Number names
You are encouraged to solve this task according to the task description, using any language you may know.
Show how to spell out a number in English. You can use a preexisting implementation or roll your own, but you should support inputs up to at least one million (or the maximum value of your language's default bounded integer type, if that's less). Support for inputs other than positive integers (like zero, negative integers, and floating-point numbers) is optional.
Ada
<lang ada>with Ada.Text_IO;
procedure Integers_In_English is
type Spellable is range -999_999_999_999_999_999..999_999_999_999_999_999;
function Spell (N : Spellable) return String is
function Twenty (N : Spellable) return String is
begin
case N mod 20 is
when 0 => return "zero";
when 1 => return "one";
when 2 => return "two";
when 3 => return "three";
when 4 => return "four";
when 5 => return "five";
when 6 => return "six";
when 7 => return "seven";
when 8 => return "eight";
when 9 => return "nine";
when 10 => return "ten";
when 11 => return "eleven";
when 12 => return "twelve";
when 13 => return "thirteen";
when 14 => return "fourteen";
when 15 => return "fifteen";
when 16 => return "sixteen";
when 17 => return "seventeen";
when 18 => return "eighteen";
when others => return "nineteen";
end case;
end Twenty;
function Decade (N : Spellable) return String is
begin
case N mod 10 is
when 2 => return "twenty";
when 3 => return "thirty";
when 4 => return "forty";
when 5 => return "fifty";
when 6 => return "sixty";
when 7 => return "seventy";
when 8 => return "eighty";
when others => return "ninety";
end case;
end Decade;
function Hundred (N : Spellable) return String is
begin
if N < 20 then
return Twenty (N);
elsif 0 = N mod 10 then
return Decade (N / 10 mod 10);
else
return Decade (N / 10) & '-' & Twenty (N mod 10);
end if;
end Hundred;
function Thousand (N : Spellable) return String is
begin
if N < 100 then
return Hundred (N);
elsif 0 = N mod 100 then
return Twenty (N / 100) & " hundred";
else
return Twenty (N / 100) & " hundred and " & Hundred (N mod 100);
end if;
end Thousand;
function Triplet
( N : Spellable;
Order : Spellable;
Name : String;
Rest : not null access function (N : Spellable) return String
) return String is
High : Spellable := N / Order;
Low : Spellable := N mod Order;
begin
if High = 0 then
return Rest (Low);
elsif Low = 0 then
return Thousand (High) & ' ' & Name;
else
return Thousand (High) & ' ' & Name & ", " & Rest (Low);
end if;
end Triplet;
function Million (N : Spellable) return String is
begin
return Triplet (N, 10**3, "thousand", Thousand'Access);
end Million;
function Milliard (N : Spellable) return String is
begin
return Triplet (N, 10**6, "million", Million'Access);
end Milliard;
function Billion (N : Spellable) return String is
begin
return Triplet (N, 10**9, "milliard", Milliard'Access);
end Billion;
function Billiard (N : Spellable) return String is
begin
return Triplet (N, 10**12, "billion", Billion'Access);
end Billiard;
begin
if N < 0 then
return "negative " & Spell(-N);
else
return Triplet (N, 10**15, "billiard", Billiard'Access);
end if;
end Spell;
procedure Spell_And_Print(N: Spellable) is
Number: constant String := Spellable'Image(N);
Spaces: constant String(1 .. 20) := (others => ' '); -- 20 * ' '
begin
Ada.Text_IO.Put_Line(Spaces(Spaces'First .. Spaces'Last-Number'Length)
& Number & ' ' & Spell(N));
end Spell_And_Print;
Samples: constant array (Natural range <>) of Spellable
:= (99, 300, 310, 1_501, 12_609, 512_609, 43_112_609, 77_000_112_609,
2_000_000_000_100, 999_999_999_999_999_999,
0, -99, -1501, -77_000_112_609, -123_456_789_987_654_321);
begin
for I in Samples'Range loop
Spell_And_Print(Samples(I));
end loop;
end Integers_In_English;</lang> The implementation goes up to 1018-1 and also supports negative and zero inputs. The solution is recursive by the triplets of decimal numbers. Sample output:
99 ninety-nine
300 three hundred
310 three hundred and ten
1501 one thousand, five hundred and one
12609 twelve thousand, six hundred and nine
512609 five hundred and twelve thousand, six hundred and nine
43112609 forty-three million, one hundred and twelve thousand, six hundred and nine
77000112609 seventy-seven milliard, one hundred and twelve thousand, six hundred and nine
2000000000100 two billion, one hundred
999999999999999999 nine hundred and ninety-nine billiard, nine hundred and ninety-nine billion, nine hundred and ninety-nine milliard, nine hundred and ninety-nine million, nine hundred and ninety-nine thousand, nine hundred and ninety-nine
0 zero
-99 negative ninety-nine
-1501 negative one thousand, five hundred and one
-77000112609 negative seventy-seven milliard, one hundred and twelve thousand, six hundred and nine
-123456789987654321 negative one hundred and twenty-three billiard, four hundred and fifty-six billion, seven hundred and eighty-nine milliard, nine hundred and eighty-seven million, six hundred and fifty-four thousand, three hundred and twenty-one
ALGOL 68
<lang algol68>PROC number words = (INT n)STRING:(
# returns a string representation of n in words. Currently
deals with anything from 0 to 999 999 999. #
[]STRING digits = []STRING
("zero","one","two","three","four","five","six","seven","eight","nine")[@0];
[]STRING teens = []STRING
("ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen")[@0];
[]STRING decades = []STRING
("twenty","thirty","forty","fifty","sixty","seventy","eighty","ninety")[@2];
PROC three digits = (INT n)STRING: (
# does the conversion for n from 0 to 999. #
INT tens = n MOD 100 OVER 10;
INT units = n MOD 10;
(n >= 100|digits[n OVER 100] + " " + "hundred" + (n MOD 100 /= 0|" and "|"")|"") +
(tens /= 0|(tens = 1|teens[units]|decades[tens] + (units /= 0|"-"|""))|"") +
(units /= 0 AND tens /= 1 OR n = 0|digits[units]|"")
);
INT m = n OVER 1 000 000;
INT k = n MOD 1 000 000 OVER 1000;
INT u = n MOD 1000;
(m /= 0|three digits(m) + " million"|"") +
(m /= 0 AND (k /= 0 OR u >= 100)|", "|"") +
(k /= 0|three digits(k) + " thousand"|"") +
((m /= 0 OR k /= 0) AND u > 0 AND u < 100|" and " |: k /= 0 AND u /= 0|", "|"") +
(u /= 0 OR n = 0|three digits(u)|"")
);
on logical file end(stand in, (REF FILE f)BOOL: GOTO stop iteration); on value error(stand in, (REF FILE f)BOOL: GOTO stop iteration); DO # until user hits EOF #
INT n;
print("n? ");
read((n, new line));
print((number words(n), new line))
OD; stop iteration:
SKIP</lang>
Example input with output:
n? 43112609 forty-three million, one hundred and twelve thousand, six hundred and nine
<lang Algol68>MODE EXCEPTION = STRUCT(STRING name, PROC VOID handler); EXCEPTION value error = ("Value Error", stop);
PROC raise = (EXCEPTION exception, STRING str error)VOID: (
put(stand error, (name OF exception,": ",str error, new line)); handler OF exception
);
MODE LINT = LONG LONG INT;
BOOL locale euro := TRUE;
PROC spell integer = (LINT n)STRING: (
[]STRING tens = []STRING (~, ~, "twenty", "thirty", "forty",
"fifty", "sixty", "seventy", "eighty", "ninety")[@0];
[]STRING small = []STRING ("zero", "one", "two", "three", "four", "five",
"six", "seven", "eight", "nine", "ten", "eleven",
"twelve", "thirteen", "fourteen", "fifteen",
"sixteen", "seventeen", "eighteen", "nineteen")[@0];
[]STRING bl = []STRING (~, ~, "m", "b", "tr", "quadr",
"quint", "sext", "sept", "oct", "non", "dec")[@0];
PROC nonzero = (STRING c, LINT n)STRING:
IF n = 0 THEN "" ELSE c + spell integer(n) FI;
PROC big =(INT e, LINT n)STRING:
spell integer(n) +
CASE e+1 IN
#0# "",
#1# " thousand"
OUT
" " +
IF locale euro THEN # handle millard, billard & trillard etc #
bl[e OVER 2 + 1 ]+"ill" + CASE e MOD 2 IN "ard" OUT "ion" ESAC
ELSE
bl[e]+"illion"
FI
ESAC;
PROC base1000 rev = (LINT in n, PROC (INT,LINT)VOID yield)VOID: (
# generates the value of the digits of n in base 1000 #
# (i.e. 3-digit chunks), in reverse. #
LINT n := in n;
FOR e FROM 0 WHILE n /= 0 DO
LINT r = n MOD 1000;
n := n OVER 1000;
yield(e, r)
OD
);
IF n < 1000 THEN
INT ssn := SHORTEN SHORTEN n;
IF ssn < 0 THEN
raise (value error, "spell integer: negative input"); ~
ELIF ssn < 20 THEN
small[ssn]
ELIF ssn < 100 THEN
INT a = ssn OVER 10,
b = ssn MOD 10;
tens[a] + nonzero("-", b)
ELIF ssn < 1000 THEN
INT a = ssn OVER 100,
b = ssn MOD 100;
small[a] + " hundred" + ( b NE 0 | " and" | "") + nonzero(" ", b)
FI
ELSE
STRING out := "", sep:="";
# FOR e, x IN # base1000 rev(n, # DO #
(INT e, LINT x)VOID:
IF x NE 0 THEN
big(e,x) + sep +=: out;
sep := IF e = 0 AND x < 100 THEN " and " ELSE ", " FI
FI
)
# OD #;
out
FI
);
PROC example = (LINT n)VOID:
print((whole(n,0),": ", spell integer(n), new line));
- examples #
LINT prod := 0; FOR i TO 6 DO prod := prod * 10**i + i; example(prod) OD;
example(1278); example(1572); example(2010)</lang>Test output:
1: one 102: one hundred and two 102003: one hundred and two thousand and three 1020030004: one millard, twenty million, thirty thousand and four 102003000400005: one hundred and two billion, three millard, four hundred thousand and five 102003000400005000006: one hundred and two trillion, three billard, four hundred millard, five million and six 1278: one thousand, two hundred and seventy-eight 1572: one thousand, five hundred and seventy-two 2010: two thousand and ten
Applesoft BASIC
Handles zero and negative integers. Rounding errors occur with big numbers. <lang ApplesoftBASIC>10 INPUT "GIMME A NUMBER! "; N 20 GOSUB 100"NUMBER NAME 30 PRINT R$ 40 END
100 REMNUMBER NAME 110 IF R$ = "" THEN FOR I = 0 TO 10 : READ S$(I), T$(I), U$(I), V$(I) : NEXT 120 IF N = 0 THEN R$ = "ZERO" : RETURN 130 R$ = "" : D = 10 : C = 100 : M = 1E3 140 A = ABS(N) 150 FOR U = 0 TO D 160 H = A - C * INT(A / C) 170 IF H > 0 AND H < D THEN R$ = S$(H) + " " + R$ 180 IF H > 9 AND H < 20 THEN R$ = T$(H - D) + " " + R$ 190 IF H > 19 AND H < C THEN S = H - D * INT(H / D) : R$ = U$(INT(H / D)) + MID$("-",1+(S=0),1) + S$(S) + " " + R$ 200 H = A - M * INT(A / M) 210 H = INT (H / C) 220 IF H THEN R$ = S$(H) + " HUNDRED " + R$ 230 A = INT(A / M) 240 IF A > 0 THEN H = A - M * INT(A / M) : IF H THEN R$ = V$(U) + " " + R$ 250 IF A > 0 THEN NEXT U 260 IF N < 0 THEN R$ = "NEGATIVE " + R$ 270 RETURN
280 DATA "", "TEN", "", "THOUSAND" 281 DATA "ONE", "ELEVEN", "", "MILLION" 282 DATA "TWO", "TWELVE", "TWENTY", "BILLION" 283 DATA "THREE", "THIRTEEN", "THIRTY", "TRILLION" 284 DATA "FOUR", "FOURTEEN", "FORTY", "QUADRILLION" 285 DATA "FIVE", "FIFTEEN", "FIFTY", "QUINTILLION" 286 DATA "SIX", "SIXTEEN", "SIXTY", "SEXTILLION" 287 DATA "SEVEN", "SEVENTEEN", "SEVENTY", "SEPTILLION" 288 DATA "EIGHT", "EIGHTEEN", "EIGHTY", "OCTILLION" 289 DATA "NINE", "NINETEEN", "NINETY", "NONILLION" 290 DATA "", "", "", "DECILLION"</lang>
AutoHotkey
<lang autohotkey>Loop { ; TEST LOOP
n =
Random Digits, 1, 36 ; random number with up to 36 digits
Loop %Digits% {
Random Digit, 0, 9 ; can have leading 0s
n .= Digit
}
MsgBox 1, Number Names, % PrettyNumber(n) "`n`n" Spell(n) "`n`n"
IfMsgBox Cancel, Break
}
Spell(n) { ; recursive function to spell out the name of a max 36 digit integer, after leading 0s removed
Static p1=" thousand ",p2=" million ",p3=" billion ",p4=" trillion ",p5=" quadrillion ",p6=" quintillion "
, p7=" sextillion ",p8=" septillion ",p9=" octillion ",p10=" nonillion ",p11=" decillion "
, t2="twenty",t3="thirty",t4="forty",t5="fifty",t6="sixty",t7="seventy",t8="eighty",t9="ninety"
, o0="zero",o1="one",o2="two",o3="three",o4="four",o5="five",o6="six",o7="seven",o8="eight"
, o9="nine",o10="ten",o11="eleven",o12="twelve",o13="thirteen",o14="fourteen",o15="fifteen"
, o16="sixteen",o17="seventeen",o18="eighteen",o19="nineteen"
n :=RegExReplace(n,"^0+(\d)","$1") ; remove leading 0s from n
If (11 < d := (StrLen(n)-1)//3) ; #of digit groups of 3
Return "Number too big"
If (d) ; more than 3 digits
Return Spell(SubStr(n,1,-3*d)) p%d% ((s:=SubStr(n,1-3*d)) ? ", " Spell(s) : "")
i := SubStr(n,1,1)
If (n > 99) ; 3 digits
Return o%i% " hundred" ((s:=SubStr(n,2)) ? " and " Spell(s) : "")
If (n > 19) ; n = 20..99
Return t%i% ((o:=SubStr(n,2)) ? "-" o%o% : "")
Return o%n% ; n = 0..19
}
PrettyNumber(n) { ; inserts thousands separators into a number string
Return RegExReplace( RegExReplace(n,"^0+(\d)","$1"), "\G\d+?(?=(\d{3})+(?:\D|$))", "$0,")
}</lang>
AWK
<lang AWK>
- syntax: GAWK -f NUMBER_NAMES.AWK
BEGIN {
init_numtowords()
n = split("-10 0 .1 8 100 123 1001 99999 100000 9123456789 111000000111",arr," ")
for (i=1; i<=n; i++) {
printf("%s = %s\n",arr[i],numtowords(arr[i]))
}
exit(0)
}
- source: The AWK Programming Language, page 75
function numtowords(n, minus,str) {
if (n < 0) {
n = n * -1
minus = "minus "
}
if (n == 0) {
str = "zero"
}
else {
str = intowords(n)
}
gsub(/ /," ",str)
return(minus str)
} function intowords(n) {
n = int(n)
if (n >= 1000000000000) {
return intowords(n/1000000000000) " trillion " intowords(n%1000000000000)
}
if (n >= 1000000000) {
return intowords(n/1000000000) " billion " intowords(n%1000000000)
}
if (n >= 1000000) {
return intowords(n/1000000) " million " intowords(n%1000000)
}
if (n >= 1000) {
return intowords(n/1000) " thousand " intowords(n%1000)
}
if (n >= 100) {
return intowords(n/100) " hundred " intowords(n%100)
}
if (n >= 20) {
return tens[int(n/10)] " " intowords(n%10)
}
return(nums[n])
} function init_numtowords() {
split("one two three four five six seven eight nine ten eleven twelve thirteen fourteen fifteen sixteen seventeen eighteen nineteen",nums," ")
split("ten twenty thirty forty fifty sixty seventy eighty ninety",tens," ")
} </lang>
output:
-10 = minus ten 0 = zero .1 = 8 = eight 100 = one hundred 123 = one hundred twenty three 1001 = one thousand one 99999 = ninety nine thousand nine hundred ninety nine 100000 = one hundred thousand 9123456789 = nine billion one hundred twenty three million four hundred fifty six thousand seven hundred eighty nine 111000000111 = one hundred eleven billion one hundred eleven
BASIC
<lang qbasic>DECLARE FUNCTION int2Text$ (number AS LONG)
'small DATA "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten" DATA "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen" 'tens DATA "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety" 'big DATA "thousand", "million", "billion"
DIM SHARED small(1 TO 19) AS STRING, tens(7) AS STRING, big(2) AS STRING
DIM tmpInt AS INTEGER
FOR tmpInt = 1 TO 19
READ small(tmpInt)
NEXT FOR tmpInt = 0 TO 7
READ tens(tmpInt)
NEXT FOR tmpInt = 0 TO 2
READ big(tmpInt)
NEXT
DIM n AS LONG
INPUT "Gimme a number! ", n PRINT int2Text$(n)
FUNCTION int2Text$ (number AS LONG)
DIM num AS LONG, outP AS STRING, unit AS INTEGER DIM tmpLng1 AS LONG
IF 0 = number THEN
int2Text$ = "zero"
EXIT FUNCTION
END IF
num = ABS(number)
DO
tmpLng1 = num MOD 100
SELECT CASE tmpLng1
CASE 1 TO 19
outP = small(tmpLng1) + " " + outP
CASE 20 TO 99
SELECT CASE tmpLng1 MOD 10
CASE 0
outP = tens((tmpLng1 \ 10) - 2) + " " + outP
CASE ELSE
outP = tens((tmpLng1 \ 10) - 2) + "-" + small(tmpLng1 MOD 10) + " " + outP
END SELECT
END SELECT
tmpLng1 = (num MOD 1000) \ 100
IF tmpLng1 THEN
outP = small(tmpLng1) + " hundred " + outP
END IF
num = num \ 1000
IF num < 1 THEN EXIT DO
tmpLng1 = num MOD 1000
IF tmpLng1 THEN outP = big(unit) + " " + outP
unit = unit + 1 LOOP
IF number < 0 THEN outP = "negative " + outP
int2Text$ = RTRIM$(outP)
END FUNCTION</lang>
Sample outputs (including the answer to the ultimate question of life, the universe, and everything):
Gimme a number! 1 one Gimme a number! 0 zero Gimme a number! -1 negative one Gimme a number! 42 forty-two Gimme a number! 1000000 one million Gimme a number! 1000000001 one billion one Gimme a number! &h7fffffff two billion one hundred forty-seven million four hundred eighty-three thousand six hundred forty-seven
BBC BASIC
<lang bbcbasic> DIM test%(20)
test%() = 0, 1, 2, 19, 20, 21, 99, 100, 101, 300, 310, 1001, -1327, 1501, \
\ 10203, 12609, 101104, 102003, 467889, 1005006, -123000789
FOR i% = 0 TO DIM(test%(),1)
PRINT FNsaynumber(test%(i%))
NEXT
END
DEF FNsaynumber(n%)
LOCAL number%(), number$(), i%, t%, a$
DIM number%(29), number$(29)
number%() = 1000000000, 1000000, 1000, 100, 90, 80, 70, 60, 50, 40, 30, 20, \
\ 19, 18, 17, 16, 15, 14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2
number$() = "billion", "million", "thousand", "hundred", "ninety", "eighty", \
\ "seventy", "sixty", "fifty", "forty", "thirty", "twenty", \
\ "nineteen", "eighteen", "seventeen", "sixteen", "fifteen", \
\ "fourteen", "thirteen", "twelve", "eleven", "ten", "nine", \
\ "eight", "seven", "six", "five", "four", "three", "two"
IF n% < 0 THEN = "minus " + FNsaynumber(-n%)
IF n% = 0 THEN = "zero"
IF n% = 1 THEN = "one "
FOR i% = 0 TO DIM(number%(),1)
IF n% >= number%(i%) THEN
t% = n% DIV number%(i%)
IF t%=1 AND i%<4 a$ += "one " ELSE IF t%<>1 a$ += FNsaynumber(t%)
a$ += number$(i%)
t% = n% MOD number%(i%)
CASE TRUE OF
WHEN i%>3 AND i%<12 AND t%<>0: a$ += "-"
WHEN i%<=3 AND t%>=100: a$ += ", "
WHEN i%<=3 AND t%<>0 AND t%<100: a$ += " and "
OTHERWISE: a$ += " "
ENDCASE
IF t% a$ += FNsaynumber(t%) ELSE IF i%<12 a$ += " "
EXIT FOR
ENDIF
NEXT i%
= a$</lang>
Output:
zero one two nineteen twenty twenty-one ninety-nine one hundred one hundred and one three hundred three hundred and ten one thousand and one minus one thousand, three hundred and twenty-seven one thousand, five hundred and one ten thousand, two hundred and three twelve thousand, six hundred and nine one hundred and one thousand, one hundred and four one hundred and two thousand and three four hundred and sixty-seven thousand, eight hundred and eighty-nine one million, five thousand and six minus one hundred and twenty-three million, seven hundred and eighty-nine
BlitzMax
<lang BlitzMax>SuperStrict
Framework BRL.StandardIO
spellIt( 99) spellIt( 300) spellIt( 310) spellIt( 1501) spellIt( 12609) spellIt( 512609) spellIt( 43112609) spellIt(1234567890)
Type TSpell
Field smallNumbers:String[] = ["zero", "one", "two", "three", "four", "five", .. "six", "seven", "eight", "nine", "ten", .. "eleven", "twelve", "thirteen", "fourteen", "fifteen", .. "sixteen", "seventeen", "eighteen", "nineteen" ]
Field decades:String[] = [ "", "", "twenty", "thirty", "forty", .. "fifty", "sixty", "seventy", "eighty", "ninety" ]
Field thousandPowers:String[] = [ " billion", " million", " thousand", "" ]
Method spellHundreds:String(number:Int) Local result:String If number > 99 Then result = smallNumbers[number / 100] result :+ " hundred" number = number Mod 100 If number Then result :+ " and " End If End If
If number >= 20 Then result :+ decades[number / 10] number = number Mod 10 If number Then result :+ "-" End If End If If number > 0 And number < 20 Then result :+ smallNumbers[number] End If
Return result End Method
Method spell:String(number:Long) If number < 20 Then Return smallNumbers[number] End If Local result:String
Local scaleIndex:Int = 0 Local scaleFactor:Long = 1000000000:Long ' 1 billion While scaleFactor > 0 If number >= scaleFactor Local h:Long = number / scaleFactor result :+ spellHundreds(h) + thousandPowers[scaleIndex] number = number Mod scaleFactor If number Then result :+ ", " End If End If scaleFactor :/ 1000 scaleIndex :+ 1 Wend
Return result End Method
End Type
Function spellIt(number:Long) Local numberSpell:TSpell = New TSpell Print number + " " + numberSpell.spell(number) End Function</lang>
99 ninety-nine 300 three hundred 310 three hundred and ten 1501 one thousand, five hundred and one 12609 twelve thousand, six hundred and nine 512609 five hundred and twelve thousand, six hundred and nine 43112609 forty-three million, one hundred and twelve thousand, six hundred and nine 1234567890 one billion, two hundred and thirty-four million, five hundred and sixty-seven thousand, eight hundred and ninety
C
<lang c>#include <stdio.h>
- include <string.h>
const char *ones[] = { 0, "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen" }; const char *tens[] = { 0, "ten", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety" }; const char *llions[] = { 0, "thousand", "million", "billion", "trillion", // "quadrillion", "quintillion", "sextillion", "septillion", // "octillion", "nonillion", "decillion" }; const int maxillion = sizeof(llions) / sizeof(llions[0]) * 3 - 3;
int say_hundred(const char *s, int len, int depth, int has_lead) { int c[3], i; for (i = -3; i < 0; i++) { if (len + i >= 0) c[i + 3] = s[len + i] - '0'; else c[i + 3] = 0; } if (!(c[0] + c[1] + c[2])) return 0;
if (c[0]) { printf("%s hundred", ones[c[0]]); has_lead = 1; }
if (has_lead && (c[1] || c[2])) printf((!depth || c[0]) && (!c[0] || !c[1]) ? "and " : c[0] ? " " : "");
if (c[1] < 2) { if (c[1] || c[2]) printf("%s", ones[c[1] * 10 + c[2]]); } else { if (c[1]) { printf("%s", tens[c[1]]); if (c[2]) putchar('-'); } if (c[2]) printf("%s", ones[c[2]]); }
return 1; }
int say_maxillion(const char *s, int len, int depth, int has_lead) { int n = len / 3, r = len % 3; if (!r) { n--; r = 3; } const char *e = s + r; do { if (say_hundred(s, r, n, has_lead) && n) { has_lead = 1; printf(" %s", llions[n]); if (!depth) printf(", "); else printf(" "); } s = e; e += 3; } while (r = 3, n--);
return 1; }
void say_number(const char *s) { int len, i, got_sign = 0;
while (*s == ' ') s++; if (*s < '0' || *s > '9') { if (*s == '-') got_sign = -1; else if (*s == '+') got_sign = 1; else goto nan; s++; } else got_sign = 1;
while (*s == '0') { s++; if (*s == '\0') { printf("zero\n"); return; } }
len = strlen(s); if (!len) goto nan;
for (i = 0; i < len; i++) { if (s[i] < '0' || s[i] > '9') { printf("(not a number)"); return; } } if (got_sign == -1) printf("minus ");
int n = len / maxillion; int r = len % maxillion; if (!r) { r = maxillion; n--; }
const char *end = s + len - n * maxillion; int has_lead = 0; do { if ((has_lead = say_maxillion(s, r, n, has_lead))) { for (i = 0; i < n; i++) printf(" %s", llions[maxillion / 3]); if (n) printf(", "); } n--; r = maxillion; s = end; end += r; } while (n >= 0);
printf("\n"); return;
nan: printf("not a number\n"); return; }
int main() { say_number("-42"); say_number("1984"); say_number("10000"); say_number("1024"); say_number("1001001001001"); say_number("123456789012345678901234567890123456789012345678900000001"); return 0; }</lang>output
minus forty-two one thousand, nine hundred eighty-four ten thousand, one thousand, and twenty-four one trillion, one billion, one million, one thousand, and one one hundred twenty-three million four hundred fifty-six thousand seven hundred eighty-nine trillion trillion trillion trillion, twelve billion three hundred forty-five million six hundred seventy-eight thousand nine hundredand one trillion trillion trillion, two hundred thirty-four billion five hundred sixty-seven million eight hundred ninety thousand one hundred twenty-three trillion trillion, four hundred fifty-six billion seven hundred eighty-nine million twelve thousand three hundred forty-five trillion, six hundred seventy-eight billion, nine hundred million, and one
C++
<lang cpp>#include <string>
- include <iostream>
using std::string;
const char* smallNumbers[] = {
"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"
};
string spellHundreds(unsigned n) {
string res;
if (n > 99) {
res = smallNumbers[n/100];
res += " hundred";
n %= 100;
if (n) res += " and ";
}
if (n >= 20) {
static const char* Decades[] = {
"", "", "twenty", "thirty", "forty",
"fifty", "sixty", "seventy", "eighty", "ninety"
};
res += Decades[n/10];
n %= 10;
if (n) res += "-";
}
if (n < 20 && n > 0)
res += smallNumbers[n];
return res;
}
const char* thousandPowers[] = {
" billion", " million", " thousand", "" };
typedef unsigned long Spellable;
string spell(Spellable n) {
if (n < 20) return smallNumbers[n];
string res;
const char** pScaleName = thousandPowers;
Spellable scaleFactor = 1000000000; // 1 billion
while (scaleFactor > 0) {
if (n >= scaleFactor) {
Spellable h = n / scaleFactor;
res += spellHundreds(h) + *pScaleName;
n %= scaleFactor;
if (n) res += ", ";
}
scaleFactor /= 1000;
++pScaleName;
}
return res;
}
int main() {
- define SPELL_IT(x) std::cout << #x " " << spell(x) << std::endl;
SPELL_IT( 99); SPELL_IT( 300); SPELL_IT( 310); SPELL_IT( 1501); SPELL_IT( 12609); SPELL_IT( 512609); SPELL_IT(43112609); SPELL_IT(1234567890); return 0;
}</lang> Sample output:
99 ninety-nine 300 three hundred 310 three hundred and ten 1501 one thousand, five hundred and one 12609 twelve thousand, six hundred and nine 512609 five hundred and twelve thousand, six hundred and nine 43112609 forty-three million, one hundred and twelve thousand, six hundred and nine 1234567890 one billion, two hundred and thirty-four million, five hundred and sixty-seven thousand, eight hundred and ninety
C#
<lang csharp>using System;
class NumberNamer {
static readonly string[] incrementsOfOne =
{ "zero", "one", "two", "three", "four",
"five", "six", "seven", "eight", "nine",
"ten", "eleven", "twelve", "thirteen", "fourteen",
"fifteen", "sixteen", "seventeen", "eighteen", "nineteen" };
static readonly string[] incrementsOfTen =
{ "", "", "twenty", "thirty", "fourty",
"fifty", "sixty", "seventy", "eighty", "ninety" };
const string millionName = "million",
thousandName = "thousand",
hundredName = "hundred",
andName = "and";
public static string GetName( int i ) {
string output = "";
if( i >= 1000000 ) {
output += ParseTriplet( i / 1000000 ) + " " + millionName;
i %= 1000000;
if( i == 0 ) return output;
}
if( i >= 1000 ) {
if( output.Length > 0 ) {
output += ", ";
}
output += ParseTriplet( i / 1000 ) + " " + thousandName;
i %= 1000;
if( i == 0 ) return output;
}
if( output.Length > 0 ) {
output += ", ";
}
output += ParseTriplet( i );
return output;
}
static string ParseTriplet( int i ) {
string output = "";
if( i >= 100 ) {
output += incrementsOfOne[i / 100] + " " + hundredName;
i %= 100;
if( i == 0 ) return output;
}
if( output.Length > 0 ) {
output += " " + andName + " ";
}
if( i >= 20 ) {
output += incrementsOfTen[i / 10];
i %= 10;
if( i == 0 ) return output;
}
if( output.Length > 0 ) {
output += " ";
}
output += incrementsOfOne[i];
return output;
}
}
class Program { // Test class
static void Main( string[] args ) {
Console.WriteLine( NumberNamer.GetName( 1 ) );
Console.WriteLine( NumberNamer.GetName( 234 ) );
Console.WriteLine( NumberNamer.GetName( 31337 ) );
Console.WriteLine( NumberNamer.GetName( 987654321 ) );
}
} /* Sample output: one two hundred and thirty four thirty one thousand, three hundred and thirty seven nine hundred and eighty seven million, six hundred and fifty four thousand, three hundred and twenty one
- /</lang>
Clojure
<lang clojure>(clojure.pprint/cl-format nil "~R" 1234) => "one thousand, two hundred thirty-four"</lang>
CoffeeScript
<lang coffeescript> spell_integer = (n) ->
tens = [null, null, "twenty", "thirty", "forty",
"fifty", "sixty", "seventy", "eighty", "ninety"]
small = ["zero", "one", "two", "three", "four", "five",
"six", "seven", "eight", "nine", "ten", "eleven",
"twelve", "thirteen", "fourteen", "fifteen",
"sixteen", "seventeen", "eighteen", "nineteen"]
bl = [null, null, "m", "b", "tr", "quadr",
"quint", "sext", "sept", "oct", "non", "dec"]
divmod = (n, d) ->
[Math.floor(n / d), n % d]
nonzero = (c, n) ->
if n == 0
""
else
c + spell_integer n
big = (e, n) ->
if e == 0
spell_integer n
else if e == 1
spell_integer(n) + " thousand"
else
spell_integer(n) + " " + bl[e] + "illion"
base1000_rev = (n) ->
# generates the value of the digits of n in base 1000
# (i.e. 3-digit chunks), in reverse.
chunks = []
while n != 0
[n, r] = divmod n, 1000
chunks.push r
chunks
if n < 0
throw Error "spell_integer: negative input"
else if n < 20
small[n]
else if n < 100
[a, b] = divmod n, 10
tens[a] + nonzero("-", b)
else if n < 1000
[a, b] = divmod n, 100
small[a] + " hundred" + nonzero(" ", b)
else
chunks = (big(exp, x) for x, exp in base1000_rev(n) when x)
chunks.reverse().join ', '
- example
console.log spell_integer 1278 console.log spell_integer 1752 console.log spell_integer 2010 console.log spell_integer 4000123007913 </lang>
output <lang> > coffee spell_number.coffee one thousand, two hundred seventy-eight one thousand, seven hundred fifty-two two thousand, ten four trillion, one hundred twenty-three million, seven thousand, nine hundred thirteen </lang>
Common Lisp
<lang lisp>(format nil "~R" 1234) => "one thousand two hundred thirty-four"</lang>
D
<lang d>import std.stdio, std.array, std.algorithm, std.bigint, std.range;
immutable tens = ["", "", "twenty", "thirty", "forty",
"fifty", "sixty", "seventy", "eighty", "ninety"];
immutable small = ["zero", "one", "two", "three", "four", "five",
"six", "seven", "eight", "nine", "ten", "eleven",
"twelve", "thirteen", "fourteen", "fifteen",
"sixteen", "seventeen", "eighteen", "nineteen"];
immutable huge = ["", ""] ~ ["m", "b", "tr", "quadr", "quint",
"sext", "sept", "oct", "non", "dec"]
.map!q{ a ~ "illion" }.array;
string spellBigInt(BigInt n) {
static string nonZero(string c, BigInt n, string connect="") {
return n == 0 ? "" : connect ~ c ~ n.spellBigInt;
}
static string lastAnd(string num) {
if (num.canFind(",")) {
string pre = num.retro.find(",").retro[0 .. $ - 1];
string last = num[pre.length + 1 .. $];
if (!last.canFind(" and "))
last = " and" ~ last;
num = pre ~ "," ~ last;
}
return num;
}
static string big(in uint e, BigInt n) {
switch (e) {
case 0: return n.spellBigInt;
case 1: return n.spellBigInt ~ " thousand";
default: return n.spellBigInt ~ " " ~ huge[e];
}
}
if (n < 0) {
return "minus " ~ spellBigInt(-n);
} else if (n < 20) {
return small[n.toInt];
} else if (n < 100) {
BigInt a = n / 10;
BigInt b = n % 10;
return tens[a.toInt] ~ nonZero("-", b);
} else if (n < 1000) {
BigInt a = n / 100;
BigInt b = n % 100;
return small[a.toInt] ~ " hundred" ~ nonZero(" ", b, " and");
} else {
string[] bigs;
uint e = 0;
while (n != 0) {
BigInt r = n % 1000;
n /= 1000;
if (r != 0)
bigs ~= big(e, r);
e++;
}
return lastAnd(bigs.retro.join(", "));
}
}
version(number_names_main) {
void main() {
foreach (n; [0, -3, 5, -7, 11, -13, 17, -19, 23, -29])
writefln("%+4d -> %s", n, n.BigInt.spellBigInt);
writeln;
auto n = 2_0121_002_001;
while (n) {
writefln("%-12d -> %s", n, n.BigInt.spellBigInt);
n /= -10;
}
writefln("%-12d -> %s", n, n.BigInt.spellBigInt);
writeln;
}
}</lang>
- Output:
+0 -> zero -3 -> minus three +5 -> five -7 -> minus seven +11 -> eleven -13 -> minus thirteen +17 -> seventeen -19 -> minus nineteen +23 -> twenty-three -29 -> minus twenty-nine 20121002001 -> twenty billion, one hundred and twenty-one million, two thousand, and one -2012100200 -> minus two billion, twelve million, one hundred thousand, and two hundred 201210020 -> two hundred and one million, two hundred and ten thousand, and twenty -20121002 -> minus twenty million, one hundred and twenty-one thousand, and two 2012100 -> two million, twelve thousand, and one hundred -201210 -> minus two hundred and one thousand, two hundred and ten 20121 -> twenty thousand, one hundred and twenty-one -2012 -> minus two thousand, and twelve 201 -> two hundred and one -20 -> minus twenty 2 -> two 0 -> zero
Euphoria
<lang euphoria>function abs(atom i)
if i < 0 then
return -i
else
return i
end if
end function
constant small = {"one", "two", "three", "four", "five", "six", "seven", "eight",
"nine", "ten","eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"}
constant tens = {"twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty",
"ninety"}
constant big = {"thousand", "million", "billion"}
function int2text(atom number)
atom num
integer unit, tmpLng1
sequence outP
outP = ""
num = 0
unit = 1
tmpLng1 = 0
if number = 0 then
return "zero"
end if
num = abs(number)
while 1 do
tmpLng1 = remainder(num,100)
if tmpLng1 > 0 and tmpLng1 < 20 then
outP = small[tmpLng1] & ' ' & outP
elsif tmpLng1 >= 20 then
if remainder(tmpLng1,10) = 0 then
outP = tens[floor(tmpLng1/10)-1] & ' ' & outP
else
outP = tens[floor(tmpLng1/10)-1] & '-' & small[remainder(tmpLng1, 10)] & ' ' & outP
end if
end if
tmpLng1 = floor(remainder(num, 1000) / 100)
if tmpLng1 then
outP = small[tmpLng1] & " hundred " & outP
end if
num = floor(num/1000)
if num < 1 then
exit
end if
tmpLng1 = remainder(num,1000)
if tmpLng1 then
outP = big[unit] & ' ' & outP
end if
unit = unit + 1
end while
if number < 0 then
outP = "negative " & outP
end if
return outP[1..$-1]
end function
puts(1,int2text(900000001) & "\n") puts(1,int2text(1234567890) & "\n") puts(1,int2text(-987654321) & "\n") puts(1,int2text(0) & "\n")</lang>
Output:
nine hundred million one one billion two hundred thirty-four million five hundred sixty-seven thousand eight hundred ninety negative nine hundred eighty-seven million six hundred fifty-four thousand three hundred twenty-one zero
Factor
Factor "cheats" by having a standard library module for this task:
<lang factor>IN: scratchpad USE: math.text.english IN: scratchpad 43112609 number>text print forty-three million, one hundred and twelve thousand, six hundred and nine </lang>
Fortran
<lang fortran>program spell
implicit none integer :: e integer :: i integer :: m integer :: n character (9), dimension (19), parameter :: small = & & (/'one ', 'two ', 'three ', 'four ', & & 'five ', 'six ', 'seven ', 'eight ', & & 'nine ', 'ten ', 'eleven ', 'twelve ', & & 'thirteen ', 'fourteen ', 'fifteen ', 'sixteen ', & & 'seventeen', 'eighteen ', 'nineteen '/) character (7), dimension (2 : 9), parameter :: tens = & & (/'twenty ', 'thirty ', 'forty ', 'fifty ', 'sixty ', & & 'seventy', 'eighty ', 'ninety '/) character (8), dimension (3), parameter :: big = & & (/'thousand', 'million ', 'billion '/) character (256) :: r
do
read (*, *, iostat = i) n
if (i /= 0) then
exit
end if
if (n == 0) then
r = 'zero'
else
r =
m = abs (n)
e = 0
do
if (m == 0) then
exit
end if
if (modulo (m, 1000) > 0) then
if (e > 0) then
r = trim (big (e)) // ' ' // r
end if
if (modulo (m, 100) > 0) then
if (modulo (m, 100) < 20) then
r = trim (small (modulo (m, 100))) // ' ' // r
else
if (modulo (m, 10) > 0) then
r = trim (small (modulo (m, 10))) // ' ' // r
r = trim (tens (modulo (m, 100) / 10)) // '-' // r
else
r = trim (tens (modulo (m, 100) / 10)) // ' ' // r
end if
end if
end if
if (modulo (m, 1000) / 100 > 0) then
r = 'hundred' // ' ' // r
r = trim (small (modulo (m, 1000) / 100)) // ' ' // r
end if
end if
m = m / 1000
e = e + 1
end do
if (n < 0) then
r = 'negative' // ' ' // r
end if
end if
write (*, '(a)') trim (r)
end do
end program spell</lang> Sample input:
-1 0 1 42 2147483647
Output:
negative one zero one forty-two two billion one hundred forty-seven million four hundred eighty-three thousand six hundred forty-seven
Go
Positive integers, to MaxInt64 <lang go>package main
import "fmt"
func main() {
for _, n := range []int64{12, 1048576, 9e18} {
fmt.Println(say(n))
}
}
var small = []string{"", "one", "two", "three", "four", "five", "six",
"seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"}
var tens = []string{"ones", "ten", "twenty", "thirty", "forty",
"fifty", "sixty", "seventy", "eighty", "ninety"}
var illions = []string{"thousand", "million", "billion",
"trillion", "quadrillion", "quintillion"}
func say(n int64) string {
switch {
case n < 1:
case n < 20:
return small[n]
case n < 100:
t := tens[n/10]
s := n % 10
if s > 0 {
t += " " + small[s]
}
return t
case n < 1000:
h := small[n/100] + " hundred"
s := n % 100
if s > 0 {
h += " " + say(s)
}
return h
default:
sx := say(n % 1000)
for i := 0; n >= 1000; i++ {
n /= 1000
p := n % 1000
if p > 0 {
ix := say(p) + " " + illions[i]
if sx > "" {
ix += " " + sx
}
sx = ix
}
}
return sx
}
return ""
}</lang> Output:
twelve one million forty eight thousand five hundred seventy six nine quintillion
Groovy
<lang groovy>def divMod(BigInteger number, BigInteger divisor) {
def qr = number.divideAndRemainder(divisor) [div:qr[0], remainder:qr[1]]
}
def toText(value) {
value = value as BigInteger
def units = ['zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine', 'ten',
'eleven', 'twelve', 'thirteen', 'fourteen', 'fifteen', 'sixteen', 'seventeen', 'eighteen', 'nineteen']
def tens = [, , 'twenty', 'thirty', 'forty', 'fifty', 'sixty', 'seventy', 'eighty', 'ninety']
def big = [, 'thousand'] + ['m', 'b', 'tr', 'quadr', 'quint', 'sext', 'sept', 'oct', 'non', 'dec'].collect { "${it}illion"}
if (value < 0) {
"negative ${toText(-value)}"
} else if (value < 20) {
units[value]
} else if (value < 100) {
divMod(value, 10).with { "${tens[div]} ${units[remainder]}".replace(' zero', ) }
} else if (value < 1000) {
divMod(value, 100).with { "${toText(div)} hundred and ${toText(remainder)}".replace(' and zero', ) }
} else {
def chunks = []
while (value != 0) {
divMod(value, 1000).with {
chunks << remainder
value = div
}
}
if (chunks.size() > big.size()) {
throw new IllegalArgumentException("Number overflow")
}
def text = []
(0..<chunks.size()).each { index ->
if (chunks[index] > 0) {
text << "${toText(chunks[index])}${index == 0 ? : ' ' + big[index]}"
if (index == 0 && chunks[index] < 100) {
text << "and"
}
}
}
text.reverse().join(', ').replace(', and,', ' and')
}
}
// Add this method to all Numbers Number.metaClass.toText = { toText(delegate) }
println toText(29) println 40.toText() println toText(401) println 9003.toText() println toText(8011673) println 8000100.toText() println 4629436.toText() 948623487512387455323784623842314234.toText().split(',').each { println it.trim() }
def verifyToText(expected, value) {
println "Checking '$expected' == $value" def actual = value.toText() assert expected == actual
}
verifyToText 'nineteen', 19 verifyToText 'one thousand, two hundred and thirty four', 1234 verifyToText 'twenty three million, four hundred and fifty nine thousand, six hundred and twelve', 23459612 verifyToText 'one thousand, nine hundred and ninety nine', 1999 verifyToText 'negative six hundred and one', -601 verifyToText 'twelve billion and nineteen', 12000000019 verifyToText 'negative one billion, two hundred and thirty four million, five hundred and sixty seven thousand, eight hundred and ninety', -1234567890 verifyToText 'one hundred and one', 101 verifyToText 'one thousand and one', 1001 verifyToText 'one million, one hundred and one', 1000101 verifyToText 'one million and forty five', 1000045 verifyToText 'one million and fifteen', 1000015 verifyToText 'one billion, forty five thousand and one', 1000045001</lang> Output:
twenty nine forty four hundred and one nine thousand and three eight million, eleven thousand, six hundred and seventy three eight million, one hundred four million, six hundred and twenty nine thousand, four hundred and thirty six nine hundred and forty eight decillion six hundred and twenty three nonillion four hundred and eighty seven octillion five hundred and twelve septillion three hundred and eighty seven sextillion four hundred and fifty five quintillion three hundred and twenty three quadrillion seven hundred and eighty four trillion six hundred and twenty three billion eight hundred and forty two million three hundred and fourteen thousand two hundred and thirty four Checking 'nineteen' == 19 Checking 'one thousand, two hundred and thirty four' == 1234 Checking 'twenty three million, four hundred and fifty nine thousand, six hundred and twelve' == 23459612 Checking 'one thousand, nine hundred and ninety nine' == 1999 Checking 'negative six hundred and one' == -601 Checking 'twelve billion and nineteen' == 12000000019 Checking 'negative one billion, two hundred and thirty four million, five hundred and sixty seven thousand, eight hundred and ninety' == -1234567890 Checking 'one hundred and one' == 101 Checking 'one thousand and one' == 1001 Checking 'one million, one hundred and one' == 1000101 Checking 'one million and forty five' == 1000045 Checking 'one million and fifteen' == 1000015 Checking 'one billion, forty five thousand and one' == 1000045001
Haskell
<lang haskell>import Data.List (intercalate, unfoldr)
spellInteger :: Integer -> String spellInteger n
| n < 0 = "negative " ++ spellInteger (-n)
| n < 20 = small n
| n < 100 = let (a, b) = n `divMod` 10
in tens a ++ nonzero '-' b
| n < 1000 = let (a, b) = n `divMod` 100
in small a ++ " hundred" ++ nonzero ' ' b
| otherwise = intercalate ", " $ map big $ reverse $
filter ((/= 0) . snd) $ zip [0..] $ unfoldr uff n
where nonzero :: Char -> Integer -> String
nonzero _ 0 = ""
nonzero c n = c : spellInteger n
uff :: Integer -> Maybe (Integer, Integer)
uff 0 = Nothing
uff n = Just $ uncurry (flip (,)) $ n `divMod` 1000
small, tens :: Integer -> String
small = (["zero", "one", "two", "three", "four", "five",
"six", "seven", "eight", "nine", "ten", "eleven",
"twelve", "thirteen", "fourteen", "fifteen", "sixteen",
"seventeen", "eighteen", "nineteen"] !!) . fromEnum
tens = ([undefined, undefined, "twenty", "thirty", "forty",
"fifty", "sixty", "seventy", "eighty", "ninety"] !!) .
fromEnum
big :: (Int, Integer) -> String
big (0, n) = spellInteger n
big (1, n) = spellInteger n ++ " thousand"
big (e, n) = spellInteger n ++ ' ' : (l !! e) ++ "illion"
where l = [undefined, undefined, "m", "b", "tr", "quadr",
"quint", "sext", "sept", "oct", "non", "dec"]</lang>
HicEst
<lang HicEst>SUBROUTINE NumberToWords(number)
CHARACTER outP*255, small*130, tens*80, big*80
REAL :: decimal_places = 7
INIT( APPENDIX("#literals"), small, tens, big)
num = ABS( INT(number) )
order = 0
outP = ' '
DO i = 1, num + 1
tmp = MOD(num, 100)
IF(tmp > 19) THEN
EDIT(Text=tens, ITeM=INT(MOD(tmp/10, 10)), Parse=medium)
IF( MOD(tmp, 10) ) THEN
EDIT(Text=small, ITeM=MOD(tmp,10)+1, Parse=mini)
outP = medium // '-' // mini // ' ' // outP
ELSE
outP = medium // ' ' // outP
ENDIF
ELSEIF(tmp > 0) THEN
EDIT(Text=small, ITeM=tmp+1, Parse=mini)
outP = mini // ' '// outP
ELSEIF(number == 0) THEN
outP = 'zero'
ENDIF
tmp = INT(MOD(num, 1000) / 100)
IF(tmp) THEN
EDIT(Text=small, ITeM=tmp+1, Parse=oneto19)
outP = oneto19 // ' hundred ' // outP
ENDIF
num = INT(num /1000)
IF( num == 0) THEN
IF(number < 0) outP = 'minus ' // outP
fraction = ABS( MOD(number, 1) )
IF(fraction) WRITE(Text=outP, APPend) ' point'
DO j = 1, decimal_places
IF( fraction >= 10^(-decimal_places) ) THEN
num = INT( 10.01 * fraction )
EDIT(Text=small, ITeM=num+1, Parse=digit)
WRITE(Text=outP, APPend) ' ', digit
fraction = 10*fraction - num
ENDIF
ENDDO
OPEN(FIle="temp.txt", APPend)
WRITE(FIle="temp.txt", Format='F10, " = ", A', CLoSe=1) number, outP
RETURN
ENDIF
order = order + 1 EDIT(Text=big, ITeM=order, Parse=kilo) IF( MOD(num, 1000) ) outP = kilo // ' and '// outP ENDDO
END
CALL NumberToWords( 0 ) CALL NumberToWords( 1234 ) CALL NumberToWords( 1234/100 ) CALL NumberToWords( 10000000 + 1.2 ) CALL NumberToWords( 2^15 ) CALL NumberToWords( 0.001 ) CALL NumberToWords( -EXP(1) )
- literals
SMALL= zero one two three four five six seven eight nine ten & eleven twelve thirteen fourteen fifteen sixteen seventeen eighteen nineteen
TENS=ten twenty thirty forty fifty sixty seventy eighty ninety
BIG=thousand million billion trillion quadrillion</lang>
<lang HicEst>0 = zero 1234 = one thousand and two hundred thirty-four 12.34 = twelve point three four 10000001.2 = ten million and one point two 32768 = thirty-two thousand and seven hundred sixty-eight 1E-3 = point zero zero one -2.7182818 = minus two point seven one eight two eight one eight</lang>
Icon and Unicon
<lang Icon>link numbers # commas, spell
procedure main(arglist) every x := !arglist do
write(commas(x), " -> ",spell(x))
end</lang>
numbers:spell was used as a based for this procedure.
<lang Icon>procedure spell(n) #: spell out integer (short scale)
local m, i
static scale
initial {
scale := [ "thousand", "million", "billion", "trillion", "quadrillion", "quintillion", "sextillion","septillion"]
every scale[i := 1 to *scale ] := [ integer(repl("999",i + 1)), -3 * i, " "||scale[i] ]
push(scale,[999,2," hundred"])
}
n := integer(n) | stop(image(n)," is not an integer")
if n < 0 then return "negative " || spell(-n)
if n <= 12 then return {
"0zero,1one,2two,3three,4four,5five,6six,7seven,8eight,_
9nine,10ten,11eleven,12twelve," ? {
tab(find(n))
move(*n)
tab(find(","))
}
}
else if n <= 19 then return {
spell(n[2] || "0") ?
(if ="for" then "four" else tab(find("ty"))) || "teen"
}
else if n <= 99 then return {
"2twen,3thir,4for,5fif,6six,7seven,8eigh,9nine," ? {
tab(find(n[1]))
move(1)
tab(find(",")) || "ty" ||
(if n[2] ~= 0 then "-" || spell(n[2]) else "")
}
}
else if n <= scale[i := 1 to *scale,1] then return { # generalize based on scale
spell(n[1:scale[i,2]]) || scale[i,3] ||
(if (m := n[scale[i,2]:0]) ~= 0 then " and " || spell(m) else "")
}
else fail # really big
end</lang> Sample output:
#spell.exe 5 11 15 67 10132767 65535 -1234567890123456 5 -> five 11 -> eleven 15 -> fifteen 67 -> sixty-seven 10,132,767 -> ten million and one hundred and thirty-two thousand and seven hundred and sixty-seven 65,535 -> sixty-five thousand and five hundred and thirty-five -1,234,567,890,123,456 -> negative one quadrillion and two hundred and thirty-four trillion and five hundred and sixty-seven billion and eight hundred and ninety million and one hundred and twenty-three thousand and four hundred and fifty-six
Inform 7
<lang inform7>say 32767 in words;</lang>
<lang inform7>say 2147483647 in words;</lang>
J
Solutions: <lang j>u=. ;:'one two three four five six seven eight nine' v=. ;:'ten eleven twelve thirteen fourteen fifteen sixteen seventeen eighteen nineteen' t=. ;:'twenty thirty forty fifty sixty seventy eighty ninety' EN100=: ; u , v , , t ,&.>/ ;'-',&.>u
z=. ; 'thousand' ; (;:'m b tr quadr quint sext sept oct non'),&.> <'illion' u=. ;:'un duo tre quattuor quin sex septen octo novem' t=. (;:'dec vigint trigint quadragint quinquagint sexagint septuagint octogint nonagint'),&.><'illion' ENU=: z , (, t ,~&.>/ ;u) , <'centillion'
en3=: 4 : 0
'p q'=. 0 100#:y
(p{::EN100),((*p)#' hundred'),((p*&*q)#x),q{::EN100
)
en=: 4 : 0
d=. 1000&#.^:_1 y
assert. (0<:y) *. ((=<.)y) *. d <:&# ENU
c=. x&en3&.> (*d)#d
((0=y)#'zero') , (-2+*{:d) }. ; , c,.(<' '),.(ENU{~I.&.|.*d),.<', '
)
uk=: ' and '&en NB. British us=: ' ' &en NB. American</lang>
Example:
uk 123456789 one hundred and twenty-three million, four hundred and fifty-six thousand, seven hundred and eighty-nine us 123456789 one hundred twenty-three million, four hundred fifty-six thousand, seven hundred eighty-nine us 1234567890123456789012345678901234567890123456789012345678901234567890x one duovigintillion, two hundred thirty-four unvigintillion, five hundred sixty-seven vigintillion, eight hundred ninety novemdecillion, one hundred twenty-three octodecillion, four hundred fifty-six septendecillion, seven hundred eighty-nine sexdecillion, twelve quindecillion, three hundred forty-five quattuordecillion, six hundred seventy-eight tredecillion, nine hundred one duodecillion, two hundred thirty-four undecillion, five hundred sixty-seven decillion, eight hundred ninety nonillion, one hundred twenty-three octillion, four hundred fifty-six septillion, seven hundred eighty-nine sextillion, twelve quintillion, three hundred forty-five quadrillion, six hundred seventy-eight trillion, nine hundred one billion, two hundred thirty-four million, five hundred sixty-seven thousand, eight hundred ninety
Java
<lang java>public class Int2Words {
static String[] small = {"one", "two", "three", "four", "five", "six",
"seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen",
"fifteen", "sixteen", "seventeen", "eighteen", "nineteen"};
static String[] tens = {"twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty",
"ninety"};
static String[] big = {"thousand", "million", "billion", "trillion"};
public static void main(String[] args) {
System.out.println(int2Text(900000001));
System.out.println(int2Text(1234567890));
System.out.println(int2Text(-987654321));
System.out.println(int2Text(0));
}
public static String int2Text(long number) {
long num = 0;
String outP = "";
int unit = 0;
long tmpLng1 = 0;
if (number == 0) {
return "zero";
}
num = Math.abs(number);
for (;;) {
tmpLng1 = num % 100;
if (tmpLng1 >= 1 && tmpLng1 <= 19) {
outP = small[(int) tmpLng1 - 1] + " " + outP;
} else if (tmpLng1 >= 20 && tmpLng1 <= 99) {
if (tmpLng1 % 10 == 0) {
outP = tens[(int) (tmpLng1 / 10) - 2] + " " + outP;
} else {
outP = tens[(int) (tmpLng1 / 10) - 2] + "-"
+ small[(int) (tmpLng1 % 10) - 1] + " " + outP;
}
}
tmpLng1 = (num % 1000) / 100;
if (tmpLng1 != 0) {
outP = small[(int) tmpLng1 - 1] + " hundred " + outP;
}
num /= 1000;
if (num == 0) {
break;
}
tmpLng1 = num % 1000;
if (tmpLng1 != 0) {
outP = big[unit] + " " + outP;
}
unit++;
}
if (number < 0) {
outP = "negative " + outP;
}
return outP.trim(); }
}</lang> Output:
nine hundred million one one billion two hundred thirty-four million five hundred sixty-seven thousand eight hundred ninety negative nine hundred eighty-seven million six hundred fifty-four thousand three hundred twenty-one zero
Recursive
<lang java>public class NumberToWordsConverter { // works upto 9999999
final private static String[] units = {"Zero","One","Two","Three","Four", "Five","Six","Seven","Eight","Nine","Ten", "Eleven","Twelve","Thirteen","Fourteen","Fifteen", "Sixteen","Seventeen","Eighteen","Nineteen"}; final private static String[] tens = {"","","Twenty","Thirty","Forty","Fifty", "Sixty","Seventy","Eighty","Ninety"};
public static String convert(Integer i) { // if( i < 20) return units[i]; if( i < 100) return tens[i/10] + ((i % 10 > 0)? " " + convert(i % 10):""); if( i < 1000) return units[i/100] + " Hundred" + ((i % 100 > 0)?" and " + convert(i % 100):""); if( i < 1000000) return convert(i / 1000) + " Thousand " + ((i % 1000 > 0)? " " + convert(i % 1000):"") ; return convert(i / 1000000) + " Million " + ((i % 1000000 > 0)? " " + convert(i % 1000000):"") ; } }</lang>
Joy
<lang Joy> DEFINE units == [ "zero" "one" "two" "three" "four" "five" "six" "seven" "eight" "nine" "ten"
"eleven" "twelve" "thirteen" "fourteen" "fifteen" "sixteen" "seventeen" "eighteen" "nineteen" ];
tens == [ "ten" "twenty" "thirty" "forty" "fifty" "sixty" "seventy" "eighty" "ninety" ];
convert6 == [1000000 <] [1000 div swap convert " thousand " putchars convert3] [1000000 div swap convert " million " putchars convert3] ifte;
convert5 == [null] [] [" and " putchars convert] ifte;
convert4 == [1000 <] [100 div swap units of putchars " hundred" putchars convert5] [convert6] ifte;
convert3 == [null] [] [32 putch convert] ifte;
convert2 == [100 <] [10 div swap pred tens of putchars convert3] [convert4] ifte;
convert == [20 <] [units of putchars] [convert2] ifte. </lang>
Logo
<lang logo>make "numbers {one two three four five six seven eight nine ten
eleven twelve thirteen fourteen fifteen sixteen seventeen eighteen nineteen}
make "tens {twenty thirty forty fifty sixty seventy eighty ninety}@2
make "thou [[] thousand million billion trillion] ; expand as desired
to to.english.thou :n :thou
if :n = 0 [output []]
if :n < 20 [output sentence item :n :numbers first :thou]
if :n < 100 [output (sentence item int :n/10 :tens
to.english.thou modulo :n 10 [[]]
first :thou)]
if :n < 1000 [output (sentence item int :n/100 :numbers
"hundred
to.english.thou modulo :n 100 [[]]
first :thou)]
output (sentence to.english.thou int :n/1000 butfirst :thou
to.english.thou modulo :n 1000 :thou)
end
to to.english :n
if :n = 0 [output "zero] if :n > 0 [output to.english.thou :n :thou] [output sentence "negative to.english.thou minus :n :thou]
end
print to.english 1234567 ; one million two hundred thirty four thousand five hundred sixty seven</lang>
Lua
<lang lua>words = {"one ", "two ", "three ", "four ", "five ", "six ", "seven ", "eight ", "nine "} levels = {"thousand ", "million ", "billion ", "trillion ", "quadrillion ", "quintillion ", "sextillion ", "septillion ", "octillion ", [0] = ""} iwords = {"ten ", "twenty ", "thirty ", "forty ", "fifty ", "sixty ", "seventy ", "eighty ", "ninety "} twords = {"eleven ", "twelve ", "thirteen ", "fourteen ", "fifteen ", "sixteen ", "seventeen ", "eighteen ", "nineteen "}
function digits(n)
local i, ret = -1 return function() i, ret = i + 1, n % 10
if n > 0 then
n = math.floor(n / 10)
return i, ret end
end
end
level = false function getname(pos, dig) --stateful, but effective.
level = level or pos % 3 == 0 if(dig == 0) then return "" end local name = (pos % 3 == 1 and iwords[dig] or words[dig]) .. (pos % 3 == 2 and "hundred " or "") if(level) then name, level = name .. levels[math.floor(pos / 3)], false end return name
end
local val, vword = io.read() + 0, ""
for i, v in digits(val) do
vword = getname(i, v) .. vword
end
for i, v in ipairs(words) do
vword = vword:gsub("ty " .. v, "ty-" .. v)
vword = vword:gsub("ten " .. v, twords[i])
end
if #vword == 0 then print "zero" else print(vword) end</lang>
Mathematica
<lang>small = "zero"["one", "two", "three", "four", "five", "six", "seven",
"eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen",
"fifteen", "sixteen", "seventeen", "eighteen",
"nineteen"]; tens = # <> "-" & /@ {"twenty", "thirty", "forty",
"fifty", "sixty", "seventy", "eighty", "ninety"};
big = Prepend[
" " <> # & /@ {"thousand", "million", "billion", "trillion",
"quadrillion", "quintillion", "sextillion", "septillion",
"octillion", "nonillion", "decillion", "undecillion",
"duodecillion", "tredecillion"}, ""];
name[n_Integer] := "negative " <> name[-n] /; n < 0; name[n_Integer] := smalln /; 0 <= n < 20; name[n_Integer] :=
StringTrim[tens#1 - 1 <> small#2 & @@ IntegerDigits[n], "-zero"] /; 10 <= n < 100;
name[n_Integer] :=
StringTrim[ small#1 <> " hundred and " <> name@#2 & @@ IntegerDigits[n, 100], " and zero"] /; 100 <= n < 1000;
name[n_Integer] :=
StringJoin@
Riffle[Select[
MapThread[StringJoin, {name /@ #, Reverse@big;; Length@#}] &@
IntegerDigits[n, 1000], StringFreeQ[#, "zero"] &], ","];</lang>
Maxima
<lang Maxima> l: [99, 300, 310, 1501, 12609, 512609, 43112609, 77000112609, 2000000000100, 999999999999999999, 0, -99, -1501, -77000112609, -123456789987654321]; map( lambda([n], printf(true, "~20d ~r~%", n, n)), l)$ </lang>
MAXScript
This example isn't a very succinct way to solve the problem, but the way it works should be quite obvious. The function will work for values up to 1000 <lang MAXScript>fn NumberToWord myNum = ( local Result = "" while myNum != 0 do ( Result += case of ( (myNum >= 1000):(myNum -= 1000; "one thousand") (myNum > 900): (myNum -= 900 ; "nine hundred and") (myNum == 900): (myNum -= 900 ; "nine hundred") (myNum > 800): (myNum -= 800 ; "eight hundred and") (myNum == 800): (myNum -= 900 ; "eight hundred") (myNum > 700): (myNum -= 700 ; "seven hundred and") (myNum == 700): (myNum -= 900 ; "seven hundred") (myNum > 600): (myNum -= 600 ; "six hundred and") (myNum == 600): (myNum -= 900 ; "six hundred") (myNum > 500): (myNum -= 500 ; "five hundred and") (myNum == 500): (myNum -= 900 ; "five hundred") (myNum > 400): (myNum -= 400 ; "four hundred and") (myNum == 400): (myNum -= 900 ; "four hundred") (myNum > 300): (myNum -= 300 ; "three hundred and") (myNum == 300): (myNum -= 900 ; "three hundred") (myNum > 200): (myNum -= 200 ; "two hundred and") (myNum == 200): (myNum -= 900 ; "two hundred") (myNum > 100): (myNum -= 100 ; "one hundred and") (myNum == 100): (myNum -= 100 ; "one hundred") (myNum >= 90): (myNum -= 90 ; "ninety") (myNum >= 80): (myNum -= 80 ; "eighty") (myNum >= 70): (myNum -= 70 ; "seventy") (myNum >= 60): (myNum -= 60 ; "sixty") (myNum >= 50): (myNum -= 50 ; "fifty") (myNum >= 40): (myNum -= 40 ; "fourty") (myNum >= 30): (myNum -= 30 ; "thirty") (myNum >= 20): (myNum -= 20 ; "twenty") (myNum >= 19): (myNum -= 19 ; "nineteen") (myNum >= 18): (myNum -= 18 ; "eighteen") (myNum >= 17): (myNum -= 17 ; "seventeen") (myNum >= 16): (myNum -= 16 ; "sixteen") (myNum >= 15): (myNum -= 15 ; "fifteen") (myNum >= 14): (myNum -= 14 ; "fourteen") (myNum >= 13): (myNum -= 13 ; "thirteen") (myNum >= 12): (myNum -= 12 ; "twelve") (myNum >= 11): (myNum -= 11 ; "eleven") (myNum >= 10): (myNum -= 10 ; "ten") (myNum >= 9): (myNum -= 9 ; "nine") (myNum >= 8): (myNum -= 8 ; "eight") (myNum >= 7): (myNum -= 7 ; "seven") (myNum >= 6): (myNum -= 6 ; "six") (myNum >= 5): (myNum -= 5 ; "five") (myNum >= 4): (myNum -= 4 ; "four") (myNum >= 3): (myNum -= 3 ; "three") (myNum >= 2): (myNum -= 2 ; "two") (myNum >= 1): (myNum -= 1 ; "one") ) if myNum != 0 then result += " " ) result )</lang>
Example: <lang MAXScript>NumberToWord(123)</lang>
Objeck
<lang objeck> class NumberNames {
small : static : String[]; tens : static : String[]; big : static : String[];
function : Main(args : String[]) ~ Nil {
small := ["one", "two", "three", "four", "five", "six", "seven",
"eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen",
"fifteen", "sixteen", "seventeen", "eighteen", "nineteen"];
tens := ["twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"];
big := ["thousand", "million", "billion", "trillion"];
Int2Text(900000001)->PrintLine();
Int2Text(1234567890)->PrintLine();
Int2Text(-987654321)->PrintLine();
Int2Text(0)->PrintLine();
}
function : native : Int2Text(number : Int) ~ String {
num := 0;
outP := "";
unit := 0;
tmpLng1 := 0;
if (number = 0) {
return "zero";
};
num := number->Abs();
while(true) {
tmpLng1 := num % 100;
if (tmpLng1 >= 1 & tmpLng1 <= 19) {
tmp := String->New();
tmp->Append(small[tmpLng1 - 1]);
tmp->Append(" ");
tmp->Append(outP);
outP := tmp;
}
else if (tmpLng1 >= 20 & tmpLng1 <= 99) {
if (tmpLng1 % 10 = 0) {
tmp := String->New();
tmp->Append(tens[(tmpLng1 / 10) - 2]);
tmp->Append(" ");
tmp->Append(outP);
outP := tmp;
}
else {
tmp := String->New();
tmp->Append(tens[(tmpLng1 / 10) - 2]);
tmp->Append( "-");
tmp->Append(small[(tmpLng1 % 10) - 1]);
tmp->Append(" ");
tmp->Append(outP);
outP := tmp;
};
};
tmpLng1 := (num % 1000) / 100;
if (tmpLng1 <> 0) {
tmp := String->New();
tmp->Append(small[tmpLng1 - 1]);
tmp->Append(" hundred ");
tmp->Append(outP);
outP := tmp;
};
num /= 1000;
if (num = 0) {
break;
};
tmpLng1 := num % 1000;
if (tmpLng1 <> 0) {
tmp := String->New();
tmp->Append(big[unit]);
tmp->Append(" ");
tmp->Append(outP);
outP := tmp;
};
unit+=1;
};
if (number < 0) {
tmp := String->New();
tmp->Append("negative ");
tmp->Append(outP);
outP := tmp;
};
return outP->Trim();
}
} </lang>
output:
nine hundred million one one billion two hundred thirty-four million five hundred sixty-seven thousand eight hundred ninety negative nine hundred eighty-seven million six hundred fifty-four thousand three hundred twenty-one zero
OCaml
<lang ocaml>let div_mod n d = (n / d, n mod d) let join = String.concat ", " ;;
let rec nonzero = function
| _, 0 -> "" | c, n -> c ^ (spell_integer n)
and tens n =
[| ""; ""; "twenty"; "thirty"; "forty"; "fifty";
"sixty"; "seventy"; "eighty"; "ninety" |].(n)
and small n =
[| "zero"; "one"; "two"; "three"; "four"; "five";
"six"; "seven"; "eight"; "nine"; "ten"; "eleven";
"twelve"; "thirteen"; "fourteen"; "fifteen";
"sixteen";"seventeen"; "eighteen"; "nineteen" |].(n)
and bl = [| ""; ""; "m"; "b"; "tr"; "quadr"; "quint";
"sext"; "sept"; "oct"; "non"; "dec" |]
and big = function
| 0, n -> (spell_integer n) | 1, n -> (spell_integer n) ^ " thousand" | e, n -> (spell_integer n) ^ " " ^ bl.(e) ^ "illion"
and uff acc = function
| 0 -> List.rev acc
| n ->
let a, b = div_mod n 1000 in
uff (b::acc) a
and spell_integer = function
| n when n < 0 -> invalid_arg "spell_integer: negative input"
| n when n < 20 -> small n
| n when n < 100 ->
let a, b = div_mod n 10 in
(tens a) ^ nonzero("-", b)
| n when n < 1000 ->
let a, b = div_mod n 100 in
(small a) ^ " hundred" ^ nonzero(" ", b)
| n ->
let seg = (uff [] n) in
let _, segn =
(* just add the index of the item in the list *)
List.fold_left
(fun (i,acc) v -> (succ i, (i,v)::acc))
(0,[])
seg
in
let fsegn =
(* remove right part "zero" *)
List.filter
(function (_,0) -> false | _ -> true)
segn
in
join(List.map big fsegn)
- </lang>
PARI/GP
<lang parigp>Eng(n:int)={ my(tmp,s=""); if (n >= 1000000, tmp = n\1000000; s = Str(Eng(tmp), " million"); n -= tmp * 1000000; if (!n, return(s)); s = Str(s, " ") ); if (n >= 1000, tmp = n\1000; s = Str(Eng(tmp), " thousand"); n -= tmp * 1000; if (!n, return(s)); s = Str(s, " ") ); if (n >= 100, tmp = n\100; s = Str(Edigit(tmp), " hundred"); n -= tmp * 100; if (!n, return(s)); s = Str(s, " ") ); if (n < 20, return (Str(s, ["one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "ninteen"][n])) ); tmp = n\10; s = Str(s, [0, "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"][tmp]); n -= tmp * 10; if (n, Str(s, "-", Edigit(n)), s) }; Edigit(n)={ ["one", "two", "three", "four", "five", "six", "seven", "eight", "nine"][n] };</lang>
Pascal
<lang pascal>program NumberNames(output);
const
smallies: array[1..19] of string =
('one', 'two', 'three', 'four', 'five', 'six',
'seven', 'eight', 'nine', 'ten', 'eleven',
'twelve', 'thirteen', 'fourteen', 'fifteen',
'sixteen', 'seventeen', 'eighteen', 'nineteen');
tens: array[2..9] of string =
('twenty', 'thirty', 'forty', 'fifty',
'sixty', 'seventy', 'eighty', 'ninety');
function domaxies(number: int64): string;
const
maxies: array[0..5] of string =
(' thousand', ' million', ' billion',
' trillion', ' quadrillion', ' quintillion');
begin
domaxies := ;
if number >= 0 then
domaxies := maxies[number];
end;
function doHundreds( number: int64): string;
begin
doHundreds := ;
if number > 99 then
begin
doHundreds := smallies[number div 100];
doHundreds := doHundreds + ' hundred';
number := number mod 100;
if number > 0 then
doHundreds := doHundreds + ' and ';
end;
if number >= 20 then
begin
doHundreds := doHundreds + tens[number div 10];
number := number mod 10;
if number > 0 then
doHundreds := doHundreds + '-';
end;
if (0 < number) and (number < 20) then
doHundreds := doHundreds + smallies[number];
end;
function spell(number: int64): string;
var
scaleFactor: int64 = 1000000000000000000;
maxieStart, h: int64;
begin
spell := ;
maxieStart := 5;
if number < 20 then
spell := smallies[number];
while scaleFactor > 0 do
begin
if number > scaleFactor then
begin
h := number div scaleFactor; spell := spell + doHundreds(h) + domaxies(maxieStart); number := number mod scaleFactor; if number > 0 then spell := spell + ', ';
end;
scaleFactor := scaleFactor div 1000;
dec(maxieStart);
end;
end;
begin
writeln(99, ': ', spell(99)); writeln(234, ': ', spell(234)); writeln(7342, ': ', spell(7342)); writeln(32784, ': ', spell(32784)); writeln(234345, ': ', spell(234345)); writeln(2343451, ': ', spell(2343451)); writeln(23434534, ': ', spell(23434534)); writeln(234345456, ': ', spell(234345456)); writeln(2343454569, ': ', spell(2343454569)); writeln(2343454564356, ': ', spell(2343454564356)); writeln(2345286538456328, ': ', spell(2345286538456328));
end.</lang> Output:
99: ninety-nine
234: two hundred and thirty-four
7342: seven thousand, three hundred and forty-two
32784: thirty-two thousand, seven hundred and eighty-four
234345: two hundred and thirty-four thousand, three hundred and forty-five
2343451: two million, three hundred and forty-three thousand, four hundred and fifty-one
23434534: twenty-three million, four hundred and thirty-four thousand, five hundred and thirty-four
234345456: two hundred and thirty-four million, three hundred and forty-five thousand, four hundred and fifty-six
2343454569: two billion, three hundred and forty-three million, four hundred and fifty-four thousand, five hundred and sixty-nine
23434545643565: twenty-three trillion, four hundred and thirty-four billion, five hundred and forty-five million, six hundred and forty-three thousand, five hundred and sixty-five
2345286538456328: two quadrillion, three hundred and forty-five trillion, two hundred and eighty-six billion, five hundred and thirty-eight million, four hundred and fifty-six thousand, three hundred and twenty-eight
Perl
<lang perl>use Lingua::EN::Numbers 'num2en';
print num2en(123456789), "\n";</lang>
Perl 6
Apart from the $m++ this can be viewed as a purely functional program; we use nested gather/take constructs to avoid accumulators. The negative and zero detection is done in the string domain because mono's big integers seem to blow up somewhere before a centillion. <lang perl6>constant @I = <zero one two three four five six seven eight nine
ten eleven twelve thirteen fourteen fifteen sixteen seventeen eighteen nineteen>;
constant @X = <0 X twenty thirty forty fifty sixty seventy eighty ninety>; constant @C = @I X~ ' hundred'; constant @M = (<0 thousand>,
((<m b tr quadr quint sext sept oct non>,
(map { (, <un duo tre quattuor quin sex septen octo novem>).flat X~ $_ },
<dec vigint trigint quadragint quinquagint sexagint septuagint octogint nonagint>),
'cent').flat X~ 'illion')).flat;
sub int-name ($num) {
if $num.substr(0,1) eq '-' { return "negative {int-name($num.substr(1))}" }
if $num eq '0' { return @I[0] }
my $m = 0;
return join ', ', reverse gather for $num.flip.comb(/\d ** 1..3/) {
my ($i,$x,$c) = .comb;
if $i or $x or $c {
take join ' ', gather {
if $c { take @C[$c] }
if $x and $x == 1 { take @I[$i+10] }
else {
if $x { take @X[$x] }
if $i { take @I[$i] }
}
take @M[$m] // die "WOW! ZILLIONS!\n" if $m;
}
}
$m++;
}
}
while ne (my $n = prompt("Number: ")) {
say int-name($n);
}</lang> Output:
Number: 0 zero Number: 17 seventeen Number: -1,234,567,890 negative one billion, two hundred thirty four million, five hundred sixty seven thousand, eight hundred ninety Number: 42 000 forty two thousand Number: 1001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001 one novemseptuagintillion, one octoseptuagintillion, one septenseptuagintillion, one sexseptuagintillion, one quinseptuagintillion, one quattuorseptuagintillion, one treseptuagintillion, one duoseptuagintillion, one unseptuagintillion, one septuagintillion, one novemsexagintillion, one octosexagintillion, one septensexagintillion, one sexsexagintillion, one quinsexagintillion, one quattuorsexagintillion, one tresexagintillion, one duosexagintillion, one unsexagintillion, one sexagintillion, one novemquinquagintillion, one octoquinquagintillion, one septenquinquagintillion, one sexquinquagintillion, one quinquinquagintillion, one quattuorquinquagintillion, one trequinquagintillion, one duoquinquagintillion, one unquinquagintillion, one quinquagintillion, one novemquadragintillion, one octoquadragintillion, one septenquadragintillion, one sexquadragintillion, one quinquadragintillion, one quattuorquadragintillion, one trequadragintillion, one duoquadragintillion, one unquadragintillion, one quadragintillion, one novemtrigintillion, one octotrigintillion, one septentrigintillion, one sextrigintillion, one quintrigintillion, one quattuortrigintillion, one tretrigintillion, one duotrigintillion, one untrigintillion, one trigintillion, one novemvigintillion, one octovigintillion, one septenvigintillion, one sexvigintillion, one quinvigintillion, one quattuorvigintillion, one trevigintillion, one duovigintillion, one unvigintillion, one vigintillion, one novemdecillion, one octodecillion, one septendecillion, one sexdecillion, one quindecillion, one quattuordecillion, one tredecillion, one duodecillion, one undecillion, one decillion, one nonillion, one octillion, one septillion, one sextillion, one quintillion, one quadrillion, one trillion, one billion, one million, one thousand, one Number: 198723483017417 one hundred ninety eight trillion, seven hundred twenty three billion, four hundred eighty three million, seventeen thousand, four hundred seventeen
PHP
<lang php>$orderOfMag = array('Hundred', 'Thousand,', 'Million,', 'Billion,', 'Trillion,'); $smallNumbers = array('Zero', 'One', 'Two', 'Three', 'Four', 'Five', 'Six', 'Seven', 'Eight', 'Nine', 'Ten', 'Eleven', 'Twelve', 'Thirteen', 'Fourteen', 'Fifteen', 'Sixteen', 'Seventeen', 'Eighteen', 'Nineteen'); $decades = array(, , 'Twenty', 'Thirty', 'Forty', 'Fifty', 'Sixty', 'Seventy', 'Eighty', 'Ninety');
function NumberToEnglish($num, $count = 0){
global $orderOfMag, $smallNumbers, $decades; $isLast = true; $str = ;
if ($num < 0){
$str = 'Negative ';
$num = abs($num);
}
(int) $thisPart = substr((string) $num, -3);
if (strlen((string) $num) > 3){
// Number still too big, work on a smaller chunk
$str .= NumberToEnglish((int) substr((string) $num, 0, strlen((string) $num) - 3), $count + 1);
$isLast = false;
}
// do translation stuff
if (($count == 0 || $isLast) && ($str == || $str == 'Negative '))
// This is either a very small number or the most significant digits of the number. Either way we don't want a preceeding "and"
$and = ;
else
$and = ' and ';
if ($thisPart > 99){
// Hundreds part of the number chunk
$str .= ($isLast ? : ' ') . "{$smallNumbers[$thisPart/100]} {$orderOfMag[0]}";
if(($thisPart %= 100) == 0){
// There is nothing else to do for this chunk (was a multiple of 100)
$str .= " {$orderOfMag[$count]}";
return $str;
}
$and = ' and '; // Set up our and string to the word "and" since there is something in the hundreds place of this chunk
}
if ($thisPart >= 20){
// Tens part of the number chunk
$str .= "{$and}{$decades[$thisPart /10]}";
$and = ' '; // Make sure we don't have any extranious "and"s
if(($thisPart %= 10) == 0)
return $str . ($count != 0 ? " {$orderOfMag[$count]}" : );
}
if ($thisPart < 20 && $thisPart > 0)
// Ones part of the number chunk
return $str . "{$and}{$smallNumbers[(int) $thisPart]} " . ($count != 0 ? $orderOfMag[$count] : );
elseif ($thisPart == 0 && strlen($thisPart) == 1)
// The number is zero
return $str . "{$smallNumbers[(int)$thisPart]}";
}</lang> Example: <lang php>NumberToEnglish(0); NumberToEnglish(12); NumberToEnglish(123); NumberToEnglish(1234567890123); NumberToEnglish(65535); NumberToEnglish(-54321);</lang> Returns:
Zero Twelve One Hundred and Twenty Three One Trillion, Two Hundred and Thirty Four Billion, Five Hundred and Sixty Seven Million, Eight Hundred and Ninety Thousand, One Hundred and Twenty Three Sixty Five Thousand, Five Hundred and Thirty Five Negative Fifty Four Thousand, Three Hundred and Twenty One
PicoLisp
<lang PicoLisp>(de numName (N)
(cond
((=0 N) "zero")
((lt0 N) (pack "minus " (numName (- N))))
(T (numNm N)) ) )
(de numNm (N)
(cond
((=0 N))
((> 14 N)
(get '("one" "two" "three" "four" "five" "six" "seven" "eight" "nine" "ten" "eleven" "twelve" "thirteen") N) )
((= 15 N) "fifteen")
((= 18 N) "eighteen")
((> 20 N) (pack (numNm (% N 10)) "teen"))
((> 100 N)
(pack
(get '("twen" "thir" "for" "fif" "six" "seven" "eigh" "nine") (dec (/ N 10)))
"ty"
(unless (=0 (% N 10))
(pack "-" (numNm (% N 10))) ) ) )
((rank N '((100 . "hundred") (1000 . "thousand") (1000000 . "million")))
(pack (numNm (/ N (car @))) " " (cdr @) " " (numNm (% N (car @)))) ) ) )</lang>
PL/I
<lang PL/I> declare integer_names (0:20) character (9) varying static initial
('zero', 'one', 'two', 'three', 'four', 'five', 'six',
'seven', 'eight', 'nine', 'ten', 'eleven', 'twelve',
'thirteen', 'fourteen', 'fifteen', 'sixteen', 'seventeen',
'eighteen', 'nineteen', 'twenty' );
declare x(10) character (7) varying static initial
('ten', 'twenty', 'thirty', 'fourty', 'fifty',
'sixty', 'seventy', 'eighty', 'ninety', 'hundred');
declare y(0:5) character (10) varying static initial
(, , ' thousand ', ' million ', ' billion ', ' trillion ');
declare (i, j, m, t) fixed binary (31);
declare (units, tens, hundreds, thousands) fixed binary (7);
declare (h, v, value) character (200) varying;
declare (d, k, n) fixed decimal (15);
declare three_digits fixed decimal (3);
value = ;
i = 5;
k = n;
do d = 1000000000000 repeat d/1000 while (d > 0);
i = i - 1;
three_digits = k/d;
k = mod(k, d);
if three_digits = 0 then iterate;
units = mod(three_digits, 10);
t = three_digits / 10;
tens = mod(t, 10);
hundreds = three_digits / 100;
m = mod(three_digits, 100);
if m <= 20 then
v = integer_names(m);
else if units = 0 then
v = ;
else
v = integer_names(units);
if tens >= 2 & units ^= 0 then
v = x(tens) || v;
else if tens > 2 & units = 0 then
v = v || x(tens);
if units + tens = 0 then
if n > 0 then v = ;
if hundreds > 0 then
h = integer_names(hundreds) || ' hundred ';
else
h = ;
if three_digits > 100 & (tens + units > 0) then
v = 'and ' || v;
if i = 1 & value ^= & three_digits <= 9 then
v = 'and ' || v;
value = value ||h || v || y(i);
end;
put skip edit (trim(N), ' = ', value) (a);</lang>
PowerBASIC
Note that the PB compiler seems to have some bugs related to the QUAD data type; see the sample output below the code.
<lang powerbasic>FUNCTION int2Text (number AS QUAD) AS STRING
IF 0 = number THEN
FUNCTION = "zero"
EXIT FUNCTION
END IF
DIM num AS QUAD, outP AS STRING, unit AS LONG DIM tmpLng1 AS QUAD
DIM small(1 TO 19) AS STRING, tens(7) AS STRING, big(5) AS STRING
DIM tmpInt AS LONG, dcnt AS LONG
ARRAY ASSIGN small() = "one", "two", "three", "four", "five", "six", _
"seven", "eight", "nine", "ten", "eleven", _
"twelve", "thirteen", "fourteen", "fifteen", _
"sixteen", "seventeen", "eighteen", "nineteen"
ARRAY ASSIGN tens() = "twenty", "thirty", "forty", "fifty", "sixty", _
"seventy", "eighty", "ninety"
ARRAY ASSIGN big() = "thousand", "million", "billion", "trillion", _
"quadrillion", "quintillion"
num = ABS(number)
DO
tmpLng1 = num MOD 100
SELECT CASE tmpLng1
CASE 1 TO 19
outP = small(tmpLng1) + " " + outP
CASE 20 TO 99
SELECT CASE tmpLng1 MOD 10
CASE 0
outP = tens((tmpLng1 \ 10) - 2) + " " + outP
CASE ELSE
outP = tens((tmpLng1 \ 10) - 2) + "-" + small(tmpLng1 MOD 10) + " " + outP
END SELECT
END SELECT
tmpLng1 = (num MOD 1000) \ 100
IF tmpLng1 THEN
outP = small(tmpLng1) + " hundred " + outP
END IF
num = num \ 1000
IF num < 1 THEN EXIT DO
tmpLng1 = num MOD 1000
IF tmpLng1 THEN outP = big(unit) + " " + outP
unit = unit + 1 LOOP
IF number < 0 THEN outP = "negative " + outP
FUNCTION = RTRIM$(outP)
END FUNCTION
FUNCTION PBMAIN () AS LONG
DIM n AS QUAD
#IF %DEF(%PB_CC32)
INPUT "Gimme a number! ", n
#ELSE
n = VAL(INPUTBOX$("Gimme a number!", "Now!"))
#ENDIF
? int2Text(n)
END FUNCTION</lang>
Sample output:
Gimme a number! 1111111111111111111 one quintillion one hundred eleven quadrillion one hundred eleven trillion one h undred eleven billion one hundred eleven million one hundred eleven thousand one hundred ten
PureBasic
The range of integers handled has been set at an obscene 45 digits. <lang PureBasic>DataSection
numberNames: ;small Data.s "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten" Data.s "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen" ;tens Data.s "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety" ;big, non-Chuquet system Data.s "thousand", "million", "billion", "trillion", "quadrillion", "quintillion", "sextillion" Data.s "septillion", "octillion", "nonillion", "decillion", "undecillion", "duodecillion" Data.s "tredecillion"
EndDataSection
Procedure.s numberWords(number.s)
;handles integers from -1E45 to +1E45
Static isInitialized = #False
Static Dim small.s(19)
Static Dim tens.s(9)
Static Dim big.s(14)
If Not isInitialized
Restore numberNames
For i = 1 To 19
Read.s small(i)
Next
For i = 2 To 9
Read.s tens(i)
Next
For i = 1 To 14
Read.s big(i)
Next
isInitialized = #True
EndIf
For i = 1 To Len(number)
If Not FindString("- 0123456789", Mid(number,i,1), 1)
number = Left(number, i - 1) ;trim number to the last valid character
Break ;exit loop
EndIf
Next
Protected IsNegative = #False
number = Trim(number)
If Left(number,1) = "-"
IsNegative = #True
number = Trim(Mid(number, 2))
EndIf
If CountString(number, "0") = Len(number)
ProcedureReturn "zero"
EndIf
If Len(number) > 45
ProcedureReturn "Number is too big!"
EndIf
Protected num.s = number, output.s, unit, unitOutput.s, working
Repeat
working = Val(Right(num, 2))
unitOutput = ""
Select working
Case 1 To 19
unitOutput = small(working)
Case 20 To 99
If working % 10
unitOutput = tens(working / 10) + "-" + small(working % 10)
Else
unitOutput = tens(working / 10)
EndIf
EndSelect
working = Val(Right(num, 3)) / 100
If working
If unitOutput <> ""
unitOutput = small(working) + " hundred " + unitOutput
Else
unitOutput = small(working) + " hundred"
EndIf
EndIf
If unitOutput <> "" And unit > 0
unitOutput + " " + big(unit)
If output <> ""
unitOutput + ", "
EndIf
EndIf
output = unitOutput + output
If Len(num) > 3
num = Left(num, Len(num) - 3)
unit + 1
Else
Break ;exit loop
EndIf
ForEver
If IsNegative
output = "negative " + output
EndIf
ProcedureReturn output
EndProcedure
Define n$ If OpenConsole()
Repeat
Repeat
Print("Give me an integer (or q to quit)! ")
n$ = Input()
Until n$ <> ""
If Left(Trim(n$),1) = "q"
Break ;exit loop
EndIf
PrintN(numberWords(n$))
ForEver
CloseConsole()
EndIf </lang> Sample output:
Give me an integer (or q to quit)! 3 three Give me an integer (or q to quit)! -1327 negative one thousand, three hundred twenty-seven Give me an integer (or q to quit)! 0 zero Give me an integer (or q to quit)! 100000000002000000000000000300000000000000004 one hundred tredecillion, two decillion, three hundred quadrillion, four
Python
Note: This example is also used as a module in the Names to numbers#Python task and should be kept in-sync.
<lang python>TENS = [None, None, "twenty", "thirty", "forty",
"fifty", "sixty", "seventy", "eighty", "ninety"]
SMALL = ["zero", "one", "two", "three", "four", "five",
"six", "seven", "eight", "nine", "ten", "eleven",
"twelve", "thirteen", "fourteen", "fifteen",
"sixteen", "seventeen", "eighteen", "nineteen"]
HUGE = [None, None] + [h + "illion"
for h in ("m", "b", "tr", "quadr", "quint", "sext",
"sept", "oct", "non", "dec")]
def nonzero(c, n, connect=):
return "" if n == 0 else connect + c + spell_integer(n)
def last_and(num):
if ',' in num:
pre, last = num.rsplit(',', 1)
if ' and ' not in last:
last = ' and' + last
num = .join([pre, ',', last])
return num
def big(e, n):
if e == 0:
return spell_integer(n)
elif e == 1:
return spell_integer(n) + " thousand"
else:
return spell_integer(n) + " " + HUGE[e]
def base1000_rev(n):
# generates the value of the digits of n in base 1000
# (i.e. 3-digit chunks), in reverse.
while n != 0:
n, r = divmod(n, 1000)
yield r
def spell_integer(n):
if n < 0:
return "minus " + spell_integer(-n)
elif n < 20:
return SMALL[n]
elif n < 100:
a, b = divmod(n, 10)
return TENS[a] + nonzero("-", b)
elif n < 1000:
a, b = divmod(n, 100)
return SMALL[a] + " hundred" + nonzero(" ", b, ' and')
else:
num = ", ".join([big(e, x) for e, x in
enumerate(base1000_rev(n)) if x][::-1])
return last_and(num)
if __name__ == '__main__':
# examples
for n in (0, -3, 5, -7, 11, -13, 17, -19, 23, -29):
print('%+4i -> %s' % (n, spell_integer(n)))
print()
n = 201021002001
while n:
print('%-12i -> %s' % (n, spell_integer(n)))
n //= -10
print('%-12i -> %s' % (n, spell_integer(n)))
print()</lang>
- Output:
+0 -> zero -3 -> minus three +5 -> five -7 -> minus seven +11 -> eleven -13 -> minus thirteen +17 -> seventeen -19 -> minus nineteen +23 -> twenty-three -29 -> minus twenty-nine 201021002001 -> two hundred and one billion, twenty-one million, two thousand, and one -20102100201 -> minus twenty billion, one hundred and two million, one hundred thousand, two hundred and one 2010210020 -> two billion, ten million, two hundred and ten thousand, and twenty -201021002 -> minus two hundred and one million, twenty-one thousand, and two 20102100 -> twenty million, one hundred and two thousand, and one hundred -2010210 -> minus two million, ten thousand, two hundred and ten 201021 -> two hundred and one thousand, and twenty-one -20103 -> minus twenty thousand, one hundred and three 2010 -> two thousand, and ten -201 -> minus two hundred and one 20 -> twenty -2 -> minus two 0 -> zero
Racket
<lang Racket>
- lang racket
(define smalls
(map symbol->string
'(zero one two three four five six seven eight nine ten eleven twelve
thirteen fourteen fifteen sixteen seventeen eighteen nineteen)))
(define tens
(map symbol->string
'(zero ten twenty thirty forty fifty sixty seventy eighty ninety)))
(define larges
(map symbol->string
'(thousand million billion trillion quadrillion quintillion sextillion
septillion octillion nonillion decillion undecillion duodecillion
tredecillion quattuordecillion quindecillion sexdecillion
septendecillion octodecillion novemdecillion vigintillion)))
(define (integer->english n)
(define (step div suffix separator [subformat integer->english])
(define-values [q r] (quotient/remainder n div))
(define S (if suffix (~a (subformat q) " " suffix) (subformat q)))
(if (zero? r) S (~a S separator (integer->english r))))
(cond [(< n 0) (~a "negative " (integer->english (- n)))]
[(< n 20) (list-ref smalls n)]
[(< n 100) (step 10 #f "-" (curry list-ref tens))]
[(< n 1000) (step 100 "hundred" " and ")]
[else (let loop ([N 1000000] [D 1000] [unit larges])
(cond [(null? unit)
(error 'integer->english "number too big: ~e" n)]
[(< n N) (step D (car unit) ", ")]
[else (loop (* 1000 N) (* 1000 D) (cdr unit))]))]))
(for ([n 10])
(define e (expt 10 n)) (define r (+ (* e (random e)) (random e))) (printf "~s: ~a\n" r (integer->english r)))
</lang>
Sample output:
0: zero 46: forty-six 969: nine hundred and sixty-nine 959365: nine hundred and fifty-nine thousand, three hundred and sixty-five 49561453: forty-nine million, five hundred and sixty-one thousand, four hundred and fifty-three 3372839576: three billion, three hundred and seventy-two million, eight hundred and thirty-nine thousand, five hundred and seventy-six 589723344094: five hundred and eighty-nine billion, seven hundred and twenty-three million, three hundred and forty-four thousand, ninety-four 76114840325710: seventy-six trillion, one hundred and fourteen billion, eight hundred and forty million, three hundred and twenty-five thousand, seven hundred and ten 7555965500511815: seven quadrillion, five hundred and fifty-five trillion, nine hundred and sixty-five billion, five hundred million, five hundred and eleven thousand, eight hundred and fifteen 225539847375452743: two hundred and twenty-five quadrillion, five hundred and thirty-nine trillion, eight hundred and forty-seven billion, three hundred and seventy-five million, four hundred and fifty-two thousand, seven hundred and forty-three
See also numspell by Neil van Dyke.
REXX
See Number names/REXX.
Ruby
<lang ruby>SMALL = %w(zero one two three four five six seven eight nine ten
eleven twelve thirteen fourteen fifteen sixteen seventeen
eighteen nineteen)
TENS = %w(wrong wrong twenty thirty forty fifty sixty seventy
eighty ninety)
BIG = [nil, "thousand"] +
%w( m b tr quadr quint sext sept oct non dec).map{ |p| "#{p}illion" }
def wordify number
if number < 0
"negative #{wordify -number}"
elsif number < 20 SMALL[number]
elsif number < 100
div, mod = number.divmod(10)
"#{TENS[div]}-#{wordify mod}".chomp("-zero")
elsif number < 1000
div, mod = number.divmod(100)
"#{wordify div} hundred and #{wordify mod}".chomp(" and zero")
else
# separate into 3-digit chunks
chunks = []
div = number
while div != 0
div, mod = div.divmod(1000)
chunks << mod # will store smallest to largest
end
if chunks.length > BIG.length
raise ArgumentError, "Integer value too large."
end
chunks.map{ |c| wordify c }.
zip(BIG). # zip pairs up corresponding elements from the two arrays
find_all { |c| c[0] != 'zero' }.
map{ |c| c.join ' '}. # join ["forty", "thousand"]
reverse.
join(', '). # join chunks
strip
end
end
[-1123, 0, 1, 20, 123, 200, 220, 1245, 2000, 2200, 2220, 467889, 23_000_467,
23_234_467, 2_235_654_234, 12_123_234_543_543_456,
123890812938219038290489327894327894723897432].each do |n|
print "#{n}: "
begin
puts "'#{wordify n}'"
rescue => e
puts "Error: #{e}"
end
end</lang>
-1123: 'negative one thousand, one hundred and twenty-three' 0: 'zero' 1: 'one' 20: 'twenty' 123: 'one hundred and twenty-three' 200: 'two hundred' 220: 'two hundred and twenty' 1245: 'one thousand, two hundred and forty-five' 2000: 'two thousand' 2200: 'two thousand, two hundred' 2220: 'two thousand, two hundred and twenty' 467889: 'four hundred and sixty-seven thousand, eight hundred and eighty-nine' 23000467: 'twenty-three million, four hundred and sixty-seven' 23234467: 'twenty-three million, two hundred and thirty-four thousand, four hundred and sixty-seven' 2235654234: 'two billion, two hundred and thirty-five million, six hundred and fifty-four thousand, two hundred and thirty-four' 12123234543543456: 'twelve quadrillion, one hundred and twenty-three trillion, two hundred and thirty-four billion, five hundred and forty-three million, five hundred and forty-three thousand, four hundred and fifty-six' 123890812938219038290489327894327894723897432: Error: Integer value too large.
Scala
<lang scala>package org.rosettacode package numbernames
import scala.annotation.tailrec import scala.collection.parallel.ParSeq
/** Spells a English numeral longhand. The numbers are expressed using words.
* * The implementation goes up to 1069-1 and also supports negative and zero inputs. * * @example longhand( 1234 ) // results in: "one thousand two hundred thirty-four". */
trait LongHand {
/** Spells a number longhand
*
* Done by recursively process the triplets of decimal numbers.
* @param numeral the numeric value to be converted
* @param showAnd flag the output extra and in output, default off
* @param zeroString the word for 0, default to "zero"
* @param showHyphen hyphenate all compound numbers e.g. twenty-four, default is on
* @return the numeric value in words
*/
def longhand(numeral: BigInt,
zeroString: String = "zero",
showAnd: Boolean = false,
showHyphen: Boolean = true): String = {
val condAndString = if (showAnd) "and " else "" val condHyphenString = if (showHyphen) "-" else " "
// 234 Becomes "two hundred [and] thirty-four"
def composeScale(nnn: String, isLSDgroup: Boolean, strE3: String): String = {
nnn match { // Rare exceptions confirms the rule
case "000" => ""
case "100" => onesAndTeens(1) + hundredString + strE3 // Solves the faulty hundred AND thousand problem
case _ => {
val eval = (nnn.par.map(_.toString.toInt).reverse zip ParSeq('units, 'tens, 'hundreds)).reverse
eval.map {
case (d, 'units) if eval.seq.contains((1, 'tens)) => onesAndTeens(d + 10)
case (d, 'units) if (isLSDgroup && nnn == "0") => zeroString
case (d, 'units) => onesAndTeens(d)
case (d, 'hundreds) if d > 0 => onesAndTeens(d) + hundredString + condAndString
case (d, 'tens) if d > 1 && eval.seq.contains((0, 'units)) => tens(d)
case (d, 'tens) if d > 1 => tens(d) + condHyphenString //'
case _ => ""
}.mkString + strE3
}
}
} // def composeScale(…
def compose(n: BigInt): String = {
// "1234" becomes List((1,"thousand"), (234, ""))
val decGroups = n.toString.reverse.grouped(3).map(_.reverse).toSeq.par // Group into powers of thousands
.zip(shortScale) // // Name the powers of Thousands
.reverse // // Put it back to most-significant first
if (decGroups.size < 24) // Detect overflow trap
{ // Send per group sections to composeScale
@tailrec
def iter(elems: Seq[(String, String)], acc: String): String = {
elems match {
case (group, powers) :: tail => {
iter(tail, acc + composeScale(group, tail == Nil, powers))
}
case _ => acc
}
}
iter(decGroups.toList, "").mkString.trim
} else "###.overflow.###"
} // def compose(…
// Here starts def longhand(… if (numeral < 0) "minus " + compose(-numeral) else compose(numeral) } // End def longhand(… @ 91 lines
val onesAndTeens = {
def lowNumerals = "one two three four five six seven eight nine ten eleven twelve".split(' ').map(_ + " ")
def tenties = "thir four fif six seven eigh nine".split(' ').map(_ + "teen ")
ParSeq("") ++ lowNumerals ++ tenties
}
val tens = (Array[String]("", "") ++ ("twen thir for fif six seven eigh nine".split(' ')).
map(_ + "ty")).par
def hundredString = "hundred "
lazy val shortScale = {
def p1 = "m b tr quadr quint sext sept oct non dec".split(' ').map(_ + "illion ").par
def p2 = "un duo tre quattuor quin sex septen octo novem ".split(' ').map(_ + "decillion ").par
def p3 = ("vigint cent".split(' ').map(_ + "illion ") :+ "overflow trap").par
ParSeq("", "thousand ") ++ p1 ++ p2 ++ p3
}
} // trait LongHand
object SpellNumber extends LongHand with App {
// Main entry A little test...
{ // Anonymous ordered list as test set
def testVal1 = BigInt("1" * 69)
def testVal9 = BigInt(10).pow(69) - 1
@tailrec // Series generator of 9, 98, 987, 9876 …
def inner(counter: Int, elem: BigInt, testList: ParSeq[BigInt]): ParSeq[BigInt] = {
if (counter < 20)
inner(counter + 1, elem * 10 + (9 - (counter % 10)), testList ++ ParSeq(elem))
else testList.par
}
inner(0, 0L, // Test values
ParSeq(-Long.MaxValue, -1000000000, 12, 13, 19, 20, 21, 112, 1001, 1012, 1013,
Long.MaxValue - 1, Long.MaxValue - 13, testVal1, testVal9)) ++
(for (z <- 0 to 69) yield BigInt(10).pow(z)) // powers of ten
}.seq.sorted.foreach(num => println(f"$num%+,80d -> ${longhand(numeral = num, showAnd = true)}"))
} // object SpellNumber @ line 110</lang>
- Output:
-9.223.372.036.854.775.807 -> minus nine quintillion two hundred and twenty-three quadrillion three hundred and seventy-two trillion thirty-six billion eight hundred and fifty-four million seven hundred and seventy-five thousand eight hundred and seven
-1.000.000.000 -> minus one billion
+0 -> zero
+1 -> one
+9 -> nine
+10 -> ten
+12 -> twelve
+13 -> thirteen
+19 -> nineteen
+20 -> twenty
+21 -> twenty-one
+98 -> ninety-eight
+100 -> one hundred
+112 -> one hundred and twelve
+987 -> nine hundred and eighty-seven
+1.000 -> one thousand
+1.001 -> one thousand one
+1.012 -> one thousand twelve
+1.013 -> one thousand thirteen
+9.876 -> nine thousand eight hundred and seventy-six
+10.000 -> ten thousand
+98.765 -> ninety-eight thousand seven hundred and sixty-five
+100.000 -> one hundred thousand
+987.654 -> nine hundred and eighty-seven thousand six hundred and fifty-four
+1.000.000 -> one million
+9.876.543 -> nine million eight hundred and seventy-six thousand five hundred and forty-three
+10.000.000 -> ten million
+98.765.432 -> ninety-eight million seven hundred and sixty-five thousand four hundred and thirty-two
+100.000.000 -> one hundred million
+987.654.321 -> nine hundred and eighty-seven million six hundred and fifty-four thousand three hundred and twenty-one
+1.000.000.000 -> one billion
+9.876.543.210 -> nine billion eight hundred and seventy-six million five hundred and forty-three thousand two hundred and ten
+10.000.000.000 -> ten billion
+98.765.432.109 -> ninety-eight billion seven hundred and sixty-five million four hundred and thirty-two thousand one hundred and nine
+100.000.000.000 -> one hundred billion
+987.654.321.098 -> nine hundred and eighty-seven billion six hundred and fifty-four million three hundred and twenty-one thousand ninety-eight
+1.000.000.000.000 -> one trillion
+9.876.543.210.987 -> nine trillion eight hundred and seventy-six billion five hundred and forty-three million two hundred and ten thousand nine hundred and eighty-seven
+10.000.000.000.000 -> ten trillion
+98.765.432.109.876 -> ninety-eight trillion seven hundred and sixty-five billion four hundred and thirty-two million one hundred and nine thousand eight hundred and seventy-six
+100.000.000.000.000 -> one hundred trillion
+987.654.321.098.765 -> nine hundred and eighty-seven trillion six hundred and fifty-four billion three hundred and twenty-one million ninety-eight thousand seven hundred and sixty-five
+1.000.000.000.000.000 -> one quadrillion
+9.876.543.210.987.654 -> nine quadrillion eight hundred and seventy-six trillion five hundred and forty-three billion two hundred and ten million nine hundred and eighty-seven thousand six hundred and fifty-four
+10.000.000.000.000.000 -> ten quadrillion
+98.765.432.109.876.543 -> ninety-eight quadrillion seven hundred and sixty-five trillion four hundred and thirty-two billion one hundred and nine million eight hundred and seventy-six thousand five hundred and forty-three
+100.000.000.000.000.000 -> one hundred quadrillion
+987.654.321.098.765.432 -> nine hundred and eighty-seven quadrillion six hundred and fifty-four trillion three hundred and twenty-one billion ninety-eight million seven hundred and sixty-five thousand four hundred and thirty-two
+1.000.000.000.000.000.000 -> one quintillion
+9.223.372.036.854.775.794 -> nine quintillion two hundred and twenty-three quadrillion three hundred and seventy-two trillion thirty-six billion eight hundred and fifty-four million seven hundred and seventy-five thousand seven hundred and ninety-four
+9.223.372.036.854.775.806 -> nine quintillion two hundred and twenty-three quadrillion three hundred and seventy-two trillion thirty-six billion eight hundred and fifty-four million seven hundred and seventy-five thousand eight hundred and six
+9.876.543.210.987.654.321 -> nine quintillion eight hundred and seventy-six quadrillion five hundred and forty-three trillion two hundred and ten billion nine hundred and eighty-seven million six hundred and fifty-four thousand three hundred and twenty-one
+10.000.000.000.000.000.000 -> ten quintillion
+100.000.000.000.000.000.000 -> one hundred quintillion
+1.000.000.000.000.000.000.000 -> one sextillion
+10.000.000.000.000.000.000.000 -> ten sextillion
+100.000.000.000.000.000.000.000 -> one hundred sextillion
+1.000.000.000.000.000.000.000.000 -> one septillion
+10.000.000.000.000.000.000.000.000 -> ten septillion
+100.000.000.000.000.000.000.000.000 -> one hundred septillion
+1.000.000.000.000.000.000.000.000.000 -> one octillion
+10.000.000.000.000.000.000.000.000.000 -> ten octillion
+100.000.000.000.000.000.000.000.000.000 -> one hundred octillion
+1.000.000.000.000.000.000.000.000.000.000 -> one nonillion
+10.000.000.000.000.000.000.000.000.000.000 -> ten nonillion
+100.000.000.000.000.000.000.000.000.000.000 -> one hundred nonillion
+1.000.000.000.000.000.000.000.000.000.000.000 -> one decillion
+10.000.000.000.000.000.000.000.000.000.000.000 -> ten decillion
+100.000.000.000.000.000.000.000.000.000.000.000 -> one hundred decillion
+1.000.000.000.000.000.000.000.000.000.000.000.000 -> one undecillion
+10.000.000.000.000.000.000.000.000.000.000.000.000 -> ten undecillion
+100.000.000.000.000.000.000.000.000.000.000.000.000 -> one hundred undecillion
+1.000.000.000.000.000.000.000.000.000.000.000.000.000 -> one duodecillion
+10.000.000.000.000.000.000.000.000.000.000.000.000.000 -> ten duodecillion
+100.000.000.000.000.000.000.000.000.000.000.000.000.000 -> one hundred duodecillion
+1.000.000.000.000.000.000.000.000.000.000.000.000.000.000 -> one tredecillion
+10.000.000.000.000.000.000.000.000.000.000.000.000.000.000 -> ten tredecillion
+100.000.000.000.000.000.000.000.000.000.000.000.000.000.000 -> one hundred tredecillion
+1.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000 -> one quattuordecillion
+10.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000 -> ten quattuordecillion
+100.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000 -> one hundred quattuordecillion
+1.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000 -> one quindecillion
+10.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000 -> ten quindecillion
+100.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000 -> one hundred quindecillion
+1.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000 -> one sexdecillion
+10.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000 -> ten sexdecillion
+100.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000 -> one hundred sexdecillion
+1.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000 -> one septendecillion
+10.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000 -> ten septendecillion
+100.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000 -> one hundred septendecillion
+1.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000 -> one octodecillion
+10.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000 -> ten octodecillion
+100.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000 -> one hundred octodecillion
+1.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000 -> one novemdecillion
+10.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000 -> ten novemdecillion
+100.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000 -> one hundred novemdecillion
+1.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000 -> one vigintillion
+10.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000 -> ten vigintillion
+100.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000 -> one hundred vigintillion
+1.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000 -> one centillion
+10.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000 -> ten centillion
+100.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000 -> one hundred centillion
+111.111.111.111.111.111.111.111.111.111.111.111.111.111.111.111.111.111.111.111.111.111.111 -> one hundred and eleven centillion one hundred and eleven vigintillion one hundred and eleven novemdecillion one hundred and eleven octodecillion one hundred and eleven septendecillion one hundred and eleven sexdecillion one hundred and eleven quindecillion one hundred and eleven quattuordecillion one hundred and eleven tredecillion one hundred and eleven duodecillion one hundred and eleven undecillion one hundred and eleven decillion one hundred and eleven nonillion one hundred and eleven octillion one hundred and eleven septillion one hundred and eleven sextillion one hundred and eleven quintillion one hundred and eleven quadrillion one hundred and eleven trillion one hundred and eleven billion one hundred and eleven million one hundred and eleven thousand one hundred and eleven
+999.999.999.999.999.999.999.999.999.999.999.999.999.999.999.999.999.999.999.999.999.999.999 -> nine hundred and ninety-nine centillion nine hundred and ninety-nine vigintillion nine hundred and ninety-nine novemdecillion nine hundred and ninety-nine octodecillion nine hundred and ninety-nine septendecillion nine hundred and ninety-nine sexdecillion nine hundred and ninety-nine quindecillion nine hundred and ninety-nine quattuordecillion nine hundred and ninety-nine tredecillion nine hundred and ninety-nine duodecillion nine hundred and ninety-nine undecillion nine hundred and ninety-nine decillion nine hundred and ninety-nine nonillion nine hundred and ninety-nine octillion nine hundred and ninety-nine septillion nine hundred and ninety-nine sextillion nine hundred and ninety-nine quintillion nine hundred and ninety-nine quadrillion nine hundred and ninety-nine trillion nine hundred and ninety-nine billion nine hundred and ninety-nine million nine hundred and ninety-nine thousand nine hundred and ninety-nine
+1.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000.000 -> ###.overflow.###
Seed7
The library wrinum.s7i contains the function str(ENGLISH, ...) which converts an integer to its written english equivalent.
<lang seed7>$ include "seed7_05.s7i";
include "stdio.s7i"; include "wrinum.s7i";
const proc: main is func
local
var integer: number is 0;
begin
for number range 1 to 999999 do
writeln(str(ENGLISH, number));
end for;
end func;</lang>
Tcl
<lang tcl>proc int2words {n} {
if { ! [regexp -- {^(-?\d+)$} $n -> n]} {
error "not a decimal integer"
}
if {$n == 0} {
return zero
}
if {$n < 0} {
return "negative [int2words [expr {abs($n)}]]"
}
if {[string length $n] > 36} {
error "value too large to represent"
}
set groups [get_groups $n]
set l [llength $groups]
foreach group $groups {
incr l -1
# ensure any group with a leading zero is not treated as octal
set val [scan $group %d]
if {$val > 0} {
lappend result [group2words $val $l]
}
}
return [join $result ", "]
}
set small {"" one two three four five six seven eight nine ten eleven twelve
thirteen fourteen fifteen sixteen seventeen eighteen nineteen}
set tens {"" "" twenty thirty forty fifty sixty seventy eighty ninety} set powers {"" thousand} foreach p {m b tr quadr quint sext sept oct non dec} {lappend powers ${p}illion}
proc group2words {n level} {
global small tens powers
if {$n < 20} {
lappend result [lindex $small $n]
} elseif {$n < 100} {
lassign [divmod $n 10] a b
set result [lindex $tens $a]
if {$b > 0} {
append result - [lindex $small $b]
}
} else {
lassign [divmod $n 100] a b
lappend result [lindex $small $a] hundred
if {$b > 0} {
lappend result and [group2words $b 0]
}
}
return [join [concat $result [lindex $powers $level]]]
}
proc divmod {n d} {
return [list [expr {$n / $d}] [expr {$n % $d}]]
}
proc get_groups {num} {
# from http://wiki.tcl.tk/5000 while {[regsub {^([-+]?\d+)(\d\d\d)} $num {\1 \2} num]} {} return [split $num]
}
foreach test {
0 -0 5 -5 10 25 99 100 101 999 1000 1008 1010 54321 1234567890
0x7F
123456789012345678901234567890123456
1234567890123456789012345678901234567
} {
catch {int2words $test} result
puts "$test -> $result"
}</lang> produces
0 -> zero -0 -> zero 5 -> five -5 -> negative five 10 -> ten 25 -> twenty-five 99 -> ninety-nine 100 -> one hundred 101 -> one hundred and one 999 -> nine hundred and ninety-nine 1000 -> one thousand 1008 -> one thousand, eight 1010 -> one thousand, ten 54321 -> fifty-four thousand, three hundred and twenty-one 1234567890 -> one billion, two hundred and thirty-four million, five hundred and sixty-seven thousand, eight hundred and ninety 0x7F -> not a decimal integer 123456789012345678901234567890123456 -> one hundred and twenty-three decillion, four hundred and fifty-six nonillion, seven hundred and eighty-nine octillion, twelve septillion, three hundred and forty-five sextillion, six hundred and seventy-eight quintillion, nine hundred and one quadrillion, two hundred and thirty-four trillion, five hundred and sixty-seven billion, eight hundred and ninety million, one hundred and twenty-three thousand, four hundred and fifty-six 1234567890123456789012345678901234567 -> value too large to represent
Visual Basic
If one were to use variants further and get them to play nice as Decimal, this could theoretically be extended up to the octillion range.
<lang vb>Option Explicit
Private small As Variant, tens As Variant, big As Variant
Sub Main()
small = Array("one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", _
"eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", _
"eighteen", "nineteen")
tens = Array("twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety")
big = Array("thousand", "million", "billion")
Dim tmpInt As Long
tmpInt = Val(InputBox("Gimme a number!", "NOW!", Trim$(Year(Now)) & IIf(Month(Now) < 10, "0", "") & _
Trim$(Month(Now)) & IIf(Day(Now) < 10, "0", "") & Trim$(Day(Now))))
MsgBox int2Text$(tmpInt)
End Sub
Function int2Text$(number As Long)
Dim num As Long, outP As String, unit As Integer Dim tmpLng1 As Long
If 0 = number Then
int2Text$ = "zero"
Exit Function
End If
num = Abs(number)
Do
tmpLng1 = num Mod 100
Select Case tmpLng1
Case 1 To 19
outP = small(tmpLng1 - 1) + " " + outP
Case 20 To 99
Select Case tmpLng1 Mod 10
Case 0
outP = tens((tmpLng1 \ 10) - 2) + " " + outP
Case Else
outP = tens((tmpLng1 \ 10) - 2) + "-" + small(tmpLng1 Mod 10) + " " + outP
End Select
End Select
tmpLng1 = (num Mod 1000) \ 100
If tmpLng1 Then
outP = small(tmpLng1 - 1) + " hundred " + outP
End If
num = num \ 1000
If num < 1 Then Exit Do
tmpLng1 = num Mod 1000
If tmpLng1 Then outP = big(unit) + " " + outP
unit = unit + 1 Loop
If number < 0 Then outP = "negative " & outP
int2Text$ = Trim$(outP)
End Function</lang>
Example output (in a msgbox) is identical to the BASIC output.
Visual Basic .NET
Platform: .NET
This solution works for integers up to 1000. It should be fairly ovbious how it works, and so can be extended if needed.
<lang vbnet>Module Module1
Sub Main()
Dim i As Integer
Console.WriteLine("Enter a number")
i = Console.ReadLine()
Console.WriteLine(words(i))
Console.ReadLine()
End Sub
Function words(ByVal Number As Integer) As String
Dim small() As String = {"zero", "one", "two", "three", "four", "five", "six", "seven", "eight",
"nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen",
"eighteen", "nineteen"}
Dim tens() As String = {"", "", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"}
Select Case Number
Case Is < 20
words = small(Number)
Case 20 To 99
words = tens(Number \ 10) + " " + small(Number Mod 10)
Case 100 To 999
words = small(Number \ 100) + " hundred " + IIf(((Number Mod 100) <> 0), "and ", "") + words(Number Mod 100)
Case 1000
words = "one thousand"
End Select
End Function
End Module</lang>
XPL0
<lang XPL0>code ChOut=8, CrLf=9, Text=12;
proc NumName(Dev, Num); \Output integer Num in prose to device Dev int Dev, Num; int OneTbl, TenTbl, ThoTbl, ThoPwr, I, Quot;
proc Out999(N); \Output number in range 0..999 (0 does nothing)
int N;
int Huns, Tens, Ones;
[Huns:= N/100; \0..9
N:= rem(0); \0..99
Tens:= N/10; \0..9
Ones:= rem(0); \0..9
if Huns # 0 then
[Text(Dev, OneTbl(Huns)); \1..9
Text(Dev, " hundred ")];
if Tens >= 2 then
[Text(Dev, TenTbl(Tens));
if Ones # 0 then
[ChOut(Dev, ^-); Text(Dev, OneTbl(Ones))];
]
else if N # 0 then Text(Dev, OneTbl(N)); \N = 1..19
];
[if Num = 0 then [Text(Dev, "zero"); return]; if Num < 0 then [Num:= -Num; Text(Dev, "minus ")];
OneTbl:=[0, "one", "two", "three", "four",
"five", "six", "seven", "eight", "nine",
"ten", "eleven", "twelve", "thirteen", "fourteen",
"fifteen", "sixteen", "seventeen", "eighteen", "nineteen"];
TenTbl:=[0, 0, "twenty", "thirty", "forty",
"fifty", "sixty", "seventy", "eighty", "ninety"];
ThoTbl:=[" billion ", " million ", " thousand "];
ThoPwr:= 1000000000; for I:= 0 to 2 do
[Quot:= Num/ThoPwr;
Num:= rem(0);
if Quot # 0 then
[Out999(Quot); Text(Dev, ThoTbl(I))];
ThoPwr:= ThoPwr/1000;
];
Out999(Num); ];
[NumName(0, 0); CrLf(0); NumName(0, 13); CrLf(0); NumName(0, 789); CrLf(0); NumName(0, -604_001); CrLf(0); NumName(0, 1_000_000); CrLf(0); NumName(0, 1_234_567_890); CrLf(0); ]</lang>
Output:
zero thirteen seven hundred eighty-nine minus six hundred four thousand one one million one billion two hundred thirty-four million five hundred sixty-seven thousand eight hundred ninety
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