Sorting algorithms/Heapsort
You are encouraged to solve this task according to the task description, using any language you may know.
Sorting Algorithm
This is a sorting algorithm. It may be applied to a set of data in order to sort it.
Heapsort | Mergesort | Quicksort
O(n log2n) Sorts
Shell Sort
O(n2) Sorts
Bubble sort | Cocktail sort | Comb sort | Gnome sort | Insertion sort | Selection sort | Strand sort
Other Sorts
Bead sort | Bogosort | Counting sort | Pancake sort | Permutation sort | Radix sort | Sleep sort | Stooge sort
| This page uses content from Wikipedia. The original article was at Heapsort. The list of authors can be seen in the page history. As with Rosetta Code, the text of Wikipedia is available under the GNU FDL. (See links for details on variance) |
Pseudocode:
function heapSort(a, count) is input: an unordered array a of length count (first place a in max-heap order) heapify(a, count) end := count - 1 while end > 0 do (swap the root(maximum value) of the heap with the last element of the heap) swap(a[end], a[0]) (decrement the size of the heap so that the previous max value will stay in its proper place) end := end - 1 (put the heap back in max-heap order) siftDown(a, 0, end)
function heapify(a,count) is (start is assigned the index in a of the last parent node) start := (count - 2) / 2 while start ≥ 0 do (sift down the node at index start to the proper place such that all nodes below the start index are in heap order) siftDown(a, start, count-1) start := start - 1 (after sifting down the root all nodes/elements are in heap order) function siftDown(a, start, end) is (end represents the limit of how far down the heap to sift) root := start while root * 2 + 1 ≤ end do (While the root has at least one child) child := root * 2 + 1 (root*2+1 points to the left child) (If the child has a sibling and the child's value is less than its sibling's...) if child + 1 ≤ end and a[child] < a[child + 1] then child := child + 1 (... then point to the right child instead) if a[root] < a[child] then (out of max-heap order) swap(a[root], a[child]) root := child (repeat to continue sifting down the child now) else return
Write a function to sort a collection of integers using heapsort.
[edit] ActionScript
function heapSort(data:Vector.<int>):Vector.<int> {
for (var start:int = (data.length-2)/2; start >= 0; start--) {
siftDown(data, start, data.length);
}
for (var end:int = data.length - 1; end > 0; end--) {
var tmp:int=data[0];
data[0]=data[end];
data[end]=tmp;
siftDown(data, 0, end);
}
return data;
}
function siftDown(data:Vector.<int>, start:int, end:int):void {
var heapRoot:int=start;
while (heapRoot * 2+1 < end) {
var child:int=heapRoot*2+1;
if (child+1<end&&data[child]<data[child+1]) {
child++;
}
if (data[heapRoot]<data[child]) {
var tmp:int=data[heapRoot];
data[heapRoot]=data[child];
data[child]=tmp;
heapRoot=child;
} else {
return;
}
}
}
[edit] Ada
This implementation is a generic heapsort for unconstrained arrays.
generic
type Element_Type is private;
type Index_Type is (<>);
type Collection is array(Index_Type range <>) of Element_Type;
with function "<" (Left, right : element_type) return boolean is <>;
procedure Generic_Heapsort(Item : in out Collection);
procedure Generic_Heapsort(Item : in out Collection) is
procedure Swap(Left : in out Element_Type; Right : in out Element_Type) is
Temp : Element_Type := Left;
begin
Left := Right;
Right := Temp;
end Swap;
procedure Sift_Down(Item : in out Collection) is
Root : Integer := Index_Type'Pos(Item'First);
Child : Integer := Index_Type'Pos(Item'Last);
Last : Integer := Index_Type'Pos(Item'Last);
begin
while Root * 2 + 1 <= Last loop
Child := Root * 2 + 1;
if Child + 1 <= Last and then Item(index_Type'Val(Child)) < Item(Index_Type'Val(Child + 1)) then
Child := Child + 1;
end if;
if Item(Index_Type'Val(Root)) < Item(Index_Type'Val(Child)) then
Swap(Item(Index_Type'Val(Root)), Item(Index_Type'Val(Child)));
Root := Child;
else
exit;
end if;
end loop;
end Sift_Down;
procedure Heapify(Item : in out Collection) is
First_Pos : Integer := Index_Type'Pos(Index_Type'First);
Last_Pos : Integer := Index_Type'Pos(Index_type'Last);
Start : Index_type := Index_Type'Val((Last_Pos - First_Pos + 1) / 2);
begin
loop
Sift_Down(Item(Start..Item'Last));
if Start > Index_Type'First then
Start := Index_Type'Pred(Start);
else
exit;
end if;
end loop;
end Heapify;
Last_Index : Index_Type := Index_Type'Last;
begin
Heapify(Item);
while Last_Index > Index_Type'First loop
Swap(Item(Last_Index), Item(Item'First));
Last_Index := Index_Type'Pred(Last_Index);
Sift_Down(Item(Item'First..Last_Index));
end loop;
end Generic_Heapsort;
Demo code:
with Generic_Heapsort;
with Ada.Text_Io; use Ada.Text_Io;
procedure Test_Generic_Heapsort is
type Days is (Sun, Mon, Tue, Wed, Thu, Fri, Sat);
type Days_Col is array(Days range <>) of Natural;
procedure Sort is new Generic_Heapsort(Natural, Days, Days_Col);
Week : Days_Col := (5, 2, 7, 3, 4, 9, 1);
begin
for I in Week'range loop
Put(Days'Image(I) & ":" & Natural'Image(Week(I)) & " ");
end loop;
New_Line;
Sort(Week);
for I in Week'range loop
Put(Days'Image(I) & ":" & Natural'Image(Week(I))& " ");
end loop;
New_Line;
end Test_Generic_Heapsort;
[edit] AutoHotkey
heapSort(a) {
Local end
end := %a%0
heapify(a,end)
While end > 1
%a%%end% := (%a%1 "", %a%1 := %a%%end%)
,siftDown(a, 1, --end)
}
heapify(a, count) {
Local start
start := count // 2
While start
siftDown(a, start--, count)
}
siftDown(a, start, end) {
Local child, c1
While start*2 <= end {
c1 := 1 + child := start*2
If (c1 <= end && %a%%child% < %a%%c1%)
child := c1
If (%a%%start% < %a%%child%)
%a%%start% := (%a%%child% "", %a%%child% := %a%%start%)
,start := child
Else Return
}
}
a = 1,5,2,7,3,4,6,8,1 ; ----- test -----
StringSplit a, a, `,
heapSort("a")
ListVars
MsgBox
[edit] BBC BASIC
DIM test(9)
test() = 4, 65, 2, -31, 0, 99, 2, 83, 782, 1
PROCheapsort(test())
FOR i% = 0 TO 9
PRINT test(i%) ;
NEXT
END
DEF PROCheapsort(a())
LOCAL e%
PROCheapify(a())
FOR e% = DIM(a(),1) TO 1 STEP -1
SWAP a(e%), a(0)
PROCsiftdown(a(), 0, e%-1)
NEXT
ENDPROC
DEF PROCheapify(a())
LOCAL s%, m%
m% = DIM(a(),1)
FOR s% = (m% - 1) / 2 TO 0 STEP -1
PROCsiftdown(a(), s%, m%)
NEXT
ENDPROC
DEF PROCsiftdown(a(), s%, e%)
LOCAL c%, r%
r% = s%
WHILE r% * 2 + 1 <= e%
c% = r% * 2 + 1
IF c% + 1 <= e% IF a(c%) < a(c% + 1) c% += 1
IF a(r%) < a(c%) SWAP a(r%), a(c%) : r% = c% ELSE ENDPROC
ENDWHILE
ENDPROC
Output:
-31 0 1 2 2 4 65 83 99 782
[edit] BCPL
// This can be run using Cintcode BCPL freely available from www.cl.cam.ac.uk/users/mr10.
GET "libhdr.h"
LET heapify(v, k, i, last) BE
{ LET j = i+i // If there is a son (or two), j = subscript of first.
AND x = k // x will hold the larger of the sons if any.
IF j<=last DO x := v!j // j, x = subscript and key of first son.
IF j< last DO
{ LET y = v!(j+1) // y = key of the other son.
IF x<y DO x,j := y, j+1 // j, x = subscript and key of larger son.
}
IF k>=x DO
{ v!i := k // k is not lower than larger son if any.
RETURN
}
v!i := x
i := j
} REPEAT
AND heapsort(v, upb) BE
{ FOR i = upb/2 TO 1 BY -1 DO heapify(v, v!i, i, upb)
FOR i = upb TO 2 BY -1 DO
{ LET k = v!i
v!i := v!1
heapify(v, k, 1, i-1)
}
}
LET start() = VALOF {
LET v = VEC 1000
FOR i = 1 TO 1000 DO v!i := randno(1_000_000)
heapsort(v, 1000)
FOR i = 1 TO 1000 DO
{ IF i MOD 10 = 0 DO newline()
writef(" %i6", v!i)
}
newline()
}
[edit] C
#include <stdio.h>
#include <stdlib.h>
#define ValType double
#define IS_LESS(v1, v2) (v1 < v2)
void siftDown( ValType *a, int start, int count);
#define SWAP(r,s) do{ValType t=r; r=s; s=t; } while(0)
void heapsort( ValType *a, int count)
{
int start, end;
/* heapify */
for (start = (count-2)/2; start >=0; start--) {
siftDown( a, start, count);
}
for (end=count-1; end > 0; end--) {
SWAP(a[end],a[0]);
siftDown(a, 0, end);
}
}
void siftDown( ValType *a, int start, int end)
{
int root = start;
while ( root*2+1 < end ) {
int child = 2*root + 1;
if ((child + 1 < end) && IS_LESS(a[child],a[child+1])) {
child += 1;
}
if (IS_LESS(a[root], a[child])) {
SWAP( a[child], a[root] );
root = child;
}
else
return;
}
}
int main()
{
int ix;
double valsToSort[] = {
1.4, 50.2, 5.11, -1.55, 301.521, 0.3301, 40.17,
-18.0, 88.1, 30.44, -37.2, 3012.0, 49.2};
#define VSIZE (sizeof(valsToSort)/sizeof(valsToSort[0]))
heapsort(valsToSort, VSIZE);
printf("{");
for (ix=0; ix<VSIZE; ix++) printf(" %.3f ", valsToSort[ix]);
printf("}\n");
return 0;
}
[edit] C++
The easiest way is to use the make_heap and sort_heap standard library functions.
#include <iostream>
#include <algorithm> // for std::make_heap, std::sort_heap
template <typename Iterator>
void heapsort(Iterator begin, Iterator end)
{
std::make_heap(begin, end);
std::sort_heap(begin, end);
}
int main()
{
double valsToSort[] = {
1.4, 50.2, 5.11, -1.55, 301.521, 0.3301, 40.17,
-18.0, 88.1, 30.44, -37.2, 3012.0, 49.2};
const int VSIZE = sizeof(valsToSort)/sizeof(*valsToSort);
heapsort(valsToSort, valsToSort+VSIZE);
for (int ix=0; ix<VSIZE; ix++) std::cout << valsToSort[ix] << std::endl;
return 0;
}
If you want to be slightly more verbose
#include <iostream>
#include <algorithm> // for std::make_heap, std::pop_heap
template <typename Iterator>
void heapsort(Iterator begin, Iterator end)
{
std::make_heap(begin, end);
while (begin != end)
std::pop_heap(begin, end--);
}
[edit] C#
using System;
using System.Collections.Generic;
using System.Text;
public class HeapSortClass
{
public static void HeapSort<T>(T[] array)
{
HeapSort<T>(array, 0, array.Length, Comparer<T>.Default);
}
public static void HeapSort<T>(T[] array, int offset, int length, IComparer<T> comparer)
{
HeapSort<T>(array, offset, length, comparer.Compare);
}
public static void HeapSort<T>(T[] array, int offset, int length, Comparison<T> comparison)
{
// build binary heap from all items
for (int i = 0; i < length; i++)
{
int index = i;
T item = array[offset + i]; // use next item
// and move it on top, if greater than parent
while (index > 0 &&
comparison(array[offset + (index - 1) / 2], item) < 0)
{
int top = (index - 1) / 2;
array[offset + index] = array[offset + top];
index = top;
}
array[offset + index] = item;
}
for (int i = length - 1; i > 0; i--)
{
// delete max and place it as last
T last = array[offset + i];
array[offset + i] = array[offset];
int index = 0;
// the last one positioned in the heap
while (index * 2 + 1 < i)
{
int left = index * 2 + 1, right = left + 1;
if (right < i && comparison(array[offset + left], array[offset + right]) < 0)
{
if (comparison(last, array[offset + right]) > 0) break;
array[offset + index] = array[offset + right];
index = right;
}
else
{
if (comparison(last, array[offset + left]) > 0) break;
array[offset + index] = array[offset + left];
index = left;
}
}
array[offset + index] = last;
}
}
static void Main()
{
// usage
byte[] r = {5, 4, 1, 2};
HeapSort(r);
string[] s = { "-", "D", "a", "33" };
HeapSort(s, 0, s.Length, StringComparer.CurrentCultureIgnoreCase);
}
}
[edit] Clojure
(defn- swap [a i j]
(assoc a i (nth a j) j (nth a i)))
(defn- sift [a pred k l]
(loop [a a x k y (inc (* 2 k))]
(if (< (inc (* 2 x)) l)
(let [ch (if (and (< y (dec l)) (pred (nth a y) (nth a (inc y))))
(inc y)
y)]
(if (pred (nth a x) (nth a ch))
(recur (swap a x ch) ch (inc (* 2 ch)))
a))
a)))
(defn- heapify[pred a len]
(reduce (fn [c term] (sift (swap c term 0) pred 0 term))
(reduce (fn [c i] (sift c pred i len))
(vec a)
(range (dec (int (/ len 2))) -1 -1))
(range (dec len) 0 -1)))
(defn heap-sort
([a pred]
(let [len (count a)]
(heapify pred a len)))
([a]
(heap-sort a <)))
Example usage:
user> (heapsort [1 2 4 6 2 3 6])
[1 2 2 3 4 6 6]
user> (heapsort [1 2 4 6 2 3 6] >)
[6 6 4 3 2 2 1]
user> (heapsort (list 1 2 4 6 2 3 6))
[1 2 2 3 4 6 6]
[edit] CoffeeScript
# Do an in-place heap sort.
heap_sort = (arr) ->
put_array_in_heap_order(arr)
end = arr.length - 1
while end > 0
[arr[0], arr[end]] = [arr[end], arr[0]]
sift_element_down_heap arr, 0, end
end -= 1
put_array_in_heap_order = (arr) ->
i = arr.length / 2 - 1
i = Math.floor i
while i >= 0
sift_element_down_heap arr, i, arr.length
i -= 1
sift_element_down_heap = (heap, i, max) ->
while i < max
i_big = i
c1 = 2*i + 1
c2 = c1 + 1
if c1 < max and heap[c1] > heap[i_big]
i_big = c1
if c2 < max and heap[c2] > heap[i_big]
i_big = c2
return if i_big is i
[heap[i], heap[i_big]] = [heap[i_big], heap[i]]
i = i_big
do ->
arr = [12, 11, 15, 10, 9, 1, 2, 3, 13, 14, 4, 5, 6, 7, 8]
heap_sort arr
console.log arr
- Output:
> coffee heap.coffee [ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15 ]
[edit] Common Lisp
(defun make-heap (&optional (length 7))
(make-array length :adjustable t :fill-pointer 0))
(defun left-index (index)
(1- (* 2 (1+ index))))
(defun right-index (index)
(* 2 (1+ index)))
(defun parent-index (index)
(floor (1- index) 2))
(defun percolate-up (heap index predicate)
(if (zerop index) heap
(do* ((element (aref heap index))
(index index pindex)
(pindex (parent-index index)
(parent-index index)))
((zerop index) heap)
(if (funcall predicate element (aref heap pindex))
(rotatef (aref heap index) (aref heap pindex))
(return-from percolate-up heap)))))
(defun heap-insert (heap element predicate)
(let ((index (vector-push-extend element heap 2)))
(percolate-up heap index predicate)))
(defun percolate-down (heap index predicate)
(let ((length (length heap))
(element (aref heap index)))
(flet ((maybe-element (index)
"return the element at index or nil, and a boolean
indicating whether there was an element."
(if (< index length)
(values (aref heap index) t)
(values nil nil))))
(do ((index index swap-index)
(lindex (left-index index) (left-index index))
(rindex (right-index index) (right-index index))
(swap-index nil) (swap-child nil))
(nil)
;; Extact the left child if there is one. If there is not,
;; return the heap. Set the left child as the swap-child.
(multiple-value-bind (lchild lp) (maybe-element lindex)
(if (not lp) (return-from percolate-down heap)
(setf swap-child lchild
swap-index lindex))
;; Extract the right child, if any, and when better than the
;; current swap-child, update the swap-child.
(multiple-value-bind (rchild rp) (maybe-element rindex)
(when (and rp (funcall predicate rchild lchild))
(setf swap-child rchild
swap-index rindex))
;; If the swap-child is better than element, rotate them,
;; and continue percolating down, else return heap.
(if (not (funcall predicate swap-child element))
(return-from percolate-down heap)
(rotatef (aref heap index) (aref heap swap-index)))))))))
(defun heap-empty-p (heap)
(eql (length heap) 0))
(defun heap-delete-min (heap predicate)
(assert (not (heap-empty-p heap)) () "Can't pop from empty heap.")
(prog1 (aref heap 0)
(setf (aref heap 0) (vector-pop heap))
(unless (heap-empty-p heap)
(percolate-down heap 0 predicate))))
(defun heapsort (sequence predicate)
(let ((h (make-heap (length sequence))))
(map nil #'(lambda (e) (heap-insert h e predicate)) sequence)
(map-into sequence #'(lambda () (heap-delete-min h predicate)))))
Example usage:
(heapsort (vector 1 9 2 8 3 7 4 6 5) '<) ; #(1 2 3 4 5 6 7 8 9) (heapsort (list 9 8 1 2 7 6 3 4 5) '<) ; (1 2 3 4 5 6 7 8 9)
[edit] D
import std.stdio, std.algorithm;
void inplaceHeapSort(R)(R seq) pure nothrow {
static void siftDown(R seq, in size_t start,
in size_t end) pure nothrow {
for (size_t root = start; root * 2 + 1 <= end; ) {
auto child = root * 2 + 1;
if (child + 1 <= end && seq[child] < seq[child + 1])
child++;
if (seq[root] < seq[child]) {
swap(seq[root], seq[child]);
root = child;
} else
break;
}
}
if (seq.length > 1)
foreach_reverse (start; 1 .. (seq.length - 2) / 2 + 2)
siftDown(seq, start - 1, seq.length - 1);
foreach_reverse (end; 1 .. seq.length) {
swap(seq[end], seq[0]);
siftDown(seq, 0, end - 1);
}
}
void main() {
auto arr = [7, 6, 5, 9, 8, 4, 3, 1, 2, 0];
inplaceHeapSort(arr);
writeln(arr);
}
[edit] Using Standard Functions
import std.stdio, std.container;
void inplaceHeapSort(T)(T[] data) {
auto h = heapify(data);
while (!h.empty)
h.removeFront();
}
void main() {
auto arr = [7, 6, 5, 9, 8, 4, 3, 1, 2, 0];
inplaceHeapSort(arr);
writeln(arr);
}
[edit] Dart
void heapSort(List a) {
int count = a.length;
// first place 'a' in max-heap order
heapify(a, count);
int end = count - 1;
while (end > 0) {
// swap the root (maximum value) of the heap with the
// last element of the heap
int tmp = a[end];
a[end] = a[0];
a[0] = tmp;
// put the heap back in max-heap order
siftDown(a, 0, end - 1);
// decrement the size of the heap so that the previous
// max value will stay in its proper place
end--;
}
}
void heapify(List a, int count) {
// start is assigned the index in 'a' of the last parent node
int start = ((count - 2)/2).toInt(); // binary heap
while (start >= 0) {
// sift down the node at index 'start' to the proper place
// such that all nodes below the 'start' index are in heap
// order
siftDown(a, start, count - 1);
start--;
}
}
void siftDown(List a, int start, int end) {
// end represents the limit of how far down the heap to shift
int root = start;
while ((root*2 + 1) <= end) { // While the root has at least one child
int child = root*2 + 1; // root*2+1 points to the left child
// if the child has a sibling and the child's value is less than its sibling's...
if (child + 1 <= end && a[child] < a[child + 1]) {
child = child+1; // .. then point to the right child instead
}
if (a[root] < a[child]) { // out of max-heap order
int tmp = a[root];
a[root] = a[child];
a[child] = tmp;
root = child; // repeat to continue shifting down the child now
} else {
return;
}
}
}
void main() {
var arr=[1,5,2,7,3,9,4,6,8];
print("Before sort");
arr.forEach((var i)=>print("$i"));
heapSort(arr);
print("After sort");
arr.forEach((var i)=>print("$i"));
}
[edit] E
def heapsort := {
def cswap(c, a, b) {
def t := c[a]
c[a] := c[b]
c[b] := t
# println(c)
}
def siftDown(array, start, finish) {
var root := start
while (var child := root * 2 + 1
child <= finish) {
if (child + 1 <= finish && array[child] < array[child + 1]) {
child += 1
}
if (array[root] < array[child]) {
cswap(array, root, child)
root := child
} else {
break
}
}
}
/** Heapsort (in-place). */
def heapsort(array) {
# in pseudo-code, heapify only called once, so inline it here
for start in (0..((array.size()-2)//2)).descending() {
siftDown(array, start, array.size()-1)
}
for finish in (0..(array.size()-1)).descending() {
cswap(array, 0, finish)
siftDown(array, 0, finish - 1)
}
}
}
[edit] F#
let inline swap (a: _ []) i j =
let temp = a.[i]
a.[i] <- a.[j]
a.[j] <- temp
let inline sift cmp (a: _ []) start count =
let rec loop root child =
if root * 2 + 1 < count then
let p = child < count - 1 && cmp a.[child] a.[child + 1] < 0
let child = if p then child + 1 else child
if cmp a.[root] a.[child] < 0 then
swap a root child
loop child (child * 2 + 1)
loop start (start * 2 + 1)
let inline heapsort cmp (a: _ []) =
let n = a.Length
for start = n/2 - 1 downto 0 do
sift cmp a start n
for term = n - 1 downto 1 do
swap a term 0
sift cmp a 0 term
[edit] Forth
This program assumes that return addresses simply reside as a single cell on the Return Stack. Most Forth compilers fulfill this requirement.
create example
70 , 61 , 63 , 37 , 63 , 25 , 46 , 92 , 38 , 87 ,
[UNDEFINED] r'@ [IF]
: r'@ r> r> r@ swap >r swap >r ;
[THEN]
defer precedes ( n1 n2 a -- f)
defer exchange ( n1 n2 a --)
: siftDown ( a e s -- a e s)
swap >r swap >r dup ( s r)
begin ( s r)
dup 2* 1+ dup r'@ < ( s r c f)
while ( s r c)
dup 1+ dup r'@ < ( s r c c+1 f)
if ( s r c c+1)
over over r@ precedes if swap then
then drop ( s r c)
over over r@ precedes ( s r c f)
while ( s r c)
tuck r@ exchange ( s r)
repeat then ( s r)
drop drop r> swap r> swap ( a e s)
;
: heapsort ( a n --)
over >r ( a n)
dup 1- 1- 2/ ( a c s)
begin ( a c s)
dup 0< 0= ( a c s f)
while ( a c s)
siftDown 1- ( a c s)
repeat drop ( a c)
1- 0 ( a e 0)
begin ( a e 0)
over 0> ( a e 0 f)
while ( a e 0)
over over r@ exchange ( a e 0)
siftDown swap 1- swap ( a e 0)
repeat ( a e 0)
drop drop drop r> drop
;
:noname >r cells r@ + @ swap cells r> + @ swap < ; is precedes
:noname >r cells r@ + swap cells r> + over @ over @ swap rot ! swap ! ; is exchange
: .array 10 0 do example i cells + ? loop cr ;
.array example 10 heapsort .array
[edit] Fortran
Translation of the pseudocode
program Heapsort_Demo
implicit none
integer, parameter :: num = 20
real :: array(num)
call random_seed
call random_number(array)
write(*,*) "Unsorted array:-"
write(*,*) array
write(*,*)
call heapsort(array)
write(*,*) "Sorted array:-"
write(*,*) array
contains
subroutine heapsort(a)
real, intent(in out) :: a(0:)
integer :: start, n, bottom
real :: temp
n = size(a)
do start = (n - 2) / 2, 0, -1
call siftdown(a, start, n);
end do
do bottom = n - 1, 1, -1
temp = a(0)
a(0) = a(bottom)
a(bottom) = temp;
call siftdown(a, 0, bottom)
end do
end subroutine heapsort
subroutine siftdown(a, start, bottom)
real, intent(in out) :: a(0:)
integer, intent(in) :: start, bottom
integer :: child, root
real :: temp
root = start
do while(root*2 + 1 < bottom)
child = root * 2 + 1
if (child + 1 < bottom) then
if (a(child) < a(child+1)) child = child + 1
end if
if (a(root) < a(child)) then
temp = a(child)
a(child) = a (root)
a(root) = temp
root = child
else
return
end if
end do
end subroutine siftdown
end program Heapsort_Demo
[edit] Go
Here's an ingenious solution that makes use of the heap module. Although the heap module usually implements an independent heap with push/pop operations, we use a helper type where the "pop" operation does not actually change the size of the underlying container, but changes a "heap length" variable indicating the length of the prefix of the underlying container that is considered "the heap".
Since we want to implement a generic algorithm, we accept an argument of type sort.Interface, and thus do not have access to the actual elements of the container we're sorting. We can only swap elements. This causes a problem for us when implementing the Pop method, as we can't actually return an element. The ingenious step is realizing that heap.Pop() must move the value to pop to the "end" of the heap area, because its interface only has access to a "Swap" function, and a "Pop" function that pops from the end. (It does not have the ability to pop a value at the beginning.) This is perfect because we precisely want to move the thing popped to the end and shrink the "heap area" by 1. Our "Pop" function returns nothing since we can't get the value, but don't actually need it. (We only need the swapping that it does for us.)
package main
import (
"sort"
"container/heap"
"fmt"
)
type HeapHelper struct {
container sort.Interface
length int
}
func (self HeapHelper) Len() int { return self.length }
// We want a max-heap, hence reverse the comparison
func (self HeapHelper) Less(i, j int) bool { return self.container.Less(j, i) }
func (self HeapHelper) Swap(i, j int) { self.container.Swap(i, j) }
// this should not be called
func (self *HeapHelper) Push(x interface{}) { panic("impossible") }
func (self *HeapHelper) Pop() interface{} {
self.length--
return nil // return value not used
}
func heapSort(a sort.Interface) {
helper := HeapHelper{ a, a.Len() }
heap.Init(&helper)
for helper.length > 0 {
heap.Pop(&helper)
}
}
func main() {
a := []int{170, 45, 75, -90, -802, 24, 2, 66}
fmt.Println("before:", a)
heapSort(sort.IntSlice(a))
fmt.Println("after: ", a)
}
- Output:
before: [170 45 75 -90 -802 24 2 66] after: [-802 -90 2 24 45 66 75 170]
If you want to implement it manually:
package main
import (
"sort"
"fmt"
)
func main() {
a := []int{170, 45, 75, -90, -802, 24, 2, 66}
fmt.Println("before:", a)
heapSort(sort.IntSlice(a))
fmt.Println("after: ", a)
}
func heapSort(a sort.Interface) {
for start := (a.Len() - 2) / 2; start >= 0; start-- {
siftDown(a, start, a.Len()-1)
}
for end := a.Len() - 1; end > 0; end-- {
a.Swap(0, end)
siftDown(a, 0, end-1)
}
}
func siftDown(a sort.Interface, start, end int) {
for root := start; root*2+1 <= end; {
child := root*2 + 1
if child+1 <= end && a.Less(child, child+1) {
child++
}
if !a.Less(root, child) {
return
}
a.Swap(root, child)
root = child
}
}
[edit] Groovy
Loose translation of the pseudocode:
def makeSwap = { a, i, j = i+1 -> print "."; a[[j,i]] = a[[i,j]] }
def checkSwap = { list, i, j = i+1 -> [(list[i] > list[j])].find{ it }.each { makeSwap(list, i, j) } }
def siftDown = { a, start, end ->
def p = start
while (p*2 < end) {
def c = p*2 + ((p*2 + 1 < end && a[p*2 + 2] > a[p*2 + 1]) ? 2 : 1)
if (checkSwap(a, c, p)) { p = c }
else { return }
}
}
def heapify = {
(((it.size()-2).intdiv(2))..0).each { start -> siftDown(it, start, it.size()-1) }
}
def heapSort = { list ->
heapify(list)
(0..<(list.size())).reverse().each { end ->
makeSwap(list, 0, end)
siftDown(list, 0, end-1)
}
list
}
Test:
println (heapSort([23,76,99,58,97,57,35,89,51,38,95,92,24,46,31,24,14,12,57,78,4]))
println (heapSort([88,18,31,44,4,0,8,81,14,78,20,76,84,33,73,75,82,5,62,70,12,7,1]))
- Output:
.......................................................................[4, 12, 14, 23, 24, 24, 31, 35, 38, 46, 51, 57, 57, 58, 76, 78, 89, 92, 95, 97, 99] ..........................................................................................[0, 1, 4, 5, 7, 8, 12, 14, 18, 20, 31, 33, 44, 62, 70, 73, 75, 76, 78, 81, 82, 84, 88]
[edit] Haskell
Using package fgl from HackageDB
import Data.Graph.Inductive.Internal.Heap(
Heap(..),insert,findMin,deleteMin)
-- heapsort is added in this module as an example application
build :: Ord a => [(a,b)] -> Heap a b
build = foldr insert Empty
toList :: Ord a => Heap a b -> [(a,b)]
toList Empty = []
toList h = x:toList r
where (x,r) = (findMin h,deleteMin h)
heapsort :: Ord a => [a] -> [a]
heapsort = (map fst) . toList . build . map (\x->(x,x))
e.g.
*Main> heapsort [[6,9],[2,13],[6,8,14,9],[10,7],[5]]
[[2,13],[5],[6,8,14,9],[6,9],[10,7]]
[edit] Icon and Unicon
procedure main() #: demonstrate various ways to sort a list and string
demosort(heapsort,[3, 14, 1, 5, 9, 2, 6, 3],"qwerty")
end
procedure heapsort(X,op) #: return sorted list ascending(or descending)
local head,tail
op := sortop(op,X) # select how and what we sort
every head := (tail := *X) / 2 to 1 by -1 do # work back from from last parent node
X := siftdown(X,op,head,tail) # sift down from head to make the heap
every tail := *X to 2 by -1 do { # work between the beginning and the tail to final positions
X[1] :=: X[tail]
X := siftdown(X,op,1,tail-1) # re-sift next (previous) branch after shortening the heap
}
return X
end
procedure siftdown(X,op,root,tail) #: the value @root is moved "down" the path of max(min) value to its level
local child
while (child := root * 2) <= tail do { # move down the branch from root to tail
if op(X[child],X[tail >= child + 1]) then # choose the larger(smaller)
child +:= 1 # ... child
if op(X[root],X[child]) then { # root out of order?
X[child] :=: X[root]
root := child # follow max(min) branch
}
else
return X
}
return X
end
Algorithm notes:
- This is a fairly straight forward implementation of the pseudo-code with 'heapify' coded in-line.
Implementation notes:
- Since this transparently sorts both string and list arguments the result must 'return' to bypass call by value (strings)
- Beware missing trailing 'returns' when translating pseudo-code. For amusement try comment out the return at the end of 'shiftdown'
Note: This example relies on the supporting procedures 'sortop', and 'demosort' in Bubble Sort. The full demosort exercises the named sort of a list with op = "numeric", "string", ">>" (lexically gt, descending),">" (numerically gt, descending), a custom comparator, and also a string.
- Abbreviated sample output:
Sorting Demo using procedure heapsort
on list : [ 3 14 1 5 9 2 6 3 ]
with op = &null: [ 1 2 3 3 5 6 9 14 ] (0 ms)
...
on string : "qwerty"
with op = &null: "eqrtwy" (0 ms)
[edit] J
Translation of the pseudocode
swap=: C.~ <
siftDown=: 4 : 0
'c e'=. x
while. e > c=.1+2*s=.c do.
before=. <&({&y)
if. e > 1+c do. c=.c+ c before c+1 end.
if. s before c do. y=. y swap c,s else. break. end.
end.
y
)
heapSort=: 3 : 0
if. 1>: c=. # y do. y return. end.
z=. siftDown&.>/ (c,~each i.<.c%2),<y NB. heapify
> ([ siftDown swap~)&.>/ (0,each}.i.c),z
)
Examples
heapSort 1 5 2 7 3 9 4 6 8 1
1 1 2 3 4 5 6 7 8 9
heapSort &. (a.&i.) 'aqwcdhkij'
acdhijkqw
[edit] Java
Direct translation of the pseudocode.
public static void heapSort(int[] a){
int count = a.length;
//first place a in max-heap order
heapify(a, count);
int end = count - 1;
while(end > 0){
//swap the root(maximum value) of the heap with the
//last element of the heap
int tmp = a[end];
a[end] = a[0];
a[0] = tmp;
//put the heap back in max-heap order
siftDown(a, 0, end - 1);
//decrement the size of the heap so that the previous
//max value will stay in its proper place
end--;
}
}
public static void heapify(int[] a, int count){
//start is assigned the index in a of the last parent node
int start = (count - 2) / 2; //binary heap
while(start >= 0){
//sift down the node at index start to the proper place
//such that all nodes below the start index are in heap
//order
siftDown(a, start, count - 1);
start--;
}
//after sifting down the root all nodes/elements are in heap order
}
public static void siftDown(int[] a, int start, int end){
//end represents the limit of how far down the heap to sift
int root = start;
while((root * 2 + 1) <= end){ //While the root has at least one child
int child = root * 2 + 1; //root*2+1 points to the left child
//if the child has a sibling and the child's value is less than its sibling's...
if(child + 1 <= end && a[child] < a[child + 1])
child = child + 1; //... then point to the right child instead
if(a[root] < a[child]){ //out of max-heap order
int tmp = a[root];
a[root] = a[child];
a[child] = tmp;
root = child; //repeat to continue sifting down the child now
}else
return;
}
}
[edit] Liberty BASIC
wikiSample=1 'comment out for random array
data 6, 5, 3, 1, 8, 7, 2, 4
itemCount = 20
if wikiSample then itemCount = 8
dim A(itemCount)
for i = 1 to itemCount
A(i) = int(rnd(1) * 100)
if wikiSample then read tmp: A(i)=tmp
next i
print "Before Sort"
call printArray itemCount
call heapSort itemCount
print "After Sort"
call printArray itemCount
end
'------------------------------------------
sub heapSort count
call heapify count
print "the heap"
call printArray count
theEnd = count
while theEnd > 1
call swap theEnd, 1
call siftDown 1, theEnd-1
theEnd = theEnd - 1
wend
end sub
sub heapify count
start = int(count / 2)
while start >= 1
call siftDown start, count
start = start - 1
wend
end sub
sub siftDown start, theEnd
root = start
while root * 2 <= theEnd
child = root * 2
swap = root
if A(swap) < A(child) then
swap = child
end if
if child+1 <= theEnd then
if A(swap) < A(child+1) then
swap = child + 1
end if
end if
if swap <> root then
call swap root, swap
root = swap
else
exit sub
end if
wend
end sub
sub swap a,b
tmp = A(a)
A(a) = A(b)
A(b) = tmp
end sub
'===========================================
sub printArray itemCount
for i = 1 to itemCount
print using("###", A(i));
next i
end sub
[edit] LotusScript
Public Sub heapsort(pavIn As Variant)
Dim liCount As Integer, liEnd As Integer
Dim lvTemp As Variant
liCount = UBound(pavIn) + 1
heapify pavIn, liCount
liEnd = liCount - 1
While liEnd > 0
lvTemp = pavIn(liEnd)
pavIn(liEnd) = pavIn(0)
pavIn(0) = lvTemp
liEnd = liEnd -1
siftDown pavIn,0, liEnd
Wend
End Sub
Private Sub heapify(pavIn As Variant,piCount As Integer)
Dim liStart As Integer
liStart = (piCount - 2) / 2
While liStart >=0
siftDown pavIn, liStart, piCount -1
liStart = liStart - 1
Wend
End Sub
Private Sub siftDown(pavIn As Variant, piStart As Integer, piEnd As Integer)
Dim liRoot As Integer, liChild As Integer
Dim lvTemp As Variant
liRoot = piStart
While liRoot *2 + 1 <= piEnd
liChild = liRoot *2 + 1
If liChild +1 <= piEnd And pavIn(liChild) < pavIn(liChild + 1) Then
liChild = liChild + 1
End If
If pavIn(liRoot) < pavIn(liChild) Then
lvTemp = pavIn(liRoot)
pavIn(liRoot) = pavIn(liChild)
pavIn(liChild) = lvTemp
liRoot = liChild
Else
Exit sub
End if
wend
End Sub
[edit] M4
divert(-1)
define(`randSeed',141592653)
define(`setRand',
`define(`randSeed',ifelse(eval($1<10000),1,`eval(20000-$1)',`$1'))')
define(`rand_t',`eval(randSeed^(randSeed>>13))')
define(`random',
`define(`randSeed',eval((rand_t^(rand_t<<18))&0x7fffffff))randSeed')
define(`set',`define(`$1[$2]',`$3')')
define(`get',`defn(`$1[$2]')')
define(`new',`set($1,size,0)')
dnl for the heap calculations, it's easier if origin is 0, so set value first
define(`append',
`set($1,get($1,size),$2)`'set($1,size,incr(get($1,size)))')
dnl swap(<name>,<j>,<name>[<j>],<k>) using arg stack for the temporary
define(`swap',`set($1,$2,get($1,$4))`'set($1,$4,$3)')
define(`deck',
`new($1)for(`x',1,$2,
`append(`$1',eval(random%100))')')
define(`show',
`for(`x',0,decr(get($1,size)),`get($1,x) ')')
define(`for',
`ifelse($#,0,``$0'',
`ifelse(eval($2<=$3),1,
`pushdef(`$1',$2)$4`'popdef(`$1')$0(`$1',incr($2),$3,`$4')')')')
define(`ifywork',
`ifelse(eval($2>=0),1,
`siftdown($1,$2,$3)`'ifywork($1,decr($2),$3)')')
define(`heapify',
`define(`start',eval((get($1,size)-2)/2))`'ifywork($1,start,
decr(get($1,size)))')
define(`siftdown',
`define(`child',eval($2*2+1))`'ifelse(eval(child<=$3),1,
`ifelse(eval(child+1<=$3),1,
`ifelse(eval(get($1,child)<get($1,incr(child))),1,
`define(`child',
incr(child))')')`'ifelse(eval(get($1,$2)<get($1,child)),1,
`swap($1,$2,get($1,$2),child)`'siftdown($1,child,$3)')')')
define(`sortwork',
`ifelse($2,0,
`',
`swap($1,0,get($1,0),$2)`'siftdown($1,0,decr($2))`'sortwork($1,
decr($2))')')
define(`heapsort',
`heapify($1)`'sortwork($1,decr(get($1,size)))')
divert
deck(`a',10)
show(`a')
heapsort(`a')
show(`a')
[edit] Mathematica
siftDown[list_,root_,theEnd_]:=
While[(root*2) <= theEnd,
child = root*2;
If[(child+1 <= theEnd)&&(list[[child]] < list[[child+1]]), child++;];
If[list[[root]] < list[[child]],
list[[{root,child}]] = list[[{child,root}]]; root = child;,
Break[];
]
]
heapSort[list_] := Module[{ count, start},
count = Length[list]; start = Floor[count/2];
While[start >= 1,list = siftDown[list,start,count];
start--;
]
While[count > 1, list[[{count,1}]] = list[[{1,count}]];
count--; list = siftDown[list,1,count];
]
]
- Output:
heapSort@{2,3,1,5,7,6}
{1,2,3,5,6,7}
[edit] MATLAB / Octave
This function definition is an almost exact translation of the pseudo-code into MATLAB, but I have chosen to make the heapify function inline because it is only called once in the pseudo-code. Also, MATLAB uses 1 based array indecies, therefore all of the pseudo-code has been translated to reflect that difference.
function list = heapSort(list)
function list = siftDown(list,root,theEnd)
while (root * 2) <= theEnd
child = root * 2;
if (child + 1 <= theEnd) && (list(child) < list(child+1))
child = child + 1;
end
if list(root) < list(child)
list([root child]) = list([child root]); %Swap
root = child;
else
return
end
end %while
end %siftDown
count = numel(list);
%Because heapify is called once in pseudo-code, it is inline here
start = floor(count/2);
while start >= 1
list = siftDown(list, start, count);
start = start - 1;
end
%End Heapify
while count > 1
list([count 1]) = list([1 count]); %Swap
count = count - 1;
list = siftDown(list,1,count);
end
end
Sample Usage:
>> heapSort([4 3 1 5 6 2])
ans =
1 2 3 4 5 6
[edit] NetRexx
/* NetRexx */
options replace format comments java crossref savelog symbols binary
import java.util.List
placesList = [String -
"UK London", "US New York", "US Boston", "US Washington" -
, "UK Washington", "US Birmingham", "UK Birmingham", "UK Boston" -
]
lists = [ -
placesList -
, heapSort(String[] Arrays.copyOf(placesList, placesList.length)) -
]
loop ln = 0 to lists.length - 1
cl = lists[ln]
loop ct = 0 to cl.length - 1
say cl[ct]
end ct
say
end ln
return
method heapSort(a = String[], count = a.length) public constant binary returns String[]
rl = String[a.length]
al = List heapSort(Arrays.asList(a), count)
al.toArray(rl)
return rl
method heapSort(a = List, count = a.size) public constant binary returns ArrayList
a = heapify(a, count)
iend = count - 1
loop label iend while iend > 0
swap = a.get(0)
a.set(0, a.get(iend))
a.set(iend, swap)
a = siftDown(a, 0, iend - 1)
iend = iend - 1
end iend
return ArrayList(a)
method heapify(a = List, count = int) public constant binary returns List
start = (count - 2) % 2
loop label strt while start >= 0
a = siftDown(a, start, count - 1)
start = start - 1
end strt
return a
method siftDown(a = List, istart = int, iend = int) public constant binary returns List
root = istart
loop label root while root * 2 + 1 <= iend
child = root * 2 + 1
if child + 1 <= iend then do
if (Comparable a.get(child)).compareTo(Comparable a.get(child + 1)) < 0 then do
child = child + 1
end
end
if (Comparable a.get(root)).compareTo(Comparable a.get(child)) < 0 then do
swap = a.get(root)
a.set(root, a.get(child))
a.set(child, swap)
root = child
end
else do
leave root
end
end root
return a
- Output:
UK London US New York US Boston US Washington UK Washington US Birmingham UK Birmingham UK Boston UK Birmingham UK Boston UK London UK Washington US Birmingham US Boston US New York US Washington
[edit] Objeck
bundle Default {
class HeapSort {
function : Main(args : String[]) ~ Nil {
values := [4, 3, 1, 5, 6, 2];
HeapSort(values);
each(i : values) {
values[i]->PrintLine();
};
}
function : HeapSort(a : Int[]) ~ Nil {
count := a->Size();
Heapify(a, count);
end := count - 1;
while(end > 0) {
tmp := a[end];
a[end] := a[0];
a[0] := tmp;
SiftDown(a, 0, end - 1);
end -= 1;
};
}
function : Heapify(a : Int[], count : Int) ~ Nil {
start := (count - 2) / 2;
while(start >= 0) {
SiftDown(a, start, count - 1);
start -= 1;
};
}
function : SiftDown(a : Int[], start : Int, end : Int) ~ Nil {
root := start;
while((root * 2 + 1) <= end) {
child := root * 2 + 1;
if(child + 1 <= end & a[child] < a[child + 1]) {
child := child + 1;
};
if(a[root] < a[child]) {
tmp := a[root];
a[root] := a[child];
a[child] := tmp;
root := child;
}
else {
return;
};
};
}
}
}
[edit] OCaml
let heapsort a =
let swap i j =
let t = a.(i) in a.(i) <- a.(j); a.(j) <- t in
let sift k l =
let rec check x y =
if 2*x+1 < l then
let ch =
if y < l-1 && a.(y) < a.(y+1) then y+1 else y in
if a.(x) < a.(ch) then (swap x ch; check ch (2*ch+1)) in
check k (2*k+1) in
let len = Array.length a in
for start = (len/2)-1 downto 0 do
sift start len;
done;
for term = len-1 downto 1 do
swap term 0;
sift 0 term;
done;;
Usage:
let a = [|3;1;4;1;5;9;2;6;5;3;5;8;97;93;23;84;62;64;33;83;27;95|] in
heapsort a;
Array.iter (Printf.printf "%d ") a;;
print_newline ();;
let s = "Just to show this is a type-checked polymorphic function" in
let b = Array.init (String.length s) (String.get s) in
heapsort b;
Array.iter print_char b;;
print_newline ();;
- Output:
1 1 2 3 3 4 5 5 5 6 8 9 23 27 33 62 64 83 84 93 95 97
-Jaccccdeeefhhhhiiiiklmnnoooooppprsssstttttuuwyy
[edit] Oz
A faithful translation of the pseudocode, adjusted to the fact that Oz arrays can start with an arbitrary index, not just 0 or 1.
declare
proc {HeapSort A}
Low = {Array.low A}
High = {Array.high A}
Count = High-Low+1
%% heapify
LastParent = Low + (Count-2) div 2
in
for Start in LastParent..Low;~1 do
{Siftdown A Start High}
end
%% repeatedly put the maximum element to the end
%% and re-heapify the rest
for End in High..Low+1;~1 do
{Swap A End Low}
{Siftdown A Low End-1}
end
end
proc {Siftdown A Start End}
Low = {Array.low A}
fun {FirstChildOf I} Low+(I-Low)*2+1 end
Root = {NewCell Start}
in
for while:{FirstChildOf @Root} =< End
break:Break
do
Child = {NewCell {FirstChildOf @Root}}
in
if @Child + 1 =< End andthen A.@Child < A.(@Child + 1) then
Child := @Child + 1
end
if A.@Root < A.@Child then
{Swap A @Root @Child}
Root := @Child
else
{Break}
end
end
end
proc {Swap A I J}
A.J := (A.I := A.J)
end
%% create array with indices ~1..7 and fill it
Arr = {Array.new ~1 7 0}
{Record.forAllInd unit(~1:3 0:1 4 1 5 9 2 6 5)
proc {$ I V}
Arr.I := V
end}
in
{HeapSort Arr}
{Show {Array.toRecord unit Arr}}
[edit] Pascal
An example, which works on arrays with arbitrary bounds :-)
program HeapSortDemo;
type
TIntArray = array[4..15] of integer;
var
data: TIntArray;
i: integer;
procedure siftDown(var a: TIntArray; start, ende: integer);
var
root, child, swap: integer;
begin
root := start;
while root * 2 - start + 1 <= ende do
begin
child := root * 2 - start + 1;
if (child + 1 <= ende) and (a[child] < a[child + 1]) then
inc(child);
if a[root] < a[child] then
begin
swap := a[root];
a[root] := a[child];
a[child] := swap;
root := child;
end
else
exit;
end;
end;
procedure heapify(var a: TIntArray);
var
start, count: integer;
begin
count := length(a);
start := low(a) + count div 2 - 1;
while start >= low(a) do
begin
siftdown(a, start, high(a));
dec(start);
end;
end;
procedure heapSort(var a: TIntArray);
var
ende, swap: integer;
begin
heapify(a);
ende := high(a);
while ende > low(a) do
begin
swap := a[low(a)];
a[low(a)] := a[ende];
a[ende] := swap;
dec(ende);
siftdown(a, low(a), ende);
end;
end;
begin
Randomize;
writeln('The data before sorting:');
for i := low(data) to high(data) do
begin
data[i] := Random(high(data));
write(data[i]:4);
end;
writeln;
heapSort(data);
writeln('The data after sorting:');
for i := low(data) to high(data) do
begin
write(data[i]:4);
end;
writeln;
end.
- Output:
The data before sorting: 12 13 0 1 0 14 13 10 1 10 9 2 The data after sorting: 0 0 1 1 2 9 10 10 12 13 13 14
[edit] Perl
Translation of the pseudocode.
my @my_list = (2,3,6,23,13,5,7,3,4,5);
heap_sort(\@my_list);
print "@my_list\n";
exit;
sub heap_sort
{
my($list) = @_;
my $count = scalar @$list;
heapify($count,$list);
my $end = $count - 1;
while($end > 0)
{
@$list[0,$end] = @$list[$end,0];
sift_down(0,$end-1,$list);
$end--;
}
}
sub heapify
{
my ($count,$list) = @_;
my $start = ($count - 2) / 2;
while($start >= 0)
{
sift_down($start,$count-1,$list);
$start--;
}
}
sub sift_down
{
my($start,$end,$list) = @_;
my $root = $start;
while($root * 2 + 1 <= $end)
{
my $child = $root * 2 + 1;
$child++ if($child + 1 <= $end && $list->[$child] < $list->[$child+1]);
if($list->[$root] < $list->[$child])
{
@$list[$root,$child] = @$list[$child,$root];
$root = $child;
}else{ return }
}
}
[edit] Perl 6
sub heap_sort ( @list is rw ) {
for ( 0 ..^ +@list div 2 ).reverse -> $start {
_sift_down $start, @list.end, @list;
}
for ( 1 ..^ +@list ).reverse -> $end {
@list[ 0, $end ] .= reverse;
_sift_down 0, $end-1, @list;
}
}
sub _sift_down ( $start, $end, @list is rw ) {
my $root = $start;
while ( my $child = $root * 2 + 1 ) <= $end {
$child++ if $child + 1 <= $end and [<] @list[ $child, $child+1 ];
return if @list[$root] >= @list[$child];
@list[ $root, $child ] .= reverse;
$root = $child;
}
}
my @data = 6, 7, 2, 1, 8, 9, 5, 3, 4;
say 'Input = ' ~ @data;
@data.&heap_sort;
say 'Output = ' ~ @data;
- Output:
Input = 6 7 2 1 8 9 5 3 4 Output = 1 2 3 4 5 6 7 8 9
[edit] PicoLisp
(de heapSort (A Cnt)
(let Cnt (length A)
(for (Start (/ Cnt 2) (gt0 Start) (dec Start))
(siftDown A Start (inc Cnt)) )
(for (End Cnt (> End 1) (dec End))
(xchg (nth A End) A)
(siftDown A 1 End) ) )
A )
(de siftDown (A Start End)
(use Child
(for (Root Start (> End (setq Child (* 2 Root))))
(and
(> End (inc Child))
(> (get A (inc Child)) (get A Child))
(inc 'Child) )
(NIL (> (get A Child) (get A Root)))
(xchg (nth A Root) (nth A Child))
(setq Root Child) ) ) )
- Output:
: (heapSort (make (do 9 (link (rand 1 999))))) -> (1 167 183 282 524 556 638 891 902)
[edit] PureBasic
Declare heapify(Array a(1), count)
Declare siftDown(Array a(1), start, ending)
Procedure heapSort(Array a(1), count)
Protected ending=count-1
heapify(a(), count)
While ending>0
Swap a(ending),a(0)
siftDown(a(), 0, ending-1)
ending-1
Wend
EndProcedure
Procedure heapify(Array a(1), count)
Protected start=(count-2)/2
While start>=0
siftDown(a(),start,count-1)
start-1
Wend
EndProcedure
Procedure siftDown(Array a(1), start, ending)
Protected root=start, child
While (root*2+1)<=ending
child=root*2+1
If child+1<=ending And a(child)<a(child+1)
child+1
EndIf
If a(root)<a(child)
Swap a(root), a(child)
root=child
Else
Break
EndIf
Wend
EndProcedure
[edit] Python
def heapsort(lst):
''' Heapsort. Note: this function sorts in-place (it mutates the list). '''
# in pseudo-code, heapify only called once, so inline it here
for start in range((len(lst)-2)/2, -1, -1):
siftdown(lst, start, len(lst)-1)
for end in range(len(lst)-1, 0, -1):
lst[end], lst[0] = lst[0], lst[end]
siftdown(lst, 0, end - 1)
return lst
def siftdown(lst, start, end):
root = start
while True:
child = root * 2 + 1
if child > end: break
if child + 1 <= end and lst[child] < lst[child + 1]:
child += 1
if lst[root] < lst[child]:
lst[root], lst[child] = lst[child], lst[root]
root = child
else:
break
Testing:
>>> ary = [7, 6, 5, 9, 8, 4, 3, 1, 2, 0] >>> heapsort(ary) [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
[edit] REXX
/*REXX program sorts an array using the heapsort method. */
call gen@ /*generate the array elements. */
call show@ 'before sort' /*show the before array elements*/
call heapSort highItem /*invoke the heap sort. */
call show@ ' after sort' /*show tge after array elements*/
exit /*stick a fork in it, we're done.*/
/*──────────────────────────────────HEAPSORT subroutine─────────────────*/
heapSort: procedure expose @.; parse arg n
do j=n%2 by -1 to 1
call shuffle j,n
end /*j*/
do n=n by -1 to 2
_=@.1; @.1=@.n; @.n=_; call shuffle 1,n
end /*n*/
return
/*──────────────────────────────────SHUFFLE subroutine──────────────────*/
shuffle: procedure expose @.; parse arg i,n; _=@.i
do while i+i<=n
j=i+i; k=j+1
if k<=n & @.k>@.j then j=k
if _>=@.j then leave
@.i=@.j; i=j
end /*while i+i<=n*/
@.i=_
return
/*──────────────────────────────────GEN@ subroutine─────────────────────*/
gen@: @.= /*assign default value for array.*/
@.1 ='---letters of the modern Greek Alphabet---' ; @.14='mu'
@.2 ='==========================================' ; @.15='nu'
@.3 ='alpha' ; @.16='xi'
@.4 ='beta' ; @.17='omicron'
@.5 ='gamma' ; @.18='pi'
@.6 ='delta' ; @.19='rho'
@.7 ='epsilon' ; @.20='sigma'
@.8 ='zeta' ; @.21='tau'
@.9 ='eta' ; @.22='upsilon'
@.10='theta' ; @.23='phi'
@.11='iota' ; @.24='chi'
@.12='kappa' ; @.25='psi'
@.13='lambda' ; @.26='omega'
do highItem=1 while @.highItem\=='' /*find how many entries. */
end /*highitem*/
highItem=highItem-1 /*adjust highItem slightly. */
return
/*──────────────────────────────────SHOW@ subroutine────────────────────*/
show@: widthH=length(highItem) /*maximum width of any line. */
do j=1 for highItem
say 'element' right(j,widthH) arg(1)':' @.j
end /*j*/
say copies('-', 79) /*show a separator line. */
return
- Output:
element 1 before sort: ---letters of the modern Greek Alphabet--- element 2 before sort: ========================================== element 3 before sort: alpha element 4 before sort: beta element 5 before sort: gamma element 6 before sort: delta element 7 before sort: epsilon element 8 before sort: zeta element 9 before sort: eta element 10 before sort: theta element 11 before sort: iota element 12 before sort: kappa element 13 before sort: lambda element 14 before sort: mu element 15 before sort: nu element 16 before sort: xi element 17 before sort: omicron element 18 before sort: pi element 19 before sort: rho element 20 before sort: sigma element 21 before sort: tau element 22 before sort: upsilon element 23 before sort: phi element 24 before sort: chi element 25 before sort: psi element 26 before sort: omega ──────────────────────────────────────────────────────────────────────────────── element 1 after sort: eta element 2 after sort: ========================================== element 3 after sort: chi element 4 after sort: beta element 5 after sort: delta element 6 after sort: ---letters of the modern Greek Alphabet--- element 7 after sort: theta element 8 after sort: iota element 9 after sort: omicron element 10 after sort: lambda element 11 after sort: omega element 12 after sort: kappa element 13 after sort: nu element 14 after sort: mu element 15 after sort: epsilon element 16 after sort: alpha element 17 after sort: phi element 18 after sort: pi element 19 after sort: psi element 20 after sort: rho element 21 after sort: sigma element 22 after sort: tau element 23 after sort: gamma element 24 after sort: upsilon element 25 after sort: xi element 26 after sort: zeta ────────────────────────────────────────────────────────────────────────────────
[edit] Ruby
class Array
def heapsort
self.dup.heapsort!
end
def heapsort!
# in pseudo-code, heapify only called once, so inline it here
((length - 2) / 2).downto(0) {|start| siftdown(start, length - 1)}
# "end" is a ruby keyword
(length - 1).downto(1) do |end_|
self[end_], self[0] = self[0], self[end_]
siftdown(0, end_ - 1)
end
self
end
def siftdown(start, end_)
root = start
loop do
child = root * 2 + 1
break if child > end_
if child + 1 <= end_ and self[child] < self[child + 1]
child += 1
end
if self[root] < self[child]
self[root], self[child] = self[child], self[root]
root = child
else
break
end
end
end
end
Testing:
irb(main):035:0> ary = [7, 6, 5, 9, 8, 4, 3, 1, 2, 0] => [7, 6, 5, 9, 8, 4, 3, 1, 2, 0] irb(main):036:0> ary.heapsort => [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
[edit] Scala
This code is not written for maximum performance, though, of course, it preserves the O(n log n) characteristic of heap sort.
def heapSort[T](a: Array[T])(implicit ord: Ordering[T]) {
import scala.annotation.tailrec // Ensure functions are tail-recursive
import ord._
val indexOrdering = Ordering by a.apply
def numberOfLeaves(heapSize: Int) = (heapSize + 1) / 2
def children(i: Int, heapSize: Int) = {
val leftChild = i * 2 + 1
leftChild to leftChild + 1 takeWhile (_ < heapSize)
}
def swap(i: Int, j: Int) = {
val tmp = a(i)
a(i) = a(j)
a(j) = tmp
}
// Maintain partial ordering by bubbling down elements
@tailrec
def siftDown(i: Int, heapSize: Int) {
val childrenOfI = children(i, heapSize)
if (childrenOfI nonEmpty) {
val biggestChild = childrenOfI max indexOrdering
if (a(i) < a(biggestChild)) {
swap(i, biggestChild)
siftDown(biggestChild, heapSize)
}
}
}
// Prepare heap by sifting down all non-leaf elements
for (i <- a.indices.reverse drop numberOfLeaves(a.size)) siftDown(i, a.size)
// Sort from the end of the array forward, by swapping the highest element,
// which is always the top of the heap, to the end of the unsorted array
for (i <- a.indices.reverse) {
swap(0, i)
siftDown(0, i)
}
}
[edit] Scheme
; swap two elements of a vector
(define (swap! v i j)
(define temp (vector-ref v i))
(vector-set! v i (vector-ref v j))
(vector-set! v j temp))
; sift element at node start into place
(define (sift-down! v start end)
(let ((child (+ (* start 2) 1)))
(cond
((> child end) 'done) ; start has no children
(else
(begin
; if child has a sibling node whose value is greater ...
(and (and (<= (+ child 1) end)
(< (vector-ref v child) (vector-ref v (+ child 1))))
; ... then we'll look at the sibling instead
(set! child (+ child 1)))
(if (< (vector-ref v start) (vector-ref v child))
(begin
(swap! v start child)
(sift-down! v child end))
'done))))))
; transform v into a binary max-heap
(define (heapify v)
(define (iter v start)
(if (>= start 0)
(begin (sift-down! v start (- (vector-length v) 1))
(iter v (- start 1)))
'done))
; start sifting with final parent node of v
(iter v (quotient (- (vector-length v) 2) 2)))
(define (heapsort v)
; swap root and end node values,
; sift the first element into place
; and recurse with new root and next-to-end node
(define (iter v end)
(if (zero? end)
'done
(begin
(swap! v 0 end)
(sift-down! v 0 (- end 1))
(iter v (- end 1)))))
(begin
(heapify v)
; start swapping with root and final node
(iter v (- (vector-length v) 1))))
; testing
(define uriah (list->vector '(3 5 7 9 0 8 1 4 2 6)))
(heapsort uriah)
uriah
- Output:
done #(0 1 2 3 4 5 6 7 8 9)
[edit] Seed7
const proc: downheap (inout array elemType: arr, in var integer: k, in integer: n) is func
local
var elemType: help is elemType.value;
var integer: j is 0;
begin
if k <= n div 2 then
help := arr[k];
repeat
j := 2 * k;
if j < n and arr[j] < arr[succ(j)] then
incr(j);
end if;
if help < arr[j] then
arr[k] := arr[j];
k := j;
end if;
until help >= arr[j] or k > n div 2;
arr[k] := help;
end if;
end func;
const proc: heapSort (inout array elemType: arr) is func
local
var integer: n is 0;
var integer: k is 0;
var elemType: help is elemType.value;
begin
n := length(arr);
for k range n div 2 downto 1 do
downheap(arr, k, n);
end for;
repeat
help := arr[1];
arr[1] := arr[n];
arr[n] := help;
decr(n);
downheap(arr, 1, n);
until n <= 1;
end func;
Original source: [1]
[edit] Tcl
Based on the algorithm from Wikipedia:
package require Tcl 8.5
proc heapsort {list {count ""}} {
if {$count eq ""} {
set count [llength $list]
}
for {set i [expr {$count/2 - 1}]} {$i >= 0} {incr i -1} {
siftDown list $i [expr {$count - 1}]
}
for {set i [expr {$count - 1}]} {$i > 0} {} {
swap list $i 0
incr i -1
siftDown list 0 $i
}
return $list
}
proc siftDown {varName i j} {
upvar 1 $varName a
while true {
set child [expr {$i*2 + 1}]
if {$child > $j} {
break
}
if {$child+1 <= $j && [lindex $a $child] < [lindex $a $child+1]} {
incr child
}
if {[lindex $a $i] >= [lindex $a $child]} {
break
}
swap a $i $child
set i $child
}
}
proc swap {varName x y} {
upvar 1 $varName a
set tmp [lindex $a $x]
lset a $x [lindex $a $y]
lset a $y $tmp
}
Demo code:
puts [heapsort {1 5 3 7 9 2 8 4 6 0}]
- Output:
0 1 2 3 4 5 6 7 8 9
[edit] TI-83 BASIC
Store list with a dimension of 7 or less into L1 (if less input will be padded with zeros), run prgmSORTHEAP, look into L2 for the sorted version of L1. It is possible to do this without L3 (thus, in place), but I coded this when I was paying attention to a math lecture. Could you make a better version that accepts any input, without having to use my clunky If structure? Could you make it in-place?
:If dim(L1)>7
:Then
:Disp "ERR:7"
:Stop
:End
:If dim(L1)<7
:Then
:For(A,1,7)
:If A>dim(L1)
:0→L1(A)
:End
:End
:{0}→L2
:For(B,2,7)
:0→L2(B)
:End
:L1→L3
:For(B,0,6)
:If L3(4)>L3(2)
:Then
:L3(2)→A
:L3(4)→L3(2)
:A→L3(4)
:End
:If L3(5)>L3(2)
:Then
:L3(2)→A
:L3(5)→L3(2)
:A→L3(5)
:End
:If L3(6)>L3(3)
:Then
:L3(3)→A
:L3(6)→L3(3)
:A→L3(6)
:End
:If L3(7)>L3(3)
:Then
:L3(3)→A
:L3(7)→L3(3)
:A→L3(7)
:End
:If L3(2)>L3(1)
:Then
:L3(1)→A
:L3(2)→L3(1)
:A→L3(2)
:End
:If L3(3)>L3(1)
:Then
:L3(1)→A
:L3(3)→L3(1)
:A→L3(3)
:End
:L3(1)→L2(7-B)
:If L3(2)>L3(3)
:Then
:L3(2)→L3(1)
:0→L3(2)
:Else
:L3(3)→L3(1)
:0→L3(3)
:End
:End
:DelVar A
:DelVar B
:DelVar L3
:Return
- Programming Tasks
- Sorting Algorithms
- WikipediaSourced
- ActionScript
- Ada
- AutoHotkey
- BBC BASIC
- BCPL
- C
- C++
- C sharp
- Clojure
- CoffeeScript
- Common Lisp
- D
- Dart
- E
- F Sharp
- Forth
- Fortran
- Go
- Groovy
- Haskell
- Icon
- Unicon
- J
- Java
- Liberty BASIC
- LotusScript
- M4
- Mathematica
- MATLAB
- Octave
- NetRexx
- Objeck
- OCaml
- Oz
- Pascal
- Perl
- Perl 6
- PicoLisp
- PureBasic
- Python
- REXX
- Ruby
- Scala
- Scheme
- Seed7
- Tcl
- TI-83 BASIC
- GUISS/Omit