments(0)
b = WScript.Arguments(1)
End Select
'At this point, a and b are strings as entered, make them numbers
a = CInt(a)
b = CInt(b)
'Write the sum
Wscript.Echo a + b
if 1 = WScript.Arguments.Count then
With FSO.CreateTextFile("out.txt")
.WriteLine a + b
.Close
End With
end if
Vedit macro language
This version implements the task as specified in the task description.
// Input two values on single line in text format
Get_Input(10, "Enter two integers separated by a space: ")
// Extract two numeric values from the text
Buf_Switch(Buf_Free)
Reg_Ins(10)
BOF
#1 = Num_Eval(ADVANCE)
#2 = Num_Eval()
Buf_Quit(OK)
// Calculate and display the results
Num_Type(#1 + #2)
A simpler version that prompts for the two numbers separately:
#1 = Get_Num("Enter number A: ")
#2 = Get_Num("Enter number B: ")
Num_Type(#1 + #2)
Verilog
module TEST;
reg signed [11:0] y;
initial begin
y= sum(2, 2);
y= sum(3, 2);
y= sum(-3, 2);
end
function signed [11:0] sum;
input signed [10:0] a, b;
begin
sum= a + b;
$display("%d + %d = %d",a,b,sum);
end
endfunction
endmodule
VHDL
LIBRARY std;
USE std.TEXTIO.all;
entity test is
end entity test;
architecture beh of test is
begin
process
variable line_in, line_out : line;
variable a,b : integer;
begin
readline(INPUT, line_in);
read(line_in, a);
read(line_in, b);
write(line_out, a+b);
writeline(OUTPUT, line_out);
wait; -- needed to stop the execution
end process;
end architecture beh;
Visual Basic .NET
Module Module1
Sub Main()
Dim s() As String = Nothing
s = Console.ReadLine().Split(" "c)
Console.WriteLine(CInt(s(0)) + CInt(s(1)))
End Sub
End Module
V (Vlang)
import os
fn main() {
mut a := 0
mut b := 0
text := os.get_raw_line()
values := text.split(' ')
a = values[0].int()
b = values[1].int()
println('$a + $b = ${a+b}')
}
Read from stdin
- Output:
Input Output 2 2 2 + 2 = 4 3 2 3 + 2 = 5
Wee Basic
Print 1 "Enter number A:"
input a
Print 1 "Enter number B:"
input b
let c=a+b
print 1 c
end
Whitespace
Wisp
display : + (read) (read)
314
315
;; displays 629
Wren
import "io" for Stdin, Stdout
while (true) {
System.write("Enter two integers separated by a space : ")
Stdout.flush()
var s = Stdin.readLine().split(" ")
if (s.count < 2) {
System.print("Insufficient numbers, try again")
} else {
var a = Num.fromString(s[0])
var b = Num.fromString(s[s.count-1])
System.print("Their sum is %(a + b)")
return
}
}
- Output:
Sample input/output:
Enter two integers separated by a space : 12 16 Their sum is 28
X86 Assembly
section .text
global _start
_print:
mov ebx, 1
mov eax, 4
int 0x80
ret
_get_input:
mov edx, 4
mov ebx, 0
mov eax, 3
int 0x80
ret
_start:
mov edx, in_val_len
mov ecx, in_val_msg
call _print
mov ecx, a
call _get_input
;make 'a' an actual number rather than a char.
sub dword [a], 0x30
mov edx, in_val_len
mov ecx, in_val_msg
call _print
mov ecx, b
call _get_input
;calc real number for 'b'
sub dword [b], 0x30
mov eax, dword [a]
mov ebx, dword [b]
add eax, ebx
;get the character for our sum.
add eax, 0x30
mov dword [sum], eax
mov edx, out_val_len
mov ecx, out_val_msg
call _print
mov [sum+1], dword 0xa
mov edx, 4
mov ecx, sum
call _print
push 0x1
mov eax, 1
push eax
int 0x80
ret
section .data
in_val_msg db "Please input an integer:",0
in_val_len equ $-in_val_msg
out_val_msg db "The sum of a+b is: ",0
out_val_len equ $-out_val_msg
section .bss
a resd 1
b resd 1
sum resd 1
This will not work on numbers over 0(from 1 to 0). This is due to the fact, numbers higher than 0(10,11, etc) are in fact strings when taken from the keyboard. A much longer conversion code is required to loop through and treat each number in the string as separate numbers. For example, The number '10' would have to be treated as a 1 and a 0.
XBS
Since XBS is written in Javascript, we have to use the Javascript prompt function to get inputs.
const Amount:number = toint(window.prompt("Input an amount"));
set Stream = [];
<|(*1..Amount)=>Stream.push(window.prompt("Input a number"));
Stream=Stream.join(" ");
const Inputs = <|(*Stream.split(" "))toint(_);
set Result = 0;
<|(*Inputs)Result+=_;
log(Result);
- Output:
If we input an amount of "2", then input "1" and "2", the output will be "3".
3
xEec
i# i# ma h#10 r o# p o$ p
XLISP
(DEFUN A-PLUS-B ()
(DISPLAY "Enter two numbers separated by a space.")
(NEWLINE)
(DISPLAY "> ")
(DEFINE A (READ))
(DEFINE B (READ))
(+ A B))
- Output:
(A-PLUS-B) Enter two numbers separated by a space. > 2 2 4
Xojo
var inp as string
var strVals() as string
print("Enter two numbers separated by a space:")
do
inp = input
strVals = inp.split(" ")
var a, b as integer
a = strVals(0).toInteger
b = strVals(1).toInteger
if a < -1000 or b > 1000 then
print("The first number should be greater than or equal to -1000 and the second number should be less " + _
"than or equal to 1000. Please re-enter:")
continue
end
var result as integer = a + b
print(a.toString + " + " + b.toString + " = " + result.toString)
exit
loop
XPL0
include c:\cxpl\codes;
int A, B;
[A:= IntIn(0);
B:= IntIn(0);
IntOut(0, A+B);
CrLf(0);
]
XQuery
(:
Using the EXPath File Module, which is built into most XQuery processors
by default and thus does not need to get imported. Some processors bind the
namespace automatically, others require explicit declaration.
:)
xquery version "3.1";
declare namespace file = 'http://expath.org/ns/file';
let $in := 'input.txt'
let $out := 'output.txt'
let $numbers := tokenize(file:read-text($in))
let $result := xs:numeric($numbers[1]) + xs:numeric($numbers[2])
return file:write-text($out, xs:string($result))
Yabasic
repeat
input "Enter two numbers (betwen -1000 ... +1000): " a, b
until(valid(a) and valid(b))
print "\nThe sum of ", a, " and ", b, " is: ", a + b
sub valid(x)
return x >= -1000 and x <= 1000
end sub
Yorick
a = b = 0;
read, a, b;
write, a + b;
ZED
Source -> http://ideone.com/WLtEfe Compiled -> http://ideone.com/fMt6ST
(A+B)
comment:
#true
(+) (read) (read)
(+) one two
comment:
#true
(003) "+" one two
(read)
comment:
#true
(001) "read"
Zig
const std = @import("std");
const stdout = std.io.getStdOut().writer();
const Input = enum { a, b };
pub fn main() !void {
var buf: [1024]u8 = undefined;
const reader = std.io.getStdIn().reader();
const input = try reader.readUntilDelimiter(&buf, '\n');
const values = std.mem.trim(u8, input, "\x20");
var count: usize = 0;
var split: usize = 0;
for (values, 0..) |c, i| {
if (!std.ascii.isDigit(c)) {
count += 1;
if (count == 1) split = i;
}
}
const a = try std.fmt.parseInt(u64, values[0..split], 10);
const b = try std.fmt.parseInt(u64, values[split + count ..], 10);
try stdout.print("{d}\n", .{a + b});
}
- Output:
1 2 3 3 6 9
zkl
do(2){ask("A B: ").split(" ").filter().sum().println()}
A B: 123 567 690 A B: -4 6 2
This actually works for any number of integers
Zoea
program: a_plus_b
input: '7 11'
output: 18
Zoea Visual
zonnon
module ABProblem;
var
a,b: integer;
begin
read(a,b);
writeln(a+b)
end ABProblem.
1 2 3
ZX Spectrum Basic
10 PRINT "Input two numbers separated by"'"space(s) "
20 INPUT LINE a$
30 GO SUB 90
40 FOR i=1 TO LEN a$
50 IF a$(i)=" " THEN LET a=VAL a$( TO i): LET b=VAL a$(i TO ): PRINT a;" + ";b;" = ";a+b: GO TO 70
60 NEXT i
70 STOP
80 REM LTrim operation
90 IF a$(1)=" " THEN LET a$=a$(2 TO ): GO TO 90
100 RETURN
Another solution
10 PRINT "Input two numbers separated by"'"space(s) "
20 INPUT LINE a$
30 LET ll=10e10: LET ls=0: LET i=1
40 IF a$(i)=" " THEN LET ls=i: GO TO 60
50 LET ll=i
60 IF ls>ll THEN GO TO 80
70 LET i=i+1: GO TO 40
80 LET a=VAL a$( TO i): LET b=VAL a$(i TO )
90 PRINT a;" + ";b;" = ";a+b
Input two numbers separated by space(s) 3.14 2^3 3.14 + 8 = 11.14
- Programming Tasks
- Solutions by Programming Task
- Simple
- 0815
- 11l
- 360 Assembly
- 4ME
- 8th
- 8080 Assembly
- AArch64 Assembly
- ABAP
- Acornsoft Lisp
- Action!
- Ada
- Agena
- Aime
- ALGOL 60
- ALGOL 68
- ALGOL W
- Amazing Hopper
- ANTLR
- Apex
- APL
- AppleScript
- Arc
- Argile
- ARM Assembly
- Arturo
- AsciiDots
- ATS
- AutoHotkey
- AutoIt
- AWK
- BabyCobol
- BASIC
- Applesoft BASIC
- BaCon
- BASIC256
- BBC BASIC
- Chipmunk Basic
- Commodore BASIC
- FreeBASIC
- GW-BASIC
- FUZE BASIC
- IS-BASIC
- Liberty BASIC
- Minimal BASIC
- MSX Basic
- OxygenBasic
- ProgressBASIC
- Sinclair ZX81 BASIC
- SmallBASIC
- Tiny BASIC
- True BASIC
- UBasic/4tH
- XBasic
- Batch File
- Bc
- Befunge
- Bird
- BlooP
- BootBASIC
- BQN
- Bracmat
- Brainf***
- Brat
- Bruijn
- Burlesque
- C
- C sharp
- C++
- Ceylon
- CFEngine
- Clojure
- COBOL
- CoffeeScript
- Common Lisp
- Component Pascal
- Computer/zero Assembly
- Crystal
- D
- Dart
- Dc
- DCL
- Delphi
- Diego
- DMS
- Dragon
- DWScript
- Déjà Vu
- EasyLang
- EchoLisp
- Ed
- EDSAC order code
- EGL
- Eiffel
- Ela
- Elena
- Elixir
- Elm
- Emacs Lisp
- EMal
- Emojicode
- Erlang
- ERRE
- Euler
- Euler Math Toolbox
- Euphoria
- Excel
- F Sharp
- Factor
- FALSE
- Fantom
- FBSL
- Fennel
- Fhidwfe
- Fish
- Forth
- Fortran
- Free Pascal
- Frink
- FunL
- Furor
- FutureBasic
- Gambas
- Gastona
- GDScript
- Gema
- Genie
- GML
- Go
- Golfscript
- Golo
- Gosu
- Groovy
- GUISS
- Harbour
- Haskell
- Hexiscript
- HicEst
- Hoon
- Hope
- Huginn
- Hy
- I
- Icon
- Unicon
- Idris
- Insitux
- J
- Java
- JavaScript
- Joy
- Jq
- Jsish
- Julia
- K
- Keg
- Kite
- Klong
- Kotlin
- KQL
- L++
- Lambdatalk
- Lang
- Lang5
- Lasso
- LIL
- Lisaac
- Little
- Little Man Computer
- LiveCode
- Logo
- Lua
- M2000 Interpreter
- M4
- Maple
- Mathematica
- Wolfram Language
- MATLAB
- Octave
- Maude
- Maxima
- Mercury
- Min
- MiniScript
- MIRC Scripting Language
- МК-61/52
- ML/I
- Modula-2
- Modula-3
- MoonScript
- Mosaic
- MUMPS
- Nanoquery
- Neko
- Nemerle
- NetRexx
- NewLISP
- Nim
- Nit
- NS-HUBASIC
- Nu
- Nutt
- Nyquist
- Oberon-2
- Objeck
- OCaml
- Oforth
- Ol
- Onyx
- OoRexx
- OpenEdge/Progress
- Openscad
- Order
- Oxygene
- Oz
- PARI/GP
- PascalABC.NET
- Pascal
- Perl
- Phix
- Phix/pGUI
- Phixmonti
- PHP
- Picat
- PicoLisp
- Piet
- Pike
- PL/I
- Plain English
- Pony
- PostScript
- Potion
- PowerShell
- Processing
- ProDOS
- Prolog
- Pure
- PureBasic
- Python
- QB64
- Quackery
- Quite BASIC
- R
- Ra
- Racket
- Raku
- REBOL
- Red
- Relation
- Retro
- REXX
- Ring
- Robotic
- Rockstar
- RPL
- Ruby
- Run BASIC
- Rust
- S-lang
- Scala
- Scheme
- Scratch
- Sed
- Seed7
- Self
- SenseTalk
- SequenceL
- SETL
- Shiny
- Sidef
- Simula
- Smalltalk
- Smart BASIC
- SmileBASIC
- SNOBOL4
- SPAD
- SparForte
- SPARK
- SPL
- SQL
- SQL PL
- SSEM
- Standard ML
- Swift
- Symsyn
- Tailspin
- Tcl
- Terraform
- TI-83 BASIC
- TI-83 Hex Assembly
- TI-89 BASIC
- TorqueScript
- Transd
- TSE SAL
- TUSCRIPT
- TXR
- TypeScript
- UNIX Shell
- C Shell
- Ursa
- Ultimate++
- Ursala
- Vala
- VBA
- VBScript
- Vedit macro language
- Verilog
- VHDL
- Visual Basic .NET
- V (Vlang)
- Wee Basic
- Whitespace
- Wisp
- Wren
- X86 Assembly
- XBS
- XEec
- XLISP
- Xojo
- XPL0
- XQuery
- Yabasic
- Yorick
- ZED
- Zig
- Zkl
- Zoea
- Zoea Visual
- Zonnon
- ZX Spectrum Basic
- Pages with too many expensive parser function calls