Tokenize a string

From Rosetta Code
Task
Tokenize a string
You are encouraged to solve this task according to the task description, using any language you may know.

Separate the string "Hello,How,Are,You,Today" by commas into an array (or list) so that each element of it stores a different word. Display the words to the 'user', in the simplest manner possible, separated by a period. To simplify, you may display a trailing period.

Related tasks:

ACL2[edit]

(defun split-at (xs delim)
(if (or (endp xs) (eql (first xs) delim))
(mv nil (rest xs))
(mv-let (before after)
(split-at (rest xs) delim)
(mv (cons (first xs) before) after))))
 
(defun split (xs delim)
(if (endp xs)
nil
(mv-let (before after)
(split-at xs delim)
(cons before (split after delim)))))
 
(defun css->strs (css)
(if (endp css)
nil
(cons (coerce (first css) 'string)
(css->strs (rest css)))))
 
(defun split-str (str delim)
(css->strs (split (coerce str 'list) delim)))
 
(defun print-with (strs delim)
(if (endp strs)
(cw "~%")
(progn$ (cw (first strs))
(cw (coerce (list delim) 'string))
(print-with (rest strs) delim))))
Output:
> (print-with (split-str "Hello,How,Are,You,Today" #\,) #\.)
Hello.How.Are.You.Today.

ActionScript[edit]

var hello:String = "Hello,How,Are,You,Today";
var tokens:Array = hello.split(",");
trace(tokens.join("."));
 
// Or as a one-liner
trace("Hello,How,Are,You,Today".split(",").join("."));

Ada[edit]

with Ada.Strings.Fixed; use Ada.Strings.Fixed;
with Ada.Text_Io; use Ada.Text_Io;
 
procedure Parse_Commas is
Source_String : String := "Hello,How,Are,You,Today";
Index_List : array(Source_String'Range) of Natural;
Next_Index : Natural := Index_List'First;
begin
Index_List(Next_Index) := Source_String'First;
while Index_List(Next_Index) < Source_String'Last loop
Next_Index := Next_Index + 1;
Index_List(Next_Index) := 1 + Index(Source_String(Index_List(Next_Index - 1)..Source_String'Last), ",");
if Index_List(Next_Index) = 1 then
Index_List(Next_Index) := Source_String'Last + 2;
end if;
Put(Source_String(Index_List(Next_Index - 1)..Index_List(Next_Index)-2) & ".");
end loop;
end Parse_Commas;

ALGOL 68[edit]

main:(
 
OP +:= = (REF FLEX[]STRING in out, STRING item)VOID:(
[LWB in out: UPB in out+1]STRING new;
new[LWB in out: UPB in out]:=in out;
new[UPB new]:=item;
in out := new
);
 
PROC string split = (REF STRING beetles, STRING substr)[]STRING:(
""" Split beetles where substr is found """;
FLEX[1:0]STRING out;
INT start := 1, pos;
WHILE string in string(substr, pos, beetles[start:]) DO
out +:= STRING(beetles[start:start+pos-2]);
start +:= pos + UPB substr - 1
OD;
IF start > LWB beetles THEN
out +:= STRING(beetles[start:])
FI;
out
);
 
PROC char split = (REF STRING beetles, STRING chars)[]STRING: (
""" Split beetles where character is found in chars """;
FLEX[1:0]STRING out;
FILE beetlef;
associate(beetlef, beetles); # associate a FILE handle with a STRING #
make term(beetlef, chars); # make term: assign CSV string terminator #
 
PROC raise logical file end = (REF FILE f)BOOL: except logical file end;
on logical file end(beetlef, raise logical file end);
 
STRING solo;
DO
getf(beetlef, ($g$, solo));
out+:=solo;
getf(beetlef, ($x$)) # skip CHAR separator #
OD;
except logical file end:
SKIP;
out
);
 
STRING beetles := "John Lennon, Paul McCartney, George Harrison, Ringo Starr";
 
printf(($g"."$, string split(beetles, ", "),$l$));
printf(($g"."$, char split(beetles, ", "),$l$))
)
Output:
 John Lennon.Paul McCartney.George Harrison.Ringo Starr.
 John.Lennon..Paul.McCartney..George.Harrison..Ringo.Starr.


AppleScript[edit]

on run {}
intercalate(".", splitOn(",", "Hello,How,Are,You,Today"))
end run
 
 
-- splitOn :: String -> String -> [String]
on splitOn(strDelim, strMain)
set {dlm, my text item delimiters} to {my text item delimiters, strDelim}
set lstParts to text items of strMain
set my text item delimiters to dlm
return lstParts
end splitOn
 
-- intercalate :: String -> [String] -> String
on intercalate(strText, lstText)
set {dlm, my text item delimiters} to {my text item delimiters, strText}
set strJoined to lstText as text
set my text item delimiters to dlm
return strJoined
end intercalate
Output:
"Hello.How.Are.You.Today"

AutoHotkey[edit]

string := "Hello,How,Are,You,Today"
stringsplit, string, string, `,
loop, % string0
{
msgbox % string%A_Index%
}

AWK[edit]

BEGIN {
s = "Hello,How,Are,You,Today"
split(s, arr, ",")
for(i=1; i < length(arr); i++) {
printf arr[i] "."
}
print
}

A more idiomatic way for AWK is

BEGIN { FS = "," }
{
for(i=1; i <= NF; i++) printf $i ".";
print ""
}

which "tokenize" each line of input and this is achieved by using "," as field separator

BASIC[edit]

Applesoft BASIC[edit]

100 T$ = "HELLO,HOW,ARE,YOU,TODAY"
110 GOSUB 200"TOKENIZE
120 FOR I = 1 TO N
130 PRINT A$(I) "." ;
140 NEXT
150 PRINT
160 END
 
200 IF N = 0 THEN DIM A$(256)
210 N = 1
220 A$(N) = "
230 FOR TI = 1 TO LEN(T$)
240 C$ = MID$(T$, TI, 1)
250 T = C$ = ","
260 IF T THEN C$ = "
270 N = N + T
280 IF T THEN A$(N) = C$
290 A$(N) = A$(N) + C$
300 NEXT TI
310 RETURN

BBC BASIC[edit]

      INSTALL @lib$+"STRINGLIB"
 
text$ = "Hello,How,Are,You,Today"
n% = FN_split(text$, ",", array$())
FOR i% = 0 TO n%-1
PRINT array$(i%) "." ;
NEXT
PRINT

Liberty BASIC[edit]

'Note that Liberty Basic's array usage can reach element #10 before having to DIM the array
For i = 0 To 4
array$(i) = Word$("Hello,How,Are,You,Today", (i + 1), ",")
array$ = array$ + array$(i) + "."
Next i
 
Print Left$(array$, (Len(array$) - 1))

PowerBASIC[edit]

PowerBASIC has a few keywords that make parsing strings trivial: PARSE, PARSE$, and PARSECOUNT. (PARSE$, not shown here, is for extracting tokens one at a time, while PARSE extracts all tokens at once into an array. PARSECOUNT returns the number of tokens found.)

FUNCTION PBMAIN () AS LONG
DIM parseMe AS STRING
parseMe = "Hello,How,Are,You,Today"
 
REDIM parsed(PARSECOUNT(parseMe) - 1) AS STRING
PARSE parseMe, parsed() 'comma is default delimiter
 
DIM L0 AS LONG, outP AS STRING
outP = parsed(0)
FOR L0 = 1 TO UBOUND(parsed) 'could reuse parsecount instead of ubound
outP = outP & "." & parsed(L0)
NEXT
 
MSGBOX outP
END FUNCTION

PureBasic[edit]

As described

NewList MyStrings.s()
 
For i=1 To 5
AddElement(MyStrings())
MyStrings()=StringField("Hello,How,Are,You,Today",i,",")
Next i
 
ForEach MyStrings()
Print(MyStrings()+".")
Next

Still, easier would be

Print(ReplaceString("Hello,How,Are,You,Today",",","."))

QBasic[edit]

DIM parseMe AS STRING
parseMe = "Hello,How,Are,You,Today"
 
DIM tmpLng1 AS INTEGER, tmpLng2 AS INTEGER, parsedCount AS INTEGER
tmpLng2 = 1
parsedCount = -1
 
'count number of tokens
DO
tmpLng1 = INSTR(tmpLng2, parseMe, ",")
IF tmpLng1 THEN
parsedCount = parsedCount + 1
tmpLng2 = tmpLng1 + 1
ELSE
IF tmpLng2 < (LEN(parseMe) + 1) THEN parsedCount = parsedCount + 1
EXIT DO
END IF
LOOP
 
IF parsedCount > -1 THEN
REDIM parsed(parsedCount) AS STRING
tmpLng2 = 1
parsedCount = -1
 
'parse
DO
tmpLng1 = INSTR(tmpLng2, parseMe, ",")
IF tmpLng1 THEN
parsedCount = parsedCount + 1
parsed(parsedCount) = MID$(parseMe, tmpLng2, tmpLng1 - tmpLng2)
tmpLng2 = tmpLng1 + 1
ELSE
IF tmpLng2 < (LEN(parseMe) + 1) THEN
parsedCount = parsedCount + 1
parsed(parsedCount) = MID$(parseMe, tmpLng2)
END IF
EXIT DO
END IF
LOOP
 
PRINT parsed(0);
FOR L0 = 1 TO parsedCount
PRINT "."; parsed(L0);
NEXT
END IF

Run BASIC[edit]

text$ = "Hello,How,Are,You,Today"
FOR i = 1 to 5
textArray$(i) = word$(text$,i,",")
print textArray$(i);" ";
NEXT

VBScript[edit]

One liner[edit]

WScript.Echo Join(Split("Hello,How,Are,You,Today", ","), ".")

In fact, the Visual Basic solution (below) could have done the same, as Join() is available.

Visual Basic[edit]

Translation of: PowerBASIC

Unlike PowerBASIC, there is no need to know beforehand how many tokens are in the string -- Split automagically builds the array for you.

Sub Main()
Dim parseMe As String, parsed As Variant
parseMe = "Hello,How,Are,You,Today"
 
parsed = Split(parseMe, ",")
 
Dim L0 As Long, outP As String
outP = parsed(0)
For L0 = 1 To UBound(parsed)
outP = outP & "." & parsed(L0)
Next
 
MsgBox outP
End Sub

Batch File[edit]

@echo off
setlocal enabledelayedexpansion
call :tokenize %1 res
echo %res%
goto :eof
 
:tokenize
set str=%~1
:loop
for %%i in (%str%) do set %2=!%2!.%%i
set %2=!%2:~1!
goto :eof

Demo

>tokenize.cmd "Hello,How,Are,You,Today"
Hello.How.Are.You.Today

Bracmat[edit]

Solution that employs string pattern matching to spot the commas

( "Hello,How,Are,You,Today":?String
& :?ReverseList
& whl
' ( @(!String:?element "," ?String)
& !element !ReverseList:?ReverseList
)
& !String:?List
& whl
' ( !ReverseList:%?element ?ReverseList
& (!element.!List):?List
)
& out$!List
)

Solution that starts by evaluating the input and employs the circumstance that the comma is a list constructing binary operator and that the string does not contain any other characters that are interpreted as operators on evaluation.

(  get$("Hello,How,Are,You,Today",MEM):?CommaseparatedList
& :?ReverseList
& whl
' ( !CommaseparatedList:(?element,?CommaseparatedList)
& !element !ReverseList:?ReverseList
)
& !CommaseparatedList:?List
& whl
' ( !ReverseList:%?element ?ReverseList
& (!element.!List):?List
)
& out$!List
)

C[edit]

Works with: ANSI C
Library: POSIX

This example uses the strtok() function to separate the tokens. This function is destructive (replacing token separators with '\0'), so we have to make a copy of the string (using strdup()) before tokenizing. strdup() is not part of ANSI C, but is available on most platforms. It can easily be implemented with a combination of strlen(), malloc(), and strcpy().

#include<string.h>
#include<stdio.h>
#include<stdlib.h>
 
int main(void)
{
char *a[5];
const char *s="Hello,How,Are,You,Today";
int n=0, nn;
 
char *ds=strdup(s);
 
a[n]=strtok(ds, ",");
while(a[n] && n<4) a[++n]=strtok(NULL, ",");
 
for(nn=0; nn<=n; ++nn) printf("%s.", a[nn]);
putchar('\n');
 
free(ds);
 
return 0;
}

Another way to accomplish the task without the built-in string functions is to temporarily modify the separator character. This method does not need any additional memory, but requires the input string to be writeable.

#include<stdio.h>
 
typedef void (*callbackfunc)(const char *);
 
void doprint(const char *s) {
printf("%s.", s);
}
 
void tokenize(char *s, char delim, callbackfunc cb) {
char *olds = s;
char olddelim = delim;
while(olddelim && *s) {
while(*s && (delim != *s)) s++;
*s ^= olddelim = *s; // olddelim = *s; *s = 0;
cb(olds);
*s++ ^= olddelim; // *s = olddelim; s++;
olds = s;
}
}
 
int main(void)
{
char array[] = "Hello,How,Are,You,Today";
tokenize(array, ',', doprint);
return 0;
}

C#[edit]

string str = "Hello,How,Are,You,Today"; 
// or Regex.Split ( "Hello,How,Are,You,Today", "," );
// (Regex is in System.Text.RegularExpressions namespace)
string[] strings = str.Split(',');
foreach (string s in strings)
{
Console.WriteLine (s + ".");
}

C++[edit]

Works with: C++98

std::getline() is typically used to tokenize strings on a single-character delimiter

#include <string>
#include <sstream>
#include <vector>
#include <iterator>
#include <iostream>
#include <algorithm>
int main()
{
std::string s = "Hello,How,Are,You,Today";
std::vector<std::string> v;
std::istringstream buf(s);
for(std::string token; getline(buf, token, ','); )
v.push_back(token);
copy(v.begin(), v.end(), std::ostream_iterator<std::string>(std::cout, "."));
std::cout << '\n';
}
Works with: C++98

C++ allows the user to redefine what is considered whitespace. If the delimiter is whitespace, tokenization becomes effortless.

#include <string>
#include <locale>
#include <sstream>
#include <vector>
#include <iterator>
#include <iostream>
#include <algorithm>
struct comma_ws : std::ctype<char> {
static const mask* make_table() {
static std::vector<mask> v(classic_table(), classic_table() + table_size);
v[','] |= space; // comma will be classified as whitespace
return &v[0];
}
comma_ws(std::size_t refs = 0) : ctype<char>(make_table(), false, refs) {}
};
int main()
{
std::string s = "Hello,How,Are,You,Today";
std::istringstream buf(s);
buf.imbue(std::locale(buf.getloc(), new comma_ws));
std::istream_iterator<std::string> beg(buf), end;
std::vector<std::string> v(beg, end);
copy(v.begin(), v.end(), std::ostream_iterator<std::string>(std::cout, "."));
std::cout << '\n';
}
Works with: C++98
Library: boost

The boost library has multiple options for easy tokenization.

#include <string>
#include <vector>
#include <iterator>
#include <algorithm>
#include <iostream>
#include <boost/tokenizer.hpp>
int main()
{
std::string s = "Hello,How,Are,You,Today";
boost::tokenizer<> tok(s);
std::vector<std::string> v(tok.begin(), tok.end());
copy(v.begin(), v.end(), std::ostream_iterator<std::string>(std::cout, "."))
std::cout << '\n';
}

Ceylon[edit]

Works with: Ceylon 1.2
shared void tokenizeAString() {
value input = "Hello,How,Are,You,Today";
value tokens = input.split(','.equals);
print(".".join(tokens));
}

COBOL[edit]

This can be made to handle more complex cases; UNSTRING allows multiple delimiters, capture of which delimiter was used for each field, a POINTER for starting position (set on ending), along with match TALLYING.

 
identification division.
program-id. tokenize.
 
environment division.
configuration section.
repository.
function all intrinsic.
 
data division.
working-storage section.
01 period constant as ".".
01 cmma constant as ",".
 
01 start-with.
05 value "Hello,How,Are,You,Today".
 
01 items.
05 item pic x(6) occurs 5 times.
 
procedure division.
tokenize-main.
unstring start-with delimited by cmma
into item(1) item(2) item(3) item(4) item(5)
 
display trim(item(1)) period trim(item(2)) period
trim(item(3)) period trim(item(4)) period
trim(item(5))
 
goback.
end program tokenize.
 
Output:
prompt$ cobc -xj tokenize.cob
Hello.How.Are.You.Today

CoffeeScript[edit]

 
arr = "Hello,How,Are,You,Today".split ","
console.log arr.join "."
 

Common Lisp[edit]

There are libraries out there that handle splitting (e.g., SPLIT-SEQUENCE, and the more-general CL-PPCRE), but this is a simple one-off, too. When the words are written with write-with-periods, there is no final period after the last word.

(defun comma-split (string)
(loop for start = 0 then (1+ finish)
for finish = (position #\, string :start start)
collecting (subseq string start finish)
until (null finish)))
 
(defun write-with-periods (strings)
(format t "~{~A~^.~}" strings))

Clojure[edit]

Using native Clojure functions and Java Interop:

(apply str (interpose "." (.split #"," "Hello,How,Are,You,Today")))

Using the clojure.string library:

(clojure.string/join "." (clojure.string/split "Hello,How,Are,You,Today" #","))

D[edit]

void main() {
import std.stdio, std.string;
 
"Hello,How,Are,You,Today".split(',').join('.').writeln;
}
Output:
Hello.How.Are.You.Today

Delphi[edit]

 
program TokenizeString;
 
{$APPTYPE CONSOLE}
 
uses
Classes;
 
var
tmp: TStringList;
i: Integer;
 
begin
 
// Instantiate TStringList class
tmp := TStringList.Create;
try
{ Use the TStringList's CommaText property to get/set
all the strings in a single comma-delimited string }

tmp.CommaText := 'Hello,How,Are,You,Today';
 
{ Now loop through the TStringList and display each
token on the console }

for i := 0 to Pred(tmp.Count) do
Writeln(tmp[i]);
 
finally
tmp.Free;
end;
 
Readln;
 
end.
 

The result is:

 
Hello
How
Are
You
Today
 

Déjà Vu[edit]

!print join "." split "Hello,How,Are,You,Today" ","
Output:
Hello.How.Are.You.Today

E[edit]

".".rjoin("Hello,How,Are,You,Today".split(","))

Elena[edit]

#import system.
#import system'routines.
 
#symbol program =
[
#var string := "Hello,How,Are,You,Today".
 
string split &by:"," run &each:s
[
console writeLiteral:(s + ".").
].
].

Elixir[edit]

 
tokens = String.split("Hello,How,Are,You,Today", ",")
IO.puts Enum.join(tokens, ".")
 

Erlang[edit]

-module(tok).
-export([start/0]).
 
start() ->
Lst = string:tokens("Hello,How,Are,You,Today",","),
io:fwrite("~s~n", [string:join(Lst,".")]),
ok.

Euphoria[edit]

function split(sequence s, integer c)
sequence out
integer first, delim
out = {}
first = 1
while first<=length(s) do
delim = find_from(c,s,first)
if delim = 0 then
delim = length(s)+1
end if
out = append(out,s[first..delim-1])
first = delim + 1
end while
return out
end function
 
sequence s
s = split("Hello,How,Are,You,Today", ',')
 
for i = 1 to length(s) do
puts(1, s[i] & ',')
end for


F#[edit]

System.String.Join(".", "Hello,How,Are,You,Today".Split(','))

Factor[edit]

"Hello,How,Are,You,Today" "," split "." join print

Fantom[edit]

A string can be split on a given character, returning a list of the intervening strings.

 
class Main
{
public static Void main ()
{
str := "Hello,How,Are,You,Today"
words := str.split(',')
words.each |Str word|
{
echo ("${word}. ")
}
}
}
 

Forth[edit]

There is no standard string split routine, but it is easily written. The results are saved temporarily to the dictionary.

: split ( str len separator len -- tokens count )
here >r 2swap
begin
2dup 2, \ save this token ( addr len )
2over search \ find next separator
while
dup negate here 2 cells - +! \ adjust last token length
2over nip /string \ start next search past separator
repeat
2drop 2drop
r> here over - ( tokens length )
dup negate allot \ reclaim dictionary
2 cells / ; \ turn byte length into token count
 
: .tokens ( tokens count -- )
1 ?do dup 2@ type ." ." cell+ cell+ loop 2@ type ;
 
s" Hello,How,Are,You,Today" s" ," split .tokens \ Hello.How.Are.You.Today

Fortran[edit]

Works with: Fortran version 90 and later
PROGRAM Example
 
CHARACTER(23) :: str = "Hello,How,Are,You,Today"
CHARACTER(5) :: word(5)
INTEGER :: pos1 = 1, pos2, n = 0, i
 
DO
pos2 = INDEX(str(pos1:), ",")
IF (pos2 == 0) THEN
n = n + 1
word(n) = str(pos1:)
EXIT
END IF
n = n + 1
word(n) = str(pos1:pos1+pos2-2)
pos1 = pos2+pos1
END DO
 
DO i = 1, n
WRITE(*,"(2A)", ADVANCE="NO") TRIM(word(i)), "."
END DO
 
END PROGRAM Example

Frink[edit]

 
println[join[".", split[",", "Hello,How,Are,You,Today"]]]
 

GAP[edit]

SplitString("Hello,How,Are,You,Today", ",");
# [ "Hello", "How", "Are", "You", "Today" ]
 
JoinStringsWithSeparator(last, ".");
# "Hello.How.Are.You.Today"

Go[edit]

package main
 
import (
"fmt"
"strings"
)
 
func main() {
s := "Hello,How,Are,You,Today"
fmt.Println(strings.Join(strings.Split(s, ","), "."))
}

Groovy[edit]

println 'Hello,How,Are,You,Today'.split(',').join('.')

Haskell[edit]

Using Data.Text

{-# OPTIONS_GHC -XOverloadedStrings #-}
import Data.Text (splitOn,intercalate)
import qualified Data.Text.IO as T (putStrLn)
 
main = T.putStrLn . intercalate "." $ splitOn "," "Hello,How,Are,You,Today"

Output: Hello.How.Are.You.Today

Alternate Solution

The necessary operations are unfortunately not in the standard library (yet), but simple to write:

splitBy :: (a -> Bool) -> [a] -> [[a]]
splitBy _ [] = []
splitBy f list = first : splitBy f (dropWhile f rest) where
(first, rest) = break f list
 
splitRegex :: Regex -> String -> [String]
 
joinWith :: [a] -> [[a]] -> [a]
joinWith d xs = concat $ List.intersperse d xs
-- "concat $ intersperse" can be replaced with "intercalate" from the Data.List in GHC 6.8 and later
 
putStrLn $ joinWith "." $ splitBy (== ',') $ "Hello,How,Are,You,Today"
 
-- using regular expression to split:
import Text.Regex
putStrLn $ joinWith "." $ splitRegex (mkRegex ",") $ "Hello,How,Are,You,Today"

Tokenizing can also be realized by using unfoldr and break:

*Main> mapM_ putStrLn $ takeWhile (not.null) $ unfoldr (Just . second(drop 1). break (==',')) "Hello,How,Are,You,Today"
Hello
How
Are
You
Today
  • You need to import the modules Data.List and Control.Arrow

As special cases, splitting / joining by white space and by newlines are provided by the Prelude functions words / unwords and lines / unlines, respectively.

HicEst[edit]

CHARACTER string="Hello,How,Are,You,Today", list
 
nWords = INDEX(string, ',', 256) + 1
maxWordLength = LEN(string) - 2*nWords
ALLOCATE(list, nWords*maxWordLength)
 
DO i = 1, nWords
EDIT(Text=string, SePaRators=',', item=i, WordEnd, CoPyto=CHAR(i, maxWordLength, list))
ENDDO
 
DO i = 1, nWords
WRITE(APPend) TRIM(CHAR(i, maxWordLength, list)), '.'
ENDDO

Icon and Unicon[edit]

procedure main()
A := []
"Hello,How,Are,You,Today" ? while put(A, 1(tab(upto(',')|0),=","))
every writes(!A,".")
write()
end
Output:
 ->ss
 Hello.How.Are.You.
 ->

Io[edit]

"Hello,How,Are,You,Today" split(",") join(".") println

J[edit]

   s=: 'Hello,How,Are,You,Today'
] t=: <;._1 ',',s
+-----+---+---+---+-----+
|Hello|How|Are|You|Today|
+-----+---+---+---+-----+
 ; t,&.>'.'
Hello.How.Are.You.Today.
 
'.' (I.','=s)}s NB. two steps combined
Hello.How.Are.You.Today

Alternatively using the system library/script strings

   require 'strings'
',' splitstring s
+-----+---+---+---+-----+
|Hello|How|Are|You|Today|
+-----+---+---+---+-----+
 
'.' joinstring ',' splitstring s
Hello.How.Are.You.Today

splitstring and joinstring also work with longer "delimiters":

   '"'([ ,~ ,) '","' joinstring ',' splitstring s
"Hello","How","Are","You","Today"

But, of course, this could be solved with simple string replacement:

   rplc&',.' s
Hello.How.Are.You.Today

The task asks us to Separate the string "Hello,How,Are,You,Today" by commas into an array (or list) so that each element of it stores a different word. but for many purposes the original string is an adequate data structure. Note also that given a string, a list of "word start" indices and "word length" integers can be logically equivalent to having an "array of words" -- and, depending on implementation details may be a superior or inferior choice to some other representation. But, in current definition of this task, the concept of "word length" plays no useful role.

Note also that J provides several built-in concepts of parsing: split on leading delimiter, split on trailing delimiter, split J language words. Also, it's sometimes more efficient to append to a string than to prepend to it. So a common practice for parsing on an embedded delimiter is to append a copy of the delimiter to the string and then use the appended result:

   fn;._2 string,','

Here fn is applied to each ',' delimited substring and the results are assembled into an array.

Or, factoring out the names:

   fn ((;._2)(@(,&','))) string

Java[edit]

Works with: Java version 1.0+

There are multiple ways to tokenize a String in Java.

The first is by splitting the String into an array of Strings. The separator is actually a regular expression so you could do very powerful things with this, but make sure to escape any characters with special meaning in regex.

Works with: Java version 1.8+
String toTokenize = "Hello,How,Are,You,Today";
System.out.println(String.join(".", toTokenize.split(",")));
Works with: Java version 1.4+
String toTokenize = "Hello,How,Are,You,Today";
 
String words[] = toTokenize.split(",");//splits on one comma, multiple commas yield multiple splits
//toTokenize.split(",+") if you want to ignore empty fields
for(int i=0; i<words.length; i++) {
System.out.print(words[i] + ".");
}

The other way is to use StringTokenizer. It will skip any empty tokens. So if two commas are given in line, there will be an empty string in the array given by the split function, but no empty string with the StringTokenizer object. This method takes more code to use, but allows you to get tokens incrementally instead of all at once.

Works with: Java version 1.0+
String toTokenize = "Hello,How,Are,You,Today";
 
StringTokenizer tokenizer = new StringTokenizer(toTokenize, ",");
while(tokenizer.hasMoreTokens()) {
System.out.print(tokenizer.nextToken() + ".");
}

JavaScript[edit]

Works with: Firefox version 2.0
alert( "Hello,How,Are,You,Today".split(",").join(".") );

jq[edit]

split(",") | join(".")
Example:
$ jq -r 'split(",") | join(".")'
"Hello,How,Are,You,Today"
Hello.How.Are.You.Today

Julia[edit]

 
s = "Hello,How,Are,You,Today"
a = split(s, ",")
t = join(a, ".")
 
println("The string \"", s, "\"")
println("Splits into ", a)
println("Reconstitutes to \"", t, "\"")
 
Output:
The string "Hello,How,Are,You,Today"
Splits into SubString{ASCIIString}["Hello","How","Are","You","Today"]
Reconstitutes to "Hello.How.Are.You.Today"

K[edit]

words: "," \: "Hello,How,Are,You,Today"
"." /: words
Output:
"Hello.How.Are.You.Today"

Kotlin[edit]

Works with: Kotlin version 1.0b4
val input = "Hello,How,Are,You,Today"
println(input.split(',').join("."))
Output:
Hello.How.Are.You.Today

LabVIEW[edit]

To tokenize the string, we use the Search/Split String function to split the string by its first comma. Add the beginning (up to, but not including the comma) to the end of the array, remove the first comma from the rest of the string, and pass it back through the shift register to the loop's next iteration. This is repeated until the string is empty. Printing is a simple matter of concatenation.
This image is a VI Snippet, an executable image of LabVIEW code. The LabVIEW version is shown on the top-right hand corner. You can download it, then drag-and-drop it onto the LabVIEW block diagram from a file browser, and it will appear as runnable, editable code.
LabVIEW Tokenize a string.png

LFE[edit]

 
> (set split (string:tokens "Hello,How,Are,You,Today" ","))
("Hello" "How" "Are" "You" "Today")
> (string:join split ".")
"Hello.How.Are.You.Today"
 

Lang5[edit]

'Hello,How,Are,You,Today ', split '. join .

Lingo[edit]

input = "Hello,How,Are,You,Today"
_player.itemDelimiter = ","
output = ""
repeat with i = 1 to input.item.count
put input.item[i]&"." after output
end repeat
delete the last char of output
put output
-- "Hello.How.Are.You.Today"

[edit]

Works with: UCB Logo
to split :str :sep
output parse map [ifelse ? = :sep ["| |] [?]] :str
end

This form is more robust, doing the right thing if there are embedded spaces.

to split :str :by [:acc []] [:w "||]
if empty? :str [output lput :w :acc]
ifelse equal? first :str :by ~
[output (split butfirst :str :by lput :w :acc)] ~
[output (split butfirst :str :by  :acc lput first :str :w)]
end
? show split "Hello,How,Are,You,Today ",
[Hello How Are You Today]

Logtalk[edit]

Using Logtalk built-in support for Definite Clause Grammars (DCGs) and representing the strings as atoms for readbility:

 
:- object(spliting).
 
:- public(convert/2).
:- mode(convert(+atom, -atom), one).
 
convert(StringIn, StringOut) :-
atom_chars(StringIn, CharactersIn),
phrase(split(',', Tokens), CharactersIn),
phrase(split('.', Tokens), CharactersOut),
atom_chars(StringOut, CharactersOut).
 
split(Separator, [t([Character| Characters])| Tokens]) -->
[Character], {Character \== Separator}, split(Separator, [t(Characters)| Tokens]).
split(Separator, [t([])| Tokens]) -->
[Separator], split(Separator, Tokens).
split(_, [t([])]) -->
[].
% the look-ahead in the next rule prevents adding a spurious separator at the end
split(_, []), [Character] -->
[Character].
 
:- end_object.
 
Output:
| ?- spliting::convert('Hello,How,Are,You,Today', Converted).
Converted = 'Hello.How.Are.You.Today'
yes

Lua[edit]

Split function callously stolen from the lua-users wiki

function string:split (sep)
local sep, fields = sep or ":", {}
local pattern = string.format("([^%s]+)", sep)
self:gsub(pattern, function(c) fields[#fields+1] = c end)
return fields
end
 
local str = "Hello,How,Are,You,Today"
print(table.concat(str:split(","), "."))
Output:
Hello.How.Are.You.Today

M4[edit]

define(`s',`Hello,How,Are,You,Today')
define(`set',`define(`$1[$2]',`$3')')
define(`get',`defn($1[$2])')
define(`n',0)
define(`fill',
`set(a,n,$1)`'define(`n',incr(n))`'ifelse(eval($#>1),1,`fill(shift($@))')')
fill(s)
define(`j',0)
define(`show',
`ifelse(eval(j<n),1,`get(a,j).`'define(`j',incr(j))`'show')')
show
Output:
 Hello.How.Are.You.Today.


Mathematica[edit]

Row[Riffle[StringSplit["Hello,How,Are,You,Today", ","], "."]]

MATLAB / Octave[edit]

function tokenizeString(string,delimeter)
 
tokens = {};
 
while not(isempty(string))
[tokens{end+1},string] = strtok(string,delimeter);
end
 
for i = (1:numel(tokens)-1)
fprintf([tokens{i} '.'])
end
 
fprintf([tokens{end} '\n'])
end
Output:
>> tokenizeString('Hello,How,Are,You,Today',',')
Hello.How.Are.You.Today

Maxima[edit]

l: split("Hello,How,Are,You,Today", ",")$
printf(true, "~{~a~^.~}~%", l)$

MAXScript[edit]

output = ""
for word in (filterString "Hello,How,Are,You,Today" ",") do
(
output += (word + ".")
)
format "%\n" output

Mercury[edit]

 
:- module string_tokenize.
:- interface.
 
:- import_module io.
:- pred main(io::di, io::uo) is det.
 
:- implementation.
:- import_module list, string.
 
main(!IO) :-
Tokens = string.split_at_char((','), "Hello,How,Are,You,Today"),
io.write_list(Tokens, ".", io.write_string, !IO),
io.nl(!IO).

MMIX[edit]

sep	IS	','
EOS IS 0
NL IS 10

// main registers

p IS $255
tp GREG
c GREG
t GREG
 
LOC Data_Segment
GREG @
Text BYTE "Hello,How,Are,You,Today",EOS
token BYTE 0
eot IS @+255
 
LOC #100 % main () {
Main LDA p,Text %
LDA tp,token % initialize pointers
2H LDBU c,p % DO get char
BZ c,5F % break if char == EOS
CMP t,c,sep % if char != sep then
PBNZ t,3F % store char
SET t,NL % terminate token with NL,EOS
STBU t,tp
SET t,EOS
INCL tp,1
STBU t,tp
JMP 4F % continue
 
3H STBU c,tp % store char
4H INCL tp,1 % update pointers
INCL p,1
JMP 2B % LOOP
 
5H SET t,NL % terminate last token and buffer
STBU t,tp
SET t,EOS
INCL tp,1
STBU t,tp
% next part is not really necessary
% program runs only once
% INCL tp,1 % terminate buffer
% STBU t,tp
 
LDA tp,token % reset token pointer
% REPEAT
2H ADD p,tp,0 % start of token
TRAP 0,Fputs,StdOut % output token
ADD tp,tp,p
INCL tp,1 % step to next token
LDBU t,tp
PBNZ t,2B % UNTIL EOB(uffer)
TRAP 0,Halt,0
Output:
 ~/MIX/MMIX/Progs> mmix tokenizing
 Hello
 How
 Are
 You
 Today

Modula-3[edit]

MODULE Tokenize EXPORTS Main;
 
IMPORT IO, TextConv;
 
TYPE Texts = REF ARRAY OF TEXT;
 
VAR tokens: Texts;
string := "Hello,How,Are,You,Today";
sep := SET OF CHAR {','};
 
BEGIN
tokens := NEW(Texts, TextConv.ExplodedSize(string, sep));
TextConv.Explode(string, tokens^, sep);
FOR i := FIRST(tokens^) TO LAST(tokens^) DO
IO.Put(tokens[i] & ".");
END;
IO.Put("\n");
END Tokenize.

MUMPS[edit]

TOKENS
NEW I,J,INP
SET INP="Hello,how,are,you,today"
NEW I FOR I=1:1:$LENGTH(INP,",") SET INP(I)=$PIECE(INP,",",I)
NEW J FOR J=1:1:I WRITE INP(J) WRITE:J'=I "."
KILL I,J,INP // Kill is optional. "New" variables automatically are killed on "Quit"
QUIT

In use:

USER>D TOKENS^ROSETTA
Hello.how.are.you.today

Nemerle[edit]

using System;
using System.Console;
using Nemerle.Utility.NString;
 
module Tokenize
{
Main() : void
{
def cswords = "Hello,How,Are,You,Today";
WriteLine(Concat(".", $[s | s in cswords.Split(',')]));
// Split() produces an array while Concat() consumes a list
// a quick in place list comprehension takes care of that
}
}

NetRexx[edit]

/*NetRexx program *****************************************************
* 20.08.2012 Walter Pachl derived from REXX Version 3
**********************************************************************/

sss='Hello,How,Are,You,Today'
Say 'input string='sss
Say ''
Say 'Words in the string:'
ss =sss.translate(' ',',')
Loop i=1 To ss.words()
Say ss.word(i)'.'
End
Say 'End-of-list.'

Output as in REXX version

NewLISP[edit]

(print (join (parse "Hello,How,Are,You,Today" ",") "."))

Nim[edit]

import strutils
 
let text = "Hello,How,Are,You,Today"
let tokens = text.split(',')
echo tokens.join(" ")

Objeck[edit]

 
class Parse {
function : Main(args : String[]) ~ Nil {
tokens := "Hello,How,Are,You,Today"->Split(",");
each(i : tokens) {
tokens[i]->PrintLine();
};
}
}

Objective-C[edit]

Works with: GNUstep
Works with: Cocoa
NSString *text = @"Hello,How,Are,You,Today";
NSArray *tokens = [text componentsSeparatedByString:@","];
NSString *result = [tokens componentsJoinedByString:@"."];
NSLog(result);

OCaml[edit]

To split on a single-character separator:

let words = String.split_on_char ',' "Hello,How,Are,You,Today" in
String.concat "." words
 

The function split_on_char has been introduced in OCaml 4.04. In previous versions, it could be implemented by:

let split_on_char sep s =
let r = ref [] in
let j = ref (String.length s) in
for i = String.length s - 1 downto 0 do
if s.[i] = sep then begin
r := String.sub s (i + 1) (!j - i - 1) :: !r;
j := i
end
done;
String.sub s 0 !j :: !r

Oforth[edit]

"Hello,How,Are,You,Today" wordsWith(',') println
Output:
[Hello, How, Are, You, Today]

ooRexx[edit]

text='Hello,How,Are,You,Today'
do while text \= ''
parse var text word1 ',' text
call charout 'STDOUT:',word1'.'
end
Output:
Hello.How.Are.You.Today.

OpenEdge/Progress[edit]

FUNCTION tokenizeString RETURNS CHAR (
i_c AS CHAR
):
 
DEF VAR ii AS INT.
DEF VAR carray AS CHAR EXTENT.
DEF VAR cresult AS CHAR.
 
EXTENT( carray ) = NUM-ENTRIES( i_c ).
 
DO ii = 1 TO NUM-ENTRIES( i_c ):
carray[ ii ] = ENTRY( ii, i_c ).
END.
 
DO ii = 1 TO EXTENT( carray ).
cresult = cresult + "." + carray[ ii ].
END.
RETURN SUBSTRING( cresult, 2 ).
 
END FUNCTION. /* tokenizeString */
 
MESSAGE
tokenizeString( "Hello,How,Are,You,Today" )
VIEW-AS ALERT-BOX.
Output:
 ---------------------------
 Message
 ---------------------------
 Hello.How.Are.You.Today
 ---------------------------
 OK   
 ---------------------------

Oz[edit]

for T in {String.tokens "Hello,How,Are,You,Today" &,} do
{System.printInfo T#"."}
end

PARI/GP[edit]

Version #1.[edit]

Simple version, like the most custom ones here (for this task). This version has 1 character delimiter, which is not allowed in the beginning and at the end of string, in addition, double, triple, etc., delimiters are not allowed too.

Works with: PARI/GP version 2.7.4 and above
 
\\ Tokenize a string str according to 1 character delimiter d. Return a list of tokens.
\\ Using ssubstr() from http://rosettacode.org/wiki/Substring#PARI.2FGP
\\ tokenize() 3/5/16 aev
tokenize(str,d)={
my(str=Str(str,d),vt=Vecsmall(str),d1=sasc(d),Lr=List(),sn=#str,v1,p1=1);
for(i=p1,sn, v1=vt[i]; if(v1==d1, listput(Lr,ssubstr(str,p1,i-p1)); p1=i+1));
return(Lr);
}
 
{
\\ TEST
print(" *** Testing tokenize from Version #1:");
print("1.", tokenize("Hello,How,Are,You,Today",","));
\\ BOTH 2 & 3 are NOT OK!!
print("2.",tokenize("Hello,How,Are,You,Today,",","));
print("3.",tokenize(",Hello,,How,Are,You,Today",","));
}
 
Output:
 *** Testing tokenize from Version #1:
1.List(["Hello", "How", "Are", "You", "Today"])
2.List(["Hello", "How", "Are", "You", "Today", ","])
3.List([",Hello,,How,Are,You,Today,", "Hello", ",How,Are,You,Today,", "How", "Ar
e", "You", "Today"])

Version #2.[edit]

Advanced version. Delimiter is allowed in any place. In addition, multiple delimiters are allowed too. This is really useful for considering omitted data. This version can be used for positional parameters processing, or for processing data from tables with string rows.

Works with: PARI/GP version 2.7.4 and above
 
\\ Tokenize a string str according to 1 character delimiter d. Return a list of tokens.
\\ Using ssubstr() from http://rosettacode.org/wiki/Substring#PARI.2FGP
\\ stok() 3/5/16 aev
stok(str,d)={
my(d1c=ssubstr(d,1,1),str=Str(str,d1c),vt=Vecsmall(str),d1=sasc(d1c),
Lr=List(),sn=#str,v1,p1=1,vo=32);
if(sn==1, return(List(""))); if(vt[sn-1]==d1,sn--);
for(i=1,sn, v1=vt[i];
if(v1!=d1, vo=v1; next);
if(vo==d1||i==1, listput(Lr,""); p1=i+1; vo=v1; next);
if(i-p1>0, listput(Lr,ssubstr(str,p1,i-p1)); p1=i+1);
vo=v1;
);
return(Lr);
}
 
{
\\ TEST
print(" *** Testing stok from Version #2:");
\\ pp - positional parameter(s)
print("1. 5 pp: ", stok("Hello,How,Are,You,Today",","));
print("2. 5 pp: ", stok("Hello,How,Are,You,Today,",","));
print("3. 9 pp: ", stok(",,Hello,,,How,Are,You,Today",","));
print("4. 6 pp: ", stok(",,,,,,",","));
print("5. 1 pp: ", stok(",",","));
print("6. 1 pp: ", stok("Hello-o-o??",","));
print("7. 0 pp: ", stok("",","));
}
 
Output:
 *** Testing stok from Version #2:
1. 5 pp: List(["Hello", "How", "Are", "You", "Today"])
2. 5 pp: List(["Hello", "How", "Are", "You", "Today"])
3. 9 pp: List(["", "", "Hello", "", "", "How", "Are", "You", "Today"])
4. 6 pp: List(["", "", "", "", "", ""])
5. 1 pp: List([""])
6. 1 pp: List(["Hello-o-o??"])
7. 0 pp: List([""])

Pascal[edit]

Works with: Free_Pascal
program TokenizeString;
 
{$mode objfpc}{$H+}
 
uses
SysUtils, Classes;
const
TestString = 'Hello,How,Are,You,Today';
var
Tokens: TStringList;
I: Integer;
begin
// Uses FCL facilities, "harder" algorithm not implemented
Tokens := TStringList.Create;
try
Tokens.Delimiter := ',';
Tokens.DelimitedText := TestString;
Tokens.Delimiter := '.'; // For example
// To standard Output
WriteLn(Format('Tokenize from: "%s"', [TestString]));
WriteLn(Format('to: "%s"',[Tokens.DelimitedText]));
finally
Tokens.Free;
end;
end.

The result is:

Tokenize from: "Hello,How,Are,You,Today"
to:            "Hello.How.Are.You.Today"

Perl[edit]

print join('.', split /,/, 'Hello,How,Are,You,Today'), "\n";

CLI one-liner form:

echo "Hello,How,Are,You,Today" | perl -aplF/,/ -e '$" = "."; $_ = "@F";'

which is a compact way of telling Perl to do

BEGIN { $/ = "\n"; $\ = "\n"; }
LINE: while (defined($_ = <ARGV>)) {
chomp $_;
our(@F) = split(/,/, $_, 0);
$" = '.';
$_ = "@F";
}
continue {
die "-p destination: $!\n" unless print $_;
}

Perl 6[edit]

Works with: Rakudo version #22 "Thousand Oaks"
'Hello,How,Are,You,Today'.split(',').join('.').say;

Or with function calls:

say join '.', split ',', 'Hello,How,Are,You,Today';

Phix[edit]

?split("Hello,How,Are,You,Today",',')
Output:
{"Hello","How","Are","You","Today"}

PHP[edit]

Works with: PHP version 5.x
<?php
$str = 'Hello,How,Are,You,Today';
echo implode('.', explode(',', $str));
?>

PicoLisp[edit]

(mapcar pack
(split (chop "Hello,How,Are,You,Today") ",") )

Pike[edit]

("Hello,How,Are,You,Today" / ",") * ".";

PL/I[edit]

tok: Proc Options(main);
declare s character (100) initial ('Hello,How,Are,You,Today');
declare n fixed binary (31);
 
n = tally(s, ',')+1;
 
begin;
declare table(n) character (50) varying;
declare c character (1);
declare (i, k) fixed binary (31);
 
table = ''; k = 1;
do i = 1 to length(s);
c = substr(s, i, 1);
if c = ',' then k = k + 1;
else table(k) = table(k) || c;
end;
 
/* display the table */
table = table || '.';
put skip list (string(table));
end;
end;
Output:
Hello.How.Are.You.Today

Pop11[edit]

The natural solution in Pop11 uses lists.

There are built in libraries for tokenising strings, illustrated below, along with code that the user could create for the task.

First show the use of sysparse_string to break up a string and make a list of strings.

;;; Make a list of strings from a string using space as separator
lvars list;
sysparse_string('the cat sat on the mat') -> list;
;;; print the list of strings
list =>
** [the cat sat on the mat]

By giving it an extra parameter 'true' we can make it recognize numbers and produce a list of strings and numbers

lvars list;
sysparse_string('one 1 two 2 three 3 four 4', true) -> list;
;;; print the list of strings and numbers
list =>
** [one 1 two 2 three 3 four 4]
;;; check that first item is a string and second an integer
isstring(list(1))=>
** <true>
isinteger(list(2))=>
** <true>

Now show some uses of the built in procedure sys_parse_string, which allows more options:

;;; Make pop-11 print strings with quotes
true -> pop_pr_quotes;
;;;
;;; Create a string of tokens using comma as token separator
lvars str='Hello,How,Are,You,Today';
;;;
;;; Make a list of strings by applying sys_parse_string
;;; to str, using the character `,` as separator (the default
;;; separator, if none is provided, is the space character).
lvars strings;
[% sys_parse_string(str, `,`) %] -> strings;
;;;
;;; print the list of strings
strings =>
** ['Hello' 'How' 'Are' 'You' 'Today']

If {% ... %} were used instead of [% ... %] the result would be a vector (i.e. array) of strings rather than a list of strings.

{% sys_parse_string(str, `,`) %} -> strings;
;;; print the vector
strings =>
** {'Hello' 'How' 'Are' 'You' 'Today'}

It is also possible to give sys_parse_string a 'conversion' procedure, which is applied to each of the tokens. E.g. it could be used to produce a vector of numbers, using the conversion procedure 'strnumber', which converts a string to a number:

lvars numbers;
{% sys_parse_string('100 101 102 103 99.9 99.999', strnumber) %} -> numbers;
;;; the result is a vector containing integers and floats,
;;; which can be printed thus:
numbers =>
** {100 101 102 103 99.9 99.999}

Using lower level pop-11 facilities to tokenise the string:

;;; Declare and initialize variables
lvars str='Hello,How,Are,You,Today';
;;; Iterate over string
lvars ls = [], i, j = 1;
for i from 1 to length(str) do
 ;;; If comma
if str(i) = `,` then
 ;;; Prepend word (substring) to list
cons(substring(j, i - j, str), ls) -> ls;
i + 1 -> j;
endif;
endfor;
;;; Prepend final word (if needed)
if j <= length(str) then
cons(substring(j, length(str) - j + 1, str), ls) -> ls;
endif;
;;; Reverse the list
rev(ls) -> ls;

Since the task requires to use array we convert list to array

;;; Put list elements and lenght on the stack
destlist(ls);
;;; Build a vector from them
lvars ar = consvector();
;;; Display in a loop, putting trailing period
for i from 1 to length(ar) do
printf(ar(i), '%s.');
endfor;
printf('\n');

We could use list directly for printing:

for i in ls do
printf(i, '%s.');
endfor;

so the conversion to vector is purely to satisfy task formulation.

PowerShell[edit]

Works with: PowerShell version 1
$words = "Hello,How,Are,You,Today".Split(',')
[string]::Join('.', $words)
Works with: PowerShell version 2
$words = "Hello,How,Are,You,Today" -split ','
$words -join '.'
Works with: PowerShell version 2

The StringSplitOptions enumeration weeds out the return of empty elements.

 
"Hello,How,Are,You,Today", ",,Hello,,Goodbye,," | ForEach-Object {($_.Split(',',[StringSplitOptions]::RemoveEmptyEntries)) -join "."}
 
Output:
Hello.How.Are.You.Today
Hello.Goodbye

Prolog[edit]

Works with: SWI Prolog
splitup(Sep,[token(B)|BL]) --> splitup(Sep,B,BL).
splitup(Sep,[A|AL],B) --> [A], {\+ [A] = Sep }, splitup(Sep,AL,B).
splitup(Sep,[],[B|BL]) --> Sep, splitup(Sep,B,BL).
splitup(_Sep,[],[]) --> [].
start :-
phrase(splitup(",",Tokens),"Hello,How,Are,You,Today"),
phrase(splitup(".",Tokens),Backtogether),
string_to_list(ABack,Backtogether),
writeln(ABack).
Output:
 ?- start.
 Hello.How.Are.You.Today
Works with: SWI Prolog 7

Using the SWI Prolog string data type and accompanying predicates, this can be accomplished in a few lines in the top level:

 
?- split_string("Hello,How,Are,You,Today", ",", "", Split),
| atomics_to_string(Split, ".", PeriodSeparated),
| writeln(PeriodSeparated).
Hello.How.Are.You.Today
 

Python[edit]

Works with: Python version 2.5
Works with: Python version 3.0
text = "Hello,How,Are,You,Today"
tokens = text.split(',')
print ('.'.join(tokens))

Or if interpretation of the task description means you don't need to keep an intermediate array:

print ('.'.join('Hello,How,Are,You,Today'.split(',')))

Q[edit]

words: "," vs "Hello,How,Are,You,Today"
"." sv words
Output:
"Hello.How.Are.You.Today"

R[edit]

text <- "Hello,How,Are,You,Today"
junk <- strsplit(text, split=",")
print(paste(unlist(junk), collapse="."))

or the one liner

paste(unlist(strsplit(text, split=",")), collapse=".")

Racket[edit]

 
#lang racket
(string-join (string-split "Hello,How,Are,You,Today" ",") ".")
;; -> "Hello.How.Are.You.Today"
 

Raven[edit]

'Hello,How,Are,You,Today' ',' split '.' join print

REBOL[edit]

print ["Original:"  original: "Hello,How,Are,You,Today"]
tokens: parse original ","
dotted: "" repeat i tokens [append dotted rejoin [i "."]]
print ["Dotted: " dotted]
Output:
 Original: Hello,How,Are,You,Today
 Dotted:   Hello.How.Are.You.Today.

Retro[edit]

{{
 : char ( -$ ) " " ;
 : tokenize ( $-$$ )
@char ^strings'splitAtChar withLength 1- over + 0 swap ! tempString ;
 : action ( $- )
keepString ^buffer'add ;
---reveal---
 : split ( $cb- )
^buffer'set !char
char ^strings'append
[ tokenize action dup 1 <> ] while drop
^buffer'get drop ;
}}

This will suffice to split a string into an array of substrings. It is used like this:

create strings 100 allot
"Hello,How,Are,You,Today" ', strings split

Since the buffer' vocabulary creates a zero-terminated buffer, we can display it using the each@ combinator and a simple quote:

strings [ @ "%s." puts ] ^types'STRING each@

REXX[edit]

version 1[edit]

This REXX version doesn't append a period to the last word in the list.

/*REXX program separates a string of comma-delimited words, and echoes. */
sss = 'Hello,How,Are,You,Today' /*words seperated by commas (,). */
say 'input string =' sss /*display the original string. */
new=sss /*make a copy of the string. */
/* [↓] string NEW is destroyed. */
do items=1 until new=='' /*keep going until NEW is empty.*/
parse var new a.items ',' new /*parse words delinated by comma.*/
end /*items*/ /* [↑] the array is named A. */
 
say; say 'Words in the string:' /*display a header for the list. */
 
do j=1 for items /*now, display all the words. */
say a.j || left('.', j\==items) /*append period to word, maybe. */
end /*j*/ /* [↑] don't append "." if last.*/
 
say 'End-of-list.' /*display a trailer for the list.*/
/*stick a fork in it, we're done.*/
Output:
input string = Hello,How,Are,You,Today
 
Words in the string:
Hello.
How.
Are.
You.
Today
End-of-list.

version 2[edit]

/*REXX program to separate a string of comma-delimited words and echo */
sss='Hello,How,Are,You,Today'
say 'input string='sss
say ''
say 'Words in the string:'
ss =translate(sss,' ',',')
Do i=1 To words(ss)
say word(ss,i)'.'
End
say 'End-of-list.'

output is almost identical to REXX version 1.

Ring[edit]

 
see substr("Hello,How,Are,You,Today", ",", ".")
 

Ruby[edit]

puts "Hello,How,Are,You,Today".split(',').join('.')

Rust[edit]

fn main() {
let s = "Hello,How,Are,You,Today";
let tokens: Vec<&str> = s.split(",").collect();
println!("{}", tokens.join("."));
}


S-lang[edit]

variable a = strchop("Hello,How,Are,You,Today", ',', 0);
print(strjoin(a, "."));
Output:
"Hello.How.Are.You.Today"

Scala[edit]

println("Hello,How,Are,You,Today" split "," mkString ".")

Scheme[edit]

Works with: Guile
(use-modules (ice-9 regex))
(define s "Hello,How,Are,You,Today")
(define words (map match:substring (list-matches "[^,]+" s)))
 
(do ((n 0 (+ n 1))) ((= n (length words)))
(display (list-ref words n))
(if (< n (- (length words) 1))
(display ".")))

(with SRFI 13)

(define s "Hello,How,Are,You,Today")
(define words (string-tokenize s (char-set-complement (char-set #\,))))
(define t (string-join words "."))
Works with: Gauche Scheme
(print
(string-join
(string-split "Hello,How,Are,You,Today" #\,)
"."))
Output:
Hello.How.Are.You.Today

Seed7[edit]

var array string: tokens is 0 times "";
 
tokens := split("Hello,How,Are,You,Today", ",");

Self[edit]

| s = 'Hello,How,Are,You,Today' |
((s splitOn: ',') joinUsing: '.') printLine.
 

Sidef[edit]

'Hello,How,Are,You,Today'.split(',').join('.').say;

Slate[edit]

('Hello,How,Are,You,Today' splitWith: $,) join &separator: '.'.

Smalltalk[edit]

|array |
array := 'Hello,How,Are,You,Today' subStrings: $,.
array fold: [:concatenation :string | concatenation, '.', string ]

Some implementations also have a join: convenience method that allows the following shorter solution:

('Hello,How,Are,You,Today' subStrings: $,) join: '.'

The solution displaying a trailing period would be:

|array |
array := 'Hello,How,Are,You,Today' subStrings: $,.
array inject: '' into: [:concatenation :string | concatenation, string, '.' ]

SNOBOL4[edit]

For this task, it's convenient to define Perl-style split( ) and join( ) functions.

        define('split(chs,str)i,j,t,w2') :(split_end)
split t = table()
sp1 str pos(0) (break(chs) | rem) $ t<i = i + 1>
+ span(chs) (break(chs) | '') . w2 = w2 :s(sp1)
* t<i> = differ(str,'') str ;* Uncomment for CSnobol
split = array(i)
sp2 split<j = j + 1> = t<j> :s(sp2)f(return)
split_end
 
define('join(ch,a)i,') :(join_end)
join join = join a<i = i + 1>
join = join ?a<i + 1> ch :s(join)f(return)
join_end
 
* # Test and display
output = join('.',split(',','Hello,How,Are,You,Today'))
end
Output:
 Hello.How.Are.You.Today

Standard ML[edit]

val splitter = String.tokens (fn c => c = #",");
val main = (String.concatWith ".") o splitter;

Test:

- main "Hello,How,Are,You,Today"
val it = "Hello.How.Are.You.Today" : string

Swift[edit]

Works with: Swift version 2.x
let text = "Hello,How,Are,You,Today"
let tokens = text.characters.split(",").map{String($0)} // for single-character separator
print(tokens)
let result = tokens.joinWithSeparator(".")
print(result)
Works with: Swift version 1.x
let text = "Hello,How,Are,You,Today"
let tokens = split(text, { $0 == "," }) // for single-character separator
println(tokens)
let result = ".".join(tokens)
println(result)
For multi-character separators:
import Foundation
 
let text = "Hello,How,Are,You,Today"
let tokens = text.componentsSeparatedByString(",")
print(tokens)

Tcl[edit]

Generating a list form a string by splitting on a comma:

split $string ","

Joining the elements of a list by a period:

join $list "."

Thus the whole thing would look like this:

puts [join [split "Hello,How,Are,You,Today" ","] "."]

If you'd like to retain the list in a variable with the name "words", it would only be marginally more complex:

puts [join [set words [split "Hello,How,Are,You,Today" ","]] "."]

(In general, the regexp command is also used in Tcl for tokenization of strings, but this example does not need that level of complexity.)

tr[edit]

tr knows nothing about arrays, so this solution only changes each comma to a period.

echo 'Hello,How,Are,You,Today' | tr ',' '.'

TUSCRIPT[edit]

 
$$ MODE TUSCRIPT
SET string="Hello,How,Are,You,Today"
SET string=SPLIT (string,":,:")
SET string=JOIN (string,".")
 

TXR[edit]

Collecting tokens which consist of non-empty sequences of non-commas.

@(next :list "Hello,How,Are,You,Today")
@(coll)@{token /[^,]+/}@(end)
@(output)
@(rep)@token.@(last)@token@(end)
@(end)

Different approach. Collect tokens, each of which is a piece of text which either terminates before a comma, or else extends to the end of the line.

@(next :list "Hello,How,Are,You,Today")
@(coll)@(maybe)@token,@(or)@token@(end)@(end)
@(output)
@(rep)@token.@(last)@token@(end)
@(end)

Using TXR Lisp:

txr -p '(cat-str (split-str "Hello,How,Are,You,Today" ",") ".")'
Hello.How.Are.You.Today

UNIX Shell[edit]

Works with: Bourne Shell
string='Hello,How,Are,You,Today'
 
(IFS=,
printf '%s.' $string
echo)

Works with: Bourne Again SHell
Works with: Public Domain Korn SHell version 5.2.14
#! /bin/bash
stripchar-l ()
#removes the specified character from the left side of the string
#USAGE: stripchar "stuff" "s" --> tuff
{
string="$1";
string=${string#"$2"};
 
echo "$string"
}
 
join ()
#join a string of characters on a specified delimiter
#USAGE: join "1;2;3;4" ";" "," --> 1,2,3,4
{
local result="";
local list="$1";
OLDIFS="$IFS";
local IFS=${2-" "};
local output_field_seperator=${3-" "};
 
for element in $list;
do
result="$result$output_field_seperator$element";
done;
 
result="`stripchar-l "$result" "$output_field_seperator"`";
echo "$result";
IFS="$OLDIFS"
}
 
split ()
{
#split a string of characters on a specified delimiter
#USAGE: split "1;2;3;4" ";" --> 1 2 3 4
local list="$1";
local input_field_seperator=${2-" "};
local output_field_seperator=" ";
 
#defined in terms of join
join "$list" "$input_field_seperator" "$output_field_seperator"
}
 
strtokenize ()
{
#splits up a string of characters into tokens,
#based on a user supplied delimiter
#USAGE:strtokenize "1;2;3;4" ";" ":" --> 1:2:3:4
local list="$1";
local input_delimiter=${2-" "};
local output_delimiter=${3-" "};
local contains_a_space=" "; #added to highlight the use
#of " " as an argument to join
 
#splits it input then joins it with a user supplied delimiter
join "$( split "$list" "$input_delimiter" )" \
"$contains_a_space" "$output_delimiter";
}

Example

 strtokenize "Hello,How,Are,You,Today" "," "." 
Hello.How.Are.You.Today

Works with: Almquist Shell
Works with: bash
Works with: pdksh
Works with: ksh93
Works with: zsh
 
string1="Hello,How,Are,You,Today"
elements_quantity=$(echo $string1|tr "," "\n"|wc -l)
 
present_element=1
while [ $present_element -le $elements_quantity ];do
echo $string1|cut -d "," -f $present_element|tr -d "\n"
if [ $present_element -lt $elements_quantity ];then echo -n ".";fi
present_element=$(expr $present_element + 1)
done
echo
 
# or to cheat
echo "Hello,How,Are,You,Today"|tr "," "."

UnixPipes[edit]

Works with: Bourne Shell
token() {
(IFS=, read -r A B; echo "$A".; test -n "$B" && (echo "$B" | token))
}
 
echo "Hello,How,Are,You" | token

Ursa[edit]

decl string text
set text "Hello,How,Are,You,Today"
decl string<> tokens
set tokens (split text ",")
for (decl int i) (< i (size tokens)) (inc i)
out tokens<i> "." console
end for
out endl console

Ursala[edit]

A list of strings is made by separating at the commas using the library function, sep. A single string is then made by joining the list of strings with periods using the library function, mat. Each of these is a second order function parameterized by the delimiter. Character literals are preceded by a backquote.

#import std
 
token_list = sep`, 'Hello,How,Are,You,Today'
 
#cast %s
 
main = mat`. token_list
Output:
 'Hello.How.Are.You.Today'

Vala[edit]

// declare test string
string s = "Hello,How,Are,You,Today";
// create array of strings, could use var words instead if desired
string[] words = s.split(",");
// create string by joining array of strings with .
string joined = string.joinv(".", words);

VBScript[edit]

 
s = "Hello,How,Are,You,Today"
WScript.StdOut.Write Join(Split(s,","),".")
 
Output:
Hello.How.Are.You.Today

Vedit macro language[edit]

Vedit does not use the concepts of array or list. Normally, the text is processed as text in an edit buffer.

However, this example shows how to split the text into multiple text registers (10, 11, 12 etc.). The contents of each text register is then displayed to user, separated by a period.

Buf_Switch(Buf_Free)
Ins_Text("Hello,How,Are,You,Today")
 
// Split the text into text registers 10, 11, ...
BOF
#1 = 9
Repeat(ALL) {
#1++
#2 = Cur_Pos
Search(",", ADVANCE+ERRBREAK)
Reg_Copy_Block(#1, #2, Cur_Pos-1)
}
Reg_Copy_Block(#1, #2, EOB_Pos)
 
// Display the list
for (#3 = 10; #3 <= #1; #3++) {
Reg_Type(#3) Message(".")
}
 
Buf_Quit(OK)

WinBatch[edit]

text  = 'Hello,How,Are,You,Today'
result = ''
BoxOpen('WinBatch Tokenizing Example', '')
for ix = 1 to itemcount(text,',')
result = result : itemextract(ix, text, ',') : '.'
BoxText(result)
next
display(10, 'End of Program', 'Dialog and program will close momentarily.')
BoxShut()
Output:
Hello.How.Are.You.Today.

Wortel[edit]

@join "." @split "," "Hello,How,Are,You,Today"

Returns

"Hello.How.Are.You.Today"

XPL0[edit]

string 0;
include c:\cxpl\codes;
int I, J, K, Char;
char String, Array(5,6); \5 words and 5 maximum chars + terminating 0
 
[String:= "Hello,How,Are,You,Today";
I:= 0; K:= 0;
repeat J:= 0;
loop [Char:= String(I);
I:= I+1;
if Char=^, or Char=0 then quit;
Array(K,J):= Char;
J:= J+1;
];
Array(K,J):= 0; \terminate word
K:= K+1; \next word in array
until K>=5;
for K:= 4 downto 0 do [Text(0, addr Array(K,0)); ChOut(0, ^.)];
CrLf(0);
]

The 'addr' operator is used to fetch the 32-bit address of Array rather than a byte from the character array.

Output (done in reverse order to emphasize the tokens are indeed separate):

Today.You.Are.How.Hello.

zkl[edit]

"Hello,How,Are,You,Today".split(",").concat(".").println();
Hello.How.Are.You.Today

Zsh[edit]

str='Hello,How,Are,You,Today'
tokens=(${(s:,:)str})
print ${(j:.:)tokens}

Or, using SH_SPLIT_WORD:

str='Hello,How,Are,You,Today'
IFS=, echo ${(j:.:)${=str}}