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Averages/Arithmetic mean: Difference between revisions
Added Q solution.
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(Added Q solution.) |
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>>> mean([Decimal(big), Decimal(-big), 3, 1, 4, 1, 5, 9, 1/Decimal(big), -1/Decimal(big)])
Decimal('2.3')</lang>
=={{header|Q}}==
A built-in solution is <tt>avg</tt>. An implementation of it could be:
<lang q>mean:{(sum x)%count x}</lang>
=={{header|R}}==
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