Array length

Determine the amount of elements in an array.
As an example use an array holding the strings 'apple' and 'orange'.

See also

String length

ALGOL 68

<lang algol68># UPB returns the upper bound of an array, LWB the lower bound # []STRING fruits = ( "apple", "orange" ); print( ( ( UPB fruits - LWB fruits ) + 1, newline ) ) # prints 2 #</lang>

AWK

BASIC

<lang basic>DIM X$(1 TO 2) X$(1) = "apple" X$(2) = "orange" PRINT UBOUND(X$) - LBOUND(X$) + 1</lang>

D

<lang d> import std.stdio;

int main() {

   auto fruit = ["apple", "orange"];
   fruit.length.writeln;
   return 0;

} </lang>

EchoLisp

<lang scheme> (length '("apple" "orange")) ;; list

  → 2

(vector-length #("apple" "orange")) ;; vector

  → 2

</lang>

FurryScript

<lang furryscript>THE_LIST( <apple> <orange> ) COUNT[ 0 SW ~| COUNT_STEP# 0 SW SU ] COUNT_STEP[ DR 1 SU ]

`THE_LIST COUNT# +<></lang>

Haskell

<lang Haskell>-- Char -> Int length ["apple", "orange"]</lang>

Java

<lang java>public class ArrayLength {

   public static void main(String[] args) {
       System.out.println(new String[]{"apple", "orange"}.length);
   }

}</lang>

JavaScript

<lang javascript>console.log(['apple', 'orange'].length);</lang>

ooRexx

<lang oorexx> /* REXX */ a = .array~of('apple','orange') say a~size 'elements' Do e over a

 say e
 End

Say "a[2]="a[2]</lang>

Output:

2 elements
apple
orange
a[2]=orange

Perl 6

<lang perl6>say <apple orange>.elems;</lang>

Output:

PHP

<lang php>print count(['apple', 'orange']); // Returns 2</lang>

Python

<lang python>>>> print(len(['apple', 'orange'])) 2 >>> </lang>

Racket

Translation of: EchoLisp

<lang racket>#lang racket/base (length '("apple" "orange")) ;; list (vector-length #("apple" "orange")) ;; vector</lang>

Output:

2
2

REXX

<lang rexx>/* REXX ----------------------------------------------

The compond variable a. implements an array
By convention, a.0 contains the number of elements
---------------------------------------------------*/

a.=0 /* initialize the "array" */ call store 'apple' Call store 'orange' Say 'There are' a.0 'elements in the array:' Do i=1 To a.0

 Say 'Element' i':' a.i
 End

Exit store: Procedure Expose a. z=a.0+1 a.z=arg(1) a.0=z Return</lang>

Output:

There are 2 elements in the array:
Element 1: apple
Element 2: orange