User input/Text
In this task, the goal is to input a string and the integer 75000, from the text console.
You are encouraged to solve this task according to the task description, using any language you may know.
See also: User input/Graphical
Ada
<lang ada>function Get_String return String is
Line : String (1 .. 1_000); Last : Natural;
begin
Get_Line (Line, Last); return Line (1 .. Last);
end Get_String;
function Get_Integer return Integer is
S : constant String := Get_String;
begin
return Integer'Value (S); -- may raise exception Constraint_Error if value entered is not a well-formed integer
end Get_Integer; </lang>
The functions above may be called as shown below <lang ada>My_String : String := Get_String; My_Integer : Integer := Get_Integer;</lang>
Another: <lang ada>with Ada.Text_IO, Ada.Integer_Text_IO;
procedure User_Input is
I : Integer;
begin
Ada.Text_IO.Put ("Enter a string: "); declare S : String := Ada.Text_IO.Get_Line; begin Ada.Text_IO.Put_Line (S); end; Ada.Text_IO.Put ("Enter an integer: "); Ada.Integer_Text_IO.Get(I); Ada.Text_IO.Put_Line (Integer'Image(I));
end User_Input; </lang>
Unbounded IO: <lang ada>with
Ada.Text_IO, Ada.Integer_Text_IO, Ada.Strings.Unbounded, Ada.Text_IO.Unbounded_IO;
procedure User_Input2 is
S : Ada.Strings.Unbounded.Unbounded_String; I : Integer;
begin
Ada.Text_IO.Put("Enter a string: "); S := Ada.Strings.Unbounded.To_Unbounded_String(Ada.Text_IO.Get_Line); Ada.Text_IO.Put_Line(Ada.Strings.Unbounded.To_String(S)); Ada.Text_IO.Unbounded_IO.Put_Line(S); Ada.Text_IO.Put("Enter an integer: "); Ada.Integer_Text_IO.Get(I); Ada.Text_IO.Put_Line(Integer'Image(I));
end User_Input2; </lang>
ALGOL 68
<lang algol68>print("Enter a string: "); STRING s := read string; print("Enter a number: "); INT i := read int; ~</lang>
ALGOL W
<lang algolw>begin
string(80) s; integer n; write( "Enter a string > " ); read( s ); write( "Enter an integer> " ); read( n )
end.</lang>
APL
<lang APL>str←⍞ int←⎕</lang>
ARM Assembly
<lang ARM Assembly>
/* ARM assembly Raspberry PI */ /* program inputText.s */
/* Constantes */ .equ BUFFERSIZE, 100 .equ STDIN, 0 @ Linux input console .equ STDOUT, 1 @ Linux output console .equ EXIT, 1 @ Linux syscall .equ READ, 3 @ Linux syscall .equ WRITE, 4 @ Linux syscall /* Initialized data */ .data szMessDeb: .asciz "Enter text : \n" szMessNum: .asciz "Enter number : \n" szCarriageReturn: .asciz "\n"
/* UnInitialized data */ .bss sBuffer: .skip BUFFERSIZE
/* code section */ .text .global main main: /* entry of program */
push {fp,lr} /* saves 2 registers */ ldr r0,iAdrszMessDeb bl affichageMess mov r0,#STDIN @ Linux input console ldr r1,iAdrsBuffer @ buffer address mov r2,#BUFFERSIZE @ buffer size mov r7, #READ @ request to read datas swi 0 @ call system ldr r1,iAdrsBuffer @ buffer address mov r2,#0 @ end of string strb r2,[r1,r0] @ store byte at the end of input string (r0 contains number of characters)
ldr r0,iAdrsBuffer @ buffer address bl affichageMess ldr r0,iAdrszCarriageReturn bl affichageMess
ldr r0,iAdrszMessNum bl affichageMess mov r0,#STDIN @ Linux input console ldr r1,iAdrsBuffer @ buffer address mov r2,#BUFFERSIZE @ buffer size mov r7, #READ @ request to read datas swi 0 @ call system ldr r1,iAdrsBuffer @ buffer address mov r2,#0 @ end of string strb r2,[r1,r0] @ store byte at the end of input string (r0 @ ldr r0,iAdrsBuffer @ buffer address bl conversionAtoD @ conversion string in number in r0
100: /* standard end of the program */
mov r0, #0 @ return code pop {fp,lr} @restaur 2 registers mov r7, #EXIT @ request to exit program swi 0 @ perform the system call
iAdrszMessDeb: .int szMessDeb iAdrszMessNum: .int szMessNum iAdrsBuffer: .int sBuffer iAdrszCarriageReturn: .int szCarriageReturn /******************************************************************/ /* display text with size calculation */ /******************************************************************/ /* r0 contains the address of the message */ affichageMess:
push {fp,lr} /* save registres */ push {r0,r1,r2,r7} /* save others registers */ mov r2,#0 /* counter length */
1: /* loop length calculation */
ldrb r1,[r0,r2] /* read octet start position + index */ cmp r1,#0 /* if 0 its over */ addne r2,r2,#1 /* else add 1 in the length */ bne 1b /* and loop */ /* so here r2 contains the length of the message */ mov r1,r0 /* address message in r1 */ mov r0,#STDOUT /* code to write to the standard output Linux */ mov r7, #WRITE /* code call system "write" */ swi #0 /* call systeme */ pop {r0,r1,r2,r7} /* restaur others registers */ pop {fp,lr} /* restaur des 2 registres */ bx lr /* return */
/******************************************************************/ /* Convert a string to a number stored in a registry */ /******************************************************************/ /* r0 contains the address of the area terminated by 0 or 0A */ /* r0 returns a number */ conversionAtoD:
push {fp,lr} @ save 2 registers push {r1-r7} @ save others registers mov r1,#0 mov r2,#10 @ factor mov r3,#0 @ counter mov r4,r0 @ save address string -> r4 mov r6,#0 @ positive sign by default mov r0,#0 @ initialization to 0
1: /* early space elimination loop */
ldrb r5,[r4,r3] @ loading in r5 of the byte located at the beginning + the position cmp r5,#0 @ end of string -> end routine beq 100f cmp r5,#0x0A @ end of string -> end routine beq 100f cmp r5,#' ' @ space ? addeq r3,r3,#1 @ yes we loop by moving one byte beq 1b cmp r5,#'-' @ first character is - moveq r6,#1 @ 1 -> r6 beq 3f @ then move on to the next position
2: /* beginning of digit processing loop */
cmp r5,#'0' @ character is not a number blt 3f cmp r5,#'9' @ character is not a number bgt 3f /* character is a number */ sub r5,#48 ldr r1,iMaxi @ check the overflow of the register cmp r0,r1 bgt 99f @ overflow error mul r0,r2,r0 @ multiply par factor 10 add r0,r5 @ add to r0
3:
add r3,r3,#1 @ advance to the next position ldrb r5,[r4,r3] @ load byte cmp r5,#0 @ end of string -> end routine beq 4f cmp r5,#0x0A @ end of string -> end routine beq 4f b 2b @ loop
4:
cmp r6,#1 @ test r6 for sign moveq r1,#-1 muleq r0,r1,r0 @ if negatif, multiply par -1 b 100f
99: /* overflow error */
ldr r0,=szMessErrDep bl affichageMess mov r0,#0 @ return zero if error
100:
pop {r1-r7} @ restaur other registers pop {fp,lr} @ restaur 2 registers bx lr @return procedure
/* constante program */ iMaxi: .int 1073741824 szMessErrDep: .asciz "Too large: overflow 32 bits.\n"
</lang>
AutoHotkey
Windows console
<lang AutoHotkey>DllCall("AllocConsole") FileAppend, please type something`n, CONOUT$ FileReadLine, line, CONIN$, 1 msgbox % line FileAppend, please type '75000'`n, CONOUT$ FileReadLine, line, CONIN$, 1 msgbox % line</lang>
Input Command
this one takes input regardless of which application has focus. <lang AutoHotkey>TrayTip, Input:, Type a string: Input(String) TrayTip, Input:, Type an int: Input(Int) TrayTip, Done!, Input was recieved. Msgbox, You entered "%String%" and "%Int%" ExitApp Return
Input(ByRef Output) {
Loop { Input, Char, L1, {Enter}{Space} If ErrorLevel contains Enter Break Else If ErrorLevel contains Space Output .= " " Else Output .= Char TrayTip, Input:, %Output% }
}</lang>
AWK
This demo shows a same-line prompt, and that the integer i becomes 0 if the line did not parse as an integer. <lang awk>~/src/opt/run $ awk 'BEGIN{printf "enter a string: "}{s=$0;i=$0+0;print "ok,"s"/"i}' enter a string: hello world ok,hello world/0 75000 ok,75000/75000</lang>
Axe
Since integers in Axe are two bytes, 75000 exceeds the maximum integer limit (65535). The task has been adjusted accordingly so the integer must be 7500 instead.
In this implementation, the number displayed is effectively the number entered modulo 65536.
Also, in the string entry, the data is a string of tokens, not a string of characters. Thankfully, the most common ASCII symbols (A-Z, 0-9, and some symbols) have the same values as their token counterparts. This means that this example will work for those symbols, but other tokens (especially multi-byte tokens) will cause problems. See this table of tokens and their codes for reference.
<lang axe>Disp "String:" input→A length(A)→L
.Copy the string to a safe location Copy(A,L₁,L)
.Display the string Disp "You entered:",i For(I,0,L-1)
Disp {L₁+I}►Char
End Disp i
Disp "Integer:",i input→B length(B)→L
.Parse the string and convert to an integer 0→C For(I,0,L-1)
{B+I}-'0'→N If N>10 .Error checking Disp "Not a number",i Return End C*10+N→C
End
.Display and check the integer Disp "You entered:",i,C►Dec,i If C≠7500 Disp "That isn't 7500" End</lang>
BASIC
Many BASICs will automatically append a question mark (?
) to the end of the prompt if the prompt is followed by a semicolon (;
).
(Some of those will skip the question mark if the prompt is followed by a comma (,
) instead of a semicolon.)
This isn't a hard-and-fast rule -- for example, Chipmunk Basic never appends a question mark.
<lang qbasic>INPUT "Enter a string"; s$ INPUT "Enter a number: ", i%</lang>
Output (QBasic):
Enter a string? foo Enter a number: 1
Applesoft BASIC
<lang basic>10 INPUT "ENTER A STRING: "; S$ 20 INPUT "ENTER A NUMBER: "; I : I = INT(I)</lang>
IS-BASIC
<lang IS-BASIC>100 INPUT PROMPT "Enter a number: ":NUM 110 INPUT PROMPT "Enter a string: ":ST$</lang>
Sinclair ZX81 BASIC
<lang basic>10 PRINT "ENTER A STRING" 20 INPUT S$ 30 PRINT "YOU ENTERED: ";S$ 40 PRINT "NOW ENTER THE NUMBER 75000" 50 INPUT N 60 IF N=75000 THEN STOP 70 PRINT "NO, "; 80 GOTO 40</lang>
Batch File
<lang dos>@echo off set /p var= echo %var% 75000</lang>
BBC BASIC
<lang bbcbasic> INPUT LINE "Enter a string: " string$
INPUT "Enter a number: " number PRINT "String = """ string$ """" PRINT "Number = " ; number</lang>
Befunge
This prompts for a string and pushes it to the stack a character at a time (~) until end of input (-1). <lang befunge><>:v:"Enter a string: "
^,_ >~:1+v ^ _@</lang>
Numeric input is easier, using the & command. <lang befunge><>:v:"Enter a number: "
^,_ & @</lang>
Bracmat
<lang bracmat>( doit = out'"Enter a string"
& get':?mystring & whl ' ( out'"Enter a number" & get':?mynumber & !mynumber:~# & out'"I said:\"a number\"!" ) & out$(mystring is !mystring \nmynumber is !mynumber \n)
);</lang>
{?} !doit Enter a string abacus Enter a number 75000h I said:"a number"! Enter a number 75000 mystring is abacus mynumber is 75000
C
<lang c>#include <stdio.h>
- include <stdlib.h>
int main(void) {
// Get a string from stdin char str[BUFSIZ]; puts("Enter a string: "); fgets(str, sizeof(str), stdin);
// Get 75000 from stdin long num; char buf[BUFSIZ]; do { puts("Enter 75000: "); fgets(buf, sizeof(buf), stdin); num = strtol(buf, NULL, 10); } while (num != 75000);
return EXIT_SUCCESS;
}</lang>
C++
<lang cpp>#include <iostream>
- include <string>
using namespace std;
int main() {
// while probably all current implementations have int wide enough for 75000, the C++ standard // only guarantees this for long int. long int integer_input; string string_input; cout << "Enter an integer: "; cin >> integer_input; cout << "Enter a string: "; cin >> string_input; return 0;
}</lang>
Note: The program as written above only reads the string up to the first whitespace character. To get a complete line into the string, replace <lang cpp> cin >> string_input;</lang> with <lang cpp> getline(cin, string_input);</lang>
Note: if a numeric input operation fails, the value is not stored for that operation, plus the fail bit is set, which causes all future stream operations to be ignored (e.g. if a non-integer is entered for the first input above, then nothing will be stored in either the integer and the string). A more complete program would test for an error in the input (with if (!cin) // handle error
) after the first input, and then clear the error (with cin.clear()
) if we want to get further input.
Alternatively, we could read the input into a string first, and then parse that into an int later.
C#
<lang csharp>using System;
namespace C_Sharp_Console {
class example {
static void Main() { string word; int num; Console.Write("Enter an integer: "); num = Console.Read(); Console.Write("Enter a String: "); word = Console.ReadLine(); } }
}</lang>
Ceylon
<lang ceylon>shared void run() { print("enter any text here"); value text = process.readLine(); print(text); print("enter the number 7500 here"); value number = parseInteger(process.readLine() else "") else -1; print("``number == 7500 then number else "close enough"``"); }</lang>
Clojure
<lang lisp>(import '(java.util Scanner)) (def scan (Scanner. *in*)) (def s (.nextLine scan)) (def n (.nextInt scan))</lang>
COBOL
<lang cobol> IDENTIFICATION DIVISION.
PROGRAM-ID. Get-Input.
DATA DIVISION. WORKING-STORAGE SECTION. 01 Input-String PIC X(30). 01 Input-Int PIC 9(5).
PROCEDURE DIVISION. DISPLAY "Enter a string:" ACCEPT Input-String
DISPLAY "Enter a number:" ACCEPT Input-Int
GOBACK .</lang>
Common Lisp
<lang lisp>(format t "Enter some text: ") (let ((s (read-line)))
(format t "You entered ~s~%" s))
(format t "Enter a number: ") (let ((n (read)))
(if (numberp n) (format t "You entered ~d.~%" n) (format t "That was not a number.")))</lang>
D
<lang D>import std.stdio;
void main() {
long number; write("Enter an integer: "); readf("%d", &number); char[] str; write("Enter a string: "); readf(" %s\n", &str); writeln("Read in '", number, "' and '", str, "'");
}</lang>
Delphi
<lang Delphi>program UserInputText;
{$APPTYPE CONSOLE}
uses SysUtils;
var
s: string; lStringValue: string; lIntegerValue: Integer;
begin
WriteLn('Enter a string:'); Readln(lStringValue);
repeat WriteLn('Enter the number 75000'); Readln(s); lIntegerValue := StrToIntDef(s, 0); if lIntegerValue <> 75000 then Writeln('Invalid entry: ' + s); until lIntegerValue = 75000;
end.</lang>
Déjà Vu
<lang dejavu>input s:
!print\ s !decode!utf-8 !read-line!stdin
local :astring input "Enter a string: " true while:
try: to-num input "Enter the number 75000: " /= 75000 catch value-error: true</lang>
Elena
ELENA 3.4 : <lang elena>import extensions.
public program [
var num := Integer new. console write:"Enter an integer: "; readLine:num. var word := console write:"Enter a String: "; readLine
]</lang>
Elixir
<lang Elixir> a = IO.gets("Enter a string: ") |> String.strip b = IO.gets("Enter an integer: ") |> String.strip |> String.to_integer f = IO.gets("Enter a real number: ") |> String.strip |> String.to_float IO.puts "String = #{a}" IO.puts "Integer = #{b}" IO.puts "Float = #{f}" </lang>
Erlang
<lang erlang>{ok, [String]} = io:fread("Enter a string: ","~s"). {ok, [Number]} = io:fread("Enter a number: ","~d").</lang>
Alternatively, you could use io:get_line to get a string: <lang erlang> String = io:get_line("Enter a string: ").</lang>
Euphoria
<lang Euphoria>include get.e
sequence s atom n
s = prompt_string("Enter a string:") puts(1, s & '\n') n = prompt_number("Enter a number:",{}) printf(1, "%d", n)</lang>
F#
<lang fsharp>open System
let ask_for_input s =
printf "%s (End with Return): " s Console.ReadLine()
[<EntryPoint>] let main argv =
ask_for_input "Input a string" |> ignore ask_for_input "Enter the number 75000" |> ignore 0</lang>
Factor
<lang factor>"Enter a string: " write readln "Enter a number: " write readln string>number</lang>
Falcon
<lang falcon>printl("Enter a string:") str = input() printl("Enter a number:") n = int(input())</lang>
FALSE
FALSE has neither a string type nor numeric input. Shown instead are routines to parse and echo a word and to parse and interpret a number using the character input command (^). <lang false>[[^$' =~][,]#,]w: [0[^'0-$$9>0@>|~][\10*+]#%]d: w;! d;!.</lang>
Fantom
The 'toInt' method on an input string will throw an exception if the input is not a number.
<lang fantom> class Main {
public static Void main () { Env.cur.out.print ("Enter a string: ").flush str := Env.cur.in.readLine echo ("Entered :$str:") Env.cur.out.print ("Enter 75000: ").flush Int n try n = Env.cur.in.readLine.toInt catch (Err e) { echo ("You had to enter a number") return } echo ("Entered :$n: which is " + ((n == 75000) ? "correct" : "wrong")) }
} </lang>
Forth
Input a string
<lang forth>: INPUT$ ( n -- addr n )
PAD SWAP ACCEPT PAD SWAP ;</lang>
Input a number
The only ANS standard number interpretation word is >NUMBER ( ud str len -- ud str len ), which is meant to be the base factor for more convenient (but non-standard) parsing words. <lang forth>: INPUT# ( -- u true | false )
0. 16 INPUT$ DUP >R >NUMBER NIP NIP R> <> DUP 0= IF NIP THEN ;</lang>
<lang forth>: INPUT# ( -- n true | d 1 | false )
16 INPUT$ SNUMBER? ;</lang>
<lang forth>: INPUT# ( -- n true | false )
16 INPUT$ NUMBER? NIP DUP 0= IF NIP THEN ;</lang>
Note that NUMBER? always leaves a double result on the stack. INPUT# returns a single precision number. If you desire a double precision result, remove the NIP.
<lang forth>: input#
begin refill drop bl parse-word ( a n) number error? ( n f) while ( n) drop ( --) repeat ( n)
- </lang>
Here is an example that puts it all together:
<lang forth>: TEST
." Enter your name: " 80 INPUT$ CR ." Hello there, " TYPE CR ." Enter a number: " INPUT# CR IF ." Your number is " . ELSE ." That's not a number!" THEN CR ;</lang>
Fortran
<lang fortran>character(20) :: s integer :: i
print*, "Enter a string (max 20 characters)" read*, s print*, "Enter the integer 75000" read*, i</lang>
FreeBASIC
<lang freebasic>' FB 1.05.0 Win64
Dim s As String Dim i AS Integer Input "Please enter a string : "; s Do
Input "Please enter 75000 : "; i
Loop Until i = 75000 Print Print s, i Sleep</lang> Sample input/output
- Output:
Please enter a string : ? Rosetta Please enter 75000 : ? 70000 Please enter 75000 : ? 75000 Rosetta 75000
Go
Go has C-like Scan and Scanf functions for quick and dirty input: <lang go>package main
import "fmt"
func main() {
var s string var i int if _, err := fmt.Scan(&s, &i); err == nil && i == 75000 { fmt.Println("good") } else { fmt.Println("wrong") }
}</lang> Code below allows much more control over interaction and error checking. <lang go> package main
import (
"bufio" "fmt" "os" "strconv" "strings"
)
func main() {
in := bufio.NewReader(os.Stdin)
fmt.Print("Enter string: ") s, err := in.ReadString('\n') if err != nil { fmt.Println(err) return } s = strings.TrimSpace(s)
fmt.Print("Enter 75000: ") s, err = in.ReadString('\n') if err != nil { fmt.Println(err) return } n, err := strconv.Atoi(strings.TrimSpace(s)) if err != nil { fmt.Println(err) return } if n != 75000 { fmt.Println("fail: not 75000") return } fmt.Println("Good")
} </lang>
Frink
<lang frink> s = input["Enter a string: "] i = parseInt[input["Enter an integer: "]] </lang>
Groovy
<lang groovy>word = System.in.readLine() num = System.in.readLine().toInteger()</lang>
Haskell
<lang haskell>import System.IO (hFlush, stdout) main = do
putStr "Enter a string: " hFlush stdout str <- getLine putStr "Enter an integer: " hFlush stdout num <- readLn :: IO Int putStrLn $ str ++ (show num)</lang>
Note: :: IO Int is only there to disambiguate what type we wanted from read. If num were used in a numerical context, its type would have been inferred by the interpreter/compiler. Note also: Haskell doesn't automatically flush stdout when doing input, so explicit flushes are necessary.
HolyC
<lang holyc>U8 *s; s = GetStr("Enter a string: ");
U32 *n; do {
n = GetStr("Enter 75000: ");
} while(Str2I64(n) != 75000);
Print("Your string: %s\n", s); Print("75000: %d\n", Str2I64(n));</lang>
Icon and Unicon
The following works in both Icon and Unicon:
<lang icon> procedure main ()
writes ("Enter something: ") s := read () write ("You entered: " || s)
writes ("Enter 75000: ") if (i := integer (read ())) then write (if (i = 75000) then "correct" else "incorrect") else write ("you must enter a number")
end </lang>
Io
<lang io>string := File clone standardInput readLine("Enter a string: ") integer := File clone standardInput readLine("Enter 75000: ") asNumber</lang>
J
Solution <lang j> require 'misc' NB. load system script
prompt 'Enter string: ' 0".prompt 'Enter an integer: '</lang>
Note that require'misc'
is old - efforts to optimize by loading misc utilities in a fine grained fashion mean that currently (J 805) that should be require'general/misc/prompt'
and the older form fails with an error to call attention to this issue.
Example Usage <lang j> prompt 'Enter string: ' NB. output string to session Enter string: Hello World Hello World
0".prompt 'Enter an integer: ' NB. output integer to session
Enter an integer: 75000 75000
mystring=: prompt 'Enter string: ' NB. store string as noun
Enter string: Hello Rosetta Code
myinteger=: 0".prompt 'Enter an integer: ' NB. store integer as noun
Enter an integer: 75000
mystring;myinteger NB. show contents of nouns
┌──────────────────┬─────┐ │Hello Rosetta Code│75000│ └──────────────────┴─────┘ </lang>
Java
<lang java> import java.util.Scanner;
public class GetInput {
public static void main(String[] args) throws Exception { Scanner s = new Scanner(System.in); System.out.print("Enter a string: "); String str = s.nextLine(); System.out.print("Enter an integer: "); int i = Integer.parseInt(s.next()); }
}</lang>
or
<lang java>import java.util.Scanner;
public class GetInput {
public static void main(String[] args) { Scanner stdin = new Scanner(System.in); String string = stdin.nextLine(); int number = stdin.nextInt(); }
}</lang>
JavaScript
and only with cscript.exe
<lang javascript>WScript.Echo("Enter a string"); var str = WScript.StdIn.ReadLine();
var val = 0; while (val != 75000) {
WScript.Echo("Enter the integer 75000"); val = parseInt( WScript.StdIn.ReadLine() );
}</lang>
<lang javascript>print("Enter a string"); var str = readline();
var val = 0; while (val != 75000) {
print("Enter the integer 75000"); val = parseInt( readline() );
}</lang>
Joy
<lang Joy> "Enter a string: " putchars stdin fgets "Enter a number: " putchars stdin fgets 10 strtol. </lang>
jq
If the input consists of a JSON string followed by a JSON number, then the jq program consisting of . will read and echo the two values.
If the goal is to continue reading the input until a JSON string is found, and then continue reading the input until the integer value 75000 is encountered, then the following program could be used on the assumption that the inputs are all valid JSON. <lang jq>def read(int):
null | until( . == int; "Expecting \(int)" | stderr | input);
def read_string:
null | until( type == "string"; "Please enter a string" | stderr | input);
(read_string | "I see the string: \(.)"), (read(75000) | "I see the expected integer: \(.)")</lang>
- Output:
The following is a transcript showing the prompts (on stderr), responses (on stdin) and output (on stdout): <lang sh>$ jq -n -r -f User_input.jq "Please enter a string" 1 "Please enter a string" "ok" I see the string: ok "Expecting 75000" 1 "Expecting 75000" "ok" "Expecting 75000" 75000 I see the expected integer: 75000</lang>
Julia
<lang Julia> print("String? ") y = readline() println("Your input was \"", y, "\".\n") print("Integer? ") y = readline() try
y = parse(Int, y) println("Your input was \"", y, "\".\n")
catch
println("Sorry, but \"", y, "\" does not compute as an integer.")
end </lang>
- Output:
String? cheese Your input was "cheese". Integer? 75000 Your input was "75000". mike@harlan:~/rosetta/julia$ julia user_input_text.jl String? theory Your input was "theory". Integer? 75,000 Sorry, but "75,000" does not compute as an integer.
Kite
<lang Kite> System.file.stdout|write("Enter a String "); string = System.file.stdin|readline(); </lang>
Kotlin
<lang scala>// version 1.1
fun main(args: Array<String>) {
print("Enter a string : ") val s = readLine()!! println(s) do { print("Enter 75000 : ") val number = readLine()!!.toInt() } while (number != 75000)
}</lang>
Lasso
<lang Lasso>#!/usr/bin/lasso9
define read_input(prompt::string) => {
local(string)
// display prompt stdout(#prompt) // the following bits wait until the terminal gives you back a line of input while(not #string or #string -> size == 0) => { #string = file_stdin -> readsomebytes(1024, 1000) } #string -> replace(bytes('\n'), bytes())
return #string -> asstring
}
local( string, number )
// get string
- string = read_input('Enter the string: ')
// get number
- number = integer(read_input('Enter the number: '))
// deliver the result stdoutnl(#string + ' (' + #string -> type + ') | ' + #number + ' (' + #number -> type + ')')</lang>
Output:
Enter the string: Hello Enter the number: 1234 Hello (string) | 1234 (integer)
Liberty BASIC
<lang lb>Input "Enter a string. ";string$ Input "Enter the value 75000.";num</lang>
Logo
Logo literals may be read from a line of input from stdin as either a list or a single word. <lang logo>make "input readlist ; in: string 75000 show map "number? :input ; [false true]
make "input readword ; in: 75000 show :input + 123 ; 75123 make "input readword ; in: string 75000 show :input ; string 75000</lang>
Logtalk
Using an atom representation for strings and type-check failure-driven loops: <lang logtalk>
- - object(user_input).
:- public(test/0). test :- repeat, write('Enter an integer: '), read(Integer), integer(Integer), !, repeat, write('Enter an atom: '), read(Atom), atom(Atom), !.
- - end_object.
</lang> Output: <lang text> | ?- user_input::test. Enter an integer: 75000. Enter an atom: 'Hello world!'. yes </lang>
Lua
<lang Lua>print('Enter a string: ') s = io.stdin:read() print('Enter a number: ') i = tonumber(io.stdin:read()) </lang>
M2000 Interpreter
<lang M2000 Interpreter> Module CheckIt {
Keyboard "75000"+chr$(13) Input "Integer:", A% \\ Input erase keyboard buffer, we can't place in first Keyboard keys for second input Keyboard "Hello World"+Chr$(13) Input "String:", A$ Print A%, A$
} CheckIt </lang>
Maple
<lang maple>printf("String:"); string_value := readline(); printf("Integer: "); int_value := parse(readline());</lang>
Mathematica / Wolfram Language
<lang Mathematica>mystring = InputString["give me a string please"]; myinteger = Input["give me an integer please"];</lang>
MATLAB
The input() function automatically converts the user input to the correct data type (i.e. string or double). We can force the input to be interpreted as a string by using an optional parameter 's'.
Sample usage: <lang MATLAB>>> input('Input string: ') Input string: 'Hello'
ans =
Hello
>> input('Input number: ') Input number: 75000
ans =
75000
>> input('Input number, the number will be stored as a string: ','s') Input number, the number will be stored as a string: 75000
ans =
75000</lang>
Metafont
<lang metafont>string s; message "write a string: "; s := readstring; message s; message "write a number now: "; b := scantokens readstring; if b = 750:
message "You've got it!"
else:
message "Sorry..."
fi; end</lang>
If we do not provide a number in the second input, Metafont will complain. (The number 75000 was reduced to 750 since Metafont biggest number is near 4096).
Mirah
<lang mirah>s = System.console.readLine()
puts s</lang>
mIRC Scripting Language
<lang mirc>alias askmesomething {
echo -a You answered: $input(What's your name?, e)
}</lang>
Modula-3
<lang modula3>MODULE Input EXPORTS Main;
IMPORT IO, Fmt;
VAR string: TEXT;
number: INTEGER;
BEGIN
IO.Put("Enter a string: "); string := IO.GetLine(); IO.Put("Enter a number: "); number := IO.GetInt(); IO.Put("You entered: " & string & " and " & Fmt.Int(number) & "\n");
END Input.</lang>
MUMPS
<lang MUMPS>TXTINP
NEW S,N WRITE "Enter a string: " READ S,! WRITE "Enter the number 75000: " READ N,! KILL S,N QUIT</lang>
Neko
<lang ActionScript>/**
User input/Text, in Neko Tectonics: nekoc userinput.neko neko userinput
- /
var stdin = $loader.loadprim("std@file_stdin", 0)() var file_read_char = $loader.loadprim("std@file_read_char", 1)
/* Read a line from file f into string s returning length without any newline */ var NEWLINE = 10 var readline = function(f, s) {
var len = 0 var ch while true { try ch = file_read_char(f) catch a break; if ch == NEWLINE break; if $sset(s, len, ch) == null break; else len += 1 } return $ssub(s, 0, len)
}
$print("Enter a line of text, then the number 75000\n")
try {
var RECL = 132 var str = $smake(RECL) var userstring = readline(stdin, str) $print(":", userstring, ":\n")
var num = $int(readline(stdin, str)) if num == 75000 $print("Rosetta Code 75000, for the win!\n") else $print("Sorry, need 75000\n")
} catch problem $print("Exception: ", problem, "\n")</lang>
- Output:
prompt$ nekoc userinput.neko prompt$ neko userinput.n Enter a line of text, then the number 75000 this is a line of text :this is a line of text: 75000 Rosetta Code 75000, for the win!
Nemerle
<lang Nemerle>using System; using System.Console;
module Input {
Main() : void { Write("Enter a string:"); _ = ReadLine()
mutable entry = 0; mutable numeric = false; do { Write("Enter 75000:"); numeric = int.TryParse(ReadLine(), out entry); } while ((!numeric) || (entry != 75000)) }
}</lang>
NetRexx
<lang NetRexx>/* NetRexx */ options replace format comments java crossref symbols nobinary
checkVal = 75000 say 'Input a string then the number' checkVal parse ask inString parse ask inNumber .
say 'Input string:' inString say 'Input number:' inNumber if inNumber == checkVal then do
say 'Success! Input number is as requested' end
else do
say 'Failure! Number' inNumber 'is not' checkVal end
return </lang>
newLISP
<lang lisp>(print "Enter an integer: ") (set 'x (read-line)) (print "Enter a string: ") (set 'y (read-line))</lang>
Nim
<lang nim>import rdstdin, strutils
let str = readLineFromStdin "Input a string: " let num = parseInt(readLineFromStdin "Input a string: ")</lang>
Oberon-2
<lang oberon2> MODULE InputText; IMPORT
In, Out;
VAR
i: INTEGER; str: ARRAY 512 OF CHAR;
BEGIN
Out.String("Enter a integer: ");Out.Flush();In.Int(i); Out.String("Enter a string: ");Out.Flush();In.String(str);
END InputText. </lang>
Objeck
<lang objeck> use IO;
bundle Default {
class Hello { function : Main(args : String[]) ~ Nil { string := Console->GetInstance()->ReadString(); string->PrintLine();
number := Console->GetInstance()->ReadString()->ToInt(); number->PrintLine(); } }
} </lang>
OCaml
<lang ocaml>print_string "Enter a string: "; let str = read_line () in
print_string "Enter an integer: "; let num = read_int () in Printf.printf "%s%d\n" str num</lang>
Octave
<lang octave>% read a string ("s") s = input("Enter a string: ", "s");
% read a GNU Octave expression, which is evaluated; e.g. % 5/7 gives 0.71429 i = input("Enter an expression: ");
% parse the input for an integer printf("Enter an integer: "); ri = scanf("%d");
% show the values disp(s); disp(i); disp(ri);</lang>
Oforth
<lang Oforth>import: console
- testInput{
| s n |
System.Console askln ->s while (System.Console askln asInteger dup ->n isNull) [ "Not an integer" println ]
System.Out "Received : " << s << " and " << n << cr ;</lang>
Oz
<lang oz>declare
StdIn = {New class $ from Open.file Open.text end init(name:stdin)} StringInput Num = {NewCell 0}
in
{System.printInfo "Enter a string: "} StringInput = {StdIn getS($)}
for until:@Num == 75000 do {System.printInfo "Enter 75000: "} Line = {StdIn getS($)} in Num := try {String.toInt Line} catch _ then 0 end end</lang>
PARI/GP
<lang parigp>s=input(); n=eval(input());</lang>
Pascal
<lang pascal>program UserInput(input, output); var i : Integer;
s : String;
begin
write('Enter an integer: '); readln(i); write('Enter a string: '); readln(s)
end.</lang>
Perl
<lang perl>print "Enter a string: "; my $string = <>; print "Enter an integer: "; my $integer = <>;</lang>
Perl 6
<lang perl6>my $str = prompt("Enter a string: "); my $int = prompt("Enter a integer: ");</lang>
Phix
<lang Phix>?prompt_string("Enter any string:") ?prompt_number("Enter the number 75000:",{75000,75000})</lang>
- Output:
Enter any string:abc "abc" Enter the number 75000:123 A number from 75000 to 75000 is expected here - try again Enter the number 75000:75000 75000
PHP
<lang php>#!/usr/bin/php <?php $string = fgets(STDIN); $integer = (int) fgets(STDIN);</lang>
PicoLisp
<lang PicoLisp>(in NIL # Guarantee reading from standard input
(let (Str (read) Num (read)) (prinl "The string is: \"" Str "\"") (prinl "The number is: " Num) ) )</lang>
Pike
<lang pike>int main(){
write("Enter a String: "); string str = Stdio.stdin->gets(); write("Enter 75000: "); int num = Stdio.stdin->gets();
}</lang>
PL/I
<lang PL/I>declare s character (100) varying; declare k fixed decimal (15);
put ('please type a string:'); get edit (s) (L); put skip list (s);
put skip list ('please type the integer 75000'); get list (k); put skip list (k); put skip list ('Thanks');</lang>
Pop11
<lang pop11>;;; Setup item reader lvars itemrep = incharitem(charin); lvars s, c, j = 0;
- read chars up to a newline and put them on the stack
while (charin() ->> c) /= `\n` do j + 1 -> j ; c endwhile;
- build the string
consstring(j) -> s;
- read the integer
lvars i = itemrep();</lang>
PostScript
<lang postscript>%open stdin for reading (and name the channel "kbd"): /kbd (%stdin) (r) file def %make ten-char buffer to read string into: /buf (..........) def %read string into buffer: kbd buf readline</lang>
At this point there will be two items on the stack: a boolean which is "true" if the read was successful and the string that was read from the kbd (input terminates on a <return>). If the length of the string exceeds the buffer length, an error condition occurs (rangecheck). For the second part, the above could be followed by this:
<lang postscript>%if the read was successful, convert the string to integer: {cvi} if</lang>
which will read the conversion operator 'cvi' (convert to integer) and the boolean and execute the former if the latter is true.
PowerShell
<lang powershell>$string = Read-Host "Input a string" [int]$number = Read-Host "Input a number"</lang>
PureBasic
<lang PureBasic>If OpenConsole()
; Declare a string and a integer to be used Define txt.s, num.i
Print("Enter a string: ") txt=Input()
Repeat Print("Enter the number 75000: ") num=Val(Input()) ; Converts the Input to a Value with Val() Until num=75000 ; Check that the user really gives us 75000! Print("You made it!") Delay(3000): CloseConsole()
EndIf</lang>
Python
Input a string
<lang python> string = raw_input("Input a string: ")</lang> In Python 3.0, raw_input will be renamed to input(). The Python 3.0 equivalent would be <lang python> string = input("Input a string: ")</lang>
Input a number
While input() gets a string in Python 3.0, in 2.x it is the equivalent of eval(raw_input(...)). Because this runs arbitrary code, and just isn't nice, it is being removed in Python 3.0. raw_input() is being changed to input() because there will be no other kind of input function in Python 3.0. <lang python> number = input("Input a number: ") # Deprecated, please don't use.</lang> Python 3.0 equivalent: <lang python> number = eval(input("Input a number: ")) # Evil, please don't use.</lang> The preferred way of getting numbers from the user is to take the input as a string, and pass it to any one of the numeric types to create an instance of the appropriate number. <lang python> number = float(raw_input("Input a number: "))</lang> Python 3.0 equivalent: <lang python> number = float(input("Input a number: "))</lang> float may be replaced by any numeric type, such as int, complex, or decimal.Decimal. Each one varies in expected input.
R
<lang R>stringval <- readline("String: ") intval <- as.integer(readline("Integer: "))</lang>
Racket
<lang Racket>
- lang racket
(printf "Input a string: ") (define s (read-line)) (printf "You entered: ~a\n" s)
(printf "Input a number: ") (define m (or (string->number (read-line))
(error "I said a number!")))
(printf "You entered: ~a\n" m)
- alternatively, use the generic `read'
(printf "Input a number: ") (define n (read)) (unless (number? n) (error "I said a number!")) (printf "You entered: ~a\n" n) </lang>
Rascal
It is possible to use the eclipse IDE to create consoles. However, just as with the graphical input, this will always return a string. This string can subsequently be evaluated. A very simple example would be: <lang rascal>import util::IDE; public void InputConsole(){
x = ""; createConsole("Input Console", "Welcome to the Input Console\nInput\> ", str (str inp) {x = "<inp == "75000" ? "You entered 75000" : "You entered a string">"; return "<x>\n<inp>\nInput\>";});
}</lang> Which has as output:
This makes it relatively easy to create Domain Specific Languages (or any programming language) and to create a rascal console for this. For examples with Exp, Func and Lisp, see the online Language Examples.
Raven
<lang raven>'Input a string: ' print expect as str 'Input an integer: ' print expect 0 prefer as num</lang>
REBOL
<lang REBOL>REBOL [ Title: "Textual User Input" URL: http://rosettacode.org/wiki/User_Input_-_text ]
s: n: ""
- Because I have several things to check for, I've made a function to
- handle it. Note the question mark in the function name, this convention
- is often used in Forth to indicate test of some sort.
valid?: func [s n][ error? try [n: to-integer n] ; Ignore error if conversion fails. all [0 < length? s 75000 = n]]
- I don't want to give up until I've gotten something useful, so I
- loop until the user enters valid data.
while [not valid? s n][ print "Please enter a string, and the number 75000:" s: ask "string: " n: ask "number: " ]
- It always pays to be polite...
print rejoin [ "Thank you. Your string was '" s "'."]</lang>
Output:
Please enter a string, and the number 75000: string: This is a test. number: ksldf Please enter a string, and the number 75000: string: number: 75000 Please enter a string, and the number 75000: string: Slert... number: 75000 Thank you. Your string was 'Slert...'.
Red
<lang Red>n: ask "Please enter # 75000: " str: ask "Please enter any string: "</lang>
Retro
<lang Retro>: example ( "- )
remapping off "Enter a string: " puts 10 accept tib tempString [ "Enter 75000: " puts getToken toNumber 75000 = cr ] until "Your string was: '%s'\n" puts remapping on ;</lang>
REXX
Note: all of the following would be accepted as being numerically equal to 75000:
- 7.5E+0004
- 75000.
- 750000e-01
- 000075000.0000
- 75000 (with leading and/or trailing blanks)
- and others
If the intent was to have the user enter the string exactly as 75000,
then the REXX do statement should be replaced with:
do until userNumber==75000
<lang rexx>/*REXX program prompts & reads/obtains a string, and also the number 75000 from terminal*/ say 'Please enter a string:' /*issue a prompt message to the term. */ parse pull userString /*the (char) string can be any length. */
/* [↑] the string could be null/empty.*/ do until userNumber=75000 /*repeat this loop until satisfied. */ say /*display a blank line to the terminal.*/ say 'Please enter the number 75000' /*display a nice prompt message to term*/ parse pull userNumber /*obtain the user text from terminal. */ end /*until*/ /*check if the response is legitimate. */ /*stick a fork in it, we're all done. */</lang>
Ring
<lang ring> see "Enter a string : " give s see "Enter an integer : " give i see "String = " + s + nl see "Integer = " + i + nl </lang>
Robotic
<lang robotic> input string "Enter string:" set "$str" to "input" input string "Enter number:" set "number" to "input" [ "You entered:" [ "&$str&" [ "&number&" end </lang>
To ensure that a specific number must be entered, just create a loop around the second input function: <lang robotic> input string "Enter string:" set "$str" to "input"
- "incorrect"
input string "Enter number:" set "number" to "input" if "number" != "(75000)" then "incorrect" [ "You entered:" [ "&$str&" [ "&number&" end </lang>
Ruby
<lang ruby>print "Enter a string: " s = gets printf "Enter an integer: " i = gets.to_i # If string entered, will return zero printf "Enter a real number: " f = Float(gets) rescue nil # converts a floating point number or returns nil puts "String = #{s}" puts "Integer = #{i}" puts "Float = #{f}"</lang>
Rust
This program shows all the proper error handling. <lang rust>use std::io::{self, Write}; use std::fmt::Display; use std::process;
fn main() {
let s = grab_input("Give me a string") .unwrap_or_else(|e| exit_err(&e, e.raw_os_error().unwrap_or(-1)));
println!("You entered: {}", s.trim());
let n: i32 = grab_input("Give me an integer") .unwrap_or_else(|e| exit_err(&e, e.raw_os_error().unwrap_or(-1))) .trim() .parse() .unwrap_or_else(|e| exit_err(&e, 2));
println!("You entered: {}", n);
}
fn grab_input(msg: &str) -> io::Result<String> {
let mut buf = String::new(); print!("{}: ", msg); try!(io::stdout().flush());
try!(io::stdin().read_line(&mut buf)); Ok(buf)
}
fn exit_err<T: Display>(msg: T, code: i32) -> ! {
let _ = writeln!(&mut io::stderr(), "Error: {}", msg); process::exit(code)
}</lang>
Scala
<lang scala>print("Enter a number: ") val i=Console.readLong // Task says to enter 75000 print("Enter a string: ") val s=Console.readLine</lang>
Scheme
The read procedure is R5RS standard, inputs a scheme representation so, in order to read a string, one must enter "hello world" <lang scheme>(define str (read)) (define num (read)) (display "String = ") (display str) (display "Integer = ") (display num)</lang>
Seed7
<lang seed7>$ include "seed7_05.s7i";
const proc: main is func
local var integer: integer_input is 0; var string: string_input is ""; begin write("Enter an integer: "); readln(integer_input); write("Enter a string: "); readln(string_input); end func;</lang>
Sidef
Using the read(Type) built-in function: <lang ruby>var s = read(String); var i = read(Number); # auto-conversion to a number</lang>
or using the Sys.readln(msg) method: <lang ruby>var s = Sys.readln("Enter a string: "); var i = Sys.readln("Enter a number: ").to_i;</lang>
Slate
<lang slate>print: (query: 'Enter a String: '). [| n |
n: (Integer readFrom: (query: 'Enter an Integer: ')). (n is: Integer) ifTrue: [print: n] ifFalse: [inform: 'Not an integer: ' ; n printString]
] do.</lang>
Smalltalk
<lang smalltalk>'Enter a number: ' display. a := stdin nextLine asInteger.
'Enter a string: ' display. b := stdin nextLine.</lang>
smart BASIC
NOTE: The INPUT command uses a colon (:) as opposed to a comma (,) or semi-conlon (;) like other forms of BASIC.
<lang qbasic>INPUT "Enter a string.":a$ INPUT "Enter the value 75000.":n</lang>
SNOBOL4
<lang snobol4> output = "Enter a string:"
str = trim(input) output = "Enter an integer:" int = trim(input) output = "String: " str " Integer: " int
end</lang>
SPL
In SPL all console input is text, so number should be converted from text using #.val function. <lang spl>text = #.input("Input a string") number = #.val(#.input("Input a number"))</lang>
Standard ML
<lang sml>print "Enter a string: "; let val str = valOf (TextIO.inputLine TextIO.stdIn) in (* note: this keeps the trailing newline *)
print "Enter an integer: "; let val num = valOf (TextIO.scanStream (Int.scan StringCvt.DEC) TextIO.stdIn) in print (str ^ Int.toString num ^ "\n") end
end</lang>
Swift
<lang swift>print("Enter a string: ", terminator: "") if let str = readLine() {
print(str)
}</lang>
Tcl
Like LISP, there is no concept of a "number" in Tcl - the only real variable type is a string (whether a string might represent a number is a matter of interpretation of the string in a mathematical expression at some later time). Thus the input is the same for both tasks: <lang tcl>set str [gets stdin] set num [gets stdin]</lang> possibly followed by something like <lang tcl>if {![string is integer -strict $num]} then { ...do something here...}</lang>
If the requirement is to prompt until the user enters the integer 75000, then: <lang tcl>set input 0 while {$input != 75000} {
puts -nonewline "enter the number '75000': " flush stdout set input [gets stdin]
}</lang>
Of course, it's nicer to wrap the primitives in a procedure: <lang tcl>proc question {var message} {
upvar 1 $var v puts -nonewline "$message: " flush stdout gets stdin $v
} question name "What is your name" question task "What is your quest" question doom "What is the air-speed velocity of an unladen swallow"</lang>
TI-83 BASIC
This program leaves the string in String1, and the integer in variable "i".
<lang ti83b>
:Input "Enter a string:",Str1 :Prompt i :If(i ≠ 75000): Then :Disp "That isn't 75000" :Else :Stop
</lang>
TI-89 BASIC
This program leaves the requested values in the global variables s and integer.
<lang ti89b>Prgm
InputStr "Enter a string", s Loop Prompt integer If integer ≠ 75000 Then Disp "That wasn't 75000." Else Exit EndIf EndLoop
EndPrgm</lang>
Toka
<lang toka>needs readline ." Enter a string: " readline is-data the-string ." Enter a number: " readline >number [ ." Not a number!" drop 0 ] ifFalse is-data the-number
the-string type cr the-number . cr</lang>
TUSCRIPT
<lang tuscript> $$ MODE TUSCRIPT LOOP ASK "Enter a string": str="" ASK "Enter an integer": int="" IF (int=='digits') THEN PRINT "int=",int," str=",str EXIT ELSE PRINT/ERROR int," is not an integer" CYCLE ENDIF ENDLOOP </lang> Output:
Enter a string >a Enter an integer >a @@@@@@@@ a is not an integer @@@@@@@@ Enter a string >a Enter an integer >1 int=1 str=a
UNIX Shell
<lang bash>#!/bin/sh
read string read integer read -p 'Enter a number: ' number echo "The number is $number"</lang>
Ursa
<lang ursa>#
- user input
- in ursa, the type of data expected must be specified
decl string str decl int i
out "input a string: " console set str (in string console) out "input an int: " console set i (in int console)
out "you entered " str " and " i endl console</lang>
VBA
<lang vb>Public Sub text()
Debug.Print InputBox("Input a string") Debug.Print InputBox("Input the integer 75000", "Input an integer", 75000, Context = "Long")
End Sub</lang>
Vedit macro language
<lang vedit>Get_Input(1, "Enter a string: ")
- 2 = Get_Num("Enter a number: ")</lang>
Visual Basic .NET
Platform: .NET
Input an Integer
<lang vbnet>Dim i As Integer Console.WriteLine("Enter an Integer") i = Console.ReadLine()</lang>
Input an Integer With Error Handling
<lang vbnet>Dim i As Integer Dim iString As String Console.WriteLine("Enter an Integer") iString = Console.ReadLine() Try
i = Convert.ToInt32(iString)
Catch ex As Exception
Console.WriteLine("This is not an Integer")
End Try</lang>
Input a String
<lang vbnet>Dim i As String Console.WriteLine("Enter a String") i = Console.ReadLine()</lang>
XLISP
READ-LINE reads a line of input as a string; READ reads an expression, of arbitrary complexity. <lang scheme>(display "Enter a string: ") (define s (read-line)) (display "Yes, ") (write s) (display " is a string.") ;; no need to verify, because READ-LINE has to return a string (newline) (display "Now enter the integer 75000: ") (define n (read)) (display
(cond ((not (integerp n)) "That's not even an integer." ) ((/= n 75000) "That is not the integer 75000." ) (t "Yes, that is the integer 75000." ) ) )</lang>
- Output:
Enter a string: Rosetta Code Yes, "Rosetta Code" is a string. Now enter the integer 75000: 75000 Yes, that is the integer 75000.
XPL0
When the ChIn(0) intrinsic is first called, it collects characters from the keyboard until the Enter key is struck. It then returns to the XPL0 program where one character is pulled from the buffer each time ChIn(0) is called. When the Enter key (which is the same as a carriage return, $0D) is pulled, the program quits the loop. A zero byte is stored in place of the Enter key to mark the end of the string.
<lang XPL0>string 0; \use zero-terminated strings, instead of MSb terminated include c:\cxpl\codes; int I; char Name(128); \the keyboard buffer limits input to 128 characters
[Text(0, "What's your name? "); I:= 0; loop [Name(I):= ChIn(0); \buffered keyboard input
if Name(I) = $0D\CR\ then quit; \Carriage Return = Enter key I:= I+1; ];
Name(I):= 0; \terminate string Text(0, "Howdy "); Text(0, Name); Text(0, "! Now please enter ^"75000^": "); IntOut(0, IntIn(0)); CrLf(0); \echo the number ]</lang>
Example output:
What's your name? Loren Blaney Howdy Loren Blaney! Now please enter "75000": 75000 75000
zkl
<lang zkl>str:=ask("Gimmie a string: "); n:=ask("Type 75000: ").toInt();</lang>
ZX Spectrum Basic
<lang basic>10 INPUT "Enter a string:"; s$ 20 INPUT "Enter a number: "; n</lang>