Day of the week
From Rosetta Code
You are encouraged to solve this task according to the task description, using any language you may know.
A company decides that whenever Xmas falls on a Sunday they will give their workers all extra paid holidays so that, together with any public holidays, workers will not have to work the following week (between the 25th of December and the first of January).
- Task
In what years between 2008 and 2121 will the 25th of December be a Sunday?
Using any standard date handling libraries of your programming language;
compare the dates calculated with the output of other languages to discover any anomalies in the handling of dates which may be due to, for example, overflow in types used to represent dates/times similar to y2k type problems.
Contents
- 1 11l
- 2 360 Assembly
- 3 ABAP
- 4 Action!
- 5 Ada
- 6 ALGOL 68
- 7 ALGOL W
- 8 ALGOL-M
- 9 APL
- 10 AppleScript
- 11 Arc
- 12 Arturo
- 13 AutoHotkey
- 14 AutoIt
- 15 AWK
- 16 BASIC
- 17 Batch File
- 18 BBC BASIC
- 19 bc
- 20 Befunge
- 21 Bracmat
- 22 C
- 23 C#
- 24 C++
- 25 Clojure
- 26 COBOL
- 27 CoffeeScript
- 28 ColdFusion
- 29 Common Lisp
- 30 Component Pascal
- 31 D
- 32 Delphi
- 33 ECL
- 34 Elixir
- 35 Erlang
- 36 ERRE
- 37 Euphoria
- 38 F#
- 39 Factor
- 40 FBSL
- 41 Forth
- 42 Fortran
- 43 Fōrmulæ
- 44 Frink
- 45 Gambas
- 46 GAP
- 47 Go
- 48 Groovy
- 49 Haskell
- 50 HicEst
- 51 Icon and Unicon
- 52 J
- 53 Java
- 54 JavaScript
- 55 jq
- 56 Jsish
- 57 Julia
- 58 K
- 59 Kotlin
- 60 Lasso
- 61 Liberty BASIC
- 62 Lingo
- 63 LiveCode
- 64 Logo
- 65 Lua
- 66 M2000 Interpreter
- 67 M4
- 68 Maple
- 69 Mathematica / Wolfram Language
- 70 MATLAB / Octave
- 71 Maxima
- 72 МК-61/52
- 73 Modula-3
- 74 MUMPS
- 75 Nanoquery
- 76 NetRexx
- 77 Nim
- 78 Oberon-2
- 79 Objective-C
- 80 OCaml
- 81 Oforth
- 82 ooRexx
- 83 PARI/GP
- 84 Pascal
- 85 Peloton
- 86 Perl
- 87 Phix
- 88 PHP
- 89 PicoLisp
- 90 Pike
- 91 PL/I
- 92 PowerShell
- 93 Prolog
- 94 PureBasic
- 95 Python
- 96 Quackery
- 97 R
- 98 Racket
- 99 Raku
- 100 REBOL
- 101 Red
- 102 REXX
- 103 Ring
- 104 Ruby
- 105 Run BASIC
- 106 Rust
- 107 S-BASIC
- 108 SAS
- 109 Scala
- 110 Scheme
- 111 Seed7
- 112 SenseTalk
- 113 Sidef
- 114 Simula
- 115 Smalltalk
- 116 SQL
- 117 Standard ML
- 118 Stata
- 119 Suneido
- 120 Swift
- 121 Tcl
- 122 TI-83 BASIC
- 123 TUSCRIPT
- 124 UNIX Shell
- 125 Ursala
- 126 VBA
- 127 VBScript
- 128 Vedit macro language
- 129 Visual Objects
- 130 Vlang
- 131 Wortel
- 132 Wren
- 133 XPL0
- 134 Yabasic
- 135 zkl
- 136 zonnon
- 137 ZX Spectrum Basic
11l[edit]
print((2008..2121).filter(y -> Time(y, 12, 25).strftime(‘%w’) == ‘0’))
- Output:
[2011, 2016, 2022, 2033, 2039, 2044, 2050, 2061, 2067, 2072, 2078, 2089, 2095, 2101, 2107, 2112, 2118]
360 Assembly[edit]
The program uses two ASSIST macro (XDECO,XPRNT) to keep the code as short as possible.
* Day of the week 06/07/2016
DOW CSECT
USING DOW,R15 base register
LA R6,2008 year=2008
LOOP C R6,=F'2121' do year=2008 to 2121
BH ELOOP .
LR R7,R6 y=year
LA R8,12 m=12
LA R9,25 d=25
C R8,=F'3' if m<3
BNL MGE3 then
LA R8,12(R8) m=m+12
BCTR R7,0 y=y-1
MGE3 LR R10,R7 y
SRDA R10,32 .
D R10,=F'100' r=y//100 ; l=y/100
LR R3,R8 m
LA R3,1(R3) m+1
M R2,=F'26' *26
D R2,=F'10' /10
AR R3,R9 +d
AR R3,R10 +r
LR R2,R10 r
SRA R2,2 /4
AR R2,R3 (d+(m+1)*26/10+r+r/4
LR R3,R11 l
SRA R3,2 /4
AR R2,R3 (d+(m+1)*26/10+r+r/4+l/4
LA R5,5 5
MR R4,R11 *l
AR R2,R5 (d+(m+1)*26/10+r+r/4+l/4+5*l)
SRDA R2,32 .
D R2,=F'7' w=(d+(m+1)*26/10+r+r/4+l/4+5*l)//7
C R2,=F'1' if w=1 (sunday)
BNE WNE1 then
XDECO R6,PG edit year
XPRNT PG,12 print year
WNE1 LA R6,1(R6) year=year+1
B LOOP next year
ELOOP BR R14 exit
PG DS CL12 buffer
YREGS
END DOW
- Output:
2011
2016
2022
2033
2039
2044
2050
2061
2067
2072
2078
2089
2095
2101
2107
2112
2118
ABAP[edit]
report zday_of_week
data: lv_start type i value 2007,
lv_n type i value 114,
lv_date type sy-datum,
lv_weekday type string,
lv_day type c,
lv_year type n length 4.
write 'December 25 is a Sunday in: '.
do lv_n times.
lv_year = lv_start + sy-index.
concatenate lv_year '12' '25' into lv_date.
call function 'DATE_COMPUTE_DAY'
exporting date = lv_date
importing day = lv_day.
select single langt from t246 into lv_weekday
where sprsl = sy-langu and
wotnr = lv_day.
if lv_weekday eq 'Sunday'.
write / lv_year.
endif.
enddo.
- Output:
December 25 is a Sunday in: 2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Action![edit]
Action! does not have a standard library providing a day of week function, therefore an adaptation of Sakamoto's method to determine the day of week for a given date using integer arithmetic is used.
Byte FUNC DayOfWeek(BYTE day, month CARD year BYTE century)
CARD weekday
BYTE ARRAY index=[0 3 2 5 0 3 5 1 4 6 2 4]
IF year < 100 THEN
year = year + century * 100
FI
IF year < 1753 THEN RETURN(7) FI
IF month < 3 THEN
year==-1
FI
month = index(month-1)
weekday=year + year/4 - year/100 + year/400 + month + day
weekday = weekday MOD 7
RETURN (weekday)
PROC main()
CARD y
PrintE("December 25 is a Sunday in:")
FOR y = 2008 to 2121
DO
IF DayOfWeek(25, 12, y)=0 THEN
PrintCE(y)
FI
OD
RETURN
- Output:
December 25 is a Sunday in: 2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Ada[edit]
with Ada.Calendar.Formatting; use Ada.Calendar.Formatting;
with Ada.Text_IO; use Ada.Text_IO;
procedure Yuletide is
begin
for Year in 2008..2121 loop
if Day_Of_Week (Time_Of (Year, 12, 25)) = Sunday then
Put_Line (Image (Time_Of (Year, 12, 25)));
end if;
end loop;
end Yuletide;
- Output:
2011-12-25 00:00:00 2016-12-25 00:00:00 2022-12-25 00:00:00 2033-12-25 00:00:00 2039-12-25 00:00:00 2044-12-25 00:00:00 2050-12-25 00:00:00 2061-12-25 00:00:00 2067-12-25 00:00:00 2072-12-25 00:00:00 2078-12-25 00:00:00 2089-12-25 00:00:00 2095-12-25 00:00:00 2101-12-25 00:00:00 2107-12-25 00:00:00 2112-12-25 00:00:00 2118-12-25 00:00:00
ALGOL 68[edit]
# example from: http://www.xs4all.nl/~jmvdveer/algol.html - GPL #
INT sun=0 # , mon=1, tue=2, wed=3, thu=4, fri=5, sat=6 #;
PROC day of week = (INT year, month, day) INT: (
# Day of the week by Zeller’s Congruence algorithm from 1887 #
INT y := year, m := month, d := day, c;
IF m <= 2 THEN
m +:= 12; y -:= 1
FI;
c := y OVER 100;
y %*:= 100;
(d - 1 + ((m + 1) * 26) OVER 10 + y + y OVER 4 + c OVER 4 - 2 * c) MOD 7
);
test:(
print("December 25th is a Sunday in:");
FOR year FROM 2008 TO 2121 DO
INT wd = day of week(year, 12, 25);
IF wd = sun THEN print(whole(year,-5)) FI
OD;
new line(stand out)
)
- Output:
December 25th is a Sunday in: 2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
ALGOL W[edit]
begin % find years where Christmas day falls on a Sunday %
integer procedure Day_of_week ( integer value d, m, y );
begin
integer j, k, mm, yy;
mm := m;
yy := y;
if mm <= 2 then begin
mm := mm + 12;
yy := yy - 1;
end if_m_le_2;
j := yy div 100;
k := yy rem 100;
(d + ( ( mm + 1 ) * 26 ) div 10 + k + k div 4 + j div 4 + 5 * j ) rem 7
end Day_of_week;
write( "25th of December is a Sunday in" );
for year := 2008 until 2121 do begin
integer day;
day := Day_of_week( 25, 12, year );
if day = 1 then writeon( I_W := 5, S_W := 0, year );
end for_year
end.
- Output:
25th of December is a Sunday in 2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
ALGOL-M[edit]
BEGIN
% CALCULATE P MOD Q %
INTEGER FUNCTION MOD(P, Q);
INTEGER P, Q;
BEGIN
MOD := P - Q * (P / Q);
END;
COMMENT
RETURN DAY OF WEEK (SUN=0, MON=1, ETC.) FOR A GIVEN
GREGORIAN CALENDAR DATE USING ZELLER'S CONGRUENCE;
INTEGER FUNCTION DAYOFWEEK(MO, DA, YR);
INTEGER MO, DA, YR;
BEGIN
INTEGER Y, C, Z;
IF MO < 3 THEN
BEGIN
MO := MO + 10;
YR := YR - 1;
END
ELSE MO := MO - 2;
Y := MOD(YR, 100);
C := YR / 100;
Z := (26 * MO - 2) / 10;
Z := Z + DA + Y + (Y / 4) + (C /4) - 2 * C + 777;
DAYOFWEEK := MOD(Z, 7);
END;
% MAIN PROGRAM STARTS HERE %
INTEGER YEAR, SUNDAY;
SUNDAY := 0;
WRITE("CHRISTMAS WILL FALL ON A SUNDAY IN THESE YEARS:");
FOR YEAR := 2008 STEP 1 UNTIL 2121 DO
BEGIN
IF DAYOFWEEK(12, 25, YEAR) = SUNDAY THEN
WRITE(YEAR);
END;
END
- Output:
CHRISTMAS WILL FALL ON A SUNDAY IN THESE YEARS: 2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
APL[edit]
⍝ Based on the simplified calculation of Zeller's congruence, since Christmas is after March 1st, no adjustment is required.
⎕IO ← 0 ⍝ Indices are 0-based
y ← 2008 + ⍳114 ⍝ Years from 2008 to 2121
⍝ Simplified Zeller function operating on table of dates formatted as 114 rows and 3 columns of (day, month, year)
⍝ 0 = Saturday, 1 = Sunday, 2 = Monday, 3 = Tuesday, 4 = Wednesday, 5 = Thursday, 6 = Friday
zeller ← { 7 | +/ (((1↑⍴⍵),6)⍴1 1 1 1 ¯1 1) × ⌊(((⍴⍵)⍴1 13 1)×⍵+(⍴⍵)⍴0 1 0)[;0 1 2 2 2 2]÷((1↑⍴⍵),6)⍴1 5 1 4 100 400 }
result ← (1 = zeller 25,[1]12,[0.5]y) / y
- Output:
result 2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
AppleScript[edit]
set ChristmasSundays to {}
set Christmas to (current date)
set month of Christmas to December
set day of Christmas to 25
repeat with |year| from 2008 to 2121
set year of Christmas to |year|
if weekday of Christmas is Sunday then set end of ChristmasSundays to |year|
end repeat
ChristmasSundays
Or, composing generic functions:
-- xmasIsSunday :: Int -> Bool
on xmasIsSunday(y)
tell (current date)
set {its year, its month, its day, its time} to {y, 12, 25, 0}
its weekday is Sunday
end tell
end xmasIsSunday
-------------------------- TEST ---------------------------
on run
filter(xmasIsSunday, enumFromTo(2008, 2121))
end run
-------------------- GENERIC FUNCTIONS --------------------
-- enumFromTo :: Int -> Int -> [Int]
on enumFromTo(m, n)
if m ≤ n then
set lst to {}
repeat with i from m to n
set end of lst to i
end repeat
lst
else
{}
end if
end enumFromTo
-- filter :: (a -> Bool) -> [a] -> [a]
on filter(f, xs)
tell mReturn(f)
set lst to {}
set lng to length of xs
repeat with i from 1 to lng
set v to item i of xs
if |λ|(v, i, xs) then set end of lst to v
end repeat
return lst
end tell
end filter
-- Lift 2nd class handler function into 1st class script wrapper
-- mReturn :: Handler -> Script
on mReturn(f)
if class of f is script then
f
else
script
property |λ| : f
end script
end if
end mReturn
- Output:
{2011, 2016, 2022, 2033, 2039, 2044, 2050, 2061, 2067,
2072, 2078, 2089, 2095, 2101, 2107, 2112, 2118}
Arc[edit]
(= day-names '(Sunday Monday Tuesday Wednesday Thursday Friday Saturday))
(= get-weekday-num (fn (year month day)
(= helper '(0 3 2 5 0 3 5 1 4 6 2 4))
(if (< month 3) (= year (- year 1)))
(mod (+ year (helper (- month 1)) day
(apply + (map [trunc (/ year _)] '(4 -100 400))))
7)))
(= get-weekday-name (fn (weekday-num) (day-names weekday-num)))
test:
(up i 2008 2121
(when (is 0 (get-weekday-num i 12 25))
(prn i)))
2011
2016
2022
2033
2039
2044
2050
2061
2067
2072
2078
2089
2095
2101
2107
2112
2118
Arturo[edit]
print select 2008..2121 'year [
"Sunday" = get to :date.format:"dd-MM-YYYY" ~"25-12-|year|" 'Day
]
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
AutoHotkey[edit]
year = 2008
stop = 2121
While year <= stop {
FormatTime, day,% year 1225, dddd
If day = Sunday
out .= year "`n"
year++
}
MsgBox,% out
AutoIt[edit]
#include <date.au3>
Const $iSunday = 1
For $iYear = 2008 To 2121 Step 1
If $iSunday = _DateToDayOfWeek($iYear, 12, 25) Then
ConsoleWrite(StringFormat($iYear & "\n"))
EndIf
Next
AWK[edit]
# syntax: GAWK -f DAY_OF_THE_WEEK.AWK
# runtime does not support years > 2037 on my 32-bit Windows XP O/S
BEGIN {
for (i=2008; i<=2121; i++) {
x = strftime("%Y/%m/%d %a",mktime(sprintf("%d 12 25 0 0 0",i)))
if (x ~ /Sun/) { print(x) }
}
}
BASIC[edit]
Works with: FreeBASIC
This program needs the modulo function because there is a bug in the built in modulo function.
Declare Function modulo(x As Double, y As Double) As Double
Declare Function wd(m As Double, d As Double, y As Double) As Integer
Cls
Dim yr As Double
For yr = 2008 To 2121
If wd(12,25,yr) = 1 Then
Print "Dec " & 25 & ", " & yr
EndIf
Next
Sleep
Function modulo(x As Double, y As Double) As Double
If y = 0 Then
Return x
Else
Return x - y * Int(x / y)
End If
End Function
Function wd(m As Double, d As Double, y As Double) As Integer
If m = 1 Or m = 2 Then
m += 12
y-= 1
End If
Return modulo(365 * y + Fix(y / 4) - Fix(y / 100) + Fix(y / 400) + d + Fix((153 * m + 8) / 5), 7) + 1
End Function
Dec 25, 2011
Dec 25, 2016
Dec 25, 2022
Dec 25, 2033
Dec 25, 2039
Dec 25, 2044
Dec 25, 2050
Dec 25, 2061
Dec 25, 2067
Dec 25, 2072
Dec 25, 2078
Dec 25, 2089
Dec 25, 2095
Dec 25, 2101
Dec 25, 2107
Dec 25, 2112
Dec 25, 2118
Atari BASIC[edit]
100 REM FIND YEARS WITH SUNDAY CHRISTMAS
110 PRINT CHR$(125);"SUNDAY CHRISTMASES 2008-2121:":PRINT
120 FOR Y=2008 TO 2121
130 EOY=Y*365+INT(Y/4)-INT(Y/100)+INT(Y/400)
140 XMAS=EOY-6
150 DOW=XMAS-7*INT(XMAS/7)
160 IF DOW THEN 220
170 PRINT Y;
180 FOUND=FOUND+1
190 IF FOUND<3 THEN PRINT ,:GOTO 220
200 FOUND=0
210 PRINT
220 NEXT Y
230 IF FOUND THEN PRINT
- Output:
SUNDAY CHRISTMASES 2008-2121 2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
BaCon[edit]
' Sunday Christmas
PRINT "Years with Christmas on a Sunday"
FOR y = 2008 TO 2121
tv = TIMEVALUE(y, 12, 25, 0, 0, 0)
IF WEEKDAY$(tv) = "Sunday" THEN PRINT y
NEXT
- Output:
prompt$ ./sunday-christmas Years with Christmas on a Sunday 2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Commodore BASIC[edit]
This takes advantage of the dynamic scope of arguments to DEF FN functions to nest definitions and ultimately turn the question "Does Christmas fall on a Sunday in year Y?" into a single Boolean function of the year number. It's easy to run afoul of stack limitations in Microsoft BASICs doing this, especially on older versions that just use the processor's 256-byte stack instead of giving BASIC its own, but this program runs fine even on an unexpanded VIC-20.
100 REM FIND OUT WHAT YEARS HAVE CHRISTMAS ON A SUNDAY
110 REM MODULO FUNCTION (USES CALLER'S N AS DIVIDEND)
120 DEF FNNM(D) = N - D * INT(N/D)
130 REM RATA DIE OF 31 DEC Y (CAN BE TAKEN MODULO 7 TO GET DAY OF WEEK)
140 DEF FNRD(Y) = 365 * Y + INT(Y/4) - INT(Y/100) + INT(Y/400)
150 REM TRUE IF THE GIVEN RD IS A SUNDAY
160 DEF FND7(N) = 0 = FNNM(7)
170 REM TRUE IF CHRISTMAS FALLS ON A SUNDAY IN THE GIVEN YEAR
180 DEF FNXS(Y) = FND7(FNRD(Y) - 6):REM 6 DAYS BEFORE THE END OF THE YEAR
190 REM TRY OUR TARGET YEARS AND OUTPUT THE ONES THAT MATCH
200 Y1 = 2008: Y2 = 2121
210 PRINT CHR$(147);"CHRISTMASES ON SUNDAY";Y1;"-";Y2;CHR$(13)
220 FOR Y=Y1 TO Y2
230 : IF FNXS(Y) THEN PRINT Y,:REM PRINT YEARS IN COLUMNS
240 NEXT Y
250 PRINT
- Output:
CHRISTMASES ON SUNDAY 2008 - 2121: 2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
FreeBASIC[edit]
' version 17-06-2015
' compile with: fbc -s console
Function wd(m As Integer, d As Integer, y As Integer) As Integer
If m < 3 Then ' If m = 1 Or m = 2 Then
m += 12
y -= 1
End If
Return (y + (y \ 4) - (y \ 100) + (y \ 400) + d + ((153 * m + 8) \ 5)) Mod 7
End Function
' ------=< MAIN >=------
For yr As Integer = 2008 To 2121
If wd(12, 25, yr) = 0 Then
Print "Dec 25 "; yr
EndIf
Next
' empty keyboard buffer
While InKey <> "" : Wend
Print : Print "hit any key to end program"
Sleep
End
- Output:
Dec 25 2011 Dec 25 2016 Dec 25 2022 Dec 25 2033 Dec 25 2039 Dec 25 2044 Dec 25 2050 Dec 25 2061 Dec 25 2067 Dec 25 2072 Dec 25 2078 Dec 25 2089 Dec 25 2095 Dec 25 2101 Dec 25 2107 Dec 25 2112 Dec 25 2118
' version 17-06-2015
' Weekday And DateSerial only works with #Include "vbcompat.bi"
' compile with: fbc -s console
#Include Once "vbcompat.bi"
Dim As Double a
For yr As Integer = 2008 To 2121
a = DateSerial (yr, 12, 25)
If Weekday(a) = 1 Then Print Format(a, "dd-mm-yyyy") ' 1 = sunday, 2 = monday ...
Next
' empty keyboard buffer
While InKey <> "" : Wend
Print : Print "hit any key to end program"
Sleep
End
- Output:
25-12-2011 25-12-2016 25-12-2022 25-12-2033 25-12-2039 25-12-2044 25-12-2050 25-12-2061 25-12-2067 25-12-2072 25-12-2078 25-12-2089 25-12-2095 25-12-2101 25-12-2107 25-12-2112 25-12-2118
GW-BASIC[edit]
10 M = 12
20 D = 25
30 FOR Y = 2007 TO 2122
40 GOSUB 100
50 IF Z = 0 THEN PRINT Y
60 NEXT Y
70 END
100 REM CALCULATE DAY OF WEEK Z GIVEN
110 REM YEAR Y, MONTH M AND DAY D
120 REM SUNDAY = 0, SATURDAY = 6
130 IF M < 3 THEN Y = Y - 1 : M = M + 12
140 Z = Y + INT(Y/4) - INT(Y/100) + INT(Y/400)
150 Z = Z + D + INT((153*M + 8)/5)
160 Z = Z MOD 7
170 RETURN
IS-BASIC[edit]
100 PROGRAM "Dayweek.bas"
110 PRINT "The years between 2008 and 2121 will the 25th of December be a Sunday:"
120 FOR Y=2008 TO 2121
130 IF DAYWEEK(Y,12,25)=0 THEN PRINT "Dec 25,";Y
140 NEXT
150 DEF DAYWEEK(Y,M,D)
160 LET A=INT((14-M)/12):LET Y=Y-A
170 LET W=D+INT((13*(M+12*A-2)-1)/5)+Y+INT(Y/4)-INT(Y/100)+INT(Y/400)
180 LET DAYWEEK=W-7*INT(W/7)
190 END DEF
Sinclair ZX81 BASIC[edit]
Works with 1k of RAM. Follows the C code quite closely: the only factors that perhaps make it less readable are (a) the absence of a modulo operator and (b) the need for continual calls to INT because we don't have an integer type. The performance is pretty acceptable; seconds rather than minutes.
10 LET M=12
20 LET D=25
30 FOR Y=2008 TO 2121
40 GOSUB 80
50 IF W=0 THEN PRINT Y
60 NEXT Y
70 STOP
80 LET A=INT ((14-M)/12)
90 LET MM=M+12*A-2
100 LET YY=Y-A
110 LET W=D+INT ((13*MM-1)/5)+YY+INT (YY/4)-INT (YY/100)+INT (YY/400)
120 LET W=W-7*INT (W/7)
130 RETURN
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
QL SuperBASIC[edit]
Works with: Sinclair QL
...having a structured BASIC with MOD and quite unlike the ZX81's "first-generation"
BASIC that's rather like using a calculator (also without an integer type). Even so, it's worth the minor effort to optimise the
code for the task at hand, as done below - which if implemented for the ZX81's routine would make it finish in a fraction of a
second, even in SLOW mode, as multiplying by 13 with a division by 5 is slower than by 256 alone, as well as that two divisions by
multiples of 100 are much slower than one by 16 as at the link. N.B. by relying on strings to have 4-digit years, this routine is not y10k-compliant
AUTO 100,10
DEF PROC Iso(S,O)
REM passing starting & ending years via integers S & O
LOCAL y$,m%,d%,i$,n%,w%
LET m%=12 : d%=25
REM m% & d% are constants, so avoid recalculating n% (=48) each iteration
LET i$=m%*256+ 19300 : n%=i$(2 TO 3)+ d%
FOR count=S TO O
LET y$=count : w%=(y$(1 TO 2)&"32"DIV 16+ count DIV 4+ count+ n%)MOD 7
REM otherwise w%=(y$(1 TO 2)&"16"DIV 16+ count DIV 4+ count)MOD 7
REM = further optimisation beyond skipping irrelevant years:
IF w%=0 THEN PRINT count : count = count+ 4
END FOR count
END DEF Iso
ctrl+space
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Tiny BASIC[edit]
LET Y = 2007
LET M = 12
LET D = 25
10 IF Y = 2122 THEN END
LET Y = Y + 1
GOSUB 100
IF Z = 0 THEN PRINT Y
GOTO 10
100 REM CALCULATE DAY OF WEEK Z GIVEN
REM YEAR Y, MONTH M AND DAY D
REM SUNDAY = 0, SATURDAY = 6
IF M < 3 THEN LET Y = Y - 1
IF M < 3 THEN LET M = M + 12
LET Z = Y + Y/4 - Y/100 + Y/400
LET Z = Z + D + (153*M + 8)/5
LET Z = Z - 7*(Z/7)
RETURN
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Batch File[edit]
:: Day of the Week task from Rosetta Code
:: Batch File Implementation
:: Question: In what years between 2008 and 2121 will the 25th of December be a Sunday?
:: Method: Zeller's Rule
@echo off
rem set month code for December
set mon=33
rem set day number
set day=25
for /L %%y in (2008,1,2121) do (
setlocal enabledelayedexpansion
set /a "a=%%y/100"
set /a "b=%%y-(a*100)"
set /a "weekday=(day+mon+b+(b/4)+(a/4)+(5*a))%%7"
if "!weekday!"=="1" echo(Dec 25, %%y is a Sunday.
endlocal
)
pause
exit /b 0
- Output:
Dec 25, 2011 is a Sunday. Dec 25, 2016 is a Sunday. Dec 25, 2022 is a Sunday. Dec 25, 2033 is a Sunday. Dec 25, 2039 is a Sunday. Dec 25, 2044 is a Sunday. Dec 25, 2050 is a Sunday. Dec 25, 2061 is a Sunday. Dec 25, 2067 is a Sunday. Dec 25, 2072 is a Sunday. Dec 25, 2078 is a Sunday. Dec 25, 2089 is a Sunday. Dec 25, 2095 is a Sunday. Dec 25, 2101 is a Sunday. Dec 25, 2107 is a Sunday. Dec 25, 2112 is a Sunday. Dec 25, 2118 is a Sunday. Press any key to continue . . .
BBC BASIC[edit]
INSTALL @lib$+"DATELIB"
FOR year% = 2008 TO 2121
IF FN_dow(FN_mjd(25, 12, year%)) = 0 THEN
PRINT "Christmas Day is a Sunday in "; year%
ENDIF
NEXT
bc[edit]
Because bc has no date library, this program uses Zeller's rule, also known as Zeller's congruence, to calculate day of week.
scale = 0
/*
* Returns day of week (0 to 6) for year, month m, day d in proleptic
* Gregorian calendar. Sunday is 0. Assumes y >= 1, scale = 0.
*/
define w(y, m, d) {
auto a
/* Calculate Zeller's congruence. */
a = (14 - m) / 12
m += 12 * a
y -= a
return ((d + (13 * m + 8) / 5 + \
y + y / 4 - y / 100 + y / 400) % 7)
}
for (y = 2008; y <= 2121; y++) {
/* If December 25 is a Sunday, print year. */
if (w(y, 12, 25) == 0) y
}
quit
Befunge[edit]
Befunge doesn't have any standard date-handling functionality, so we calculate the day of the week directly using a simple variation of the Zeller rule.
8 >:"2("*+::::4/+\"d"/-\45v
@_^#`"y": +1$<_v#%7+1+/*:*<
>:#,_>$:.55+,^ >0" ,52 ceD"
- Output:
Dec 25, 2011 Dec 25, 2016 Dec 25, 2022 Dec 25, 2033 Dec 25, 2039 Dec 25, 2044 Dec 25, 2050 Dec 25, 2061 Dec 25, 2067 Dec 25, 2072 Dec 25, 2078 Dec 25, 2089 Dec 25, 2095 Dec 25, 2101 Dec 25, 2107 Dec 25, 2112 Dec 25, 2118
Bracmat[edit]
{ Calculate day of week in proleptic Gregorian calendar. Sunday == 0. }
( wday
= year month day adjustment mm yy
. !arg:(?year,?month,?day)
& div$(14+-1*!month,12):?adjustment
& !month+12*!adjustment+-2:?mm
& !year+-1*!adjustment:?yy
& mod
$ ( !day
+ div$(13*!mm+-1,5)
+ !yy
+ div$(!yy,4)
+ -1*div$(!yy,100)
+ div$(!yy,400)
, 7
)
)
& 2008:?y
& whl
' ( !y:~>2121
& ( wday$(!y,12,25):0
& put$(str$(!y "-12-25\n"))
|
)
& 1+!y:?y
)
& done;
- Output:
2011-12-25 2016-12-25 2022-12-25 2033-12-25 2039-12-25 2044-12-25 2050-12-25 2061-12-25 2067-12-25 2072-12-25 2078-12-25 2089-12-25 2095-12-25 2101-12-25 2107-12-25 2112-12-25 2118-12-25
C[edit]
Because of problems with various C libraries (such as time_t overflowing during 2038, or strptime() or mktime() not filling in tm_wday), this program uses Zeller's Rule to calculate day of week.
#include <stdio.h>
/* Calculate day of week in proleptic Gregorian calendar. Sunday == 0. */
int wday(int year, int month, int day)
{
int adjustment, mm, yy;
adjustment = (14 - month) / 12;
mm = month + 12 * adjustment - 2;
yy = year - adjustment;
return (day + (13 * mm - 1) / 5 +
yy + yy / 4 - yy / 100 + yy / 400) % 7;
}
int main()
{
int y;
for (y = 2008; y <= 2121; y++) {
if (wday(y, 12, 25) == 0) printf("%04d-12-25\n", y);
}
return 0;
}
C#[edit]
using System;
class Program
{
static void Main(string[] args)
{
for (int i = 2008; i <= 2121; i++)
{
DateTime date = new DateTime(i, 12, 25);
if (date.DayOfWeek == DayOfWeek.Sunday)
{
Console.WriteLine(date.ToString("dd MMM yyyy"));
}
}
}
}
Using LINQ:
using System;Lambda expressions FTW:
using System.Linq;
class Program
{
static void Main(string[] args)
{
string[] days = Enumerable.Range(2008, 2121 - 2007)
.Select(year => new DateTime(year, 12, 25))
.Where(day => day.DayOfWeek == DayOfWeek.Sunday)
.Select(day => day.ToString("dd MMM yyyy")).ToArray();
foreach (string day in days) Console.WriteLine(day);
}
}
using System;
using System.Linq;
class Program
{
static void Main(string[] args)
{
Enumerable.Range(2008, 113).ToList()
.ConvertAll(ent => new DateTime(ent, 12, 25))
.Where(ent => ent.DayOfWeek.Equals(DayOfWeek.Sunday)).ToList()
.ForEach(ent => Console.WriteLine(ent.ToString("dd MMM yyyy")));
}
}
- Output:
25 Dec 2011 25 Dec 2016 25 Dec 2022 25 Dec 2033 25 Dec 2039 25 Dec 2044 25 Dec 2050 25 Dec 2061 25 Dec 2067 25 Dec 2072 25 Dec 2078 25 Dec 2089 25 Dec 2095 25 Dec 2101 25 Dec 2107 25 Dec 2112 25 Dec 2118
C++[edit]
#include <boost/date_time/gregorian/gregorian.hpp>
#include <iostream>
int main( ) {
using namespace boost::gregorian ;
std::cout
<< "Yuletide holidays must be allowed in the following years:\n" ;
for ( int i = 2008 ; i < 2121 ; i++ ) {
greg_year gy = i ;
date d ( gy, Dec , 25 ) ;
if ( d.day_of_week( ) == Sunday ) {
std::cout << i << std::endl ;
}
}
std::cout << "\n" ;
return 0 ;
}
- Output:
Yuletide holidays must be allowed in the following years: 2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Clojure[edit]
Utilizing Java interop
(import '(java.util GregorianCalendar))
(defn yuletide [start end]
(filter #(= (. (new GregorianCalendar %
(. GregorianCalendar DECEMBER) 25) get (. GregorianCalendar DAY_OF_WEEK))
(. GregorianCalendar SUNDAY)) (range start (inc end))))
(yuletide 2008 2121)
(2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118)
COBOL[edit]
Using Date Intrinsic Functions
program-id. dec25.
data division.
working-storage section.
1 work-date.
2 yr pic 9(4) value 2008.
2 mo-da pic 9(4) value 1225. *> Dec 25
1 wk-date redefines work-date pic 9(8).
1 binary.
2 int-date pic 9(8).
2 dow pic 9(4).
procedure division.
perform varying yr from 2008 by 1
until yr > 2121
compute int-date = function integer-of-date (wk-date)
compute dow = function mod ((int-date - 1) 7) + 1
if dow = 7 *> Sunday = 7 per ISO 8601 and ISO 1989
display yr
end-if
end-perform
stop run
.
end program dec25.
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Without Date Intrinsic Functions
identification division.
program-id. dowtest.
data division.
working-storage section.
01 ws-inp-date pic x(08).
01 filler redefines ws-inp-date.
03 ws-inp-year pic 9(04).
01 ws-dow pic 9(05).
procedure division.
move '00001225' to ws-inp-date
perform test before
varying ws-inp-year from 2008 by +1
until ws-inp-year > 2121
call "todow" using
by reference ws-inp-date
by reference ws-dow
if ws-dow = 1 then
display 'year=' ws-inp-year
end-if
end-perform
stop run.
end program dowtest.
identification division.
program-id. todow.
environment division.
input-output section.
file-control.
data division.
file section.
working-storage section.
01 tally pic 9(05).
01 wms-work-area.
03 wms-year pic 9(04).
03 wms-month pic 9(02).
03 wms-csys pic 9(01) value 1.
03 wms-sum pic 9(05).
linkage section.
01 lkip-date.
03 lkip-date-year pic 9(04).
03 lkip-date-month pic 9(02).
03 lkip-date-day pic 9(02).
01 lkop-dow pic 9(05).
88 lkop-sunday value 1.
procedure division using
by reference lkip-date
by reference lkop-dow
.
if lkip-date-month < 3
compute wms-month = lkip-date-month + 12
compute wms-year = lkip-date-year - 1
else
compute wms-month = lkip-date-month
compute wms-year = lkip-date-year
end-if
compute wms-sum =
( lkip-date-day + 2 * wms-month + wms-year
+ function integer (6 * (wms-month + 1) / 10)
+ function integer ( wms-year / 4 )
- function integer ( wms-year / 100 )
+ function integer ( wms-year / 400 )
+ wms-csys )
compute lkop-dow = function mod (wms-sum, 7) + 1
.
end program todow.
- Output:
year=2011 year=2016 year=2022 year=2033 year=2039 year=2044 year=2050 year=2061 year=2067 year=2072 year=2078 year=2089 year=2095 year=2101 year=2107 year=2112 year=2118
CoffeeScript[edit]
december = 11 # gotta love Date APIs :)one-liner:
sunday = 0
for year in [2008..2121]
xmas = new Date year, december, 25
console.log year if xmas.getDay() is sunday
console.log year for year in [2008...2121] when new Date(year, 11, 25).getDay() is 0
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
ColdFusion[edit]
<cfloop from = "2008" to = "2121" index = "i">
<cfset myDate = createDate(i, 12, 25) />
<cfif dayOfWeek(myDate) eq 1>
December 25th falls on a Sunday in <cfoutput>#i#</cfoutput><br />
</cfif>
</cfloop>
Common Lisp[edit]
(loop for year from 2008 upto 2121
when (= 6 (multiple-value-bind
(second minute hour date month year day-of-week dst-p tz)
(decode-universal-time (encode-universal-time 0 0 0 25 12 year))
(declare (ignore second minute hour date month year dst-p tz))
day-of-week))
collect year)
(loop for year from 2008 upto 2121
for xmas = (encode-universal-time 0 0 0 25 12 year)
for day = (nth-value 6 (decode-universal-time xmas))
when (= day 6) collect year)
Component Pascal[edit]
MODULE DayOfWeek;
IMPORT DevCommanders, TextMappers, Dates, StdLog;
PROCEDURE XmastOnSun(s,e: INTEGER);
VAR
i: INTEGER;
d: Dates.Date;
BEGIN
i := s;d.day := 25;d.month := 12;
WHILE i < e DO
d.year := i;
IF Dates.DayOfWeek(d) = Dates.sunday THEN
StdLog.Int(i);StdLog.Ln
END;
INC(i)
END
END XmastOnSun;
PROCEDURE Do*;
VAR
s: TextMappers.Scanner;
r: ARRAY 2 OF INTEGER;
i: INTEGER;
BEGIN
s.ConnectTo(DevCommanders.par.text);
s.SetPos(DevCommanders.par.beg);
s.Scan;i := 0;
WHILE ~s.rider.eot DO
IF s.type = TextMappers.int THEN
r[i] := s.int; INC(i)
END;
s.Scan
END;
XmastOnSun(r[0],r[1]);
END Do;
END DayOfWeek.
Execute: ^Q DayOfWeek.Do 2008 2121~
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
D[edit]
void main() {
import std.stdio, std.range, std.algorithm, std.datetime;
writeln("Christmas comes on a Sunday in the years:\n",
iota(2008, 2122)
.filter!(y => Date(y, 12, 25).dayOfWeek == DayOfWeek.sun));
}
- Output:
Christmas comes on a Sunday in the years: [2011, 2016, 2022, 2033, 2039, 2044, 2050, 2061, 2067, 2072, 2078, 2089, 2095, 2101, 2107, 2112, 2118]
Delphi[edit]
always in uses clause in Delphiprocedure IsXmasSunday(fromyear, toyear: integer);
var
i: integer;
TestDate: TDateTime;
outputyears: string;
begin
outputyears := '';
for i:= fromyear to toyear do
begin
TestDate := EncodeDate(i,12,25);
if dayofweek(TestDate) = 1 then
begin
outputyears := outputyears + inttostr(i) + ' ';
end;
end;
//CONSOLE
//writeln(outputyears);
//GUI
form1.label1.caption := outputyears;
end;
Procedure called with year range to test and outputs a space-delimited array of years to a label. There is no error check that fromyear < toyear, but this is easily added.
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
ECL[edit]
//In what years between 2008 and 2121 will the 25th of December be a Sunday?
IMPORT STD;
BaseYear := 2008;
EndYear := 2121;
ChristmasDay := RECORD
UNSIGNED1 DayofWeek;
UNSIGNED2 Year;
END;
ChristmasDay FindDate(INTEGER Ctr) := TRANSFORM
SELF.DayofWeek := (STD.Date.FromGregorianYMD((BaseYear-1) + Ctr,12,25)) % 7; //0=Sunday
SELF.Year := (BaseYear-1) + Ctr;
END;
YearDS := DATASET(EndYear-BaseYear,FindDate(COUNTER));
OUTPUT(YearDS(DayofWeek=0),{Year});
/* Outputs:
2011
2016
2022
2033
2039
2044
2050
2061
2067
2072
2078
2089
2095
2101
2107
2112
2118
*/
This code solves a specific task, but can easily be modified as a generic function to return the DayOfWeek for any day after 1 AD.
Elixir[edit]
Enum.each(2008..2121, fn year ->
wday = Date.from_erl!({year, 12, 25}) |> Date.day_of_week
if wday==7, do: IO.puts "25 December #{year} is sunday"
end)
- Output:
25 December 2011 is sunday 25 December 2016 is sunday 25 December 2022 is sunday 25 December 2033 is sunday 25 December 2039 is sunday 25 December 2044 is sunday 25 December 2050 is sunday 25 December 2061 is sunday 25 December 2067 is sunday 25 December 2072 is sunday 25 December 2078 is sunday 25 December 2089 is sunday 25 December 2095 is sunday 25 December 2101 is sunday 25 December 2107 is sunday 25 December 2112 is sunday 25 December 2118 is sunday
Erlang[edit]
% Implemented by bengt kleberg
-module(yuletide).
-export([main/0, sunday_years/2]).
main() ->
[io:fwrite("25 December ~p is Sunday~n", [X]) || X <- sunday_years(2008, 2121)].
sunday_years( Start, Stop ) ->
[X || X <- lists:seq(Start, Stop), is_sunday(calendar:day_of_the_week({X, 12, 25}))].
is_sunday( 7 ) -> true;
is_sunday( _ ) -> false.
- Output:
25 December 2011 is Sunday 25 December 2016 is Sunday 25 December 2022 is Sunday 25 December 2033 is Sunday 25 December 2039 is Sunday 25 December 2044 is Sunday 25 December 2050 is Sunday 25 December 2061 is Sunday 25 December 2067 is Sunday 25 December 2072 is Sunday 25 December 2078 is Sunday 25 December 2089 is Sunday 25 December 2095 is Sunday 25 December 2101 is Sunday 25 December 2107 is Sunday 25 December 2112 is Sunday 25 December 2118 is Sunday
ERRE[edit]
PROGRAM DAY_OF_THE_WEEK
PROCEDURE MODULO(X,Y->RES)
IF Y=0 THEN
RES=X
ELSE
RES=X-Y*INT(X/Y)
END IF
END PROCEDURE
PROCEDURE WD(M,D,Y->RES%)
IF M=1 OR M=2 THEN
M+=12
Y-=1
END IF
MODULO(365*Y+INT(Y/4)-INT(Y/100)+INT(Y/400)+D+INT((153*M+8)/5),7->RES)
RES%=RES+1.0
END PROCEDURE
BEGIN
PRINT(CHR$(12);) ! CLS
FOR YR=2008 TO 2121 DO
WD(12,25,YR->RES%)
IF RES%=1 THEN ! day 1 is Sunday......
PRINT("Dec";25;",";YR)
END IF
END FOR
GET(K$)
END PROGRAM
- Output:
Dec 25, 2011 Dec 25, 2016 Dec 25, 2022 Dec 25, 2033 Dec 25, 2039 Dec 25, 2044 Dec 25, 2050 Dec 25, 2061 Dec 25, 2067 Dec 25, 2072 Dec 25, 2078 Dec 25, 2089 Dec 25, 2095 Dec 25, 2101 Dec 25, 2107 Dec 25, 2112 Dec 25, 2118
Euphoria[edit]
--Day of the week task from Rosetta Code wiki
--User:Lnettnay
--In what years between 2008 and 2121 will the 25th of December be a Sunday
include std/datetime.e
datetime dt
for year = 2008 to 2121 do
dt = new(year, 12, 25)
if weeks_day(dt) = 1 then -- Sunday = 1
? year
end if
end for
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
F#[edit]
open System
[ 2008 .. 2121 ]
|> List.choose (fun y -> if DateTime(y,12,25).DayOfWeek = DayOfWeek.Sunday then Some(y) else None)
|> printfn "%A"
- Output:
[2011; 2016; 2022; 2033; 2039; 2044; 2050; 2061; 2067; 2072; 2078; 2089; 2095; 2101; 2107; 2112; 2118]
Factor[edit]
USING: calendar math.ranges prettyprint sequences ;
2008 2121 [a,b] [ 12 25 <date> sunday? ] filter .
FBSL[edit]
#APPTYPE CONSOLE
'In what years between 2008 and 2121 will the 25th of December be a Sunday?
DIM date AS INTEGER, dayname AS STRING
FOR DIM year = 2008 TO 2121
date = year * 10000 + 1225
dayname = dateconv(date,"dddd")
IF dayname = "Sunday" THEN
PRINT "Christmas Day is on a Sunday in ", year
END IF
NEXT
PAUSE
Forth[edit]
Forth has only TIME&DATE, which does not give day of week. Many public Forth Julian date calculators had year-2100 problems, but this algorithm works well.
\ Zeller's Congruence
: weekday ( d m y -- wd) \ 1 mon..7 sun
over 3 < if 1- swap 12 + swap then
100 /mod
dup 4 / swap 2* -
swap dup 4 / + +
swap 1+ 13 5 */ + +
( in zeller 0=sat, so -2 to 0= mon, then mod, then 1+ for 1=mon)
2- 7 mod 1+ ;
: yuletide
." December 25 is Sunday in "
2122 2008 do
25 12 i weekday
7 = if i . then
loop cr ;
cr yuletide
December 25 is Sunday in 2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
ok
To show year-2100 problems with SwiftForth's provided Modified Julian Day support:
: yuletide
." December 25 is Sunday in "
2122 2008 do
25 12 i d/m/y
7 mod 0= if i . then
loop cr ;
cr yuletide
December 25 is Sunday in 2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2100 2106 2117
In 4tH a library is available which provides the right answer:
include lib/time.4th
: yuletide
." December 25 is Sunday in "
2122 2008 do
25 12 i weekday
6 = if i . then
loop cr ;
cr yuletide
The code is derived from "Collected Algorithms from ACM", Volume 1 Algorithms 1-220.
Fortran[edit]
Based on Forth example
PROGRAM YULETIDE
IMPLICIT NONE
INTEGER :: day, year
WRITE(*, "(A)", ADVANCE="NO") "25th of December is a Sunday in"
DO year = 2008, 2121
day = Day_of_week(25, 12, year)
IF (day == 1) WRITE(*, "(I5)", ADVANCE="NO") year
END DO
CONTAINS
FUNCTION Day_of_week(d, m, y)
INTEGER :: Day_of_week, j, k, mm, yy
INTEGER, INTENT(IN) :: d, m, y
mm=m
yy=y
IF(mm.le.2) THEN
mm=mm+12
yy=yy-1
END IF
j = yy / 100
k = MOD(yy, 100)
Day_of_week = MOD(d + ((mm+1)*26)/10 + k + k/4 + j/4 + 5*j, 7)
END FUNCTION Day_of_week
END PROGRAM YULETIDE
- Output:
25th of December is a Sunday in 2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Fōrmulæ[edit]
Fōrmulæ programs are not textual, visualization/edition of programs is done showing/manipulating structures but not text. Moreover, there can be multiple visual representations of the same program. Even though it is possible to have textual representation —i.e. XML, JSON— they are intended for storage and transfer purposes more than visualization and edition.
Programs in Fōrmulæ are created/edited online in its website, However they run on execution servers. By default remote servers are used, but they are limited in memory and processing power, since they are intended for demonstration and casual use. A local server can be downloaded and installed, it has no limitations (it runs in your own computer). Because of that, example programs can be fully visualized and edited, but some of them will not run if they require a moderate or heavy computation/memory resources, and no local server is being used.
In this page you can see the program(s) related to this task and their results.
Frink[edit]
for y = 2008 to 2121
if (parseDate["$y-12-25"] -> ### u ###) == "7"
println[y]
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Gambas[edit]
Click this link to run this code
Public Sub Main()
Dim siCount As Short
For siCount = 2008 To 2121
If WeekDay(Date(siCount, 12, 25)) = 0 Then Print Format(Date(siCount, 12, 25), "dddd dd mmmm yyyy") & " falls on a Sunday"
Next
End
Output:
Sunday 25 December 2011 falls on a Sunday Sunday 25 December 2016 falls on a Sunday Sunday 25 December 2022 falls on a Sunday Sunday 25 December 2033 falls on a Sunday Sunday 25 December 2039 falls on a Sunday Sunday 25 December 2044 falls on a Sunday Sunday 25 December 2050 falls on a Sunday Sunday 25 December 2061 falls on a Sunday Sunday 25 December 2067 falls on a Sunday Sunday 25 December 2072 falls on a Sunday Sunday 25 December 2078 falls on a Sunday Sunday 25 December 2089 falls on a Sunday Sunday 25 December 2095 falls on a Sunday Sunday 25 December 2101 falls on a Sunday Sunday 25 December 2107 falls on a Sunday Sunday 25 December 2112 falls on a Sunday Sunday 25 December 2118 falls on a Sunday
GAP[edit]
Filtered([2008 .. 2121], y -> WeekDay([25, 12, y]) = "Sun");
# [ 2011, 2016, 2022, 2033, 2039, 2044, 2050, 2061, 2067, 2072, 2078, 2089, 2095, 2101, 2107, 2112, 2118 ]
# A possible implementation of WeekDayAlt
days := ["Mon", "Tue", "Wed", "Thu", "Fri", "Sat", "Sun"];;
WeekDayAlt := function(args)
local d, m, y, k;
d := args[1];
m := args[2];
y := args[3];
if m < 3 then
m := m + 12;
y := y - 1;
fi;
k := 1 + RemInt(d + QuoInt((m + 1)*26, 10) + y + QuoInt(y, 4)
+ 6*QuoInt(y, 100) + QuoInt(y, 400) + 5, 7);
return days[k];
end;
Filtered([2008 .. 2121], y -> WeekDayAlt([25, 12, y]) = "Sun");
# [ 2011, 2016, 2022, 2033, 2039, 2044, 2050, 2061, 2067, 2072, 2078, 2089, 2095, 2101, 2107, 2112, 2118 ]
Go[edit]
package main
import "fmt"
import "time"
func main() {
for year := 2008; year <= 2121; year++ {
if time.Date(year, 12, 25, 0, 0, 0, 0, time.UTC).Weekday() ==
time.Sunday {
fmt.Printf("25 December %d is Sunday\n", year)
}
}
}
- Output:
25 December 2011 is Sunday 25 December 2016 is Sunday 25 December 2022 is Sunday 25 December 2033 is Sunday 25 December 2039 is Sunday 25 December 2044 is Sunday 25 December 2050 is Sunday 25 December 2061 is Sunday 25 December 2067 is Sunday 25 December 2072 is Sunday 25 December 2078 is Sunday 25 December 2089 is Sunday 25 December 2095 is Sunday 25 December 2101 is Sunday 25 December 2107 is Sunday 25 December 2112 is Sunday 25 December 2118 is Sunday
Groovy[edit]
Solution:
def yuletide = { start, stop -> (start..stop).findAll { Date.parse("yyyy-MM-dd", "${it}-12-25").format("EEE") == "Sun" } }
Test program:
println yuletide(2008, 2121)
- Output:
[2011, 2016, 2022, 2033, 2039, 2044, 2050, 2061, 2067, 2072, 2078, 2089, 2095, 2101, 2107, 2112, 2118]
Haskell[edit]
Using the time library:
import Data.Time (fromGregorian)
import Data.Time.Calendar.WeekDate (toWeekDate)
isXmasSunday :: Integer -> Bool
isXmasSunday year =
let (_, _, wday) = toWeekDate $ fromGregorian year 12 25
in wday == 7
main :: IO ()
main =
mapM_
putStrLn
[ "25 December " ++ show year ++ " is Sunday"
| year <- [2008 .. 2121]
, isXmasSunday year ]
- Output:
25 December 2011 is Sunday 25 December 2016 is Sunday 25 December 2022 is Sunday 25 December 2033 is Sunday 25 December 2039 is Sunday 25 December 2044 is Sunday 25 December 2050 is Sunday 25 December 2061 is Sunday 25 December 2067 is Sunday 25 December 2072 is Sunday 25 December 2078 is Sunday 25 December 2089 is Sunday 25 December 2095 is Sunday 25 December 2101 is Sunday 25 December 2107 is Sunday 25 December 2112 is Sunday 25 December 2118 is Sunday
The built-in System.Time module can overflow at the Unix epoch in 2038:
import System.Time
isXmasSunday :: Int -> Bool
isXmasSunday year = ctWDay cal == Sunday
where
cal = toUTCTime $ toClockTime cal'
cal' =
CalendarTime
{ ctYear = year
, ctMonth = December
, ctDay = 25
, ctHour = 0
, ctMin = 0
, ctSec = 0
, ctPicosec = 0
, ctWDay = Friday
, ctYDay = 0
, ctTZName = ""
, ctTZ = 0
, ctIsDST = False
}
main :: IO ()
main =
mapM_
putStrLn
[ "25 December " ++ show year ++ " is Sunday"
| year <- [2008 .. 2121]
, isXmasSunday year ]
- Output:
25 December 2011 is Sunday 25 December 2016 is Sunday 25 December 2022 is Sunday 25 December 2033 is Sunday *** Exception: user error (Time.toClockTime: invalid input)
but with 64 bit systems, running current versions of GHC:
25 December 2011 is Sunday 25 December 2016 is Sunday 25 December 2022 is Sunday 25 December 2033 is Sunday 25 December 2039 is Sunday 25 December 2044 is Sunday 25 December 2050 is Sunday 25 December 2061 is Sunday 25 December 2067 is Sunday 25 December 2072 is Sunday 25 December 2078 is Sunday 25 December 2089 is Sunday 25 December 2095 is Sunday 25 December 2101 is Sunday 25 December 2107 is Sunday 25 December 2112 is Sunday 25 December 2118 is Sunday
HicEst[edit]
DO year = 1, 1000000
TIME(Year=year, MOnth=12, Day=25, TO, WeekDay=weekday)
IF( weekday == 7) WRITE(StatusBar) year
ENDDO
END
No anomalies detected for the first million years :-)
Dec 25 = Sunday in
5 ... 2011 2016 2022 2033 2039 2044 2050 2061 2067
2072 2078 2089 2095 2101 2107 2112 2118 ... 999994
Icon and Unicon[edit]
link datetime
procedure main()
writes("December 25th is a Sunday in: ")
every writes((dayoweek(25,12,y := 2008 to 2122)=="Sunday",y)," ")
end
procedure dayoweek(day, month, year) #: day of the week
static d_code, c_code, m_code, ml_code, y, C, M, Y
initial {
d_code := ["Saturday", "Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday"]
c_code := table()
c_code[16] := c_code[20] := 0
c_code[17] := c_code[21] := 6
c_code[18] := c_code[22] := 4
c_code[19] := c_code[23] := 2
m_code := table()
m_code[1] := m_code["January"] := 1
m_code[2] := m_code["February"] := 4
m_code[3] := m_code["March"] := 4
m_code[4] := m_code["April"] := 0
m_code[5] := m_code["May"] := 2
m_code[6] := m_code["June"] := 5
m_code[7] := m_code["July"] := 0
m_code[8] := m_code["August"] := 3
m_code[9] := m_code["September"] := 6
m_code[10] := m_code["October"] := 1
m_code[11] := m_code["November"] := 4
m_code[12] := m_code["December"] := 6
ml_code := copy(m_code)
ml_code[1] := ml_code["January"] := 0
ml_code[2] := ml_code["February"] := 3
}
if year < 1600 then stop("*** can't compute day of week that far back")
if year > 2299 then stop("*** can't compute day of week that far ahead")
C := c_code[(year / 100) + 1]
y := year % 100
Y := (y / 12) + (y % 12) + ((y % 12) / 4)
month := integer(month)
M := if (year % 4) = 0 then ml_code[month] else m_code[month]
return d_code[(C + Y + M + day) % 7 + 1]
end
- Output:
December 25th is a Sunday in: 2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
J[edit]
load 'dates' NB. provides verb 'weekday'
xmasSunday=: #~ 0 = [: weekday 12 25 ,~"1 0 ] NB. returns years where 25 Dec is a Sunday
xmasSunday 2008 + i.114 NB. check years from 2008 to 2121
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Java[edit]
import java.util.Calendar;
import java.util.Date;
import java.util.GregorianCalendar;
public class Yuletide{
public static void main(String[] args) {
for(int i = 2008;i<=2121;i++){
Calendar cal = new GregorianCalendar(i, Calendar.DECEMBER,
25);
if(cal.get(Calendar.DAY_OF_WEEK)==Calendar.SUNDAY){
System.out.println(cal.getTime());
}
}
}
}
- Output:
Sun Dec 25 00:00:00 CST 2011 Sun Dec 25 00:00:00 CST 2016 Sun Dec 25 00:00:00 CST 2022 Sun Dec 25 00:00:00 CST 2033 Sun Dec 25 00:00:00 CST 2039 Sun Dec 25 00:00:00 CST 2044 Sun Dec 25 00:00:00 CST 2050 Sun Dec 25 00:00:00 CST 2061 Sun Dec 25 00:00:00 CST 2067 Sun Dec 25 00:00:00 CST 2072 Sun Dec 25 00:00:00 CST 2078 Sun Dec 25 00:00:00 CST 2089 Sun Dec 25 00:00:00 CST 2095 Sun Dec 25 00:00:00 CST 2101 Sun Dec 25 00:00:00 CST 2107 Sun Dec 25 00:00:00 CST 2112 Sun Dec 25 00:00:00 CST 2118
JavaScript[edit]
ES5[edit]
Iteration[edit]
for (var year = 2008; year <= 2121; year++){
var xmas = new Date(year, 11, 25)
if ( xmas.getDay() === 0 )
console.log(year)
}
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Functional composition[edit]
(function () {
'use strict';
// isXmasSunday :: Integer -> Bool
function isXmasSunday(year) {
return (new Date(year, 11, 25))
.getDay() === 0;
}
// range :: Int -> Int -> [Int]
function range(m, n) {
return Array.apply(null, Array(n - m + 1))
.map(function (_, i) {
return m + i;
});
}
return range(2008, 2121)
.filter(isXmasSunday);
})();
- Output:
[2011, 2016, 2022, 2033, 2039, 2044, 2050, 2061, 2067, 2072, 2078, 2089, 2095, 2101, 2107, 2112, 2118]
ES6[edit]
(() => {
'use strict';
// main :: IO ()
const main = () => {
const
xs = enumFromTo(2008, 2121)
.filter(xmasIsSunday);
return (
console.log(xs),
xs
);
};
// xmasIsSunday :: Int -> Bool
const xmasIsSunday = year =>
(new Date(year, 11, 25))
.getDay() === 0;
// enumFromTo :: Int -> Int -> [Int]
const enumFromTo = (m, n) =>
Array.from({
length: 1 + n - m
}, (_, i) => m + i);
return main();
})();
- Output:
[2011, 2016, 2022, 2033, 2039, 2044, 2050, 2061, 2067, 2072, 2078, 2089, 2095, 2101, 2107, 2112, 2118]
jq[edit]
# Use Zeller's Congruence to determine the day of the week, given
# year, month and day as integers in the conventional way.
# If iso == "iso" or "ISO", then emit an integer in 1 -- 7 where
# 1 represents Monday, 2 Tuesday, etc;
# otherwise emit 0 for Saturday, 1 for Sunday, etc.
#
def day_of_week(year; month; day; iso):
if month == 1 or month == 2 then
[month + 12, year - 1]
else
[month, year]
end
| day + (13*(.[0] + 1)/5|floor)
+ (.[1]%100) + ((.[1]%100)/4|floor)
+ (.[1]/400|floor) - 2*(.[1]/100|floor)
| if iso == "iso" or iso == "ISO" then 1 + ((. + 5) % 7)
else . % 7
end;
The task:
# Give the results as an array so they can
# readily be presented on a single line:
[range(2008; 2122) | select( day_of_week(.;12;25;0) == 1 )]
- Output:
$ jq -n -c -f zeller.jq [2011,2016,2022,2033,2039,2044,2050,2061,2067,2072,2078,2089,2095,2101,2107,2112,2118]
Jsish[edit]
Jsi does not yet implement the Javascript Date object. strftime' and strptime functions are used here instead.
/* Day of the week, December 25th on a Sunday */
for (var year = 2008; year <= 2121; year++) {
var xmas = strptime(year + '/12/25', '%Y/%m/%d');
var weekDay = strftime(xmas, '%w');
if (weekDay == 0) puts(year);
}
/*
=!EXPECTSTART!=
2011
2016
2022
2033
2039
2044
2050
2061
2067
2072
2078
2089
2095
2101
2107
2112
2118
=!EXPECTEND!=
*/
- Output:
prompt$ jsish -u dayOfTheWeek.jsi [PASS] dayOfTheWeek.jsi
Julia[edit]
using Dates
lo, hi = 2008, 2121
xmas = collect(Date(lo, 12, 25):Year(1):Date(hi, 12, 25))
filter!(xmas) do dt
dayofweek(dt) == Dates.Sunday
end
println("Years from $lo to $hi having Christmas on Sunday: ")
foreach(println, year.(xmas))
- Output:
Years from 2008 to 2121 having Christmas on Sunday: 2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
K[edit]
wd:{(__jd x)!7} / Julian day count, Sun=6
[email protected]&6={wd 1225+x*10000}'y:2008+!114
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Kotlin[edit]
// version 1.0.6
import java.util.*
fun main(args: Array<String>) {
println("Christmas day in the following years falls on a Sunday:\n")
val calendar = GregorianCalendar(2008, Calendar.DECEMBER, 25)
for (year in 2008..2121) {
if (Calendar.SUNDAY == calendar[Calendar.DAY_OF_WEEK]) println(year)
calendar.add(Calendar.YEAR, 1)
}
}
- Output:
Christmas day in the following years falls on a Sunday: 2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Lasso[edit]
loop(-From=2008, -to=2121) => {^
local(tDate = date('12/25/' + loop_count))
#tDate->dayOfWeek == 1 ? '\r' + #tDate->format('%D') + ' is a Sunday'
^}
- Output:
12/25/2011 is a Sunday 12/25/2016 is a Sunday 12/25/2022 is a Sunday 12/25/2033 is a Sunday 12/25/2039 is a Sunday 12/25/2044 is a Sunday 12/25/2050 is a Sunday 12/25/2061 is a Sunday 12/25/2067 is a Sunday 12/25/2072 is a Sunday 12/25/2078 is a Sunday 12/25/2089 is a Sunday 12/25/2095 is a Sunday 12/25/2101 is a Sunday 12/25/2107 is a Sunday 12/25/2112 is a Sunday 12/25/2118 is a Sunday
Liberty BASIC[edit]
count = 0
for year = 2008 to 2121
dateString$="12/25/";year
dayNumber=date$(dateString$)
if dayNumber mod 7 = 5 then
count = count + 1
print dateString$
end if
next year
print count; " years when Christmas Day falls on a Sunday"
end
Lingo[edit]
put "December 25 is a Sunday in:"
refDateObj = date(1905,1,2)
repeat with year = 2008 to 2121
dateObj = date(year, 12, 25)
dayOfWeek = ((dateObj - refDateObj) mod 7)+1 -- 1=Monday..7=Sunday
if dayOfWeek=7 then put year
end repeat
- Output:
-- "December 25 is a Sunday in:" -- 2011 -- 2016 -- 2022 -- 2033 -- 2039 -- 2044 -- 2050 -- 2061 -- 2067 -- 2072 -- 2078 -- 2089 -- 2095 -- 2101 -- 2107 -- 2112 -- 2118
LiveCode[edit]
function xmasSunday startDate endDateExample
convert the long date to dateitems
put it into xmasDay
put 12 into item 2 of xmasDay
put 25 into item 3 of xmasDay
repeat with i = startDate to endDate
put i into item 1 of xmasDay
convert xmasDay to dateItems
if item 7 of xmasDay is 1 then put i & comma after xmasYear
end repeat
if the last char of xmasYear is comma then delete the last char of xmasYear
return xmasYear
end xmasSunday
put xmasSunday(2008,2121)Output
2011,2016,2022,2033,2039,2044,2050,2061,2067,2072,2078,2089,2095,2101,2107,2112,2118
Logo[edit]
; Determine if a Gregorian calendar year is leap
to leap? :year
output (and
equal? 0 modulo :year 4
not member? modulo :year 400 [100 200 300]
)
end
; Convert Gregorian calendar date to a simple day count from
; day 1 = January 1, 1 CE
to day_number :year :month :day
local "elapsed make "elapsed difference :year 1
output (sum product 365 :elapsed
int quotient :elapsed 4
minus int quotient :elapsed 100
int quotient :elapsed 400
int quotient difference product 367 :month 362 12
ifelse lessequal? :month 2 0 ifelse leap? :year -1 -2
:day)
end
; Find the day of the week from a day number; 0 = Sunday through 6 = Saturday
to day_of_week :day_number
output modulo :day_number 7
end
; True if the given day is a Sunday
to sunday? :year :month :day
output equal? 0 day_of_week day_number :year :month :day
end
; Put it all together to answer the question posed in the problem
print filter [sunday? ? 12 25] iseq 2008 2121
bye
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Lua[edit]
Library: LuaDate
require("date")
for year=2008,2121 do
if date(year, 12, 25):getweekday() == 1 then
print(year)
end
end
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Without external modules[edit]
Same output as above
local dTab = {day = 25, month = 12}
for year = 2008, 2121 do
dTab.year = year
if os.date("%A", os.time(dTab)) == "Sunday" then
print(year)
end
end
M2000 Interpreter[edit]
Str$( number, format$) use Visual Basic 6 format
Print "December 25 is a Sunday in:"
For Year=2008 to 2121 {
if Str$(Date("25/12/"+str$(Year,"")),"w")="1" Then {
Print Year
}
}
\\ is the same with this:
Print "December 25 is a Sunday in:"
For Year=2008 to 2121 {
if Str$(Date(str$(Year,"")+"-12-25"),"w")="1" Then {
Print Year
}
}
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
M4[edit]
divert(-1)
define(`for',
`ifelse($#,0,``$0'',
`ifelse(eval($2<=$3),1,
`pushdef(`$1',$2)$4`'popdef(`$1')$0(`$1',incr($2),$3,`$4')')')')
dnl julian day number corresponding to December 25th of given year
define(`julianxmas',
`define(`yrssince0',eval($1+4712))`'define(`noOfLpYrs',
eval((yrssince0+3)/4))`'define(`jd',
eval(365*yrssince0+noOfLpYrs-10-($1-1501)/100+($1-1201)/400+334+25-1))`'
ifelse(eval($1%4==0 && ($1%100!=0 || $1%400==0)),1,
`define(`jd',incr(jd))')`'jd')
divert
for(`yr',2008,2121,
`ifelse(eval(julianxmas(yr)%7==6),1,`yr ')')
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Maple[edit]
xmas:= proc()
local i, dt;
for i from 2008 to 2121 by 1 do
dt := Date(i, 12, 25);
if (Calendar:-DayOfWeek(dt) = 1) then
print(i);
end if;
end do;
end proc;
xmas();
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Or simply:
select(y->Calendar:-DayOfWeek(Date(y,12,25))=1,[$2008..2121]);
- Output:
[2011, 2016, 2022, 2033, 2039, 2044, 2050, 2061, 2067, 2072, 2078, 2089, 2095, 2101, 2107, 2112, 2118]
Mathematica / Wolfram Language[edit]
Reap[If[DateString[{#,12,25},"DayName"]=="Sunday",Sow[#]]&/@Range[2008,2121]][[2,1]]
gives back:
{2011,2016,2022,2033,2039,2044,2050,2061,2067,2072,2078,2089,2095,2101,2107,2112,2118}
MATLAB / Octave[edit]
t = datenum([[2008:2121]',repmat([12,25,0,0,0], 2121-2007, 1)]);
t = t(strmatch('Sunday', datestr(t,'dddd')), :);
datestr(t,'yyyy')
- Output:
ans = 2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Maxima[edit]
weekday(year, month, day) := block([m: month, y: year, k],
if m < 3 then (m: m + 12, y: y - 1),
k: 1 + remainder(day + quotient((m + 1)*26, 10) + y + quotient(y, 4)
+ 6*quotient(y, 100) + quotient(y, 400) + 5, 7),
['monday, 'tuesday, 'wednesday, 'thurdsday, 'friday, 'saturday, 'sunday][k]
)$
sublist(makelist(i, i, 2008, 2121),
lambda([y], weekday(y, 12, 25) = 'sunday));
/* [2011, 2016, 2022, 2033, 2039, 2044, 2050, 2061, 2067, 2072, 2078, 2089, 2095, 2101, 2107, 2112, 2118] */
МК-61/52[edit]
П9 7 П7 1 П8 НОП ИП8 2 2 -
1 0 / [x] П6 ИП9 + 1 8 9
9 - 3 6 5 , 2 5 * [x]
ИП8 ИП6 1 2 * - 1 4 - 3
0 , 5 9 * [x] + 2 9 +
ИП7 + П4 ИП4 7 / [x] 7 * -
x=0 64 ИП9 С/П ИП9 1 + П9 БП 06
Input: РX: starting year.
Output: the year in which Christmas falls on a Sunday. For example, enter 2008, the first result: 2018 (January 7, 2018 is Sunday).
Modula-3[edit]
Modula-3 represents time using a (safe) wrapper around the C time interface. Consequently, it suffers from the same problem as C.
MODULE Yule EXPORTS Main;
IMPORT IO, Fmt, Date, Time;
VAR date: Date.T;
time: Time.T;
BEGIN
FOR year := 2008 TO 2121 DO
date.day := 25;
date.month := Date.Month.Dec;
date.year := year;
TRY
time := Date.ToTime(date);
EXCEPT
| Date.Error =>
IO.Put(Fmt.Int(year) & " is the last year we can specify\n");
EXIT;
END;
date := Date.FromTime(time);
IF date.weekDay = Date.WeekDay.Sun THEN
IO.Put("25th of December " & Fmt.Int(year) & " is Sunday\n");
END;
END;
END Yule.
- Output:
25th of December 2011 is Sunday 25th of December 2016 is Sunday 25th of December 2022 is Sunday 25th of December 2033 is Sunday 2038 is the last year we can specify
MUMPS[edit]
Usage:
DOWHOLIDAY
;In what years between 2008 and 2121 will December 25 be a Sunday?
;Uses the VA's public domain routine %DTC (Part of the Kernel) named here DIDTC
NEW BDT,EDT,CHECK,CHKFOR,LIST,I,X,Y
;BDT - the beginning year to check
;EDT - the end year to check
;BDT and EDT are year offsets from the epoch date 1/1/1700
;CHECK - the month and day to look at
;CHKFOR - what day of the week to look for
;LIST - list of years in which the condition is true
;I - the year currently being checked
;X - the date in an "internal" format, for input to DOW^DIDTC
;Y - the output from DOW^DIDTC
SET BDT=308,EDT=421,CHECK="1225",CHKFOR=0,LIST=""
FOR I=BDT:1:EDT SET X=I_CHECK D DOW^DIDTC SET:(Y=0) LIST=$SELECT($LENGTH(LIST):LIST_", ",1:"")_(I+1700)
IF $LENGTH(LIST)=0 WRITE !,"There are no years that have Christmas on a Sunday in the given range."
IF $LENGTH(LIST) WRITE !,"The following years have Christmas on a Sunday: ",LIST
KILL BDT,EDT,CHECK,CHKFOR,LIST,I,X,Y
QUIT
USER>D ^DOWThe following years have Christmas on a Sunday: 2011, 2016, 2022, 2033, 2039, 2044, 2050, 2061, 2067, 2072, 2078, 2089, 2095, 2101, 2107, 2112, 2118
Nanoquery[edit]
import Nanoquery.Util
// loop through the years 2008 through 2121
for year in range(2008, 2121)
if (new(Date,"12/25/" + str(year)).getDayOfWeek() = "Sunday")
println "In " + year + ", December 25th is a Sunday."
end if
end for
NetRexx[edit]
/* NetRexx */
options replace format comments java crossref savelog symbols nobinary
yearRanges = [int 2008, 2121]
searchday = ''
cal = Calendar
loop year = yearRanges[0] to yearRanges[1]
cal = GregorianCalendar(year, Calendar.DECEMBER, 25)
dayIndex = cal.get(Calendar.DAY_OF_WEEK)
if dayIndex = Calendar.SUNDAY then searchday = searchday year
end year
say 'Between' yearRanges[0] 'and' yearRanges[1]', Christmas day falls on a Sunday on the following years:'
searchday = searchday.strip.changestr(' ', ',')
say ' 'searchday
return
- Output:
Between 2008 and 2121, Christmas day falls on a Sunday on the following years: 2011,2016,2022,2033,2039,2044,2050,2061,2067,2072,2078,2089,2095,2101,2107,2112,2118
Comparison of Some Common Day-of-Week Algorithms[edit]
The following program exercises some common "Day-0f-Week" algorithms to confirm they all arrive at the same result.
/* NetRexx */
options replace format comments java crossref savelog symbols nobinary
days = 'Monday Tuesday Wednesday Thursday Friday Saturday Sunday'
yearRanges = [int 2008, 2121]
searchday = ''
searchday['index'] = days.wordpos('Sunday')
searchday[0] = 0
algorithmName = ['Java Calendar', 'Zeller[1]', 'Zeller[2]', 'Sakamoto', 'Gauss', 'Keith', 'Babwani']
loop alg = 0 to algorithmName.length - 1
sd = searchday[0] + 1
searchday[0] = sd
searchday['agorithm', sd] = algorithmName[alg]
loop year = yearRanges[0] to yearRanges[1]
select case alg
when 0 then dayIndex = getDaynumJavaLibrary(year, 12, 25)
when 1 then dayIndex = getDaynumZellersCongruenceMethod1(year, 12, 25)
when 2 then dayIndex = getDaynumZellersCongruenceMethod2(year, 12, 25)
when 3 then dayIndex = getDaynumSakamoto(year, 12, 25)
when 4 then dayIndex = getDaynumGauss(year, 12, 25)
when 5 then dayIndex = getDaynumKeith(year, 12, 25)
when 6 then dayIndex = getDaynumBabwani(year, 12, 25)
otherwise nop
end
if dayIndex = searchday['index'] then
searchday[sd] = searchday[sd] year
end year
end alg
-- display results
say 'Between' yearRanges[0] 'and' yearRanges[1]', Christmas day falls on a Sunday in the following years:'
loop r_ = 1 to searchday[0]
searchday[r_] = searchday[r_].strip.changestr(' ', ',')
say searchday['agorithm', r_].right(20)':' searchday[r_]
end r_
return
-- -----------------------------------------------------------------------------
method getDaynumJavaLibrary(Year = int, Month = int, Day = int, iso = Rexx 'Y') public static binary returns int
-- The day-of-week is an integer value where 1 is Sunday, 2 is Monday, ..., and 7 is Saturday
-- For an ISO week date Day-of-Week d (1 = Monday to 7 = Sunday), use d = ((h - 1 + 6) mod 7) + 1
cal = Calendar
jmNumber = [ -
Calendar.JANUARY, Calendar.FEBRUARY, Calendar.MARCH, Calendar.APRIL -
, Calendar.MAY, Calendar.JUNE, Calendar.JULY, Calendar.AUGUST -
, Calendar.SEPTEMBER, Calendar.OCTOBER, Calendar.NOVEMBER, Calendar.DECEMBER -
]
mon = jmNumber[Month - 1]
cal = GregorianCalendar(Year, mon, Day)
h = cal.get(Calendar.DAY_OF_WEEK)
if 'YES'.abbrev(iso.upper, 1) then w = ((h - 1 + 6) // 7) + 1
else w = h
return w
-- -----------------------------------------------------------------------------
method getDaynumZellersCongruenceMethod1(Year = int, Month = int, Day = int, iso = Rexx 'Y') public static returns int
-- DayNum results in an integer in the range 0-6 where 0 represents Monday etc.
-- For an ISO week date add 1
if Month = 1 | Month = 2 then do
Month = Month + 12
Year = Year - 1
end
MonthFactor = 2 * Month + 3 * (Month + 1) % 5
YearFactor = Year + Year % 4 - Year % 100 + Year % 400
DayNum = (Day + MonthFactor + YearFactor) // 7
if 'YES'.abbrev(iso.upper, 1) then d = DayNum + 1
else d = DayNum
return d
-- -----------------------------------------------------------------------------
method getDaynumZellersCongruenceMethod2(Year = int, Month = int, Day = int, iso = Rexx 'Y') public static binary returns int
-- h is the day of the week (0 = Saturday, 1 = Sunday, 2 = Monday, ...)
-- For an ISO week date Day-of-Week d (1 = Monday to 7 = Sunday), use d = ((h + 5) mod 7) + 1
if Month < 3 then do
Month = Month + 12
Year = Year - 1
end
q = Day
m = Month
Y = Year
h = (q + ((m + 1) * 26 % 10) + Y + (Y % 4) + 6 * (Y % 100) + (Y % 400)) // 7
if 'YES'.abbrev(iso.upper, 1) then d = ((h + 5) // 7) + 1
else d = h
return d
-- -----------------------------------------------------------------------------
method getDaynumSakamoto(y = int, m = int, d = int, iso = Rexx 'Y') public static binary returns int
-- h is the day of the week (0 = Sunday, 1 = Monday, 2 = Tuesday...)
-- For an ISO week date Day-of-Week d (1 = Monday to 7 = Sunday), use d = ((h + 6) mod 7) + 1
t = [int 0, 3, 2, 5, 0, 3, 5, 1, 4, 6, 2, 4]
y = y - (m < 3)
h = (y + y % 4 - y % 100 + y % 400 + t[m - 1] + d) // 7
if 'YES'.abbrev(iso.upper, 1) then d = ((h + 6) // 7) + 1
else d = h
return d
-- -----------------------------------------------------------------------------
method getDaynumGauss(Year = int, Month = int, Day = int, iso = Rexx 'Y') public static binary returns int
-- W is week day (0 = Sunday, ..., 6 = Saturday)
-- For an ISO week date Day-of-Week d (1 = Monday to 7 = Sunday), use d = ((h + 6) mod 7) + 1
Year = Year - (Month < 3)
k = double Day
C = double Year % 100
Y = double Year // 100
m = double ((Month + 9) // 12) + 1
W = modulo(int (k + Math.floor(2.6 * m - 0.2) + y + Math.floor(y / 4) + Math.floor(c / 4) - 2 * c), 7)
if 'YES'.abbrev(iso.upper, 1) then h = ((W + 6) // 7) + 1
else h = W
return h
-- -----------------------------------------------------------------------------
method getDaynumKeith(y = int, m = int, d = int, iso = Rexx 'Y') public constant binary returns int
-- W is week day (0 = Sunday, ..., 6 = Saturday)
-- For an ISO week date Day-of-Week d (1 = Monday to 7 = Sunday), use d = ((h + 6) mod 7) + 1
if m < 3 then do
d = d + y
y = y - 1
end
else do
d = d + y - 2
end
h = (23 * m % 9 + d + 4 + y % 4 - y % 100 + y % 400) // 7
if 'YES'.abbrev(iso.upper, 1) then W = ((h + 6) // 7) + 1
else W = h
return W
-- -----------------------------------------------------------------------------
method getDaynumBabwani(Year = int, Month = int, Day = int, iso = Rexx 'Y') public constant binary returns int
-- return dow = Day of week: 0 = Saturday, 1 = Sunday, ... 6 = Friday
-- For an ISO week date Day-of-Week W (1 = Monday to 7 = Sunday), use W = ((dow + 5) mod 7) + 1
y = Year
m = Month
d = Day
dow = int -- dow stands for day of week
dowfg = double
fmonth = int
leap = int
if ((y // 100 == 0) & (y // 400 \= 0)) then -- leap function 1 for leap & 0 for non-leap
leap = 0
else if (y // 4 == 0) then
leap = 1
else
leap = 0
fmonth = 3 + (2 - leap) * ((m + 2) % (2 * m)) + (5 * m + m % 9) % 2 -- f(m) formula
fmonth = fmonth // 7 -- f(m) is brought in range of 0 to 6
century = y % 100
lastdigits = y // 100
dowfg = 1.25 * lastdigits + fmonth + d - 2 * (century // 4) -- function of weekday for Gregorian
dow = int dowfg // 7 -- remainder on division by 7
if 'YES'.abbrev(iso.upper, 1) then W = ((dow + 5) // 7) + 1
else W = dow
return W
-- -----------------------------------------------------------------------------
method modulo(N = int, D = int) inheritable static binary returns int
return (D + (N // D)) // D
- Output:
Between 2008 and 2121, Christmas day falls on a Sunday in the following years:
Java Calendar: 2011,2016,2022,2033,2039,2044,2050,2061,2067,2072,2078,2089,2095,2101,2107,2112,2118
Zeller[1]: 2011,2016,2022,2033,2039,2044,2050,2061,2067,2072,2078,2089,2095,2101,2107,2112,2118
Zeller[2]: 2011,2016,2022,2033,2039,2044,2050,2061,2067,2072,2078,2089,2095,2101,2107,2112,2118
Sakamoto: 2011,2016,2022,2033,2039,2044,2050,2061,2067,2072,2078,2089,2095,2101,2107,2112,2118
Gauss: 2011,2016,2022,2033,2039,2044,2050,2061,2067,2072,2078,2089,2095,2101,2107,2112,2118
Keith: 2011,2016,2022,2033,2039,2044,2050,2061,2067,2072,2078,2089,2095,2101,2107,2112,2118
Babwani: 2011,2016,2022,2033,2039,2044,2050,2061,2067,2072,2078,2089,2095,2101,2107,2112,2118
Nim[edit]
import times
for year in 2008..2121:
if getDayOfWeek(25, mDec, year) == dSun:
stdout.write year, ' '
echo ""
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Oberon-2[edit]
MODULE DayOfWeek;
IMPORT NPCT:Dates, Out;
VAR
year: INTEGER;
date: Dates.Date;
BEGIN
FOR year := 2008 TO 2121 DO
date := Dates.NewDate(25,12,year);
IF date.DayOfWeek() = Dates.sunday THEN
Out.Int(date.year,4);Out.Ln
END
END
END DayOfWeek.
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
MODULE DaysOfWeek; (** AUTHOR ""; PURPOSE ""; *)
IMPORT
Out := KernelLog, Dates;
PROCEDURE Do*;
VAR
date: Dates.DateTime;
i,y,w,wd: LONGINT;
BEGIN
FOR i := 2008 TO 2121 DO
date.year := i;date.month :=12; date.day := 25;
date.hour := 0;date.minute := 0; date.second := 0;
Dates.WeekDate(date,y,w,wd);
IF wd = 7 THEN Out.Int(i,0);Out.Ln END
END
END Do;
END DaysOfWeek.
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Objective-C[edit]
#import <Foundation/Foundation.h>
int main()
{
@autoreleasepool {
for(NSUInteger i=2008; i<2121; i++)
{
NSCalendarDate *d = [[NSCalendarDate alloc]
initWithYear: i
month: 12
day: 25
hour: 0 minute: 0 second:0
timeZone: [NSTimeZone timeZoneWithAbbreviation:@"CET"] ];
if ( [d dayOfWeek] == 0 )
{
printf("25 Dec %u is Sunday\n", i);
}
}
}
return 0;
}
- Output:
25 Dec 2011 is Sunday 25 Dec 2016 is Sunday 25 Dec 2022 is Sunday 25 Dec 2033 is Sunday 25 Dec 2039 is Sunday 25 Dec 2044 is Sunday 25 Dec 2050 is Sunday 25 Dec 2061 is Sunday 25 Dec 2067 is Sunday 25 Dec 2072 is Sunday 25 Dec 2078 is Sunday 25 Dec 2089 is Sunday 25 Dec 2095 is Sunday 25 Dec 2101 is Sunday 25 Dec 2107 is Sunday 25 Dec 2112 is Sunday 25 Dec 2118 is Sunday
OCaml[edit]
#load "unix.cma"
open Unix
try
for i = 2008 to 2121 do
(* I'm lazy so we'll just borrow the current time
instead of having to set all the fields explicitly *)
let mytime = { (localtime (time ())) with
tm_year = i - 1900;
tm_mon = 11;
tm_mday = 25 } in
try
let _, mytime = mktime mytime in
if mytime.tm_wday = 0 then
Printf.printf "25 December %d is Sunday\n" i
with e ->
Printf.printf "%d is the last year we can specify\n" (i-1);
raise e
done
with _ -> ()
- Output:
25 December 2011 is Sunday 25 December 2016 is Sunday 25 December 2022 is Sunday 25 December 2033 is Sunday 2037 is the last year we can specify
With a dedicated library[edit]
Unlike the previous example which only uses the OCaml standard library, here with the OCaml Calendar Library we can go until the year 2121:
open CalendarLib
let list_make_seq first last =
let rec aux i acc =
if i < first then acc
else aux (pred i) (i::acc)
in
aux last []
let print_date (year, month, day) =
Printf.printf "%d-%02d-%02d\n" year month day
let () =
let years = list_make_seq 2008 2121 in
let years = List.filter (fun year ->
Date.day_of_week (Date.make year 12 25) = Date.Sun) years in
print_endline "December 25 is a Sunday in:";
List.iter (Printf.printf "%d\n") years
- Output:
$ ocaml unix.cma str.cma -I +calendar calendarLib.cma xmas_sundays.ml December 25 is a Sunday in: 2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Oforth[edit]
import: date
seqFrom(2008, 2121) filter(#[ 12 25 Date newDate dayOfWeek Date.SUNDAY == ]) .
- Output:
[2011, 2016, 2022, 2033, 2039, 2044, 2050, 2061, 2067, 2072, 2078, 2089, 2095, 2101, 2107, 2112, 2118]
ooRexx[edit]
date = .datetime~new(2008, 12, 25)
lastdate = .datetime~new(2121, 12, 25)
resultList = .array~new -- our collector of years
-- date objects are directly comparable
loop while date <= lastdate
if date~weekday == 7 then resultList~append(date~year)
-- step to the next year
date = date~addYears(1)
end
say "Christmas falls on Sunday in the years" resultList~toString("Line", ", ")
- Output:
Christmas falls on Sunday in the years 2011, 2016, 2022, 2033, 2039, 2044, 2050, 2061, 2067, 2072, 2078, 2089, 2095, 2101, 2107, 2112, 2118
PARI/GP[edit]
njd(D) =
{
my (m, y);
if (D[2] > 2, y = D[1]; m = D[2]+1, y = D[1]-1; m = D[2]+13);
(1461*y)\4 + (306001*m)\10000 + D[3] - 694024 + if (100*(100*D[1]+D[2])+D[3] > 15821004, 2 - y\100 + y\400)
}
for (y = 2008, 2121, if (njd([y,12,25]) % 7 == 1, print(y)));
Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Pascal[edit]
See Delphi
Peloton[edit]
<@ SAI>
<@ ITEFORLI3>2121|2008|
<@ LETVARCAP>Christmas Day|25-Dec-<@ SAYVALFOR>...</@></@>
<@ TSTDOWVARLIT>Christmas Day|1</@>
<@ IFF>
<@ SAYCAP>Christmas Day <@ SAYVALFOR>...</@> is a Sunday</@><@ SAYKEY>__Newline</@>
</@>
</@>
</@>
English dialect variable-length space-padded opcodes
<# suppressimplicitoutput>
<# iterate foriteration literalstring3>2121|2008|
<# let variable capture>Christmas Day|25-Dec-<# say value foriteration>...</#></#>
<# test dayofweek variable literal>Christmas Day|1</#>
<# if>
<# say capture>Christmas Day <# say value foriteration>...</#> is a Sunday</#><# say keyword>__Newline</#>
</#>
</#>
</#>
- Output:
Christmas Day 2011 is a Sunday Christmas Day 2016 is a Sunday Christmas Day 2022 is a Sunday Christmas Day 2033 is a Sunday Christmas Day 2039 is a Sunday Christmas Day 2044 is a Sunday Christmas Day 2050 is a Sunday Christmas Day 2061 is a Sunday Christmas Day 2067 is a Sunday Christmas Day 2072 is a Sunday Christmas Day 2078 is a Sunday Christmas Day 2089 is a Sunday Christmas Day 2095 is a Sunday Christmas Day 2101 is a Sunday Christmas Day 2107 is a Sunday Christmas Day 2112 is a Sunday Christmas Day 2118 is a Sunday
Perl[edit]
#! /usr/bin/perl -w
use Time::Local;
use strict;
foreach my $i (2008 .. 2121)
{
my $time = timelocal(0,0,0,25,11,$i);
my ($s,$m,$h,$md,$mon,$y,$wd,$yd,$is) = localtime($time);
if ( $wd == 0 )
{
print "25 Dec $i is Sunday\n";
}
}
exit 0;
- Output:
25 Dec 2011 is Sunday 25 Dec 2016 is Sunday 25 Dec 2022 is Sunday 25 Dec 2033 is Sunday Day too big - 25195 > 24855 Sec too small - 25195 < 78352 Sec too big - 25195 > 15247 Cannot handle date (0, 0, 0, 25, 11, 2038) at ./ydate.pl line 8
Using the DateTime module from CPAN:
#! /usr/bin/perl -w
use DateTime;
use strict;
foreach my $i (2008 .. 2121)
{
my $dt = DateTime->new( year => $i,
month => 12,
day => 25
);
if ( $dt->day_of_week == 7 )
{
print "25 Dec $i is Sunday\n";
}
}
exit 0;
or shorter:
#! /usr/bin/perl -w
use DateTime;
use strict;
for (2008 .. 2121) {
print "25 Dec $_ is Sunday\n"
if DateTime->new(year => $_, month => 12, day => 25)->day_of_week == 7;
}
exit 0;
- Output:
25 Dec 2011 is Sunday 25 Dec 2016 is Sunday 25 Dec 2022 is Sunday 25 Dec 2033 is Sunday 25 Dec 2039 is Sunday 25 Dec 2044 is Sunday 25 Dec 2050 is Sunday 25 Dec 2061 is Sunday 25 Dec 2067 is Sunday 25 Dec 2072 is Sunday 25 Dec 2078 is Sunday 25 Dec 2089 is Sunday 25 Dec 2095 is Sunday 25 Dec 2101 is Sunday 25 Dec 2107 is Sunday 25 Dec 2112 is Sunday 25 Dec 2118 is Sunday
Alternatively in one line using grep (read from right to left):
#! /usr/bin/perl -w
use DateTime;
use strict;
print join " ", grep { DateTime->new(year => $_, month => 12, day => 25)->day_of_week == 7 } (2008 .. 2121);
0;
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Phix[edit]
-- demo\rosetta\Day_of_the_week.exw sequence res = {} for y=2008 to 2121 do if day_of_week(y,12,25,true)="Sunday" then res = append(res,y) end if end for ?res
- Output:
{2011,2016,2022,2033,2039,2044,2050,2061,2067,2072,2078,2089,2095,2101,2107,2112,2118}
PHP[edit]
<?php
for($i=2008; $i<2121; $i++)
{
$datetime = new DateTime("$i-12-25 00:00:00");
if ( $datetime->format("w") == 0 )
{
echo "25 Dec $i is Sunday\n";
}
}
?>
- Output:
25 Dec 2011 is Sunday 25 Dec 2016 is Sunday 25 Dec 2022 is Sunday 25 Dec 2033 is Sunday 25 Dec 2039 is Sunday 25 Dec 2044 is Sunday 25 Dec 2050 is Sunday 25 Dec 2061 is Sunday 25 Dec 2067 is Sunday 25 Dec 2072 is Sunday 25 Dec 2078 is Sunday 25 Dec 2089 is Sunday 25 Dec 2095 is Sunday 25 Dec 2101 is Sunday 25 Dec 2107 is Sunday 25 Dec 2112 is Sunday 25 Dec 2118 is Sunday
PicoLisp[edit]
(for (Y 2008 (>= 2121 Y) (inc Y))
(when (= "Sunday" (day (date Y 12 25)))
(printsp Y) ) )
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Pike[edit]
filter(Calendar.Year(2008)->range(Calendar.Year(2121))->years()->month(12)->day(25), lambda(object day){ return day->week_day()==7; })->year()->format_nice();
- Output:
Result: ({ /* 17 elements */
"2011",
"2016",
"2022",
"2033",
"2039",
"2044",
"2050",
"2061",
"2067",
"2072",
"2078",
"2089",
"2095",
"2101",
"2107",
"2112",
"2118"
})
PL/I[edit]
declare i picture '9999';
do i = 2008 to 2121;
if weekday(days('25Dec' || i, 'DDMmmYYYY')) = 1 then
put skip list ('Christmas day ' || i || ' is a Sunday');
end;
PowerShell[edit]
2008..2121 | Where-Object { (Get-Date $_-12-25).DayOfWeek -eq "Sunday" }
Find Christmas holiday for any day and/or year[edit]
function Get-ChristmasHoliday
{
[CmdletBinding()]
[OutputType([PSCustomObject])]
Param
(
[Parameter(Mandatory=$false,
ValueFromPipeline=$true,
ValueFromPipelineByPropertyName=$true,
Position=0)]
[ValidateRange(1,9999)]
[int[]]
$Year = (Get-Date).Year
)
Process
{
[datetime]$christmas = Get-Date $Year/12/25
switch ($christmas.DayOfWeek)
{
"Sunday" {[datetime[]]$dates = 1..5 | ForEach-Object {$christmas.AddDays($_)}}
"Monday" {[datetime[]]$dates = $christmas, $christmas.AddDays(1)}
"Saturday" {[datetime[]]$dates = $christmas.AddDays(-2), $christmas.AddDays(-1)}
Default {[datetime[]]$dates = $christmas.AddDays(-1), $christmas}
}
$dates | Group-Object -Property Year |
Select-Object -Property @{Name="Year" ; Expression={$_.Name}},
@{Name="DayOfWeek"; Expression={$christmas.DayOfWeek}},
@{Name="Christmas"; Expression={$christmas.ToString("MM/dd/yyyy")}},
@{Name="DaysOff" ; Expression={$_.Group | ForEach-Object {$_.ToString("MM/dd/yyyy")}}}
}
}
Satisfy the task requirement:
2008..2121 | Get-ChristmasHoliday | where DayOfWeek -match Su
- Output:
Year DayOfWeek Christmas DaysOff
---- --------- --------- -------
2011 Sunday 12/25/2011 {12/26/2011, 12/27/2011, 12/28/2011, 12/29/2011...}
2016 Sunday 12/25/2016 {12/26/2016, 12/27/2016, 12/28/2016, 12/29/2016...}
2022 Sunday 12/25/2022 {12/26/2022, 12/27/2022, 12/28/2022, 12/29/2022...}
2033 Sunday 12/25/2033 {12/26/2033, 12/27/2033, 12/28/2033, 12/29/2033...}
2039 Sunday 12/25/2039 {12/26/2039, 12/27/2039, 12/28/2039, 12/29/2039...}
2044 Sunday 12/25/2044 {12/26/2044, 12/27/2044, 12/28/2044, 12/29/2044...}
2050 Sunday 12/25/2050 {12/26/2050, 12/27/2050, 12/28/2050, 12/29/2050...}
2061 Sunday 12/25/2061 {12/26/2061, 12/27/2061, 12/28/2061, 12/29/2061...}
2067 Sunday 12/25/2067 {12/26/2067, 12/27/2067, 12/28/2067, 12/29/2067...}
2072 Sunday 12/25/2072 {12/26/2072, 12/27/2072, 12/28/2072, 12/29/2072...}
2078 Sunday 12/25/2078 {12/26/2078, 12/27/2078, 12/28/2078, 12/29/2078...}
2089 Sunday 12/25/2089 {12/26/2089, 12/27/2089, 12/28/2089, 12/29/2089...}
2095 Sunday 12/25/2095 {12/26/2095, 12/27/2095, 12/28/2095, 12/29/2095...}
2101 Sunday 12/25/2101 {12/26/2101, 12/27/2101, 12/28/2101, 12/29/2101...}
2107 Sunday 12/25/2107 {12/26/2107, 12/27/2107, 12/28/2107, 12/29/2107...}
2112 Sunday 12/25/2112 {12/26/2112, 12/27/2112, 12/28/2112, 12/29/2112...}
2118 Sunday 12/25/2118 {12/26/2118, 12/27/2118, 12/28/2118, 12/29/2118...}
Get days off for a random year:
Get-ChristmasHoliday -Year (2008..2121 | Get-Random)
- Output:
Year DayOfWeek Christmas DaysOff
---- --------- --------- -------
2110 Thursday 12/25/2110 {12/24/2110, 12/25/2110}
Get days off for the current year using the Year property returned by Get-Date:
(Get-Date | Get-ChristmasHoliday).DaysOff
- Output:
12/26/2016 12/27/2016 12/28/2016 12/29/2016 12/30/2016
Get days off for the current year as [DateTime] objects:
(Get-Date | Get-ChristmasHoliday).DaysOff | Get-Date
- Output:
Monday, December 26, 2016 12:00:00 AM Tuesday, December 27, 2016 12:00:00 AM Wednesday, December 28, 2016 12:00:00 AM Thursday, December 29, 2016 12:00:00 AM Friday, December 30, 2016 12:00:00 AM
Prolog[edit]
Works with SWI-Prolog;
main() :-
christmas_days_falling_on_sunday(2011, 2121, SundayList),
writeln(SundayList).
christmas_days_falling_on_sunday(StartYear, EndYear, SundayList) :-
numlist(StartYear, EndYear, YearRangeList),
include(is_christmas_day_a_sunday, YearRangeList, SundayList).
is_christmas_day_a_sunday(Year) :-
Date = date(Year, 12, 25),
day_of_the_week(Date, DayOfTheWeek),
DayOfTheWeek == 7.
- Output:
?- main. [2011,2016,2022,2033,2039,2044,2050,2061,2067,2072,2078,2089,2095,2101,2107,2112,2118] true.
PureBasic[edit]
PureBasic's internal Date() is limited between 1970-01-01 00:00:00 and 2038-01-19 03:14:07
For i=2008 To 2037
If DayOfWeek(Date(i,12,25,0,0,0))=0
PrintN(Str(i))
EndIf
Next
Python[edit]
from calendar import weekday, SUNDAY
[year for year in range(2008, 2122) if weekday(year, 12, 25) == SUNDAY]
- Output:
[2011, 2016, 2022, 2033, 2039, 2044, 2050, 2061, 2067, 2072, 2078, 2089, 2095, 2101, 2107, 2112, 2118]
The function calendar.weekday accepts all dates between 1/1/1 and 9999/12/31, and uses the proleptic Gregorian calendar before adoption of the Gregorian calendar in 1582. There is no gap between 1582/10/4 and 1582/10/15, as can be seen with print(calendar.calendar(1582)).
Or, in terms of datetime:
'''Days of the week'''
from datetime import date
from itertools import islice
# xmasIsSunday :: Int -> Bool
def xmasIsSunday(y):
'''True if Dec 25 in the given year is a Sunday.'''
return 6 == date(y, 12, 25).weekday()
# main :: IO ()
def main():
'''Years between 2008 and 2121 with 25 Dec on a Sunday'''
xs = list(filter(
xmasIsSunday,
enumFromTo(2008)(2121)
))
total = len(xs)
print(
fTable(main.__doc__ + ':\n\n' + '(Total ' + str(total) + ')\n')(
lambda i: str(1 + i)
)(str)(index(xs))(
enumFromTo(0)(total - 1)
)
)
# GENERIC -------------------------------------------------
# enumFromTo :: (Int, Int) -> [Int]
def enumFromTo(m):
'''Integer enumeration from m to n.'''
return lambda n: list(range(m, 1 + n))
# index (!!) :: [a] -> Int -> a
def index(xs):
'''Item at given (zero-based) index.'''
return lambda n: None if 0 > n else (
xs[n] if (
hasattr(xs, "__getitem__")
) else next(islice(xs, n, None))
)
# FORMATTING ---------------------------------------------
# fTable :: String -> (a -> String) ->
# (b -> String) -> (a -> b) -> [a] -> String
def fTable(s):
'''Heading -> x display function -> fx display function ->
f -> xs -> tabular string.
'''
def go(xShow, fxShow, f, xs):
ys = [xShow(x) for x in xs]
w = max(map(len, ys))
return s + '\n' + '\n'.join(map(
lambda x, y: y.rjust(w, ' ') + ' -> ' + fxShow(f(x)),
xs, ys
))
return lambda xShow: lambda fxShow: lambda f: lambda xs: go(
xShow, fxShow, f, xs
)
# MAIN --
if __name__ == '__main__':
main()
- Output:
Years between 2008 and 2121 with 25 Dec on a Sunday: (Total 17) 1 -> 2011 2 -> 2016 3 -> 2022 4 -> 2033 5 -> 2039 6 -> 2044 7 -> 2050 8 -> 2061 9 -> 2067 10 -> 2072 11 -> 2078 12 -> 2089 13 -> 2095 14 -> 2101 15 -> 2107 16 -> 2112 17 -> 2118
Quackery[edit]
Using Tomohiko Sakamoto's algorithm.
[ over 3 < if [ 1 - ]
dup 4 / over +
over 100 / -
swap 400 / +
swap 1 -
[ table
0 3 2 5 0 3
5 1 4 6 2 4 ]
+ + 7 mod ] is dayofweek ( day month year --> weekday )
say "The 25th of December is a Sunday in: " cr
2121 1+ 2008 - times
[ 25 12 i^ 2008 + dayofweek
0 = if [ i^ 2008 + echo sp ] ]
- Output:
The 25th of December is a Sunday in: 2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
R[edit]
years <- 2008:2121
xmas <- as.POSIXlt(paste0(years, '/12/25'))
years[xmas$wday==0]
# 2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
# Also:
xmas=seq(as.Date("2008/12/25"), as.Date("2121/12/25"), by="year")
as.numeric(format(xmas[weekdays(xmas)== 'Sunday'], "%Y"))
# Still another solution, using ISOdate and weekdays
with(list(years=2008:2121), years[weekdays(ISOdate(years, 12, 25)) == "Sunday"])
# Or with "subset"
subset(data.frame(years=2008:2121), weekdays(ISOdate(years, 12, 25)) == "Sunday")$years
# Simply replace "Sunday" with whatever it's named in your country,
# or set locale first, with
Sys.setlocale(cat="LC_ALL", "en")
# Under MS Windows, write instead
Sys.setlocale("LC_ALL", "English")
Racket[edit]
#lang racket
(require racket/date)
(define (xmas-on-sunday? year)
(zero? (date-week-day (seconds->date (find-seconds 0 0 12 25 12 year)))))
(for ([y (in-range 2008 2121)] #:when (xmas-on-sunday? y))
(displayln y))
Raku[edit]
(formerly Perl 6)
As Perl 5, except DateTime is built-in, so you don't need to download a module of that name:
say join ' ', grep { Date.new($_, 12, 25).day-of-week == 7 }, 2008 .. 2121;
REBOL[edit]
rebol [
Title: "Yuletide Holiday"
URL: http://rosettacode.org/wiki/Yuletide_Holiday
]
for y 2008 2121 1 [
d: to-date reduce [y 12 25]
if 7 = d/weekday [prin [y ""]]
]
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Red[edit]
Red []
repeat yy 114 [
d: to-date reduce [25 12 (2007 + yy )]
if 7 = d/weekday [ print d ] ;; 7 = sunday
]
;; or
print "version 2"
d: to-date [25 12 2008]
while [d <= 25/12/2121 ] [
if 7 = d/weekday [
print rejoin [d/day '. d/month '. d/year ]
]
d/year: d/year + 1
]
- Output:
25-Dec-201125-Dec-2016 25-Dec-2022 25-Dec-2033 25-Dec-2039 25-Dec-2044 25-Dec-2050 25-Dec-2061 25-Dec-2067 25-Dec-2072 25-Dec-2078 25-Dec-2089 25-Dec-2095 25-Dec-2101 25-Dec-2107 25-Dec-2112 25-Dec-2118 version 2 25.12.2011 25.12.2016 25.12.2022 25.12.2033 25.12.2039 25.12.2044 25.12.2050 25.12.2061 25.12.2067 25.12.2072 25.12.2078 25.12.2089 25.12.2095 25.12.2101 25.12.2107 25.12.2112 25.12.2118 >>
REXX[edit]
using DATE weekday[edit]
The extended DATE parameters (arguments 2 and 3) are only supported by the newer REXX interpreters.
do year=2008 to 2121
if date('w', year"1225", 's') == 'Sunday' then say year
end /*year*/
- output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
using DATE base[edit]
The extended DATE parameters (arguments 2 and 3) are only supported by the newer REXX interpreters.
do year=2008 to 2121
if date('b', year"1225", 's') // 7 == 6 then say year
end /*year*/
- output is identical to the 1st REXX version.
using DATE iso[edit]
Works with Regina REXX only.
The extended DATE parameters (arguments 2 and 3) are only supported by the newer REXX interpreters.
Programming note: The ISO option of the date BIF is a Regina extension.
Language note: the DATE built-in function always returns the day-of-week in English, no matter what the native language is in effect.
/*REXX program displays in which years 12/25 (December 25th) falls on a Sunday. */
parse arg start finish . /*get the START and FINISH years. */
if start=='' | start=="," then start=2008 /*Not specified? Then use the default.*/
if finish=='' | finish=="," then finish=2121 /* " " " " " " */
do y=start to finish /*process all the years specified. */
if date('Weekday', y"-12-25", 'ISO')\=='Sunday' then iterate
/* if date('w' , y"-12-25", 'i' ) ··· (same as above). */
/* ↑↑↑↑↑↑ ↑↑↑↑↑↑↑↑↑↑ ↑↑↑ */
/* option yyyy-mm-dd fmt */
say 'December 25th,' y "falls on a Sunday."
end /*y*/
/*stick a fork in it, we're all done. */
- output when using the default inputs:
December 25th, 2011 falls on a Sunday. December 25th, 2016 falls on a Sunday. December 25th, 2022 falls on a Sunday. December 25th, 2033 falls on a Sunday. December 25th, 2039 falls on a Sunday. December 25th, 2044 falls on a Sunday. December 25th, 2050 falls on a Sunday. December 25th, 2061 falls on a Sunday. December 25th, 2067 falls on a Sunday. December 25th, 2072 falls on a Sunday. December 25th, 2078 falls on a Sunday. December 25th, 2089 falls on a Sunday. December 25th, 2095 falls on a Sunday. December 25th, 2101 falls on a Sunday. December 25th, 2107 falls on a Sunday. December 25th, 2112 falls on a Sunday. December 25th, 2118 falls on a Sunday.
old school DOW[edit]
This DOW (day-of-week) version will work with any version of a REXX interpreter.
/*REXX program (old school) displays in which years 12/25 (Dec. 25th) falls on a Sunday.*/
parse arg start finish . /*get the START and FINISH years. */
if start=='' | start=="," then start=2008 /*Not specified? Then use the default.*/
if finish=='' | finish=="," then finish=2121 /* " " " " " " */
do y=start to finish /*process all the years specified. */
if dow(12,25,y)==1 then say 'December 25th,' y "falls on a Sunday."
end /*y*/
exit /*stick a fork in it, we're all done. */
/*──────────────────────────────────────────────────────────────────────────────────────*/
dow: procedure; parse arg m,d,y; if m<3 then do; m= m+12; y= y-1; end
yL= left(y, 2); yr= right(y, 2); w= (d + (m+1)*26%10 +yr +yr%4 +yL%4 +5*yL) //7
if w==0 then w= 7; return w /*Sunday=1, Monday=2, ··· Saturday=7*/
- output when using the default input:
December 25th, 2011 falls on a Sunday. December 25th, 2016 falls on a Sunday. December 25th, 2022 falls on a Sunday. December 25th, 2033 falls on a Sunday. December 25th, 2039 falls on a Sunday. December 25th, 2044 falls on a Sunday. December 25th, 2050 falls on a Sunday. December 25th, 2061 falls on a Sunday. December 25th, 2067 falls on a Sunday. December 25th, 2072 falls on a Sunday. December 25th, 2078 falls on a Sunday. December 25th, 2089 falls on a Sunday. December 25th, 2095 falls on a Sunday. December 25th, 2101 falls on a Sunday. December 25th, 2107 falls on a Sunday. December 25th, 2112 falls on a Sunday. December 25th, 2118 falls on a Sunday.
Ring[edit]
for n = 2008 to 2121
if n < 2100 leap = n - 1900 else leap = n - 1904 ok
m = (((n-1900)%7) + floor(leap/4) + 27) % 7
if m = 4 see "25 Dec " + n + nl ok
next
Ruby[edit]
require 'date'
(2008..2121).each {|year| puts "25 Dec #{year}" if Date.new(year, 12, 25).sunday? }
- Output:
25 Dec 2011 25 Dec 2016 25 Dec 2022 25 Dec 2033 25 Dec 2039 25 Dec 2044 25 Dec 2050 25 Dec 2061 25 Dec 2067 25 Dec 2072 25 Dec 2078 25 Dec 2089 25 Dec 2095 25 Dec 2101 25 Dec 2107 25 Dec 2112 25 Dec 2118
Or using the Time class
(2008..2121).each {|year| puts "25 Dec #{year}" if Time.local(year, 12, 25).sunday?}
- Output:
25 Dec 2011 25 Dec 2016 25 Dec 2022 25 Dec 2033 25 Dec 2039 25 Dec 2044 25 Dec 2050 25 Dec 2061 25 Dec 2067 25 Dec 2072 25 Dec 2078 25 Dec 2089 25 Dec 2095 25 Dec 2101 25 Dec 2107 25 Dec 2112 25 Dec 2118
(Note: The Time class could not handle dates beyond 2038 prior to Ruby 1.9.2.[1])
Run BASIC[edit]
for year = 2008 to 2121
if val(date$("12-25-";year)) mod 7 = 5 then print "For ";year;"xmas is Sunday"
next year
For 2011 xmas is Sunday For 2016 xmas is Sunday For 2022 xmas is Sunday For 2033 xmas is Sunday For 2039 xmas is Sunday For 2044 xmas is Sunday For 2050 xmas is Sunday For 2061 xmas is Sunday For 2067 xmas is Sunday For 2072 xmas is Sunday For 2078 xmas is Sunday For 2089 xmas is Sunday For 2095 xmas is Sunday For 2101 xmas is Sunday For 2107 xmas is Sunday For 2112 xmas is Sunday For 2118 xmas is Sunday
Rust[edit]
extern crate chrono;
use chrono::prelude::*;
fn main() {
let years = (2008..2121).filter(|&y| Local.ymd(y, 12, 25).weekday() == Weekday::Sun).collect::<Vec<i32>>();
println!("Years = {:?}", years);
}
Output:
Years = [2011, 2016, 2022, 2033, 2039, 2044, 2050, 2061, 2067, 2072, 2078, 2089, 2095, 2101, 2107, 2112, 2118]
S-BASIC[edit]
$constant SUNDAY = 0
rem - compute p mod q
function mod(p, q = integer) = integer
end = p - q * (p/q)
comment
return day of week (Sun = 0, Mon = 1, etc.) for a
given Gregorian calendar date using Zeller's congruence
end
function dayofweek (mo, da, yr = integer) = integer
var y, c, z = integer
if mo < 3 then
begin
mo = mo + 10
yr = yr - 1
end
else mo = mo - 2
y = mod(yr,100)
c = int(yr / 100)
z = int((26 * mo - 2) / 10)
z = z + da + y + int(y/4) + int(c/4) - 2 * c + 777
z = mod(z,7)
end = z
rem - main program
var year = integer
print "Christmas will fall on a Sunday in"
for year=2008 to 2121
if dayofweek(12,25,year) = SUNDAY then
print year
next year
end
- Output:
Christmas will fall on a Sunday in 2011 2016 2011 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
SAS[edit]
data _null_;
do y=2008 to 2121;
a=mdy(12,25,y);
if weekday(a)=1 then put y;
end;
run;
/* 2011 2016 2022 2033 2039 2044 2050 2061 2067
2072 2078 2089 2095 2101 2107 2112 2118 */
Scala[edit]
JDK (discouraged)[edit]
import java.util.{ Calendar, GregorianCalendar }
import Calendar.{ DAY_OF_WEEK, DECEMBER, SUNDAY }
object DayOfTheWeek extends App {
val years = 2008 to 2121
val yuletide =
years.filter(year => (new GregorianCalendar(year, DECEMBER, 25)).get(DAY_OF_WEEK) == SUNDAY)
// If you want a test: (optional)
assert(yuletide ==
Seq(2011, 2016, 2022, 2033, 2039, 2044, 2050, 2061,
2067, 2072, 2078, 2089, 2095, 2101, 2107, 2112, 2118))
println(yuletide.mkString(
s"${yuletide.length} Years between ${years.head} and ${years.last}" +
" including where Christmas is observed on Sunday:\n", ", ", "."))
}
JDK >= 8 (recommended)[edit]
Naive programming[edit]
import java.time.{ DayOfWeek, LocalDate }
object DayOfTheWeek1 extends App {
val years = 2008 to 2121
val yuletide = for {
year <- years
if LocalDate.of(year, 12, 25).getDayOfWeek() == DayOfWeek.SUNDAY
} yield year
println(yuletide.mkString(
s"${yuletide.count(p => true)} Years between ${years.head} and ${years.last}" +
" including where Christmas is observed on Sunday:\n", ", ", "."))
}
Idiomatic programming[edit]
import java.time.{ DayOfWeek, LocalDate }
object DayOfTheWeek1 extends App {
val years = 2008 to 2121
val yuletide =
years.filter(year => (LocalDate.of(year, 12, 25).getDayOfWeek() == DayOfWeek.SUNDAY))
// If you want a test: (optional)
assert(yuletide ==
Seq(2011, 2016, 2022, 2033, 2039, 2044, 2050, 2061,
2067, 2072, 2078, 2089, 2095, 2101, 2107, 2112, 2118))
println(yuletide.mkString(
s"${yuletide.length} Years between ${years.head} and ${years.last}" +
" including where Christmas is observed on Sunday:\n", ", ", "."))
}
Tail recursion[edit]
import java.time.{ DayOfWeek, LocalDate }
import scala.annotation.tailrec
object DayOfTheWeek3 extends App {
val years = 2008 to 2121
val yuletide = {
@tailrec
def inner(anni: List[Int], accu: List[Int]): List[Int] = {
if (anni == Nil) accu
else inner(anni.tail, accu ++
(if (LocalDate.of(anni.head, 12, 25).getDayOfWeek() == DayOfWeek.SUNDAY) List(anni.head)
else Nil))
}
inner(years.toList, Nil)
}
// If you want a test: (optional)
assert(yuletide ==
Seq(2011, 2016, 2022, 2033, 2039, 2044, 2050, 2061,
2067, 2072, 2078, 2089, 2095, 2101, 2107, 2112, 2118))
println(yuletide.mkString(
s"${yuletide.length} Years between ${years.head} and ${years.last}" +
" including where Christmas is observed on Sunday:\n", ", ", "."))
}
- Output of all solutions:
Years between 2008 and 2121 including when Christmas is observed on Sunday: 2011, 2016, 2022, 2033, 2039, 2044, 2050, 2061, 2067, 2072, 2078, 2089, 2095, 2101, 2107, 2112, 2118.
Scheme[edit]
(define (day-of-week year month day)
(if (< month 3)
(begin (set! month (+ month 12)) (set! year (- year 1))))
(+ 1
(remainder (+ 5 day (quotient (* (+ 1 month) 13) 5)
year (quotient year 4) (* (quotient year 100) 6) (quotient year 400))
7)))
(define (task)
(let loop ((y 2121) (v '()))
(if (< y 2008)
v
(loop (- y 1)
(if (= 7 (day-of-week y 12 25))
(cons y v)
v)))))
(task)
; (2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118)
Seed7[edit]
The library time.s7i defines the function dayOfWeek, which returns 1 for monday, 2 for tuesday, and so on up to 7 for sunday.
$ include "seed7_05.s7i";
include "time.s7i";
const proc: main is func
local
var integer: year is 0;
begin
for year range 2008 to 2122 do
if dayOfWeek(date(year, 12, 25)) = 7 then
writeln("Christmas comes on a sunday in " <& year);
end if;
end for;
end func;
- Output:
Christmas comes on a sunday in 2011 Christmas comes on a sunday in 2016 Christmas comes on a sunday in 2022 Christmas comes on a sunday in 2033 Christmas comes on a sunday in 2039 Christmas comes on a sunday in 2044 Christmas comes on a sunday in 2050 Christmas comes on a sunday in 2061 Christmas comes on a sunday in 2067 Christmas comes on a sunday in 2072 Christmas comes on a sunday in 2078 Christmas comes on a sunday in 2089 Christmas comes on a sunday in 2095 Christmas comes on a sunday in 2101 Christmas comes on a sunday in 2107 Christmas comes on a sunday in 2112 Christmas comes on a sunday in 2118
SenseTalk[edit]
// In what years between 2008 and 2121 will the 25th of December be a Sunday?
repeat with year = 2008 to 2121
set Christmas to "12/25/" & year
if the WeekDayName of Christmas is Sunday then
put "Christmas in " & year & " falls on a Sunday"
end if
end repeat
- Output:
Christmas in 2011 falls on a Sunday Christmas in 2016 falls on a Sunday Christmas in 2022 falls on a Sunday Christmas in 2033 falls on a Sunday Christmas in 2039 falls on a Sunday Christmas in 2044 falls on a Sunday Christmas in 2050 falls on a Sunday Christmas in 2061 falls on a Sunday Christmas in 2067 falls on a Sunday Christmas in 2072 falls on a Sunday Christmas in 2078 falls on a Sunday Christmas in 2089 falls on a Sunday Christmas in 2095 falls on a Sunday Christmas in 2101 falls on a Sunday Christmas in 2107 falls on a Sunday Christmas in 2112 falls on a Sunday Christmas in 2118 falls on a Sunday
Sidef[edit]
require('Time::Local')
for year in (2008 .. 2121) {
var time = %S<Time::Local>.timelocal(0,0,0,25,11,year)
var wd = Time(time).local.wday
if (wd == 0) {
say "25 Dec #{year} is Sunday"
}
}
- Output:
25 Dec 2011 is Sunday 25 Dec 2016 is Sunday 25 Dec 2022 is Sunday 25 Dec 2033 is Sunday 25 Dec 2039 is Sunday 25 Dec 2044 is Sunday 25 Dec 2050 is Sunday 25 Dec 2061 is Sunday 25 Dec 2067 is Sunday 25 Dec 2072 is Sunday 25 Dec 2078 is Sunday 25 Dec 2089 is Sunday 25 Dec 2095 is Sunday 25 Dec 2101 is Sunday 25 Dec 2107 is Sunday 25 Dec 2112 is Sunday 25 Dec 2118 is Sunday
Simula[edit]
BEGIN
INTEGER M,D,Y;
M := 12;
D := 25;
FOR Y := 2008 STEP 1 UNTIL 2121 DO BEGIN
INTEGER W,A,MM,YY;
A := (14 - M)//12;
MM := M + 12*A - 2;
YY := Y - A;
W := D + ((13*MM - 1)//5) + YY + (YY//4) - (YY//100) + (YY//400);
W := MOD(W,7);
IF W = 0 THEN
BEGIN OUTINT(Y,0);
OUTIMAGE;
END;
END;
END.
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Smalltalk[edit]
2008 to: 2121 do: [ :year | |date|
date := Date newDay: 25 monthIndex: 12 year: year.
date dayName = #Sunday
ifTrue: [ date displayNl ]
]
- Output:
25-Dec-2011 25-Dec-2016 25-Dec-2022 25-Dec-2033 25-Dec-2039 25-Dec-2044 25-Dec-2050 25-Dec-2061 25-Dec-2067 25-Dec-2072 25-Dec-2078 25-Dec-2089 25-Dec-2095 25-Dec-2101 25-Dec-2107 25-Dec-2112 25-Dec-2118
SQL[edit]
SQL has good support for date functions; care must be taken with NLS settings (globalization support), in the code below the date format language is passed in as an argument to the relevant function. (Or, see a variation that does not depend on language settings, after the output shown below.)
SELECT EXTRACT(YEAR FROM dt) AS year_with_xmas_on_sunday
FROM (
SELECT add_months(DATE '2008-12-25', 12 * (level - 1)) AS dt
FROM dual
CONNECT BY level <= 2121 - 2008 + 1
)
WHERE to_char(dt, 'Dy', 'nls_date_language=English') = 'Sun'
ORDER BY 1
;
- Output:
YEAR_WITH_XMAS_ON_SUNDAY
------------------------
2011
2016
2022
2033
2039
2044
2050
2061
2067
2072
2078
2089
2095
2101
2107
2112
2118
17 rows selected.
Alternatively, the WHERE clause can be written in a way that avoids the complication of language settings. The (overloaded) TRUNC function, as applied to dates, takes a second argument indicating "to what" we must truncate. One option is 'iw' for "ISO week"; this truncates to the most recent Monday (the beginning of the ISO standard week, which is Monday through Sunday by definition). Like so (replace in the query above):
WHERE dt - trunc(dt, 'iw') = 6
Standard ML[edit]
(* Call: yearsOfSundayXmas(2008, 2121) *)
fun yearsOfSundayXmas(fromYear, toYear) =
if fromYear>toYear then
()
else
let
val d = Date.date {year=fromYear, month=Date.Dec, day=25,
hour=0, minute=0, second=0,
offset=SOME Time.zeroTime}
val wd = Date.weekDay d
in
if wd=Date.Sun then
(
print(Int.toString fromYear ^ "\n");
yearsOfSundayXmas(fromYear+1, toYear)
)
else
yearsOfSundayXmas(fromYear+1, toYear)
end;
- Output:
- yearsOfSundayXmas(2008, 2121); 2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Stata[edit]
The dow() function returns the day of week, where sunday is zero and saturday is 6.
clear
sca n=2121-2008+1
set obs `=n'
gen year=2007+_n
list if dow(mdy(12,25,year))==0, noobs sep(0)
+------+
| year |
|------|
| 2011 |
| 2016 |
| 2022 |
| 2033 |
| 2039 |
| 2044 |
| 2050 |
| 2061 |
| 2067 |
| 2072 |
| 2078 |
| 2089 |
| 2095 |
| 2101 |
| 2107 |
| 2112 |
| 2118 |
+------+
Mata[edit]
year=2008::2121
select(year,dow(mdy(12,25,year)):==0)
Suneido[edit]
year = 2008
while (year <= 2121)
{
if Date('#' $ year $ '1225').WeekDay() is 0
Print(year)
++year
}
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Swift[edit]
import Cocoa
var year=2008
let formatter=NSDateFormatter()
formatter.dateFormat = "yyyy-MM-dd"
let gregorian:NSCalendar! = NSCalendar(calendarIdentifier: NSCalendarIdentifierGregorian)
while (year<2122){
var date:NSDate!=formatter.dateFromString(String(year)+"-12-25")
var components=gregorian.components(NSCalendarUnit.CalendarUnitWeekday, fromDate: date)
var dayOfWeek:NSInteger=components.weekday
if(dayOfWeek==1){
println(year)
}
year++
}
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Tcl[edit]
package require Tcl 8.5
for {set y 2008} {$y <= 2121} {incr y} {
if {[clock format [clock scan "$y-12-25" -format {%Y-%m-%d}] -format %w] == 0} {
puts "xmas $y is a sunday"
}
}
- Output:
xmas 2011 is a sunday xmas 2016 is a sunday xmas 2022 is a sunday xmas 2033 is a sunday xmas 2039 is a sunday xmas 2044 is a sunday xmas 2050 is a sunday xmas 2061 is a sunday xmas 2067 is a sunday xmas 2072 is a sunday xmas 2078 is a sunday xmas 2089 is a sunday xmas 2095 is a sunday xmas 2101 is a sunday xmas 2107 is a sunday xmas 2112 is a sunday xmas 2118 is a sunday
TI-83 BASIC[edit]
Works with TI-84+/SE only
:For(A,2008,2121
:If dayofWk(A,12,25)=1
:Disp A
:End
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118 Done
TUSCRIPT[edit]
$$ MODE TUSCRIPT
PRINT "25th of December will be a Sunday in the following years: "
LOOP year=2008,2121
SET dayofweek = DATE (number,25,12,year,nummer)
IF (dayofweek==7) PRINT year
ENDLOOP
- Output:
25th of December will be a Sunday in the following years: 2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
UNIX Shell[edit]
Unix commands may use time_t to count seconds since the epoch. For systems with 32-bit time, the counter overflows during 19 January 2038. These scripts continue to 2121 and may need a system with 64-bit time, to prevent the overflow.
With GNU date[edit]
This solution uses date -d, which seems to be a GNU extension, so it only works with those systems.
#! /bin/bash
for (( i=2008; i<=2121; ++i ))
do
date -d "$i-12-25"
done |grep Sun
exit 0
The first lines of output (from a GNU/Linux system with 32bit time_t, date version 6.9) are
Sun Dec 25 00:00:00 CET 2011
Sun Dec 25 00:00:00 CET 2016
Sun Dec 25 00:00:00 CET 2022
Sun Dec 25 00:00:00 CET 2033
date: invalid date `2038-12-25'
I.e., starting from year 2038, the date command (which uses the glibc library, at least on GNU systems), is not able to recognise the date as a valid one!
Different machine/OS version (64 bit time_t): This is the same command run on RedHat Linux.
bash-3.00$ date --version
date (coreutils) 5.2.1
Written by David MacKenzie.
Copyright (C) 2004 Free Software Foundation, Inc.
This is free software; see the source for copying conditions. There is NO
warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.
bash-3.00$ uname -a
Linux brslln01 2.6.9-67.ELsmp #1 SMP Wed Nov 7 13:56:44 EST 2007 x86_64 x86_64 x86_64 GNU/Linux
bash-3.00$ for((i=2009; i <= 2121; i++)); do date -d "$i-12-25" |egrep Sun; done
Sun Dec 25 00:00:00 GMT 2011
Sun Dec 25 00:00:00 GMT 2016
Sun Dec 25 00:00:00 GMT 2022
Sun Dec 25 00:00:00 GMT 2033
Sun Dec 25 00:00:00 GMT 2039
Sun Dec 25 00:00:00 GMT 2044
Sun Dec 25 00:00:00 GMT 2050
Sun Dec 25 00:00:00 GMT 2061
Sun Dec 25 00:00:00 GMT 2067
Sun Dec 25 00:00:00 GMT 2072
Sun Dec 25 00:00:00 GMT 2078
Sun Dec 25 00:00:00 GMT 2089
Sun Dec 25 00:00:00 GMT 2095
Sun Dec 25 00:00:00 GMT 2101
Sun Dec 25 00:00:00 GMT 2107
Sun Dec 25 00:00:00 GMT 2112
Sun Dec 25 00:00:00 GMT 2118
bash-3.00$
With GNU date and GNU seq (UnixPipes)[edit]
Like the previous solution, this solution uses date -d, which seems to be a GNU extension. Output is same as previous solution.
seq 2008 2121 | xargs -IYEAR -n 1 date +%c -d 'Dec 25 YEAR' | grep Sun
With Unix cal[edit]
The cal command is a tradition since Version 6 AT&T UNIX. This solution assumes that cal will always output a calendar in this format.
$ cal 12 2011
December 2011
Su Mo Tu We Th Fr Sa
1 2 3
4 5 6 7 8 9 10
11 12 13 14 15 16 17
18 19 20 21 22 23 24
25 26 27 28 29 30 31
This format always puts Sunday in columns 1 and 2. The solution uses tail to delete the first 2 lines (month, year, names of days), cut to extract Sunday's columns, and grep to check if "25" appears in those columns.
y=2008
while test $y -lt 2122; do
cal 12 $y | tail +3 | cut -c1-2 | grep -Fq 25 && echo 25 Dec $y
y=`expr $y + 1`
done
Running this script with OpenBSD, the output is identical to the C# program. OpenBSD cal accepts any year from 1 to 9999, so 2008 to 2122 is well within range.
With zsh[edit]
zmodload zsh/datetime
for (( year = 2010; year <= 2121; year++ ));
if [[ $(strftime '%A' $(strftime -r '%F' $year-12-25)) == Sunday ]] print $year
If the system has 32-bit time, this script will malfunction for years >= 2038; it will print no year from 2038 to 2121 (unless today is Sunday, then it prints every year from 2038 to 2121). This happens because strftime -r '%F' $year-12-25 yields -1 for an out-of-range date, and strftime '%A' -1 yields name of today.
Ursala[edit]
A standard library, stt, provides basic date manipulation functions,
and is imported in this example. Unix era times denominated in seconds since
1969 (excluding leap seconds) are represented as natural numbers with
unlimited precision. Results are valid for the arbitrarily distant
future assuming the Gregorian calendar remains in effect.
The algorithm relies on the string_to_time function converting a date
expressed as a character string to seconds without needing a weekday field in
the input, and the time_to_string function outputting the corresponding
date with the weekday included. The output is then filtered for Sundays.
#import std
#import nat
#import stt
christmases = time_to_string* string_to_time*TS 'Dec 25 0:0:0 '-*@hS %nP* nrange/2008 2121
#show+
sunday_years = ~&zS sep` * =]'Sun'*~ christmases
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
VBA[edit]
Option Explicit
Sub MainDayOfTheWeek()
Debug.Print "Xmas will be a Sunday in : " & XmasSunday(2008, 2121)
End Sub
Private Function XmasSunday(firstYear As Integer, lastYear As Integer) As String
Dim i As Integer, temp$
For i = firstYear To lastYear
If Weekday(CDate("25/12/" & i)) = vbSunday Then temp = temp & ", " & i
Next
XmasSunday = Mid(temp, 2)
End Function
- Output:
Xmas will be a Sunday in : 2011, 2016, 2022, 2033, 2039, 2044, 2050, 2061, 2067, 2072, 2078, 2089, 2095, 2101, 2107, 2112, 2118
VBScript[edit]
For year = 2008 To 2121
If Weekday(DateSerial(year, 12, 25)) = 1 Then
WScript.Echo year
End If
Next
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Vedit macro language[edit]
Buf_Switch(Buf_Free)
for (#3 = 2008; #3 < 2122; #3++) {
Reg_Set(10, "12/25/")
Num_Str(#3, 10, LEFT+APPEND)
if (JDate(@10) % 7 == 0) {
Num_Ins(#3, NOCR)
}
}
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Visual Objects[edit]
local i as dword
for i := 2008 upto 2121
if DOW(ConDate(i, 12, 25)) = 1
? AsString(i)
endif
next i
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Vlang[edit]
Updated for Vlang version 0.2.2
import time
fn main() {
for year := 2008; year <= 2121; year++ {
date := time.parse('${year}-12-25 00:00:00') or { continue }
if date.long_weekday_str() == 'Sunday' {
println('December 25 ${year} is a ${date.long_weekday_str()}')
}
}
}
- Output:
December 25 2011 is a Sunday December 25 2016 is a Sunday December 25 2022 is a Sunday December 25 2033 is a Sunday December 25 2039 is a Sunday December 25 2044 is a Sunday December 25 2050 is a Sunday December 25 2061 is a Sunday December 25 2067 is a Sunday December 25 2072 is a Sunday December 25 2078 is a Sunday December 25 2089 is a Sunday December 25 2095 is a Sunday December 25 2101 is a Sunday December 25 2107 is a Sunday December 25 2112 is a Sunday December 25 2118 is a Sunday
Wortel[edit]
!-&y = 0 `.getDay. @new Date[y 11 25] @range[2008 2121]Returns:
[2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118]
Wren[edit]
import "/date" for Date
System.print("Years between 2008 and 2121 when 25th December falls on Sunday:")
for (year in 2008..2121) {
if (Date.new(year, 12, 25).dayOfWeek == 7) System.print(year)
}
- Output:
Years between 2008 and 2121 when 25th December falls on Sunday: 2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
XPL0[edit]
The original routine in the library only worked correctly between the years 1980 and 2099. It was upgraded with this new routine that handles all dates in the Gregorian calendar, from 1583 onward. It's based on Zeller's Congruence.
include c:\cxpl\codes; \intrinsic 'code' declarations
func WeekDay(Year, Month, Day); \Return day of week (0=Sat 1=Sun..6=Fri)
int Year, Month, Day;
[if Month<=2 then [Month:= Month+12; Year:= Year-1];
return rem((Day + (Month+1)*26/10 + Year + Year/4 + Year/100*6 + Year/400) / 7);
]; \WeekDay
int Year;
[for Year:= 2008 to 2121 do
if WeekDay(Year, 12, 25) = 1 then \25th of December is a Sunday
[IntOut(0, Year); CrLf(0)];
]
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
Yabasic[edit]
sub wd(m, d, y)
If m < 3 Then // If m = 1 Or m = 2 Then
m = m + 12
y = y - 1
End If
Return mod((y + int(y / 4) - int(y / 100) + int(y / 400) + d + int((153 * m + 8) / 5)), 7)
End sub
// ------=< MAIN >=------
For yr = 2008 To 2121
If wd(12, 25, yr) = 0 Then
Print "Dec 25 ", yr
EndIf
Next
zkl[edit]
ISO dates, monday is 1, sunday is 7
var [const] D=Time.Date;
foreach y in ([2008..2121]){
if (D.Sunday==D.weekDay(y,12,25)) println(y)
}
Or, in a more functional manner:
var [const] D=Time.Date;
[2008..2121].filter(fcn(y){ D.Sunday==D.weekDay(y,12,25) }).println()
- Output:
2011 2016 2022 2033 2039 2044 2050 2061 2067 2072 2078 2089 2095 2101 2107 2112 2118
zonnon[edit]
module Main;
(*Access to Mono System package *)
import System;
var
now: System.DateTime;
begin
now := System.DateTime.Now;
System.Console.Write(now.ToString("yyyy-MM-dd :"));
System.Console.WriteLine(now.DayOfWeek);
end Main.
- Output:
2017-12-05 :Tuesday
ZX Spectrum Basic[edit]
10 CLS
20 FOR y=2008 TO 2121
30 LET year=y: LET m=12: LET d=25: GO SUB 1000
40 IF wd=0 THEN PRINT d;" ";m;" ";y
50 NEXT y
60 STOP
1000 REM week day
1010 IF m=1 OR m=2 THEN LET m=m+12: LET year=year-1
1020 LET wd=FN m(year+INT (year/4)-INT (year/100)+INT (year/400)+d+INT ((153*m+8)/5),7)
1030 RETURN
1100 DEF FN m(a,b)=a-INT (a/b)*b
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