Comma quibbling: Difference between revisions
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=={{header|Tcl}}== |
=={{header|Tcl}}== |
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<lang tcl>proc commaQuibble {lst} { |
<lang tcl>proc commaQuibble {lst} { |
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if {[llength $lst] > 1} { |
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} |
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return \{[join $lst ", "]\} |
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} |
} |
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Revision as of 00:50, 7 October 2013
![Task](http://static.miraheze.org/rosettacodewiki/thumb/b/ba/Rcode-button-task-crushed.png/64px-Rcode-button-task-crushed.png)
You are encouraged to solve this task according to the task description, using any language you may know.
Comma quibbling is a task originally set by Eric Lippert in his blog.
The task is to write a function to generate a string output which is the concatenation of input words from a list/sequence where:
- An input of no words produces the output string of just the two brace characters "{}".
- An input of just one word, e.g. ["ABC"], produces the output string of the word inside the two braces, e.g. "{ABC}".
- An input of two words, e.g. ["ABC", "DEF"], produces the output string of the two words inside the two braces with the words separated by the string " and ", e.g. "{ABC and DEF}".
- An input of three or more words, e.g. ["ABC", "DEF", "G", "H"], produces the output string of all but the last word separated by ", " with the last word separated by " and " and all within braces; e.g. "{ABC, DEF, G and H}".
Test your function with the following series of inputs showing your output here on this page:
- [] # (No input words).
- ["ABC"]
- ["ABC", "DEF"]
- ["ABC", "DEF", "G", "H"]
Note: Assume words are non-empty strings of uppercase characters for this task.
AWK
<lang awk>function quibble(a, n, i, s) { for (i = 1; i < n - 1; i++) s = s a[i] ", " i = n - 1; if (i > 0) s = s a[i] " and " if (n > 0) s = s a[n] return "{" s "}" }
BEGIN { print quibble(a, 0) n = split("ABC", b); print quibble(b, n) n = split("ABC DEF", c); print quibble(c, n) n = split("ABC DEF G H", d); print quibble(d, n) }</lang>
- Output:
{} {ABC} {ABC and DEF} {ABC, DEF, G and H}
C#
<lang csharp>public static string Quibble(string[] input) {
var len = input.Length; return "{ " + String.Join("", input.Take(len - 2).Select(n => n + ", ") .Concat(input.Skip(len < 2 ? len : len - 2).Take(1).Select(n => n + " and "))) + (input.LastOrDefault() ?? "") + " }";
} static void Main(string[] args) {
Console.WriteLine(Quibble(new string[] { })); Console.WriteLine(Quibble(new[] { "A" })); Console.WriteLine(Quibble(new[] { "A", "B" })); Console.WriteLine(Quibble(new[] { "A", "B", "C" })); Console.WriteLine(Quibble(new[] { "A", "B", "C", "D" })); Console.WriteLine(Quibble(new[] { "A", "B", "C", "D", "E" }));
}</lang>
- Output:
{ } { A } { A and B } { A, B and C } { A, B, C and D } { A, B, C, D and E }
C++
<lang cpp>#include <iostream>
template<class T> void quibble(std::ostream& o, T i, T e) {
o << "{"; if (e != i) { T n = i++; const char* more = ""; while (e != i) { o << more << *n; more = ", "; n = i++; } o << (*more?" and ":"") << *n; } o << "}";
}
int main(int argc, char** argv) {
char const* a[] = {"ABC","DEF","G","H"}; for (int i=0; i<5; i++) { quibble(std::cout, a, a+i); std::cout << std::endl; } return 0;
}</lang>
- Output:
{} {ABC} {ABC and DEF} {ABC, DEF and G} {ABC, DEF, G and H}
Clojure
<lang clojure> (defn quibbling [sequence]
(let [sep (if (> (count sequence) 1) " and " "")] (apply str (concat (interpose ", " (butlast sequence)) [sep (last sequence)]))))
(map quibbling [[]
["ABC"] ["ABC", "DEF"] ["ABC", "DEF", "G", "H"]])
</lang>
- Output:
("" "ABC" "ABC and DEF" "ABC, DEF, G and H")
D
<lang d>import std.stdio, std.string;
string quibbler(in string[] seq) pure /*nothrow*/ {
if (seq.length <= 1) return format("{%-(%s, %)}", seq); else return format("{%-(%s, %) and %s}", seq[0 .. $-1], seq[$-1]);
}
void main() {
//foreach (immutable test; [[], foreach (const test; [[], ["ABC"], ["ABC", "DEF"], ["ABC", "DEF", "G", "H"]]) test.quibbler.writeln;
}</lang>
- Output:
{} {ABC} {ABC and DEF} {ABC, DEF, G and H}
F#
<lang fsharp>let quibble list =
let rec inner = function | [] -> "" | [x] -> x | [x;y] -> sprintf "%s and %s" x y | h::t -> sprintf "%s, %s" h (inner t) sprintf "{%s}" (inner list)
// test interactively quibble [] quibble ["ABC"] quibble ["ABC"; "DEF"] quibble ["ABC"; "DEF"; "G"] quibble ["ABC"; "DEF"; "G"; "H"]</lang>
Perl
<lang perl>sub comma_quibbling(@) { my @A = @_; return "{$_}" for @_ < 3 ? join(' and ', @A) : join(',', @A[0..@A-2]) . ' and ' . $A[-1]; }
print comma_quibbling(@$_), "\n" for [], [qw(ABC)], [qw(ABC DEF)], [qw(ABC DEF G H)];</lang>
- Output:
{} {ABC} {ABC and DEF} {ABC,DEF,G and H}
Perl 6
<lang perl6>sub comma-quibbling(@A) {
"\{$_\}" given @A < 3 ?? @A.join(' and ') !! @A[0..*-2].join(',') ~ ' and ' ~ @A[*-1]
}
say comma-quibbling($_) for ((), (<ABC>,), (<ABC DEF>), (<ABC DEF G H>)).tree;</lang>
- Output:
{} {ABC} {ABC and DEF} {ABC,DEF,G and H}
Python
<lang python>>>> def strcat(sequence): # replace(..) can only replace the first X occurrences not the last # Hence the replace is done on the reverse of the intermediate string # then reversed back. return '{%s}' % ', '.join(sequence)[::-1].replace(',', 'dna ', 1)[::-1]
>>> for seq in ([], ["ABC"], ["ABC", "DEF"], ["ABC", "DEF", "G", "H"]): print('Input: %-24r -> Output: %r' % (seq, strcat(seq)))
Input: [] -> Output: '{}'
Input: ['ABC'] -> Output: '{ABC}'
Input: ['ABC', 'DEF'] -> Output: '{ABC and DEF}'
Input: ['ABC', 'DEF', 'G', 'H'] -> Output: '{ABC, DEF, G and H}'
>>> </lang>
PL/I
<lang pli>*process or(!);
quib: Proc Options(main); /********************************************************************* * 06.10.2013 Walter Pachl *********************************************************************/ put Edit(quibbling())(Skip,a); put Edit(quibbling('ABC'))(Skip,a); put Edit(quibbling('ABC DEF'))(Skip,a); put Edit(quibbling('ABC DEF G H'))(Skip,a); return;
quibbling: proc(s) Returns(Char(100) Var); Dcl s Char(*); Dcl result Char(100) Var; Dcl (wi,p) Bin Fixed(31); If s= Then result=; Else Do; Do wi=1 By 1 While(s^=); p=index(s,' '); If p=0 Then Do; If wi>1 Then result=result!!' and '!!s; else result=s; s=; End; Else Do; If wi=1 Then result=left(s,p-1); Else result=result!!', '!!left(s,p-1); s=substr(s,p+1); End; End; End; Return('{'!!result!!'}'); End; End;</lang>
- Output:
{} {ABC} {ABC, DEF} {ABC, DEF, G, H}
REXX
<lang rexx>say quibbling() say quibbling('ABC') say quibbling('ABC DEF') say quibbling('ABC DEF G H') exit
quibbling: procedure
parse arg list Select When list= Then result= When words(list)=1 then result=word(list,1) Otherwise result=translate(strip(subword(list,1,words(list)-1)),',',' '), 'and' word(list,words(list)) End Return '{'result'}'</lang>
- Output:
{} {ABC} {ABC and DEF} {ABC,DEF,G and H}
Rust
<lang Rust>fn quibble(seq: &[~str]) -> ~str {
match seq { [] => ~"{}", [ref w] => fmt!("{%s}", *w), [..ws, ref w] => fmt!("{%s and %s}", ws.connect(", "), *w), }
}
fn main() {
println(quibble([~"ABC"])); println(quibble([~"ABC", ~"DEF"])); println(quibble([~"ABC", ~"DEF", ~"G", ~"H"]));
}</lang>
- Output:
{ABC} {ABC and DEF} {ABC, DEF, G and H}
Scala
<lang scala>def quibble( s:List[String] ) = s match {
case m if m.isEmpty => "{}" case m if m.length < 3 => m.mkString("{", " and ", "}") case m => "{" + m.init.mkString(", ") + " and " + m.last + "}"
}
// A little test... {
println( quibble( List() ) ) println( quibble( List("ABC") ) ) println( quibble( List("ABC","DEF") ) ) println( quibble( List("ABC","DEF","G","H") ) )
}</lang>
- Output:
{} {ABC} {ABC and DEF} {ABC, DEF, G and H}
Tcl
<lang tcl>proc commaQuibble {lst} {
return \{[join [lreplace $lst end-1 end [join [lrange $lst end-1 end] " and "]] ", "]\}
}
foreach input { {} {"ABC"} {"ABC" "DEF"} {"ABC" "DEF" "G" "H"} } {
puts [commaQuibble $input]
}</lang>
- Output:
{} {ABC} {ABC and DEF} {ABC, DEF, G and H}
UNIX Shell
<lang bash>quibble() { # Here awk(1) is easier than sed(1). awk 'BEGIN { for (i = 1; i < ARGC - 2; i++) s = s ARGV[i] ", " i = ARGC - 2; if (i > 0) s = s ARGV[i] " and " i = ARGC - 1; if (i > 0) s = s ARGV[i] printf "{%s}\n", s exit 0 }' "$@" }
quibble quibble ABC quibble ABC DEF quibble ABC DEF G H</lang>
- Output:
{} {ABC} {ABC and DEF} {ABC, DEF, G and H}