Sum and product of an array: Difference between revisions
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=={{header|Vala}}== |
=={{header|Vala}}== |
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<lang Vala>void main() { |
<lang Vala>void main() { |
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int sum=0, prod = 1; |
int sum = 0, prod = 1; |
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int[] data = { 1, 2, 3, 4 }; |
int[] data = { 1, 2, 3, 4 }; |
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foreach (int val in data) { |
foreach (int val in data) { |
Revision as of 14:12, 29 January 2021
You are encouraged to solve this task according to the task description, using any language you may know.
- Task
Compute the sum and product of an array of integers.
360 Assembly
<lang 360asm>* Sum and product of an array 20/04/2017 SUMPROD CSECT
USING SUMPROD,R15 base register SR R3,R3 su=0 LA R5,1 pr=1 LA R6,1 i=1 DO WHILE=(CH,R6,LE,=AL2((PG-A)/4)) do i=1 to hbound(a) LR R1,R6 i SLA R1,2 *4 A R3,A-4(R1) su=su+a(i) M R4,A-4(R1) pr=pr*a(i) LA R6,1(R6) i++ ENDDO , enddo i XDECO R3,PG su XDECO R5,PG+12 pr XPRNT PG,L'PG print BR R14 exit
A DC F'1',F'2',F'3',F'4',F'5',F'6',F'7',F'8',F'9',F'10' PG DS CL24 buffer
YREGS END SUMPROD</lang>
- Output:
55 3628800
4D
<lang 4d>ARRAY INTEGER($list;0) For ($i;1;5)
APPEND TO ARRAY($list;$i)
End for
$sum:=0 $product:=1 For ($i;1;Size of array($list))
$sum:=$var+$list{$i} $product:=$product*$list{$i}
End for
// since 4D v13
$sum:=sum($list) </lang>
ACL2
<lang Lisp>(defun sum (xs)
(if (endp xs) 0 (+ (first xs) (sum (rest xs)))))
(defun prod (xs)
(if (endp xs) 1 (* (first xs) (prod (rest xs)))))</lang>
ActionScript
<lang actionscript>package { import flash.display.Sprite;
public class SumAndProduct extends Sprite { public function SumAndProduct() { var arr:Array = [1, 2, 3, 4, 5]; var sum:int = 0; var prod:int = 1;
for (var i:int = 0; i < arr.length; i++) { sum += arr[i]; prod *= arr[i]; }
trace("Sum: " + sum); // 15 trace("Product: " + prod); // 120 } } }</lang>
Ada
<lang ada>type Int_Array is array(Integer range <>) of Integer;
array : Int_Array := (1,2,3,4,5,6,7,8,9,10); Sum : Integer := 0; for I in array'range loop
Sum := Sum + array(I);
end loop;</lang> Define the product function <lang ada>function Product(Item : Int_Array) return Integer is
Prod : Integer := 1;
begin
for I in Item'range loop Prod := Prod * Item(I); end loop; return Prod;
end Product;</lang> This function will raise the predefined exception Constraint_Error if the product overflows the values represented by type Integer
Aime
<lang aime>void compute(integer &s, integer &p, list l) {
integer v;
s = 0; p = 1; for (, v in l) { s += v; p *= v; }
}
integer main(void) {
integer sum, product;
compute(sum, product, list(2, 3, 5, 7, 11, 13, 17, 19));
o_form("~\n~\n", sum, product);
return 0;
}</lang>
- Output:
77 9699690
ALGOL 68
<lang algol68>main:(
INT default upb := 3; MODE INTARRAY = [default upb]INT; INTARRAY array = (1,2,3,4,5,6,7,8,9,10); INT sum := 0; FOR i FROM LWB array TO UPB array DO sum +:= array[i] OD; # Define the product function # PROC int product = (INTARRAY item)INT: ( INT prod :=1; FOR i FROM LWB item TO UPB item DO prod *:= item[i] OD; prod ) # int product # ; printf(($" Sum: "g(0)$,sum,$", Product:"g(0)";"l$,int product(array)))
)</lang>
- Output:
Sum: 55, Product:3628800;
ALGOL W
<lang algolw>begin
% computes the sum and product of intArray % % the results are returned in sum and product % % the bounds of the array must be specified in lb and ub % procedure sumAndProduct( integer array intArray ( * ) ; integer value lb, ub ; integer result sum, product ) ; begin
sum := 0; product := 1;
for i := lb until ub do begin sum := sum + intArray( i ); product := product * intArray( i ); end for_i ;
end sumAndProduct ;
% test the sumAndProduct procedure % begin
integer array v ( 1 :: 10 ); integer sum, product;
for i := 1 until 10 do v( i ) := i;
sumAndProduct( v, 1, 10, sum, product ); write( sum, product ); end
end.</lang>
- Output:
55 3628800
APL
<lang apl> sum ← +/
prod ← ×/ list ← 1 2 3 4 5 sum list
15
prod list
120</lang>
AppleScript
<lang applescript>set array to {1, 2, 3, 4, 5} set sum to 0 set product to 1 repeat with i in array
set sum to sum + i set product to product * i
end repeat</lang>
Or, using an AppleScript implementation of fold/reduce:
<lang AppleScript>on summed(a, b)
a + b
end summed
on product(a, b)
a * b
end product
-- TEST ----------------------------------------------------------------------- on run
set xs to enumFromTo(1, 10) {xs, ¬ {sum:foldl(summed, 0, xs)}, ¬ {product:foldl(product, 1, xs)}} --> {{1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, {sum:55}, {product:3628800}}
end run
-- GENERIC FUNCTIONS ----------------------------------------------------------
-- enumFromTo :: Int -> Int -> [Int] on enumFromTo(m, n)
if n < m then set d to -1 else set d to 1 end if set lst to {} repeat with i from m to n by d set end of lst to i end repeat return lst
end enumFromTo
-- foldl :: (a -> b -> a) -> a -> [b] -> a on foldl(f, startValue, xs)
tell mReturn(f) set v to startValue set lng to length of xs repeat with i from 1 to lng set v to |λ|(v, item i of xs, i, xs) end repeat return v end tell
end foldl
-- Lift 2nd class handler function into 1st class script wrapper -- mReturn :: Handler -> Script on mReturn(f)
if class of f is script then f else script property |λ| : f end script end if
end mReturn</lang>
- Output:
<lang AppleScript>{{1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, {sum:55}, {product:3628800}}</lang>
Arturo
<lang arturo>arr: 1..10
print "Sum = " + [sum arr] print "Product = " + [product arr]</lang>
- Output:
Sum = 55 Product = 3628800
AutoHotkey
<lang AutoHotkey>numbers = 1,2,3,4,5 product := 1 loop, parse, numbers, `, { sum += A_LoopField product *= A_LoopField } msgbox, sum = %sum%`nproduct = %product%</lang>
AWK
For array input, it is easiest to "deserialize" it from a string with the split() function. <lang awk>$ awk 'func sum(s){split(s,a);r=0;for(i in a)r+=a[i];return r}{print sum($0)}' 1 2 3 4 5 6 7 8 9 10 55
$ awk 'func prod(s){split(s,a);r=1;for(i in a)r*=a[i];return r}{print prod($0)}' 1 2 3 4 5 6 7 8 9 10 3628800</lang>
Babel
<lang babel>main: { [2 3 5 7 11 13] sp }
sum! : { <- 0 -> { + } eachar } product!: { <- 1 -> { * } eachar }
sp!:
{ dup sum %d cr << product %d cr << }
Result: 41 30030</lang>
Perhaps better Babel:
<lang babel>main:
{ [2 3 5 7 11 13] ar2ls dup cp <- sum_stack -> prod_stack %d cr << %d cr << }
sum_stack:
{ { give { + } { depth 1 > } do_while } nest }
prod_stack:
{ { give { * } { depth 1 > } do_while } nest }</lang>
The nest operator creates a kind of argument-passing context - it saves whatever is on Top-of-Stack (TOS), saves the old stack, clears the stack and places the saved TOS on the new, cleared stack. This permits a section to monopolize the stack. At the end of the nest context, whatever is on TOS will be "passed back" to the original stack which will be restored.
The depth operator returns the current depth of the stack.
BASIC
<lang freebasic>dim array(5) as integer = { 1, 2, 3, 4, 5 }
dim sum as integer = 0 dim prod as integer = 1 for index as integer = lbound(array) to ubound(array)
sum += array(index) prod *= array(index)
next</lang>
Applesoft BASIC
<lang ApplesoftBasic> 10 N = 5
20 S = 0:P = 1: DATA 1,2,3,4,5 30 N = N - 1: DIM A(N) 40 FOR I = 0 TO N 50 READ A(I): NEXT 60 FOR I = 0 TO N 70 S = S + A(I):P = P * A(I) 80 NEXT 90 PRINT "SUM="S,"PRODUCT="P</lang>
BaCon
<lang freebasic> '--- set some values into the array DECLARE a[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10 } TYPE int
sum = 0 product = 1 i = 1
WHILE a[i] <= 10 sum = sum + a[i] product = product * a[i] INCR i WEND
PRINT "The sum is ",sum PRINT "The product is ",product </lang>
BBC BASIC
<lang bbcbasic> DIM array%(5)
array%() = 1, 2, 3, 4, 5, 6 PRINT "Sum of array elements = " ; SUM(array%()) product% = 1 FOR I% = 0 TO DIM(array%(),1) product% *= array%(I%) NEXT PRINT "Product of array elements = " ; product%</lang>
IS-BASIC
<lang IS-BASIC>100 RANDOMIZE 110 LET N=5 120 NUMERIC A(1 TO N) 130 LET SUM=0:LET PROD=1 140 FOR I=1 TO N 150 LET A(I)=RND(9)+1 160 PRINT A(I); 170 NEXT 180 PRINT 190 FOR I=1 TO N 200 LET SUM=SUM+A(I):LET PROD=PROD*A(I) 210 NEXT 220 PRINT "Sum =";SUM,"Product =";PROD</lang>
bc
<lang bc>a[0] = 3.0 a[1] = 1 a[2] = 4.0 a[3] = 1.0 a[4] = 5 a[5] = 9.00 n = 6 p = 1 for (i = 0; i < n; i++) {
s += a[i] p *= a[i]
} "Sum: "; s "Product: "; p</lang>
Befunge
The program first reads the number of elements in the array, then the elements themselves (each number on a separate line) and calculates their sum. <lang Befunge>0 &>: #v_ $. @
>1- \ & + \v ^ <</lang>
Bracmat
<lang bracmat>( ( sumprod
= sum prod num . 0:?sum & 1:?prod & ( !arg : ? ( #%?num ? & !num+!sum:?sum & !num*!prod:?prod & ~ ) | (!sum.!prod) ) )
& out$sumprod$(2 3 5 7 11 13 17 19) );</lang>
- Output:
77.9699690
C
<lang c>/* using pointer arithmetic (because we can, I guess) */ int arg[] = { 1,2,3,4,5 }; int arg_length = sizeof(arg)/sizeof(arg[0]); int *end = arg+arg_length; int sum = 0, prod = 1; int *p;
for (p = arg; p!=end; ++p) {
sum += *p; prod *= *p;
}</lang>
C#
<lang csharp>int sum = 0, prod = 1; int[] arg = { 1, 2, 3, 4, 5 }; foreach (int value in arg) {
sum += value; prod *= value;
}</lang>
Alternative using Linq (C# 3)
<lang csharp>int[] arg = { 1, 2, 3, 4, 5 }; int sum = arg.Sum(); int prod = arg.Aggregate((runningProduct, nextFactor) => runningProduct * nextFactor);</lang>
C++
<lang cpp>#include <numeric>
- include <functional>
int arg[] = { 1, 2, 3, 4, 5 }; int sum = std::accumulate(arg, arg+5, 0, std::plus<int>()); // or just // std::accumulate(arg, arg + 5, 0); // since plus() is the default functor for accumulate int prod = std::accumulate(arg, arg+5, 1, std::multiplies<int>());</lang> Template alternative: <lang cpp>// this would be more elegant using STL collections template <typename T> T sum (const T *array, const unsigned n) {
T accum = 0; for (unsigned i=0; i<n; i++) accum += array[i]; return accum;
} template <typename T> T prod (const T *array, const unsigned n) {
T accum = 1; for (unsigned i=0; i<n; i++) accum *= array[i]; return accum;
}
- include <iostream>
using std::cout; using std::endl;
int main () {
int aint[] = {1, 2, 3}; cout << sum(aint,3) << " " << prod(aint, 3) << endl; float aflo[] = {1.1, 2.02, 3.003, 4.0004}; cout << sum(aflo,4) << " " << prod(aflo,4) << endl; return 0;
}</lang>
Chef
<lang chef>Sum and Product of Numbers as a Piece of Cake.
This recipe sums N given numbers.
Ingredients. 1 N 0 sum 1 product 1 number
Method. Put sum into 1st mixing bowl. Put product into 2nd mixing bowl. Take N from refrigerator. Chop N. Take number from refrigerator. Add number into 1st mixing bowl. Combine number into 2nd mixing bowl. Chop N until choped. Pour contents of 2nd mixing bowl into the baking dish. Pour contents of 1st mixing bowl into the baking dish.
Serves 1.</lang>
Clean
<lang clean>array = {1, 2, 3, 4, 5} Sum = sum [x \\ x <-: array] Prod = foldl (*) 1 [x \\ x <-: array]</lang>
Clojure
<lang lisp>(defn sum [vals] (reduce + vals))
(defn product [vals] (reduce * vals))</lang>
COBOL
<lang cobol> IDENTIFICATION DIVISION.
PROGRAM-ID. array-sum-and-product.
DATA DIVISION. WORKING-STORAGE SECTION. 78 Array-Size VALUE 10. 01 array-area VALUE "01020304050607080910". 03 array PIC 99 OCCURS Array-Size TIMES.
01 array-sum PIC 9(8). 01 array-product PIC 9(10) VALUE 1.
01 i PIC 99.
PROCEDURE DIVISION. PERFORM VARYING i FROM 1 BY 1 UNTIL Array-Size < i ADD array (i) TO array-sum MULTIPLY array (i) BY array-product END-PERFORM
DISPLAY "Sum: " array-sum DISPLAY "Product: " array-product
GOBACK .</lang>
CoffeeScript
<lang coffeescript> sum = (array) ->
array.reduce (x, y) -> x + y
product = (array) ->
array.reduce (x, y) -> x * y
</lang>
ColdFusion
Sum of an Array, <lang cfm><cfset Variables.myArray = [1,2,3,4,5,6,7,8,9,10]> <cfoutput>#ArraySum(Variables.myArray)#</cfoutput></lang>
Product of an Array, <lang cfm><cfset Variables.myArray = [1,2,3,4,5,6,7,8,9,10]> <cfset Variables.Product = 1> <cfloop array="#Variables.myArray#" index="i">
<cfset Variables.Product *= i>
</cfloop> <cfoutput>#Variables.Product#</cfoutput></lang>
Common Lisp
<lang lisp>(let ((data #(1 2 3 4 5))) ; the array
(values (reduce #'+ data) ; sum (reduce #'* data))) ; product</lang>
The loop macro also has support for sums. <lang lisp>(loop for i in '(1 2 3 4 5) sum i)</lang>
Crystal
Declarative
<lang Ruby> def sum_product(a)
{ a.sum(), a.product() }
end </lang>
Imperative
<lang Ruby> def sum_product_imperative(a)
sum, product = 0, 1 a.each do |e| sum += e product *= e end
{sum, product}
end </lang>
<lang Ruby> require "benchmark" Benchmark.ips do |x|
x.report("declarative") { sum_product [1, 2, 3, 4, 5] } x.report("imperative") { sum_product_imperative [1, 2, 3, 4, 5] }
end </lang>
<lang Bash> declarative 8.1M (123.45ns) (± 2.99%) 65 B/op 1.30× slower
imperative 10.57M ( 94.61ns) (± 2.96%) 65 B/op fastest
</lang>
D
<lang d>import std.stdio;
void main() {
immutable array = [1, 2, 3, 4, 5];
int sum = 0; int prod = 1;
foreach (x; array) { sum += x; prod *= x; }
writeln("Sum: ", sum); writeln("Product: ", prod);
}</lang>
- Output:
Sum: 15 Product: 120
Compute sum and product of array in one pass (same output): <lang d>import std.stdio, std.algorithm, std.typecons;
void main() {
immutable array = [1, 2, 3, 4, 5];
// Results are stored in a 2-tuple immutable r = reduce!(q{a + b}, q{a * b})(tuple(0, 1), array);
writeln("Sum: ", r[0]); writeln("Product: ", r[1]);
}</lang>
dc
<lang dc>1 3 5 7 9 11 13 0ss1sp[dls+sslp*spz0!=a]dsax[Sum: ]Plsp[Product: ]Plpp Sum: 49 Product: 135135</lang>
Delphi
<lang delphi>program SumAndProductOfArray;
{$APPTYPE CONSOLE}
var
i: integer; lIntArray: array [1 .. 5] of integer = (1, 2, 3, 4, 5); lSum: integer = 0; lProduct: integer = 1;
begin
for i := 1 to length(lIntArray) do begin Inc(lSum, lIntArray[i]); lProduct := lProduct * lIntArray[i] end;
Write('Sum: '); Writeln(lSum); Write('Product: '); Writeln(lProduct);
end.</lang>
E
<lang e>pragma.enable("accumulator") accum 0 for x in [1,2,3,4,5] { _ + x } accum 1 for x in [1,2,3,4,5] { _ * x }</lang>
Eiffel
<lang eiffel> class APPLICATION
create make
feature {NONE}
make local test: ARRAY [INTEGER] do create test.make_empty test := <<5, 1, 9, 7>> io.put_string ("Sum: " + sum (test).out) io.new_line io.put_string ("Product: " + product (test).out) end
sum (ar: ARRAY [INTEGER]): INTEGER -- Sum of the items of the array 'ar'. do across ar.lower |..| ar.upper as c loop Result := Result + ar [c.item] end end
product (ar: ARRAY [INTEGER]): INTEGER -- Product of the items of the array 'ar'. do Result := 1 across ar.lower |..| ar.upper as c loop Result := Result * ar [c.item] end end
end </lang>
- Output:
Sum of the elements of the array: 30 Product of the elements of the array: 3840
Elena
ELENA 5.0: <lang elena>import system'routines; import extensions;
public program() {
var list := new int[]{1, 2, 3, 4, 5 }; var sum := list.summarize(new Integer()); var product := list.accumulate(new Integer(1), (var,val => var * val));
}</lang>
Elixir
When an accumulator is omitted, the first element of the collection is used as the initial value of acc. <lang elixir>iex(26)> Enum.reduce([1,2,3,4,5], 0, fn x,acc -> x+acc end) 15 iex(27)> Enum.reduce([1,2,3,4,5], 1, fn x,acc -> x*acc end) 120 iex(28)> Enum.reduce([1,2,3,4,5], fn x,acc -> x+acc end) 15 iex(29)> Enum.reduce([1,2,3,4,5], fn x,acc -> x*acc end) 120 iex(30)> Enum.reduce([], 0, fn x,acc -> x+acc end) 0 iex(31)> Enum.reduce([], 1, fn x,acc -> x*acc end) 1 iex(32)> Enum.reduce([], fn x,acc -> x+acc end)
- (Enum.EmptyError) empty error
(elixir) lib/enum.ex:1287: Enum.reduce/2
iex(32)> Enum.reduce([], fn x,acc -> x*acc end)
- (Enum.EmptyError) empty error
(elixir) lib/enum.ex:1287: Enum.reduce/2</lang>
The function with sum <lang elixir>Enum.sum([1,2,3,4,5]) #=> 15</lang>
Emacs Lisp
<lang lisp>(setq array [1 2 3 4 5]) (eval (concatenate 'list '(+) array)) (eval (concatenate 'list '(*) array))</lang>
With a list
<lang lisp>(setq array '(1 2 3 4 5)) (apply '+ array) (apply '* array)</lang>
With explicit conversion
<lang lisp>(setq array [1 2 3 4 5]) (apply '+ (append array nil)) (apply '* (append array nil))</lang>
Erlang
Using the standard libraries: <lang erlang>% create the list: L = lists:seq(1, 10).
% and compute its sum: S = lists:sum(L). P = lists:foldl(fun (X, P) -> X * P end, 1, L).</lang> To compute sum and products in one pass: <lang erlang> {Prod,Sum} = lists:foldl(fun (X, {P,S}) -> {P*X,S+X} end, {1,0}, lists:seq(1,10)).</lang> Or defining our own versions: <lang erlang>-module(list_sum). -export([sum_rec/1, sum_tail/1]).
% recursive definition: sum_rec([]) ->
0;
sum_rec([Head|Tail]) ->
Head + sum_rec(Tail).
% tail-recursive definition: sum_tail(L) ->
sum_tail(L, 0).
sum_tail([], Acc) ->
Acc;
sum_tail([Head|Tail], Acc) ->
sum_tail(Tail, Head + Acc).</lang>
Euphoria
<lang euphoria>sequence array integer sum,prod
array = { 1, 2, 3, 4, 5 }
sum = 0 prod = 1 for i = 1 to length(array) do
sum += array[i] prod *= array[i]
end for
printf(1,"sum is %d\n",sum) printf(1,"prod is %d\n",prod)</lang>
- Output:
sum is 15 prod is 120
F#
<lang fsharp> let numbers = [| 1..10 |] let sum = numbers |> Array.sum let product = numbers |> Array.reduce (*) </lang>
Factor
<lang factor>1 5 1 <range> [ sum . ] [ product . ] bi
15 120
{ 1 2 3 4 } [ sum ] [ product ] bi
10 24</lang>
sum and product are defined in the sequences vocabulary: <lang factor>: sum ( seq -- n ) 0 [ + ] reduce ;
- product ( seq -- n ) 1 [ * ] reduce ;</lang>
FALSE
Strictly speaking, there are no arrays in FALSE. However, a number of elements on the stack could be considered an array. The implementation below assumes the length of the array on top of the stack, and the actual items below it. Note that this implementation does remove the "array" from the stack, so in case the original values need to be retained, a copy should be provided before executing this logic. <lang false>1 2 3 4 5 {input "array"} 5 {length of input} 0s: {sum} 1p: {product}
[$0=~][1-\$s;+s:p;*p:]#%
"Sum: "s;." Product: "p;.</lang>
- Output:
Sum: 15 Product: 120
Fantom
<lang fantom> class Main {
public static Void main () { Int[] array := (1..20).toList // you can use a loop Int sum := 0 array.each |Int n| { sum += n } echo ("Sum of array is : $sum")
Int product := 1 array.each |Int n| { product *= n } echo ("Product of array is : $product")
// or use 'reduce' // 'reduce' takes a function, // the first argument is the accumulated value // and the second is the next item in the list sum = array.reduce(0) |Obj r, Int v -> Obj| { return (Int)r + v } echo ("Sum of array : $sum")
product = array.reduce(1) |Obj r, Int v -> Obj| { return (Int)r * v } echo ("Product of array : $product") }
} </lang>
Forth
<lang forth>: third ( a b c -- a b c a ) 2 pick ;
- reduce ( xt n addr cnt -- n' ) \ where xt ( a b -- n )
cells bounds do i @ third execute cell +loop nip ;
create a 1 , 2 , 3 , 4 , 5 ,
' + 0 a 5 reduce . \ 15 ' * 1 a 5 reduce . \ 120</lang>
Fortran
In ISO Fortran 90 and later, use SUM and PRODUCT intrinsics: <lang fortran>integer, dimension(10) :: a = (/ (i, i=1, 10) /) integer :: sresult, presult
sresult = sum(a) presult = product(a)</lang>
FreeBASIC
<lang freebasic>' FB 1.05.0 Win64
Dim a(1 To 4) As Integer = {1, 4, 6, 3} Dim As Integer i, sum = 0, prod = 1 For i = 1 To 4
sum += a(i) prod *= a(i)
Next Print "Sum ="; sum Print "Product ="; prod Print Print "Press any key to quit" Sleep</lang>
- Output:
Sum = 14 Product = 72
Frink
<lang frink> a = [1,2,3,5,7] sum[a] product[a] </lang>
Fōrmulæ
In this page you can see the solution of this task.
Fōrmulæ programs are not textual, visualization/edition of programs is done showing/manipulating structures but not text (more info). Moreover, there can be multiple visual representations of the same program. Even though it is possible to have textual representation —i.e. XML, JSON— they are intended for transportation effects more than visualization and edition.
The option to show Fōrmulæ programs and their results is showing images. Unfortunately images cannot be uploaded in Rosetta Code.
Gambas
Click this link to run this code <lang gambas>Public Sub Main() Dim iList As Integer[] = [1, 2, 3, 4, 5] Dim iSum, iCount As Integer Dim iPrd As Integer = 1
For iCount = 0 To iList.Max
iSum += iList[iCount] iPrd *= iList[iCount]
Next
Print "The Sum =\t" & iSum Print "The Product =\t" & iPrd
End</lang> Output:
The Sum = 15 The Product = 120
GAP
<lang gap>v := [1 .. 8];
Sum(v);
- 36
Product(v);
- 40320
- You can sum or multiply the result of a function
Sum(v, n -> n^2);
- 204
Product(v, n -> 1/n);
- 1/40320</lang>
GFA Basic
<lang basic> DIM a%(10) ' put some values into the array FOR i%=1 TO 10
a%(i%)=i%
NEXT i% ' sum%=0 product%=1 FOR i%=1 TO 10
sum%=sum%+a%(i%) product%=product%*a%(i%)
NEXT i% ' PRINT "Sum is ";sum% PRINT "Product is ";product% </lang>
Go
- Implementation
<lang go>package main
import "fmt"
func main() {
sum, prod := 0, 1 for _, x := range []int{1,2,5} { sum += x prod *= x } fmt.Println(sum, prod)
}</lang>
- Output:
8 10
- Library
<lang go>package main
import (
"fmt"
"github.com/gonum/floats"
)
var a = []float64{1, 2, 5}
func main() {
fmt.Println("Sum: ", floats.Sum(a)) fmt.Println("Product:", floats.Prod(a))
}</lang>
- Output:
Sum: 8 Product: 10
Groovy
Groovy adds a "sum()" method for collections, but not a "product()" method: <lang groovy>[1,2,3,4,5].sum()</lang> However, for general purpose "reduction" or "folding" operations, Groovy does provide an "inject()" method for collections similar to "inject" in Ruby. <lang groovy>[1,2,3,4,5].inject(0) { sum, val -> sum + val } [1,2,3,4,5].inject(1) { prod, val -> prod * val }</lang> You can also combine these operations: <lang groovy>println ([1,2,3,4,5].inject([sum: 0, product: 1]) { result, value ->
[sum: result.sum + value, product: result.product * value]})</lang>
GW-BASIC
<lang qbasic>10 REM Create an array with some test data in it 20 DIM A(5) 30 FOR I = 1 TO 5: READ A(I): NEXT I 40 DATA 1, 2, 3, 4, 5 50 REM Find the sum of elements in the array 60 S = 0 65 P = 1 70 FOR I = 1 TO 5 72 S = SUM + A(I) 75 P = P * A(I) 77 NEXT I 80 PRINT "The sum is "; S; 90 PRINT " and the product is "; P</lang>
Haskell
For lists, sum and product are already defined in the Prelude: <lang haskell>values = [1..10]
s = sum values -- the easy way p = product values
s1 = foldl (+) 0 values -- the hard way p1 = foldl (*) 1 values</lang> To do the same for an array, just convert it lazily to a list: <lang haskell>import Data.Array
values = listArray (1,10) [1..10]
s = sum . elems $ values p = product . elems $ values</lang>
Or perhaps: <lang haskell>import Data.Array (listArray, elems)
main :: IO () main = mapM_ print $ [sum, product] <*> [elems $ listArray (1, 10) [11 .. 20]]</lang>
- Output:
155 670442572800
HicEst
<lang hicest>array = $ ! 1, 2, ..., LEN(array)
sum = SUM(array)
product = 1 ! no built-in product function in HicEst DO i = 1, LEN(array)
product = product * array(i)
ENDDO
WRITE(ClipBoard, Name) n, sum, product ! n=100; sum=5050; product=9.33262154E157;</lang>
Icon and Unicon
The program below prints the sum and product of the arguments to the program. <lang Icon>procedure main(arglist) every ( sum := 0 ) +:= !arglist every ( prod := 1 ) *:= !arglist write("sum := ", sum,", prod := ",prod) end</lang>
IDL
<lang idl>array = [3,6,8] print,total(array) print,product(array)</lang>
Inform 7
<lang inform7>Sum And Product is a room.
To decide which number is the sum of (N - number) and (M - number) (this is summing): decide on N + M.
To decide which number is the product of (N - number) and (M - number) (this is production): decide on N * M.
When play begins: let L be {1, 2, 3, 4, 5}; say "List: [L in brace notation], sum = [summing reduction of L], product = [production reduction of L]."; end the story.</lang>
J
<lang j>sum =: +/ product =: */</lang>
For example:
<lang j> sum 1 3 5 7 9 11 13 49
product 1 3 5 7 9 11 13
135135
a=: 3 10 ?@$ 100 NB. random array a
90 47 58 29 22 32 55 5 55 73 58 50 40 5 69 46 34 40 46 84 29 8 75 97 24 40 21 82 77 9
NB. on a table, each row is an item to be summed: sum a
177 105 173 131 115 118 110 127 178 166
product a
151380 18800 174000 14065 36432 58880 39270 16400 194810 55188
NB. but we can tell J to sum everything within each row, instead: sum"1 a
466 472 462
product"1 a
5.53041e15 9.67411e15 1.93356e15</lang>
Java
<lang java5>public class SumProd {
public static void main(final String[] args) { int sum = 0; int prod = 1; int[] arg = {1,2,3,4,5}; for (int i : arg) { sum += i; prod *= i; } }
}</lang>
<lang java5>import java.util.Arrays;
public class SumProd {
public static void main(final String[] args) { int[] arg = {1,2,3,4,5}; System.out.printf("sum = %d\n", Arrays.stream(arg).sum()); System.out.printf("sum = %d\n", Arrays.stream(arg).reduce(0, (a, b) -> a + b)); System.out.printf("product = %d\n", Arrays.stream(arg).reduce(1, (a, b) -> a * b)); }
}</lang>
- Output:
sum = 15 sum = 15 product = 120
JavaScript
ES5
<lang javascript>var array = [1, 2, 3, 4, 5],
sum = 0, prod = 1, i;
for (i = 0; i < array.length; i += 1) {
sum += array[i]; prod *= array[i];
} alert(sum + ' ' + prod);</lang>
Where supported, the reduce method can also be used: <lang javascript>var array = [1, 2, 3, 4, 5],
sum = array.reduce(function (a, b) { return a + b; }, 0), prod = array.reduce(function (a, b) { return a * b; }, 1);
alert(sum + ' ' + prod);</lang>
ES6
<lang JavaScript>(() => {
'use strict';
// sum :: (Num a) => [a] -> a const sum = xs => xs.reduce((a, x) => a + x, 0);
// product :: (Num a) => [a] -> a const product = xs => xs.reduce((a, x) => a * x, 1);
// TEST // show :: a -> String const show = x => JSON.stringify(x, null, 2);
return show( [sum, product] .map(f => f([1, 2, 3, 4, 5, 6, 7, 8, 9, 10])) );
})();</lang>
- Output:
[ 55, 3628800 ]
jq
The builtin filter, add/0, computes the sum of an array: <lang jq>[4,6,8] | add
- => 18</lang>
<lang jq>[range(2;5) * 2] | add
- => 18</lang>
An efficient companion filter for computing the product of the items in an array can be defined as follows: <lang jq>def prod: reduce .[] as $i (1; . * $i);</lang> Examples: <lang jq>[4,6,8] | prod
# => 192</lang>
10! <lang jq>[range(1;11)] | prod
- =>3628800</lang>
Julia
<lang julia>julia> sum([4,6,8]) 18
julia> +((1:10)...) 55
julia +([1,2,3]...) 6
julia> prod([4,6,8]) 192</lang>
K
<lang k> sum: {+/}x
product: {*/}x a: 1 3 5 7 9 11 13 sum a
49
product a
135135</lang>
It is easy to see the relationship of K to J here.
Kotlin
<lang scala>// version 1.1.2
fun main(args: Array<String>) {
val a = intArrayOf(1, 5, 8, 11, 15) println("Array contains : ${a.contentToString()}") val sum = a.sum() println("Sum is $sum") val product = a.fold(1) { acc, i -> acc * i } println("Product is $product")
}</lang>
- Output:
Array contains : [1, 5, 8, 11, 15] Sum is 40 Product is 6600
Lambdatalk
<lang lisp> {A.serie start end [step]} creates a sequence from start to end with optional step {A.new words} creates an array from a sequence of words {A.toS array} creates a sequence from the items of an array {long_add x y} returns the sum of two integers of any size {long_mult x y} returns the product of two integers of any size
{def A {A.new {S.serie 1 10}}} -> [1,2,3,4,5,6,7,8,9,10] {+ {A.toS {A}}} -> 55 {* {A.toS {A}}} -> 3628800
{def B {A.new {S.serie 1 100}}} -> [1,2,3,4,5,6,7,8,9,10,...,95,96,97,98,99,100] {S.reduce long_add {A.toS {B}}} -> 5050 {S.reduce long_mult {A.toS {B}}} -> 9332621544394415268169923885626670049071596826438162146859296389521759999322991 5608941463976156518286253697920827223758251185210916864000000000000000000000000 </lang>
Lang5
<lang lang5>4 iota 1 + dup
'+ reduce '* reduce</lang>
langur
<lang langur>val .arr = series 19 writeln " array: ", .arr writeln " sum: ", fold f .x + .y, .arr writeln "product: ", fold f .x x .y, .arr</lang>
<lang langur>val .arr = series 19 writeln " array: ", .arr writeln " sum: ", fold f{+}, .arr writeln "product: ", fold f{x}, .arr</lang>
- Output:
array: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19] sum: 190 product: 121645100408832000
Lasso
<lang Lasso>local(x = array(1,2,3,4,5,6,7,8,9,10)) // sum of array elements 'Sum: ' with n in #x sum #n '\r' // product of arrray elements 'Product: ' local(product = 1) with n in #x do => { #product *= #n }
- product</lang>
- Output:
Sum: 55 Product: 3628800
Liberty BASIC
<lang lb>Dim array(19)
For i = 0 To 19
array(i) = Int(Rnd(1) * 20)
Next i
'product must first equal one or you will get 0 as the product product = 1 For i = 0 To 19
sum = (sum + array(i)) product = (product * array(i))
next i
Print "Sum is " + str$(sum) Print "Product is " + str$(product)</lang>
Lingo
<lang lingo>on sum (intList)
res = 0 repeat with v in intList res = res + v end repeat return res
end
on product (intList)
res = 1 repeat with v in intList res = res * v end repeat return res
end</lang>
LiveCode
<lang LiveCode>//sum put "1,2,3,4" into nums split nums using comma answer sum(nums)
// product local prodNums repeat for each element n in nums
if prodNums is empty then put n into prodNums else multiply prodnums by n end if
end repeat answer prodnums</lang>
Logo
<lang logo>print apply "sum arraytolist {1 2 3 4 5} print apply "product arraytolist {1 2 3 4 5}</lang>
Lua
<lang lua> function sumf(a, ...) return a and a + sumf(...) or 0 end function sumt(t) return sumf(unpack(t)) end function prodf(a, ...) return a and a * prodf(...) or 1 end function prodt(t) return prodf(unpack(t)) end
print(sumt{1, 2, 3, 4, 5}) print(prodt{1, 2, 3, 4, 5})</lang>
<lang lua> function table.sum(arr, length)
--same as if <> then <> else <> return length == 1 and arr[1] or arr[length] + table.sum(arr, length -1)
end
function table.product(arr, length)
return length == 1 and arr[1] or arr[length] * table.product(arr, length -1)
end
t = {1,2,3} print(table.sum(t,#t)) print(table.product(t,3)) </lang>
Lucid
prints a running sum and product of sequence 1,2,3... <lang lucid>[%sum,product%]
where x = 1 fby x + 1; sum = 0 fby sum + x; product = 1 fby product * x end</lang>
M2000 Interpreter
<lang M2000 Interpreter> Module Checkit {
a = (1,2,3,4,5,6,7,8,9,10) print a#sum() = 55 sum = lambda->{push number+number} product = lambda->{Push number*number} print a#fold(lambda->{Push number*number}, 1), a#fold(lambda->{push number+number},0) dim a(2,2) = 5 Print a()#sum() = 20
} checkit </lang>
Maple
<lang maple>a := Array([1, 2, 3, 4, 5, 6]); add(a); mul(a);</lang>
Mathematica
Mathematica provides many ways of doing the sum of an array (any kind of numbers or symbols): <lang Mathematica>a = {1, 2, 3, 4, 5} Plus @@ a Apply[Plus, a] Total[a] Total@a a // Total Sum[ai, {i, 1, Length[a]}] Sum[i, {i, a}]</lang> all give 15. For product we also have a couple of choices: <lang Mathematica>a = {1, 2, 3, 4, 5} Times @@ a Apply[Times, a] Product[ai, {i, 1, Length[a]}] Product[i, {i, a}]</lang> all give 120.
MATLAB
These two function are built into MATLAB as the "sum(array)" and "prod(array)" functions.
Sample Usage: <lang MATLAB>>> array = [1 2 3;4 5 6;7 8 9]
array =
1 2 3 4 5 6 7 8 9
>> sum(array,1)
ans =
12 15 18
>> sum(array,2)
ans =
6 15 24
>> prod(array,1)
ans =
28 80 162
>> prod(array,2)
ans =
6 120 504</lang>
Maxima
<lang maxima>lreduce("+", [1, 2, 3, 4, 5, 6, 7, 8]); 36
lreduce("*", [1, 2, 3, 4, 5, 6, 7, 8]); 40320</lang>
MAXScript
<lang maxscript>arr = #(1, 2, 3, 4, 5) sum = 0 for i in arr do sum += i product = 1 for i in arr do product *= i</lang>
min
<lang min>(1 2 3 4 5) ((sum) (1 '* reduce)) cleave "Sum: $1\nProduct: $2" get-stack % puts</lang>
- Output:
Sum: 15 Product: 120
МК-61/52
<lang>^ 1 ПE + П0 КИП0 x#0 18 ^ ИПD + ПD <-> ИПE * ПE БП 05 С/П</lang>
Instruction: РX - array length, Р1:РC - array, РD and РE - sum and product of an array.
Modula-3
<lang modula3>MODULE Sumprod EXPORTS Main;
FROM IO IMPORT Put; FROM Fmt IMPORT Int;
VAR a := ARRAY [1..5] OF INTEGER {1, 2, 3, 4, 5}; VAR sum: INTEGER := 0; VAR prod: INTEGER := 1;
BEGIN
FOR i := FIRST(a) TO LAST(a) DO INC(sum, a[i]); prod := prod * a[i]; END; Put("Sum of array: " & Int(sum) & "\n"); Put("Product of array: " & Int(prod) & "\n");
END Sumprod.</lang>
- Output:
Sum of array: 15 Product of array: 120
MUMPS
<lang MUMPS> SUMPROD(A)
;Compute the sum and product of the numbers in the array A NEW SUM,PROD,POS ;SUM is the running sum, ;PROD is the running product, ;POS is the position within the array A SET SUM=0,PROD=1,POS="" FOR SET POS=$ORDER(A(POS)) Q:POS="" SET SUM=SUM+A(POS),PROD=PROD*A(POS) WRITE !,"The sum of the array is "_SUM WRITE !,"The product of the array is "_PROD KILL SUM,PROD,POS QUIT</lang>
Example:
USER>SET C(-1)=2,C("A")=3,C(42)=1,C(0)=7 USER>D SUMPROD^ROSETTA(.C) The sum of the array is 13 The product of the array is 42
Note - the string "A" converts to 0 when doing mathematical operations.
USER>SET C(-1)=2,C("A")="3H",C(42)=.1,C(0)=7.0,C("B")="A" USER>D SUMPROD^ROSETTA(.C) The sum of the array is 12.1 The product of the array is 0
Nemerle
As mentioned for some of the other functional languages, it seems more natural to work with lists in Nemerle, but as the task specifies working on an array, this solution will work on either. <lang Nemerle>using System; using System.Console; using System.Collections.Generic; using Nemerle.Collections;
module SumProd {
Sum[T] (nums : T) : int where T : IEnumerable[int] { nums.FoldLeft(0, _+_) } Product[T] (nums : T) : int where T : IEnumerable[int] { nums.FoldLeft(1, _*_) } Main() : void { def arr = array[1, 2, 3, 4, 5]; def lis = [1, 2, 3, 4, 5]; def suml = Sum(lis); def proda = Product(arr); WriteLine("Sum is: {0}\tProduct is: {1}", suml, proda); }
}</lang>
NetRexx
<lang NetRexx>/* NetRexx */
options replace format comments java crossref savelog symbols binary
harry = [long 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
sum = long 0 product = long 1 entries = Rexx
loop n_ = int 0 to harry.length - 1
nxt = harry[n_] entries = entries nxt sum = sum + nxt product = product * nxt end n_
entries = entries.strip
say 'Sum and product of' entries.changestr(' ', ',')':' say ' Sum:' sum say ' Product:' product
return </lang>
- Output:
Sum and product of 1,2,3,4,5,6,7,8,9,10: Sum: 55 Product: 3628800
NewLISP
<lang NewLISP>(setq a '(1 2 3 4 5)) (apply + a) (apply * a)</lang>
Nial
Nial being an array language, what applies to individual elements are extended to cover array operations by default strand notation <lang nial>+ 1 2 3 = 6
- 1 2 3
= 6</lang> array notation <lang nial>+ [1,2,3]</lang> grouped notation <lang nial>(* 1 2 3) = 6
- (1 2 3)
= 6</lang> (All these notations are equivalent)
Nim
<lang nim>var xs = @[1,2,3,4,5,6]
var sum, product: int
product = 1
for x in xs:
sum += x product *= x</lang>
Or functionally: <lang nim>import sequtils
let
xs = @[1,2,3,4,5,6] sum = xs.foldl(a + b) product = xs.foldl(a * b)</lang>
Or using a math function: <lang nim>import math
let numbers = @[1, 5, 4] let total = sum(numbers)
var product = 1 for n in numbers:
product *= n</lang>
Objeck
<lang objeck> sum := 0; prod := 1; arg := [1, 2, 3, 4, 5]; each(i : arg) {
sum += arg[i]; prod *= arg[i];
}; </lang>
Objective-C
Sum: <lang objc>- (float) sum:(NSMutableArray *)array { int i, sum, value; sum = 0; value = 0;
for (i = 0; i < [array count]; i++) { value = [[array objectAtIndex: i] intValue]; sum += value; }
return suml; }</lang> Product: <lang objc>- (float) prod:(NSMutableArray *)array { int i, prod, value; prod = 0; value = 0;
for (i = 0; i < [array count]; i++) { value = [[array objectAtIndex: i] intValue]; prod *= value; }
return suml; }</lang>
OCaml
Arrays
<lang ocaml>(* ints *) let a = [| 1; 2; 3; 4; 5 |];; Array.fold_left (+) 0 a;; Array.fold_left ( * ) 1 a;; (* floats *) let a = [| 1.0; 2.0; 3.0; 4.0; 5.0 |];; Array.fold_left (+.) 0.0 a;; Array.fold_left ( *.) 1.0 a;;</lang>
Lists
<lang ocaml>(* ints *) let x = [1; 2; 3; 4; 5];; List.fold_left (+) 0 x;; List.fold_left ( * ) 1 x;; (* floats *) let x = [1.0; 2.0; 3.0; 4.0; 5.0];; List.fold_left (+.) 0.0 x;; List.fold_left ( *.) 1.0 x;;</lang>
Octave
<lang octave>a = [ 1, 2, 3, 4, 5, 6 ]; b = [ 10, 20, 30, 40, 50, 60 ]; vsum = a + b; vprod = a .* b;</lang>
Oforth
<lang Oforth>[1, 2, 3, 4, 5 ] sum println [1, 3, 5, 7, 9 ] prod println</lang>
- Output:
15 945
Ol
<lang scheme> (print (fold + 0 '(1 2 3 4 5))) (print (fold * 1 '(1 2 3 4 5))) </lang>
ooRexx
<lang oorexx>a=.my_array~new(20) do i=1 To 20
a[i]=i End
s=a~makestring((LINE),',') Say s Say ' sum='a~sum Say 'product='a~prod
- class my_array subclass array
- method sum
sum=0 Do i=1 To self~dimension(1)
sum+=self[i] End
Return sum
- method prod
Numeric Digits 30 prod=1 Do i=1 To self~dimension(1)
prod*=self[i] End
Return prod</lang>
- Output:
1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20 sum=210 product=2432902008176640000
Oz
Calculations like this are typically done on lists, not on arrays: <lang oz>declare
Xs = [1 2 3 4 5] Sum = {FoldL Xs Number.'+' 0} Product = {FoldL Xs Number.'*' 1}
in
{Show Sum} {Show Product}</lang>
If you are actually working with arrays, a more imperative approach seems natural: <lang oz>declare
Arr = {Array.new 1 3 0} Sum = {NewCell 0}
in
Arr.1 := 1 Arr.2 := 2 Arr.3 := 3
for I in {Array.low Arr}..{Array.high Arr} do Sum := @Sum + Arr.I end {Show @Sum}</lang>
PARI/GP
These are built in to GP: vecsum
and factorback
(the latter can also take factorization matrices, thus the name). They could be coded like so:
<lang parigp>vecsum1(v)={
sum(i=1,#v,v[i])
}; vecprod(v)={
prod(i=1,#v,v[i])
};</lang>
In 2.10.0 the function vecprod
was introduced as well. Like factorback
it gives the product of the elements of an array but unlike factorback
it doesn't handle factorization matrices.
Pascal
See Delphi
Perl
<lang perl>my @list = ( 1, 2, 3 );
my ( $sum, $prod ) = ( 0, 1 ); $sum += $_ foreach @list; $prod *= $_ foreach @list;</lang> Or using the List::Util module: <lang perl>use List::Util qw/sum0 product/; my @list = (1..9);
say "Sum: ", sum0(@list); # sum0 returns 0 for an empty list say "Product: ", product(@list);</lang>
- Output:
Sum: 45 Product: 362880
Phix
<lang Phix>sequence s = {1,2,3,4,5} printf(1,"sum is %d\n",sum(s)) printf(1,"prod is %d\n",product(s))</lang>
- Output:
sum is 15 prod is 120
Phixmonti
<lang Phixmonti>include ..\Utilitys.pmt
( 1 2 3 4 5 )
dup sum "sum is " print print nl
1 swap len for
get rot * swap
endfor drop
"mult is " print print nl</lang>
PHP
<lang php>$array = array(1,2,3,4,5,6,7,8,9); echo array_sum($array); echo array_product($array);</lang>
PicoLisp
<lang PicoLisp>(let Data (1 2 3 4 5)
(cons (apply + Data) (apply * Data) ) )</lang>
- Output:
(15 . 120)
PL/I
<lang pli>declare A(10) fixed binary static initial
(1, 2, 3, 4, 5, 6, 7, 8, 9, 10);
put skip list (sum(A)); put skip list (prod(A));</lang>
Plain English
<lang plainenglish>An element is a thing with a number.
To find a sum and a product of some elements: Put 0 into the sum. Put 1 into the product. Get an element from the elements. Loop. If the element is nil, exit. Add the element's number to the sum. Multiply the product by the element's number. Put the element's next into the element. Repeat.
To make some example elements: If a counter is past 10, exit. Allocate memory for an element. Put the counter into the element's number. Append the element to the example. Repeat.
A product is a number.
To run: Start up. Make some example elements. Find a sum and a product of the example elements. Destroy the example elements. Write "Sum: " then the sum on the console. Write "Product: " then the product on the console. Wait for the escape key. Shut down.
A sum is a number.</lang>
- Output:
Sum: 55 Product: 3628800
Pop11
Simple loop: <lang pop11>lvars i, sum = 0, prod = 1, ar = {1 2 3 4 5 6 7 8 9}; for i from 1 to length(ar) do
ar(i) + sum -> sum; ar(i) * prod -> prod;
endfor;</lang> One can alternatively use second order iterator: <lang pop11>lvars sum = 0, prod = 1, ar = {1 2 3 4 5 6 7 8 9}; appdata(ar, procedure(x); x + sum -> sum; endprocedure); appdata(ar, procedure(x); x * prod -> prod; endprocedure);</lang>
PostScript
<lang> /sumandproduct { /x exch def /sum 0 def /prod 0 def /i 0 def x length 0 eq { } { /prod prod 1 add def x length{ /sum sum x i get add def /prod prod x i get mul def /i i 1 add def }repeat }ifelse sum == prod == }def </lang>
<lang postscript> % sum [1 1 1 1 1] 0 {add} fold % product [1 1 1 1 1] 1 {mul} fold
</lang>
PowerShell
The Measure-Object
cmdlet already knows how to compute a sum:
<lang powershell>function Get-Sum ($a) {
return ($a | Measure-Object -Sum).Sum
}</lang> But not how to compute a product: <lang powershell>function Get-Product ($a) {
if ($a.Length -eq 0) { return 0 } else { $p = 1 foreach ($x in $a) { $p *= $x } return $p }
}</lang> One could also let PowerShell do all the work by simply creating an expression to evaluate:
<lang powershell>function Get-Product ($a) {
if ($a.Length -eq 0) { return 0 } $s = $a -join '*' return (Invoke-Expression $s)
}</lang> Even nicer, however, is a function which computes both at once and returns a custom object with appropriate properties: <lang powershell>function Get-SumAndProduct ($a) {
$sum = 0 if ($a.Length -eq 0) { $prod = 0 } else { $prod = 1 foreach ($x in $a) { $sum += $x $prod *= $x } } $ret = New-Object PSObject $ret | Add-Member NoteProperty Sum $sum $ret | Add-Member NoteProperty Product $prod return $ret
}</lang>
- Output:
PS> Get-SumAndProduct 5,9,7,2,3,8,4 Sum Product --- ------- 38 60480
Prolog
<lang prolog>sum([],0). sum([H|T],X) :- sum(T,Y), X is H + Y. product([],1). product([H|T],X) :- product(T,Y), X is H * X.</lang>
test
:- sum([1,2,3,4,5,6,7,8,9],X). X =45; :- product([1,2,3,4,5],X). X = 120;
Using fold
<lang prolog>
add(A,B,R):-
R is A + B.
mul(A,B,R):-
R is A * B.
% define fold now. fold([], Act, Init, Init).
fold(Lst, Act, Init, Res):-
head(Lst,Hd), tail(Lst,Tl), apply(Act,[Init, Hd, Ra]), fold(Tl, Act, Ra, Res).
sumproduct(Lst, Sum, Prod):-
fold(Lst,mul,1, Prod), fold(Lst,add,0, Sum).
?- sumproduct([1,2,3,4],Sum,Prod). Sum = 10, Prod = 24 .
</lang>
PureBasic
<lang PureBasic>Dim MyArray(9) Define a, sum=0, prod=1
For a = 0 To ArraySize(MyArray()) ; Create a list of some random numbers
MyArray(a) = 1 + Random(9) ; Insert a number [1...10] in current element
Next
For a = 0 To ArraySize(MyArray()) ; Calculate Sum and Product of this Array
sum + MyArray(a) prod * MyArray(a)
Next
Debug "The sum is " + Str(sum) ; Present the results Debug "Product is " + Str(prod)</lang>
Python
<lang python>numbers = [1, 2, 3] total = sum(numbers)
product = 1 for i in numbers:
product *= i</lang>
Or functionally (faster but perhaps less clear):
<lang python>from operator import mul, add sum = reduce(add, numbers) # note: this version doesn't work with empty lists sum = reduce(add, numbers, 0) product = reduce(mul, numbers) # note: this version doesn't work with empty lists product = reduce(mul, numbers, 1)</lang>
<lang python>from numpy import r_ numbers = r_[1:4] total = numbers.sum() product = numbers.prod()</lang>
If you are summing floats in Python 2.6+, you should use math.fsum() to avoid loss of precision:
<lang python>import math total = math.fsum(floats)</lang>
Quackery
<lang Quackery>[ 0 swap witheach + ] is sum ( [ --> n )
[ 1 swap witheach * ] is product ( [ --> n )</lang> In the shell (i.e. Quackery REPL): <lang Quackery> /O> ' [ 1 2 3 4 5 ] sum echo cr ... ' [ 1 2 3 4 5 ] product echo ... 15 120 Stack empty.</lang>
R
<lang r>total <- sum(1:5) product <- prod(1:5)</lang>
Racket
<lang racket>#lang racket
(for/sum ([x #(3 1 4 1 5 9)]) x) (for/product ([x #(3 1 4 1 5 9)]) x)</lang>
Raku
(formerly Perl 6) <lang perl6>my @ary = 1, 5, 10, 100; say 'Sum: ', [+] @ary; say 'Product: ', [*] @ary;</lang>
Raven
<lang raven>0 [ 1 2 3 ] each + 1 [ 1 2 3 ] each *</lang>
REBOL
<lang REBOL>REBOL [
Title: "Sum and Product" URL: http://rosettacode.org/wiki/Sum_and_product_of_array
]
- Simple
sum: func [a [block!] /local x] [x: 0 forall a [x: x + a/1] x]
product: func [a [block!] /local x] [x: 1 forall a [x: x * a/1] x]
- Way too fancy
redux: func [ "Applies an operation across an array to produce a reduced value." a [block!] "Array to operate on." op [word!] "Operation to perform." /init x "Initial value (default 0)." ][if not init [x: 0] forall a [x: do compose [x (op) (a/1)]] x]
rsum: func [a [block!]][redux a '+]
rproduct: func [a [block!]][redux/init a '* 1]
- Tests
assert: func [code][print [either do code [" ok"]["FAIL"] mold code]]
print "Simple dedicated functions:" assert [55 = sum [1 2 3 4 5 6 7 8 9 10]] assert [3628800 = product [1 2 3 4 5 6 7 8 9 10]]
print [crlf "Fancy reducing function:"] assert [55 = rsum [1 2 3 4 5 6 7 8 9 10]] assert [3628800 = rproduct [1 2 3 4 5 6 7 8 9 10]]</lang>
- Output:
Simple dedicated functions: ok [55 = sum [1 2 3 4 5 6 7 8 9 10]] ok [3628800 = product [1 2 3 4 5 6 7 8 9 10]] Fancy reducing function: ok [55 = rsum [1 2 3 4 5 6 7 8 9 10]] ok [3628800 = rproduct [1 2 3 4 5 6 7 8 9 10]]
REXX
<lang rexx>/*REXX program adds and multiplies N elements of a (populated) array @. */ numeric digits 200 /*200 decimal digit #s (default is 9).*/ parse arg N .; if N== then N=20 /*Not specified? Then use the default.*/
do j=1 for N /*build array of N elements (or 20?).*/ @.j=j /*set 1st to 1, 3rd to 3, 8th to 8 ··· */ end /*j*/
sum=0 /*initialize SUM (variable) to zero. */ prod=1 /*initialize PROD (variable) to unity.*/
do k=1 for N sum = sum + @.k /*add the element to the running total.*/ prod = prod * @.k /*multiply element to running product. */ end /*k*/ /* [↑] this pgm: same as N factorial.*/
say ' sum of ' m " elements for the @ array is: " sum say ' product of ' m " elements for the @ array is: " prod
/*stick a fork in it, we're all done. */</lang>
output using the default input of: 20
sum of M elements for the @ array is: 210 product of M elements for the @ array is: 2432902008176640000
Ring
<lang ring> aList = 1:10 nSum=0 nProduct=0 for x in aList nSum += x nProduct *= x next See "Sum = " + nSum + nl See "Product = " + nProduct + nl </lang>
Ruby
<lang ruby>arr = [1,2,3,4,5] # or ary = *1..5, or ary = (1..5).to_a p sum = arr.inject(0) { |sum, item| sum + item }
- => 15
p product = arr.inject(1) { |prod, element| prod * element }
- => 120</lang>
<lang ruby>arr = [1,2,3,4,5] p sum = arr.inject(0, :+) #=> 15 p product = arr.inject(1, :*) #=> 120
- If you do not explicitly specify an initial value for memo,
- then the first element of collection is used as the initial value of memo.
p sum = arr.inject(:+) #=> 15 p product = arr.inject(:*) #=> 120</lang>
Note: When the Array is empty, the initial value returns. However, nil returns if not giving an initial value. <lang ruby>arr = [] p arr.inject(0, :+) #=> 0 p arr.inject(1, :*) #=> 1 p arr.inject(:+) #=> nil p arr.inject(:*) #=> nil</lang>
Enumerable#reduce is the alias of Enumerable#inject.
<lang ruby>arr = [1,2,3,4,5] p sum = arr.sum #=> 15 p [].sum #=> 0</lang>
Run BASIC
<lang runbasic>dim array(100) for i = 1 To 100
array(i) = rnd(0) * 100
next i
product = 1 for i = 0 To 19
sum = (sum + array(i)) product = (product * array(i))
next i
Print " Sum is ";sum Print "Product is ";product</lang>
Rust
<lang rust>
fn main() {
let arr = vec![1, 2, 3, 4, 5, 6, 7, 8, 9];
// using fold let sum = arr.iter().fold(0i32, |a, &b| a + b); let product = arr.iter().fold(1i32, |a, &b| a * b); println!("the sum is {} and the product is {}", sum, product);
// or using sum and product let sum = arr.iter().sum::<i32>(); let product = arr.iter().product::<i32>(); println!("the sum is {} and the product is {}", sum, product);
} </lang>
S-lang
<lang S-lang>variable a = [5, -2, 3, 4, 666, 7];</lang>
The sum of array elements is handled by an intrinsic. [note: print is slsh-specific; if not available, use printf().]
<lang S-lang>print(sum(a));</lang>
The product is slightly more involved; I'll use this as a chance to show the alternate stack-based use of 'foreach': <lang S-lang>variable prod = a[0];
% Skipping the loop variable causes the val to be placed on the stack. % Also note that the double-brackets ARE required. The inner one creates % a "range array" based on the length of a. foreach (a1:)
% () pops it off. prod *= ();
print(prod);</lang>
SAS
<lang sas>data _null_;
array a{*} a1-a100; do i=1 to 100; a{i}=i*i; end; b=sum(of a{*}); put b c;
run;</lang>
Sather
<lang sather>class MAIN is
main is a :ARRAY{INT} := |10, 5, 5, 20, 60, 100|; sum, prod :INT; loop sum := sum + a.elt!; end; prod := 1; loop prod := prod * a.elt!; end; #OUT + sum + " " + prod + "\n"; end;
end;</lang>
Scala
<lang scala>val seq = Seq(1, 2, 3, 4, 5) val sum = seq.foldLeft(0)(_ + _) val product = seq.foldLeft(1)(_ * _)</lang>
Or even shorter: <lang scala>val sum = seq.sum val product = seq.product</lang>
Works with all data types for which a Numeric implicit is available.
Scheme
<lang scheme>(apply + '(1 2 3 4 5)) (apply * '(1 2 3 4 5))</lang> A tail-recursive solution, without the n-ary operator "trick". Because Scheme supports tail call optimization, this is as space-efficient as an imperative loop. <lang scheme>(define (reduce f i l)
(if (null? l) i (reduce f (f i (car l)) (cdr l))))
(reduce + 0 '(1 2 3 4 5)) ;; 0 is unit for + (reduce * 1 '(1 2 3 4 5)) ;; 1 is unit for *</lang>
Seed7
<lang seed7>const func integer: sumArray (in array integer: valueArray) is func
result var integer: sum is 0; local var integer: value is 0; begin for value range valueArray do sum +:= value; end for; end func;
const func integer: prodArray (in array integer: valueArray) is func
result var integer: prod is 1; local var integer: value is 0; begin for value range valueArray do prod *:= value; end for; end func;</lang>
Call these functions with:
writeln(sumArray([](1, 2, 3, 4, 5))); writeln(prodArray([](1, 2, 3, 4, 5)));
SETL
<lang SETL>numbers := [1 2 3 4 5 6 7 8 9]; print(+/ numbers, */ numbers);</lang>
=> 45 362880
Sidef
Using built-in methods: <lang ruby>var ary = [1, 2, 3, 4, 5]; say ary.sum; # => 15 say ary.prod; # => 120</lang>
Alternatively, using hyper-operators: <lang ruby>var ary = [1, 2, 3, 4, 5]; say ary«+»; # => 15 say ary«*»; # => 120</lang>
Slate
<lang slate>#(1 2 3 4 5) reduce: [:sum :number | sum + number]
- (1 2 3 4 5) reduce: [:product :number | product * number]</lang>
Shorthand for the above with a macro: <lang slate>#(1 2 3 4 5) reduce: #+ `er
- (1 2 3 4 5) reduce: #* `er</lang>
Smalltalk
<lang smalltalk>#(1 2 3 4 5) inject: 0 into: [:sum :number | sum + number]
- (1 2 3 4 5) inject: 1 into: [:product :number | product * number]</lang>
Some implementation also provide a fold: message: <lang smalltalk>#(1 2 3 4 5) fold: [:sum :number | sum + number]
- (1 2 3 4 5) fold: [:product :number | product * number]</lang>
SNOBOL4
<lang snobol> t = table()
- read the integer from the std. input
init_tab t<x = x + 1> = trim(input) :s(init_tab)
product = 1 sum = 0
- counting backwards to 1
loop i = t< x = ?gt(x,1) x - 1> :f(out)
sum = sum + i product = product * i :(loop)
out output = "Sum: " sum
output = "Prod: " product
end</lang>
Input
1 2 3 4 5
- Output:
Sum: 15 Prod: 120
Sparkling
<lang Sparkling>spn:1> reduce({ 1, 2, 3, 4, 5 }, 0, function(x, y) { return x + y; }) = 15 spn:2> reduce({ 1, 2, 3, 4, 5 }, 1, function(x, y) { return x * y; }) = 120</lang>
Standard ML
Arrays
<lang sml>(* ints *) val a = Array.fromList [1, 2, 3, 4, 5]; Array.foldl op+ 0 a; Array.foldl op* 1 a; (* reals *) val a = Array.fromList [1.0, 2.0, 3.0, 4.0, 5.0]; Array.foldl op+ 0.0 a; Array.foldl op* 1.0 a;</lang>
Lists
<lang sml>(* ints *) val x = [1, 2, 3, 4, 5]; foldl op+ 0 x; foldl op* 1 x; (* reals *) val x = [1.0, 2.0, 3.0, 4.0, 5.0]; foldl op+ 0.0 x; foldl op* 1.0 x;</lang>
Stata
Mata does not have a builtin product function, but one can do the following, which will compute the product of nonzero elements of the array:
<lang stata>a = 1,-2,-3,-4,5 sum(a)
-3
(-1)^mod(sum(a:<0),2)*exp(sum(log(abs(a))))
-120</lang>
Swift
<lang swift>let a = [1, 2, 3, 4, 5] println(a.reduce(0, +)) // prints 15 println(a.reduce(1, *)) // prints 120
println(reduce(a, 0, +)) // prints 15 println(reduce(a, 1, *)) // prints 120</lang>
Tcl
<lang tcl>set arr [list 3 6 8] set sum [expr [join $arr +]] set prod [expr [join $arr *]]</lang>
<lang tcl>set arr [list 3 6 8] set sum [tcl::mathop::+ {*}$arr] set prod [tcl::mathop::* {*}$arr]</lang>
TI-83 BASIC
Use the built-in functions sum()
and prod()
.
<lang ti83b>seq(X,X,1,10,1)→L₁
{1 2 3 4 5 6 7 8 9 10}
sum(L₁)
55
prod(L₁)
3628800</lang>
Toka
<lang toka>4 cells is-array foo
212 1 foo array.put 51 2 foo array.put 12 3 foo array.put 91 4 foo array.put
[ ( array size -- sum )
>r 0 r> 0 [ over i swap array.get + ] countedLoop nip ] is sum-array
( product )
reset 1 4 0 [ i foo array.get * ] countedLoop .</lang>
Trith
<lang trith>[1 2 3 4 5] 0 [+] foldl</lang> <lang trith>[1 2 3 4 5] 1 [*] foldl</lang>
TUSCRIPT
<lang tuscript> $$ MODE TUSCRIPT list="1'2'3'4'5" sum=SUM(list) PRINT " sum: ",sum
product=1 LOOP l=list product=product*l ENDLOOP PRINT "product: ",product </lang>
- Output:
sum: 15 product: 120
UNIX Shell
From an internal variable, $IFS delimited:
<lang bash>sum=0 prod=1 list="1 2 3" for n in $list do sum="$(($sum + $n))"; prod="$(($prod * $n))" done echo $sum $prod</lang>
From the argument list (ARGV):
<lang bash>sum=0 prod=1 for n do sum="$(($sum + $n))"; prod="$(($prod * $n))" done echo $sum $prod</lang>
From STDIN, one integer per line:
<lang bash>sum=0 prod=1 while read n do sum="$(($sum + $n))"; prod="$(($prod * $n))" done echo $sum $prod</lang>
From variable:
<lang bash>LIST='20 20 2'; SUM=0; PROD=1; for i in $LIST; do
SUM=$[$SUM + $i]; PROD=$[$PROD * $i];
done; echo $SUM $PROD</lang>
UnixPipes
Uses ksh93-style process substitution.
<lang bash>prod() {
(read B; res=$1; test -n "$B" && expr $res \* $B || echo $res)
}
sum() {
(read B; res=$1; test -n "$B" && expr $res + $B || echo $res)
}
fold() {
(func=$1; while read a ; do fold $func | $func $a ; done)
}
(echo 3; echo 1; echo 4;echo 1;echo 5;echo 9) |
tee >(fold sum) >(fold prod) > /dev/null</lang>
There is a race between fold sum
and fold prod
, which run in parallel. The program might print sum before product, or print product before sum.
Ursa
Ursa doesn't have arrays in the traditional sense. Its equivalent is the stream. All math operators take streams as arguments, so sums and products of streams can be found like this. <lang ursa>declare int<> stream append 34 76 233 8 2 734 56 stream
- outputs 1143
out (+ stream) endl console
- outputs 3.95961079808E11
out (* stream) endl console</lang>
Ursala
The reduction operator, :-, takes an associative binary function and a constant for the empty case. Natural numbers are unsigned and of unlimited size. <lang Ursala>#import nat
- cast %nW
sp = ^(sum:-0,product:-1) <62,43,46,40,29,55,51,82,59,92,48,73,93,35,42,25></lang>
- Output:
(875,2126997171723931187788800000)
V
<lang v>[sp dup 0 [+] fold 'product=' put puts 1 [*] fold 'sum=' put puts].</lang>
- Using it:
<lang v>[1 2 3 4 5] sp = product=15 sum=120</lang>
Vala
<lang Vala>void main() {
int sum = 0, prod = 1; int[] data = { 1, 2, 3, 4 }; foreach (int val in data) { sum += val; prod *= val; } print(@"sum: $(sum)\nproduct: $(prod)");
}</lang>
- Output:
sum: 10 product: 24
VBA
Assumes Excel is used. <lang vb>Sub Demo() Dim arr
arr = Array(1, 2, 3, 4, 5, 6, 7, 8, 9, 10) Debug.Print "sum : " & Application.WorksheetFunction.Sum(arr) Debug.Print "product : " & Application.WorksheetFunction.Product(arr)
End Sub</lang>
- Output:
sum : 55 product : 3628800
VBScript
<lang vb>Function sum_and_product(arr) sum = 0 product = 1 For i = 0 To UBound(arr) sum = sum + arr(i) product = product * arr(i) Next WScript.StdOut.Write "Sum: " & sum WScript.StdOut.WriteLine WScript.StdOut.Write "Product: " & product WScript.StdOut.WriteLine End Function
myarray = Array(1,2,3,4,5,6) sum_and_product(myarray) </lang>
- Output:
Sum: 21 Product: 720
Visual Basic .NET
<lang vbnet>Module Program
Sub Main() Dim arg As Integer() = {1, 2, 3, 4, 5} Dim sum = arg.Sum() Dim prod = arg.Aggregate(Function(runningProduct, nextFactor) runningProduct * nextFactor) End Sub
End Module</lang>
Wart
<lang wart>def (sum_prod nums)
(list (+ @nums) (* @nums))</lang>
WDTE
<lang WDTE>let a => import 'arrays'; let s => import 'stream';
let sum array => a.stream array -> s.reduce 0 +; let prod array => a.stream prod -> s.reduce 1 *;</lang>
Wortel
<lang wortel>@sum [1 2 3 4] ; returns 10 @prod [1 2 3 4] ; returns 24</lang>
Wren
<lang ecmascript>import "/math" for Nums var a = [7, 10, 2, 4, 6, 1, 8, 3, 9, 5] System.print("Array : %(a)") System.print("Sum : %(Nums.sum(a))") System.print("Product : %(Nums.prod(a))")</lang>
- Output:
Array : [7, 10, 2, 4, 6, 1, 8, 3, 9, 5] Sum : 55 Product : 3628800
XPL0
<lang XPL0>code CrLf=9, IntOut=11;
func SumProd(A, L); int A, L; int S, P, I; [S:= 0; P:= 1; for I:= 0 to L-1 do [S:= S+A(I); P:= P*A(I)]; IntOut(0, S); CrLf(0); IntOut(0, P); CrLf(0); ]; \SumSq
SumProd([1,2,3,4,5,6,7,8,9,10], 10)</lang>
- Output:
55 3628800
XSLT
XSLT (or XPath rather) has a few built-in functions for reducing from a collection, but product is not among them. Because of referential transparency, one must resort to recursive solutions for general iterative operations upon collections. The following code represents the array by numeric values in <price> elements in the source document.
<lang xml><xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text" /> <xsl:template name="sum-prod"> <xsl:param name="values" /> <xsl:param name="sum" select="0" /> <xsl:param name="prod" select="1" /> <xsl:choose> <xsl:when test="not($values)"> <xsl:text>
Sum: </xsl:text>
<xsl:value-of select="$sum" /> <xsl:text>
Product: </xsl:text>
<xsl:value-of select="$prod" /> </xsl:when> <xsl:otherwise> <xsl:call-template name="sum-prod"> <xsl:with-param name="values" select="$values[position() > 1]" /> <xsl:with-param name="sum" select="$sum + $values[1]" /> <xsl:with-param name="prod" select="$prod * $values[1]" /> </xsl:call-template> </xsl:otherwise> </xsl:choose> </xsl:template> <xsl:template match="/"> <xsl:text>
Sum (built-in): </xsl:text>
<xsl:value-of select="sum(//price)" /> <xsl:call-template name="sum-prod"> <xsl:with-param name="values" select="//price" /> </xsl:call-template> </xsl:template>
</xsl:stylesheet></lang>
zkl
<lang zkl>fcn sum(vals){vals.reduce('+,0)} fcn product(vals){vals.reduce('*,1)}</lang>
sum(T(1,2,3,4)) //-->10 product(T(1,2,3,4)) //-->24
Zoea
<lang Zoea> program: sum_and_product
case: 1 input: [3,5] output: [8,15] case: 2 input: [2,3,4] output: [9,24]
</lang>
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