# N'th

**N'th**

You are encouraged to solve this task according to the task description, using any language you may know.

Write a function/method/subroutine/... that when given an integer greater than or equal to zero returns a string of the number followed by an apostrophe then the ordinal suffix.

Example returns would include `1'st 2'nd 3'rd 11'th 111'th 1001'st 1012'th`

- Task

Use your routine to show here the output for *at least* the following (inclusive) ranges of integer inputs:
`0..25, 250..265, 1000..1025`

**Note:** apostrophes are now *optional* to allow correct apostrophe-less English.

## Contents

- 1 Ada
- 2 ALGOL 68
- 3 AppleScript
- 4 Applesoft BASIC
- 5 AutoHotkey
- 6 AWK
- 7 Babel
- 8 BaCon
- 9 Batch File
- 10 BBC BASIC
- 11 Befunge
- 12 C
- 13 C++
- 14 C#
- 15 Clojure
- 16 COBOL
- 17 Common Lisp
- 18 D
- 19 Elixir
- 20 ERRE
- 21 FreeBASIC
- 22 F#
- 23 Factor
- 24 Forth
- 25 Fortran
- 26 Gambas
- 27 Go
- 28 Haskell
- 29 Icon and Unicon
- 30 J
- 31 Java
- 32 JavaScript
- 33 jq
- 34 Julia
- 35 Kotlin
- 36 Lua
- 37 Maple
- 38 Mathematica
- 39 MATLAB
- 40 Nim
- 41 OCaml
- 42 Oforth
- 43 PARI/GP
- 44 Pascal
- 45 Perl
- 46 Perl 6
- 47 Phix
- 48 PHP
- 49 PicoLisp
- 50 PL/I
- 51 PowerShell
- 52 Prolog
- 53 Python
- 54 R
- 55 Racket
- 56 REXX
- 57 Ring
- 58 Ruby
- 59 Rust
- 60 Scala
- 61 Seed7
- 62 Set lang
- 63 Sidef
- 64 Sinclair ZX81 BASIC
- 65 SQL
- 66 Swift
- 67 Tcl
- 68 uBasic/4tH
- 69 XLISP
- 70 zkl
- 71 ZX Spectrum Basic

## Ada[edit]

with Ada.Text_IO;

procedure Nth is

function Suffix(N: Natural) return String is

begin

if N mod 10 = 1 and then N mod 100 /= 11 then return "st";

elsif N mod 10 = 2 and then N mod 100 /= 12 then return "nd";

elsif N mod 10 = 3 and then N mod 100 /= 13 then return "rd";

else return "th";

end if;

end Suffix;

procedure Print_Images(From, To: Natural) is

begin

for I in From .. To loop

Ada.Text_IO.Put(Natural'Image(I) & Suffix(I));

end loop;

Ada.Text_IO.New_Line;

end Print_Images;

begin

Print_Images( 0, 25);

Print_Images( 250, 265);

Print_Images(1000, 1025);

end Nth;

- Output:

0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## ALGOL 68[edit]

# PROC to suffix a number with st, nd, rd or th as appropriate #

PROC nth = ( INT number )STRING:

BEGIN

INT number mod 100 = number MOD 100;

# RESULT #

whole( number, 0 )

+ IF number mod 100 >= 10 AND number mod 100 <= 20

THEN

# numbers in the range 10 .. 20 always have "th" #

"th"

ELSE

# not in the range 10 .. 20, suffix is st, nd, rd or th #

# depending on the final digit #

CASE number MOD 10

IN # 1 # "st"

, # 2 # "nd"

, # 3 # "rd"

OUT "th"

ESAC

FI

END; # nth #

# PROC to test nth, displays nth for all numbers in the range from .. to #

PROC test nth = ( INT from, INT to )VOID:

BEGIN

INT test count := 0;

FOR test value FROM from TO to

DO

STRING test result = nth( test value );

print( ( " "[ 1 : 8 - UPB test result ], nth( test value ) ) );

test count +:= 1;

IF test count MOD 8 = 0

THEN

print( ( newline ) )

FI

OD;

print( ( newline ) )

END; # test nth #

main: (

test nth( 0, 25 );

test nth( 250, 265 );

test nth( 1000, 1025 )

)

- Output:

0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## AppleScript[edit]

-- ORDINAL STRINGS -----------------------------------------------------------

-- ordinalString :: Int -> String

on ordinalString(n)

(n as string) & ordinalSuffix(n)

end ordinalString

-- ordinalSuffix :: Int -> String

on ordinalSuffix(n)

set modHundred to n mod 100

if (11 ≤ modHundred) and (13 ≥ modHundred) then

"th"

else

item ((n mod 10) + 1) of ¬

{"th", "st", "nd", "rd", "th", "th", "th", "th", "th", "th"}

end if

end ordinalSuffix

-- TEST ----------------------------------------------------------------------

on run

-- showOrdinals :: [Int] -> [String]

script showOrdinals

on |λ|(lstInt)

map(ordinalString, lstInt)

end |λ|

end script

map(showOrdinals, ¬

map(uncurry(enumFromTo), ¬

[[0, 25], [250, 265], [1000, 1025]]))

end run

-- GENERIC FUNCTIONS ---------------------------------------------------------

-- enumFromTo :: Int -> Int -> [Int]

on enumFromTo(m, n)

if m > n then

set d to -1

else

set d to 1

end if

set lst to {}

repeat with i from m to n by d

set end of lst to i

end repeat

return lst

end enumFromTo

-- map :: (a -> b) -> [a] -> [b]

on map(f, xs)

tell mReturn(f)

set lng to length of xs

set lst to {}

repeat with i from 1 to lng

set end of lst to |λ|(item i of xs, i, xs)

end repeat

return lst

end tell

end map

-- Lift 2nd class handler function into 1st class script wrapper

-- mReturn :: Handler -> Script

on mReturn(f)

if class of f is script then

f

else

script

property |λ| : f

end script

end if

end mReturn

-- uncurry :: Handler (a -> b -> c) -> Script |λ| ((a, b) -> c)

on uncurry(f)

script

on |λ|(xy)

set {x, y} to xy

mReturn(f)'s |λ|(x, y)

end |λ|

end script

end uncurry

- Output:

{{"0th", "1st", "2nd", "3rd", "4th", "5th", "6th", "7th", "8th", "9th", "10th", "11th", "12th", "13th", "14th", "15th", "16th", "17th", "18th", "19th", "20th", "21st", "22nd", "23rd", "24th", "25th"}, {"250th", "251st", "252nd", "253rd", "254th", "255th", "256th", "257th", "258th", "259th", "260th", "261st", "262nd", "263rd", "264th", "265th"}, {"1000th", "1001st", "1002nd", "1003rd", "1004th", "1005th", "1006th", "1007th", "1008th", "1009th", "1010th", "1011th", "1012th", "1013th", "1014th", "1015th", "1016th", "1017th", "1018th", "1019th", "1020th", "1021st", "1022nd", "1023rd", "1024th", "1025th"}}

## Applesoft BASIC[edit]

0 OP = 1

10 FOR N = 0 TO 25 : GOSUB 100 : NEXT

20 FOR N = 250 TO 265 : GOSUB 100 : NEXT

30 FOR N = 1000 TO 1025 : GOSUB 100 : NEXT

40 END

100 GOSUB 200"NTH

110 PRINT NTH$ " ";

120 RETURN

200 M1 = N - INT(N / 10) * 10

210 M2 = N - INT(N / 100) * 100

220 NTH$ = "TH"

230 IF M1 = 1 AND M2 <> 11 THEN NTH$ = "ST"

240 IF M1 = 2 AND M2 <> 12 THEN NTH$ = "ND"

250 IF M1 = 3 AND M2 <> 13 THEN NTH$ = "RD"

260 IF NOT OP THEN NTH$ = "'" + NTH$

270 NTH$ = STR$(N) + NTH$

280 RETURN

- Output:

0'TH 1'ST 2'ND 3'RD 4'TH 5'TH 6'TH 7'TH 8'TH 9'TH 10'TH 11'TH 12'TH 13'TH 14'TH 15'TH 16'TH 17'TH 18'TH 19'TH 20'TH 21'ST 22'ND 23'RD 24'TH 25'TH 250'TH 251'ST 252'ND 253'RD 254'TH 255'TH 256'TH 257'TH 258'TH 259'TH 260'TH 261'ST 262'ND 263'RD 264'TH 265'TH 1000'TH 1001'ST 1002'ND 1003'RD 1004'TH 1005'TH 1006'TH 1007'TH 1008'TH 1009'TH 1010'TH 1011'TH 1012'TH 1013'TH 1014'TH 1015'TH 1016'TH 1017'TH 1018'TH 1019'TH 1020'TH 1021'ST 1022'ND 1023'RD 1024'TH 1025'TH

## AutoHotkey[edit]

for k, v in [[0, 25], [250, 265], [1000, 1025]] {

while v[1] <= v[2] {

Out .= Ordinal(v[1]) " "

v[1]++

}

Out .= "`n"

}

MsgBox, % Out

Ordinal(n) {

s2 := Mod(n, 100)

if (s2 > 10 && s2 < 14)

return n "th"

s1 := Mod(n, 10)

return n (s1 = 1 ? "st" : s1 = 2 ? "nd" : s1 = 3 ? "rd" : "th")

}

- Output:

0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## AWK[edit]

# syntax: GAWK -f NTH.AWK

BEGIN {

prn(0,25)

prn(250,265)

prn(1000,1025)

exit(0)

}

function prn(start,stop, i) {

printf("%d-%d: ",start,stop)

for (i=start; i<=stop; i++) {

printf("%d%s ",i,nth(i))

}

printf("\n")

}

function nth(yearday, nthday) {

if (yearday ~ /1[1-3]$/) { # 11th,12th,13th

nthday = "th"

}

else if (yearday ~ /1$/) { # 1st,21st,31st,etc.

nthday = "st"

}

else if (yearday ~ /2$/) { # 2nd,22nd,32nd,etc.

nthday = "nd"

}

else if (yearday ~ /3$/) { # 3rd,23rd,33rd,etc.

nthday = "rd"

}

else if (yearday ~ /[0456789]$/) { # 4th-10th,20th,24th-30th,etc.

nthday = "th"

}

return(nthday)

}

- Output:

0-25: 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250-265: 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000-1025: 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## Babel[edit]

((irregular ("st" "nd" "rd"))

(main

{(0 250 1000)

{ test ! "\n" << }

each})

(test {

<-

{iter 1 - -> dup <- + ordinalify ! <<

{iter 10 %} {" "} {"\n"} ifte << }

26 times})

(ordinalify {

<-

{{ -> dup <- 100 % 10 cugt } !

{ -> dup <- 100 % 14 cult } !

and not

{ -> dup <- 10 % 0 cugt } !

{ -> dup <- 10 % 4 cult } !

and

and}

{ -> dup

<- %d "'"

irregular -> 10 % 1 - ith

. . }

{ -> %d "'th" . }

ifte }))

- Output:

25'th 24'th 23'rd 22'nd 21'st 20'th 19'th 18'th 17'th 16'th 15'th 14'th 13'th 12'th 11'th 10'th 9'th 8'th 7'th 6'th 5'th 4'th 3'rd 2'nd 1'st 0'th 275'th 274'th 273'rd 272'nd 271'st 270'th 269'th 268'th 267'th 266'th 265'th 264'th 263'rd 262'nd 261'st 260'th 259'th 258'th 257'th 256'th 255'th 254'th 253'rd 252'nd 251'st 250'th 1025'th 1024'th 1023'rd 1022'nd 1021'st 1020'th 1019'th 1018'th 1017'th 1016'th 1015'th 1014'th 1013'th 1012'th 1011'th 1010'th 1009'th 1008'th 1007'th 1006'th 1005'th 1004'th 1003'rd 1002'nd 1001'st 1000'th

## BaCon[edit]

' Nth (sans apostrophes)

FUNCTION nth$(NUMBER n) TYPE STRING

LOCAL suffix

IF n < 0 THEN RETURN STR$(n)

IF MOD(n, 100) >= 11 AND MOD(n, 100) <= 13 THEN

suffix = "th"

ELSE

suffix = MID$("thstndrdthththththth", MOD(n, 10) * 2 + 1, 2)

ENDIF

RETURN CONCAT$(STR$(n), suffix)

END FUNCTION

' Test a few ranges

FOR i = 1 TO 4

READ first, last

per = 1

FOR n = first TO last

PRINT nth$(n) FORMAT "%s "

' limit to 10 entries per line

IF per = 10 OR n = last THEN

per = 1

ELSE

INCR per

ENDIF

NEXT

NEXT

DATA 0, 25, 250, 265, 1000, 1025, -20, -11

- Output:

prompt$ ./nth 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th -20 -19 -18 -17 -16 -15 -14 -13 -12 -11

## Batch File[edit]

@echo off

::Main thing...

call :Nth 0 25

call :Nth 250 265

call :Nth 1000 1025

pause

exit /b

::The subroutine

:Nth <lbound> <ubound>

setlocal enabledelayedexpansion

for /l %%n in (%~1,1,%~2) do (

set curr_num=%%n

set "out=%%nth"

if !curr_num:~-1!==1 (set "out=%%nst")

if !curr_num:~-1!==2 (set "out=%%nnd")

if !curr_num:~-1!==3 (set "out=%%nrd")

set "range_output=!range_output! !out!"

)

echo."!range_output:~1!"

goto :EOF

- Output:

"0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11st 12nd 13rd 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th" "250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th" "1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011st 1012nd 1013rd 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th" Press any key to continue . . .

## BBC BASIC[edit]

PROCNth( 0, 25)

PROCNth( 250, 265)

PROCNth(1000,1025)

END

DEF PROCNth(s%,e%)

LOCAL i%,suff$

FOR i%=s% TO e%

suff$="th"

IF i% MOD 10 = 1 AND i% MOD 100 <> 11 suff$="st"

IF i% MOD 10 = 2 AND i% MOD 100 <> 12 suff$="nd"

IF i% MOD 10 = 3 AND i% MOD 100 <> 13 suff$="rd"

PRINT STR$i%+suff$+" ";

NEXT

ENDPROC

- Output:

## Befunge[edit]

The bottom section of code contains the "subroutine" that calculates the ordinal of a given number; the top section generates the list of values to test.

0>55*:>1-\:0\`!v

#v$#$<^:\+*8"}"_

>35*:>1-\:0\`!v

#v$#$<^:\+*2"}"_

5< v$_v#!::-<0*5

@v <,*>#81#4^# _

>>:0\>:55+%68*v:

tsnr |:/+ 55\+<,

htdd >$>:#,_$:vg

v"d"\*!`3:%+55<9

>%55+/1-!!*:8g,^

- Output:

## C[edit]

#include <stdio.h>

char* addSuffix(int num, char* buf, size_t len)

{

char *suffixes[4] = { "th", "st", "nd", "rd" };

int i;

switch (num % 10)

{

case 1 : i = (num % 100 == 11) ? 0 : 1;

break;

case 2 : i = (num % 100 == 12) ? 0 : 2;

break;

case 3 : i = (num % 100 == 13) ? 0 : 3;

break;

default: i = 0;

};

snprintf(buf, len, "%d%s", num, suffixes[i]);

return buf;

}

int main(void)

{

int i;

printf("Set [0,25]:\n");

for (i = 0; i < 26; i++)

{

char s[5];

printf("%s ", addSuffix(i, s, 5));

}

putchar('\n');

printf("Set [250,265]:\n");

for (i = 250; i < 266; i++)

{

char s[6];

printf("%s ", addSuffix(i, s, 6));

}

putchar('\n');

printf("Set [1000,1025]:\n");

for (i = 1000; i < 1026; i++)

{

char s[7];

printf("%s ", addSuffix(i, s, 7));

}

putchar('\n');

return 0;

}

- Output:

Set [0,25] : 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th Set [250,265] : 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th Set [1000,1025] : 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## C++[edit]

#include <string>

#include <iostream>

using namespace std;

string Suffix(int num)

{

switch (num % 10)

{

case 1 : if(num % 100 != 11) return "st";

break;

case 2 : if(num % 100 != 12) return "nd";

break;

case 3 : if(num % 100 != 13) return "rd";

}

return "th";

}

int main()

{

cout << "Set [0,25]:" << endl;

for (int i = 0; i < 26; i++)

cout << i << Suffix(i) << " ";

cout << endl;

cout << "Set [250,265]:" << endl;

for (int i = 250; i < 266; i++)

cout << i << Suffix(i) << " ";

cout << endl;

cout << "Set [1000,1025]:" << endl;

for (int i = 1000; i < 1026; i++)

cout << i << Suffix(i) << " ";

cout << endl;

return 0;

}

- Output:

Set [0,25] : 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th Set [250,265] : 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th Set [1000,1025] : 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## C#[edit]

class Program

{

private static string Ordinalize(int i)

{

i = Math.Abs(i);

if (new[] {11, 12, 13}.Contains(i%100))

return i + "th";

switch (i%10)

{

case 1:

return i + "st";

case 2:

return i + "nd";

case 3:

return i + "rd";

default:

return i + "th";

}

}

static void Main()

{

Console.WriteLine(string.Join(" ", Enumerable.Range(0, 26).Select(Ordinalize)));

Console.WriteLine(string.Join(" ", Enumerable.Range(250, 16).Select(Ordinalize)));

Console.WriteLine(string.Join(" ", Enumerable.Range(1000, 26).Select(Ordinalize)));

}

}

- Output:

## Clojure[edit]

(defn n-th [n]

(str n

(let [rem (mod n 100)]

(if (and (>= rem 11) (<= rem 13))

"th"

(condp = (mod n 10)

1 "st"

2 "nd"

3 "rd"

"th")))))

(apply str (interpose " " (map n-th (range 0 26))))

(apply str (interpose " " (map n-th (range 250 266))))

(apply str (interpose " " (map n-th (range 1000 1026))))

- Output:

"0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th" "250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th" "1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th"

Alternatively, if you want to print the full ordinal English, it becomes trivial with pprint:

(apply str (interpose " " (map #(clojure.pprint/cl-format nil "~:R" %) (range 0 26))))

- Output:

"zeroth first second third fourth fifth sixth seventh eighth ninth tenth eleventh twelfth thirteenth fourteenth fifteenth sixteenth seventeenth eighteenth nineteenth twentieth twenty-first twenty-second twenty-third twenty-fourth twenty-fifth"

## COBOL[edit]

COBOL stores numbers in decimal form, so there is no need to use a modulo function: the last digit or the last two digits can be extracted directly.

IDENTIFICATION DIVISION.

PROGRAM-ID. NTH-PROGRAM.

DATA DIVISION.

WORKING-STORAGE SECTION.

01 WS-NUMBER.

05 N PIC 9(8).

05 LAST-TWO-DIGITS PIC 99.

05 LAST-DIGIT PIC 9.

05 N-TO-OUTPUT PIC Z(7)9.

05 SUFFIX PIC AA.

PROCEDURE DIVISION.

TEST-PARAGRAPH.

PERFORM NTH-PARAGRAPH VARYING N FROM 0 BY 1 UNTIL N IS GREATER THAN 25.

PERFORM NTH-PARAGRAPH VARYING N FROM 250 BY 1 UNTIL N IS GREATER THAN 265.

PERFORM NTH-PARAGRAPH VARYING N FROM 1000 BY 1 UNTIL N IS GREATER THAN 1025.

STOP RUN.

NTH-PARAGRAPH.

MOVE 'TH' TO SUFFIX.

MOVE N (7:2) TO LAST-TWO-DIGITS.

IF LAST-TWO-DIGITS IS LESS THAN 4,

OR LAST-TWO-DIGITS IS GREATER THAN 20,

THEN PERFORM DECISION-PARAGRAPH.

MOVE N TO N-TO-OUTPUT.

DISPLAY N-TO-OUTPUT WITH NO ADVANCING.

DISPLAY SUFFIX WITH NO ADVANCING.

DISPLAY SPACE WITH NO ADVANCING.

DECISION-PARAGRAPH.

MOVE N (8:1) TO LAST-DIGIT.

IF LAST-DIGIT IS EQUAL TO 1 THEN MOVE 'ST' TO SUFFIX.

IF LAST-DIGIT IS EQUAL TO 2 THEN MOVE 'ND' TO SUFFIX.

IF LAST-DIGIT IS EQUAL TO 3 THEN MOVE 'RD' TO SUFFIX.

Output:

0TH 1ST 2ND 3RD 4TH 5TH 6TH 7TH 8TH 9TH 10TH 11TH 12TH 13TH 14TH 15TH 16TH 17TH 18TH 19TH 20TH 21ST 22ND 23RD 24TH 25TH 250TH 251ST 252ND 253RD 254TH 255TH 256TH 257TH 258TH 259TH 260TH 261ST 262ND 263RD 264TH 265TH 1000TH 1001ST 1002ND 1003RD 1004TH 1005TH 1006TH 1007TH 1008TH 1009TH 1010TH 1011TH 1012TH 1013TH 1014TH 1015TH 1016TH 1017TH 1018TH 1019TH 1020TH 1021ST 1022ND 1023RD 1024TH 1025TH

## Common Lisp[edit]

(defun add-suffix (number)

(let* ((suffixes #10("th" "st" "nd" "rd" "th"))

(last2 (mod number 100))

(last-digit (mod number 10))

(suffix (if (< 10 last2 20)

"th"

(svref suffixes last-digit))))

(format nil "~a~a" number suffix)))

A more concise, albeit less readable version:

(defun add-suffix (n)

(format nil "~d'~:[~[th~;st~;nd~;rd~:;th~]~;th~]" n (< (mod (- n 10) 100) 10) (mod n 10)))

Display the results:

(loop for (low high) in '((0 25) (250 265) (1000 1025))

do (progn

(format t "~a to ~a: " low high)

(loop for n from low to high

do (format t "~a " (add-suffix n))

finally (terpri))))

- Output:

0 to 25: 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250 to 265: 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000 to 1025: 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## D[edit]

import std.stdio, std.string, std.range, std.algorithm;

string nth(in uint n) pure {

static immutable suffix = "th st nd rd th th th th th th".split;

return "%d'%s".format(n, (n % 100 <= 10 || n % 100 > 20) ?

suffix[n % 10] : "th");

}

void main() {

foreach (r; [iota(26), iota(250, 266), iota(1000, 1026)])

writefln("%-(%s %)", r.map!nth);

}

- Output:

0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 25'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th 1025'th

## Elixir[edit]

defmodule RC do

def ordinalize(n) do

num = abs(n)

ordinal = if rem(num, 100) in 4..20 do

"th"

else

case rem(num, 10) do

1 -> "st"

2 -> "nd"

3 -> "rd"

_ -> "th"

end

end

"#{n}#{ordinal}"

end

end

Enum.each([0..25, 250..265, 1000..1025], fn range ->

Enum.map(range, fn n -> RC.ordinalize(n) end) |> Enum.join(" ") |> IO.puts

end)

- Output:

## ERRE[edit]

PROGRAM NTH_SOLVE

!

! for rosettacode.org

!

PROCEDURE NTH(S%,E%)

LOCAL I%,SUFF$

FOR I%=S% TO E% DO

SUFF$="th"

IF I% MOD 10=1 AND I% MOD 100<>11 THEN SUFF$="st" END IF

IF I% MOD 10=2 AND I% MOD 100<>12 THEN SUFF$="nd" END IF

IF I% MOD 10=3 AND I% MOD 100<>13 THEN SUFF$="rd" END IF

PRINT(STR$(I%)+SUFF$+" ";)

END FOR

END PROCEDURE

BEGIN

NTH(0,25)

NTH(250,265)

NTH(1000,1025)

END PROGRAM

- Output:

## FreeBASIC[edit]

' FB 1.05.0 Win64

' Apostrophes NOT used as incorrect English

Function ordinal(n As UInteger) As String

Dim ns As String = Str(n)

Select Case Right(ns, 1)

Case "0", "4" To "9"

Return ns + "th"

Case "1"

If Right(ns, 2) = "11" Then Return ns + "th"

Return ns + "st"

Case "2"

If Right(ns, 2) = "12" Then Return ns + "th"

Return ns + "nd"

Case "3"

If Right(ns, 2) = "13" Then Return ns + "th"

Return ns + "rd"

End Select

End Function

Dim i As Integer

For i = 0 To 25

Print ordinal(i); " ";

Next

Print : Print

For i = 250 To 265

Print ordinal(i); " ";

Next

Print : Print

For i = 1000 To 1025

Print ordinal(i); " ";

Next

Print : Print

Print "Press any key to quit"

Sleep

- Output:

## F#[edit]

open System

let ordinalsuffix n =

let suffixstrings = [|"th"; "st"; "nd"; "rd"|]

let (d, r) = Math.DivRem(n, 10)

n.ToString() + suffixstrings.[ if r < 4 && (d &&& 1) = 0 then r else 0 ]

[<EntryPoint>]

let main argv =

let show = (Seq.iter (ordinalsuffix >> (printf " %s"))) >> (Console.WriteLine)

[0..25] |> show

[250..265] |> show

[1000..1025] |> show

0

- Output:

0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251th 252th 253th 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## Factor[edit]

USING: math kernel combinators math.ranges math.parser

sequences io ;

IN: nth

: tens-digit ( n -- n ) 10 [ /i ] [ mod ] bi ;

: teens? ( n -- ? ) tens-digit 1 = ;

: non-teen-suffix ( n -- str )

10 mod {

{ 1 [ "st" ] }

{ 2 [ "nd" ] }

{ 3 [ "rd" ] }

[ drop "th" ]

} case ;

: ordinal-suffix ( n -- str )

dup teens? [ drop 0 ] when non-teen-suffix ;

: join-suffix ( n -- str ) dup ordinal-suffix

[ number>string ] dip append ;

: main ( -- )

0 25 250 265 1000 1025 [ [a,b] ] [email protected]

[ [ join-suffix ] map ] [email protected]

[ [ bl ] [ write ] interleave nl ] [email protected] ;

MAIN: main

- Output:

## Forth[edit]

: 'nth ( -- c-addr ) s" th st nd rd th th th th th th " drop ;

: .nth ( n -- )

dup 10 20 within if 0 .r ." th " exit then

dup 0 .r 10 mod 3 * 'nth + 3 type ;

: test ( n n -- ) cr do i 5 mod 0= if cr then i .nth loop ;

: tests ( -- )

26 0 test 266 250 test 1026 1000 test ;

tests

- Output:

0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011st 1012nd 1013rd 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1024th ok

## Fortran[edit]

Please find the compilation instructions and examples in comments at the start of the source.

!-*- mode: compilation; default-directory: "/tmp/" -*-

!Compilation started at Fri Jun 6 15:40:18

!

!a=./f && make -k $a && echo 0 25 | $a && echo 250 265 | $a && echo 1000 1025 | $a

!gfortran -std=f2008 -Wall -fopenmp -ffree-form -fall-intrinsics -fimplicit-none -g f.f08 -o f

! 0'th 1'st 2'nd

! 3'rd 4'th 5'th

! 6'th 7'th 8'th

! 9'th 10'th 11'th

! 12'th 13'th 14'th

! 15'th 16'th 17'th

! 18'th 19'th 20'th

! 21'st 22'nd 23'rd

! 24'th 25'th

! 250'th 251'st

! 252'nd 253'rd 254'th

! 255'th 256'th 257'th

! 258'th 259'th 260'th

! 261'st 262'nd 263'rd

! 264'th 265'th

! 1000th 1001st

! 1002nd 1003rd 1004th

! 1005th 1006th 1007th

! 1008th 1009th 1010th

! 1011th 1012th 1013th

! 1014th 1015th 1016th

! 1017th 1018th 1019th

! 1020th 1021st 1022nd

! 1023rd 1024th 1025th

!

!Compilation finished at Fri Jun 6 15:40:18

program nth

implicit none

logical :: need

integer :: here, there, n, i, iostat

read(5,*,iostat=iostat) here, there

if (iostat .ne. 0) then

write(6,*)'such bad input never before seen.'

write(6,*)'I AYE EYE QUIT!'

call exit(1)

end if

need = .false.

n = abs(there - here) + 1

i = 0

do while (0 /= mod(3+mod(here-i, 3), 3))

write(6,'(a22)',advance='no') ''

i = i+1

end do

do i = here, there, sign(1, there-here)

write(6,'(a22)',advance='no') ordinate(i)

if (2 /= mod(i,3)) then

need = .true.

else

write(6,'(a)')''

need = .false.

end if

end do

if (need) write(6,'(a)')''

contains

character(len=22) function ordinate(n)

character(len=19) :: a

character(len=20), parameter :: &

&a09 = "thstndrdthththththth",&

&ateen = "thththththththththth"

integer :: ones, tens, ones_index

integer, intent(in) :: n

write(a,'(i19)') n

ones = mod(n,10)

tens = mod(n,100)

ones_index = ones*2+1

if (n < 1000) then

if ((10 .le. tens) .and. (tens .lt. 20)) then

ordinate = a // "'" // ateen(ones_index:ones_index+1)

else

ordinate = a // "'" // a09(ones_index:ones_index+1)

end if

else

if ((10 .le. tens) .and. (tens .lt. 20)) then

ordinate = a // ateen(ones_index:ones_index+1)

else

ordinate = a // a09(ones_index:ones_index+1)

end if

end if

end function ordinate

end program nth

## Gambas[edit]

**Click this link to run this code**

Public Sub Main()

Dim siNums As Short[] = [0, 25, 250, 265, 1000, 1025]

Dim siCount, siNumbers As Short

Dim sOrdinal As String

For siNumbers = 0 To 4 Step 2

For siCount = siNums[siNumbers] To siNums[siNumbers + 1]

sOrdinal = "th"

If Right(Str(siCount), 1) = "1" And Right(Str(siCount), 2) <> "11" Then sOrdinal = "st"

If Right(Str(siCount), 1) = "2" And Right(Str(siCount), 2) <> "12" Then sOrdinal = "nd"

If Right(Str(siCount), 1) = "3" And Right(Str(siCount), 2) <> "13" Then sOrdinal = "rd"

Print siCount & sOrdinal;;

Next

Print gb.NewLine

Next

End

Output:

## Go[edit]

package main

import "fmt"

func ord(n int) string {

s := "th"

switch c := n % 10; c {

case 1, 2, 3:

if n%100/10 == 1 {

break

}

switch c {

case 1:

s = "st"

case 2:

s = "nd"

case 3:

s = "rd"

}

}

return fmt.Sprintf("%d%s", n, s)

}

func main() {

for n := 0; n <= 25; n++ {

fmt.Printf("%s ", ord(n))

}

fmt.Println()

for n := 250; n <= 265; n++ {

fmt.Printf("%s ", ord(n))

}

fmt.Println()

for n := 1000; n <= 1025; n++ {

fmt.Printf("%s ", ord(n))

}

fmt.Println()

}

- Output:

## Haskell[edit]

import Data.Array

ordSuffs :: Array Integer String

ordSuffs = listArray (0,9) ["th", "st", "nd", "rd", "th",

"th", "th", "th", "th", "th"]

ordSuff :: Integer -> String

ordSuff n = show n ++ suff n

where suff m | (m `rem` 100) >= 11 && (m `rem` 100) <= 13 = "th"

| otherwise = ordSuffs ! (m `rem` 10)

printOrdSuffs :: [Integer] -> IO ()

printOrdSuffs = putStrLn . unwords . map ordSuff

main :: IO ()

main = do

printOrdSuffs [ 0.. 25]

printOrdSuffs [ 250.. 265]

printOrdSuffs [1000..1025]

- Output:

## Icon and Unicon[edit]

The following works in both languages.

procedure main(A)

every writes(" ",nth(0 to 25) | "\n")

every writes(" ",nth(250 to 265) | "\n")

every writes(" ",nth(1000 to 1025) | "\n")

end

procedure nth(n)

return n || ((n%10 = 1, n%100 ~= 11, "st") |

(n%10 = 2, n%100 ~= 12, "nd") |

(n%10 = 3, n%100 ~= 13, "rd") | "th")

end

- Output:

->nth 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13h 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013h 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th ->

## J[edit]

Implementation:

suf=: (;:'th st nd rd th') {::~ 4 <. 10 10 (* 1&~:)~/@#: ]

nth=: [: ;:inv (": , suf)each

Task:

thru=: <./ + [email protected](+ *)@-~

nth 0 thru 25

0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th

nth 250 thru 265

250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th

nth 1000 thru 1025

1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## Java[edit]

public class Nth {

public static String ordinalAbbrev(int n){

String ans = "th"; //most of the time it should be "th"

if(n % 100 / 10 == 1) return ans; //teens are all "th"

switch(n % 10){

case 1: ans = "st"; break;

case 2: ans = "nd"; break;

case 3: ans = "rd"; break;

}

return ans;

}

public static void main(String[] args){

for(int i = 0; i <= 25;i++){

System.out.print(i + ordinalAbbrev(i) + " ");

}

System.out.println();

for(int i = 250; i <= 265;i++){

System.out.print(i + ordinalAbbrev(i) + " ");

}

System.out.println();

for(int i = 1000; i <= 1025;i++){

System.out.print(i + ordinalAbbrev(i) + " ");

}

}

}

package nth;

import java.util.stream.IntStream;

import java.util.stream.Stream;

public interface Nth {

public static String suffix(int n){

if(n % 100 / 10 == 1){

return "th"; //teens are all "th"

}

switch(n % 10){

case 1: return "st";

case 2: return "nd";

case 3: return "rd";

default: return "th"; //most of the time it should be "th"

}

}

public static void print(int start, int end) {

IntStream.rangeClosed(start, end)

.parallel()

.mapToObj(i -> i + suffix(i) + " ")

.reduce(String::concat)

.ifPresent(System.out::println)

;

}

public static void print(int[] startAndEnd) {

print(startAndEnd[0], startAndEnd[1]);

}

public static int[] startAndEnd(int start, int end) {

return new int[] {

start,

end

};

}

public static void main(String... arguments){

Stream.of(

startAndEnd(0, 25),

startAndEnd(250, 265),

startAndEnd(1000, 1025)

)

.forEach(Nth::print)

;

}

}

- Output:

## JavaScript[edit]

### ES5[edit]

console.log(function () {

var lstSuffix = 'th st nd rd th th th th th th'.split(' '),

fnOrdinalForm = function (n) {

return n.toString() + (

11 <= n % 100 && 13 >= n % 100 ?

"th" : lstSuffix[n % 10]

);

},

range = function (m, n) {

return Array.apply(

null, Array(n - m + 1)

).map(function (x, i) {

return m + i;

});

};

return [[0, 25], [250, 265], [1000, 1025]].map(function (tpl) {

return range.apply(null, tpl).map(fnOrdinalForm).join(' ');

}).join('\n\n');

}());

- Output:

250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th

1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

### ES6[edit]

(function (lstTestRanges) {

'use strict'

let lstSuffix = 'th st nd rd th th th th th th'.split(' '),

// ordinalString :: Int -> String

ordinalString = n =>

n.toString() + (

11 <= n % 100 && 13 >= n % 100 ?

"th" : lstSuffix[n % 10]

),

// range :: Int -> Int -> [Int]

range = (m, n) =>

Array.from({

length: (n - m) + 1

}, (_, i) => m + i);

return lstTestRanges

.map(tpl => range

.apply(null, tpl)

.map(ordinalString)

);

})([[0, 25], [250, 265], [1000, 1025]]);

- Output:

[["0th", "1st", "2nd", "3rd", "4th", "5th", "6th", "7th", "8th", "9th", "10th", "11th", "12th", "13th", "14th", "15th", "16th", "17th", "18th", "19th", "20th", "21st", "22nd", "23rd", "24th", "25th"], ["250th", "251st", "252nd", "253rd", "254th", "255th", "256th", "257th", "258th", "259th", "260th", "261st", "262nd", "263rd", "264th", "265th"], ["1000th", "1001st", "1002nd", "1003rd", "1004th", "1005th", "1006th", "1007th", "1008th", "1009th", "1010th", "1011th", "1012th", "1013th", "1014th", "1015th", "1016th", "1017th", "1018th", "1019th", "1020th", "1021st", "1022nd", "1023rd", "1024th", "1025th"]]

## jq[edit]

# ordinalize an integer input, positive or negative

def ordinalize:

(if . < 0 then -(.) else . end) as $num

| ($num % 100) as $small

| (if 11 <= $small and $small <= 13 then "th"

else

( $num % 10)

| (if . == 1 then "st"

elif . == 2 then "nd"

elif . == 3 then "rd"

else "th"

end)

end) as $ordinal

| "\(.)\($ordinal)" ;

([range(-5; -1)], [range(0;26)], [range(250;266)], [range(1000;1026)])

| map(ordinalize)

- Output:

["-5th","-4th","-3rd","-2nd"] ["0th","1st","2nd","3rd","4th","5th","6th","7th","8th","9th","10th","11th","12th","13th","14th","15th","16th","17th","18th","19th","20th","21st","22nd","23rd","24th","25th"] ["250th","251st","252nd","253rd","254th","255th","256th","257th","258th","259th","260th","261st","262nd","263rd","264th","265th"] ["1000th","1001st","1002nd","1003rd","1004th","1005th","1006th","1007th","1008th","1009th","1010th","1011th","1012th","1013th","1014th","1015th","1016th","1017th","1018th","1019th","1020th","1021st","1022nd","1023rd","1024th","1025th"]

## Julia[edit]

**Function**

function sprintfordinal{T<:Integer}(n::T)

const sfixes = ["st", "nd", "rd"]

0 <= n || throw(ArgumentError("number to be formatted must be ≥ 0, got $n"))

u = n%10

t = div(n, 10)%10

if 3 < u || u == 0 || t == 1

sf = "th"

else

sf = sfixes[u]

end

@sprintf "%d%s" n sf

end

**Main**

println("Tests of ordinal formatting of integers.")

for (i, n) in enumerate(0:25)

if (i-1)%10 == 0

print("\n ")

end

print(@sprintf("%7s", sprintfordinal(n)))

end

println()

for (i, n) in enumerate(250:265)

if (i-1)%10 == 0

print("\n ")

end

print(@sprintf("%7s", sprintfordinal(n)))

end

println()

for (i, n) in enumerate(1000:1025)

if (i-1)%10 == 0

print("\n ")

end

print(@sprintf("%7s", sprintfordinal(n)))

end

println()

- Output:

Tests of ordinal formatting of integers. 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## Kotlin[edit]

fun Int.ordinalAbbrev() =

if (this % 100 / 10 == 1) "th"

else when (this % 10) { 1 -> "st" 2 -> "nd" 3 -> "rd" else -> "th" }

fun IntRange.ordinalAbbrev() = map { "$it" + it.ordinalAbbrev() }.joinToString(" ")

fun main(args: Array<String>) {

listOf((0..25), (250..265), (1000..1025)).forEach { println(it.ordinalAbbrev()) }

}

## Lua[edit]

The apostrophe just looks weird if you ask me. No one did, obviously.

function getSuffix (n)

local lastTwo, lastOne = n % 100, n % 10

if lastTwo > 3 and lastTwo < 21 then return "th" end

if lastOne == 1 then return "st" end

if lastOne == 2 then return "nd" end

if lastOne == 3 then return "rd" end

return "th"

end

function Nth (n) return n .. "'" .. getSuffix(n) end

for i = 0, 25 do print(Nth(i), Nth(i + 250), Nth(i + 1000)) end

- Output:

0'th 250'th 1000'th 1'st 251'st 1001'st 2'nd 252'nd 1002'nd 3'rd 253'rd 1003'rd 4'th 254'th 1004'th 5'th 255'th 1005'th 6'th 256'th 1006'th 7'th 257'th 1007'th 8'th 258'th 1008'th 9'th 259'th 1009'th 10'th 260'th 1010'th 11'th 261'st 1011'th 12'th 262'nd 1012'th 13'th 263'rd 1013'th 14'th 264'th 1014'th 15'th 265'th 1015'th 16'th 266'th 1016'th 17'th 267'th 1017'th 18'th 268'th 1018'th 19'th 269'th 1019'th 20'th 270'th 1020'th 21'st 271'st 1021'st 22'nd 272'nd 1022'nd 23'rd 273'rd 1023'rd 24'th 274'th 1024'th 25'th 275'th 1025'th

## Maple[edit]

toOrdinal := proc(n:: nonnegint)

if 1 <= n and n <= 10 then

if n >= 4 then

printf("%ath", n);

elif n = 3 then

printf("%ard", n);

elif n = 2 then

printf("%and", n);

else

printf("%ast", n);

end if:

else

printf(convert(n, 'ordinal'));

end if:

return NULL;

end proc:

a := [[0, 25], [250, 265], [1000, 1025]]:

for i in a do

for j from i[1] to i[2] do

toOrdinal(j);

printf(" ");

end do;

printf("\n\n");

end do;

- Output:

## Mathematica[edit]

I borrowed the logic from the Python code.

suffixlist = {"th", "st", "nd", "rd", "th", "th", "th", "th", "th","th"};

addsuffix[n_] := Module[{suffix},

suffix = Which[

Mod[n, 100] <= 10, suffixlist[[Mod[n, 10] + 1]],

Mod[n, 100] > 20, suffixlist[[Mod[n, 10] + 1]],

True, "th"

];

ToString[n] <> suffix

]

addsuffix[#] & /@ Range[0, 25] (* test 1 *)

addsuffix[#] & /@ Range[250, 265] (* test 2 *)

addsuffix[#] & /@ Range[1000, 1025] (* test 3 *)

- Output:

{"0th", "1st", "2nd", "3rd", "4th", "5th", "6th", "7th", "8th", "9th", "10th", "11th", "12th", "13th", "14th", "15th", "16th", "17th", "18th", "19th", "20th", "21st", "22nd", "23rd", "24th", "25th"} {"250th", "251st", "252nd", "253rd", "254th", "255th", "256th", "257th", "258th", "259th", "260th", "261st", "262nd", "263rd", "264th", "265th"} {"1000th", "1001st", "1002nd", "1003rd", "1004th", "1005th", "1006th", "1007th", "1008th", "1009th", "1010th", "1011th", "1012th", "1013th", "1014th", "1015th", "1016th", "1017th", "1018th", "1019th", "1020th", "1021st", "1022nd", "1023rd", "1024th", "1025th"}

## MATLAB[edit]

function s = nth(n)

tens = mod(n, 100);

if tens > 9 && tens < 20

suf = 'th';

else

switch mod(n, 10)

case 1

suf = 'st';

case 2

suf = 'nd';

case 3

suf = 'rd';

otherwise

suf = 'th';

end

end

s = sprintf('%d%s', n, suf);

end

- Output:

## Nim[edit]

const suffix = ["th", "st", "nd", "rd", "th", "th", "th", "th", "th", "th"]

proc nth(n): string =

$n & "'" & (if n mod 100 <= 10 or n mod 100 > 20: suffix[n mod 10] else: "th")

for j in countup(0, 1000, 250):

for i in j..j+24:

stdout.write nth(i), " "

echo ""

- Output:

0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 266'th 267'th 268'th 269'th 270'th 271'st 272'nd 273'rd 274'th 500'th 501'st 502'nd 503'rd 504'th 505'th 506'th 507'th 508'th 509'th 510'th 511'th 512'th 513'th 514'th 515'th 516'th 517'th 518'th 519'th 520'th 521'st 522'nd 523'rd 524'th 750'th 751'st 752'nd 753'rd 754'th 755'th 756'th 757'th 758'th 759'th 760'th 761'st 762'nd 763'rd 764'th 765'th 766'th 767'th 768'th 769'th 770'th 771'st 772'nd 773'rd 774'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th

## OCaml[edit]

let show_nth n =

if (n mod 10 = 1) && (n mod 100 <> 11) then "st"

else if (n mod 10 = 2) && (n mod 100 <> 12) then "nd"

else if (n mod 10 = 3) && (n mod 100 <> 13) then "rd"

else "th"

let () =

let show_ordinals (min, max) =

for i=min to max do

Printf.printf "%d%s " i (show_nth i)

done;

print_newline() in

List.iter show_ordinals [ (0,25); (250,265); (1000,1025) ]

- Output:

## Oforth[edit]

: nth(n)

| r |

n "th" over 10 mod ->r

r 1 == ifTrue: [ n 100 mod 11 == ifFalse: [ drop "st" ] ]

r 2 == ifTrue: [ n 100 mod 12 == ifFalse: [ drop "nd" ] ]

r 3 == ifTrue: [ n 100 mod 13 == ifFalse: [ drop "rd" ] ]

+ ;

- Output:

seqFrom(0, 25) map(#nth) println [0th, 1st, 2nd, 3rd, 4th, 5th, 6th, 7th, 8th, 9th, 10th, 11th, 12th, 13th, 14th, 15th, 16t h, 17th, 18th, 19th, 20th, 21st, 22nd, 23rd, 24th, 25th] seqFrom(250, 265) map(#nth) println [250th, 251st, 252nd, 253rd, 254th, 255th, 256th, 257th, 258th, 259th, 260th, 261st, 262nd , 263rd, 264th, 265th] seqFrom(1000, 1025) map(#nth) println [1000th, 1001st, 1002nd, 1003rd, 1004th, 1005th, 1006th, 1007th, 1008th, 1009th, 1010th, 1 011th, 1012th, 1013th, 1014th, 1015th, 1016th, 1017th, 1018th, 1019th, 1020th, 1021st, 102 2nd, 1023rd, 1024th, 1025th]

## PARI/GP[edit]

(Spurious apostrophes intentionally omitted, following Perl 6.)

ordinal(n)=my(k=n%10,m=n%100); Str(n,if(m<21&&m>3,"th",k==1,"st",k==2,"nd",k==3,"rd","th"));

apply(ordinal, [0..25])

apply(ordinal, [250..265])

apply(ordinal, [1000..1025])

apply(ordinal, [111, 1012])

- Output:

%1 = ["0th", "1st", "2nd", "3rd", "4th", "5th", "6th", "7th", "8th", "9th", "10th", "11th", "12th", "13th", "14th", "15th", "16th", "17th", "18th", "19th", "20th", "21st", "22nd", "23rd", "24th", "25th"] %2 = ["250th", "251st", "252nd", "253rd", "254th", "255th", "256th", "257th", "258th", "259th", "260th", "261st", "262nd", "263rd", "264th", "265th"] %3 = ["1000th", "1001st", "1002nd", "1003rd", "1004th", "1005th", "1006th", "1007th", "1008th", "1009th", "1010th", "1011th", "1012th", "1013th", "1014th", "1015th", "1016th", "1017th", "1018th", "1019th", "1020th", "1021st", "1022nd", "1023rd", "1024th", "1025th"] %4 = ["111th", "1012th"]

## Pascal[edit]

nearly copy of Ada

Program n_th;

function Suffix(N: NativeInt):AnsiString;

var

res: AnsiString;

begin

res:= 'th';

case N mod 10 of

1:IF N mod 100 <> 11 then

res:= 'st';

2:IF N mod 100 <> 12 then

res:= 'nd';

3:IF N mod 100 <> 13 then

res:= 'rd';

else

end;

Suffix := res;

end;

procedure Print_Images(loLim, HiLim: NativeInt);

var

i : NativeUint;

begin

for I := LoLim to HiLim do

write(i,Suffix(i),' ');

writeln;

end;

begin

Print_Images( 0, 25);

Print_Images( 250, 265);

Print_Images(1000, 1025);

end.

- Output:

0th 1st 2nd 3rd 4th ... 11th 12th 13th ..20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th ..261st 262nd 263rd 264th 265th ..1001st 1002nd 1003rd 1004th..1011th..1013th..1021st 1022nd 1023rd 1024th

## Perl[edit]

Requires Perl 5.10 or newer for the Defined OR operator (//).

my %irregulars = ( 1 => 'st',

2 => 'nd',

3 => 'rd',

11 => 'th',

12 => 'th',

13 => 'th');

sub nth

{

my $n = shift;

$n . # q(') . # Uncomment this to add apostrophes to output

($irregulars{$n % 100} // $irregulars{$n % 10} // 'th');

}

sub range { join ' ', map { nth($_) } @{$_[0]} }

print range($_), "\n" for ([0..25], [250..265], [1000..1025]);

- Output:

Same as Perl 6

use Lingua::EN::Numbers::Ordinate 'ordinate';

foreach my $i (0..25, 250..265, 1000..1025) {

print ordinate($i),"\n";

}

## Perl 6[edit]

(Spurious apostrophes intentionally omitted.)

my %irregulars = <1 st 2 nd 3 rd>, (11..13 X=> 'th');

sub nth ($n) { $n ~ ( %irregulars{$n % 100} // %irregulars{$n % 10} // 'th' ) }

say .list».&nth for [^26], [250..265], [1000..1025];

- Output:

If you want to get Unicodally fancy, use this version instead:

my %irregulars = <1 ˢᵗ 2 ⁿᵈ 3 ʳᵈ>, (11..13 X=> 'ᵗʰ');

sub nth ($n) { $n ~ ( %irregulars{$n % 100} // %irregulars{$n % 10} // 'ᵗʰ' ) }

say .list».&nth for [^26], [250..265], [1000..1025];

- Output:

0ᵗʰ 1ˢᵗ 2ⁿᵈ 3ʳᵈ 4ᵗʰ 5ᵗʰ 6ᵗʰ 7ᵗʰ 8ᵗʰ 9ᵗʰ 10ᵗʰ 11ᵗʰ 12ᵗʰ 13ᵗʰ 14ᵗʰ 15ᵗʰ 16ᵗʰ 17ᵗʰ 18ᵗʰ 19ᵗʰ 20ᵗʰ 21ˢᵗ 22ⁿᵈ 23ʳᵈ 24ᵗʰ 25ᵗʰ

250ᵗʰ 251ˢᵗ 252ⁿᵈ 253ʳᵈ 254ᵗʰ 255ᵗʰ 256ᵗʰ 257ᵗʰ 258ᵗʰ 259ᵗʰ 260ᵗʰ 261ˢᵗ 262ⁿᵈ 263ʳᵈ 264ᵗʰ 265ᵗʰ

1000ᵗʰ 1001ˢᵗ 1002ⁿᵈ 1003ʳᵈ 1004ᵗʰ 1005ᵗʰ 1006ᵗʰ 1007ᵗʰ 1008ᵗʰ 1009ᵗʰ 1010ᵗʰ 1011ᵗʰ 1012ᵗʰ 1013ᵗʰ 1014ᵗʰ 1015ᵗʰ 1016ᵗʰ 1017ᵗʰ 1018ᵗʰ 1019ᵗʰ 1020ᵗʰ 1021ˢᵗ 1022ⁿᵈ 1023ʳᵈ 1024ᵗʰ 1025ᵗʰ

## Phix[edit]

constant ordinals = {"th","st","nd","rd"}

function Nth(integer n, bool apostrophe=false)

integer mod10 = mod(n,10)+1

if mod10>4 or mod(n,100)=mod10+9 then mod10 = 1 end if

return sprintf("%d%s",{n,repeat('\'',apostrophe)&ordinals[mod10]})

end function

constant ranges = {{0,25},{250,265},{1000,1025}}

for i=1 to length(ranges) do

for j=ranges[i][1] to ranges[i][2] do

if mod(j,10)=0 then puts(1,"\n") end if

printf(1," %6s",{Nth(j,i=2)})

end for

puts(1,"\n")

end for

- Output:

0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## PHP[edit]

function nth($num) {

$os = "th";

if ($num % 100 <= 10 or $num % 100 > 20) {

switch ($num % 10) {

case 1:

$os = "st";

break;

case 2:

$os = "nd";

break;

case 3:

$os = "rd";

break;

}

}

return $num . $os;

}

foreach ([[0,25], [250,265], [1000,1025]] as $i) {

while ($i[0] <= $i[1]) {

echo nth($i[0]) . " ";

$i[0]++;

}

echo "\n";

}

- Output:

## PicoLisp[edit]

(de rangeth (A B)

(mapcar

'((I)

(pack I

(if (member (% I 100) (11 12 13))

'th

(case (% I 10)

(1 'st)

(2 'nd)

(3 'rd)

(T 'th) ) ) ) )

(range A B) ) )

(prinl (glue " " (rangeth 0 25)))

(prinl (glue " " (rangeth 250 265)))

(prinl (glue " " (rangeth 1000 1025)))

(bye)

- Output:

## PL/I[edit]

Nth: procedure options (main); /* 1 June 2014 */

declare i fixed (10);

do i = 0 to 25, 250 to 265, 1000 to 1025;

if i = 250 | i = 1000 then put skip (2);

put edit (enth(i)) (x(1), a);

end;

enth: procedure (i) returns (character (25) varying);

declare i fixed (10);

declare suffix character (2);

select (mod(i, 10));

when (1) suffix = 'st';

when (2) suffix = 'nd';

when (3) suffix = 'rd';

otherwise suffix = 'th';

end;

select (mod(i, 100));

when (11, 12, 13) suffix = 'th';

otherwise ;

end;

return ( trim(i) || suffix );

end enth;

end Nth;

- Output:

## PowerShell[edit]

function nth($inp){

$suffix = "th"

switch($inp % 10){

1{$suffix="st"}

2{$suffix="nd"}

3{$suffix="rd"}

}

return "$inp$suffix "

}

0..25 | %{Write-host -nonewline (nth "$_")};""

250..265 | %{Write-host -nonewline (nth "$_")};""

1000..1025 | %{Write-host -nonewline (nth "$_")};""

- Output:

0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11st 12nd 13rd 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011st 1012nd 1013rd 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

### An Alternate Version[edit]

This is, I think, is a more "PowerShelly" way:

function Get-Nth ([int]$Number)

{

$suffix = "th"

switch ($Number % 10)

{

1 {$suffix = "st"}

2 {$suffix = "nd"}

3 {$suffix = "rd"}

}

"$Number$suffix"

}

1..25 | ForEach-Object {Get-Nth $_} | Format-Wide {$_} -Column 5 -Force

251..265 | ForEach-Object {Get-Nth $_} | Format-Wide {$_} -Column 5 -Force

1001..1025 | ForEach-Object {Get-Nth $_} | Format-Wide {$_} -Column 5 -Force

- Output:

1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11st 12nd 13rd 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011st 1012nd 1013rd 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## Prolog[edit]

Following Icon:

nth(N, N_Th) :-

( tween(N) -> Th = "th"

; 1 is N mod 10 -> Th = "st"

; 2 is N mod 10 -> Th = "nd"

; 3 is N mod 10 -> Th = "rd"

; Th = "th" ),

string_concat(N, Th, N_Th).

tween(N) :- Tween is N mod 100, between(11, 13, Tween).

test :-

forall( between(0,25, N), (nth(N, N_Th), format('~w, ', N_Th)) ),

nl, nl,

forall( between(250,265,N), (nth(N, N_Th), format('~w, ', N_Th)) ),

nl, nl,

forall( between(1000,1025,N), (nth(N, N_Th), format('~w, ', N_Th)) ).

- Output:

?- test. 0th, 1st, 2nd, 3rd, 4th, 5th, 6th, 7th, 8th, 9th, 10th, 11th, 12th, 13th, 14th, 15th, 16th, 17th, 18th, 19th, 20th, 21st, 22nd, 23rd, 24th, 25th, 250th, 251st, 252nd, 253rd, 254th, 255th, 256th, 257th, 258th, 259th, 260th, 261st, 262nd, 263rd, 264th, 265th, 1000th, 1001st, 1002nd, 1003rd, 1004th, 1005th, 1006th, 1007th, 1008th, 1009th, 1010th, 1011th, 1012th, 1013th, 1014th, 1015th, 1016th, 1017th, 1018th, 1019th, 1020th, 1021st, 1022nd, 1023rd, 1024th, 1025th, true.

## Python[edit]

_suffix = ['th', 'st', 'nd', 'rd', 'th', 'th', 'th', 'th', 'th', 'th']

def nth(n):

return "%i'%s" % (n, _suffix[n%10] if n % 100 <= 10 or n % 100 > 20 else 'th')

if __name__ == '__main__':

for j in range(0,1001, 250):

print(' '.join(nth(i) for i in list(range(j, j+25))))

- Output:

0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 266'th 267'th 268'th 269'th 270'th 271'st 272'nd 273'rd 274'th 500'th 501'st 502'nd 503'rd 504'th 505'th 506'th 507'th 508'th 509'th 510'th 511'th 512'th 513'th 514'th 515'th 516'th 517'th 518'th 519'th 520'th 521'st 522'nd 523'rd 524'th 750'th 751'st 752'nd 753'rd 754'th 755'th 756'th 757'th 758'th 759'th 760'th 761'st 762'nd 763'rd 764'th 765'th 766'th 767'th 768'th 769'th 770'th 771'st 772'nd 773'rd 774'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th

**Alternate version**

#!/usr/bin/env python3

def ord(n):

try:

s = ['st', 'nd', 'rd'][(n-1)%10]

if (n-10)%100//10:

return str(n)+s

except IndexError:

pass

return str(n)+'th'

if __name__ == '__main__':

print(*(ord(n) for n in range(26)))

print(*(ord(n) for n in range(250,266)))

print(*(ord(n) for n in range(1000,1026)))

- Output:

## R[edit]

Note that R vectors are 1-indexed.

nth <- function(n)

{

if (length(n) > 1) return(sapply(n, nth))

mod <- function(m, n) ifelse(!(m%%n), n, m%%n)

suffices <- c("th", "st", "nd", "rd", "th", "th", "th", "th", "th", "th")

if (n %% 100 <= 10 || n %% 100 > 20)

suffix <- suffices[mod(n+1, 10)]

else

suffix <- 'th'

paste(n, "'", suffix, sep="")

}

range <- list(0:25, 250:275, 500:525, 750:775, 1000:1025)

sapply(range, nth)

- Output:

[,1] [,2] [,3] [,4] [,5] [1,] "0'th" "250'th" "500'th" "750'th" "1000'th" [2,] "1'st" "251'st" "501'st" "751'st" "1001'st" [3,] "2'nd" "252'nd" "502'nd" "752'nd" "1002'nd" [4,] "3'rd" "253'rd" "503'rd" "753'rd" "1003'rd" [5,] "4'th" "254'th" "504'th" "754'th" "1004'th" [6,] "5'th" "255'th" "505'th" "755'th" "1005'th" [7,] "6'th" "256'th" "506'th" "756'th" "1006'th" [8,] "7'th" "257'th" "507'th" "757'th" "1007'th" [9,] "8'th" "258'th" "508'th" "758'th" "1008'th" [10,] "9'th" "259'th" "509'th" "759'th" "1009'th" [11,] "10'th" "260'th" "510'th" "760'th" "1010'th" [12,] "11'th" "261'st" "511'th" "761'st" "1011'th" [13,] "12'th" "262'nd" "512'th" "762'nd" "1012'th" [14,] "13'th" "263'rd" "513'th" "763'rd" "1013'th" [15,] "14'th" "264'th" "514'th" "764'th" "1014'th" [16,] "15'th" "265'th" "515'th" "765'th" "1015'th" [17,] "16'th" "266'th" "516'th" "766'th" "1016'th" [18,] "17'th" "267'th" "517'th" "767'th" "1017'th" [19,] "18'th" "268'th" "518'th" "768'th" "1018'th" [20,] "19'th" "269'th" "519'th" "769'th" "1019'th" [21,] "20'th" "270'th" "520'th" "770'th" "1020'th" [22,] "21'st" "271'st" "521'st" "771'st" "1021'st" [23,] "22'nd" "272'nd" "522'nd" "772'nd" "1022'nd" [24,] "23'rd" "273'rd" "523'rd" "773'rd" "1023'rd" [25,] "24'th" "274'th" "524'th" "774'th" "1024'th" [26,] "25'th" "275'th" "525'th" "775'th" "1025'th"

## Racket[edit]

#lang racket

(define (teen? n) (<= 11 (modulo n 100) 19))

(define (Nth n)

(format

"~a'~a" n

(match* ((modulo n 10) n)

[((or 1 2 3) (? teen?)) 'th] [(1 _) 'st] [(2 _) 'nd] [(3 _) 'rd] [(_ _) 'th])))

(for ((range (list (in-range 26) (in-range 250 266) (in-range 1000 1026))))

(displayln (string-join (for/list ((nth (sequence-map Nth range))) nth) " ")))

- Output:

0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 25'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th 1025'th

## REXX[edit]

This version adds suffixes without apostrophes.

Negative numbers and fractions are also handled.

/*REXX program shows ranges of numbers with ordinal (st/nd/rd/th) suffixes attached.*/

call tell 0, 25 /*display the 1st range of numbers. */

call tell 250, 265 /* " " 2nd " " " */

call tell 1000, 1025 /* " " 3rd " " " */

exit /*stick a fork in it, we're all done. */

/*──────────────────────────────────────────────────────────────────────────────────────*/

tell: procedure; parse arg L,H,,$ /*get the Low and High #s, nullify list*/

do j=L to H; $=$ th(j); end /*process the range, from low ───► high*/

say 'numbers from ' L " to " H ' (inclusive):' /*display the title. */

say strip($); say; say /*display line; 2 sep*/

return /*return to invoker. */

/*──────────────────────────────────────────────────────────────────────────────────────*/

th: parse arg z; x=abs(z); return z||word('th st nd rd',1+x//10*(x//100%10\==1)*(x//10<4))

**output** using the default inputs:

numbers from 0 to 25 (inclusive): 0th 1st 2nd 3rd 4th 5th 6th 7th 8th 9th 10th 11th 12th 13th 14th 15th 16th 17th 18th 19th 20th 21st 22nd 23rd 24th 25th numbers from 250 to 265 (inclusive): 250th 251st 252nd 253rd 254th 255th 256th 257th 258th 259th 260th 261st 262nd 263rd 264th 265th numbers from 1000 to 1025 (inclusive): 1000th 1001st 1002nd 1003rd 1004th 1005th 1006th 1007th 1008th 1009th 1010th 1011th 1012th 1013th 1014th 1015th 1016th 1017th 1018th 1019th 1020th 1021st 1022nd 1023rd 1024th 1025th

## Ring[edit]

for nr = 0 to 25

see Nth(nr) + Nth(nr + 250) + Nth(nr + 1000) + nl

next

func getSuffix n

lastTwo = n % 100

lastOne = n % 10

if lastTwo > 3 and lastTwo < 21 "th" ok

if lastOne = 1 return "st" ok

if lastOne = 2 return "nd" ok

if lastOne = 3 return "rd" ok

return "th"

func Nth n

return "" + n + "'" + getSuffix(n) + " "

## Ruby[edit]

Code (slightly adapted) and methodname taken from ActiveSupport (Ruby on Rails).

class Integer

def ordinalize

num = self.abs

ordinal = if (11..13).include?(num % 100)

"th"

else

case num % 10

when 1; "st"

when 2; "nd"

when 3; "rd"

else "th"

end

end

"#{self}#{ordinal}"

end

end

[(0..25),(250..265),(1000..1025)].each{|r| puts r.map(&:ordinalize).join(", "); puts}

- Output:

0th, 1st, 2nd, 3rd, 4th, 5th, 6th, 7th, 8th, 9th, 10th, 11th, 12th, 13th, 14th, 15th, 16th, 17th, 18th, 19th, 20th, 21st, 22nd, 23rd, 24th, 25th 250th, 251st, 252nd, 253rd, 254th, 255th, 256th, 257th, 258th, 259th, 260th, 261st, 262nd, 263rd, 264th, 265th 1000th, 1001st, 1002nd, 1003rd, 1004th, 1005th, 1006th, 1007th, 1008th, 1009th, 1010th, 1011th, 1012th, 1013th, 1014th, 1015th, 1016th, 1017th, 1018th, 1019th, 1020th, 1021st, 1022nd, 1023rd, 1024th, 1025th

## Rust[edit]

fn nth(num: i32) -> String {

format!("{}{}", num, match (num % 10, num % 100) {

(1, 11) => "th",

(1, _) => "st",

(2, 12) => "th",

(2, _) => "nd",

(3, 13) => "th",

(3, _) => "rd",

_ => "th"

})

}

fn main() {

let ranges = vec![

(0, 26),

(250, 266),

(1000, 1026)

];

for &(s, e) in ranges.iter() {

println!("[{}, {}) :", s, e);

for i in s..e {

print!("{}, ", nth(i));

}

println!("");

}

}

- Output:

[0, 26) : 0th, 1st, 2nd, 3rd, 4th, 5th, 6th, 7th, 8th, 9th, 10th, 11th, 12th, 13th, 14th, 15th, 16th, 17th, 18th, 19th, 20th, 21st, 22nd, 23rd, 24th, 25th, [250, 266) : 250th, 251st, 252nd, 253rd, 254th, 255th, 256th, 257th, 258th, 259th, 260th, 261st, 262nd, 263rd, 264th, 265th, [1000, 1026) : 1000th, 1001st, 1002nd, 1003rd, 1004th, 1005th, 1006th, 1007th, 1008th, 1009th, 1010th, 1011th, 1012th, 1013th, 1014th, 1015th, 1016th, 1017th, 1018th, 1019th, 1020th, 1021st, 1022nd, 1023rd, 1024th, 1025th,

## Scala[edit]

object Nth extends App {

def abbrevNumber(i: Int) = print(s"$i${ordinalAbbrev(i)} ")

def ordinalAbbrev(n: Int) = {

val ans = "th" //most of the time it should be "th"

if (n % 100 / 10 == 1) ans //teens are all "th"

else (n % 10) match {

case 1 => "st"

case 2 => "nd"

case 3 => "rd"

case _ => ans

}

}

(0 to 25).foreach(abbrevNumber)

println()

(250 to 265).foreach(abbrevNumber)

println();

(1000 to 1025).foreach(abbrevNumber)

}

## Seed7[edit]

$ include "seed7_05.s7i";

const func string: suffix (in integer: num) is func

result

var string: suffix is "";

begin

if num rem 10 = 1 and num rem 100 <> 11 then suffix := "st";

elsif num rem 10 = 2 and num rem 100 <> 12 then suffix := "nd";

elsif num rem 10 = 3 and num rem 100 <> 13 then suffix := "rd";

else suffix := "th";

end if;

end func;

const proc: printImages (in integer: start, in integer: stop) is func

local

var integer: num is 0;

begin

for num range start to stop do

write(num <& suffix(num) <& " ");

end for;

writeln;

end func;

const proc: main is func

begin

printImages( 0, 25);

printImages( 250, 265);

printImages(1000, 1025);

end func;

- Output:

## Set lang[edit]

Due to the language's specification, the input can only contain one character. Therefore, the following code only works with 0-9.

set o 49

set t 50

set h 51

set n !

set ! n

set ! 39

[n=o] set ? 13

[n=t] set ? 16

[n=h] set ? 19

set ! T

set ! H

set ? 21

set ! S

set ! T

set ? 21

set ! N

set ! D

set ? 12

set ! R

set ! D

> EOF

Input: I, Output: O

I: 1, O: 1'ST I: 2, O: 2'ND I: 3, O: 3'RD I: 4, O: 4'TH I: 5, O: 5'TH ...

## Sidef[edit]

func nth(n) {

static irregulars = Hash(<1 ˢᵗ 2 ⁿᵈ 3 ʳᵈ 11 ᵗʰ 12 ᵗʰ 13 ᵗʰ>...)

n.to_s + (irregulars{n % 100} \\ irregulars{n % 10} \\ 'ᵗʰ')

}

for r in [0..25, 250..265, 1000..1025] {

say r.map {|n| nth(n) }.join(" ")

}

- Output:

0ᵗʰ 1ˢᵗ 2ⁿᵈ 3ʳᵈ 4ᵗʰ 5ᵗʰ 6ᵗʰ 7ᵗʰ 8ᵗʰ 9ᵗʰ 10ᵗʰ 11ᵗʰ 12ᵗʰ 13ᵗʰ 14ᵗʰ 15ᵗʰ 16ᵗʰ 17ᵗʰ 18ᵗʰ 19ᵗʰ 20ᵗʰ 21ˢᵗ 22ⁿᵈ 23ʳᵈ 24ᵗʰ 25ᵗʰ 250ᵗʰ 251ˢᵗ 252ⁿᵈ 253ʳᵈ 254ᵗʰ 255ᵗʰ 256ᵗʰ 257ᵗʰ 258ᵗʰ 259ᵗʰ 260ᵗʰ 261ˢᵗ 262ⁿᵈ 263ʳᵈ 264ᵗʰ 265ᵗʰ 1000ᵗʰ 1001ˢᵗ 1002ⁿᵈ 1003ʳᵈ 1004ᵗʰ 1005ᵗʰ 1006ᵗʰ 1007ᵗʰ 1008ᵗʰ 1009ᵗʰ 1010ᵗʰ 1011ᵗʰ 1012ᵗʰ 1013ᵗʰ 1014ᵗʰ 1015ᵗʰ 1016ᵗʰ 1017ᵗʰ 1018ᵗʰ 1019ᵗʰ 1020ᵗʰ 1021ˢᵗ 1022ⁿᵈ 1023ʳᵈ 1024ᵗʰ 1025ᵗʰ

## Sinclair ZX81 BASIC[edit]

Works flawlessly with 2k or more of RAM. With 1k, the subroutine itself works but you can't quite print all the tests: the program crashes with an 'out of memory' error code after 1017th. (A slightly less useful and readable version gets as far as 1023rd; 1025th is probably attainable, but might involve obfuscating the program more than is appropriate for this site.)

10 FOR N=0 TO 25

20 GOSUB 160

30 PRINT N$;" ";

40 NEXT N

50 PRINT

60 FOR N=250 TO 265

70 GOSUB 160

80 PRINT N$;" ";

90 NEXT N

100 PRINT

110 FOR N=1000 TO 1025

120 GOSUB 160

130 PRINT N$;" ";

140 NEXT N

150 STOP

160 LET N$=STR$ N

170 LET S$="TH"

180 IF LEN N$=1 THEN GOTO 200

190 IF N$(LEN N$-1)="1" THEN GOTO 230

200 IF N$(LEN N$)="1" THEN LET S$="ST"

210 IF N$(LEN N$)="2" THEN LET S$="ND"

220 IF N$(LEN N$)="3" THEN LET S$="RD"

230 LET N$=N$+S$

240 RETURN

- Output:

0TH 1ST 2ND 3RD 4TH 5TH 6TH 7TH 8TH 9TH 10TH 11TH 12TH 13TH 14TH 15TH 16TH 17TH 18TH 19TH 20TH 21ST 22ND 23RD 24TH 25TH 250TH 251ST 252ND 253RD 254TH 255TH 256TH 257TH 258TH 259TH 260TH 261ST 262ND 263RD 264TH 265TH 1000TH 1001ST 1002ND 1003RD 1004TH 1005TH 1006TH 1007TH 1008TH 1009TH 1010TH 1011TH 1012TH 1013TH 1014TH 1015TH 1016TH 1017TH 1018TH 1019TH 1020TH 1021ST 1022ND 1023RD 1024TH 1025TH

## SQL[edit]

Oracle

SELECT level card,

to_char(to_date(level,'j'),'fmjth') ord

FROM dual

CONNECT BY level <= 15;

SELECT to_char(to_date(5373485,'j'),'fmjth')

FROM dual;

CARD ORD ---------- ------------------------------ 1 1st 2 2nd 3 3rd 4 4th 5 5th 6 6th 7 7th 8 8th 9 9th 10 10th 11 11th 12 12th 13 13th 14 14th 15 15th 15 rows selected. select to_char(to_date(5373485,'j'),'fmjth') * ERROR at line 1: ORA-01854: julian date must be between 1 and 5373484

## Swift[edit]

func addSuffix(n:Int) -> String {

if n % 100 / 10 == 1 {

return "th"

}

switch n % 10 {

case 1:

return "st"

case 2:

return "nd"

case 3:

return "rd"

default:

return "th"

}

}

for i in 0...25 {

print("\(i)\(addSuffix(i)) ")

}

println()

for i in 250...265 {

print("\(i)\(addSuffix(i)) ")

}

println()

for i in 1000...1025 {

print("\(i)\(addSuffix(i)) ")

}

println()

- Output:

## Tcl[edit]

proc ordinal {n} {

if {$n%100<10 || $n%100>20} {

set suff [lindex {th st nd rd th th th th th th} [expr {$n % 10}]]

} else {

set suff th

}

return "$n'$suff"

}

foreach start {0 250 1000} {

for {set n $start; set l {}} {$n<=$start+25} {incr n} {

lappend l [ordinal $n]

}

puts $l

}

- Output:

0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 25'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 266'th 267'th 268'th 269'th 270'th 271'st 272'nd 273'rd 274'th 275'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th 1025'th

## uBasic/4tH[edit]

For x = 0 to 25 ' Test range 0..25

Push x : GoSub _PrintOrdinal

Next x : Print

For x = 250 to 265 ' Test range 250..265

Push x : GoSub _PrintOrdinal

Next x : Print

For x = 1000 to 1025 ' Test range 1000..1025

Push x : GoSub _PrintOrdinal

Next x : Print

End ' End test program

' ( n --)

_PrintOrdinal ' Ordinal subroutine

If Tos() > -1 Then ' If within range then

Print Using "____#";Tos();"'"; ' Print the number

' Take care of 11, 12 and 13

If (Tos()%100 > 10) * (Tos()%100 < 14) Then

Gosub (Pop() * 0) + 100 ' Clear stack and print "th"

Return ' We're done here

EndIf

Push Pop() % 10 ' Calculate n mod 10

GoSub 100 + 10 * ((Tos()>0) + (Tos()>1) + (Tos()>2) - (3 * (Pop()>3)))

Else ' And decide which ordinal to use

Print Pop();" is less than zero" ' Otherwise, it is an error

EndIf

Return

' Select and print proper ordinal

100 Print "th"; : Return

110 Print "st"; : Return

120 Print "nd"; : Return

130 Print "rd"; : Return

- Output:

0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 25'th 250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th 1025'th

## XLISP[edit]

(DEFUN NTH (N)

(COND

((AND (> (MOD N 100) 3) (< (MOD N 100) 21)) `(,N TH))

((= (MOD N 10) 1) `(,N ST))

((= (MOD N 10) 2) `(,N ND))

((= (MOD N 10) 3) `(,N RD))

(T `(,N TH))))

(DEFUN RANGE (X Y)

(IF (<= X Y)

(CONS X (RANGE (+ X 1) Y))))

(DEFUN TEST-NTH ()

(DISPLAY (MAPCAR NTH (RANGE 1 25)))

(NEWLINE)

(DISPLAY (MAPCAR NTH (RANGE 250 265)))

(NEWLINE)

(DISPLAY (MAPCAR NTH (RANGE 1000 1025))))

(TEST-NTH)

- Output:

((1 ST) (2 ND) (3 RD) (4 TH) (5 TH) (6 TH) (7 TH) (8 TH) (9 TH) (10 TH) (11 TH) (12 TH) (13 TH) (14 TH) (15 TH) (16 TH) (17 TH) (18 TH) (19 TH) (20 TH) (21 ST) (22 ND) (23 RD) (24 TH) (25 TH)) ((250 TH) (251 ST) (252 ND) (253 RD) (254 TH) (255 TH) (256 TH) (257 TH) (258 TH) (259 TH) (260 TH) (261 ST) (262 ND) (263 RD) (264 TH) (265 TH)) ((1000 TH) (1001 ST) (1002 ND) (1003 RD) (1004 TH) (1005 TH) (1006 TH) (1007 TH) (1008 TH) (1009 TH) (1010 TH) (1011 TH) (1012 TH) (1013 TH) (1014 TH) (1015 TH) (1016 TH) (1017 TH) (1018 TH) (1019 TH) (1020 TH) (1021 ST) (1022 ND) (1023 RD) (1024 TH) (1025 TH))

## zkl[edit]

Two versions, your choice

#if 0

fcn addSuffix(n){

z:=n.abs()%100;

if(11<=z<=13) return(String(n,"th"));

z=z%10;

String(n,(z==1 and "st") or (z==2 and "nd") or (z==3 and "rd") or "th");

}

#else

fcn addSuffix(n){

var suffixes=T("th","st","nd","rd","th","th","th","th","th","th"); //0..10

z:=n.abs()%100;

String(n,(z<=10 or z>20) and suffixes[z%10] or "th");

}

#endif

[0..25] .apply(addSuffix).concat(",").println();

[250..265] .apply(addSuffix).concat(",").println();

[1000..1025].apply(addSuffix).concat(",").println();

- Output:

0th,1st,2nd,3rd,4th,5th,6th,7th,8th,9th,10th,11th,12th,13th,14th,15th,16th,17th,18th,19th,20th,21st,22nd,23rd,24th,25th 250th,251st,252nd,253rd,254th,255th,256th,257th,258th,259th,260th,261st,262nd,263rd,264th,265th 1000th,1001st,1002nd,1003rd,1004th,1005th,1006th,1007th,1008th,1009th,1010th,1011th,1012th,1013th,1014th,1015th,1016th,1017th,1018th,1019th,1020th,1021st,1022nd,1023rd,1024th,1025th

## ZX Spectrum Basic[edit]

10 FOR n=0 TO 25

20 GO SUB 140

30 PRINT n$;" ";

40 NEXT n

50 FOR n=250 TO 265

60 GO SUB 140

70 PRINT n$;" ";

80 NEXT n

90 FOR n=1000 TO 1025

100 GO SUB 140

110 PRINT n$;" ";

120 NEXT n

130 STOP

140 LET s$="th"

150 LET n$=STR$ n

160 IF LEN n$=1 THEN GO TO 180

170 IF n$(LEN n$-1)="1" THEN GO TO 210

180 IF n$(LEN n$)="1" THEN LET s$="st"

190 IF n$(LEN n$)="2" THEN LET s$="nd"

200 IF n$(LEN n$)="3" THEN LET s$="rd"

210 LET n$=n$+s$

220 RETURN

- Output:

- Programming Tasks
- Ordinal numbers
- String manipulation
- Ada
- ALGOL 68
- AppleScript
- Applesoft BASIC
- AutoHotkey
- AWK
- Babel
- BaCon
- Batch File
- BBC BASIC
- Befunge
- C
- C++
- C sharp
- Clojure
- COBOL
- Common Lisp
- D
- Elixir
- ERRE
- FreeBASIC
- F Sharp
- Factor
- Forth
- Fortran
- Examples needing attention
- Gambas
- Go
- Haskell
- Icon
- Unicon
- J
- Java
- JavaScript
- Jq
- Julia
- Kotlin
- Lua
- Maple
- Mathematica
- MATLAB
- Nim
- OCaml
- Oforth
- PARI/GP
- Pascal
- Perl
- Lingua::EN::Numbers::Ordinate
- Perl 6
- Phix
- PHP
- PicoLisp
- PL/I
- PowerShell
- Prolog
- Python
- R
- Racket
- REXX
- Ring
- Ruby
- Rust
- Scala
- Seed7
- Set lang
- Sidef
- Sinclair ZX81 BASIC
- SQL
- Swift
- Tcl
- UBasic/4tH
- XLISP
- Zkl
- ZX Spectrum Basic