Hough transform: Difference between revisions
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=={{header|Racket}}== |
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* see [[Example:Hough transform/Racket]] |
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=={{header|Ruby}}== |
=={{header|Ruby}}== |
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Revision as of 06:09, 10 June 2014
You are encouraged to solve this task according to the task description, using any language you may know.
Implement the Hough transform, which is used as part of feature extraction with digital images. It is a tool that makes it far easier to identify straight lines in the source image, whatever their orientation.
The transform maps each point in the target image, , to the average color of the pixels on the corresponding line of the source image (in -space, where the line corresponds to points of the form ). The idea is that where there is a straight line in the original image, it corresponds to a bright (or dark, depending on the color of the background field) spot; by applying a suitable filter to the results of the transform, it is possible to extract the locations of the lines in the original image.
The target space actually uses polar coordinates, but is conventionally plotted on rectangular coordinates for display. There's no specification of exactly how to map polar coordinates to a flat surface for display, but a convenient method is to use one axis for and the other for , with the center of the source image being the origin.
There is also a spherical Hough transform, which is more suited to identifying planes in 3D data.
BBC BASIC
BBC BASIC uses Cartesian coordinates so the image is 'upside down' compared with some other solutions.
<lang bbcbasic> Width% = 320
Height% = 240
VDU 23,22,Width%;Height%;8,16,16,128
*DISPLAY Pentagon.bmp
OFF
DIM hist%(Width%-1, Height%-1)
rs = 2 * SQR(Width%^2 + Height%^2) / Height% : REM Radial step
ts = PI / Width% : REM Angular step
h% = Height% / 2
REM Hough transform:
FOR y% = 0 TO Height%-1
FOR x% = 0 TO Width%-1
IF TINT(x%*2, y%*2) = 0 THEN
FOR t% = 0 TO Width%-1
th = t% * ts
r% = (x%*COS(th) + y%*SIN(th)) / rs + h% + 0.5
hist%(t%,r%) += 1
NEXT
ENDIF
NEXT
NEXT y%
REM Find max:
max% = 0
FOR y% = 0 TO Height%-1
FOR x% = 0 TO Width%-1
IF hist%(x%,y%) > max% max% = hist%(x%,y%)
NEXT
NEXT y%
REM Plot:
GCOL 1
FOR y% = 0 TO Height%-1
FOR x% = 0 TO Width%-1
c% = 255 * hist%(x%,y%) / max%
COLOUR 1, c%, c%, c%
LINE x%*2,y%*2,x%*2,y%*2
NEXT
NEXT y%
REPEAT
WAIT 1
UNTIL FALSE</lang>
C
D
This uses the module from the Grayscale image Task. The output image is the same as in the Go solution. <lang d>import std.math, grayscale_image;
Image!Gray houghTransform(in Image!Gray im,
in size_t hx=460, in size_t hy=360)
pure nothrow in {
assert(im !is null); assert(hx > 0 && hy > 0); assert((hy & 1) == 0, "hy argument must be even.");
} body {
auto result = new Image!Gray(hx, hy); result.clear(Gray.white);
immutable double rMax = hypot(im.nx, im.ny); immutable double dr = rMax / (hy / 2.0); immutable double dTh = PI / hx;
foreach (immutable y; 0 .. im.ny) {
foreach (immutable x; 0 .. im.nx) {
if (im[x, y] == Gray.white)
continue;
foreach (immutable iTh; 0 .. hx) {
immutable double th = dTh * iTh;
immutable double r = x * cos(th) + y * sin(th);
immutable iry = hy / 2 - cast(int)floor(r / dr + 0.5);
if (result[iTh, iry] > Gray(0))
result[iTh, iry]--;
}
}
}
return result;
}
void main() {
(new Image!RGB)
.loadPPM6("Pentagon.ppm")
.rgb2grayImage()
.houghTransform()
.savePGM("Pentagon_hough.pgm");
}</lang>
Go
<lang go>package main
import (
"fmt" "image" "image/color" "image/draw" "image/png" "math" "os"
)
func hough(im image.Image, ntx, mry int) draw.Image {
nimx := im.Bounds().Max.X
mimy := im.Bounds().Max.Y
mry = int(mry/2) * 2
him := image.NewGray(image.Rect(0, 0, ntx, mry))
draw.Draw(him, him.Bounds(), image.NewUniform(color.White),
image.ZP, draw.Src)
rmax := math.Hypot(float64(nimx), float64(mimy)) dr := rmax / float64(mry/2) dth := math.Pi / float64(ntx)
for jx := 0; jx < nimx; jx++ {
for iy := 0; iy < mimy; iy++ {
col := color.GrayModel.Convert(im.At(jx, iy)).(color.Gray)
if col.Y == 255 {
continue
}
for jtx := 0; jtx < ntx; jtx++ {
th := dth * float64(jtx)
r := float64(jx)*math.Cos(th) + float64(iy)*math.Sin(th)
iry := mry/2 - int(math.Floor(r/dr+.5))
col = him.At(jtx, iry).(color.Gray)
if col.Y > 0 {
col.Y--
him.SetGray(jtx, iry, col)
}
}
}
}
return him
}
func main() {
f, err := os.Open("Pentagon.png")
if err != nil {
fmt.Println(err)
return
}
pent, err := png.Decode(f)
if err != nil {
fmt.Println(err)
return
}
if err = f.Close(); err != nil {
fmt.Println(err)
}
h := hough(pent, 460, 360)
if f, err = os.Create("hough.png"); err != nil {
fmt.Println(err)
return
}
if err = png.Encode(f, h); err != nil {
fmt.Println(err)
}
if cErr := f.Close(); cErr != nil && err == nil {
fmt.Println(err)
}
}</lang>
J
Solution: <lang j>NB.*houghTransform v Produces a density plot of image y in hough space NB. y is picture as an array with 1 at non-white points, NB. x is resolution (width,height) of resulting image houghTransform=: dyad define
'w h'=. x NB. width and height of target image theta=. o. (%~ 0.5+i.) w NB. theta in radians from 0 to π rho=. (4$.$. |.y) +/ .* 2 1 o./theta NB. rho for each pixel at each theta 'min max'=. (,~-) +/&.:*: $y NB. min/max possible rho rho=. <. 0.5+ h * (rho-min) % max-min NB. Rescale rho from 0 to h and round to int |.([: <:@(#/.~) (i.h)&,)"1&.|: rho NB. consolidate into picture
)</lang>
Example use:
<lang j> require 'viewmat media/platimg'
Img=: readimg jpath '~temp/pentagon.png' viewmat 460 360 houghTransform _1 > Img</lang>
Java
Code: <lang Java>import java.awt.image.*; import java.io.File; import java.io.IOException; import javax.imageio.*;
public class HoughTransform {
public static ArrayData houghTransform(ArrayData inputData, int thetaAxisSize, int rAxisSize, int minContrast)
{
int width = inputData.width;
int height = inputData.height;
int maxRadius = (int)Math.ceil(Math.hypot(width, height));
int halfRAxisSize = rAxisSize >>> 1;
ArrayData outputData = new ArrayData(thetaAxisSize, rAxisSize);
// x output ranges from 0 to pi
// y output ranges from -maxRadius to maxRadius
double[] sinTable = new double[thetaAxisSize];
double[] cosTable = new double[thetaAxisSize];
for (int theta = thetaAxisSize - 1; theta >= 0; theta--)
{
double thetaRadians = theta * Math.PI / thetaAxisSize;
sinTable[theta] = Math.sin(thetaRadians);
cosTable[theta] = Math.cos(thetaRadians);
}
for (int y = height - 1; y >= 0; y--)
{
for (int x = width - 1; x >= 0; x--)
{
if (inputData.contrast(x, y, minContrast))
{
for (int theta = thetaAxisSize - 1; theta >= 0; theta--)
{
double r = cosTable[theta] * x + sinTable[theta] * y;
int rScaled = (int)Math.round(r * halfRAxisSize / maxRadius) + halfRAxisSize;
outputData.accumulate(theta, rScaled, 1);
}
}
}
}
return outputData;
}
public static class ArrayData
{
public final int[] dataArray;
public final int width;
public final int height;
public ArrayData(int width, int height)
{
this(new int[width * height], width, height);
}
public ArrayData(int[] dataArray, int width, int height)
{
this.dataArray = dataArray;
this.width = width;
this.height = height;
}
public int get(int x, int y)
{ return dataArray[y * width + x]; }
public void set(int x, int y, int value)
{ dataArray[y * width + x] = value; }
public void accumulate(int x, int y, int delta)
{ set(x, y, get(x, y) + delta); }
public boolean contrast(int x, int y, int minContrast)
{
int centerValue = get(x, y);
for (int i = 8; i >= 0; i--)
{
if (i == 4)
continue;
int newx = x + (i % 3) - 1;
int newy = y + (i / 3) - 1;
if ((newx < 0) || (newx >= width) || (newy < 0) || (newy >= height))
continue;
if (Math.abs(get(newx, newy) - centerValue) >= minContrast)
return true;
}
return false;
}
public int getMax()
{
int max = dataArray[0];
for (int i = width * height - 1; i > 0; i--)
if (dataArray[i] > max)
max = dataArray[i];
return max;
}
}
public static ArrayData getArrayDataFromImage(String filename) throws IOException
{
BufferedImage inputImage = ImageIO.read(new File(filename));
int width = inputImage.getWidth();
int height = inputImage.getHeight();
int[] rgbData = inputImage.getRGB(0, 0, width, height, null, 0, width);
ArrayData arrayData = new ArrayData(width, height);
// Flip y axis when reading image
for (int y = 0; y < height; y++)
{
for (int x = 0; x < width; x++)
{
int rgbValue = rgbData[y * width + x];
rgbValue = (int)(((rgbValue & 0xFF0000) >>> 16) * 0.30 + ((rgbValue & 0xFF00) >>> 8) * 0.59 + (rgbValue & 0xFF) * 0.11);
arrayData.set(x, height - 1 - y, rgbValue);
}
}
return arrayData;
}
public static void writeOutputImage(String filename, ArrayData arrayData) throws IOException
{
int max = arrayData.getMax();
BufferedImage outputImage = new BufferedImage(arrayData.width, arrayData.height, BufferedImage.TYPE_INT_ARGB);
for (int y = 0; y < arrayData.height; y++)
{
for (int x = 0; x < arrayData.width; x++)
{
int n = Math.min((int)Math.round(arrayData.get(x, y) * 255.0 / max), 255);
outputImage.setRGB(x, arrayData.height - 1 - y, (n << 16) | (n << 8) | 0x90 | -0x01000000);
}
}
ImageIO.write(outputImage, "PNG", new File(filename));
return;
}
public static void main(String[] args) throws IOException
{
ArrayData inputData = getArrayDataFromImage(args[0]);
int minContrast = (args.length >= 4) ? 64 : Integer.parseInt(args[4]);
ArrayData outputData = houghTransform(inputData, Integer.parseInt(args[2]), Integer.parseInt(args[3]), minContrast);
writeOutputImage(args[1], outputData);
return;
}
}</lang>
Example use:
java HoughTransform pentagon.png JavaHoughTransform.png 640 480 100
Mathematica
<lang Mathematica> Radon[image, Method -> "Hough"] </lang>
MATLAB
Python
This is the classical Hough transform as described in wikipedia. The code does not compute averages; it merely makes a point on the transformed image darker if a lot of points on the original image lie on the corresponding line. The output is almost identical to that of the Tcl code. The code works only with gray-scale images, but it is easy to extend to RGB. <lang python> from math import hypot, pi, cos, sin import Image
def hough(im, ntx=460, mry=360):
"Calculate Hough transform."
pim = im.load()
nimx, mimy = im.size
mry = int(mry/2)*2 #Make sure that this is even
him = Image.new("L", (ntx, mry), 255)
phim = him.load()
rmax = hypot(nimx, mimy) dr = rmax / (mry/2) dth = pi / ntx
for jx in xrange(nimx):
for iy in xrange(mimy):
col = pim[jx, iy]
if col == 255: continue
for jtx in xrange(ntx):
th = dth * jtx
r = jx*cos(th) + iy*sin(th)
iry = mry/2 + int(r/dr+0.5)
phim[jtx, iry] -= 1
return him
def test():
"Test Hough transform with pentagon."
im = Image.open("pentagon.png").convert("L")
him = hough(im)
him.save("ho5.bmp")
if __name__ == "__main__": test()
</lang>
Racket
Ruby
<lang Ruby> require 'mathn' require 'rubygems' require 'gd2' include GD2
def hough_transform(img)
mx, my = img.w*0.5, img.h*0.5
max_d = Math.sqrt(mx**2 + my**2)
min_d = max_d * -1
hough = Hash.new(0)
(0..img.w).each do |x|
puts "#{x} of #{img.w}"
(0..img.h).each do |y|
if img.pixel2color(img.get_pixel(x,y)).g > 32
(0...180).each do |a|
rad = a * (Math::PI / 180.0)
d = (x-mx) * Math.cos(rad) + (y-my) * Math.sin(rad)
hough["#{a.to_i}_#{d.to_i}"] = hough["#{a.to_i}_#{d.to_i}"] + 1
end
end
end
end
heat = GD2::Image.import 'heatmap.png'
out = GD2::Image::TrueColor.new(180,max_d*2)
max = hough.values.max
p max
hough.each_pair do |k,v|
a,d = k.split('_').map(&:to_i)
c = (v / max) * 255
c = heat.get_pixel(c,0)
out.set_pixel(a, max_d + d, c)
end
out
end </lang>