Sorting algorithms/Bogosort: Difference between revisions

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=={{header|J}}==
bogo=: 3 : 0
whilst. -. *./ 2 </\ Ry do. Ry=. (A.~ ?@!@#) y end. Ry
)


=={{header|Fortran}}==
=={{header|Fortran}}==
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[1,2,4,5,7,12,18,23]
[1,2,4,5,7,12,18,23]
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=={{header|J}}==

bogo=: 3 : 0
whilst. -. *./ 2 </\ Ry do. Ry=. (A.~ ?@!@#) y end. Ry
)
=={{header|Java}}==
=={{header|Java}}==
{{works with|Java|1.5+}}
{{works with|Java|1.5+}}

Revision as of 13:58, 23 October 2008

Task
Sorting algorithms/Bogosort
You are encouraged to solve this task according to the task description, using any language you may know.

Bogosort a list of numbers. Bogosort simply shuffles a collection until it is sorted. (read the article on Wikipedia)

Pseudocode:

while not InOrder(list) do Shuffle(list);

C++

The following algorithm actually works for all sequences of comparable types; restricting to lists of integers would not make the code simpler. <cpp>#include <iterator>

  1. include <algorithm>

template<typename ForwardIterator>

void bogosort(ForwardIterator begin, ForwardIterator end)

{

 typedef std::iterator_traits<ForwardIterator>::value_type value_type;
 // if we find two adjacent values where the first is greater than the second, the sequence isn't sorted.
 while (std::adjacent_find(begin, end, std::greater<value_type>()) != end)
   std::random_shuffle(begin, end);

}</cpp> Using the is_sorted function, part of the SGI STL implementation:

Works with: GCC

<cpp>#include <algorithm>

  1. include <ext/algorithm>

template<typename ForwardIterator>

void bogosort(ForwardIterator begin, ForwardIterator end)

{

 while (!__gnu_cxx::is_sorted(begin, end))
   std::random_shuffle(begin, end);

}</cpp>

D

<d>module bogosort ; import std.stdio, std.random ;

bool isSorted(T)(inout T[] a) { // test if a is already sorted

 if(a.length <= 1) return true ; // 1-elemented/empty array is defined as sorted
 for(int i = 1 ; i < a.length ; i++) if(a[i] < a[i-1]) return false ;
 return true ;

}

T[] bogosort(T)(T[] s) {

 while(!isSorted(s)) {
   for(int n = s.length ; n > 1 ; n--) { 
     int i = rand() % n ;        // random shuffling
     T tmp = s[i] ; s[i] = s[n - 1] ; s[n - 1] = tmp ;
   }
 }
 return s ;

}

void main() {

 auto b = [2,7,4,3] ;
 writefln("%s", bogosort(b)) ;
 writefln("%s", b) ;             // sort is in place
 

}</d>

Fortran

Works with: Fortran version 90 and later
MODULE BOGO
IMPLICIT NONE
CONTAINS
  FUNCTION Sorted(a)
    LOGICAL :: Sorted
    INTEGER, INTENT(IN) :: a(:)
    INTEGER :: i

    Sorted = .TRUE.  
    DO i = 1, SIZE(a)-1
      IF(a(i) > a(i+1)) THEN
        Sorted = .FALSE.
        EXIT
      END IF
    END DO
  END FUNCTION Sorted

  SUBROUTINE SHUFFLE(a)
    INTEGER, INTENT(IN OUT) :: a(:)
    INTEGER :: i, rand, temp
    REAL :: x

    DO i = SIZE(a), 1, -1
       CALL RANDOM_NUMBER(x)
       rand = INT(x * i) + 1
       temp = a(rand)
       a(rand) = a(i)
       a(i) = temp
    END DO
  END SUBROUTINE
END MODULE

PROGRAM BOGOSORT

  USE BOGO
  IMPLICIT NONE
  INTEGER :: iter = 0
  INTEGER :: array(8) = (/2, 7, 5, 3, 4, 8, 6, 1/)
  LOGICAL :: s
 
  DO
    s = Sorted(array)
    IF (s) EXIT
    CALL SHUFFLE(array)
    iter = iter + 1
  END DO
  WRITE (*,*) "Array required", iter, " shuffles to sort"
 
END PROGRAM BOGOSORT

Haskell

import System.Random
import Data.Array.IO
import Control.Monad

isSorted :: (Ord a) => [a] -> Bool
isSorted (e1:e2:r) = e1 <= e2 && isSorted (e2:r)
isSorted _         = True

-- Plagiarized from http://www.haskell.org/haskellwiki/Random_shuffle
shuffle :: [a] -> IO [a]
shuffle xs = do
        ar <- newArray n xs
        forM [1..n] $ \i -> do
            j <- randomRIO (i,n)
            vi <- readArray ar i
            vj <- readArray ar j
            writeArray ar j vi
            return vj
  where
    n = length xs
    newArray :: Int -> [a] -> IO (IOArray Int a)
    newArray n xs =  newListArray (1,n) xs

bogosort :: (Ord a) => [a] -> IO [a]
bogosort li | isSorted li = return li
            | otherwise   = shuffle li >>= bogosort

Example:

*Main> bogosort [7,5,12,1,4,2,23,18]
[1,2,4,5,7,12,18,23]

J

bogo=: 3 : 0
whilst. -. *./ 2 </\ Ry  do. Ry=. (A.~ ?@!@#) y  end. Ry
)

Java

Works with: Java version 1.5+

This implementation works for all comparable types (types with compareTo defined). <java>import java.util.Collections; import java.util.List; import java.util.Iterator;

public class Bogosort {

   private static <T extends Comparable<? super T>> boolean isSorted(List<T> list) {
       if (list.isEmpty())
           return true;
       Iterator<T> it = list.iterator();
       T last = it.next();
       while (it.hasNext()) {
           T current = it.next();
           if (last.compareTo(current) > 0)
               return false;
           last = current;
       }
       return true;
   }
   public static <T extends Comparable<? super T>> void bogoSort(List<T> list) {
       while (!isSorted(list))
           Collections.shuffle(list);
   }

}</java>

Oberon-2

Works with Oxford Oberon-2 Compiler.

MODULE Bogo;

   IMPORT Out, Random;

   VAR a: ARRAY 10 OF INTEGER;

   PROCEDURE Init;
      VAR i: INTEGER;
   BEGIN
      FOR i := 0 TO LEN(a) - 1 DO
         a[i] := i + 1;
      END;
   END Init;

   PROCEDURE Sorted(VAR a: ARRAY OF INTEGER): BOOLEAN;
      VAR i: INTEGER;
   BEGIN 
      IF LEN(a) <= 1 THEN
         RETURN TRUE;
      END;
      FOR i := 1 TO LEN(a) - 1 DO
         IF (a[i] < a[i - 1]) THEN 
            RETURN FALSE;
         END;
      END;
      RETURN TRUE;
   END Sorted;

   PROCEDURE PrintArray(VAR a: ARRAY OF INTEGER);
      VAR i: INTEGER;
   BEGIN
      FOR i := 0 TO LEN(a) - 1 DO
         Out.Int(a[i], 0);
         Out.String(" ");
      END;
   END PrintArray;

   PROCEDURE Shuffle*(VAR a: ARRAY OF INTEGER);
      VAR n, t, r: INTEGER;
   BEGIN
      FOR n := 0 TO LEN(a) - 1 DO
         r := Random.Roll(n);
         t := a[n];
         a[n] := a[r];
         a[r] := t;
      END;
   END Shuffle;

BEGIN
   Init;
   Shuffle(a);
   WHILE ~Sorted(a) DO
      Shuffle(a);
   END;
   PrintArray(a);
   Out.Ln;
END Bogo.

Init initializes the array as 1..10, then it is shuffled, and then the while loop continually shuffles until Sorted returns true.

OCaml

<ocaml> let rec is_sorted comp = function

| e1 :: e2 :: r -> comp e1 e2 <= 0 && is_sorted comp (e2 :: r)
| _             -> true

(* Fisher-Yates shuffle on lists; uses temp array *) let shuffle l =

 let ar = Array.of_list l in
   for n = Array.length ar - 1 downto 1 do
     let k = Random.int (n+1) in
     let temp = ar.(k) in (* swap ar.(k) and ar.(n) *)
       ar.(k) <- ar.(n);
       ar.(n) <- temp
   done;
   Array.to_list ar

let rec bogosort li =

 if is_sorted compare li then
   li
 else
   bogosort (shuffle li)

</ocaml> Example:

# bogosort [7;5;12;1;4;2;23;18] ;;
- : int list = [1; 2; 4; 5; 7; 12; 18; 23]

Perl

<perl>sub bogosort

{my @l = @_;
 shuffle(\@l) until in_order(@l);
 return @l;}

sub in_order

{my $last = shift(@_);
 foreach (@_)
    {$_ >= $last or return 0;
     $last = $_;}
 return 1;}

sub shuffle

  1. This uses the algorithm described at:
  2. http://en.wikipedia.org/wiki/Fisher-Yates_shuffle#The_modern_algorithm
{our @l; local *l = shift;
   # @l is now an alias of the original argument.
 for (my $n = $#l ; $n ; --$n)
    {my $k = int rand($n + 1);
     @l[$k, $n] = @l[$n, $k] if $k != $n;}}</perl>

Python

<python>import random

def bogosort(l):

   while not in_order(l):
       random.shuffle(l)
   return l

def in_order(l):

   if not l:
       return True
   last = l[0]
   for x in l[1:]:
       if x < last:
           return False
       last = x
   return True</python>

Alternative definition for in_order (Python 2.5) <python>def in_order(l):

   return not l or all( l[i] < l[i+1] for i in range(0,len(l)-1))</python>