100 doors

100 doors
You are encouraged to solve this task according to the task description, using any language you may know.

There are 100 doors in a row that are all initially closed.

You make 100 passes by the doors.

The first time through, visit every door and  toggle  the door  (if the door is closed,  open it;   if it is open,  close it).

The second time, only visit every 2^nd door   (door #2, #4, #6, ...),   and toggle it.

The third time, visit every 3^rd door   (door #3, #6, #9, ...), etc,   until you only visit the 100^th door.

Task

Answer the question:   what state are the doors in after the last pass?   Which are open, which are closed?

Alternate: As noted in this page's   discussion page,   the only doors that remain open are those whose numbers are perfect squares.

Opening only those doors is an   optimization   that may also be expressed; however, as should be obvious, this defeats the intent of comparing implementations across programming languages.

360 Assembly

*        100 doors                 13/08/2015
HUNDOOR  CSECT
         USING  HUNDOOR,R12
         LR     R12,R15
         LA     R6,0
         LA     R8,1               step 1
         LA     R9,100
LOOPI    BXH    R6,R8,ELOOPI       do ipass=1 to 100 (R6)
         LR     R7,R6
         SR     R7,R6
         LR     R10,R6             step ipass
         LA     R11,100
LOOPJ    BXH    R7,R10,ELOOPJ      do idoor=ipass to 100 by ipass (R7)
         LA     R5,DOORS-1
         AR     R5,R7
         XI     0(R5),X'01'        doors(idoor)=not(doors(idoor))
NEXTJ    B      LOOPJ
ELOOPJ   B      LOOPI
ELOOPI   LA     R10,BUFFER         R10 address of the buffer
         LA     R5,DOORS           R5 address of doors item
         LA     R6,1               idoor=1 (R6)
         LA     R9,100             loop counter
LOOPN    CLI    0(R5),X'01'        if doors(idoor)=1
         BNE    NEXTN
         XDECO  R6,XDEC            idoor to decimal
         MVC    0(4,R10),XDEC+8    move decimal to buffer
         LA     R10,4(R10)
NEXTN	 LA     R6,1(R6)           idoor=idoor+1
         LA     R5,1(R5)
         BCT    R9,LOOPN           loop
ELOOPN   XPRNT  BUFFER,80
RETURN   XR     R15,R15
         BR     R14
DOORS    DC     100X'00'
BUFFER   DC     CL80' '
XDEC     DS     CL12
         YREGS
         END    HUNDOOR

Output:

   1   4   9  16  25  36  49  64  81 100

4DOS Batch

 
@echo off
set doors=%@repeat[C,100]
do step = 1 to 100
  do door = %step to 100 by %step
    set doors=%@left[%@eval[%door-1],%doors]%@if[%@instr[%@eval[%door-1],1,%doors]==C,O,C]%@right[%@eval[100-%door],%doors]
  enddo
enddo
 

The SET line consists of three functions:

 
%@left[n,string]                      ^: Return n leftmost chars in string
%@right[n,string]                     ^: Return n rightmost chars in string
%@if[condition,true-val,false-val]    ^: Evaluate condition; return true-val if true, false-val if false
 

Here @IF is used to toggle between C and O.

6502 Assembly

Works with: [www.6502asm.com] version beta

unoptimized Based on BASIC QB64 unoptimized version

; 100 DOORS in  6502 assembly language for: http://www.6502asm.com/beta/index.html
; Written for the original MOS Technology, Inc. NMOS version of the 6502, but should work with any version.
; Based on BASIC QB64 unoptimized version: http://rosettacode.org/wiki/100_doors#BASIC
;
; Notes:
;    Doors array[1..100] is at $0201..$0264. On the specified emulator, this is in video memory, so tbe results will 
; be directly shown as pixels in the display.
;    $0200 (door 0) is cleared for display purposes but is not involved in the open/close loops.
;    Y register holds Stride
;    X register holds Index
;    Zero Page address $01 used to add Stride to Index (via A) because there's no add-to-X or add-Y-to-A instruction.
 
  ; First, zero door array
    LDA #00
    LDX #100
Z_LOOP:
    STA 200,X
    DEX
    BNE Z_LOOP
    STA 200,X
 
  ; Now do doors repeated open/close
    LDY #01        ; Initial value of Stride
S_LOOP:
    CPY #101
    BCS S_DONE
    TYA            ; Initial value of Index
I_LOOP:
    CMP #101
    BCS I_DONE
    TAX            ; Use as Door array index
    INC $200,X     ; Toggle bit 0 to reverse state of door
    STY 01         ; Add stride (Y) to index (X, via A)
    ADC 01
    BCC I_LOOP
I_DONE:
    INY
    BNE S_LOOP
S_DONE:
 
  ; Finally, format array values for output: 0 for closed, 1 for open
    LDX #100
C_LOOP:
    LDA $200,X
    AND #$01
    STA $200,X
    DEX
    BNE C_LOOP

48. bytes of code; the specified emulator does not report cycles.

Works with: [6502asm.com] version 1.2

optimized Largely inspired by the optimized C implementation - makes use of the fact that finally only the doors whose numbers are squares of integers are open, as well as the fact that

$n^{2}=1+3+5+\ldots +(2n-1)$.

  ;assumes memory at $02xx is initially set to 0 and stack pointer is initialized
  ;the 1 to 100 door byte array will be at $0200-$0263 (decimal 512 to 611)
  ;Zero-page location $01 will hold delta
  ;At end, closed doors = $00, open doors = $01
 
start:    ldx #0        ;initialize index - first door will be at $200 + $0
          stx $1
          inc $1        ;start out with a delta of 1 (0+1=1)
openloop: inc $200,X    ;open X'th door
          inc $1        ;add 2 to delta
          inc $1
          txa           ;add delta to X by transferring X to A, adding delta to A, then transferring back to X
          clc           ;  clear carry before adding (6502 has no add-without-carry instruction)
          adc $1
          tax
          cpx #$64      ;check to see if we're at or past the 100th door (at $200 + $63)
          bmi openloop  ;jump back to openloop if less than 100

22. bytes of code; the specified emulator does not report cycles.

68000 Assembly

Works with: [EASy68K v5.13.00]

Some of the macro code is derived from the examples included with EASy68K.

*-----------------------------------------------------------
* Title      : 100Doors.X68
* Written by : G. A. Tippery
* Date       : 2014-01-17
* Description: Solves "100 Doors" problem, see: http://rosettacode.org/wiki/100_doors
* Notes      : Translated from C "Unoptimized" version, http://rosettacode.org/wiki/100_doors#unoptimized
*            : No optimizations done relative to C version; "for("-equivalent loops could be optimized.
*-----------------------------------------------------------
 
*
*   System-specific general console I/O macros (Sim68K, in this case)
*
PUTS    MACRO
    ** Print a null-terminated string w/o CRLF **
    ** Usage: PUTS stringaddress
    ** Returns with D0, A1 modified
        MOVEQ   #14,D0      ; task number 14 (display null string)
        LEA     \1,A1       ; address of string
        TRAP    #15         ; display it
        ENDM
*
PRINTN  MACRO
    ** Print decimal integer from number in register
    ** Usage: PRINTN register
    ** Returns with D0,D1 modified
        IFNC '\1','D1'      ;if some register other than D1
          MOVE.L \1,D1      ;put number to display in D1
        ENDC
        MOVE.B  #3,D0
        TRAP    #15         ;display number in D1
*
*   Generic constants
*
CR      EQU     13      ;ASCII Carriage Return
LF      EQU     10      ;ASCII Line Feed
 
*
*   Definitions specific to this program
*
*   Register usage:
*   D3 == pass (index)
*   D4 == door (index)
*   A2 == Doors array pointer
*
SIZE    EQU     100             ;Define a symbolic constant for # of doors
 
        ORG     $1000           ;Specify load address for program -- actual address system-specific
START:                          ; Execution starts here
        LEA     Doors,A2        ; make A2 point to Doors byte array
        MOVEQ   #0,D3
PassLoop:
        CMP     #SIZE,D3
        BCC     ExitPassLoop    ; Branch on Carry Clear - being used as Branch on Higher or Equal
        MOVE    D3,D4
DoorLoop:
        CMP     #SIZE,D4
        BCC     ExitDoorLoop
        NOT.B   0(A2,D4)
        ADD     D3,D4
        ADDQ    #1,D4
        BRA     DoorLoop
ExitDoorLoop:
        ADDQ    #1,D3
        BRA     PassLoop
ExitPassLoop:

* $28 = 40. bytes of code to this point. 32626 cycles so far.
*   At this point, the result exists as the 100 bytes starting at address Doors.
* To get output, we must use methods specific to the particular hardware, OS, or
* emulator system that the code is running on.  I use macros to "hide" some of the
* system-specific details; equivalent macros would be written for another system.
 
        MOVEQ   #0,D4
PrintLoop:
        CMP     #SIZE,D4
        BCC     ExitPrintLoop
        PUTS    DoorMsg1
        MOVE    D4,D1
        ADDQ    #1,D1           ; Convert index to 1-based instead of 0-based
        PRINTN  D1
        PUTS    DoorMsg2
        TST.B   0(A2,D4)        ; Is this door open (!= 0)?
        BNE     ItsOpen
        PUTS    DoorMsgC
        BRA     Next
ItsOpen:
        PUTS    DoorMsgO
Next:
        ADDQ    #1,D4
        BRA     PrintLoop
ExitPrintLoop:

*  What to do at end of program is also system-specific
        SIMHALT             ;Halt simulator
*
* $78 = 120. bytes of code to this point, but this will depend on how the I/O macros are actually written.
* Cycle count is nearly meaningless, as the I/O hardware and routines will dominate the timing.
 
*
*   Data memory usage
*
        ORG     $2000
Doors   DCB.B   SIZE,0      ;Reserve 100 bytes, prefilled with zeros
 
DoorMsg1 DC.B   'Door ',0
DoorMsg2 DC.B   ' is ',0
DoorMsgC DC.B   'closed',CR,LF,0
DoorMsgO DC.B   'open',CR,LF,0
 
        END     START       ;last line of source
 
 

8086 Assembly

See 100 doors/8086 Assembly

8th

 
\ Array of doors; init to empty; accessing a non-extant member will return
\ 'null', which is treated as 'false', so we don't need to initialize it:
[] var, doors    
 
\ given a door number, get the value and toggle it:
: toggle-door \ n --
	doors @ over a:@
	not rot swap a:! drop ;
 
\ print which doors are open:
: .doors
	( 
		doors @ over a:@ nip
		if . space else drop then
	) 1 100 loop ;
 
\ iterate over the doors, skipping 'n':
: main-pass \ n --
	0
	true
	repeat
		drop
		dup toggle-door
		over n:+
		dup 101 <
	while 2drop drop ;
 
\ calculate the first 100 doors:
' main-pass 1 100 loop
\ print the results:
.doors cr bye
 

Output:

1 4 9 16 25 36 49 64 81 100

ABAP

unoptimized

form open_doors_unopt.
  data: lv_door  type i,
        lv_count type i value 1.
  data: lt_doors type standard table of c initial size 100.
  field-symbols: <wa_door> type c.
  do 100 times.
    append initial line to lt_doors assigning <wa_door>.
    <wa_door> = 'X'.
  enddo.
 
  while lv_count < 100.
    lv_count = lv_count + 1.
    lv_door = lv_count.
    while lv_door < 100.
      read table lt_doors index lv_door assigning <wa_door>.
      if <wa_door> = ' '.
        <wa_door> = 'X'.
      else.
        <wa_door> = ' '.
      endif.
      add lv_count to lv_door.
    endwhile.
  endwhile.
 
  loop at lt_doors assigning <wa_door>.
    if <wa_door> = 'X'.
      write : / 'Door', (4) sy-tabix right-justified, 'is open' no-gap.
    endif.
  endloop.
endform.

unoptimized / functional

 
cl_demo_output=>display( REDUCE stringtab( INIT list TYPE stringtab
                                              aux TYPE i
                                          FOR door = 1 WHILE door <= 100
                                          FOR pass = 1 WHILE pass <= 100
                                         NEXT aux   = COND #( WHEN pass = 1 THEN 1
                                                              WHEN door MOD pass = 0 THEN aux + 1 ELSE aux  )
                                              list  = COND #( WHEN pass = 100
                                                                THEN COND #( WHEN aux MOD 2 <> 0 THEN VALUE #( BASE list ( CONV #( door ) ) )
                                                                              ELSE list ) ELSE list ) ) ).
 
 

optimized

Using $\sum _{i=1}^{n}(2i-1)=n^{2}$

form open_doors_opt.
  data: lv_square type i value 1,
        lv_inc    type i value 3.
  data: lt_doors  type standard table of c initial size 100.
  field-symbols: <wa_door> type c.
  do 100 times.
    append initial line to lt_doors assigning <wa_door>.
    if sy-index = lv_square.
      <wa_door> = 'X'.
      add: lv_inc to lv_square, 2 to lv_inc.
      write : / 'Door', (4) sy-index right-justified, 'is open' no-gap.
    endif.
  enddo.
endform.

ultra-optimized / imperative

 
DO 10 TIMES.
  DATA(val) = sy-index * sy-index.
  WRITE: / val.
ENDDO.
 

ultra-optimized / functional

 
cl_demo_output=>display( REDUCE stringtab( INIT list TYPE stringtab
                                          FOR i = 1 WHILE i <= 10
                                         NEXT list = VALUE #( BASE list ( i * i ) ) ) ).
 

ACL2

(defun rep (n x)
   (if (zp n)
       nil
       (cons x
             (rep (- n 1) x))))
 
(defun toggle-every-r (n i bs)
   (if (endp bs)
       nil
       (cons (if (zp i)
                 (not (first bs))
                 (first bs))
             (toggle-every-r n (mod (1- i) n) (rest bs)))))
 
(defun toggle-every (n bs)
   (toggle-every-r n (1- n) bs))
 
(defun 100-doors (i doors)
   (if (zp i)
       doors
       (100-doors (1- i) (toggle-every i doors))))

ActionScript

Works with: ActionScript version 3.0

unoptimized

package {                                                                                
    import flash.display.Sprite;                                              
 
    public class Doors extends Sprite {
        public function Doors() {
 
            // Initialize the array
            var doors:Array = new Array(100);
            for (var i:Number = 0; i < 100; i++) {
                doors[i] = false;
 
            // Do the work
            for (var pass:Number = 0; pass < 100; pass++) {
                for (var j:Number = pass; j < 100; j += (pass+1)) {
                    doors[j] = !doors[j];
                }
            }
            trace(doors);
        }
    }
}

Acurity Architect

Using #HASH-OFF, OPTION OICC ="^" , CICC ="^"

 
VAR sStatus: SHORT
VAR sArray: SHORT
VAR sCount: SHORT
VAR sDoor: SHORT
VAR sPass: SHORT
VAR zIndex: STRING
VAR zState: STRING
//
SET sStatus = GET_UNUSED_ARRAY_HANDLE(sArray)
SET sStatus = INIT_SORTED_ARRAY(sArray, 0, 0, 1)
//
DO sCount = 1 TO 100
  DO sPass = 1 TO 100
    SET sDoor = sCount * sPass
    IF sDoor <= 100
      SET zIndex = REPEAT("0", 3 - LENGTH(STR(sDoor))) + STR(sDoor)
      SET sStatus = READ_ARRAY_REC("=", sArray, zIndex)
      SET zState = "OPEN"
      IF GET_STRING_SAY(sArray, 1) = "OPEN"
        SET zState = "CLOSE"
      ENDIF
      //
      SET sStatus = ADD_ARRAY_REC(sArray, zIndex)
      SET sStatus = PUT_STRING_SAY(sArray, 1, zState)
    ELSE
      BREAK
    ENDIF
  ENDDO
ENDDO
//
SET zIndex = ""
SET sStatus = READ_ARRAY_REC(">=", sArray, zIndex)
DO WHILE sStatus = 0
  >>Door:  ^zIndex^  State: ^GET_STRING_SAY(sArray, 1)^
  SET sStatus = READ_ARRAY_REC("+", sArray, zIndex)
ENDDO
 

Output:

Door:  001  State: OPEN
Door:  002  State: CLOSE
Door:  003  State: CLOSE
Door:  004  State: OPEN
Door:  005  State: CLOSE
Door:  006  State: CLOSE
Door:  007  State: CLOSE
Door:  008  State: CLOSE
Door:  009  State: OPEN
Door:  010  State: CLOSE
Door:  011  State: CLOSE
Door:  012  State: CLOSE
Door:  013  State: CLOSE
Door:  014  State: CLOSE
Door:  015  State: CLOSE
Door:  016  State: OPEN
Door:  017  State: CLOSE
Door:  018  State: CLOSE
Door:  019  State: CLOSE
Door:  020  State: CLOSE
Door:  021  State: CLOSE
Door:  022  State: CLOSE
Door:  023  State: CLOSE
Door:  024  State: CLOSE
Door:  025  State: OPEN
Door:  026  State: CLOSE
Door:  027  State: CLOSE
Door:  028  State: CLOSE
Door:  029  State: CLOSE
Door:  030  State: CLOSE
Door:  031  State: CLOSE
Door:  032  State: CLOSE
Door:  033  State: CLOSE
Door:  034  State: CLOSE
Door:  035  State: CLOSE
Door:  036  State: OPEN
Door:  037  State: CLOSE
Door:  038  State: CLOSE
Door:  039  State: CLOSE
Door:  040  State: CLOSE
Door:  041  State: CLOSE
Door:  042  State: CLOSE
Door:  043  State: CLOSE
Door:  044  State: CLOSE
Door:  045  State: CLOSE
Door:  046  State: CLOSE
Door:  047  State: CLOSE
Door:  048  State: CLOSE
Door:  049  State: OPEN
Door:  050  State: CLOSE
Door:  051  State: CLOSE
Door:  052  State: CLOSE
Door:  053  State: CLOSE
Door:  054  State: CLOSE
Door:  055  State: CLOSE
Door:  056  State: CLOSE
Door:  057  State: CLOSE
Door:  058  State: CLOSE
Door:  059  State: CLOSE
Door:  060  State: CLOSE
Door:  061  State: CLOSE
Door:  062  State: CLOSE
Door:  063  State: CLOSE
Door:  064  State: OPEN
Door:  065  State: CLOSE
Door:  066  State: CLOSE
Door:  067  State: CLOSE
Door:  068  State: CLOSE
Door:  069  State: CLOSE
Door:  070  State: CLOSE
Door:  071  State: CLOSE
Door:  072  State: CLOSE
Door:  073  State: CLOSE
Door:  074  State: CLOSE
Door:  075  State: CLOSE
Door:  076  State: CLOSE
Door:  077  State: CLOSE
Door:  078  State: CLOSE
Door:  079  State: CLOSE
Door:  080  State: CLOSE
Door:  081  State: OPEN
Door:  082  State: CLOSE
Door:  083  State: CLOSE
Door:  084  State: CLOSE
Door:  085  State: CLOSE
Door:  086  State: CLOSE
Door:  087  State: CLOSE
Door:  088  State: CLOSE
Door:  089  State: CLOSE
Door:  090  State: CLOSE
Door:  091  State: CLOSE
Door:  092  State: CLOSE
Door:  093  State: CLOSE
Door:  094  State: CLOSE
Door:  095  State: CLOSE
Door:  096  State: CLOSE
Door:  097  State: CLOSE
Door:  098  State: CLOSE
Door:  099  State: CLOSE
Door:  100  State: OPEN

Ada

unoptimized

with Ada.Text_Io; use Ada.Text_Io;
 
 procedure Doors is
    type Door_State is (Closed, Open);
    type Door_List is array(Positive range 1..100) of Door_State;
    The_Doors : Door_List := (others => Closed);
 begin
    for I in 1..100 loop
       for J in The_Doors'range loop
          if J mod I = 0 then
             if The_Doors(J) = Closed then
                 The_Doors(J) := Open;
             else
                The_Doors(J) := Closed;
             end if;
          end if;
       end loop;
    end loop;
    for I in The_Doors'range loop
       Put_Line(Integer'Image(I) & " is " & Door_State'Image(The_Doors(I)));
    end loop;
 end Doors;

optimized

with Ada.Text_Io; use Ada.Text_Io;
 with Ada.Numerics.Elementary_Functions; use Ada.Numerics.Elementary_Functions;
 
 procedure Doors_Optimized is
    Num : Float;
 begin
    for I in 1..100 loop
       Num := Sqrt(Float(I));
       Put(Integer'Image(I) & " is ");
       if Float'Floor(Num) = Num then
          Put_Line("Opened");
       else
          Put_Line("Closed");
       end if;
    end loop;
 end Doors_Optimized;

Agena

Translation of Algol W. Tested with Agena 2.9.5 Win32

# find the first few squares via the unoptimised door flipping method
scope
 
    local doorMax := 100;
    local door;
    create register door( doorMax );
 
    # set all doors to closed
    for i to doorMax do door[ i ] := false od;
 
    # repeatedly flip the doors
    for i to doorMax do
        for j from i to doorMax by i do door[ j ] := not door[ j ] od
    od;
 
    # display the results
    for i to doorMax do if door[ i ] then write( " ", i ) fi od; print()
 
epocs

Aikido

 
var doors = new int [100]
 
foreach pass 100 {
    for (var door = pass ; door < 100 ; door += pass+1) {
        doors[door] = !doors[door]
    }
}
 
var d = 1
foreach door doors {
    println ("door " + d++ + " is " + (door ? "open" : "closed"))
 
}
 
 

ALGOL 68

unoptimized

# declare some constants #
INT limit = 100;
 
PROC doors = VOID:
(
  MODE DOORSTATE = BOOL;
  BOOL closed = FALSE;
  BOOL open = NOT closed;
  MODE DOORLIST = [limit]DOORSTATE;
 
  DOORLIST the doors;
  FOR i FROM LWB the doors TO UPB the doors DO the doors[i]:=closed OD;
 
  FOR i FROM LWB the doors TO UPB the doors DO
    FOR j FROM LWB the doors TO UPB the doors DO
      IF j MOD i = 0 THEN
        the doors[j] :=  NOT the doors[j]
      FI
    OD
  OD;
  FOR i FROM LWB the doors TO UPB the doors DO
    printf(($g" is "gl$,i,(the doors[i]|"opened"|"closed")))
  OD
);
doors;

optimized

PROC doors optimised = ( INT limit )VOID:
  FOR i TO limit DO
    REAL num := sqrt(i);
    printf(($g" is "gl$,i,(ENTIER num = num |"opened"|"closed") ))
  OD
;
doors optimised(limit)

ALGOL W

begin
    % find the first few squares via the unoptimised door flipping method   %
 
    integer doorMax;
    doorMax := 100;
 
    begin
        % need to start a new block so the array can have variable bounds   %
 
        % array of doors - door( i ) is true if open, false if closed       %
        logical array door( 1 :: doorMax );
 
        % set all doors to closed                                           %
        for i := 1 until doorMax do door( i ) := false;
 
        % repeatedly flip the doors                                         %
        for i := 1 until doorMax
        do begin
            for j := i step j until doorMax
            do begin
                door( j ) := not door( j )
            end
        end;
 
        % display the results                                               %
        i_w := 1; % set integer field width                                 %
        s_w := 1; % and separator width                                     %
        for i := 1 until doorMax do if door( i ) then writeon( i )
 
    end
 
end.

Output:

 1 4 9 16 25 36 49 64 81 100 

AmigaE

PROC main()
  DEF t[100]: ARRAY,
      pass, door
  FOR door := 0 TO 99 DO t[door] := FALSE
  FOR pass := 0 TO 99
    door := pass
    WHILE door <= 99
      t[door] := Not(t[door])
      door := door + pass + 1
    ENDWHILE
  ENDFOR
  FOR door := 0 TO 99 DO WriteF('\d is \s\n', door+1,
                                IF t[door] THEN 'open' ELSE 'closed')
ENDPROC

APL

Works with: GNU APL

doors←{100⍴((⍵-1)⍴0),1}
≠⌿⊃doors¨ ⍳100

Output:

1 0 0 1 0 0 0 0 1 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 
      0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 
      0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1

optimized Note that ⎕IO = 1

2|+/[1]0=D∘.|D←⍳100

The idea is that the n:th door will be flipped the same number of times as there are divisors for n. So first we make D all ints 1..100 (D←⍳100).
The next step is to find the remainders of every such int when divided by every other (D∘.|D).
This results in a 100×100 matrix which we turn into a binary one by testing if the values are equal to zero i.e. divisors.
Next: sum along axis 1, i.e. the columns. This tells us the number of divisors. Finally calculate the remainder of these when divided by 2, i.e. find which n have an odd number of divisors, i.e. will be flipped an odd number of times and thus end up open.

AppleScript

Iteration

set is_open to {}
repeat 100 times
   set end of is_open to false
end
repeat with pass from 1 to 100
  repeat with door from pass to 100 by pass
    set item door of is_open to not item door of is_open
  end
end
set open_doors to {}
repeat with door from 1 to 100
   if item door of is_open then
     set end of open_doors to door
   end
end
set text item delimiters to ", "
display dialog "Open doors: " & open_doors

Functional composition

-- FINAL DOOR STATES ---------------------------------------------------------
 
-- finalDoors :: Int -> [(Int, Bool)]
on finalDoors(n)
 
    -- toggledCorridor :: [(Int, Bool)] -> (Int, Bool) -> Int -> [(Int, Bool)]
    script toggledCorridor
        on |λ|(a, _, k)
 
            -- perhapsToggled :: Bool -> Int -> Bool
            script perhapsToggled
                on |λ|(x, i)
                    if i mod k = 0 then
                        {i, not item 2 of x}
                    else
                        {i, item 2 of x}
                    end if
                end |λ|
            end script
 
            map(perhapsToggled, a)
        end |λ|
    end script
 
    set xs to enumFromTo(1, n)
 
    foldl(toggledCorridor, ¬
        zip(xs, replicate(n, {false})), xs)
end finalDoors
 
-- TEST ----------------------------------------------------------------------
on run
    -- isOpenAtEnd :: (Int, Bool) -> Bool
    script isOpenAtEnd
        on |λ|(door)
            (item 2 of door)
        end |λ|
    end script
 
    -- doorNumber :: (Int, Bool) -> Int
    script doorNumber
        on |λ|(door)
            (item 1 of door)
        end |λ|
    end script
 
    map(doorNumber, filter(isOpenAtEnd, finalDoors(100)))
 
    --> {1, 4, 9, 16, 25, 36, 49, 64, 81, 100}
end run
 
 
-- GENERIC FUNCTIONS ---------------------------------------------------------
 
-- enumFromTo :: Int -> Int -> [Int]
on enumFromTo(m, n)
    if n < m then
        set d to -1
    else
        set d to 1
    end if
    set lst to {}
    repeat with i from m to n by d
        set end of lst to i
    end repeat
    return lst
end enumFromTo
 
-- filter :: (a -> Bool) -> [a] -> [a]
on filter(f, xs)
    tell mReturn(f)
        set lst to {}
        set lng to length of xs
        repeat with i from 1 to lng
            set v to item i of xs
            if |λ|(v, i, xs) then set end of lst to v
        end repeat
        return lst
    end tell
end filter
 
-- foldl :: (a -> b -> a) -> a -> [b] -> a
on foldl(f, startValue, xs)
    tell mReturn(f)
        set v to startValue
        set lng to length of xs
        repeat with i from 1 to lng
            set v to |λ|(v, item i of xs, i, xs)
        end repeat
        return v
    end tell
end foldl
 
-- map :: (a -> b) -> [a] -> [b]
on map(f, xs)
    tell mReturn(f)
        set lng to length of xs
        set lst to {}
        repeat with i from 1 to lng
            set end of lst to |λ|(item i of xs, i, xs)
        end repeat
        return lst
    end tell
end map
 
-- min :: Ord a => a -> a -> a
on min(x, y)
    if y < x then
        y
    else
        x
    end if
end min
 
-- Lift 2nd class handler function into 1st class script wrapper 
-- mReturn :: Handler -> Script
on mReturn(f)
    if class of f is script then
        f
    else
        script
            property |λ| : f
        end script
    end if
end mReturn
 
-- replicate :: Int -> a -> [a]
on replicate(n, a)
    set out to {}
    if n < 1 then return out
    set dbl to {a}
 
    repeat while (n > 1)
        if (n mod 2) > 0 then set out to out & dbl
        set n to (n div 2)
        set dbl to (dbl & dbl)
    end repeat
    return out & dbl
end replicate
 
-- zip :: [a] -> [b] -> [(a, b)]
on zip(xs, ys)
    set lng to min(length of xs, length of ys)
    set lst to {}
    repeat with i from 1 to lng
        set end of lst to {item i of xs, item i of ys}
    end repeat
    return lst
end zip

Output:

{1, 4, 9, 16, 25, 36, 49, 64, 81, 100}

Odd numbers of integer factors

The question of which doors are flipped an odd number of times reduces to the question of which numbers in the range have an odd number of integer factors (for an AppleScript implementation of integerFactors(n) see Factors of An Integer). Using map from the functional composition example above:

map(factorCountMod2, enumFromTo(1, 100))
 
on factorCountMod2(n)
    {n, (length of integerFactors(n)) mod 2 = 1}
end factorCountMod2

This, on inspection, and further reflection, then collapses to the even simpler question of which numbers are perfect squares, since all other numbers have an even number of integer factors (n factors below the square root, plus n paired cofactors above the square root). Using map and enumFromTo from the functional composition example above:

-- perfectSquaresUpTo :: Int -> [Int]
on perfectSquaresUpTo(n)
    script squared
        -- (Int -> Int)
        on |λ|(x)
            x * x
        end |λ|
    end script
 
    set realRoot to n ^ (1 / 2)
    set intRoot to realRoot as integer
    set blnNotPerfectSquare to not (intRoot = realRoot)
 
    map(squared, enumFromTo(1, intRoot - (blnNotPerfectSquare as integer)))
end perfectSquaresUpTo
 
on run
 
    perfectSquaresUpTo(100)
 
end run

Output:

{1, 4, 9, 16, 25, 36, 49, 64, 81, 100}

Arbre

 
openshut(n):
  for x in [1..n]
    x%n==0
 
pass(n):
  if n==100
    openshut(n)
  else
    openshut(n) xor pass(n+1)
 
100doors():
  pass(1) -> io
 

Argile

use std, array
 
close all doors
for each pass from 1 to 100
  for (door = pass) (door <= 100) (door += pass)
    toggle door
 
let int pass, door.
 
.: close all doors :. {memset doors 0 size of doors}
.:toggle <int door>:. {    !!(doors[door - 1])     }
 
let doors be an array of 100 bool
 
for each door from 1 to 100
  printf "#%.3d %s\n" door (doors[door - 1]) ? "[ ]", "[X]"

Astro

 
var doors = falses 100
for a in [:101]:
    for b in [a:a:101]: doors[b] = !doors[b]
    print "Door $a is $('open.' if doors[a] else 'closed.')"
 

ATS

 
#include "share/atspre_staload.hats"
 
implement
main0((*void*)) = let
//
var A = @[bool][100](false)
val A = $UNSAFE.cast{arrayref(bool,100)}([email protected])
//
fnx
loop
(
  pass: intGte(0)
) : void =
  if pass < 100
    then loop2 (pass, pass)
  // end of [if]
and
loop2
(
  pass: natLt(100), door: intGte(0)
) : void =
  if door < 100
    then (A[door] := ~A[door]; loop2(pass, door+pass+1))
    else loop(pass+1)
  // end of [if]
//
fun
loop3
(
  door: intGte(0)
) : void =
  if door < 100
    then (
      println!("door #", door+1, " is ", (if A[door] then "open" else "closed"): string, ".");
      loop3(door+1)
    ) (* end of [then] *)
  // end of [if]
//
in
  loop(0); loop3 (0)
end // end of [main0]
 

AutoHotkey

Standard Approach

Loop, 100
  Door%A_Index% := "closed"
 
Loop, 100 {
  x := A_Index, y := A_Index
  While (x <= 100)
  {
    CurrentDoor := Door%x%
    If CurrentDoor contains closed
    {
      Door%x% := "open"
      x += y
    }
    else if CurrentDoor contains open
    {
      Door%x% := "closed"
      x += y
    }
  }
}
 
Loop, 100 {
   CurrentDoor := Door%A_Index%
   If CurrentDoor contains open
      Res .= "Door " A_Index " is open`n"
}
MsgBox % Res

Alternative Approach

Making use of the identity:

$\sum _{i=1}^{n}(2i-1)=n^{2}$

increment := 3, square := 1 
Loop, 100 
    If (A_Index = square) 
        outstring .= "`nDoor " A_Index " is open" 
        ,square += increment, increment += 2 
MsgBox,, Succesfull, % SubStr(outstring, 2)

Optimized

While (Door := A_Index ** 2) <= 100
   Result .= "Door " Door " is open`n"
MsgBox, %Result%

AutoIt

 
#include <array.au3>
$doors = 100
 
;door array, 0 = closed, 1 = open
Local $door[$doors +1]
 
For $ii = 1 To $doors
	For $i = $ii To $doors Step $ii
		$door[$i] = Not $door[$i]
	next
Next
 
;display to screen
For $i = 1 To $doors
	ConsoleWrite (Number($door[$i])& " ")
	If Mod($i,10) = 0 Then ConsoleWrite(@CRLF)
Next
 

Axiom

Unoptimized:

(open,closed,change,open?) := (true,false,not,test);
doors := bits(100,closed);
for i in 1..#doors repeat
  for j in i..#doors by i repeat
    doors.j := change doors.j
[i for i in 1..#doors | open? doors.i]
 

Optimized:

[i for i in 1..100 | perfectSquare? i] -- or
[i^2 for i in 1..sqrt(100)::Integer]

AWK

unoptimized

BEGIN {
  for(i=1; i <= 100; i++)
  {
    doors[i] = 0 # close the doors
  }
  for(i=1; i <= 100; i++)
  {
    for(j=i; j <= 100; j += i)
    {
      doors[j] = (doors[j]+1) % 2
    }
  }
  for(i=1; i <= 100; i++)
  {
    print i, doors[i] ? "open" : "close"
  }
}

optimized

BEGIN {
  for(i=1; i <= 100; i++) {
    doors[i] = 0 # close the doors
  }
  for(i=1; i <= 100; i++) {
    if ( int(sqrt(i)) == sqrt(i) ) {
      doors[i] = 1
    }
  }
  for(i=1; i <= 100; i++)
  {
    print i, doors[i] ? "open" : "close"
  }
}

BASIC

QBASIC

Works with: QBASIC, QB64

unoptimized

REM "100 Doors" program FOR QB64 BASIC (http://www.qb64.net/), a QuickBASIC-like compiler.
REM Author: G. A. Tippery
REM Date: 12-Feb-2014
REM
REM   Unoptimized (naive) version, per specifications at http://rosettacode.org/wiki/100_doors
 
DEFINT A-Z
CONST N = 100
DIM door(N)
 
FOR stride = 1 TO N
    FOR index = stride TO N STEP stride
        LET door(index) = NOT (door(index))
    NEXT index
NEXT stride
 
PRINT "Open doors:"
FOR index = 1 TO N
    IF door(index) THEN PRINT index
NEXT index
 
END

Works with: QuickBasic version 4.5

unoptimized

DIM doors(0 TO 99)
FOR pass = 0 TO 99
	FOR door = pass TO 99 STEP pass + 1
		PRINT doors(door)
		PRINT NOT doors(door)
		doors(door) = NOT doors(door)
	NEXT door
NEXT pass
FOR i = 0 TO 99
	PRINT "Door #"; i + 1; " is ";
	IF NOT doors(i) THEN
		PRINT "closed"
	ELSE
		PRINT "open"
	END IF
NEXT i

optimized

DIM doors(0 TO 99)
FOR door = 0 TO 99
	IF INT(SQR(door)) = SQR(door) THEN doors(door) = -1
NEXT door
FOR i = 0 TO 99
	PRINT "Door #"; i + 1; " is ";
	IF NOT doors(i) THEN
		PRINT "closed"
	ELSE
		PRINT "open"
	END IF
NEXT i

optimized

 
'lrcvs 04.11.12
CLS
x = 1 : y = 3 : z = 0
PRINT x + " Open"
DO
z = x + y
PRINT z + " Open"
x = z : y = y + 2
UNTIL z >= 100
END
 

Sinclair ZX81 BASIC

Works with only 1k of RAM, although it doesn't leave too much to play with.

10 DIM D(100)
20 FOR I=1 TO 100
30 FOR J=I TO 100 STEP I
40 LET D(J)=NOT D(J)
50 NEXT J
60 NEXT I
70 FOR I=1 TO 100
80 IF D(I) THEN PRINT I,
90 NEXT I

BASIC256

# 100 doors problem
dim d(100)
 
# simple solution
print "simple solution"
gosub initialize
for t = 1 to 100
   for j = t to 100 step t
      d[j-1] = not d[j-1]
   next j
next t
gosub showopen
 
# more optimized solution
print "more optimized solution"
gosub initialize
for t = 1 to 10
      d[t^2-1] = true
next t
gosub showopen
end
 
initialize:
for t = 1 to d[?]
   d[t-1] = false	 # closed
next t
return
 
showopen:
for t = 1 to d[?]
   print d[t-1]+ " ";
   if t%10 = 0 then print
next t
return

Commodore BASIC

Based on the Sinclair ZX81 BASIC implementation.

10 DIM D(100)
20 FOR I=1 TO 100
30 FOR J=I TO 100 STEP I
40 D(J) = NOT D(J)
50 NEXT J
60 NEXT I
70 FOR I=1 TO 100
80 IF D(I) THEN PRINT I,
90 NEXT I

BaCon

 
OPTION BASE 1
 
DECLARE doors[100]
 
FOR size = 1 TO 100
    FOR pass = 0 TO 100 STEP size
	doors[pass] = NOT(doors[pass])
    NEXT
NEXT
 
FOR which = 1 TO 100
    IF doors[which] THEN PRINT which
NEXT
 

Output:

1
4
9
16
25
36
49
64
81
100

Batch File

unoptimized

 
@echo off
setlocal enableDelayedExpansion
:: 0 = closed
:: 1 = open
:: SET /A treats undefined variable as 0
:: Negation operator ! must be escaped because delayed expansion is enabled
for /l %%p in (1 1 100) do for /l %%d in (%%p %%p 100) do set /a "door%%d=^!door%%d"
for /l %%d in (1 1 100) do if !door%%d!==1 (
  echo door %%d is open
) else echo door %%d is closed
 

optimized

 
@echo off
setlocal enableDelayedExpansion
set /a square=1, incr=3
for /l %%d in (1 1 100) do (
  if %%d neq !square! (echo door %%d is closed) else (
    echo door %%d is open
    set /a square+=incr, incr+=2
  )
)
 

BBC BASIC

      DIM doors%(100)
 
      FOR pass% = 1 TO 100
        FOR door% = pass% TO 100 STEP pass%
          doors%(door%) = NOT doors%(door%)
        NEXT door%
      NEXT pass%
 
      FOR door% = 1 TO 100
        IF doors%(door%) PRINT "Door " ; door% " is open"
      NEXT door%

bc

/* 0 means door is closed, 1 means door is open */
for (i = 0; i < 100; i++) {
    for (j = i; j < 100; j += (i + 1)) {
        d[j] = 1 - d[j]     /* Toggle door */
    }
}
 
"Open doors:
"
for (i = 0; i < 100; i++) {
    if (d[i] == 1) (i + 1)
}

Befunge

Befunge-93

Unoptimized

Requires an interpreter with working read-write memory support. Padding the code page with extra blank lines can sometimes help.

>"d">:00p1-:>:::9%\9/9+g2%!\:9v
$.v_^#!$::$_^#`"c":+g00p+9/9\%<
::<[email protected]#`$:\*:+55:+1p27g1g+9/9\%9
 

Optimized

Just calculates the first 10 perfect squares.

1+:::*.9`#@_
 

Befunge-98

Works with: CCBI version 2.1

108p0>:18p;;>:9g!18g9p08g]
*`!0\|+relet|-1`*aap81::+]
;::+1<r]!g9;>$08g1+:08paa[
*`#@_^._aa

BlitzMax

Works with: BlitzMax version 1.37

optimized

Graphics 640,480
i=1
While ((i*i)<=100)
	a$=i*i
	DrawText a$,10,20*i
	Print i*i
	i=i+1 
Wend
Flip 
WaitKey 

Bracmat

Bracmat is not really at home in tasks that involve addressing things by index number. Here are four solutions that each do the task, but none should win a price for cleanliness.

Solution 1. Use an indexable array. Local variables are stored in stacks. Each stack corresponds to one variable name and vice versa. Stacks can also be used as arrays, but because of how local variables are implemented, arrays cannot be declared as local variables.

( 100doors-tbl
=   door step
  .   tbl$(doors.101) { Create an array. Indexing is 0-based. Add one extra for addressing element nr. 100 }
    & 0:?step
    &   whl
      ' ( 1+!step:~>100:?step   { ~> means 'not greater than', i.e. 'less than or equal' }
        & 0:?door
        &   whl
          ' ( !step+!door:~>100:?door
            & 1+-1*!(!door$doors):?doors  { <number>$<variable> sets the current index, which stays the same until explicitly changed. }
            )
        )
    & 0:?door
    &   whl
      ' ( 1+!door:~>100:?door
        &   out
          $ ( door
              !door
              is
              ( !(!door$doors):1&open
              | closed
              )
            )
        )
    & tbl$(doors.0)  { clean up the array }
)

Solution 2. Use one variable for each door. In Bracmat, a variable name can be any non-empty string, even a number, so we use the numbers 1 .. 100 as variable names, but also as door numbers. When used as variable an extra level of indirection is needed. See the occurrences of ?! and !! in the following code.

( 100doors-var
=   step door
  .   0:?door
    &   whl
      ' ( 1+!door:~>100:?door
        & closed:?!door { this creates a variable and assigns a value 'closed' to it }
        )
    & 0:?step
    &   whl
      ' ( 1+!step:~>100:?step
        & 0:?door
        &   whl
          ' ( !step+!door:~>100:?door
            &   ( !!door:closed&open
                | closed
                )
              : ?!door   
            )
        )
    & 0:?door
    &   whl
      ' ( 1+!door:~>100:?door
        & out$(door !door is !!door)
        )
    & 0:?door
    &   whl
      ' ( 1+!door:~>100:?door
        & tbl$(!door.0)         { cleanup the variable }
        )
)

Solution 3. Use a list and a dedicated positioning pattern to address the right door in the list. Create a new list by concatenating the skipped elements with the toggled elements. This solution is computationally unfavourable because of the many concatenations.

( 100doors-list
=   doors door doorIndex step
  .   :?doors
    & 0:?door
    &   whl
      ' ( 1+!door:~>100:?door
        & closed !doors:?doors
        )
    & 0:?skip
    &   whl
      ' ( :?ndoors
        &   whl
          ' ( !doors:?skipped [!skip %?door ?doors  { the [<number> pattern only succeeds when the scanning cursor is at position <number> }
            &     !ndoors
                  !skipped
                  ( !door:open&closed
                  | open
                  )
              : ?ndoors
            )
        & !ndoors !doors:?doors
        & 1+!skip:<100:?skip
        )
    & out$!doors
)

Solution 4. Use a list of objects. Each object can be changed without the need to re-create the whole list.

( 100doors-obj
=   doors door doorIndex step
  .   :?doors
    & 0:?door
    &   whl
      ' ( 1+!door:~>100:?door
        & new$(=closed) !doors:?doors
        )
    & 0:?skip
    &   whl
      ' ( !doors:?tododoors
        &   whl
          ' ( !tododoors:? [!skip %?door ?tododoors
            &   ( !(door.):open&closed
                | open
                )
              : ?(door.)
            )
        & 1+!skip:<100:?skip
        )
    & out$!doors
)

These four functions are called in the following way:

100doors-tbl$
& 100doors-var$
& 100doors-list$
& 100doors-obj$;

Burlesque

Version using square numbers:

 
blsq ) 10ro2?^
{1 4 9 16 25 36 49 64 81 100}
 

C

unoptimized

Uses: C Runtime (Components:printf,)

#include <stdio.h>
 
int main()
{
  char is_open[100] = { 0 };
  int pass, door;
 
  /* do the 100 passes */
  for (pass = 0; pass < 100; ++pass)
    for (door = pass; door < 100; door += pass+1)
      is_open[door] = !is_open[door];
 
  /* output the result */
  for (door = 0; door < 100; ++door)
    printf("door #%d is %s.\n", door+1, (is_open[door]? "open" : "closed"));
 
  return 0;
}

Using defensive programming, pointers, sentinel values and some other standard programming practices,

Uses: C Runtime (Components:printf,)

#include <stdio.h>
 
#define NUM_DOORS 100
 
int main(int argc, char *argv[])
{
  int is_open[NUM_DOORS] = { 0 } ;
  int * doorptr, * doorlimit = is_open + NUM_DOORS ;
  int pass ;
 
  /* do the N passes, go backwards because the order is not important */
  for ( pass= NUM_DOORS ; ( pass ) ; -- pass ) {
    for ( doorptr= is_open + ( pass-1 ); ( doorptr < doorlimit ) ; doorptr += pass ) {
      ( * doorptr ) ^= 1 ;
    }
  }
 
  /* output results */
  for ( doorptr= is_open ; ( doorptr != doorlimit ) ; ++ doorptr ) {
    printf("door #%ld is %s\n", ( doorptr - is_open ) + 1, ( * doorptr ) ? "open" : "closed" ) ;
  }
}

optimized

This optimized version makes use of the fact that finally only the doors with square index are open, as well as the fact that $n^{2}=1+3+5+\ldots +(2n-1)$.

Uses: C Runtime (Components:printf,)

#include <stdio.h>
 
int main()
{
  int square = 1, increment = 3, door;
  for (door = 1; door <= 100; ++door)
  {
    printf("door #%d", door);
    if (door == square)
    {
      printf(" is open.\n");
      square += increment;
      increment += 2;
    }
    else
      printf(" is closed.\n");
  }
  return 0;
}

The following ultra-short optimized version demonstrates the flexibility of C loops, but isn't really considered good C style:

#include <stdio.h>
 
int main()
{
  int door, square, increment;
  for (door = 1, square = 1, increment = 1; door <= 100; door++ == square && (square += increment += 2))
    printf("door #%d is %s.\n", door, (door == square? "open" : "closed"));
  return 0;
}

Or really optimize it -- square of an integer is, well, computable:

#include <stdio.h>
 
int main()
{
	int i;
	for (i = 1; i * i <= 100; i++)
		printf("door %d open\n", i * i);
 
	return 0;
}

C++

Works with: GCC version 4.1.2 20061115 (prerelease) (SUSE Linux)

unoptimized

#include <iostream>
 
int main()
{
  bool is_open[100] = { false };
 
  // do the 100 passes
  for (int pass = 0; pass < 100; ++pass)
    for (int door = pass; door < 100; door += pass+1)
      is_open[door] = !is_open[door];
 
  // output the result
  for (int door = 0; door < 100; ++door)
    std::cout << "door #" << door+1 << (is_open[door]? " is open." : " is closed.") << std::endl;
  return 0;
}

optimized This optimized version makes use of the fact that finally only the doors with square index are open, as well as the fact that $(n+1)^{2}=1+3+5+\ldots +(2n+1)$.

#include <iostream>
 
int main()
{
  int square = 1, increment = 3;
  for (int door = 1; door <= 100; ++door)
  {
    std::cout << "door #" << door;
    if (door == square)
    {
      std::cout << " is open." << std::endl;
      square += increment;
      increment += 2;
    }
    else
      std::cout << " is closed." << std::endl;
  }
  return 0;
}

The only calculation that's really needed:

#include <iostream> //compiled with "Dev-C++" , from RaptorOne
 
int main()
{
    for(int i=1; i*i<=100; i++)
            std::cout<<"Door "<<i*i<<" is open!"<<std::endl;
}

C#

Unoptimized with Modulus % Operator

namespace ConsoleApplication1
{
    using System;
    class Program
    {
        static void Main(string[] args)
        {
            bool[] doors = new bool[100];
 
            //Close all doors to start.
            for (int d = 0; d < 100; d++) doors[d] = false;
 
            //For each pass...
            for (int p = 0; p < 100; p++)//number of passes
            {
                //For each door to toggle...
                for (int d = 0; d < 100; d++)//door number
                {
                    if ((d + 1) % (p + 1) == 0)
                    {
                        doors[d] = !doors[d];
                    }
                }
            }
 
            //Output the results.
            Console.WriteLine("Passes Completed!!!  Here are the results: \r\n");
            for (int d = 0; d < 100; d++)
            {
                if (doors[d])
                {
                    Console.WriteLine(String.Format("Door #{0}: Open", d + 1));
                }
                else
                {
                    Console.WriteLine(String.Format("Door #{0}: Closed", d + 1));
                }
            }
            Console.ReadKey(true);
        }
    }
}

Optimized for Increments

namespace ConsoleApplication1
{
    using System;
    class Program
    {
        static void Main()
        {
            //The o variable stores the number of the next OPEN door.
            int o = 1;
 
            //The n variable is used to help calculate the next value of the o variable.
            int n = 0;
 
            //The d variable determines the door to be output next.
            for (int d = 1; d <= 100; d++)
            {
                Console.Write("Door #{0}: ", d);
                if (d == o)
                {
                    Console.WriteLine("Open");
                    n++;
                    o += 2 * n + 1;
                }
                else
                    Console.WriteLine("Closed");
            }
            Console.ReadKey(true);
        }
    }
}

Optimized for Orthogonality

(This version demonstrates a different thought pattern during development, where operation and presentation are separated. It could easily be refactored so that the operations to determine which doors are opened and to display the list of doors would be in separate methods, at which point it would become simple to extract them to separate classes and employ a DI pattern to switch the algorithm or display mechanism being used. It also keeps the calculation clear and concise.)

namespace ConsoleApplication1
{
    using System;
    class Program
    {
        static void Main(string[] args)
        {
            //Perform the operation.
            bool[] doors = new bool[100];
            int n = 0;
            int d;
            while ((d = (++n * n)) <= 100)
                doors[d - 1] = true;
 
            //Perform the presentation.
            for (d = 0; d < doors.Length; d++)
                Console.WriteLine("Door #{0}: {1}", d + 1, doors[d] ? "Open" : "Closed");
            Console.ReadKey(true);
        }
    }
}

Unoptimized but Concise

namespace ConsoleApplication1
{
    using System;
    class Program
    {
        static void Main()
        {
            bool[] doors = new bool[100];
 
            //The number of passes can be 1-based, but the number of doors must be 0-based.
            for (int p = 1; p <= 100; p++)
                for (int d = p - 1; d < 100; d += p)
                    doors[d] = !doors[d];
            for (int d = 0; d < 100; d++)
                Console.WriteLine("Door #{0}: {1}", d + 1, doors[d] ? "Open" : "Closed");
            Console.ReadKey(true);
        }
    }
}

Optimized for brevity

namespace ConsoleApplication1
{
    using System;
    class Program
    {
        static void Main()
        {
            double n;
 
            //If the current door number is the perfect square of an integer, say it is open, else say it is closed.
            for (int d = 1; d <= 100; d++)
                Console.WriteLine("Door #{0}: {1}", d, (n = Math.Sqrt(d)) == (int)n ? "Open" : "Closed");
            Console.ReadKey(true);
        }
    }
}

Ceylon

shared void run() {
    print("Open doors (naive):     ``naive()``
           Open doors (optimized): ``optimized()``");
 
}
 
shared {Integer*} naive(Integer count = 100) {
    variable value doors = [ for (_ in 1..count) closed ];
    for (step in 1..count) {
        doors = [for (i->door in doors.indexed) let (index = i+1) if (step == 1 || step.divides(index)) then door.toggle() else door ];
    }
    return doors.indexesWhere((door) => door == opened).map(1.plusInteger);
}
 
shared {Integer*} optimized(Integer count = 100) =>
        { for (i in 1..count) i*i }.takeWhile(count.notSmallerThan);
 
 
shared abstract class Door(shared actual String string) of opened | closed {
    shared formal Door toggle();
}
object opened extends Door("opened") { toggle() => closed; }
object closed extends Door("closed") { toggle() => opened; }

Output:

Open doors (naive):     { 1, 4, 9, 16, 25, 36, 49, 64, 81, 100 }
Open doors (optimized): { 1, 4, 9, 16, 25, 36, 49, 64, 81, 100 }

C1R

100_doors

Caché ObjectScript

 
 for i=1:1:100 {
	 set doors(i) = 0
 }
 for i=1:1:100 {
	 for door=i:i:100 {
		  Set doors(door)='doors(door)
	 }
 }
 for i = 1:1:100
 {
	if doors(i)=1 write i_": open",!
 }
 

Output:

 
1: open
4: open
9: open
16: open
25: open
36: open
49: open
64: open
81: open
100: open
 

Clarion

 
    program
 
    map
    end
 
MAX_DOOR_NUMBER         equate(100)
CRLF                    equate('<13,10>')
 
Doors                   byte,dim(MAX_DOOR_NUMBER)
Pass                    byte
DoorNumber              byte
DisplayString           cstring(2000)
 
ResultWindow            window('Result'),at(,,133,291),center,double,auto
                            prompt('Door states:'),at(8,4),use(?PromptTitle)
                            text,at(8,16,116,266),use(DisplayString),boxed,vscroll,font('Courier New',,,,CHARSET:ANSI),readonly
                        end
 
    code
 
    Doors :=: false
    loop Pass = 1 to MAX_DOOR_NUMBER
        loop DoorNumber = Pass to MAX_DOOR_NUMBER by Pass
            Doors[DoorNumber] = choose(Doors[DoorNumber], false, true)
        end
    end
 
    clear(DisplayString)
    loop DoorNumber = 1 to MAX_DOOR_NUMBER
        DisplayString = DisplayString & format(DoorNumber, @n3) & ' is ' & choose(Doors[DoorNumber], 'opened', 'closed') & CRLF
    end
    open(ResultWindow)
    accept
    end
    close(ResultWindow)
 
    return
 

CLIPS

Unoptimized

(deffacts initial-state
  (door-count 100)
)
 
(deffunction toggle
  (?state)
  (switch ?state
    (case "open" then "closed")
    (case "closed" then "open")
  )
)
 
(defrule create-doors-and-visits
  (door-count ?count)
  =>
  (loop-for-count (?num 1 ?count) do
    (assert (door ?num "closed"))
    (assert (visit-from ?num ?num))
  )
  (assert (doors initialized))
)
 
(defrule visit
  (door-count ?max)
  ?visit <- (visit-from ?num ?step)
  ?door <- (door ?num ?state)
  =>
  (retract ?visit)
  (retract ?door)
  (assert (door ?num (toggle ?state)))
  (if
    (<= (+ ?num ?step) ?max)
    then
    (assert (visit-from (+ ?num ?step) ?step))
  )
)
 
(defrule start-printing
  (doors initialized)
  (not (visit-from ? ?))
  =>
  (printout t "These doors are open:" crlf)
  (assert (print-from 1))
)
 
(defrule print-door
  (door-count ?max)
  ?pf <- (print-from ?num)
  (door ?num ?state)
  =>
  (retract ?pf)
  (if
    (= 0 (str-compare "open" ?state))
    then
    (printout t ?num " ")
  )
  (if
    (< ?num ?max)
    then
    (assert (print-from (+ ?num 1)))
    else
    (printout t crlf "All other doors are closed." crlf)
  )
)

Optimized

(deffacts initial-state
  (door-count 100)
)
 
(deffunction is-square
  (?num)
  (= (sqrt ?num) (integer (sqrt ?num)))
)
 
(defrule check-doors
  (door-count ?count)
  =>
  (printout t "These doors are open:" crlf)
  (loop-for-count (?num 1 ?count) do
    (if (is-square ?num) then
      (printout t ?num " ")
    )
  )
  (printout t crlf "All other doors are closed." crlf)
)

Clojure

Unoptimized / mutable array

(defn doors []
  (let [doors (into-array (repeat 100 false))]
    (doseq [pass   (range 1 101) 
            i      (range (dec pass) 100 pass) ]
      (aset doors i (not (aget doors i))))
    doors))   
 
(defn open-doors [] (for [[d n] (map vector (doors) (iterate inc 1)) :when d] n))
 
(defn print-open-doors []
  (println 
    "Open doors after 100 passes:"
    (apply str (interpose ", " (open-doors)))))

Unoptimized / functional

(defn doors []
  (reduce (fn [doors toggle-idx] (update-in doors [toggle-idx] not))
          (into [] (repeat 100 false))
          (for [pass   (range 1 101)
                i      (range (dec pass) 100 pass) ]
            i)))
 
(defn open-doors [] (for [[d n] (map vector (doors) (iterate inc 1)) :when d] n))
 
(defn print-open-doors []
  (println 
    "Open doors after 100 passes:"
    (apply str (interpose ", " (open-doors)))))

Alternative Unoptimized / functional

(defn open-doors []
  (->> (for [step (range 1 101), occ (range step 101 step)] occ)
       frequencies
       (filter (comp odd? val))
       keys
       sort))
 
(defn print-open-doors []
  (println 
    "Open doors after 100 passes:"
    (apply str (interpose ", " (open-doors)))))

Optimized / functional

(defn doors []
	(reduce (fn [doors idx] (assoc doors idx true)) 
	        (into [] (repeat 100 false))
	        (map #(dec (* % %)) (range 1 11))))
 
(defn open-doors [] (for [[d n] (map vector (doors) (iterate inc 1)) :when d] n))
 
(defn print-open-doors []
  (println 
    "Open doors after 100 passes:"
    (apply str (interpose ", " (open-doors)))))

Alternative Optimized / functional

(defn open-doors [] (->> (iterate inc 1) (map #(* % %)) (take-while #(<= % 100))))
 
(defn print-open-doors []
  (println 
    "Open doors after 100 passes:"
    (apply str (interpose ", " (open-doors)))))

COBOL

       IDENTIFICATION DIVISION.
       PROGRAM-ID. 100Doors.
 
       DATA DIVISION.
       WORKING-STORAGE SECTION.
       01 Current-n      PIC 9(3).
       01 StepSize       PIC 9(3).
       01 DoorTable.
          02 Doors       PIC 9(1)   OCCURS 100 TIMES.
             88 ClosedDoor          VALUE ZERO.
       01 Idx            PIC 9(3).
 
       PROCEDURE DIVISION.
       Begin.
           INITIALIZE DoorTable
           PERFORM VARYING StepSize FROM 1 BY 1 UNTIL StepSize > 100
             PERFORM VARYING Current-n FROM StepSize BY StepSize
                     UNTIL Current-n > 100
               SUBTRACT Doors (Current-n) FROM 1 GIVING Doors (Current-n)
             END-PERFORM
           END-PERFORM
 
           PERFORM VARYING Idx FROM 1 BY 1
                   UNTIL Idx > 100
             IF ClosedDoor (Idx)
               DISPLAY Idx " is closed."
             ELSE
               DISPLAY Idx " is open."
             END-IF
           END-PERFORM
 
           STOP RUN
           .

Coco

We use the naive algorithm.

doors = [false] * 100
 
for pass til doors.length
    for i from pass til doors.length by pass + 1
        ! = doors[i]
 
for i til doors.length
    console.log 'Door %d is %s.', i + 1, if doors[i] then 'open' else 'closed'

CoffeeScript

unoptimized:

doors = []
 
for pass in [1..100]
  for i in [pass..100] by pass
    doors[i] = !doors[i]
 
console.log "Doors #{index for index, open of doors when open} are open"
 
# matrix output
console.log doors.map (open) -> +open
 

optimized:

isInteger = (i) -> Math.floor(i) == i
 
console.log door for door in [1..100] when isInteger Math.sqrt door

ultra-optimized:

console.log Math.pow(i,2) for i in [1..10]

ColdFusion

Basic Solution: Returns List of 100 values: 1=open 0=closed

 
	doorCount = 1;
	doorList = "";
	// create all doors and set all doors to open
	while (doorCount LTE 100) {
		doorList = ListAppend(doorList,"1");
		doorCount = doorCount + 1;
	}
	loopCount = 2;
	doorListLen = ListLen(doorList);
	while (loopCount LTE 100) {
		loopDoorListCount = 1;
		while (loopDoorListCount LTE 100) {
			testDoor = loopDoorListCount / loopCount;
			if (testDoor EQ Int(testDoor)) {
				checkOpen = ListGetAt(doorList,loopDoorListCount);
				if (checkOpen EQ 1) {
					doorList = ListSetAt(doorList,loopDoorListCount,"0");
				} else {
					doorList = ListSetAt(doorList,loopDoorListCount,"1");
				}
			}
			loopDoorListCount = loopDoorListCount + 1;
		}
		loopCount = loopCount + 1;
	}
 

Squares of Integers Solution: Returns List of 100 values: 1=open 0=closed

 
	doorCount = 1;
	doorList = "";
	loopCount = 1;
	while (loopCount LTE 100) {
		if (Sqr(loopCount) NEQ Int(Sqr(loopCount))) {
			doorList = ListAppend(doorList,0);
		} else {
			doorList = ListAppend(doorList,1);
		}
		loopCount = loopCount + 1;
	}
 

Display only

// Display all doors
<cfloop from="1" to="100" index="x">
    Door #x# Open: #YesNoFormat(ListGetAt(doorList,x))#<br />
</cfloop>
 
// Output only open doors
<cfloop from="1" to="100" index="x">
    <cfif ListGetAt(doorList,x) EQ 1>
        #x#<br />
    </cfif>
</cfloop>

Another Route

<Cfparam name="doorlist" default="">
<cfloop from="1" to="100" index="i">
    <Cfset doorlist = doorlist & 'c,'>
</cfloop>
<cfloop from="1" to="100" index="i">
    <Cfloop from="1" to="100" index="door" step="#i#">
    <Cfif listgetat(doorlist, door) eq 'c'>
        <Cfset doorlist = listsetat(doorlist, door, 'O')>
    <Cfelse>
        <Cfset doorlist = listsetat(doorlist, door, 'c')>
    </Cfif>
    </Cfloop>
</cfloop>
<Cfoutput>#doorlist#</Cfoutput>

Commodore BASIC

 
10 D=100: DIMD(D): P=1
20 PRINT CHR$(147);"PASS: ";P
22 FOR I=P TO D STEP P: D(I)=NOTD(I): NEXT
30 IF P=100 THEN 40
32 P=P+1: GOTO20
40 PRINT: PRINT"THE FOLLOWING DOORS ARE OPEN: "
42 FOR I=1 TO D: IF D(I)=-1 THEN PRINTI;
44 NEXT
 

Common Lisp

Unoptimized / functional This is a very unoptimized version of the problem, using recursion and quite considerable list-copying. It emphasizes the functional way of solving this problem.

(defun visit-door (doors doornum value1 value2)
  "visits a door, swapping the value1 to value2 or vice-versa"
  (let ((d (copy-list doors))
        (n (- doornum 1)))
    (if (eql  (nth n d) value1)
        (setf (nth n d) value2)
      (setf (nth n d) value1))
    d))
 
(defun visit-every (doors num iter value1 value2)
  "visits every 'num' door in the list"
  (if (> (* iter num) (length doors))
      doors
    (visit-every (visit-door doors (* num iter) value1 value2)
                 num
                 (+ 1 iter)
                 value1
                 value2)))
 
(defun do-all-visits (doors cnt value1 value2)
  "Visits all doors changing the values accordingly"
  (if (< cnt 1)
      doors
    (do-all-visits (visit-every doors cnt 1 value1 value2)
                   (- cnt 1)
                   value1
                   value2)))
 
(defun print-doors (doors)
  "Pretty prints the doors list"
  (format T "~{~A ~A ~A ~A ~A ~A ~A ~A ~A ~A~%~}~%" doors))
 
(defun start (&optional (size 100))
  "Start the program"
  (let* ((open "_")
         (shut "#")
         (doors (make-list size :initial-element shut)))
    (print-doors (do-all-visits doors size open shut))))

Unoptimized, imperative This is a version that closely follows the problem description and is still quite short. Of all the presented solutions it might be closest to "idiomatic Common Lisp".

(define-modify-macro toggle () not)
 
(defun 100-doors ()
  (let ((doors (make-array 100)))
    (dotimes (i 100)
      (loop for j from i below 100 by (1+ i)
	 do (toggle (svref doors j))))
    (dotimes (i 100)
      (format t "door ~a: ~:[closed~;open~]~%" (1+ i) (svref doors i)))))

Unoptimized, n-doors.

(defun toggle (w m z)
  (loop for a in w for n from 1 to z
        collect (if (zerop (mod n m)) (not a) a)))
 
(defun doors (z &optional (w (make-list z)) (n 1))
  (if (> n z) w (doors z (toggle w n z) (1+ n))))
 
> (doors 100)
(T NIL NIL T NIL NIL NIL NIL T NIL NIL NIL NIL NIL NIL T NIL NIL NIL NIL NIL
 NIL NIL NIL T NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL T NIL NIL NIL NIL NIL
 NIL NIL NIL NIL NIL NIL NIL T NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL
 NIL NIL T NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL T
 NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL T)

Optimized This is an optimized version, using the perfect square algorithm.

(defun 100-doors ()
  (let ((doors (make-array 100)))
    (dotimes (i 10)
      (setf (svref doors (* i i)) t))
    (dotimes (i 100)
      (format t "door ~a: ~:[closed~;open~]~%" (1+ i) (svref doors i)))))

Optimized 2 Another optimized version, with finer granular separation of functionality (might be a bit excessive).

(defun perfect-square-list (n)                       
  "Generates a list of perfect squares from 0 up to n"
  (loop for i from 1 to (isqrt n) collect (expt i 2))) 
 
(defun print-doors (doors)
  "Pretty prints the doors list"
  (format T "~{~A ~A ~A ~A ~A ~A ~A ~A ~A ~A~%~}~%" doors))
 
(defun open-door (doors num open)
  "Sets door at num to open"
  (setf (nth (- num 1) doors) open)) 
 
(defun visit-all (doors vlist open)
  "Visits and opens all the doors indicated in vlist"
  (dolist (dn vlist doors)
    (open-door doors dn open)))
 
(defun start2 (&optional (size 100))                        
  "Start the program"
  (print-doors
   (visit-all (make-list size :initial-element '\#)
              (perfect-square-list size)
              '_)))

Optimized (2) This version displays a much more functional solution through the use of MAPCAR.

(let  ((i 0))
    (mapcar (lambda (x)
                (if (zerop (mod (sqrt (incf i)) 1))
                    "_" "#"))
            (make-list 100)))

Component Pascal

BlackBox Component Builder

 
MODULE Doors100;
IMPORT StdLog;
 
PROCEDURE Do*;
VAR
	i,j: INTEGER;
	closed: ARRAY 101 OF BOOLEAN;
BEGIN
	(* initilization of close to true *)
	FOR i := 0 TO LEN(closed) - 1 DO closed[i] := TRUE END;
	(* process *)
	FOR i := 1 TO LEN(closed)  DO;
		j := 1;
		WHILE j < LEN(closed) DO
			IF j MOD i = 0 THEN closed[j] := ~closed[j] END;INC(j)
		END
	END;
	(* print results *)
	i := 1;
	WHILE  i < LEN(closed)  DO
		IF (i - 1) MOD 10 = 0 THEN StdLog.Ln END;
		IF closed[i] THEN StdLog.String("C ") ELSE StdLog.String("O ") END;
		INC(i) 
	END;
END Do;
END Doors100.
 
 

Execute: ^Q Doors100.Do

Output:

O C C O C C C C O C 
C C C C C O C C C C 
C C C C O C C C C C 
C C C C C O C C C C 
C C C C C C C C O C 
C C C C C C C C C C 
C C C O C C C C C C 
C C C C C C C C C C 
O C C C C C C C C C 
C C C C C C C C C O 

Coq

Basic solution:

Require Import List.
 
Fixpoint rep {A} (a : A) n :=
  match n with
    | O => nil
    | S n' => a::(rep a n')
  end.
 
Fixpoint flip (l : list bool) (n k : nat) : list bool :=
  match l with
    | nil => nil
    | cons h t => match k with
                | O => (negb h) :: (flip t n n)
                | S k' => h :: (flip t n k')
              end
  end.
 
Definition flipeach l n := flip l n n.
 
Fixpoint flipwhile l n :=
  match n with
    | O => flipeach l 0
    | S n' => flipwhile (flipeach l (S n')) n'
  end.
 
Definition prison cells := flipwhile (rep false cells) cells.

Optimized version ((n+1)^2 = n^2 + 2n + 1):

Require Import List.
 
Fixpoint prisoo' nd n k accu :=
  match nd with
    | O => rev accu
    | S nd' => let ra := match k with
                 | O => (true, S n, (n + n))
                 | S k' => (false, n, k')
               end in
               prisoo' nd' (snd (fst ra)) (snd ra) ((fst (fst ra))::accu)
  end.
 
Definition prisoo cells := prisoo' cells 1 0 nil.

Unit test:

Goal prison 100 = prisoo 100. compute. reflexivity. Qed.

Full proof at github:

Goal forall n, prison n = prisoo n. Abort.

Crystal

doors = Array.new(100, false)
 
1.upto(100) do |i|
  i.step(by: i, limit: 100) do |j|
    doors[j - 1] = !doors[j - 1]
  end
end
 
doors.each_with_index do |open, i|
  puts "Door #{i + 1} is #{open ? "open" : "closed"}"
end

D

import std.stdio, std.algorithm, std.range;
 
enum DoorState : bool { closed, open }
alias Doors = DoorState[];
 
Doors flipUnoptimized(Doors doors) pure nothrow {
    doors[] = DoorState.closed;
 
    foreach (immutable i; 0 .. doors.length)
        for (ulong j = i; j < doors.length; j += i + 1)
            if (doors[j] == DoorState.open)
                doors[j] = DoorState.closed;
            else
                doors[j] = DoorState.open;
    return doors;
}
 
Doors flipOptimized(Doors doors) pure nothrow {
    doors[] = DoorState.closed;
    for (int i = 1; i ^^ 2 <= doors.length; i++)
        doors[i ^^ 2 - 1] = DoorState.open;
    return doors;
}
 
void main() {
    auto doors = new Doors(100);
 
    foreach (const open; [doors.dup.flipUnoptimized,
                          doors.dup.flipOptimized])
        iota(1, open.length + 1).filter!(i => open[i - 1]).writeln;
}

Output:

[1, 4, 9, 16, 25, 36, 49, 64, 81, 100]
[1, 4, 9, 16, 25, 36, 49, 64, 81, 100]

Unoptimized. Demonstrates very basic language syntax/features. Program output allows to see what the code is doing:

 
import std.stdio;
 
void printAllDoors(bool[] doors)
{
   // Prints the state of all the doors
   foreach(i, door; doors)
   {
      writeln("#: ", i + 1, (door) ? " open" : " closed");
      }
}
void main()
{
   bool[100] doors = false;   //Create 100 closed doors
   for(int a = 0; a < 100; ++a) {
      writefln("Pass #%s; visiting every %s door.", a + 1, a + 1);  // Optional
	 for(int i = a; i < 100; i += (a + 1)) {
	 writefln("Visited door %s", i + 1);  //Optional
	 doors[i] = !doors[i];
	 }
      writeln();  // Optional
      }
   printAllDoors(doors);   // Prints the state of each door
}
 

Dafny

The InitializeDoors function demonstrates some of Dafny's advanced features.

 
datatype Door = Closed | Open
 
method InitializeDoors(n:int) returns (doors:array<Door>)
  // Precondition: n must be a valid array size.
  requires n >= 0
  // Postcondition: doors is an array, which is not an alias for any other
  // object, with a length of n, all of whose elements are Closed. The "fresh"
  // (non-alias) condition is needed to allow doors to be modified by the
  // remaining code.
  ensures doors != null && fresh(doors) && doors.Length == n
  ensures forall j :: 0 <= j < doors.Length ==> doors[j] == Closed;
{
  doors := new Door[n];
  var i := 0;
  // Invariant: i is always a valid index inside the loop, and all doors less
  // than i are Closed. These invariants are needed to ensure the second
  // postcondition.
  while i < doors.Length
    invariant i <= doors.Length
    invariant forall j :: 0 <= j < i ==> doors[j] == Closed;
  {
    doors[i] := Closed;
    i := i + 1;
  }
}
 
method Main ()
{
  var doors := InitializeDoors(100);
 
  var pass := 1;
  while pass <= doors.Length
  {
    var door := pass;
    while door < doors.Length
    {
      doors[door] := if doors[door] == Closed then Open else Closed;
      door := door + pass;
    }
    pass := pass + 1;
  }
  var i := 0;
  while i < doors.Length
  {
    print i, " is ", if doors[i] == Closed then "closed\n" else "open\n";
    i := i + 1;
  }
}
 

Dart

unoptimized

main() {
    for (var k = 1, x = new List(101); k <= 100; k++) {
        for (int i = k; i <= 100; i += k)
            x[i] = !x[i];
        if (x[k]) print("$k open");
    }
}

optimized version (including generating squares without multiplication)

main() {
  for(int i=1,s=3;i<=100;i+=s,s+=2)
    print("door $i is open");
}

DCL

Adapted from optimized Batch example

 
$! doors.com
$! Excecute by running @doors at prompt.
$ square = 1
$ incr = 3
$ count2 = 0
$ d = 1
$ LOOP2:
$       count2 = count2 + 1
$       IF (d .NE. square)
$               THEN WRITE SYS$OUTPUT "door ''d' is closed"
$       ELSE WRITE SYS$OUTPUT "door ''d' is open"
$               square = incr + square
$               incr = incr + 2
$       ENDIF
$       d = d + 1
$       IF (count2 .LT. 100) THEN GOTO LOOP2
 

Delphi

See Pascal

Déjà Vu

local :open-doors [ rep 101 false ]
 
for i range 1 100:
	local :j i
	while <= j 100:
		set-to open-doors j not open-doors! j
		set :j + j i
 
!print\ "Open doors: "
for i range 1 100:
	if open-doors! i:
		!print\( to-str i " " )

Output:

Open doors: 1 4 9 16 25 36 49 64 81 100 

DUP

100[$][0^:1-]#                                                  {initialize doors}
%
[s;[$101<][$$;~\:s;+]#%]d:                                     {function d, switch door state function}
1s:[s;101<][d;!s;1+s:]#                                        {increment step width from 1 to 100, execute function d each time}
1[$101<][$$.' ,;['o,'p,'e,'n,10,]['c,'l,'o,'s,'e,'d,10,]?1+]#  {loop through doors, print door number and state}

Result:

1 open
2 closed
3 closed
4 open
5 closed
6 closed
7 closed
8 closed
9 open
10 closed
11 closed
12 closed
...
94 closed
95 closed
96 closed
97 closed
98 closed
99 closed
100 open

Compare this solution to the FALSE solution of this problem.

DWScript

Unoptimized

var doors : array [1..100] of Boolean;
var i, j : Integer;
 
for i := 1 to 100 do
   for j := i to 100 do
      if (j mod i) = 0 then
         doors[j] := not doors[j];F
 
for i := 1 to 100 do
   if doors[i] then
      PrintLn('Door '+IntToStr(i)+' is open');

Dylan

Unoptimized

define method doors()
  let doors = make(<array>, fill: #f, size: 100);
  for (x from 0 below 100)
    for (y from x below 100 by x + 1)
      doors[y] := ~doors[y]
    end
  end;
  for (x from 1 to 100) 
    if (doors[x - 1]) 
      format-out("door %d open\n", x)
    end
  end
end

E

Graphical

Works with: E-on-Java

This version animates the changes of the doors (as checkboxes).

#!/usr/bin/env rune
 
var toggles := []
var gets := []
 
# Set up GUI (and data model)
def frame := <swing:makeJFrame>("100 doors")
frame.getContentPane().setLayout(<awt:makeGridLayout>(10, 10))
for i in 1..100 {
  def component := <import:javax.swing.makeJCheckBox>(E.toString(i))
  toggles with= fn { component.setSelected(!component.isSelected()) }
  gets with= fn { component.isSelected() }
  frame.getContentPane().add(component)
}
 
# Set up termination condition
def done
frame.addWindowListener(def _ {
  to windowClosing(event) {
    bind done := true
  }
  match _ {}
})
 
# Open and close doors
def loop(step, i) {
  toggles[i] <- ()
  def next := i + step
  timer.whenPast(timer.now() + 10, fn {
    if (next >= 100) {
      if (step >= 100) {
        # Done.
      } else {
        loop <- (step + 1, step)
      }
    } else {
      loop <- (step, i + step)
    }    
  })
}
loop(1, 0)
 
frame.pack()
frame.show()
interp.waitAtTop(done)

EchoLisp

The result is obviously the same in we run the process backwards. So, we check the state of each door during the 100-th step (opening/closing every door)

 
; initial state = closed = #f
(define doors (make-vector 101 #f))
; run pass 100 to 1
(for* 
   ((pass (in-range 100 0 -1)) 
   (door (in-range 0 101 pass))) 
    (when (and 
        (vector-set! doors door (not (vector-ref doors door))) 
        (= pass 1)) 
        (writeln door "is open"))) 
 
1     "is open"    
4     "is open"    
9     "is open"    
16     "is open"    
25     "is open"    
36     "is open"    
49     "is open"    
64     "is open"    
81     "is open"    
100     "is open"    
 

ECL

optimized version

 
Doors := RECORD
 UNSIGNED1 DoorNumber;
 STRING6   State;
END;
 
AllDoors := DATASET([{0,0}],Doors);
 
Doors  OpenThem(AllDoors L,INTEGER Cnt) := TRANSFORM
 SELF.DoorNumber := Cnt;
 SELF.State      := IF((CNT * 10) % (SQRT(CNT)*10)<>0,'Closed','Opened');
END;
 
OpenDoors := NORMALIZE(AllDoors,100,OpenThem(LEFT,COUNTER));
 
OpenDoors;
 

unoptimized version - demonstrating LOOP

 
Doors := RECORD
  UNSIGNED1 DoorNumber;
  STRING6   State;
END;
 
AllDoors := DATASET([{0,'0'}],Doors);
 
//first build the 100 doors
 
Doors  OpenThem(AllDoors L,INTEGER Cnt) := TRANSFORM
  SELF.DoorNumber := Cnt;
  SELF.State      := 'Closed';
END;
 
ClosedDoors := NORMALIZE(AllDoors,100,OpenThem(LEFT,COUNTER));
 
//now iterate through them and use door logic
 
loopBody(DATASET(Doors) ds, UNSIGNED4 c) :=
            PROJECT(ds,    //ds=original input
              TRANSFORM(Doors,
                      	SELF.State := CASE((COUNTER % c) * 100,
		                            0 => IF(LEFT.STATE = 'Opened','Closed','Opened')
					    ,LEFT.STATE);
			SELF.DoorNumber := COUNTER;     //PROJECT COUNTER
                    ));
 
g1 := LOOP(ClosedDoors,100,loopBody(ROWS(LEFT),COUNTER));
 
OUTPUT(g1);
 
 

unoptimized version - using ITERATE This is a bit more efficient than the LOOP version

 
DoorSet := DATASET(100,TRANSFORM({UNSIGNED1 DoorState},SELF.DoorState := 1));
SetDoors := SET(DoorSet,DoorState);
 
Doors := RECORD
  UNSIGNED1 Pass;
  SET OF UNSIGNED1 DoorSet;
END;
 
StartDoors := DATASET(100,TRANSFORM(Doors,SELF.Pass := COUNTER,SELF.DoorSet := SetDoors));
 
Doors XF(Doors L, Doors R) := TRANSFORM
  ds := DATASET(L.DoorSet,{UNSIGNED1 DoorState});
  NextDoorSet := PROJECT(ds,  
                         TRANSFORM({UNSIGNED1 DoorState},
                      	           SELF.DoorState := CASE((COUNTER % R.Pass) * 100,
                                                          0 => IF(LEFT.DoorState = 1,0,1),
                                                          LEFT.DoorState)));
  SELF.DoorSet := IF(L.Pass=0,R.DoorSet,SET(NextDoorSet,DoorState));									
  SELF.Pass := R.Pass										
END;										
 
Res := DATASET(ITERATE(StartDoors,XF(LEFT,RIGHT))[100].DoorSet,{UNSIGNED1 DoorState});
PROJECT(Res,TRANSFORM({STRING20 txt},SELF.Txt := 'Door ' + COUNTER + ' is ' + IF(LEFT.DoorState=1,'Open','Closed')));
 

Eero

 
#import <Foundation/Foundation.h>
 
int main()
  square := 1, increment = 3
 
  for int door in 1 .. 100
    printf("door #%d", door)
 
    if door == square
      puts(" is open.")
      square += increment
      increment += 2
    else
      puts(" is closed.")
 
  return 0
 

EGL

 
program OneHundredDoors
 
   function main()
 
      doors boolean[] = new boolean[100];
      n int = 100;
 
      for (i int from 1 to n)
         for (j int from i to n by i)
            doors[j] = !doors[j];
         end
      end
 
      for (i int from 1 to n)
         if (doors[i])
            SysLib.writeStdout( "Door " + i + " is open" );
         end
      end
 
   end
 
end
 

Eiffel

This is my first RosettaCode submission, as well as a foray into Eiffel for myself. I've tried to adhere to the description of the problem statement, as well as showcase a few Eiffelisms shown in the documentation.

The replacement code below took the original code and has made improvements in some ways, such as:

1. Removal of "magic" many magic numbers and strings.
2. Refactor of various code blocks to routines (commands and queries with good CQS).
3. Utilization/Demonstration of full, secret, and selective feature exporting.
4. Utilization/Demonstration of constants as expanded type constants and once-functions.
5. Utilization/Demonstration of static-references (e.g. {APPLICATION}.min_door_count).
6. Utilization/Demonstration of "like" keyword type anchoring (e.g. a_index_address: like {DOOR}.address).
7. Utilization/Demonstration of semi-strict logical implication (e.g. consistency: is_open implies not Is_closed).
8. Utilization/Demonstration of contracts, including require, ensure, and class invariant.
9. Utilization/Demonstration of agent and `do_all' call on ITERABLE type.
10. Utilization/Demonstration of various forms of across including "loop" and "all".

... as well as other Eiffel-ism's and some coding standards/best-practices.

file: application.e

note
	description: "100 Doors problem"
	date: "08-JUL-2015"
	revision: "1.1"
 
class
	APPLICATION
 
create
	make
 
feature {NONE} -- Initialization
 
	make
			-- Main application routine.
		do
			initialize_closed_doors
			toggle_doors
			output_door_states
		end
 
feature -- Access
 
	doors: ARRAYED_LIST [DOOR]
			-- A set of doors (self-initialized to capacity of `max_door_count').
		attribute
			create Result.make (max_door_count)
		end
 
feature -- Basic Operations
 
	initialize_closed_doors
			-- Initialize all `doors'.
		do
			across min_door_count |..| max_door_count as ic_address_list loop
				doors.extend (create {DOOR}.make_closed (ic_address_list.item))
			end
		ensure
			has_all_closed_doors: across doors as ic_doors_list all not ic_doors_list.item.is_open end
		end
 
	toggle_doors
			-- Toggle all `doors'.
		do
			across min_door_count |..| max_door_count as ic_addresses_list loop
				across doors as ic_doors_list loop
					if is_door_to_toggle (ic_doors_list.item.address, ic_addresses_list.item) then
						ic_doors_list.item.toggle_door
					end
				end
			end
		end
 
	output_door_states
			-- Output the state of all `doors'.
		do
			doors.do_all (agent door_state_out)
		end
 
feature -- Status Report
 
	is_door_to_toggle (a_door_address, a_index_address: like {DOOR}.address): BOOLEAN
			-- Is the door at `a_door_address' needing to be toggled, when compared to `a_index_address'?
		do
			Result := a_door_address \\ a_index_address = 0
		ensure
			only_modulus_zero: Result = (a_door_address \\ a_index_address = 0)
		end
 
feature -- Outputs
 
	door_state_out (a_door: DOOR)
			-- Output the state of `a_door'.
		do
			print ("Door " + a_door.address.out + " is ")
			if a_door.is_open then
				print ("open.")
			else
				print ("closed.")
			end
			io.new_line
		end
 
feature {DOOR} -- Constants
 
	min_door_count: INTEGER = 1
			-- Minimum number of doors.
 
	max_door_count: INTEGER = 100
			-- Maximum number of doors.
 
end

file: door.e

note
	description: "A door with an address and an open or closed state."
	date: "08-JUL-2015"
	revision: "1.1"
 
class
	DOOR
 
create
	make_closed,
	make
 
feature {NONE} -- initialization
 
	make_closed (a_address: INTEGER)
			-- Initialize Current {DOOR} at `a_address' and state of `Is_closed'.
		require
			positive: a_address >= {APPLICATION}.min_door_count and a_address >= Min_door_count
		do
			make (a_address, Is_closed)
		ensure
			closed: is_open = Is_closed
		end
 
	make (a_address: INTEGER; a_status: BOOLEAN)
			-- Initialize Current {DOOR} with `a_address' and `a_status', denoting position and `is_open' or `Is_closed'.
		require
			positive: a_address >= {APPLICATION}.min_door_count and a_address >= Min_door_count
		do
			address := a_address
			is_open := a_status
		ensure
			address_set: address = a_address
			status_set: is_open = a_status
		end
 
feature -- access
 
	address: INTEGER
			-- `address' of Current {DOOR}.
 
	is_open: BOOLEAN assign set_open
			-- `is_open' (or not) status of Current {DOOR}.
 
feature -- Setters
 
	set_open (a_status: BOOLEAN)
			-- Set `status' with `a_status'
		do
			is_open := a_status
		ensure
			open_updated: is_open = a_status
		end
 
feature {APPLICATION} -- Basic Operations
 
	toggle_door
			-- Toggle Current {DOOR} from `is_open' to not `is_open'.
		do
			is_open := not is_open
		ensure
			toggled: is_open /= old is_open
		end
 
feature {NONE} -- Implementation: Constants
 
	Is_closed: BOOLEAN = False
			-- State of being not `is_open'.
 
	Min_door_count: INTEGER = 1
			-- Minimum door count.
 
invariant
	one_or_more: address >= 1
	consistency: is_open implies not Is_closed
 
end

Ela

Standard Approach

open generic
 
type Door = Open | Closed
  deriving Show
 
gate [] _ = []
gate (x::xs) (y::ys) 
  | x == y = Open :: gate xs ys
  | else = Closed :: gate xs ys
 
run n = gate [1..n] [& k*k \\ k <- [1..]]

Alternate Approach

open list
run n = takeWhile (<n) [& k*k \\ k <- [1..]]

Elena

ELENA 3.2 :

import system'routines.
import extensions.
 
program =
[
    var Doors := Array new:100; populate(:n)( false ).
 
    0 till:100 do(:i)
    [
        i till:100 by(i + 1) do(:j)
        [  
            Doors[j] := Doors[j] not
        ]
    ].
 
    0 till:100 do(:i)
    [
        console printLine("Door #",i + 1," :",Doors[i] iif("Open","Closed"))
    ].
 
    console readChar.
].

Elixir

defmodule HundredDoors do
  def doors(n \\ 100) do
    List.duplicate(false, n)
  end
 
  def toggle(doors, n) do
    List.update_at(doors, n, &(!&1))
  end
 
  def toggle_every(doors, n) do
    Enum.reduce( Enum.take_every((n-1)..99, n), doors, fn(n, acc) -> toggle(acc, n) end )
  end
end
 
# unoptimized
final_state = Enum.reduce(1..100, HundredDoors.doors, fn(n, acc) -> HundredDoors.toggle_every(acc, n) end)
 
open_doors = Enum.with_index(final_state)
             |> Enum.filter_map(fn {door,_} -> door end, fn {_,index} -> index+1 end)
 
IO.puts "All doors are closed except these: #{inspect open_doors}"
 
 
# optimized 
final_state = Enum.reduce(1..10, HundredDoors.doors, fn(n, acc) -> HundredDoors.toggle(acc, n*n-1) end)
 
open_doors = Enum.with_index(final_state)
             |> Enum.filter_map(fn {door,_} -> door end, fn {_,index} -> index+1 end)
 
IO.puts "All doors are closed except these: #{inspect open_doors}"

Output:

All doors are closed except these: [1, 4, 9, 16, 25, 36, 49, 64, 81, 100]

Elm

-- Unoptimized
import List exposing (indexedMap, foldl, repeat, range)
import Html exposing (text)
 
type Door = Open | Closed
 
toggle d = if d == Open then Closed else Open
 
toggleEvery : Int -> List Door -> List Door
toggleEvery k doors = indexedMap 
  (\i door -> if i % k == 0 then toggle door else door)
  doors
 
n = 100
 
main = 
  text (toString (foldl toggleEvery (repeat n Closed) (range 1 n)))
 

Emacs Lisp

Unoptimized

(defun create-doors ()
  "Returns a list of closed doors
 
Each door only has two status: open or closed.
If a door is closed it has the value 0, if it's open it has the value 1."
  (let ((return_value '(0))
         ;; There is already a door in the return_value, so k starts at 1
         ;; otherwise we would need to compare k against 99 and not 100 in
         ;; the while loop
         (k 1))
    (while (< k 100)
      (setq return_value (cons 0 return_value))
      (setq k (+ 1 k)))
    return_value))
 
(defun toggle-single-door (doors)
  "Toggle the stat of the door at the `car' position of the DOORS list
 
DOORS is a list of integers with either the value 0 or 1 and it represents
a row of doors.
 
Returns a list where the `car' of the list has it's value toggled (if open
it becomes closed, if closed it becomes open)."
  (if (= (car doors) 1)
    (cons 0 (cdr doors))
    (cons 1 (cdr doors))))
 
(defun toggle-doors (doors step original-step)
  "Step through all elements of the doors' list and toggle a door when step is 1
 
DOORS is a list of integers with either the value 0 or 1 and it represents
a row of doors.
STEP is the number of doors we still need to transverse before we arrive
at a door that has to be toggled.
ORIGINAL-STEP is the value of the argument step when this function is
called for the first time.
 
Returns a list of doors"
  (cond ((null doors)
          '())
    ((= step 1)
      (cons (car (toggle-single-door doors))
        (toggle-doors (cdr doors) original-step original-step)))
    (t
      (cons (car doors)
        (toggle-doors (cdr doors) (- step 1) original-step)))))
 
(defun main-program ()
  "The main loop for the program"
  (let ((doors_list (create-doors))
         (k 1)
         ;; We need to define max-specpdl-size and max-specpdl-size to big
         ;; numbers otherwise the loop reaches the max recursion depth and
         ;; throws an error.
         ;; If you want more information about these variables, press Ctrl
         ;; and h at the same time and then press v and then type the name
         ;; of the variable that you want to read the documentation.
         (max-specpdl-size 5000)
         (max-lisp-eval-depth 2000))
    (while (< k 101)
      (setq doors_list (toggle-doors doors_list k k))
      (setq k (+ 1 k)))
    doors_list))
 
(defun print-doors (doors)
  "This function prints the values of the doors into the current buffer.
 
DOORS is a list of integers with either the value 0 or 1 and it represents
a row of doors.
"
  ;; As in the main-program function, we need to set the variable
  ;; max-lisp-eval-depth to a big number so it doesn't reach max recursion
  ;; depth.
  (let ((max-lisp-eval-depth 5000))
    (unless (null doors)
      (insert (int-to-string (car doors)))
      (print-doors (cdr doors)))))
 
;; Returns a list with the final solution
(main-program)
 
;; Print the final solution on the buffer
(print-doors (main-program))

Erlang

non-optimized

 
-module(hundoors).
 
-export([go/0]).
 
toggle(closed) -> open;
toggle(open) -> closed.
 
go() -> go([closed || _ <- lists:seq(1, 100)],[], 1, 1).
go([], L, N, _I) when N =:= 101 -> lists:reverse(L);
go([], L, N, _I) -> go(lists:reverse(L), [], N + 1, 1);
go([H|T], L, N, I) ->
  H2 = case I rem N of
    0 -> toggle(H);
    _ -> H
  end,
  go(T, [H2|L], N, I + 1).
 

optimized

doors() ->
     F = fun(X) -> Root = math:pow(X,0.5), Root == trunc(Root) end,
     Out = fun(X, true) -> io:format("Door ~p: open~n",[X]);
              (X, false)-> io:format("Door ~p: close~n",[X]) end,
     [Out(X,F(X)) || X <- lists:seq(1,100)].

ERRE

 
! "100 Doors" program for ERRE LANGUAGE
! Author: Claudio Larini
! Date: 21-Nov-2014
!
! PC Unoptimized version translated from a QB version
 
PROGRAM 100DOORS
 
!$INTEGER
 
CONST N=100
 
DIM DOOR[N]
 
BEGIN
 
FOR STRIDE=1 TO N DO
    FOR INDEX=STRIDE TO N STEP STRIDE DO
        DOOR[INDEX]=NOT(DOOR[INDEX])
    END FOR
END FOR
 
PRINT("Open doors:";)
FOR INDEX=1 TO N DO
    IF DOOR[INDEX] THEN PRINT(INDEX;) END IF
END FOR
PRINT
 
END PROGRAM
 

Euler Math Toolbox

 
>function Doors () ...
$  doors:=zeros(1,100);
$  for i=1 to 100
$    for j=i to 100 step i
$      doors[j]=!doors[j];
$    end;
$  end;
$  return doors
$endfunction
>nonzeros(Doors())
 [ 1  4  9  16  25  36  49  64  81  100 ]
 

Euphoria

unoptimised

-- doors.ex
include std/console.e
sequence doors
doors = repeat( 0, 100 ) -- 1 to 100, initialised to false 
 
for pass = 1 to 100 do
	for door = pass to 100 by pass do
		--printf( 1, "%d", doors[door] )
		--printf( 1, "%d", not doors[door] )
		doors[door] = not doors[door]
	end for
end for
 
sequence oc
 
for i = 1 to 100 do
	if doors[i] then
		oc = "open"
	else
		oc = "closed"
	end if
 	printf( 1, "door %d is %s\n", { i, oc } )
end for
 

F#

Requires #light in versions of F# prior to 2010 beta.

let answerDoors =
    let ToggleNth n (lst:bool array) =                  // Toggle every n'th door
        [(n-1) .. n .. 99]                              // For each appropriate door
        |> Seq.iter (fun i -> lst.[i] <- not lst.[i])   // toggle it
    let doors = Array.create 100 false                  // Initialize all doors to closed
    Seq.iter (fun n -> ToggleNth n doors) [1..100]      // toggle the appropriate doors for each pass
    doors                                               // Initialize all doors to closed
 

Unoptimized / functional

 
let modifier doors skip =
    let rec modifierInner doors skip counter =
        match doors with
        | [] -> []                                                  //base case: end of hall
        | first::rest when counter >= skip ->                       //case: reached door marked for change
            not first::(modifierInner rest skip 0)                  //  open or close that door
        | first::rest ->                                            //case: reached door to skip
            first::(modifierInner rest skip (counter+1))            //  skip it                         
    modifierInner doors skip 0                                      //Initial state for walkthrough
 
let answerDoors doors =
    let rec modifyDoors skipRange doors modifier =                  //fold each door result to the next with
        List.fold modifier doors skipRange                          //with an increasing skip
    modifyDoors [0..99] doors modifier                              //Initial starting state
 
let initDoors = Array.create 100 false |> Array.toList              //Initialize all doors to closed (false)
 
answerDoors initDoors |> printfn "%A"                               //print answer (false is closed door)
 

Tail-Recursive Optimized/Functional

 
let modifier doors skip =
    let rec modifier' doors skip counter result =
        match doors with
        | [] -> result |> List.rev                                  //base case: end of hall
        | first::rest when counter >= skip ->                       //case: reached door marked for change
            modifier' rest skip 0 ((not first)::result)             //  open or close that door
        | first::rest ->                                            //case: reached door to skip
            modifier' rest skip (counter+1) (first::result)         //  skip it                         
    modifier' doors skip 0 []                                       //Initial state for walkthrough
 

Following is the solution using perfect squares. The coercions in PerfectSquare are, I believe, slightly different in versions prior to 2010 beta and, again, #light is required in those versions.

open System
let answer2 =
    let PerfectSquare n =
        let sqrt = int(Math.Sqrt(float n))
        n = sqrt * sqrt
    [| for i in 1..100 do yield PerfectSquare i |]

Factor

Unoptimized

USING: bit-arrays formatting fry kernel math math.ranges
sequences ;
IN: rosetta.doors
 
CONSTANT: number-of-doors 100
 
: multiples ( n -- range )
    0 number-of-doors rot <range> ;
 
: toggle-multiples ( n doors -- )
    [ multiples ] dip '[ _ [ not ] change-nth ] each ;
 
: toggle-all-multiples ( doors -- )
    [ number-of-doors [1,b] ] dip '[ _ toggle-multiples ] each ;
 
: print-doors ( doors -- )
    [
        swap "open" "closed" ? "Door %d is %s\n" printf
    ] each-index ;
 
: main ( -- )
    number-of-doors 1 + <bit-array>
    [ toggle-all-multiples ] [ print-doors ] bi ;
 
main

Optimized

 
USING:
    formatting
    math math.primes.factors math.ranges
    sequences ;
IN: rosetta-doors2
 
: main ( -- )
    100 [1,b] [ divisors length odd? ] filter "Open %[%d, %]\n" printf ;
 

Falcon

Unoptimized code

doors = arrayBuffer( 101, false )
 
for pass in [ 0 : doors.len() ]
  for door in [ 0 : doors.len() : pass+1 ]
    doors[ door ] = not doors[ door ]
  end
end
 
for door in [ 1 : doors.len() ]  // Show Output
  >  "Door ", $door, " is: ", ( doors[ door ] ) ? "open" : "closed"
end
 

Optimized code

 
for door in [ 1 : 101 ]: > "Door ", $door, " is: ", fract( door ** 0.5 ) ? "closed" : "open"

FALSE

100[$][0 1ø:1-]#              {initialize doors}
%
[s;[$101\>][$$;~\:s;+]#%]d:   {function d, switch door state function}
1s:[s;101\>][d;!s;1+s:]#      {increment step width from 1 to 100, execute function d each time}
1[$101\>][$$." ";$["open
"]?~["closed
"]?1+]#                       {loop through doors, print door number and state}

Result:

1 open
2 closed
3 closed
4 open
5 closed
6 closed
7 closed
8 closed
9 open
10 closed
...
98 closed
99 closed
100 open

Compare this solution to the DUP solution of this problem.

Fantom

Unoptimized

 
    states := (1..100).toList
    100.times |i| {
      states = states.map |state| { state % (i+1) == 0 ? -state : +state }
    }
    echo("Open doors are " + states.findAll { it < 0 }.map { -it })
 

Optimized

 
    echo("Open doors are " + (1..100).toList.findAll { it.toFloat.pow(0.5f).toInt.pow(2) == it})
 

FBSL

Unoptimised

#AppType Console
 
DIM doors[], n AS INTEGER = 100
 
FOR DIM i = 1 TO n
	FOR DIM j = i TO n STEP i
		doors[j] = NOT doors[j]
	NEXT
NEXT
 
FOR i = 1 TO n
	IF doors[i] THEN PRINT "Door ", i, " is open"
NEXT
 
Pause

Optimised (by ML)

#APPTYPE CONSOLE
 
DIM i = 0, j = 0, door = 1
 
WHILE INCR(i) < 101
 IF i = door THEN
   PRINT "Door ", door, " open"
   INCR(door, INCR((INCR(j) << 1)))
 END IF
WEND
 
PAUSE

friendly interactive shell

Unoptimized

# Set doors to empty list
set doors
 
# Initialize doors arrays
for i in (seq 100)
    set doors[$i] 0
end
 
for i in (seq 100)
    set j $i
    while test $j -le 100
        # Logical not on doors
        set doors[$j] (math !$doors[$j])
        set j (math $j + $i)
    end
end
 
# Print every door
for i in (seq (count $doors))
    echo -n "$i "
    if test $doors[$i] -eq 0
        echo closed
    else
        echo open
    end
end
 

Optimized

# Set doors to empty list
set doors
 
for i in (seq 100)
    set doors[(math "$i * $i")] 1
    echo -n "$i "
    if test $doors[$i] -eq 1
        echo open
    else
        echo closed
    end
end

Forth

Unoptimized

: toggle ( c-addr -- )  \ toggle the byte at c-addr
    dup [email protected] 1 xor swap c! ;
 
100  1+ ( 1-based indexing ) constant ndoors
create doors  ndoors allot
 
: init ( -- )  doors ndoors erase ;  \ close all doors
 
: pass ( n -- )  \ toggle every nth door
    ndoors over do
        doors i + toggle
    dup ( n ) +loop drop ;
 
: run ( -- )  ndoors 1 do  i pass  loop ;
: display ( -- )  \ display open doors
    ndoors 1 do  doors i + [email protected] if  i .  then loop cr ;
 
init run display

Optimized

: squared ( n -- n' )  dup * ;
: doors ( n -- )
    1 begin 2dup squared >= while
        dup squared .
    1+ repeat 2drop ;
100 doors

Fortran

Works with: Fortran 90

unoptimized

program doors
    implicit none
    integer, allocatable :: door(:)
    character(6), parameter :: s(0:1) = ["closed", "open  "]
    integer :: i, n
 
    print "(A)", "Number of doors?"
    read *, n
    allocate (door(n))
    door = 1
    do i = 1, n
        door(i:n:i) = 1 - door(i:n:i)
        print "(A,G0,2A)", "door ", i, " is ", s(door(i))
    end do
end program

optimized

PROGRAM DOORS
 
  INTEGER, PARAMETER :: n = 100    ! Number of doors
  INTEGER :: i
  LOGICAL :: door(n) = .TRUE.      ! Initially closed
 
  DO i = 1, SQRT(REAL(n))
    door(i*i) = .FALSE.
  END DO  
 
  DO i = 1, n
    WRITE(*,"(A,I3,A)", ADVANCE="NO") "Door ", i, " is "
    IF (door(i)) THEN
      WRITE(*,"(A)") "closed"
    ELSE
      WRITE(*,"(A)") "open"
    END IF
  END DO
 
END PROGRAM DOORS

FreeBASIC

Toggle

' version 27-10-2016
' compile with: fbc -s console
 
#Define max_doors 100
 
Dim As ULong c, n, n1, door(1 To max_doors)
 
' toggle, at start all doors are closed (0)
' 0 = door closed, 1 = door open
For n = 1 To max_doors
    For n1 = n To max_doors Step n
        door(n1) = 1 - door(n1)
    Next
Next
 
' count the doors that are open (1)
Print "doors that are open nr: ";
For n = 1 To max_doors
    If door(n) = 1 Then
        Print n; " ";
        c = c + 1
    End If
Next
 
Print : Print
Print "There are " + Str(c) + " doors open"
 
' empty keyboard buffer
While InKey <> "" : Wend
Print : Print "hit any key to end program"
Sleep
End

Output:

doors that are open nr: 1 4 9 16 25 36 49 64 81 100 

There are 10 doors open

Count

' version 27-10-2016
' compile with: fbc -s console
 
#Define max_doors 100
 
Dim As ULong c, n, n1, door(1 To max_doors)
 
' at start all doors are closed
' simple add 1 each time we open or close a door
' doors with odd numbers are open
' doors with even numbers are closed
For n = 1 To max_doors
    For n1 = n To max_doors Step n
        door(n1) += 1
    Next
Next
 
Print "doors that are open nr: ";
For n = 1 To max_doors
    If door(n) And 1 Then
        Print n; " ";
        c = c + 1
    End If
Next
 
Print : Print
Print "There are " + Str(c) + " doors open"
 
' empty keyboard buffer
While InKey <> "" : Wend
Print : Print "hit any key to end program"
Sleep
End

Output is the same as the first version.

Optimized

' version 27-10-2016
' compile with: fbc -s console
 
#Define max_doors 100
 
Dim As ULong c, n
 
Print "doors that are open nr: ";
For n = 1 To 10
    Print n * n; " ";
    c = c + 1
Next
 
Print : Print
Print "There are " + Str(c) + " doors open"
 
' empty keyboard buffer
While InKey <> "" : Wend
Print : Print "hit any key to end program"
Sleep
End

Output is the same as the first version.

Frink

 
doors = new array[[101], false]
for pass=1 to 100
   for door=pass to 100 step pass
      [email protected] = ! [email protected]
 
print["Open doors:  "]
for door=1 to 100
   if [email protected]
      print["$door "]
 

FunL

Unoptimized

for i <- 1..100
  r = foldl1( \a, b -> a xor b, [(a|i) | a <- 1..100] )
  println( i + ' ' + (if r then 'open' else 'closed') )

Optimized

import math.sqrt
 
for i <- 1..100
  println( i + ' ' + (if sqrt(i) is Integer then 'open' else 'closed') )

Futhark

 
fun main(n: int): [n]bool =
  let is_open = replicate n False
  loop (is_open) = for i < n do
    let js = map (*i+1) (iota n)
    let flips = map (fn j =>
                       if j < n
                       then unsafe !is_open[j]
                       else True -- Doesn't matter.
                    ) js
    in write js flips is_open
  in is_open
 

FutureBasic

 
include "ConsoleWindow"
 
dim as short door, square : square = 1
dim as short increment : increment = 3
 
for door = 1 to 100
   if (door == square)
      print "Door"; door; " is open."
      square += increment
      increment += 2
   else
      print "Door"; door; " is closed."
   end if
next
 

Output:

Door 1 is open.
Door 2 is closed.
Door 3 is closed.
Door 4 is open.
Door 5 is closed.
Door 6 is closed.
Door 7 is closed.
Door 8 is closed.
Door 9 is open.
Door 10 is closed.
Door 11 is closed.
Door 12 is closed.
Door 13 is closed.
Door 14 is closed.
Door 15 is closed.
Door 16 is open.
Door 17 is closed.
Door 18 is closed.
Door 19 is closed.
Door 20 is closed.
Door 21 is closed.
Door 22 is closed.
Door 23 is closed.
Door 24 is closed.
Door 25 is open.
Door 26 is closed.
Door 27 is closed.
Door 28 is closed.
Door 29 is closed.
Door 30 is closed.
Door 31 is closed.
Door 32 is closed.
Door 33 is closed.
Door 34 is closed.
Door 35 is closed.
Door 36 is open.
Door 37 is closed.
Door 38 is closed.
Door 39 is closed.
Door 40 is closed.
Door 41 is closed.
Door 42 is closed.
Door 43 is closed.
Door 44 is closed.
Door 45 is closed.
Door 46 is closed.
Door 47 is closed.
Door 48 is closed.
Door 49 is open.
Door 50 is closed.
Door 51 is closed.
Door 52 is closed.
Door 53 is closed.
Door 54 is closed.
Door 55 is closed.
Door 56 is closed.
Door 57 is closed.
Door 58 is closed.
Door 59 is closed.
Door 60 is closed.
Door 61 is closed.
Door 62 is closed.
Door 63 is closed.
Door 64 is open.
Door 65 is closed.
Door 66 is closed.
Door 67 is closed.
Door 68 is closed.
Door 69 is closed.
Door 70 is closed.
Door 71 is closed.
Door 72 is closed.
Door 73 is closed.
Door 74 is closed.
Door 75 is closed.
Door 76 is closed.
Door 77 is closed.
Door 78 is closed.
Door 79 is closed.
Door 80 is closed.
Door 81 is open.
Door 82 is closed.
Door 83 is closed.
Door 84 is closed.
Door 85 is closed.
Door 86 is closed.
Door 87 is closed.
Door 88 is closed.
Door 89 is closed.
Door 90 is closed.
Door 91 is closed.
Door 92 is closed.
Door 93 is closed.
Door 94 is closed.
Door 95 is closed.
Door 96 is closed.
Door 97 is closed.
Door 98 is closed.
Door 99 is closed.
Door 100 is open.

FUZE BASIC

-- Scott A. Rossell, 02-27-16

READ x,y,z
PRINT "Open doors: ";x;" ";
CYCLE
    z=x+y
    PRINT z;" ";
    x=z
    y=y+2
REPEAT UNTIL z>=100
DATA 1,3,0
END

Gambas

Click this link to run this code

Public Sub Main()
Dim bDoor As New Boolean[101]
Dim siCount1, siCount2, siStart As Short
 
For siCount1 = 1 To 100
  Inc siStart
  For siCount2 = siStart To 100 Step siCount1
    bDoor[siCount2] = Not bDoor[siCount2]
  Next
Next
 
For siCount1 = 1 To 100
  If bDoor[siCount1] Then Print siCount1;;
Next
 
End

Output:

1 4 9 16 25 36 49 64 81 100

GAP

doors := function(n)
  local a,j,s;
  a := [ ];
  for j in [1 .. n] do
    a[j] := 0;
  od;
  for s in [1 .. n] do
    j := s;
    while j <= n do
      a[j] := 1 - a[j];
      j := j + s;
    od;
  od;
  return Filtered([1 .. n], j -> a[j] = 1);
end;
 
doors(100);
# [ 1, 4, 9, 16, 25, 36, 49, 64, 81, 100 ]

GFA Basic

 
'
' 100 doors problem
'
DIM doors!(101) ! use indices 1 to 100
@close_doors
@do_passes
@show_doors
'
PROCEDURE close_doors
  ARRAYFILL doors!(),FALSE
RETURN
'
PROCEDURE do_passes
  LOCAL i%,j%
  FOR i%=1 TO 100
    FOR j%=i% TO 100 STEP i%
      doors!(j%)=NOT doors!(j%)
    NEXT j%
  NEXT i%
RETURN
'
PROCEDURE show_doors
  LOCAL i%
  OPENW 1
  CLEARW 1
  FOR i%=1 TO 100
    IF doors!(i%)
      PRINT "Door ";i%;" is open"
    ENDIF
  NEXT i%
  PRINT "(press a key to end program)"
  ~INP(2)
  CLOSEW 1
RETURN
 

Glee

100` *=0=>d                      $$ create vector 1..100, create bit pattern d, marking all equal to 0
:for (1..100[.s]){               $$ loop s from 1 to 100
  d^(100` %s *=0 )=>d;}          $$ d = d xor (bit pattern of vector 1..100 % s)
d                                $$ output d
 

The resulting output is the bit pattern showing the state of the 100 doors:

Result:
10010000 10000001 00000000 10000000 00010000 00000000 10000000 00000001 00000000 00000000 10000000 00000000 0001

GML

var doors,a,i;
//Sets up the array for all of the doors.
for (i = 1; i<=100; i += 1)
    {
    doors[i]=0;
    }
 
//This first for loop goes through and passes the interval down to the next for loop.
for (i = 1; i <= 100; i += 1;)
    {
    //This for loop opens or closes the doors and uses the interval(if interval is 2 it only uses every other etc..)
    for (a = 0; a <= 100; a += i;)
        {
        //Opens or closes a door.
        doors[a] = !doors[a];
        }
    }
open_doors = '';
 
//This for loop goes through the array and checks for open doors.
//If the door is open it adds it to the string then displays the string.
for (i = 1; i <= 100; i += 1;)
    {
    if (doors[i] == 1)
        {
        open_doors += "Door Number "+string(i)+" is open#";
        }
    }
show_message(open_doors);
game_end();

Go

unoptimized

package main
 
import "fmt"
 
func main() {
    doors := make([]bool, 100)
 
    // the 100 passes called for in the task description
    for pass := 1; pass <= 100; pass++ {
        for door := pass-1; door < 100; door += pass {
            doors[door] = !doors[door]
        }
    }
 
    // one more pass to answer the question
    for i, v := range doors {
        if v {
            fmt.Print("1")
        } else {
            fmt.Print("0")
        }
 
        if i%10 == 9 {
            fmt.Print("\n")
        } else {
            fmt.Print(" ")
        }
 
    }
}

Output:

1 0 0 1 0 0 0 0 1 0
0 0 0 0 0 1 0 0 0 0
0 0 0 0 1 0 0 0 0 0
0 0 0 0 0 1 0 0 0 0
0 0 0 0 0 0 0 0 1 0
0 0 0 0 0 0 0 0 0 0
0 0 0 1 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0
1 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 1

optimized

package main
 
import "fmt"
 
func main() {
    var door int = 1
    var incrementer = 0
 
    for current := 1; current <= 100; current++ {
        fmt.Printf("Door %d ", current)
 
        if current == door {
            fmt.Printf("Open\n")
            incrementer++
            door += 2*incrementer + 1
        } else {
            fmt.Printf("Closed\n")
        }
    }
}

Golfscript

100:c;[{0}c*]:d;
c,{.c,>\)%{.d<\.d=1^\)d>++:d;}/}/
[c,{)"door "\+" is"+}%d{{"open"}{"closed"}if}%]zip
{" "*puts}/

optimized with sqrt (Original version of GolfScript has no sqrt operator, but it can be added easily; the code was tested using a work-in-progress C interpreter for a language compatible enough with Golfscript)

100,{)}%
{:d.sqrt 2?=
{"open"}{"close"}if"door "d+" is "+\+puts}/

optimized without sqrt

[{"close"}100*]:d;
10,{)2?(.d<\["open"]\)d>++:d;}/
[100,{)"door "\+" is"+}%d]zip
{" "*puts}/

Gosu

unoptimized

 
uses java.util.Arrays
 
var doors = new boolean[100]
Arrays.fill( doors, false )
 
for( pass in 1..100 ) {
    var counter = pass-1
    while( counter < 100 ) {
        doors[counter] = !doors[counter]
        counter += pass
  }
}
 
for( door in doors index i ) {
    print( "door ${i+1} is ${door ? 'open' : 'closed'}" )
}
 
 

optimized

 
var door = 1
var delta = 0
 
for( i in 1..100 ) {
    if( i == door ) {
        print( "door ${i} is open" )
        delta++
        door += 2*delta + 1
    } else {
        print( "door ${i} is closed" )
    }
}
 

Groovy

unoptimized

doors = [false] * 100
(0..99).each {
   it.step(100, it + 1) {
      doors[it] ^= true
   }
}
(0..99).each {
   println("Door #${it + 1} is ${doors[it] ? 'open' : 'closed'}.")
}

optimized a Using square roots

(1..100).each {
   println("Door #${it} is ${Math.sqrt(it).with{it==(int)it} ? 'open' : 'closed'}.")
}

optimized b Without using square roots

doors = ['closed'] * 100
(1..10).each { doors[it**2 - 1] = 'open' }
(0..99).each {
   println("Door #${it + 1} is ${doors[it]}.")
}

GW-BASIC

10 DIM A(100)
20 FOR OFFSET = 1 TO 100
30      FOR I = 0 TO 100 STEP OFFSET
40              A(I) = A(I) + 1
50      NEXT I
60 NEXT OFFSET
70 ' Print "opened" doors
80 FOR I = 1 TO 100
90      IF A(I) MOD 2 = 1 THEN PRINT I
100 NEXT I

Output:

1
4
9
16
25
36
49
64
81
100

Harbour

Unoptimized code:

#define ARRAY_ELEMENTS 100
PROCEDURE Main()
   LOCAL aDoors := Array( ARRAY_ELEMENTS )
   LOCAL i, j
 
   AFill( aDoors, .F. )
   FOR i := 1 TO ARRAY_ELEMENTS
      FOR j := i TO ARRAY_ELEMENTS STEP i
         aDoors[ j ] = ! aDoors[ j ]
      NEXT
   NEXT
   AEval( aDoors, {|e, n| QQout( Padl(n,3) + " is " + Iif(aDoors[n], "*open*", "closed" ) + "|" ), Iif( n%5 == 0, Qout(), e:=NIL) } )
   RETURN

Optimized code

#define ARRAY_ELEMENTS 100
PROCEDURE Main()
   LOCAL aDoors := Array( ARRAY_ELEMENTS )
 
   AFill( aDoors, .F. )
   AEval( aDoors, {|e, n| aDoors[n] := e := Iif( Int(Sqrt(n))==Sqrt(n), .T., .F. ) } )
   AEval( aDoors, {|e, n| QQout( Padl(n,3) + " is " + Iif(aDoors[n], "*open*", "closed" ) + "|" ), Iif( n%5 == 0, Qout(), e:=NIL )} )
   RETURN

Output:

 1 is *open*|  2 is closed|  3 is closed|  4 is *open*|  5 is closed| 
 6 is closed|  7 is closed|  8 is closed|  9 is *open*| 10 is closed| 
11 is closed| 12 is closed| 13 is closed| 14 is closed| 15 is closed| 
16 is *open*| 17 is closed| 18 is closed| 19 is closed| 20 is closed| 
21 is closed| 22 is closed| 23 is closed| 24 is closed| 25 is *open*| 
26 is closed| 27 is closed| 28 is closed| 29 is closed| 30 is closed| 
31 is closed| 32 is closed| 33 is closed| 34 is closed| 35 is closed| 
36 is *open*| 37 is closed| 38 is closed| 39 is closed| 40 is closed| 
41 is closed| 42 is closed| 43 is closed| 44 is closed| 45 is closed| 
46 is closed| 47 is closed| 48 is closed| 49 is *open*| 50 is closed| 
51 is closed| 52 is closed| 53 is closed| 54 is closed| 55 is closed| 
56 is closed| 57 is closed| 58 is closed| 59 is closed| 60 is closed| 
61 is closed| 62 is closed| 63 is closed| 64 is *open*| 65 is closed| 
66 is closed| 67 is closed| 68 is closed| 69 is closed| 70 is closed| 
71 is closed| 72 is closed| 73 is closed| 74 is closed| 75 is closed| 
76 is closed| 77 is closed| 78 is closed| 79 is closed| 80 is closed| 
81 is *open*| 82 is closed| 83 is closed| 84 is closed| 85 is closed| 
86 is closed| 87 is closed| 88 is closed| 89 is closed| 90 is closed| 
91 is closed| 92 is closed| 93 is closed| 94 is closed| 95 is closed| 
96 is closed| 97 is closed| 98 is closed| 99 is closed|100 is *open*|

Haskell

unoptimized

data Door
  = Open
  | Closed
  deriving (Eq, Show)
 
toggle :: Door -> Door
toggle Open = Closed
toggle Closed = Open
 
toggleEvery :: Int -> [Door] -> [Door]
toggleEvery k = zipWith toggleK [1 ..]
  where
    toggleK n door
      | n `mod` k == 0 = toggle door
      | otherwise = door
 
run :: Int -> [Door]
run n = foldr toggleEvery (replicate n Closed) [1 .. n]
 
main :: IO ()
main = print $ filter ((== Open) . snd) $ zip [1 ..] (run 100)

Output:

[(1,Open),(4,Open),(9,Open),(16,Open),(25,Open),(36,Open),(49,Open),(64,Open),(81,Open),(100,Open)]

optimized (without using square roots)

gate :: Eq a => [a] -> [a] -> [Door]
gate (x:xs) (y:ys) | x == y  =  Open   : gate xs ys
gate (x:xs) ys               =  Closed : gate xs ys
gate []     _                =  []
 
run n = gate [1..n] [k*k | k <- [1..]]

alternatively, returning a list of all open gates, it's a one-liner:

run n = takeWhile (< n) [k*k | k <- [1..]]

Haxe

class RosettaDemo
{
    static public function main()
    {
        findOpenLockers(100);
    }
 
    static function findOpenLockers(n : Int)
    {
        var i = 1;
 
        while((i*i) <= n)
        {
            Sys.print(i*i + "\n");
            i++;
        }
    }
}

HicEst

Unoptimized

REAL :: n=100, open=1, door(n)
 
door = 1 - open ! = closed
DO i = 1, n
  DO j = i, n, i
    door(j) = open - door(j)
  ENDDO
ENDDO
DLG(Text=door, TItle=SUM(door)//" doors open") 

Optimized

door = 1 - open ! = closed
DO i = 1, n^0.5
  door(i*i) = open
ENDDO
DLG(Text=door, TItle=SUM(door)//" doors open") 

Hy

Translation of: Coco

(def doors (* [False] 100))
 
(for [pass (range (len doors))]
  (for [i (range pass (len doors) (inc pass))]
    (assoc doors i (not (get doors i)))))
 
(for [i (range (len doors))]
  (print (.format "Door {} is {}."
    (inc i)
    (if (get doors i) "open" "closed"))))

I

software {
	var doors = len(100)
 
	for pass over [1, 100]
		var door = pass - 1
		loop door < len(doors) {
			doors[door] = doors[door]/0
			door += pass
		}
	end
 
	for door,isopen in doors
		if isopen
			print("Door ",door+1,": open")
		end
	end
	print("All other doors are closed")
}

Icon and Unicon

Icon and Unicon don't have a boolean type because most often, logic is expressed in terms of success or failure, which affects flow at run time.

Unoptimized solution.

 
procedure main()
    door := table(0)    # default value of entries is 0
    every pass := 1 to 100 do
        every door[i := pass to 100 by pass] := 1 - door[i]
 
    every write("Door ", i := 1 to 100, " is ", if door[i] = 1 then "open" else "closed")
end
 

Optimized solution.

 
procedure main()
    every write("Door ", i := 1 to 100, " is ", if integer(sqrt(i)) = sqrt(i) then "open" else "closed")
end
 

or

procedure main(args)
    dMap := table("closed")
    every dMap[(1 to sqrt(100))^2] := "open"
    every write("Door ",i := 1 to 100," is ",dMap[i])
end

Idris

import Data.Vect
 
-- Creates list from 0 to n (not including n) 
upTo : (m : Nat) -> Vect m (Fin m)
upTo Z = []
upTo (S n) = 0 :: (map FS (upTo n))
 
data DoorState = DoorOpen | DoorClosed
 
toggleDoor : DoorState -> DoorState
toggleDoor DoorOpen = DoorClosed
toggleDoor DoorClosed = DoorOpen
 
isOpen : DoorState -> Bool
isOpen DoorOpen = True
isOpen DoorClosed = False
 
initialDoors : Vect 100 DoorState
initialDoors = fromList $ map (\_ => DoorClosed) [1..100]
 
iterate : (n : Fin m) -> Vect m DoorState -> Vect m DoorState
iterate n doors {m} = 
  map (\(idx, doorState) => 
          if ((S (finToNat idx)) `mod` (S (finToNat n))) == Z 
              then toggleDoor doorState 
              else doorState)  
      (zip (upTo m) doors)
 
-- Returns all doors left open at the end
solveDoors : List (Fin 100)
solveDoors = 
  findIndices isOpen $ foldl (\doors,val => iterate val doors) initialDoors (upTo 100)
 
main : IO ()
main = print $ map (\n => S (finToNat n)) solveDoors

Inform 7

Works with: Z-machine version 8

Works with: Glulx virtual machine

Hallway is a room.
 
A toggle door is a kind of thing.
A toggle door can be open or closed. It is usually closed.
A toggle door has a number called the door number.
Understand the door number property as referring to a toggle door.
Rule for printing the name of a toggle door: say "door #[door number]".
 
There are 100 toggle doors.
 
When play begins (this is the initialize doors rule):
	let the next door number be 1;
	repeat with D running through toggle doors:
		now the door number of D is the next door number;
		increment the next door number.
 
To toggle (D - open toggle door): now D is closed.
To toggle (D - closed toggle door): now D is open.
 
When play begins (this is the solve puzzle rule):
	let the door list be the list of toggle doors;
	let the door count be the number of entries in the door list;
	repeat with iteration running from 1 to 100:
		let N be the iteration;
		while N is less than the door count:
			toggle entry N in the door list;
			increase N by the iteration;
	say "Doors left open: [list of open toggle doors].";
	end the story.

Informix 4GL

 
MAIN
    DEFINE
        i, pass SMALLINT,
        doors ARRAY[100] OF SMALLINT
 
    FOR i = 1 TO 100
        LET doors[i] = FALSE
    END FOR
 
    FOR pass = 1 TO 100
        FOR i = pass TO 100 STEP pass
            LET doors[i] = NOT doors[i]
        END FOR
    END FOR
 
    FOR i = 1 TO 100
        IF doors[i]
          THEN DISPLAY i USING "Door <<& is open"
          ELSE DISPLAY i USING "Door <<& is closed"
        END IF
    END FOR
END MAIN
 

Io

simple boolean list solution:

doors := List clone
100 repeat(doors append(false))
for(i,1,100,
    for(x,i,100, i, doors atPut(x - 1, doors at(x - 1) not))
)
doors foreach(i, x, if(x, "Door #{i + 1} is open" interpolate println))

Optimized solution:

(Range 1 to(10) asList) foreach(v, "Door #{v ** 2} is open." interpolate println)

Sample output:

Door 1 is open.
Door 4 is open.
Door 9 is open.
Door 16 is open.
Door 25 is open.
Door 36 is open.
Door 49 is open.
Door 64 is open.
Door 81 is open.
Door 100 is open.

Ioke

Unoptimized Object Oriented solution.

NDoors = Origin mimic
 
NDoors Toggle = Origin mimic do(
  initialize = method(toggled?, @toggled? = toggled?)
  toggle! = method(@toggled? = !toggled?. self)
)
 
NDoors Doors = Origin mimic do(
  initialize = method(n,
    @n = n
    @doors = {} addKeysAndValues(1..n, (1..n) map(_, NDoors Toggle mimic(false)))
  )
  numsToToggle = method(n, for(x <- ([email protected]), (x % n) zero?, x))
  toggleThese = method(nums, nums each(x, @doors[x] = @doors at(x) toggle))
  show = method(@doors filter:dict(value toggled?) keys sort println)
)
 
; Test code
x = NDoors Doors mimic(100)
(1..100) each(n, x toggleThese(x numsToToggle(n)))
x show

J

unoptimized

   ~:/ (100 $ - {. 1:)"0 >:i.100
1 0 0 1 0 0 0 0 1 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 ...
   ~:/ 0=|/~ >:i.100  NB. alternative
1 0 0 1 0 0 0 0 1 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 ...

optimized

   (e. *:) 1+i.100
1 0 0 1 0 0 0 0 1 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 ...
   1 (<:*:i.10)} 100$0  NB. alternative
1 0 0 1 0 0 0 0 1 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 ...

with formatting

   'these doors are open' ; >: I. (>:i.100) e. *: i.11
+------------------------------------------------+
¦these doors are open¦1 4 9 16 25 36 49 64 81 100¦
+------------------------------------------------+
 
 

Java

class HundredDoors {
    public static void main(String[] args) {
        boolean[] doors = new boolean[101];
 
        for (int i = 1; i < doors.length; i++) {
            for (int j = i; j < doors.length; j += i) {
                doors[j] = !doors[j];
            }
        }
 
        for (int i = 1; i < doors.length; i++) {
            if (doors[i]) {
                System.out.printf("Door %d is open.%n", i);
            }
        }
    }
}

If only printing the result is required.

class HundredDoors {
    public static void main(String[] args) {
        for (int i = 1; i <= 10; i++)
            System.out.printf("Door %d is open.%n", i * i);
    }
}

Output:

Door 1 is open.
Door 4 is open.
Door 9 is open.
Door 16 is open.
Door 25 is open.
Door 36 is open.
Door 49 is open.
Door 64 is open.
Door 81 is open.
Door 100 is open.

If only printing the result is required, using streams.

import java.util.stream.Collectors;
import java.util.stream.IntStream;
 
class HundredDoors {
    public static void main(String args[]) {
        String openDoors = IntStream.rangeClosed(1, 100)
                .filter(i -> Math.pow((int) Math.sqrt(i), 2) == i)
                .mapToObj(Integer::toString)
                .collect(Collectors.joining(", "));
        System.out.printf("Open doors: %s%n", openDoors);
    }
}
 

Output:

Open doors: 1, 4, 9, 16, 25, 36, 49, 64, 81, 100

JavaScript

ES5

Iterative

 
var doors=[];
for(var i=0;i<100;i++)
 doors[i]=false;             //create doors
for(var i=1;i<=100;i++)
 for(var i2=i-1,g;i2<100;i2+=i)
  doors[i2]=!doors[i2];      //toggle doors
for(var i=1;i<=100;i++)      //read doors
 console.log("Door %d is %s",i,doors[i-1]?"open":"closed")
 

Functional Composition

Naive search

(function (n) {
    'use strict';
 
 
    // finalDoors :: Int -> [(Int, Bool)]
    function finalDoors(n) {
        var lstRange = range(1, n);
 
        return lstRange
            .reduce(function (a, _, k) {
                var m = k + 1;
 
                return a.map(function (x, i) {
                    var j = i + 1;
 
                    return [j, j % m ? x[1] : !x[1]];
                });
            }, zip(
                lstRange,
                replicate(n, false)
            ));
    };
 
 
 
    // GENERIC FUNCTIONS
 
    // zip :: [a] -> [b] -> [(a,b)]
    function zip(xs, ys) {
        return xs.length === ys.length ? (
            xs.map(function (x, i) {
                return [x, ys[i]];
            })
        ) : undefined;
    }
 
    // replicate :: Int -> a -> [a]
    function replicate(n, a) {
        var v = [a],
            o = [];
 
        if (n < 1) return o;
        while (n > 1) {
            if (n & 1) o = o.concat(v);
            n >>= 1;
            v = v.concat(v);
        }
        return o.concat(v);
    }
 
    // range(intFrom, intTo, optional intStep)
    // Int -> Int -> Maybe Int -> [Int]
    function range(m, n, delta) {
        var d = delta || 1,
            blnUp = n > m,
            lng = Math.floor((blnUp ? n - m : m - n) / d) + 1,
            a = Array(lng),
            i = lng;
 
        if (blnUp)
            while (i--) a[i] = (d * i) + m;
        else
            while (i--) a[i] = m - (d * i);
 
        return a;
    }
 
 
    return finalDoors(n)
        .filter(function (tuple) {
            return tuple[1];
        })
        .map(function (tuple) {
            return {
                door: tuple[0],
                open: tuple[1]
            };
        });
 
})(100);

Output:

[{"door":1, "open":true}, {"door":4, "open":true}, {"door":9, "open":true}, {"door":16, "open":true}, {"door":25, "open":true}, {"door":36, "open":true}, {"door":49, "open":true}, {"door":64, "open":true}, {"door":81, "open":true}, {"door":100, "open":true}]

Optimized ( iterative )

for (var door = 1; door <= 100; door++) {
  var sqrt = Math.sqrt(door);
  if (sqrt === (sqrt | 0)) {
    console.log("Door %d is open", door);
  }
}

Simple for loop. Optimizing the optimized?

for(var door=1;i<10/*Math.sqrt(100)*/;i++){
 console.log("Door %d is open",i*i);
}

Optimized ( functional )

The question of which doors are flipped an odd number of times reduces to the question of which numbers have an odd number of integer factors.

We can simply search for these:

(function (n) {
    'use strict';
 
    return range(1, 100)
        .filter(function (x) {
            return integerFactors(x)
                .length % 2;
        });
 
    function integerFactors(n) {
        var rRoot = Math.sqrt(n),
            intRoot = Math.floor(rRoot),
 
            lows = range(1, intRoot)
            .filter(function (x) {
                return (n % x) === 0;
            });
 
        // for perfect squares, we can drop the head of the 'highs' list
        return lows.concat(lows.map(function (x) {
                return n / x;
            })
            .reverse()
            .slice((rRoot === intRoot) | 0));
    }
 
    // range(intFrom, intTo, optional intStep)
    // Int -> Int -> Maybe Int -> [Int]
    function range(m, n, delta) {
        var d = delta || 1,
            blnUp = n > m,
            lng = Math.floor((blnUp ? n - m : m - n) / d) + 1,
            a = Array(lng),
            i = lng;
 
        if (blnUp)
            while (i--) a[i] = (d * i) + m;
        else
            while (i--) a[i] = m - (d * i);
 
        return a;
    }
 
})(100);

Or we can note, on inspection and further reflection, that only perfect squares have odd numbers of integer factors - all other numbers have only matched pairs of factors - low factors below the non-integer square root, and the corresponding quotients above the square root. In the case of perfect squares, the additional integer square root (not paired with any other factor than itself) makes the total number of distinct factors odd.

(function (n) {
    'use strict';
 
    return perfectSquaresUpTo(100);
 
    function perfectSquaresUpTo(n) {
        return range(1, Math.floor(Math.sqrt(n)))
            .map(function (x) {
                return x * x;
            });
    }
 
    // GENERIC
 
    // range(intFrom, intTo, optional intStep)
    // Int -> Int -> Maybe Int -> [Int]
    function range(m, n, delta) {
        var d = delta || 1,
            blnUp = n > m,
            lng = Math.floor((blnUp ? n - m : m - n) / d) + 1,
            a = Array(lng),
            i = lng;
 
        if (blnUp)
            while (i--) a[i] = (d * i) + m;
        else
            while (i--) a[i] = m - (d * i);
        return a;
    }
 
})(100);

Output:

[1, 4, 9, 16, 25, 36, 49, 64, 81, 100]

ES6

 
Array.apply(null, { length: 100 })
  .map((v, i) => i + 1)
    .forEach(door => { 
      var sqrt = Math.sqrt(door); 
 
      if (sqrt === (sqrt | 0)) {
        console.log("Door %d is open", door);
      } 
    });

// Array comprehension style
[ for (i of Array.apply(null, { length: 100 })) i ].forEach((_, i) => { 
  var door = i + 1
  var sqrt = Math.sqrt(door); 
 
  if (sqrt === (sqrt | 0)) {
    console.log("Door %d is open", door);
  } 
});

The result is always:

Door 1 is open
Door 4 is open
Door 9 is open
Door 16 is open
Door 25 is open
Door 36 is open
Door 49 is open
Door 64 is open
Door 81 is open
Door 100 is open

Or using a more general function for listing perfect squares:

(function (n) {
 
 
    // ONLY PERFECT SQUARES HAVE AN ODD NUMBER OF INTEGER FACTORS
    // (Leaving the door open at the end of the process) 
 
    return perfectSquaresUpTo(n);
 
 
    // perfectSquaresUpTo :: Int -> [Int]
    function perfectSquaresUpTo(n) {
        return range(1, Math.floor(Math.sqrt(n)))
            .map(x => x * x);
    }
 
 
    // GENERIC
 
    // range(intFrom, intTo, optional intStep)
    // Int -> Int -> Maybe Int -> [Int]
    function range(m, n, step) {
        let d = (step || 1) * (n >= m ? 1 : -1);
 
        return Array.from({
            length: Math.floor((n - m) / d) + 1
        }, (_, i) => m + (i * d));
    }
 
})(100);

Output:

[1, 4, 9, 16, 25, 36, 49, 64, 81, 100]

jq

jq arrays have 0 as their index origin, but in the following, the 100 doors are numbered from 1 to 100.

Solution by simulation

# Solution for n doors:
def doors(n):
 
  def print:
    . as $doors
    | range(1; length+1)
    | if $doors[.] then "Door \(.) is open" else empty end;
 
    [range(n+1)|null] as $doors
  | reduce range(1; n+1) as $run
      ( $doors; reduce range($run; n+1; $run ) as $door
                  ( .; .[$door] = (.[$door] | not) ) )
  | print ;
 
 

Analytical solution

# Solution for 100 doors:
def solution:
  range(1;11) | "Door \(. * .) is open";
 

Julia

unoptimized:
-falses(100) creates a 100-element Bool array filled with false values
-'b in a:a:100' translates to 'start:step:end'
-string concatenation by '*'

doors = falses(100)
for a = 1:100, b in a:a:100
    doors[b] = !doors[b]
end
for a = 1:100
    println("Door $a is " * (doors[a] ? "open." : "closed.")) 
end

ultra-optimized:

for i = 1:10 println("Door $(i^2) is open.") end

K

unoptimized / converted from Q .

 `closed `open ![ ; 2 ] @ #:' 1 _ = ,/ &:' 0 = t !\:/: t : ! 101

optimized / 1 origin indices

 ( 1 + ! 10 ) ^ 2

/ As parameterized function :

 { ( 1 + ! _ x ^ % 2 ) ^ 2 } 100 

Kotlin

fun oneHundredDoors(): List<Int> {
    val doors = BooleanArray(100, { false })
    for (i in 0..99) {
        for (j in i..99 step (i + 1)) {
            doors[j] = !doors[j]
        }
    }
    return doors
        .mapIndexed { i, b -> i to b }
        .filter { it.second }
        .map { it.first + 1 }
}

LabVIEW

This image is a VI Snippet, an executable image of LabVIEW code. The LabVIEW version is shown on the top-right hand corner. You can download it, then drag-and-drop it onto the LabVIEW block diagram from a file browser, and it will appear as runnable, editable code.

Optimized

This image is a VI Snippet, an executable image of LabVIEW code. The LabVIEW version is shown on the top-right hand corner. You can download it, then drag-and-drop it onto the LabVIEW block diagram from a file browser, and it will appear as runnable, editable code.

Lasso

Loop

loop(100) => {^
	local(root = math_sqrt(loop_count))
	local(state = (#root == math_ceil(#root) ? '<strong>open</strong>' | 'closed'))
	#state != 'closed' ? 'Door ' + loop_count + ': ' + #state + '<br>'
^}

Output:

Door 1: open
Door 4: open
Door 9: open
Door 16: open
Door 25: open
Door 36: open
Door 49: open
Door 64: open
Door 81: open
Door 100: open

Lhogho

This implementation defines 100 variables, named "1 through "100, rather than using a list. Thanks to Pavel Boytchev, the author of Lhogho, for help with the code.

to doors
	;Problem 100 Doors 
	;Lhogho
 
	for "p [1 100] 
	[
		make :p "false
	]
 
	for "a [1 100 1]
	[
		for "b [:a 100 :a]
		[
			if :b < 101 
			[
				make :b not thing :b
			]
		]
	]
 
	for "c [1 100]
	[
		if thing :c 
		[ 
			(print "door :c "is "open) 
		]
	] 
end
 
doors

Liberty BASIC

dim doors(100)
for pass = 1 to 100
    for door = pass to 100 step pass
        doors(door) = not(doors(door))
    next door
next pass
print "open doors ";
for door = 1 to 100
    if doors(door) then print door;"  ";
next door

Lily

var doors = List.fill(100, false)
 
for i in 0...99:
    for j in i...99 by i + 1:
        doors[j] = !doors[j]
 
# The type must be specified since the list starts off empty.
var open_doors: List[Integer] = []
 
doors.each_index{|i|
    if doors[i]:
        open_doors.push(i + 1)
}
 
print($"Open doors: ^(open_doors)")

Output:

Open doors: [1, 4, 9, 16, 25, 36, 49, 64, 81, 100]

LiveCode

 
on mouseUp   
   repeat with tStep = 1 to 100
      repeat with tDoor = tStep to 100 step tStep
         put not tDoors[tDoor] into tDoors[tDoor]
      end repeat
      if tDoors[tStep] then put "Door " & tStep & " is open" & cr after tList
   end repeat
   set the text of field "Doors" to tList
end mouseUp
 

Logo

to doors
;Problem 100 Doors 
;FMSLogo
;lrcvs 2010
 
make "door (vector 100 1) 
for [p 1 100][setitem :p :door 0] 
 
for [a 1 100 1][for [b :a 100 :a][make "x item :b :door 
	                          ifelse :x  = 0 [setitem :b :door 1][setitem :b :door 0] ] ] 
 
for [c 1 100][make "y item :c :door 
	      ifelse :y = 0 [pr (list :c "Close)] [pr (list :c "Open)] ] 
end

LOLCODE

HAI 1.3
 
I HAS A doors ITZ A BUKKIT
IM IN YR hallway UPPIN YR door TIL BOTH SAEM door AN 100
    doors HAS A SRS door ITZ FAIL BTW, INISHULIZE ALL TEH DOORZ AS CLOZD
IM OUTTA YR hallway
 
IM IN YR hallway UPPIN YR pass TIL BOTH SAEM pass AN 100
    I HAS A door ITZ pass
    IM IN YR passer
        doors'Z SRS door R NOT doors'Z SRS door
        door R SUM OF door AN SUM OF pass AN 1
        DIFFRINT door AN SMALLR OF door AN 99, O RLY?
            YA RLY, GTFO
        OIC
    IM OUTTA YR passer
IM OUTTA YR hallway
 
IM IN YR printer UPPIN YR door TIL BOTH SAEM door AN 100
    VISIBLE "Door #" SUM OF door AN 1 " is "!
    doors'Z SRS door, O RLY?
        YA RLY, VISIBLE "open."
        NO WAI, VISIBLE "closed."
    OIC
IM OUTTA YR printer
 
KTHXBYE

Lua

local is_open = {}
 
for pass = 1,100 do
    for door = pass,100,pass do
        is_open[door] = not is_open[door]
    end
end
 
for i,v in next,is_open do
    print ('Door '..i..':',v and 'open' or 'close')
end

M4

define(`_set', `define(`$1[$2]', `$3')')dnl
define(`_get', `defn(`$1[$2]')')dnl
define(`for',`ifelse($#,0,``$0'',`ifelse(eval($2<=$3),1,
`pushdef(`$1',$2)$5`'popdef(`$1')$0(`$1',eval($2+$4),$3,$4,`$5')')')')dnl
define(`opposite',`_set(`door',$1,ifelse(_get(`door',$1),`closed',`open',`closed'))')dnl
define(`upper',`100')dnl
for(`x',`1',upper,`1',`_set(`door',x,`closed')')dnl
for(`x',`1',upper,`1',`for(`y',x,upper,x,`opposite(y)')')dnl
for(`x',`1',upper,`1',`door x is _get(`door',x)
')dnl

Maple

 
NDoors := proc( N :: posint )
        # Initialise, using 0 to represent "closed"
        local pass, door, doors := Array( 1 .. N, 'datatype' = 'integer'[ 1 ] );
        # Now do N passes
        for pass from 1 to N do
                for door from pass by pass while door <= N do
                        doors[ door ] := 1 - doors[ door ]
                end do
        end do;
        # Output
        for door from 1 to N do
                printf( "Door %d is %s.\n", door, `if`( doors[ door ] = 0, "closed", "open" ) )
        end do;
        # Since this is a printing routine, return nothing.
        NULL
end proc:
 

To solve the problem, call it with 100 as argument (output not shown here).

 
> NDoors( 100 );
 

Here is the optimised version, which outputs only the open doors.

 
> seq( i^2, i = 1 .. isqrt( 100 ) );
                  1, 4, 9, 16, 25, 36, 49, 64, 81, 100
 

Alternatively,

 
> [seq]( 1 .. 10 )^~2;
                 [1, 4, 9, 16, 25, 36, 49, 64, 81, 100]
 

Mathematica

unoptimized 1

n=100;
tmp=ConstantArray[-1,n];
Do[tmp[[i;;;;i]]*=-1;,{i,n}];
Do[Print["door ",i," is ",If[tmp[[i]]==-1,"closed","open"]],{i,1,Length[tmp]}]

unoptimized 2

f[n_] = "Closed"; 
Do[Do[If[f[n] == "Closed", f[n] = "Open", f[n] = "Closed"], {n, k, 100, k}], {k, 1, 100}]; 
Table[f[n], {n, 1, 100}]

unoptimized 3

Mathematica also supports immutable data paradigms, like so:

 
Fold[
 ReplacePart[#1, (i_ /; Mod[i, #2] == 0) :> (-#1[[i]])] &,
 ConstantArray[-1, {100}],
 Range[100]
] /. {1 -> "Open", -1 -> "Closed"}
 

optimized 1

Do[Print["door ",i," is ",If[IntegerQ[Sqrt[i]],"open","closed"]],{i,100}]

optimized 2

n=100;
a=Range[1,Sqrt[n]]^2
Do[Print["door ",i," is ",If[MemberQ[a,i],"open","closed"]],{i,100}]

optimized 3

n=100
nn=1
a=0
For[i=1,i<=n,i++,
 If[i==nn,
  Print["door ",i," is open"];
  a++;
  nn+=2a+1;
 ,
  Print["door ",i," is closed"];
 ];
]

These will only give the indices for the open doors: unoptimized 2

Pick[Range[100], [email protected]@@Array[Divisible[#1,#2]&, {100,100}]]

optimized 4

Range[Sqrt[100]]^2

MATLAB / Octave

Iterative Method

Unoptimized

a = false(1,100);
for b=1:100
  for i = b:b:100
    a(i) = ~a(i);
  end
end
a
 

Optimized

 
for x=1:100;
  if sqrt(x) == floor(sqrt(x))
    a(i)=1;
  end
end
a
 

More Optimized

 
a = zeros(100,1);
for counter = 1:sqrt(100);
  a(counter^2) = 1;
end
a
 

Vectorized Method

function [doors,opened,closed] = hundredDoors()
 
    %Initialize the doors, make them booleans for easy vectorization
    doors = logical( (1:1:100) );
 
    %Go through the flipping process, ignore the 1 case because the doors
    %array is already initialized to all open
    for initialPosition = (2:100)
        doors(initialPosition:initialPosition:100) = not( doors(initialPosition:initialPosition:100) );
    end
 
    opened = find(doors); %Stores the numbers of the open doors
    closed = find( not(doors) ); %Stores the numbers of the closed doors
 
end

Known-Result Method

 
doors((1:10).^2) = 1;
 
doors
 

Maxima

doors(n) := block([v], local(v),
  v: makelist(true, n),
  for i: 2 thru n do
  for j: i step i thru n do v[j]: not v[j],
  sublist_indices(v, 'identity));

Usage:

doors(100);
/* [1, 4, 9, 16, 25, 36, 49, 64, 81, 100] */

MAXScript

unoptimized

doorsOpen = for i in 1 to 100 collect false
 
for pass in 1 to 100 do
(
    for door in pass to 100 by pass do
    (
        doorsOpen[door] = not doorsOpen[door]
    )
)
 
for i in 1 to doorsOpen.count do
(
    format ("Door % is open?: %\n") i doorsOpen[i]
)

optimized

for i in 1 to 100 do
(
    root = pow i 0.5
    format ("Door % is open?: %\n") i (root == (root as integer))
)

Mercury

:- module doors.
:- interface.
:- import_module array, io, int.
 
:- type door ---> open ; closed.
:- type doors == array(door).
 
:- func toggle(door) = door.
:- pred walk(int::in, doors::in, doors::out) is semidet.
:- pred walks(int::in, int::in, doors::in, doors::out) is det.
 
:- pred main(io::di, io::uo) is det.
 
:- implementation.
 
toggle(open) = closed.
toggle(closed) = open.
 
walk(N, !D) :- walk(N, N, !D).
 
:- pred walk(int::in, int::in, doors::in, doors::out) is semidet.
walk(At, By, !D) :-
        semidet_lookup(!.D, At - 1, Door),
        slow_set(At - 1, toggle(Door), !D),
        ( walk(At + By, By, !D) -> true ; true ).
 
walks(N, End, !D) :-
        ( N =< End, walk(N, !D) -> walks(N + 1, End, !D) ; true ).
 
main(!IO) :-
        io.write(Doors1, !IO), io.nl(!IO),
        array.init(100, closed, Doors0),
        walks(1, 100, Doors0, Doors1).

Metafont

boolean doors[];
for i = 1 upto 100: doors[i] := false; endfor
for i = 1 upto 100:
  for j = 1 step i until 100:
    doors[j] := not doors[j];
  endfor
endfor
for i = 1 upto 100:
  message decimal(i) & " " & if doors[i]: "open" else: "close" fi;
endfor
end

MIPS Assembly

.data
  doors:     .space 100
  num_str:   .asciiz "Number "
  comma_gap: .asciiz " is "
  newline:   .asciiz "\n"
 
.text
main:
# Clear all the cells to zero
  li $t1, 100
  la $t2, doors
clear_loop:
  sb $0, ($t2)
  add $t2, $t2, 1
  sub $t1, $t1, 1
  bnez $t1, clear_loop
 
# Now start the loops
  li $t0, 1         # This will the the step size
  li $t4, 1         # just an arbitrary 1
loop1:
  move $t1, $t0      # Counter
  la $t2, doors      # Current pointer
  add $t2, $t2, $t0
  addi $t2, $t2, -1
loop2:
  lb $t3, ($t2)
  sub $t3, $t4, $t3
  sb $t3, ($t2)
  add $t1, $t1, $t0
  add $t2, $t2, $t0
  ble $t1, 100, loop2
 
  addi $t0, $t0, 1
  ble $t0, 100, loop1
 
  # Now display everything
  la $t0, doors
  li $t1, 1
loop3:
  li $v0, 4
  la $a0, num_str
  syscall
 
  li $v0, 1
  move $a0, $t1
  syscall
 
  li $v0, 4
  la $a0, comma_gap
  syscall
 
  li $v0, 1
  lb $a0, ($t0)
  syscall
 
  li $v0, 4,
  la $a0, newline
  syscall
 
  addi $t0, $t0, 1
  addi $t1, $t1, 1
  bne $t1, 101 loop3
 

Mirah

import java.util.ArrayList
 
class Door
	:state
 
	def initialize
		@state=false
	end
 
	def closed?; [email protected]; end
	def open?; @state; end
 
	def close; @state=false; end
	def open; @state=true; end
 
	def toggle
		if closed?
			open
		else
			close
		end
	end
 
	def toString; Boolean.toString(@state); end
end
 
doors=ArrayList.new
1.upto(100) do
    doors.add(Door.new)
end 
 
1.upto(100) do |multiplier|
    index = 0
    doors.each do |door|
        Door(door).toggle if (index+1)%multiplier == 0
        index += 1
    end
end
 
i = 0
doors.each do |door| 
    puts "Door #{i+1} is #{door}."
    i+=1
end
 

mIRC Scripting Language

var %d = $str(0 $+ $chr(32),100), %m = 1
while (%m <= 100) {
  var %n = 1
  while ($calc(%n * %m) <= 100) {
    var %d = $puttok(%d,$iif($gettok(%d,$calc(%n * %m),32),0,1),$calc(%n * %m),32)
    inc %n
  }
  inc %m
}
echo -ag All Doors (Boolean): %d
var %n = 1
while (%n <= $findtok(%d,1,0,32)) {
  var %t = %t $findtok(%d,1,%n,32)
  inc %n
}
echo -ag Open Door Numbers: %t

ML/I

MCSKIP "WITH" NL
"" 100 doors
MCINS %.
MCSKIP MT,<>
"" Doors represented by P1-P100, 0 is closed
MCPVAR 100
"" Set P variables to 0
MCDEF ZEROPS WITHS NL AS <MCSET T1=1
%L1.MCSET PT1=0
MCSET T1=T1+1
MCGO L1 UNLESS T1 EN 101
>
ZEROPS
"" Generate door state
MCDEF STATE WITHS () AS <MCSET T1=%A1.
MCGO L1 UNLESS T1 EN 0
closed<>MCGO L0
%L1.open>
"" Main macro - no arguments
"" T1 is pass number
"" T2 is door number
MCDEF DOORS WITHS NL
AS <MCSET T1=1
"" pass loop
%L1.MCGO L4 IF T1 GR 100
"" door loop
MCSET T2=T1
%L2.MCGO L3 IF T2 GR 100
MCSET PT2=1-PT2
MCSET T2=T2+T1
MCGO L2
%L3.MCSET T1=T1+1
MCGO L1
%L4."" now output the result
MCSET T1=1
%L5.door %T1. is STATE(%PT1.)
MCSET T1=T1+1
MCGO L5 UNLESS T1 GR 100
>
"" Do it
DOORS

MMIX

See 100 doors/MMIX

Modula-2

unoptimized

MODULE Doors;
IMPORT InOut;
 
TYPE State = (Closed, Open);
TYPE List = ARRAY [1 .. 100] OF State;
 
VAR
  Doors: List;
  I, J:  CARDINAL;
 
BEGIN
  FOR I := 1 TO 100 DO
    FOR J := 1 TO 100 DO
      IF J MOD I = 0 THEN
        IF Doors[J] = Closed THEN
          Doors[J] := Open
        ELSE
          Doors[J] := Closed
        END
      END
    END
  END;
 
  FOR I := 1 TO 100 DO
    InOut.WriteCard(I, 3);
    InOut.WriteString(' is ');
 
    IF Doors[I] = Closed THEN
      InOut.WriteString('Closed.')
    ELSE
      InOut.WriteString('Open.')
    END;
 
    InOut.WriteLn
  END
END Doors.

optimized

MODULE DoorsOpt;
IMPORT InOut;
 
TYPE State = (Closed, Open);
TYPE List = ARRAY [1 .. 100] OF State;
 
VAR
  Doors: List;
  I:  CARDINAL;
 
BEGIN
  FOR I := 1 TO 10 DO
    Doors[I*I] := Open
  END;
 
  FOR I := 1 TO 100 DO
    InOut.WriteCard(I, 3);
    InOut.WriteString(' is ');
    IF Doors[I] = Closed THEN
      InOut.WriteString('Closed.')
    ELSE
      InOut.WriteString('Open.')
    END;
    InOut.WriteLn
  END
END DoorsOpt.

Modula-3

unoptimized

MODULE Doors EXPORTS Main;
 
IMPORT IO, Fmt;
 
TYPE State = {Closed, Open};
TYPE List = ARRAY [1..100] OF State;
 
VAR doors := List{State.Closed, ..};
 
BEGIN
  FOR i := 1 TO 100 DO
    FOR j := FIRST(doors) TO LAST(doors) DO
      IF j MOD i = 0 THEN
        IF doors[j] = State.Closed THEN
          doors[j] := State.Open;
        ELSE
          doors[j] := State.Closed;
        END;
      END;
    END;
  END;
 
  FOR i := FIRST(doors) TO LAST(doors) DO
    IO.Put(Fmt.Int(i) & " is ");
    IF doors[i] = State.Closed THEN
      IO.Put("Closed.\n");
    ELSE
      IO.Put("Open.\n");
    END;
  END;
END Doors.

optimized

MODULE DoorsOpt EXPORTS Main;
 
IMPORT IO, Fmt;
 
TYPE State = {Closed, Open};
TYPE List = ARRAY [1..100] OF State;
 
VAR doors := List{State.Closed, ..};
 
BEGIN
  FOR i := 1 TO 10 DO
    doors[i * i] := State.Open;
  END;
 
  FOR i := FIRST(doors) TO LAST(doors) DO
    IO.Put(Fmt.Int(i) & " is ");
    IF doors[i] = State.Closed THEN
      IO.Put("Closed.\n");
    ELSE
      IO.Put("Open.\n");
    END;
  END;
END DoorsOpt.

MOO

is_open = make(100);
for pass in [1..100]
  for door in [pass..100]
    if (door % pass)
      continue;
    endif
    is_open[door] = !is_open[door];
  endfor
endfor
 
"output the result";
for door in [1..100]
  player:tell("door #", door, " is ", (is_open[door] ? "open" : "closed"), ".");
endfor

MoonScript

is_open = [false for door = 1,100]
 
for pass = 1,100 
    for door = pass,100,pass
        is_open[door] = not is_open[door]
 
for i,v in ipairs is_open
    print "Door #{i}: " .. if v then 'open' else 'closed'

MUMPS

doors	new door,pass
	For door=1:1:100 Set door(door)=0
	For pass=1:1:100 For door=pass:pass:100 Set door(door)='door(door)
	For door=1:1:100 If door(door) Write !,"Door",$j(door,4)," is open"
	Write !,"All other doors are closed."
	Quit
Do doors
Door   1 is open
Door   4 is open
Door   9 is open
Door  16 is open
Door  25 is open
Door  36 is open
Door  49 is open
Door  64 is open
Door  81 is open
Door 100 is open
All other doors are closed.

MySQL

 
DROP PROCEDURE IF EXISTS one_hundred_doors;
 
DELIMITER |
 
CREATE PROCEDURE one_hundred_doors (n INT)
BEGIN
  DROP TEMPORARY TABLE IF EXISTS doors; 
  CREATE TEMPORARY TABLE doors (
    id INTEGER NOT NULL,
    open BOOLEAN DEFAULT FALSE,
    PRIMARY KEY (id)
  );
 
  SET @i = 1;
  create_doors: LOOP
    INSERT INTO doors (id, open) values (@i, FALSE);
    SET @i = @i + 1;
    IF @i > n THEN
      LEAVE create_doors;
    END IF;
  END LOOP create_doors;
 
  SET @i = 1;
  toggle_doors: LOOP
    UPDATE doors SET open = NOT open WHERE MOD(id, @i) = 0;
    SET @i = @i + 1;
    IF @i > n THEN
      LEAVE toggle_doors;
    END IF;
  END LOOP toggle_doors;
 
  SELECT id FROM doors WHERE open;
END|
 
DELIMITER ;
 
CALL one_hundred_doors(100);
 

Output:

+-----+
| id  |
+-----+
|   1 |
|   4 |
|   9 |
|  16 |
|  25 |
|  36 |
|  49 |
|  64 |
|  81 |
| 100 |
+-----+
10 rows in set (0.02 sec)

NetRexx

unoptimized

/* NetRexx */
options replace format comments java crossref symbols binary
 
True  = Rexx(1 == 1)
False = Rexx(\True)
 
doors = False
 
loop i_ = 1 to 100
  loop j_ = 1 to 100
    if 0 = (j_ // i_) then doors[j_] = \doors[j_]
    end j_
  end i_
 
loop d_ = 1 to 100
  if doors[d_] then  state = 'open'
  else  state = 'closed'
 
  say 'Door Nr.' Rexx(d_).right(4) 'is' state
  end d_

optimized (Based on the Java 'optimized' version)

Translation of: Java

/* NetRexx */
options replace format comments java crossref symbols binary
 
True  = (1 == 1)
False = \True
 
doors = boolean[100]
 
loop i_ = 0 to 9
  doors[(i_ + 1) * (i_ + 1) - 1] = True;
  end i_
 
loop i_ = 0 to 99
  if doors[i_] then  state = 'open'
  else  state = 'closed'
 
  say 'Door Nr.' Rexx(i_ + 1).right(4) 'is' state
  end i_

optimized 2 (Based on the Java 'optimized 2' version)

Translation of: Java

/* NetRexx */
options replace format comments java crossref savelog symbols binary
 
resultstring = ''
 
loop i_ = 1 to 10
  resultstring = resultstring || 'Door Nr.' Rexx(i_ * i_).right(4) 'is open\n'
  end i_
 
say resultstring

optimized 3

/* NetRexx */
 
loop i = 1 to 10
   say 'Door Nr.' i * i 'is open.'
  end i

NewLISP

(define (status door-num)
    (let ((x (int (sqrt door-num))))
     (if
       (= (* x x) door-num) (string "Door " door-num " Open")
       (string "Door " door-num " Closed"))))
 
(dolist (n (map status (sequence 1 100)))
  (println n))
 

Not optimized:

 
(set 'Doors (array 100))  ;; Default value: nil (Closed)
 
(for (x 0 99)
    (for (y x 99 (+ 1 x))
        (setf (Doors y) (not (Doors y)))))
 
(for (x 0 99)  ;; Display open doors
    (if (Doors x)
        (println (+ x 1) " : Open")))
 

Output:

1 : Open
4 : Open
9 : Open
16 : Open
25 : Open
36 : Open
49 : Open
64 : Open
81 : Open
100 : Open

Nim

unoptimized:

from strutils import format
 
proc check_doors() =
  const n = 100
  var is_open : array[1..n, bool] # auto-initialized to false
  # pass over the doors n times
  for pass in 1..n:
    var i = pass
    while i <= n:
      is_open[i] = not is_open[i]
      i += pass
  # print the result
  for door in 1..n:
    echo format("door $1 is $2.", door, (if is_open[door]: "open" else: "closed"))
 
check_doors()

another:

var isOpen: array[1..100, bool]
 
for pass in countup(1, 100):
  for door in countup(pass,100,pass):
    isOpen[door] = not isOpen[door]
 
for i in countup(1, 100):
  if isOpen[i]:
    echo("Door ",i," is open.")

Objeck

optimized

 
bundle Default {
  class Doors {
    function : Main(args : String[]) ~ Nil {
      doors := Bool->New[100];
 
      for(pass := 0; pass < 10; pass += 1;) {
        doors[(pass + 1) * (pass + 1) - 1] := true;
      };
 
      for(i := 0; i < 100; i += 1;) {    
        IO.Console->GetInstance()->Print("Door #")->Print(i + 1)->Print(" is ");
        if(doors[i]) {
          "open."->PrintLine();
        }
        else {
          "closed."->PrintLine();
        };
      };
    }
  }
}
 

Objective-C

A basic implementation in Objective-C:

This is a very basic Objective-C sample that shows the usage of standard types and classes such as NSInteger and NSMutableArray.

It uses modern Objective-C syntax such as literals, blocks, and a compiler module import statement.

 
@import Foundation;
 
int main(int argc, const char * argv[]) {
    @autoreleasepool {
 
        // Create a mutable array
        NSMutableArray *doorArray = [@[] mutableCopy];
 
        // Fill the doorArray with 100 closed doors
        for (NSInteger i = 0; i < 100; ++i) {
            doorArray[i] = @NO;
        }
 
        // Do the 100 passes
        for (NSInteger pass = 0; pass < 100; ++pass) {
            for (NSInteger door = pass; door < 100; door += pass+1) {
                doorArray[door] = [doorArray[door]  isEqual: @YES] ? @NO : @YES;
            }
        }
 
        // Print the results
        [doorArray enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
            if ([obj isEqual: @YES]) {
                NSLog(@"Door number %lu is open", idx + 1);
            }
        }];
    }
}
 

A more typical implementation in Objective-C:

This example is more along the lines of what typical Objective-C program would look like.

Language features used include:

• MVC design pattern with separate classes for the data model, user interface, and controller (Here, main steps in to represent the controller class.)
• Class category to extend the standard NSMutableArray class to add doors without a subclass
• Class inheritance in the DoorViewClass when subclassing NSObject
• Pragma mark statements for IDE navigation in Xcode

In a real world program classes are normally separated into different files.

 
@import Foundation;
 
#pragma mark - Classes
////////////////////////////////////////////////////
// Model class header - A we are using a category to add a method to MSMutableArray
@interface NSMutableArray (DoorModelExtension)
 
- (void)setNumberOfDoors:(NSUInteger)doors;
 
@end
 
// Model class implementation
@implementation NSMutableArray (DoorModelExtension)
 
- (void)setNumberOfDoors:(NSUInteger)doors {
    // Fill the doorArray with 100 closed doors
    for (NSInteger i = 0; i < doors; ++i) {
        self[i] = @NO;
    }
}
@end
////////////////////////////////////////////////////
 
// View class header - A simple class to handle printing our values
@interface DoorViewClass : NSObject
 
- (void)printResultsOfDoorTask:(NSMutableArray *)doors;
 
@end
 
// View class implementation
@implementation DoorViewClass
 
- (void)printResultsOfDoorTask:(NSMutableArray *)doors {
 
    // Print the results, using an enumeration block for easy index tracking
    [doors enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
        if ([obj isEqual: @YES]) {
            NSLog(@"Door number %lu is open", idx + 1);
        }
    }];
}
 
@end
////////////////////////////////////////////////////
 
#pragma mark - main
// With our classes set we can use them from our controller, in this case main
int main(int argc, const char * argv[]) {
 
    // Init our classes
    NSMutableArray *doorArray = [NSMutableArray array];
    DoorViewClass *doorView = [DoorViewClass new];
 
    // Use our class category to add the doors
    [doorArray setNumberOfDoors:100];
 
    // Do the 100 passes
    for (NSUInteger pass = 0; pass < 100; ++pass) {
        for (NSUInteger door = pass; door < 100; door += pass+1) {
            doorArray[door] = [doorArray[door]  isEqual: @YES] ? @NO : @YES;
        }
    }
 
    // Print the results
    [doorView printResultsOfDoorTask:doorArray];
 
}
 

OCaml

unoptimized

let max_doors = 100
 
let show_doors =
  Array.iteri (fun i x -> Printf.printf "Door %d is %s\n" (i+1)
                                        (if x then "open" else "closed"))
 
let flip_doors doors =
  for i = 1 to max_doors do
    let rec flip idx =
      if idx < max_doors then begin
        doors.(idx) <- not doors.(idx);
        flip (idx + i)
      end
    in flip (i - 1)
  done;
  doors
 
let () =
  show_doors (flip_doors (Array.make max_doors false))

optimized

let optimised_flip_doors doors =
  for i = 1 to int_of_float (sqrt (float_of_int max_doors)) do
    doors.(i*i - 1) <- true
  done;
  doors
 
let () =
  show_doors (optimised_flip_doors (Array.make max_doors false))

This variant is more functional style (loops are recursions), unoptimized, and we do rather 100 passes on first element, then 100 * second, to avoid mutable data structures and many intermediate lists.

type door = Open | Closed    (* human readable code *)
 
let flipdoor = function Open -> Closed | Closed -> Open
 
let string_of_door =       
  function Open -> "is open." | Closed -> "is closed."
 
let printdoors ls =
  let f i d = Printf.printf "Door %i %s\n" (i + 1) (string_of_door d)
  in List.iteri f ls
 
let outerlim = 100
let innerlim = 100
 
let rec outer cnt accu =
  let rec inner i door = match i > innerlim with (* define inner loop *)
    | true  -> door                         
    | false -> inner (i + 1) (if (cnt mod i) = 0 then flipdoor door else door)
  in (* define and do outer loop *)
  match cnt > outerlim with
  | true  -> List.rev accu
  | false -> outer  (cnt + 1)  (inner 1 Closed :: accu) (* generate new entries with inner *)
 
let () = printdoors (outer 1 [])

Octave

doors = false(100,1);
for i = 1:100
  for j = i:i:100
    doors(j) = !doors(j);
  endfor
endfor
for i = 1:100
  if ( doors(i) )
    s = "open";
  else
    s = "closed";
  endif
  printf("%d %s\n", i, s);
endfor

See also the solutions in Matlab. They will work in Octave, too.

Oforth

: doors
| i j l |
   ListBuffer initValue(100, false) ->l
   100 loop: i [ 
      i 100 i step: j [ l put(j, l at(j) not) ] 
      ] 
   l println ;

Onyx

$Door dict def
1 1 100 {Door exch false put} for
$Toggle {dup Door exch get not Door up put} def
$EveryNthDoor {dup 100 {Toggle} for} def
$Run {1 1 100 {EveryNthDoor} for} def
$ShowDoor {dup `Door no. ' exch cvs cat ` is ' cat
  exch Door exch get {`open.\n'}{`shut.\n'} ifelse cat
  print flush} def
Run 1 1 100 {ShowDoor} for

Output:

Door no. 1 is open.
Door no. 2 is shut.
Door no. 3 is shut.
Door no. 4 is open.
Door no. 5 is shut.
Door no. 6 is shut.
Door no. 7 is shut.
Door no. 8 is shut.
Door no. 9 is open.
Door no. 10 is shut.
Door no. 11 is shut.
Door no. 12 is shut.
Door no. 13 is shut.
Door no. 14 is shut.
Door no. 15 is shut.
Door no. 16 is open.
Door no. 17 is shut.
Door no. 18 is shut.
Door no. 19 is shut.
Door no. 20 is shut.
Door no. 21 is shut.
Door no. 22 is shut.
Door no. 23 is shut.
Door no. 24 is shut.
Door no. 25 is open.
Door no. 26 is shut.
Door no. 27 is shut.
Door no. 28 is shut.
Door no. 29 is shut.
Door no. 30 is shut.
Door no. 31 is shut.
Door no. 32 is shut.
Door no. 33 is shut.
Door no. 34 is shut.
Door no. 35 is shut.
Door no. 36 is open.
Door no. 37 is shut.
Door no. 38 is shut.
Door no. 39 is shut.
Door no. 40 is shut.
Door no. 41 is shut.
Door no. 42 is shut.
Door no. 43 is shut.
Door no. 44 is shut.
Door no. 45 is shut.
Door no. 46 is shut.
Door no. 47 is shut.
Door no. 48 is shut.
Door no. 49 is open.
Door no. 50 is shut.
Door no. 51 is shut.
Door no. 52 is shut.
Door no. 53 is shut.
Door no. 54 is shut.
Door no. 55 is shut.
Door no. 56 is shut.
Door no. 57 is shut.
Door no. 58 is shut.
Door no. 59 is shut.
Door no. 60 is shut.
Door no. 61 is shut.
Door no. 62 is shut.
Door no. 63 is shut.
Door no. 64 is open.
Door no. 65 is shut.
Door no. 66 is shut.
Door no. 67 is shut.
Door no. 68 is shut.
Door no. 69 is shut.
Door no. 70 is shut.
Door no. 71 is shut.
Door no. 72 is shut.
Door no. 73 is shut.
Door no. 74 is shut.
Door no. 75 is shut.
Door no. 76 is shut.
Door no. 77 is shut.
Door no. 78 is shut.
Door no. 79 is shut.
Door no. 80 is shut.
Door no. 81 is open.
Door no. 82 is shut.
Door no. 83 is shut.
Door no. 84 is shut.
Door no. 85 is shut.
Door no. 86 is shut.
Door no. 87 is shut.
Door no. 88 is shut.
Door no. 89 is shut.
Door no. 90 is shut.
Door no. 91 is shut.
Door no. 92 is shut.
Door no. 93 is shut.
Door no. 94 is shut.
Door no. 95 is shut.
Door no. 96 is shut.
Door no. 97 is shut.
Door no. 98 is shut.
Door no. 99 is shut.
Door no. 100 is open.

ooRexx

doors = .array~new(100)    -- array containing all of the doors
do i = 1 to doors~size     -- initialize with a collection of closed doors
   doors[i] = .door~new(i)
end
 
do inc = 1 to doors~size
  do d = inc to doors~size by inc
    doors[d]~toggle
  end
end
say "The open doors after 100 passes:"
do door over doors
  if door~isopen then say door
end
 
::class door           -- simple class to represent a door
::method init          -- initialize an instance of a door
  expose id state      -- instance variables of a door
  use strict arg id    -- set the id
  state = .false       -- initial state is closed
 
::method toggle        -- toggle the state of the door
  expose state
  state = \state
 
::method isopen        -- test if the door is open
  expose state
  return state
 
::method string        -- return a string value for a door
  expose state id
  if state then return "Door" id "is open"
  else return "Door" id "is closed"
 
::method state         -- return door state as a descriptive string
  expose state
  if state then return "open"
  else return "closed"

The two programs in the Rexx section run under ooRexx when '#' is replaced by, e.g., 'dd'.
'#' is not supported by ooRexx as part of or as a symbol. Neither are @ and $.

OpenEdge/Progress

DEFINE VARIABLE lopen   AS LOGICAL     NO-UNDO EXTENT 100.
DEFINE VARIABLE idoor   AS INTEGER     NO-UNDO.
DEFINE VARIABLE ipass   AS INTEGER     NO-UNDO.
DEFINE VARIABLE cresult AS CHARACTER   NO-UNDO.
 
DO ipass = 1 TO 100:
   idoor = 0.
   DO WHILE idoor <= 100:
      idoor = idoor + ipass.
      IF idoor <= 100 THEN
         lopen[ idoor ] = NOT lopen[ idoor ].
   END.
END.
 
DO idoor = 1 TO 100:
   cresult = cresult + STRING( lopen[ idoor ], "1  /0  " ).
   IF idoor MODULO 10 = 0 THEN
      cresult = cresult + "~r":U.
END.
 
MESSAGE cresult VIEW-AS ALERT-BOX.
 

OxygenBasic

def    doors 100
int    door[doors],i ,j, c
string cr,tab,pr
'
for i=1 to doors
  for j=i to doors step i
    door[j]=1-door[j]
    if door[j] then c++ else c--
  next
next
'
cr=chr(13) chr(10)
pr="Doors Open: " c cr cr 
'
for i=1 to doors
   if door[i] then pr+=i cr
next
print pr

Oz

declare
  NumDoors = 100
  NumPasses = 100
 
  fun {NewDoor} closed end
 
  fun {Toggle Door}
     case Door of closed then open
     [] open then closed
     end
  end
 
  fun {Pass Doors I}
     {List.mapInd Doors
      fun {$ Index Door}
         if Index mod I == 0 then {Toggle Door}
         else Door
         end
      end}
  end
 
  Doors0 = {MakeList NumDoors}
  {ForAll Doors0 NewDoor}
 
  DoorsN = {FoldL {List.number 1 NumPasses 1} Pass Doors0}
in
  %% print open doors
  {List.forAllInd DoorsN
   proc {$ Index Door}
      if Door == open then
	 {System.showInfo "Door "#Index#" is open."}
      end
   end
  }

Output:

Door 1 is open.
Door 4 is open.
Door 9 is open.
Door 16 is open.
Door 25 is open.
Door 36 is open.
Door 49 is open.
Door 64 is open.
Door 81 is open.
Door 100 is open.

PARI/GP

Unoptimized version.

 
v=vector(d=100);/*set 100 closed doors*/
for(i=1,d,forstep(j=i,d,i,v[j]=1-v[j]));
for(i=1,d,if(v[i],print("Door ",i," is open.")))
 

Optimized version.

for(n=1,sqrt(100),print("Door ",n^2," is open."))

Pascal

Program OneHundredDoors;
 
var
   doors : Array[1..100] of Boolean;
   i, j	 : Integer;
 
begin
   for i := 1 to 100 do
      doors[i] := False;
   for i := 1 to 100 do begin
      j := i;
      while j <= 100 do begin
	 doors[j] := not doors[j];
	 j := j + i
      end
   end;
   for i := 1 to 100 do begin
      Write(i, ' ');
      if doors[i] then
	 WriteLn('open')
      else
	 WriteLn('closed');
   end
end.

Optimized version.

program OneHundredDoors;
 
{$APPTYPE CONSOLE}
 
uses
  math, sysutils;
 
var
   AOpendoors  : String;
   ACloseDoors : String;
   i	       : Integer;
 
begin
   for i := 1 to 100 do
   begin
      if (sqrt(i) = floor(sqrt(i))) then
        AOpenDoors := AOpenDoors + IntToStr(i) + ';'
      else
        ACloseDoors := ACloseDoors + IntToStr(i) +';';
   end;
 
   WriteLn('Open doors: ' + AOpenDoors);
   WriteLn('Close doors: ' + ACloseDoors);
end.     

Perl

unoptimized

Works with: Perl version 5.x

my @doors;
for my $pass (1 .. 100) {
    for (1 .. 100) {
        if (0 == $_ % $pass) {
            $doors[$_] = not $doors[$_];
        };
    };
};
 
print "Door $_ is ", $doors[$_] ? "open" : "closed", "\n" for 1 .. 100;

semi-optimized

Works with: Perl version 5.x

This version flips doors, but doesn't visit (iterate over) doors that aren't toggled. Note: I represent open doors as 0 and closed as 1 just for preference. (When I print it as a bit vector, 0 looks more like an open door to me.)

 
#!/usr/bin/perl
use strict;
use warnings;
 
my @doors = (1) x 100;
for my $N (1 .. 100) {
   $doors[$_]=1-$doors[$_] for map { $_*$N - 1 } 1 .. int(100/$N);
}
print join("\n", map { "Door $_ is Open" } grep { ! $doors[$_-1] } 1 .. 100), "\n";
print "The rest are closed\n";
 

optimized

Works with: Perl version 5.x

print "Door $_ is open\n" for map $_**2, 1 .. 10;

print "Door $_ is ", qw"closed open"[int sqrt == sqrt], "\n" for 1..100;

while( ++$i <= 100 )
{
    $root = sqrt($i);
    if ( int( $root ) == $root )
    {
        print "Door $i is open\n";
    }
    else
    {
        print "Door $i is closed\n";
    }
}

Perl5i

 
use perl5i::2;
 
package doors {
 
  use perl5i::2;
  use Const::Fast;
 
  const my $OPEN   => 1;
  const my $CLOSED => 0;
 
  # ----------------------------------------
  # Constructor: door->new( @args );
  # input: N - how many doors?
  # returns: door object
  #
  method new($class: @args ) {
    my $self = bless {}, $class;
    $self->_init( @args );
    return $self;
  }
 
  # ----------------------------------------
  # class initializer.
  # input: how many doors?
  # sets N, creates N+1 doors ( door zero is not used ).
  #
  method _init( $N ) {
    $self->{N} = $N;
    $self->{doors} = [ ($CLOSED) x ($N+1) ];
  }
 
  # ----------------------------------------
  # $self->toggle( $door_number );
  # input: number of door to toggle.
  # OPEN a CLOSED door; CLOSE an OPEN  door.
  #
  method toggle( $which ) {
    $self->{doors}[$which] = ( $self->{doors}[$which] == $OPEN
                               ? $CLOSED
                               : $OPEN
        		     );
  }
 
  # ----------------------------------------
  # $self->toggle_n( $cycle );
  # input: number.
  # Toggle doors 0, $cycle, 2 * $cycle, 3 * $cycle, .. $self->{N}
  #
  method toggle_n( $n ) {
    $self->toggle($_)
      for map { $n * $_ }
          ( 1 .. int( $self->{N} / $n) );
 
  }
 
  # ----------------------------------------
  # $self->toggle_all();
  # Toggle every door, then every other door, every third door, ...
  #
  method toggle_all() {
    $self->toggle_n( $_ ) for ( 1 .. $self->{N} );
  }
 
 
  # ----------------------------------------
  # $self->print_open();
  # Print list of which doors are open.
  #
  method print_open() {
    say join ', ', grep { $self->{doors}[$_] == $OPEN } ( 1 ... $self->{N} );
  }
}
 
# ----------------------------------------------------------------------
# Main Thread
#
my $doors = doors->new(100);
$doors->toggle_all();
$doors->print_open();
 

Perl 6

unoptimized

Works with: Rakudo version 2015.09"

my @doors = False xx 101;
 
(.=not for @doors[0, $_ ... 100]) for 1..100;
 
say "Door $_ is ", <closed open>[ @doors[$_] ] for 1..100;

optimized

say "Door $_ is open" for map {$^n ** 2}, 1..10;

Here's a version using the cross meta-operator instead of a map:

 say "Door $_ is open" for 1..10 X** 2;

This one prints both opened and closed doors:

say "Door $_ is ", <closed open>[.sqrt == .sqrt.floor] for 1..100;

verbose version, but uses ordinary components

Works with: Rakudo version 2016.07 Tom Legrady

 
sub  output( @arr, $max ) {
    my $output = 1;
    for 1..^$max -> $index {
	if @arr[$index] {
	    printf "%4d", $index;
	    say '' if $output++ %%  10;
	}
    }
    say '';
}
 
sub MAIN ( Int :$doors = 100 ) {
    my $doorcount = $doors + 1;
    my @door[$doorcount] = 0 xx ($doorcount);
 
    INDEX:
    for 1...^$doorcount -> $index {
        # flip door $index & its multiples, up to last door.
        #
	for ($index, * + $index ... *)[^$doors] -> $multiple {
	    next INDEX if $multiple > $doors;
	    @door[$multiple] =  @door[$multiple] ?? 0 !! 1;
	}
    }
    output @door, $doors+1;
}
 

Output:

$ ./100_doors.pl6 -doors=100
   1   4   9  16  25  36  49  64  81

Phix

unoptimised

sequence doors = repeat(false,100)
 
for i=1 to 100 do
    for j=i to 100 by i do
        doors[j] = not doors[j]
    end for
end for
 
for i=1 to 100 do
    if doors[i] == true then
        printf(1,"Door #%d is open.\n", i)
    end if
end for

Output:

Door #1 is open.
Door #4 is open.
Door #9 is open.
Door #16 is open.
Door #25 is open.
Door #36 is open.
Door #49 is open.
Door #64 is open.
Door #81 is open.
Door #100 is open.

optimised

function doors(integer n)
-- returns the perfect squares<=n
integer door = 1, step = 1
sequence res = {}
    while door<=n do
        res &= door
        step += 2
        door += step
    end while
    return res
end function
 
?doors(100)

Output:

{1,4,9,16,25,36,49,64,81,100}

PHL

unoptimized

module doors;
 
extern printf;
 
@Integer main [
	@Array<@Boolean> doors = new @Array<@Boolean>.init(100);
	var i = 1;
	while (i <= 100) {
		var j = i-1;
		while (j < 100) {
			doors.set(j, doors.get(j)::not);
			j = j + i;
		}
		i = i::inc;
	}
	i = 0;
	while (i < 100) {
		printf("%i %s\n", i+1, iif(doors.get(i), "open", "closed"));
		i = i::inc;
	}
	return 0;
]

optimized

Translation of: C#

module var;
 
extern printf;
 
@Integer main [
	var door = 1;
	var incrementer = 0;
	var current = 1;
        while (current <= 100)
        {
		printf("Door %i ", current);
		if (current == door)
		{
			printf("open\n");
			incrementer = incrementer::inc;
			door = door + 2 * incrementer + 1;
		}
		else
			printf("closed\n");
 
		current = current + 1;
 
        }
 
	return 0;
]

PHP

See: Demo optimized

<?php
for ($i = 1; $i <= 100; $i++) {
	$root = sqrt($i);
	$state = ($root == ceil($root)) ? 'open' : 'closed';
	echo "Door {$i}: {$state}\n";
}
?>

unoptimized

<?php
$doors = array_fill(1, 100, false);
for ($pass = 1; $pass <= 100; ++$pass) {
	for ($nr = 1; $nr <= 100; ++$nr) {
		if ($nr % $pass == 0) {
			$doors[$nr] = !$doors[$nr];
		}
	}
}
for ($nr = 1; $nr <= 100; ++$nr)
	printf("Door %d: %s\n", $nr, ($doors[$nr])?'open':'closed');
?>

PicoLisp

unoptimized

(let Doors (need 100)
   (for I 100
      (for (D (nth Doors I)  D  (cdr (nth D I)))
         (set D (not (car D))) ) )
   (println Doors) )

optimized

(let Doors (need 100)
   (for I (sqrt 100)
      (set (nth Doors (* I I)) T) )
   (println Doors) )

Output in both cases:

(T NIL NIL T NIL NIL NIL NIL T NIL NIL NIL NIL NIL NIL T NIL NIL NIL NIL NIL NIL
 NIL NIL T NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL T NIL NIL NIL NIL NIL NIL NIL
 NIL NIL NIL NIL NIL T NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL T
 NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL T NIL NIL NIL N
IL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL NIL T)

With formatting:

(let Doors (need 100)
   (for I (sqrt 100)
      (set (nth Doors (* I I)) T) )
   (make
      (for (N . D) Doors
         (when D (link N)) ) ) )

Output:

(1 4 9 16 25 36 49 64 81 100)

Piet

image

Pike

array onehundreddoors()
{
    array doors = allocate(100);
    foreach(doors; int i;)
        for(int j=i; j<100; j+=i+1)
            doors[j] = !doors[j];
    return doors;
}

optimized version:

array doors = map(enumerate(100,1,1), lambda(int x)
                                      {  
                                          return sqrt((float)x)%1 == 0.0; 
                                      });

write("%{%d %d %d %d %d %d %d %d %d %d\n%}\n", doors/10)

output:

1 0 0 1 0 0 0 0 1 0
0 0 0 0 0 1 0 0 0 0
0 0 0 0 1 0 0 0 0 0
0 0 0 0 0 1 0 0 0 0
0 0 0 0 0 0 0 0 1 0
0 0 0 0 0 0 0 0 0 0
0 0 0 1 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0
1 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 1

PL/I

 
declare door(100) bit (1) aligned;
declare closed bit (1) static initial ('0'b),
        open   bit (1) static initial ('1'b);
declare (i, inc) fixed binary;
 
door = closed;
inc = 1;
do until (inc >= 100);
   do i = inc to 100 by inc;
      door(i) = ^door(i); /* close door if open; open it if closed. */
   end;
   inc = inc+1;
end;
 
do i = 1 to 100;
   put skip edit ('Door ', trim(i), ' is ') (a);
   if door(i) then put edit (' open.') (a);
   else put edit (' closed.') (a);
end;
 

PL/SQL

Unoptimized

 
DECLARE
  TYPE doorsarray IS VARRAY(100) OF BOOLEAN;
  doors doorsarray := doorsarray();
BEGIN
 
doors.EXTEND(100);  --ACCOMMODATE 100 DOORS
 
FOR i IN 1 .. doors.COUNT  --MAKE ALL 100 DOORS FALSE TO INITIALISE
  LOOP
     doors(i) := FALSE;                    
  END LOOP;
 
FOR j IN 1 .. 100 --ITERATE THRU USING MOD LOGIC AND FLIP THE DOOR RIGHT OPEN OR CLOSE
 LOOP
      FOR k IN 1 .. 100
        LOOP
                  IF MOD(k,j)=0 THEN 
                     doors(k) := NOT doors(k); 
                  END IF;
        END LOOP;
 END LOOP;
 
FOR l IN 1 .. doors.COUNT  --PRINT THE STATUS IF ALL 100 DOORS AFTER ALL ITERATION
  LOOP
       DBMS_OUTPUT.PUT_LINE('DOOR '||l||' IS -->> '||CASE WHEN SYS.DBMS_SQLTCB_INTERNAL.I_CONVERT_FROM_BOOLEAN(doors(l)) = 'TRUE' 
                                                                THEN 'OPEN' 
                                                              ELSE 'CLOSED' 
                                                        END);
  END LOOP;
 
END;
 

Pop11

unoptimized

lvars i;
lvars doors = {% for i from 1 to 100 do false endfor %};
for i from 1 to 100 do
   for j from i by i to 100 do
      not(doors(j)) -> doors(j);
   endfor;
endfor;
;;; Print state
for i from 1 to 100 do
   printf('Door ' >< i >< ' is ' ><
            if doors(i) then 'open' else 'closed' endif, '%s\n');
endfor;

optimized

for i to 100 do
    lvars root = sqrt(i);
    i; if root = round(root) then ' open' ><; else ' closed' ><; endif; =>
endfor;

PostScript

Bruteforce:

/doors [ 100 { false } repeat ] def
 
1 1 100 { dup 1 sub exch 99 {
        dup doors exch get not doors 3 1 roll put
} for } for
doors pstack

Shows:

[true false false true false false false false true false ...<90 doors later>... true]

Potion

square=1, i=3
1 to 100(door):
  if (door == square):
    ("door", door, "is open") say
    square += i
    i += 2.
.

PowerShell

unoptimized

$doors = @(0..99)
for($i=0; $i -lt 100; $i++) {
  $doors[$i] = 0  # start with all doors closed
}
for($i=0; $i -lt 100; $i++) {
  $step = $i + 1
  for($j=$i; $j -lt 100; $j = $j + $step) {
    $doors[$j] = $doors[$j] -bxor 1
  }
}
foreach($doornum in 1..100) {
  if($doors[($doornum-1)] -eq $true) {"$doornum open"}
  else {"$doornum closed"}
}

Alternative Method

function Get-DoorState($NumberOfDoors)
{
   begin 
   {
      $Doors = @()
      $Multiple = 1
   }
 
   process
   {
      for ($i = 1; $i -le $NumberOfDoors; $i++)
      {
         $Door = [pscustomobject]@{
                    Name = $i
                    Open = $false
                 }
 
         $Doors += $Door   
      }
 
      While ($Multiple -le $NumberOfDoors)
      {
	 Foreach ($Door in $Doors)
	 {
	    if ($Door.name % $Multiple -eq 0)
               {
	          If ($Door.open -eq $False){$Door.open = $True}
	          Else {$Door.open = $False}
	       }
	 }
 
         $Multiple++
      }
    }
 
    end {$Doors}
}

unoptimized Pipeline

$doors = 1..100 | ForEach-Object {0}
1..100 | ForEach-Object { $a=$_;1..100 | Where-Object { -not ( $_ % $a )  } | ForEach-Object { $doors[$_-1] = $doors[$_-1] -bxor 1 }; if ( $doors[$a-1] ) { "door opened" } else { "door closed" } }
 

unoptimized Pipeline 2

$doors = 1..100 | ForEach-Object {0}
$visited = 1..100
1..100 | ForEach-Object { $a=$_;$visited[0..([math]::floor(100/$a)-1)] | Where-Object { -not ( $_ % $a )  } | ForEach-Object { $doors[$_-1] = $doors[$_-1] -bxor 1;$visited[$_/$a-1]+=($_/$a) }; if ( $doors[$a-1] ) { "door opened" } else { "door closed" } }
 

unoptimized Pipeline 3 (dynamically build pipeline)

1..100|foreach-object {$pipe += "toggle $_ |"} -begin {$pipe=""}
filter toggle($pass) {$_.door = $_.door -xor !($_.index % $pass);$_}
invoke-expression "1..100| foreach-object {@{index=`$_;door=`$false}} | $pipe  out-host"
 

Using Powershell Workflow for Parallelism

 
 
Workflow Calc-Doors {
    Foreach –parallel ($number in 1..100) {
        "Door " + $number.ToString("0000") + ": " + @{$true="Closed";$false="Open"}[([Math]::pow($number, 0.5)%1) -ne 0]
    }
}
Calc-Doors | sort
 
 

optimized

 
1..10|%{"Door "+ $_*$_ + " is open"}
 

ProDOS

Uses math module.

enableextensions 
enabledelayedexpansion
editvar /newvar /value=0 /title=closed
editvar /newvar /value=1 /title=open
editvar /newvar /range=1-100 /increment=1 /from=2
editvar /newvar /value=2 /title=next
:doors
for /alloccurrences (!next!-!102!) do editvar /modify /value=-open-
editvar /modify /value=-next-=+1
if -next- /hasvalue=100 goto :cont else goto :doors
:cont
printline !1!-!102!
stoptask

Prolog

unoptimized

Declarative:

main :-
    forall(between(1,100,Door), ignore(display(Door))).
 
% show output if door is open after the 100th pass
display(Door) :-
    status(Door, 100, open),
    format("Door ~d is open~n", [Door]).
 
% true if Door has Status after Pass is done
status(Door, Pass, Status) :-
    Pass > 0,
    Remainder is Door mod Pass,
    toggle(Remainder, OldStatus, Status),
    OldPass is Pass - 1,
    status(Door, OldPass, OldStatus).
status(_Door, 0, closed).
 
toggle(Remainder, Status, Status) :-
    Remainder > 0.
toggle(0, open, closed).
toggle(0, closed, open).
 

Doors as a list:

doors_unoptimized(N) :-
	length(L, N),
	maplist(init, L),
	doors(N, N, L, L1),
	affiche(N, L1).
 
init(close).
 
doors(Max, 1, L, L1) :-
	!,
       inverse(1, 1, Max, L, L1).
 
doors(Max, N, L, L1) :-
	N1 is N - 1,
	doors(Max, N1, L, L2),
	inverse(N, 1, Max, L2, L1).
 
 
inverse(N, Max, Max, [V], [V1]) :-
	!,
	0 =:= Max mod N -> inverse(V, V1); V1 = V.
 
inverse(N, M, Max, [V|T], [V1|T1]) :-
	M1 is M+1,
	inverse(N, M1, Max, T, T1),
	(   0 =:= M mod N -> inverse(V, V1); V1 = V).
 
 
inverse(open, close).
inverse(close, open).
 
affiche(N, L) :-
	forall(between(1, N, I),
	       (   nth1(I, L, open) -> format('Door ~w is open.~n', [I]); true)).
 

Using dynamic-rules. Tried to be ISO:

doors(Num, Passes) :-
    forall(( everyNth(1,Passes,1,Pass)
           , forall((everyNth(Pass,Num,Pass,Door), toggle(Door)))
           ))
  , show(Num)
  .
 
 
toggle(Door) :-
    Opened = opened(Door)
  , ( clause(Opened,_) -> retract(Opened)
                        ; asserta(Opened)
    ).
 
 
show(Num) :-
    forall(( between(1,Num,Door)
           , (opened(Door) -> State = opened ; State = closed)
           , write(Door), write(' '), write(State), nl
           )).
 
 
% utils
forall(X) :- findall(_, X, _).
 
everyNth(From,To,Step,X) :-
    From =< To
  , ( X = From ; From1 is From + Step, everyNth(From1,To,Step,X) )
  .
 
main :- doors(100,100), halt.

optimized

doors_optimized(N) :-
	Max is floor(sqrt(N)),
	forall(between(1, Max, I),
	       (   J is I*I,format('Door ~w is open.~n',[J]))).
 
 

Processing

Unoptimized, Brute Force

boolean[] doors = new boolean[100];
 
void setup() {
  for (int i = 0; i < 100; i++) {
    doors[i] = false;
  }
  for (int i = 1; i < 100; i++) {
    for (int j = 0; j < 100; j += i) {
      doors[j] = !doors[j];
    }
  }
  println("Open:");
  for (int i = 1; i < 100; i++) {
    if (doors[i]) {
      println(i);
    }
  }
  exit();
}

Output:

Open:
1
4
9
16
25
36
49
64
81

Pure

using system;
 
// initialize doors as pairs: number, status where 0 means open
let doors = zip (1..100) (repeat 1);
 
toogle (x,y) = x,~y;
 
toogleEvery n d = map (tooglep n) d with
                    tooglep n [email protected]((x,_)) = toogle d if ~(x mod n);
                                        = d otherwise; end;
 
// show description of given doors
status (n,x) = (str n) + (case x of
                            1 = " close";
                            0 = " open"; end);
 
let result = foldl (\a n -> toogleEvery n a) doors (1..100);
 
// pretty print the result (only open doors)
showResult = do (puts.status) final when
               final = filter open result with
                         open (_,x) = ~x;
                       end; end;
 

Output:

 
> showResult;
1 open
4 open
9 open
16 open
25 open
...

PureBasic

unoptimized

Dim doors.i(100)
 
For x = 1 To 100
  y = x
  While y <= 100
    doors(y) = 1 - doors(y)
    y + x
  Wend
Next
 
OpenConsole()
PrintN("Following Doors are open:")
For x = 1 To 100
  If doors(x)
    Print(Str(x) + ", ")
  EndIf
Next
Input()

optimized

OpenConsole()
PrintN("Following Doors are open:")
For i = 1 To 100
    root.f = Sqr(i)
    If root = Int(root)
    	Print (Str(i) + ", ")
    EndIf
Next     
Input()

Output:

Following Doors are open:
1, 4, 9, 16, 25, 36, 49, 64, 81, 100,

Pyret

 
data Door:
  | open
  | closed
end
 
fun flip-door(d :: Door) -> Door:
  cases(Door) d:
    | open => closed
    | closed => open
  end
end
 
 
fun flip-doors(doors :: List<Door>) -> List<Door>:
  doc:```Given a list of door positions, repeatedly switch the positions of
      every nth door for every nth pass, and return the final list of door
      positions```
  for fold(flipped-doors from doors, n from range(1, doors.length() + 1)):
    for map_n(m from 1, d from flipped-doors):
      if num-modulo(m, n) == 0:
        flip-door(d)
      else:
        d
      end
    end
  end
where:
    flip-doors([list: closed, closed, closed]) is
  [list: open, closed, closed]
 
  flip-doors([list: closed, closed, closed, closed]) is
  [list: open, closed, closed, open]
 
  flip-doors([list: closed, closed, closed, closed, closed, closed]) is
  [list: open, closed, closed, open, closed, closed]
 
  closed-100 = for map(_ from range(1, 101)): closed end
  answer-100 = for map(n from range(1, 101)):
    if num-is-integer(num-sqrt(n)): open
    else: closed
    end
  end
 
  flip-doors(closed-100) is answer-100
end
 
fun find-indices<A>(pred :: (A -> Boolean), xs :: List<A>) -> List<Number>:
    doc:```Given a list and a predicate function, produce a list of index
      positions where there's a match on the predicate```
  ps = map_n(lam(n,e): if pred(e): n else: -1 end end, 1, xs)
  ps.filter(lam(x): x >= 0 end)
where:
  find-indices((lam(i): i == true end), [list: true,false,true]) is [list:1,3]
end
 
 
fun run(n):
  doc:```Given a list of doors that are closed, make repeated passes 
      over the list, switching the positions of every nth door for 
      each nth pass. Return a list of positions in the list where the
      door is Open.```
  doors = repeat(n, closed)
  ys = flip-doors(doors)
  find-indices((lam(y): y == open end), ys)
where:
  run(4) is [list: 1,4]
end
 
run(100)
 
 

Python

Works with: Python version 2.5+

unoptimized

 
doors = [False] * 100
for i in range(100):
   for j in range(i, 100, i+1):
       doors[j] = not doors[j]
   print("Door %d:" % (i+1), 'open' if doors[i] else 'close')
 

optimized

A version that only visits each door once:

for i in xrange(1, 101):
    root = i ** 0.5
    print "Door %d:" % i, 'open' if root == int(root) else 'close'

One liner using a list comprehension, item lookup, and is_integer

print '\n'.join(['Door %s is %s' % (i, ('closed', 'open')[(i**0.5).is_integer()]) for i in xrange(1, 101)])

One liner using a generator expression, ternary operator, and modulo

print '\n'.join('Door %s is %s' % (i, 'closed' if i**0.5 % 1 else 'open') for i in range(1, 101))

Works with: Python version 3.x

 
for i in range(1, 101):
    if i**0.5 % 1:
        state='open'
    else:
        state='close'
    print("Door {}:{}".format(i, state))
 

ultra-optimized: ported from Julia version

for i in range(1,11): print("Door %s is open" % i**2)

Q

unoptimized

`closed`open mod[;2]count each 1 _ group raze where each 0=t mod\:/:t:til 101

optimized

`closed`open (1+til 100) in `int$xexp[;2] 1+til 10

R

Using a loop

doors_puzzle <- function(ndoors=100,passes=100) {
    doors <- rep(FALSE,ndoors)
    for (ii in seq(1,passes)) {
        mask <- seq(0,ndoors,ii)
        doors[mask] <- !doors[mask]	
    }
    return (which(doors == TRUE))
}
 
doors_puzzle()

optimized

x <- rep(1, 100)
for (i in 1:100-1) {
    x <- xor(x, rep(c(rep(0,i),1), length.out=100))
}
which(!x)

Using a **ply function

doors_puzzle <- function(ndoors=100,passes=100) {
names(which(table(unlist(sapply(1:passes, function(X) seq(0, ndoors, by=X)))) %% 2 == 1))
}
 
doors_puzzle()

Racket

 
#lang racket
 
;; Applies fun to every step-th element of seq, leaving the others unchanged.
(define (map-step fun step seq)
  (for/list ([elt seq] [i (in-naturals)])
    ((if (zero? (modulo i step)) fun values) elt)))
 
(define (toggle-nth n seq)
  (map-step not n seq))
 
(define (solve seq)
  (for/fold ([result seq]) ([_ seq] [pass (in-naturals 1)])
    (toggle-nth pass result)))
 
(for ([door (solve (make-vector 101 #f))] [index (in-naturals)]
      #:when (and door (> index 0)))
  (printf "~a is open~%" index))
 

Optimized:

 
#lang racket
(for ([x (in-range 1 101)] #:when (exact-integer? (sqrt x)))
  (printf "~a is open\n" x))
 

Unoptimized imperative, with graphic rendering:

 
#lang slideshow
(define-syntax-rule (vector-neg! vec pos)
  (vector-set! vec pos (not (vector-ref vec pos))))
 
(define (make-doors)
  (define doors (make-vector 100 #f))
  (for* ([i 100] [j (in-range i 100 (add1 i))]) (vector-neg! doors j))
  doors)
 
(displayln (list->string (for/list ([d (make-doors)]) (if d #\o #\-))))
 
(define closed-door (inset (filled-rectangle 4 20) 2))
(define open-door (inset (rectangle 4 20) 2))
 
(for/fold ([doors (rectangle 0 0)]) ([open? (make-doors)])
  (hc-append doors (if open? open-door closed-door)))
 

Output:

RapidQ

 
dim x as integer, y as integer
dim door(1 to 100) as byte
 
'initialize array
for x = 1 to 100 : door(x) = 0 : next
 
'set door values
for y = 1 to 100
    for x = y to 100 step y
        door(x) = not door(x)
    next x
next y
 
'print result
for x = 1 to 100
    if door(x) then print "Door " + str$(x) + " = open"
next 
 
while inkey$="":wend
end
 

Output

Door 1 = open
Door 4 = open
Door 9 = open
Door 16 = open
Door 25 = open
Door 36 = open
Door 49 = open
Door 64 = open
Door 81 = open
Door 100 = open

REALbasic

'True=Open; False=Closed
  Dim doors(100) As Boolean   'Booleans default to false
  For j As Integer = 1 To 100
    For i As Integer = 1 to 100
      If i Mod j = 0 Then doors(i) = Not doors(i)
    Next
  Next

REBOL

Unoptimized

doors: array/initial 100 'closed
repeat i 100 [
    door: at doors i
    forskip door i [change door either 'open = first door ['closed] ['open]]
]

Optimized

doors: array/initial 100 'closed
repeat i 10 [doors/(i * i): 'open]
 

Red

Unoptimized

Red [
  Purpose: "100 Doors Problem (Perfect Squares)"
  Author: "Barry Arthur"
  Date: "07-Oct-2016"
]
doors: make vector! [char! 8 100]
repeat i 100 [change at doors i #"."]
 
repeat i 100 [
    j: i
    while [j <= 100] [
      door: at doors j
      change door either #"O" = first door [#"."] [#"O"]
      j: j + i
    ]
]
 
repeat i 10 [
  print copy/part at doors (i - 1 * 10 + 1) 10
]
 

Retro

: squared ( n-n  ) dup * ;
: doors   ( n-   ) [ 1 repeat 2over squared > 0; drop dup squared putn space 1+ again ] do 2drop ;
100 doors

REXX

version 1, the hard way

/*REXX pgm solves the  100 doors puzzle, doing it the hard way by opening/closing doors.*/
parse arg doors .                                /*obtain the optional argument from CL.*/
if doors=='' | doors==","  then doors=100        /*not specified?  Then assume 100 doors*/
                                                 /*        0 =  the door is  closed.    */
                                                 /*        1 =   "    "   "  open.      */
door.=0                                          /*assume all doors are closed at start.*/
                do #=1  for doors                /*process a pass─through for all doors.*/
                    do j=#  by #  to doors       /*  ··· every Jth door from this point.*/
                    door.j= \door.j              /*toggle the  "openness"  of the door. */
                    end   /*j*/
                end       /*#*/
 
say 'After '                doors          " passes, the following doors are open:"
say
                do k=1  for doors
                if door.k  then say right(k, 20) /*add some indentation for the output. */
                end    /*k*/                     /*stick a fork in it,  we're all done. */

output   using the default input:

After  100  passes, the following doors are open:

                   1
                   4
                   9
                  16
                  25
                  36
                  49
                  64
                  81
                 100

version 2, the easy way

/*REXX pgm solves the  100 doors  puzzle,  doing it the easy way by calculating squares.*/
parse arg doors .                                /*obtain the optional argument from CL.*/
if doors=='' | doors==","  then doors=100        /*not specified?  Then assume 100 doors*/
say 'After '          doors          " passes, the following doors are open:"
say
          do #=1  while  #**2 <= doors           /*process easy pass─through  (squares).*/
          say right(#**2, 20)                    /*add some indentation for the output. */
          end   /*#*/                            /*stick a fork in it,  we're all done. */

output   is identical to the 1^st REXX version.

Ring

Unoptimized

doors = list(100)
for i = 1 to 100
doors[i] = false
next
 
For pass = 1 To 100
         For door = pass To 100
             if doors[door] doors[door] = false else doors[door] = true ok
         door += pass-1
         Next
Next
 
For door = 1 To 100
     see "Door (" + door + ") is "
     If doors[door] see "Open" else see "Closed" ok
     see nl
Next

Optimized

doors = list(100)
for i = 1 to 100
doors[i] = false
next
 
For p = 1 To 10
        doors[pow(p,2)] = True
Next
 
For door = 1 To 100
     see "Door (" + door + ") is "
     If doors[door] see "Open" else see "Closed" ok
     see nl
Next

Ruby

unoptimized; Ruby-way

class Door
  attr_reader :state
 
  def initialize
    @state = :closed
  end
 
  def close
    @state = :closed
  end
 
  def open
    @state = :open
  end
 
  def closed?
    @state == :closed
  end
 
  def open?
    @state == :open
  end
 
  def toggle
    if closed? then open else close end
  end
 
  def to_s
    @state.to_s
  end
end
 
doors = Array.new(100) { Door.new }
1.upto(100) do |multiplier|
  doors.each_with_index do |door, i|
    door.toggle if (i + 1) % multiplier == 0
  end
end
 
doors.each_with_index { |door, i| puts "Door #{i+1} is #{door}." }

unoptimized

n = 100
Open = "open"
Closed = "closed"
def Open.toggle
  Closed
end
def Closed.toggle
  Open
end
doors = [Closed] * (n + 1)
for mul in 1..n
  for x in (mul..n).step(mul)
    doors[x] = doors[x].toggle
  end
end
doors.each_with_index do |b, i|
  puts "Door #{i} is #{b}" if i > 0
end

optimized

n = 100
(1..n).each do |i| 
  puts "Door #{i} is #{i**0.5 == (i**0.5).round ? "open" : "closed"}"
end

generic true/false, with another way of handling the inner loop demonstrating Range#step

doors = [false] * 100
100.times do |i|
  (i ... doors.length).step(i + 1) do |j|
    doors[j] = !doors[j]
  end
end
puts doors.map.with_index(1){|d,i| "Door #{i} is #{d ? 'open' : 'closed'}."}

Output:

Door 1 is open
Door 2 is closed
Door 3 is closed
Door 4 is open
Door 5 is closed
Door 6 is closed
Door 7 is closed
Door 8 is closed
Door 9 is open
Door 10 is closed
Door 11 is closed
Door 12 is closed
Door 13 is closed
Door 14 is closed
Door 15 is closed
Door 16 is open
Door 17 is closed
Door 18 is closed
Door 19 is closed
Door 20 is closed
Door 21 is closed
Door 22 is closed
Door 23 is closed
Door 24 is closed
Door 25 is open
Door 26 is closed
Door 27 is closed
Door 28 is closed
Door 29 is closed
Door 30 is closed
Door 31 is closed
Door 32 is closed
Door 33 is closed
Door 34 is closed
Door 35 is closed
Door 36 is open
Door 37 is closed
Door 38 is closed
Door 39 is closed
Door 40 is closed
Door 41 is closed
Door 42 is closed
Door 43 is closed
Door 44 is closed
Door 45 is closed
Door 46 is closed
Door 47 is closed
Door 48 is closed
Door 49 is open
Door 50 is closed
Door 51 is closed
Door 52 is closed
Door 53 is closed
Door 54 is closed
Door 55 is closed
Door 56 is closed
Door 57 is closed
Door 58 is closed
Door 59 is closed
Door 60 is closed
Door 61 is closed
Door 62 is closed
Door 63 is closed
Door 64 is open
Door 65 is closed
Door 66 is closed
Door 67 is closed
Door 68 is closed
Door 69 is closed
Door 70 is closed
Door 71 is closed
Door 72 is closed
Door 73 is closed
Door 74 is closed
Door 75 is closed
Door 76 is closed
Door 77 is closed
Door 78 is closed
Door 79 is closed
Door 80 is closed
Door 81 is open
Door 82 is closed
Door 83 is closed
Door 84 is closed
Door 85 is closed
Door 86 is closed
Door 87 is closed
Door 88 is closed
Door 89 is closed
Door 90 is closed
Door 91 is closed
Door 92 is closed
Door 93 is closed
Door 94 is closed
Door 95 is closed
Door 96 is closed
Door 97 is closed
Door 98 is closed
Door 99 is closed
Door 100 is open

Run BASIC

dim doors(100)
print "Open doors ";
for i = 1 to 100 
    for door = i to 100 step i
        doors(door) = (doors(door) <> 1)
        if i = door and doors(door) = 1 then   print i;" ";
    next door
next i

Output:

Open doors 1 4 9 16 25 36 49 64 81 100

Rust

#![feature(inclusive_range_syntax)]
 
fn main() {
    let mut door_open = [false; 100];
    for pass in 1...100 {
        let mut door = pass;
        while door <= 100 {
            door_open[door - 1] = !door_open[door - 1];
            door += pass;
        }
    }
    for (i, &is_open) in door_open.iter().enumerate() {
        println!("Door {} is {}.", i + 1, if is_open {"open"} else {"closed"});
    }
}

Declarative version of above:

#![feature(inclusive_range_syntax)]
 
fn main() {
    let doors = vec![false; 100].iter_mut().enumerate()
                                .map(|(door, door_state)| (1...100).into_iter()
                                                                   .filter(|pass| door % pass == 0)
                                                                   .map(|_| { *door_state = !*door_state; *door_state })
                                                                   .last().unwrap()).collect::<Vec<_>>();
 
    println!("{:?}", doors);
}
 

Optimized version:
(In this case the printing is the bottleneck so this version is not faster than the above one.)

#![feature(inclusive_range_syntax)]
 
fn main() {
    let squares: Vec<_> = (1...10).map(|n| n*n).collect();
    let is_square = |num| squares.binary_search(&num).is_ok();
 
    for i in 1...100 {
        let state = if is_square(i) {"open"} else {"closed"};
        println!("Door {} is {}", i, state);
    }
}

ultra-optimized: ported from Julia version

#![feature(inclusive_range_syntax)]
 
fn main() {
    for i in 1u32...10u32{
        println!("Door {} is open", i.pow(2));
    }
}

S-lang

variable door,
    isOpen = Char_Type [101],
    pass;
 
for (door = 1; door <= 100; door++) {
    isOpen[door] = 0;
}
 
for (pass = 1; pass <= 100; pass++) {
    for (door = pass; door <= 100; door += pass) {
        isOpen[door] = not isOpen[door];
    }
}
 
for (door = 1; door <= 100; door++) {
    if (isOpen[door]) {
        print("Door " + string(door) + ":open");
    } else {
        print("Door " + string(door) + ":close");
    }
}

Salmon

Here's an unoptimized version:

variable open := <<(* --> false)>>;
for (pass; 1; pass <= 100)
    for (door_num; pass; door_num <= 100; pass)
        open[door_num] := !(open[door_num]);;;
iterate (door_num; [1...100])
    print("Door ", door_num, " is ",
          (open[door_num] ? "open.\n" : "closed.\n"));;

And here's an optimized one-line version:

iterate (x; [1...10]) { iterate (y; [(x-1)*(x-1)+1...x*x-1]) { print("Door ", y, " is closed.\n"); }; print("Door ", x*x, " is open.\n"); };

And a shorter optimized one-line version:

variable y:=1;for(x;1;x<101)"Door "~sprint(x)~" is "~(x==y*y?{++y;return"open";}:"closed")!;

SAS

data _null_;
   open=1;
   close=0;
   array Door{100};
   do Pass = 1 to 100;
      do Current = Pass to 100 by Pass;
         if Door{Current} ne open 
            then Door{Current} = open;
            else Door{Current} = close;
      end;
   end;
   NumberOfOpenDoors = sum(of Door{*});
   put "Number of Open Doors:  " NumberOfOpenDoors; 
run;

Scala

for { i <- 1 to 100
      r = 1 to 100 map (i % _ == 0) reduceLeft (_^_)                 
    } println (i +" "+ (if (r) "open" else "closed"))

The map operation maps each door (i) to a boolean sequence of toggles, one for each pass: true toggles, false leaves the same.

The reduceLeft method combines all the toggles sequentially, using the XOR operator.

And then we just need to output the result.

I made a version that optional accepts an argument for the number of doors. It is also a little more a ‘classical’ solution:

 
def openDoors(length : Int = 100) = {
    var isDoorOpen = new Array[Boolean](length)
 
    for (i <- 0 until length) {
        for (j <- i until length by i + 1) {
            isDoorOpen(j) ^= true
        }
    }
    isDoorOpen
}
 
val doorState  = scala.collection.immutable.Map(false -> "closed", true -> "open")
val isDoorOpen = openDoors()
 
for (doorNo <- 0 until isDoorOpen.length) {
    println("Door %d is %s".format(doorNo + 1, doorState(isDoorOpen(doorNo))))
}
 

I created the function openDoors which gives back an array signifying if a door is open and optional accepts an argument for the number of doors. (I like to make things general.) I call the function and use the result to display the status of the doors.

"Optimized" version:

val o = 1 to 10 map (i => i * i)
println("open: " + o)
println("closed: " + (1 to 100 filterNot o.contains))

Sather

class MAIN is
  main is
    pass, door :INT;
    doors :ARRAY{BOOL} := #(100);
    loop 
      doors[0.upto!(99)] := false;
    end;
    pass := 0;
    loop while!(pass < 100);
      door := pass;
      loop while! (door < 100);
        doors[door] := ~doors[door];
	door := door + pass + 1
      end;
      pass := pass + 1;
    end;
    loop
      door := 0.upto!(99);
      #OUT + (door+1) + " " + doors[door] + "\n";
    end;
  end;
end;

Scheme

unoptimized

(define *max-doors* 100)
 
(define (show-doors doors)
  (let door ((i 0)
             (l (vector-length doors)))
    (cond ((= i l) 
           (newline))
          (else 
           (printf "~nDoor ~a is ~a" 
                   (+ i 1) 
                   (if (vector-ref doors i) "open" "closed"))
           (door (+ i 1) l)))))
 
(define (flip-doors doors)
  (define (flip-all i)
    (cond ((> i *max-doors*) doors)
          (else 
           (let flip ((idx (- i 1)))
             (cond ((>= idx *max-doors*) 
                    (flip-all (+ i 1))) 
                   (else 
                    (vector-set! doors idx (not (vector-ref doors idx)))
                    (flip (+ idx i))))))))
  (flip-all 1))
 
(show-doors (flip-doors (make-vector *max-doors* #f)))

optimized

(define (optimised-flip-doors doors)
  (define (flip-all i)
    (cond ((> i (floor (sqrt *max-doors*))) doors)
          (else 
           (vector-set! doors (- (* i i) 1) #t)
           (flip-all (+ i 1)))))
  (flip-all 1))
 
(show-doors (optimised-flip-doors (make-vector *max-doors* #f)))

the 3rd version

(define (N_doors N)
  (define (init)
    (define (str n)
      (if (> n N) '() (cons 0 (str (+ 1 n)))))
    (str 1))
  (define (toggle x str)
    (define (s n lis)
      (define (revert x)
        (if (eq? x 0) 1 0))
      (cond ((null? lis) '())
          ((zero? (remainder n x)) (cons (revert (car lis)) (s (+ n 1) (cdr lis))))
          (else (cons (car lis) (s (+ n 1) (cdr lis))))))
    (s 1 str))
  (define (iterate x lis)
    (if (> x N) lis (iterate (+ x 1) (toggle x lis))))
  (iterate 1 (init)))
(N_doors 100)

Output of the 3rd version: 1 represents open, 0 represents closed.

(1 0 0 1 0 0 0 0 1 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1)

Scilab

Translation of: Octave

doors=zeros(1,100);
for i = 1:100
  for j = i:i:100
    doors(j) = ~doors(j);
  end
end
for i = 1:100
  if ( doors(i) )
    s = "open";
  else
    s = "closed";
  end
  printf("%d %s\n", i, s);
end

Output:

1 open
2 closed
3 closed
4 open
5 closed
6 closed
7 closed
8 closed
9 open
10 closed
11 closed
12 closed
13 closed
14 closed
15 closed
16 open
17 closed
18 closed
19 closed
20 closed
21 closed
22 closed
23 closed
24 closed
25 open
26 closed
27 closed
28 closed
29 closed
30 closed
31 closed
32 closed
33 closed
34 closed
35 closed
36 open
37 closed
38 closed
39 closed
40 closed
41 closed
42 closed
43 closed
44 closed
45 closed
46 closed
47 closed
48 closed
49 open
50 closed
51 closed
52 closed
53 closed
54 closed
55 closed
56 closed
57 closed
58 closed
59 closed
60 closed
61 closed
62 closed
63 closed
64 open
65 closed
66 closed
67 closed
68 closed
69 closed
70 closed
71 closed
72 closed
73 closed
74 closed
75 closed
76 closed
77 closed
78 closed
79 closed
80 closed
81 open
82 closed
83 closed
84 closed
85 closed
86 closed
87 closed
88 closed
89 closed
90 closed
91 closed
92 closed
93 closed
94 closed
95 closed
96 closed
97 closed
98 closed
99 closed
100 open

Scratch

Scratch is a visual programming language. Click the link, then "see inside" to see the code.

https://scratch.mit.edu/projects/168687954/

Output: 100 indications that "Door ___ is _____," where doors with perfect square indices are open and the rest are closed.

Seed7

unoptimized

$ include "seed7_05.s7i";
 
const proc: main is func
  local
    var array boolean: doorOpen is 100 times FALSE;
    var integer: pass is 0;
    var integer: index is 0;
    var array[boolean] string: closedOrOpen is [boolean] ("closed", "open");
  begin
    for pass range 1 to 100 do
      for key index range doorOpen do
        if index rem pass = 0 then
          doorOpen[index] := not doorOpen[index];
        end if;
      end for;
    end for;
    for key index range doorOpen do
      write(index lpad 3 <& " is " <& closedOrOpen[doorOpen[index]] rpad 7);
      if index rem 5 = 0 then
        writeln;
      end if;
    end for;
  end func;

optimized

$ include "seed7_05.s7i";
 
const proc: main is func
  local
    var integer: index is 0;
    var integer: number is 0;
    var array[boolean] string: closedOrOpen is [boolean] ("closed", "open");
  begin
    for index range 1 to 100 do
      number := sqrt(index);
      write(index lpad 3 <& " is " <& closedOrOpen[number**2 = index] rpad 7);
      if index rem 5 = 0 then
        writeln;
      end if;
    end for;
  end func;

Output of both programs:

  1 is open     2 is closed   3 is closed   4 is open     5 is closed 
  6 is closed   7 is closed   8 is closed   9 is open    10 is closed 
 11 is closed  12 is closed  13 is closed  14 is closed  15 is closed 
 16 is open    17 is closed  18 is closed  19 is closed  20 is closed 
 21 is closed  22 is closed  23 is closed  24 is closed  25 is open   
 26 is closed  27 is closed  28 is closed  29 is closed  30 is closed 
 31 is closed  32 is closed  33 is closed  34 is closed  35 is closed 
 36 is open    37 is closed  38 is closed  39 is closed  40 is closed 
 41 is closed  42 is closed  43 is closed  44 is closed  45 is closed 
 46 is closed  47 is closed  48 is closed  49 is open    50 is closed 
 51 is closed  52 is closed  53 is closed  54 is closed  55 is closed 
 56 is closed  57 is closed  58 is closed  59 is closed  60 is closed 
 61 is closed  62 is closed  63 is closed  64 is open    65 is closed 
 66 is closed  67 is closed  68 is closed  69 is closed  70 is closed 
 71 is closed  72 is closed  73 is closed  74 is closed  75 is closed 
 76 is closed  77 is closed  78 is closed  79 is closed  80 is closed 
 81 is open    82 is closed  83 is closed  84 is closed  85 is closed 
 86 is closed  87 is closed  88 is closed  89 is closed  90 is closed 
 91 is closed  92 is closed  93 is closed  94 is closed  95 is closed 
 96 is closed  97 is closed  98 is closed  99 is closed 100 is open   

SequenceL

Unoptimized

 
import <Utilities/Sequence.sl>;
 
main:=
	let
		doors := flipDoors(duplicate(false, 100), 1);
		open[i] := i when doors[i];
	in
		open;
 
flipDoors(doors(1), count) :=
	let
		newDoors[i] := not doors[i] when i mod count = 0 else doors[i];
	in
		doors when count >= 100 else flipDoors(newDoors, count + 1);
 

Optimized

 
main := flipDoors([1], 2);
 
flipDoors(openDoors(1), i) :=
	openDoors when i * i >= 100 else flipDoors(openDoors ++ [i * i], i + 1);
 

SETL

Unoptimized

program hundred_doors;
 
const toggle := {['open', 'closed'], ['closed', 'open']};
 
doorStates := ['closed'] * 100;
 
(for interval in [1..100])
  doorStates := [if i mod interval = 0 then
                    toggle(prevState) else
                    prevState end:
                 prevState = doorStates(i)];
end;
 
(for finalState = doorStates(i))
  print('door', i, 'is', finalState);
end;
 
end program;

If 'open' weren't a reserved word, we could omit the single quotes around it.

Optimized Exploits the fact that squares are separated by successive odd numbers. Use array replication to insert the correct number of closed doors in between the open ones.

program hundred_doors;
 
doorStates := (+/ [['closed'] * oddNum with 'open': oddNum in [1,3..17]]);
 
(for finalState = doorStates(i))
  print('door', i, 'is', finalState);
end;
 
end program;

Sidef

Unoptimized

var doors = []
 
{ |pass|
    { |i|
        if (pass `divides` i) {
            doors[i] := false -> not!
        }
    } << 1..100
} << 1..100
 
{ |i|
    say ("Door %3d is %s" % (i, doors[i] ? 'open' : 'closed'))
} << 1..100

Optimized

{ |i|
    "Door %3d is %s\n".printf(i, <closed open>[i.is_sqr])
} << 1..100

Simula

BEGIN
    INTEGER I, PASS;
    BOOLEAN ARRAY DOORS(1:100);
 
    FOR I := 1 STEP 1 UNTIL 100 DO
        DOORS(I) := FALSE;
 
    FOR PASS := 1 STEP 1 UNTIL 100 DO
        FOR I := PASS STEP PASS UNTIL 100 DO
            DOORS(I) := NOT DOORS(I);
 
    FOR I := 1 STEP 1 UNTIL 100 DO
        IF DOORS(I)
          THEN BEGIN OUTTEXT("DOOR "); OUTINT(I,0); OUTTEXT(" IS OPEN");   OUTIMAGE END
 
END.
 

Output:

DOOR 1 IS OPEN
DOOR 4 IS OPEN
DOOR 9 IS OPEN
DOOR 16 IS OPEN
DOOR 25 IS OPEN
DOOR 36 IS OPEN
DOOR 49 IS OPEN
DOOR 64 IS OPEN
DOOR 81 IS OPEN
DOOR 100 IS OPEN

Slate

Unoptimized

define: #a -> (Array newSize: 100).
a infect: [| :_ | False].
 
a keysDo: [| :pass |
  pass to: a indexLast by: pass do: [| :door |
    a at: door infect: #not `er]].
 
a keysAndValuesDo: [| :door :isOpen |
  inform: 'door #' ; door ; ' is ' ; (isOpen ifTrue: ['open'] ifFalse: ['closed'])].

Optimized

define: #a -> (Array newSize: 100).
a infect: [| :_ | False].
 
0 below: 10 do: [| :door | a at: door squared put: True].
a keysAndValuesDo: [| :door :isOpen |
  inform: 'door #' ; door ; ' is ' ; (isOpen ifTrue: ['open'] ifFalse: ['closed'])].

Smalltalk

Works with: GNU Smalltalk

Unoptimized

|a|
a := Array new: 100 .
1 to: 100 do: [ :i | a at: i put: false ].
 
1 to: 100 do: [ :pass |
  pass to: 100 by: pass do: [ :door |
    a at: door put: (a at: door) not .
  ]
].
 
"output"
1 to: 100 do: [ :door |
   ( 'door #%1 is %2' %
     { door . (a at: door) ifTrue: [ 'open' ] ifFalse: [ 'closed' ] } ) displayNl
]

Optimized

|a|
a := (1 to: 100) collect: [ :x | false ].
1 to: 10 do: [ :i | a at: (i squared) put: true ].
1 to: 100 do: [ :i |
   ( 'door #%1 is %2' % { i . 
           (a at: i) ifTrue: [ 'open' ] 
                     ifFalse: [ 'closed' ] }
   ) displayNl
]

Works with: Squeak Smalltalk

Unoptimized, using Morphs

 
| m w h smh smw delay closedDoor border subMorphList |
 
closedDoor := Color black.
border := Color veryLightGray.
delay := Delay forMilliseconds: 50.
w := World bounds corner x.
h := (World bounds corner y) / 2.
smw := w/100.
smh := h/2.
 
m := BorderedMorph new position: 0@h.
m height: smh; width: w; borderColor: border.
m color: Color veryLightGray.
 
1 to: 100 do: [ :pos || sm |
	sm := BorderedMorph new height: smh ; width: smw ; 
		borderColor: border; color: closedDoor; 
		position: (smw*pos)@h.
	m addMorph: sm asElementNumber: pos].
 
m openInWorld.
delay wait.
subMorphList := m submorphs.
"display every step"
[1 to: 100 do: [ :step |
	step to: 100 by: step do: [ :pos | | subMorph |
		subMorph := subMorphList at: pos.
		subMorph color: subMorph color negated.
		delay wait]]] fork. 
 

smart BASIC

-- Scott A. Rossell, 12-16-16

x=1!y=3!z=0
PRINT "Open doors: ";x;" ";
DO
    z=x+y
    PRINT z;" ";
    x=z
    y=y+2
UNTIL z>=100
END

SNOBOL4

unoptimized

 
		DEFINE('PASS(A,I),O')		:(PASS.END)
PASS		O = 0
PASS.LOOP	O = O + I
		EQ(A<O>,1)			:S(PASS.1)F(PASS.0)
PASS.0		A<O> = 1			:S(PASS.LOOP)F(RETURN)
PASS.1		A<O> = 0			:S(PASS.LOOP)F(RETURN)
PASS.END
 
MAIN		D = ARRAY(100,0)
		I = 0
 
MAIN.LOOP	I = LE(I,100) I + 1		:F(OUTPUT)
		PASS(D,I)			:(MAIN.LOOP)
 
OUTPUT		I = 1 ; OPEN = 'Opened doors are: '
OUTPUT.LOOP	OPEN = OPEN EQ(D<I>,1) " " I
		I = LE(I,100) I + 1		:S(OUTPUT.LOOP)F(OUTPUT.WRITE)
OUTPUT.WRITE	OUTPUT = OPEN
 
END
 

A run of this using CSNOBOL4 looks like this:

$ snobol4 100doors.sno 
The Macro Implementation of SNOBOL4 in C (CSNOBOL4) Version 1.3+
    by Philip L. Budne, January 23, 2011
SNOBOL4 (Version 3.11, May 19, 1975)
    Bell Telephone Laboratories, Incorporated

No errors detected in source program

Opened doors are:  1 4 9 16 25 36 49 64 81 100
Normal termination at level 0
100doors.sno:18: Last statement executed was 19

(There are command flags to remove the header and the summary, but these have been left in to keep the original SNOBOL4 experience intact.)

optimized

 
MAIN		D = ARRAY(100,0)
		I = 1
 
MAIN.LOOP	LE(I, 10)			:F(OUTPUT)
		D<I ** 2> = 1		
		I = I + 1			:(MAIN.LOOP)
 
OUTPUT		I = 1 ; O = 'Opened doors are: '
OUTPUT.LOOP	O = O EQ(D<I>,1) " " I
		I = LE(I,100) I + 1		:S(OUTPUT.LOOP)F(OUTPUT.WRITE)
OUTPUT.WRITE	OUTPUT = O
END
 

The output of this version is almost identical to the above.

Sparkling

unoptimized

/* declare the variables */
var isOpen = {};
var pass, door;
 
/* initialize the doors */
for door = 0; door < 100; door++ {
	isOpen[door] = true;
}
 
/* do the 99 remaining passes */
for pass = 1; pass < 100; ++pass {
	for door = pass; door < 100; door += pass+1 {
  		isOpen[door] = !isOpen[door];
	}
}
 
/* print the results */
var states = { true: "open", false: "closed" };
for door = 0; door < 100; door++ {
	printf("Door #%d is %s.\n", door+1, states[isOpen[door]]);
}

optimized

/* declare the variables */
var door_sqrt = 1;
var door;
 
/* print the perfect square doors as open */
for door = 0; door < 100; door++ {
	if (door_sqrt*door_sqrt == door+1) {
		printf("Door #%d is open.\n", door+1);
		door_sqrt ++;
	} else {
		printf("Door #%d is closed.\n", door+1);
	}
}

SQL

optimized

 
DECLARE	@sqr INT,
		@i INT,
		@door INT;
 
SELECT @sqr =1,
	@i = 3,
	@door = 1;	
 
WHILE(@door <=100)
BEGIN
	IF(@door = @sqr)
	BEGIN
		PRINT 'Door ' + RTRIM(CAST(@door AS CHAR)) + ' is open.';
		SET @sqr= @sqr+@i;
		SET @i=@i+2;
	END
	ELSE
	BEGIN
		PRINT 'Door ' + RTRIM(CONVERT(CHAR,@door)) + ' is closed.';
	END
SET @door = @door + 1
END
 
 

Standard ML

 
datatype Door = Closed | Opened
 
fun toggle Closed = Opened
  | toggle Opened = Closed
 
fun pass (steps, doors) = List.mapi (fn (k, door) => if (k+1) mod steps = 0 then toggle door else door) doors
 
(* [1..n] *)
fun runs n = List.tabulate (n, fn k => k+1)
 
fun run n =
	let
		val initialdoors = List.tabulate (n, fn _ => Closed)
		val runs = runs n
	in 
		foldl pass initialdoors runs
	end
 
fun opened_doors n = List.mapPartiali (fn (k, Closed) => NONE | (k, Opened) => SOME (k+1)) (run n)
 

Output:

- opened_doors 100;
val it = [1,4,9,16,25,36,49,64,81,100] : int list

Stata

clear all
set obs 100
gen doors=0
gen index=_n
forvalues i=1/100 {
	quietly replace doors=1-doors if mod(_n,`i')==0
}
list index if doors
 
     +-------+
     | index |
     |-------|
  1. |     1 |
  4. |     4 |
  9. |     9 |
 16. |    16 |
 25. |    25 |
     |-------|
 36. |    36 |
 49. |    49 |
 64. |    64 |
 81. |    81 |
100. |   100 |
     +-------+

SuperCollider

(
var n = 100, doors = false ! n;
var pass = { |j| (0, j .. n-1).do { |i| doors[i] = doors[i].not } };
(1..n-1).do(pass);
doors.selectIndices { |open| open }; // all are closed except [ 0, 1, 4, 9, 16, 25, 36, 49, 64, 81 ]
)

Swift

unoptimized

/* declare enum to identify the state of a door */
enum DoorState : String {
    case Opened = "Opened"
    case Closed = "Closed"
}
 
/* declare list of doors state and initialize them */
var doorsStateList = [DoorState](count: 100, repeatedValue: DoorState.Closed)
 
/* do the 100 passes */
for i in 1...100 {
    /* map on a strideTo instance to only visit the needed doors on each iteration */
    map(stride(from: i - 1, to: 100, by: i)) {
        doorsStateList[$0] = doorsStateList[$0] == .Opened ? .Closed : .Opened
    }
}
 
/* print the results */
for (index, item) in enumerate(doorsStateList) {
    println("Door \(index+1) is \(item.rawValue)")
}

optimized

/* declare enum to identify the state of a door */
enum DoorState : String {
    case Opened = "Opened"
    case Closed = "Closed"
}
 
/* declare list of doors state and initialize them */
var doorsStateList = [DoorState](count: 100, repeatedValue: DoorState.Closed)
 
/* set i^2 doors to opened */
var i = 1
do {
    doorsStateList[(i*i)-1] = DoorState.Opened
    ++i
} while (i*i) <= doorsStateList.count
 
/* print the results */
for (index, item) in enumerate(doorsStateList) {
    println("Door \(index+1) is \(item.rawValue)")
}

Tcl

unoptimized

package require Tcl 8.5
set n 100
set doors [concat - [lrepeat $n 0]]
for {set step 1} {$step <= $n} {incr step} {
    for {set i $step} {$i <= $n} {incr i $step} {
        lset doors $i [expr { ! [lindex $doors $i]}]
    }
}
for {set i 1} {$i <= $n} {incr i} {
    puts [format "door %d is %s" $i [expr {[lindex $doors $i] ? "open" : "closed"}]]
}

optimized

package require Tcl 8.5
set doors [lrepeat [expr {$n + 1}] closed]
for {set i 1} {$i <= sqrt($n)} {incr i} {
    lset doors [expr {$i ** 2}] open
}
for {set i 1} {$i <= $n} {incr i} {
    puts [format "door %d is %s" $i [lindex $doors $i]]
}

graphical

Library: Tk

Inspired by the E solution, here's a visual representation

package require Tcl 8.5
package require Tk
 
array set door_status {}
 
# create the gui
set doors [list x]
for {set i 0} {$i < 10} {incr i} {
    for {set j 0} {$j < 10} {incr j} {
        set k [expr {1 + $j + 10*$i}]
        lappend doors [radiobutton .d_$k -text $k -variable door_status($k) \
                         -indicatoron no -offrelief flat -width 3 -value open]
        grid [lindex $doors $k] -column $j -row $i
    }
}
 
# create the controls
button .start -command go -text Start
label .i_label -text " door:"
entry .i -textvariable i -width 4
label .step_label -text " step:"
entry .step -textvariable step -width 4
grid .start - .i_label - .i - .step_label - .step - -row $i
grid configure .start -sticky ew
grid configure .i_label .step_label -sticky e
grid configure .i .step -sticky w
 
proc go {} {
    global doors door_status i step
 
    # initialize the door_status (all closed)
    for {set d 1} {$d <= 100} {incr d} {
        set door_status($d) closed
    }
 
    # now, begin opening and closing
    for {set step 1} {$step <= 100} {incr step} {
        for {set i 1} {$i <= 100} {incr i} {
            if {$i % $step == 0} {
                [lindex $doors $i] [expr {$door_status($i) eq "open" ? "deselect" : "select"}]
                update
                after 50
            }
        }
    }
}

TI-83 BASIC

Naive

seq(0,X,1,100
For(X,1,100
0 or Ans-not(fPart(cumSum(1 or Ans)/A
End
Pause Ans

A^-1cumsum(1 or Ans should be able to replace cumsum(1 or Ans)/A (saving a byte because of the unnecessary closing parenthesis) but it falls victim to a rounding error that causes X^(-1)*X to be stored as 0.99999999999999... (although it's still displayed as the original X). When the fPart( [fractional part] command evaluates this, it returns .999999999, which not( turns to 0 (meaning a closed door). Regular division, as shown, isn't prone to this.

Optimized

Pause not(fPart(√(seq(X,X,1,100

TI-89 BASIC

Define doors(fast) = Func
  Local doors,i,j
  seq(false,x,1,100) ? doors
  If fast Then
    For i,1,10,1
      true ? doors[i^2]
    EndFor
  Else
    For i,1,100,1
      For j,i,100,i
        not doors[j] ? doors[j]
      EndFor
    EndFor
  EndIf
  Return doors
EndFunc

TorqueScript

for(%steps = 1; %a <= 100; %a++)
	for(%current = %steps; %current <= 100; %current += %steps)
		%door[%current] = !%door[%current];
for(%a = 1; %a <= 100; %a++)
	echo("Door #" @ %a @ " is" SPC %door[%current] ? "Open" : "Closed" @ ".");

TSE SAL

 
 
// library: math: get: task: door: open: close100 <description></description> <version control></version control> <version>1.0.0.0.11</version> <version control></version control> (filenamemacro=getmaocl.s) [<Program>] [<Research>] [kn, ri, mo, 31-12-2012 22:03:16]
PROC PROCMathGetTaskDoorOpenClose( INTEGER doorMaxI, INTEGER passMaxI )
 // e.g. PROC Main()
 // e.g.  PROCMathGetTaskDoorOpenClose( 100, 100 )
 // e.g. END
 // e.g.
 // e.g. <F12> Main()
 //
 // ===
 //
 // The output will be:
 //
 // door 1 is open
 // door 4 is open
 // door 9 is open
 // door 16 is open
 // door 25 is open
 // door 36 is open
 // door 49 is open
 // door 64 is open
 // door 81 is open
 // door 100 is open
 // all other doors are closed
 //
 // ===
 //
 INTEGER passMinI = 1
 INTEGER passI = 0
 //
 INTEGER doorminI = 1
 INTEGER doorI = 0
 //
 STRING s[255] = ""
 //
 INTEGER bufferI = 0
 //
 PushPosition()
 bufferI = CreateTempBuffer()
 PopPosition()
 //
 FOR doorI = doorMinI TO doorMaxI
  //
  SetGlobalInt( Format( "doorsI", doorI ), 0 )
  //
 ENDFOR
 //
 FOR passI = passMinI TO passMaxI
  //
  doorI = passI - passI
  //
  REPEAT
   //
   doorI = doorI + passI
   //
   SetGlobalInt( Format( "doorsI", doorI ), NOT( GetGlobalInt( Format( "doorsI", doorI ) ) ) )
   //
  UNTIL ( doorI >= doorMaxI )
  //
 ENDFOR
 //
 FOR doorI = doorMinI TO doorMaxI
  //
  IF ( GetGlobalInt( Format( "doorsI", doorI ) ) > 0 )
   //
   s = "open"
   //
   AddLine( Format( "door", " ", doorI, " ", "is", " ", s ), bufferI )
   //
  ELSE
   //
   s = "closed"
   //
  ENDIF
  //
 ENDFOR
 //
 AddLine( "all other doors are closed", bufferI )
 //
 GotoBufferId( bufferI )
 //
END
 
PROC Main()
 PROCMathGetTaskDoorOpenClose( 100, 100 )
END
 
 

True BASIC

 
! Optimized solution with True BASIC
 
OPTION NOLET
x = 1 
y = 3 
z = 0
PRINT STR$(x) & " Open"
DO UNTIL z >= 100
z = x + y
PRINT STR$(z) & " Open"
x = z 
y = y + 2
LOOP
 
END
 

TUSCRIPT

 
$$ MODE TUSCRIPT
DICT doors create
COMPILE
LOOP door=1,100
 LOOP pass=1,100
 SET go=MOD (door,pass)
 DICT doors lookup door,num,cnt,status
   IF (num==0) THEN
     SET status="open"
     DICT doors add  door,num,cnt,status
   ELSE
    IF (go==0) THEN
       IF (status=="closed") THEN
         SET status="open"
       ELSE
         SET status="closed"
       ENDIF
     DICT doors update door,num,cnt,status
     ENDIF
   ENDIF
 ENDLOOP
ENDLOOP
ENDCOMPILE
DICT doors unload door,num,cnt,status
 

Output (variable status):

 status       = *
           1 = open
           2 = closed
           3 = closed
           4 = open
           5 = closed
           6 = closed
           7 = closed
           8 = closed
           9 = open
          10 = closed
          11 = closed
          12 = closed
          13 = closed
          14 = closed
          15 = closed
          16 = open
          17 = closed
          18 = closed
          19 = closed
          20 = closed
          21 = closed
          22 = closed
          23 = closed
          24 = closed
          25 = open
          26 = closed
          27 = closed
          28 = closed
          29 = closed
          30 = closed
          31 = closed
          32 = closed
          33 = closed
          34 = closed
          35 = closed
          36 = open
          37 = closed
          38 = closed
          39 = closed
          40 = closed
          41 = closed
          42 = closed
          43 = closed
          44 = closed
          45 = closed
          46 = closed
          47 = closed
          48 = closed
          49 = open
          50 = closed
          51 = closed
          52 = closed
          53 = closed
          54 = closed
          55 = closed
          56 = closed
          57 = closed
          58 = closed
          59 = closed
          60 = closed
          61 = closed
          62 = closed
          63 = closed
          64 = open
          65 = closed
          66 = closed
          67 = closed
          68 = closed
          69 = closed
          70 = closed
          71 = closed
          72 = closed
          73 = closed
          74 = closed
          75 = closed
          76 = closed
          77 = closed
          78 = closed
          79 = closed
          80 = closed
          81 = open
          82 = closed
          83 = closed
          84 = closed
          85 = closed
          86 = closed
          87 = closed
          88 = closed
          89 = closed
          90 = closed
          91 = closed
          92 = closed
          93 = closed
          94 = closed
          95 = closed
          96 = closed
          97 = closed
          98 = closed
          99 = closed
         100 = open

TXR

(defun hyaku-mai-tobira ()
  (let ((doors (vector 100)))
    (each ((i (range 0 99)))
      (each ((j (range i 99 (+ i 1))))
        (flip [doors j])))
    doors))
 
(each ((counter (range 1))
       (door (hyaku-mai-tobira)))
  (put-line `door @counter is @(if door "open" "closed")`))

uBasic/4tH

Translation of: BBC BASIC

Deliberately unoptimized.

FOR p = 1 TO 100
  FOR d = p TO 100 STEP p
    @(d) = @(d) = 0
  NEXT d
NEXT p
 
FOR d= 1 TO 100
  IF @(d) PRINT "Door ";d;" is open"
NEXT d

Uniface

unoptimized

Works with: Uniface 9.6

 
entry LP_DO_IT
 
    variables
        string  V_DOORS
        boolean V_DOOR_STATE
        string  V_DOOR_STATE_S
        numeric V_IDX
        numeric V_TOTAL_DOORS
        string  V_DOOR_STATE_LIST
        numeric V_LOOP_COUNT
    endvariables
 
    V_TOTAL_DOORS = 100
    putitem V_DOORS, V_TOTAL_DOORS, 0
 
    V_DOORS = $replace (V_DOORS, 1, "·;", "·;0", -1)
 
    putitem/id V_DOOR_STATE_LIST, "1", "Open"
    putitem/id V_DOOR_STATE_LIST, "0", "Close"
 
    V_LOOP_COUNT = 1
    while (V_LOOP_COUNT <= V_TOTAL_DOORS)
        V_IDX = 0
        V_IDX = V_IDX + V_LOOP_COUNT
 
        getitem V_DOOR_STATE, V_DOORS, V_IDX
        while (V_IDX <= V_TOTAL_DOORS)
 
            V_DOOR_STATE = !V_DOOR_STATE
            getitem/id V_DOOR_STATE_S, V_DOOR_STATE_LIST, $number(V_DOOR_STATE)
            putitem V_DOORS, V_IDX, V_DOOR_STATE
 
            V_IDX = V_IDX + V_LOOP_COUNT
            getitem V_DOOR_STATE, V_DOORS, V_IDX
        endwhile
 
        V_LOOP_COUNT = V_LOOP_COUNT + 1
 
    endwhile
 
    V_IDX = 1
    getitem V_DOOR_STATE, V_DOORS, V_IDX
    while (V_IDX <= V_TOTAL_DOORS)
        getitem/id V_DOOR_STATE_S, V_DOOR_STATE_LIST, $number(V_DOOR_STATE)
        if (V_DOOR_STATE)
            putmess "Door %%V_IDX%%% is finally %%V_DOOR_STATE_S%%%"
        endif
 
        V_IDX = V_IDX + 1
        getitem V_DOOR_STATE, V_DOORS, V_IDX
    endwhile
 
end ; LP_DO_IT
 
 

Output:

Door 1 is finally Open
Door 4 is finally Open
Door 9 is finally Open
Door 16 is finally Open
Door 25 is finally Open
Door 36 is finally Open
Door 49 is finally Open
Door 64 is finally Open
Door 81 is finally Open
Door 100 is finally Open

UNIX Shell

Works with: Bourne Again SHell

#! /bin/bash
 
declare -a doors
for((i=1; i <= 100; i++)); do
    doors[$i]=0
done
 
for((i=1; i <= 100; i++)); do
    for((j=i; j <= 100; j += i)); do
	echo $i $j
	doors[$j]=$(( doors[j] ^ 1 ))
    done
done
 
for((i=1; i <= 100; i++)); do
    if [[ ${doors[$i]} -eq 0 ]]; then
	op="closed"
    else
	op="open"
    fi
    echo $i $op
done

Optimised version

#!/bin/bash
 
for i in {1..100}; do
  door[$i*$i]=1
  [ -z ${door[$i]} ] && echo "$i closed" || echo "$i open"
done

Ursa

 
#
# 100 doors
#
 
decl int i j
decl boolean<> doors
 
# append 101 boolean values to doors stream
for (set i 0) (or (< i 100) (= i 100)) (inc i)
        append false doors
end for
 
# loop through, opening and closing doors
for (set i 1) (or (< i 100) (= i 100)) (inc i)
        for (set j i) (or (< j 100) (= j 100)) (inc j)
                if (= (mod j i) 0)
                        set doors<j> (not doors<j>)
                end if
        end for
end for
 
# loop through and output which doors are open
for (set i 1) (or (< i 100) (= i 100)) (inc i)
        out "Door " i ": " console
        if doors<i>
                out "open" endl console
        else
                out "closed" endl console
        end if
end if
 

Ursala

The doors are represented as a list of 100 booleans initialized to false. The pass function takes a number and a door list to a door list with doors toggled at indices that are multiples of the number. The main program folds the pass function (to the right) over the list of pass numbers from 100 down to 1, numbers the result, and filters out the numbers of the open doors.

#import std
#import nat
 
doors = 0!* iota 100
 
pass("n","d") = remainder\"n"?l(~&r,not ~&r)* num "d"
 
#cast %nL
 
main = ~&rFlS num pass=>doors nrange(100,1)

optimized version:

#import nat
 
#cast %nL
 
main = product*tiiXS iota10

output:

<1,4,9,16,25,36,49,64,81>

Vala

Unoptimized

int main() {
	bool doors_open[101];
	for(int i = 1; i < doors_open.length; i++) {
		for(int j = 1; i*j < doors_open.length; j++) {
			doors_open[i*j] = !doors_open[i*j];
		}
		stdout.printf("%d: %s\n", i, (doors_open[i] ? "open" : "closed"));
	}
	return 0;
}

Output:

1: open
2: closed
3: closed
4: open
5: closed
6: closed
7: closed
8: closed
9: open
10: closed
11: closed
...

Optimized

int main() {
	int i = 1;
	while(i*i <= 100) {
		stdout.printf("${i*i} open\n");
		i++;
	}
	return 0;
}

Output:

1 open
4 open
9 open
16 open
25 open
36 open
49 open
64 open
81 open
100 open

VBA

 
Sub Rosetta_100Doors()
Dim Door(100) As Boolean, i As Integer, j As Integer
For i = 1 To 100 Step 1
    For j = i To 100 Step i
        Door(j) = Not Door(j)
    Next j
    If Door(i) = True Then
        Debug.Print "Door " & i & " is Open"
    Else
        Debug.Print "Door " & i & " is Closed"
    End If
Next i
End Sub
<!-- /lang -->
 
*** USE THIS ONE, SEE COMMENTED LINES, DONT KNOW WHY EVERYBODY FOLLOWED OTHERS ANSWERS AND CODED THE PROBLEM DIFFERENTLY ***
*** ALWAYS USE AND TEST A READABLE, EASY TO COMPREHEND CODING BEFORE 'OPTIMIZING' YOUR CODE AND TEST THE 'OPTIMIZED' CODE AGAINST THE 'READABLE' ONE.
Panikkos Savvides.
 
 
Sub Rosetta_100Doors2()
Dim Door(100) As Boolean, i As Integer, j As Integer
Dim strAns As String
' There are 100 doors in a row that are all initially closed.
' You make 100 passes by the doors.
For j = 1 To 100
    ' The first time through, visit every door and toggle the door
    ' (if the door is closed, open it; if it is open, close it).
    For i = 1 To 100 Step 1
      Door(i) = Not Door(i)
    Next i
    ' The second time, only visit every 2nd door (door #2, #4, #6, ...), and toggle it.
    For i = 2 To 100 Step 2
      Door(i) = Not Door(i)
    Next i
    ' The third time, visit every 3rd door (door #3, #6, #9, ...), etc, until you only visit the 100th door.
    For i = 3 To 100 Step 3
      Door(i) = Not Door(i)
    Next i
Next j
 
For j = 1 To 100
    If Door(j) = True Then
        strAns = j & strAns & ", "
    End If
Next j
 
If Right(strAns, 2) = ", " Then strAns = Left(strAns, Len(strAns) - 2)
If Len(strAns) = 0 Then strAns = "0"
Debug.Print "Doors [" & strAns & "] are open, the rest are closed."
' Doors [0] are open, the rest are closed., AKA ZERO DOORS OPEN
End Sub
 

VBScript

Works with: Windows Script Host version 5.7

Unoptimized

Dim doorIsOpen(100), pass, currentDoor, text
 
For currentDoor = 0 To 99
	doorIsOpen(currentDoor) = False
Next
 
For pass = 0 To 99
	For currentDoor = pass To 99 Step pass + 1
		doorIsOpen(currentDoor) = Not doorIsOpen(currentDoor)
	Next
Next
 
For currentDoor = 0 To 99
	text = "Door #" & currentDoor + 1 & " is "
	If doorIsOpen(currentDoor) Then
		text = text & "open."
	Else
		text = text & "closed."
	End If
	WScript.Echo(text)
Next

Vedit macro language

Unoptimized This implementation uses a free edit buffer as data array and for displaying the results.
A closed door is represented by a character '-' and an open door by character 'O'.

Buf_Switch(Buf_Free)
Ins_Char('-', COUNT, 100)                      // All doors closed
for (#1 = 1; #1 <= 100; #1++) {
    for (#2 = #1; #2 <= 100; #2 += #1) {
        Goto_Col(#2)
        Ins_Char((Cur_Char^0x62), OVERWRITE)   // Toggle between '-' and 'O'
    }
}

Optimized

Buf_Switch(Buf_Free)
Ins_Char('-', COUNT, 100)
for (#1=1; #1 <= 10; #1++) {
    Goto_Col(#1*#1)
    Ins_Char('O', OVERWRITE)
}

Output:

O--O----O------O--------O----------O------------O--------------O----------------O------------------O

VHDL

unoptimized

library IEEE;
use IEEE.STD_LOGIC_1164.ALL;
 
entity DOORS is
	port (CLK: in std_logic; OUTPUT: out std_logic_vector(1 to 100));
end DOORS;
 
architecture Behavioral of DOORS is
begin
	process (CLK)
	variable TEMP: std_logic_vector(1 to 100);
	begin
		--setup closed doors
		TEMP := (others => '0');
 
		--looping through
		for i in 1 to TEMP'length loop
			for j in i to TEMP'length loop
				if (j mod i) = 0 then
					TEMP(j) := not TEMP(j);
				end if;
			end loop;
		end loop;
 
		--assign output
		OUTPUT <= TEMP;
	end process;
end Behavioral;
 

unoptimized and synthesizable

LIBRARY ieee;
USE ieee.std_logic_1164.all;
 
 
entity doors is
  port (
        clk   : in std_logic;
        reset : in std_logic;
        door  : buffer std_logic_vector(1 to 100)
        );
end entity doors;
 
 
architecture rtl of doors is
  signal step : integer range 1 to 101;
  signal addr : integer range 1 to 201;
begin
  proc_step: process(clk, reset)
  begin
    if reset = '1' then
      step  <= 1;
      addr  <= 1;
      door <= (others => '0');
    elsif rising_edge(clk) then
      if addr <= 100 then
        door(addr) <= not door(addr);
        addr <= addr + step;
      elsif step <= 100 then
        addr <= step + 1;
        step <= step + 1;
      end if;
    end if;
  end process;
end;

The synthesis requires 116 FFs plus combinatorial logic.

The result is stable after 581 clock cycles.

Visual Basic .NET

Works with: Visual Basic .NET version 9.0+

unoptimized

Module Module1
 
   Sub Main()
       Dim doors(100) As Boolean 'Door 1 is at index 0
 
       For pass = 1 To 100
           For door = pass - 1 To 99 Step pass
               doors(door) = Not doors(door)
           Next
       Next
 
       For door = 0 To 99
           Console.WriteLine("Door # " & (door + 1) & " is " & If(doors(door), "Open", "Closed"))
       Next
 
       Console.ReadLine()
   End Sub
 
End Module

optimized

Module Module1
 
   Sub Main()
       Dim doors(100) As Boolean 'Door 1 is at index 0
 
       For i = 1 To 10
           doors(i ^ 2 - 1) = True
       Next
 
       For door = 0 To 99
           Console.WriteLine("Door # " & (door + 1) & " is " & If(doors(door), "Open", "Closed"))
       Next
 
       Console.ReadLine()
   End Sub
 
End Module

Wart

def (doors n)
  let door (table)
    for step 1 (step <= n) ++step
      for j 0 (j < n) (j <- j+step)
        zap! not door.j
 
    for j 0 (j < n) ++j
      when door.j
        pr j
        pr " "

Wortel

Translation of: JavaScript

; unoptimized
+^[
  @var doors []
 
  @for i rangei [1 100]
    @for j rangei [i 100 i]
      :[email protected] `j doors
 
  @for i rangei [1 100]
    @if `i doors
      !console.log "door {i} is open"
]
; optimized, map square over 1 to 10
!*^@sq @to 10

Wrapl

Unoptimized

MOD Doors;
 
IMP Agg.Table;
IMP Std.String;
IMP IO.Terminal USE Out;
 
VAR door <- {}; EVERY door[1:to(100), "closed"];
 
DEF toggle(num) door[num] <- door[num] = "open" => "closed" // "open";
 
EVERY WITH pass <- 1:to(100), num <- pass:to(100, pass) DO toggle(num);
 
Out:write('Doors {door @ String.T}.');
 
END Doors.

Optimized

MOD Doors;
 
IMP IO.Terminal USE Out;
 
DEF open <- ALL 1:to(100) ^ 2 \ $ <= 100;
DEF closed <- ALL 1:to(100) \ NOT $ IN open;
 
Out:write('Doors {open} are open.\n');
Out:write('Doors {closed} are closed.\n');
 
END Doors.

Wren

Unoptimized

 
var doors = [true] * 100
for (i in 1..100) {
    var j = i
    while(j < 100) {
        doors[j] = !doors[j]
        j = j + i + 1
    }
}
 
for (i in 0...100) {
    if (doors[i]) System.print(i + 1)
}
 

Optimized

 
var door = 1
var increment = 3
while(door <= 100) {
    System.print(door)
    door = door + increment
    increment = increment + 2
}
 

X86 Assembly

 
; linux x86_64
 
section .data
open: db "open", 10
closed: db "closed", 10
 
section .bss
doors resb 101
 
section .text
 
global _start
 
_start:
mov rax, 1
  mov bl, 0
  zeroset_door:
    mov [doors + rax], bl
    inc rax
    cmp rax, 101
    jl zeroset_door
 
  mov rax, 0
  set_doors:
    inc rax
    cmp rax, 101
    je display_result
    mov rbx, 0
 
    make_pass:
      add rbx, rax
      cmp rbx, 101
      jge set_doors
      not byte [doors + rbx]
      jmp make_pass
 
  display_result:
    mov rbx, 0
    display_door:
      inc rbx
      cmp rbx, 101
      je exit
      cmp byte [doors + rbx], 0
      je print_closed
      jmp print_open
 
  print_open:
    mov rax, 1
    mov rdi, 1
    mov rsi, open
    mov rdx, 5
    syscall
    jmp display_door
 
  print_closed:
    mov rax, 1
    mov rdi, 1
    mov rsi, closed
    mov rdx, 7
    syscall
    jmp display_door
 
  exit:
    mov rax, 60
    mov rdi, 0
    syscall
 
 

XPL0

include c:\cxpl\codes;          \intrinsic 'code' declarations
int     Door(100);              \You have 100 doors in a row
define  Open, Closed;
int     D, Pass, Step;
 
[for D:= 0 to 100-1 do          \that are all initially closed
        Door(D):= Closed;
 
Step:= 1;                       \The first time through, you visit every door
for Pass:= 1 to 100 do          \You make 100 passes by the doors
        [D:= Step-1;
        repeat  \if the door is closed, you open it; if it is open, you close it
                if Door(D)=Closed then Door(D):= Open else Door(D):= Closed;
                D:= D+Step;
        until   D>=100;
        Step:= Step+1;          \The second time you only visit every 2nd door
        ];                      \The third time, every 3rd door
                                \until you only visit the 100th door
\What state are the doors in after the last pass?
Text(0, "Open: ");              \Which are open?
for D:= 0 to 100-1 do 
        if Door(D)=Open then [IntOut(0, D+1); ChOut(0,^ )];
CrLf(0);
 
Text(0, "Closed: ");            \Which are closed?
for D:= 0 to 100-1 do 
        if Door(D)=Closed then [IntOut(0, D+1); ChOut(0,^ )];
CrLf(0);
 
\Optimized: The only doors that remain open are those that are perfect squares
Text(0, "Open: ");
D:= 1;
repeat  IntOut(0, D*D); ChOut(0,^ );
        D:= D+1;
until   D*D>100;
CrLf(0);
]

XSLT 1.0

With input document ...

<hallway>
  <door number="1">closed</door>
  <door number="2">closed</door>
  <door number="3">closed</door>
  <door number="4">closed</door>
  ... etc ...
  <door number="100">closed</door>
<hallway>

... visually representing the initial state of the hallway, apply the following XSLT 1.0 style-sheet...

<xsl:stylesheet version="1.0"
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  xmlns:exsl="http://exslt.org/common"
  exclude-result-prefixes="xsl exsl">
<xsl:output method="xml" indent="yes" omit-xml-declaration="yes"/>
 
<xsl:template match="/*">
  <xsl:copy>
    <xsl:apply-templates select="door" />
  </xsl:copy>
</xsl:template>
 
<xsl:template match="door">
  <xsl:variable name="door-num" select="@number" />
  <xsl:variable name="knocks">
    <xsl:for-each select="/*/door">
      <xsl:if test="$door-num mod position() = 0">
        <xsl:text>!</xsl:text>
      </xsl:if>
    </xsl:for-each>
  </xsl:variable>
  <door number="{$door-num}">
   <xsl:choose>
     <xsl:when test="string-length($knocks) mod 2 = 1">
        <xsl:text>open</xsl:text>
     </xsl:when>
     <xsl:otherwise>
        <xsl:text>closed</xsl:text>
     </xsl:otherwise>
   </xsl:choose> 
  </door>
</xsl:template>
 
</xsl:stylesheet>

Also see: 100 doors/XSLT

XSLT 2.0

This XSLT 2.0 style-sheet does not use the input document.

<xsl:stylesheet version="2.0"
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes" omit-xml-declaration="yes"/>
 
<xsl:template match="/">
  <hallway>
    <xsl:for-each select="1 to 100">
      <xsl:variable name="door-num" select="position()" />
      <door number="{$door-num}">
        <xsl:value-of select="('closed','open')[
	    number( sum( for $pass in 1 to 100 return
	    number(($door-num mod $pass) = 0)) mod 2 = 1) + 1]" />
      </door>
    </xsl:for-each>
  </hallway>
</xsl:template>
 
</xsl:stylesheet>

Yorick

Unoptimized, iterative

doors = array(0, 100);
for(i = 1; i <= 100; i++)
    for(j = i; j <= 100; j += i)
        doors(j) ~= 1;
print, where(doors);

Unoptimized, vectorized

doors = array(0, 100);
for(i = 1; i <= 100; i++)
    doors(i::i) ~= 1;
print, where(doors);

Optimized

print, indgen(1:long(sqrt(100)))^2

All of the above output:

[1,4,9,16,25,36,49,64,81,100]

zkl

Pure brute force.

doors:=List.createLong(100,False);	// list of 100 Falses
foreach n,m in (100,[n..99,n+1]){ doors[m]=(not doors[m]); } //foreach{ foreach{} }
doors.filterNs().apply('+(1)).println();

The filterNs method returns the index of each item that passes the filter.

Output:

L(1,4,9,16,25,36,49,64,81,100)

ZX Spectrum Basic

simple calculation

 10 REM 100 doors open/closed?
 20 DIM d(100)
 25 LET o=0
 30 FOR a=1 TO 100
 40 FOR b=a TO 100 STEP a
 50 LET d(b)=NOT d(b)
 55 LET o=o+(d(b)=1)-(d(b)=0)
 60 NEXT b
 70 NEXT a
 80 PRINT o;" open doors"

changing viewable grid

 10 REM 100 doors open/closed?
 20 DIM d(100)
 25 GO SUB 170
 30 FOR a=1 TO 100
 35 PRINT AT 0,0;"step ";a
 40 FOR b=a TO 100 STEP a
 45 PRINT AT 0,10;"door:";b;"  "
 50 LET d(b)=NOT d(b)
 55 GO SUB 150
 60 NEXT b
 70 NEXT a
 80 GO SUB 170
 90 STOP 
150 REM print door status
151 LET p=(b-1)/10
152 LET q=1+10*(p-INT p)
153 LET p=INT p
154 LET op=op+(d(b)=1)-(d(b)=0)
156 PRINT AT 2*p+2,2*q;d(b);AT 0,27;op;"  "
160 RETURN 
165 REM print step status
170 LET op=0
175 FOR p=0 TO 9
180 FOR q=1 TO 10
185 PRINT AT 2*p+2,2*q;d(p*10+q)
188 LET op=op+d(p*10+q)
190 NEXT q
200 NEXT p
205 PRINT AT 0,22;"open:";op;"  "
210 RETURN