Array length: Difference between revisions
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Element 1: apple |
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Element 2: orange</pre> |
Element 2: orange</pre> |
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=={{header|Ruby}}== |
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<lang ruby>puts ['apple', 'orange'].length # or .size</lang> |
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=={{header|SQL}}== |
=={{header|SQL}}== |
Revision as of 21:27, 27 September 2015
You are encouraged to solve this task according to the task description, using any language you may know.
Determine the amount of elements in an array.
As an example use an array holding the strings 'apple' and 'orange'.
- See also
ALGOL 68
<lang algol68># UPB returns the upper bound of an array, LWB the lower bound # []STRING fruits = ( "apple", "orange" ); print( ( ( UPB fruits - LWB fruits ) + 1, newline ) ) # prints 2 #</lang>
EchoLisp
<lang scheme> (length '("apple" "orange")) ;; list
→ 2
(vector-length #("apple" "orange")) ;; vector
→ 2
</lang>
Haskell
<lang Haskell>-- Char -> Int length ["apple", "orange"]</lang>
JavaScript
<lang javascript>console.log(['apple', 'orange'].length);</lang>
ooRexx
<lang oorexx> /* REXX */ a = .array~of('apple','orange') say a~size 'elements' Do e over a
say e End
Say "a[2]="a[2]</lang>
- Output:
2 elements apple orange a[2]=orange
PHP
<lang php>print count(['apple', 'orange']); // Returns 2</lang>
Python
<lang python>>>> print(len(['apple', 'orange'])) 2 >>> </lang>
REXX
<lang rexx>/* REXX ----------------------------------------------
- The compond variable a. implements an array
- By convention, a.0 contains the number of elements
- ---------------------------------------------------*/
a.=0 /* initialize the "array" */ call store 'apple' Call store 'orange' Say 'There are' a.0 'elements in the array:' Do i=1 To a.0
Say 'Element' i':' a.i End
Exit store: Procedure Expose a. z=a.0+1 a.z=arg(1) a.0=z Return</lang>
- Output:
There are 2 elements in the array: Element 1: apple Element 2: orange
Ruby
<lang ruby>puts ['apple', 'orange'].length # or .size</lang>
SQL
<lang sql>SELECT COUNT() FROM (VALUES ('apple'),('orange'));</lang>
zkl
zkl doesn't support arrays natively, use lists instead. <lang zkl>List("apple", "orange").len().println() //-->2, == L("apple", "orange") T("apple", "orange").len().println() //-->2, read only list (ROList) </lang>