Sorting algorithms/Strand sort

From Rosetta Code
Task
Sorting algorithms/Strand sort
You are encouraged to solve this task according to the task description, using any language you may know.
This page uses content from Wikipedia. The original article was at Strand sort. The list of authors can be seen in the page history. As with Rosetta Code, the text of Wikipedia is available under the GNU FDL. (See links for details on variance)


Task

Implement the Strand sort.

This is a way of sorting numbers by extracting shorter sequences of already sorted numbers from an unsorted list.

AutoHotkey

Works with: AutoHotkey_L

<lang AutoHotkey>string = ( -2 0 -2 5 5 3 -1 -3 5 5 0 2 -4 4 2 ) string2 := string Loop { loop, parse, string, %A_space% { list := 1 = A_index ? A_loopfield : list StringSplit, k, list, %A_space%

if ( k%k0% <= A_loopfield ) && ( l != "" ) && ( A_index != 1 ) list := list . " " . A_loopfield

if ( k%k0% > A_loopfield ) list := A_loopfield . " " . list , index++ l := A_loopfield } if ( index = 0 ) { MsgBox % "unsorted:" string2 "`n Sorted:" list exitapp } string := list, list = "", index := 0 } esc::ExitApp</lang>outout<lang> unsorted:-2 0 -2 5 5 3 -1 -3 5 5 0 2 -4 4 2

 Sorted:-4 -3 -2 -2 -1 0 0 2 2 3 4 5 5 5 5</lang>

C

Strand sort using singly linked list. C99, compiled with gcc -std=c99 <lang C>#include <stdio.h>

typedef struct node_t *node, node_t; struct node_t { int v; node next; }; typedef struct { node head, tail; } slist;

void push(slist *l, node e) { if (!l->head) l->head = e; if (l->tail) l->tail->next = e; l->tail = e; }

node removehead(slist *l) { node e = l->head; if (e) { l->head = e->next; e->next = 0; } return e; }

void join(slist *a, slist *b) { push(a, b->head); a->tail = b->tail; }

void merge(slist *a, slist *b) { slist r = {0}; while (a->head && b->head) push(&r, removehead(a->head->v <= b->head->v ? a : b));

join(&r, a->head ? a : b); *a = r; b->head = b->tail = 0; }

void sort(int *ar, int len) { node_t all[len];

// array to list for (int i = 0; i < len; i++) all[i].v = ar[i], all[i].next = i < len - 1 ? all + i + 1 : 0;

slist list = {all, all + len - 1}, rem, strand = {0}, res = {0};

for (node e = 0; list.head; list = rem) { rem.head = rem.tail = 0; while ((e = removehead(&list))) push((!strand.head || e->v >= strand.tail->v) ? &strand : &rem, e);

merge(&res, &strand); }

// list to array for (int i = 0; res.head; i++, res.head = res.head->next) ar[i] = res.head->v; }

void show(const char *title, int *x, int len) { printf("%s ", title); for (int i = 0; i < len; i++) printf("%3d ", x[i]); putchar('\n'); }

int main(void) { int x[] = {-2,0,-2,5,5,3,-1,-3,5,5,0,2,-4,4,2};

  1. define SIZE sizeof(x)/sizeof(int)

show("before sort:", x, SIZE); sort(x, sizeof(x)/sizeof(int)); show("after sort: ", x, SIZE);

return 0; }</lang>outout<lang>before sort: -2 0 -2 5 5 3 -1 -3 5 5 0 2 -4 4 2 after sort: -4 -3 -2 -2 -1 0 0 2 2 3 4 5 5 5 5</lang>

C++

<lang cpp>#include <list>

template <typename T> std::list<T> strandSort(std::list<T> lst) {

 if (lst.size() <= 1)
   return lst;
 std::list<T> result;
 std::list<T> sorted;
 while (!lst.empty()) {
   sorted.push_back(lst.front());
   lst.pop_front();
   for (typename std::list<T>::iterator it = lst.begin(); it != lst.end(); ) {
     if (sorted.back() <= *it) {
       sorted.push_back(*it);
       it = lst.erase(it);
     } else
       it++;
   }
   result.merge(sorted);
 }
 return result;

}</lang>

Clojure

<lang Clojure>(ns rosettacode.strand-sort)

(defn merge-join

 "Produces a globally sorted seq from two sorted seqables"
 [[a & la :as all] [b & lb :as bll]]
 (cond (nil? a) bll
       (nil? b) all
       (< a b) (cons a (lazy-seq (merge-join la bll)))
       true    (cons b (lazy-seq (merge-join all lb)))))

(defn unbraid

 "Separates a sorted list from a sequence"
 [u]
 (when (seq u)
   (loop [[x & xs] u
          u []
          s []
          e x]
     (if (nil? x)
       [s u]
       (if (>= x e)
         (recur xs u (conj s x) x)
         (recur xs (conj u x) s e))))))

(defn strand-sort

 "http://en.wikipedia.org/wiki/Strand_sort"
 [s]
 (loop [[s u] (unbraid s)
        m nil]
   (if s
     (recur (unbraid u) (merge-join m s))
     m)))

(strand-sort [1, 6, 3, 2, 1, 7, 5, 3])

=> (1 1 2 3 3 5 6 7)

</lang>

CMake

Only for lists of integers. <lang cmake># strand_sort(<output variable> [<value>...]) sorts a list of integers. function(strand_sort var)

 # Strand sort moves elements from _ARGN_ to _answer_.
 set(answer)                   # answer: a sorted list
 while(DEFINED ARGN)
   # Split _ARGN_ into two lists, _accept_ and _reject_.
   set(accept)                 # accept: elements in sorted order
   set(reject)                 # reject: all other elements
   set(p)
   foreach(e ${ARGN})
     if(DEFINED p AND p GREATER ${e})
       list(APPEND reject ${e})
     else()
       list(APPEND accept ${e})
       set(p ${e})
     endif()
   endforeach(e)
   # Prepare to merge _accept_ into _answer_. First, convert both lists
   # into arrays, for better indexing: set(e ${answer${i}}) is faster
   # than list(GET answer ${i} e).
   set(la 0)
   foreach(e ${answer})
     math(EXPR la "${la} + 1")
     set(answer${la} ${e})
   endforeach(e)
   set(lb 0)
   foreach(e ${accept})
     math(EXPR lb "${lb} + 1")
     set(accept${lb} ${e})
   endforeach(e)
   # Merge _accept_ into _answer_.
   set(answer)
   set(ia 1)
   set(ib 1)
   while(NOT ia GREATER ${la})         # Iterate elements of _answer_.
     set(ea ${answer${ia}})
     while(NOT ib GREATER ${lb})       # Take elements from _accept_,
       set(eb ${accept${ib}})          #   while they are less than
       if(eb LESS ${ea})               #   next element of _answer_.
         list(APPEND answer ${eb})
         math(EXPR ib "${ib} + 1")
       else()
         break()
       endif()
     endwhile()
     list(APPEND answer ${ea})         # Take next from _answer_.
     math(EXPR ia "${ia} + 1")
   endwhile()
   while(NOT ib GREATER ${lb})         # Take rest of _accept_.
     list(APPEND answer ${accept${ib}})
     math(EXPR ib "${ib} + 1")
   endwhile()
   # This _reject_ becomes next _ARGN_. If _reject_ is empty, then
   # set(ARGN) undefines _ARGN_, breaking the loop.
   set(ARGN ${reject})
 endwhile(DEFINED ARGN)
 set("${var}" ${answer} PARENT_SCOPE)

endfunction(strand_sort)</lang>

<lang cmake>strand_sort(result 11 55 55 44 11 33 33 44 22 22) message(STATUS "${result}") # -- 11;11;22;22;33;33;44;44;55;55</lang>

Common Lisp

<lang lisp>(defun strand-sort (l cmp)

 (if l
   (let* ((l (reverse l))    

(o (list (car l))) n)

     (loop for i in (cdr l) do

(push i (if (funcall cmp (car o) i) n o)))

     (merge 'list o (strand-sort n cmp) #'<))))

(let ((r (loop repeat 15 collect (random 10))))

 (print r)
 (print (strand-sort r #'<)))</lang>output<lang>(5 8 6 0 6 8 4 7 0 7 1 5 3 3 6) 

(0 0 1 3 3 4 5 5 6 6 6 7 7 8 8)</lang>

D

Using doubly linked lists

<lang d>import std.stdio, std.container;

DList!T strandSort(T)(DList!T list) {

   static DList!T merge(DList!T left, DList!T right) {
       DList!T result;
       while (!left.empty && !right.empty) {
           if (left.front <= right.front) {
               result.insertBack(left.front);
               left.removeFront();
           } else {
               result.insertBack(right.front);
               right.removeFront();
           }
       }
       result.insertBack(left[]);
       result.insertBack(right[]);
       return result;
   }
   DList!T result, sorted, leftover;
   while (!list.empty) {
       leftover.clear();
       sorted.clear();
       sorted.insertBack(list.front);
       list.removeFront();
       foreach (item; list) {
           if (sorted.back <= item)
               sorted.insertBack(item);
           else
               leftover.insertBack(item);
       }
       result = merge(sorted, result);
       list = leftover;
   }
   return result;

}

void main() {

   auto lst = DList!int([-2,0,-2,5,5,3,-1,-3,5,5,0,2,-4,4,2]);
   foreach (e; strandSort(lst))
       write(e, " ");

}</lang>

Output:
-4 -3 -2 -2 -1 0 0 2 2 3 4 5 5 5 5 

Faster version using slices

<lang d>import std.stdio, std.array;

T[] strandSort(T)(const(T)[] list) pure nothrow {

   static T[] merge(const(T)[] left, const(T)[] right) pure nothrow {
       T[] res;
       while (!left.empty && !right.empty) {
           if (left.front <= right.front) {
               res ~= left.front;
               left.popFront;
           } else {
               res ~= right.front;
               right.popFront;
           }
       }
       return res ~ left ~ right;
   }
   T[] result;
   while (!list.empty) {
       auto sorted = list[0 .. 1];
       list.popFront;
       typeof(sorted) leftover;
       foreach (const item; list)
           (sorted.back <= item ? sorted : leftover) ~= item;
       result = merge(sorted, result);
       list = leftover;
   }
   return result;

}

void main() {

   const arr = [-2, 0, -2, 5, 5, 3, -1, -3, 5, 5, 0, 2, -4, 4, 2];
   arr.strandSort.writeln;

}</lang>

Output:
[-4, -3, -2, -2, -1, 0, 0, 2, 2, 3, 4, 5, 5, 5, 5]

Elixir

Translation of: Ruby

<lang elixir>defmodule Sort do

 def strand_sort(args), do: strand_sort(args, [])
 
 defp strand_sort([], result), do: result
 defp strand_sort(a, result) do
   {_, sublist, b} = Enum.reduce(a, {hd(a),[],[]}, fn val,{v,l1,l2} ->
                       if v <= val, do: {val, [val | l1], l2},
                                  else: {v,   l1, [val | l2]}
                     end)
   strand_sort(b, :lists.merge(Enum.reverse(sublist), result))
 end

end

IO.inspect Sort.strand_sort [7, 17, 6, 20, 20, 12, 1, 1, 9]</lang>

Output:
[1, 1, 6, 7, 9, 12, 17, 20, 20]

Euphoria

<lang euphoria>function merge(sequence left, sequence right)

   sequence result
   result = {}
   while length(left) > 0 and length(right) > 0 do
       if left[$] <= right[1] then
           exit
       elsif right[$] <= left[1] then
           return result & right & left
       elsif left[1] < right[1] then
           result = append(result,left[1])
           left = left[2..$]
       else
           result = append(result,right[1])
           right = right[2..$]
       end if
   end while
   return result & left & right

end function

function strand_sort(sequence s)

   integer j
   sequence result
   result = {}
   while length(s) > 0 do
       j = length(s)
       for i = 1 to length(s)-1 do
           if s[i] > s[i+1] then
               j = i
               exit
           end if
       end for
       
       result = merge(result,s[1..j])
       s = s[j+1..$]
   end while
   return result

end function

constant s = rand(repeat(1000,10)) puts(1,"Before: ") ? s puts(1,"After: ") ? strand_sort(s)</lang>

Output:

Before: {551,746,940,903,51,18,346,417,340,502}
After:  {18,51,340,346,417,502,551,746,903,940}

Go

<lang go>package main

import "fmt"

type link struct {

   int
   next *link

}

func linkInts(s []int) *link {

   if len(s) == 0 {
       return nil
   }
   return &link{s[0], linkInts(s[1:])}

}

func (l *link) String() string {

   if l == nil {
       return "nil"
   }
   r := fmt.Sprintf("[%d", l.int)
   for l = l.next; l != nil; l = l.next {
       r = fmt.Sprintf("%s %d", r, l.int)
   }
   return r + "]"

}

func main() {

   a := linkInts([]int{170, 45, 75, -90, -802, 24, 2, 66})
   fmt.Println("before:", a)
   b := strandSort(a)
   fmt.Println("after: ", b)

}

func strandSort(a *link) (result *link) {

   for a != nil {
       // build sublist
       sublist := a
       a = a.next
       sTail := sublist
       for p, pPrev := a, a; p != nil; p = p.next {
           if p.int > sTail.int {
               // append to sublist
               sTail.next = p
               sTail = p
               // remove from a
               if p == a {
                   a = p.next
               } else {
                   pPrev.next = p.next
               }
           } else {
               pPrev = p
           }
       }
       sTail.next = nil // terminate sublist
       if result == nil {
           result = sublist
           continue
       }
       // merge
       var m, rr *link
       if sublist.int < result.int {
           m = sublist
           sublist = m.next
           rr = result
       } else {
           m = result
           rr = m.next
       }
       result = m
       for {
           if sublist == nil {
               m.next = rr
               break
           }
           if rr == nil {
               m.next = sublist
               break
           }
           if sublist.int < rr.int {
               m.next = sublist
               m = sublist
               sublist = m.next
           } else {
               m.next = rr
               m = rr
               rr = m.next
           }
       }
   }
   return

}</lang> Output:

before: [170 45 75 -90 -802 24 2 66]
after:  [-802 -90 2 24 45 66 75 170]

Haskell

<lang haskell>-- Same merge as in Merge Sort merge :: (Ord a) => [a] -> [a] -> [a] merge [] ys = ys merge xs [] = xs merge (x : xs) (y : ys) | x <= y = x : merge xs (y : ys) | otherwise = y : merge (x : xs) ys

strandSort :: (Ord a) => [a] -> [a] strandSort [] = [] strandSort (x : xs) = merge strand (strandSort rest) where (strand, rest) = extractStrand x xs extractStrand x [] = ([x], []) extractStrand x (x1 : xs) | x <= x1 = let (strand, rest) = extractStrand x1 xs in (x : strand, rest) | otherwise = let (strand, rest) = extractStrand x xs in (strand, x1 : rest)</lang>

J

Generally, this task should be accomplished in J using /:~. Here we take an approach that's more comparable with the other examples on this page.

Using merge defined at Sorting algorithms/Merge sort#J:

<lang j>strandSort=: (#~ merge $:^:(0<#)@(#~ -.)) (= >./\)</lang>

Example use:

<lang j> strandSort 3 1 5 4 2 1 2 3 4 5</lang>

Note: the order in which this J implementation processes the strands differs from the pseudocode currently at the wikipedia page on strand sort and matches the haskell implementation currently at the wikipedia page.

Also note that the individual strands can be seen by using ; instead of merge.

<lang j> ((#~ ; $:^:(0<#)@(#~ -.)) (= >./\)) 3 1 5 4 2 ┌───┬───┬─┬┐ │3 5│1 4│2││ └───┴───┴─┴┘

  ((#~ ; $:^:(0<#)@(#~ -.)) (= >./\)) 3 3 1 2 4 3 5 6

┌─────────┬─────┬┐ │3 3 4 5 6│1 2 3││ └─────────┴─────┴┘</lang>

Java

Works with: Java version 1.6+

<lang java5>import java.util.Arrays; import java.util.LinkedList;

public class Strand{ // note: the input list is destroyed public static <E extends Comparable<? super E>> LinkedList<E> strandSort(LinkedList<E> list){ if(list.size() <= 1) return list;

LinkedList<E> result = new LinkedList<E>(); while(list.size() > 0){ LinkedList<E> sorted = new LinkedList<E>(); sorted.add(list.removeFirst()); //same as remove() or remove(0) for(Iterator<E> it = list.iterator(); it.hasNext(); ){ E elem = it.next(); if(sorted.peekLast().compareTo(elem) <= 0){ sorted.addLast(elem); //same as add(elem) or add(0, elem) it.remove(); } } result = merge(sorted, result); } return result; }

private static <E extends Comparable<? super E>> LinkedList<E> merge(LinkedList<E> left, LinkedList<E> right){ LinkedList<E> result = new LinkedList<E>(); while(!left.isEmpty() && !right.isEmpty()){ //change the direction of this comparison to change the direction of the sort if(left.peek().compareTo(right.peek()) <= 0) result.add(left.remove()); else result.add(right.remove()); } result.addAll(left); result.addAll(right); return result; }

public static void main(String[] args){ System.out.println(strandSort(new LinkedList<Integer>(Arrays.asList(3,1,2,4,5)))); System.out.println(strandSort(new LinkedList<Integer>(Arrays.asList(3,3,1,2,4,5)))); System.out.println(strandSort(new LinkedList<Integer>(Arrays.asList(3,3,1,2,4,3,5,6)))); } }</lang> Output:

[1, 2, 3, 4, 5]
[1, 2, 3, 3, 4, 5]
[1, 2, 3, 3, 3, 4, 5, 6]

jq

Most of the implementation is the "merge" function for merging two arrays. Notice that the helper function, strand, is defined here as an inner function.<lang jq># merge input array with array x by comparing the heads of the arrays

  1. in turn; # if both arrays are sorted, the result will be sorted:

def merge(x):

 length as $length
 | (x|length) as $xl
 | if $length == 0 then x
   elif $xl == 0 then .
   else 
     . as $in
     | reduce range(0; $xl + $length) as $z
        # state [ix, xix, ans]
        ( [0, 0, []];
          if .[0] < $length and 
             ((.[1] < $xl and $in[.[0]] <= x[.[1]]) or .[1] == $xl)
          then [(.[0] + 1), .[1], (.[2] + [$in[.[0]]]) ]
          else [.[0], (.[1] + 1), (.[2] + [x[.[1]]]) ]
          end
        ) | .[2]
   end ;

def strand_sort:

 # The inner function emits [strand, remainder]
 def strand:
   if length <= 1 then .
   else 
     reduce .[] as $x 
     # state: [strand, remainder]
     ([ [], [] ];
      if ((.[0]|length) == 0) or .[0][-1] <= $x
      then [ (.[0] + [$x]), .[1] ]
      else [ .[0], (.[1] + [$x]) ]
      end )
   end ;
 if length <= 1 then .
 else strand as $s
   | ($s[0] | merge( $s[1] | strand_sort))
 end ;

</lang> Example:

[1,3,5,2,4,6] | strand_sort

Julia

Translation of: Python

<lang julia>function mergelist(a, b)

   out = Vector{Int}()
   while !isempty(a) && !isempty(b)
       if a[1] < b[1]
           push!(out, popfirst!(a))
       else
           push!(out, popfirst!(b))
       end
   end
   append!(out, a)
   append!(out, b)
   out

end

function strand(a)

   i, s = 1, [popfirst!(a)]
   while i < length(a) + 1
       if a[i] > s[end]
           append!(s, splice!(a, i))
       else
           i += 1
       end
   end
   s

end

strandsort(a) = (out = strand(a); while !isempty(a) out = mergelist(out, strand(a)) end; out)

println(strandsort([1, 6, 3, 2, 1, 7, 5, 3]))

</lang>

Output:

[1, 1, 2, 3, 3, 5, 6, 7]

Kotlin

Translation of: D

<lang scala>// version 1.1.2

fun <T : Comparable<T>> strandSort(l: List<T>): List<T> {

   fun merge(left: MutableList<T>, right: MutableList<T>): MutableList<T> {
       val res = mutableListOf<T>()
       while (!left.isEmpty() && !right.isEmpty()) {
           if (left[0] <= right[0]) {
               res.add(left[0])
               left.removeAt(0)
           }
           else {
               res.add(right[0])
               right.removeAt(0)
           }
       }
       res.addAll(left)
       res.addAll(right)
       return res
   }
   
   var list = l.toMutableList() 
   var result = mutableListOf<T>()
   while (!list.isEmpty()) {
       val sorted = mutableListOf(list[0])
       list.removeAt(0)
       val leftover = mutableListOf<T>()
       for (item in list) {
           if (sorted.last() <= item)
               sorted.add(item)
           else
               leftover.add(item)
       }
       result = merge(sorted, result)
       list = leftover  
   }
   return result

}

fun main(args: Array<String>) {

   val l = listOf(-2, 0, -2, 5, 5, 3, -1, -3, 5, 5, 0, 2, -4, 4, 2)
   println(strandSort(l))

}</lang>

Output:
[-4, -3, -2, -2, -1, 0, 0, 2, 2, 3, 4, 5, 5, 5, 5]

Mathematica

<lang Mathematica>StrandSort[ input_ ] := Module[ {results = {}, A = input}, While[Length@A > 0,

sublist = {A1}; A = A2;;All;
 For[i = 1, i < Length@A, i++,
  If[ Ai > Last@sublist, AppendTo[sublist, Ai]; A = Delete[A, i];]
 ];
results = #Ordering@#&@Join[sublist, results];];

results ]</lang> Example usage :

StrandSort[{2, 3, 7, 5, 1, 4, 7}]
{1, 2, 3, 4, 5, 7, 7}

MAXScript

<lang MAXScript>fn strandSort arr = ( arr = deepcopy arr local sub = #() local results = #() while arr.count > 0 do ( sub = #() append sub (amax arr) deleteitem arr (for i in 1 to arr.count where arr[i] == amax arr collect i)[1] local i = 1 while i <= arr.count do ( if arr[i] > sub[sub.count] do ( append sub arr[i] deleteitem arr i ) i += 1 ) results = join sub results ) return results

)</lang> Output: <lang MAXScript> a = for i in 1 to 20 collect random 1 40

  1. (19, 26, 14, 31, 11, 33, 2, 14, 32, 28, 12, 38, 2, 37, 27, 18, 31, 24, 39, 28)

strandSort a

  1. (2, 2, 11, 12, 14, 14, 18, 19, 24, 26, 27, 28, 28, 31, 31, 32, 33, 37, 38, 39)

</lang>

NetRexx

<lang NetRexx>/* NetRexx */ options replace format comments java crossref savelog symbols binary

import java.util.List

placesList = [String -

   "UK  London",     "US  New York",   "US  Boston",     "US  Washington" -
 , "UK  Washington", "US  Birmingham", "UK  Birmingham", "UK  Boston"     -

]

lists = [ -

   placesList -
 , strandSort(String[] Arrays.copyOf(placesList, placesList.length)) -

]

loop ln = 0 to lists.length - 1

 cl = lists[ln]
 loop ct = 0 to cl.length - 1
   say cl[ct]
   end ct
   say
 end ln

return

method strandSort(A = String[]) public constant binary returns String[]

 rl = String[A.length]
 al = List strandSort(Arrays.asList(A))
 al.toArray(rl)
 return rl

method strandSort(Alst = List) public constant binary returns ArrayList

 A = ArrayList(Alst)
 result = ArrayList()
 loop label A_ while A.size > 0
   sublist = ArrayList()
   sublist.add(A.get(0))
   A.remove(0)
   loop i_ = 0 while i_ < A.size - 1
     if (Comparable A.get(i_)).compareTo(Comparable sublist.get(sublist.size - 1)) > 0 then do
       sublist.add(A.get(i_))
       A.remove(i_)
       end
     end i_
     result = merge(result, sublist)
   end A_
 return result

method merge(left = List, right = List) public constant binary returns ArrayList

 result = ArrayList()
 loop label mx while left.size > 0 & right.size > 0
   if (Comparable left.get(0)).compareTo(Comparable right.get(0)) <= 0 then do
     result.add(left.get(0))
     left.remove(0)
     end
   else do
     result.add(right.get(0))
     right.remove(0)
     end
   end mx
   if left.size > 0 then do
     result.addAll(left)
     end
   if right.size > 0 then do
     result.addAll(right)
     end
 return result

</lang>

Output
UK  London
US  New York
US  Boston
US  Washington
UK  Washington
US  Birmingham
UK  Birmingham
UK  Boston

UK  Birmingham
UK  Boston
UK  London
UK  Washington
US  Birmingham
US  Boston
US  New York
US  Washington

Nim

<lang nim>proc mergeList[T](a, b: var seq[T]): seq[T] =

 result = @[]
 while a.len > 0 and b.len > 0:
   if a[0] < b[0]:
     result.add a[0]
     a.delete 0
   else:
     result.add b[0]
     b.delete 0
 result.add a
 result.add b

proc strand[T](a: var seq[T]): seq[T] =

 var i = 0
 result = @[a[0]]
 a.delete 0
 while i < a.len:
   if a[i] > result[result.high]:
     result.add a[i]
     a.delete i
   else:
     inc i

proc strandSort[T](a: seq[T]): seq[T] =

 var a = a
 result = a.strand
 while a.len > 0:
   var s = a.strand
   result = mergeList(result, s)

var a = @[1, 6, 3, 2, 1, 7, 5, 3] echo a.strandSort</lang> Output:

@[1, 1, 2, 3, 3, 5, 6, 7]

OCaml

Translation of: Haskell

<lang ocaml>let rec strand_sort (cmp : 'a -> 'a -> int) : 'a list -> 'a list = function

  []    -> []
| x::xs ->
  let rec extract_strand x = function
     [] -> [x], []
   | x1::xs when cmp x x1 <= 0 ->
     let strand, rest = extract_strand x1 xs in x::strand, rest
   | x1::xs ->
     let strand, rest = extract_strand x xs in strand, x1::rest
  in
  let strand, rest = extract_strand x xs in
  List.merge cmp strand (strand_sort cmp rest)</lang>

usage

# strand_sort compare [170; 45; 75; -90; -802; 24; 2; 66];;
- : int list = [-802; -90; 2; 24; 45; 66; 75; 170]

PARI/GP

<lang parigp>strandSort(v)={ my(sorted=[],unsorted=v,remaining,working); while(#unsorted, remaining=working=List(); listput(working, unsorted[1]); for(i=2,#unsorted, if(unsorted[i]<working[#working], listput(remaining, unsorted[i]) , listput(working, unsorted[i]) ) ); unsorted=Vec(remaining); sorted=merge(sorted, Vec(working)) ); sorted }; merge(u,v)={ my(ret=vector(#u+#v),i=1,j=1); for(k=1,#ret, if(i<=#u & (j>#v | u[i]<v[j]), ret[k]=u[i]; i++ , ret[k]=v[j]; j++ ) ); ret };</lang>

Pascal

<lang Pascal>program StrandSortDemo;

type

 TIntArray = array of integer;

function merge(left: TIntArray; right: TIntArray): TIntArray;

 var
   i, j, k: integer;
 begin
   setlength(merge, length(left) + length(right));
   i := low(merge);
   j := low(left);
   k := low(right);
   repeat
     if ((left[j] <= right[k]) and (j <= high(left))) or (k > high(right)) then
     begin
       merge[i] := left[j];
       inc(j);
     end
     else
     begin
       merge[i] := right[k];
       inc(k);
     end;
     inc(i);
   until i > high(merge);
 end;

function StrandSort(s: TIntArray): TIntArray;

 var
   strand: TIntArray;
   i, j: integer;
 begin
   setlength(StrandSort, length(s));
   setlength(strand, length(s));
   i := low(s);
   repeat
     StrandSort[i] := s[i];
     inc(i);
   until (s[i] < s[i-1]);
   setlength(StrandSort, i);
   repeat
     setlength(strand, 1);
     j := low(strand);
     strand[j] := s[i];
     while (s[i+1] > s[i]) and (i < high(s)) do
     begin
       inc(i);
       inc(j);

setlength(strand, length(strand) + 1);

       Strand[j] := s[i];
     end;
     StrandSort := merge(StrandSort, strand);
     inc(i);
   until (i > high(s));
 end;

var

 data: TIntArray;
 i: integer;

begin

 setlength(data, 8);
 Randomize;
 writeln('The data before sorting:');
 for i := low(data) to high(data) do
 begin
   data[i] := Random(high(data));
   write(data[i]:4);
 end;
 writeln;
 data := StrandSort(data);
 writeln('The data after sorting:');
 for i := low(data) to high(data) do
 begin
   write(data[i]:4);
 end;
 writeln;

end.</lang>

Perl

<lang Perl>use 5.10.0; # for given/when sub merge {

       my ($x, $y) = @_;
       my @out;
       while (@$x and @$y) {
               given ($x->[-1] <=> $y->[-1]) {
                       when( 1) { unshift @out, pop @$x }
                       when(-1) { unshift @out, pop @$y }
                       default  { splice @out, 0, 0, pop(@$x), pop(@$y) }
               }
       }
       return @$x, @$y, @out

}

sub strand {

       my $x = shift;
       my @out = shift @$x // return;
       if (@$x) {
               for (-@$x .. -1) {
                       if ($x->[$_] >= $out[-1]) {
                               push @out, splice @$x, $_, 1
                       }
               }
       }
       return @out

}

sub strand_sort {

       my @x = @_;
       my @out;
       while (my @strand = strand(\@x)) {
               @out = merge(\@out, \@strand)
       }
       @out

}

my @a = map (int rand(100), 1 .. 10); say "Before @a"; @a = strand_sort(@a); say "After @a";</lang>

Perl 6

Works with: Rakudo version 2018.04.01

<lang perl6>sub infix:<M> (@x-in, @y-in) {

   my @x = | @x-in;
   my @y = | @y-in;
   flat @x, @y,
       reverse gather while @x and @y {
           take do given @x[*-1] cmp @y[*-1] {
               when More { pop @x }
               when Less { pop @y }
               when Same { pop(@x), pop(@y) }
           }
       }

}

sub strand (@x) {

   my $i = 0;
   my $prev = -Inf;
   gather while $i < @x {
       @x[$i] before $prev ?? $i++ !! take $prev = splice(@x, $i, 1)[0];
   }

}

sub strand_sort (@x is copy) {

   my @out;
   @out M= strand(@x) while @x;
   @out;

}

my @a = (^100).roll(10); say "Before {@a}"; @a = strand_sort(@a); say "After {@a}";

@a = <The quick brown fox jumps over the lazy dog>; say "Before {@a}"; @a = strand_sort(@a); say "After {@a}";</lang>

Output:
Before 1 20 64 72 48 75 96 55 42 74
After  1 20 42 48 55 64 72 74 75 96
Before The quick brown fox jumps over the lazy dog
After  The brown dog fox jumps lazy over quick the

Phix

Copy of Euphoria <lang Phix>function merge(sequence left, sequence right) sequence result = {}

   while length(left)>0 and length(right)>0 do
       if left[$]<=right[1] then
           exit
       elsif right[$]<=left[1] then
           return result & right & left
       elsif left[1]<right[1] then
           result = append(result,left[1])
           left = left[2..$]
       else
           result = append(result,right[1])
           right = right[2..$]
       end if
   end while
   return result & left & right

end function

function strand_sort(sequence s) integer j sequence result = {}

   while length(s)>0 do
       j = length(s)
       for i=1 to length(s)-1 do
           if s[i]>s[i+1] then
               j = i
               exit
           end if
       end for
       result = merge(result,s[1..j])
       s = s[j+1..$]
   end while
   return result

end function</lang>

PHP

Translation of: D
Works with: PHP 5.3.0+

<lang php>$lst = new SplDoublyLinkedList(); foreach (array(1,20,64,72,48,75,96,55,42,74) as $v)

   $lst->push($v);

foreach (strandSort($lst) as $v)

   echo "$v ";

function strandSort(SplDoublyLinkedList $lst) {

   $result = new SplDoublyLinkedList();
   while (!$lst->isEmpty()) {
       $sorted = new SplDoublyLinkedList();
       $remain = new SplDoublyLinkedList();
       $sorted->push($lst->shift());
       foreach ($lst as $item) {
           if ($sorted->top() <= $item) {
               $sorted->push($item);
           } else {
               $remain->push($item);
           }
       }
       $result = _merge($sorted, $result);
       $lst = $remain;
   }
   return $result;

}

function _merge(SplDoublyLinkedList $left, SplDoublyLinkedList $right) {

   $res = new SplDoublyLinkedList();
   while (!$left->isEmpty() && !$right->isEmpty()) {
       if ($left->bottom() <= $right->bottom()) {
           $res->push($left->shift());
       } else {
           $res->push($right->shift());
       }
   }
   foreach ($left as $v)  $res->push($v);
   foreach ($right as $v) $res->push($v);
   return $res;

}</lang>

1 20 42 48 55 64 72 74 75 96

PicoLisp

<lang PicoLisp>(de strandSort (Lst)

  (let Res NIL  # Result list
     (while Lst
        (let Sub (circ (car Lst))  # Build sublist as fifo
           (setq
              Lst (filter
                 '((X)
                    (or
                       (> (car Sub) X)
                       (nil (fifo 'Sub X)) ) )
                 (cdr Lst) )
              Res (make
                 (while (or Res Sub)  # Merge
                    (link
                       (if2 Res Sub
                          (if (>= (car Res) (cadr Sub))
                             (fifo 'Sub)
                             (pop 'Res) )
                          (pop 'Res)
                          (fifo 'Sub) ) ) ) ) ) ) )
     Res ) )</lang>

Test:

: (strandSort (3 1 5 4 2))
-> (1 2 3 4 5)

: (strandSort (3 abc 1 (d e f) 5 T 4 NIL 2))
-> (NIL 1 2 3 4 5 abc (d e f) T)

PL/I

<lang PL/I>strand: procedure options (main); /* 27 Oct. 2012 */

  declare A(100) fixed, used(100) bit (1), sorted fixed controlled;
  declare (temp, work) fixed controlled;
  declare (i, j, k, n) fixed binary;
  n = hbound(A, 1);
  used = '1'b;
  A = random()*99;
  put edit (A) (f(3));
  do while (allocation(sorted) < n);
     call fetch (A, work);
     call move  (temp, work);
     call merge(sorted, temp); 
        /* Merges elements in SORTED with elements in TEMP. */
  end;
  /* Transfer the sorted elements to A. */
  do i = 1 to allocation(sorted);
     A(i) = sorted; free sorted;
  end;
  /* Print the sorted values. */
  put skip list ('The sorted values are:');
  put skip edit (A) (f(3));

/* Merges elements of SORTED with elements of TEMP and places */ /* the result in SORTED. */ /* Elements in SORTED and TEMP are in forward order. */ merge: procedure (sorted, temp);

  declare (sorted, temp) fixed controlled;
  declare work fixed controlled;
  declare (j_ok, k_ok) bit (1);
  do until ((k_ok | j_ok) = '0'b);
     k_ok = allocation(sorted) > 0;
     j_ok = allocation(temp)   > 0;
     if k_ok & j_ok then
        do; 
           if sorted <= temp then 
              do; allocate work; work = sorted; free sorted; end;
           else
              do; allocate work; work = temp; free temp; end;
        end;
     else
        if allocation(temp) = 0 then
            /* temp is empty; copy remainder of sorted into work */
           do while (allocation(sorted) > 0);
              allocate work; work = sorted; free sorted;
           end;
        else
           /* sorted is empty; copy remainder of temp onto work */
           do while (allocation(temp) > 0);
              allocate work; work = temp; free temp;
           end;
  end;
  call move (sorted, work); /* Move the values to SORTED. */

end merge;

/* Collect a thread of ascending values from aray A, and stack them in temp. */ /* Note: the values in temp are in reverse order. */ fetch: procedure (A, temp);

  declare A(*) fixed, temp controlled fixed;
  declare i fixed binary;
  
  do i = 1 to hbound(A,1); 
     if used(i) then
        do; allocate temp; temp = A(i); used(i) = '0'b; go to found; end;
  end;

found:

  do i = i+1 to hbound(A,1);
     if (temp <= A(i)) & used(i) then 
        do; allocate temp; temp = A(i); used(i) = '0'b; end;
  end;

end fetch;

/* Copy the stack at TEMP to the stack at SORTED. */ /* In TEMP, elements are in reverse order; */ /* in SORTED, elements are in forward order. */ move: procedure (sorted, temp);

  declare (sorted, temp) fixed controlled;
  do while (allocation(sorted) > 0); free sorted; end;
  do while (allocation (temp) > 0);
     allocate sorted; sorted = temp; free temp;
  end;

end move;

end strand;</lang> Generated data:

 43  5 79 16 90 48 29 73 29 19 77 59 49  2 54 35 39 71 25 76 34 48 31 91 28 13 23 70 27 59 96  7 63 82 59 81 28 96 34 43
 81 98 21 47 72 57 45 64 94 51 18 11 65 12 61 97 13 84 95 89 43  8 14 31 58 68 58 39 59 26 72 38 26 85 30 89 42 90 29 11
 14 63 97 60  1 17 45 42 62 29 45 15 69 11 29 25 11 48 92  3

Results:

The sorted values are: 
  1  2  3  5  7  8 11 11 11 11 12 13 13 14 14 15 16 17 18 19 21 23 25 25 26 26 27 28 28 29 29 29 29 29 30 31 31 34 34 35
 38 39 39 42 42 43 43 43 45 45 45 47 48 48 48 49 51 54 57 58 58 59 59 59 59 60 61 62 63 63 64 65 68 69 70 71 72 72 73 76
 77 79 81 81 82 84 85 89 89 90 90 91 92 94 95 96 96 97 97 98

PureBasic

<lang PureBasic>Procedure strandSort(List a())

 Protected NewList subList()
 Protected NewList results()
 
 While ListSize(a()) > 0
   ClearList(subList())
   AddElement(subList())
   FirstElement(a())
   subList() = a()
   DeleteElement(a())
   ForEach a()
     If a() >= subList()
       AddElement(subList())
       subList() = a()
       DeleteElement(a())
     EndIf
   Next
   
   ;merge lists
   FirstElement(subList())
   If Not FirstElement(results())
     ;copy all of sublist() to results()
     MergeLists(subList(), results(), #PB_List_Last)
   Else
     Repeat
       If subList() < results()
         InsertElement(results())
         results() = subList()
         DeleteElement(subList())
         If Not NextElement(subList())
           Break
         EndIf
       ElseIf Not NextElement(results())
         ;add remainder of sublist() to end of results()
         MergeLists(subList(), results(), #PB_List_Last)
         Break 
       EndIf
     ForEver
   EndIf 
   
 Wend 
 CopyList(results(), a())

EndProcedure

Procedure.s listContents(List a())

 Protected output.s
 PushListPosition(a())
 ForEach a()
   output + Str(a()) + ","
 Next
 PopListPosition(a())
 ProcedureReturn Left(output, Len(output) - 1)

EndProcedure

Procedure setupList(List a())

 ClearList(a())
 Protected elementCount, i
 
 elementCount = Random(5) + 10
 For i = 1 To elementCount
   AddElement(a())
   a() = Random(10) - 5
 Next

EndProcedure


If OpenConsole()

 NewList sample()
 Define i
 
 For i = 1 To 3
   setupList(sample())
   PrintN("List " + Str(i) + ":")
   PrintN("  Before:  " + listContents(sample()))
   strandSort(sample())
   PrintN("  After :  " + listContents(sample()))
   PrintN("")
 Next
 
 Print(#CRLF$ + #CRLF$ + "Press ENTER to exit"): Input()
 CloseConsole()

EndIf</lang> Sample output:

List 1:
  Before:  3,-2,-4,4,-1,-3,-2,-2,2,2,0
  After :  -4,-3,-2,-2,-2,-1,0,2,2,3,4

List 2:
  Before:  -4,4,3,-2,3,-2,5,0,-1,0,5,1
  After :  -4,-2,-2,-1,0,0,1,3,3,4,5,5

List 3:
  Before:  -2,0,-2,5,5,3,-1,-3,5,5,0,2,-4,4,2
  After :  -4,-3,-2,-2,-1,0,0,2,2,3,4,5,5,5,5

Python

<lang Python>def merge_list(a, b): out = [] while len(a) and len(b): if a[0] < b[0]: out.append(a.pop(0)) else: out.append(b.pop(0)) out += a out += b return out

def strand(a): i, s = 0, [a.pop(0)] while i < len(a): if a[i] > s[-1]: s.append(a.pop(i)) else: i += 1 return s

def strand_sort(a): out = strand(a) while len(a): out = merge_list(out, strand(a)) return out

print strand_sort([1, 6, 3, 2, 1, 7, 5, 3])</lang> Output:<lang>[1, 1, 2, 3, 3, 5, 6, 7]</lang>

Racket

<lang racket>

  1. lang racket

(require mzlib/list) (define (merge xs ys) (merge-sorted-lists xs ys <=))

(define (strand-sort xs)

 (let loop ([xs xs] [ys '[]])
   (cond [(empty? xs) ys]
         [else (define-values (sorted unsorted) (extract-strand xs))
               (loop unsorted (merge sorted ys))])))

(define (extract-strand xs)

 (for/fold ([strand '()] [unsorted '[]]) ([x xs])
   (if (or (empty? strand) (< x (first strand)))
       (values (cons x strand) unsorted)
       (values strand (cons x unsorted)))))        

(strand-sort (build-list 10 (λ(_) (random 15)))) </lang>

REXX

This REXX program was written to generate a specified amount of random numbers as well as allowing a pre-pended list of numbers).

It can handle integers, floating point numbers, exponentiated numbers, and/or character strings. <lang rexx>/*REXX program sorts a random list of words (or numbers) using the strand sort algorithm*/ parse arg size minv maxv old /*obtain optional arguments from the CL*/ if size== | size=="," then size=20 /*Not specified? Then use the default.*/ if minv== | minv=="," then minv= 0 /*Not specified? Then use the default.*/ if maxv== | maxv=="," then maxv=size /*Not specified? Then use the default.*/

              do i=1  for size                  /*generate a list of random numbers.   */
              old=old  random(0,maxv-minv)+minv /*append a random number to a list.    */
              end  /*i*/

old=space(old) /*elide extraneous blanks from the list*/

         say center('unsorted list', length(old), "─");         say old

new=strand_sort(old) /*sort the list of the random numbers. */ say; say center('sorted list' , length(new), "─"); say new exit /*stick a fork in it, we're all done. */ /*──────────────────────────────────────────────────────────────────────────────────────*/ strand_sort: procedure; parse arg x; y=

                         do  while words(x)\==0;          w=words(x)
                                do j=1  for w-1                /*anything out of order?*/
                                if word(x,j)>word(x,j+1)  then do;  w=j;  leave;  end
                                end   /*j*/
                         y=merge(y,subword(x,1,w));       x=subword(x,w+1)
                         end            /*while*/
            return y

/*──────────────────────────────────────────────────────────────────────────────────────*/ merge: procedure; parse arg a.1,a.2; p=

                  do forever;  w1=words(a.1);  w2=words(a.2)   /*do while 2 lists exist*/
                  if w1==0 | if w2==0              then leave  /*Any list empty?  Stop.*/
                  if word(a.1,w1)  <= word(a.2,1)  then leave  /*lists are now sorted? */
                  if word(a.2,w2)  <= word(a.1,1)  then return space(p a.2 a.1)
                  #=1+(word(a.1,1) >= word(a.2,1));  p=p word(a.#,1);  a.#=subword(a.#,2)
                  end   /*forever*/
            return space(p a.1 a.2)</lang>

output   when using the input of:   25 -9 30 1000 2000 3000

────────────────────────────────unsorted list────────────────────────────────
1000 2000 3000 9 0 3 -8 17 8 -2 4 0 -3 19 -1 3 1 8 27 14 20 2 -6 23 1 -8 -4 4

─────────────────────────────────sorted list─────────────────────────────────
-8 -8 -6 -4 -3 -2 -1 0 0 1 1 2 3 3 4 4 8 8 9 14 17 19 20 23 27 1000 2000 3000

The REXX program can also sort words as well as numbers.

output   when using the input of:   24 -9 100 66 66 8.8 carp Carp

──────────────────────────────────────unsorted list───────────────────────────────────────
66 66 8.8 carp Carp 20 77 88 9 39 -5 10 12 80 87 26 61 87 94 73 27 49 35 95 81 76 40 13 72

───────────────────────────────────────sorted list────────────────────────────────────────
-5 8.8 9 10 12 13 20 26 27 35 39 40 49 61 66 66 72 73 76 77 80 81 87 87 88 94 95 Carp carp

Note that an   ASCII   computer will sort words differently than an   EBCDIC   machine.

The order of sorting on an   ASCII   machine is:   numbers, upperCase, lowerCase
The order of sorting on an EBCDIC machine is:   lowerCase, upperCase, numbers

Ring

<lang ring>

  1. Project : Sorting algorithms/Strand sort

test = [-2,0,-2,5,5,3,-1,-3,5,5,0,2,-4,4,2] results = [] resultsend = [] see "before sort:" + nl showarray(test) test = strandsort(test) see "after sort:" + nl showarray(test)

func strandsort(a)

       while len(a) > 0
                sublist = []
                add(sublist,a[1])
                del(a,1)
                for i = 1 to len(a)
                    if a[i] > sublist[len(sublist)] 
                      add(sublist,a[i])
                      del(a,i)
                    ok
               next
               for n = 1 to len(sublist)
                    add(results,sublist[n])
               next 
               for n = 1 to len(results)
                    for m = n + 1 to len(results)  
                         if results[m] < results[n]
                            temp = results[m]
                            results[m] = results[n]
                            results[n] = temp
                         ok 
                    next
               next                      
       end 
       return results

func showarray(vect)

       svect = ""
       for n = 1 to len(vect)
             svect = svect + vect[n] + " "
       next
       svect = left(svect, len(svect) - 1)
       see svect + nl

</lang> Output:

before sort:
-2 0 -2 5 5 3 -1 -3 5 5 0 2 -4 4 2
after sort:
-4 -3 -2 -2 -1 0 0 2 2 3 4 5 5 5 5

Ruby

<lang ruby>class Array

 def strandsort
   a = dup
   result = []
   until a.empty?
     v = a.first
     sublist, a = a.partition{|val| v=val if v<=val}   # In case of v>val, it becomes nil.
     
     result.each_index do |idx|
       break if sublist.empty?
       result.insert(idx, sublist.shift) if sublist.first < result[idx]
     end
     result += sublist
   end
   result
 end
 
 def strandsort!
   replace(strandsort)
 end

end

p [1, 6, 3, 2, 1, 7, 5, 3].strandsort</lang>

Output:
[1, 1, 2, 3, 3, 5, 6, 7]

Sidef

Translation of: Perl

<lang ruby>func merge(x, y) {

   var out = [];
   while (x && y) {
       given (x[-1] <=> y[-1]) {
           when ( 1) { out.prepend(x.pop) }
           when (-1) { out.prepend(y.pop) }
           default   { out.prepend(x.pop, y.pop) }
       }
   }
   x + y + out;

}

func strand(x) {

   x || return [];
   var out = [x.shift];
   if (x.len) {
       for i in (-x.len .. -1) {
           if (x[i] >= out[-1]) {
               out.append(x.pop_at(i));
           }
       }
   }
   return out;

}

func strand_sort(x) {

   var out = [];
   while (var strd = strand(x)) {
       out = merge(out, strd);
   }
   return out;

}

var a = 10.of { 100.irand }; say "Before: #{a}"; say "After: #{strand_sort(a)}";</lang>

Output:
Before: 24 62 29 95 11 21 46 3 23 20
After: 3 11 20 21 23 24 29 46 62 95

Tcl

<lang tcl>proc merge {listVar toMerge} {

   upvar 1 $listVar v
   set i [set j 0]
   set out {}
   while {$i<[llength $v] && $j<[llength $toMerge]} {

if {[set a [lindex $v $i]] < [set b [lindex $toMerge $j]]} { lappend out $a incr i } else { lappend out $b incr j }

   }
   # Done the merge, but will be one source with something left
   # This will handle all that by doing a merge of the remnants onto the end
   set v [concat $out [lrange $v $i end] [lrange $toMerge $j end]]
   return

}

proc strandSort A {

   set results {}
   while {[llength $A]} {

set sublist [lrange $A 0 0] # We build a list of items that weren't filtered rather than removing "in place" # because this fits better with the way Tcl values work (the underlying data # structure is an array, not a linked list). set newA {} foreach a [lrange $A 1 end] { if {$a > [lindex $sublist end]} { lappend sublist $a } else { lappend newA $a } } set A $newA merge results $sublist

   }
   return $results

}

puts [strandSort {3 1 5 4 2}]</lang>

Ursala

<lang Ursala>strand_sort "r" = # parameterized by a relational predicate "r"

@NiX -+

  :-0 ~&B^?a\~&Y@a "r"?abh/~&alh2faltPrXPRC ~&arh2falrtPXPRC,
  ~&r->l ^|rlPlCrrPX/~& @hNCNXtX ~&r->lbx "r"?rllPXh/~&llPrhPlrPCXrtPX ~&rhPllPClrPXrtPX+-</lang>

demonstration code:<lang Ursala>#cast %nL

x = (strand_sort nat-nleq) <3,1,5,4,2></lang>output:

<1,2,3,4,5>

zkl

<lang zkl>fcn strandSort(A){ //--> new list, A is cleared, should add A=A.copy()

  sublist:=List.createLong(A.len()); results:=List.createLong(A.len());
  while(A){
     sublist.clear(A.pop(0));
     foreach i in (A.len() - 1){

if(A[i]>sublist[-1]) sublist.append(A.pop(i));

     }
     results.merge(sublist);
  }
  results

}</lang> The createLong list method creates a new list with pre-allocated space <lang zkl>strandSort(L(3,1,5,4,2)).println(); strandSort("azbfe".split("")).println();</lang>

Output:
L(1,2,3,4,5)
L("a","b","e","f","z")