Ethiopian multiplication: Difference between revisions

From Rosetta Code
Content added Content deleted
(Replaced all instances of EXIT PROGRAM to GOBACK)
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=={{header|COBOL}}==
=={{header|COBOL}}==
{{trans|Common Lisp}}
{{trans|Common Lisp}}
{{works with|COBOL|2002}}
{{works with|OpenCOBOL|1.1}}
{{works with|OpenCOBOL|1.1}}
In COBOL, ''double'' is a reserved word, so the doubling functions is named ''twice'', instead.
In COBOL, ''double'' is a reserved word, so the doubling functions is named ''twice'', instead.
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END-CALL
END-CALL
END-PERFORM
END-PERFORM
EXIT PROGRAM.
GOBACK.
END PROGRAM ethiopian-multiply.
END PROGRAM ethiopian-multiply.


Line 668: Line 669:
PROCEDURE DIVISION USING n, m.
PROCEDURE DIVISION USING n, m.
DIVIDE n BY 2 GIVING m END-DIVIDE
DIVIDE n BY 2 GIVING m END-DIVIDE
EXIT PROGRAM.
GOBACK.
END PROGRAM halve.
END PROGRAM halve.


Line 680: Line 681:
PROCEDURE DIVISION USING n, m.
PROCEDURE DIVISION USING n, m.
MULTIPLY n by 2 GIVING m END-MULTIPLY
MULTIPLY n by 2 GIVING m END-MULTIPLY
EXIT PROGRAM.
GOBACK.
END PROGRAM twice.
END PROGRAM twice.


Line 696: Line 697:
DIVIDE n BY 2 GIVING q REMAINDER m END-DIVIDE
DIVIDE n BY 2 GIVING q REMAINDER m END-DIVIDE
SUBTRACT m FROM 1 GIVING m END-SUBTRACT
SUBTRACT m FROM 1 GIVING m END-SUBTRACT
EXIT PROGRAM.
GOBACK.
END PROGRAM evenp.</lang>
END PROGRAM evenp.</lang>


Revision as of 04:25, 7 June 2012

Task
Ethiopian multiplication
You are encouraged to solve this task according to the task description, using any language you may know.

A method of multiplying integers using only addition, doubling, and halving.

Method:

  1. Take two numbers to be multiplied and write them down at the top of two columns.
  2. In the left-hand column repeatedly halve the last number, discarding any remainders, and write the result below the last in the same column, until you write a value of 1.
  3. In the right-hand column repeatedly double the last number and write the result below. stop when you add a result in the same row as where the left hand column shows 1.
  4. Examine the table produced and discard any row where the value in the left column is even.
  5. Sum the values in the right-hand column that remain to produce the result of multiplying the original two numbers together

For example: 17 × 34 

       17    34

Halving the first column: 

       17    34
        8
        4
        2
        1

Doubling the second column: 

       17    34
        8    68
        4   136 
        2   272
        1   544

Strike-out rows whose first cell is even: 

       17    34
        8    68 
        4   136 
        2   272 
        1   544

Sum the remaining numbers in the right-hand column: 

       17    34
        8    -- 
        4   --- 
        2   --- 
        1   544
           ====
            578

So 17 multiplied by 34, by the Ethiopian method is 578.

The task is to define three named functions/methods/procedures/subroutines:

  1. one to halve an integer,
  2. one to double an integer, and
  3. one to state if an integer is even.

Use these functions to create a function that does Ethiopian multiplication.

References

ACL2

<lang Lisp>(include-book "arithmetic-3/top" :dir :system)

(defun halve (x) 

  (floor x 2))

(defun double (x) 

  (* x 2))

(defun is-even (x) 

  (evenp x))

(defun multiply (x y) 

  (if (zp (1- x))
      y
      (+ (if (is-even x)
             0
             y)
         (multiply (halve x) (double y)))))</lang>

ActionScript

Works with: ActionScript version 2.0

<lang ActionScript>


function Divide(a:Number):Number { return ((a-(a%2))/2); } function Multiply(a:Number):Number { return (a *= 2); } function isEven(a:Number):Boolean { if (a%2 == 0) { return (true); } else { return (false); } } function Ethiopian(left:Number, right:Number) { var r:Number = 0; trace(left+" "+right); while (left != 1) { var State:String = "Keep"; if (isEven(Divide(left))) { State = "Strike"; } trace(Divide(left)+" "+Multiply(right)+" "+State); left = Divide(left); right = Multiply(right); if (State == "Keep") { r += right; } } trace("="+" "+r); } } </lang>

Output: ex. Ethiopian(17,34); <lang ActionScript> 17 34 8 68 Strike 4 136 Strike 2 272 Strike 1 544 Keep = 578


</lang>

Ada

<lang Ada>package Ethiopian is 

  function Multiply(Left, Right : Integer) return Integer;

end Ethiopian;</lang> <lang Ada>package body Ethiopian is 

  function Is_Even(Item : Integer) return Boolean is
  begin
     return Item mod 2 = 0;
  end Is_Even;
  
  function Double(Item : Integer) return Integer is
  begin
     return Item * 2;
  end Double;
  
  function Half(Item : Integer) return Integer is
  begin
     return Item / 2;
  end Half;
     
  function Multiply(Left, Right : Integer) return Integer is
     Temp : Integer := 0;
     Plier : Integer := Left;
     Plicand : Integer := Right;
  begin
     while Plier >= 1 loop
        if not Is_Even(Plier) then
           Temp := Temp + Plicand;
        end if;
        Plier := Half(Plier);
        Plicand := Double(Plicand);
     end loop;
     return Temp;
  end Multiply;

end Ethiopian;</lang>

<lang Ada>with Ethiopian; use Ethiopian; with Ada.Text_Io; use Ada.Text_Io;

procedure Ethiopian_Test is 

  First  : Integer := 17;
  Second : Integer := 34;

begin 

  Put_Line(Integer'Image(First) & " times " &
     Integer'Image(Second) & " = " &
     Integer'Image(Multiply(First, Second)));

end Ethiopian_Test;</lang>

ALGOL 68

Translation of: C
Works with: ALGOL 68 version Standard - no extensions to language used
Works with: ALGOL 68G version Any - tested with release 1.18.0-9h.tiny

<lang algol68>PROC halve = (REF INT x)VOID: x := ABS(BIN x SHR 1); PROC doublit = (REF INT x)VOID: x := ABS(BIN x SHL 1); PROC iseven = (#CONST# INT x)BOOL: NOT ODD x;

PROC ethiopian = (INT in plier, 

             INT in plicand, #CONST# BOOL tutor)INT:

( 

 INT plier := in plier, plicand := in plicand;
 INT result:=0;

 IF tutor THEN
   printf(($"ethiopian multiplication of "g(0)," by "g(0)l$, plier, plicand)) FI;

 WHILE plier >= 1 DO
   IF iseven(plier) THEN
     IF tutor THEN printf(($" "4d,"  "6d" struck"l$, plier, plicand)) FI
   ELSE
     IF tutor THEN printf(($" "4d,"  "6d" kept"l$, plier, plicand)) FI;
     result +:= plicand
   FI;
   halve(plier); doublit(plicand)
 OD;
 result

);

main: ( 

 printf(($g(0)l$, ethiopian(17, 34, TRUE)))

)</lang> Output: 

ethiopian multiplication of 17 by 34
 0017  000034 kept
 0008  000068 struck
 0004  000136 struck
 0002  000272 struck
 0001  000544 kept
578

AutoHotkey

<lang AutoHotkey>MsgBox % Ethiopian(17, 34) "`n" Ethiopian2(17, 34)

func definitions

half( x ) { return x >> 1 }

double( x ) { return x << 1 }

isEven( x ) { return x & 1 == 0 }

Ethiopian( a, b ) { r := 0 While (a >= 1) { if !isEven(a) r += b a := half(a) b := double(b) } return r }

or a recursive function

Ethiopian2( a, b, r = 0 ) { ;omit r param on initial call return a==1 ? r+b : Ethiopian2( half(a), double(b), !isEven(a) ? r+b : r ) }</lang>

AutoIt

<lang AutoIt> Func Halve($x) Return Int($x/2) EndFunc

Func Double($x) Return ($x*2) EndFunc

Func IsEven($x) Return (Mod($x,2) == 0) EndFunc

this version also supports negative parameters

Func Ethiopian($nPlier, $nPlicand, $bTutor = True) Local $nResult = 0 If ($nPlier < 0) Then $nPlier =- $nPlier $nPlicand =- $nPlicand ElseIf ($nPlicand > 0) And ($nPlier > $nPlicand) Then $nPlier = $nPlicand $nPlicand = $nPlier EndIf If $bTutor Then _ 

   ConsoleWrite(StringFormat("Ethiopian multiplication of %d by %d...\n", $nPlier, $nPlicand))

While ($nPlier >= 1) If Not IsEven($nPlier) Then $nResult += $nPlicand If $bTutor Then ConsoleWrite(StringFormat("%d\t%d\tKeep\n", $nPlier, $nPlicand)) Else If $bTutor Then ConsoleWrite(StringFormat("%d\t%d\tStrike\n", $nPlier, $nPlicand)) EndIf $nPlier = Halve($nPlier) $nPlicand = Double($nPlicand) WEnd If $bTutor Then ConsoleWrite(StringFormat("Answer = %d\n", $nResult)) Return $nResult EndFunc

MsgBox(0, "Ethiopian multiplication of 17 by 34", Ethiopian(17, 34) ) </lang>

AWK

Implemented without the tutor. <lang awk>function halve(x) { 

 return int(x/2)

}

function double(x) { 

 return x*2

}

function iseven(x) { 

 return x%2 == 0

}

function ethiopian(plier, plicand) { 

 r = 0
 while(plier >= 1) {
   if ( !iseven(plier) ) {
     r += plicand
   }
   plier = halve(plier)
   plicand = double(plicand)
 }
 return r

}

BEGIN { 

 print ethiopian(17, 34)

}</lang>

BASIC

Works with: QBasic

While building the table, it's easier to simply not print unused values, rather than have to go back and strike them out afterward. (Both that and the actual adding happen in the "IF NOT (isEven(x))" block.)

<lang qbasic>DECLARE FUNCTION half% (a AS INTEGER) DECLARE FUNCTION doub% (a AS INTEGER) DECLARE FUNCTION isEven% (a AS INTEGER)

DIM x AS INTEGER, y AS INTEGER, outP AS INTEGER

x = 17 y = 34

DO 

   PRINT x,
   IF NOT (isEven(x)) THEN
       outP = outP + y
       PRINT y
   ELSE
       PRINT
   END IF
   IF x < 2 THEN EXIT DO
   x = half(x)
   y = doub(y)

LOOP

PRINT " =", outP

FUNCTION doub% (a AS INTEGER) 

   doub% = a * 2

END FUNCTION

FUNCTION half% (a AS INTEGER) 

   half% = a \ 2

END FUNCTION

FUNCTION isEven% (a AS INTEGER) 

   isEven% = (a MOD 2) - 1

END FUNCTION</lang>

Output: 

17            34
8
4
2
1             544
=             578

BBC BASIC

<lang bbcbasic> x% = 17 

     y% = 34
     
     REPEAT
       IF NOT FNeven(x%) THEN
         p% += y%
         PRINT x%, y%
       ELSE
         PRINT x%, "       ---"
       ENDIF
       x% = FNhalve(x%)
       y% = FNdouble(y%)
     UNTIL x% = 0
     PRINT " " , "       ==="
     PRINT " " , p%
     END
     
     DEF FNdouble(A%) = A% * 2
     
     DEF FNhalve(A%) = A% DIV 2
     
     DEF FNeven(A%) = ((A% AND 1) = 0)</lang>

Output: 

        17        34
         8       ---
         4       ---
         2       ---
         1       544
                 ===
                 578

C

<lang c>#include <stdio.h>

  1. include <stdbool.h>

void halve(int *x) { *x >>= 1; } void doublit(int *x) { *x <<= 1; } bool iseven(const int x) { return (x & 1) == 0; }

int ethiopian(int plier, int plicand, const bool tutor) { 

 int result=0;

 if (tutor)
   printf("ethiopian multiplication of %d by %d\n", plier, plicand);
 
 while(plier >= 1) {
   if ( iseven(plier) ) {
     if (tutor) printf("%4d %6d struck\n", plier, plicand);
   } else {
     if (tutor) printf("%4d %6d kept\n", plier, plicand);
     result += plicand;
   }
   halve(&plier); doublit(&plicand);
 }
 return result;

}

int main() { 

 printf("%d\n", ethiopian(17, 34, true));
 return 0;

}</lang>

C++

Using C++ templates, these kind of tasks can be implemented as meta-programs. The program runs at compile time, and the result is statically saved into regularly compiled code. Here is such an implementation without tutor, since there is no mechanism in C++ to output messages during program compilation. <lang cpp>template<int N> struct Half { 

       enum { Result = N >> 1 };

};

template<int N> struct Double { 

       enum { Result = N << 1 };

};

template<int N> struct IsEven { 

       static const bool Result = (N & 1) == 0;

};

template<int Multiplier, int Multiplicand> struct EthiopianMultiplication { 

       template<bool Cond, int Plier, int RunningTotal>
       struct AddIfNot
       {
               enum { Result = Plier + RunningTotal };
       };
       template<int Plier, int RunningTotal>
       struct AddIfNot <true, Plier, RunningTotal>
       {
               enum { Result = RunningTotal };
       };

       template<int Plier, int Plicand, int RunningTotal>
       struct Loop
       {
               enum { Result = Loop<Half<Plier>::Result, Double<Plicand>::Result,
                      AddIfNot<IsEven<Plier>::Result, Plicand, RunningTotal >::Result >::Result };
       };
       template<int Plicand, int RunningTotal>
       struct Loop <0, Plicand, RunningTotal>
       {
               enum { Result = RunningTotal };
       };

       enum { Result = Loop<Multiplier, Multiplicand, 0>::Result };

};

  1. include <iostream>

int main(int, char **) { 

       std::cout << EthiopianMultiplication<17, 54>::Result << std::endl;
       return 0;

}</lang>

C#

Works with: C# version 3+


Library: System.Linq


<lang csharp> using System; using System.Linq;

namespace RosettaCode.Tasks { public static class EthiopianMultiplication_Task { public static void Test ( ) { Console.WriteLine ( "Ethiopian Multiplication" ); int A = 17, B = 34; Console.WriteLine ( "Recursion: {0}*{1}={2}", A, B, EM_Recursion ( A, B ) ); Console.WriteLine ( "Linq: {0}*{1}={2}", A, B, EM_Linq ( A, B ) ); Console.WriteLine ( "Loop: {0}*{1}={2}", A, B, EM_Loop ( A, B ) ); Console.WriteLine ( ); }

public static int Halve ( this int p_Number ) { return p_Number >> 1; } public static int Double ( this int p_Number ) { return p_Number << 1; } public static bool IsEven ( this int p_Number ) { return ( p_Number % 2 ) == 0; }

public static int EM_Recursion ( int p_NumberA, int p_NumberB ) { // Anchor Point, Recurse to find the next row Sum it with the second number according to the rules return p_NumberA == 1 ? p_NumberB : EM_Recursion ( p_NumberA.Halve ( ), p_NumberB.Double ( ) ) + ( p_NumberA.IsEven ( ) ? 0 : p_NumberB ); } public static int EM_Linq ( int p_NumberA, int p_NumberB ) { // Creating a range from 1 to x where x the number of times p_NumberA can be halved. // This will be 2^x where 2^x <= p_NumberA. Basically, ln(p_NumberA)/ln(2). return Enumerable.Range ( 1, Convert.ToInt32 ( Math.Log ( p_NumberA, Math.E ) / Math.Log ( 2, Math.E ) ) + 1 ) // For every item (Y) in that range, create a new list, comprising the pair (p_NumberA,p_NumberB) Y times. .Select ( ( item ) => Enumerable.Repeat ( new { Col1 = p_NumberA, Col2 = p_NumberB }, item ) // The aggregate method iterates over every value in the target list, passing the accumulated value and the current item's value. .Aggregate ( ( agg_pair, orig_pair ) => new { Col1 = agg_pair.Col1.Halve ( ), Col2 = agg_pair.Col2.Double ( ) } ) ) // Remove all even items .Where ( pair => !pair.Col1.IsEven ( ) ) // And sum! .Sum ( pair => pair.Col2 ); } public static int EM_Loop ( int p_NumberA, int p_NumberB ) { int RetVal = 0; while ( p_NumberA >= 1 ) { RetVal += p_NumberA.IsEven ( ) ? 0 : p_NumberB; p_NumberA = p_NumberA.Halve ( ); p_NumberB = p_NumberB.Double ( ); } return RetVal; } } }

</lang>

Clojure

<lang lisp>(defn halve [n] 

 (bit-shift-right n 1))

(defn twice [n]  ; 'double' is taken 

 (bit-shift-left n 1))

(defn even [n]  ; 'even?' is the standard fn 

 (zero? (bit-and n 1)))

(defn emult [x y] 

 (reduce + 
   (map second 
     (filter #(not (even (first %))) ; a.k.a. 'odd?'
       (take-while #(pos? (first %)) 
         (map vector 
           (iterate halve x) 
           (iterate twice y)))))))

(defn emult2 [x y] 

 (loop [a x, b y, r 0]
   (if (= a 1)
     (+ r b)
     (if (even a)
       (recur (halve a) (twice b) r)
       (recur (halve a) (twice b) (+ r b))))))</lang>

COBOL

Translation of: Common Lisp
Works with: COBOL version 2002
Works with: OpenCOBOL version 1.1

In COBOL, double is a reserved word, so the doubling functions is named twice, instead. <lang COBOL> *>* Ethiopian multiplication 

      IDENTIFICATION DIVISION.
      PROGRAM-ID. ethiopian-multiplication.
      DATA DIVISION.
      LOCAL-STORAGE SECTION.
      01  l                  PICTURE 9(10) VALUE 17.
      01  r                  PICTURE 9(10) VALUE 34.
      01  ethiopian-multiply PICTURE 9(20).
      01  product            PICTURE 9(20).
      PROCEDURE DIVISION.
        CALL "ethiopian-multiply" USING
          BY CONTENT l, BY CONTENT r,
          BY REFERENCE ethiopian-multiply
        END-CALL
        DISPLAY ethiopian-multiply END-DISPLAY
        MULTIPLY l BY r GIVING product END-MULTIPLY
        DISPLAY product END-DISPLAY
        STOP RUN.
      END PROGRAM ethiopian-multiplication.

      IDENTIFICATION DIVISION.
      PROGRAM-ID. ethiopian-multiply.
      DATA DIVISION.
      LOCAL-STORAGE SECTION.
      01  evenp   PICTURE 9.
        88 even   VALUE 1.
        88 odd    VALUE 0.
      LINKAGE SECTION.
      01  l       PICTURE 9(10).
      01  r       PICTURE 9(10).
      01  product PICTURE 9(20) VALUE ZERO.
      PROCEDURE DIVISION using l, r, product.
        MOVE ZEROES TO product
        PERFORM UNTIL l EQUAL ZERO
          CALL "evenp" USING
            BY CONTENT l,
            BY REFERENCE evenp
          END-CALL
          IF odd
            ADD r TO product GIVING product END-ADD
          END-IF
          CALL "halve" USING
            BY CONTENT l,
            BY REFERENCE l
          END-CALL
          CALL "twice" USING
            BY CONTENT r,
            BY REFERENCE r
          END-CALL
        END-PERFORM
        GOBACK.
      END PROGRAM ethiopian-multiply.

      IDENTIFICATION DIVISION.
      PROGRAM-ID. halve.
      DATA DIVISION.
      LOCAL-STORAGE SECTION.
      LINKAGE SECTION.
      01  n   PICTURE 9(10).
      01  m   PICTURE 9(10).
      PROCEDURE DIVISION USING n, m.
        DIVIDE n BY 2 GIVING m END-DIVIDE
        GOBACK.
      END PROGRAM halve.

      IDENTIFICATION DIVISION.
      PROGRAM-ID. twice.
      DATA DIVISION.
      LOCAL-STORAGE SECTION.
      LINKAGE SECTION.
      01  n   PICTURE 9(10).
      01  m   PICTURE 9(10).
      PROCEDURE DIVISION USING n, m.
        MULTIPLY n by 2 GIVING m END-MULTIPLY
        GOBACK.
      END PROGRAM twice.

      IDENTIFICATION DIVISION.
      PROGRAM-ID. evenp.
      DATA DIVISION.
      LOCAL-STORAGE SECTION.
      01  q   PICTURE 9(10).
      LINKAGE SECTION.
      01  n   PICTURE 9(10).
      01  m   PICTURE 9(1).
        88 even   VALUE 1.
        88 odd    VALUE 0.
      PROCEDURE DIVISION USING n, m.
        DIVIDE n BY 2 GIVING q REMAINDER m END-DIVIDE
        SUBTRACT m FROM 1 GIVING m END-SUBTRACT
        GOBACK.
      END PROGRAM evenp.</lang>

CoffeeScript

<lang coffeescript> halve = (n) -> Math.floor n / 2 double = (n) -> n * 2 is_even = (n) -> n % 2 == 0

multiply = (a, b) -> 

 prod = 0
 while a > 0
   prod += b if !is_even a
   a = halve a
   b = double b
 prod
  1. tests

do -> 

 for i in [0..100]
   for j in [0..100]
     throw Error("broken for #{i} * #{j}") if multiply(i,j) != i * j

</lang>


ColdFusion

Version with as a function of functions:

<lang cfm><cffunction name="double"> 

   <cfargument name="number" type="numeric" required="true">

<cfset answer = number * 2> 

   <cfreturn answer>

</cffunction>

<cffunction name="halve"> 

   <cfargument name="number" type="numeric" required="true">

<cfset answer = int(number / 2)> 

   <cfreturn answer>

</cffunction>

<cffunction name="even"> 

   <cfargument name="number" type="numeric" required="true">

<cfset answer = number mod 2> 

   <cfreturn answer>

</cffunction>

<cffunction name="ethiopian"> 

   <cfargument name="Number_A" type="numeric" required="true">
   <cfargument name="Number_B" type="numeric" required="true">
   <cfset Result = 0>
   
   <cfloop condition = "Number_A GTE 1">
       <cfif even(Number_A) EQ 1>
           <cfset Result = Result + Number_B>
       </cfif>
       <cfset Number_A = halve(Number_A)>
       <cfset Number_B = double(Number_B)>
   </cfloop>
   <cfreturn Result>

</cffunction>


<cfoutput>#ethiopian(17,34)#</cfoutput></lang>

Version with display pizza:

<lang cfm><cfset Number_A = 17> <cfset Number_B = 34> <cfset Result = 0>

<cffunction name="double"> 

   <cfargument name="number" type="numeric" required="true">

<cfset answer = number * 2> 

   <cfreturn answer>

</cffunction>

<cffunction name="halve"> 

   <cfargument name="number" type="numeric" required="true">

<cfset answer = int(number / 2)> 

   <cfreturn answer>

</cffunction>

<cffunction name="even"> 

   <cfargument name="number" type="numeric" required="true">

<cfset answer = number mod 2> 

   <cfreturn answer>

</cffunction>


<cfoutput>

Ethiopian multiplication of #Number_A# and #Number_B#...


<cfloop condition = "Number_A GTE 1"> <cfif even(Number_A) EQ 1> <cfset Result = Result + Number_B> <cfset Action = "Keep"> <cfelse> <cfset Action = "Strike"> </cfif> <cfset Number_A = halve(Number_A)> <cfset Number_B = double(Number_B)> </cfloop>
#Number_A# #Number_B# #Action#

...equals #Result#

</cfoutput></lang>

Sample output: 

Ethiopian multiplication of 17 and 34...
17 	34 	Keep
8 	68 	Strike
4 	136 	Strike
2 	272 	Strike
1 	544 	Keep
...equals 578

Common Lisp

Common Lisp already has evenp, but all three of halve, double, and even-p are locally defined within ethiopian-multiply. (Note that the termination condition is (zerop l) because we terminate 'after' the iteration wherein the left column contains 1, and (halve 1) is 0.)

<lang lisp>(defun ethiopian-multiply (l r) 

 (flet ((halve (n) (floor n 2))
        (double (n) (* n 2))
        (even-p (n) (zerop (mod n 2))))
   (do ((product 0 (if (even-p l) product (+ product r)))
        (l l (halve l))
        (r r (double r)))
       ((zerop l) product))))</lang>

D

<lang d>import std.stdio;

int ethiopian(int n1, int n2) pure nothrow in { 

   assert(n1 >= 0, "muliplier cannot be negative");

} body { 

   static int doubleNum(in int n) pure nothrow { return n * 2; }
   static int halveNum(in int n) pure nothrow { return n / 2; }
   static bool isEven(in int n) pure nothrow { return !(n & 1); }

   int result;
   while (n1 >= 1) {
       if (!isEven(n1))
           result += n2;
       n1 = halveNum(n1);
       n2 = doubleNum(n2);
   }

   return result;

}

unittest { 

   assert(ethiopian(77, 54) == 77 * 54);
   assert(ethiopian(8, 923) == 8 * 923);
   assert(ethiopian(64, -4) == 64 * -4);

}

void main() { 

   writeln("17 ethiopian 34 is ", ethiopian(17, 34));

}</lang> Output: 

17 ethiopian 34 is 578

E

<lang e>def halve(&x) { x //= 2 } def double(&x) { x *= 2 } def even(x) { return x %% 2 <=> 0 }

def multiply(var a, var b) { 

   var ab := 0
   while (a > 0) {
       if (!even(a)) { ab += b }
       halve(&a)
       double(&b)
   }
   return ab

}</lang>

Ela

Translation of Haskell: <lang ela>open Core

let halve = (/2) let double = (*2) let odd = (==1) << (%2)

let ethiopicmult a b = sum <| map snd <| filter (odd << fst) <| zip 

     (takeWhile (>=1) <| iterate halve a)
     (iterate double b)

ethiopicmult 17 34</lang>

Output: 

578

Erlang

<lang erlang>-module(ethopian). -export([multiply/2]).

halve(N) -> 

   N div 2.

double(N) -> 

   N * 2.

even(N) -> 

   (N rem 2) == 0.

multiply(LHS,RHS) when is_integer(Lhs) and Lhs > 0 and is_integer(Rhs) and Rhs > 0 -> 

   multiply(LHS,RHS,0).

multiply(1,RHS,Acc) -> 

   RHS+Acc;

multiply(LHS,RHS,Acc) -> 

   case even(LHS) of
       true ->
           multiply(halve(LHS),double(RHS),Acc);
       false ->
           multiply(halve(LHS),double(RHS),Acc+RHS)
   end.

</lang>

Euphoria

<lang euphoria>function emHalf(integer n) 

 return floor(n/2)

end function

function emDouble(integer n) 

 return n*2

end function

function emIsEven(integer n) 

 return (remainder(n,2) = 0)

end function

function emMultiply(integer a, integer b) 

integer sum
 sum = 0
 while (a) do
   if (not emIsEven(a)) then sum += b end if
   a = emHalf(a)
   b = emDouble(b)
 end while
 
 return sum

end function

-- runtime

printf(1,"emMultiply(%d,%d) = %d\n",{17,34,emMultiply(17,34)})

printf(1,"\nPress Any Key\n",{}) while (get_key() = -1) do end while </lang>

Factor

<lang factor>USING: arrays kernel math multiline sequences ; IN: ethiopian-multiplication

/* This function is built-in

odd? ( n -- ? ) 1 bitand 1 number= ;
  • /
double ( n -- 2*n ) 2 * ;
halve ( n -- n/2 ) 2 /i ;
ethiopian-mult ( a b -- a*b )
   [ 0 ] 2dip
   [ dup 0 > ] [
       [ odd? [ + ] [ drop ] if ] 2keep
       [ double ] [ halve ] bi*
   ] while 2drop ;</lang>

FALSE

This example is incorrect. Please fix the code and remove this message.

Details: Different results with different interpreters (like http://morphett.info/false/false.html and http://www.quirkster.com/iano/js/false-js.html

<lang false>[2/]h: [2*]d: [1&]o: [0[@$][$o;![@@\$@+@]?h;!@d;!@]#%\%]m: 17 34m;!. {578}</lang>

Forth

<lang forth>: e* ( x y -- x*y ) 

 dup 0= if nip exit then
 over 2* over 2/ recurse
 swap 1 and if + else nip then ;</lang>

The author of Forth, Chuck Moore, designed a similar primitive into his MISC Forth microprocessors. The +* instruction is a multiply step: it adds S to T if A is odd, then shifts both A and T right one. The idea is that you only need to perform as many of these multiply steps as you have significant bits in the operand. (See his core instruction set for details.)

Fortran

Works with: Fortran version 90 and later

<lang fortran>program EthiopicMult 

 implicit none

 print *, ethiopic(17, 34, .true.)

contains 

 subroutine halve(v)
   integer, intent(inout) :: v
   v = int(v / 2)
 end subroutine halve

 subroutine doublit(v)
   integer, intent(inout) :: v
   v = v * 2
 end subroutine doublit

 function iseven(x)
   logical :: iseven
   integer, intent(in) :: x
   iseven = mod(x, 2) == 0
 end function iseven

 function ethiopic(multiplier, multiplicand, tutorialized) result(r)
   integer :: r
   integer, intent(in) :: multiplier, multiplicand
   logical, intent(in), optional :: tutorialized

   integer :: plier, plicand
   logical :: tutor

   plier = multiplier
   plicand = multiplicand

   if ( .not. present(tutorialized) ) then
      tutor = .false.
   else
      tutor = tutorialized
   endif

   r = 0

   if ( tutor ) write(*, '(A, I0, A, I0)') "ethiopian multiplication of ", plier, " by ", plicand

   do while(plier >= 1)
      if ( iseven(plier) ) then
         if (tutor) write(*, '(I4, " ", I6, A)') plier, plicand, " struck"
      else
         if (tutor) write(*, '(I4, " ", I6, A)') plier, plicand, " kept"
         r = r + plicand
      endif
      call halve(plier)
      call doublit(plicand)
   end do

 end function ethiopic

end program EthiopicMult</lang>

Go

<lang go>package main

import "fmt"

func halve(i int) int { return i/2 }

func double(i int) int { return i*2 }

func isEven(i int) bool { return i%2 == 0 }

func ethMulti(i, j int) (r int) { 

   for ; i > 0; i, j = halve(i), double(j) {
       if !isEven(i) {
           r += j
       }
   }
   return

}

func main() { 

   fmt.Printf("17 ethiopian 34 = %d\n", ethMulti(17, 34))

} </lang>

GW-BASIC

<lang qbasic>10 DEF FNE(A)=(A+1) MOD 2 20 DEF FNH(A)=INT(A/2) 30 DEF FND(A)=2*A 40 X=17:Y=34:TOT=0 50 WHILE X>=1 60 PRINT X, 70 IF FNE(X)=0 THEN TOT=TOT+Y:PRINT Y ELSE PRINT 80 X=FNH(X):Y=FND(Y) 90 WEND 100 PRINT "=", TOT</lang>

Haskell

<lang haskell>import Prelude hiding (odd)

halve, double :: Integral a => a -> a halve = (`div` 2) double = (2 *)

odd :: Integral a => a -> Bool odd = (== 1) . (`mod` 2)

ethiopicmult :: Integral a => a -> a -> a ethiopicmult a b = sum $ map snd $ filter (odd . fst) $ zip 

   (takeWhile (>= 1) $ iterate halve a)
   (iterate double b)

main = print $ ethiopicmult 17 34 == 17 * 34</lang>

Usage example from the interpreter 

*Main> ethiopicmult 17 34
578

HicEst

<lang hicest> WRITE(Messagebox) ethiopian( 17, 34 ) END ! of "main"

FUNCTION ethiopian(x, y) 

   ethiopian = 0
   left = x
   right = y
   DO i = x, 1, -1
     IF( isEven(left) == 0 ) ethiopian = ethiopian + right
     IF( left == 1 ) RETURN
     left = halve(left)
     right = double(right)
   ENDDO
END

FUNCTION halve( x ) 

   halve = INT( x/2 )
END

FUNCTION double( x ) 

   double = 2 * x
END

FUNCTION isEven( x ) 

   isEven = MOD(x, 2) == 0
END </lang>

Icon and Unicon

<lang Icon>procedure main(arglist) while ethiopian(integer(get(arglist)),integer(get(arglist))) # multiply successive pairs of command line arguments end

procedure ethiopian(i,j) # recursive Ethiopian multiplication return ( if not even(i) then j # this exploits that icon control expressions return values 

        else 0 ) + 
      ( if i ~= 0 then ethiopian(halve(i),double(j)) 
        else 0 )

end

procedure double(i) return i * 2 end

procedure halve(i) return i / 2 end

procedure even(i) return ( i % 2 = 0, i ) end</lang>

While not it seems a task requirement, most implementations have a tutorial version. This seemed easiest in an iterative version. <lang Icon>procedure ethiopian(i,j) # iterative tutor local p,w w := *j+3 write("Ethiopian Multiplication of ",i," * ",j)

p := 0 until i = 0 do { 

  writes(right(i,w),right(j,w))
  if not even(i) then {
     p +:= j
     write(" add")
     }
  else write(" discard")
  i := halve(i)
  j := double(j)
  }

write(right("=",w),right(p,w)) return p end</lang>

J

Solution: <lang j>double =: 2&* halve =:  %&2 NB. or the primitive -: odd =: 2&|

ethiop =: +/@(odd@] # (double~ <@#)) (1>.<.@halve)^:a:</lang>

Example: <lang j> 17 ethiop 34 578</lang>

Note that double will repeatedly double its right argument if given a repetition count for its left argument:

<lang J> (<5) double 17 17 34 68 136 272</lang>

Note: this implementation assumes that the number on the right is a positive integer. In contexts where it can be negative, its absolute value should be used and you should multiply the result of ethiop by its sign.

<lang j>ethio=: *@] * (ethiop |)</lang>

Alternatively, if multiplying by negative 1 is prohibited, you can use a conditional function which optionally negates its argument.

<lang j>ethio=: *@] -@]^:(0 > [) (ethiop |)</lang>

Examples:

<lang j> 7 ethio 11 77 

  7 ethio _11

_77 

  _7 ethio 11

_77 

  _7 ethio _11

77</lang>

Java

Works with: Java version 1.5+

<lang java5>import java.util.HashMap; import java.util.Map; import java.util.Scanner; public class Mult{ 

 public static void main(String[] args){
   Scanner sc = new Scanner(System.in);
   int first = sc.nextInt();
   int second = sc.nextInt();

   if(first < 0){
       first = -first;
       second = -second;
   }

   Map<Integer, Integer> columns = new HashMap<Integer, Integer>();
       columns.put(first, second);
   int sum = isEven(first)? 0 : second;
   do{
     first = halveInt(first);
     second = doubleInt(second);
     columns.put(first, second);
     if(!isEven(first)){
         sum += second;
     }
   }while(first > 1);

   System.out.println(sum);
 }

 public static int doubleInt(int doubleMe){
   return doubleMe << 1; //shift left
 }

 public static int halveInt(int halveMe){
   return halveMe >>> 1; //shift right
 }

 public static boolean isEven(int num){
   return (num & 1) == 0;
 }

}</lang> An optimised variant using the three helper functions from the other example. <lang java5>/** 

* This method will use ethiopian styled multiplication.
* @param a Any non-negative integer.
* @param b Any integer.
* @result a multiplied by b
*/

public static int ethiopianMultiply(int a, int b) { 

 if(a==0 || b==0) {
   return 0;
 }
 int result = 0;
 while(a>=1) {
   if(!isEven(a)) {
     result+=b;
   }
   b = doubleInt(b);
   a = halveInt(a);
 }
 return result;

}

/** 

* This method is an improved version that will use
* ethiopian styled multiplication, and also
* supports negative parameters.
* @param a Any integer.
* @param b Any integer.
* @result a multiplied by b
*/

public static int ethiopianMultiplyWithImprovement(int a, int b) { 

 if(a==0 || b==0) {
   return 0;
 }
 if(a<0) {
   a=-a;
   b=-b;
 } else if(b>0 && a>b) {
   int tmp = a;
   a = b;
   b = tmp;
 }
 int result = 0;
 while(a>=1) {
   if(!isEven(a)) {
     result+=b;
   }
   b = doubleInt(b);
   a = halveInt(a);
 }
 return result;

}</lang>

JavaScript

<lang javascript>var eth = {

halve : function ( n ){ return Math.floor(n/2); }, double: function ( n ){ return 2*n; }, isEven: function ( n ){ return n%2 === 0); },

mult: function ( a , b ){ var sum = 0, a = [a], b = [b];

while ( a[0] !== 1 ){ a.unshift( eth.halve( a[0] ) ); b.unshift( eth.double( b[0] ) ); }

for( var i = a.length - 1; i > 0 ; i -= 1 ){

if( !eth.isEven( a[i] ) ){ sum += b[i]; } }

return sum + b[0];

} }

// eth.mult(17,34) returns 578</lang>

Liberty BASIC

<lang lb>x = 17 y = 34 msg$ = str$(x) + " * " + str$(y) + " = " Print str$(x) + " " + str$(y) 'In this routine we will not worry about discarding the right hand value whos left hand partner is even; 'we will just not add it to our product. Do Until x < 2 

   If Not(isEven(x)) Then
       product = (product + y)
   End If
   x = halveInt(x)
   y = doubleInt(y)
   Print str$(x) + "    " + str$(y)

Loop product = (product + y) If (x < 0) Then product = (product * -1) Print msg$ + str$(product)

Function isEven(num) 

   isEven = Abs(Not(num Mod 2))

End Function

Function halveInt(num) 

   halveInt = Int(num/ 2)

End Function

Function doubleInt(num) 

   doubleInt = (num * 2)

End Function</lang>

Locomotive Basic

<lang locobasic>10 DEF FNiseven(a)=(a+1) MOD 2 20 DEF FNhalf(a)=INT(a/2) 30 DEF FNdouble(a)=2*a 40 x=17:y=34:tot=0 50 WHILE x>=1 60 PRINT x, 70 IF FNiseven(x)=0 THEN tot=tot+y:PRINT y ELSE PRINT 80 x=FNhalf(x):y=FNdouble(y) 90 WEND 100 PRINT "=", tot</lang>

Output: 

 17           34
 8
 4
 2
 1            544
=             578

<lang logo>to double :x 

 output ashift :x  1

end to halve :x 

 output ashift :x -1

end to even? :x 

 output equal? 0 bitand 1 :x

end to eproduct :x :y 

 if :x = 0 [output 0]
 ifelse even? :x ~
   [output      eproduct halve :x double :y] ~
   [output :y + eproduct halve :x double :y]

end</lang>

Lua

<lang lua>function halve(a) 

   return a/2

end

function double(a) 

   return a*2

end

function isEven(a) 

   return a%2 == 0

end

function ethiopian(x, y) 

   local result = 0

   while (x >= 1) do
       if not isEven(x) then
           result = result + y
       end

       x = math.floor(halve(x))
       y = double(y)
   end

   return result;

end

print(ethiopian(17, 34))</lang>

Mathematica

<lang Mathematica>IntegerHalving[x_]:=Floor[x/2] IntegerDoubling[x_]:=x*2; OddInteger OddQ Ethiopian[x_, y_] := Total[Select[NestWhileList[{IntegerHalving[#1],IntegerDoubling[#2]}&, {x,y}, (#1>1&)], OddQ[#1]&]]2

Ethiopian[17, 34]</lang>

Output: 

578

Metafont

Implemented without the tutor. <lang metafont>vardef halve(expr x) = floor(x/2) enddef; vardef double(expr x) = x*2 enddef; vardef iseven(expr x) = if (x mod 2) = 0: true else: false fi enddef;

primarydef a ethiopicmult b = 

 begingroup
   save r_, plier_, plicand_;
   plier_ := a; plicand_ := b;
   r_ := 0;
   forever: exitif plier_ < 1;
     if not iseven(plier_): r_ := r_ + plicand_; fi
     plier_ := halve(plier_);
     plicand_ := double(plicand_);
   endfor
   r_
 endgroup

enddef;

show( (17 ethiopicmult 34) ); end</lang>

MATLAB

First we define the three subroutines needed for this task. These must be saved in their own individual ".m" files. The file names must be the same as the function name stored in that file. Also, they must be saved in the same directory as the script that performs the Ethiopian Multiplication.

In addition, with the exception of the "isEven" and "doubleInt" functions, the inputs of the functions have to be an integer data type. This means that the input to these functions must be coerced from the default IEEE754 double precision floating point data type that all numbers and variables are represented as, to integer data types. As of MATLAB 2007a, 64-bit integer arithmetic is not supported. So, at best, these will work for 32-bit integer data types.

halveInt.m: <lang MATLAB>function result = halveInt(number) 

   result = idivide(number,2,'floor');

end</lang>

doubleInt.m: <lang MATLAB>function result = doubleInt(number) 

   result = times(2,number);

end</lang>

isEven.m: <lang MATLAB>%Returns a logical 1 if the number is even, 0 otherwise. function trueFalse = isEven(number) 

   trueFalse = logical( mod(number,2)==0 );

end</lang>

ethiopianMultiplication.m: <lang MATLAB>function answer = ethiopianMultiplication(multiplicand,multiplier) 

   %Generate columns
   while multiplicand(end)>1
       multiplicand(end+1,1) = halveInt( multiplicand(end) );
       multiplier(end+1,1) = doubleInt( multiplier(end) );
   end

   %Strike out appropriate rows
   multiplier( isEven(multiplicand) ) = [];

   %Generate answer
   answer = sum(multiplier);

end</lang>

Sample input: (with data type coercion) <lang MATLAB>ethiopianMultiplication( int32(17),int32(34) )

ans = 

  578

</lang>

MMIX

In order to assemble and run this program you'll have to install MMIXware from [1]. This provides you with a simple assembler, a simulator, example programs and full documentation.

<lang mmix>A IS 17 B IS 34

pliar IS $255 % designating main registers pliand GREG acc GREG str IS pliar % reuse reg $255 for printing

LOC Data_Segment GREG @ BUF OCTA #3030303030303030 % reserve a buffer that is big enough to hold OCTA #3030303030303030 % a max (signed) 64 bit integer: OCTA #3030300a00000000 % 2^63 - 1 = 9223372036854775807  % string is terminated with NL, 0

LOC #1000 % locate program at address GREG @ halve SR pliar,pliar,1 GO $127,$127,0

double SL pliand,pliand,1 GO $127,$127,0

odd DIV $77,pliar,2 GET $78,rR GO $127,$127,0

% Main is the entry point of the program Main SET pliar,A % initialize registers for calculation SET pliand,B SET acc,0 1H GO $127,odd BZ $78,2F % if pliar is even skip incr. acc with pliand ADD acc,acc,pliand % 2H GO $127,halve % halve pliar GO $127,double % and double pliand PBNZ pliar,1B % repeat from 1H while pliar > 0 // result: acc = 17 x 34 // next: print result --> stdout // $0 is a temp register LDA str,BUF+19 % points after the end of the string 2H SUB str,str,1 % update buffer pointer DIV acc,acc,10 % do a divide and mod GET $0,rR % get digit from special purpose reg. rR % containing the remainder of the division INCL $0,'0' % convert to ascii STBU $0,str % place digit in buffer PBNZ acc,2B % next % 'str' points to the start of the result TRAP 0,Fputs,StdOut % output answer to stdout TRAP 0,Halt,0 % exit</lang> Assembling: 

~/MIX/MMIX/Progs> mmixal ethiopianmult.mms

Running: 

~/MIX/MMIX/Progs> mmix ethiopianmult
578

Modula-3

Translation of: Ada

<lang modula3>MODULE Ethiopian EXPORTS Main;

IMPORT IO, Fmt;

PROCEDURE IsEven(n: INTEGER): BOOLEAN = 

 BEGIN
   RETURN n MOD 2 = 0;
 END IsEven;

PROCEDURE Double(n: INTEGER): INTEGER = 

 BEGIN
   RETURN n * 2;
 END Double;

PROCEDURE Half(n: INTEGER): INTEGER = 

 BEGIN
   RETURN n DIV 2;
 END Half;

PROCEDURE Multiply(a, b: INTEGER): INTEGER = 

 VAR
   temp := 0;
   plier := a;
   plicand := b;
 BEGIN
   WHILE plier >= 1 DO
     IF NOT IsEven(plier) THEN
       temp := temp + plicand;
     END;
     plier := Half(plier);
     plicand := Double(plicand);
   END;
   RETURN temp;
 END Multiply;

BEGIN 

 IO.Put("17 times 34 = " & Fmt.Int(Multiply(17, 34)) & "\n");

END Ethiopian.</lang>

MUMPS

<lang MUMPS> HALVE(I) 

;I should be an integer
QUIT I\2

DOUBLE(I) 

;I should be an integer
QUIT I*2

ISEVEN(I) 

;I should be an integer
QUIT '(I#2)

E2(M,N) 

New W,A,E,L Set W=$Select($Length(M)>=$Length(N):$Length(M)+2,1:$L(N)+2),A=0,L=0,A(L,1)=M,A(L,2)=N
Write "Multiplying two numbers:"
For  Write !,$Justify(A(L,1),W),?W,$Justify(A(L,2),W) Write:$$ISEVEN(A(L,1)) ?(2*W)," Struck" Set:'$$ISEVEN(A(L,1)) A=A+A(L,2) Set L=L+1,A(L,1)=$$HALVE(A(L-1,1)),A(L,2)=$$DOUBLE(A(L-1,2)) Quit:A(L,1)<1
Write ! For E=W:1:(2*W) Write ?E,"="
Write !,?W,$Justify(A,W),!
Kill W,A,E,L
Q

</lang>

Output:

USER>D E2^ROSETTA(1439,7)
Multiplying two numbers:
  1439     7
   719    14
   359    28
   179    56
    89   112
    44   224 Struck
    22   448 Struck
    11   896
     5  1792
     2  3584 Struck
     1  7168
      =======
       10073

Nemerle

<lang Nemerle>using System; using System.Console;

module Ethiopian { 

   Multiply(x : int, y : int) : int
   {
       def halve(a)  {a / 2}
       def doble(a)  {a * 2}
       def isEven(a) {a % 2 == 0}
       def multiply(p, q)
       {
           match(p)
           {
               |p when (p < 1) => 0
               |p when (isEven(p)) => 0 + multiply(halve(p), doble(q))
               |_ => q + multiply(halve(p), doble(q))
           }
       }
       multiply(x, y)
   }
   
   Main() : void
   {
       WriteLine("By Ethiopian multiplication, 17 * 34 = {0}", Multiply(17, 34));
   }

}</lang>

Object Pascal

multiplication.pas:

<lang pascal>unit Multiplication; interface

function Double(Number: Integer): Integer; function Halve(Number: Integer): Integer; function Even(Number: Integer): Boolean; function Ethiopian(NumberA, NumberB: Integer): Integer;

implementation 

 function Double(Number: Integer): Integer;
 begin
   result := Number * 2
 end;

 function Halve(Number: Integer): Integer;
 begin
   result := Number div 2
 end;

 function Even(Number: Integer): Boolean;
 begin
   result := Number mod 2 = 0
 end;

 function Ethiopian(NumberA, NumberB: Integer): Integer;
 begin
   result := 0;
   while NumberA >= 1 do
   begin
     if not Even(NumberA) then
       result := result + NumberB;
     NumberA := Halve(NumberA);
     NumberB := Double(NumberB)
   end
 end;

begin end.</lang>

ethiopianmultiplication.pas:

<lang pascal>program EthiopianMultiplication;

uses 

 Multiplication;

begin 

 WriteLn('17 * 34 = ', Ethiopian(17, 34))

end.</lang>

Output:

<lang pascal>17 * 34 = 578</lang>

Objective-C

Using class methods except for the generic useful function iseven. <lang objc>#import <stdio.h>

  1. import <objc/Object.h>

BOOL iseven(int x) { 

 return (x&1) == 0;

}

@interface EthiopicMult : Object + (int)mult: (int)plier by: (int)plicand; + (int)halve: (int)a; + (int)double: (int)a; @end

@implementation EthiopicMult + (int)mult: (int)plier by: (int)plicand { 

 int r = 0;
 while(plier >= 1) {
   if ( !iseven(plier) ) r += plicand;
   plier = [EthiopicMult halve: plier];
   plicand = [EthiopicMult double: plicand];
 }
 return r;

}

+ (int)halve: (int)a { 

 return (a>>1);

}

+ (int)double: (int)a { 

 return (a<<1);

} @end

int main() { 

 printf("%d\n", [EthiopicMult mult: 17 by: 34]);
 return 0;

}</lang>


OCaml

<lang ocaml>(* We optimize a bit by not keeping the intermediate lists, and summing 

  the right column on-the-fly, like in the C version.
  The function takes "halve" and "double" operators and "is_even" predicate as arguments,
  but also "is_zero", "zero" and "add". This allows for more general uses of the
  ethiopian multiplication. *)

let ethiopian is_zero is_even halve zero double add b a = 

 let rec g a b r =
   if is_zero a
   then (r)
   else g (halve a) (double b) (if not (is_even a) then (add b r) else (r))
 in
 g a b zero

let imul = 

 ethiopian (( = ) 0) (fun x -> x mod 2 = 0) (fun x -> x / 2) 0 (( * ) 2) ( + );;

imul 17 34;; (* - : int = 578 *)

(* Now, we have implemented the same algorithm as "rapid exponentiation", 

  merely changing operator names *)

let ipow = 

 ethiopian (( = ) 0) (fun x -> x mod 2 = 0) (fun x -> x / 2) 1 (fun x -> x*x) ( * )

ipow 2 16;; (* - : int = 65536 *)

(* still renaming operators, if "halving" is just subtracting one, 

  and "doubling", adding one, then we get an addition *)

let iadd a b = 

 ethiopian (( = ) 0) (fun x -> false) (pred) b (function x -> x) (fun x y -> succ y) 0 a

iadd 421 1000;; (* - : int = 1421 *)

(* One can do much more with "ethiopian multiplication", 

  since the two "multiplicands" and the result may be of three different types,
  as shown by the typing system of ocaml *)

ethiopian;; - : ('a -> bool) -> (* is_zero *) 

   ('a -> bool) ->          (* is_even *)
   ('a -> 'a) ->            (* halve *)
   'b ->                    (* zero *)
   ('c -> 'c) ->            (* double *)
   ('c -> 'b -> 'b) ->      (* add *)
   'c ->                    (* b *)
   'a ->                    (* a *)
   'b                       (* result *)

= <fun>

(* Here zero is the starting value for the accumulator of the sums 

  of values in the right column in the original algorithm. But the "add"
  me do something else, see for example the RosettaCode page on 
  "Exponentiation operator". *)</lang>

Octave

<lang octave>function r = halve(a) 

 r = floor(a/2);

endfunction

function r = doublit(a) 

 r = a*2;

endfunction

function r = iseven(a) 

 r = mod(a,2) == 0;

endfunction

function r = ethiopicmult(plier, plicand, tutor=false) 

 r = 0;
 if (tutor)
   printf("ethiopic multiplication of %d and %d\n", plier, plicand);
 endif
 while(plier >= 1)
   if ( iseven(plier) )
     if (tutor)

printf("%4d %6d struck\n", plier, plicand); 

     endif
   else
     r = r + plicand;
     if (tutor)

printf("%4d %6d kept\n", plier, plicand); 

     endif
   endif
   plier = halve(plier);
   plicand = doublit(plicand);
 endwhile

endfunction

disp(ethiopicmult(17, 34, true))</lang>

Oz

<lang oz>declare 

 fun {Halve X}   X div 2             end
 fun {Double X}  X * 2               end
 fun {Even X}    {Abs X mod 2} == 0  end  %% standard function: Int.isEven

 fun {EthiopicMult X Y}
    X >= 0 = true %% assert: X must not be negative

    Rows = for
              L in X; L>0;  {Halve L}  %% C-like iterator: "Init; While; Next"
              R in Y; true; {Double R}
              collect:Collect

do {Collect L#R} end 

    OddRows = {Filter Rows LeftIsOdd}
    RightColumn = {Map OddRows SelectRight}
 in
    {Sum RightColumn}
 end

 %% Helpers
 fun {LeftIsOdd L#_}   {Not {Even L}}          end
 fun {SelectRight _#R} R                       end
 fun {Sum Xs}          {FoldL Xs Number.'+' 0} end

in 

 {Show {EthiopicMult 17 34}}</lang>

PARI/GP

<lang parigp>halve(n)=n\2; double(n)=2*n; even(n)=!(n%2); multE(a,b)={ my(d=0); 

    while(a,
         if(!even(a),
              d+=b);
         a=halve(a);
         b=double(b));
    d

};</lang>

Pascal

<lang pascal>program EthiopianMultiplication; 

 function Double(Number: Integer): Integer;
 begin
   Double := Number * 2
 end;

 function Halve(Number: Integer): Integer;
 begin
   Halve := Number div 2
 end;

 function Even(Number: Integer): Boolean;
 begin
   Even := Number mod 2 = 0
 end;

 function Ethiopian(NumberA, NumberB: Integer): Integer;
 begin
   Ethiopian := 0;
   while NumberA >= 1 do

begin if not Even(NumberA) then Ethiopian := Ethiopian + NumberB; NumberA := Halve(NumberA); NumberB := Double(NumberB) end 

 end;

begin 

 Write(Ethiopian(17, 34))

end.</lang>

Perl

<lang perl>use strict;

sub halve { int((shift) / 2); } sub double { (shift) * 2; } sub iseven { ((shift) & 1) == 0; }

sub ethiopicmult { 

   my ($plier, $plicand, $tutor) = @_;
   print "ethiopic multiplication of $plier and $plicand\n" if $tutor;
   my $r = 0;
   while ($plier >= 1)
   {

$r += $plicand unless iseven($plier); if ($tutor) { print "$plier, $plicand ", (iseven($plier) ? " struck" : " kept"), "\n"; } $plier = halve($plier); $plicand = double($plicand); 

   }
   return $r;

}

print ethiopicmult(17,34, 1), "\n";</lang>

Perl 6

Works with: Rakudo Star version 2010-08

<lang perl6>sub halve (Int $n is rw) { $n div= 2 } sub double (Int $n is rw) { $n *= 2 } sub even (Int $n --> Bool) { $n %% 2 }

sub ethiopicmult (Int $a is copy, Int $b is copy --> Int) { 

   my Int $r = 0;
   while $a {

even $a or $r += $b; halve $a; double $b; 

   }
   return $r;

}</lang> More succinctly using implicit typing, primed lambdas, and an infinite loop: <lang perl6>sub ethiopicmult { 

   my &halve  = * div= 2;
   my &double = * *= 2;
   my &even   = * %% 2;

   my ($a,$b) = @_;
   my $r;
   loop {
       even  $a or $r += $b;
       halve $a or return $r;
       double $b;
   }

}</lang>

PHP

Not object oriented version: <lang php><?php function halve($x) { 

 return floor($x/2);

}

function double($x) { 

 return $x*2;

}

function iseven($x) { 

 return !($x & 0x1);

}

function ethiopicmult($plier, $plicand, $tutor) { 

 if ($tutor) echo "ethiopic multiplication of $plier and $plicand\n";
 $r = 0;
 while($plier >= 1) {
   if ( !iseven($plier) ) $r += $plicand;
   if ($tutor)
     echo "$plier, $plicand ", (iseven($plier) ? "struck" : "kept"), "\n";
   $plier = halve($plier);
   $plicand = double($plicand);
 }
 return $r;

}

echo ethiopicmult(17, 34, true), "\n";

?></lang>

Output 

ethiopic multiplication of 17 and 34
 17, 34 kept
 8, 68 struck
 4, 136 struck
 2, 272 struck
 1, 544 kept
 578

Object Oriented version:

Works with: PHP5

<lang php><?php

class ethiopian_multiply { 

  protected $result = 0;

  protected function __construct($x, $y){
     while($x >= 1){
        $this->sum_result($x, $y);
        $x = $this->half_num($x);
        $y = $this->double_num($y);
     }
  }
  
  protected function half_num($x){
     return floor($x/2);
  }

  protected function double_num($y){
     return $y*2;
  }
  
  protected function not_even($n){
     return $n%2 != 0 ? true : false;
  }
  
  protected function sum_result($x, $y){
     if($this->not_even($x)){
        $this->result += $y;
     }
  }
  
  protected function get_result(){
     return $this->result;
  }
  
  static public function init($x, $y){
     $init = new ethiopian_multiply($x, $y);
     return $init->get_result();
  }

}

echo ethiopian_multiply::init(17, 34);

?></lang>

PicoLisp

<lang PicoLisp>(de halve (N) 

  (/ N 2) )

(de double (N) 

  (* N 2) )

(de even? (N) 

  (not (bit? 1 N)) )

(de ethiopian (X Y) 

  (let R 0
     (while (>= X 1)
        (or (even? X) (inc 'R Y))
        (setq
           X (halve X)
           Y (double Y) ) )
     R ) )</lang>

Pike

<lang Pike>int ethopian_multiply(int l, int r) { 

   int halve(int n) { return n/2; };
   int double(int n) { return n*2; };
   int(0..1) evenp(int n) { return !(n%2); };

   int product = 0;
   do
   {
       write("%5d %5d\n", l, r);
       if (!evenp(l))
           product += r;
       l = halve(l);
       r = double(r);          
   }
   while(l);
   return product;

}</lang>

PL/I

<lang PL/I> 

  declare (L(30), R(30)) fixed binary;
  declare (i, s) fixed binary;

  L, R = 0;
  put skip list
     ('Hello, please type two values and I will print their product:');
  get list (L(1), R(1));
  put edit ('The product of ', trim(L(1)), ' and ', trim(R(1)), ' is ') (a);
  do i = 1 by 1 while (L(i) ^= 0);
     L(i+1) = halve(L(i));
     R(i+1) = double(R(i));
  end;
  s = 0;
  do i = 1 by 1 while (L(i) > 0);
     if odd(L(i)) then s = s + R(i);
  end;
  put edit (trim(s)) (a);

halve: procedure (k) returns (fixed binary); 

  declare k fixed binary;
  return (k/2);

end halve; double: procedure (k) returns (fixed binary); 

  declare k fixed binary;
  return (2*k);

end; odd: procedure (k) returns (bit (1)); 

  return (iand(k, 1) ^= 0);

end odd; </lang>

PL/SQL

This code was taken from the ADA example above - very minor differences. <lang plsql>create or replace package ethiopian is 

 function multiply
   ( left    in  integer,
     right   in  integer)
 return integer;

end ethiopian; /

create or replace package body ethiopian is 

 function is_even(item  in integer) return boolean is
 begin
   return item mod 2 = 0;
 end is_even;

 function double(item  in integer) return integer is
 begin
   return item * 2;
 end double;

 function half(item  in integer) return integer is
 begin
   return trunc(item / 2);
 end half;

 function multiply
   ( left   in integer,
     right  in integer)
   return Integer
 is
   temp     integer := 0;
   plier    integer := left;
   plicand  integer := right;
 begin

   loop
     if not is_even(plier) then
       temp := temp + plicand;
     end if;
     exit when plier <= 1;
     plier := half(plier);
     plicand := double(plicand);
   end loop;

   return temp;

 end multiply;

end ethiopian; /

/* example call */ begin 

 dbms_output.put_line(ethiopian.multiply(17, 34));

end; /</lang>


Powerbuilder

<lang powerbuilder>public function boolean wf_iseven (long al_arg);return mod(al_arg, 2 ) = 0 end function

public function long wf_halve (long al_arg);RETURN int(al_arg / 2) end function

public function long wf_double (long al_arg);RETURN al_arg * 2 end function

public function long wf_ethiopianmultiplication (long al_multiplicand, long al_multiplier);// calculate result long ll_product

DO WHILE al_multiplicand >= 1 IF wf_iseven(al_multiplicand) THEN // do nothing ELSE ll_product += al_multiplier END IF al_multiplicand = wf_halve(al_multiplicand) al_multiplier = wf_double(al_multiplier) LOOP

return ll_product end function

// example call long ll_answer ll_answer = wf_ethiopianmultiplication(17,34)</lang>


PowerShell

Traditional

<lang PowerShell>function isEven { param ([int]$value) return [bool]($value % 2 -eq 0) }

function doubleValue { param ([int]$value) return [int]($value * 2) }

function halveValue { param ([int]$value) return [int]($value / 2) }

function multiplyValues { param ( [int]$plier, [int]$plicand, [int]$temp = 0 )

while ($plier -ge 1) { if (!(isEven $plier)) { $temp += $plicand } $plier = halveValue $plier $plicand = doubleValue $plicand }

return $temp }

multiplyValues 17 34</lang>

Pipes with Busywork

This uses several PowerShell specific features, in functions everything is returned automatically, so explicitly stating return is unnecessary. type conversion happens automatically for certain types, [int] into [boolean] maps 0 to false and everything else to true. A hash is used to store the values as they are being written, then a pipeline is used to iterate over the keys of the hash, determine which are odd, and only sum those. The three-valued ForEach-Object is used to set a start expression, an iterative expression, and a return expression. <lang PowerShell>function halveInt( [int] $rhs ) { [math]::floor( $rhs / 2 ) }

function doubleInt( [int] $rhs ) { $rhs*2 }

function isEven( [int] $rhs ) { -not ( $_ % 2 ) }

function Ethiopian( [int] $lhs , [int] $rhs ) { $scratch = @{} 1..[math]::floor( [math]::log( $lhs , 2 ) + 1 ) | ForEach-Object { $scratch[$lhs] = $rhs $lhs $lhs = halveInt( $lhs ) $rhs = doubleInt( $rhs ) } | Where-Object { -not ( isEven $_ ) } | ForEach-Object { $sum = 0 } { $sum += $scratch[$_] } { $sum } }

Ethiopian 17 34 </lang>

PureBasic

<lang PureBasic>Procedure isEven(x) 

 ProcedureReturn (x & 1) ! 1

EndProcedure

Procedure halveValue(x) 

 ProcedureReturn x / 2

EndProcedure

Procedure doubleValue(x) 

 ProcedureReturn x << 1

EndProcedure

Procedure EthiopianMultiply(x, y) 

 Protected sum
 Print("Ethiopian multiplication of " + Str(x) + " and " + Str(y) + " ... ")
 Repeat
   If Not isEven(x)
     sum + y
   EndIf
   x = halveValue(x)
   y = doubleValue(y)
 Until x < 1
 PrintN(" equals " + Str(sum))
 ProcedureReturn sum

EndProcedure

If OpenConsole() 

 EthiopianMultiply(17,34)

 Print(#CRLF$ + #CRLF$ + "Press ENTER to exit")
 Input()
 CloseConsole()

EndIf</lang> Sample output: 

Ethiopian multiplication of 17 and 34 ...  equals 578

It became apparent that according to the way the Ethiopian method is described above it can't produce a correct result if the first multiplicand (the one being repeatedly halved) is negative. I've addressed that in this variation. If the first multiplicand is negative then the resulting sum (which may already be positive or negative) is negated. <lang PureBasic>Procedure isEven(x) 

 ProcedureReturn (x & 1) ! 1

EndProcedure

Procedure halveValue(x) 

 ProcedureReturn x / 2

EndProcedure

Procedure doubleValue(x) 

 ProcedureReturn x << 1

EndProcedure

Procedure EthiopianMultiply(x, y) 

 Protected sum, sign = x
 
 Print("Ethiopian multiplication of " + Str(x) + " and " + Str(y) + " ...")
 Repeat
   If Not isEven(x)
     sum + y
   EndIf
   x = halveValue(x)
   y = doubleValue(y)
 Until x = 0
 If sign < 0 : sum * -1: EndIf
 
 PrintN(" equals " + Str(sum))
 ProcedureReturn sum

EndProcedure

If OpenConsole() 

 EthiopianMultiply(17,34)
 EthiopianMultiply(-17,34)
 EthiopianMultiply(-17,-34)
 
 Print(#CRLF$ + #CRLF$ + "Press ENTER to exit")
 Input()
 CloseConsole()

EndIf</lang> Sample output: 

Ethiopian multiplication of 17 and 34 ... equals 578
Ethiopian multiplication of -17 and 34 ... equals -578
Ethiopian multiplication of -17 and -34 ... equals 578

Python

Python: With tutor

<lang python>tutor = True

def halve(x): 

   return x//2

def double(x): 

   return x*2

def even(x): 

   return not x % 2

def ethiopian(multiplier, multiplicand): 

   if tutor:
       print( "Ethiopian multiplication of %i and %i" %
              (multiplier, multiplicand) )
   result = 0
   while multiplier >= 1:
       if even(multiplier):
           if tutor: print( "%4i %6i STRUCK" %
                            (multiplier, multiplicand) )
       else:
           if tutor: print( "%4i %6i KEPT" %
                            (multiplier, multiplicand) )
           result += multiplicand
       multiplier   = halve(multiplier)
       multiplicand = double(multiplicand)
   if tutor: print()
   return result</lang>

Sample output 

Python 3.1 (r31:73574, Jun 26 2009, 20:21:35) [MSC v.1500 32 bit (Intel)] on win32
Type "copyright", "credits" or "license()" for more information.
>>> ethiopian(17, 34)
Ethiopian multiplication of 17 and 34
  17     34 KEPT
   8     68 STRUCK
   4    136 STRUCK
   2    272 STRUCK
   1    544 KEPT

578
>>>

Python: Without tutor

Without the tutorial code, and taking advantage of Python's lambda:

<lang python>halve = lambda x: x // 2 double = lambda x: x*2 even = lambda x: not x % 2

def ethiopian(multiplier, multiplicand): 

   result = 0

   while multiplier >= 1:
       if not even(multiplier):
           result += multiplicand
       multiplier   = halve(multiplier)
       multiplicand = double(multiplicand)

   return result</lang>

Python: With tutor. More Functional

Using some features which Python has for use in functional programming. The example also tries to show how to mix different programming styles while keeping close to the task specification, a kind of "executable pseudocode". Note: While column2 could theoretically generate a sequence of infinite length, izip will stop requesting values from it (and so provide the necessary stop condition) when column1 has no more values. When not using the tutor, table will generate the table on the fly in an efficient way, not keeping any intermediate values.

<lang python>tutor = True

from itertools import izip, takewhile

def iterate(function, arg): 

   while 1:
       yield arg
       arg = function(arg)

def halve(x): return x // 2 def double(x): return x * 2 def even(x): return x % 2 == 0

def show_heading(multiplier, multiplicand): 

   print "Multiplying %d by %d" % (multiplier, multiplicand),
   print "using Ethiopian multiplication:"
   print

TABLE_FORMAT = "%8s %8s %8s %8s %8s"

def show_table(table): 

   for p, q in table:
       print TABLE_FORMAT % (p, q, "->",
                             p, q if not even(p) else "-" * len(str(q)))

def show_result(result): 

   print TABLE_FORMAT % (, , , , "=" * (len(str(result)) + 1))
   print TABLE_FORMAT % (, , , , result)

def ethiopian(multiplier, multiplicand): 

   def column1(x): return takewhile(lambda v: v >= 1, iterate(halve, x))
   def column2(x): return iterate(double, x)
   def rows(x, y): return izip(column1(x), column2(y))
   table = rows(multiplier, multiplicand)
   if tutor: 
       table = list(table)
       show_heading(multiplier, multiplicand)
       show_table(table)
   result = sum(q for p, q in table if not even(p))
   if tutor: 
       show_result(result)
   return result</lang>

Example output: 

>>> ethiopian(17, 34)
Multiplying 17 by 34 using Ethiopian multiplication:

      17       34       ->       17       34
       8       68       ->        8       --
       4      136       ->        4      ---
       2      272       ->        2      ---
       1      544       ->        1      544
                                        ====
                                         578
578

R

<lang R>halve <- function(a) floor(a/2) double <- function(a) a*2 iseven <- function(a) (a%%2)==0

ethiopicmult <- function(plier, plicand, tutor=FALSE) { 

 if (tutor) { cat("ethiopic multiplication of", plier, "and", plicand, "\n") }
 result <- 0
 while(plier >= 1) {
   if (!iseven(plier)) { result <- result + plicand }
   if (tutor) {
     cat(plier, ", ", plicand, " ", ifelse(iseven(plier), "struck", "kept"), "\n", sep="")
   }
   plier <- halve(plier)
   plicand <- double(plicand)
 }
 result

}

print(ethiopicmult(17, 34, TRUE))</lang>


Rascal

<lang Rascal>import IO;

public int halve(int n) = n/2;

public int double(int n) = n*2;

public bool uneven(int n) = (n % 2) != 0);

public int ethiopianMul(int n, int m) { result = 0; while(n >= 1) { if(uneven(n)) result += m; n = halve(n); m = double(m); } return result; } </lang>

REXX

<lang rexx> /*REXX program multiplies 2 integers by Ethiopian/Russian peasant method*/ numeric digits 1000 /*handle extremely large integers. */ parse arg a b . /*handles zeroes and negative integers.*/ 

                                /*A & B  should be checked if integers.*/

say 'a=' a say 'b=' b say 'product=' emult(a,b) exit

emult: procedure; parse arg x 1 ox,y prod=0 

         do while x\==0
         if \iseven(x) then prod=prod+y
         x=halve(x)
         y=double(y)
         end

return prod*sign(ox)

halve: return arg(1)%2 double: return arg(1)*2 iseven: return arg(1)//2==0 

         /*Note:  the above procedures don't modify (or define) any    */
         /*local variables, so there is no need to specify   PROCEDURE */

         /*REXX allows multiple definitions, only the 1st one is used. */
         /*Three different argument names (methodologies?) are shown.  */

halve: procedure; parse arg ?; return ?%2 double: procedure; parse arg x; return x+x iseven: procedure; parse arg _; return _//2 == 0 </lang>

Ruby

Iterative and recursive implementations here. I've chosen to highlight the example 20*5 which I think is more illustrative. <lang ruby>def even(x); x.even?; end def halve(x); x/2; end def double(x); x*2; end

  1. iterative

def ethopian_multiply(a, b) 

 product = 0
 while a >= 1 
   p [a, b, even(a) ? "STRIKE" : "KEEP"] if $DEBUG
   product += b if not even(a)
   a = halve(a)
   b = double(b)
 end
 product

end

  1. recursive

def rec_ethopian_multiply(a, b) 

 return 0 if a < 1
 p [a, b, even(a) ? "STRIKE" : "KEEP"] if $DEBUG
 (even(a) ? 0 : b) + rec_ethopian_multiply(halve(a), double(b))

end

$DEBUG = true # $DEBUG also set to true if "-d" option given a, b = 20, 5 puts "#{a} * #{b} = #{ethopian_multiply(a,b)}"; puts</lang>

Output: 

[20, 5, "STRIKE"]
[10, 10, "STRIKE"]
[5, 20, "KEEP"]
[2, 40, "STRIKE"]
[1, 80, "KEEP"]
20 * 5 = 100

A test suite: <lang ruby>require 'test/unit' class EthiopianTests < Test::Unit::TestCase 

 def test_iter1; assert_equal(578, ethopian_multiply(17,34)); end
 def test_iter2; assert_equal(100, ethopian_multiply(20,5));  end
 def test_iter3; assert_equal(5,   ethopian_multiply(5,1));   end
 def test_iter4; assert_equal(5,   ethopian_multiply(1,5));   end
 def test_iter5; assert_equal(0,   ethopian_multiply(5,0));   end
 def test_iter6; assert_equal(0,   ethopian_multiply(0,5));   end
 def test_rec1;  assert_equal(578, rec_ethopian_multiply(17,34)); end
 def test_rec2;  assert_equal(100, rec_ethopian_multiply(20,5));  end
 def test_rec3;  assert_equal(5,   rec_ethopian_multiply(5,1));   end
 def test_rec4;  assert_equal(5,   rec_ethopian_multiply(1,5));   end
 def test_rec5;  assert_equal(0,   rec_ethopian_multiply(5,0));   end
 def test_rec6;  assert_equal(0,   rec_ethopian_multiply(0,5));   end

end</lang> 

Loaded suite ethopian
Started
............
Finished in 0.001 seconds.

12 tests, 12 assertions, 0 failures, 0 errors


Scala

The first and second are only slightly different and use functional style. The third uses a for loop to yield the result.

<lang scala> def ethiopian(i:Int, j:Int):Int= 

  pairIterator(i,j).filter(x=> !isEven(x._1)).map(x=>x._2).foldLeft(0){(x,y)=>x+y}

def ethiopian2(i:Int, j:Int):Int= 

  pairIterator(i,j).map(x=>if(isEven(x._1)) 0 else x._2).foldLeft(0){(x,y)=>x+y}

def ethiopian3(i:Int, j:Int):Int= { 

  var res=0;
  for((h,d) <- pairIterator(i,j) if !isEven(h)) res+=d;
  res

}

def isEven(x:Int)=(x&1)==0 def halve(x:Int)=x>>>1 def double(x:Int)=x<<1

// generates pairs of values (halve,double) def pairIterator(x:Int, y:Int)=new Iterator[(Int, Int)] { 

  var i=(x, y)
  def hasNext=i._1>0
  def next={val r=i; i=(halve(i._1), double(i._2)); r}

} </lang>

Scheme

In Scheme, even? is a standard procedure. <lang scheme>(define (halve num) 

 (quotient num 2))

(define (double num) 

 (* num 2))

(define (*mul-eth plier plicand acc) 

 (cond ((zero? plier) acc)
       ((even? plier) (*mul-eth (halve plier) (double plicand) acc))
       (else (*mul-eth (halve plier) (double plicand) (+ acc plicand)))))

(define (mul-eth plier plicand) 

 (*mul-eth plier plicand 0))

(display (mul-eth 17 34)) (newline)</lang> Output: 

578

Seed7

Ethiopian Multiplication is another name for the peasant multiplication:

<lang seed7>const proc: double (inout integer: a) is func 

 begin
   a *:= 2;
 end func;

const proc: halve (inout integer: a) is func 

 begin
   a := a div 2;
 end func;

const func boolean: even (in integer: a) is 

 return not odd(a);

const func integer: peasantMult (in var integer: a, in var integer: b) is func 

 result
   var integer: result is 0;
 begin
   while a <> 0 do
     if not even(a) then
       result +:= b;
     end if;
     halve(a);
     double(b);
   end while;
 end func;</lang>

Original source (without separate functions for doubling, halving, and checking if a number is even): [2]

Smalltalk

Works with: GNU Smalltalk

<lang smalltalk>Number extend [ 

 double [ ^ self * 2 ]
 halve  [ ^ self // 2 ]
 ethiopianMultiplyBy: aNumber withTutor: tutor [
   |result multiplier multiplicand|
   multiplier := self.
   multiplicand := aNumber.
   tutor ifTrue: [ ('ethiopian multiplication of %1 and %2' % 
                     { multiplier. multiplicand }) displayNl ].
   result := 0.
   [ multiplier >= 1 ]
     whileTrue: [
       multiplier even ifFalse: [
                          result := result + multiplicand.
                          tutor ifTrue: [
                             ('%1, %2 kept' % { multiplier. multiplicand })
                               displayNl
                          ]       
                       ]
                       ifTrue: [
                          tutor ifTrue: [
                            ('%1, %2 struck' % { multiplier. multiplicand })

displayNl 

                          ]
                       ].
       multiplier := multiplier halve.
       multiplicand := multiplicand double.
     ].
   ^result
 ]
 ethiopianMultiplyBy: aNumber [ ^ self ethiopianMultiplyBy: aNumber withTutor: false ]

].</lang>

<lang smalltalk>(17 ethiopianMultiplyBy: 34 withTutor: true) displayNl.</lang>

SNOBOL4

<lang snobol4> define('halve(num)') :(halve_end) halve eq(num,1) :s(freturn) halve = num / 2 :(return) halve_end

define('double(num)') :(double_end) double double = num * 2 :(return) double_end

define('odd(num)') :(odd_end) odd eq(num,1) :s(return) eq(num,double(halve(num))) :s(freturn)f(return)

odd_end l = trim(input) r = trim(input) s = 0 next s = odd(l) s + r r = double(r) l = halve(l) :s(next) stop output = s end</lang>

SNUSP

<lang snusp> /==!/==atoi==@@@-@-----# 

   |   |          /-\          /recurse\    #/?\ zero

$>,@/>,@/?\<=zero=!\?/<=print==!\@\>?!\@/<@\.!\-/ 

       < @     #                 |   \=/  \=itoa=@@@+@+++++#
    /==\ \===?!/===-?\>>+# halve !     /+ !/+ !/+ !/+   \    mod10
  1. ! @ | #>>\?-<+>/ /<+> -\!?-\!?-\!?-\!?-\!

/-<+>\ > ? />+<<++>-\ \?!\-?!\-?!\-?!\-?!\-?/\ div10 ?down? | \-<<<!\=======?/\ add & # +/! +/! +/! +/! +/ \>+<-/ | \=<<<!/====?\=\ | double ! # | \<++>-/ | | \=======\!@>============/!/</lang>

This is possibly the smallest multiply routine so far discovered for SNUSP.

Tcl

<lang tcl># This is how to declare functions - the mathematical entities - as opposed to procedures proc function {name arguments body} { 

   uplevel 1 [list proc tcl::mathfunc::$name $arguments [list expr $body]]

}

function double n {$n * 2} function halve n {$n / 2} function even n {($n & 1) == 0} function mult {a b} { 

   $a < 1 ? 0 :
   even($a) ? [logmult STRUCK] + mult(halve($a), double($b))

 : [logmult KEPT] + mult(halve($a), double($b)) + $b }

  1. Wrapper to set up the logging

proc ethiopianMultiply {a b {tutor false}} { 

   if {$tutor} {

set wa [expr {[string length $a]+1}] set wb [expr {$wa+[string length $b]-1}] puts stderr "Ethiopian multiplication of $a and $b" interp alias {} logmult {} apply {{wa wb msg} { upvar 1 a a b b puts stderr [format "%*d %*d %s" $wa $a $wb $b $msg] return 0 }} $wa $wb 

   } else {

proc logmult args {return 0} 

   }
   return [expr {mult($a,$b)}]

}</lang> Demo code: <lang tcl>puts "17 * 34 = [ethiopianMultiply 17 34 true]"</lang> Output: 

Ethiopian multiplication of 17 and 34
 17   34 KEPT
  8   68 STRUCK
  4  136 STRUCK
  2  272 STRUCK
  1  544 KEPT
17 * 34 = 578

TUSCRIPT

<lang tuscript> $$ MODE TUSCRIPT ASK "insert number1", nr1="" ASK "insert number2", nr2=""

SET nrs=APPEND(nr1,nr2),size_nrs=SIZE(nrs) IF (size_nrs!=2) ERROR/STOP "insert two numbers" LOOP n=nrs IF (n!='digits') ERROR/STOP n, " is not a digit" ENDLOOP

PRINT "ethopian multiplication of ",nr1," and ",nr2

SET sum=0 SECTION checkifeven SET even=MOD(nr1,2) 

IF (even==0) THEN
  SET action="struck"
ELSE
  SET action="kept"
  SET sum=APPEND (sum,nr2)
ENDIF

SET nr1=CENTER (nr1,+6),nr2=CENTER (nr2,+6),action=CENTER (action,8) PRINT nr1,nr2,action ENDSECTION

SECTION halve_i SET nr1=nr1/2 ENDSECTION

SECTION double_i nr2=nr2*2 ENDSECTION

DO checkifeven

LOOP DO halve_i DO double_i DO checkifeven IF (nr1==1) EXIT ENDLOOP

SET line=REPEAT ("=",20), sum = sum(sum),sum=CENTER (sum,+12) PRINT line PRINT sum </lang> Output: 

ethopian multiplication of 17 and 34
    17    34  kept
     8    68 struck
     4   136 struck
     2   272 struck
     1   544  kept
====================
         578

UNIX Shell

Tried with bash --posix, and also with Heirloom's sh. Beware that bash --posix has more features than sh; this script uses only sh features.

Works with: Bourne Shell

<lang bash>halve() { 

   expr "$1" / 2

}

double() { 

   expr "$1" \* 2

}

is_even() { 

   expr "$1" % 2 = 0 >/dev/null

}

ethiopicmult() { 

   plier=$1
   plicand=$2
   r=0
   while [ "$plier" -ge 1 ]; do

is_even "$plier" || r=`expr $r + "$plicand"` plier=`halve "$plier"` plicand=`double "$plicand"` 

   done
   echo $r

}

ethiopicmult 17 34

  1. => 578</lang>

While breaking if the --posix flag is passed to bash, the following alternative script avoids the *, /, and % operators. It also uses local variables and built-in arithmetic.

Works with: bash
Works with: pdksh
Works with: zsh

<lang bash>halve() { 

 (( $1 >>= 1 ))

}

double() { 

 (( $1 <<= 1 ))

}

is_even() { 

 (( ($1 & 1) == 0 ))

}

multiply() { 

 local plier=$1
 local plicand=$2
 local result=0

 while (( plier > 0 ))
 do
   is_even plier || (( result += plicand ))
   halve plier
   double plicand
 done
 echo $result

}

multiply 17 34

  1. => 578</lang>

C Shell

<lang csh>alias halve '@ \!:1 /= 2' alias double '@ \!:1 *= 2' alias is_even '@ \!:1 = ! ( \!:2 % 2 )'

alias multiply eval \set multiply_args=( \!*:q ) \\ @ multiply_plier = $multiply_args[2] \\ @ multiply_plicand = $multiply_args[3] \\ @ multiply_result = 0 \\ while ( $multiply_plier > 0 ) \\ is_even multiply_is_even $multiply_plier \\ if ( ! $multiply_is_even ) then \\ @ multiply_result += $multiply_plicand \\ endif \\ halve multiply_plier \\ double multiply_plicand \\ end \\ @ $multiply_args[1] = $multiply_result \\ '\'

multiply p 17 34 echo $p

  1. => 578</lang>

Ursala

This solution makes use of the functions odd, double, and half, which respectively check the parity, double a given natural number, or perform truncating division by two. These functions are normally imported from the nat library but defined here explicitly for the sake of completeness. <lang Ursala>odd = ~&ihB double = ~&iNiCB half = ~&itB</lang> The functions above are defined in terms of bit manipulations exploiting the concrete representations of natural numbers. The remaining code treats natural numbers instead as abstract types by way of the library API, and uses the operators for distribution (*-), triangular iteration (|\), and filtering (*~) among others. <lang Ursala>#import nat

emul = sum:-0@rS+ odd@l*~+ ^|(~&,double)|\+ *-^|\~& @iNC ~&h~=0->tx :^/half@h ~&</lang>

test program: <lang Ursala>#cast %n

test = emul(34,17)</lang> output: 

578

VBScript

Nowhere near as optimal a solution as the Ada. Yes, it could have made as optimal, but the long way seemed more interesting.

Demonstrates a List class. The .recall and .replace methods have bounds checking but the code does not test for the exception that would be raised. List class extends the storage allocated for the list when the occupation of the list goes beyond the original allocation.

option explicit makes sure that all variables are declared.

Implementation <lang vb> option explicit

class List private theList private nOccupiable private nTop

sub class_initialize nTop = 0 nOccupiable = 100 redim theList( nOccupiable ) end sub

public sub store( x ) if nTop >= nOccupiable then nOccupiable = nOccupiable + 100 redim preserve theList( nOccupiable ) end if theList( nTop ) = x nTop = nTop + 1 end sub

public function recall( n ) if n >= 0 and n <= nOccupiable then recall = theList( n ) else err.raise vbObjectError + 1000,,"Recall bounds error" end if end function

public sub replace( n, x ) if n >= 0 and n <= nOccupiable then theList( n ) = x else err.raise vbObjectError + 1001,,"Replace bounds error" end if end sub

public property get listCount listCount = nTop end property

end class

function halve( n ) halve = int( n / 2 ) end function

function twice( n ) twice = int( n * 2 ) end function

function iseven( n ) iseven = ( ( n mod 2 ) = 0 ) end function


function multiply( n1, n2 ) dim LL set LL = new List

dim RR set RR = new List

LL.store n1 RR.store n2

do while n1 <> 1 n1 = halve( n1 ) LL.store n1 n2 = twice( n2 ) RR.store n2 loop

dim i for i = 0 to LL.listCount if iseven( LL.recall( i ) ) then RR.replace i, 0 end if next

dim total total = 0 for i = 0 to RR.listCount total = total + RR.recall( i ) next

multiply = total end function </lang>

Invocation <lang vb> wscript.echo multiply(17,34) </lang>

Output <lang vb> 578 </lang>

x86 Assembly

Works with: nasm

, linking with the C standard library and start code.

<lang asm> extern printf global main

section .text

halve shr ebx, 1 ret

double shl ebx, 1 ret

iseven and ebx, 1 cmp ebx, 0 ret ; ret preserves flags

main push 1 ; tutor = true push 34 ; 2nd operand push 17 ; 1st operand call ethiopicmult add esp, 12

push eax ; result of 17*34 push fmt call printf add esp, 8

ret


%define plier 8 %define plicand 12 %define tutor 16

ethiopicmult enter 0, 0 cmp dword [ebp + tutor], 0 je .notut0 push dword [ebp + plicand] push dword [ebp + plier] push preamblefmt call printf add esp, 12 .notut0

xor eax, eax ; eax -> result mov ecx, [ebp + plier] ; ecx -> plier mov edx, [ebp + plicand]  ; edx -> plicand

.whileloop cmp ecx, 1 jl .multend cmp dword [ebp + tutor], 0 je .notut1 call tutorme .notut1 mov ebx, ecx call iseven je .iseven add eax, edx ; result += plicand .iseven mov ebx, ecx ; plier >>= 1 call halve mov ecx, ebx

mov ebx, edx ; plicand <<= 1 call double mov edx, ebx

jmp .whileloop .multend leave ret


tutorme push eax push strucktxt mov ebx, ecx call iseven je .nostruck mov dword [esp], kepttxt .nostruck push edx push ecx push tutorfmt call printf add esp, 4 pop ecx pop edx add esp, 4 pop eax ret

section .data

fmt db "%d", 10, 0 preamblefmt db "ethiopic multiplication of %d and %d", 10, 0 tutorfmt db "%4d %6d %s", 10, 0 strucktxt db "struck", 0 kepttxt db "kept", 0</lang>


Smaller version

Using old style 16 bit registers created in debug

The functions to halve double and even are coded inline. To half a value 

  shr,1

to double a value 

  shl,1

to test if the value is even

<lang asm>test,01 jz Even Odd: Even:</lang>


<lang asm>;calling program 

1BDC:0100 6A11           PUSH   11  ;17  Put operands on the stack
1BDC:0102 6A22           PUSH   22  ;34
1BDC:0104 E80900         CALL   0110  ; call the mulitplcation routine
putting some space in, (not needed)
1BDC:0107 90             NOP
1BDC:0108 90             NOP
1BDC:0109 90             NOP
1BDC:010A 90             NOP
1BDC:010B 90             NOP
1BDC:010C 90             NOP
1BDC:010D 90             NOP
1BDC:010E 90             NOP
1BDC:010F 90             NOP
mulitplication routine starts here
1BDC:0110 89E5           MOV    BP,SP      ; prepare to get operands off stack
1BDC:0112 8B4E02         MOV    CX,[BP+02] ; Get the first operand
1BDC:0115 8B5E04         MOV    BX,[BP+04] ; get the second oerand
1BDC:0118 31C0           XOR    AX,AX      ; zero out the result
1BDC:011A F7C10100       TEST   CX,0001     ; are we odd
1BDC:011E 7402           JZ     0122       ; no skip the next instruction
1BDC:0120 01D8           ADD    AX,BX     ; we are odd so add to the result
1BDC:0122 D1E3           SHL    BX,1      ; multiply by 2
1BDC:0124 D1E9           SHR    CX,1      ; divide by 2 (if zr flag is set, we are done)
1BDC:0126 75F2           JNZ    011A      ; cx not 0, go back and do it again
1BDC:0128 C3             RET              ; return with the result in AX
pretty small, just 24 bytes </lang>
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