Averages/Arithmetic mean

From Rosetta Code
Task
Averages/Arithmetic mean
You are encouraged to solve this task according to the task description, using any language you may know.
Task

Write a program to find the mean (arithmetic average) of a numeric vector.

In case of a zero-length input, since the mean of an empty set of numbers is ill-defined, the program may choose to behave in any way it deems appropriate, though if the programming language has an established convention for conveying math errors or undefined values, it's preferable to follow it.

See also


0815[edit]

{x{+=<:2:x/%<:d:~$<:01:~><:02:~><:03:~><:04:~><:05:~><:06:~><:07:~><:08:
~><:09:~><:0a:~><:0b:~><:0c:~><:0d:~><:0e:~><:0f:~><:10:~><:11:~><:12:~>
<:13:~><:14:~><:15:~><:16:~><:17:~><:18:~><:19:~><:ffffffffffffffff:~>{x
{+>}:8f:{&={+>{~>&=x<:ffffffffffffffff:/#:8f:{{=<:19:x/%
Output:
0
D

11l[edit]

Translation of: Python
F average(x)
   R sum(x) / Float(x.len)

print(average([0, 0, 3, 1, 4, 1, 5, 9, 0, 0]))
Output:
2.3

360 Assembly[edit]

Compact and functional.

AVGP     CSECT
         USING  AVGP,12
         LR     12,15
         SR     3,3                i=0
         SR     6,6                sum=0
LOOP     CH     3,=AL2(NN-T-1)     for i=1 to nn
         BH     ENDLOOP
         L      2,T(3)             t(i)
         MH     2,=H'100'          scaling factor=2
         AR     6,2                sum=sum+t(i)
         LA     3,4(3)             next i
         B      LOOP
ENDLOOP  LR     5,6                sum
         LA     4,0
         D      4,NN               sum/nn
         XDECO  5,Z                edit binary 
         MVC    U,Z+10             descale
         MVI    Z+10,C'.'
         MVC    Z+11(2),U
         XPRNT  Z,80               output
         XR     15,15
         BR     14
T        DC     F'10',F'9',F'8',F'7',F'6',F'5',F'4',F'3',F'2',F'1'
NN       DC     A((NN-T)/4)
Z        DC     CL80' '
U        DS     CL2
         END    AVGP
Output:
         5.50

6502 Assembly[edit]

Called as a subroutine (i.e., JSR ArithmeticMean), this calculates the integer average of up to 255 8-bit unsigned integers. The address of the beginning of the list of integers is in the memory location ArrayPtr and the number of integers is in the memory location NumberInts. The arithmetic mean is returned in the memory location ArithMean.

ArithmeticMean:		PHA
			TYA
			PHA		;push accumulator and Y register onto stack


			LDA #0
			STA Temp
			STA Temp+1	;temporary 16-bit storage for total

			LDY NumberInts	
			BEQ Done	;if NumberInts = 0 then return an average of zero

			DEY		;start with NumberInts-1
AddLoop:		LDA (ArrayPtr),Y
			CLC
			ADC Temp
			STA Temp
			LDA Temp+1
			ADC #0
			STA Temp+1
			DEY
			CPY #255
			BNE AddLoop

			LDY #-1
DivideLoop:		LDA Temp
			SEC
			SBC NumberInts
			STA Temp
			LDA Temp+1
			SBC #0
			STA Temp+1
			INY
			BCS DivideLoop
			
Done:			STY ArithMean	;store result here
			PLA		;restore accumulator and Y register from stack
			TAY
			PLA
			RTS		;return from routine

8th[edit]

: avg \ a -- avg(a)
  dup ' n:+ 0 a:reduce
  swap a:len nip n:/ ;

\ test:
[ 1.0, 2.3, 1.1, 5.0, 3, 2.8, 2.01, 3.14159 ] avg . cr 
[ ] avg . cr
[ 10 ] avg . cr
bye

Output is:
2.54395
NaN
10.00000

ACL2[edit]

(defun mean-r (xs)
   (if (endp xs)
       (mv 0 0)
       (mv-let (m j)
               (mean-r (rest xs))
          (mv (+ (first xs) m) (+ j 1)))))
 
(defun mean (xs)
   (if (endp xs)
       0
       (mv-let (n d)
               (mean-r xs)
          (/ n d))))

Action![edit]

INCLUDE "D2:REAL.ACT" ;from the Action! Tool Kit

PROC Mean(INT ARRAY a INT count REAL POINTER result)
  INT i
  REAL x,sum,tmp

  IntToReal(0,sum)
  FOR i=0 TO count-1
  DO
    IntToReal(a(i),x)
    RealAdd(sum,x,tmp)
    RealAssign(tmp,sum)
  OD
  IntToReal(count,tmp)
  RealDiv(sum,tmp,result)
RETURN

PROC Test(INT ARRAY a INT count)
  INT i
  REAL result

  Mean(a,count,result)
  Print("mean(")
  FOR i=0 TO count-1
  DO
    PrintI(a(i))
    IF i<count-1 THEN
      Put(',)
    FI
  OD
  Print(")=")
  PrintRE(result)
RETURN

PROC Main()
  INT ARRAY a1=[1 2 3 4 5 6]
  INT ARRAY a2=[1 10 100 1000 10000]
  INT ARRAY a3=[9]

  Put(125) PutE() ;clear screen
  Test(a1,6)
  Test(a2,5)
  Test(a3,1)
  Test(a3,0)
RETURN
Output:

Screenshot from Atari 8-bit computer

mean(1,2,3,4,5,6)=3.5
mean(1,10,100,1000,10000)=2222.2
mean(9)=9
mean()=0

ActionScript[edit]

function mean(vector:Vector.<Number>):Number
{
	var sum:Number = 0;
	for(var i:uint = 0; i < vector.length; i++)
		sum += vector[i];
	return vector.length == 0 ? 0 : sum / vector.length;
}

Ada[edit]

This example shows how to pass a zero length vector as well as a larger vector. With Ada 2012 it is possible to check that pre conditions are satisfied (otherwise an exception is thrown). So we check that the length is not zero.

with Ada.Float_Text_Io; use Ada.Float_Text_Io;
with Ada.Text_IO; use Ada.Text_IO;

procedure Mean_Main is
   type Vector is array (Positive range <>) of Float;
   function Mean (Item : Vector) return float with pre => Item'length > 0;
   function Mean (Item : Vector) return Float is
      Sum : Float := 0.0;
   begin
      for I in Item'range loop
         Sum := Sum + Item(I);
      end loop;
	  return Sum / Float(Item'Length);
   end Mean;
   A : Vector := (3.0, 1.0, 4.0, 1.0, 5.0, 9.0);
begin
    Put(Item => Mean (A), Fore => 1, Exp => 0);
   New_Line;
   -- test for zero length vector
   Put(Item => Mean(A (1..0)), Fore => 1, Exp => 0);
   New_Line;
end Mean_Main;

Output: 3.83333

raised SYSTEM.ASSERTIONS.ASSERT_FAILURE : failed precondition from mean_main.adb:6

Aime[edit]

real
mean(list l)
{
    real sum, x;

    sum = 0;
    for (, x in l) {
        sum += x;
    }

    sum / ~l;
}

integer
main(void)
{
    o_form("%f\n", mean(list(4.5, 7.25, 5r, 5.75)));

    0;
}

ALGOL 68[edit]

Translation of: C
Works with: ALGOL 68 version Standard - no extensions to language used
Works with: ALGOL 68G version Any - tested with release mk15-0.8b.fc9.i386
Works with: ELLA ALGOL 68 version Any (with appropriate job cards) - tested with release 1.8.8d.fc9.i386 - note that some necessary LONG REAL operators are missing from ELLA's library.
PROC mean = (REF[]REAL p)REAL:
# Calculates the mean of qty REALs beginning at p. #
  IF LWB p > UPB p THEN 0.0
  ELSE 
    REAL total := 0.0;
    FOR i FROM LWB p TO UPB p DO total +:= p[i] OD;
    total / (UPB p - LWB p + 1)
  FI;
 
main:(
  [6]REAL test := (1.0, 2.0, 5.0, -5.0, 9.5, 3.14159);
  print((mean(test),new line))
)

ALGOL W[edit]

begin
    % procedure to find the mean of the elements of a vector.                %
    % As the procedure can't find the bounds of the array for itself,        %
    % we pass them in lb and ub          %
    real procedure mean ( real    array vector ( * )
                        ; integer value lb
                        ; integer value ub
                        ) ;
    begin
        real sum;
        assert( ub > lb ); % terminate the program if there are no elements  %
        sum := 0;
        for i := lb until ub do sum := sum + vector( i );
        sum / ( ( ub + 1 ) - lb )
    end mean ;

    % test the mean procedure by finding the mean of 1.1, 2.2, 3.3, 4.4, 5.5 %
    real array numbers ( 1 :: 5 );
    for i := 1 until 5 do numbers( i ) := i + ( i / 10 );
    r_format := "A"; r_w := 10; r_d := 2; % set fixed point output           %
    write( mean( numbers, 1, 5 ) );
end.

AmigaE[edit]

Because of the way Amiga E handles floating point numbers, the passed list/vector must contain all explicitly floating point values (e.g., you need to write "1.0", not "1")

PROC mean(l:PTR TO LONG)
  DEF m, i, ll
  ll := ListLen(l)
  IF ll = 0 THEN RETURN 0.0
  m := 0.0
  FOR i := 0 TO ll-1 DO m := !m + l[i]
  m := !m / (ll!)
ENDPROC m

PROC main()
  DEF s[20] : STRING
  WriteF('mean \s\n',
         RealF(s,mean([1.0, 2.0, 3.0, 4.0, 5.0]), 2))
ENDPROC

AntLang[edit]

AntLang has a built-in avg function.

avg[list]

APL[edit]

Works with: APL2
      X3 1 4 1 5 9
      (+/X)÷⍴X
3.833333333

AppleScript[edit]

Vanilla[edit]

With vanilla AppleScript, the process is the literal one of adding the numbers and dividing by the list length. It naturally returns results of class real, but it would be simple to return integer-representable results as integers if required.

on average(listOfNumbers)
    set len to (count listOfNumbers)
    if (len is 0) then return missing value
    
    set sum to 0
    repeat with thisNumber in listOfNumbers
        set sum to sum + thisNumber
    end repeat
    
    return sum / len
end average

average({2500, 2700, 2400, 2300, 2550, 2650, 2750, 2450, 2600, 2400})
Output:
2530.0

ASObjC[edit]

The vanilla method above is the more efficient with lists of up to around 100 numbers. But for longer lists, using Foundation methods with AppleScriptObjectC can be useful

use AppleScript version "2.4" -- OS X 10.10 (Yosemite) or later
use framework "Foundation"

on average(listOfNumbers)
    if ((count listOfNumbers) is 0) then return missing value
    
    set arrayOfNumbers to current application's class "NSArray"'s arrayWithArray:(listOfNumbers)
    return (arrayOfNumbers's valueForKeyPath:("@avg.self")) as real
end average

average({2500, 2700, 2400, 2300, 2550, 2650, 2750, 2450, 2600, 2400})
Output:
2530.0

Applesoft BASIC[edit]

REM COLLECTION IN DATA STATEMENTS, EMPTY DATA IS THE END OF THE COLLECTION
    0 READ V$
    1 IF LEN(V$) = 0 THEN END
    2 N = 0
    3 S = 0
    4 FOR I = 0 TO 1 STEP 0
    5     S = S + VAL(V$)
    6     N = N + 1
    7     READ V$
    8     IF LEN(V$) THEN NEXT
    9 PRINT S / N
10000 DATA1,2,2.718,3,3.142
63999 DATA

REM COLLECTION IN AN ARRAY, ITEM 0 IS THE SIZE OF THE COLLECTION
A(0) = 5 : A(1) = 1 : A(2) = 2 : A(3) = 2.718 : A(4) = 3 : A(5) = 3.142
N = A(0) : IF N THEN S = 0 : FOR I = 1 TO N : S = S + A(I) : NEXT : ? S / N

Arturo[edit]

arr: [1 2 3 4 5 6 7]
 
print average arr
Output:
4.0

Astro[edit]

mean([1, 2, 3])
mean(1..10)
mean([])

AutoHotkey[edit]

i = 10
Loop, % i {
  Random, v, -3.141592, 3.141592
  list .= v "`n"
  sum += v
}
MsgBox, % i ? list "`nmean: " sum/i:0

AWK[edit]

cat mean.awk
#!/usr/local/bin/gawk -f

# User defined function
function mean(v,      i,n,sum) {
  for (i in v) {
    n++
    sum += v[i]
  }
  if (n>0) {
    return(sum/n)
  } else {
    return("zero-length input !")
  }
}

BEGIN {
  # fill a vector with random numbers
  for(i=0; i < 10; i++) {
    vett[i] = rand()*10
  }
  print mean(vett)
  print mean(nothing)
}
Output:
$ awk -f mean.awk 
3.92689
zero-length input !

Babel[edit]

(3 24 18 427 483 49 14 4294 2 41) dup len <- sum ! -> / itod <<
Output:
535

BASIC[edit]

Works with: QBasic

Assume the numbers are in an array named "nums".

mean = 0
sum = 0;
FOR i = LBOUND(nums) TO UBOUND(nums)
   sum = sum + nums(i);
NEXT i
size = UBOUND(nums) - LBOUND(nums) + 1
PRINT "The mean is: ";
IF size <> 0 THEN
   PRINT (sum / size)
ELSE
   PRINT 0
END IF

BBC BASIC[edit]

To calculate the mean of an array:

      REM specific functions for the array/vector types
      
      REM Byte Array
      DEF FN_Mean_Arithmetic&(n&())
      = SUM(n&()) / (DIM(n&(),1)+1)
      
      REM Integer Array
      DEF FN_Mean_Arithmetic%(n%())
      = SUM(n%()) / (DIM(n%(),1)+1)
      
      REM Float 40 array
      DEF FN_Mean_Arithmetic(n())
      = SUM(n()) / (DIM(n(),1)+1)

      REM A String array
      DEF FN_Mean_Arithmetic$(n$())
      LOCAL I%, S%, sum, Q%
      S% = DIM(n$(),1)
      FOR I% = 0 TO S%
        Q% = TRUE
        ON ERROR LOCAL Q% = FALSE
        IF Q% sum += EVAL(n$(I%))
      NEXT
      = sum / (S%+1)
     
      REM Float 64 array
      DEF FN_Mean_Arithmetic#(n#())
      = SUM(n#()) / (DIM(n#(),1)+1)

Michael Hutton 14:02, 29 May 2011 (UTC)

IS-BASIC[edit]

100 NUMERIC ARR(3 TO 8)
110 LET ARR(3)=3:LET ARR(4)=1:LET ARR(5)=4:LET ARR(6)=1:LET ARR(7)=5:LET ARR(8)=9
120 PRINT AM(ARR)
130 DEF AM(REF A)
140   LET T=0
150   FOR I=LBOUND(A) TO UBOUND(A)
160     LET T=T+A(I)
170   NEXT
180   LET AM=T/SIZE(A)
190 END DEF

bc[edit]

Uses the current scale for calculating the mean.

define m(a[], n) {
    auto i, s

    for (i = 0; i < n; i++) {
        s += a[i]
    }
    return(s / n)
}

Befunge[edit]

The first input is the length of the vector. If a length of 0 is entered, the result is equal to 0/0.

&:0\:!v!:-1<
 @./\$_\&+\^

blz[edit]

:mean(vec)
    vec.fold_left(0, (x, y -> x + y)) / vec.length()
end

Bracmat[edit]

Here are two solutions. The first uses a while loop, the second scans the input by backtracking.

(mean1=
  sum length n
.   0:?sum:?length
  &   whl
    ' ( !arg:%?n ?arg
      & 1+!length:?length
      & !n+!sum:?sum
      )
  & !sum*!length^-1
);

(mean2=
  sum length n
.     0:?sum:?length
    &   !arg
      :   ?
          ( #%@?n
          & 1+!length:?length
          & !n+!sum:?sum
          & ~
          )
          ?
  | !sum*!length^-1
);

To test with a list of all numbers 1 .. 999999:

( :?test
& 1000000:?Length
& whl'(!Length+-1:?Length:>0&!Length !test:?test)
& out$mean1$!test
& out$mean2$!test
)

Brat[edit]

mean = { list |
  true? list.empty?, 0, { list.reduce(0, :+) / list.length }
}

p mean 1.to 10  #Prints 5.5

Burlesque[edit]

blsq ) {1 2 2.718 3 3.142}av
2.372
blsq ) {}av
NaN

BQN[edit]

Defines a tacit Avg function which works on any simple numeric list.

Avg ← +´÷≠

Avg 1‿2‿3‿4
2.5

Try It!

C[edit]

Compute mean of a double array of given length. If length is zero, does whatever 0.0/0 does (usually means returning NaN).

#include <stdio.h>

double mean(double *v, int len)
{
	double sum = 0;
	int i;
	for (i = 0; i < len; i++)
		sum += v[i];
	return sum / len;
}

int main(void)
{
	double v[] = {1, 2, 2.718, 3, 3.142};
	int i, len;
	for (len = 5; len >= 0; len--) {
		printf("mean[");
		for (i = 0; i < len; i++)
			printf(i ? ", %g" : "%g", v[i]);
		printf("] = %g\n", mean(v, len));
	}

	return 0;
}
Output:

mean[1, 2, 2.718, 3, 3.142] = 2.372 mean[1, 2, 2.718, 3] = 2.1795 mean[1, 2, 2.718] = 1.906 mean[1, 2] = 1.5 mean[1] = 1 mean[] = -nan

C#[edit]

using System;
using System.Linq;

class Program
{
    static void Main()
    {
        Console.WriteLine(new[] { 1, 2, 3 }.Average());
    }
}

Alternative version (not using the built-in function):

using System;

class Program
{
    static void Main(string[] args)
    {
        double average = 0;

        double[] numArray = { 1, 2, 3, 4, 5 };
        average = Average(numArray);

        Console.WriteLine(average); // Output is 3

        // Alternative use
        average = Average(1, 2, 3, 4, 5);

        Console.WriteLine(average); // Output is still 3
        Console.ReadLine();
    }

    static double Average(params double[] nums)
    {
        double d = 0;

        foreach (double num in nums)
            d += num;
        return d / nums.Length;
    }
}

C++[edit]

Library: STL
#include <vector>

double mean(const std::vector<double>& numbers)
{
     if (numbers.size() == 0)
          return 0;

     double sum = 0;
     for (std::vector<double>::iterator i = numbers.begin(); i != numbers.end(); i++)
          sum += *i;
     return sum / numbers.size();
}

Shorter (and more idiomatic) version:

#include <vector>
#include <algorithm>

double mean(const std::vector<double>& numbers)
{
    if (numbers.empty())
        return 0;
    return std::accumulate(numbers.begin(), numbers.end(), 0.0) / numbers.size();
}

Idiomatic version templated on any kind of iterator:

#include <iterator>
#include <algorithm>

template <typename Iterator>
double mean(Iterator begin, Iterator end)
{
    if (begin == end)
        return 0;
    return std::accumulate(begin, end, 0.0) / std::distance(begin, end);
}

Chef[edit]

Mean.

Chef has no way to detect EOF, so rather than interpreting
some arbitrary number as meaning "end of input", this program
expects the first input to be the sample size. Pass in the samples
themselves as the other inputs. For example, if you wanted to
compute the mean of 10, 100, 47, you could pass in 3, 10, 100, and
47. To test the "zero-length vector" case, you need to pass in 0.

Ingredients.
0 g Sample Size
0 g Counter
0 g Current Sample

Method.
Take Sample Size from refrigerator.
Put Sample Size into mixing bowl.
Fold Counter into mixing bowl.
Put Current Sample into mixing bowl.
Loop Counter.
Take Current Sample from refrigerator.
Add Current Sample into mixing bowl.
Endloop Counter until looped.
If Sample Size.
Divide Sample Size into mixing bowl.
Put Counter into 2nd mixing bowl.
Fold Sample Size into 2nd mixing bowl.
Endif until ifed.
Pour contents of mixing bowl into baking dish.

Serves 1.

Clojure[edit]

Returns a ratio:

(defn mean [sq]
  (if (empty? sq)
      0
      (/ (reduce + sq) (count sq))))

Returns a float:

(defn mean [sq]
  (if (empty? sq)
      0
      (float (/ (reduce + sq) (count sq)))))

COBOL[edit]

Intrinsic function:

FUNCTION MEAN(some-table (ALL))

Sample implementation:

       IDENTIFICATION DIVISION.
       PROGRAM-ID. find-mean.

       DATA DIVISION.
       LOCAL-STORAGE SECTION.
       01  i                       PIC 9(4).
       
       01  summ                    USAGE FLOAT-LONG.
       
       LINKAGE SECTION.
       01  nums-area.
           03  nums-len            PIC 9(4).
           03  nums                USAGE FLOAT-LONG
                                   OCCURS 0 TO 1000 TIMES
                                   DEPENDING ON nums-len.
                                  
       01  result                  USAGE FLOAT-LONG.

       PROCEDURE DIVISION USING nums-area, result.
           IF nums-len = 0
               MOVE 0 TO result
               GOBACK
           END-IF

           DIVIDE FUNCTION SUM(nums (ALL)) BY nums-len GIVING result

           GOBACK
           .

Cobra[edit]

class Rosetta
	def mean(ns as List<of number>) as number
		if ns.count == 0
			return 0
		else
			sum = 0.0
			for n in ns 
				sum += n
			return sum / ns.count

	def main
		print "mean of [[]] is [.mean(List<of number>())]"
		print "mean of [[1,2,3,4]] is [.mean([1.0,2.0,3.0,4.0])]"

Output:

mean of [] is 0
mean of [1, 2, 3, 4] is 2.5

CoffeeScript[edit]

mean = (array) ->
 return 0 if array.length is 0
 sum = array.reduce (s,i,0) -> s += i
 sum / array.length
 
 
alert mean [1]

Common Lisp[edit]

With Reduce

(defun mean (&rest sequence)
  (when sequence
    (/ (reduce #'+ sequence) (length sequence))))

With Loop

(defun mean (list)
  (when list
    (/ (loop for i in list sum i)
       (length list))))

Crystal[edit]

# Crystal will return NaN if an empty array is passed
def mean(arr) : Float64
  arr.sum / arr.size.to_f
end

D[edit]

Imperative Version[edit]

real mean(Range)(Range r) pure nothrow @nogc {
    real sum = 0.0;
    int count;

    foreach (item; r) {
        sum += item;
        count++;
    }

    if (count == 0)
        return 0.0;
    else
        return sum / count;
}

void main() {
    import std.stdio;

    int[] data;
    writeln("Mean: ", data.mean);
    data = [3, 1, 4, 1, 5, 9];
    writeln("Mean: ", data.mean);
}
Output:
mean: 0
mean: 3.83333

More Functional Version[edit]

import std.stdio, std.algorithm, std.range;

real mean(Range)(Range r) pure nothrow @nogc {
    return r.sum / max(1.0L, r.count);
}

void main() {
    writeln("Mean: ", (int[]).init.mean);
    writeln("Mean: ", [3, 1, 4, 1, 5, 9].mean);
}
Output:
Mean: 0
Mean: 3.83333

More Precise Version[edit]

A (naive?) version that tries to minimize precision loss (but already the sum algorithm applied to a random access range of floating point values uses a more precise summing strategy):

import std.stdio, std.conv, std.algorithm, std.math, std.traits;

CommonType!(T, real) mean(T)(T[] n ...) if (isNumeric!T) {
    alias E = CommonType!(T, real);
    auto num = n.dup;
    num.schwartzSort!(abs, "a > b");
    return num.map!(to!E).sum(0.0L) / max(1, num.length);
}

void main() {
    writefln("%8.5f", mean((int[]).init));
    writefln("%8.5f", mean(     0, 3, 1, 4, 1, 5, 9, 0));
    writefln("%8.5f", mean([-1e20, 3, 1, 4, 1, 5, 9, 1e20]));
}
Output:
 0.00000
 2.87500
 2.87500

Dart[edit]

num mean(List<num> l) => l.reduce((num p, num n) => p + n) / l.length;

void main(){
  print(mean([1,2,3,4,5,6,7]));
}
Output:
4.0

dc[edit]

This is not a translation of the bc solution. Array handling would add some complexity. This one-liner is similar to the K solution.

1 2 3 5 7 zsn1k[+z1<+]ds+xln/p
3.6

An expanded example, identifying an empty sample set, could be created as a file, e.g., amean.cd:

[[Nada Mean: ]Ppq]sq
zd0=qsn [stack length = n]sz
1k [precision can be altered]sz
[+z1<+]ds+x[Sum: ]Pp
ln/[Mean: ]Pp
[Sample size: ]Plnp

By saving the sample set "1 2 3 5 7" in a file (sample.dc), the routine, listing summary information, could be called in a command line:

$ dc sample.dc amean.cd
Sum: 18
Mean: 3.6
Sample size: 5
$

Delphi[edit]

program AveragesArithmeticMean;

{$APPTYPE CONSOLE}

uses Types;

function ArithmeticMean(aArray: TDoubleDynArray): Double;
var
  lValue: Double;
begin
  Result := 0;

  for lValue in aArray do
    Result := Result + lValue;
  if Result > 0 then
    Result := Result / Length(aArray);
end;

begin
  Writeln(Mean(TDoubleDynArray.Create()));
  Writeln(Mean(TDoubleDynArray.Create(1,2,3,4,5)));
end.

Dyalect[edit]

func avg(args...) {
    var acc = .0
    var len = 0
    for x in args {
        len += 1
        acc += x
    }
    acc / len
}

avg(1, 2, 3, 4, 5, 6)

E[edit]

Slightly generalized to support any object that allows iteration.

def meanOrZero(numbers) {
    var count := 0
    var sum := 0
    for x in numbers {
        sum += x
        count += 1
    }
    return sum / 1.max(count)
}

EasyLang[edit]

func mean . f[] r .
  for i = 1 to len f[]
    s += f[i]
  .
  r = s / len f[]
.
f[] = [ 1 2 3 4 5 6 7 8 ]
call mean f[] r
print r

EchoLisp[edit]

(mean values) is included in math.lib. values may be a list, vector, sequence, or any kind of procrastinator.

(lib 'math)
(mean '(1 2 3 4)) ;; mean of a list
     2.5
(mean #(1 2 3 4)) ;; mean of a vector
     2.5

(lib 'sequences)
(mean [1 3 .. 10]) ;; mean of a sequence
     5

;; error handling
(mean 'elvis)
     error: mean : expected sequence : elvis
(mean ())
    💣 error: mean : null is not an object
(mean #())
    😐 warning: mean : zero-divide : empty-vector
     0
(mean [2 2 .. 2])
    😁 warning: mean : zero-divide : empty-sequence
     0

ECL[edit]

AveVal(SET OF INTEGER s) := AVE(s);
 
//example usage

SetVals := [14,9,16,20,91];
AveVal(SetVals) //returns 30.0 ;

Elena[edit]

ELENA 5.0:

import extensions;

extension op
{
    average()
    {
        real sum := 0;
        int count := 0;
        
        var enumerator := self.enumerator();
        
        while (enumerator.next())
        {
            sum += enumerator.get();
            count += 1;
        };
        
        ^ sum / count
    }
}

public program()
{
    var array := new int[]{1, 2, 3, 4, 5, 6, 7, 8};
    console.printLine(
        "Arithmetic mean of {",array.asEnumerable(),"} is ",
        array.average()).readChar()
}
Output:
Arithmetic mean of {1,2,3,4,5,6,7,8} is 4.5

Elixir[edit]

defmodule Average do
  def mean(list), do: Enum.sum(list) / length(list)
end

Emacs Lisp[edit]

(defun mean (lst)
  (/ (float (apply '+ lst)) (length lst)))
(mean '(1 2 3 4))
Library: Calc
(let ((x '(1 2 3 4)))
  (calc-eval "vmean($1)" nil (append '(vec) x)))

Erlang[edit]

mean([]) -> 0;
mean(L)  -> lists:sum(L)/erlang:length(L).

Euphoria[edit]

function mean(sequence s)
  atom sum
  if length(s) = 0 then
    return 0
  else
    sum = 0
    for i = 1 to length(s) do
      sum += s[i]
    end for
    return sum/length(s)
  end if
end function

sequence test
test = {1.0, 2.0, 5.0, -5.0, 9.5, 3.14159}
? mean(test)

Excel[edit]

Assuming the values are entered in the A column, type into any cell which will not be part of the list:

=AVERAGE(A1:A10)

Assuming 10 values will be entered, alternatively, you can just type:

=AVERAGE(

and then select the start and end cells, not necessarily in the same row or column.

The output for the first expression, for the set {x | 1 <= x <= 10, x E N} is

1	5,5
2	
3	
4	
5	
6	
7	
8	
9	
10	

F#[edit]

The following computes the running mean using a tail-recursive approach. If we just sum all the values then divide by the number of values then we will suffer from overflow problems for large lists. See wikipedia about the moving average computation.

let avg (a:float) (v:float) n =
    a + (1. / ((float n) + 1.)) * (v - a)

let mean_series list =
    let a, _ = List.fold_left (fun (a, n) h -> avg a (float h) n, n + 1) (0., 0) list in
    a

Checking this:

 > mean_series [1; 8; 2; 8; 1; 7; 1; 8; 2; 7; 3; 6; 1; 8; 100] ;;
 val it : float = 10.86666667
 > mean_series [] ;;
 val it : float = 0.0

We can also make do with the built-in List.average function:

List.average [4;1;7;5;8;4;5;2;1;5;2;5]

Factor[edit]

USING: math math.statistics ;

: arithmetic-mean ( seq -- n )
    [ 0 ] [ mean ] if-empty ;

Tests:

( scratchpad ) { 2 3 5 } arithmetic-mean >float
3.333333333333333

Fantom[edit]

class Main
{
  static Float average (Float[] nums)
  {
    if (nums.size == 0) return 0.0f
    Float sum := 0f
    nums.each |num| { sum += num }
    return sum / nums.size.toFloat
  }

  public static Void main ()
  {
    [[,], [1f], [1f,2f,3f,4f]].each |Float[] i|
    {
      echo ("Average of $i is: " + average(i))
    }
  }
}

Fish[edit]

!vl0=?vl1=?vl&!
v<  +<>0n; >n;
>l1)?^&,n;

Must be called with the values pre-populated on the stack, which can be done in the fish.py interpreter with the -v switch:

fish.py mean.fish -v 10 100 47 207.4

which generates:

91.1

Forth[edit]

: fmean ( addr n -- f )
  0e
  dup 0= if 2drop exit then
  tuck floats bounds do
    i f@ f+
  1 floats +loop
  0 d>f f/ ;

create test 3e f, 1e f, 4e f, 1e f, 5e f, 9e f,
test 6 fmean f.     \ 3.83333333333333

Fortran[edit]

In ISO Fortran 90 or later, use the SUM intrinsic, the SIZE intrinsic and the MAX intrinsic (to avoid divide by zero):

real, target, dimension(100) :: a = (/ (i, i=1, 100) /)
real, dimension(5,20) :: b = reshape( a, (/ 5,20 /) )
real, pointer, dimension(:) :: p => a(2:1)       ! pointer to zero-length array
real :: mean, zmean, bmean
real, dimension(20) :: colmeans
real, dimension(5) :: rowmeans

mean = sum(a)/size(a)                ! SUM of A's elements divided by SIZE of A
mean = sum(a)/max(size(a),1)         ! Same result, but safer code
                                     ! MAX of SIZE and 1 prevents divide by zero if SIZE == 0 (zero-length array)

zmean = sum(p)/max(size(p),1)        ! Here the safety check pays off. Since P is a zero-length array,
                                     ! expression becomes "0 / MAX( 0, 1 ) -> 0 / 1 -> 0", rather than "0 / 0 -> NaN"

bmean = sum(b)/max(size(b),1)        ! multidimensional SUM over multidimensional SIZE

rowmeans = sum(b,1)/max(size(b,2),1) ! SUM elements in each row (dimension 1)
                                     ! dividing by the length of the row, which is the number of columns (SIZE of dimension 2)
colmeans = sum(b,2)/max(size(b,1),1) ! SUM elements in each column (dimension 2)
                                     ! dividing by the length of the column, which is the number of rows (SIZE of dimension 1)

FreeBASIC[edit]

' FB 1.05.0 Win64

Function Mean(array() As Double) As Double
  Dim length As Integer = Ubound(array) - Lbound(array) + 1
  If length = 0 Then
    Return 0.0/0.0 'NaN
  End If
  Dim As Double sum = 0.0
  For i As Integer = LBound(array) To UBound(array)
    sum += array(i)
  Next
  Return sum/length
End Function

Function IsNaN(number As Double) As Boolean
  Return Str(number) = "-1.#IND" ' NaN as a string in FB
End Function

Dim As Integer n, i
Dim As Double num
Print "Sample input and output"
Print
Do
  Input "How many numbers are to be input ? : ", n
Loop Until n > 0
Dim vector(1 To N) As Double
Print
For i = 1 to n
  Print "  Number #"; i; " : ";
  Input "", vector(i)
Next
Print
Print "Mean is"; Mean(vector())
Print
Erase vector
num = Mean(vector())
If IsNaN(num) Then
  Print "After clearing the vector, the mean is 'NaN'"
End If
Print
Print "Press any key to quit the program"
Sleep
Output:
Sample input and output

How many numbers are to be input ? : 6

  Number # 1 : 12
  Number # 2 : 18
  Number # 3 : 5.6
  Number # 4 : 6
  Number # 5 : 23
  Number # 6 : 17

Mean is 13.6

After clearing the vector, the mean is 'NaN'

Frink[edit]

The following works on arrays or sets. If the collection is empty, this returns the special value undef.

mean[x] := length[x] > 0 ? sum[x] / length[x] : undef


FutureBasic[edit]

local fn MeanAverageOfNumberArray( numberArr as CFArrayRef ) as CFStringRef
  CFStringRef result = NULL
  if len(numberArr) == 0 then result = @"Mean undefined for empty array." : exit fn
  result = fn StringWithFormat( @"Mean average of %d numbers: %@", len(numberArr), fn ObjectValueForKeyPath( numberArr, @"@avg.self" ) )
end fn = result

CFArrayRef numberArray
numberArray = @[@1, @2, @3, @4, @5, @6, @7, @8, @9, @10]
print fn MeanAverageOfNumberArray( numberArray )
numberArray = @[@3, @1, @4, @1, @5, @9]
print fn MeanAverageOfNumberArray( numberArray )

HandleEvents
Output:
Mean average of 10 numbers: 5.5
Man average of 6 numbers: 3.83333333333333333333333333333333333333


GAP[edit]

Mean := function(v)
  local n;
  n := Length(v);
  if n = 0 then
    return 0;
  else
    return Sum(v)/n;
  fi;
end;

Mean([3, 1, 4, 1, 5, 9]);
# 23/6

GEORGE[edit]

R (n) P ;
0
1, n rep (i)
   R P +
]
n div
P

Output:

 7.000000000000000      
 1.500000000000000E+0001
 1.300000000000000E+0001
 8.000000000000000      
 2.500000000000000E+0001
 7.400000000000000E+0001
 3.100000000000000E+0001
 2.900000000000000E+0001
 1.700000000000000E+0001
 4.300000000000000E+0001
 2.620000000000000E+0001

GFA Basic[edit]

This works for arrays of integers.

DIM a%(10)
FOR i%=0 TO 10
  a%(i%)=i%*2
  PRINT "element ";i%;" is ";a%(i%)
NEXT i%
PRINT "mean is ";@mean(a%)
'
FUNCTION mean(a%)
  LOCAL i%,size%,sum
  ' find size of array,
  size%=DIM?(a%())
  ' return 0 for empty arrays
  IF size%<=0
    RETURN 0
  ENDIF
  ' find sum of all elements
  sum=0
  FOR i%=0 TO size%-1
    sum=sum+a%(i%)
  NEXT i%
  ' mean is sum over size
  RETURN sum/size%
ENDFUNC

Go[edit]

A little more elaborate that the task requires. The function "mean" fulfills the task of "a program to find the mean." As a Go idiom, it returns an ok value of true if result m is valid. An ok value of false means the input "vector" (a Go slice) was empty. The fancy accuracy preserving algorithm is a little more than was called more. The program main is a test program demonstrating the ok idiom and several data cases.

package main

import (
    "fmt"
    "math"
)

func mean(v []float64) (m float64, ok bool) {
    if len(v) == 0 {
        return
    }
    // an algorithm that attempts to retain accuracy
    // with widely different values.
    var parts []float64
    for _, x := range v {
        var i int
        for _, p := range parts {
            sum := p + x
            var err float64
            switch ax, ap := math.Abs(x), math.Abs(p); {
            case ax < ap:
                err = x - (sum - p)
            case ap < ax:
                err = p - (sum - x)
            }
            if err != 0 {
                parts[i] = err
                i++
            }
            x = sum
        }
        parts = append(parts[:i], x)
    }
    var sum float64
    for _, x := range parts {
        sum += x
    }
    return sum / float64(len(v)), true
}

func main() {
    for _, v := range [][]float64{
        []float64{},                         // mean returns ok = false
        []float64{math.Inf(1), math.Inf(1)}, // answer is +Inf

        // answer is NaN, and mean returns ok = true, indicating NaN
        // is the correct result
        []float64{math.Inf(1), math.Inf(-1)},

        []float64{3, 1, 4, 1, 5, 9},

        // large magnitude numbers cancel. answer is mean of small numbers.
        []float64{1e20, 3, 1, 4, 1, 5, 9, -1e20},

        []float64{10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0, 0, 0, 0, .11},
        []float64{10, 20, 30, 40, 50, -100, 4.7, -11e2},
    } {
        fmt.Println("Vector:", v)
        if m, ok := mean(v); ok {
            fmt.Printf("Mean of %d numbers is %g\n\n", len(v), m)
        } else {
            fmt.Println("Mean undefined\n")
        }
    }
}
Output:
Vector: []
Mean undefined

Vector: [+Inf +Inf]
Mean of 2 numbers is +Inf

Vector: [+Inf -Inf]
Mean of 2 numbers is NaN

Vector: [3 1 4 1 5 9]
Mean of 6 numbers is 3.8333333333333335

Vector: [1e+20 3 1 4 1 5 9 -1e+20]
Mean of 8 numbers is 2.875

Vector: [10 9 8 7 6 5 4 3 2 1 0 0 0 0 0.11]
Mean of 15 numbers is 3.674

Vector: [10 20 30 40 50 -100 4.7 -1100]
Mean of 8 numbers is -130.6625

Groovy[edit]

def avg = { list -> list == [] ? 0 : list.sum() / list.size() }

Test Program:

println avg(0..9)
println avg([2,2,2,4,2])
println avg ([])

Output:

4.5
2.4
0

Haskell[edit]

This function works if the element type is an instance of Fractional:

mean :: (Fractional a) => [a] -> a
mean [] = 0
mean xs = sum xs / Data.List.genericLength xs

But some types, e.g. integers, are not Fractional; the following function works for all Real types:

meanReals :: (Real a, Fractional b) => [a] -> b
meanReals = mean . map realToFrac

If you want to avoid keeping the list in memory and traversing it twice:

{-# LANGUAGE BangPatterns #-}

import Data.List (foldl') --'

mean
  :: (Real n, Fractional m)
  => [n] -> m
mean xs =
  let (s, l) =
        foldl' --'
          f
          (0, 0)
          xs
  in realToFrac s / l
  where
    f (!s, !l) x = (s + x, l + 1)

main :: IO ()
main = print $ mean [1 .. 100]

HicEst[edit]

REAL :: vec(100)               ! no zero-length arrays in HicEst

   vec = $ - 1/2               ! 0.5 ... 99.5
   mean = SUM(vec) / LEN(vec)  ! 50
END

Hy[edit]

Returns None if the input is of length zero.

(defn arithmetic-mean [xs]
    (if xs
        (/ (sum xs) (len xs))))

Icon and Unicon[edit]

procedure main(args)
    every (s := 0) +:= !args
    write((real(s)/(0 ~= *args)) | 0)
end

Sample outputs:

->am 1 2 3 4 5 6 7
4.0
->am
0
->

IDL[edit]

If truly only the mean is wanted, one could use

x = [3,1,4,1,5,9]
print,mean(x)

But mean() is just a thin wrapper returning the zeroth element of moment() :

print,moment(x)
; ==>
  3.83333      8.96667     0.580037     -1.25081

which are mean, variance, skewness and kurtosis.

There are no zero-length vectors in IDL. Every variable has at least one value or otherwise it is <Undefined>.

J[edit]

mean=: +/ % #

That is, sum divided by the number of items. The verb also works on higher-ranked arrays. For example:

   mean 3 1 4 1 5 9
3.83333
   mean $0         NB. $0 is a zero-length vector
0
   x=: 20 4 ?@$ 0  NB. a 20-by-4 table of random (0,1) numbers
   mean x
0.58243 0.402948 0.477066 0.511155

The computation can also be written as a loop. It is shown here for comparison only and is highly non-preferred compared to the version above.

mean1=: 3 : 0
 z=. 0
 for_i. i.#y do. z=. z+i{y end.
 z % #y
)
   mean1 3 1 4 1 5 9
3.83333
   mean1 $0
0
   mean1 x
0.58243 0.402948 0.477066 0.511155

Java[edit]

Works with: Java version 1.5+
public static double avg(double... arr) {
    double sum = 0.0;
    for (double x : arr) {
        sum += x;
    }
    return sum / arr.length;
}

JavaScript[edit]

ES5[edit]

function mean(array)
{
 var sum = 0, i;
 for (i = 0; i < array.length; i++)
 {
  sum += array[i];
 }
  return array.length ? sum / array.length : 0;
}

alert( mean( [1,2,3,4,5] ) );   // 3
alert( mean( [] ) );            // 0

Using the native function `.forEach()`:

function mean(array) {
    var sum = 0;
    array.forEach(function(value){
        sum += value;
        });
    return array.length ? sum / array.length : 0;
    }

alert( mean( [1,2,3,4,5] ) );   // 3

Using the native function `.reduce()`:

function mean(array) {
    return !array.length ? 0
        : array.reduce(function(pre, cur, i) {
            return (pre * i + cur) / (i + 1);
            });
    }

alert( mean( [1,2,3,4,5] ) );   // 3
alert( mean( [] ) );            // 0

Extending the `Array` prototype:

Array.prototype.mean = function() {
    return !this.length ? 0
        : this.reduce(function(pre, cur, i) {
            return (pre * i + cur) / (i + 1);
            });
    }

alert( [1,2,3,4,5].mean() );   // 3
alert( [].mean() );            // 0


Library: Functional
function mean(a)
{
 return a.length ? Functional.reduce('+', 0, a) / a.length : 0;
}


ES6[edit]

(sample => {

    // mean :: [Num] => (Num | NaN)
    let mean = lst => {
        let lng = lst.length;

        return lng ? (
            lst.reduce((a, b) => a + b, 0) / lng
        ) : NaN;
    };
    
    return mean(sample);

})([1, 2, 3, 4, 5, 6, 7, 8, 9]);
Output:
5

jq[edit]

The mean of an array of numbers can be computed by simply writing

add/length

This definition raises an error condition if the array is empty, so it may make sense to define mean as follows, null being jq's null value:

def mean: if length == 0 then null 
  else add/length
  end;

Julia[edit]

Julia's built-in mean function accepts AbstractArrays (vector, matrix, etc.)

julia> using Statistics; mean([1,2,3])
2.0
julia> mean(1:10)
5.5
julia> mean([])
ERROR: mean of empty collection undefined: []

K[edit]

  mean: {(+/x)%#x}
  mean 1 2 3 5 7
3.6
  mean@!0    / empty array
0.0

Kotlin[edit]

Kotlin has builtin functions for some collection types. Example:

fun main(args: Array<String>) {
    val nums = doubleArrayOf(1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0, 9.0, 10.0)
    println("average = %f".format(nums.average()))
}

KQL[edit]

let dataset = datatable(values:real)[
                        1,      1.5,    3,  5,      6.5];

dataset|summarize avg(values)

Output:

	
avg_values
3.4

LabVIEW[edit]

This image is a VI Snippet, an executable image of LabVIEW code. The LabVIEW version is shown on the top-right hand corner. You can download it, then drag-and-drop it onto the LabVIEW block diagram from a file browser, and it will appear as runnable, editable code.
LabVIEW Averages Arithmetic mean.png

Lambdatalk[edit]

{def mean
 {lambda {:s}
  {if {S.empty? :s}
   then 0
   else {/ {+ :s} {S.length :s}}}}}

{mean {S.serie 0 1000}}
-> 500

langur[edit]

The built-in mean() function works with an array, hash, or range of numbers.

We could use fold() to write a function that takes an array and calculates the mean.

Works with: langur version 0.6.6
val .mean = f(.x) fold(f{+}, .x) / len(.x)

writeln "  custom: ", .mean([7, 3, 12])
writeln "built-in: ", mean([7, 3, 12])
Output:
  custom: 7.333333333333333333333333333333333
built-in: 7.333333333333333333333333333333333

Lasso[edit]

define average(a::array) => {
	not #a->size ? return 0
	local(x = 0.0)
	with i in #a do => { #x += #i }
	return #x / #a->size
}

average(array(1,2,5,17,7.4)) //6.48

LFE[edit]

1-Arity[edit]

(defun mean (data)
  (/ (lists:sum data)
     (length data)))

Usage:

> (mean '(1 1))
1.0
> (mean '(1 2))
1.5
> (mean '(2 10))
6.0
> (mean '(6 12 18 24 30 36 42 48 54 60 66 72 78))
42.0

n-Arity[edit]

Functions in LFE (and Erlang) have set arity, but macros can be used to provide the same use as n-arity functions:

(defmacro mean args
  `(/ (lists:sum ,args)
      ,(length args)))

Usage:

> (mean 42)
42.0
> (mean 18 66)
42.0
> (mean 6 12 18 24 30 36 42 48 54 60 66 72 78)
42.0

Liberty BASIC[edit]

total=17
dim nums(total)
for i = 1 to total
    nums(i)=i-1
next

for j = 1 to total
    sum=sum+nums(j)
next
if total=0 then mean=0 else mean=sum/total
print "Arithmetic mean: ";mean

Limbo[edit]

implement Command;

include "sys.m";
sys: Sys;

include "draw.m";

include "sh.m";

init(nil: ref Draw->Context, nil: list of string)
{
	sys = load Sys Sys->PATH;

	a := array[] of {1.0, 2.0, 500.0, 257.0};
	sys->print("mean of a: %f\n", getmean(a));
}

getmean(a: array of real): real
{
	n: real = 0.0;
	for (i := 0; i < len a; i++)
		n += a[i];
	return n / (real len a);
}

Lingo[edit]

-- v can be (2D) point, (3D) vector or list of integers/floats
on mean (v)
    case ilk(v) of
        #point: cnt = 2
        #vector: cnt = 3
        #list: cnt = v.count
        otherwise: return
    end case
    sum = 0
    repeat with i = 1 to cnt
        sum = sum + v[i]
    end repeat
    return float(sum)/cnt
end
put mean(point(1, 2.5))
-- 1.7500
put mean(vector(1.2, 4.7, 5.6))
-- 3.8333
put mean([6,12,18,24,30,36,42,48,54,60,66,72,78])
-- 42.0000

LiveCode[edit]

Livecode provides arithmeticMean (avg, average) built-in.

average(1,2,3,4,5)  -- 3
average(empty)  -- 0

[edit]

to average :l
  if empty? :l [output 0]
  output quotient apply "sum :l count :l
end
print average [1 2 3 4]    ; 2.5

Logtalk[edit]

Logtalk's standard library provides an arithmetic average predicate but we ignore it here. Representing a vector using a list:

:- object(averages).

    :- public(arithmetic/2).

    % fails for empty vectors
    arithmetic([X| Xs], Mean) :-
        sum_and_count([X| Xs], 0, Sum, 0, Count),
        Mean is Sum / Count.

    % use accumulators to make the predicate tail-recursive
    sum_and_count([], Sum, Sum, Count, Count).
    sum_and_count([X| Xs], Sum0, Sum, Count0, Count) :-
        Sum1 is Sum0 + X,
        Count1 is Count0 + 1,
        sum_and_count(Xs, Sum1, Sum, Count1, Count).

:- end_object.

Sample output:

| ?- averages::arithmetic([1,2,3,4,5,6,7,8,9,10], Mean).
Mean = 5.5
yes

LSL[edit]

integer MAX_ELEMENTS = 10;
integer MAX_VALUE = 100;
default {
    state_entry() {
        list lst = [];
        integer x = 0;
        for(x=0 ; x<MAX_ELEMENTS ; x++) {
            lst += llFrand(MAX_VALUE);
        }
        llOwnerSay("lst=["+llList2CSV(lst)+"]");
        llOwnerSay("Geometric Mean: "+(string)llListStatistics(LIST_STAT_GEOMETRIC_MEAN, lst));
        llOwnerSay("           Max: "+(string)llListStatistics(LIST_STAT_MAX, lst));
        llOwnerSay("          Mean: "+(string)llListStatistics(LIST_STAT_MEAN, lst));
        llOwnerSay("        Median: "+(string)llListStatistics(LIST_STAT_MEDIAN, lst));
        llOwnerSay("           Min: "+(string)llListStatistics(LIST_STAT_MIN, lst));
        llOwnerSay("     Num Count: "+(string)llListStatistics(LIST_STAT_NUM_COUNT, lst));
        llOwnerSay("         Range: "+(string)llListStatistics(LIST_STAT_RANGE, lst));
        llOwnerSay("       Std Dev: "+(string)llListStatistics(LIST_STAT_STD_DEV, lst));
        llOwnerSay("           Sum: "+(string)llListStatistics(LIST_STAT_SUM, lst));
        llOwnerSay("   Sum Squares: "+(string)llListStatistics(LIST_STAT_SUM_SQUARES, lst));
    }
}

Output:

lst=[23.815209, 85.890704, 10.811144, 31.522696, 54.619416, 12.211729, 42.964463, 87.367889, 7.106129, 18.711078]
Geometric Mean:    27.325070
           Max:    87.367889
          Mean:    37.502046
        Median:    27.668953
           Min:     7.106129
     Num Count:    10.000000
         Range:    80.261761
       Std Dev:    29.819840
           Sum:   375.020458
   Sum Squares: 22067.040048

Lua[edit]

function mean (numlist)
    if type(numlist) ~= 'table' then return numlist end
    num = 0
    table.foreach(numlist,function(i,v) num=num+v end)
    return num / #numlist
end

print (mean({3,1,4,1,5,9}))

Lucid[edit]

avg(x)
 where 
    sum = first(x) fby sum + next(x);
    n = 1 fby n + 1;
    avg = sum / n;
 end

M4[edit]

M4 handle only integers, so in order to have a slightly better math for the mean, we must pass to the mean macro integers multiplied by 100. The macro rmean could embed the macro fmean and extractdec directly, but it is a little bit clearer to keep them separated.

define(`extractdec', `ifelse(eval(`$1%100 < 10'),1,`0',`')eval($1%100)')dnl
define(`fmean', `eval(`($2/$1)/100').extractdec(eval(`$2/$1'))')dnl
define(`mean', `rmean(`$#', $@)')dnl
define(`rmean', `ifelse(`$3', `', `fmean($1,$2)',dnl
`rmean($1, eval($2+$3), shift(shift(shift($@))))')')dnl
mean(0,100,200,300,400,500,600,700,800,900,1000)

Maple[edit]

This version accepts any indexable structure, including numeric arrays. We use a call to the "environment variable" (dynamically scoped global) "Normalizer" to provide normalization of symbolic expressions. This can be set by the caller to adjust the strength of normalization desired.

mean := proc( a :: indexable )
        local   i;
        Normalizer( add( i, i in a ) / numelems( a ) )
end proc:

For example:

> mean( { 1/2, 2/3, 3/4, 4/5, 5/6 } ); # set
                                  71
                                  ---
                                  100

> mean( [ a, 2, c, 2.3, e ] ); # list
                     0.8600000000 + a/5 + c/5 + e/5

> mean( Array( [ 1, sin( s ), 3, exp( I*t ), 5 ] ) ); # array
                    9/5 + 1/5 sin(s) + 1/5 exp(t I)

> mean( [ sin(s)^2, cos(s)^2 ] );
                                 2             2
                       1/2 sin(s)  + 1/2 cos(s)

> Normalizer := simplify: # use a stronger normalizer than the default
> mean( [ sin(s)^2, cos(s)^2 ] );
                                  1/2

> mean([]); # empty argument causes an exception to be raised.
Error, (in mean) numeric exception: division by zero

A slightly different design computes the mean of all its arguments, instead of requiring a single container argument. This seems a little more Maple-like for a general purpose utility.

mean := () -> Normalizer( `+`( args ) / nargs ):

This can be called as in the following examples.

> mean( 1, 2, 3, 4, 5 );
                                   3

> mean( a + b, b + c, c + d, d + e, e + a );
                      2 a   2 b   2 c   2 d   2 e
                      --- + --- + --- + --- + ---
                       5     5     5     5     5

> mean(); # again, an exception is raised
Error, (in mean) numeric exception: division by zero

If desired, we can add argument type-checking as follows.

mean := ( s :: seq(algebraic) ) -> Normalizer( `+`( args ) / nargs ):

Mathematica / Wolfram Language[edit]

Modify the built-in Mean function to give 0 for empty vectors (lists in Mathematica):

Unprotect[Mean];
Mean[{}] := 0

Examples:

Mean[{3,4,5}]
Mean[{3.2,4.5,5.9}]
Mean[{-4, 1.233}]
Mean[{}]
Mean[{1/2,1/3,1/4,1/5}]
Mean[{a,c,Pi,-3,a}]

gives (a set of integers gives back an integer or a rational, a set of floats gives back a float, a set of rationals gives a rational back, a list of symbols and numbers keeps the symbols exact and a mix of exact and approximate numbers gives back an approximate number):

4
4.53333
-1.3835
0
77/240
1/5 (-3+2 a+c+Pi)

Mathprog[edit]

Summing the vector and then dividing the sum by the vector's length is slightly less boring than calling a builtin function Mean or similar.

Mathprog is never boring so this program finds a number M such that when M is subtracted from each value in the vector a second vector is formed with the property that the sum of the elements in the second vector is zero. In this case M is the Arithmetic Mean.

Euclid proved that for any vector there is only one such number and from this derived the Division Theorem.

To make it more interesting I find the Arithmectic Mean of more than a million Integers.

/*Arithmetic Mean of a large number of Integers
  - or - solve a very large constraint matrix
         over 1 million rows and columns
  Nigel_Galloway
  March 18th., 2008.
*/

param e := 20;
set Sample := {1..2**e-1};

var Mean;
var E{z in Sample};

/* sum of variances is zero */
zumVariance: sum{z in Sample} E[z] = 0;

/* Mean + variance[n] = Sample[n] */
variances{z in Sample}: Mean + E[z] = z;

solve;

printf "The arithmetic mean of the integers from 1 to %d is %f\n", 2**e-1, Mean;

end;

When run this produces:

GLPSOL: GLPK LP/MIP Solver, v4.47
Parameter(s) specified in the command line:
 --nopresol --math AM.mprog
Reading model section from AM.mprog...
24 lines were read
Generating zumVariance...
Generating variances...
Model has been successfully generated
Scaling...
 A: min|aij| = 1.000e+000  max|aij| = 1.000e+000  ratio = 1.000e+000
Problem data seem to be well scaled
Constructing initial basis...
Size of triangular part = 1048575
GLPK Simplex Optimizer, v4.47
1048576 rows, 1048576 columns, 3145725 non-zeros
      0: obj =  0.000000000e+000  infeas = 5.498e+011 (1)
*     1: obj =  0.000000000e+000  infeas = 0.000e+000 (0)
OPTIMAL SOLUTION FOUND
Time used:   2.0 secs
Memory used: 1393.8 Mb (1461484590 bytes)
The arithmetic mean of the integers from 1 to 1048575 is 524288.000000
Model has been successfully processed

MATLAB[edit]

function meanValue = findmean(setOfValues)
   meanValue = mean(setOfValues);
end

Maxima[edit]

load("descriptive");
mean([2, 7, 11, 17]);

MAXScript[edit]

fn mean data =
(
    total = 0
    for i in data do
    (
        total += i
    )
    if data.count == 0 then 0 else total as float/data.count
)

print (mean #(3, 1, 4, 1, 5, 9))

Mercury[edit]

:- module arithmetic_mean.
:- interface.

:- import_module io.

:- pred main(io::di, io::uo) is det.

:- implementation.

:- import_module float, list, require.

main(!IO) :-
    io.print_line(mean([1.0, 2.0, 3.0, 4.0, 5.0]), !IO).

:- func mean(list(float)) = float.

mean([]) = func_error("mean: emtpy list").
mean(Ns @ [_ | _]) = foldl((+), Ns, 0.0) / float(length(Ns)).

:- end_module arithmetic_mean.

Alternatively, we could use inst subtyping to ensure we get a compilation error if the mean function is called with an empty list.

:- func mean(list(float)::in(non_empty_list)) = (float::out).

mean(Ns) = foldl((+), Ns, 0.0) / float(length(Ns)).

min[edit]

Returns nan for an empty quotation.

Works with: min version 0.19.3
(((0 (+) reduce) (size /)) cleave) :mean
(2 3 5) mean print
Output:
3.333333333333334

MiniScript[edit]

arr = [ 1, 3, 7, 8, 9, 1 ]

avg = function(arr)
    avgNum = 0
    for num in arr
        avgNum = avgNum + num
    end for
    return avgNum / arr.len
end function

print avg(arr)

МК-61/52[edit]

0	П0	П1	С/П	ИП0	ИП1	*	+	ИП1	1
+	П1	/	П0	БП	03

Instruction: В/О С/П Number С/П Number ...

Each time you press the С/П on the indicator would mean already entered numbers.

Modula-2[edit]

PROCEDURE  Avg;

VAR     avg             : REAL;

BEGIN
   avg := sx / n;
   InOut.WriteString ("Average = ");
   InOut.WriteReal (avg, 8, 2);
   InOut.WriteLn
END Avg;

OR

PROCEDURE Average (Data  : ARRAY OF REAL;   Samples : CARDINAL) : REAL;

(*  Calculate the average over 'Samples' values, stored in array 'Data'.     *)

VAR     sum         : REAL;
        n           : CARDINAL;

BEGIN
  sum := 0.0;
  FOR n := 0 TO Samples - 1 DO
    sum := sum + Data [n]
  END;
  RETURN sum / FLOAT(Samples)
END Average;

MUMPS[edit]

MEAN(X)
 ;X is assumed to be a list of numbers separated by "^"
 QUIT:'$DATA(X) "No data"
 QUIT:X="" "Empty Set"
 NEW S,I
 SET S=0,I=1
 FOR  QUIT:I>$L(X,"^")  SET S=S+$P(X,"^",I),I=I+1
 QUIT (S/$L(X,"^"))
USER>W $$MEAN^ROSETTA
No data
USER>W $$MEAN^ROSETTA("")
Empty Set
USER>
 
USER>W $$MEAN^ROSETTA("1^6^12^4")
5.75

Nanoquery[edit]

def sum(lst)
        sum = 0
        for n in lst
                sum += n
        end
        return sum
end

def average(x)
        return sum(x) / len(x)
end

Nemerle[edit]

using System;
using System.Console;
using Nemerle.Collections;

module Mean
{
    ArithmeticMean(x : list[int]) : double
    {
        |[] => 0.0
        |_  =>(x.FoldLeft(0, _+_) :> double) / x.Length
    }
    
    Main() : void
    {
        WriteLine("Mean of [1 .. 10]: {0}", ArithmeticMean($[1 .. 10]));
    }
}

NetRexx[edit]

/* NetRexx */
options replace format comments java crossref symbols nobinary

launchSample()
return

-- ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
method arithmeticMean(vv = Vector) public static signals DivideException returns Rexx
  sum = 0
  n_ = Rexx
  loop n_ over vv
    sum = sum + n_
    end n_
  mean = sum / vv.size()

  return mean

-- ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
method launchSample() public static
  TRUE_  = 1 == 1
  FALSE_ = \TRUE_
  tracing = FALSE_
  vectors = getSampleData()
  loop v_ = 0 to vectors.length - 1
    say 'Average of:' vectors[v_].toString()
    do
      say '          =' arithmeticMean(vectors[v_])
    catch dex = DivideException
      say 'Caught "Divide By Zero"; bypassing...'
      if tracing then dex.printStackTrace()
    catch xex = RuntimeException
      say 'Caught unspecified run-time exception; bypassing...'
      if tracing then xex.printStackTrace()
    end
    say
    end v_
  return

-- ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
method getSampleData() private static returns Vector[]
  seed = 1066
  rng = Random(seed)
  vectors =[ -
    Vector(Arrays.asList([Rexx 1, 2, 3, 4, 5, 6, 7, 8, 9, 10])), -
    Vector(), -
    Vector(Arrays.asList([Rexx rng.nextInt(seed), rng.nextInt(seed), rng.nextInt(seed), rng.nextInt(seed), rng.nextInt(seed), rng.nextInt(seed)])), -
    Vector(Arrays.asList([Rexx rng.nextDouble(), rng.nextDouble(), rng.nextDouble(), rng.nextDouble(), rng.nextDouble(), rng.nextDouble(), rng.nextDouble()])), -
    Vector(Arrays.asList([Rexx '1.0', '2.0', 3.0])), -
    Vector(Arrays.asList([Rexx '1.0', 'not a number', 3.0])) -
    ]
  return vectors

Output:

Average of: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
          = 5.5

Average of: []
Caught "Divide By Zero"; bypassing...

Average of: [294, 726, 945, 828, 1031, 825]
          = 774.833333

Average of: [0.3318379308729921, 0.7612271993941618, 0.9517290891755477, 0.7687823629521795, 0.2201768257213939, 0.1083471020993242, 0.5158554699332363]
          = 0.52256514

Average of: [1.0, 2.0, 3.0]
          = 2

Average of: [1.0, not a number, 3.0]
Caught unspecified run-time exception; bypassing...

NewLISP[edit]

(define (Mean Lst)
   (if (empty? Lst)
      0
      (/ (apply + Lst) (length Lst)))) 
 
 (Mean (sequence 1 1000))-> 500
 (Mean '()) -> 0

Nial[edit]

in the standard way, mean is

mean is / [sum, tally] 

mean 6 2 4 
= 4

but it fails with 0 length vectors. so using a tally with a minimum value 1

dtally is recur [ empty rest, 1 first, 1 first, plus, rest ]
mean is / [sum, dtally]

mean []
=0

Nim[edit]

Translation of: C
import strutils

proc mean(xs: openArray[float]): float =
  for x in xs:
    result += x
  result = result / float(xs.len)

var v = @[1.0, 2.0, 2.718, 3.0, 3.142]
for i in 0..5:
  echo "mean of first ", v.len, " = ", formatFloat(mean(v), precision = 0)
  if v.len > 0: v.setLen(v.high)

Output:

mean of first 5 = 2.372
mean of first 4 = 2.1795
mean of first 3 = 1.906
mean of first 2 = 1.5
mean of first 1 = 1
mean of first 0 = -1.#IND

Niue[edit]

[ [ , len 1 - at ! ] len 3 - times swap , ] 'map ; ( a Lisp like map, to sum the stack )
[ len 'n ; [ + ] 0 n swap-at map n / ] 'avg ;

1 2 3 4 5 avg .
=> 3
3.4 2.3 .01 2.0 2.1 avg .
=> 1.9619999999999997

Oberon-2[edit]

Oxford Oberon-2

MODULE AvgMean;
IMPORT Out;
CONST MAXSIZE = 10;
PROCEDURE Avg(a: ARRAY OF REAL; items: INTEGER): REAL;
VAR
	i: INTEGER;
	total: REAL;
BEGIN
	total := 0.0;
	FOR i := 0 TO LEN(a) -  1 DO
		total := total + a[i]
	END;
	RETURN total/LEN(a)
END Avg;
VAR
	ary: ARRAY MAXSIZE OF REAL;
BEGIN
	ary[0] := 10.0;
	ary[1] := 11.01;
	ary[2] := 12.02;
	ary[3] := 13.03;
	ary[4] := 14.04;
	ary[5] := 15.05;
	ary[6] := 16.06;
	ary[7] := 17.07;
	ary[8] := 18.08;
	ary[9] := 19.09;
	Out.Fixed(Avg(ary),4,2);Out.Ln
END AvgMean.

Output:

14.55

Objeck[edit]

function : native : PrintAverage(values : FloatVector) ~ Nil {
  values->Average()->PrintLine();
}

OCaml[edit]

These functions return a float:

let mean_floats = function
  | [] -> 0.
  | xs -> List.fold_left (+.) 0. xs /. float_of_int (List.length xs)

let mean_ints xs = mean_floats (List.map float_of_int xs)

the previous code is easier to read and understand, though if you wish the fastest implementation to use in production code notice several points: it is possible to save a call to List.length computing the length through the List.fold_left, and for mean_ints it is possible to save calling float_of_int on every numbers, converting only the result of the addition. (also when using List.map and when the order is not important, you can use List.rev_map instead to save an internal call to List.rev). Also the task asks to return 0 on empty lists, but in OCaml this case would rather be handled by an exception.

let mean_floats xs =
  if xs = [] then
    invalid_arg "empty list"
  else
    let total, length =
      List.fold_left
        (fun (tot,len) x -> (x +. tot), len +. 1.)
        (0., 0.) xs
    in
    (total /. length)
;;


let mean_ints xs =
  if xs = [] then
    invalid_arg "empty list"
  else
    let total, length =
      List.fold_left
        (fun (tot,len) x -> (x + tot), len +. 1.)
        (0, 0.) xs
    in
    (float total /. length)
;;

Octave[edit]

GNU Octave has a mean function (from statistics package), but it does not handle an empty vector; an implementation that allows that is:

function m = omean(l)
  if ( numel(l) == 0 )
    m = 0;
  else
    m = mean(l);
  endif
endfunction

disp(omean([]));
disp(omean([1,2,3]));

If the data contains missing value, encoded as non-a-number:

function m = omean(l)
     n = sum(~isnan(l));
     l(isnan(l))=0;
     s = sum(l);
     m = s./n; 
end;

Oforth[edit]

: avg ( x -- avg )
   x sum 
   x size dup ifZero: [ 2drop null ] else: [ >float / ]
;
Output:
[1, 2, 2.718, 3, 3.142] avg .
2.372 ok
[ ] avg .
null ok

ooRexx[edit]

call testAverage .array~of(10, 9, 8, 7, 6, 5, 4, 3, 2, 1)
call testAverage .array~of(10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0, 0, 0, 0, .11)
call testAverage .array~of(10, 20, 30, 40, 50, -100, 4.7, -11e2)
call testAverage .array~new

::routine testAverage
  use arg numbers
  say "numbers =" numbers~toString("l", ", ")
  say "average =" average(numbers)
  say

::routine average
  use arg numbers
  -- return zero for an empty list
  if numbers~isempty then return 0

  sum = 0
  do number over numbers
      sum += number
  end
  return sum/numbers~items

Output:

numbers = 10, 9, 8, 7, 6, 5, 4, 3, 2, 1
average = 5.5

numbers = 10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0, 0, 0, 0, .11
average = 3.674

numbers = 10, 20, 30, 40, 50, -100, 4.7, -1100
average = -130.6625

numbers =
average = 0

Oz[edit]

A version working on floats:

declare
  fun {Mean Xs}
     {FoldL Xs Number.'+' 0.0} / {Int.toFloat {Length Xs}}
  end 
in
  {Show {Mean [3. 1. 4. 1. 5. 9.]}}

PARI/GP[edit]

avg(v)={
  if(#v,vecsum(v)/#v)
};

Pascal[edit]

Program Mean;

  function DoMean(vector: array of double): double;
  var
    sum: double;
    i, len: integer;
  begin
    sum := 0;
    len := length(vector);
    if len > 0 then
      begin
      for i := low(vector) to high(vector) do
	sum := sum + vector[i];
      sum := sum / len;
      end;
     DoMean := sum;
  end;

const
  vector: array [3..8] of double = (3.0, 1.0, 4.0, 1.0, 5.0, 9.0);
var
  i: integer;
begin
  writeln('Calculating the arithmetic mean of a series of numbers:');
  write('Numbers: [ ');
  for i := low(vector) to high(vector) do
    write (vector[i]:3:1, ' ');
  writeln (']');
  writeln('Mean: ', DoMean(vector):10:8);
end.

Output:

Calculating the arithmetic mean of a series of numbers:
Numbers: [ 3.0 1.0 4.0 1.0 5.0 9.0 ]
Mean: 3.83333333

Alternative version using the Math unit:

Program DoMean;
uses math;
const
  vector: array [3..8] of double = (3.0, 1.0, 4.0, 1.0, 5.0, 9.0);
var
  i: integer;
  mean: double;
begin
  writeln('Calculating the arithmetic mean of a series of numbers:');
  write('Numbers: [ ');
  for i := low(vector) to high(vector) do
    write (vector[i]:3:1, ' ');
  writeln (']');
  mean := 0;
  if length(vector) > 0 then
    mean := sum(vector)/length(vector);
  writeln('Mean: ', mean:10:8);
end.

Perl[edit]

sub avg {
  @_ or return 0;
  my $sum = 0;
  $sum += $_ foreach @_;
  return $sum/@_;
}
 
print avg(qw(3 1 4 1 5 9)), "\n";

Phix[edit]

with javascript_semantics
function mean(sequence s)
    if length(s)=0 then return 0 end if
    return sum(s)/length(s)
end function
 
? mean({1, 2, 5, -5, -9.5, 3.14159})

Phixmonti[edit]

1 2 5 -5 -9.5 3.14159 stklen tolist
len swap sum swap / print

PHP[edit]

$nums = array(3, 1, 4, 1, 5, 9);
if ($nums)
    echo array_sum($nums) / count($nums), "\n";
else
    echo "0\n";


Picat[edit]

mean([]) = false.
mean(V) = sum(V) / len(V).

PicoLisp[edit]

(de mean (Lst)
   (if (atom Lst)
      0
      (/ (apply + Lst) (length Lst)) ) )

Output:

: (mean (range 1 1000))
-> 500

PL/I[edit]

arithmetic_mean = sum(A)/dimension(A,1);

Plain English[edit]

To run:
Start up.
Demonstrate finding the arithmetic mean.
Wait for the escape key.
Shut down.

An entry is a thing with a fraction.
A list is some entries.
A sum is a fraction.
A mean is a fraction.

To demonstrate finding the arithmetic mean:
Create an example list.
Write "A list: " then the example list on the console.
Find a mean of the example list.
Write "The list's mean: " then the mean on the console.
Destroy the example list.

To add a fraction to a list:
Allocate memory for an entry.
Put the fraction into the entry's fraction.
Append the entry to the list.

To create an example list:
Add 1/1 to the example list.
Add 2/1 to the example list.
Add 5-1/3 to the example list.
Add 7-1/2 to the example list.

To find a sum of a list:
Put 0 into the sum.
Get an entry from the list.
Loop.
If the entry is nil, exit.
Add the entry's fraction to the sum.
Put the entry's next into the entry.
Repeat.

To find a mean of a list:
Find a sum of the list.
Put the sum divided by the list's count into the mean.

To convert a list to a string:
Get an entry from the list.
Loop.
If the entry is nil, break.
Append the entry's fraction to the string.
If the entry's next is not nil, append ", " to the string.
Put the entry's next into the entry.
Repeat.
Output:
A list: 1, 2, 5-1/3, 7-1/2
The list's mean: 3-23/24

Pop11[edit]

define mean(v);
    lvars n = length(v), i, s = 0;
    if n = 0 then
        return(0);
    else
        for i from 1 to n do
            s + v(i) -> s;
        endfor;
    endif;
    return(s/n);
enddefine;

PostScript[edit]

/findmean{
/x exch def
/sum 0 def
/i 0 def
x length 0 eq
{}
{
x length{
/sum sum x i get add def
/i i 1 add def
}repeat
/sum sum x length div def
}ifelse
sum ==
}def
Library: initlib
Works with: Ghostscript
/avg {
    dup length
    {0 gt} {
       exch 0 {add} fold exch div 
    } {
        exch pop 
    } ifte
}.

PowerShell[edit]

The hard way by calculating a sum and dividing:

function mean ($x) {
    if ($x.Count -eq 0) {
        return 0
    } else {
        $sum = 0
        foreach ($i in $x) {
            $sum += $i
        }
        return $sum / $x.Count
    }
}

or, shorter, by using the Measure-Object cmdlet which already knows how to compute an average:

function mean ($x) {
    if ($x.Count -eq 0) {
        return 0
    } else {
        return ($x | Measure-Object -Average).Average
    }
}

Processing[edit]

float mean(float[] arr) {
  float out = 0;
  for (float n : arr) {
    out += n;
  }
  return out / arr.length;
}

Prolog[edit]

Works with: SWI-Prolog version 6.6
mean(List, Mean) :-
    length(List, Length),
    sumlist(List, Sum),
    Mean is Sum / Length.

PureBasic[edit]

Procedure.d mean(List number())
  Protected sum=0

  ForEach number()
    sum + number()
  Next
  ProcedureReturn sum / ListSize(number())
  ; Depends on programm if zero check needed, returns nan on division by zero
EndProcedure

Python[edit]

Works with: Python version 3.0
.
Works with: Python version 2.6

Uses fsum which tracks multiple partial sums to avoid losing precision

from math import fsum
def average(x):
    return fsum(x)/float(len(x)) if x else 0
print (average([0,0,3,1,4,1,5,9,0,0]))
print (average([1e20,-1e-20,3,1,4,1,5,9,-1e20,1e-20]))
Output:
2.3
2.3


Works with: Python version 2.5
def average(x):
    return sum(x)/float(len(x)) if x else 0
print (average([0,0,3,1,4,1,5,9,0,0]))
print (average([1e20,-1e-20,3,1,4,1,5,9,-1e20,1e-20]))
Output:

(Notice how the second call gave the wrong result)

2.3
1e-21


Works with: Python version 2.4
def avg(data):
    if len(data)==0:
        return 0
    else:
        return sum(data)/float(len(data))
print avg([0,0,3,1,4,1,5,9,0,0])
Output:
2.3
Works with: Python version 3.4

Since 3.4, Python has a [statistics library in the stdlib, which takes care of these precision overflow issues in a way that works for all standard types, not just float, even with values way too big or small to fit in a float. (For Python 2.6-2.7, there's a backport available on PyPI.)

>>> from statistics import mean
>>> mean([1e20,-1e-20,3,1,4,1,5,9,-1e20,1e-20])
2.3
>>> mean([10**10000, -10**10000, 3, 1, 4, 1, 5, 9, 0, 0])
2.3
>>> mean([10**10000, -10**10000, 3, 1, 4, 1, 5, 9, Fraction(1, 10**10000), Fraction(-1, 10**10000)])
Fraction(23, 10)
>>> big = 10**10000
>>> mean([Decimal(big), Decimal(-big), 3, 1, 4, 1, 5, 9, 1/Decimal(big), -1/Decimal(big)])
Decimal('2.3')

Q[edit]

A built-in solution is avg. An implementation of it could be:

mean:{(sum x)%count x}

Quackery[edit]

Using the Quackery big number rational arithmetic library bigrat.qky.

  [ $ 'bigrat.qky' loadfile ] now!
 
  [ [] swap times
    [ 20001 random 10000 -
      n->v 100 n->v v/
      join nested join ] ]   is makevector   (   --> [   )
 
  [ witheach 
      [ unpack 
        2 point$ echo$
        i 0 > if 
          [ say ", " ] ] ]   is echodecs      ( [ -->     )

  [ dup size n->v rot
    0 n->v rot
    witheach 
      [ unpack v+ ]
    2swap v/ ]               is arithmean    ( [ --> n/d )

  [ 5 makevector  
  
    say "Internal representation of a randomly generated vector" cr
    say "of five rational numbers. They are distributed between" cr
    say "-100.00 and +100.00 and are multiples of 0.01."
    cr cr dup echo cr cr
    say "Shown as decimal fractions."
    cr cr dup echodecs cr cr
 
    arithmean
 
    say "Arithmetic mean of vector as a decimal fraction to" cr 
    say "5 places after the point, as a rounded proper" cr
    say "fraction with the denominator not exceeding 10, and" cr
    say "finally as a vulgar fraction without rounding." cr cr
    2dup 5 point$ echo$
    say ", "
    2dup proper 10 round improper
    proper$ echo$
    say ", "
    vulgar$ echo$ cr cr
 
    say "The same, but with a vector of 9973 rational numbers," cr
    say "20 decimal places and a denominator not exceeding 100." cr cr
 
    9973 makevector arithmean
 
    2dup 20 point$ echo$
    say ", "
    2dup proper 100 round improper
    proper$ echo$
    say ", "
    vulgar$ echo$ cr ]       is demonstrate  (   -->     )
Output:
Internal representation of a randomly generated vector
of five rational numbers. They are distributed between
-100.00 and +100.00 and are multiples of 0.01.
 
[ [ -1999 100 ] [ 253 50 ] [ 2867 50 ] [ 3929 50 ] [ -25 2 ] ]
 
Shown as decimal fractions.
 
-19.99, 5.06, 57.34, 78.58, -12.5
 
Arithmetic mean of vector as a decimal fraction to
5 places after the point, as a rounded proper
fraction with the denominator not exceeding 10, and
finally as a vulgar fraction without rounding.
 
21.698, 21 7/10, 10849/500
 
The same, but with a vector of 9973 rational numbers,
20 decimal places and a denominator not exceeding 100.
 
-0.41664995487817106187, -5/12, -16621/39892

R[edit]

R has its mean function but it does not allow for NULL (void vectors or whatever) as argument: in this case it raises a warning and the result is NA. An implementation that does not suppress the warning could be:

omean <- function(v) {
  m <- mean(v)
  ifelse(is.na(m), 0, m)
}

Racket[edit]

Racket's math library (available in v5.3.2 and newer) comes with a mean function that works on arbitrary sequences.

#lang racket
(require math)

(mean (in-range 0 1000)) ; -> 499 1/2
(mean '(2 2 4 4))        ; -> 3
(mean #(3 4 5 8))        ; -> 5

Raku[edit]

(formerly Perl 6)

Works with: Rakudo version 2015.10-11
multi mean([]){ Failure.new('mean on empty list is not defined') }; # Failure-objects are lazy exceptions
multi mean (@a) { ([+] @a) / @a }

Rapira[edit]

fun mean(arr)
  sum := 0
  for N from 1 to #arr do
    sum := sum + arr[N]
  od
  return (sum / #arr)
end

REBOL[edit]

rebol [
    Title: "Arithmetic Mean (Average)"
    URL: http://rosettacode.org/wiki/Average/Arithmetic_mean
]

average: func [v /local sum][
	if empty? v [return 0]

	sum: 0
	forall v [sum: sum + v/1]
	sum / length? v
]

; Note precision loss as spread increased.

print [mold x: [] "->" average x]
print [mold x: [3 1 4 1 5 9] "->" average x]
print [mold x: [1000 3 1 4 1 5 9 -1000] "->" average x]
print [mold x: [1e20 3 1 4 1 5 9 -1e20] "->" average x]

Output:

[] -> 0
[3 1 4 1 5 9] -> 3.83333333333333
[1000 3 1 4 1 5 9 -1000] -> 2.875
[1E+20 3 1 4 1 5 9 -1E+20] -> 0.0

Red[edit]

Red comes with the average function.

Red ["Arithmetic mean"]

print average []
print average [2 3 5]
Output:
none
3.333333333333334

The source code for average:

average: func [
    "Returns the average of all values in a block" 
    block [block! vector! paren! hash!]
][
    if empty? block [return none] 
    divide sum block to float! length? block
]

ReScript[edit]

let arr = [3, 8, 4, 1, 5, 12]

let num = Js.Array.length(arr)
let tot = Js.Array.reduce(\"+", 0, arr)
let mean = float_of_int(tot) /. float_of_int(num)

Js.log(Js.Float.toString(mean))
Output:
$ bsc arithmean.res > arithmean.js
$ node arithmean.js
5.5

REXX[edit]

The vectors (list) can contain any valid (REXX) numbers.

A check is made to validate if the numbers in the list are all numeric.

/*REXX program finds the averages/arithmetic mean of several lists (vectors) or CL input*/
parse arg @.1; if @.1=''  then do;   #=6                         /*vector from the C.L.?*/
                               @.1 =   10 9 8 7 6 5 4 3 2 1
                               @.2 =   10 9 8 7 6 5 4 3 2 1 0 0 0 0  .11
                               @.3 =  '10 20 30 40 50  -100  4.7  -11e2'
                               @.4 =  '1 2 3 4  five  6 7 8 9  10.1.  ±2'
                               @.5 =  'World War I  &  World War II'
                               @.6 =                             /*  ◄─── a null value. */
                               end
                          else #=1                               /*number of CL vectors.*/
     do j=1  for #
     say '       numbers = '   @.j
     say '       average = '   avg(@.j)
     say copies('═', 79)
     end   /*t*/
exit                                             /*stick a fork in it,  we're all done. */
/*──────────────────────────────────────────────────────────────────────────────────────*/
avg: procedure;  parse arg x;     #=words(x)                      /*#:  number of items.*/
     if #==0  then return  'N/A: ───[null vector.]'               /*No words? Return N/A*/
     $=0
          do k=1  for #;      _=word(x,k)                         /*obtain a number.    */
          if datatype(_,'N')  then do;  $=$+_;  iterate;   end    /*if numeric, then add*/
          say left('',40) "***error***  non-numeric: " _;  #=#-1  /*error; adjust number*/
          end   /*k*/

     if #==0  then return  'N/A: ───[no numeric values.]'         /*No nums?  Return N/A*/
     return $ / #                                                 /*return the average. */

output   when using the (internal) lists:

       numbers =  10 9 8 7 6 5 4 3 2 1
       average =  5.5
═══════════════════════════════════════════════════════════════════════════════
       numbers =  10 9 8 7 6 5 4 3 2 1 0 0 0 0 .11
       average =  3.674
═══════════════════════════════════════════════════════════════════════════════
       numbers =  10 20 30 40 50  -100  4.7  -11e2
       average =  -130.6625
═══════════════════════════════════════════════════════════════════════════════
       numbers =  1 2 3 4  five  6 7 8 9  10.1.  ±2
                                         ***error***  non-numeric:  five
                                         ***error***  non-numeric:  10.1.
                                         ***error***  non-numeric:  ±2
       average =  5
═══════════════════════════════════════════════════════════════════════════════
       numbers =  World War I  &  World War II
                                         ***error***  non-numeric:  World
                                         ***error***  non-numeric:  War
                                         ***error***  non-numeric:  I
                                         ***error***  non-numeric:  &
                                         ***error***  non-numeric:  World
                                         ***error***  non-numeric:  War
                                         ***error***  non-numeric:  II
       average =  N/A: ───[no numeric values.]
═══════════════════════════════════════════════════════════════════════════════
       numbers =
       average =  N/A: ───[null vector.]
═══════════════════════════════════════════════════════════════════════════════

Ring[edit]

nums = [1,2,3,4,5,6,7,8,9,10]
sum = 0
see "Average = " + average(nums) + nl

func average numbers
     for i = 1 to len(numbers)
         sum = sum + nums[i]
     next
     return sum/len(numbers)

RPL/2[edit]

This is a simple rewrite of the dc version above. This works on an HP 48. "->" is a single right arrow character on the 48. Feel free to alter this code as necessary to work on RPL/2.

1 2 3 5 7
AMEAN
   << DEPTH DUP 'N' STO ->LIST ΣLIST N / >>
3.6

Ruby[edit]

def mean(nums)
  nums.sum(0.0) / nums.size
end

nums = [3, 1, 4, 1, 5, 9]
nums.size.downto(0) do |i|
  ary = nums[0,i]
  puts "array size #{ary.size} : #{mean(ary)}"
end
Output:
array size 6 : 3.8333333333333335
array size 5 : 2.8
array size 4 : 2.25
array size 3 : 2.6666666666666665
array size 2 : 2.0
array size 1 : 3.0
array size 0 : NaN

Run BASIC[edit]

print "Gimme the number in the array:";input numArray
dim value(numArray)
for i = 1 to numArray
    value(i) = i * 1.5
next
 
for i = 1 to total
    totValue = totValue +value(numArray)
next
if totValue <> 0 then mean = totValue/numArray
print "The mean is: ";mean

Rust[edit]

fn sum(arr: &[f64]) -> f64 {
    arr.iter().fold(0.0, |p,&q| p + q)
}

fn mean(arr: &[f64]) -> f64 {
    sum(arr) / arr.len() as f64
}

fn main() {
    let v = &[2.0, 3.0, 5.0, 7.0, 13.0, 21.0, 33.0, 54.0];
    println!("mean of {:?}: {:?}", v, mean(v));

    let w = &[];
    println!("mean of {:?}: {:?}", w, mean(w));
}

Output:

mean of [2, 3, 5, 7, 13, 21, 33, 54]: 17.25
mean of []: NaN

Sather[edit]

Built to work with VEC, ("geometric" vectors), whose elements must be floats. A 0-dimension vector yields "nan".

class VECOPS is
  mean(v:VEC):FLT is
    m ::= 0.0;
    loop m := m + v.aelt!; end;
    return m / v.dim.flt;
  end;
end;

class MAIN is
  main is
    v ::= #VEC(|1.0, 5.0, 7.0|);
    #OUT + VECOPS::mean(v) + "\n";
  end;
end;

Scala[edit]

Using Scala 2.7, this has to be defined for each numeric type:

def mean(s: Seq[Int]) = s.foldLeft(0)(_+_) / s.size

However, Scala 2.8 gives much more flexibility, but you still have to opt between integral types and fractional types. For example:

def mean[T](s: Seq[T])(implicit n: Integral[T]) = {
  import n._
  s.foldLeft(zero)(_+_) / fromInt(s.size)
}

This can be used with any subclass of Sequence on integral types, up to and including BigInt. One can also create singletons extending Integral for user-defined numeric classes. Likewise, Integral can be replaced by Fractional in the code to support fractional types, such as Float and Double.

Alas, Scala 2.8 also simplifies the task in another way:

def mean[T](s: Seq[T])(implicit n: Fractional[T]) = n.div(s.sum, n.fromInt(s.size))

Here we show a function that supports fractional types. Instead of importing the definitions from n, we are calling them on n itself. And because we did not import them, the implicit definitions that would allow us to use / were not imported as well. Finally, we use sum instead of foldLeft.

Scheme[edit]

(define (mean l)
  (if (null? l)
      0
      (/ (apply + l) (length l))))
> (mean (list 3 1 4 1 5 9))
3 5/6

Seed7[edit]

$ include "seed7_05.s7i";
  include "float.s7i";

const array float: numVector is [] (1.0, 2.0, 3.0, 4.0, 5.0);

const func float: mean (in array float: numbers) is func
  result
    var float: result is 0.0;
  local
    var float: total is 0.0;
    var float: num is 0.0;
  begin
    if length(numbers) <> 0 then
      for num range numbers do
        total +:= num;
      end for;
      result := total / flt(length(numbers));
    end if;
  end func;

const proc: main is func
  begin
    writeln(mean(numVector));
  end func;

SenseTalk[edit]

SenseTalk has a built-in average function.

put the average of [12,92,-17,66,128]

put average(empty)
Output:
56.2
     nan

Sidef[edit]

func avg(Array list) {
    list.len > 0 || return 0;
    list.sum / list.len;
}

say avg([Math.inf, Math.inf]);
say avg([3,1,4,1,5,9]);
say avg([1e+20, 3, 1, 4, 1, 5, 9, -1e+20]);
say avg([10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0, 0, 0, 0, 0.11]);
say avg([10, 20, 30, 40, 50, -100, 4.7, -1100]);
Output:
inf
3.833333333333333333333333333333333333333
2.875
3.674
-130.6625

Slate[edit]

[|:list| (list reduce: #+ `er ifEmpty: [0]) / (list isEmpty ifTrue: [1] ifFalse: [list size])] applyWith: #(3 1 4 1 5 9).
[|:list| (list reduce: #+ `er ifEmpty: [0]) / (list isEmpty ifTrue: [1] ifFalse: [list size])] applyWith: {}.

Smalltalk[edit]

| numbers |

numbers := #(1 2 3 4 5 6 7 8).
(numbers isEmpty 
    ifTrue:[0] 
    ifFalse: [
         (numbers inject: 0 into: [:sumSoFar :eachElement | sumSoFar + eachElement]) / numbers size ]
) displayNl.

However, the empty check can be omitted, as inject returns the injected value for empty collections, and we probably do not care for the average of nothing (i.e. the division by zero exception):

| numbers |

numbers := #(1 2 3 4 5 6 7 8).
( numbers inject: 0 into: [:sumSoFar :eachElement | sumSoFar + eachElement]) / numbers size] ) displayNl.

also, most Smalltalk's collection classes already provide sum and average methods, which makes it:

Works with: Pharo
Works with: Smalltalk/X
| numbers |

numbers := #(1 2 3 4 5 6 7 8).
(numbers sum / numbers size) displayNl.

or

| numbers |

numbers := #(1 2 3 4 5 6 7 8).
numbers average displayNl.

SNOBOL4[edit]

Works with: Macro Spitbol
Works with: Snobol4+
Works with: CSnobol
        define('avg(a)i,sum') :(avg_end)
avg     i = i + 1; sum = sum + a<i> :s(avg)
        avg = 1.0 * sum / prototype(a) :(return)
avg_end

*       # Fill arrays
        str = '1 2 3 4 5 6 7 8 9 10'; arr = array(10)
loop    i = i + 1; str len(p) span('0123456789') . arr<i> @p :s(loop)
        empty = array(1) ;* Null vector

*       # Test and display
        output = '[' str '] -> ' avg(arr)
        output = '[ ] -> ' avg(empty)
end

Output:

[1 2 3 4 5 6 7 8 9 10] -> 5.5
[ ] -> 0.

SQL[edit]

Tested on Oracle 11gR2, the more limited the tool, the more resourceful one becomes :)

create table "numbers" ("datapoint" integer);

insert into "numbers" select rownum from tab;

select sum("datapoint")/count(*)  from "numbers";

...or...

select avg("datapoint") from "numbers";

Standard ML[edit]

These functions return a real:

fun mean_reals [] = 0.0
  | mean_reals xs = foldl op+ 0.0 xs / real (length xs);

val mean_ints = mean_reals o (map real);

The previous code is easier to read and understand, though if you want the fastest implementation to use in production code notice several points: it is possible to save a call to length computing the length through the foldl, and for mean_ints it is possible to save calling real on every numbers, converting only the result of the addition. Also the task asks to return 0 on empty lists, but in Standard ML this case would rather be handled by an exception.

fun mean_reals [] = raise Empty
  | mean_reals xs = let
    val (total, length) =
      foldl
        (fn (x, (tot,len)) => (x + tot, len + 1.0))
        (0.0, 0.0) xs
    in
      (total / length)
    end;


fun mean_ints [] = raise Empty
  | mean_ints xs = let
    val (total, length) =
      foldl
        (fn (x, (tot,len)) => (x + tot, len + 1.0))
        (0, 0.0) xs
    in
      (real total / length)
    end;

Stata[edit]

Mean of a dataset variable[edit]

Illustration of the mean on the population (in millions) in january 2016 of a few european countries (source Eurostat).

clear all
input str20 country population
Belgium 11311.1
Bulgaria 7153.8
"Czech Republic" 10553.8
Denmark 5707.3
Germany 82175.7
Estonia 1315.9
Ireland 4724.7
Greece 10783.7
end

. mean population

Mean estimation                   Number of obs   =          8

--------------------------------------------------------------
             |       Mean   Std. Err.     [95% Conf. Interval]
-------------+------------------------------------------------
  population |   16715.75   9431.077     -5585.203     39016.7
--------------------------------------------------------------

. tabstat population, statistic(mean)
    variable |      mean
-------------+----------
  population |  16715.75
------------------------

. quietly summarize population
. display r(mean)
16715.75

Mean in Mata[edit]

mata
a=11311.1\7153.8\10553.8\5707.3\
82175.7\1315.9\4724.7\10783.7

mean(a)
16715.75

Swift[edit]

func meanDoubles(s: [Double]) -> Double {
  return s.reduce(0, +) / Double(s.count)
}
func meanInts(s: [Int]) -> Double {
  return meanDoubles(s.map{Double($0)})
}

Tcl[edit]

package require Tcl 8.5
proc mean args {
    if {[set num [llength $args]] == 0} {return 0}
    expr {[tcl::mathop::+ {*}$args] / double($num)}
}
mean 3 1 4 1 5 9 ;# ==> 3.8333333333333335

TI-83 BASIC[edit]

Mean(Ans

TI-89 BASIC[edit]

Define rcmean(nums) = when(dim(nums) = 0, 0, mean(nums))

Trith[edit]

: mean dup empty? [drop 0] [dup [+] foldl1 swap length /] branch ;

[3 1 4 1 5 9] mean

TypeScript[edit]

function mean(numbersArr)
{
    let arrLen = numbersArr.length;
    if (arrLen > 0) {
        let sum: number = 0;
        for (let i of numbersArr) {
            sum += i;
        }
        return sum/arrLen;
    }
    else return "Not defined";
}
 
alert( mean( [1,2,3,4,5] ) );   
alert( mean( [] ) );

UNIX Shell[edit]

1) First solution with bash (V >= 3), works with floats :

echo "`cat f | paste -sd+ | bc -l` / `cat f | wc -l`" | bc -l
cat f
1
2
4
8
16
-200

echo "`cat f | paste -sd+ | bc -l`/`cat f | wc -l`" | bc -l
-28.16666666666666666666

cat f
1.109434
2
4.5
8.45
16
-200
400.56

echo "`cat f | paste -sd+ | bc -l`/`cat f | wc -l`" |bc -l
33.23134771428571428571

2) This example uses expr, so it only works with integers. It checks that each string in the list is an integer.

mean() {
	if expr $# >/dev/null; then
		(count=0
		 sum=0
		 while expr $# \> 0 >/dev/null; do
			sum=`expr $sum + "$1"`
			result=$?
			expr $result \> 1 >/dev/null && exit $result

			count=`expr $count + 1`
			shift
		 done
		 expr $sum / $count)
	else
		echo 0
	fi
}

printf "test 1: "; mean				# 0
printf "test 2: "; mean 300			# 300
printf "test 3: "; mean 300 100 400		# 266
printf "test 4: "; mean -400 400 -1300 200	# -275
printf "test 5: "; mean -			# expr: syntax error
printf "test 6: "; mean 1 2 A 3			# expr: non-numeric argument

UnixPipes[edit]

This example is incorrect. Please fix the code and remove this message.
Details: There is a race between parallel commands. cat count might try to read the file before wc -l >count writes it. This may cause an error like cat: count: No such file or directory, then bc: stdin:1: syntax error: ) unexpected.

Uses ksh93-style process substitution. Also overwrites the file named count in the current directory.

Works with: bash
term() {
   b=$1;res=$2
   echo "scale=5;$res+$b" | bc
}

sum() {
  (read B; res=$1;
  test -n "$B" && (term $B $res) || (term 0 $res))
}

fold() {
  func=$1
  (while read a ; do
      fold $func | $func $a
  done)
}

mean() {
  tee >(wc -l > count) | fold sum | xargs echo "scale=5;(1/" $(cat count) ") * " | bc
}

(echo 3; echo 1; echo 4) | mean

Ursa[edit]

#
# arithmetic mean
#

decl int<> input
decl int i
for (set i 1) (< i (size args)) (inc i)
        append (int args<i>) input
end for

out (/ (+ input) (size input)) endl console

Ursala[edit]

There is a library function for means already, although it doesn't cope with empty vectors. A mean function could be defined as shown for this task.

#import nat
#import flo

mean = ~&?\0.! div^/plus:-0. float+ length

#cast %e

example = mean <5.,3.,-2.,6.,-4.>

output:

1.600000e+00

V[edit]

[mean
   [sum 0 [+] fold].
   dup sum
   swap size [[1 <] [1]] when /
].

Vala[edit]

Using array to hold the numbers of the list:

double arithmetic(double[] list){
	double mean;
	double sum = 0;
	
	if (list.length == 0)
		return 0.0;
	foreach(double number in list){
		sum += number;
	} // foreach
	
	mean = sum / list.length;
	
	return mean;
} // end arithmetic mean

public static void main(){
	double[] test = {1.0, 2.0, 5.0, -5.0, 9.5, 3.14159};
	double[] zero_len = {};
	
	double mean = arithmetic(test);
	double mean_zero = arithmetic(zero_len);
	
	stdout.printf("%s\n", mean.to_string());
	stdout.printf("%s\n", mean_zero.to_string());
}

Output:

2.6069316666666666
0

VBA[edit]

Private Function mean(v() As Double, ByVal leng As Integer) As Variant
    Dim sum As Double, i As Integer
    sum = 0: i = 0
    For i = 0 To leng - 1
        sum = sum + vv
    Next i
    If leng = 0 Then
        mean = CVErr(xlErrDiv0)
    Else
        mean = sum / leng
    End If
End Function
Public Sub main()
    Dim v(4) As Double
    Dim i As Integer, leng As Integer
    v(0) = 1#
    v(1) = 2#
    v(2) = 2.178
    v(3) = 3#
    v(4) = 3.142
    For leng = 5 To 0 Step -1
        Debug.Print "mean[";
        For i = 0 To leng - 1
            Debug.Print IIf(i, "; " & v(i), "" & v(i));
        Next i
        Debug.Print "] = "; mean(v, leng)
    Next leng
End Sub
Output:
mean[1; 2; 2,178; 3; 3,142] =  0 
mean[1; 2; 2,178; 3] =  0 
mean[1; 2; 2,178] =  0 
mean[1; 2] =  0 
mean[1] =  0 
mean[] = Fout 2007

VBScript[edit]

Function mean(arr)
	size = UBound(arr) + 1
	mean = 0
	For i = 0 To UBound(arr)
		mean = mean + arr(i)
	Next
	mean = mean/size
End Function

'Example
WScript.Echo mean(Array(3,1,4,1,5,9))
Output:
3.83333333333333

Vedit macro language[edit]

The numeric data is stored in current edit buffer as ASCII strings, one value per line.

#1 = 0			// Sum
#2 = 0			// Count
BOF
While(!At_EOF) {
    #1 += Num_Eval(SIMPLE)
    #2++
    Line(1, ERRBREAK)
}
if (#2) { #1 /= #2 }
Num_Type(#1)

Vim Script[edit]

Throws an exception if the list is empty.

function Mean(lst)
    if empty(a:lst)
        throw "Empty"
    endif
    let sum = 0.0
    for i in a:lst
        let sum += i
    endfor
    return sum / len(a:lst)
endfunction

V (Vlang)[edit]

import math
import arrays
 
fn main() {
    for v in [
        []f64{},                         // mean returns ok = false
        [math.inf(1), math.inf(1)], // answer is +Inf
 
        // answer is NaN, and mean returns ok = true, indicating NaN
        // is the correct result
        [math.inf(1), math.inf(-1)],
 
        [f64(3), 1, 4, 1, 5, 9],
 
        [f64(10), 9, 8, 7, 6, 5, 4, 3, 2, 1, 0, 0, 0, 0, .11],
        [f64(10), 20, 30, 40, 50, -100, 4.7, -11e2],
    ] {
        println("Vector: $v")
        m := arrays.fold(v, 0.0, fn(r f64, v f64) f64 { return r+v })/v.len
        println("Mean of $v.len numbers is $m\n")
    }
}
Output:
Vector: []
Mean of 0 numbers is nan

Vector: [+inf, +inf]
Mean of 2 numbers is +inf

Vector: [+inf, -inf]
Mean of 2 numbers is nan

Vector: [3, 1, 4, 1, 5, 9]
Mean of 6 numbers is 3.8333333333333335

Vector: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0, 0, 0, 0, 0.11]
Mean of 15 numbers is 3.674

Vector: [10, 20, 30, 40, 50, -100, 4.7, -1100]
Mean of 8 numbers is -130.66

Wart[edit]

def (mean l)
  sum.l / len.l

Example run:

mean '(1 2 3)
=> 2

WDTE[edit]

let s => import 'stream';
let a => import 'arrays';

let mean nums =>
  a.stream nums
  -> s.reduce [0; 0] (@ s p n => [+ (a.at p 0) 1; + (a.at p 1) n])
  -> (@ s p => / (a.at p 1) (a.at p 0));

This is a tad messier than it has to be due to a lack of a way to get the length of an array in WDTE currently.

Usage:

mean [1; 2; 3] -- io.writeln io.stdout;

Output:

2

Wortel[edit]

@let {
  ; using a fork (sum divided-by length)
  mean1 @(@sum / #)
	
  ; using a function with a named argument
  mean2 &a / @sum a #a

  [[
    !mean1 [3 1 4 1 5 9 2]
    !mean2 [3 1 4 1 5 9 2]
  ]]
}

Returns:

[3.5714285714285716 3.5714285714285716]

Wren[edit]

class Arithmetic {
    static mean(arr) {
        if (arr.count == 0) Fiber.abort("Length must be greater than zero")
        return arr.reduce(Fn.new{ |x,y| x+y }) / arr.count
    }
}
Arithmetic.mean([1,2,3,4,5]) // 3

XLISP[edit]

The specification calls for a function that takes a vector; for convenience, we convert this vector internally to a list. The mean of a zero-length vector is returned as nil, equivalent to the empty list or logical false.

(defun mean (v)
    (if (= (vector-length v) 0)
        nil
        (let ((l (vector->list v)))
            (/ (apply + l) (length l)))))

XPL0[edit]

code CrLf=9;
code real RlOut=48;

func real Mean(A, N);
real A;  int N;
real S;  int I;
[if N=0 then return 0.0;
S:= 0.0;
for I:= 0 to N-1 do
        S:= S+A(I);
return S/float(N);
]; \Mean

real Test;
[Test:= [1.0, 2.0, 5.0, -5.0, 9.5, 3.14159];
RlOut(0, Mean(Test, 6));  CrLf(0);
]

Output:

    2.60693

XSLT[edit]

Where $values is some variable indicating a set of nodes containing numbers, the average is given by the XPath expression:

sum($values) div count($values)

Runnable example[edit]

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
	<xsl:output method="text"/>

	<xsl:template match="/">
		<xsl:variable name="values" select="/*/*"/>
		<xsl:value-of select="sum($values) div count($values)"/>
	</xsl:template>
</xsl:stylesheet>

Sample input:

<numbers>
	<!-- Average is 2.4 -->
	<number>1</number>
	<number>1</number>
	<number>2</number>
	<number>3</number>
	<number>5</number>
</numbers>

Yorick[edit]

func mean(x) {
    if(is_void(x)) return 0;
    return x(*)(avg);
}

zkl[edit]

Converts int to floats (implicitly):

fcn mean(a,b,c,etc){ z:=vm.arglist; z.reduce('+,0.0)/z.len() }
mean(3,1,4,1,5,9);  //-->3.83333
mean(); //-->Exception thrown: MathError(NaN (Not a number))

To pass in a vector/list:

fcn meanV(z){ z.reduce('+,0.0)/z.len() }
meanV(T(3,1,4,1,5,9)); // --> 3.83333

Zoea[edit]

program: average
  case: 1
    input: [2,3,10]
    output: 5
  case: 2
    input: [7,11]
    output: 9

zonnon[edit]

module Averages;
type 
	Vector = array {math} * of real;

	procedure ArithmeticMean(x: Vector): real;
	begin
		(* sum is a predefined function for mathematical arrays *)
		return sum(x)
	end ArithmeticMean;
var
	x: Vector;

begin
	x := new Vector(4);
	x := [1.0, 2.3, 3.2, 2.1, 5.3];
	write("arithmetic mean: ");writeln(ArithmeticMean(x):10:2)
end Averages.
Output:
arithmetic mean:       13,9