Rosetta Code/Rank languages by number of users: Difference between revisions
Rosetta Code/Rank languages by number of users (view source)
Revision as of 06:32, 17 May 2021
, 3 years agoA Python implementation
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(A Python implementation) |
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19: 59 - Common Lisp
20: 58 - AWK
</pre>
=={{header|Python}}==
{{libheader|requests}}
<lang python>"""Rank languages by number of users. Requires Python >=3.5"""
import requests
# MediaWiki API URL.
URL = "http://rosettacode.org/mw/api.php"
# Query string parameters
PARAMS = {
"action": "query",
"format": "json",
"formatversion": 2,
"generator": "categorymembers",
"gcmtitle": "Category:Language users",
"gcmlimit": 500,
"prop": "categoryinfo",
}
def fetch_data():
counts = {}
continue_ = {"continue": ""}
# Keep making HTTP requests to the MediaWiki API if more records are
# available.
while continue_:
resp = requests.get(URL, params={**PARAMS, **continue_})
resp.raise_for_status()
data = resp.json()
# Grab the title (language) and size (count) only.
counts.update(
{
p["title"]: p.get("categoryinfo", {}).get("size", 0)
for p in data["query"]["pages"]
}
)
continue_ = data.get("continue", {})
return counts
if __name__ == "__main__":
# Request data from the MediaWiki API.
counts = fetch_data()
# Filter out languages that have less than 100 users.
at_least_100 = [(lang, count) for lang, count in counts.items() if count >= 100]
# Sort languages by number of users
top_languages = sorted(at_least_100, key=lambda x: x[1], reverse=True)
# Pretty print
for i, lang in enumerate(top_languages):
print(f"{i+1:<5}{lang[0][9:][:-5]:<20}{lang[1]}")
</lang>
{{out}}
<pre>
1 C 423
2 Java 308
3 C++ 301
4 Python 301
5 JavaScript 279
6 PHP 182
7 Perl 181
8 SQL 158
9 UNIX Shell 149
10 Pascal 130
11 C sharp 130
12 BASIC 129
13 Haskell 111
14 Ruby 102
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