User input/Text

User input/Text
You are encouraged to solve this task according to the task description, using any language you may know.

In this task, the goal is to input a string and the integer 75000, from the text console.

See also: User Input - graphical

Ada

Works with: GCC version 4.1.2

<lang ada>function Get_String return String is

 Line : String (1 .. 1_000);
 Last : Natural;

begin

 Get_Line (Line, Last);
 return Line (1 .. Last);

end Get_String; function Get_Integer return Integer is

 S : constant String := Get_String;

begin

 return Integer'Value (S);
 --  may raise exception Constraint_Error if value entered is not a well-formed integer

end Get_Integer;</lang> The functions above may be called as shown below <lang ada>My_String  : String  := Get_String; My_Integer : Integer := Get_Integer;</lang>

ALGOL 68

<lang algol68>print("Enter a string: "); STRING s := read string; print("Enter a number: "); INT i := read int; ~</lang>

AutoHotkey

Windows console

<lang AutoHotkey>DllCall("AllocConsole") FileAppend, please type something`n, CONOUT$ FileReadLine, line, CONIN$, 1 msgbox % line FileAppend, please type '75000'`n, CONOUT$ FileReadLine, line, CONIN$, 1 msgbox % line</lang>

Input Command

this one takes input regardless of which application has focus. <lang AutoHotkey>TrayTip, Input:, Type a string: Input(String) TrayTip, Input:, Type an int: Input(Int) TrayTip, Done!, Input was recieved. Msgbox, You entered "%String%" and "%Int%" ExitApp Return

Input(ByRef Output) {

 Loop
 {
   Input, Char, L1, {Enter}{Space}
   If ErrorLevel contains Enter 
     Break
   Else If ErrorLevel contains Space
     Output .= " "
   Else 
     Output .= Char
   TrayTip, Input:, %Output%
 }

}</lang>

AWK

This demo shows a same-line prompt, and that the integer i becomes 0 if the line did not parse as an integer. <lang awk>~/src/opt/run $ awk 'BEGIN{printf "enter a string: "}{s=$0;i=$0+0;print "ok,"s"/"i}' enter a string: hello world ok,hello world/0 75000 ok,75000/75000</lang>

BASIC

Works with: QuickBasic version 4.5

 INPUT "Enter a string: ", s$
 INPUT "Enter a number: ", i%

Works with: FreeBASIC

 dim s as string
 dim i as integer
 
 input "Enter a string: ", s
 input "Enter the integer 75000: ", i

Befunge

This prompts for a string and pushes it to the stack a character at a time (~) until end of input (-1). <lang befunge><>:v:"Enter a string: "

^,_ >~:1+v
    ^    _@</lang>

Numeric input is easier, using the & command. <lang befunge><>:v:"Enter a number: "

^,_ & @</lang>

C

Works with: gcc

<lang c>#include <stdio.h> int main(int argc, char* argv[]) {

       int input;
       if((scanf("%d", &input))==1)
       {
               printf("Read in %d\n", input);
               return 1;
       }
       return 0;

}</lang>

C++

Works with: g++

<lang cpp>#include <iostream>

1. include <string>

using namespace std;

int main() {

    // while probably all current implementations have int wide enough for 75000, the C++ standard
    // only guarantees this for long int.
    long int integer_input;
    string string_input;
    cout << "Enter an integer:  ";
    cin >> integer_input;
    cout << "Enter a string:  ";
    cin >> string_input;
    return 0;

}</lang>

Note: The program as written above only reads the string up to the first whitespace character. To get a complete line into the string, replace <lang cpp> cin >> string_input;</lang> with <lang cpp> getline(cin, string_input);</lang>

Note: if a numeric input operation fails, the value is not stored for that operation, plus the fail bit is set, which causes all future stream operations to be ignored (e.g. if a non-integer is entered for the first input above, then nothing will be stored in either the integer and the string). A more complete program would test for an error in the input (with if (!cin) // handle error) after the first input, and then clear the error (with cin.clear()) if we want to get further input.

Alternatively, we could read the input into a string first, and then parse that into an int later.

C#

<lang csharp>using System;

namespace C_Sharp_Console {

   class example {

       static void Main() {
           string word;
           int num;
           
           Console.Write("Enter an integer: ");
           num = Console.Read();
           Console.Write("Enter a String: ");
           word = Console.ReadLine();
       }
   }

}</lang>

Clojure

<lang lisp>(import '(java.util Scanner)) (def scan (Scanner. *in*)) (def s (.nextLine scan)) (def n (.nextInt scan))</lang>

Common Lisp

<lang lisp>(format t "Enter some text: ") (let ((s (read-line)))

   (format t "You entered ~s~%" s))

(format t "Enter a number: ") (let ((n (read)))

   (if (numberp n)
       (format t "You entered ~d.~%" n)
     (format t "That was not a number.")))</lang>

D

<lang D>import tango.io.Console; import Integer = tango.text.convert.Integer;

void main() {

 int num;
 char[] word;
 Cout("Enter an integer:")();
 num = Integer.parse(Cin.get());
 Cout("Enter a string:")();
 word = Cin.get();
}</lang>

Erlang

<lang erlang>{ok, [String]} = io:fread("Enter a string: ","~s"). {ok, [Number]} = io:fread("Enter a number: ","~d").</lang>

Alternatively, you could use io:get_line to get a string: <lang erlang> String = io:get_line("Enter a string: ").</lang>

FALSE

FALSE has neither a string type nor numeric input. Shown instead are routines to parse and echo a word and to parse and interpret a number using the character input command (^). <lang false>[[^$' =~][,]#,]w: [0[^'0-$$9>0@>|~][\10*+]#%]d: w;! d;!.</lang>

Forth

Input a string

<lang forth>: INPUT$ ( n -- addr n )

  PAD SWAP ACCEPT
  PAD SWAP ;</lang>

Input a number

The only ANS standard number interpretation word is >NUMBER ( ud str len -- ud str len ), which is meant to be the base factor for more convenient (but non-standard) parsing words. <lang forth>: INPUT# ( -- u true | false )

 0. 16 INPUT$ DUP >R
 >NUMBER NIP NIP 
 R> <> DUP 0= IF NIP THEN ;</lang>

Works with: GNU Forth

<lang forth>: INPUT# ( -- n true | d 1 | false )

  16 INPUT$ SNUMBER? ;</lang>

Works with: Win32Forth

<lang forth>: INPUT# ( -- n true | false )

  16 INPUT$ NUMBER? NIP
  DUP 0= IF NIP THEN ;</lang>

Note that NUMBER? always leaves a double result on the stack. INPUT# returns a single precision number. If you desire a double precision result, remove the NIP.

Here is an example that puts it all together:

<lang forth>: TEST

 ." Enter your name: " 80 INPUT$ CR
 ." Hello there, " TYPE CR
 ." Enter a number: " INPUT# CR
 IF   ." Your number is " .
 ELSE ." That's not a number!" THEN CR ;</lang>

Fortran

Works with: Fortran version 90 and later

<lang fortran>character(20) :: s integer :: i

print*, "Enter a string (max 20 characters)" read*, s print*, "Enter the integer 75000" read*, i</lang>

Groovy

<lang groovy>word = System.in.readLine() num = System.in.readLine().toInteger()</lang>

Haskell

<lang haskell>import System.IO (hFlush, stdout) main = do

   putStr "Enter a string: "
   hFlush stdout
   str <- getLine
   putStr "Enter an integer: "
   hFlush stdout
   num <- readLn :: IO Int 
   putStrLn $ str ++ (show num)</lang>

Note: :: IO Int is only there to disambiguate what type we wanted from read. If num were used in a numerical context, its type would have been inferred by the interpreter/compiler. Note also: Haskell doesn't automatically flush stdout when doing input, so explicit flushes are necessary.

J

<lang j>require 'misc' NB. load system script</lang> <lang j>prompt 'Enter string: '

0".prompt 'Enter 75000: '</lang> Both of these sentences return the user provided input. But this implementation implements no error checking: For example, if a different number is entered at the second prompt, it will be used instead of 75000.

Java

<lang java>import java.io.BufferedReader; import java.io.InputStreamReader;

public class GetInput {

   public static void main(String[] args) throws Exception {
       BufferedReader sysin = new BufferedReader(new InputStreamReader(System.in));
       int number = Integer.parseInt(sysin.readLine());
       String string = sysin.readLine();
   }

}</lang>

or

Works with: Java version 1.5/5.0+

<lang java>import java.util.Scanner;

Scanner stdin = new Scanner(System.in); String string = stdin.nextLine(); int number = stdin.nextInt();</lang>

JavaScript

Works with: JScript

and only with cscript.exe

<lang javascript>WScript.Echo("Enter a string"); var str = WScript.StdIn.ReadLine();

var val = 0; while (val != 75000) {

   WScript.Echo("Enter the integer 75000");
   val = parseInt( WScript.StdIn.ReadLine() );

}</lang>

Works with: SpiderMonkey

<lang javascript>print("Enter a string"); var str = readline();

var val = 0; while (val != 75000) {

   print("Enter the integer 75000");
   val = parseInt( readline() );

}</lang>

Logo

Logo literals may be read from a line of input from stdin as either a list or a single word. <lang logo>make "input readlist  ; in: string 75000 show map "number? :input  ; [false true]

make "input readword  ; in: 75000 show :input + 123  ; 75123 make "input readword  ; in: string 75000 show :input  ; string 75000</lang>

Mathematica

<lang Mathematica>mystring = InputString["give me a string please"]; myinteger = Input["give me an integer please"];</lang>

Metafont

<lang metafont>string s; message "write a string: "; s := readstring; message s; message "write a number now: "; b := scantokens readstring; if b = 750:

 message "You've got it!"

else:

 message "Sorry..."

fi; end</lang>

If we do not provide a number in the second input, Metafont will complain. (The number 75000 was reduced to 750 since Metafont biggest number is near 4096).

mIRC Scripting Language

<lang mirc>alias askmesomething {

 echo -a You answered: $input(What's your name?, e)

}</lang>

Modula-3

<lang modula3>MODULE Input EXPORTS Main;

IMPORT IO, Fmt;

VAR string: TEXT;

   number: INTEGER;

BEGIN

 IO.Put("Enter a string: ");
 string := IO.GetLine();
 IO.Put("Enter a number: ");
 number := IO.GetInt();
 IO.Put("You entered: " & string & " and " & Fmt.Int(number) & "\n");

END Input.</lang>

newLISP

Works with: newLISP version 9.0

<lang lisp>(print "Enter an integer: ") (set 'x (read-line)) (print "Enter a string: ") (set 'y (read-line))</lang>

OCaml

<lang ocaml>print_string "Enter a string: "; let str = read_line () in

 print_string "Enter an integer: ";
 let num = read_int () in
   Printf.printf "%s%d\n" str num</lang>

Octave

<lang octave>% read a string ("s") s = input("Enter a string: ", "s");

% read a GNU Octave expression, which is evaluated; e.g. % 5/7 gives 0.71429 i = input("Enter an expression: ");

% parse the input for an integer printf("Enter an integer: "); ri = scanf("%d");

% show the values disp(s); disp(i); disp(ri);</lang>

Pascal

<lang pascal>program UserInput(input, output); var i : Integer;

   s : String;

begin

write('Enter an integer: ');
readln(i);
write('Enter a string: ');
readln(s)

end.</lang>

Perl

Works with: Perl version 5.8.8

<lang perl>#!/usr/bin/perl

my $string = <>; # equivalent to readline(*STDIN) my $integer = <>;</lang>

PHP

Works with: CLI SAPI

<lang php>#!/usr/bin/php <?php $string = fgets(STDIN); $integer = (int) fgets(STDIN);</lang>

Pop11

<lang pop11>;;; Setup item reader lvars itemrep = incharitem(charin); lvars s, c, j = 0;

read chars up to a newline and put them on the stack

while (charin() ->> c) /= `\n` do j + 1 -> j ; c endwhile;

build the string

consstring(j) -> s;

read the integer

lvars i = itemrep();</lang>

PostScript

Works with: PostScript version level-2

<lang postscript>%open stdin for reading (and name the channel "kbd"): /kbd (%stdin) (r) file def %make ten-char buffer to read string into: /buf (..........) def %read string into buffer: kbd buf readline</lang>

At this point there will be two items on the stack: a boolean which is "true" if the read was successful and the string that was read from the kbd (input terminates on a <return>). If the length of the string exceeds the buffer length, an error condition occurs (rangecheck). For the second part, the above could be followed by this:

<lang postscript>%if the read was successful, convert the string to integer: {cvi} if</lang>

which will read the conversion operator 'cvi' (convert to integer) and the boolean and execute the former if the latter is true.

PowerShell

<lang powershell>$string = Read-Host "Input a string" $number = Read-Host "Input a number"</lang>

Python

Input a string

<lang python> string = raw_input("Input a string: ")</lang> In Python 3.0, raw_input will be renamed to input(). The Python 3.0 equivalent would be <lang python> string = input("Input a string: ")</lang>

Input a number

While input() gets a string in Python 3.0, in 2.x it is the equivalent of eval(raw_input(...)). Because this runs arbitrary code, and just isn't nice, it is being removed in Python 3.0. raw_input() is being changed to input() because there will be no other kind of input function in Python 3.0. <lang python> number = input("Input a number: ") # Deprecated, please don't use.</lang> Python 3.0 equivalent: <lang python> number = eval(input("Input a number: ")) # Evil, please don't use.</lang> The preferred way of getting numbers from the user is to take the input as a string, and pass it to any one of the numeric types to create an instance of the appropriate number. <lang python> number = float(raw_input("Input a number: "))</lang> Python 3.0 equivalent: <lang python> number = float(input("Input a number: "))</lang> float may be replaced by any numeric type, such as int, complex, or decimal.Decimal. Each one varies in expected input.

R

Works with: R version 2.81

<lang R>stringval <- readline("String: ") intval <- as.integer(readline("Integer: "))</lang>

Raven

<lang raven>'Input a string: ' print expect as str 'Input an integer: ' print expect 0 prefer as num</lang>

REXX

<lang rexx>do until i = 75000

 say "Input 75000"
 pull i

end</lang>

Ruby

Works with: Ruby version 1.8.4

<lang ruby>print "Enter a string: " s = gets print "Enter an integer: " i = gets.to_i # If string entered, will return zero puts "String = " + s puts "Integer = " + i.to_s</lang>

Scheme

The read procedure is R5RS standard, inputs a scheme representation so, in order to read a string, one must enter "hello world" <lang scheme>(define str (read)) (define num (read)) (display "String = ") (display str) (display "Integer = ") (display num)</lang>

Slate

<lang slate>print: (query: 'Enter a String: '). [| n |

 n: (Integer readFrom: (query: 'Enter an Integer: ')).
 (n is: Integer)
   ifTrue: [print: n]
   ifFalse: [inform: 'Not an integer: ' ; n printString]

] do.</lang>

Smalltalk

<lang smalltalk>'Enter a number: ' display. a := stdin nextLine asInteger.

'Enter a string: ' display. b := stdin nextLine.</lang>

Standard ML

<lang sml>print "Enter a string: "; let val str = valOf (TextIO.inputLine TextIO.stdIn) in (* note: this keeps the trailing newline *)

 print "Enter an integer: ";
 let val num = valOf (TextIO.scanStream (Int.scan StringCvt.DEC) TextIO.stdIn) in
   print (str ^ Int.toString num ^ "\n")
 end

end</lang>

Tcl

Like LISP, there is no concept of a "number" in TCL - the only real variable type is a string (whether a string might represent a number is a matter of interpretation of the string in a mathematical expression at some later time). Thus the input is the same for both tasks:

<lang tcl>set str [gets stdin] set num [gets stdin]</lang>

possibly followed by something like

<lang tcl>if {![string is integer -strict $num]} then { ...do something here...}</lang>

If the requirement is to prompt until the user enters the integer 75000, then: <lang tcl>set input 0 while {$input != 75000} {

   puts -nonewline "enter the number '75000': "
   flush stdout
   set input [gets stdin]

}</lang>

Of course, it's nicer to wrap the primitives in a procedure: <lang tcl>proc question {var message} {

   upvar 1 $var v
   puts -nonewline "$message: "
   flush stdout
   gets stdin $v

} question name "What is your name" question task "What is your quest" question doom "What is the air-speed velocity of an unladen swallow"</lang>

TI-89 BASIC

This program leaves the requested values in the global variables s and integer.

<lang ti89b>Prgm

 InputStr "Enter a string", s
 Loop
   Prompt integer
   If integer ≠ 75000 Then
     Disp "That wasn't 75000."
   Else
     Exit
   EndIf
 EndLoop

EndPrgm</lang>

Toka

<lang toka>needs readline ." Enter a string: " readline is-data the-string ." Enter a number: " readline >number [ ." Not a number!" drop 0 ] ifFalse is-data the-number

the-string type cr the-number . cr</lang>

UNIX Shell

Works with: Debian Almquish SHell

<lang bash>#!/bin/sh

read STRING read INTEGER</lang>

Works with: Bourne Again SHell

<lang bash>#!/bin/bash

read STRING read INTEGER</lang>

Vedit macro language

<lang vedit>Get_Input(1, "Enter a string: ")

1. 2 = Get_Num("Enter a number: ")</lang>

Visual Basic .NET

Platform: .NET

Works with: Visual Basic .NET version 9.0+

Input an Integer

<lang vbnet>Dim i As Integer Console.WriteLine("Enter an Integer") i = Console.ReadLine()</lang>

Input an Integer With Error Handling

<lang vbnet>Dim i As Integer Dim iString As String Console.WriteLine("Enter an Integer") iString = Console.ReadLine() Try

   i = Convert.ToInt32(iString)

Catch ex As Exception

   Console.WriteLine("This is not an Integer")

End Try</lang>

Input a String

<lang vbnet>Dim i As String Console.WriteLine("Enter a String") i = Console.ReadLine()</lang>