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Append numbers at same position in strings

From Rosetta Code
Append numbers at same position in strings is a draft programming task. It is not yet considered ready to be promoted as a complete task, for reasons that should be found in its talk page.
Task


Let given three list:
list1 = [1,2,3,4,5,6,7,8,9]
list2 = [10,11,12,13,14,15,16,17,18]
list3 = [19,20,21,22,23,24,25,26,27]
Append numbers at same position in strings.
The result should be:
list = [11019,21120,31221,41322,51423,61524,71625,81726,91827]

Ada[edit]

with Ada.Text_Io;
with Ada.Strings.Fixed;
 
procedure Append_Numbers is
 
use Ada.Text_Io, Ada.Strings;
 
type List_Type is array (Positive range <>) of Natural;
 
procedure Put (List : List_Type) is
begin
Put ("[");
for E of List loop
Put (Natural'Image (E));
end loop;
Put ("]");
end Put;
 
List_1 : constant List_Type := ( 1, 2, 3, 4, 5, 6, 7, 8, 9);
List_2 : constant List_Type := (10, 11, 12, 13, 14, 15, 16, 17, 18);
List_3 : constant List_Type := (19, 20, 21, 22, 23, 24, 25, 26, 27);
List  : List_Type (List_1'Range);
begin
for A in List'Range loop
List (A) := Natural'Value
(Fixed.Trim (Natural'Image (List_1 (A)), Left) &
Fixed.Trim (Natural'Image (List_2 (A)), Left) &
Fixed.Trim (Natural'Image (List_3 (A)), Left));
end loop;
 
Put (List); New_Line;
end Append_Numbers;
Output:
[ 11019 21120 31221 41322 51423 61524 71625 81726 91827]

ALGOL 68[edit]

BEGIN # form a list of strings by concatenating numbers from 3 lists #
[]INT list1 = ( 1, 2, 3, 4, 5, 6, 7, 8, 9 )
, list2 = ( 10, 11, 12, 13, 14, 15, 16, 17, 18 )
, list3 = ( 19, 20, 21, 22, 23, 24, 25, 26, 27 )
;
[ LWB list1 : UPB list1 ]STRING result;
FOR i FROM LWB list1 TO UPB list1 DO
result[ i ] := whole( list1[ i ], 0 ) + whole( list2[ i ], 0 ) + whole( list3[ i ], 0 )
OD;
STRING prefix := "[ ";
FOR i FROM LWB result TO UPB result DO
print( ( prefix, result[ i ] ) );
prefix := ", "
OD;
print( ( " ]", newline ) )
END
Output:
[ 11019, 21120, 31221, 41322, 51423, 61524, 71625, 81726, 91827 ]

AutoHotkey[edit]

list1 := [1,2,3,4,5,6,7,8,9]
list2 := [10,11,12,13,14,15,16,17,18]
list3 := [19,20,21,22,23,24,25,26,27]
list4 := []
 
for i, v in list1
list4.Push(v . list2[i] . list3[i])
for i, v in list4
result .= v ", "
MsgBox % "[" trim(result, ", ") "]"
Output:
[11019, 21120, 31221, 41322, 51423, 61524, 71625, 81726, 91827]

AWK[edit]

 
# syntax: GAWK -f APPEND_NUMBERS_AT_SAME_POSITION_IN_STRINGS.AWK
BEGIN {
n1 = split("1,2,3,4,5,6,7,8,9",list1,",")
n2 = split("10,11,12,13,14,15,16,17,18",list2,",")
n3 = split("19,20,21,22,23,24,25,26,27",list3,",")
if (n1 != n2 || n1 != n3) {
print("error: arrays must be same length")
exit(1)
}
for (i=1; i<=n1; i++) {
list[i] = list1[i] list2[i] list3[i]
printf("%s ",list[i])
}
printf("\n")
exit(0)
}
 
Output:
11019 21120 31221 41322 51423 61524 71625 81726 91827

C[edit]

#include<stdio.h>
#include<stdlib.h>
 
int main(void) {
int list[3][9], i;
for(i=0;i<27;i++) list[i/9][i%9]=1+i;
for(i=0;i<9;i++) printf( "%d%d%d ", list[0][i], list[1][i], list[2][i] );
return 0;
}
Output:
11019  21120  31221  41322  51423  61524  71625  81726  91827

Factor[edit]

Works with: Factor version 0.99 2021-06-02
USING: kernel math.parser math.ranges present prettyprint
sequences ;
 
27 [1,b] 9 cut 9 cut [ [ present ] [email protected] 3append dec> ] 3map .
Output:
{ 11019 21120 31221 41322 51423 61524 71625 81726 91827 }

FreeBASIC[edit]

dim as integer list1(1 to 9) = {1,2,3,4,5,6,7,8,9}
dim as integer list2(1 to 9) = {10,11,12,13,14,15,16,17,18}
dim as integer list3(1 to 9) = {19,20,21,22,23,24,25,26,27}
dim as integer catlist(1 to 9)
dim as string temp
 
for i as uinteger = 1 to 9
temp = str(list1(i)) + str(list2(i)) + str(list3(i))
catlist(i) = val(temp)
print catlist(i);" ";
next i
Output:
11019  21120  31221  41322  51423  61524  71625  81726  91827

jq[edit]

Works with: jq

Works with gojq, the Go implementation of jq

def list1 : [ range(1;10) ];
def list2 : [ range(10; 19)];
def list3 : [ range(19; 28) ];
 
[list1, list2, list3]
| transpose
| map( map(tostring) | add | tonumber)
Output:
[11019,21120,31221,41322,51423,61524,71625,81726,91827]


Julia[edit]

list1 = [1,2,3,4,5,6,7,8,9]
list2 = [10,11,12,13,14,15,16,17,18]
list3 = [19,20,21,22,23,24,25,26,27]
 
println([prod(string(n) for n in z) for z in zip(list1, list2, list3)]) # ["11019", "21120", "31221", "41322", "51423", "61524", "71625", "81726", "91827"]
 

Perl[edit]

use strict;
use warnings;
 
my @a = < 1 2 3 4 5 6 7 8 9>;
my @b = <10 11 12 13 14 15 16 17 18>;
my @c = <19 20 21 22 23 24 25 26 27>;
my @d = <1 2 2 2 2 2 2 2 2 >;
my @e = < 9 0 1 2 3 4 5 6 7>;
my @f = (\@a, \@b, \@d, \@e);
 
# for just the three given lists
print $a[$_] . $b[$_] . $c[$_] . ' ' for 0..$#a; print "\n";
 
# for arbitrary number of lists
for my $i (0 .. $#{$f[0]}) {
map {print $f[$_][$i] } 0 .. $#f and print ' '
}
print "\n";
Output:
11019 21120 31221 41322 51423 61524 71625 81726 91827
11019 21120 31221 41322 51423 61524 71625 81726 91827

Phix[edit]

printf(1,"%V%V\n",repeat(apply(apply(true,vslice,{{sq_mul({tagset(9),tagset(18,10),tagset(27,19)},{1e4,1e2,1})},tagset(9)}),sum),2))
Output:
{11019,21120,31221,41322,51423,61524,71625,81726,91827}{11019,21120,31221,41322,51423,61524,71625,81726,91827}

Python[edit]

from functools import reduce
 
list1 = [1, 2, 3, 4, 5, 6, 7, 8, 9]
list2 = [10, 11, 12, 13, 14, 15, 16, 17, 18]
list3 = [19, 20, 21, 22, 23, 24, 25, 26, 27]
 
print(list(
reduce(lambda x, y: x + y, [str(n) for n in z]) for z
in zip(list1, list2, list3)
))
Output:
['11019', '21120', '31221', '41322', '51423', '61524', '71625', '81726', '91827']

Raku[edit]

Not really seeing why we need to show the result twice but that's what the requirement is... ¯\_(ツ)_/¯ (I find myself making that gesture often in response to Calmosofts tasks.)

say [[Z~] [1,2,3,4,5,6,7,8,9], [10,11,12,13,14,15,16,17,18], [19,20,21,22,23,24,25,26,27]] xx 2;
Output:
([11019 21120 31221 41322 51423 61524 71625 81726 91827] [11019 21120 31221 41322 51423 61524 71625 81726 91827])

Ring[edit]

 
load "stdlib.ring"
list1 = [1,2,3,4,5,6,7,8,9]
list2 = [10,11,12,13,14,15,16,17,18]
list3 = [19,20,21,22,23,24,25,26,27]
list = []
 
for n = 1 to len(list1)
str1 = string(list1[n])
str2 = string(list2[n])
str3 = string(list3[n])
str = str1 + str2 + str3
add(list,str)
next
 
showArray(list)
 
func showArray(array)
txt = ""
see "["
for n = 1 to len(array)
txt = txt + array[n] + ","
next
txt = left(txt,len(txt)-1)
txt = txt + "]"
see txt
 
Output:
list = [11019,21120,31221,41322,51423,61524,71625,81726,91827][11019,21120,31221,41322,51423,61524,71625,81726,91827]

Wren[edit]

var list1 = (1..9).toList
var list2 = (10..18).toList
var list3 = (19..27).toList
var list = (0..8).map { |i| 1e4*list1[i] + 100*list2[i] + list3[i] }.toList
System.print(list)
Output:
[11019, 21120, 31221, 41322, 51423, 61524, 71625, 81726, 91827]

XPL0[edit]

intI;forI:=1to9do[IntOut(0,I*10000+(I+9)*100+I+18);ChOut(0,^ )]
Output:
11019 21120 31221 41322 51423 61524 71625 81726 91827