# N'th

Write a function/method/subroutine/... that when given an integer greater than or equal to zero returns a string of the number followed by an apostrophe then the ordinal suffix.

**N'th**

You are encouraged to solve this task according to the task description, using any language you may know.

- Example

Returns would include `1'st 2'nd 3'rd 11'th 111'th 1001'st 1012'th`

- Task

Use your routine to show here the output for *at least* the following (inclusive) ranges of integer inputs:
`0..25, 250..265, 1000..1025`

**Note:** apostrophes are now *optional* to allow correct apostrophe-less English.

## 11l

```
V _suffix = [‘th’, ‘st’, ‘nd’, ‘rd’, ‘th’, ‘th’, ‘th’, ‘th’, ‘th’, ‘th’]
F nth(n)
R ‘#.'#.’.format(n, I n % 100 <= 10 | n % 100 > 20 {:_suffix[n % 10]} E ‘th’)
L(j) (0..1000).step(250)
print_elements(Array(j.+25).map(i -> nth(i)))
```

- Output:

0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 266'th 267'th 268'th 269'th 270'th 271'st 272'nd 273'rd 274'th 500'th 501'st 502'nd 503'rd 504'th 505'th 506'th 507'th 508'th 509'th 510'th 511'th 512'th 513'th 514'th 515'th 516'th 517'th 518'th 519'th 520'th 521'st 522'nd 523'rd 524'th 750'th 751'st 752'nd 753'rd 754'th 755'th 756'th 757'th 758'th 759'th 760'th 761'st 762'nd 763'rd 764'th 765'th 766'th 767'th 768'th 769'th 770'th 771'st 772'nd 773'rd 774'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th

## 68000 Assembly

The function itself:

```
Nth:
MOVEQ #1,D1
.loop:
MOVE.L D1,-(SP)
MOVE.L D0,-(SP)
MOVE.B (2,SP),D0
JSR printhex
MOVE.B (3,SP),D0
JSR printhex
MOVE.L (SP)+,D0
MOVE.L D0,-(SP)
AND.W #$00FF,D0
;HANDLE SPECIAL CASES
CMP.B #$11,D0
BEQ .fourth
CMP.B #$12,D0
BEQ .fourth
CMP.B #$13,D0
BEQ .fourth
;HANDLE THE REST
AND.W #$000F,D0
CMP.B #1,D0
BEQ .first
CMP.B #2,D0
BEQ .second
CMP.B #3,D0
BEQ .third
.fourth:
LEA th,A3
bra .print
.third:
LEA rd,a3
bra .print
.second:
LEA nd,a3
bra .print
.first:
LEA est,a3
.print:
JSR PrintString
JSR newline
MOVE.L (SP)+,d0
MOVE.L (SP)+,d1
ABCD D1,D0
DBRA D7,.loop
rts
th:
dc.b "th",255
even
est:
dc.b "st",255
even
nd:
dc.b "nd",255
even
rd:
dc.b "rd",255
even
```

And the test cases (each was executed in separate builds of the Sega Genesis cartridge to have enough room to see them all at once)

```
MOVE.w #0,D0
MOVE.W #25,D7
JSR Nth
MOVE.w #$250,D0 ;since we're working with binary-coded decimal, this number is stored as hex.
MOVE.W #15,D7
JSR Nth
MOVE.w #$1000,D0 ;since we're working with binary-coded decimal, this number is stored as hex.
MOVE.W #25,D7
JSR Nth
jmp * ;stop the cpu - we're done.
```

- Output:

0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## 8080 Assembly

```
org 100h
jmp demo
;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
;; Given a 16-bit unsigned integer in HL, return a string
;; consisting of its ASCII representation plus an ordinal
;; suffix in HL.
nth: lxi b,-10 ; Divisor for digit loop
push h ; Push integer to stack
lxi h,nthsfx ; Pointer to end of digit area
xthl ; Swap digit pointer with integer
nthdigit: lxi d,-1 ; Get current digit - DE holds quotient
nthdiv10: inx d ; Increment quotient,
dad b ; subtract 10 from integer,
jc nthdiv10 ; Keep going until HL<0
mvi a,'0'+10 ; Calculate ASCII value for digit
add l ; Modulus is in (H)L
xthl ; Swap integer with pointer
dcx h ; Point to one digit further left
mov m,a ; Store the digit
xthl ; Swap pointer with integer
xchg ; Put quotient in HL
mov a,h ; Is it zero?
ora l
jnz nthdigit ; If not, go calculate next digit
mvi e,0 ; Default suffix is 'th'.
lxi h,nthnum+3 ; Look at tens digit
mov a,m
cpi '1' ; Is it '1'?
jz nthsetsfx ; Then it is always 'th'.
inx h ; Look at zeroes digit
mov a,m
sui '0' ; Subtract ASCII '0'
cpi 4 ; 4 or higher?
jnc nthsetsfx ; Then it is always 'th'.
rlc ; Otherwise, suffix is at N*2+nthord
mov e,a
nthsetsfx: mvi d,0 ; Look up suffix in list
lxi h,nthord
dad d ; Pointer to suffix in HL
lxi d,nthsfx ; Pointer to space for suffix in DE
mov a,m ; Get first letter of suffix
stax d ; Store it in output
inx h ; Increment both pointers
inx d
mov a,m ; Get second letter of suffix
stax d ; Store it in output
pop h ; Return pointer to leftmost digit
ret
nthord: db 'thstndrd' ; Ordinal suffixes
nthnum: db '*****' ; Room for digits
nthsfx: db '**$' ; Room for suffix
;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
demo: ;; Demo code
lxi h,0 ; Starting at 0...
mvi b,26 ; ...print 26 numbers [0..25]
call printnums
lxi h,250 ; Starting at 250...
mvi b,16 ; ...print 16 numbers [250..265]
call printnums
lxi h,1000 ; Starting at 1000...
mvi b,26 ; ...print 26 numbers [1000..1025]
;; Print values from HL up to HL+B
printnums: push h ; Keep number
push b ; Keep counter
call nth ; Get string for current HL
xchg ; Put it in DE
mvi c,9 ; CP/M print string
call 5
mvi e,' ' ; Separate numbers with spaces
mvi c,2 ; CP/M print character
call 5
pop b ; Restore counter
pop h ; Restore number
inx h ; Increment number
dcr b ; Decrement counter
jnz printnums ; If not zero, print next number
ret
```

- Output:

Line breaks added for clarity.

0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## 8086 Assembly

```
bits 16
cpu 8086
segment .text
org 100h
jmp demo
;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
;; Given a number in AX, return string with ordinal suffix
;; in DX.
nth: mov cx,10 ; Divisor
mov bx,.sfx ; Pointer to end of number
.digit: xor dx,dx ; Zero DX
div cx ; AX = DX:AX/10; DX=remainder
add dl,'0' ; Make digit
dec bx ; Back up the pointer
mov [bx],dl ; Store digit
and ax,ax ; Done yet? (AX=0?)
jnz .digit ; If not, get next digit
mov dx,bx ; Keep string pointer in DX
xor bx,bx ; Default suffix is 'th'.
cmp byte [.num+3],'1' ; Is the tens digit '1'?
je .setsfx ; Then the suffix is 'th'.
mov cl,[.num+4] ; Get the ones digit
cmp cl,'4' ; Is it '4' or higher?
jae .setsfx ; Then the suffix is 'th'.
mov bl,cl
sub bl,'0' ; Calculate offset.
shl bl,1 ; [0..3]*2 + .ord
.setsfx: mov ax,[bx+.ordsfx] ; Set suffix
mov [.sfx],ax
ret
.ordsfx: db 'thstndrd'
.num: db '*****'
.sfx: db '**$'
;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
;; Print numbers.
demo: mov ax,0 ; Starting at 0...
mov bl,26 ; ...print 26 numbers [0..25]
call printn
mov ax,250 ; Starting at 250...
mov bl,16 ; ...print 16 numbers [250..265]
call printn
mov ax,1000 ; Starting at 1000...
mov bl,26 ; ...print 26 numbers [1000..1025]
;; Print BL numbers starting at AX
printn: push ax ; Keep number
push bx ; Keep counter
call nth ; Get string for current AX
mov ah,9 ; MS-DOS print string
int 21h
mov dl,' ' ; Separate numbers by spaces
mov ah,2 ; MS-DOS print character
int 21h
pop bx ; Restore counter
pop ax ; Restore number
inc ax ; Next number
dec bl ; Are we done yet?
jnz printn
ret
```

- Output:

Line breaks added for clarity.

0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## Action!

```
PROC Nth(CARD val,CHAR ARRAY s)
CHAR ARRAY sfx
BYTE d
StrC(val,s)
s(0)=s(0)+1
s(s(0))=''
d=val MOD 100
IF d>10 AND d<14 THEN
sfx="th"
ELSE
d=val MOD 10
IF d=1 THEN sfx="st"
ELSEIF d=2 THEN sfx="nd"
ELSEIF d=3 THEN sfx="rd"
ELSE sfx="th"
FI
FI
s(0)=s(0)+2
SAssign(s,sfx,s(0)-1,s(0)+1)
RETURN
PROC Main()
CARD ARRAY n=[0 250 1000]
CHAR ARRAY s(10)
CARD i,j
FOR i=0 TO 2
DO
FOR j=n(i) TO n(i)+25
DO
Nth(j,s)
PrintF("%S ",s)
OD
PutE() PutE()
OD
RETURN
```

- Output:

Screenshot from Atari 8-bit computer

0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 25'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 266'th 267'th 268'th 269'th 270'th 271'st 272'nd 273'rd 274'th 275'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th 1025'th

## Ada

```
with Ada.Text_IO;
procedure Nth is
function Suffix(N: Natural) return String is
begin
if N mod 10 = 1 and then N mod 100 /= 11 then return "st";
elsif N mod 10 = 2 and then N mod 100 /= 12 then return "nd";
elsif N mod 10 = 3 and then N mod 100 /= 13 then return "rd";
else return "th";
end if;
end Suffix;
procedure Print_Images(From, To: Natural) is
begin
for I in From .. To loop
Ada.Text_IO.Put(Natural'Image(I) & Suffix(I));
end loop;
Ada.Text_IO.New_Line;
end Print_Images;
begin
Print_Images( 0, 25);
Print_Images( 250, 265);
Print_Images(1000, 1025);
end Nth;
```

- Output:

## ALGOL 68

```
# PROC to suffix a number with st, nd, rd or th as appropriate #
PROC nth = ( INT number )STRING:
BEGIN
INT number mod 100 = number MOD 100;
# RESULT #
whole( number, 0 )
+ IF number mod 100 >= 10 AND number mod 100 <= 20
THEN
# numbers in the range 10 .. 20 always have "th" #
"th"
ELSE
# not in the range 10 .. 20, suffix is st, nd, rd or th #
# depending on the final digit #
CASE number MOD 10
IN # 1 # "st"
, # 2 # "nd"
, # 3 # "rd"
OUT "th"
ESAC
FI
END; # nth #
# PROC to test nth, displays nth for all numbers in the range from .. to #
PROC test nth = ( INT from, INT to )VOID:
BEGIN
INT test count := 0;
FOR test value FROM from TO to
DO
STRING test result = nth( test value );
print( ( " "[ 1 : 8 - UPB test result ], nth( test value ) ) );
test count +:= 1;
IF test count MOD 8 = 0
THEN
print( ( newline ) )
FI
OD;
print( ( newline ) )
END; # test nth #
main: (
test nth( 0, 25 );
test nth( 250, 265 );
test nth( 1000, 1025 )
)
```

- Output:

## ALGOL W

```
begin % suffix number with st, nd, rd or th as appropriate %
string(2) procedure ordinalSuffix ( integer value number ) ;
begin
integer numberRem100;
numberRem100 := number rem 100;
if numberRem100 >= 10 and numberRem100 <= 20 then begin
% numbers in the range 10 .. 20 always have "th" %
"th"
end
else begin
% not in the range 10 .. 20, suffix is st, nd, rd or th %
% depending on the final digit %
integer numberRem10;
numberRem10 := number rem 10;
if numberRem10 = 1 then "st"
else if numberRem10 = 2 then "nd"
else if numberRem10 = 3 then "rd"
else "th"
end if_numberRem100_in_10_to_20__
end ordinalSuffix ;
% tests ordinalSuffix, displays the suffix for all numbers in from .. to %
procedure testSuffix ( integer value from, to ) ;
begin
integer count;
count := 0;
for testValue := from until to do begin
writeon( i_w := 4, s_w := 0, " ", testValue, ordinalSuffix( testValue ) );
count := count + 1;
if count rem 8 = 0 then write()
end for_testValue ;
if count rem 8 not = 0 then write();
write()
end testSuffix ;
begin % task %
testSuffix( 0, 25 );
testSuffix( 250, 265 );
testSuffix( 1000, 1025 )
end
end.
```

- Output:

## APL

```
nth←{
sfx←4 2⍴'stndrdth'
tens←(10<100|⍵)∧20>100|⍵
(⍕⍵),sfx[(4×tens)⌈(⍳3)⍳10|⍵;]
}
```

- Output:

2 13⍴ nth¨ 0,⍳25 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 2 7⍴ nth¨ 250+0,⍳15 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 2 13⍴ nth¨ 1000+0,⍳25 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## AppleScript

```
-- ORDINAL STRINGS -----------------------------------------------------------
-- ordinalString :: Int -> String
on ordinalString(n)
(n as string) & ordinalSuffix(n)
end ordinalString
-- ordinalSuffix :: Int -> String
on ordinalSuffix(n)
set modHundred to n mod 100
if (11 ≤ modHundred) and (13 ≥ modHundred) then
"th"
else
item ((n mod 10) + 1) of ¬
{"th", "st", "nd", "rd", "th", "th", "th", "th", "th", "th"}
end if
end ordinalSuffix
-- TEST ----------------------------------------------------------------------
on run
-- showOrdinals :: [Int] -> [String]
script showOrdinals
on |λ|(lstInt)
map(ordinalString, lstInt)
end |λ|
end script
map(showOrdinals, ¬
map(uncurry(enumFromTo), ¬
[[0, 25], [250, 265], [1000, 1025]]))
end run
-- GENERIC FUNCTIONS ---------------------------------------------------------
-- enumFromTo :: Int -> Int -> [Int]
on enumFromTo(m, n)
if m > n then
set d to -1
else
set d to 1
end if
set lst to {}
repeat with i from m to n by d
set end of lst to i
end repeat
return lst
end enumFromTo
-- map :: (a -> b) -> [a] -> [b]
on map(f, xs)
tell mReturn(f)
set lng to length of xs
set lst to {}
repeat with i from 1 to lng
set end of lst to |λ|(item i of xs, i, xs)
end repeat
return lst
end tell
end map
-- Lift 2nd class handler function into 1st class script wrapper
-- mReturn :: Handler -> Script
on mReturn(f)
if class of f is script then
f
else
script
property |λ| : f
end script
end if
end mReturn
-- uncurry :: Handler (a -> b -> c) -> Script |λ| ((a, b) -> c)
on uncurry(f)
script
on |λ|(xy)
set {x, y} to xy
mReturn(f)'s |λ|(x, y)
end |λ|
end script
end uncurry
```

- Output:

{{"0th", "1st", "2nd", "3rd", "4th", "5th", "6th", "7th", "8th", "9th", "10th", "11th", "12th", "13th", "14th", "15th", "16th", "17th", "18th", "19th", "20th", "21st", "22nd", "23rd", "24th", "25th"}, {"250th", "251st", "252nd", "253rd", "254th", "255th", "256th", "257th", "258th", "259th", "260th", "261st", "262nd", "263rd", "264th", "265th"}, {"1000th", "1001st", "1002nd", "1003rd", "1004th", "1005th", "1006th", "1007th", "1008th", "1009th", "1010th", "1011th", "1012th", "1013th", "1014th", "1015th", "1016th", "1017th", "1018th", "1019th", "1020th", "1021st", "1022nd", "1023rd", "1024th", "1025th"}}

## Arturo

```
suffixes: ["th" "st" "nd" "rd" "th" "th" "th" "th" "th" "th"]
nth: function [n][
if? or? 100 >= n%100
20 < n%100
-> (to :string n) ++ "'" ++ suffixes\[n%10]
else -> (to :string n) ++ "'th"
]
loop range.step:250 0 1000 'j [
loop j..j+24 'i ->
prints (nth i)++" "
print ""
]
```

- Output:

0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'st 12'nd 13'rd 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 266'th 267'th 268'th 269'th 270'th 271'st 272'nd 273'rd 274'th 500'th 501'st 502'nd 503'rd 504'th 505'th 506'th 507'th 508'th 509'th 510'th 511'st 512'nd 513'rd 514'th 515'th 516'th 517'th 518'th 519'th 520'th 521'st 522'nd 523'rd 524'th 750'th 751'st 752'nd 753'rd 754'th 755'th 756'th 757'th 758'th 759'th 760'th 761'st 762'nd 763'rd 764'th 765'th 766'th 767'th 768'th 769'th 770'th 771'st 772'nd 773'rd 774'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'st 1012'nd 1013'rd 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th

## AutoHotkey

```
for k, v in [[0, 25], [250, 265], [1000, 1025]] {
while v[1] <= v[2] {
Out .= Ordinal(v[1]) " "
v[1]++
}
Out .= "`n"
}
MsgBox, % Out
Ordinal(n) {
s2 := Mod(n, 100)
if (s2 > 10 && s2 < 14)
return n "th"
s1 := Mod(n, 10)
return n (s1 = 1 ? "st" : s1 = 2 ? "nd" : s1 = 3 ? "rd" : "th")
}
```

- Output:

## AWK

```
# syntax: GAWK -f NTH.AWK
BEGIN {
prn(0,25)
prn(250,265)
prn(1000,1025)
exit(0)
}
function prn(start,stop, i) {
printf("%d-%d: ",start,stop)
for (i=start; i<=stop; i++) {
printf("%d%s ",i,nth(i))
}
printf("\n")
}
function nth(yearday, nthday) {
if (yearday ~ /1[1-3]$/) { # 11th,12th,13th
nthday = "th"
}
else if (yearday ~ /1$/) { # 1st,21st,31st,etc.
nthday = "st"
}
else if (yearday ~ /2$/) { # 2nd,22nd,32nd,etc.
nthday = "nd"
}
else if (yearday ~ /3$/) { # 3rd,23rd,33rd,etc.
nthday = "rd"
}
else if (yearday ~ /[0456789]$/) { # 4th-10th,20th,24th-30th,etc.
nthday = "th"
}
return(nthday)
}
```

- Output:

0-25: 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250-265: 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000-1025: 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## Babel

```
((irregular ("st" "nd" "rd"))
(main
{(0 250 1000)
{ test ! "\n" << }
each})
(test {
<-
{iter 1 - -> dup <- + ordinalify ! <<
{iter 10 %} {" "} {"\n"} ifte << }
26 times})
(ordinalify {
<-
{{ -> dup <- 100 % 10 cugt } !
{ -> dup <- 100 % 14 cult } !
and not
{ -> dup <- 10 % 0 cugt } !
{ -> dup <- 10 % 4 cult } !
and
and}
{ -> dup
<- %d "'"
irregular -> 10 % 1 - ith
. . }
{ -> %d "'th" . }
ifte }))
```

- Output:

25'th 24'th 23'rd 22'nd 21'st 20'th 19'th 18'th 17'th 16'th 15'th 14'th 13'th 12'th 11'th 10'th 9'th 8'th 7'th 6'th 5'th 4'th 3'rd 2'nd 1'st 0'th 275'th 274'th 273'rd 272'nd 271'st 270'th 269'th 268'th 267'th 266'th 265'th 264'th 263'rd 262'nd 261'st 260'th 259'th 258'th 257'th 256'th 255'th 254'th 253'rd 252'nd 251'st 250'th 1025'th 1024'th 1023'rd 1022'nd 1021'st 1020'th 1019'th 1018'th 1017'th 1016'th 1015'th 1014'th 1013'th 1012'th 1011'th 1010'th 1009'th 1008'th 1007'th 1006'th 1005'th 1004'th 1003'rd 1002'nd 1001'st 1000'th

## BASIC

### ANSI BASIC

```
100 REM Nth
110 DECLARE EXTERNAL FUNCTION Suffix$
120 DECLARE EXTERNAL SUB PrintImages
130 CALL PrintImages(0, 25)
140 CALL PrintImages(250, 265)
150 CALL PrintImages(1000, 1025)
160 END
170 REM
180 EXTERNAL SUB PrintImages(LoLim, HiLim)
190 FOR I = LoLim TO HiLim
200 PRINT STR$(I); Suffix$(I); " ";
210 NEXT I
220 PRINT
230 END SUB
240 REM
250 EXTERNAL FUNCTION Suffix$(N)
260 LET NMod10 = MOD(N, 10)
270 LET NMod100 = MOD(N, 100)
280 IF NMod10 = 1 AND NMod100 <> 11 THEN
290 LET Suffix$ = "st"
300 ELSEIF NMod10 = 2 AND NMod100 <> 12 THEN
310 LET Suffix$ = "nd"
320 ELSEIF NMod10 = 3 AND NMod100 <> 13 THEN
330 LET Suffix$ = "rd"
340 ELSE
350 LET Suffix$ = "th"
360 END IF
370 END FUNCTION
```

- Output:

### Applesoft BASIC

```
0 OP = 1
10 FOR N = 0 TO 25 : GOSUB 100 : NEXT
20 FOR N = 250 TO 265 : GOSUB 100 : NEXT
30 FOR N = 1000 TO 1025 : GOSUB 100 : NEXT
40 END
100 GOSUB 200"NTH
110 PRINT NTH$ " ";
120 RETURN
200 M1 = N - INT(N / 10) * 10
210 M2 = N - INT(N / 100) * 100
220 NTH$ = "TH"
230 IF M1 = 1 AND M2 <> 11 THEN NTH$ = "ST"
240 IF M1 = 2 AND M2 <> 12 THEN NTH$ = "ND"
250 IF M1 = 3 AND M2 <> 13 THEN NTH$ = "RD"
260 IF NOT OP THEN NTH$ = "'" + NTH$
270 NTH$ = STR$(N) + NTH$
280 RETURN
```

- Output:

0'TH 1'ST 2'ND 3'RD 4'TH 5'TH 6'TH 7'TH 8'TH 9'TH 10'TH 11'TH 12'TH 13'TH 14'TH 15'TH 16'TH 17'TH 18'TH 19'TH 20'TH 21'ST 22'ND 23'RD 24'TH 25'TH 250'TH 251'ST 252'ND 253'RD 254'TH 255'TH 256'TH 257'TH 258'TH 259'TH 260'TH 261'ST 262'ND 263'RD 264'TH 265'TH 1000'TH 1001'ST 1002'ND 1003'RD 1004'TH 1005'TH 1006'TH 1007'TH 1008'TH 1009'TH 1010'TH 1011'TH 1012'TH 1013'TH 1014'TH 1015'TH 1016'TH 1017'TH 1018'TH 1019'TH 1020'TH 1021'ST 1022'ND 1023'RD 1024'TH 1025'TH

### BaCon

```
' Nth (sans apostrophes)
FUNCTION nth$(NUMBER n) TYPE STRING
LOCAL suffix
IF n < 0 THEN RETURN STR$(n)
IF MOD(n, 100) >= 11 AND MOD(n, 100) <= 13 THEN
suffix = "th"
ELSE
suffix = MID$("thstndrdthththththth", MOD(n, 10) * 2 + 1, 2)
ENDIF
RETURN CONCAT$(STR$(n), suffix)
END FUNCTION
' Test a few ranges
FOR i = 1 TO 4
READ first, last
per = 1
FOR n = first TO last
PRINT nth$(n) FORMAT "%s "
' limit to 10 entries per line
IF per = 10 OR n = last THEN
per = 1
PRINT
ELSE
INCR per
ENDIF
NEXT
NEXT
DATA 0, 25, 250, 265, 1000, 1025, -20, -11
```

- Output:

prompt$ ./nth 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th -20 -19 -18 -17 -16 -15 -14 -13 -12 -11

### BASIC256

```
function ordinal(n)
ns$ = string(n)
begin case
case right(ns$, 1) = "1"
if right(ns$, 2) = "11" then return ns$ + "th"
return ns$ + "st"
case right(ns$, 1) = "2"
if right(ns$, 2) = "12" then return ns$ + "th"
return ns$ + "nd"
case right(ns$, 1) = "3"
if right(ns$, 2) = "13" then return ns$ + "th"
return ns$ + "rd"
else
return ns$ + "th"
end case
end function
subroutine imprimeOrdinal(a, b)
for i = a to b
print ordinal(i); " ";
next i
print
end subroutine
call imprimeOrdinal (0, 25)
call imprimeOrdinal (250, 265)
call imprimeOrdinal (1000, 1025)
end
```

### BBC BASIC

```
PROCNth( 0, 25)
PROCNth( 250, 265)
PROCNth(1000,1025)
END
DEF PROCNth(s%,e%)
LOCAL i%,suff$
FOR i%=s% TO e%
suff$="th"
IF i% MOD 10 = 1 AND i% MOD 100 <> 11 suff$="st"
IF i% MOD 10 = 2 AND i% MOD 100 <> 12 suff$="nd"
IF i% MOD 10 = 3 AND i% MOD 100 <> 13 suff$="rd"
PRINT STR$i%+suff$+" ";
NEXT
PRINT
ENDPROC
```

- Output:

### Chipmunk Basic

```
100 cls
110 imprimeordinal(0,25)
120 print : print
130 imprimeordinal(250,265)
140 print : print
150 imprimeordinal(1000,1025)
160 print
170 end
180 sub ordinal$(n)
190 ns$ = str$(n)
200 ordinal$ = ""
210 select case right$(ns$,1)
220 case "1"
230 if right$(ns$,2) = "11" then ordinal$ = ns$+"th" : goto 340
240 ordinal$ = ns$+"st" : goto 340
250 case "2"
260 if right$(ns$,2) = "12" then ordinal$ = ns$+"th" : goto 340
270 ordinal$ = ns$+"nd" : goto 340
280 case "3"
290 if right$(ns$,2) = "13" then ordinal$ = ns$+"th" : goto 340
300 ordinal$ = ns$+"rd" : goto 340
310 case else
320 ordinal$ = ns$+"th" : goto 340
330 end case
340 return
350 sub imprimeordinal(a,b)
360 for i = a to b
370 print ordinal$(i);" ";
380 next i
390 return
```

### Commodore BASIC

```
0 REM ROSETTACODE.ORG
1 REM N'TH
2 REM WRITE A FUNCTION/METHOD/SUBROUTINE/... THAT WHEN GIVEN AN INTEGER GREATER
3 REM THAN OR EQUAL TO ZERO RETURNS A STRING OF THE NUMBER FOLLOWED BY
4 REM AN APOSTROPHE THEN THE ORDINAL SUFFIX.
5 REM BASED ON APPLESOFT BASIC VERSION @ ROSETTACODE.ORG
6 REM
7 REM *************************
8 PRINT CHR$(14): REM CHANGE TO LOWER/UPPER CASE CHAR SET
9 OP = 1
10 FOR N = 0 TO 25 : GOSUB 100 : NEXT : PRINT
20 FOR N = 250 TO 265 : GOSUB 100 : NEXT : PRINT
30 FOR N = 1000 TO 1025 : GOSUB 100 : NEXT : PRINT
40 END
50 REM *************************
100 GOSUB 200
110 PRINT NTH$ " ";
120 RETURN
130 REM ************************
200 M1 = N - INT(N / 10) * 10
210 M2 = N - INT(N / 100) * 100
220 NTH$ = "TH"
230 IF M1 = 1 AND M2 <> 11 THEN NTH$ = "ST"
240 IF M1 = 2 AND M2 <> 12 THEN NTH$ = "ND"
250 IF M1 = 3 AND M2 <> 13 THEN NTH$ = "RD"
260 IF NOT OP THEN NTH$ = "'" + NTH$
270 NTH$ = STR$(N) + NTH$
280 RETURN
```

- Output:

Commodore 64 (40 column text)

0'th 1'st 2'nd 3'rd 4'th 5'th 6't h 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18' th 19'th 20'th 21'st 22'nd 23'rd 2 4'th 25'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 1000'th 1001'st 1002'nd 1003'rd 100 4'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 10 13'th 1014'th 1015'th 1016'th 1017't h 1018'th 1019'th 1020'th 1021'st 1 022'nd 1023'rd 1024'th 1025'th

### FreeBASIC

```
' FB 1.05.0 Win64
' Apostrophes NOT used as incorrect English
Function ordinal(n As UInteger) As String
Dim ns As String = Str(n)
Select Case Right(ns, 1)
Case "0", "4" To "9"
Return ns + "th"
Case "1"
If Right(ns, 2) = "11" Then Return ns + "th"
Return ns + "st"
Case "2"
If Right(ns, 2) = "12" Then Return ns + "th"
Return ns + "nd"
Case "3"
If Right(ns, 2) = "13" Then Return ns + "th"
Return ns + "rd"
End Select
End Function
Dim i As Integer
For i = 0 To 25
Print ordinal(i); " ";
Next
Print : Print
For i = 250 To 265
Print ordinal(i); " ";
Next
Print : Print
For i = 1000 To 1025
Print ordinal(i); " ";
Next
Print : Print
Print "Press any key to quit"
Sleep
```

- Output:

### Gambas

**Click this link to run this code**

```
Public Sub Main()
Dim siNums As Short[] = [0, 25, 250, 265, 1000, 1025]
Dim siCount, siNumbers As Short
Dim sOrdinal As String
For siNumbers = 0 To 4 Step 2
For siCount = siNums[siNumbers] To siNums[siNumbers + 1]
sOrdinal = "th"
If Right(Str(siCount), 1) = "1" And Right(Str(siCount), 2) <> "11" Then sOrdinal = "st"
If Right(Str(siCount), 1) = "2" And Right(Str(siCount), 2) <> "12" Then sOrdinal = "nd"
If Right(Str(siCount), 1) = "3" And Right(Str(siCount), 2) <> "13" Then sOrdinal = "rd"
Print siCount & sOrdinal;;
Next
Print gb.NewLine
Next
End
```

Output:

### GW-BASIC

```
10 ' N'th
20 LET LOLIM% = 0
30 LET HILIM% = 25
40 GOSUB 1000
50 LET LOLIM% = 250
60 LET HILIM% = 265
70 GOSUB 1000
80 LET LOLIM% = 1000
90 LET HILIM% = 1025
100 GOSUB 1000
110 END
995 ' Print images
1000 FOR I% = LOLIM% TO HILIM%
1010 LET NR% = I%
1020 GOSUB 1500
1030 LET SI$ = STR$(I%)
1040 PRINT RIGHT$(SI$, LEN(SI$) - 1); SUF$; " ";
1050 NEXT I%
1060 PRINT
1070 RETURN
1495 ' Get suffix
1500 IF (NR% MOD 10 = 1) AND (NR% MOD 100 <> 11) THEN LET SUF$ = "st": GOTO 2000
1600 IF (NR% MOD 10 = 2) AND (NR% MOD 100 <> 12) THEN LET SUF$ = "nd": GOTO 2000
1700 IF (NR% MOD 10 = 3) AND (NR% MOD 100 <> 13) THEN LET SUF$ = "rd": GOTO 2000
1800 LET SUF$ = "th"
2000 RETURN
```

- Output:

### Liberty BASIC

```
call printImages 0, 25
call printImages 250, 265
call printImages 1000, 1025
end
sub printImages loLim, hiLim
loLim = int(loLim)
hiLIm = int(hiLim)
for i = loLim to hiLim
print str$(i) + suffix$(i) + " ";
next i
print
end sub
function suffix$(n)
n = int(n)
nMod10 = n mod 10
nMod100 = n mod 100
if (nMod10 = 1) and (nMod100 <> 11) then
suffix$ = "st"
else
if (nMod10 = 2) and (nMod100 <> 12) then
suffix$ = "nd"
else
if (NMod10 = 3) and (NMod100 <> 13) then
suffix$ = "rd"
else
suffix$ = "th"
end if
end if
end if
end function
```

- Output:

0th 1st 2nd 3th 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23th 24th 25th 250th 251st 252nd 253th 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263th 264th 265th 1000th 1001st 1002nd 1003th 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023th 1024th 1025th

### Microsoft Small Basic

```
loLim = 0
hiLim = 25
PrintImages()
loLim = 250
hiLim = 265
PrintImages()
loLim = 1000
hiLim = 1025
PrintImages()
Sub PrintImages
For i = loLim To hiLim
nr = i
GetSuffix()
TextWindow.Write(i + suffix + " ")
EndFor
TextWindow.WriteLine("")
EndSub
Sub GetSuffix
rem10 = Math.Remainder(nr, 10)
rem100 = Math.Remainder(nr, 100)
If rem10 = 1 And rem100 <> 11 Then
suffix = "st"
ElseIf rem10 = 2 And rem100 <> 12 Then
suffix = "nd"
ElseIf rem10 = 3 And rem100 <> 13 Then
suffix = "rd"
Else
suffix = "th"
EndIf
EndSub
```

### Nascom BASIC

```
10 REM N'th
20 LOLIM=0
30 HILIM=25
40 GOSUB 1000
50 LOLIM=250
60 HILIM=265
70 GOSUB 1000
80 LOLIM=1000
90 HILIM=1025
100 GOSUB 1000
110 END
995 REM ** Print images
1000 FOR I=LOLIM TO HILIM
1010 NR=I
1020 GOSUB 1500
1030 SI$=STR$(I)
1040 PRINT RIGHT$(SI$,LEN(SI$)-1);SUF$;" ";
1050 NEXT I
1060 PRINT
1070 RETURN
1495 REM ** Get suffix
1500 LA=NR-INT(NR/10)*10:NLA=NR-INT(NR/100)*100
1510 IF LA=1 AND NLA<>11 THEN SUF$="st":RETURN
1520 IF LA=2 AND NLA<>12 THEN SUF$="nd":RETURN
1530 IF LA=3 AND NLA<>13 THEN SUF$="rd":RETURN
1540 SUF$="th"
1550 RETURN
```

- Output:

### PureBasic

```
Procedure.s Suffix(n.i)
Select n%10
Case 1 : If n%100<>11 : ProcedureReturn "st" : EndIf
Case 2 : If n%100<>12 : ProcedureReturn "nd" : EndIf
Case 3 : If n%100<>13 : ProcedureReturn "rd" : EndIf
EndSelect
ProcedureReturn "th"
EndProcedure
Procedure put(a.i,b.i)
For i=a To b : Print(Str(i)+Suffix(i)+" ") : Next
PrintN("")
EndProcedure
If OpenConsole()=0 : End 1 : EndIf
put(0,25)
put(250,265)
put(1000,1025)
Input()
```

- Output:

### QBasic

```
DECLARE FUNCTION sufijo$ (n%)
DECLARE SUB imprimeOrdinal (loLim%, hiLim%)
imprimeOrdinal 0, 25
imprimeOrdinal 250, 265
imprimeOrdinal 1000, 1025
END
DEFINT A-Z
SUB imprimeOrdinal (loLim, hiLim)
loLim = INT(loLim)
hiLim = INT(hiLim)
FOR i = loLim TO hiLim
PRINT STR$(i) + sufijo$(i) + " ";
NEXT i
PRINT
END SUB
FUNCTION sufijo$ (n)
n = INT(n)
NMod10 = n MOD 10
NMod100 = n MOD 100
IF (NMod10 = 1) AND (NMod100 <> 11) THEN
sufijo$ = "st"
ELSE
IF (NMod10 = 2) AND (NMod100 <> 12) THEN
sufijo$ = "nd"
ELSE
IF (NMod10 = 3) AND (NMod100 <> 13) THEN
sufijo$ = "rd"
ELSE
sufijo$ = "th"
END IF
END IF
END IF
END FUNCTION
```

### Run BASIC

The Liberty BASIC solution works without any changes.

### Sinclair ZX81 BASIC

Works flawlessly with 2k or more of RAM. With 1k, the subroutine itself works but you can't quite print all the tests: the program crashes with an 'out of memory' error code after 1017th. (A slightly less useful and readable version gets as far as 1023rd; 1025th is probably attainable, but might involve obfuscating the program more than is appropriate for this site.)

```
10 FOR N=0 TO 25
20 GOSUB 160
30 PRINT N$;" ";
40 NEXT N
50 PRINT
60 FOR N=250 TO 265
70 GOSUB 160
80 PRINT N$;" ";
90 NEXT N
100 PRINT
110 FOR N=1000 TO 1025
120 GOSUB 160
130 PRINT N$;" ";
140 NEXT N
150 STOP
160 LET N$=STR$ N
170 LET S$="TH"
180 IF LEN N$=1 THEN GOTO 200
190 IF N$(LEN N$-1)="1" THEN GOTO 230
200 IF N$(LEN N$)="1" THEN LET S$="ST"
210 IF N$(LEN N$)="2" THEN LET S$="ND"
220 IF N$(LEN N$)="3" THEN LET S$="RD"
230 LET N$=N$+S$
240 RETURN
```

- Output:

0TH 1ST 2ND 3RD 4TH 5TH 6TH 7TH 8TH 9TH 10TH 11TH 12TH 13TH 14TH 15TH 16TH 17TH 18TH 19TH 20TH 21ST 22ND 23RD 24TH 25TH 250TH 251ST 252ND 253RD 254TH 255TH 256TH 257TH 258TH 259TH 260TH 261ST 262ND 263RD 264TH 265TH 1000TH 1001ST 1002ND 1003RD 1004TH 1005TH 1006TH 1007TH 1008TH 1009TH 1010TH 1011TH 1012TH 1013TH 1014TH 1015TH 1016TH 1017TH 1018TH 1019TH 1020TH 1021ST 1022ND 1023RD 1024TH 1025TH

### True BASIC

```
SUB sufijo (n)
LET n = INT(n)
LET NMod10 = MOD(n, 10)
LET NMod100 = MOD(n, 100)
IF (NMod10 = 1) AND (NMod100 <> 11) THEN
LET sufi$ = "st"
ELSE
IF (NMod10 = 2) AND (NMod100 <> 12) THEN
LET sufi$ = "nd"
ELSE
IF (NMod10 = 3) AND (NMod100 <> 13) THEN
LET sufi$ = "rd"
ELSE
LET sufi$ = "th"
END IF
END IF
END IF
PRINT sufi$;
END SUB
SUB imprimeOrdinal (loLim, hiLim)
LET loLim = INT(loLim)
LET hiLim = INT(hiLim)
FOR i = loLim TO hiLim
PRINT i;
CALL sufijo (i)
PRINT " ";
NEXT i
PRINT
END SUB
CALL imprimeOrdinal (0, 25)
CALL imprimeOrdinal (250, 265)
CALL imprimeOrdinal (1000, 1025)
END
```

### uBasic/4tH

```
For x = 0 to 25 ' Test range 0..25
Push x : GoSub _PrintOrdinal
Next x : Print
For x = 250 to 265 ' Test range 250..265
Push x : GoSub _PrintOrdinal
Next x : Print
For x = 1000 to 1025 ' Test range 1000..1025
Push x : GoSub _PrintOrdinal
Next x : Print
End ' End test program
' ( n --)
_PrintOrdinal ' Ordinal subroutine
If Tos() > -1 Then ' If within range then
Print Using "____#";Tos();"'"; ' Print the number
' Take care of 11, 12 and 13
If (Tos()%100 > 10) * (Tos()%100 < 14) Then
Gosub (Pop() * 0) + 100 ' Clear stack and print "th"
Return ' We're done here
EndIf
Push Pop() % 10 ' Calculate n mod 10
GoSub 100 + 10 * ((Tos()>0) + (Tos()>1) + (Tos()>2) - (3 * (Pop()>3)))
Else ' And decide which ordinal to use
Print Pop();" is less than zero" ' Otherwise, it is an error
EndIf
Return
' Select and print proper ordinal
100 Print "th"; : Return
110 Print "st"; : Return
120 Print "nd"; : Return
130 Print "rd"; : Return
```

- Output:

0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 25'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th 1025'th

### VBA

```
Private Function ordinals() As Variant
ordinals = [{"th","st","nd","rd"}]
End Function
Private Function Nth(n As Variant, Optional apostrophe As Boolean = False) As String
Dim mod10 As Integer: mod10 = n Mod 10 + 1
If mod10 > 4 Or n Mod 100 = mod10 + 9 Then mod10 = 1
Nth = CStr(n) & String$(Val(-apostrophe), "'") & ordinals()(mod10)
End Function
Public Sub main()
Ranges = [{0,25;250,265;1000,1025}]
For i = 1 To UBound(Ranges)
For j = Ranges(i, 1) To Ranges(i, 2)
If j Mod 10 = 0 Then Debug.Print
Debug.Print Format(Nth(j, i = 2), "@@@@@@@");
Next j
Debug.Print
Next i
End Sub
```

- Output:

0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

### XBasic

```
PROGRAM "nth"
VERSION "0.0002"
DECLARE FUNCTION Entry()
INTERNAL FUNCTION Suffix$(n&&)
INTERNAL FUNCTION PrintImages (loLim&&, hiLim&&)
FUNCTION Entry()
PrintImages( 0, 25)
PrintImages( 250, 265)
PrintImages(1000, 1025)
END FUNCTION
FUNCTION Suffix$(n&&)
nMod10@@ = n&& MOD 10
nMod100@@ = n&& MOD 100
SELECT CASE TRUE
CASE (nMod10@@ = 1) AND (nMod100@@ <> 11):
RETURN ("st")
CASE (nMod10@@ = 2) AND (nMod100@@ <> 12):
RETURN ("nd")
CASE (nMod10@@ = 3) AND (nMod100@@ <> 13):
RETURN ("rd")
CASE ELSE:
RETURN ("th")
END SELECT
END FUNCTION
FUNCTION PrintImages(loLim&&, hiLim&&)
FOR i&& = loLim&& TO hiLim&&
PRINT TRIM$(STRING$(i&&)); Suffix$(i&&); " ";
NEXT
PRINT
END FUNCTION
END PROGRAM
```

- Output:

### Yabasic

```
sub ordinal$ (n)
NMod10 = mod(n, 10)
NMod100 = mod(n, 100)
if (NMod10 = 1) and (NMod100 <> 11) then
return "st"
else
if (NMod10 = 2) and (NMod100 <> 12) then
return "nd"
else
if (NMod10 = 3) and (NMod100 <> 13) then
return "rd"
else
return "th"
end if
end if
end if
end sub
sub imprimeOrdinal(a, b)
for i = a to b
print i, ordinal$(i), " ";
next i
print
end sub
imprimeOrdinal (0, 25)
imprimeOrdinal (250, 265)
imprimeOrdinal (1000, 1025)
end
```

### ZX Spectrum Basic

```
10 FOR n=0 TO 25
20 GO SUB 140
30 PRINT n$;" ";
40 NEXT n
50 FOR n=250 TO 265
60 GO SUB 140
70 PRINT n$;" ";
80 NEXT n
90 FOR n=1000 TO 1025
100 GO SUB 140
110 PRINT n$;" ";
120 NEXT n
130 STOP
140 LET s$="th"
150 LET n$=STR$ n
160 IF LEN n$=1 THEN GO TO 180
170 IF n$(LEN n$-1)="1" THEN GO TO 210
180 IF n$(LEN n$)="1" THEN LET s$="st"
190 IF n$(LEN n$)="2" THEN LET s$="nd"
200 IF n$(LEN n$)="3" THEN LET s$="rd"
210 LET n$=n$+s$
220 RETURN
```

- Output:

## Batch File

```
@echo off
::Main thing...
call :Nth 0 25
call :Nth 250 265
call :Nth 1000 1025
pause
exit /b
::The subroutine
:Nth <lbound> <ubound>
setlocal enabledelayedexpansion
for /l %%n in (%~1,1,%~2) do (
set curr_num=%%n
if !curr_num:~-2!==11 (set "out=%%nth"
) else if !curr_num:~-2!==12 (set "out=%%nth"
) else if !curr_num:~-2!==13 (set "out=%%nth"
) else if !curr_num:~-1!==1 (set "out=%%nst"
) else if !curr_num:~-1!==2 (set "out=%%nnd"
) else if !curr_num:~-1!==3 (set "out=%%nrd"
) else (set "out=%%nth")
set "range_output=!range_output! !out!"
)
echo."!range_output:~1!"
goto :EOF
```

- Output:

"0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th" "250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th" "1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th" Press any key to continue . . .

## BCPL

```
get "libhdr"
// Generate ASCII string of number n with ordinal suffix
// The string is stored at v.
let nth(n, v) = valof
$( let sfx = "thstndrd"
let c, s = 0, ?
// Generate digits
$( c := c + 1
v%c := n rem 10 + '0'
n := n / 10
$) repeatuntil n = 0
// Put digits in correct order
for i = 1 to c/2 do
$( let d = v%i
v%i := v%(c+1-i)
v%(c+1-i) := d
$)
// The length of the string is the amount of digits + 2
v%0 := c+2;
// Figure out the proper suffix from the last two digits
test v%(c-1)='1' | v%c>'3'
then s := 0
else s := 2*(v%c - '0')
v%(c+1) := sfx%(s+1)
v%(c+2) := sfx%(s+2)
resultis v
$)
let start() be
$( let buf = vec 10
for i = 0 to 25 do writef("%S*N", nth(i, buf))
for i = 250 to 265 do writef("%S*N", nth(i, buf))
for i = 1000 to 1025 do writef("%S*N", nth(i, buf))
$)
```

- Output:

## Befunge

The bottom section of code contains the "subroutine" that calculates the ordinal of a given number; the top section generates the list of values to test.

```
0>55*:>1-\:0\`!v
#v$#$<^:\+*8"}"_
>35*:>1-\:0\`!v
#v$#$<^:\+*2"}"_
5< v$_v#!::-<0*5
@v <,*>#81#4^# _
>>:0\>:55+%68*v:
tsnr |:/+ 55\+<,
htdd >$>:#,_$:vg
v"d"\*!`3:%+55<9
>%55+/1-!!*:8g,^
```

- Output:

## BQN

```
Nth ← {
sfx ← ⟨"th","st","nd","rd"⟩
(•Fmt 𝕩)∾sfx⊑˜ (1≠10|⌊𝕩÷10)×(3≥10|𝕩)×10|𝕩
}
∘‿4⥊ Nth¨ (↕26) ∾ (250+↕16) ∾ (1000+↕26)
```

- Output:

┌─ ╵ "0th" "1st" "2nd" "3rd" "4th" "5th" "6th" "7th" "8th" "9th" "10th" "11th" "12th" "13th" "14th" "15th" "16th" "17th" "18th" "19th" "20th" "21st" "22nd" "23rd" "24th" "25th" "250th" "251st" "252nd" "253rd" "254th" "255th" "256th" "257th" "258th" "259th" "260th" "261st" "262nd" "263rd" "264th" "265th" "1000th" "1001st" "1002nd" "1003rd" "1004th" "1005th" "1006th" "1007th" "1008th" "1009th" "1010th" "1011th" "1012th" "1013th" "1014th" "1015th" "1016th" "1017th" "1018th" "1019th" "1020th" "1021st" "1022nd" "1023rd" "1024th" "1025th" ┘

## C

```
#include <stdio.h>
char* addSuffix(int num, char* buf, size_t len)
{
char *suffixes[4] = { "th", "st", "nd", "rd" };
int i;
switch (num % 10)
{
case 1 : i = (num % 100 == 11) ? 0 : 1;
break;
case 2 : i = (num % 100 == 12) ? 0 : 2;
break;
case 3 : i = (num % 100 == 13) ? 0 : 3;
break;
default: i = 0;
};
snprintf(buf, len, "%d%s", num, suffixes[i]);
return buf;
}
int main(void)
{
int i;
printf("Set [0,25]:\n");
for (i = 0; i < 26; i++)
{
char s[5];
printf("%s ", addSuffix(i, s, 5));
}
putchar('\n');
printf("Set [250,265]:\n");
for (i = 250; i < 266; i++)
{
char s[6];
printf("%s ", addSuffix(i, s, 6));
}
putchar('\n');
printf("Set [1000,1025]:\n");
for (i = 1000; i < 1026; i++)
{
char s[7];
printf("%s ", addSuffix(i, s, 7));
}
putchar('\n');
return 0;
}
```

Another method with dynamic memory allocation

```
#include <stdlib.h>
#include <stdio.h>
static int digits(const int x) {
if (x / 10 == 0) return 1;
return 1 + digits(x / 10);
}
static char * get_ordinal(const int i) {
const int string_size = digits(i) + 3;
char * o_number = malloc(string_size);
char * ordinal;
if(i % 100 >= 11 && i % 100 <= 13) ordinal = "th";
else ordinal = i/10==1?"th":i%10==1?"st":i%10==2?"nd":i%10==3?"rd":"th";
sprintf_s(o_number, string_size, "%d%s", i, ordinal);
return o_number;
}
static void print_range(const int begin, const int end) {
printf("Set [%d,%d]:\n", begin, end);
for (int i = begin; i <= end; i++) {
char * o_number = get_ordinal(i);
printf("%s ", o_number);
free(o_number);
}
printf("\n");
}
int main(void) {
print_range(0, 25);
print_range(250, 265);
print_range(1000, 1025);
}
```

- Output:

Set [0,25] : 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th Set [250,265] : 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th Set [1000,1025] : 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## C#

```
using System;
using System.Linq;
class Program
{
private static string Ordinalize(int i)
{
i = Math.Abs(i);
if (new[] {11, 12, 13}.Contains(i%100))
return i + "th";
switch (i%10)
{
case 1:
return i + "st";
case 2:
return i + "nd";
case 3:
return i + "rd";
default:
return i + "th";
}
}
static void Main()
{
Console.WriteLine(string.Join(" ", Enumerable.Range(0, 26).Select(Ordinalize)));
Console.WriteLine(string.Join(" ", Enumerable.Range(250, 16).Select(Ordinalize)));
Console.WriteLine(string.Join(" ", Enumerable.Range(1000, 26).Select(Ordinalize)));
}
}
```

Dotnet 5 version without LINQ

```
using System;
static string Ordinalize(int i)
{
return i + (
i % 100 is >= 11 and <= 13 ? "th" :
i % 10 == 1 ? "st" :
i % 10 == 2 ? "nd" :
i % 10 == 3 ? "rd" :
"th");
}
static void PrintRange(int begin, int end)
{
for(var i = begin; i <= end; i++)
Console.Write(Ordinalize(i) + (i == end ? "" : " "));
Console.WriteLine();
}
PrintRange(0, 25);
PrintRange(250, 265);
PrintRange(1000, 1025);
```

- Output:

## C++

```
#include <string>
#include <iostream>
using namespace std;
string Suffix(int num)
{
switch (num % 10)
{
case 1 : if(num % 100 != 11) return "st";
break;
case 2 : if(num % 100 != 12) return "nd";
break;
case 3 : if(num % 100 != 13) return "rd";
}
return "th";
}
int main()
{
cout << "Set [0,25]:" << endl;
for (int i = 0; i < 26; i++)
cout << i << Suffix(i) << " ";
cout << endl;
cout << "Set [250,265]:" << endl;
for (int i = 250; i < 266; i++)
cout << i << Suffix(i) << " ";
cout << endl;
cout << "Set [1000,1025]:" << endl;
for (int i = 1000; i < 1026; i++)
cout << i << Suffix(i) << " ";
cout << endl;
return 0;
}
```

- Output:

Set [0,25] : 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th Set [250,265] : 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th Set [1000,1025] : 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## Clojure

```
(defn n-th [n]
(str n
(let [rem (mod n 100)]
(if (and (>= rem 11) (<= rem 13))
"th"
(condp = (mod n 10)
1 "st"
2 "nd"
3 "rd"
"th")))))
(apply str (interpose " " (map n-th (range 0 26))))
(apply str (interpose " " (map n-th (range 250 266))))
(apply str (interpose " " (map n-th (range 1000 1026))))
```

- Output:

"0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th" "250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th" "1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th"

Alternatively, if you want to print the full ordinal English, it becomes trivial with pprint:

```
(apply str (interpose " " (map #(clojure.pprint/cl-format nil "~:R" %) (range 0 26))))
```

- Output:

"zeroth first second third fourth fifth sixth seventh eighth ninth tenth eleventh twelfth thirteenth fourteenth fifteenth sixteenth seventeenth eighteenth nineteenth twentieth twenty-first twenty-second twenty-third twenty-fourth twenty-fifth"

## CLU

```
nth = proc (n: int) returns (string)
num: string := int$unparse(n)
sfx: array[string] := array[string]$[0: "th", "st", "nd", "rd"]
if n / 10 // 10 = 1 cor n // 10 > 3 then
return(num || sfx[0])
else
return(num || sfx[n // 10])
end
end nth
do_range = proc (from, to: int)
po: stream := stream$primary_output()
col: int := 0
for i: int in int$from_to(from,to) do
stream$putleft(po, nth(i), 7)
col := col + 1
if col = 10 then
stream$putc(po, '\n')
col := 0
end
end
stream$putl(po, "\n")
end do_range
start_up = proc ()
do_range(0,25)
do_range(250,265)
do_range(1000,1025)
end start_up
```

- Output:

## COBOL

COBOL stores numbers in decimal form, so there is no need to use a modulo function: the last digit or the last two digits can be extracted directly.

```
IDENTIFICATION DIVISION.
PROGRAM-ID. NTH-PROGRAM.
DATA DIVISION.
WORKING-STORAGE SECTION.
01 WS-NUMBER.
05 N PIC 9(8).
05 LAST-TWO-DIGITS PIC 99.
05 LAST-DIGIT PIC 9.
05 N-TO-OUTPUT PIC Z(7)9.
05 SUFFIX PIC AA.
PROCEDURE DIVISION.
TEST-PARAGRAPH.
PERFORM NTH-PARAGRAPH VARYING N FROM 0 BY 1 UNTIL N IS GREATER THAN 25.
PERFORM NTH-PARAGRAPH VARYING N FROM 250 BY 1 UNTIL N IS GREATER THAN 265.
PERFORM NTH-PARAGRAPH VARYING N FROM 1000 BY 1 UNTIL N IS GREATER THAN 1025.
STOP RUN.
NTH-PARAGRAPH.
MOVE 'TH' TO SUFFIX.
MOVE N (7:2) TO LAST-TWO-DIGITS.
IF LAST-TWO-DIGITS IS LESS THAN 4,
OR LAST-TWO-DIGITS IS GREATER THAN 20,
THEN PERFORM DECISION-PARAGRAPH.
MOVE N TO N-TO-OUTPUT.
DISPLAY N-TO-OUTPUT WITH NO ADVANCING.
DISPLAY SUFFIX WITH NO ADVANCING.
DISPLAY SPACE WITH NO ADVANCING.
DECISION-PARAGRAPH.
MOVE N (8:1) TO LAST-DIGIT.
IF LAST-DIGIT IS EQUAL TO 1 THEN MOVE 'ST' TO SUFFIX.
IF LAST-DIGIT IS EQUAL TO 2 THEN MOVE 'ND' TO SUFFIX.
IF LAST-DIGIT IS EQUAL TO 3 THEN MOVE 'RD' TO SUFFIX.
```

Output:

0TH 1ST 2ND 3RD 4TH 5TH 6TH 7TH 8TH 9TH 10TH 11TH 12TH 13TH 14TH 15TH 16TH 17TH 18TH 19TH 20TH 21ST 22ND 23RD 24TH 25TH 250TH 251ST 252ND 253RD 254TH 255TH 256TH 257TH 258TH 259TH 260TH 261ST 262ND 263RD 264TH 265TH 1000TH 1001ST 1002ND 1003RD 1004TH 1005TH 1006TH 1007TH 1008TH 1009TH 1010TH 1011TH 1012TH 1013TH 1014TH 1015TH 1016TH 1017TH 1018TH 1019TH 1020TH 1021ST 1022ND 1023RD 1024TH 1025TH

## Common Lisp

```
(defun add-suffix (number)
(let* ((suffixes #10("th" "st" "nd" "rd" "th"))
(last2 (mod number 100))
(last-digit (mod number 10))
(suffix (if (< 10 last2 20)
"th"
(svref suffixes last-digit))))
(format nil "~a~a" number suffix)))
```

A more concise, albeit less readable version:

```
(defun add-suffix (n)
(format nil "~d'~:[~[th~;st~;nd~;rd~:;th~]~;th~]" n (< (mod (- n 10) 100) 10) (mod n 10)))
```

Display the results:

```
(loop for (low high) in '((0 25) (250 265) (1000 1025))
do (progn
(format t "~a to ~a: " low high)
(loop for n from low to high
do (format t "~a " (add-suffix n))
finally (terpri))))
```

- Output:

0 to 25: 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250 to 265: 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000 to 1025: 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## Cowgol

```
include "cowgol.coh";
include "strings.coh";
# Given an int32, return decimal string and add an ordinal suffix
sub ordsfx(n: int32, buf: [uint8]): (out: [uint8]) is
var sfx: [uint8][] := {"th", "st", "nd", "rd"};
out := buf;
buf := IToA(n, 10, buf); # IToA is included in standard library
# Since we now already have the digits, we can make the decision
# without doing any more work.
if (n > 10 and [@prev @prev buf] == '1')
or ([@prev buf] > '3') then
CopyString(sfx[0], buf);
else
CopyString(sfx[[@prev buf]-'0'], buf);
end if;
end sub;
# Print suffixed numerals from start to end inclusive
sub test(start: int32, end_: int32) is
var buf: uint8[16]; # buffer
var n: uint8 := 10;
while start <= end_ loop
print(ordsfx(start, &buf[0]));
print_char(' ');
start := start + 1;
n := n - 1;
if n == 0 then
print_nl();
n := 10;
end if;
end loop;
print_nl();
end sub;
test(0, 25);
test(250,265);
test(1000,1025);
```

- Output:

## Crystal

```
struct Int
def ordinalize
num = self.abs
ordinal = if (11..13).includes?(num % 100)
"th"
else
case num % 10
when 1; "st"
when 2; "nd"
when 3; "rd"
else "th"
end
end
"#{self}#{ordinal}"
end
end
[(0..25),(250..265),(1000..1025)].each{|r| puts r.map{ |n| n.ordinalize }.join(", "); puts}
```

- Output:

0th, 1st, 2nd, 3rd, 4th, 5th, 6th, 7th, 8th, 9th, 10th, 11th, 12th, 13th, 14th, 15th, 16th, 17th, 18th, 19th, 20th, 21st, 22nd, 23rd, 24th, 25th 250th, 251st, 252nd, 253rd, 254th, 255th, 256th, 257th, 258th, 259th, 260th, 261st, 262nd, 263rd, 264th, 265th 1000th, 1001st, 1002nd, 1003rd, 1004th, 1005th, 1006th, 1007th, 1008th, 1009th, 1010th, 1011th, 1012th, 1013th, 1014th, 1015th, 1016th, 1017th, 1018th, 1019th, 1020th, 1021st, 1022nd, 1023rd, 1024th, 1025th

## D

```
import std.stdio, std.string, std.range, std.algorithm;
string nth(in uint n) pure {
static immutable suffix = "th st nd rd th th th th th th".split;
return "%d'%s".format(n, (n % 100 <= 10 || n % 100 > 20) ?
suffix[n % 10] : "th");
}
void main() {
foreach (r; [iota(26), iota(250, 266), iota(1000, 1026)])
writefln("%-(%s %)", r.map!nth);
}
```

- Output:

0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 25'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th 1025'th

## Delphi

See Pascal.

## Draco

```
proc nonrec nth(word n; *char buf) *char:
channel output text ch;
open(ch, buf);
write(ch; n,
if (n/10)%10=1 then "th"
elif n%10=1 then "st"
elif n%10=2 then "nd"
elif n%10=3 then "rd"
else "th"
fi
);
close(ch);
buf
corp;
proc nonrec print_range(word start, stop) void:
[8] char buf;
word col, n;
col := 0;
for n from start upto stop do
write(nth(n, &buf[0]));
col := col + 1;
if col%10=0 then writeln() else write('\t') fi
od;
writeln()
corp
proc nonrec main() void:
print_range(0, 25);
print_range(250, 265);
print_range(1000, 1025)
corp
```

- Output:

## EasyLang

```
func$ nth num .
last2 = num mod 100
last = num mod 10
if last2 >= 11 and last2 <= 13
return num & "th"
elif last = 1
return num & "st"
elif last = 2
return num & "nd"
elif last = 3
return num & "rd"
else
return num & "th"
.
.
print "0 to 25:"
for i = 0 to 25
write nth i & " "
.
print ""
print "250 to 265:"
for i = 250 to 265
write nth i & " "
.
print ""
print "1000 to 1025:"
for i = 1000 to 1025
write nth i & " "
.
```

- Output:

0 to 25: 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250 to 265: 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000 to 1025: 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## Elena

ELENA 6.x :

```
import extensions;
import system'math;
import system'routines;
extension op
{
ordinalize()
{
int i := self.Absolute;
if (new int[]{11,12,13}.ifExists(i.mod(100)))
{
^ i.toPrintable() + "th"
};
(i.mod(10)) =>
1 { ^ i.toPrintable() + "st" }
2 { ^ i.toPrintable() + "nd" }
3 { ^ i.toPrintable() + "rd" };
^ i.toPrintable() + "th"
}
}
public program()
{
console.printLine(new Range(0,26).selectBy(mssgconst ordinalize<op>[1]));
console.printLine(new Range(250,26).selectBy(mssgconst ordinalize<op>[1]));
console.printLine(new Range(1000,26).selectBy(mssgconst ordinalize<op>[1]))
}
```

- Output:

0th,1st,2nd,3rd,4th,5th,6th,7th,8th,9th,10th,11th,12th,13th,14th,15th,16th,17th,18th,19th,20th,21st,22nd,23rd,24th,25th 250th,251st,252nd,253rd,254th,255th,256th,257th,258th,259th,260th,261st,262nd,263rd,264th,265th,266th,267th,268th,269th,270th,271st,272nd,273rd,274th,275th 1000th,1001st,1002nd,1003rd,1004th,1005th,1006th,1007th,1008th,1009th,1010th,1011th,1012th,1013th,1014th,1015th,1016th,1017th,1018th,1019th,1020th,1021st,1022nd,1023rd,1024th,1025th

## Elixir

```
defmodule RC do
def ordinalize(n) do
num = abs(n)
ordinal = if rem(num, 100) in 4..20 do
"th"
else
case rem(num, 10) do
1 -> "st"
2 -> "nd"
3 -> "rd"
_ -> "th"
end
end
"#{n}#{ordinal}"
end
end
Enum.each([0..25, 250..265, 1000..1025], fn range ->
Enum.map(range, fn n -> RC.ordinalize(n) end) |> Enum.join(" ") |> IO.puts
end)
```

- Output:

## ERRE

```
PROGRAM NTH_SOLVE
!
! for rosettacode.org
!
PROCEDURE NTH(S%,E%)
LOCAL I%,SUFF$
FOR I%=S% TO E% DO
SUFF$="th"
IF I% MOD 10=1 AND I% MOD 100<>11 THEN SUFF$="st" END IF
IF I% MOD 10=2 AND I% MOD 100<>12 THEN SUFF$="nd" END IF
IF I% MOD 10=3 AND I% MOD 100<>13 THEN SUFF$="rd" END IF
PRINT(STR$(I%)+SUFF$+" ";)
END FOR
PRINT
END PROCEDURE
BEGIN
NTH(0,25)
NTH(250,265)
NTH(1000,1025)
END PROGRAM
```

- Output:

## F#

```
open System
let ordinalsuffix n =
let suffixstrings = [|"th"; "st"; "nd"; "rd"|]
let (d, r) = Math.DivRem(n, 10)
n.ToString() + suffixstrings.[ if r < 4 && (d &&& 1) = 0 then r else 0 ]
[<EntryPoint>]
let main argv =
let show = (Seq.iter (ordinalsuffix >> (printf " %s"))) >> (Console.WriteLine)
[0..25] |> show
[250..265] |> show
[1000..1025] |> show
0
```

- Output:

0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251th 252th 253th 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## Factor

```
USING: io kernel math math.order math.parser math.ranges qw
sequences ;
IN: rosetta-code.nth
: n'th ( n -- str )
dup 10 /mod swap 1 = [ drop 0 ] when
[ number>string ]
[ 4 min qw{ th st nd rd th } nth ] bi* append ;
: n'th-demo ( -- )
0 25 250 265 1000 1025 [ [a,b] ] 2tri@
[ [ n'th write bl ] each nl ] tri@ ;
MAIN: n'th-demo
```

- Output:

## Fennel

```
(fn get-suffix [n]
(let [last-two (% n 100)
last-one (% n 10)]
(if (and (> last-two 3) (< last-two 21)) :th
(= last-one 1) :st
(= last-one 2) :nd
(= last-one 3) :rd
:th)))
(fn nth [n]
(.. n "'" (get-suffix n)))
(for [i 0 25]
(print (nth i) (nth (+ i 250)) (nth (+ i 1000))))
```

- Output:

Same as Lua.

## Forth

```
: 'nth ( -- c-addr ) s" th st nd rd th th th th th th " drop ;
: .nth ( n -- )
dup 100 mod 10 20 within if 0 .r ." th " exit then
dup 0 .r 10 mod 3 * 'nth + 3 type ;
: test ( n n -- ) cr do i 5 mod 0= if cr then i .nth loop ;
: tests ( -- )
26 0 test 266 250 test 1026 1000 test ;
tests
```

- Output:

0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1022th ok

## Fortran

THE INSTRUCTIONS! Write a function/method/subroutine/... that when given an integer greater than or equal to zero returns a string of the number followed by an apostrophe then the ordinal suffix. Example returns would include 1'st 2'nd 3'rd 11'th 111'th 1001'st 1012'th

Please find the compilation instructions and examples in comments at the start of the source.

```
!-*- mode: compilation; default-directory: "/tmp/" -*-
!Compilation started at Fri Jun 6 15:40:18
!
!a=./f && make -k $a && echo 0 25 | $a && echo 250 265 | $a && echo 1000 1025 | $a
!gfortran -std=f2008 -Wall -fopenmp -ffree-form -fall-intrinsics -fimplicit-none -g f.f08 -o f
! 0'th 1'st 2'nd
! 3'rd 4'th 5'th
! 6'th 7'th 8'th
! 9'th 10'th 11'th
! 12'th 13'th 14'th
! 15'th 16'th 17'th
! 18'th 19'th 20'th
! 21'st 22'nd 23'rd
! 24'th 25'th
! 250'th 251'st
! 252'nd 253'rd 254'th
! 255'th 256'th 257'th
! 258'th 259'th 260'th
! 261'st 262'nd 263'rd
! 264'th 265'th
! 1000th 1001st
! 1002nd 1003rd 1004th
! 1005th 1006th 1007th
! 1008th 1009th 1010th
! 1011th 1012th 1013th
! 1014th 1015th 1016th
! 1017th 1018th 1019th
! 1020th 1021st 1022nd
! 1023rd 1024th 1025th
!
!Compilation finished at Fri Jun 6 15:40:18
program nth
implicit none
logical :: need
integer :: here, there, n, i, iostat
read(5,*,iostat=iostat) here, there
if (iostat .ne. 0) then
write(6,*)'such bad input never before seen.'
write(6,*)'I AYE EYE QUIT!'
call exit(1)
end if
need = .false.
n = abs(there - here) + 1
i = 0
do while (0 /= mod(3+mod(here-i, 3), 3))
write(6,'(a22)',advance='no') ''
i = i+1
end do
do i = here, there, sign(1, there-here)
write(6,'(a22)',advance='no') ordinate(i)
if (2 /= mod(i,3)) then
need = .true.
else
write(6,'(a)')''
need = .false.
end if
end do
if (need) write(6,'(a)')''
contains
character(len=22) function ordinate(n)
character(len=19) :: a
character(len=20), parameter :: &
&a09 = "thstndrdthththththth",&
&ateen = "thththththththththth"
integer :: ones, tens, ones_index
integer, intent(in) :: n
write(a,'(i19)') n
ones = mod(n,10)
tens = mod(n,100)
ones_index = ones*2+1
if (n < 1000) then
if ((10 .le. tens) .and. (tens .lt. 20)) then
ordinate = a // "'" // ateen(ones_index:ones_index+1)
! ^^^^^^ remove these characters to remove the important '
else
ordinate = a // "'" // a09(ones_index:ones_index+1)
! ^^^^^^ remove these characters to remove the important '
end if
else
if ((10 .le. tens) .and. (tens .lt. 20)) then
ordinate = a // ateen(ones_index:ones_index+1)
else
ordinate = a // a09(ones_index:ones_index+1)
end if
end if
end function ordinate
end program nth
```

## Go

```
package main
import "fmt"
func ord(n int) string {
s := "th"
switch c := n % 10; c {
case 1, 2, 3:
if n%100/10 == 1 {
break
}
switch c {
case 1:
s = "st"
case 2:
s = "nd"
case 3:
s = "rd"
}
}
return fmt.Sprintf("%d%s", n, s)
}
func main() {
for n := 0; n <= 25; n++ {
fmt.Printf("%s ", ord(n))
}
fmt.Println()
for n := 250; n <= 265; n++ {
fmt.Printf("%s ", ord(n))
}
fmt.Println()
for n := 1000; n <= 1025; n++ {
fmt.Printf("%s ", ord(n))
}
fmt.Println()
}
```

- Output:

## Haskell

```
import Data.Array
ordSuffs :: Array Integer String
ordSuffs = listArray (0,9) ["th", "st", "nd", "rd", "th",
"th", "th", "th", "th", "th"]
ordSuff :: Integer -> String
ordSuff n = show n ++ suff n
where suff m | (m `rem` 100) >= 11 && (m `rem` 100) <= 13 = "th"
| otherwise = ordSuffs ! (m `rem` 10)
printOrdSuffs :: [Integer] -> IO ()
printOrdSuffs = putStrLn . unwords . map ordSuff
main :: IO ()
main = do
printOrdSuffs [ 0.. 25]
printOrdSuffs [ 250.. 265]
printOrdSuffs [1000..1025]
```

- Output:

## Icon and Unicon

The following works in both languages.

```
procedure main(A)
every writes(" ",nth(0 to 25) | "\n")
every writes(" ",nth(250 to 265) | "\n")
every writes(" ",nth(1000 to 1025) | "\n")
end
procedure nth(n)
return n || ((n%10 = 1, n%100 ~= 11, "st") |
(n%10 = 2, n%100 ~= 12, "nd") |
(n%10 = 3, n%100 ~= 13, "rd") | "th")
end
```

- Output:

->nth 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13h 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013h 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th ->

## Insitux

```
(function ordinal n
(if ([11 12 13] (rem n 100))
(str n "th")
(str n (or ((rem n 10) ["th" "st" "nd" "rd"]) "th"))))
(function line x y
(-> (range x y)
(map (comp ordinal (pad-left " " 6)))
(join " ")))
(.. str (line 0 13) "\n" (line 1000 1013)
"\n\n" (line 13 26) "\n" (line 1013 1026)
"\n\n" (line 250 266))
```

- Output:

0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th

## J

Implementation:

```
suf=: (;:'th st nd rd th') {::~ 4 <. 10 10 (* 1&~:)~/@#: ]
nth=: [: ;:inv (": , suf)each
```

Task:

```
thru=: <./ + i.@(+ *)@-~
nth 0 thru 25
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th
nth 250 thru 265
250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th
nth 1000 thru 1025
1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
```

## Java

```
public class Nth {
public static String ordinalAbbrev(int n){
String ans = "th"; //most of the time it should be "th"
if(n % 100 / 10 == 1) return ans; //teens are all "th"
switch(n % 10){
case 1: ans = "st"; break;
case 2: ans = "nd"; break;
case 3: ans = "rd"; break;
}
return ans;
}
public static void main(String[] args){
for(int i = 0; i <= 25;i++){
System.out.print(i + ordinalAbbrev(i) + " ");
}
System.out.println();
for(int i = 250; i <= 265;i++){
System.out.print(i + ordinalAbbrev(i) + " ");
}
System.out.println();
for(int i = 1000; i <= 1025;i++){
System.out.print(i + ordinalAbbrev(i) + " ");
}
}
}
```

```
package nth;
import java.util.stream.IntStream;
import java.util.stream.Stream;
public interface Nth {
public static String suffix(int n){
if(n % 100 / 10 == 1){
return "th"; //teens are all "th"
}
switch(n % 10){
case 1: return "st";
case 2: return "nd";
case 3: return "rd";
default: return "th"; //most of the time it should be "th"
}
}
public static void print(int start, int end) {
IntStream.rangeClosed(start, end)
.parallel()
.mapToObj(i -> i + suffix(i) + " ")
.reduce(String::concat)
.ifPresent(System.out::println)
;
}
public static void print(int[] startAndEnd) {
print(startAndEnd[0], startAndEnd[1]);
}
public static int[] startAndEnd(int start, int end) {
return new int[] {
start,
end
};
}
public static void main(String... arguments){
Stream.of(
startAndEnd(0, 25),
startAndEnd(250, 265),
startAndEnd(1000, 1025)
)
.forEach(Nth::print)
;
}
}
```

- Output:

## JavaScript

### ES5

```
console.log(function () {
var lstSuffix = 'th st nd rd th th th th th th'.split(' '),
fnOrdinalForm = function (n) {
return n.toString() + (
11 <= n % 100 && 13 >= n % 100 ?
"th" : lstSuffix[n % 10]
);
},
range = function (m, n) {
return Array.apply(
null, Array(n - m + 1)
).map(function (x, i) {
return m + i;
});
};
return [[0, 25], [250, 265], [1000, 1025]].map(function (tpl) {
return range.apply(null, tpl).map(fnOrdinalForm).join(' ');
}).join('\n\n');
}());
```

- Output:

```
0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th
250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th
1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th
```

### ES6

```
(function (lstTestRanges) {
'use strict'
let lstSuffix = 'th st nd rd th th th th th th'.split(' '),
// ordinalString :: Int -> String
ordinalString = n =>
n.toString() + (
11 <= n % 100 && 13 >= n % 100 ?
"th" : lstSuffix[n % 10]
),
// range :: Int -> Int -> [Int]
range = (m, n) =>
Array.from({
length: (n - m) + 1
}, (_, i) => m + i);
return lstTestRanges
.map(tpl => range
.apply(null, tpl)
.map(ordinalString)
);
})([[0, 25], [250, 265], [1000, 1025]]);
```

- Output:

[["0th", "1st", "2nd", "3rd", "4th", "5th", "6th", "7th", "8th", "9th", "10th", "11th", "12th", "13th", "14th", "15th", "16th", "17th", "18th", "19th", "20th", "21st", "22nd", "23rd", "24th", "25th"], ["250th", "251st", "252nd", "253rd", "254th", "255th", "256th", "257th", "258th", "259th", "260th", "261st", "262nd", "263rd", "264th", "265th"], ["1000th", "1001st", "1002nd", "1003rd", "1004th", "1005th", "1006th", "1007th", "1008th", "1009th", "1010th", "1011th", "1012th", "1013th", "1014th", "1015th", "1016th", "1017th", "1018th", "1019th", "1020th", "1021st", "1022nd", "1023rd", "1024th", "1025th"]]

## Joy

```
DEFINE
suffix == abs 89 + 100 rem 9 - 10 rem [{1 2 3} in] [] [pop 0] ifte ["th" "st" "nd" "rd"] of;
nth == ['d 1 1 format] [suffix] cleave concat.
[0 250 1000] [25 [dup nth putchars ' putch succ] times nth putchars '\n putch] step.
```

- Output:

0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 266th 267th 268th 269th 270th 271st 272nd 273rd 274th 275th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## jq

```
# ordinalize an integer input, positive or negative
def ordinalize:
(if . < 0 then -(.) else . end) as $num
| ($num % 100) as $small
| (if 11 <= $small and $small <= 13 then "th"
else
( $num % 10)
| (if . == 1 then "st"
elif . == 2 then "nd"
elif . == 3 then "rd"
else "th"
end)
end) as $ordinal
| "\(.)\($ordinal)" ;
([range(-5; -1)], [range(0;26)], [range(250;266)], [range(1000;1026)])
| map(ordinalize)
```

- Output:

["-5th","-4th","-3rd","-2nd"] ["0th","1st","2nd","3rd","4th","5th","6th","7th","8th","9th","10th","11th","12th","13th","14th","15th","16th","17th","18th","19th","20th","21st","22nd","23rd","24th","25th"] ["250th","251st","252nd","253rd","254th","255th","256th","257th","258th","259th","260th","261st","262nd","263rd","264th","265th"] ["1000th","1001st","1002nd","1003rd","1004th","1005th","1006th","1007th","1008th","1009th","1010th","1011th","1012th","1013th","1014th","1015th","1016th","1017th","1018th","1019th","1020th","1021st","1022nd","1023rd","1024th","1025th"]

## Julia

```
using Printf
```

**Function**:

```
function ordinal(n::Integer)
n < 0 && throw(DomainError())
suffixes = ("st", "nd", "rd")
u = n % 10
t = n ÷ 10 % 10
if u > 3 || u == 0 || t == 1
suf = "th"
else
suf = suffixes[u]
end
return string(n, suf)
end
```

**Main**:

```
println("Tests of ordinal formatting of integers.")
for (i, n) in enumerate(0:25)
(i - 1) % 10 == 0 && println()
@printf("%7s", ordinal(n))
end
println()
for (i, n) in enumerate(250:265)
(i - 1) % 10 == 0 && println()
@printf("%7s", ordinal(n))
end
println()
for (i, n) in enumerate(1000:1025)
(i - 1) % 10 == 0 && println()
@printf("%7s", ordinal(n))
end
```

**Main2**:

```
Nth(x::Integer) = if x % 100 ∈ [11, 12, 13] "th" else ["th", "st", "nd", "rd", "th"][min(x % 10 + 1, 5)] end
NthA(x::Integer) = "$(x)'$(Nth(x)) "
[0:25..., 250:265..., 1000:1025...] .|> NthA .|> print;
```

- Output:

Tests of ordinal formatting of integers. 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## Kotlin

```
fun Int.ordinalAbbrev() =
if (this % 100 / 10 == 1) "th"
else when (this % 10) { 1 -> "st" 2 -> "nd" 3 -> "rd" else -> "th" }
fun IntRange.ordinalAbbrev() = map { "$it" + it.ordinalAbbrev() }.joinToString(" ")
fun main(args: Array<String>) {
listOf((0..25), (250..265), (1000..1025)).forEach { println(it.ordinalAbbrev()) }
}
```

## Lambdatalk

Translation from the javascript entry

```
{def fnOrdinalForm
{lambda {:n}
{if {and {<= 11 {% :n 100}} {>= 13 {% :n 100}}}
then :nth
else :n{A.get {% :n 10} th st nd rd th th th th th th}}}}
-> fnOrdinalForm
{S.map fnOrdinalForm {S.serie 0 25}}
-> 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th
16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th
{S.map fnOrdinalForm {S.serie 250 265}}
-> 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th
261st 262nd 263rd 264th 265th
{S.map fnOrdinalForm {S.serie 1000 1025}}
-> 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th
1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th
1021st 1022nd 1023rd 1024th 1025th
```

## Lua

The apostrophe just looks weird if you ask me. No one did, obviously.

```
function getSuffix (n)
local lastTwo, lastOne = n % 100, n % 10
if lastTwo > 3 and lastTwo < 21 then return "th" end
if lastOne == 1 then return "st" end
if lastOne == 2 then return "nd" end
if lastOne == 3 then return "rd" end
return "th"
end
function Nth (n) return n .. "'" .. getSuffix(n) end
for i = 0, 25 do print(Nth(i), Nth(i + 250), Nth(i + 1000)) end
```

- Output:

0'th 250'th 1000'th 1'st 251'st 1001'st 2'nd 252'nd 1002'nd 3'rd 253'rd 1003'rd 4'th 254'th 1004'th 5'th 255'th 1005'th 6'th 256'th 1006'th 7'th 257'th 1007'th 8'th 258'th 1008'th 9'th 259'th 1009'th 10'th 260'th 1010'th 11'th 261'st 1011'th 12'th 262'nd 1012'th 13'th 263'rd 1013'th 14'th 264'th 1014'th 15'th 265'th 1015'th 16'th 266'th 1016'th 17'th 267'th 1017'th 18'th 268'th 1018'th 19'th 269'th 1019'th 20'th 270'th 1020'th 21'st 271'st 1021'st 22'nd 272'nd 1022'nd 23'rd 273'rd 1023'rd 24'th 274'th 1024'th 25'th 275'th 1025'th

## Maple

```
toOrdinal := proc(n:: nonnegint)
if 1 <= n and n <= 10 then
if n >= 4 then
printf("%ath", n);
elif n = 3 then
printf("%ard", n);
elif n = 2 then
printf("%and", n);
else
printf("%ast", n);
end if:
else
printf(convert(n, 'ordinal'));
end if:
return NULL;
end proc:
a := [[0, 25], [250, 265], [1000, 1025]]:
for i in a do
for j from i[1] to i[2] do
toOrdinal(j);
printf(" ");
end do;
printf("\n\n");
end do;
```

- Output:

## Mathematica/Wolfram Language

I borrowed the logic from the Python code.

```
suffixlist = {"th", "st", "nd", "rd", "th", "th", "th", "th", "th","th"};
addsuffix[n_] := Module[{suffix},
suffix = Which[
Mod[n, 100] <= 10, suffixlist[[Mod[n, 10] + 1]],
Mod[n, 100] > 20, suffixlist[[Mod[n, 10] + 1]],
True, "th"
];
ToString[n] <> suffix
]
addsuffix[#] & /@ Range[0, 25] (* test 1 *)
addsuffix[#] & /@ Range[250, 265] (* test 2 *)
addsuffix[#] & /@ Range[1000, 1025] (* test 3 *)
```

- Output:

{"0th", "1st", "2nd", "3rd", "4th", "5th", "6th", "7th", "8th", "9th", "10th", "11th", "12th", "13th", "14th", "15th", "16th", "17th", "18th", "19th", "20th", "21st", "22nd", "23rd", "24th", "25th"} {"250th", "251st", "252nd", "253rd", "254th", "255th", "256th", "257th", "258th", "259th", "260th", "261st", "262nd", "263rd", "264th", "265th"} {"1000th", "1001st", "1002nd", "1003rd", "1004th", "1005th", "1006th", "1007th", "1008th", "1009th", "1010th", "1011th", "1012th", "1013th", "1014th", "1015th", "1016th", "1017th", "1018th", "1019th", "1020th", "1021st", "1022nd", "1023rd", "1024th", "1025th"}

## MATLAB

```
function s = nth(n)
tens = mod(n, 100);
if tens > 9 && tens < 20
suf = 'th';
else
switch mod(n, 10)
case 1
suf = 'st';
case 2
suf = 'nd';
case 3
suf = 'rd';
otherwise
suf = 'th';
end
end
s = sprintf('%d%s', n, suf);
end
```

- Output:

## MiniScript

To get the output all on one line, we append it to a list as we go, and then print the list all at once at the end.

```
ordinal = function(n)
if n % 100 > 3 and n %100 < 20 then return n + "th"
if n % 10 == 1 then return n + "st"
if n % 10 == 2 then return n + "nd"
if n % 10 == 3 then return n + "rd"
return n + "th"
end function
test = function(from, to)
out = []
for i in range(from, to)
out.push ordinal(i)
end for
print out.join
end function
test 0, 25
test 250, 265
test 1000, 1025
```

- Output:

## Modula-2

```
MODULE Nth;
FROM STextIO IMPORT
WriteString, WriteLn;
FROM WholeStr IMPORT
IntToStr;
PROCEDURE Suffix(N: CARDINAL; VAR OUT Destination: ARRAY OF CHAR);
VAR
NMod10, NMod100: CARDINAL;
BEGIN
NMod10 := N MOD 10;
NMod100 := N MOD 100;
IF (NMod10 = 1) AND (NMod100 <> 11) THEN
Destination := "st";
ELSIF (NMod10 = 2) AND (NMod100 <> 12) THEN
Destination := "nd";
ELSIF (NMod10 = 3) AND (NMod100 <> 13) THEN
Destination := "rd";
ELSE
Destination := "th";
END;
END Suffix;
PROCEDURE PrintImages(LoLim, HiLim: CARDINAL);
VAR
I: CARDINAL;
IString: ARRAY [0 .. 15] OF CHAR;
ISuff: ARRAY [0 .. 1] OF CHAR;
BEGIN
FOR I := LoLim TO HiLim DO
IntToStr(I, IString);
Suffix(I, ISuff);
WriteString(IString);
WriteString(ISuff);
WriteString(" ");
END;
WriteLn;
END PrintImages;
BEGIN
PrintImages( 0, 25);
PrintImages( 250, 265);
PrintImages(1000, 1025);
END Nth.
```

## Nanoquery

```
def ordinalAbbrev(n)
if int(n % 100 / 10) = 1
return "th"
end
if n % 10 = 1
return "st"
else if n % 10 = 2
return "nd"
else if n % 10 = 3
return "rd"
else
return "th"
end
end
for i in range(0, 25)
print (i + "'" + ordinalAbbrev(i) + " ")
end
println
for i in range(250, 265)
print (i + "'" + ordinalAbbrev(i) + " ")
end
println
for i in range(1000, 1025)
print (i + "'" + ordinalAbbrev(i) + " ")
end
println
```

- Output:

0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 25'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th 1025'th

## Nim

```
const Suffix = ["th", "st", "nd", "rd", "th", "th", "th", "th", "th", "th"]
proc nth(n: Natural): string =
$n & "'" & (if n mod 100 in 11..20: "th" else: Suffix[n mod 10])
for j in countup(0, 1000, 250):
for i in j..j+24:
stdout.write nth(i), " "
echo ""
```

- Output:

0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 266'th 267'th 268'th 269'th 270'th 271'st 272'nd 273'rd 274'th 500'th 501'st 502'nd 503'rd 504'th 505'th 506'th 507'th 508'th 509'th 510'th 511'th 512'th 513'th 514'th 515'th 516'th 517'th 518'th 519'th 520'th 521'st 522'nd 523'rd 524'th 750'th 751'st 752'nd 753'rd 754'th 755'th 756'th 757'th 758'th 759'th 760'th 761'st 762'nd 763'rd 764'th 765'th 766'th 767'th 768'th 769'th 770'th 771'st 772'nd 773'rd 774'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th

## Objeck

```
class Nth {
function : OrdinalAbbrev(n : Int ) ~ String {
ans := "th"; # most of the time it should be "th"
if(n % 100 / 10 = 1) {
return ans; # teens are all "th"
};
select(n % 10){
label 1: { ans := "st"; }
label 2: { ans := "nd"; }
label 3: { ans := "rd"; }
};
return ans;
}
function : Main(args : String[]) ~ Nil {
for(i := 0; i <= 25; i+=1;) {
abbr := OrdinalAbbrev(i);
"{$i}{$abbr} "->Print();
};
""->PrintLine();
for(i := 250; i <= 265; i+=1;) {
abbr := OrdinalAbbrev(i);
"{$i}{$abbr} "->Print();
};
""->PrintLine();
for(i := 1000; i <= 1025; i+=1;) {
abbr := OrdinalAbbrev(i);
"{$i}{$abbr} "->Print();
};
}
}
```

- Output:

## OCaml

```
let show_nth n =
if (n mod 10 = 1) && (n mod 100 <> 11) then "st"
else if (n mod 10 = 2) && (n mod 100 <> 12) then "nd"
else if (n mod 10 = 3) && (n mod 100 <> 13) then "rd"
else "th"
let () =
let show_ordinals (min, max) =
for i=min to max do
Printf.printf "%d%s " i (show_nth i)
done;
print_newline() in
List.iter show_ordinals [ (0,25); (250,265); (1000,1025) ]
```

- Output:

## Oforth

```
: nth(n)
| r |
n "th" over 10 mod ->r
r 1 == ifTrue: [ n 100 mod 11 == ifFalse: [ drop "st" ] ]
r 2 == ifTrue: [ n 100 mod 12 == ifFalse: [ drop "nd" ] ]
r 3 == ifTrue: [ n 100 mod 13 == ifFalse: [ drop "rd" ] ]
+ ;
```

- Output:

seqFrom(0, 25) map(#nth) println [0th, 1st, 2nd, 3rd, 4th, 5th, 6th, 7th, 8th, 9th, 10th, 11th, 12th, 13th, 14th, 15th, 16t h, 17th, 18th, 19th, 20th, 21st, 22nd, 23rd, 24th, 25th] seqFrom(250, 265) map(#nth) println [250th, 251st, 252nd, 253rd, 254th, 255th, 256th, 257th, 258th, 259th, 260th, 261st, 262nd , 263rd, 264th, 265th] seqFrom(1000, 1025) map(#nth) println [1000th, 1001st, 1002nd, 1003rd, 1004th, 1005th, 1006th, 1007th, 1008th, 1009th, 1010th, 1 011th, 1012th, 1013th, 1014th, 1015th, 1016th, 1017th, 1018th, 1019th, 1020th, 1021st, 102 2nd, 1023rd, 1024th, 1025th]

## PARI/GP

(Spurious apostrophes intentionally omitted, following Raku.)

```
ordinal(n)=my(k=n%10,m=n%100); Str(n,if(m<21&&m>3,"th",k==1,"st",k==2,"nd",k==3,"rd","th"));
apply(ordinal, [0..25])
apply(ordinal, [250..265])
apply(ordinal, [1000..1025])
apply(ordinal, [111, 1012])
```

- Output:

%1 = ["0th", "1st", "2nd", "3rd", "4th", "5th", "6th", "7th", "8th", "9th", "10th", "11th", "12th", "13th", "14th", "15th", "16th", "17th", "18th", "19th", "20th", "21st", "22nd", "23rd", "24th", "25th"] %2 = ["250th", "251st", "252nd", "253rd", "254th", "255th", "256th", "257th", "258th", "259th", "260th", "261st", "262nd", "263rd", "264th", "265th"] %3 = ["1000th", "1001st", "1002nd", "1003rd", "1004th", "1005th", "1006th", "1007th", "1008th", "1009th", "1010th", "1011th", "1012th", "1013th", "1014th", "1015th", "1016th", "1017th", "1018th", "1019th", "1020th", "1021st", "1022nd", "1023rd", "1024th", "1025th"] %4 = ["111th", "1012th"]

## Pascal

nearly copy of Ada

```
Program n_th;
function Suffix(N: NativeInt):AnsiString;
var
res: AnsiString;
begin
res:= 'th';
case N mod 10 of
1:IF N mod 100 <> 11 then
res:= 'st';
2:IF N mod 100 <> 12 then
res:= 'nd';
3:IF N mod 100 <> 13 then
res:= 'rd';
else
end;
Suffix := res;
end;
procedure Print_Images(loLim, HiLim: NativeInt);
var
i : NativeUint;
begin
for I := LoLim to HiLim do
write(i,Suffix(i),' ');
writeln;
end;
begin
Print_Images( 0, 25);
Print_Images( 250, 265);
Print_Images(1000, 1025);
end.
```

- Output:

shortened

0th 1st 2nd 3rd 4th ... 11th 12th 13th ..20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th ..261st 262nd 263rd 264th 265th ..1001st 1002nd 1003rd 1004th..1011th..1013th..1021st 1022nd 1023rd 1024th

## Perl

Requires Perl 5.10 or newer for the Defined OR operator (//).

```
use 5.10.0;
my %irregulars = ( 1 => 'st',
2 => 'nd',
3 => 'rd',
11 => 'th',
12 => 'th',
13 => 'th');
sub nth
{
my $n = shift;
$n . # q(') . # Uncomment this to add apostrophes to output
($irregulars{$n % 100} // $irregulars{$n % 10} // 'th');
}
sub range { join ' ', map { nth($_) } @{$_[0]} }
print range($_), "\n" for ([0..25], [250..265], [1000..1025]);
```

- Output:

Alternatively, can use a library.

```
use Lingua::EN::Numbers::Ordinate 'ordinate';
foreach my $i (0..25, 250..265, 1000..1025) {
print ordinate($i),"\n";
}
```

## Phix

constant ordinals = {"th","st","nd","rd"} function Nth(integer n, bool apostrophe=false) integer mod10 = mod(n,10)+1 if mod10>4 or mod(n,100)=mod10+9 then mod10 = 1 end if return sprintf("%d%s",{n,repeat('\'',apostrophe)&ordinals[mod10]}) end function constant ranges = {{0,25},{250,265},{1000,1025}} for i=1 to length(ranges) do for j=ranges[i][1] to ranges[i][2] do if mod(j,10)=0 then puts(1,"\n") end if printf(1," %6s",{Nth(j,i=2)}) end for puts(1,"\n") end for

- Output:

0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

Alternatively you can use the builtin ord(), and a more functional style, as follows (same output)

function do_one(integer n, string apostrophe) return pad_head(sprintf("%d%s%s",{n,apostrophe,ord(n)}),7) end function procedure do_set(sequence s, bool bApostrophe=false) puts(1,join_by(apply(true,do_one,{s,{repeat('`',bApostrophe)}}),1,10,"")&"\n") end procedure constant {rs,re} = columnize({{0,25},{250,265},{1000,1025}}) papply(true,do_set,{apply(true,tagset,{re,rs}),{false,true,false}})

## PHP

```
function nth($num) {
$os = "th";
if ($num % 100 <= 10 or $num % 100 > 20) {
switch ($num % 10) {
case 1:
$os = "st";
break;
case 2:
$os = "nd";
break;
case 3:
$os = "rd";
break;
}
}
return $num . $os;
}
foreach ([[0,25], [250,265], [1000,1025]] as $i) {
while ($i[0] <= $i[1]) {
echo nth($i[0]) . " ";
$i[0]++;
}
echo "\n";
}
```

- Output:

## Picat

`nth/3`

is a built-in predicate in Picat, so let's call the functions `nth2/1`

and onward.

### Prolog style

```
nth2(N) = N.to_string() ++ Th =>
( tween(N) -> Th = "th"
; 1 = N mod 10 -> Th = "st"
; 2 = N mod 10 -> Th = "nd"
; 3 = N mod 10 -> Th = "rd"
; Th = "th" ).
tween(N) => Tween = N mod 100, between(11, 13, Tween).
```

### Function with explicit conditions

```
nth3(N) = cc(N,"th"), tween(N) => true.
nth3(N) = cc(N,"st"), N mod 10 = 1 => true.
nth3(N) = cc(N,"nd"), N mod 10 = 2 => true.
nth3(N) = cc(N,"rd"), N mod 10 = 3 => true.
nth3(N) = cc(N,"th") => true.
% helper function
cc(N,Th) = N.to_string() ++ Th.
```

### List of suffixes

```
nth4(N) = Nth =>
Suffix = ["th","st","nd","rd","th","th","th","th","th","th"],
Nth = N.to_string() ++ cond((N mod 100 <= 10; N mod 100 > 20), Suffix[1 + N mod 10], "th").
```

### Test

```
go =>
Ranges = [ 0..25, 250..265, 1000..1025],
foreach(Range in Ranges) println([nth2(I) : I in Range])
end,
nl.
```

- Output:

[0th,1st,2nd,3rd,4th,5th,6th,7th,8th,9th,10th,11th,12th,13th,14th,15th,16th,17th,18th,19th,20th,21st,22nd,23rd,24th,25th] [250th,251st,252nd,253rd,254th,255th,256th,257th,258th,259th,260th,261st,262nd,263rd,264th,265th] [1000th,1001st,1002nd,1003rd,1004th,1005th,1006th,1007th,1008th,1009th,1010th,1011th,1012th,1013th,1014th,1015th,1016th,1017th,1018th,1019th,1020th,1021st,1022nd,1023rd,1024th,1025th]

## PicoLisp

```
(de rangeth (A B)
(mapcar
'((I)
(pack I
(if (member (% I 100) (11 12 13))
'th
(case (% I 10)
(1 'st)
(2 'nd)
(3 'rd)
(T 'th) ) ) ) )
(range A B) ) )
(prinl (glue " " (rangeth 0 25)))
(prinl (glue " " (rangeth 250 265)))
(prinl (glue " " (rangeth 1000 1025)))
(bye)
```

- Output:

## PL/I

```
Nth: procedure options (main); /* 1 June 2014 */
declare i fixed (10);
do i = 0 to 25, 250 to 265, 1000 to 1025;
if i = 250 | i = 1000 then put skip (2);
put edit (enth(i)) (x(1), a);
end;
enth: procedure (i) returns (character (25) varying);
declare i fixed (10);
declare suffix character (2);
select (mod(i, 10));
when (1) suffix = 'st';
when (2) suffix = 'nd';
when (3) suffix = 'rd';
otherwise suffix = 'th';
end;
select (mod(i, 100));
when (11, 12, 13) suffix = 'th';
otherwise ;
end;
return ( trim(i) || suffix );
end enth;
end Nth;
```

- Output:

## PL/M

... under CP/M (or an emulator)

The 8080 PL/M compiler doesn't recognise lower-case letters, so the letters for the suffixes have to be specified by their ASCII codes.

```
100H: /* SUFFIX NUMBERS WITH ST, ND, RD OR TH AS APPROPRIATE */
/* CP/M BDOS SYSTEM CALL AND I/O ROUTINES */
BDOS: PROCEDURE( FN, ARG ); DECLARE FN BYTE, ARG ADDRESS; GOTO 5; END;
PR$CHAR: PROCEDURE( C ); DECLARE C BYTE; CALL BDOS( 2, C ); END;
PR$STRING: PROCEDURE( S ); DECLARE S ADDRESS; CALL BDOS( 9, S ); END;
PR$NL: PROCEDURE; CALL PR$CHAR( 0DH ); CALL PR$CHAR( 0AH ); END;
PR$NUMBER: PROCEDURE( N ); /* PRINTS A NUMBER IN THE MINIMUN FIELD WIDTH */
DECLARE N ADDRESS;
DECLARE V ADDRESS, N$STR ( 6 )BYTE, W BYTE;
V = N;
W = LAST( N$STR );
N$STR( W ) = '$';
N$STR( W := W - 1 ) = '0' + ( V MOD 10 );
DO WHILE( ( V := V / 10 ) > 0 );
N$STR( W := W - 1 ) = '0' + ( V MOD 10 );
END;
CALL PR$STRING( .N$STR( W ) );
END PR$NUMBER;
/* TASK */
DECLARE LD LITERALLY '100' /* LOWER CASE LETTERS NEEDED FOR THE SUFFICES */
, LH LITERALLY '104'
, LN LITERALLY '110'
, LR LITERALLY '114'
, LS LITERALLY '115'
, LT LITERALLY '116'
;
/* RETURNS THE TWO CHARACTER ORDINAL SUFFIX FOR N */
SUFFIX: PROCEDURE( N )ADDRESS;
DECLARE N ADDRESS;
DECLARE ( S1, S2 ) BYTE;
S1 = LT;
S2 = LH;
IF N MOD 100 < 4 OR N MOD 100 > 20 THEN DO;
DECLARE N10 ADDRESS;
N10 = N MOD 10;
IF N10 = 1 THEN DO;
S1 = LS;
S2 = LT;
END;
ELSE IF N10 = 2 THEN DO;
S1 = LN;
S2 = LD;
END;
ELSE IF N10 = 3 THEN DO;
S1 = LR;
S2 = LD;
END;
END;
RETURN ( S1 * 256 ) + S2;
END SUFFIX;
/* PRINTS THE TWO CHARACTER SUFFIX IN S */
PR$SUFFIX: PROCEDURE( S );
DECLARE S ADDRESS;
CALL PR$CHAR( HIGH( S ) );
CALL PR$CHAR( LOW( S ) );
END PR$SUFFIX ;
DECLARE I ADDRESS;
DO I = 0 TO 25;
IF I < 10 THEN CALL PR$CHAR( ' ' );
CALL PR$CHAR( ' ' );CALL PR$NUMBER( I );CALL PR$SUFFIX( SUFFIX( I ) );
IF ( I + 1 ) MOD 10 = 0 THEN CALL PR$NL;
END;
CALL PR$NL;
CALL PR$NL;
DO I = 250 TO 265;
CALL PR$CHAR( ' ' );CALL PR$NUMBER( I );CALL PR$SUFFIX( SUFFIX( I ) );
IF ( I - 249 ) MOD 10 = 0 THEN CALL PR$NL;
END;
CALL PR$NL;
CALL PR$NL;
DO I = 1000 TO 1025;
CALL PR$CHAR( ' ' );CALL PR$NUMBER( I );CALL PR$SUFFIX( SUFFIX( I ) );
IF ( I - 999 ) MOD 10 = 0 THEN CALL PR$NL;
END;
CALL PR$NL;
EOF
```

- Output:

## PowerShell

```
function nth($inp){
$suffix = "th"
switch($inp % 100){
11{$suffix="th"}
12{$suffix="th"}
13{$suffix="th"}
default{
switch($inp % 10){
1{$suffix="st"}
2{$suffix="nd"}
3{$suffix="rd"}
}
}
}
return "$inp$suffix "
}
0..25 | %{Write-host -nonewline (nth "$_")};""
250..265 | %{Write-host -nonewline (nth "$_")};""
1000..1025 | %{Write-host -nonewline (nth "$_")};""
```

- Output:

### An Alternate Version

This is, I think, is a more "PowerShelly" way:

```
function Get-Nth ([int]$Number)
{
$suffix = "th"
switch ($Number % 100){
11 {$suffix = "th"}
12 {$suffix = "th"}
13 {$suffix = "th"}
default {
switch ($Number % 10){
1 {$suffix = "st"}
2 {$suffix = "nd"}
3 {$suffix = "rd"}
}
}
}
"$Number$suffix"
}
1..25 | ForEach-Object {Get-Nth $_} | Format-Wide {$_} -Column 5 -Force
251..265 | ForEach-Object {Get-Nth $_} | Format-Wide {$_} -Column 5 -Force
1001..1025 | ForEach-Object {Get-Nth $_} | Format-Wide {$_} -Column 5 -Force
```

- Output:

1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## Prolog

Following Icon:

```
nth(N, N_Th) :-
( tween(N) -> Th = "th"
; 1 is N mod 10 -> Th = "st"
; 2 is N mod 10 -> Th = "nd"
; 3 is N mod 10 -> Th = "rd"
; Th = "th" ),
string_concat(N, Th, N_Th).
tween(N) :- Tween is N mod 100, between(11, 13, Tween).
test :-
forall( between(0,25, N), (nth(N, N_Th), format('~w, ', N_Th)) ),
nl, nl,
forall( between(250,265,N), (nth(N, N_Th), format('~w, ', N_Th)) ),
nl, nl,
forall( between(1000,1025,N), (nth(N, N_Th), format('~w, ', N_Th)) ).
```

- Output:

of `test/0`

?- test. 0th, 1st, 2nd, 3rd, 4th, 5th, 6th, 7th, 8th, 9th, 10th, 11th, 12th, 13th, 14th, 15th, 16th, 17th, 18th, 19th, 20th, 21st, 22nd, 23rd, 24th, 25th, 250th, 251st, 252nd, 253rd, 254th, 255th, 256th, 257th, 258th, 259th, 260th, 261st, 262nd, 263rd, 264th, 265th, 1000th, 1001st, 1002nd, 1003rd, 1004th, 1005th, 1006th, 1007th, 1008th, 1009th, 1010th, 1011th, 1012th, 1013th, 1014th, 1015th, 1016th, 1017th, 1018th, 1019th, 1020th, 1021st, 1022nd, 1023rd, 1024th, 1025th, true.

## Python

```
_suffix = ['th', 'st', 'nd', 'rd', 'th', 'th', 'th', 'th', 'th', 'th']
def nth(n):
return "%i'%s" % (n, _suffix[n%10] if n % 100 <= 10 or n % 100 > 20 else 'th')
if __name__ == '__main__':
for j in range(0,1001, 250):
print(' '.join(nth(i) for i in list(range(j, j+25))))
```

- Output:

0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 266'th 267'th 268'th 269'th 270'th 271'st 272'nd 273'rd 274'th 500'th 501'st 502'nd 503'rd 504'th 505'th 506'th 507'th 508'th 509'th 510'th 511'th 512'th 513'th 514'th 515'th 516'th 517'th 518'th 519'th 520'th 521'st 522'nd 523'rd 524'th 750'th 751'st 752'nd 753'rd 754'th 755'th 756'th 757'th 758'th 759'th 760'th 761'st 762'nd 763'rd 764'th 765'th 766'th 767'th 768'th 769'th 770'th 771'st 772'nd 773'rd 774'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th

**Alternate version**

```
#!/usr/bin/env python3
def ord(n):
try:
s = ['st', 'nd', 'rd'][(n-1)%10]
if (n-10)%100//10:
return str(n)+s
except IndexError:
pass
return str(n)+'th'
if __name__ == '__main__':
print(*(ord(n) for n in range(26)))
print(*(ord(n) for n in range(250,266)))
print(*(ord(n) for n in range(1000,1026)))
```

- Output:

## Quackery

```
[ table ] is suffix ( n --> $ )
$ "th st nd rd th th th th th th"
nest$ witheach [ ' suffix put ]
[ dup number$
swap dup 100 mod
10 21 within iff
[ drop $ "th" join ]
else
[ 10 mod
suffix join ] ] is ordinal$ ( n --> $ )
[ over - 1+
[] swap times
[ over i^ + ordinal$
nested join ]
nip 50 wrap$ ] is test ( n n --> )
0 25 test
cr
250 265 test
cr
1000 1025 test
```

- Output:

## R

Note that R vectors are 1-indexed.

```
nth <- function(n)
{
if (length(n) > 1) return(sapply(n, nth))
mod <- function(m, n) ifelse(!(m%%n), n, m%%n)
suffices <- c("th", "st", "nd", "rd", "th", "th", "th", "th", "th", "th")
if (n %% 100 <= 10 || n %% 100 > 20)
suffix <- suffices[mod(n+1, 10)]
else
suffix <- 'th'
paste(n, "'", suffix, sep="")
}
range <- list(0:25, 250:275, 500:525, 750:775, 1000:1025)
sapply(range, nth)
```

- Output:

[,1] [,2] [,3] [,4] [,5] [1,] "0'th" "250'th" "500'th" "750'th" "1000'th" [2,] "1'st" "251'st" "501'st" "751'st" "1001'st" [3,] "2'nd" "252'nd" "502'nd" "752'nd" "1002'nd" [4,] "3'rd" "253'rd" "503'rd" "753'rd" "1003'rd" [5,] "4'th" "254'th" "504'th" "754'th" "1004'th" [6,] "5'th" "255'th" "505'th" "755'th" "1005'th" [7,] "6'th" "256'th" "506'th" "756'th" "1006'th" [8,] "7'th" "257'th" "507'th" "757'th" "1007'th" [9,] "8'th" "258'th" "508'th" "758'th" "1008'th" [10,] "9'th" "259'th" "509'th" "759'th" "1009'th" [11,] "10'th" "260'th" "510'th" "760'th" "1010'th" [12,] "11'th" "261'st" "511'th" "761'st" "1011'th" [13,] "12'th" "262'nd" "512'th" "762'nd" "1012'th" [14,] "13'th" "263'rd" "513'th" "763'rd" "1013'th" [15,] "14'th" "264'th" "514'th" "764'th" "1014'th" [16,] "15'th" "265'th" "515'th" "765'th" "1015'th" [17,] "16'th" "266'th" "516'th" "766'th" "1016'th" [18,] "17'th" "267'th" "517'th" "767'th" "1017'th" [19,] "18'th" "268'th" "518'th" "768'th" "1018'th" [20,] "19'th" "269'th" "519'th" "769'th" "1019'th" [21,] "20'th" "270'th" "520'th" "770'th" "1020'th" [22,] "21'st" "271'st" "521'st" "771'st" "1021'st" [23,] "22'nd" "272'nd" "522'nd" "772'nd" "1022'nd" [24,] "23'rd" "273'rd" "523'rd" "773'rd" "1023'rd" [25,] "24'th" "274'th" "524'th" "774'th" "1024'th" [26,] "25'th" "275'th" "525'th" "775'th" "1025'th"

## Racket

```
#lang racket
(define (teen? n) (<= 11 (modulo n 100) 19))
(define (Nth n)
(format
"~a'~a" n
(match* ((modulo n 10) n)
[((or 1 2 3) (? teen?)) 'th] [(1 _) 'st] [(2 _) 'nd] [(3 _) 'rd] [(_ _) 'th])))
(for ((range (list (in-range 26) (in-range 250 266) (in-range 1000 1026))))
(displayln (string-join (for/list ((nth (sequence-map Nth range))) nth) " ")))
```

- Output:

## Raku

(formerly Perl 6) (Spurious apostrophes intentionally omitted.)

```
my %irregulars = <1 st 2 nd 3 rd>, (11..13 X=> 'th');
sub nth ($n) { $n ~ ( %irregulars{$n % 100} // %irregulars{$n % 10} // 'th' ) }
say .list».&nth for [^26], [250..265], [1000..1025];
```

- Output:

If you want to get Unicodally fancy, use this version instead:

```
my %irregulars = <1 ˢᵗ 2 ⁿᵈ 3 ʳᵈ>, (11..13 X=> 'ᵗʰ');
sub nth ($n) { $n ~ ( %irregulars{$n % 100} // %irregulars{$n % 10} // 'ᵗʰ' ) }
say .list».&nth for [^26], [250..265], [1000..1025];
```

- Output:

0ᵗʰ 1ˢᵗ 2ⁿᵈ 3ʳᵈ 4ᵗʰ 5ᵗʰ 6ᵗʰ 7ᵗʰ 8ᵗʰ 9ᵗʰ 10ᵗʰ 11ᵗʰ 12ᵗʰ 13ᵗʰ 14ᵗʰ 15ᵗʰ 16ᵗʰ 17ᵗʰ 18ᵗʰ 19ᵗʰ 20ᵗʰ 21ˢᵗ 22ⁿᵈ 23ʳᵈ 24ᵗʰ 25ᵗʰ

250ᵗʰ 251ˢᵗ 252ⁿᵈ 253ʳᵈ 254ᵗʰ 255ᵗʰ 256ᵗʰ 257ᵗʰ 258ᵗʰ 259ᵗʰ 260ᵗʰ 261ˢᵗ 262ⁿᵈ 263ʳᵈ 264ᵗʰ 265ᵗʰ

1000ᵗʰ 1001ˢᵗ 1002ⁿᵈ 1003ʳᵈ 1004ᵗʰ 1005ᵗʰ 1006ᵗʰ 1007ᵗʰ 1008ᵗʰ 1009ᵗʰ 1010ᵗʰ 1011ᵗʰ 1012ᵗʰ 1013ᵗʰ 1014ᵗʰ 1015ᵗʰ 1016ᵗʰ 1017ᵗʰ 1018ᵗʰ 1019ᵗʰ 1020ᵗʰ 1021ˢᵗ 1022ⁿᵈ 1023ʳᵈ 1024ᵗʰ 1025ᵗʰ

## Red

```
Red[]
nth: function [n][
d: n % 10
dd: n % 100
suffix: either any [ all [ dd > 3 dd < 20 ] d < 1 d > 4 1 = to-integer n / 10] [4] [d]
rejoin [n pick ["st" "nd" "rd" "th"] suffix]
]
test: function [low high][
repeat i high - low + 1 [
prin [nth i + low - 1 ""]
]
prin newline
]
test 0 25
test 250 265
test 1000 1025
```

- Output:

## Refal

```
$ENTRY Go {
= <Show 0 25>
<Show 250 265>
<Show 1000 1025>;
};
Nth {
s.N, <Symb s.N>: {
e.X '1' s.Y = e.X '1' s.Y 'th';
e.X '1' = e.X '1st';
e.X '2' = e.X '2nd';
e.X '3' = e.X '3rd';
e.X = e.X 'th';
};
};
Cell {
s.N, <First 8 <Nth s.N> ' '>: (e.1) e.2 = e.1;
}
Group {
s.N e.1 = <Group (s.N s.N) () e.1>;
(s.N s.M) (e.1) = (e.1);
(s.N 0) (e.1) e.2 = (e.1) <Group (s.N s.N) () e.2>;
(s.N s.M) (e.1) s.2 e.3 = <Group (s.N <- s.M 1>) (e.1 s.2) e.3>;
};
Iota {
s.End s.End = s.End;
s.Start s.End = s.Start <Iota <+ s.Start 1> s.End>;
};
Each {
s.F = ;
s.F t.I e.X = <Mu s.F t.I> <Each s.F e.X>;
};
ShowLine {
(e.Line) = <Prout <Each Cell e.Line>>;
};
Show {
s.Start s.End,
<Iota s.Start s.End>: e.Range,
<Group 10 e.Range>: e.Lines
= <Prout <Each ShowLine e.Lines>>;
};
```

- Output:

## REXX

This version adds suffixes without apostrophes.

Negative numbers are also handled.

Two alternate solutions added to the oiginal

```
/*REXX program shows ranges of numbers with ordinal (st/nd/rd/th) suffixes attached.*/
Call tell 0,25 /* display the 1st range of numbers */
Call tell 250,265 /* " " 2nd " " " */
Call tell 1000,1025 /* " " 3rd " " " */
Exit /* stick a fork in it, we're all done */
/*-------------------------------------------------------------------------*/
tell: Procedure
Parse Arg low,high /* get the Low and High numbers */
out.=''
Do n=low To high /* process the range, from low */
out.1=out.1 th(n)
out.2=out.2 th2(n)
out.3=out.3 th3(n)
End
Say 'numbers from' low 'to' high '(inclusive):' /*display the output */
Say strip(out.1)
Say ''
If out.2<>out.1 Then Say 'th2 must be wrong'
If out.3<>out.1 Then Say 'th3 must be wrong'
Return
/*-------------------------------------------------------------------------*/
th: /* compact original */
Parse Arg z
x=abs(z)
Return z||word('th st nd rd',1+x//10*(x//100%10\==1)*(x//10<4))
/*-------------------------------------------------------------------------*/
th2: /* rather verbose logic */
Parse Arg z
x=abs(z)
Select
When length(x)=1 Then
If x<4 Then
suffix=word('th st nd rd',x+1)
Else
suffix='th'
When suffixstr(x,length(x)-1,1)=1 Then
suffix='th'
When right(x,1)<4 Then
suffix=word('th st nd rd',right(x,1)+1)
Otherwise
suffix='th'
End
Return z||suffix
/*-------------------------------------------------------------------------*/
th3: /* compact yet quite readable */
Parse Arg z
Parse Value reverse(z) with last +1 prev +1
If last<4 &, /* last digit is 0,1,2,3 */
prev<>1 Then /* and number is not **1x */
suffix=word('th st nd rd',last+1)
Else /* all oher cases */
suffix='th'
Return z||suffix
```

**output** using the default inputs:

numbers from 0 to 25 (inclusive): 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th numbers from 250 to 265 (inclusive): 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th numbers from 1000 to 1025 (inclusive): 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## Ring

```
for nr = 0 to 25
see Nth(nr) + Nth(nr + 250) + Nth(nr + 1000) + nl
next
func getSuffix n
lastTwo = n % 100
lastOne = n % 10
if lastTwo > 3 and lastTwo < 21 "th" ok
if lastOne = 1 return "st" ok
if lastOne = 2 return "nd" ok
if lastOne = 3 return "rd" ok
return "th"
func Nth n
return "" + n + "'" + getSuffix(n) + " "
```

## RPL

### Clean version

≪ IP DUP 10 MOD OVER 100 MOD 10 / IP → units tens ≪ →STR "'" +IFunits 1 ≥ units 3 ≤ AND tens 1 ≠ ANDTHEN{ "st" "nd" "rd" } units GETELSE"th"END+ ≫ ≫ 'NTH' STO

### One-liner

This version uses a mix of arithmetic and boolean operations to determine when to apply the "st/nd/rd" exception.

```
≪ IP →STR LAST { "'th" "'st" "'nd" "'rd" } OVER 10 MOD DUP 4 < * ROT 100 MOD 10 / IP 1 ≠ * 1 + GET + ≫ 'NTH' STO
```

≪ { } ROT ROTFORj j NTH +NEXT≫ 'SHOW' STO 0 25 SHOW 250 265 SHOW 1000 1025 SHOW

- Output:

3: { "0'th" "1'st" "2'nd" "3'rd" "4'th" "5'th" "6'th" "7'th" "8'th" "9'th" "10'th" "11'th" "12'th" "13'th" "14'th" "15'th" "16'th" "17'th" "18'th" "19'th" "20'th" "21'st" "22'nd" "23'rd" "24'th" "25'th" } 2: { "250'th" "251'st" "252'nd" "253'rd" "254'th" "255'th" "256'th" "257'th" "258'th" "259'th" "260'th" "261'st" "262'nd" "263'rd" "264'th" "265'th" } 1: { "1000'th" "1001'st" "1002'nd" "1003'rd" "1004'th" "1005'th" "1006'th" "1007'th" "1008'th" "1009'th" "1010'th" "1011'th" "1012'th" "1013'th" "1014'th" "1015'th" "1016'th" "1017'th" "1018'th" "1019'th" "1020'th" "1021'st" "1022'nd" "1023'rd" "1024'th" "1025'th" }

## Ruby

Code (slightly adapted) and methodname taken from ActiveSupport (Ruby on Rails).

```
class Integer
def ordinalize
num = self.abs
ordinal = if (11..13).include?(num % 100)
"th"
else
case num % 10
when 1; "st"
when 2; "nd"
when 3; "rd"
else "th"
end
end
"#{self}#{ordinal}"
end
end
[(0..25),(250..265),(1000..1025)].each{|r| puts r.map(&:ordinalize).join(", "); puts}
```

- Output:

0th, 1st, 2nd, 3rd, 4th, 5th, 6th, 7th, 8th, 9th, 10th, 11th, 12th, 13th, 14th, 15th, 16th, 17th, 18th, 19th, 20th, 21st, 22nd, 23rd, 24th, 25th 250th, 251st, 252nd, 253rd, 254th, 255th, 256th, 257th, 258th, 259th, 260th, 261st, 262nd, 263rd, 264th, 265th 1000th, 1001st, 1002nd, 1003rd, 1004th, 1005th, 1006th, 1007th, 1008th, 1009th, 1010th, 1011th, 1012th, 1013th, 1014th, 1015th, 1016th, 1017th, 1018th, 1019th, 1020th, 1021st, 1022nd, 1023rd, 1024th, 1025th

## Rust

```
fn nth(num: isize) -> String {
format!("{}{}", num, match (num % 10, num % 100) {
(1, 11) | (2, 12) | (3, 13) => "th",
(1, _) => "st",
(2, _) => "nd",
(3, _) => "rd",
_ => "th",
})
}
fn main() {
let ranges = [(0, 26), (250, 266), (1000, 1026)];
for &(s, e) in &ranges {
println!("[{}, {}) :", s, e);
for i in s..e {
print!("{}, ", nth(i));
}
println!();
}
}
```

- Output:

[0, 26) : 0th, 1st, 2nd, 3rd, 4th, 5th, 6th, 7th, 8th, 9th, 10th, 11th, 12th, 13th, 14th, 15th, 16th, 17th, 18th, 19th, 20th, 21st, 22nd, 23rd, 24th, 25th, [250, 266) : 250th, 251st, 252nd, 253rd, 254th, 255th, 256th, 257th, 258th, 259th, 260th, 261st, 262nd, 263rd, 264th, 265th, [1000, 1026) : 1000th, 1001st, 1002nd, 1003rd, 1004th, 1005th, 1006th, 1007th, 1008th, 1009th, 1010th, 1011th, 1012th, 1013th, 1014th, 1015th, 1016th, 1017th, 1018th, 1019th, 1020th, 1021st, 1022nd, 1023rd, 1024th, 1025th,

## Scala

```
object Nth extends App {
def abbrevNumber(i: Int) = print(s"$i${ordinalAbbrev(i)} ")
def ordinalAbbrev(n: Int) = {
val ans = "th" //most of the time it should be "th"
if (n % 100 / 10 == 1) ans //teens are all "th"
else (n % 10) match {
case 1 => "st"
case 2 => "nd"
case 3 => "rd"
case _ => ans
}
}
(0 to 25).foreach(abbrevNumber)
println()
(250 to 265).foreach(abbrevNumber)
println();
(1000 to 1025).foreach(abbrevNumber)
}
```

## sed

```
/1.$/!{s/1$/1st/;s/2$/2nd/;s/3$/3rd/;};s/[0-9]$/&th/
```

- Output:

$ for n in 0 250 1000; do echo $(seq $n $((n + 25)) | sed -f nth.sed); done 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 266th 267th 268th 269th 270th 271st 272nd 273rd 274th 275th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## Seed7

```
$ include "seed7_05.s7i";
const func string: suffix (in integer: num) is func
result
var string: suffix is "";
begin
if num rem 10 = 1 and num rem 100 <> 11 then suffix := "st";
elsif num rem 10 = 2 and num rem 100 <> 12 then suffix := "nd";
elsif num rem 10 = 3 and num rem 100 <> 13 then suffix := "rd";
else suffix := "th";
end if;
end func;
const proc: printImages (in integer: start, in integer: stop) is func
local
var integer: num is 0;
begin
for num range start to stop do
write(num <& suffix(num) <& " ");
end for;
writeln;
end func;
const proc: main is func
begin
printImages( 0, 25);
printImages( 250, 265);
printImages(1000, 1025);
end func;
```

- Output:

## SETL

```
program nth;
loop for r in [[0..25], [250..265], [1000..1025]] do
showrange(r);
end loop;
proc showrange(r);
i := 0;
loop for s in [nth(n) : n in r] do
putchar(rpad(s, 8));
if (i +:= 1) mod 6 = 0 then print(); end if;
end loop;
print();
end proc;
proc nth(n);
sfx := {[1,"st"], [2,"nd"], [3,"rd"]};
return str n +
if n div 10 mod 10 = 1
then "th"
else sfx(n mod 10) ? "th"
end if;
end proc;
end program;
```

- Output:

## Set lang

Due to the language's specification, the input can only contain one character. Therefore, the following code only works with 0-9.

```
set o 49
set t 50
set h 51
set n !
set ! n
set ! 39
[n=o] set ? 13
[n=t] set ? 16
[n=h] set ? 19
set ! T
set ! H
set ? 21
set ! S
set ! T
set ? 21
set ! N
set ! D
set ? 12
set ! R
set ! D
> EOF
```

Input: I, Output: O

I: 1, O: 1'ST I: 2, O: 2'ND I: 3, O: 3'RD I: 4, O: 4'TH I: 5, O: 5'TH ...

## Sidef

```
func nth(n) {
static irregulars = Hash(<1 ˢᵗ 2 ⁿᵈ 3 ʳᵈ 11 ᵗʰ 12 ᵗʰ 13 ᵗʰ>...)
n.to_s + (irregulars{n % 100} \\ irregulars{n % 10} \\ 'ᵗʰ')
}
for r in [0..25, 250..265, 1000..1025] {
say r.map {|n| nth(n) }.join(" ")
}
```

- Output:

0ᵗʰ 1ˢᵗ 2ⁿᵈ 3ʳᵈ 4ᵗʰ 5ᵗʰ 6ᵗʰ 7ᵗʰ 8ᵗʰ 9ᵗʰ 10ᵗʰ 11ᵗʰ 12ᵗʰ 13ᵗʰ 14ᵗʰ 15ᵗʰ 16ᵗʰ 17ᵗʰ 18ᵗʰ 19ᵗʰ 20ᵗʰ 21ˢᵗ 22ⁿᵈ 23ʳᵈ 24ᵗʰ 25ᵗʰ 250ᵗʰ 251ˢᵗ 252ⁿᵈ 253ʳᵈ 254ᵗʰ 255ᵗʰ 256ᵗʰ 257ᵗʰ 258ᵗʰ 259ᵗʰ 260ᵗʰ 261ˢᵗ 262ⁿᵈ 263ʳᵈ 264ᵗʰ 265ᵗʰ 1000ᵗʰ 1001ˢᵗ 1002ⁿᵈ 1003ʳᵈ 1004ᵗʰ 1005ᵗʰ 1006ᵗʰ 1007ᵗʰ 1008ᵗʰ 1009ᵗʰ 1010ᵗʰ 1011ᵗʰ 1012ᵗʰ 1013ᵗʰ 1014ᵗʰ 1015ᵗʰ 1016ᵗʰ 1017ᵗʰ 1018ᵗʰ 1019ᵗʰ 1020ᵗʰ 1021ˢᵗ 1022ⁿᵈ 1023ʳᵈ 1024ᵗʰ 1025ᵗʰ

## SQL

Oracle

```
select level card,
to_char(to_date(level,'j'),'fmjth') ord
from dual
connect by level <= 15;
select to_char(to_date(5373485,'j'),'fmjth')
from dual;
```

CARD ORD ---------- ------------------------------ 1 1st 2 2nd 3 3rd 4 4th 5 5th 6 6th 7 7th 8 8th 9 9th 10 10th 11 11th 12 12th 13 13th 14 14th 15 15th 15 rows selected. select to_char(to_date(5373485,'j'),'fmjth') * ERROR at line 1: ORA-01854: julian date must be between 1 and 5373484

## Standard ML

```
local
val v = Vector.tabulate (10, fn 1 => "st" | 2 => "nd" | 3 => "rd" | _ => "th")
fun getSuffix x =
if 3 < x andalso x < 21 then "th" else Vector.sub (v, x mod 10)
in
fun nth n =
Int.toString n ^ getSuffix (n mod 100)
end
(* some test ouput *)
val () = (print o concat o List.tabulate)
(26, fn i => String.concatWith "\t" (map nth [i, i + 250, i + 1000]) ^ "\n")
```

- Output:

0th 250th 1000th 1st 251st 1001st 2nd 252nd 1002nd 3rd 253rd 1003rd 4th 254th 1004th 5th 255th 1005th 6th 256th 1006th 7th 257th 1007th 8th 258th 1008th 9th 259th 1009th 10th 260th 1010th 11th 261st 1011th 12th 262nd 1012th 13th 263rd 1013th 14th 264th 1014th 15th 265th 1015th 16th 266th 1016th 17th 267th 1017th 18th 268th 1018th 19th 269th 1019th 20th 270th 1020th 21st 271st 1021st 22nd 272nd 1022nd 23rd 273rd 1023rd 24th 274th 1024th 25th 275th 1025th

## Stata

We reuse here the **maps** function defined in the task Apply a callback to an array.

```
mata
function maps(f,a) {
nr = rows(a)
nc = cols(a)
b = J(nr,nc,"")
for (i=1;i<=nr;i++) {
for (j=1;j<=nc;j++) b[i,j] = (*f)(a[i,j])
}
return(b)
}
function nth(n) {
k = max((min((mod(n-1,10)+1,4)),4*(mod(n-10,100)<10)))
return(strofreal(n)+("st","nd","rd","th")[k])
}
maps(&nth(),((0::25),(250::275),(1000::1025)))
end
```

**Output:**

1 2 3 +----------------------------+ 1 | 0th 250th 1000th | 2 | 1st 251st 1001st | 3 | 2nd 252nd 1002nd | 4 | 3rd 253rd 1003rd | 5 | 4th 254th 1004th | 6 | 5th 255th 1005th | 7 | 6th 256th 1006th | 8 | 7th 257th 1007th | 9 | 8th 258th 1008th | 10 | 9th 259th 1009th | 11 | 10th 260th 1010th | 12 | 11th 261st 1011th | 13 | 12th 262nd 1012th | 14 | 13th 263rd 1013th | 15 | 14th 264th 1014th | 16 | 15th 265th 1015th | 17 | 16th 266th 1016th | 18 | 17th 267th 1017th | 19 | 18th 268th 1018th | 20 | 19th 269th 1019th | 21 | 20th 270th 1020th | 22 | 21st 271st 1021st | 23 | 22nd 272nd 1022nd | 24 | 23rd 273rd 1023rd | 25 | 24th 274th 1024th | 26 | 25th 275th 1025th | +----------------------------+

## Stringle

```
#i
s "th"
.\#i "1" .:\#i !"1" s "st"
.\#i "2" .:\#i !"1" s "nd"
.\#i "3" .:\#i !"1" s "rd"
$ #i s
i i "."
#i +26 26 +#i #@i 250
#i +266 266 +#i #@i 1000
#i +1026 i ""
#i
```

## Swift

```
func addSuffix(n:Int) -> String {
if n % 100 / 10 == 1 {
return "th"
}
switch n % 10 {
case 1:
return "st"
case 2:
return "nd"
case 3:
return "rd"
default:
return "th"
}
}
for i in 0...25 {
print("\(i)\(addSuffix(i)) ")
}
println()
for i in 250...265 {
print("\(i)\(addSuffix(i)) ")
}
println()
for i in 1000...1025 {
print("\(i)\(addSuffix(i)) ")
}
println()
```

- Output:

## Tcl

```
proc ordinal {n} {
if {$n%100<10 || $n%100>20} {
set suff [lindex {th st nd rd th th th th th th} [expr {$n % 10}]]
} else {
set suff th
}
return "$n'$suff"
}
foreach start {0 250 1000} {
for {set n $start; set l {}} {$n<=$start+25} {incr n} {
lappend l [ordinal $n]
}
puts $l
}
```

- Output:

0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 25'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 266'th 267'th 268'th 269'th 270'th 271'st 272'nd 273'rd 274'th 275'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th 1025'th

## TypeScript

```
// N'th
function suffix(n: number): string {
var nMod10: number = n % 10;
var nMod100: number = n % 100;
if (nMod10 == 1 && nMod100 != 11)
return "st";
else if (nMod10 == 2 && nMod100 != 12)
return "nd";
else if (nMod10 == 3 && nMod100 != 13)
return "rd";
else
return "th";
}
function printImages(loLim: number, hiLim: number) {
for (i = loLim; i <= hiLim; i++)
process.stdout.write(`${i}` + suffix(i) + " ");
process.stdout.write("\n");
}
printImages( 0, 25);
printImages( 250, 265);
printImages(1000, 1025);
```

- Output:

## UNIX Shell

```
nth() {
local ordinals=(th st nd rd)
local -i n=$1 i
if (( n < 0 )); then
printf '%s%s\n' - "$(nth $(( -n )) )"
return 0
fi
case $(( n % 100 )) in
11|12|13) i=0;;
*) (( i= n%10 < 4 ? n%10 : 0 ));;
esac
printf '%d%s\n' "$n" "${ordinals[i]}"
}
for n in {0..25} {250..265} {1000..1025}; do
nth $n
done | column
```

- Output:

0th 7th 14th 21st 252nd 259th 1000th 1007th 1014th 1021st 1st 8th 15th 22nd 253rd 260th 1001st 1008th 1015th 1022nd 2nd 9th 16th 23rd 254th 261st 1002nd 1009th 1016th 1023rd 3rd 10th 17th 24th 255th 262nd 1003rd 1010th 1017th 1024th 4th 11th 18th 25th 256th 263rd 1004th 1011th 1018th 1025th 5th 12th 19th 250th 257th 264th 1005th 1012th 1019th 6th 13th 20th 251st 258th 265th 1006th 1013th 1020th

## V (Vlang)

```
fn ord(n int) string {
mut s := "th"
c := n % 10
if c in [1,2,3] {
if n%100/10 == 1 {
return "$n$s"
}
match c {
1 {
s = 'st'
}
2 {
s = 'nd'
}
3 {
s = 'rd'
}
else{}
}
}
return "$n$s"
}
fn main() {
for n := 0; n <= 25; n++ {
print("${ord(n)} ")
}
println('')
for n := 250; n <= 265; n++ {
print("${ord(n)} ")
}
println('')
for n := 1000; n <= 1025; n++ {
print("${ord(n)} ")
}
println('')
}
```

- Output:

## VTL-2

The subroutine at 2000 sets S and T to the first and second letters of the suffix for N. The subroutine at 3000 prints N and the suffix.

```
1110 N=0
1120 #=3000
1130 N=N+1
1140 #=N<26*1120
1150 ?=" "
1210 N=250
1220 #=3000
1230 N=N+1
1240 #=N<266*1220
1250 ?=" "
1310 N=1000
1320 #=3000
1330 N=N+1
1340 #=N<1026*1320
1350 ?=" "
1400 #=9999
2000 R=!
2010 S=116
2020 T=104
2030 M=N/100*0+%
2040 #=M<20+(M>4)=2*R
2050 M=N/10*0+%
2060 #=M=1=0*2100
2070 S=115
2080 T=116
2090 #=R
2100 #=M=2=0*2140
2110 S=110
2120 T=100
2130 #=R
2140 #=M=3=0*R
2150 S=114
2160 T=100
2170 #=R
3000 Z=!
3010 $=32
3020 ?=N
3030 #=2000
3040 $=S
3050 $=T
3060 #=Z
```

- Output:

## Wren

```
import "./fmt" for Fmt
var ranges = [ 0..25, 250..265, 1000..1025 ]
for (r in ranges) {
r.each { |i| Fmt.write("$r ", i) }
System.print("\n")
}
```

- Output:

## XLISP

```
(DEFUN NTH (N)
(COND
((AND (> (MOD N 100) 3) (< (MOD N 100) 21)) `(,N TH))
((= (MOD N 10) 1) `(,N ST))
((= (MOD N 10) 2) `(,N ND))
((= (MOD N 10) 3) `(,N RD))
(T `(,N TH))))
(DEFUN RANGE (X Y)
(IF (<= X Y)
(CONS X (RANGE (+ X 1) Y))))
(DEFUN TEST-NTH ()
(DISPLAY (MAPCAR NTH (RANGE 1 25)))
(NEWLINE)
(DISPLAY (MAPCAR NTH (RANGE 250 265)))
(NEWLINE)
(DISPLAY (MAPCAR NTH (RANGE 1000 1025))))
(TEST-NTH)
```

- Output:

((1 ST) (2 ND) (3 RD) (4 TH) (5 TH) (6 TH) (7 TH) (8 TH) (9 TH) (10 TH) (11 TH) (12 TH) (13 TH) (14 TH) (15 TH) (16 TH) (17 TH) (18 TH) (19 TH) (20 TH) (21 ST) (22 ND) (23 RD) (24 TH) (25 TH)) ((250 TH) (251 ST) (252 ND) (253 RD) (254 TH) (255 TH) (256 TH) (257 TH) (258 TH) (259 TH) (260 TH) (261 ST) (262 ND) (263 RD) (264 TH) (265 TH)) ((1000 TH) (1001 ST) (1002 ND) (1003 RD) (1004 TH) (1005 TH) (1006 TH) (1007 TH) (1008 TH) (1009 TH) (1010 TH) (1011 TH) (1012 TH) (1013 TH) (1014 TH) (1015 TH) (1016 TH) (1017 TH) (1018 TH) (1019 TH) (1020 TH) (1021 ST) (1022 ND) (1023 RD) (1024 TH) (1025 TH))

## XPL0

```
\N'th
code Rem=2, CrLf=9, IntIn=10, IntOut=11, Text=12;
procedure Suf(N, S);
integer N;
character S;
integer NMod10, NMod100;
begin
NMod10:= Rem(N/10);
NMod100:= Rem(N/100);
case of
NMod10 = 1 & NMod100 # 11: S(0):= "st";
NMod10 = 2 & NMod100 # 12: S(0):= "nd";
NMod10 = 3 & NMod100 # 13: S(0):= "rd"
other
S(0):= "th";
end;
procedure PrintImages(LoLim, HiLim);
integer LoLim, HiLim;
integer I;
character S;
begin
for I:= LoLim, HiLim do
begin
Suf(I, addr S);
IntOut(0, I); Text(0, S); Text(0, " ")
end;
CrLf(0)
end;
begin
PrintImages(0, 25);
PrintImages(250, 265);
PrintImages(1000, 1025)
end
```

- Output:

## zkl

Two versions, your choice

```
#if 0
fcn addSuffix(n){
z:=n.abs()%100;
if(11<=z<=13) return(String(n,"th"));
z=z%10;
String(n,(z==1 and "st") or (z==2 and "nd") or (z==3 and "rd") or "th");
}
#else
fcn addSuffix(n){
var suffixes=T("th","st","nd","rd","th","th","th","th","th","th"); //0..10
z:=n.abs()%100;
String(n,(z<=10 or z>20) and suffixes[z%10] or "th");
}
#endif
```

```
[0..25] .apply(addSuffix).concat(",").println();
[250..265] .apply(addSuffix).concat(",").println();
[1000..1025].apply(addSuffix).concat(",").println();
```

- Output:

0th,1st,2nd,3rd,4th,5th,6th,7th,8th,9th,10th,11th,12th,13th,14th,15th,16th,17th,18th,19th,20th,21st,22nd,23rd,24th,25th 250th,251st,252nd,253rd,254th,255th,256th,257th,258th,259th,260th,261st,262nd,263rd,264th,265th 1000th,1001st,1002nd,1003rd,1004th,1005th,1006th,1007th,1008th,1009th,1010th,1011th,1012th,1013th,1014th,1015th,1016th,1017th,1018th,1019th,1020th,1021st,1022nd,1023rd,1024th,1025th