Sorting algorithms/Insertion sort

An O(n^2) sorting algorithm which moves elements one at a time into the correct position. The algorithm is as follows (from the wikipedia):

Sorting algorithms/Insertion sort
You are encouraged to solve this task according to the task description, using any language you may know.

Sorting Algorithm
This is a sorting algorithm.   It may be applied to a set of data in order to sort it.     For comparing various sorts, see compare sorts.   For other sorting algorithms,   see sorting algorithms,   or:

O(n logn) sorts

Heap sort | Merge sort | Patience sort | Quick sort

O(n log²n) sorts
Shell Sort

O(n²) sorts
Bubble sort | Cocktail sort | Cocktail sort with shifting bounds | Comb sort | Cycle sort | Gnome sort | Insertion sort | Selection sort | Strand sort

other sorts
Bead sort | Bogo sort | Common sorted list | Composite structures sort | Custom comparator sort | Counting sort | Disjoint sublist sort | External sort | Jort sort | Lexicographical sort | Natural sorting | Order by pair comparisons | Order disjoint list items | Order two numerical lists | Object identifier (OID) sort | Pancake sort | Quickselect | Permutation sort | Radix sort | Ranking methods | Remove duplicate elements | Sleep sort | Stooge sort | [Sort letters of a string] | Three variable sort | Topological sort | Tree sort

insertionSort(array A)
        for i = 1 to length[A]-1 do
               value = A[i] 
               j = i-1
               while j >= 0 and A[j] > value do 
                        A[j + 1] = A[j]
                        j = j-1
               A[j+1] = value

Writing the algorithm for integers will suffice.

Java

public static void insertSort(int[] A){
	for(int i = 1; i < A.length; i++){
		int value = A[i];
		int j = i - 1;
		while(j >= 0 && A[j] > value){
			A[j + 1] = A[j];
			j = j - 1;
		}
		A[j + 1] = value;
	}
}

Python

def insertion_sort(l):
    for i in xrange(1, len(l)):
        j = i-1 
        key = l[i]
        while (l[j] > key) and (j >= 0):
           l[j+1] = l[j]
           j -= 1
        l[j+1] = key