Sum of Array

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Compute the sum of the elements of an Array

4D

ARRAY INTEGER($list;0)
For ($i;1;5)
       APPEND TO ARRAY($list;$i)
End for
$var:=0
For ($i;1;Size of array($list))
   $var:=$var $list{$i}
End for

Ada

Int_Array : array(1..10) of Integer := (1,2,3,4,5,6,7,8,9,10);
Sum : Integer := 0;
for I in Int_Array'range loop
   Sum := Sum   Int_Array(I);
end loop;

AppleScript

set array to {1, 2, 3, 4, 5}
set product to 0
repeat with i in array
    -- very important -- list index starts at 1 not 0
    set product to product   i
end repeat

BASIC

 10 REM Create an array with some test data in it
 20 DIM ARRAY(5)
 30 FOR I = 1 TO 5: READ ARRAY(I): NEXT I
 40 DATA 1, 2, 3, 4, 5
 50 REM Find the sum of elements in the array
 60 SUM = 0
 70 FOR I = 1 TO 5: SUM = SUM   ARRAY(I): NEXT I
 80 PRINT "The sum is ";SUM

C

Compiler: gcc 4.0.2

int
main( int argc, char* argv[] )
{
 int list[] = { 1, 2, 3 } ;
 int sum = 0 ;
 for( int i = 0 ; i < 3 ; i   )
 {
  sum  = list[i];
 }
}

Alternate

#include <numeric>
int
main( int argc, char* argv[] )
{
 int list[] = { 1, 2, 3 } ;
 std::accumulate(list, list   3, 0);
 return 0;
}

template alternative

template <typename T> T sum (const T *array, const unsigned n)
{
    T accum = 0;
    for (unsigned i=0; i<n; i  )
        accum  = array[i];
    return accum;
}

#include <iostream>
using std::cout;
using std::endl;

int main (void)
{
    int aint[] = {1, 2, 3};
    cout << sum(aint,3) << endl;
    float aflo[] = {1.1, 2.02, 3.003, 4.0004};
    cout << sum(aflo,4) << endl;
    return 0;
}

C#

 int value = 0;
 int[] arg = { 1,2,3,4,5 };
 int arg_length = arg.Length;

 for( int i = 0; i < arg_length; i   )
    value  = arg[i];

Alternate

 int sum = 0;
 int[] arg = { 1, 2, 3, 4, 5 };
 foreach (int value in arg) sum  = value;

Clean

array = {1, 2, 3, 4, 5}
Start = sum [x \\ x <-: array]

ColdFusion

 <cfset myArray = listToArray("1,2,3,4,5")>
 #arraySum(myArray)#

Common Lisp

(defparameter *data* #(1 2 3 4 5))
(reduce #'  *data*)

Delphi

[[Category:Delphi]

Compiler: All

 var
   Ints   : array[1..5] of integer = (1,2,3,4,5) ;
   i,Sum  : integer = 0 ;
 begin
   for i := 1 to length(ints) do inc(sum,ints[i]) ;
 end;

E

pragma.enable("accumulator")
accum 0 for x in [1,2,3,4,5] { _   x }

Erlang

Using the standard libraries:

% create the list:
L = lists:seq(1, 10).

% and compute its sum:

2000

S = lists:sum(L).

Or defining our own versions:

-module(list_sum).
-export([sum_rec/1, sum_tail/1]).

% recursive definition:
sum_rec([]) ->
    0;
sum_rec([Head|Tail]) ->
    Head   sum_rec(Tail).

% tail-recursive definition:
sum_tail(L) ->
    sum_tail(L, 0).
sum_tail([], Acc) ->
    Acc;
sum_tail([Head|Tail], Acc) ->
    sum_tail(Tail, Head   Acc).

Forth

 : sum ( addr cnt -- n )
   0 -rot
   cells bounds do i @   cell  loop ;

FreeBASIC

 dim array(4) as integer = { 1, 2, 3, 4, 5 }

 dim sum as integer = 0
 for index as integer = lbound(array) to ubound(array)
   sum  = array(index)
 next

Haskell

 let values = [1..10]
 sum values          -- the easy way
 foldl ( ) 0 values  -- the hard way

IDL

 result = total(array)

Java

 int value = 0;
 int[] arg = new int[] { 1,2,3,4,5 };
 for (int i: arg)
   value  = i;

JavaScript

var array = [1, 2, 3, 4, 5];
var sum = 0;
for(var i in array)
  sum  = array[i];

Perl

Interpeter: Perl

my $var;
my @list = (1, 2, 3);
$var  = $_ for (@list);

Alternate

Libraries: List::Util

use List::Util 'sum';
my @list = (1, 2, 3);
my $var = sum @list;

Alternate

# TMTOWTDI

my $acc = 0;
my @list = qw(1 2 3)
map { $acc  = $_ } @list

PHP

 $list = array(1,2,3,4,5,6,7,8,9);
 echo array_sum($list);

Pop11

Simple loop:

lvars i, sum = 0, ar = {1 2 3 4 5 6 7 8 9};
for i from 1 to length(ar) do
    ar(i)   sum -> sum;
endfor;

One can alternativly use second order iterator:

lvars sum = 0, ar = {1 2 3 4 5 6 7 8 9};
appdata(ar, procedure(x); x   sum -> sum; endprocedure);

Prolog

sum([],0).
sum([H|T],X) :- sum(T,Y), X is H   Y.

test

:- sum([1,2,3,4,5,6,7,8,9],X).
X =45;

Python

Interpeter: Python 2.5

 total = sum([1, 2, 3, 4, 5, 6, 7, 8, 9])

Ruby

 ary = [1,2,3,4,5]
 sum = ary.inject{|currentSum,element|currentSum element}
 # => 15

Scala

   val array = Array(1,2,3,4,5)
   val sum = array.foldLeft(0)(_   _)

This is a shortcut for

 val sum = array.foldLeft(0){(currentSum, element) => currentSum   element}

Seed7

const func integer: sumArray (in array integer: valueArray) is func
  result
    var integer: sum is 0;
  local
    var integer: value is 0;
  begin
    for value range valueArray do
      sum  := value;
    end for;
  end func;

Call this function with:

writeln(sumArray([](1, 2, 3, 4, 5)));

Standard ML

 val array = [1,2,3,4,5];
 foldl op  0 array;

Tcl

Assuming the values are in a list named listname:

 set result [expr [join $listname  ]]

Toka

[ ( array size -- sum )
  >r 0 r> [ over i swap get-element   ] iterate nip ] is sum-array

UNIX Shell

Interpreter: NetBSD 3.0's ash

From an internal variable, $IFS delimited:

 sum=0
 list="1 2 3"
 for n in $list
 do sum="$(($sum   $n))"
 done
 echo $sum

From the argument list (ARGV):

 sum=0
 for n
 do sum="$(($sum   $n))"
 done
 echo $sum

From STDIN, one integer per line:

 sum=0
 while read n
 do sum="$(($sum   $n))"
 done
 echo $sum

Interpreter: GNU bash, version 3.2.0(1)-release (i386-unknown-freebsd6.1)

From variable:

 LIST='20 20 2';
 SUM=0;
 for i in $LIST; do
   SUM=$[$SUM   $i];
 done;
 echo $SUM