Zeckendorf arithmetic: Difference between revisions
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=={{header|Perl 6}}== |
=={{header|Perl 6}}== |
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This is a somewhat limited implementation of Zeckendorf arithmetic operators. They only handle positive integer values. There are no actual calculations, everything is done with string manipulations, so it doesn't matter what glyphs you use for 1 and 0. |
This is a somewhat limited implementation of Zeckendorf arithmetic operators. They only handle positive integer values. There are no actual calculations, everything is done with string manipulations, so it doesn't matter what glyphs you use for 1 and 0. |
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{{works with|rakudo|2015.09}} |
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Implemented arithmetic operators: |
Implemented arithmetic operators: |
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# post increment |
# post increment |
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sub postfix:<++z>($a is rw) { |
sub postfix:<++z>($a is rw) { |
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$a = ("$z0$z0"~$a).subst(/("$z0$z0")($z1+ %% $z0)?$/, |
$a = ("$z0$z0"~$a).subst(/("$z0$z0")($z1+ %% $z0)?$/, |
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-> $/ { "$z0$z1" ~ ($1 ?? $z0 x $1.chars !! '') }); |
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$a ~~ s/^$z0+//; |
$a ~~ s/^$z0+//; |
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$a |
$a |
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# post decrement |
# post decrement |
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sub postfix:<--z>($a is rw) { |
sub postfix:<--z>($a is rw) { |
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$a.=subst(/$z1($z0*)$/, |
$a.=subst(/$z1($z0*)$/, |
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-> $/ {$z0 ~ "$z1$z0" x $0.chars div 2 ~ $z1 x $0.chars mod 2}); |
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$a ~~ s/^$z0+(.+)$/$0/; |
$a ~~ s/^$z0+(.+)$/$0/; |
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$a |
$a |
Revision as of 13:51, 20 September 2015
You are encouraged to solve this task according to the task description, using any language you may know.
This task is a total immersion zeckendorf task; using decimal numbers will attract serious disapprobation.
The task is to implement addition, subtraction, multiplication, and division using Zeckendorf number representation. Optionally provide decrement, increment and comparitive operation functions.
- Addition
Like binary 1 + 1 = 10, note carry 1 left. There the similarity ends. 10 + 10 = 101, note carry 1 left and 1 right. 100 + 100 = 1001, note carry 1 left and 2 right, this is the general case.
Occurrences of 11 must be changed to 100. Occurrences of 111 may be changed from the right by replacing 11 with 100, or from the left converting 111 to 100 + 100;
- Subtraction
10 - 1 = 1. The general rule is borrow 1 right carry 1 left. eg:
abcde 10100 - 1000 _____ 100 borrow 1 from a leaves 100 + 100 add the carry _____ 1001
A larger example:
abcdef 100100 - 1000 ______ 1*0100 borrow 1 from b + 100 add the carry ______ 1*1001 Sadly we borrowed 1 from b which didn't have it to lend. So now b borrows from a: 1001 + 1000 add the carry ____ 10100
- Multiplication
Here you teach your computer its zeckendorf tables. eg. 101 * 1001:
a = 1 * 101 = 101 b = 10 * 101 = a + a = 10000 c = 100 * 101 = b + a = 10101 d = 1000 * 101 = c + b = 101010 1001 = d + a therefore 101 * 1001 = 101010 + 101 ______ 1000100
- Division
Lets try 1000101 divided by 101, so we can use the same table used for multiplication.
1000101 - 101010 subtract d (1000 * 101) _______ 1000 - 101 b and c are too large to subtract, so subtract a ____ 1 so 1000101 divided by 101 is d + a (1001) remainder 1
Efficient algorithms for Zeckendorf arithmetic is interesting. The sections on addition and subtraction are particularly relevant for this task.
C++
<lang cpp>// For a class N which implements Zeckendorf numbers: // I define an increment operation ++() // I define a comparison operation <=(other N) // I define an addition operation +=(other N) // I define a subtraction operation -=(other N) // Nigel Galloway October 28th., 2012
- include <iostream>
enum class zd {N00,N01,N10,N11}; class N { private:
int dVal = 0, dLen; void _a(int i) { for (;; i++) { if (dLen < i) dLen = i; switch ((zd)((dVal >> (i*2)) & 3)) { case zd::N00: case zd::N01: return; case zd::N10: if (((dVal >> ((i+1)*2)) & 1) != 1) return; dVal += (1 << (i*2+1)); return; case zd::N11: dVal &= ~(3 << (i*2)); _b((i+1)*2); }}} void _b(int pos) { if (pos == 0) {++*this; return;} if (((dVal >> pos) & 1) == 0) { dVal += 1 << pos; _a(pos/2); if (pos > 1) _a((pos/2)-1); } else { dVal &= ~(1 << pos); _b(pos + 1); _b(pos - ((pos > 1)? 2:1)); }} void _c(int pos) { if (((dVal >> pos) & 1) == 1) {dVal &= ~(1 << pos); return;} _c(pos + 1); if (pos > 0) _b(pos - 1); else ++*this; return; }
public:
N(char const* x = "0") { int i = 0, q = 1; for (; x[i] > 0; i++); for (dLen = --i/2; i >= 0; i--) {dVal+=(x[i]-48)*q; q*=2; }} const N& operator++() {dVal += 1; _a(0); return *this;} const N& operator+=(const N& other) { for (int GN = 0; GN < (other.dLen + 1) * 2; GN++) if ((other.dVal >> GN) & 1 == 1) _b(GN); return *this; } const N& operator-=(const N& other) { for (int GN = 0; GN < (other.dLen + 1) * 2; GN++) if ((other.dVal >> GN) & 1 == 1) _c(GN); for (;((dVal >> dLen*2) & 3) == 0 or dLen == 0; dLen--); return *this; } const N& operator*=(const N& other) { N Na = other, Nb = other, Nt, Nr; for (int i = 0; i <= (dLen + 1) * 2; i++) { if (((dVal >> i) & 1) > 0) Nr += Nb; Nt = Nb; Nb += Na; Na = Nt; } return *this = Nr; } const bool operator<=(const N& other) const {return dVal <= other.dVal;} friend std::ostream& operator<<(std::ostream&, const N&);
}; N operator "" N(char const* x) {return N(x);} std::ostream &operator<<(std::ostream &os, const N &G) {
const static std::string dig[] {"00","01","10"}, dig1[] {"","1","10"}; if (G.dVal == 0) return os << "0"; os << dig1[(G.dVal >> (G.dLen*2)) & 3]; for (int i = G.dLen-1; i >= 0; i--) os << dig[(G.dVal >> (i*2)) & 3]; return os;
} </lang>
Testing
The following tests addtition: <lang cpp>int main(void) {
N G; G = 10N; G += 10N; std::cout << G << std::endl; G += 10N; std::cout << G << std::endl; G += 1001N; std::cout << G << std::endl; G += 1000N; std::cout << G << std::endl; G += 10101N; std::cout << G << std::endl; return 0;
}</lang>
- Output:
101 1001 10101 100101 1010000
The following tests subtraction: <lang cpp>int main(void) {
N G; G = 1000N; G -= 101N; std::cout << G << std::endl; G = 10101010N; G -= 1010101N; std::cout << G << std::endl; return 0;
}</lang>
- Output:
1 1000000
The following tests multiplication: <lang cpp> int main(void) {
N G = 1001N; G *= 101N; std::cout << G << std::endl;
G = 101010N; G += 101N; std::cout << G << std::endl; return 0;
}</lang>
- Output:
1000100 1000100
Perl 6
This is a somewhat limited implementation of Zeckendorf arithmetic operators. They only handle positive integer values. There are no actual calculations, everything is done with string manipulations, so it doesn't matter what glyphs you use for 1 and 0.
Implemented arithmetic operators:
addition: +z subtraction: -z multiplication: *z division: /z (more of a divmod really) post increment: ++z post decrement: --z
Comparison operators:
equal eqz not equal nez greater than gtz less than ltz
<lang perl6> my $z1 = '1'; # glyph to use for a '1' my $z0 = '0'; # glyph to use for a '0'
sub zorder($a) { ($z0 lt $z1) ?? $a !! $a.trans([$z0, $z1] => [$z1, $z0]) };
- Zeckendorf comparison operators #########
- less than
sub infix:<ltz>($a, $b) { $a.&zorder lt $b.&zorder };
- greater than
sub infix:<gtz>($a, $b) { $a.&zorder gt $b.&zorder };
- equal
sub infix:<eqz>($a, $b) { $a eq $b };
- not equal
sub infix:<nez>($a, $b) { $a ne $b };
- Operators for Zeckendorf arithmetic ########
- post increment
sub postfix:<++z>($a is rw) {
$a = ("$z0$z0"~$a).subst(/("$z0$z0")($z1+ %% $z0)?$/, -> $/ { "$z0$z1" ~ ($1 ?? $z0 x $1.chars !! ) }); $a ~~ s/^$z0+//; $a
}
- post decrement
sub postfix:<--z>($a is rw) {
$a.=subst(/$z1($z0*)$/, -> $/ {$z0 ~ "$z1$z0" x $0.chars div 2 ~ $z1 x $0.chars mod 2}); $a ~~ s/^$z0+(.+)$/$0/; $a
}
- addition
sub infix:<+z>($a is copy, $b is copy) { $a++z while $b--z nez $z0; $a };
- subtraction
sub infix:<-z>($a is copy, $b is copy) { $a--z while $b--z nez $z0; $a };
- multiplication
sub infix:<*z>($a, $b) {
return $z0 if $a eqz $z0 or $b eqz $z0; return $a if $b eqz $z1; return $b if $a eqz $z1; my $c = $a; my $d = $z1; repeat { my $e = $z0; repeat { $c++z; $e++z } until $e eqz $a; $d++z; } until $d eqz $b; $c
};
- division (really more of a div mod)
sub infix:</z>($a is copy, $b is copy) {
fail "Divide by zero" if $b eqz $z0; return $a if $a eqz $z0 or $b eqz $z1; my $c = $z0; repeat { my $d = $b +z ($z1 ~ $z0); $c++z; $a--z while $d--z nez $z0 } until $a ltz $b; $c ~= " remainder $a" if $a nez $z0; $c
};
- Testing ######################
- helper sub to translate constants into the particular glyphs you used
sub z($a) { $a.trans([<1 0>] => [$z1, $z0]) };
say "Using the glyph '$z1' for 1 and '$z0' for 0\n";
my $fmt = "%-22s = %15s %s\n";
my $zeck = $z1;
printf( $fmt, "$zeck++z", $zeck++z, '# increment' ) for 1 .. 10;
printf $fmt, "$zeck +z {z('1010')}", $zeck +z= z('1010'), '# addition';
printf $fmt, "$zeck -z {z('100')}", $zeck -z= z('100'), '# subtraction';
printf $fmt, "$zeck *z {z('100101')}", $zeck *z= z('100101'), '# multiplication';
printf $fmt, "$zeck /z {z('100')}", $zeck /z= z('100'), '# division';
printf( $fmt, "$zeck--z", $zeck--z, '# decrement' ) for 1 .. 5;
printf $fmt, "$zeck *z {z('101001')}", $zeck *z= z('101001'), '# multiplication';
printf $fmt, "$zeck /z {z('100')}", $zeck /z= z('100'), '# division';</lang>
Testing Output
Using the glyph '1' for 1 and '0' for 0 1++z = 10 # increment 10++z = 100 # increment 100++z = 101 # increment 101++z = 1000 # increment 1000++z = 1001 # increment 1001++z = 1010 # increment 1010++z = 10000 # increment 10000++z = 10001 # increment 10001++z = 10010 # increment 10010++z = 10100 # increment 10100 +z 1010 = 100101 # addition 100101 -z 100 = 100010 # subtraction 100010 *z 100101 = 100001000001 # multiplication 100001000001 /z 100 = 101010001 # division 101010001--z = 101010000 # decrement 101010000--z = 101001010 # decrement 101001010--z = 101001001 # decrement 101001001--z = 101001000 # decrement 101001000--z = 101000101 # decrement 101000101 *z 101001 = 101010000010101 # multiplication 101010000010101 /z 100 = 1001010001001 remainder 10 # division
Output using 'X' for 1 and 'O' for 0:
Using the glyph 'X' for 1 and 'O' for 0 X++z = XO # increment XO++z = XOO # increment XOO++z = XOX # increment XOX++z = XOOO # increment XOOO++z = XOOX # increment XOOX++z = XOXO # increment XOXO++z = XOOOO # increment XOOOO++z = XOOOX # increment XOOOX++z = XOOXO # increment XOOXO++z = XOXOO # increment XOXOO +z XOXO = XOOXOX # addition XOOXOX -z XOO = XOOOXO # subtraction XOOOXO *z XOOXOX = XOOOOXOOOOOX # multiplication XOOOOXOOOOOX /z XOO = XOXOXOOOX # division XOXOXOOOX--z = XOXOXOOOO # decrement XOXOXOOOO--z = XOXOOXOXO # decrement XOXOOXOXO--z = XOXOOXOOX # decrement XOXOOXOOX--z = XOXOOXOOO # decrement XOXOOXOOO--z = XOXOOOXOX # decrement XOXOOOXOX *z XOXOOX = XOXOXOOOOOXOXOX # multiplication XOXOXOOOOOXOXOX /z XOO = XOOXOXOOOXOOX remainder XO # division
PicoLisp
<lang>(seed (in "/dev/urandom" (rd 8)))
(de unpad (Lst)
(while (=0 (car Lst)) (pop 'Lst) ) Lst )
(de numz (N)
(let Fibs (1 1) (while (>= N (+ (car Fibs) (cadr Fibs))) (push 'Fibs (+ (car Fibs) (cadr Fibs))) ) (make (for I (uniq Fibs) (if (> I N) (link 0) (link 1) (dec 'N I) ) ) ) ) )
(de znum (Lst)
(let Fibs (1 1) (do (dec (length Lst)) (push 'Fibs (+ (car Fibs) (cadr Fibs))) ) (sum '((X Y) (unless (=0 X) Y)) Lst (uniq Fibs) ) ) )
(de incz (Lst)
(addz Lst (1)) )
(de decz (Lst)
(subz Lst (1)) )
(de addz (Lst1 Lst2)
(let Max (max (length Lst1) (length Lst2)) (reorg (mapcar + (need Max Lst1 0) (need Max Lst2 0)) ) ) )
(de subz (Lst1 Lst2)
(use (@A @B) (let (Max (max (length Lst1) (length Lst2)) Lst (mapcar - (need Max Lst1 0) (need Max Lst2 0)) ) (loop (while (match '(@A 1 0 0 @B) Lst) (setq Lst (append @A (0 1 1) @B)) ) (while (match '(@A 1 -1 0 @B) Lst) (setq Lst (append @A (0 0 1) @B)) ) (while (match '(@A 1 -1 1 @B) Lst) (setq Lst (append @A (0 0 2) @B)) ) (while (match '(@A 1 0 -1 @B) Lst) (setq Lst (append @A (0 1 0) @B)) ) (while (match '(@A 2 0 0 @B) Lst) (setq Lst (append @A (1 1 1) @B)) ) (while (match '(@A 2 -1 0 @B) Lst) (setq Lst (append @A (1 0 1) @B)) ) (while (match '(@A 2 -1 1 @B) Lst) (setq Lst (append @A (1 0 2) @B)) ) (while (match '(@A 2 0 -1 @B) Lst) (setq Lst (append @A (1 1 0) @B)) ) (while (match '(@A 1 -1) Lst) (setq Lst (append @A (0 1))) ) (while (match '(@A 2 -1) Lst) (setq Lst (append @A (1 1))) ) (NIL (match '(@A -1 @B) Lst)) ) (reorg (unpad Lst)) ) ) )
(de mulz (Lst1 Lst2)
(let (Sums (list Lst1) Mulz (0)) (mapc '((X) (when (= 1 (car X)) (setq Mulz (addz (cdr X) Mulz)) ) Mulz ) (mapcar '((X) (cons X (push 'Sums (addz (car Sums) (cadr Sums))) ) ) (reverse Lst2) ) ) ) )
(de divz (Lst1 Lst2)
(let Q 0 (while (lez Lst2 Lst1) (setq Lst1 (subz Lst1 Lst2)) (setq Q (incz Q)) ) (list Q (or Lst1 (0))) ) )
(de reorg (Lst)
(use (@A @B) (let Lst (reverse Lst) (loop (while (match '(@A 1 1 @B) Lst) (if @B (inc (nth @B 1)) (setq @B (1)) ) (setq Lst (append @A (0 0) @B) ) ) (while (match '(@A 2 @B) Lst) (inc (if (cdr @A) (tail 2 @A) @A ) ) (if @B (inc (nth @B 1)) (setq @B (1)) ) (setq Lst (append @A (0) @B)) ) (NIL (or (match '(@A 1 1 @B) Lst) (match '(@A 2 @B) Lst) ) ) ) (reverse Lst) ) ) )
(de lez (Lst1 Lst2)
(let Max (max (length Lst1) (length Lst2)) (<= (need Max Lst1 0) (need Max Lst2 0)) ) )
(let (X 0 Y 0)
(do 1024 (setq X (rand 1 1024)) (setq Y (rand 1 1024)) (test (numz (+ X Y)) (addz (numz X) (numz Y))) (test (numz (* X Y)) (mulz (numz X) (numz Y))) (test (numz (+ X 1)) (incz (numz X))) )
(do 1024 (setq X (rand 129 1024)) (setq Y (rand 1 128)) (test (numz (- X Y)) (subz (numz X) (numz Y))) (test (numz (/ X Y)) (car (divz (numz X) (numz Y)))) (test (numz (% X Y)) (cadr (divz (numz X) (numz Y)))) (test (numz (- X 1)) (decz (numz X))) ) )
(bye)</lang>
Racket
This implementation only handles natural (non-negative numbers). The algorithms for addition and subtraction use the techniques explained in the paper "Efficient algorithms for Zeckendorf arithmetic" (http://arxiv.org/pdf/1207.4497.pdf).
<lang racket>#lang racket (require math)
(define sqrt5 (sqrt 5)) (define phi (* 0.5 (+ 1 sqrt5)))
- What is the nth fibonnaci number, shifted by 2 so that
- F(0) = 1, F(1) = 2, ...?
(define (F n)
(fibonacci (+ n 2)))
- What is the largest n such that F(n) <= m?
(define (F* m)
(let ([n (- (inexact->exact (round (/ (log (* m sqrt5)) (log phi)))) 2)]) (if (<= (F n) m) n (sub1 n))))
(define (zeck->natural z)
(for/sum ([i (reverse z)] [j (in-naturals)]) (* i (F j))))
(define (natural->zeck n)
(if (zero? n) null (for/list ([i (in-range (F* n) -1 -1)]) (let ([f (F i)]) (cond [(>= n f) (set! n (- n f)) 1] [else 0])))))
- Extend list to the right to a length of len with repeated padding elements
(define (pad lst len [padding 0])
(append lst (make-list (- len (length lst)) padding)))
- Strip padding elements from the left of the list
(define (unpad lst [padding 0])
(cond [(null? lst) lst] [(equal? (first lst) padding) (unpad (rest lst) padding)] [else lst]))
- Run a filter function across a window in a list from left to right
(define (left->right width fn)
(λ (lst) (let F ([a lst]) (if (< (length a) width) a (let ([f (fn (take a width))]) (cons (first f) (F (append (rest f) (drop a width)))))))))
- Run a function fn across a window in a list from right to left
(define (right->left width fn)
(λ (lst) (let F ([a lst]) (if (< (length a) width) a (let ([f (fn (take-right a width))]) (append (F (append (drop-right a width) (drop-right f 1))) (list (last f))))))))
- (a0 a1 a2 ... an) -> (a0 a1 a2 ... (fn ... an))
(define (replace-tail width fn)
(λ (lst) (append (drop-right lst width) (fn (take-right lst width)))))
(define (rule-a lst)
(match lst [(list 0 2 0 x) (list 1 0 0 (add1 x))] [(list 0 3 0 x) (list 1 1 0 (add1 x))] [(list 0 2 1 x) (list 1 1 0 x)] [(list 0 1 2 x) (list 1 0 1 x)] [else lst]))
(define (rule-a-tail lst)
(match lst [(list x 0 3 0) (list x 1 1 1)] [(list x 0 2 0) (list x 1 0 1)] [(list 0 1 2 0) (list 1 0 1 0)] [(list x y 0 3) (list x y 1 1)] [(list x y 0 2) (list x y 1 0)] [(list x 0 1 2) (list x 1 0 0)] [else lst]))
(define (rule-b lst)
(match lst [(list 0 1 1) (list 1 0 0)] [else lst]))
(define (rule-c lst)
(match lst [(list 1 0 0) (list 0 1 1)] [(list 1 -1 0) (list 0 0 1)] [(list 1 -1 1) (list 0 0 2)] [(list 1 0 -1) (list 0 1 0)] [(list 2 0 0) (list 1 1 1)] [(list 2 -1 0) (list 1 0 1)] [(list 2 -1 1) (list 1 0 2)] [(list 2 0 -1) (list 1 1 0)] [else lst]))
(define (zeck-combine op y z [f identity])
(let* ([bits (max (add1 (length y)) (add1 (length z)) 4)] [f0 (λ (x) (pad (reverse x) bits))] [f1 (left->right 4 rule-a)] [f2 (replace-tail 4 rule-a-tail)] [f3 (right->left 3 rule-b)] [f4 (left->right 3 rule-b)]) ((compose1 unpad f4 f3 f2 f1 f reverse) (map op (f0 y) (f0 z)))))
(define (zeck+ y z)
(zeck-combine + y z))
(define (zeck- y z)
(when (zeck< y z) (error (format "~a" `(zeck-: cannot subtract since ,y < ,z)))) (zeck-combine - y z (left->right 3 rule-c)))
(define (zeck* y z)
(define (M ry Zn Zn_1 [acc null]) (if (null? ry) acc (M (rest ry) (zeck+ Zn Zn_1) Zn (if (zero? (first ry)) acc (zeck+ acc Zn))))) (cond [(zeck< z y) (zeck* z y)] [(null? y) null] ; 0 * z -> 0 [else (M (reverse y) z z)]))
(define (zeck-quotient/remainder y z)
(define (M Zn acc) (if (zeck< y Zn) (drop-right acc 1) (M (zeck+ Zn (first acc)) (cons Zn acc)))) (define (D x m [acc null]) (if (null? m) (values (reverse acc) x) (let* ([v (first m)] [smaller (zeck< v x)] [bit (if smaller 1 0)] [x_ (if smaller (zeck- x v) x)]) (D x_ (rest m) (cons bit acc))))) (D y (M z (list z))))
(define (zeck-quotient y z)
(let-values ([(quotient _) (zeck-quotient/remainder y z)]) quotient))
(define (zeck-remainder y z)
(let-values ([(_ remainder) (zeck-quotient/remainder y z)]) remainder))
(define (zeck-add1 z)
(zeck+ z '(1)))
(define (zeck= y z)
(equal? (unpad y) (unpad z)))
(define (zeck< y z)
; Compare equal-length unpadded zecks (define (LT a b) (if (null? a) #f (let ([a0 (first a)] [b0 (first b)]) (if (= a0 b0) (LT (rest a) (rest b)) (= a0 0))))) (let* ([a (unpad y)] [len-a (length a)] [b (unpad z)] [len-b (length b)]) (cond [(< len-a len-b) #t] [(> len-a len-b) #f] [else (LT a b)])))
(define (zeck> y z)
(not (or (zeck= y z) (zeck< y z))))
- Examples
(define (example op-name op a b)
(let* ([y (natural->zeck a)] [z (natural->zeck b)] [x (op y z)] [c (zeck->natural x)]) (printf "~a ~a ~a = ~a ~a ~a = ~a = ~a\n" a op-name b y op-name z x c)))
(example '+ zeck+ 888 111) (example '- zeck- 888 111) (example '* zeck* 8 111) (example '/ zeck-quotient 9876 1000) (example '% zeck-remainder 9876 1000) </lang>
- Output:
888 + 111 = (1 0 1 0 0 0 1 0 0 1 0 1 0 0) + (1 0 0 1 0 0 0 0 0 1) = (1 0 0 0 0 0 0 0 0 0 1 0 1 0 1) = 999 888 - 111 = (1 0 1 0 0 0 1 0 0 1 0 1 0 0) - (1 0 0 1 0 0 0 0 0 1) = (1 0 0 1 0 0 0 1 0 0 0 0 1 0) = 777 8 * 111 = (1 0 0 0 0) * (1 0 0 1 0 0 0 0 0 1) = (1 0 1 0 0 0 1 0 0 1 0 1 0 0) = 888 9876 / 1000 = (1 0 1 0 0 0 1 0 1 0 0 0 0 0 0 1 0 0 1) / (1 0 0 0 0 0 0 0 0 1 0 0 0 0 0) = (1 0 0 0 1) = 9 9876 % 1000 = (1 0 1 0 0 0 1 0 1 0 0 0 0 0 0 1 0 0 1) % (1 0 0 0 0 0 0 0 0 1 0 0 0 0 0) = (1 0 1 0 0 0 0 1 0 1 0 1 0 1) = 876
Scala
The addition is an implementation of an algorithm suggested in http[:]//arxiv.org/pdf/1207.4497.pdf: Efficient Algorithms for Zeckendorf Arithmetic. <lang Scala>object ZA extends App {
import Stream._ import scala.collection.mutable.ListBuffer
object Z {
// only for comfort and result checking: val fibs: Stream[BigInt] = {def series(i:BigInt,j:BigInt):Stream[BigInt] = i #:: series(j,i+j); series(1,0).tail.tail.tail } val z2i: Z => BigInt = z => (z.z.abs.toString.map(_.asDigit).reverse.zipWithIndex.map{case (v,i)=>v*fibs(i)}:\BigInt(0))(_+_)*z.z.signum
var fmts = Map(Z("0")->List[Z](Z("0"))) //map of Fibonacci multiples table of divisors
// get multiply table from fmts def mt(z: Z): List[Z] = {fmts.getOrElse(z,Nil) match {case Nil => {val e = mwv(z); fmts=fmts+(z->e); e}; case l => l}} // multiply weight vector def mwv(z: Z): List[Z] = { val wv = new ListBuffer[Z]; wv += z; wv += (z+z) var zs = "11"; val upper = z.z.abs.toString while ((zs.size<upper.size)) {wv += (wv.toList.last + wv.toList.reverse.tail.head); zs = "1"+zs} wv.toList } // get division table (division weight vector) def dt(dd: Z, ds: Z): List[Z] = { val wv = new ListBuffer[Z]; mt(ds).copyToBuffer(wv) var zs = ds.z.abs.toString; val upper = dd.z.abs.toString while ((zs.size<upper.size)) {wv += (wv.toList.last + wv.toList.reverse.tail.head); zs = "1"+zs} wv.toList }
}
case class Z(var zs: String) {
import Z._ require ((zs.toSet--Set('-','0','1')==Set()) && (!zs.contains("11")))
var z: BigInt = BigInt(zs) override def toString = z+"Z(i:"+z2i(this)+")" def size = z.abs.toString.size
//--- fa(summand1.z,summand2.z) -------------------------- val fa: (BigInt,BigInt) => BigInt = (z1, z2) => { val v =z1.toString.map(_.asDigit).reverse.padTo(5,0).zipAll(z2.toString.map(_.asDigit).reverse, 0, 0) val arr1 = (v.map(p=>p._1+p._2):+0 reverse).toArray (0 to arr1.size-4) foreach {i=> //stage1 val a = arr1.slice(i,i+4).toList val b = (a:\"")(_+_) dropRight 1 val a1 = b match { case "020" => List(1,0,0, a(3)+1) case "030" => List(1,1,0, a(3)+1) case "021" => List(1,1,0, a(3)) case "012" => List(1,0,1, a(3)) case _ => a } 0 to 3 foreach {j=>arr1(j+i) = a1(j)} } val arr2 = (arr1:\"")(_+_) .replace("0120","1010").replace("030","111").replace("003","100").replace("020","101") .replace("003","100").replace("012","101").replace("021","110") .replace("02","10").replace("03","11") .reverse.toArray (0 to arr2.size-3) foreach {i=> //stage2, step1 val a = arr2.slice(i,i+3).toList val b = (a:\"")(_+_) val a1 = b match { case "110" => List('0','0','1') case _ => a } 0 to 2 foreach {j=>arr2(j+i) = a1(j)} } val arr3 = (arr2:\"")(_+_).concat("0").reverse.toArray (0 to arr3.size-3) foreach {i=> //stage2, step2 val a = arr3.slice(i,i+3).toList val b = (a:\"")(_+_) val a1 = b match { case "011" => List('1','0','0') case _ => a } 0 to 2 foreach {j=>arr3(j+i) = a1(j)} } BigInt((arr3:\"")(_+_)) }
//--- fs(minuend.z,subtrahend.z) ------------------------- val fs: (BigInt,BigInt) => BigInt = (min,sub) => { val zmvr = min.toString.map(_.asDigit).reverse val zsvr = sub.toString.map(_.asDigit).reverse.padTo(zmvr.size,0) val v = zmvr.zipAll(zsvr, 0, 0).reverse val last = v.size-1 val zma = zmvr.reverse.toArray; val zsa = zsvr.reverse.toArray for (i <- 0 to last reverse) { val e = zma(i)-zsa(i) if (e<0) { zma(i-1) = zma(i-1)-1 zma(i) = 0 val part = Z((((i to last).map(zma(_))):\"")(_+_)) val carry = Z(("1".padTo(last-i,"0"):\"")(_+_)) val sum = part + carry; val sums = sum.z.toString (1 to sum.size) foreach {j=>zma(last-sum.size+j)=sums(j-1).asDigit} if (zma(i-1)<0) { for (j <- 0 to i-1 reverse) { if (zma(j)<0) { zma(j-1) = zma(j-1)-1 zma(j) = 0 val part = Z((((j to last).map(zma(_))):\"")(_+_)) val carry = Z(("1".padTo(last-j,"0"):\"")(_+_)) val sum = part + carry; val sums = sum.z.toString (1 to sum.size) foreach {k=>zma(last-sum.size+k)=sums(k-1).asDigit} } } } } else zma(i) = e zsa(i) = 0 } BigInt((zma:\"")(_+_)) }
//--- fm(multiplicand.z,multplier.z) --------------------- val fm: (BigInt,BigInt) => BigInt = (mc, mp) => { val mct = mt(Z(mc.toString)) val mpxi = mp.toString.reverse.map(_.asDigit).zipWithIndex.filter(_._1 != 0).map(_._2) (mpxi:\Z("0"))((fi,sum)=>sum+mct(fi)).z }
//--- fd(dividend.z,divisor.z) --------------------------- val fd: (BigInt,BigInt) => BigInt = (dd, ds) => { val dst = dt(Z(dd.toString),Z(ds.toString)).reverse var diff = Z(dd.toString) val zd = ListBuffer[String]() (0 to dst.size-1) foreach {i=> if (dst(i)>diff) zd+="0" else {diff = diff-dst(i); zd+="1"} } BigInt(zd.mkString) } val fasig: (Z, Z) => Int = (z1, z2) => if (z1.z.abs>z2.z.abs) z1.z.signum else z2.z.signum val fssig: (Z, Z) => Int = (z1, z2) => if ((z1.z.abs>z2.z.abs && z1.z.signum>0)||(z1.z.abs<z2.z.abs && z1.z.signum<0)) 1 else -1
def +(that: Z): Z = if (this==Z("0")) that else if (that==Z("0")) this else if (this.z.signum == that.z.signum) Z((fa(this.z.abs.max(that.z.abs),this.z.abs.min(that.z.abs))*this.z.signum).toString) else if (this.z.abs == that.z.abs) Z("0") else Z((fs(this.z.abs.max(that.z.abs),this.z.abs.min(that.z.abs))*fasig(this, that)).toString)
def ++ : Z = {val za = this + Z("1"); this.zs = za.zs; this.z = za.z; this}
def -(that: Z): Z = if (this==Z("0")) Z((that.z*(-1)).toString) else if (that==Z("0")) this else if (this.z.signum != that.z.signum) Z((fa(this.z.abs.max(that.z.abs),this.z.abs.min(that.z.abs))*this.z.signum).toString) else if (this.z.abs == that.z.abs) Z("0") else Z((fs(this.z.abs.max(that.z.abs),this.z.abs.min(that.z.abs))*fssig(this, that)).toString)
def -- : Z = {val zs = this - Z("1"); this.zs = zs.zs; this.z = zs.z; this}
def * (that: Z): Z = if (this==Z("0")||that==Z("0")) Z("0") else if (this==Z("1")) that else if (that==Z("1")) this else Z((fm(this.z.abs.max(that.z.abs),this.z.abs.min(that.z.abs))*this.z.signum*that.z.signum).toString)
def / (that: Z): Option[Z] = if (that==Z("0")) None else if (this==Z("0")) Some(Z("0")) else if (that==Z("1")) Some(Z("1")) else if (this.z.abs < that.z.abs) Some(Z("0")) else if (this.z == that.z) Some(Z("1")) else Some(Z((fd(this.z.abs.max(that.z.abs),this.z.abs.min(that.z.abs))*this.z.signum*that.z.signum).toString))
def % (that: Z): Option[Z] = if (that==Z("0")) None else if (this==Z("0")) Some(Z("0")) else if (that==Z("1")) Some(Z("0")) else if (this.z.abs < that.z.abs) Some(this) else if (this.z == that.z) Some(Z("0") ) else this/that match {case None => None; case Some(z) => Some(this-z*that)}
def < (that: Z): Boolean = this.z < that.z def <= (that: Z): Boolean = this.z <= that.z def > (that: Z): Boolean = this.z > that.z def >= (that: Z): Boolean = this.z >= that.z
}
val elapsed: (=> Unit) => Long = f => {val s = System.currentTimeMillis; f; (System.currentTimeMillis - s)/1000}
val add: (Z,Z) => Z = (z1,z2) => z1+z2 val subtract: (Z,Z) => Z = (z1,z2) => z1-z2 val multiply: (Z,Z) => Z = (z1,z2) => z1*z2 val divide: (Z,Z) => Option[Z] = (z1,z2) => z1/z2 val modulo: (Z,Z) => Option[Z] = (z1,z2) => z1%z2
val ops = Map(("+",add),("-",subtract),("*",multiply),("/",divide),("%",modulo))
val calcs = List(
(Z("101"),"+",Z("10100"))
, (Z("101"),"-",Z("10100")) , (Z("101"),"*",Z("10100")) , (Z("101"),"/",Z("10100")) , (Z("-1010101"),"+",Z("10100")) , (Z("-1010101"),"-",Z("10100")) , (Z("-1010101"),"*",Z("10100")) , (Z("-1010101"),"/",Z("10100")) , (Z("1000101010"),"+",Z("10101010")) , (Z("1000101010"),"-",Z("10101010")) , (Z("1000101010"),"*",Z("10101010")) , (Z("1000101010"),"/",Z("10101010")) , (Z("10100"),"+",Z("1010")) , (Z("100101"),"-",Z("100")) , (Z("1010101010101010101"),"+",Z("-1010101010101")) , (Z("1010101010101010101"),"-",Z("-1010101010101")) , (Z("1010101010101010101"),"*",Z("-1010101010101")) , (Z("1010101010101010101"),"/",Z("-1010101010101")) , (Z("1010101010101010101"),"%",Z("-1010101010101")) , (Z("1010101010101010101"),"+",Z("101010101010101")) , (Z("1010101010101010101"),"-",Z("101010101010101")) , (Z("1010101010101010101"),"*",Z("101010101010101")) , (Z("1010101010101010101"),"/",Z("101010101010101")) , (Z("1010101010101010101"),"%",Z("101010101010101")) , (Z("10101010101010101010"),"+",Z("1010101010101010")) , (Z("10101010101010101010"),"-",Z("1010101010101010")) , (Z("10101010101010101010"),"*",Z("1010101010101010")) , (Z("10101010101010101010"),"/",Z("1010101010101010")) , (Z("10101010101010101010"),"%",Z("1010101010101010")) , (Z("1010"),"%",Z("10")) , (Z("1010"),"%",Z("-10")) , (Z("-1010"),"%",Z("10")) , (Z("-1010"),"%",Z("-10")) , (Z("100"),"/",Z("0")) , (Z("100"),"%",Z("0")) )
// just for result checking: import Z._ val iadd: (BigInt,BigInt) => BigInt = (a,b) => a+b val isub: (BigInt,BigInt) => BigInt = (a,b) => a-b val imul: (BigInt,BigInt) => BigInt = (a,b) => a*b val idiv: (BigInt,BigInt) => Option[BigInt] = (a,b) => if (b==0) None else Some(a/b) val imod: (BigInt,BigInt) => Option[BigInt] = (a,b) => if (b==0) None else Some(a%b) val iops = Map(("+",iadd),("-",isub),("*",imul),("/",idiv),("%",imod))
println("elapsed time: "+elapsed{
calcs foreach {case (op1,op,op2) => println(op1+" "+op+" "+op2+" = " +{(ops(op))(op1,op2) match {case None => None; case Some(z) => z; case z => z}} .ensuring{x=>(iops(op))(z2i(op1),z2i(op2)) match {case None => None == x; case Some(i) => i == z2i(x.asInstanceOf[Z]); case i => i == z2i(x.asInstanceOf[Z])}})} }+" sec"
)
}</lang> Output:
101Z(i:4) + 10100Z(i:11) = 100010Z(i:15) 101Z(i:4) - 10100Z(i:11) = -1010Z(i:-7) 101Z(i:4) * 10100Z(i:11) = 10010010Z(i:44) 101Z(i:4) / 10100Z(i:11) = 0Z(i:0) -1010101Z(i:-33) + 10100Z(i:11) = -1000001Z(i:-22) -1010101Z(i:-33) - 10100Z(i:11) = -10010010Z(i:-44) -1010101Z(i:-33) * 10100Z(i:11) = -101010001010Z(i:-363) -1010101Z(i:-33) / 10100Z(i:11) = -100Z(i:-3) 1000101010Z(i:109) + 10101010Z(i:54) = 10000101001Z(i:163) 1000101010Z(i:109) - 10101010Z(i:54) = 100000000Z(i:55) 1000101010Z(i:109) * 10101010Z(i:54) = 101000001000101001Z(i:5886) 1000101010Z(i:109) / 10101010Z(i:54) = 10Z(i:2) 10100Z(i:11) + 1010Z(i:7) = 101000Z(i:18) 100101Z(i:17) - 100Z(i:3) = 100001Z(i:14) 1010101010101010101Z(i:10945) + -1010101010101Z(i:-609) = 1010100000000000000Z(i:10336) 1010101010101010101Z(i:10945) - -1010101010101Z(i:-609) = 10000001010101010100Z(i:11554) 1010101010101010101Z(i:10945) * -1010101010101Z(i:-609) = -100010001000001001010010100100001Z(i:-6665505) 1010101010101010101Z(i:10945) / -1010101010101Z(i:-609) = -100101Z(i:-17) 1010101010101010101Z(i:10945) % -1010101010101Z(i:-609) = 1010100100100Z(i:592) 1010101010101010101Z(i:10945) + 101010101010101Z(i:1596) = 10000101010101010100Z(i:12541) 1010101010101010101Z(i:10945) - 101010101010101Z(i:1596) = 1010000000000000000Z(i:9349) 1010101010101010101Z(i:10945) * 101010101010101Z(i:1596) = 10001000100001010001001010001001001Z(i:17468220) 1010101010101010101Z(i:10945) / 101010101010101Z(i:1596) = 1001Z(i:6) 1010101010101010101Z(i:10945) % 101010101010101Z(i:1596) = 101000000001000Z(i:1369) 10101010101010101010Z(i:17710) + 1010101010101010Z(i:2583) = 100001010101010101001Z(i:20293) 10101010101010101010Z(i:17710) - 1010101010101010Z(i:2583) = 10100000000000000000Z(i:15127) 10101010101010101010Z(i:17710) * 1010101010101010Z(i:2583) = 1000100010001000000000001000100010001Z(i:45744930) 10101010101010101010Z(i:17710) / 1010101010101010Z(i:2583) = 1001Z(i:6) 10101010101010101010Z(i:17710) % 1010101010101010Z(i:2583) = 1010000000001000Z(i:2212) 1010Z(i:7) % 10Z(i:2) = 1Z(i:1) 1010Z(i:7) % -10Z(i:-2) = 1Z(i:1) -1010Z(i:-7) % 10Z(i:2) = -1Z(i:-1) -1010Z(i:-7) % -10Z(i:-2) = -1Z(i:-1) 100Z(i:3) / 0Z(i:0) = None 100Z(i:3) % 0Z(i:0) = None elapsed time: 1 sec
Tcl
<lang tcl>namespace eval zeckendorf {
# Want to use alternate symbols? Change these variable zero "0" variable one "1"
# Base operations: increment and decrement proc zincr var {
upvar 1 $var a namespace upvar [namespace current] zero 0 one 1 if {![regsub "$0$" $a $1$0 a]} {append a $1} while {[regsub "$0$1$1" $a "$1$0$0" a] || [regsub "^$1$1" $a "$1$0$0" a]} {} regsub ".$" $a "" a return $a
} proc zdecr var {
upvar 1 $var a namespace upvar [namespace current] zero 0 one 1 regsub "^$0+(.+)$" [subst [regsub "${1}($0*)$" $a "$0\[ string repeat {$1$0} \[regsub -all .. {\\1} {} x]]\[ string repeat {$1} \[expr {\$x ne {}}]]"] ] {\1} a return $a
}
# Exported operations proc eq {a b} {
expr {$a eq $b}
} proc add {a b} {
variable zero while {![eq $b $zero]} { zincr a zdecr b } return $a
} proc sub {a b} {
variable zero while {![eq $b $zero]} { zdecr a zdecr b } return $a
} proc mul {a b} {
variable zero variable one if {[eq $a $zero] || [eq $b $zero]} {return $zero} if {[eq $a $one]} {return $b} if {[eq $b $one]} {return $a} set c $a while {![eq [zdecr b] $zero]} { set c [add $c $a] } return $c
} proc div {a b} {
variable zero variable one if {[eq $b $zero]} {error "div zero"} if {[eq $a $zero] || [eq $b $one]} {return $a} set r $zero while {![eq $a $zero]} { if {![eq $a [add [set a [sub $a $b]] $b]]} break zincr r } return $r
} # Note that there aren't any ordering operations in this version
# Assemble into a coherent API namespace export \[a-y\]* namespace ensemble create
}</lang> Demonstrating: <lang tcl>puts [zeckendorf add "10100" "1010"] puts [zeckendorf sub "10100" "1010"] puts [zeckendorf mul "10100" "1010"] puts [zeckendorf div "10100" "1010"] puts [zeckendorf div [zeckendorf mul "10100" "1010"] "1010"]</lang>
- Output:
101000 101 101000001 1 10100