Loops/Continue: Difference between revisions
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=={{header|Sidef}}== |
=={{header|Sidef}}== |
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<lang ruby>for (1..10) { |
<lang ruby>for i in (1..10) { |
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print i |
print i |
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if (i %% 5) { |
if (i %% 5) { |
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print "\n" |
print "\n" |
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next |
next |
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} |
} |
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print ', ' |
print ', ' |
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}</lang> |
}</lang> |
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Revision as of 11:34, 19 August 2016
![Task](http://static.miraheze.org/rosettacodewiki/thumb/b/ba/Rcode-button-task-crushed.png/64px-Rcode-button-task-crushed.png)
You are encouraged to solve this task according to the task description, using any language you may know.
- Task
Show the following output using one loop.
1, 2, 3, 4, 5 6, 7, 8, 9, 10
Try to achieve the result by forcing the next iteration within the loop
upon a specific condition, if your language allows it.
360 Assembly
<lang 360asm>* Loops/Continue 12/08/2015 LOOPCONT CSECT
USING LOOPCONT,R12 LR R12,R15
BEGIN LA R8,0
SR R5,R5 LA R6,1 LA R7,10
LOOPI BXH R5,R6,ELOOPI for i=1 to 10
LA R3,MVC(R8) XDECO R5,XDEC MVC 0(4,R3),XDEC+8 LA R8,4(R8) LR R10,R5 LA R1,5 SRDA R10,32 DR R10,R1 LTR R10,R10 BNZ COMMA XPRNT MVC,80 LA R8,0 B NEXTI
COMMA LA R3,MVC(R8)
MVC 0(2,R3),=C', ' LA R8,2(R8)
NEXTI B LOOPI next i ELOOPI XR R15,R15
BR R14
MVC DC CL80' ' XDEC DS CL16
YREGS END LOOPCONT</lang>
- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
Ada
Ada doesn't have a continue statement, so we have to use a goto statement. The previous submitter said continue is not needed. In this example it is indeed not needed, but that is not always the case. An example is a loop where a number of interdependent conditions are checked before executing the main body of the loop. Without a continue statement (or goto), one ends up with nested statements with the main body to the far right of the page.
B.N. You should always try to avoid using a goto, but if you really must, it's there in Ada.
P.S. it is often simplest to place the label on top of the loop, as in real life the need occurs when reading input, so there is no range condition in the loop and we can forgo the null statement.
<lang ada>with Ada.Text_IO; use Ada.Text_IO;
procedure Loop_Continue is begin
for I in 1..10 loop Put (Integer'Image(I)); if I = 5 or I = 10 then New_Line; goto Continue; end if; Put (","); <<Continue>> --Ada 2012 no longer requires a statement after the label end loop;
end Loop_Continue;</lang>
Aikido
<lang aikido>foreach i 1..10 {
print (i) if ((i % 5) == 0) { println() continue } print (", ")
}</lang>
ALGOL 68
ALGOL 68 has no continue reserved word, nor does it need one. The continue reserved word is only syntactic sugar for operations that can be achieved without it as in the following example: <lang algol68>FOR i FROM 1 TO 10 DO
print ((i, IF i MOD 5 = 0 THEN new line ELSE "," FI ))
OD</lang>
- Output:
+1, +2, +3, +4, +5 +6, +7, +8, +9, +10
Applesoft BASIC
<lang ApplesoftBasic> 10 FOR I = 1 TO 10
20 PRINT I; 30 IF I - INT (I / 5) * 5 = 0 THEN PRINT : GOTO 50"CONTINUE 40 PRINT ", "; 50 NEXT</lang>
AutoHotkey
<lang autohotkey>Loop, 10 {
Delimiter := (A_Index = 5) || (A_Index = 10) ? "`n":", " Index .= A_Index . Delimiter
} MsgBox %Index%</lang>
AWK
<lang awk>BEGIN {
for(i=1; i <= 10; i++) { printf("%d", i) if ( i % 5 == 0 ) { print continue } printf(", ") }
}</lang>
BBC BASIC
BBC BASIC doesn't have a 'continue' statement so the remainder of the loop must be made conditional. <lang bbcbasic> FOR i% = 1 TO 10
PRINT ; i% ; IF i% MOD 5 = 0 PRINT ELSE PRINT ", "; NEXT</lang>
bc
Requires a bc with the print and continue statements. POSIX bc has not these statements.
<lang bc>for (i = 1; i <= 10; i++) { print i if (i % 5) { print ", " continue } print "\n" } quit</lang>
C
<lang c>for(int i = 1;i <= 10; i++){
printf("%d", i); if(i % 5 == 0){ printf("\n"); continue; } printf(", ");
}</lang>
C++
<lang cpp>for(int i = 1;i <= 10; i++){
cout << i; if(i % 5 == 0){ cout << endl; continue; } cout << ", ";
}</lang>
C#
<lang csharp>using System;
class Program {
static void Main(string[] args) { for (int i = 1; i <= 10; i++) { Console.Write(i);
if (i % 5 == 0) { Console.WriteLine(); continue; }
Console.Write(", "); } }
}</lang>
Chapel
<lang chapel>for i in 1..10 {
write(i); if i % 5 == 0 then { writeln(); continue; } write(", ");
}</lang>
Clipper
LOOP keyword is used here instead of continue.
Works as is with Harbour 3.0.0 (Rev. 16951) <lang visualfoxpro>FOR i := 1 TO 10
?? i IF i % 5 == 0 ? LOOP ENDIF ?? ", "
NEXT</lang>
Clojure
Clojure doesn't have a continue keyword. It has a recur keyword, although I prefer to work with ranges in this case. <lang clojure>(doseq [n (range 1 11)]
(print n) (if (zero? (rem n 5)) (println) (print ", ")))</lang>
To address the task, however, here's an example loop/recur: <lang clojure>(loop [xs (range 1 11)]
(when-let [x (first xs)] (print x) (if (zero? (rem x 5)) (println) (print ", ")) (recur (rest xs))))</lang>
COBOL
<lang cobol> IDENTIFICATION DIVISION.
PROGRAM-ID. loop-continue.
DATA DIVISION. WORKING-STORAGE SECTION. 01 i PIC 99.
PROCEDURE DIVISION. PERFORM VARYING i FROM 1 BY 1 UNTIL 10 < i DISPLAY i WITH NO ADVANCING
IF FUNCTION MOD(i, 5) = 0 DISPLAY SPACE EXIT PERFORM CYCLE END-IF
DISPLAY ", " WITH NO ADVANCING END-PERFORM
GOBACK .</lang>
Note: COBOL does have a CONTINUE
verb, but this is a no-operation statement used in IF
and EVALUATE
statements.
ColdFusion
Remove the leading space from the line break tag. <lang cfm><cfscript>
for( i = 1; i <= 10; i++ ) { writeOutput( i ); if( 0 == i % 5 ) { writeOutput( "< br />" ); continue; } writeOutput( "," ); }
</cfscript></lang>
Common Lisp
Common Lisp doesn't have a continue keyword, but the do
iteration construct does use an implicit tagbody
, so it's easy to go
to any label.
Four solutions follow.
The first pushes the conditional (whether to print a comma and a space or a newline) into the format string.
The second uses the implicit tagbody
and go
.
The third is a do loop with conditionals outside of the output functions.
<lang lisp>(do ((i 1 (1+ i))) ((> i 10))
(format t "~a~:[, ~;~%~]" i (zerop (mod i 5))))
(do ((i 1 (1+ i))) ((> i 10))
(write i) (when (zerop (mod i 5)) (terpri) (go end)) (write-string ", ") end)
(do ((i 1 (1+ i))) ((> i 10))
(write i) (if (zerop (mod i 5)) (terpri) (write-string ", ")))</lang>
These use the loop
iteration form, which does not contain an implicit tagbody (though one could be explicitly included).
The first uses an explicit condition to omit the rest of the loop;
the second uses block
/return-from
to obtain the effect of skipping the rest of the code in the block
which makes up the entire loop body.
<lang lisp>(loop for i from 1 to 10
do (write i) if (zerop (mod i 5)) do (terpri) else do (write-string ", "))
(loop for i from 1 to 10 do
(block continue (write i) (when (zerop (mod i 5)) (terpri) (return-from continue)) (write-string ", ")))</lang>
D
<lang d>import std.stdio;
void main() {
foreach (i; 1 .. 11) { write(i); if (i % 5 == 0) { writeln(); continue; } write(", "); }
}</lang>
- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
dc
The four commands # n J M are special to OpenBSD dc. The # command starts a comment. The n command prints a number without a newline.
<lang dc>1 si # i = 1 [2Q]sA # A = code to break loop [[, ]P 1J]sB # B = code to print comma, continue loop [
li n # print i li 5 % 0 !=B # call B if i % 5 [
]P # print newline
M # mark from calling B li 1 + si # i += 1 li 10!<C # continue loop if 10 >= i
]sC li 10!<C # enter loop if 10 >= i</lang>
This program uses J and M to force the next iteration of a loop. The nJ command breaks n levels of brackets (like nQ does so), but then skips to the next M command. One can place M at the end of the iteration.
Delphi
<lang Delphi>program DoLoop(output); var
i: integer;
begin
for i := 1 to 10 do begin write(i); if i mod 5 = 0 then begin writeln; continue; end; write(', '); end;
end.</lang>
- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
DWScript
<lang Delphi>var i : Integer;
for i := 1 to 10 do begin
Print(i); if i mod 5 = 0 then begin PrintLn(); continue; end; Print(', ');
end;</lang>
Ela
Direct Approach
<lang ela>open monad io
loop n =
if n > 10 then do return () else do putStr (show n) putStr f loop (n + 1) where f | n % 5 == 0 = "\r\n" | else = ", "
_ = loop 1 ::: IO</lang>
Using list
<lang ela>open monad io
loop [] = return () loop (x::xs) = do
putStr (show x) putStr f loop xs where f | x % 5 == 0 = "\r\n" | else = ", "
_ = loop [1..10] ::: IO</lang>
This version is more generic and can work for any given range of values.
Elixir
<lang elixir>defmodule Loops do
def continue do Enum.each(1..10, fn i -> IO.write i IO.write if rem(i,5)==0, do: "\n", else: ", " end) end
end
Loops.continue</lang>
- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
Erlang
<lang erlang>%% Implemented by Arjun Sunel -module(continue). -export([main/0, for_loop/1]).
main() -> for_loop(1).
for_loop(N) when N /= 5 , N <10 -> io:format("~p, ",[N] ), for_loop(N+1);
for_loop(N) when N >=10-> if N=:=10 -> io:format("~p\n",[N] ) end;
for_loop(N) -> if N=:=5 -> io:format("~p\n",[N] ), for_loop(N+1) end. </lang>
- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10 ok
ERRE
<lang ERRE> FOR I=1 TO 10 DO
PRINT(I;CHR$(29);) ! printing a numeric value leaves a blank after it ! chr$(29) delete it..... IF I MOD 5=0 THEN PRINT CONTINUE FOR END IF PRINT(",";)
END FOR PRINT </lang>
Euphoria
<lang euphoria>include std\console.e --only for any_key to make running command window easier on windows
for i = 1 to 10 do
if remainder(i,5) = 0 then printf(1, "%d\n", i) else printf(1,"%d, ", i) continue end if
end for any_key()</lang> Version without newline after 10 below. <lang euphoria>include std\console.e --only for any_key to make running command window easier on windows
for i = 1 to 10 do
if remainder(i,5) = 0 then switch i do case 10 then printf(1,"%d ",i) break --new to euphoria 4.0.0+ case else printf(1,"%d\n", i) end switch else printf(1,"%d, ", i) continue --new to euphoria 4.0.0+ end if
end for any_key() </lang>
F#
continue
is a reserved word, but it has no function.
In any case, it is not needed to complete this task.
<lang fsharp>for i in 1 .. 10 do
printf "%d" i if i % 5 = 0 then printf "\n" else printf ", "</lang>
Factor
There is no built-in continue
in Factor.
<lang factor>1 10 [a,b] [
[ number>string write ] [ 5 mod 0 = "\n" ", " ? write ] bi
] each</lang>
Fantom
While and for loops support continue
to jump back to begin the next iteration of the loop.
<lang fantom> class LoopsContinue {
public static Void main () { for (Int i := 1; i <= 10; ++i) { Env.cur.out.print (i) if (i % 5 == 0) { Env.cur.out.printLine ("") continue } Env.cur.out.print (", ") } Env.cur.out.printLine ("") }
} </lang>
Forth
Although this code solves the task, there is no portable equivalent to "continue" for either DO-LOOPs or BEGIN loops. <lang forth>: main
11 1 do i dup 1 r. 5 mod 0= if cr else [char] , emit space then loop ;</lang>
Fortran
<lang fortran>do i = 1, 10
write(*, '(I0)', advance='no') i if ( mod(i, 5) == 0 ) then write(*,*) cycle end if write(*, '(A)', advance='no') ', '
end do</lang>
<lang fortran>C WARNING: This program is not valid ANSI FORTRAN 77 code. It uses C one nonstandard character on the line labelled 5001. Many F77 C compilers should be okay with it, but it is *not* standard. C C It is also worth noting that FORTRAN 77 uses the command CONTINUE, C but not in the semantic, looping sense of the word. In FORTRAN, C CONTINUE means "do absolutely nothing." It is a placeholder. If C anything, it means "continue to the next line." C C Python does the same thing with `pass`; C and its family of C languages, with `{/* do nothing */}`. Write CONTINUE when you need C to write something but have nothing to write. C C This page on Rosetta Code is about a very different "continue" C statement that tells a loop to go back to the beginning. In C FORTRAN, we use (you guessed it!) a GOTO to accomplish this.
PROGRAM CONTINUELOOP INTEGER I
DO 10 I = 1, 10
C Is it five or ten?
IF (MOD(I, 5) .EQ. 0) THEN
C If it is, write a newline and no comma.
WRITE (*,5000) I
C Continue the loop; that is, skip to the end of the loop.
GOTO 10 ENDIF
C Write I with a comma and no newline.
WRITE (*,5001) I
C Again, in this case, CONTINUE is completely unrelated to the C semantic, looping sense of the word.
10 CONTINUE
STOP
C This will print an integer and a newline (no comma).
5000 FORMAT (I3)
C Standard FORTRAN 77 is completely incapable of completing a C WRITE statement without printing a newline. If you want to print C five integers in standard code, you have to do something like C this: C C FORMAT (I3, ',', I3, ',', I3, ',', I3, ',', I3) C C Writing `1, 2, 3, 4, 5` and then `6, 7, 8, 9, 10` to that format C would produce the following two lines: C C 1, 2, 3, 4, 5 C 6, 7, 8, 9, 10 C C However, this code exists to demonstrate continuing a FORTRAN 77 C loop and not to demonstrate how to get around its rigidity about C newlines. C C The dollar sign at the end of the format is a nonstandard C character. It tells the compiler not to print a newline. If you C are actually using FORTRAN 77, you should figure out what your C particular compiler accepts. If you are actually using Fortran C 90 or later, you should replace this line with the commented C line that follows it.
5001 FORMAT (I3, ',', $)
C5001 FORMAT (I3, ',', ADVANCE='NO')
END</lang>
Relying instead upon the looping features of FORMAT
For historical reasons, 6 is often the default unit number for standard output. <lang Fortran>
WRITE (6,1) (I,I = 1,10) 1 FORMAT (4(1X,I0,","),1X,I0) END
</lang> Here the break and continuation comes through the workings of the FORMAT interpreter. The feature 4(etc) means four repetitions of the format items within the brackets, and as each datum from the WRITE statement arrives, it is aligned with the next format item that can receive a datum, the I-format specifier (here I0, which means an integer of only as many digits as are needed for the value) and until such a reciever is encountered, intervening format items are acted upon - 1X means "one space", and the quotes surround a text literal. Accordingly, the first datum generates a space, a one-digit value, and a comma, as does the second and so on. When the sixth datum is received, the end of the format statement has been reached, and the convention is to write the current line and start a new line of output, and further, go back in the FORMAT specification to the first-encountered open-bracket symbol (the rightmost) which in this case is not the beginning of the FORMAT statement but the one that has a repetition count of four in front of it, and, resume interpretation. When the last datum has been accepted, naturally, the line is printed.
An alternative might be FORMAT (4(I2,","),I2) but that would generate
1, 2, 3, 4, 5 6, 7, 8, 9,10
Alternatively, FORMAT (4(I2,","),I2,/,4(I2,","),I3) would do the trick but there would no longer be the loop, break, continue aspect to the interpretation of the FORMAT statement, merely a grinding through a list.
This sort of scheme facilitates a compact way of printing a table with a heading, where the WRITE statement simply pours forth the data and relies on something like FORMAT("heading",/,(complex details for one line)) - thus printing the table line-by-line with only the first line having the heading, a saving on having a write and format statement pair for the heading and a second pair for the table body.
GAP
<lang gap>for i in [1 .. 11] do
if RemInt(i, 5) = 0 then Print(i, "\n"); continue; fi; Print(i, ", ");
od;
- 1, 2, 3, 4, 5
- 6, 7, 8, 9, 10</lang>
GML
<lang GML>for(i = 1; i <= 10; i += 1)
{ show_message(string(i)) i += 1 if(i <= 10) continue }</lang>
Go
<lang go>package main
import "fmt"
func main() {
for i := 1; i <= 10; i++ { fmt.Printf("%d", i) if i%5 == 0 { fmt.Printf("\n") continue } fmt.Printf(", ") }
}</lang>
- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
Groovy
<lang groovy>for (i in 1..10) {
print i if (i % 5 == 0) { println () continue } print ', '
}</lang>
Haskell
As a functional language, it is not idiomatic to have true loops - recursion is used instead. Below is one of many possible implementations of the task. The below code uses a guard (| symbol) to compose functions differently for the two alternative output paths, instead of using continue like in an imperative language.
<lang haskell>import Control.Monad (forM) main = forM [1..10] out
where out x | x `mod` 5 == 0 = print x | otherwise = (putStr . (++", ") . show) x</lang>
HicEst
<lang hicest>DO i = 1, 10
IF( MOD(i, 5) == 1 ) THEN WRITE(Format="i3") i ELSE WRITE(APPend, Format=" ',', i3 ") i ENDIF
ENDDO </lang>
Icon and Unicon
The following code demonstrates the use of 'next' (the reserved word for 'continue'): <lang Icon>procedure main() every writes(x := 1 to 10) do {
if x % 5 = 0 then { write() next } writes(", ") }
end</lang> However, the output sequence can be written without 'next' and far more succinctly as: <lang Icon>every writes(x := 1 to 10, if x % 5 = 0 then "\n" else ", ")</lang>
Io
<lang io>for(i,1,10,
write(i) if(i%5 == 0, writeln() ; continue) write(" ,")
)</lang>
J
J is array-oriented, so there is very little need for loops. For example, one could satisfy this task this way:
<lang j>_2}."1'lq<, >'8!:2>:i.2 5</lang>
J does support loops for those times they can't be avoided (just like many languages support gotos for those time they can't be avoided). <lang j>3 : 0 ] 10
z=. for_i. 1 + i.y do. z =. z , ": i
if. 0 = 5 | i do. z 1!:2 ]2 z =. continue. end.
z =. z , ', ' end. i.0 0 )</lang>
Though it's rare to see J code like this.
Java
<lang java>for(int i = 1;i <= 10; i++){
System.out.print(i); if(i % 5 == 0){ System.out.println(); continue; } System.out.print(", ");
}</lang>
JavaScript
Using the print()
function from Rhino or SpiderMonkey.
<lang javascript>var output = "";
for (var i = 1; i <= 10; i++) {
output += i; if (i % 5 == 0) { print(output); output = ""; continue; } output += ", ";
}</lang>
Stepping back from any assumption that repetitive patterns of computation necessarily entail 'loops', and using a functional idiom of JavaScript, we can make the value of one or more subexpressions in a reduce() fold conditional on any special cases that we define.
For example:
<lang JavaScript>function rng(n) {
return n ? rng(n - 1).concat(n) : [];
}
console.log(
rng(10).reduce( function (a, x) { return a + x.toString() + (x % 5 ? ', ' : '\n'); }, )
);</lang>
Output: <lang JavaScript>1, 2, 3, 4, 5 6, 7, 8, 9, 10 </lang>
jq
jq does not have a "continue" statement. In jq 1.4, the simplest way to accomplish the given task is probably as follows: <lang jq>reduce range(1;11) as $i
(""; . + "\($i)" + (if $i % 5 == 0 then "\n" else ", " end))</lang>
Julia
<lang Julia> for i in 1:10
print(i) if i%5 == 0 println() continue end print(", ")
end </lang>
- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
Lasso
<lang Lasso>loop(10) => {^ loop_count loop_count % 5 ? ', ' | '\r' loop_count < 100 ? loop_continue 'Hello, World!' // never gets executed ^}</lang>
Liberty BASIC
<lang lb> for i =1 to 10
if i mod 5 <>0 then print i; ", "; else print i
next i end </lang>
Lisaac
<lang Lisaac>1.to 10 do { i : INTEGER;
i.print; (i % 5 = 0).if { '\n'.print; } else { ','.print; };
};</lang>
LiveCode
<lang LiveCode>repeat with n = 1 to 10
put n if n is 5 then put return if n < 10 and n is not 5 then put ","
end repeat</lang>
Lua
<lang Lua>for i = 1, 10 do
io.write( i ) if i % 5 == 0 then io.write( "\n" ) else io.write( ", " ) end
end</lang>
Maple
<lang Maple>for i from 1 to 10 do
printf( "%d", i ); if irem( i, 5 ) = 0 then printf( "\n" ); next end if; printf( ", " )
end do:</lang>
This can also be done as follows, but without the use of "next". <lang Maple>for i to 10 do
printf( "%d%s", i, `if`( irem( i, 5 ) = 0, "\n", ", " ) )
end do:</lang>
Mathematica
<lang Mathematica>tmp = ""; For[i = 1, i <= 10, i++,
tmp = tmp <> ToString[i]; If[Mod[i, 5] == 0, tmp = tmp <> "\n"; , tmp = tmp <> ", "; ]; ];
Print[tmp]</lang>
MATLAB / Octave
Loops are considered slow in Matlab and Octave, it is preferable to vectorize the code. <lang Matlab>disp([1:5; 6:10])</lang> or <lang Matlab>disp(reshape([1:10],5,2)')</lang>
A non-vectorized version of the code is shown below in Octave
<lang Matlab>for i = 1:10
printf(' %2d', i); if ( mod(i, 5) == 0 ) printf('\n'); continue end
end</lang>
Maxima
<lang maxima>/* There is no "continue" in Maxima, the easiest is using a "if" instead */ block(
[s: ""], for n thru 10 do ( s: sconcat(s, n), if mod(n, 5) = 0 then ( ldisp(s), s: "" ) else ( s: sconcat(s, ", ") ) )
)$</lang>
MAXScript
<lang maxscript>for i in 1 to 10 do (
format "%" i if mod i 5 == 0 then ( format "\n" continue ) continue format ", "
)</lang> Insert non-formatted text here
Metafont
Metafont has no a continue (or similar) keyword. As the Ada solution, we can complete the task just with conditional.
<lang metafont>string s; s := ""; for i = 1 step 1 until 10: if i mod 5 = 0:
s := s & decimal i & char10;
else:
s := s & decimal i & ", "
fi; endfor message s; end</lang>
Since message append always a newline at the end, we need to build a string and output it at the end, instead of writing the output step by step.
Note: mod is not a built in; like TeX, "bare Metafont" is rather primitive, and normally a set of basic macros is preloaded to make it more usable; in particular mod is defined as
<lang metafont>primarydef x mod y = (x-y*floor(x/y)) enddef;</lang>
Modula-3
Modula-3 defines the keyword RETURN as an exception, but when it is used with no arguments it works just like continue in C.
Note, however, that RETURN only works inside a procedure or a function procedure; use EXIT otherwise.
Module code and imports are omitted. <lang modula3>FOR i := 1 TO 10 DO
IO.PutInt(i); IF i MOD 5 = 0 THEN IO.Put("\n"); RETURN; END; IO.Put(", ");
END;</lang>
MOO
<lang moo>s = ""; for i in [1..10]
s += tostr(i); if (i % 5 == 0) player:tell(s); s = ""; continue; endif s += ", ";
endfor</lang>
Nemerle
<lang Nemerle>using System; using System.Console; using Nemerle.Imperative;
module Continue {
Main() : void { foreach (i in [1 .. 10]) { Write(i); when (i % 5 == 0) {WriteLine(); continue;} Write(", "); } }
}</lang>
NetRexx
<lang NetRexx>/* NetRexx */ options replace format comments java crossref savelog symbols nobinary
say say 'Loops/Continue'
nul = '\-' loop i_ = 1 to 10 say i_.right(2) || nul if i_ // 5 = 0 then do say iterate i_ end say ', ' || nul end i_
</lang>
NewLISP
<lang NewLISP>(for (i 1 10)
(print i) (if (= 0 (% i 5)) (println) (print ", ")))</lang>
Nim
<lang nim>for i in 1..10:
if i mod 5 == 0: echo i continue stdout.write i, ","</lang>
OCaml
There is no continue statement for for loops in OCaml, but it is possible to achieve the same effect with an exception. <lang ocaml># for i = 1 to 10 do
try print_int i; if (i mod 5) = 0 then raise Exit; print_string ", " with Exit -> print_newline() done ;;
1, 2, 3, 4, 5 6, 7, 8, 9, 10 - : unit = ()</lang> Though even if the continue statement does not exist, it is possible to add it with camlp4.
Octave
<lang octave>v = ""; for i = 1:10
v = sprintf("%s%d", v, i); if ( mod(i, 5) == 0 ) disp(v) v = ""; continue endif v = sprintf("%s, ", v);
endfor</lang>
Oforth
<lang Oforth>: loopCont | i |
10 loop: i [ i dup print 5 mod ifZero: [ printcr continue ] "," . ] ;</lang>
Oz
By using the "continue" feature of the for-loop, we bind C to a nullary procedure which, when invoked, immediately goes on to the next iteration of the loop. <lang oz>for I in 1..10 continue:C do
{System.print I} if I mod 5 == 0 then {System.printInfo "\n"} {C} end {System.printInfo ", "}
end</lang>
PARI/GP
<lang parigp>for(n=1,10,
print1(n); if(n%5 == 0, print();continue); print1(", ")
)</lang>
Pascal
See Delphi
Perl
<lang perl>foreach (1..10) {
print $_; if ($_ % 5 == 0) { print "\n"; next; } print ', ';
}</lang>
It is also possible to use a goto statement to jump over the iterative code section for a particular loop:
<lang perl>foreach (1..10) {
print $_; if ($_ % 5 == 0) { print "\n"; goto MYLABEL; } print ', ';
MYLABEL: }</lang>
Perl 6
<lang perl6>for 1 .. 10 {
.print; if $_ %% 5 { print "\n"; next; } print ', ';
}</lang>
or without using a loop:
<lang perl6>$_.join(", ").say for [1..5], [6..10];</lang>
Phix
<lang Phix>for i=1 to 10 do
printf(1,"%d", i) if remainder(i,5)=0 then printf(1, "\n") continue end if printf(1,", ")
end for {} = wait_key()</lang>
PHP
<lang php>for ($i = 1; $i <= 10; $i++) {
echo $i; if ($i % 5 == 0) { echo "\n"; continue; } echo ', ';
}</lang>
PicoLisp
PicoLisp doesn't have an explicit 'continue' functionality. It can always be emulated with a conditional expression. <lang PicoLisp>(for I 10
(print I) (if (=0 (% I 5)) (prinl) (prin ", ") ) )</lang>
Pike
<lang pike>int main(){
for(int i = 1; i <= 10; i++){ write(sprintf("%d",i)); if(i % 5 == 0){ write("\n"); continue; } write(", "); }
}</lang>
PL/I
<lang pli>loop: do i = 1 to 10;
put edit (i) (f(3)); if mod(i,5) = 0 then do; put skip; iterate loop; end; put edit (', ') (a);
end;</lang>
Pop11
<lang pop11>lvars i; for i from 1 to 10 do
printf(i, '%p'); if i rem 5 = 0 then printf('\n'); nextloop; endif; printf(', ')
endfor;</lang>
PowerShell
<lang powershell>for ($i = 1; $i -le 10; $i++) {
Write-Host -NoNewline $i if ($i % 5 -eq 0) { Write-Host continue } Write-Host -NoNewline ", "
}</lang>
PureBasic
<lang purebasic>OpenConsole()
For i.i = 1 To 10
Print(Str(i)) If i % 5 = 0 PrintN("") Continue EndIf Print(",")
Next
Repeat: Until Inkey() <> ""</lang>
Python
<lang python>for i in xrange(1,11):
if i % 5 == 0: print i continue print i, ",",</lang>
R
<lang R>for(i in 1:10) {
cat(i) if(i %% 5 == 0) { cat("\n") next } cat(", ")
}</lang>
Racket
It is possible to skip loop iterations in Racket, but an explicit continue construct is rarely used:
<lang racket>
- lang racket
- Idiomatic way
(for ([i (in-range 1 11)])
(if (= (remainder i 5) 0) (printf "~a~n" i) (printf "~a, " i)))
- Forces a skip, but not idiomatic because
- the logic is less obvious
(for ([i (in-range 1 11)]
#:unless (and (= (remainder i 5) 0) (printf "~a~n" i))) (printf "~a, " i))
</lang>
REBOL
<lang REBOL>REBOL [ Title: "Loop/Continue" Author: oofoe Date: 2010-01-05 URL: http://rosettacode.org/wiki/Loop/Continue ]
- REBOL does not provide a 'continue' word for loop constructs,
- however, you may not even miss it
print "One liner (compare to ALGOL 68 solution):" repeat i 10 [prin rejoin [i either 0 = mod i 5 [crlf][", "]]]
print [crlf "Port of ADA solution:"] for i 1 10 1 [ prin i either 0 = mod i 5 [ prin newline ][ prin ", " ] ]</lang>
- Output:
One liner (compare to ALGOL 68 solution): 1, 2, 3, 4, 5 6, 7, 8, 9, 10 Port of ADA solution: 1, 2, 3, 4, 5 6, 7, 8, 9, 10
REXX
version 1
(This program could be simpler by using a then/else construct, but an iterate was used to conform to the task.) <lang rexx>/*REXX program illustrates an example of a DO loop with an ITERATE (continue). */
do j=1 for 10 /*this is equivalent to: DO J=1 TO 10 */ call charout , j /*write the integer to the terminal. */ if j//5\==0 then do /*Not a multiple of five? Then ··· */ call charout , ", " /* write a comma to the terminal, ··· */ iterate /* ··· & then go back for next integer.*/ end say /*force REXX to display on next line. */ end /*j*/ /*stick a fork in it, we're all done. */</lang>
Program note: the comma (,) immediately after the charout BIF indicates to use the terminal output stream.
output
1, 2, 3, 4, 5 6, 7, 8, 9, 10
version 2
<lang rexx>/*REXX program illustrates an example of a DO loop with an ITERATE (continue). */ $= /*nullify the variable used for display*/
do j=1 for 10 /*this is equivalent to: DO J=1 TO 10 */ $=$ || j', ' /*append the integer to a placeholder. */ if j//5==0 then say left($, length($) - 2) /*Is J a multiple of five? Then SAY.*/ if j==5 then $= /*start the display line over again. */ end /*j*/ /*stick a fork in it, we're all done. */</lang>
output is the same as the 1st REXX version.
Ring
<lang ring> for i = 1 TO 10
see i if i % 5 = 0 see nl loop ok see ", "
next </lang>
Ruby
<lang ruby>for i in 1..10 do
print i if i % 5 == 0 then puts next end print ', '
end</lang> The "for" look could be written like this: <lang ruby>(1..10).each do |i| ... 1.upto(10) do |i| ... 10.times do |n| i=n+1; ...</lang> Without meeting the criteria (showing loop continuation), this task could be written as: <lang ruby>(1..10).each_slice(5){|ar| puts ar.join(", ")}</lang>
Run BASIC
<lang runbasic>for i = 1 to 10
if i mod 5 <> 0 then print i;", "; else print i
next i</lang>
Rust
<lang rust>fn main() {
for i in 1..10+1 { print!("{}", i); if i % 5 == 0 { print!("\n"); continue; } print!(", "); }
}</lang>
Salmon
<lang Salmon>iterate (x; [1...10])
{ print(x); if (x % 5 == 0) { print("\n"); continue; }; print(", "); };</lang>
Sather
There's no continue!
in Sather. The code solve the task without forcing a new iteration.
<lang sather>class MAIN is
main is i:INT; loop i := 1.upto!(10); #OUT + i; if i%5 = 0 then #OUT + "\n"; else #OUT + ", "; end; end; end;
end;</lang>
Scala
Scala doesn't have a continue
keyword.
However, you may not even miss it, if
could be used here.
The intuitive way
<lang scala>for (i <- 1 to 10) {
print(i) if (i % 5 == 0) println() else print(", ") }</lang>
Functional solution
Thinking In Scala© says: we avoid for loops and handle it the Functional way:
- Create a Range 1..10 included
- Split the range after converting to a List to a pair of List's
- A List of the elements of pair of will be created: List(List(1,2,3,4,5),List(6,7,8,9,10))
- The map makes for both elements in the List a conversion to a comma separated String, yielding a List of two Strings.
- Both comma separated strings will be separated by an EOL
<lang scala> val a = (1 to 10 /*1.*/ ).toList.splitAt(5) //2.
println(List(a._1, a._2) /*3.*/ .map(_.mkString(", ") /*4.*/ ).mkString("\n") /*5.*/ )</lang>
Scheme
<lang scheme>(define (loop i)
(if (> i 10) 'done (begin (display i) (cond ((zero? (modulo i 5)) (newline) (loop (+ 1 i))) (else (display ", ") (loop (+ 1 i)))))))</lang>
Scilab
<lang>for i=1:10
printf("%2d ",i) if modulo(i,5)~=0 then printf(", ") continue end printf("\n")
end </lang>
- Output:
1 , 2 , 3 , 4 , 5 6 , 7 , 8 , 9 , 10
Sidef
<lang ruby>for i in (1..10) {
print i if (i %% 5) { print "\n" next } print ', '
}</lang>
Suneido
<lang Suneido>ob = Object() for (i = 1; i <= 10; ++i)
{ ob.Add(i) if i is 5 { Print(ob.Join(',')) ob = Object() } }
Print(ob.Join(','))</lang>
- Output:
<lang Suneido>1,2,3,4,5 6,7,8,9,10 ok</lang>
Swift
<lang swift>for i in 1...10 {
print(i) if i%5 == 0 { println() continue } print(", ")
}</lang>
- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
Tcl
<lang tcl>for {set i 1} {$i <= 10} {incr i} {
puts -nonewline $i if {$i % 5 == 0} { puts "" continue } puts -nonewline ", "
}</lang>
TI-89 BASIC
<lang ti-89>count() Prgm
""→s For i,1,10 s&string(i)→s If mod(i,5)=0 Then Disp s ""→s Cycle EndIf s&", "→s EndFor
EndPrgm</lang>
Ti-89 lacks support for multi-argument display command or controlling the print position so that one can print several data on the same line. The display command (Disp) only accepts one argument and prints it on a single line (causing a line a feed at the end, so that the next Disp command will print in the next line). The solution is appending data to a string (s), using the concatenator operator (&), by converting numbers to strings, and then printing the string at the end of the line.
TUSCRIPT
<lang tuscript> $$ MODE TUSCRIPT numbers="" LOOP n=1,10 numbers=APPEND (numbers,", ",n) rest=n%5 IF (rest!=0) CYCLE
PRINT numbers numbers=""
ENDLOOP </lang>
- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
UnixPipes
<lang bash>yes \ | cat -n | head -n 10 | xargs -n 5 echo | tr ' ' ,</lang>
UNIX Shell
<lang bash>Z=1 while (( Z<=10 )); do
echo -e "$Z\c" if (( Z % 5 != 0 )); then echo -e ", \c" else echo -e "" fi (( Z++ ))
done</lang>
<lang bash>for ((i=1;i<=10;i++)); do
echo -n $i if [ $((i%5)) -eq 0 ]; then echo continue fi echo -n ", "
done</lang>
Ursa
<lang ursa>decl int i for (set i 1) (< i 11) (inc i)
if (= (mod i 5) 0) out i endl console continue end if out i ", " console
end for</lang>
Vedit macro language
<lang vedit>for (#1 = 1; #1 <= 10; #1++) {
Num_Type(#1, LEFT+NOCR) if (#1 % 5 == 0) { Type_Newline Continue } Message(", ")
}</lang>
Visual Basic .NET
<lang vbnet>For i = 1 To 10
Console.Write(i) If i Mod 5 = 0 Then Console.WriteLine() Else Console.Write(", ") End If
Next</lang>
XPL0
Like Ada and ALGOL there's no 'continue' command. The task is solved very simply anyway. The commands 'int' and 'rem' are shown spelled out here. Only the first three characters of a command are required.
<lang XPL0>code CrLf=9, IntOut=11, Text=12; integer N; for N:= 1 to 10 do
[IntOut(0, N); if remainder(N/5) \#0\ then Text(0, ", ") else CrLf(0)]</lang>
- Output:
1, 2, 3, 4, 5 6, 7, 8, 9, 10
zkl
<lang zkl>foreach n in ([1..10]){print(n); if(n%5==0){println(); continue;} print(", ")} // or foreach n in ([1..10]){print(n,(n%5) and ", " or "\n")}</lang>
- Programming Tasks
- Iteration
- Loop modifiers
- GUISS/Omit
- M4/Omit
- 360 Assembly
- Ada
- Aikido
- ALGOL 68
- Applesoft BASIC
- AutoHotkey
- AWK
- BBC BASIC
- Bc
- C
- C++
- C sharp
- Chapel
- Clipper
- Clojure
- COBOL
- ColdFusion
- Common Lisp
- D
- Dc
- Delphi
- DWScript
- Ela
- Elixir
- Erlang
- ERRE
- Euphoria
- F Sharp
- Factor
- Fantom
- Forth
- Fortran
- GAP
- GML
- Go
- Groovy
- Haskell
- HicEst
- Icon
- Unicon
- Io
- J
- Java
- JavaScript
- Jq
- Julia
- Lasso
- Liberty BASIC
- Lisaac
- LiveCode
- Lua
- Maple
- Mathematica
- MATLAB
- Octave
- Maxima
- MAXScript
- Metafont
- Modula-3
- MOO
- Nemerle
- NetRexx
- NewLISP
- Nim
- OCaml
- Oforth
- Oz
- PARI/GP
- Pascal
- Perl
- Perl 6
- Phix
- PHP
- PicoLisp
- Pike
- PL/I
- Pop11
- PowerShell
- PureBasic
- Python
- R
- Racket
- REBOL
- REXX
- Ring
- Ruby
- Run BASIC
- Rust
- Salmon
- Sather
- Scala
- Scheme
- Scilab
- Sidef
- Suneido
- Swift
- Tcl
- TI-89 BASIC
- TUSCRIPT
- UnixPipes
- UNIX Shell
- Ursa
- Vedit macro language
- Visual Basic .NET
- XPL0
- Zkl