Sum of elements below main diagonal of matrix

From Rosetta Code
Task
Sum of elements below main diagonal of matrix
You are encouraged to solve this task according to the task description, using any language you may know.
Task

Find and display the sum of elements that are below the main diagonal of a matrix.

The matrix should be a square matrix.


───   Matrix to be used:   ───

     [[1,3,7,8,10],
      [2,4,16,14,4],
      [3,1,9,18,11],
      [12,14,17,18,20],
      [7,1,3,9,5]] 



11l

Translation of: Nim
F sumBelowDiagonal(m)
   V result = 0
   L(i) 1 .< m.len
      L(j) 0 .< i
         result += m[i][j]
   R result

V m = [[ 1,  3,  7,  8, 10],
       [ 2,  4, 16, 14,  4],
       [ 3,  1,  9, 18, 11],
       [12, 14, 17, 18, 20],
       [ 7,  1,  3,  9,  5]]

print(sumBelowDiagonal(m))
Output:
69

Action!

PROC PrintMatrix(INT ARRAY m BYTE size)
  BYTE x,y
  INT v

  FOR y=0 TO size-1
  DO
    FOR x=0 TO size-1
    DO
      v=m(x+y*size)
      IF v<10 THEN Put(32) FI
      PrintB(v) Put(32)
    OD
    PutE()
  OD
RETURN

INT FUNC SumBelowDiagonal(INT ARRAY m BYTE size)
  BYTE x,y
  INT sum

  sum=0
  FOR y=1 TO size-1
  DO
    FOR x=0 TO y-1
    DO
      sum==+m(x+y*size)
    OD
  OD
RETURN (sum)

PROC Main()
  INT sum
  INT ARRAY m=[
     1  3  7  8 10
     2  4 16 14  4
     3  1  9 18 11
    12 14 17 18 20
     7  1  3  9  5]

  PrintE("Matrix")
  PrintMatrix(m,5)
  PutE()
  sum=SumBelowDiagonal(m,5)
  PrintF("Sum below diagonal is %I",sum)
RETURN
Output:

Screenshot from Atari 8-bit computer

Matrix
 1  3  7  8 10
 2  4 16 14  4
 3  1  9 18 11
12 14 17 18 20
 7  1  3  9  5

Sum below diagonal is 69

Ada

with Ada.Text_Io;
with Ada.Numerics.Generic_Real_Arrays;

procedure Sum_Below_Diagonals is

   type Real is new Float;

   package Real_Arrays
   is new Ada.Numerics.Generic_Real_Arrays (Real);

   function Sum_Below_Diagonal (M : Real_Arrays.Real_Matrix) return Real
   with Pre => M'Length (1) = M'Length (2)
   is
      Sum : Real := 0.0;
   begin
      for Row in 0 .. M'Length (1) - 1 loop
         for Col in 0 .. Row - 1 loop
            Sum := Sum + M (M'First (1) + Row,
                            M'First (2) + Col);
         end loop;
      end loop;
      return Sum;
   end Sum_Below_Diagonal;

   M : constant Real_Arrays.Real_Matrix :=
     (( 1.0,  3.0,  7.0,  8.0, 10.0),
      ( 2.0,  4.0, 16.0, 14.0,  4.0),
      ( 3.0,  1.0,  9.0, 18.0, 11.0),
      (12.0, 14.0, 17.0, 18.0, 20.0),
      ( 7.0,  1.0,  3.0,  9.0,  5.0));
   Sum : constant Real := Sum_Below_Diagonal (M);

   package Real_Io is new Ada.Text_Io.Float_Io (Real);
   use Ada.Text_Io, Real_Io;
begin
   Put ("Sum below diagonal: ");
   Put (Sum, Exp => 0, Aft => 1);
   New_Line;
end Sum_Below_Diagonals;
Output:
Sum below diagonal: 69.0

ALGOL 68

BEGIN # sum the elements below the main diagonal of a matrix  #
    # returns the sum of the elements below the main diagonal #
    # of m, m must be a square matrix                         #
    OP   LOWERSUM = ( [,]INT m )INT:
         IF 1 LWB m /= 2 LWB m OR 1 UPB m /= 2 UPB m THEN
            # the matrix isn't square                         #
            print( ( "Matrix must be suare for LOWERSUM", newline ) );
            stop
         ELSE
            # have a square matrix                            #
            INT sum := 0;
            FOR r FROM 1 LWB m + 1 TO 1 UPB m DO
                 FOR c FROM 1 LWB m TO r - 1 DO
                     sum +:= m[ r, c ]
                 OD
            OD;
            sum
         FI; # LOWERSUM #
    # task test case                                          #
    print( ( whole( LOWERSUM [,]INT( (  1,  3,  7,  8, 10 )
                                   , (  2,  4, 16, 14,  4 )
                                   , (  3,  1,  9, 18, 11 )
                                   , ( 12, 14, 17, 18, 20 )
                                   , (  7,  1,  3,  9,  5 )
                                   )
                  , 0
                  )
            , newline
            )
          )
END
Output:
69

ALGOL W

One of the rare occasions where the lack of lower/upper bound operators in Algol W actually simplifies things, assuming the programmer gets things right...

begin % sum the elements below the main diagonal of a matrix  %
    % returns the sum of the elements below the main diagonal %
    % of m, m must have bounds lb :: ub, lb :: ub             %
    integer procedure lowerSum ( integer array m ( *, * )
                               ; integer value lb, ub
                               ) ;
    begin
        integer sum;
        sum := 0;
        for r := lb + 1 until ub do begin
             for c := lb until r - 1 do sum := sum + m( r, c )
        end for_r;
        sum
    end lowerSum ;
    begin % task test case                                    %
        integer array m ( 1 :: 5, 1 :: 5 );
        integer r, c;
        r := 1; c := 0; for v :=  1,  3,  7,  8, 10 do begin c := c + 1; m( r, c ) := v end;
        r := 2; c := 0; for v :=  2,  4, 16, 14,  4 do begin c := c + 1; m( r, c ) := v end;
        r := 3; c := 0; for v :=  3,  1,  9, 18, 11 do begin c := c + 1; m( r, c ) := v end;
        r := 4; c := 0; for v := 12, 14, 17, 18, 20 do begin c := c + 1; m( r, c ) := v end;
        r := 5; c := 0; for v :=  7,  1,  3,  9,  5 do begin c := c + 1; m( r, c ) := v end;
        write( i_w := 1, lowerSum( m, 1, 5 ) )
    end
end.
Output:
69

APL

Works with: Dyalog APL
sum_below_diagonal  +/(∊⊢×(>))
Output:
      matrix ← 5 5⍴1 3 7 8 10 2 4 16 14 4 3 1 9 18 11 12 14 17 18 20 7 1 3 9 5
      sum_below_diagonal matrix
69

Arturo

square?: $[m][every? m 'row -> equal? size row size m]

sumBelow: function [m][
    ensure -> square? m
    fold.seed: 0 .with:'i m [a b] -> a + sum take b i
]

m: [[1  3  7  8  10]
    [2  4  16 14 4 ]
    [3  1  9  18 11]
    [12 14 17 18 20]
    [7  1  3  9  5 ]] 

print ["Sum below diagonal is" sumBelow m]
Output:
Sum below diagonal is 69

AutoHotkey

matrx :=[[1,3,7,8,10]
		,[2,4,16,14,4]
		,[3,1,9,18,11]
		,[12,14,17,18,20]
		,[7,1,3,9,5]]
sumA := sumB := sumD :=  sumAll := 0
for r, obj in matrx
	for c, val in obj
		sumAll += val
		,sumA += r<c ? val : 0
		,sumB += r>c ? val : 0
		,sumD += r=c ? val : 0

MsgBox % result := "sum above diagonal = " sumA 
. "`nsum below diagonal = " sumB 
. "`nsum on diagonal = " sumD 
. "`nsum all = " sumAll
Output:
sum above diagonal = 111
sum below diagonal = 69
sum on diagonal = 37
sum all = 217

AWK

# syntax: GAWK -f SUM_OF_ELEMENTS_BELOW_MAIN_DIAGONAL_OF_MATRIX.AWK
BEGIN {
    arr1[++n] = "1,3,7,8,10"
    arr1[++n] = "2,4,16,14,4"
    arr1[++n] = "3,1,9,18,11"
    arr1[++n] = "12,14,17,18,20"
    arr1[++n] = "7,1,3,9,5"
    for (i=1; i<=n; i++) {
      x = split(arr1[i],arr2,",")
      if (x != n) {
        printf("error: row %d has %d elements; S/B %d\n",i,x,n)
        errors++
        continue
      }
      for (j=1; j<i; j++) { # below main diagonal
        sum_b += arr2[j]
        cnt_b++
      }
      for (j=i+1; j<=n; j++) { # above main diagonal
        sum_a += arr2[j]
        cnt_a++
      }
      for (j=1; j<=i; j++) { # on main diagonal
        if (j == i) {
          sum_o += arr2[j]
          cnt_o++
        }
      }
    }
    if (errors > 0) { exit(1) }
    printf("%5g Sum of the %d elements below main diagonal\n",sum_b,cnt_b)
    printf("%5g Sum of the %d elements above main diagonal\n",sum_a,cnt_a)
    printf("%5g Sum of the %d elements on main diagonal\n",sum_o,cnt_o)
    printf("%5g Sum of the %d elements in the matrix\n",sum_b+sum_a+sum_o,cnt_b+cnt_a+cnt_o)
    exit(0)
}
Output:
   69 Sum of the 10 elements below main diagonal
  111 Sum of the 10 elements above main diagonal
   37 Sum of the 5 elements on main diagonal
  217 Sum of the 25 elements in the matrix

BASIC

BASIC256

Translation of: FreeBASIC
arraybase 1
dim diag = {{ 1, 3, 7, 8,10}, { 2, 4,16,14, 4}, { 3, 1, 9,18,11}, {12,14,17,18,20}, { 7, 1, 3, 9, 5}}
ind = diag[?,]
sumDiag = 0

for x = 1 to diag[?,]
	for y = 1 to diag[,?]-ind
		sumDiag += diag[x, y]
	next y
	ind -= 1
next x

print "Sum of elements below main diagonal of matrix is "; sumDiag
end

FreeBASIC

Dim As Integer diag(1 To 5, 1 To 5) = { _
    { 1, 3, 7, 8,10}, _
    { 2, 4,16,14, 4}, _
    { 3, 1, 9,18,11}, _
    {12,14,17,18,20}, _
    { 7, 1, 3, 9, 5}}
Dim As Integer lenDiag = Ubound(diag), ind = lenDiag
Dim As Integer sumDiag = 0, x, y

For x = 1 To lenDiag
    For y = 1 To lenDiag-ind
        sumDiag += diag(x, y)
    Next y
    ind -= 1
Next x

Print "Sum of elements below main diagonal of matrix is"; sumDiag
Sleep
Output:
Sum of elements below main diagonal of matrix is 69

GW-BASIC

10 DATA 1,3,7,8,10
20 DATA 2,4,16,14,4
30 DATA 3,1,9,18,11
40 DATA 12,14,17,18,20
50 DATA 7,1,3,9,5
60 FOR ROW = 1 TO 5
70 FOR COL = 1 TO 5
80 READ N
90 IF ROW > COL THEN SUM = SUM + N
100 NEXT COL
110 NEXT ROW
120 PRINT SUM
Output:
69

QBasic

Works with: QBasic
Works with: QuickBasic version 4.5
Translation of: FreeBASIC
DEFINT A-Z

DIM diag(1 TO 5, 1 TO 5)
lenDiag = UBOUND(diag)
ind = lenDiag
sumDiag = 0

FOR x = 1 TO lenDiag
    FOR y = 1 TO lenDiag
        READ diag(x, y)
    NEXT y
NEXT x

FOR x = 1 TO lenDiag
    FOR y = 1 TO lenDiag - ind
        sumDiag = sumDiag + diag(x, y)
    NEXT y
    ind = ind - 1
NEXT x

PRINT "Sum of elements below main diagonal of matrix is"; sumDiag
END

DATA 1, 3, 7, 8,10
DATA 2, 4,16,14, 4
DATA 3, 1, 9,18,11
DATA 12,14,17,18,20
DATA 7, 1, 3, 9, 5

True BASIC

Translation of: FreeBASIC
DIM diag(5, 5)
LET lenDiag = UBOUND(diag, 1)
LET ind = lenDiag
LET sumDiag = 0

DATA 1, 3, 7, 8,10
DATA 2, 4,16,14, 4
DATA 3, 1, 9,18,11
DATA 12,14,17,18,20
DATA 7, 1, 3, 9, 5

FOR x = 1 TO lenDiag
    FOR y = 1 TO lenDiag
        READ diag(x, y)
    NEXT y
NEXT x

FOR x = 1 TO lenDiag
    FOR y = 1 TO lenDiag - ind
        LET sumDiag = sumDiag + diag(x, y)
    NEXT y
    LET ind = ind - 1
NEXT x

PRINT "Sum of elements below main diagonal of matrix:"; sumDiag
END

Yabasic

Translation of: FreeBASIC
dim diag(5, 5)
lenDiag = arraysize(diag(),1)
ind = lenDiag
sumDiag = 0

for x = 1 to lenDiag
    for y = 1 to lenDiag
        read diag(x, y)
    next y
next x

for x = 1 to lenDiag
    for y = 1 to lenDiag-ind
        sumDiag = sumDiag + diag(x, y)
    next y
    ind = ind - 1
next x

print "Sum of elements below main diagonal of matrix: ", sumDiag
end

data 1, 3, 7, 8,10
data 2, 4,16,14, 4
data 3, 1, 9,18,11
data 12,14,17,18,20
data 7, 1, 3, 9, 5


BQN

SumBelowDiagonal  +´⥊⊢×(>⌜´)(¨)

matrix  >⟨⟨ 1, 3, 7, 8,10⟩,
            2, 4,16,14, 4⟩,
            3, 1, 9,18,11⟩,
           12,14,17,18,20⟩,
            7, 1, 3, 9, 5⟩⟩

SumBelowDiagonal matrix
Output:
69

C

Interactive program which reads the matrix from a file :

#include<stdlib.h>
#include<stdio.h>

typedef struct{
	int rows,cols;
	int** dataSet;
}matrix;

matrix readMatrix(char* dataFile){
	FILE* fp = fopen(dataFile,"r");
	matrix rosetta;
	int i,j;
	
	fscanf(fp,"%d%d",&rosetta.rows,&rosetta.cols);
	
	rosetta.dataSet = (int**)malloc(rosetta.rows*sizeof(int*));
	
	for(i=0;i<rosetta.rows;i++){
		rosetta.dataSet[i] = (int*)malloc(rosetta.cols*sizeof(int));
		for(j=0;j<rosetta.cols;j++)
			fscanf(fp,"%d",&rosetta.dataSet[i][j]);
	}
	
	fclose(fp);
	return rosetta;
}

void printMatrix(matrix rosetta){
	int i,j;
	
	for(i=0;i<rosetta.rows;i++){
		printf("\n");
		for(j=0;j<rosetta.cols;j++)
			printf("%3d",rosetta.dataSet[i][j]);
	}
}

int findSum(matrix rosetta){
	int i,j,sum = 0;
	
	for(i=1;i<rosetta.rows;i++){
		for(j=0;j<i;j++){
			sum += rosetta.dataSet[i][j];
		}
	}
	
	return sum;
}

int main(int argC,char* argV[])
{
	if(argC!=2)
		return printf("Usage : %s <filename>",argV[0]);
	
	matrix data = readMatrix(argV[1]);
	
	printf("\n\nMatrix is : \n\n");
	printMatrix(data);
	
	printf("\n\nSum below main diagonal : %d",findSum(data));
	
	return 0;
}

Input Data file, first row specifies rows and columns :

5 5
1 3 7 8 10
2 4 16 14 4
3 1 9 18 11
12 14 17 18 20
7 1 3 9 5

And output follows :

Output:
C:\My Projects\BGI>a.exe rosettaData.txt


Matrix is :


  1  3  7  8 10
  2  4 16 14  4
  3  1  9 18 11
 12 14 17 18 20
  7  1  3  9  5

Sum below main diagonal : 69

C++

#include <iostream>
#include <vector>

template<typename T>
T sum_below_diagonal(const std::vector<std::vector<T>>& matrix) {
    T sum = 0;
    for (std::size_t y = 0; y < matrix.size(); y++)
        for (std::size_t x = 0; x < matrix[y].size() && x < y; x++)
            sum += matrix[y][x];
    return sum;
}

int main() {
    std::vector<std::vector<int>> matrix = {
        {1,3,7,8,10},
        {2,4,16,14,4},
        {3,1,9,18,11},
        {12,14,17,18,20},
        {7,1,3,9,5}
    };
    
    std::cout << sum_below_diagonal(matrix) << std::endl;
    return 0;
}
Output:
69

Delphi

Works with: Delphi version 6.0


type T5Matrix = array[0..4, 0..4] of Double;

var TestMatrix: T5Matrix =
    	(( 1,  3,  7,  8, 10),
	 ( 2,  4, 16, 14,  4),
	 ( 3,  1,  9, 18, 11),
	 (12, 14, 17, 18, 20),
	 ( 7,  1,  3,  9,  5));


function BottomTriangleSum(Mat: T5Matrix): double;
var X,Y: integer;
begin
Result:=0;
for Y:=1 to 4 do
 for X:=0 to Y-1 do
	begin
	Result:=Result+Mat[Y,X];
	end;
end;


procedure ShowBottomTriangleSum(Memo: TMemo);
var Sum: double;
begin
Sum:=BottomTriangleSum(TestMatrix);
Memo.Lines.Add(IntToStr(Trunc(Sum)));
end;
Output:
69
Elapsed Time: 0.873 ms.

EasyLang

proc sumbd . m[][] r .
   r = 0
   for i = 2 to len m[][]
      for j = 1 to i - 1
         r += m[i][j]
      .
   .
.
m[][] = [ [ 1 3 7 8 10 ] [ 2 4 16 14 4 ] [ 3 1 9 18 11 ] [ 12 14 17 18 20 ] [ 7 1 3 9 5 ] ]
sumbd m[][] r
print r
Output:
69

Excel

LAMBDA

Binding the name matrixTriangle to the following lambda expression in the Name Manager of the Excel WorkBook:

(See LAMBDA: The ultimate Excel worksheet function)

=LAMBDA(isUpper,
    LAMBDA(matrix,
        LET(
            nCols, COLUMNS(matrix),
            nRows, ROWS(matrix),
            ixs, SEQUENCE(nRows, nCols, 0, 1),
            x, MOD(ixs, nCols),
            y, QUOTIENT(ixs, nRows),
        
            IF(nCols=nRows,
                LET(
                    p, LAMBDA(x, y,
                        IF(isUpper, x > y, x < y)
                    ),
                    
                    IF(p(x, y), 
                        INDEX(matrix, 1 + y, 1 + x), 
                        0
                    )
                ),
                "Matrix not square"
            )
        )
    )
)
Output:

The formulae in cells B2 and B9 define and populate the matrices which fill the ranges B2:F6 and B9:F12

(The formula in B9 differs from that in B2 only in the first (Boolean) argument)

fx =matrixTriangle(FALSE)(B16#)
A B C D E F
1
2 Lower triangle: 0 0 0 0 0
3 2 0 0 0 0
4 3 1 0 0 0
5 12 14 17 0 0
6 7 1 3 9 0
7 Sum 69
8
9 Upper triangle: 0 3 7 8 10
10 0 0 16 14 4
11 0 0 0 18 11
12 0 0 0 0 20
13 0 0 0 0 0
14 Sum 111
15
16 Full matrix 1 3 7 8 10
17 2 4 16 14 4
18 3 1 9 18 11
19 12 14 17 18 20
20 7 1 3 9 5

F#

// Sum below leading diagnal. Nigel Galloway: July 21st., 2021
let _,n=[[ 1; 3; 7; 8;10];
         [ 2; 4;16;14; 4];
         [ 3; 1; 9;18;11];
         [12;14;17;18;20];
         [ 7; 1; 3; 9; 5]]|>List.fold(fun(n,g) i->let i,_=i|>List.splitAt n in (n+1,g+(i|>List.sum)))(0,0) in printfn "%d" n
Output:
69

Factor

Works with: Factor version 0.99 2021-06-02
USING: kernel math math.matrices prettyprint sequences ;

: sum-below-diagonal ( matrix -- sum )
    dup square-matrix? [ "Matrix must be square." throw ] unless
    0 swap [ head sum + ] each-index ;

{
    { 1 3 7 8 10 }
    { 2 4 16 14 4 }
    { 3 1 9 18 11 }
    { 12 14 17 18 20 }
    { 7 1 3 9 5 }
} sum-below-diagonal .
Output:
69

Go

package main

import (
    "fmt"
    "log"
)

func main() {
    m := [][]int{
        {1, 3, 7, 8, 10},
        {2, 4, 16, 14, 4},
        {3, 1, 9, 18, 11},
        {12, 14, 17, 18, 20},
        {7, 1, 3, 9, 5},
    }
    if len(m) != len(m[0]) {
        log.Fatal("Matrix must be square.")
    }
    sum := 0
    for i := 1; i < len(m); i++ {
        for j := 0; j < i; j++ {
            sum = sum + m[i][j]
        }
    }
    fmt.Println("Sum of elements below main diagonal is", sum)
}
Output:
Sum of elements below main diagonal is 69

Haskell

Defining both upper and lower triangle of a square matrix:

----------------- UPPER OR LOWER TRIANGLE ----------------

matrixTriangle :: Bool -> [[a]] -> Either String [[a]]
matrixTriangle upper matrix
  | upper = go drop id
  | otherwise = go take pred
  where
    go f g
      | isSquare matrix =
        (Right . snd) $
          foldr
            (\xs (n, rows) -> (pred n, f n xs : rows))
            (g $ length matrix, [])
            matrix
      | otherwise = Left "Defined only for a square matrix."

isSquare :: [[a]] -> Bool
isSquare rows = all ((n ==) . length) rows
  where
    n = length rows

--------------------------- TEST -------------------------
main :: IO ()
main =
  mapM_ putStrLn $
    zipWith
      ( flip ((<>) . (<> " triangle:\n\t"))
          . either id (show . sum . concat)
      )
      ( [matrixTriangle] <*> [False, True]
          <*> [ [ [1, 3, 7, 8, 10],
                  [2, 4, 16, 14, 4],
                  [3, 1, 9, 18, 11],
                  [12, 14, 17, 18, 20],
                  [7, 1, 3, 9, 5]
                ]
              ]
      )
      ["Lower", "Upper"]
Output:
Lower triangle:
    69
Upper triangle:
    111

J

sum_below_diagonal =: [:+/@,[*>/~@i.@#
Output:
   mat
 1  3  7  8 10
 2  4 16 14  4
 3  1  9 18 11
12 14 17 18 20
 7  1  3  9  5
   sum_below_diagonal mat
69

Java

public static void main(String[] args) {
    int[][] matrix = {{1, 3, 7, 8, 10},
                      {2, 4, 16, 14, 4},
                      {3, 1, 9, 18, 11},
                      {12, 14, 17, 18, 20},
                      {7, 1, 3, 9, 5}};
    int sum = 0;
    for (int row = 1; row < matrix.length; row++) {
        for (int col = 0; col < row; col++) {
            sum += matrix[row][col];
        }
    }
    System.out.println(sum);
}
Output:
69

JavaScript

Defining the lower triangle of a square matrix.

(() => {
    "use strict";

    // -------- LOWER TRIANGLE OF A SQUARE MATRIX --------

    // lowerTriangle :: [[a]] -> Either String [[a]]
    const lowerTriangle = matrix =>
        // Either a message, if the matrix is not square,
        // or the lower triangle of the matrix.
        isSquare(matrix) ? (
            Right(
                matrix.reduce(
                    ([n, rows], xs) => [
                        1 + n,
                        rows.concat([xs.slice(0, n)])
                    ],
                    [0, []]
                )[1]
            )
        ) : Left("Not a square matrix");


    // isSquare :: [[a]] -> Bool
    const isSquare = rows => {
        // True if the length of every row in the matrix
        // matches the number of rows in the matrix.
        const n = rows.length;

        return rows.every(x => n === x.length);
    };

    // ---------------------- TEST -----------------------
    const main = () =>
        either(
            msg => `Lower triangle undefined :: ${msg}`
        )(
            rows => sum([].concat(...rows))
        )(
            lowerTriangle([
                [1, 3, 7, 8, 10],
                [2, 4, 16, 14, 4],
                [3, 1, 9, 18, 11],
                [12, 14, 17, 18, 20],
                [7, 1, 3, 9, 5]
            ])
        );

    // --------------------- GENERIC ---------------------

    // Left :: a -> Either a b
    const Left = x => ({
        type: "Either",
        Left: x
    });


    // Right :: b -> Either a b
    const Right = x => ({
        type: "Either",
        Right: x
    });


    // either :: (a -> c) -> (b -> c) -> Either a b -> c
    const either = fl =>
        // Application of the function fl to the
        // contents of any Left value in e, or
        // the application of fr to its Right value.
        fr => e => e.Left ? (
            fl(e.Left)
        ) : fr(e.Right);


    // sum :: [Num] -> Num
    const sum = xs =>
        // The numeric sum of all values in xs.
        xs.reduce((a, x) => a + x, 0);

    // MAIN ---
    return main();
})();
Output:
69

jq

Works with: jq

Works with gojq, the Go implementation of jq

def add(s): reduce s as $x (null; . + $x);

# input: a square matrix
def sum_below_diagonal:
  add( range(0;length) as $i | .[$i][:$i][] ) ;

The task:

  [[1,3,7,8,10],
   [2,4,16,14,4],
   [3,1,9,18,11],
   [12,14,17,18,20],
   [7,1,3,9,5]]
  | sum_below_diagonal
Output:
69


Julia

The tril function is part of Julia's built-in LinearAlgebra package. tril(A) includes the main diagonal and the components of the matrix A to the left and below the main diagonal. tril(A, -1) returns the lower triangular elements of A excluding the main diagonal. The excluded elements of the matrix are set to 0.

using LinearAlgebra

A = [ 1  3  7  8 10;
      2  4 16 14  4;
      3  1  9 18 11;
     12 14 17 18 20;
      7  1  3  9  5 ]

@show tril(A)

@show tril(A, -1)

@show sum(tril(A, -1))  # 69
Output:

tril(A) = [1 0 0 0 0; 2 4 0 0 0; 3 1 9 0 0; 12 14 17 18 0; 7 1 3 9 5] tril(A, -1) = [0 0 0 0 0; 2 0 0 0 0; 3 1 0 0 0; 12 14 17 0 0; 7 1 3 9 0] sum(tril(A, -1)) = 69

Mathematica/Wolfram Language

m = {{1, 3, 7, 8, 10}, {2, 4, 16, 14, 4}, {3, 1, 9, 18, 11}, {12, 14, 17, 18, 20}, {7, 1, 3, 9, 5}};
Total[LowerTriangularize[m, -1], 2]
Output:
69

MATLAB

clear all;close all;clc;
A = [1, 3, 7, 8, 10;
     2, 4, 16, 14, 4;
     3, 1, 9, 18, 11;
     12, 14, 17, 18, 20;
     7, 1, 3, 9, 5];

lower_triangular = tril(A, -1);
sum_of_elements = sum(lower_triangular(:)); % Sum of all elements in the lower triangular part

fprintf('%d\n', sum_of_elements);  % Prints 69
Output:
69

MiniZinc

% Sum below leading diagnal. Nigel Galloway: July 22nd., 2021
array [1..5,1..5] of int: N=[|1,3,7,8,10|2,4,16,14,4|3,1,9,18,11|12,14,17,18,20|7,1,3,9,5|];
int: res=sum(n,g in 1..5 where n>g)(N[n,g]);
output([show(res)])
Output:
69
----------

Nim

We use a generic definition for the square matrix type. The compiler insures that the matrix we provide is actually square.

type SquareMatrix[T: SomeNumber; N: static Positive] = array[N, array[N, T]]

func sumBelowDiagonal[T, N](m: SquareMatrix[T, N]): T =
  for i in 1..<N:
    for j in 0..<i:
      result += m[i][j]

const M = [[ 1,  3,  7,  8, 10],
           [ 2,  4, 16, 14,  4],
           [ 3,  1,  9, 18, 11],
           [12, 14, 17, 18, 20],
           [ 7,  1,  3,  9,  5]]

echo sumBelowDiagonal(M)
Output:
69

Perl

#!/usr/bin/perl

use strict;
use warnings;
use List::Util qw( sum );

my $matrix =
  [[1,3,7,8,10],
  [2,4,16,14,4],
  [3,1,9,18,11],
  [12,14,17,18,20],
  [7,1,3,9,5]];

my $lowersum = sum map @{ $matrix->[$_] }[0 .. $_ - 1], 1 .. $#$matrix;
print "lower sum = $lowersum\n";
Output:
lower sum = 69

Phix

constant M = {{ 1,  3,  7,  8, 10},
              { 2,  4, 16, 14,  4},
              { 3,  1,  9, 18, 11},
              {12, 14, 17, 18, 20},
              { 7,  1,  3,  9,  5}}
atom res = 0
integer height = length(M)
for row=1 to height do
    integer width = length(M[row])
    if width!=height then crash("not square") end if
    for col=1 to row-1 do
        res += M[row][col]
    end for
end for
?res

You could of course start row from 2 and get the same result, for row==1 the col loop iterates zero times.
Without the checks for square M expect (when not square) wrong/partial answers for height<=width+1, and (still human readable) runtime crashes for height>width+1.

Output:
69

PL/I

trap: procedure options (main);      /* 17 December 2021 */
   declare n fixed binary;
   get (n);
   put ('The order of the matrix is ' || trim(n));
   begin;
      declare A (n,n) fixed binary;
      declare sum fixed binary;
      declare (i, j) fixed binary;

      get (A);
      sum = 0;
      do i = 2 to n;
         do j = 1 to i-1;
            sum = sum + a(i,j);
         end;
      end;
      put edit (A) (skip, (n) f(4) );
      put skip data (sum);
   end;
end trap;
Output:
The order of the matrix is 5 

   1   3   7   8  10
   2   4  16  14   4
   3   1   9  18  11
  12  14  17  18  20
   7   1   3   9   5
SUM=       69;

PL/M

This can be compiled with the original 8080 PL/M compiler and run under CP/M or an emulator/clone.

100H: /* SUM THE ELEMENTS BELOW THE MAIN DIAGONAL OF A MATRIX                */

   /* CP/M BDOS SYSTEM CALL, IGNORE THE RETURN VALUE                         */
   BDOS: PROCEDURE( FN, ARG ); DECLARE FN BYTE, ARG ADDRESS; GOTO 5;     END;
   PR$STRING: PROCEDURE( S ); DECLARE S ADDRESS; CALL BDOS( 9, S );      END;
   PR$NUMBER: PROCEDURE( N ); /* PRINTS A NUMBER IN THE MINIMUN FIELD WIDTH  */
      DECLARE N ADDRESS;
      DECLARE V ADDRESS, N$STR ( 6 )BYTE, W BYTE;
      V = N;
      W = LAST( N$STR );
      N$STR( W ) = '$';
      N$STR( W := W - 1 ) = '0' + ( V MOD 10 );
      DO WHILE( ( V := V / 10 ) > 0 );
         N$STR( W := W - 1 ) = '0' + ( V MOD 10 );
      END;
      CALL PR$STRING( .N$STR( W ) );
   END PR$NUMBER;

   /* RETURNS THE SUM OF THE ELEMENTS BELOW THE MAIN DIAGONAL OF MX          */
   /* MX WOULD BE DECLARED AS ''( UB, UB )ADDRESS'' IF PL/M SUPPORTED        */
   /* 2-DIMENSIONAL ARRAYS, IT DOESN'T SO MX MUST ACTULLY BE DECLARED        */
   /* ''( UB * UB )ADDRESS'' - EXCEPT THE BOUND MUST BE A CONSTANT, NOT AN   */
   /* EXPRESSION                                                             */
   /* NOTE ''ADDRESS'' MEANS UNSIGNED 16-BIT QUANTITY, WHICH CAN BE USED FOR */
   /* OTHER PURPOSES THAN JUST POINTERS                                      */
   LOWER$SUM: PROCEDURE( MX, UB )ADDRESS;
      DECLARE ( MX, UB ) ADDRESS;
      DECLARE ( SUM, R, C, STRIDE, R$PTR ) ADDRESS;
      DECLARE M$PTR ADDRESS, M$VALUE BASED M$PTR ADDRESS;
      SUM    = 0;
      STRIDE = UB + UB;
      R$PTR  = MX + STRIDE;      /* ADDRESS OF ROW 1 ( THE FIRST ROW IS 0 )  */
      DO R = 1 TO UB - 1;
         M$PTR = R$PTR;
         DO C = 0 TO R - 1;
            SUM = SUM + M$VALUE;
            M$PTR = M$PTR + 2;
         END;
         R$PTR = R$PTR + STRIDE; /* ADDRESS OF THE NEXT ROW                  */
      END;
      RETURN SUM;
   END LOWER$SUM ;

   /* TASK TEST CASE                                                         */
   DECLARE T ( 25 )ADDRESS
                   INITIAL(  1,  3,  7,  8, 10
                          ,  2,  4, 16, 14,  4
                          ,  3,  1,  9, 18, 11
                          , 12, 14, 17, 18, 20
                          ,  7,  1,  3,  9,  5
                          );
   CALL PR$NUMBER( LOWER$SUM( .T, 5 ) );

EOF
Output:
69

Python

from numpy import array, tril, sum

A = [[1,3,7,8,10],
    [2,4,16,14,4],
    [3,1,9,18,11],
    [12,14,17,18,20],
    [7,1,3,9,5]]

print(sum(tril(A, -1)))   # 69


Or, defining the lower triangle for ourselves:

'''Lower triangle of a matrix'''

from itertools import chain, islice
from functools import reduce


# lowerTriangle :: [[a]] -> None | [[a]]
def lowerTriangle(matrix):
    '''Either None, if the matrix is not square, or
       the rows of the matrix, each containing only
       those values that form part of the lower triangle.
    '''
    def go(n_rows, xs):
        n, rows = n_rows
        return 1 + n, rows + [list(islice(xs, n))]

    return reduce(
        go,
        matrix,
        (0, [])
    )[1] if isSquare(matrix) else None


# isSquare :: [[a]] -> Bool
def isSquare(matrix):
    '''True if all rows of the matrix share
       the length of the matrix itself.
    '''
    n = len(matrix)
    return all([n == len(x) for x in matrix])


# ------------------------- TEST -------------------------
# main :: IO ()
def main():
    '''Sum of integers in the lower triangle of a matrix.
    '''
    rows = lowerTriangle([
        [1, 3, 7, 8, 10],
        [2, 4, 16, 14, 4],
        [3, 1, 9, 18, 11],
        [12, 14, 17, 18, 20],
        [7, 1, 3, 9, 5]
    ])

    print(
        "Not a square matrix." if None is rows else (
            sum(chain(*rows))
        )
    )

# MAIN ---
if __name__ == '__main__':
    main()
Output:
69

R

R has lots of native matrix support, so this is trivial.

mat <- rbind(c(1,3,7,8,10),
             c(2,4,16,14,4),
             c(3,1,9,18,11),
             c(12,14,17,18,20),
             c(7,1,3,9,5))
print(sum(mat[lower.tri(mat)]))
Output:
[1] 69

Raku

sub lower-triangle-sum (@matrix) { sum flat (1..@matrix).map( { @matrix[^$_]»[^($_-1)] } )»[*-1] }

say lower-triangle-sum 
[
    [  1,  3,  7,  8, 10 ],
    [  2,  4, 16, 14,  4 ],
    [  3,  1,  9, 18, 11 ],
    [ 12, 14, 17, 18, 20 ],
    [  7,  1,  3,  9,  5 ]
];
Output:
69

REXX

version 1

/* REXX */
ml ='1 3 7 8 10 2 4 16 14 4 3 1 9 18 11 12 14 17 18 20 7 1 3 9 5'
Do i=1 To 5
  Do j=1 To 5
    Parse Var ml m.i.j ml
    End
  End

l=''
Do i=1 To 5
  Do j=1 To 5
    l=l right(m.i.j,2)
    End
  Say l
  l=''
  End

sum=0
Do i=2 To 5
  Do j=1 To i-1
    sum=sum+m.i.j
    End
  End
Say 'Sum below main diagonal:' sum
 
  1  3  7  8 10
  2  4 16 14  4
  3  1  9 18 11
 12 14 17 18 20
  7  1  3  9  5
Sum below main diagonal: 69 

version 2

This REXX version makes no assumption about the size of the matrix,   and it determines the maximum width of any
matrix element   (instead of assuming a width that might not properly show the true value of an element).

/*REXX pgm finds & shows the sum of elements below the main diagonal of a square matrix.*/
$= '1 3 7 8 10 2 4 16 14 4 3 1 9 18 11 12 14 17 18 20 7 1 3 9 5';       #= words($)
     do siz=1  while siz*siz<#;  end             /*determine the size of the matrix.    */
w= 0                                             /*W:  the maximum width any any element*/
     do j=1  for #;         parse var $  @..j  $ /*obtain a number of the array (list). */
     w= max(w, length(@..j))                     /*examine each element for its width.  */
     end   /*j*/                                 /* [↑] this is aligning matrix elements*/
s= 0;                       z= 0                 /*initialize the sum  [S]  to zero.    */
     do      r=1  for siz;  _= left('', 12)      /*_:  contains a row of matrix elements*/
          do c=1  for siz;  z= z + 1;  @.z= @..z /*get a  number  of the    "      "    */
          _= _  right(@.z, w)                    /*build a row of elements for display. */
          if c<r  then s= s + @.z                /*add a  "lower element"  to the sum.  */
          end   /*r*/
     say _                                       /*display a row of the matrix to term. */
     end        /*c*/
say 'sum of elements below main diagonal is: ' s /*stick a fork in it,  we're all done. */
output   when using the internal default input:
              1  3  7  8 10
              2  4 16 14  4
              3  1  9 18 11
             12 14 17 18 20
              7  1  3  9  5
sum of elements below main diagonal is:  69

Ring

see "working..." + nl
see "Sum of elements below main diagonal of matrix:" + nl
diag = [[1,3,7,8,10],
        [2,4,16,14,4],
        [3,1,9,18,11],
        [12,14,17,18,20],
        [7,1,3,9,5]]

lenDiag = len(diag)
ind = lenDiag
sumDiag = 0

for n=1 to lenDiag
    for m=1 to lenDiag-ind
        sumDiag += diag[n][m]
    next
    ind--
next

see "" + sumDiag + nl
see "done..." + nl
Output:
working...
Sum of elements below main diagonal of matrix:
69
done...

RPL

« → m
  « 0 2 m SIZE 1 GET FOR r 
        1 r 1 - FOR c 
           m r c 2 →LIST GET + 
    NEXT NEXT
» » '∑BELOW' STO
[[1 3 7 8 10]
 [2 4 16 14 4]
 [3 1 9 18 11]
 [12 14 17 18 20]
 [7 1 3 9 5]] ∑BELOW
Output:
1: 69
Works with: HP version 49/50
« DUP SIZE OBJ→ DROP « > » LCXM
  HADAMARD AXL ∑LIST ∑LIST
» '∑BELOW' STO

Ruby

arr = [
   [ 1,  3,  7,  8, 10],
   [ 2,  4, 16, 14,  4],
   [ 3,  1,  9, 18, 11],
   [12, 14, 17, 18, 20],
   [ 7,  1,  3,  9,  5]
]
p  arr.each_with_index.sum {|row, x| row[0, x].sum}
Output:
69

Scala

object Main {
  def main(args: Array[String]): Unit = {
    val matrix = Array(
      Array(1, 3, 7, 8, 10),
      Array(2, 4, 16, 14, 4),
      Array(3, 1, 9, 18, 11),
      Array(12, 14, 17, 18, 20),
      Array(7, 1, 3, 9, 5)
    )
    var sum = 0
    for (row <- 1 until matrix.length) {
      for (col <- 0 until row) {
        sum += matrix(row)(col)
      }
    }
    println(sum)
  }
}
Output:
69

Seed7

$ include "seed7_05.s7i";

const proc: main is func
  local
    var integer: sum is 0;
    var integer: i is 0;
    var integer: j is 0;
    const array array integer: m is [] ([] ( 1,  3,  7,  8, 10),
                                        [] ( 2,  4, 16, 14,  4),
                                        [] ( 3,  1,  9, 18, 11),
                                        [] (12, 14, 17, 18, 20),
                                        [] ( 7,  1,  3,  9,  5));
  begin
    for i range 2 to length(m) do
      for j range 1 to i - 1 do
        sum +:= m[i][j];
      end for;
    end for;
    writeln(sum);
  end func;
Output:
69

Wren

var m = [
    [ 1,  3,  7,  8, 10],
    [ 2,  4, 16, 14,  4],
    [ 3,  1,  9, 18, 11],
    [12, 14, 17, 18, 20],
    [ 7,  1,  3,  9,  5]
]
if (m.count != m[0].count) Fiber.abort("Matrix must be square.")
var sum = 0
for (i in 1...m.count) {
   for (j in 0...i) {
       sum = sum + m[i][j]
  }
}
System.print("Sum of elements below main diagonal is %(sum).")
Output:
Sum of elements below main diagonal is 69.

XPL0

int Mat, X, Y, Sum;
[Mat:=  [[1,3,7,8,10],
        [2,4,16,14,4],
        [3,1,9,18,11],
        [12,14,17,18,20],
        [7,1,3,9,5]];
Sum:= 0;
for Y:= 0 to 4 do
  for X:= 0 to 4 do
    if Y > X then
      Sum:= Sum + Mat(Y,X);
IntOut(0, Sum);
]
Output:
69