User input/Text
Input a string and the integer 75000 from the text console.
You are encouraged to solve this task according to the task description, using any language you may know.
- Task
See also: User input/Graphical
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11l
V string = input(‘Input a string: ’)
V number = Float(input(‘Input a number: ’))
4ME
P:I is ns
AArch64 Assembly
//Consts
.equ BUFFERSIZE, 100
.equ STDIN, 0 // linux input console
.equ STDOUT, 1 // linux output console
.equ READ, 63
.equ WRITE, 64
.equ EXIT, 93
.data
enterText: .asciz "Enter text: "
carriageReturn: .asciz "\n"
//Read Buffer
.bss
buffer: .skip BUFFERSIZE
.text
.global _start
quadEnterText: .quad enterText
quadBuffer: .quad buffer
quadCarriageReturn: .quad carriageReturn
writeMessage:
mov x2,0 // reset size counter to 0
checkSize: // get size of input
ldrb w1,[x0,x2] // load char with offset of x2
add x2,x2,#1 // add 1 char read legnth
cbz w1,output // if char found
b checkSize // loop
output:
mov x1,x0 // move string address into system call func parm
mov x0,STDOUT
mov x8,WRITE
svc 0 // trigger system write
ret
_start:
//Output enter text
ldr x0,quadEnterText // load enter message
bl writeMessage // output enter message
//Read User Input
mov x0,STDIN // linux input console
ldr x1,quadBuffer // load buffer address
mov x2,BUFFERSIZE // load buffer size
mov x8,READ // request to read data
svc 0 // trigger system read input
//Output User Message
mov x2, #0 // prep end of string
ldr x1,quadBuffer // load buffer address
strb w2,[x1, x0] // store x2 0 byte at the end of input string, offset x0
ldr x0,quadBuffer // load buffer address
bl writeMessage
//Output newline
ldr x0,quadCarriageReturn
bl writeMessage
//End Program
mov x0, #0 // return code
mov x8, #EXIT // request to exit program
svc 0 // trigger end of program
Action!
INCLUDE "H6:REALMATH.ACT"
PROC Main()
CHAR ARRAY sUser(255)
REAL r75000,rUser
Put(125) PutE() ;clear the screen
ValR("75000",r75000)
Print("Please enter a text: ")
InputS(sUser)
DO
Print("Please enter number ")
PrintR(r75000) Print(": ")
InputR(rUser)
UNTIL RealEqual(rUser,r75000)
OD
PutE()
Print("Text: ") PrintE(sUser)
Print("Number: ") PrintRE(rUser)
RETURN
- Output:
Screenshot from Atari 8-bit computer
Please enter a text: Atari 130XE Please enter number 75000: 123 Please enter number 75000: 76000 Please enter number 75000: 75000 Text: Atari 130XE Number: 75000
Ada
function Get_String return String is
Line : String (1 .. 1_000);
Last : Natural;
begin
Get_Line (Line, Last);
return Line (1 .. Last);
end Get_String;
function Get_Integer return Integer is
S : constant String := Get_String;
begin
return Integer'Value (S);
-- may raise exception Constraint_Error if value entered is not a well-formed integer
end Get_Integer;
The functions above may be called as shown below
My_String : String := Get_String;
My_Integer : Integer := Get_Integer;
Another:
with Ada.Text_IO, Ada.Integer_Text_IO;
procedure User_Input is
I : Integer;
begin
Ada.Text_IO.Put ("Enter a string: ");
declare
S : String := Ada.Text_IO.Get_Line;
begin
Ada.Text_IO.Put_Line (S);
end;
Ada.Text_IO.Put ("Enter an integer: ");
Ada.Integer_Text_IO.Get(I);
Ada.Text_IO.Put_Line (Integer'Image(I));
end User_Input;
Unbounded IO:
with
Ada.Text_IO,
Ada.Integer_Text_IO,
Ada.Strings.Unbounded,
Ada.Text_IO.Unbounded_IO;
procedure User_Input2 is
S : Ada.Strings.Unbounded.Unbounded_String;
I : Integer;
begin
Ada.Text_IO.Put("Enter a string: ");
S := Ada.Strings.Unbounded.To_Unbounded_String(Ada.Text_IO.Get_Line);
Ada.Text_IO.Put_Line(Ada.Strings.Unbounded.To_String(S));
Ada.Text_IO.Unbounded_IO.Put_Line(S);
Ada.Text_IO.Put("Enter an integer: ");
Ada.Integer_Text_IO.Get(I);
Ada.Text_IO.Put_Line(Integer'Image(I));
end User_Input2;
ALGOL 68
print("Enter a string: ");
STRING s := read string;
print("Enter a number: ");
INT i := read int;
~
ALGOL W
begin
string(80) s;
integer n;
write( "Enter a string > " );
read( s );
write( "Enter an integer> " );
read( n )
end.
Amazing Hopper
Version: hopper-FLOW!
#include <flow.h>
#import lib/input.bas.lib
#include include/flow-input.h
DEF-MAIN(argv,argc)
CLR-SCR
MSET( número, cadena )
LOCATE(2,2), PRNL( "Input an string : "), LOC-COL(20), LET( cadena := READ-STRING( cadena ) )
LOCATE(3,2), PRNL( "Input an integer: "), LOC-COL(20), LET( número := INT( VAL(READ-NUMBER( número )) ) )
LOCATE(5,2), PRNL( cadena, "\n ",número )
END
- Output:
Input an string : Juanita Pérez Input an integer: 75000.789 Juanita Pérez 75000
APL
str←⍞
int←⎕
ARM Assembly
/* ARM assembly Raspberry PI */
/* program inputText.s */
/* Constantes */
.equ BUFFERSIZE, 100
.equ STDIN, 0 @ Linux input console
.equ STDOUT, 1 @ Linux output console
.equ EXIT, 1 @ Linux syscall
.equ READ, 3 @ Linux syscall
.equ WRITE, 4 @ Linux syscall
/* Initialized data */
.data
szMessDeb: .asciz "Enter text : \n"
szMessNum: .asciz "Enter number : \n"
szCarriageReturn: .asciz "\n"
/* UnInitialized data */
.bss
sBuffer: .skip BUFFERSIZE
/* code section */
.text
.global main
main: /* entry of program */
push {fp,lr} /* saves 2 registers */
ldr r0,iAdrszMessDeb
bl affichageMess
mov r0,#STDIN @ Linux input console
ldr r1,iAdrsBuffer @ buffer address
mov r2,#BUFFERSIZE @ buffer size
mov r7, #READ @ request to read datas
swi 0 @ call system
ldr r1,iAdrsBuffer @ buffer address
mov r2,#0 @ end of string
strb r2,[r1,r0] @ store byte at the end of input string (r0 contains number of characters)
ldr r0,iAdrsBuffer @ buffer address
bl affichageMess
ldr r0,iAdrszCarriageReturn
bl affichageMess
ldr r0,iAdrszMessNum
bl affichageMess
mov r0,#STDIN @ Linux input console
ldr r1,iAdrsBuffer @ buffer address
mov r2,#BUFFERSIZE @ buffer size
mov r7, #READ @ request to read datas
swi 0 @ call system
ldr r1,iAdrsBuffer @ buffer address
mov r2,#0 @ end of string
strb r2,[r1,r0] @ store byte at the end of input string (r0
@
ldr r0,iAdrsBuffer @ buffer address
bl conversionAtoD @ conversion string in number in r0
100: /* standard end of the program */
mov r0, #0 @ return code
pop {fp,lr} @restaur 2 registers
mov r7, #EXIT @ request to exit program
swi 0 @ perform the system call
iAdrszMessDeb: .int szMessDeb
iAdrszMessNum: .int szMessNum
iAdrsBuffer: .int sBuffer
iAdrszCarriageReturn: .int szCarriageReturn
/******************************************************************/
/* display text with size calculation */
/******************************************************************/
/* r0 contains the address of the message */
affichageMess:
push {fp,lr} /* save registres */
push {r0,r1,r2,r7} /* save others registers */
mov r2,#0 /* counter length */
1: /* loop length calculation */
ldrb r1,[r0,r2] /* read octet start position + index */
cmp r1,#0 /* if 0 its over */
addne r2,r2,#1 /* else add 1 in the length */
bne 1b /* and loop */
/* so here r2 contains the length of the message */
mov r1,r0 /* address message in r1 */
mov r0,#STDOUT /* code to write to the standard output Linux */
mov r7, #WRITE /* code call system "write" */
swi #0 /* call systeme */
pop {r0,r1,r2,r7} /* restaur others registers */
pop {fp,lr} /* restaur des 2 registres */
bx lr /* return */
/******************************************************************/
/* Convert a string to a number stored in a registry */
/******************************************************************/
/* r0 contains the address of the area terminated by 0 or 0A */
/* r0 returns a number */
conversionAtoD:
push {fp,lr} @ save 2 registers
push {r1-r7} @ save others registers
mov r1,#0
mov r2,#10 @ factor
mov r3,#0 @ counter
mov r4,r0 @ save address string -> r4
mov r6,#0 @ positive sign by default
mov r0,#0 @ initialization to 0
1: /* early space elimination loop */
ldrb r5,[r4,r3] @ loading in r5 of the byte located at the beginning + the position
cmp r5,#0 @ end of string -> end routine
beq 100f
cmp r5,#0x0A @ end of string -> end routine
beq 100f
cmp r5,#' ' @ space ?
addeq r3,r3,#1 @ yes we loop by moving one byte
beq 1b
cmp r5,#'-' @ first character is -
moveq r6,#1 @ 1 -> r6
beq 3f @ then move on to the next position
2: /* beginning of digit processing loop */
cmp r5,#'0' @ character is not a number
blt 3f
cmp r5,#'9' @ character is not a number
bgt 3f
/* character is a number */
sub r5,#48
ldr r1,iMaxi @ check the overflow of the register
cmp r0,r1
bgt 99f @ overflow error
mul r0,r2,r0 @ multiply par factor 10
add r0,r5 @ add to r0
3:
add r3,r3,#1 @ advance to the next position
ldrb r5,[r4,r3] @ load byte
cmp r5,#0 @ end of string -> end routine
beq 4f
cmp r5,#0x0A @ end of string -> end routine
beq 4f
b 2b @ loop
4:
cmp r6,#1 @ test r6 for sign
moveq r1,#-1
muleq r0,r1,r0 @ if negatif, multiply par -1
b 100f
99: /* overflow error */
ldr r0,=szMessErrDep
bl affichageMess
mov r0,#0 @ return zero if error
100:
pop {r1-r7} @ restaur other registers
pop {fp,lr} @ restaur 2 registers
bx lr @return procedure
/* constante program */
iMaxi: .int 1073741824
szMessErrDep: .asciz "Too large: overflow 32 bits.\n"
Arturo
str: input "Enter a string: "
num: to :integer input "Enter an integer: "
print ["Got:" str "," num]
- Output:
Enter a string: hello world Enter an integer: 1986 Got: hello world , 1986
AutoHotkey
Windows console
DllCall("AllocConsole")
FileAppend, please type something`n, CONOUT$
FileReadLine, line, CONIN$, 1
msgbox % line
FileAppend, please type '75000'`n, CONOUT$
FileReadLine, line, CONIN$, 1
msgbox % line
Input Command
this one takes input regardless of which application has focus.
TrayTip, Input:, Type a string:
Input(String)
TrayTip, Input:, Type an int:
Input(Int)
TrayTip, Done!, Input was recieved.
Msgbox, You entered "%String%" and "%Int%"
ExitApp
Return
Input(ByRef Output)
{
Loop
{
Input, Char, L1, {Enter}{Space}
If ErrorLevel contains Enter
Break
Else If ErrorLevel contains Space
Output .= " "
Else
Output .= Char
TrayTip, Input:, %Output%
}
}
AWK
This demo shows a same-line prompt, and that the integer i becomes 0 if the line did not parse as an integer.
~/src/opt/run $ awk 'BEGIN{printf "enter a string: "}{s=$0;i=$0+0;print "ok,"s"/"i}'
enter a string: hello world
ok,hello world/0
75000
ok,75000/75000
Axe
Since integers in Axe are two bytes, 75000 exceeds the maximum integer limit (65535). The task has been adjusted accordingly so the integer must be 7500 instead.
In this implementation, the number displayed is effectively the number entered modulo 65536.
Also, in the string entry, the data is a string of tokens, not a string of characters. Thankfully, the most common ASCII symbols (A-Z, 0-9, and some symbols) have the same values as their token counterparts. This means that this example will work for those symbols, but other tokens (especially multi-byte tokens) will cause problems. See this table of tokens and their codes for reference.
Disp "String:"
input→A
length(A)→L
.Copy the string to a safe location
Copy(A,L₁,L)
.Display the string
Disp "You entered:",i
For(I,0,L-1)
Disp {L₁+I}►Char
End
Disp i
Disp "Integer:",i
input→B
length(B)→L
.Parse the string and convert to an integer
0→C
For(I,0,L-1)
{B+I}-'0'→N
If N>10
.Error checking
Disp "Not a number",i
Return
End
C*10+N→C
End
.Display and check the integer
Disp "You entered:",i,C►Dec,i
If C≠7500
Disp "That isn't 7500"
End
BabyCobol
* NB: whitespace insignificance and case insensitivity
* are used in the field name.
IDENTIFICATION DIVISION.
PROGRAM-ID. USER INPUT.
DATA DIVISION.
01 HUNDRED CHAR STRING PICTURE IS X(100).
01 FIVE DIGIT NUMBER PICTURE IS 9(5).
PROCEDURE DIVISION.
DISPLAY "Enter a string of appropriate length: " WITH NO ADVANCING
ACCEPT HundredChar String.
DISPLAY "Enter a number (preferably 75000): " WITH NO ADVANCING
ACCEPT FiveDigit Number.
BASIC
Many BASICs will automatically append a question mark (?
) to the end of the prompt if the prompt is followed by a semicolon (;
).
(Some of those will skip the question mark if the prompt is followed by a comma (,
) instead of a semicolon.)
This isn't a hard-and-fast rule -- for example, Chipmunk Basic never appends a question mark.
INPUT "Enter a string"; s$
INPUT "Enter a number: ", i%
Output (QBasic):
Enter a string? foo Enter a number: 1
Applesoft BASIC
10 INPUT "ENTER A STRING: "; S$
20 INPUT "ENTER A NUMBER: "; I : I = INT(I)
Commodore BASIC
When using the prompt feature of the INPUT
command, the string literal must be followed by a semicolon and then the string variable, or else a ?SYNTAX ERROR
will occur. The question mark prompt is always presented with the INPUT
command. Any other behavior would have to come from a user-built routine using the GET
command.
Also, when a numeric variable is provided for input, the computer will make repeated attempts to obtain valid input from the user until the input can be clearly interpreted as a numeric value.
10 input "what is a word i should remember";a$
20 print "thank you."
30 input "will you please type the number 75000";nn
40 if nn<>75000 then print "i'm sorry, that's not right.":goto 30
50 print "thank you.":print "you provided the following values:"
60 print a$
70 print nn
80 end
Output
READY. RUN WHAT IS A WORD I SHOULD REMEMBER? PANCAKE THANK YOU. WILL YOU PLEASE TYPE THE NUMBER 75000? NO. ?REDO FROM START WILL YOU PLEASE TYPE THE NUMBER 75000? 848 I'M SORRY, THAT'S NOT RIGHT. WILL YOU PLEASE TYPE THE NUMBER 75000? 75000 THANK YOU. YOU PROVIDED THE FOLLOWING VALUES: PANCAKE 75000 READY. █
IS-BASIC
100 INPUT PROMPT "Enter a number: ":NUM
110 INPUT PROMPT "Enter a string: ":ST$
QB64
The use of a Long int (l&) is required as the Int variable type is only 2 bytes and even if _UNSIGNED can only hold values up to 65535. If no value is entered for either input value, it will continue to hold whatever value it did previously.
Input "Enter text and a number", s$, l&
Print s$
Print l&
BASIC256
input string "Please enter a string: ", s
do
input "Please enter 75000 : ", i
until i = 75000
print
print s, i
Run BASIC
input "Please enter a string: "; s$
while i <> 75000
input "Please enter 75000 : "; i
wend
print
print s$; chr$(9); i
True BASIC
PRINT "Please enter a string";
INPUT s$
DO
PRINT "Please enter 75000 ";
INPUT i
LOOP Until i = 75000
PRINT
PRINT s$, i
END
Yabasic
input "Please enter a string: " s$
repeat
input "Please enter 75000 : " i
until i = 75000
print
print s$, chr$(9), i
Sinclair ZX81 BASIC
10 PRINT "ENTER A STRING"
20 INPUT S$
30 PRINT "YOU ENTERED: ";S$
40 PRINT "NOW ENTER THE NUMBER 75000"
50 INPUT N
60 IF N=75000 THEN STOP
70 PRINT "NO, ";
80 GOTO 40
Batch File
@echo off
set /p var=
echo %var% 75000
BBC BASIC
INPUT LINE "Enter a string: " string$
INPUT "Enter a number: " number
PRINT "String = """ string$ """"
PRINT "Number = " ; number
Befunge
This prompts for a string and pushes it to the stack a character at a time (~) until end of input (-1).
<>:v:"Enter a string: "
^,_ >~:1+v
^ _@
Numeric input is easier, using the & command.
<>:v:"Enter a number: "
^,_ & @
Bracmat
( doit
= out'"Enter a string"
& get':?mystring
& whl
' ( out'"Enter a number"
& get':?mynumber
& !mynumber:~#
& out'"I said:\"a number\"!"
)
& out$(mystring is !mystring \nmynumber is !mynumber \n)
);
{?} !doit Enter a string abacus Enter a number 75000h I said:"a number"! Enter a number 75000 mystring is abacus mynumber is 75000
C
#include <stdio.h>
#include <stdlib.h>
int main(void)
{
// Get a string from stdin
char str[BUFSIZ];
puts("Enter a string: ");
fgets(str, sizeof(str), stdin);
// Get 75000 from stdin
long num;
char buf[BUFSIZ];
do
{
puts("Enter 75000: ");
fgets(buf, sizeof(buf), stdin);
num = strtol(buf, NULL, 10);
} while (num != 75000);
return EXIT_SUCCESS;
}
#include <gadget/gadget.h>
LIB_GADGET_START
Main
Cls;
String text;
int number=0;
At 5,5; Print "Enter text : ";
Atrow 7; Print "Enter ‘75000’: ";
Atcol 20;
Atrow 5; Fn_let(text, Input ( text, 30 ) );
Free secure text;
Atrow 7; Stack{
while (number!=75000 )
/*into stack, Input() not need var*/
number = Str2int( Input ( NULL, 6 ) );
}Stack_off;
Prnl;
End
- Output:
$ ./tests/input_cons Enter text : Juanita la mañosa Enter ‘75000’: 75000 $
C#
using System;
namespace C_Sharp_Console {
class example {
static void Main() {
string word;
int num;
Console.Write("Enter an integer: ");
num = Console.Read();
Console.Write("Enter a String: ");
word = Console.ReadLine();
}
}
}
C++
#include <iostream>
#include <string>
using namespace std;
int main()
{
// while probably all current implementations have int wide enough for 75000, the C++ standard
// only guarantees this for long int.
long int integer_input;
string string_input;
cout << "Enter an integer: ";
cin >> integer_input;
cout << "Enter a string: ";
cin >> string_input;
return 0;
}
Note: The program as written above only reads the string up to the first whitespace character. To get a complete line into the string, replace
cin >> string_input;
with
getline(cin, string_input);
Note: if a numeric input operation fails, the value is not stored for that operation, plus the fail bit is set, which causes all future stream operations to be ignored (e.g. if a non-integer is entered for the first input above, then nothing will be stored in either the integer and the string). A more complete program would test for an error in the input (with if (!cin) // handle error
) after the first input, and then clear the error (with cin.clear()
) if we want to get further input.
Alternatively, we could read the input into a string first, and then parse that into an int later.
Ceylon
shared void run() {
print("enter any text here");
value text = process.readLine();
print(text);
print("enter the number 75000 here");
if (is Integer number = Integer.parse(process.readLine() else "")) {
print("``number == 75k then number else "close enough"``");
}
else {
print("That was not a number per se.");
}
}
Clojure
(import '(java.util Scanner))
(def scan (Scanner. *in*))
(def s (.nextLine scan))
(def n (.nextInt scan))
COBOL
IDENTIFICATION DIVISION.
PROGRAM-ID. Get-Input.
DATA DIVISION.
WORKING-STORAGE SECTION.
01 Input-String PIC X(30).
01 Input-Int PIC 9(5).
PROCEDURE DIVISION.
DISPLAY "Enter a string:"
ACCEPT Input-String
DISPLAY "Enter a number:"
ACCEPT Input-Int
GOBACK
.
Common Lisp
(format t "Enter some text: ")
(let ((s (read-line)))
(format t "You entered ~s~%" s))
(format t "Enter a number: ")
(let ((n (read)))
(if (numberp n)
(format t "You entered ~d.~%" n)
(format t "That was not a number.")))
Crystal
puts "You entered: #{gets}"
begin
puts "You entered: #{gets.not_nil!.chomp.to_i}"
rescue ex
puts ex
end
Example with valid input:
Hello You entered: Hello 75000 You entered: 75000
Example with invalid input:
Hello You entered: Hello Goodbye Invalid Int32: Goodbye
D
import std.stdio;
void main() {
long number;
write("Enter an integer: ");
readf("%d", &number);
char[] str;
write("Enter a string: ");
readf(" %s\n", &str);
writeln("Read in '", number, "' and '", str, "'");
}
Dart
import 'dart:io' show stdout, stdin;
main() {
stdout.write('Enter a string: ');
final string_input = stdin.readLineSync();
int number_input;
do {
stdout.write('Enter the number 75000: ');
var number_input_string = stdin.readLineSync();
try {
number_input = int.parse(number_input_string);
if (number_input != 75000)
stdout.writeln('$number_input is not 75000!');
} on FormatException {
stdout.writeln('$number_input_string is not a valid number!');
} catch ( e ) {
stdout.writeln(e);
}
} while ( number_input != 75000 );
stdout.writeln('input: $string_input\nnumber: $number_input');
}
Delphi
program UserInputText;
{$APPTYPE CONSOLE}
uses SysUtils;
var
s: string;
lStringValue: string;
lIntegerValue: Integer;
begin
WriteLn('Enter a string:');
Readln(lStringValue);
repeat
WriteLn('Enter the number 75000');
Readln(s);
lIntegerValue := StrToIntDef(s, 0);
if lIntegerValue <> 75000 then
Writeln('Invalid entry: ' + s);
until lIntegerValue = 75000;
end.
Déjà Vu
input s:
!print\ s
!decode!utf-8 !read-line!stdin
local :astring input "Enter a string: "
true
while:
try:
to-num input "Enter the number 75000: "
/= 75000
catch value-error:
true
EasyLang
write "Enter a string: "
a$ = input
print ""
repeat
write "Enter the number 75000: "
h = number input
print ""
until h = 75000
.
print a$ & " " & h
Elena
ELENA 6.x :
import extensions;
public program()
{
var num := new Integer();
console.write("Enter an integer: ").loadLineTo(num);
var word := console.write("Enter a String: ").readLine()
}
Elixir
a = IO.gets("Enter a string: ") |> String.strip
b = IO.gets("Enter an integer: ") |> String.strip |> String.to_integer
f = IO.gets("Enter a real number: ") |> String.strip |> String.to_float
IO.puts "String = #{a}"
IO.puts "Integer = #{b}"
IO.puts "Float = #{f}"
EMal
text string ← ask(text, "Enter a string: ")
int number
for ever
number ← ask(int, "Enter the integer 75000: ")
if number æ 75000 do break end
end
writeLine()
writeLine(string)
writeLine(number)
- Output:
Enter a string: Hello Enter the integer 75000: 75000.12 Enter the integer 75000: 32 Enter the integer 75000: 75000 Hello 75000
Erlang
{ok, [String]} = io:fread("Enter a string: ","~s").
{ok, [Number]} = io:fread("Enter a number: ","~d").
Alternatively, you could use io:get_line to get a string:
String = io:get_line("Enter a string: ").
Euphoria
include get.e
sequence s
atom n
s = prompt_string("Enter a string:")
puts(1, s & '\n')
n = prompt_number("Enter a number:",{})
printf(1, "%d", n)
F#
open System
let ask_for_input s =
printf "%s (End with Return): " s
Console.ReadLine()
[<EntryPoint>]
let main argv =
ask_for_input "Input a string" |> ignore
ask_for_input "Enter the number 75000" |> ignore
0
Factor
"Enter a string: " write
readln
"Enter a number: " write
readln string>number
Falcon
printl("Enter a string:")
str = input()
printl("Enter a number:")
n = int(input())
FALSE
FALSE has neither a string type nor numeric input. Shown instead are routines to parse and echo a word and to parse and interpret a number using the character input command (^).
[[^$' =~][,]#,]w:
[0[^'0-$$9>0@>|~][\10*+]#%]d:
w;! d;!.
Fantom
The 'toInt' method on an input string will throw an exception if the input is not a number.
class Main
{
public static Void main ()
{
Env.cur.out.print ("Enter a string: ").flush
str := Env.cur.in.readLine
echo ("Entered :$str:")
Env.cur.out.print ("Enter 75000: ").flush
Int n
try n = Env.cur.in.readLine.toInt
catch (Err e)
{
echo ("You had to enter a number")
return
}
echo ("Entered :$n: which is " + ((n == 75000) ? "correct" : "wrong"))
}
}
Forth
Input a string
: INPUT$ ( n -- addr n )
PAD SWAP ACCEPT
PAD SWAP ;
Input a number
The only ANS standard number interpretation word is >NUMBER ( ud str len -- ud str len ), which is meant to be the base factor for more convenient (but non-standard) parsing words.
: INPUT# ( -- u true | false )
0. 16 INPUT$ DUP >R
>NUMBER NIP NIP
R> <> DUP 0= IF NIP THEN ;
: INPUT# ( -- n true | d 1 | false )
16 INPUT$ SNUMBER? ;
: INPUT# ( -- n true | false )
16 INPUT$ NUMBER? NIP
DUP 0= IF NIP THEN ;
Note that NUMBER? always leaves a double result on the stack. INPUT# returns a single precision number. If you desire a double precision result, remove the NIP.
: input#
begin
refill drop bl parse-word ( a n)
number error? ( n f)
while ( n)
drop ( --)
repeat ( n)
;
Here is an example that puts it all together:
: TEST
." Enter your name: " 80 INPUT$ CR
." Hello there, " TYPE CR
." Enter a number: " INPUT# CR
IF ." Your number is " .
ELSE ." That's not a number!" THEN CR ;
Fortran
character(20) :: s
integer :: i
print*, "Enter a string (max 20 characters)"
read*, s
print*, "Enter the integer 75000"
read*, i
FreeBASIC
' FB 1.05.0 Win64
Dim s As String
Dim i AS Integer
Input "Please enter a string : "; s
Do
Input "Please enter 75000 : "; i
Loop Until i = 75000
Print
Print s, i
Sleep
Sample input/output
- Output:
Please enter a string : ? Rosetta Please enter 75000 : ? 70000 Please enter 75000 : ? 75000 Rosetta 75000
Frink
s = input["Enter a string: "]
i = parseInt[input["Enter an integer: "]]
FutureBasic
void local fn DoIt
window 1, @"User/input Text"
CFStringRef string = input @"Enter a string:"
print string
CFStringRef number = @""
while ( intval(number) != 75000 )
number = input @"Enter the integer 75000", @"0123456789", YES, 5
wend
print number
end fn
fn DoIt
HandleEvents
GDScript
Run with godot --headless --script <file>
extends MainLoop
func _process(_delta: float) -> bool:
printraw("Input a string: ")
var read_line := OS.read_string_from_stdin() # Mote that this retains the newline.
printraw("Input an integer: ")
var read_integer := int(OS.read_string_from_stdin())
print("read_line = %s" % read_line.trim_suffix("\n"))
print("read_integer = %d" % read_integer)
return true # Exit instead of looping
Go
Go has C-like Scan and Scanf functions for quick and dirty input:
package main
import "fmt"
func main() {
var s string
var i int
if _, err := fmt.Scan(&s, &i); err == nil && i == 75000 {
fmt.Println("good")
} else {
fmt.Println("wrong")
}
}
Code below allows much more control over interaction and error checking.
package main
import (
"bufio"
"fmt"
"os"
"strconv"
"strings"
)
func main() {
in := bufio.NewReader(os.Stdin)
fmt.Print("Enter string: ")
s, err := in.ReadString('\n')
if err != nil {
fmt.Println(err)
return
}
s = strings.TrimSpace(s)
fmt.Print("Enter 75000: ")
s, err = in.ReadString('\n')
if err != nil {
fmt.Println(err)
return
}
n, err := strconv.Atoi(strings.TrimSpace(s))
if err != nil {
fmt.Println(err)
return
}
if n != 75000 {
fmt.Println("fail: not 75000")
return
}
fmt.Println("Good")
}
Groovy
word = System.in.readLine()
num = System.in.readLine().toInteger()
Haskell
import System.IO (hFlush, stdout)
main = do
putStr "Enter a string: "
hFlush stdout
str <- getLine
putStr "Enter an integer: "
hFlush stdout
num <- readLn :: IO Int
putStrLn $ str ++ (show num)
Note: :: IO Int is only there to disambiguate what type we wanted from read. If num were used in a numerical context, its type would have been inferred by the interpreter/compiler. Note also: Haskell doesn't automatically flush stdout when doing input, so explicit flushes are necessary.
hexiscript
print "Enter a string: "
let s scan str
print "Enter a number: "
let n scan int
HolyC
U8 *s;
s = GetStr("Enter a string: ");
U32 *n;
do {
n = GetStr("Enter 75000: ");
} while(Str2I64(n) != 75000);
Print("Your string: %s\n", s);
Print("75000: %d\n", Str2I64(n));
Icon and Unicon
The following works in both Icon and Unicon:
Io
string := File clone standardInput readLine("Enter a string: ")
integer := File clone standardInput readLine("Enter 75000: ") asNumber
J
Solution
require 'misc' NB. load system script
prompt 'Enter string: '
0".prompt 'Enter an integer: '
Note that require'misc'
is old - efforts to optimize by loading misc utilities in a fine grained fashion mean that currently (J 805) that should be require'general/misc/prompt'
and the older form fails with an error to call attention to this issue.
Example Usage
prompt 'Enter string: ' NB. output string to session
Enter string: Hello World
Hello World
0".prompt 'Enter an integer: ' NB. output integer to session
Enter an integer: 75000
75000
mystring=: prompt 'Enter string: ' NB. store string as noun
Enter string: Hello Rosetta Code
myinteger=: 0".prompt 'Enter an integer: ' NB. store integer as noun
Enter an integer: 75000
mystring;myinteger NB. show contents of nouns
┌──────────────────┬─────┐
│Hello Rosetta Code│75000│
└──────────────────┴─────┘
Java
import java.util.Scanner;
public class GetInput {
public static void main(String[] args) throws Exception {
Scanner s = new Scanner(System.in);
System.out.print("Enter a string: ");
String str = s.nextLine();
System.out.print("Enter an integer: ");
int i = Integer.parseInt(s.next());
}
}
or
import java.util.Scanner;
public class GetInput {
public static void main(String[] args) {
Scanner stdin = new Scanner(System.in);
String string = stdin.nextLine();
int number = stdin.nextInt();
}
}
JavaScript
and only with cscript.exe
WScript.Echo("Enter a string");
var str = WScript.StdIn.ReadLine();
var val = 0;
while (val != 75000) {
WScript.Echo("Enter the integer 75000");
val = parseInt( WScript.StdIn.ReadLine() );
}
print("Enter a string");
var str = readline();
var val = 0;
while (val != 75000) {
print("Enter the integer 75000");
val = parseInt( readline() );
}
Joy
"Enter a string: " putchars
stdin fgets
"Enter a number: " putchars
stdin fgets 10 strtol.
jq
If the input consists of a JSON string followed by a JSON number, then the jq program consisting of . will read and echo the two values.
If the goal is to continue reading the input until a JSON string is found, and then continue reading the input until the integer value 75000 is encountered, then the following program could be used on the assumption that the inputs are all valid JSON.
def read(int):
null | until( . == int; "Expecting \(int)" | stderr | input);
def read_string:
null | until( type == "string"; "Please enter a string" | stderr | input);
(read_string | "I see the string: \(.)"),
(read(75000) | "I see the expected integer: \(.)")
- Output:
The following is a transcript showing the prompts (on stderr), responses (on stdin) and output (on stdout):
$ jq -n -r -f User_input.jq
"Please enter a string"
1
"Please enter a string"
"ok"
I see the string: ok
"Expecting 75000"
1
"Expecting 75000"
"ok"
"Expecting 75000"
75000
I see the expected integer: 75000
Julia
print("String? ")
y = readline()
println("Your input was \"", y, "\".\n")
print("Integer? ")
y = readline()
try
y = parse(Int, y)
println("Your input was \"", y, "\".\n")
catch
println("Sorry, but \"", y, "\" does not compute as an integer.")
end
- Output:
String? cheese Your input was "cheese". Integer? 75000 Your input was "75000". mike@harlan:~/rosetta/julia$ julia user_input_text.jl String? theory Your input was "theory". Integer? 75,000 Sorry, but "75,000" does not compute as an integer.
Kite
System.file.stdout|write("Enter a String ");
string = System.file.stdin|readline();
Kotlin
// version 1.1
fun main(args: Array<String>) {
print("Enter a string : ")
val s = readLine()!!
println(s)
do {
print("Enter 75000 : ")
val number = readLine()!!.toInt()
} while (number != 75000)
}
Lambdatalk
{input
{@ type="text"
placeholder="Please enter a string and dblclick"
ondblclick="alert( 'You wrote « ' +
this.value +
' » and it is ' +
((isNaN(this.value)) ? 'not' : '') +
' a number.' )"
}}
Please enter a string and dblclick
Input: Hello World
Output: You wrote « Hello World » and it is not a number.
Input: 123
Output: You wrote « 123 » and it is a number.
Lasso
#!/usr/bin/lasso9
define read_input(prompt::string) => {
local(string)
// display prompt
stdout(#prompt)
// the following bits wait until the terminal gives you back a line of input
while(not #string or #string -> size == 0) => {
#string = file_stdin -> readsomebytes(1024, 1000)
}
#string -> replace(bytes('\n'), bytes(''))
return #string -> asstring
}
local(
string,
number
)
// get string
#string = read_input('Enter the string: ')
// get number
#number = integer(read_input('Enter the number: '))
// deliver the result
stdoutnl(#string + ' (' + #string -> type + ') | ' + #number + ' (' + #number -> type + ')')
Output:
Enter the string: Hello Enter the number: 1234 Hello (string) | 1234 (integer)
LDPL
data:
myText is text
myNumber is number
procedure:
display "Enter some text: "
accept myText
display "Enter a number: "
accept myNumber
Liberty BASIC
Input "Enter a string. ";string$
Input "Enter the value 75000.";num
LIL
# User input/text, in LIL
write "Enter a string: "
set text [readline]
set num 0
while {[canread] && $num != 75000} {
write "Enter the number 75000: "
set num [readline]
}
print $text
print $num
Logo
Logo literals may be read from a line of input from stdin as either a list or a single word.
make "input readlist ; in: string 75000
show map "number? :input ; [false true]
make "input readword ; in: 75000
show :input + 123 ; 75123
make "input readword ; in: string 75000
show :input ; string 75000
Logtalk
Using an atom representation for strings and type-check failure-driven loops:
:- object(user_input).
:- public(test/0).
test :-
repeat,
write('Enter an integer: '),
read(Integer),
integer(Integer),
!,
repeat,
write('Enter an atom: '),
read(Atom),
atom(Atom),
!.
:- end_object.
Output:
| ?- user_input::test.
Enter an integer: 75000.
Enter an atom: 'Hello world!'.
yes
LOLCODE
HAI 1.4
I HAS A string
GIMMEH string
I HAS A number
GIMMEH number
BTW converts number input to an integer
MAEK number A NUMBR
KTHXBYE
Lua
print('Enter a string: ')
s = io.stdin:read()
print('Enter a number: ')
i = tonumber(io.stdin:read())
M2000 Interpreter
Module CheckIt {
Keyboard "75000"+chr$(13)
Input "Integer:", A%
\\ Input erase keyboard buffer, we can't place in first Keyboard keys for second input
Keyboard "Hello World"+Chr$(13)
Input "String:", A$
Print A%, A$
}
CheckIt
MACRO-10
TITLE User Input
COMMENT !
User Input ** PDP-10 assembly language (kjx, 2022)
Assembler: MACRO-10 Operating system: TOPS-20
This program reads a string (maximum of 80 characters) and
a decimal number. The number is checked to be 75000. Invalid
input (like entering characters instead of a decimal number)
is detected, and an error message is printed in that case.
!
SEARCH MONSYM,MACSYM
.REQUIRE SYS:MACREL
STDAC. ;Set standard register names.
STRING: BLOCK 20 ;20 octal words = 80 characters.
NUMBER: BLOCK 1 ;1 word for number.
;;
;; Execution starts here:
;;
GO:: RESET% ;Initialize process.
;; Print prompt:
HRROI T1,[ASCIZ /Please type a string, 80 chars max.: /]
PSOUT%
;; Read string from terminal:
HRROI T1,STRING ;Pointer to string-buffer.
MOVEI T2,^D80 ;80 characters max.
SETZ T3 ;No special ctrl-r prompt.
RDTTY% ;Read from terminal.
ERJMP ERROR ; On error, go to ERROR.
;; Print second prompt:
NUMI: HRROI T1,[ASCIZ /Please type the decimal number 75000: /]
PSOUT%
;; Input number from terminal:
MOVEI T1,.PRIIN ;Read from terminal.
MOVEI T3,^D10 ;Decimal input.
NIN% ;Input number.
ERJMP ERROR ; On error, go to ERROR.
;; Make sure number is actually 75000.
CAIE T2,^D75000 ;Compare number...
JRST [ HRROI T1,[ASCIZ /Number is not 75000! /]
PSOUT% ; ...complain and
JRST NUMI ] ; try again.
MOVEM T2,NUMBER ;Store number if correct.
;; Now print out string and number:
HRROI T1,STRING ;String ptr into T1.
PSOUT% ;Print string.
MOVEI T1,.PRIOU ;Print on standard output.
MOVE T2,NUMBER ;Load number into T2.
MOVEI T3,^D10 ;Decimal output.
NOUT% ;And print the number.
ERJMP ERROR ; On error, go to ERROR.
;; End program:
HALTF% ;Halt program.
JRST GO ;Allow for 'continue'-command.
;;
;; The following routine prints out an error message,
;; similar to perror() in C:
;;
ERROR: MOVEI T1,.PRIOU ;Standard output.
MOVE T2,[.FHSLF,,-1] ;Own program, last error.
SETZ T3, ;No size-limit on message.
ERSTR% ;Print error-message.
JFCL ; Ignore errors from ERSTR.
JFCL ; dito.
HALTF% ;Halt program.
JRST GO ;Allow for 'continue'-command.
END GO
Example output:
@ exec uinput MACRO: User LINK: Loading [LNKXCT USER execution] Please type a string, 80 chars max.: This is a test. Please type the decimal number 75000: 74998 Number is not 75000! Please type the decimal number 75000: 74999 Number is not 75000! Please type the decimal number 75000: 75000 This is a test. 75000 @ _
Maple
printf("String:"); string_value := readline();
printf("Integer: "); int_value := parse(readline());
Mathematica / Wolfram Language
mystring = InputString["give me a string please"];
myinteger = Input["give me an integer please"];
MATLAB
The input() function automatically converts the user input to the correct data type (i.e. string or double). We can force the input to be interpreted as a string by using an optional parameter 's'.
Sample usage:
>> input('Input string: ')
Input string: 'Hello'
ans =
Hello
>> input('Input number: ')
Input number: 75000
ans =
75000
>> input('Input number, the number will be stored as a string: ','s')
Input number, the number will be stored as a string: 75000
ans =
75000
Maxima
/* String routine */
block(
s:read("enter a string"),
if stringp(s) then print(s,"is an actual string") else "that is not a string")$
/* Number routine */
block(
n:read("enter a number"),
if numberp(n) then print(n,"is an actual number") else "that is not a number")$
Metafont
string s;
message "write a string: ";
s := readstring;
message s;
message "write a number now: ";
b := scantokens readstring;
if b = 750:
message "You've got it!"
else:
message "Sorry..."
fi;
end
If we do not provide a number in the second input, Metafont will complain. (The number 75000 was reduced to 750 since Metafont biggest number is near 4096).
min
"Enter a string" ask
"Enter an integer" ask int
Mirah
s = System.console.readLine()
puts s
mIRC Scripting Language
alias askmesomething {
echo -a You answered: $input(What's your name?, e)
}
Modula-3
MODULE Input EXPORTS Main;
IMPORT IO, Fmt;
VAR string: TEXT;
number: INTEGER;
BEGIN
IO.Put("Enter a string: ");
string := IO.GetLine();
IO.Put("Enter a number: ");
number := IO.GetInt();
IO.Put("You entered: " & string & " and " & Fmt.Int(number) & "\n");
END Input.
MUMPS
TXTINP
NEW S,N
WRITE "Enter a string: "
READ S,!
WRITE "Enter the number 75000: "
READ N,!
KILL S,N
QUIT
Nanoquery
string = str(input("Enter a string: "))
integer = int(input("Enter an integer: "))
Neko
/**
User input/Text, in Neko
Tectonics:
nekoc userinput.neko
neko userinput
*/
var stdin = $loader.loadprim("std@file_stdin", 0)()
var file_read_char = $loader.loadprim("std@file_read_char", 1)
/* Read a line from file f into string s returning length without any newline */
var NEWLINE = 10
var readline = function(f, s) {
var len = 0
var ch
while true {
try ch = file_read_char(f) catch a break;
if ch == NEWLINE break;
if $sset(s, len, ch) == null break; else len += 1
}
return $ssub(s, 0, len)
}
$print("Enter a line of text, then the number 75000\n")
try {
var RECL = 132
var str = $smake(RECL)
var userstring = readline(stdin, str)
$print(":", userstring, ":\n")
var num = $int(readline(stdin, str))
if num == 75000 $print("Rosetta Code 75000, for the win!\n")
else $print("Sorry, need 75000\n")
} catch problem $print("Exception: ", problem, "\n")
- Output:
prompt$ nekoc userinput.neko prompt$ neko userinput.n Enter a line of text, then the number 75000 this is a line of text :this is a line of text: 75000 Rosetta Code 75000, for the win!
Nemerle
using System;
using System.Console;
module Input
{
Main() : void
{
Write("Enter a string:");
_ = ReadLine()
mutable entry = 0;
mutable numeric = false;
do
{
Write("Enter 75000:");
numeric = int.TryParse(ReadLine(), out entry);
} while ((!numeric) || (entry != 75000))
}
}
NetRexx
/* NetRexx */
options replace format comments java crossref symbols nobinary
checkVal = 75000
say 'Input a string then the number' checkVal
parse ask inString
parse ask inNumber .
say 'Input string:' inString
say 'Input number:' inNumber
if inNumber == checkVal then do
say 'Success! Input number is as requested'
end
else do
say 'Failure! Number' inNumber 'is not' checkVal
end
return
newLISP
(print "Enter an integer: ")
(set 'x (read-line))
(print "Enter a string: ")
(set 'y (read-line))
Nim
import rdstdin, strutils
let str = readLineFromStdin "Input a string: "
let num = parseInt(readLineFromStdin "Input an integer: ")
NS-HUBASIC
10 INPUT "ENTER A STRING: ",STRING$
20 PRINT "YOU ENTERED ";STRING$;"."
30 INPUT "ENTER AN INTEGER: ",INTEGER
40 PRINT "YOU ENTERED";INTEGER;"."
Nu
{
String: (input "Enter a string: ")
Number: (input "Enter an integer: ")
}
- Output:
Enter a string: Hello world! Enter an integer: 75000 ╭────────┬──────────────╮ │ String │ Hello world! │ │ Number │ 75000 │ ╰────────┴──────────────╯
Oberon-2
MODULE InputText;
IMPORT
In,
Out;
VAR
i: INTEGER;
str: ARRAY 512 OF CHAR;
BEGIN
Out.String("Enter a integer: ");Out.Flush();In.Int(i);
Out.String("Enter a string: ");Out.Flush();In.String(str);
END InputText.
Objeck
use IO;
bundle Default {
class Hello {
function : Main(args : String[]) ~ Nil {
string := Console->GetInstance()->ReadString();
string->PrintLine();
number := Console->GetInstance()->ReadString()->ToInt();
number->PrintLine();
}
}
}
OCaml
print_string "Enter a string: ";
let str = read_line () in
print_string "Enter an integer: ";
let num = read_int () in
Printf.printf "%s%d\n" str num
Octave
% read a string ("s")
s = input("Enter a string: ", "s");
% read a GNU Octave expression, which is evaluated; e.g.
% 5/7 gives 0.71429
i = input("Enter an expression: ");
% parse the input for an integer
printf("Enter an integer: ");
ri = scanf("%d");
% show the values
disp(s);
disp(i);
disp(ri);
Oforth
import: console
: testInput{
| s n |
System.Console askln ->s
while (System.Console askln asInteger dup ->n isNull) [ "Not an integer" println ]
System.Out "Received : " << s << " and " << n << cr ;
Oz
declare
StdIn = {New class $ from Open.file Open.text end init(name:stdin)}
StringInput
Num = {NewCell 0}
in
{System.printInfo "Enter a string: "}
StringInput = {StdIn getS($)}
for until:@Num == 75000 do
{System.printInfo "Enter 75000: "}
Line = {StdIn getS($)}
in
Num := try {String.toInt Line} catch _ then 0 end
end
PARI/GP
s=input();
n=eval(input());
Pascal
program UserInput(input, output);
var i : Integer;
s : String;
begin
write('Enter an integer: ');
readln(i);
write('Enter a string: ');
readln(s)
end.
PascalABC.NET
##
var s := ReadString('Input a string:');
var n := ReadInteger('Input an integer:');
Perl
print "Enter a string: ";
my $string = <>;
print "Enter an integer: ";
my $integer = <>;
Phix
?prompt_string("Enter any string:") ?prompt_number("Enter the number 75000:",{75000,75000})
- Output:
Enter any string:abc "abc" Enter the number 75000:123 A number from 75000 to 75000 is expected here - try again Enter the number 75000:75000 75000
Phixmonti
/# Rosetta Code problem: https://rosettacode.org/wiki/User_input/Text
by Galileo, 10/2022 #/
"Enter any string: " input nl
true while
75000 "Enter the number " over tostr chain ": " chain input
nl tonum over == not
endwhile
drop pstack
- Output:
Enter any string: Hello Enter the number 75000: 1000 Enter the number 75000: 75000 ["Hello", 75000] === Press any key to exit ===
PHP
#!/usr/bin/php
<?php
$string = fgets(STDIN);
$integer = (int) fgets(STDIN);
Picat
main =>
print("Enter a string: "),
String = read_line(),
print("Enter a number: "),
Number = read_int(),
println([string=String,number=Number]).
PicoLisp
(in NIL # Guarantee reading from standard input
(let (Str (read) Num (read))
(prinl "The string is: \"" Str "\"")
(prinl "The number is: " Num) ) )
Pike
int main(){
write("Enter a String: ");
string str = Stdio.stdin->gets();
write("Enter 75000: ");
int num = Stdio.stdin->gets();
}
PL/I
declare s character (100) varying;
declare k fixed decimal (15);
put ('please type a string:');
get edit (s) (L);
put skip list (s);
put skip list ('please type the integer 75000');
get list (k);
put skip list (k);
put skip list ('Thanks');
Plain English
To run:
Start up.
Demonstrate input.
Wait for the escape key.
Shut down.
To demonstrate input:
Write "Enter a string: " to the console without advancing.
Read a string from the console.
Write "Enter a number: " to the console without advancing.
Read a number from the console.
\Now show the input values
Write "The string: " then the string to the console.
Write "The number: " then the number to the console.
A sample run of the program:
- Output:
Enter a string: abc Enter a number: 123 The string: abc The number: 123
Pop11
;;; Setup item reader
lvars itemrep = incharitem(charin);
lvars s, c, j = 0;
;;; read chars up to a newline and put them on the stack
while (charin() ->> c) /= `\n` do j + 1 -> j ; c endwhile;
;;; build the string
consstring(j) -> s;
;;; read the integer
lvars i = itemrep();
PostScript
%open stdin for reading (and name the channel "kbd"):
/kbd (%stdin) (r) file def
%make ten-char buffer to read string into:
/buf (..........) def
%read string into buffer:
kbd buf readline
At this point there will be two items on the stack: a boolean which is "true" if the read was successful and the string that was read from the kbd (input terminates on a <return>). If the length of the string exceeds the buffer length, an error condition occurs (rangecheck). For the second part, the above could be followed by this:
%if the read was successful, convert the string to integer:
{cvi} if
which will read the conversion operator 'cvi' (convert to integer) and the boolean and execute the former if the latter is true.
PowerShell
$string = Read-Host "Input a string"
[int]$number = Read-Host "Input a number"
PureBasic
If OpenConsole()
; Declare a string and a integer to be used
Define txt.s, num.i
Print("Enter a string: ")
txt=Input()
Repeat
Print("Enter the number 75000: ")
num=Val(Input()) ; Converts the Input to a Value with Val()
Until num=75000
; Check that the user really gives us 75000!
Print("You made it!")
Delay(3000): CloseConsole()
EndIf
Python
Input a string
string = raw_input("Input a string: ")
In Python 3.0, raw_input will be renamed to input(). The Python 3.0 equivalent would be
string = input("Input a string: ")
Input a number
While input() gets a string in Python 3.0, in 2.x it is the equivalent of eval(raw_input(...)). Because this runs arbitrary code, and just isn't nice, it is being removed in Python 3.0. raw_input() is being changed to input() because there will be no other kind of input function in Python 3.0.
number = input("Input a number: ") # Deprecated, please don't use.
Python 3.0 equivalent:
number = eval(input("Input a number: ")) # Evil, please don't use.
The preferred way of getting numbers from the user is to take the input as a string, and pass it to any one of the numeric types to create an instance of the appropriate number.
number = float(raw_input("Input a number: "))
Python 3.0 equivalent:
number = float(input("Input a number: "))
float may be replaced by any numeric type, such as int, complex, or decimal.Decimal. Each one varies in expected input.
Quackery
The word $->n
attempts to convert a string to an integer, and returns an integer and a success flag. Validating the input is not part of the task, but since the flag is there we might as well use it. Similarly, might as well trim leading and trailing spaces, because users, eh.
$ "Please enter a string: " input
say 'You entered: "' echo$ say '"' cr cr
$ "Please enter an integer: " input
trim reverse trim reverse
$->n iff
[ say "You entered: " echo cr ]
else
[ say "That was not an integer." cr
drop ]
- Output:
Please enter a string: 3-ply sisal twine You entered: "3-ply sisal twine" Please enter an integer: 75000 You entered: 75000
R
stringval <- readline("String: ")
intval <- as.integer(readline("Integer: "))
Racket
#lang racket
(printf "Input a string: ")
(define s (read-line))
(printf "You entered: ~a\n" s)
(printf "Input a number: ")
(define m (or (string->number (read-line))
(error "I said a number!")))
(printf "You entered: ~a\n" m)
;; alternatively, use the generic `read'
(printf "Input a number: ")
(define n (read))
(unless (number? n) (error "I said a number!"))
(printf "You entered: ~a\n" n)
Raku
(formerly Perl 6)
my $str = prompt("Enter a string: ");
my $int = prompt("Enter a integer: ");
Rascal
It is possible to use the eclipse IDE to create consoles. However, just as with the graphical input, this will always return a string. This string can subsequently be evaluated. A very simple example would be:
import util::IDE;
public void InputConsole(){
x = "";
createConsole("Input Console",
"Welcome to the Input Console\nInput\> ",
str (str inp) {x = "<inp == "75000" ? "You entered 75000" : "You entered a string">";
return "<x>\n<inp>\nInput\>";});
}
Which has as output:
This makes it relatively easy to create Domain Specific Languages (or any programming language) and to create a rascal console for this. For examples with Exp, Func and Lisp, see the online Language Examples.
Raven
'Input a string: ' print expect as str
'Input an integer: ' print expect 0 prefer as num
REBOL
REBOL [
Title: "Textual User Input"
URL: http://rosettacode.org/wiki/User_Input_-_text
]
s: n: ""
; Because I have several things to check for, I've made a function to
; handle it. Note the question mark in the function name, this convention
; is often used in Forth to indicate test of some sort.
valid?: func [s n][
error? try [n: to-integer n] ; Ignore error if conversion fails.
all [0 < length? s 75000 = n]]
; I don't want to give up until I've gotten something useful, so I
; loop until the user enters valid data.
while [not valid? s n][
print "Please enter a string, and the number 75000:"
s: ask "string: "
n: ask "number: "
]
; It always pays to be polite...
print rejoin [ "Thank you. Your string was '" s "'."]
Output:
Please enter a string, and the number 75000: string: This is a test. number: ksldf Please enter a string, and the number 75000: string: number: 75000 Please enter a string, and the number 75000: string: Slert... number: 75000 Thank you. Your string was 'Slert...'.
Red
n: ask "Please enter # 75000: " str: ask "Please enter any string: "
Retro
:example ("-)
'Enter_a_string:_ s:put s:get s:keep
[ 'Enter_75000:_ s:put s:get-word s:to-number nl #75000 eq? ] until
'Your_string_was:_'%s'\n s:format s:put ;
REXX
Note: all of the following would be accepted as being numerically equal to 75000:
- 7.5E+0004
- 75000.
- 750000e-01
- 000075000.0000
- 75000 (with leading and/or trailing blanks)
- and others
If the intent was to have the user enter the string exactly as 75000,
then the REXX do statement should be replaced with:
do until userNumber==75000
/*REXX program prompts & reads/obtains a string, and also the number 75000 from terminal*/
say 'Please enter a string:' /*issue a prompt message to the term. */
parse pull userString /*the (char) string can be any length. */
/* [↑] the string could be null/empty.*/
do until userNumber=75000 /*repeat this loop until satisfied. */
say /*display a blank line to the terminal.*/
say 'Please enter the number 75000' /*display a nice prompt message to term*/
parse pull userNumber /*obtain the user text from terminal. */
end /*until*/ /*check if the response is legitimate. */
/*stick a fork in it, we're all done. */
Ring
see "Enter a string : " give s
see "Enter an integer : " give i
see "String = " + s + nl
see "Integer = " + i + nl
Robotic
input string "Enter string:"
set "$str" to "input"
input string "Enter number:"
set "number" to "input"
[ "You entered:"
[ "&$str&"
[ "&number&"
end
To ensure that a specific number must be entered, just create a loop around the second input function:
input string "Enter string:"
set "$str" to "input"
: "incorrect"
input string "Enter number:"
set "number" to "input"
if "number" != "(75000)" then "incorrect"
[ "You entered:"
[ "&$str&"
[ "&number&"
end
RPL
≪ "Enter text" { "" 𝛼 } INPUT @ Set keyboard alpha mode 75000 → string n75000 ≪ DO "Enter number " n + "" INPUT UNTIL n →STR == END string number ≫ ≫ 'TASK' STO
Ruby
print "Enter a string: "
s = gets
printf "Enter an integer: "
i = gets.to_i # If string entered, will return zero
printf "Enter a real number: "
f = Float(gets) rescue nil # converts a floating point number or returns nil
puts "String = #{s}"
puts "Integer = #{i}"
puts "Float = #{f}"
Rust
This program shows all the proper error handling.
use std::io::{self, Write};
use std::fmt::Display;
use std::process;
fn main() {
let s = grab_input("Give me a string")
.unwrap_or_else(|e| exit_err(&e, e.raw_os_error().unwrap_or(-1)));
println!("You entered: {}", s.trim());
let n: i32 = grab_input("Give me an integer")
.unwrap_or_else(|e| exit_err(&e, e.raw_os_error().unwrap_or(-1)))
.trim()
.parse()
.unwrap_or_else(|e| exit_err(&e, 2));
println!("You entered: {}", n);
}
fn grab_input(msg: &str) -> io::Result<String> {
let mut buf = String::new();
print!("{}: ", msg);
try!(io::stdout().flush());
try!(io::stdin().read_line(&mut buf));
Ok(buf)
}
fn exit_err<T: Display>(msg: T, code: i32) -> ! {
let _ = writeln!(&mut io::stderr(), "Error: {}", msg);
process::exit(code)
}
Scala
print("Enter a number: ")
val i=Console.readLong // Task says to enter 75000
print("Enter a string: ")
val s=Console.readLine
Scheme
The read procedure is R5RS standard, inputs a scheme representation so, in order to read a string, one must enter "hello world"
(define str (read))
(define num (read))
(display "String = ") (display str)
(display "Integer = ") (display num)
Seed7
$ include "seed7_05.s7i";
const proc: main is func
local
var integer: integer_input is 0;
var string: string_input is "";
begin
write("Enter an integer: ");
readln(integer_input);
write("Enter a string: ");
readln(string_input);
end func;
Sidef
Using the read(Type) built-in function:
var s = read(String);
var i = read(Number); # auto-conversion to a number
or using the Sys.readln(msg) method:
var s = Sys.readln("Enter a string: ");
var i = Sys.readln("Enter a number: ").to_i;
Slate
print: (query: 'Enter a String: ').
[| n |
n: (Integer readFrom: (query: 'Enter an Integer: ')).
(n is: Integer)
ifTrue: [print: n]
ifFalse: [inform: 'Not an integer: ' ; n printString]
] do.
Smalltalk
'Enter a number: ' display.
a := stdin nextLine asInteger.
'Enter a string: ' display.
b := stdin nextLine.
smart BASIC
NOTE: The INPUT command uses a colon (:) as opposed to a comma (,) or semi-conlon (;) like other forms of BASIC.
INPUT "Enter a string.":a$
INPUT "Enter the value 75000.":n
SNOBOL4
output = "Enter a string:"
str = trim(input)
output = "Enter an integer:"
int = trim(input)
output = "String: " str " Integer: " int
end
SPL
In SPL all console input is text, so number should be converted from text using #.val function.
text = #.input("Input a string")
number = #.val(#.input("Input a number"))
SparForte
As a structured script.
#!/usr/local/bin/spar
pragma annotate( summary, "get_string" )
@( description, "Input a string and the integer 75000 from the text console." )
@( see_also, "https://rosettacode.org/wiki/User_input/Text" )
@( author, "Ken O. Burtch" );
pragma license( unrestricted );
pragma restriction( no_external_commands );
procedure get_string is
s : unbounded_string;
i : integer;
begin
s := get_line;
i := integer( numerics.value( get_line ) );
? s @ i;
exception when others =>
put_line( standard_error, "the value is not valid" );
end get_string;
As a unstructured script and no exception handling.
s := get_line;
i := numerics.value( get_line );
? s @ i;
Standard ML
print "Enter a string: ";
let val str = valOf (TextIO.inputLine TextIO.stdIn) in (* note: this keeps the trailing newline *)
print "Enter an integer: ";
let val num = valOf (TextIO.scanStream (Int.scan StringCvt.DEC) TextIO.stdIn) in
print (str ^ Int.toString num ^ "\n")
end
end
Swift
print("Enter a string: ", terminator: "")
if let str = readLine() {
print(str)
}
print("Enter a string: ", terminator: "")
guard let str = readLine() else {
fatalError("Nothing read!")
}
print(str)
print("Enter a number: ", terminator: "")
guard let nstr = readLine(), let num = Int(nstr) else {
fatalError("Not a number!")
}
print(num)
Tcl
Like LISP, there is no concept of a "number" in Tcl - the only real variable type is a string (whether a string might represent a number is a matter of interpretation of the string in a mathematical expression at some later time). Thus the input is the same for both tasks:
set str [gets stdin]
set num [gets stdin]
possibly followed by something like
if {![string is integer -strict $num]} then { ...do something here...}
If the requirement is to prompt until the user enters the integer 75000, then:
set input 0
while {$input != 75000} {
puts -nonewline "enter the number '75000': "
flush stdout
set input [gets stdin]
}
Of course, it's nicer to wrap the primitives in a procedure:
proc question {var message} {
upvar 1 $var v
puts -nonewline "$message: "
flush stdout
gets stdin $v
}
question name "What is your name"
question task "What is your quest"
question doom "What is the air-speed velocity of an unladen swallow"
TI-83 BASIC
This program leaves the string in String1, and the integer in variable "i".
:Input "Enter a string:",Str1
:Prompt i
:If(i ≠ 75000): Then
:Disp "That isn't 75000"
:Else
:Stop
TI-89 BASIC
This program leaves the requested values in the global variables s and integer.
Prgm
InputStr "Enter a string", s
Loop
Prompt integer
If integer ≠ 75000 Then
Disp "That wasn't 75000."
Else
Exit
EndIf
EndLoop
EndPrgm
Toka
needs readline
." Enter a string: " readline is-data the-string
." Enter a number: " readline >number [ ." Not a number!" drop 0 ] ifFalse is-data the-number
the-string type cr
the-number . cr
TUSCRIPT
$$ MODE TUSCRIPT
LOOP
ASK "Enter a string": str=""
ASK "Enter an integer": int=""
IF (int=='digits') THEN
PRINT "int=",int," str=",str
EXIT
ELSE
PRINT/ERROR int," is not an integer"
CYCLE
ENDIF
ENDLOOP
Output:
Enter a string >a Enter an integer >a @@@@@@@@ a is not an integer @@@@@@@@ Enter a string >a Enter an integer >1 int=1 str=a
UNIX Shell
#!/bin/sh
read string
read integer
read -p 'Enter a number: ' number
echo "The number is $number"
Ursa
#
# user input
#
# in ursa, the type of data expected must be specified
decl string str
decl int i
out "input a string: " console
set str (in string console)
out "input an int: " console
set i (in int console)
out "you entered " str " and " i endl console
VBA
Public Sub text()
Debug.Print InputBox("Input a string")
Debug.Print InputBox("Input the integer 75000", "Input an integer", 75000, Context = "Long")
End Sub
Vedit macro language
Get_Input(1, "Enter a string: ")
#2 = Get_Num("Enter a number: ")
Visual Basic .NET
Platform: .NET
Input an Integer
Dim i As Integer
Console.WriteLine("Enter an Integer")
i = Console.ReadLine()
Input an Integer With Error Handling
Dim i As Integer
Dim iString As String
Console.WriteLine("Enter an Integer")
iString = Console.ReadLine()
Try
i = Convert.ToInt32(iString)
Catch ex As Exception
Console.WriteLine("This is not an Integer")
End Try
Input a String
Dim i As String
Console.WriteLine("Enter a String")
i = Console.ReadLine()
V (Vlang)
import os
fn main() {
s := os.input('Enter string').int()
if s == 75000 {
println('good')
} else {
println('bad')
}
}
Input conversion with Error Handling
import os
import strconv
fn main() {
s := strconv.atoi(os.input('Enter string')) ?
if s == 75000 {
println('good')
} else {
println('bad $s')
}
}
Wee Basic
print 1 "Enter a string."
input string$
print 1 "Enter an integer."
input integer
Wren
import "io" for Stdin, Stdout
var string
while (true) {
System.write("Enter a string : ")
Stdout.flush()
string = Stdin.readLine()
if (string.count == 0) {
System.print("String cannot be empty, try again.")
} else {
break
}
}
var number
while (true) {
System.write("Enter a number : ")
Stdout.flush()
number = Num.fromString(Stdin.readLine())
if (!number || !number.isInteger) {
System.print("Please enter a vaid integer, try again.")
} else {
break
}
}
System.print("\nYou entered:")
System.print(" string: %(string)")
System.print(" number: %(number)")
- Output:
Enter a string : Rosetta Code Enter a number : 75000 You entered: string: Rosetta Code number: 75000
XLISP
READ-LINE reads a line of input as a string; READ reads an expression, of arbitrary complexity.
(display "Enter a string: ")
(define s (read-line))
(display "Yes, ")
(write s)
(display " is a string.") ;; no need to verify, because READ-LINE has to return a string
(newline)
(display "Now enter the integer 75000: ")
(define n (read))
(display
(cond
((not (integerp n))
"That's not even an integer." )
((/= n 75000)
"That is not the integer 75000." )
(t
"Yes, that is the integer 75000." ) ) )
- Output:
Enter a string: Rosetta Code Yes, "Rosetta Code" is a string. Now enter the integer 75000: 75000 Yes, that is the integer 75000.
XPL0
When the ChIn(0) intrinsic is first called, it collects characters from the keyboard until the Enter key is struck. It then returns to the XPL0 program where one character is pulled from the buffer each time ChIn(0) is called. When the Enter key (which is the same as a carriage return, $0D) is pulled, the program quits the loop. A zero byte is stored in place of the Enter key to mark the end of the string.
string 0; \use zero-terminated strings, instead of MSb terminated
include c:\cxpl\codes;
int I;
char Name(128); \the keyboard buffer limits input to 128 characters
[Text(0, "What's your name? ");
I:= 0;
loop [Name(I):= ChIn(0); \buffered keyboard input
if Name(I) = $0D\CR\ then quit; \Carriage Return = Enter key
I:= I+1;
];
Name(I):= 0; \terminate string
Text(0, "Howdy "); Text(0, Name); Text(0, "! Now please enter ^"75000^": ");
IntOut(0, IntIn(0)); CrLf(0); \echo the number
]
Example output:
What's your name? Loren Blaney Howdy Loren Blaney! Now please enter "75000": 75000 75000
zkl
str:=ask("Gimmie a string: ");
n:=ask("Type 75000: ").toInt();
ZX Spectrum Basic
10 INPUT "Enter a string:"; s$
20 INPUT "Enter a number: "; n