Sort an integer array
Sort an array (or list) of integers in ascending numerical order. Use a sorting facility provided by the language/library if possible.
You are encouraged to solve this task according to the task description, using any language you may know.
4D
English
<lang 4d>ARRAY INTEGER($nums;0) APPEND TO ARRAY($nums;2) APPEND TO ARRAY($nums;4) APPEND TO ARRAY($nums;3) APPEND TO ARRAY($nums;1) APPEND TO ARRAY($nums;2) SORT ARRAY($nums) ` sort in ascending order SORT ARRAY($nums;<) ` sort in descending order</lang>
Français
<lang 4d>TABLEAU ENTIER($nombres;0) AJOUTER A TABLEAU($nombres;2) AJOUTER A TABLEAU($nombres;4) AJOUTER A TABLEAU($nombres;3) AJOUTER A TABLEAU($nombres;1) AJOUTER A TABLEAU($nombres;2) TRIER TABLEAU($nombres) ` pour effectuer un tri par ordre croissant TRIER TABLEAU($nombres;<) ` pour effectuer un tri par ordre décroissant</lang>
ActionScript
<lang ActionScript>//Comparison function must returns Numbers even though it deals with integers. function compare(x:int, y:int):Number { return Number(x-y); } var nums:Vector.<int> = Vector.<int>([5,12,3,612,31,523,1,234,2]); nums.sort(compare);</lang>
Ada
<lang ada>with Gnat.Heap_Sort_G;
procedure Integer_Sort is
-- Heap sort package requires data to be in index values starting at
-- 1 while index value 0 is used as temporary storage
type Int_Array is array(Natural range <>) of Integer;
Values : Int_Array := (0,1,8,2,7,3,6,4,5);
-- define move and less than subprograms for use by the heap sort package
procedure Move_Int(From : Natural; To : Natural) is
begin
Values(To) := Values(From);
end Move_Int;
function Lt_Int(Left, Right : Natural) return Boolean is
begin
return Values(Left) < Values (Right);
end Lt_Int;
-- Instantiate the generic heap sort package
package Heap_Sort is new Gnat.Heap_Sort_G(Move_Int, Lt_Int);
begin
Heap_Sort.Sort(8);
end Integer_Sort;
requires an Ada05 compiler, e.g GNAT GPL 2007 with Ada.Containers.Generic_Array_Sort;
procedure Integer_Sort is
--
type Int_Array is array(Natural range <>) of Integer;
Values : Int_Array := (0,1,8,2,7,3,6,4,5);
-- Instantiate the generic sort package from the standard Ada library
procedure Sort is new Ada.Containers.Generic_Array_Sort
(Index_Type => Natural,
Element_Type => Integer,
Array_Type => Int_Array);
begin
Sort(Values);
end Integer_Sort;</lang>
ALGOL 68
<lang algol68>CO PR READ "shell_sort.a68" PR CO MODE TYPE = INT;
PROC in place shell sort = (REF[]TYPE seq)REF[]TYPE:(
INT inc := ( UPB seq + LWB seq + 1 ) OVER 2;
WHILE inc NE 0 DO
FOR index FROM LWB seq TO UPB seq DO
INT i := index;
TYPE el = seq[i];
WHILE ( i - LWB seq >= inc | seq[i - inc] > el | FALSE ) DO
seq[i] := seq[i - inc];
i -:= inc
OD;
seq[i] := el
OD;
inc := IF inc = 2 THEN 1 ELSE ENTIER(inc * 5 / 11) FI
OD;
seq
);
PROC shell sort = ([]TYPE seq)[]TYPE:
in place shell sort(LOC[LWB seq: UPB seq]TYPE:=seq);
print((shell sort((2, 4, 3, 1, 2)), new line))</lang> Output:
+1 +2 +2 +3 +4
APL
<lang apl> X←63 92 51 92 39 15 43 89 36 69
X[⍋X]
15 36 39 43 51 63 69 89 92 92</lang>
AutoHotkey
<lang AutoHotkey>numbers = 5 4 1 2 3 sort, numbers, N D%A_Space% Msgbox % numbers</lang>
Befunge
Elements of the array are read from standard input, preceded by their quantity. The algorithm uses counting sort and allows numbers between 1 and 60, inclusive. <lang Befunge>v > 543** > :#v_ $&> :#v_ 1 > :0g > :#v_ $ 1+: 543** `! #v_ 25*,@
^-1p0\0:< ^-1 p0\+1 g0:&< ^-1\.:\<
^ <</lang>
C
<lang c>#include <stdlib.h> /* qsort() */
- include <stdio.h> /* printf() */
int intcmp(const void *aa, const void *bb) {
const int *a = aa, *b = bb; return (*a < *b) ? -1 : (*a > *b);
}
int main() {
int nums[5] = {2,4,3,1,2};
qsort(nums, 5, sizeof(int), intcmp);
printf("result: %d %d %d %d %d\n",
nums[0], nums[1], nums[2], nums[3], nums[4]);
return 0;
}</lang>
Caution: An older version of intcmp() did return *a - *b. This is only correct when the subtraction does not overflow. Suppose that *a = 2000000000 and *b = -2000000000 on a machine with 32-bit int. The subtraction *a - *b would overflow to -294967296, and intcmp() would believe *a < *b, but the correct answer is *a > *b.
C++
Simple Array
<lang cpp>#include <algorithm>
int main() {
int nums[] = {2,4,3,1,2};
std::sort(nums, nums+5);
return 0;
}</lang>
std::vector
<lang cpp>#include <algorithm>
- include <vector>
int main() {
std::vector<int> nums; nums.push_back(2); nums.push_back(4); nums.push_back(3); nums.push_back(1); nums.push_back(2); std::sort(nums.begin(), nums.end()); return 0;
}</lang>
std::list
<lang cpp>#include <list>
int main() {
std::list<int> nums; nums.push_back(2); nums.push_back(4); nums.push_back(3); nums.push_back(1); nums.push_back(2); nums.sort(); return 0;
}</lang>
C#
<lang csharp>using System; using System.Collections.Generic;
public class Program {
static void Main() {
int[] unsorted = { 6, 2, 7, 8, 3, 1, 10, 5, 4, 9 };
Array.Sort(unsorted);
}
}</lang>
Clean
We use list and array comprehensions to convert an array to and from a list in order to use the built-in sort on lists. <lang clean>import StdEnv
sortArray :: (a e) -> a e | Array a e & Ord e sortArray array = {y \\ y <- sort [x \\ x <-: array]}
Start :: {#Int} Start = sortArray {2, 4, 3, 1, 2}</lang>
Clojure
<lang clojure>(sort [5 4 3 2 1]) ; sort can also take a comparator function (1 2 3 4 5)</lang>
Common Lisp
In Common Lisp, the sort function takes a predicate that is used as the comparator. This parameter can be any two-argument function. To sort a sequence (list or array) of integers, call sort with the < operator as the predicate: <lang lisp>CL-USER> (sort #(9 -2 1 2 8 0 1 2) #'<)
- (-2 0 1 1 2 2 8 9)</lang>
D
<lang d>import std.stdio, std.algorithm;
void main() {
auto data = [2, 4, 3, 1, 2]; data.sort(); // in-place assert(data == [1, 2, 2, 3, 4]);
}</lang>
Delphi
<lang Delphi>uses Types, Generics.Collections;
var
a: TIntegerDynArray;
begin
a := TIntegerDynArray.Create(5, 4, 3, 2, 1); TArray.Sort<Integer>(a);</lang>
E
<lang e>[2,4,3,1,2].sort()</lang>
Erlang
<lang erlang>List = [2, 4, 3, 1, 2]. SortedList = lists:sort(List).</lang>
Euphoria
<lang euphoria>include sort.e print(1,sort({20, 7, 65, 10, 3, 0, 8, -60}))</lang>
Factor
<lang factor>{ 1 4 9 2 3 0 5 } natural-sort .</lang>
Fantom
The List collection contains a sort method which uses the usual comparison method for the data in the list; the sort is done 'in place'.
fansh> a := [5, 1, 4, 2, 3] [5, 1, 4, 2, 3] fansh> a.sort [1, 2, 3, 4, 5] fansh> a [1, 2, 3, 4, 5]
Forth
<lang forth>create test-data 2 , 4 , 3 , 1 , 2 , test-data 5 cell-sort</lang>
Fortran
<lang fortran>CALL ISORT@(b, a, n) ! n = number of elements ! a = array to be sorted ! b = array of indices of a. b(1) 'points' to the minimum value etc.</lang>
F#
<lang fsharp>// sorting an array in place let nums = [| 2; 4; 3; 1; 2 |] Array.sortInPlace nums
// create a sorted copy of a list let nums2 = [2; 4; 3; 1; 2] let sorted = List.sort nums2</lang>
GAP
<lang gap>a := [ 8, 2, 5, 9, 1, 3, 6, 7, 4 ];
- Make a copy (with "b := a;", b and a would point to the same list)
b := ShallowCopy(a);
- Sort in place
Sort(a); a;
- [ 1, 2, 3, 4, 5, 6, 7, 8, 9 ]
- Sort without changing the argument
SortedList(b);
- [ 1, 2, 3, 4, 5, 6, 7, 8, 9 ]
b;
- [ 8, 2, 5, 9, 1, 3, 6, 7, 4 ]</lang>
Go
<lang go>package main import "fmt" import "sort"
func main() {
nums := []int {2, 4, 3, 1, 2}
sort.Ints(nums)
fmt.Println(nums)
}</lang>
Golfscript
<lang golfscript>[2 4 3 1 2]$</lang>
Groovy
<lang groovy>println ([2,4,0,3,1,2,-12].sort())</lang>
Output:
[-12, 0, 1, 2, 2, 3, 4]
Haskell
<lang haskell>nums = [2,4,3,1,2] :: [Int] sorted = List.sort nums</lang>
HicEst
<lang hicest>DIMENSION array(100)
array = INT( RAN(100) ) SORT(Vector=array, Sorted=array) </lang>
IDL
<lang idl>result = array[sort(array)]</lang>
Icon and Unicon
Icon and Unicon lists allow mixed type and the built-in function 'sort' will deal with mixed type arrays by sorting by type first then value. Integers sort before, reals, strings, lists, tables, etc. As a result a list of mixed numeric valuess (i.e. integers and reals) will not sort by numeric value, rather the reals will appear after the integers. Sort returns a sorted copy of it's argument. It will also perform some type conversion, such converting an unordered set into an ordered list.
In the example below, L will remain an unsorted list and S will be sorted. <lang Icon>S := sort(L:= [63, 92, 51, 92, 39, 15, 43, 89, 36, 69]) # will sort a list</lang>
Io
<lang lua>mums := list(2,4,3,1,2) sorted := nums sort # returns a new sorted array. 'nums' is unchanged nums sortInPlace # sort 'nums' "in-place"</lang>
Inform 7
<lang inform7>let L be {5, 4, 7, 1, 18}; sort L;</lang>
J
<lang j>/:~</lang> The verb /:~ sorts anything. For example:
<lang j> ] a=: 10 ?@$ 100 NB. random vector 63 92 51 92 39 15 43 89 36 69
/:~ a
15 36 39 43 51 63 69 89 92 92</lang>
Arrays of any rank are treated as lists of component arrays. Thus /:~ sorts not only atoms within a list, but whole lists within a table, tables within a three-axis array, and so on. The level of structure at which sorting occurs may also be specified, so that /:~"1 sorts the atoms within the finest-grained list within the array, regardless of the overall rank of the array.
This code also applies to any data type.
Java
Array
<lang java>import java.util.Arrays;
public class example {
public static void main(String[] args)
{
int[] nums = {2,4,3,1,2};
Arrays.sort(nums);
}
}</lang>
List
<lang java5>import java.util.Arrays; import java.util.Collections; import java.util.List;
public class example {
public static void main(String[] args)
{
List<Integer> nums = Arrays.asList(2,4,3,1,2);
Collections.sort(nums);
}
}</lang>
JavaScript
JavaScript sorts lexically by default, so "10000" comes before "2". To sort numerically, a custom comparator is used.
<lang javascript>function numberSorter(a, b) {
return a - b;
} var numbers = [20, 7, 65, 10, 3, 0, 8, -60]; numbers.sort(numberSorter); alert( numbers );</lang>
K
<lang k>
num: -10?10 / Integers from 0 to 9 in random order
5 9 4 2 0 3 6 1 8 7
srt: {x@<x} / Generalized sort ascending
srt num
0 1 2 3 4 5 6 7 8 9 </lang>
Liberty BASIC
LB has an array-sort command. Parameters are arrayname, start term, finish term. <lang lb> N =20 dim IntArray( N)
print "Original order" for i =1 to N
t =int( 1000 *rnd( 1)) IntArray( i) =t print t
next i
sort IntArray(), 1, N
print "Sorted oprder" for i =1 to N
print IntArray( i)
next i </lang>
Lua
<lang lua>t = {4, 5, 2} table.sort(t) print(unpack(t))</lang>
Mathematica
<lang mathematica>numbers = Sort[{2,4,3,1,2}]</lang>
MATLAB
<lang Matlab>a = [4,3,7,-2,9,1]; b = sort(a) % b contains elements of a in ascending order [b,idx] = sort(a) % b contains a(idx)</lang>
MAXScript
<lang maxscript>arr = #(5, 4, 3, 2, 1) arr = sort arr</lang>
Mercury
<lang>
- - module sort_int_list.
- - interface.
- - import_module io.
- - pred main(io::di, uo::uo) is det.
- - implementation.
- - import_module list.
main(!IO) :-
Nums = [2, 4, 0, 3, 1, 2], list.sort(Nums, Sorted), io.write(Sorted, !IO), io.nl(!IO).
</lang>
Modula-3
Modula-3 provides a generic ArraySort module, as well as an instance of that module for integers called IntArraySort. <lang modula3>MODULE ArraySort EXPORTS Main;
IMPORT IntArraySort;
VAR arr := ARRAY [1..10] OF INTEGER{3, 6, 1, 2, 10, 7, 9, 4, 8, 5};
BEGIN
IntArraySort.Sort(arr);
END ArraySort.</lang>
MUMPS
<lang MUMPS>SORTARRAY(X,SEP)
;X is the list of items to sort ;X1 is the temporary array ;SEP is the separator string between items in the list X ;Y is the returned list ;This routine uses the inherent sorting of the arrays NEW I,X1,Y SET Y="" FOR I=1:1:$LENGTH(X,SEP) SET X1($PIECE(X,SEP,I))="" SET I="" FOR SET I=$O(X1(I)) Q:I="" SET Y=$SELECT($L(Y)=0:I,1:Y_SEP_I) KILL I,X1 QUIT Y</lang>
Output:
USER>W $$SORTARRAY^ROSETTA("3,5,1,99,27,16,0,-1",",")
-1,0,1,3,5,16,27,99
NetRexx
<lang NetRexx>/* NetRexx */ options replace format comments java crossref savelog symbols binary
ia = int[] ia = [ 2, 4, 3, 1, 2, -1, 0, -2 ]
display(ia) Arrays.sort(ia) display(ia)
-- Display results method display(in = int[]) public static
sorted = Rexx()
loop ix = 0 for in.length sorted = sorted || Rexx(in[ix]).right(4) end ix
say sorted.strip('t')
return
</lang>
Output
2 4 3 1 2 -1 0 -2 -2 -1 0 1 2 2 3 4
NetRexx reimplementations of the Rexx samples from below:
<lang NetRexx>/* NetRexx */ options replace format comments java crossref savelog symbols
/*REXX program to sort an integer array.*/
numeric digits 20 /*handle larger numbers.*/ a = a[ 1]= 1 a[ 2]= 0 a[ 3]= -1 a[ 4]= 0 a[ 5]= 5 a[ 6]= 0 a[ 7]= -61 a[ 8]= 0 a[ 9]= 1385 a[10]= 0 a[11]= -50521 a[12]= 0 a[13]= 2702765 a[14]= 0 a[15]= -199360981 a[16]= 0 a[17]= 19391512145 a[18]= 0 a[19]= -2404879675441 a[20]= 0 a[21]= 370371188237525
size = 21 /*we have a list of 21 Euler numbers.*/ tell('un-sorted', a, size) a[0] = size esort(a, 1) tell(' sorted', a, size)
return
/*----------------------------------ESORT subroutine--------------------*/ method esort(a, size) public static --esort: procedure expose a.;
h = a[0]
loop while h > 1
h = h % 2
loop i = 1 for a[0] - h
j = i
k = h + i
loop while a[k] < a[j]
t = a[j]
a[j] = a[k]
a[k] = t
if h >= j then leave
j = j - h
k = k - h
end
end i
end
return
/*----------------------------------TELL subroutine---------------------*/ method tell(arg, a, size) public static --tell:
say arg.center(40, '-') loop j = 1 for size say arg 'array element' j.right(size.length)'='a[j].right(25) end j say
return
</lang>
Output
---------------un-sorted---------------- un-sorted array element 1= 1 un-sorted array element 2= 0 un-sorted array element 3= -1 un-sorted array element 4= 0 un-sorted array element 5= 5 un-sorted array element 6= 0 un-sorted array element 7= -61 un-sorted array element 8= 0 un-sorted array element 9= 1385 un-sorted array element 10= 0 un-sorted array element 11= -50521 un-sorted array element 12= 0 un-sorted array element 13= 2702765 un-sorted array element 14= 0 un-sorted array element 15= -199360981 un-sorted array element 16= 0 un-sorted array element 17= 19391512145 un-sorted array element 18= 0 un-sorted array element 19= -2404879675441 un-sorted array element 20= 0 un-sorted array element 21= 370371188237525 --------------- sorted---------------- sorted array element 1= -2404879675441 sorted array element 2= -199360981 sorted array element 3= -50521 sorted array element 4= -61 sorted array element 5= -1 sorted array element 6= 0 sorted array element 7= 0 sorted array element 8= 0 sorted array element 9= 0 sorted array element 10= 0 sorted array element 11= 0 sorted array element 12= 0 sorted array element 13= 0 sorted array element 14= 0 sorted array element 15= 0 sorted array element 16= 1 sorted array element 17= 5 sorted array element 18= 1385 sorted array element 19= 2702765 sorted array element 20= 19391512145 sorted array element 21= 370371188237525
<lang NetRexx>/* NetRexx */ options replace format comments java crossref savelog symbols
/*REXX program to sort an interesting integer list.*/
bell = '1 1 2 5 15 52 203 877 4140 21147 115975' /*some Bell numbers.*/ bern = '1 -1 1 0 -1 0 1 0 -1 0 5 0 -691 0 7 0 -3617' /*some Bernoulli num*/ perrin = '3 0 2 3 2 5 5 7 10 12 17 22 29 39 51 68 90' /*some Perrin nums. */ list = bell bern perrin /*combine the three.*/
size = list.words
a = 0 loop j = 1 for size
a[j] = list.word(j) end j
say ' as is='list a[0] = size esort(a, size) bList =
loop j = 1 for size
bList = bList a[j] end j
blist = bList.strip say ' sorted='bList
return
/*----------------------------------ESORT subroutine--------------------*/ method esort(a, size) public static --esort: procedure expose a.;
h = a[0]
loop while h > 1
h = h % 2
loop i = 1 for a[0] - h
j = i
k = h + i
loop while a[k] < a[j]
t = a[j]
a[j] = a[k]
a[k] = t
if h >= j then leave
j = j - h
k = k - h
end
end i
end
return </lang>
Output
as is=1 1 2 5 15 52 203 877 4140 21147 115975 1 -1 1 0 -1 0 1 0 -1 0 5 0 -691 0 7 0 -3617 3 0 2 3 2 5 5 7 10 12 17 22 29 39 51 68 90 sorted=-3617 -691 -1 -1 -1 0 0 0 0 0 0 0 0 1 1 1 1 1 2 2 2 3 3 5 5 5 5 7 7 10 12 15 17 22 29 39 51 52 68 90 203 877 4140 21147 115975
Nial
<lang nial>sort >= 9 6 8 7 1 10 = 10 9 8 7 6 1</lang>
Niue
Library <lang Niue>2 6 1 0 3 8 sort .s 0 1 2 3 6 8 </lang>
Objective-C
<lang objc>- (void)example {
NSArray *nums, *sorted;
nums = [NSArray arrayWithObjects:
[NSNumber numberWithInt:2],
[NSNumber numberWithInt:4],
[NSNumber numberWithInt:3],
[NSNumber numberWithInt:1],
[NSNumber numberWithInt:2],
nil];
sorted = [nums sortedArrayUsingSelector:@selector(compare:)];
}</lang>
Objeck
<lang objeck>bundle Default {
class Sort {
function : Main(args : System.String[]) ~ Nil {
nums := Structure.IntVector->New([2,4,3,1,2]);
nums->Sort();
}
}
}</lang>
OCaml
Array
<lang ocaml>let nums = [|2; 4; 3; 1; 2|] Array.sort compare nums</lang>
List
<lang ocaml>let nums = [2; 4; 3; 1; 2] let sorted = List.sort compare nums</lang>
Octave
The variable v can be a vector or a matrix (columns will be sorted).
<lang octave>sortedv = sort(v);</lang>
Oz
<lang oz>declare
Nums = [2 4 3 1 2]
Sorted = {List.sort Nums Value.'<'}
in
{Show Sorted}</lang>
PARI/GP
<lang parigp>vecsort(v)</lang>
Perl
<lang perl>@nums = (2,4,3,1,2); @sorted = sort {$a <=> $b} @nums;</lang>
Perl 6
If @a contains only numbers:
<lang perl6>my @sorted = sort @a;</lang>
If some elements of @a are strings or are otherwise non-numeric but you want to treat them as numbers:
<lang perl6>my @sorted = sort +*, @a;</lang>
For an in-place sort:
<lang perl6>@a .= sort;</lang>
PHP
<lang php><?php $nums = array(2,4,3,1,2); sort($nums); ?></lang>
PicoLisp
The sort function in PicoLisp returns already by default an ascending list (of any type, not only integers): <lang PicoLisp>(sort (2 4 3 1 2)) -> (1 2 2 3 4)</lang>
PL/I
<lang pli>DCL (T(10)) FIXED BIN(31); /* scratch space of length N/2 */
MERGE: PROCEDURE (A,LA,B,LB,C);
DECLARE (A(*),B(*),C(*)) FIXED BIN(31);
DECLARE (LA,LB) FIXED BIN(31) NONASGN;
DECLARE (I,J,K) FIXED BIN(31);
I=1; J=1; K=1;
DO WHILE ((I <= LA) & (J <= LB));
IF(A(I) <= B(J)) THEN
DO; C(K)=A(I); K=K+1; I=I+1; END;
ELSE
DO; C(K)=B(J); K=K+1; J=J+1; END;
END;
DO WHILE (I <= LA);
C(K)=A(I); I=I+1; K=K+1;
END;
RETURN;
END MERGE;
MERGESORT: PROCEDURE (A,N) RECURSIVE ;
DECLARE (A(*)) FIXED BINARY(31);
DECLARE N FIXED BINARY(31) NONASGN;
DECLARE Temp FIXED BINARY;
DECLARE (M,I) FIXED BINARY;
DECLARE AMP1(N) FIXED BINARY(31) BASED(P);
DECLARE P POINTER;
IF (N=1) THEN RETURN;
M = trunc((N+1)/2);
IF (M>1) THEN CALL MERGESORT(A,M);
P=ADDR(A(M+1));
IF (N-M > 1) THEN CALL MERGESORT(AMP1,N-M);
IF A(M) <= AMP1(1) THEN RETURN;
DO I=1 to M; T(I)=A(I); END;
CALL MERGE(T,M,AMP1,N-M,A);
RETURN;
END MERGESORT;</lang>
Pop11
Pop11 library function sorts lists. So we first convert array to list, then sort and finally convert back:
<lang pop11>lvars ar = {2 4 3 1 2};
- Convert array to list.
- destvector leaves its results and on the pop11 stack + an integer saying how many there were
destvector(ar);
- conslist uses the items left on the stack plus the integer, to make a list of those items.
lvars ls = conslist();
- Sort it
sort(ls) -> ls;
- Convert list to array
destlist(ls); consvector() -> ar;</lang>
The above can be abbreviated to more economical, but possibly more opaque, syntax, using pop11 as a functional language:
<lang pop11>lvars ar = {2 4 3 1 2}; consvector(destlist(sort(conslist(destvector(ar))))) -> ar;
- print the sorted vector
ar =>
- {1 2 2 3 4}</lang>
(The list created by conslist will be garbage-collected.)
Alternatively, using the datalist function, even more economically:
<lang pop11>lvars ar = {2 4 3 1 2}; consvector(destlist(sort(datalist(ar)))) -> ar;</lang>
or in Forth-like pop11 postfix syntax:
<lang pop11>lvars ar = {2 4 3 1 2}; ar.datalist.sort.destlist.consvector -> ar;</lang>
PowerBASIC
PowerBASIC has several options available for sorting. At its simplest, an array (of any type) is sorted using ARRAY SORT:
<lang powerbasic>ARRAY SORT x()</lang>
Options are available to limit sorting to only part of the array, collate string arrays, sort multiple arrays together, etc. (Details here.)
PowerShell
<lang powershell>34,12,23,56,1,129,4,2,73 | Sort-Object</lang>
Prolog
?- msort([10,5,13,3, 85,3,1], L). L = [1,3,3,5,10,13,85].
Note that sort/2 remove duplicates.
PureBasic
<lang PureBasic>Dim numbers(20) For i = 0 To 20
numbers(i) = Random(1000)
Next
SortArray(numbers(), #PB_Sort_Ascending)</lang>
Python
<lang python>nums = [2,4,3,1,2] nums.sort()</lang>
Note: The array nums is sorted in place.
Interpreter: Python 2.4 (and above)
You could also use the built-in sorted() function
<lang python>nums = sorted([2,4,3,1,2])</lang>
R
<lang r>nums <- c(2,4,3,1,2) sorted <- sort(nums)</lang>
Raven
Sort list in place:
<lang raven>[ 2 4 3 1 2 ] sort</lang>
REBOL
<lang rebol>sort [2 4 3 1 2]</lang>
REXX
This version creates an array with 20 random integers, then sorts it. <lang rexx> /*REXX program to sort an integer array.*/
numeric digits 20 /*handle larger numbers.*/ a.1= 1 a.2= 0 a.3= -1 a.4= 0 a.5= 5 a.6= 0 a.7= -61 a.8= 0 a.9= 1385
a.10= 0 a.11= -50521 a.12= 0 a.13= 2702765 a.14= 0 a.15= -199360981 a.16= 0 a.17= 19391512145 a.18= 0 a.19= -2404879675441 a.20= 0 a.21= 370371188237525
size=21 /*we have a list of 21 Euler numbers.*/ call tell 'un-sorted' a.0=size call esort 1,size call tell ' sorted' exit
/*----------------------------------ESORT subroutine--------------------*/
esort: procedure expose a.; h=a.0
do while h>1; h=h%2
do i=1 for a.0-h; j=i; k=h+i
do while a.k<a.j
t=a.j; a.j=a.k; a.k=t; if h>=j then leave; j=j-h; k=k-h
end
end
end
return
/*----------------------------------TELL subroutine---------------------*/
tell: say center(arg(1),40,'-')
do j=1 for size say arg(1) 'array element' right(j,length(size))'='right(a.j,20) end
say return </lang> Output:
---------------un-sorted---------------- un-sorted array element 1= 1 un-sorted array element 2= 0 un-sorted array element 3= -1 un-sorted array element 4= 0 un-sorted array element 5= 5 un-sorted array element 6= 0 un-sorted array element 7= -61 un-sorted array element 8= 0 un-sorted array element 9= 1385 un-sorted array element 10= 0 un-sorted array element 11= -50521 un-sorted array element 12= 0 un-sorted array element 13= 2702765 un-sorted array element 14= 0 un-sorted array element 15= -199360981 un-sorted array element 16= 0 un-sorted array element 17= 19391512145 un-sorted array element 18= 0 un-sorted array element 19= -2404879675441 un-sorted array element 20= 0 un-sorted array element 21= 370371188237525 --------------- sorted---------------- sorted array element 1= -2404879675441 sorted array element 2= -199360981 sorted array element 3= -50521 sorted array element 4= -61 sorted array element 5= -1 sorted array element 6= 0 sorted array element 7= 0 sorted array element 8= 0 sorted array element 9= 0 sorted array element 10= 0 sorted array element 11= 0 sorted array element 12= 0 sorted array element 13= 0 sorted array element 14= 0 sorted array element 15= 0 sorted array element 16= 1 sorted array element 17= 5 sorted array element 18= 1385 sorted array element 19= 2702765 sorted array element 20= 19391512145 sorted array element 21= 370371188237525
This version creates a list with a bunch of interesting integers,
then sorts it.
Because it so much more efficient to sort an array, an array is
built from the list, sorted, than the list is re-constituted.
<lang rexx>
/*REXX program to sort an interesting integer list.*/
bell='1 1 2 5 15 52 203 877 4140 21147 115975' /*some Bell numbers.*/ bern='1 -1 1 0 -1 0 1 0 -1 0 5 0 -691 0 7 0 -3617' /*some Bernoulli num*/ perrin='3 0 2 3 2 5 5 7 10 12 17 22 29 39 51 68 90' /*some Perrin nums. */ list=bell bern perrin /*combine the three.*/
size=words(list)
do j=1 for size a.j=word(list,j) end
say ' as is='list a.0=size call esort 1,size bList=
do j=1 for size bList=bList a.j end
blist=strip(bList) say 'sorted='bList exit
/*----------------------------------ESORT subroutine--------------------*/
esort:procedure expose a.;h=a.0
do while h>1;h=h%2
do i=1 for a.0-h;j=i; k=h+i
do while a.k<a.j;_=a.j;a.j=a.k;a.k=_;if h>=j then leave;j=j-h;k=k-h;end
end
end
return </lang> Output:
as is=1 1 2 5 15 52 203 877 4140 21147 115975 1 -1 1 0 -1 0 1 0 -1 0 5 0 -691 0 7 0 -3617 3 0 2 3 2 5 5 7 10 12 17 22 29 39 51 68 90 sorted=-3617 -691 -1 -1 -1 0 0 0 0 0 0 0 0 1 1 1 1 1 2 2 2 3 3 5 5 5 5 7 7 10 12 15 17 22 29 39 51 52 68 90 203 877 4140 21147 115975
Ruby
<lang ruby>nums = [2,4,3,1,2] sorted = nums.sort # returns a new sorted array. 'nums' is unchanged nums.sort! # sort 'nums' "in-place"</lang>
Scala
<lang scala>println(List(5,2,78,2,578,-42).sortWith(_<_)) //--> List(-42, 2, 2, 5, 78, 578)</lang>
Scheme
Same as Common Lisp <lang scheme>(sort #(9 -2 1 2 8 0 1 2) #'<)</lang>
Seed7
<lang seed7>var array integer: nums is [] (2, 4, 3, 1, 2);
nums := sort(nums);</lang>
Slate
<lang slate> #(7 5 2 9 0 -1) sort</lang>
Smalltalk
<lang smalltalk> #(7 5 2 9 0 -1) asSortedCollection</lang>
Standard ML
Array
<lang sml>val nums = Array.fromList [2, 4, 3, 1, 2]; ArrayQSort.sort Int.compare nums;</lang>
List
<lang sml>val nums = [2, 4, 3, 1, 2]; val sorted = ListMergeSort.sort (op >) nums;</lang>
Tcl
<lang tcl>set result [lsort -integer $unsorted_list]</lang>
TI-83 BASIC
Store input into L1, run prgmSORTBTIN, and L2 will be L1, only sorted.
:L1→L2 :SortA(L2)
SortA is found via: [LIST] → ENTER. SortD is also available for a descending sort.
Toka
This can be done by using the bubble sort library:
<lang toka>needs bsort arrayname number_elements bsort</lang>
See the Toka entry on Bubble Sort for a full example.
UNIX Shell
Each shell parameter separates the integers using the default IFS whitespace (space, tab, newline).
<lang bash>nums="2 4 3 1 5" sorted=`printf "%s\n" $nums | sort -n` echo $nums # prints 1 2 3 4 5</lang>
Alternate solution: sorted=`for i in $nums; do echo $i; done | sort -n`
Some shells have real arrays. You still need IFS to split the string from sort -n to an array.
<lang bash>set -A nums 2 4 3 1 5 set -A sorted $(printf "%s\n" ${nums[*]} | sort -n) echo ${nums[*]} # prints 1 2 3 4 5</lang>
Users of bash, ksh93 and mksh can probably use the nums=(2 4 3 1 2) syntax.
Ursala
using the built in sort operator, -<, with the nleq library function for comparing natural numbers <lang Ursala>#import nat
- cast %nL
example = nleq-< <39,47,40,53,14,23,88,52,78,62,41,92,88,66,5,40></lang> output:
<5,14,23,39,40,40,41,47,52,53,62,66,78,88,88,92>
Yorick
In Yorick, sort returns an index list into the array that will put it in sorted order. <lang yorick> nums = [2,4,3,1,2]; nums = nums(sort(nums)); </lang>