Monty Hall problem: Difference between revisions

#"Another simpler(my opinion) way to do this is below, also in python 3:"

# "1 represents a car"

# "0 represent a goat"

stay = 0 # "amount won if stay in the same position "

switch = 0 #" amount won if you switch "

lst = [1,0,0] #" one car and two goats"

random.shuffle(lst) #" shffles the list randomly"

ran = random.randrange(3) #" gets a random number for the random guess"

user = lst[ran] #"storing the random guess "

del(lst[ran]) #" deleting the random guess"

for i in lst: #" getting a value 0 and deleting it"

del(lst[huh]) #" deletes a goat when it finds it"

if user ==1: #" if the original choice is 1 then stay adds 1"

if lst[0] == 1: #" if the switched value is 1 then switch adds 1"

#" Done by Sam Witton 09/04/2014"