Function composition

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Revision as of 15:07, 21 November 2009 by 91.168.184.128 (talk) (exchange Mathematica and ObjC (M comes before O))
Task
Function composition
You are encouraged to solve this task according to the task description, using any language you may know.

Create a function, compose, whose two arguments f and g, are both functions with one argument. The result of compose is to be a function of one argument, (lets call the argument x), which works like applying function f to the result of applying function g to x.

I.e:

 compose(f, g)(x) == f( g(x) )

Reference: Function composition

Hint: Implementing compose correctly requires creating a closure. If your language does not support closures directly, you will need to implement it yourself.

Ada

The interface of a generic functions package. The package can be instantiated with any type that has value semantics. Functions are composed using the operation '*'. The same operation applied to an argument evaluates it there: f * x. Functions can be composed with pointers to Ada functions. (In Ada functions are not first-class): <lang ada>generic

  type Argument is private;      

package Functions is

  type Primitive_Operation is not null
     access function (Value : Argument) return Argument;
  type Func (<>) is private;
  function "*" (Left : Func; Right : Argument) return Argument;
  function "*" (Left : Func; Right : Primitive_Operation) return Func;
  function "*" (Left, Right : Primitive_Operation) return Func;
  function "*" (Left, Right : Func) return Func;

private

  type Func is array (Positive range <>) of Primitive_Operation;

end Functions;</lang> Here is an implementation; <lang ada>package body Functions is

  function "*" (Left : Func; Right : Argument) return Argument is
  Result : Argument := Right;
  begin
     for I in reverse Left'Range loop
        Result := Left (I) (Result);
     end loop;
     return Result;
  end "*";
  function "*" (Left, Right : Func) return Func is
  begin
     return Left & Right;
  end "*";
  function "*" (Left : Func; Right : Primitive_Operation) return Func is
  begin
     return Left & (1 => Right);
  end "*";
  
  function "*" (Left, Right : Primitive_Operation) return Func is
  begin
     return (Left, Right);
  end "*";

end Functions;</lang> The following is an example of use: <lang ada>with Ada.Numerics.Elementary_Functions; use Ada.Numerics.Elementary_Functions; with Ada.Text_IO; use Ada.Text_IO; with Functions;

procedure Test_Compose is

  package Float_Functions is new Functions (Float);
  use Float_Functions;
  Sin_Arcsin : Func := Sin'Access * Arcsin'Access;

begin

  Put_Line (Float'Image (Sin_Arcsin * 0.5));

end Test_Compose;</lang> Sample output:

 5.00000E-01

ALGOL 68

Translation of: Python
Works with: ELLA ALGOL 68 version Any (with appropriate job cards) - tested with release 1.8.8d.fc9.i386

Note: Returning PROC (REAL x)REAL: f1(f2(x)) from a function apparently violates standard ALGOL 68's scoping rules. ALGOL 68G warns about this during parsing, and then rejects during runtime. <lang algol68>MODE F = PROC(REAL)REAL; # ALGOL 68 is strong typed #

  1. As a procedure for real to real functions #

PROC compose = (F f, g)F: (REAL x)REAL: f(g(x));

OP (F,F)F O = compose; # or an OPerator that can be overloaded #

  1. Example use: #

F sin arc sin = compose(sin, arc sin); print((sin arc sin(0.5), (sin O arc sin)(0.5), new line))</lang> Output:

+.500000000000000e +0 +.500000000000000e +0

ALGOL 68 is a stack based language, and the following apparently does not violate it's scoping rules.

Works with: ALGOL 68 version Standard - Jan 1975 Boston SC allowed Partial Parametrization.
Works with: ALGOL 68G version Any - tested with release mk15-0.8b.fc9.i386

<lang algol68>MODE F = PROC(REAL)REAL; # ALGOL 68 is strong typed #

  1. As a procedure for real to real functions #

PROC compose = (F f, g)F: ((F f2, g2, REAL x)REAL: f2(g2(x)))(f, g, ); # Curry #

PRIO O = 7; OP (F,F)F O = compose; # or an OPerator that can be overloaded #

  1. Example use: #

F sin arc sin = compose(sin, arc sin); print((sin arc sin(0.5), (sin O arc sin)(0.5), new line))</lang>

AutoHotkey

contributed by Laszlo on the ahk forum <lang AutoHotkey>MsgBox % compose("sin","cos",1.5)

compose(f,g,x) { ; function composition

  Return %f%(%g%(x))

}</lang>

C

Only works for functions taking a double and returning a double: <lang c>#include <stdlib.h>

/* generic interface for functors from double to double */ typedef struct double_to_double {

 double (*fn)(struct double_to_double *, double);

} double_to_double;

  1. define CALL(f, x) f->fn(f, x)


/* functor returned by compose */ typedef struct compose_functor {

 double (*fn)(struct compose_functor *, double);
 double_to_double *f;
 double_to_double *g;

} compose_functor; /* function to be used in "fn" in preceding functor */ double compose_call(compose_functor *this, double x) {

 return CALL(this->f, CALL(this->g, x));

} /* returns functor that is the composition of functors

  f & g. caller is responsible for deallocating memory */

double_to_double *compose(double_to_double *f,

                         double_to_double *g) {
 compose_functor *result = malloc(sizeof(compose_functor));
 result->fn = &compose_call;
 result->f = f;
 result->g = g;
 return (double_to_double *)result;

}


  1. include <math.h>

/* we can make functors for sin and asin by using

  the following as "fn" in a functor */

double sin_call(double_to_double *this, double x) {

 return sin(x);

} double asin_call(double_to_double *this, double x) {

 return asin(x);

}


  1. include <stdio.h>

int main() {

 double_to_double *my_sin = malloc(sizeof(double_to_double));
 my_sin->fn = &sin_call;
 double_to_double *my_asin = malloc(sizeof(double_to_double));
 my_asin->fn = &asin_call;
 double_to_double *sin_asin = compose(my_sin, my_asin);
 printf("%f\n", CALL(sin_asin, 0.5)); /* prints "0.500000" */
 free(sin_asin);
 free(my_sin);
 free(my_asin);
 return 0;

}</lang>

C++

Note: this is already implemented as __gnu_cxx::compose1() <lang cpp>#include <functional>

  1. include <cmath>
  2. include <iostream>

// functor class to be returned by compose function template <class Fun1, class Fun2> class compose_functor :

 public std::unary_function<typename Fun2::argument_type,
                            typename Fun1::result_type>

{ protected:

 Fun1 f;
 Fun2 g;

public:

 compose_functor(const Fun1& _f, const Fun2& _g)
   : f(_f), g(_g) { }
 typename Fun1::result_type
 operator()(const typename Fun2::argument_type& x) const
 { return f(g(x)); }

};

// we wrap it in a function so the compiler infers the template arguments // whereas if we used the class directly we would have to specify them explicitly template <class Fun1, class Fun2> inline compose_functor<Fun1, Fun2> compose(const Fun1& f, const Fun2& g) { return compose_functor<Fun1,Fun2>(f, g); }

int main() {

 std::cout << compose(std::ptr_fun(::sin), std::ptr_fun(::asin))(0.5) << std::endl;
 return 0;

}</lang>

C#

<lang csharp>using System; class Program {

   static void Main(string[] args)
   {
       Func<int, int> outfunc = Composer<int, int, int>.Compose(functA, functB);
       Console.WriteLine(outfunc(5)); //Prints 100
   }
   static int functA(int i) { return i * 10; }
   static int functB(int i) { return i + 5; }
   class Composer<A, B, C>
   {
       public static Func<C, A> Compose(Func<B, A> a, Func<C, B> b)
       {
           return delegate(C i) { return a(b(i)); };
       }
   }

}</lang>

Common Lisp

<lang lisp>(defun compose (f g) (lambda (x) (funcall f (funcall g x))))</lang> Example use: <lang lisp>>(defun compose (f g) (lambda (x) (funcall f (funcall g x)))) COMPOSE >(let ((sin-asin (compose #'sin #'asin))))

  (funcall sin-asin 0.5))

0.5</lang>

D

D 2.0 version of compose function (template). <lang D>import std.stdio; import std.math;

T delegate(S) compose(T, U, S)(T delegate(U) f, U delegate(S) g) {

   return (S s) { return f(g(s)); };

}</lang>

Compose working both in D 1.0 and 2.0: <lang D>T delegate(S) compose(T, U, S)(T delegate(U) f, U delegate(S) g) {

   struct Wrapper {
       typeof(f) fcp;
       typeof(g) gcp;
       T foobar(S s) { return fcp(gcp(s)); }
   }
   Wrapper* hold = new Wrapper;
   hold.fcp = f;
   hold.gcp = g;
   return &hold.foobar;

}</lang>

E

<lang e>def compose(f, g) {

 return fn x { return f(g(x)) }

}</lang>

Erlang

<lang erlang>-module(fn). -export([compose/1, multicompose/2]).

compose(F,G) -> fun(X) -> F(G(X)) end.

multicompose(Fs) ->

   lists:foldl(fun compose/2, fun(X) -> X end, Fs).</lang>

Using them: <lang erlang>1> (fn:compose(fun math:sin/1, fun math:asin/1))(0.5). 0.5 2> Sin_asin_plus1 = fn:multicompose([fun math:sin/1, fun math:asin/1, fun(X) -> X + 1 end]).

  1. Fun<tests.0.59446746>

82> Sin_asin_plus1(0.5). 1.5</lang>

F#

The composition operator in F# is >> for forward composition and << for reverse. <lang fsharp>let compose f g = f << g ;;</lang> Usage: <lang fsharp>> let sin_asin = compose sin asin ;; val sin_asin : (float -> float) > sin_asin 0.5 ;; val it : float = 0.5</lang> To see that this can be a closure we can use arithmetic functions: <lang fsharp>> let add_then_halve = compose (fun n -> n / 2) (fun n -> n + 10) ;; val add_then_halve : (int -> int) > add_then_halve 6 ;; val it : int = 8</lang>

Forth

<lang forth>: compose ( xt1 xt2 -- xt3 )

 >r >r :noname
    r> compile,
    r> compile,
    postpone ;

' 2* ' 1+ compose ( xt ) 3 swap execute . \ 7</lang>

Groovy

Solution: <lang groovy>def compose = { f, g -> { x -> f(g(x)) } }</lang>

Test program: <lang groovy>def sq = { it * it } def plus1 = { it + 1 } def minus1 = { it - 1 }

def plus1sqd = compose(sq,plus1) def sqminus1 = compose(minus1,sq) def identity = compose(plus1,minus1) def plus1sqdminus1 = compose(minus1,compose(sq,plus1)) def identity2 = compose(Math.&sin,Math.&asin)

println "(x+1)**2 = (0+1)**2 = " + plus1sqd(0) println "x**2-1 = 20**2-1 = " + sqminus1(20) println "(x+1)-1 = (12+1)-1 = " + identity(12) println "(x+1)**2-1 = (3+1)**2-1 = " + plus1sqdminus1(3) println "sin(asin(x)) = sin(asin(1)) = " + identity2(1)</lang>

Output:

(x+1)**2 = (0+1)**2 = 1
x**2-1 = 20**2-1 = 399
(x+1)-1 = (12+1)-1 = 12
(x+1)**2-1 = (3+1)**2-1 = 15
sin(asin(x)) = sin(asin(1)) = 1.0

Haskell

This is already defined as the . (dot) operator in Haskell. <lang haskell>compose f g x = f (g x)</lang> Example use: <lang haskell>Prelude> let compose f g x = f (g x) Prelude> let sin_asin = compose sin asin Prelude> sin_asin 0.5 0.5</lang>

J

Solution: <lang j>compose =: @</lang>

Example: <lang j>f compose g</lang>

Of course, given that @ is only one character long and is a built-in primitive, there is no need for the cover function compose. And @ is not the only composition primitive; composition is a very important concept in J. For more details, see the talk page.

Java

<lang java>public class Compose {

   // Java doesn't have function type so we define an interface
   // of function objects instead
   public interface Fun<A,B> {
       B call(A x);
   }
   public static <A,B,C> Fun<A,C> compose(final Fun<B,C> f, final Fun<A,B> g) {
       return new Fun<A,C>() {
           public C call(A x) {
               return f.call(g.call(x));
           }
       };
   }
   public static void main(String[] args) {
       Fun<Double,Double> sin = new Fun<Double,Double>() {
           public Double call(Double x) {
               return Math.sin(x);
           }
       };
       Fun<Double,Double> asin = new Fun<Double,Double>() {
           public Double call(Double x) {
               return Math.asin(x);
           }
       };
       Fun<Double,Double> sin_asin = compose(sin, asin);
       System.out.println(sin_asin.call(0.5)); // prints "0.5"
   }

}</lang>

JavaScript

<lang javascript>function compose(f, g) {

 return function(x) { return f(g(x)) }

}

var id = compose(Math.sin, Math.asin) print id(0.5) // 0.5</lang>

Joy

Composition is the default operation in Joy. The composition of two functions is the concatenation of those functions, in the order in which they are to be applied. <lang joy>g f</lang>

Mathematica

Built-in function that takes any amount of function-arguments: <lang Mathematica>Composition[f, g][x] Composition[f, g, h, i][x]</lang> gives back: <lang Mathematica>f[g[x]] f[g[h[i[x]]]]</lang> Custom function: <lang Mathematica>compose[f_, g_][x_] := f[g[x]] compose[Sin, Cos][r]</lang> gives back: <lang Mathematica>Sin[Cos[r]]</lang> Composition can be done in more than 1 way: <lang Mathematica>Composition[f,g,h][x] f@g@h@x x//h//g//f</lang> all give back: <lang Mathematica>f[g[h[x]]]</lang> The built-in function has a couple of automatic simplifications: <lang Mathematica>Composition[f, Identity, g] Composition[f, InverseFunction[f], h][x]</lang> becomes: <lang Mathematica>f[g[x]] h[x]</lang>

Objective-C

The FunctionComposer is able to compose any object that conforms to the protocol FunctionCapsule (a selector/method accepting any object as argument and returning another object, i.e. computing a "function" of an object). A FunctionCaps class thought to encapsulate a function returning a double and with a double as argument is shown; anyway, as said, any object conforming to FunctionCapsule protocol can be composed with another object conforming to the same protocol. Argument passed and returned can be of any object type.

<lang objc>#include <Foundation/Foundation.h>

// the protocol of objects that can behave "like function" @protocol FunctionCapsule -(id)computeWith: (id)x; @end


// a commodity for "encapsulating" double f(double) typedef double (*func_t)(double); @interface FunctionCaps : NSObject <FunctionCapsule> {

 func_t function;

} +(id)capsuleFor: (func_t)f; -(id)initWithFunc: (func_t)f; @end

@implementation FunctionCaps -(id)initWithFunc: (func_t)f {

 self = [self init];
 function = f;
 return self;

} +(id)capsuleFor: (func_t)f {

 return [[[self alloc] initWithFunc: f] autorelease];

} -(id)computeWith: (id)x {

 return [NSNumber numberWithDouble: function([x doubleValue])];

} @end


// the "functions" composer @interface FunctionComposer : NSObject <FunctionCapsule> {

 id funcA;
 id funcB;

} +(id) createCompositeFunctionWith: (id)A and: (id)B; -(id) initComposing: (id)A with: (id)B; -(id) init; -(id) dealloc; @end

@implementation FunctionComposer +(id) createCompositeFunctionWith: (id)A and: (id)B {

 return [[[self alloc] initComposing: A with: B] autorelease];

}

-(id) init {

 NSLog(@"FunctionComposer: init with initComposing!");
 funcA = nil; funcB = nil;
 return self;

}

-(id) initComposing: (id)A with: (id)B {

 self = [super init];
 if ( ([A conformsToProtocol: @protocol(FunctionCapsule)] == YES) &&
      ([B conformsToProtocol: @protocol(FunctionCapsule)] == YES) ) {
   [A retain]; [B retain];
   funcA = A; funcB = B;
   return self;
 }
 NSLog(@"FunctionComposer: cannot compose functions not responding to protocol FunctionCapsule!");
 return nil;

}

-(id)computeWith: (id)x {

 return [funcA computeWith: [funcB computeWith: x]];

} @end

-(void) dealloc {

 [funcA release];
 [funcB release];
 [super dealloc];

}


// functions outside... double my_f(double x) {

 return x+1.0;

}

double my_g(double x) {

 return x*x;

}


int main() {

 NSAutoreleasePool *pool = [[NSAutoreleasePool alloc] init];
 id funcf = [FunctionCaps capsuleFor: my_f];
 id funcg = [FunctionCaps capsuleFor: my_g];
 id composed = [FunctionComposer 

createCompositeFunctionWith: funcf and: funcg];

 printf("g(2.0) = %lf\n", [[funcg computeWith: [NSNumber numberWithDouble: 2.0]] doubleValue]);
 printf("f(2.0) = %lf\n", [[funcf computeWith: [NSNumber numberWithDouble: 2.0]] doubleValue]);
 printf("f(g(2.0)) = %lf\n", [[composed computeWith: [NSNumber numberWithDouble: 2.0]] doubleValue]);
 [pool release];
 return 0;

}</lang>

OCaml

<lang ocaml>let compose f g x = f (g x)</lang> Example use: <lang ocaml># let compose f g x = f (g x);; val compose : ('a -> 'b) -> ('c -> 'a) -> 'c -> 'b = <fun>

  1. let sin_asin = compose sin asin;;

val sin_asin : float -> float = <fun>

  1. sin_asin 0.5;;

- : float = 0.5</lang>

Octave

<lang octave>function r = compose(f, g)

 r = @(x) f(g(x));

endfunction

r = compose(@exp, @sin); r(pi/3)</lang>

Perl

<lang perl>sub compose

  {my ($f, $g) = @_;
   return sub {$f->($g->(@_))};}

use Math::Trig; print compose(sub {sin $_[0]}, \&asin)->(0.5), "\n";</lang>

Perl 6

Works with: Rakudo version #23 "Lisbon"

<lang perl6>sub infix:<∘> (&f, &g --> Block) {

   sub (*@args) { f g |@args };

}</lang>

Example of use:

<lang perl6>sub triple($n) { 3 * $n } my $f = &triple ∘ { $^x + 2 }; say $f(5); # Prints "21".</lang>

Python

<lang python>compose = lambda f, g: lambda x: f( g(x) )</lang> Example use: <lang python>>>> compose = lambda f, g: lambda x: f( g(x) ) >>> from math import sin, asin >>> sin_asin = compose(sin, asin) >>> sin_asin(0.5) 0.5 >>></lang>

R

<lang R>compose <- function(f,g) function(x) { f(g(x)) } r <- compose(sin, cos) print(r(.5))</lang>

Ruby

This compose method gets passed two Method objects <lang ruby>def compose(f,g)

 lambda {|x| f.call(g.call(x))}

end s = compose(Math.method('sin'), Math.method('cos')) s.call(0.5) # => 0.769196354841008

  1. verify

Math.sin(Math.cos(0.5)) # => 0.769196354841008</lang>

With this method, you pass two symbols <lang ruby>include Math def compose(f,g)

 lambda {|x| send(f, send(g, x))}

end s = compose(:sin, :cos) s.call(0.5) # => 0.769196354841008</lang>

Scala

<lang scala>def compose[A](f: A => A, g: A => A) = { x: A => f(g(x)) }

def add1(x: Int) = x+1 val add2 = compose(add1, add1)</lang>

We can achieve a more natural style by creating a container class for composable functions, which provides the compose method 'o':

<lang scala>class Composable[A](f: A => A) {

 def o (g: A => A) = compose(f, g)

}

implicit def toComposable[A](f: A => A) = new Composable(f)

val add3 = (add1 _) o add2</lang>

> (add2 o add3)(37)
res0: Int = 42

Scheme

<lang scheme>(define (compose f g) (lambda (x) (f (g x))))</lang> Example use: <lang scheme>> (define (compose f g) (lambda (x) (f (g x)))) > (define sin_asin (compose sin asin)) > (sin_asin 0.5) 0.5</lang>

Slate

Function (method) composition is standard: <lang slate>[| :x | x + 1] ** [| :x | x squared] applyTo: {3}</lang>

Smalltalk

<lang smalltalk>| composer fg | composer := [ :f :g | [ :x | f value: (g value: x) ] ]. fg := composer value: [ :x | x + 1 ]

              value: [ :x | x * x ].

(fg value:3) displayNl.</lang>

Standard ML

This is already defined as the o operator in Standard ML. <lang sml>fun compose (f, g) x = f (g x)</lang> Example use: <lang sml>- fun compose (f, g) x = f (g x); val compose = fn : ('a -> 'b) * ('c -> 'a) -> 'c -> 'b - val sin_asin = compose (Math.sin, Math.asin); val sin_asin = fn : real -> real - sin_asin 0.5; val it = 0.5 : real</lang>

Tcl

Works with: Tcl version 8.5


This creates a compose procedure that returns an anonymous function term that should be expanded as part of application to its argument. <lang tcl>package require Tcl 8.5 namespace path {::tcl::mathfunc}

proc compose {f g} {

   list apply [list {f g x} {{*}$f [{*}$g $x]}] $f $g]

}

set sin_asin [compose sin asin] {*}$sin_asin 0.5 ;# ==> 0.5 {*}[compose abs int] -3.14 ;# ==> 3</lang>

Clojure

Composition is built in to Clojure. Simply call the comp function

<lang lisp>user=>(comp rest rest);returns a closure that takes the rest of rest.</lang>

Ursala

Functional composition is a built in operation expressible as f+g for functions f and g, hence hardly worth defining. However, it could be defined without using the operator like this. <lang Ursala>compose("f","g") "x" = "f" "g" "x"</lang> test program: <lang Ursala>#import nat

  1. cast %n

test = compose(successor,double) 3</lang> output:

7