Knuth shuffle: Difference between revisions
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class |
class |
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APPLICATION |
APPLICATION |
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inherit |
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ARGUMENTS |
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create |
create |
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make |
make |
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feature {NONE} |
feature {NONE} -- Initialization |
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make |
make |
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do |
do |
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test := <<1, 2 |
test := <<1, 2>> |
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io.put_string ("Initial: ") |
io.put_string ("Initial: ") |
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across |
across |
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shuffle (ar: ARRAY [INTEGER]): ARRAY [INTEGER] |
shuffle (ar: ARRAY [INTEGER]): ARRAY [INTEGER] |
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-- Array containing the same elements as 'ar' in a shuffled order. |
-- Array containing the same elements as 'ar' in a shuffled order. |
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require |
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more_than_one_element: ar.count > 1 |
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local |
local |
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count, j, ith: INTEGER |
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ith: INTEGER |
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random: V_RANDOM |
random: V_RANDOM |
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do |
do |
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create Result.make_empty |
create Result.make_empty |
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Result.deep_copy (ar) |
Result.deep_copy (ar) |
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⚫ | |||
from |
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across |
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⚫ | |||
1 |..| count as c |
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until |
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i = 2 |
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loop |
loop |
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j := random.bounded_item ( |
j := random.bounded_item (c.item, count) |
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ith := Result [ |
ith := Result [c.item] |
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Result [ |
Result [c.item] := Result [j] |
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Result [j] := ith |
Result [j] := ith |
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random.forth |
random.forth |
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i := i - 1 |
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end |
end |
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ensure |
ensure |
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same_elements: across ar as a all Result.has (a.item) end |
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end |
end |
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Revision as of 14:54, 29 March 2015
You are encouraged to solve this task according to the task description, using any language you may know.
Implement the Knuth shuffle (a.k.a. the Fisher-Yates shuffle) for an integer array (or, if possible, an array of any type). The Knuth shuffle is used to create a random permutation of an array.
ACL2
<lang Lisp>:set-state-ok t
(defun array-swap (name array i j)
(let ((ai (aref1 name array i)) (aj (aref1 name array j))) (aset1 name (aset1 name array j ai) i aj)))
(defun shuffle-r (name array m state)
(if (zp m) (mv array state) (mv-let (i state) (random$ m state) (shuffle-r name (array-swap name array i m) (1- m) state))))
(defun shuffle (name array state)
(shuffle-r name array (1- (first (dimensions name array))) state))</lang>
Ada
This implementation is a generic shuffle routine, able to shuffle an array of any type. <lang Ada>generic
type Element_Type is private; type Array_Type is array (Positive range <>) of Element_Type;
procedure Generic_Shuffle (List : in out Array_Type);</lang> <lang Ada>with Ada.Numerics.Discrete_Random;
procedure Generic_Shuffle (List : in out Array_Type) is
package Discrete_Random is new Ada.Numerics.Discrete_Random(Result_Subtype => Integer); use Discrete_Random; K : Integer; G : Generator; T : Element_Type;
begin
Reset (G); for I in reverse List'Range loop K := (Random(G) mod I) + 1; T := List(I); List(I) := List(K); List(K) := T; end loop;
end Generic_Shuffle;</lang> An example using Generic_Shuffle. <lang Ada>with Ada.Text_IO; with Generic_Shuffle;
procedure Test_Shuffle is
type Integer_Array is array (Positive range <>) of Integer;
Integer_List : Integer_Array := (1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18); procedure Integer_Shuffle is new Generic_Shuffle(Element_Type => Integer, Array_Type => Integer_Array);
begin
for I in Integer_List'Range loop Ada.Text_IO.Put(Integer'Image(Integer_List(I))); end loop; Integer_Shuffle(List => Integer_List); Ada.Text_IO.New_Line; for I in Integer_List'Range loop Ada.Text_IO.Put(Integer'Image(Integer_List(I))); end loop;
end Test_Shuffle;</lang>
Aime
The shuffle function works on any type (the lists are heterogenous). <lang aime>void shuffle(list l) {
integer i;
i = l_length(l); if (i) { i -= 1; while (i) { l_spin(l, i, drand(i)); i -= 1; } }
}</lang>
ALGOL 68
<lang algol68>PROC between = (INT a, b)INT : (
ENTIER (random * ABS (b-a+1) + (a<b|a|b))
);
PROC knuth shuffle = (REF[]INT a)VOID: (
FOR i FROM LWB a TO UPB a DO INT j = between(LWB a, UPB a); INT t = a[i]; a[i] := a[j]; a[j] := t OD
);</lang> <lang algol68>main:(
[20]INT a; FOR i FROM 1 TO 20 DO a[i] := i OD; knuth shuffle(a); print(a)
)</lang>
AppleScript
<lang AppleScript>set n to 25
set array to {} repeat with i from 1 to n set end of array to i end repeat copy {array, array} to {unshuffled, shuffled} repeat with i from n to 1 by -1 set j to (((random number) * (i - 1)) as integer) + 1 set shuffled's item i to array's item j if j ≠ i's contents then set array's item j to array's item i end repeat
return {unshuffled, shuffled}</lang> Example: <lang AppleScript>{{1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25}, {14, 25, 3, 1, 12, 18, 11, 20, 16, 15, 21, 5, 22, 19, 2, 24, 8, 10, 13, 6, 17, 23, 9, 7, 4}}</lang>
AutoHotkey
ahk forum: discussion <lang AutoHotkey>MsgBox % shuffle("1,2,3,4,5,6,7,8,9") MsgBox % shuffle("1,2,3,4,5,6,7,8,9")
shuffle(list) { ; shuffle comma separated list, converted to array
StringSplit a, list, `, ; make array (length = a0) Loop % a0-1 { Random i, A_Index, a0 ; swap item 1,2... with a random item to the right of it t := a%i%, a%i% := a%A_Index%, a%A_Index% := t } Loop % a0 ; construct string from sorted array s .= "," . a%A_Index% Return SubStr(s,2) ; drop leading comma
}</lang>
AutoIt
<lang AutoIt> Dim $a[10] ConsoleWrite('array before permutation:' & @CRLF) For $i = 0 To 9 $a[$i] = Random(20,100,1) ConsoleWrite($a[$i] & ' ') Next ConsoleWrite(@CRLF)
_Permute($a) ConsoleWrite('array after permutation:' & @CRLF) For $i = 0 To UBound($a) -1 ConsoleWrite($a[$i] & ' ') Next ConsoleWrite(@CRLF)
Func _Permute(ByRef $array)
Local $random, $tmp
For $i = UBound($array) -1 To 0 Step -1
$random = Random(0,$i,1)
$tmp = $array[$random]
$array[$random] = $array[$i]
$array[$i] = $tmp
Next
EndFunc
</lang>
- Output:
array before permutation: 43 57 37 20 97 98 69 76 97 70 array after permutation: 57 69 97 70 37 97 20 76 43 98
AWK
Many arrays in AWK have the first index at 1. This example shows how to shuffle such arrays. The elements can be integers, floating-point numbers, or strings. <lang awk># Shuffle an _array_ with indexes from 1 to _len_. function shuffle(array, len, i, j, t) { for (i = len; i > 1; i--) { # j = random integer from 1 to i j = int(i * rand()) + 1
# swap array[i], array[j] t = array[i] array[i] = array[j] array[j] = t } }
- Test program.
BEGIN { len = split("11 22 33 44 55 66 77 88 99 110", array) shuffle(array, len)
for (i = 1; i < len; i++) printf "%s ", array[i] printf "%s\n", array[len] }</lang>
BASIC
<lang qbasic>RANDOMIZE TIMER
DIM cards(51) AS INTEGER DIM L0 AS LONG, card AS LONG
PRINT "before:" FOR L0 = 0 TO 51
cards(L0) = L0 PRINT LTRIM$(STR$(cards(L0))); " ";
NEXT
FOR L0 = 51 TO 0 STEP -1
card = INT(RND * (L0 + 1)) IF card <> L0 THEN SWAP cards(card), cards(L0)
NEXT
PRINT : PRINT "after:" FOR L0 = 0 TO 51
PRINT LTRIM$(STR$(cards(L0))); " ";
NEXT PRINT</lang>
- Output:
before: 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 after: 27 14 37 35 3 44 25 38 46 1 22 49 2 51 16 32 20 30 4 33 36 6 31 21 41 34 9 13 0 50 47 48 40 39 7 18 19 26 24 10 29 5 12 28 11 17 43 45 8 23 42 15
BBC BASIC
<lang bbcbasic> cards% = 52
DIM pack%(cards%) FOR I% = 1 TO cards% pack%(I%) = I% NEXT I% FOR N% = cards% TO 2 STEP -1 SWAP pack%(N%),pack%(RND(N%)) NEXT N% FOR I% = 1 TO cards% PRINT pack%(I%); NEXT I% PRINT</lang>
bc
I provide a shuffle() function. It can only shuffle an array of numbers. It fails if the array has more than 32768 elements. It always shuffles the array named shuffle[]; the array is not a function parameter because bc passes arrays by copying.
This code requires a bc with long names; the test program also requires a bc with the print statement.
<lang bc>seed = 1 /* seed of the random number generator */ scale = 0
/* Random number from 0 to 32767. */ define rand() { /* Formula (from POSIX) for random numbers of low quality. */ seed = (seed * 1103515245 + 12345) % 4294967296 return ((seed / 65536) % 32768) }
/* Shuffle the first _count_ elements of shuffle[]. */ define shuffle(count) { auto b, i, j, t
i = count while (i > 0) { /* j = random number in [0, i) */ b = 32768 % i /* want rand() >= b */ while (1) { j = rand() if (j >= b) break } j = j % i
/* decrement i, swap shuffle[i] and shuffle[j] */ t = shuffle[--i] shuffle[i] = shuffle[j] shuffle[j] = t } }
/* Test program. */ define print_array(count) { auto i for (i = 0; i < count - 1; i++) print shuffle[i], ", " print shuffle[i], "\n" }
for (i = 0; i < 10; i++) shuffle[i] = 11 * (i + 1) "Original array: "; trash = print_array(10)
trash = shuffle(10) "Shuffled array: "; trash = print_array(10) quit</lang>
- Output:
Original array: 11, 22, 33, 44, 55, 66, 77, 88, 99, 110 Shuffled array: 66, 44, 11, 55, 33, 77, 110, 22, 88, 99
Brat
<lang brat>shuffle = { a |
(a.length - 1).to 1 { i | random_index = random(0, i) temp = a[i] a[i] = a[random_index] a[random_index] = temp }
a
}
p shuffle [1 2 3 4 5 6 7]</lang>
C
This shuffles any "object"; it imitates qsort in the syntax. <lang c>#include <stdlib.h>
- include <string.h>
int rrand(int m) {
return (int)((double)m * ( rand() / (RAND_MAX+1.0) ));
}
- define BYTE(X) ((unsigned char *)(X))
void shuffle(void *obj, size_t nmemb, size_t size) {
void *temp = malloc(size); size_t n = nmemb; while ( n > 1 ) { size_t k = rrand(n--); memcpy(temp, BYTE(obj) + n*size, size); memcpy(BYTE(obj) + n*size, BYTE(obj) + k*size, size); memcpy(BYTE(obj) + k*size, temp, size); } free(temp);
} </lang> Alternatively, using Durstenfeld's method (swapping selected item and last item in each iteration instead of literally shifting everything), and macro'd function declaration/definition: <lang C>#include <stdio.h>
- include <stdlib.h>
/* define a shuffle function. e.g. decl_shuffle(double).
* advantage: compiler is free to optimize the swap operation without * indirection with pointers, which could be much faster. * disadvantage: each datatype needs a separate instance of the function. * for a small funciton like this, it's not very big a deal. */
- define decl_shuffle(type) \
void shuffle_##type(type *list, size_t len) { \ int j; \ type tmp; \ while(len) { \ j = irand(len); \ if (j != len - 1) { \ tmp = list[j]; \ list[j] = list[len - 1]; \ list[len - 1] = tmp; \ } \ len--; \ } \ } \
/* random integer from 0 to n-1 */ int irand(int n) { int r, rand_max = RAND_MAX - (RAND_MAX % n); /* reroll until r falls in a range that can be evenly * distributed in n bins. Unless n is comparable to * to RAND_MAX, it's not *that* important really. */ while ((r = rand()) >= rand_max); return r / (rand_max / n); }
/* declare and define int type shuffle function from macro */ decl_shuffle(int);
int main() { int i, x[20];
for (i = 0; i < 20; i++) x[i] = i; for (printf("before:"), i = 0; i < 20 || !printf("\n"); i++) printf(" %d", x[i]);
shuffle_int(x, 20);
for (printf("after: "), i = 0; i < 20 || !printf("\n"); i++) printf(" %d", x[i]); return 0; }</lang>
C++
Compiler: g++ (version 4.3.2 20081105 (Red Hat 4.3.2-7)) <lang cpp>#include <cstdlib>
- include <algorithm>
- include <iterator>
template<typename RandomAccessIterator> void knuthShuffle(RandomAccessIterator begin, RandomAccessIterator end) {
for(unsigned int n = end - begin - 1; n >= 1; --n) { unsigned int k = rand() % (n + 1); if(k != n) { std::iter_swap(begin + k, begin + n); } }
}</lang>
The standard library provides this in the form of std::random_shuffle
.
<lang cpp>#include <algorithm>
- include <vector>
int main() {
int array[] = { 1,2,3,4,5,6,7,8,9 }; // C-style array of integers std::vector<int> vec(array, array + 9); // build STL container from int array
std::random_shuffle(array, array + 9); // shuffle C-style array std::random_shuffle(vec.begin(), vec.end()); // shuffle STL container
}</lang>
C#
<lang csharp>public static void KnuthShuffle<T>(T[] array) {
System.Random random = new System.Random(); for (int i = 0; i < array.Length; i++) { int j = random.Next(i, array.Length); // Don't select from the entire array on subsequent loops T temp = array[i]; array[i] = array[j]; array[j] = temp; }
}</lang>
Clojure
<lang lisp>(defn shuffle [vect]
(reduce (fn [v i] (let [r (rand-int i)] (assoc v i (v r) r (v i))) vect (range (dec (count vect)) 1 -1)))</lang>
This works by generating a sequence of end-indices from n-1 to 1, then reducing that sequence (starting with the original vector) through a function that, given a vector and end-index, performs a swap between the end-index and some random index less than the end-index.
COBOL
<lang cobol> IDENTIFICATION DIVISION.
PROGRAM-ID. knuth-shuffle.
DATA DIVISION. LOCAL-STORAGE SECTION. 01 i PIC 9(8). 01 j PIC 9(8).
01 temp PIC 9(8).
LINKAGE SECTION. 78 Table-Len VALUE 10. 01 ttable-area. 03 ttable PIC 9(8) OCCURS Table-Len TIMES.
PROCEDURE DIVISION USING ttable-area. MOVE FUNCTION RANDOM(FUNCTION CURRENT-DATE (11:6)) TO i
PERFORM VARYING i FROM Table-Len BY -1 UNTIL i = 0 COMPUTE j = FUNCTION MOD(FUNCTION RANDOM * 10000, Table-Len) + 1
MOVE ttable (i) TO temp MOVE ttable (j) TO ttable (i) MOVE temp TO ttable (j) END-PERFORM
GOBACK .</lang>
CMake
<lang cmake># shuffle(<output variable> [<value>...]) shuffles the values, and
- stores the result in a list.
function(shuffle var)
set(forever 1)
# Receive ARGV1, ARGV2, ..., ARGV${last} as an array of values. math(EXPR last "${ARGC} - 1")
# Shuffle the array with Knuth shuffle (Fisher-Yates shuffle). foreach(i RANGE ${last} 1) # Roll j = a random number from 1 to i. math(EXPR min "100000000 % ${i}") while(forever) string(RANDOM LENGTH 8 ALPHABET 0123456789 j) if(NOT j LESS min) # Prevent modulo bias when j < min. break() # Break loop when j >= min. endif() endwhile() math(EXPR j "${j} % ${i} + 1")
# Swap ARGV${i} with ARGV${j}. set(t ${ARGV${i}}) set(ARGV${i} ${ARGV${j}}) set(ARGV${j} ${t}) endforeach(i)
# Convert array to list. set(answer) foreach(i RANGE 1 ${last}) list(APPEND answer ${ARGV${i}}) endforeach(i) set("${var}" ${answer} PARENT_SCOPE)
endfunction(shuffle)</lang>
<lang cmake>shuffle(result 11 22 33 44 55 66) message(STATUS "${result}")
- One possible output:
- -- 66;33;22;55;44;11</lang>
CoffeeScript
<lang coffeescript>knuth_shuffle = (a) ->
n = a.length while n > 1 r = Math.floor(n * Math.random()) n -= 1 [a[n], a[r]] = [a[r], a[n]] a
counts =
"1,2,3": 0 "1,3,2": 0 "2,1,3": 0 "2,3,1": 0 "3,1,2": 0 "3,2,1": 0
for i in [1..100000]
counts[knuth_shuffle([ 1, 2, 3 ]).join(",")] += 1
for key, val of counts
console.log "#{key}: #{val}"</lang>
- Output:
> coffee knuth_shuffle.coffee 1,2,3: 16714 1,3,2: 16566 2,1,3: 16460 2,3,1: 16715 3,1,2: 16750 3,2,1: 16795
Common Lisp
<lang lisp>(defun nshuffle (sequence)
(loop for i from (length sequence) downto 2 do (rotatef (elt sequence (random i)) (elt sequence (1- i)))) sequence)</lang>
This operates on arbitrary sequences, but will be inefficient applied to a list as opposed to a vector. Dispatching on type, and using an intermediate vector to hold the contents of list can make both cases more efficient (since the array specific case can use aref
rather than elt
):
<lang lisp>(defun nshuffle (sequence)
(etypecase sequence (list (nshuffle-list sequence)) (array (nshuffle-array sequence))))
(defun nshuffle-list (list)
"Shuffle the list using an intermediate vector." (let ((array (nshuffle-array (coerce list 'vector)))) (declare (dynamic-extent array)) (map-into list 'identity array)))
(defun nshuffle-array (array)
(loop for i from (length array) downto 2 do (rotatef (aref array (random i)) (aref array (1- i))) finally (return array)))</lang>
D
Standard Version
A variant of the Knuth shuffle is in the D standard library Phobos: <lang d>void main() {
import std.stdio, std.random;
auto a = [1, 2, 3, 4, 5, 6, 7, 8, 9]; a.randomShuffle; a.writeln;
}</lang>
- Output:
[8, 9, 3, 1, 7, 5, 4, 6, 2]
One Implementation
This shuffles any collection that supports random access, length and swapping of items: <lang d>import std.stdio, std.algorithm, std.random, std.range;
void knuthShuffle(Range)(Range r) if (isRandomAccessRange!Range && hasLength!Range &&
hasSwappableElements!Range) { foreach_reverse (immutable i, ref ri; r[1 .. $ - 1]) ri.swap(r[uniform(0, i + 1)]);
}
void main() {
auto a = [1, 2, 3, 4, 5, 6, 7, 8, 9]; a.knuthShuffle; a.writeln;
}</lang>
Delphi
DWScript
<lang delphi>procedure KnuthShuffle(a : array of Integer); var
i, j, tmp : Integer;
begin
for i:=a.High downto 1 do begin j:=RandomInt(a.Length); tmp:=a[i]; a[i]:=a[j]; a[j]:=tmp; end;
end;</lang>
E
<lang e>def shuffle(array, random) {
for bound in (2..(array.size())).descending() { def i := random.nextInt(bound) def swapTo := bound - 1 def t := array[swapTo] array[swapTo] := array[i] array[i] := t }
}</lang> <lang e>? def arr := [1,2,3,4,5,6,7,8,9,10].diverge()
- value: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10].diverge()
? shuffle(arr, entropy) ? arr
- value: [4, 5, 2, 9, 7, 8, 1, 3, 6, 10].diverge()</lang>
Eiffel
<lang Eiffel> class APPLICATION
inherit
ARGUMENTS
create make
feature {NONE} -- Initialization
make do test := <<1, 2>> io.put_string ("Initial: ") across test as t loop io.put_string (t.item.out + " ") end test := shuffle (test) io.new_line io.put_string ("Shuffled: ") across test as t loop io.put_string (t.item.out + " ") end end
test: ARRAY [INTEGER]
shuffle (ar: ARRAY [INTEGER]): ARRAY [INTEGER] -- Array containing the same elements as 'ar' in a shuffled order. require more_than_one_element: ar.count > 1 local count, j, ith: INTEGER random: V_RANDOM do create random create Result.make_empty Result.deep_copy (ar) count := ar.count across 1 |..| count as c loop j := random.bounded_item (c.item, count) ith := Result [c.item] Result [c.item] := Result [j] Result [j] := ith random.forth end ensure same_elements: across ar as a all Result.has (a.item) end end
end
</lang >
- Output:
Initial: 1 2 3 4 5 6 7 Shuffeld: 1 5 3 4 7 6 2
Erlang
<lang Erlang> -module( knuth_shuffle ).
-export( [list/1] ).
list( Inputs ) -> N = erlang:length( Inputs ), {[], Acc} = lists:foldl( fun random_move/2, {Inputs, []}, lists:reverse(lists:seq(1, N)) ), Acc.
random_move( N, {Inputs, Acc} ) -> Item = lists:nth( random:uniform(N), Inputs ), {lists:delete(Item, Inputs), [Item | Acc]}. </lang>
- Output:
21> knuth_shuffle:list(lists:seq(1,9)). [5,7,8,1,4,2,3,9,6]
ERRE
<lang ERRE>PROGRAM KNUTH_SHUFFLE
CONST CARDS%=52
DIM PACK%[CARDS%]
BEGIN
RANDOMIZE(TIMER) FOR I%=1 TO CARDS% DO PACK%[I%]=I% END FOR FOR N%=CARDS% TO 2 STEP -1 DO SWAP(PACK%[N%],PACK%[1+INT(N%*RND(1))]) END FOR FOR I%=1 TO CARDS% DO PRINT(PACK%[I%];) END FOR PRINT
END PROGRAM </lang>
Euphoria
<lang Euphoria>sequence cards cards = repeat(0,52) integer card,temp
puts(1,"Before:\n") for i = 1 to 52 do
cards[i] = i printf(1,"%d ",cards[i])
end for
for i = 52 to 1 by -1 do
card = rand(i) if card != i then temp = cards[card] cards[card] = cards[i] cards[i] = temp end if
end for
puts(1,"\nAfter:\n") for i = 1 to 52 do
printf(1,"%d ",cards[i])
end for</lang>
Factor
There is a randomize
word already in the standard library. Implementation:
<lang factor>: randomize ( seq -- seq )
dup length [ dup 1 > ] [ [ iota random ] [ 1 - ] bi [ pick exchange ] keep ] while drop ;</lang>
Fantom
<lang fantom>class Main {
static Void knuthShuffle (List array) { ((array.size-1)..1).each |Int i| { r := Int.random(0..i) array.swap (i, r) } }
public static Void main () { List a := [1,2,3,4,5] knuthShuffle (a) echo (a)
List b := ["apples", "oranges", "pears", "bananas"] knuthShuffle (b) echo (b) }
}</lang>
Forth
<lang forth>include random.fs
- shuffle ( deck size -- )
2 swap do dup i random cells + over @ over @ swap rot ! over ! cell+ -1 +loop drop ;
- .array 0 do dup @ . cell+ loop drop ;
create deck 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10 ,
deck 10 2dup shuffle .array</lang>
Fortran
<lang fortran>program Knuth_Shuffle
implicit none
integer, parameter :: reps = 1000000 integer :: i, n integer, dimension(10) :: a, bins = 0, initial = (/ (n, n=1,10) /)
do i = 1, reps a = initial call Shuffle(a) where (a == initial) bins = bins + 1 ! skew tester end do write(*, "(10(i8))") bins
! prints 100382 100007 99783 100231 100507 99921 99941 100270 100290 100442
contains
subroutine Shuffle(a)
integer, intent(inout) :: a(:) integer :: i, randpos, temp real :: r
do i = size(a), 2, -1 call random_number(r) randpos = int(r * i) + 1 temp = a(randpos) a(randpos) = a(i) a(i) = temp end do
end subroutine Shuffle
end program Knuth_Shuffle</lang>
Frink
The built-in method array.shuffle[]
implements the Fisher-Yates-Knuth shuffle algorithm:
<lang frink>
a = [1,2,3]
a.shuffle[]
</lang>
F#
Allows a shuffle of arrays of arbitrary items. Requires 2010 beta of F#. Lazily returns a sequence.
This is the original Fisher-Yates shuffle as described by the link: <lang fsharp>open System
let FisherYatesShuffle (initialList : array<'a>) = // '
let availableFlags = Array.init initialList.Length (fun i -> (i, true)) // Which items are available and their indices let rnd = new Random() let nextItem nLeft = let nItem = rnd.Next(0, nLeft) // Index out of available items let index = // Index in original deck availableFlags // Go through available array |> Seq.filter (fun (ndx,f) -> f) // and pick out only the available tuples |> Seq.nth nItem // Get the one at our chosen index |> fst // and retrieve it's index into the original array availableFlags.[index] <- (index, false) // Mark that index as unavailable initialList.[index] // and return the original item seq {(initialList.Length) .. -1 .. 1} // Going from the length of the list down to 1 |> Seq.map (fun i -> nextItem i) // yield the next item</lang>
Here's the modified Knuth shuffle which shuffles the original array in place <lang fsharp>let KnuthShuffle (lst : array<'a>) = // '
let Swap i j = // Standard swap let item = lst.[i] lst.[i] <- lst.[j] lst.[j] <- item let rnd = new Random() let ln = lst.Length [0..(ln - 2)] // For all indices except the last |> Seq.iter (fun i -> Swap i (rnd.Next(i, ln))) // swap th item at the index with a random one following it (or itself) lst // Return the list shuffled in place</lang>
Example: <lang fsharp>> KnuthShuffle [| "Darrell"; "Marvin"; "Doug"; "Greg"; "Sam"; "Ken" |];; val it : string array = [|"Marvin"; "Doug"; "Sam"; "Darrell"; "Ken"; "Greg"|]</lang>
FunL
<lang funl>def shuffle( a ) =
res = array( a ) n = a.length() for i <- 0:n r = rnd( i:n ) res(i), res(r) = res(r), res(i) res.toList()</lang>
GAP
<lang gap># Return the list L after applying Knuth shuffle. GAP also has the function Shuffle, which does the same. ShuffleAlt := function(a)
local i, j, n, t; n := Length(a); for i in [n, n - 1 .. 2] do j := Random(1, i); t := a[i]; a[i] := a[j]; a[j] := t; od; return a;
end;
- Return a "Permutation" object (a permutation of 1 .. n).
- They are printed in GAP, in cycle decomposition form.
PermShuffle := n -> PermList(ShuffleAlt([1 .. n]));
ShuffleAlt([1 .. 10]);
- [ 4, 7, 1, 5, 8, 2, 6, 9, 10, 3 ]
PermShuffle(10);
- (1,9)(2,3,6,4,5,10,8,7)
- One may also call the built-in random generator on the symmetric group :
Random(SymmetricGroup(10)); (1,8,2,5,9,6)(3,4,10,7)</lang>
Go
<lang go>package main
import (
"fmt" "math/rand" "time"
)
func main() {
var a [20]int for i := range a { a[i] = i } fmt.Println(a)
rand.Seed(time.Now().UnixNano()) for i := len(a) - 1; i >= 1; i-- { j := rand.Intn(i + 1) a[i], a[j] = a[j], a[i] } fmt.Println(a)
}</lang> To shuffle any type: <lang go>package main
import (
"fmt" "math/rand" "time"
)
// Generic Knuth Shuffle algorithm. In Go, this is done with interface // types. The parameter s of function shuffle is an interface type. // Any type satisfying the interface "shuffler" can be shuffled with // this function. Since the shuffle function uses the random number // generator, it's nice to seed the generator at program load time. func init() {
rand.Seed(time.Now().UnixNano())
} func shuffle(s shuffler) {
for i := s.Len() - 1; i >= 1; i-- { j := rand.Intn(i + 1) s.Swap(i, j) }
}
// Conceptually, a shuffler is an indexed collection of things. // It requires just two simple methods. type shuffler interface {
Len() int // number of things in the collection Swap(i, j int) // swap the two things indexed by i and j
}
// ints is an example of a concrete type implementing the shuffler // interface. type ints []int
func (s ints) Len() int { return len(s) } func (s ints) Swap(i, j int) { s[i], s[j] = s[j], s[i] }
// Example program. Make an ints collection, fill with sequential numbers, // print, shuffle, print. func main() {
a := make(ints, 20) for i := range a { a[i] = i } fmt.Println(a) shuffle(a) fmt.Println(a)
}</lang>
- Example output:
(of either program)
[0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19] [11 10 12 19 4 13 15 17 14 2 5 18 8 0 6 9 7 3 1 16]
Groovy
Solution: <lang groovy>def shuffle = { list ->
if (list == null || list.empty) return list def r = new Random() def n = list.size() (n..1).each { i -> def j = r.nextInt(i) listi-1, j = listj, i-1 } list
}</lang> Test: <lang groovy>def list = [] + (0..20) println list println shuffle(list) println shuffle(list) println shuffle(list)</lang>
- Output:
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20] [12, 16, 7, 13, 1, 9, 17, 20, 15, 3, 5, 6, 8, 0, 18, 10, 14, 4, 2, 11, 19] [17, 6, 10, 1, 18, 5, 7, 13, 2, 11, 16, 3, 14, 0, 4, 20, 19, 12, 8, 9, 15] [6, 20, 11, 4, 7, 12, 5, 14, 19, 18, 13, 15, 1, 2, 8, 16, 17, 10, 0, 9, 3]
Haskell
<lang Haskell>import System.Random import Data.List import Control.Monad import Control.Arrow
mkRands = mapM (randomRIO.(,)0 ). enumFromTo 1. pred
replaceAt :: Int -> a -> [a] -> [a] replaceAt i c = let (a,b) = splitAt i l in a++x:(drop 1 b)
swapElems :: (Int, Int) -> [a] -> [a] swapElems (i,j) xs | i==j = xs
| otherwise = replaceAt j (xs!!i) $ replaceAt i (xs!!j) xs
knuthShuffle :: [a] -> IO [a] knuthShuffle xs =
liftM (foldr swapElems xs. zip [1..]) (mkRands (length xs))</lang>
Examples of use:
*Main> knuthShuffle ['a'..'k'] "bhjdgfciake" *Main> knuthShuffle $ map(ap (,)(+10)) [0..9] [(0,10),(8,18),(2,12),(3,13),(9,19),(4,14),(7,17),(1,11),(6,16),(5,15)]
Function for showing intermediate results: <lang Haskell>knuthShuffleProcess :: (Show a) => [a] -> IO () knuthShuffleProcess =
(mapM_ print. reverse =<<). ap (fmap. (. zip [1..]). scanr swapElems) (mkRands. length)</lang>
- Output:
Detailed example
*Main> knuthShuffleProcess ['a'..'k'] "abcdefghijk" "abckefghijd" "jbckefghiad" "jbckeighfad" "jbckeihgfad" "jbhkeicgfad" "jbhiekcgfad" "jbeihkcgfad" "ibejhkcgfad" "iebjhkcgfad" "iebjhkcgfad"
An imperative implementation using arrays and the ST
monad:
<lang haskell>import Data.Array.ST
import Data.STRef
import Control.Monad
import Control.Monad.ST
import Control.Arrow
import System.Random
shuffle :: RandomGen g => [a] -> g -> ([a], g) shuffle list g = runST $ do
r <- newSTRef g let rand range = liftM (randomR range) (readSTRef r) >>= runKleisli (second (Kleisli $ writeSTRef r) >>> arr fst) a <- newAry (1, len) list forM_ [len, len - 1 .. 2] $ \n -> do k <- rand (1, n) liftM2 (,) (readArray a k) (readArray a n) >>= runKleisli (Kleisli (writeArray a n) *** Kleisli (writeArray a k)) liftM2 (,) (getElems a) (readSTRef r) where len = length list newAry :: (Int, Int) -> [a] -> ST s (STArray s Int a) newAry = newListArray</lang>
Icon and Unicon
The shuffle method used here can shuffle lists, record fields, and strings: <lang icon>procedure main()
show(shuffle([3,1,4,1,5,9,2,6,3])) show(shuffle("this is a string"))
end
procedure shuffle(A)
every A[i := *A to 1 by -1] :=: A[?i] return A
end
procedure show(A)
every writes(!A," ") write()
end</lang>
- Output:
->ks 9 6 1 4 3 1 3 5 2 i n t i s r t g h s a i s ->
Note that the gloriously succinct 'standard' Icon shuffle: <lang icon>procedure shuffle(A)
every !A :=: ?A
end</lang> is subtly biased.
Inform 6
<lang Inform 6>[ shuffle a n i j tmp;
for(i = n - 1: i > 0: i--) { j = random(i + 1) - 1;
tmp = a->j; a->j = a->i; a->i = tmp; }
];</lang>
J
<lang j>KS=:{~ (2&{.@[ {`(|.@[)`]} ])/@(,~(,.?@>:))@i.@#</lang> The input array is transformed to a rectangular array of indexes. By doing this all kinds of arrays can serve as input (see examples below). The process is imitated by using using a fold, swapping elements in a restricted part of this index-array in each fold step. <lang j>process J
fold swap transform array <==> f / g y</lang>
Example of a transformed input: <lang j>(,~(,.?@>:))@i.@# 1+i.6 0 0 0 0 0 0 1 1 0 0 0 0 2 0 0 0 0 0 3 2 0 0 0 0 4 3 0 0 0 0 5 0 0 0 0 0 0 1 2 3 4 5</lang> The last row is the index-array that has to be shuffled. The other rows have valid indexes in the first two columns. The second column has a randomized value <= value first column.
The index-swapping is done by the part: <lang j>2&{.@[ {`(|.@[)`]} ]</lang> Finally, the shuffled indexes select elements from the original array. <lang j>input { ~ shuffled indexes</lang> Alternatively, instead of creating a rectangular array, the swapping indices and the original data can be individually boxed.
In other words, (,~ (,. ?@>:))@i.@#
can be replaced with |.@; ;&~./@(,. ?@>:)@i.@#
, and the swapping can be achieved using (<@C. >)/
instead of (2&{.@[ {`(|.@[)`]} ])/
.
With this approach, the data structure with the swapping indices and the original data could look like this:
<lang j> (|.@; ;&~./@(,. ?@>:)@i.@#)'abcde'
+---+-+---+---+-+-----+
|4 2|3|2 1|1 0|0|abcde|
+---+-+---+---+-+-----+</lang>
Note that we have the original data here, instead of indices to select all of its items. Note also that we have only a single value in a box where an item is being "swapped" with itself (this is required by J's cycle operation (C.
)).
The resulting definition looks like this: <lang j>KS=: [: > (<@C. >)/@(|.@; ;&~./@(,. ?@>:)@i.@#)</lang> Note that here we did not wind up with a list of indices which we used to permute the original data set. That data set is permuted directly. However, it is in a box and we do have to remove it from that box.
Permuting the data directly, instead of permuting indices, has performance implications when the items being swapped are large, but see the note at the end of this entry for J for how you would do this operation in a "real" J program.
Examples:<lang j>]A=: 5+i.9 5 6 7 8 9 10 11 12 13</lang> Shuffle: <lang j>KS A 13 10 7 5 11 9 8 6 12</lang>Input <lang j>]M=: /:~(1 2 3,:2 3 4),(11 2 3,: 0 11 2),(1 1 1,:1 0),:1 1 1,:1 0 1
1 1 1 1 0 0
1 1 1 1 0 1
1 2 3 2 3 4
11 2 3
0 11 2</lang>Shuffle
<lang j>KS M 11 2 3
0 11 2
1 1 1 1 0 1
1 1 1 1 0 0
1 2 3 2 3 4</lang>Input
<lang j>]L=:'aA';'bbB';'cC%$';'dD@' +--+---+----+---+ |aA|bbB|cC%$|dD@| +--+---+----+---+</lang>Shuffle <lang j>KS L +--+----+---+---+ |aA|cC%$|dD@|bbB| +--+----+---+---+</lang> In J the shuffling of an arbitrary array can easily be implemented by the phrase ( ref http://www.jsoftware.com/jwiki/JPhrases/RandomNumbers ): <lang j>({~?~@#)</lang> Applied on the former examples: <lang j>({~?~@#) A 8 7 13 6 10 11 5 9 12
({~?~@#) M 1 1 1 1 0 1
1 2 3 2 3 4
11 2 3
0 11 2
1 1 1 1 0 0
({~?~@#) L
+----+---+--+---+ |cC%$|bbB|aA|dD@| +----+---+--+---+</lang>
Java
<lang java>import java.util.Random;
public static final Random gen = new Random();
// version for array of ints public static void shuffle (int[] array) {
int n = array.length; while (n > 1) { int k = gen.nextInt(n--); //decrements after using the value int temp = array[n]; array[n] = array[k]; array[k] = temp; }
} // version for array of references public static void shuffle (Object[] array) {
int n = array.length; while (n > 1) { int k = gen.nextInt(n--); //decrements after using the value Object temp = array[n]; array[n] = array[k]; array[k] = temp; }
}</lang>
JavaScript
<lang javascript>function knuth_shuffle(a) {
var n = a.length, r, temp; while (n > 1) { r = Math.floor(n * Math.random()); n -= 1; temp = a[n]; a[n] = a[r]; a[r] = temp; } return a;
}
var res, i, key;
res = {
'1,2,3': 0, '1,3,2': 0, '2,1,3': 0, '2,3,1': 0, '3,1,2': 0, '3,2,1': 0
};
for (i = 0; i < 100000; i++) {
res[knuth_shuffle([1,2,3]).join(',')] += 1;
} for (key in res) {
print(key + "\t" + res[key]);
}</lang> Results in:
1,2,3 16619 1,3,2 16614 2,1,3 16752 2,3,1 16959 3,1,2 16460 3,2,1 16596
Joy
<lang Joy>DEFINE knuth-shuffle ==
(* Take the size of the array (without destroying it) *) dup dup size
(* Generate a list of as many random numbers *) [rand] [rem] enconcat map
(* Zip the two lists *) swap zip
(* Sort according to the new index number *) [small] [] [uncons unswonsd [first >] split [swons] dip2] [enconcat] binrec
(* Delete the new index number *) [second] map.</lang> Using knuth-shuffle (file shuffle.joy): <lang Joy>(* Sorted array of 21 integers *) [ 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20] knuth-shuffle.</lang> Command line:
- joy shuffle.joy
- Output:
usrlib is loaded inilib is loaded agglib is loaded [12 6 8 4 14 18 7 15 1 0 11 13 5 10 16 2 19 17 9 20 3]
LabVIEW
Lasso
<lang lasso>define staticarray->swap(p1::integer,p2::integer) => {
fail_if( #p1 < 1 or #p2 < 1 or #p1 > .size or #p2 > .size, 'invalid parameters' ) #p1 == #p2 ? return
local(tmp) = .get(#p2) .get(#p2) = .get(#p1) .get(#p1) = #tmp
} define staticarray->knuthShuffle => {
loop(-from=.size, -to=2, -by=-1) => { .swap(math_random(1, loop_count), loop_count) }
}
(1 to 10)->asStaticArray->knuthShuffle&asString</lang>
- Output:
staticarray(9, 5, 6, 1, 10, 8, 3, 4, 2, 7)
Liberty BASIC
<lang lb>'Declared the UpperBound to prevent confusion with lots of 9's floating around.... UpperBound = 9 Dim array(UpperBound)
For i = 0 To UpperBound
array(i) = Int(Rnd(1) * 10) Print array(i)
Next i
For i = 0 To UpperBound
'set a random value because we will need to use the same value twice randval = Int(Rnd(1) * (UpperBound - i)) temp1 = array(randval) temp2 = array((UpperBound - i)) array(randval) = temp2 array((UpperBound - i)) = temp1
Next i
Print For i = 0 To UpperBound
Print array(i)
Next i</lang>
Logo
<lang logo>to swap :i :j :a
localmake "t item :i :a setitem :i :a item :j :a setitem :j :a :t
end to shuffle :a
for [i [count :a] 2] [swap 1 + random :i :i :a]
end
make "a {1 2 3 4 5 6 7 8 9 10} shuffle :a show :a</lang> Lhogho does not have a setitem, and also does things more 'function'ally. <lang logo>to slice :lst :start :finish local "res make "res [] for "i [:start :finish 1] [ make "j item :i :lst make "res se :res :j ] op :res end
to setitem :n :lst :val local "lhs local "rhs make "lhs slice :lst 1 :n-1 make "rhs slice :lst :n+1 count :lst op (se :lhs :val :rhs) end
to swap :i :j :a local "t make "t item :i :a make "a setitem :i :a item :j :a make "a setitem :j :a :t op :a end
to shuffle :a for "i [count :a 2] [ make "a swap 1 + random :i :i :a ] op :a end
make "a ( list 1 2 3 4 5 6 7 8 9 10 ) make "a shuffle :a show :a</lang>
Lua
<lang lua>function table.shuffle(t)
local n = #t while n > 1 do local k = math.random(n) t[n], t[k] = t[k], t[n] n = n - 1 end return t
end math.randomseed( os.time() ) a = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} table.shuffle(a) for i,v in ipairs(a) do print(i,v) end</lang>
M4
<lang M4>divert(-1) define(`randSeed',141592653) define(`rand_t',`eval(randSeed^(randSeed>>13))') define(`random',
`define(`randSeed',eval((rand_t^(rand_t<<18))&0x7fffffff))randSeed')
define(`for',
`ifelse($#,0,``$0, `ifelse(eval($2<=$3),1, `pushdef(`$1',$2)$4`'popdef(`$1')$0(`$1',incr($2),$3,`$4')')')')
define(`set',`define(`$1[$2]',`$3')') define(`get',`defn($1[$2])') define(`new',`set($1,size,0)') define(`deck',
`new($1)for(`x',1,$2, `set(`$1',x,x)')`'set(`$1',size,$2)')
define(`show',
`for(`x',1,get($1,size),`get($1,x)`'ifelse(x,get($1,size),`',`, ')')')
define(`swap',`set($1,$2,get($1,$4))`'set($1,$4,$3)') define(`shuffle',
`define(`s',get($1,size))`'for(`x',1,decr(s), `swap($1,x,get($1,x),eval(x+random%(s-x+1)))')')
divert
deck(`b',52) show(`b') shuffle(`b') show(`b')</lang>
- Output:
1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52 6, 22, 33, 51, 35, 45, 16, 32, 7, 34, 10, 44, 5, 38, 43, 25, 29, 9, 37, 20, 21, 48, 24, 46, 8, 26, 41, 47, 49, 36, 14, 31, 15, 39, 12, 17, 13, 1, 3, 4, 27, 11, 28, 2, 19, 30, 42, 50, 18, 52, 40, 23
Mathematica
Usage of built-in function: <lang Mathematica>RandomSample[{1, 2, 3, 4, 5, 6}]</lang> Custom function: <lang Mathematica>Shuffle[input_List /; Length[input] >= 1] :=
Module[{indices = {}, allindices = Range[Length[input]]}, Do[ AppendTo[indices, Complement[allindices, indices][[RandomInteger[{1, i}]]]]; , {i, Length[input], 1, -1} ]; inputindices ]</lang>
Example: <lang Mathematica>Shuffle[{1, 2, 3, 4, 5, 6}]</lang>
MATLAB
Because this shuffle is done using rounds of operations on subsets of decreasing size, this is not an algorithm that can be vectorized using built-in MATLAB functions. So, we have to go old-school, no fancy MATLAB trickery. <lang MATLAB>function list = knuthShuffle(list)
for i = (numel(list):-1:2) j = floor(i*rand(1) + 1); %Generate random int between 1 and i %Swap element i with element j. list([j i]) = list([i j]); end
end</lang> There is an alternate way to do this that is not a true Knuth Shuffle, but operates with the same spirit. This alternate version produces the same output, saves some space, and can be implemented in-line without the need to encapsulate it in a function call like the Knuth Shuffle. <lang MATLAB>function list = randSort(list)
list = list( randperm(numel(list)) );
end</lang>
Maxima
<lang maxima>/* Maxima has an implementation of Knuth shuffle */ random_permutation([a, b, c]);</lang>
Modula-3
<lang modula3>MODULE Shuffle EXPORTS Main;
IMPORT IO, Fmt, Random;
VAR a := ARRAY [0..9] OF INTEGER {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
PROCEDURE Shuffle(VAR a: ARRAY OF INTEGER) =
VAR temp: INTEGER; n: INTEGER := NUMBER(a);
BEGIN
WITH rand = NEW(Random.Default).init() DO WHILE n > 1 DO WITH k = rand.integer(0, n - 1) DO DEC(n); temp := a[n]; a[n] := a[k]; a[k] := temp; END; END; END;
END Shuffle;
BEGIN
Shuffle(a); FOR i := FIRST(a) TO LAST(a) DO IO.Put(Fmt.Int(a[i]) & " "); END; IO.Put("\n");
END Shuffle.</lang>
- Output:
martin@thinkpad:~$ ./shuffle 9 2 7 3 6 8 4 5 1 10 martin@thinkpad:~$ ./shuffle 1 7 8 10 5 4 6 3 9 2
MUMPS
<lang MUMPS>Shuffle(items,separator) New ii,item,list,n Set list="",n=0 Set ii="" For Set ii=$Order(items(ii)) Quit:ii="" Do . Set n=n+1,list(n)=items(ii),list=list_$Char(n) . Quit For Quit:list="" Do . Set n=$Random($Length(list))+1 . Set item=list($ASCII(list,n)) . Set $Extract(list,n)="" . Write item,separator . Quit Quit CardDeck New card,ii,suite Set ii=0 For suite="Spades","Hearts","Clubs","Diamonds" Do . For card=2:1:10,"Jack","Queen","King","Ace" Do . . Set ii=ii+1,items(ii)=card_" of "_suite . . Quit . Quit Quit
Kill items Set items(91)="Red" Set items(82)="White" Set items(73)="Blue" Set items(64)="Yellow" Set items(55)="Green" Do Shuffle(.items," ") ; Red Yellow White Green Blue Do Shuffle(.items," ") ; Red Blue Yellow White Green Do Shuffle(.items," ") ; Green Blue Yellow White Red
Kill items Do CardDeck,Shuffle(.items,$Char(13,10)) Queen of Hearts 9 of Diamonds 10 of Hearts King of Hearts 7 of Diamonds 9 of Clubs 6 of Diamonds 8 of Diamonds Jack of Spades Ace of Hearts Queen of Diamonds 9 of Hearts 2 of Hearts King of Clubs 10 of Spades 7 of Clubs 6 of Clubs 3 of Diamonds 3 of Spades Queen of Clubs Ace of Spades 4 of Hearts Ace of Diamonds 7 of Spades Ace of Clubs King of Spades 10 of Diamonds Jack of Diamonds 8 of Clubs 4 of Spades Jack of Hearts 10 of Clubs 4 of Diamonds 3 of Hearts 2 of Diamonds 5 of Hearts Jack of Clubs 2 of Clubs 5 of Diamonds 6 of Hearts 4 of Clubs 9 of Spades 3 of Clubs 5 of Spades 6 of Spades 7 of Hearts 8 of Spades 8 of Hearts 2 of Spades Queen of Spades King of Diamonds 5 of Clubs</lang>
Nemerle
<lang Nemerle>Shuffle[T] (arr : array[T]) : array[T] {
def rnd = Random(); foreach (i in [0 .. (arr.Length - 2)]) arr[i] <-> arr[(rnd.Next(i, arr.Length))]; arr
}</lang>
NetRexx
version 1
<lang NetRexx>/* NetRexx */ options replace format comments java crossref savelog symbols nobinary
import java.util.List
cards = [String -
'hA', 'h2', 'h3', 'h4', 'h5', 'h6', 'h7', 'h8', 'h9', 'h10', 'hJ', 'hQ', 'hK' - , 'cA', 'c2', 'c3', 'c4', 'c5', 'c6', 'c7', 'c8', 'c9', 'c10', 'cJ', 'cQ', 'cK' - , 'dA', 'd2', 'd3', 'd4', 'd5', 'd6', 'd7', 'd8', 'd9', 'd10', 'dJ', 'dQ', 'dK' - , 'sA', 's2', 's3', 's4', 's5', 's6', 's7', 's8', 's9', 's10', 'sJ', 'sQ', 'sK' -
] cardsLen = cards.length deck = ArrayList(cardsLen) loop c_ = 0 to cardsLen - 1
deck.add(String(cards[c_])) end c_
showHand(deck) deck = ArrayList shuffle(deck) showHand(deck)
return
method shuffle(deck = List) public static binary returns List
rn = Random() dl = deck.size
loop i_ = dl - 1 to 1 by -1 j_ = rn.nextInt(i_) __ = deck.get(i_) deck.set(i_, deck.get(j_)) deck.set(j_, __) end i_
return deck
method showHand(deck = ArrayList) public static binary
dl = deck.size hl = dl % 4 loop c_ = 0 to dl - 1 by hl d_ = c_ + hl if d_ >= dl then d_ = dl say ArrayList(deck.subList(c_, d_)).toString end c_ say
return</lang>
- Output:
[hA, h2, h3, h4, h5, h6, h7, h8, h9, h10, hJ, hQ, hK] [cA, c2, c3, c4, c5, c6, c7, c8, c9, c10, cJ, cQ, cK] [dA, d2, d3, d4, d5, d6, d7, d8, d9, d10, dJ, dQ, dK] [sA, s2, s3, s4, s5, s6, s7, s8, s9, s10, sJ, sQ, sK] [s8, c10, sJ, c8, h10, h3, s3, d6, hJ, d3, c7, h5, s5] [h8, d10, cK, s6, dQ, d9, d4, c4, c6, h6, cA, sA, dK] [dJ, dA, d7, c2, d2, s10, sK, h2, c5, s7, cJ, d5, h9] [c9, d8, c3, s9, cQ, sQ, h4, s4, hQ, h7, hK, hA, s2]
version 2
<lang NetRexx>/* NetRexx ------------------------------------------------------------
- 08.01.2014 Walter Pachl modified to show state development a la Rexx
- --------------------------------------------------------------------*/
options replace format comments java crossref savelog symbols nobinary
import java.util.List
cards = [String '1','2','3','4','5','6','7','8','9','10'] cardsLen = cards.length deck = ArrayList(cardsLen) loop c_ = 0 to cardsLen - 1
deck.add(String(cards[c_])) end c_
showHand(deck,'In ') deck = ArrayList shuffle(deck) showHand(deck,'Out') return
method shuffle(deck = List) public static binary returns List
rn = Random() dl = deck.size loop i_ = dl - 1 to 1 by -1 j_ = rn.nextInt(i_) __ = deck.get(i_) deck.set(i_, deck.get(j_)) deck.set(j_, __) say i_ j_ ArrayList(deck.subList(0,i_+1)).toString end i_ return deck
method showHand(deck = ArrayList,tag=REXX) public static binary
say tag ArrayList(deck.subList(0,deck.size)).toString return</lang>
- Output:
In [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] 9 5 [1, 2, 3, 4, 5, 10, 7, 8, 9, 6] 8 4 [1, 2, 3, 4, 9, 10, 7, 8, 5] 7 2 [1, 2, 8, 4, 9, 10, 7, 3] 6 0 [7, 2, 8, 4, 9, 10, 1] 5 4 [7, 2, 8, 4, 10, 9] 4 1 [7, 10, 8, 4, 2] 3 2 [7, 10, 4, 8] 2 0 [4, 10, 7] 1 0 [10, 4] Out [10, 4, 7, 8, 2, 9, 1, 3, 5, 6]
Nim
<lang nim>import math randomize()
proc shuffle[T](x: var seq[T]) =
for i in countdown(x.high, 0): let j = random(i + 1) swap(x[i], x[j])
var x = @[0,1,2,3,4,5,6,7,8,9] shuffle(x) echo x</lang>
Objective-C
<lang objc>#import <Foundation/Foundation.h>
@interface NSMutableArray (KnuthShuffle) - (void)knuthShuffle; @end @implementation NSMutableArray (KnuthShuffle) - (void)knuthShuffle {
for (NSUInteger i = self.count-1; i > 0; i--) { NSUInteger j = arc4random_uniform(i+1); [self exchangeObjectAtIndex:i withObjectAtIndex:j]; }
} @end
int main() {
@autoreleasepool { NSMutableArray *x = [NSMutableArray arrayWithObjects:@0, @1, @2, @3, @4, @5, @6, @7, @8, @9, nil]; [x knuthShuffle]; NSLog(@"%@", x); } return 0;
}</lang>
- Output:
( 9, 4, 0, 8, 5, 3, 2, 1, 7, 6 )
OCaml
<lang ocaml>let shuffle arr =
for n = Array.length arr - 1 downto 1 do let k = Random.int (n + 1) in let temp = arr.(n) in arr.(n) <- arr.(k); arr.(k) <- temp done</lang>
Oforth
Works with any object that has the property to be Indexable (Lists, Intervals, ...) Returns a new list
<lang Oforth>Indexable method: shuffle { | s i l |
self size dup ->s ListBuffer newSize dup addAll(self) ->l s loop: i [ i l at s rand dup l at i l put l put ] l dup freeze
}</lang>
Oz
<lang oz>declare
proc {Shuffle Arr} Low = {Array.low Arr} High = {Array.high Arr} in for I in High..Low;~1 do
J = Low + {OS.rand} mod (I - Low + 1)
OldI = Arr.I in
Arr.I := Arr.J
Arr.J := OldI end end
X = {Tuple.toArray unit(0 1 2 3 4 5 6 7 8 9)}
in
{Show {Array.toRecord unit X}} {Shuffle X} {Show {Array.toRecord unit X}}</lang>
PARI/GP
<lang parigp>FY(v)={
forstep(n=#v,2,-1, my(i=random(n)+1,t=v[i]); v[i]=v[n]; v[n]=t ); v
};
FY(vector(52,i,i))</lang>
Pascal
<lang Pascal>program Knuth;
const
max = 10;
type
list = array [1..max] of integer;
procedure shuffle(var a: list); var
i,k,tmp: integer;
begin
randomize; for i := max downto 2 do begin k := random(i) + 1; if (a[i] <> a[k]) then begin tmp := a[i]; a[i] := a[k]; a[k] := tmp end end
end;
{ Test and display } var
a: list; i: integer;
begin
for i := 1 to max do a[i] := i; shuffle(a); for i := 1 to max do write(a[i], ' '); writeln
end.</lang>
- Output:
2 7 10 4 3 5 1 9 6 8
Perl
<lang perl>sub shuffle {
my @a = @_; foreach my $n (1 .. $#a) { my $k = int rand $n + 1; $k == $n or @a[$k, $n] = @a[$n, $k]; } return @a;
}</lang>
Perl 6
<lang perl6>sub shuffle (@a is copy) {
for 1 ..^ @a -> $n { my $k = (0 .. $n).pick; $k == $n or @a[$k, $n] = @a[$n, $k]; } return @a;
}</lang> The shuffle is also built into the pick method on lists when you pass it a "whatever" for the number to pick: <lang perl6>my @deck = @cards.pick(*);</lang>
PHP
<lang php>//The Fisher-Yates original Method function yates_shuffle($arr){ $shuffled = Array(); while($arr){ $rnd = array_rand($arr); $shuffled[] = $arr[$rnd]; array_splice($arr, $rnd, 1); } return $shuffled; }
//The modern Durstenfeld-Knuth algorithm function knuth_shuffle(&$arr){ for($i=count($arr)-1;$i>0;$i--){ $rnd = mt_rand(0,$i); list($arr[$i], $arr[$rnd]) = array($arr[$rnd], $arr[$i]); } }</lang>
PicoLisp
<lang PicoLisp>(de shuffle (Lst)
(make (for (N (length Lst) (gt0 N)) (setq Lst (conc (cut (rand 0 (dec 'N)) 'Lst) (prog (link (car Lst)) (cdr Lst)) ) ) ) ) )</lang>
PL/I
version 1
<lang pli>declare T(0:10) fixed binary initial (1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11); declare (i, j, temp) fixed binary; do i = lbound(T,1) to hbound(T,1);
j = min(random() * 12, 11); temp = T(j); T(j) = T(i); T(i) = temp;
end;</lang>
version 2
<lang pli> kn: Proc Options(main);
/*-------------------------------------------------------------------- * 07.01.2014 Walter Pachl translated from REXX version 2 * Iteration i: only the first i elements are candidates for swapping *-------------------------------------------------------------------*/ Dcl T(10) Bin Fixed(15) Init(1,2,3,4,5,6,7,8,9,10); Dcl (i,j,temp) Bin Fixed(15) init(0); Dcl h Char(6); Call show('In',10); /* show start */ do i = 10 To 2 By -1; /* shuffle */ j=random()*i+1; Put string(h)Edit(i,j)(f(2),f(3)); temp=t(i); t(i)=t(j); t(j)=temp; /* t(i) <-> t(j) */ Call show(h,i); /* show intermediate states */ end; Call show('Out',10); /* show final state */
show: Proc(txt,n); Dcl txt Char(*); Dcl n Bin Fixed(15); Put Edit(txt,(t(k) do k=1 To n))(Skip,a(7),10(f(3))); End; end;</lang>
- Output:
In 1 2 3 4 5 6 7 8 9 10 10 5 1 2 3 4 10 6 7 8 9 5 9 1 9 2 3 4 10 6 7 8 1 8 7 9 2 3 4 10 6 8 7 7 2 9 8 3 4 10 6 2 6 6 9 8 3 4 10 6 5 3 9 8 10 4 3 4 2 9 4 10 8 3 3 9 4 10 2 1 4 9 Out 4 9 10 8 3 6 2 7 1 5
PowerShell
<lang powershell>function shuffle ($a) {
$c = $a.Clone() # make copy to avoid clobbering $a 1..($c.Length - 1) | ForEach-Object { $i = Get-Random -Minimum $_ -Maximum $c.Length $c[$_-1],$c[$i] = $c[$i],$c[$_-1] $c[$_-1] # return newly-shuffled value } $c[-1] # last value
}</lang> This yields the values one by one instead of returning the array as a whole, so the rest of the pipeline can work on the values while shuffling is still in progress.
PureBasic
<lang PureBasic>EnableExplicit
Procedure KnuthShuffle(Array a(1))
Protected i, last = ArraySize(a()) For i = last To 1 Step -1 Swap a(i), a(Random(i)) Next
EndProcedure
Procedure.s ArrayToString(Array a(1))
Protected ret$, i, last = ArraySize(a()) ret$ = Str(a(0)) For i = 1 To last ret$ + "," + Str(a(i)) Next ProcedureReturn ret$
EndProcedure
- NumElements = 10
Dim a(#NumElements-1) Define i
For i = 0 To #NumElements-1
a(i) = i
Next
KnuthShuffle(a()) Debug "shuffled: " + ArrayToString(a())</lang>
- Output:
shuffled: 1,8,6,0,5,9,2,4,7,3
Python
Python's standard library function random.shuffle
uses this algorithm and so should normally be used.
The function below is very similar:
<lang python>from random import randrange
def knuth_shuffle(x):
for i in range(len(x)-1, 0, -1): j = randrange(i + 1) x[i], x[j] = x[j], x[i]
x = list(range(10)) knuth_shuffle(x) print("shuffled:", x)</lang>
- Output:
shuffled: [5, 1, 6, 0, 8, 4, 2, 3, 9, 7]
R
See also, the built-in function 'sample'.
Original Fisher-Yates version <lang r>fisheryatesshuffle <- function(n) {
pool <- seq_len(n) a <- c() while(length(pool) > 0) { k <- sample.int(length(pool), 1) a <- c(a, pool[k]) pool <- pool[-k] } a
}</lang> Knuth variation: <lang r>fisheryatesknuthshuffle <- function(n) {
a <- seq_len(n) while(n >=2) { k <- sample.int(n, 1) if(k != n) { temp <- a[k] a[k] <- a[n] a[n] <- temp } n <- n - 1 } a
}
- Example usage:
fisheryatesshuffle(6) # e.g. 1 3 6 2 4 5 x <- c("foo", "bar", "baz", "quux") x[fisheryatesknuthshuffle(4)] # e.g. "bar" "baz" "quux" "foo"</lang>
Racket
<lang Racket>
- lang racket
(define (swap! vec i j)
(let ([tmp (vector-ref vec i)]) (vector-set! vec i (vector-ref vec j)) (vector-set! vec j tmp)))
(define (knuth-shuffle x)
(if (list? x) (vector->list (knuth-shuffle (list->vector x))) (begin (for ([i (in-range (sub1 (vector-length x)) 0 -1)]) (define r (random i)) (swap! x i r)) x)))
(knuth-shuffle '(1 2 3 4)) </lang>
REBOL
<lang rebol>REBOL [
Title: "Fisher-Yates" Purpose: {Fisher-Yates shuffling algorithm}
]
fisher-yates: func [b [block!] /local n i j k] [
n: length? b: copy b i: n while [i > 1] [ if i <> j: random i [ error? set/any 'k pick b j change/only at b j pick b i change/only at b i get/any 'k ] i: i - 1 ] b
]</lang>
REXX
version 0, card pips
<lang rexx>/*REXX program shuffles a deck of playing cards using the Knuth shuffle.*/ rank='A 2 3 4 5 6 7 8 9 10 J Q K' /*pips of the playing cards. */ suit='♣♠♦♥' /*suit " " " " */ parse arg seed .; if seed\== then call random ,,seed /*repeatability?*/ say '────────────────── getting a new deck out of the box ···' deck.1='highJoker' /*good decks have a color joker, */ deck.2='lowJoker' /*··· and a black & white joker. */ cards=2 /*now, two cards are in the deck.*/
do j =1 for length(suit) do k=1 for words(rank); cards=cards+1 deck.cards=substr(suit,j,1)word(rank,k) end /*k*/ end /*j*/
call showDeck say '────────────────── shuffling' cards "cards ···"
do s=cards by -1 to 2; rand=random(1,s) parse value deck.rand deck.s with deck.s deck.rand /* [↑] swap two cards in the deck*/ end /*s*/
call showDeck exit /*stick a fork in it, we're done.*/ /*──────────────────────────────────SHOWDECK subroutine─────────────────*/ showDeck: _=; do m=1 for cards; _=_ deck.m; end /*m*/; say _; say; return</lang>
- Output:
────────────────── getting a new deck out of the box ··· highJoker lowJoker ♣A ♣2 ♣3 ♣4 ♣5 ♣6 ♣7 ♣8 ♣9 ♣10 ♣J ♣Q ♣K ♠A ♠2 ♠3 ♠4 ♠5 ♠6 ♠7 ♠8 ♠9 ♠10 ♠J ♠Q ♠K ♦A ♦2 ♦3 ♦4 ♦5 ♦6 ♦7 ♦8 ♦9 ♦10 ♦J ♦Q ♦K ♥A ♥2 ♥3 ♥4 ♥5 ♥6 ♥7 ♥8 ♥9 ♥10 ♥J ♥Q ♥K ────────────────── shuffling 54 cards ··· ♥3 ♦7 ♦4 ♥10 ♠K ♠Q ♣K ♣4 ♠3 ♦9 ♥J ♣10 ♦2 ♦3 ♠10 ♦8 ♣9 ♠J ♥5 ♣7 ♠4 ♥9 ♥8 ♠9 ♠7 ♠6 ♠A ♠5 ♥A ♣6 ♣A ♦5 ♥K ♥Q ♦6 ♣Q ♣J ♣8 ♣2 ♦A ♦K ♣3 ♦J ♥4 ♥2 ♥7 ♣5 highJoker ♦10 ♠2 lowJoker ♥6 ♦Q ♠8
version 1, card names
<lang rexx>/*REXX program shuffles a deck of playing cards using the Knuth shuffle.*/ rank = 'ace deuce trey 4 5 6 7 8 9 10 jack queen king' /*use pip names.*/ suit = 'club spade diamond heart' /* " suit " */ say '────────────────── getting a new deck out of the box ···' deck.1 = ' color joker' /*good decks have a color joker, */ deck.2 = ' b&w joker' /*··· and a black & white joker. */ cards=2 /*now, two cards are in the deck.*/
do j =1 for words(suit) do k=1 for words(rank); cards=cards+1 /*bump counter.*/ deck.cards=right(word(suit,j),7) word(rank,k) /*assign.*/ end /*k*/ end /*j*/
call showDeck 'ace' /*inserts blank when ACE is found*/ say '────────────────── shuffling' cards "cards ···"
do s=cards by -1 to 2; rand=random(1,s) /*get random number for swap*/ _=deck.rand; deck.rand=deck.s; deck.s=_ /*swap 2 cards in card deck.*/ end /*s*/
call showDeck exit /*stick a fork in it, we're done.*/ /*──────────────────────────────────SHOWDECK subroutine─────────────────*/ showDeck: parse arg break; say /*get sep card, shows blank line*/
do m=1 for cards /*traipse through the deck. */ if pos(break,deck.m)\==0 then say /*a blank: easier to read cards.*/ say 'card' right(m,2) '───►' deck.m /*display a particular card. */ end /*m*/
say /*show a trailing blank line. */ return</lang>
- Output:
────────────────── getting a new deck out of the box ··· card 1 ───► color joker card 2 ───► b&w joker card 3 ───► club ace card 4 ───► club deuce card 5 ───► club trey card 6 ───► club 4 card 7 ───► club 5 card 8 ───► club 6 card 9 ───► club 7 card 10 ───► club 8 card 11 ───► club 9 card 12 ───► club 10 card 13 ───► club jack card 14 ───► club queen card 15 ───► club king card 16 ───► spade ace card 17 ───► spade duece card 18 ───► spade trey card 19 ───► spade 4 card 20 ───► spade 5 card 21 ───► spade 6 card 22 ───► spade 7 card 23 ───► spade 8 card 24 ───► spade 9 card 25 ───► spade 10 card 26 ───► spade jack card 27 ───► spade queen card 28 ───► spade king card 29 ───► diamond ace card 30 ───► diamond duece card 31 ───► diamond trey card 32 ───► diamond 4 card 33 ───► diamond 5 card 34 ───► diamond 6 card 35 ───► diamond 7 card 36 ───► diamond 8 card 37 ───► diamond 9 card 38 ───► diamond 10 card 39 ───► diamond jack card 40 ───► diamond queen card 41 ───► diamond king card 42 ───► heart ace card 43 ───► heart duece card 44 ───► heart trey card 45 ───► heart 4 card 46 ───► heart 5 card 47 ───► heart 6 card 48 ───► heart 7 card 49 ───► heart 8 card 50 ───► heart 9 card 51 ───► heart 10 card 52 ───► heart jack card 53 ───► heart queen card 54 ───► heart king ────────────────── shuffling 54 cards ··· card 1 ───► diamond king card 2 ───► spade jack card 3 ───► spade 7 card 4 ───► club 4 card 5 ───► heart 7 card 6 ───► heart 10 card 7 ───► club jack card 8 ───► diamond duece card 9 ───► club 10 card 10 ───► diamond 5 card 11 ───► spade 10 card 12 ───► heart jack card 13 ───► club king card 14 ───► diamond 8 card 15 ───► heart 9 card 16 ───► spade ace card 17 ───► spade king card 18 ───► spade trey card 19 ───► color joker card 20 ───► heart 8 card 21 ───► diamond 7 card 22 ───► diamond jack card 23 ───► club duece card 24 ───► club 9 card 25 ───► club 5 card 26 ───► spade 9 card 27 ───► spade queen card 28 ───► heart 5 card 29 ───► spade 6 card 30 ───► club 8 card 31 ───► heart duece card 32 ───► diamond ace card 33 ───► spade 4 card 34 ───► diamond 9 card 35 ───► b&w joker card 36 ───► diamond 4 card 37 ───► heart king card 38 ───► club ace card 39 ───► spade duece card 40 ───► club trey card 41 ───► diamond queen card 42 ───► diamond 10 card 43 ───► spade 8 card 44 ───► diamond trey card 45 ───► club queen card 46 ───► heart ace card 47 ───► heart queen card 48 ───► heart trey card 49 ───► club 7 card 50 ───► club 6 card 51 ───► heart 4 card 52 ───► heart 6 card 53 ───► diamond 6 card 54 ───► spade 5
version 2
<lang rexx>/* REXX ---------------------------------------------------------------
- 05.01.2014 Walter Pachl
- borrow one improvement from version 1
- 06.01.2014 removed -"- (many tests cost more than few "swaps")
- --------------------------------------------------------------------*/
Call random ,,123456 /* seed for random */ Do i=1 To 10; a.i=i; End; /* fill array */ Call show 'In',10 /* show start */ do i = 10 To 2 By -1 /* shuffle */
j=random(i-1)+1; h=right(i,2) right(j,2) Parse Value a.i a.j With a.j a.i /* a.i <-> a.j */ Call show h,i /* show intermediate states */ end;
Call show 'Out',10 /* show fomaö state */ Exit
show: Procedure Expose a. Parse Arg txt,n ol=left(txt,6); Do k=1 To n; ol=ol right(a.k,2); End Say ol Return</lang>
- Output:
In 1 2 3 4 5 6 7 8 9 10 10 2 1 10 3 4 5 6 7 8 9 2 9 6 1 10 3 4 5 9 7 8 6 8 6 1 10 3 4 5 8 7 9 7 3 1 10 7 4 5 8 3 6 5 1 10 7 4 8 5 5 1 8 10 7 4 1 4 1 4 10 7 8 3 1 7 10 4 2 1 10 7 Out 10 7 4 8 1 5 3 9 6 2
Ruby
<lang ruby>class Array
def knuth_shuffle! j = length i = 0 while j > 1 r = i + rand(j) self[i], self[r] = self[r], self[i] i += 1 j -= 1 end self end
end
r = Hash.new(0) 100_000.times do |i|
a = [1,2,3].knuth_shuffle! r[a] += 1
end
r.keys.sort.each {|a| puts "#{a.inspect} => #{r[a]}"}</lang> results in
[1, 2, 3] => 16572 [1, 3, 2] => 16610 [2, 1, 3] => 16633 [2, 3, 1] => 16714 [3, 1, 2] => 16838 [3, 2, 1] => 16633
More idomatic: <lang ruby>class Array
def knuth_shuffle! (length - 1).downto(1) do |i| j = rand(i + 1) self[i], self[j] = self[j], self[i] end self end
end</lang>
Run BASIC
<lang runbasic>dim cards(52) for i = 1 to 52 ' make deck
cards(i) = i
next
for i = 52 to 1 step -1 ' shuffle deck
r = int((rnd(1)*i) + 1) if r <> i then hold = cards(r) cards(r) = cards(i) cards(i) = hold end if
next
print "== Shuffled Cards ==" ' print shuffled cards for i = 1 to 52
print cards(i);" "; if i mod 18 = 0 then print
next print</lang>
Rust
<lang rust>use std::iter; use std::rand; use std::rand::Rng; use std::vec;
fn knuth_shuffle<T>(v: &mut [T]) {
let mut rng = rand::rng(); let l = v.len();
for n in iter::range(0, l) { let i = rng.gen_range(0, l - n); v.swap(i, l - n - 1); }
}
fn main() {
let mut v = vec::from_fn(10, |i| i);
println!("before: {:?}", v); knuth_shuffle(v); println!("after: {:?}", v);
}</lang>
Works as of 2014-01-05.
Scala
<lang Scala>def shuffle[T](a: Array[T]) = {
for (i <- 1 until a.size reverse) { val j = util.Random nextInt (i + 1) val t = a(i) a(i) = a(j) a(j) = t } a
}</lang>
Seed7
<lang seed7>$ include "seed7_05.s7i";
const type: intArray is array integer;
const proc: shuffle (inout intArray: a) is func
local var integer: i is 0; var integer: k is 0; var integer: tmp is 0; begin for i range maxIdx(a) downto 2 do k := rand(1, i); tmp := a[i]; a[i] := a[k]; a[k] := tmp; end for; end func;
const proc: main is func
local var intArray: a is 10 times 0; var integer: i is 0; begin for key i range a do a[i] := i; end for; shuffle(a); for i range a do write(i <& " "); end for; writeln; end func;</lang>
- Output:
7 5 6 8 3 10 9 4 2 1
Sidef
<lang ruby>func shuffle (a) {
{ |n| var k = (n + 1 -> rand.int); k == n || (a[k, n] = a[n, k]); } * a.offset;
return a;
}</lang>
Smalltalk
<lang smalltalk>"The selector swap:with: is documented, but it seems not
implemented (GNU Smalltalk version 3.0.4); so here it is an implementation"
SequenceableCollection extend [
swap: i with: j [ |t| t := self at: i. self at: i put: (self at: j). self at: j put: t. ]
].
Object subclass: Shuffler [
Shuffler class >> Knuth: aSequenceableCollection [ |n k| n := aSequenceableCollection size. [ n > 1 ] whileTrue: [ k := Random between: 1 and: n. aSequenceableCollection swap: n with: k. n := n - 1 ] ]
].</lang> Testing <lang smalltalk>"Test" |c| c := OrderedCollection new. c addAll: #( 1 2 3 4 5 6 7 8 9 ). Shuffler Knuth: c. c display.</lang>
SNOBOL4
<lang SNOBOL4>* Library for random() -include 'Random.sno'
- # String -> array
define('s2a(str,n)i') :(s2a_end)
s2a s2a = array(n); str = str ' ' sa1 str break(' ') . s2a span(' ') = :s(sa1)f(return) s2a_end
- # Array -> string
define('a2s(a)i') :(a2s_end)
a2s a2s = a2s a ' ' :s(a2s)f(return) a2s_end
- # Knuth shuffle in-place
define('shuffle(a)alen,n,k,tmp') :(shuffle_end)
shuffle n = alen = prototype(a); sh1 k = convert(random() * alen,'integer') + 1
eq(a<n>,a<k>) :s(sh2) tmp = a<n>; a<n> = a<k>; a<k> = tmp
sh2 n = gt(n,1) n - 1 :s(sh1)
shuffle = a :(return)
shuffle_end
- # Test and display
a = s2a('1 2 3 4 5 6 7 8 9 10',10) output = a2s(a) '->' shuffle(a) output = a2s(a)
end</lang>
- Output:
1 2 3 4 5 6 7 8 9 10 -> 2 10 4 9 1 5 6 8 7 3
Swift
Uses generics to allow shuffling arrays of any type.
<lang swift>import Darwin
func shuffle<T>(inout array: [T]) {
for i in 1..<array.count { let j = Int(arc4random_uniform(UInt32(i))) (array[i], array[j]) = (array[j], array[i]) }
}</lang>
Test program
<lang swift>var array = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] println(array) shuffle(&array) println(array)</lang>
- Output:
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10] [2, 5, 7, 1, 6, 10, 4, 3, 8, 9]
Tcl
<lang tcl>proc knuth_shuffle lst {
set j [llength $lst] for {set i 0} {$j > 1} {incr i;incr j -1} { set r [expr {$i+int(rand()*$j)}] set t [lindex $lst $i] lset lst $i [lindex $lst $r] lset lst $r $t } return $lst
}
% knuth_shuffle {1 2 3 4 5} 2 1 3 5 4 % knuth_shuffle {1 2 3 4 5} 5 2 1 4 3 % knuth_shuffle {tom dick harry peter paul mary} tom paul mary harry peter dick</lang> As a test of skewing (an indicator of a poor implementation) this code was used: <lang tcl>% for {set i 0} {$i<100000} {incr i} {
foreach val [knuth_shuffle {1 2 3 4 5}] pos {pos0 pos1 pos2 pos3 pos4} { incr tots($pos) $val }
} % parray tots tots(pos0) = 300006 tots(pos1) = 300223 tots(pos2) = 299701 tots(pos3) = 299830 tots(pos4) = 300240</lang>
TI-83 BASIC
Input L1, output L2.
:"SHUFFLE" :L1→L2 :dim(L2)→A :For(B,1,dim(L2)-1) :randInt(1,A)→C :L2(C)→D :L2(A)→L2(C) :D→L2(A) :A-1→A :End :DelVar A :DelVar B :DelVar C :DelVar D :Return
TUSCRIPT
<lang tuscript>$$ MODE TUSCRIPT oldnumbers=newnumbers="",range=20 LOOP nr=1,#range
oldnumbers=APPEND(oldnumbers,nr)
ENDLOOP
PRINT "before ",oldnumbers
LOOP r=#range,1,-1
RANDNR=RANDOM_NUMBERS (1,#r,1) shuffle=SELECT (oldnumbers,#randnr,oldnumbers) newnumbers=APPEND(newnumbers,shuffle)
ENDLOOP
PRINT "after ",newnumbers</lang>
- Output:
before 1'2'3'4'5'6'7'8'9'10'11'12'13'14'15'16'17'18'19'20 after 7'16'13'11'1'9'15'4'18'14'3'12'17'8'19'20'6'5'2'10
UNIX Shell
<lang bash># Shuffle array[@]. function shuffle { integer i j t
((i = ${#array[@]})) while ((i > 1)); do ((j = RANDOM)) # 0 <= j < 32768 ((j < 32768 % i)) && continue # no modulo bias ((j %= i)) # 0 <= j < i
((i -= 1)) ((t = array[i])) ((array[i] = array[j])) ((array[j] = t)) done }
- Test program.
set -A array 11 22 33 44 55 66 77 88 99 110 shuffle echo "${array[@]}"</lang>
Ursala
This function works on lists of any type and length, including character strings. <lang Ursala>shuffle = @iNX ~&l->r ^jrX/~&l ~&lK8PrC</lang> test program: <lang Ursala>#cast %s
example = shuffle 'abcdefghijkl'</lang>
- Output:
'keacfjlbdigh'
VBScript
- Implementation
<lang vb> function shuffle( a ) dim i dim r randomize timer for i = lbound( a ) to ubound( a ) r = int( rnd * ( ubound( a ) + 1 ) ) if r <> i then swap a(i), a(r) end if next shuffle = a end function
sub swap( byref a, byref b ) dim tmp tmp = a a = b b = tmp end sub</lang>
- Invocation
<lang vb>dim a a = array( 1,2,3,4,5,6,7,8,9) wscript.echo "before: ", join( a, ", " ) shuffle a wscript.echo "after: ", join( a, ", " ) shuffle a wscript.echo "after: ", join( a, ", " ) wscript.echo "--" a = array( now(), "cow", 123, true, sin(1), 16.4 ) wscript.echo "before: ", join( a, ", " ) shuffle a wscript.echo "after: ", join( a, ", " ) shuffle a wscript.echo "after: ", join( a, ", " )</lang>
- Output:
before: 1, 2, 3, 4, 5, 6, 7, 8, 9 after: 6, 4, 1, 2, 7, 3, 5, 8, 9 after: 8, 7, 3, 2, 6, 5, 9, 1, 4 -- before: 16/02/2010 5:46:58 PM, cow, 123, True, 0.841470984807897, 16.4 after: True, 16.4, 16/02/2010 5:46:58 PM, 123, cow, 0.841470984807897 after: 16.4, 16/02/2010 5:46:58 PM, 123, 0.841470984807897, True, cow
Vedit macro language
The shuffle routine in Playing Cards shuffles text lines in edit buffer. This example shuffles numeric registers #0 to #19.
The output will be inserted in current edit buffer. <lang vedit>// Test main
- 90 = Time_Tick // seed for random number generator
- 99 = 20 // number of items in the array
IT("Before:") IN for (#100 = 0; #100 < #99; #100++) {
#@100 = #100 Num_Ins(#@100, LEFT+NOCR) IT(" ")
} IN
Call("SHUFFLE_NUMBERS")
IT("After:") IN for (#100 = 0; #100 < #99; #100++) {
Num_Ins(#@100, LEFT+NOCR) IT(" ")
} IN Return
//-------------------------------------------------------------- // Shuffle numeric registers #0 to #nn // #99 = number of registers to shuffle (nn-1) //
- SHUFFLE_NUMBERS:
for (#91 = #99-1; #91 > 0; #91--) {
Call("RANDOM") #101 = Return_Value #102 = #@101; #@101 = #@91; #@91 = #102
} Return
//-------------------------------------------------------------- // Generate random numbers in range 0 <= Return_Value < #91 // #90 = Seed (0 to 0x7fffffff) // #91 = Scaling (0 to 0x10000) //
- RANDOM:
- 92 = 0x7fffffff / 48271
- 93 = 0x7fffffff % 48271
- 90 = (48271 * (#90 % #92) - #93 * (#90 / #92)) & 0x7fffffff
Return ((#90 & 0xffff) * #91 / 0x10000)</lang>
- Output:
Before: 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 After: 9 13 8 18 10 1 17 15 0 16 14 19 3 2 7 11 6 4 5 12
zkl
Two versions, imperative and functional, same results. xs has to be a mutable list. <lang zkl>fcn kshuffle(xs){foreach i in ([xs.len()-1..1,-1]){
xs.swap(i,(0).random(0,i+1))} xs
} fcn kshufflep(xs){[xs.len()-1..1,-1].pump(Void,'wrap(i){
xs.swap(i,(0).random(0,i+1))})
}</lang>
var ns=(1).pump(10,List).copy() // [1..10] made mutable kshuffle(ns) //-->L(6,3,8,2,4,5,10,9,1,7) ns="this is a test foo bar hoho".split(" ").copy(); kshufflep(ns) //-->L("a","bar","hoho","foo","test","is","this")
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