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Thiele's interpolation formula

From Rosetta Code
Task
Thiele's interpolation formula
You are encouraged to solve this task according to the task description, using any language you may know.
This page uses content from Wikipedia. The original article was at Thiele's interpolation formula. The list of authors can be seen in the page history. As with Rosetta Code, the text of Wikipedia is available under the GNU FDL. (See links for details on variance)


Thiele's interpolation formula is an interpolation formula for a function f(•) of a single variable.   It is expressed as a continued fraction:

  represents the   reciprocal difference,   demonstrated here for reference:

Demonstrate Thiele's interpolation function by:

  1. Building a   32   row trig table of values   for     from   0   by   0.05   to   1.55   of the trig functions:
    •   sin
    •   cos
    •   tan
  2. Using columns from this table define an inverse - using Thiele's interpolation - for each trig function;
  3. Finally: demonstrate the following well known trigonometric identities:
    •   6 × sin-1 ½ =
    •   3 × cos-1 ½ =
    •   4 × tan-1 1 =



Ada[edit]

thiele.ads:

with Ada.Numerics.Generic_Real_Arrays;
 
generic
type Real is digits <>;
package Thiele is
package Real_Arrays is new Ada.Numerics.Generic_Real_Arrays (Real);
subtype Real_Array is Real_Arrays.Real_Vector;
 
type Thiele_Interpolation (Length : Natural) is private;
 
function Create (X, Y : Real_Array) return Thiele_Interpolation;
function Inverse (T : Thiele_Interpolation; X : Real) return Real;
private
type Thiele_Interpolation (Length : Natural) is record
X, Y, RhoX : Real_Array (1 .. Length);
end record;
end Thiele;

thiele.adb:

package body Thiele is
use type Real_Array;
 
function "/" (Left, Right : Real_Array) return Real_Array is
Result : Real_Array (Left'Range);
begin
if Left'Length /= Right'Length then
raise Constraint_Error with "arrays not same size";
end if;
for I in Result'Range loop
Result (I) := Left (I) / Right (I);
end loop;
return Result;
end "/";
 
function Rho (X, Y : Real_Array) return Real_Array is
N  : constant Natural  := X'Length;
P  : array (1 .. N) of Real_Array (1 .. N) :=
(others => (others => 9.9));
Result : Real_Array (1 .. N);
begin
P (1) (1 .. N)  := Y (1 .. N);
P (2) (1 .. N - 1)  := (X (1 .. N - 1) - X (2 .. N)) /
(P (1) (1 .. N - 1) - P (1) (2 .. N));
for I in 3 .. N loop
P (I) (1 .. N - I + 1)  := P (I - 2) (2 .. N - I + 2) +
(X (1 .. N - I + 1) - X (I .. N)) /
(P (I - 1) (1 .. N - I + 1) - P (I - 1) (2 .. N - I + 2));
end loop;
for I in X'Range loop
Result (I) := P (I) (1);
end loop;
return Result;
end Rho;
 
function Create (X, Y : Real_Array) return Thiele_Interpolation is
begin
if X'Length < 3 then
raise Constraint_Error with "at least 3 values";
end if;
if X'Length /= Y'Length then
raise Constraint_Error with "input arrays not same size";
end if;
return (Length => X'Length, X => X, Y => Y, RhoX => Rho (X, Y));
end Create;
 
function Inverse (T : Thiele_Interpolation; X : Real) return Real is
A : Real := 0.0;
begin
for I in reverse 3 .. T.Length loop
A := (X - T.X (I - 1)) / (T.RhoX (I) - T.RhoX (I - 2) + A);
end loop;
return T.Y (1) + (X - T.X (1)) / (T.RhoX (2) + A);
end Inverse;
 
end Thiele;

example:

with Ada.Text_IO;
with Ada.Numerics.Generic_Elementary_Functions;
with Thiele;
 
procedure Main is
package Math is new Ada.Numerics.Generic_Elementary_Functions
(Long_Float);
package Float_Thiele is new Thiele (Long_Float);
use Float_Thiele;
 
Row_Count : Natural := 32;
 
X_Values  : Real_Array (1 .. Row_Count);
Sin_Values : Real_Array (1 .. Row_Count);
Cos_Values : Real_Array (1 .. Row_Count);
Tan_Values : Real_Array (1 .. Row_Count);
begin
-- build table
for I in 1 .. Row_Count loop
X_Values (I)  := Long_Float (I) * 0.05 - 0.05;
Sin_Values (I) := Math.Sin (X_Values (I));
Cos_Values (I) := Math.Cos (X_Values (I));
Tan_Values (I) := Math.Tan (X_Values (I));
end loop;
declare
Sin : Thiele_Interpolation := Create (Sin_Values, X_Values);
Cos : Thiele_Interpolation := Create (Cos_Values, X_Values);
Tan : Thiele_Interpolation := Create (Tan_Values, X_Values);
begin
Ada.Text_IO.Put_Line
("Internal Math.Pi: " &
Long_Float'Image (Ada.Numerics.Pi));
Ada.Text_IO.Put_Line
("Thiele 6*InvSin(0.5):" &
Long_Float'Image (6.0 * Inverse (Sin, 0.5)));
Ada.Text_IO.Put_Line
("Thiele 3*InvCos(0.5):" &
Long_Float'Image (3.0 * Inverse (Cos, 0.5)));
Ada.Text_IO.Put_Line
("Thiele 4*InvTan(1): " &
Long_Float'Image (4.0 * Inverse (Tan, 1.0)));
end;
end Main;

output:

Internal Math.Pi:     3.14159265358979E+00
Thiele 6*InvSin(0.5): 3.14159265358979E+00
Thiele 3*InvCos(0.5): 3.14159265358979E+00
Thiele 4*InvTan(1):   3.14159265358979E+00

ALGOL 68[edit]

Works with: ALGOL 68 version Revision 1 - except the Currying (aka partial parametrisation) in test block is a proposal for ALGOL 68 Rev2
Works with: ALGOL 68G version Any - tested with release 1.18.0-9h.tiny - Currying is supported.
PROC raise exception = ([]STRING msg)VOID: ( putf(stand error,("Exception:", $" "g$, msg, $l$)); stop );
 
# The MODE of lx and ly here should really be a UNION of "something REAL",
"something COMPLex", and "something SYMBOLIC" ... #

 
PROC thiele=([]REAL lx,ly, REAL x) REAL:
BEGIN
[]REAL xx=lx[@1],yy=ly[@1];
INT n=UPB xx;
IF UPB yy=n THEN
# Assuming that the values of xx are distinct ... #
[0:n-1,1:n]REAL p;
p[0,]:=yy[];
FOR i TO n-1 DO p[1,i]:=(xx[i]-xx[1+i])/(p[0,i]-p[0,1+i]) OD;
FOR i FROM 2 TO n-1 DO
FOR j TO n-i DO
p[i,j]:=(xx[j]-xx[j+i])/(p[i-1,j]-p[i-1,j+1])+p[i-2,j+1]
OD
OD;
REAL a:=0;
FOR i FROM n-1 BY -1 TO 2 DO a:=(x-xx[i])/(p[i,1]-p[i-2,1]+a) OD;
yy[1]+(x-xx[1])/(p[1,1]+a)
ELSE
raise exception(("Unequal length arrays supplied: ",whole(UPB xx,0)," NE ",whole(UPB yy,0))); SKIP
FI
END;
 
test:(
FORMAT real fmt = $g(0,real width-2)$;
 
REAL lwb x=0, upb x=1.55, delta x = 0.05;
 
[0:ENTIER ((upb x-lwb x)/delta x)]STRUCT(REAL x, sin x, cos x, tan x) trig table;
 
PROC init trig table = VOID:
FOR i FROM LWB trig table TO UPB trig table DO
REAL x = lwb x+i*delta x;
trig table[i]:=(x, sin(x), cos(x), tan(x))
OD;
 
init trig table;
 
# Curry the thiele function to create matching inverse trigonometric functions #
PROC (REAL)REAL inv sin = thiele(sin x OF trig table, x OF trig table,),
inv cos = thiele(cos x OF trig table, x OF trig table,),
inv tan = thiele(tan x OF trig table, x OF trig table,);
 
printf(($"pi estimate using "g" interpolation: "f(real fmt)l$,
"sin", 6*inv sin(1/2),
"cos", 3*inv cos(1/2),
"tan", 4*inv tan(1)
))
)

Output:

pi estimate using sin interpolation: 3.1415926535898
pi estimate using cos interpolation: 3.1415926535898
pi estimate using tan interpolation: 3.1415926535898

C[edit]

The recursive relations of s can be made clearer: Given sampled points , rewrite the symbol as

where ,

with suplements

.

Now the recursive relation is simply

Also note how in the interpolation formula can be replaced by ; define Thiele interpolation at step as

with the termination , and the interpolation formula is now , easily implemented as a recursive function.

Note that each needs to look up twice, so the total look ups go up as while there are only values. This is a text book situation for memoization.

#include <stdio.h>
#include <string.h>
#include <math.h>
 
#define N 32
#define N2 (N * (N - 1) / 2)
#define STEP .05
 
double xval[N], t_sin[N], t_cos[N], t_tan[N];
 
/* rho tables, layout:
rho_{n-1}(x0)
rho_{n-2}(x0), rho_{n-1}(x1),
....
rho_0(x0), rho_0(x1), ... rho_0(x_{n-1})
rho_i row starts at index (n - 1 - i) * (n - i) / 2 */

double r_sin[N2], r_cos[N2], r_tan[N2];
 
/* both rho and thiele functions recursively resolve values as decribed by
formulas. rho is cached, thiele is not. */

 
/* rho_n(x_i, x_{i+1}, ..., x_{i + n}) */
double rho(double *x, double *y, double *r, int i, int n)
{
if (n < 0) return 0;
if (!n) return y[i];
 
int idx = (N - 1 - n) * (N - n) / 2 + i;
if (r[idx] != r[idx]) /* only happens if value not computed yet */
r[idx] = (x[i] - x[i + n])
/ (rho(x, y, r, i, n - 1) - rho(x, y, r, i + 1, n - 1))
+ rho(x, y, r, i + 1, n - 2);
return r[idx];
}
 
double thiele(double *x, double *y, double *r, double xin, int n)
{
if (n > N - 1) return 1;
return rho(x, y, r, 0, n) - rho(x, y, r, 0, n - 2)
+ (xin - x[n]) / thiele(x, y, r, xin, n + 1);
}
 
#define i_sin(x) thiele(t_sin, xval, r_sin, x, 0)
#define i_cos(x) thiele(t_cos, xval, r_cos, x, 0)
#define i_tan(x) thiele(t_tan, xval, r_tan, x, 0)
 
int main()
{
int i;
for (i = 0; i < N; i++) {
xval[i] = i * STEP;
t_sin[i] = sin(xval[i]);
t_cos[i] = cos(xval[i]);
t_tan[i] = t_sin[i] / t_cos[i];
}
for (i = 0; i < N2; i++)
/* init rho tables to NaN */
r_sin[i] = r_cos[i] = r_tan[i] = 0/0.;
 
printf("%16.14f\n", 6 * i_sin(.5));
printf("%16.14f\n", 3 * i_cos(.5));
printf("%16.14f\n", 4 * i_tan(1.));
return 0;
}
output
3.14159265358979
3.14159265358979
3.14159265358979

Common Lisp[edit]

Using the notations from above the C code instead of task desc.

;; 256 is heavy overkill, but hey, we memoized
(defparameter *thiele-length* 256)
(defparameter *rho-cache* (make-hash-table :test #'equal))
 
(defmacro make-thele-func (f name xx0 xx1)
(let ((xv (gensym)) (yv (gensym))
(x0 (gensym)) (x1 (gensym)))
`(let* ((,xv (make-array (1+ *thiele-length*)))
(,yv (make-array (1+ *thiele-length*)))
(,x0 ,xx0)
(,x1 ,xx1))
(loop for i to *thiele-length* with x do
(setf x (+ ,x0 (* (/ (- ,x1 ,x0) *thiele-length*) i))
(aref ,yv i) x
(aref ,xv i) (funcall ,f x)))
(defun ,name (x) (thiele x ,yv ,xv, 0)))))
 
(defun rho (yv xv n i)
(let (hit (key (list yv xv n i)))
(if (setf hit (gethash key *rho-cache*))
hit
(setf (gethash key *rho-cache*)
(cond ((zerop n) (aref yv i))
((minusp n) 0)
(t (+ (rho yv xv (- n 2) (1+ i))
(/ (- (aref xv i)
(aref xv (+ i n)))
(- (rho yv xv (1- n) i)
(rho yv xv (1- n) (1+ i)))))))))))
 
(defun thiele (x yv xv n)
(if (= n *thiele-length*)
1
(+ (- (rho yv xv n 1) (rho yv xv (- n 2) 1))
(/ (- x (aref xv (1+ n)))
(thiele x yv xv (1+ n))))))
 
(make-thele-func #'sin inv-sin 0 (/ pi 2))
(make-thele-func #'cos inv-cos 0 (/ pi 2))
(make-thele-func #'tan inv-tan 0 (/ pi 2.1)) ; tan(pi/2) is INF
 
(format t "~f~%" (* 6 (inv-sin .5)))
(format t "~f~%" (* 3 (inv-cos .5)))
(format t "~f~%" (* 4 (inv-tan 1)))
output (SBCL):
3.141592653589793
3.1415926535885172
3.141592653589819

D[edit]

import std.stdio, std.range, std.array, std.algorithm, std.math;
 
struct Domain {
const real b, e, s;
 
auto range() const pure /*nothrow*/ @safe [email protected]*/ {
return iota(b, e + s, s);
}
}
 
real eval0(alias RY, alias X, alias Y)(in real x) pure nothrow @safe @nogc {
real a = 0.0L;
foreach_reverse (immutable i; 2 .. X.length - 3)
a = (x - X[i]) / (RY[i] - RY[i-2] + a);
return Y[1] + (x - X[1]) / (RY[1] + a);
}
 
immutable struct Thiele {
immutable real[] Y, X, rhoY, rhoX;
 
this(real[] y, real[] x) immutable pure nothrow [email protected]*/
in {
assert(x.length > 2, "at leat 3 values");
assert(x.length == y.length, "input arrays not of same size");
} body {
this.Y = y.idup;
this.X = x.idup;
rhoY = rhoN(Y, X);
rhoX = rhoN(X, Y);
}
 
this(in real function(real) pure nothrow @safe @nogc f,
Domain d = Domain(0.0L, 1.55L, 0.05L))
immutable pure /*nothrow @safe*/ {
auto xrng = d.range.array;
this(xrng.map!f.array, xrng);
}
 
auto rhoN(immutable real[] y, immutable real[] x)
pure nothrow @safe {
immutable int N = x.length;
auto p = new real[][](N, N);
p[0][] = y[];
p[1][0 .. $ - 1] = (x[0 .. $-1] - x[1 .. $]) /
(p[0][0 .. $-1] - p[0][1 .. $]);
foreach (immutable int j; 2 .. N - 1) {
immutable M = N - j - 1;
p[j][0..M] = p[j-2][1..M+1] + (x[0..M] - x[j..M+j]) /
(p[j-1][0 .. M] - p[j-1][1 .. M+1]);
}
return p.map!q{ a[1] }.array;
}
 
alias eval = eval0!(rhoY, X, Y);
alias inverse = eval0!(rhoX, Y, X);
}
 
void main() {
// Can't pass sin, cos and tan directly.
immutable tsin = Thiele(x => x.sin);
immutable tcos = Thiele(x => x.cos);
immutable ttan = Thiele(x => x.tan);
 
writefln(" %d interpolating points\n", tsin.X.length);
writefln("std.math.sin(0.5): %20.18f", 0.5L.sin);
writefln(" Thiele sin(0.5): %20.18f\n", tsin.eval(0.5L));
 
writefln("*%20.19f library constant", PI);
writefln(" %20.19f 6 * inv_sin(0.5)", tsin.inverse(0.5L) * 6.0L);
writefln(" %20.19f 3 * inv_cos(0.5)", tcos.inverse(0.5L) * 3.0L);
writefln(" %20.19f 4 * inv_tan(1.0)", ttan.inverse(1.0L) * 4.0L);
}
Output:
 32 interpolating points

std.math.sin(0.5): 0.479425538604203000
  Thiele sin(0.5): 0.479425538604203000

*3.1415926535897932385 library constant
 3.1415926535897932380 6 * inv_sin(0.5)
 3.1415926535897932382 3 * inv_cos(0.5)
 3.1415926535897932382 4 * inv_tan(1.0)

Go[edit]

Translation of: ALGOL 68
package main
 
import (
"fmt"
"math"
)
 
func main() {
// task 1: build 32 row trig table
const nn = 32
const step = .05
xVal := make([]float64, nn)
tSin := make([]float64, nn)
tCos := make([]float64, nn)
tTan := make([]float64, nn)
for i := range xVal {
xVal[i] = float64(i) * step
tSin[i], tCos[i] = math.Sincos(xVal[i])
tTan[i] = tSin[i] / tCos[i]
}
// task 2: define inverses
iSin := thieleInterpolator(tSin, xVal)
iCos := thieleInterpolator(tCos, xVal)
iTan := thieleInterpolator(tTan, xVal)
// task 3: demonstrate identities
fmt.Printf("%16.14f\n", 6*iSin(.5))
fmt.Printf("%16.14f\n", 3*iCos(.5))
fmt.Printf("%16.14f\n", 4*iTan(1))
}
 
func thieleInterpolator(x, y []float64) func(float64) float64 {
n := len(x)
ρ := make([][]float64, n)
for i := range ρ {
ρ[i] = make([]float64, n-i)
ρ[i][0] = y[i]
}
for i := 0; i < n-1; i++ {
ρ[i][1] = (x[i] - x[i+1]) / (ρ[i][0] - ρ[i+1][0])
}
for i := 2; i < n; i++ {
for j := 0; j < n-i; j++ {
ρ[j][i] = (x[j]-x[j+i])/(ρ[j][i-1]-ρ[j+1][i-1]) + ρ[j+1][i-2]
}
}
// ρ0 used in closure. the rest of ρ becomes garbage.
ρ0 := ρ[0]
return func(xin float64) float64 {
var a float64
for i := n - 1; i > 1; i-- {
a = (xin - x[i-1]) / (ρ0[i] - ρ0[i-2] + a)
}
return y[0] + (xin-x[0])/(ρ0[1]+a)
}
}

Output:

3.14159265358979
3.14159265358979
3.14159265358980

Haskell[edit]

Caching of rho is automatic due to lazy lists.

thiele xs ys = f rho1 (tail xs) where
f _ [] _ = 1
f r@(r0:r1:r2:rs) (x:xs) v = r2 - r0 + (v-x) / f (tail r) xs v
 
rho1 = (map ((!!1).(++[0])) rho)
 
rho = [0,0..] : [0,0..] : ys : rnext (tail rho) xs (tail xs) where
rnext _ _ [] = []
rnext r@(r0:r1:rs) x xn = let z_ = zipWith in
(z_ (+) (tail r0)
(z_ (/) (z_ (-) x xn)
(z_ (-) r1 (tail r1))))
: rnext (tail r) x (tail xn)
 
-- inverted interpolation function of f
inv_interp f xs = thiele (map f xs) xs
 
main = do print $ 3.21 * inv_sin (sin (pi / 3.21))
print $ pi/1.2345 * inv_cos (cos (1.2345))
print $ 7 * inv_tan (tan (pi / 7))
where
inv_sin = inv_interp sin $ div_pi 2 31
inv_cos = inv_interp cos $ div_pi 2 100
inv_tan = inv_interp tan $ div_pi 4 1000 -- because we can
-- uniformly take n points from 0 to Pi/d
div_pi d n = map (* (pi / (d * n))) [0..n]
Output:
3.141592653589795
3.1415926535897802
3.1415926535835275

J[edit]

 
span =: {. - {: NB. head - tail
spans =: span\ NB. apply span to successive infixes
 
   span 12 888 6 4 8 3
9
   4 spans 12 888 6 4 8 3
8 880 3
 
NB. abscissae_of_knots coef ordinates_of_knots
NB. returns the interpolation coefficients for eval
coef =: 4 : 0
p =. _2 _{.,:y
for_i. i. # x do.
p =. (p , ([: }. - }. p {~ _2:) + (x spans~ 2+]) % 2 spans - }. [: {: p"_) i
end.
x; , _ 1 {. p
)
 
NB. unknown_abscissae eval coefficients
eval =: 4 : 0
'xx p' =. y
a =. 0
i =. <: # xx
while. 0 < i=.<:i do.
a =. (x-i{xx)%-/(p{~i+2),(i{p),a
end.
(p{~>:i)+(x-i{xx)%(p{~i+2)+a
)
 
   trig_table =: 1 2 3 o./ angles =: 5r100*i.32

   0 _1 }. ": (;:'angle sin cos tan'),.<"1] 8j4": _ 5{.angles,trig_table
┌─────┬────────────────────────────────────────
│angle│  0.0000  0.0500  0.1000  0.1500  0.2000
├─────┼────────────────────────────────────────
│sin  │  0.0000  0.0500  0.0998  0.1494  0.1987
├─────┼────────────────────────────────────────
│cos  │  1.0000  0.9988  0.9950  0.9888  0.9801
├─────┼────────────────────────────────────────
│tan  │  0.0000  0.0500  0.1003  0.1511  0.2027
└─────┴────────────────────────────────────────


   ('Thiele pi';'error'),;/"1(,. 1p1&-)6 3 4 * 1r2 1r2 1 eval"0 1 trig_table coef"1 angles
┌─────────┬────────────┐
│Thiele pi│error       │
├─────────┼────────────┤
│3.14159  │_4.44089e_15│
├─────────┼────────────┤
│3.14159  │_4.44089e_16│
├─────────┼────────────┤
│3.14159  │_7.10543e_15│
└─────────┴────────────┘
 
thiele =: 2 : 0
p =. _2 _{.,:n
for_i. i.#m do.
p =. (p , ([: }. - }. p {~ _2:) + (m spans~ 2+]) % 2 spans - }. [: {: p"_) i
end.
p =. , _ 1 {. p
a =. 0
i =. <:#m
while. 0 < i=.<:i do.
a =. (y-i{m)%-/(p{~i+2),(i{p),a
end.
(p{~>:i)+(y-i{m)%a+p{~i+2
)
 
   's c t' =: trig_table
   asin =: s thiele angles

   6*asin 0.5
3.14159

   1r5 * i.6
0 1r5 2r5 3r5 4r5 1
   100*(_1&o. %~ _1&o. - asin) 1r5*i.6   NB. % error arcsin
0 1.4052 4.50319 9.32495 16.9438 39.321

Java[edit]

Translation of: C
import static java.lang.Math.*;
 
public class Test {
final static int N = 32;
final static int N2 = (N * (N - 1) / 2);
final static double STEP = 0.05;
 
static double[] xval = new double[N];
static double[] t_sin = new double[N];
static double[] t_cos = new double[N];
static double[] t_tan = new double[N];
 
static double[] r_sin = new double[N2];
static double[] r_cos = new double[N2];
static double[] r_tan = new double[N2];
 
static double rho(double[] x, double[] y, double[] r, int i, int n) {
if (n < 0)
return 0;
 
if (n == 0)
return y[i];
 
int idx = (N - 1 - n) * (N - n) / 2 + i;
if (r[idx] != r[idx])
r[idx] = (x[i] - x[i + n])
/ (rho(x, y, r, i, n - 1) - rho(x, y, r, i + 1, n - 1))
+ rho(x, y, r, i + 1, n - 2);
 
return r[idx];
}
 
static double thiele(double[] x, double[] y, double[] r, double xin, int n) {
if (n > N - 1)
return 1;
return rho(x, y, r, 0, n) - rho(x, y, r, 0, n - 2)
+ (xin - x[n]) / thiele(x, y, r, xin, n + 1);
}
 
public static void main(String[] args) {
for (int i = 0; i < N; i++) {
xval[i] = i * STEP;
t_sin[i] = sin(xval[i]);
t_cos[i] = cos(xval[i]);
t_tan[i] = t_sin[i] / t_cos[i];
}
 
for (int i = 0; i < N2; i++)
r_sin[i] = r_cos[i] = r_tan[i] = Double.NaN;
 
System.out.printf("%16.14f%n", 6 * thiele(t_sin, xval, r_sin, 0.5, 0));
System.out.printf("%16.14f%n", 3 * thiele(t_cos, xval, r_cos, 0.5, 0));
System.out.printf("%16.14f%n", 4 * thiele(t_tan, xval, r_tan, 1.0, 0));
}
}
3.14159265358979
3.14159265358979
3.14159265358980

OCaml[edit]

This example shows how the accuracy changes with the degree of interpolation. The table 'columns' are only constructed implicitly during the recursive calculation of rdiff and thiele, but (as mentioned in the C code example) using memoization or explicit tabulation would speed up the calculation. The interpolation uses the nearest points around x for accuracy.

let xv, fv = fst, snd
 
let rec rdiff a l r =
if l > r then 0.0 else
if l = r then fv a.(l) else
if l+1 = r then (xv a.(l) -. xv a.(r)) /. (fv a.(l) -. fv a.(r)) else
(xv a.(l) -. xv a.(r)) /. (rdiff a l (r-1) -. rdiff a (l+1) r) +. rdiff a (l+1) (r-1)
 
let rec thiele x a a0 k n =
if k = n then 1.0 else
rdiff a a0 (a0+k) -. rdiff a a0 (a0+k-2) +. (x -. xv a.(a0+k)) /. thiele x a a0 (k+1) n
 
let interpolate x a n =
let m = Array.length a in
let dist i = abs_float (x -. xv a.(i)) in
let nearer i j = if dist j < dist i then j else i in
let rec closest i j = if j = m then i else closest (nearer i j) (j+1) in
let c = closest 0 1 in
let c' = if c < n/2 then 0 else if c > m-n then m-n else c-(n/2) in
thiele x a c' 0 n
 
let table a b n f =
let g i =
let x = a +. (b-.a)*.(float i)/.(float (n-1)) in
(f x, x) in
Array.init n g
 
let [sin_tab; cos_tab; tan_tab] = List.map (table 0.0 1.55 32) [sin; cos; tan]
 
let test n =
Printf.printf "\nDegree %d interpolation:\n" n;
Printf.printf "6*arcsin(0.5) = %.15f\n" (6.0*.(interpolate 0.5 sin_tab n));
Printf.printf "3*arccos(0.5) = %.15f\n" (3.0*.(interpolate 0.5 cos_tab n));
Printf.printf "4*arctan(1.0) = %.15f\n" (4.0*.(interpolate 1.0 tan_tab n));;
 
List.iter test [8; 12; 16]

Output:

Degree 8 interpolation:
6*arcsin(0.5) = 3.141592654456238
3*arccos(0.5) = 3.141592653520809
4*arctan(1.0) = 3.141592653437432

Degree 12 interpolation:
6*arcsin(0.5) = 3.141592653587590
3*arccos(0.5) = 3.141592653562618
4*arctan(1.0) = 3.141592653589756

Degree 16 interpolation:
6*arcsin(0.5) = 3.141592653589793
3*arccos(0.5) = 3.141592653589793
4*arctan(1.0) = 3.141592653589793

Perl 6[edit]

Works with: rakudo version 2016.07

Implemented to parallel the (generalized) formula. (i.e. clearer, but naive and very slow.)

use v6;
 
# reciprocal difference:
multi sub ρ(&f, @x where * < 1) { 0 } # Identity
multi sub ρ(&f, @x where * == 1) { &f(@x[0]) }
multi sub ρ(&f, @x where * > 1) {
( @x[0] - @x[* - 1] ) # ( x - x[n] )
/ (ρ(&f, @x[^(@x - 1)]) # / ( ρ[n-1](x[0], ..., x[n-1])
- ρ(&f, @x[1..^@x]) ) # - ρ[n-1](x[1], ..., x[n]) )
+ ρ(&f, @x[1..^(@x - 1)]); # + ρ[n-2](x[1], ..., x[n-1])
}
 
# Thiele:
multi sub thiele($x, %f, $ord where { $ord == +%f }) { 1 } # Identity
multi sub thiele($x, %f, $ord) {
my &f = {%f{$^a}}; # f(x) as a table lookup
 
# Caveat: depends on the fact that Rakudo maintains key order within hashes
my $a = ρ(&f, %f.keys[^($ord +1)]);
my $b = ρ(&f, %f.keys[^($ord -1)]);
 
my $num = $x - %f.keys[$ord];
my $cont = thiele($x, %f, $ord +1);
 
# Thiele always takes this form:
return $a - $b + ( $num / $cont );
}
 
## Demo
sub mk-inv(&fn, $d, $lim) {
my %h;
for 0..$lim { %h{ &fn($_ * $d) } = $_ * $d }
return %h;
}
 
sub MAIN($tblsz = 12) {
my %invsin = mk-inv(&sin, 0.05, $tblsz);
my %invcos = mk-inv(&cos, 0.05, $tblsz);
my %invtan = mk-inv(&tan, 0.05, $tblsz);
 
my $sin_pi = 6 * thiele(0.5, %invsin, 0);
my $cos_pi = 3 * thiele(0.5, %invcos, 0);
my $tan_pi = 4 * thiele(1.0, %invtan, 0);
 
say "pi = {pi}";
say "estimations using a table of $tblsz elements:";
say "sin interpolation: $sin_pi";
say "cos interpolation: $cos_pi";
say "tan interpolation: $tan_pi";
}

Output:

pi = 3.14159265358979
estimations using a table of 12 elements:
sin interpolation: 3.14159265358961
cos interpolation: 3.1387286696692
tan interpolation: 3.14159090545243

PicoLisp[edit]

Translation of: C
(scl 17)
(load "@lib/math.l")
 
(setq
*X-Table (range 0.0 1.55 0.05)
*SinTable (mapcar sin *X-Table)
*CosTable (mapcar cos *X-Table)
*TanTable (mapcar tan *X-Table)
*TrigRows (length *X-Table) )
 
(let N2 (>> 1 (* *TrigRows (dec *TrigRows)))
(setq
*InvSinTable (need N2)
*InvCosTable (need N2)
*InvTanTable (need N2) ) )
 
(de rho (Tbl Inv I N)
(cond
((lt0 N) 0)
((=0 N) (get *X-Table I))
(T
(let Idx (+ I (>> 1 (* (- *TrigRows 1 N) (- *TrigRows N))))
(or
(get Inv Idx)
(set (nth Inv Idx) # only happens if value not computed yet
(+
(rho Tbl Inv (inc I) (- N 2))
(*/
(- (get Tbl I) (get Tbl (+ I N)))
1.0
(-
(rho Tbl Inv I (dec N))
(rho Tbl Inv (inc I) (dec N)) ) ) ) ) ) ) ) ) )
 
(de thiele (Tbl Inv X N)
(if (> N *TrigRows)
1.0
(+
(-
(rho Tbl Inv 1 (dec N))
(rho Tbl Inv 1 (- N 3)) )
(*/
(- X (get Tbl N))
1.0
(thiele Tbl Inv X (inc N)) ) ) ) )
 
(de iSin (X)
(thiele *SinTable *InvSinTable X 1) )
 
(de iCos (X)
(thiele *CosTable *InvCosTable X 1) )
 
(de iTan (X)
(thiele *TanTable *InvTanTable 1.0 1) )

Test:

(prinl (round (* 6 (iSin 0.5)) 15))
(prinl (round (* 3 (iCos 0.5)) 15))
(prinl (round (* 4 (iTan 1.0)) 15))

Output:

3.141592653589793
3.141592653589793
3.141592653589793

PowerShell[edit]

Function Reciprocal-Difference( [Double[][]] $function )
{
$rho=@()
$rho+=0
$funcl = $function.length
if( $funcl -gt 0 )
{
-2..($funcl-1) | ForEach-Object {
$i=$_
#Write-Host "$($i+1) - $($rho[$i+1]) - $($rho[$i+1].GetType())"
$rho[$i+2] = $( 0..($funcl-$i-1) | Where-Object {$_ -lt $funcl} | ForEach-Object {
$j=$_
switch ($i) {
{$_ -lt 0 } { 0 }
{$_ -eq 0 } { $function[$j][1] }
{$_ -gt 0 } { ( $function[$j][0] - $function[$j+$i][0] ) / ( $rho[$i+1][$j] - $rho[$i+1][$j+1] ) + $rho[$i][$j+1] }
}
if( $_ -lt $funcl )
{
$rho += 0
}
})
}
}
$rho
}
 
Function Thiele-Interpolation ( [Double[][]] $function )
{
$funcl = $function.length
$invoke = "{`n`tparam([Double] `$x)`n"
if($funcl -gt 1)
{
$rho = Reciprocal-Difference $function
($funcl-1)..0 | ForEach-Object {
$invoke += "`t"
$invoke += '$x{0} = {1} - {2}' -f $_, @($rho[$_+2])[0], @($rho[$_])[0]
if($_ -lt ($funcl-1))
{
$invoke += ' + ( $x - {0} ) / $x{1} ' -f $function[$_][0], ($_+1)
}
$invoke += "`n"
}
$invoke+="`t`$x0`n}"
} else {
$invoke += "`t`$x`n}"
}
invoke-expression $invoke
}
 
$sint=@{}; 0..31 | ForEach-Object { $_ * 0.05 } | ForEach-Object { $sint[$_] = [Math]::sin($_) }
$cost=@{}; 0..31 | ForEach-Object { $_ * 0.05 } | ForEach-Object { $cost[$_] = [Math]::cos($_) }
$tant=@{}; 0..31 | ForEach-Object { $_ * 0.05 } | ForEach-Object { $tant[$_] = [Math]::tan($_) }
$asint=New-Object 'Double[][]' 32,2; $sint.GetEnumerator() | Sort-Object Value | ForEach-Object {$i=0}{ $asint[$i][0] = $_.Value; $asint[$i][1] = $_.Name; $i++ }
$acost=New-Object 'Double[][]' 32,2; $cost.GetEnumerator() | Sort-Object Value | ForEach-Object { $i=0 }{ $acost[$i][0] = $_.Value; $acost[$i][1] = $_.Name; $i++ }
$atant=New-Object 'Double[][]' 32,2; $tant.GetEnumerator() | Sort-Object Value | ForEach-Object {$i=0}{ $atant[$i][0] = $_.Value; $atant[$i][1] = $_.Name; $i++ }
 
$asin = (Thiele-Interpolation $asint)
#uncomment to see the function
#"{$asin}"
6*$asin.InvokeReturnAsIs(.5)
$acos = (Thiele-Interpolation $acost)
#uncomment to see the function
#"{$acos}"
3*$acos.InvokeReturnAsIs(.5)
$atan = (Thiele-Interpolation $atant)
#uncomment to see the function
#"{$atan}"
4*$atan.InvokeReturnAsIs(1)

Python[edit]

Translation of: Go
#!/usr/bin/env python3
 
import math
 
def thieleInterpolator(x, y):
ρ = [[yi]*(len(y)-i) for i, yi in enumerate(y)]
for i in range(len(ρ)-1):
ρ[i][1] = (x[i] - x[i+1]) / (ρ[i][0] - ρ[i+1][0])
for i in range(2, len(ρ)):
for j in range(len(ρ)-i):
ρ[j][i] = (x[j]-x[j+i]) / (ρ[j][i-1][j+1][i-1]) + ρ[j+1][i-2]
ρ0 = ρ[0]
def t(xin):
a = 0
for i in range(len(ρ0)-1, 1, -1):
a = (xin - x[i-1]) / (ρ0[i] - ρ0[i-2] + a)
return y[0] + (xin-x[0]) / (ρ0[1]+a)
return t
 
# task 1: build 32 row trig table
xVal = [i*.05 for i in range(32)]
tSin = [math.sin(x) for x in xVal]
tCos = [math.cos(x) for x in xVal]
tTan = [math.tan(x) for x in xVal]
# task 2: define inverses
iSin = thieleInterpolator(tSin, xVal)
iCos = thieleInterpolator(tCos, xVal)
iTan = thieleInterpolator(tTan, xVal)
# task 3: demonstrate identities
print('{:16.14f}'.format(6*iSin(.5)))
print('{:16.14f}'.format(3*iCos(.5)))
print('{:16.14f}'.format(4*iTan(1)))
Output:
3.14159265358979
3.14159265358979
3.14159265358980

Racket[edit]

 
#lang racket
(define xs (for/vector ([x (in-range 0.0 1.6 0.05)]) x))
(define (x i) (vector-ref xs i))
 
(define-syntax define-table
(syntax-rules ()
[(_ f tf rf if)
(begin (define tab (for/vector ([x xs]) (f x)))
(define (tf n) (vector-ref tab n))
(define cache (make-vector (/ (* 32 31) 2) #f))
(define (rf n thunk)
(or (vector-ref cache n)
(let ([v (thunk)])
(vector-set! cache n v)
v)))
(define (if t) (thiele tf x rf t 0)))]))
 
(define-table sin tsin rsin isin)
(define-table cos tcos rcos icos)
(define-table tan ttan rtan itan)
 
(define (rho x y r i n)
(cond
[(< n 0) 0]
[(= n 0) (y i)]
[else (r (+ (/ (* (- 32 1 n) (- 32 n)) 2) i)
(λ() (+ (/ (- (x i) (x (+ i n)))
(- (rho x y r i (- n 1)) (rho x y r (+ i 1) (- n 1))))
(rho x y r (+ i 1) (- n 2)))))]))
 
(define (thiele x y r xin n)
(cond
[(> n 31) 1]
[(+ (rho x y r 0 n) (- (rho x y r 0 (- n 2)))
(/ (- xin (x n)) (thiele x y r xin (+ n 1))))]))
 
(* 6 (isin 0.5))
(* 3 (icos 0.5))
(* 4 (itan 1.))
 

Output:

 
3.141592653589793
3.1415926535897936
3.1415926535897953
 

Sidef[edit]

Translation of: Python
func thiele(x, y) {
var ρ = y.range.map {|i| [y[i]]*(y.len-i) }
 
for i in ^(ρ.end) {
ρ[i][1] = ((x[i] - x[i+1]) / (ρ[i][0] - ρ[i+1][0]))
}
for i in range(2, ρ.end) {
for j in range(0, ρ.end - i) {
ρ[j][i] = (((x[j]-x[j+i]) / (ρ[j][i-1]-ρ[j+1][i-1])) + ρ[j+1][i-2])
}
}
 
var ρ0 = ρ[0]
 
func t(xin) {
var a = 0
for i in range(ρ0.end, 2, -1) {
a = ((xin - x[i-1]) / (ρ0[i] - ρ0[i-2] + a))
}
y[0] + ((xin-x[0]) / (ρ0[1]+a))
}
return t
}
 
# task 1: build 32 row trig table
var xVal = range(32).map { |k| k * 0.05 }
var tSin = xVal.map { .sin }
var tCos = xVal.map { .cos }
var tTan = xVal.map { .tan }
 
# task 2: define inverses
var iSin = thiele(tSin, xVal)
var iCos = thiele(tCos, xVal)
var iTan = thiele(tTan, xVal)
 
# task 3: demonstrate identities
say 6*iSin(0.5)
say 3*iCos(0.5)
say 4*iTan(1)
Output:
3.14159265358979323846438729976819
3.14159265358979323846157620314931
3.14159265358979323846264318595256

Tcl[edit]

Works with: Tcl version 8.5
Translation of: D
#
### Create a thiele-interpretation function with the given name that interpolates
### off the given table.
#
proc thiele {name : X -> F} {
# Sanity check
if {[llength $X] != [llength $F]} {
error "unequal length lists supplied: [llength $X] != [llength $F]"
}
 
#
### Compute the table of reciprocal differences
#
set p [lrepeat [llength $X] [lrepeat [llength $X] 0.0]]
set i 0
foreach x0 [lrange $X 0 end-1] x1 [lrange $X 1 end] \
f0 [lrange $F 0 end-1] f1 [lrange $F 1 end] {
lset p $i 0 $f0
lset p $i 1 [expr {($x0 - $x1) / ($f0 - $f1)}]
lset p [incr i] 0 $f1
}
for {set j 2} {$j<[llength $X]-1} {incr j} {
for {set i 0} {$i<[llength $X]-$j} {incr i} {
lset p $i $j [expr {
[lindex $p $i+1 $j-2] +
([lindex $X $i] - [lindex $X $i+$j]) /
([lindex $p $i $j-1] - [lindex $p $i+1 $j-1])
}]
}
}
 
#
### Make pseudo-curried function that actually evaluates Thiele's formula
#
interp alias {} $name {} apply {{X rho f1 x} {
set a 0.0
foreach Xi [lreverse [lrange $X 2 end]] \
Ri [lreverse [lrange $rho 2 end]] \
Ri2 [lreverse [lrange $rho 0 end-2]] {
set a [expr {($x - $Xi) / ($Ri - $Ri2 + $a)}]
}
expr {$f1 + ($x - [lindex $X 1]) / ([lindex $rho 1] + $a)}
}} $X [lindex $p 1] [lindex $F 1]
}

Demonstration code:

proc initThieleTest {} {
for {set i 0} {$i < 32} {incr i} {
lappend trigTable(x) [set x [expr {0.05 * $i}]]
lappend trigTable(sin) [expr {sin($x)}]
lappend trigTable(cos) [expr {cos($x)}]
lappend trigTable(tan) [expr {tan($x)}]
}
 
thiele invSin : $trigTable(sin) -> $trigTable(x)
thiele invCos : $trigTable(cos) -> $trigTable(x)
thiele invTan : $trigTable(tan) -> $trigTable(x)
}
initThieleTest
puts "pi estimate using sin interpolation: [expr {6 * [invSin 0.5]}]"
puts "pi estimate using cos interpolation: [expr {3 * [invCos 0.5]}]"
puts "pi estimate using tan interpolation: [expr {4 * [invTan 1.0]}]"

Output:

pi estimate using sin interpolation: 3.1415926535897936
pi estimate using cos interpolation: 3.141592653589793
pi estimate using tan interpolation: 3.141592653589794

zkl[edit]

Translation of: C

Please see the C example for the comments I've removed (this is an as pure-as-I-make-it translation).

const N=32, N2=(N * (N - 1) / 2), STEP=0.05;
 
fcn rho(xs,ys,rs, i,n){
if (n < 0) return(0.0);
if (not n) return(ys[i]);
 
idx := (N - 1 - n) * (N - n) / 2 + i;
if (Void==rs[idx])
rs[idx] = (xs[i] - xs[i + n])
/ (rho(xs, ys, rs, i, n - 1) - rho(xs, ys, rs, i + 1, n - 1))
+ rho(xs, ys, rs, i + 1, n - 2);
return(rs[idx]);
}
 
fcn thiele(xs,ys,rs, xin, n){
if (n > N - 1) return(1.0);
rho(xs, ys, rs, 0, n) - rho(xs, ys, rs, 0, n - 2)
+ (xin - xs[n]) / thiele(xs, ys, rs, xin, n + 1);
}
 
///////////
 
reg t_sin=L(), t_cos=L(), t_tan=L(),
r_sin=L(), r_cos=L(), r_tan=L(), xval=L();
 
i_sin := thiele.fpM("11101",t_sin, xval, r_sin, 0);
i_cos := thiele.fpM("11101",t_cos, xval, r_cos, 0);
i_tan := thiele.fpM("11101",t_tan, xval, r_tan, 0);
 
foreach i in (N){
xval.append(x:=STEP*i);
t_sin.append(x.sin());
t_cos.append(x.cos());
t_tan.append(t_sin[i] / t_cos[i]);
}
foreach i in (N2){ r_sin+Void; r_cos+Void; r_tan+Void; }
 
print("%16.14f\n".fmt( 6.0 * i_sin(0.5)));
print("%16.14f\n".fmt( 3.0 * i_cos(0.5)));
print("%16.14f\n".fmt( 4.0 * i_tan(1.0)));
Output:
3.14159265358979
3.14159265358979
3.14159265358979