Sorting algorithms/Bogosort

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Revision as of 02:13, 10 June 2008 by 64.238.49.65 (talk) (→‎{{header|Python}}: in_order alternative)
Task
Sorting algorithms/Bogosort
You are encouraged to solve this task according to the task description, using any language you may know.

Bogosort a list of numbers. Bogosort simply shuffles a collection until it is sorted.

Pseudocode:

while not InOrder(list) do Shuffle(list);

C++

The following algorithm actually works for all sequences of comparable types; restricting to lists of integers would not make the code simpler. <cpp>#include <iterator>

  1. include <algorithm>

template<typename ForwardIterator>

void bogosort(ForwardIterator begin, ForwardIterator end)

{

 typedef std::iterator_traits<ForwardIterator>::value_type value_type;
 // if we find two adjacent values where the first is greater than the second, the sequence isn't sorted.
 while (std::adjacent_find(begin, end, std::greater<value_type>()) != end)
   std::random_shuffle(begin, end);

}</cpp> Using the is_sorted function, part of the SGI STL implementation:

Works with: GCC

<cpp>#include <algorithm>

  1. include <ext/algorithm>

template<typename ForwardIterator>

void bogosort(ForwardIterator begin, ForwardIterator end)

{

 while (!__gnu_cxx::is_sorted(begin, end))
   std::random_shuffle(begin, end);

}</cpp>

D

<d>module bogosort ; import std.stdio, std.random ;

bool isSorted(T)(inout T[] a) { // test if a is already sorted

 if(a.length <= 1) return true ; // 1-elemented/empty array is defined as sorted
 for(int i = 1 ; i < a.length ; i++) if(a[i] < a[i-1]) return false ;
 return true ;

}

T[] bogosort(T)(T[] s) {

 while(!isSorted(s)) {
   for(int n = s.length ; n > 1 ; n--) { 
     int i = rand() % n ;        // random shuffling
     T tmp = s[i] ; s[i] = s[n - 1] ; s[n - 1] = tmp ;
   }
 }
 return s ;

}

void main() {

 auto b = [2,7,4,3] ;
 writefln("%s", bogosort(b)) ;
 writefln("%s", b) ;             // sort is in place
 

}</d>

J

bogo=: 3 : 0
whilst. -. *./ 2 </\ Ry  do. Ry=. (A.~ ?@!@#) y  end. Ry
)

Java

Works with: Java version 1.5+

This implementation works for all comparable types (types with compareTo defined). <java>import java.util.Collections; import java.util.List; import java.util.Iterator;

public class Bogosort {

   private static <T extends Comparable<? super T>> boolean isSorted(List<T> list) {
       if (list.isEmpty())
           return true;
       Iterator<T> it = list.iterator();
       T last = it.next();
       while (it.hasNext()) {
           T current = it.next();
           if (last.compareTo(current) > 0)
               return false;
           last = current;
       }
       return true;
   }
   public static <T extends Comparable<? super T>> void bogoSort(List<T> list) {
       while (!isSorted(list))
           Collections.shuffle(list);
   }

}</java>

Perl

<perl>sub bogosort

{my @l = @_;
 shuffle(\@l) until in_order(@l);
 return @l;}

sub in_order

{my $last = shift(@_);
 foreach (@_)
    {$_ >= $last or return 0;
     $last = $_;}
 return 1;}

sub shuffle

  1. This uses the algorithm described at:
  2. http://en.wikipedia.org/wiki/Fisher-Yates_shuffle#The_modern_algorithm
{our @l; local *l = shift;
   # @l is now an alias of the original argument.
 for (my $n = $#l ; $n ; --$n)
    {my $k = int rand($n + 1);
     @l[$k, $n] = @l[$n, $k] if $k != $n;}}</perl>

Python

<python>import random

def bogosort(l):

   while not in_order(l):
       random.shuffle(l)
   return l

def in_order(l):

   if not l:
       return True
   last = l[0]
   for x in l[1:]:
       if x < last:
           return False
       last = x
   return True</python>

Alternative definition for in_order (Python 2.5) <python>def in_order(l):

   return not l or all( l[i] < l[i+1] for i in range(0,len(l)-1))</python>