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==={{header|FutureBasic}}===
==={header|FutureBasic}===
<lang futurebasic>local fn MyArraySortFunction( obj1 as CFTypeRef, obj2 as CFTypeRef, context as ptr ) as NSComparisonResult
<lang futurebasic>local fn MyArraySortFunction( obj1 as CFTypeRef, obj2 as CFTypeRef, context as ptr ) as NSComparisonResult
NSComparisonResult result = NSOrderedDescending
NSComparisonResult result = NSOrderedDescending

Revision as of 14:49, 24 June 2022

Task
Compare length of two strings
You are encouraged to solve this task according to the task description, using any language you may know.

Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.

You may see other such operations in the Basic Data Operations category, or:

Integer Operations
Arithmetic | Comparison

Boolean Operations
Bitwise | Logical

String Operations
Concatenation | Interpolation | Comparison | Matching

Memory Operations
Pointers & references | Addresses

Task

Given two strings of different length, determine which string is longer or shorter. Print both strings and their length, one on each line. Print the longer one first.

Measure the length of your string in terms of bytes or characters, as appropriate for your language. If your language doesn't have an operator for measuring the length of a string, note it.

Extra credit

Given more than two strings:
list = ["abcd","123456789","abcdef","1234567"]
Show the strings in descending length order.

Other tasks related to string operations:
Metrics
Counting
Remove/replace
Anagrams/Derangements/shuffling
Find/Search/Determine
Formatting
Song lyrics/poems/Mad Libs/phrases
Tokenize
Sequences



Ada

<lang ada>with ada.command_line, ada.containers.indefinite_vectors, ada.text_io; procedure compare_lengths is

  package string_vector is new ada.containers.indefinite_vectors
    (index_type => Positive, element_type => String);
  function "<" (left, right : String) return Boolean is
  begin
     return left'length > right'length;
  end "<";
  package string_vector_sorting is new string_vector.generic_sorting;
  list : string_vector.Vector;

begin

  for i in 1 .. ada.command_line.argument_count loop
     list.append (ada.command_line.argument (i));
  end loop;
  string_vector_sorting.sort (list);
  for elem of list loop
     ada.text_io.put_line (elem'length'image & ": " & elem);
  end loop;

end compare_lengths; </lang>

Output:

./compare_lengths Like sands through the hourglass these are the days of our lives

 9: hourglass
 7: through
 5: lives
 5: sands
 5: these
 4: days
 4: Like
 3: are
 3: our
 3: the
 3: the
 2: of

ALGOL 68

Algol 68 does not have an in-built "LENGTH" operator, it does have operators LWB and UPB which return the lower bound and upper bound of an array and as strings are arrays of characters, LENGTH can easily be constructed from these.
In most Algol 68 implementations such as Algol 68G and Rutgers Algol 68, the CHAR type is an 8-bit byte. <lang algol68>BEGIN # compare string lengths #

   # returns the length of s using the builtin UPB and LWB operators #
   OP LENGTH = ( STRING s )INT: ( UPB s + 1 ) - LWB s;
   # prints s and its length #
   PROC print string = ( STRING s )VOID:
        print( ( """", s, """ has length: ", whole( LENGTH s, 0 ), " bytes.", newline ) );
   STRING shorter     = "short";
   STRING not shorter = "longer";
   IF LENGTH shorter >  LENGTH not shorter THEN print string( shorter ) FI;
   print string( not shorter );
   IF LENGTH shorter <= LENGTH not shorter THEN print string( shorter ) FI

END</lang>

Output:
"longer" has length: 6 bytes.
"short" has length: 5 bytes.

APL

For a good intro to APL, see APL2 At A Glance <lang APL>

     sv ← 'defg' 'hijklm' 'abc' 'abcd'
     ⍉(⍴¨sv[⍒sv]),[0.5]sv[⍒sv]
6  hijklm 
4  defg   
4  abcd   
3  abc    

</lang>

Arturo

<lang rebol>sortByLength: function [strs][

   map sort.descending.by:'v 
       map strs 'str -> #[s: str, v: size str] 
       'z -> z\s

]

A: "I am string" B: "I am string too"

sA: size A sB: size B

if? sA < sB ->

   print ["string ->" A "(" sA ") is smaller than string ->" B "(" sB ")"]

else [

   if? sA > sB ->
       print ["string ->" A "(" sA ") is larger than string ->" B "(" sB ")"]
   else ->
       print ["string ->" A "(" sA ") and string ->" B "(" sB ") are of equal length"]

]

print ["sorted strings (by length):" sortByLength ["abcd" "123456789" "abcdef" "1234567"]]</lang>

Output:
string -> I am string ( 11 ) is smaller than string -> I am string too ( 15 ) 
sorted strings (by length): [123456789 1234567 abcdef abcd]

Asymptote

<lang Asymptote>string A, B, t = '\t';

void comp(string A, string B) {

   if (length(A) >= length(B)) {
       write(A+t, length(A));
       write(B+t, length(B));
   } else {
       write(B+t, length(B));
       write(A+t, length(A));
   }

}

comp("abcd", "123456789");</lang>

Output:
123456789	9
abcd	4

AutoHotkey

<lang AutoHotkey>list := ["abcd","123456789","abcdef","1234567"]

sorted := [] for i, s in list

   sorted[0-StrLen(s), s] := s

for l, obj in sorted {

   i := A_Index
   for s, v in obj
   {
       if (i = 1)
           result .= """" s """ has length " 0-l " and is the longest string.`n"
       else if (i < sorted.Count())
           result .= """"s """ has length " 0-l " and is neither the longest nor the shortest string.`n"
       else
           result .= """"s """ has length " 0-l " and is the shorted string.`n"
   }

} MsgBox % result</lang>

Output:
"123456789" has length 9 and is the longest string.
"1234567" has length 7 and is neither the longest nor the shortest string.
"abcdef" has length 6 and is neither the longest nor the shortest string.
"abcd" has length 4 and is the shorted string.

AWK

<lang AWK>

  1. syntax: GAWK -f COMPARE_LENGTH_OF_TWO_STRINGS.AWK

BEGIN {

   main("abcd","123456789")
   main("longer","short")
   main("hello","world")
   exit(0)

} function main(Sa,Sb, La,Lb) {

   La = length(Sa)
   Lb = length(Sb)
   if (La > Lb) {
     printf("a>b\n%3d %s\n%3d %s\n\n",La,Sa,Lb,Sb)
   }
   else if (La < Lb) {
     printf("a<b\n%3d %s\n%3d %s\n\n",Lb,Sb,La,Sa)
   }
   else {
     printf("a=b\n%3d %s\n%3d %s\n\n",Lb,Sb,La,Sa)
   }

} </lang>

Output:
a<b
  9 123456789
  4 abcd

a>b
  6 longer
  5 short

a=b
  5 world
  5 hello

BQN

BQN's grade functions(similar to APL) produces the indices to sort an array. We grade the lengths, then use those to arrage the strings correctly.

<lang bqn>Compare ← >·(⍒⊑¨)⊸⊏≠⊸⋈¨

•Show Compare ⟨"hello", "person"⟩ •Show Compare ⟨"abcd", "123456789", "abcdef", "1234567"⟩</lang> <lang>┌─ ╵ 6 "person"

 5 "hello"   
            ┘

┌─ ╵ 9 "123456789"

 7 "1234567"    
 6 "abcdef"     
 4 "abcd"       
               ┘</lang>

C

Works with: C11

<lang C>#include <stdio.h>

  1. include <stdlib.h>
  2. include <string.h>

int cmp(const int* a, const int* b) {

   return *b - *a; // reverse sort!

}

void compareAndReportStringsLength(const char* strings[], const int n) {

   if (n > 0)
   {
       char* has_length = "has length";
       char* predicate_max = "and is the longest string";
       char* predicate_min = "and is the shortest string";
       char* predicate_ave = "and is neither the longest nor the shortest string";
       int* si = malloc(2 * n * sizeof(int));
       if (si != NULL)
       {
           for (int i = 0; i < n; i++)
           {
               si[2 * i] = strlen(strings[i]);
               si[2 * i + 1] = i;
           }
           qsort(si, n, 2 * sizeof(int), cmp);
           int max = si[0];
           int min = si[2 * (n - 1)];
           for (int i = 0; i < n; i++)
           {
               int length = si[2 * i];
               char* string = strings[si[2 * i + 1]];
               char* predicate;
               if (length == max)
                   predicate = predicate_max;
               else if (length == min)
                   predicate = predicate_min;
               else
                   predicate = predicate_ave;
               printf("\"%s\" %s %d %s\n",
                   string, has_length, length, predicate);
           }
           free(si);
       }
       else
       {
           fputs("unable allocate memory buffer", stderr);
       }
   }

}

int main(int argc, char* argv[]) {

   char* list[] = { "abcd", "123456789", "abcdef", "1234567" };
   compareAndReportStringsLength(list, 4);
   return EXIT_SUCCESS;

}</lang>

Output:
"123456789" has length 9 and is the longest string
"1234567" has length 7 and is neither the longest nor the shortest string
"abcdef" has length 6 and is neither the longest nor the shortest string
"abcd" has length 4 and is the shortest string

C++

<lang cpp>#include <iostream>

  1. include <algorithm>
  2. include <string>
  3. include <list>

using namespace std;

bool cmp(const string& a, const string& b) {

   return b.length() < a.length(); // reverse sort!

}

void compareAndReportStringsLength(list<string> listOfStrings) {

   if (!listOfStrings.empty())
   {
       char Q = '"';
       string has_length(" has length ");
       string predicate_max(" and is the longest string");
       string predicate_min(" and is the shortest string");
       string predicate_ave(" and is neither the longest nor the shortest string");
       list<string> ls(listOfStrings); // clone to avoid side-effects
       ls.sort(cmp);
       int max = ls.front().length();
       int min = ls.back().length();
       for (list<string>::iterator s = ls.begin(); s != ls.end(); s++)
       {
           int length = s->length();
           string* predicate;
           if (length == max)
               predicate = &predicate_max;
           else if (length == min)
               predicate = &predicate_min;
           else
               predicate = &predicate_ave;
           cout << Q << *s << Q << has_length << length << *predicate << endl;
       }
   }

}

int main(int argc, char* argv[]) {

   list<string> listOfStrings{ "abcd", "123456789", "abcdef", "1234567" };
   compareAndReportStringsLength(listOfStrings);
   return EXIT_SUCCESS;

}</lang>

Output:
"123456789" has length 9 and is the longest string
"1234567" has length 7 and is neither the longest nor the shortest string
"abcdef" has length 6 and is neither the longest nor the shortest string
"abcd" has length 4 and is the shortest string

C#

<lang csharp>using System; using System.Collections.Generic;

namespace example {

   class Program
   {
       static void Main(string[] args)
       {
           var strings = new string[] { "abcd", "123456789", "abcdef", "1234567" };
           compareAndReportStringsLength(strings);
       }
       private static void compareAndReportStringsLength(string[] strings)
       {
           if (strings.Length > 0)
           {
               char Q = '"';
               string hasLength = " has length ";
               string predicateMax = " and is the longest string";
               string predicateMin = " and is the shortest string";
               string predicateAve = " and is neither the longest nor the shortest string";
               string predicate;
               (int, int)[] li = new (int, int)[strings.Length];
               for (int i = 0; i < strings.Length; i++)
                   li[i] = (strings[i].Length, i);
               Array.Sort(li, ((int, int) a, (int, int) b) => b.Item1 - a.Item1);
               int maxLength = li[0].Item1;
               int minLength = li[strings.Length - 1].Item1;
               for (int i = 0; i < strings.Length; i++)
               {
                   int length = li[i].Item1;
                   string str = strings[li[i].Item2];
                   if (length == maxLength)
                       predicate = predicateMax;
                   else if (length == minLength)
                       predicate = predicateMin;
                   else
                       predicate = predicateAve;
                   Console.WriteLine(Q + str + Q + hasLength + length + predicate);
               }
           }
       }
   }

} </lang>

Output:
"123456789" has length 9 and is the longest string
"1234567" has length 7 and is neither the longest nor the shortest string
"abcdef" has length 6 and is neither the longest nor the shortest string
"abcd" has length 4 and is the shortest string

CFEngine

<lang cfengine3> bundle agent __main__ {

 vars:
     "strings" slist => { "abcd", "123456789", "abcdef", "1234567" };
     "sorted[$(with)]"
       string => "$(strings)",
       with => string_length( "$(strings)" );
     "sort_idx" slist => reverse( sort( getindices( "sorted" ), lex ) );
 reports:
     "'$(sorted[$(sort_idx)])' is $(sort_idx) characters in length.";

} </lang>

Output:
R: '123456789' is 9 characters in length.
R: '1234567' is 7 characters in length.
R: 'abcdef' is 6 characters in length.
R: 'abcd' is 4 characters in length.

BASIC

Applesoft BASIC

Printing CHR$(14) does nothing by default in Applesoft BASIC. Commodore BASIC appends spaces to numbers, but otherwise the Compare_length_of_two_strings#Commodore_BASIC code works the same in Applesoft BASIC.

Output:
*** (1) TWO STRINGS ***
LONGER STRING (13)
SHORT STRING (12)


*** (2) MORE THAN 2 STRINGS***
SHE DOESN'T STUDY GERMAN ON MONDAY (34)
EVERY CHILD LIKES AN ICE CREAM (30)
THE COURSE STARTS NEXT SUNDAY (29)
DOES SHE LIVE IN PARIS? (23)
SHE SWIMS EVERY MORNING (23)
THE EARTH IS SPHERICAL (22)
WE SEE THEM EVERY WEEK (22)
HE DOESN'T TEACH MATH (21)
CATS HATE WATER (15)
I LIKE TEA (10)

Commodore BASIC

Works with: Applesoft BASIC
Works with: Commodore BASIC version 2.0
Works with: Commodore BASIC version 3.5

<lang gwbasic>0 REM ROSETTACODE.ORG 1 REM COMPARE LENGTH OF TWO STRINGS 2 REM GIVEN TWO STRINGS OF DIFFERENT 3 REM LENGTH, DETERMINE WHICH STRING IS 4 REM LONGER OR SHORTER. 5 REM PRINT BOTH STRINGS AND THEIR 6 REM LENGTH, ONE ON EACH LINE. PRINT 7 REM THE LONGER ONE FIRST. 8 REM 9 REM ******************************** 10 REM 20 REM PRINT CHR$(14): REM CHANGE TO LOWER/UPPER CASE CHAR SET 30 GOSUB 200: REM 1 - COMPARE LENGTH OF 2 STRINGS 40 GOSUB 300: REM 2- MORE THAN 2 STRINGS 50 END 200 PRINT"*** (1) TWO STRINGS ***" 210 A$ = "SHORT STRING" 220 B$ = "LONGER STRING" 230 A = LEN(A$) 240 B = LEN(B$) 250 IF A>B THEN PRINT A$;" (";A;")": PRINT B$;" (";B;")" 260 IF A<=B THEN PRINT B$;" (";B;")": PRINT A$;" (";A;")" 270 PRINT: PRINT 280 RETURN 300 PRINT"*** (2) MORE THAN 2 STRINGS***" 310 DIM C$(100) 320 N = 0 330 READ A$ 340 IF A$ = "$$$" THEN 400 350 N = N+1 360 C$(N) = A$ 370 IF N = 100 THEN 400 380 GOTO 330 390 REM SORT THE STRINGS 400 FOR J=1 TO N-1 410 FOR I=1 TO N-J 420 IF LEN(C$(I)) < LEN(C$(I+1)) THEN A$=C$(I): C$(I)=C$(I+1): C$(I+1)=A$ 430 NEXT 440 NEXT 450 REM PRINT OUT THE STRINGS 460 FOR I=1 TO N 470 PRINT C$(I);" (";LEN(C$(I));")" 480 NEXT 490 PRINT: PRINT 500 RETURN 1000 DATA "DOES SHE LIVE IN PARIS?" 1010 DATA "HE DOESN'T TEACH MATH" 1020 DATA "CATS HATE WATER" 1030 DATA "SHE DOESN'T STUDY GERMAN ON MONDAY" 1040 DATA "EVERY CHILD LIKES AN ICE CREAM" 1050 DATA "THE EARTH IS SPHERICAL" 1060 DATA "THE COURSE STARTS NEXT SUNDAY" 1070 DATA "SHE SWIMS EVERY MORNING" 1080 DATA "I LIKE TEA" 1090 DATA "WE SEE THEM EVERY WEEK" 1100 DATA "$$$"</lang>

Output:
*** (1) TWO STRINGS ***
LONGER STRING ( 13 )
SHORT STRING ( 12 )


*** (2) MORE THAN 2 STRINGS***
SHE DOESN'T STUDY GERMAN ON MONDAY ( 34
)
EVERY CHILD LIKES AN ICE CREAM ( 30 )
THE COURSE STARTS NEXT SUNDAY ( 29 )
DOES SHE LIVE IN PARIS? ( 23 )
SHE SWIMS EVERY MORNING ( 23 )
THE EARTH IS SPHERICAL ( 22 )
WE SEE THEM EVERY WEEK ( 22 )
HE DOESN'T TEACH MATH ( 21 )
CATS HATE WATER ( 15 )
I LIKE TEA ( 10 )

BASIC256

<lang basic256>subroutine comp(A$, B$)

   if length(A$) >= length(B$) then 
       print A$, length(A$)
       print B$, length(B$)
   else
       print B$, length(B$)
       print A$, length(A$)
   end if

end subroutine

call comp("abcd", "123456789")</lang>

PureBasic

<lang PureBasic>Procedure comp(A.s, B.s)

 If Len(A) >= Len(B)
   PrintN(A + #TAB$ + Str(Len(A)))
   PrintN(B + #TAB$ + Str(Len(B)))
 Else
   PrintN(B + #TAB$ + Str(Len(B)))
   PrintN(A + #TAB$ + Str(Len(A)))
 EndIf

EndProcedure

OpenConsole() comp("abcd", "123456789") Input() CloseConsole()</lang>

QBasic

Works with: QBasic version 1.1
Works with: QuickBasic version 4.5
Works with: True BASIC

<lang QBasic>SUB comp(A$, B$)

   IF LEN(A$) >= LEN(B$) THEN
      PRINT A$, LEN(A$)
      PRINT B$, LEN(B$)
   ELSE
      PRINT B$, LEN(B$)
      PRINT A$, LEN(A$)
   END IF

END SUB

CALL comp("abcd", "123456789") END</lang>

Run BASIC

<lang runbasic>sub comp A$, B$

   if len(A$) >= len(B$) then 
       print A$; chr$(9); len(A$)
       print B$; chr$(9); len(B$)
   else
       print B$; chr$(9); len(B$)
       print A$; chr$(9); len(A$)
   end if

end sub

call comp "abcd", "123456789"</lang>

True BASIC

Works with: QBasic

<lang qbasic>SUB comp(A$, B$)

   IF LEN(A$) >= LEN(B$) THEN
      PRINT A$, LEN(A$)
      PRINT B$, LEN(B$)
   ELSE
      PRINT B$, LEN(B$)
      PRINT A$, LEN(A$)
   END IF

END SUB

CALL comp("abcd", "123456789") END</lang>

Output:
Igual que la entrada de FreeBASIC.

Yabasic

<lang yabasic>sub comp(A$, B$)

   if len(A$) >= len(B$) then 
       print A$, chr$(9), len(A$)
       print B$, chr$(9), len(B$)
   else
       print B$, chr$(9), len(B$)
       print A$, chr$(9), len(A$)
   end if

end sub

comp("abcd", "123456789")</lang>

FreeBASIC

<lang freebasic>sub comp( A as string, B as string )

   if len(A)>=len(B) then 
       print A, len(A)
       print B, len(B)
   else
       print B, len(B)
       print A, len(A)
   end if

end sub

comp( "abcd", "123456789" )</lang>

Output:
123456789      9
abcd           4

Fortran

Normally would use an external library for sorting, but to remain self-contained, created (a very inefficient) sort_int() procedure. <lang fortran> program demo_sort_indexed implicit none

  call print_sorted_by_length( [character(len=20) :: "shorter","longer"] )
  call print_sorted_by_length( [character(len=20) :: "abcd","123456789","abcdef","1234567"] )
  call print_sorted_by_length( [character(len=20) :: 'the','quick','brown','fox','jumps','over','the','lazy','dog'])

contains

subroutine print_sorted_by_length(list) character(len=*) :: list(:) integer :: i

  list(sort_int(len_trim(list)))=list ! sort by length from small to large
  write(*,'(i9,1x,a)')(len_trim(list(i)), list(i),i=size(list),1,-1)! print from last to first
  write(*,*)

end subroutine print_sorted_by_length

function sort_int(input) result(counts) ! **very** inefficient mini index sort integer :: input(:), counts(size(input)), i

  counts=[(count(input(i) > input)+count(input(i) == input(:i)),i=1, size(input) )]

end function sort_int

end program demo_sort_indexed </lang>

Output:
        7 shorter             
        6 longer              

        9 123456789           
        7 1234567             
        6 abcdef              
        4 abcd                

        5 jumps               
        5 brown               
        5 quick               
        4 lazy                
        4 over                
        3 dog                 
        3 the                 
        3 fox                 
        3 the                 

{header|FutureBasic}

<lang futurebasic>local fn MyArraySortFunction( obj1 as CFTypeRef, obj2 as CFTypeRef, context as ptr ) as NSComparisonResult

 NSComparisonResult result = NSOrderedDescending
 if len(obj1) >= len(obj2) then result = NSOrderedAscending

end fn = result

void local fn DoIt

 CFStringRef string1 = @"abcd", string2 = @"abcdef", s
 if len(string1) >= len(string2)
   print string1,len(string1)
   print string2,len(string2)
 else
   print string2,len(string2)
   print string1,len(string1)
 end if
 print
 text ,,,,, 85
 CFArrayRef strings = @[@"abcd",@"123456789",@"abcdef",@"1234567"]
 strings = fn ArraySortedArrayUsingFunction( strings, @fn MyArraySortFunction, NULL )
 for s in strings
   print s,len(s)
 next

end fn

window 1

fn DoIt

HandleEvents</lang>

Output:

abcdef  6
abcd    4

123456789  9
1234567    7
abcdef     6
abcd       4

Harbour

We can, easily, realize this task with Harbour, utilizing its strong array-handling set of functions. <lang visualfoxpro>

PROCEDURE Main() LOCAL s1 := "The long string" LOCAL s2 := "The short string" LOCAL a  := { s1, s2 } LOCAL s3

? s3 := "Here is how you can print the longer string first using Harbour language" ? ? "-------------------------------------------" PrintTheLongerFirst( a )

a := hb_ATokens( s3, " " ) ? "-------------------------------------------" PrintTheLongerFirst( a ) ? "-------------------------------------------" RETURN

FUNCTION PrintTheLongerFirst( a ) LOCAL n, tmp a := ASort( a,,, {|x,y| Len(x) > Len(y) } ) n:= Len( a[1] ) AEval( a, { |e| tmp := n-Len(e), Qout( e, Space(tmp) + ; hb_strFormat( "(length = %d chars)", Len(e) ) ) } ) RETURN NIL </lang> Output:

Here is how you can print the longer string first using Harbour language
-------------------------------------------
The short string (length = 16 chars)
The long string  (length = 15 chars)
-------------------------------------------
language (length = 8 chars)
Harbour  (length = 7 chars)
longer   (length = 6 chars)
string   (length = 6 chars)
print    (length = 5 chars)
first    (length = 5 chars)
using    (length = 5 chars)
Here     (length = 4 chars)
how      (length = 3 chars)
you      (length = 3 chars)
can      (length = 3 chars)
the      (length = 3 chars)
is       (length = 2 chars)
-------------------------------------------

Haskell

Using native String type: <lang haskell>task s1 s2 = do

 let strs = if length s1 > length s2 then [s1, s2] else [s2, s1]
 mapM_ (\s -> putStrLn $ show (length s) ++ "\t" ++ show s) strs</lang>
λ> task "short string" "longer string"
13	"longer string"
12	"short string"

λ> Data.List.sortOn length ["abcd","123456789","abcdef","1234567"]
["abcd","abcdef","1234567","123456789"]

Data.List.sortOn (negate . length) ["abcd","123456789","abcdef","1234567"]
["123456789","1234567","abcdef","abcd"]

or more practically useful Text: <lang haskell>import qualified Data.Text as T

taskT s1 s2 = do

 let strs = if T.length s1 > T.length s2 then [s1, s2] else [s2, s1]
 mapM_ (\s -> putStrLn $ show (T.length s) ++ "\t" ++ show s) strs</lang>
λ> :set -XOverloadedStrings
λ> taskT "short string" "longer string"
13	"longer string"
12	"short string"

J

   NB. solution
   NB. `Haruno-umi Hinemosu-Notari Notarikana'
   NB. Spring ocean ; Swaying gently ; All day long.

   ,/ _2 }.\ ": (;~ #)&>  <@(7&u:);._2 '春の海 ひねもすのたり のたりかな '
│3│春の海        │    
│7│ひねもすのたり│
│5│のたりかな    │  
                         

   NB.  # y  is the tally of items (penultimate dimension) in the array y
   # 323 43 5j3
3
   
   # 'literal (a string)'
18
   
   /: 'cbad'   NB. index ordering vector (grade up)
2 1 0 3
   
   ;: 'j tokenize a sentence.'
┌─┬────────┬─┬─────────┐
│j│tokenize│a│sentence.│
└─┴────────┴─┴─────────┘
   
   #S:0 ;: 'j tokenize a sentence.'  NB. length of leaves (lowest box level)
1 8 1 9
  
   A=: '1234567 abcd 123456789 abcdef'  NB. global assignment

   (\: #S:0) ;: A  NB. order by grade down
┌─────────┬───────┬──────┬────┐
│123456789│1234567│abcdef│abcd│
└─────────┴───────┴──────┴────┘
   
   (;:'length literal') , ((;~ #)&> \: #S:0) ;: A  NB. box incompatible types with header
┌──────┬─────────┐
│length│literal  │
├──────┼─────────┤
│9     │123456789│
├──────┼─────────┤
│7     │1234567  │
├──────┼─────────┤
│6     │abcdef   │
├──────┼─────────┤
│4     │abcd     │
└──────┴─────────┘

   (;:'len vector') , ((;~ #)&> \: #S:0) 0 1 2 3 ; 0 1 ; (i. 8) ; 0
┌───┬───────────────┐
│len│vector         │
├───┼───────────────┤
│8  │0 1 2 3 4 5 6 7│
├───┼───────────────┤
│4  │0 1 2 3        │
├───┼───────────────┤
│2  │0 1            │
├───┼───────────────┤
│1  │0              │
└───┴───────────────┘

Java

Works with: Java version 11
Works with: Java version 17

<lang Java>package stringlensort;

import java.io.PrintStream; import java.util.Arrays; import java.util.Comparator;

public class ReportStringLengths {

   public static void main(String[] args) {
       String[] list = {"abcd", "123456789", "abcdef", "1234567"};
       String[] strings = args.length > 0 ? args : list;
       compareAndReportStringsLength(strings);
   }
   /**
    * Compare and report strings length to System.out.
    * 
    * @param strings an array of strings
    */    
   public static void compareAndReportStringsLength(String[] strings) {
       compareAndReportStringsLength(strings, System.out);
   }
   /**
    * Compare and report strings length.
    * 
    * @param strings an array of strings
    * @param stream the output stream to write results
    */
   public static void compareAndReportStringsLength(String[] strings, PrintStream stream) {
       if (strings.length > 0) {
           strings = strings.clone();
           final String QUOTE = "\"";
           Arrays.sort(strings, Comparator.comparing(String::length));
           int min = strings[0].length();
           int max = strings[strings.length - 1].length();
           for (int i = strings.length - 1; i >= 0; i--) {
               int length = strings[i].length();
               String predicate;
               if (length == max) {
                   predicate = "is the longest string";
               } else if (length == min) {
                   predicate = "is the shortest string";
               } else {
                   predicate = "is neither the longest nor the shortest string";
               }
               //@todo: StringBuilder may be faster
               stream.println(QUOTE + strings[i] + QUOTE + " has length " + length
                       + " and " + predicate);
           }
       }
   }

}</lang>

Output:
"123456789" has length 9 and is the longest string
"1234567" has length 7 and is neither the longest nor the shortest string
"abcdef" has length 6 and is neither the longest nor the shortest string
"abcd" has length 4 and is the shortest string

JavaScript

JavaScript (ECMA Script) file stringlensort.js. <lang javascript>/**

* Compare and report strings lengths.
* 
* @param {Element} input - a TextArea DOM element with input
* @param {Element} output - a TextArea DOM element for output
*/

function compareStringsLength(input, output) {

 // Safe defaults.
 //
 output.value = "";
 let output_lines = [];
 // Split input into an array of lines.
 //
 let strings = input.value.split(/\r\n|\r|\n/g);
 // Is strings array empty?
 //
 if (strings && strings.length > 0) {
   // Remove leading and trailing spaces.
   //
   for (let i = 0; i < strings.length; i++)
     strings[i] = strings[i].trim();
   // Sort by lengths.
   //
   strings.sort((a, b) => a.length - b.length);
   // Remove empty strings.
   //
   while (strings[0] == "")
     strings.shift();
   // Check if any strings remain.
   //
   if (strings && strings.length > 0) {
     // Get min and max length of strings.
     //
     const min = strings[0].length;
     const max = strings[strings.length - 1].length;
     // Build output verses - longest strings first.
     //
     for (let i = strings.length - 1; i >= 0; i--) {
       let length = strings[i].length;
       let predicate;
       if (length == max) {
         predicate = "is the longest string";
       } else if (length == min) {
         predicate = "is the shortest string";
       } else {
         predicate = "is neither the longest nor the shortest string";
       }
       output_lines.push(`"${strings[i]}" has length ${length} and ${predicate}\n`);
     }
     // Send all lines from output_lines array to an TextArea control.
     //
     output.value = output_lines.join();
   }
 }

}

document.getElementById("input").value = "abcd\n123456789\nabcdef\n1234567"; compareStringsLength(input, output);</lang> HTML file (with embeded CSS) to run the script. <lang HTML><html>

<head>

 <style>
   div {
     margin-top: 4ch;
     margin-bottom: 4ch;
   }
   label {
     display: block;
     margin-bottom: 1ch;
   }
   textarea {
     display: block;
   }
   input {
     display: block;
     margin-top: 4ch;
     margin-bottom: 4ch;
   }
 </style>

</head>

<body>

 <main>
   <form>
       <label for="input">Input:
       </label>
       <textarea rows="20" cols="80" id="input"></textarea>
     <input type="button" value="press to compare strings" onclick="compareStringsLength(input, output);">
     </input>
       <label for="output">Output:
       </label>
       <textarea rows="20" cols="80" id="output"></textarea>
   </form>
 </main>
 <script src="stringlensort.js"></script>

</body>

</html></lang>

Output:
"123456789" has length 9 and is the longest string
"1234567" has length 7 and is neither the longest nor the shortest string
"abcdef" has length 6 and is neither the longest nor the shortest string
"abcd" has length 4 and is the shortest string

Julia

Per the Julia docs, a String in Julia is a sequence of characters encoded as UTF-8. Most string methods in Julia actually accept an AbstractString, which is the supertype of strings in Julia regardless of the encoding, including the default UTF-8.

The Char data type in Julia is a 32-bit, potentially Unicode data type, so that if we enumerate a String as a Char array, we get a series of 32-bit characters: <lang julia>s = "niño" println("Position Char Bytes\n==============================") for (i, c) in enumerate(s)

   println("$i          $c     $(sizeof(c))")

end

</lang>

Output:
Position  Char Bytes
==============================
1          n     4
2          i     4
3          ñ     4
4          o     4

However, if we index into the string, the index into the string will function as if the string was an ordinary C string, that is, an array of unsigned 8-bit integers. If the index attempts to index within a character of size greater than one byte, an error is thrown for bad indexing. This can be demonstrated by casting the above string to codeunits: <lang julia>println("Position Codeunit Bytes\n==============================") for (i, c) in enumerate(codeunits(s))

   println("$i            $(string(c, base=16))     $(sizeof(c))")

end

</lang>

Output:
Position  Codeunit Bytes
==============================
1            6e     1
2            69     1
3            c3     1
4            b1     1
5            6f     1

Note that the length of "niño" as a String is 4 characters, and the length of "niño" as codeunits (ie, 8 bit bytes) is 5. Indexing into the 4th position results in an error: <lang julia> julia> s[4] ERROR: StringIndexError: invalid index [4], valid nearby indices [3]=>'ñ', [5]=>'o' </lang>

So, whether a string is longer or shorter depends on the encoding, as below: <lang julia>length("ñññ") < length("nnnn") # true, and the usual meaning of length of a String

length(codeunits("ñññ")) > length(codeunits("nnnn")) # true as well </lang>

jq

Works with: jq

Works with gojq, the Go implementation of jq <lang jq> def s1: "longer"; def s2: "shorter😀";

[s1,s2] | sort_by(length) | reverse[] | "\"\(.)\" has length (codepoints) \(length) and utf8 byte length \(utf8bytelength)."

</lang>

Output:
"shorter😀" has length (codepoints) 8 and utf8 byte length 11.
"longer" has length (codepoints) 6 and utf8 byte length 6.

Lambdatalk

Lambdatalk comes with primitives working on words, [W.equal?, W.length, ...], on sentences, [S.empty?, S.first, S.rest, ...] and pairs, [P.new, P.left, P.right, ...].

Using these primitives we define 2 helper functions, [L.new, L.disp], to build and display a list according to a chosen format. <lang Scheme> {def L.new

{lambda {:s}
 {if {S.empty? {S.rest :s}}
  then {P.new {S.first :s} nil}
  else {P.new {S.first :s} {L.new {S.rest :s}}}}}}

-> L.new

{def L.disp

{lambda {:l}
 {if {W.equal? :l nil}
  then 
  else {br} {W.length {P.left :l}} : {P.left :l}
       {L.disp {P.right :l}}}}}

-> L.disp </lang>

For instance

<lang Scheme> {def B {L.new abcd 123456789 abcdef 1234567}} -> B

{L.disp {B}} ->

4 : abcd 
9 : 123456789 
6 : abcdef 
7 : 1234567

</lang>

Then we define the L.sort function waiting for a predicate function and a list.

<lang Scheme> {def L.sort

{lambda {:filter :l} 
 {if {W.equal? :l nil} 
  then nil 
  else {L.insert {P.left :l} :filter
                 {L.sort :filter {P.right :l}}}}}}

-> L.sort

{def L.insert

{lambda {:x :filter :l} 
 {if {W.equal? :l nil} 
  then {P.new :x nil} 
  else {if {:filter :x {P.left :l}} 
  then {P.new :x :l} 
  else {P.new {P.left :l}
             {L.insert :x :filter {P.right :l}}}}}}}

-> L.insert </lang>

Using the following predicate function (which could be anonymous) testing the length of 2 words

<lang Scheme> {def filter

{lambda {:a :b}
 {> {W.length :a} {W.length :b}}}}

-> filter </lang>

we display the B list sorted according to the length of its elements.

<lang Scheme> {L.disp {L.sort filter {B}}} ->

9 : 123456789 
7 : 1234567 
6 : abcdef 
4 : abcd

</lang>

Note that in lambdatalk words (and numbers) don't need to be quoted.

Lua

<lang lua>function test(list)

 table.sort(list, function(a,b) return #a > #b end)
 for _,s in ipairs(list) do print(#s, s) end

end test{"abcd", "123456789", "abcdef", "1234567"}</lang>

Output:
9       123456789
7       1234567
6       abcdef
4       abcd

Mathematica / Wolfram Language

<lang Mathematica>list = {"abcd", "123456789", "abcdef", "1234567"}; Reverse@SortBy[list, StringLength] // TableForm</lang>

Output:

123456789 1234567 abcdef abcd

Nim

In Nim, a character (char) is represented on a byte. A string is a sequence of characters with a length. For interoperability reason, an extra null is added at the end of the characters. A string is supposed to be encoded in UTF-8, but this is not enforced. The function len returns the length of the string i.e. its number of characters (without the extra null).

If we want to manage a string as a Unicode sequence of code points, we have to use the module unicode. We can convert a string in a sequence of runes, each rune being a unicode UTF-32 value. The length of this sequence is the number of code points.

<lang Nim>import strformat, unicode

const

 S1 = "marche"
 S2 = "marché"

echo &"“{S2}”, byte length = {S2.len}, code points: {S2.toRunes.len}" echo &"“{S1}”, byte length = {S1.len}, code points: {S1.toRunes.len}"</lang>

Output:
“marché”, byte length = 7, code points: 6
“marche”, byte length = 6, code points: 6

Pascal

Works with: Extended Pascal

<lang pascal>program compareLengthOfStrings(output);

const specimenA = 'RosettaCode'; specimenB = 'Pascal'; specimenC = 'Foobar'; specimenD = 'Pascalish';

type specimen = (A, B, C, D); specimens = set of specimen value [];

const specimenMinimum = A; specimenMaximum = D;

var { the explicit range min..max serves as a safeguard to update max const } list: array[specimenMinimum..specimenMaximum] of string(24) value [A: specimenA; B: specimenB; C: specimenC; D: specimenD]; lengthRelationship: array[specimen] of specimens;

procedure analyzeLengths; var left, right: specimen; begin for left := specimenMinimum to specimenMaximum do begin for right := specimenMinimum to specimenMaximum do begin if length(list[left]) < length(list[right]) then begin lengthRelationship[right] := lengthRelationship[right] + [right] end end end end;

procedure printSortedByLengths; var i: ord(specimenMinimum)..ord(specimenMaximum); s: specimen; begin { first the string longer than all other strings } { lastly print the string not longer than any other string } for i := ord(specimenMaximum) downto ord(specimenMinimum) do begin { for demonstration purposes: iterate over a set } for s in [specimenMinimum..specimenMaximum] do begin { card returns the cardinality ("population count") } if card(lengthRelationship[s]) = i then begin writeLn(length(list[s]):8, ' ', list[s]) end end end end;

begin analyzeLengths; printSortedByLengths end.</lang>

Output:
      11 RosettaCode
       9 Pascalish
       6 Pascal
       6 Foobar

Perl

<lang perl>#!/usr/bin/perl

use strict; # https://rosettacode.org/wiki/Compare_length_of_two_strings use warnings;

for ( 'shorter thelonger', 'abcd 123456789 abcdef 1234567' )

 {
 print "\nfor strings => $_\n";
 printf "length %d: %s\n", length(), $_
   for sort { length $b <=> length $a } split;
 }</lang>
Output:

for strings => shorter thelonger
length 9: thelonger
length 7: shorter

for strings => abcd 123456789 abcdef 1234567
length 9: 123456789
length 7: 1234567
length 6: abcdef
length 4: abcd

Phix

Lengths are in bytes, for codepoints use length(utf8_to_utf32()) or similar.

with javascript_semantics
sequence list = {"abcd","123456789","abcdef","1234567"},
         lens = apply(list,length),
         tags = reverse(custom_sort(lens,tagset(length(lens))))
papply(true,printf,{1,{"%s (length %d)\n"},columnize({extract(list,tags),extract(lens,tags)})})
Output:
123456789 (length 9)
1234567 (length 7)
abcdef (length 6)
abcd (length 4)

PHP

<lang PHP> <?php


function retrieveStrings() {

   if (isset($_POST['input'])) {
       $strings = explode("\n", $_POST['input']);
   } else {
       $strings = ['abcd', '123456789', 'abcdef', '1234567'];
   }
   return $strings;

}


function setInput() {

   echo join("\n", retrieveStrings());

}


function setOutput() {

   $strings = retrieveStrings();
   // Remove empty strings
   //
   $strings = array_map('trim', $strings);
   $strings = array_filter($strings);
   if (!empty($strings)) {
       usort($strings, function ($a, $b) {
           return strlen($b) - strlen($a);
       });
       $max_len = strlen($strings[0]);
       $min_len = strlen($strings[count($strings) - 1]);
       foreach ($strings as $s) {
           $length = strlen($s);
           if ($length == $max_len) {
               $predicate = "is the longest string";
           } elseif ($length == $min_len) {
               $predicate = "is the shortest string";
           } else {
               $predicate = "is neither the longest nor the shortest string";
           }
           echo "$s has length $length and $predicate\n";
       }
   }

}

?>


<!DOCTYPE html> <html lang="en">

<head>

   <style>
       div {
           margin-top: 4ch;
           margin-bottom: 4ch;
       }
       label {
           display: block;
           margin-bottom: 1ch;
       }
       textarea {
           display: block;
       }
       input {
           display: block;
           margin-top: 4ch;
           margin-bottom: 4ch;
       }
   </style>

</head>


<body>

   <main>
       <form action=<?php echo $_SERVER['SCRIPT_NAME'] ?> method="post" accept-charset="utf-8">
               <label for="input">Input:
               </label>
               <textarea rows='20' cols='80' name='input'><?php setInput(); ?></textarea>
               </label>
           <input type="submit" value="press to compare strings">
           </input>
               <label for="Output">Output:
               </label>
               <textarea rows='20' cols='80' name='output'><?php setOutput(); ?></textarea>
       </form>
   </main>

</body>

</html></lang>

Python

Naive solution

Works with: Python version 3.8

<lang Python>A = 'I am string' B = 'I am string too'

if len(A) > len(B):

   print('"' + A + '"', 'has length', len(A), 'and is the longest of the two strings')
   print('"' + B + '"', 'has length', len(B), 'and is the shortest of the two strings')

elif len(A) < len(B):

   print('"' + B + '"', 'has length', len(B), 'and is the longest of the two strings')
   print('"' + A + '"', 'has length', len(A), 'and is the shortest of the two strings')

else:

   print('"' + A + '"', 'has length', len(A), 'and it is as long as the second string')
   print('"' + B + '"', 'has length', len(B), 'and it is as long as the second string')</lang>
Output:
"I am string too" has length 15 and is the longest of the two strings
"I am string" has length 11 and is the shortest of the two strings

Advanced solution

Works with: Python version 3.8

The solution below has some imperfection. When the longest strings of characters are of equal length, instead of describing them as "one of the longest" they are described as "the longest". This works similarly for the shortest strings. Also, if all strings (in this case where there is only one) have the same length it is not printed that they are the shortest strings. Of course, this could be improved.

<lang Python>""" An example code for the task "Compare length of two strings" (Rosseta Code).

This example code can handle not only strings, but any objects. """


def _(message):

   """Translate: an placeholder for i18n and l10n gettext or similar."""
   return message


def compare_and_report_length(*objects, sorted_=True, reverse=True):

   """
   For objects given as parameters it prints which of them are the longest.
   So if the parameters are strings, then the strings are printed, their
   lengths and classification as the longest, shortest or average length.
   Note that for N > 0 such objects (e.g., strings, bytes, lists) it is
   possible that exactly M > 0 of them will be of the maximum length, K > 0 of
   them will be of the minimum length. In particular, it is possible that all
   objects will be exactly the same length. So we assume that if an object has
   both the maximum and minimum length, it is referred to as a string with the
   maximum length.
   Args:
       *objects (object): Any objects with defined length.
       sorted_ (bool, optional): If sorted_ is False then objects are not
               sorted. Defaults to True.
       reverse (bool, optional): If reverse is True and sorted_ is True
               objects are sorted in the descending order. If reverse is False
               and sorted_ is True objects are sorted in the ascending order.
               Defaults to True.
   Returns:
       None.
   """
   lengths = list(map(len, objects))
   max_length = max(lengths)
   min_length = min(lengths)
   lengths_and_objects = zip(lengths, objects)
   # Longer phrases make translations into other natural languages easier.
   #
   has_length = _('has length')
   if all(isinstance(obj, str) for obj in objects):
       predicate_max = _('and is the longest string')
       predicate_min = _('and is the shortest string')
       predicate_ave = _('and is neither the longest nor the shortest string')
   else:
       predicate_max = _('and is the longest object')
       predicate_min = _('and is the shortest object')
       predicate_ave = _('and is neither the longest nor the shortest object')
   if sorted_:
       lengths_and_objects = sorted(lengths_and_objects, reverse=reverse)
   for length, obj in lengths_and_objects:
       if length == max_length:
           predicate = predicate_max
       elif length == min_length:
           predicate = predicate_min
       else:
           predicate = predicate_ave
       print(obj, has_length, length, predicate)


A = 'I am string' B = 'I am string too' LIST = ["abcd", "123456789", "abcdef", "1234567"]


print('Two strings') print() compare_and_report_length(A, B) print()

print('A list of strings') print() compare_and_report_length(*LIST) print() </lang>

Output:
Two strings

"I am string too" has length 15 and is the longest string
"I am string" has length 11 and is the shortest string

A list of strings

"123456789" has length 9 and is the longest string
"1234567" has length 7 and is neither the longest nor the shortest string
"abcdef" has length 6 and is neither the longest nor the shortest string
"abcd" has length 4 and is the shortest string

QB64

<lang QB64> Dim Words(1 To 4) As String Dim Lengths As Integer, Index As Integer, Position As Integer, Done As String, Index2 As Integer ' inititialization Words(1) = "abcd" Words(2) = "123456789" Words(3) = "abcdef" Words(4) = "1234567"

Print " Word Length" For Index2 = 1 To 4 Step 1

   Lengths = 0
   Position = 0
   For Index = 1 To 4 Step 1
       If Lengths < Len(Words(Index)) And InStr(Done, Words(Index) + " ") = 0 Then
           Lengths = Len(Words(Index))
           Position = Index
       End If
   Next Index
   Done = Done + Words(Position) + " /@/"
   Print Words(Position), Len(Words(Position))

Next Index2 </lang>

Quackery

<lang Quackery> $ "A short string of"

 $ "A slightly longer string of"
  
 2dup size dip size > if swap 
 dup echo$ sp size echo say " characters." cr
 dup echo$ sp size echo say " characters." cr cr
 '  [ $ "From troubles of the world I turn to ducks,"
      $ "Beautiful comical things"
      $ "Sleeping or curled"
      $ "Their heads beneath white wings"
      $ "By water cool,"
      $ "Or finding curious things"
      $ "To eat in various mucks"
      $ "Beneath the pool," ] 
  []  swap witheach [ do nested join ]

 sortwith [ size dip size < ]
 witheach [ echo$ cr ] </lang>
Output:
A slightly longer string of 27 characters.
A short string of 17 characters.

From troubles of the world I turn to ducks,
Their heads beneath white wings
Or finding curious things
Beautiful comical things
To eat in various mucks
Sleeping or curled
Beneath the pool,
By water cool,

Raku

So... In what way does this task differ significantly from String length? Other than being horribly under specified?

In the modern world, string "length" is pretty much a useless measurement, especially in the absence of a specified encoding; hence Raku not even having an operator: "length" for strings.

<lang perl6>say 'Strings (👨‍👩‍👧‍👦, 🤔🇺🇸, BOGUS!) sorted: "longest" first:'; say "$_: characters:{.chars}, Unicode code points:{.codes}, UTF-8 bytes:{.encode('UTF8').bytes}, UTF-16 bytes:{.encode('UTF16').bytes}" for <👨‍👩‍👧‍👦 BOGUS! 🤔🇺🇸>.sort: -*.chars;</lang>

Output:
Strings (👨‍👩‍👧‍👦, 🤔🇺🇸, BOGUS!) sorted: "longest" first:
BOGUS!: characters:6,  Unicode code points:6,  UTF-8 bytes:6,  UTF-16 bytes:12
🤔🇺🇸: characters:2,  Unicode code points:3,  UTF-8 bytes:12,  UTF-16 bytes:12
👨‍👩‍👧‍👦: characters:1,  Unicode code points:7,  UTF-8 bytes:25,  UTF-16 bytes:22

REXX

<lang rexx>/* REXX */ list = '"abcd","123456789","abcdef","1234567"' Do i=1 By 1 While list>

 Parse Var list s.i ',' list
 s.i=strip(s.i,,'"')
 End

n=i-1 Do While n>1

 max=0
 Do i=1 To n
   If length(s.i)>max Then Do
     k=i
     max=length(s.i)
     End
   End
 Call o s.k
 If k<n Then
   s.k=s.n
 n=n-1
 End

Call o s.1 Exit o: Say length(arg(1)) arg(1) Return</lang>

Output:
9 123456789
7 1234567
6 abcdef
4 abcd

Ring

Two strings

<lang ring> see "working..." + nl

list = ["abcd","123456789"] if len(list[1]) > len(list[2])

  first = list[1]
  second = list[2]

else

  first = list[2]
  second = list[1]

ok

see "Compare length of two strings:" + nl see "" + first + " len = " + len(first) + nl + second + " len = " + len(second) + nl see "done..." + nl </lang>

Output:
working...
Compare length of two strings:
123456789 len = 9
abcd len = 4
done...

More than two strings

<lang ring> see "working..." + nl

lenList = [] list = ["abcd","123456789","abcdef","1234567"] for n = 1 to len(list)

   len = len(list[n])
   add(lenList,[len,n])

next

lenList = sort(lenList,1) lenList = reverse(lenList)

see "Compare length of strings in descending order:" + nl for n = 1 to len(lenList)

   see "" + list[lenList[n][2]] + " len = " + lenList[n][1] + nl

next see "done..." + nl </lang>

Output:
working...
Compare length of strings in descending order:
123456789 len = 9
1234567 len = 7
abcdef len = 6
abcd len = 4
done...

Rust

<lang Rust> fn compare_and_report<T: ToString>(string1: T, string2: T) -> String {

   let strings = [string1.to_string(), string2.to_string()];
   let difference = strings[0].len() as i32 - strings[1].len() as i32;
   if difference == 0 { // equal
       format!("\"{}\" and \"{}\" are of equal length, {}", strings[0], strings[1], strings[0].len())
   } else if difference > 1 { // string1 > string2
       format!("\"{}\" has length {} and is the longest\n\"{}\" has length {} and is the shortest", strings[0], strings[0].len(), strings[1], strings[1].len())
   } else { // string2 > string1
       format!("\"{}\" has length {} and is the longest\n\"{}\" has length {} and is the shortest", strings[1], strings[1].len(), strings[0], strings[0].len())
   }

}

fn main() {

   println!("{}", compare_and_report("a", "b"));
   println!("\n{}", compare_and_report("cd", "e"));
   println!("\n{}", compare_and_report("f", "gh"));

} </lang>

Output:
"a" and "a" are of equal length, 1

"d" has length 1 and is the longest  
"bc" has length 2 and is the shortest

"fg" has length 2 and is the longest 
"e" has length 1 and is the shortest


Vlang

<lang go>// Compare lenth of two strings, in V // Tectonics: v run compare-length-of-two-strings.v module main

// starts here pub fn main() {

   mut strs := ["abcd","123456789"]
   println("Given: $strs")
   strs.sort_by_len()
   for i := strs.len-1; i >= 0; i-- {
       println("${strs[i]}: with length ${strs[i].len}")
   }
   // more than 2 strings. note = vs :=, := for definition, = for assignment
   strs = ["abcd","123456789","abcdef","1234567"]
   println("\nGiven: $strs")
   strs.sort_by_len()
   for i := strs.len-1; i >= 0; i-- {
       println("${strs[i]}: with length ${strs[i].len}")
   }

}</lang>

Output:
prompt$ v run compare-length-of-two-strings.v
Given: ['abcd', '123456789']
123456789: with length 9
abcd: with length 4

Given: ['abcd', '123456789', 'abcdef', '1234567']
123456789: with length 9
1234567: with length 7
abcdef: with length 6
abcd: with length 4

Wren

Library: Wren-upc

In Wren a string (i.e. an object of the String class) is an immutable sequence of bytes which is usually interpreted as UTF-8 but does not have to be.

With regard to string length, the String.count method returns the number of 'codepoints' in the string. If the string contains bytes which are invalid UTF-8, each such byte adds one to the count.

To find the number of bytes one can use String.bytes.count.

Unicode grapheme clusters, where what appears to be a single 'character' may in fact be an amalgam of several codepoints, are not directly supported by Wren but it is possible to measure the length in grapheme clusters of a string (i.e. the number of user perceived characters) using the Graphemes.clusterCount method of the Wren-upc module. <lang ecmascript>import "./upc" for Graphemes

var printCounts = Fn.new { |s1, s2, c1, c2|

  var l1 = (c1 > c2) ? [s1, c1] : [s2, c2]
  var l2 = (c1 > c2) ? [s2, c2] : [s1, c1]
  System.print(  "%(l1[0]) : length %(l1[1])")
  System.print(  "%(l2[0]) : length %(l2[1])\n")

}

var codepointCounts = Fn.new { |s1, s2|

  var c1 = s1.count
  var c2 = s2.count
  System.print("Comparison by codepoints:")
  printCounts.call(s1, s2, c1, c2)

}

var byteCounts = Fn.new { |s1, s2|

  var c1 = s1.bytes.count
  var c2 = s2.bytes.count
  System.print("Comparison by bytes:")
  printCounts.call(s1, s2, c1, c2)

}

var graphemeCounts = Fn.new { |s1, s2|

  var c1 = Graphemes.clusterCount(s1)
  var c2 = Graphemes.clusterCount(s2)
  System.print("Comparison by grapheme clusters:")
  printCounts.call(s1, s2, c1, c2)

}

for (pair in [ ["nino", "niño"], ["👨‍👩‍👧‍👦", "🤔🇺🇸"] ]) {

   codepointCounts.call(pair[0], pair[1])
   byteCounts.call(pair[0], pair[1])
   graphemeCounts.call(pair[0], pair[1])

}

var list = ["abcd", "123456789", "abcdef", "1234567"] System.write("Sorting in descending order by length in codepoints:\n%(list) -> ") list.sort { |a, b| a.count > b.count } System.print(list)</lang>

Output:
Comparison by codepoints:
niño : length 4
nino : length 4

Comparison by bytes:
niño : length 5
nino : length 4

Comparison by grapheme clusters:
niño : length 4
nino : length 4

Comparison by codepoints:
👨‍👩‍👧‍👦 : length 7
🤔🇺🇸 : length 3

Comparison by bytes:
👨‍👩‍👧‍👦 : length 25
🤔🇺🇸 : length 12

Comparison by grapheme clusters:
🤔🇺🇸 : length 2
👨‍👩‍👧‍👦 : length 1

Sorting in descending order by length in codepoints:
[abcd, 123456789, abcdef, 1234567] -> [123456789, 1234567, abcdef, abcd]

XPL0

<lang XPL0>string 0; \use zero-terminated string convention

func StrLen(A); \Return number of characters in an ASCIIZ string char A; int I; for I:= 0 to -1>>1 do

       if A(I) = 0 then return I;

char List; int M, N, SN, Len, Max; [List:= ["abcd","123456789","abcdef","1234567"]; for M:= 0 to 3 do

   [Max:= 0;
   for N:= 0 to 3 do
       [Len:= StrLen(@List(N,0));
       if Len > Max then [Max:= Len;  SN:= N];
       ];
   Text(0, @List(SN,0));
   Text(0, " length is ");  IntOut(0, StrLen(@List(SN,0)));  CrLf(0);
   List(SN, 0):= 0;    \truncate largest string
   ];

]</lang>

Output:
123456789 length is 9
1234567 length is 7
abcdef length is 6
abcd length is 4

Z80 Assembly

<lang z80>Terminator equ 0 ;null terminator PrintChar equ &BB5A ;Amstrad CPC BIOS call, prints accumulator to screen as an ASCII character.

       org &8000

ld hl,String1 ld de,String2 call CompareStringLengths

jp nc, Print_HL_First ex de,hl Print_HL_First: push bc push hl call PrintString pop hl push hl ld a,' ' call PrintChar call getStringLength ld a,b call ShowHex_NoLeadingZeroes call NewLine pop hl pop bc

ex de,hl push bc push hl call PrintString pop hl push hl ld a,' ' call PrintChar call getStringLength ld a,b call ShowHex_NoLeadingZeroes call NewLine pop hl pop bc ReturnToBasic: RET

String1: byte "Hello",Terminator String2: byte "Goodbye",Terminator

RELEVANT SUBROUTINES - PRINTSTRING AND NEWLINE CREATED BY KEITH S. OF CHIBIAKUMAS

CompareStringLengths: ;HL = string 1 ;DE = string 2 ;CLOBBERS A,B,C push hl push de ex de,hl call GetStringLength ld b,c

ex de,hl call GetStringLength ld a,b cp c pop de pop hl ret ;returns carry set if HL < DE, zero set if equal, zero & carry clear if HL >= DE ;returns len(DE) in C, and len(HL) in B.

GetStringLength: ld b,0 loop_getStringLength: ld a,(hl) cp Terminator ret z inc hl inc b jr loop_getStringLength

NewLine: push af ld a,13 ;Carriage return call PrintChar ld a,10 ;Line Feed call PrintChar pop af ret

PrintString: ld a,(hl) cp Terminator ret z inc hl call PrintChar jr PrintString

ShowHex_NoLeadingZeroes:

useful for printing values where leading zeroes don't make sense,
such as money etc.

push af and %11110000 ifdef gbz80 ;game boy swap a else ;zilog z80 rrca rrca rrca rrca endif or a call nz,PrintHexChar ;if top nibble of A is zero, don't print it. pop af and %00001111 or a ret z ;if bottom nibble of A is zero, don't print it! jp PrintHexChar

PrintHexChar: or a ;Clear Carry Flag daa add a,&F0 adc a,&40 ;This sequence converts a 4-bit hex digit to its ASCII equivalent. jp PrintChar</lang>

Output:
Goodbye 7
Hello 5