# N'th

**N'th**

You are encouraged to solve this task according to the task description, using any language you may know.

Write a function/method/subroutine/... that when given an integer greater than or equal to zero returns a string of the number followed by an apostrophe then the ordinal suffix.

- Example

Returns would include `1'st 2'nd 3'rd 11'th 111'th 1001'st 1012'th`

- Task

Use your routine to show here the output for *at least* the following (inclusive) ranges of integer inputs:
`0..25, 250..265, 1000..1025`

**Note:** apostrophes are now *optional* to allow correct apostrophe-less English.

## Contents

- 1 11l
- 2 8080 Assembly
- 3 8086 Assembly
- 4 Action!
- 5 Ada
- 6 ALGOL 68
- 7 APL
- 8 AppleScript
- 9 Applesoft BASIC
- 10 Arturo
- 11 AutoHotkey
- 12 AWK
- 13 Babel
- 14 BaCon
- 15 BASIC
- 16 Batch File
- 17 BBC BASIC
- 18 BCPL
- 19 Befunge
- 20 BQN
- 21 C
- 22 C#
- 23 C++
- 24 Clojure
- 25 CLU
- 26 COBOL
- 27 Common Lisp
- 28 Cowgol
- 29 Crystal
- 30 D
- 31 Delphi
- 32 Draco
- 33 Elena
- 34 Elixir
- 35 ERRE
- 36 F#
- 37 Factor
- 38 Forth
- 39 Fortran
- 40 FreeBASIC
- 41 Gambas
- 42 Go
- 43 GW-BASIC
- 44 Haskell
- 45 Icon and Unicon
- 46 J
- 47 Java
- 48 JavaScript
- 49 jq
- 50 Julia
- 51 Kotlin
- 52 Lambdatalk
- 53 Liberty BASIC
- 54 Lua
- 55 Maple
- 56 Mathematica/Wolfram Language
- 57 MATLAB
- 58 Microsoft Small Basic
- 59 MiniScript
- 60 Modula-2
- 61 Nanoquery
- 62 Nim
- 63 Objeck
- 64 OCaml
- 65 Oforth
- 66 PARI/GP
- 67 Pascal
- 68 Perl
- 69 Phix
- 70 PHP
- 71 Picat
- 72 PicoLisp
- 73 PL/I
- 74 PowerShell
- 75 Prolog
- 76 PureBasic
- 77 Python
- 78 Quackery
- 79 R
- 80 Racket
- 81 Raku
- 82 Red
- 83 REXX
- 84 Ring
- 85 Ruby
- 86 Rust
- 87 Scala
- 88 Seed7
- 89 Set lang
- 90 Sidef
- 91 Sinclair ZX81 BASIC
- 92 SQL
- 93 Standard ML
- 94 Stata
- 95 Swift
- 96 Tcl
- 97 True BASIC
- 98 uBasic/4tH
- 99 UNIX Shell
- 100 VBA
- 101 Vlang
- 102 Wren
- 103 XBasic
- 104 XLISP
- 105 XPL0
- 106 Yabasic
- 107 zkl
- 108 ZX Spectrum Basic

## 11l[edit]

V _suffix = [‘th’, ‘st’, ‘nd’, ‘rd’, ‘th’, ‘th’, ‘th’, ‘th’, ‘th’, ‘th’]

F nth(n)

R ‘#.'#.’.format(n, I n % 100 <= 10 | n % 100 > 20 {:_suffix[n % 10]} E ‘th’)

L(j) (0..1000).step(250)

print_elements(Array(j.+25).map(i -> nth(i)))

- Output:

0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 266'th 267'th 268'th 269'th 270'th 271'st 272'nd 273'rd 274'th 500'th 501'st 502'nd 503'rd 504'th 505'th 506'th 507'th 508'th 509'th 510'th 511'th 512'th 513'th 514'th 515'th 516'th 517'th 518'th 519'th 520'th 521'st 522'nd 523'rd 524'th 750'th 751'st 752'nd 753'rd 754'th 755'th 756'th 757'th 758'th 759'th 760'th 761'st 762'nd 763'rd 764'th 765'th 766'th 767'th 768'th 769'th 770'th 771'st 772'nd 773'rd 774'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th

## 8080 Assembly[edit]

org 100h

jmp demo

;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;

;; Given a 16-bit unsigned integer in HL, return a string

;; consisting of its ASCII representation plus an ordinal

;; suffix in HL.

nth: lxi b,-10 ; Divisor for digit loop

push h ; Push integer to stack

lxi h,nthsfx ; Pointer to end of digit area

xthl ; Swap digit pointer with integer

nthdigit: lxi d,-1 ; Get current digit - DE holds quotient

nthdiv10: inx d ; Increment quotient,

dad b ; subtract 10 from integer,

jc nthdiv10 ; Keep going until HL<0

mvi a,'0'+10 ; Calculate ASCII value for digit

add l ; Modulus is in (H)L

xthl ; Swap integer with pointer

dcx h ; Point to one digit further left

mov m,a ; Store the digit

xthl ; Swap pointer with integer

xchg ; Put quotient in HL

mov a,h ; Is it zero?

ora l

jnz nthdigit ; If not, go calculate next digit

mvi e,0 ; Default suffix is 'th'.

lxi h,nthnum+3 ; Look at tens digit

mov a,m

cpi '1' ; Is it '1'?

jz nthsetsfx ; Then it is always 'th'.

inx h ; Look at zeroes digit

mov a,m

sui '0' ; Subtract ASCII '0'

cpi 4 ; 4 or higher?

jnc nthsetsfx ; Then it is always 'th'.

rlc ; Otherwise, suffix is at N*2+nthord

mov e,a

nthsetsfx: mvi d,0 ; Look up suffix in list

lxi h,nthord

dad d ; Pointer to suffix in HL

lxi d,nthsfx ; Pointer to space for suffix in DE

mov a,m ; Get first letter of suffix

stax d ; Store it in output

inx h ; Increment both pointers

inx d

mov a,m ; Get second letter of suffix

stax d ; Store it in output

pop h ; Return pointer to leftmost digit

ret

nthord: db 'thstndrd' ; Ordinal suffixes

nthnum: db '*****' ; Room for digits

nthsfx: db '**$' ; Room for suffix

;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;

demo: ;; Demo code

lxi h,0 ; Starting at 0...

mvi b,26 ; ...print 26 numbers [0..25]

call printnums

lxi h,250 ; Starting at 250...

mvi b,16 ; ...print 16 numbers [250..265]

call printnums

lxi h,1000 ; Starting at 1000...

mvi b,26 ; ...print 26 numbers [1000..1025]

;; Print values from HL up to HL+B

printnums: push h ; Keep number

push b ; Keep counter

call nth ; Get string for current HL

xchg ; Put it in DE

mvi c,9 ; CP/M print string

call 5

mvi e,' ' ; Separate numbers with spaces

mvi c,2 ; CP/M print character

call 5

pop b ; Restore counter

pop h ; Restore number

inx h ; Increment number

dcr b ; Decrement counter

jnz printnums ; If not zero, print next number

ret

- Output:

Line breaks added for clarity.

0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## 8086 Assembly[edit]

bits 16

cpu 8086

segment .text

org 100h

jmp demo

;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;

;; Given a number in AX, return string with ordinal suffix

;; in DX.

nth: mov cx,10 ; Divisor

mov bx,.sfx ; Pointer to end of number

.digit: xor dx,dx ; Zero DX

div cx ; AX = DX:AX/10; DX=remainder

add dl,'0' ; Make digit

dec bx ; Back up the pointer

mov [bx],dl ; Store digit

and ax,ax ; Done yet? (AX=0?)

jnz .digit ; If not, get next digit

mov dx,bx ; Keep string pointer in DX

xor bx,bx ; Default suffix is 'th'.

cmp byte [.num+3],'1' ; Is the tens digit '1'?

je .setsfx ; Then the suffix is 'th'.

mov cl,[.num+4] ; Get the ones digit

cmp cl,'4' ; Is it '4' or higher?

jae .setsfx ; Then the suffix is 'th'.

mov bl,cl

sub bl,'0' ; Calculate offset.

shl bl,1 ; [0..3]*2 + .ord

.setsfx: mov ax,[bx+.ordsfx] ; Set suffix

mov [.sfx],ax

ret

.ordsfx: db 'thstndrd'

.num: db '*****'

.sfx: db '**$'

;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;

;; Print numbers.

demo: mov ax,0 ; Starting at 0...

mov bl,26 ; ...print 26 numbers [0..25]

call printn

mov ax,250 ; Starting at 250...

mov bl,16 ; ...print 16 numbers [250..265]

call printn

mov ax,1000 ; Starting at 1000...

mov bl,26 ; ...print 26 numbers [1000..1025]

;; Print BL numbers starting at AX

printn: push ax ; Keep number

push bx ; Keep counter

call nth ; Get string for current AX

mov ah,9 ; MS-DOS print string

int 21h

mov dl,' ' ; Separate numbers by spaces

mov ah,2 ; MS-DOS print character

int 21h

pop bx ; Restore counter

pop ax ; Restore number

inc ax ; Next number

dec bl ; Are we done yet?

jnz printn

ret

- Output:

Line breaks added for clarity.

0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## Action![edit]

PROC Nth(CARD val,CHAR ARRAY s)

CHAR ARRAY sfx

BYTE d

StrC(val,s)

s(0)=s(0)+1

s(s(0))=''

d=val MOD 100

IF d>10 AND d<14 THEN

sfx="th"

ELSE

d=val MOD 10

IF d=1 THEN sfx="st"

ELSEIF d=2 THEN sfx="nd"

ELSEIF d=3 THEN sfx="rd"

ELSE sfx="th"

FI

FI

s(0)=s(0)+2

SAssign(s,sfx,s(0)-1,s(0)+1)

RETURN

PROC Main()

CARD ARRAY n=[0 250 1000]

CHAR ARRAY s(10)

CARD i,j

FOR i=0 TO 2

DO

FOR j=n(i) TO n(i)+25

DO

Nth(j,s)

PrintF("%S ",s)

OD

PutE() PutE()

OD

RETURN

- Output:

Screenshot from Atari 8-bit computer

0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 25'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 266'th 267'th 268'th 269'th 270'th 271'st 272'nd 273'rd 274'th 275'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th 1025'th

## Ada[edit]

with Ada.Text_IO;

procedure Nth is

function Suffix(N: Natural) return String is

begin

if N mod 10 = 1 and then N mod 100 /= 11 then return "st";

elsif N mod 10 = 2 and then N mod 100 /= 12 then return "nd";

elsif N mod 10 = 3 and then N mod 100 /= 13 then return "rd";

else return "th";

end if;

end Suffix;

procedure Print_Images(From, To: Natural) is

begin

for I in From .. To loop

Ada.Text_IO.Put(Natural'Image(I) & Suffix(I));

end loop;

Ada.Text_IO.New_Line;

end Print_Images;

begin

Print_Images( 0, 25);

Print_Images( 250, 265);

Print_Images(1000, 1025);

end Nth;

- Output:

0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## ALGOL 68[edit]

# PROC to suffix a number with st, nd, rd or th as appropriate #

PROC nth = ( INT number )STRING:

BEGIN

INT number mod 100 = number MOD 100;

# RESULT #

whole( number, 0 )

+ IF number mod 100 >= 10 AND number mod 100 <= 20

THEN

# numbers in the range 10 .. 20 always have "th" #

"th"

ELSE

# not in the range 10 .. 20, suffix is st, nd, rd or th #

# depending on the final digit #

CASE number MOD 10

IN # 1 # "st"

, # 2 # "nd"

, # 3 # "rd"

OUT "th"

ESAC

FI

END; # nth #

# PROC to test nth, displays nth for all numbers in the range from .. to #

PROC test nth = ( INT from, INT to )VOID:

BEGIN

INT test count := 0;

FOR test value FROM from TO to

DO

STRING test result = nth( test value );

print( ( " "[ 1 : 8 - UPB test result ], nth( test value ) ) );

test count +:= 1;

IF test count MOD 8 = 0

THEN

print( ( newline ) )

FI

OD;

print( ( newline ) )

END; # test nth #

main: (

test nth( 0, 25 );

test nth( 250, 265 );

test nth( 1000, 1025 )

)

- Output:

## APL[edit]

nth←{

sfx←4 2⍴'stndrdth'

tens←(10<100|⍵)∧20>100|⍵

(⍕⍵),sfx[(4×tens)⌈(⍳3)⍳10|⍵;]

}

- Output:

2 13⍴ nth¨ 0,⍳25 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 2 7⍴ nth¨ 250+0,⍳15 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 2 13⍴ nth¨ 1000+0,⍳25 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## AppleScript[edit]

-- ORDINAL STRINGS -----------------------------------------------------------

-- ordinalString :: Int -> String

on ordinalString(n)

(n as string) & ordinalSuffix(n)

end ordinalString

-- ordinalSuffix :: Int -> String

on ordinalSuffix(n)

set modHundred to n mod 100

if (11 ≤ modHundred) and (13 ≥ modHundred) then

"th"

else

item ((n mod 10) + 1) of ¬

{"th", "st", "nd", "rd", "th", "th", "th", "th", "th", "th"}

end if

end ordinalSuffix

-- TEST ----------------------------------------------------------------------

on run

-- showOrdinals :: [Int] -> [String]

script showOrdinals

on |λ|(lstInt)

map(ordinalString, lstInt)

end |λ|

end script

map(showOrdinals, ¬

map(uncurry(enumFromTo), ¬

[[0, 25], [250, 265], [1000, 1025]]))

end run

-- GENERIC FUNCTIONS ---------------------------------------------------------

-- enumFromTo :: Int -> Int -> [Int]

on enumFromTo(m, n)

if m > n then

set d to -1

else

set d to 1

end if

set lst to {}

repeat with i from m to n by d

set end of lst to i

end repeat

return lst

end enumFromTo

-- map :: (a -> b) -> [a] -> [b]

on map(f, xs)

tell mReturn(f)

set lng to length of xs

set lst to {}

repeat with i from 1 to lng

set end of lst to |λ|(item i of xs, i, xs)

end repeat

return lst

end tell

end map

-- Lift 2nd class handler function into 1st class script wrapper

-- mReturn :: Handler -> Script

on mReturn(f)

if class of f is script then

f

else

script

property |λ| : f

end script

end if

end mReturn

-- uncurry :: Handler (a -> b -> c) -> Script |λ| ((a, b) -> c)

on uncurry(f)

script

on |λ|(xy)

set {x, y} to xy

mReturn(f)'s |λ|(x, y)

end |λ|

end script

end uncurry

- Output:

{{"0th", "1st", "2nd", "3rd", "4th", "5th", "6th", "7th", "8th", "9th", "10th", "11th", "12th", "13th", "14th", "15th", "16th", "17th", "18th", "19th", "20th", "21st", "22nd", "23rd", "24th", "25th"}, {"250th", "251st", "252nd", "253rd", "254th", "255th", "256th", "257th", "258th", "259th", "260th", "261st", "262nd", "263rd", "264th", "265th"}, {"1000th", "1001st", "1002nd", "1003rd", "1004th", "1005th", "1006th", "1007th", "1008th", "1009th", "1010th", "1011th", "1012th", "1013th", "1014th", "1015th", "1016th", "1017th", "1018th", "1019th", "1020th", "1021st", "1022nd", "1023rd", "1024th", "1025th"}}

## Applesoft BASIC[edit]

0 OP = 1

10 FOR N = 0 TO 25 : GOSUB 100 : NEXT

20 FOR N = 250 TO 265 : GOSUB 100 : NEXT

30 FOR N = 1000 TO 1025 : GOSUB 100 : NEXT

40 END

100 GOSUB 200"NTH

110 PRINT NTH$ " ";

120 RETURN

200 M1 = N - INT(N / 10) * 10

210 M2 = N - INT(N / 100) * 100

220 NTH$ = "TH"

230 IF M1 = 1 AND M2 <> 11 THEN NTH$ = "ST"

240 IF M1 = 2 AND M2 <> 12 THEN NTH$ = "ND"

250 IF M1 = 3 AND M2 <> 13 THEN NTH$ = "RD"

260 IF NOT OP THEN NTH$ = "'" + NTH$

270 NTH$ = STR$(N) + NTH$

280 RETURN

- Output:

0'TH 1'ST 2'ND 3'RD 4'TH 5'TH 6'TH 7'TH 8'TH 9'TH 10'TH 11'TH 12'TH 13'TH 14'TH 15'TH 16'TH 17'TH 18'TH 19'TH 20'TH 21'ST 22'ND 23'RD 24'TH 25'TH 250'TH 251'ST 252'ND 253'RD 254'TH 255'TH 256'TH 257'TH 258'TH 259'TH 260'TH 261'ST 262'ND 263'RD 264'TH 265'TH 1000'TH 1001'ST 1002'ND 1003'RD 1004'TH 1005'TH 1006'TH 1007'TH 1008'TH 1009'TH 1010'TH 1011'TH 1012'TH 1013'TH 1014'TH 1015'TH 1016'TH 1017'TH 1018'TH 1019'TH 1020'TH 1021'ST 1022'ND 1023'RD 1024'TH 1025'TH

## Arturo[edit]

suffixes: ["th" "st" "nd" "rd" "th" "th" "th" "th" "th" "th"]

nth: function [n][

if? or? 100 >= n%100

20 < n%100

-> (to :string n) ++ "'" ++ suffixes\[n%10]

else -> (to :string n) ++ "'th"

]

loop range.step:250 0 1000 'j [

loop j..j+24 'i ->

prints (nth i)++" "

print ""

]

- Output:

0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'st 12'nd 13'rd 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 266'th 267'th 268'th 269'th 270'th 271'st 272'nd 273'rd 274'th 500'th 501'st 502'nd 503'rd 504'th 505'th 506'th 507'th 508'th 509'th 510'th 511'st 512'nd 513'rd 514'th 515'th 516'th 517'th 518'th 519'th 520'th 521'st 522'nd 523'rd 524'th 750'th 751'st 752'nd 753'rd 754'th 755'th 756'th 757'th 758'th 759'th 760'th 761'st 762'nd 763'rd 764'th 765'th 766'th 767'th 768'th 769'th 770'th 771'st 772'nd 773'rd 774'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'st 1012'nd 1013'rd 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th

## AutoHotkey[edit]

for k, v in [[0, 25], [250, 265], [1000, 1025]] {

while v[1] <= v[2] {

Out .= Ordinal(v[1]) " "

v[1]++

}

Out .= "`n"

}

MsgBox, % Out

Ordinal(n) {

s2 := Mod(n, 100)

if (s2 > 10 && s2 < 14)

return n "th"

s1 := Mod(n, 10)

return n (s1 = 1 ? "st" : s1 = 2 ? "nd" : s1 = 3 ? "rd" : "th")

}

- Output:

## AWK[edit]

# syntax: GAWK -f NTH.AWK

BEGIN {

prn(0,25)

prn(250,265)

prn(1000,1025)

exit(0)

}

function prn(start,stop, i) {

printf("%d-%d: ",start,stop)

for (i=start; i<=stop; i++) {

printf("%d%s ",i,nth(i))

}

printf("\n")

}

function nth(yearday, nthday) {

if (yearday ~ /1[1-3]$/) { # 11th,12th,13th

nthday = "th"

}

else if (yearday ~ /1$/) { # 1st,21st,31st,etc.

nthday = "st"

}

else if (yearday ~ /2$/) { # 2nd,22nd,32nd,etc.

nthday = "nd"

}

else if (yearday ~ /3$/) { # 3rd,23rd,33rd,etc.

nthday = "rd"

}

else if (yearday ~ /[0456789]$/) { # 4th-10th,20th,24th-30th,etc.

nthday = "th"

}

return(nthday)

}

- Output:

0-25: 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250-265: 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000-1025: 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## Babel[edit]

((irregular ("st" "nd" "rd"))

(main

{(0 250 1000)

{ test ! "\n" << }

each})

(test {

<-

{iter 1 - -> dup <- + ordinalify ! <<

{iter 10 %} {" "} {"\n"} ifte << }

26 times})

(ordinalify {

<-

{{ -> dup <- 100 % 10 cugt } !

{ -> dup <- 100 % 14 cult } !

and not

{ -> dup <- 10 % 0 cugt } !

{ -> dup <- 10 % 4 cult } !

and

and}

{ -> dup

<- %d "'"

irregular -> 10 % 1 - ith

. . }

{ -> %d "'th" . }

ifte }))

- Output:

25'th 24'th 23'rd 22'nd 21'st 20'th 19'th 18'th 17'th 16'th 15'th 14'th 13'th 12'th 11'th 10'th 9'th 8'th 7'th 6'th 5'th 4'th 3'rd 2'nd 1'st 0'th 275'th 274'th 273'rd 272'nd 271'st 270'th 269'th 268'th 267'th 266'th 265'th 264'th 263'rd 262'nd 261'st 260'th 259'th 258'th 257'th 256'th 255'th 254'th 253'rd 252'nd 251'st 250'th 1025'th 1024'th 1023'rd 1022'nd 1021'st 1020'th 1019'th 1018'th 1017'th 1016'th 1015'th 1014'th 1013'th 1012'th 1011'th 1010'th 1009'th 1008'th 1007'th 1006'th 1005'th 1004'th 1003'rd 1002'nd 1001'st 1000'th

## BaCon[edit]

' Nth (sans apostrophes)

FUNCTION nth$(NUMBER n) TYPE STRING

LOCAL suffix

IF n < 0 THEN RETURN STR$(n)

IF MOD(n, 100) >= 11 AND MOD(n, 100) <= 13 THEN

suffix = "th"

ELSE

suffix = MID$("thstndrdthththththth", MOD(n, 10) * 2 + 1, 2)

ENDIF

RETURN CONCAT$(STR$(n), suffix)

END FUNCTION

' Test a few ranges

FOR i = 1 TO 4

READ first, last

per = 1

FOR n = first TO last

PRINT nth$(n) FORMAT "%s "

' limit to 10 entries per line

IF per = 10 OR n = last THEN

per = 1

ELSE

INCR per

ENDIF

NEXT

NEXT

DATA 0, 25, 250, 265, 1000, 1025, -20, -11

- Output:

prompt$ ./nth 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th -20 -19 -18 -17 -16 -15 -14 -13 -12 -11

## BASIC[edit]

### BASIC256[edit]

function ordinal(n)

ns$ = string(n)

begin case

case right(ns$, 1) = "1"

if right(ns$, 2) = "11" then return ns$ + "th"

return ns$ + "st"

case right(ns$, 1) = "2"

if right(ns$, 2) = "12" then return ns$ + "th"

return ns$ + "nd"

case right(ns$, 1) = "3"

if right(ns$, 2) = "13" then return ns$ + "th"

return ns$ + "rd"

else

return ns$ + "th"

end case

end function

subroutine imprimeOrdinal(a, b)

for i = a to b

print ordinal(i); " ";

next i

end subroutine

call imprimeOrdinal (0, 25)

call imprimeOrdinal (250, 265)

call imprimeOrdinal (1000, 1025)

end

### Commodore BASIC[edit]

0 REM ROSETTACODE.ORG

1 REM N'TH

2 REM WRITE A FUNCTION/METHOD/SUBROUTINE/... THAT WHEN GIVEN AN INTEGER GREATER

3 REM THAN OR EQUAL TO ZERO RETURNS A STRING OF THE NUMBER FOLLOWED BY

4 REM AN APOSTROPHE THEN THE ORDINAL SUFFIX.

5 REM BASED ON APPLESOFT BASIC VERSION @ ROSETTACODE.ORG

6 REM

7 REM *************************

8 PRINT CHR$(14): REM CHANGE TO LOWER/UPPER CASE CHAR SET

9 OP = 1

10 FOR N = 0 TO 25 : GOSUB 100 : NEXT : PRINT

20 FOR N = 250 TO 265 : GOSUB 100 : NEXT : PRINT

30 FOR N = 1000 TO 1025 : GOSUB 100 : NEXT : PRINT

40 END

50 REM *************************

100 GOSUB 200

110 PRINT NTH$ " ";

120 RETURN

130 REM ************************

200 M1 = N - INT(N / 10) * 10

210 M2 = N - INT(N / 100) * 100

220 NTH$ = "TH"

230 IF M1 = 1 AND M2 <> 11 THEN NTH$ = "ST"

240 IF M1 = 2 AND M2 <> 12 THEN NTH$ = "ND"

250 IF M1 = 3 AND M2 <> 13 THEN NTH$ = "RD"

260 IF NOT OP THEN NTH$ = "'" + NTH$

270 NTH$ = STR$(N) + NTH$

280 RETURN

- Output:

Commodore 64 (40 column text)

0'th 1'st 2'nd 3'rd 4'th 5'th 6't h 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18' th 19'th 20'th 21'st 22'nd 23'rd 2 4'th 25'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 1000'th 1001'st 1002'nd 1003'rd 100 4'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 10 13'th 1014'th 1015'th 1016'th 1017't h 1018'th 1019'th 1020'th 1021'st 1 022'nd 1023'rd 1024'th 1025'th

### Nascom BASIC[edit]

10 REM N'th

20 LOLIM=0

30 HILIM=25

40 GOSUB 1000

50 LOLIM=250

60 HILIM=265

70 GOSUB 1000

80 LOLIM=1000

90 HILIM=1025

100 GOSUB 1000

110 END

995 REM ** Print images

1000 FOR I=LOLIM TO HILIM

1010 NR=I

1020 GOSUB 1500

1030 SI$=STR$(I)

1040 PRINT RIGHT$(SI$,LEN(SI$)-1);SUF$;" ";

1050 NEXT I

1060 PRINT

1070 RETURN

1495 REM ** Get suffix

1500 LA=NR-INT(NR/10)*10:NLA=NR-INT(NR/100)*100

1510 IF LA=1 AND NLA<>11 THEN SUF$="st":RETURN

1520 IF LA=2 AND NLA<>12 THEN SUF$="nd":RETURN

1530 IF LA=3 AND NLA<>13 THEN SUF$="rd":RETURN

1540 SUF$="th"

1550 RETURN

- Output:

### QBasic[edit]

DECLARE FUNCTION sufijo$ (n%)

DECLARE SUB imprimeOrdinal (loLim%, hiLim%)

imprimeOrdinal 0, 25

imprimeOrdinal 250, 265

imprimeOrdinal 1000, 1025

END

DEFINT A-Z

SUB imprimeOrdinal (loLim, hiLim)

loLim = INT(loLim)

hiLim = INT(hiLim)

FOR i = loLim TO hiLim

PRINT STR$(i) + sufijo$(i) + " ";

NEXT i

END SUB

FUNCTION sufijo$ (n)

n = INT(n)

NMod10 = n MOD 10

NMod100 = n MOD 100

IF (NMod10 = 1) AND (NMod100 <> 11) THEN

sufijo$ = "st"

ELSE

IF (NMod10 = 2) AND (NMod100 <> 12) THEN

sufijo$ = "nd"

ELSE

IF (NMod10 = 3) AND (NMod100 <> 13) THEN

sufijo$ = "rd"

ELSE

sufijo$ = "th"

END IF

END IF

END IF

END FUNCTION

## Batch File[edit]

@echo off

::Main thing...

call :Nth 0 25

call :Nth 250 265

call :Nth 1000 1025

pause

exit /b

::The subroutine

:Nth <lbound> <ubound>

setlocal enabledelayedexpansion

for /l %%n in (%~1,1,%~2) do (

set curr_num=%%n

set "out=%%nth"

if !curr_num:~-1!==1 (set "out=%%nst")

if !curr_num:~-1!==2 (set "out=%%nnd")

if !curr_num:~-1!==3 (set "out=%%nrd")

set "range_output=!range_output! !out!"

)

echo."!range_output:~1!"

goto :EOF

- Output:

"0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11st 12nd 13rd 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th" "250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th" "1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011st 1012nd 1013rd 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th" Press any key to continue . . .

## BBC BASIC[edit]

PROCNth( 0, 25)

PROCNth( 250, 265)

PROCNth(1000,1025)

END

DEF PROCNth(s%,e%)

LOCAL i%,suff$

FOR i%=s% TO e%

suff$="th"

IF i% MOD 10 = 1 AND i% MOD 100 <> 11 suff$="st"

IF i% MOD 10 = 2 AND i% MOD 100 <> 12 suff$="nd"

IF i% MOD 10 = 3 AND i% MOD 100 <> 13 suff$="rd"

PRINT STR$i%+suff$+" ";

NEXT

ENDPROC

- Output:

## BCPL[edit]

get "libhdr"

// Generate ASCII string of number n with ordinal suffix

// The string is stored at v.

let nth(n, v) = valof

$( let sfx = "thstndrd"

let c, s = 0, ?

// Generate digits

$( c := c + 1

v%c := n rem 10 + '0'

n := n / 10

$) repeatuntil n = 0

// Put digits in correct order

for i = 1 to c/2 do

$( let d = v%i

v%i := v%(c+1-i)

v%(c+1-i) := d

$)

// The length of the string is the amount of digits + 2

v%0 := c+2;

// Figure out the proper suffix from the last two digits

test v%(c-1)='1' | v%c>'3'

then s := 0

else s := 2*(v%c - '0')

v%(c+1) := sfx%(s+1)

v%(c+2) := sfx%(s+2)

resultis v

$)

let start() be

$( let buf = vec 10

for i = 0 to 25 do writef("%S*N", nth(i, buf))

for i = 250 to 265 do writef("%S*N", nth(i, buf))

for i = 1000 to 1025 do writef("%S*N", nth(i, buf))

$)

- Output:

## Befunge[edit]

The bottom section of code contains the "subroutine" that calculates the ordinal of a given number; the top section generates the list of values to test.

0>55*:>1-\:0\`!v

#v$#$<^:\+*8"}"_

>35*:>1-\:0\`!v

#v$#$<^:\+*2"}"_

5< v$_v#!::-<0*5

@v <,*>#81#4^# _

>>:0\>:55+%68*v:

tsnr |:/+ 55\+<,

htdd >$>:#,_$:vg

v"d"\*!`3:%+55<9

>%55+/1-!!*:8g,^

- Output:

## BQN[edit]

Nth ← {

sfx ← ⟨"th","st","nd","rd"⟩

(•Fmt 𝕩)∾sfx⊑˜ (1≠10|⌊𝕩÷10)×(3≥10|𝕩)×10|𝕩

}

∘‿4⥊ Nth¨ (↕26) ∾ (250+↕16) ∾ (1000+↕26)

- Output:

┌─ ╵ "0th" "1st" "2nd" "3rd" "4th" "5th" "6th" "7th" "8th" "9th" "10th" "11th" "12th" "13th" "14th" "15th" "16th" "17th" "18th" "19th" "20th" "21st" "22nd" "23rd" "24th" "25th" "250th" "251st" "252nd" "253rd" "254th" "255th" "256th" "257th" "258th" "259th" "260th" "261st" "262nd" "263rd" "264th" "265th" "1000th" "1001st" "1002nd" "1003rd" "1004th" "1005th" "1006th" "1007th" "1008th" "1009th" "1010th" "1011th" "1012th" "1013th" "1014th" "1015th" "1016th" "1017th" "1018th" "1019th" "1020th" "1021st" "1022nd" "1023rd" "1024th" "1025th" ┘

## C[edit]

#include <stdio.h>

char* addSuffix(int num, char* buf, size_t len)

{

char *suffixes[4] = { "th", "st", "nd", "rd" };

int i;

switch (num % 10)

{

case 1 : i = (num % 100 == 11) ? 0 : 1;

break;

case 2 : i = (num % 100 == 12) ? 0 : 2;

break;

case 3 : i = (num % 100 == 13) ? 0 : 3;

break;

default: i = 0;

};

snprintf(buf, len, "%d%s", num, suffixes[i]);

return buf;

}

int main(void)

{

int i;

printf("Set [0,25]:\n");

for (i = 0; i < 26; i++)

{

char s[5];

printf("%s ", addSuffix(i, s, 5));

}

putchar('\n');

printf("Set [250,265]:\n");

for (i = 250; i < 266; i++)

{

char s[6];

printf("%s ", addSuffix(i, s, 6));

}

putchar('\n');

printf("Set [1000,1025]:\n");

for (i = 1000; i < 1026; i++)

{

char s[7];

printf("%s ", addSuffix(i, s, 7));

}

putchar('\n');

return 0;

}

Another method with dynamic memory allocation

#include <stdlib.h>

#include <stdio.h>

static int digits(const int x) {

if (x / 10 == 0) return 1;

return 1 + digits(x / 10);

}

static char * get_ordinal(const int i) {

const int string_size = digits(i) + 3;

char * o_number = malloc(string_size);

char * ordinal;

if(i % 100 >= 11 && i % 100 <= 13) ordinal = "th";

else ordinal = i/10==1?"th":i%10==1?"st":i%10==2?"nd":i%10==3?"rd":"th";

sprintf_s(o_number, string_size, "%d%s", i, ordinal);

return o_number;

}

static void print_range(const int begin, const int end) {

printf("Set [%d,%d]:\n", begin, end);

for (int i = begin; i <= end; i++) {

char * o_number = get_ordinal(i);

printf("%s ", o_number);

free(o_number);

}

printf("\n");

}

int main(void) {

print_range(0, 25);

print_range(250, 265);

print_range(1000, 1025);

}

- Output:

Set [0,25] : 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th Set [250,265] : 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th Set [1000,1025] : 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## C#[edit]

using System;

using System.Linq;

class Program

{

private static string Ordinalize(int i)

{

i = Math.Abs(i);

if (new[] {11, 12, 13}.Contains(i%100))

return i + "th";

switch (i%10)

{

case 1:

return i + "st";

case 2:

return i + "nd";

case 3:

return i + "rd";

default:

return i + "th";

}

}

static void Main()

{

Console.WriteLine(string.Join(" ", Enumerable.Range(0, 26).Select(Ordinalize)));

Console.WriteLine(string.Join(" ", Enumerable.Range(250, 16).Select(Ordinalize)));

Console.WriteLine(string.Join(" ", Enumerable.Range(1000, 26).Select(Ordinalize)));

}

}

Dotnet 5 version without LINQ

using System;

static string Ordinalize(int i)

{

return i + (

i % 100 is >= 11 and <= 13 ? "th" :

i % 10 == 1 ? "st" :

i % 10 == 2 ? "nd" :

i % 10 == 3 ? "rd" :

"th");

}

static void PrintRange(int begin, int end)

{

for(var i = begin; i <= end; i++)

Console.Write(Ordinalize(i) + (i == end ? "" : " "));

Console.WriteLine();

}

PrintRange(0, 25);

PrintRange(250, 265);

PrintRange(1000, 1025);

- Output:

## C++[edit]

#include <string>

#include <iostream>

using namespace std;

string Suffix(int num)

{

switch (num % 10)

{

case 1 : if(num % 100 != 11) return "st";

break;

case 2 : if(num % 100 != 12) return "nd";

break;

case 3 : if(num % 100 != 13) return "rd";

}

return "th";

}

int main()

{

cout << "Set [0,25]:" << endl;

for (int i = 0; i < 26; i++)

cout << i << Suffix(i) << " ";

cout << endl;

cout << "Set [250,265]:" << endl;

for (int i = 250; i < 266; i++)

cout << i << Suffix(i) << " ";

cout << endl;

cout << "Set [1000,1025]:" << endl;

for (int i = 1000; i < 1026; i++)

cout << i << Suffix(i) << " ";

cout << endl;

return 0;

}

- Output:

Set [0,25] : 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th Set [250,265] : 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th Set [1000,1025] : 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## Clojure[edit]

(defn n-th [n]

(str n

(let [rem (mod n 100)]

(if (and (>= rem 11) (<= rem 13))

"th"

(condp = (mod n 10)

1 "st"

2 "nd"

3 "rd"

"th")))))

(apply str (interpose " " (map n-th (range 0 26))))

(apply str (interpose " " (map n-th (range 250 266))))

(apply str (interpose " " (map n-th (range 1000 1026))))

- Output:

"0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th" "250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th" "1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th"

Alternatively, if you want to print the full ordinal English, it becomes trivial with pprint:

(apply str (interpose " " (map #(clojure.pprint/cl-format nil "~:R" %) (range 0 26))))

- Output:

"zeroth first second third fourth fifth sixth seventh eighth ninth tenth eleventh twelfth thirteenth fourteenth fifteenth sixteenth seventeenth eighteenth nineteenth twentieth twenty-first twenty-second twenty-third twenty-fourth twenty-fifth"

## CLU[edit]

nth = proc (n: int) returns (string)

num: string := int$unparse(n)

sfx: array[string] := array[string]$[0: "th", "st", "nd", "rd"]

if n / 10 // 10 = 1 cor n // 10 > 3 then

return(num || sfx[0])

else

return(num || sfx[n // 10])

end

end nth

do_range = proc (from, to: int)

po: stream := stream$primary_output()

col: int := 0

for i: int in int$from_to(from,to) do

stream$putleft(po, nth(i), 7)

col := col + 1

if col = 10 then

stream$putc(po, '\n')

col := 0

end

end

stream$putl(po, "\n")

end do_range

start_up = proc ()

do_range(0,25)

do_range(250,265)

do_range(1000,1025)

end start_up

- Output:

## COBOL[edit]

COBOL stores numbers in decimal form, so there is no need to use a modulo function: the last digit or the last two digits can be extracted directly.

IDENTIFICATION DIVISION.

PROGRAM-ID. NTH-PROGRAM.

DATA DIVISION.

WORKING-STORAGE SECTION.

01 WS-NUMBER.

05 N PIC 9(8).

05 LAST-TWO-DIGITS PIC 99.

05 LAST-DIGIT PIC 9.

05 N-TO-OUTPUT PIC Z(7)9.

05 SUFFIX PIC AA.

PROCEDURE DIVISION.

TEST-PARAGRAPH.

PERFORM NTH-PARAGRAPH VARYING N FROM 0 BY 1 UNTIL N IS GREATER THAN 25.

PERFORM NTH-PARAGRAPH VARYING N FROM 250 BY 1 UNTIL N IS GREATER THAN 265.

PERFORM NTH-PARAGRAPH VARYING N FROM 1000 BY 1 UNTIL N IS GREATER THAN 1025.

STOP RUN.

NTH-PARAGRAPH.

MOVE 'TH' TO SUFFIX.

MOVE N (7:2) TO LAST-TWO-DIGITS.

IF LAST-TWO-DIGITS IS LESS THAN 4,

OR LAST-TWO-DIGITS IS GREATER THAN 20,

THEN PERFORM DECISION-PARAGRAPH.

MOVE N TO N-TO-OUTPUT.

DISPLAY N-TO-OUTPUT WITH NO ADVANCING.

DISPLAY SUFFIX WITH NO ADVANCING.

DISPLAY SPACE WITH NO ADVANCING.

DECISION-PARAGRAPH.

MOVE N (8:1) TO LAST-DIGIT.

IF LAST-DIGIT IS EQUAL TO 1 THEN MOVE 'ST' TO SUFFIX.

IF LAST-DIGIT IS EQUAL TO 2 THEN MOVE 'ND' TO SUFFIX.

IF LAST-DIGIT IS EQUAL TO 3 THEN MOVE 'RD' TO SUFFIX.

Output:

0TH 1ST 2ND 3RD 4TH 5TH 6TH 7TH 8TH 9TH 10TH 11TH 12TH 13TH 14TH 15TH 16TH 17TH 18TH 19TH 20TH 21ST 22ND 23RD 24TH 25TH 250TH 251ST 252ND 253RD 254TH 255TH 256TH 257TH 258TH 259TH 260TH 261ST 262ND 263RD 264TH 265TH 1000TH 1001ST 1002ND 1003RD 1004TH 1005TH 1006TH 1007TH 1008TH 1009TH 1010TH 1011TH 1012TH 1013TH 1014TH 1015TH 1016TH 1017TH 1018TH 1019TH 1020TH 1021ST 1022ND 1023RD 1024TH 1025TH

## Common Lisp[edit]

(defun add-suffix (number)

(let* ((suffixes #10("th" "st" "nd" "rd" "th"))

(last2 (mod number 100))

(last-digit (mod number 10))

(suffix (if (< 10 last2 20)

"th"

(svref suffixes last-digit))))

(format nil "~a~a" number suffix)))

A more concise, albeit less readable version:

(defun add-suffix (n)

(format nil "~d'~:[~[th~;st~;nd~;rd~:;th~]~;th~]" n (< (mod (- n 10) 100) 10) (mod n 10)))

Display the results:

(loop for (low high) in '((0 25) (250 265) (1000 1025))

do (progn

(format t "~a to ~a: " low high)

(loop for n from low to high

do (format t "~a " (add-suffix n))

finally (terpri))))

- Output:

0 to 25: 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250 to 265: 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000 to 1025: 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## Cowgol[edit]

include "cowgol.coh";

include "strings.coh";

# Given an int32, return decimal string and add an ordinal suffix

sub ordsfx(n: int32, buf: [uint8]): (out: [uint8]) is

var sfx: [uint8][] := {"th", "st", "nd", "rd"};

out := buf;

buf := IToA(n, 10, buf); # IToA is included in standard library

# Since we now already have the digits, we can make the decision

# without doing any more work.

if (n > 10 and [@prev @prev buf] == '1')

or ([@prev buf] > '3') then

CopyString(sfx[0], buf);

else

CopyString(sfx[[@prev buf]-'0'], buf);

end if;

end sub;

# Print suffixed numerals from start to end inclusive

sub test(start: int32, end_: int32) is

var buf: uint8[16]; # buffer

var n: uint8 := 10;

while start <= end_ loop

print(ordsfx(start, &buf[0]));

print_char(' ');

start := start + 1;

n := n - 1;

if n == 0 then

print_nl();

n := 10;

end if;

end loop;

print_nl();

end sub;

test(0, 25);

test(250,265);

test(1000,1025);

- Output:

## Crystal[edit]

struct Int

def ordinalize

num = self.abs

ordinal = if (11..13).includes?(num % 100)

"th"

else

case num % 10

when 1; "st"

when 2; "nd"

when 3; "rd"

else "th"

end

end

"#{self}#{ordinal}"

end

end

[(0..25),(250..265),(1000..1025)].each{|r| puts r.map{ |n| n.ordinalize }.join(", "); puts}

- Output:

0th, 1st, 2nd, 3rd, 4th, 5th, 6th, 7th, 8th, 9th, 10th, 11th, 12th, 13th, 14th, 15th, 16th, 17th, 18th, 19th, 20th, 21st, 22nd, 23rd, 24th, 25th 250th, 251st, 252nd, 253rd, 254th, 255th, 256th, 257th, 258th, 259th, 260th, 261st, 262nd, 263rd, 264th, 265th 1000th, 1001st, 1002nd, 1003rd, 1004th, 1005th, 1006th, 1007th, 1008th, 1009th, 1010th, 1011th, 1012th, 1013th, 1014th, 1015th, 1016th, 1017th, 1018th, 1019th, 1020th, 1021st, 1022nd, 1023rd, 1024th, 1025th

## D[edit]

import std.stdio, std.string, std.range, std.algorithm;

string nth(in uint n) pure {

static immutable suffix = "th st nd rd th th th th th th".split;

return "%d'%s".format(n, (n % 100 <= 10 || n % 100 > 20) ?

suffix[n % 10] : "th");

}

void main() {

foreach (r; [iota(26), iota(250, 266), iota(1000, 1026)])

writefln("%-(%s %)", r.map!nth);

}

- Output:

0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 25'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th 1025'th

## Delphi[edit]

See Pascal.

## Draco[edit]

proc nonrec nth(word n; *char buf) *char:

channel output text ch;

open(ch, buf);

write(ch; n,

if (n/10)%10=1 then "th"

elif n%10=1 then "st"

elif n%10=2 then "nd"

elif n%10=3 then "rd"

else "th"

fi

);

close(ch);

buf

corp;

proc nonrec print_range(word start, stop) void:

[8] char buf;

word col, n;

col := 0;

for n from start upto stop do

write(nth(n, &buf[0]));

col := col + 1;

if col%10=0 then writeln() else write('\t') fi

od;

writeln()

corp

proc nonrec main() void:

print_range(0, 25);

print_range(250, 265);

print_range(1000, 1025)

corp

- Output:

## Elena[edit]

ELENA 5.0 :

import extensions;

import system'math;

import system'routines;

extension op

{

ordinalize()

{

int i := self.Absolute;

if (new int[]{11,12,13}.ifExists(i.mod:100))

{

^ i.toPrintable() + "th"

};

(i.mod(10)) =>

1 { ^ i.toPrintable() + "st" }

2 { ^ i.toPrintable() + "nd" }

3 { ^ i.toPrintable() + "rd" };

^ i.toPrintable() + "th"

}

}

public program()

{

console.printLine(new Range(0,26).selectBy(mssgconst ordinalize<op>[1]));

console.printLine(new Range(250,26).selectBy(mssgconst ordinalize<op>[1]));

console.printLine(new Range(1000,26).selectBy(mssgconst ordinalize<op>[1]))

}

- Output:

0th,1st,2nd,3rd,4th,5th,6th,7th,8th,9th,10th,11th,12th,13th,14th,15th,16th,17th,18th,19th,20th,21st,22nd,23rd,24th,25th 250th,251st,252nd,253rd,254th,255th,256th,257th,258th,259th,260th,261st,262nd,263rd,264th,265th,266th,267th,268th,269th,270th,271st,272nd,273rd,274th,275th 1000th,1001st,1002nd,1003rd,1004th,1005th,1006th,1007th,1008th,1009th,1010th,1011th,1012th,1013th,1014th,1015th,1016th,1017th,1018th,1019th,1020th,1021st,1022nd,1023rd,1024th,1025th

## Elixir[edit]

defmodule RC do

def ordinalize(n) do

num = abs(n)

ordinal = if rem(num, 100) in 4..20 do

"th"

else

case rem(num, 10) do

1 -> "st"

2 -> "nd"

3 -> "rd"

_ -> "th"

end

end

"#{n}#{ordinal}"

end

end

Enum.each([0..25, 250..265, 1000..1025], fn range ->

Enum.map(range, fn n -> RC.ordinalize(n) end) |> Enum.join(" ") |> IO.puts

end)

- Output:

## ERRE[edit]

PROGRAM NTH_SOLVE

!

! for rosettacode.org

!

PROCEDURE NTH(S%,E%)

LOCAL I%,SUFF$

FOR I%=S% TO E% DO

SUFF$="th"

IF I% MOD 10=1 AND I% MOD 100<>11 THEN SUFF$="st" END IF

IF I% MOD 10=2 AND I% MOD 100<>12 THEN SUFF$="nd" END IF

IF I% MOD 10=3 AND I% MOD 100<>13 THEN SUFF$="rd" END IF

PRINT(STR$(I%)+SUFF$+" ";)

END FOR

END PROCEDURE

BEGIN

NTH(0,25)

NTH(250,265)

NTH(1000,1025)

END PROGRAM

- Output:

## F#[edit]

open System

let ordinalsuffix n =

let suffixstrings = [|"th"; "st"; "nd"; "rd"|]

let (d, r) = Math.DivRem(n, 10)

n.ToString() + suffixstrings.[ if r < 4 && (d &&& 1) = 0 then r else 0 ]

[<EntryPoint>]

let main argv =

let show = (Seq.iter (ordinalsuffix >> (printf " %s"))) >> (Console.WriteLine)

[0..25] |> show

[250..265] |> show

[1000..1025] |> show

0

- Output:

0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251th 252th 253th 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## Factor[edit]

USING: io kernel math math.order math.parser math.ranges qw

sequences ;

IN: rosetta-code.nth

: n'th ( n -- str )

dup 10 /mod swap 1 = [ drop 0 ] when

[ number>string ]

[ 4 min qw{ th st nd rd th } nth ] bi* append ;

: n'th-demo ( -- )

0 25 250 265 1000 1025 [ [a,b] ] [email protected]

[ [ n'th write bl ] each nl ] [email protected] ;

MAIN: n'th-demo

- Output:

## Forth[edit]

: 'nth ( -- c-addr ) s" th st nd rd th th th th th th " drop ;

: .nth ( n -- )

dup 10 20 within if 0 .r ." th " exit then

dup 0 .r 10 mod 3 * 'nth + 3 type ;

: test ( n n -- ) cr do i 5 mod 0= if cr then i .nth loop ;

: tests ( -- )

26 0 test 266 250 test 1026 1000 test ;

tests

- Output:

0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011st 1012nd 1013rd 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1024th ok

## Fortran[edit]

THE INSTRUCTIONS! Write a function/method/subroutine/... that when given an integer greater than or equal to zero returns a string of the number followed by an apostrophe then the ordinal suffix. Example returns would include 1'st 2'nd 3'rd 11'th 111'th 1001'st 1012'th

Please find the compilation instructions and examples in comments at the start of the source.

!-*- mode: compilation; default-directory: "/tmp/" -*-

!Compilation started at Fri Jun 6 15:40:18

!

!a=./f && make -k $a && echo 0 25 | $a && echo 250 265 | $a && echo 1000 1025 | $a

!gfortran -std=f2008 -Wall -fopenmp -ffree-form -fall-intrinsics -fimplicit-none -g f.f08 -o f

! 0'th 1'st 2'nd

! 3'rd 4'th 5'th

! 6'th 7'th 8'th

! 9'th 10'th 11'th

! 12'th 13'th 14'th

! 15'th 16'th 17'th

! 18'th 19'th 20'th

! 21'st 22'nd 23'rd

! 24'th 25'th

! 250'th 251'st

! 252'nd 253'rd 254'th

! 255'th 256'th 257'th

! 258'th 259'th 260'th

! 261'st 262'nd 263'rd

! 264'th 265'th

! 1000th 1001st

! 1002nd 1003rd 1004th

! 1005th 1006th 1007th

! 1008th 1009th 1010th

! 1011th 1012th 1013th

! 1014th 1015th 1016th

! 1017th 1018th 1019th

! 1020th 1021st 1022nd

! 1023rd 1024th 1025th

!

!Compilation finished at Fri Jun 6 15:40:18

program nth

implicit none

logical :: need

integer :: here, there, n, i, iostat

read(5,*,iostat=iostat) here, there

if (iostat .ne. 0) then

write(6,*)'such bad input never before seen.'

write(6,*)'I AYE EYE QUIT!'

call exit(1)

end if

need = .false.

n = abs(there - here) + 1

i = 0

do while (0 /= mod(3+mod(here-i, 3), 3))

write(6,'(a22)',advance='no') ''

i = i+1

end do

do i = here, there, sign(1, there-here)

write(6,'(a22)',advance='no') ordinate(i)

if (2 /= mod(i,3)) then

need = .true.

else

write(6,'(a)')''

need = .false.

end if

end do

if (need) write(6,'(a)')''

contains

character(len=22) function ordinate(n)

character(len=19) :: a

character(len=20), parameter :: &

&a09 = "thstndrdthththththth",&

&ateen = "thththththththththth"

integer :: ones, tens, ones_index

integer, intent(in) :: n

write(a,'(i19)') n

ones = mod(n,10)

tens = mod(n,100)

ones_index = ones*2+1

if (n < 1000) then

if ((10 .le. tens) .and. (tens .lt. 20)) then

ordinate = a // "'" // ateen(ones_index:ones_index+1)

! ^^^^^^ remove these characters to remove the important '

else

ordinate = a // "'" // a09(ones_index:ones_index+1)

! ^^^^^^ remove these characters to remove the important '

end if

else

if ((10 .le. tens) .and. (tens .lt. 20)) then

ordinate = a // ateen(ones_index:ones_index+1)

else

ordinate = a // a09(ones_index:ones_index+1)

end if

end if

end function ordinate

end program nth

## FreeBASIC[edit]

' FB 1.05.0 Win64

' Apostrophes NOT used as incorrect English

Function ordinal(n As UInteger) As String

Dim ns As String = Str(n)

Select Case Right(ns, 1)

Case "0", "4" To "9"

Return ns + "th"

Case "1"

If Right(ns, 2) = "11" Then Return ns + "th"

Return ns + "st"

Case "2"

If Right(ns, 2) = "12" Then Return ns + "th"

Return ns + "nd"

Case "3"

If Right(ns, 2) = "13" Then Return ns + "th"

Return ns + "rd"

End Select

End Function

Dim i As Integer

For i = 0 To 25

Print ordinal(i); " ";

Next

Print : Print

For i = 250 To 265

Print ordinal(i); " ";

Next

Print : Print

For i = 1000 To 1025

Print ordinal(i); " ";

Next

Print : Print

Print "Press any key to quit"

Sleep

- Output:

## Gambas[edit]

**Click this link to run this code**

Public Sub Main()

Dim siNums As Short[] = [0, 25, 250, 265, 1000, 1025]

Dim siCount, siNumbers As Short

Dim sOrdinal As String

For siNumbers = 0 To 4 Step 2

For siCount = siNums[siNumbers] To siNums[siNumbers + 1]

sOrdinal = "th"

If Right(Str(siCount), 1) = "1" And Right(Str(siCount), 2) <> "11" Then sOrdinal = "st"

If Right(Str(siCount), 1) = "2" And Right(Str(siCount), 2) <> "12" Then sOrdinal = "nd"

If Right(Str(siCount), 1) = "3" And Right(Str(siCount), 2) <> "13" Then sOrdinal = "rd"

Print siCount & sOrdinal;;

Next

Print gb.NewLine

Next

End

Output:

## Go[edit]

package main

import "fmt"

func ord(n int) string {

s := "th"

switch c := n % 10; c {

case 1, 2, 3:

if n%100/10 == 1 {

break

}

switch c {

case 1:

s = "st"

case 2:

s = "nd"

case 3:

s = "rd"

}

}

return fmt.Sprintf("%d%s", n, s)

}

func main() {

for n := 0; n <= 25; n++ {

fmt.Printf("%s ", ord(n))

}

fmt.Println()

for n := 250; n <= 265; n++ {

fmt.Printf("%s ", ord(n))

}

fmt.Println()

for n := 1000; n <= 1025; n++ {

fmt.Printf("%s ", ord(n))

}

fmt.Println()

}

- Output:

## GW-BASIC[edit]

10 ' N'th

20 LET LOLIM% = 0

30 LET HILIM% = 25

40 GOSUB 1000

50 LET LOLIM% = 250

60 LET HILIM% = 265

70 GOSUB 1000

80 LET LOLIM% = 1000

90 LET HILIM% = 1025

100 GOSUB 1000

110 END

995 ' Print images

1000 FOR I% = LOLIM% TO HILIM%

1010 LET NR% = I%

1020 GOSUB 1500

1030 LET SI$ = STR$(I%)

1040 PRINT RIGHT$(SI$, LEN(SI$) - 1); SUF$; " ";

1050 NEXT I%

1060 PRINT

1070 RETURN

1495 ' Get suffix

1500 IF (NR% MOD 10 = 1) AND (NR% MOD 100 <> 11) THEN LET SUF$ = "st": GOTO 2000

1600 IF (NR% MOD 10 = 2) AND (NR% MOD 100 <> 12) THEN LET SUF$ = "nd": GOTO 2000

1700 IF (NR% MOD 10 = 3) AND (NR% MOD 100 <> 13) THEN LET SUF$ = "rd": GOTO 2000

1800 LET SUF$ = "th"

2000 RETURN

- Output:

## Haskell[edit]

import Data.Array

ordSuffs :: Array Integer String

ordSuffs = listArray (0,9) ["th", "st", "nd", "rd", "th",

"th", "th", "th", "th", "th"]

ordSuff :: Integer -> String

ordSuff n = show n ++ suff n

where suff m | (m `rem` 100) >= 11 && (m `rem` 100) <= 13 = "th"

| otherwise = ordSuffs ! (m `rem` 10)

printOrdSuffs :: [Integer] -> IO ()

printOrdSuffs = putStrLn . unwords . map ordSuff

main :: IO ()

main = do

printOrdSuffs [ 0.. 25]

printOrdSuffs [ 250.. 265]

printOrdSuffs [1000..1025]

- Output:

## Icon and Unicon[edit]

The following works in both languages.

procedure main(A)

every writes(" ",nth(0 to 25) | "\n")

every writes(" ",nth(250 to 265) | "\n")

every writes(" ",nth(1000 to 1025) | "\n")

end

procedure nth(n)

return n || ((n%10 = 1, n%100 ~= 11, "st") |

(n%10 = 2, n%100 ~= 12, "nd") |

(n%10 = 3, n%100 ~= 13, "rd") | "th")

end

- Output:

->nth 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13h 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013h 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th ->

## J[edit]

Implementation:

suf=: (;:'th st nd rd th') {::~ 4 <. 10 10 (* 1&~:)~/@#: ]

nth=: [: ;:inv (": , suf)each

Task:

thru=: <./ + [email protected](+ *)@-~

nth 0 thru 25

0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th

nth 250 thru 265

250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th

nth 1000 thru 1025

1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## Java[edit]

public class Nth {

public static String ordinalAbbrev(int n){

String ans = "th"; //most of the time it should be "th"

if(n % 100 / 10 == 1) return ans; //teens are all "th"

switch(n % 10){

case 1: ans = "st"; break;

case 2: ans = "nd"; break;

case 3: ans = "rd"; break;

}

return ans;

}

public static void main(String[] args){

for(int i = 0; i <= 25;i++){

System.out.print(i + ordinalAbbrev(i) + " ");

}

System.out.println();

for(int i = 250; i <= 265;i++){

System.out.print(i + ordinalAbbrev(i) + " ");

}

System.out.println();

for(int i = 1000; i <= 1025;i++){

System.out.print(i + ordinalAbbrev(i) + " ");

}

}

}

package nth;

import java.util.stream.IntStream;

import java.util.stream.Stream;

public interface Nth {

public static String suffix(int n){

if(n % 100 / 10 == 1){

return "th"; //teens are all "th"

}

switch(n % 10){

case 1: return "st";

case 2: return "nd";

case 3: return "rd";

default: return "th"; //most of the time it should be "th"

}

}

public static void print(int start, int end) {

IntStream.rangeClosed(start, end)

.parallel()

.mapToObj(i -> i + suffix(i) + " ")

.reduce(String::concat)

.ifPresent(System.out::println)

;

}

public static void print(int[] startAndEnd) {

print(startAndEnd[0], startAndEnd[1]);

}

public static int[] startAndEnd(int start, int end) {

return new int[] {

start,

end

};

}

public static void main(String... arguments){

Stream.of(

startAndEnd(0, 25),

startAndEnd(250, 265),

startAndEnd(1000, 1025)

)

.forEach(Nth::print)

;

}

}

- Output:

## JavaScript[edit]

### ES5[edit]

console.log(function () {

var lstSuffix = 'th st nd rd th th th th th th'.split(' '),

fnOrdinalForm = function (n) {

return n.toString() + (

11 <= n % 100 && 13 >= n % 100 ?

"th" : lstSuffix[n % 10]

);

},

range = function (m, n) {

return Array.apply(

null, Array(n - m + 1)

).map(function (x, i) {

return m + i;

});

};

return [[0, 25], [250, 265], [1000, 1025]].map(function (tpl) {

return range.apply(null, tpl).map(fnOrdinalForm).join(' ');

}).join('\n\n');

}());

- Output:

250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th

1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

### ES6[edit]

(function (lstTestRanges) {

'use strict'

let lstSuffix = 'th st nd rd th th th th th th'.split(' '),

// ordinalString :: Int -> String

ordinalString = n =>

n.toString() + (

11 <= n % 100 && 13 >= n % 100 ?

"th" : lstSuffix[n % 10]

),

// range :: Int -> Int -> [Int]

range = (m, n) =>

Array.from({

length: (n - m) + 1

}, (_, i) => m + i);

return lstTestRanges

.map(tpl => range

.apply(null, tpl)

.map(ordinalString)

);

})([[0, 25], [250, 265], [1000, 1025]]);

- Output:

[["0th", "1st", "2nd", "3rd", "4th", "5th", "6th", "7th", "8th", "9th", "10th", "11th", "12th", "13th", "14th", "15th", "16th", "17th", "18th", "19th", "20th", "21st", "22nd", "23rd", "24th", "25th"], ["250th", "251st", "252nd", "253rd", "254th", "255th", "256th", "257th", "258th", "259th", "260th", "261st", "262nd", "263rd", "264th", "265th"], ["1000th", "1001st", "1002nd", "1003rd", "1004th", "1005th", "1006th", "1007th", "1008th", "1009th", "1010th", "1011th", "1012th", "1013th", "1014th", "1015th", "1016th", "1017th", "1018th", "1019th", "1020th", "1021st", "1022nd", "1023rd", "1024th", "1025th"]]

## jq[edit]

# ordinalize an integer input, positive or negative

def ordinalize:

(if . < 0 then -(.) else . end) as $num

| ($num % 100) as $small

| (if 11 <= $small and $small <= 13 then "th"

else

( $num % 10)

| (if . == 1 then "st"

elif . == 2 then "nd"

elif . == 3 then "rd"

else "th"

end)

end) as $ordinal

| "\(.)\($ordinal)" ;

([range(-5; -1)], [range(0;26)], [range(250;266)], [range(1000;1026)])

| map(ordinalize)

- Output:

["-5th","-4th","-3rd","-2nd"] ["0th","1st","2nd","3rd","4th","5th","6th","7th","8th","9th","10th","11th","12th","13th","14th","15th","16th","17th","18th","19th","20th","21st","22nd","23rd","24th","25th"] ["250th","251st","252nd","253rd","254th","255th","256th","257th","258th","259th","260th","261st","262nd","263rd","264th","265th"] ["1000th","1001st","1002nd","1003rd","1004th","1005th","1006th","1007th","1008th","1009th","1010th","1011th","1012th","1013th","1014th","1015th","1016th","1017th","1018th","1019th","1020th","1021st","1022nd","1023rd","1024th","1025th"]

## Julia[edit]

using Printf

**Function**:

function ordinal(n::Integer)

n < 0 && throw(DomainError())

suffixes = ("st", "nd", "rd")

u = n % 10

t = n ÷ 10 % 10

if u > 3 || u == 0 || t == 1

suf = "th"

else

suf = suffixes[u]

end

return string(n, suf)

end

**Main**:

println("Tests of ordinal formatting of integers.")

for (i, n) in enumerate(0:25)

(i - 1) % 10 == 0 && println()

@printf("%7s", ordinal(n))

end

println()

for (i, n) in enumerate(250:265)

(i - 1) % 10 == 0 && println()

@printf("%7s", ordinal(n))

end

println()

for (i, n) in enumerate(1000:1025)

(i - 1) % 10 == 0 && println()

@printf("%7s", ordinal(n))

end

**Main2**:

Nth(x::Integer) = if x % 100 ∈ [11, 12, 13] "th" else ["th", "st", "nd", "rd", "th"][min(x % 10 + 1, 5)] end

NthA(x::Integer) = "$(x)'$(Nth(x)) "

[0:25..., 250:265..., 1000:1025...] .|> NthA .|> print;

- Output:

Tests of ordinal formatting of integers. 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## Kotlin[edit]

fun Int.ordinalAbbrev() =

if (this % 100 / 10 == 1) "th"

else when (this % 10) { 1 -> "st" 2 -> "nd" 3 -> "rd" else -> "th" }

fun IntRange.ordinalAbbrev() = map { "$it" + it.ordinalAbbrev() }.joinToString(" ")

fun main(args: Array<String>) {

listOf((0..25), (250..265), (1000..1025)).forEach { println(it.ordinalAbbrev()) }

}

## Lambdatalk[edit]

Translation from the javascript entry

{def fnOrdinalForm

{lambda {:n}

{if {and {<= 11 {% :n 100}} {>= 13 {% :n 100}}}

then :nth

else :n{A.get {% :n 10} th st nd rd th th th th th th}}}}

-> fnOrdinalForm

{S.map fnOrdinalForm {S.serie 0 25}}

-> 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th

16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th

{S.map fnOrdinalForm {S.serie 250 265}}

-> 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th

261st 262nd 263rd 264th 265th

{S.map fnOrdinalForm {S.serie 1000 1025}}

-> 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th

1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th

1021st 1022nd 1023rd 1024th 1025th

## Liberty BASIC[edit]

call printImages 0, 25

call printImages 250, 265

call printImages 1000, 1025

end

sub printImages loLim, hiLim

loLim = int(loLim)

hiLIm = int(hiLim)

for i = loLim to hiLim

print str$(i) + suffix$(i) + " ";

next i

end sub

function suffix$(n)

n = int(n)

nMod10 = n mod 10

nMod100 = n mod 100

if (nMod10 = 1) and (nMod100 <> 11) then

suffix$ = "st"

else

if (nMod10 = 2) and (nMod100 <> 12) then

suffix$ = "nd"

else

if (NMod10 = 3) and (NMod100 <> 13) then

suffix$ = "rd"

else

suffix$ = "th"

end if

end if

end if

end function

- Output:

0th 1st 2nd 3th 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23th 24th 25th 250th 251st 252nd 253th 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263th 264th 265th 1000th 1001st 1002nd 1003th 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023th 1024th 1025th

## Lua[edit]

The apostrophe just looks weird if you ask me. No one did, obviously.

function getSuffix (n)

local lastTwo, lastOne = n % 100, n % 10

if lastTwo > 3 and lastTwo < 21 then return "th" end

if lastOne == 1 then return "st" end

if lastOne == 2 then return "nd" end

if lastOne == 3 then return "rd" end

return "th"

end

function Nth (n) return n .. "'" .. getSuffix(n) end

for i = 0, 25 do print(Nth(i), Nth(i + 250), Nth(i + 1000)) end

- Output:

0'th 250'th 1000'th 1'st 251'st 1001'st 2'nd 252'nd 1002'nd 3'rd 253'rd 1003'rd 4'th 254'th 1004'th 5'th 255'th 1005'th 6'th 256'th 1006'th 7'th 257'th 1007'th 8'th 258'th 1008'th 9'th 259'th 1009'th 10'th 260'th 1010'th 11'th 261'st 1011'th 12'th 262'nd 1012'th 13'th 263'rd 1013'th 14'th 264'th 1014'th 15'th 265'th 1015'th 16'th 266'th 1016'th 17'th 267'th 1017'th 18'th 268'th 1018'th 19'th 269'th 1019'th 20'th 270'th 1020'th 21'st 271'st 1021'st 22'nd 272'nd 1022'nd 23'rd 273'rd 1023'rd 24'th 274'th 1024'th 25'th 275'th 1025'th

## Maple[edit]

toOrdinal := proc(n:: nonnegint)

if 1 <= n and n <= 10 then

if n >= 4 then

printf("%ath", n);

elif n = 3 then

printf("%ard", n);

elif n = 2 then

printf("%and", n);

else

printf("%ast", n);

end if:

else

printf(convert(n, 'ordinal'));

end if:

return NULL;

end proc:

a := [[0, 25], [250, 265], [1000, 1025]]:

for i in a do

for j from i[1] to i[2] do

toOrdinal(j);

printf(" ");

end do;

printf("\n\n");

end do;

- Output:

## Mathematica/Wolfram Language[edit]

I borrowed the logic from the Python code.

suffixlist = {"th", "st", "nd", "rd", "th", "th", "th", "th", "th","th"};

addsuffix[n_] := Module[{suffix},

suffix = Which[

Mod[n, 100] <= 10, suffixlist[[Mod[n, 10] + 1]],

Mod[n, 100] > 20, suffixlist[[Mod[n, 10] + 1]],

True, "th"

];

ToString[n] <> suffix

]

addsuffix[#] & /@ Range[0, 25] (* test 1 *)

addsuffix[#] & /@ Range[250, 265] (* test 2 *)

addsuffix[#] & /@ Range[1000, 1025] (* test 3 *)

- Output:

{"0th", "1st", "2nd", "3rd", "4th", "5th", "6th", "7th", "8th", "9th", "10th", "11th", "12th", "13th", "14th", "15th", "16th", "17th", "18th", "19th", "20th", "21st", "22nd", "23rd", "24th", "25th"} {"250th", "251st", "252nd", "253rd", "254th", "255th", "256th", "257th", "258th", "259th", "260th", "261st", "262nd", "263rd", "264th", "265th"} {"1000th", "1001st", "1002nd", "1003rd", "1004th", "1005th", "1006th", "1007th", "1008th", "1009th", "1010th", "1011th", "1012th", "1013th", "1014th", "1015th", "1016th", "1017th", "1018th", "1019th", "1020th", "1021st", "1022nd", "1023rd", "1024th", "1025th"}

## MATLAB[edit]

function s = nth(n)

tens = mod(n, 100);

if tens > 9 && tens < 20

suf = 'th';

else

switch mod(n, 10)

case 1

suf = 'st';

case 2

suf = 'nd';

case 3

suf = 'rd';

otherwise

suf = 'th';

end

end

s = sprintf('%d%s', n, suf);

end

- Output:

## Microsoft Small Basic[edit]

loLim = 0

hiLim = 25

PrintImages()

loLim = 250

hiLim = 265

PrintImages()

loLim = 1000

hiLim = 1025

PrintImages()

Sub PrintImages

For i = loLim To hiLim

nr = i

GetSuffix()

TextWindow.Write(i + suffix + " ")

EndFor

TextWindow.WriteLine("")

EndSub

Sub GetSuffix

rem10 = Math.Remainder(nr, 10)

rem100 = Math.Remainder(nr, 100)

If rem10 = 1 And rem100 <> 11 Then

suffix = "st"

ElseIf rem10 = 2 And rem100 <> 12 Then

suffix = "nd"

ElseIf rem10 = 3 And rem100 <> 13 Then

suffix = "rd"

Else

suffix = "th"

EndIf

EndSub

## MiniScript[edit]

To get the output all on one line, we append it to a list as we go, and then print the list all at once at the end.

ordinal = function(n)

if n > 3 and n < 20 then return n + "th"

if n % 10 == 1 then return n + "st"

if n % 10 == 2 then return n + "nd"

if n % 10 == 3 then return n + "rd"

return n + "th"

end function

out = []

test = function(from, to)

for i in range(from, to)

out.push ordinal(i)

end for

end function

test 0, 25

test 250, 265

test 1000, 1025

print out.join

- Output:

0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011st 1012nd 1013rd 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## Modula-2[edit]

MODULE Nth;

FROM STextIO IMPORT

WriteString, WriteLn;

FROM WholeStr IMPORT

IntToStr;

PROCEDURE Suffix(N: CARDINAL; VAR OUT Destination: ARRAY OF CHAR);

VAR

NMod10, NMod100: CARDINAL;

BEGIN

NMod10 := N MOD 10;

NMod100 := N MOD 100;

IF (NMod10 = 1) AND (NMod100 <> 11) THEN

Destination := "st";

ELSIF (NMod10 = 2) AND (NMod100 <> 12) THEN

Destination := "nd";

ELSIF (NMod10 = 3) AND (NMod100 <> 13) THEN

Destination := "rd";

ELSE

Destination := "th";

END;

END Suffix;

PROCEDURE PrintImages(LoLim, HiLim: CARDINAL);

VAR

I: CARDINAL;

IString: ARRAY [0 .. 15] OF CHAR;

ISuff: ARRAY [0 .. 1] OF CHAR;

BEGIN

FOR I := LoLim TO HiLim DO

IntToStr(I, IString);

Suffix(I, ISuff);

WriteString(IString);

WriteString(ISuff);

WriteString(" ");

END;

WriteLn;

END PrintImages;

BEGIN

PrintImages( 0, 25);

PrintImages( 250, 265);

PrintImages(1000, 1025);

END Nth.

## Nanoquery[edit]

def ordinalAbbrev(n)

if int(n % 100 / 10) = 1

return "th"

end

if n % 10 = 1

return "st"

else if n % 10 = 2

return "nd"

else if n % 10 = 3

return "rd"

else

return "th"

end

end

for i in range(0, 25)

print (i + "'" + ordinalAbbrev(i) + " ")

end

println

for i in range(250, 265)

print (i + "'" + ordinalAbbrev(i) + " ")

end

println

for i in range(1000, 1025)

print (i + "'" + ordinalAbbrev(i) + " ")

end

println

- Output:

0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 25'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th 1025'th

## Nim[edit]

const Suffix = ["th", "st", "nd", "rd", "th", "th", "th", "th", "th", "th"]

proc nth(n: Natural): string =

$n & "'" & (if n mod 100 in 11..20: "th" else: Suffix[n mod 10])

for j in countup(0, 1000, 250):

for i in j..j+24:

stdout.write nth(i), " "

echo ""

- Output:

0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 266'th 267'th 268'th 269'th 270'th 271'st 272'nd 273'rd 274'th 500'th 501'st 502'nd 503'rd 504'th 505'th 506'th 507'th 508'th 509'th 510'th 511'th 512'th 513'th 514'th 515'th 516'th 517'th 518'th 519'th 520'th 521'st 522'nd 523'rd 524'th 750'th 751'st 752'nd 753'rd 754'th 755'th 756'th 757'th 758'th 759'th 760'th 761'st 762'nd 763'rd 764'th 765'th 766'th 767'th 768'th 769'th 770'th 771'st 772'nd 773'rd 774'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th

## Objeck[edit]

class Nth {

function : OrdinalAbbrev(n : Int ) ~ String {

ans := "th"; # most of the time it should be "th"

if(n % 100 / 10 = 1) {

return ans; # teens are all "th"

};

select(n % 10){

label 1: { ans := "st"; }

label 2: { ans := "nd"; }

label 3: { ans := "rd"; }

};

return ans;

}

function : Main(args : String[]) ~ Nil {

for(i := 0; i <= 25; i+=1;) {

abbr := OrdinalAbbrev(i);

"{$i}{$abbr} "->Print();

};

""->PrintLine();

for(i := 250; i <= 265; i+=1;) {

abbr := OrdinalAbbrev(i);

"{$i}{$abbr} "->Print();

};

""->PrintLine();

for(i := 1000; i <= 1025; i+=1;) {

abbr := OrdinalAbbrev(i);

"{$i}{$abbr} "->Print();

};

}

}

- Output:

## OCaml[edit]

let show_nth n =

if (n mod 10 = 1) && (n mod 100 <> 11) then "st"

else if (n mod 10 = 2) && (n mod 100 <> 12) then "nd"

else if (n mod 10 = 3) && (n mod 100 <> 13) then "rd"

else "th"

let () =

let show_ordinals (min, max) =

for i=min to max do

Printf.printf "%d%s " i (show_nth i)

done;

print_newline() in

List.iter show_ordinals [ (0,25); (250,265); (1000,1025) ]

- Output:

## Oforth[edit]

: nth(n)

| r |

n "th" over 10 mod ->r

r 1 == ifTrue: [ n 100 mod 11 == ifFalse: [ drop "st" ] ]

r 2 == ifTrue: [ n 100 mod 12 == ifFalse: [ drop "nd" ] ]

r 3 == ifTrue: [ n 100 mod 13 == ifFalse: [ drop "rd" ] ]

+ ;

- Output:

seqFrom(0, 25) map(#nth) println [0th, 1st, 2nd, 3rd, 4th, 5th, 6th, 7th, 8th, 9th, 10th, 11th, 12th, 13th, 14th, 15th, 16t h, 17th, 18th, 19th, 20th, 21st, 22nd, 23rd, 24th, 25th] seqFrom(250, 265) map(#nth) println [250th, 251st, 252nd, 253rd, 254th, 255th, 256th, 257th, 258th, 259th, 260th, 261st, 262nd , 263rd, 264th, 265th] seqFrom(1000, 1025) map(#nth) println [1000th, 1001st, 1002nd, 1003rd, 1004th, 1005th, 1006th, 1007th, 1008th, 1009th, 1010th, 1 011th, 1012th, 1013th, 1014th, 1015th, 1016th, 1017th, 1018th, 1019th, 1020th, 1021st, 102 2nd, 1023rd, 1024th, 1025th]

## PARI/GP[edit]

(Spurious apostrophes intentionally omitted, following Raku.)

ordinal(n)=my(k=n%10,m=n%100); Str(n,if(m<21&&m>3,"th",k==1,"st",k==2,"nd",k==3,"rd","th"));

apply(ordinal, [0..25])

apply(ordinal, [250..265])

apply(ordinal, [1000..1025])

apply(ordinal, [111, 1012])

- Output:

%1 = ["0th", "1st", "2nd", "3rd", "4th", "5th", "6th", "7th", "8th", "9th", "10th", "11th", "12th", "13th", "14th", "15th", "16th", "17th", "18th", "19th", "20th", "21st", "22nd", "23rd", "24th", "25th"] %2 = ["250th", "251st", "252nd", "253rd", "254th", "255th", "256th", "257th", "258th", "259th", "260th", "261st", "262nd", "263rd", "264th", "265th"] %3 = ["1000th", "1001st", "1002nd", "1003rd", "1004th", "1005th", "1006th", "1007th", "1008th", "1009th", "1010th", "1011th", "1012th", "1013th", "1014th", "1015th", "1016th", "1017th", "1018th", "1019th", "1020th", "1021st", "1022nd", "1023rd", "1024th", "1025th"] %4 = ["111th", "1012th"]

## Pascal[edit]

nearly copy of Ada

Program n_th;

function Suffix(N: NativeInt):AnsiString;

var

res: AnsiString;

begin

res:= 'th';

case N mod 10 of

1:IF N mod 100 <> 11 then

res:= 'st';

2:IF N mod 100 <> 12 then

res:= 'nd';

3:IF N mod 100 <> 13 then

res:= 'rd';

else

end;

Suffix := res;

end;

procedure Print_Images(loLim, HiLim: NativeInt);

var

i : NativeUint;

begin

for I := LoLim to HiLim do

write(i,Suffix(i),' ');

writeln;

end;

begin

Print_Images( 0, 25);

Print_Images( 250, 265);

Print_Images(1000, 1025);

end.

- Output:

0th 1st 2nd 3rd 4th ... 11th 12th 13th ..20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th ..261st 262nd 263rd 264th 265th ..1001st 1002nd 1003rd 1004th..1011th..1013th..1021st 1022nd 1023rd 1024th

## Perl[edit]

Requires Perl 5.10 or newer for the Defined OR operator (//).

use 5.10.0;

my %irregulars = ( 1 => 'st',

2 => 'nd',

3 => 'rd',

11 => 'th',

12 => 'th',

13 => 'th');

sub nth

{

my $n = shift;

$n . # q(') . # Uncomment this to add apostrophes to output

($irregulars{$n % 100} // $irregulars{$n % 10} // 'th');

}

sub range { join ' ', map { nth($_) } @{$_[0]} }

print range($_), "\n" for ([0..25], [250..265], [1000..1025]);

- Output:

Alternatively, can use a library.

use Lingua::EN::Numbers::Ordinate 'ordinate';

foreach my $i (0..25, 250..265, 1000..1025) {

print ordinate($i),"\n";

}

## Phix[edit]

constant ordinals = {"th","st","nd","rd"} function Nth(integer n, bool apostrophe=false) integer mod10 = mod(n,10)+1 if mod10>4 or mod(n,100)=mod10+9 then mod10 = 1 end if return sprintf("%d%s",{n,repeat('\'',apostrophe)&ordinals[mod10]}) end function constant ranges = {{0,25},{250,265},{1000,1025}} for i=1 to length(ranges) do for j=ranges[i][1] to ranges[i][2] do if mod(j,10)=0 then puts(1,"\n") end if printf(1," %6s",{Nth(j,i=2)}) end for puts(1,"\n") end for

- Output:

0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

Alternatively you can use the builtin ord(), and a more functional style, as follows (same output)

function do_one(integer n, string apostrophe) return pad_head(sprintf("%d%s%s",{n,apostrophe,ord(n)}),7) end function procedure do_set(sequence s, bool bApostrophe=false) puts(1,join_by(apply(true,do_one,{s,{repeat('`',bApostrophe)}}),1,10,"")&"\n") end procedure constant {rs,re} = columnize({{0,25},{250,265},{1000,1025}}) papply(true,do_set,{apply(true,tagset,{re,rs}),{false,true,false}})

## PHP[edit]

function nth($num) {

$os = "th";

if ($num % 100 <= 10 or $num % 100 > 20) {

switch ($num % 10) {

case 1:

$os = "st";

break;

case 2:

$os = "nd";

break;

case 3:

$os = "rd";

break;

}

}

return $num . $os;

}

foreach ([[0,25], [250,265], [1000,1025]] as $i) {

while ($i[0] <= $i[1]) {

echo nth($i[0]) . " ";

$i[0]++;

}

echo "\n";

}

- Output:

## Picat[edit]

`nth/3`

is a built-in predicate in Picat, so let's call the functions `nth2/1`

and onward.

### Prolog style[edit]

nth2(N) = N.to_string() ++ Th =>

( tween(N) -> Th = "th"

; 1 = N mod 10 -> Th = "st"

; 2 = N mod 10 -> Th = "nd"

; 3 = N mod 10 -> Th = "rd"

; Th = "th" ).

tween(N) => Tween = N mod 100, between(11, 13, Tween).

### Function with explicit conditions[edit]

nth3(N) = cc(N,"th"), tween(N) => true.

nth3(N) = cc(N,"st"), N mod 10 = 1 => true.

nth3(N) = cc(N,"nd"), N mod 10 = 2 => true.

nth3(N) = cc(N,"rd"), N mod 10 = 3 => true.

nth3(N) = cc(N,"th") => true.

% helper function

cc(N,Th) = N.to_string() ++ Th.

### List of suffixes[edit]

nth4(N) = Nth =>

Suffix = ["th","st","nd","rd","th","th","th","th","th","th"],

Nth = N.to_string() ++ cond((N mod 100 <= 10; N mod 100 > 20), Suffix[1 + N mod 10], "th").

### Test[edit]

go =>

Ranges = [ 0..25, 250..265, 1000..1025],

foreach(Range in Ranges) println([nth2(I) : I in Range])

end,

nl.

- Output:

[0th,1st,2nd,3rd,4th,5th,6th,7th,8th,9th,10th,11th,12th,13th,14th,15th,16th,17th,18th,19th,20th,21st,22nd,23rd,24th,25th] [250th,251st,252nd,253rd,254th,255th,256th,257th,258th,259th,260th,261st,262nd,263rd,264th,265th] [1000th,1001st,1002nd,1003rd,1004th,1005th,1006th,1007th,1008th,1009th,1010th,1011th,1012th,1013th,1014th,1015th,1016th,1017th,1018th,1019th,1020th,1021st,1022nd,1023rd,1024th,1025th]

## PicoLisp[edit]

(de rangeth (A B)

(mapcar

'((I)

(pack I

(if (member (% I 100) (11 12 13))

'th

(case (% I 10)

(1 'st)

(2 'nd)

(3 'rd)

(T 'th) ) ) ) )

(range A B) ) )

(prinl (glue " " (rangeth 0 25)))

(prinl (glue " " (rangeth 250 265)))

(prinl (glue " " (rangeth 1000 1025)))

(bye)

- Output:

## PL/I[edit]

Nth: procedure options (main); /* 1 June 2014 */

declare i fixed (10);

do i = 0 to 25, 250 to 265, 1000 to 1025;

if i = 250 | i = 1000 then put skip (2);

put edit (enth(i)) (x(1), a);

end;

enth: procedure (i) returns (character (25) varying);

declare i fixed (10);

declare suffix character (2);

select (mod(i, 10));

when (1) suffix = 'st';

when (2) suffix = 'nd';

when (3) suffix = 'rd';

otherwise suffix = 'th';

end;

select (mod(i, 100));

when (11, 12, 13) suffix = 'th';

otherwise ;

end;

return ( trim(i) || suffix );

end enth;

end Nth;

- Output:

## PowerShell[edit]

function nth($inp){

$suffix = "th"

switch($inp % 10){

1{$suffix="st"}

2{$suffix="nd"}

3{$suffix="rd"}

}

return "$inp$suffix "

}

0..25 | %{Write-host -nonewline (nth "$_")};""

250..265 | %{Write-host -nonewline (nth "$_")};""

1000..1025 | %{Write-host -nonewline (nth "$_")};""

- Output:

0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11st 12nd 13rd 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011st 1012nd 1013rd 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

### An Alternate Version[edit]

This is, I think, is a more "PowerShelly" way:

function Get-Nth ([int]$Number)

{

$suffix = "th"

switch ($Number % 10)

{

1 {$suffix = "st"}

2 {$suffix = "nd"}

3 {$suffix = "rd"}

}

"$Number$suffix"

}

1..25 | ForEach-Object {Get-Nth $_} | Format-Wide {$_} -Column 5 -Force

251..265 | ForEach-Object {Get-Nth $_} | Format-Wide {$_} -Column 5 -Force

1001..1025 | ForEach-Object {Get-Nth $_} | Format-Wide {$_} -Column 5 -Force

- Output:

1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11st 12nd 13rd 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011st 1012nd 1013rd 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## Prolog[edit]

Following Icon:

nth(N, N_Th) :-

( tween(N) -> Th = "th"

; 1 is N mod 10 -> Th = "st"

; 2 is N mod 10 -> Th = "nd"

; 3 is N mod 10 -> Th = "rd"

; Th = "th" ),

string_concat(N, Th, N_Th).

tween(N) :- Tween is N mod 100, between(11, 13, Tween).

test :-

forall( between(0,25, N), (nth(N, N_Th), format('~w, ', N_Th)) ),

nl, nl,

forall( between(250,265,N), (nth(N, N_Th), format('~w, ', N_Th)) ),

nl, nl,

forall( between(1000,1025,N), (nth(N, N_Th), format('~w, ', N_Th)) ).

- Output:

?- test. 0th, 1st, 2nd, 3rd, 4th, 5th, 6th, 7th, 8th, 9th, 10th, 11th, 12th, 13th, 14th, 15th, 16th, 17th, 18th, 19th, 20th, 21st, 22nd, 23rd, 24th, 25th, 250th, 251st, 252nd, 253rd, 254th, 255th, 256th, 257th, 258th, 259th, 260th, 261st, 262nd, 263rd, 264th, 265th, 1000th, 1001st, 1002nd, 1003rd, 1004th, 1005th, 1006th, 1007th, 1008th, 1009th, 1010th, 1011th, 1012th, 1013th, 1014th, 1015th, 1016th, 1017th, 1018th, 1019th, 1020th, 1021st, 1022nd, 1023rd, 1024th, 1025th, true.

## PureBasic[edit]

Procedure.s Suffix(n.i)

Select n%10

Case 1 : If n%100<>11 : ProcedureReturn "st" : EndIf

Case 2 : If n%100<>12 : ProcedureReturn "nd" : EndIf

Case 3 : If n%100<>13 : ProcedureReturn "rd" : EndIf

EndSelect

ProcedureReturn "th"

EndProcedure

Procedure put(a.i,b.i)

For i=a To b : Print(Str(i)+Suffix(i)+" ") : Next

PrintN("")

EndProcedure

If OpenConsole()=0 : End 1 : EndIf

put(0,25)

put(250,265)

put(1000,1025)

Input()

- Output:

## Python[edit]

_suffix = ['th', 'st', 'nd', 'rd', 'th', 'th', 'th', 'th', 'th', 'th']

def nth(n):

return "%i'%s" % (n, _suffix[n%10] if n % 100 <= 10 or n % 100 > 20 else 'th')

if __name__ == '__main__':

for j in range(0,1001, 250):

print(' '.join(nth(i) for i in list(range(j, j+25))))

- Output:

0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 266'th 267'th 268'th 269'th 270'th 271'st 272'nd 273'rd 274'th 500'th 501'st 502'nd 503'rd 504'th 505'th 506'th 507'th 508'th 509'th 510'th 511'th 512'th 513'th 514'th 515'th 516'th 517'th 518'th 519'th 520'th 521'st 522'nd 523'rd 524'th 750'th 751'st 752'nd 753'rd 754'th 755'th 756'th 757'th 758'th 759'th 760'th 761'st 762'nd 763'rd 764'th 765'th 766'th 767'th 768'th 769'th 770'th 771'st 772'nd 773'rd 774'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th

**Alternate version**

#!/usr/bin/env python3

def ord(n):

try:

s = ['st', 'nd', 'rd'][(n-1)%10]

if (n-10)%100//10:

return str(n)+s

except IndexError:

pass

return str(n)+'th'

if __name__ == '__main__':

print(*(ord(n) for n in range(26)))

print(*(ord(n) for n in range(250,266)))

print(*(ord(n) for n in range(1000,1026)))

- Output:

## Quackery[edit]

[ table ] is suffix ( n --> $ )

$ "th st nd rd th th th th th th"

nest$ witheach [ ' suffix put ]

[ dup number$

swap dup 100 mod

10 21 within iff

[ drop $ "th" join ]

else

[ 10 mod

suffix join ] ] is ordinal$ ( n --> $ )

[ over - 1+

[] swap times

[ over i^ + ordinal$

nested join ]

nip 50 wrap$ ] is test ( n n --> )

0 25 test

cr

250 265 test

cr

1000 1025 test

- Output:

## R[edit]

Note that R vectors are 1-indexed.

nth <- function(n)

{

if (length(n) > 1) return(sapply(n, nth))

mod <- function(m, n) ifelse(!(m%%n), n, m%%n)

suffices <- c("th", "st", "nd", "rd", "th", "th", "th", "th", "th", "th")

if (n %% 100 <= 10 || n %% 100 > 20)

suffix <- suffices[mod(n+1, 10)]

else

suffix <- 'th'

paste(n, "'", suffix, sep="")

}

range <- list(0:25, 250:275, 500:525, 750:775, 1000:1025)

sapply(range, nth)

- Output:

[,1] [,2] [,3] [,4] [,5] [1,] "0'th" "250'th" "500'th" "750'th" "1000'th" [2,] "1'st" "251'st" "501'st" "751'st" "1001'st" [3,] "2'nd" "252'nd" "502'nd" "752'nd" "1002'nd" [4,] "3'rd" "253'rd" "503'rd" "753'rd" "1003'rd" [5,] "4'th" "254'th" "504'th" "754'th" "1004'th" [6,] "5'th" "255'th" "505'th" "755'th" "1005'th" [7,] "6'th" "256'th" "506'th" "756'th" "1006'th" [8,] "7'th" "257'th" "507'th" "757'th" "1007'th" [9,] "8'th" "258'th" "508'th" "758'th" "1008'th" [10,] "9'th" "259'th" "509'th" "759'th" "1009'th" [11,] "10'th" "260'th" "510'th" "760'th" "1010'th" [12,] "11'th" "261'st" "511'th" "761'st" "1011'th" [13,] "12'th" "262'nd" "512'th" "762'nd" "1012'th" [14,] "13'th" "263'rd" "513'th" "763'rd" "1013'th" [15,] "14'th" "264'th" "514'th" "764'th" "1014'th" [16,] "15'th" "265'th" "515'th" "765'th" "1015'th" [17,] "16'th" "266'th" "516'th" "766'th" "1016'th" [18,] "17'th" "267'th" "517'th" "767'th" "1017'th" [19,] "18'th" "268'th" "518'th" "768'th" "1018'th" [20,] "19'th" "269'th" "519'th" "769'th" "1019'th" [21,] "20'th" "270'th" "520'th" "770'th" "1020'th" [22,] "21'st" "271'st" "521'st" "771'st" "1021'st" [23,] "22'nd" "272'nd" "522'nd" "772'nd" "1022'nd" [24,] "23'rd" "273'rd" "523'rd" "773'rd" "1023'rd" [25,] "24'th" "274'th" "524'th" "774'th" "1024'th" [26,] "25'th" "275'th" "525'th" "775'th" "1025'th"

## Racket[edit]

#lang racket

(define (teen? n) (<= 11 (modulo n 100) 19))

(define (Nth n)

(format

"~a'~a" n

(match* ((modulo n 10) n)

[((or 1 2 3) (? teen?)) 'th] [(1 _) 'st] [(2 _) 'nd] [(3 _) 'rd] [(_ _) 'th])))

(for ((range (list (in-range 26) (in-range 250 266) (in-range 1000 1026))))

(displayln (string-join (for/list ((nth (sequence-map Nth range))) nth) " ")))

- Output:

0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 25'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th 1025'th

## Raku[edit]

(formerly Perl 6) (Spurious apostrophes intentionally omitted.)

my %irregulars = <1 st 2 nd 3 rd>, (11..13 X=> 'th');

sub nth ($n) { $n ~ ( %irregulars{$n % 100} // %irregulars{$n % 10} // 'th' ) }

say .list».&nth for [^26], [250..265], [1000..1025];

- Output:

If you want to get Unicodally fancy, use this version instead:

my %irregulars = <1 ˢᵗ 2 ⁿᵈ 3 ʳᵈ>, (11..13 X=> 'ᵗʰ');

sub nth ($n) { $n ~ ( %irregulars{$n % 100} // %irregulars{$n % 10} // 'ᵗʰ' ) }

say .list».&nth for [^26], [250..265], [1000..1025];

- Output:

0ᵗʰ 1ˢᵗ 2ⁿᵈ 3ʳᵈ 4ᵗʰ 5ᵗʰ 6ᵗʰ 7ᵗʰ 8ᵗʰ 9ᵗʰ 10ᵗʰ 11ᵗʰ 12ᵗʰ 13ᵗʰ 14ᵗʰ 15ᵗʰ 16ᵗʰ 17ᵗʰ 18ᵗʰ 19ᵗʰ 20ᵗʰ 21ˢᵗ 22ⁿᵈ 23ʳᵈ 24ᵗʰ 25ᵗʰ

250ᵗʰ 251ˢᵗ 252ⁿᵈ 253ʳᵈ 254ᵗʰ 255ᵗʰ 256ᵗʰ 257ᵗʰ 258ᵗʰ 259ᵗʰ 260ᵗʰ 261ˢᵗ 262ⁿᵈ 263ʳᵈ 264ᵗʰ 265ᵗʰ

1000ᵗʰ 1001ˢᵗ 1002ⁿᵈ 1003ʳᵈ 1004ᵗʰ 1005ᵗʰ 1006ᵗʰ 1007ᵗʰ 1008ᵗʰ 1009ᵗʰ 1010ᵗʰ 1011ᵗʰ 1012ᵗʰ 1013ᵗʰ 1014ᵗʰ 1015ᵗʰ 1016ᵗʰ 1017ᵗʰ 1018ᵗʰ 1019ᵗʰ 1020ᵗʰ 1021ˢᵗ 1022ⁿᵈ 1023ʳᵈ 1024ᵗʰ 1025ᵗʰ

## Red[edit]

Red[]

nth: function [n][

d: n % 10

suffix: either any [d < 1 d > 4 1 = to-integer n / 10] [4] [d]

rejoin [n pick ["st" "nd" "rd" "th"] suffix]

]

test: function [low high][

repeat i high - low + 1 [

prin [nth i + low - 1 ""]

]

prin newline

]

test 0 25

test 250 265

test 1000 1025

- Output:

0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011st 1012nd 1013rd 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## REXX[edit]

This version adds suffixes without apostrophes.

Negative numbers and fractions are also handled.

/*REXX program shows ranges of numbers with ordinal (st/nd/rd/th) suffixes attached.*/

call tell 0, 25 /*display the 1st range of numbers. */

call tell 250, 265 /* " " 2nd " " " */

call tell 1000, 1025 /* " " 3rd " " " */

exit /*stick a fork in it, we're all done. */

/*──────────────────────────────────────────────────────────────────────────────────────*/

tell: procedure; parse arg L,H,,$ /*get the Low and High #s, nullify list*/

do j=L to H; $=$ th(j); end /*process the range, from low ───► high*/

say 'numbers from ' L " to " H ' (inclusive):' /*display the title. */

say strip($); say; say /*display line; 2 sep*/

return /*return to invoker. */

/*──────────────────────────────────────────────────────────────────────────────────────*/

th: parse arg z; x=abs(z); return z||word('th st nd rd',1+x//10*(x//100%10\==1)*(x//10<4))

**output** using the default inputs:

numbers from 0 to 25 (inclusive): 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th numbers from 250 to 265 (inclusive): 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th numbers from 1000 to 1025 (inclusive): 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## Ring[edit]

for nr = 0 to 25

see Nth(nr) + Nth(nr + 250) + Nth(nr + 1000) + nl

next

func getSuffix n

lastTwo = n % 100

lastOne = n % 10

if lastTwo > 3 and lastTwo < 21 "th" ok

if lastOne = 1 return "st" ok

if lastOne = 2 return "nd" ok

if lastOne = 3 return "rd" ok

return "th"

func Nth n

return "" + n + "'" + getSuffix(n) + " "

## Ruby[edit]

Code (slightly adapted) and methodname taken from ActiveSupport (Ruby on Rails).

class Integer

def ordinalize

num = self.abs

ordinal = if (11..13).include?(num % 100)

"th"

else

case num % 10

when 1; "st"

when 2; "nd"

when 3; "rd"

else "th"

end

end

"#{self}#{ordinal}"

end

end

[(0..25),(250..265),(1000..1025)].each{|r| puts r.map(&:ordinalize).join(", "); puts}

- Output:

0th, 1st, 2nd, 3rd, 4th, 5th, 6th, 7th, 8th, 9th, 10th, 11th, 12th, 13th, 14th, 15th, 16th, 17th, 18th, 19th, 20th, 21st, 22nd, 23rd, 24th, 25th 250th, 251st, 252nd, 253rd, 254th, 255th, 256th, 257th, 258th, 259th, 260th, 261st, 262nd, 263rd, 264th, 265th 1000th, 1001st, 1002nd, 1003rd, 1004th, 1005th, 1006th, 1007th, 1008th, 1009th, 1010th, 1011th, 1012th, 1013th, 1014th, 1015th, 1016th, 1017th, 1018th, 1019th, 1020th, 1021st, 1022nd, 1023rd, 1024th, 1025th

## Rust[edit]

fn nth(num: isize) -> String {

format!("{}{}", num, match (num % 10, num % 100) {

(1, 11) | (2, 12) | (3, 13) => "th",

(1, _) => "st",

(2, _) => "nd",

(3, _) => "rd",

_ => "th",

})

}

fn main() {

let ranges = [(0, 26), (250, 266), (1000, 1026)];

for &(s, e) in &ranges {

println!("[{}, {}) :", s, e);

for i in s..e {

print!("{}, ", nth(i));

}

println!();

}

}

- Output:

[0, 26) : 0th, 1st, 2nd, 3rd, 4th, 5th, 6th, 7th, 8th, 9th, 10th, 11th, 12th, 13th, 14th, 15th, 16th, 17th, 18th, 19th, 20th, 21st, 22nd, 23rd, 24th, 25th, [250, 266) : 250th, 251st, 252nd, 253rd, 254th, 255th, 256th, 257th, 258th, 259th, 260th, 261st, 262nd, 263rd, 264th, 265th, [1000, 1026) : 1000th, 1001st, 1002nd, 1003rd, 1004th, 1005th, 1006th, 1007th, 1008th, 1009th, 1010th, 1011th, 1012th, 1013th, 1014th, 1015th, 1016th, 1017th, 1018th, 1019th, 1020th, 1021st, 1022nd, 1023rd, 1024th, 1025th,

## Scala[edit]

object Nth extends App {

def abbrevNumber(i: Int) = print(s"$i${ordinalAbbrev(i)} ")

def ordinalAbbrev(n: Int) = {

val ans = "th" //most of the time it should be "th"

if (n % 100 / 10 == 1) ans //teens are all "th"

else (n % 10) match {

case 1 => "st"

case 2 => "nd"

case 3 => "rd"

case _ => ans

}

}

(0 to 25).foreach(abbrevNumber)

println()

(250 to 265).foreach(abbrevNumber)

println();

(1000 to 1025).foreach(abbrevNumber)

}

## Seed7[edit]

$ include "seed7_05.s7i";

const func string: suffix (in integer: num) is func

result

var string: suffix is "";

begin

if num rem 10 = 1 and num rem 100 <> 11 then suffix := "st";

elsif num rem 10 = 2 and num rem 100 <> 12 then suffix := "nd";

elsif num rem 10 = 3 and num rem 100 <> 13 then suffix := "rd";

else suffix := "th";

end if;

end func;

const proc: printImages (in integer: start, in integer: stop) is func

local

var integer: num is 0;

begin

for num range start to stop do

write(num <& suffix(num) <& " ");

end for;

writeln;

end func;

const proc: main is func

begin

printImages( 0, 25);

printImages( 250, 265);

printImages(1000, 1025);

end func;

- Output:

## Set lang[edit]

Due to the language's specification, the input can only contain one character. Therefore, the following code only works with 0-9.

set o 49

set t 50

set h 51

set n !

set ! n

set ! 39

[n=o] set ? 13

[n=t] set ? 16

[n=h] set ? 19

set ! T

set ! H

set ? 21

set ! S

set ! T

set ? 21

set ! N

set ! D

set ? 12

set ! R

set ! D

> EOF

Input: I, Output: O

I: 1, O: 1'ST I: 2, O: 2'ND I: 3, O: 3'RD I: 4, O: 4'TH I: 5, O: 5'TH ...

## Sidef[edit]

func nth(n) {

static irregulars = Hash(<1 ˢᵗ 2 ⁿᵈ 3 ʳᵈ 11 ᵗʰ 12 ᵗʰ 13 ᵗʰ>...)

n.to_s + (irregulars{n % 100} \\ irregulars{n % 10} \\ 'ᵗʰ')

}

for r in [0..25, 250..265, 1000..1025] {

say r.map {|n| nth(n) }.join(" ")

}

- Output:

0ᵗʰ 1ˢᵗ 2ⁿᵈ 3ʳᵈ 4ᵗʰ 5ᵗʰ 6ᵗʰ 7ᵗʰ 8ᵗʰ 9ᵗʰ 10ᵗʰ 11ᵗʰ 12ᵗʰ 13ᵗʰ 14ᵗʰ 15ᵗʰ 16ᵗʰ 17ᵗʰ 18ᵗʰ 19ᵗʰ 20ᵗʰ 21ˢᵗ 22ⁿᵈ 23ʳᵈ 24ᵗʰ 25ᵗʰ 250ᵗʰ 251ˢᵗ 252ⁿᵈ 253ʳᵈ 254ᵗʰ 255ᵗʰ 256ᵗʰ 257ᵗʰ 258ᵗʰ 259ᵗʰ 260ᵗʰ 261ˢᵗ 262ⁿᵈ 263ʳᵈ 264ᵗʰ 265ᵗʰ 1000ᵗʰ 1001ˢᵗ 1002ⁿᵈ 1003ʳᵈ 1004ᵗʰ 1005ᵗʰ 1006ᵗʰ 1007ᵗʰ 1008ᵗʰ 1009ᵗʰ 1010ᵗʰ 1011ᵗʰ 1012ᵗʰ 1013ᵗʰ 1014ᵗʰ 1015ᵗʰ 1016ᵗʰ 1017ᵗʰ 1018ᵗʰ 1019ᵗʰ 1020ᵗʰ 1021ˢᵗ 1022ⁿᵈ 1023ʳᵈ 1024ᵗʰ 1025ᵗʰ

## Sinclair ZX81 BASIC[edit]

Works flawlessly with 2k or more of RAM. With 1k, the subroutine itself works but you can't quite print all the tests: the program crashes with an 'out of memory' error code after 1017th. (A slightly less useful and readable version gets as far as 1023rd; 1025th is probably attainable, but might involve obfuscating the program more than is appropriate for this site.)

10 FOR N=0 TO 25

20 GOSUB 160

30 PRINT N$;" ";

40 NEXT N

50 PRINT

60 FOR N=250 TO 265

70 GOSUB 160

80 PRINT N$;" ";

90 NEXT N

100 PRINT

110 FOR N=1000 TO 1025

120 GOSUB 160

130 PRINT N$;" ";

140 NEXT N

150 STOP

160 LET N$=STR$ N

170 LET S$="TH"

180 IF LEN N$=1 THEN GOTO 200

190 IF N$(LEN N$-1)="1" THEN GOTO 230

200 IF N$(LEN N$)="1" THEN LET S$="ST"

210 IF N$(LEN N$)="2" THEN LET S$="ND"

220 IF N$(LEN N$)="3" THEN LET S$="RD"

230 LET N$=N$+S$

240 RETURN

- Output:

0TH 1ST 2ND 3RD 4TH 5TH 6TH 7TH 8TH 9TH 10TH 11TH 12TH 13TH 14TH 15TH 16TH 17TH 18TH 19TH 20TH 21ST 22ND 23RD 24TH 25TH 250TH 251ST 252ND 253RD 254TH 255TH 256TH 257TH 258TH 259TH 260TH 261ST 262ND 263RD 264TH 265TH 1000TH 1001ST 1002ND 1003RD 1004TH 1005TH 1006TH 1007TH 1008TH 1009TH 1010TH 1011TH 1012TH 1013TH 1014TH 1015TH 1016TH 1017TH 1018TH 1019TH 1020TH 1021ST 1022ND 1023RD 1024TH 1025TH

## SQL[edit]

Oracle

SELECT level card,

to_char(to_date(level,'j'),'fmjth') ord

FROM dual

CONNECT BY level <= 15;

SELECT to_char(to_date(5373485,'j'),'fmjth')

FROM dual;

CARD ORD ---------- ------------------------------ 1 1st 2 2nd 3 3rd 4 4th 5 5th 6 6th 7 7th 8 8th 9 9th 10 10th 11 11th 12 12th 13 13th 14 14th 15 15th 15 rows selected. select to_char(to_date(5373485,'j'),'fmjth') * ERROR at line 1: ORA-01854: julian date must be between 1 and 5373484

## Standard ML[edit]

local

val v = Vector.tabulate (10, fn 1 => "st" | 2 => "nd" | 3 => "rd" | _ => "th")

fun getSuffix x =

if 3 < x andalso x < 21 then "th" else Vector.sub (v, x mod 10)

in

fun nth n =

Int.toString n ^ getSuffix (n mod 100)

end

(* some test ouput *)

val () = (print o concat o List.tabulate)

(26, fn i => String.concatWith "\t" (map nth [i, i + 250, i + 1000]) ^ "\n")

- Output:

0th 250th 1000th 1st 251st 1001st 2nd 252nd 1002nd 3rd 253rd 1003rd 4th 254th 1004th 5th 255th 1005th 6th 256th 1006th 7th 257th 1007th 8th 258th 1008th 9th 259th 1009th 10th 260th 1010th 11th 261st 1011th 12th 262nd 1012th 13th 263rd 1013th 14th 264th 1014th 15th 265th 1015th 16th 266th 1016th 17th 267th 1017th 18th 268th 1018th 19th 269th 1019th 20th 270th 1020th 21st 271st 1021st 22nd 272nd 1022nd 23rd 273rd 1023rd 24th 274th 1024th 25th 275th 1025th

## Stata[edit]

We reuse here the **maps** function defined in the task Apply a callback to an array.

mata

function maps(f,a) {

nr = rows(a)

nc = cols(a)

b = J(nr,nc,"")

for (i=1;i<=nr;i++) {

for (j=1;j<=nc;j++) b[i,j] = (*f)(a[i,j])

}

return(b)

}

function nth(n) {

k = max((min((mod(n-1,10)+1,4)),4*(mod(n-10,100)<10)))

return(strofreal(n)+("st","nd","rd","th")[k])

}

maps(&nth(),((0::25),(250::275),(1000::1025)))

end

**Output:**

1 2 3 +----------------------------+ 1 | 0th 250th 1000th | 2 | 1st 251st 1001st | 3 | 2nd 252nd 1002nd | 4 | 3rd 253rd 1003rd | 5 | 4th 254th 1004th | 6 | 5th 255th 1005th | 7 | 6th 256th 1006th | 8 | 7th 257th 1007th | 9 | 8th 258th 1008th | 10 | 9th 259th 1009th | 11 | 10th 260th 1010th | 12 | 11th 261st 1011th | 13 | 12th 262nd 1012th | 14 | 13th 263rd 1013th | 15 | 14th 264th 1014th | 16 | 15th 265th 1015th | 17 | 16th 266th 1016th | 18 | 17th 267th 1017th | 19 | 18th 268th 1018th | 20 | 19th 269th 1019th | 21 | 20th 270th 1020th | 22 | 21st 271st 1021st | 23 | 22nd 272nd 1022nd | 24 | 23rd 273rd 1023rd | 25 | 24th 274th 1024th | 26 | 25th 275th 1025th | +----------------------------+

## Swift[edit]

func addSuffix(n:Int) -> String {

if n % 100 / 10 == 1 {

return "th"

}

switch n % 10 {

case 1:

return "st"

case 2:

return "nd"

case 3:

return "rd"

default:

return "th"

}

}

for i in 0...25 {

print("\(i)\(addSuffix(i)) ")

}

println()

for i in 250...265 {

print("\(i)\(addSuffix(i)) ")

}

println()

for i in 1000...1025 {

print("\(i)\(addSuffix(i)) ")

}

println()

- Output:

## Tcl[edit]

proc ordinal {n} {

if {$n%100<10 || $n%100>20} {

set suff [lindex {th st nd rd th th th th th th} [expr {$n % 10}]]

} else {

set suff th

}

return "$n'$suff"

}

foreach start {0 250 1000} {

for {set n $start; set l {}} {$n<=$start+25} {incr n} {

lappend l [ordinal $n]

}

puts $l

}

- Output:

0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 25'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 266'th 267'th 268'th 269'th 270'th 271'st 272'nd 273'rd 274'th 275'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th 1025'th

## True BASIC[edit]

SUB sufijo (n)

LET n = INT(n)

LET NMod10 = MOD(n, 10)

LET NMod100 = MOD(n, 100)

IF (NMod10 = 1) AND (NMod100 <> 11) THEN

LET sufi$ = "st"

ELSE

IF (NMod10 = 2) AND (NMod100 <> 12) THEN

LET sufi$ = "nd"

ELSE

IF (NMod10 = 3) AND (NMod100 <> 13) THEN

LET sufi$ = "rd"

ELSE

LET sufi$ = "th"

END IF

END IF

END IF

PRINT sufi$;

END SUB

SUB imprimeOrdinal (loLim, hiLim)

LET loLim = INT(loLim)

LET hiLim = INT(hiLim)

FOR i = loLim TO hiLim

PRINT i;

CALL sufijo (i)

PRINT " ";

NEXT i

END SUB

CALL imprimeOrdinal (0, 25)

CALL imprimeOrdinal (250, 265)

CALL imprimeOrdinal (1000, 1025)

END

## uBasic/4tH[edit]

For x = 0 to 25 ' Test range 0..25

Push x : GoSub _PrintOrdinal

Next x : Print

For x = 250 to 265 ' Test range 250..265

Push x : GoSub _PrintOrdinal

Next x : Print

For x = 1000 to 1025 ' Test range 1000..1025

Push x : GoSub _PrintOrdinal

Next x : Print

End ' End test program

' ( n --)

_PrintOrdinal ' Ordinal subroutine

If Tos() > -1 Then ' If within range then

Print Using "____#";Tos();"'"; ' Print the number

' Take care of 11, 12 and 13

If (Tos()%100 > 10) * (Tos()%100 < 14) Then

Gosub (Pop() * 0) + 100 ' Clear stack and print "th"

Return ' We're done here

EndIf

Push Pop() % 10 ' Calculate n mod 10

GoSub 100 + 10 * ((Tos()>0) + (Tos()>1) + (Tos()>2) - (3 * (Pop()>3)))

Else ' And decide which ordinal to use

Print Pop();" is less than zero" ' Otherwise, it is an error

EndIf

Return

' Select and print proper ordinal

100 Print "th"; : Return

110 Print "st"; : Return

120 Print "nd"; : Return

130 Print "rd"; : Return

- Output:

## UNIX Shell[edit]

nth() {

local ordinals=(th st nd rd)

local -i n=$1 i

if (( n < 0 )); then

printf '%s%s\n' - "$(nth $(( -n )) )"

return 0

fi

case $(( n % 100 )) in

11|12|13) i=0;;

*) (( i= n%10 < 4 ? n%10 : 0 ));;

esac

printf '%d%s\n' "$n" "${ordinals[i]}"

}

for n in {0..25} {250..265} {1000..1025}; do

nth $n

done | column

- Output:

0th 7th 14th 21st 252nd 259th 1000th 1007th 1014th 1021st 1st 8th 15th 22nd 253rd 260th 1001st 1008th 1015th 1022nd 2nd 9th 16th 23rd 254th 261st 1002nd 1009th 1016th 1023rd 3rd 10th 17th 24th 255th 262nd 1003rd 1010th 1017th 1024th 4th 11th 18th 25th 256th 263rd 1004th 1011th 1018th 1025th 5th 12th 19th 250th 257th 264th 1005th 1012th 1019th 6th 13th 20th 251st 258th 265th 1006th 1013th 1020th

## VBA[edit]

Private Function ordinals() As Variant

ordinals = [{"th","st","nd","rd"}]

End Function

Private Function Nth(n As Variant, Optional apostrophe As Boolean = False) As String

Dim mod10 As Integer: mod10 = n Mod 10 + 1

If mod10 > 4 Or n Mod 100 = mod10 + 9 Then mod10 = 1

Nth = CStr(n) & String$(Val(-apostrophe), "'") & ordinals()(mod10)

End Function

Public Sub main()

Ranges = [{0,25;250,265;1000,1025}]

For i = 1 To UBound(Ranges)

For j = Ranges(i, 1) To Ranges(i, 2)

If j Mod 10 = 0 Then Debug.Print

Debug.Print Format(Nth(j, i = 2), "@@@@@@@");

Next j

Debug.Print

Next i

End Sub

- Output:

0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## Vlang[edit]

fn ord(n int) string {

mut s := "th"

c := n % 10

if c in [1,2,3] {

if n%100/10 == 1 {

return "$n$s"

}

match c {

1 {

s = 'st'

}

2 {

s = 'nd'

}

3 {

s = 'rd'

}

else{}

}

}

return "$n$s"

}

fn main() {

for n := 0; n <= 25; n++ {

print("${ord(n)} ")

}

println('')

for n := 250; n <= 265; n++ {

print("${ord(n)} ")

}

println('')

for n := 1000; n <= 1025; n++ {

print("${ord(n)} ")

}

println('')

}

- Output:

## Wren[edit]

import "/fmt" for Conv

var ranges = [ 0..25, 250..265, 1000..1025 ]

for (r in ranges) {

r.each { |i| System.write("%(Conv.ord(i)) ") }

System.print("\n")

}

- Output:

## XBasic[edit]

PROGRAM "nth"

VERSION "0.0002"

DECLARE FUNCTION Entry()

INTERNAL FUNCTION Suffix$(n&&)

INTERNAL FUNCTION PrintImages (loLim&&, hiLim&&)

FUNCTION Entry()

PrintImages( 0, 25)

PrintImages( 250, 265)

PrintImages(1000, 1025)

END FUNCTION

FUNCTION Suffix$(n&&)

nMod10@@ = n&& MOD 10

nMod100@@ = n&& MOD 100

SELECT CASE TRUE

CASE (nMod10@@ = 1) AND (nMod100@@ <> 11):

RETURN ("st")

CASE (nMod10@@ = 2) AND (nMod100@@ <> 12):

RETURN ("nd")

CASE (nMod10@@ = 3) AND (nMod100@@ <> 13):

RETURN ("rd")

CASE ELSE:

RETURN ("th")

END SELECT

END FUNCTION

FUNCTION PrintImages(loLim&&, hiLim&&)

FOR i&& = loLim&& TO hiLim&&

PRINT TRIM$(STRING$(i&&)); Suffix$(i&&); " ";

NEXT

END FUNCTION

END PROGRAM

- Output:

## XLISP[edit]

(DEFUN NTH (N)

(COND

((AND (> (MOD N 100) 3) (< (MOD N 100) 21)) `(,N TH))

((= (MOD N 10) 1) `(,N ST))

((= (MOD N 10) 2) `(,N ND))

((= (MOD N 10) 3) `(,N RD))

(T `(,N TH))))

(DEFUN RANGE (X Y)

(IF (<= X Y)

(CONS X (RANGE (+ X 1) Y))))

(DEFUN TEST-NTH ()

(DISPLAY (MAPCAR NTH (RANGE 1 25)))

(NEWLINE)

(DISPLAY (MAPCAR NTH (RANGE 250 265)))

(NEWLINE)

(DISPLAY (MAPCAR NTH (RANGE 1000 1025))))

(TEST-NTH)

- Output:

((1 ST) (2 ND) (3 RD) (4 TH) (5 TH) (6 TH) (7 TH) (8 TH) (9 TH) (10 TH) (11 TH) (12 TH) (13 TH) (14 TH) (15 TH) (16 TH) (17 TH) (18 TH) (19 TH) (20 TH) (21 ST) (22 ND) (23 RD) (24 TH) (25 TH)) ((250 TH) (251 ST) (252 ND) (253 RD) (254 TH) (255 TH) (256 TH) (257 TH) (258 TH) (259 TH) (260 TH) (261 ST) (262 ND) (263 RD) (264 TH) (265 TH)) ((1000 TH) (1001 ST) (1002 ND) (1003 RD) (1004 TH) (1005 TH) (1006 TH) (1007 TH) (1008 TH) (1009 TH) (1010 TH) (1011 TH) (1012 TH) (1013 TH) (1014 TH) (1015 TH) (1016 TH) (1017 TH) (1018 TH) (1019 TH) (1020 TH) (1021 ST) (1022 ND) (1023 RD) (1024 TH) (1025 TH))

## XPL0[edit]

\N'th

code Rem=2, CrLf=9, IntIn=10, IntOut=11, Text=12;

procedure Suf(N, S);

integer N;

character S;

integer NMod10, NMod100;

begin

NMod10:= Rem(N/10);

NMod100:= Rem(N/100);

case of

NMod10 = 1 & NMod100 # 11: S(0):= "st";

NMod10 = 2 & NMod100 # 12: S(0):= "nd";

NMod10 = 3 & NMod100 # 13: S(0):= "rd"

other

S(0):= "th";

end;

procedure PrintImages(LoLim, HiLim);

integer LoLim, HiLim;

integer I;

character S;

begin

for I:= LoLim, HiLim do

begin

Suf(I, addr S);

IntOut(0, I); Text(0, S); Text(0, " ")

end;

CrLf(0)

end;

begin

PrintImages(0, 25);

PrintImages(250, 265);

PrintImages(1000, 1025)

end

- Output:

## Yabasic[edit]

sub ordinal$ (n)

NMod10 = mod(n, 10)

NMod100 = mod(n, 100)

if (NMod10 = 1) and (NMod100 <> 11) then

return "st"

else

if (NMod10 = 2) and (NMod100 <> 12) then

return "nd"

else

if (NMod10 = 3) and (NMod100 <> 13) then

return "rd"

else

return "th"

end if

end if

end if

end sub

sub imprimeOrdinal(a, b)

for i = a to b

print i, ordinal$(i), " ";

next i

end sub

imprimeOrdinal (0, 25)

imprimeOrdinal (250, 265)

imprimeOrdinal (1000, 1025)

end

## zkl[edit]

Two versions, your choice

#if 0

fcn addSuffix(n){

z:=n.abs()%100;

if(11<=z<=13) return(String(n,"th"));

z=z%10;

String(n,(z==1 and "st") or (z==2 and "nd") or (z==3 and "rd") or "th");

}

#else

fcn addSuffix(n){

var suffixes=T("th","st","nd","rd","th","th","th","th","th","th"); //0..10

z:=n.abs()%100;

String(n,(z<=10 or z>20) and suffixes[z%10] or "th");

}

#endif

[0..25] .apply(addSuffix).concat(",").println();

[250..265] .apply(addSuffix).concat(",").println();

[1000..1025].apply(addSuffix).concat(",").println();

- Output:

0th,1st,2nd,3rd,4th,5th,6th,7th,8th,9th,10th,11th,12th,13th,14th,15th,16th,17th,18th,19th,20th,21st,22nd,23rd,24th,25th 250th,251st,252nd,253rd,254th,255th,256th,257th,258th,259th,260th,261st,262nd,263rd,264th,265th 1000th,1001st,1002nd,1003rd,1004th,1005th,1006th,1007th,1008th,1009th,1010th,1011th,1012th,1013th,1014th,1015th,1016th,1017th,1018th,1019th,1020th,1021st,1022nd,1023rd,1024th,1025th

## ZX Spectrum Basic[edit]

10 FOR n=0 TO 25

20 GO SUB 140

30 PRINT n$;" ";

40 NEXT n

50 FOR n=250 TO 265

60 GO SUB 140

70 PRINT n$;" ";

80 NEXT n

90 FOR n=1000 TO 1025

100 GO SUB 140

110 PRINT n$;" ";

120 NEXT n

130 STOP

140 LET s$="th"

150 LET n$=STR$ n

160 IF LEN n$=1 THEN GO TO 180

170 IF n$(LEN n$-1)="1" THEN GO TO 210

180 IF n$(LEN n$)="1" THEN LET s$="st"

190 IF n$(LEN n$)="2" THEN LET s$="nd"

200 IF n$(LEN n$)="3" THEN LET s$="rd"

210 LET n$=n$+s$

220 RETURN

- Output:

- Programming Tasks
- Ordinal numbers
- String manipulation
- 11l
- 8080 Assembly
- 8086 Assembly
- Action!
- Ada
- ALGOL 68
- APL
- AppleScript
- Applesoft BASIC
- Arturo
- AutoHotkey
- AWK
- Babel
- BaCon
- BASIC
- BASIC256
- Commodore BASIC
- Nascom BASIC
- QBasic
- Batch File
- BBC BASIC
- BCPL
- Befunge
- BQN
- C
- C sharp
- C++
- Clojure
- CLU
- COBOL
- Common Lisp
- Cowgol
- Crystal
- D
- Delphi
- Draco
- Elena
- Elixir
- ERRE
- F Sharp
- Factor
- Forth
- Fortran
- FreeBASIC
- Gambas
- Go
- GW-BASIC
- Haskell
- Icon
- Unicon
- J
- Java
- JavaScript
- Jq
- Julia
- Kotlin
- Lambdatalk
- Liberty BASIC
- Lua
- Maple
- Mathematica
- Wolfram Language
- MATLAB
- Microsoft Small Basic
- MiniScript
- Modula-2
- Nanoquery
- Nim
- Objeck
- OCaml
- Oforth
- PARI/GP
- Pascal
- Perl
- Lingua::EN::Numbers::Ordinate
- Phix
- PHP
- Picat
- PicoLisp
- PL/I
- PowerShell
- Prolog
- PureBasic
- Python
- Quackery
- R
- Racket
- Raku
- Red
- REXX
- Ring
- Ruby
- Rust
- Scala
- Seed7
- Set lang
- Sidef
- Sinclair ZX81 BASIC
- SQL
- Standard ML
- Stata
- Swift
- Tcl
- True BASIC
- UBasic/4tH
- UNIX Shell
- VBA
- Vlang
- Wren
- Wren-fmt
- XBasic
- XLISP
- XPL0
- Yabasic
- Zkl
- ZX Spectrum Basic