Multiple distinct objects

From Rosetta Code
Task
Multiple distinct objects
You are encouraged to solve this task according to the task description, using any language you may know.

Create a sequence (array, list, whatever) consisting of n distinct, initialized items of the same type. n should be determined at runtime.

By distinct we mean that if they are mutable, changes to one do not affect all others; if there is an appropriate equality operator they are considered unequal; etc. The code need not specify a particular kind of distinction, but do not use e.g. a numeric-range generator which does not generalize.

By initialized we mean that each item must be in a well-defined state appropriate for its type, rather than e.g. arbitrary previous memory contents in an array allocation. Do not show only an initialization technique which initializes only to "zero" values (e.g. calloc() or int a[n] = {}; in C), unless user-defined types can provide definitions of "zero" for that type.

This task was inspired by the common error of intending to do this, but instead creating a sequence of n references to the same mutable object; it might be informative to show the way to do that as well, both as a negative example and as how to do it when that's all that's actually necessary.

This task is most relevant to languages operating in the pass-references-by-value style (most object-oriented, garbage-collected, and/or 'dynamic' languages).

See also: Closures/Value capture

Ada[edit]

A : array (1..N) of T;

Here N can be unknown until run-time. T is any constrained type. In Ada all objects are always initialized, though some types may have null initialization. When T requires a non-null initialization, it is done for each array element. For example, when T is a task type, N tasks start upon initialization of A. Note that T can be a limited type like task. Limited types do not have predefined copy operation. Arrays of non-limited types can also be initialized by aggregates of:

A : array (1..N) of T := (others => V);

Here V is some value or expression of the type T. As an expression V may have side effects, in that case it is evaluated exactly N times, though the order of evaluation is not defined. Also an aggregate itself can be considered as a solution of the task:

(1..N => V)

Aime[edit]

void
show_sublist(list l)
{
integer i, v;
 
for (i, v in l) {
o_space(sign(i));
o_integer(v);
}
}
 
void
show_list(list l)
{
integer i;
list v;
 
for (i, v in l) {
o_text(" [");
show_sublist(v);
o_text("]");
}
 
o_byte('\n');
}
 
list
multiple_distinct(integer n, object o)
{
list l;
 
call_n(n, l_append, l, o);
 
return l;
}
 
integer
main(void)
{
list l, z;
 
# create a list of integers - `3' will serve as initializer
l = multiple_distinct(8, 3);
 
l_clear(l);
 
# create a list of distinct lists - `z' will serve as initializer
l_append(z, 4);
l = multiple_distinct(8, z);
 
# modify one of the sublists
l_q_list(l, 3)[0] = 7;
 
# display the list of lists
show_list(l);
 
return 0;
}
Output:
 [4] [4] [4] [7] [4] [4] [4] [4]

ALGOL 68[edit]

Translation of: python
Works with: ALGOL 68 version Standard - no extensions to language used
Works with: ALGOL 68G version Any - tested with release mk15-0.8b.fc9.i386
Works with: ELLA ALGOL 68 version Any (with appropriate job cards) - tested with release 1.8.8d.fc9.i386
MODE FOO = STRUCT(CHAR u,l);
INT n := 26;
[n]FOO f;
 
# Additionally each item can be initialised #
FOR i TO UPB f DO f[i] := (REPR(ABS("A")-1+i), REPR(ABS("a")-1+i)) OD;
 
print((f, new line))

Output:

AaBbCcDdEeFfGgHhIiJjKkLlMmNnOoPpQqRrSsTtUuVvWwXxYyZz


AppleScript[edit]

-- nObjects Constructor -> Int -> [Object]
on nObjects(f, n)
map(f, range(1, n))
end nObjects
 
 
-- TEST
on run
 
-- someConstructor :: a -> Int -> b
script someConstructor
on lambda(_, i)
{index:i}
end lambda
end script
 
nObjects(someConstructor, 6)
 
--> {{index:1}, {index:2}, {index:3}, {index:4}, {index:5}, {index:6}}
end run
 
 
 
-- GENERIC FUNCTIONS -----------------------------------------------------------
 
-- map :: (a -> b) -> [a] -> [b]
on map(f, xs)
tell mReturn(f)
set lng to length of xs
set lst to {}
repeat with i from 1 to lng
set end of lst to lambda(item i of xs, i, xs)
end repeat
return lst
end tell
end map
 
-- Lift 2nd class handler function into 1st class script wrapper
-- mReturn :: Handler -> Script
on mReturn(f)
if class of f is script then
f
else
script
property lambda : f
end script
end if
end mReturn
 
-- range :: Int -> Int -> [Int]
on range(m, n)
if n < m then
set d to -1
else
set d to 1
end if
set lst to {}
repeat with i from m to n by d
set end of lst to i
end repeat
return lst
end range
Output:
{{index:1}, {index:2}, {index:3}, {index:4}, {index:5}, {index:6}}

AutoHotkey[edit]

Works with: AutoHotkey_L
a := []
Loop, %n%
a[A_Index] := new Foo()

BBC BASIC[edit]

      REM Determine object count at runtime:
n% = RND(1000)
 
REM Declare an array of structures; all members are initialised to zero:
DIM objects{(n%) a%, b$}
 
REM Initialise the objects to distinct values:
FOR i% = 0 TO DIM(objects{()},1)
objects{(i%)}.a% = i%
objects{(i%)}.b$ = STR$(i%)
NEXT
 
REM This is how to create an array of pointers to the same object:
DIM objects%(n%), object{a%, b$}
FOR i% = 0 TO DIM(objects%(),1)
objects%(i%) = object{}
NEXT

Brat[edit]

The wrong way, which creates an array of n references to the same new foo:

n.of foo.new

The right way, which calls the block n times and creates an array of new foos:

n.of { foo.new }

C[edit]

foo *foos = malloc(n * sizeof(*foos));
for (int i = 0; i < n; i++)
init_foo(&foos[i]);

(Or if no particular initialization is needed, skip that part, or use calloc.)

C++[edit]

By default C++ has value semantics, so this problem does not present itself unless the programmer deliberately choses to refer to objects though a pointer. Examples are given for both cases.

Using only language primitives:

// this assumes T is a default-constructible type (all built-in types are)
T* p = new T[n]; // if T is POD, the objects are uninitialized, otherwise they are default-initialized
 
//If default initialisation is not what you want, or if T is a POD type which will be uninitialized
for(size_t i = 0; i != n; ++i)
p[i] = make_a_T(); //or some other expression of type T
 
// when you don't need the objects any more, get rid of them
delete[] p;

Using the standard library

#include <vector>
#include <algorithm>
#include <iterator>
 
// this assumes T is default-constructible
std::vector<T> vec1(n); // all n objects are default-initialized
 
// this assumes t is a value of type T (or a type which implicitly converts to T)
std::vector<T> vec2(n, t); // all n objects are copy-initialized with t
 
// To initialise each value differently
std::generate_n(std::back_inserter(vec), n, makeT); //makeT is a function of type T(void)
 

In C++ reference semantics are achieved by holding objects by pointer. Here is an example of the error, and a correct way of achieving distinctness.

These examples assume T has a public copy constructor, and that p is a pointer to T;

#include <vector>
#include <tr1/memory>
using namespace std;
using namespace std::tr1;
 
typedef shared_ptr<T> TPtr_t;
// the following is NOT correct:
std::vector<TPtr_t > bvec_WRONG(n, p); // create n copies of p, which all point to the same opject p points to.
 
// nor is this:
std::vector<TPtr_t> bvec_ALSO_WRONG(n, TPtr_t(new T(*p)) ); // create n pointers to a single copy of *p
 
// the correct solution
std::vector<TPtr_t > bvec(n);
for (int i = 0; i < n; ++i)
bvec[i] = TPtr_t(new T(*p); //or any other call to T's constructor
 
// another correct solution
// this solution avoids uninitialized pointers at any point
std::vector<TPtr_t> bvec2;
for (int i = 0; i < n; ++i)
bvec2.push_back(TPtr_t(new T(*p));
 
 

Of course, also in this case one can use the other sequence containers or plain new/delete instead of vector.

C#[edit]

using System;
using System.Linq;
using System.Collections.Generic;
 
List<Foo> foos = Enumerable.Range(1, n).Select(x => new Foo()).ToList();

Clojure[edit]

An example using pseudo-random numbers:

user> (take 3 (repeat (rand))) ; repeating the same random number three times
(0.2787011365537204 0.2787011365537204 0.2787011365537204)
user> (take 3 (repeatedly rand)) ; creating three different random number
(0.8334795669220695 0.08405601245793926 0.5795448744634744)
user>

Common Lisp[edit]

The mistake is often written as one of these:

(make-list n :initial-element (make-the-distinct-thing))
(make-array n :initial-element (make-the-distinct-thing))

which are incorrect since the form (make-the-distinct-thing) is only evaluated once and the single object is put in every position of the sequence. A commonly used correct version is:

(loop repeat n collect (make-the-distinct-thing))

which evaluates (make-the-distinct-thing) n times and collects each result in a list.

It is also possible to use map-into, the destructive map operation, to do this since it may take zero input sequences; this method can produce any sequence type, such as a vector (array) rather than a list, and takes a function rather than a form to specify the thing created:

(map-into (make-list n) #'make-the-distinct-thing)
(map-into (make-array n) #'make-the-distinct-thing)

D[edit]

For reference types (classes):

auto fooArray = new Foo[n];
foreach (ref item; fooArray)
item = new Foo();
 

For value types:

auto barArray = new Bar[n];
barArray[] = initializerValue;

Delphi[edit]

Same object accessed multiple times (bad)

var
i: Integer;
lObject: TMyObject;
lList: TObjectList<TMyObject>;
begin
lList := TObjectList<TMyObject>.Create;
lObject := TMyObject.Create;
for i := 1 to 10 do
lList.Add(lObject);
// ...

Distinct objects (good)

var
i: Integer;
lList: TObjectList<TMyObject>;
begin
lList := TObjectList<TMyObject>.Create;
for i := 1 to 10 do
lList.Add(TMyObject.Create);
// ...

E[edit]

E needs development of better map/filter/stream facilities. The easiest way to do this so far is with the accumulator syntax, which is officially experimental because we're not satisfied with it as yet.
pragma.enable("accumulator")
...
 
accum [] for _ in 1..n { _.with(makeWhatever()) }

EchoLisp[edit]

 
;; wrong - make-vector is evaluated one time - same vector
 
(define L (make-list 3 (make-vector 4)))
L(#(0 0 0 0) #(0 0 0 0) #(0 0 0 0))
(vector-set! (first L ) 1 '🔴) ;; sets the 'first' vector
 
L(#(0 🔴 0 0) #(0 🔴 0 0) #(0 🔴 0 0))
 
;; right - three different vectors
 
(define L(map make-vector (make-list 3 4)))
L(#(0 0 0 0) #(0 0 0 0) #(0 0 0 0))
(vector-set! (first L ) 1 '🔵) ;; sets the first vector
 
L(#(0 🔵 0 0) #(0 0 0 0) #(0 0 0 0)) ;; OK
 

Elixir[edit]

randoms = for _ <- 1..10, do: :rand.uniform(1000)

Erlang[edit]

List comprehension that will create 20 random integers between 1 and 1000. They will only be equal by accident.

Randoms = [random:uniform(1000) || _ <- lists:seq(1,10)].

Factor[edit]

clone is the important word here to have distinct objects. This creates an array of arrays.

1000 [ { 1 } clone ] replicate

Forth[edit]

Works with: Forth

Works with any ANS Forth

Needs the FMS-SI (single inheritance) library code located here: http://soton.mpeforth.com/flag/fms/index.html

include FMS-SI.f
include FMS-SILib.f
 
 
\ create a list of VAR objects the right way
\ each: returns a unique object reference
o{ 0 0 0 } dup p: o{ 0 0 0 }
dup each: drop . 10774016
dup each: drop . 10786896
dup each: drop . 10786912
 
 
\ create a list of VAR objects the wrong way
\ each: returns the same object reference
var x
object-list2 list
x list add:
x list add:
x list add:
list p: o{ 0 0 0 }
list each: drop . 1301600
list each: drop . 1301600
list each: drop . 1301600
 


Fortran[edit]

 
program multiple
! Define a simple type
type T
integer :: a = 3
end type T
 
! Define a type containing a pointer
type S
integer, pointer :: a
end type S
 
type(T), allocatable :: T_array(:)
type(S), allocatable :: S_same(:)
integer :: i
integer, target :: v
integer, parameter :: N = 10
 
! Create 10
allocate(T_array(N))
 
! Set the fifth one to b something different
T_array(5)%a = 1
 
! Print them out to show they are distinct
write(*,'(10i2)') (T_array(i),i=1,N)
 
! Create 10 references to the same object
allocate(S_same(N))
v = 5
do i=1, N
allocate(S_same(i)%a)
S_same(i)%a => v
end do
 
! Print them out - should all be 5
write(*,'(10i2)') (S_same(i)%a,i=1,N)
 
! Change the referenced object and reprint - should all be 3
v = 3
write(*,'(10i2)') (S_same(i)%a,i=1,N)
 
end program multiple
 

F#[edit]

The wrong way:

>List.replicate 3 (System.Guid.NewGuid());;
 
val it : Guid list =
[485632d7-1fd6-4d9e-8910-7949d7b2b485; 485632d7-1fd6-4d9e-8910-7949d7b2b485;
485632d7-1fd6-4d9e-8910-7949d7b2b485]

The right way:

> List.init 3 (fun _ -> System.Guid.NewGuid());;
 
val it : Guid list =
[447acb0c-092e-4f85-9c3a-d369e4539dae; 5f41c04d-9bc0-4e96-8165-76b41fe8cd93;
1086400c-72ff-4763-9bb9-27e17bd4c7d2]

Go[edit]

Useful:

func nxm(n, m int) [][]int {
d2 := make([][]int, n)
for i := range d2 {
d2[i] = make([]int, m)
}
return d2
}

Probably not what the programmer wanted:

func nxm(n, m int) [][]int {
d1 := make([]int, m)
d2 := make([][]int, n)
for i := range d2 {
d2[i] = d1
}
return d2
}

Groovy[edit]

Correct Solution:

def createFoos1 = { n -> (0..<n).collect { new Foo() } }

Incorrect Solution:

// Following fails, creates n references to same object
def createFoos2 = {n -> [new Foo()] * n }

Test:

[createFoos1, createFoos2].each { createFoos ->
print "Objects distinct for n = "
(2..<20).each { n ->
def foos = createFoos(n)
foos.eachWithIndex { here, i ->
foos.eachWithIndex { there, j ->
assert (here == there) == (i == j)
}
}
print "${n} "
}
println()
}

Output:

Objects distinct for n = 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 
Objects distinct for n = Caught: Assertion failed: 

assert (here == there) == (i == j)
        |    |  |      |   | |  |
        |    |  |      |   0 |  1
        |    |  |      false false
        |    |  [email protected]
        |    true
        [email protected]

Haskell[edit]

Below, we are assuming that makeTheDistinctThing is a monadic expression (i.e. it has type m a where m is some monad, like IO or ST), and we are talking about distinctness in the context of the monad. Otherwise, this task is pretty meaningless in Haskell, because Haskell is referentially transparent (so two values that are equal to the same expression are necessarily not distinct) and all values are immutable.

replicateM n makeTheDistinctThing

in an appropriate do block. If it is distinguished by, say, a numeric label, one could write

mapM makeTheDistinctThing [1..n]

An incorrect version:

do x <- makeTheDistinctThing
return (replicate n x)

Icon and Unicon[edit]

An incorrect approach uses, e.g., the list constructor procedure with an initial value:

 
items_wrong := list (10, [])
# prints '0' for size of each item
every item := !items_wrong do write (*item)
# after trying to add an item to one of the lists
push (items_wrong[1], 2)
# now prints '1' for size of each item
every item := !items_wrong do write (*item)
 

A correct approach initialises each element separately:

 
items := list(10)
every i := 1 to 10 do items[i] := []
 

J[edit]

i.

Example use:

   i. 4
0 1 2 3

J almost always uses pass-by-value, so this topic is not very relevant to J.

Note also that J offers a variety of other ways of generating multiple distinct objects. This just happens to be one of the simplest of them. In essence, though: generating multiple distinct objects is what J *does* - this is an elemental feature of most of the primitives.

Java[edit]

Works with: Java version 1.5+

simple array:

Foo[] foos = new Foo[n]; // all elements initialized to null
for (int i = 0; i < foos.length; i++)
foos[i] = new Foo();
 
// incorrect version:
Foo[] foos_WRONG = new Foo[n];
Arrays.fill(foos, new Foo()); // new Foo() only evaluated once

simple list:

List<Foo> foos = new ArrayList<Foo>();
for (int i = 0; i < n; i++)
foos.add(new Foo());
 
// incorrect:
List<Foo> foos_WRONG = Collections.nCopies(n, new Foo()); // new Foo() only evaluated once

Generic version for class given at runtime:

It's not pretty but it gets the job done. The first method here is the one that does the work. The second method is a convenience method so that you can pass in a String of the class name. When using the second method, be sure to use the full class name (ex: "java.lang.String" for "String"). InstantiationExceptions will be thrown when instantiating classes that you would not normally be able to call new on (abstract classes, interfaces, etc.). Also, this only works on classes that have a no-argument constructor, since we are using newInstance().

public static <E> List<E> getNNewObjects(int n, Class<? extends E> c){
List<E> ans = new LinkedList<E>();
try {
for(int i=0;i<n;i++)
ans.add(c.newInstance());//can't call new on a class object
} catch (InstantiationException e) {
e.printStackTrace();
} catch (IllegalAccessException e) {
e.printStackTrace();
}
return ans;
}
 
public static List<Object> getNNewObjects(int n, String className)
throws ClassNotFoundException{
return getNNewObjects(n, Class.forName(className));
}

JavaScript[edit]

ES5[edit]

var a = new Array(n);
for (var i = 0; i < n; i++)
a[i] = new Foo();


ES6[edit]

(n => {
 
let nObjects = n => Array.from({
length: n + 1
}, (_, i) => {
// optionally indexed object constructor
return {
index: i
};
});
 
return nObjects(6);
 
})(6);


Output:
[{"index":0}, {"index":1}, {"index":2}, {"index":3}, 
{"index":4}, {"index":5}, {"index":6}]

jq[edit]

jq does not have mutable data types, and therefore in the context of jq, the given task is probably of little interest. However, it is possible to fulfill the task requirements for jq types other than "null" and "boolean":
 
def Array(atype; n):
if atype == "number" then [ range(0;n) ]
elif atype == "object" then [ range(0;n)| {"value": . } ]
elif atype == "array" then [ range(0;n)| [.] ]
elif atype == "string" then [ range(0;n)| tostring ]
elif atype == "boolean" then
if n == 0 then [] elif n == 1 then [false] elif n==2 then [false, true]
else error("there are only two boolean values")
end
elif atype == "null" then
if n == 0 then [] elif n == 1 then [null]
else error("there is only one null value")
end
else error("\(atype) is not a jq type")
end;
 
# Example:
 
Array("object"; 4)

Kotlin[edit]

// version 1.1.2
 
class Foo {
val id: Int
 
init {
id = ++numCreated // creates a distict id for each object
}
 
companion object {
private var numCreated = 0
}
}
 
fun main(args: Array<String>) {
val n = 3 // say
 
/* correct approach - creates references to distinct objects */
val fooList = List(n) { Foo() }
for (foo in fooList) println(foo.id)
 
/* incorrect approach - creates references to same object */
val f = Foo()
val fooList2 = List(n) { f }
for (foo in fooList2) println(foo.id)
}
Output:
1
2
3
4
4
4

Logtalk[edit]

Using prototypes, we first dynamically create a protocol to declare a predicate and then create ten prototypes implementing that protocol, which one with a different definition for the predicate:

 
| ?- create_protocol(statep, [], [public(state/1)]),
findall(
Id,
(integer::between(1, 10, N),
create_object(Id, [implements(statep)], [], [state(N)])),
Ids
).
Ids = [o1, o2, o3, o4, o5, o6, o7, o8, o9, o10].
 

Using classes, we first dynamically create a class (that is its own metaclass) to declare a predicate (and define a default value for it) and then create ten instances of the class, which one with a different definition for the predicate:

 
| ?- create_object(state, [instantiates(state)], [public(state/1)], [state(0)]),
findall(
Id,
(integer::between(1, 10, N),
create_object(Id, [instantiates(state)], [], [state(N)])),
Ids
).
Ids = [o1, o2, o3, o4, o5, o6, o7, o8, o9, o10].
 

Lua[edit]

-- This concept is relevant to tables in Lua
local table1 = {1,2,3}
 
-- The following will create a table of references to table1
local refTab = {}
for i = 1, 10 do refTab[i] = table1 end
 
-- Instead, tables should be copied using a function like this
function copy (t)
local new = {}
for k, v in pairs(t) do new[k] = v end
return new
end
 
-- Now we can create a table of independent copies of table1
local copyTab = {}
for i = 1, 10 do copyTab[i] = copy(table1) end

Mathematica[edit]

The mistake is often written as:

{x, x, x, x} /. x -> Random[]

Here Random[] can be any expression that returns a new value which is incorrect since Random[] is only evaluated once. e.g. {0.175125, 0.175125, 0.175125, 0.175125}

A correct version is:

{x, x, x, x} /. x :> Random[]

which evaluates Random[] each time e.g. ->{0.514617, 0.0682395, 0.609602, 0.00177382}

Maxima[edit]

a: [1, 2]$
 
b: makelist(copy(a), 3);
[[1,2],[1,2],[1,2]]
 
b[1][2]: 1000$
 
b;
[[1,1000],[1,2],[1,2]]

Modula-3[edit]

This example is incorrect. Please fix the code and remove this message.
Details: It does not initialize the sequence.

Similar to the Ada version above:

VAR a: ARRAY OF T

This creates an open array (an array who's size is not known until runtime) of distinct elements of type T.

Modula-3 does not define what values the elements of A have, but it does guarantee that they will be of type T.

NGS[edit]

Incorrect, same object n times:

{ [foo()] * n }

Correct:

{ foo * n }

Nim[edit]

The simplest form of initialization works, but is a bit cumbersome to write:

proc foo(): string =
echo "Foo()"
"mystring"
 
let n = 100
var ws = newSeq[string](n)
for i in 0 .. <n: ws[i] = foo()

If actual values instead of references are stored in the sequence, then objects can be initialized like this. Objects are distinct, but the initializer foo() is called only once, then copies of the resulting object are made:

proc newSeqWith[T](len: int, init: T): seq[T] =
result = newSeq[T] len
for i in 0 .. <len:
result[i] = init
 
var xs = newSeqWith(n, foo())

To get the initial behaviour, where foo() is called to create each object, a template can be used:

template newSeqWith2(len: int, init: expr): expr =
var result {.gensym.} = newSeq[type(init)](len)
for i in 0 .. <len:
result[i] = init
result
 
var ys = newSeqWith2(n, foo())

OCaml[edit]

For arrays:

Incorrect:

Array.make n (new foo);;
(* here (new foo) can be any expression that returns a new object,
record, array, or string *)

which is incorrect since new foo is only evaluated once. A correct version is:

Array.init n (fun _ -> new foo);;

Oforth[edit]

The right way : the block sent as parameter is performed n times :

ListBuffer init(10, #[ Float rand ]) println
Output:
[0.281516067014556, 0.865269004241814, 0.101437334065733, 0.924166132625347, 0.88135127712
167, 0.176233635448137, 0.963837773505447, 0.570264579328023, 0.385577832707742, 0.9086026
42741616]

The "wrong" way : the same value is stored n times into the list buffer

ListBuffer initValue(10, Float rand) println
Output:
[0.314870762000671, 0.314870762000671, 0.314870762000671, 0.314870762000671, 0.31487076200
0671, 0.314870762000671, 0.314870762000671, 0.314870762000671, 0.314870762000671, 0.314870
762000671]

ooRexx[edit]

 
-- get an array of directory objects
array = fillArrayWith(3, .directory)
say "each object will have a different identityHash"
say
loop d over array
say d~identityHash
end
 
::routine fillArrayWith
use arg size, class
 
array = .array~new(size)
loop i = 1 to size
-- Note, this assumes this object class can be created with
-- no arguments
array[i] = class~new
end
 
return array
 


Oz[edit]

With lists, it is difficult to do wrong.

declare
Xs = {MakeList 5} %% a list of 5 unbound variables
in
{ForAll Xs OS.rand} %% fill it with random numbers (CORRECT)
{Show Xs}

With arrays on the other hand, it is easy to get wrong:

declare
Arr = {Array.new 0 10 {OS.rand}} %% WRONG: contains ten times the same number
in
%% CORRECT: fill it with ten (probably) different numbers
for I in {Array.low Arr}..{Array.high Arr} do
Arr.I := {OS.rand}
end

Pascal[edit]

See Delphi

Perl[edit]

incorrect:

(Foo->new) x $n 
# here Foo->new can be any expression that returns a reference representing
# a new object

which is incorrect since Foo->new is only evaluated once.

A correct version is:

map { Foo->new } 1 .. $n;

which evaluates Foo->new $n times and collects each result in a list.

Perl 6[edit]

Unlike in Perl 5, the list repetition operator evaluates the left argument thunk each time, so

my @a = Foo.new xx $n;

produces $n distinct objects.

Phix[edit]

Phix uses shared reference counts with copy-on-write semantics. Creating n references to the same mutable object is in fact the norm, but does not cause any of the issues implicitly feared in the task description. In fact, it is not possible to create shared references such that when one is updated they all are, instead store an index to another table that stores the object, rather than the object itself. Also, apart from low-level trickery and interfacing to shared libraries, there are no pointers to normal hll objects. Sequences need not be homogeneous, they can contain any type-mix of elements.

sequence s = repeat("x",3*rand(3))
?s
s[rand(length(s))] = 5
?s
s[rand(length(s))] &= 'y'
?s
s[rand(length(s))] = s
?s
Output:
{"x","x","x","x","x","x"}
{"x","x","x","x","x",5}
{"xy","x","x","x","x",5}
{"xy",{"xy","x","x","x","x",5},"x","x","x",5}

Note that the last statement did not create a circular structure, something that is not possible in Phix, except via index-emulation.
I suppose it is possible that someone could write

sequence s = repeat(my_func(),5)

and expect my_func() to be invoked 5 times, but for that you need a loop

sequence s = repeat(0,5)
for i=1 to length(s) do
s[i] = my_func()
end for

PicoLisp[edit]

Create 5 distinct (empty) objects:

: (make (do 5 (link (new))))
-> ($384717187 $384717189 $384717191 $384717193 $384717195)

Create 5 anonymous symbols with the values 1 .. 5:

: (mapcar box (range 1 5))
-> ($384721107 $384721109 $384721111 $384721113 $384721115)
: (val (car @))
-> 1
: (val (cadr @@))
-> 2

PowerShell[edit]

Do some randomization that could easily return three equal values (but each value is a separate value in the array):

 
1..3 | ForEach-Object {((Get-Date -Hour ($_ + (1..4 | Get-Random))).AddDays($_ + (1..4 | Get-Random)))} |
Select-Object -Unique |
ForEach-Object {$_.ToString()}
 
Output:
11/18/2016 3:32:16 AM
11/21/2016 3:32:16 AM
11/22/2016 7:32:16 AM

Run the same commands a few times and the Select-Object -Unique command filters equal (but separate values):

 
1..3 | ForEach-Object {((Get-Date -Hour ($_ + (1..4 | Get-Random))).AddDays($_ + (1..4 | Get-Random)))} |
Select-Object -Unique |
ForEach-Object {$_.ToString()}
 
Output:
11/18/2016 4:32:17 AM
11/21/2016 5:32:17 AM

PureBasic[edit]

n=Random(50)+25
Dim A.i(n)
; Creates a Array of n [25-75] elements depending on the outcome of Random().
; Each element will be initiated to zero.
 
For i=0 To ArraySize(A())
A(i)=2*i
Next i
; Set each individual element at a wanted (here 2*i) value and
; automatically adjust accordingly to the unknown length of the Array.
 
NewList *PointersToA()
For i=0 To ArraySize(A())
AddElement(*PointersToA())
*PointersToA()=@A(i)
Next
; Create a linked list of the same length as A() above.
; Each element is then set to point to the Array element
; of the same order.
 
ForEach *PointersToA()
Debug PeekI(*PointersToA())
Next
; Verify by sending each value of A() via *PointersToA()
; to the debugger's output.

Python[edit]

The mistake is often written as:

[Foo()] * n # here Foo() can be any expression that returns a new object

which is incorrect since Foo() is only evaluated once. A common correct version is:

[Foo() for i in range(n)]

which evaluates Foo() n times and collects each result in a list. This last form is also discussed here, on the correct construction of a two dimensional array.

R[edit]

The mistake is often written as:

rep(foo(), n)        # foo() is any code returning a value

A common correct version is:

replicate(n, foo())

which evaluates foo() n times and collects each result in a list. (Using simplify=TRUE lets the function return an array, where possible.)

Racket[edit]

 
#lang racket
 
;; a list of 10 references to the same vector
(make-list 10 (make-vector 10 0))
 
;; a list of 10 distinct vectors
(build-list 10 (λ (n) (make-vector 10 0)))
 

Ruby[edit]

The mistake is often written as one of these:

[Foo.new] * n         # here Foo.new can be any expression that returns a new object
Array.new(n, Foo.new)

which are incorrect since Foo.new is only evaluated once, and thus you now have n references to the same object. A common correct version is:

Array.new(n) { Foo.new }

which evaluates Foo.new n times and collects each result in an Array. This last form is also discussed here, on the correct construction of a two dimensional array.

Scala[edit]

Yielding a normal class instance here (rather than a case class instance), as case objects are identical if created with the same constructor arguments.

for (i <- (0 until n)) yield new Foo()

Scheme[edit]

Library: Scheme/SRFIs

There is a standard function make-list which makes a list of size n, but repeats its given value.

sash[r7rs]> (define-record-type <a> (make-a x) a? (x get-x))
#<unspecified>
sash[r7rs]> (define l1 (make-list 5 (make-a 3)))
#<unspecified>
sash[r7rs]> (eq? (list-ref l1 0) (list-ref l1 1))
#t

In SRFI 1, a function list-tabulate is provided which instead calls a function to create a fresh value each time.

sash[r7rs]> (define l2 (list-tabulate 5 (lambda (i) (make-a i))))
#<unspecified>
sash[r7rs]> (eq? (list-ref l2 0) (list-ref l2 1))
#f
sash[r7rs]> (map get-x l2)
(0 1 2 3 4)


Seed7[edit]

The example below defines the local array variable fileArray. The times operator creates a new array value with a specified size. Finally multiple distinct objects are assigned to the array elements.

$ include "seed7_05.s7i";
 
const func array file: openFiles (in array string: fileNames) is func
result
var array file: fileArray is 0 times STD_NULL; # Define array variable
local
var integer: i is 0;
begin
fileArray := length(fileNames) times STD_NULL; # Array size computed at run-time
for key i range fileArray do
fileArray[i] := open(fileNames[i], "r"); # Assign multiple distinct objects
end for;
end func;
 
const proc: main is func
local
var array file: files is 0 times STD_NULL;
begin
files := openFiles([] ("abc.txt", "def.txt", "ghi.txt", "jkl.txt"));
end func;

Sidef[edit]

[Foo.new] * n;      # incorrect (only one distinct object is created)
n.of {Foo.new};     # correct

Smalltalk[edit]

|c|
"Create an ordered collection that will grow while we add elements"
c := OrderedCollection new.
"fill the collection with 9 arrays of 10 elements; elements (objects)
are initialized to the nil object, which is a well-defined 'state'"

1 to: 9 do: [ :i | c add: (Array new: 10) ].
"However, let us show a way of filling the arrays with object number 0"
c := OrderedCollection new.
1 to: 9 do: [ :i | c add: ((Array new: 10) copyReplacing: nil withObject: 0) ].
"demonstrate that the arrays are distinct: modify the fourth of each"
1 to: 9 do: [ :i | (c at: i) at: 4 put: i ].
"show it"
c do: [ :e | e printNl ].

Swift[edit]

class Foo { }
 
var foos = [Foo]()
for i in 0..<n {
foos.append(Foo())
}
 
// incorrect version:
var foos_WRONG = [Foo](count: n, repeatedValue: Foo()) // Foo() only evaluated once

Tcl[edit]

Tcl values are implemented using copy-on-write reference semantics with no (exposed) mechanism for determining whether two values are really references to the same value, which makes this task relatively moot. However, in the case where there is a collection of objects it becomes important to perform the construction correctly (i.e., repeatedly) otherwise it is just the name of the object that will be copied when it is written to.

Works with: Tcl version 8.6
or
Library: TclOO
package require TclOO
 
# The class that we want to make unique instances of
set theClass Foo
 
# Wrong version; only a single object created
set theList [lrepeat $n [$theClass new]]
 
# Right version; objects distinct
set theList {}
for {set i 0} {$i<$n} {incr i} {
lappend theList [$theClass new]
}

XPL0[edit]

code Reserve=3, IntIn=10;
char A; int N, I;
[N:= IntIn(8); \get number of items from command line
A:= Reserve(N); \create array of N bytes
for I:= 0 to N-1 do A(I):= I*3; \initialize items with different values
for I:= 0 to N-1 do A:= I*3; \error: "references to the same mutable object"
]

zkl[edit]

The pump and partial application methods are useful tools for creating initialized lists.

n:=3;
n.pump(List) //-->L(0,1,2)
 
n.pump(List,List) //-->L(0,1,2), not expected
because the second list can be used to describe a calculation
n.pump(List,List(Void,List)) //--> L(L(),L(),L()) all same
List(Void,List) means returns List, which is a "known" value
n.pump(List,List.fpM("-")) //--> L(L(),L(),L()) all distinct
fpM is partial application: call List.create()
 
n.pump(List,(0.0).random.fp(1)) //--> 3 [0,1) randoms
L(0.902645,0.799657,0.0753809)
 
n.pump(String) //-->"012", default action is id function
 
class C{ var n; fcn init(x){n=x} }
n.pump(List,C) //--> L(C,C,C)
n.pump(List,C).apply("n") //-->L(0,1,2) ie all classes distinct