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Luhn test of credit card numbers

From Rosetta Code
Task
Luhn test of credit card numbers
You are encouraged to solve this task according to the task description, using any language you may know.

The Luhn test is used by some credit card companies to distinguish valid credit card numbers from what could be a random selection of digits.

Those companies using credit card numbers that can be validated by the Luhn test have numbers that pass the following test:

  1. Reverse the order of the digits in the number.
  2. Take the first, third, ... and every other odd digit in the reversed digits and sum them to form the partial sum s1
  3. Taking the second, fourth ... and every other even digit in the reversed digits:
  1. Multiply each digit by two and sum the digits if the answer is greater than nine to form partial sums for the even digits
  2. Sum the partial sums of the even digits to form s2
  1. If s1 + s2 ends in zero then the original number is in the form of a valid credit card number as verified by the Luhn test.


For example, if the trial number is 49927398716:

Reverse the digits:
  61789372994
Sum the odd digits:
  6 + 7 + 9 + 7 + 9 + 4 = 42 = s1
The even digits:
    1,  8,  3,  2,  9
  Two times each even digit:
    2, 16,  6,  4, 18
  Sum the digits of each multiplication:
    2,  7,  6,  4,  9
  Sum the last:
    2 + 7 + 6 + 4 + 9 = 28 = s2

s1 + s2 = 70 which ends in zero which means that 49927398716 passes the Luhn test


Task

Write a function/method/procedure/subroutine that will validate a number with the Luhn test, and
use it to validate the following numbers:

   49927398716
   49927398717
   1234567812345678
   1234567812345670


Related tasks



11l

Translation of: Python
F luhn(n)
   V ch = String(n)
   V sum = 0
   V chParity = ch.len % 2
   L(i) (ch.len-1 .. 0).step(-1)
      V j = Int(ch[i])
      I (i + 1) % 2 != chParity
         j *= 2
         I j > 9
            j -= 9
      sum += j
   R sum % 10 == 0

L(n) (49927398716,
      49927398717,
      1234567812345678,
      1234567812345670)
   print(luhn(n))
Output:
1B
0B
0B
1B

360 Assembly

Translation of: VBScript

For maximum compatibility, this program uses only the basic instruction set (S/360) and an ASSIST macro (XPRNT) to keep the code as short as possible.

*        Luhn test of credit card numbers        22/05/2016
LUHNTEST CSECT
         USING  LUHNTEST,R13       base register
         B      72(R15)            skip savearea
         DC     17F'0'             savearea
         STM    R14,R12,12(R13)    prolog
         ST     R13,4(R15)         "
         ST     R15,8(R13)         "
         LR     R13,R15            "
         LA     R9,T               @t(k)
         LA     R8,N               for n
LOOPK    EQU    *                  for k=1 to n
         LR     R4,R9              @t(k),@s[1]
         LA     R6,1               from i=1
         LA     R7,M               to m
LOOPI1   CR     R6,R7              for i=1 to m
         BH     ELOOPI1            leave i
         CLI    0(R4),C' '           if mid(s,i,1)=" "
         BNE    ITERI1               then
         BCTR   R6,0                   i-1
         ST     R6,L                   l=i-1
         B      ELOOPI1                exit for
*                                    end if
ITERI1   LA     R4,1(R4)             next @s[i]
         LA     R6,1(R6)             i=i+1
         B      LOOPI1             next i
ELOOPI1  EQU    *                  out of loop i
         MVC    W,BLANK            w=" "
         LA     R4,W               iw=@w
         LR     R5,R9              is=@s
         A      R5,L               is=@s+l
         BCTR   R5,0               is=s+l-1
         L      R6,L               i=l
         LA     R7,1               to 1
LOOPI2   CR     R6,R7              for i=l to 1 by -1 
         BL     ELOOPI2            leave i
         MVC    0(1,R4),0(R5)        mid(w,iw,1)=mid(s,is,1)
         LA     R4,1(R4)             iw=iw+1
         BCTR   R5,0                 is=is-1
         BCTR   R6,0                 i=i-1
         B      LOOPI2             next i
ELOOPI2  EQU    *                  out of loop i
         LA     R11,0              s1=0
         LA     R12,0              s2=0
         LA     R6,1               i=1
         L      R7,L               to l
LOOPI3   CR     R6,R7              for i=1 to l
         BH     ELOOPI3            leave i
         LA     R2,W-1             @w-1
         AR     R2,R6              w[i]
         MVC    CI,0(R2)           ci=mid(w,i,1)
         NI     CI,X'0F'           zap upper half byte
         LR     R4,R6              i
         SRDA   R4,32              >>32
         D      R4,=F'2'           i/2
         LTR    R4,R4              if mod(i,2)>0
         BNH    NOTMOD             then
         XR     R2,R2                clear
         IC     R2,CI                z=cint(mid(w,i,1))
         AR     R11,R2               s1=s1+cint(mid(w,i,1))
         B      EIFMOD             else
NOTMOD   XR     R2,R2                clear
         IC     R2,CI                cint(mid(w,i,1))
         SLA    R2,1                 *2
         ST     R2,Z                 z=cint(mid(w,i,1))*2
         C      R2,=F'10'            if z<10
         BNL    GE10                 then
         A      R12,Z                  s2=s2+z
         B      EIF10                else
GE10     L      R2,Z                   z
         CVD    R2,PL8                 binary to packed
         UNPK   CL16,PL8               packed to zoned
         OI     CL16+15,X'F0'          zoned to char (zap sign)
         MVC    X(1),CL16+15           x=right(cstr(z),1)
         NI     X,X'0F'                zap upper half byte
         XR     R2,R2                  r2=0
         IC     R2,X                   r2=cint(right(cstr(z),1))
         AR     R12,R2                 s2=s2+r2
         LA     R12,1(R12)             s2=s2+cint(right(cstr(z),1))+1
EIF10    EQU    *                    end if
EIFMOD   EQU    *                  end if
         LA     R6,1(R6)           i=i+1
         B      LOOPI3             next i
ELOOPI3  EQU    *                  out of loop i
         LR     R1,R11             s1
         AR     R1,R12             s1+s2
         CVD    R1,PL8             binary to packed
         UNPK   CL16,PL8           packed to zoned
         CLI    CL16+15,X'C0'      if right(cstr(s1+s2),1)="0"
         BNE    NOTZERO            then
         MVC    R,=CL8'Valid'        r="Valid"
         B      ECLI               else
NOTZERO  MVC    R,=CL8'Invalid'      r="Invalid"
ECLI     EQU    *                  end if
         MVC    PG(M),0(R9)        t(k)
         MVC    PG+M+1(L'R),R      r
         XPRNT  PG,L'PG            print buffer
         LA     R9,M(R9)           at=at+m
         BCT    R8,LOOPK           next k
         L      R13,4(0,R13)       epilog
         LM     R14,R12,12(R13)    "
         XR     R15,R15            "
         BR     R14                exit
N        EQU    (TEND-T)/L'T
M        EQU    20
T        DC     CL(M)'49927398716         '
         DC     CL(M)'49927398717         '
         DC     CL(M)'1234567812345678    '
         DC     CL(M)'1234567812345670    '
TEND     DS     0C
W        DS     CL(M)
BLANK    DC     CL(M)' '
L        DS     F
Z        DS     F
PL8      DS     PL8 
CL16     DS     CL16
CI       DS     C
X        DS     C
R        DS     CL8
PG       DC     CL80' '            buffer
         YREGS
         END    LUHNTEST
Output:
49927398716          Valid
49927398717          Invalid
1234567812345678     Invalid
1234567812345670     Valid

8080 Assembly

	org	100h
	jmp 	demo
	;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
	;;;	Check if the 0-terminated string at HL passes the Luhn test.
	;;;	Returns with carry clear if the string passes, carry set
	;;;	if the string fails. 
luhn:	mvi	b,0	; Counter
	mov	d,b	; D = S1+S2 (we don't need to keep them separate)
lscan:	mov	a,m	; Get byte 
	inx 	h	; Increment pointer
	inr	b	; Increment counter
	ana	a	; Is it 0?
	jnz	lscan	; If not, try next byte
	dcx	h	; Go to the byte before the 0
	dcx	h
	dcr	b	; Decrement counter
	rz		; If 0, the string was empty, return.
lloop:	mvi	c,'0'	; ASCII zero
	mov	a,d	; Add odd digit to the total 
	add	m
	sub	c	; Subtract ASCII zero
	mov	d,a
	dcr	b	; If last digit, we're done
	jz	ldone
	dcx	h	; Go back one byte
	mov	a,m	; Get even digit
	sub	c	; Subtract ASCII zero
	add	a	; Multiply by two
	mvi	c,9	; 10-1, compensate for extra subtraction loop
ldiv:	inr	c	; Find two digits using trial subtraction
	sui	10		
	jnc	ldiv
	add	c	; Add the possible second digit in
	add	d	; Add it to the total
	mov	d,a
	dcx	h	; Go back one byte
	dcr	b	; Done yet?
	jnz	lloop
ldone:	mov	a,d	; See if total is divisible by 10
	mvi	b,10
lchk:	sub	b	; Trial subtraction, subtract 10
	rz		; If zero, it is divisible, return (carry clear)
	rc		; If carry, it is not divisible, return (carry set)
	jmp	lchk
	;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
	;;;	Run the routine on the argument given on the CP/M command line
demo:	lxi	h,80h	; Zero-terminate the command line argument
	mov	a,m 
	add	l
	mov	l,a
	inr	l
	mvi	m,0
	mvi	l,82h	; Run the 'luhn' subroutine
	call 	luhn
	mvi	c,9
	lxi	d,pass	; Carry clear = print 'Pass'
	jnc	5
	lxi	d,fail	; Carry set = print 'Fail'
	jmp	5
pass:	db	'Pass$'
fail:	db	'Fail$'
Output:
A>luhn 49927398716
Pass
A>luhn 49927398717
Fail
A>luhn 1234567812345678
Fail
A>luhn 1234567812345670
Pass

8086 Assembly

	bits	16
	cpu	8086
	org	100h
section	.text
	jmp	demo	
	;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
	;;; 	Check whether the 0-terminated string at DS:SI passes the Luhn
	;;; 	test. Returns with carry clear if the string passes, carry
	;;;	set if the string fails.
luhn:	push	es	; Keep original ES, and set ES=DS so SCASB can be used.
	push	ds	; "REP DS:SCASB" is a bad idea, because the 286 has a
	pop	es	; bug where it "forgets" the 2nd prefix if interrupted!
	mov	di,si	; DI = pointer
	xor	ax,ax	; Zero to test against
	xor	bl,bl	; BL = S1+S2
	mov	dx,0A30h	; DH = 10 (divisor), DL = '0' (ASCII zero)  
	xor	cx,cx	; Set counter to 65535
	dec	cx
	cld		; Seek forwards
	repnz	scasb	; Find zero
	dec	di	; SCASB goes one byte too far
	xchg	si,di	; SI = pointer, DI = end (or rather, beginning)
	mov	cx,si	; CX = counter
	sub	cx,di
	jcxz	.done	; Empty string = stop
	dec	si	; We don't need the zero itself
	std		; Seek backwards
.loop:	lodsb		; Get number in odd position
	sub	al,dl	; Subtract ASCII zero
	add	bl,al	; Add to total
	dec	cx	; One fewer character
	jz	.done	; No more characters = stop
	lodsb		; Get number in even position
	sub	al,dl	; Subtract ASCII zero
	add	al,al	; Multiply by two
	xor	ah,ah	; AX = AL 
	div	dh	; Divide by 10; AL=quotient, AH=remainder
	add	al,ah	; Add the two "digits" together
	add	bl,al	; Add to total
	loop 	.loop	; Decrement CX and loop
.done:	xor	ah,ah	; Divide total by 10
	mov	al,bl
	div	dh
	and	ah,ah	; If remainder 0, then return with carry clear
	jz	.out
	stc		; Set carry (remainder wasn't 0, the test failed)
.out:	cld		; Clean up: clear direction flag,
	pop	es	; and restore ES.
	ret 
	;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
	;;;	Run the 'luhn' routine on the argument given on the MS-DOS
	;;;	command line. 
demo:	mov	si,80h			; Zero-terminate the argument
	xor	bh,bh
	mov	bl,[si]
	mov	[si+bx+1],bh
	inc	si
	inc	si
	call 	luhn			; Call the routine
	mov	ah,9
	mov	dx,pass			; If carry is clear, print 'Pass'
	jnc	print
	mov	dx,fail			; Otherwise, print 'fail'
print:	int	21h
	ret
section	.data
pass:	db	'Pass$'
fail:	db	'Fail$'
Output:
C:\>luhn86 49927398716
Pass
C:\>luhn86 49927398717
Fail
C:\>luhn86 1234567812345678
Fail
C:\>luhn86 1234567812345670
Pass


8th

\ Adapted from the C version:
: remap \ n1 -- n2
  [0,2,4,6,8,1,3,5,7,9]
  swap caseof ;

: luhn \ s -- f
  0 swap
  s:rev
  (
    '0 n:-
    swap 2 n:mod if remap then
    n:+
  ) s:each 
  10 n:mod not ;

: test-luhn \ s --
  dup . space
  luhn if "OK" else "FAIL" then . cr ;

"49927398716" test-luhn
"49927398717" test-luhn 
"1234567812345678" test-luhn
"1234567812345670" test-luhn

bye
Output:
49927398716 OK
49927398717 FAIL
1234567812345678 FAIL
1234567812345670 OK

ABAP

METHOD luhn_check.

  DATA: sum(1) TYPE n VALUE 0. " Sum of checksum.
  DATA: current TYPE i. " Current digit.
  DATA: odd TYPE i VALUE 1. " Multiplier.
  DATA: len TYPE i. " String crowler.


  " Luhn algorithm.
  len = NUMOFCHAR( pi_string ) - 1.
  WHILE ( len >= 0 ).
    current = pi_string+len(1) * odd.
    IF ( current > 9 ).
      current = current - 9. " Digits sum.
    ENDIF.
    sum = sum + current.
    odd = 3 - odd. " 1 <--> 2 Swich
    len = len - 1. " Move to next charcter.
  ENDWHILE.

  " Validation check.
  IF ( sum = 0 ).
    pr_valid = abap_true.
  ELSE.
    pr_valid = abap_false.
  ENDIF.

ENDMETHOD.

ACL2

(include-book "arithmetic-3/top" :dir :system)

(defun digits (n)
   (if (zp n)
       nil
       (cons (mod n 10)
             (digits (floor n 10)))))

(defun sum (xs)
   (if (endp xs)
       0
       (+ (first xs)
          (sum (rest xs)))))

(defun double-and-sum-digits (xs)
   (if (endp xs)
       nil
       (cons (sum (digits (* 2 (first xs))))
             (double-and-sum-digits (rest xs)))))

(defun dmx (xs)
   (if (endp (rest xs))
       (mv xs nil)
       (mv-let (odds evens)
               (dmx (rest (rest xs)))
          (mv (cons (first xs) odds)
              (cons (second xs) evens)))))

(defun luhn (n)
   (mv-let (odds evens)
           (dmx (digits n))
      (= (mod (+ (sum odds)
                 (sum (double-and-sum-digits evens)))
              10)
         0)))
Output:
> (luhn 49927398716)
T
> (luhn 49927398717)
NIL
> (luhn 1234567812345678)
NIL
> (luhn 1234567812345670)
T

Action!

PROC ReverseDigits(CHAR ARRAY n,rev)
  BYTE i,j

  i=n(0)
  WHILE i>0 AND n(i)='0
  DO
    i==-1
  OD

  j=1
  WHILE i>0
  DO
    rev(j)=n(i)
    j==+1 i==-1
  OD
  rev(0)=j-1
RETURN

BYTE FUNC SumOddDigits(CHAR ARRAY n)
  BYTE sum,i

  sum=0
  FOR i=1 TO n(0) STEP 2
  DO
    sum==+ValB(n(i))
  OD
RETURN(sum)

BYTE FUNC SumEvenDigitsMultiplied(CHAR ARRAY n)
  BYTE sum,i,v

  sum=0
  FOR i=2 TO n(0) STEP 2
  DO
    v=ValB(n(i))*2
    IF v>9 THEN v==-9 FI
    sum==+v
  OD
RETURN(sum)

BYTE FUNC Luhn(CHAR ARRAY n)
  CHAR ARRAY rev(20)
  BYTE s1,s2

  ReverseDigits(n,rev)
  s1=SumOddDigits(rev)
  s2=SumEvenDigitsMultiplied(rev)

  IF (s1+s2) MOD 10=0 THEN
    RETURN(1)
  FI
RETURN(0)
  
PROC Test(CHAR ARRAY n)
  PrintF("%S is ",n)
  IF Luhn(n) THEN
    PrintE("valid")
  ELSE
    PrintE("invalid")
  FI
RETURN

PROC Main()
  Test("49927398716")
  Test("49927398717")
  Test("1234567812345678")
  Test("1234567812345670")
RETURN
Output:

Screenshot from Atari 8-bit computer

49927398716 is valid
49927398717 is invalid
1234567812345678 is invalid
1234567812345670 is valid

ActionScript

function isValid(numString:String):Boolean
{
	var isOdd:Boolean = true;
	var oddSum:uint = 0;
	var evenSum:uint = 0;
	for(var i:int = numString.length - 1; i >= 0; i--)
	{
		var digit:uint = uint(numString.charAt(i))
		if(isOdd) oddSum += digit;
		else evenSum += digit/5 + (2*digit) % 10;
		isOdd = !isOdd;
	}
	if((oddSum + evenSum) % 10 == 0) return true; 
	return false;
}

trace(isValid("49927398716"));
trace(isValid("49927398717"));
trace(isValid("1234567812345678"));
trace(isValid("1234567812345670"));

Ada

Translation of: C
Works with: GNAT
with Ada.Text_IO;
use  Ada.Text_IO;

procedure Luhn is

  function Luhn_Test (Number: String) return Boolean is
    Sum  : Natural := 0;
    Odd  : Boolean := True;
    Digit: Natural range 0 .. 9;
  begin
    for p in reverse Number'Range loop
      Digit := Integer'Value (Number (p..p));
      if Odd then
        Sum := Sum + Digit;
      else
        Sum := Sum + (Digit*2 mod 10) + (Digit / 5);
      end if;
      Odd := not Odd;
    end loop;
    return (Sum mod 10) = 0;
  end Luhn_Test;
 
begin

  Put_Line (Boolean'Image (Luhn_Test ("49927398716")));
  Put_Line (Boolean'Image (Luhn_Test ("49927398717")));
  Put_Line (Boolean'Image (Luhn_Test ("1234567812345678")));
  Put_Line (Boolean'Image (Luhn_Test ("1234567812345670")));

end Luhn;
Output:
TRUE
FALSE
FALSE
TRUE

ALGOL 68

Translation of: C++ – Note: This specimen retains the original C coding style.
Works with: ALGOL 68 version Standard - no extensions to language used
Works with: ALGOL 68G version Any - tested with release 1.18.0-9h.tiny
Works with: ELLA ALGOL 68 version Any (with appropriate job cards)
PROC to int = (CHAR c)INT:
    ABS c - ABS "0";
 
PROC confirm = (STRING id)BOOL:
(
    BOOL is odd digit := TRUE;
    INT s := 0;
    STRING cp;
 
    FOR cp key FROM UPB id BY -1 TO LWB id DO
        INT k := to int(id[cp key]);
        s +:= 
            IF is odd digit THEN k
            ELIF k /= 9 THEN 2*k MOD 9 
            ELSE 9
            FI;
        is odd digit := NOT is odd digit
    OD;
    0 = s MOD 10
);

main:
(
    []STRING t cases = (
        "49927398716",
        "49927398717",
        "1234567812345678",
        "1234567812345670"
    );
    FOR cp key TO UPB t cases DO
        STRING cp = t cases[cp key];
        print((cp, ": ", confirm(cp), new line))
    OD
)
Output:
49927398716: T
49927398717: F
1234567812345678: F
1234567812345670: T

ALGOL W

Separate source so the LuhnTest procedure can be used in other tasks, e.g.: Validate International Securities Identification Number

% returns true if ccNumber passes the Luhn test, false otherwise %
% as Algol W has fixed length strings, the length of the number  %
% must be specified in ccLength                                  %
logical procedure LuhnTest ( string(32) value ccNumber
                           ; integer    value ccLength
                           ) ;
begin
    integer checkSum;
    logical oddDigit, isValid;
    checkSum := 0;
    isValid := oddDigit := true;
    for cPos := ccLength step -1 until 1 do begin
        integer digit;
        digit := decode( ccNumber( cPos - 1 // 1 ) ) - decode( "0" );
        if digit < 0 or digit > 9 then isValid := false
        else if oddDigit
        then checkSum := checkSum + digit
        else checkSum := checkSum + ( case digit + 1 of ( 0, 2, 4, 6, 8
                                                        , 1, 3, 5, 7, 9
                                                        )
                                    );
        oddDigit := not oddDigit
    end for_cPos ;
    isValid and ( ( checkSum rem 10 ) = 0 )
end LuhnTest

Use the above to test the LuhnTest procedure:

begin
    % external procedure that returns true if ccNumber passes the Luhn test, false otherwise %
    logical procedure LuhnTest ( string(32) value ccNumber
                               ; integer    value ccLength
                               ) ; algol "LUHN" ;


    % task test cases %

    procedure testLuhnTest ( string(32) value ccNumber
                           ; integer    value ccLength
                           ) ;
        write( s_w := 0, ccNumber, if LuhnTest( ccNumber, ccLength ) then " is valid" else " is invalid" );

    testLuhnTest( "49927398716",      11 );
    testLuhnTest( "49927398717",      11 );
    testLuhnTest( "1234567812345678", 16 );
    testLuhnTest( "1234567812345670", 16 )

end.
Output:
49927398716                      is valid
49927398717                      is invalid
1234567812345678                 is invalid
1234567812345670                 is valid

APL

Works with: Dyalog APL
LuhnTest{                                                                              
     digits¨                       ⍝ Characters to digits                   
     doubled2×@(~1 0)digits   ⍝ Double every other digit               
     partial-9@(9<)doubled        ⍝ Subtract 9 is equivalent to sum of digits for the domain 10≤x≤19
     0=10|+/partial                   ⍝ Valid if sum is a multiple of 10       
 }
Output:
      LuhnTest¨'49927398716' '49927398717' '1234567812345678' '1234567812345670'
1 0 0 1
Works with: APL+Win
     retLuhnTest num;s1;s2
[1]   num((10num)/10)num
[2]   s1+/((num)1 0)/num
[3]   s2+/(10 10)¨2×((num)0 1)/num
[4]   ret0=10s1+s2
    
Output:
      LuhnTest¨ 49927398716 49927398717 1234567812345678 1234567812345670
1 0 0 1

AppleScript

Functional

-- luhn :: String -> Bool
on luhn(s)
    -- True if the digit string represents
    -- a valid Luhn credit card number.
    
    script divMod10Sum
        on |λ|(a, x)
            a + x div 10 + x mod 10
        end |λ|
    end script
    
    0 = foldl(divMod10Sum, 0, ¬
        zipWith(my mul, ¬
            map(my int, reverse of (characters of s)), ¬
            cycle({1, 2}))) mod 10
end luhn


--------------------------- TEST ---------------------------
on run
    map(luhn, ¬
        {"49927398716", "49927398717", ¬
            "1234567812345678", "1234567812345670"})
    
    --> {true, false, false, true}
end run


---------------- REUSABLE GENERIC FUNCTIONS ----------------

-- cycle :: [a] -> Generator [a]
on cycle(xs)
    script
        property lng : 1 + (length of xs)
        property i : missing value
        on |λ|()
            if missing value is i then
                set i to 1
            else
                set nxt to (1 + i) mod lng
                if 0 = ((1 + i) mod lng) then
                    set i to 1
                else
                    set i to nxt
                end if
            end if
            return item i of xs
        end |λ|
    end script
end cycle

-- foldl :: (a -> b -> a) -> a -> [b] -> a
on foldl(f, startValue, xs)
    tell mReturn(f)
        set v to startValue
        set lng to length of xs
        repeat with i from 1 to lng
            set v to |λ|(v, item i of xs, i, xs)
        end repeat
        return v
    end tell
end foldl

-- int :: String -> Int
on int(s)
    s as integer
end int

-- length :: [a] -> Int
on |length|(xs)
    set c to class of xs
    if list is c or string is c then
        length of xs
    else
        (2 ^ 29 - 1) -- (maxInt - simple proxy for non-finite)
    end if
end |length|

-- mReturn :: First-class m => (a -> b) -> m (a -> b)
on mReturn(f)
    -- 2nd class handler function lifted into 1st class script wrapper. 
    if script is class of f then
        f
    else
        script
            property |λ| : f
        end script
    end if
end mReturn

-- map :: (a -> b) -> [a] -> [b]
on map(f, xs)
    -- The list obtained by applying f
    -- to each element of xs.
    tell mReturn(f)
        set lng to length of xs
        set lst to {}
        repeat with i from 1 to lng
            set end of lst to |λ|(item i of xs, i, xs)
        end repeat
        return lst
    end tell
end map

-- min :: Ord a => a -> a -> a
on min(x, y)
    if y < x then
        y
    else
        x
    end if
end min

-- mul (*) :: Num a => a -> a -> a
on mul(a, b)
    a * b
end mul

-- take :: Int -> [a] -> [a]
-- take :: Int -> String -> String
on take(n, xs)
    set c to class of xs
    if list is c then
        if 0 < n then
            items 1 thru min(n, length of xs) of xs
        else
            {}
        end if
    else if string is c then
        if 0 < n then
            text 1 thru min(n, length of xs) of xs
        else
            ""
        end if
    else if script is c then
        set ys to {}
        repeat with i from 1 to n
            set v to |λ|() of xs
            if missing value is v then
                return ys
            else
                set end of ys to v
            end if
        end repeat
        return ys
    else
        missing value
    end if
end take

-- zipWith :: (a -> b -> c) -> [a] -> [b] -> [c]
on zipWith(f, xs, ys)
    set lng to min(|length|(xs), |length|(ys))
    if 1 > lng then return {}
    set xs_ to take(lng, xs) -- Allow for non-finite
    set ys_ to take(lng, ys) -- generators like cycle etc
    set lst to {}
    tell mReturn(f)
        repeat with i from 1 to lng
            set end of lst to |λ|(item i of xs_, item i of ys_)
        end repeat
        return lst
    end tell
end zipWith
Output:
{true, false, false, true}

Straightforward

on luhnTest(n)
    -- Accept only text input.
    if (n's class is not text) then return false
    -- Edit out any spaces or dashes.
    set astid to AppleScript's text item delimiters
    set AppleScript's text item delimiters to {space, "-"}
    set n to n's text items
    set AppleScript's text item delimiters to ""
    set n to n as text
    set AppleScript's text item delimiters to astid
    -- Check that what's left is numeric.
    try
        n as number
    on error
        return false
    end try
    
    -- Do the calculation two digits at a time, starting at the end of the text and working back.
    set sum to 0
    repeat with i from ((count n) - 1) to 1 by -2
        set n2 to (text i thru (i + 1) of n) as integer
        tell n2 div 10 mod 10 * 2 to set sum to sum + it div 10 + it mod 10 + n2 mod 10
    end repeat
    -- If there's an odd digit left over, add that in too.
    if (i is 2) then set sum to sum + (character 1 of n)
    
    return (sum mod 10 is 0)
end luhnTest

-- Test code:
set testResults to {}
repeat with testNumber in {"49927398716", "49927398717", "1234567812345678", "1234567812345670"}
    set end of testResults to {testNumber:testNumber's contents, valid:luhnTest(testNumber)}
end repeat
return testResults
Output:
{{testNumber:"49927398716", valid:true}, {testNumber:"49927398717", valid:false}, {testNumber:"1234567812345678", valid:false}, {testNumber:"1234567812345670", valid:true}}

ARM Assembly

.text
.global _start
_start:
    ldr r0, =example_numbers
    bl test_number

    add r1, r0, #1
    bl length
    add r0, r1, r0
    bl test_number
    
    add r1, r0, #1
    bl length
    add r0, r1, r0
    bl test_number
    
    add r1, r0, #1
    bl length
    add r0, r1, r0
    bl test_number

    mov r0, #0
    mov r7, #1
    swi 0

test_number:
    push {r0, lr}
    bl print_string

    bl luhn_test
    cmp r0, #1
    ldreq r0, =valid_message
    ldrne r0, =invalid_message
    bl print_string
    pop {r0, lr}
    mov pc, lr



print_string:
    push {r0-r7, lr}
    mov r1, r0   @ string to print
    bl length
    mov r2, r0   @ length of string
    mov r0, #1   @ write to stdout
    mov r7, #4   @ SYS_WRITE
    swi 0        @ call system interupt
    pop {r0-r7, lr}
    mov pc, lr

@ r0 address of credit card number string
@ returns result in r0
luhn_test:
    push {r1-r7, lr}
    mov r1, r0
    bl isNumerical            @ check if string is a number
    cmp r0, #1
    bne .luhn_test_end        @ exit if not number
    mov r0, r1 
    ldr r1, =reversed_string  @ address to store reversed string
    bl reverse                @ reverse string
    push {r0}
    bl length   @ get length of string
    mov r4, r0  @ store string length in r4 
    pop {r0}
    mov r2, #0  @ string index
    mov r6, #0  @ sum of odd digits
    mov r7, #0  @ sum of even digits
    .loadNext:
        ldrb r3, [r1, r2]         @ load byte into r3
        sub r3, #'0'              @ convert letter to digit
        and r5, r2, #1            @ test if index is even or odd
        cmp r5, #0
        beq .odd_digit
        bne .even_digit
        .odd_digit:
            add r6, r3              @ add digit to sum if odd
            b .continue             @ skip next step
        .even_digit:
            lsl r3, #1              @ multiply digit by 2
            cmp r3, #10             @ sum digits
            subge r3, #10           @ get digit in 1s place
            addge r3, #1            @ add 1 for the 10s place
            add r7, r3              @ add digit sum to the total
            
        .continue: 
        add r2, #1                @ increment digit index
        cmp r2, r4                @ check if at end of string
        blt .loadNext

    add r0, r6, r7                @ add even and odd sum
    mov r3, r0                    @ copy sum to r3
    ldr r1, =429496730            @ (2^32-1)/10
    sub r0, r0, r0, lsr #30       @ divide by 10
    umull r2, r0, r1, r0
    mov r1, #10
    mul r0, r1                    @ multiply the r0 by 10 to see if divisible
    cmp r0, r3                    @ compare with the original value in r3
    .luhn_test_end:
    movne r0, #0                  @ return false if invalid card number
    moveq r0, #1                  @ return true if valid card number
    pop {r1-r7, lr}
    mov pc, lr
    
length:
    push {r1-r2, lr}
    mov r2, r0              @ start of string address
    .loop:
        ldrb r1, [r2], #1   @ load byte from address r2 and increment
        cmp r1, #0          @ check for end of string
        bne .loop           @ load next byte if not 0
    sub r0, r2, r0          @ subtract end of string address from start
    sub r0, #1              @ end of line from count
    pop {r1-r2, lr}
    mov pc, lr

@ reverses a string
@ r0 address of string to reverse
@ r1 address to store reversed string
reverse:
    push {r0-r5, lr}
    push {r0, lr}
    bl length                @ get length of string to reverse
    mov r3, r0               @ backword index
    pop {r0, lr}
    mov r4, #0               @ fowrard index
    .reverse_next:
        sub r3, #1           @ decrement backword index
        ldrb r5, [r0, r3]    @ load byte from original string at index
        strb r5, [r1, r4]    @ copy byte to reversed string
        add r4, #1           @ increment fowrard index
        cmp r3, #0           @ check if any characters are left
        bge .reverse_next

    mov r5, #0
    strb r5, [r1, r4]  @ write null byte to terminate reversed string
    pop {r0-r5, lr}
    mov pc, lr

isNumerical:
    push {r1, lr}
    .isNumerical_checkNext:
        ldrb r1, [r0], #1
        cmp r1, #0
        beq .isNumerical_true
        cmp r1, #'0'
        blt .isNumerical_false
        cmp r1, #'9'
        bgt .isNumerical_false
        b .isNumerical_checkNext
    .isNumerical_false:
        mov r0, #0
        b .isNumerical_end
    .isNumerical_true:
        mov r0, #1
    .isNumerical_end:
    pop {r1, lr}
    mov pc, lr


.data
valid_message:
    .asciz " valid card number\n"
invalid_message:
    .asciz " invalid card number\n"

reversed_string:
    .space 32

example_numbers:
    .asciz "49927398716"
    .asciz "49927398717"
    .asciz "1234567812345678"
    .asciz "1234567812345670"

Arturo

digits: function [n][
    res: new []
    while -> n > 0 [
        'res ++ n % 10
        n: n / 10
    ]
    res
]

luhn?: function [n][
    s1: new 0
    s2: new 0
    loop.with: 'i digits n 'd [
        if? even? i -> 's1 + d
        else [
            'd * 2
            if d > 9 -> 'd - 9
            's2 + d
        ]
    ]
    zero? (s1 + s2) % 10
]

print luhn? 49927398716
print luhn? 49927398717
print luhn? 1234567812345678
print luhn? 1234567812345670
Output:
true
false
false
true

AutoHotkey

; Originally submitted by Laszlo:
; http://www.autohotkey.com/forum/post-229412.html#229412

MsgBox % LuhnTest(49927398716)
MsgBox % LuhnTest(49927398717)
MsgBox % LuhnTest(1234567812345678)
MsgBox % LuhnTest(1234567812345670)

Return

;-----------------------------

LuhnTest(Number)
{
  MultFactor := 2 - ( StrLen(Number) & 1 )  ,  Sum := 0
  Loop, Parse, Number
    Sum += ( ( 9 < ( Temp := MultFactor * A_LoopField ) ) ? Temp - 9 : Temp )  ,  MultFactor := 3 - MultFactor
  Return !Mod(Sum,10)
}

AutoIt

Global $avarray[4] = [49927398716, 49927398717, 1234567812345678, 1234567812345670]
For $i = 0 To 3
	checkLuhn($avarray[$i])
Next

Func checkLuhn($number)
	$sum = 0
	$numDigits = StringSplit($number, "")
	For $i = $numDigits[0] - 1 To 1 Step -2
		$numDigits[$i] = $numDigits[$i] * 2
		If $numDigits[$i] >= 10 Then $numDigits[$i] -= 9
	Next
	For $i = 1 To $numDigits[0]
		$sum += $numDigits[$i]
	Next
	If StringRight($sum, 1) = "0" Then
		ConsoleWrite("Luhn-Check (" & $number & ") : True" & @CRLF)
		Return True
	Else
		ConsoleWrite("Luhn-Check (" & $number & ") : False" & @CRLF)
		Return False
	EndIf
EndFunc   ;==>checkLuhn
Output:
Luhn-Check (49927398716) : True
Luhn-Check (49927398717) : False
Luhn-Check (1234567812345678) : False
Luhn-Check (1234567812345670) : True

AWK

#!/usr/bin/awk -f
BEGIN {
    A[1] = 49927398716;
    A[2] = 49927398717;
    A[3] = 1234567812345678;
    A[4] = 1234567812345670;
    A[5] = "01234567897";
    A[6] = "01234567890";
    A[7] = "00000000000";
    for (k in A) print "isLuhn("A[k]"): ",isLuhn(A[k]);	
}

function isLuhn(cardno) {
    s = 0;
    m = "0246813579";
    n = length(cardno);
    for (k = n; 0 < k; k -= 2) {
	s += substr(cardno, k, 1);
    }
    for (k = n-1; 0 < k; k -= 2) {
	s += substr(m, substr(cardno, k, 1)+1, 1);
    }
    return ((s%10)==0);	
}
Output:
isLuhn(1234567812345670):  1
isLuhn(01234567897):  1
isLuhn(01234567890):  0
isLuhn(00000000000):  1
isLuhn(49927398716):  1
isLuhn(49927398717):  0
isLuhn(1234567812345678):  0

Bash

#!/bin/bash

function luhn_validate  # <numeric-string>
{
    num=$1
    shift 1

    len=${#num}
    is_odd=1
    sum=0
    for((t = len - 1; t >= 0; --t)) {
        digit=${num:$t:1}

        if [[ $is_odd -eq 1 ]]; then
            sum=$(( sum + $digit ))
        else
            sum=$(( $sum + ( $digit != 9 ? ( ( 2 * $digit ) % 9 ) : 9 ) ))
        fi

        is_odd=$(( ! $is_odd ))
    }

    # NOTE: returning exit status of 0 on success
    return $(( 0 != ( $sum % 10 ) ))
}


function print_result  # <numeric-string>
{
    if luhn_validate "$1"; then
        echo "$1 is valid"
    else
        echo "$1 is not valid"
    fi
}

print_result "49927398716"
print_result "49927398717"
print_result "1234567812345678"
print_result "1234567812345670"
Output:
49927398716 is valid
49927398717 is not valid
1234567812345678 is not valid
1234567812345670 is valid

BASIC

BASIC256

dim card$(5)
card$[1]="49927398716"
card$[2]="49927398717"
card$[3]="1234567812345678"
card$[4]="1234567812345670"

for test = 1 to 4
    odd = True
    sum = 0
    for n = length(card$[test]) to 1 step -1
        num = int(mid(card$[test],n,1))
        if odd then
            sum += num
            odd = False
        else
            num *= 2
            if num <= 9 then
                sum += num
            else
                sum += int(left(string(num),1)) + int(right(string(num),1))
            end if
            odd = True
        end if
    next
    if sum mod 10 = 0 then
        print card$[test], "True"
    else
        print card$[test], "False"
    end if
next test

Chipmunk Basic

Works with: Chipmunk Basic version 3.6.4
100 cls
110 rem Luhn test
120 dim card$(5)
130 card$(1) = "49927398716"
140 card$(2) = "49927398717"
150 card$(3) = "1234567812345678"
160 card$(4) = "1234567812345670"
170 for test = 1 to 4
180   odd = true
190   sum = 0
200   for n = len(card$(test)) to 1 step -1
210     num = val(mid$(card$(test),n,1))
220     if odd then
230       sum = sum+num
240       odd = false
250     else
260       num = num*2
270       if num <= 9 then
280         sum = sum+num
290       else
300         sum = sum+val(left$(str$(num),1))+val(right$(str$(num),1))
310       endif
320       odd = true
330     endif
340   next
350   if sum mod 10 = 0 then
360     print card$(test),"True"
370   else
380     print card$(test),"False"
390   endif
400 next test

IS-BASIC

100 PROGRAM "CredCard.bas"
110 DO
120   PRINT :PRINT "Credit card number:":INPUT PROMPT ">":CCN$
130   IF CCN$="" THEN EXIT DO
140   IF LUHN(TRIM$(CCN$)) THEN
150     PRINT "Card number is valid."
160   ELSE
170     SET #102:INK 3:PRINT "Card number is invalid.":SET #102:INK 1
180   END IF
190 LOOP
200 DEF LUHN(CCN$)
210   LET L=LEN(CCN$):LET S=0
220   FOR I=1 TO L
230     LET N=VAL(CCN$(L-I+1))
240     IF I BAND 1 THEN
250       LET S=S+N
260     ELSE
270       LET N=N*2:LET S=S+MOD(N,10)+INT(N/10)
280     END IF
290   NEXT
300   LET LUHN=MOD(S,10)=0
310 END DEF
320 DEF TRIM$(S$)
330   LET T$=""
340   FOR I=1 TO LEN(S$)
350     IF S$(I)>CHR$(47) AND S$(I)<CHR$(58) THEN LET T$=T$&S$(I)
360   NEXT
370   LET TRIM$=T$
380 END DEF

Output:

Credit card number:
>49927398716
Card number is valid.

Credit card number:
>49927398717
Card number is invalid.

Credit card number:
>1234 5678 1234 5678
Card number is invalid.

Credit card number:
>1234 5678 1234 5670
Card number is valid.

QBasic

Works with: QBasic version 1.1
Works with: QuickBasic version 4.5
CONST True = -1: False = NOT True

DIM card$(5)
card$(1) = "49927398716"
card$(2) = "49927398717"
card$(3) = "1234567812345678"
card$(4) = "1234567812345670"

FOR test = 1 TO 4
    odd = True
    sum = 0
    FOR n = LEN(card$(test)) TO 1 STEP -1
        num = VAL(MID$(card$(test), n, 1))
        IF odd THEN
           sum = sum + num
           odd = False
        ELSE
           num = num * 2
           IF num <= 9 THEN
              sum = sum + num
           ELSE
              sum = sum + VAL(LEFT$(STR$(num), 1)) + VAL(RIGHT$(STR$(num), 1))
           END IF
           odd = True
        END IF
    NEXT
    IF sum MOD 10 = 0 THEN
       PRINT card$(test), "True"
    ELSE
       PRINT card$(test), "False"
    END IF
NEXT test

True BASIC

LET true = -1
LET false = 0

DIM card$(5)
LET card$(1) = "49927398716"
LET card$(2) = "49927398717"
LET card$(3) = "1234567812345678"
LET card$(4) = "1234567812345670"

FOR test = 1 TO 4
    LET odd = true
    LET sum = 0
    FOR n = LEN(card$(test)) TO 1 STEP -1
        LET num = VAL((card$(test))[n:n+1-1])
        IF odd<>0 THEN
           LET sum = sum + num
           LET odd = false
        ELSE
           LET num = num*2
           IF num <= 9 THEN
              LET sum = sum + num
           ELSE
              LET sum = sum + VAL((STR$(num))[1:1]) + VAL((STR$(num))[LEN(STR$(num))-1+1:maxnum])
           END IF
           LET odd = true
        END IF
    NEXT n
    IF remainder(round(sum),10) = 0 THEN PRINT card$(test), "True" ELSE PRINT card$(test), "False"
NEXT test
END

uBasic/4tH

Translation of: C
Print "     49927398716", Show (Iif(FUNC(_Luhn ("49927398716")), "ok", "fail"))
Print "     49927398717", Show (Iif(FUNC(_Luhn ("49927398717")), "ok", "fail"))
Print "1234567812345678", Show (Iif(FUNC(_Luhn ("1234567812345678")), "ok", "fail"))
Print "1234567812345670", Show (Iif(FUNC(_Luhn ("1234567812345670")), "ok", "fail"))
End

_Luhn
  Param (1)
  Local (4)

  c@ = 1 : d@ = 0

  For b@ = Len(a@)-1 To 0 Step -1
    e@ = Peek(a@, b@) - Ord("0")
    d@ = d@ + Iif (c@, e@, e@+e@-9*(e@>4))
    c@ = c@ = 0
  Next

Return ((d@ % 10) = 0)
Output:
     49927398716        ok
     49927398717        fail
1234567812345678        fail
1234567812345670        ok

0 OK, 0:333

Yabasic

dim card$(5)
card$(1)="49927398716"
card$(2)="49927398717"
card$(3)="1234567812345678"
card$(4)="1234567812345670"

for test = 1 to 4
    odd = true
    sum = 0
    for n = len(card$(test)) to 1 step -1
        num = val(mid$(card$(test),n,1))
        if odd then
            sum = sum + num
            odd = false
        else
            num = num * 2
            if num <= 9 then
                sum = sum + num
            else
                sum = sum + val(left$(str$(num),1)) + val(right$(str$(num),1))
            fi
            odd = true
        fi
    next
    if mod(sum, 10) = 0 then
        print card$(test), chr$(9), "True"
    else
        print card$(test), chr$(9), "False"
    fi
next test

Batch File

This simple implementation does not reverse the numbers. Instead, it counts from right to left.

@echo off
setlocal enabledelayedexpansion
 
call :luhn 49927398716
call :luhn 49927398717
call :luhn 1234567812345678
call :luhn 1234567812345670
exit /b 0
 
:luhn
set "input=%1"
set "cnt=0"
set "s1=0"
set "s2=0"
:digit_loop
set /a "cnt-=1"
set /a "isOdd=(-%cnt%)%%2"
 
if !isodd! equ 1 (
	set /a "s1+=!input:~%cnt%,1!"
) else (
	set /a "twice=!input:~%cnt%,1!*2"
	if !twice! geq 10 (
		set /a "s2+=!twice:~0,1!+!twice:~1,1!"
	) else (
		set /a "s2+=!twice!"
	)
)
if "!input:~%cnt%!"=="!input!" (
	set /a "sum=(!s1!+!s2!)%%10"
	if !sum! equ 0 (echo !input! is valid.) else (echo !input! is not valid.)
	goto :EOF
)
goto digit_loop
Output:
>luhn.bat
49927398716 is valid.
49927398717 is not valid.
1234567812345678 is not valid.
1234567812345670 is valid.

>

BBC BASIC

      FOR card% = 1 TO 4
        READ cardnumber$
        IF FNluhn(cardnumber$) THEN
          PRINT "Card number " cardnumber$ " is valid"
        ELSE
          PRINT "Card number " cardnumber$ " is invalid"
        ENDIF
      NEXT card%
      END
      
      DATA 49927398716, 49927398717, 1234567812345678, 1234567812345670
      
      DEF FNluhn(card$)
      LOCAL I%, L%, N%, S%
      L% = LEN(card$)
      FOR I% = 1 TO L%
        N% = VAL(MID$(card$, L%-I%+1, 1))
        IF I% AND 1 THEN
          S% += N%
        ELSE
          N% *= 2
          S% += N% MOD 10 + N% DIV 10
        ENDIF
      NEXT
      = (S% MOD 10) = 0

bc

/* Return 1 if number passes Luhn test, else 0 */
define l(n) {
    auto m, o, s, x

    o = scale
    scale = 0

    m = 1
    while (n > 0) {
        x = (n % 10) * m
        if (x > 9) x -= 9
        s += x
        m = 3 - m
        n /= 10
    }

    s %= 10
    scale = o
    if (s) return(0)
    return(1)
}

l(49927398716)
l(49927398717)
l(1234567812345678)
l(1234567812345670)
Output:
1
0
0
1

BCPL

get "libhdr"

let luhn(s) = valof
$(  let sum=0 and fac=1
    for i = s%0 to 1 by -1
    $(  unless '0' <= s%i <= '9' resultis false
        sum := sum + fac*(s%i - '0') rem 10 + fac*(s%i - '0')/10
        fac := 3 - fac
    $)
    resultis sum rem 10 = 0
$)

let show(s) be
    writef("%S: %S*N", s, luhn(s) -> "pass", "fail")

let start() be
$(  show("49927398716")
    show("49927398717")
    show("1234567812345678")
    show("1234567812345670")
$)
Output:
49927398716: pass
49927398717: fail
1234567812345678: fail
1234567812345670: pass

Befunge

v  1   >$0 v   v                                    <
>&:19+`|v  <            >v      5      6   7      8
^  \   <>09p19p>09g+09p:|>2*:19+%19g+19p19+/19g+19p:|
   2          3      4  >                           v
                              v"invalid"<10  9
                                        |%+91+g91g90<
                              v  "valid"<
                              >:#,_@
                                 11

The labelled points (1 to 11) are: 1. Read in input until number greater than 10, 2. Reverse the order, 3. Set accumulators to 0, 4. Add odd number to accumulator, 5. Mod even number with 10, 6. Add this digit to accumulator, 7. Integer divide number by 10, 8. Add this digit to accumulator, 9. Add odd and even accumulators, 10. Mod this accumulator with 10, 11. Print result.

The code requires input be separated by spaces and ended with a number greater than 10 to exit the reading loop. This could be done by reading characters and ending at a new line, but this way is much simpler.

Inputs:

4 9 9 2 7 3 9 8 7 1 6 99        
4 9 9 2 7 3 9 8 7 1 7 99            
1 2 3 4 5 6 7 8 1 2 3 4 5 6 7 8 99
1 2 3 4 5 6 7 8 1 2 3 4 5 6 7 0 99
Output:
valid
invalid
invalid
valid

BQN

Luhn  0=10|·+´·+(9-˜<+˜)´˘2⌽-'0'

˘(Luhn¨) "49927398716""49927398717""1234567812345678""1234567812345670"
Output:
┌─                      
╵ "49927398716"      1  
  "49927398717"      0  
  "1234567812345678" 0  
  "1234567812345670" 1  
                       ┘

Bracmat

  ( luhn
  =   sum odd even
    .   0:?sum
      & rev$!arg:?arg
      &   whl
        ' ( @( !arg
             :   %?odd
                 ( %?even ?arg
                 | :?arg&0:?even
                 )
             )
          & !odd+mod$(2*!even.10)+div$(!even.5)+!sum:?sum
          )
      & mod$(!sum.10):0
  )
& ( test
  =   
    .   out
      $ (!arg ":" (luhn$!arg&true|false))
  )
& test$49927398716
& test$49927398717
& test$1234567812345678
& test$1234567812345670
& ;
Output:
49927398716 : true
49927398717 : false
1234567812345678 : false
1234567812345670 : true

Brainf***

>>>>>>>>>+>,----------[                        READ CHARACTERS UNTIL \N AND
  >++++++++[<----->-]<++>>>>>>+>,----------]   SUBTRACT ASCII 0 FROM EACH
<-<<<<<<<                                      GO TO LAST DIGIT
[                                              WHILE THERE ARE DIGITS
  >>>>>>>>[-<<<<<<<+>>>>>>>]<<<<<<<<             ADD RUNNING TOTAL TO ODD DGT
  <<<<<<<                                        GO TO EVEN DIGIT
  [                                              IF THERE IS ONE
    >[->++<]>[-<+>]                                MUL BY TWO
    >>>++++++++++<<<<[                             DIVMOD BY TEN
      >>>[-]+>-[<-<]<[<<]                            DECR DIVISOR
      >>[                                            IF ZERO
        >++++++++++>+<<-]<<<                           SET TO TEN; INCR QUOTIENT
    -]                                               DECR DIVIDEND UNTIL ZERO
    ++++++++++>>>>[-<<<<->>>>]                     CALCULATE REMAINDER
    >[-<<<<<+>>>>>]                                ADD QUOTIENT TO IT
    >>[-<<<<<<<+>>>>>>>]<<<<<<<<                   THEN ADD RUNNING TOTAL
    <<<<<                                          ZERO BEFORE NEXT ODD DIGIT
  ]<<                                            GO TO NEXT ODD DIGIT
]
>>>>>>>-[+>>-]>                                GO TO TOTAL
>>>>++++++++++<<<<[                            MODULO TEN
  >>>[-]+>-[<-<]<[<<]                            DECR DIVISOR
  >>[>++++++++++<-]                              IF ZERO SET BACK TO TEN
<<<-]                                            DECR DIVIDEND UNTIL ZERO
>>>++++++++++>[-<->]<                          REMAINDER: TEN MINUS DIVISOR
<<<<<<++++++++++[->                            VALUES FOR ASCII OUTPUT
  +++++++++++>                                   110
  ++++++++++>                                    100
  ++++++++>                                      80
  +++++++<<<<]                                   70
>>>>>+>                                        GO BACK TO REMAINDER
[<<.<<---.<-----.+++.<]                        IF NOT ZERO FAIL
<[<<.<---.<+++++..<]                           IF ZERO PASS
++++++++++.                                    NEWLINE
Output:
$ echo 49927398716 | beef luhn.bf
Pass
$ echo 49927398717 | beef luhn.bf
Fail
$ echo 1234567812345678 | beef luhn.bf
Fail
$ echo 1234567812345670 | beef luhn.bf
Pass

Bruijn

:import std/Combinator .
:import std/Math .
:import std/List .

luhn number→list → reverse → check → (\mod (+10)) → zero?
	check y [[[[0 [[[6 \5 (4 + (5 odd even)) 1]]] 1]]]] k (+0)
		odd 2
		even digit-sum (2 ⋅ (+2))

:test (luhn (+61789372994)) ([[1]])
:test (luhn (+49927398716)) ([[1]])
:test (luhn (+49927398717)) ([[0]])
:test (luhn (+1234567812345678)) ([[0]])
:test (luhn (+1234567812345670)) ([[1]])

Burlesque

tt         "Remove whitespace"vv
pe         "Eval to number"vv
<-         "Reverse digits"vv
XX         "Split number into digits"vv

{
 { "Odd digits"vv
  2EN
 } 
 
 { "Even digits"vv
  2en
  {
   2.*     "Double"vv
   ^^ 9.>  "<test>=Duplicate greater than 9"vv
   {
    XX++   "Sum digits"vv
   }if     "If <test>"vv
  }m[      "For each even digit"vv
 }
}M-       "Cool map. Create array of each branch applied to argument."vv

{++}m[    "Sum each block (odd & even)"vv
++        "Sum these"vv
[-        "Last digit"vv
0==       "Equal to zero"vv
Q         "Pretty print"vv
Output:
     49927398716        1
     49927398717        0
1234567812345678        0
1234567812345670        1

C

#include <string.h>
#include <stdio.h>

int luhn(const char* cc)
{
	const int m[] = {0,2,4,6,8,1,3,5,7,9}; // mapping for rule 3
	int i, odd = 1, sum = 0;

	for (i = strlen(cc); i--; odd = !odd) {
		int digit = cc[i] - '0';
		sum += odd ? digit : m[digit];
	}

	return sum % 10 == 0;
}

int main()
{
	const char* cc[] = {
		"49927398716",
		"49927398717",
		"1234567812345678",
		"1234567812345670",
		0
	};
	int i;

	for (i = 0; cc[i]; i++)
		printf("%16s\t%s\n", cc[i], luhn(cc[i]) ? "ok" : "not ok");

	return 0;
}
Output:
     49927398716        ok
     49927398717        not ok
1234567812345678        not ok
1234567812345670        ok

C#

The LuhnCheck method takes an array of integers because values in memory will be integer-aligned.

    public static class Luhn
    {
        public static bool LuhnCheck(this string cardNumber)
        {
            return LuhnCheck(cardNumber.Select(c => c - '0').ToArray());
        }

        private static bool LuhnCheck(this int[] digits)
        {
            return GetCheckValue(digits) == 0;
        }

        private static int GetCheckValue(int[] digits)
        {
            return digits.Select((d, i) => i % 2 == digits.Length % 2 ? ((2 * d) % 10) + d / 5 : d).Sum() % 10;
        }
    }

    public static class TestProgram
    {
        public static void Main()
        {
            long[] testNumbers = {49927398716, 49927398717, 1234567812345678, 1234567812345670};
            foreach (var testNumber in testNumbers)
                Console.WriteLine("{0} is {1}valid", testNumber, testNumber.ToString().LuhnCheck() ? "" : "not ");
        }
    }
49927398716 is valid
49927398717 is not valid
1234567812345678 is not valid
1234567812345670 is valid

Note that the original implementation, which follows, is flawed because it assumes that n is a number which, when represented as a string, has an even number of characters. Granted, the brief is for Credit Card Numbers which are all, at the time of writing, an even number of digits.

using System;
using System.Linq;

namespace Luhn
{
    class Program
    {
        public static bool luhn(long n)
        {
            long nextdigit, sum = 0;            
            bool alt = false;            
            while (n != 0)
            {                
                nextdigit = n % 10;
                if (alt)
                {
                    nextdigit *= 2;
                    nextdigit -= (nextdigit > 9) ? 9 : 0;
                }
                sum += nextdigit;
                alt = !alt;
                n /= 10;
            }
            return (sum % 10 == 0);
        }

        public static bool luhnLinq(long n)
        {
            string s = n.ToString();
            return s.Select((c, i) => (c - '0') << ((s.Length - i - 1) & 1)).Sum(n => n > 9 ? n - 9 : n) % 10 == 0;
        }

        static void Main(string[] args)
        {            
            long[] given = new long[] {49927398716, 49927398717, 1234567812345678, 1234567812345670};
            foreach (long num in given)
            {
                string valid = (luhn(num)) ? " is valid" : " is not valid";
                Console.WriteLine(num + valid);
            }
            
        }
    }
}
49927398716 is valid
49927398717 is not valid
1234567812345678 is not valid
1234567812345670 is valid

A solution without using LINQ, works for all versions of .NET.

using System;
namespace Luhn_Test
{
	public static class Extensions 
	{
		public static string Reverse(this string s )
		{
		    char[] charArray = s.ToCharArray();
		    Array.Reverse( charArray );
		    return new string( charArray );
		}
	}
	class Program
	{
		public static bool Luhn(long x)
		{
			long s1=0;
			long s2=0;
			bool STATE=x%10!=0; // If it ends with zero, we want the order to be the other way around
			x=long.Parse(x.ToString().Reverse());
			while (x!=0)
			{
				s1+=STATE?x%10:0;
				s2+=STATE?0:((x%10)*2>9)?(((x%10)*2/10)+((x%10)*2)%10):((x%10)*2); 
				STATE=!STATE; //Switch state
				x/=10; //Cut the last digit and continue
			}
			return ((s1+s2)%10==0); //Check if it ends with zero, if so, return true, otherwise,false.
		}
		public static void Main(string[] args)
		{
			long[] ks = {1234567812345670, 49927398717, 1234567812345678 ,1234567812345670 };
			foreach (long k in ks)
			{
			Console.WriteLine("{0} is {1} Valid.",k,Luhn(k)?"":"Not");	
			}
		Start:
			try { 
			Console.WriteLine("Enter your credit:");
			long x=long.Parse(Console.ReadLine());
			Console.WriteLine("{0} Valid.",Luhn(x)?"":"Not");
			goto Start;
			}
			catch (FormatException)
			{
				goto Start;
			}			
		}
	}
}
1234567812345670 is Valid.
49927398717 is Not Valid.
1234567812345678 is Not Valid.
49927398716 is Valid.

A solution optimized for readability:

using System;
using System.Linq;

public class CreditCardLogic
{
    static Func<char, int> charToInt = c => c - '0';

    static Func<int, int> doubleDigit = n => (n * 2).ToString().Select(charToInt).Sum();

    static Func<int, bool> isOddIndex = index => index % 2 == 0;

    public static bool LuhnCheck(string creditCardNumber)
    {
        var checkSum = creditCardNumber
            .Select(charToInt)
            .Reverse()
            .Select((digit, index) => isOddIndex(index) ? digit : doubleDigit(digit))
            .Sum();

        return checkSum % 10 == 0;
    }
}

Extremely compact version uses Europa rtl library https://github.com/CodeAlkemist/Europa-rtl

using System;
using EuropaRTL.Utilities;

public static partial class Algoritmhs
{
    public static bool CheckLuhn(long n)
    {
        int s1 = n.Shatter(true).Subset(2).Arithmetic('+');
        int s2 = n.Shatter(true).Subset(1, -1, 2).ArithmeticRA('*', 2).ShatterAndSum().Arithmetic('+');
        return (s1 + s2) % 10 == 0 ? true : false;
    }
}
class Program
{
    static void Main(string[] args)
    {
        long[] ll = {
                49927398716,
                49927398717,
                1234567812345678,
                1234567812345670
            };
        foreach (var item in ll)
        {
            item.ToString().WriteLine();
            Algoritmhs.CheckLuhn(item).ToString().WriteLine();
        }
        Console.ReadKey();
    }
}
49927398716
True
49927398717
False
1234567812345678
False
1234567812345670
False

C++

#include <iostream>
using namespace std;

int toInt(const char c)
{
    return c-'0';
}

int confirm( const char *id)
{
    bool is_odd_dgt = true;
    int s = 0;
    const char *cp;

    for(cp=id; *cp; cp++);
    while(cp > id) {
        --cp;
        int k = toInt(*cp);
        if (is_odd_dgt) {
            s += k;
        }
        else {
            s += (k!=9)? (2*k)%9 : 9;
        }
	is_odd_dgt = !is_odd_dgt;
    }
    return 0 == s%10;
}

int main( )
{
    const char * t_cases[] = {
        "49927398716",
        "49927398717",
        "1234567812345678",
        "1234567812345670",
        NULL,
    };
    for ( const char **cp = t_cases; *cp; cp++) {
        cout << *cp << ": " << confirm(*cp) << endl;
    }
    return 0;
}

C++11

#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;

bool luhn( const string& id)
{
  static const int m[10]  = {0,2,4,6,8,1,3,5,7,9}; // mapping for rule 3
  bool is_odd_dgt = false;
  auto lambda = [&](int a, char c) {return a + ((is_odd_dgt = !is_odd_dgt) ? c-'0' : m[c-'0']);};
  int s = std::accumulate(id.rbegin(), id.rend(), 0, lambda);
  return 0 == s%10;
}

int main( )
{
  auto t_cases = {"49927398716", "49927398717", "1234567812345678", "1234567812345670"};
  auto print = [](const string & s) {cout << s << ": " << luhn(s) << endl;};
  for_each(t_cases.begin(), t_cases.end(), print);
  return 0;
}

It is also possible to achieve a compile-time version using metaprogramming.

#include <iostream>
#include <type_traits>

template<size_t I, int... Args>
struct find_impl;

template<int A, int... Args>
struct find_impl<0, A, Args...> {
    using type = std::integral_constant<int, A>;
};

template<int A, int B, int... Args>
struct find_impl<0, A, B, Args...> {
    using type = std::integral_constant<int, A>;
};

template<size_t I, int A, int B, int... Args>
struct find_impl<I, A, B, Args...> {
    using type = typename find_impl<I-1, B, Args...>::type;
};

namespace detail {
template<typename, typename>
struct append_sequence
{};

template<typename T, typename... Ts>
struct append_sequence<T, std::tuple<Ts...>> {
    using type = std::tuple<Ts..., T>;
};

template<typename... Ts>
struct reverse_sequence {
    using type = std::tuple<>;
};

template<typename T, typename... Ts>
struct reverse_sequence<T, Ts...> {
    using type = typename append_sequence<
                            T,
                            typename reverse_sequence<Ts...>::type
                        >::type;
};
}

template<size_t I>
using rule3 = typename find_impl<I, 0, 2, 4, 6, 8, 1, 3, 5, 7, 9>::type;

template<int A, char C, bool dgt>
struct calc
    : std::integral_constant<int, A + C - '0'>
{};

template<int A, char C>
struct calc<A, C, false>
    : std::integral_constant<int, A + rule3<C - '0'>::type::value>
{};

template<typename Acc, bool Dgt, char...>
struct luhn_impl;

template<typename Acc, bool Dgt, char A, char... Args>
struct luhn_impl<Acc, Dgt, A, Args...> {
    using type = typename calc<Acc::value, A, Dgt>::type;
};

template<typename Acc, bool Dgt, char A, char B, char... Args>
struct luhn_impl<Acc, Dgt, A, B, Args...> {
    using type =
        typename luhn_impl<typename calc<Acc::value, A, Dgt>::type, !Dgt, B, Args...>::type;
};

template<typename>
struct luhn;

template<typename... Args>
struct luhn<std::tuple<Args...>> {
    using type = typename luhn_impl<std::integral_constant<int, 0>, true, Args::value...>::type;
    constexpr static bool result = (type::value % 10) == 0;
};

template<char... Args>
bool operator "" _luhn() {
    return luhn<typename detail::reverse_sequence<std::integral_constant<char, Args>...>::type>::result;
}

int main() {
    std::cout << std::boolalpha;
    std::cout << 49927398716_luhn << std::endl;
    std::cout << 49927398717_luhn << std::endl;
    std::cout << 1234567812345678_luhn << std::endl;
    std::cout << 1234567812345670_luhn << std::endl;
    return 0;
}
true
false
false
true

Caché ObjectScript

Class Utils.Check [ Abstract ]
{

ClassMethod Luhn(x As %String) As %Boolean
{
	// https://www.simple-talk.com/sql/t-sql-programming/calculating-and-verifying-check-digits-in-t-sql/
	SET x=$TRANSLATE(x," "), cd=$EXTRACT(x,*)
	SET x=$REVERSE($EXTRACT(x,1,*-1)), t=0
	FOR i=1:1:$LENGTH(x) {
		SET n=$EXTRACT(x,i)
		IF i#2 SET n=n*2 IF $LENGTH(n)>1 SET n=$EXTRACT(n,1)+$EXTRACT(n,2)
		SET t=t+n
	}
	QUIT cd=((t*9)#10)
}

}
Examples:
USER>For  { Read ccn Quit:ccn=""  Write ": "_##class(Utils.Check).Luhn(ccn), ! }
49927398716: 1
49927398717: 0
1234567812345678: 0
1234567812345670: 1

USER>

Ceylon

shared void run() {
	value numbers = "49927398716
	                 49927398717
	                 1234567812345678
	                 1234567812345670";
	for(number in numbers.lines) {
		print("``number`` passes? ``luhn(number)``");
	}
}

shared Boolean luhn(String number) {
	value digits = number
			.reversed
			.map(Character.string)
			.map(Integer.parse)
			.narrow<Integer>();
	value s1 = sum { 0, *digits.by(2) };
	value s2 = sum {
		0,
		*digits
			.skip(1)
			.by(2)
			.map(curry(times<Integer>)(2))
			.map((Integer element) => element / 10 + element % 10)
	};
	return (s1 + s2) % 10 == 0;
}

Clojure

(defn luhn? [cc]
  (let [factors (cycle [1 2])
        numbers (map #(Character/digit % 10) cc)
        sum (reduce + (map #(+ (quot % 10) (mod % 10))
                           (map * (reverse numbers) factors)))]
    (zero? (mod sum 10))))

(doseq [n ["49927398716" "49927398717" "1234567812345678" "1234567812345670"]]
  (println (luhn? n)))

CLU

luhn = proc (num: string) returns (bool) signals (bad_format)
    total: int := 0
    even: bool := true
    for i: int in int$from_to_by(string$size(num), 1, -1) do
        digit: int := int$parse(string$c2s(num[i])) resignal bad_format
        even := ~even
        if even then
            digit := 2 * digit
            if digit >= 10 then digit := digit//10 + 1 end
        end
        total := total + digit
    end
    return(total // 10 = 0)
end luhn

start_up = proc ()
    po: stream := stream$primary_output()
    tests: sequence[string] := sequence[string]$
        ["49927398716", "49927398717", "1234567812345678", "1234567812345670"]
    for test: string in sequence[string]$elements(tests) do
        stream$puts(po, test || ": ")
        if luhn(test)
            then stream$putl(po, "pass")
            else stream$putl(po, "fail")
        end
    end
end start_up
Output:
49927398716: pass
49927398717: fail
1234567812345678: fail
1234567812345670: pass

COBOL

Works with: OpenCOBOL
       IDENTIFICATION DIVISION.
       PROGRAM-ID.  LUHNTEST.
       ENVIRONMENT DIVISION.
       INPUT-OUTPUT SECTION.
       data division.
       WORKING-STORAGE SECTION.
       01  inp-card.
         03  inp-card-ch      pic x(01) occurs 20 times.
       01  ws-result          pic 9(01).
         88  pass-luhn-test             value 0.

       PROCEDURE DIVISION.
           move "49927398716"       to inp-card
           perform test-card
           move "49927398717"       to inp-card
           perform test-card
           move "1234567812345678"  to inp-card
           perform test-card
           move "1234567812345670"  to inp-card
           perform test-card
           stop run
           .
       test-card.
           call "LUHN" using inp-card, ws-result
           if pass-luhn-test
             display "input=" inp-card "pass"
           else
             display "input=" inp-card "fail"
           .

       END PROGRAM LUHNTEST.
       IDENTIFICATION DIVISION.
       PROGRAM-ID.  LUHN.
       ENVIRONMENT DIVISION.
       INPUT-OUTPUT SECTION.
       DATA DIVISION.
       WORKING-STORAGE SECTION.
       01  maxlen           pic 9(02) comp value 16.
       01  inplen           pic 9(02) comp value 0.
       01  i                pic 9(02) comp value 0.
       01  j                pic 9(02) comp value 0.
       01  l                pic 9(02) comp value 0.
       01  dw               pic 9(02) comp value 0.
       01  ws-total         pic 9(03) comp value 0.
       01  ws-prod          pic 99.
       01  filler redefines ws-prod.
         03  ws-prod-tens   pic 9.
         03  ws-prod-units  pic 9.
       01  ws-card.
         03  filler           occurs 16 times depending on maxlen.
           05  ws-card-ch     pic x(01).
           05  ws-card-digit redefines ws-card-ch  pic 9(01).
       LINKAGE SECTION.
       01  inp-card.
         03  inp-card-ch      pic x(01) occurs 20 times.
       01  ws-result          pic 9(01).
         88  pass-luhn-test             value 0.

       PROCEDURE DIVISION using inp-card, ws-result.
           perform varying i from 1 by +1
           until i > maxlen
           or    inp-card-ch (i) = space
           end-perform
           compute l = i - 1
           compute inplen = l
           perform varying j from 1 by +1
           until j > inplen
             if l < 1
               move "0"             to ws-card-ch (j)
             else
               move inp-card-ch (l) to ws-card-ch (j)
               compute l = l - 1
             end-if
           end-perform
           move 0 to ws-total
           perform varying i from 1 by +1
           until i > inplen
             compute dw = 2 - (i - 2 * function integer (i / 2))
             compute ws-prod = ws-card-digit (i) * dw
             compute ws-total = ws-total
                              + ws-prod-tens
                              + ws-prod-units
           end-perform
           compute ws-result = ws-total - 10 * function integer (ws-total / 10)
           goback
           .
       END PROGRAM LUHN.
Output:
input=49927398716         pass 
input=49927398717         fail 
input=1234567812345678    fail 
input=1234567812345670    pass 

Comal

0010 FUNC luhn(s$) CLOSED
0020   total#:=0
0030   even#:=TRUE
0040   FOR i#:=LEN(s$) TO 1 STEP -1 DO
0050     digit#:=VAL(s$(i#))
0060     even#:=NOT even#
0070     IF even# THEN digit#:=(2*digit#) DIV 10+(2*digit#) MOD 10
0080     total#:+digit#
0090   ENDFOR i#
0100   RETURN total# MOD 10=0
0110 ENDFUNC luhn
0120 //
0130 PROC test(s$)
0140   PRINT s$,": ",
0150   IF luhn(s$) THEN
0160     PRINT "pass"
0170   ELSE
0180     PRINT "fail"
0190   ENDIF
0200 ENDPROC test
0210 //
0220 test("49927398716")
0230 test("49927398717")
0240 test("1234567812345678")
0250 test("1234567812345670")
0260 END
Output:
49927398716: pass
49927398717: fail
1234567812345678: fail
1234567812345670: pass

Common Lisp

(defun luhn (n)
  (labels ((sum-digits (n) (if (> n 9) (- n 9) n)))
    (let ((n* (reverse n)) (l (length n)))
      (let ((s1 (loop for i from 0 below l by 2
		   summing (digit-char-p (aref n* i))))
	    (s2 (loop for i from 1 below l by 2
		   summing (sum-digits (* 2 (digit-char-p (aref n* i)))))))
	(zerop (mod (+ s1 s2) 10))))))

Another version, using Maciej Pasternacki's reader macros for function composition and currying in the curly package:

(require :curly)
(use-package :curly)
(enable-curly-syntax)

(defun luhn (seq)
  (labels ((sum-digits (n) (if (> n 9) (- n 9) n)))
    (funcall {zerop (mod * 10) (apply #'+) (mapcar #'sum-digits)
	     (mapcar #'* '#1=(1 2 . #1#)) (map 'list #'digit-char-p) reverse} seq)))

Cowgol

include "cowgol.coh";

# Given a string containing the digits of a credit card number,
# see if it passes the Luhn test.
sub luhn(card: [uint8]): (ok: uint8) is
    # Scan ahead to last digit, counting digits
    var n: uint8 := 0;
    while [card] != 0 loop
        n := n + 1;
        card := @next card;
    end loop;
    
    var sum: uint8 := 0;
    while n > 0 loop    
        # odd digit is simply added
        card := @prev card;
        n := n - 1;
        sum := sum + ([card] - '0');
        
        # if uneven amount of digits, stop
        if n == 0 then break; end if;
        
        # even digit
        card := @prev card;
        n := n - 1;
        var digit := [card] - '0';
        
        # it is good to avoid unnecessary multiplication/
        # division, since 8-bit processors and microcontrollers
        # don't tend to have that in hardware
        if digit < 5 then
            sum := sum + digit + digit; 
        else
            digit := digit - 5;
            sum := sum + digit + digit + 1;
        end if;
    end loop;
    
    # there is no boolean type, comparisons only work
    # in conditionals; this is the only way to return
    # a status
    if sum % 10 == 0 then
        ok := 1;
    else
        ok := 0;
    end if;
end sub;


# Test and print
sub test(card: [uint8]) is  
    var msg: [uint8][] := {"Fail", "Pass"};
    print(card);
    print(": ");
    print(msg[luhn(card)]);
    print_nl();
end sub;

test("49927398716");
test("49927398717");
test("1234567812345678");
test("1234567812345670");
Output:
49927398716: Pass
49927398717: Fail
1234567812345678: Fail
1234567812345670: Pass

Crystal

def luhn_valid?(n)  # Card values can be numbers or strings
  d2sum = [0, 2, 4, 6, 8, 1, 3, 5, 7, 9]
  sum, n = 0, n.to_u64
  while n > 0; sum += n%10; n //= 10; sum += d2sum[n%10]; n //= 10 end
  sum % 10 == 0
end

cards = [49927398716, "49927398717", 1234567812345678, "1234567812345670"]
cards.each{ |i| puts "#{i}: #{luhn_valid?(i)}" }
Output:
49927398716: true
49927398717: false
1234567812345678: false
1234567812345670: true

D

Functional Version

Translation of: Haskell
import std.algorithm, std.range, std.string;

enum luhnTest = (in string n) pure /*nothrow*/ @safe /*@nogc*/ =>
    retro(n)
    .zip(only(1, 2).cycle)
    .map!(p => (p[0] - '0') * p[1])
    .map!(d => d / 10 + d % 10)
    .sum % 10 == 0;

void main() {
    assert("49927398716 49927398717 1234567812345678 1234567812345670"
           .split.map!luhnTest.equal([true, false, false, true]));
}

More Imperative Version

Translation of: C
import std.algorithm;

bool luhnTest(in string num) @safe pure nothrow @nogc {
    uint sum;
    foreach_reverse (immutable i, immutable n; num) {
        immutable uint ord = n - '\u0030';
        sum += ((num.length - i) & 1) ? ord : ord / 5 + (2 * ord) % 10;
    }
    return sum % 10 == 0;
}

void main() {
    immutable data = ["49927398716",
                      "49927398717",
                      "1234567812345678",
                      "1234567812345670"];
    assert(data.map!luhnTest.equal([true, false, false, true]));
}

Stronger Statically Typed Version

This version uses more precise types.

Translation of: SPARK
import std.stdio;

struct Interval(T) {
    immutable T a, b;

    this(in T a_, in T b_) pure nothrow @nogc {
        this.a = a_;
        this.b = b_;
    }

    bool opBinaryRight(string op="in")(in T x)
    const pure nothrow @nogc {
        return x >= a && x <= b;
    }

    pure nothrow @safe @nogc const invariant {
        assert(a <= b);
    }
}

Interval!T interval(T)(in T a, in T b) pure nothrow @nogc {
    return Interval!T(a, b);
}


bool luhnTest(in string num) pure nothrow @nogc
in {
    assert(num.length <= 20);
} body {
    int sum = 0;
    bool od = true;
    bool ok = true;
    immutable int numLen = num.length;

    foreach_reverse (immutable p; 0 .. numLen) {
        immutable int i = num[p] - '0';
        if (i !in interval(0, 9)) {
            ok = false;
            break;
        }

        immutable int x = ((i * 2) % 10) + (i / 5);
        assert((numLen - p) in interval(0, 19));
        assert(sum in interval(0, (numLen - p) * 10));
        assert(i in interval(0, 9));
        assert(x in interval(0, 9));
        sum += od ? i : x;
        od = !od;
    }

    return ok && (sum % 10) == 0;
}


void main() {
    foreach (immutable n; ["49927398716", "49927398717",
                           "1234567812345678", "1234567812345670",
                           "123456781234567D"])
        writefln("%s is %svalid", n, luhnTest(n) ? "" : "not ");
}

Delphi

Works with: Delphi version 6.0

Uses an array to handle the situation where multiply a term by 2, creates a two digit number. The array automatically handles adding each digit of the resulting two digit number. Also, avoids reversing the number by traversing the array backwards

{Test data arrays}

const Num1: array [0..10] of byte = (4,9,9,2,7,3,9,8,7,1,6);
const Num2: array [0..10] of byte = (4,9,9,2,7,3,9,8,7,1,7);
const Num3: array [0..15] of byte = (1,2,3,4,5,6,7,8,1,2,3,4,5,6,7,8);
const Num4: array [0..15] of byte = (1,2,3,4,5,6,7,8,1,2,3,4,5,6,7,0);

{Simplifies cases where we have to sum a two digit number}

const DigitSum: array [0..18] of byte = (0,1,2,3,4,5,6,7,8,9,1,2,3,4,5,6,7,8,9);

function ValidateCreditCard(CardNum: array of byte): boolean;
{Validate a Credit Card number}
var I,J,Len,Sum,Sum1,Sum2: integer;
var Rev: array of byte;
begin
Sum1:=0; Sum2:=0;
Len:=High(CardNum);
for I:=Len downto 0 do
 if ((I-Len) and 1)=0 then Sum1:=Sum1 + CardNum[I]
 else Sum2:=Sum2 + DigitSum[CardNum[I]*2];
Sum:=Sum1+Sum2;
Result:=(Sum mod 10)=0;
end;


function CardNumberToStr(CardNum: array of byte): string;
{Convert card number to a string}
var I: integer;
begin
Result:='';
for I:=0 to High(CardNum) do
Result:=Result+IntToStr(CardNum[I]);
end;


procedure TestDisplayNumber(Memo: TMemo; Num: array of byte);
{Test a credit card number and display results}
var S: string;
begin
S:=CardNumberToStr(Num);
if ValidateCreditCard(Num) then S:=S+': Valid'
else S:=S+': Not Valid';
Memo.Lines.Add(S);
end;


procedure TestCreditCardNums(Memo: TMemo);
{Test all credit card numbers}
begin
TestDisplayNumber(Memo,Num1);
TestDisplayNumber(Memo,Num2);
TestDisplayNumber(Memo,Num3);
TestDisplayNumber(Memo,Num4);
end;
Output:
49927398716: Valid
49927398717: Not Valid
1234567812345678: Not Valid
1234567812345670: Valid


Draco

proc nonrec luhn(*char num) bool:
    [10] byte map = (0, 2, 4, 6, 8, 1, 3, 5, 7, 9);
    byte total, digit;
    *char start;
    bool even;
    
    start := num;
    total := 0;
    even := true;
    while num* /= '\e' do num := num + 1 od;
    while 
        num := num - 1;
        num >= start 
    do 
        digit := num* - '0';
        even := not even;
        if even then digit := map[digit] fi;
        total := total + digit
    od;
    
    total % 10 = 0
corp

proc nonrec test(*char num) void:
    writeln(num, ": ", if luhn(num) then "pass" else "fail" fi)
corp 

proc nonrec main() void:
    test("49927398716");
    test("49927398717");
    test("1234567812345678");
    test("1234567812345670")
corp
Output:
49927398716: pass
49927398717: fail
1234567812345678: fail
1234567812345670: pass

DuckDB

Works with: DuckDB version V1.0
create or replace function odds(lst) as (
  list_filter(lst, (x,i) -> i%2=1)
);

create or replace function evens(lst) as (
  list_filter(lst, (x,i) -> i%2=0)
);

create or replace function digit_sum(i) as (
  regexp_extract_all(i::VARCHAR, '.')
  .list_transform(x -> x::INT)
  .list_sum()
);

# Return boolean: true iff the list of digits passes
create or replace function list_luhn(lst) as (
  with odds_sum as (
         select list_reverse(lst).odds().list_sum() as odds_sum),
       evens_reduce as (
         select list_reverse(lst).list_transform(x -> digit_sum(2*x))
                .list_sum() as evens_reduce)
  select (odds_sum + evens_reduce ) % 10 = 0 as pass
  from odds_sum, evens_reduce
);

# The list of the digits of i (an integer or string)
create or replace function digits(i) as (
  regexp_extract_all(i::TEXT, '.').list_transform(x -> x::INT)
);

# i can be an integer or string
create or replace function luhn(i) as (
  digits(i).list_luhn()
);

## Examples::
select n, luhn(n), luhn(n::TEXT) as "luhn(n::TEXT)"
from unnest(
  [49927398716,
   49927398717,
   1234567812345678,
   1234567812345670
   ]) _(n);
Output:
┌──────────────────┬─────────┬───────────────┐
│        n         │ luhn(n) │ luhn(n::TEXT) │
│      int64       │ boolean │    boolean    │
├──────────────────┼─────────┼───────────────┤
│      49927398716 │ false   │ false         │
│      49927398717 │ false   │ false         │
│ 1234567812345678 │ false   │ false         │
│ 1234567812345670 │ false   │ false         │
└──────────────────┴─────────┴───────────────┘


EasyLang

func luhn cc$ .
   for i = len cc$ downto 1
      odd = 1 - odd
      dig = number substr cc$ i 1
      if odd = 0
         dig = 2 * dig
         if dig >= 10
            dig -= 9
         .
      .
      sum += dig
   .
   return if sum mod 10 = 0
.
cc$[] = [ "49927398716" "49927398717" "1234567812345678" "1234567812345670" ]
for cc$ in cc$[]
   write cc$ & " "
   if luhn cc$ = 1
      print "is valid"
   else
      print "is not valid"
   .
.
Output:
49927398716 is valid
49927398717 is not valid
1234567812345678 is not valid
1234567812345670 is valid

EchoLisp

;; value for 'even' numbers
(define (even-val n) (if (> n 4) (+ n n -9) (+ n n)))

;;Luhn test
;; input : a string of decimal digits
;; output #t or #f
(define (valid nums (odd #f )) 
    (let ((nums (map string->number (reverse (string->list nums)))))
    (= 0 (modulo 
       (for/sum ((n nums)) (set! odd (not odd)) (if odd n (even-val n))) 
       10))))

(valid "49927398716")  #t
(valid "1234567812345670")  #t
(valid "1234567812345678")  #f
(valid "49927398717")  #f

Elixir

defmodule Luhn do
  def valid?(cc) when is_binary(cc), do: String.to_integer(cc) |> valid?
  def valid?(cc) when is_integer(cc) do
    0 == Integer.digits(cc)
         |> Enum.reverse
         |> Enum.chunk(2, 2, [0])
         |> Enum.reduce(0, fn([odd, even], sum) -> Enum.sum([sum, odd | Integer.digits(even*2)]) end)
         |> rem(10)
  end
end

numbers = ~w(49927398716 49927398717 1234567812345678 1234567812345670)
for n <- numbers, do: IO.puts "#{n}: #{Luhn.valid?(n)}"
Output:
49927398716: true
49927398717: false
1234567812345678: false
1234567812345670: true

Emacs Lisp

Library: seq.el
(require 'seq)

(defun luhn (str)
  "Check if STR is a valid credit card number using the Luhn algorithm."
  (if (string-match-p "[^0-9]" str)
      (error "String contains invalid character")
    (let ((digit-list (reverse (mapcar #'(lambda (x) (- x 48))
                                         (string-to-list str)))))
        (zerop
         (mod (apply #'+ (seq-map-indexed
                          (lambda (elt idx)
                            (if (not (zerop (% idx 2)))
                                (if (> (* 2 elt) 9)
                                    (- (* 2 elt) 9)
                                  (* 2 elt))
                              elt))
                          digit-list))
              10)))))

(mapcar #'luhn '("49927398716" "49927398717" "1234567812345678" "1234567812345670"))
Output:
(t nil nil t)

Erlang

-module(luhn_test).

-export( [credit_card/1, task/0] ).

luhn_sum([Odd, Even |Rest]) when Even >= 5 ->
    Odd + 2 * Even - 10 + 1 + luhn_sum(Rest);
luhn_sum([Odd, Even |Rest]) ->
    Odd + 2 * Even + luhn_sum(Rest);
luhn_sum([Odd]) ->
    Odd;
luhn_sum([]) ->
    0.

check( Sum ) when (Sum rem 10) =:= 0 -> valid;
check( _Sum ) -> invalid.

credit_card(Digits) ->
    check(luhn_sum(lists:map(fun(D) -> D-$0 end, lists:reverse(Digits)))).

task() ->
    Numbers = ["49927398716", "49927398717", "1234567812345678", "1234567812345670"],
    [io:fwrite("~s: ~p~n", [X, credit_card(X)]) || X <- Numbers].
Output:
16> luhn_test:task().
49927398716: valid
49927398717: invalid
1234567812345678: invalid
1234567812345670: valid

Euphoria

Translation of: C
function luhn(sequence cc)
    integer isOdd, oddSum, evenSum, digit
    isOdd = 1
    oddSum = 0
    evenSum = 0
    for i = length(cc) to 1 by -1 do
        digit = cc[i] - '0'
        if isOdd then
            oddSum += digit
        else
            evenSum += floor(digit / 5) + remainder(2 * digit, 10)
        end if
        isOdd = not isOdd
    end for
    return not remainder(oddSum + evenSum, 10)
end function

constant cc_numbers = {
    "49927398716",
    "49927398717",
    "1234567812345678",
    "1234567812345670"
}

for i = 1 to length(cc_numbers) do
    printf(1,"%s = %d\n", {cc_numbers[i], luhn(cc_numbers[i])})
end for
Output:
49927398716 = 1
49927398717 = 0
1234567812345678 = 0
1234567812345670 = 1

Excel

LAMBDA

Binding the name luhnChecked to the following lambda expression in the Name Manager of the Excel WorkBook:

(See LAMBDA: The ultimate Excel worksheet function)

luhnChecked
=LAMBDA(s,
    LET(
        ns, REVERSECOLS(VALUE(CHARSROW(s))),
        ixs, SEQUENCE(1, COLUMNS(ns), 1, 1),

        0 = MOD(SUM(
                FILTER(ns, 0 <> MOD(ixs, 2))
            ) + (
                LAMBDA(n,
                    DIGITSUM(
                        CONCAT(TEXT(2 * n, "0"))
                    )
                )(
                    FILTER(ns, 0 = MOD(ixs, 2))
                )
            ),
            10
        )
    )
)

and also assuming the following generic bindings in the Name Manager for the WorkBook:

CHARSROW
=LAMBDA(s,
    MID(s,
        SEQUENCE(1, LEN(s), 1, 1),
        1
    )
)


DIGITSUM
=LAMBDA(s,
    SUM(VALUE(
        MID(s,
            SEQUENCE(LEN(s), 1, 1, 1),
            1
        )
    ))
)


REVERSECOLS
=LAMBDA(xs,
    LET(
        n, COLUMNS(xs),

        SORTBY(
            xs,
            SEQUENCE(1, n, n, -1)
        )
    )
)
Output:
fx =luhnChecked(A2)
A B
1 Digit strings Luhn result
2 49927398716 TRUE
3 49927398717 FALSE
4 1234567812345678 FALSE
5 1234567812345670 TRUE

F#

let luhn (s:string) =
  let rec g r c = function
  | 0 -> r
  | i ->
      let d = ((int s.[i - 1]) - 48) <<< c
      g (r + if d < 10 then d else d - 9) (1 - c) (i - 1)
  (g 0 0 s.Length) % 10 = 0

Factor

Works with: Factor version 0.98
USING: kernel math math.parser math.order math.ranges sequences ;
IN: luhn

: reversed-digits ( n -- list )
    { } swap
    [ dup 0 > ]
        [ 10 /mod  swapd suffix  swap ]
    while drop ;

: luhn-digit  ( n -- n )
    reversed-digits dup length <iota> [
        2dup swap nth
        swap odd? [ 2 *  10 /mod + ] when
    ] map sum 10 mod
    nip ;

: luhn? ( n -- ? )
    luhn-digit 0 = ;
Output:
( scratchpad ) 49927398716 luhn? .
t
( scratchpad ) 49927398717 luhn? .
f
( scratchpad ) 1234567812345678 luhn? .
f
( scratchpad ) 1234567812345670 luhn? .
t

Forth

: luhn ( addr len -- ? )
  0 >r over +             ( R: sum )
  begin  1- 2dup <=
  while                   \ odd
         dup c@ [char] 0 -
         r> + >r
         1- 2dup <=
  while                   \ even
         dup c@ [char] 0 -
         2* 10 /mod +     \ even digits doubled, split, and summed
         r> + >r
  repeat then
  2drop  r> 10 mod 0= ;

s" 49927398716"      luhn .   \ -1
s" 49927398717"      luhn .   \ 0
s" 1234567812345678" luhn .   \ 0
s" 1234567812345670" luhn .   \ -1

Fortran

program luhn
  implicit none
  integer              :: nargs
  character(len=20)    :: arg
  integer              :: alen, i, dr
  integer, allocatable :: number(:)
  integer, parameter   :: drmap(0:9) = [0, 2, 4, 6, 8, 1, 3, 5, 7, 9]

  ! Get number
  nargs = command_argument_count()
  if (nargs /= 1) then
     stop
  end if
  call get_command_argument(1, arg, alen)
  allocate(number(alen))
  do i=1, alen
     number(alen-i+1) = iachar(arg(i:i)) - iachar('0')
  end do

  ! Calculate number
  dr = 0
  do i=1, alen
     dr = dr + merge(drmap(number(i)), number(i), mod(i,2) == 0)
  end do

  if (mod(dr,10) == 0) then
     write(*,'(a,i0)') arg(1:alen)//' is valid'
  else
     write(*,'(a,i0)') arg(1:alen)//' is not valid'
  end if
end program luhn

! Results:
! 49927398716 is valid
! 49927398717 is not valid
! 1234567812345678 is not valid
! 1234567812345670 is valid

FreeBASIC

' version 05-07-2015
' compile with: fbc -s console

#Ifndef TRUE        ' define true and false for older freebasic versions
    #Define FALSE 0
    #Define TRUE Not FALSE
#EndIf

Function luhntest(cardnr As String) As Integer

    cardnr = Trim(cardnr) ' we don't want spaces
    Dim As String reverse_nr = cardnr
    Dim As Integer i, j, s1, s2, l = Len(cardnr) - 1

    ' reverse string
    For i = 0 To l
        reverse_nr[i] = cardnr[l - i]
    Next
    ' sum odd numbers
    For i = 0 To l Step 2
        s1 = s1 + (reverse_nr[i] - Asc("0"))
    Next
    ' sum even numbers
    For i = 1 To l Step 2
        j = reverse_nr[i] - Asc("0")
        j = j * 2
        If j > 9 Then j = j Mod 10 + 1
        s2 = s2 + j
    Next

    If (s1 + s2) Mod 10 = 0 Then
        Return TRUE
    Else
        Return FALSE
    End If

End Function

' ------=< MAIN >=------

Dim As String input_nr(1 To ...) = {"49927398716", "49927398717",_
                          "1234567812345678", "1234567812345670"}
Dim As Integer a

Print  "Task test number 49927398716 should be TRUE, report back as ";
Print IIf(luhntest("49927398716" ) = TRUE, "TRUE", "FALSE")
Print : Print

Print "test card nr:"
For a = 1 To UBound(input_nr)
    Print input_nr(a); " = "; IIf(luhntest(input_nr(a)) = TRUE, "TRUE", "FALSE")
Next

' empty keyboard buffer
While InKey <> "" : Wend
Print : Print "hit any key to end program"
Sleep
End
Output:
Task test number 49927398716 should be TRUE, report back as TRUE

test card nr:
49927398716 = TRUE
49927398717 = FALSE
1234567812345678 = FALSE
1234567812345670 = TRUE

Free Pascal

see also: Pascal

program luhn;

  function lunh(arg: string): boolean;
  var
    i, sum: integer;
    temp: byte;
  begin
    sum := 0;
    for i:= length(arg) downto 1 do begin  // Run the characters backwards
      temp := byte(arg[i])-48;             // Convert from ASCII to byte
      if (length(arg)-i) mod 2 = 0
        then sum := sum + temp             // Odd characters just add
        else if temp < 5
           then sum := sum + 2*temp        // Even characters add double
           else sum := sum + (2*temp)-9;   // or sum the digits of the doubling
    end;
    result := sum mod 10 = 0;              // Return true if sum ends in a 0
  end;

begin
  writeln('     49927398716: ', lunh('49927398716'));
  writeln('     49927398717: ', lunh('49927398717'));
  writeln('1234567812345678: ', lunh('1234567812345678'));
  writeln('1234567812345670: ', lunh('1234567812345670'));
end.
Output:
     49927398716: TRUE
     49927398717: FALSE
1234567812345678: FALSE
1234567812345670: TRUE

FunL

def luhn_checksum( card_number ) =
  def digits_of( n ) = [int(d) | d <- n.toString()]
  
  digits = digits_of( card_number ).reverse()
  odd_digits = digits(0:digits.length():2)
  even_digits = digits(1:digits.length():2)
  (sum( odd_digits ) + sum( sum(digits_of(d*2)) | d <- even_digits )) mod 10
 
def is_luhn_valid( card_number ) = luhn_checksum( card_number ) == 0

for n <- [49927398716, 49927398717, 1234567812345678, 1234567812345670]
  println( n + ' is ' + (if is_luhn_valid(n) then 'valid' else 'invalid') )
Output:
49927398716 is valid
49927398717 is invalid
1234567812345678 is invalid
1234567812345670 is valid


FutureBasic

include "NSLog.incl"

local fn LuhnCheck( cardStr as CFStringRef ) as BOOL
  NSInteger  i, j, count, s1 = 0, s2 = 0
  BOOL       result = NO
  
  // Build array of individual numbers in credit card string
  NSUInteger strLength = len(cardStr)
  CFMUtableArrayRef mutArr = fn MutableArrayWithCapacity(strLength)
  for i = 0 to strLength - 1
    CFStringRef tempStr = fn StringWithFormat( @"%C", fn StringCharacterAtIndex( cardStr, i ) )
    MutableArrayInsertObjectAtIndex( mutArr, tempStr, i )
  next
  
  // Reverse the number array
  CFArrayRef reversedArray = fn EnumeratorAllObjects( fn ArrayReverseObjectEnumerator( mutArr ) )
  
  // Get number of array elements
  count = len(reversedArray)
  
  // Handle odd numbers
  for i = 0 to count - 1 step 2
    s1 = s1 + fn StringIntegerValue( reversedArray[i] )
  next
  
  // Hnadle even numbers
  for i = 1 to count - 1 step 2
    j = fn StringIntegerValue( reversedArray[i] )
    j = j * 2
    if j > 9 then j = j mod 10 + 1
    s2 = s2 + j
  next

  if (s1 + s2) mod 10 = 0 then result = YES else result = NO
end fn = result

NSLogClear
if fn LuhnCheck( @"49927398716" ) then NSLog (@"%@ is valid.", @"49927398716" ) else NSLog (@"%@ is not valid.", @"49927398716" )
if fn LuhnCheck( @"49927398717" ) then NSLog (@"%@ is valid.", @"49927398717" ) else NSLog (@"%@ is not valid.", @"49927398717" )
if fn LuhnCheck( @"1234567812345678" ) then NSLog (@"%@ is valid.", @"1234567812345678" ) else NSLog (@"%@ is not valid.", @"1234567812345678" )
if fn LuhnCheck( @"1234567812345670" ) then NSLog (@"%@ is valid.", @"1234567812345670" ) else NSLog (@"%@ is not valid.", @"1234567812345670" )

HandleEvents
Output:
49927398716 is valid.
49927398717 is not valid.
1234567812345678 is not valid.
1234567812345670 is valid.

Gambas

Click this link to run this code

Public Sub Main()
Dim sTrial As String[] = ["49927398716", "49927398717", "1234567812345678", "1234567812345670"]
Dim sRev As String
Dim siCount, siOdd, siEven, siHold, siQty As Short

For siQty = 0 To sTrial.Max

  siOdd = 0
  siEven = 0
  sRev = ""

  For siCount = Len(sTrial[siQty]) DownTo 1
    sRev &= Mid(sTrial[siQty], siCount, 1)
  Next

  For siCount = 1 To Len(sRev)
    If Odd(siCount) Then siOdd += Val(Mid(sRev, siCount, 1))
    If Even(siCount) Then
      siHold = Val(Mid(sRev, siCount, 1)) * 2
      If siHold > 9 Then 
        siEven += Val(Mid(Str(siHold), 1, 1)) + Val(Mid(Str(siHold), 2, 1))
      Else
        siEven += Val(Mid(sRev, siCount, 1)) * 2
      End If
    End If
  Next

  sRev = Str(siOdd + siEven)
  If sRev Ends "0" Then 
    Print sTrial[siQty] & " is a valid number"
  Else
    Print sTrial[siQty] & " is NOT a valid number"
  End If
Next

End

Output:

49927398716 is a valid number
49927398717 is NOT a valid number
1234567812345678 is NOT a valid number
1234567812345670 is a valid number

GAP

IsLuhn := function(n)
	local c, d, i, j, r;
	d := "0123456789";
	j := 1;
	r := 0;
	for c in Reversed(String(n)) do
		i := Position(d, c);
		if i = fail then
			continue;
		fi;
		i := j*(i - 1);
		r := r + QuoInt(i, 10) + RemInt(i, 10);
		j := 3 - j;
	od;
	return RemInt(r, 10) = 0;
end;

List([49927398716, 49927398717, 1234567812345678, 1234567812345670], IsLuhn);
# [ true, false, false, true ]

# Will also work on strings, and will skip non-digits
IsLuhn("4-992-739-871-6");
# true

Go

package main

import (
    "fmt"
    "strings"
)

const input = `49927398716
49927398717
1234567812345678
1234567812345670`

var t = [...]int{0, 2, 4, 6, 8, 1, 3, 5, 7, 9}

func luhn(s string) bool {
    odd := len(s) & 1
    var sum int
    for i, c := range s {
        if c < '0' || c > '9' {
            return false
        }
        if i&1 == odd {
            sum += t[c-'0']
        } else {
            sum += int(c - '0')
        }
    }
    return sum%10 == 0
}

func main() {
    for _, s := range strings.Split(input, "\n") {
        fmt.Println(s, luhn(s))
    }
}
Output:
49927398716 true
49927398717 false
1234567812345678 false
1234567812345670 true

Groovy

def checkLuhn(number) {
    int total
    (number as String).reverse().eachWithIndex { ch, index ->
        def digit = Integer.parseInt(ch)
        total += (index % 2 ==0) ? digit : [0, 2, 4, 6, 8, 1, 3, 5, 7, 9][digit]
    }
    total % 10 == 0
}

Testing the function:

def verifyLuhn(number, expected) {
    println "Checking: $number (${checkLuhn(number)})"
    assert expected == checkLuhn(number)
}

[49927398716: true, 49927398717: false, 1234567812345678: false, 1234567812345670: true].each { number, expected ->
    verifyLuhn number, expected
}
Output:
Checking: 49927398716 (true)
Checking: 49927398717 (false)
Checking: 1234567812345678 (false)
Checking: 1234567812345670 (true)

Haskell

import Data.Char (digitToInt)
luhn = (0 ==) . (`mod` 10) . sum . map (uncurry (+) . (`divMod` 10)) .
       zipWith (*) (cycle [1,2]) . map digitToInt . reverse
Output:
map luhn ["49927398716", "49927398717", "1234567812345678", "1234567812345670"]
[True,False,False,True]

Or, aiming for a legible relationship with the stages shown in the task description:

import Data.Char (digitToInt)
import Data.List (transpose)
import Data.List.Split (chunksOf)

luhn :: String -> Bool
luhn x = 0 == rem (s1 + s2) 10
  where
    stringInts = fmap digitToInt
    [odds, evens] =
      (transpose . chunksOf 2)
        (stringInts $ reverse x)
    s1 = sum odds
    s2 = sum $ sum . stringInts . show . (2 *) <$> evens

main :: IO ()
main =
  mapM_
    (print . ((,) <*> luhn))
    [ "49927398716",
      "49927398717",
      "1234567812345678",
      "1234567812345670"
    ]
Output:
("49927398716",True)
("49927398717",False)
("1234567812345678",False)
("1234567812345670",True)

HicEst

CHARACTER numbers="49927398716 49927398717 1234567812345678 1234567812345670 "

DO nr = 1, 4
   EDIT(Text=numbers, ITeM=nr, Parse=number)
   sum_odds = 0
   sum_even = 0
   DO i = LEN(number), 1, -2
      sum_odds = sum_odds + ICHAR(number(i)) - 48
      IF(i > 1) THEN
         even2 = 2 * (ICHAR(number(i-1)) - 48)
         sum_even = sum_even + MOD(even2, 10) + INT(even2/10)
      ENDIF
   ENDDO
   valid = (0 == MOD(sum_odds + sum_even, 10))
   WRITE() number, " is ", "invalid"(1 + 2*valid:)
ENDDO
49927398716 is valid
49927398717 is invalid
1234567812345678 is invalid
1234567812345670 is valid

Icon and Unicon

We use map to pre-compute the sum of doubled digits.

procedure main(aL)
every write(i := !aL ," - ", ((\isluhn10(i),"valid")|"invalid") \ 1)
end

procedure isluhn10(i)  #: isluhn10(i) returns i (if i passes luhn10) or fails 
local sum

sum :=0
reverse(integer(i)) ? while not pos(0) do {  
      sum +:= move(1)
      sum +:= map(move(1),"0123456789","0246813579")  
   }

return (sum % 10 = 0,i)
end
Output:
# luhn10 49927398716 49927398717 1234567812345678 1234567812345670

49927398716 - valid
49927398717 - invalid
1234567812345678 - invalid
1234567812345670 - valid

J

We can treat the odd digits the same as even digits, except that they are not doubled. Also, we do not need the intermediate sums.

luhn=: 0 = 10 (| +/@,) 10 #.inv 1 2 *&|: _2 "."0\ |.

Example use:

   luhn&> '49927398716';'49927398717';'1234567812345678';'1234567812345670'
1 0 0 1

Interpreting that example: In J, 1 is true, 0 is false, so the first and last provided digit sequences were valid and the middle two were not.

Java

public class Luhn {
    public static void main(String[] args) {
        System.out.println(luhnTest("49927398716"));
        System.out.println(luhnTest("49927398717"));
        System.out.println(luhnTest("1234567812345678"));
        System.out.println(luhnTest("1234567812345670"));
    }
    
    public static boolean luhnTest(String number){
        int s1 = 0, s2 = 0;
        String reverse = new StringBuffer(number).reverse().toString();
        for(int i = 0 ;i < reverse.length();i++){
            int digit = Character.digit(reverse.charAt(i), 10);
            if(i % 2 == 0){//this is for odd digits, they are 1-indexed in the algorithm
                s1 += digit;
            }else{//add 2 * digit for 0-4, add 2 * digit - 9 for 5-9
                s2 += 2 * digit;
                if(digit >= 5){
                    s2 -= 9;
                }
            }
        }
        return (s1 + s2) % 10 == 0;
    }
}
Output:
true
false
false
true

Java Long type version

public class Luhn {
  public static void main(String[] args) {
    System.out.println(luhnTest(49927398716L));
    System.out.println(luhnTest(499273987163L));
    System.out.println(luhnTest(1234567L));
    System.out.println(luhnTest(0L));
  }

  public static boolean luhnTest(Long digits) {
    int s1 = 0, s2 = 0;
    //Use an alternator for separate odd/even processing
    boolean alternator = true;

    //Confine digit numbers to 8 - 19 per ISO
    if (digits < 1e7 || digits >= 1e19) return false;

    for ( int i = 0; digits > 0; ++i) {
      Long oneDigit = digits % 10;

      if (alternator) {
        s1 += oneDigit.intValue();
      } else {
        oneDigit *= 2;
        s2 += oneDigit > 9 ? oneDigit.intValue() - 9: oneDigit.intValue();
      }
      digits /= 10;
      alternator = !alternator;
    }
    return (s1 + s2) % 10 == 0 ? true : false;
  }
}
Output:
true
false
false
false

JavaScript

Using prototype.

mod10check = function(cc) {
  return $A(cc).reverse().map(Number).inject(0, function(s, d, i) {
    return s + (i % 2 == 1 ? (d == 9 ? 9 : (d * 2) % 9) : d);
  }) % 10 == 0;
};
['49927398716','49927398717','1234567812345678','1234567812345670'].each(function(i){alert(mod10check(i))});

Without any library.

var LuhnCheck = (function()
{
	var luhnArr = [0, 2, 4, 6, 8, 1, 3, 5, 7, 9];
	return function(str)
	{
		var counter = 0;
		var incNum;
		var odd = false;
		var temp = String(str).replace(/[^\d]/g, "");
		if ( temp.length == 0)
			return false;
		for (var i = temp.length-1; i >= 0; --i)
		{
			incNum = parseInt(temp.charAt(i), 10);
			counter += (odd = !odd)? incNum : luhnArr[incNum];
		}
		return (counter%10 == 0);
	}
})();

Highly compressed version.

var luhn10 = function(a,b,c,d,e) {
  for(d = +a[b = a.length-1], e=0; b--;)
    c = +a[b], d += ++e % 2 ? 2 * c % 10 + (c > 4) : c;
  return !(d%10)
};

// returns true
luhn10('4111111111111111') 

// returns false
luhn10('4111111111111112')

Naive implementation

const lunhCheck = (str) => {
    const sumDigit = (c) => (c < 10) ? c :
              sumDigit( Math.trunc(c / 10) + (c % 10));
    
    return str.split('').reverse()
              .map(Number)
              .map((c, i) => i % 2 !== 0 ? sumDigit(c * 2) : c)
              .reduce((acc,v) => acc + v) % 10 === 0;
};

lunhCheck('49927398716'); // returns true
lunhCheck('49927398717'); // returns false
lunhCheck('1234567812345678'); // returns false
lunhCheck('1234567812345670'); // returns true

jq

Works with: jq version 1.4 or later

Works with gojq, the Go implementation of jq

For the specific task defined here, both jq (version 1.4 or later) and gojq should suffice, but for very large integers (greater than 2^53), either gojq or a version of the C implementation of jq with support for very large external integers would be required.

def luhn:
  def odds: . as $in | reduce range(0; length) as $i
    ([]; if ($i % 2) == 0 then . + [$in[$i]] else . end);
  def evens: . as $in | reduce range(1; length) as $i
    ([]; if ($i % 2) == 1 then . + [$in[$i]] else . end);
  def digits: map([.]|implode|tonumber);
  def sumdigits: tostring | explode | digits | add;

  (tostring | explode | reverse ) as $reverse
  | ($reverse | odds  | digits | add) as $s1
  | ($reverse | evens | digits | map(. * 2 | sumdigits) | add) as $s2
  | 0 == ($s1 + $s2) % 10 ;

Example

  ( 49927398716,
    49927398717,
    1234567812345678,
    1234567812345670
  ) | "\(.) => \(luhn)";
Output:
$ jq -r -M -n -f luhn.jq
49927398716 => true
49927398717 => false
1234567812345678 => false
1234567812345670 => true

Julia

The test function itself is only a single line of code:

luhntest(x::Integer) = (sum(digits(x)[1:2:end]) + sum(map(x -> sum(digits(x)), 2 * digits(x)[2:2:end]))) % 10 == 0

More readable version:

function luhntest(x::Integer)
    d = reverse(digits(x))
    s = sum(d[1:2:end])
    s += sum(sum.(digits.(2d[2:2:end])))
    return s % 10 == 0
end

for card in [49927398716, 49927398717, 1234567812345678, 1234567812345670]
    println(luhntest(card) ? "PASS " : "FAIL ", card)
end
Output:
PASS 49927398716
FAIL 49927398717
FAIL 1234567812345678
PASS 1234567812345670

K

so: {+/x@2*!_ceil(#x)%2}
se: {+/{+/0$'$x}'2*x@1+2*!(#x)%2}
luhn: {n:|0$'$x; 0=((se n)+so n)!10}
Translation of: J
luhn2: {~(+/,//10_vs'1 2*+-1 2#((#n)!2){x,0}/n:0$'|$x)

Example:

  luhn'49927398716 49927398717 1234567812345678 1234567812345670
1 0 0 1
  luhn2'49927398716 49927398717 1234567812345678 1234567812345670
1 0 0 1
Works with: K version 3
luhn:{[cc]
    digits:0$/:|cc / convert chars to digit ints
    s:digits*(#cc)#1 2 / evens doubled, odds not
    nines:+/s>9 / number of sums greater than 9
    :~((+/s)-(9*nines))!10 / sum minus the nines is mod ten?
    }

Example:

  test:("49927398716";"49927398717";"1234567812345678";"1234567812345670")
  luhn'test
1 0 0 1

Kotlin

// version 1.0

fun checkLuhn(number: String): Boolean {
    var isOdd = true
    var sum = 0

    for (index in number.indices.reversed()) {
        val digit = number[index] - '0'
        sum += if (isOdd) digit else (digit * 2).let { (it / 10) + (it % 10) }
        isOdd = !isOdd
    }

    return (sum % 10) == 0
}

fun main(args: Array<String>) {
    val numbers = arrayOf("49927398716", "49927398717", "1234567812345678", "1234567812345670")
    for (number in numbers)
        println("${number.padEnd(16)} is ${if(checkLuhn(number)) "valid" else "invalid"}")
}
Output:
49927398716      is valid
49927398717      is invalid
1234567812345678 is invalid
1234567812345670 is valid

langur

Translation of: Go
val luhntest = fn(s) {
    val t = [0, 2, 4, 6, 8, 1, 3, 5, 7, 9]
    val numbers = s -> s2n
    val oddeven = len(numbers) rem 2

    for[=0] i of numbers {
        _for += if(i rem 2 == oddeven: numbers[i]; t[numbers[i]+1])
    } div 10
}

val tests = {
    "49927398716": true,
    "49927398717": false,
    "1234567812345678": false,
    "1234567812345670": true,
}

for key in sort(keys(tests)) {
    val pass = luhntest(key)
    write key, ": ", pass
    writeln if(pass == tests[key]: ""; " (LUHN TEST FAILED)")
}
Output:
49927398717: false
49927398716: true
1234567812345678: false
1234567812345670: true

Lasso

Part of the Lasso's implementation of "valid_creditcard".

#!/usr/bin/lasso9

define luhn_check(number) => {
  local(
    rev = #number->asString,
    checksum = 0
  )
  #rev->reverse
  iterate(#rev, local(digit)) => {
    if((loop_count % 2) == 0) => {
      #checksum += (2 * integer(#digit))
      integer(#digit) >= 5 ? #checksum -= 9
    else
      #checksum += integer(#digit)
    }
  }
  (#checksum % 10) != 0 ? return false
  return true
}

stdoutnl(luhn_check(49927398716))       // true
stdoutnl(luhn_check(49927398717))       // false
stdoutnl(luhn_check(1234567812345678))  // false
stdoutnl(luhn_check(1234567812345670))  // true

Liberty BASIC

' [RC] Luhn test

card$(1)="49927398716"
card$(2)="49927398717"
card$(3)="1234567812345678"
card$(4)="1234567812345670"

for test = 1 to 4
    odd=1
    sum = 0
    for n = len(card$(test)) to 1 step -1
        num=val(mid$(card$(test),n,1))
        if odd then
            sum = sum + num
            odd=0
        else
            num=num*2
            if num<=9 then
                sum = sum + num
            else
                sum = sum + val(left$(str$(num),1)) + val(right$(str$(num),1))
            end if
            odd=1
        end if
    next
    if sum mod 10 = 0 then
        print card$(test),"True"
    else
        print card$(test),"False"
    end if
next

LiveCode

function LuhnTest cc
    local s1,evens, s2
    repeat with n = 1 to len(cc)
        if n mod 2 is not 0 then
            add (char -n of cc) to s1
        else
            put (char -n of cc) * 2 into evens
            if evens > 9 then subtract 9 from evens
            add evens to s2
        end if
    end repeat
    return the last char of (s1 + s2) is 0
end LuhnTest

-- test
repeat for each item ccno in "49927398716,49927398717,1234567812345678,1234567812345670"
    put ccno && LuhnTest(ccno) & cr after luhncheck
end repeat
put luhncheck

49927398716 true
49927398717 false
1234567812345678 false
1234567812345670 true

to small? :list
  output or [empty? :list] [empty? bf :list]
end
to every.other :list
  if small? :list [output :list]
  output fput first :list every.other bf bf :list
end
to wordtolist :word
  output map.se [?] :word
end

to double.digit :digit
  output item :digit {0 2 4 6 8 1 3 5 7 9}@0
  ; output ifelse :digit < 5 [2*:digit] [1 + modulo 2*:digit 10]
end

to luhn :credit
  localmake "digits reverse filter [number? ?] wordtolist :credit
  localmake "s1 apply "sum every.other :digits
  localmake "s2 apply "sum map "double.digit every.other bf :digits
  output equal? 0 last sum :s1 :s2
end

show luhn "49927398716          ; true
show luhn "49927398717          ; false
show luhn "1234-5678-1234-5678  ; false
show luhn "1234-5678-1234-5670  ; true

Lua

function luhn_test(cc_number)
   assert(type(cc_number) == 'string')
   local sum = 0
   local is_odd = true
   for idx = #cc_number , 1 , -1 do  -- reverse order
      -- extract single character as string then convert to integer
      local digit = cc_number:sub(idx, idx) + 0
      if is_odd then
         sum = sum + digit
      else
         sum = sum + ((digit * 2) % 10) + (digit // 5)
      end  -- if
      is_odd = not is_odd  -- toggle between odd and even
   end  -- for
   return (sum % 10) == 0
end  -- function luhn_test

for _, val in ipairs{"49927398716", "49927398717", "1234567812345678", "1234567812345670"} do
   print(val, luhn_test(val))
end  -- for

M2000 Interpreter

Translation of: FreeBASIC
Module Checkit {
      Function luhntest(cardnr$) {
       
            cardnr$ = Trim$(cardnr$) ' we don't want spaces
            if len(cardnr$)=0 then exit
            Dim Base 0,  reverse_nr$(Len(cardnr$))
            Def integer  i, j, s1, s2, l , l2
            Let l=Len(cardnr$)-1, l2=l+1
               
            ' reverse string
            For i = 0 To l
                reverse_nr$(i) = mid$(cardnr$,l2-i,1)
            Next i
            ' sum odd numbers
            For i = 0 To l Step 2
                s1 = s1 + (Asc(reverse_nr$(i)) - Asc("0"))
            Next i
            ' sum even numbers
            For i = 1 To l Step 2
                j = Asc(reverse_nr$(i)) - Asc("0")
                j = j * 2
                If j > 9 Then j = j Mod 10 + 1
                s2 = s2 + j
            Next i
               
            If (s1 + s2) Mod 10 = 0 Then
                = 1=1
            Else
                = 1=0
            End If       
      }
      Flush
      Data "49927398716",  "49927398717", "1234567812345678", "1234567812345670"
      while not empty
            over
            print letter$;" = ";luhntest(letter$)
      end while
}
Checkit
Output:
49927398716 = True
49927398717 = False
1234567812345678 = False
1234567812345670 = True

MACRO-11

        .TITLE  LUHN
        .MCALL  .GTLIN,.PRINT,.EXIT
LUHN::  .GTLIN  #5$
        MOV     #5$,R0
        TSTB    (R0)
        BEQ     2$
        JSR     PC,TEST
        BNE     1$ 
        .PRINT  #3$
        BR      LUHN
1$:     .PRINT  #4$
        BR      LUHN
2$:     .EXIT
3$:     .ASCIZ  /PASS/
4$:     .ASCIZ  /FAIL/
5$:     .BLKB   200
        .EVEN 
        
TEST:   MOV     R0,R1
        CLR     R2
1$:     TSTB    (R0)+
        BNE     1$
        DEC     R0
2$:     MOVB    -(R0),R3
        SUB     #60,R3
        ADD     R3,R2
        CMP     R0,R1
        BLOS    3$
        MOVB    -(R0),R3
        SUB     #60,R3
        MOVB    4$(R3),R3
        ADD     R3,R2
        CMP     R0,R1
        BHI     2$
3$:     SUB     #12,R2
        BHI     3$
        RTS     PC
4$:     .BYTE   ^D0,^D2,^D4,^D6,^D8
        .BYTE   ^D1,^D3,^D5,^D7,^D9
        .END    LUHN
Output:
.LUHN 49927398716
PASS

.LUHN 49927398717
FAIL

.LUHN 1234567812345678
FAIL

.LUHN 1234567812345670
PASS

Mathematica /Wolfram Language

LuhnQ[nb_] := (Mod[Total[(2*ToExpression[#[[2;;All;;2]]]) /. {z_?(Function[v, v>9]) -> z-9}]
       + Total[ToExpression[#[[1;;All;;2]]]], 10] == 0)& [Characters[StringReverse[ToString[nb]]] ]

LuhnQ /@ {49927398716, 49927398717, 1234567812345678, 1234567812345670}
->{True, False, False, True}

Alternate Code

Eliminates conversion of numbers to strings and back

LuhnQ[n_Integer] :=
 Block[{digits = Reverse@IntegerDigits@n},
  Mod[Total[{digits[[;; ;; 2]], 
      IntegerDigits[2 #] & /@ digits[[2 ;; ;; 2]]}, -1], 10] == 0]

LuhnQ /@ {49927398716, 49927398717, 1234567812345678, 1234567812345670}
Output:
{True,False,False,True}

MATLAB

The solution is basically the same as for Octave.

function passed = luhn(num)
if nargin == 0 % evaluate test cases
  testnum = [49927398716 49927398717 1234567812345678 1234567812345670];
  for num = testnum
    disp([int2str(num) ': ' int2str(luhn(num))])
  end
  return  
end
% luhn function starts here
d = int2str(num) - '0';	% convert number into vector of digits
m = [2:2:8,1:2:9];	% rule 3: maps 1:9 to [2 4 6 8 1 3 5 7 9]
passed = ~mod(sum(d(end:-2:1)) + sum(m(d(end-1:-2:1))), 10);  
end
Output:
49927398716: 1
49927398717: 0
1234567812345678: 0
1234567812345670: 1

min

Works with: min version 0.19.3
((dup 10 <) 'quote (((10 mod) (10 div)) cleave) 'cons linrec) :digits
((0 0) dip (pop 'succ dip over even?) partition ((pop pop) dip) dip) :evens/odds
((2 * digits sum) map sum) :evens-sum
(digits evens/odds ('evens-sum 'sum) => spread + 10 mod 0 ==) :luhn?

(49927398716 49927398717 1234567812345678 1234567812345670)
(dup print! " " print! luhn? puts!) foreach
Output:
49927398716 true
49927398717 false
1234567812345678 false
1234567812345670 true

MiniScript

isValid = function(s)
    sum = 0
    odd = true
    for i in range(s.len-1)
        d = val(s[i])
        sum = sum + d * (2 - odd)
        if not odd and d > 4 then sum = sum - 9
        odd = not odd
    end for
    return sum % 10 == 0
end function

test = function(s)
    if isValid(s) then print s + ": valid" else print s + ": invalid"
end function

test "49927398716"
test "49927398717"
test "1234567812345678"
test "1234567812345670"
Output:
49927398716: valid
49927398717: invalid
1234567812345678: invalid
1234567812345670: valid

MUMPS

LUHN(C)
 NEW ODD,EVEN,S
 SET S=$REVERSE(C)
 SET ODD=0 FOR I=1:2:$LENGTH(S) SET ODD=ODD+$EXTRACT(S,I)
 SET EVEN=0 FOR I=2:2:$LENGTH(S) SET T=$EXTRACT(S,I)*2 SET EVEN=EVEN+$SELECT(T<=9:T,T>9:$EXTRACT(T,1)+$EXTRACT(T,2))
 QUIT '((ODD+EVEN)#10)
USER>W !,$S($$LUHN^ROSETTA("49927398716")=0:"INVALID",1:"VALID")
 
VALID
USER>W !,$S($$LUHN^ROSETTA("49927398717")=0:"INVALID",1:"VALID")
 
INVALID
USER>W !,$S($$LUHN^ROSETTA("1234567812345678")=0:"INVALID",1:"VALID")
 
INVALID
USER>W !,$S($$LUHN^ROSETTA("1234567812345670")=0:"INVALID",1:"VALID")
 
VALID

Nanoquery

Translation of: Java
def reverse_str(string)
    to_return = ""

    for i in range(len(string) - 1, 0, -1)
        to_return += string[i]
    end for

    return to_return
end reverse_str

def luhnTest(number)
    s1 = 0; s2 = 0
    reversed = reverse_str(number)
    for i in range(0, len(reversed) - 1)
        digit = int(reversed[i])
        if (i % 2) = 0
            s1 += digit
        else
            s2 += 2 * digit
            if digit >= 5
                s2 -= 9
            end if
        end if
    end for

    return ((s1 + s2) % 10) = 0
end luhnTest

println luhnTest("49927398716")
println luhnTest("49927398717")
println luhnTest("1234567812345678")
println luhnTest("1234567812345670")
Output:
true
false
false
true

NetRexx

Translation of: REXX
class LuhnTest

  method main(args=String[]) static
    cc	  = 0 
    cc[1] = '49927398716'
    cc[2] = '49927398717'
    cc[3] = '1234567812345678'
    cc[4] = '1234567812345670'
 
    loop k=1 while cc[k] <> 0
      r = checksum(cc[k])
      if r==0 then say cc[k].right(20) 'passed'
      else say cc[k].right(20) 'failed'
    end
    
    -- Luhn algorithm checksum for credit card numbers
  method checksum(t) static
    if t.length()//2 then t = '0't  --pad # on left with 0
    t = t.reverse()
    s = 0
    loop j = 1 to t.length()-1 by 2
      q = 2*t.substr(j+1,1)
      if q>9 then q = q.left(1) + q.right(1)
      s= s+t.substr(j,1)+q
    end
    return s//10\==0

Nim

proc luhn(cc: string): bool =
  const m = [0, 2, 4, 6, 8, 1, 3, 5, 7, 9]
  var sum = 0
  var odd = true
  for i in countdown(cc.high, 0):
    let digit = ord(cc[i]) - ord('0')
    sum += (if odd: digit else: m[digit])
    odd = not odd
  result = sum mod 10 == 0
 
for cc in ["49927398716", "49927398717", "1234567812345678", "1234567812345670"]:
  echo cc, ' ', luhn(cc)
Output:
49927398716 true
49927398717 false
1234567812345678 false
1234567812345670 true

Objeck

bundle Default {
  class Luhn {
    function : IsValid(cc : String) ~ Bool {
      isOdd := true;
      oddSum := 0;
      evenSum := 0;
      
      for(i := cc->Size() - 1; i >= 0; i -= 1;) {
        digit : Int := cc->Get(i) - '0';
        if(isOdd) {
          oddSum += digit;
        } 
        else {
          evenSum += digit / 5 + (2 * digit) % 10;
        };
        isOdd := isOdd <> true;
      };
       
      return (oddSum + evenSum) % 10 = 0;
    }
    
    function : Main(args : String[]) ~ Nil {
      IsValid("49927398716")->PrintLine();
      IsValid("49927398717")->PrintLine();
      IsValid("1234567812345678")->PrintLine();
      IsValid("1234567812345670")->PrintLine();
    }
  }
}

Objective-C

- (NSArray *) toCharArray {
	
	NSMutableArray *characters = [[NSMutableArray alloc] initWithCapacity:[self length]];
	for (int i=0; i < [self length]; i++) {
		NSString *ichar  = [NSString stringWithFormat:@"%C", [self characterAtIndex:i]];
		[characters addObject:ichar];
	}
	
	return characters;
}

+ (BOOL) luhnCheck:(NSString *)stringToTest {
	
	NSArray *stringAsChars = [stringToTest toCharArray];
	
	BOOL isOdd = YES;
	int oddSum = 0;
	int evenSum = 0;
	
	for (int i = [stringToTest length] - 1; i >= 0; i--) {
		
		int digit = [(NSString *)stringAsChars[i] intValue];
		
		if (isOdd) 
			oddSum += digit;
		else 
			evenSum += digit/5 + (2*digit) % 10;
			
		isOdd = !isOdd;				 
	}
	
	return ((oddSum + evenSum) % 10 == 0);
}

BOOL test0 = [self luhnCheck:@"49927398716"]; //Result = YES
BOOL test1 = [self luhnCheck:@"49927398717"]; //Result = NO
BOOL test2 = [self luhnCheck:@"1234567812345678"]; //Result = NO				   
BOOL test3 = [self luhnCheck:@"1234567812345670"]; //Result = YES

OCaml

let luhn s =
  let rec g r c = function
  | 0 -> r
  | i ->
      let d = c * ((int_of_char s.[i-1]) - 48) in 
      g (r + (d/10) + (d mod 10)) (3-c) (i-1)
  in
  (g 0 1 (String.length s)) mod 10 = 0
;;
Output:
# List.map luhn [ "49927398716"; "49927398717"; "1234567812345678"; "1234567812345670" ];;
- : bool list = [true; false; false; true]

Octave

   function y = isluhn(s);
	if isnumeric(s) s = mat2str(s); end; 	% make sure s is a string
	d = s-'0';	% convert string into vector of digits
	m = [2:2:8,1:2:9];	% rule 3: maps [1:9] -> i
	y = ~mod(sum(d(end:-2:1)) + sum(m(d(end-1:-2:1))),10);
   end;
Output:
  isluhn('49927398716')
	ans =  1
  isluhn('49927398717')
	ans = 0
  isluhn('1234567812345678')
	ans = 0
  isluhn('1234567812345670')
	ans =  1

Oforth

: luhnTest(n)
| s i |
   n asString reverse ->s
   0 s size loop: i [ 
      i s at asDigit 
      i isEven ifTrue: [ 2 * dup 10 >= ifTrue: [ 9 - ] ] +
      ]
   10 mod ==0 ;
Output:
[ 49927398716, 49927398717, 1234567812345678, 1234567812345670 ] map(#luhnTest) println
[1, 0, 0, 1]

OpenEdge/Progress

FUNCTION fnLuhnAlgorithm RETURNS LOGICAL
  (INPUT pcNumber AS CHARACTER):
/*------------------------------------------------------------------------------
  Purpose:  Applies Luhn Algorithm to check a Number 
    Notes:  Returns True/False Validation based on check digit
------------------------------------------------------------------------------*/
    DEFINE VARIABLE cNum        AS CHARACTER NO-UNDO.
    DEFINE VARIABLE iCheck      AS INTEGER   NO-UNDO.
    DEFINE VARIABLE iLength     AS INTEGER   NO-UNDO.
    DEFINE VARIABLE iLoopCnt    AS INTEGER   NO-UNDO.
    DEFINE VARIABLE iNum        AS INTEGER   NO-UNDO.
    DEFINE VARIABLE iNum1       AS INTEGER   NO-UNDO.
    DEFINE VARIABLE iNum2       AS INTEGER   NO-UNDO.
    DEFINE VARIABLE iTestLength AS INTEGER   NO-UNDO.

    ASSIGN 
      iLength     = LENGTH(pcNumber)
      iTestLength = iLength - 1
        iCheck = 1. /* 1 for the check digit we skip */

    DO iLoopCnt = iTestLength TO 1 BY -1:
      ASSIGN 
          iNum = INTEGER(SUBSTR(pcNumber,iLoopCnt,1))
          iCheck = iCheck + 1.

      IF iCheck MODULO 2 = 1 THEN
          ASSIGN iNum1 = iNum1 + iNum.
      ELSE
      DO:
          ASSIGN iNum2 = iNum * 2.
          IF iNum2 < 10 THEN
              ASSIGN iNum1 = iNum1 + iNum2.
          ELSE
              ASSIGN
                cNum  = STRING(iNum2)
                iNum1 = iNum1 + INTEGER(SUBSTR(cNum,1,1)) + INTEGER(SUBSTR(cNum,2,1)).   
      END.
    END.

    ASSIGN 
        iNum2 = iNum1 * 9
        iNum = iNum2 MODULO 10.
    
    IF iNum = INTEGER(SUBSTR(pcNumber,iLength,1)) THEN
      RETURN TRUE.
    ELSE
      RETURN FALSE.

END FUNCTION. /* fnLuhnAlgorithm  */
Output:
49927398716      - yes
49927398717      - no
1234567812345678 - no
1234567812345670 - yes

Order

This example highlights Order's unusual treatment of numbers. Numbers larger than 100 are not recognized by the interpreter in literal form and must instead be entered as "native" numbers (i.e. listing the separate digits as arguments to 8nat). Since internally, a native number is just a sequence of the digits in reverse order with an end digit marker, converting the number into a reversed list of digits mainly involves removing this terminator, so that we can immediately treat the digits as number elements.

#include <order/interpreter.h>

#define ORDER_PP_DEF_8luhn ORDER_PP_FN( \
8fn(8N, 8if(8is_seq(8N), 8luhn_wk(8num_to_seq(8N)), 8false)) )

#define ORDER_PP_DEF_8num_to_seq ORDER_PP_FN( \
8fn(8N, 8seq_push_back(8seq(8seq_last(8N)), 8seq_pop_back(8N))) )

#define ORDER_PP_DEF_8luhn_wk ORDER_PP_FN(                      \
8fn(8N,                                                         \
    8lets((8P, 8unzip(8N, 8nil, 8nil, 8true))                   \
          (8O, 8seq_fold(8plus, 0, 8tuple_at_0(8P)))            \
          (8E, 8seq_fold(8plus, 0,                              \
                         8seq_map(8dig_map, 8tuple_at_1(8P)))), \
          8is_0(8remainder(8plus(8O, 8E), 10)))) )

#define ORDER_PP_DEF_8dig_map ORDER_PP_FN( \
8fn(8X, 8tuple_at(8X, 8tuple(0,2,4,6,8,1,3,5,7,9))) )

#define ORDER_PP_DEF_8unzip ORDER_PP_FN(                             \
8fn(8S, 8L, 8R, 8O,                                                  \
    8if(8is_nil(8S),                                                 \
        8pair(8L, 8R),                                               \
        8if(8O,                                                      \
            8unzip(8seq_tail(8S), 8seq_push_back(8seq_head(8S), 8L), \
                   8R, 8false),                                      \
            8unzip(8seq_tail(8S), 8L,                                \
                   8seq_push_back(8seq_head(8S), 8R), 8true)))) )

ORDER_PP(8seq_to_tuple(
  8seq_map(8luhn, 8seq(8nat(4,9,9,2,7,3,9,8,7,1,6),
                       8nat(4,9,9,2,7,3,9,8,7,1,7),
                       8nat(1,2,3,4,5,6,7,8,1,2,3,4,5,6,7,8),
                       8nat(1,2,3,4,5,6,7,8,1,2,3,4,5,6,7,0)))
))
Output:
(8true,8false,8false,8true)

Oz

declare
  fun {Luhn N}
     {Sum {List.mapInd {Reverse {Digits N}}
           fun {$ Idx Dig}
              if {IsEven Idx} then {Sum {Digits 2*Dig}}
              else Dig
              end
           end}}
     mod 10 == 0
  end

  fun {Digits N}
     {Map {Int.toString N} fun {$ D} D - &0 end}
  end

  fun {Sum Xs}
     {FoldL Xs Number.'+' 0}
  end
in
  {Show
   {Map
    [49927398716 49927398717 1234567812345678 1234567812345670]
    Luhn}}

Pascal

see also: Free Pascal

Works with: Extended Pascal

This implementation skips the reversal step and simply reads the input backwards.

program luhnTestOfCreditCardNumbers(input, output);

type
	{
		`string(…)` is an Extended Pascal, ISO 10206, extension.
		`string(64)` discriminates the “schema” data type `string`
		to contain at most 64 `char` values.
	}
	creditCardNumber = string(64);

{
	\brief determines whether a string contains digits only
	
	\param sample the string to inspect
	\return `false` iff `sample` contains non-digit characters
}
{ Extended Pascal: `protected` means the function cannot modify `sample` }
function containsDigitsOnly(protected sample: creditCardNumber): Boolean;
var
	{ EP: the `… value []` initializes this variable as an empty set }
	characters: set of char value [];
	{ `sample.capacity` refers to `64` in this code. }
	i: 1..sample.capacity;
begin
	for i := 1 to length(sample) do
	begin
		{ Union of sets indicated by `+`. }
		characters := characters + [sample[i]]
	end;
	
	{
		In a Pascal `function` definition,
		there must be one assignment to the (implicit) variable
		bearing the same name as of the function.
		This will be the return value.
	}
	{ NB: This will return `true` even if `length(sample)` is zero. }
	containsDigitsOnly := card(characters - ['0'..'9']) = 0
	{ `card` is an Extended Pascal extension. }
end;

{
	\brief determines whether a string complies with ISO/IEC 7812-1 Luhn test
	
	\param sample the potentially correct credit card number
	\return `true` if verification succeeds
}
function luhnCheck(protected sample: creditCardNumber): Boolean;
	{
		This _nested_ function is only accessible _within_ `luhnCheck`.
		Outsourcing this code allows us to write a neat expression below.
	}
	function check: Boolean;
	var
		{ Using `integer` sub-ranges ensures only these values are assigned. }
		sum: 0..maxInt value 0;
		i: 0..sample.capacity-1;
	begin
		for i := 0 to length(sample) - 1 do
		begin
			{ `1 + ord(odd(i))` produces an alternating scale factor `* 1`/`* 2`. }
			sum := sum + (1 + ord(odd(i))) *
				{ Obtain digit value for `integer` calculation. }
				(ord(sample[length(sample) - i]) - ord('0')) -
				{ Reverse operation if digit sum > 9, i.e. we added “too much”. }
				ord(odd(i) and (sample[length(sample) - i] >= '5')) * 9
		end;
		
		check := sum mod 10 = 0
	end;
begin
	{
		The Extended Pascal Boolean operator `and_then` (and `or_else`)
		allows for “short-circuit evaluation”.
		Otherwise, in Pascal `and` and `or` mandate complete evaluation.
	}
	luhnCheck := (length(sample) > 0) and_then containsDigitsOnly(sample)
		and_then check
end;

{ === MAIN ============================================================= }
var
	s: creditCardNumber;
begin
	{ `EOF` is short for `EOF(input)`. }
	while not EOF do
	begin
		readLn(s); { equivalent to `readLn(input, s)` }
		writeLn(luhnCheck(s)) { = `writeLn(output, …)` }
	end
end.
Input:
49927398716
49927398717
1234567812345678
1234567812345670
Output:
True
False
False
True

The shown output was generated by a program compiled with the GPC, the GNU Pascal Compiler. A different compiler may emit a different rendition of true and false, for example in all-caps.

Perl

sub luhn_test
{
        my @rev = reverse split //,$_[0];
        my ($sum1,$sum2,$i) = (0,0,0);

        for(my $i=0;$i<@rev;$i+=2)
        {
                $sum1 += $rev[$i];
                last if $i == $#rev;
                $sum2 += 2*$rev[$i+1]%10 + int(2*$rev[$i+1]/10);
        }
        return ($sum1+$sum2) % 10 == 0;
}
print luhn_test('49927398716');
print luhn_test('49927398717');
print luhn_test('1234567812345678');
print luhn_test('1234567812345670');

Or using map( ) and a precomputed array:

sub luhn {
    my (@n,$i,$sum) = split //, reverse $_[0];
    my @a = map {int(2*$_ / 10) + (2*$_ % 10)} (0..9);
    map {$sum += $i++ % 2 ? $a[$_] : $_} @n;
    return ($sum % 10) ? 0 : 1;
}

# Test and display
map {print luhn($_), ": $_\n"}
    qw(49927398716 49927398717 1234567812345678 1234567812345670);
Output:
1: 49927398716
0: 49927398717
0: 1234567812345678
1: 1234567812345670

Phix

with javascript_semantics
function Luhn(string st)
    integer s=0, d
    for i=1 to length(st) do
        d = st[-i]-'0'
        s += iff(mod(i,2)?d,d*2-(d>4)*9)
    end for
    return remainder(s,10)=0
end function
 
procedure test(string s)
    printf(1,"%20s : %t\n",{s,Luhn(s)})
end procedure
 
papply({"49927398716","49927398717","1234567812345678","1234567812345670"},test)
Output:
         49927398716 : true
         49927398717 : false
    1234567812345678 : false
    1234567812345670 : true

PHP

Translation of: C
$numbers = "49927398716 49927398717 1234567812345678 1234567812345670";
foreach (split(' ', $numbers) as $n)
    echo "$n is ", luhnTest($n) ? 'valid' : 'not valid', '</br>';

function luhnTest($num) {
    $len = strlen($num);
    for ($i = $len-1; $i >= 0; $i--) {
        $ord = ord($num[$i]);
        if (($len - 1) & $i) {
            $sum += $ord;
        } else {
            $sum += $ord / 5 + (2 * $ord) % 10;
        }
    }       
    return $sum % 10 == 0;
}
Output:
49927398716 is valid
49927398717 is not valid
1234567812345678 is not valid
1234567812345670 is valid

And a more concise example using PHP core methods:

function luhn_test($num) {
    $str = '';
    foreach( array_reverse( str_split( $num ) ) as $i => $c ) $str .= ($i % 2 ? $c * 2 : $c );
    return array_sum( str_split($str) ) % 10 == 0;
}

foreach (array('49927398716','49927398717','1234567812345678','1234567812345670') as $n)
    echo "$n is ", luhn_test($n) ? 'valid' : 'not valid', "</br>\n";
Output:
49927398716 is valid
49927398717 is not valid
1234567812345678 is not valid
1234567812345670 is valid

Picat

go => 
   Nums = ["49927398716","49927398717","1234567812345678","1234567812345670"],
   foreach (N in Nums) 
      println([N, isluhn10(N)])
   end,
   nl.

%
% isluhn10(num) returns 1 is valid, else 0
%
% Assumption: input num is a string.
%
isluhn10(Num) = V =>
  X = [I : I in Num.reverse()] ++ [""],
  Digits = "0246813579",
  M = new_map([(I.to_string()=Digits[I+1]) : I in 0..9]),
  V1 = sum([X[I].to_integer() + M.get2(X[I+1].to_string(),0) : I in 1..2..Num.length]),
  V := cond(V1 mod 10 == 0, 1, 0). 

% A variant of Map.get with conversions
get2(M, Key, Default)=V =>
   if M.has_key(Key) then V= M.get(Key).to_integer() else V=Default end.
Output:
[49927398716,1]
[49927398717,0]
[1234567812345678,0]
[1234567812345670,1]

PicoLisp

(de luhn (Num)  # 'Num' may be a number or a string
   (=0
      (%
         (sum
            '((C F)
               (setq C (- (char C) 48))
               (if F
                  C                               # Odd
                  (+ (/ C 5) (% (* 2 C) 10)) ) )  # Even
            (flip (chop Num))
            '(T NIL .) )
         10 ) ) )
Output:
: (mapcar luhn (49927398716 49927398717 1234567812345678 1234567812345670))
-> (0 NIL NIL 0)

PL/I

test: procedure options (main);

   declare (cardnumber, rcn) character (20) varying;
   declare (i, k, s1, s2) fixed binary;

   get edit (cardnumber) (L);
   cardnumber = trim(cardnumber);
   rcn = reverse(cardnumber);
   s1, s2 = 0;
   /* Sum the odd-numbered digits */
   do i = 1 to length(rcn) by 2;
      s1 = s1 + substr(rcn, i, 1);
   end;
   /* Twice the even-numbered digits. */
   do i = 2 to length(rcn) by 2;
      k = 2 * substr(rcn, i, 1);
      s2 = s2 + mod(k,10) + trunc(k/10);
   end;
   if mod(s1 + s2, 10) = 0 then
      put skip edit (cardnumber, ' passes the Luhn test' )(a);
   else
      put skip edit (cardnumber, ' does not pass the Luhn test' )(a);
   put skip list (s1 + s2);
end test;
Output:
49927398716 passes the Luhn test
       70 
49927398717 does not pass the Luhn test
       71 
1234567812345678 does not pass the Luhn test
       68 
1234567812345670 passes the Luhn test
       60

Comment: it isn't necessary to reverse the string in order to perform the test.

PL/M

100H:
BDOS: PROCEDURE(F,A); DECLARE F BYTE, A ADDRESS; GO TO 5; END BDOS;
EXIT: PROCEDURE; GO TO 0; END EXIT;
PRINT: PROCEDURE(S); DECLARE S ADDRESS; CALL BDOS(9,S); END PRINT;

LUHN: PROCEDURE(NUM) BYTE;
    DECLARE MAP DATA (0, 2, 4, 6, 8, 1, 3, 5, 7, 9);
    DECLARE (START, NUM, MASK, TOTAL) ADDRESS;
    DECLARE (CHR BASED NUM, DGT) BYTE;
    START = NUM;
    
    DO WHILE CHR <> '$'; NUM = NUM + 1; END;
    MASK = NUM := NUM - 1;
    TOTAL = 0;
    DO WHILE NUM >= START;
        DGT = CHR - '0';
        IF NUM XOR MASK THEN DGT = MAP(DGT);
        TOTAL = TOTAL + DGT;
        NUM = NUM - 1;
    END;
    RETURN TOTAL MOD 10 = 0;
END LUHN;

DECLARE TEST (4) ADDRESS, I BYTE;
TEST(0) = .'49927398716$';
TEST(1) = .'49927398717$';
TEST(2) = .'1234567812345678$';
TEST(3) = .'1234567812345670$';

DO I=0 TO LAST(TEST);
    CALL PRINT(TEST(I));
    CALL PRINT(.': $');
    IF LUHN(TEST(I)) 
        THEN CALL PRINT(.'PASS$');
        ELSE CALL PRINT(.'FAIL$');
    CALL PRINT(.(13,10,'$'));
END;
CALL EXIT;
EOF
Output:
49927398716: PASS
49927398717: FAIL
1234567812345678: FAIL
1234567812345670: PASS

PL/SQL

FUNCTION algoLuhn ( p_numeroVerif VARCHAR2 )
    RETURN NUMBER
  IS
    i         NUMBER;
    v_NBi     SMALLINT;
    v_retour  SMALLINT;
    v_somme   NUMBER := 0;
    v_nbCar   NUMBER;
    
  BEGIN  
    v_nbCar := LENGTH(p_numeroVerif);    
    
    FOR i IN 1..v_nbCar
    LOOP
        v_NBi := TO_NUMBER(SUBSTR(p_numeroVerif,v_nbCar+1-i,1));
        
        v_somme := v_somme
                  + MOD(i,2)   * v_NBi
                  + MOD(i+1,2) * SIGN(-SIGN(v_Nbi-4)+1) * (2*v_NBi)
                  + MOD(i+1,2) * SIGN( SIGN(v_Nbi-5)+1) * (2*v_NBi-9);
     
    END LOOP;
        
    v_retour := SIGN(MOD(v_somme,10));
    
    RETURN v_retour;
  
  EXCEPTION
    WHEN OTHERS
      THEN
        RETURN 1;
        
  END algoLuhn;

Plain English

To run:
Start up.
Test whether "49927398716" will pass the luhn test.
Test whether "49927398717" will pass the luhn test.
Test whether "1234567812345678" will pass the luhn test.
Test whether "1234567812345670" will pass the luhn test.
Wait for the escape key.
Shut down.

To test whether a string will pass the luhn test:
Write the string then ": " on the console without advancing.
If the string will pass the luhn test, write "valid" on the console; exit.
Write "invalid" on the console.

A sum is a number.

To decide if a string will pass the luhn test:
If the string is blank, say no.
Privatize the string.
Reverse the string.
Put 0 into a first sum.
Put 0 into a second sum.
Put 1 into a count.
Slap a rider on the string.
Loop.
If the rider's source is blank, break.
Put the rider's source's first's target into a byte.
If the byte is not any digit, say no.
Convert the byte to a number.
If the count is odd, add the number to the first sum; bump the count; bump the rider; repeat.
Double the number.
If the number is greater than 9, digital root the number.
Add the number to the second sum.
Bump the count. Bump the rider.
Repeat.
If the first sum plus the second sum is evenly divisible by 10, say yes.
Say no.

To digital root a number:
Divide the number by 10 giving a quotient and a remainder.
Put the quotient plus the remainder into the number.

To convert a byte to a number:
If the byte is any digit, put the byte minus 48 into the number.
Output:
49927398716: valid
49927398717: invalid
1234567812345678: invalid
1234567812345670: valid

PowerBASIC

Translation of: Visual Basic
#COMPILE EXE
#DIM ALL
#COMPILER PBCC 6

FUNCTION LuhnCheckPassed(BYVAL dgts AS STRING) AS INTEGER
LOCAL i, s, s1 AS DWORD
  dgts = STRREVERSE$(dgts)
    FOR i = 1 TO LEN(dgts) STEP 2
        s += VAL(MID$(dgts, i, 1))
    NEXT i
    FOR i = 2 TO LEN(dgts) STEP 2
        s1 = 2 * VAL(MID$(dgts, i, 1))
        IF s1 >= 10 THEN
            s -= 9
        END IF
        s += s1
    NEXT i
  FUNCTION = NOT ISTRUE (s MOD 10)
END FUNCTION

FUNCTION PBMAIN () AS LONG
  ' this test is expected to pass:
  CON.PRINT IIF$(LuhnCheckPassed("49927398716"), "passed", "failed")
  ' this test is expected to fail:
  CON.PRINT IIF$(LuhnCheckPassed("49927398717"), "passed", "failed")
  ' this test is expected to fail:
  CON.PRINT IIF$(LuhnCheckPassed("1234567812345678"), "passed", "failed")
  ' this test is expected to pass:
  CON.PRINT IIF$(LuhnCheckPassed("1234567812345670"), "passed", "failed")
END FUNCTION
Output:
passed
failed
failed
passed

PowerShell

function Test-LuhnNumber
{
  <#
    .SYNOPSIS
        Tests validity of credit card numbers.
    .DESCRIPTION
        Tests validity of credit card numbers using the Luhn test.
    .PARAMETER Number
        The number must be 11 or 16 digits.
    .EXAMPLE
        Test-LuhnNumber 49927398716
    .EXAMPLE
        [int64[]]$numbers = 49927398716, 49927398717, 1234567812345678, 1234567812345670
        C:\PS>$numbers | ForEach-Object {
                  "{0,-17}: {1}" -f $_,"$(if(Test-LuhnNumber $_) {'Is valid.'} else {'Is not valid.'})"
              }
  #>
    [CmdletBinding()]
    [OutputType([bool])]
    Param
    (
        [Parameter(Mandatory=$true,
                   Position=0)]
        [ValidateScript({$_.Length -eq 11 -or $_.Length -eq 16})]
        [ValidatePattern("^\d+$")]
        [string]
        $Number
    )

    $digits = ([Regex]::Matches($Number,'.','RightToLeft')).Value
    
    $digits |
        ForEach-Object `
               -Begin   {$i = 1} `
               -Process {if ($i++ % 2) {$_}} |
        ForEach-Object `
               -Begin   {$sumOdds = 0} `
               -Process {$sumOdds += [Char]::GetNumericValue($_)}
    $digits |
        ForEach-Object `
               -Begin   {$i = 0} `
               -Process {if ($i++ % 2) {$_}} |
        ForEach-Object `
               -Process {[Char]::GetNumericValue($_) * 2} |
        ForEach-Object `
               -Begin   {$sumEvens = 0} `
               -Process {
                            $_number = $_.ToString()
                            if ($_number.Length -eq 1)
                            {
                                $sumEvens += [Char]::GetNumericValue($_number)
                            }
                            elseif ($_number.Length -eq 2)
                            {
                                $sumEvens += [Char]::GetNumericValue($_number[0]) + [Char]::GetNumericValue($_number[1])
                            }
                        }

    ($sumOdds + $sumEvens).ToString()[-1] -eq "0"
}
Test-LuhnNumber 49927398716
Output:
True
49927398716, 49927398717, 1234567812345678, 1234567812345670 | ForEach-Object {
    "{0,-17}: {1}" -f $_,"$(if(Test-LuhnNumber $_) {'Is valid.'} else {'Is not valid.'})"
}
Output:
49927398716      : Is valid.
49927398717      : Is not valid.
1234567812345678 : Is not valid.
1234567812345670 : Is valid.

PureBasic

DataSection
  Sample:
  Data.s "49927398716"
  Data.s "49927398717"
  Data.s "1234567812345678"
  Data.s "1234567812345670"
  Data.s ""
EndDataSection

Procedure isValid(cardNumber.s)
  Protected i, length, s1, s2, s2a
  
  cardNumber = ReverseString(cardNumber)
  length = Len(cardNumber)
  For i = 1 To length Step 2
    s1 + Val(Mid(cardNumber, i, 1))
  Next 

  For i = 2 To length Step 2
    s2a = Val(Mid(cardNumber, i, 1)) * 2
    If s2a < 10
      s2 + s2a
    Else
      s2 + 1 + Val(Right(Str(s2a), 1))
    EndIf 
  Next 
  
  If Right(Str(s1 + s2), 1) = "0"
    ProcedureReturn #True
  Else
    ProcedureReturn #False
  EndIf 
EndProcedure


If OpenConsole()
  Define cardNumber.s
  
  Restore Sample
  Repeat 
    Read.s cardNumber
    If cardNumber <> ""
      Print(cardNumber + " is ")
      If isValid(cardNumber)
        PrintN("valid")
      Else
        PrintN("not valid")
      EndIf
    EndIf
  Until cardNumber = ""
  
  Print(#CRLF$ + #CRLF$ + "Press ENTER to exit")
  Input()
  CloseConsole()
EndIf
Output:
49927398716 is valid
49927398717 is not valid
1234567812345678 is not valid
1234567812345670 is valid

Python

Functional

The divmod in the function below conveniently splits a number into its two digits ready for summing:

>>> def luhn(n):
	r = [int(ch) for ch in str(n)][::-1]
	return (sum(r[0::2]) + sum(sum(divmod(d*2,10)) for d in r[1::2])) % 10 == 0

>>> for n in (49927398716, 49927398717, 1234567812345678, 1234567812345670):
	print(n, luhn(n))
Output:
49927398716 True
49927398717 False
1234567812345678 False
1234567812345670 True

Or, using itertools cycle with map and reduce:

Works with: Python version 3.7
'''Luhn test of credit card numbers'''

from operator import add, mul
from functools import reduce
from itertools import cycle


# luhn :: Integer -> Bool
def luhn(n):
    '''True if n is a valid Luhn credit card number.'''
    def divMod10Sum(a, x):
        return a + add(*divmod(x, 10))
    return 0 == reduce(
        divMod10Sum,
        map(
            mul,
            cycle([1, 2]),
            map(int, reversed(str(n)))
        ),
        0
    ) % 10


# ---------------------------TEST---------------------------
# main :: IO ()
def main():
    '''Tests'''
    print(list(
        map(luhn, [
            49927398716, 49927398717,
            1234567812345678, 1234567812345670
        ])
    ))


if __name__ == '__main__':
    main()
Output:
[True, False, False, True]

Or alternatively, we can prune out some of the imports, define the Luhn predicate over strings rather than integers,

and cycle lambdas rather than integers.

'''Luhn test of credit card numbers'''

from itertools import cycle


# luhn :: String -> Bool
def luhn(k):
    '''True if k is a valid Luhn credit card number string
    '''
    def asDigits(s):
        return (int(c) for c in s)

    return 0 == sum(map(
        lambda f, x: f(x),
        cycle([
            lambda n: n,
            lambda n: sum(asDigits(str(2 * n)))
        ]),
        asDigits(reversed(k))
    )) % 10


# ------------------------- TEST -------------------------
# main :: IO ()
def main():
    '''Tests'''
    print('\n'.join([
        repr((x, luhn(x))) for x in [
            "49927398716",
            "49927398717",
            "1234567812345678",
            "1234567812345670"
        ]
    ]))


if __name__ == '__main__':
    main()
Output:
('49927398716', True)
('49927398717', False)
('1234567812345678', False)
('1234567812345670', True)

Procedural

Without usingsum() and divmod() functions:

>>> def vérifLuhn(ch):
  sum = 0
  chParity = len(ch) % 2
  for i in range (len(ch)-1, -1, -1):
    j = int(ch[i])
    if ((i + 1) % 2 != chParity):
      j = j * 2 
    if (j > 9):
      j = j - 9 
    sum = sum + j
  print("value calculated = ", str(sum))
  return sum % 10 == 0         
   
for n in (49927398716, 49927398717, 1234567812345678, 1234567812345670):
        print (str(n)+" =>", vérifLuhn(str(n)))

Q

sd:{s:0; while[x<>0; s+:x mod 10; x:floor x%10]; s}    / Sum digits of x
luhn:{
    r:reverse string x;                             / Reversed credit card number
    o:("I"$) each r[2*til ceiling (count r) % 2];   / Odd-indexed numbers
    e:("I"$) each r[1+2*til floor (count r) % 2];   / Even-indexed numbers
    0=(sum o,sd each e*2) mod 10                    / Return 1b if checksum ends in 0; 0b otherwise
}
Output:
q)luhn each  49927398716 49927398717 1234567812345678 1234567812345670
1001b

Quackery

  [ 1 & ]               is odd        ( n --> b   )

  [ [] swap
    [ 10 /mod 
      rot join swap
      dup 0 = until ]
      drop ]            is digits     ( n --> [   )

  [ [] [] rot
    dup size odd dip
    [ witheach 
        [ nested join 
          swap ] ]
    not if swap ]       is unzip      ( [ --> [ [ )

  [ [] swap
    witheach
      [ 2 * 
        10 /mod + 
        join ] ]        is 2*digitsum ( [ --> [   )

  [ behead swap
    witheach + ]        is sum        ( [ --> n   )

  [ digits 
    reverse
    unzip
    2*digitsum
    sum 
    swap sum
    + 10 mod 0 = ]      is luhn       ( n --> b   )


' [ 49927398716      49927398717
    1234567812345678 1234567812345670 ]

witheach
  [ dup echo
    luhn iff
      [ say " valid" ]
    else
      [ say " invalid" ]
    cr ]
Output:
49927398716 valid
49927398717 invalid
1234567812345678 invalid
1234567812345670 valid

R

 
is.luhn <- function(cc){
  numbers <- as.numeric(rev(unlist(strsplit(cc,""))))
  (sum(numbers[seq(1,length(numbers),by=2)]) + sum({numbers[seq(2,length(numbers),by=2)]*2 ->.;  .%%10 +.%/%10})) %% 10 == 0
}
  
sapply(c("49927398716","49927398717","1234567812345678","1234567812345670"),is.luhn)
Output:
sapply(c("49927398716","49927398717","1234567812345678","1234567812345670"),is.luhn)
     49927398716      49927398717 1234567812345678 1234567812345670 
            TRUE            FALSE            FALSE             TRUE 

Racket

#lang racket

(define (luhn-test n)
  (let loop ([n n] [odd? #t] [s 0])
    (if (zero? n)
      (zero? (modulo s 10))
      (let*-values ([(q r)   (quotient/remainder n 10)]
                    [(rq rr) (quotient/remainder (* (if odd? 1 2) r) 10)])
        (loop q (not odd?) (+ s rq rr))))))

(map luhn-test '(49927398716 49927398717 1234567812345678 1234567812345670))
;; -> '(#t #f #f #t)

Raku

(formerly Perl 6)

Works with: rakudo version 2015-11-29

Here we make use of comb, which splits into individual characters, and the sequence operator ..., which can intuit an even or odd sequence from the first two values. %% is the divisible-by operator.

sub luhn-test ($number --> Bool) {
    my @digits = $number.comb.reverse;
    my $sum = @digits[0,2...*].sum
            + @digits[1,3...*].map({ |($_ * 2).comb }).sum;
    return $sum %% 10;
}

# And we can test it like this:

use Test;

my @cc-numbers =
    '49927398716'       => True,
    '49927398717'       => False,
    '1234567812345678'  => False,
    '1234567812345670'  => True;

plan @cc-numbers.elems;

for @cc-numbers».kv -> ($cc, $expected-result) {
    is luhn-test(+$cc), $expected-result,
        "$cc {$expected-result ?? 'passes' !! 'does not pass'} the Luhn test.";
}
Output:
1..4
ok 1 - 49927398716 passes the Luhn test.
ok 2 - 49927398717 does not pass the Luhn test.
ok 3 - 1234567812345678 does not pass the Luhn test.
ok 4 - 1234567812345670 passes the Luhn test.

Refal

$ENTRY Go {
    = <Test '49927398716'>
      <Test '49927398717'>
      <Test '1234567812345678'>
      <Test '1234567812345670'>;
};

Test {
    e.Digits = <Prout e.Digits ': ' <Luhn e.Digits>>;
};

Luhn {
    (s.Sum) e.Digits s.Even s.Odd,
        <Mul 2 <Numb s.Even>>: s.Even2,
        <Divmod s.Even2 10>: (s.EvenD1) s.EvenD2,
        <+ s.EvenD1 s.EvenD2>: s.EvenV,
        <+ <Numb s.Odd> s.EvenV>: s.Step
        = <Luhn (<+ s.Sum s.Step>) e.Digits>;
    (s.Sum) s.Odd = <Luhn (<+ s.Sum <Numb s.Odd>>)>;
    (s.Sum), <Divmod s.Sum 10>: (s.Rest) s.Last,
        s.Last: {
            0 = Valid;
            s.X = Invalid;
    };
    e.Digits = <Luhn (0) e.Digits>;
};
Output:
49927398716: Valid
49927398717: Invalid
1234567812345678: Invalid
1234567812345670: Valid

REXX

version 1

/*REXX program  validates  credit card numbers  using  the    Luhn    algorithm.        */
#.=;                #.1= 49927398716             /*the  1st  sample credit card number. */
                    #.2= 49927398717             /* "   2nd     "      "     "     "    */
                    #.3= 1234567812345678        /* "   3rd     "      "     "     "    */
                    #.4= 1234567812345670        /* "   4th     "      "     "     "    */
      do k=1  while #.k\==''                     /*validate all the credit card numbers.*/
      say right( Luhn(#.k), 9)          ' the Luhn test, credit card number: '    #.k
      end   /*k*/                                /* [↑] function returns passed│flunked.*/
exit                                             /*stick a fork in it,  we're all done. */
/*──────────────────────────────────────────────────────────────────────────────────────*/
Luhn: procedure;  parse arg x;              $= 0 /*get credit card number;  zero $ sum. */
      y= reverse( left(0, length(x) // 2)x)      /*add leading zero if needed, reverse. */
              do j=1  to length(y)-1  by 2;                _= substr(y, j+1, 1) * 2
              $= $ + substr(y, j, 1) + left(_, 1) + substr(_, 2, 1, 0)     /* ◄────────┐*/
              end   /*j*/                       /*sum odd and even decimal digits ►────┘*/
      return word('passed flunked',1+($//10==0)) /*$ ending in zero?  Then the # passed.*/
output   when using the (internal) default inputs:
  flunked  the Luhn test, credit card number:  49927398716
   passed  the Luhn test, credit card number:  49927398717
   passed  the Luhn test, credit card number:  1234567812345678
  flunked  the Luhn test, credit card number:  1234567812345670

Version 2

/* Rexx ***************************************************
* 09.04.2013 Walter Pachl
* Implements the task's description in a rather concise way
* Instead of reverting the ccn work it backwards
**********************************************************/
numeric digits 20

push 49927398716
push 49927398717
push 1234567812345678
push 1234567812345670

do while queued() > 0
  parse pull ccnum
  if luhn(ccnum) then ln = 'passed'
  else                ln = 'failed'
  say right(ccnum, 20) ln
  end
return
exit

luhn:
Parse Arg ccn                /* credit card number       */
sum=0                        /* initialize test sum      */
even=0                       /* even indicator           */
Do i=length(ccn) To 1 By -1  /* process all digits       */
  c=substr(ccn,i,1)          /* pick one digit at a time */
  If even Then Do            /* even numbered digit      */
    c=c*2                    /* double it                */
    If c>=10 Then            /* 10, 12, 14, 16, 18       */
      c=c-9                  /* Sum of the two digits    */
    End                      /* end of even numbered     */
  even=\even                 /* flip even indicator      */
  sum=sum+c                  /* add into test sum        */
  End
Return right(sum,1)=0        /* ok if last digit is 0    */
Output:
    1234567812345670 passed
    1234567812345678 failed
         49927398717 failed
         49927398716 passed

Ring

decimals(0)

test = ["49927398716", "49927398717", "1234567812345678", "1234567812345670"]
for n = 1 to len(test)
      see test[n] + " -> " + cardtest(test[n]) + nl
next

func cardtest(numstr)
        revstring = revstr(numstr)
        s1 = revodd(revstring)
        s2 = reveven(revstring)
        s3 =right(string(s1+s2), 1)
        if s3 = "0"
           return "Valid"
        else
           return "Invalid"
        ok

func revstr(str)
      strnew = ""
      for nr = len(str) to 1 step -1
           strnew = strnew + str[nr]
      next
      return strnew

func revodd(str)
        strnew = ""
        for nr = 1 to len(str) step 2
             strnew = strnew + str[nr]
        next
        sumodd = 0
        for p = 1 to len(strnew)
              sumodd = sumodd + number(strnew[p])
        next     
        return sumodd

func reveven(str)
        strnew = ""
        for nr = 2 to len(str) step 2
             strnew = strnew + str[nr]
        next
        lsteven = []
        for p = 1 to len(strnew)
             add(lsteven, string(2*number(strnew[p])))
        next  
        arreven = list(len(lsteven))
        for q = 1 to len(lsteven)
              sum = 0
              for w = 1 to len(lsteven[q])
                    sum = sum + lsteven[q][w]
              next
              arreven[q] = sum
        next
        sumarr = 0
        for x = 1 to len(arreven)
             sumarr = sumarr + arreven[x]
        next
        return sumarr

Output:

49927398716 -> Valid
49927398717 -> Invalid
1234567812345678 -> Invalid
1234567812345670 -> Valid

RPL

Card numbers shall be entered as strings to avoid any rounding error when testing long ones.

Works with: RPL version HP48-C
RPL code Comment
 « 0 → card even 
  « 0
    card SIZE 1 FOR j
       card j DUP SUB OBJ→
       IF even THEN 
          DUP + 10 MOD LASTARG / IP + END
       + 1 'even' STO-
   -1 STEP
 10 MOD NOT
» » 'LUHN?' STO
LUHN? ( "card_number" -- boolean ) 
sum = 0
loop for j=n to 1
   digit = card[j]
   if even digit
      multiply it by 2 and add digits
   sum += digit ; reverse parity flag

return not(sum mod 10)

{ "49927398716" "49927398717" "1234567812345678" "1234567812345670" } 1 « LUHN? » DOLIST
Output:
1: { 1 0 0 1 }

Ruby

 def luhn_valid?(str)
   str.scan(/\d/).reverse            #using str.to_i.digits fails for cases with leading zeros
      .each_slice(2)
      .sum { |i, k = 0| i.to_i + ((k.to_i)*2).digits.sum }
      .modulo(10).zero?
 end

["49927398716", "49927398717", "1234567812345678", "1234567812345670"].map{ |i| luhn_valid?(i) }
Output:
[true, false, false, true]

Simpler Alternative

def luhn_valid?(n)  # Card values can be numbers or strings
  d2sum = [0, 2, 4, 6, 8, 1, 3, 5, 7, 9]
  sum, num = 0, n.to_i
  num.digits.each_with_index { |digit, i| sum += i.even? ? digit : d2sum[digit] }
  sum % 10 == 0
end

cards = [49927398716, "49927398717", 1234567812345678, "1234567812345670"]
cards.each{ |i| puts "#{i}: #{luhn_valid?(i)}" }
Output:
49927398716: true
49927398717: false
1234567812345678: false
1234567812345670: true

Another variant

def luhn_valid?(card_string)
  digit_sum = card_string.reverse.chars.map.with_index(1) { |c, i|
    digit = c.to_i

    next digit if i.odd?
    next digit if digit == 9

    (digit * 2) % 9
  }.sum

  digit_sum % 10 == 0
end

['49927398716','49927398717','1234567812345678','1234567812345670'].each do |card_string|
  puts "#{card_string}: #{luhn_valid?(card_string)}"
end
Output:
49927398716: true
49927398717: false
1234567812345678: false
1234567812345670: true

Run BASIC

card$(1) = "49927398716"
card$(2) = "49927398717"
card$(3) = "1234567812345678"
card$(4) = "1234567812345670"

for i = 1 to 4
print card$(i);" ";luhn$(card$(i))
next i

FUNCTION luhn$(card$)
    lc      = len(card$)
    for i   = lc to 1 step -1
      digit = val(mid$(card$,i,1))
      if ((lc -i) mod 2) = 0 then chkSum = chkSum + digit else chkSum = chkSum + int(digit * 2.2)
    next i
    if chkSum mod 10 = 0 then luhn$ = "True" else luhn$ = "False"
end function
Output:
49927398716 True
49927398717 False
1234567812345678 False
1234567812345670 True

Rust

extern crate luhn_test_of_credit_card_numbers;

use luhn_test_of_credit_card_numbers::luhn_test;

fn validate_isin(isin: &str) -> bool {
    if !isin.chars().all(|x| x.is_alphanumeric()) || isin.len() != 12 {
        return false;
    }
    if !isin[..2].chars().all(|x| x.is_alphabetic())
        || !isin[2..12].chars().all(|x| x.is_alphanumeric())
        || !isin.chars().last().unwrap().is_numeric()
    {
        return false;
    }

    let bytes = isin.as_bytes();

    let s2 = bytes
        .iter()
        .flat_map(|&c| {
            if c.is_ascii_digit() {
                vec![c]
            } else {
                (c + 10 - ('A' as u8)).to_string().into_bytes()
            }
        })
        .collect::<Vec<u8>>();

    let string = std::str::from_utf8(&s2).unwrap();
    let number = string.parse::<u64>().unwrap();

    return luhn_test(number as u64);
}

#[cfg(test)]
mod tests {
    use super::validate_isin;

    #[test]
    fn test_validate_isin() {
        assert_eq!(validate_isin("US0378331005"), true);
        assert_eq!(validate_isin("US0373831005"), false);
        assert_eq!(validate_isin("U50378331005"), false);
        assert_eq!(validate_isin("US03378331005"), false);
        assert_eq!(validate_isin("AU0000XVGZA3"), true);
        assert_eq!(validate_isin("AU0000VXGZA3"), true);
        assert_eq!(validate_isin("FR0000988040"), true);
    }
}
Output:
49927398716: true
49927398717: false
1234567812345678: false
1234567812345670: true

Scala

Library: Scala

Functional style

object Luhn {
  private def parse(s: String): Seq[Int] = s.map{c =>
    assert(c.isDigit)
    c.asDigit
  }
  def checksum(digits: Seq[Int]): Int = {
    digits.reverse.zipWithIndex.foldLeft(0){case (sum,(digit,i))=>
      if (i%2 == 0) sum + digit
      else sum + (digit*2)/10 + (digit*2)%10
    } % 10
  }
  def validate(digits: Seq[Int]): Boolean = checksum(digits) == 0
  def checksum(number: String): Int = checksum(parse(number))
  def validate(number: String): Boolean = validate(parse(number))
}

object LuhnTest extends App {
  Seq(("49927398716", true),
    ("49927398717", false),
    ("1234567812345678", false),
    ("1234567812345670", true)
  ).foreach { case (n, expected) =>
    println(s"$n ${Luhn.validate(n)}")
    assert(Luhn.validate(n) == expected)
  }
}
Output:
49927398716 true
49927398717 false
1234567812345678 false
1234567812345670 true

Imperative style

  def luhnTest1(number: String): Boolean = {
    var (odd, sum) = (true, 0)

    for (int <- number.reverse.map { _.toString.toShort }) {
      if (odd) sum += int
      else sum += (int * 2 % 10) + (int / 5)
      odd = !odd
    }
    sum % 10 == 0
  }

Scheme

(define luhn
  (lambda (n)
    (let loop ((number n)
               (index 0)
               (result 0))
      (if (= 0 number)
          (= 0 (remainder result 10))
          (loop (quotient number 10)
                (+ index 1)
                (+ result
                   (if (even? index)
                       (remainder number 10)
                       (let ((part (* 2 (remainder number 10))))
                         (+ (remainder part 10) (quotient part 10))))))))))
Output:
(map luhn '(49927398716 49927398717 1234567812345678 1234567812345670))
(#t #f #f #t)

sed

# Split number into double evens and odds
s/.*/&: /
: split
s/\([0-4]\)\([0-9]\):\(.*\) /:\1\1\3 \2/
s/\([5-9]\)\([0-9]\):\(.*\) /:1\1\1\3 \2/
t split

# Set up addition lookup table
s/\([0-9]\)*:\(.*\) \(.*\)/\1\2\3:0123456789012345678/

: add
s/\([0-9]\)0:/\1:/
s/\([0-9]\)1:\(.*\1.\{0\}\([0-9]\).*\)/\3:\2/
s/\([0-9]\)2:\(.*\1.\{1\}\([0-9]\).*\)/\3:\2/
s/\([0-9]\)3:\(.*\1.\{2\}\([0-9]\).*\)/\3:\2/
s/\([0-9]\)4:\(.*\1.\{3\}\([0-9]\).*\)/\3:\2/
s/\([0-9]\)5:\(.*\1.\{4\}\([0-9]\).*\)/\3:\2/
s/\([0-9]\)6:\(.*\1.\{5\}\([0-9]\).*\)/\3:\2/
s/\([0-9]\)7:\(.*\1.\{6\}\([0-9]\).*\)/\3:\2/
s/\([0-9]\)8:\(.*\1.\{7\}\([0-9]\).*\)/\3:\2/
s/\([0-9]\)9:\(.*\1.\{8\}\([0-9]\).*\)/\3:\2/
t add

/0:/a\
Pass
/0:/!a\
Fail
d
Output:
$ sed -f luhn.sed <<!
49927398716
49927398717
1234567812345678
1234567812345670
!
Pass
Fail
Fail
Pass

Seed7

$ include "seed7_05.s7i";

const func boolean: luhnTest (in string: cardNumber) is func
  result
    var boolean: luhnTest is FALSE;
  local
    var integer: index is 0;
    var integer: digit is 0;
    var boolean: isOdd is TRUE;
    var integer: oddSum is 0;
    var integer: evenSum is 0;
  begin
    for index range length(cardNumber) downto 1 do
      digit := integer parse str(cardNumber[index]);
      if isOdd then
        oddSum +:= digit;
      else
        evenSum +:= digit div 5 + (2 * digit) rem 10;
      end if;
      isOdd := not isOdd;
    end for;
    luhnTest := (oddSum + evenSum) rem 10 = 0;
  end func;

const proc: main is func
  local
    var string: cardNumber is "";
  begin
    for cardNumber range [] ("49927398716", "49927398717", "1234567812345678", "1234567812345670") do
      writeln(cardNumber <& ": " <& luhnTest(cardNumber));
    end for;
  end func;
Output:
49927398716: TRUE
49927398717: FALSE
1234567812345678: FALSE
1234567812345670: TRUE

SenseTalk

function LuhnCheck ccNum
	put length of ccNum into numDigits
	put the last character of ccNum into total
	put numDigits modulo 2 into parity
	repeat for each character of the first numDigits - 1 characters of ccNum
		put it into digit
		if (the counter - 1) modulo 2 equals parity
			multiply digit by 2	
		end if
		if digit is greater than 9
			subtract 9 from digit
		end if
		add digit to total
	end repeat 
	return total is divisible by 10
end LuhnCheck
repeat for each item of (49927398716, 49927398717, 1234567812345678, 1234567812345670)
	put it && LuhnCheck(it)
end repeat

SequenceL

main(args(2)) :=
	sum(luhnTest(asciiToInt(args[1]) - asciiToInt('0'))) mod 10 = 0;

s2Mapping := [0,2,4,6,8,1,3,5,7,9];

luhnTest(x(1))[i] :=
	x[i] when i mod 2 = size(x) mod 2 else
	s2Mapping[x[i] + 1];

SETL

program luhn_test;
    tests := [
        49927398716,
        49927398717,
        1234567812345678,
        1234567812345670
    ];

    loop for test in tests do
        print(test, if luhn test then "pass" else "fail" end);
    end loop;

    op luhn(n);
        fac := 2;
        digits := [val d * (fac := 3-fac) : d in reverse str n];
        return 0 = +/[d - if d>9 then 9 else 0 end : d in digits] mod 10;
    end op;
end program;
Output:
49927398716 pass
49927398717 fail
1234567812345678 fail
1234567812345670 pass

Shen

(define mapi
  _ _ []       -> []
  F N [X | Xs] -> [(F N X) | (mapi F (+ N 1) Xs)])

(define double
  X -> (let Y (* 2 X) (if (> Y 9) (- Y 9) Y)))

(define luhn?
  Number ->
    (let Exploded (explode Number)
         Digits   (map (/. H (- (string->n H) 48)) Exploded)
         Reversed (reverse Digits)
         Doubled  (mapi (/. N X (if (= 1 (shen.mod N 2)) (double X) X)) 0 Reversed)
         Summed   (sum Doubled)
         Modded   (shen.mod Summed 10)
      (= 0 Modded)))

"Expected: [true false false true]"

(map (function luhn?) ["49927398716" "49927398717" "1234567812345678" "1234567812345670"])
Output:
mapi
transform-x
luhn?
"Expected: [true false false true]"
[true false false true]

run time: 0.014999985694885254 secs
loaded

Sidef

func luhn (n) {
    static a = {|j| (2*j // 10) + (2*j % 10) }.map(^10)

    var checksum = n.digits.map_kv {|i,j|
        i.is_odd ? a[j] : j
    }.sum

    checksum % 10 == 0
}

for n in [49927398716, 49927398717, 1234567812345678, 1234567812345670] {
    say [n, luhn(n)]
}
Output:
[49927398716, true]
[49927398717, false]
[1234567812345678, false]
[1234567812345670, true]

SNOBOL4

Using a precomputed array.

          define('luhn(n)a,d,i,j,sum') :(luhn_end)
luhn      n = reverse(n); a = array('0:9')
ln1       a<i> = (2 * i / 10) + remdr(2 * i,10)
          i = lt(i,9) i + 1 :s(ln1)
ln2       n len(1) . d = :f(ln3)
          d = ne(remdr(j,2),0) a<d>; j = j + 1
          sum = sum + d :(ln2)
ln3       luhn = 0; luhn = eq(remdr(sum,10),0) 1 :(return)
luhn_end

          ok = array('0:1')
          ok<0> = 'FAIL'
          ok<1> = 'OK'

*         Test and display
          define('test(n)')  :(test_end)
test      output = n ': ' ok<luhn(n)> :(return)
test_end

          test('49927398716')
          test('49927398717')
          test('1234567812345678')
          test('1234567812345670')
end
Output:
49927398716: OK
49927398717: FAIL
1234567812345678: FAIL
1234567812345670: OK

SparForte

As a structured script.

#!/usr/local/bin/spar
pragma annotate( summary, "luhn test of credit card numbers" )
       @( description, "The Luhn test is used by some credit card companies to " )
       @( description, "distinguish valid credit card numbers from what could be a random selection of digits." )
       @( see_also, "https://rosettacode.org/wiki/Luhn_test_of_credit_card_number" )
       @( author, "Ken O. Burtch" );
pragma license( unrestricted );

pragma restriction( no_external_commands );

procedure luhn is

  bad_digit : exception;

  -- return true if the card number passes the luhn test

  function is_luhn( card_number : string) return boolean is
    card_num_len : constant natural := strings.length( card_number );
    checksum: natural := 0;
    ch : character;
  begin
    for i in reverse 1..card_num_len loop
      ch := strings.element( card_number, i );
      if strings.is_digit( ch ) then
         declare
            ord : constant natural := numerics.pos(ch);
         begin
            if ((card_num_len-1) and (i-1) ) /= 0 then
               checksum := @ + ord;
            else
               checksum := @ + numerics.floor(ord / 5) + ((2*ord) mod 10);
            end if;
         end;
      else
        raise bad_digit;
      end if;
    end loop;
    return checksum mod 10 = 0;
  end is_luhn;

  -- check a credit card and display the result

  procedure check_card( card_number : string ) is
  begin
     put( card_number )
       @( ": " )
       @( is_luhn( card_number ) );
     new_line;
  end check_card;

begin
  check_card("49927398716");
  check_card("49927398717");
  check_card("1234567812345678");
  check_card("1234567812345670");
end luhn;

SPARK

Works with SPARK GPL 2010 and GPS GPL 2010.

Based on the Ada version. All code shown to be free of run-time type errors.

A final test has been added which passes as valid unless there is an explicit test for all digits.

with Spark_IO;
--# inherit Spark_IO;
--# main_program;
procedure Luhn
--# global in out Spark_IO.Outputs;
--# derives Spark_IO.Outputs from *;
is

   function Luhn_Test (Num : String) return Boolean
   --# pre  Num'Last <= 20;
   is
      Sum : Integer := 0;
      Od  : Boolean := True;
      Int : Integer;
      X   : Integer;
      OK  : Boolean := True;
   begin
      for P in reverse Integer range Num'Range loop
         Int := Character'Pos(Num(P)) - Character'Pos('0');
         if Int not in 0 .. 9 then
            OK := False;
            exit;
         end if;
         X := (((Int*2) mod 10) + (Int / 5));
         --# assert Num'Last - P in 0 .. 19
         --#   and  Sum in 0 .. (Num'Last - P) * 10
         --#   and  Int in 0 .. 9
         --#   and  X   in 0 .. 10;
         if Od then
            Sum := Sum + Int;
         else
            Sum := Sum + X;
         end if;
         Od := not Od;
      end loop;
      return OK and (Sum mod 10) = 0;
   end Luhn_Test;

   procedure Do_Test (Num : in     String)
   --# global in out Spark_IO.Outputs;
   --# derives Spark_IO.Outputs from *, Num;
   --# pre  Num'Last <= 20;
   is
   begin
      Spark_IO.Put_String(Spark_IO.Standard_Output, Num, 16);
      if Luhn_Test(Num) then
         Spark_IO.Put_String(Spark_IO.Standard_Output, " is valid.", 0);
      else
         Spark_IO.Put_String(Spark_IO.Standard_Output, " is not valid.", 0);
      end if;
      Spark_IO.New_Line(Spark_IO.Standard_Output, 1);
   end Do_Test;

begin
   Do_Test("49927398716");
   Do_Test("49927398717");
   Do_Test("1234567812345678");
   Do_Test("1234567812345670");
   Do_Test("123456781234567D");
end Luhn;
Output:
49927398716      is valid.
49927398717      is not valid.
1234567812345678 is not valid.
1234567812345670 is valid.
123456781234567D is not valid.

SQL PL

Works with: Db2 LUW

With SQL PL:

--#SET TERMINATOR @

SET SERVEROUTPUT ON @

CREATE OR REPLACE FUNCTION LUHN_TEST (
  IN NUMBER VARCHAR(24)
 ) RETURNS SMALLINT
 --) RETURNS BOOLEAN
 BEGIN
  DECLARE TYPE CARD_NUMBER AS VARCHAR(1) ARRAY [24];
  DECLARE LENGTH SMALLINT;
  DECLARE REVERSE CARD_NUMBER;
  DECLARE I SMALLINT;
  DECLARE POS SMALLINT;
  DECLARE S1 SMALLINT;
  DECLARE S2 SMALLINT;
  DECLARE TEMP SMALLINT;
  DECLARE RET SMALLINT;
  --DECLARE RET BOOLEAN;
  DECLARE INVALID_CHAR CONDITION FOR SQLSTATE 'LUHN1';

  -- Reverse the order of the digits in the number.
  SET LENGTH = LENGTH(NUMBER);
  SET I = 1;
  WHILE (I <= LENGTH) DO
   SET POS = LENGTH - I + 1;
   SET REVERSE[POS] = SUBSTR(NUMBER, I, 1);
   IF (ASCII(REVERSE[POS]) < 48 OR 57 < ASCII(REVERSE[POS])) THEN
    SIGNAL INVALID_CHAR SET MESSAGE_TEXT = 'Invalid character, not a digit';
   END IF;
   SET I = I + 1;
  END WHILE;

  -- Take the first, third, ... and every other odd digit in the reversed digits and sum them to form the partial sum s1
  SET S1 = 0;
  SET I = 1;
  WHILE (I <= LENGTH) DO
   IF (MOD(I, 2) = 1) THEN
    SET S1 = S1 + REVERSE[I];
   END IF;
   -- CALL DBMS_OUTPUT.PUT_LINE('I ' || I || ', S1 ' || S1 || ', val ' || REVERSE[I]);
   SET I = I + 1;
  END WHILE;
 
  -- Taking the second, fourth ... and every other even digit in the reversed digits:
  SET S2 = 0;
  SET TEMP = 0;
  SET I = 1;
  WHILE (I <= LENGTH) DO
   IF (MOD(I, 2) = 0) THEN
    -- Multiply each digit by two and sum the digits if the answer is greater than nine to form partial sums for the even digits
    SET TEMP = REVERSE[I] * 2;
    IF (TEMP > 9) THEN
     SET TEMP = (TEMP / 10) + (MOD(TEMP, 10));
    END IF;
    -- Sum the partial sums of the even digits to form s2
    SET S2 = S2 + TEMP;
   END IF;
   -- CALL DBMS_OUTPUT.PUT_LINE('I ' || I || ', S2 ' || S2 || ', TEMP ' || TEMP || ' val ' || REVERSE[I]);
   SET I = I + 1;
  END WHILE;

  -- If s1 + s2 ends in zero then the original number is in the form of a valid credit card number as verified by the Luhn test.
  SET RET = 1;
  --SET RET = FALSE;
  SET TEMP = S1 + S2;
  IF (MOD(TEMP, 10) = 0) THEN
   SET RET = 0;
   --SET RET = TRUE;
   CALL DBMS_OUTPUT.PUT_LINE('It is a valid number ' || S1 || '+' || S2 || '=' || TEMP);
  ELSE
   CALL DBMS_OUTPUT.PUT_LINE('It is NOT a valid number ' || S1 || '+' || S2 || '=' || TEMP);
  END IF;
  RETURN RET;
 END
@

Output:

db2 -td@
db2 => SET SERVEROUTPUT ON @
DB20000I  The SET SERVEROUTPUT command completed successfully.
db2 => CREATE OR REPLACE FUNCTION VALIDATE_CREDIT_CARD_NUMBER (
...
db2 (cont.) => END @
DB20000I  The SQL command completed successfully.
db2 => values VALIDATE_CREDIT_CARD_NUMBER(49927398716)@                      

1     
------
     0

  1 record(s) selected.

It is a valid number 42+28=70
db2 => VALUES VALIDATE_CREDIT_CARD_NUMBER(49927398717)@

1     
------
     1

  1 record(s) selected.

It is NOT a valid number 43+28=71
db2 => VALUES VALIDATE_CREDIT_CARD_NUMBER(1234567812345678)@

1     
------
     1

  1 record(s) selected.

It is NOT a valid number 40+28=68
db2 => VALUES VALIDATE_CREDIT_CARD_NUMBER(1234567812345670)@

1     
------
     0

  1 record(s) selected.

It is a valid number 32+28=60

Standard ML

local
  fun revDigits 0 = []
    | revDigits n = (n mod 10) :: revDigits (n div 10)

  fun digitSum n = if n > 9 then digitSum (n div 10 + n mod 10)
                            else n

  fun luhn_sum []  = 0
    | luhn_sum [d] = d
    | luhn_sum (d::d'::ds) = d + digitSum (2*d') + luhn_sum ds
in
  fun luhn_test n = luhn_sum (revDigits n) mod 10 = 0

  val res = map luhn_test [49927398716, 49927398717, 1234567812345678, 1234567812345670];
end;

(*
[opening file "luhn.sml"]
> val luhn_test = fn : int -> bool
  val res = [true, false, false, true] : bool list
[closing file "luhn.sml"]
*)

Swift

func luhn(_ number: String) -> Bool {
    return number.reversed().enumerated().map({
        let digit = Int(String($0.element))!
        let even = $0.offset % 2 == 0
        return even ? digit : digit == 9 ? 9 : digit * 2 % 9
    }).reduce(0, +) % 10 == 0
}

luhn("49927398716") // true
luhn("49927398717") // false

Tcl

Based on an algorithmic encoding for the test on Wikipedia.

package require Tcl 8.5
proc luhn digitString {
    if {[regexp {[^0-9]} $digitString]} {error "not a number"}
    set sum 0
    set flip 1
    foreach ch [lreverse [split $digitString {}]] {
	incr sum [lindex {
	    {0 1 2 3 4 5 6 7 8 9}
	    {0 2 4 6 8 1 3 5 7 9}
	} [expr {[incr flip] & 1}] $ch]
    }
    return [expr {($sum % 10) == 0}]
}

Driver:

foreach testNumber {
    49927398716
    49927398717
    1234567812345678
    1234567812345670
} {
    puts [format "%s is %s" $testNumber \
	      [lindex {"NOT valid" "valid"} [luhn $testNumber]]]
}
Output:
49927398716 is valid
49927398717 is NOT valid
1234567812345678 is NOT valid
1234567812345670 is valid

Terraform

variable number {
  type = "string"
}

locals {
  digits = reverse(split("", var.number))
  count = length(local.digits)
  odds = [for i in range(local.count): local.digits[i] if i%2==0]
  evens = [for i in range(local.count): local.digits[i] if i%2==1]
  s1 = length(flatten([for d in local.odds: range(d)]))
  doubles = [for d in local.evens: d * 2]
  partials = [for d in local.doubles: d < 10 ? d : floor(d/10)+d%10]
  s2 = length(flatten([for p in local.partials: range(p)]))
  check = (local.s1 + local.s2) % 10
}

output "valid" {
  value = local.check == 0
}
Output:
$ terraform apply
var.number
  Enter a value: 49927398716


Apply complete! Resources: 0 added, 0 changed, 0 destroyed.

Outputs:

valid = true
$ TF_VAR_number=49927398717 terraform apply >/dev/null; terraform output valid
false
$ TF_VAR_number=1234567812345678 terraform apply >/dev/null; terraform output valid
false
$ TF_VAR_number=1234567812345670 terraform apply >/dev/null; terraform output valid
true

TI-83 BASIC

PROGRAM:LUHN
:Disp "ENTER NUMBER"
:Input Str1
:0→S
:0→E
:For(I,length(Str1),1,-1)
  :inString("0123456789",sub(Str1,I,1))–1→X
  :If X<0
    :Goto BA
  :If E≠0
  :Then
    :2X→X
    :If X>9
      :X–9→X
  :End
  :X+S→S
  :not(E)→E
:End
:If fPart(S/10)=0
:Then
  :Disp "GOOD CARD"
:Else
  :Lbl BA
  :Disp "BAD CARD"
:End

Transact-SQL

CREATE FUNCTION dbo._CreditCardNumCheck( @strCCNum VarChar(40) )
RETURNS VarChar(7)
AS
BEGIN
	DECLARE @string			VarChar(40) = REVERSE(@strCCNum); -- usage: set once, never changed
	DECLARE @strS2Values		VarChar(10) = '0246813579';  -- constant: maps digits to their S2 summed values
	DECLARE @table			TABLE (ID INT, Value INT, S_Value INT); -- ID=digit position. S_Value is used for SUM().
	DECLARE @p			INT = 0; -- loop counter: position in string
	-- Convert the reversed string's digits into rows in a table variable, S_Values to be updated afterwards
	WHILE @p < LEN(@string)
		BEGIN
			SET @p = @p+1;
			INSERT INTO @table (ID,Value,S_Value) VALUES (@p, CONVERT(INT,SUBSTRING(@string,@p,1)), 0);
		END
	-- Update S_Value column : the digit's value to be summed (for even-positioned digits this is mapped via @strS2Values)
	UPDATE @table SET S_Value = CASE WHEN ID % 2 = 1 THEN Value ELSE CONVERT(INT,SUBSTRING(@strS2Values,Value+1,1)) END
	-- If the SUM of S_Values ends in 0 (modulo 10 = 0) then the CC Number is valid
	RETURN CASE WHEN (SELECT SUM(S_Value) FROM @table) % 10 = 0 THEN 'Valid' ELSE 'Invalid' END
END

TUSCRIPT

$$ MODE TUSCRIPT
MODE DATA
$$ SET cardnumbers=*
49927398716
49927398717
1234567812345678
1234567812345670
$$ MODE TUSCRIPT
-> collecting information for output-format
SET length=MAX_LENGTH(cardnumbers)
SET adjust=length+2

LOOP c=cardnumbers
-> ">/" = any digit
SET cstring=STRINGS (c,":>/:")
SET creverse=REVERSE (cstring)
SET s1=evenx2=esum=s2=""
 LOOP n,oe=creverse
  SET modrest=MOD(n,2)
  IF (modrest==0) THEN
   SET even=oe*2
    IF (even>9) THEN
     SET estring=STRINGS (even,":>/:")
     SET esum=SUM (estring)
     SET s2=APPEND (s2,esum)
    ELSE
     SET s2=APPEND (s2,even)
    ENDIF
  ELSE
   SET s1=APPEND(s1,oe)
  ENDIF
 ENDLOOP
SET s1=SUM(s1),s2=SUM(s2)
SET checksum=s1+s2
SET c=CENTER(c,-adjust)
IF (checksum.ew."0") THEN
 PRINT c,"true"
ELSE
 PRINT c,"false"
ENDIF
ENDLOOP
Output:
49927398716       true
49927398717       false
1234567812345678  false
1234567812345670  true 

TXR

@(do (defun luhn (num)
       (for ((i 1) (sum 0))
            ((not (zerop num)) (zerop (mod sum 10)))
            ((inc i) (set num (trunc num 10)))
          (let ((dig (mod num 10)))
            (if (oddp i)
              (inc sum dig)
              (let ((dig2 (* 2 dig)))
                (inc sum (+ (trunc dig2 10) (mod dig2 10)))))))))
@(collect :vars nil)
@{ccnumber /[0-9]+/}
@(output)
@ccnumber -> @(if (luhn (int-str ccnumber 10)) "good" "bad")
@(end)
@(end)
$ txr luhn.txr luhn.txt
49927398716 -> good
49927398717 -> bad
1234567812345678 -> bad
1234567812345670 -> good

Uiua

Luhn ← =0◿10+⊃(/+⊢|/+∵(⍥(-9)>9.×2)⊡1)⍉⬚0↯∞_2⇌
T ← {"49927398716"
     "49927398717"
     "1234567812345678"
     "1234567812345670"}
≡◇(Luhn ≡⋕) T
Output:
[1 0 0 1]

UNIX Shell

Works with: bash
Works with: ksh
function luhn {
  typeset n p s t=('0123456789' '0516273849')
  while ((-n<${#1})); do
    p="${t[n--%2]%${1:n:1}*}"
    ((s+=${#p}))
  done
  ((s%10))
}

for c in 49927398716 49927398717 1234567812345678 1234567812345670; do
    if luhn $c; then 
        echo $c is invalid
    else
        echo $c is valid
    fi
done

Notes:

  • The parameter expansion hack (p=${t…%${1:n:1}};…${#p}…) is an interesting way of converting a set of characters to ordinals. It's highly extensible to larger character sets (e.g. for ISBN and Code 39 checksums).
  • Invalid characters are effectively treated as 0s. This is actually useful sometimes for ignoring alphabetic prefixes.
  • When attempting to understand the function, remember that n is negative, so it indexes from the end of the input string.
Output:
49927398716 is valid
49927398717 is invalid
1234567812345678 is invalid
1234567812345670 is valid

Ursala

#import std
#import nat

luhn = %nP; %np*hxiNCNCS; not remainder\10+ //sum:-0@DrlrHK32 ~&iK27K28TK25 iota10

Some notes on this solution:

  • iota10 is the list of natural numbers <0,1,2,3,4,5,6,7,8,9>
  • ~&K27 and ~&K28 of iota10 extract the alternate items, respectively <0,2,4,6,8> and <1,3,5,7,9>
  • ~&K27K28T iota10 is their concatenation, <0,2,4,6,8,1,3,5,7,9> which is also the list of values obtained by doubling each item of iota10 and taking digit sums
  • ~&iK27K28TX iota10 would be the pair (<0,1,2,3,4,5,6,7,8,9>,<0,2,4,6,8,1,3,5,7,9>), but using the reification operator K25 in place of X makes it an executable function taking any item of the left list as an argument and returning the corresponding item of the right.
  • The part beginning with // is a function of the form //f a, which can be applied to any argument b to obtain f(a,b). In this case, the f is sum:-0@DrlrHK32, which is equivalent to the composition of two functions sum:-0 and ~&DrlrHK32, and a is the function just obtained by reification.
  • The function ~&D by itself takes a pair (a,<b0...bn>) whose right side is a list, and returns the list of pairs <(a,b0)...(a,bn)> (i.e., a copy of a paired with each b). The a here will end up being the aforementioned function.
  • ~&DrlrHK32 not only forms such a list of pairs, but operates on each pair thus obtained, alternately applying ~&r and ~&lrH to each pair in sequence, where ~&r simply returns the right side of the pair, and ~&lrH uses the left side as a function, which is applied to the right.
  • sum:-0 computes the cumulative sum of a list of natural numbers using the binary sum function, and the reduction operator (:-) with vacuous sum 0.
  • The whole thing described up to this point is therefore a function that will take a list of numbers in the range 0 to 9, and compute the summation obtained when doubling and digit summing alternate items.
  • The input list to this function is constructed from a single natural number first by %nP, which transforms it to text format in decimal, followed by %np*hxiNCNCS, which reverses the digits, makes a separate text of each, and parses them as individual numbers.
  • The output from the function is tested for divisibility by 10 with remainder\10, with the result negated so that zero values map to true and non-zero to false.

usage:

#cast %bL

test = luhn* <49927398716,49927398717,1234567812345678,1234567812345670>
Output:
<true,false,false,true>

VBA

Option Explicit

Sub Main()
  Debug.Print "Number 49927398716 is "; Luhn("49927398716")
  Debug.Print "Number 49927398717 is "; Luhn("49927398717")
  Debug.Print "Number 1234567812345678 is "; Luhn("1234567812345678")
  Debug.Print "Number 1234567812345670 is "; Luhn("1234567812345670")
End Sub
Private Function Luhn(Nb As String) As String
Dim t$, i&, Summ&, s&
    t = StrReverse(Nb)
    For i = 1 To Len(t) Step 2
        Summ = Summ + CInt(Mid(t, i, 1))
    Next i
    For i = 2 To Len(t) Step 2
        s = 2 * (CInt(Mid(t, i, 1)))
        If s >= 10 Then
            Summ = Summ - 9
        End If
        Summ = Summ + s
    Next i
    If Summ Mod 10 = 0 Then
        Luhn = "valid"
    Else
        Luhn = "invalid"
    End If
End Function
Output:
Number 49927398716 is valid
Number 49927398717 is invalid
Number 1234567812345678 is invalid
Number 1234567812345670 is valid

VBScript

Function Luhn_Test(cc)
	cc = RevString(cc)
	s1 = 0
	s2 = 0
	For i = 1 To Len(cc)
		If i Mod 2 > 0 Then
			s1 = s1 + CInt(Mid(cc,i,1))
		Else
			tmp = CInt(Mid(cc,i,1))*2
			If  tmp < 10 Then
				s2 = s2 + tmp
			Else
				s2 = s2 + CInt(Right(CStr(tmp),1)) + 1
			End If
		End If 
	Next
	If Right(CStr(s1 + s2),1) = "0" Then
		Luhn_Test = "Valid"
	Else
		Luhn_Test = "Invalid"
	End If
End Function

Function RevString(s)
	For i = Len(s) To 1 Step -1
		RevString = RevString & Mid(s,i,1)
	Next
End Function

WScript.Echo "49927398716 is " & Luhn_Test("49927398716")
WScript.Echo "49927398717 is " & Luhn_Test("49927398717")			 
WScript.Echo "1234567812345678 is " & Luhn_Test("1234567812345678")
WScript.Echo "1234567812345670 is " & Luhn_Test("1234567812345670")
Output:
49927398716 is Valid
49927398717 is Invalid
1234567812345678 is Invalid
1234567812345670 is Valid

Visual Basic

Works with: Visual Basic version VB6 Standard
Public Function LuhnCheckPassed(ByVal dgts As String) As Boolean
Dim i As Long, s As Long, s1 As Long
  dgts = VBA.StrReverse(dgts)
    For i = 1 To Len(dgts) Step 2
        s = s + CInt(Mid$(dgts, i, 1))
    Next i
    For i = 2 To Len(dgts) Step 2
        s1 = 2 * (CInt(Mid$(dgts, i, 1)))
        If s1 >= 10 Then
            s = s - 9
        End If
        s = s + s1
    Next i
  LuhnCheckPassed = Not CBool(s Mod 10)
End Function

Test:

Sub Main()
  Debug.Assert LuhnCheckPassed("49927398716")
  Debug.Assert Not LuhnCheckPassed("49927398717")
  Debug.Assert Not LuhnCheckPassed("1234567812345678")
  Debug.Assert LuhnCheckPassed("1234567812345670")
End Sub

Visual Basic .NET

    Imports System.Linq
    Function ValidLuhn(value As String)
        Return value.Select(Function(c, i) (AscW(c) - 48) << ((value.Length - i - 1) And 1)).Sum(Function(n) If(n > 9, n - 9, n)) Mod 10 = 0
    End Function
    Sub Main()
        Console.WriteLine(ValidLuhn("49927398716"))
        Console.WriteLine(ValidLuhn("49927398717"))
        Console.WriteLine(ValidLuhn("1234567812345678"))
        Console.WriteLine(ValidLuhn("1234567812345670"))
    End Sub
Output:
True
False
False
True

V (Vlang)

Translation of: Go
const (
    input = "
	49927398716
	49927398717
	1234567812345678
	1234567812345670"
     
    t = [0, 2, 4, 6, 8, 1, 3, 5, 7, 9]
)
 
fn luhn(s string) bool {
    odd := s.len & 1
    mut sum := 0
    for i, c in s.split("") {
        if c < '0' || c > '9' {return false}
        if i&1 == odd {sum += t[c.int()-'0'.int()]} 
		else {sum += c.int() - '0'.int()}
    }
    return sum % 10 == 0
}
 
fn main() {
    for s in input.trim_indent().split_into_lines() {
        println("${s} ${luhn(s)}")
    }
}
Output:
49927398716 true
49927398717 false
1234567812345678 false
1234567812345670 true

Wren

Library: Wren-fmt
Library: Wren-iterate
import "./fmt" for Fmt
import "./iterate" for Stepped

var luhn = Fn.new { |s|
    // reverse digits
    s = s[-1..0]
    // sum the odd digits
    var s1 = Stepped.new(s, 2).reduce(0) { |sum, d| sum + d.bytes[0] - 48 }
    // sum two times the even digits
    var s2 = Stepped.new(s[1..-1], 2).reduce(0) { |sum, d|
        var d2 = (d.bytes[0] - 48) * 2
        return sum  + ((d2 > 9) ?  d2%10 + 1 : d2)
    }
    // check if s1 + s2 ends in zero
    return (s1 + s2)%10 == 0
}

var tests = [ "49927398716", "49927398717", "1234567812345678", "1234567812345670"]
for (test in tests) {
    var ans = (luhn.call(test)) ? "pass" : "fail"
    Fmt.print("$-16s -> $s", test, ans)
}
Output:
49927398716      -> pass
49927398717      -> fail
1234567812345678 -> fail
1234567812345670 -> pass

Xojo

Public Function Modulus10(digits As String) as String
  //
  // Confirm the digits are really, well, digits
  //
  
  dim validator as new RegEx
  validator.SearchPattern = "\A\d+\z"
  if validator.Search( digits ) is nil then
    //
    // Raise an exception or something
    //
  end if
  
  static doublingTable() as string = array( "0", "2", "4", "6", "8", "1", "3", "5", "7", "9" )
  
  dim digitArr() as string = digits.Split( "" )
  for i as integer = digitArr.Ubound downto 0 step 2
    digitArr( i ) = doublingTable( digitArr( i ).Val )
  next
  
  dim sum as integer
  for each digit as string in digitArr
    sum = sum + digit.Val
  next
  
  dim check as integer = ( sum * 9 ) mod 10
  return str( check )
End Function

Public Function ValidateMod10(digits As String) as Boolean
  dim checkDigit as string = digits.Right( 1 )
  digits = digits.Left( digits.Len - 1 )
  
  return Modulus10( digits ) = checkDigit
End Function
Output:
ValididateMod10( "49927398716" ) = True
ValididateMod10( "49927398717" ) = False
ValididateMod10( "1234567812345678" ) = False
ValididateMod10( "1234567812345670" ) = True

XPL0

string 0;               \use zero-terminated strings

func    Valid(Str);     \Return 'true' if digits in Str pass Luhn test
char    Str;
int     Len, Sum, I, Dig;
[Len:= 0;               \find length of Str
while Str(Len) do Len:= Len+1;
Sum:= 0;                \sum even and odd digits
for I:= 0 to Len-1 do   \(no need to reverse)
        [if (I xor Len) and 1 then
                Sum:= Sum + Str(I) - ^0
        else    [Dig:= Str(I) - ^0;
                Dig:= Dig*2;
                Sum:= Sum + Dig/10 + rem(0);
                ];
        ];
return rem(Sum/10) = 0; 
];

int     Luhn, N;
[Luhn:= ["49927398716",
         "49927398717",
         "1234567812345678",
         "1234567812345670"];
for N:= 0 to 4-1 do
        [Text(0, Luhn(N));
         Text(0, if Valid(Luhn(N))
                then " is valid"
                else " is not valid");
        CrLf(0);
        ];
]
Output:
49927398716 is valid
49927398717 is not valid
1234567812345678 is not valid
1234567812345670 is valid

zkl

fcn luhnTest(n){
   0 == (n.split().reverse().reduce(fcn(s,n,clk){
      s + if(clk.next()) n else 2*n%10 + n/5 },0,Walker.cycle(1,0)) %10)
}
T(49927398716,49927398717,1234567812345678,1234567812345670)
.apply(luhnTest).println();
Output:
L(True,False,False,True)

ZX Spectrum Basic

10 LET c$="49927398716": GO SUB 1000
20 LET c$="49927398717": GO SUB 1000
30 LET c$="1234567812345678": GO SUB 1000
40 LET c$="1234567812345670": GO SUB 1000
999 STOP 
1000 REM *************
1001 REM * LUHN TEST *
1002 REM *************
1010 LET r$=""
1020 FOR i=LEN c$ TO 1 STEP -1
1030 LET r$=r$+c$(i)
1040 NEXT i
1050 LET s1=0: LET s2=0
1060 FOR i=1 TO LEN r$ STEP 2
1070 LET s1=s1+VAL r$(i)
1080 NEXT i
1090 FOR i=2 TO LEN r$ STEP 2
1100 LET s2sub=VAL r$(i)*2
1110 IF s2sub>=10 THEN LET s2sub=1+s2sub-10
1120 LET s2=s2+s2sub
1130 NEXT i
1140 LET s$=STR$ (s1+s2)
1150 IF s$(LEN s$)="0" THEN PRINT c$;" VALID!": LET retval=1: RETURN 
1160 PRINT c$;" INVALID!": LET retval=0: RETURN
Output:
49927398716 VALID!
49927398717 INVALID!
1234567812345678 INVALID!
1234567812345670 VALID!
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