Four sides of square
Fill with 1's the four sides of square. The rest of the square should be filled with 0's.
If you can please use GUI
Four sides of square - image
- Task
Ada
<lang Ada>with Ada.Text_Io; with Ada.Command_Line;
procedure Four_Sides is
type Matrix_Type is array (Natural range <>, Natural range <>) of Character;
function Hollow (Length : Natural) return Matrix_Type is
begin
return M : Matrix_Type (1 .. Length, 1 .. Length) do
for Row in M'Range(1) loop
for Col in M'Range (2) loop
M (Row, Col) := (if Row in M'First (1) | M'Last (1) or
Col in M'First (2) | M'Last (2)
then '1' else '0');
end loop;
end loop;
end return;
end Hollow;
procedure Put (M : Matrix_Type) is
begin
for Row in M'Range (1) loop
for Col in M'Range (2) loop
Ada.Text_Io.Put (" ");
Ada.Text_Io.Put (M(Row,Col));
end loop;
Ada.Text_Io.New_Line;
end loop;
end Put;
begin
Put (Hollow (Length => Natural'Value (Ada.Command_Line.Argument (1))));
exception
when others =>
Ada.Text_Io.Put_Line ("Usage: ./four_sides <length>");
end Four_Sides;</lang>
- Output:
$ ./four_sides 4 1 1 1 1 1 0 0 1 1 0 0 1 1 1 1 1 $ ./four_sides 1 1 $ ./four_sides 0 $ ./four_sides 2 1 1 1 1 $ ./four_sides -1 Usage: ./four_sides <length>
ALGOL 68
<lang algol68>BEGIN # draw a matrix with 1s on the edges and 0s elsewhere #
# draws a matrix with height and width = n with 1s on the edges #
PROC draw square = ( INT n )VOID:
FOR i TO n DO
FOR j TO n DO
print( ( " ", whole( ABS ( i = 1 OR i = n OR j = 1 OR j = n ), 0 ) ) )
OD;
print( ( newline ) )
OD # draw square # ;
# test the draw square procedure #
draw square( 6 );
print( ( newline ) );
draw square( 7 )
END </lang>
- Output:
1 1 1 1 1 1 1 0 0 0 0 1 1 0 0 0 0 1 1 0 0 0 0 1 1 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 1 1 0 0 0 0 0 1 1 0 0 0 0 0 1 1 0 0 0 0 0 1 1 0 0 0 0 0 1 1 1 1 1 1 1 1
AWK
<lang AWK>
- syntax: GAWK -f FOUR_SIDES_OF_SQUARE.AWK
BEGIN {
for (n=6; n<=7; n++) {
for (i=1; i<=n; i++) {
for (j=1; j<=n; j++) {
tmp = (i==1 || i==n || j==1 || j==n) ? 1 : 0
printf("%2d",tmp)
}
printf("\n")
}
print("")
}
exit(0)
} </lang>
- Output:
1 1 1 1 1 1 1 0 0 0 0 1 1 0 0 0 0 1 1 0 0 0 0 1 1 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 1 1 0 0 0 0 0 1 1 0 0 0 0 0 1 1 0 0 0 0 0 1 1 0 0 0 0 0 1 1 1 1 1 1 1 1
C
<lang c>#include <stdio.h>
void hollowMatrix(unsigned int n) {
int i, j;
for (i = 0; i < n; ++i) {
for (j = 0; j < n; ++j) {
if (i == 0 || i == n - 1 || j == 0 || j == n - 1) {
printf("%d ", 1);
} else {
printf("%d ", 0);
}
}
printf("\n");
}
}
int main() {
hollowMatrix(10);
printf("\n");
hollowMatrix(11);
return 0;
}</lang>
- Output:
1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 1
C++
<lang cpp>#include <concepts>
- include <iostream>
// Print each element of a matrix according to a predicate. It // will print a '1' if the predicate function is true, otherwise '0'. void PrintMatrix(std::predicate<int, int, int> auto f, int size) {
for(int y = 0; y < size; y++)
{
for(int x = 0; x < size; x++)
{
std::cout << " " << f(x, y, size);
}
std::cout << "\n";
}
std::cout << "\n";
}
int main() {
// a lambda to show the sides
auto fourSides = [](int x, int y, int size)
{
return x == 0 || (y == 0) || (x == size - 1) || (y == size - 1);
};
PrintMatrix(fourSides, 8); PrintMatrix(fourSides, 9);
}
</lang>
- Output:
1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 1 1 0 0 0 0 0 0 1 1 0 0 0 0 0 0 1 1 0 0 0 0 0 0 1 1 0 0 0 0 0 0 1 1 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1
F#
<lang fsharp> // Four sides of square. Nigel Galloway: February 18th., 2022 let m11 m=Array2D.init m m (fun n g->if n=0 || g=0 || g=m-1 || n=m-1 then 1 else 0) printfn "%A\n\n%A" (m11 5) (m11 6) </lang>
- Output:
[[1; 1; 1; 1; 1] [1; 0; 0; 0; 1] [1; 0; 0; 0; 1] [1; 0; 0; 0; 1] [1; 1; 1; 1; 1]] [[1; 1; 1; 1; 1; 1] [1; 0; 0; 0; 0; 1] [1; 0; 0; 0; 0; 1] [1; 0; 0; 0; 0; 1] [1; 0; 0; 0; 0; 1] [1; 1; 1; 1; 1; 1]]
FreeBASIC
Text based
<lang freebasic>Sub hollowMatrix(n As Integer)
For i As Integer = 0 To n
For j As Integer = 0 To n
Print Iif((i = 0) Or (i = n) Or (j = 0) Or (j = n), "1 ", "0 ");
Next j
Print
Next i
End Sub
hollowMatrix(9) Sleep</lang>
- Output:
1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1
Graphical
<lang freebasic>Dim As Integer n = 9, size = 60 * n + 70 Screenres size, size, 24 Cls Windowtitle "Four sides of square"
Dim As Integer beige = Rgb(245, 245, 220), brown = Rgb(171, 82, 54)
For x As Integer = 0 To n
For y As Integer = 0 To n
Dim As Integer cx = x*60 + 10
Dim As Integer cy = y*60 + 10
If (x = 0) Or (x = n) Or (y = 0) Or (y = n) Then
Line (cx,cy) - (cx+50, cy+50), brown, BF
Draw String (cx + 22, cy + 22), "1", 0
Else
Line (cx,cy) - (cx+50, cy+50), beige, BF
Draw String (cx + 22, cy + 22), "0", 0
End If
Next y
Next x Bsave "hollowMatrix.bmp",0 Sleep</lang>
- Output:
https://www.dropbox.com/s/9g5ahfzw1muuzgm/hollowMatrix.bmp?dl=0
Go
<lang go>package main
import "fmt"
func hollowMatrix(n uint) {
for i := uint(0); i < n; i++ {
for j := uint(0); j < n; j++ {
if i == 0 || i == n-1 || j == 0 || j == n-1 {
fmt.Printf("%d ", 1)
} else {
fmt.Printf("%d ", 0)
}
}
fmt.Println()
}
}
func main() {
hollowMatrix(8) fmt.Println() hollowMatrix(9)
}</lang>
- Output:
1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 1 1 0 0 0 0 0 0 1 1 0 0 0 0 0 0 1 1 0 0 0 0 0 0 1 1 0 0 0 0 0 0 1 1 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1
J
Implementation: <lang J>fsosq=: Template:+./~(+.</lang>
Some examples:
<lang J> fsosq 0
fsosq 1
1
fsosq 2
1 1 1 1
fsosq 3
1 1 1 1 0 1 1 1 1
fsosq 4
1 1 1 1 1 0 0 1 1 0 0 1 1 1 1 1
fsosq 10
1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1</lang>
Gui examples are not visible here, but, for example: <lang J> require'viewmat'
viewmat fsosq 20 viewmat fsosq 5</lang>
jq
Works with gojq, the Go implementation of jq <lang jq>def square_perimeter_matrix:
[range(0; .) | 1] as $top | [1, (range(0; .-2) | 0), 1] as $two | [$top, (range(0; .-2)|$two), $top];
def display:
map(join(" ")) | join("\n");</lang>
Example: <lang jq>9|square_perimeter_matrix|display </lang>
- Output:
1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1
Julia
Gtk graphical version. <lang julia>using Gtk
function set_gtk_style!(widget::Gtk.GtkWidget, style::String, value::Int)
sc = Gtk.GAccessor.style_context(widget)
pr = Gtk.CssProviderLeaf(data=" button {$style}")
push!(sc, Gtk.StyleProvider(pr), value)
end
function squareonesapp(N)
win = GtkWindow("Ones Square", 700, 700)
grid = GtkGrid()
buttons = [GtkButton(i == 1 || j == 1 || i == N || j == N ? " 1 " : " 0 ") for i in 1:N, j in 1:N]
for i in 1:N, j in 1:N
grid[i, j] = buttons[i, j]
set_gtk_property!(buttons[i, j], :expand, true)
c = i == 1 || j == 1 || i == N || j == N ? "red" : "navy"
set_gtk_style!(buttons[i, j], " font-size: 32px; background-color: $c ; ", 600)
end
push!(win, grid)
condition = Condition()
endit(w) = notify(condition)
signal_connect(endit, win, :destroy)
showall(win)
wait(condition)
end
squareonesapp(8) </lang>
Perl
<lang perl>use strict; use warnings; use feature 'say';
my $n = 5; say join ' ', @$_ for ([(1)x$n], (map { [1, (0)x($n-2), 1] } 0..$n-3), [(1)x$n]);</lang>
- Output:
1 1 1 1 1 1 0 0 0 1 1 0 0 0 1 1 0 0 0 1 1 1 1 1 1
Phix
See Matrix_with_two_diagonals#Phix and press 'O'.
Python
Procedural
<lang python>size = 9 for Row in range(size):
for Col in range(size):
if (Row == 0 or Row == size-1 or Col == 0 or Col == size-1):
print("1", end=" ")
else:
print("0", end=" ")
print()</lang>
- Output:
See Raku output.
Functional
<lang python>Four sides of a square
- fourSides :: Int -> Int
def fourSides(n):
A square grid with ones in all edge values
and zeros elsewhere.
edge = [1, n]
return matrix(
n, n, lambda row, col: int(
row in edge or col in edge
)
)
- ------------------------- TEST -------------------------
- main :: IO ()
def main():
Square grids of dimension 7 and 10
for n in [7, 10]:
print(
showMatrix(
fourSides(n)
) + '\n'
)
- ----------------------- GENERIC ------------------------
- matrix :: Int -> Int -> ((Int, Int) -> a) -> a
def matrix(nRows, nCols, f):
A matrix of a given number of columns and rows,
in which each value is a given function over the
tuple of its (one-based) row and column indices.
return [
[f(y, x) for x in range(1, 1 + nCols)]
for y in range(1, 1 + nRows)
]
- showMatrix :: a -> String
def showMatrix(rows):
String representation of a matrix
return '\n'.join([
' '.join([str(x) for x in y]) for y in rows
])
- MAIN ---
if __name__ == '__main__':
main()</lang>
- Output:
1 1 1 1 1 1 1 1 0 0 0 0 0 1 1 0 0 0 0 0 1 1 0 0 0 0 0 1 1 0 0 0 0 0 1 1 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1
Raku
This isn't a matrix, especially if it is supposed to be graphical; it's a very small (or extremely low resolution) bitmap.
<lang perl6>sub hollow ($n) { [1 xx $n], |(0 ^..^ $n).map( { [flat 1, 0 xx $n - 2, 1] } ), [1 xx $n] }
.put for hollow 7; put ; .put for hollow 10;</lang>
- Output:
1 1 1 1 1 1 1 1 0 0 0 0 0 1 1 0 0 0 0 0 1 1 0 0 0 0 0 1 1 0 0 0 0 0 1 1 0 0 0 0 0 1 1 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1
Red
<lang rebol>Red[]
view-square: function [size][
matrix: copy [
title "Four sides of a square"
style cell: base 50x50 font-size 20
style one: cell brown font-color beige "1" ; I am not an artist. Please have mercy!
style zero: cell beige font-color brown "0"
]
repeat i size [
either any [i = 1 i = size] [
append matrix append/dup copy [] 'one size
][
row: append/dup copy [] 'zero size
row/1: row/:size: 'one
append matrix row
]
append matrix 'return
]
view matrix
]
view-square 9</lang>
- Output:
https://commons.wikimedia.org/wiki/File:Hollow_matrix_gui.png
Ring
<lang ring>
- Project : Identity Matrix
- Date : 2022/16/02
- Author : Gal Zsolt (~ CalmoSoft ~)
- Email : <calmosoft@gmail.com>
load "stdlib.ring" load "guilib.ring"
size = 9 C_Spacing = 1
C_ButtonBlueStyle = 'border-radius:6px;color:black; background-color: blue' C_ButtonOrangeStyle = 'border-radius:6px;color:black; background-color: orange'
Button = newlist(size,size) LayoutButtonRow = list(size)
app = new qApp {
win = new qWidget() {
setWindowTitle('Identity Matrix') move(500,100) reSize(600,600) winheight = win.height() fontSize = 18 + (winheight / 100)
LayoutButtonMain = new QVBoxLayout()
LayoutButtonMain.setSpacing(C_Spacing) LayoutButtonMain.setContentsmargins(0,0,0,0)
for Row = 1 to size LayoutButtonRow[Row] = new QHBoxLayout() { setSpacing(C_Spacing) setContentsmargins(0,0,0,0) }
for Col = 1 to size
Button[Row][Col] = new QPushButton(win) {
setSizePolicy(1,1)
}
LayoutButtonRow[Row].AddWidget(Button[Row][Col]) next LayoutButtonMain.AddLayout(LayoutButtonRow[Row]) next
LayoutDataRow1 = new QHBoxLayout() { setSpacing(C_Spacing) setContentsMargins(0,0,0,0) }
LayoutButtonMain.AddLayout(LayoutDataRow1)
setLayout(LayoutButtonMain)
show()
}
pBegin()
exec()
}
func pBegin()
for Row = 1 to size
for Col = 1 to size
if Row = 1 or row = size or Col = 1 or Col = size
Button[Row][Col].setStyleSheet(C_ButtonOrangeStyle)
Button[Row][Col].settext("1")
else
Button[Row][Col].setStyleSheet(C_ButtonBlueStyle)
Button[Row][Col].settext("0")
ok
next
next
</lang>
Output image:
Four sides of square
Wren
Text based
<lang ecmascript>var hollowMatrix = Fn.new { |n|
for (i in 0...n) {
for (j in 0...n) {
System.write((i == 0 || i == n-1 || j == 0 || j == n-1) ? "1 " : "0 ")
}
System.print()
}
}
hollowMatrix.call(9)</lang>
- Output:
1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1
Graphical
This is designed to look as close as possible to the Red entry's image so that we don't have to fill up Wikimedia Commons with similar looking images. <lang ecmascript>import "dome" for Window import "graphics" for Canvas, Color, Font class Main {
construct new(n) {
var size = 60 * n + 10
Window.resize(size, size)
Canvas.resize(size, size)
Window.title = "Four sides of a square"
// see Go-fonts page
Font.load("Go-Regular20", "Go-Regular.ttf", 20)
Canvas.font = "Go-Regular20"
var beige = Color.new(245, 245, 220)
Canvas.cls(Color.lightgray)
for (x in 0...n) {
for (y in 0...n) {
var cx = x*60 + 10
var cy = y*60 + 10
if (x == 0 || x == n-1 || y == 0 || y == n-1) {
Canvas.rectfill(cx, cy, 50, 50, Color.brown)
Canvas.print("1", cx + 20, cy + 15, beige)
} else {
Canvas.rectfill(cx, cy, 50, 50, beige)
Canvas.print("0", cx + 20, cy + 15, Color.brown)
}
}
}
}
init() {}
update() {}
draw(alpha) {}
}
var Game = Main.new(9)</lang>
- Output:
Similar to Red entry image.
XPL0
<lang XPL0>proc DrawMat(S); int S, I, J; [for I:= 0 to S-1 do
[for J:= 0 to S-1 do
Text(0, if I>0 & I<S-1 & J>0 & J<S-1 then "0 " else "1 ");
CrLf(0);
];
]; [DrawMat(6); CrLf(0);
DrawMat(7); CrLf(0);
]</lang>
- Output:
1 1 1 1 1 1 1 0 0 0 0 1 1 0 0 0 0 1 1 0 0 0 0 1 1 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 1 1 0 0 0 0 0 1 1 0 0 0 0 0 1 1 0 0 0 0 0 1 1 0 0 0 0 0 1 1 1 1 1 1 1 1