Sorting algorithms/Bubble sort

In this task, the goal is to sort an array of elements using the bubble sort algorithm. The elements must have a total order and the index of the array can be of any discrete type. For languages where this is not possible, sort an array of integers.

Task
Sorting algorithms/Bubble sort
You are encouraged to solve this task according to the task description, using any language you may know.

The bubble sort is generally considered to be the simplest sorting algorithm. Because of its simplicity and ease of visualization, it is often taught in introductory computer science courses. Because of its abysmal O(n2) performance, it is not used often for large (or even medium-sized) datasets.

The bubble sort works by passing sequentially over a list, comparing each value to the one immediately after it. If the first value is greater than the second, their positions are switched. Over a number of passes, at most equal to the number of elements in the list, all of the values drift into their correct positions (large values "bubble" rapidly toward the end, pushing others down around them). Because each pass finds the maximum item and puts it at the end, the portion of the list to be sorted can be reduced at each pass. A boolean variable is used to track whether any changes have been made in the current pass; when a pass completes without changing anything, the algorithm exits.

This can be expressed in pseudocode as follows (assuming 1-based indexing):

repeat
    hasChanged := false
    decrement itemCount
    repeat with index from 1 to itemCount
        if (item at index) > (item at (index + 1))
            swap (item at index) with (item at (index + 1))
            hasChanged := true
until hasChanged = false
References

360 Assembly

For maximum compatibility, this program uses only the basic instruction set. <lang 360 Assembly>* Bubble Sort BUBBLE CSECT

        USING  BUBBLE,R13,R12

SAVEAREA B STM-SAVEAREA(R15) skip savearea

        DC     17F'0'
        DC     CL8'BUBBLE'

STM STM R14,R12,12(R13) save calling context

        ST     R13,4(R15)
        ST     R15,8(R13)
        LR     R13,R15         set addessability
        LA     R12,4095(R13)
        LA     R12,1(R12)

MORE EQU *

        LA     R8,0            R8=no more
        LA     R1,A            R1=Addr(A(I))
        LA     R2,2(R1)        R2=Addr(A(I+1))
        LA     R4,0            to start at 1
        LA     R6,1            increment
        L      R7,N            R7=N 
        BCTR   R7,0            R7=N-1

LOOP BXH R4,R6,ENDLOOP for R4=1 to N-1

        LH     R3,0(R1)        R3=A(I)         
        CH     R3,0(R2)        A(I)::A(I+1)
        BNH    NOSWAP          if A(I)<=A(I+1) then goto NOSWAP
        LH     R9,0(R1)        R9=A(I)
        LH     R3,0(R2)        R3=A(I+1)
        STH    R3,0(R1)        A(I)=R3
        STH    R9,0(R2)        A(I+1)=R9
        LA     R8,1            R8=more

NOSWAP EQU *

        LA     R1,2(R1)        next A(I)
        LA     R2,2(R2)        next A(I+1)
        B      LOOP

ENDLOOP EQU *

        LTR    R8,R8
        BNZ    MORE
        LA     R3,A            R3=Addr(A(I))
        LA     R4,0            to start at 1
        LA     R6,1            increment
        L      R7,N          

PRNT BXH R4,R6,ENDPRNT for R4=1 to N

        LH     R5,0(R3)        R5=A(I)
        CVD    R4,P            Store I to packed P
        UNPK   Z,P             Z=P
        MVC    C,Z             C=Z
        OI     C+L'C-1,X'F0'   ZAP SIGN
        MVC    BUFFER(4),C+12
        CVD    R5,P            Store A(I) to packed P
        UNPK   Z,P             Z=P
        MVC    C,Z             C=Z
        OI     C+L'C-1,X'F0'   ZAP SIGN
        MVC    BUFFER+10(6),C+10
        WTO    MF=(E,WTOMSG)
        LA     R3,2(R3)        next A(I)
        B      PRNT

ENDPRNT EQU *

        CNOP   0,4
        L      R13,4(0,R13)
        LM     R14,R12,12(R13) restore context
        XR     R15,R15         set return code to 0
        BR     R14             return to caller

N DC A((AEND-A)/2) number of items in A, so N=F'80' A DC H'223',H'356',H'018',H'820',H'664',H'845',H'927',H'198' 8

        DC H'261',H'802',H'523',H'982',H'242',H'192',H'913',H'230' 16 
        DC H'353',H'565',H'195',H'174',H'665',H'807',H'050',H'539' 24 
        DC H'436',H'249',H'848',H'010',H'006',H'794',H'100',H'433' 32 
        DC H'782',H'728',H'259',H'358',H'206',H'081',H'701',H'997' 40 
        DC H'880',H'520',H'780',H'293',H'861',H'942',H'735',H'091' 48 
        DC H'503',H'582',H'716',H'836',H'135',H'653',H'856',H'142' 56 
        DC H'919',H'498',H'303',H'894',H'536',H'211',H'539',H'986' 64 
        DC H'356',H'796',H'644',H'552',H'771',H'443',H'035',H'780' 72 
        DC H'474',H'278',H'332',H'949',H'351',H'282',H'558',H'904' 80 

AEND EQU * P DS PL8 packed Z DS ZL16 zoned C DS CL16 character WTOMSG CNOP 0,4

        DC     H'80'           length of WTO buffer
        DC     H'0'            must be binary zeroes

BUFFER DC 80C' '

        LTORG  
        YREGS  
        END    BUBBLE</lang>
Output:
0001      000006
0002      000010
0003      000018
0004      000035
0005      000050
0006      000081
0007      000091
0008      000100
0009      000135
0010      000142
0011      000174
0012      000192
0013      000195
0014      000198
0015      000206
0016      000211
0017      000223
0018      000230
0019      000242
0020      000249
0021      000259
0022      000261
0023      000278
0024      000282
0025      000293
0026      000303
0027      000332
0028      000351
0029      000353
0030      000356
0031      000356
0032      000358
0033      000433
0034      000436
0035      000443
0036      000474
0037      000498
0038      000503
0039      000520
0040      000523
0041      000536
0042      000539
0043      000539
0044      000552
0045      000558
0046      000565
0047      000582
0048      000644
0049      000653
0050      000664
0051      000665
0052      000701
0053      000716
0054      000728
0055      000735
0056      000771
0057      000780
0058      000780
0059      000782
0060      000794
0061      000796
0062      000802
0063      000807
0064      000820
0065      000836
0066      000845
0067      000848
0068      000856
0069      000861
0070      000880
0071      000894
0072      000904
0073      000913
0074      000919
0075      000927
0076      000942
0077      000949
0078      000982
0079      000986
0080      000997

ACL2

<lang Lisp>(defun bubble (xs)

  (if (endp (rest xs))
      (mv nil xs)
      (let ((x1 (first xs))
            (x2 (second xs)))
        (if (> x1 x2)
            (mv-let (_ ys)
                    (bubble (cons x1 (rest (rest xs))))
               (declare (ignore _))
               (mv t (cons x2 ys)))
            (mv-let (has-changed ys)
                    (bubble (rest xs))
               (mv has-changed (cons x1 ys)))))))

(defun bsort-r (xs limit)

  (declare (xargs :measure (nfix limit)))
  (if (zp limit)
      xs
      (mv-let (has-changed ys)
              (bubble xs)
         (if has-changed
             (bsort-r ys (1- limit))
             ys))))

(defun bsort (xs)

  (bsort-r xs (len xs)))</lang>

ActionScript

<lang actionscript>public function bubbleSort(toSort:Array):Array { var changed:Boolean = false;

while (!changed) { changed = true;

for (var i:int = 0; i < toSort.length - 1; i++) { if (toSort[i] > toSort[i + 1]) { var tmp:int = toSort[i]; toSort[i] = toSort[i + 1]; toSort[i + 1] = tmp;

changed = false; } } }

return toSort; }</lang>

Ada

Works with: GCC version 4.1.2

<lang ada>generic

type Element is private;
with function "=" (E1, E2 : Element) return Boolean is <>;
with function "<" (E1, E2 : Element) return Boolean is <>;
type Index is (<>);
type Arr is array (Index range <>) of Element;

procedure Bubble_Sort (A : in out Arr);

procedure Bubble_Sort (A : in out Arr) is

Finished : Boolean;
Temp     : Element;

begin

loop
 Finished := True;
 for J in A'First .. Index'Pred (A'Last) loop
  if A (Index'Succ (J)) < A (J) then
   Finished := False;
   Temp := A (Index'Succ (J));
   A (Index'Succ (J)) := A (J);
   A (J) := Temp;
  end if;
 end loop;
 exit when Finished;
end loop;

end Bubble_Sort;

-- Example of usage: with Ada.Text_IO; use Ada.Text_IO; with Bubble_Sort; procedure Main is

type Arr is array (Positive range <>) of Integer;
procedure Sort is new
 Bubble_Sort
  (Element => Integer,
   Index   => Positive,
   Arr     => Arr);
A : Arr := (1, 3, 256, 0, 3, 4, -1);

begin

Sort (A);
for J in A'Range loop
 Put (Integer'Image (A (J)));
end loop;
New_Line;

end Main;</lang>

ALGOL 68

<lang algol68>MODE DATA = INT; PROC swap = (REF[]DATA slice)VOID: (

 DATA tmp = slice[1];
 slice[1] := slice[2];
 slice[2] := tmp

);

PROC sort = (REF[]DATA array)VOID: (

 BOOL sorted;
 INT shrinkage := 0;
 FOR size FROM UPB array - 1 BY -1 WHILE
   sorted := TRUE;
   shrinkage +:= 1;
   FOR i FROM LWB array TO size DO
     IF array[i+1] < array[i] THEN
       swap(array[i:i+1]);
       sorted := FALSE
     FI
   OD;
   NOT sorted
 DO SKIP OD

);

main:(

 [10]INT random := (1,6,3,5,2,9,8,4,7,0); 
 printf(($"Before: "10(g(3))l$,random));
 sort(random);
 printf(($"After: "10(g(3))l$,random))

)</lang>

Output:
 Before:  +1 +6 +3 +5 +2 +9 +8 +4 +7 +0
 After:  +0 +1 +2 +3 +4 +5 +6 +7 +8 +9

ALGOL W

<lang algolw>begin

   % As algol W does not allow overloading, we have to have type-specific   %
   % sorting procedures - this bubble sorts an integer array                %
   % as there is no way for the procedure to determine the array bounds, we %
   % pass the lower and upper bounds in lb and ub                           %
   procedure bubbleSortIntegers( integer array item( * )
                               ; integer value lb
                               ; integer value ub
                               ) ;
   begin
       integer lower, upper;
       lower := lb;
       upper := ub;
       while
           begin
               logical swapped;
               upper   := upper - 1;
               swapped := false;
               for i := lower until upper
               do begin
                   if item( i ) > item( i + 1 )
                   then begin
                       integer val;
                       val           := item( i );
                       item( i )     := item( i + 1 );
                       item( i + 1 ) := val;
                       swapped       := true;
                   end if_must_swap ;
               end for_i ;
               swapped
           end
       do  begin end;
   end bubbleSortIntegers ;
   begin % test the bubble sort                                             %
       integer array data( 1 :: 10 );
       procedure writeData ;
       begin
           write( data( 1 ) );
           for i := 2 until 10 do writeon( data( i ) );
       end writeData ;
       % initialise data to unsorted values                                 %
       integer       dPos;
       dPos  := 1;
       for i := 16, 2, -6, 9, 90, 14, 0, 23, 8, 9
       do begin
           data( dPos ) := i;
           dPos         := dPos + 1;
       end for_i ;
       i_w := 3; s_w := 1; % set output format %
       writeData;
       bubbleSortIntegers( data, 1, 10 );
       writeData;
   end test 

end.</lang>

Output:
 16   2  -6   9  90  14   0  23   8   9 
 -6   0   2   8   9   9  14  16  23  90 

Arendelle

A function that returns a sorted version of it's x input

< x > ( i , 0 )

( sjt , 1; 0; 0 ) // swapped:0 / j:1 / temp:2

[ @sjt = 1 ,

	( sjt , 0 )
	( sjt[ 1 ] , +1 )

	( i , 0 )

	[ @i < @x? - @sjt[ 1 ],

		{ @x[ @i ] < @x[ @i + 1 ],

			( sjt[ 2 ] , @x[ @i ] )
			( x[ @i ] , @x[ @i + 1 ] )
			( x[ @i + 1 ] , @sjt[ 2 ] )
			( sjt , 1 )
		}

		( i , +1 )
	]
]

( return , @x )

AutoHotkey

<lang AutoHotkey>var = ( dog cat pile abc ) MsgBox % bubblesort(var)

bubblesort(var) ; each line of var is an element of the array {

 StringSplit, array, var, `n
 hasChanged = 1
 size := array0
 While hasChanged
 {
   hasChanged = 0
   Loop, % (size - 1)
   {
     i := array%A_Index%
     aj := A_Index + 1
     j := array%aj%
     If (j < i)
     {
       temp := array%A_Index%
       array%A_Index% := array%aj%
       array%aj% := temp
       hasChanged = 1
     } 
   }
 }
 Loop, % size
   sorted .= array%A_Index% . "`n"
 Return sorted

}</lang>

AWK

Sort the standard input and print it to standard output. <lang awk>{ # read every line into an array

 line[NR] = $0

} END { # sort it with bubble sort

 do {
   haschanged = 0
   for(i=1; i < NR; i++) {
     if ( line[i] > line[i+1] ) {

t = line[i] line[i] = line[i+1] line[i+1] = t haschanged = 1

     }
   }
 } while ( haschanged == 1 )
 # print it
 for(i=1; i <= NR; i++) {
   print line[i]
 }

}</lang>

GNU awk contains built in functions for sorting, but POSIX Awk doesn't. Here is a generic bubble sort() implementation that you can copy/paste to your Awk programs. Adapted from the above example. Note that it is not possible to return arrays from Awk functions so the array is "edited in place". The extra parameters passed in function's argument list is a well known trick to define local variables.

<lang awk>

  1. Test this example file from command line with:
  2. awk -f file.awk /dev/null
  3. Code by Jari Aalto <jari.aalto A T cante net>
  4. Licensed and released under GPL-2+, see http://spdx.org/licenses

function alen(array, dummy, len) {

   for (dummy in array)
       len++;
   return len;

}

function sort(array, haschanged, len, tmp, i) {

   len = alen(array)
   haschanged = 1
   while ( haschanged == 1 )
   {
       haschanged = 0
       for (i = 1; i <= len - 1; i++)
       {
           if (array[i] > array[i+1])
           {
               tmp = array[i]
               array[i] = array[i + 1]
               array[i + 1] = tmp
               haschanged = 1
           }
       }
   }

}

  1. An Example. Sorts array to order: b, c, z

{

   array[1] = "c"
   array[2] = "z"
   array[3] = "b"
   sort(array)
   print array[1] " " array[2] " " array[3]
   exit

} </lang>

BASIC

Works with: QuickBasic version 4.5
Translation of: Java

Assume numbers are in a DIM of size "size" called "nums". <lang qbasic> DO

 changed = 0
 FOR I = 1 to size -1
   IF nums(I) > nums(I + 1) THEN
     tmp = nums(I)
     nums(I) = nums(I + 1)
     nums(I + 1) = tmp
     changed = 1
   END IF
 NEXT

LOOP WHILE(NOT changed)</lang>

BASIC256

Works with: BASIC256

<lang basic256> Dim a(11): ordered=false print "Original set" For n = 0 to 9 a[n]=int(rand*20+1) print a[n]+", "; next n

  1. algorithm

while ordered=false

  ordered=true
  For n = 0 to 9
     if a[n]> a[n+1] then
         x=a[n]
         a[n]=a[n+1]
         a[n+1]=x
         ordered=false
      end if
   next n

end while

print print "Ordered set" For n = 1 to 10 print a[n]+", "; next n </lang>

Output:

(example)

Original set
2, 10, 17, 13, 20, 14, 3, 17, 16, 16, 
Ordered set
2, 3, 10, 13, 14, 16, 16, 17, 17, 20, 

BBC BASIC

The Bubble sort is very inefficient for 99% of cases. This routine uses a couple of 'tricks' to try and mitigate the inefficiency to a limited extent. Note that the array index is assumed to start at zero. <lang bbcbasic> DIM test(9)

     test() = 4, 65, 2, -31, 0, 99, 2, 83, 782, 1
     PROCbubblesort(test(), 10)
     FOR i% = 0 TO 9
       PRINT test(i%) ;
     NEXT
     PRINT
     END
     
     DEF PROCbubblesort(a(), n%)
     LOCAL i%, l%
     REPEAT
       l% = 0
       FOR i% = 1 TO n%-1
         IF a(i%-1) > a(i%) THEN
           SWAP a(i%-1),a(i%)
           l% = i%
         ENDIF
       NEXT
       n% = l%
     UNTIL l% = 0
     ENDPROC</lang>
Output:
       -31         0         1         2         2         4        65        83        99       782

C

<lang c>#include <stdio.h>

void bubble_sort (int *a, int n) {

   int i, t, s = 1;
   while (s) {
       s = 0;
       for (i = 1; i < n; i++) {
           if (a[i] < a[i - 1]) {
               t = a[i];
               a[i] = a[i - 1];
               a[i - 1] = t;
               s = 1;
           }
       }
   }

}

int main () {

   int a[] = {4, 65, 2, -31, 0, 99, 2, 83, 782, 1};
   int n = sizeof a / sizeof a[0];
   int i;
   for (i = 0; i < n; i++)
       printf("%d%s", a[i], i == n - 1 ? "\n" : " ");
   bubble_sort(a, n);
   for (i = 0; i < n; i++)
       printf("%d%s", a[i], i == n - 1 ? "\n" : " ");
   return 0;

} </lang>

Output:
4 65 2 -31 0 99 2 83 782 1
-31 0 1 2 2 4 65 83 99 782

C++

Uses C++11. Compile with

g++ -std=c++11 bubble.cpp

<lang cpp>#include <algorithm>

  1. include <iostream>
  2. include <iterator>

template <typename RandomAccessIterator> void bubble_sort(RandomAccessIterator begin, RandomAccessIterator end) {

 bool swapped = true;
 while (begin != end-- && swapped) {
   swapped = false;
   for (auto i = begin; i != end; ++i) {
     if (*(i + 1) < *i) {
       std::iter_swap(i, i + 1);
       swapped = true;
     }
   }
 }

}

int main() {

 int a[] = {100, 2, 56, 200, -52, 3, 99, 33, 177, -199};
 bubble_sort(std::begin(a), std::end(a));
 copy(std::begin(a), std::end(a), std::ostream_iterator<int>(std::cout, " "));
 std::cout << "\n";

}</lang>

Output:
-199 -52 2 3 33 56 99 100 177 200

C#

Works with: C# version 3.0+

<lang csharp>using System; using System.Collections.Generic;

namespace RosettaCode.BubbleSort {

   public static class BubbleSortMethods
   {
       //The "this" keyword before the method parameter identifies this as a C# extension
       //method, which can be called using instance method syntax on any generic list,
       //without having to modify the generic List<T> code provided by the .NET framework.
       public static void BubbleSort<T>(this List<T> list) where T : IComparable
       {
           bool madeChanges;
           int itemCount = list.Count;
           do
           {
               madeChanges = false;
               itemCount--;
               for (int i = 0; i < itemCount; i++)
               {
                   if (list[i].CompareTo(list[i + 1]) > 0)
                   {
                       T temp = list[i + 1];
                       list[i + 1] = list[i];
                       list[i] = temp;
                       madeChanges = true;
                   }
               }
           } while (madeChanges);
       }
   }
   //A short test program to demonstrate the BubbleSort. The compiler will change the
   //call to testList.BubbleSort() into one to BubbleSortMethods.BubbleSort<T>(testList).
   class Program
   {
       static void Main()
       {
           List<int> testList = new List<int> { 3, 7, 3, 2, 1, -4, 10, 12, 4 };
           testList.BubbleSort();
           foreach (var t in testList) Console.Write(t + " ");
       }
   }

}</lang>

Clojure

Bubble sorts a Java ArrayList in place. Uses 'doseq' iteration construct with a short-circuit when a pass didn't produce any change, and within the pass, an atomic 'changed' variable that gets reset whenever a change occurs.

<lang clojure>(ns bubblesort

 (:import java.util.ArrayList))

(defn bubble-sort

 "Sort in-place.
 arr must implement the Java List interface and should support
 random access, e.g. an ArrayList."
 ([arr] (bubble-sort compare arr))
 ([cmp arr]
    (letfn [(swap! [i j]
                   (let [t (.get arr i)]
                     (doto arr
                       (.set i (.get arr j))
                       (.set j t))))
            (sorter [stop-i]
                    (let [changed (atom false)]
                      (doseq [i (range stop-i)]
                        (if (pos? (cmp (.get arr i) (.get arr (inc i))))
                          (do
                            (swap! i (inc i))
                            (reset! changed true))))
                      @changed))]
      (doseq [stop-i (range (dec (.size arr)) -1 -1)
              :while (sorter stop-i)])
      arr)))

(println (bubble-sort (ArrayList. [10 9 8 7 6 5 4 3 2 1])))</lang>

Purely functional version working on Clojure sequences: <lang clojure>(defn- bubble-step

 "was-changed: whether any elements prior to the current first element
 were swapped;
 returns a two-element vector [partially-sorted-sequence is-sorted]"
[less? xs was-changed]
 (if (< (count xs) 2)
   [xs (not was-changed)]
   (let [[x1 x2 & xr] xs

first-is-smaller (less? x1 x2) is-changed (or was-changed (not first-is-smaller)) [smaller larger] (if first-is-smaller [x1 x2] [x2 x1]) [result is-sorted] (bubble-step less? (cons larger xr) is-changed)]

     [(cons smaller result) is-sorted])))

(defn bubble-sort

 "Takes an optional less-than predicate and a sequence.
 Returns the sorted sequence.
 Very inefficient (O(n²))"
 ([xs] (bubble-sort <= xs))
 ([less? xs] 
    (let [[result is-sorted] (bubble-step less? xs false)]
      (if is-sorted

result (recur less? result)))))

(println (bubble-sort [10 9 8 7 6 5 4 3 2 1]))</lang>

CMake

Only for lists of integers.

<lang cmake># bubble_sort(var [value1 value2...]) sorts a list of integers. function(bubble_sort var)

 math(EXPR last "${ARGC} - 1")  # Prepare to sort ARGV[1]..ARGV[last].
 set(again YES)
 while(again)
   set(again NO)
   math(EXPR last "${last} - 1")               # Decrement last index.
   foreach(index RANGE 1 ${last})              # Loop for each index.
     math(EXPR index_plus_1 "${index} + 1")
     set(a "${ARGV${index}}")                  # a = ARGV[index]
     set(b "${ARGV${index_plus_1}}")           # b = ARGV[index + 1]
     if(a GREATER "${b}")                      # If a > b...
       set(ARGV${index} "${b}")                # ...then swap a, b
       set(ARGV${index_plus_1} "${a}")         #    inside ARGV.
       set(again YES)
     endif()
   endforeach(index)
 endwhile()
 set(answer)
 math(EXPR last "${ARGC} - 1")
 foreach(index RANGE 1 "${last}")
   list(APPEND answer "${ARGV${index}}")
 endforeach(index)
 set("${var}" "${answer}" PARENT_SCOPE)

endfunction(bubble_sort)</lang>

<lang cmake>bubble_sort(result 33 11 44 22 66 55) message(STATUS "${result}")</lang>

-- 11;22;33;44;55;66

COBOL

This is a complete program that demonstrates the bubble sort algorithm in COBOL. <lang cobol>

      identification division.
      program-id. BUBBLSRT.
      data division.
      working-storage section.
      01 changed-flag      pic x.
         88 hasChanged         value 'Y'.
         88 hasNOTChanged      value 'N'.
      01 itemCount         pic 99.
      01 tempItem          pic 99.
      01 itemArray.   
         03 itemArrayCount pic 99.
         03 item           pic 99 occurs 99 times
                                  indexed by itemIndex.
     *          
      procedure division.
      main.
     * place the values to sort into itemArray
          move 10 to itemArrayCount 
          move 28 to item (1)
          move 44 to item (2)
          move 46 to item (3)           
          move 24 to item (4)
          move 19 to item (5)
          move  2 to item (6)
          move 17 to item (7)
          move 11 to item (8)
          move 24 to item (9)           
          move  4 to item (10)
     * store the starting count in itemCount and perform the sort    
          move itemArrayCount to itemCount
          perform bubble-sort
     * output the results     
          perform varying itemIndex from 1 by 1 
             until itemIndex > itemArrayCount
             display item (itemIndex) ';' with no advancing
          end-perform   
     * thats it!       
          stop run.
     *     
      bubble-sort.
          perform with test after until hasNOTchanged
             set hasNOTChanged to true
             subtract 1 from itemCount
             perform varying itemIndex from 1 by 1 
                until itemIndex > itemCount
                if item (itemIndex) > item (itemIndex + 1)
                   move item (itemIndex) to tempItem
                   move item (itemIndex + 1) to item (itemIndex)
                   move tempItem to item (itemIndex + 1)
                   set hasChanged to true
                end-if   
             end-perform   
          end-perform   
          .

</lang>

Output:
 Output: 02;04;11;17;19;24;24;28;44;46; 

Common Lisp

Bubble sort an sequence in-place, using the < operator for comparison if no comaprison function is provided <lang lisp>(defun bubble-sort (sequence &optional (compare #'<))

 "sort a sequence (array or list) with an optional comparison function (cl:< is the default)"
 (loop with sorted = nil until sorted do
       (setf sorted t)
       (loop for a below (1- (length sequence)) do
             (unless (funcall compare (elt sequence a)
                                      (elt sequence (1+ a)))
               (rotatef (elt sequence a)
                        (elt sequence (1+ a)))
               (setf sorted nil)))))</lang>

<lang lisp>(bubble-sort (list 5 4 3 2 1))</lang>

elt has linear access time for lists, making the prior implementation of bubble-sort very expensive (although very clear, and straightforward to code. Here is an implementation that works efficiently for both vectors and lists. For lists it also has the nice property that the input list and the sorted list begin with the same cons cell.

<lang lisp>(defun bubble-sort-vector (vector predicate &aux (len (1- (length vector))))

 (do ((swapped t)) ((not swapped) vector)
   (setf swapped nil)
   (do ((i (min 0 len) (1+ i))) ((eql i len))
     (when (funcall predicate (aref vector (1+ i)) (aref vector i))
       (rotatef (aref vector i) (aref vector (1+ i)))
       (setf swapped t)))))

(defun bubble-sort-list (list predicate)

 (do ((swapped t)) ((not swapped) list)
   (setf swapped nil)
   (do ((list list (rest list))) ((endp (rest list)))
     (when (funcall predicate (second list) (first list))
       (rotatef (first list) (second list))
       (setf swapped t)))))

(defun bubble-sort (sequence predicate)

 (etypecase sequence
   (list (bubble-sort-list sequence predicate))
   (vector (bubble-sort-vector sequence predicate))))</lang>

D

<lang d>import std.stdio, std.algorithm;

void bubbleSort(T)(T[] data) pure nothrow {

   auto itemCount = data.length;
   bool hasChanged = false;
   do {
       hasChanged = false;
       itemCount--;
       foreach (immutable i; 0 .. itemCount)
           if (data[i] > data[i + 1]) {
               swap(data[i], data[i + 1]);
               hasChanged = true;
           }
   } while (hasChanged);

}

void main() {

   auto array = [28, 44, 46, 24, 19, 2, 17, 11, 25, 4];
   array.bubbleSort();
   writeln(array);

}</lang>

Output:
[2, 4, 11, 17, 19, 24, 25, 28, 44, 46]

Delphi

Dynamic array is a 0-based array of variable length

Static array is an arbitrary-based array of fixed length <lang Delphi>program TestBubbleSort;

{$APPTYPE CONSOLE}

{.$DEFINE DYNARRAY} // remove '.' to compile with dynamic array

type

 TItem = Integer;   // declare ordinal type for array item

{$IFDEF DYNARRAY}

 TArray = array of TItem;          // dynamic array

{$ELSE}

 TArray = array[0..15] of TItem;   // static array

{$ENDIF}

procedure BubbleSort(var A: TArray); var

 Item: TItem;
 K, L, J: Integer;

begin

 L:= Low(A) + 1;
 repeat
   K:= High(A);
   for J:= High(A) downto L do begin
     if A[J - 1] > A[J] then begin
       Item:= A[J - 1];
       A[J - 1]:= A[J];
       A[J]:= Item;
       K:= J;
     end;
   end;
   L:= K + 1;
 until L > High(A);

end;

var

 A: TArray;
 I: Integer;

begin {$IFDEF DYNARRAY}

 SetLength(A, 16);

{$ENDIF}

 for I:= Low(A) to High(A) do
   A[I]:= Random(100);
 for I:= Low(A) to High(A) do
   Write(A[I]:3);
 Writeln;
 BubbleSort(A);
 for I:= Low(A) to High(A) do
   Write(A[I]:3);
 Writeln;
 Readln;

end.</lang>

Output:
  0  3 86 20 27 67 31 16 37 42  8 47  7 84  5 29
  0  3  5  7  8 16 20 27 29 31 37 42 47 67 84 86

E

<lang e>def bubbleSort(target) {

 __loop(fn {
   var changed := false
   for i in 0..(target.size() - 2) {
     def [a, b] := target(i, i + 2)
     if (a > b) {
       target(i, i + 2) := [b, a]
       changed := true
     }
   }
   changed
 })

}</lang>

(Uses the primitive __loop directly because it happens to map to the termination test for this algorithm well.)

EchoLisp

<lang scheme>

sorts a vector of objects in place
proc is an user defined comparison procedure

(define (bubble-sort V proc) (define length (vector-length V))

   (for* ((i (in-range 0 (1- length))) (j (in-range (1+ i) length)))
   (unless (proc (vector-ref V i) (vector-ref V j)) (vector-swap! V i j)))
   V)


(define V #( albert antoinette elvis zen simon)) (define (sort/length a b) ;; sort by string length

   (< (string-length a) (string-length b)))

(bubble-sort V sort/length)

   → #(zen simon elvis albert antoinette)

</lang>

Eiffel

Works with: EiffelStudio version 6.6 (with provisional loop syntax)

This solution is presented in two classes. The first is a simple application that creates a set, an instance of MY_SORTED_SET, and adds elements to the set in unsorted order. It iterates across the set printing the elements, then it sorts the set, and reprints the elements.

<lang eiffel>class

   APPLICATION

create

   make

feature

   make
           -- Create and print sorted set
       do
           create my_set.make
           my_set.put_front (2)
           my_set.put_front (6)
           my_set.put_front (1)
           my_set.put_front (5)
           my_set.put_front (3)
           my_set.put_front (9)
           my_set.put_front (8)
           my_set.put_front (4)
           my_set.put_front (10)
           my_set.put_front (7)
           print ("Before: ")
           across my_set as ic loop print (ic.item.out + " ")  end
           print ("%NAfter : ")
           my_set.sort
           across my_set as ic loop print (ic.item.out + " ")  end
       end
   my_set: MY_SORTED_SET [INTEGER]
           -- Set to be sorted

end</lang>

The second class is MY_SORTED_SET.

<lang eiffel>class

   MY_SORTED_SET [G -> COMPARABLE]

inherit

   TWO_WAY_SORTED_SET [G]
       redefine
           sort
       end

create

   make

feature

   sort
           -- Sort with bubble sort
       local
           l_unchanged: BOOLEAN
           l_item_count: INTEGER
           l_temp: G
       do
           from
               l_item_count := count
           until
               l_unchanged
           loop
               l_unchanged := True
               l_item_count := l_item_count - 1
               across 1 |..| l_item_count as ic loop
                   if Current [ic.item] > Current [ic.item + 1] then
                       l_temp := Current [ic.item]
                       Current [ic.item] := Current [ic.item + 1]
                       Current [ic.item + 1] := l_temp
                       l_unchanged := False
                   end
               end
           end
       end

end</lang>

This class inherits from the Eiffel library class TWO_WAY_SORTED_SET, which implements sets whose elements are comparable. Therefore, the set can be ordered and in fact is kept so under normal circumstances.

MY_SORTED_SET redefines only the routine sort which contains the implementation of the sort algorithm. The implementation in the redefined version of sort in MY_SORTED_SET uses a bubble sort.

Output:
Before: 7 10 4 8 9 3 5 1 6 2
After : 1 2 3 4 5 6 7 8 9 10

TWO_WAY_SORTED_SET is implemented internally as a list. For this example, we use the feature put_front which explicitly adds each new element to the beginning of the list, allowing us to show that the elements are unordered until we sort them. It also causes, in the "Before" output, the elements to be printed in the reverse of the order in which they were added. Under normal circumstances, we would use the feature extend (rather than put_front) to add elements to the list. This would assure that the order was maintained even as elements were added.

Elixir

<lang elixir>defmodule Sort do

 def bubble_sort(list) when length(list)<=1, do: list
 def bubble_sort(list) when is_list(list), do: bubble_sort(list, [])
 
 def bubble_sort([x], sorted), do: [x | sorted]
 def bubble_sort(list, sorted) do
   {rest, [max]} = Enum.split(bubble_move(list), -1)
   bubble_sort(rest, [max | sorted])
 end
 
 def bubble_move([x]), do: [x]
 def bubble_move([x, y | t]) when x > y, do: [y | bubble_move([x | t])]
 def bubble_move([x, y | t])           , do: [x | bubble_move([y | t])]
 

end

IO.inspect Sort.bubble_sort([3,2,1,4,5,2])</lang>

Output:
[1, 2, 2, 3, 4, 5]

Erlang

sort/3 copied from Stackoverflow. <lang Erlang> -module( bubble_sort ).

-export( [list/1, task/0] ).

list( To_be_sorted ) -> sort( To_be_sorted, [], true ).

task() -> List = "asdqwe123", Sorted = list( List ), io:fwrite( "List ~p is sorted ~p~n", [List, Sorted] ).


sort( [], Acc, true ) -> lists:reverse( Acc ); sort( [], Acc, false ) -> sort( lists:reverse(Acc), [], true ); sort( [X, Y | T], Acc, _Done ) when X > Y -> sort( [X | T], [Y | Acc], false ); sort( [X | T], Acc, Done ) -> sort( T, [X | Acc], Done ). </lang>

Output:
7> bubble_sort:task().
List "asdqwe123" is sorted "123adeqsw"

Euphoria

<lang euphoria>function bubble_sort(sequence s)

   object tmp
   integer changed
   for j = length(s) to 1 by -1 do
       changed = 0
       for i = 1 to j-1 do
           if compare(s[i], s[i+1]) > 0 then
               tmp = s[i]
               s[i] = s[i+1]
               s[i+1] = tmp
               changed = 1
           end if
       end for
       if not changed then
           exit
       end if
   end for
   return s

end function

include misc.e constant s = {4, 15, "delta", 2, -31, 0, "alfa", 19, "gamma", 2, 13, "beta", 782, 1}

puts(1,"Before: ") pretty_print(1,s,{2}) puts(1,"\nAfter: ") pretty_print(1,bubble_sort(s),{2})</lang>

Output:
Before: {
  4,
  15,
  "delta",
  2,
  -31,
  0,
  "alfa",
  19,
  "gamma",
  2,
  13,
  "beta",
  782,
  1
}
After: {
  -31,
  0,
  1,
  2,
  2,
  4,
  13,
  15,
  19,
  782,
  "alfa",
  "beta",
  "delta",
  "gamma"
}

Ezhil

<lang Ezhil>

    1. இந்த நிரல் ஒரு பட்டியலில் உள்ள எண்களை Bubble Sort என்ற முறைப்படி ஏறுவரிசையிலும் பின்னர் அதையே இறங்குவரிசையிலும் அடுக்கித் தரும்
    1. மாதிரிக்கு நாம் ஏழு எண்களை எடுத்துக்கொள்வோம்

எண்கள் = [5, 1, 10, 8, 1, 21, 4, 2] எண்கள்பிரதி = எண்கள்

பதிப்பி "ஆரம்பப் பட்டியல்:" பதிப்பி எண்கள்

நீளம் = len(எண்கள்) குறைநீளம் = நீளம் - 1

@(குறைநீளம் != -1) வரை

 மாற்றம் = -1
 @(எண் = 0, எண் < குறைநீளம், எண் = எண் + 1) ஆக
   முதலெண் = எடு(எண்கள், எண்)
   இரண்டாமெண் = எடு(எண்கள், எண் + 1)
   @(முதலெண் > இரண்டாமெண்) ஆனால்
     ## பெரிய எண்களை ஒவ்வொன்றாகப் பின்னே நகர்த்துகிறோம்
     வெளியேஎடு(எண்கள், எண்)
     நுழைக்க(எண்கள், எண், இரண்டாமெண்)
     வெளியேஎடு(எண்கள், எண் + 1)
     நுழைக்க(எண்கள், எண் + 1, முதலெண்)
     மாற்றம் = எண்
   முடி
 முடி
 குறைநீளம் = மாற்றம்

முடி

பதிப்பி "ஏறு வரிசையில் அமைக்கப்பட்ட பட்டியல்:" பதிப்பி எண்கள்

    1. இதனை இறங்குவரிசைக்கு மாற்றுவதற்கு எளிய வழி

தலைகீழ்(எண்கள்)

    1. இப்போது, நாம் ஏற்கெனவே எடுத்துவைத்த எண்களின் பிரதியை Bubble Sort முறைப்படி இறங்குவரிசைக்கு மாற்றுவோம்

நீளம் = len(எண்கள்பிரதி) குறைநீளம் = நீளம் - 1

@(குறைநீளம் != -1) வரை

 மாற்றம் = -1
 @(எண் = 0, எண் < குறைநீளம், எண் = எண் + 1) ஆக
   முதலெண் = எடு(எண்கள்பிரதி, எண்)
   இரண்டாமெண் = எடு(எண்கள்பிரதி, எண் + 1)
   @(முதலெண் < இரண்டாமெண்) ஆனால்
     ## சிறிய எண்களை ஒவ்வொன்றாகப் பின்னே நகர்த்துகிறோம்
     வெளியேஎடு(எண்கள்பிரதி, எண்)
     நுழைக்க(எண்கள்பிரதி, எண், இரண்டாமெண்)
     வெளியேஎடு(எண்கள்பிரதி, எண் + 1)
     நுழைக்க(எண்கள்பிரதி, எண் + 1, முதலெண்)
     மாற்றம் = எண்
   முடி
 முடி
 குறைநீளம் = மாற்றம்

முடி

பதிப்பி "இறங்கு வரிசையில் அமைக்கப்பட்ட பட்டியல்:" பதிப்பி எண்கள்பிரதி

</lang>

F#

<lang fsharp>let BubbleSort (lst : list<int>) =

   let rec sort accum rev lst =
       match lst, rev with
       | [], true -> accum |> List.rev
       | [], false -> accum |> List.rev |> sort [] true
       | x::y::tail, _ when x > y -> sort (y::accum) false (x::tail)
       | head::tail, _ -> sort (head::accum) rev tail
   sort [] true lst

</lang>

Factor

<lang factor>USING: fry kernel locals math math.order sequences sequences.private ; IN: rosetta.bubble

<PRIVATE

?exchange ( i seq quot -- ? )
   i i 1 + [ seq nth-unsafe ] bi@ quot call +gt+ = :> doit?
   doit? [ i i 1 + seq exchange ] when
   doit? ; inline
1pass ( seq quot -- ? )
   [ [ length 1 - iota ] keep ] dip
   '[ _ _ ?exchange ] [ or ] map-reduce ; inline

PRIVATE>

sort! ( seq quot -- )
   over empty?
   [ 2drop ] [ '[ _ _ 1pass ] loop ] if ; inline
natural-sort! ( seq -- )
   [ <=> ] sort! ;</lang>

It is possible to pass your own comparison operator to sort!, so you can f.e. sort your sequence backwards with passing [ >=< ] into it.

<lang factor>10 [ 10000 random ] replicate [ "Before: " write . ] [ "Natural: " write [ natural-sort! ] keep . ] [ "Reverse: " write [ [ >=< ] sort! ] keep . ] tri</lang>

Before:  { 3707 5045 4661 1489 3140 7195 8844 6506 6322 3199 }
Natural: { 1489 3140 3199 3707 4661 5045 6322 6506 7195 8844 }
Reverse: { 8844 7195 6506 6322 5045 4661 3707 3199 3140 1489 }

Fish

This is not a complete implementation of bubblesort: it doesn't keep a boolean flag whether to stop, so it goes on printing each stage of the sorting process ad infinitum.

<lang fish>v Sorts the (pre-loaded) stack

 with bubblesort.

v < \l0=?;l& >&:1=?v1-&2[$:{:{](?${

         >~{ao       ^
     >~}l &{   v

o","{n:&-1^?=0:&<</lang>

Forth

Sorts the 'cnt' cells stored at 'addr' using the test stored in the deferred word 'bubble-test'. Uses forth local variables for clarity.

<lang forth>defer bubble-test ' > is bubble-test

bubble { addr cnt -- }
 cnt 1 do
   addr cnt i - cells bounds do
     i 2@ bubble-test if i 2@ swap i 2! then
   cell +loop
 loop ;</lang>

This is the same algorithm done without the local variables:

<lang forth>: bubble ( addr cnt -- )

 dup 1 do
   2dup i - cells bounds do
     i 2@ bubble-test if i 2@ swap i 2! then
   cell +loop
 loop ;</lang>

Version with O(n) best case: <lang forth>: bubble ( addr len -- )

 begin
   1- 2dup  true -rot  ( sorted addr len-1 )
   cells bounds ?do
     i 2@ bubble-test if
       i 2@ swap i 2!
       drop false   ( mark unsorted )
     then
   cell +loop  ( sorted )
 until 2drop ;</lang>

Test any version with this:

create test
8 , 1 , 4 , 2 , 10 , 3 , 7 , 9 , 6 , 5 ,
here test - cell / constant tcnt

test tcnt cells dump
' > is bubble-test
test tcnt bubble
test tcnt cells dump
' < is bubble-test
test tcnt bubble
test tcnt cells dump

Fortran

<lang fortran>SUBROUTINE Bubble_Sort(a)

 REAL, INTENT(in out), DIMENSION(:) :: a
 REAL :: temp
 INTEGER :: i, j
 LOGICAL :: swapped

 DO j = SIZE(a)-1, 1, -1
   swapped = .FALSE.
   DO i = 1, j
     IF (a(i) > a(i+1)) THEN
       temp = a(i)
       a(i) = a(i+1)
       a(i+1) = temp
       swapped = .TRUE.
     END IF
   END DO
   IF (.NOT. swapped) EXIT
 END DO

END SUBROUTINE Bubble_Sort</lang>

FreeBASIC

Per task pseudo code: <lang FreeBASIC>' version 21-06-2015 ' compile with: fbc -s console ' for boundry checks on array's compile with: fbc -s console -exx

Sub bubblesort(bs() As Integer)

   ' sort from lower bound to the highter bound
   ' array's can have subscript range from -2147483648 to +2147483647
   Dim As Integer lb = LBound(bs)
   Dim As Integer ub = UBound(bs) -1
   Dim As Integer done, i
   Do
       done = 0
       For i = lb To ub 
           ' replace "<" with ">" for downwards sort
           If bs(i) > bs(i + 1) Then
               Swap bs(i), bs(i + 1)
               done = 1
           End If
       Next
       ub = ub -1
   Loop Until done = 0

End Sub

' ------=< MAIN >=------

Dim As Integer i, array(-7 To 7)

Dim As Integer a = LBound(array), b = UBound(array)

Randomize Timer For i = a To b : array(i) = i  : Next For i = a To b ' little shuffle

   Swap array(i), array(Rnd * b)

Next

Print "unsort "; For i = a To b : Print Using "####"; array(i); : Next : Print bubblesort(array()) ' sort the array Print " sort "; For i = a To b : Print Using "####"; array(i); : Next : Print

' empty keyboard buffer While InKey <> "" : Var _key_ = InKey : Wend Print : Print "hit any key to end program" Sleep End</lang>

Output:
unsort    6   2   4   7   1   5  -6  -2   3  -4  -7  -3  -1  -5   0
  sort   -7  -6  -5  -4  -3  -2  -1   0   1   2   3   4   5   6   7

Go

Per task pseudocode: <lang go>package main

import "fmt"

func main() {

   list := []int{31, 41, 59, 26, 53, 58, 97, 93, 23, 84}
   fmt.Println("unsorted:", list)
   bubblesort(list)
   fmt.Println("sorted!  ", list)

}

func bubblesort(a []int) {

   for itemCount := len(a) - 1; ; itemCount-- {
       hasChanged := false
       for index := 0; index < itemCount; index++ {
           if a[index] > a[index+1] {
               a[index], a[index+1] = a[index+1], a[index]
               hasChanged = true
           }
       }
       if hasChanged == false {
           break
       }
   }

}</lang>

More generic version that can sort anything that implements sort.Interface: <lang go>package main

import (

 "sort"
 "fmt"

)

func main() {

   list := []int{31, 41, 59, 26, 53, 58, 97, 93, 23, 84}
   fmt.Println("unsorted:", list)
   bubblesort(sort.IntSlice(list))
   fmt.Println("sorted!  ", list)

}

func bubblesort(a sort.Interface) {

   for itemCount := a.Len() - 1; ; itemCount-- {
       hasChanged := false
       for index := 0; index < itemCount; index++ {
           if a.Less(index+1, index) {
               a.Swap(index, index+1)
               hasChanged = true
           }
       }
       if !hasChanged {
           break
       }
   }

}</lang>

Groovy

Solution: <lang groovy>def makeSwap = { a, i, j = i+1 -> print "."; ai,j = aj,i }

def checkSwap = { a, i, j = i+1 -> [(a[i] > a[j])].find { it }.each { makeSwap(a, i, j) } }

def bubbleSort = { list ->

   boolean swapped = true
   while (swapped) { swapped = (1..<list.size()).any { checkSwap(list, it-1) } }
   list

}</lang>

Test Program: <lang groovy>println bubbleSort([23,76,99,58,97,57,35,89,51,38,95,92,24,46,31,24,14,12,57,78,4]) println bubbleSort([88,18,31,44,4,0,8,81,14,78,20,76,84,33,73,75,82,5,62,70,12,7,1])</lang>

Output:
..............................................................................................................................................[4, 12, 14, 23, 24, 24, 31, 35, 38, 46, 51, 57, 57, 58, 76, 78, 89, 92, 95, 97, 99]
.........................................................................................................................................[0, 1, 4, 5, 7, 8, 12, 14, 18, 20, 31, 33, 44, 62, 70, 73, 75, 76, 78, 81, 82, 84, 88]

Haskell

This version checks for changes in a separate step for simplicity, because Haskell has no variables to track them with. <lang haskell>bsort :: Ord a => [a] -> [a] bsort s = case _bsort s of

              t | t == s    -> t
                | otherwise -> bsort t
 where _bsort (x:x2:xs) | x > x2    = x2:(_bsort (x:xs))
                        | otherwise = x:(_bsort (x2:xs))
       _bsort s = s</lang>

This version uses the polymorphic Maybe type to designate unchanged lists. (The type signature of _bsort is now Ord a => [a] -> Maybe [a].) It is slightly faster than the previous one.

<lang haskell>import Data.Maybe (fromMaybe) import Control.Monad

bsort :: Ord a => [a] -> [a] bsort s = maybe s bsort $ _bsort s

 where _bsort (x:x2:xs) = if x > x2
           then Just $ x2 : fromMaybe (x:xs) (_bsort $ x:xs)
           else liftM (x:) $ _bsort (x2:xs)
       _bsort _         = Nothing</lang>

This version is based on the above, but avoids sorting whole list each time. To implement this without a counter and retain using pattern matching, inner sorting is reversed, and then result is reversed back. Sorting is based on a predicate, e. g. (<) or (>).

<lang haskell>import Data.Maybe (fromMaybe) import Control.Monad

bubbleSortBy :: (a -> a -> Bool) -> [a] -> [a] bubbleSortBy f as = case innerSort $ reverse as of

                        Nothing -> as
                        Just v  -> let (x:xs) = reverse v
                                  in x : bubbleSortBy f xs
   where innerSort (a:b:cs) = if b `f` a
                                 then liftM (a:) $ innerSort (b:cs)
                                 else Just $ b : fromMaybe (a:cs)
                                               (innerSort $ a:cs)
         innerSort _        = Nothing

bsort :: Ord a => [a] -> [a] bsort = bubbleSortBy (<)</lang>

HicEst

<lang fortran>SUBROUTINE Bubble_Sort(a)

 REAL :: a(1)

 DO j = LEN(a)-1, 1, -1
   swapped = 0
   DO i = 1, j
     IF (a(i) > a(i+1)) THEN
       temp = a(i)
       a(i) = a(i+1)
       a(i+1) = temp
       swapped = 1
     ENDIF
   ENDDO
   IF (swapped == 0) RETURN
 ENDDO

END</lang>

Icon and Unicon

Icon/Unicon implementation of a bubble sort <lang Icon>procedure main() #: demonstrate various ways to sort a list and string

  demosort(bubblesort,[3, 14, 1, 5, 9, 2, 6, 3],"qwerty")

end

procedure bubblesort(X,op) #: return sorted list local i,swapped

  op := sortop(op,X)                # select how and what we sort

  swapped := 1 
  while \swapped := &null do         # the sort
     every  i := 2 to *X do  
        if op(X[i],X[i-1]) then  
           X[i-1] :=: X[swapped := i] 
  return X

end</lang>

Output:
Sorting Demo using procedure bubblesort
  on list : [ 3 14 1 5 9 2 6 3 ]
    with op = &null:         [ 1 2 3 3 5 6 9 14 ]   (0 ms)
    with op = "numeric":     [ 1 2 3 3 5 6 9 14 ]   (0 ms)
    with op = "string":      [ 1 14 2 3 3 5 6 9 ]   (0 ms)
    with op = ">>":          [ 9 6 5 3 3 2 14 1 ]   (0 ms)
    with op = ">":           [ 14 9 6 5 3 3 2 1 ]   (0 ms)
    with op = procedure cmp: [ 1 2 3 3 5 6 9 14 ]   (1 ms)
    with op = "cmp":         [ 1 2 3 3 5 6 9 14 ]   (0 ms)
  on string : "qwerty"
    with op = &null:         "eqrtwy"   (0 ms)

The following code supports this and other sorting demonstrations.

  • Sorting illustrates a difference in the way Icon and Unicon handles data types. Built-in operators for comparing data types make a syntactic distinction between numeric and string types, and sorting structured and user-defined types require custom code. An added complication arises because mixed types are allowed. Two approaches are possible here: (1) that taken by the built-in sort which sorts first by type and then value The sort order of types is: &null, integer, real, string, cset, procedure, list, set, table, and record; and (2) Coercion of types which is used here (and implemented in 'sortop') to decide on using string or numeric sorting. These sorts will not handle more exotic type mixes.
  • The 'sortop' procedure allows various methods of comparison be selected including customized ones. The example could be made more general to deal with coercion of types like cset to string (admittedly an uninteresting example as csets are already sorted). Custom comparators are shown by and example procedure 'cmp'.
  • 'demosort' can apply different sorting procedures and operators to lists and strings to show how this works. The routines 'displaysort' and 'writex' are helpers.

<lang icon>invocable all # for op

procedure sortop(op,X) #: select how to sort

   op := case op of {               
            "string":  "<<"
            "numeric": "<"
            &null:     if type(!X) == "string" then "<<" else "<"
            default:   op
         }

return proc(op, 2) | runerr(123, image(op)) end

procedure cmp(a,b) #: example custom comparison procedure

   return a < b                      #  Imagine a complex comparison test here!

end

procedure demosort(sortproc,L,s) # demonstrate sort on L and s

   write("Sorting Demo using ",image(sortproc))
   writes("  on list : ")
   writex(L)
   displaysort(sortproc,L)           # default string sort
   displaysort(sortproc,L,"numeric") # explicit numeric sort
   displaysort(sortproc,L,"string")  # explicit string sort
   displaysort(sortproc,L,">>")      # descending string sort
   displaysort(sortproc,L,">")       # descending numeric sort
   displaysort(sortproc,L,cmp)       # ascending custom comparison
   displaysort(sortproc,L,"cmp")     # ascending custom comparison

   writes("  on string : ")
   writex(s)
   displaysort(sortproc,s)           # sort characters in a string
   write()
   return

end

procedure displaysort(sortproc,X,op) #: helper to show sort behavior local t,SX

   writes("    with op = ",left(image(op)||":",15))
   X := copy(X)
   t := &time
   SX := sortproc(X,op)
   writex(SX,"   (",&time - t," ms)")
   return 

end

procedure writex(X,suf[]) #: helper for displaysort

   if type(X) == "string" then 
       writes(image(X))
   else {
       writes("[")
       every writes(" ",image(!X))
       writes(" ]")
       }
   every writes(!suf)
   write()

return end</lang>

J

Generally, this task should be accomplished in J using /:~ list. Here we take an approach that's more comparable with the other examples on this page.

<lang j>bubbleSort=: (([ (<. , >.) {.@]) , }.@])/^:_</lang>

Test program:

<lang j>  ?. 10 $ 10 4 6 8 6 5 8 6 6 6 9

  bubbleSort ?. 10 $ 10

4 5 6 6 6 6 6 8 8 9</lang>

For the most part, bubble sort works against J's strengths. However, once a single pass has been implemented as a list operation, ^:_ tells J to repeat this until the result stops changing.

Java

Bubble sorting (ascending) an array of any Comparable type: <lang java>public static <E extends Comparable<? super E>> void bubbleSort(E[] comparable) {

   boolean changed = false;
   do {
       changed = false;
       for (int a = 0; a < comparable.length - 1; a++) {
           if (comparable[a].compareTo(comparable[a + 1]) > 0) {
               E tmp = comparable[a];
               comparable[a] = comparable[a + 1];
               comparable[a + 1] = tmp;
               changed = true;
           }
       }
   } while (changed);

}</lang>

For descending, simply switch the direction of comparison: <lang java>if (comparable[a].compareTo(comparable[b]) < 0){

  //same swap code as before

}</lang>

JavaScript

<lang javascript>Array.prototype.bubblesort = function() {

   var done = false;
   while (!done) {
       done = true;
       for (var i = 1; i<this.length; i++) {
           if (this[i-1] > this[i]) {
               done = false;
               [this[i-1], this[i]] = [this[i], this[i-1]]
           }
       }
   }
   return this;

}</lang>

Works with: SEE version 3.0
Works with: OSSP js version 1.6.20070208

<lang javascript>Array.prototype.bubblesort = function() {

 var done = false;
 while (! done) {
   done = true;
   for (var i = 1; i < this.length; i++) {
     if (this[i - 1] > this[i]) {
       done = false;
       var tmp = this[i - 1];
       this[i - 1] = this[i];
       this[i] = tmp;
     }
   }
 }
 return this;

}</lang>

Example: <lang javascript>var my_arr = ["G", "F", "C", "A", "B", "E", "D"]; my_arr.bubblesort(); print(my_arr);</lang>

Output:
 A,B,C,D,E,F,G

jq

<lang jq>def bubble_sort:

 def swap(i;j): .[i] as $x | .[i]=.[j] | .[j]=$x;
 # input/output: [changed, list]
 reduce range(0; length) as $i
   ( [false, .];
     if $i > 0 and (.[0]|not) then .
     else reduce range(0; (.[1]|length) - $i - 1) as $j
       (.[0] = false;
       .[1] as $list
       | if $list[$j] > $list[$j + 1] then [true, ($list|swap($j; $j+1))]
         else .
         end )
     end  ) | .[1] ;</lang>

Example: <lang jq>(

[3,2,1],
[1,2,3],
["G", "F", "C", "A", "B", "E", "D"]

) | bubble_sort</lang>

Output:

<lang sh>$ jq -c -n -f Bubble_sort.jq [1,2,3] [1,2,3] ["A","B","C","D","E","F","G"]</lang>

Julia

<lang Julia> function bubblesort{T}(a::AbstractArray{T,1})

   b = copy(a)
   isordered = false
   span = length(b)
   while !isordered && span > 1
       isordered = true
       for i in 2:span
           if b[i] < b[i-1]
               t = b[i]
               b[i] = b[i-1]
               b[i-1] = t
               isordered = false
           end
       end
       span -= 1
   end
   return b

end

a = [rand(-100:100) for i in 1:20] println("Before bubblesort:") println(a) a = bubblesort(a) println("\nAfter bubblesort:") println(a) </lang>

Output:
Before bubblesort:
[95,-40,-93,38,95,-20,-13,-61,81,51,-54,77,-4,-49,-99,-55,28,-52,2,-28]

After bubblesort:
[-99,-93,-61,-55,-54,-52,-49,-40,-28,-20,-13,-4,2,28,38,51,77,81,95,95]

Here bubblesort was used on a list of integers. As written the function will work on lists of any objects for which isless is defined.

Kotlin

Translation of: Java

<lang kotlin>fun <T> bubbleSort(a : Array<T>, c: Comparator<T>) {

   var changed : Boolean
   do {
       changed = false
       for (i in 0 .. a.size - 2) {
           if (c.compare(a[i], a[i + 1]) > 0) {
               val tmp = a[i]
               a[i] = a[i + 1]
               a[i + 1] = tmp
               changed = true
           }
       }
   } while (changed)

}</lang>

Io

<lang Io> List do(

 bubblesort := method(
   t := true
   while( t,
     t := false
     for( j, 0, self size - 2,
       if( self at( j ) start > self at( j+1 ) start,
         self swapIndices( j,j+1 )
         t := true
       )
     )
   )
   return( self )
 )

) </lang>

Liberty BASIC

<lang lb>

   itemCount = 20
   dim item(itemCount)
   for i = 1 to itemCount
       item(i) = int(rnd(1) * 100)
   next i
   print "Before Sort"
   for i = 1 to itemCount
       print item(i)
   next i
   print: print
   counter = itemCount
   do
       hasChanged = 0
       for i = 1 to counter - 1
           if item(i) > item(i + 1) then
               temp = item(i)
               item(i) = item(i + 1)
               item(i + 1) = temp
               hasChanged = 1
           end if
       next i
       counter =counter -1
   loop while hasChanged = 1
   print "After Sort"
   for i = 1 to itemCount
       print item(i)
   next i

end </lang>

Lisaac

<lang Lisaac>Section Header

+ name := BUBBLE_SORT;

- external := `#include <time.h>`;

Section Public

- main <- (

 + a : ARRAY(INTEGER);
 a := ARRAY(INTEGER).create 0 to 100;
 `srand(time(NULL))`;
 0.to 100 do { i : INTEGER;
   a.put `rand()`:INTEGER to i;
 };
 bubble a;
 a.foreach { item : INTEGER;
   item.print;
   '\n'.print;
 };

);

- bubble a : ARRAY(INTEGER) <- (

 + lower, size, t : INTEGER;
 + sorted : BOOLEAN;
 lower := a.lower;
 size := a.upper - lower + 1;
 {
   sorted := TRUE;
   size := size - 1;
   0.to (size - 1) do { i : INTEGER;
     (a.item(lower + i + 1) < a.item(lower + i)).if {
       t := a.item(lower + i + 1);
       a.put (a.item(lower + i)) to (lower + i + 1);
       a.put t to (lower + i);
       sorted := FALSE;
     };
   };
 }.do_while {!sorted};

);</lang>

Lua

<lang Lua> function bubbleSort(A)

 local itemCount=#A
 local hasChanged
 repeat
   hasChanged = false
   itemCount=itemCount - 1
   for i = 1, itemCount do
     if A[i] > A[i + 1] then
       A[i], A[i + 1] = A[i + 1], A[i]
       hasChanged = true
     end
   end
 until hasChanged == false

end </lang>

Example: <lang lua> list = { 5, 6, 1, 2, 9, 14, 2, 15, 6, 7, 8, 97 } bubbleSort(list) for i, j in pairs(list) do

   print(j)

end </lang>

Lucid

[1] <lang lucid>bsort(a) = if iseod(first a) then a else

             follow(bsort(allbutlast(b)),last(b)) fi
 where
  b = bubble(a);
  bubble(a) = smaller(max, next a)
      where
       max = first a fby larger(max, next a);
       larger(x,y) = if iseod(y) then y elseif x
      end;
  follow(x,y) = if xdone then y upon xdone else x fi
                  where
                     xdone = iseod x fby xdone or iseod x;
                  end;
  last(x) = (x asa iseod next x) fby eod;
  allbutlast(x) = if not iseod(next x) then x else eod fi;
 end</lang>

M4

<lang M4>divert(-1)

define(`randSeed',141592653) define(`setRand',

  `define(`randSeed',ifelse(eval($1<10000),1,`eval(20000-$1)',`$1'))')

define(`rand_t',`eval(randSeed^(randSeed>>13))') define(`random',

  `define(`randSeed',eval((rand_t^(rand_t<<18))&0x7fffffff))randSeed')

define(`set',`define(`$1[$2]',`$3')') define(`get',`defn(`$1[$2]')') define(`new',`set($1,size,0)') dnl for the heap calculations, it's easier if origin is 0, so set value first define(`append',

  `set($1,size,incr(get($1,size)))`'set($1,get($1,size),$2)')

dnl swap(<name>,<j>,<name>[<j>],<k>) using arg stack for the temporary define(`swap',`set($1,$2,get($1,$4))`'set($1,$4,$3)')

define(`deck',

  `new($1)for(`x',1,$2,
        `append(`$1',eval(random%100))')')

define(`show',

  `for(`x',1,get($1,size),`get($1,x) ')')

define(`for',

  `ifelse($#,0,``$0,
  `ifelse(eval($2<=$3),1,
  `pushdef(`$1',$2)$4`'popdef(`$1')$0(`$1',incr($2),$3,`$4')')')')

define(`bubbleonce',

  `for(`x',1,$2,
     `ifelse(eval(get($1,x)>get($1,incr(x))),1,
        `swap($1,x,get($1,x),incr(x))`'1')')0')

define(`bubbleupto',

  `ifelse(bubbleonce($1,$2),0,
     `',
     `bubbleupto($1,decr($2))')')

define(`bubblesort',

  `bubbleupto($1,decr(get($1,size)))')

divert deck(`a',10) show(`a') bubblesort(`a') show(`a')</lang>

Output:
17 63 80 55 90 88 25 9 71 38

9 17 25 38 55 63 71 80 88 90

Mathematica / Wolfram Language

<lang Mathematica>bubbleSort[{w___, x_, y_, z___}] /; x > y := bubbleSort[{w, y, x, z}] bubbleSort[sortedList_] := sortedList</lang> Example:

bubbleSort[{10, 3, 7, 1, 4, 3, 8, 13, 9}]
{1, 3, 3, 4, 7, 8, 9, 10, 13}

MATLAB

<lang MATLAB>function list = bubbleSort(list)

   hasChanged = true;
   itemCount = numel(list);
   
   while(hasChanged)
       
       hasChanged = false;
       itemCount = itemCount - 1;
       
       for index = (1:itemCount)
 
           if(list(index) > list(index+1))
               list([index index+1]) = list([index+1 index]); %swap
               hasChanged = true;
           end %if
           
       end %for
   end %while

end %bubbleSort</lang>

Output:
bubbleSort([5 3 8 4 9 7 6 2 1])

ans =

     1     2     3     4     5     6     7     8     9

MAXScript

<lang maxscript>fn bubbleSort arr = (

   while true do
   (
       changed = false
       for i in 1 to (arr.count - 1) do
       (
           if arr[i] > arr[i+1] then
           (
               swap arr[i] arr[i+1]
               changed = true
           )
       )
       if not changed then exit
   )
   arr

)</lang>

-- Usage

<lang maxscript>myArr = #(9, 8, 7, 6, 5, 4, 3, 2, 1) myArr = bubbleSort myArr</lang>

MMIX

<lang mmix>Ja IS $127

         LOC Data_Segment

DataSeg GREG @ Array IS @-Data_Segment

         OCTA   999,200,125,1,1020,40,4,5,60,100

ArrayLen IS (@-Array-Data_Segment)/8

NL IS @-Data_Segment BYTE #a,0 LOC @+(8-@)&7

Buffer IS @-Data_Segment


           LOC #1000
           GREG @

sorted IS $5 i IS $6 size IS $1 a IS $0 t IS $20 t1 IS $21 t2 IS $22 % Input: $0 ptr to array, $1 its length (in octabyte) % Trashed: $5, $6, $1, $20, $21, $22 BubbleSort SETL sorted,1  % sorted = true

           SUB   size,size,1       % size--
           SETL  i,0               % i = 0

3H CMP t,i,size  % i < size ?

           BNN   t,1F              % if false, end for loop
           8ADDU $12,i,a           % compute addresses of the
           ADDU  t,i,1             % octas a[i] and a[i+1]
           8ADDU $11,t,a
           LDO   t1,$12,0          % get their values
           LDO   t2,$11,0
           CMP   t,t1,t2           % compare
           BN    t,2F              % if t1<t2, next
           STO   t1,$11,0          % else swap them
           STO   t2,$12,0
           SETL  sorted,0          % sorted = false

2H INCL i,1  % i++

           JMP   3B                % next (for loop)

1H PBZ sorted,BubbleSort % while sorted is false, loop

           GO    Ja,Ja,0
           

% Help function (Print an octabyte) % Input: $0 (the octabyte) BufSize IS 64

           GREG  @

PrintInt8 ADDU t,DataSeg,Buffer  % get buffer address

           ADDU  t,t,BufSize       % end of buffer
           SETL  t1,0              % final 0 for Fputs            
           STB   t1,t,0

1H SUB t,t,1  % t--

           DIV   $0,$0,10          % ($0,rR) = divmod($0,10)
           GET   t1,rR             % get reminder
           INCL  t1,'0'            % turn it into ascii digit
           STB   t1,t,0            % store it
           PBNZ  $0,1B             % if $0 /= 0, loop
           OR    $255,t,0          % $255 = t
           TRAP  0,Fputs,StdOut 
           GO    Ja,Ja,0           % print and return


Main ADDU $0,DataSeg,Array  % $0 = Array address

           SETL  $1,ArrayLen       % $1 = Array Len
           GO    Ja,BubbleSort     % BubbleSort it
           SETL  $4,ArrayLen       % $4 = ArrayLen

ADDU $3,DataSeg,Array  % $3 = Array address 2H BZ $4,1F  % if $4 == 0, break

           LDO   $0,$3,0           % $0 = * ($3 + 0)
           GO    Ja,PrintInt8      % print the octa
           ADDU  $255,DataSeg,NL   % add a trailing newline

TRAP 0,Fputs,StdOut

           ADDU  $3,$3,8           % next octa
           SUB   $4,$4,1           % $4--

JMP 2B  % loop 1H XOR $255,$255,$255

           TRAP  0,Halt,0          % exit(0)</lang>

Modula-2

<lang modula2>PROCEDURE BubbleSort(VAR a: ARRAY OF INTEGER);

 VAR
   changed:        BOOLEAN;
   temp, count, i: INTEGER;

BEGIN

 count := HIGH(a);
 REPEAT
   changed := FALSE;
   DEC(count);
   FOR i := 0 TO count DO
     IF a[i] > a[i+1] THEN
       temp := a[i];
       a[i] := a[i+1];
       a[i+1] := temp;
       changed := TRUE
     END
   END
 UNTIL NOT changed

END BubbleSort;</lang>

Modula-3

<lang modula3>MODULE Bubble;

PROCEDURE Sort(VAR a: ARRAY OF INTEGER) =

 VAR sorted: BOOLEAN;
     temp, len: INTEGER := LAST(a);
 BEGIN
   WHILE NOT sorted DO
     sorted := TRUE;
     DEC(len);
     FOR i := FIRST(a) TO len DO
       IF a[i+1] < a[i] THEN
         temp := a[i];
         a[i] := a[i + 1];
         a[i + 1] := temp;
         sorted := FALSE;
       END;
     END;
   END;
 END Sort;

END Bubble.</lang>

Nemerle

Functional

<lang Nemerle>using System; using System.Console;

module Bubblesort {

   Bubblesort[T] (x : list[T]) : list[T]
     where T : IComparable
   {
       def isSorted(y)
       {
           |[_] => true
           |y1::y2::ys => (y1.CompareTo(y2) < 0) && isSorted(y2::ys)
       }
       
       def sort(y)
       {
           |[y]        => [y]
           |y1::y2::ys => if (y1.CompareTo(y2) < 0) y1::sort(y2::ys)
                          else y2::sort(y1::ys)
       }
       
       def loop(y)
       {
           if (isSorted(y)) y else {def z = sort(y); loop(z)}            
       }
       
       match(x)
       {
           |[]  => []
           |_   => loop(x)
       }
   }
   
   Main() : void
   {
       def empty = [];
       def single = [2];
       def several = [2, 6, 1, 7, 3, 9, 4];
       WriteLine(Bubblesort(empty));
       WriteLine(Bubblesort(single));
       WriteLine(Bubblesort(several));
   }

}</lang>

Imperative

Translation of: C#

We use an array for this version so that we can update in place. We could use a C# style list (as in the C# example), but that seemed too easy to confuse with a Nemerle style list. <lang Nemerle>using System; using System.Console;

module Bubblesort {

   public static Bubblesort[T](this x : array[T]) : void
     where T : IComparable
   {
       mutable changed = false;
       def ln = x.Length;
       
       do
       {
           changed = false;
           foreach (i in [0 .. (ln - 2)])
           {
               when (x[i].CompareTo(x[i + 1]) > 0)
               {
                   x[i] <-> x[i + 1];
                   changed = true;
               }
           }
       } while (changed);
   }
   
   Main() : void
   {
       def several = array[2, 6, 1, 7, 3, 9, 4];
       several.Bubblesort();
       foreach (i in several)
           Write($"$i  ");
   }

}</lang>

NetRexx

<lang NetRexx>/* NetRexx */ options replace format comments java crossref savelog symbols binary

placesList = [String -

   "UK  London",     "US  New York"   -
 , "US  Boston",     "US  Washington" -
 , "UK  Washington", "US  Birmingham" -
 , "UK  Birmingham", "UK  Boston"     -

] sortedList = bubbleSort(String[] Arrays.copyOf(placesList, placesList.length))

lists = [placesList, sortedList] loop ln = 0 to lists.length - 1

 cl = lists[ln]
 loop ct = 0 to cl.length - 1
   say cl[ct]
   end ct
   say
 end ln

return

method bubbleSort(list = String[]) public constant binary returns String[]

listLen = list.length loop i_ = 0 to listLen - 1

 loop j_ = i_ + 1 to listLen - 1
   if list[i_].compareTo(list[j_]) > 0 then do
     tmpstor  = list[j_]
     list[j_] = list[i_]
     list[i_] = tmpstor
     end
   end j_
 end i_

return list </lang>

Output:
UK  London
US  New York
US  Boston
US  Washington
UK  Washington
US  Birmingham
UK  Birmingham
UK  Boston

UK  Birmingham
UK  Boston
UK  London
UK  Washington
US  Birmingham
US  Boston
US  New York
US  Washington

Translation of Pseudocode

This version is a direct implementation of this task's pseudocode. <lang NetRexx>/* NetRexx */ options replace format comments java crossref savelog symbols binary

placesList = [String -

   "UK  London",     "US  New York"   -
 , "US  Boston",     "US  Washington" -
 , "UK  Washington", "US  Birmingham" -
 , "UK  Birmingham", "UK  Boston"     -

] sortedList = bubbleSort(String[] Arrays.copyOf(placesList, placesList.length))

lists = [placesList, sortedList] loop ln = 0 to lists.length - 1

 cl = lists[ln]
 loop ct = 0 to cl.length - 1
   say cl[ct]
   end ct
   say
 end ln

return

method bubbleSort(item = String[]) public constant binary returns String[]

hasChanged = boolean itemCount = item.length loop label h_ until \hasChanged

 hasChanged  = isFalse
 itemCount = itemCount - 1
 loop index = 0 to itemCount - 1
   if item[index].compareTo(item[index + 1]) > 0 then do
     swap            = item[index]
     item[index]     = item[index + 1]
     item[index + 1] = swap
     hasChanged      = isTrue
     end
   end index
 end h_

return item

method isTrue public constant binary returns boolean

 return 1 == 1

method isFalse public constant binary returns boolean

 return \isTrue

</lang>

Nim

<lang nim>proc bubbleSort[T](a: var openarray[T]) =

 var t = true
 for n in countdown(a.len-2, 0):
   if not t: break
   t = false
   for j in 0..n:
     if a[j] <= a[j+1]: continue
     swap a[j], a[j+1]
     t = true

var a = @[4, 65, 2, -31, 0, 99, 2, 83, 782] bubbleSort a echo a</lang>

Output:
@[-31, 0, 2, 2, 4, 65, 83, 99, 782]

Objeck

Translation of: C

<lang objeck> function : Swap(p : Int[]) ~ Nil {

 t := p[0];
 p[0] := p[1];
 p[1] := t;

}

function : Sort(a : Int[]) ~ Nil {

 do {
   sorted := true;
   size -= 1;
   for (i:=0; i<a->Size(); i+=1;) {
     if (a[i+1] < a[i]) {
       swap(a+i);
       sorted := 0;
     };
   };
 } 
 while (sorted = false);

} </lang>

Objective-C

<lang objc>- (NSArray *) bubbleSort:(NSMutableArray *)unsorted {

   BOOL done = false;
   
   while (!done) {
       done = true;
       for (int i = 1; i < unsorted.count; i++) {
           if ( [[unsorted objectAtIndex:i-1] integerValue] > [[unsorted objectAtIndex:i] integerValue] ) {
               [unsorted exchangeObjectAtIndex:i withObjectAtIndex:i-1];
               done = false;
           }
       }
   }
   
   return unsorted;

} </lang>

OCaml

Like the Haskell versions above:

This version checks for changes in a separate step for simplicity. <lang ocaml>let rec bsort s =

 let rec _bsort = function
   | x :: x2 :: xs when x > x2 ->
       x2 :: _bsort (x :: xs)
   | x :: x2 :: xs ->
       x :: _bsort (x2 :: xs)
   | s -> s
 in
 let t = _bsort s in
   if t = s then t
   else bsort t</lang>

This version uses the polymorphic option type to designate unchanged lists. (The type signature of _bsort is now 'a list -> 'a list option.) It is slightly faster than the previous one. <lang ocaml>let rec bsort s =

 let rec _bsort = function
   | x :: x2 :: xs when x > x2 -> begin
       match _bsort (x :: xs) with
         | None -> Some (x2 :: x :: xs)
         | Some xs2 -> Some (x2 :: xs2)
     end
   | x :: x2 :: xs -> begin
       match _bsort (x2 :: xs) with
         | None -> None
         | Some xs2 -> Some (x :: xs2)
     end
   | _ -> None
 in
   match _bsort s with
     | None -> s
     | Some s2 -> bsort s2</lang>

Octave

<lang octave>function s = bubblesort(v)

 itemCount = length(v);
 do
   hasChanged = false;
   itemCount--;
   for i = 1:itemCount
     if ( v(i) > v(i+1) )

v([i,i+1]) = v([i+1,i]);  % swap hasChanged = true;

     endif
   endfor
 until(hasChanged == false)
 s = v;

endfunction</lang>

<lang octave>v = [9,8,7,3,1,100]; disp(bubblesort(v));</lang>

ooRexx

Reimplementation of NetRexx

Translation of: NetRexx

This version exploits the "Collection Classes" and some other features of the language that are only available in Open Object Rexx. <lang ooRexx>/* Rexx */ Do

 placesList = sampleData()
 call show placesList
 say
 sortedList = bubbleSort(placesList)
 call show sortedList
 say
 return

End Exit

-- ----------------------------------------------------------------------------- bubbleSort: procedure Do

 il = arg(1)
 sl = il~copy
 listLen = sl~size
 loop i_ = 1 to listLen
   loop j_ = i_ + 1 to listLen
     cmpi = sl[i_]
     cmpj = sl[j_]
     if cmpi > cmpj then do
       sl[i_] = cmpj
       sl[j_] = cmpi
       end
     end j_
   end i_
 return sl

End Exit

-- ----------------------------------------------------------------------------- show: procedure Do

 al = arg(1)
 loop e_ over al
   say e_
   end e_
 
 return

End Exit

-- ----------------------------------------------------------------------------- sampleData: procedure Do

 placesList = .array~of( ,
   "UK  London",     "US  New York",   "US  Boston",     "US  Washington", ,
   "UK  Washington", "US  Birmingham", "UK  Birmingham", "UK  Boston"      ,
   )
 return placesList

End Exit

</lang>

Output:
UK  London
US  New York
US  Boston
US  Washington
UK  Washington
US  Birmingham
UK  Birmingham
UK  Boston

UK  Birmingham
UK  Boston
UK  London
UK  Washington
US  Birmingham
US  Boston
US  New York
US  Washington

Translation of Pseudocode

This version is a direct implementation of this task's pseudocode. <lang ooRexx>/* Rexx */ Do

 placesList = sampleData()
 call show placesList
 say
 sortedList = bubbleSort(placesList)
 call show sortedList
 say
 return

End Exit

-- ----------------------------------------------------------------------------- bubbleSort: procedure Do

 il = arg(1)
 sl = il~copy
 itemCount = sl~size
 loop label c_ until \hasChanged
   hasChanged = isFalse()
   itemCount = itemCount - 1
   loop i_ = 1 to itemCount
     if sl[i_] > sl[i_ + 1] then do
       t_         = sl[i_]
       sl[i_]     = sl[i_ + 1]
       sl[i_ + 1] = t_
       hasChanged = isTrue()
       end
     end i_
   end c_
 return sl

End Exit

-- ----------------------------------------------------------------------------- show: procedure Do

 al = arg(1)
 loop e_ over al
   say e_
   end e_
 
 return

End Exit

-- ----------------------------------------------------------------------------- sampleData: procedure Do

 placesList = .array~of( ,
   "UK  London",     "US  New York",   "US  Boston",     "US  Washington", ,
   "UK  Washington", "US  Birmingham", "UK  Birmingham", "UK  Boston"      ,
   )
 return placesList

End Exit

-- ----------------------------------------------------------------------------- isTrue: procedure

 return (1 == 1)

-- ----------------------------------------------------------------------------- isFalse: procedure

 return \isTrue()

</lang>

Classic Rexx Implementation

A more "traditional" implementation of version 1 using only Rexx primitive constructs. This version has been tested with the Open Object Rexx and Regina Rexx interpreters and could equally have been exhibited as a Rexx solution. <lang ooRexx>/* Rexx */ Do

 placesList. = 
 sortedList. = 
 call sampleData
 call bubbleSort
 do i_ = 1 to placesList.0
   say placesList.i_
   end i_
 say
 do i_ = 1 to sortedList.0
   say sortedList.i_
   end i_
 say
 return

End Exit

/* -------------------------------------------------------------------------- */ bubbleSort: procedure expose sortedList. placesList. Do

 /* Copy list */
 do !_ = 0 to placesList.0
   sortedList.!_ = placesList.!_
   end !_
 listLen = sortedList.0
 do i_ = 1 to listLen
   do j_ = i_ + 1 to listLen
     if sortedList.i_ > sortedList.j_ then do
       !_            = sortedList.j_
       sortedList.j_ = sortedList.i_
       sortedList.i_ = !_
       end
     end j_
   end i_
 return

End Exit

/* -------------------------------------------------------------------------- */ sampleData: procedure expose placesList. Do

 ! = 0
 ! = ! + 1; placesList.0 = !; placesList.! = "UK  London"
 ! = ! + 1; placesList.0 = !; placesList.! = "US  New York"
 ! = ! + 1; placesList.0 = !; placesList.! = "US  Boston"
 ! = ! + 1; placesList.0 = !; placesList.! = "US  Washington"
 ! = ! + 1; placesList.0 = !; placesList.! = "UK  Washington"
 ! = ! + 1; placesList.0 = !; placesList.! = "US  Birmingham"
 ! = ! + 1; placesList.0 = !; placesList.! = "UK  Birmingham"
 ! = ! + 1; placesList.0 = !; placesList.! = "UK  Boston"
 return

End Exit </lang>

Oz

In-place sorting of mutable arrays: <lang oz>declare

 proc {BubbleSort Arr}
    proc {Swap I J}
       Arr.J := (Arr.I := Arr.J) %% assignment returns the old value
    end
    IsSorted = {NewCell false}
    MaxItem = {NewCell {Array.high Arr}-1}
 in
    for until:@IsSorted do
       IsSorted := true
       for I in {Array.low Arr}..@MaxItem do
          if Arr.I > Arr.(I+1) then
             IsSorted := false
             {Swap I I+1}
          end
       end
       MaxItem := @MaxItem - 1
    end
 end
 Arr = {Tuple.toArray unit(10 9 8 7 6 5 4 3 2 1)}

in

 {BubbleSort Arr}
 {Inspect Arr}</lang>

Purely-functional sorting of immutable lists: <lang oz>declare

 local
    fun {Loop Xs Changed ?IsSorted}
       case Xs
       of X1|X2|Xr andthen X1 > X2 then
          X2|{Loop X1|Xr true IsSorted}
       [] X|Xr then
          X|{Loop Xr Changed IsSorted}
       [] nil then
          IsSorted = {Not Changed}
          nil
       end
    end
 in
    fun {BubbleSort Xs}
       IsSorted
       Result = {Loop Xs false ?IsSorted}
    in
       if IsSorted then Result
       else {BubbleSort Result}
       end
    end
 end

in

 {Show {BubbleSort [3 1 4 1 5 9 2 6 5]}}</lang>

PARI/GP

<lang parigp>bubbleSort(v)={

 for(i=1,#v-1,
   for(j=i+1,#v,
     if(v[j]<v[i],
       my(t=v[j]);
       v[j]=v[i];
       v[i]=t
     )
   )
 );
 v

};</lang>

Pascal

<lang pascal>procedure bubble_sort(var list: array of real); var

 i, j, n: integer;
 t: real;

begin

 n := length(list);
 for i := n downto 2 do
   for j := 0 to i - 1 do
     if list[j] > list[j + 1] then
     begin
       t := list[j];
       list[j] := list[j + 1];
       list[j + 1] := t;
     end;

end;</lang>

Usage:<lang pascal>var

 list: array[0 .. 9] of real;

// ... bubble_sort(list);</lang>

Perl

<lang perl># Sorts an array in place sub bubble_sort {

   for my $i (0 .. $#_){
       for my $j ($i + 1 .. $#_){
           $_[$j] < $_[$i] and @_[$i, $j] = @_[$j, $i];
       }
   }

}</lang>

Usage:

<lang perl>my @a = (39, 25, 30, 28, 36, 72, 98, 25, 43, 38); bubble_sort(@a);</lang>

Perl 6

Works with: Rakudo version #24 "Seoul"

<lang perl6>sub bubble_sort (@a is rw) {

   for ^@a -> $i {
       for $i ^..^ @a -> $j {
           @a[$j] < @a[$i] and @a[$i, $j] = @a[$j, $i];
       }
   }

}</lang>

Phix

Copy of Euphoria <lang Phix>function bubble_sort(sequence s) object tmp integer changed

   for j=length(s) to 1 by -1 do
       changed = 0
       for i=1 to j-1 do
           if s[i]>s[i+1] then
               {s[i],s[i+1],changed} = {s[i+1],s[i],1}
           end if
       end for
       if changed=0 then exit end if
   end for
   return s

end function

constant s = {4, 15, "delta", 2, -31, 0, "alfa", 19, "gamma", 2, 13, "beta", 782, 1}

puts(1,"Before: ") ?s puts(1,"After: ") ?bubble_sort(s)</lang>

Output:
Before: {4,15,"delta",2,-31,0,"alpha",19,"gamma",2,13,"beta",782,1}
After: {-31,0,1,2,2,4,13,15,19,782,"alpha","beta","delta","gamma"}

PHP

<lang php>function bubbleSort( array &$array ) { do { $swapped = false; for( $i = 0, $c = count( $array ) - 1; $i < $c; $i++ ) { if( $array[$i] > $array[$i + 1] ) { list( $array[$i + 1], $array[$i] ) = array( $array[$i], $array[$i + 1] ); $swapped = true; } } } while( $swapped ); }</lang>

PL/I

<lang pli>/* A primitive bubble sort */ bubble_sort: procedure (A);

  declare A(*) fixed binary;
  declare temp fixed binary;
  declare i fixed binary, no_more_swaps bit (1) aligned;
  do until (no_more_swaps);
     no_more_swaps = true;
     do i = lbound(A,1) to hbound(A,1)-1;
        if A(i) > A(i+1) then
           do; temp = A(i); A(i) = A(i+1); A(i+1) = temp;
               no_more_swaps = false;
           end;
     end;
  end;

end bubble_sort;</lang>

PicoLisp

<lang PicoLisp>(de bubbleSort (Lst)

  (use Chg
     (loop
        (off Chg)
        (for (L Lst (cdr L) (cdr L))
           (when (> (car L) (cadr L))
              (xchg L (cdr L))
              (on Chg) ) )
        (NIL Chg Lst) ) ) )</lang>

Pop11

<lang pop11>define bubble_sort(v); lvars n=length(v), done=false, i; while not(done) do

  true -> done;
  n - 1 -> n;
  for i from 1 to n do
     if v(i) > v(i+1) then
        false -> done;
        ;;; Swap using multiple assignment
        (v(i+1), v(i)) -> (v(i), v(i+1));
     endif;
  endfor;

endwhile; enddefine;

Test it

vars ar = { 10 8 6 4 2 1 3 5 7 9}; bubble_sort(ar); ar =></lang>

PostScript

<lang PostScript> /bubblesort{ /x exch def /temp x x length 1 sub get def /i x length 1 sub def /j i 1 sub def

x length 1 sub{ i 1 sub{ x j 1 sub get x j get lt { /temp x j 1 sub get def x j 1 sub x j get put x j temp put }if /j j 1 sub def }repeat /i i 1 sub def /j i 1 sub def }repeat x pstack }def </lang>

PowerShell

<lang powershell>function bubblesort ($a) {

   $l = $a.Length
   $hasChanged = $true
   while ($hasChanged) {
       $hasChanged = $false
       $l--
       for ($i = 0; $i -lt $l; $i++) {
           if ($a[$i] -gt $a[$i+1]) {
               $a[$i], $a[$i+1] = $a[$i+1], $a[$i]
               $hasChanged = $true
           }
       }
   }

}</lang>

Prolog

It's surprisingly easy in Prolog while coding this sort, to accidentally create a sort that is similar, but not identical to the bubble sort algorithm. Some of these are easier and shorter to code and work as well if not better. Having said that, it's difficult to think of a reason to code the bubble sort these days except as an example of inefficiency. <lang prolog>%___________________________________________________________________________ % Bubble sort

bubble(0, Res, Res, sorted). bubble(Len, [A,B|T], Res, unsorted) :- A > B, !, bubble(Len,[B,A|T], Res, _). bubble(Len, [A|T], [A|Ts], Ch) :- L is Len-1, bubble(L, T, Ts, Ch).

bubblesort(In, Out) :- length(In, Len), bubblesort(Len, In, Out). bubblesort(0, In, In). bubblesort(Len, In, Out) :- bubble(Len, In, Bubbled, SortFlag),  % bubble the list (SortFlag=sorted -> Out=Bubbled;  % list is already sorted SegLen is Len - 1,  % one fewer to process writef('bubbled=%w\n', [Bubbled]),  % show progress bubblesort(SegLen, Bubbled, Out)).

test :- In = [8,9,1,3,4,2,6,5,4], writef(' input=%w\n', [In]), bubblesort(In, R), writef('-> %w\n', [R]).</lang> for example:

?- test.
  input=[8,9,1,3,4,2,6,5,4]
bubbled=[8,1,3,4,2,6,5,4,9]
bubbled=[1,3,4,2,6,5,4,8,9]
bubbled=[1,3,2,4,5,4,6,8,9]
bubbled=[1,2,3,4,4,5,6,8,9]
-> [1,2,3,4,4,5,6,8,9]
true.

Alternative version

Should be ISO (but tested only with GNU Prolog). Note: doesn't constuct list for each swap, only for each pass. <lang prolog>:- initialization(main).


bubble_sort(Xs,Res) :-

   write(Xs), nl
 , bubble_pass(Xs,Ys,Changed)
 , ( Changed == true -> bubble_sort(Ys,Res) ; Res = Xs )
 .

bubble_pass(Xs,Res,Changed) :-

   Xs = [X|Ys], Ys = [Y|Zs]
 , ( X > Y -> H = Y, T = [X|Zs], Changed = true
            ; H = X, T = Ys
   )
 , Res = [H|R], !, bubble_pass(T,R,Changed)
 ; Res = Xs
 .


test([8,9,1,3,4,2,6,5,4]).

main :- test(T), bubble_sort(T,_), halt.</lang>

Output:
[8,9,1,3,4,2,6,5,4]
[8,1,3,4,2,6,5,4,9]
[1,3,4,2,6,5,4,8,9]
[1,3,2,4,5,4,6,8,9]
[1,2,3,4,4,5,6,8,9]

PureBasic

<lang PureBasic>Procedure bubbleSort(Array a(1))

 Protected i, itemCount, hasChanged
 
 itemCount = ArraySize(a())
 Repeat
   hasChanged = #False
   itemCount - 1
   For i = 0 To itemCount
     If a(i) > a(i + 1)
       Swap a(i), a(i + 1)
       hasChanged = #True
     EndIf 
   Next  
 Until hasChanged = #False

EndProcedure</lang>

Python

<lang python>def bubble_sort(seq):

   """Inefficiently sort the mutable sequence (list) in place.
      seq MUST BE A MUTABLE SEQUENCE.
      As with list.sort() and random.shuffle this does NOT return 
   """
   changed = True
   while changed:
       changed = False
       for i in xrange(len(seq) - 1):
           if seq[i] > seq[i+1]:
               seq[i], seq[i+1] = seq[i+1], seq[i]
               changed = True
   return None

if __name__ == "__main__":

  """Sample usage and simple test suite"""
  from random import shuffle
  testset = range(100)
  testcase = testset[:] # make a copy
  shuffle(testcase)
  assert testcase != testset  # we've shuffled it
  bubble_sort(testcase)
  assert testcase == testset  # we've unshuffled it back into a copy</lang>


Qi

<lang Qi>(define bubble-shot

 [A]     -> [A]
 [A B|R] -> [B|(bubble-shot [A|R])] where (> A B)
 [A  |R] -> [A|(bubble-shot R)])

(define bubble-sort

 X -> (fix bubble-shot X))

(bubble-sort [6 8 5 9 3 2 2 1 4 7]) </lang>

R

<lang R>bubblesort <- function(v) {

 itemCount <- length(v)
 repeat {
   hasChanged <- FALSE
   itemCount <- itemCount - 1
   for(i in 1:itemCount) {
     if ( v[i] > v[i+1] ) {
       t <- v[i]
       v[i] <- v[i+1]
       v[i+1] <- t
       hasChanged <- TRUE
     }
   }
   if ( !hasChanged ) break;
 }
 v

}

v <- c(9,8,7,3,1,100) print(bubblesort(v))</lang>

Ra

<lang Ra> class BubbleSort **Sort a list with the Bubble Sort algorithm**

on start

args := program arguments .sort(args) print args

define sort(list) is shared **Sort the list**

test list := [4, 2, 7, 3] .sort(list) assert list = [2, 3, 4, 7]

body last := list.count - 1

post while changed

changed := false

for i in last

if list[i] > list[i + 1] temp := list[i] list[i] := list[i + 1] list[i + 1] := temp changed := true </lang>

Racket

This bubble sort sorts the elelement in the vector v with regard to <?.

<lang racket>

  1. lang racket

(define (bubble-sort <? v)

 (define len (vector-length v))
 (define ref vector-ref)
 (let loop ([max len] 
            [again? #f])
   (for ([i (in-range 0 (- max 1))]
         [j (in-range 1 max)])
     (define vi (ref v i))
     (when (<? (ref v j) vi)
       (vector-set! v i (ref v j))
       (vector-set! v j vi)
       (set! again? #t)))
   (when again? (loop (- max 1) #f)))
 v)

</lang>

Example: Sorting a vector of length 10 with random entries. <lang racket> (bubble-sort < (for/vector ([_ 10]) (random 20))) </lang>

REALbasic

Sorts an array of Integers

<lang vb>

 Dim sortable() As Integer ' assume the array is populated
 sortable.Shuffle() ' sortable is now randomized
 Dim swapped As Boolean
 Do
   Dim index, bound As Integer
   bound = sortable.Ubound
   While index < bound
     If Sortable(index) > Sortable(index + 1) Then
       Dim s As Integer = Sortable(index)
       Sortable.Remove(index)
       Sortable.Insert(index + 1, s)
       swapped = True
     End If
     index = index + 1
   Wend
   
 Loop Until Not swapped

'sortable is now sorted </lang>

REXX

<lang rexx>/*REXX program sorts an array (of any items) using the bubble-sort algorithm.*/ call gen /*generate the array elements (items).*/ call show 'before sort' /*show the before array elements. */

    say copies('─',79)                /*show a separator line (before/after).*/

call bubbleSort # /*invoke the bubble sort with # items.*/ call show ' after sort' /*show the after array elements. */ exit /*stick a fork in it, we're all done. */ /*────────────────────────────────────────────────────────────────────────────*/ bubbleSort: procedure expose @.; parse arg n /*N: number of array elements.*/ m=n-1 /*use this as a handy variable for sort*/

      do  until done;     done=1      /*keep sorting the array until done.   */
         do j=1  for m;   k=j+1       /*search for an element  out─of─order. */
         if @.j>@.k  then do; _=@.j   /*Out of order?  Then swap two elements*/
                              @.j=@.k /*swap current element with the next···*/
                              @.k=_   /*            ··· and the next with  _ */
                              done=0  /*indicate that the sorting isn't done,*/
                          end         /*               (1≡true,  0≡false).   */
         end   /*j*/
      end       /*until ··· */

return /*────────────────────────────────────────────────────────────────────────────*/ gen: @. = /*assign a default value to all of @. */

    @.1  = '---letters of the Hebrew alphabet---'  ;   @.13 = 'kaph    [kaf]'
    @.2  = '===================================='  ;   @.14 = 'lamed'
    @.3  = 'aleph   [alef]'                        ;   @.15 = 'mem'
    @.4  = 'beth    [bet]'                         ;   @.16 = 'nun'
    @.5  = 'gimel'                                 ;   @.17 = 'samekh'
    @.6  = 'daleth  [dalet]'                       ;   @.18 = 'ayin'
    @.7  = 'he'                                    ;   @.19 = 'pe'
    @.8  = 'waw     [vav]'                         ;   @.20 = 'sadhe   [tsadi]'
    @.9  = 'zayin'                                 ;   @.21 = 'qoph    [qof]'
    @.10 = 'heth    [het]'                         ;   @.22 = 'resh'
    @.11 = 'teth    [tet]'                         ;   @.23 = 'shin'
    @.12 = 'yod'                                   ;   @.24 = 'taw     [tav]'
       do #=1  while  @.#\==; end;  #=#-1 /*find how many elements in list.*/
    w=length(#)                             /*the maximum width of any index.*/
    return

/*────────────────────────────────────────────────────────────────────────────*/ show: do j=1 for #; say 'element' right(j,w) arg(1)":" @.j; end; return</lang> output   when using the internal array list:

element  1 before sort: ---letters of the Hebrew alphabet---
element  2 before sort: ====================================
element  3 before sort: aleph   [alef]
element  4 before sort: beth    [bet]
element  5 before sort: gimel
element  6 before sort: daleth  [dalet]
element  7 before sort: he
element  8 before sort: waw     [vav]
element  9 before sort: zayin
element 10 before sort: heth    [het]
element 11 before sort: teth    [tet]
element 12 before sort: yod
element 13 before sort: kaph    [kaf]
element 14 before sort: lamed
element 15 before sort: mem
element 16 before sort: nun
element 17 before sort: samekh
element 18 before sort: ayin
element 19 before sort: pe
element 20 before sort: sadhe   [tsadi]
element 21 before sort: qoph    [qof]
element 22 before sort: resh
element 23 before sort: shin
element 24 before sort: taw     [tav]
───────────────────────────────────────────────────────────────────────────────
element  1  after sort: ---letters of the Hebrew alphabet---
element  2  after sort: ====================================
element  3  after sort: aleph   [alef]
element  4  after sort: ayin
element  5  after sort: beth    [bet]
element  6  after sort: daleth  [dalet]
element  7  after sort: gimel
element  8  after sort: he
element  9  after sort: heth    [het]
element 10  after sort: kaph    [kaf]
element 11  after sort: lamed
element 12  after sort: mem
element 13  after sort: nun
element 14  after sort: pe
element 15  after sort: qoph    [qof]
element 16  after sort: resh
element 17  after sort: sadhe   [tsadi]
element 18  after sort: samekh
element 19  after sort: shin
element 20  after sort: taw     [tav]
element 21  after sort: teth    [tet]
element 22  after sort: waw     [vav]
element 23  after sort: yod
element 24  after sort: zayin

Ring

<lang ring>bubbleList = [4,2,1,3] flag = 0 bubbleSort(bubbleList) see bubbleList

func bubbleSort A

  n = len(A)
  while flag = 0
        flag = 1
        for i = 1 to n-1 
            if A[i] > A[i+1]
               temp = A[i]
               A[i] = A[i+1]
               A[i+1] = temp
               flag = 0
             ok
         next
   end

</lang>

Ruby

Generally, this task should be accomplished in Ruby using Array.sort!. Here we take an approach that's more comparable with the other examples on this page.

This example adds the bubblesort! method to the Array object. Below are two different methods that show four different iterating constructs in ruby.

<lang ruby>class Array

 def bubblesort1!
   length.times do |j|
     for i in 1...(length - j)
       if self[i] < self[i - 1]
         self[i], self[i - 1] = self[i - 1], self[i]
       end
     end
   end
   self
 end
  def bubblesort2!
   each_index do |index|
     (length - 1).downto( index ) do |i|
       self[i-1], self[i] = self[i], self[i-1] if self[i-1] < self[i]
     end
   end
   self
 end

end ary = [3, 78, 4, 23, 6, 8, 6] ary.bubblesort1! p ary

  1. => [3, 4, 6, 6, 8, 23, 78]</lang>

Run BASIC

<lang runbasic>siz = 100 dim data$(siz) unSorted = 1

WHILE unSorted

 unSorted = 0
 FOR i = 1 TO siz -1
   IF data$(i) > data$(i + 1) THEN
     tmp       = data$(i)
     data$(i)  = data$(i + 1)
     data$(i + 1) = tmp
     unSorted  = 1
   END IF
 NEXT

WEND</lang>

Rust

<lang rust>fn bubble_sort<T: Ord>(values: &mut[T]) {

   let mut n = values.len();
   let mut swapped = true;
   while swapped {
       swapped = false;
       for i in 1..n {
           if values[i - 1] > values[i] {
               values.swap(i - 1, i);
               swapped = true;
           }
       }
       n = n - 1;
   }

}

fn main() {

   // Sort numbers.
   let mut numbers = [8, 7, 1, 2, 9, 3, 4, 5, 0, 6];
   println!("Before: {:?}", numbers);
   bubble_sort(&mut numbers);
   println!("After: {:?}", numbers);
   // Sort strings.
   let mut strings = ["empty", "beach", "art", "car", "deal"];
   println!("Before: {:?}", strings);
   bubble_sort(&mut strings);
   println!("After: {:?}", strings);

}</lang>

Sather

<lang sather>class SORT{T < $IS_LT{T}} is

 private swap(inout a, inout b:T) is
   temp ::= a;
   a := b;
   b := temp;
 end;
 bubble_sort(inout a:ARRAY{T}) is
   i:INT;
   if a.size < 2 then return; end;
   loop
     sorted ::= true;
     loop i := 0.upto!(a.size - 2);
       if a[i+1] < a[i] then
         swap(inout a[i+1], inout a[i]);
         sorted := false;
       end;
     end;
     until!(sorted);
   end;
 end;

end;</lang>

<lang sather>class MAIN is

 main is
   a:ARRAY{INT} := |10, 9, 8, 7, 6, -10, 5, 4|;
   SORT{INT}::bubble_sort(inout a);
   #OUT + a + "\n";
 end;

end;</lang>

This should be able to sort (in ascending order) any object for which is_lt (less than) is defined.

Scala

Library: Scala

This slightly more complex version of Bubble Sort avoids errors with indices.

<lang scala>def bubbleSort[T](arr: Array[T])(implicit o: Ordering[T]) {

 import o._
 val consecutiveIndices = (arr.indices, arr.indices drop 1).zipped
 var hasChanged = true
 do {
   hasChanged = false
   consecutiveIndices foreach { (i1, i2) =>
     if (arr(i1) > arr(i2)) {
       hasChanged = true
       val tmp = arr(i1)
       arr(i1) = arr(i2)
       arr(i2) = tmp
     }
   }
 } while(hasChanged)

}</lang>

<lang scala>import scala.annotation.tailrec

def bubbleSort(xt: List[Int]) = {

 @tailrec
 def bubble(xs: List[Int], rest: List[Int], sorted: List[Int]): List[Int] = xs match {
   case x :: Nil =>
     if (rest.isEmpty) x :: sorted
     else bubble(rest, Nil, x :: sorted)
   case a :: b :: xs =>
     if (a > b) bubble(a :: xs, b :: rest, sorted)
     else       bubble(b :: xs, a :: rest, sorted)
 }
 bubble(xt, Nil, Nil)

}</lang>

Scheme

<lang scheme>(define (bubble-sort x gt?)

 (letrec
   ((fix (lambda (f i)
      (if (equal? i (f i))
          i
          (fix f (f i)))))
    (sort-step (lambda (l)
       (if (or (null? l) (null? (cdr l)))
           l
           (if (gt? (car l) (cadr l))
               (cons (cadr l) (sort-step (cons (car l) (cddr l))))
               (cons (car  l) (sort-step (cdr l))))))))
 (fix sort-step x)))</lang>

This solution recursively finds the fixed point of sort-step. A comparison function must be passed to bubblesort. Example usages: <lang scheme>(bubble-sort (list 1 3 5 9 8 6 4 2) >) (bubble-sort (string->list "Monkey") char<?)</lang>

Here is the same function, using a different syntax:

<lang scheme>(define (bsort l gt?)

 (define (dosort l)
   (cond ((null? (cdr l))
          l)
         ((gt? (car l) (cadr l))
          (cons (cadr l) (dosort (cons (car l) (cddr l)))))
         (else 
          (cons (car l) (dosort (cdr l))))))
 (let ((try (dosort l)))
   (if (equal? l try)
       l
       (bsort try gt?))))

</lang> For example, you could do <lang scheme>(bsort > '(2 4 6 2)) (1 2 3)</lang>

Scilab

<lang>function b=BubbleSort(a)

 n=length(a)
 swapped=%T
 while swapped
   swapped=%F
   for i=1:1:n-1
     if a(i)>a(i+1) then
       temp=a(i)
       a(i)=a(i+1)
       a(i+1)=temp
       swapped=%T
     end
   end
 end
 b=a

endfunction BubbleSort</lang>

Output:
-->y=[5 4 3 2 1]
 y  =
     5.    4.    3.    2.    1.  
-->x=BubbleSort(a) 
 x  =
     1.    2.    3.    4.    5.  

Scratch

This solution is hosted at the Scratch site, because it is difficult to document visual programming solutions directly here at Rosetta Code. There you can see the solution results as well as examine the code. This solution is intended to illustrate the Bubble sort algorithm rather than to maximize performance. Scratch provides visual queues to indicate list access, and these are used to help show what is happening.

Seed7

<lang seed7>const proc: bubbleSort (inout array elemType: arr) is func

 local
   var boolean: swapped is FALSE;
   var integer: i is 0;
   var elemType: help is elemType.value;
 begin
   repeat
     swapped := FALSE;
     for i range 1 to length(arr) - 1 do
       if arr[i] > arr[i + 1] then
         help := arr[i];
         arr[i] := arr[i + 1];
         arr[i + 1] := help;
         swapped := TRUE;
       end if;
     end for;
   until not swapped;
 end func;</lang>

Original source: [2]

Sidef

<lang ruby>func bubble_sort(arr) {

   loop {
       var swapped = false;
       { |i|
           arr[i-1] > arr[i] && (
               arr[i-1, i] = arr[i, i-1];
               swapped = true;
           );
       } * arr.end;
       swapped || break;
   }
   return arr;

}</lang>

Smalltalk

A straight translation from the pseudocode above. Swap is done with a block closure.

<lang smalltalk>|item swap itemCount hasChanged| item := #(1 4 5 6 10 8 7 61 0 -3) copy. swap := [:indexOne :indexTwo| |temp| temp := item at: indexOne. item at: indexOne put: (item at: indexTwo). item at: indexTwo put: temp].

itemCount := item size. [hasChanged := false. itemCount := itemCount - 1. 1 to: itemCount do: [:index | (item at: index) > (item at: index + 1) ifTrue: [swap value: index value: index + 1. hasChanged := true]]. hasChanged] whileTrue.</lang>

SNOBOL4

<lang SNOBOL4>* # Sort array in place, return array

       define('bubble(a,alen)i,j,ub,tmp') :(bubble_end)

bubble i = 1; ub = alen outer gt(ub,1) :f(bdone)

       j = 1

inner le(a<j>, a<j + 1>) :s(incrj)

       tmp = a<j>
       a<j> = a<j + 1>
       a<j + 1> = tmp

incrj j = lt(j + 1,ub) j + 1 :s(inner)

       ub = ub - 1 :(outer)

bdone bubble = a :(return) bubble_end

  • # Fill array with test data
       str = '33 99 15 54 1 20 88 47 68 72'
       output = str; arr = array(10)

floop i = i + 1; str span('0123456789') . arr = :s(floop)

  • # Test and display
       bubble(arr,10); str = 

sloop j = j + 1; str = str arr<j> ' ' :s(sloop)

       output = trim(str)

end</lang>

Output:
33 99 15 54 1 20 88 47 68 72
1 15 20 33 47 54 68 72 88 99

SPARK

Works with: SPARK GPL version 2010

The first version is based on the Ada version, with Integer for both the array index and the array element.

Static analysis of this code shows that it is guaranteed free of any run-time error when called from any other SPARK code. <lang Ada>package Bubble is

  type Arr is array(Integer range <>) of Integer;
  procedure Sort (A : in out Arr);
  --# derives A from *;

end Bubble;


package body Bubble is

  procedure Sort (A : in out Arr)
  is
     Finished : Boolean;
     Temp     : Integer;
  begin
     if A'Last /= A'First then
        loop
           Finished := True;
           for J in Integer range A'First .. A'Last - 1 loop
              if A (J + 1) < A (J) then
                 Finished := False;
                 Temp := A (J + 1);
                 A (J + 1) := A (J);
                 A (J) := Temp;
              end if;
           end loop;
           --# assert A'Last /= A'First;
           exit when Finished;
        end loop;
     end if;
  end Sort;

end Bubble; </lang> The next version has a postcondition to guarantee that the returned array is sorted correctly. This requires the two proof rules that follow the source. The Ada code is identical with the first version. <lang Ada>package Bubble is

  type Arr is array(Integer range <>) of Integer;
  --  Sorted is a proof function with the definition:
  --    Sorted(A, From_I, To_I)
  --      <->
  --    (for all I in Integer range From_I .. To_I - 1 =>
  --               (A(I) <= A(I + 1))) .
  --
  --# function Sorted (A            : Arr;
  --#                  From_I, To_I : Integer) return Boolean;
  
  procedure Sort (A : in out Arr);
  --# derives A from *;
  --# post Sorted(A, A'First, A'Last);
  

end Bubble;


package body Bubble is

  procedure Sort (A : in out Arr)
  is
     Finished : Boolean;
     Temp     : Integer;
  begin
     if A'Last > A'First then
        loop
           Finished := True;
           for J in Integer range A'First .. A'Last - 1
           --# assert Finished -> Sorted(A, A'First, J);
           loop
              if A (J + 1) < A (J) then
                 Finished := False;
                 Temp := A (J + 1);
                 A (J + 1) := A (J);
                 A (J) := Temp;
              end if;
           end loop;
           --# assert A'Last /= A'First
           --#   and  (Finished -> Sorted(A, A'First, A'Last));
           exit when Finished;
        end loop;
     end if;
  end Sort;
  

end Bubble; </lang> The proof rules are stated here without justification (but they are fairly obvious). A formal proof of these rules from the definition of Sorted has been completed.

bubble_sort_rule(1): sorted(A, I, J)
                       may_be_deduced_from
                     [ J <= I ] .

bubble_sort_rule(2): Fin -> sorted(A, I, J + 1)
                       may_be_deduced_from
                     [ Fin -> sorted(A, I, J),
                       element(A, [J]) <= element(A, [J + 1]) ] .

Both of the two versions above use an inner loop that scans over all the array on every pass of the outer loop. This makes the proof in the second version very simple.

The final version scans over a reducing portion of the array in the inner loop, consequently the proof becomes more complex. The package specification for this version is the same as the second version above. The package body defines two more proof functions. <lang Ada>package body Bubble is

  procedure Sort (A : in out Arr)
  is
     Finished : Boolean;
     --  In_Position is a proof function with the definition:
     --    In_Position(A, A_Start, A_I, A_End)
     --      <->
     --    ((for all K in Integer range A_Start .. A_I - 1 =>
     --                (A(K) <= A(A_I)))
     --     and
     --     Sorted(A, A_I, A_End) .
     --
     --# function In_Position (A                  : Arr;
     --#                       A_Start, A_I, A_End : Integer) return Boolean;
     --  Swapped is a proof function with the definition:
     --    Swapped(A_In, A_Out, I1, I2)
     --      <->
     --    (A_Out = A_In[I1 => A_In(I2); I2 => A_In(I1)]).
     --
     --# function Swapped (A_In, A_Out : Arr;
     --#                   I1, I2      : Integer) return Boolean;
     procedure Swap (A  : in out Arr;
                     I1 : in     Integer;
                     I2 : in     Integer)
     --# derives A from *, I1, I2;
     --# pre  I1 in A'First .. A'Last
     --#  and I2 in A'First .. A'Last;
     --# post Swapped(A~, A, I1, I2);
     is
        Temp : Integer;
     begin
        Temp  := A(I2);
        A(I2) := A(I1);
        A(I1) := Temp;
     end Swap;
     pragma Inline (Swap);
  begin
     if A'Last > A'First then
        for I in reverse Integer range A'First + 1 .. A'Last loop
           Finished := True;
           for J in Integer range A'First .. I - 1 loop
              if A (J + 1) < A (J) then
                 Finished := False;
                 Swap (A, J, J + 1);
              end if;
              --# assert I% = I  --  I is unchanged by execution of the loop
              --#   and  (for all K in Integer range A'First .. J =>
              --#                    (A(K) <= A(J + 1)))
              --#   and  (I < A'Last -> In_Position(A, A'First, I + 1, A'Last))
              --#   and  (Finished -> Sorted(A, A'First, J + 1));
           end loop;
           exit when Finished;
           --# assert In_Position(A, A'First, I, A'Last);
        end loop;
     end if;
  end Sort;

end Bubble; </lang> Completion of the proof of this version requires more rules than the previous version and they are rather more complex. Creation of these rules is quite straightforward - I tend to write whatever rules the Simplifier needs first and then validate them afterwards. A formal proof of these rules from the definition of Sorted, In_Position and Swapped has been completed.

bubble_sort_rule(1):  sorted(A, I, J)
                        may_be_deduced_from
                      [ J <= I ] .

bubble_sort_rule(2):  sorted(A, I - 1, J)
                        may_be_deduced_from
                      [ sorted(A, I, J),
                        element(A, [I - 1]) <= element(A, [I]) ] .

bubble_sort_rule(3):  Fin -> sorted(A, I, J + 1)
                        may_be_deduced_from
                      [ Fin -> sorted(A, I, J),
                        element(A, [J]) <= element(A, [J + 1]) ] .

bubble_sort_rule(4):  sorted(A, Fst, Lst)
                        may_be_deduced_from
                      [ sorted(A, Fst, I),
                        I < Lst -> in_position(A, Fst, I + 1, Lst),
                        I <= Lst ] .

bubble_sort_rule(5):  in_position(A, Fst, I, Lst)
                        may_be_deduced_from
                      [ I < Lst -> in_position(A, Fst, I + 1, Lst),
                        for_all(K : integer, Fst <= K and K <= I - 1
                                  -> element(A, [K]) <= element(A, [I])),
                        I >= Fst,
                        I <= Lst ] .

bubble_sort_rule(6):  I < Lst -> in_position(A2, Fst, I + 1, Lst)
                        may_be_deduced_from
                      [ I < Lst -> in_position(A1, Fst, I + 1, Lst),
                        swapped(A1, A2, J + 1, J + 2),
                        J + 2 < I + 1,
                        J >= Fst ] .

bubble_sort_rule(7):  I - 1 < Lst -> in_position(A2, Fst, I, Lst)
                        may_be_deduced_from
                      [ in_position(A1, Fst, I, Lst),
                        swapped(A1, A2, J, J + 1),
                        J + 1 < I,
                        J >= Fst ] .

bubble_sort_rule(8):  for_all(K : integer, I <= K and K <= I
                                 -> element(A, [K]) <= element(A, [I + 1]))
                        may_be_deduced_from
                      [ element(A, [I]) <= element(A, [I + 1]) ] .

bubble_sort_rule(9):  for_all(K : integer, I <= K and K <= I
                                 -> element(A2, [K]) <= element(A2, [I + 1]))
                        may_be_deduced_from
                      [ element(A1, [I]) > element(A1, [I + 1]),
                        swapped(A1, A2, I, I + 1) ] .

bubble_sort_rule(10): for_all(K2 : integer, Fst <= K2 and K2 <= J + 1
                                 -> element(A, [K2]) <= element(A, [J + 2]))
                        may_be_deduced_from
                      [ for_all(K1 : integer, Fst <= K1 and K1 <= J
                                   -> element(A, [K1]) <= element(A, [J + 1])),
                        element(A, [J + 1]) <= element(A, [J + 2]) ] .

bubble_sort_rule(11): for_all(K2 : integer, Fst <= K2 and K2 <= J + 1
                                 -> element(A2, [K2]) <= element(A2, [J + 2]))
                        may_be_deduced_from
                      [ for_all(K1 : integer, Fst <= K1 and K1 <= J
                                   -> element(A1, [K1]) <= element(A1, [J + 1])),
                        element(A1, [J + 1]) > element(A1, [J + 2]),
                        swapped(A1, A2, J + 1, J + 2) ] .

Standard ML

Assumes a list of integers.

fun bubble_select [] = []
  | bubble_select [a] = [a]
  | bubble_select (a::b::xs) =
    if b < a then b::(bubble_select(a::xs)) else a::(bubble_select(b::xs))
 
fun bubblesort [] = []
  | bubblesort (x::xs) =bubble_select (x::(bubblesort xs))

Swift

<lang Swift>func bubbleSort<T:Comparable>(inout list:[T]) {

   var done = false
   while !done {
       done = true
       for i in 1..<list.count {
           if list[i - 1] > list[i] {
               (list[i], list[i - 1]) = (list[i - 1], list[i])
               done = false
           }
       }
   }

}</lang>

TI-83 BASIC

Input your data into L1 and run this program to organize it.

:L1→L2
:1+dim(L2)→N
:For(D,1,dim(L2))
:N-1→N
:0→I
:For(C,1,dim(L2)-2)
:For(A,dim(L2)-N+1,dim(L2)-1)
:If L2(A)>L2(A+1)
:Then
:1→I
:L2(A)→B
:L2(A+1)→L2(A)
:B→L2(A+1)
:End
:End
:End
:If I=0
:Goto C
:End
:Lbl C
:If L2(1)>L2(2)
:Then
:L2(1)→B
:L2(2)→L2(1)
:B→L2(2)
:End
:DelVar A
:DelVar B
:DelVar C
:DelVar D
:DelVar N
:DelVar I
:Return

Odd-Even Bubble Sort (same IO):

:"ODD-EVEN"
:L1→L2(
:1+dim(L2)→N
:For(D,1,dim(L2))
:N-1→N
:0→O
:For(C,1,dim(L2)-2)
:For(A,dim(L2)-N+2,dim(L2)-1,2)
:If L2(A)>L2(A+1)
:Then
:1→O
:L2(A)→B
:L2(A+1)→L2(A)
:B→L2(A+1)
:End
:End
:For(A,dim(L2)-N+1,dim(L2)-1,2)
:If L2(A)>L2(A+1)
:Then
:1→O
:L2(A)→B
:L2(A+1)→L2(A)
:B→L2(A+1)
:End
:End
:End
:If O=0
:Goto C
:End
:Lbl C
:If L2(1)>L2(2)
:Then
:L2(1)→B
:L2(2)→L2(1)
:B→L2(2)
:End
:DelVar A
:DelVar B
:DelVar C
:DelVar D
:DelVar N
:DelVar O
:Return

Implementation of the pseudo code given at the top of the page. Place data to be sorted in L1

:dim(L1)→D
:Repeat C=0
  :0→C
  :D–1→D
  :For(I,1,D)
    :If L1(I)>L1(I+1):Then
      :L1(I)→C
      :L1(I+1)→L1(I)
      :C→L1(I+1)
      :1→C
    :End
  :End
:End
:L1

Tcl

Library: Tcllib (Package: struct::list)

<lang tcl>package require Tcl 8.5 package require struct::list

proc bubblesort {A} {

   set len [llength $A]
   set swapped true
   while {$swapped} {
       set swapped false
       for {set i 0} {$i < $len - 1} {incr i} {
           set j [expr {$i + 1}]
           if {[lindex $A $i] > [lindex $A $j]} {
               struct::list swap A $i $j
               set swapped true
           }
       }
       incr len -1
   }
   return $A

}

puts [bubblesort {8 6 4 2 1 3 5 7 9}] ;# => 1 2 3 4 5 6 7 8 9</lang>

Idiomatic code uses the builtin lsort instead, which is a stable O(n log n) sort.

Toka

Toka does not have a bubble sort predefined, but it is easy to code a simple one:

<lang toka>#! A simple Bubble Sort function value| array count changed | [ ( address count -- )

 to count to array
 count 0
 [ count 0
   [ i array array.get i 1 + array array.get 2dup >
     [ i array array.put  i 1 + array array.put ]
     [ 2drop ] ifTrueFalse
   ] countedLoop
   count 1 - to count
 ] countedLoop

] is bsort

  1. ! Code to display an array

[ ( array count -- )

 0 swap [ dup i swap array.get . ] countedLoop drop cr 

] is .array

  1. ! Create a 10-cell array

10 cells is-array foo

  1. ! Fill it with random values
 20  1 foo array.put
 50  2 foo array.put
650  3 foo array.put
120  4 foo array.put
110  5 foo array.put
101  6 foo array.put

1321 7 foo array.put 1310 8 foo array.put

987  9 foo array.put
10 10 foo array.put
  1. ! Display the array, sort it, and display it again

foo 10 .array foo 10 bsort foo 10 .array</lang>

TorqueScript

<lang TorqueScript>//Note that we're assuming that the list of numbers is separated by tabs. function bubbleSort(%list) { %ct = getFieldCount(%list); for(%i = 0; %i < %ct; %i++) { for(%k = 0; %k < (%ct - %i - 1); %k++) { if(getField(%list, %k) > getField(%list, %k+1)) { %tmp = getField(%list, %k); %list = setField(%list, %k, getField(%list, %k+1)); %list = setField(%list, %k+1, %tmp); } } } return %list; }</lang>

uBasic/4tH

<lang>PRINT "Bubble sort:"

 n = FUNC (_InitArray)
 PROC _ShowArray (n)
 PROC _Bubblesort (n)
 PROC _ShowArray (n)

PRINT

END

_Bubblesort PARAM(1) ' Bubble sort

 LOCAL (2)
 DO
   b@ = 0
   FOR c@ = 1 TO a@-1
     IF @(c@-1) > @(c@) THEN PROC _Swap (c@, c@-1) : b@ = c@
   NEXT
   a@ = b@
   UNTIL b@ = 0
 LOOP

RETURN


_Swap PARAM(2) ' Swap two array elements

 PUSH @(a@)
 @(a@) = @(b@)
 @(b@) = POP()

RETURN


_InitArray ' Init example array

 PUSH 4, 65, 2, -31, 0, 99, 2, 83, 782, 1

 FOR i = 0 TO 9
   @(i) = POP()
 NEXT

RETURN (i)


_ShowArray PARAM (1) ' Show array subroutine

 FOR i = 0 TO a@-1
   PRINT @(i),
 NEXT

 PRINT

RETURN</lang>

Unicon

See Icon.

UnixPipes

<lang bash>rm -f _sortpass

reset() {

  test -f _tosort || mv _sortpass _tosort

}

bpass() {

 (read a; read b
 test -n "$b" -a "$a" && (
     test $a -gt $b && (reset; echo $b;  (echo $a ; cat) | bpass ) || (echo $a;  (echo $b ; cat) | bpass )
 ) || echo $a)

}

bubblesort() {

 cat > _tosort
 while test -f _tosort
 do
     cat _tosort | (rm _tosort;cat) |bpass > _sortpass
 done
 cat _sortpass

}

cat to.sort | bubblesort</lang>

Ursala

The bubblesort function is parameterized by a relational predicate. <lang Ursala>#import nat

bubblesort "p" = @iNX ^=T ^llPrEZryPrzPlrPCXlQ/~& @l ~&aitB^?\~&a "p"?ahthPX/~&ahPfatPRC ~&ath2fahttPCPRC

  1. cast %nL

example = bubblesort(nleq) <362,212,449,270,677,247,567,532,140,315></lang>

Output:
<140,212,247,270,315,362,449,532,567,677>

VBScript

Doing the decr and incr thing is superfluous, really. I just had stumbled over the byref thing for swap and wanted to see where else it would work.

For those unfamiliar with Perth, WA Australia, the five strings being sorted are names of highways.

Implementation

<lang vb> sub decr( byref n ) n = n - 1 end sub

sub incr( byref n ) n = n + 1 end sub

sub swap( byref a, byref b) dim tmp tmp = a a = b b = tmp end sub

function bubbleSort( a ) dim changed dim itemCount itemCount = ubound(a) do changed = false decr itemCount for i = 0 to itemCount if a(i) > a(i+1) then swap a(i), a(i+1) changed = true end if next loop until not changed bubbleSort = a end function </lang>

Invocation

<lang vb> dim a a = array( "great eastern", "roe", "stirling", "albany", "leach") wscript.echo join(a,", ") bubbleSort a wscript.echo join(a,", ") </lang>

Output:
great eastern, roe, stirling, albany, leach
albany, great eastern, leach, roe, stirling

Visual Basic .NET

Platform: .NET

Works with: Visual Basic .NET version 9.0+

<lang vbnet>Do Until NoMoreSwaps = True

    NoMoreSwaps = True
    For Counter = 1 To (NumberOfItems - 1)
        If List(Counter) > List(Counter + 1) Then
            NoMoreSwaps = False
            Temp = List(Counter)
            List(Counter) = List(Counter + 1)
            List(Counter + 1) = Temp
        End If
    Next
    NumberOfItems = NumberOfItems - 1

Loop</lang>

X86 Assembly

Translation of XPL0. Assemble with tasm, tlink /t <lang asm> .model tiny

       .code
       .486
       org     100h

start: mov si, offset array

       mov     ax, 40          ;length of array (not including $)
       call    bsort
       mov     dx, si          ;point to array
       mov     ah, 09h         ;display it as a string
       int     21h
       ret

array db "Pack my box with five dozen liquor jugs.$"

Bubble sort
si = array addrsss, ax = number of bytes

bsort: pusha

       xchg    cx, ax          ;get size of array N
       dec     cx              ;for J:= N-1 downto 0

bs10: xor bx, bx ;for I:= 0 to J-1 bs20: mov ax, [bx+si]

       cmp     al, ah          ;if A(I) > A(I+1) then
       jbe     bs30
        xchg   al, ah          ; swap bytes
        mov    [bx+si], ax

bs30: inc bx ;next I

       cmp     bx, cx
       jb      bs20
       loop    bs10
       popa
       ret
       end     start</lang>
Output:
       .Pabcdeefghiiijklmnoooqrstuuvwxyz

XPL0

<lang XPL0>include c:\cxpl\codes; \intrinsic 'code' declarations string 0; \use zero-terminated strings

proc BSort(A, N); \Bubble sort array in ascending order char A; \address of array int N; \number of items in array (size) int I, J, T; [for J:= N-1 downto 0 do

   for I:= 0 to J-1 do
       if A(I) > A(I+1) then
           [T:= A(I);  A(I):= A(I+1);  A(I+1):= T];    \swap items

]; \BSort

func StrLen(Str); \Return number of characters in an ASCIIZ string char Str; int I; for I:= 0 to -1>>1-1 do

       if Str(I) = 0 then return I;

char Str; [Str:= "Pack my box with five dozen liquor jugs."; BSort(Str, StrLen(Str)); Text(0, Str); CrLf(0); ]</lang>

Output:
"       .Pabcdeefghiiijklmnoooqrstuuvwxyz"

Yorick

<lang yorick>func bubblesort(&items) {

 itemCount = numberof(items);
 do {
   hasChanged = 0;
   itemCount--;
   for(index = 1; index <= itemCount; index++) {
     if(items(index) > items(index+1)) {
       items([index,index+1]) = items([index+1,index]);
       hasChanged = 1;
     }
   }
 } while(hasChanged);

}</lang>

zkl

<lang zkl>fcn bubbleSort(list){

  itemCount := list.len();
  do{
     hasChanged := False;
     foreach index in (itemCount -= 1){

if (list[index] > list[index + 1]){ list.swap(index,index + 1); hasChanged = True; }

     }
  }while(hasChanged);
  list

}</lang> Or, punting early termination: <lang zkl>fcn bubbleSort(list){

  foreach n,index in ([list.len()-1..0,-1],n){
     if (list[index] > list[index + 1]) list.swap(index,index + 1);
  }
  list

}</lang> <lang zkl>bubbleSort("This is a test".split("")).println();</lang>

Output:
L(" "," "," ","T","a","e","h","i","i","s","s","s","t","t")

ZX Spectrum Basic

<lang zxbasic>5000 CLS 5002 LET a$="": FOR f=1 TO 64: LET a$=a$+CHR$ (32+INT (RND*96)): NEXT f 5004 PRINT a$; AT 10,0;"ZigZag BubbleSORT" 5010 LET la=LEN a$ 5011 LET i=1: LET u=0 5020 LET d=0: LET p=(u=0)-(u=1) 5021 LET l=(i AND u=0)+(la-i+u AND u=1) 5030 IF u=0 THEN IF a$(l+1)>=a$(l) THEN GO TO 5050 5031 IF u=1 THEN IF a$(l-1)<=a$(l) THEN GO TO 5050 5040 LET d=1 5042 LET t$=a$(l+p) 5043 LET a$(l+p)=a$(l) 5044 LET a$(l)=t$ 5050 LET l=l+p 5051 PRINT AT 10,21;a$(l);AT 12,0;a$ 5055 IF l<=la-i AND l>=i THEN GO TO 5023 5061 LET i=i+NOT u 5063 LET u=NOT u 5064 IF d AND i<la THEN GO TO 5020 5072 PRINT AT 12,0;a$ 9000 STOP </lang>