Input/Output for pairs of numbers: Difference between revisions

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}</lang>
}</lang>



=={{header|PARI/GP}}==

Interestingly, this task is not possible to implement directly in GP, since <code>input()</code>, like the gp REPL itself, ignores spaces. One must use PARI:
<lang c>#include <stdio.h>
#include <stdlib.h>
#include <pari/pari.h>

int main(void);
int
main()
{
int i, n, a, b;
GEN f, sum;
pari_sp ltop;
// 1 MB stack, not using prime table
pari_init(1000000, 0);
scanf("%d", &n);
GEN f = cgetg(n+1, t_VEC);

for (i = 1; i <= n; i++) {
if (2 != scanf("%d %d", &a, &b)) abort();
ltop = avma;
// Add a and b in PARI
sum = addii(stoi(a), stoi(b));
// Store the sum in a vector, collecting garbage as you go.
gel(f, i) = gerepileupto(ltop, sum);
}

pari_printf("%Ps", f);
return 0;
}</lang>
Of course for such a simple task this has very little advantage over C, but it does demonstrate the general principle.


=={{header|Perl 6}}==
=={{header|Perl 6}}==

Revision as of 13:51, 17 June 2014

Input/Output for pairs of numbers is a draft programming task. It is not yet considered ready to be promoted as a complete task, for reasons that should be found in its talk page.

From lines of input starting with a line containing the numbers of pairs to follows, followed by that number of pairs of integers separated by a space on separate lines from STDIN, output the sum of each pair to STDOUT.


Sample input with corresponding output

Input

5
1 2
10 20
-3 5
100 2
5 5

Output

3
30
2
102
10

AWK

<lang awk>NR == 1 {n=$1; next} NR > n+1 {exit} {print $1+$2}</lang>

C

<lang C>#include <stdio.h>

  1. include <stdlib.h>

int main(void) { int i, n, a, b, *f; scanf("%d", &n); f = malloc(sizeof(*f) * n);

for (i = 0; i < n; i++) { if (2 != scanf("%d %d", &a, &b)) abort(); f[i] = a + b; }

for (i = 0; i < n; i++) printf("%d\n", f[i]);

return 0; }</lang>

Output for example input

3
30
2
102
10

C++

Modified in order to take in all inputs and then give the output, the original gave the output for each pair immediately. <lang cpp> /*Modified by Abhishek Ghosh, 19th March 2014, Rotterdam*/

  1. include <iostream>

using namespace std;

int doStuff(int a, int b) {

   return a + b;

}

int main() {

int t, **list;

cin >> t;

list = new int*[t];

for(int j=0; j<t; j++){

list[j] = new int[2]; cin >> list[j][0]>> list[j][1];

}

cout << endl;

for(int j=0;j<t;j++){ cout << doStuff(list[j][0], list[j][1]) << endl;; } return 0; } </lang>

Run as per given input

5
1 2
10 20
-3 5
100 2
5 5

3
30
2
102
10


D

This works with any number of integers on lines. <lang d>void main() {

   import std.stdio, std.string, std.conv, std.algorithm;
   foreach (immutable _; 0 .. readln.strip.to!uint)
       readln.split.to!(int[]).sum.writeln;

}</lang>

Haskell

This solution will actually add any number of integers placed on each line. Additionally, after removing the bits of code that cut out the specified number of lines, the solution will sum any number of lines of integers.

<lang Haskell>main = do

   contents <- getContents
   let numberOfLines  =  read.head.lines$ contents
       nums  =  map (map read.words).take numberOfLines.tail.lines$ contents
       sums  =  map sum nums
   mapM_ print sums</lang>

J

<lang J> $ cat <<EOF | jconsole -js '([: exit 0: [: smoutput [: ,. [: ({. {. }.) [: (+/"1) [: (0&".;._2) (1!:1)) 3' > 5 > 1 2 > 10 20 > -3 5 > 100 2 > 5 5 > EOF

 3
30
 2

102

10

</lang> Considerably simpler than [explanation] output for lines of text, this sentence is a single fork. J pads the numeric arrays of 0&".;._2 (numbers cut) with 0 . We form the +/"1 (row sums), then take the sum of the first row of the beheaded sums ({. {. }.) for display. ,. (raveled items) reshapes the vector into a column-vector shaped matrix. And the [: (cap) causes the monadic form of the verb to cap's right.

Java

<lang java>import java.util.Scanner;

public class Main {

public static int doStuff(int a, int b){ int sum = a+b; return sum; }

public static void main(String[] args) { Scanner in = new Scanner(System.in);

int n = in.nextInt(); for(int i=0; i<n; i++){ int a = in.nextInt(); int b= in.nextInt(); int result = doStuff(a, b); System.out.println(result); } } }</lang>


PARI/GP

Interestingly, this task is not possible to implement directly in GP, since input(), like the gp REPL itself, ignores spaces. One must use PARI: <lang c>#include <stdio.h>

  1. include <stdlib.h>
  2. include <pari/pari.h>

int main(void);

int main() {

 int i, n, a, b;
 GEN f, sum;
 pari_sp ltop;
 
 // 1 MB stack, not using prime table
 pari_init(1000000, 0);
 
 scanf("%d", &n);
 GEN f = cgetg(n+1, t_VEC);
 for (i = 1; i <= n; i++) {
   if (2 != scanf("%d %d", &a, &b)) abort();
   ltop = avma;

// Add a and b in PARI sum = addii(stoi(a), stoi(b));

// Store the sum in a vector, collecting garbage as you go. gel(f, i) = gerepileupto(ltop, sum);

 }
 pari_printf("%Ps", f);
 return 0;

}</lang> Of course for such a simple task this has very little advantage over C, but it does demonstrate the general principle.

Perl 6

<lang perl6>for ^get() { say [+] get.words }</lang> This does more than the task asks. It will sum as many numbers as you care to put on each line, and the numbers need not be integers, but may also be a mix of rational, floating-point, or complex numbers. More subtly, get can read from a file specified as a command-line argument, but defaults to taking STDIN if no filename is specified.

Python

<lang python>def do_stuff(a, b): return a + b

t = input() for x in range(0, t): a, b = raw_input().strip().split() print do_stuff(int(a), int(b))</lang>

Python: Alternative

Or without the function do_stuff() and that works for Python 3 and Python 2: <lang python>>>> try: raw_input except NameError: raw_input = input

>>> for i in range(int(raw_input())): print(sum(int(numberstring) for numberstring in raw_input().strip().split()))


5 1 2 3 10 20 30 -3 5 2 100 2 102 5 5 10 >>> </lang> (All but the first line of single numbers, (the 5), is output from the program).

Python: With prompts

More than is asked for by the task, but if working interactively then the following version adds prompts. <lang python>>>> for i in range(int(raw_input('lines: '))): print(sum(int(numberstring)

                 for numberstring in raw_input('two numbers: ').strip().split()))


lines: 5 two numbers: 1 2 3 two numbers: 10 20 30 two numbers: -3 5 2 two numbers: 100 2 102 two numbers: 5 5 10 >>> </lang>

Racket

<lang Racket>#lang racket

(define line-number (read)) ;reads all kind of things
(for ([i (in-range line-number)])
(displayln (+ (read) (read))))

(define line-count (string->number ;only reads numbers

                   (string-trim (read-line)))) 

(for ([i (in-range line-count)])

 (displayln (apply + 
                   (map string->number 
                        (string-split (read-line))))))</lang>

REXX

This version isn't limited to summing integers, any form of number that REXX supports can be used. <lang rexx>/*REXX pgm reads a number, then reads that # of pairs, writes their sum.*/

      do  linein()                    /*read the number of pairs to add*/
      x=linein()                      /*read a line (record) from input*/
      say word(x,1) + word(x,2)       /*write the sum of a pair of nums*/
      end
                                      /*stick a fork in it, we're done.*/</lang>

Ruby

<lang ruby>def do_stuff(a, b) a + b end

t = gets.to_i for i in 1..t do a, b = gets.strip.split.map {|i| i.to_i} puts do_stuff(a, b) end</lang>

Tcl

<lang tcl>gets stdin n while {$n > 0} {

   if {[scan [gets stdin] "%d %d" a b] == 2} {
       puts [expr {$a + $b}]
   }
   incr n -1

}</lang>

UNIX Shell

Works with: Bourne Again SHell

<lang bash>read n while (( n > 0 )); do

   read a b
   echo $((a+b))
   ((n--))

done</lang>

zkl

Using the console as the input stream: <lang zkl>fcn pairs{

  n:=ask("num pairs: ").toInt(); 
  do(n){ask("1 pair: ").split(" ").sum().println()}

}</lang>

Output:
pairs()
num pairs: 5
1 pair: 1 2
3
1 pair: 10 20
30
1 pair: -3 5
2
1 pair: 100 2
102
1 pair: 5 5 
10