Pangram checker: Difference between revisions
Not a robot (talk | contribs) Add Cowgol |
imported>Thebeez Added uBasic/4tH version |
||
(52 intermediate revisions by 26 users not shown) | |||
Line 1:
[[Category:String manipulation]]
{{task}}
{{omit from|Lilypond}}
Line 17:
:* [https://rosettacode.org/wiki/Determine_if_a_string_has_all_unique_characters determine if a string has all unique characters]
<br><br>
=={{header|11l}}==
<syntaxhighlight lang="11l">F is_pangram(sentence)
R Set(sentence.lowercase().filter(ch -> ch C ‘a’..‘z’)).len == 26
L(sentence) [‘The quick brown fox jumps over the lazy dog.’,
‘The quick brown fox jumped over the lazy dog.’]
print(‘'#.' is #.a pangram’.format(sentence, ‘not ’ * !is_pangram(sentence)))</syntaxhighlight>
{{out}}
<pre>
'The quick brown fox jumps over the lazy dog.' is a pangram
'The quick brown fox jumped over the lazy dog.' is not a pangram
</pre>
=={{header|360 Assembly}}==
<
PANGRAM CSECT
USING PANGRAM,R12
Line 35 ⟶ 49:
LA R5,1 found
NEXTK LA R11,1(R11) next character
BCT R8,LOOPK
LTR R5,R5 if found
BNZ NEXTJ
Line 41 ⟶ 55:
B PRINT
NEXTJ LA R10,1(R10) next letter
BCT R7,LOOPJ
MVC BUFFER(2),=CL2'OK'
PRINT MVC BUFFER+3(60),0(R9)
XPRNT BUFFER,80
NEXTI LA R9,60(R9) next sentence
BCT R6,LOOPI
RETURN XR R15,R15
BR R14
Line 55 ⟶ 69:
DC CL60'PACK MY BOX WITH FIVE DOZEN LIQUOR JUGS.'
BUFFER DC CL80' '
YREGS
END PANGRAM</
{{out}}
<pre>OK THE QUICK BROWN FOX JUMPS OVER THE LAZY DOG.
Line 64 ⟶ 78:
=={{header|ACL2}}==
<
(if (endp needles)
t
Line 72 ⟶ 86:
(defun pangramp (str)
(contains-each (coerce "abcdefghijklmnopqrstuvwxyz" 'list)
(coerce (string-downcase str) 'list)))</
=={{header|Action!}}==
{{libheader|Action! Tool Kit}}
<syntaxhighlight lang="action!">INCLUDE "D2:CHARTEST.ACT" ;from the Action! Tool Kit
DEFINE CHAR_COUNT="26"
BYTE FUNC IsPangram(CHAR ARRAY t)
BYTE ARRAY tab(CHAR_COUNT)
BYTE i,c
FOR i=0 TO CHAR_COUNT-1
DO tab(i)=0 OD
FOR i=1 TO t(0)
DO
c=ToLower(t(i))
IF c>='a AND c<='z THEN
tab(c-'a)=1
FI
OD
FOR i=0 TO CHAR_COUNT-1
DO
IF tab(i)=0 THEN
RETURN (0)
FI
OD
RETURN (1)
PROC Test(CHAR ARRAY t)
BYTE res
res=IsPangram(t)
PrintF("""%S"" is ",t)
IF res=0 THEN
Print("not ")
FI
PrintE("a pangram.")
PutE()
RETURN
PROC Main()
Put(125) PutE() ;clear screen
Test("The quick brown fox jumps over the lazy dog.")
Test("QwErTyUiOpAsDfGhJkLzXcVbNm")
Test("Not a pangram")
Test("")
RETURN</syntaxhighlight>
{{out}}
[https://gitlab.com/amarok8bit/action-rosetta-code/-/raw/master/images/Pangram_checker.png Screenshot from Atari 8-bit computer]
<pre>
"The quick brown fox jumps over the lazy dog." is a pangram.
"QwErTyUiOpAsDfGhJkLzXcVbNm" is a pangram.
"Not a pangram" is not a pangram.
"" is not a pangram.
</pre>
=={{header|ActionScript}}==
{{works with|ActionScript|2.0}}
<
var lowerK:String = k.toLowerCase();
var has:Object = {}
for (var i:Number=0; i<=k.length-1; i++) {
has[lowerK.charAt(i)] = true;
}
var result:Boolean = true;
for (var ch:String='a'; ch <= 'z'; ch=String.fromCharCode(ch.charCodeAt(0)+1)) {
result = result && has[ch]
}
return result || false;
}</
=={{header|Ada}}==
=== Using character sets ===
<
with Ada.Strings.Maps; use Ada.Strings.Maps;
with Ada.Characters.Handling; use Ada.Characters.Handling;
procedure pangram is
function ispangram(txt: String) return Boolean is
(Is_Subset(To_Set(Span => ('a','z')), To_Set(To_Lower(txt))));
begin
put_line(Boolean'Image(ispangram("This is a test")));
Line 109 ⟶ 183:
put_line(Boolean'Image(ispangram("abcdefghijklopqrstuvwxyz"))); --Missing m, n
end pangram;
</syntaxhighlight>
=== Using quantified expressions ===
<
with Ada.Characters.Handling; use Ada.Characters.Handling;
procedure pangram is
function ispangram(txt : in String) return Boolean is
(for all Letter in Character range 'a'..'z' =>
Line 125 ⟶ 199:
put_line(Boolean'Image(ispangram("abcdefghijklopqrstuvwxyz"))); --Missing m, n
end pangram;
</syntaxhighlight>
{{out}}
<pre>
Line 140 ⟶ 214:
{{works with|ELLA ALGOL 68|Any (with appropriate job cards)}}
<
INT la = ABS "a", lz = ABS "z";
INT ua = ABS "A", uz = ABS "Z";
Line 175 ⟶ 249:
FI
OD
)</
{{out}}
<pre>
Line 183 ⟶ 257:
=={{header|APL}}==
<
a←'abcdefghijklmnopqrstuvwxyz' ⍝ or ⎕ucs 96 + ⍳26 in GNU/Dyalog
A←'ABCDEFGHIJKLMNOPQRSTUVWXYZ' ⍝ or ⎕ucs 64 + ⍳26, or just ⎕a in Dyalog
0
1
</syntaxhighlight>
=={{header|AppleScript}}==
===AppleScriptObjC===
Out of the box, AppleScript lacks many library basics – no regex, no higher order functions, not even string functions for mapping to upper or lower case.
From OSX 10.10 onwards, we can, however, use ObjC functions from AppleScript by importing the Foundation framework. We do this below to get a toLowerCase() function. If we also add generic filter and map functions, we can write and test a simple isPangram() function as follows:
<
-- isPangram :: String -> Bool
Line 212 ⟶ 286:
end |λ|
end script
0 = length of filter(charUnUsed,
"abcdefghijklmnopqrstuvwxyz")
end isPangram
on run
map(isPangram, {¬
"is this a pangram", ¬
"The quick brown fox jumps over the lazy dog"})
--> {false, true}
end run
-------------------- GENERIC FUNCTIONS -------------------
-- filter :: (a -> Bool) -> [a] -> [a]
Line 240 ⟶ 316:
end tell
end filter
-- map :: (a -> b) -> [a] -> [b]
Line 253 ⟶ 330:
end map
-- Lift 2nd class handler function into
-- 1st class script wrapper
-- mReturn :: Handler -> Script
on mReturn(f)
Line 264 ⟶ 343:
end if
end mReturn
-- toLower :: String -> String
Line 270 ⟶ 350:
((ca's NSString's stringWithString:(str))'s ¬
lowercaseStringWithLocale:(ca's NSLocale's currentLocale())) as text
end toLower</
{{Out}}
<syntaxhighlight lang
----
===Core language===
Contrary to the impression given above, AppleScript is perfectly capable of handling this task very simply and without the need for imported libraries.
<syntaxhighlight lang="applescript">on isPangram(txt)
set alphabet to "abcedfghijklmnopqrstuvwxyz"
ignoring case -- The default, but ensure it here.
repeat with letter in alphabet
if (txt does not contain letter) then return false
end repeat
end ignoring
return true
end isPangram
local result1, result2
set result1 to isPangram("The Quick Brown Fox Jumps Over The Lazy Dog")
set result2 to isPangram("This is not a pangram")
return {result1, result2}</syntaxhighlight>
{{output}}
<syntaxhighlight lang="applescript">{true, false}</syntaxhighlight>
=={{header|Arturo}}==
<syntaxhighlight lang="rebol">chars: map 97..122 => [to :string to :char &]
pangram?: function [sentence][
every? chars 'ch ->
in? ch sentence
]
print pangram? "this is a sentence"
print pangram? "The quick brown fox jumps over the lazy dog."</syntaxhighlight>
{{out}}
<pre>false
true</pre>
=={{header|ATS}}==
<syntaxhighlight lang="ats">
(* ****** ****** *)
//
Line 321 ⟶ 437:
(* ****** ****** *)
</syntaxhighlight>
An alternate implementation that makes a single pass through the string:
<
val letters: arrayref(bool, 26) = arrayref_make_elt<bool>(i2sz(26), false)
fn check(): bool = loop(0) where {
Line 344 ⟶ 460:
end
}
</syntaxhighlight>
=={{header|AutoHotkey}}==
<
Gui, Add, Edit, w300 r5 vText
Gui, Add, Button, x105 w100 Default, Check Pangram
Line 365 ⟶ 481:
}
MsgBox,, Pangram, OK`, this is a Pangram!
Return</
=={{header|AutoIt}}==
<
Pangram("The quick brown fox jumps over the lazy dog")
Func Pangram($s_String)
Line 378 ⟶ 494:
Return MsgBox(0,"Pangram", "Sentence is a Pangram")
EndFunc
</syntaxhighlight>
=={{header|AWK}}==
===Solution using string-operations===
<
BEGIN {
allChars="ABCDEFGHIJKLMNOPQRSTUVWXYZ";
Line 397 ⟶ 513:
for (k=1; k<=length(allChars); k++) {
if (!X[substr(allChars,k,1)]) return 0;
}
return 1;
}</
{{out}}
Line 408 ⟶ 524:
{{Works with|gawk|4.1.0}}
{{Works with|mawk|1.3.3}}
<
#
# Pangram-checker, using associative arrays and split
Line 434 ⟶ 550:
}
print "# hit:",hit, "# miss:",miss, "." ##
if (miss) return 0
return 1
}</
{{out}}
Line 459 ⟶ 575:
=={{header|BASIC}}==
==={{header|Applesoft BASIC}}===
<syntaxhighlight lang="gwbasic"> 100 P$ = "11111111111111111111111111"
110 FOR Q = 1 TO 3
120 READ S$
130 GOSUB 200"IS PANGRAM?
140 PRINT MID$ ("NO YES ",P * 4 + 1,4)S$
150 NEXT Q
160 END
170 DATA"THE QUICK BROWN FOX JUMPS OVER THE LAZY DOG."
180 DATA"THE QUICK BROWN FOX JUMPED OVER THE LAZY DOG."
190 DATA"THE FIVE BOXING WIZARDS JUMP QUICKLY."
200 P = 0:L = LEN (S$): IF NOT L THEN RETURN
210 F$ = "00000000000000000000000000"
220 FOR I = 1 TO L
230 C = ASC ( MID$ (S$,I,1)):C = C - 32 * (C > 95): IF C > 64 AND C < 91 THEN J = C - 64:F$ = MID$ (F$,1,J - 1) + "1" + MID$ (F$,J + 1):P = F$ = P$: IF P THEN RETURN
240 NEXT I
250 RETURN</syntaxhighlight>
{{out}}
<pre>
YES THE QUICK BROWN FOX JUMPS OVER THE LAZY DOG.
NO THE QUICK BROWN FOX JUMPED OVER THE LAZY DOG.
YES THE FIVE BOXING WIZARDS JUMP QUICKLY.
</pre>
==={{header|BaCon}}===
This can be done in a one-liner.
<syntaxhighlight lang="bacon">DEF FN Pangram(x) = IIF(AMOUNT(UNIQ$(EXPLODE$(EXTRACT$(LCASE$(x), "[^[:alpha:]]", TRUE), 1))) = 26, TRUE, FALSE)
PRINT Pangram("The quick brown fox jumps over the lazy dog.")
PRINT Pangram("Jackdaws love my big sphinx of quartz.")
PRINT Pangram("My dog has fleas.")
PRINT Pangram("What's a jackdaw?")
PRINT Pangram("The five boxing wizards jump quickly")</syntaxhighlight>
{{out}}
<pre>1
1
0
0
1
</pre>
==={{header|BASIC256}}===
<syntaxhighlight lang="freebasic">function isPangram$(texto$)
longitud = Length(texto$)
if longitud < 26 then return "is not a pangram"
t$ = lower(texto$)
print "'"; texto$; "' ";
for i = 97 to 122
if instr(t$, chr(i)) = 0 then return "is not a pangram"
next i
return "is a pangram"
end function
print isPangram$("The quick brown fox jumps over the lazy dog.") # --> true
print isPangram$("The quick brown fox jumped over the lazy dog.") # --> false
print isPangram$("ABC.D.E.FGHI*J/KL-M+NO*PQ R\nSTUVWXYZ") # --> true</syntaxhighlight>
==={{header|BBC BASIC}}===
<syntaxhighlight lang="bbcbasic"> FOR test% = 1 TO 2
READ test$
PRINT """" test$ """ " ;
IF FNpangram(test$) THEN
PRINT "is a pangram"
ELSE
PRINT "is not a pangram"
ENDIF
NEXT test%
END
DATA "The quick brown fox jumped over the lazy dog"
DATA "The five boxing wizards jump quickly"
DEF FNpangram(A$)
LOCAL C%
A$ = FNlower(A$)
FOR C% = ASC("a") TO ASC("z")
IF INSTR(A$, CHR$(C%)) = 0 THEN = FALSE
NEXT
= TRUE
DEF FNlower(A$)
LOCAL A%, C%
FOR A% = 1 TO LEN(A$)
C% = ASCMID$(A$,A%)
IF C% >= 65 IF C% <= 90 MID$(A$,A%,1) = CHR$(C%+32)
NEXT
= A$</syntaxhighlight>
{{out}}
<pre>"The quick brown fox jumped over the lazy dog" is not a pangram
"The five boxing wizards jump quickly" is a pangram</pre>
String manipulation is expensive, especially in loops, so it may be better to buffer the string and use character values:
<pre>DEFFNisPangram(text$)
LOCAL size%,text%,char%,bits%
size%=LENtext$
IF size%<27 THEN =FALSE:REM too few characters
DIM text% LOCAL size%:REM BB4W and RISC OS 5 only
$text%=text$:REM buffer the string
FOR text%=text% TO text%+size%-1:REM each character
char%=?text% OR 32:REM to lower case
IF 96<char% AND char%<123 THEN bits%=bits% OR 1<<(char%-97):REM set ordinal bit
IF bits%=&3FFFFFF THEN =TRUE:REM all ordinal bits set
NEXT text%
=FALSE</pre>
==={{header|Commodore BASIC}}===
<syntaxhighlight lang="gwbasic">10 rem detect model for title display
20 mx=peek(213): if mx=21 or mx=39 or mx=79 then 50:rem pet, vic, c64
30 mx=peek(238): if mx=39 or mx=79 then 50: rem c128
40 mx=39:color 4,1:rem assume plus/4 or c-16
50 if mx=21 then poke 36879,30:rem fix color on vic-20
60 print chr$(147);chr$(14);chr$(18);"**";:for i=2 to (mx-15)/2:print " ";:next
70 print "Pangram Checker";
80 for i=(mx-15)/2+16 to mx-2: print " ";: next: print "**"
100 read s$
110 if len(s$)=0 then end
120 gosub 1000:print
130 print "'"s$"' is";
140 if p=0 then print " not";
150 print " a pangram."
160 goto 100
500 data "The quick brown fox jumps over the lazy dog."
510 data "The quick brown fox jumped over the lazy dog."
520 data "The five boxing wizards jump quickly."
530 data
900 rem pangram checker
1000 if f=0 then f=1:dim seen(25),a(2):a(0)=65:a(1)=97:a(2)=193:goto 1020
1010 for i=0 to 25:seen(i)=0:next
1020 for i=1 to len(s$)
1030 : c=asc(mid$(s$,i))
1040 : for a = 0 to 2
1050 : if c>=a(a) and c<=a(a)+25 then seen(c-a(a))=seen(c-a(a))+1
1060 : next a
1070 next i
1080 p=-1
1090 for i=0 to 25
1100 : if seen(i)=0 then p=0:i=25
1110 next i
1120 return</syntaxhighlight>
{{Out}}
<pre>** Pangram Checker **
'The quick brown fox jumps over the lazy dog.' is a pangram.
'The quick brown fox jumped over the lazy dog.' is not a pangram.
'The five boxing wizards jump quickly.' is a pangram.
ready.</pre>
==={{header|Chipmunk Basic}}===
The [[#Applesoft BASIC|Applesoft BASIC]] solution works without any changes.
==={{header|FreeBASIC}}===
<syntaxhighlight lang="freebasic">' FB 1.05.0 Win64
Function isPangram(s As Const String) As Boolean
Dim As Integer length = Len(s)
If length < 26 Then Return False
Dim p As String = LCase(s)
For i As Integer = 97 To 122
If Instr(p, Chr(i)) = 0 Then Return False
Next
Return True
End Function
Dim s(1 To 3) As String = _
{ _
"The quick brown fox jumps over the lazy dog", _
"abbdefghijklmnopqrstuVwxYz", _ '' no c!
"How vexingly quick daft zebras jump!" _
}
For i As Integer = 1 To 3:
Print "'"; s(i); "' is "; IIf(isPangram(s(i)), "a", "not a"); " pangram"
Print
Next
Print
Print "Press nay key to quit"
Sleep</syntaxhighlight>
{{out}}
<pre>
'The quick brown fox jumps over the lazy dog' is a pangram
'abbdefghijklmnopqrstuVwxYz' is not a pangram
'How vexingly quick daft zebras jump!' is a pangram
</pre>
==={{header|Liberty BASIC}}===
<syntaxhighlight lang="lb">'Returns 0 if the string is NOT a pangram or >0 if it IS a pangram
string$ = "The quick brown fox jumps over the lazy dog."
Print isPangram(string$)
Function isPangram(string$)
string$ = Lower$(string$)
For i = Asc("a") To Asc("z")
isPangram = Instr(string$, chr$(i))
If isPangram = 0 Then Exit Function
Next i
End Function</syntaxhighlight>
==={{header|PureBasic}}===
<syntaxhighlight lang="purebasic">Procedure IsPangram_fast(String$)
String$ = LCase(string$)
char_a=Asc("a")
; sets bits in a variable if a letter is found, reads string only once
For a = 1 To Len(string$)
char$ = Mid(String$, a, 1)
pos = Asc(char$) - char_a
check.l | 1 << pos
Next
If check & $3FFFFFF = $3FFFFFF
ProcedureReturn 1
EndIf
ProcedureReturn 0
EndProcedure
Procedure IsPangram_simple(String$)
String$ = LCase(string$)
found = 1
For a = Asc("a") To Asc("z")
; searches for every letter in whole string
If FindString(String$, Chr(a), 0) = 0
found = 0
EndIf
Next
ProcedureReturn found
EndProcedure
Debug IsPangram_fast("The quick brown fox jumps over lazy dogs.")
Debug IsPangram_simple("The quick brown fox jumps over lazy dogs.")
Debug IsPangram_fast("No pangram")
Debug IsPangram_simple("No pangram")</syntaxhighlight>
==={{header|QBasic}}===
<
DIM x AS STRING
Line 502 ⟶ 859:
IsPangram! = -1
END FUNCTION</
{{out}}
<pre>
Line 510 ⟶ 867:
0 What's a jackdaw?
</pre>
==={{header|Run BASIC}}===
<syntaxhighlight lang="runbasic">s$ = "The quick brown fox jumps over the lazy dog."
Print pangram(s$);" ";s$
s$ = "My dog has fleas."
Print pangram(s$);" ";s$
function pangram(str$)
str$ = lower$(str$)
for i = asc("a") to asc("z")
pangram = pangram + (instr(str$, chr$(i)) <> 0)
next i
pangram = (pangram = 26)
end function</syntaxhighlight><pre>1 The quick brown fox jumps over the lazy dog.
0 My dog has fleas.</pre>
==={{header|Sinclair ZX81 BASIC}}===
Works (just) with the 1k RAM model. The "37" that crops up a couple of times stops being a mystery if we remember that the ZX81 character code for <code>A</code> is 38 and that strings (like arrays) are indexed from 1, not from 0.
<
20 LET L=26
30 INPUT P$
Line 530 ⟶ 903:
160 GOTO 180
170 PRINT "NOT A PANGRAM"
180 SLOW</
{{in}}
<pre>THE QUICK BROWN FOX JUMPS OVER THE LAZY DOG.</pre>
Line 540 ⟶ 913:
<pre>NOT A PANGRAM</pre>
==={{header|
<syntaxhighlight lang="basic">Proc _ShowPangram ("The quick brown fox jumps over the lazy dog.")
Proc _ShowPangram ("QwErTyUiOpAsDfGhJkLzXcVbNm")
Proc _ShowPangram ("Not a pangram")
End
_ShowPangram ' demonstrate the Pangram() function
Param (1)
Print Show (a@);Tab (50);Show (Iif (FUNC(_Pangram (a@)), "A pangram", "Not a pangram"))
Return
_Pangram
Param (1) ' pangram candidate
Local (3)
b@ = 0 ' reset the bitmap
For d@ = 0 To Len(a@) -1 ' parse the string
c@ = Peek (a@, d@) ' get current character
If (c@ > Ord ("A") - 1) * (c@ < Ord ("Z") + 1) Then c@ = c@ + 32
If (c@ > Ord ("a") - 1) * (c@ < Ord ("z") + 1) Then b@ = OR(b@, 2^(c@ - Ord ("a")))
Next ' update the bitmap
Return (b@ = 67108863) ' all bits set?</syntaxhighlight>
{{Out}}
<pre>The quick brown fox jumps over the lazy dog. A pangram
QwErTyUiOpAsDfGhJkLzXcVbNm A pangram
Not a pangram Not a pangram
0 OK, 0:156</pre>
==={{header|Yabasic}}===
<syntaxhighlight lang="yabasic">sub isPangram$(t$, l1$)
local lt, ll, r$, i, cc, ic
if numparams = 1 then
l1$ = "abcdefghijklmnopqrstuvwxyz"
end if
t$ = lower$(t$)
ll = len(l1$)
for i = 1 to ll
r$ = r$ + " "
next
lt = len(t$)
cc = asc("a")
for i = 1 to lt
ic = asc(mid$(t$, i, 1)) - cc + 1
if ic > 0 and ic <= ll then
mid$(r$, ic, 1) = chr$(ic + cc - 1)
end if
next i
if l1$ = r$ then return "true" else return "false" end if
end sub
print isPangram$("The quick brown fox jumps over the lazy dog.") // --> true
print isPangram$("The quick brown fox jumped over the lazy dog.") // --> false
print isPangram$("ABC.D.E.FGHI*J/KL-M+NO*PQ R\nSTUVWXYZ") // --> true</syntaxhighlight>
=={{header|Batch File}}==
<
setlocal enabledelayedexpansion
Line 587 ⟶ 1,004:
set letters=!letters:%chr%=!
set /a cnt+=1
goto loop</
{{Out}}
<pre>"The quick brown fox jumps over the lazy dog." is a pangram!
Line 594 ⟶ 1,011:
Press any key to continue . . .</pre>
=={{header|
<syntaxhighlight lang="bcpl">get "libhdr"
// Test if s is a pangram. The ASCII character set is assumed.
let pangram(s) = valof
$( let letters = vec 25
for i=0 to 25
for i=1 to s%0 do
$( let c
if c >= 0 & c < 26 then
for i=0 to 25 unless letters!i resultis false
resultis true
$)
// Display s and whether or not it is a pangram.
let check(s) be
$( writes(s)
writes(" -> ")
test
else writes("no*N")
$)
let start() be
$( check("The quick brown fox jumps over the lazy dog.")
check("The five boxing wizards dump quickly.")
$)</syntaxhighlight>
{{out}}
<pre>
=={{header|Befunge}}==
Line 632 ⟶ 1,048:
Reads the sentence to test from stdin.
<
^#*`\*93\`0<::-"@"-*<^40!%2g4:_
"pangram."<v*84<_v#-":"g40\" a"
>>:#,_55+,@>"ton">48*>"si tahT"</
{{in}}
Line 644 ⟶ 1,060:
=={{header|Bracmat}}==
<
k
. low$!arg:?arg
Line 653 ⟶ 1,069:
)
& !k:>z
&
);</
Some examples:
<pre>isPangram$("the Quick brown FOX jumps over the lazy do")
Line 672 ⟶ 1,088:
=={{header|Brat}}==
<
letters = [:a :b :c :d :e :f :g :h :i :j :k :l :m
:n :o :p :q :r :s :t :u :v :w :x :y :z]
Line 686 ⟶ 1,102:
p pangram? 'The quick brown fox jumps over the lazy dog.' #Prints true
p pangram? 'Probably not a pangram.' #Prints false</
Alternative version:
<
sentence.downcase.dice.unique.select(:alpha?).length == 26
}</
=={{header|C}}==
<
int is_pangram(const char *s)
Line 735 ⟶ 1,151:
tests[i], is_pangram(tests[i])?"":"not ");
return 0;
}</
===Using bitmask===
Assumes an execution environment using the ASCII character set (will invoke undefined behavior on other systems).
<
int pangram(const char *s)
Line 761 ⟶ 1,177:
return 0;
}</
{{out}}
<pre>yes: The quick brown fox jumps over lazy dogs.
Line 769 ⟶ 1,185:
C# 3.0 or higher (.NET Framework 3.5 or higher)
<
using System.Linq;
Line 783 ⟶ 1,199:
Console.WriteLine(arguments.Any() && arguments.First().IsPangram());
}
}</
Any version of C# language and .NET Framework
<
namespace PangrammChecker
Line 826 ⟶ 1,242:
}
}
}</
=={{header|C++}}==
<
#include <cctype>
#include <string>
Line 853 ⟶ 1,269:
}
}
</syntaxhighlight>
=={{header|Ceylon}}==
<
function pangram(String sentence) =>
let(alphabet = set('a'..'z'),
Line 872 ⟶ 1,288:
print("\"``sentence``\" is a pangram? ``pangram(sentence)``");
}
}</
=={{header|Clojure}}==
<
(let [letters (into #{} "abcdefghijklmnopqrstuvwxyz")]
(= (->> s .toLowerCase (filter letters) (into #{})) letters)))</
=={{header|CLU}}==
<syntaxhighlight lang="clu">pangram = proc (s: string) returns (bool)
letters: array[bool] := array[bool]$fill(0,26,false)
for c: char in string$chars(s) do
if c>='a' & c<='z' then
c := char$i2c(char$c2i(c) - 32)
end
if c>='A' & c<='Z' then
letters[char$c2i(c) - 65] := true
end
end
for seen: bool in array[bool]$elements(letters) do
if ~seen then return(false) end
end
return(true)
end pangram
start_up = proc ()
po: stream := stream$primary_output()
examples: array[string] := array[string]$[
"The quick brown fox jumps over the lazy dog.",
"The five boxing wizards dump quickly.",
"abcdefghijklmnopqrstuvwxyz"
]
for example: string in array[string]$elements(examples) do
stream$puts(po, "\"" || example || "\" is")
if ~pangram(example) then
stream$puts(po, " not")
end
stream$putl(po, " a pangram.")
end
end start_up</syntaxhighlight>
{{out}}
<pre>"The quick brown fox jumps over the lazy dog." is a pangram.
"The five boxing wizards dump quickly." is not a pangram.
"abcdefghijklmnopqrstuvwxyz" is a pangram.</pre>
=={{header|COBOL}}==
<
program-id. pan-test.
data division.
Line 930 ⟶ 1,384:
exit program
.
end program pangram.</
=={{header|CoffeeScript}}==
<
is_pangram = (s) ->
# This is optimized for longish strings--as soon as all 26 letters
Line 943 ⟶ 1,397:
for i in [a_code...a_code+26]
required_letters[String.fromCharCode(i)] = true
cnt = 0
for c in s
Line 968 ⟶ 1,422:
throw Error("fail") if is_pangram(long_str) != exp_value
console.log "Passed tests: #{s}"
</syntaxhighlight>
=={{header|Comal}}==
<syntaxhighlight lang="comal">0010 FUNC pangram#(s$) CLOSED
0020 FOR i#:=ORD("A") TO ORD("Z") DO
0030 IF NOT (CHR$(i#) IN s$ OR CHR$(i#+32) IN s$) THEN RETURN FALSE
0040 ENDFOR i#
0050 RETURN TRUE
0060 ENDFUNC
0070 //
0080 WHILE NOT EOD DO
0090 READ s$
0100 PRINT "'",s$,"' is ",
0110 IF NOT pangram#(s$) THEN PRINT "not ",
0120 PRINT "a pangram"
0130 ENDWHILE
0140 END
0150 DATA "The quick brown fox jumps over the lazy dog."
0160 DATA "The five boxing wizards dump quickly."</syntaxhighlight>
{{out}}
<pre>'The quick brown fox jumps over the lazy dog.' is a pangram
'The five boxing wizards dump quickly.' is not a pangram</pre>
=={{header|Common Lisp}}==
<
(null (set-difference
(loop for c from (char-code #\A) upto (char-code #\Z) collect (code-char c))
(coerce (string-upcase s) 'list))))</
=={{header|Component Pascal}}==
BlackBox Component Builder
<
MODULE BbtPangramChecker;
IMPORT StdLog,DevCommanders,TextMappers;
PROCEDURE Check(str: ARRAY OF CHAR): BOOLEAN;
CONST
letters = 26;
VAR
i,j: INTEGER;
status: ARRAY letters OF BOOLEAN;
resp : BOOLEAN;
BEGIN
FOR i := 0 TO LEN(status) -1 DO status[i] := FALSE END;
FOR i := 0 TO LEN(str) - 1 DO
j := ORD(CAP(str[i])) - ORD('A');
IF (0 <= j) & (25 >= j) & ~status[j] THEN status[j] := TRUE END
END;
resp := TRUE;
FOR i := 0 TO LEN(status) - 1 DO;
Line 1,027 ⟶ 1,502:
END BbtPangramChecker.
</syntaxhighlight>
Execute: ^Q BbtPangramChecker.Do "The quick brown fox jumps over the lazy dog"~ <br/>
^Q BbtPangramChecker.Do "abcdefghijklmnopqrstuvwxyz"~<br/>
Line 1,039 ⟶ 1,514:
=={{header|Cowgol}}==
<
sub pangram(str: [uint8]): (r: uint8) is
var letters: uint8[26];
MemZero(&letters[0], 26);
loop
var chr := [str];
Line 1,053 ⟶ 1,528:
letters[chr] := letters[chr] | 1;
end loop;
r := 1;
chr := 0;
Line 1,074 ⟶ 1,549:
print(yesno[pangram(test[i])]);
i := i + 1;
end loop;</
{{out}}
Line 1,085 ⟶ 1,560:
Copied and modified from the Ruby version.
<
('a'..'z').all? {|c| sentence.downcase.includes?(c) }
end
p pangram?("not a pangram")
p pangram?("The quick brown fox jumps over the lazy dog.")</
<pre>
Line 1,099 ⟶ 1,574:
=={{header|D}}==
===ASCII Bitmask version===
<
uint bitset;
Line 1,117 ⟶ 1,592:
assert(!"ABCDEFGHIJKL.NOPQRSTUVWXYZ".isPangram);
assert("ABC.D.E.FGHI*J/KL-M+NO*PQ R\nSTUVWXYZ".isPangram);
}</
===Unicode version===
<
// Do not compile with -g (debug info).
Line 1,141 ⟶ 1,616:
assert(isPangram("Falsches Üben von Xylophonmusik quält jeden größeren Zwerg"d, Alphabet.DE));
assert(isPangram("Yxskaftbud, ge vår wczonmö iqhjälp"w, Alphabet.SV));
}</
=={{header|Delphi}}==
<
{$APPTYPE CONSOLE}
Line 1,164 ⟶ 1,639:
Writeln(IsPangram('The quick brown fox jumps over the lazy dog')); // true
Writeln(IsPangram('Not a panagram')); // false
end.</
=={{header|Draco}}==
<syntaxhighlight lang="draco">proc nonrec pangram(*char s) bool:
ulong letters;
char c;
byte b;
byte A = pretend('a', byte);
byte Z = pretend('z', byte);
letters := 0L0;
while
c := s*;
s := s + 1;
c /= '\e'
do
b := pretend(c, byte) | 32;
if b >= A and b <= Z then
letters := letters | 0L1 << (b-A)
fi
od;
letters = 0x3FFFFFF
corp
proc nonrec test(*char s) void:
writeln("\"", s, "\": ",
if pangram(s) then "yes" else "no" fi)
corp
proc nonrec main() void:
test("The quick brown fox jumps over the lazy dog.");
test("The five boxing wizards jump quickly.");
test("Not a pangram")
corp</syntaxhighlight>
{{out}}
<pre>"The quick brown fox jumps over the lazy dog.": yes
"The five boxing wizards jump quickly.": yes
"Not a pangram": no</pre>
=={{header|E}}==
<
return ("abcdefghijklmnopqrstuvwxyz".asSet() &! sentence.toLowerCase().asSet()).size() == 0
}</
<code>&!</code> is the “but-not” or set difference operator.
=={{header|EasyLang}}==
<syntaxhighlight lang="easylang">
func pangr s$ .
len d[] 26
for c$ in strchars s$
c = strcode c$
if c >= 97 and c <= 122
c -= 32
.
if c >= 65 and c <= 91
d[c - 64] = 1
.
.
for h in d[]
s += h
.
return s
.
repeat
s$ = input
until s$ = ""
print s$
if pangr s$ = 26
print " --> pangram"
.
print ""
.
input_data
This is a test.
The quick brown fox jumps over the lazy dog.
The quick brown fox jumped over the lazy dog.
QwErTyUiOpAsDfGhJkLzXcVbNm
</syntaxhighlight>
=={{header|EDSAC order code}}==
Line 1,179 ⟶ 1,725:
it in a text file, making that file the active file, and clicking Reset.
The string must be terminated by a blank row of tape (represented by '.' in EdsacPC).
<
[Pangram checker for Rosetta Code.
EDSAC program, Initial Orders 2.]
Line 1,312 ⟶ 1,858:
P F [acc = 0 on entry]
THE!QUICK!BROWN!FOX!JUMPS!OVER!THE!LAZY!DOG.
</syntaxhighlight>
{{out}}
<pre>
Line 1,319 ⟶ 1,865:
=={{header|Elixir}}==
<
def checker(str) do
unused = Enum.to_list(?a..?z) -- to_char_list(String.downcase(str))
Line 1,329 ⟶ 1,875:
IO.puts "#{Pangram.checker(text)}\t#{text}"
text = (Enum.to_list(?A..?Z) -- 'Test') |> to_string
IO.puts "#{Pangram.checker(text)}\t#{text}"</
{{out}}
Line 1,338 ⟶ 1,884:
=={{header|Erlang}}==
<
-export([is_pangram/1]).
is_pangram(String) ->
ordsets:is_subset(lists:seq($a, $z), ordsets:from_list(string:to_lower(String))).</
=={{header|Excel}}==
===LAMBDA===
With the following lambda bound to the name ISPANGRAM in the Excel Workbook Name Manager:
(See [https://www.microsoft.com/en-us/research/blog/lambda-the-ultimatae-excel-worksheet-function/ LAMBDA: The ultimate Excel worksheet function])
{{works with|Office 265 Betas 2010}}
<syntaxhighlight lang="lisp">ISPANGRAM
=LAMBDA(s,
LET(
abc, CHARS(LOWER("abcdefghijklmnopqrstuvwxyz")),
AND(
LAMBDA(c,
ISNUMBER(SEARCH(c, s, 1))
)(
abc
)
)
)
)</syntaxhighlight>
And assuming that the name CHARS is also bound in the Name Manager
to the generic (String -> Array Char) lambda:
<syntaxhighlight lang="lisp">CHARS
=LAMBDA(s,
MID(s, ROW(INDIRECT("1:" & LEN(s))), 1)
)</syntaxhighlight>
{{Out}}
{| class="wikitable"
|-
|||style="text-align:right; font-family:serif; font-style:italic; font-size:120%;"|fx
! colspan="2" style="text-align:left; vertical-align: bottom; font-family:Arial, Helvetica, sans-serif !important;"|=ISPANGRAM(A2)
|- style="text-align:center; font-family:Arial, Helvetica, sans-serif !important; background-color:#000000; color:#ffffff;"
|
| A
| B
|- style="text-align:left;"
| style="text-align:center; font-family:Arial, Helvetica, sans-serif !important; background-color:#000000; color:#ffffff" | 1
| style="text-align:right; font-weight:bold" | Test strings
| style="font-weight:bold" | Verdicts
|- style="text-align:right;"
| style="text-align:center; font-family:Arial, Helvetica, sans-serif !important; background-color:#000000; color:#ffffff" | 2
| style="text-align:right;" | The quick brown fox jumps over the lazy dog
| style="background-color:#cbcefb; text-align:left; " | TRUE
|- style="text-align:right;"
| style="text-align:center; font-family:Arial, Helvetica, sans-serif !important; background-color:#000000; color:#ffffff" | 3
| style="text-align:right;" | Is this a pangram
| style="text-align:left; | FALSE
|- style="text-align:right;"
| style="text-align:center; font-family:Arial, Helvetica, sans-serif !important; background-color:#000000; color:#ffffff" | 4
| style="text-align:right;" | How vexingly quick daft zebras jump!
| style="text-align:left;" | TRUE
|- style="text-align:right;"
| style="text-align:center; font-family:Arial, Helvetica, sans-serif !important; background-color:#000000; color:#ffffff" | 5
| style="text-align:right;" | The five boxing wizards jumped quickly.
| style="text-align:left;| TRUE
|}
=={{header|F Sharp|F#}}==
If the difference between the set of letters in the alphabet and the set of letters in the given string (after conversion to lower case) is the empty set then every letter appears somewhere in the given string:
<
=={{header|Factor}}==
{{trans|E}}
<
[ "abcdefghijklmnopqrstuvwxyz" ] dip >lower diff length 0 = ;
"How razorback-jumping frogs can level six piqued gymnasts!" pangram? .</
=={{header|Forth}}==
<
0 -rot bounds do
i c@ 32 or [char] a -
Line 1,365 ⟶ 1,973:
1 26 lshift 1- = ;
s" The five boxing wizards jump quickly." pangram? . \ -1</
=={{header|Fortran}}==
{{works with|Fortran|90 and later}}
<
implicit none
Line 1,416 ⟶ 2,024:
end function is_pangram
end module pangram</
Example:
<
use pangram, only: is_pangram
Line 1,432 ⟶ 2,040:
write (*, '(l1)') is_pangram (string)
end program test</
{{out}}
<pre>This is a sentence.
Line 1,439 ⟶ 2,047:
T</pre>
=={{header|
<syntaxhighlight lang="frink">s = "The quick brown fox jumps over the lazy dog."
println["\"$s\" is" + (isPangram[s] ? "" : " not") + " a pangram."]
{
charSet = toSet[charList[lc[s]]]
if ! charSet.contains[c]
return true
}</syntaxhighlight>
{{out}}
<pre>
"The quick brown fox jumps over the lazy dog." is a pangram.
</pre>
=={{header|FutureBasic}}==
<syntaxhighlight lang="futurebasic">
include "NSLog.incl"
local fn IsPangram( pangramString as CFStringRef ) as BOOL
NSUInteger i, count
BOOL result
CFStringRef lcPanStr = fn StringLowerCaseString( pangramString )
CFMutableSetRef mutSet = fn MutableSetWithCapacity( 0 )
count = len(lcPanStr)
for i = 0 to count - 1
if ( fn CharacterSetCharacterIsMember( fn CharacterSetLowercaseLetterSet, fn StringCharacterAtIndex( lcPanStr, i ) ) )
MutableSetAddObject( mutSet, fn StringWithFormat( @"%c", fn StringCharacterAtIndex( lcPanStr, i ) ) )
end if
next
if fn SetCount( mutSet ) >= 26 then result = YES else result = NO
end fn = result
CFStringRef testStr, trueStr, falseStr
CFArrayRef array
trueStr = @"Is a pangram"
falseStr = @"Not a pangram"
array = @[¬
@"My dog has fleas.",¬
@"The quick brown fox jumps over the lazy do.",¬
@"The quick brown fox jumped over the lazy dog.",¬
@"The quick brown fox jumps over the lazy dog.",¬
@"Jackdaws love my big sphinx of quartz.",¬
@"What's a jackdaw?",¬
@"Watch \"Jeopardy!\", Alex Trebek's fun TV quiz game.",¬
@"Pack my box with five dozen liquor jugs.",¬
@"This definitely is not a pangram.",¬
@"This is a random long sentence just for testing purposes."]
for testStr in array
if ( fn IsPangram( testStr ) )
NSLog( @"%13s : %@", fn StringUTF8String( trueStr ), testStr ) else NSLog( @"%s : %@", fn StringUTF8String( falseStr ), testStr )
end if
next
HandleEvents
</syntaxhighlight>
{{output}}
<pre>
Not a pangram : My dog has fleas.
Not a pangram : The quick brown fox jumps over the lazy do.
Not a pangram : The quick brown fox jumped over the lazy dog.
Is a pangram : The quick brown fox jumps over the lazy dog.
Is a pangram : Jackdaws love my big sphinx of quartz.
Not a pangram : What's a jackdaw?
Is a pangram : Watch "Jeopardy!", Alex Trebek's fun TV quiz game.
Is a pangram : Pack my box with five dozen liquor jugs.
Not a pangram : This definitely is not a pangram.
Not a pangram : This is a random long sentence just for testing purposes.
</pre>
=={{header|Fōrmulæ}}==
'''Solution'''
[[File:Fōrmulæ - Pangram checker 01.png]]
'''Test cases'''
[[File:Fōrmulæ - Pangram checker 02.png]]
[[File:Fōrmulæ - Pangram checker 03.png]]
[[File:Fōrmulæ - Pangram checker 04.png]]
[[File:Fōrmulæ - Pangram checker 05.png]]
=={{header|Go}}==
<
import "fmt"
Line 1,522 ⟶ 2,185:
}
return false
}</
{{out}}
<pre>
Line 1,532 ⟶ 2,195:
=={{header|Haskell}}==
<
import Data.List ((\\))
Line 1,538 ⟶ 2,201:
pangram = null . (['a' .. 'z'] \\) . map toLower
main = print $ pangram "How razorback-jumping frogs can level six piqued gymnasts!"</
=={{header|HicEst}}==
<
PangramBrokenAt("The quick Brown Fox jumps over the Lazy Dog") ! => 0 (OK)
Line 1,548 ⟶ 2,211:
PangramBrokenAt = INDEX(Alfabet, string, 64)
! option 64: verify = 1st letter of string not in Alfabet
END</
=={{header|Icon}} and {{header|Unicon}}==
A panagram procedure:
<
if (map(s) ** &lcase) === &lcase then return s
end</
And a main to drive it:
<
if *arglist > 0 then
every ( s := "" ) ||:= !arglist || " "
else
s := "The quick brown fox jumps over the lazy dog."
writes(image(s), " -- is")
writes(if not panagram(s) then "n't")
write(" a panagram.")
end</
=={{Header|Insitux}}==
<syntaxhighlight lang="insitux">
(function pangram? sentence
(let prepped (-> sentence lower-case to-vec))
(all? prepped (map char-code (range 97 123))))
(pangram? "The five boxing wizards jump quickly.")
</syntaxhighlight>
=={{header|Io}}==
<
letters := " " repeated(26)
ia := "a" at(0)
Line 1,583 ⟶ 2,256:
"The quick brown fox jumps over the lazy dog." isPangram println // --> true
"The quick brown fox jumped over the lazy dog." isPangram println // --> false
"ABC.D.E.FGHI*J/KL-M+NO*PQ R\nSTUVWXYZ" isPangram println // --> true</
=={{header|Ioke}}==
<
letters = "abcdefghijklmnopqrstuvwxyz" chars
text = self lower chars
letters map(x, text include?(x)) reduce(&&)
)</
Here is an example of it's use in the Ioke REPL:
<
iik> "The quick brown fox jumps over the lazy dog" isPangram?
"The quick brown fox jumps over the lazy dog" isPangram?
Line 1,601 ⟶ 2,274:
iik> "The quick brown fox jumps over the" isPangram?
"The quick brown fox jumps over the" isPangram?
+> false</
=={{header|J}}==
'''Solution:'''
<
isPangram=: (a. {~ 97+i.26) */@e. tolower</
'''Example use:'''
<
1
isPangram 'The quick brown fox falls over the lazy dog.'
0</
=={{header|Java}}==
{{works with|Java|1.5+}}
<
public static boolean isPangram(String test){
for (char a = 'A'; a <= 'Z'; a++)
Line 1,633 ⟶ 2,306:
System.out.println(isPangram(""));//false
}
}</
{{out}}
<pre>true
Line 1,647 ⟶ 2,320:
====Iterative====
<
var letters = "zqxjkvbpygfwmucldrhsnioate"
// sorted by frequency ascending (http://en.wikipedia.org/wiki/Letter_frequency)
Line 1,657 ⟶ 2,330:
console.log(isPangram("is this a pangram")) // false
console.log(isPangram("The quick brown fox jumps over the lazy dog")) // true</
===ES6===
====Functional====
<
// ----------------- PANGRAM CHECKER -----------------
// isPangram :: String -> Bool
.split("")
.filter(c => -1 === s.toLowerCase().indexOf(c))
.length;
// ---------------------- TEST -----------------------
return [
].map(isPangram);
})();</syntaxhighlight>
{{Out}}
Line 1,687 ⟶ 2,358:
=={{header|jq}}==
<
explode
| map( if 65 <= . and . <= 90 then . + 32 # uppercase
Line 1,697 ⟶ 2,368:
# Example:
"The quick brown fox jumps over the lazy dog" | is_pangram</
{{Out}}
$ jq -M -n -f pangram.jq
Line 1,704 ⟶ 2,375:
=={{header|Julia}}==
<tt>makepangramchecker</tt> creates a function to test for pangramity based upon the contents of its input string, allowing one to create arbitrary pangram checkers.
<
alphabet = Set(uppercase.(alphabet))
function ispangram(s)
Line 1,723 ⟶ 2,394:
for s in tests
println("The sentence \"", s, "\" is ", is_english_pangram(s) ? "" : "not ", "a pangram.")
end</
{{out}}
Line 1,735 ⟶ 2,406:
=={{header|K}}==
{{works with|Kona}}
<syntaxhighlight lang="k">lcase : _ci 97+!26
ucase : _ci 65+!26
tolower : {@[x;p;:;lcase@n@p:&26>n:ucase?/:x]}
panagram: {&/lcase _lin tolower x}</
Example:
<
1
panagram "Panagram test"
0</
{{works with|ngn/k}}
<syntaxhighlight lang=K>isPangram:0=#(`c$"a"+!26)^_:
isPangram"This is a test"
0
isPangram"The quick brown fox jumps over the lazy dog."
1</syntaxhighlight>
=={{header|Kotlin}}==
<
fun isPangram(s: String): Boolean {
Line 1,755 ⟶ 2,435:
if (c !in t) return false
return true
}
fun main(args: Array<String>) {
Line 1,764 ⟶ 2,444:
"A very mad quack might jinx zippy fowls" // no 'b' now!
)
for (candidate in candidates)
println("'$candidate' is ${if (isPangram(candidate)) "a" else "not a"} pangram")
}</
{{out}}
Line 1,776 ⟶ 2,456:
</pre>
=={{header|
<syntaxhighlight lang="ksh">
#!/bin/ksh
# Pangram checker
# # Variables:
#
alphabet='abcdefghijklmnopqrstuvwxyz'
typeset -a strs
strs+=( 'Mr. Jock, TV quiz PhD., bags few lynx.' )
strs+=( 'A very mad quack might jinx zippy fowls.' )
# # Functions:
#
# # Function _ispangram(str) - return 0 if str is a pangram
#
function _ispangram {
typeset _str ; typeset -l _str="$1"
typeset _buff ; _buff="${alphabet}"
typeset _i ; typeset -si _i
for ((_i=0; _i<${#_str} && ${#_buff}>0; _i++)); do
_buff=${_buff/${_str:${_i}:1}/}
done
return ${#_buff}
}
######
# main #
######
typeset -si i
for ((i=0; i<${#strs[*]}; i++)); do
_ispangram "${strs[i]}"
if (( ! $? )); then
print "${strs[i]} <<< IS A PANGRAM."
else
print "${strs[i]} <<< Is not a pangram."
fi
done
</syntaxhighlight>
{{out}}<pre>
Mr. Jock, TV quiz PhD., bags few lynx. <<< IS A PANGRAM.
A very mad quack might jinx zippy fowls. <<< Is not a pangram.
</pre>
=={{header|Logo}}==
<
if empty? :s [output :set]
if word? :s [output remove.all butfirst :s remove first :s :set]
Line 1,800 ⟶ 2,515:
end
show pangram? [The five boxing wizards jump quickly.] ; true</
=={{header|Lua}}==
<
S, C = lpeg.S, lpeg.C
function ispangram(s)
Line 1,811 ⟶ 2,526:
print(ispangram"waltz, bad nymph, for quick jigs vex")
print(ispangram"bobby")
print(ispangram"long sentence")</
=={{header|Maple}}==
<
is_pangram := proc(str)
local present := StringTools:-LowerCase~(select(StringTools:-HasAlpha, StringTools:-Explode(str)));
Line 1,821 ⟶ 2,536:
return evalb(present = alphabets);
end proc;
</syntaxhighlight>
{{out|Usage}}
<syntaxhighlight lang="text">is_pangram("The quick brown fox jumps over the lazy dog.");
is_pangram("The 2 QUIck brown foxes jumped over the lazy DOG!!");
is_pangram(""The quick brown fox jumps over the lay dog.");</
{{out|Output}}
<pre>
Line 1,833 ⟶ 2,548:
</pre>
=={{header|Mathematica}}/{{header|Wolfram Language}}==
<
Usage:
<pre>pangramQ["The quick brown fox jumps over the lazy dog."]
Line 1,840 ⟶ 2,555:
Or a slightly more verbose version that outputs the missing characters if the string is not a pangram:
<
Function[If[# === {}, Print["The string is a pangram!"],
Print["The string is not a pangram. It's missing the letters " <>
ToString[#]]]][
Complement[CharacterRange["a", "z"], Characters[ToLowerCase[msg]]]]</
Usage:
<pre>pangramQ["The quick brown fox jumps over the lazy dog."]
Line 1,852 ⟶ 2,567:
=={{header|MATLAB}}==
<
%This works by histogramming the ascii character codes for lower case
Line 1,863 ⟶ 2,578:
trueFalse = isempty(find( histc(lower(string),(97:122))==0,1 ));
end</
{{out}}
<
ans =
1</
=={{header|MATLAB}} / {{header|Octave}}==
<
% X is a histogram of letters
X = sparse(abs(lower(string)),1,1,128,1);
trueFalse = full(all(X('a':'z') > 0));
end</
{{out}}
Line 1,887 ⟶ 2,602:
=={{header|min}}==
{{works with|min|0.19.3}}
<
('alphabet dip lowercase (swap match) prepend all?) :pangram?
"The quick brown fox jumps over the lazy dog." pangram? puts</
=={{header|MiniScript}}==
<
"Peter Piper picked a peck of pickled peppers.",
"Waltz job vexed quick frog nymphs."]
alphabet = "abcdefghijklmnopqrstuvwxyz"
pangram = function (toCheck)
sentence = toCheck.lower
Line 1,907 ⟶ 2,622:
return true
end function
for sentence in sentences
if pangram(sentence) then
print """" + sentence + """ is a Pangram"
else
print """" + sentence + """ is not a Pangram"
end if
end for</
{{out}}
<pre>
Line 1,924 ⟶ 2,639:
=={{header|ML}}==
==={{header|mLite}}===
<
fun is_pangram
(h :: t, T) =
let
val flen = len (filter (fn c = c eql h) T)
in
Line 1,936 ⟶ 2,651:
is_pangram (t, T)
end
| ([], T) = true
| S = is_pangram (explode "abcdefghijklmnopqrstuvwxyz", explode ` to_locase S)
fun is_pangram_i
(h :: t, T) =
let
val flen = len (filter (fn c = c eql h) T)
in
Line 1,949 ⟶ 2,664:
is_pangram (t, T)
end
| ([], T) = true
| (A,S) = is_pangram (explode A, explode ` to_locase S)
fun test (f, arg, res, ok, notok) = if (f arg eql res) then ("'" @ arg @ "' " @ ok) else ("'" @ arg @ "' " @ notok)
fun test2 (f, arg, res, ok, notok) = if (f arg eql res) then ("'" @ ref (arg,1) @ "' " @ ok) else ("'" @ ref (arg,1) @ "' " @ notok)
;
println ` test (is_pangram, "The quick brown fox jumps over the lazy dog", true, "is a pangram", "is not a pangram");
println ` test (is_pangram, "abcdefghijklopqrstuvwxyz", true, "is a pangram", "is not a pangram");
val SValphabet = "abcdefghijklmnopqrstuvwxyzåäö";
val SVsentence = "Yxskaftbud, ge vår wczonmö iq hjälp";
println ` test2 (is_pangram_i, (SValphabet, SVsentence), true, "is a Swedish pangram", "is not a Swedish pangram");
</syntaxhighlight>
{{out}}
<pre>'The quick brown fox jumps over the lazy dog' is a pangram
Line 1,967 ⟶ 2,682:
'Yxskaftbud, ge vår wczonmö iq hjälp' is a Swedish pangram
</pre>
=={{header|Modula-2}}==
<syntaxhighlight lang="modula2">MODULE Pangrams;
FROM InOut IMPORT WriteString, WriteLn;
FROM Strings IMPORT Length;
(* Check if a string is a pangram *)
PROCEDURE pangram(s: ARRAY OF CHAR): BOOLEAN;
VAR letters: ARRAY [0..25] OF BOOLEAN;
i: CARDINAL;
BEGIN
FOR i := 0 TO 25 DO letters[i] := FALSE; END;
FOR i := 0 TO Length(s)-1 DO
IF (s[i] >= 'A') AND (s[i] <= 'Z') THEN
letters[ORD(s[i]) - ORD('A')] := TRUE;
ELSIF (s[i] >= 'a') AND (s[i] <= 'z') THEN
letters[ORD(s[i]) - ORD('a')] := TRUE;
END;
END;
FOR i := 0 TO 25 DO
IF NOT letters[i] THEN
RETURN FALSE;
END;
END;
RETURN TRUE;
END pangram;
PROCEDURE example(s: ARRAY OF CHAR);
BEGIN
WriteString("'");
WriteString(s);
WriteString("' is ");
IF NOT pangram(s) THEN
WriteString("not ");
END;
WriteString("a pangram.");
WriteLn();
END example;
BEGIN
example("The quick brown fox jumps over the lazy dog");
example("The five boxing wizards dump quickly");
example("abcdefghijklmnopqrstuvwxyz");
END Pangrams.</syntaxhighlight>
{{out}}
<pre>'The quick brown fox jumps over the lazy dog' is a pangram.
'The five boxing wizards dump quickly' is not a pangram.
'abcdefghijklmnopqrstuvwxyz' is a pangram.</pre>
=={{header|NetRexx}}==
NetRexx's <code>verify</code> built–in method is all you need!
<
options replace format comments java crossref savelog symbols nobinary
Line 1,999 ⟶ 2,762:
return pangrams
</syntaxhighlight>
{{out}}
<pre style="overflow:scroll">
Line 2,010 ⟶ 2,773:
=={{header|NewLISP}}==
<
(context 'PGR) ;; Switch to context (say namespace) PGR
(define (is-pangram? str)
Line 2,029 ⟶ 2,792:
(println (PGR:is-pangram? "abcdef")) ;; Print nil
(exit)
</syntaxhighlight>
=={{header|Nim}}==
<
proc isPangram(sentence: string, alphabet = {'a'..'z'}): bool =
Line 2,039 ⟶ 2,802:
alphabet <= sentset
echo isPangram(readLineFromStdin "Sentence: ")</
Example usage:
<pre>Sentence: The quick brown fox jumps over the lazy dog
Line 2,046 ⟶ 2,809:
=={{header|Objeck}}==
{{trans|Java}}
<
bundle Default {
class Pangram {
Line 2,070 ⟶ 2,833:
}
}
</syntaxhighlight>
=={{header|OCaml}}==
<
let ar = Array.make 26 false in
String.iter (function
Line 2,080 ⟶ 2,843:
| _ -> ()
) (String.lowercase str);
Array.fold_left ( && ) true ar</
<
Printf.printf " %b -- %s\n" (pangram str) str
Line 2,088 ⟶ 2,851:
check "this is a sentence";
check "The quick brown fox jumps over the lazy dog.";
;;</
{{out}}
Line 2,095 ⟶ 2,858:
=={{header|Oz}}==
<
fun {IsPangram Xs}
{List.sub
Line 2,102 ⟶ 2,865:
end
in
{Show {IsPangram "The quick brown fox jumps over the lazy dog."}}</
=={{header|PARI/GP}}==
<
s=vecsort(Vec(s),,8);
for(i=97,122,
Line 2,116 ⟶ 2,879:
pangram("The quick brown fox jumps over the lazy dog.")
pangram("The quick brown fox jumps over the lazy doe.")</
=={{header|Pascal}}==
Line 2,123 ⟶ 2,886:
=={{header|Perl}}==
Get an answer with a module, or without.
<
use warnings;
use feature 'say';
Line 2,146 ⟶ 2,909:
say pangram1($_,@alpha) ? 'Yes' : 'No';
say pangram2($_,@alpha) ? 'Yes' : 'No';
}</
{{out}}
<pre>Yes
Line 2,154 ⟶ 2,917:
=={{header|Phix}}==
<!--<syntaxhighlight lang="phix">(phixonline)-->
<span style="color: #008080;">function</span> <span style="color: #000000;">pangram</span><span style="color: #0000FF;">(</span><span style="color: #004080;">string</span> <span style="color: #000000;">s</span><span style="color: #0000FF;">)</span>
<span style="color: #004080;">sequence</span> <span style="color: #000000;">az</span> <span style="color: #0000FF;">=</span> <span style="color: #7060A8;">repeat</span><span style="color: #0000FF;">(</span><span style="color: #004600;">false</span><span style="color: #0000FF;">,</span><span style="color: #000000;">26</span><span style="color: #0000FF;">)</span>
<span style="color: #004080;">integer</span> <span style="color: #000000;">count</span> <span style="color: #0000FF;">=</span> <span style="color: #000000;">0</span>
<span style="color: #008080;">for</span> <span style="color: #000000;">i</span><span style="color: #0000FF;">=</span><span style="color: #000000;">1</span> <span style="color: #008080;">to</span> <span style="color: #7060A8;">length</span><span style="color: #0000FF;">(</span><span style="color: #000000;">s</span><span style="color: #0000FF;">)</span> <span style="color: #008080;">do</span>
<span style="color: #004080;">integer</span> <span style="color: #000000;">ch</span> <span style="color: #0000FF;">=</span> <span style="color: #7060A8;">lower</span><span style="color: #0000FF;">(</span><span style="color: #000000;">s</span><span style="color: #0000FF;">[</span><span style="color: #000000;">i</span><span style="color: #0000FF;">])</span>
<span style="color: #008080;">if</span> <span style="color: #000000;">ch</span><span style="color: #0000FF;">>=</span><span style="color: #008000;">'a'</span>
<span style="color: #008080;">and</span> <span style="color: #000000;">ch</span><span style="color: #0000FF;"><=</span><span style="color: #008000;">'z'</span>
<span style="color: #008080;">and</span> <span style="color: #008080;">not</span> <span style="color: #000000;">az</span><span style="color: #0000FF;">[</span><span style="color: #000000;">ch</span><span style="color: #0000FF;">-</span><span style="color: #000000;">96</span><span style="color: #0000FF;">]</span> <span style="color: #008080;">then</span>
<span style="color: #000000;">count</span> <span style="color: #0000FF;">+=</span> <span style="color: #000000;">1</span>
<span style="color: #008080;">if</span> <span style="color: #000000;">count</span><span style="color: #0000FF;">=</span><span style="color: #000000;">26</span> <span style="color: #008080;">then</span> <span style="color: #008080;">return</span> <span style="color: #0000FF;">{</span><span style="color: #004600;">true</span><span style="color: #0000FF;">,</span><span style="color: #000000;">0</span><span style="color: #0000FF;">}</span> <span style="color: #008080;">end</span> <span style="color: #008080;">if</span>
<span style="color: #000000;">az</span><span style="color: #0000FF;">[</span><span style="color: #000000;">ch</span><span style="color: #0000FF;">-</span><span style="color: #000000;">96</span><span style="color: #0000FF;">]</span> <span style="color: #0000FF;">=</span> <span style="color: #004600;">true</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">if</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">for</span>
<span style="color: #008080;">return</span> <span style="color: #0000FF;">{</span><span style="color: #004600;">false</span><span style="color: #0000FF;">,</span><span style="color: #7060A8;">find</span><span style="color: #0000FF;">(</span><span style="color: #004600;">false</span><span style="color: #0000FF;">,</span><span style="color: #000000;">az</span><span style="color: #0000FF;">)+</span><span style="color: #000000;">96</span><span style="color: #0000FF;">}</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">function</span>
<span style="color: #004080;">sequence</span> <span style="color: #000000;">checks</span> <span style="color: #0000FF;">=</span> <span style="color: #0000FF;">{</span><span style="color: #008000;">"The quick brown fox jumped over the lazy dog"</span><span style="color: #0000FF;">,</span>
<span style="color: #008000;">"The quick brown fox jumps over the lazy dog"</span><span style="color: #0000FF;">,</span>
<span style="color: #008000;">".!$\"AbCdEfghijklmnoprqstuvwxyz"</span><span style="color: #0000FF;">,</span>
<span style="color: #008000;">"THE FIVE BOXING WIZARDS DUMP QUICKLY."</span><span style="color: #0000FF;">,</span>
<span style="color: #008000;">"THE FIVE BOXING WIZARDS JUMP QUICKLY."</span><span style="color: #0000FF;">,</span>
<span style="color: #008000;">"HEAVY BOXES PERFORM WALTZES AND JIGS."</span><span style="color: #0000FF;">,</span>
<span style="color: #008000;">"PACK MY BOX WITH FIVE DOZEN LIQUOR JUGS."</span><span style="color: #0000FF;">,</span>
<span style="color: #008000;">"Big fjiords vex quick waltz nymph"</span><span style="color: #0000FF;">,</span>
<span style="color: #008000;">"The quick onyx goblin jumps over the lazy dwarf."</span><span style="color: #0000FF;">,</span>
<span style="color: #008000;">"no"</span><span style="color: #0000FF;">}</span>
<span style="color: #008080;">for</span> <span style="color: #000000;">i</span><span style="color: #0000FF;">=</span><span style="color: #000000;">1</span> <span style="color: #008080;">to</span> <span style="color: #7060A8;">length</span><span style="color: #0000FF;">(</span><span style="color: #000000;">checks</span><span style="color: #0000FF;">)</span> <span style="color: #008080;">do</span>
<span style="color: #004080;">string</span> <span style="color: #000000;">ci</span> <span style="color: #0000FF;">=</span> <span style="color: #000000;">checks</span><span style="color: #0000FF;">[</span><span style="color: #000000;">i</span><span style="color: #0000FF;">]</span>
<span style="color: #004080;">integer</span> <span style="color: #0000FF;">{</span><span style="color: #000000;">r</span><span style="color: #0000FF;">,</span><span style="color: #000000;">ch</span><span style="color: #0000FF;">}</span> <span style="color: #0000FF;">=</span> <span style="color: #000000;">pangram</span><span style="color: #0000FF;">(</span><span style="color: #000000;">ci</span><span style="color: #0000FF;">)</span>
<span style="color: #7060A8;">printf</span><span style="color: #0000FF;">(</span><span style="color: #000000;">1</span><span style="color: #0000FF;">,</span><span style="color: #008000;">"%-50s - %s\n"</span><span style="color: #0000FF;">,{</span><span style="color: #000000;">ci</span><span style="color: #0000FF;">,</span><span style="color: #008080;">iff</span><span style="color: #0000FF;">(</span><span style="color: #000000;">r</span><span style="color: #0000FF;">?</span><span style="color: #008000;">"yes"</span><span style="color: #0000FF;">:</span><span style="color: #008000;">"no "</span><span style="color: #0000FF;">&</span><span style="color: #000000;">ch</span><span style="color: #0000FF;">)})</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">for</span>
<!--</syntaxhighlight>-->
{{out}}
<pre>
Line 2,198 ⟶ 2,963:
no - no a
</pre>
=={{header|Phixmonti}}==
<syntaxhighlight lang="Phixmonti">include ..\Utilitys.pmt
def pangram?
lower "abcdefghijklmnopqrstuvwxyz" swap remove len not nip
enddef
"The quick brown fox jumps over the lazy dog." pangram?
"This is a test" pangram?
"NOPQRSTUVWXYZ abcdefghijklm" pangram?
"abcdefghijklopqrstuvwxyz" pangram?
pstack</syntaxhighlight>
{{out}}
<pre>
[1, 0, 1, 0]
=== Press any key to exit ===</pre>
=={{header|PHP}}==
{{trans|D}}
<
foreach (str_split($text) as $c) {
if ($c >= 'a' && $c <= 'z')
Line 2,220 ⟶ 3,004:
foreach ($test as $str)
echo "$str : ", isPangram($str) ? 'T' : 'F', '</br>';</
<pre>the quick brown fox jumps over the lazy dog : T
Line 2,230 ⟶ 3,014:
Using array
<
// define "alphabet"
Line 2,257 ⟶ 3,041:
echo is_pangram( $txt ) ? "Yes" : "No", PHP_EOL, PHP_EOL;
}
</syntaxhighlight>
{{Out}}
Line 2,283 ⟶ 3,067:
Yes
</pre>
=={{header|Picat}}==
<syntaxhighlight lang="picat">go =>
S1 = "The quick brown fox jumps over the lazy dog",
S2 = "The slow brown fox jumps over the lazy dog",
println([S1, is_pangram(S1)]),
println([S2, is_pangram(S2)]),
nl,
println("With missing chars:"),
println([S1, is_pangram2(S1)]),
println([S2, is_pangram2(S2)]),
nl.
% Check if S is a pangram and get the missing chars
is_pangram(S) = P =>
Lower = S.to_lowercase,
Alpha = [chr(I+96) : I in 1..26],
foreach(A in Alpha) membchk(A,Lower) end -> P = true ; P = false.
% Check if S is a pangram and get the missing chars (if any)
is_pangram2(S) = [pangram=cond(Missing==[],true,false),missing=Missing] =>
Lower = S.to_lowercase,
Missing = [A : A in [chr(I+96) : I in 1..26], not membchk(A,Lower)].</syntaxhighlight>
{{out}}
<pre>[The quick brown fox jumps over the lazy dog,true]
[The slow brown fox jumps over the lazy dog,false]
With missing chars:
[The quick brown fox jumps over the lazy dog,[pangram = true,missing = []]]
[The slow brown fox jumps over the lazy dog,[pangram = false,missing = cikq]]</pre>
=={{header|PicoLisp}}==
<
(not
(diff
'`(chop "abcdefghijklmnopqrstuvwxyz")
(chop (lowc Str)) ) ) )</
=={{header|PL/I}}==
<syntaxhighlight lang="pl/i">
test_pangram: procedure options (main);
Line 2,321 ⟶ 3,136:
end test_pangram;
</syntaxhighlight>
{{out}}
<pre>
Please type a sentence
the quick brown fox jumps over the lazy dog
The sentence is a pangram.
</pre>
Line 2,334 ⟶ 3,149:
Cyrillic test sample borrowed from Raku.
{{works with|PowerShell|2}}
<syntaxhighlight lang="powershell">
function Test-Pangram ( [string]$Text, [string]$Alphabet = 'abcdefghijklmnopqrstuvwxyz' )
{
$Text = $Text.ToLower()
$Alphabet = $Alphabet.ToLower()
$IsPangram = @( $Alphabet.ToCharArray() | Where-Object { $Text.Contains( $_ ) } ).Count -eq $Alphabet.Length
return $IsPangram
}
Test-Pangram 'The quick brown fox jumped over the lazy dog.'
Test-Pangram 'The quick brown fox jumps over the lazy dog.'
Test-Pangram 'Съешь же ещё этих мягких французских булок, да выпей чаю' 'абвгдежзийклмнопрстуфхцчшщъыьэюяё'
</syntaxhighlight>
{{out}}
<pre>
Line 2,356 ⟶ 3,171:
</pre>
A faster version can be created using .Net HashSet to do what the F# version does:
<syntaxhighlight lang="powershell">
Function Test-Pangram ( [string]$Text, [string]$Alphabet = 'abcdefghijklmnopqrstuvwxyz' )
{
Line 2,366 ⟶ 3,181:
return $alSet.Count -eq 0 # any alphabet letters still remaining?
}
</syntaxhighlight>
=={{header|Prolog}}==
Works with SWI-Prolog
<
numlist(0'a, 0'z, Alphabet),
forall(member(C, Alphabet), member(C, L)).
Line 2,383 ⟶ 3,198:
( pangram(L2) -> R2 = ok; R2 = ko),
format('~s --> ~w ~n', [L2, R2]).
</syntaxhighlight>
{{out}}
<pre>?- pangram_example.
the quick brown fox jumps over the lazy dog --> ok
the quick brown fox jumped over the lazy dog --> ko
true.</pre>
=={{header|Python}}==
Using set arithmetic:
<
if sys.version_info[0] < 3:
input = raw_input
Line 2,433 ⟶ 3,215:
return alphaset <= set(sentence.lower())
print ( ispangram(input('Sentence: ')) )</
{{out}}
<pre>Sentence: The quick brown fox jumps over the lazy dog
True</pre>
=={{header|Quackery}}==
<syntaxhighlight lang="quackery">
[ dup char A char [ within
swap char a char { within
or ] is letter ( c --> b )
[ 0 26 of swap witheach
[ dup letter iff
[ 1 unrot lower
char a - poke ]
else drop ]
0 swap find 26 = ] is pangram ( $ --> b )
$ "This is a sentence." pangram echo cr ( 0 )
$ "The five boxing wizards jumped quickly." pangram echo cr ( 1 )
</syntaxhighlight>
=={{header|R}}==
Using the built-in R vector "letters":
<
my.letters <- tolower(unlist(strsplit(sentence, "")))
is.pangram <- all(letters %in% my.letters)
if (is.pangram){
cat("\"", sentence, "\" is a pangram! \n", sep="")
Line 2,451 ⟶ 3,250:
}
}
</
{{out}}
Line 2,464 ⟶ 3,263:
=={{header|Racket}}==
<syntaxhighlight lang="racket">
#lang racket
(define (pangram? str)
Line 2,470 ⟶ 3,269:
(= 26 (length (remove-duplicates (string->list chars)))))
(pangram? "The quick Brown Fox jumps over the Lazy Dog")
</syntaxhighlight>
=={{header|Raku}}==
(formerly Perl 6)
<syntaxhighlight lang="raku"
constant Cyr = (set
constant Hex = set 'a' .. 'f';
sub pangram($str, Set $alpha = Eng) {
$alpha ⊆ $str.lc.comb
}
Line 2,486 ⟶ 3,285:
say pangram("My dog has fleas.", Hex);
say pangram("My dog backs fleas.", Hex);
say pangram "Съешь же ещё этих мягких французских булок, да выпей чаю", Cyr;</
{{out}}
<pre>True
Line 2,495 ⟶ 3,294:
=={{header|Retro}}==
<
'__________________________ 'TEST s:const
:s:pangram? (s-f)
Line 2,502 ⟶ 3,301:
[ dup $a - &TEST + store ] s:for-each
&TEST &FULL s:eq? ;
</syntaxhighlight>
=={{header|REXX}}==
<
@abc= 'ABCDEFGHIJKLMNOPQRSTUVWXYZ' /*a list of all (Latin) capital letters*/
Line 2,518 ⟶ 3,317:
end /*forever*/
say '──────── PANGRAM program ended. ────────' /*stick a fork in it, we're all done. */</
{{out|output|:}}
<pre>
Line 2,532 ⟶ 3,331:
──────── Please enter a pangramic sentence (or a blank to quit):
◄■■■■■■■■■■ user input (null or some blanks).
──────── PANGRAM program ended. ────────
Line 2,538 ⟶ 3,337:
=={{header|Ring}}==
<
pangram = 0
s = "The quick brown fox jumps over the lazy dog."
see "" + pangram(s) + " " + s + nl
s = "My dog has fleas."
see "" + pangram(s) + " " + s + nl
func pangram str
str = lower(str)
Line 2,551 ⟶ 3,350:
bool = substr(str, char(i)) > 0
pangram = pangram + bool
next
pan = (pangram = 26)
return pan
</syntaxhighlight>
=={{header|RPL}}==
====Structurally programmed====
{| class="wikitable" ≪
! RPL code
! Comment
|-
|
≪
# 0h SWAP 1 OVER SIZE '''FOR''' j
DUP j DUP SUB NUM
'''IF''' DUP 97 ≥ OVER 122 ≤ AND '''THEN''' 32 - '''END'''
'''IF''' DUP 65 ≥ OVER 90 ≤ AND '''THEN'''
2 SWAP 65 - ^ R→B ROT OR SWAP
'''ELSE''' DROP '''END'''
'''NEXT''' DROP # 3FFFFFFh ==
≫ ‘<span style="color:blue">PANG?</span>’ STO
|
<span style="color:blue">PANG?</span> ''( "sentence" → boolean ) ''
alpha = 0; loop for j = 1 to length(sentence)
c = ascii(sentence[j])
if c lowercase then make it uppercase
if c in ("A".."Z") then
alpha &= 2^(c-65)
end loop
return alpha & 3FFFFFFh
|}
====Idiomatically optimized for HP-28S====
{| class="wikitable" ≪
! RPL code
! Comment
|-
|
≪
# 7FFFFFEh RCLF OVER NOT AND STOF SWAP
1 OVER SIZE '''FOR''' j
DUP j DUP SUB NUM
DUP 97 ≥ 95 63 IFTE - 1 MAX 28 MIN SF
'''NEXT''' DROP RCLF OVER AND ==
≫ ‘<span style="color:blue">PANG?</span>’ STO
|
<span style="color:blue">PANG?</span> ''( "sentence" → boolean ) ''
clear flags 1 to 28
loop for j = 1 to length(sentence)
c = ascii(sentence[j])
reduce c to a value between 1 and 28 and set related flag
return 1 if all flags between 2 and 27 are set
|}
To run on more recent models, the following sequence in line 2
RCLF OVER NOT AND STOF
must be replaced by
RCLF DUP 2 GET 3 PICK NOT AND 2 SWAP PUT STOF
and <code>RCLF</code> in the last line by <code>RCLF 2 GET</code>.
"The quick brown fox jumps over the lazy dog" <span style="color:blue">PANG?</span>
"The quick brown fox jumped over the lazy dog" <span style="color:blue">PANG?</span>
{{out}}
<pre>
2: 1
1: 0
</pre>
=={{header|Ruby}}==
<
('a'..'z').all? {|char| s.include? (char) }
end
p pangram?('this is a sentence') # ==> false
p pangram?('The quick brown fox jumps over the lazy dog.') # ==> true</
=={{header|Rust}}==
<
extern crate test;
Line 2,649 ⟶ 3,495:
is_pangram_hashset);
}
}</
=={{header|Scala}}==
<
</syntaxhighlight>
<
scala> is_pangram("This is a sentence")
res0: Boolean = false
Line 2,661 ⟶ 3,507:
scala> is_pangram("The quick brown fox jumps over the lazy dog")
res1: Boolean = true
</syntaxhighlight>
=={{header|Seed7}}==
<
const func boolean: isPangram (in string: stri) is func
Line 2,687 ⟶ 3,533:
writeln(isPangram("NOPQRSTUVWXYZ abcdefghijklm"));
writeln(isPangram("abcdefghijklopqrstuvwxyz")); # Missing m, n
end func;</
{{out}}
Line 2,699 ⟶ 3,545:
=={{header|Sidef}}==
{{trans|Raku}}
<
define Hex = 'a'..'f';
define Cyr = %w(а б в г д е ж з и й к л м н о п р с т у ф х ц ч ш щ ъ ы ь э ю я ё);
Line 2,712 ⟶ 3,558:
say pangram("My dog has fleas.", Hex);
say pangram("My dog backs fleas.", Hex);
say pangram("Съешь же ещё этих мягких французских булок, да выпей чаю", Cyr);</
{{out}}
<pre>
Line 2,723 ⟶ 3,569:
=={{header|Smalltalk}}==
<
isPangram
^((self collect: [:c | c asUppercase]) select: [:c | c >= $A and: [c <= $Z]]) asSet size = 26
</syntaxhighlight>
<
'The quick brown fox jumps over the lazy dog.' isPangram
</syntaxhighlight>
=={{header|SNOBOL4}}==
Line 2,738 ⟶ 3,584:
{{works with|CSnobol}}
<
pangram str = replace(str,&ucase,&lcase)
alfa = &lcase
Line 2,746 ⟶ 3,592:
define('panchk(str)tf') :(panchk_end)
panchk output = str
tf = 'False'; tf = pangram(str) 'True'
output = 'Pangram: ' tf :(return)
Line 2,755 ⟶ 3,601:
panchk("My girl wove six dozen plaid jackets before she quit.")
panchk("This 41-character string: it's a pangram!")
end</
{{out}}
Line 2,766 ⟶ 3,612:
=={{header|Swift}}==
<
let str = "the quick brown fox jumps over the lazy dog"
Line 2,781 ⟶ 3,627:
isPangram(str) // True
isPangram("Test string") // False</
Swift 2.0:
<
let (char, alph) = (Set(str.characters), "abcdefghijklmnopqrstuvwxyz".characters)
return !alph.contains {!char.contains($0)}
}</
=={{header|Tcl}}==
<
set letters [regexp -all -inline {[a-z]} [string tolower $sentence]]
expr {
Line 2,797 ⟶ 3,643:
}
puts [pangram? "This is a sentence"]; # ==> false
puts [pangram? "The quick brown fox jumps over the lazy dog."]; # ==> true</
=={{header|TI-83 BASIC}}==
<
:For(L,1,26
:If not(inString(Str1,sub("ABCDEFGHIJKLMNOPQRSTUVWXYZ",L,1))
Line 2,806 ⟶ 3,652:
:End
:If L<28
:Disp "IS A PANGRAM"</
(not tested yet)
=={{header|TUSCRIPT}}==
<
$$ MODE TUSCRIPT,{}
alfabet="abcdefghijklmnopqrstuvwxyz"
Line 2,824 ⟶ 3,670:
IF (chars_in_s!=alfabet) PRINT "no pangram: ",s
ENDLOOP
</syntaxhighlight>
{{out}}
<pre>
Line 2,832 ⟶ 3,678:
=={{header|TXR}}==
<
.*[Ee].*&.*[Ff].*&.*[Gg].*&.*[Hh].*& \
.*[Ii].*&.*[Jj].*&.*[Kk].*&.*[Ll].*& \
Line 2,838 ⟶ 3,684:
.*[Qq].*&.*[Rr].*&.*[Ss].*&.*[Tt].*& \
.*[Uu].*&.*[Vv].*&.*[Ww].*&.*[Xx].*& \
.*[Yy].*&.*[Zz].*/</
{{out|Run}}
Line 2,850 ⟶ 3,696:
=={{header|UNIX Shell}}==
{{works with|Bourne Again SHell}}
{{works with|Korn Shell}}
{{works with|Z Shell}}
<syntaxhighlight lang="bash">function is_pangram {
typeset alphabet=abcdefghijklmnopqrstuvwxyz
while [[
alphabet=${alphabet/$ch}
done
[[ -z
}</
=={{header|Ursala}}==
<syntaxhighlight lang="ursala">
#import std
is_pangram = ^jZ^(!@l,*+ @rlp -:~&) ~=`A-~ letters
</syntaxhighlight>
example usage:
<syntaxhighlight lang="ursala">
#cast %bL
test =
is_pangram* <
'The quick brown fox jumps over the lazy dog',
'this is not a pangram'>
</syntaxhighlight>
{{out}}
<pre>
Line 2,888 ⟶ 3,735:
Here is an alternative version:
<syntaxhighlight lang="vb">
Function pangram2(s As String) As Boolean
Const sKey As String = "abcdefghijklmnopqrstuvwxyz"
Dim sLow As String
Dim i As Integer
sLow = LCase(s)
For i = 1 To 26
Line 2,903 ⟶ 3,750:
pangram2 = True
End Function
</syntaxhighlight>
Invocation e.g. (typed in the Immediate window):
Line 2,913 ⟶ 3,760:
=={{header|VBScript}}==
====Implementation====
<
dim i
dim sKey
Line 2,934 ⟶ 3,781:
pangram = ( ltrim(sKey) = vbnullstring )
end function
function eef( bCond, exp1, exp2 )
if bCond then
Line 2,941 ⟶ 3,788:
eef = exp2
end if
end function</
====Invocation====
<
wscript.echo eef(pangram(""), "is a pangram", "is not a pangram")"</
=={{header|VTL-2}}==
<syntaxhighlight lang="vtl2">10 I=1
20 :I)=0
30 I=I+1
40 #=26>I*20
50 ?="Enter sentence: ";
60 C=$
70 #=C=13*120
80 C=C<97*32+C-96
90 #=C>27*60
100 :C)=1
110 #=60
120 ?=""
130 I=1
140 N=0
150 N=N+:I)
160 I=I+1
170 #=26>I*150
180 #=N=26*200
190 ?="not ";
200 ?="a pangram"</syntaxhighlight>
{{out}}
<pre>#=1
Enter sentence: The quick brown fox jumps over the lazy dog.
a pangram
OK
#=1
Enter sentence: This is not a pangram.
not a pangram
OK</pre>
=={{header|Wren}}==
{{libheader|Wren-str}}
<
var isPangram = Fn.new { |s|
Line 2,973 ⟶ 3,853:
for (candidate in candidates) {
System.print(" %(candidate) -> %(isPangram.call(candidate))")
}</
{{out}}
Line 2,987 ⟶ 3,867:
=={{header|XPL0}}==
<
string 0; \use zero-terminated strings
Line 3,017 ⟶ 3,897:
CrLf(0);
];
]</
{{out}}
Line 3,025 ⟶ 3,905:
no
</pre>
=={{header|zkl}}==
<
fcn isPangram(text){(not (letters-text.toLower()))}</
{{out}}
<pre>
|
Latest revision as of 18:16, 14 January 2024
![Task](http://static.miraheze.org/rosettacodewiki/thumb/b/ba/Rcode-button-task-crushed.png/64px-Rcode-button-task-crushed.png)
You are encouraged to solve this task according to the task description, using any language you may know.
A pangram is a sentence that contains all the letters of the English alphabet at least once.
For example: The quick brown fox jumps over the lazy dog.
- Task
Write a function or method to check a sentence to see if it is a pangram (or not) and show its use.
- Related tasks
11l
F is_pangram(sentence)
R Set(sentence.lowercase().filter(ch -> ch C ‘a’..‘z’)).len == 26
L(sentence) [‘The quick brown fox jumps over the lazy dog.’,
‘The quick brown fox jumped over the lazy dog.’]
print(‘'#.' is #.a pangram’.format(sentence, ‘not ’ * !is_pangram(sentence)))
- Output:
'The quick brown fox jumps over the lazy dog.' is a pangram 'The quick brown fox jumped over the lazy dog.' is not a pangram
360 Assembly
* Pangram RC 11/08/2015
PANGRAM CSECT
USING PANGRAM,R12
LR R12,R15
BEGIN LA R9,SENTENCE
LA R6,4
LOOPI LA R10,ALPHABET loop on sentences
LA R7,26
LOOPJ LA R5,0 loop on letters
LR R11,R9
LA R8,60
LOOPK MVC BUFFER+1(1),0(R10) loop in sentence
CLC 0(1,R10),0(R11) if alphabet[j=sentence[i]
BNE NEXTK
LA R5,1 found
NEXTK LA R11,1(R11) next character
BCT R8,LOOPK
LTR R5,R5 if found
BNZ NEXTJ
MVI BUFFER,C'?' not found
B PRINT
NEXTJ LA R10,1(R10) next letter
BCT R7,LOOPJ
MVC BUFFER(2),=CL2'OK'
PRINT MVC BUFFER+3(60),0(R9)
XPRNT BUFFER,80
NEXTI LA R9,60(R9) next sentence
BCT R6,LOOPI
RETURN XR R15,R15
BR R14
ALPHABET DC CL26'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
SENTENCE DC CL60'THE QUICK BROWN FOX JUMPS OVER THE LAZY DOG.'
DC CL60'THE FIVE BOXING WIZARDS DUMP QUICKLY.'
DC CL60'HEAVY BOXES PERFORM WALTZES AND JIGS.'
DC CL60'PACK MY BOX WITH FIVE DOZEN LIQUOR JUGS.'
BUFFER DC CL80' '
YREGS
END PANGRAM
- Output:
OK THE QUICK BROWN FOX JUMPS OVER THE LAZY DOG. ?J THE FIVE BOXING WIZARDS DUMP QUICKLY. ?C HEAVY BOXES PERFORM WALTZES AND JIGS. OK PACK MY BOX WITH FIVE DOZEN LIQUOR JUGS.
ACL2
(defun contains-each (needles haystack)
(if (endp needles)
t
(and (member (first needles) haystack)
(contains-each (rest needles) haystack))))
(defun pangramp (str)
(contains-each (coerce "abcdefghijklmnopqrstuvwxyz" 'list)
(coerce (string-downcase str) 'list)))
Action!
INCLUDE "D2:CHARTEST.ACT" ;from the Action! Tool Kit
DEFINE CHAR_COUNT="26"
BYTE FUNC IsPangram(CHAR ARRAY t)
BYTE ARRAY tab(CHAR_COUNT)
BYTE i,c
FOR i=0 TO CHAR_COUNT-1
DO tab(i)=0 OD
FOR i=1 TO t(0)
DO
c=ToLower(t(i))
IF c>='a AND c<='z THEN
tab(c-'a)=1
FI
OD
FOR i=0 TO CHAR_COUNT-1
DO
IF tab(i)=0 THEN
RETURN (0)
FI
OD
RETURN (1)
PROC Test(CHAR ARRAY t)
BYTE res
res=IsPangram(t)
PrintF("""%S"" is ",t)
IF res=0 THEN
Print("not ")
FI
PrintE("a pangram.")
PutE()
RETURN
PROC Main()
Put(125) PutE() ;clear screen
Test("The quick brown fox jumps over the lazy dog.")
Test("QwErTyUiOpAsDfGhJkLzXcVbNm")
Test("Not a pangram")
Test("")
RETURN
- Output:
Screenshot from Atari 8-bit computer
"The quick brown fox jumps over the lazy dog." is a pangram. "QwErTyUiOpAsDfGhJkLzXcVbNm" is a pangram. "Not a pangram" is not a pangram. "" is not a pangram.
ActionScript
function pangram(k:string):Boolean {
var lowerK:String = k.toLowerCase();
var has:Object = {}
for (var i:Number=0; i<=k.length-1; i++) {
has[lowerK.charAt(i)] = true;
}
var result:Boolean = true;
for (var ch:String='a'; ch <= 'z'; ch=String.fromCharCode(ch.charCodeAt(0)+1)) {
result = result && has[ch]
}
return result || false;
}
Ada
Using character sets
with Ada.Text_IO; use Ada.Text_IO;
with Ada.Strings.Maps; use Ada.Strings.Maps;
with Ada.Characters.Handling; use Ada.Characters.Handling;
procedure pangram is
function ispangram(txt: String) return Boolean is
(Is_Subset(To_Set(Span => ('a','z')), To_Set(To_Lower(txt))));
begin
put_line(Boolean'Image(ispangram("This is a test")));
put_line(Boolean'Image(ispangram("The quick brown fox jumps over the lazy dog")));
put_line(Boolean'Image(ispangram("NOPQRSTUVWXYZ abcdefghijklm")));
put_line(Boolean'Image(ispangram("abcdefghijklopqrstuvwxyz"))); --Missing m, n
end pangram;
Using quantified expressions
with Ada.Text_IO; use Ada.Text_IO;
with Ada.Characters.Handling; use Ada.Characters.Handling;
procedure pangram is
function ispangram(txt : in String) return Boolean is
(for all Letter in Character range 'a'..'z' =>
(for some Char of txt => To_Lower(Char) = Letter));
begin
put_line(Boolean'Image(ispangram("This is a test")));
put_line(Boolean'Image(ispangram("The quick brown fox jumps over the lazy dog")));
put_line(Boolean'Image(ispangram("NOPQRSTUVWXYZ abcdefghijklm")));
put_line(Boolean'Image(ispangram("abcdefghijklopqrstuvwxyz"))); --Missing m, n
end pangram;
- Output:
FALSE TRUE TRUE FALSE
ALGOL 68
# init pangram: #
INT la = ABS "a", lz = ABS "z";
INT ua = ABS "A", uz = ABS "Z";
IF lz-la+1 > bits width THEN
put(stand error, "Exception: insufficient bits in word for task");
stop
FI;
PROC is a pangram = (STRING test)BOOL: (
BITS a2z := BIN(ABS(2r1 SHL (lz-la))-1); # assume: ASCII & Binary #
FOR i TO UPB test WHILE
INT c = ABS test[i];
IF la <= c AND c <= lz THEN
a2z := a2z AND NOT(2r1 SHL (c-la))
ELIF ua <= c AND c <= uz THEN
a2z := a2z AND NOT(2r1 SHL (c-ua))
FI;
# WHILE # a2z /= 2r0 DO
SKIP
OD;
a2z = 2r0
);
main:(
[]STRING test list = (
"Big fjiords vex quick waltz nymph",
"The quick brown fox jumps over a lazy dog",
"A quick brown fox jumps over a lazy dog"
);
FOR key TO UPB test list DO
STRING test = test list[key];
IF is a pangram(test) THEN
print(("""",test,""" is a pangram!", new line))
FI
OD
)
- Output:
"Big fjiords vex quick waltz nymph" is a pangram! "The quick brown fox jumps over a lazy dog" is a pangram!
APL
a←'abcdefghijklmnopqrstuvwxyz' ⍝ or ⎕ucs 96 + ⍳26 in GNU/Dyalog
A←'ABCDEFGHIJKLMNOPQRSTUVWXYZ' ⍝ or ⎕ucs 64 + ⍳26, or just ⎕a in Dyalog
Pangram ← {∧/ ∨⌿ 2 26⍴(a,A) ∊ ⍵}
Pangram 'This should fail'
0
Pangram 'The quick brown fox jumps over the lazy dog'
1
AppleScript
AppleScriptObjC
Out of the box, AppleScript lacks many library basics – no regex, no higher order functions, not even string functions for mapping to upper or lower case.
From OSX 10.10 onwards, we can, however, use ObjC functions from AppleScript by importing the Foundation framework. We do this below to get a toLowerCase() function. If we also add generic filter and map functions, we can write and test a simple isPangram() function as follows:
use framework "Foundation" -- ( for case conversion function )
--------------------- PANGRAM CHECKER --------------------
-- isPangram :: String -> Bool
on isPangram(s)
script charUnUsed
property lowerCaseString : my toLower(s)
on |λ|(c)
lowerCaseString does not contain c
end |λ|
end script
0 = length of filter(charUnUsed, ¬
"abcdefghijklmnopqrstuvwxyz")
end isPangram
--------------------------- TEST -------------------------
on run
map(isPangram, {¬
"is this a pangram", ¬
"The quick brown fox jumps over the lazy dog"})
--> {false, true}
end run
-------------------- GENERIC FUNCTIONS -------------------
-- filter :: (a -> Bool) -> [a] -> [a]
on filter(f, xs)
tell mReturn(f)
set lst to {}
set lng to length of xs
repeat with i from 1 to lng
set v to item i of xs
if |λ|(v, i, xs) then set end of lst to v
end repeat
return lst
end tell
end filter
-- map :: (a -> b) -> [a] -> [b]
on map(f, xs)
tell mReturn(f)
set lng to length of xs
set lst to {}
repeat with i from 1 to lng
set end of lst to |λ|(item i of xs, i, xs)
end repeat
return lst
end tell
end map
-- Lift 2nd class handler function into
-- 1st class script wrapper
-- mReturn :: Handler -> Script
on mReturn(f)
if class of f is script then
f
else
script
property |λ| : f
end script
end if
end mReturn
-- toLower :: String -> String
on toLower(str)
set ca to current application
((ca's NSString's stringWithString:(str))'s ¬
lowercaseStringWithLocale:(ca's NSLocale's currentLocale())) as text
end toLower
- Output:
{false, true}
Core language
Contrary to the impression given above, AppleScript is perfectly capable of handling this task very simply and without the need for imported libraries.
on isPangram(txt)
set alphabet to "abcedfghijklmnopqrstuvwxyz"
ignoring case -- The default, but ensure it here.
repeat with letter in alphabet
if (txt does not contain letter) then return false
end repeat
end ignoring
return true
end isPangram
local result1, result2
set result1 to isPangram("The Quick Brown Fox Jumps Over The Lazy Dog")
set result2 to isPangram("This is not a pangram")
return {result1, result2}
- Output:
{true, false}
Arturo
chars: map 97..122 => [to :string to :char &]
pangram?: function [sentence][
every? chars 'ch ->
in? ch sentence
]
print pangram? "this is a sentence"
print pangram? "The quick brown fox jumps over the lazy dog."
- Output:
false true
ATS
(* ****** ****** *)
//
#include
"share/atspre_staload.hats"
#include
"share/HATS/atspre_staload_libats_ML.hats"
//
(* ****** ****** *)
//
fun
letter_check
(
cs: string, c0: char
) : bool = cs.exists()(lam(c) => c0 = c)
//
(* ****** ****** *)
fun
Pangram_check
(text: string): bool = let
//
val
alphabet = "abcdefghijklmnopqrstuvwxyz"
val
((*void*)) = assertloc(length(alphabet) = 26)
//
in
alphabet.forall()(lam(c) => letter_check(text, c) || letter_check(text, toupper(c)))
end // end of [Pangram_check]
(* ****** ****** *)
implement
main0 () =
{
//
val
text0 = "The quick brown fox jumps over the lazy dog."
//
val-true = Pangram_check(text0)
val-false = Pangram_check("This is not a pangram sentence.")
//
} (* end of [main0] *)
(* ****** ****** *)
An alternate implementation that makes a single pass through the string:
fn is_pangram{n:nat}(s: string(n)): bool = loop(s, i2sz(0)) where {
val letters: arrayref(bool, 26) = arrayref_make_elt<bool>(i2sz(26), false)
fn check(): bool = loop(0) where {
fun loop{i:int | i >= 0 && i <= 26}(i: int(i)) =
if i < 26 then
if letters[i] then loop(i+1) else
false
else true
}
fun add{c:int}(c: char(c)): void =
if (c >= 'A') * (c <= 'Z') then letters[char2int1(c) - char2int1('A')] := true else
if (c >= 'a') * (c <= 'z') then letters[char2int1(c) - char2int1('a')] := true
fun loop{i:nat | i <= n}.<n-i>.(s: string(n), i: size_t(i)): bool =
if string_is_atend(s, i) then check() else
begin
add(s[i]);
loop(s, succ(i))
end
}
AutoHotkey
Gui, -MinimizeBox
Gui, Add, Edit, w300 r5 vText
Gui, Add, Button, x105 w100 Default, Check Pangram
Gui, Show,, Pangram Checker
Return
GuiClose:
ExitApp
Return
ButtonCheckPangram:
Gui, Submit, NoHide
Loop, 26
If Not InStr(Text, Char := Chr(64 + A_Index)) {
MsgBox,, Pangram, Character %Char% is missing!
Return
}
MsgBox,, Pangram, OK`, this is a Pangram!
Return
AutoIt
Pangram("The quick brown fox jumps over the lazy dog")
Func Pangram($s_String)
For $i = 1 To 26
IF Not StringInStr($s_String, Chr(64 + $i)) Then
Return MsgBox(0,"No Pangram", "Character " & Chr(64 + $i) &" is missing")
EndIf
Next
Return MsgBox(0,"Pangram", "Sentence is a Pangram")
EndFunc
AWK
Solution using string-operations
#!/usr/bin/awk -f
BEGIN {
allChars="ABCDEFGHIJKLMNOPQRSTUVWXYZ";
print isPangram("The quick brown fox jumps over the lazy dog.");
print isPangram("The quick brown fo.");
}
function isPangram(string) {
delete X;
for (k=1; k<length(string); k++) {
X[toupper(substr(string,k,1))]++; # histogram
}
for (k=1; k<=length(allChars); k++) {
if (!X[substr(allChars,k,1)]) return 0;
}
return 1;
}
- Output:
1 0
Solution using associative arrays and split
# usage: awk -f pangram.awk -v p="The five boxing wizards dump quickly." input.txt
#
# Pangram-checker, using associative arrays and split
BEGIN {
alfa="ABCDEFGHIJKLMNOPQRSTUVWXYZ"; ac=split(alfa,A,"")
print "# Checking for all",ac,"chars in '" alfa "' :"
print testPangram("The quick brown fox jumps over the lazy dog.");
print testPangram(p);
}
{ print testPangram($0) }
function testPangram(str, c,i,S,H,hit,miss) {
print str ##
split( toupper(str), S, "")
for (c in S) {
H[ S[c] ]++
#print c, S[c], H[ S[c] ] ##
}
for (i=1; i<=ac; i++) {
c = A[i]
#printf("%2d %c : %4d\n", i, c, H[c] ) ##
if (H[c]) { hit=hit c } else { miss=miss c }
}
print "# hit:",hit, "# miss:",miss, "." ##
if (miss) return 0
return 1
}
- Output:
# Checking for all 26 chars in 'ABCDEFGHIJKLMNOPQRSTUVWXYZ' : The quick brown fox jumps over the lazy dog. # hit: ABCDEFGHIJKLMNOPQRSTUVWXYZ # miss: . 1 The five boxing wizards dump quickly. # hit: ABCDEFGHIKLMNOPQRSTUVWXYZ # miss: J . 0 Heavy boxes perform waltzes and jigs # hit: ABDEFGHIJLMNOPRSTVWXYZ # miss: CKQU . 0 The quick onyx goblin jumps over the lazy dwarf. # hit: ABCDEFGHIJKLMNOPQRSTUVWXYZ # miss: . 1 Pack my box with five dozen liquor jugs # hit: ABCDEFGHIJKLMNOPQRSTUVWXYZ # miss: . 1
BASIC
Applesoft BASIC
100 P$ = "11111111111111111111111111"
110 FOR Q = 1 TO 3
120 READ S$
130 GOSUB 200"IS PANGRAM?
140 PRINT MID$ ("NO YES ",P * 4 + 1,4)S$
150 NEXT Q
160 END
170 DATA"THE QUICK BROWN FOX JUMPS OVER THE LAZY DOG."
180 DATA"THE QUICK BROWN FOX JUMPED OVER THE LAZY DOG."
190 DATA"THE FIVE BOXING WIZARDS JUMP QUICKLY."
200 P = 0:L = LEN (S$): IF NOT L THEN RETURN
210 F$ = "00000000000000000000000000"
220 FOR I = 1 TO L
230 C = ASC ( MID$ (S$,I,1)):C = C - 32 * (C > 95): IF C > 64 AND C < 91 THEN J = C - 64:F$ = MID$ (F$,1,J - 1) + "1" + MID$ (F$,J + 1):P = F$ = P$: IF P THEN RETURN
240 NEXT I
250 RETURN
- Output:
YES THE QUICK BROWN FOX JUMPS OVER THE LAZY DOG. NO THE QUICK BROWN FOX JUMPED OVER THE LAZY DOG. YES THE FIVE BOXING WIZARDS JUMP QUICKLY.
BaCon
This can be done in a one-liner.
DEF FN Pangram(x) = IIF(AMOUNT(UNIQ$(EXPLODE$(EXTRACT$(LCASE$(x), "[^[:alpha:]]", TRUE), 1))) = 26, TRUE, FALSE)
PRINT Pangram("The quick brown fox jumps over the lazy dog.")
PRINT Pangram("Jackdaws love my big sphinx of quartz.")
PRINT Pangram("My dog has fleas.")
PRINT Pangram("What's a jackdaw?")
PRINT Pangram("The five boxing wizards jump quickly")
- Output:
1 1 0 0 1
BASIC256
function isPangram$(texto$)
longitud = Length(texto$)
if longitud < 26 then return "is not a pangram"
t$ = lower(texto$)
print "'"; texto$; "' ";
for i = 97 to 122
if instr(t$, chr(i)) = 0 then return "is not a pangram"
next i
return "is a pangram"
end function
print isPangram$("The quick brown fox jumps over the lazy dog.") # --> true
print isPangram$("The quick brown fox jumped over the lazy dog.") # --> false
print isPangram$("ABC.D.E.FGHI*J/KL-M+NO*PQ R\nSTUVWXYZ") # --> true
BBC BASIC
FOR test% = 1 TO 2
READ test$
PRINT """" test$ """ " ;
IF FNpangram(test$) THEN
PRINT "is a pangram"
ELSE
PRINT "is not a pangram"
ENDIF
NEXT test%
END
DATA "The quick brown fox jumped over the lazy dog"
DATA "The five boxing wizards jump quickly"
DEF FNpangram(A$)
LOCAL C%
A$ = FNlower(A$)
FOR C% = ASC("a") TO ASC("z")
IF INSTR(A$, CHR$(C%)) = 0 THEN = FALSE
NEXT
= TRUE
DEF FNlower(A$)
LOCAL A%, C%
FOR A% = 1 TO LEN(A$)
C% = ASCMID$(A$,A%)
IF C% >= 65 IF C% <= 90 MID$(A$,A%,1) = CHR$(C%+32)
NEXT
= A$
- Output:
"The quick brown fox jumped over the lazy dog" is not a pangram "The five boxing wizards jump quickly" is a pangram
String manipulation is expensive, especially in loops, so it may be better to buffer the string and use character values:
DEFFNisPangram(text$) LOCAL size%,text%,char%,bits% size%=LENtext$ IF size%<27 THEN =FALSE:REM too few characters DIM text% LOCAL size%:REM BB4W and RISC OS 5 only $text%=text$:REM buffer the string FOR text%=text% TO text%+size%-1:REM each character char%=?text% OR 32:REM to lower case IF 96<char% AND char%<123 THEN bits%=bits% OR 1<<(char%-97):REM set ordinal bit IF bits%=&3FFFFFF THEN =TRUE:REM all ordinal bits set NEXT text% =FALSE
Commodore BASIC
10 rem detect model for title display
20 mx=peek(213): if mx=21 or mx=39 or mx=79 then 50:rem pet, vic, c64
30 mx=peek(238): if mx=39 or mx=79 then 50: rem c128
40 mx=39:color 4,1:rem assume plus/4 or c-16
50 if mx=21 then poke 36879,30:rem fix color on vic-20
60 print chr$(147);chr$(14);chr$(18);"**";:for i=2 to (mx-15)/2:print " ";:next
70 print "Pangram Checker";
80 for i=(mx-15)/2+16 to mx-2: print " ";: next: print "**"
100 read s$
110 if len(s$)=0 then end
120 gosub 1000:print
130 print "'"s$"' is";
140 if p=0 then print " not";
150 print " a pangram."
160 goto 100
500 data "The quick brown fox jumps over the lazy dog."
510 data "The quick brown fox jumped over the lazy dog."
520 data "The five boxing wizards jump quickly."
530 data
900 rem pangram checker
1000 if f=0 then f=1:dim seen(25),a(2):a(0)=65:a(1)=97:a(2)=193:goto 1020
1010 for i=0 to 25:seen(i)=0:next
1020 for i=1 to len(s$)
1030 : c=asc(mid$(s$,i))
1040 : for a = 0 to 2
1050 : if c>=a(a) and c<=a(a)+25 then seen(c-a(a))=seen(c-a(a))+1
1060 : next a
1070 next i
1080 p=-1
1090 for i=0 to 25
1100 : if seen(i)=0 then p=0:i=25
1110 next i
1120 return
- Output:
** Pangram Checker ** 'The quick brown fox jumps over the lazy dog.' is a pangram. 'The quick brown fox jumped over the lazy dog.' is not a pangram. 'The five boxing wizards jump quickly.' is a pangram. ready.
Chipmunk Basic
The Applesoft BASIC solution works without any changes.
FreeBASIC
' FB 1.05.0 Win64
Function isPangram(s As Const String) As Boolean
Dim As Integer length = Len(s)
If length < 26 Then Return False
Dim p As String = LCase(s)
For i As Integer = 97 To 122
If Instr(p, Chr(i)) = 0 Then Return False
Next
Return True
End Function
Dim s(1 To 3) As String = _
{ _
"The quick brown fox jumps over the lazy dog", _
"abbdefghijklmnopqrstuVwxYz", _ '' no c!
"How vexingly quick daft zebras jump!" _
}
For i As Integer = 1 To 3:
Print "'"; s(i); "' is "; IIf(isPangram(s(i)), "a", "not a"); " pangram"
Print
Next
Print
Print "Press nay key to quit"
Sleep
- Output:
'The quick brown fox jumps over the lazy dog' is a pangram 'abbdefghijklmnopqrstuVwxYz' is not a pangram 'How vexingly quick daft zebras jump!' is a pangram
Liberty BASIC
'Returns 0 if the string is NOT a pangram or >0 if it IS a pangram
string$ = "The quick brown fox jumps over the lazy dog."
Print isPangram(string$)
Function isPangram(string$)
string$ = Lower$(string$)
For i = Asc("a") To Asc("z")
isPangram = Instr(string$, chr$(i))
If isPangram = 0 Then Exit Function
Next i
End Function
PureBasic
Procedure IsPangram_fast(String$)
String$ = LCase(string$)
char_a=Asc("a")
; sets bits in a variable if a letter is found, reads string only once
For a = 1 To Len(string$)
char$ = Mid(String$, a, 1)
pos = Asc(char$) - char_a
check.l | 1 << pos
Next
If check & $3FFFFFF = $3FFFFFF
ProcedureReturn 1
EndIf
ProcedureReturn 0
EndProcedure
Procedure IsPangram_simple(String$)
String$ = LCase(string$)
found = 1
For a = Asc("a") To Asc("z")
; searches for every letter in whole string
If FindString(String$, Chr(a), 0) = 0
found = 0
EndIf
Next
ProcedureReturn found
EndProcedure
Debug IsPangram_fast("The quick brown fox jumps over lazy dogs.")
Debug IsPangram_simple("The quick brown fox jumps over lazy dogs.")
Debug IsPangram_fast("No pangram")
Debug IsPangram_simple("No pangram")
QBasic
DECLARE FUNCTION IsPangram! (sentence AS STRING)
DIM x AS STRING
x = "My dog has fleas."
GOSUB doIt
x = "The lazy dog jumps over the quick brown fox."
GOSUB doIt
x = "Jackdaws love my big sphinx of quartz."
GOSUB doIt
x = "What's a jackdaw?"
GOSUB doIt
END
doIt:
PRINT IsPangram!(x), x
RETURN
FUNCTION IsPangram! (sentence AS STRING)
'returns -1 (true) if sentence is a pangram, 0 (false) otherwise
DIM l AS INTEGER, s AS STRING, t AS INTEGER
DIM letters(25) AS INTEGER
FOR l = 1 TO LEN(sentence)
s = UCASE$(MID$(sentence, l, 1))
SELECT CASE s
CASE "A" TO "Z"
t = ASC(s) - 65
letters(t) = 1
END SELECT
NEXT
FOR l = 0 TO 25
IF letters(l) < 1 THEN
IsPangram! = 0
EXIT FUNCTION
END IF
NEXT
IsPangram! = -1
END FUNCTION
- Output:
0 My dog has fleas. -1 The quick brown fox jumps over the lazy dog. -1 Jackdaws love my big sphinx of quartz. 0 What's a jackdaw?
Run BASIC
s$ = "The quick brown fox jumps over the lazy dog."
Print pangram(s$);" ";s$
s$ = "My dog has fleas."
Print pangram(s$);" ";s$
function pangram(str$)
str$ = lower$(str$)
for i = asc("a") to asc("z")
pangram = pangram + (instr(str$, chr$(i)) <> 0)
next i
pangram = (pangram = 26)
end function
1 The quick brown fox jumps over the lazy dog. 0 My dog has fleas.
Sinclair ZX81 BASIC
Works (just) with the 1k RAM model. The "37" that crops up a couple of times stops being a mystery if we remember that the ZX81 character code for A
is 38 and that strings (like arrays) are indexed from 1, not from 0.
10 LET A$="ABCDEFGHIJKLMNOPQRSTUVWXYZ"
20 LET L=26
30 INPUT P$
40 IF LEN P$<26 THEN GOTO 170
50 FAST
60 LET C=1
70 IF P$(C)<"A" OR P$(C)>"Z" THEN GOTO 120
80 IF A$(CODE P$(C)-37)=" " THEN GOTO 120
90 LET A$(CODE P$(C)-37)=" "
100 LET L=L-1
110 IF L=0 THEN GOTO 150
120 IF C=LEN P$ THEN GOTO 170
130 LET C=C+1
140 GOTO 70
150 PRINT "PANGRAM"
160 GOTO 180
170 PRINT "NOT A PANGRAM"
180 SLOW
- Input:
THE QUICK BROWN FOX JUMPS OVER THE LAZY DOG.
- Output:
PANGRAM
- Input:
AND DARK THE SUN AND MOON, AND THE ALMANACH DE GOTHA
- Output:
NOT A PANGRAM
uBasic/4tH
Proc _ShowPangram ("The quick brown fox jumps over the lazy dog.")
Proc _ShowPangram ("QwErTyUiOpAsDfGhJkLzXcVbNm")
Proc _ShowPangram ("Not a pangram")
End
_ShowPangram ' demonstrate the Pangram() function
Param (1)
Print Show (a@);Tab (50);Show (Iif (FUNC(_Pangram (a@)), "A pangram", "Not a pangram"))
Return
_Pangram
Param (1) ' pangram candidate
Local (3)
b@ = 0 ' reset the bitmap
For d@ = 0 To Len(a@) -1 ' parse the string
c@ = Peek (a@, d@) ' get current character
If (c@ > Ord ("A") - 1) * (c@ < Ord ("Z") + 1) Then c@ = c@ + 32
If (c@ > Ord ("a") - 1) * (c@ < Ord ("z") + 1) Then b@ = OR(b@, 2^(c@ - Ord ("a")))
Next ' update the bitmap
Return (b@ = 67108863) ' all bits set?
- Output:
The quick brown fox jumps over the lazy dog. A pangram QwErTyUiOpAsDfGhJkLzXcVbNm A pangram Not a pangram Not a pangram 0 OK, 0:156
Yabasic
sub isPangram$(t$, l1$)
local lt, ll, r$, i, cc, ic
if numparams = 1 then
l1$ = "abcdefghijklmnopqrstuvwxyz"
end if
t$ = lower$(t$)
ll = len(l1$)
for i = 1 to ll
r$ = r$ + " "
next
lt = len(t$)
cc = asc("a")
for i = 1 to lt
ic = asc(mid$(t$, i, 1)) - cc + 1
if ic > 0 and ic <= ll then
mid$(r$, ic, 1) = chr$(ic + cc - 1)
end if
next i
if l1$ = r$ then return "true" else return "false" end if
end sub
print isPangram$("The quick brown fox jumps over the lazy dog.") // --> true
print isPangram$("The quick brown fox jumped over the lazy dog.") // --> false
print isPangram$("ABC.D.E.FGHI*J/KL-M+NO*PQ R\nSTUVWXYZ") // --> true
Batch File
@echo off
setlocal enabledelayedexpansion
%===The Main Thing===%
call :pangram "The quick brown fox jumps over the lazy dog."
call :pangram "The quick brown fox jumped over the lazy dog."
echo.
pause
exit /b 0
%===The Function===%
:pangram
set letters=abcdefgihjklmnopqrstuvwxyz
set cnt=0
set inp=%~1
set str=!inp: =!
:loop
set chr=!str:~%cnt%,1!
if "!letters!"=="" (
echo %1 is a pangram^^!
goto :EOF
)
if "!chr!"=="" (
echo %1 is not a pangram.
goto :EOF
)
set letters=!letters:%chr%=!
set /a cnt+=1
goto loop
- Output:
"The quick brown fox jumps over the lazy dog." is a pangram! "The quick brown fox jumped over the lazy dog." is not a pangram. Press any key to continue . . .
BCPL
get "libhdr"
// Test if s is a pangram. The ASCII character set is assumed.
let pangram(s) = valof
$( let letters = vec 25
for i=0 to 25 do letters!i := false
for i=1 to s%0 do
$( let c = (s%i | 32) - 'a'
if c >= 0 & c < 26 then
letters!c := true
$)
for i=0 to 25 unless letters!i resultis false
resultis true
$)
// Display s and whether or not it is a pangram.
let check(s) be
$( writes(s)
writes(" -> ")
test pangram(s)
then writes("yes*N")
else writes("no*N")
$)
let start() be
$( check("The quick brown fox jumps over the lazy dog.")
check("The five boxing wizards dump quickly.")
$)
- Output:
The quick brown fox jumps over the lazy dog. -> yes The five boxing wizards dump quickly. -> no
Befunge
Reads the sentence to test from stdin.
>~>:65*`!#v_:"`"`48*v>g+04p1\4p
^#*`\*93\`0<::-"@"-*<^40!%2g4:_
"pangram."<v*84<_v#-":"g40\" a"
>>:#,_55+,@>"ton">48*>"si tahT"
- Input:
The quick brown fox jumps over the lazy dog.
- Output:
That is a pangram.
Bracmat
(isPangram=
k
. low$!arg:?arg
& a:?k
& whl
' ( @(!arg:? !k ?)
& chr$(1+asc$!k):?k:~>z
)
& !k:>z
&
);
Some examples:
isPangram$("the Quick brown FOX jumps over the lazy do") no isPangram$("the Quick brown FOX jumps over the lazy dog") yes isPangram$"My dog has fleas." no isPangram$"The quick brown fox jumps over the lazy dog." yes isPangram$"Jackdaws love my big sphinx of quartz." yes isPangram$"What's a jackdaw?" no isPangram$"Lynx c.q. vos prikt bh: dag zwemjuf!" yes
Brat
pangram? = { sentence |
letters = [:a :b :c :d :e :f :g :h :i :j :k :l :m
:n :o :p :q :r :s :t :u :v :w :x :y :z]
sentence.downcase!
letters.reject! { l |
sentence.include? l
}
letters.empty?
}
p pangram? 'The quick brown fox jumps over the lazy dog.' #Prints true
p pangram? 'Probably not a pangram.' #Prints false
Alternative version:
pangram? = { sentence |
sentence.downcase.dice.unique.select(:alpha?).length == 26
}
C
#include <stdio.h>
int is_pangram(const char *s)
{
const char *alpha = ""
"abcdefghjiklmnopqrstuvwxyz"
"ABCDEFGHIJKLMNOPQRSTUVWXYZ";
char ch, wasused[26] = {0};
int total = 0;
while ((ch = *s++) != '\0') {
const char *p;
int idx;
if ((p = strchr(alpha, ch)) == NULL)
continue;
idx = (p - alpha) % 26;
total += !wasused[idx];
wasused[idx] = 1;
if (total == 26)
return 1;
}
return 0;
}
int main(void)
{
int i;
const char *tests[] = {
"The quick brown fox jumps over the lazy dog.",
"The qu1ck brown fox jumps over the lazy d0g."
};
for (i = 0; i < 2; i++)
printf("\"%s\" is %sa pangram\n",
tests[i], is_pangram(tests[i])?"":"not ");
return 0;
}
Using bitmask
Assumes an execution environment using the ASCII character set (will invoke undefined behavior on other systems).
#include <stdio.h>
int pangram(const char *s)
{
int c, mask = (1 << 26) - 1;
while ((c = (*s++)) != '\0') /* 0x20 converts lowercase to upper */
if ((c &= ~0x20) <= 'Z' && c >= 'A')
mask &= ~(1 << (c - 'A'));
return !mask;
}
int main()
{
int i;
const char *s[] = { "The quick brown fox jumps over lazy dogs.",
"The five boxing wizards dump quickly.", };
for (i = 0; i < 2; i++)
printf("%s: %s\n", pangram(s[i]) ? "yes" : "no ", s[i]);
return 0;
}
- Output:
yes: The quick brown fox jumps over lazy dogs. no : The five boxing wizards dump quickly.
C#
C# 3.0 or higher (.NET Framework 3.5 or higher)
using System;
using System.Linq;
static class Program
{
static bool IsPangram(this string text, string alphabet = "abcdefghijklmnopqrstuvwxyz")
{
return alphabet.All(text.ToLower().Contains);
}
static void Main(string[] arguments)
{
Console.WriteLine(arguments.Any() && arguments.First().IsPangram());
}
}
Any version of C# language and .NET Framework
using System;
namespace PangrammChecker
{
public class PangrammChecker
{
public static bool IsPangram(string str)
{
bool[] isUsed = new bool[26];
int ai = (int)'a';
int total = 0;
for (CharEnumerator en = str.ToLower().GetEnumerator(); en.MoveNext(); )
{
int d = (int)en.Current - ai;
if (d >= 0 && d < 26)
if (!isUsed[d])
{
isUsed[d] = true;
total++;
}
}
return (total == 26);
}
}
class Program
{
static void Main(string[] args)
{
string str1 = "The quick brown fox jumps over the lazy dog.";
string str2 = "The qu1ck brown fox jumps over the lazy d0g.";
Console.WriteLine("{0} is {1}a pangram", str1,
PangrammChecker.IsPangram(str1)?"":"not ");
Console.WriteLine("{0} is {1}a pangram", str2,
PangrammChecker.IsPangram(str2)?"":"not ");
Console.WriteLine("Press Return to exit");
Console.ReadLine();
}
}
}
C++
#include <algorithm>
#include <cctype>
#include <string>
#include <iostream>
const std::string alphabet("abcdefghijklmnopqrstuvwxyz");
bool is_pangram(std::string s)
{
std::transform(s.begin(), s.end(), s.begin(), ::tolower);
std::sort(s.begin(), s.end());
return std::includes(s.begin(), s.end(), alphabet.begin(), alphabet.end());
}
int main()
{
const auto examples = {"The quick brown fox jumps over the lazy dog",
"The quick white cat jumps over the lazy dog"};
std::cout.setf(std::ios::boolalpha);
for (auto& text : examples) {
std::cout << "Is \"" << text << "\" a pangram? - " << is_pangram(text) << std::endl;
}
}
Ceylon
shared void run() {
function pangram(String sentence) =>
let(alphabet = set('a'..'z'),
letters = set(sentence.lowercased.filter(alphabet.contains)))
letters == alphabet;
value sentences = [
"The quick brown fox jumps over the lazy dog",
"""Watch "Jeopardy!", Alex Trebek's fun TV quiz game.""",
"Pack my box with five dozen liquor jugs.",
"blah blah blah"
];
for(sentence in sentences) {
print("\"``sentence``\" is a pangram? ``pangram(sentence)``");
}
}
Clojure
(defn pangram? [s]
(let [letters (into #{} "abcdefghijklmnopqrstuvwxyz")]
(= (->> s .toLowerCase (filter letters) (into #{})) letters)))
CLU
pangram = proc (s: string) returns (bool)
letters: array[bool] := array[bool]$fill(0,26,false)
for c: char in string$chars(s) do
if c>='a' & c<='z' then
c := char$i2c(char$c2i(c) - 32)
end
if c>='A' & c<='Z' then
letters[char$c2i(c) - 65] := true
end
end
for seen: bool in array[bool]$elements(letters) do
if ~seen then return(false) end
end
return(true)
end pangram
start_up = proc ()
po: stream := stream$primary_output()
examples: array[string] := array[string]$[
"The quick brown fox jumps over the lazy dog.",
"The five boxing wizards dump quickly.",
"abcdefghijklmnopqrstuvwxyz"
]
for example: string in array[string]$elements(examples) do
stream$puts(po, "\"" || example || "\" is")
if ~pangram(example) then
stream$puts(po, " not")
end
stream$putl(po, " a pangram.")
end
end start_up
- Output:
"The quick brown fox jumps over the lazy dog." is a pangram. "The five boxing wizards dump quickly." is not a pangram. "abcdefghijklmnopqrstuvwxyz" is a pangram.
COBOL
identification division.
program-id. pan-test.
data division.
working-storage section.
1 text-string pic x(80).
1 len binary pic 9(4).
1 trailing-spaces binary pic 9(4).
1 pangram-flag pic x value "n".
88 is-not-pangram value "n".
88 is-pangram value "y".
procedure division.
begin.
display "Enter text string:"
accept text-string
set is-not-pangram to true
initialize trailing-spaces len
inspect function reverse (text-string)
tallying trailing-spaces for leading space
len for characters after space
call "pangram" using pangram-flag len text-string
cancel "pangram"
if is-pangram
display "is a pangram"
else
display "is not a pangram"
end-if
stop run
.
end program pan-test.
identification division.
program-id. pangram.
data division.
1 lc-alphabet pic x(26) value "abcdefghijklmnopqrstuvwxyz".
linkage section.
1 pangram-flag pic x.
88 is-not-pangram value "n".
88 is-pangram value "y".
1 len binary pic 9(4).
1 text-string pic x(80).
procedure division using pangram-flag len text-string.
begin.
inspect lc-alphabet converting
function lower-case (text-string (1:len))
to space
if lc-alphabet = space
set is-pangram to true
end-if
exit program
.
end program pangram.
CoffeeScript
is_pangram = (s) ->
# This is optimized for longish strings--as soon as all 26 letters
# are encountered, we will be done. Our worst case scenario is a really
# long non-pangram, or a really long pangram with at least one letter
# only appearing toward the end of the string.
a_code = 'a'.charCodeAt(0)
required_letters = {}
for i in [a_code...a_code+26]
required_letters[String.fromCharCode(i)] = true
cnt = 0
for c in s
c = c.toLowerCase()
if required_letters[c]
cnt += 1
return true if cnt == 26
delete required_letters[c]
false
do ->
tests = [
["is this a pangram", false]
["The quick brown fox jumps over the lazy dog", true]
]
for test in tests
[s, exp_value] = test
throw Error("fail") if is_pangram(s) != exp_value
# try long strings
long_str = ''
for i in [1..500000]
long_str += s
throw Error("fail") if is_pangram(long_str) != exp_value
console.log "Passed tests: #{s}"
Comal
0010 FUNC pangram#(s$) CLOSED
0020 FOR i#:=ORD("A") TO ORD("Z") DO
0030 IF NOT (CHR$(i#) IN s$ OR CHR$(i#+32) IN s$) THEN RETURN FALSE
0040 ENDFOR i#
0050 RETURN TRUE
0060 ENDFUNC
0070 //
0080 WHILE NOT EOD DO
0090 READ s$
0100 PRINT "'",s$,"' is ",
0110 IF NOT pangram#(s$) THEN PRINT "not ",
0120 PRINT "a pangram"
0130 ENDWHILE
0140 END
0150 DATA "The quick brown fox jumps over the lazy dog."
0160 DATA "The five boxing wizards dump quickly."
- Output:
'The quick brown fox jumps over the lazy dog.' is a pangram 'The five boxing wizards dump quickly.' is not a pangram
Common Lisp
(defun pangramp (s)
(null (set-difference
(loop for c from (char-code #\A) upto (char-code #\Z) collect (code-char c))
(coerce (string-upcase s) 'list))))
Component Pascal
BlackBox Component Builder
MODULE BbtPangramChecker;
IMPORT StdLog,DevCommanders,TextMappers;
PROCEDURE Check(str: ARRAY OF CHAR): BOOLEAN;
CONST
letters = 26;
VAR
i,j: INTEGER;
status: ARRAY letters OF BOOLEAN;
resp : BOOLEAN;
BEGIN
FOR i := 0 TO LEN(status) -1 DO status[i] := FALSE END;
FOR i := 0 TO LEN(str) - 1 DO
j := ORD(CAP(str[i])) - ORD('A');
IF (0 <= j) & (25 >= j) & ~status[j] THEN status[j] := TRUE END
END;
resp := TRUE;
FOR i := 0 TO LEN(status) - 1 DO;
resp := resp & status[i]
END;
RETURN resp;
END Check;
PROCEDURE Do*;
VAR
params: DevCommanders.Par;
s: TextMappers.Scanner;
BEGIN
params := DevCommanders.par;
s.ConnectTo(params.text);
s.SetPos(params.beg);
s.Scan;
WHILE (~s.rider.eot) DO
IF (s.type = TextMappers.char) & (s.char = '~') THEN
RETURN
ELSIF (s.type # TextMappers.string) THEN
StdLog.String("Invalid parameter");StdLog.Ln
ELSE
StdLog.Char("'");StdLog.String(s.string + "' is pangram?:> ");
StdLog.Bool(Check(s.string));StdLog.Ln
END;
s.Scan
END
END Do;
END BbtPangramChecker.
Execute: ^Q BbtPangramChecker.Do "The quick brown fox jumps over the lazy dog"~
^Q BbtPangramChecker.Do "abcdefghijklmnopqrstuvwxyz"~
^Q BbtPangramChecker.Do "A simple text"~
- Output:
'The quick brown fox jumps over the lazy dog' is pangram?:> $TRUE 'abcdefghijklmnopqrstuvwxyz' is pangram?:> $TRUE 'A simple text' is pangram?:> $FALSE
Cowgol
include "cowgol.coh";
sub pangram(str: [uint8]): (r: uint8) is
var letters: uint8[26];
MemZero(&letters[0], 26);
loop
var chr := [str];
if chr == 0 then break; end if;
str := @next str;
chr := (chr | 32) - 'a';
if chr >= 26 then continue; end if;
letters[chr] := letters[chr] | 1;
end loop;
r := 1;
chr := 0;
while chr < 26 loop
r := r & letters[chr];
if r == 0 then break; end if;
chr := chr + 1;
end loop;
end sub;
var yesno: [uint8][] := {": no\n", ": yes\n"};
var test: [uint8][] := {
"The quick brown fox jumps over the lazy dog.",
"The five boxing wizards dump quickly."
};
var i: @indexof test := 0;
while i < @sizeof test loop
print(test[i]);
print(yesno[pangram(test[i])]);
i := i + 1;
end loop;
- Output:
The quick brown fox jumps over the lazy dog.: yes The five boxing wizards dump quickly.: no
Crystal
Copied and modified from the Ruby version.
def pangram?(sentence)
('a'..'z').all? {|c| sentence.downcase.includes?(c) }
end
p pangram?("not a pangram")
p pangram?("The quick brown fox jumps over the lazy dog.")
false true
D
ASCII Bitmask version
bool isPangram(in string text) pure nothrow @safe @nogc {
uint bitset;
foreach (immutable c; text) {
if (c >= 'a' && c <= 'z')
bitset |= (1u << (c - 'a'));
else if (c >= 'A' && c <= 'Z')
bitset |= (1u << (c - 'A'));
}
return bitset == 0b11_11111111_11111111_11111111;
}
void main() {
assert("the quick brown fox jumps over the lazy dog".isPangram);
assert(!"ABCDEFGHIJKLMNOPQSTUVWXYZ".isPangram);
assert(!"ABCDEFGHIJKL.NOPQRSTUVWXYZ".isPangram);
assert("ABC.D.E.FGHI*J/KL-M+NO*PQ R\nSTUVWXYZ".isPangram);
}
Unicode version
import std.string, std.traits, std.uni;
// Do not compile with -g (debug info).
enum Alphabet : dstring {
DE = "abcdefghijklmnopqrstuvwxyzßäöü",
EN = "abcdefghijklmnopqrstuvwxyz",
SV = "abcdefghijklmnopqrstuvwxyzåäö"
}
bool isPangram(S)(in S s, dstring alpha = Alphabet.EN)
pure /*nothrow*/ if (isSomeString!S) {
foreach (dchar c; alpha)
if (indexOf(s, c) == -1 && indexOf(s, std.uni.toUpper(c)) == -1)
return false;
return true;
}
void main() {
assert(isPangram("the quick brown fox jumps over the lazy dog".dup, Alphabet.EN));
assert(isPangram("Falsches Üben von Xylophonmusik quält jeden größeren Zwerg"d, Alphabet.DE));
assert(isPangram("Yxskaftbud, ge vår wczonmö iqhjälp"w, Alphabet.SV));
}
Delphi
program PangramChecker;
{$APPTYPE CONSOLE}
uses StrUtils;
function IsPangram(const aString: string): Boolean;
var
c: char;
begin
for c := 'a' to 'z' do
if not ContainsText(aString, c) then
Exit(False);
Result := True;
end;
begin
Writeln(IsPangram('The quick brown fox jumps over the lazy dog')); // true
Writeln(IsPangram('Not a panagram')); // false
end.
Draco
proc nonrec pangram(*char s) bool:
ulong letters;
char c;
byte b;
byte A = pretend('a', byte);
byte Z = pretend('z', byte);
letters := 0L0;
while
c := s*;
s := s + 1;
c /= '\e'
do
b := pretend(c, byte) | 32;
if b >= A and b <= Z then
letters := letters | 0L1 << (b-A)
fi
od;
letters = 0x3FFFFFF
corp
proc nonrec test(*char s) void:
writeln("\"", s, "\": ",
if pangram(s) then "yes" else "no" fi)
corp
proc nonrec main() void:
test("The quick brown fox jumps over the lazy dog.");
test("The five boxing wizards jump quickly.");
test("Not a pangram")
corp
- Output:
"The quick brown fox jumps over the lazy dog.": yes "The five boxing wizards jump quickly.": yes "Not a pangram": no
E
def isPangram(sentence :String) {
return ("abcdefghijklmnopqrstuvwxyz".asSet() &! sentence.toLowerCase().asSet()).size() == 0
}
&!
is the “but-not” or set difference operator.
EasyLang
func pangr s$ .
len d[] 26
for c$ in strchars s$
c = strcode c$
if c >= 97 and c <= 122
c -= 32
.
if c >= 65 and c <= 91
d[c - 64] = 1
.
.
for h in d[]
s += h
.
return s
.
repeat
s$ = input
until s$ = ""
print s$
if pangr s$ = 26
print " --> pangram"
.
print ""
.
input_data
This is a test.
The quick brown fox jumps over the lazy dog.
The quick brown fox jumped over the lazy dog.
QwErTyUiOpAsDfGhJkLzXcVbNm
EDSAC order code
The program includes a test string (at the end). If the program is running in the EdsacPC simulator, the user can enter another string by storing it in a text file, making that file the active file, and clicking Reset. The string must be terminated by a blank row of tape (represented by '.' in EdsacPC).
[Pangram checker for Rosetta Code.
EDSAC program, Initial Orders 2.]
[Outline: Make a table, one entry per 5-bit character code.
Initialize entry for each letter to 1.
When a letter is read, convert its entry to 0.]
[Subroutine to read string from the input and
store it with character codes in low 5 bits.
String is terminated by blank row of tape, which is stored.
Input: 0F holds address of string in address field (bits 1..11).
21 locations; workspace: 4F]
T 56 K
GKA3FT17@AFA18@T7@I4FA4FUFS19@G12@S20@G16@T4FA7@A2FE4@T4FEFUFP8FPD
[*************** Rosetta Code task ***************
Subroutine to test whether string is a pangram.
Input: 0F = address of string, characters in low 5 bits,
terminated by blank row of tape.
Output: 1F = (number of missing letters) - 1.
87 memory locations; workspace 4F.]
T 88 K
G K
A 3 F [make and plant link for return]
T 48 @
[Fill letter table with 1's.
The code is a bit neater if we work backwards.]
A 54 @ [index of last entry]
[3] A 51 @ [make T order for table entry]
T 6 @ [plant in code]
A 53 @ [acc := 1]
[6] T F [table entry := 1]
A 6 @ [dec address in table]
S 2 F
S 51 @ [finished table?]
E 3 @ [loop back if not]
[Set non-letters to 0, except blank row := -1]
T 4 F [clear acc]
T 66 @ [figures shift]
T 70 @ [letters shift]
T 73 @ [carriage return]
T 75 @ [space]
T 79 @ [line feed]
S 53 @ [acc := -1]
T 71 @ [blank row of tape]
[Loop to read characters from string.
Terminated by blank row of tape.
Assume acc = 0 here.]
A F [load address of string]
A 49 @ [make order to read first char]
[21] T 22 @ [plant in code]
[22] A F [char to acc]
L D [shift to address field]
A 50 @ [make A order for this char in table]
U 28 @ [plant in code]
A 52 @ [convert to T order]
T 31 @ [plant in code]
[28] A F [load table entry]
G 35 @ [jump out if it's -1, i.e. blank row]
T 4 F [clear acc]
[31] T F [table entry := 0 to flag that letter is present]
A 22 @ [inc address in input string]
A 2 F
G 21 @ [back to read next char]
[Get total of table entries, again working backwards.
The number of missing letters is (total + 1).]
[35] T 4 F [clear acc]
T 1 F [initialize total := 0]
A 54 @ [index of last entry]
[38] A 50 @ [make A order for table entry]
T 41 @ [plant in code]
A 1 F [load total so far]
[41] A F [add table entry]
T 1 F [update total]
A 41 @ [load A order]
S 2 F [dec address]
S 50 @ [finished table?]
E 38 @ [loop back if not]
T 4 F [clear acc before exit]
[48] E F
[Constants]
[49] A F [to make A order referring to input]
[50] A 55 @ [to make A order referring to table]
[51] T 55 @ [to make T order referring to table]
[52] O F [add to A order to convert to T order]
[53] P D [constant 1]
[54] P 31 F [to change address by 31]
[Table]
[55] PFPFPFPFPFPFPFPFPFPFPF
[66] PFPFPFPF [11 = figures shift]
[70] PF [15 = letters shift]
[71] PFPF [16 = blank row of tape]
[73] PFPF [18 = carriage return]
[75] PFPFPFPF [20 = space]
[79] PFPFPFPFPFPFPFPF [24 = line feed]
[Main routine to demonstrate pangram-checking subroutine]
T 200 K
G K
[Constants]
[0] P 25 @ [address for input string]
[1] N F [letter N]
[2] Y F [letter Y]
[3] K 2048 F [letter shift]
[4] @ F [carriage return]
[5] & F [line feed]
[6] K 4096 F [null char]
[Enter with acc = 0]
[7] O 3 @ [set letters shift]
[8] A @ [load address of input]
T F [pass to input subroutine in 0F]
[10] A 10 @ [call input subroutine, doesn't change 0F]
G 56 F
[12] A 12 @ [call pangram subroutine]
G 88 F
[We could print the number of missing letters,
but we'll just print 'Y' or 'N'.]
A 1 F [load (number missing) - 1]
E 18 @ [jump if not pangram]
O 2 @ [print 'Y']
G 19 @ [exit]
[18] O 1 @ [print 'N']
[19] O 4 @ [print CR, LF]
O 5 @
O 6 @ [print null to flush printer buffer]
Z F [stop]
T F [on Reset, clear acc]
E 8 @ [and test another string]
[25] [input string goes here]
E 7 Z [define entry point]
P F [acc = 0 on entry]
THE!QUICK!BROWN!FOX!JUMPS!OVER!THE!LAZY!DOG.
- Output:
Y
Elixir
defmodule Pangram do
def checker(str) do
unused = Enum.to_list(?a..?z) -- to_char_list(String.downcase(str))
Enum.empty?(unused)
end
end
text = "The quick brown fox jumps over the lazy dog."
IO.puts "#{Pangram.checker(text)}\t#{text}"
text = (Enum.to_list(?A..?Z) -- 'Test') |> to_string
IO.puts "#{Pangram.checker(text)}\t#{text}"
- Output:
true The quick brown fox jumps over the lazy dog. false ABCDEFGHIJKLMNOPQRSUVWXYZ
Erlang
-module(pangram).
-export([is_pangram/1]).
is_pangram(String) ->
ordsets:is_subset(lists:seq($a, $z), ordsets:from_list(string:to_lower(String))).
Excel
LAMBDA
With the following lambda bound to the name ISPANGRAM in the Excel Workbook Name Manager:
(See LAMBDA: The ultimate Excel worksheet function)
ISPANGRAM
=LAMBDA(s,
LET(
abc, CHARS(LOWER("abcdefghijklmnopqrstuvwxyz")),
AND(
LAMBDA(c,
ISNUMBER(SEARCH(c, s, 1))
)(
abc
)
)
)
)
And assuming that the name CHARS is also bound in the Name Manager
to the generic (String -> Array Char) lambda:
CHARS
=LAMBDA(s,
MID(s, ROW(INDIRECT("1:" & LEN(s))), 1)
)
- Output:
fx | =ISPANGRAM(A2) | ||
---|---|---|---|
A | B | ||
1 | Test strings | Verdicts | |
2 | The quick brown fox jumps over the lazy dog | TRUE | |
3 | Is this a pangram | FALSE | |
4 | How vexingly quick daft zebras jump! | TRUE | |
5 | The five boxing wizards jumped quickly. | TRUE |
F#
If the difference between the set of letters in the alphabet and the set of letters in the given string (after conversion to lower case) is the empty set then every letter appears somewhere in the given string:
let isPangram (str: string) = (set['a'..'z'] - set(str.ToLower())).IsEmpty
Factor
: pangram? ( str -- ? )
[ "abcdefghijklmnopqrstuvwxyz" ] dip >lower diff length 0 = ;
"How razorback-jumping frogs can level six piqued gymnasts!" pangram? .
Forth
: pangram? ( addr len -- ? )
0 -rot bounds do
i c@ 32 or [char] a -
dup 0 26 within if
1 swap lshift or
else drop then
loop
1 26 lshift 1- = ;
s" The five boxing wizards jump quickly." pangram? . \ -1
Fortran
module pangram
implicit none
private
public :: is_pangram
character (*), parameter :: lower_case = 'abcdefghijklmnopqrstuvwxyz'
character (*), parameter :: upper_case = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
contains
function to_lower_case (input) result (output)
implicit none
character (*), intent (in) :: input
character (len (input)) :: output
integer :: i
integer :: j
output = input
do i = 1, len (output)
j = index (upper_case, output (i : i))
if (j /= 0) then
output (i : i) = lower_case (j : j)
end if
end do
end function to_lower_case
function is_pangram (input) result (output)
implicit none
character (*), intent (in) :: input
character (len (input)) :: lower_case_input
logical :: output
integer :: i
lower_case_input = to_lower_case (input)
output = .true.
do i = 1, len (lower_case)
if (index (lower_case_input, lower_case (i : i)) == 0) then
output = .false.
exit
end if
end do
end function is_pangram
end module pangram
Example:
program test
use pangram, only: is_pangram
implicit none
character (256) :: string
string = 'This is a sentence.'
write (*, '(a)') trim (string)
write (*, '(l1)') is_pangram (string)
string = 'The five boxing wizards jumped quickly.'
write (*, '(a)') trim (string)
write (*, '(l1)') is_pangram (string)
end program test
- Output:
This is a sentence. F The five boxing wizards jumped quickly. T
Frink
s = "The quick brown fox jumps over the lazy dog."
println["\"$s\" is" + (isPangram[s] ? "" : " not") + " a pangram."]
isPangram[s] :=
{
charSet = toSet[charList[lc[s]]]
for c = "a" to "z"
if ! charSet.contains[c]
return false
return true
}
- Output:
"The quick brown fox jumps over the lazy dog." is a pangram.
FutureBasic
include "NSLog.incl"
local fn IsPangram( pangramString as CFStringRef ) as BOOL
NSUInteger i, count
BOOL result
CFStringRef lcPanStr = fn StringLowerCaseString( pangramString )
CFMutableSetRef mutSet = fn MutableSetWithCapacity( 0 )
count = len(lcPanStr)
for i = 0 to count - 1
if ( fn CharacterSetCharacterIsMember( fn CharacterSetLowercaseLetterSet, fn StringCharacterAtIndex( lcPanStr, i ) ) )
MutableSetAddObject( mutSet, fn StringWithFormat( @"%c", fn StringCharacterAtIndex( lcPanStr, i ) ) )
end if
next
if fn SetCount( mutSet ) >= 26 then result = YES else result = NO
end fn = result
CFStringRef testStr, trueStr, falseStr
CFArrayRef array
trueStr = @"Is a pangram"
falseStr = @"Not a pangram"
array = @[¬
@"My dog has fleas.",¬
@"The quick brown fox jumps over the lazy do.",¬
@"The quick brown fox jumped over the lazy dog.",¬
@"The quick brown fox jumps over the lazy dog.",¬
@"Jackdaws love my big sphinx of quartz.",¬
@"What's a jackdaw?",¬
@"Watch \"Jeopardy!\", Alex Trebek's fun TV quiz game.",¬
@"Pack my box with five dozen liquor jugs.",¬
@"This definitely is not a pangram.",¬
@"This is a random long sentence just for testing purposes."]
for testStr in array
if ( fn IsPangram( testStr ) )
NSLog( @"%13s : %@", fn StringUTF8String( trueStr ), testStr ) else NSLog( @"%s : %@", fn StringUTF8String( falseStr ), testStr )
end if
next
HandleEvents
- Output:
Not a pangram : My dog has fleas. Not a pangram : The quick brown fox jumps over the lazy do. Not a pangram : The quick brown fox jumped over the lazy dog. Is a pangram : The quick brown fox jumps over the lazy dog. Is a pangram : Jackdaws love my big sphinx of quartz. Not a pangram : What's a jackdaw? Is a pangram : Watch "Jeopardy!", Alex Trebek's fun TV quiz game. Is a pangram : Pack my box with five dozen liquor jugs. Not a pangram : This definitely is not a pangram. Not a pangram : This is a random long sentence just for testing purposes.
Fōrmulæ
Fōrmulæ programs are not textual, visualization/edition of programs is done showing/manipulating structures but not text. Moreover, there can be multiple visual representations of the same program. Even though it is possible to have textual representation —i.e. XML, JSON— they are intended for storage and transfer purposes more than visualization and edition.
Programs in Fōrmulæ are created/edited online in its website.
In this page you can see and run the program(s) related to this task and their results. You can also change either the programs or the parameters they are called with, for experimentation, but remember that these programs were created with the main purpose of showing a clear solution of the task, and they generally lack any kind of validation.
Solution
Test cases
Go
package main
import "fmt"
func main() {
for _, s := range []string{
"The quick brown fox jumps over the lazy dog.",
`Watch "Jeopardy!", Alex Trebek's fun TV quiz game.`,
"Not a pangram.",
} {
if pangram(s) {
fmt.Println("Yes:", s)
} else {
fmt.Println("No: ", s)
}
}
}
func pangram(s string) bool {
var missing uint32 = (1 << 26) - 1
for _, c := range s {
var index uint32
if 'a' <= c && c <= 'z' {
index = uint32(c - 'a')
} else if 'A' <= c && c <= 'Z' {
index = uint32(c - 'A')
} else {
continue
}
missing &^= 1 << index
if missing == 0 {
return true
}
}
return false
}
- Output:
Yes: The quick brown fox jumps over the lazy dog. Yes: Watch "Jeopardy!", Alex Trebek's fun TV quiz game. No: Not a pangram.
Haskell
import Data.Char (toLower)
import Data.List ((\\))
pangram :: String -> Bool
pangram = null . (['a' .. 'z'] \\) . map toLower
main = print $ pangram "How razorback-jumping frogs can level six piqued gymnasts!"
HicEst
PangramBrokenAt("This is a Pangram.") ! => 2 (b is missing)
PangramBrokenAt("The quick Brown Fox jumps over the Lazy Dog") ! => 0 (OK)
FUNCTION PangramBrokenAt(string)
CHARACTER string, Alfabet="abcdefghijklmnopqrstuvwxyz"
PangramBrokenAt = INDEX(Alfabet, string, 64)
! option 64: verify = 1st letter of string not in Alfabet
END
Icon and Unicon
A panagram procedure:
And a main to drive it:
Insitux
(function pangram? sentence
(let prepped (-> sentence lower-case to-vec))
(all? prepped (map char-code (range 97 123))))
(pangram? "The five boxing wizards jump quickly.")
Io
Sequence isPangram := method(
letters := " " repeated(26)
ia := "a" at(0)
foreach(ichar,
if(ichar isLetter,
letters atPut((ichar asLowercase) - ia, ichar)
)
)
letters contains(" " at(0)) not // true only if no " " in letters
)
"The quick brown fox jumps over the lazy dog." isPangram println // --> true
"The quick brown fox jumped over the lazy dog." isPangram println // --> false
"ABC.D.E.FGHI*J/KL-M+NO*PQ R\nSTUVWXYZ" isPangram println // --> true
Ioke
Text isPangram? = method(
letters = "abcdefghijklmnopqrstuvwxyz" chars
text = self lower chars
letters map(x, text include?(x)) reduce(&&)
)
Here is an example of it's use in the Ioke REPL:
iik> "The quick brown fox jumps over the lazy dog" isPangram?
"The quick brown fox jumps over the lazy dog" isPangram?
+> true
iik> "The quick brown fox jumps over the" isPangram?
"The quick brown fox jumps over the" isPangram?
+> false
J
Solution:
require 'strings'
isPangram=: (a. {~ 97+i.26) */@e. tolower
Example use:
isPangram 'The quick brown fox jumps over the lazy dog.'
1
isPangram 'The quick brown fox falls over the lazy dog.'
0
Java
public class Pangram {
public static boolean isPangram(String test){
for (char a = 'A'; a <= 'Z'; a++)
if ((test.indexOf(a) < 0) && (test.indexOf((char)(a + 32)) < 0))
return false;
return true;
}
public static void main(String[] args){
System.out.println(isPangram("the quick brown fox jumps over the lazy dog"));//true
System.out.println(isPangram("the quick brown fox jumped over the lazy dog"));//false, no s
System.out.println(isPangram("ABCDEFGHIJKLMNOPQRSTUVWXYZ"));//true
System.out.println(isPangram("ABCDEFGHIJKLMNOPQSTUVWXYZ"));//false, no r
System.out.println(isPangram("ABCDEFGHIJKL.NOPQRSTUVWXYZ"));//false, no m
System.out.println(isPangram("ABC.D.E.FGHI*J/KL-M+NO*PQ R\nSTUVWXYZ"));//true
System.out.println(isPangram(""));//false
}
}
- Output:
true false true false false true false
JavaScript
ES5
Iterative
function isPangram(s) {
var letters = "zqxjkvbpygfwmucldrhsnioate"
// sorted by frequency ascending (http://en.wikipedia.org/wiki/Letter_frequency)
s = s.toLowerCase().replace(/[^a-z]/g,'')
for (var i = 0; i < 26; i++)
if (s.indexOf(letters[i]) < 0) return false
return true
}
console.log(isPangram("is this a pangram")) // false
console.log(isPangram("The quick brown fox jumps over the lazy dog")) // true
ES6
Functional
(() => {
"use strict";
// ----------------- PANGRAM CHECKER -----------------
// isPangram :: String -> Bool
const isPangram = s =>
0 === "abcdefghijklmnopqrstuvwxyz"
.split("")
.filter(c => -1 === s.toLowerCase().indexOf(c))
.length;
// ---------------------- TEST -----------------------
return [
"is this a pangram",
"The quick brown fox jumps over the lazy dog"
].map(isPangram);
})();
- Output:
[false, true]
jq
def is_pangram:
explode
| map( if 65 <= . and . <= 90 then . + 32 # uppercase
elif 97 <= . and . <= 122 then . # lowercase
else empty
end )
| unique
| length == 26;
# Example:
"The quick brown fox jumps over the lazy dog" | is_pangram
- Output:
$ jq -M -n -f pangram.jq true
Julia
makepangramchecker creates a function to test for pangramity based upon the contents of its input string, allowing one to create arbitrary pangram checkers.
function makepangramchecker(alphabet)
alphabet = Set(uppercase.(alphabet))
function ispangram(s)
lengthcheck = length(s) ≥ length(alphabet)
return lengthcheck && all(c in uppercase(s) for c in alphabet)
end
return ispangram
end
const tests = ["Pack my box with five dozen liquor jugs.",
"The quick brown fox jumps over a lazy dog.",
"The quick brown fox jumps\u2323over the lazy dog.",
"The five boxing wizards jump quickly.",
"This sentence contains A-Z but not the whole alphabet."]
is_english_pangram = makepangramchecker('a':'z')
for s in tests
println("The sentence \"", s, "\" is ", is_english_pangram(s) ? "" : "not ", "a pangram.")
end
- Output:
The sentence "Pack my box with five dozen liquor jugs." is a pangram. The sentence "The quick brown fox jumps over a lazy dog." is a pangram. The sentence "The quick brown fox jumps⌣over the lazy dog." is a pangram. The sentence "The five boxing wizards jump quickly." is a pangram. The sentence "This sentence contains A-Z but not the whole alphabet." is not a pangram.
K
lcase : _ci 97+!26
ucase : _ci 65+!26
tolower : {@[x;p;:;lcase@n@p:&26>n:ucase?/:x]}
panagram: {&/lcase _lin tolower x}
Example:
panagram "The quick brown fox jumps over the lazy dog"
1
panagram "Panagram test"
0
isPangram:0=#(`c$"a"+!26)^_:
isPangram"This is a test"
0
isPangram"The quick brown fox jumps over the lazy dog."
1
Kotlin
// version 1.0.6
fun isPangram(s: String): Boolean {
if (s.length < 26) return false
val t = s.toLowerCase()
for (c in 'a' .. 'z')
if (c !in t) return false
return true
}
fun main(args: Array<String>) {
val candidates = arrayOf(
"The quick brown fox jumps over the lazy dog",
"New job: fix Mr. Gluck's hazy TV, PDQ!",
"A very bad quack might jinx zippy fowls",
"A very mad quack might jinx zippy fowls" // no 'b' now!
)
for (candidate in candidates)
println("'$candidate' is ${if (isPangram(candidate)) "a" else "not a"} pangram")
}
- Output:
'The quick brown fox jumps over the lazy dog' is a pangram 'New job: fix Mr. Gluck's hazy TV, PDQ!' is a pangram 'A very bad quack might jinx zippy fowls' is a pangram 'A very mad quack might jinx zippy fowls' is not a pangram
Ksh
#!/bin/ksh
# Pangram checker
# # Variables:
#
alphabet='abcdefghijklmnopqrstuvwxyz'
typeset -a strs
strs+=( 'Mr. Jock, TV quiz PhD., bags few lynx.' )
strs+=( 'A very mad quack might jinx zippy fowls.' )
# # Functions:
#
# # Function _ispangram(str) - return 0 if str is a pangram
#
function _ispangram {
typeset _str ; typeset -l _str="$1"
typeset _buff ; _buff="${alphabet}"
typeset _i ; typeset -si _i
for ((_i=0; _i<${#_str} && ${#_buff}>0; _i++)); do
_buff=${_buff/${_str:${_i}:1}/}
done
return ${#_buff}
}
######
# main #
######
typeset -si i
for ((i=0; i<${#strs[*]}; i++)); do
_ispangram "${strs[i]}"
if (( ! $? )); then
print "${strs[i]} <<< IS A PANGRAM."
else
print "${strs[i]} <<< Is not a pangram."
fi
done
- Output:
Mr. Jock, TV quiz PhD., bags few lynx. <<< IS A PANGRAM. A very mad quack might jinx zippy fowls. <<< Is not a pangram.
Logo
to remove.all :s :set
if empty? :s [output :set]
if word? :s [output remove.all butfirst :s remove first :s :set]
output remove.all butfirst :s remove.all first :s :set
end
to pangram? :s
output empty? remove.all :s "abcdefghijklmnopqrstuvwxyz
end
show pangram? [The five boxing wizards jump quickly.] ; true
Lua
require"lpeg"
S, C = lpeg.S, lpeg.C
function ispangram(s)
return #(C(S(s)^0):match"abcdefghijklmnopqrstuvwxyz") == 26
end
print(ispangram"waltz, bad nymph, for quick jigs vex")
print(ispangram"bobby")
print(ispangram"long sentence")
Maple
#Used built-in StringTools package
is_pangram := proc(str)
local present := StringTools:-LowerCase~(select(StringTools:-HasAlpha, StringTools:-Explode(str)));
local alphabets := {"a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"};
present := convert(present, set);
return evalb(present = alphabets);
end proc;
- Usage:
is_pangram("The quick brown fox jumps over the lazy dog.");
is_pangram("The 2 QUIck brown foxes jumped over the lazy DOG!!");
is_pangram(""The quick brown fox jumps over the lay dog.");
- Output:
true true false
Mathematica /Wolfram Language
pangramQ[msg_]:=Complement[CharacterRange["a", "z"], Characters[ToLowerCase[msg]]]=== {}
Usage:
pangramQ["The quick brown fox jumps over the lazy dog."] True
Or a slightly more verbose version that outputs the missing characters if the string is not a pangram:
pangramQ[msg_] :=
Function[If[# === {}, Print["The string is a pangram!"],
Print["The string is not a pangram. It's missing the letters " <>
ToString[#]]]][
Complement[CharacterRange["a", "z"], Characters[ToLowerCase[msg]]]]
Usage:
pangramQ["The quick brown fox jumps over the lazy dog."] The string is a pangram!
pangramQ["Not a pangram"] The string is not a pangram. It's missing the letters {b, c, d, e, f, h, i, j, k, l, q, s, u, v, w, x, y, z}
MATLAB
function trueFalse = isPangram(string)
%This works by histogramming the ascii character codes for lower case
%letters contained in the string (which is first converted to all
%lower case letters). Then it finds the index of the first letter that
%is not contained in the string (this is faster than using the find
%without the second parameter). If the find returns an empty array then
%the original string is a pangram, if not then it isn't.
trueFalse = isempty(find( histc(lower(string),(97:122))==0,1 ));
end
- Output:
isPangram('The quick brown fox jumps over the lazy dog.')
ans =
1
MATLAB / Octave
function trueFalse = isPangram(string)
% X is a histogram of letters
X = sparse(abs(lower(string)),1,1,128,1);
trueFalse = full(all(X('a':'z') > 0));
end
- Output:
>>isPangram('The quick brown fox jumps over the lazy dog.') ans = 1
min
"abcdefghijklmnopqrstuvwxyz" "" split =alphabet
('alphabet dip lowercase (swap match) prepend all?) :pangram?
"The quick brown fox jumps over the lazy dog." pangram? puts
MiniScript
sentences = ["The quick brown fox jumps over the lazy dog.",
"Peter Piper picked a peck of pickled peppers.",
"Waltz job vexed quick frog nymphs."]
alphabet = "abcdefghijklmnopqrstuvwxyz"
pangram = function (toCheck)
sentence = toCheck.lower
fail = false
for c in alphabet
if sentence.indexOf(c) == null then return false
end for
return true
end function
for sentence in sentences
if pangram(sentence) then
print """" + sentence + """ is a Pangram"
else
print """" + sentence + """ is not a Pangram"
end if
end for
- Output:
"The quick brown fox jumps over the lazy dog." is a Pangram "Peter Piper picked a peck of pickled peppers." is not a Pangram "Waltz job vexed quick frog nymphs." is a Pangram
ML
mLite
fun to_locase s = implode ` map (c_downcase) ` explode s
fun is_pangram
(h :: t, T) =
let
val flen = len (filter (fn c = c eql h) T)
in
if (flen = 0) then
false
else
is_pangram (t, T)
end
| ([], T) = true
| S = is_pangram (explode "abcdefghijklmnopqrstuvwxyz", explode ` to_locase S)
fun is_pangram_i
(h :: t, T) =
let
val flen = len (filter (fn c = c eql h) T)
in
if (flen = 0) then
false
else
is_pangram (t, T)
end
| ([], T) = true
| (A,S) = is_pangram (explode A, explode ` to_locase S)
fun test (f, arg, res, ok, notok) = if (f arg eql res) then ("'" @ arg @ "' " @ ok) else ("'" @ arg @ "' " @ notok)
fun test2 (f, arg, res, ok, notok) = if (f arg eql res) then ("'" @ ref (arg,1) @ "' " @ ok) else ("'" @ ref (arg,1) @ "' " @ notok)
;
println ` test (is_pangram, "The quick brown fox jumps over the lazy dog", true, "is a pangram", "is not a pangram");
println ` test (is_pangram, "abcdefghijklopqrstuvwxyz", true, "is a pangram", "is not a pangram");
val SValphabet = "abcdefghijklmnopqrstuvwxyzåäö";
val SVsentence = "Yxskaftbud, ge vår wczonmö iq hjälp";
println ` test2 (is_pangram_i, (SValphabet, SVsentence), true, "is a Swedish pangram", "is not a Swedish pangram");
- Output:
'The quick brown fox jumps over the lazy dog' is a pangram 'abcdefghijklopqrstuvwxyz' is not a pangram 'Yxskaftbud, ge vår wczonmö iq hjälp' is a Swedish pangram
Modula-2
MODULE Pangrams;
FROM InOut IMPORT WriteString, WriteLn;
FROM Strings IMPORT Length;
(* Check if a string is a pangram *)
PROCEDURE pangram(s: ARRAY OF CHAR): BOOLEAN;
VAR letters: ARRAY [0..25] OF BOOLEAN;
i: CARDINAL;
BEGIN
FOR i := 0 TO 25 DO letters[i] := FALSE; END;
FOR i := 0 TO Length(s)-1 DO
IF (s[i] >= 'A') AND (s[i] <= 'Z') THEN
letters[ORD(s[i]) - ORD('A')] := TRUE;
ELSIF (s[i] >= 'a') AND (s[i] <= 'z') THEN
letters[ORD(s[i]) - ORD('a')] := TRUE;
END;
END;
FOR i := 0 TO 25 DO
IF NOT letters[i] THEN
RETURN FALSE;
END;
END;
RETURN TRUE;
END pangram;
PROCEDURE example(s: ARRAY OF CHAR);
BEGIN
WriteString("'");
WriteString(s);
WriteString("' is ");
IF NOT pangram(s) THEN
WriteString("not ");
END;
WriteString("a pangram.");
WriteLn();
END example;
BEGIN
example("The quick brown fox jumps over the lazy dog");
example("The five boxing wizards dump quickly");
example("abcdefghijklmnopqrstuvwxyz");
END Pangrams.
- Output:
'The quick brown fox jumps over the lazy dog' is a pangram. 'The five boxing wizards dump quickly' is not a pangram. 'abcdefghijklmnopqrstuvwxyz' is a pangram.
NetRexx
NetRexx's verify
built–in method is all you need!
/* NetRexx */
options replace format comments java crossref savelog symbols nobinary
A2Z = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
pangrams = create_samples
loop p_ = 1 to pangrams[0]
pangram = pangrams[p_]
q_ = A2Z.verify(pangram.upper) -- <= it basically all happens in this function call!
say pangram.left(64)'\-'
if q_ == 0 then -
say ' [OK, a pangram]'
else -
say ' [Not a pangram. Missing:' A2Z.substr(q_, 1)']'
end p_
method create_samples public static returns Rexx
pangrams = ''
x_ = 0
x_ = x_ + 1; pangrams[0] = x_; pangrams[x_] = 'The quick brown fox jumps over a lazy dog.' -- best/shortest pangram
x_ = x_ + 1; pangrams[0] = x_; pangrams[x_] = 'The quick brown fox jumps over the lazy dog.' -- not as short but at least it's still a pangram
x_ = x_ + 1; pangrams[0] = x_; pangrams[x_] = 'The quick brown fox jumped over the lazy dog.' -- common misquote; not a pangram
x_ = x_ + 1; pangrams[0] = x_; pangrams[x_] = 'The quick onyx goblin jumps over the lazy dwarf.'
x_ = x_ + 1; pangrams[0] = x_; pangrams[x_] = 'Bored? Craving a pub quiz fix? Why, just come to the Royal Oak!' -- (Used to advertise a pub quiz in Bowness-on-Windermere)
return pangrams
- Output:
The quick brown fox jumps over a lazy dog. [OK, a pangram] The quick brown fox jumps over the lazy dog. [OK, a pangram] The quick brown fox jumped over the lazy dog. [Not a pangram. Missing: S] The quick onyx goblin jumps over the lazy dwarf. [OK, a pangram] Bored? Craving a pub quiz fix? Why, just come to the Royal Oak! [OK, a pangram]
NewLISP
(context 'PGR) ;; Switch to context (say namespace) PGR
(define (is-pangram? str)
(setf chars (explode (upper-case str))) ;; Uppercase + convert string into a list of chars
(setf is-pangram-status true) ;; Default return value of function
(for (c (char "A") (char "Z") 1 (nil? is-pangram-status)) ;; For loop with break condition
(if (not (find (char c) chars)) ;; If char not found in list, "is-pangram-status" becomes "nil"
(setf is-pangram-status nil)
)
)
is-pangram-status ;; Return current value of symbol "is-pangram-status"
)
(context 'MAIN) ;; Back to MAIN context
;; - - - - - - - - - -
(println (PGR:is-pangram? "abcdefghijklmnopqrstuvwxyz")) ;; Print true
(println (PGR:is-pangram? "abcdef")) ;; Print nil
(exit)
Nim
import rdstdin
proc isPangram(sentence: string, alphabet = {'a'..'z'}): bool =
var sentset: set[char] = {}
for c in sentence: sentset.incl c
alphabet <= sentset
echo isPangram(readLineFromStdin "Sentence: ")
Example usage:
Sentence: The quick brown fox jumps over the lazy dog true
Objeck
bundle Default {
class Pangram {
function : native : IsPangram(test : String) ~ Bool {
for(a := 'A'; a <= 'Z'; a += 1;) {
if(test->Find(a) < 0 & test->Find(a->ToLower()) < 0) {
return false;
};
};
return true;
}
function : Main(args : String[]) ~ Nil {
IsPangram("the quick brown fox jumps over the lazy dog")->PrintLine(); # true
IsPangram("the quick brown fox jumped over the lazy dog")->PrintLine(); # false, no s
IsPangram("ABCDEFGHIJKLMNOPQRSTUVWXYZ")->PrintLine(); # true
IsPangram("ABCDEFGHIJKLMNOPQSTUVWXYZ")->PrintLine(); # false, no r
IsPangram("ABCDEFGHIJKL.NOPQRSTUVWXYZ")->PrintLine(); # false, no m
IsPangram("ABC.D.E.FGHI*J/KL-M+NO*PQ R\nSTUVWXYZ")->PrintLine(); # true
IsPangram("")->PrintLine(); # false
}
}
}
OCaml
let pangram str =
let ar = Array.make 26 false in
String.iter (function
| 'a'..'z' as c -> ar.(Char.code c - Char.code 'a') <- true
| _ -> ()
) (String.lowercase str);
Array.fold_left ( && ) true ar
let check str =
Printf.printf " %b -- %s\n" (pangram str) str
let () =
check "this is a sentence";
check "The quick brown fox jumps over the lazy dog.";
;;
- Output:
false -- this is a sentence true -- The quick brown fox jumps over the lazy dog.
Oz
declare
fun {IsPangram Xs}
{List.sub
{List.number &a &z 1}
{Sort {Map Xs Char.toLower} Value.'<'}}
end
in
{Show {IsPangram "The quick brown fox jumps over the lazy dog."}}
PARI/GP
pangram(s)={
s=vecsort(Vec(s),,8);
for(i=97,122,
if(!setsearch(s,Strchr(i)) && !setsearch(s,Strchr(i-32)),
return(0)
)
);
1
};
pangram("The quick brown fox jumps over the lazy dog.")
pangram("The quick brown fox jumps over the lazy doe.")
Pascal
See Delphi
Perl
Get an answer with a module, or without.
use strict;
use warnings;
use feature 'say';
sub pangram1 {
my($str,@set) = @_;
use List::MoreUtils 'all';
all { $str =~ /$_/i } @set;
}
sub pangram2 {
my($str,@set) = @_;
'' eq (join '',@set) =~ s/[$str]//gir;
}
my @alpha = 'a' .. 'z';
for (
'Cozy Lummox Gives Smart Squid Who Asks For Job Pen.',
'Crabby Lummox Gives Smart Squid Who Asks For Job Pen.'
) {
say pangram1($_,@alpha) ? 'Yes' : 'No';
say pangram2($_,@alpha) ? 'Yes' : 'No';
}
- Output:
Yes Yes No No
Phix
function pangram(string s) sequence az = repeat(false,26) integer count = 0 for i=1 to length(s) do integer ch = lower(s[i]) if ch>='a' and ch<='z' and not az[ch-96] then count += 1 if count=26 then return {true,0} end if az[ch-96] = true end if end for return {false,find(false,az)+96} end function
sequence checks = {"The quick brown fox jumped over the lazy dog", "The quick brown fox jumps over the lazy dog", ".!$\"AbCdEfghijklmnoprqstuvwxyz", "THE FIVE BOXING WIZARDS DUMP QUICKLY.", "THE FIVE BOXING WIZARDS JUMP QUICKLY.", "HEAVY BOXES PERFORM WALTZES AND JIGS.", "PACK MY BOX WITH FIVE DOZEN LIQUOR JUGS.", "Big fjiords vex quick waltz nymph", "The quick onyx goblin jumps over the lazy dwarf.", "no"} for i=1 to length(checks) do string ci = checks[i] integer {r,ch} = pangram(ci) printf(1,"%-50s - %s\n",{ci,iff(r?"yes":"no "&ch)}) end for
- Output:
The quick brown fox jumped over the lazy dog - no s The quick brown fox jumps over the lazy dog - yes .!$"AbCdEfghijklmnoprqstuvwxyz - yes THE FIVE BOXING WIZARDS DUMP QUICKLY. - no j THE FIVE BOXING WIZARDS JUMP QUICKLY. - yes HEAVY BOXES PERFORM WALTZES AND JIGS. - no c PACK MY BOX WITH FIVE DOZEN LIQUOR JUGS. - yes Big fjiords vex quick waltz nymph - yes The quick onyx goblin jumps over the lazy dwarf. - yes no - no a
Phixmonti
include ..\Utilitys.pmt
def pangram?
lower "abcdefghijklmnopqrstuvwxyz" swap remove len not nip
enddef
"The quick brown fox jumps over the lazy dog." pangram?
"This is a test" pangram?
"NOPQRSTUVWXYZ abcdefghijklm" pangram?
"abcdefghijklopqrstuvwxyz" pangram?
pstack
- Output:
[1, 0, 1, 0] === Press any key to exit ===
PHP
function isPangram($text) {
foreach (str_split($text) as $c) {
if ($c >= 'a' && $c <= 'z')
$bitset |= (1 << (ord($c) - ord('a')));
else if ($c >= 'A' && $c <= 'Z')
$bitset |= (1 << (ord($c) - ord('A')));
}
return $bitset == 0x3ffffff;
}
$test = array(
"the quick brown fox jumps over the lazy dog",
"the quick brown fox jumped over the lazy dog",
"ABCDEFGHIJKLMNOPQSTUVWXYZ",
"ABCDEFGHIJKL.NOPQRSTUVWXYZ",
"ABC.D.E.FGHI*J/KL-M+NO*PQ R\nSTUVWXYZ"
);
foreach ($test as $str)
echo "$str : ", isPangram($str) ? 'T' : 'F', '</br>';
the quick brown fox jumps over the lazy dog : T the quick brown fox jumped over the lazy dog : F ABCDEFGHIJKLMNOPQSTUVWXYZ : F ABCDEFGHIJKL.NOPQRSTUVWXYZ : F ABC.D.E.FGHI*J/KL-M+NO*PQ R STUVWXYZ : T
Using array
function is_pangram( $sentence ) {
// define "alphabet"
$alpha = range( 'a', 'z' );
// split lowercased string into array
$a_sentence = str_split( strtolower( $sentence ) );
// check that there are no letters present in alpha not in sentence
return empty( array_diff( $alpha, $a_sentence ) );
}
$tests = array(
"The quick brown fox jumps over the lazy dog.",
"The brown fox jumps over the lazy dog.",
"ABCDEFGHIJKL.NOPQRSTUVWXYZ",
"ABC.D.E.FGHI*J/KL-M+NO*PQ R\nSTUVWXYZ",
"How vexingly quick daft zebras jump",
"Is hotdog?",
"How razorback-jumping frogs can level six piqued gymnasts!"
);
foreach ( $tests as $txt ) {
echo '"', $txt, '"', PHP_EOL;
echo is_pangram( $txt ) ? "Yes" : "No", PHP_EOL, PHP_EOL;
}
- Output:
"The quick brown fox jumps over the lazy dog." Yes "The brown fox jumps over the lazy dog." No "ABCDEFGHIJKL.NOPQRSTUVWXYZ" No "ABC.D.E.FGHI*J/KL-M+NO*PQ R STUVWXYZ" Yes "How vexingly quick daft zebras jump" Yes "Is hotdog?" No "How razorback-jumping frogs can level six piqued gymnasts!" Yes
Picat
go =>
S1 = "The quick brown fox jumps over the lazy dog",
S2 = "The slow brown fox jumps over the lazy dog",
println([S1, is_pangram(S1)]),
println([S2, is_pangram(S2)]),
nl,
println("With missing chars:"),
println([S1, is_pangram2(S1)]),
println([S2, is_pangram2(S2)]),
nl.
% Check if S is a pangram and get the missing chars
is_pangram(S) = P =>
Lower = S.to_lowercase,
Alpha = [chr(I+96) : I in 1..26],
foreach(A in Alpha) membchk(A,Lower) end -> P = true ; P = false.
% Check if S is a pangram and get the missing chars (if any)
is_pangram2(S) = [pangram=cond(Missing==[],true,false),missing=Missing] =>
Lower = S.to_lowercase,
Missing = [A : A in [chr(I+96) : I in 1..26], not membchk(A,Lower)].
- Output:
[The quick brown fox jumps over the lazy dog,true] [The slow brown fox jumps over the lazy dog,false] With missing chars: [The quick brown fox jumps over the lazy dog,[pangram = true,missing = []]] [The slow brown fox jumps over the lazy dog,[pangram = false,missing = cikq]]
PicoLisp
(de isPangram (Str)
(not
(diff
'`(chop "abcdefghijklmnopqrstuvwxyz")
(chop (lowc Str)) ) ) )
PL/I
test_pangram: procedure options (main);
is_pangram: procedure() returns (bit(1) aligned);
declare text character (200) varying;
declare c character (1);
get edit (text) (L);
put skip list (text);
text = lowercase(text);
do c = 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k',
'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u',
'v', 'w', 'x', 'y', 'z';
if index(text, c) = 0 then return ('0'b);
end;
return ('1'b);
end is_pangram;
put skip list ('Please type a sentence');
if is_pangram() then
put skip list ('The sentence is a pangram.');
else
put skip list ('The sentence is not a pangram.');
end test_pangram;
- Output:
Please type a sentence the quick brown fox jumps over the lazy dog The sentence is a pangram.
PowerShell
Cyrillic test sample borrowed from Raku.
function Test-Pangram ( [string]$Text, [string]$Alphabet = 'abcdefghijklmnopqrstuvwxyz' )
{
$Text = $Text.ToLower()
$Alphabet = $Alphabet.ToLower()
$IsPangram = @( $Alphabet.ToCharArray() | Where-Object { $Text.Contains( $_ ) } ).Count -eq $Alphabet.Length
return $IsPangram
}
Test-Pangram 'The quick brown fox jumped over the lazy dog.'
Test-Pangram 'The quick brown fox jumps over the lazy dog.'
Test-Pangram 'Съешь же ещё этих мягких французских булок, да выпей чаю' 'абвгдежзийклмнопрстуфхцчшщъыьэюяё'
- Output:
False True True
A faster version can be created using .Net HashSet to do what the F# version does:
Function Test-Pangram ( [string]$Text, [string]$Alphabet = 'abcdefghijklmnopqrstuvwxyz' )
{
$alSet = [Collections.Generic.HashSet[char]]::new($Alphabet.ToLower())
$textSet = [Collections.Generic.HashSet[char]]::new($Text.ToLower())
$alSet.ExceptWith($textSet) # remove text chars from the alphabet
return $alSet.Count -eq 0 # any alphabet letters still remaining?
}
Prolog
Works with SWI-Prolog
pangram(L) :-
numlist(0'a, 0'z, Alphabet),
forall(member(C, Alphabet), member(C, L)).
pangram_example :-
L1 = "the quick brown fox jumps over the lazy dog",
( pangram(L1) -> R1= ok; R1 = ko),
format('~s --> ~w ~n', [L1,R1]),
L2 = "the quick brown fox jumped over the lazy dog",
( pangram(L2) -> R2 = ok; R2 = ko),
format('~s --> ~w ~n', [L2, R2]).
- Output:
?- pangram_example. the quick brown fox jumps over the lazy dog --> ok the quick brown fox jumped over the lazy dog --> ko true.
Python
Using set arithmetic:
import string, sys
if sys.version_info[0] < 3:
input = raw_input
def ispangram(sentence, alphabet=string.ascii_lowercase):
alphaset = set(alphabet)
return alphaset <= set(sentence.lower())
print ( ispangram(input('Sentence: ')) )
- Output:
Sentence: The quick brown fox jumps over the lazy dog True
Quackery
[ dup char A char [ within
swap char a char { within
or ] is letter ( c --> b )
[ 0 26 of swap witheach
[ dup letter iff
[ 1 unrot lower
char a - poke ]
else drop ]
0 swap find 26 = ] is pangram ( $ --> b )
$ "This is a sentence." pangram echo cr ( 0 )
$ "The five boxing wizards jumped quickly." pangram echo cr ( 1 )
R
Using the built-in R vector "letters":
checkPangram <- function(sentence){
my.letters <- tolower(unlist(strsplit(sentence, "")))
is.pangram <- all(letters %in% my.letters)
if (is.pangram){
cat("\"", sentence, "\" is a pangram! \n", sep="")
} else {
cat("\"", sentence, "\" is not a pangram! \n", sep="")
}
}
- Output:
s1 <- "The quick brown fox jumps over the lazy dog" s2 <- "The quick brown fox jumps over the sluggish dog" checkPangram(s1) "The quick brown fox jumps over the lazy dog" is a pangram! checkPangram(s2) "The quick brown fox jumps over the sluggish dog" is not a pangram!
Racket
#lang racket
(define (pangram? str)
(define chars (regexp-replace* #rx"[^a-z]+" (string-downcase str) ""))
(= 26 (length (remove-duplicates (string->list chars)))))
(pangram? "The quick Brown Fox jumps over the Lazy Dog")
Raku
(formerly Perl 6)
constant Eng = set 'a' .. 'z';
constant Cyr = (set 'а' .. 'ё') (-) (set 'ъ', 'ѐ');
constant Hex = set 'a' .. 'f';
sub pangram($str, Set $alpha = Eng) {
$alpha ⊆ $str.lc.comb
}
say pangram("The quick brown fox jumps over the lazy dog.");
say pangram("My dog has fleas.");
say pangram("My dog has fleas.", Hex);
say pangram("My dog backs fleas.", Hex);
say pangram "Съешь же ещё этих мягких французских булок, да выпей чаю", Cyr;
- Output:
True False False True True
Retro
'abcdefghijklmnopqrstuvwxyz 'FULL s:const
'__________________________ 'TEST s:const
:s:pangram? (s-f)
'__________________________ &TEST #26 copy
s:to-lower [ c:letter? ] s:filter
[ dup $a - &TEST + store ] s:for-each
&TEST &FULL s:eq? ;
REXX
/*REXX program verifies if an entered/supplied string (sentence) is a pangram. */
@abc= 'ABCDEFGHIJKLMNOPQRSTUVWXYZ' /*a list of all (Latin) capital letters*/
do forever; say /*keep promoting 'til null (or blanks).*/
say '──────── Please enter a pangramic sentence (or a blank to quit):'; say
pull y /*this also uppercases the Y variable.*/
if y='' then leave /*if nothing entered, then we're done.*/
absent= space( translate( @abc, , y), 0) /*obtain a list of any absent letters. */
if absent=='' then say "──────── Sentence is a pangram."
else say "──────── Sentence isn't a pangram, missing: " absent
say
end /*forever*/
say '──────── PANGRAM program ended. ────────' /*stick a fork in it, we're all done. */
- output:
──────── Please enter a pangramic sentence (or a blank to quit): The quick brown fox jumped over the lazy dog. ◄■■■■■■■■■■ user input. ──────── Sentence isn't a pangram, missing: S ──────── Please enter a pangramic sentence (or a blank to quit): The quick brown fox JUMPS over the lazy dog!!! ◄■■■■■■■■■■ user input. ──────── Sentence is a pangram. ──────── Please enter a pangramic sentence (or a blank to quit): ◄■■■■■■■■■■ user input (null or some blanks). ──────── PANGRAM program ended. ────────
Ring
pangram = 0
s = "The quick brown fox jumps over the lazy dog."
see "" + pangram(s) + " " + s + nl
s = "My dog has fleas."
see "" + pangram(s) + " " + s + nl
func pangram str
str = lower(str)
for i = ascii("a") to ascii("z")
bool = substr(str, char(i)) > 0
pangram = pangram + bool
next
pan = (pangram = 26)
return pan
RPL
Structurally programmed
RPL code | Comment |
---|---|
≪
# 0h SWAP 1 OVER SIZE FOR j
DUP j DUP SUB NUM
IF DUP 97 ≥ OVER 122 ≤ AND THEN 32 - END
IF DUP 65 ≥ OVER 90 ≤ AND THEN
2 SWAP 65 - ^ R→B ROT OR SWAP
ELSE DROP END
NEXT DROP # 3FFFFFFh ==
≫ ‘PANG?’ STO
|
PANG? ( "sentence" → boolean )
alpha = 0; loop for j = 1 to length(sentence)
c = ascii(sentence[j])
if c lowercase then make it uppercase
if c in ("A".."Z") then
alpha &= 2^(c-65)
end loop
return alpha & 3FFFFFFh
|
Idiomatically optimized for HP-28S
RPL code | Comment |
---|---|
≪
# 7FFFFFEh RCLF OVER NOT AND STOF SWAP
1 OVER SIZE FOR j
DUP j DUP SUB NUM
DUP 97 ≥ 95 63 IFTE - 1 MAX 28 MIN SF
NEXT DROP RCLF OVER AND ==
≫ ‘PANG?’ STO
|
PANG? ( "sentence" → boolean )
clear flags 1 to 28
loop for j = 1 to length(sentence)
c = ascii(sentence[j])
reduce c to a value between 1 and 28 and set related flag
return 1 if all flags between 2 and 27 are set
|
To run on more recent models, the following sequence in line 2
RCLF OVER NOT AND STOF
must be replaced by
RCLF DUP 2 GET 3 PICK NOT AND 2 SWAP PUT STOF
and RCLF
in the last line by RCLF 2 GET
.
"The quick brown fox jumps over the lazy dog" PANG? "The quick brown fox jumped over the lazy dog" PANG?
- Output:
2: 1 1: 0
Ruby
def pangram?(sentence)
s = sentence.downcase
('a'..'z').all? {|char| s.include? (char) }
end
p pangram?('this is a sentence') # ==> false
p pangram?('The quick brown fox jumps over the lazy dog.') # ==> true
Rust
#![feature(test)]
extern crate test;
use std::collections::HashSet;
pub fn is_pangram_via_bitmask(s: &str) -> bool {
// Create a mask of set bits and convert to false as we find characters.
let mut mask = (1 << 26) - 1;
for chr in s.chars() {
let val = chr as u32 & !0x20; /* 0x20 converts lowercase to upper */
if val <= 'Z' as u32 && val >= 'A' as u32 {
mask = mask & !(1 << (val - 'A' as u32));
}
}
mask == 0
}
pub fn is_pangram_via_hashset(s: &str) -> bool {
// Insert lowercase letters into a HashSet, then check if we have at least 26.
let letters = s.chars()
.flat_map(|chr| chr.to_lowercase())
.filter(|&chr| chr >= 'a' && chr <= 'z')
.fold(HashSet::new(), |mut letters, chr| {
letters.insert(chr);
letters
});
letters.len() == 26
}
pub fn is_pangram_via_sort(s: &str) -> bool {
// Copy chars into a vector, convert to lowercase, sort, and remove duplicates.
let mut chars: Vec<char> = s.chars()
.flat_map(|chr| chr.to_lowercase())
.filter(|&chr| chr >= 'a' && chr <= 'z')
.collect();
chars.sort();
chars.dedup();
chars.len() == 26
}
fn main() {
let examples = ["The quick brown fox jumps over the lazy dog",
"The quick white cat jumps over the lazy dog"];
for &text in examples.iter() {
let is_pangram_sort = is_pangram_via_sort(text);
println!("Is \"{}\" a pangram via sort? - {}", text, is_pangram_sort);
let is_pangram_bitmask = is_pangram_via_bitmask(text);
println!("Is \"{}\" a pangram via bitmask? - {}",
text,
is_pangram_bitmask);
let is_pangram_hashset = is_pangram_via_hashset(text);
println!("Is \"{}\" a pangram via bitmask? - {}",
text,
is_pangram_hashset);
}
}
Scala
def is_pangram(sentence: String) = sentence.toLowerCase.filter(c => c >= 'a' && c <= 'z').toSet.size == 26
scala> is_pangram("This is a sentence")
res0: Boolean = false
scala> is_pangram("The quick brown fox jumps over the lazy dog")
res1: Boolean = true
Seed7
$ include "seed7_05.s7i";
const func boolean: isPangram (in string: stri) is func
result
var boolean: isPangram is FALSE;
local
var char: ch is ' ';
var set of char: usedChars is (set of char).value;
begin
for ch range lower(stri) do
if ch in {'a' .. 'z'} then
incl(usedChars, ch);
end if;
end for;
isPangram := usedChars = {'a' .. 'z'};
end func;
const proc: main is func
begin
writeln(isPangram("This is a test"));
writeln(isPangram("The quick brown fox jumps over the lazy dog"));
writeln(isPangram("NOPQRSTUVWXYZ abcdefghijklm"));
writeln(isPangram("abcdefghijklopqrstuvwxyz")); # Missing m, n
end func;
- Output:
FALSE TRUE TRUE FALSE
Sidef
define Eng = 'a'..'z';
define Hex = 'a'..'f';
define Cyr = %w(а б в г д е ж з и й к л м н о п р с т у ф х ц ч ш щ ъ ы ь э ю я ё);
func pangram(str, alpha=Eng) {
var lstr = str.lc;
alpha.all {|c| lstr.contains(c) };
}
say pangram("The quick brown fox jumps over the lazy dog.");
say pangram("My dog has fleas.");
say pangram("My dog has fleas.", Hex);
say pangram("My dog backs fleas.", Hex);
say pangram("Съешь же ещё этих мягких французских булок, да выпей чаю", Cyr);
- Output:
true false false true true
Smalltalk
!String methodsFor: 'testing'!
isPangram
^((self collect: [:c | c asUppercase]) select: [:c | c >= $A and: [c <= $Z]]) asSet size = 26
'The quick brown fox jumps over the lazy dog.' isPangram
SNOBOL4
define('pangram(str)alfa,c') :(pangram_end)
pangram str = replace(str,&ucase,&lcase)
alfa = &lcase
pgr_1 alfa len(1) . c = :f(return)
str c :s(pgr_1)f(freturn)
pangram_end
define('panchk(str)tf') :(panchk_end)
panchk output = str
tf = 'False'; tf = pangram(str) 'True'
output = 'Pangram: ' tf :(return)
panchk_end
* # Test and display
panchk("The quick brown fox jumped over the lazy dogs.")
panchk("My girl wove six dozen plaid jackets before she quit.")
panchk("This 41-character string: it's a pangram!")
end
- Output:
The quick brown fox jumped over the lazy dogs. Pangram: True My girl wove six dozen plaid jackets before she quit. Pangram: True This 41-character string: it's a pangram! Pangram: False
Swift
import Foundation
let str = "the quick brown fox jumps over the lazy dog"
func isPangram(str:String) -> Bool {
let stringArray = Array(str.lowercaseString)
for char in "abcdefghijklmnopqrstuvwxyz" {
if (find(stringArray, char) == nil) {
return false
}
}
return true
}
isPangram(str) // True
isPangram("Test string") // False
Swift 2.0:
func isPangram(str: String) -> Bool {
let (char, alph) = (Set(str.characters), "abcdefghijklmnopqrstuvwxyz".characters)
return !alph.contains {!char.contains($0)}
}
Tcl
proc pangram? {sentence} {
set letters [regexp -all -inline {[a-z]} [string tolower $sentence]]
expr {
[llength [lsort -unique $letters]] == 26
}
}
puts [pangram? "This is a sentence"]; # ==> false
puts [pangram? "The quick brown fox jumps over the lazy dog."]; # ==> true
TI-83 BASIC
:Prompt Str1
:For(L,1,26
:If not(inString(Str1,sub("ABCDEFGHIJKLMNOPQRSTUVWXYZ",L,1))
:L=28
:End
:If L<28
:Disp "IS A PANGRAM"
(not tested yet)
TUSCRIPT
$$ MODE TUSCRIPT,{}
alfabet="abcdefghijklmnopqrstuvwxyz"
sentences = *
DATA The quick brown fox jumps over the lazy dog
DATA the quick brown fox falls over the lazy dog
LOOP s=sentences
getchars =STRINGS (s," {&a} ")
sortchars =ALPHA_SORT (getchars)
reducechars =REDUCE (sortchars)
chars_in_s =EXCHANGE (reducechars," ' ")
IF (chars_in_s==alfabet) PRINT " pangram: ",s
IF (chars_in_s!=alfabet) PRINT "no pangram: ",s
ENDLOOP
- Output:
pangram: The quick brown fox jumps over the lazy dog no pangram: the quick brown fox falls over the lazy dog
TXR
@/.*[Aa].*&.*[Bb].*&.*[Cc].*&.*[Dd].*& \
.*[Ee].*&.*[Ff].*&.*[Gg].*&.*[Hh].*& \
.*[Ii].*&.*[Jj].*&.*[Kk].*&.*[Ll].*& \
.*[Mm].*&.*[Nn].*&.*[Oo].*&.*[Pp].*& \
.*[Qq].*&.*[Rr].*&.*[Ss].*&.*[Tt].*& \
.*[Uu].*&.*[Vv].*&.*[Ww].*&.*[Xx].*& \
.*[Yy].*&.*[Zz].*/
- Run:
$ echo "The quick brown fox jumped over the lazy dog." | txr is-pangram.txr - $echo $? # failed termination 1 $ echo "The quick brown fox jumped over the lazy dogs." | txr is-pangram.txr - $ echo $? # successful termination 0
UNIX Shell
function is_pangram {
typeset alphabet=abcdefghijklmnopqrstuvwxyz
typeset -l string=$*
while [[ -n $string && -n $alphabet ]]; do
typeset ch=${string%%${string#?}}
string=${string#?}
alphabet=${alphabet/$ch}
done
[[ -z $alphabet ]]
}
Ursala
#import std
is_pangram = ^jZ^(!@l,*+ @rlp -:~&) ~=`A-~ letters
example usage:
#cast %bL
test =
is_pangram* <
'The quick brown fox jumps over the lazy dog',
'this is not a pangram'>
- Output:
<true,false>
VBA
The function pangram() in the VBScript section below will do just fine.
Here is an alternative version:
Function pangram2(s As String) As Boolean
Const sKey As String = "abcdefghijklmnopqrstuvwxyz"
Dim sLow As String
Dim i As Integer
sLow = LCase(s)
For i = 1 To 26
If InStr(sLow, Mid(sKey, i, 1)) = 0 Then
pangram2 = False
Exit Function
End If
Next
pangram2 = True
End Function
Invocation e.g. (typed in the Immediate window):
print pangram2("the quick brown dog jumps over a lazy fox") print pangram2("it is time to say goodbye!")
VBScript
Implementation
function pangram( s )
dim i
dim sKey
dim sChar
dim nOffset
sKey = "abcdefghijklmnopqrstuvwxyz"
for i = 1 to len( s )
sChar = lcase(mid(s,i,1))
if sChar <> " " then
if instr(sKey, sChar) then
nOffset = asc( sChar ) - asc("a") + 1
if nOffset > 1 then
sKey = left(sKey, nOffset - 1) & " " & mid( sKey, nOffset + 1)
else
sKey = " " & mid( sKey, nOffset + 1)
end if
end if
end if
next
pangram = ( ltrim(sKey) = vbnullstring )
end function
function eef( bCond, exp1, exp2 )
if bCond then
eef = exp1
else
eef = exp2
end if
end function
Invocation
wscript.echo eef(pangram("a quick brown fox jumps over the lazy dog"), "is a pangram", "is not a pangram")
wscript.echo eef(pangram(""), "is a pangram", "is not a pangram")"
VTL-2
10 I=1
20 :I)=0
30 I=I+1
40 #=26>I*20
50 ?="Enter sentence: ";
60 C=$
70 #=C=13*120
80 C=C<97*32+C-96
90 #=C>27*60
100 :C)=1
110 #=60
120 ?=""
130 I=1
140 N=0
150 N=N+:I)
160 I=I+1
170 #=26>I*150
180 #=N=26*200
190 ?="not ";
200 ?="a pangram"
- Output:
#=1 Enter sentence: The quick brown fox jumps over the lazy dog. a pangram OK #=1 Enter sentence: This is not a pangram. not a pangram OK
Wren
import "./str" for Str
var isPangram = Fn.new { |s|
s = Str.lower(s)
var used = List.filled(26, false)
for (cp in s.codePoints) {
if (cp >= 97 && cp <= 122) used[cp-97] = true
}
for (u in used) if (!u) return false
return true
}
var candidates = [
"The quick brown fox jumps over the lazy dog.",
"New job: fix Mr. Gluck's hazy TV, PDQ!",
"Peter Piper picked a peck of pickled peppers.",
"Sphinx of black quartz, judge my vow.",
"Foxy diva Jennifer Lopez wasn’t baking my quiche.",
"Grumpy wizards make a toxic stew for the jovial queen."
]
System.print("Are the following pangrams?")
for (candidate in candidates) {
System.print(" %(candidate) -> %(isPangram.call(candidate))")
}
- Output:
Are the following pangrams? The quick brown fox jumps over the lazy dog. -> true New job: fix Mr. Gluck's hazy TV, PDQ! -> true Peter Piper picked a peck of pickled peppers. -> false Sphinx of black quartz, judge my vow. -> true Foxy diva Jennifer Lopez wasn’t baking my quiche. -> true Grumpy wizards make a toxic stew for the jovial queen. -> false
XPL0
include c:\cxpl\codes; \intrinsic 'code' declarations
string 0; \use zero-terminated strings
func StrLen(Str); \Return number of characters in an ASCIIZ string
char Str;
int I;
for I:= 0 to -1>>1-1 do
if Str(I) = 0 then return I;
func Pangram(S);
char S;
int A, I, C;
[A:= 0;
for I:= 0 to StrLen(S)-1 do
[C:= S(I);
if C>=^A & C<=^Z then C:= C or $20;
if C>=^a & C<=^z then [C:= C - ^a; A:= A or 1<<C];
];
return A = $3FFFFFF;
]; \Pangram
int Sentence, I;
[Sentence:=
["The quick brown fox jumps over the lazy dog.",
"Pack my box with five dozen liquor jugs.",
"Now is the time for all good men to come to the aid of their country."];
for I:= 0 to 3-1 do
[Text(0, if Pangram(Sentence(I)) then "yes" else "no");
CrLf(0);
];
]
- Output:
yes yes no
zkl
var letters=["a".."z"].pump(String); //-->"abcdefghijklmnopqrstuvwxyz"
fcn isPangram(text){(not (letters-text.toLower()))}
- Output:
isPangram("The quick brown fox jumps over the lazy dog.") True isPangram("Pack my box with five dozen liquor jugs.") True isPangram("Now is the time for all good men to come to the aid of their country.") False
- String manipulation
- Programming Tasks
- Solutions by Programming Task
- Lilypond/Omit
- 11l
- 360 Assembly
- ACL2
- Action!
- Action! Tool Kit
- ActionScript
- Ada
- ALGOL 68
- APL
- AppleScript
- Arturo
- ATS
- AutoHotkey
- AutoIt
- AWK
- BASIC
- Applesoft BASIC
- BaCon
- BASIC256
- BBC BASIC
- Commodore BASIC
- Chipmunk Basic
- FreeBASIC
- Liberty BASIC
- PureBasic
- QBasic
- Run BASIC
- Sinclair ZX81 BASIC
- UBasic/4tH
- Yabasic
- Batch File
- BCPL
- Befunge
- Bracmat
- Brat
- C
- C sharp
- C++
- Ceylon
- Clojure
- CLU
- COBOL
- CoffeeScript
- Comal
- Common Lisp
- Component Pascal
- Cowgol
- Crystal
- D
- Delphi
- Draco
- E
- EasyLang
- EDSAC order code
- Elixir
- Erlang
- Excel
- F Sharp
- Factor
- Forth
- Fortran
- Frink
- FutureBasic
- Fōrmulæ
- Go
- Haskell
- HicEst
- Icon
- Unicon
- Insitux
- Io
- Ioke
- J
- Java
- JavaScript
- Jq
- Julia
- K
- Kotlin
- Ksh
- Logo
- Lua
- Maple
- Mathematica
- Wolfram Language
- MATLAB
- Octave
- Min
- MiniScript
- ML
- MLite
- Modula-2
- NetRexx
- NewLISP
- Nim
- Objeck
- OCaml
- Oz
- PARI/GP
- Pascal
- Perl
- Phix
- Phixmonti
- PHP
- Picat
- PicoLisp
- PL/I
- PowerShell
- Prolog
- Python
- Quackery
- R
- Racket
- Raku
- Retro
- REXX
- Ring
- RPL
- Ruby
- Rust
- Scala
- Seed7
- Sidef
- Smalltalk
- SNOBOL4
- Swift
- Tcl
- TI-83 BASIC
- TUSCRIPT
- TXR
- UNIX Shell
- Ursala
- VBA
- VBScript
- VTL-2
- Wren
- Wren-str
- XPL0
- Zkl
- Pages with too many expensive parser function calls