# Calculating the value of e

You are encouraged to solve this task according to the task description, using any language you may know.

Calculate the value of   e.

(e   is also known as   Euler's number   and   Napier's constant.)

See details: Calculating the value of e

## 11l

Translation of: Python
```V e0 = 0.0
V e = 2.0
V n = 0
V fact = 1
L (e - e0 > 1e-15)
e0 = e
n++
fact *= 2 * n * (2 * n + 1)
e += (2.0 * n + 2) / fact

print(‘Computed e = ’e)
print(‘Real e = ’math:e)
print(‘Error = ’(math:e - e))
print(‘Number of iterations = ’n)```
Output:
```Computed e = 2.718281779
Real e = 2.718281828
Error = 4.941845111e-8
Number of iterations = 8
```

## 360 Assembly

The 'include' file FORMAT, to format a floating point number, can be found in: Include files 360 Assembly.

```*        Calculating the value of e - 21/07/2018
CALCE    PROLOG
LE     F0,=E'0'
STE    F0,EOLD            eold=0
LE     F2,=E'1'           e=1
LER    F4,F2              xi=1
LER    F6,F2              facti=1
BWHILE   CE     F2,EOLD            while e<>eold
BE     EWHILE             ~
STE    F2,EOLD              eold=e
LE     F0,=E'1'             1
DER    F0,F6                1/facti
AER    F2,F0                e=e+1/facti
AE     F4,=E'1'             xi=xi+1
MER    F6,F4                facti=facti*xi
LER    F0,F4                xi
B      BWHILE             end while
EWHILE   LER    F0,F2              e
LA     R0,5               number of decimals
BAL    R14,FORMATF        format a float number
MVC    PG(13),0(R1)       output e
XPRNT  PG,L'PG            print e
EPILOG
COPY   FORMATF            format a float number
EOLD     DS     E                  eold
PG       DC     CL80' '            buffer
REGEQU
END    CALCE```
Output:
```      2.71828
```

## Action!

```INCLUDE "H6:REALMATH.ACT"

PROC Euler(REAL POINTER e)
REAL e0,fact,tmp,tmp2,one
INT n

IntToReal(1,one)
IntToReal(2,e)
IntToReal(1,fact)
n=2

DO
RealAssign(e,e0)
IntToReal(n,tmp)
RealMult(fact,tmp,tmp2)
RealAssign(tmp2,fact)
n==+1
RealDiv(one,fact,tmp)
RealAssign(tmp2,e)
UNTIL RealGreaterOrEqual(e0,e)
OD
RETURN

PROC Main()
REAL e,calc,diff

Put(125) PutE() ;clear screen
ValR("2.71828183",e)
Euler(calc)
RealSub(calc,e,diff)
Print("      real e=") PrintRE(e)
Print("calculated e=") PrintRE(calc)
Print("       error=") PrintRE(diff)
RETURN```
Output:
```      real e=2.71828183
calculated e=2.71828178
error=-5E-08
```

Translation of: Kotlin
```with Ada.Text_IO;            use Ada.Text_IO;

procedure Euler is
Epsilon : constant     := 1.0E-15;
Fact    : Long_Integer := 1;
E       : Long_Float   := 2.0;
E0      : Long_Float   := 0.0;
N       : Long_Integer := 2;

begin

loop
E0   := E;
Fact := Fact * N;
N    := N + 1;
E    := E + (1.0 / Long_Float (Fact));
exit when abs (E - E0) < Epsilon;
end loop;

Put ("e = ");
Put (E, 0, 15, 0);
New_Line;

end Euler;
```
Output:
```e = 2.718281828459046
```

## ALGOL 60

Works with: A60
```begin

real fact, n, result, epsilon;
fact := 1.0;
result := 2.0;
n := 2.0;
epsilon := 0.000000000001;  comment 1E-12;
for n := n while fact >= epsilon do
begin
fact := fact / n;
n := n + 1;
result := result + fact;
end;

outstring(1,"Computed value of e  =");
outreal(1, result);
outstring(1,"\nValue of e as exp(1) =");
outreal(1,exp(1.0));
outstring(1,"\nPublished value of e = 2.718281828459045");

end```
Output:
```Computed value of e  = 2.71828182846
Value of e as exp(1) = 2.71828182846
Published value of e = 2.718281828459045
```

## ALGOL 68

Translation of: Kotlin
```BEGIN
# calculate an approximation to e #
LONG REAL epsilon = 1.0e-15;
LONG INT  fact   := 1;
LONG REAL e      := 2;
LONG INT  n      := 2;
WHILE
LONG REAL e0 = e;
fact *:= n;
n    +:= 1;
e    +:= 1.0 / fact;
ABS ( e - e0 ) >= epsilon
DO SKIP OD;
print( ( "e = ", fixed( e, -17, 15 ), newline ) )
END```
Output:
```e = 2.718281828459045
```

## AppleScript

For the purposes of 32 bit floating point, the value seems to stabilise after summing c. 16 terms.

```--------------- CALCULATING THE VALUE OF E ----------------
on run

sum(map(inverse, ¬
scanl(product, 1, enumFromTo(1, 16))))

--> 2.718281828459

end run

-- inverse :: Float -> Float
on inverse(x)
1 / x
end inverse

-- product :: Float -> Float -> Float
on product(a, b)
a * b
end product

--------------------- GENERIC FUNCTIONS ---------------------

-- enumFromTo :: Int -> Int -> [Int]
on enumFromTo(m, n)
if m ≤ n then
set lst to {}
repeat with i from m to n
set end of lst to i
end repeat
lst
else
{}
end if
end enumFromTo

-- foldl :: (a -> b -> a) -> a -> [b] -> a
on foldl(f, startValue, xs)
tell mReturn(f)
set v to startValue
set lng to length of xs
repeat with i from 1 to lng
set v to |λ|(v, item i of xs, i, xs)
end repeat
return v
end tell
end foldl

-- Lift 2nd class handler function into 1st class script wrapper
-- mReturn :: First-class m => (a -> b) -> m (a -> b)
on mReturn(f)
if class of f is script then
f
else
script
property |λ| : f
end script
end if
end mReturn

-- map :: (a -> b) -> [a] -> [b]
on map(f, xs)
-- The list obtained by applying f
-- to each element of xs.
tell mReturn(f)
set lng to length of xs
set lst to {}
repeat with i from 1 to lng
set end of lst to |λ|(item i of xs, i, xs)
end repeat
return lst
end tell
end map

-- scanl :: (b -> a -> b) -> b -> [a] -> [b]
on scanl(f, startValue, xs)
tell mReturn(f)
set v to startValue
set lng to length of xs
set lst to {startValue}
repeat with i from 1 to lng
set v to |λ|(v, item i of xs, i, xs)
set end of lst to v
end repeat
return lst
end tell
end scanl

-- sum :: [Num] -> Num
on sum(xs)
on |λ|(a, b)
a + b
end |λ|
end script

end sum
```
Output:
`2.718281828459`

Or, as a single fold:

```------------- APPROXIMATION OF THE VALUE OF E ------------

-- eApprox :: Int -> Float
on eApprox(n)
-- The approximation of E obtained after N iterations.
script go
on |λ|(efl, x)
set {e, fl} to efl
set flx to fl * x

{e + (1 / flx), flx}
end |λ|
end script

item 1 of foldl(go, {1, 1}, enumFromTo(1, n))
end eApprox

--------------------------- TEST -------------------------
on run
-- The approximation of E obtained after 20 iterations.
eApprox(20)
end run

------------------------- GENERIC ------------------------

-- enumFromTo :: Int -> Int -> [Int]
on enumFromTo(m, n)
if m ≤ n then
set xs to {}
repeat with i from m to n
set end of xs to i
end repeat
xs
else
{}
end if
end enumFromTo

-- foldl :: (a -> b -> a) -> a -> [b] -> a
on foldl(f, startValue, xs)
tell mReturn(f)
set v to startValue
set lng to length of xs
repeat with i from 1 to lng
set v to |λ|(v, item i of xs, i, xs)
end repeat
return v
end tell
end foldl

-- mReturn :: First-class m => (a -> b) -> m (a -> b)
on mReturn(f)
-- 2nd class handler function lifted into 1st class script wrapper.
if script is class of f then
f
else
script
property |λ| : f
end script
end if
end mReturn
```
Output:
`2.718281828459`

## Applesoft BASIC

```?"E = "EXP(1)
```
Output:
`E = 2.71828183`

## Arturo

```fact: 1
e: 2.0
e0: 0.0
n: 2
lim: 0.0000000000000010

while [lim =< abs e-e0][
e0: e
fact: fact * n
n: n + 1
e: e + 1.0 / fact
]

print e
```
Output:
`2.718281828459046`

## Asymptote

```real n, n1;
real e1, e;

n = 1.0;
n1 = 1.0;
e1 = 0.0;
e = 1.0;

while (e != e1){
e1 = e;
e += (1.0 / n);
n1 += 1;
n *= n1;
}
write("The value of e = ", e);
```
Output:
`The value of e = 2.71828182845905`

## AWK

```BEGIN {
for (e = n = rfact = 1; rfact >= 1e-15; rfact /= ++n)
e += rfact
printf "e = %.15f\n", e
}
```
Output:
`e = 2.718281828459046`

## BASIC

### BASIC256

```n = 1  : n1 = 1
e1 = 0 : e = 1 / 1

while e <> e1
e1 = e
e += 1 / n
n1 += 1
n *= n1
end while

print "The value of e = "; e
end```
Output:
`The value of e = 2.71828182829`

### BBC BASIC

```      @%=&1302
EPSILON = 1.0E-15
Fact    = 1
E       = 2.0
E0      = 0.0
N%      = 2
WHILE ABS(E - E0) >= EPSILON
E0    = E
Fact *= N%
N%   += 1
E    += 1.0 / Fact
ENDWHILE
PRINT "e = ";E
END
```
Output:
`e = 2.718281828459045226`

### Chipmunk Basic

Works with: Chipmunk Basic version 3.6.4
Works with: GW-BASIC
Translation of: QBasic
```10 CLS
20 N = 1 : N1 = 1
30 E1 = 0 : E = 1/1
40 WHILE E <> E1
50  E1 = E
60  E = E+1/N
70  N1 = N1+1
80  N = N*N1
90 WEND
100 PRINT "The value of E = " E
110 END
```
Output:
`The value of E = 2.718282`

### IS-BASIC

```100 PROGRAM "e.bas"
110 LET E1=0:LET E,N,N1=1
120 DO WHILE E<>E1
130   LET E1=E:LET E=E+1/N
140   LET N1=N1+1:LET N=N*N1
150 LOOP
160 PRINT "The value of e =";E```
Output:
`The value of e = 2.71828183`

### GW-BASIC

The Chipmunk Basic solution works without any changes.

### MSX Basic

The Commodore BASIC solution works without any changes.

### QBasic

Works with: QBasic version 1.1
Works with: QuickBasic version 4.5
```n = 1: n1 = 1

e! = 1 / 1

DO WHILE e <> e1
e1 = e
e = e + 1 / n
n1 = n1 + 1
n = n * n1
LOOP

PRINT "The value of e ="; e
```
Output:
`The value of e = 2.718282`

### True BASIC

Works with: QBasic
```LET n = 1
LET n1 = 1

LET e = 1 / 1

DO WHILE e <> e1
LET e1 = e
LET e = e + 1 / n
LET n1 = n1 + 1
LET n = n * n1
LOOP

PRINT "The value of e ="; e
END
```
Output:
`The value of e = 2.7182818`

### Run BASIC

Works with: Just BASIC
Works with: Liberty BASIC
```n = 1  : n1 = 1
e1 = 0 : e = 1 / 1

while e <> e1
e1 = e
e = e + 1 / n
n1 = n1 + 1
n = n * n1
wend

print "The value of e = "; e```
Output:
`The value of e = 2.71828`

### XBasic

Works with: Windows XBasic
```PROGRAM	"progname"
VERSION	"0.0000"

DECLARE FUNCTION  Entry ()

FUNCTION  Entry ()

DOUBLE e1
DOUBLE e
DOUBLE n

n = 1
n1 = 1
e1 = 0
e = 1 / 1

DO WHILE e != e1
e1 = e
e = e + 1 / n
n1 = n1 + 1
n = n * n1
LOOP

PRINT "The value of e = "; e

END FUNCTION
END PROGRAM```
Output:
`The value of e = 2.718281828459`

### Yabasic

Works with: QBasic
Works with: FreeBASIC version with #lang "qb"
```n = 1  : n1 = 1
e1 = 0 : e = 1 / 1

while e <> e1
e1 = e
e = e + 1 / n
n1 = n1 + 1
n = n * n1
wend

print "The value of e = ", e```
Output:
`The value of e = 2.71828`

## bc

```scale = 64
for (e = n = f = 1; f != 0; f /= ++n) e += f
e
```
Output:
`2.7182818284590452353602874713526624977572470936999595749669676254`

## Befunge

Befunge has no decimal capabilities, evaluates as fractions of 10^17

```52*92*1->01p:01g1-:v  v *_\$101p011p54*21p>:11g1+:01g*01p:11p/21g1-:v v    <
^          _\$\$>\:^               ^                      p12_\$>+\:#^_\$554**/@
```
Output:
`2718281828459045`

## BQN

```E←1+´1÷·×`1+↕
```
```   E 20
2.7182818284590455
```

## Burlesque

```blsq ) 70rz?!{10 100**\/./}ms36.+Sh'.1iash
2.7182818284590452353602874713526624977572470936999595749669676277240766303535475945713821785251664274```

## C

### solution 1

```#include <stdio.h>
#include <math.h>

int main(void)
{
double e;

puts("The double precision in C give about 15 significant digits.\n"
"Values below are presented with 16 digits after the decimal point.\n");

// The most direct way to compute Euler constant.
//
e = exp(1);
printf("Euler constant e = %.16lf\n", e);

// The fast and independed method: e = lim (1 + 1/n)**n
//
e = 1.0 + 0x1p-26;
for (int i = 0; i < 26; i++)
e *= e;
printf("Euler constant e = %.16lf\n", e);

// Taylor expansion e = 1 + 1/1 + 1/2 + 1/2/3 + 1/2/3/4 + 1/2/3/4/5 + ...
// Actually Kahan summation may improve the accuracy, but is not necessary.
//
const int N = 1000;
double a;
a = 1.0;
for (int i = 1; i < N; i++)
{
a[i] = a[i-1] / i;
}
e = 1.;
for (int i = N - 1; i > 0; i--)
e += a[i];
printf("Euler constant e = %.16lf\n", e);

return 0;
}
```
Output:
```The double precision in C give about 15 significant digits.
Values below are presented with 16 digits after the decimal point.

Euler constant e = 2.7182818284590451
Euler constant e = 2.7182818081824731
Euler constant e = 2.7182818284590455
```

### solution 2

Translation of: Kotlin
```#include <stdio.h>
#include <math.h>

#define EPSILON 1.0e-15

int main() {
unsigned long long fact = 1;
double e = 2.0, e0;
int n = 2;
do {
e0 = e;
fact *= n++;
e += 1.0 / fact;
}
while (fabs(e - e0) >= EPSILON);
printf("e = %.15f\n", e);
return 0;
}
```
Output:
```e = 2.718281828459046
```

## C#

```using System;

namespace CalculateE {
class Program {
public const double EPSILON = 1.0e-15;

static void Main(string[] args) {
ulong fact = 1;
double e = 2.0;
double e0;
uint n = 2;
do {
e0 = e;
fact *= n++;
e += 1.0 / fact;
} while (Math.Abs(e - e0) >= EPSILON);
Console.WriteLine("e = {0:F15}", e);
}
}
}
```
Output:
`e = 2.718281828459050`

### Using Decimal type

```using System;

class Calc_E
{

static Decimal CalcE()
{
Decimal f = 1, e = 2; int n = 1;
do e += (f = f / ++n); while (f > 1e-27M);
return e;
}

static void Main()
{
Console.WriteLine(Math.Exp(1)); // double precision built-in result
Console.WriteLine(CalcE());  // Decimal precision result
}
}
```
Output:
```2.71828182845905
2.7182818284590452353602874713```

### Arbitrary Precision

Automatically determines number of padding digits required for the arbitrary precision output. Can calculate a quarter million digits of e in under half a minute.

```using System; using System.Numerics;
using static System.Math; using static System.Console;

static class Program
{
static string CalcE(int nDigs)
{
int pad = (int)Round(Log10(nDigs)), n = 1;
BigInteger f = BigInteger.Pow(10, nDigs + pad), e = f + f;
do e += (f /= ++n); while (f > n);
return (e / BigInteger.Pow(10, pad + 1)).ToString().Insert(1, ".");
}

static void Main()
{
WriteLine(Exp(1));  //  double precision built-in function
WriteLine(CalcE(100));   //  arbitrary precision result
DateTime st = DateTime.Now; int qmil = 250_000;
string es = CalcE(qmil);  //  large arbitrary precision result string
WriteLine("{0:n0} digits in {1:n3} seconds.", qmil, (DateTime.Now - st).TotalSeconds);
WriteLine("partial: {0}...{1}", es.Substring(0, 46), es.Substring(es.Length - 45));
}
}
```
Output:
```2.71828182845905
2.718281828459045235360287471352662497757247093699959574966967627724076630353547594571382178525166427
250,000 digits in 22.833 seconds.
partial: 2.71828182845904523536028747135266249775724709...026587951482508371108187783411598287506586313
```

## C++

Translation of: C
```#include <iostream>
#include <iomanip>
#include <cmath>

using namespace std;

int main() {
const double EPSILON = 1.0e-15;
unsigned long long fact = 1;
double e = 2.0, e0;
int n = 2;
do {
e0 = e;
fact *= n++;
e += 1.0 / fact;
}
while (fabs(e - e0) >= EPSILON);
cout << "e = " << setprecision(16) << e << endl;
return 0;
}
```
Output:
```e = 2.718281828459046
```

## Clojure

```;; Calculating the number e, euler-napier number.
;; We will use two methods
;; First method: the forumula (1 + 1/n)^n
;; Second method: the series partial sum 1/(p!)

;;first method

(defn inverse-plus-1 [n]
(+ 1 (/ 1 n)))

(defn e-return [n]
(Math/pow (inverse-plus-1 n) n))

(time (e-return 100000.))

;;"Elapsed time: 0.165629 msecs"
;;2.7182682371922975

;;SECOND METHOD

(defn method-e [n]
(loop [e-aprx 0M
p  1M]
(if (> p n)
e-aprx

(time (with-precision 110 (method-e 200M)))
```
```"Elapsed time: 11.310568 msecs"
2.7182818284590452353602874713526624977572470936999595749669676277240766303535475945713821785251664274274663923M
```

## COBOL

Translation of: C
```       >>SOURCE FORMAT IS FIXED
IDENTIFICATION DIVISION.
PROGRAM-ID. EULER.
DATA DIVISION.
WORKING-STORAGE SECTION.
01 EPSILON USAGE COMPUTATIONAL-2 VALUE 1.0E-15.
01 FACT USAGE BINARY-DOUBLE UNSIGNED VALUE 1.
01 N USAGE BINARY-INT UNSIGNED.
01 E USAGE COMPUTATIONAL-2 VALUE 2.0.
01 E0 USAGE COMPUTATIONAL-2 value 0.0.
01 RESULT-MESSAGE.
03 FILLER PIC X(4) VALUE 'e = '.
03 RESULT-VALUE PIC 9.9(18) USAGE DISPLAY.
PROCEDURE DIVISION.
MAIN SECTION.
PERFORM
VARYING N FROM 2 BY 1
UNTIL FUNCTION ABS(E - E0) < EPSILON
MOVE E TO E0
COMPUTE FACT = FACT * N
COMPUTE E = E + 1.0 / FACT
END-PERFORM.
MOVE E TO RESULT-VALUE.
DISPLAY RESULT-MESSAGE.
STOP RUN.
```
Output:
```e = 2.718281828459041093
```

## Commodore BASIC

Commodore BASIC floats have a 40-bit mantissa, so we get max precision after just 11 iterations:

```100 REM COMPUTE E VIA INVERSE FACTORIAL SUM
110 N = 11:REM NUMBER OF ITERATIONS
120 E =  1:REM APPROXIMATE E HERE
130 F =  1:REM BUILD FACTORIAL HERE
140 FOR I = 1 TO N
150 : F = F*I
160 : E = E + 1/F
170 NEXT I
180 PRINT "AFTER" N "ITERATIONS, E =" E
```
Output:
```AFTER 11 ITERATIONS, E = 2.71828183

## Common Lisp

Common Lisp performs exact rational arithmetic, but printing those results out in decimal form is challenging; the built-in options require conversion to floating point values of relatively low precision. The QuickLisp module computable-reals makes printing out precise decimal representations easy, though:

```(ql:quickload :computable-reals :silent t)
(use-package :computable-reals)

(defparameter *iterations* 1000)

(let ((e 1) (f 1))
(loop for i from 1 to *iterations* doing
(setq f (* f i))
(setq e (+ e (/ 1 f))))
(format t "After ~a iterations, e = " *iterations*)
(print-r e 2570))
```
Output:
```After 1000 iterations, e =
+2.71828182845904523536028747135266249775724709369995957496696762772407663035354759457138217852516642742746639193200305992181741359662904357290033429526059563073813232862794349076323382988075319525101901157383418793070215408914993488416750924476146066808226480016847741185374234544243710753907774499206955170276183860626133138458300075204493382656029760673711320070932870912744374704723069697720931014169283681902551510865746377211125238978442505695369677078544996996794686445490598793163688923009879312773617821542499922957635148220826989519366803318252886939849646510582093923982948879332036250944311730123819706841614039701983767932068328237646480429531180232878250981945581530175671736133206981125099618188159304169035159888851934580727386673858942287922849989208680582574927961048419844436346324496848756023362482704197862320900216099023530436994184914631409343173814364054625315209618369088870701676839642437814059271456354906130310720851038375051011574770417189861068739696552126715468895703503540212340784981933432106817012100562788023519303322474501585390473041995777709350366041699732972508868769664035557071622684471625607988265178713419512466520103059212366771943252786753985589448969709640975459185695638023637016211204774272283648961342251644507818244235294863637214174023889344124796357437026375529444833799801612549227850925778256209262264832627793338656648162772516401910590049164499828931505660472580277863186415519565324425869829469593080191529872117255634754639644791014590409058629849679128740687050489585867174798546677575732056812884592054133405392200011378630094556068816674001698420558040336379537645203040243225661352783695117788386387443966253224985065499588623428189970773327617178392803494650143455889707194258639877275471096295374152111513683506275260232648472870392076431005958411661205452970302364725492966693811513732275364509888903136020572481765851180630364428123149655070475102544650117272115551948668508003685322818315219600373562527944951582841882947876108526398139559900673764829224437528718462457803619298197139914756448826260390338144182326251509748279877799643730899703888677822713836057729788241256119071766394650706330452795466185509666618566470971134447401607046262156807174818778443714369882185596709591025968620023537185887485696522000503117343920732113908032936344797273559552773490717837934216370120500545132638354400018632399149070547977805669785335804896690629511943247309958765523681285904138324116072260299833053537087613893963917795745401613722361878936526053815584158718692553860616477983402543512843961294603529133259...
```

## Craft Basic

```let n = 1
let m = 1
let f = 0
let e = 1

do

if e <> f then

let f = e
let e = e + 1 / n
let m = m + 1
let n = n * m

endif

loop e <> f

print "The value of e = ", e
```
Output:
`The value of e = 2.72`

## D

```import std.math;
import std.stdio;

enum EPSILON = 1.0e-15;

void main() {
ulong fact = 1;
double e = 2.0;
double e0;
int n = 2;
do {
e0 = e;
fact *= n++;
e += 1.0 / fact;
} while (abs(e - e0) >= EPSILON);
writefln("e = %.15f", e);
}
```
Output:
`e = 2.718281828459046`

## Dart

Translation of: C++
```void main() {
const double EPSILON = 1.0e-15;
double fact = 1;
double e = 2.0, e0;
int n = 2;
do {
e0 = e;
fact *= n++;
e += 1.0 / fact;
} while ((e-e0).abs() >= EPSILON);
print('The value of e = \$e');
}
```
Output:
`The value of e = 2.7182818284590455`

## dc

After 51 iterations the result is correct to 67 digits after the decimal, which gets as many digits as dc will display on a single line. After 1000 iterations the approximation is correct to 2,570 digits after the decimal. In each case you need to tell dc to (k)eep several digits past the target or else it will hit a plateau and stop improving before it reaches the desired precision.

Here's the 1000-iteration code, which keeps 2574 digits of precision to ensure that it gets the answer right to 2570 (and then only prints it out to 2570):

```1000 sn                 [ n = number of iterations ]sx
2574k                   [ precision to use during computation ]sx
1 d sf                  [ set e (kept on the stack) and f to 1 ]sx
[                       [ p = begin ]sx
lf li 1 + d si / d sf   [ f = f / ++i ]sx
+                       [ e = e + f ]sx
ln li <p                [ if i<n recur ]sx
]sp                     [ end ]sx

lpx                     [ call p ]sx

[After ]n lnn           [ output header. uses n + 10P for newline ]sx
[ iterations, e =]n     [ instead of p, so nothing is left hanging ]sx
10P                     [ around on the stack.]sx

2570k                   [ now reset precision to match correct digits ]sx
1 /                     [ get result truncated to that precision ]sx
n 10P                   [ and print it out, again with n + 10P ]sx```
Output:
```After 1000 iterations, e =
2.7182818284590452353602874713526624977572470936999595749669676277240\
766303535475945713821785251664274274663919320030599218174135966290435\
729003342952605956307381323286279434907632338298807531952510190115738\
341879307021540891499348841675092447614606680822648001684774118537423\
454424371075390777449920695517027618386062613313845830007520449338265\
602976067371132007093287091274437470472306969772093101416928368190255\
151086574637721112523897844250569536967707854499699679468644549059879\
316368892300987931277361782154249992295763514822082698951936680331825\
288693984964651058209392398294887933203625094431173012381970684161403\
970198376793206832823764648042953118023287825098194558153017567173613\
320698112509961818815930416903515988885193458072738667385894228792284\
998920868058257492796104841984443634632449684875602336248270419786232\
090021609902353043699418491463140934317381436405462531520961836908887\
070167683964243781405927145635490613031072085103837505101157477041718\
986106873969655212671546889570350354021234078498193343210681701210056\
278802351930332247450158539047304199577770935036604169973297250886876\
966403555707162268447162560798826517871341951246652010305921236677194\
325278675398558944896970964097545918569563802363701621120477427228364\
896134225164450781824423529486363721417402388934412479635743702637552\
944483379980161254922785092577825620926226483262779333865664816277251\
640191059004916449982893150566047258027786318641551956532442586982946\
959308019152987211725563475463964479101459040905862984967912874068705\
048958586717479854667757573205681288459205413340539220001137863009455\
606881667400169842055804033637953764520304024322566135278369511778838\
638744396625322498506549958862342818997077332761717839280349465014345\
588970719425863987727547109629537415211151368350627526023264847287039\
207643100595841166120545297030236472549296669381151373227536450988890\
313602057248176585118063036442812314965507047510254465011727211555194\
866850800368532281831521960037356252794495158284188294787610852639813\
955990067376482922443752871846245780361929819713991475644882626039033\
814418232625150974827987779964373089970388867782271383605772978824125\
611907176639465070633045279546618550966661856647097113444740160704626\
215680717481877844371436988218559670959102596862002353718588748569652\
200050311734392073211390803293634479727355955277349071783793421637012\
050054513263835440001863239914907054797780566978533580489669062951194\
324730995876552368128590413832411607226029983305353708761389396391779\
574540161372236187893652605381558415871869255386061647798340254351284\
3961294603529133259```

## Delphi

See Pascal

Hand-coded version:

Translation of: C
```program Calculating_the_value_of_e;

{\$APPTYPE CONSOLE}

{\$R *.res}

uses
System.SysUtils;

const
EPSILON = 1.0e-15;

function fAbs(value: Extended): Extended;
begin
Result := value;
if value < 0 then
Result := -Result;
end;

function e: Extended;
var
fact: UInt64;
e, e0: Extended;
n: Integer;
begin
fact := 1;
Result := 2.0;
n := 2;
repeat
e0 := Result;
fact := fact * n;
inc(n);
Result := Result + (1.0 / fact);
until (fAbs(Result - e0) < EPSILON);
end;

begin
writeln(format('e = %.15f', [e]));
end.
```
Output:
```e = 2,718281828459045
```

## Dyalect

Translation of: Swift
```func calculateE(epsilon = 1.0e-15) {
func abs(n) {
if n < 0 {
-n
} else {
n
}
}

var fact = 1
var e = 2.0
var e0 = 0.0
var n = 2

while true {
e0 = e
fact *= n
n += 1
e += 1.0 / Float(fact)

if abs(e - e0) < epsilon {
break
}
}

return e
}

print(calculateE())```
Output:
`2.71828182845905`

## EasyLang

```numfmt 5 0
fact = 1
n = 2
e = 2
while abs (e - e0) > 0.0001
e0 = e
fact = fact * n
n += 1
e += 1 / fact
.
print e
```

## EDSAC order code

### Simple arithmetic

The difficulty here is that the EDSAC was designed to hold real numbers in the range -1 <= x < 1 only. Subroutines were devised for floating-point arithmetic, but rather than get involved with those we'll cheat slightly by calculating e - 2 and printing the result with '2' in front. It will be seen that the answer is 3 out in the 10th decimal place.

```  [Calculate e]
[EDSAC program, Initial Orders 2]

[Library subroutine M3. Prints header and is then overwritten]
[Here, last character sets teleprinter to figures]
PFGKIFAFRDLFUFOFE@A6FG@E8FEZPF
@&*CALCULATION!OF!E@&#
..PZ  [blank tape, needed to mark end of header text]

[Library subroutine D6. Division, accurate, fast.
Closed, 36 locations, working positions 6D and 8D.
C(0D) := C(0D)/C(4D), where C(4D) <> 0, -1.]
T6DE25@U8DN8DA6DT6DH6DS6DN4DA4DYFG21@SDVDTDEFW1526D

[Library subroutine P1.
Prints a single positive number (without layout or round-off).
Prints number in 0D to n places of decimals, where
n is specified by 'P n F' pseudo-order after subroutine call.
Closed, 21 locations.]
GKA18@U17@S20@T5@H19@PFT5@VDUFOFFFSFL4FTDA5@A2FG6@EFU3FJFM1F
..PZ

[Main routine]
Must be even, because of double values at start.]
GK     [set @ (theta) for relative addresses]
 PF PF  [build sum 4*(1/3! + 1/4! + 1/5! + ...)]
 PF PF  [term in sum]
 PD PF  [2^-34, stop when term < this]
 PF     [divisor]
 IF     [1/2]
 QF     [1/16]
 @F     [carriage return]
 &F     [line feed]
 WF     [digit '2']
 MF     [full stop / decimal point]
 K4096F [teleprinter null]

LD     [shift, makes 1/8]
UD     [to 0D for subroutine D6]
T6@    [divisor := 1/8]
T#@    [sum := 0]

[loop, acc assumed to be 0 here]
U6@    [update divisor]
T4D    [to 4D for subroutine D6]
 A23@   [for subroutine return]
G56F   [call D6]
U2#@   [store as term]
T#@    [update sum]
S4#@   [test for convergence]
G36@   [jump out if so]
A4#@   [restore term after test]
R4F    [divide by 16]
TD     [to 0D for subroutine D6]
E19@   [loop back]

[here when converged]
 TF     [clear acc]
R1F    [shift to divide by 4]
A7@    [add 1/2, now have (e - 2)]
YF     [round]
TD     [to 0D for subroutine P1]
O11@   [print '2.']
O12@
 A44@   [for subroutine return]
G92F   [call P1 to print (e - 2)]
P10F   [10 decimals]
O9@    [print CR]
O10@   [print LF]
O13@   [null to flush print buffer]
ZF     [stop]
PF     [enter with accumulator = 0]```
Output:
```CALCULATION OF E
2.7182818282
```

### Multiword arithmetic

This version uses multiword arithmetic to output a lot more decimal places than the simple version.

The program calculates e as 1/0! + 1/1! + 1/2! + ..., stopping when 1/n! is too small to be distinguished from zero. There are two multiword variables, for 1/n! and the result respectively. The code leaves enough room for each variable to have 332 words.

For simplicity in printing the result, arithmetic is done in base 10^4. A larger base, e.g. 2^15, would give more decimals, but not as many as one might think. Moreover, the extra code required for printing would leave less room for the variables.

The program executes about 38 million orders (16 hours on the original EDSAC) and prints e to 1324 decimal places. Because of rounding errors, the last two places are wrong (should be 61, not 44).

```  [Calculate  e  by multilength variables.
EDSAC program, Initial Orders 2.

Subroutine to print 4-digit number in 0F.
6F >= 0 to print leading zeros, 6F < 0 to suppress them.
42 locations.]
T   56 K
GKA3FT36@T40@A6FE8@T1FA13@T40@T1FS2FL1FT39@H37@VFL2FA2FTFA40@E23@AFG27@
T1FT40@OFH38@CFTFT1FA39@A2FE36@T39@H26@VFL8FE16@EFI393FP2047DPFPF

[Division subroutine for positive 35-bit integers.
Input:  dividend at 4D, divisor at 6D
Output: remainder at 4D, quotient at 6D.
37 locations; working locations 0D, 8D.]
T   98 K

[Define multilength variables, to base 10^4 for simplicity in printing out.
Low address = low order digit.
Variable starting at 360 is result = 1/0! + 1/1! + 1/2! + 1/3! + ...
Variable starting at 692 is the term 1/n!]
T   54 K  [instruction to loader: store at 54, 55, ...]
P  360 F  [address of result in 54; referred to by code letter C]
P  692 F  [address of term in 55; referred to by code letter V]

T  135 K  [instruction to loader: store at 135, 136, ...]

[Constants]
   #      F  [figure shift]
   M      F  [(1) decimal point for printing
(2) subtracted from A order to make T order]
   @      F  [carriage return]
   &      F  [line feed]
   K 4096 F  [null character]
   P   12 F  [groups of 4 digits per line, as an address]
   P  332 F  [length of variable, as an address
(max is 332 at present, 2020-07-04)]
   P      D  
   W  904 F  [10000 = base for multibyte variables]
   A      C  [used to manufacture orders]
   A      V  [used to manufacture orders

Variables]
   A      C  ['A m C' order where m = length of result]
   A      V  ['A m V' order where m = length of term 1/n!]
   A      V  [divisor := 2, 3, 4, ... to get term 1/n!]

[Subroutine to set top word of multilength value and clear rest.
Input: 4F = A order for lowest value of multibyte
5F = value, assumed < base]
   A    3 F  [make and plant link for return]
T   32 @
A    4 F  [load A order]
S    1 @  [convert to T order]
U   24 @  [plant in code]
A    6 @  [make T order for top word]
S    2 F
T   31 @  [plant in code]
   T      F  [clear acc]
   T      F  [clear word in variable]
A   24 @  [load T order]
U   24 @  [store back]
S   31 @  [reached top word?]
G   23 @  [no, loop back]
A    5 F  [yes, load passed-in value]
   T      F  [store it]
   E      F  [return]

[Subroutine to set result := result + term, where term = 1/n!]
   A    3 F  [make and plant link for return]
T   66 @
T    1 F  [carry in 1F, initially := 0]
A    9 @  [load A order for start of result]
   U   44 @  [plant A order for result]
A   11 @  [make A order for term]
T   45 @  [plant A order for term]
A   44 @  [load A order for result]
S    1 @  [make T order for result]
U   50 @  [plant in code, 2 places]
T   56 @
   A      C  [load word from result]
   A      V  [add word from term]
A    1 F  [add carry from last time]
S    8 @  [is sum >= base?]
E   56 @  [yes, jump]
A    8 @  [no, restore sum after test]
   T      C  [store in result]
[No carry. If rest of term is all 0's we can finish.]
A   45 @  [load A order for term]
S   13 @  [beyond end of non-zero part?]
T      F  [no, clear acc]
[Here if there's a carry]
   T      C  [save word of result]
A    7 @  [load 1 for carry]
   T    1 F  [update carry for next time]
A   44 @  [load A order for result]
S   12 @  [reached end?]
A   12 @  [no, restore A order after test]
G   37 @  [loop back]
   T      F  [clear acc]
   E      F  [return]

[Subroutine to round term 1/n!
Increments low word of term by 1. Assume this doesn't increase the length.]
   A    3 F  [make and plant return link]
T   84 @
A   10 @  [load A order for start of term]
   U   74 @  [plant A order in code]
S    1 @  [convert to T order]
U   78 @  [plant T order, 2 places]
T   83 @
   A      V  [load word from term]
S    8 @  [carry needed?]
G   82 @  [no, store and exit]
   T      V  [yes, store dec'd word (must be 0)]
A   74 @  [load A order]
G   70 @  [loop back]
   A    8 @  [no carry, restore sum after test]
   T      V  [store in word of term]
   E      F  [exit]

[Subroutine to divide term 1/n! by the 17-bit positive number in location 0.
Called when n is incremented; location 0 contains new value of n.
Adjusts the value of endAV if necessary.]
   A    3 F  [make and plant return link]
T  130 @
T  131 @  [store locally]
A   13 @  [load A order for end of term]
T  102 @  [plant in code]
T    1 F  [carry in 1F, initially := 0]
[Start of loop]
   T      F  [clear acc]
A  102 @  [load A order for word in term]
S   10 @  [now beyond start?]
A   10 @  [no, restore order after test]
U  102 @  [plant in code]
S    1 @  [convert to T order]
T  115 @  [plant in code]
T    4 D  [clear 5F and sandwich bit]
   A      V  [load word from term]
T    4 F  [store as double in 4D]
T    6 D  [clear 7F and sandwich bit]
T    6 F  [store as double in 6D]
H    8 @  [multiplier register := base]
V    1 F  [acc := base*carry]
R    1 F  [shift 2 right]
A    4 D  [add word from term]
T    4 D  [to \$D as dividend]
A  112 @  [call division routine]
G   98 F
   T      V  [to word in term]
T    1 F  [to carry]
E   92 @  [loop for next]
[Done division, round quotient if necessary]
   T      F  [clear acc]
A    1 F  [load carry out of last digit]
L      D  [carry*2]
S  131 @  [subtract divisor]
G  127 @  [if carry < divisor/2, skip rounding]
T      F  [clear acc]
A  125 @  [call routine to inc low word of term by 1]
G   67 @
   T      F  [clear acc]
A  128 @  [call routine to adjust endAV]
G  132 @
   E      F  [exit with acc = 0]
   P      F  [divisor]

[Subroutine to update endAV, i.e. the A order for start of zero words in the term 1/n!
The address *before* endAV must be either (1) less than ordAV or (2) contain non-zero.]
   A    3 F  [make and plant return link]
T  148 @
[Start of loop. here acc = 0.]
   A   13 @  [load current endAV]
S    2 F  [tentative new value]
U  140 @  [plant in code]
S   10 @  [less than ordAV?]
G  147 @  [yes, done]
T      F  [no, clear acc]
   A      V  [load word in term]
S    7 @  [greater than 0?]
E  147 @  [yes, done]
T      F  [no, clear acc]
A  140 @  [update endAV to tentative value]
T   13 @
E  134 @  [loop back to test new value]
   T      F
   E      F

[Subroutine to print multibyte result with formatting.
Assumes top word (integer part) is <= 9; OK since integer part = 2 here.
Uses 5F for countdown of words on current line.]
   A    3 F  [make and plant return link]
T  183 @
A   12 @  [start at top end]
S    2 F  [point to top word]
U  156 @  [plant A order, 2 places]
T  176 @
T    5 F  [countdown := 0 to force newline]
   A      F  [load top word]
T      F  [to 0F for printing]
S    7 @  [acc := -1]
T    6 F  [make 6F < 0 to suppress leading 0's]
A  160 @
G   56 F
O    1 @  [print decimal point]
[Start of loop to print fractional part of result. Assumes acc = 0.]
   A  176 @  [load A order for result]
S    9 @  [now beyond start?]
G  182 @  [yes, exit]
A    9 @  [no, restore order after test]
T  176 @  [plant in code]
A    5 F  [load printing countdown]
S    2 F  [decrement]
E  175 @  [skip if not gone negative]
A    5 @  [reset print countdown]
O    2 @  [start new line]
O    3 @
   T    5 F
T      F  [to 0F for printing]
T    6 F  [print leading 0's]
A  179 @  [call subroutine to print 0F]
G   56 F    [(clears acc)]
E  163 @  [loop back]
   T      F  [exit with acc = 0]
   E      F

[Enter with acc = 0]
   O      @
A   10 @  [acc := A order for start of term 1/n!]
S    9 @  [subtract A order for start of result]
T   11 @  [store difference of addresses]
A    9 @  [A order for start of result]
A    6 @  [add length of result]
T   12 @  [store result]
A   10 @  [similarly for term]
A    6 @
T   13 @
A    9 @  [load A order for start of result]
T    4 F  [to 4F for subroutine]
T    5 F  [to 5F for subroutine]
A  198 @  [call subroutine to set result := 1]
G   15 @
A   10 @  [similarly term := 1]
T    4 F
A    7 @
U   14 @
T    5 F
A  205 @
G   15 @
   T      F
A  208 @  [result := result + term]
G   33 @
T      F
A   14 @  [inc n]
A    7 @
U   14 @
T      F  [also in 0F]
A  215 @  [divide term by n]
G   85 @
A   10 @
S   13 @
G  207 @
[Here 1/n! has been reduced to 0; time to stop]
T      F  [clear acc]
A  221 @  [call subroutine to print result]
G  149 @
O    4 @  [null to flush printer buffer]
Z      F  [stop]
E  184 Z  [define entry point]
P      F  [acc = 0 on entry]```
Output:
```2.
718281828459045235360287471352662497757247093699
959574966967627724076630353547594571382178525166
427427466391932003059921817413596629043572900334
295260595630738132328627943490763233829880753195
251019011573834187930702154089149934884167509244
761460668082264800168477411853742345442437107539
077744992069551702761838606261331384583000752044
933826560297606737113200709328709127443747047230
696977209310141692836819025515108657463772111252
389784425056953696770785449969967946864454905987
931636889230098793127736178215424999229576351482
208269895193668033182528869398496465105820939239
829488793320362509443117301238197068416140397019
837679320683282376464804295311802328782509819455
815301756717361332069811250996181881593041690351
598888519345807273866738589422879228499892086805
825749279610484198444363463244968487560233624827
041978623209002160990235304369941849146314093431
738143640546253152096183690888707016768396424378
140592714563549061303107208510383750510115747704
171898610687396965521267154688957035035402123407
849819334321068170121005627880235193033224745015
853904730419957777093503660416997329725088687696
640355570716226844716256079882651787134195124665
201030592123667719432527867539855894489697096409
754591856956380236370162112047742722836489613422
516445078182442352948636372141740238893441247963
5743702637552944483379980144
```

### Spigot algorithm

The EDSAC program to calculate pi by means of a spigot algorithm is easily modified to calculate e. It will then output 2070 correct digits of e (though it outputs only 252 correct digits of pi). Details will be found under the task "Pi".

```[Code not given, as it is almost the same as the EDSAC spigot algorithm for pi.
See the task "Pi" for the EDSAC program and the changes needed to calculate e.]```
Output:
```2718281828459045235360287471352662497757247093699959574966967627724076630353547594571382178525166427
4274663919320030599218174135966290435729003342952605956307381323286279434907632338298807531952510190
1157383418793070215408914993488416750924476146066808226480016847741185374234544243710753907774499206
9551702761838606261331384583000752044933826560297606737113200709328709127443747047230696977209310141
6928368190255151086574637721112523897844250569536967707854499699679468644549059879316368892300987931
2773617821542499922957635148220826989519366803318252886939849646510582093923982948879332036250944311
7301238197068416140397019837679320683282376464804295311802328782509819455815301756717361332069811250
9961818815930416903515988885193458072738667385894228792284998920868058257492796104841984443634632449
6848756023362482704197862320900216099023530436994184914631409343173814364054625315209618369088870701
6768396424378140592714563549061303107208510383750510115747704171898610687396965521267154688957035035
4021234078498193343210681701210056278802351930332247450158539047304199577770935036604169973297250886
8769664035557071622684471625607988265178713419512466520103059212366771943252786753985589448969709640
9754591856956380236370162112047742722836489613422516445078182442352948636372141740238893441247963574
3702637552944483379980161254922785092577825620926226483262779333865664816277251640191059004916449982
8931505660472580277863186415519565324425869829469593080191529872117255634754639644791014590409058629
8496791287406870504895858671747985466775757320568128845920541334053922000113786300945560688166740016
9842055804033637953764520304024322566135278369511778838638744396625322498506549958862342818997077332
7617178392803494650143455889707194258639877275471096295374152111513683506275260232648472870392076431
0059584116612054529703023647254929666938115137322753645098889031360205724817658511806303644281231496
5507047510254465011727211555194866850800368532281831521960037356252794495158284188294787610852639813
9559900673764829224437528718462457803619298197139914756448826260390338
```

## Emacs Lisp

```(defun factorial (i)
"Compute factorial of i."
(apply #'* (number-sequence 1 i)))

(defun compute-e (iter)
"Compute e."
(apply #'+ 1 (mapcar (lambda (x) (/ 1.0 x))
(mapcar #'factorial (number-sequence 1 iter)))))

(compute-e 20)
```
Output:
`2.7182818284590455`

## Epoxy

```fn CalculateE(P)
var E:1,F:1
loop I:1;I<=P;I+:1 do
F*:I
E+:1/F
cls
return E
cls

log(CalculateE(100))
log(math.e)```
Output:
```2.7182818284590455
2.718281828459045```

## Excel

### LAMBDA

Binding the name eApprox to the following lambda expression in the Name Manager of the Excel WorkBook:

```eApprox
=LAMBDA(n,
INDEX(
FOLDROW(
LAMBDA(efl,
LAMBDA(x,
LET(
flx, INDEX(efl, 2) * x,
e, INDEX(efl, 1),

CHOOSE(
{1;2},
e + (1 / flx),
flx
)
)
)
)
)({1;1})(
SEQUENCE(1, n)
),
1
)
)
```

and also assuming the following generic bindings in the Name Manager for the WorkBook:

```FOLDROW
=LAMBDA(op,
LAMBDA(a,
LAMBDA(xs,
LET(

IF(1 < COLUMNS(xs),
FOLDROW(op)(b)(
TAILROW(xs)
),
b
)
)
)
)
)

=LAMBDA(xs,
LET(REM, "The first item of each row in xs",

INDEX(
xs,
SEQUENCE(ROWS(xs)),
SEQUENCE(1, 1)
)
)
)

TAILROW
=LAMBDA(xs,
LET(REM,"The tail of each row in the grid",
n, COLUMNS(xs) - 1,

IF(0 < n,
INDEX(
xs,
SEQUENCE(ROWS(xs), 1, 1, 1),
SEQUENCE(1, n, 2, 1)
),
NA()
)
)
)
```
Output:

Within the finite precision of Excel floating point numbers (IEEE 754 doubles) the approximation converges with the built-in EXP(n) function at around the 16th iteration.

 =eApprox(A2) fx A B C 1 Iterations Approximation IEEE 754 difference 2 1 2 0.71828182845905 3 2 2.5 0.21828182845905 4 3 2.66666666666667 0.05161516179238 5 4 2.70833333333333 0.00994849512571 6 5 2.71666666666667 0.00161516179238 7 6 2.71805555555556 0.00022627290349 8 7 2.71825396825397 0.00002786020508 9 8 2.71827876984127 0.00000305861778 10 9 2.71828152557319 0.00000030288585 11 10 2.71828180114638 0.00000002731266 12 11 2.71828182619849 0.00000000226055 13 12 2.71828182828617 0.00000000017288 14 13 2.71828182844676 0.00000000001229 15 14 2.71828182845823 0.00000000000081 16 15 2.71828182845899 0.00000000000005 17 16 2.71828182845904 0

## F#

```// A function to generate the sequence 1/n!). Nigel Galloway: May 9th., 2018
let e = Seq.unfold(fun (n,g)->Some(n,(n/g,g+1N))) (1N,1N)
```

Which may be used:

```printfn "%.14f" (float (e |> Seq.take 20 |> Seq.sum))
```
Output:
```2.71828182845905
```

## Factor

Works with: Factor version 0.98
```USING: math math.factorials prettyprint sequences ;
IN: rosetta-code.calculate-e

CONSTANT: terms 20

terms <iota> [ n! recip ] map-sum >float .
```
Output:
```2.718281828459045
```

## FOCAL

Translation of: ZX Spectrum Basic
```1.1 S K=1; S E=0
1.2 F X=1,10; D 2
1.3 Q

2.1 S E=E+1/K
2.2 S K=K*X
2.3 T %2,X,%6.5,E,!```
Output:
```*G
=  1= 1.00000
=  2= 2.00000
=  3= 2.50000
=  4= 2.66667
=  5= 2.70833
=  6= 2.71667
=  7= 2.71806
=  8= 2.71825
=  9= 2.71828
= 10= 2.71828```

FOCAL always computes six significant digits at most, so it only takes a few iterations until e = 2.71828, the same value as the built-in exponential function:

```*T FEXP(1),!
= 2.71828```

## Forth

Algorithm e-spigot: compute the first n decimal digits of e (due to Stanley Rabinowitz and Stan Wagon):

1. Initialize: Let the first digit be 2 and initialize an array A of length n + 1 to (1, 1, 1, . . . , 1).

2. Repeat n − 1 times:

• Multiply by 10: Multiply each entry of A by 10.
• Take the fractional part: Starting from the right, reduce the ith entry of A modulo i + 1, carrying the quotient one place left.
• Output the next digit: The final quotient is the next digit of e.
```100 constant #digits
: int-array  create cells allot  does> swap cells + ;

#digits 1+ int-array e-digits[]

: init-e ( -- )
[ #digits 1+ ] literal 0 DO
1  i e-digits[]  !
LOOP
." = 2." ;

: .e  ( -- )
init-e
[ #digits 1- ] literal 0 DO
0  \ carry
0 #digits DO
i e-digits[] dup @  10 *  rot +  i 2 + /mod -rot  swap !
-1 +LOOP
0 .r
LOOP ;
```
Output:
```Gforth 0.7.3, Copyright (C) 1995-2008 Free Software Foundation, Inc.
Gforth comes with ABSOLUTELY NO WARRANTY; for details type `license'
Type `bye' to exit
.e = 2.718281828459045235360287471352662497757247093699959574966967627724076630353547594571382178525166427 ok
```

## Fortran

```Program eee
implicit none
integer, parameter  :: QP = selected_real_kind(16)
real(QP), parameter :: one = 1.0
real(QP)            :: ee

write(*,*) '    exp(1.) ', exp(1._QP)

ee = 1. +(one +(one +(one +(one +(one+ (one +(one +(one +(one +(one +(one &
+(one +(one +(one +(one +(one +(one +(one +(one +(one +(one)      &
/21.)/20.)/19.)/18.)/17.)/16.)/15.)/14.)/13.)/12.)/11.)/10.)/9.)  &
/8.)/7.)/6.)/5.)/4.)/3.)/2.)

write(*,*) ' polynomial ', ee

end Program eee
```
Output:
```     exp(1.)    2.71828182845904523543
polynomial    2.71828182845904523543
```

See Pascal

## FreeBASIC

### Normal basic

```' version 02-07-2018
' compile with: fbc -s console

Dim As Double e , e1
Dim As ULongInt n = 1, n1 = 1

e = 1 / 1

While e <> e1
e1 = e
e += 1 / n
n1 += 1
n *= n1
Wend

Print "The value of e ="; e

' empty keyboard buffer
While InKey <> "" : Wend
Print : Print "hit any key to end program"
Sleep
End```
Output:
`The value of e = 2.718281828459046`

### GMP version

Library: GMP
```' version 02-07-2018
' compile with: fbc -s console

#Include "gmp.bi"

Sub value_of_e(e As Mpf_ptr)

Dim As ULong n = 1
Dim As Mpf_ptr e1, temp
e1   = Allocate(Len(__mpf_struct)) : Mpf_init(e1)
temp = Allocate(Len(__mpf_struct)) : Mpf_init(temp)

Dim As Mpz_ptr fac
fac = Allocate(Len(__mpz_struct)) : Mpz_init_set_ui(fac, 1)

Mpf_set_ui(e, 1)     ' 1 / 0! = 1 / 1

While Mpf_cmp(e1, e) <> 0
Mpf_set(e1, e)
Mpf_set_z(temp, fac)
n+= 1
Mpz_mul_ui(fac, fac, n)
Mpf_ui_div(temp, 1, temp)
Wend

End Sub

' ------=< MAIN >=------

Dim As UInteger prec = 50  ' precision = 50 digits
Dim As ZString Ptr outtext = Callocate (prec + 10)
Mpf_set_default_prec(prec * 3.5)
Dim As Mpf_ptr e
e = Allocate(Len(__mpf_struct)) : Mpf_init(e)
value_of_e(e)

Gmp_sprintf(outtext,"%.*Ff", prec, e)

Print "The value of e = "; *outtext

' empty keyboard buffer
While Inkey <> "" : Wend
Print : Print "hit any key to end program"
Sleep
End```
Output:
`The value of e = 2.71828182845904523536028747135266249775724709369996`

## Furor

```###sysinclude math.uh
1.0e-15 sto EPSILON
one fact
2. sto e
2  sto n
((
@e sto e0
#g @n++ prd fact
1.0 @fact !(#d) / sum e
( @e @e0 - abs @EPSILON < )))
."e = " @e printnl
end
{ „EPSILON” }
{ „fact” }
{ „e” }
{ „e0” }
{ „n” }```
Output:
```e = +2.71828182845905
```

## Peri

```###sysinclude standard.uh
###sysinclude math.uh
1.0e-15 sto EPSILON
one fact
2. sto en
2  sto nn
ciklus:
@en sto e0
#g @nn++ prd fact
1.0 @fact !(#d) / sum en
@en @e0 - abs @EPSILON < else §ciklus
."e = " @en printnl
end
{ „EPSILON” }
{ „fact” }
{ „en” }
{ „e0” }
{ „nn” }```
Output:
```e = +2.71828182845905
```

## FutureBasic

```local fn EulerConstant_e as double
UInt64  n = 1, n1 = 1
double  e1 = 0, e = 1 / 1

while ( e <> e1 )
e1 = e
e  = e + 1 / n
n1 = n1 + 1
n  = n * n1
wend
end fn = e

window 1

print "Euler constant e = "; fn EulerConstant_e

HandleEvents```
Output:
```Euler constant e = 2.718281828459046
```

## Fōrmulæ

Fōrmulæ programs are not textual, visualization/edition of programs is done showing/manipulating structures but not text. Moreover, there can be multiple visual representations of the same program. Even though it is possible to have textual representation —i.e. XML, JSON— they are intended for storage and transfer purposes more than visualization and edition.

Programs in Fōrmulæ are created/edited online in its website.

In this page you can see and run the program(s) related to this task and their results. You can also change either the programs or the parameters they are called with, for experimentation, but remember that these programs were created with the main purpose of showing a clear solution of the task, and they generally lack any kind of validation.

Solution 1. In Fōrmulæ, the Euler's number can be directly calculated within an arbitrary given precision.

Solution 2. Using series

Solution 3. Using a program

## Go

Translation of: Kotlin
```package main

import (
"fmt"
"math"
)

const epsilon = 1.0e-15

func main() {
fact := uint64(1)
e := 2.0
n := uint64(2)
for {
e0 := e
fact *= n
n++
e += 1.0 / float64(fact)
if math.Abs(e - e0) < epsilon {
break
}
}
fmt.Printf("e = %.15f\n", e)
}
```
Output:
```e = 2.718281828459046
```

## Groovy

Solution:
If the difference between previous and next iteration is less than the tolerance (ε) we judge that the sequence of partial sums has converged "enough".

Since the difference between partial sums is always the "last" term, it suffices to ensure that the "last" term is less than the tolerance.

```def ε = 1.0e-15
def φ = 1/ε

def n = 0.0
def fact = 1.0
while (true) {
fact *= (n < 2 ? 1.0 : n) as double
if (fact > φ) break // any further addends would not pass the tolerance test
n++
}
}

```

Test:

```printf "%17.15f\n%17.15f\n", e, Math.E
```

Output:

```2.718281828459045
2.718281828459045```

For the purposes of 64 bit floating point precision, the value seems to stabilise after summing c. 17-20 terms.

```------ APPROXIMATION OF E OBTAINED AFTER N ITERATIONS ----

eApprox :: Int -> Double
eApprox n =
(sum . take n) \$ (1 /) <\$> scanl (*) 1 [1 ..]

--------------------------- TEST -------------------------
main :: IO ()
main = print \$ eApprox 20
```
Output:
`2.7182818284590455`

Or equivalently, in a single fold:

```------ APPROXIMATION OF E OBTAINED AFTER N ITERATIONS ----

eApprox n =
snd \$
foldr
( \x (fl, e) ->
(,) <*> (e +) . (1 /) \$ fl * x
)
(1, 1)
[n, pred n .. 1]

--------------------------- TEST -------------------------
main :: IO ()
main = print \$ eApprox 20
```
Output:
`2.7182818284590455`

Or in terms of iterate:

```{-# LANGUAGE TupleSections #-}

------------------- APPROXIMATIONS TO E ------------------

approximatEs :: [Double]
approximatEs =
fst
<\$> iterate
( \(e, (i, n)) ->
(,) . (e +) . (1 /) <*> (succ i,) \$ i * n
)
(1, (1, 1))

--------------------------- TEST -------------------------
main :: IO ()
main = print \$ approximatEs !! 17
```
Output:
`2.7182818284590455`

## Hoon

```:-  %say
|=  *
:-  %noun
=/  i  .~2
=/  e  .~1
=/  e0  .~0
=/  denom  .~1
|-
?:  (lth:rd (sub:rd e e0) .~1e-15)
e
%=  \$
e      (add:rd e (div:rd .~1 denom))
e0     e
denom  (mul:rd denom i)
==```

## Icon and Unicon

Translation of: C

For Icon, the EPSILON preprocessor constant would need to be an inline constant where tested, or set in a variable.

```\$define EPSILON 1.0e-15

procedure main()
local e0
local e := 2.0
local fact := 1
local n := 2

repeat {
e0 := e
fact *:= n
n +:= 1
e +:= (1.0 / fact)
if abs(e - e0) < EPSILON then break
}
write("computed e ", e)
write("keyword &e ", &e)
end
```
Output:
```prompt\$ unicon -s euler.icn -x
computed e 2.718281828459046
keyword &e 2.718281828459045```

## J

Perhaps too brief:

```    0j100": +/%!i.100x
2.7182818284590452353602874713526624977572470936999595749669676277240766303535475945713821785251664274
```

The j language has expressive notations for numbers. Examples:

```   NB. rational one half times pi to the first power
NB. pi to the power of negative two
NB. two oh in base 111
NB. complex number length 1, angle in degrees 180
1.5708 0.101321 222 0j_1
```

And in j we can write

```   1x1  NB. 1 times e^1
2.71828
```

This is a floating point value (and, thus, accurate to 16 decimal places (15 places after the decimal point, in this example)).

The unary power verb ^ uses Euler's number as the base, hence

```   ^ 1
2.71828
```

If we need higher accuracy, we can use an approximation expressed as a rational number. To compute e: find the sum as insert plus +/ of the reciprocals % of factorials ! of integers i. . Using x to denote extended precision integers j will give long precision decimal expansions of rational numbers. Format ": several expansions to verify the number of valid digits to the expansion. Let's try for arbitrary digits.

```   NB. approximation to e as a rational number
NB. note the "r" separating numerator from denominator
+/ % ! i. x: 20
82666416490601r30411275102208

NB. 31 places shown with 20 terms
0j30 ": +/ % ! i. x: 20
2.718281828459045234928752728335

NB. 40 terms
0j30 ": +/ % ! i. x: 40
2.718281828459045235360287471353

NB. 50 terms,
0j30 ": +/ % ! i. x: 50
2.718281828459045235360287471353

NB. verb to compute e as a rational number
e =: [: +/ [: % [: ! [: i. x:

NB. format for e to so many places
places =: >: j. <:

NB. verb f computes e for y terms  and formats it in x decimal places
f =: (":~ places)~ e

While =: conjunction def 'u^:(0~:v)^:_'

NB. return number of terms and the corresponding decimal representation
e_places =: ({: , {.)@:(((f n) ; {.@:] , <@:(>:@:n@:]))While([: ~:/ 2 {. ]) '0' ; '1'&;)&1

e_places 1
┌─┬──┐
│5│ 3│
└─┴──┘

e_places 4
┌─┬─────┐
│9│2.718│
└─┴─────┘

e_places 40
┌──┬─────────────────────────────────────────┐
│37│2.718281828459045235360287471352662497757│
└──┴─────────────────────────────────────────┘

```

## Java

If you wanted to do this with the basic, bounded, primitive data-types, you could use the following implementation.

```double e(long limit) {
double e = 1;
for (long term = 1; term <= limit; term++)
e += 1d / factorial(term);
return e;
}

long factorial(long value) {
return value == 1 ? value : value * factorial(--value);
}
```

Here is an execution with 65 terms.

```2.7182818284590455
```

Alternately, this can be done using the `BigDecimal` and `BigInteger` classes.
Each which offer the ability to compute values beyond the constraints of both `double` and `long`, respectively.

I used a rounding-mode of "half-up", which rounds at 0.5 to 1, and at -0.5 to -1.

You can set the scale with the scale argument, which will ultimately be the `int` maximum, which is 2,147,483,647.

```import static java.math.RoundingMode.HALF_UP;
import java.math.BigDecimal;
import java.math.BigInteger;
```
```BigDecimal e(BigInteger limit, int scale) {
BigDecimal e = BigDecimal.ONE.setScale(scale, HALF_UP);
BigDecimal n;
BigInteger term = BigInteger.ONE;
while (term.compareTo(limit) <= 0) {
n = new BigDecimal(String.valueOf(factorial(term)));
}
return e;
}

BigInteger factorial(BigInteger value) {
if (value.compareTo(BigInteger.ONE) > 0) {
return value.multiply(factorial(value.subtract(BigInteger.ONE)));
} else {
return BigInteger.ONE;
}
}
```

Here is a execution using 100 terms, and a scale of 1000.

```BigDecimal e = e(BigInteger.valueOf(100), 1000);
```
```2.718281828459045235360287471352662497757247093699959574966967627724076630353547
59457138217852516642742746639193200305992181741359662904357290033429526059563073
80251882050351967424723324653614466387706813388353430034139974174573454428990064
20505625641288373144866257181218169558839675319515277938384101062576645231282166
05239098395155129969477630231658550707025356578811143735087981194929233692894922
18803532415232263419815664514069500471960037083157525314472746953376422185585970
49072791947918398790373277485203358571021151276932683987895240761723360600431495
39142130255178704446106587993897518897018555141736300685184133175671746042499671
27787770519325213151660446607713922514023318509164691235154486907393983388487303
71051660145947922319807187020285702323658476026591320639392924337656895542820166
62247170847987607703419588398315167187799994627689255589861192622972941592318112
80945595959314875046163012079992544503657235607075679104723168137049185311508243
129582873013636538450324418025276976013009
```

Or, you could use the following implementation.

Translation of: Kotlin
```public class CalculateE {
public static final double EPSILON = 1.0e-15;

public static void main(String[] args) {
long fact = 1;
double e = 2.0;
int n = 2;
double e0;
do {
e0 = e;
fact *= n++;
e += 1.0 / fact;
} while (Math.abs(e - e0) >= EPSILON);
System.out.printf("e = %.15f\n", e);
}
}
```
Output:
`e = 2.718281828459046`

## JavaScript

Summing over a scan

```(() => {
"use strict";

// - APPROXIMATION OF E OBTAINED AFTER N ITERATIONS --

// eApprox : Int -> Float
const eApprox = n =>
sum(
scanl(mul)(1)(
enumFromTo(1)(n)
)
.map(x => 1 / x)
);

// ---------------------- TEST -----------------------
const main = () =>
eApprox(20);

// ---------------- GENERIC FUNCTIONS ----------------

// enumFromTo :: Int -> Int -> [Int]
const enumFromTo = m =>
n => Array.from({
length: 1 + n - m
}, (_, i) => m + i);

// mul (*) :: Num a => a -> a -> a
const mul = a =>
// The arithmetic product of a and b.
b => a * b;

// scanl :: (b -> a -> b) -> b -> [a] -> [b]
const scanl = f => startValue => xs =>
// The series of interim values arising
// from a catamorphism. Parallel to foldl.
xs.reduce((a, x) => {
const v = f(a)(x);

return [v, a.concat(v)];
}, [startValue, [startValue]]);

// sum :: [Num] -> Num
const sum = xs =>
// The numeric sum of all values in xs.
xs.reduce((a, x) => a + x, 0);

// MAIN ---
return main();
})();
```
`2.7182818284590455`

Or as a single fold/reduce:

```(() => {
"use strict";

// --------------- APPROXIMATION OF E ----------------

const eApprox = n =>
// Approximation of E obtained after Nth iteration.
enumFromTo(1)(n).reduce(
([fl, e], x) => (
flx => [flx, e + (1 / flx)]
)(
fl * x
),
[1, 1]
);

// ---------------------- TEST -----------------------
// main :: IO ()
const main = () =>
eApprox(20);

// --------------------- GENERIC ---------------------

// enumFromTo :: Int -> Int -> [Int]
const enumFromTo = m =>
n => Array.from({
length: 1 + n - m
}, (_, i) => m + i);

// MAIN ---
return main();
})();
```
Output:
`2.7182818284590455`

## Joy

`1 dup 2 52 pow dup [/ +] dip pow.`
Output:
`2.71828`

## jq

```1|exp  #=> 2.718281828459045
```
```def e:
[null,0,1,1]
| until(. == .; .=. | .+=1/. | . *= . | .+=1)
| .;
e  #=> 2.7182818284590455
```

## Julia

Works with: Julia version 0.6

Module:

```module NeperConstant

export NeperConst

struct NeperConst{T}
val::T
end

Base.show(io::IO, nc::NeperConst{T}) where T = print(io, "ℯ (", T, ") = ", nc.val)

function NeperConst{T}() where T
local e::T  = 2.0
local e2::T = 1.0
local den::(T ≡ BigFloat ? BigInt : Int128) = 1
local n::typeof(den) = 2
while e ≠ e2
e2 = e
den *= n
n += one(n)
e += 1.0 / den
end
return NeperConst{T}(e)
end

end  # module NeperConstant
```

Main:

```for F in (Float16, Float32, Float64, BigFloat)
println(NeperConst{F}())
end
```
Output:
```(Float16) 2.717
(Float32) 2.718282
(Float64) 2.7182818284590455
(BigFloat) 2.718281828459045235360287471352662497757247093699959574966967627724076630353416```

## K

```/ Computing value of e
/ ecomp.k
\p 17
fact: {*/1+!:x}
evalue:{1 +/(1.0%)'fact' 1+!20}
evalue[]
```
Output:
```  \l ecomp
2.7182818284590455
```

## Klingphix

```%e0 %e %n %fact %v

0 !e0 2 !e 0 !n 1 !fact
1e-15 !v

:printOp swap print print nl ;
:test \$e \$e0 - abs \$v >= ;

[\$e !e0
\$n 1 + !n
2 \$n * 2 \$n * 1 + * \$fact * !fact
2 \$n * 2 + \$fact / \$e + !e]
[test]
while

%rE
2.718281828459045 !rE

"Computed e = " \$e tostr printOp
"Real e = " \$rE tostr printOp
"Error = " \$rE \$e sub printOp
"Number of iterations = " \$n printOp

" " input
```

## Kotlin

```// Version 1.2.40

import kotlin.math.abs

const val EPSILON = 1.0e-15

fun main(args: Array<String>) {
var fact = 1L
var e = 2.0
var n = 2
do {
val e0 = e
fact *= n++
e += 1.0 / fact
}
while (abs(e - e0) >= EPSILON)
println("e = %.15f".format(e))
}
```
Output:
```e = 2.718281828459046
```

This can also be done in a functional style. Empirically, 17 iterations are enough to get the maximum precision for 64-bit floating-point numbers. Also, for best results, we should sum smaller values before larger values; otherwise we can lose precision when adding a small value to a large value. The `asReversed()` call below is optional but highly recommended. The result of the calculation is identical to the standard library constant.

```fun main() {
val e = (1..17).runningFold(1L, Long::times)
.asReversed()  // summing smaller values first improves accuracy
.sumOf { 1.0 / it }
println(e)
println(e == kotlin.math.E)
}
```
Output:
```2.718281828459045
true
```

## Lambdatalk

```1) straightforward

{+ 1 {S.map {lambda {:n} {/ 1 {* {S.serie 1 :n}}}} {S.serie 1 17}}}
-> 2.7182818284590455

which is the value given by javascript : 2.718281828459045.

2) using recursion

{def fac
{lambda {:a :b}
{if {< :b 1}
then :a
else {fac {* :a :b} {- :b 1}}}}}
-> fac

{def euler
{lambda {:a :b}
{if {< :b 1}
then :a
else {euler {+ :a {/ 1 {fac 1 :b}}} {- :b 1}}}}}
-> euler

{euler 1 17}
-> 2.7182818284590455
```

## langur

Translation of: Go
```mode divMaxScale = 104

val .epsilon = 1.0e-104

var .e = 2

for .fact, .n = 1, 2 ; ; .n += 1 {
val .e0 = .e
.fact x= .n
.e += 1 / .fact
if abs(.e - .e0) < .epsilon: break
}

writeln ".e = ", .e

# compare to built-in constant e
writeln " e = ", e```
Output:

The result depends on the .epsilon value and the divMaxScale mode. Set to 15, this would give the same result as the Go example.

```.e = 2.71828182845904523536028747135266249775724709369995957496696762772407663035354759457138217852516642742747
e = 2.71828182845904523536028747135266249775724709369995957496696762772407663035354759457138217852516642742746
```

## Lua

```EPSILON = 1.0e-15;

fact = 1
e = 2.0
e0 = 0.0
n = 2

repeat
e0 = e
fact = fact * n
n = n + 1
e = e + 1.0 / fact
until (math.abs(e - e0) < EPSILON)

io.write(string.format("e = %.15f\n", e))
```
Output:
`e = 2.718281828459046`

## M2000 Interpreter

Using @ for Decimal, and ~ for Float, # for Currency (Double is the default type for M2000)

```Module FindE {
Function comp_e (n){
\\ max 28 for decimal (in one line with less spaces)
n/=28:For i=27to 1:n=1+n/i:Next i:=n
}
Clipboard Str\$(comp_e(1@),"")+" Decimal"+{
}+Str\$(comp_e(1),"")+" Double"+{
}+Str\$(comp_e(1~),"")+" Float"+{
}+Str\$(comp_e(1#),"")+" Currency"+{
}
Report Str\$(comp_e(1@),"")+" Decimal"+{
}+Str\$(comp_e(1),"")+" Double"+{
}+Str\$(comp_e(1~),"")+" Float"+{
}+Str\$(comp_e(1#),"")+" Currency"+{
}
}
FindE```
Output:
```2.7182818284590452353602874712 Decimal
2.71828182845905 Double
2.718282 Float
2.7183 Currency
```

As a lambda function (also we use a faster For, using block {})

`      comp_e=lambda (n)->{n/=28:For i=27to 1 {n=1+n/i}:=n}`

## Maple

```evalf(add(1/n!,n=0..100));
# 2.7182818284590452353602874713526624977572470937000

evalf(exp(1));
# 2.7182818284590452353602874713526624977572470937000```

With continued fractions:

```with(NumberTheory):
e:=ContinuedFraction(exp(1)):
Convergent(e,100);
evalf(%);

# 13823891428306770374331665289458907890372191037173036666131/5085525453460186301777867529962655859538011626631066055111
# 2.7182818284590452353602874713526624977572470937000```

## Mathematica/Wolfram Language

```1+Fold[1.+#1/#2&,1,Range[10,2,-1]]
```
Output:
```2.7182818261984928652
```
```Sum[1/x!, {x, 0, ∞}]
```
```Limit[(1+1/x)^x,x->∞]
```
```Exp
```

or even just

```𝕖
```
input as
```≡ee≡
```
Output:
`𝕖`

## Maxima

Using the expansion of an associated continued fraction

```block(cfexpand([2,1,2,1,1,4,1,1,6,1,1,8,1,1,10,1,1,12,1,1,14]),float(%%[1,1]/%%[2,1]));

/* Comparing with built-in constant */
%e,numer;
```
Output:
```2.718281828459045

2.718281828459045
```

## min

Works with: min version 0.37.0
```1 0
(dup 16 >) 'pop (succ over over / swap) '+ linrec
puts!```
Output:
`2.718281828459045`

## МК-61/52

```П0	П1	0	П2	1	П2	1	П3
ИП3	ИП2	ИП1	ИП0	-	1	+	*	П2	1/x	+	П3
ИП0	x#0	25	L0	08	ИП3	С/П```

At n = 10, the value is 2.7182819.

## Modula-2

```MODULE CalculateE;
FROM RealStr IMPORT RealToStr;

CONST EPSILON = 1.0E-15;

PROCEDURE abs(n : REAL) : REAL;
BEGIN
IF n < 0.0 THEN
RETURN -n
END;
RETURN n
END abs;

VAR
buf : ARRAY[0..31] OF CHAR;
fact,n : LONGCARD;
e,e0 : LONGREAL;
BEGIN
fact := 1;
e := 2.0;
n := 2;

REPEAT
e0 := e;
fact := fact * n;
INC(n);
e := e + 1.0 / LFLOAT(fact)
UNTIL abs(e - e0) < EPSILON;

WriteString("e = ");
RealToStr(e, buf);
WriteString(buf);
WriteLn;

END CalculateE.
```

## Myrddin

```use std

const main = {
var f: uint64 = 1
var e: flt64 = 2.0
var e0: flt64 = 0.0
var n = 2

while e > e0
e0 = e
f *= n
e += 1.0 / (f : flt64)
n++
;;
std.put("e: {}\n", e)
}```

## Nanoquery

Translation of: Python
```e0 = 0
e = 2
n = 0
fact = 1
while (e - e0) > 10^-15
e0 = e
n += 1
fact *= 2*n*((2*n)+1)
e += ((2.0*n)+2)/fact
end

println "Computed e = " + e
println "Number of iterations = " + n```
Output:
```Computed e = 2.7182818284590452349287527283351994002986043726966476833155148405875077310383076614195442493493357765
Number of iterations = 9
```

## Nim

```const epsilon : float64 = 1.0e-15
var fact : int64 = 1
var e : float64 = 2.0
var e0 : float64 = 0.0
var n : int64 = 2

while abs(e - e0) >= epsilon:
e0 = e
fact = fact * n
inc(n)
e = e + 1.0 / fact.float64

echo e
```

## OCaml

```let n = 0x1p52

let e = (1. /. n +. 1.) ** n

let () = Printf.printf "%.15f (%B)\n" e (exp(1.) = e)
```
Output:
`2.718281828459045 (true)`

## Pascal

Like delphi and many other.Slightly modified to calculate (1/n!) not n! and then divide to (1/n!)

```program Calculating_the_value_of_e;
{\$IFDEF FPC}
{\$MODE DELPHI}
{\$ENDIF}

{\$IFDEF WINDOWS}
{\$APPTYPE CONSOLE}
{\$ENDIF}
uses
SysUtils;

const
EPSILON = 1.0e-14;

function Get_E: Extended;
var
recfact: Extended;
n: Integer;
begin
recfact := 1.0;
Result := 2.0;
n := 2;
repeat
recfact /= n;
inc(n);
Result := Result + recfact;
until (recfact < EPSILON);
end;

begin
writeln(format('calc e = %.15f intern e= %.15f', [Get_E,exp(1.0)]));
end.
```
Output:
`calc e = 2.718281828459045 intern e= 2.718281828459045`

## Perl

With the `bignum` core module in force, Brother's algorithm requires only 18 iterations to match the precision of the built-in value, `e`.

```use bignum qw(e);

\$e = 2;
\$f = 1;
do {
\$e0 = \$e;
\$n++;
\$f *= 2*\$n * (1 + 2*\$n);
\$e += (2*\$n + 2) / \$f;
} until (\$e-\$e0) < 1.0e-39;

print "Computed " . substr(\$e, 0, 41), "\n";
print "Built-in " . e, "\n";
```
Output:
```Computed 2.718281828459045235360287471352662497757
Built-in 2.718281828459045235360287471352662497757```

To calculate 𝑒 to an arbitrary precision, enable the `bigrat` core module evaluate the Taylor series as a rational number, then use `Math::Decimal` do to the 'long division' with the large integers. Here, 71 terms of the Taylor series yield 𝑒 to 101 digits.

```use bigrat;
use Math::Decimal qw(dec_canonise dec_mul dec_rndiv_and_rem);

sub factorial { my \$n = 1; \$n *= \$_ for 1..shift; \$n }

for \$n (0..70) {
\$sum += 1/factorial(\$n);
}

(\$num,\$den) = \$sum =~ m#(\d+)/(\d+)#;
print "numerator:   \$num\n";
print "denominator: \$den\n";

\$num_dec = dec_canonise(\$num);
\$den_dec = dec_canonise(\$den);
\$ten     = dec_canonise("10");

(\$q, \$r) = dec_rndiv_and_rem("FLR", \$num_dec, \$den_dec);
\$e = "\$q.";
for (1..100) {
\$num_dec = dec_mul(\$r, \$ten);
(\$q, \$r) = dec_rndiv_and_rem("FLR", \$num_dec, \$den_dec);
\$e .= \$q;
}

printf "\n%s\n", subset \$e, 0,102;
```
Output:
```numerator:   32561133701373476427912330475884581607687531065877567210421813247164172713574202714721554378508046501
denominator: 11978571669969891796072783721689098736458938142546425857555362864628009582789845319680000000000000000

2.7182818284590452353602874713526624977572470936999595749669676277240766303535475945713821785251664274```

## Phix

Translation of: Python
```with javascript_semantics
requires("1.0.2") -- (builtin constant E renamed as EULER)
atom e0 = 0, e = 2, n = 0, fact = 1
while abs(e-e0)>=1e-15 do
e0 = e
n += 1
fact *= 2*n*(2*n+1)
e += (2*n+2)/fact
end while
printf(1,"Computed e = %.15f\n",e)
printf(1,"    Real e = %.15f\n",EULER)
printf(1,"     Error = %g\n",EULER-e)
printf(1,"Number of iterations = %d\n",n)
```
Output:
```Computed e = 2.718281828459045
Real e = 2.718281828459045
Error = 4.4409e-16
Number of iterations = 9
```

## Phixmonti

Translation of: Python
```0 var e0 2 var e 0 var n 1 var fact
1e-15 var v

def printOp
swap print print nl
enddef

def test e e0 - abs v >= enddef

test
while
e var e0
n 1 + var n
2 n * 2 n * 1 + * fact * var fact
2 n * 2 + fact / e + var e
test
endwhile

2.718281828459045 var rE

"Computed e = " e tostr printOp
"Real e = " rE tostr printOp
"Error = " rE e - printOp
"Number of iterations = " n printOp```
Output:
```Computed e = 2.718281828459045
Real e = 2.718281828459045
Error = 4.4409e-16
Number of iterations = 9
```

## PicoLisp

```(scl 15)
(let (F 1  E 2.0  E0 0  N 2)
(while (> E E0)
(setq E0 E  F (* F N))
(inc 'E (*/ 1.0 F))
(inc 'N) )
(prinl "e = " (format E *Scl)) )```
Output:
`e = 2.718281828459046`

## PowerShell

Translation of: Python
```\$e0 = 0
\$e = 2
\$n = 0
\$fact = 1
while([Math]::abs(\$e-\$e0) -gt 1E-15){
\$e0 = \$e
\$n += 1
\$fact *= 2*\$n*(2*\$n+1)
\$e += (2*\$n+2)/\$fact
}

Write-Host "Computed e = \$e"
Write-Host "    Real e = \$([Math]::Exp(1))"
Write-Host "     Error = \$([Math]::Exp(1) - \$e)"
Write-Host "Number of iterations = \$n"
```
Output:
```Computed e = 2.71828182845904
Real e = 2.71828182845905
Error = 4.44089209850063E-16
Number of iterations = 9```

## Processing

Updated to show that computed value matches library value after 21 iterations.

```void setup() {
double e = 0;
long factorial = 1;
int iterations = 11;
for (int i = 0; i < iterations; i++) {
e += (double) (2 * i + 1) / factorial;
factorial *= (2 * i + 1) * (2 * i + 2);
}
println("After " + iterations + " iterations");
println("Computed value: " + e);
println("Real value: " + Math.E);
println("Error: " + (e - Math.E));

iterations = 21;
for (int i = 11; i < iterations; i++) {
e += (double) (2 * i + 1) / factorial;
factorial *= (2 * i + 1) * (2 * i + 2);
}
println("After " + iterations + " iterations");
println("Computed value: " + e);
println("Real value: " + Math.E);
println("Error: " + (e - Math.E));
}
```
Output:
```After 11 iterations
Computed value: 2.7182818284590455
Real value: 2.718281828459045
Error: 4.440892098500626E-16
After 21 iterations
Computed value: 2.718281828459045
Real value: 2.718281828459045
Error: 0.0
```

## Prolog

### Floating-point solution

Uses Newton's method to solve ln x = 1

```% Calculate the value e = exp 1
%   Use Newton's method: x0 = 2; y = x(2 - ln x)

tolerance(1e-15).

exp1_iter(L) :-
lazy_list(newton, 2, L).

newton(X0, X1, X1) :-
X1 is X0*(2 - log(X0)).

e([X1, X2|_], X1) :- tolerance(Eps), abs(X2 - X1) < Eps.
e([_|Xs], E) :- e(Xs, E).

main :-
exp1_iter(Iter),
e(Iter, E),
format("e = ~w~n", [E]),
halt.

?- main.
```
Output:
```\$ swipl e.pl
e = 2.7182818284590455
```

### Arbitrary-precision solution

```% John Devou: 26-Nov-2021
% Simple program to calculate e up to n decimal digits.
% Works fast for n ≤ 1 000 000.

l(M,F,L,S):- F > L -> S is M-1; M_ is M+1, F_ is F*M_, l(M_,F_,L,S).

e(S,X,Y,N,E):- S < 2 -> E is div(X*10**N,Y);
S_ is S-1, X_ is X+Y, Y_ is S*Y, e(S_,X_,Y_,N,E).

main:-
get_time(Start),				% start computation
atom_number(X,N),				% convert first argument to number
L is 3*10**(N+1), l(1,1,L,S),		% find the smallest S, such that (S+1)! > 3*10^(N+1)
e(S,0,1,N,E),				% compute decimal part of series 1/2! + 1/3! + ... + 1/S!
get_time(End),				% finish computation
format("e = 2.~d\n",E),			% show number
format("Computed in ~f sec",End- Start),	% show computation time
halt.

?- main.
```
Output:
```\$ swipl e.pl 1000
e = 2.718281828459045235360287471352662497757247093699959574966967627724076630353547594571382178525166427427466391932003059921817413596629
043572900334295260595630738132328627943490763233829880753195251019011573834187930702154089149934884167509244761460668082264800168477411853
742345442437107539077744992069551702761838606261331384583000752044933826560297606737113200709328709127443747047230696977209310141692836819
025515108657463772111252389784425056953696770785449969967946864454905987931636889230098793127736178215424999229576351482208269895193668033
182528869398496465105820939239829488793320362509443117301238197068416140397019837679320683282376464804295311802328782509819455815301756717
361332069811250996181881593041690351598888519345807273866738589422879228499892086805825749279610484198444363463244968487560233624827041978
623209002160990235304369941849146314093431738143640546253152096183690888707016768396424378140592714563549061303107208510383750510115747704
1718986106873969655212671546889570350354
Computed in 0.000998 sec
```

## PureBasic

```Define f.d=1.0, e.d=1.0, e0.d=e, n.i=1
LOOP:
f*n : e+1.0/f
If e-e0>=1.0e-15 : e0=e : n+1 : Goto LOOP : EndIf
Debug "e="+StrD(e,15)```
Output:
`e=2.718281828459046`

## Python

### Imperative

```import math
#Implementation of Brother's formula
e0 = 0
e = 2
n = 0
fact = 1
while(e-e0 > 1e-15):
e0 = e
n += 1
fact *= 2*n*(2*n+1)
e += (2.*n+2)/fact

print "Computed e = "+str(e)
print "Real e = "+str(math.e)
print "Error = "+str(math.e-e)
print "Number of iterations = "+str(n)
```
Output:
```Computed e = 2.71828182846
Real e = 2.71828182846
Error = 4.4408920985e-16
Number of iterations = 9
```
Using integer arithmetic only

Easily generate thousands of digits:

```e = rfct = 10 ** 1000
n = 1
while rfct:
n += 1
e += rfct
rfct //= n
print(f"{e}\n...in {n} steps")
```
Output:

Turns out that just the last three decimal places are wrong.

```27182818284590452353602874713526624977572470936999595749669676277240766303535475945713821785251664274274663919320030599218174135966290435729003342952605956307381323286279434907632338298807531952510190115738341879307021540891499348841675092447614606680822648001684774118537423454424371075390777449920695517027618386062613313845830007520449338265602976067371132007093287091274437470472306969772093101416928368190255151086574637721112523897844250569536967707854499699679468644549059879316368892300987931277361782154249992295763514822082698951936680331825288693984964651058209392398294887933203625094431173012381970684161403970198376793206832823764648042953118023287825098194558153017567173613320698112509961818815930416903515988885193458072738667385894228792284998920868058257492796104841984443634632449684875602336248270419786232090021609902353043699418491463140934317381436405462531520961836908887070167683964243781405927145635490613031072085103837505101157477041718986106873969655212671546889570350116
...in 450 steps```

### Functional

This approximation stabilises (within the constraints of available floating point precision) after about the 17th term of the series.

Works with: Python version 3.7
```'''Calculating an approximate value for e'''

from itertools import (accumulate, chain)
from functools import (reduce)
from operator import (mul)

# eApprox :: () -> Float
def eApprox():
'''Approximation to the value of e.'''
return reduce(
lambda a, x: a + 1 / x,
scanl(mul)(1)(
range(1, 18)
),
0
)

# TEST ----------------------------------------------------
# main :: IO ()
def main():
'''Test'''

print(
eApprox()
)

# GENERIC ABSTRACTIONS ------------------------------------

# scanl is like reduce, but returns a succession of
# intermediate values, building from the left.
# See, for example, under `scan` in the Lists chapter of
# the language-independent Bird & Wadler 1988.

# scanl :: (b -> a -> b) -> b -> [a] -> [b]
def scanl(f):
'''scanl is like reduce, but returns a succession of
intermediate values, building from the left.'''
return lambda a: lambda xs: (
accumulate(chain([a], xs), f)
)

# MAIN ---
if __name__ == '__main__':
main()
```
Output:
`2.7182818284590455`

Or in terms of a single fold/reduce:

```'''Approximation of E'''

from functools import reduce

# eApprox :: Int -> Float
def eApprox(n):
'''Approximation of E obtained after N iterations.
'''
def go(efl, x):
e, fl = efl
flx = fl * x
return e + 1 / flx, flx

return reduce(
go,
range(1, 1 + n),
(1, 1)
)

# ------------------------- TEST -------------------------
# main :: IO ()
def main():
'''Approximation of E obtained after 20 iterations.'''

print(eApprox(20))

# MAIN ---
if __name__ == '__main__':
main()
```
Output:
`2.7182818284590455`

## Quackery

Using the Quackery bignum rational arithmetic library.

```  \$ "bigrat.qky" loadfile

[ swap number\$
tuck size -
times sp echo\$ ] is echo-rj ( n n --> )

[ 2dup swap
say "  First " echo
say " approximations of e by sum of 1/n! displayed to "
echo say " decimal places." cr
cr
temp put
1 n->v rot
1 swap times
[ i^ 1+ *
dup n->v 1/v
rot dip
[ v+ 2dup
i^ 1+ 5 echo-rj
say " : "
temp share point\$ echo\$
cr ] ]
3 times drop temp release ]    is approximate-e ( n n --> )

55 70 approximate-e```
Output:
```  First 55 approximations of e by sum of 1/n! displayed to 70 decimal places.

1 : 2
2 : 2.5
3 : 2.6666666666666666666666666666666666666666666666666666666666666666666667
4 : 2.7083333333333333333333333333333333333333333333333333333333333333333333
5 : 2.7166666666666666666666666666666666666666666666666666666666666666666667
6 : 2.7180555555555555555555555555555555555555555555555555555555555555555556
7 : 2.7182539682539682539682539682539682539682539682539682539682539682539683
8 : 2.7182787698412698412698412698412698412698412698412698412698412698412698
9 : 2.7182815255731922398589065255731922398589065255731922398589065255731922
10 : 2.7182818011463844797178130511463844797178130511463844797178130511463845
11 : 2.7182818261984928651595318261984928651595318261984928651595318261984929
12 : 2.7182818282861685639463417241195018972796750574528352306130083907861686
13 : 2.718281828446759002314557870113425668981224536780092335647891203446759
14 : 2.7182818284582297479122875948272773669599066424463249860075256900653726
15 : 2.7182818284589944642854695764748674801584854494907404960315013225066135
16 : 2.7182818284590422590587934503278418622333966249310164654079997995341911
17 : 2.718281828459045070516047795848605061178979635251032698900735004065225
18 : 2.7182818284590452267081174817108696833426231358243669340947758487613936
19 : 2.7182818284590452349287527283351994002986043726966476833155148405875077
20 : 2.7182818284590452353397844906664158861464034345402617207765517901788134
21 : 2.7182818284590452353593574317298071473772510089137671511318392639688756
22 : 2.7182818284590452353602471108690522047059258986580173979661705127775148
23 : 2.7182818284590452353602857925707585115463030677773326260894023062039774
24 : 2.71828182845904523536028740430832960766465211649063742726120363093008
25 : 2.7182818284590452353602874687778324515093860784391696193080756839191241
26 : 2.7182818284590452353602874712574287147341835385141131651560323013417796
27 : 2.7182818284590452353602874713492656133721389999983703335207714353203965
28 : 2.7182818284590452353602874713525455026092088379085223752480835472482042
29 : 2.7182818284590452353602874713526586022380733150778379628938529304181287
30 : 2.7182818284590452353602874713526623722257021309834818158153785765237928
31 : 2.7182818284590452353602874713526624938382062863352767788128471457530078
32 : 2.7182818284590452353602874713526624976385970411900203714065180385414207
33 : 2.718281828459045235360287471352662497753760397397739874212386853474403
34 : 2.718281828459045235360287471352662497757147554933261036059618289207726
35 : 2.7182818284590452353602874713526624977572443308628473549695391873715352
36 : 2.7182818284590452353602874713526624977572470190831136416059258789871966
37 : 2.7182818284590452353602874713526624977572470917377154331366390328146469
38 : 2.7182818284590452353602874713526624977572470936496786381769209579153692
39 : 2.7182818284590452353602874713526624977572470936987033357420563918923108
40 : 2.7182818284590452353602874713526624977572470936999289531811847777417344
41 : 2.7182818284590452353602874713526624977572470936999588462894562017868423
42 : 2.7182818284590452353602874713526624977572470936999595580301293309307734
43 : 2.7182818284590452353602874713526624977572470936999595745822380083527253
44 : 2.7182818284590452353602874713526624977572470936999595749584222964759515
45 : 2.7182818284590452353602874713526624977572470936999595749667819473231343
46 : 2.7182818284590452353602874713526624977572470936999595749669636788632904
47 : 2.7182818284590452353602874713526624977572470936999595749669675454918044
48 : 2.7182818284590452353602874713526624977572470936999595749669676260465651
49 : 2.7182818284590452353602874713526624977572470936999595749669676276905398
50 : 2.7182818284590452353602874713526624977572470936999595749669676277234193
51 : 2.718281828459045235360287471352662497757247093699959574966967627724064
52 : 2.7182818284590452353602874713526624977572470936999595749669676277240764
53 : 2.7182818284590452353602874713526624977572470936999595749669676277240766
54 : 2.7182818284590452353602874713526624977572470936999595749669676277240766
55 : 2.7182818284590452353602874713526624977572470936999595749669676277240766```

## R

```options(digits=22)
cat("e =",sum(rep(1,20)/factorial(0:19)))
```
Output:
```e = 2.718281828459046
```

## Racket

```#lang racket
(require math/number-theory)

(define (calculate-e (terms 20))
(apply + (map (compose / factorial) (range terms))))

(module+ main
(let ((e (calculate-e)))
(displayln e)
(displayln (real->decimal-string e 20))
(displayln (real->decimal-string (- (exp 1) e) 20))))
```
Output:
```82666416490601/30411275102208
2.71828182845904523493
0.00000000000000000000```

## Raku

(formerly Perl 6)

Works with: Rakudo version 2023.09
```# If you need high precision: Sum of a Taylor series method.
# Adjust the terms parameter to suit. Theoretically the
# terms could be ∞. Practically, calculating an infinite
# series takes an awfully long time so limit to 500.

constant 𝑒 = [\+] flat 1, [\/] 1.FatRat..*;

.say for 𝑒.comb(80);

say '';

# Or, if you don't need high precision, it's a built-in.
say e;
```
Output:
```2.718281828459045235360287471352662497757247093699959574966967627724076630353547
59457138217852516642742746639193200305992181741359662904357290033429526059563073
81323286279434907632338298807531952510190115738341879307021540891499348841675092
44761460668082264800168477411853742345442437107539077744992069551702761838606261
33138458300075204493382656029760673711320070932870912744374704723069697720931014
16928368190255151086574637721112523897844250569536967707854499699679468644549059
87931636889230098793127736178215424999229576351482208269895193668033182528869398
49646510582093923982948879332036250944311730123819706841614039701983767932068328
23764648042953118023287825098194558153017567173613320698112509961818815930416903
51598888519345807273866738589422879228499892086805825749279610484198444363463244
96848756023362482704197862320900216099023530436994184914631409343173814364054625
31520961836908887070167683964243781405927145635490613031072085103837505101157477
04171898610687396965521267154688957035035402123407849819334321068170121005627880
23519303322474501585390473041995777709350366041699732972508868769664035557071622
68447162560798827

2.718281828459045```

## REXX

### version 1

This REXX version uses the following formula to calculate Napier's constant   e:

``` ╔═══════════════════════════════════════════════════════════════════════════════════════╗
║                                                                                       ║
║           1         1         1         1         1         1         1               ║
║   e  =   ───   +   ───   +   ───   +   ───   +   ───   +   ───   +   ───   +    ∙∙∙   ║
║           0!        1!        2!        3!        4!        5!        6!              ║
║                                                                                       ║
╚═══════════════════════════════════════════════════════════════════════════════════════╝
```

If the argument (digs) is negative, a running number of decimal digits of   e   is shown.

```/*REXX pgm calculates  e  to a # of decimal digits. If digs<0, a running value is shown.*/
parse arg digs .                                 /*get optional number of decimal digits*/
if digs=='' | digs==","  then digs= 101          /*Not specified?  Then use the default.*/
numeric digits abs(digs);     w=length(digits()) /*use the absolute value of  digs.     */
e= 1;     q= 1               /*1st value of  e    and     q.        */
do #=1  until e==old;   old= e             /*start calculations at the second term*/
q= q / #                                   /*calculate the divisor for this term. */
e= e + q                                   /*add quotient to running   e   value. */
if digs>0  then iterate                    /*DIGS>0?  Then don't show running digs*/
\$= compare(e, old)                         /*\$  is first digit not compared equal.*/
if \$>0  then say right('with', 10)    right(#+1, w)     "terms,"      right(\$-1, w),
"decimal digits were calculated for   e   (Napier's constant)"     /*   ↑   */
end   /*#*/                                /* -1  is for the decimal point────┘   */
say                                              /*stick a fork in it,  we're all done. */
say '(with'    abs(digs)      "decimal digits)   the value of   e   is:";         say e
```

Programming note:   the factorial of the   do   loop index is calculated by   division,   not by the usual   multiplication   (for optimization).

output   when using the default input:
```(with 101 decimal digits)   the value of   e   is:
2.7182818284590452353602874713526624977572470936999595749669676277240766303535475945713821785251664274
```
output   when using the input of:   -101

(Shown at three-quarter size.)

```      with   2 terms,   0 decimal digits were calculated for   e   (Napier's constant)
with   3 terms,   1 decimal digits were calculated for   e   (Napier's constant)
with   4 terms,   2 decimal digits were calculated for   e   (Napier's constant)
with   5 terms,   2 decimal digits were calculated for   e   (Napier's constant)
with   6 terms,   3 decimal digits were calculated for   e   (Napier's constant)
with   7 terms,   4 decimal digits were calculated for   e   (Napier's constant)
with   8 terms,   5 decimal digits were calculated for   e   (Napier's constant)
with   9 terms,   6 decimal digits were calculated for   e   (Napier's constant)
with  10 terms,   6 decimal digits were calculated for   e   (Napier's constant)
with  11 terms,   8 decimal digits were calculated for   e   (Napier's constant)
with  12 terms,   9 decimal digits were calculated for   e   (Napier's constant)
with  13 terms,  10 decimal digits were calculated for   e   (Napier's constant)
with  14 terms,  11 decimal digits were calculated for   e   (Napier's constant)
with  15 terms,  12 decimal digits were calculated for   e   (Napier's constant)
with  16 terms,  14 decimal digits were calculated for   e   (Napier's constant)
with  17 terms,  13 decimal digits were calculated for   e   (Napier's constant)
with  18 terms,  16 decimal digits were calculated for   e   (Napier's constant)
with  19 terms,  17 decimal digits were calculated for   e   (Napier's constant)
with  20 terms,  18 decimal digits were calculated for   e   (Napier's constant)
with  21 terms,  19 decimal digits were calculated for   e   (Napier's constant)
with  22 terms,  21 decimal digits were calculated for   e   (Napier's constant)
with  23 terms,  21 decimal digits were calculated for   e   (Napier's constant)
with  24 terms,  24 decimal digits were calculated for   e   (Napier's constant)
with  25 terms,  25 decimal digits were calculated for   e   (Napier's constant)
with  26 terms,  27 decimal digits were calculated for   e   (Napier's constant)
with  27 terms,  27 decimal digits were calculated for   e   (Napier's constant)
with  28 terms,  29 decimal digits were calculated for   e   (Napier's constant)
with  29 terms,  30 decimal digits were calculated for   e   (Napier's constant)
with  30 terms,  32 decimal digits were calculated for   e   (Napier's constant)
with  31 terms,  33 decimal digits were calculated for   e   (Napier's constant)
with  32 terms,  35 decimal digits were calculated for   e   (Napier's constant)
with  33 terms,  37 decimal digits were calculated for   e   (Napier's constant)
with  34 terms,  38 decimal digits were calculated for   e   (Napier's constant)
with  35 terms,  40 decimal digits were calculated for   e   (Napier's constant)
with  36 terms,  41 decimal digits were calculated for   e   (Napier's constant)
with  37 terms,  43 decimal digits were calculated for   e   (Napier's constant)
with  38 terms,  45 decimal digits were calculated for   e   (Napier's constant)
with  39 terms,  46 decimal digits were calculated for   e   (Napier's constant)
with  40 terms,  48 decimal digits were calculated for   e   (Napier's constant)
with  41 terms,  49 decimal digits were calculated for   e   (Napier's constant)
with  42 terms,  51 decimal digits were calculated for   e   (Napier's constant)
with  43 terms,  52 decimal digits were calculated for   e   (Napier's constant)
with  44 terms,  54 decimal digits were calculated for   e   (Napier's constant)
with  45 terms,  56 decimal digits were calculated for   e   (Napier's constant)
with  46 terms,  57 decimal digits were calculated for   e   (Napier's constant)
with  47 terms,  59 decimal digits were calculated for   e   (Napier's constant)
with  48 terms,  61 decimal digits were calculated for   e   (Napier's constant)
with  49 terms,  62 decimal digits were calculated for   e   (Napier's constant)
with  50 terms,  64 decimal digits were calculated for   e   (Napier's constant)
with  51 terms,  65 decimal digits were calculated for   e   (Napier's constant)
with  52 terms,  67 decimal digits were calculated for   e   (Napier's constant)
with  53 terms,  69 decimal digits were calculated for   e   (Napier's constant)
with  54 terms,  71 decimal digits were calculated for   e   (Napier's constant)
with  55 terms,  72 decimal digits were calculated for   e   (Napier's constant)
with  56 terms,  74 decimal digits were calculated for   e   (Napier's constant)
with  57 terms,  76 decimal digits were calculated for   e   (Napier's constant)
with  58 terms,  78 decimal digits were calculated for   e   (Napier's constant)
with  59 terms,  80 decimal digits were calculated for   e   (Napier's constant)
with  60 terms,  81 decimal digits were calculated for   e   (Napier's constant)
with  61 terms,  83 decimal digits were calculated for   e   (Napier's constant)
with  62 terms,  84 decimal digits were calculated for   e   (Napier's constant)
with  63 terms,  87 decimal digits were calculated for   e   (Napier's constant)
with  64 terms,  88 decimal digits were calculated for   e   (Napier's constant)
with  65 terms,  91 decimal digits were calculated for   e   (Napier's constant)
with  66 terms,  92 decimal digits were calculated for   e   (Napier's constant)
with  67 terms,  94 decimal digits were calculated for   e   (Napier's constant)
with  68 terms,  96 decimal digits were calculated for   e   (Napier's constant)
with  69 terms,  98 decimal digits were calculated for   e   (Napier's constant)
with  70 terms, 100 decimal digits were calculated for   e   (Napier's constant)
with  71 terms, 101 decimal digits were calculated for   e   (Napier's constant)

(with 101 decimal digits)   the value of   e   is:
2.7182818284590452353602874713526624977572470936999595749669676277240766303535475945713821785251664274
```

### version 2

Using the series shown in version 1 compute e to the specified precision.

```/*REXX pgm calculates e to nn of decimal digits             */
Parse Arg dig             /* the desired precision          */
Numeric Digits (dig+3)    /* increase precision             */
dig2=dig+2                /* limit the loop                 */
e=1                       /* first element of the series    */
q=1                       /* next element of the series     */
Do n=1 By 1               /* start adding the elements      */
old=e                   /* current sum                    */
q=q/n                   /* new element                    */
e=e+q                   /* add the new element to the sum */
If left(e,dig2)=left(old,dig2) Then /* no change          */
Leave                 /* we are done                    */
End
Numeric Digits dig        /* the desired precision          */
e=e/1                     /* the desired approximation      */
Return left(e,dig+1) '('n 'iterations required)'
```
Output:
```J:\>rexx eval compey(66)
compey(66)=2.71828182845904523536028747135266249775724709369995957496696762772 (52 iterations required)```

Check the function's correctness

``` /*REXX check the correctness of compey */
e_='2.7182818284590452353602874713526624977572470936999595749669676277240'||,
'766303535475945713821785251664274274663919320030599218174135966290435'||,
'729003342952605956307380251882050351967424723324653614466387706813388353430034'
ok=0
Do d=3 To 100
Parse Value compey(d) with e .
Numeric digits d
If e<>e_/1 Then Do
say d e
Say e
Say e_/1
End
Else ok=ok+1
End
Say ok 'comparisons are ok'
```
Output:
```J:\>rexx compez
98 comparisons are ok```

## Ring

```# Project : Calculating the value of e

decimals(14)

for n = 1 to 100000
e = pow((1 + 1/n),n)
next
see "Calculating the value of e with method #1:" + nl
see "e = " + e + nl

e = 0
for n = 0 to 12
e = e + (1 / factorial(n))
next
see "Calculating the value of e with method #2:" + nl
see "e = " + e + nl

func factorial(n)
if n = 0 or n = 1
return 1
else
return n * factorial(n-1)
ok```

Output:

```Calculating the value of e with method #1:
e = 2.71826823719230
Calculating the value of e with method #2:
e = 2.71828182828617
```

## RPL

Translation of: Forth
Works with: Halcyon Calc version 4.2.7
``` ≪ "e = 2." → n result
≪  {} n 1 + + 1 CON
2 n START
0 SWAP
n 1 + 1 FOR j
DUP j GET 10 * ROT +
j 1 + MOD LAST / IP ROT ROT
j SWAP PUT
-1 STEP
result ROT →STR + 'result' STO
NEXT
DROP result
≫ ≫ ‘°e’ STO
```
```( n  --  "2.718..." )
Create a (n+1)-array filled with 1s
Loop n-1 times
Reset carry
Scan array from the right
a(j) modulo j+1 , send quotient to stack
Replace a(j) with a(j) mod j+1

Add final quotient to output string

Show only result

```

The following line of command delivers what is required:

```100 °e
```
Output:
```1: "e = 2.718281828459045235360287471352662497757247093699959574966967627724076630353547594571382178525166427"
```

## Ruby

Translation of: C
```fact = 1
e = 2
e0 = 0
n = 2

until (e - e0).abs < Float::EPSILON do
e0 = e
fact *= n
n += 1
e += 1.0 / fact
end

puts e
```

Built in:

```require "bigdecimal/math"

puts BigMath.E(50).to_s # 50 decimals
```
Output:
```0.27182818284590452353602874713526624977572470937e1
```

## Rust

```const EPSILON: f64 = 1e-15;

fn main() {
let mut fact: u64 = 1;
let mut e: f64 = 2.0;
let mut n: u64 = 2;
loop {
let e0 = e;
fact *= n;
n += 1;
e += 1.0 / fact as f64;
if (e - e0).abs() < EPSILON {
break;
}
}
println!("e = {:.15}", e);
}
```
Output:
`e = 2.718281828459046`

## S-BASIC

```rem - return double-precision value of e
function e = real.double
var fact, n, result, epsilon = real.double
result = 2.0
fact = 1.0
n = 2.0
epsilon = 1.0E-12
repeat
begin
fact = fact / n
n = n + 1.0
result = result + fact
end
until fact < epsilon
end = result

rem - test the function
print "Calculated value of e  ="; e
print "Value of e as exp(1.0) ="; exp(1.0)
print "Published value of e   = 2.718281828459045"

end
```
Output:
```Calculated value of e  = 2.718281828459
Value of e as exp(1.0) = 2.71828
Published value of e   = 2.718281828459045
```

## Scala

Output:
Best seen running in your browser either by ScalaFiddle (ES aka JavaScript, non JVM) or Scastie (remote JVM).
```import scala.annotation.tailrec

object CalculateE extends App {
private val ε = 1.0e-15

@tailrec
def iter(fact: Long, ℯ: Double, n: Int, e0: Double): Double = {
val newFact = fact * n
val newE = ℯ + 1.0 / newFact
if (math.abs(newE - ℯ) < ε) ℯ
else iter(newFact, newE, n + 1, ℯ)
}

println(f"ℯ = \${iter(1L, 2.0, 2, 0)}%.15f")
}
```

## Scheme

Translation of: JavaScript
```(import (rnrs))

(define (e)
(sum
(map
(lambda (x) (/ 1.0 x))
(scanl
(lambda (a x) (* a x))
1
(enum-from-to 1 20)))))

(define (enum-from-to m n)
(if (>= n m)
(iterate-until (lambda (x) (>= x n)) (lambda (x) (+ 1 x)) m)
'()))

(define (iterate-until p f x)
(let loop ((vs (list x)) (h x))
(if (p h)
(reverse vs)
(loop (cons (f h) vs) (f h)))))

(define (sum xs)
(fold-left + 0 xs))

(define-record-type scan (fields acc scan))

(define (scanl f start-value xs)
(scan-scan
(fold-left
(lambda (a x)
(let ((v (f (scan-acc a) x)))
(make-scan v (cons v (scan-scan a)))))
(make-scan start-value (cons start-value '()))
xs)))

(display (e))
(newline)
```

### High Precision

Works with: Chez Scheme

Series Implementation
Scheme will in general, when passed an exact value (integer or rational), try to preserve the exactness of the calculation. So, calling exp with the integer 1 will return an exact rational value, allowing for higher precision than floating point would.

```; Use series to compute approximation to exp(z) (using N terms of series).
;          n-1
; exp(z) ~ SUM ( z^k / k! )
;          k=0

(define exp
(lambda (z n)
(do ((k 0 (1+ k))
(sum 0 (+ sum (/ (expt z k) (fact k)))))
((>= k n) sum))))

; Procedure to compute factorial.

(define fact
(lambda (n)
(if (<= n 0)
1
(* n (fact (1- n))))))
```

Convert for Display

```; Convert the given Rational number to a Decimal string.
; If opt contains an integer, show to that many places past the decimal regardless of repeating.
; If opt contains 'nopar, do not insert the parentheses indicating the repeating places.
; If opt contains 'plus, prefix positive numbers with plus ('+') sign.
; N.B.:  When number of decimals specified, this truncates instead of rounds.

(define rat->dec-str
(lambda (rat . opt)
(let* ((num (abs (numerator rat)))
(den (abs (denominator rat)))
(no-par (find (lambda (a) (eq? a 'nopar)) opt))
(plus (find (lambda (a) (eq? a 'plus)) opt))
(dec-lim (find integer? opt))
(rep-inx #f)
(rems-seen '())
(int-part (format (cond ((< rat 0) "-~d") (plus "+~d") (else "~d")) (quotient num den)))
(frc-list
(cond
((zero? num)
'())
(else
(let loop ((rem (modulo num den)) (decs 0))
(cond
((or (<= rem 0) (and dec-lim (>= decs dec-lim)))
'())
((and (not dec-lim) (assq rem rems-seen))
(set! rep-inx (cdr (assq rem rems-seen)))
'())
(else
(set! rems-seen (cons (cons rem decs) rems-seen))
(cons
(integer->char (+ (quotient (* 10 rem) den) (char->integer #\0)))
(loop (modulo (* 10 rem) den) (1+ decs))))))))))
(when (and rep-inx (not no-par))
(set! frc-list (append
(list #\()
(list-tail frc-list rep-inx)
(list #\)))))
(if (null? frc-list)
int-part
(format "~a.~a" int-part (list->string frc-list))))))
```

```; Use the series approximation to exp(z) to compute e (= exp(1)) to 100 places.

(let*
((n 75)
(p 100)
(z 1)
(e (exp z n)))
(newline)
(printf "Computing exp(~a) using ~a terms...~%" z n)
(printf "the computed exact rational:~%~a~%" e)
(printf "converted to decimal (~a places):~%~a~%" p (rat->dec-str e p))
(printf "converted to an inexact (float):~%~a~%" (exact->inexact e)))
```
Output:
```Computing exp(1) using 75 terms...
the computed exact rational:
179835297726127476904046655197496828465249950976990919915482284588791312285099346749580175495960957663725089/66157708830387728245190605644250756429136650364186994234122385367082247140194313091850174464000000000000000
converted to decimal (100 places):
2.7182818284590452353602874713526624977572470936999595749669676277240766303535475945713821785251664274
converted to an inexact (float):
2.718281828459045```

## Seed7

The Seed7 library math.s7i defines the constant E. The program below computes e:

```\$ include "seed7_05.s7i";
include "float.s7i";

const float: EPSILON is 1.0e-15;

const proc: main is func
local
var integer: fact is 1;
var float: e is 2.0;
var float: e0 is 0.0;
var integer: n is 2;
begin
repeat
e0 := e;
fact *:= n;
incr(n);
e +:= 1.0 / flt(fact);
until abs(e - e0) < EPSILON;
writeln("e = " <& e digits 15);
end func;```
Output:
```e = 2.718281828459046
```

## Sidef

```func calculate_e(n=50) {
sum(0..n, {|k| 1/k! })
}

say calculate_e()
say calculate_e(69).as_dec(100)```
Output:
```2.7182818284590452353602874713526624977572470937
2.718281828459045235360287471352662497757247093699959574966967627724076630353547594571382178525166427
```

For finding the number of required terms for calculating e to a given number of decimal places, using the formula Sum_{k=0..n} 1/k!, we have:

```func f(n) {
var t = n*log(10)
(n + 10).bsearch_le { |k|
lngamma(k+1) <=> t
}
}

for k in (1..10) {
var n = f(10**k)
say "Sum_{k=0..#{n}} 1/k! = e correct to #{10**k->commify} decimal places"
}```
Output:
```Sum_{k=0..13} 1/k! = e correct to 10 decimal places
Sum_{k=0..69} 1/k! = e correct to 100 decimal places
Sum_{k=0..449} 1/k! = e correct to 1,000 decimal places
Sum_{k=0..3248} 1/k! = e correct to 10,000 decimal places
Sum_{k=0..25205} 1/k! = e correct to 100,000 decimal places
Sum_{k=0..205022} 1/k! = e correct to 1,000,000 decimal places
Sum_{k=0..1723507} 1/k! = e correct to 10,000,000 decimal places
Sum_{k=0..14842906} 1/k! = e correct to 100,000,000 decimal places
Sum_{k=0..130202808} 1/k! = e correct to 1,000,000,000 decimal places
Sum_{k=0..1158787577} 1/k! = e correct to 10,000,000,000 decimal places
```

## Standard ML

```fun calcEToEps() =
let
val eps = 1.0e~15
fun calcToEps'(eest: real, prev: real, denom, i) =
if Real.abs(eest - prev) < eps then
eest
else
let
val denom' = denom * i;
val prev' = eest
in
calcToEps'(eest + 1.0/denom', prev', denom', i + 1.0)
end
in
calcToEps'(2.0, 1.0, 1.0, 2.0)
end;```
Output:
```- val eEst = calcEToEps();
val eEst = 2.71828182846 : real
- Math.e - eEst;
val it = ~4.4408920985E~16 : real
```

## Swift

Translation of: C
```import Foundation

func calculateE(epsilon: Double = 1.0e-15) -> Double {
var fact: UInt64 = 1
var e = 2.0, e0 = 0.0
var n = 2

repeat {
e0 = e
fact *= UInt64(n)
n += 1
e += 1.0 / Double(fact)
} while fabs(e - e0) >= epsilon

return e
}

print(String(format: "e = %.15f\n", arguments: [calculateE()]))```
Output:
`e = 2.718281828459046`

## Tcl

### By the power series of exp(x)

```set ε 1.0e-15
set fact 1
set e 2.0
set e0 0.0
set n 2

while {[expr abs(\$e - \$e0)] > \${ε}} {
set e0 \$e
set fact [expr \$fact * \$n]
incr n
set e [expr \$e + 1.0/\$fact]
}
puts "e = \$e"```
Output:
```e = 2.7182818284590455
```

### By the continued fraction for e

This has the advantage, that arbitrary large precision can be achieved, should that become a demand. Also, full precision for the floating point value can be guaranteed.

```## We use (regular) continued fractions, step by step.
## The partial CF is coded (a n b m) for (a+nr) / (b+mr) for rest r.
## The (current) approximation is a/b (for r=0)

proc cfExt {anbm u} {
if {\$u <= 0} {
return \$anbm
}
lassign \$anbm a n b m

set na [expr {(\$a * \$u) + \$n}]
set nn \$a
set nb [expr {(\$b * \$u) + \$m}]
set nm \$b

return [list \$na \$nn \$nb \$nm]
}

proc cfPrec {anbm} {
lassign \$anbm a n b m

## The next term will change about 1 / (b*m)
return [expr {[string length \$b\$m] - 1}]
}

proc cfInt {k} {
return [list \$k 1 1 0]
}

proc calcE {decplaces} {
## cf for e is [2;1, 2,1,1, 4,1,1, 6,1,1, 8,1,1, ...]
set ecf [cfInt 2]
set ecf [cfExt \$ecf 1]
for {set j 2} {1} {incr j 2} {
if {[cfPrec \$ecf] >= \$decplaces} {
break
}
set ecf [cfExt \$ecf \$j]
set ecf [cfExt \$ecf 1]
set ecf [cfExt \$ecf 1]
}
lassign \$ecf a n b m
set q [expr {(10**\$decplaces * \$a) / \$b}]
puts "e = \$a / \$b  ([string range \$q 0 0].[string range \$q 1 end])"
puts "e = [expr {(0.0 + \$a) / \$b}]"
}

calcE 17```
Output:
```e = 848456353 / 312129649  (2.71828182845904523)
e = 2.718281828459045
```

## TI-83 BASIC

Guided by the Awk version.

```0->D
2->N
2->E
1->F
1.0E-12->Z
While abs(E-D)>Z
F*N->F
N+1->N
E->D
E+1/F->E
End
Disp E```
Output:
`2.718281828`

## UNIX Shell

```# POSIX requires "signed long" for shell arithmetic, so assume to have at
# least 31 bits available, which is sufficient to store (e - 1) * 10^9

one=1000000000

e=0 n=0 rfct=\$one
while [ \$((rfct /= (n += 1))) -ne 0 ]
do
e=\$((e + rfct))
done

echo "\$((e / one + 1)).\$((e % one))"```
Output:
`2.718281823`

## VBScript

Translation of: Python
```e0 = 0 : e = 2 : n = 0 : fact = 1
While (e - e0) > 1E-15
e0 = e
n = n + 1
fact = fact * 2*n * (2*n + 1)
e = e + (2*n + 2)/fact
Wend

WScript.Echo "Computed e = " & e
WScript.Echo "Real e = " & Exp(1)
WScript.Echo "Error = " & (Exp(1) - e)
WScript.Echo "Number of iterations = " & n```
Output:
```Computed e = 2.71828182845904
Real e = 2.71828182845905
Error = 4.44089209850063E-16
Number of iterations = 9```

## Verilog

```module main;
real n, n1;
real e1, e;

initial begin
n = 1.0;
n1 = 1.0;
e1 = 0.0;
e = 1.0;

while (e != e1) begin
e1 = e;
e = e + (1.0 / n);
n1 = n1 + 1;
n = n * n1;
end
\$display("The value of e = ", e);
\$finish ;
end
endmodule```
Output:
`The value of e = 2.71828`

## Visual Basic .NET

Translation of: C#
Automatically determines number of padding digits required for the arbitrary precision output. Can calculate a quarter million digits of e in under a half a minute.
```Imports System, System.Numerics, System.Math, System.Console

Module Program
Function CalcE(ByVal nDigs As Integer) As String
Dim pad As Integer = Round(Log10(nDigs)), n = 1,
f As BigInteger = BigInteger.Pow(10, nDigs + pad), e = f + f
Do : n+= 1 : f /= n : e += f : Loop While f > n
Return (e / BigInteger.Pow(10, pad + 1)).ToString().Insert(1, ".")
End Function

Sub Main()
WriteLine(Exp(1))  '  double precision built-in function
WriteLine(CalcE(100))   '  arbitrary precision result
Dim st As DateTime = DateTime.Now, qmil As Integer = 250_000,
es As String = CalcE(qmil)  '  large arbitrary precision result string
WriteLine("{0:n0} digits in {1:n3} seconds.", qmil, (DateTime.Now - st).TotalSeconds)
WriteLine("partial: {0}...{1}", es.Substring(0, 46), es.Substring(es.Length - 45))
End Sub
End Module```
Output:
```2.71828182845905
2.718281828459045235360287471352662497757247093699959574966967627724076630353547594571382178525166427
250,000 digits in 22.559 seconds.
partial: 2.71828182845904523536028747135266249775724709...026587951482508371108187783411598287506586313```

## V (Vlang)

Translation of: Go
```import math
const epsilon = 1.0e-15

fn main() {
mut fact := u64(1)
mut e := 2.0
mut n := u64(2)
for {
e0 := e
fact *= n
n++
e += 1.0 / f64(fact)
if math.abs(e - e0) < epsilon {
break
}
}
println("e = \${e:.15f}")
}```
Output:
```e = 2.718281828459046
```

## Wren

Translation of: Go
```var epsilon = 1e-15
var fact = 1
var e = 2
var n = 2
while (true) {
var e0 = e
fact = fact * n
n = n + 1
e = e + 1/fact
if ((e - e0).abs < epsilon) break
}
System.print("e = %(e)")```
Output:
```e = 2.718281828459
```

## XPL0

```real N, E, E0, F;       \index, Euler numbers, factorial
[Format(1, 16);         \show 16 places after decimal point
N:= 1.0;  E:= 1.0;  F:= 1.0;
loop    [E0:= E;
E:= E + 1.0/F;
if E = E0 then quit;
N:= N + 1.0;
F:= F*N;
];
RlOut(0, E);  CrLf(0);
IntOut(0, fix(N));  Text(0, " iterations");
]```
Output:
```2.7182818284590500
18 iterations
```

## Zig

Works with: Zig version 0.11.0

This uses the continued fraction method to generate the maximum ratio that can be computed using 64 bit math. The final ratio is correct to 35 decimal places.

```const std = @import("std");

pub fn main() !void {
const stdout = std.io.getStdOut().writer();

var n: u32 = 0;
var state: u2 = 0;
var p0: u64 = 0;
var q0: u64 = 1;
var p1: u64 = 1;
var q1: u64 = 0;
while (true) {
var a: u64 = undefined;
switch (state) {
0 => {
a = 2;
state = 1;
},
1 => {
a = 1;
state = 2;
},
2 => {
n += 2;
a = n;
state = 3;
},
3 => {
a = 1;
state = 1;
},
}
const ov1 = @mulWithOverflow(a, p1);
if (ov1 != 0) break;
if (ov2 != 0) break;
const ov3 = @mulWithOverflow(a, q1);
if (ov3 != 0) break;
if (ov4 != 0) break;
const p2 = ov2;
const q2 = ov4;

try stdout.print("e ~= {d:>19} / {d:>19} = ", .{ p2, q2 });
try decPrint(stdout, p2, q2, 36);
try stdout.writeByte('\n');
p0 = p1;
p1 = p2;
q0 = q1;
q1 = q2;
}
}

fn decPrint(ostream: anytype, num: u64, den: u64, prec: usize) !void {
// print out integer part.
try ostream.print("{}.", .{num / den});

// arithmetic with the remainders is done with u128, as the
// multiply by 10 could potentially overflow a u64.
//
const m: u128 = @intCast(den);
var r = @as(u128, num) % m;
var dec: usize = 0; // decimal place we're in.
while (dec < prec and r > 0) {
const n = 10 * r;
r = n % m;
dec += 1;
const ch = @as(u8, @intCast(n / m)) + '0';
try ostream.writeByte(ch);
}
}```
Output:
```e ~=                   2 /                   1 = 2.
e ~=                   3 /                   1 = 3.
e ~=                   8 /                   3 = 2.666666666666666666666666666666666666
e ~=                  11 /                   4 = 2.75
e ~=                  19 /                   7 = 2.714285714285714285714285714285714285
e ~=                  87 /                  32 = 2.71875
e ~=                 106 /                  39 = 2.717948717948717948717948717948717948
e ~=                 193 /                  71 = 2.718309859154929577464788732394366197
e ~=                1264 /                 465 = 2.718279569892473118279569892473118279
e ~=                1457 /                 536 = 2.718283582089552238805970149253731343
e ~=                2721 /                1001 = 2.718281718281718281718281718281718281
e ~=               23225 /                8544 = 2.718281835205992509363295880149812734
e ~=               25946 /                9545 = 2.718281822943949711891042430591932949
e ~=               49171 /               18089 = 2.718281828735695726684725523798993863
e ~=              517656 /              190435 = 2.718281828445401318035025074172289757
e ~=              566827 /              208524 = 2.718281828470583721777828930962383226
e ~=             1084483 /              398959 = 2.718281828458563411277850606202642376
e ~=            13580623 /             4996032 = 2.718281828459065114074529546648220027
e ~=            14665106 /             5394991 = 2.718281828459028013207065591026935911
e ~=            28245729 /            10391023 = 2.718281828459045851404621084949961134
e ~=           410105312 /           150869313 = 2.718281828459045213521983758221262663
e ~=           438351041 /           161260336 = 2.718281828459045254624795027092092875
e ~=           848456353 /           312129649 = 2.718281828459045234757560631479773329
e ~=         14013652689 /          5155334720 = 2.718281828459045235379013372772815806
e ~=         14862109042 /          5467464369 = 2.718281828459045235343535532787301096
e ~=         28875761731 /         10622799089 = 2.718281828459045235360753230188480692
e ~=        534625820200 /        196677847971 = 2.718281828459045235360274593941296140
e ~=        563501581931 /        207300647060 = 2.718281828459045235360299120911002524
e ~=       1098127402131 /        403978495031 = 2.718281828459045235360287179900086259
e ~=      22526049624551 /       8286870547680 = 2.718281828459045235360287478611074351
e ~=      23624177026682 /       8690849042711 = 2.718281828459045235360287464726031034
e ~=      46150226651233 /      16977719590391 = 2.718281828459045235360287471503357984
e ~=    1038929163353808 /     382200680031313 = 2.718281828459045235360287471349248563
e ~=    1085079390005041 /     399178399621704 = 2.718281828459045235360287471355803092
e ~=    2124008553358849 /     781379079653017 = 2.718281828459045235360287471352597036
e ~=   52061284670617417 /   19152276311294112 = 2.718281828459045235360287471352663857
e ~=   54185293223976266 /   19933655390947129 = 2.718281828459045235360287471352661238
e ~=  106246577894593683 /   39085931702241241 = 2.718281828459045235360287471352662521
e ~= 2816596318483412024 / 1036167879649219395 = 2.718281828459045235360287471352662497
e ~= 2922842896378005707 / 1075253811351460636 = 2.718281828459045235360287471352662498
e ~= 5739439214861417731 / 2111421691000680031 = 2.718281828459045235360287471352662497
```

## zkl

Translation of: C
```const EPSILON=1.0e-15;
fact,e,n := 1, 2.0, 2;
do{
e0:=e;
fact*=n; n+=1;
e+=1.0/fact;
}while((e - e0).abs() >= EPSILON);
println("e = %.15f".fmt(e));```
Output:
```e = 2.718281828459046
```

## ZX Spectrum Basic

```10 LET p=13: REM precision, or the number of terms in the Taylor expansion, from 0 to 33...
20 LET k=1: REM ...the Spectrum's maximum expressible precision is reached at p=13, while...
30 LET e=0: REM ...the factorial can't go any higher than 33
40 FOR x=1 TO p
50 LET e=e+1/k
60 LET k=k*x
70 NEXT x
80 PRINT e
90 PRINT e-EXP 1: REM the Spectrum ROM uses Chebyshev polynomials to evaluate EXP x = e^x```
Output:
```2.7182818
9.3132257E-10
```