Sorting algorithms/Insertion sort: Difference between revisions

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> a
> a
# value: [10, 10, 10, 13, 14, 17, 22, 23, 24, 26, 27, 27, 39, 40, 47, 50, 52, 53, 54, 55, 59, 60, 61, 62, 63, 65, 67, 71, 75, 75, 78, 83, 85, 85, 88, 91, 93, 94, 96, 99].diverge()</lang>
# value: [10, 10, 10, 13, 14, 17, 22, 23, 24, 26, 27, 27, 39, 40, 47, 50, 52, 53, 54, 55, 59, 60, 61, 62, 63, 65, 67, 71, 75, 75, 78, 83, 85, 85, 88, 91, 93, 94, 96, 99].diverge()</lang>

=={{header|Easyprog.online}}==

<lang easyprog.online>subr sort
for i = 1 to len data[] - 1
h = data[i]
j = i - 1
while j >= 0 and h < data[j]
data[j + 1] = data[j]
j -= 1
.
data[j + 1] = h
.
.
data[] = [ 29 4 72 44 55 26 27 77 92 5 ]
call sort
print data[]</lang>


=={{header|Eiffel}}==
=={{header|Eiffel}}==

Revision as of 07:21, 5 May 2019

Task
Sorting algorithms/Insertion sort
You are encouraged to solve this task according to the task description, using any language you may know.
This page uses content from Wikipedia. The original article was at Insertion sort. The list of authors can be seen in the page history. As with Rosetta Code, the text of Wikipedia is available under the GNU FDL. (See links for details on variance)


An O(n2) sorting algorithm which moves elements one at a time into the correct position. The algorithm consists of inserting one element at a time into the previously sorted part of the array, moving higher ranked elements up as necessary. To start off, the first (or smallest, or any arbitrary) element of the unsorted array is considered to be the sorted part.

Although insertion sort is an O(n2) algorithm, its simplicity, low overhead, good locality of reference and efficiency make it a good choice in two cases:
(i) small n,
(ii) as the final finishing-off algorithm for O(n logn) algorithms such as mergesort and quicksort.

The algorithm is as follows (from wikipedia):

function insertionSort(array A)
    for i from 1 to length[A]-1 do
        value := A[i] 
        j := i-1
        while j >= 0 and A[j] > value do
            A[j+1] := A[j]
            j := j-1
        done
        A[j+1] = value
    done

Writing the algorithm for integers will suffice.

360 Assembly

Translation of: PL/I

These programs use two ASSIST macros (XDECO, XPRNT) to keep the code as short as possible.

Basic

<lang 360asm>* Insertion sort 16/06/2016 INSSORT CSECT

        USING  INSSORT,R13        base register
        B      72(R15)            skip savearea
        DC     17F'0'             savearea
        STM    R14,R12,12(R13)    prolog
        ST     R13,4(R15)         "
        ST     R15,8(R13)         " 
        LR     R13,R15            "
        LA     R6,2               i=2
        LA     R9,A+L'A           @a(2)

LOOPI C R6,N do i=2 to n

        BH     ELOOPI             leave i
        L      R2,0(R9)           a(i)
        ST     R2,V               v=a(i)
        LR     R7,R6              j=i
        BCTR   R7,0               j=i-1
        LR     R8,R9              @a(i)
        S      R8,=A(L'A)         @a(j)

LOOPJ LTR R7,R7 do j=i-1 to 1 by -1 while j>0

        BNH    ELOOPJ             leave j
        L      R2,0(R8)           a(j)
        C      R2,V               a(j)>v
        BNH    ELOOPJ             leave j
        MVC    L'A(L'A,R8),0(R8)  a(j+1)=a(j)
        BCTR   R7,0               j=j-1
        S      R8,=A(L'A)         @a(j)
        B      LOOPJ              next j

ELOOPJ MVC L'A(L'A,R8),V a(j+1)=v;

        LA     R6,1(R6)           i=i+1
        LA     R9,L'A(R9)         @a(i)
        B      LOOPI              next i

ELOOPI LA R9,PG pgi=0

        LA     R6,1               i=1
        LA     R8,A               @a(1)

LOOPXI C R6,N do i=1 to n

        BH     ELOOPXI            leave i
        L      R1,0(R8)           a(i)
        XDECO  R1,XDEC            edit a(i)
        MVC    0(4,R9),XDEC+8     output a(i)
        LA     R9,4(R9)           pgi=pgi+1
        LA     R6,1(R6)           i=i+1
        LA     R8,L'A(R8)         @a(i)
        B      LOOPXI             next i

ELOOPXI XPRNT PG,L'PG print buffer

        L      R13,4(0,R13)       epilog 
        LM     R14,R12,12(R13)    "
        XR     R15,R15            "
        BR     R14                exit

A DC F'4',F'65',F'2',F'-31',F'0',F'99',F'2',F'83',F'782',F'1'

  DC F'45',F'82',F'69',F'82',F'104',F'58',F'88',F'112',F'89',F'74'

V DS F variable N DC A((V-A)/L'A) n=hbound(a) PG DC CL80' ' buffer XDEC DS CL12 for xdeco

        YREGS                     symbolics for registers
        END    INSSORT</lang>
Output:
 -31   0   1   2   2   4  45  58  65  69  74  82  82  83  88  89  99 104 112 782

Assembler Structured Macros

No harmful gotos [:)Dijkstra], no labels. It's cleaner, but is it clearer? <lang 360asm>* Insertion sort 16/06/2016 INSSORTS CSECT

    USING  INSSORTS,R13       base register
    B      72(R15)            skip savearea
    DC     17F'0'             savearea
    STM    R14,R12,12(R13)    prolog
    ST     R13,4(R15)         "
    ST     R15,8(R13)         " 
    LR     R13,R15            "
    LA     R6,2               i=2
    LA     R9,A+L'A           @a(2)
    DO     WHILE=(C,R6,LE,N)  do while i<=n
      L      R2,0(R9)           a(i)
      ST     R2,V               v=a(i)
      LR     R7,R6              j=i
      BCTR   R7,0               j=i-1
      LR     R8,R9              @a(i)
      S      R8,=A(L'A)         @a(j)
      L      R2,0(R8)           a(j)
      DO     WHILE=(C,R7,GT,0,AND,C,R2,GT,V)  do while j>0 & a(j)>v
        MVC    L'A(L'A,R8),0(R8)  a(j+1)=a(j)
        BCTR   R7,0               j=j-1
        S      R8,=A(L'A)         @a(j)
        L      R2,0(R8)           a(j)
      ENDDO  ,                  next j
      MVC    L'A(L'A,R8),V      a(j+1)=v;
      LA     R6,1(R6)           i=i+1
      LA     R9,L'A(R9)         @a(i)
    ENDDO  ,                  next i
    LA     R9,PG              pgi=0
    LA     R6,1               i=1
    LA     R8,A               @a(1)
    DO     WHILE=(C,R6,LE,N)  do while i<=n
      L      R1,0(R8)           a(i)
      XDECO  R1,XDEC            edit a(i)
      MVC    0(4,R9),XDEC+8     output a(i)
      LA     R9,4(R9)           pgi=pgi+1
      LA     R6,1(R6)           i=i+1
      LA     R8,L'A(R8)         @a(i)
    ENDDO  ,                  next i
    XPRNT  PG,L'PG            print buffer
    L      R13,4(0,R13)       epilog 
    LM     R14,R12,12(R13)    "
    XR     R15,R15            "
    BR     R14                exit

A DC F'4',F'65',F'2',F'-31',F'0',F'99',F'2',F'83',F'782',F'1'

  DC F'45',F'82',F'69',F'82',F'104',F'58',F'88',F'112',F'89',F'74'

V DS F variable N DC A((V-A)/L'A) n=hbound(a) PG DC CL80' ' buffer XDEC DS CL12 for xdeco

    YREGS                     symbolics for registers
    END    INSSORTS</lang>
Output:

Same as previous

ACL2

<lang Lisp>(defun insert (x xs)

  (cond ((endp xs) (list x))
        ((< x (first xs))
         (cons x xs))
        (t (cons (first xs)
                 (insert x (rest xs))))))

(defun isort (xs)

  (if (endp xs)
      nil
      (insert (first xs)
              (isort (rest xs)))))</lang>

ActionScript

<lang ActionScript>function insertionSort(array:Array) { for(var i:int = 1; i < array.length;i++) { var value = array[i]; var j:int = i-1; while(j >= 0 && array[j] > value) { array[j+1] = array[j]; j--; } array[j+1] = value; } return array; }</lang>

Ada

<lang ada>type Data_Array is array(Natural range <>) of Integer;

procedure Insertion_Sort(Item : in out Data_Array) is

  First : Natural := Item'First;
  Last  : Natural := Item'Last;
  Value : Integer;
  J     : Integer;

begin

  for I in (First + 1)..Last loop
     Value := Item(I);
     J := I - 1;
     while J in Item'range and then Item(J) > Value loop
        Item(J + 1) := Item(J);
        J := J - 1;
     end loop;
     Item(J + 1) := Value;
  end loop;

end Insertion_Sort;</lang>

ALGOL 68

Translation of: Ada
Works with: ALGOL 68 version Revision 1 - no extensions to language used
Works with: ALGOL 68G version Any - tested with release 1.18.0-9h.tiny
Works with: ELLA ALGOL 68 version Any (with appropriate job cards) - tested with release 1.8-8d

<lang algol68>MODE DATA = REF CHAR;

PROC in place insertion sort = (REF[]DATA item)VOID: BEGIN

  INT first := LWB item;
  INT last  := UPB item;
  INT j;
  DATA value;
  FOR i FROM first + 1 TO last DO
     value := item[i];
     j := i - 1;
  #  WHILE j >= LWB item AND j <= UPB item ANDF item[j] > value DO // example of ANDF extension #
     WHILE ( j >= LWB item AND j <= UPB item | item[j]>value | FALSE ) DO # no extension! #
        item[j + 1] := item[j];
        j -:=  1
     OD;
     item[j + 1] := value
  OD

END # in place insertion sort #;

[32]CHAR data := "big fjords vex quick waltz nymph"; [UPB data]DATA ref data; FOR i TO UPB data DO ref data[i] := data[i] OD; in place insertion sort(ref data); FOR i TO UPB ref data DO print(ref data[i]) OD; print(new line); print((data))</lang>

Output:
abcdefghiijklmnopqrstuvwxyz
big fjords vex quick waltz nymph

ALGOL W

External in-place insertion sort routine for integers. From the pseudo code but with variable bounds. <lang algolw>% insertion sorts in-place the array A. As Algol W procedures can't find the bounds % % of an array parameter, the lower and upper bounds must be specified in lb and ub  % procedure insertionSortI ( integer array A ( * ); integer value lb, ub ) ;

   for i := lb + 1 until ub do begin
       integer v, j;
       v := A( i ); 
       j := i - 1;
       while j >= lb and A( j ) > v do begin
           A( j + 1 ) := A( j );
           j := j - 1
       end while_j_ge_0_and_Aj_gt_v ;
       A( j + 1 ) := v
   end insertionSortI ;</lang>

Test the insertionSortI procedure. <lang algolw>begin

   % external in-place insertion sort procedure %
   procedure insertionSortI ( integer array A( * ); integer value lb, ub ) ;
       algol "ISORTI" ;
   integer array d ( 1 :: 8 );
   integer p;
   p := 1;
   for i := 34, 2, -1, 0, 0, 9, -56, 3 do begin
       d( p ) := i;
       p := p + 1
   end for_i ;
   insertionSortI( d, 1, 8 );
   write( i_w := 1, d( 1 ) );
   for i := 2 until 8 do writeon( i_w := 1, d( i ) )

end.</lang>

Output:
-56  -1  0  0  2  3  9  34

ARM Assembly

Works with: as version Raspberry Pi

<lang ARM Assembly> /* ARM assembly Raspberry PI */ /* program insertionSort.s */ /* look Pseudocode begin this task */

/************************************/ /* Constantes */ /************************************/ .equ STDOUT, 1 @ Linux output console .equ EXIT, 1 @ Linux syscall .equ WRITE, 4 @ Linux syscall /*********************************/ /* Initialized data */ /*********************************/ .data szMessSortOk: .asciz "Table sorted.\n" szMessSortNok: .asciz "Table not sorted !!!!!.\n" sMessResult: .ascii "Value  : " sMessValeur: .fill 11, 1, ' ' @ size => 11 szCarriageReturn: .asciz "\n"

.align 4 iGraine: .int 123456 .equ NBELEMENTS, 10

  1. TableNumber: .int 1,3,6,2,5,9,10,8,4,7

TableNumber: .int 10,9,8,7,6,5,4,3,2,1 /*********************************/ /* UnInitialized data */ /*********************************/ .bss /*********************************/ /* code section */ /*********************************/ .text .global main main: @ entry of program

1:

   ldr r0,iAdrTableNumber                         @ address number table
   mov r1,#0
   mov r2,#NBELEMENTS                             @ number of élements 
   bl insertionSort
   ldr r0,iAdrTableNumber                         @ address number table
   bl displayTable

   ldr r0,iAdrTableNumber                         @ address number table
   mov r1,#NBELEMENTS                             @ number of élements 
   bl isSorted                                    @ control sort
   cmp r0,#1                                      @ sorted ?
   beq 2f                                    
   ldr r0,iAdrszMessSortNok                       @ no !! error sort
   bl affichageMess
   b 100f

2: @ yes

   ldr r0,iAdrszMessSortOk
   bl affichageMess

100: @ standard end of the program

   mov r0, #0                                     @ return code
   mov r7, #EXIT                                  @ request to exit program
   svc #0                                         @ perform the system call

iAdrsMessValeur: .int sMessValeur iAdrszCarriageReturn: .int szCarriageReturn iAdrsMessResult: .int sMessResult iAdrTableNumber: .int TableNumber iAdrszMessSortOk: .int szMessSortOk iAdrszMessSortNok: .int szMessSortNok /******************************************************************/ /* control sorted table */ /******************************************************************/ /* r0 contains the address of table */ /* r1 contains the number of elements > 0 */ /* r0 return 0 if not sorted 1 if sorted */ isSorted:

   push {r2-r4,lr}                                    @ save registers
   mov r2,#0
   ldr r4,[r0,r2,lsl #2]

1:

   add r2,#1
   cmp r2,r1
   movge r0,#1
   bge 100f
   ldr r3,[r0,r2, lsl #2]
   cmp r3,r4
   movlt r0,#0
   blt 100f
   mov r4,r3
   b 1b

100:

   pop {r2-r4,lr}
   bx lr                                              @ return 

/******************************************************************/ /* insertion sort */ /******************************************************************/ /* r0 contains the address of table */ /* r1 contains the first element */ /* r2 contains the number of element */ insertionSort:

   push {r2,r3,r4,lr}                                     @ save registers
   add r3,r1,#1                                           @ start index i

1: @ start loop

   ldr r4,[r0,r3,lsl #2]                                  @ load value A[i]
   sub r5,r3,#1                                           @ index j

2:

   ldr r6,[r0,r5,lsl #2]                                  @ load value A[j]
   cmp r6,r4                                              @ compare value
   ble 3f
   add r5,#1                                              @ increment index j
   str r6,[r0,r5,lsl #2]                                  @ store value A[j+1]
   sub r5,#2                                              @ j = j - 1
   cmp r5,r1
   bge 2b                                                 @ loop if j >= first item

3:

   add r5,#1                                              @ increment index j
   str r4,[r0,r5,lsl #2]                                  @ store value A[i] in A[j+1]
   add r3,#1                                              @ increment index i
   cmp r3,r2                                              @ end ?
   blt 1b                                                 @ no -> loop

100:

   pop {r2,r3,r4,lr}
   bx lr                                                  @ return 

/******************************************************************/ /* Display table elements */ /******************************************************************/ /* r0 contains the address of table */ displayTable:

   push {r0-r3,lr}                                    @ save registers
   mov r2,r0                                          @ table address
   mov r3,#0

1: @ loop display table

   ldr r0,[r2,r3,lsl #2]
   ldr r1,iAdrsMessValeur                             @ display value
   bl conversion10                                    @ call function
   ldr r0,iAdrsMessResult
   bl affichageMess                                   @ display message
   add r3,#1
   cmp r3,#NBELEMENTS - 1
   ble 1b
   ldr r0,iAdrszCarriageReturn
   bl affichageMess

100:

   pop {r0-r3,lr}
   bx lr

/******************************************************************/ /* display text with size calculation */ /******************************************************************/ /* r0 contains the address of the message */ affichageMess:

   push {r0,r1,r2,r7,lr}                          @ save  registres
   mov r2,#0                                      @ counter length 

1: @ loop length calculation

   ldrb r1,[r0,r2]                                @ read octet start position + index 
   cmp r1,#0                                      @ if 0 its over 
   addne r2,r2,#1                                 @ else add 1 in the length 
   bne 1b                                         @ and loop 
                                                  @ so here r2 contains the length of the message 
   mov r1,r0                                      @ address message in r1 
   mov r0,#STDOUT                                 @ code to write to the standard output Linux 
   mov r7, #WRITE                                 @ code call system "write" 
   svc #0                                         @ call systeme 
   pop {r0,r1,r2,r7,lr}                           @ restaur des  2 registres */ 
   bx lr                                          @ return  

/******************************************************************/ /* Converting a register to a decimal unsigned */ /******************************************************************/ /* r0 contains value and r1 address area */ /* r0 return size of result (no zero final in area) */ /* area size => 11 bytes */ .equ LGZONECAL, 10 conversion10:

   push {r1-r4,lr}                                 @ save registers 
   mov r3,r1
   mov r2,#LGZONECAL

1: @ start loop

   bl divisionpar10U                               @ unsigned  r0 <- dividende. quotient ->r0 reste -> r1
   add r1,#48                                      @ digit
   strb r1,[r3,r2]                                 @ store digit on area
   cmp r0,#0                                       @ stop if quotient = 0 
   subne r2,#1                                     @ else previous position
   bne 1b	                                    @ and loop
                                                   @ and move digit from left of area
   mov r4,#0

2:

   ldrb r1,[r3,r2]
   strb r1,[r3,r4]
   add r2,#1
   add r4,#1
   cmp r2,#LGZONECAL
   ble 2b
                                                     @ and move spaces in end on area
   mov r0,r4                                         @ result length 
   mov r1,#' '                                       @ space

3:

   strb r1,[r3,r4]                                   @ store space in area
   add r4,#1                                         @ next position
   cmp r4,#LGZONECAL
   ble 3b                                            @ loop if r4 <= area size

100:

   pop {r1-r4,lr}                                    @ restaur registres 
   bx lr                                             @return

/***************************************************/ /* division par 10 unsigned */ /***************************************************/ /* r0 dividende */ /* r0 quotient */ /* r1 remainder */ divisionpar10U:

   push {r2,r3,r4, lr}
   mov r4,r0                                          @ save value
   //mov r3,#0xCCCD                                   @ r3 <- magic_number lower  raspberry 3
   //movt r3,#0xCCCC                                  @ r3 <- magic_number higter raspberry 3
   ldr r3,iMagicNumber                                @ r3 <- magic_number    raspberry 1 2
   umull r1, r2, r3, r0                               @ r1<- Lower32Bits(r1*r0) r2<- Upper32Bits(r1*r0) 
   mov r0, r2, LSR #3                                 @ r2 <- r2 >> shift 3
   add r2,r0,r0, lsl #2                               @ r2 <- r0 * 5 
   sub r1,r4,r2, lsl #1                               @ r1 <- r4 - (r2 * 2)  = r4 - (r0 * 10)
   pop {r2,r3,r4,lr}
   bx lr                                              @ leave function 

iMagicNumber: .int 0xCCCCCCCD </lang>

AutoHotkey

contributed by Laszlo on the ahk forum <lang AutoHotkey>MsgBox % InsertionSort("") MsgBox % InsertionSort("xxx") MsgBox % InsertionSort("3,2,1") MsgBox % InsertionSort("dog,000000,xx,cat,pile,abcde,1,cat,zz,xx,z")

InsertionSort(var) {  ; SORT COMMA SEPARATED LIST

  StringSplit a, var, `,                ; make array, size = a0
  Loop % a0-1 {
     i := A_Index+1, v := a%i%, j := i-1
     While j>0 and a%j%>v
        u := j+1, a%u% := a%j%, j--
     u := j+1, a%u% := v
  }
  Loop % a0                             ; construct string from sorted array
     sorted .= "," . a%A_Index%
  Return SubStr(sorted,2)               ; drop leading comma

}</lang>

AWK

Sort standard input (storing lines into an array) and output to standard output <lang awk>{

 line[NR] = $0

} END { # sort it with insertion sort

 for(i=1; i <= NR; i++) {
   value = line[i]
   j = i - 1
   while( ( j > 0) && ( line[j] > value ) ) {
     line[j+1] = line[j]
     j--
   }
   line[j+1] = value
 }
 #print it
 for(i=1; i <= NR; i++) {
   print line[i]
 }

}</lang>

BASIC

Translation of: REALbasic
Works with: QBasic

This version should work on any BASIC that can accept arrays as function arguments. <lang qbasic>DECLARE SUB InsertionSort (theList() AS INTEGER)

DIM n(10) AS INTEGER, L AS INTEGER, o AS STRING FOR L = 0 TO 10

   n(L) = INT(RND * 32768)

NEXT InsertionSort n() FOR L = 1 TO 10

   PRINT n(L); ";";

NEXT

SUB InsertionSort (theList() AS INTEGER)

   DIM insertionElementIndex AS INTEGER
   FOR insertionElementIndex = 1 TO UBOUND(theList)
       DIM insertionElement AS INTEGER
       insertionElement = theList(insertionElementIndex)
       DIM j AS INTEGER
       j = insertionElementIndex - 1
       DO WHILE (j >= 0)
           'necessary for BASICs without short-circuit evaluation
           IF (insertionElement < theList(j)) THEN
               theList(j + 1) = theList(j)
               j = j - 1
           ELSE
               EXIT DO
           END IF
       LOOP
       theList(j + 1) = insertionElement
   NEXT

END SUB</lang>

Output:
 1486 ; 9488 ; 9894 ; 17479 ; 18989 ; 23119 ; 23233 ; 24927 ; 25386 ; 26689 ;

BBC BASIC

Note that the array index is assumed to start at zero. <lang bbcbasic> DIM test(9)

     test() = 4, 65, 2, -31, 0, 99, 2, 83, 782, 1
     PROCinsertionsort(test(), 10)
     FOR i% = 0 TO 9
       PRINT test(i%) ;
     NEXT
     PRINT
     END
     
     DEF PROCinsertionsort(a(), n%)
     LOCAL i%, j%, t
     FOR i% = 1 TO n%-1
       t = a(i%)
       j% = i%
       WHILE j%>0 AND t<a(ABS(j%-1))
         a(j%) = a(j%-1)
         j% -= 1
       ENDWHILE
       a(j%) = t
     NEXT
     ENDPROC</lang>
Output:
       -31         0         1         2         2         4        65        83        99       782

Commodore BASIC

<lang basic> 10 DIM A(10): N=9 11 REM GENERATE SOME RANDOM NUMBERS AND PRINT THEM 12 FOR I=0 TO N: A(I)=INT(RND(1)*10)+1: NEXT: GOSUB 50 20 FOR J=1 TO N:KEY=A(J): I=J-1: GOSUB 30: A(I+1)=KEY: NEXT: GOSUB 50: END 30 IFI=-1 THEN RETURN 31 IFA(I)>KEY THEN A(I+1)=A(I):I=I-1: GOTO 30 32 RETURN 50 PRINT: FOR I=0 TO N: PRINTA(I): NEXT: RETURN </lang>

IS-BASIC

<lang IS-BASIC> 100 PROGRAM "InserSrt.bas" 110 RANDOMIZE 120 NUMERIC ARRAY(5 TO 21) 130 CALL INIT(ARRAY) 140 CALL WRITE(ARRAY) 150 CALL INSERTSORT(ARRAY) 160 CALL WRITE(ARRAY) 170 DEF INIT(REF A) 180 FOR I=LBOUND(A) TO UBOUND(A) 190 LET A(I)=RND(98)+1 200 NEXT 210 END DEF 220 DEF WRITE(REF A) 230 FOR I=LBOUND(A) TO UBOUND(A) 240 PRINT A(I); 250 NEXT 260 PRINT 270 END DEF 280 DEF INSERTSORT(REF A) 290 FOR J=LBOUND(A)+1 TO UBOUND(A) 300 LET I=J-1:LET SW=A(J) 310 DO WHILE I>=LBOUND(A) AND SW<A(I) 320 LET A(I+1)=A(I):LET I=I-1 330 LOOP 340 LET A(I+1)=SW 350 NEXT 360 END DEF</lang>

C

<lang c>#include <stdio.h>

void insertion_sort(int *a, int n) { for(size_t i = 1; i < n; ++i) { int tmp = a[i]; size_t j = i; while(j > 0 && tmp < a[j - 1]) { a[j] = a[j - 1]; --j; } a[j] = tmp; } }

int main () {

   int a[] = {4, 65, 2, -31, 0, 99, 2, 83, 782, 1};
   int n = sizeof a / sizeof a[0];
   int i;
   for (i = 0; i < n; i++)
       printf("%d%s", a[i], i == n - 1 ? "\n" : " ");
   insertion_sort(a, n);
   for (i = 0; i < n; i++)
       printf("%d%s", a[i], i == n - 1 ? "\n" : " ");
   return 0;

} </lang>

Output:
4 65 2 -31 0 99 2 83 782 1
-31 0 1 2 2 4 65 83 99 782

C++

Uses C++11. Compile with

g++ -std=c++11 insertion.cpp

Uses binary search via std::upper_bound() to find the insertion position in logarithmic time and then performs the insertion via std::rotate() in linear time. <lang cpp>#include <algorithm>

  1. include <iostream>
  2. include <iterator>

template <typename RandomAccessIterator, typename Predicate> void insertion_sort(RandomAccessIterator begin, RandomAccessIterator end,

                   Predicate p) {
 for (auto i = begin; i != end; ++i) {
   std::rotate(std::upper_bound(begin, i, *i, p), i, i + 1);
 }

}

template <typename RandomAccessIterator> void insertion_sort(RandomAccessIterator begin, RandomAccessIterator end) {

 insertion_sort(
     begin, end,
     std::less<
         typename std::iterator_traits<RandomAccessIterator>::value_type>());

}

int main() {

 int a[] = { 100, 2, 56, 200, -52, 3, 99, 33, 177, -199 };
 insertion_sort(std::begin(a), std::end(a));
 copy(std::begin(a), std::end(a), std::ostream_iterator<int>(std::cout, " "));
 std::cout << "\n";

}</lang>

Output:
-199 -52 2 3 33 56 99 100 177 200

C#

<lang csharp>namespace Sort {

 using System;
 static class InsertionSort<T> where T : IComparable {
   public static void Sort(T[] entries) {
     Sort(entries, 0, entries.Length - 1);
   }
   public static void Sort(T[] entries, Int32 first, Int32 last) {
     for (var i = first + 1; i <= last; i++) {
       var entry = entries[i];
       var j = i;
       while (j > first && entries[j - 1].CompareTo(entry) > 0)
         entries[j] = entries[--j];
       entries[j] = entry;
     }
   }
 }

}</lang> Example: <lang csharp> using Sort;

 using System;
 class Program {
   static void Main(String[] args) {
     var entries = new Int32[] { 3, 9, 4, 6, 8, 1, 7, 2, 5 };
     InsertionSort<Int32>.Sort(entries);
     Console.WriteLine(String.Join(" ", entries));
   }
 }</lang>

Clojure

<lang clojure> (defn insertion-sort [coll]

  (reduce (fn [result input]
            (let [[less more] (split-with #(< % input) result)]
              (concat less [input] more)))
          []
          coll))

</lang>

Translated from the Haskell example: <lang clojure> (defn in-sort! [data]

 (letfn [(insert ([raw x](insert [] raw x))

([sorted [y & raw] x] (if (nil? y) (conj sorted x) (if (<= x y ) (concat sorted [x,y] raw) (recur (conj sorted y) raw x )))))]

   (reduce insert [] data)))
Usage
(in-sort! [6,8,5,9,3,2,1,4,7])
Returns
[1 2 3 4 5 6 7 8 9]</lang>

CMake

<lang cmake># insertion_sort(var [value1 value2...]) sorts a list of integers. function(insertion_sort var)

 math(EXPR last "${ARGC} - 1")         # Sort ARGV[1..last].
 foreach(i RANGE 1 ${last})
   # Extend the sorted area to ARGV[1..i].
   set(b ${i})
   set(v ${ARGV${b}})
   # Insert v == ARGV[b] in sorted order. While b > 1, check if b is
   # too high, then decrement b. After loop, set ARGV[b] = v.
   while(b GREATER 1)
     math(EXPR a "${b} - 1")
     set(u ${ARGV${a}})
     # Now u == ARGV[a]. Pretend v == ARGV[b]. Compare.
     if(u GREATER ${v})
       # ARGV[a] and ARGV[b] are in wrong order. Fix by moving ARGV[a]
       # to ARGV[b], making room for later insertion of v.
       set(ARGV${b} ${u})
     else()
       break()
     endif()
     math(EXPR b "${b} - 1")
   endwhile()
   set(ARGV${b} ${v})
 endforeach(i)
 set(answer)
 foreach(i RANGE 1 ${last})
   list(APPEND answer ${ARGV${i}})
 endforeach(i)
 set("${var}" "${answer}" PARENT_SCOPE)

endfunction(insertion_sort)</lang>

<lang cmake>insertion_sort(result 33 11 44 22 66 55) message(STATUS "${result}") # -- 11;22;33;44;55;66</lang>

COBOL

This exerpt contains just enough of the procedure division to show the sort itself. The appropriate data division entries can be inferred. See also the entry for the Bubble sort for a full program. <lang COBOL> C-PROCESS SECTION.

          PERFORM E-INSERTION VARYING WB-IX-1 FROM 1 BY 1
                              UNTIL WB-IX-1 > WC-SIZE.

...

      E-INSERTION SECTION.
      E-000.
          MOVE WB-ENTRY(WB-IX-1) TO WC-TEMP.
          SET WB-IX-2 TO WB-IX-1.
          PERFORM F-PASS UNTIL WB-IX-2 NOT > 1 OR
                               WC-TEMP NOT < WB-ENTRY(WB-IX-2 - 1).
          IF WB-IX-1 NOT = WB-IX-2
             MOVE WC-TEMP TO WB-ENTRY(WB-IX-2).
      E-999.
          EXIT.
      F-PASS SECTION.
      F-000.
          MOVE WB-ENTRY(WB-IX-2 - 1) TO WB-ENTRY(WB-IX-2).
          SET WB-IX-2                DOWN BY 1.
      F-999.
          EXIT.</lang>

And a fully runnable version, by Steve Williams

Works with: GnuCOBOL

<lang COBOL>

       >>SOURCE FORMAT FREE
  • > This code is dedicated to the public domain
  • > This is GNUCOBOL 2.0

identification division. program-id. insertionsort. environment division. configuration section. repository. function all intrinsic. data division. working-storage section. 01 filler.

   03  a pic 99.
   03  a-lim pic 99 value 10.
   03  array occurs 10 pic 99.

01 filler.

   03  s pic 99.
   03  o pic 99.
   03  o1 pic 99.
   03  sorted-len pic 99.
   03  sorted-lim pic 99 value 10.
   03  sorted-array occurs 10 pic 99.

procedure division. start-insertionsort.

   *> fill the array
   compute a = random(seconds-past-midnight)
   perform varying a from 1 by 1 until a > a-lim
       compute array(a) = random() * 100
   end-perform
   *> display the array
   perform varying a from 1 by 1 until a > a-lim
       display space array(a) with no advancing
   end-perform
   display  space 'initial array'
   *> sort the array
   move 0 to sorted-len
   perform varying a from 1 by 1 until a > a-lim
       *> find the insertion point
       perform varying s from 1 by 1
       until s > sorted-len
       or array(a) <= sorted-array(s)
           continue
       end-perform
       *>open the insertion point
       perform varying o from sorted-len by -1
       until o < s
           compute o1 = o + 1
           move sorted-array(o) to sorted-array(o1)
       end-perform
       *> move the array-entry to the insertion point
       move array(a) to sorted-array(s)
       add 1 to sorted-len
   end-perform
   *> display the sorted array
   perform varying s from 1 by 1 until s > sorted-lim
       display space sorted-array(s) with no advancing
   end-perform
   display space 'sorted array'
   stop run
   .

end program insertionsort.</lang>

Output:
prompt$ cobc -xj insertionsort.cob
 89 04 86 32 65 62 83 75 24 69 initial array
 04 24 32 62 65 69 75 83 86 89 sorted array

Common Lisp

<lang lisp>(defun span (predicate list)

 (let ((tail (member-if-not predicate list)))
   (values (ldiff list tail) tail)))

(defun less-than (x)

 (lambda (y) (< y x)))

(defun insert (list elt)

 (multiple-value-bind (left right) (span (less-than elt) list)
   (append left (list elt) right)))

(defun insertion-sort (list)

 (reduce #'insert list :initial-value nil))</lang>

<lang lisp>(defun insertion-sort (sequence &optional (predicate #'<))

 (if (cdr sequence)
     (insert (car sequence)                 ;; insert the current item into
             (insertion-sort (cdr sequence) ;; the already-sorted
                             predicate)     ;; remainder of the list
             predicate)
     sequence)) ; a list of one element is already sorted

(defun insert (item sequence predicate)

 (cond ((null sequence) (list item))
       ((funcall (complement predicate)      ;; if the first element of the list
                             (car sequence)  ;; isn't better than the item,
                             item)           ;; cons the item onto
        (cons item sequence))                ;; the front of the list
       (t (cons (car sequence) ;; otherwise cons the first element onto the front of
                (insert item   ;; the list of the item sorted with the rest of the list
                        (cdr sequence)
                        predicate)))))</lang>

D

<lang d>void insertionSort(T)(T[] data) pure nothrow @safe @nogc {

   foreach (immutable i, value; data[1 .. $]) {
       auto j = i + 1;
       for ( ; j > 0 && value < data[j - 1]; j--)
           data[j] = data[j - 1];
       data[j] = value;
   }

}

void main() {

   import std.stdio;
   auto items = [28, 44, 46, 24, 19, 2, 17, 11, 25, 4];
   items.insertionSort;
   items.writeln;

}</lang>

Output:
[2, 4, 11, 17, 19, 24, 25, 28, 44, 46]

Higher Level Version

Translation of: C++

<lang d>import std.stdio, std.range, std.algorithm, std.traits;

void insertionSort(R)(R arr) if (hasLength!R && isRandomAccessRange!R && hasSlicing!R) {

   foreach (immutable i; 1 .. arr.length)
       bringToFront(arr[0 .. i].assumeSorted.upperBound(arr[i]), arr[i .. i + 1]);

}

void main() {

   import std.random, std.container;
   auto arr1 = [28, 44, 46, 24, 19, 2, 17, 11, 25, 4];
   arr1.insertionSort;
   assert(arr1.isSorted);
   writeln("arr1 sorted: ", arr1);
   auto arr2 = Array!int([28, 44, 46, 24, 19, 2, 17, 11, 25, 4]);
   arr2[].insertionSort;
   assert(arr2[].isSorted);
   writeln("arr2 sorted: ", arr2[]);
   // Random data test.
   int[10] buf;
   foreach (immutable _; 0 .. 100_000) {
       auto arr3 = buf[0 .. uniform(0, $)];
       foreach (ref x; arr3)
           x = uniform(-6, 6);
       arr3.insertionSort;
       assert(arr3.isSorted);
   }

}</lang>

Output:
arr1 sorted: [2, 4, 11, 17, 19, 24, 25, 28, 44, 46]
arr2 sorted: [2, 4, 11, 17, 19, 24, 25, 28, 44, 46]

Delphi

Array sort

Dynamic array is a 0-based array of variable length

Static array is an arbitrary-based array of fixed length <lang Delphi>program TestInsertionSort;

{$APPTYPE CONSOLE}

{.$DEFINE DYNARRAY} // remove '.' to compile with dynamic array

type

 TItem = Integer;   // declare ordinal type for array item

{$IFDEF DYNARRAY}

 TArray = array of TItem;          // dynamic array

{$ELSE}

 TArray = array[0..15] of TItem;   // static array

{$ENDIF}

procedure InsertionSort(var A: TArray); var

 I, J: Integer;
 Item: TItem;

begin

 for I:= 1 + Low(A) to High(A) do begin
   Item:= A[I];
   J:= I - 1;
   while (J >= Low(A)) and (A[J] > Item) do begin
     A[J + 1]:= A[J];
     Dec(J);
   end;
   A[J + 1]:= Item;
 end;

end;

var

 A: TArray;
 I: Integer;

begin {$IFDEF DYNARRAY}

 SetLength(A, 16);

{$ENDIF}

 for I:= Low(A) to High(A) do
   A[I]:= Random(100);
 for I:= Low(A) to High(A) do
   Write(A[I]:3);
 Writeln;
 InsertionSort(A);
 for I:= Low(A) to High(A) do
   Write(A[I]:3);
 Writeln;
 Readln;

end.</lang>

Output:
  0  3 86 20 27 67 31 16 37 42  8 47  7 84  5 29
  0  3  5  7  8 16 20 27 29 31 37 42 47 67 84 86

String sort

// string is 1-based variable-length array of Char <lang Delphi>procedure InsertionSort(var S: string); var

 I, J, L: Integer;
 Ch: Char;

begin

 L:= Length(S);
 for I:= 2 to L do begin
   Ch:= S[I];
   J:= I - 1;
   while (J > 0) and (S[J] > Ch) do begin
     S[J + 1]:= S[J];
     Dec(J);
   end;
   S[J + 1]:= Ch;
 end;

end;</lang>

// in : S = 'the quick brown fox jumps over the lazy dog'
// out: S = '        abcdeeefghhijklmnoooopqrrsttuuvwxyz'

E

Some lines in this example are too long (more than 80 characters). Please fix the code if it's possible and remove this message.

A direct conversion of the pseudocode.

<lang e>def insertionSort(array) {

   for i in 1..!(array.size()) {
       def value := array[i]
       var j := i-1
       while (j >= 0 && array[j] > value) {
           array[j + 1] := array[j]
           j -= 1
       }
       array[j+1] := value
  }

}</lang>

Test case:

<lang e>? def a := [71, 53, 22, 24, 83, 54, 39, 78, 65, 26, 60, 75, 67, 27, 52, 59, 93, 62, 85, 99, 88, 10, 91, 85, 13, 17, 14, 96, 55, 10, 61, 94, 27, 50, 75, 40, 47, 63, 10, 23].diverge() > insertionSort(a) > a

  1. value: [10, 10, 10, 13, 14, 17, 22, 23, 24, 26, 27, 27, 39, 40, 47, 50, 52, 53, 54, 55, 59, 60, 61, 62, 63, 65, 67, 71, 75, 75, 78, 83, 85, 85, 88, 91, 93, 94, 96, 99].diverge()</lang>

Easyprog.online

<lang easyprog.online>subr sort

 for i = 1 to len data[] - 1
   h = data[i]
   j = i - 1
   while j >= 0 and h < data[j]
     data[j + 1] = data[j]
     j -= 1
   .
   data[j + 1] = h
 .

. data[] = [ 29 4 72 44 55 26 27 77 92 5 ] call sort print data[]</lang>

Eiffel

Works with: EiffelStudio version 6.6 (with provisional loop syntax)

This solution is shown in the routine sort of the class MY_SORTED_SET.

For a more complete explanation of the Eiffel sort examples, see the Bubble sort.

<lang eiffel>class

   MY_SORTED_SET [G -> COMPARABLE]

inherit

   TWO_WAY_SORTED_SET [G]
       redefine
           sort
       end

create

   make

feature

   sort
           -- Insertion sort
       local
           l_j: INTEGER
           l_value: like item
       do
           across 2 |..| count as ii loop
               from
                   l_j := ii.item - 1
                   l_value := Current.i_th (ii.item)
               until
                   l_j < 1 or Current.i_th (l_j) <= l_value
               loop
                   Current.i_th (l_j + 1) := Current.i_th (l_j)
                   l_j := l_j - 1
               end
               Current.i_th (l_j + 1) := l_value
           end
       end

end</lang>

Elena

ELENA 4.x : <lang elena>import extensions;

extension op {

   insertionSort()
       = self.clone().insertionSort(0, self.Length - 1);

   insertionSort(int first, int last)
   {
       for(int i := first + 1, i <= last, i += 1)
       {
           var entry := self[i];
           int j := i;

           while (j > first && self[j - 1] > entry)
           {
               self[j] := self[j - 1];

               j -= 1
           };

           self[j] := entry
       }
   }

}

public program() {

   var list := new int[]{3, 9, 4, 6, 8, 1, 7, 2, 5};

   console.printLine("before:", list.asEnumerable());
   console.printLine("after :", list.insertionSort().asEnumerable());

}</lang>

Output:
before:3,9,4,6,8,1,7,2,5
after :1,2,3,4,5,6,7,8,9

Elixir

<lang elixir>defmodule Sort do

 def insert_sort(list) when is_list(list), do: insert_sort(list, [])
 
 def insert_sort([], sorted), do: sorted
 def insert_sort([h | t], sorted), do: insert_sort(t, insert(h, sorted))
 
 defp insert(x, []), do: [x]
 defp insert(x, sorted) when x < hd(sorted), do: [x | sorted]
 defp insert(x, [h | t]), do: [h | insert(x, t)]

end</lang>

Example:

iex(10)> Sort.insert_sort([5,3,9,4,1,6,8,2,7])
[1, 2, 3, 4, 5, 6, 7, 8, 9]

Emacs Lisp

<lang lisp>

(defun min-or-max-of-2-numbers (n1 n2 rel)

 "n1 and n2 are two numbers, rel can be '< or '> according to

what sort of sorting is wanted, this function returns the greater or smaller number n1 or n2"

 (cond
  ((eval (list rel n1 n2)) n1)
  (t n2)))
 

(defun min-or-max-of-a-list (lon rel)

 "lon is a list of numbers, rel is '< or '>, this fonction

returns the higher or lower number of the list"

 (if (cdr lon)
     (min-or-max-of-2-numbers (car lon) 

(min-or-max-of-a-list (cdr lon) rel) rel)

   (car lon)))

(defun remove-number-from-list (n lon)

 "lon is a list of numbers, n is a number belonging to the list,

this function returns the same list but the number n. If n is present twice or more, it will be removed only once"

 (if lon
     (cond
      ((= (car lon) n) (cdr lon))
      (t (cons (car lon) (remove-number-from-list n (cdr lon)))))
   nil))


(defun sort-insertion (lon rel)

 "lon is a list of numbers, rel can be '< or '>, this function

returns a list containing the same elements but which is sorted according to rel"

 (if lon
     (cons (min-or-max-of-a-list lon rel)

(sort-insertion (remove-number-from-list (min-or-max-of-a-list lon rel) lon) rel))

   nil))
let's try it

(sort-insertion (list 1 2 3 9 8 7 25 12 3 2 1) '>)

</lang>

Erlang

<lang Erlang>-module(sort). -export([insertion/1]).

insertion(L) -> lists:foldl(fun insert/2, [], L).

insert(X,[]) -> [X]; insert(X,L=[H|_]) when X =< H -> [X|L]; insert(X,[H|T]) -> [H|insert(X, T)].</lang>

And the calls: <lang erlang>1> c(sort). {ok,sort} 2> sort:insertion([5,3,9,4,1,6,8,2,7]). [1,2,3,4,5,6,7,8,9]</lang>

ERRE

Note: array index is assumed to start at zero. <lang ERRE> PROGRAM INSERTION_SORT

DIM A[9]

PROCEDURE INSERTION_SORT(A[])

   LOCAL I,J
   FOR I=0 TO UBOUND(A,1) DO
       V=A[I]
       J=I-1
       WHILE J>=0 DO
         IF A[J]>V THEN
           A[J+1]=A[J]
           J=J-1
          ELSE
           EXIT
         END IF
       END WHILE
       A[J+1]=V
   END FOR

END PROCEDURE

BEGIN

 A[]=(4,65,2,-31,0,99,2,83,782,1)
 FOR I%=0 TO UBOUND(A,1) DO
    PRINT(A[I%];)
 END FOR
 PRINT
 INSERTION_SORT(A[])
 FOR I%=0 TO UBOUND(A,1) DO
    PRINT(A[I%];)
 END FOR
 PRINT

END PROGRAM </lang>

Output:
 4  65  2 -31  0  99  2  83  782  1
-31  0  1  2  2  4  65  83  99  782

Euphoria

<lang euphoria>function insertion_sort(sequence s)

   object temp
   integer j
   for i = 2 to length(s) do
       temp = s[i]
       j = i-1
       while j >= 1 and compare(s[j],temp) > 0 do
           s[j+1] = s[j]
           j -= 1
       end while
       s[j+1] = temp
   end for
   return s

end function

include misc.e constant s = {4, 15, "delta", 2, -31, 0, "alfa", 19, "gamma", 2, 13, "beta", 782, 1}

puts(1,"Before: ") pretty_print(1,s,{2}) puts(1,"\nAfter: ") pretty_print(1,insertion_sort(s),{2})</lang>

Output:
Before: {
  4,
  15,
  "delta",
  2,
  -31,
  0,
  "alfa",
  19,
  "gamma",
  2,
  13,
  "beta",
  782,
  1
}
After: {
  -31,
  0,
  1,
  2,
  2,
  4,
  13,
  15,
  19,
  782,
  "alfa",
  "beta",
  "delta",
  "gamma"
}

F#

Procedural Version <lang fsharp> // This function performs an insertion sort with an array. // The input parameter is a generic array (any type that can perform comparison). // As is typical of functional programming style the input array is not modified; // a copy of the input array is made and modified and returned. let insertionSort (A: _ array) =

   let B = Array.copy A
   for i = 1 to B.Length - 1 do
       let mutable value = B.[i]
       let mutable j = i - 1
       while (j >= 0 && B.[j] > value) do
           B.[j+1] <- B.[j]
           j <- j - 1
       B.[j+1] <- value
   B  // the array B is returned

</lang>

Functional Version <lang fsharp> let insertionSort collection =

   // Inserts an element into its correct place in a sorted collection
   let rec sinsert element collection =
       match element, collection with
       | x, [] -> [x]
       | x, y::ys when x < y -> x::y::ys
       | x, y::ys -> y :: (ys |> sinsert x)
   // Performs Insertion Sort
   let rec isort acc collection = 
       match collection, acc with
       | [], _ -> acc
       | x::xs, ys -> xs |> isort (sinsert x ys)
   collection |> isort []

</lang>

Forth

<lang forth>: insert ( start end -- start )

 dup @ >r ( r: v )	\ v = a[i]
 begin
   2dup <			\ j>0
 while
   r@ over cell- @ <		\ a[j-1] > v
 while
   cell-			\ j--
   dup @ over cell+ !		\ a[j] = a[j-1]
 repeat then
 r> swap ! ;		\ a[j] = v

sort ( array len -- )
 1 ?do dup i cells + insert loop drop ;

create test 7 , 3 , 0 , 2 , 9 , 1 , 6 , 8 , 4 , 5 , test 10 sort test 10 cells dump</lang>

Fortran

Works with: Fortran version 90 and later

<lang fortran>subroutine sort(n, a)

   implicit none
   integer :: n, i, j
   real :: a(n), x
   
   do i = 2, n
       x = a(i)
       j = i - 1
       do while (j >= 1)
           if (a(j) <= x) exit
           a(j + 1) = a(j)
           j = j - 1
       end do
       a(j + 1) = x
   end do

end subroutine</lang>

Alternate Fortran 77 version

This also could have a problem with the compound test always being fully evaluated, so... <lang fortran> SUBROUTINE SORT(N,A)

     IMPLICIT NONE
     INTEGER N,I,J
     DOUBLE PRECISION A(N),X
     DO 30 I = 2,N
       X = A(I)
       J = I
  10   J = J - 1

Can't IF (J.EQ.0 .OR. A(J).LE.X) GO TO 20 in case both sides are ALWAYS evaluated.

       IF (J.EQ.0) GO TO 20
       IF (A(J).LE.X) GO TO 20
       A(J + 1) = A(J)
       GO TO 10
  20   A(J + 1) = X
  30 CONTINUE
     END</lang>

FreeBASIC

<lang freebasic>' version 20-10-2016 ' compile with: fbc -s console ' for boundry checks on array's compile with: fbc -s console -exx

Sub insertionSort( arr() As Long )

 ' sort from lower bound to the highter bound
 ' array's can have subscript range from -2147483648 to +2147483647
 Dim As Long lb = LBound(arr)
 Dim As Long i, j, value
 For i = lb +1 To UBound(arr)
   value = arr(i)
   j = i -1
   While j >= lb  And arr(j) > value
     arr(j +1) = arr(j)
     j = j -1
   Wend
   arr(j +1) = value
 Next

End Sub

' ------=< MAIN >=------

Dim As Long i, array(-7 To 7) Dim As Long a = LBound(array), b = UBound(array)

Randomize Timer For i = a To b : array(i) = i  : Next For i = a To b ' little shuffle

 Swap array(i), array(Int(Rnd * (b - a +1)) + a)

Next

Print "unsort "; For i = a To b : Print Using "####"; array(i); : Next : Print insertionSort(array()) ' sort the array Print " sort "; For i = a To b : Print Using "####"; array(i); : Next : Print


' empty keyboard buffer While Inkey <> "" : Wend Print : Print "hit any key to end program" Sleep End</lang>

Output:
unsort   -7  -1   4  -6   5   2   1  -2   0  -5  -4   6  -3   7   3
  sort   -7  -6  -5  -4  -3  -2  -1   0   1   2   3   4   5   6   7

GAP

<lang gap>InsertionSort := function(L)

 local n, i, j, x;
 n := Length(L);
 for i in [ 2 .. n ] do
   x := L[i];
   j := i - 1;
   while j >= 1 and L[j] > x do
     L[j + 1] := L[j];
     j := j - 1;
   od;
   L[j + 1] := x;
 od;

end;

s := "BFKRIMPOQACNESWUTXDGLVZHYJ"; InsertionSort(s); s;

  1. "ABCDEFGHIJKLMNOPQRSTUVWXYZ"</lang>

Go

<lang go>package main

import "fmt"

func insertionSort(a []int) {

   for i := 1; i < len(a); i++ {
       value := a[i]
       j := i - 1
       for j >= 0 && a[j] > value {
           a[j+1] = a[j]
           j = j - 1
       }
       a[j+1] = value
   }

}

func main() {

   list := []int{31, 41, 59, 26, 53, 58, 97, 93, 23, 84}
   fmt.Println("unsorted:", list)
   insertionSort(list)
   fmt.Println("sorted!  ", list)

}</lang>

Output:
unsorted: [31 41 59 26 53 58 97 93 23 84]
sorted!   [23 26 31 41 53 58 59 84 93 97]

A generic version that takes any container that conforms to sort.Interface: <lang go>package main

import (

 "fmt"
 "sort"

)

func insertionSort(a sort.Interface) {

   for i := 1; i < a.Len(); i++ {
       for j := i; j > 0 && a.Less(j, j-1); j-- {
           a.Swap(j-1, j)
       }
   }

}

func main() {

   list := []int{31, 41, 59, 26, 53, 58, 97, 93, 23, 84}
   fmt.Println("unsorted:", list)
   insertionSort(sort.IntSlice(list))
   fmt.Println("sorted!  ", list)

}</lang>

Output:
unsorted: [31 41 59 26 53 58 97 93 23 84]
sorted!   [23 26 31 41 53 58 59 84 93 97]

Using binary search to locate the place to insert: <lang go>package main

import (

 "fmt"
 "sort"

)

func insertionSort(a []int) {

   for i := 1; i < len(a); i++ {
       value := a[i]
       j := sort.Search(i, func(k int) bool { return a[k] > value })
       copy(a[j+1:i+1], a[j:i])
       a[j] = value
   }

}

func main() {

   list := []int{31, 41, 59, 26, 53, 58, 97, 93, 23, 84}
   fmt.Println("unsorted:", list)
   insertionSort(list)
   fmt.Println("sorted!  ", list)

}</lang>

Output:
unsorted: [31 41 59 26 53 58 97 93 23 84]
sorted!   [23 26 31 41 53 58 59 84 93 97]

Groovy

Solution: <lang groovy>def insertionSort = { list ->

   def size = list.size()
   (1..<size).each { i ->
       def value = list[i]
       def j = i - 1
       for (; j >= 0 && list[j] > value; j--) {
           print "."; list[j+1] = list[j]
       }
       print "."; list[j+1] = value
   }
   list

}</lang>

Test: <lang groovy>println (insertionSort([23,76,99,58,97,57,35,89,51,38,95,92,24,46,31,24,14,12,57,78,4])) println (insertionSort([88,18,31,44,4,0,8,81,14,78,20,76,84,33,73,75,82,5,62,70,12,7,1]))</lang>

Output:
..................................................................................................................................................................[4, 12, 14, 23, 24, 24, 31, 35, 38, 46, 51, 57, 57, 58, 76, 78, 89, 92, 95, 97, 99]
...............................................................................................................................................................[0, 1, 4, 5, 7, 8, 12, 14, 18, 20, 31, 33, 44, 62, 70, 73, 75, 76, 78, 81, 82, 84, 88]

Haskell

<lang haskell>import Data.List (insert)

insertionSort :: Ord a => [a] -> [a] insertionSort = foldr insert []

-- Example use: -- *Main> insertionSort [6,8,5,9,3,2,1,4,7] -- [1,2,3,4,5,6,7,8,9]</lang>

HicEst

<lang hicest>DO i = 2, LEN(A)

  value = A(i)
  j = i - 1
1 IF( j > 0 ) THEN
    IF( A(j) > value ) THEN
      A(j+1) = A(j)
      j = j - 1
      GOTO 1 ! no WHILE in HicEst
    ENDIF
  ENDIF
  A(j+1) = value

ENDDO</lang>

Icon and Unicon

<lang Icon>procedure main() #: demonstrate various ways to sort a list and string

  demosort(insertionsort,[3, 14, 1, 5, 9, 2, 6, 3],"qwerty")

end

procedure insertionsort(X,op) #: return sorted X local i,temp

  op := sortop(op,X)                # select how and what we sort
  
  every i := 2 to *X do {
     temp := X[j := i]
     while op(temp,X[1 <= (j -:= 1)]) do 
        X[j+1] := X[j]
     X[j+1] := temp
     }
  return X

end</lang>

Note: This example relies on the supporting procedures 'sortop', and 'demosort' in Bubble Sort. The full demosort exercises the named sort of a list with op = "numeric", "string", ">>" (lexically gt, descending),">" (numerically gt, descending), a custom comparator, and also a string.

abbreviated:
Sorting Demo using procedure insertionsort
  on list : [ 3 14 1 5 9 2 6 3 ]
    with op = &null:         [ 1 2 3 3 5 6 9 14 ]   (0 ms)
  ...
  on string : "qwerty"
    with op = &null:         "eqrtwy"   (0 ms)

Io

<lang io> List do(

 insertionSortInPlace := method(
   for(j, 1, size - 1,
     key := at(j)
     i := j - 1
     while(i >= 0 and at(i) > key,
       atPut(i + 1, at(i))
       i = i - 1
     )
     atPut(i + 1, key)
   )
 )

)

lst := list(7, 6, 5, 9, 8, 4, 3, 1, 2, 0) lst insertionSortInPlace println # ==> list(0, 1, 2, 3, 4, 5, 6, 7, 8, 9)</lang>

A shorter, but slightly less efficient, version: <lang io>List do(

   insertionSortInPlace := method(
       # In fact, we could've done slice(1, size - 1) foreach(...)
       # but creating a new list in memory can only make it worse.
       foreach(idx, key,
           newidx := slice(0, idx) map(x, x > key) indexOf(true)
           if(newidx, insertAt(removeAt(idx), newidx))
       )
   self)

)

lst := list(7, 6, 5, 9, 8, 4, 3, 1, 2, 0) lst insertionSortInPlace println # ==> list(0, 1, 2, 3, 4, 5, 6, 7, 8, 9) </lang>

J

Generally, this task should be accomplished in J using /:~. Here we take an approach that's more comparable with the other examples on this page.

Solution inspired by the Common LISP solution: <lang J>isort=:((>: # ]) , [ , < #])/</lang> Example of use: <lang J> isort 32 4 1 34 95 3 2 120 _38 _38 1 2 3 4 32 34 95 120</lang>

Java

<lang java5>public static void insertSort(int[] A){

 for(int i = 1; i < A.length; i++){
   int value = A[i];
   int j = i - 1;
   while(j >= 0 && A[j] > value){
     A[j + 1] = A[j];
     j = j - 1;
   }
   A[j + 1] = value;
 }

}</lang>

Using some built-in algorithms (warning: not stable, due to the lack of an "upper bound" binary search function)

Translation of: C++

<lang java5>public static <E extends Comparable<? super E>> void insertionSort(List<E> a) {

 for (int i = 1; i < a.size(); i++) {
   int j = Math.abs(Collections.binarySearch(a.subList(0, i), a.get(i)) + 1);
   Collections.rotate(a.subList(j, i+1), j - i);
 }

} public static <E extends Comparable<? super E>> void insertionSort(E[] a) {

 for (int i = 1; i < a.length; i++) {
   E x = a[i];
   int j = Math.abs(Arrays.binarySearch(a, 0, i, x) + 1);
   System.arraycopy(a, j, a, j+1, i-j);
   a[j] = x;
 }

}</lang>

JavaScript

<lang javascript> function insertionSort (a) {

   for (var i = 0; i < a.length; i++) {
       var k = a[i];
       for (var j = i; j > 0 && k < a[j - 1]; j--)
           a[j] = a[j - 1];
       a[j] = k;
   }
   return a;

}

var a = [4, 65, 2, -31, 0, 99, 83, 782, 1]; insertionSort(a); document.write(a.join(" "));</lang>

jq

Works with: jq version 1.4

The insertion sort can be expressed directly in jq as follows: <lang jq>def insertion_sort:

 reduce .[] as $x ([]; insert($x));</lang>where insert/1 inserts its argument into its input, which can, by construction, be assumed here to be sorted.  This algorithm will work in jq for any JSON array.

The following solution uses an "industrial strength" implementation of bsearch (binary search) that requires the following control structure: <lang jq># As soon as "condition" is true, then emit . and stop: def do_until(condition; next):

 def u: if condition then . else (next|u) end;
 u;</lang>

bsearch is the only non-trivial part of this solution, and so we include its complete specification:

Assuming the input array is sorted, bsearch/1 returns the index of the target if the target is in the input array; and otherwise (-1 - ix), where ix is the insertion point that would leave the array sorted.

If the input is not sorted, bsearch will terminate but with irrelevant results.<lang jq>def bsearch(target):

 if length == 0 then -1
 elif length == 1 then
    if target == .[0] then 0 elif target < .[0] then -1 else -2 end
 else . as $in
   # state variable: [start, end, answer]
   # where start and end are the upper and lower offsets to use.
     | [0, length-1, null]
     | do_until( .[0] > .[1] ;
               (if .[2] != null then (.[1] = -1) # i.e. break
                else
                  ( ( (.[1] + .[0]) / 2 ) | floor ) as $mid
                | $in[$mid] as $monkey
                | if $monkey == target  then (.[2] = $mid)     # success
                  elif .[0] == .[1]     then (.[1] = -1)       # failure
                  elif $monkey < target then (.[0] = ($mid + 1))
                  else (.[1] = ($mid - 1))
                  end
                end ))
   | if .[2] == null then # compute the insertion point
        if $in[ .[0] ] < target then (-2 -.[0]) 
        else (-1 -.[0])
        end
     else .[2]
     end
 end;
  1. insert x assuming input is sorted

def insert(x):

 if length == 0 then [x]
 else
   bsearch(x) as $i 
   | ( if $i < 0 then -(1+$i) else $i end ) as $i
   | .[0:$i] + [x] + .[$i:]
 end ;

def insertion_sort:

  reduce .[] as $x ([]; insert($x));</lang>

Example:<lang jq>[1, 2, 1, 1.1, -1.1, null, [null], {"null":null}] | insertion_sort</lang>

Output:
[null,-1.1,1,1,1.1,2,[null],{"null":null}]


Julia

<lang julia># v0.6

function insertionsort!(A::Array{T}) where T <: Number

   for i in 1:length(A)-1
       value = A[i+1]
       j = i
       while j > 0 && A[j] > value
           A[j+1] = A[j]
           j -= 1
       end
       A[j+1] = value
   end
   return A

end

x = randn(5) @show x insertionsort!(x)</lang>

Output:
x = [-1.24011, -1.23848, 0.176698, -1.01986, 0.830544]
insertionsort!(x) = [-1.24011, -1.23848, -1.01986, 0.176698, 0.830544]

Kotlin

<lang kotlin>fun insertionSort(array: IntArray) {

   for (index in 1 until array.size) {
       val value = array[index]
       var subIndex = index - 1
       while (subIndex >= 0 && array[subIndex] > value) {
           array[subIndex + 1] = array[subIndex]
           subIndex--
       }
       array[subIndex + 1] = value
   }

}

fun main(args: Array<String>) {

   val numbers = intArrayOf(5, 2, 3, 17, 12, 1, 8, 3, 4, 9, 7)
   fun printArray(message: String, array: IntArray) = with(array) {
       print("$message [")
       forEachIndexed { index, number ->
           print(if (index == lastIndex) number else "$number, ")
       }
       println("]")
   }
   printArray("Unsorted:", numbers)
   insertionSort(numbers)
   printArray("Sorted:", numbers)

}</lang>

Output:
Unsorted: [5, 2, 3, 17, 12, 1, 8, 3, 4, 9, 7]
Sorted:   [1, 2, 3, 3, 4, 5, 7, 8, 9, 12, 17]

Liberty BASIC

<lang lb> itemCount = 20

   dim A(itemCount)
   for i = 1 to itemCount
       A(i) = int(rnd(1) * 100)
   next i
   print "Before Sort"
   gosub [printArray]

'--- Insertion sort algorithm

   for i = 2 to itemCount
       value = A(i)
       j = i-1
       while j >= 0 and A(j) > value
           A(j+1) = A(j)
           j = j-1
       wend
       A(j+1) = value
   next

'--- end of (Insertion sort algorithm)

   print "After Sort"
   gosub [printArray]

end

[printArray]

   for i = 1 to itemCount
       print using("###", A(i));
   next i
   print

return</lang>

Lua

<lang lua>function bins(tb, val, st, en)

 local st, en = st or 1, en or #tb
 local mid = math.floor((st + en)/2)
 if en == st then return tb[st] > val and st or st+1
 else return tb[mid] > val and bins(tb, val, st, mid) or bins(tb, val, mid+1, en)
 end

end function isort(t)

 local ret = {t[1], t[2]}
 for i = 3, #t do
   table.insert(ret, bins(ret, t[i]), t[i])
 end
 return ret

end

print(unpack(isort{4,5,2,7,8,3}))</lang>

Maple

<lang Maple>arr := Array([17,3,72,0,36,2,3,8,40,0]): len := numelems(arr): for i from 2 to len do val := arr[i]: j := i-1: while(j > 0 and arr[j] > val) do arr[j+1] := arr[j]: j--: end do: arr[j+1] := val: end do: arr;</lang>

Output:
[0,0,2,3,3,8,17,36,40,72]

Mathematica

<lang Mathematica>insertionSort[a_List] := Module[{A = a},

 For[i = 2, i <= Length[A], i++,
  value = Ai;    j = i - 1;
  While[j >= 1 && Aj > value, Aj + 1 = Aj; j--;];
  Aj + 1 = value;]; 

A ]</lang>

insertionSort@{ 2, 1, 3, 5}
{1, 2, 3, 5}

MATLAB / Octave

This is a direct translation of the pseudo-code above, except that it has been modified to compensate for MATLAB's 1 based arrays. <lang MATLAB>function list = insertionSort(list)

   for i = (2:numel(list))
       
       value = list(i);
       j = i - 1;
       
       while (j >= 1) && (list(j) > value)
           list(j+1) = list(j);
           j = j-1;
       end
       
       list(j+1) = value;
                  
   end %for

end %insertionSort</lang>

Sample Usage: <lang MATLAB>>> insertionSort([4 3 1 5 6 2])

ans =

    1     2     3     4     5     6</lang>

Maxima

<lang maxima>insertion_sort(u) := block(

  [n: length(u), x, j],
  for i from 2 thru n do (
     x: u[i],
     j: i - 1,
     while j >= 1 and u[j] > x do (
        u[j + 1]: u[j],
        j: j - 1      
     ),
     u[j + 1]: x
  )

)$</lang>

MAXScript

<lang MAXScript> fn inSort arr = ( arr = deepcopy arr for i = 1 to arr.count do ( j = i while j > 1 and arr[j-1] > arr[j] do ( swap arr[j] arr[j-1] j -= 1 ) ) return arr ) </lang> Output: <lang MAXScript> b = for i in 1 to 20 collect random 1 40

  1. (2, 28, 35, 31, 27, 24, 2, 22, 15, 34, 9, 10, 22, 40, 26, 5, 23, 6, 18, 33)

a = insort b

  1. (2, 2, 5, 6, 9, 10, 15, 18, 22, 22, 23, 24, 26, 27, 28, 31, 33, 34, 35, 40)

</lang>

ML

mLite

Translation of: OCaml

<lang ocaml>fun insertion_sort L = let fun insert (x,[]) = [x] | (x, y :: ys) = if x <= y then x :: y :: ys else y :: insert (x, ys) in foldr (insert,[]) L end;

println ` insertion_sort [6,8,5,9,3,2,1,4,7]; </lang> Output

[1, 2, 3, 4, 5, 6, 7, 8, 9]

Standard ML

<lang sml>fun insertion_sort cmp = let

 fun insert (x, []) = [x]
   | insert (x, y::ys) =
      case cmp (x, y) of GREATER => y :: insert (x, ys)
                       | _       => x :: y :: ys

in

foldl insert []

end;

insertion_sort Int.compare [6,8,5,9,3,2,1,4,7];</lang>

Modula-3

Translation of: Ada

<lang modula3>MODULE InsertSort;

PROCEDURE IntSort(VAR item: ARRAY OF INTEGER) =

 VAR j, value: INTEGER;
 BEGIN
   FOR i := FIRST(item) + 1 TO LAST(item) DO
     value := item[i];
     j := i - 1;
     WHILE j >= FIRST(item) AND item[j] > value DO
       item[j + 1] := item[j];
       DEC(j);
     END;
     item[j + 1] := value;
   END;
 END IntSort;

END InsertSort.</lang>

N/t/roff

Works with: GNU Troff version 1.22.2

Sliding method

<lang N/t/roff>.de end .. .de array . nr \\$1.c 0 1 . de \\$1.push end . nr \\$1..\\\\n+[\\$1.c] \\\\$1 . end . de \\$1.pushln end . if \\\\n(.$>0 .\\$1.push \\\\$1 . if \\\\n(.$>1 \{ \ . shift . \\$1.pushln \\\\$@ . \} . end . de \\$1.dump end . nr i 0 1 . ds out " . while \\\\n+i<=\\\\n[\\$1.c] .as out "\\\\n[\\$1..\\\\ni] . tm \\\\*[out] . rm out . rr i . end . de \\$1.slideright end . nr i \\\\$1 . nr i+1 \\\\ni+1 . nr \\$1..\\\\n[i+1] \\\\n[\\$1..\\\\ni] . rr i . rr i+1 . end .. .de insertionsort . nr keyidx 1 1 . while \\n+[keyidx]<=\\n[\\$1.c] \{ \ . nr key \\n[\\$1..\\n[keyidx]] . nr compidx \\n[keyidx] 1 . while \\n-[compidx]>=0 \{ \ . if \\n[compidx]=0 \{ \ . nr \\$1..1 \\n[key] . break . \} . ie \\n[\\$1..\\n[compidx]]>\\n[key] \{ \ . \\$1.slideright \\n[compidx] . \} . el \{ \ . nr compidx+1 \\n[compidx]+1 . nr \\$1..\\n[compidx+1] \\n[key] . break . \} . \} . \} .. .array a .a.pushln 13 64 22 87 54 87 23 92 11 64 5 9 3 3 0 .insertionsort a .a.dump</lang>

Swapping method

<lang N/t/roff>.de end .. .de array . nr \\$1.c 0 1 . de \\$1.push end . nr \\$1..\\\\n+[\\$1.c] \\\\$1 . end . de \\$1.pushln end . if \\\\n(.$>0 .\\$1.push \\\\$1 . if \\\\n(.$>1 \{ \ . shift . \\$1.pushln \\\\$@ . \} . end . de \\$1.dump end . nr i 0 1 . ds out " . while \\\\n+i<=\\\\n[\\$1.c] .as out "\\\\n[\\$1..\\\\ni] . tm \\\\*[out] . rm out . rr i . end . de \\$1.swap end . if (\\\\$1<=\\\\n[\\$1.c])&(\\\\$1<=\\\\n[\\$1.c]) \{ \ . nr tmp \\\\n[\\$1..\\\\$2] . nr \\$1..\\\\$2 \\\\n[\\$1..\\\\$1] . nr \\$1..\\\\$1 \\\\n[tmp] . rr tmp . \} . end .. .de insertionsort . nr keyidx 1 1 . while \\n+[keyidx]<=\\n[\\$1.c] \{ \ . nr compidx \\n[keyidx]+1 1 . nr compidx-1 \\n[keyidx] 1 . while (\\n-[compidx]>0)&(\\n[\\$1..\\n-[compidx-1]]>\\n[\\$1..\\n[compidx]]) \{ \ . \\$1.swap \\n[compidx] \\n[compidx-1] . \} . \} .. .array a .a.pushln 13 64 22 87 54 87 23 92 11 64 5 9 3 3 0 .insertionsort a .a.dump</lang>

Nemerle

From the psuedocode. <lang Nemerle>using System.Console; using Nemerle.English;

module InsertSort {

   public static Sort(this a : array[int]) : void
   {
       mutable value = 0; mutable j = 0;
       foreach (i in [1 .. (a.Length - 1)])
       {
           value = a[i]; j = i - 1;
           while (j >= 0 and a[j] > value)
           {
               a[j + 1] = a[j];
               j = j - 1;
           }
           a[j + 1] = value;
       }
   }
   
   Main() : void
   {
       def arr = array[1, 4, 8, 3, 8, 3, 5, 2, 6];
       arr.Sort();
       foreach (i in arr) Write($"$i  ");
   }

}</lang>

NetRexx

<lang NetRexx>/* NetRexx */ options replace format comments java crossref savelog symbols binary

import java.util.List

placesList = [String -

   "UK  London",     "US  New York",   "US  Boston",     "US  Washington" -
 , "UK  Washington", "US  Birmingham", "UK  Birmingham", "UK  Boston"     -

]

lists = [ -

   placesList -
 , insertionSort(String[] Arrays.copyOf(placesList, placesList.length)) -

]

loop ln = 0 to lists.length - 1

 cl = lists[ln]
 loop ct = 0 to cl.length - 1
   say cl[ct]
   end ct
   say
 end ln

return

method insertionSort(A = String[]) public constant binary returns String[]

 rl = String[A.length]
 al = List insertionSort(Arrays.asList(A))
 al.toArray(rl)
 return rl

method insertionSort(A = List) public constant binary returns ArrayList

 loop i_ = 1 to A.size - 1
   value = A.get(i_)
   j_ = i_ - 1
   loop label j_ while j_ >= 0
     if (Comparable A.get(j_)).compareTo(Comparable value) <= 0 then leave j_
     A.set(j_ + 1, A.get(j_))
     j_ = j_ - 1
     end j_
     A.set(j_ + 1, value)
   end i_
 return ArrayList(A)

</lang>

Output:
UK  London
US  New York
US  Boston
US  Washington
UK  Washington
US  Birmingham
UK  Birmingham
UK  Boston

UK  Birmingham
UK  Boston
UK  London
UK  Washington
US  Birmingham
US  Boston
US  New York
US  Washington

Nim

<lang nim>proc insertSort[T](a: var openarray[T]) =

 for i in 1 .. <a.len:
   let value = a[i]
   var j = i
   while j > 0 and value < a[j-1]:
     a[j] = a[j-1]
     dec j
   a[j] = value

var a = @[4, 65, 2, -31, 0, 99, 2, 83, 782] insertSort a echo a</lang>

Output:
@[-31, 0, 2, 2, 4, 65, 83, 99, 782]

Objeck

<lang objeck> bundle Default {

 class Insert {
   function : Main(args : String[]) ~ Nil {
     values := [9, 7, 10, 2, 9, 7, 4, 3, 10, 2, 7, 10];
     InsertionSort(values);
     each(i : values) {
       values[i]->PrintLine();
     };
   }
     
   function : InsertionSort (a : Int[]) ~ Nil {
     each(i : a) {
       value := a[i];
       j := i - 1;
       while(j >= 0 & a[j] > value) {
         a[j + 1] := a[j];
         j -= 1;
       };
       a[j + 1] := value;
     };
   }
 }

} </lang>

OCaml

<lang ocaml>let rec insert lst x =

 match lst with
   [] -> [x]
 | y :: ys  when x <= y -> x :: y :: ys
 | y :: ys -> y :: insert ys x

let insertion_sort = List.fold_left insert [];;

insertion_sort [6;8;5;9;3;2;1;4;7];;</lang>

Oforth

Returns a new sorted list.

<lang Oforth>: insertionSort(a) | l i j v |

  a asListBuffer ->l
  2 l size for: i [
     l at(i) ->v
     i 1- ->j
     while(j) [ 
        l at(j) dup v <= ifTrue: [ drop break ]
        j 1+ swap l put
        j 1- ->j
        ]
     l put(j 1 +, v)
     ]
  l ;</lang>
Output:
>[ 4, 65, 2, -31, 0, 99, 2, 83, 782, 1 ] insertionSort .
[-31, 0, 1, 2, 2, 4, 65, 83, 99, 782] ok
>

ooRexx

Translation of: REXX

<lang oorexx>/* REXX program sorts a stemmed array (has characters) */ /* using the insertion sort algorithm */

 Call gen                          /* fill the array with test data  */
 Call show 'before sort'           /* display the elements           */
 Say copies('-',79)                /* display a separator line       */
 Call insertionSort x.0            /* invoke the insertion sort.     */
 Call show ' after sort'           /* display the elements after sort*/
 Exit

/*--------------------------------------------------------------------*/ gen: Procedure Expose x.

 x.1="---Monday's Child Is Fair of Face  (by Mother Goose)---"
 x.2="======================================================="
 x.3="Monday's child is fair of face;"
 x.4="Tuesday's child is full of grace;"
 x.5="Wednesday's child is full of woe;"
 x.6="Thursday's child has far to go;"
 x.7="Friday's child is loving and giving;"
 x.8="Saturday's child works hard for a living;"
 x.9="But the child that is born on the Sabbath day"
 x.10="Is blithe and bonny, good and gay."
 x.0=10                            /* number of elements             */
 Return

/*--------------------------------------------------------------------*/ insertionsort: Procedure Expose x.

 Parse Arg n
 Do i=2 To n
   y=x.i
   Do j=i-1 By -1 To 1 While x.j>y
     z=j+1
     x.z=x.j
     /* Say 'set x.'z 'to x.'j '('||x.j||')' */
     End
   z=j+1
   x.z=y
   /* Say 'set x.'z 'to' y                   */
   End
 Return

/*--------------------------------------------------------------------*/ show:

 Do j=1 To x.0
   Say 'Element' right(j,length(x.0)) arg(1)":" x.j
   End
 Return</lang>
Output:
Element  1 before sort: ---Monday's Child Is Fair of Face  (by Mother Goose)---
Element  2 before sort: =======================================================
Element  3 before sort: Monday's child is fair of face;
Element  4 before sort: Tuesday's child is full of grace;
Element  5 before sort: Wednesday's child is full of woe;
Element  6 before sort: Thursday's child has far to go;
Element  7 before sort: Friday's child is loving and giving;
Element  8 before sort: Saturday's child works hard for a living;
Element  9 before sort: But the child that is born on the Sabbath day
Element 10 before sort: Is blithe and bonny, good and gay.
-------------------------------------------------------------------------------
Element  1  after sort: ---Monday's Child Is Fair of Face  (by Mother Goose)---
Element  2  after sort: =======================================================
Element  3  after sort: But the child that is born on the Sabbath day
Element  4  after sort: Friday's child is loving and giving;
Element  5  after sort: Is blithe and bonny, good and gay.
Element  6  after sort: Monday's child is fair of face;
Element  7  after sort: Saturday's child works hard for a living;
Element  8  after sort: Thursday's child has far to go;
Element  9  after sort: Tuesday's child is full of grace;
Element 10  after sort: Wednesday's child is full of woe;

Oz

Direct translation of pseudocode. In-place sorting of mutable arrays. <lang oz>declare

 proc {InsertionSort A}
    Low = {Array.low A}
    High = {Array.high A}
 in
    for I in Low+1..High do
       Value = A.I
       J = {NewCell I-1}
    in
       for while:@J >= Low andthen A.@J > Value do
          A.(@J+1) := A.@J
          J := @J - 1
       end
       A.(@J+1) := Value
    end
 end
 Arr = {Tuple.toArray unit(3 1 4 1 5 9 2 6 5)}

in

 {InsertionSort Arr}
 {Show {Array.toRecord unit Arr}}</lang>

Qi

Based on the scheme version. <lang qi>(define insert

 X []     -> [X]
 X [Y|Ys] -> [X Y|Ys] where (<= X Y)
 X [Y|Ys] -> [Y|(insert X Ys)])

(define insertion-sort

 []     -> []
 [X|Xs] -> (insert X (insertion-sort Xs)))

(insertion-sort [6 8 5 9 3 2 1 4 7]) </lang>

PARI/GP

<lang parigp>insertionSort(v)={

 for(i=1,#v-1,
   my(j=i-1,x=v[i]);
   while(j && v[j]>x,
     v[j+1]=v[j];
     j--
   );
   v[j+1]=x
 );
 v

};</lang>

Pascal

See Delphi

Perl

<lang perl> sub insertion_sort {

   my (@list) = @_;
   foreach my $i (1 .. $#list) {
       my $j = $i;
       my $k = $list[$i];
       while ( $j > 0 && $k < $list[$j - 1]) {
           $list[$j] = $list[$j - 1];
           $j--;
       }
       $list[$j] = $k;
   }
   return @list;

}

my @a = insertion_sort(4, 65, 2, -31, 0, 99, 83, 782, 1); print "@a\n"; </lang>

Output:
-31 0 1 2 4 65 83 99 782

Perl 6

<lang perl6>sub insertion_sort ( @a is copy ) {

   for 1 .. @a.end -> $i {
       my $value = @a[$i];
       my $j;
       loop ( $j = $i-1; $j >= 0 and @a[$j] > $value; $j-- ) {
           @a[$j+1] = @a[$j];
       }
       @a[$j+1] = $value;
   }
   return @a;

}

my @data = 22, 7, 2, -5, 8, 4; say 'input = ' ~ @data; say 'output = ' ~ @data.&insertion_sort; </lang>

Output:
input  = 22 7 2 -5 8 4
output = -5 2 4 7 8 22

Phix

Copy of Euphoria <lang Phix>function insertion_sort(sequence s) object temp integer j

   for i=2 to length(s) do
       temp = s[i]
       j = i-1
       while j>=1 and s[j]>temp do
           s[j+1] = s[j]
           j -= 1
       end while
       s[j+1] = temp
   end for
   return s

end function

constant s = {4, 15, "delta", 2, -31, 0, "alpha", 19, "gamma", 2, 13, "beta", 782, 1}

puts(1,"Before: ") ?s puts(1,"After: ") ?insertion_sort(s)</lang>

Output:
Before: {4,15,"delta",2,-31,0,"alpha",19,"gamma",2,13,"beta",782,1}
After: {-31,0,1,2,2,4,13,15,19,782,"alpha","beta","delta","gamma"}

PHP

<lang php>function insertionSort(&$arr){ for($i=0;$i<count($arr);$i++){ $val = $arr[$i]; $j = $i-1; while($j>=0 && $arr[$j] > $val){ $arr[$j+1] = $arr[$j]; $j--; } $arr[$j+1] = $val; } }

$arr = array(4,2,1,6,9,3,8,7); insertionSort($arr); echo implode(',',$arr);</lang>

1,2,3,4,6,7,8,9

PicoLisp

<lang PicoLisp>(de insertionSort (Lst)

  (for (I (cdr Lst)  I  (cdr I))
     (for (J Lst  (n== J I)  (cdr J))
        (T (> (car J) (car I))
           (rot J (offset I J)) ) ) )
  Lst )</lang>
Output:
: (insertionSort (5 3 1 7 4 1 1 20))
-> (1 1 1 3 4 5 7 20)

PL/I

<lang pli> INSSORT: PROC(A);

  DCL A(*)        FIXED BIN(31);
  DCL (I,J,V,N,M) FIXED BIN(31);
  N = HBOUND(A,1); M = LBOUND(A,1);
  DO I=M+1 TO N;
     V=A(I);
     DO J=I-1 BY -1 WHILE (J>M-1 & A(J)>V);
        A(J+1)=A(J);
     END;
     A(J+1)=V;
  END;
  RETURN;

END INSSORT; </lang>

PowerShell

Very similar to the PHP code. <lang powershell>function insertionSort($arr){ for($i=0;$i -lt $arr.length;$i++){ $val = $arr[$i] $j = $i-1 while($j -ge 0 -and $arr[$j] -gt $val){ $arr[$j+1] = $arr[$j] $j-- } $arr[$j+1] = $val } }

$arr = @(4,2,1,6,9,3,8,7) insertionSort($arr) $arr -join ","</lang>

Output:
1,2,3,4,6,7,8,9

Prolog

<lang prolog>insert_sort(L1,L2) :-

 insert_sort_intern(L1,[],L2).

insert_sort_intern([],L,L). insert_sort_intern([H|T],L1,L) :-

 insert(L1,H,L2),
 insert_sort_intern(T,L2,L).

insert([],X,[X]). insert([H|T],X,[X,H|T]) :-

 X =< H,
 !.

insert([H|T],X,[H|T2]) :-

 insert(T,X,T2).</lang>

% Example use:
%    ?- insert_sort([2,23,42,3,10,1,34,5],L).
%    L = [1,2,3,5,10,23,34,42] ? 
%    yes

Functional approach

Works with SWI-Prolog.
Insertion sort inserts elements of a list in a sorted list. So we can use foldl to sort a list. <lang Prolog>% insertion sort isort(L, LS) :- foldl(insert, [], L, LS).


% foldl(Pred, Init, List, R). foldl(_Pred, Val, [], Val). foldl(Pred, Val, [H | T], Res) :- call(Pred, Val, H, Val1), foldl(Pred, Val1, T, Res).

% insertion in a sorted list insert([], N, [N]).

insert([H | T], N, [N, H|T]) :- N =< H, !.

insert([H | T], N, [H|L1]) :- insert(T, N, L1). </lang> Example use:

 ?- isort([2,23,42,3,10,1,34,5],L).
L = [1,2,3,5,10,23,34,42] 

PureBasic

<lang PureBasic>Procedure insertionSort(Array a(1))

 Protected low, high
 Protected firstIndex, lastIndex = ArraySize(a())
 
 If lastIndex > firstIndex + 1
   low = firstIndex + 1
   While low <= lastIndex
     high = low
     While high > firstIndex
       If a(high) < a(high - 1)
         Swap a(high), a(high - 1)
       Else
         Break
       EndIf
       high - 1
     Wend
     low + 1
   Wend
 EndIf

EndProcedure</lang>

Python

<lang python>def insertion_sort(l):

   for i in xrange(1, len(l)):
       j = i-1 
       key = l[i]
       while (l[j] > key) and (j >= 0):
          l[j+1] = l[j]
          j -= 1
       l[j+1] = key</lang>

Insertion sort with binary search

<lang python>def insertion_sort_bin(seq):

   for i in range(1, len(seq)):
       key = seq[i]
       # invariant: ``seq[:i]`` is sorted        
       # find the least `low' such that ``seq[low]`` is not less then `key'.
       #   Binary search in sorted sequence ``seq[low:up]``:
       low, up = 0, i
       while up > low:
           middle = (low + up) // 2
           if seq[middle] < key:
               low = middle + 1              
           else:
               up = middle
       # insert key at position ``low``
       seq[:] = seq[:low] + [key] + seq[low:i] + seq[i + 1:]</lang>

This is also built-in to the standard library:

<lang python>import bisect def insertion_sort_bin(seq):

   for i in range(1, len(seq)):
       bisect.insort(seq, seq.pop(i), 0, i)</lang>

R

Direct translation of pseudocode. <lang r>insertionsort <- function(x) {

  for(i in 2:(length(x)))
  {
     value <- x[i]
     j <- i - 1
     while(j >= 1 && x[j] > value)
     {
        x[j+1] <- x[j]
        j <- j-1
     }
     x[j+1] <- value
  }
  x

} insertionsort(c(4, 65, 2, -31, 0, 99, 83, 782, 1)) # -31 0 1 2 4 65 83 99 782</lang>

R has native vectorized operations which allow the following, more efficient implementation.

<lang r> insertion_sort <- function(x) {

 for (j in 2:length(x)) {
   key <- x[j]
   bp <- which.max(x[1:j] > key)
   # 'bp' stands for breakpoint
   if (bp == 1) {
     if (key < ar[1]){
         x <- c(key, ar[-j])
     }
   }
   else {
     x <- x[-j]
     x <- c(ar[1:bp - 1], key, x[bp : (s-1)])
   }
 return(x)
 }

} </lang>

Racket

This implementation makes use of the pattern matching facilities in the Racket distribution.

<lang racket>

  1. lang racket

(define (sort < l)

 (define (insert x ys)
   (match ys
     [(list) (list x)]
     [(cons y rst) (cond [(< x y) (cons x ys)]
                         [else (cons y (insert x rst))])]))
 (foldl insert '() l))</lang>

Rascal

<lang rascal>import List;

public list[int] insertionSort(a){ for(i <- [0..size(a)-1]){ v = a[i]; j = i-1; while(j >= 0 && a[j] > v){ a[j+1] = a[j]; j -= 1;

               }

a[j+1] = v;

       }

return a; }</lang>

Output:

<lang rascal>rascal>rascal>insertionSort([4, 65, 2, -31, 0, 99, 83, 782, 1]) list[int]: [-31,0,1,2,4,65,83,99,782]</lang>

REALbasic

<lang vb>Sub InsertionSort(theList() as Integer)

 for insertionElementIndex as Integer = 1 to UBound(theList)
   dim insertionElement as Integer = theList(insertionElementIndex)
   dim j as Integer = insertionElementIndex - 1
   while (j >= 0) and (insertionElement < theList(j))
     theList(j + 1) = theList(j)
     j = j - 1
   wend
   theList(j + 1) = insertionElement
 next

End Sub</lang>

REBOL

<lang rebol>

This program works with REBOL version R2 and R3, to make it work with Red
change the word func to function

insertion-sort: func [ a [block!] /local i [integer!] j [integer!] n [integer!] value [integer! string! date!] ][ i: 2 n: length? a

while [i <= n][

       	value: a/:i

j: i while [ all [ 1 < j value < a/(j - 1) ]][

a/:j: a/(j - 1) j: j - 1

       	]
       	a/:j: value

i: i + 1 ] a ]

probe insertion-sort [4 2 1 6 9 3 8 7]

probe insertion-sort [ "---Monday's Child Is Fair of Face (by Mother Goose)---"

 "Monday's child is fair of face;"
 "Tuesday's child is full of grace;"
 "Wednesday's child is full of woe;"
"Thursday's child has far to go;"
 "Friday's child is loving and giving;"
 "Saturday's child works hard for a living;"
 "But the child that is born on the Sabbath day"
 "Is blithe and bonny, good and gay."]
just by adding the date! type to the local variable value the same function can sort dates.

probe insertion-sort [12-Jan-2015 11-Jan-2015 11-Jan-2016 12-Jan-2014] </lang>

Output:
[1 2 3 4 6 7 8 9]
[{---Monday's Child Is Fair of Face (by Mother Goose)---} 
    "But the child that is born on the Sabbath day" 
    "Friday's child is loving and giving;" 
    "Is blithe and bonny, good and gay." 
    "Monday's child is fair of face;" 
    "Saturday's child works hard for a living;" 
    "Thursday's child has far to go;" 
    "Tuesday's child is full of grace;" 
    "Wednesday's child is full of woe;"
]
[12-Jan-2014 11-Jan-2015 12-Jan-2015 11-Jan-2016]

REXX

<lang rexx>/*REXX program sorts a stemmed array (has characters) using the insertion sort algorithm*/ call gen /*generate the array's (data) elements.*/ call show 'before sort' /*display the before array elements. */ say copies('▒', 85) /*display a separator line (a fence). */ call insertionSort # /*invoke the insertion sort. */ call show ' after sort' /*display the after array elements. */ exit /*stick a fork in it, we're all done. */ /*──────────────────────────────────────────────────────────────────────────────────────*/ gen: @.=; @.1 = "---Monday's Child Is Fair of Face (by Mother Goose)---"

                         @.2  = "======================================================="
                         @.3  = "Monday's child is fair of face;"
                         @.4  = "Tuesday's child is full of grace;"
                         @.5  = "Wednesday's child is full of woe;"
                         @.6  = "Thursday's child has far to go;"
                         @.7  = "Friday's child is loving and giving;"
                         @.8  = "Saturday's child works hard for a living;"
                         @.9  = "But the child that is born on the Sabbath day"
                         @.10 = "Is blithe and bonny, good and gay."
           do #=1  while @.#\==; end;  #=#-1  /*determine how many entries in @ array*/
    return

/*──────────────────────────────────────────────────────────────────────────────────────*/ insertionSort: procedure expose @.; parse arg #

                         do i=2  to #;  $=@.i;         do j=i-1  by -1  to 1  while @.j>$
                                                       _=j+1;    @._=@.j
                                                       end   /*j*/
                         _=j+1;         @._=$
                         end   /*i*/
               return

/*──────────────────────────────────────────────────────────────────────────────────────*/ show: do j=1 for #; say ' element' right(j,length(#)) arg(1)": " @.j; end; return</lang> output   when using the internal data:

   element  1 before sort:  ---Monday's Child Is Fair of Face  (by Mother Goose)---
   element  2 before sort:  =======================================================
   element  3 before sort:  Monday's child is fair of face;
   element  4 before sort:  Tuesday's child is full of grace;
   element  5 before sort:  Wednesday's child is full of woe;
   element  6 before sort:  Thursday's child has far to go;
   element  7 before sort:  Friday's child is loving and giving;
   element  8 before sort:  Saturday's child works hard for a living;
   element  9 before sort:  But the child that is born on the Sabbath day
   element 10 before sort:  Is blithe and bonny, good and gay.
▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒▒
   element  1  after sort:  ---Monday's Child Is Fair of Face  (by Mother Goose)---
   element  2  after sort:  =======================================================
   element  3  after sort:  But the child that is born on the Sabbath day
   element  4  after sort:  Friday's child is loving and giving;
   element  5  after sort:  Is blithe and bonny, good and gay.
   element  6  after sort:  Monday's child is fair of face;
   element  7  after sort:  Saturday's child works hard for a living;
   element  8  after sort:  Thursday's child has far to go;
   element  9  after sort:  Tuesday's child is full of grace;
   element 10  after sort:  Wednesday's child is full of woe;

Ring

<lang ring> alist = [7,6,5,9,8,4,3,1,2,0] see insertionsort(alist)

func insertionsort blist

    for i = 1 to len(blist)
        value = blist[i]
        j = i - 1
        while j >= 1 and blist[j] > value
              blist[j+1] = blist[j]
              j = j - 1
        end   
        blist[j+1] = value
     next
     return blist

</lang>

Ruby

<lang ruby>class Array

 def insertionsort!
   1.upto(length - 1) do |i|
     value = self[i]
     j = i - 1
     while j >= 0 and self[j] > value
       self[j+1] = self[j]
       j -= 1
     end
     self[j+1] = value
   end
   self
 end

end ary = [7,6,5,9,8,4,3,1,2,0] p ary.insertionsort!

  1. => [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]</lang>

Alternative version which doesn't swap elements but rather removes and inserts the value at the correct place: <lang ruby>class Array

 def insertionsort!
   1.upto(length - 1) do |i|
     value = delete_at i
     j = i - 1
     j -= 1 while j >= 0 && value < self[j]
     insert(j + 1, value)
   end
   self
 end

end

ary = [7,6,5,9,8,4,3,1,2,0] p ary.insertionsort!

  1. => [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]</lang>

Run BASIC

<lang runbasic>dim insSort(100) sortEnd = 0 global inSort global sortEnd

' -- insert some random numbers --

for i = 1 to 20

 a = int(1000 * rnd(1))
 x = insertSort(a)

next i

' --- Print the Sorted Data -----

print "End Sort:";sortEnd ' number sorted for i = 1 to sortEnd

print i;" ";insSort(i)                  ' location and sorted data

next i wait

function insertSort(x) ' Insert Sort Function i = 1 while x > insSort(i) and i <= sortEnd

 i = i + 1

wend for j = sortEnd to i step -1

  insSort(j + 1) = insSort(j)

next j insSort(i) = x sortEnd = sortEnd + 1 end function</lang>

End Sort:20
1 124
2 248
3 263
4 279
5 390
6 431
7 458
8 480
9 543
10 556
11 567
12 619
13 625
........

Rust

<lang rust>fn insertion_sort<T: std::cmp::Ord>(arr: &mut [T]) {

   for i in 1..arr.len() {
       let mut j = i;
       while j > 0 && arr[j] < arr[j-1] {
           arr.swap(j, j-1);
           j = j-1;
       }
   }

}</lang>

Scala

version 1

<lang scala>def insertSort[X](list: List[X])(implicit ord: Ordering[X]) = {

 def insert(list: List[X], value: X) = list.span(x => ord.lt(x, value)) match {
   case (lower, upper) => lower ::: value :: upper
 }
 list.foldLeft(List.empty[X])(insert)

}</lang>

version 2

Copied from SASL manual, Appendix II, answer (2)(a) <lang SASL> DEF sort () = () sort (a : x) = insert a (sort x) insert a () = a, insert a (b : x) = a < b -> a : b : x

         b : insert a x

?</lang>

Scheme

<lang scheme>(define (insert x lst)

 (if (null? lst)
     (list x)
     (let ((y (car lst))
           (ys (cdr lst)))
       (if (<= x y)
           (cons x lst)
           (cons y (insert x ys))))))

(define (insertion-sort lst)

 (if (null? lst)
     '()
     (insert (car lst)
             (insertion-sort (cdr lst)))))

(insertion-sort '(6 8 5 9 3 2 1 4 7))</lang>

Seed7

<lang seed7>const proc: insertionSort (inout array elemType: arr) is func

 local
   var integer: i is 0;
   var integer: j is 0;
   var elemType: help is elemType.value;
 begin
   for i range 2 to length(arr) do
     j := i;
     help := arr[i];
     while j > 1 and arr[pred(j)] > help do
       arr[j] := arr[pred(j)];
       decr(j);
     end while;
     arr[j] := help;
   end for;
 end func;</lang>

Original source: [1]

Sidef

<lang ruby>class Array {

   method insertion_sort {
       { |i|
           var j = i-1
           var k = self[i]
           while ((j >= 0) && (k < self[j])) {
               self[j+1] = self[j]
               j--
           }
           self[j+1] = k
       } << 1..self.end
       return self
   }

}

var a = 10.of { 100.irand } say a.insertion_sort</lang>

SNOBOL4

<lang snobol>* read data into an array A = table() i = 0 readln A = trim(input) :s(readln) aSize = i - 1

  • sort array

i = 1 loop1 value = A j = i - 1 loop2 gt(j,0) gt(A<j>,value) :f(done2) A<j + 1> = A<j> j = j - 1 :(loop2) done2 A<j + 1> = value i = ?lt(i,aSize) i + 1 :s(loop1) i = 1

  • output sorted data

while output = A; i = ?lt(i,aSize) i + 1 :s(while) end</lang>

Stata

<lang stata>mata void insertion_sort(real vector a) { real scalar i, j, n, x

n = length(a) for (i=2; i<=n; i++) { x = a[i] for (j=i-1; j>=1; j--) { if (a[j] <= x) break a[j+1] = a[j] } a[j+1] = x } } end</lang>

Swift

Using generics. <lang Swift>func insertionSort<T:Comparable>(inout list:[T]) {

   for i in 1..<list.count {
       var j = i
       
       while j > 0 && list[j - 1] > list[j] {
          swap(&list[j], &list[j - 1])
           j--
       }
   }

}</lang>

TI-83 BASIC

Store input in L1, run prgmSORTINS, get output in L2.

:L1→L2
:0→A
:Lbl L
:A+1→A
:A→B
:While B>0
:If L2(B)<L2(B+1)
:Goto B
:L2(B)→C
:L2(B+1)→L2(B)
:C→L2(B+1)
:B-1→B
:End
:Lbl B
:If A<(dim(L2)-1)
:Goto L
:DelVar A
:DelVar B
:DelVar C
:Stop

Tcl

<lang tcl>package require Tcl 8.5

proc insertionsort {m} {

   for {set i 1} {$i < [llength $m]} {incr i} {
       set val [lindex $m $i]
       set j [expr {$i - 1}]
       while {$j >= 0 && [lindex $m $j] > $val} {
           lset m [expr {$j + 1}] [lindex $m $j]
           incr j -1
       }
       lset m [expr {$j + 1}] $val
   }
   return $m

}

puts [insertionsort {8 6 4 2 1 3 5 7 9}] ;# => 1 2 3 4 5 6 7 8 9</lang>

TI-83 BASIC

Input into L1, run prgmSORTINS, output in L2.

:"INSERTION"
:L1→L2
:0→A
:Lbl L
:A+1→A
:A→B
:While B>0
:If L2(B)≤L2(B+1)
:Goto B
:L2(B)→C
:L2(B+1)→L2(B)
:C→L2(B+1)
:B-1→B
:End
:Lbl B
:If A<(dim(L2)-1)
:Goto L
:DelVar A
:DelVar B
:DelVar C
:Return

uBasic/4tH

<lang>PRINT "Insertion sort:"

 n = FUNC (_InitArray)
 PROC _ShowArray (n)
 PROC _Insertionsort (n)
 PROC _ShowArray (n)

PRINT

END


_Insertionsort PARAM (1) ' Insertion sort

 LOCAL (3)
 FOR b@ = 1 TO a@-1
   c@ = @(b@)
   d@ = b@
   DO WHILE (d@>0) * (c@ < @(ABS(d@-1)))
       @(d@) = @(d@-1)
       d@ = d@ - 1
   LOOP
   @(d@) = c@
 NEXT

RETURN


_Swap PARAM(2) ' Swap two array elements

 PUSH @(a@)
 @(a@) = @(b@)
 @(b@) = POP()

RETURN


_InitArray ' Init example array

 PUSH 4, 65, 2, -31, 0, 99, 2, 83, 782, 1

 FOR i = 0 TO 9
   @(i) = POP()
 NEXT

RETURN (i)


_ShowArray PARAM (1) ' Show array subroutine

 FOR i = 0 TO a@-1
   PRINT @(i),
 NEXT

 PRINT

RETURN</lang>

UnixPipes

<lang bash>selectionsort() {

  read a
  test -n "$a" && ( selectionsort | sort -nm <(echo $a) -)

}</lang> <lang bash>cat to.sort | selectionsort</lang>

Ursala

<lang Ursala>#import nat

insort = ~&i&& @hNCtX ~&r->lx ^\~&rt nleq-~rlrSPrhlPrSCPTlrShlPNCTPQ@rhPlD</lang> test program: <lang Ursala>#cast %nL

example = insort <45,82,69,82,104,58,88,112,89,74></lang>

Output:
<45,58,69,74,82,82,88,89,104,112>

VBA

Translation of: Phix

<lang vb>Option Base 1

Private Function insertion_sort(s As Variant) As Variant

   Dim temp As Variant
   Dim j As Integer
   For i = 2 To UBound(s)
       temp = s(i)
       j = i - 1
       Do While s(j) > temp
           s(j + 1) = s(j)
           j = j - 1
           If j = 0 Then Exit Do
       Loop
       s(j + 1) = temp
   Next i
   insertion_sort = s

End Function

Public Sub main()

   s = [{4, 15, "delta", 2, -31, 0, "alpha", 19, "gamma", 2, 13, "beta", 782, 1}]
   Debug.Print "Before: ", Join(s, ", ")
   Debug.Print "After: ", Join(insertion_sort(s), "' ")

End Sub</lang>

Output:
Before:       4, 15, delta, 2, -31, 0, alpha, 19, gamma, 2, 13, beta, 782, 1
After:        -31' 0' 1' 2' 2' 4' 13' 15' 19' 782' alpha' beta' delta' gamma

VBScript

Translation of: REALbasic

<lang vb>Randomize Dim n(9) 'nine is the upperbound.

        'since VBS arrays are 0-based, it will have 10 elements.

For L = 0 to 9

  n(L) = Int(Rnd * 32768)

Next

WScript.StdOut.Write "ORIGINAL : " For L = 0 to 9

  WScript.StdOut.Write n(L) & ";"

Next

InsertionSort n

WScript.StdOut.Write vbCrLf & " SORTED : " For L = 0 to 9

  WScript.StdOut.Write n(L) & ";"

Next

'the function Sub InsertionSort(theList)

  For insertionElementIndex = 1 To UBound(theList)
     insertionElement = theList(insertionElementIndex)
     j = insertionElementIndex - 1
     Do While j >= 0
        'necessary for BASICs without short-circuit evaluation
        If insertionElement < theList(j) Then
           theList(j + 1) = theList(j)
           j = j - 1
        Else
           Exit Do
        End If
     Loop
     theList(j + 1) = insertionElement
  Next

End Sub </lang>

Output:
ORIGINAL : 26699;2643;10249;31612;21346;19702;29799;31115;20413;5197;
  SORTED : 2643;5197;10249;19702;20413;21346;26699;29799;31115;31612;

XPL0

<lang XPL0>code ChOut=8, IntOut=11;

proc InsertionSort(A, L); \Sort array A of length L int A, L; int I, J, V; [for I:= 1 to L-1 do

   [V:= A(I); 
   J:= I-1;
   while J>=0 and A(J)>V do
       [A(J+1):= A(J);
       J:= J-1;
       ];
   A(J+1):= V;
   ];

];

int A, I; [A:= [3, 1, 4, 1, -5, 9, 2, 6, 5, 4]; InsertionSort(A, 10); for I:= 0 to 10-1 do [IntOut(0, A(I)); ChOut(0, ^ )]; ]</lang>

Output:
-5 1 1 2 3 4 4 5 6 9 

Yorick

Based on pseudocode, except using 1-based arrays. <lang yorick>func insertionSort(&A) {

 for(i = 2; i <= numberof(A); i++) {
   value = A(i);
   j = i - 1;
   while(j >= 1 && A(j) > value) {
     A(j+1) = A(j);
     j--;
   }
   A(j+1) = value;
 }

}</lang>

zkl

<lang zkl>fcn insertionSort(list){

  sink:=List();
  foreach x in (list){
     if(False==(n:=sink.filter1n('>(x)))) sink.append(x); // x>all items in sink
     else sink.insert(n,x);
  }
  sink.close();

}</lang> <lang zkl>insertionSort(T(4,65,2,-31,0,99,2,83,782,1)).println(); insertionSort("big fjords vex quick waltz nymph".split()).println();</lang>

Output:
L(-31,0,1,2,2,4,65,83,99,782)
L("big","fjords","nymph","quick","vex","waltz")