Sorting algorithms/Sleep sort

From Rosetta Code
Task
Sorting algorithms/Sleep sort
You are encouraged to solve this task according to the task description, using any language you may know.

In general, sleep sort works by starting a separate task for each item to be sorted, where each task sleeps for an interval corresponding to the item's sort key, then emits the item. Items are then collected sequentially in time.

Task: Write a program that implements sleep sort. Have it accept non-negative integers on the command line and print the integers in sorted order. If this is not idomatic in your language or environment, input and output may be done differently. Enhancements for optimization, generalization, practicality, robustness, and so on are not required.

Sleep sort was presented anonymously on 4chan and has been discussed on Hacker News.

Ada[edit]

with Ada.Text_IO;
with Ada.Command_Line; use Ada.Command_Line;
procedure SleepSort is
   task type PrintTask (num : Integer);
   task body PrintTask is begin
      delay Duration (num) / 100.0;
      Ada.Text_IO.Put(num'Img);
   end PrintTask;
   type TaskAcc is access PrintTask;
   TaskList : array (1 .. Argument_Count) of TaskAcc;
begin
   for i in TaskList'Range loop
      TaskList(i) := new PrintTask(Integer'Value(Argument(i)));
   end loop;
end SleepSort;
Output:
./sleepsort 35 21 11 1 2 27 32 7 42 20 50 42 25 41 43 14 46 20 30 8
 1 2 7 8 11 14 20 20 21 25 27 30 32 35 41 42 42 43 46 50

APL[edit]

 
sleepsort{{r}⎕TSYNC{r,,⎕DL },r}

AutoHotkey[edit]

items := [1,5,4,9,3,4]
for i, v in SleepSort(items)
    result .= v ", "
MsgBox, 262144, , % result := "[" Trim(result, ", ") "]"
return

SleepSort(items){
    global Sorted := []
    slp := 50
    for i, v in items{
        fn := Func("PushFn").Bind(v)
        SetTimer, %fn%, % v * -slp
    }
    Sleep % Max(items*) * slp
    return Sorted
}

PushFn(v){
    global Sorted
    Sorted.Push(v)
}
Output:
[1, 3, 4, 4, 5, 9]

Bash[edit]

function sleep_and_echo {
  sleep "$1"
  echo "$1"
}

for val in "$@"; do
  sleep_and_echo "$val" &
done

wait
Output:
$ ./sleep_sort.sh 35 21 11 1 2 27 32 7 42 20 50 42 25 41 43 14 46 20 30 8
1
2
7
8
11
14
20
20
21
25
27
30
32
35
41
42
42
43
46
50

BBC BASIC[edit]

This does not explicitly 'sleep', but uses timers to implement the different delays.

      INSTALL @lib$+"TIMERLIB"
      
      DIM test%(9)
      test%() = 4, 65, 2, 31, 0, 99, 2, 83, 782, 1
      
      FOR i% = 0 TO DIM(test%(),1)
        p% = EVAL("!^PROCtask" + STR$(i%))
        tid% = FN_ontimer(100 + test%(i%), p%, 0)
      NEXT
      
      REPEAT
        WAIT 0
      UNTIL FALSE
      
      DEF PROCtask0 : PRINT test%(0) : ENDPROC
      DEF PROCtask1 : PRINT test%(1) : ENDPROC
      DEF PROCtask2 : PRINT test%(2) : ENDPROC
      DEF PROCtask3 : PRINT test%(3) : ENDPROC
      DEF PROCtask4 : PRINT test%(4) : ENDPROC
      DEF PROCtask5 : PRINT test%(5) : ENDPROC
      DEF PROCtask6 : PRINT test%(6) : ENDPROC
      DEF PROCtask7 : PRINT test%(7) : ENDPROC
      DEF PROCtask8 : PRINT test%(8) : ENDPROC
      DEF PROCtask9 : PRINT test%(9) : ENDPROC

Output:

         0
         1
         2
         2
         4
        31
        65
        83
        99
       782

Brainf***[edit]

>>>>>,----------[++++++++
++[->+>+<<]>+>[-<<+>>]+++
+++++[-<------>]>>+>,----
------<<+[->>>>>+<<<<<]>>
]>>>[<<<<[<<<[->>+<<[->+>
[-]<<]]>[-<+>]>[-<<<.>>>>
->>>>>[>>>>>]<-<<<<[<<<<<
]+<]<<<<]>>>>>[>>>>>]<]

Not exactly 'sleep' sort but it is similar: it inputs an array of digits and in each iteration reduces elements by 1. When an element becomes 0 – it prints the original digit.

Input: 1539\n

Output: 1359

C[edit]

#include <stdlib.h>
#include <unistd.h>
#include <sys/types.h>
#include <sys/wait.h>

int main(int c, char **v)
{
        while (--c > 1 && !fork());
        sleep(c = atoi(v[c]));
        printf("%d\n", c);
        wait(0);
        return 0;
}
Running it:
% ./a.out 5 1 3 2 11 6 4
1
2
3
4
5
6
11

If you worry about time efficiency of this sorting algorithm (ha!), you can make it a 100 times faster by replacing the sleep(... with usleep(10000 * (c = atoi(v[c]))). The smaller the coefficient, the faster it is, but make sure it's not comparable to your kernel clock ticks or the wake up sequence will be wrong.

C#[edit]

using System;
using System.Collections.Generic;
using System.Linq;
using System.Threading;

class Program
{
    static void ThreadStart(object item)
    {
        Thread.Sleep(1000 * (int)item);
        Console.WriteLine(item);
    }

    static void SleepSort(IEnumerable<int> items)
    {
        foreach (var item in items)
        {
            new Thread(ThreadStart).Start(item);
        }
    }

    static void Main(string[] arguments)
    {
        SleepSort(arguments.Select(int.Parse));
    }
}

Using Tasks[edit]

var input = new[] { 1, 9, 2, 1, 3 };

foreach (var n in input)
	Task.Run(() =>
	{
		Thread.Sleep(n * 1000);
		Console.WriteLine(n);
	});

Output, i.e. in LINQPad:

1
1
2
3
9

C++[edit]

#include <chrono>
#include <iostream>
#include <thread>
#include <vector>

int main(int argc, char* argv[]) {
  std::vector<std::thread> threads;

  for (int i = 1; i < argc; ++i) {
    threads.emplace_back([i, &argv]() {
      int arg = std::stoi(argv[i]);
      std::this_thread::sleep_for(std::chrono::seconds(arg));
      std::cout << argv[i] << std::endl;
    });
  }

  for (auto& thread : threads) {
    thread.join();
  }
}
Output:
./a.out 8 15 14 9 17 20 16 24 6 24 21 23 19 23 19 
6
8
9
14
15
16
17
19
19
20
21
23
23
24
24 

Clojure[edit]

Using core.async

(ns sleepsort.core
  (require [clojure.core.async :as async :refer [chan go <! <!! >! timeout]]))

(defn sleep-sort [l]
  (let [c (chan (count l))]
    (doseq [i l]
      (go (<! (timeout (* 1000 i)))
          (>! c i)))
    (<!! (async/into [] (async/take (count l) c)))))
(sleep-sort [4 5 3 1 2 7 6])
;=> [1 2 3 4 5 6 7]

CoffeeScript[edit]

Works with: node.js
after = (s, f) -> setTimeout f, s*1000

# Setting Computer Science back at least a century, maybe more,
# this algorithm sorts integers using a highly parallelized algorithm.
sleep_sort = (arr) ->
  for n in arr
    do (n) -> after n, -> console.log n
    
do ->
  input = (parseInt(arg) for arg in process.argv[2...])
  sleep_sort input

output

> time coffee sleep_sort.coffee 5, 1, 3, 4, 2
1
2
3
4
5

real	0m5.184s
user	0m0.147s
sys	0m0.024s

Common Lisp[edit]

Works with: SBCL
(defun sleeprint(n)
    (sleep (/ n 10))
    (format t "~a~%" n))

(loop for arg in (cdr sb-ext:*posix-argv*) doing
      (sb-thread:make-thread (lambda() (sleeprint (parse-integer arg)))))

(loop while (not (null (cdr (sb-thread:list-all-threads)))))
Output:
$ sbcl --script ss.cl 3 1 4 1 5
1
1
3
4
5

D[edit]

void main(string[] args)
{
    import core.thread, std;
    args.drop(1).map!(a => a.to!uint).parallel.each!((a)
    {
        Thread.sleep(dur!"msecs"(a));
        write(a, " ");
    });
}
Output:
$ ./sorting_algorithms_sleep_sort 200 20 50 10 80
10 20 50 80 200

Dart[edit]

void main() async {
  Future<void> sleepsort(Iterable<int> input) => Future.wait(input
      .map((i) => Future.delayed(Duration(milliseconds: i), () => print(i))));

  await sleepsort([3, 10, 2, 120, 122, 121, 54]);
}
Output:
2
3
10
54
120
121
122

Delphi[edit]

program SleepSortDemo;

{$APPTYPE CONSOLE}

uses
  Windows, SysUtils, Classes;

type
  TSleepThread = class(TThread)
  private
    FValue: Integer;
    FLock: PRTLCriticalSection;
  protected
    constructor Create(AValue: Integer; ALock: PRTLCriticalSection);
    procedure Execute; override;
  end;

constructor TSleepThread.Create(AValue: Integer; ALock: PRTLCriticalSection);
begin
  FValue:= AValue;
  FLock:= ALock;
  inherited Create(False);
end;

procedure TSleepThread.Execute;
begin
  Sleep(1000 * FValue);
  EnterCriticalSection(FLock^);
  Write(FValue:3);
  LeaveCriticalSection(FLock^);
end;

var
  A: array[0..15] of Integer;
  Handles: array[0..15] of THandle;
  Threads: array[0..15] of TThread;
  Lock: TRTLCriticalSection;
  I: Integer;

begin
  for I:= Low(A) to High(A) do
    A[I]:= Random(15);
  for I:= Low(A) to High(A) do
    Write(A[I]:3);
  Writeln;

  InitializeCriticalSection(Lock);
  for I:= Low(A) to High(A) do begin
    Threads[I]:= TSleepThread.Create(A[I], @Lock);
    Handles[I]:= Threads[I].Handle;
  end;
  WaitForMultipleObjects(Length(A), @Handles, True, INFINITE);
  for I:= Low(A) to High(A) do
    Threads[I].Free;
  DeleteCriticalSection(Lock);

  Writeln;
  ReadLn;
end.

Output:

  0  0 12  3  4 10  4  2  5  6  1  7  1 12  0  4
  0  0  0  1  1  2  3  4  4  4  5  6  7 10 12 12

Elena[edit]

ELENA 5.0 :

import extensions;
import system'routines;
import extensions'threading;
import system'threading;
 
static sync = new object();
 
extension op
{
    sleepSort()
    {
        self.forEach:(n)
        {
            threadControl.start(
            {
                threadControl.sleep(1000 * n);
 
                lock(sync)
                {
                    console.printLine(n)
                }
            })
        }
    }
}
 
public program()
{
    program_arguments.skipping:1.selectBy(mssgconst toInt<convertorOp>[1]).toArray().sleepSort();
 
    console.readChar()
}

Elixir[edit]

Translation of: Erlang
defmodule Sort do
  def sleep_sort(args) do
    Enum.each(args, fn(arg) -> Process.send_after(self, arg, 5 * arg) end)
    loop(length(args))
  end
  
  defp loop(0), do: :ok
  defp loop(n) do
    receive do
        num -> IO.puts num
               loop(n - 1)
    end
  end
end

Sort.sleep_sort [2, 4, 8, 12, 35, 2, 12, 1]
Output:
1
2
2
4
8
12
12
35

Emacs Lisp[edit]

GNU Emacs supports threads, but it's more straightforward to do this by just using timers. Evaluate in the *scratch* buffer by typing C-M-x on the expression:

(dolist (i '(3 1 4 1 5 92 65 3 5 89 79 3))
  (run-with-timer (* i 0.001) nil 'message "%d" i))

The output printed in the *Messages* buffer is:

1 [2 times]
3 [3 times]
4
5 [2 times]
65
79
89
92

Erlang[edit]

#!/usr/bin/env escript
%% -*- erlang -*-
%%! -smp enable -sname sleepsort

main(Args) ->
    lists:foreach(fun(Arg) ->
                          timer:send_after(5 * list_to_integer(Arg), self(), Arg)
                  end, Args),
    loop(length(Args)).

loop(0) ->
    ok;
loop(N) ->
    receive
        Num ->
            io:format("~s~n", [Num]),
            loop(N - 1)
    end.
Output:
./sleepsort 2 4 8 12 35 2 12 1
1
2
2
4
8
12
12
35

Euphoria[edit]

include get.e

integer count

procedure sleeper(integer key)
    ? key
    count -= 1
end procedure

sequence s, val
atom task

s = command_line()
s = s[3..$]
if length(s)=0 then
    puts(1,"Nothing to sort.\n")
else
    count = 0
    for i = 1 to length(s) do
        val = value(s[i])
        if val[1] = GET_SUCCESS then
            task = task_create(routine_id("sleeper"),{val[2]})
            task_schedule(task,{val[2],val[2]}/10)
            count += 1
        end if
    end for
    
    while count do
        task_yield()
    end while
end if

F#[edit]

let sleepSort (values: seq<int>) =
    values
    |> Seq.map (fun x -> async {
        do! Async.Sleep x
        Console.WriteLine x
    })
    |> Async.Parallel
    |> Async.Ignore
    |> Async.RunSynchronously

Usage:

sleepSort [10; 33; 80; 32]
10
32
33
80

Factor[edit]

USING: threads calendar concurrency.combinators ;

: sleep-sort ( seq -- ) [ dup seconds sleep . ] parallel-each ;

Usage:

{ 1 9 2 6 3 4 5 8 7 0 } sleep-sort

Fortran[edit]

program sleepSort
    use omp_lib
    implicit none
    integer::nArgs,myid,i,stat
    integer,allocatable::intArg(:)
    character(len=5)::arg

    !$omp master
    nArgs=command_argument_count()
    if(nArgs==0)stop ' : No argument is given !'
    allocate(intArg(nArgs))
    do i=1,nArgs
        call get_command_argument(i, arg)
	read(arg,'(I5)',iostat=stat)intArg(i)
	if(intArg(i)<0 .or. stat/=0) stop&
        &' :Only 0 or positive integer allowed !'
    end do
    call omp_set_num_threads(nArgs)
    !$omp end master
 

    !$omp parallel private(myid)
    myid =omp_get_thread_num()
    call sleepNprint(intArg(myid+1))
    !$omp end parallel

  contains
	subroutine sleepNprint(nSeconds)
	    integer::nSeconds
            call sleep(nSeconds)
	    print*,nSeconds
	end subroutine sleepNprint
end program sleepSort

Compile and Output:

gfortran -fopenmp sleepSort.f90 -o sleepSort
./sleepSort 0 3 1 4 1 5 9
0
1
1
3
4
5
9

FreeBASIC[edit]

Can't use FreeBASIC sleep since it halts the program. Instead it uses a second array filled with times based on the value of number, this array is check against the timer. If the timer is past the stored time the value is printed.

' version 21-10-2016
' compile with: fbc -s console
' compile with: fbc -s console -exx (for bondry check on the array's)
' not very well suited for large numbers and large array's
' positive numbers only 

Sub sandman(sleepy() As ULong)
    Dim As Long lb = LBound(sleepy)
    Dim As Long ub = UBound(sleepy)
    Dim As Long i, count = ub
    Dim As Double wakeup(lb To ub)
    Dim As Double t = Timer

    For i = lb To ub
        wakeup(i) = sleepy(i) +1 + t
    Next

    Do
        t = Timer
        For i = lb To ub
            If wakeup(i) <= t Then
                Print Using "####";sleepy(i);
                wakeup(i) = 1e9 ' mark it as used
                count = count -1
            End If
        Next
        Sleep (1 - (Timer - t)) * 300, 1 ' reduce CPU load
    Loop Until count < lb

End Sub

' ------=< MAIN >=------

Dim As ULong i, arr(10)
Dim As ULong lb = LBound(arr)
Dim As ULong ub = UBound(arr)

Randomize Timer
For i = lb To ub -1 ' leave last one zero
    arr(i) = Int(Rnd * 10) +1
Next

Print "unsorted  ";
For i = lb To ub
    Print Using "####";arr(i);
Next
Print : Print

Print "  sorted  ";
sandman(arr())

Print : Print

' empty keyboard buffer
While InKey <> "" : Wend
Print : Print "hit any key to end program"
Sleep
End
Output:
unsorted     5   2   5   6   4   6   9   5   1   2   0

  sorted     0   1   2   2   4   5   5   5   6   6   9

Go[edit]

package main

import (
	"fmt"
	"log"
	"os"
	"strconv"
	"time"
)

func main() {
	out := make(chan uint64)
	for _, a := range os.Args[1:] {
		i, err := strconv.ParseUint(a, 10, 64)
		if err != nil {
			log.Fatal(err)
		}
		go func(n uint64) {
			time.Sleep(time.Duration(n) * time.Millisecond)
			out <- n
		}(i)
	}
	for _ = range os.Args[1:] {
		fmt.Println(<-out)
	}
}

Usage and output:

./sleepsort 3 1 4 1 5 9
1
1
3
4
5
9

Using sync.WaitGroup[edit]

package main

import (
        "fmt"
        "log"
        "os"
        "strconv"
        "sync"
        "time"
)

func main() {
        var wg sync.WaitGroup
        wg.Add(len(os.Args[1:]))
        for _,i := range os.Args[1:] {
                x, err := strconv.ParseUint(i, 10, 64)
                if err != nil {
                        log.Println(err)
                }
                wg.Add(1)
                go func(i uint64, wg *sync.WaitGroup) {
                        defer wg.Done()
                        time.Sleep(time.Duration(i) * time.Second)
                        fmt.Println(i)
                }(x, &wg)
        }
        wg.Wait()
}

Usage and output are the same as the version using channels. Note that the original version would sleep for increments of 1 full second, so I made my code do the same.

Groovy[edit]

@Grab(group = 'org.codehaus.gpars', module = 'gpars', version = '1.2.1')
import groovyx.gpars.GParsPool

GParsPool.withPool args.size(), {
    args.eachParallel {
        sleep(it.toInteger() * 10)
        println it
    }
}

Sample Run:

> groovy sleepsort.groovy 42 23 16 15 8 4
4
8
15
16
23
42

Haskell[edit]

import System.Environment
import Control.Concurrent
import Control.Monad

sleepSort :: [Int] -> IO ()
sleepSort values = do
        chan <- newChan
        forM_ values (\time -> forkIO (threadDelay (50000 * time) >> writeChan chan time))
        forM_ values (\_ -> readChan chan >>= print)

main :: IO ()
main = getArgs >>= sleepSort . map read

Using mapConcurrently_[edit]

import System.Environment
import Control.Concurrent
import Control.Concurrent.Async

sleepSort :: [Int] -> IO ()
sleepSort = mapConcurrently_ (\x -> threadDelay (x*10^4) >> print x)

main :: IO ()
main = getArgs >>= sleepSort . map read

This is problematic for inputs with multiple duplicates like [1,2,3,1,4,1,5,1] because simultaneous prints are done concurrently and the 1s and newlines get output in jumbled up order. The channels-based version above doesn't have this problem.

Icon and Unicon[edit]

The following solution only works in Unicon.

procedure main(A)
    every insert(t:=set(),mkThread(t,!A))
    every spawn(!t)    # start threads as closely grouped as possible
    while (*t > 0) do write(<<@)
end

procedure mkThread(t,n)    # 10ms delay scale factor
    return create (delay(n*10),delete(t,&current),n@>&main)
end

Sample run:

->ss 3 1 4 1 5 9 2 6
1
1
2
3
4
5
6
9
->

J[edit]

Works with: J version 903+
scheduledumb=: {{
  id=:'dumb',":x:6!:9''
  wd 'pc ',id  
  (t)=: u {{u y[erase n}} t=. id,'_timer'
  wd 'ptimer ',":n p.y
}}


ssort=: {{
  R=: ''
  poly=. 1,>./ y
  poly{{ y{{R=:R,m[y}}scheduledumb m y}}"0 y
  {{echo R}} scheduledumb poly"0 >:>./ y
  EMPTY
}}

Task example:

   t=: ?~30
   t
11 7 22 16 17 2 1 19 23 29 9 21 15 10 12 27 3 4 24 20 14 5 26 18 8 6 0 13 25 28
   ssort t
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29

Note that since t is the result of an RNG, the order of values in t would be different in subsequent attempts. For example:

   t=: ?~30
   t
23 26 24 25 10 12 4 5 7 27 16 17 14 8 3 15 18 13 19 21 2 28 22 9 6 20 11 1 29 0
   ssort t
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29

Java[edit]

Works with: Java version 1.5+
import java.util.concurrent.CountDownLatch;

public class SleepSort {
	public static void sleepSortAndPrint(int[] nums) {
		final CountDownLatch doneSignal = new CountDownLatch(nums.length);
		for (final int num : nums) {
			new Thread(new Runnable() {
				public void run() {
					doneSignal.countDown();
					try {
						doneSignal.await();

						//using straight milliseconds produces unpredictable
						//results with small numbers
						//using 1000 here gives a nifty demonstration
						Thread.sleep(num * 1000);
						System.out.println(num);
					} catch (InterruptedException e) {
						e.printStackTrace();
					}
				}
			}).start();
		}
	}
	public static void main(String[] args) {
		int[] nums = new int[args.length];
		for (int i = 0; i < args.length; i++)
			nums[i] = Integer.parseInt(args[i]);
		sleepSortAndPrint(nums);
	}
}

Output (using "3 1 4 5 2 3 1 6 1 3 2 5 4 6" as arguments):

1
1
1
2
2
3
3
3
4
4
5
5
6
6

JavaScript[edit]

Array.prototype.timeoutSort = function (f) {
	this.forEach(function (n) {
		setTimeout(function () { f(n) }, 5 * n)
	});
}

Usage and output:

[1, 9, 8, 7, 6, 5, 3, 4, 5, 2, 0].timeoutSort(function(n) { document.write(n + '<br>'); })
0
1
2
3
4
5
6
7
8
9
Array.prototype.sleepSort = function(callback) {
  const res = [];
  for (let n of this)
    setTimeout(() => {
      res.push(n);
      if (this.length === res.length)
        callback(res);
    }, n + 1);
  return res;
};

[1, 9, 8, 7, 6, 5, 3, 4, 5, 2, 0].sleepSort(console.log);
// [ 1, 0, 2, 3, 4, 5, 5, 6, 7, 8, 9 ]

jq[edit]

Translation of: Brainf***

Doesn't actually sleep. Instead, iterates reducing the values by one until each is zero.

echo '[5, 1, 3, 2, 11, 6, 4]' | jq '
def f:
  if .unsorted == [] then
    .sorted
  else
    { unsorted: [.unsorted[] | .t = .t - 1 | select(.t != 0)]
    , sorted: (.sorted + [.unsorted[] | .t = .t - 1 | select(.t == 0) | .v]) }
    | f
  end;
{unsorted: [.[] | {v: ., t: .}], sorted: []} | f | .[]
'
Output:
1
2
3
4
5
6
11

Julia[edit]

Works with: Julia version 1.6
function sleepsort(V::Vector{T}) where {T <: Real}
    U = Vector{T}()
    sizehint!(U, length(V))
    @sync for v in V
        @async begin
            sleep(abs(v))
            (v < 0 ? pushfirst! : push!)(U, v)
        end
    end
    return U
end



v = rand(-10:10, 10)
println("# unordered: $v\n -> ordered: ", sleepsort(v))
Output:
# unordered: [10, -1, 3, -9, 1, -5, -8, -7, -3, 3]
 -> ordered: [-9, -8, -7, -5, -3, -1, 1, 3, 3, 10]

Kotlin[edit]

// version 1.1.51

import kotlin.concurrent.thread

fun sleepSort(list: List<Int>, interval: Long) {
    print("Sorted  : ")
    for (i in list) {
        thread {
            Thread.sleep(i * interval)
            print("$i ")
        }
    }
    thread { // print a new line after displaying sorted list
        Thread.sleep ((1 + list.max()!!) * interval)
        println()
    }
}

fun main(args: Array<String>) {
   val list = args.map { it.toInt() }.filter { it >= 0 } // ignore negative integers
   println("Unsorted: ${list.joinToString(" ")}")
   sleepSort(list, 50)
}

Sample output:

$ java -jar sleepsort.jar 5 7 -1 2 4 1 8 0 3 9 6 
Unsorted: 5 7 2 4 1 8 0 3 9 6
Sorted  : 0 1 2 3 4 5 6 7 8 9 

Lua[edit]

Here's a slow implementation using only stock C Lua:

function sleeprint(n)
  local t0 = os.time()
  while os.time() - t0 <= n do
    coroutine.yield(false)
  end
  print(n)
  return true
end

coroutines = {}
for i=1, #arg do
  wrapped = coroutine.wrap(sleeprint)
  table.insert(coroutines, wrapped)
  wrapped(tonumber(arg[i]))
end

done = false
while not done do
  done = true
  for i=#coroutines,1,-1 do
    if coroutines[i]() then
      table.remove(coroutines, i)
    else
      done = false
    end
  end
end

By installing LuaSocket, you can get better than 1-second precision on the clock, and therefore faster output:

socket = require 'socket'

function sleeprint(n)
  local t0 = socket.gettime()
  while (socket.gettime() - t0)*100 <= n do
    coroutine.yield(false)
  end
  print(n)
  return true
end

coroutines = {}
for i=1, #arg do 
  wrapped = coroutine.wrap(sleeprint)
  table.insert(coroutines, wrapped)
  wrapped(tonumber(arg[i]))
end

done = false
while not done do
  done = true
  for i=#coroutines,1,-1 do 
    if coroutines[i]() then
      table.remove(coroutines, i)
    else
      done = false
    end
  end
end

Either way, the output is the same:

Output:
$ lua sleep_sort.lua 3 1 4 1 5 9 2 6 5 3 5
1
1
2
3
3
4
5
5
5
6
9

Mathematica/Wolfram Language[edit]

SleepSort = RunScheduledTask[Print@#, {#, 1}] & /@ # &;
SleepSort@{1, 9, 8, 7, 6, 5, 3, 4, 5, 2, 0};
Output:
0
1
2
3
4
5
6
7
8
9

NetRexx[edit]

As implemented this sample goes beyond the scope of the task as defined; it will handle negative numbers.

/* NetRexx */
options replace format comments java crossref symbols nobinary
import java.util.concurrent.CountDownLatch

-- =============================================================================
class RSortingSleepsort
  properties constant private
    dflt = '-6 3 1 4 5 2 3 -7 1 6 001 3 -9 2 5 -009 -8 4 6 1 9 8 7 6 5 -7 3 4 5 2 0 -2 -1 -5 -4 -3 -0 000 0'
  properties indirect
    startLatch = CountDownLatch
    doneLatch  = CountDownLatch
    floor      = 0
    sorted     = ''
  -- ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
  method main(args = String[]) public static
    arg = Rexx(args)
    if arg = '' then arg = dflt
    say ' unsorted:' arg
    say '   sorted:' (RSortingSleepsort()).sleepSort(arg)
    return
  -- ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
  method sleepSort(iArg) public
    setStartLatch(CountDownLatch(1))           -- used to put all threads on hold until we're ready to run
    setDoneLatch(CountDownLatch(iArg.words())) -- used to indicate all work is done
    loop mn = 1 to iArg.words()
      setFloor(getFloor().min(iArg.word(mn)))   -- save smallest -ve number so we can use it as a scale for sleep
      Thread(SortThread(iArg.word(mn))).start() -- loop through input and create a thread for each element
      end mn
    getStartLatch().countDown() -- cry 'Havoc', and let slip the dogs of war.
    do
      getDoneLatch().await() -- wait for worker threads to complete
    catch ix = InterruptedException
      ix.printStackTrace()
    end
    return getSorted()

-- =============================================================================
class RSortingSleepsort.SortThread dependent implements Runnable
  properties indirect
    num
  -- ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
  method SortThread(nm)
    setNum(nm)
    return
  -- ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
  method run() public
    do
      parent.getStartLatch().await()                 -- wait until all threads are constructed
      sleepTime = getNum() + parent.getFloor().abs() -- shifted by value of smallest number (permits numbers < 0)
      sleepTime = sleepTime * 250                    -- scale up; milliseconds are not granular enough
      Thread.sleep(sleepTime)                        -- wait for this number's turn to run
    catch ie = InterruptedException
      ie.printStackTrace()
    end
    do protect parent -- lock the parent to prevent collisions
      parent.setSorted((parent.getSorted() num).strip()) -- stow the number in the results List
    end
    parent.getDoneLatch().countDown() -- this one's done; decrement the latch
    return

Output:

 unsorted: -6 3 1 4 5 2 3 -7 1 6 001 3 -9 2 5 -009 -8 4 6 1 9 8 7 6 5 -7 3 4 5 2 0 -2 -1 -5 -4 -3 -0 000 0
   sorted: -9 -009 -8 -7 -7 -6 -5 -4 -3 -2 -1 000 0 0 -0 1 1 001 1 2 2 2 3 3 3 3 4 4 4 5 5 5 5 6 6 6 7 8 9

Nim[edit]

Compile with nim --threads:on c sleepsort:

import os, strutils

proc single(n: int) =
  sleep n
  echo n

proc main =
  var thr = newSeq[TThread[int]](paramCount())
  for i,c in commandLineParams():
    thr[i].createThread(single, c.parseInt)
  thr.joinThreads

main()

Usage:

$ ./sleepsort 5 1 3 2 11 6 4
1
2
3
4
5
6
11

Objeck[edit]

use System.Concurrency;
use Collection;

bundle Default {
  class Item from Thread {
    @value : Int;
    
    New(value : Int) {
      Parent();
      @value := value;
    }

    method : public : Run(param : System.Base) ~ Nil {
      Sleep(1000 * @value);
      @value->PrintLine();
    }
  }

  class SleepSort {
    function : Main(args : String[]) ~ Nil {
      items := Vector->New();
      each(i : args) {
        items->AddBack(Item->New(args[i]->ToInt()));
      };
    
      each(i : items) {
        items->Get(i)->As(Item)->Execute(Nil);
      };
    }
  }
}

Objective-C[edit]

#import <Foundation/Foundation.h>

int main(int argc, char **argv)
{
    NSOperationQueue *queue = [[NSOperationQueue alloc] init];
    while (--argc) {
        int i = atoi(argv[argc]);
        [queue addOperationWithBlock: ^{
            sleep(i);
            NSLog(@"%d\n", i);
        }];
    }
    [queue waitUntilAllOperationsAreFinished];
}

Rather than having multiple operations that sleep, we could also dispatch the tasks after a delay:

#import <Foundation/Foundation.h>

int main(int argc, char **argv)
{
    while (--argc) {
        int i = atoi(argv[argc]);
        dispatch_after(dispatch_time(DISPATCH_TIME_NOW, i * NSEC_PER_SEC),
                       dispatch_get_main_queue(),
                       ^{ NSLog(@"%d\n", i); });
    }
}

Oforth[edit]

Instead of printing numbers, each task sends its integer into a channel (after sleeping 20 * n milliseconds). This allows the main task to create a new sorted list with those integers.

20 milliseconds is used to (try to) handle scheduler tick on Windows systems (around 15 ms). On Linux systems (after kernel 2.6.8), this value can be smaller.

import: parallel

: sleepSort(l)
| ch n |
   Channel new ->ch
   l forEach: n [ #[ n dup 20 * sleep ch send drop ] & ]
   ListBuffer newSize(l size) #[ ch receive over add ] times(l size) ;
Output:
100 seq 100 seq + sleepSort println
[1, 1, 2, 2, 3, 3, 4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 9, 9, 10, 10, 11, 11, 12, 12, 13, 13, 14,
 14, 15, 15, 16, 16, 17, 17, 18, 18, 19, 19, 20, 20, 21, 21, 22, 22, 23, 23, 24, 24, 25, 2
5, 26, 26, 27, 27, 28, 28, 29, 29, 30, 30, 31, 31, 32, 32, 33, 33, 34, 34, 35, 35, 36, 36,
 37, 37, 38, 38, 39, 39, 40, 40, 41, 41, 42, 42, 43, 43, 44, 44, 45, 45, 46, 46, 47, 47, 4
8, 48, 49, 49, 50, 50, 51, 51, 52, 52, 53, 53, 54, 54, 55, 55, 56, 56, 57, 57, 58, 58, 59,
 59, 60, 60, 61, 61, 62, 62, 63, 63, 64, 64, 65, 65, 66, 66, 67, 67, 68, 68, 69, 69, 70, 7
0, 71, 71, 72, 72, 73, 73, 74, 74, 75, 75, 76, 76, 77, 77, 78, 78, 79, 79, 80, 80, 81, 81,
 82, 82, 83, 83, 84, 84, 85, 85, 86, 86, 87, 87, 88, 88, 89, 89, 90, 90, 91, 91, 92, 92, 9
3, 93, 94, 94, 95, 95, 96, 96, 97, 97, 98, 98, 99, 99, 100, 100]

Ol[edit]

(define (sleep-sort lst)
   (for-each (lambda (timeout)
         (async (lambda ()
            (sleep timeout)
            (print timeout))))
      lst))

(sleep-sort '(5 8 2 7 9 10 5))
Output:
2
5
5
7
8
9
10

Pascal[edit]

Works with: Free Pascal

my limit under linux was 4000 threads nearly 2 GB.

program sleepsort;
{$IFDEF FPC}
  {$MODE DELPHI} {$Optimization ON,ALL}
{$ElSE}
  {$APPTYPE CONSOLE}
{$ENDIF}
uses
  {$IFDEF UNIX}
  cthreads,
  {$ENDIF}
  SysUtils;

const
  HiLimit = 40;
type
  tCombineForOneThread = record
    cft_count : Uint64;
    cft_ThreadID: NativeUint;
    cft_ThreadHandle: NativeUint;
  end;
  pThreadBlock = ^tCombineForOneThread;
var
  SortIdx : array of INteger;
  ThreadBlocks : array of tCombineForOneThread;
  gblThreadCount,
  Finished: Uint32;

  procedure PrepareThreads(thdCount:NativeInt);
  var
    i : NativeInt;
  Begin
    For i := 0 to thdCount-1 do
      ThreadBlocks[i].cft_count:= random(2*HiLimit);
  end;

  procedure TestRunThd(parameter: pointer);
  var
     pThdBlk: pThreadBlock;
     fi: NativeInt;
  begin
    pThdBlk := @ThreadBlocks[NativeUint(parameter)];
    with pThdBlk^ do
    begin
      sleep(40*cft_count+1);
      fi := Finished-1;
      //write(fi:5,cft_count:8,#13); 
      InterLockedDecrement(Finished);
      SortIdx[fi]:= NativeUint(parameter);
    end;
    EndThread(0);
  end;

  procedure Test;
  var
    j,UsedThreads: NativeInt;
  begin
    randomize;
    UsedThreads:= GblThreadCount;
    Finished :=UsedThreads;
    PrepareThreads(UsedThreads);
    j := 0;
    while (j < UsedThreads) do
    begin
      with ThreadBlocks[j] do
        begin
          cft_ThreadHandle :=
          BeginThread(@TestRunThd, Pointer(j), cft_ThreadID,16384 {stacksize} );
          If cft_ThreadHandle = 0 then break;
        end;
      Inc(j);
    end;
    writeln(j);
    UsedThreads := j;
    Finished :=UsedThreads;
    repeat
      sleep(1);
    until finished = 0;
    For j := 0 to  UsedThreads-1 do
      CloseThread(ThreadBlocks[j].cft_ThreadID);

    //output of sleep-sorted data
    For j := UsedThreads-1 downto 1 do
      write(ThreadBlocks[SortIdx[j]].cft_count,',');
    writeln(ThreadBlocks[SortIdx[0]].cft_count);
  end;


begin
  randomize;
  gblThreadCount := Hilimit;
  Writeln('Testthreads : ',gblThreadCount);
  setlength(ThreadBlocks,gblThreadCount);
  setlength(SortIdx,gblThreadCount);
  Test;

  setlength(ThreadBlocks, 0);
  {$IFDEF WINDOWS}
  readln;
  {$ENDIF}
end.
Output:
time ./sleepsort
Testthreads : 40
40
1,8,9,10,11,12,12,13,14,18,24,24,24,26,28,35,35,37,42,49,50,52,54,54,56,57,59,60,61,62,64,69,69,71,72,73,76,77,78,79

real	0m3,164s

Perl[edit]

Basically the C code.

1 while ($_ = shift and @ARGV and !fork);
sleep $_;
print "$_\n";
wait;


A more optimal solution makes use of Coro, a cooperative threading library. It has the added effect of being much faster, fully deterministic (sleep is not exact), and it allows you to easily collect the return value:

use Coro;
$ret = Coro::Channel->new;
@nums = qw(1 32 2 59 2 39 43 15 8 9 12 9 11);

for my $n (@nums){
	async {
		Coro::cede for 1..$n;
		$ret->put($n);
	}
}

print $ret->get,"\n" for 1..@nums;

Phix[edit]

Based on Euphoria

without js -- (multitasking)
integer count
 
procedure sleeper(integer key)
    ? key -- (or maybe res &= key)
    count -= 1
end procedure
 
--sequence s = command_line()[3..$]
sequence s = split("3 1 4 1 5 9 2 6 5")
if length(s)=0 then
    puts(1,"Nothing to sort.\n")
else
    count = 0
    for i=1 to length(s) do
        object si = to_number(s[i])
        if integer(si) then
            atom task = task_create(sleeper,{si})
            task_schedule(task,{si/10,si/10})
            count += 1
        end if
    end for
 
    while count do
        task_yield()
    end while
end if

PicoLisp[edit]

Sleeping in main process[edit]

(de sleepSort (Lst)
   (make
      (for (I . N) Lst
         (task (- I) (* N 100)  N N  I I
            (link N)
            (pop 'Lst)
            (task (- I)) ) )
      (wait NIL (not Lst)) ) )

Sleeping in child processes[edit]

(de sleepSort (Lst)
   (make
      (for N Lst
         (task (pipe (wait (* N 100))) N N
            (link N)
            (pop 'Lst)
            (task (close @)) ) )
      (wait NIL (not Lst)) ) )

Output in both cases:

: (sleepSort (3 1 4 1 5 9 2 6 5))
-> (1 1 2 3 4 5 5 6 9)

Just printing (no sorted result list)[edit]

Basically the C code.

(for N (3 1 4 1 5 9 2 6 5)
   (unless (fork)
      (call 'sleep N)
      (msg N)
      (bye) ) )

Output:

1              
1
2
3
4
5
5
6
9

Pike[edit]

#!/usr/bin/env pike
  
int main(int argc, array(string) argv)
{
        foreach(argv[1..], string value)
        {
                int v = (int)value;
                if(v<0)
                        continue;
                call_out(print, v, value);
        }
        return -1;
}

void print(string value)
{
        write("%s\n", value);
        if(find_call_out(print)==-1)
                exit(0);
        return;
}

Output :

$ ./sleep-sort.pike 4 5 -3 1 2 7 6
1
2
4
5
6
7

Prolog[edit]

Works with SWI-Prolog.

sleep_sort(L) :-
	thread_pool_create(rosetta, 1024, []) ,
	maplist(initsort, L, LID),
	maplist(thread_join, LID, _LStatus),
	thread_pool_destroy(rosetta).

initsort(V, Id) :-
	thread_create_in_pool(rosetta, (sleep(V), writeln(V)), Id, []).

Output :

 sleep_sort([5, 1, 3, 2, 11, 6, 3, 4]).
1
2
3
3
4
5
6
11
true.

PureBasic[edit]

NewMap threads()

Procedure Foo(n)
  Delay(n)
  PrintN(Str(n))
EndProcedure

If OpenConsole()
  For i=1 To CountProgramParameters()
    threads(Str(i)) = CreateThread(@Foo(), Val(ProgramParameter()))
  Next
  
  ForEach threads()
    WaitThread(threads())
  Next
  Print("Press ENTER to exit"): Input()
EndIf
Sleep_sort.exe 3 1 4 1 5 9
1
1
3
4
5
9
Press ENTER to exit

Python[edit]

Python: Using threading.Timer[edit]

from time import sleep
from threading import Timer

def sleepsort(values):
    sleepsort.result = []
    def add1(x):
        sleepsort.result.append(x)
    mx = values[0]
    for v in values:
        if mx < v: mx = v
        Timer(v, add1, [v]).start()
    sleep(mx+1)
    return sleepsort.result

if __name__ == '__main__':
    x = [3,2,4,7,3,6,9,1]
    if sleepsort(x) == sorted(x):
        print('sleep sort worked for:',x)
    else:
        print('sleep sort FAILED for:',x)
Sample output
sleep sort worked for: [3, 2, 4, 7, 3, 6, 9, 1]

Python v3.5+: Using asyncio[edit]

Since the introduction of async/await syntax, the implementation could be a sole translation from the original version in Bash:

Works with: Python 3.5+
#!/usr/bin/env python3
from asyncio import run, sleep, wait
from sys import argv

async def f(n):
    await sleep(n)
    print(n)

if __name__ == '__main__': 
    run(wait(map(f, map(int, argv[1:]))))

Example usage:

$ ./sleepsort.py 5 3 6 3 6 3 1 4 7
1
3
3
3
4
5
6
6
7

Racket[edit]

#lang racket

;; accepts a list to sort
(define (sleep-sort lst)
  (define done (make-channel))
  (for ([elem lst])
    (thread 
     (λ () 
       (sleep elem)
       (channel-put done elem))))
  (for/list ([_ (length lst)])
    (channel-get done)))

;; outputs '(2 5 5 7 8 9 10)
(sleep-sort '(5 8 2 7 9 10 5))

Raku[edit]

(formerly Perl 6)

await map -> $delay { start { sleep $delay ; say $delay } },
    <6 8 1 12 2 14 5 2 1 0>;
Output:
0
1
1
2
2
5
6
8
12
14

This can also be written using reactive programming:

#!/usr/bin/env raku
use v6;
react whenever Supply.from-list(@*ARGS).start({ .&sleep // +$_ }).flat { .say }
Output:
$ ./sleep-sort 1 3 5 6 2 4
1
2
3
4
5
6

REXX[edit]

This sort will accept any manner of numbers,   or for that matter,   any character string as well.
REXX isn't particular what is being sorted.

/*REXX program implements a sleep sort (with numbers entered from the command line (CL).*/
numeric digits 300                               /*over the top,  but what the hey!     */
                                                 /*  (above)  ··· from vaudeville.      */
@.=                                              /*placeholder for the array of numbers.*/
stuff= 1e9 50 5 40 4 1 100 30 3 12 2 8 9 7 6 6 10 20 0      /*alphabetically ··· so far.*/
parse arg numbers                                /*obtain optional arguments from the CL*/
if numbers=''  then numbers= stuff               /*Not specified?  Then use the default.*/
N= words(numbers)                                /*N  is the number of numbers in list. */
w= length(N)                                     /*width of  N  (used for nice output). */
parse upper version !ver .                       /*obtain which REXX we're running under*/
!regina= ('REXX-REGINA'==left(!ver, 11) )        /*indicate (or not) if this is Regina. */
say N  'numbers to be sorted:'   numbers         /*informative informational information*/
                                                 /*from department of redundancy depart.*/
    do j=1  for N                                /*let's start to boogie─woogie da sort.*/
    @.j= word(numbers, j)                        /*plug in a single number at a time.   */
    if datatype(@.j, 'N')  then @.j= @.j / 1     /*normalize it if it's a numeric number*/
    if !regina  then call fork                   /*only REGINA REXX supports  FORK  BIF.*/
    call sortItem j                              /*start a sort for an array number.    */
    end   /*j*/

      do forever  while \inOrder(N)              /*wait for the sorts to complete.      */
      call delay 1                               /*one second is minimum effective time.*/
      end    /*forever while*/                   /*well heck,  other than zero seconds. */

m= max(length(@.1), length(@.N) )                /*width of smallest or largest number. */
say;                        say  'after sort:'   /*display a blank line and a title.    */

      do k=1  for N                              /*list the  (sorted)  array's elements.*/
      say left('', 20)     'array element'      right(k, w)      '───►'      right(@.k, m)
      end   /*k*/
exit                                             /*stick a fork in it,  we're all done. */
/*──────────────────────────────────────────────────────────────────────────────────────*/
sortItem: procedure expose @.;   parse arg ?     /*sorts a single  (numeric)  item.     */
              do Asort=1  until \switched        /*sort unsorted array until it's sorted*/
              switched= 0                        /*it's all hunky─dorey, happy─dappy ···*/
                                     do i=1   while   @.i\==''  &  \switched
                                     if @.? >= @.i then iterate     /*item is in order. */
                                     parse value   @.?  @.i     with     @.i  @.?
                                     switched= 1                    /* [↑]  swapped one.*/
                                     end   /*i*/
              if Asort//?==0  then call delay switched              /*sleep if last item*/
              end   /*Asort*/
          return               /*Sleeping Beauty awakes.  Not to worry:  (c)=circa 1697.*/
/*──────────────────────────────────────────────────────────────────────────────────────*/
inOrder: procedure expose @.;  parse arg howMany /*is the array in numerical order?     */
           do m=1  for howMany-1;  next= m+1;  if @.m>@.next  then return 0 /*¬ in order*/
           end   /*m*/                           /*keep looking for fountain of youth.  */
         return 1                                /*yes, indicate with an indicator.     */

Programming note:   this REXX program makes use of   DELAY   BIF which delays (sleeps) for a specified amount of seconds.
Some REXXes don't have a   DELAY   BIF,   so one is included here   ──►   DELAY.REX.


output   when using the internal default input:
19 numbers to be sorted: 1E9 50 5 40 4 1 100 30 3 12 2 8 9 7 6 6 10 20 0

after sort:
                     array element  1 ───►          0
                     array element  2 ───►          1
                     array element  3 ───►          2
                     array element  4 ───►          3
                     array element  5 ───►          4
                     array element  6 ───►          5
                     array element  7 ───►          6
                     array element  8 ───►          6
                     array element  9 ───►          7
                     array element 10 ───►          8
                     array element 11 ───►          9
                     array element 12 ───►         10
                     array element 13 ───►         12
                     array element 14 ───►         20
                     array element 15 ───►         30
                     array element 16 ───►         40
                     array element 17 ───►         50
                     array element 18 ───►        100
                     array element 19 ───► 1000000000

Ruby[edit]

require 'thread'

nums = ARGV.collect(&:to_i)
sorted = []
mutex = Mutex.new

threads = nums.collect do |n|
  Thread.new do
    sleep 0.01 * n
    mutex.synchronize {sorted << n}
  end
end
threads.each {|t| t.join}

p sorted

Example

$ ruby sleepsort.rb 3 1 4 5 2 3 1 6 1 3 2 5 4 6
[1, 1, 1, 2, 2, 3, 3, 3, 4, 4, 5, 5, 6, 6]

Rust[edit]

use std::thread;

fn sleepsort<I: Iterator<Item=u32>>(nums: I) {
    let threads: Vec<_> = nums.map(|n|
        thread::spawn(move || {
            thread::sleep_ms(n);
            println!("{}", n); })).collect();
    for t in threads { t.join(); }
}

fn main() {
    sleepsort(std::env::args().skip(1).map(|s| s.parse().unwrap()));
}

Output:

$ ./sleepsort 50 34 43 3 2
2
3
34
43
50

Scala[edit]

object SleepSort {

  def main(args: Array[String]): Unit = {
    val nums = args.map(_.toInt)
    sort(nums)
    Thread.sleep(nums.max * 21) // Keep the JVM alive for the example
  }

  def sort(nums: Seq[Int]): Unit =
    nums.foreach(i => new Thread {
      override def run() {
        Thread.sleep(i * 20) // just `i` is unpredictable with small numbers
        print(s"$i ")
      }
    }.start())

}
Output:
$ scala SleepSort 1 3 6 0 9 7 4 2 5 8
0 1 2 3 4 5 5 6 7 8 9

Sidef[edit]

ARGV.map{.to_i}.map{ |i|
    {Sys.sleep(i); say i}.fork;
}.each{.wait};
Output:
% sidef test.sf 5 1 3 2 11 6 4
1
2
3
4
5
6
11

Simula[edit]

SIMULATION
BEGIN

    PROCESS CLASS SORTITEM(N); INTEGER N;
    BEGIN
        HOLD(N);
        OUTINT(N, 3);
    END;

    INTEGER I;
    FOR I := 3, 2, 4, 7, 3, 6, 9, 1 DO
    BEGIN
        REF(SORTITEM) SI;
        SI :- NEW SORTITEM(I);
        ACTIVATE SI;
    END;
    HOLD(100000);
    OUTIMAGE;

END;
Output:
  1  2  3  3  4  6  7  9

SNUSP[edit]

Bloated SNUSP is ideally suited to this task, since this the variant adds multithreading and an additional dimension of data space. Sleep time is simulated by the loop delay required to copy each cell value, thereby ensuring that smaller values are printed earlier than larger values. This program requires a Bloated SNUSP interpreter which returns zero on input end-of-file.

      /$>\  input until eof
  #/?<\?,/  foreach: fork
   \ &/:+   copy and\
    /:\?-;    delay /
    \.#     print and exit thread

Legend:

  • & - SPLIT creates a new thread. Like @ ENTER, it skips one cell of code space to start its continuation.
  • : ; - UP and DOWN are equivalent to < > LEFT and RIGHT, but moves the data pointer in the second dimension.
  • # - in Bloated SNUSP, LEAVE only terminates the current thread. The overall program only exits when all threads have quit.

Swift[edit]

import Foundation

for i in [5, 2, 4, 6, 1, 7, 20, 14] {
    let time = dispatch_time(DISPATCH_TIME_NOW,
        Int64(i * Int(NSEC_PER_SEC)))
    
    dispatch_after(time, dispatch_get_main_queue()) {
        print(i)
    }
}

CFRunLoopRun()
Output:
1
2
4
5
6
7
14
20

Tcl[edit]

Tcl 8.5[edit]

#!/bin/env tclsh
set count 0
proc process val {
    puts $val
    incr ::count
}
# Schedule the output of the values
foreach val $argv {
    after [expr {$val * 10}] [list process $val]
}
# Run event loop until all values output...
while {$count < $argc} {
    vwait count
}

Demo:

bash$ sleepsort.tcl 3 1 4 5 2 3 1 6 1 3 2 5 4 6
1
1
1
2
2
3
3
3
4
4
5
5
6
6

Tcl 8.6[edit]

set sorted {}
lmap x $argv {after $x [list lappend sorted $x]}
while {[llength $sorted] != $argc} {
	vwait sorted
}
puts $sorted
Output:
$ echo 'puts [lmap _ [lrepeat 30 {}] {expr {int(rand() * 100)}}]' | tclsh | tee /dev/tty | xargs tclsh sleepsort.tcl
5 8 70 27 15 80 49 2 69 93 29 1 14 84 43 2 81 44 60 62 8 75 23 61 42 68 79 46 72 65
1 2 2 5 8 8 14 15 23 27 29 42 43 44 46 49 60 61 62 65 68 69 70 72 75 79 80 81 84 93

Tcl 8.6: coroutine[edit]

#! /usr/bin/env tclsh
 
package require Tcl 8.6
 
# By aspect (https://wiki.tcl-lang.org/page/aspect).  Modified slightly.
# 1. Schedule N delayed calls to our own coroutine.
# 2. Yield N times to grab the scheduled values.  Print each.
# 3. Store the sorted list in $varName.
proc sleep-sort {ls varName} {
    foreach x $ls {
        after $x [info coroutine] $x
    }
 
    set $varName [lmap x $ls {
        set newX [yield]
        puts $newX
        lindex $newX
    }]
}

# Ensure the list is suitable for use with [sleep-sort].
proc validate ls {
    if {[llength $ls] == 0} {
        error {list is empty}
    }
 
    foreach x $ls {
        if {![string is integer -strict $x] || $x < 0} {
            error [list invalid value: $x]
        }        
    }
 
    return $ls
}
 
coroutine c sleep-sort [validate $argv] ::sorted
vwait sorted

Demo:

$ ./sleepsort.tcl 1 2 100 40 76 0 0 0 200 199
0
0
0
1
2
40
76
100
199
200

UNIX Shell[edit]

Works with: Bourne Shell
f() {
    sleep "$1"
    echo "$1"
}
while [ -n "$1" ]
do
    f "$1" &
    shift
done
wait

Usage and output:

sh sleepsort.sh 3 1 4 1 5 9
1
1
3
4
5
9

Visual Basic .NET[edit]

Imports System.Threading

Module Module1

    Sub SleepSort(items As IEnumerable(Of Integer))
        For Each item In items
            Task.Factory.StartNew(Sub()
                                      Thread.Sleep(1000 * item)
                                      Console.WriteLine(item)
                                  End Sub)
        Next
    End Sub

    Sub Main()
        SleepSort({1, 5, 2, 1, 8, 10, 3})
        Console.ReadKey()
    End Sub

End Module
Output:
1
1
2
3
5
8
10

Wren[edit]

More of a simulation than a 'true' sleep sort.

import "timer" for Timer
import "io" for Stdout
import "os" for Process

var args = Process.arguments
var n = args.count
if (n < 2) Fiber.abort("There must be at least two arguments passed.")
var list = args.map{ |a| Num.fromString(a) }.toList
if (list.any { |i| i == null || !i.isInteger || i < 0 } ) {
    Fiber.abort("All arguments must be non-negative integers.")
}
var max = list.reduce { |acc, i| acc = (i > acc) ? i : acc }
var fibers = List.filled(max+1, null)
System.print("Before: %(list.join(" "))")
for (i in list) {
    var sleepSort = Fiber.new { |i|
        Timer.sleep(1000)
        Fiber.yield(i)
    }
    fibers[i] = sleepSort
}
System.write("After : ")
for (i in 0..max) {
    var fib = fibers[i]
    if (fib) {
        System.write("%(fib.call(i)) ")
        Stdout.flush()
    }
}
System.print()
Output:

Sample run:

$ wren sleepsort.wren  1 8 3 7 4 6
Before: 1 8 3 7 4 6
After : 1 3 4 6 7 8 

zkl[edit]

vm.arglist.apply(fcn(n){ Atomic.sleep(n); print(n) }.launch);
Atomic.waitFor(fcn{ vm.numThreads == 1 }); Atomic.sleep(2); println();
Output:
$ zkl bbb 7 6 9 2 4 8 1 3 5
123456789
$